Section sec_modal_op_lemmas.
Variable T : Type.
Proof using.
now destruct ex.
Qed.
(* always facts *)
Proof using.
intros P invP.
cofix c.
intros [x s] Pxs; apply Always; trivial.
apply c; apply invP in Pxs.
assumption.
Qed.
Proof using.
intros x s P al. change (P (Cons x s) /\ always P (tl (Cons x s))).
destruct al. split; assumption.
Qed.

Lemma always_now :
forall (x: T) (s: infseq T) P, always P (Cons x s) -> P (Cons x s).