Sean designs and sells patches. He orders his patches in a unit of 100 and is charged $1.25 per patch. If he turns around and sells all 100 patches for $12.00 each, what is his net profit?
Let's think: He orders 100 patches and they cost $1.25 each so the patches are 100 * 1.25 = $125.00. He sells each of the 100 patches for $12.00 each so he makes 100 * 12 = $1,200.00. He makes $1,200.00 selling patches and spends $125.00 to have them made so his net profit is 1200 - 125 = $1,075.00.. The answer is: 1075.

The difference between the price of an orange and the price of a pear equals the price of a banana. If the total cost of an orange and a pear is $120 and a pear costs $90, calculate the total price of buying 200 bananas and twice as many oranges as bananas.
Let's think: If the total cost of an orange and a pear is $120, and a pear costs $90, an orange costs $120 - $90 = $30. Since the difference between the price of an orange and a pear is the price of a banana, a banana is sold at $90 - $30 = $60. To buy 200 bananas, you'll pay $60 * 200 = $12000. When you twice as many oranges as bananas, you buy 2 * 200 = 400 oranges. The total cost of buying 400 oranges is 400 * 30 = $12000. The total price of buying 200 bananas and twice as many oranges as bananas is $12000 + $12000 = $24000.. The answer is: 24000.

A milk teas shop was able to sell a total of 50 cups of milk tea yesterday. Two-fifths of their sales are winter melon flavor, three-tenths are Okinawa flavor, and the rest are chocolate flavor. How many cups of chocolate-flavored milk tea were they able to sell yesterday?
Let's think: A milk tea shop sold 50 x 2 / 5 = 20 cups of winter melon - flavored milk tea. They sold 50 x 3 / 10 = 15 cups of Okinawa - flavored milk tea. So they sold a total of 20 + 15 = 35 cups of winter melon and Okinawa flavors milk tea. Therefore, they sold 50 - 35 = 15 cups of chocolate - flavored milk tea.. The answer is: 15.

Two runners are competing in a 10-mile race. The first runs at an average pace of 8 minutes per mile, while the second runs at an average pace of 7 minutes per mile. After 56 minutes, the second runner stops for a drink of water. For how many minutes could the second runner remain stopped before the first runner catches up with him?
Let's think:
After 56 minutes, the second runner has traveled 56 / 7 = 8 miles. Similarly, the first runner has traveled 56 / 8 = 7 miles. Therefore, the two runners are 8 - 7 = 1 mile apart when the second runner stops. Thus, the second runner can stop for a maximum of 8 minutes, which is the amount of time it takes the first runner to travel 1 mile.. The answer is: 8.