Consider the question. If six persons sit in a row, then the probability that three particular persons are always together is?
Options:
(A) 1/6
(B) 1/3
(C) 1/5
(D) 1/1
(E) 1/2
If the answer is '(C)'; explain the reasoning:
Six persons can be arranged in a row in 6! ways. Treat the three persons to sit together as one unit then there four persons and they can be arranged in 4! ways. Again three persons can be arranged among them selves in 3! ways. Favourable outcomes = 3!4! Required probability = 3!4!/6! = 1/5