Some question: In how many different ways can the letters of the word "NEGLIGENCE" be rearrangement?
Options:
(A) 3628800
(B) 3628800
(C) 3628812
(D) 3428800
(E) 3368800
Some stream of consciousness:
Option 'B'
The total number of arrangements is
10P10 = 10! = 3628800 The answer: (B).