## Solution
In 1 kg mixture quantity of iron = 200 gm
Let x gm sand should be added, then
10% of (1000 + x) = 200
\ x = 1000 gm = 1 kg
## What the question and answer could be
In 1 kg mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10%?
Options:
(A) 1 kg
(B) 200 gms
(C) 800 gms
(D) 1.8 kg
(E) None of these
(A)

## Solution
Given Exp. = (12)3 x 64 = (12)3 x 64 = (12)2 x 62 = (72)2 = 5184
432 12 x 62
## What the question and answer could be
Find the value of y from (12)^3 x 6^4 432 = y?
Options:
(A) 4567
(B) 3435
(C) 5667
(D) 4567
(E) 5184
(E)

## Solution
(60/100) * 50 (40/100) * 30
30 - 12 = 18
## What the question and answer could be
How much 60% of 50 is greater than 40% of 30?
Options:
(A) 18
(B) 28
(C) 29
(D) 11
(E) 12
(A)

## Solution
Work done by X in 1 day = 1/24
Work done by Y in 1 day = 1/16
Work done by Y in 10 days = 10/16 = 5/8
Remaining work = 1 5/8 = 3/8
Number of days in which X can finish the remaining work = (3/8) / (1/24) = 9
## What the question and answer could be
X can finish a work in 24 days. Y can finish the same work in 16 days. Yworked for 10 days and left the job. how many days does X alone need to finish the remaining work?
Options:
(A) 3
(B) 5
(C) 6
(D) 8
(E) 9
(E)