Rationale: My ans is 15C4 = 1365
The answer: (E)
Question: Fifteen telegenic contestants with a variety of personality disorders are to be divided into two "tribes" of four members each, tribe A and tribe B, for a competition. How many distinct groupings of two tribes are possible?
Options:
(A) 120
(B) 126
(C) 252
(D) 1200
(E) 1365
Reasoning: D = 72 * 5/18 = 15 = 300 250 = 50m
Ans: (A)
Question: A train 250 m long running at 72 kmph crosses a platform in 15 sec. What is the length of the platform?
Options:
(A) 50m
(B) 200m
(C) 250m
(D) 270m
(E) 300 m
Rationale: S = 160/12 * 18/5 = 48 kmph
The answer: (A)
Question: A 160 meter long train crosses a man standing on the platform in 12 sec. What is the speed of the train?
Options:
(A) 48 kmph
(B) 54 kmph
(C) 92 kmph
(D) 86 kmph
(E) 76 kmph
Reasoning: Others are equal to 3x2 + 8xy + 4y2
Ans: (E)
Question: Four of the five parts numbered (a), (b), (c), (d) and (e) in the following equation are exactly equal. Which part is not equal to the other four ? The number of that part is the answer.
Options:
(A) (x + 2y) (3x + 2y)
(B) (x + 2y) 2 + 2x(x + 2y)
(C) (3x + 2y) 2 2x(3x + 2y)
(D) 3x(x + 2y) + 2y(x + 2y)
(E) x(3x + 2y) 2y(3x 2y)
Rationale: The number of photographs either framed by Jack or taken by Octavia = {Jack} + {Octavia} - {overlap} = 36 + 36 - 24 = 48 ({overlap} is green box).
The answer: (B)
Question: In a photography exhibition, some photographs were taken by Octavia the photographer, and some photographs were framed by Jack the framer. Jack had framed 24 photographs taken by Octavia, and 12 photographs taken by other photographers. If 36 of the photographs in the exhibition were taken by Octavia, how many photographs were either framed by Jack or taken by Octavia?
Options:
(A) 36
(B) 48
(C) 72
(D) 96
(E) 108
Rationale: S = 160/12 * 18/5 = 48 kmph
The answer: (A)
Question: A 160 meter long train crosses a man standing on the platform in 12 sec. What is the speed of the train?
Options:
(A) 48 kmph
(B) 54 kmph
(C) 92 kmph
(D) 86 kmph
(E) 76 kmph