TASK DEFINITION: Given a question and a context passage, generate the answer having the word or phrase from the context passage. Here, the answer should be a shortest continous span from the passage.
PROBLEM: Context: Ca2+ is a ubiquitous intracellular messenger responsible for controlling numerous cellular processes including fertilization, mitosis, neuronal transmission, contraction and relaxation of muscles, gene transcription, and cell death. At rest, the cytoplasmic Ca2+ concentration [Ca2+]i is approximately 100 nM, but this level rises to 500-1,000 nM upon activation. In osteoblasts, the elevation of [Ca2+]i is a result of an increase in the release of Ca2+ from endoplasmic reticulum and/or extracellular Ca2+ influx through voltage gated Ca2+ channels. Many of the cellular effects of Ca2+ are mediated by the Ca2+ binding protein, calmodulin (CaM). Upon binding up to four calcium ions, CaM undergoes a conformational change, which enables it to bind to specific proteins eliciting a specific response. Calmodulin kinase II (CaMKII) is a major target of the Ca(2+)/CaM second messenger system. Once bound to Ca(2+)/CaM, the multimeric CaMKII is released from its autoinhibitory status and maximally activated, which then leads to an intraholoenzyme autophosphorylation reaction. Calcineurin (Cn) is another major target protein that is activated by Ca(2+)/CaM. Cn is a serine-threonine phosphatase that consists of a heterodimeric protein complex composed of a catalytic subunit (CnA) and a regulatory subunit (CnB). Upon activation, Cn directly binds to, and dephosphorylates nuclear factor of activated T cells (NFAT) transcription factors within the cytoplasm allowing them to translocate to the nucleus and participate in the regulation of gene expression. This review will examine the potential mechanisms by which calcium, CaM, CaMKII, and Cn/NFAT control osteoblast proliferation and differentiation.
Question: Which calcium/calmodulin dependent protein phosphatase is involved in the activation of the family of NFAT transcription factors (Nuclear Factors of Activated T cells)?

SOLUTION: can

PROBLEM: Context: What determines if a baby is a male or female? Recall that you have 23 pairs of chromosomesand one of those pairs is the sex chromosomes. Everyone has two sex chromosomes. Your sex chromosomes can be X or Y. Females have two X chromosomes (XX), while males have one X chromosome and one Y chromosome (XY). If a baby inherits an X chromosome from the father and an X chromosome from the mother, what will be the childs sex? The baby will have two X chromosomes, so it will be female. If the fathers sperm carries the Y chromosome, the child will be male. Notice that a mother can only pass on an X chromosome, so the sex of the baby is determined by the father. The father has a 50 percent chance of passing on the Y or X chromosome, so there is a 50 percent chance that a child will be male, and there is a 50 percent chance a child will be female. This 50:50 chance occurs for each baby. A couples first five children could all be boys. The sixth child still has a 50:50 chance of being a girl. One special pattern of inheritance that doesnt fit Mendels rules is sex-linked inheritance, referring to the inher- itance of traits that are located on genes on the sex chromosomes. Since males and females do not have the same sex chromosomes, there will be differences between the sexes in how these sex-linked traitstraits linked to genes located on the sex chromosomesare expressed. Sex-linked traits usually refer to traits due to genes on the X chromosome. One example of a sex-linked trait is red-green colorblindness. People with this type of colorblindness cannot tell the difference between red and green. They often see these colors as shades of brown ( Figure 1.1). Boys are much more likely to be colorblind than girls ( Table 1.1). This is because colorblindness is a sex-linked, recessive trait. Boys only have one X chromosome, so if that chromosome carries the gene for colorblindness, they will be colorblind. As girls have two X chromosomes, a girl can have one X chromosome with the colorblind gene and one X chromosome with a normal gene for color vision. Since colorblindness is recessive, the dominant normal gene will mask the recessive colorblind gene. Females with one colorblindness allele and one normal allele are referred to as carriers. They carry the allele but do not express it. How would a female become colorblind? She would have to inherit two genes for colorblindness, which is very unlikely. Many sex-linked traits are inherited in a recessive manner. Xc Xc X (carrier female) Xc Y (colorblind male) X Y X XX (normal female) XY (normal male) According to this Punnett square ( Table 1.1), the son of a woman who carries the colorblindness trait and a male with normal vision has a 50% chance of being colorblind.
Question: most sex-linked genes are ___________.

SOLUTION: recessive

PROBLEM: Context: The Raytown Branch of Mid-Continent Public Library is offering the following activities for the month of March. The library is located at 6131 Raytown Road. All activities are free, but registration is required. Tax Help for Seniors 10 a.m. Mondays and Wednesdays. AARP Tax-Aide representatives will be at the Library to assist seniors with medium to low incomes with tax questions and free tax return preparation. Time listed indicates starting time. Teen Games 2 p.m. March 2. Challenge yourself, challenge your friends. Movie Classics For adults, 2 p.m. March 4. Join us for an afternoon of nostalgia as we watch classic films. Call to see what's showing. KC Zoomobile Africa, for ages 5 and older, 11 a.m. March 5. Join the Kansas City Zoo for an African adventure. We will share African culture as well as show you an animal or two. Come with us to learn something new about Africa. Kids at the Library For ages 6 and older, 11 a.m. March 12. Discover, create, and play. Explore big ideas in a new way. Chess Free Play For ages 6 and older, 1 p.m. March 12. Play chess, learn the basics, brush up on your chess skills, challenge other players at Free Chess Play at the library. The Raytown Branch, in cooperation with the Raytown High School Chess Team coaches, will be hosting chess on the second Saturday of the month from 1 to 3 p.m. Chess boards and chess pieces will be provided. Eggstravaganza Noon March 26. Join us for story time with Mayor Mike McDonough, as we take part in Raytown's Easter festivities. After the stories, the Easter Bunny will escort the children across the street for an Easter egg hunt.
Question: Which activity is more likely to develop imagination and creativity?

SOLUTION:
kids at the library.