(* NB: Z.modulo and Z.div are not morphisms with respect to eqm. For instance, let (==) be (eqm 2). Then we have (3 == 1) but: ~ (3 mod 3 == 1 mod 3) ~ (1 mod 3 == 1 mod 1) ~ (3/3 == 1/3) ~ (1/3 == 1/1) *)

Lemma Zdiv_Zdiv : forall a b c, 0<=b -> 0<=c -> (a/b)/c = a/(b*c).