Rationale: Largest 4 digit number is 9999
After doing 9999 88 we get remainder 55
Hence largest 4 digit number exactly divisible by 88 = 9999 - 55 = 9944
The answer: (C)
Question: Find the largest 4 digit number which isexactly divisible by 88?
Options:
(A) 3454
(B) 4586
(C) 9944
(D) 10564
(E) 18664
Reasoning: Maximum points of intersection between n different circles = n*(n - 1) = 15*14 = 210
Ans: (E)
Question: There are different 15 circles. What is the number of the greatest possible points with which the circles intersect?
Options:
(A) 390
(B) 100
(C) 110
(D) 180
(E) 210
Rationale: K + 3K +3 + 3K - 4 + 5K +1 = 12K
(12K)/4 = 60
12K = 60 * 4 = 240
K = 240/ 12 = 20.
The answer: (C)
Question: If the average (arithmetic mean) of the four numbers K, 3K + 3, 3K 4 and 5K + 1 is 60, what is the value of K?
Options:
(A) 11
(B) 15 3/4
(C) 20
(D) 23
(E) 25 3/10
Reasoning: T = 70/36 * 18/5 = 7 sec
Ans: (D)
Question: In what time will a railway train 70 m long moving at the rate of 36 kmph pass a telegraph post on its way?
Options:
(A) 5 sec
(B) 4 sec
(C) 3 sec
(D) 7 sec
(E) 1 sec
Rationale: Since the coin is a fair coin, every toss is independent of any other toss. Hence, the probability of appearance of tail on the fifth toss is = 1/2
The answer: (B)
Question: A fair coin is tossed repeatedly. If head appears on the first four tosses, then the probability of appearance of tail on the fifth toss is.
Options:
(A) 1/7
(B) 1/2
(C) 3/7
(D) 2/3
(E) 1/3
Rationale: Speed = 81 * 5/18 = 45/2 m/sec
Total distance covered = 650 + 340 = 990 m
Required time = 990 * 2/45 = 44 se
The answer: (C)
Question: A train 650 m long is running at a speed of 81 km/hr. In what time will it pass a bridge 340 m long?
Options:
(A) 42
(B) 43
(C) 44
(D) 45
(E) 46