Arguments memmx_subP {m1 m2 n R1 R2}.

Lemma memmx_eqP m1 m2 n (R1 : 'A_(m1, n)) (R2 : 'A_(m2, n)) :
reflect (forall A, (A \in R1) = (A \in R2)) (R1 == R2)%MS.