In 2 bags, there are to be put together 5 red and 12 white balls, neither bag being empty. How must the balls be divided so as to give a person who draws 1 ball from either bag-
Options:
(A) 9/18
(B) 9/16
(C) 9/11
(D) 9/12
(E) 9/13 OK. Let's think. Some random thoughts first:
(1) Put 1 white in first bag, and all the remaining ball in second bag. Probability = 120+12516120+12516 = 532532
(2) To maximize, we put 1 red in the first bag, and all the remaining in the second. Probability = 121+12432121+12432 = 9/16 The answer: (B).