question: John has $2500 in his bank account that earns 10% interest every year. How much will be in John's bank account after one year?
Options:
(A) $2600
(B) $3000
(C) $2250
(D) $2750
(E) $3500
answer: Stream of consciousness: Final number = Initial number + 20%(original number) = 2500 + 10%(2500) = 2500 + 250 = 2750. The answer is (D).

q: A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 200. How much did he have with him in the beginning?
Options:
(A) s 200
(B) s 500
(C) s 300
(D) s 450
(E) s 550
a: Stream of consciousness: Suppose the amount in the beginning was Rs 'x'
Money spent on clothes = Rs 1x/3 Balance = Rs 2x/3
Money spent on food = 1/5 of 2x/3 = Rs 2x/15
Balance = 2x/3 - 2x/15 = Rs 8x/15
Money spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5
Therefore 2x/5 = 200 = 500 The answer is (B).

question: Every day, Fred takes the train to travel from his work back to Alkmaar, his place of residence. Usually, he arrives at the station of Alkmaar at six o'clock, and exactly at that moment, his wife picks him up by car. Yesterday evening, Fred took an earlier train, without informing his wife, and therefore he already was at the station of Alkmaar at five o'clock. He decided to walk part of the way to meet his wife. When he met the car with his wife, he drove home with her. In this way, they were home ten minutes earlier than normal. Fred's wife always drives the entire way between home and station at the same constant speed.How long did Fred walk yesterday evening?
Options:
(A) 55
(B) 45
(C) 58
(D) 65
(E) 59
answer: Stream of consciousness: Fred's wife needed to drive ten minutes less than usual, which is five minutes less in the direction of the station and five minutes less back home. Therefore, Fred met his wife at five minutes to six. He had walked already since five o'clock, so he walked 55 minutes in total. The answer is (A).

q: A and B can do a work in 5 days and 10 days respectively. A starts the work and B joins him after 4 days. In how many days can they complete the remaining work?
Options:
(A) 6 days
(B) 2/3 days
(C) 8 days
(D) 3 days
(E) 9 days
a: Stream of consciousness: Work done by A in 4 days = 4/5
Remaining work = 1/5
Work done by both A and B in one day = 1/5 + 1/10 = 3/10
Remaining work = 1/5 * 10/3 = 2/3 days. The answer is (B).

question: If P(A) = 8/15, P(B) = 4/15, and P(A B) = 16/15 Find P(B|A)
Options:
(A) 1/2
(B) 2/3
(C) 3/2
(D) 2
(E) 4/7
answer: Stream of consciousness: P(B|A) = P(A B)/P(A)
P(B|A) = (16/15)/(8/15) = 2. The answer is (D).

question: Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 5 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is?
Options:
(A) 60 gallons
(B) 200 gallons
(C) 120 gallons
(D) 180 gallons
(E) 130 gallons
answer:
Stream of consciousness: Work done by the waste pipe in 1 minute = 1/15 - (1/20 + 1/24) = - 1/40
Volume of 1/40 part = 5 gallonsVolume of whole = 5 * 40 = 200 gallons. The answer is (B).