(** * Breaking 64-bit memory accesses into two 32-bit accesses *)

Lemma bytes_of_int_append:
forall n2 x2 n1 x1,
0 <= x1 < two_p (Z.of_nat n1 * 8) ->
bytes_of_int (n1 + n2) (x1 + x2 * two_p (Z.of_nat n1 * 8)) =
bytes_of_int n1 x1 ++ bytes_of_int n2 x2.