intros a b H' H'0; try assumption.
lapply (ppc_is_ppcm a b);
[ intros H'3; lapply H'3; clear H'3; [ intros H'4 | idtac ] | idtac ];
auto; auto.
inversion H'4; auto.
Qed.

Theorem divP_ppcr :
forall a b : Term A n,
~ zeroP (A:=A) A0 eqA (n:=n) a ->
~ zeroP (A:=A) A0 eqA (n:=n) b -> divP (ppc a b) b.