Q: Santana has 7 brothers. 3 of them have birthdays in March, 1 of them has a birthday in October, 1 has a birthday in November, and another 2 of them were born in December. If Santana always buys each of her brothers a birthday present and a Christmas present, how many more presents does she have to buy in the second half of the year than the first half of the year?
A: Santana has 1 + 1 + 2 = 4 brothers with birthdays in the second half of the year. She has 7 brothers - 4 brothers = 3 brothers with birthdays in the first half of the year. Altogether, she has to buy 4 + 7 = 11 presents in the second half of the year. Therefore, she has to buy 11 - 3 = 8 more presents in the second half of the year. The answer is 8.

Q: George and Amelia are picking oranges and apples at an orchard. George picks 45 oranges and 5 more apples than Amelia. Amelia picks 18 fewer oranges than George and 15 apples. How many fruits do they pick altogether?
A: Amelia picks 45 - 18 = 27 oranges. The total number of oranges that they pick is 45 + 27 = 72. George picks 15 + 5 = 20 apples. The total number of apples that they pick is 20 + 15 = 35. So, they pick 72 + 35 = 107 fruits altogether. The answer is 107.

Q: Terese thinks that running various distances throughout the week can make one healthy. On Monday, she runs 4.2 miles; Tuesday, 3.8 miles; Wednesday, 3.6 miles; and on Thursday, 4.4 miles. Determine the average distance Terese runs on each of the days she runs.
A:
The total distance Terese runs is 4.2 + 3.8 + 4.4 + 3.6 = 16 miles. Therefore, she runs with an average distance of 16 / 4 = 4 miles. The answer is 4.