Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is
Options:
(A) 1
(B) 3
(C) 4
(D) 0
(E) 2 Hmmm, my stream of consciousness:
4 points are possible in which 1 point is the incentre of the circle and other 3 are excentres So, the answer is (C).