Proof spec_Qquadratic_Qpositive_to_Q_dL_nR.

Lemma spec_Qquadratic_Qpositive_to_Q_dL_dL :
forall (a b c d e f g h : Z) (p1 p2 : Qpositive),
spec_Qquadratic_Qpositive_to_Q a b c d e f g h (dL p1) (dL p2) =
spec_Qquadratic_Qpositive_to_Q (a + b + c + d) (b + d)
(c + d) d (e + f + g + h) (f + h) (g + h) h p1 p2.