Rationale: 10 * 155 = 1550
3 * 100 + 5 * 150 = 1050
1550 1050 = 500
The answer: (C)
Question: A women purchased 3 towels @ Rs.100 each, 5 towels @ Rs.150 each and two towels at a certain rate which is now slipped off from his memory. But she remembers that the average price of the towels was Rs.155. Find the unknown rate of two towels?
Options:
(A) A) 400
(B) B) 450
(C) C) 500
(D) D) 550
(E) E) 600
Reasoning: 1/15 + 1/6 = 7/30
30/7 = 4 2/7 days
Ans: (E)
Question: Ravi can do a piece of work in 15 days while Prakash can do it in 6 days. In how many days will they finish it together?
Options:
(A) 5 7/9 days
(B) 6 7/9 days
(C) 5 1/9 days
(D) 5 7/2 days
(E) 4 2/7 days
Rationale: Total age of students is 32X16 = 512 Years
Total age inclusive of teacher = 33X (16+1) = 561
So, Teacher's age is 561-512 = 49 Yrs
There is a shortcut for these type of problems
Teacher's age is 16+(33X1) = 49 Years
The answer: (D)
Question: The average age of a class of 32 students is 16 yrs. if the teacher's age is also included, the average increases by one year. Find the age of the teacher
Options:
(A) 29 Years
(B) 32 Years
(C) 37 Years
(D) 49 Years
(E) 50 Years
Reasoning: 2 + 3 + 5 + 7 +11 + 13 + 17 + 23 + 29 = 100 ( sum is even)
Least number = 2
Ans: (A)
Question: Q is a set of nine distinct prime numbers. If the sum of the integers in Q is even and the number x is a member of Q, then what is the least value that x can be?
Options:
(A) 2
(B) 3
(C) 4
(D) 5
(E) 7
Rationale: The integer should be divisible by: 10, 11, 12, 13, 14 and 15, that is 5*2, 11, 3*2^2, 13, 2*7, and 3*5. The least common multiple of these integers is the product of 13, 11, 7, 5, 3 and 2^2. Then, R/26 is (13 * 11 * 7 * 5 * 3 * 2^2)/2 * 13 = 11*7*5*3*2 = 2310.
The answer: (B)
Question: If J is the least positive integer that is divisible by every integer from 10 to 15 inclusive, then J/26 is =
Options:
(A) 1155
(B) 2310
(C) 4620
(D) 30030
(E) 60060
Rationale: Population after n years = P [1 + (R/100)]2
Population after 2 years = 130000 * [1 + 6/100]2 = (130000 x 53/50 x 53/50) = 146068
The answer: (D)
Question: he population of a city is 130,000. If it increases at the rate of 6% per annum, then what will be its population 2 years hence?
Options:
(A) 146069
(B) 146067
(C) 156068
(D) 146068
(E) 179718