Section second_geq_2_a.
Hypothesis m : EQ Zero sA.
Let stepa_1 : has_leq_0_elements sA :=
Big_Extensionality has_leq_0_elements Zero sA zero_has_leq_0_elements m.
Definition second_geq_2_a_Out : False := step1 stepa_1.
End second_geq_2_a.
Let step2 : NEQ Zero sA := second_geq_2_a_Out.
Definition second_has_geq_2_elements_Out : has_geq_2_elements E :=
distinct_Doubletons_have_geq_2_elements Zero sA step2.
End second_has_geq_2_elements_proof.

Theorem Second_has_geq_2_elements :
forall A : Ens, has_geq_2_elements (Second A).