q: X can finish a work in 18 days. Y can finish the same work in 15 days. Yworked for 10 days and left the job. how many days does X alone need to finish the remaining work?
Options:
(A) 2
(B) 3
(C) 6
(D) 8
(E) 9
a: OK... Work done by X in 1 day = 1/18
Work done by Y in 1 day = 1/15
Work done by Y in 10 days = 10/15 = 2/3
Remaining work = 1 2/3 = 1/3
Number of days in which X can finish the remaining work = (1/3) / (1/18) = 6
The answer is (C).

q: Find the odd man out
445, 221, 109, 46, 25, 11, 4
Options:
(A) 221
(B) 109
(C) 46
(D) 25
(E) 21
a: OK... 4*2+3 = 11
11*2+3 = 25
25*2+3 = 53
53*2+3 = 109
109*2+3 = 221
221*2+3 = 445
The answer is (C).

q: A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 30 as remainder. Find the no. is?
Options:
(A) 122443
(B) 154546
(C) 165454
(D) 186545
(E) 220030
a:
OK... (555 + 445) * 2 * 110 + 30 = 220000 + 30 = 220030
The answer is (E).