(y^n - b^n) is completely divisible by (y - b), when
Options:
(A) n is odd natural number
(B) n is even natural number
(C) n is any natural number
(D) n is prime
(E) None Think first, then make a decision. Some random thoughts:
For every natural number n, (y^n - b^n) is completely divisible by (y - b). So the answer is (C).