q: 3 candidates in an election and received 1136, 7636 and 11628 votes respectively. What % of the total votes did the winningcandidate got in that election?
Options:
(A) 34%
(B) 56%
(C) 57%
(D) 67%
(E) 78%
a: OK... Total number of votes polled = (1136 + 7636 + 11628) = 20400
So, Required percentage = 11628/20400 * 100 = 57%
The answer is (C).

q: Of the families in City X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. what percent of the families in City X owned a personal computer in 1998?
Options:
(A) 50%
(B) 52%
(C) 56%
(D) 70%
(E) 74%
a: OK... Say a 100 families existed in 1994 then the number of families owning a computer in 1994 - 40
Number of families owning computer in 1998 = 40 * 130/100 = 52
Number of families in 1998 = 104
The percentage = 52/104 * 100 = 50%.
The answer is (A).

q: The average mark obtained by 23 candidates in an examination is 45. The average of the first ten is 55 while the last eleven is 40 .The marks obtained by the 11th candidate is ?
Options:
(A) 26
(B) 45
(C) 90
(D) 80
(E) 65
a:
OK... It is clear that 23 x 45 = 10 x 55 + K + 11 x 40 K = 45
The answer is (B).