Question: What is the least value of integer N such that N! is divisible by 888 ?
Options:
(A) 13
(B) 88
(C) 31
(D) 37
(E) D) 888 Let's think first. Some random reasoning:
888 = 8*111 = 3*8*37
Hence 888 is a multiple of 37 and we need at least one 37 in N!
Therefore least value of N! is 37!, which will contain all of 3, 8, and 37. The final answer: (D).