Q: Answer the following question given this paragraph: The same principles govern the solubilities of molecular solids in liquids. For example, elemental sulfur is a solid consisting of cyclic S8 molecules that have no dipole moment. Because the S8 rings in solid sulfur are held to other rings by London dispersion forces, elemental sulfur is insoluble in water. It is, however, soluble in nonpolar solvents that have comparable London dispersion forces, such as CS2 (23 g/100 mL). In contrast, glucose contains five OH groups that can form hydrogen bonds. Consequently, glucose is very soluble in water (91 g/120 mL of water) but essentially insoluble in nonpolar solvents such as benzene. The structure of one isomer of glucose is shown here. Q: What type of solvents is glucose insoluble in? A:

OPTIONS:
- alkaline
- polar
- acidic
- nonpolar

A: nonpolar

input: OPTIONS:
- lipids
- acids
- hormones
- proteins Now, answer this question: Answer the following question given this paragraph: Q: Most enzymes are classified as what? A:
A:
output: proteins

Answer the following question given this paragraph: Sometimes power is measured in a unit called the horsepower. For example, the power of car engines is usually expressed in horsepowers. One horsepower is the amount of work a horse can do in 1 minute. It equals 745 watts of power. Compare the horsepowers in the Figure below to the other Figure below . Q: How many watts equals a horse power? A:

OPTIONS:
- 695
- 904
- 375
- 745

Answer: 745

Problem: OPTIONS:
- vapor
- sodium
- Water
- solute
Q: Answer the following question given this paragraph: Often, a worker will need to change the concentration of a solution by changing the amount of solvent. Dilution is the addition of solvent, which decreases the concentration of the solute in the solution. Concentration is the removal of solvent, which increases the concentration of the solute in the solution. (Do not confuse the two uses of the word concentration here!) In both dilution and concentration, the amount of solute stays the same. This gives us a way to calculate what the new solution volume must be for the desired concentration of solute. From the definition of molarity,. Q: Concentration is the removal of solvent, which increases the concentration of what? A:
Answer: solute

Problem:OPTIONS:
- belt microscope
- Fixing microscope
- part microscope
- compound microscope

Answer the following question given this paragraph: Example 26.5 Microscope Magnification Calculate the magnification of an object placed 6.20 mm from a compound microscope that has a 6.00 mm focal length objective and a 50.0 mm focal length eyepiece. The objective and eyepiece are separated by 23.0 cm. Strategy and Concept This situation is similar to that shown in Figure 26.16. To find the overall magnification, we must find the magnification of the objective, then the magnification of the eyepiece. This involves using the thin lens equation. Solution The magnification of the objective lens is given as. Q: Find the overall magnification of what instrument by finding the magnification of the objective, then the magnification of the eyepiece? A:
****
A: compound microscope

Problem:OPTIONS:
- pleasurable pressure
- impervious pressure
- transverse pressure
- osmotic pressure

Answer the following question given this paragraph: When water moves into a cell by osmosis, osmotic pressure may build up inside the cell. If a cell has a cell wall, the wall helps maintain the cell's water balance. Osmotic pressure is the main cause of support in many plants. When a plant cell is in a hypotonic environment, the osmotic entry of water raises the turgor pressure exerted against the cell wall until the pressure prevents more water from coming into the cell. At this point the plant cell is turgid ( Figure below ). The effects of osmotic pressures on plant cells are shown in Figure above . Q: What type of pressure may build up inside the cell when water moves into a cell by osmosis? A:
****
A:
osmotic pressure