Rationale: Given Speed = k/n
To Find distance in x hours with same speed
Distance = speed * time
Distance = k/n*x = kx/n
The answer: (D)
Question: A deer runs k miles in n hours. How many miles will it run in x hours at the same rate?
Options:
(A) knx
(B) kn
(C) kx2n
(D) kxn
(E) knx
Reasoning: Increase = (30/40)*100 = (3/4)*100 = 75%.
Ans: (E)
Question: John makes $40 a week from his job. He earns a raise and now makes $70 a week. What is the % increase?
Options:
(A) 16%
(B) 16.66%
(C) 17.9%
(D) 18.12%
(E) 75%
Rationale: A = 7500(26/25)^5 = 9125
The answer: (D)
Question: If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 5 years the amount to be paid is?
Options:
(A) 3377
(B) 2688
(C) 2688
(D) 9125
(E) 1268
Reasoning: 12/43 m/s = 12/43 * 18/5 = 1 (1/250) = 1 kmph.
Ans: (C)
Question: Convert the 12/43 m/s into kilometers per hour?
Options:
(A) 3.5 kmph.
(B) 2.5 kmph.
(C) 1 kmph.
(D) 1.5 kmph.
(E) 1.9 kmph.
Rationale: 34 + 28 + 10 = 72%
100 72 = 28%
850 * 28/100 = 238
The answer: (D)
Question: In a school of 850 boys, 34% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
Options:
(A) A) 125
(B) B) 627
(C) C) 153
(D) D) 238
(E) E) 159
Rationale: Assume the price = 100
Price during sale = 90
Price after sale = 100
Percent increase = 10/90*100 = 11% approx.
The answer: (C)
Question: During a sale, the price of a pair of shoes is marked down 10% from the regular price. After the sale ends, the price goes back to the original price. What is the percent of increase to the nearest percent from the sale price back to the regular price for the shoes?
Options:
(A) 9%
(B) 10%
(C) 11%
(D) 15%
(E) 90%