Question: Willy has 10 stuffed animals. His mom gives him 2 more stuffed animals for his birthday. After his birthday, if his dad gives him 3 times more stuffed animals than he has, how many stuffed animals does Willy have in total?
Answer: After his mom gives him stuffed animals, Willy has 10 + 2 = 12 stuffed animals. His dad gives him 12 * 3 = 36 stuffed animals. In total, Willy has 12 + 36 = 48 stuffed animals. The answer is 48.
[Question]John buys dinner plates and silverware. The silverware cost $20. The dinner plates cost 50% as much as the silverware. How much did he pay for everything?
[Answer]The dinner plates cost 20 * .5 = $10. So he paid 10 + 20 = $30. The answer is 30.
Q: Together, Alan and Marcy handed out 150 parking tickets. If Marcy handed out 6 fewer than 5 times as many tickets as Alan, how many tickets did Alan hand out?
A: Let a be the number of tickets Alan hands out and m be the number Marcy hands out. We know that a + m = 150 and m = 5a - 6. Substituting the second equation into the first, we get a + 5a - 6 = 150. Adding 2 to both sides, we get a + 5a = 156. Combining like terms, we get 6a = 156. Dividing both sides by 6, we get a = 26. The answer is 26.
Question: A performing magician has a disappearing act where he makes a random member of his audience disappear and reappear. Unfortunately, one-tenth of the time, the audience member never reappears. However, one-fifth of the time, two people reappear instead of only one. If the magician has put on 100 performances of the act this year, how many people have reappeared?
Answer: One - tenth of the time, no one reappears, so there have been 100 / 10 = 10 times no one has reappeared. One - fifth of the time, two people reappear, so there have been 100 / 5 = 20 times 2 people have reappeared. In those 20 times, 2 * 20 = 40 people have reappeared in all. Thus, there have been 100 - 10 - 20 = 70 times one person has reappeared. Therefore, over 100 acts, 70 + 40 = 100 people have reappeared in all. The answer is 110.
[Question]The cheerleading coach is ordering new uniforms. There are 4 cheerleaders who need a size 2, a certain number who need a size 6, and half that number who need a size 12. If there are 19 cheerleaders total, how many cheerleaders need a size 6?
[Answer]Let s be the number of cheerleaders who need a size 6 and t be the number who need a size 12. We know that s = 2t and s + t + 4 = 19. Substituting the first equation into the second equation, we get 2t + t + 4 = 19. Combining like terms, we get 3t + 4 = 19. Subtracting 4 from both sides, we get 3t = 15. Dividing both sides by 3, we get t = 5. Substituting that value back into the equation s = 2t, we get s = 2 * 5 = 10. The answer is 10.
[Question]Luke is planning a trip to London and wants to see how long it will take him to travel there. He decides that he will take a bus to the town center, walk for 15 minutes to the train center, wait twice this long for the train to arrive, and then take the 6-hour train ride to London. If Luke's entire trip takes him 8 hours, how many minutes does his bus ride take?
[Answer]
Removing the time of the train ride from the journey shows that his trip to get on the train took him 8 hours 6 hours = 2 hours. Converting this time into minutes shows that getting to the train took 2 hours * 60 minutes / hour = 120 minutes. Waiting for the train to arrive took twice as long as his walk, so 15 minutes * 2 = 30 minutes. This means that his bus ride must have taken 120 minutes 30 minutes - 15 minutes = 75 minutes. The answer is 75.