I can use this background: When waves travel into areas of shallow water, they begin to be affected by the ocean bottom. The free orbital motion of the water is disrupted, and water particles in orbital motion no longer return to their original position. As the water becomes shallower, the swell becomes higher and steeper, ultimately assuming the familiar sharp-crested wave shape. After the wave breaks, it becomes a wave of translation and erosion of the ocean bottom intensifies. Now, I have a new situation: Most surfers used Wide beach because of the areas of shallow water, but some surfers were happy with Sandy beach, although the water was much deeper at the shore there. Answer this question please: Which beach had better and larger waves?
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Answer: Wide beach

I can use this background: The water level is seasonal, being lowered by about 10 feet (3.0 m) over the winter. The reservoir fills in the spring from snow melt and underground springs. The lake is usually at full level by late spring, but in the occasional years of low snow melt and low rainfall, it may remain up to several feet below its typical level. Water is let out of the lake in the fall so that ice will not damage docks and other structures around the lake. This also leads to excellent water quality, as a significant portion of the water is replaced every year. Now, I have a new situation: There are two hydroelectric dams in North Dakota. Both of them has large lakes or reservoirs, reservoir A and reservoir B. Since North Dakota has one the lowest unemployment rates in the country, it's hard to find an engineer to regulate and maintain the reservoirs. This year reservoir A could hire an engineer, but reservoir B failed to find an engineer. As a result, there is no one to regulate reservoir B. The engineer for reservoir A let the water out in the fall. But there was no one to do that for reservoir B. Answer this question please: Which reservoir would most likely not casue damaged dock, reservoir A or reservoir B?
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Answer: reservoir A

I can use this background: Ammonia toxicity is believed to be a cause of otherwise unexplained losses in fish hatcheries. Excess ammonia may accumulate and cause alteration of metabolism or increases in the body pH of the exposed organism. Tolerance varies among fish species. At lower concentrations, around 0.05 mg/L, un-ionised ammonia is harmful to fish species and can result in poor growth and feed conversion rates, reduced fecundity and fertility and increase stress and susceptibility to bacterial infections and diseases. Exposed to excess ammonia, fish may suffer loss of equilibrium, hyper-excitability, increased respiratory activity and oxygen uptake and increased heart rate. At concentrations exceeding 2.0 mg/L, ammonia causes gill and tissue damage, extreme lethargy, convulsions, coma, and death. Experiments have shown that the lethal concentration for a variety of fish species ranges from 0.2 to 2.0 mg/l.During winter, when reduced feeds are administered to aquaculture stock, ammonia levels can be higher. Lower ambient temperatures reduce the rate of algal photosynthesis so less ammonia is removed by any algae present. Within an aquaculture environment, especially at large scale, there is no fast-acting remedy to elevated ammonia levels. Prevention rather than correction is recommended to reduce harm to farmed fish and in open water systems, the surrounding environment. Now, I have a new situation: Woodland had two nearby fish hatcheries. Pine hatchery had great result the past few years because they found a way to reduce ammonia water toxicity. Spruce hatchery has big ammonia toxicity problems and hadn't find a way to remediate them. Answer this question please: Which hatchery found more fish with an increased body pH?
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Answer:
Spruce