Question. Find the 100th place digit of a number forming from digits 1 to 9 without repeatation and number passes the divisibility test of 11 means difference of sum of alternative digits is 0 or divisible by 11.
Options:
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Answer. (D)
What step-by-step reasoning justifies that answer?
Reasoning: Largest no is 987652413
So digit will be 4