Question: Susan is picking strawberries. She's trying to fill her basket, but out of every handful of 5 strawberries she can't help but eat one of them herself. If her basket holds 60 strawberries, how many berries will she actually pick before she fills it?
Answer: Out of every 5 berries, she eats 1, so only 5 strawberries - 1 strawberry = 4 strawberries go into the basket for each handful. The basket holds 60 strawberries, so it will take 60 strawberries / 4 strawberries per handful = 15 handfuls to fill the basket. So in total, Susan will pick 60 strawberries + 15 handfuls * 1 strawberry eaten per handful = 75 strawberries. The answer is 75.

Question: Jason's dog has a tail that's half the length of its body, and a head that's 1/6 the length of its body. If the dog is 30 inches long overall, how long is its tail?
Answer: If b is the length of the body, h is the length of the head, and t is the length of the tail, we know that b + h + t = 30, h = b / 6 and t = b / 2. We can substitute the second two equations into the first equation to get b + b / 6 + b / 2 = 30. Now multiply both sides of this equation by 6: 6b + b + 3b = 180. Now combine like terms: 10b = 180. Now divide both sides by 10: b = 180. The dog's body is 18 inches long. Now divide that length by 2 to find the length of its tail: 18 inches / 2 = 9 inches. The answer is 9.

Question: The Grey's bought several chickens at a sale. John took 5 more of the chickens than Mary took. Ray took 6 chickens less than Mary. If Ray took 10 chickens, how many more chickens did John take than Ray?
Answer: Mary took 10 + 6 = 16 chickens. John took 16 + 5 = 21 chickens. John took 21 - 10 = 11 more chickens than Ray. The answer is 11.

Question: Josh and Anna were both born on August 17th, but in different years. To consolidate celebrations they also got married on August 17 when Josh turned 22. If today they're celebrating 30 years of marriage and their combined age is exactly 5 times what Josh's age was when they married, how old was Anna when they got married?
Answer:
We know that Josh must be 30 years older than his age when they got married, therefore he is 30 + 22 = 52 years old today. If their current combined age is 5 times the age Josh was when they married (22), then their total combined age is 5 * 22 = 110 years. That means that Anna must be 110 - 52 = 58 years old today. If they married 30 years ago, Anna must have been 58 - 30 = 28 years old when they married. The answer is 28.