Another effective way to decrease the transmission rate of infectious diseases is to recognize the effects of small-world networks. In epidemics, there are often extensive interactions within hubs or groups of infected individuals and other interactions within discrete hubs of susceptible individuals. Despite the low interaction between discrete hubs, the disease can jump to and spread in a susceptible hub via a single or few interactions with an infected hub. Thus, infection rates in small-world networks can be reduced somewhat if interactions between individuals within infected hubs are eliminated (Figure 1). However, infection rates can be drastically reduced if the main focus is on the prevention of transmission jumps between hubs. The use of needle exchange programs in areas with a high density of drug users with HIV is an example of the successful implementation of this treatment method. Another example is the use of ring culling or vaccination of potentially susceptible livestock in adjacent farms to prevent the spread of the foot-and-mouth virus in 2001.
If it is possible to answer this question, answer it for me (else, reply "unanswerable"): What is an example of a success implementation of preventing transmission jumps?
Ah, so.. needle exchange programs in areas with a high density of drug users

Canadian defence policy today is based on the Canada First Defence Strategy, introduced in 2008. Based on that strategy, the Canadian military is oriented and being equipped to carry out six core missions within Canada, in North America and globally. Specifically, the Canadian Armed Forces are tasked with having the capacity to:
If it is possible to answer this question, answer it for me (else, reply "unanswerable"): What other location does the Canada First Defence Strategy Cover?
Ah, so.. North America

The current I(t) through any component in an electric circuit is defined as the rate of flow of a charge Q(t) passing through it, but actual chargeselectronscannot pass through the dielectric layer of a capacitor. Rather, one electron accumulates on the negative plate for each one that leaves the positive plate, resulting in an electron depletion and consequent positive charge on one electrode that is equal and opposite to the accumulated negative charge on the other. Thus the charge on the electrodes is equal to the integral of the current as well as proportional to the voltage, as discussed above. As with any antiderivative, a constant of integration is added to represent the initial voltage V(t0). This is the integral form of the capacitor equation:
If it is possible to answer this question, answer it for me (else, reply "unanswerable"): To what is the charge on the electrodes of a capacitor disproportional to?
Ah, so..
unanswerable