A group of hawks is called a kettle. It is breeding season for hawks. A group of ornithologists are tracking 6 kettles of hawks. Each kettle has an average of 15 pregnancies that yield 4 babies per batch. How many babies are expected this season if approximately 25% are lost? Let's think first. Chain of thought:
Each kettle has 15 hawks that get pregnant and each one yields 4 babies per pregnancy so there are 15 * 4 = 60 babies expected per kettle. If 60 baby hawks are expected per kettle and the ornithologists are tracking 6 kettles total then there are 60 * 6 = 360 baby hawks expected across all six kettles this breeding season. If there 25% of eggs do not hatch, then we are looking for 25 (percent that do not make it) / 100 (total number of babies expected) = .25 (percentage converted to decimal form for the proportion of expected baby hawks to be lost). The total number of baby hawks expected equals 360 * .25 expected los s = 90 babies not expected to hatch (lost). There are 360 total number of baby hawks expected and there are 90 babies expected to be lost so 360 - 90 = 270 remaining baby hawks expected this breeding season.
Therefore, the answer is 270.