question: For some integer y, y^2 - 5 is divisible by all of the following EXCEPT
Options:
(A) 29
(B) 30
(C) 31
(D) 38
(E) 41
answer: Stream of consciousness: Hint: y^2-5 (y is an integer) is never multiple of 3 (try to prove this), hence 30 is out. The answer is (B).

q: Four of the five parts numbered (a), (b), (c), (d) and (e) in the following equation are exactly equal. Which part is not equal to the other four ? The number of that part is the answer.
Options:
(A) (x + 2y) (3x + 2y)
(B) (x + 2y) 2 + 2x(x + 2y)
(C) (3x + 2y) 2 2x(3x + 2y)
(D) 3x(x + 2y) + 2y(x + 2y)
(E) x(3x + 2y) 2y(3x 2y)
a: Stream of consciousness: Others are equal to 3x2 + 8xy + 4y2 The answer is (E).

question: What should come in the place of the question mark(?) in the following equation?
69012 20167 + (51246 6) = ?
Options:
(A) 57385
(B) 57286
(C) 57476
(D) 57368
(E) None of these
answer: Stream of consciousness: ? = 48845 + 512466 = 48845 + 8541 = 57386 The answer is (E).

q: How many terminating zeroes Q does 200! have?
Options:
(A) 40
(B) 48
(C) 49
(D) 55
(E) 64
a: Stream of consciousness: You have 40 multiples of 5, 8 of 25 and 1 of 125. This will give 49 zeros. The answer is (C).

question: The price of a T.V. set worth Rs. 10000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be?
Options:
(A) 9000
(B) 26699
(C) 96000
(D) 19000
(E) 26711
answer: Stream of consciousness: Money paid in cash = Rs. 1000
Balance payment = (10000 - 1000) = Rs. 9000 The answer is (A).

question: The average of five numbers is 41. The average of first two numbers is 32 and the average of last two numbers is 38. What is the middle number?
Options:
(A) 59
(B) 64
(C) 61
(D) 72
(E) 65
answer:
Stream of consciousness: The total of five numbers = 5X41 = 205
The total of first 2 and last 2 numbers is = 2 X 32+2 X 38 = 140
So, the middle number is (205 - 140 ) = 65 The answer is (E).