Question: If 12x = 16y = 28z, then what is a possible sum of positive integers x, y, and z?
Options:
(A) 52
(B) 58
(C) 122
(D) 84
(E) 168 Let's think first. Some random reasoning:
12x = 16y = 28z
3x = 4y = 7z
3(4*7) = 4(3*7) = 7(3*4)
Addition = 28+21+12 = 61
Answer would be multiple of 61 which is 122 The final answer: (C).