Javier is an Olympic javelin thrower. In the last Olympics, he threw the javelin three times. The first throw, he threw the javelin twice as far as he threw the javelin on his second throw, but only half as far as he threw it the third throw. If the sum of all three throws was 1050 meters, then how far, in meters, did he throw the javelin on his first throw? Let's think first. Chain of thought:
Let x be the distance he threw the javelin on the first throw. Thus, the sum of his three throws is x + 0.5x + 2x = 1050 meters. Thus, 3.5x = 1050. And we find the distance he threw the javelin on the first throw is x = 300 meters.
Therefore, the answer is 300.