(** Lemma 14.28 is something like exists f, prod O E X A B C -> prod O' E' f(X) f(A') f(B') f(C') ? *)
(** Lemma 14.29 *)
(** From Pappus-Pascal we can derive that the product is symmetric, hence we have a field. *)
(* already done : prod_comm *)

Lemma l14_31_2 : forall O E E' A B C D ,
Ar2_4 O E E' A B C D -> C <> O -> Prod O C E' A B D ->
(exists X, Prod O E E' A B X /\ Prod O E E' C D X).