(Ans). (A)
(Question). John has 10pairs of dark blue socks and 10pairs of black socks. He keeps them all in the same bag. If he picks out 3socks at random, then what is the probability thathe will get a matching pair?
Options:
(A) 1
(B) 3
(C) 4
(D) 5
(E) 6
(CoT). If he draws any combination of 3 socks he will definitely have the matching pair of either colour.

(Ans). (C)
(Question). A boy multiplied 987 by a certain number and obtained 559981 as his answer. If in the answer both 9 are wrong and the other digits are correct, then the correct answer would be:
Options:
(A) 553681
(B) 555181
(C) 555681
(D) 556581
(E) 556881
(CoT). 987 = 3 x 7 x 47
So, the required number must be divisible by each one of 3, 7, 47
553681->(Sum of digits = 28, not divisible by 3)
555181->(Sum of digits = 25, not divisible by 3)
555681 is divisible by 3, 7, 47

(Ans). (C)
(Question). The year next to 1991 having the same calendar as that of 1990 is
Options:
(A) 1998
(B) 2001
(C) 2002
(D) 2003
(E) None of these
(CoT). We go on counting the odd days from 1991 onward still the sum is divisible by 7. The number of such days are 14 upto the year 2001. So, the calender for 1991 will be repeated in the year 2002.

(Ans). (D)
(Question).
If a company allocates 25 percent of its budget to advertising, 15 percent to capital improvements, and 55 percent to salaries, what fraction of its budget remains for other allocations?
Options:
(A) 4/5
(B) 3/5
(C) 3/10
(D) 1/20
(E) 1/40
(CoT). 25 + 15 + 55 = 95% 100 - 95 = 5% to all others