Problem p02660 (C++)

Buggy submission (status: Time Limit Exceeded):
#include <bits/stdc++.h>
// #include<ext/pb_ds/assoc_container.hpp>
// #include<ext/pb_ds/tree_policy.hpp>
//
//     #pragma GCC optimize("unroll-loops")
//     #pragma GCC optimize("Ofast")
//     #pragma GCC optimize("-O3")
//     #pragma GCC optimize("no-stack-protector")
//     #pragma GCC optimize("fast-math")

#define fi first
#define f first
#define se second
#define s second
#define vi_a vector<int> a;
#define p_b push_back
////////////////////////////////???????????????CHECK THIS
///OUT???????????????//////////////////////////////
#define ll long long
////////////////////////////////???????????????CHECK THIS
///OUT???????????????//////////////////////////////
#define ld long double
#define pll pair<ll, ll>
#define pii pair<int, int>
#define m_p make_pair
#define fast_io                                                                \
  cin.tie(0);                                                                  \
  cout.tie(0);                                                                 \
  ios_base::sync_with_stdio(0);
#define all(x) x.begin(), x.end()
#define getfiles                                                               \
  ifstream cin("input.txt");                                                   \
  ofstream cout("output.txt");
#define pw(x) (1ll << x)
#define sz(x) (ll) x.size()
#define endl "\n"
#define rall(x) x.rbegin(), x.rend()
#define len(a) (ll) a.size()
#define rep(x, l, r) for (ll x = l; x < r; x++)
// #define for(int i=0;i<n;i++) for(ll i=0;i<n;i++)
using namespace std;
// using namespace __gnu_pbds;
ld eps = (ld)1 / 1e6;
ll inf = 1e18, mod2 = 998244353, mod1 = 1e9 + 7;
ll sqr(ll a) { return a * a; }
ll qb(ll a) { return a * a * a; }
ll gcd(ll a, ll b) { return !a ? b : gcd(b % a, a); }
ll binpow(ll a, ll b, ll mod) {
  return b ? (b % 2 ? (a * (sqr(binpow(a, b / 2, mod)) % mod)) % mod
                    : sqr(binpow(a, b / 2, mod)) % mod)
           : 1;
}
ll binmult(ll a, ll b, ll mod) {
  return b ? (b % 2 ? (2 * binmult(a, b / 2, mod) + a) % mod
                    : (2 * binmult(a, b / 2, mod)) % mod)
           : 0;
}
/////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// const ll to[5]={0,4,6,7,9};
// const ll N=2*1e5+1;
const ll R = 1e4;
// const ll to[7]={1,2,3,1,3,2,1};
// const ll tx[4]={0,0,-1,1};
// const ll ty[4]={-1,1,0,0};
const char rev_to[4] = {'E', 'W', 'N', 'S'};
const ll N = 2 * 1e5 + 4;
// set<int> lol2[26][26];
// set<int>ab;
// set<int>ba;
signed main() {
  fast_io;
  ll n;
  cin >> n;
  ll ans = 0;
  for (int i = 2; i * i <= n; i++) {
    if (n % i)
      continue;
    ll cnt = 0;
    while (n % i == 0) {
      n /= i;
      cnt++;
    }
    ll D = 1 + 8 * cnt;
    ll x = ((ld)-1 + sqrt(D)) / 2;
    ans += x;
  }
  if (n > 1) {
    ans++;
  }
  cout << ans;
  return 0;
}
/*
    (x+1)*x/2=cnt
    cnt*2=(x+1)*x
    x^2+x-2*cnt=0;
    D=1+8*cnt
    x1=(-1+D)/2
    если WA , то чекер говно, поэтому почекай l8 строчку
    !x || !y x-проигрышная или выигрышная , y-колво таких позиций
    x==0 проигрышная
    y==0 четное проигрышных или четное выигрышных
    x==0 && y==0 четное проигрышных
*/


Fixed submission:
#include <bits/stdc++.h>
// #include<ext/pb_ds/assoc_container.hpp>
// #include<ext/pb_ds/tree_policy.hpp>
//
//     #pragma GCC optimize("unroll-loops")
//     #pragma GCC optimize("Ofast")
//     #pragma GCC optimize("-O3")
//     #pragma GCC optimize("no-stack-protector")
//     #pragma GCC optimize("fast-math")

#define fi first
#define f first
#define se second
#define s second
#define vi_a vector<int> a;
#define p_b push_back
////////////////////////////////???????????????CHECK THIS
///OUT???????????????//////////////////////////////
#define ll long long
////////////////////////////////???????????????CHECK THIS
///OUT???????????????//////////////////////////////
#define ld long double
#define pll pair<ll, ll>
#define pii pair<int, int>
#define m_p make_pair
#define fast_io                                                                \
  cin.tie(0);                                                                  \
  cout.tie(0);                                                                 \
  ios_base::sync_with_stdio(0);
#define all(x) x.begin(), x.end()
#define getfiles                                                               \
  ifstream cin("input.txt");                                                   \
  ofstream cout("output.txt");
#define pw(x) (1ll << x)
#define sz(x) (ll) x.size()
#define endl "\n"
#define rall(x) x.rbegin(), x.rend()
#define len(a) (ll) a.size()
#define rep(x, l, r) for (ll x = l; x < r; x++)
// #define for(int i=0;i<n;i++) for(ll i=0;i<n;i++)
using namespace std;
// using namespace __gnu_pbds;
ld eps = (ld)1 / 1e6;
ll inf = 1e18, mod2 = 998244353, mod1 = 1e9 + 7;
ll sqr(ll a) { return a * a; }
ll qb(ll a) { return a * a * a; }
ll gcd(ll a, ll b) { return !a ? b : gcd(b % a, a); }
ll binpow(ll a, ll b, ll mod) {
  return b ? (b % 2 ? (a * (sqr(binpow(a, b / 2, mod)) % mod)) % mod
                    : sqr(binpow(a, b / 2, mod)) % mod)
           : 1;
}
ll binmult(ll a, ll b, ll mod) {
  return b ? (b % 2 ? (2 * binmult(a, b / 2, mod) + a) % mod
                    : (2 * binmult(a, b / 2, mod)) % mod)
           : 0;
}
/////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// const ll to[5]={0,4,6,7,9};
// const ll N=2*1e5+1;
const ll R = 1e4;
// const ll to[7]={1,2,3,1,3,2,1};
// const ll tx[4]={0,0,-1,1};
// const ll ty[4]={-1,1,0,0};
const char rev_to[4] = {'E', 'W', 'N', 'S'};
const ll N = 2 * 1e5 + 4;
// set<int> lol2[26][26];
// set<int>ab;
// set<int>ba;
signed main() {
  fast_io;
  ll n;
  cin >> n;
  ll ans = 0;
  for (ll i = 2; i * i <= n; i++) {
    if (n % i)
      continue;
    ll cnt = 0;
    while (n % i == 0) {
      n /= i;
      cnt++;
    }
    ll D = 1 + 8 * cnt;
    ll x = ((ld)-1 + sqrt(D)) / 2;
    ans += x;
  }
  if (n > 1) {
    ans++;
  }
  cout << ans;
  return 0;
}
/*
    (x+1)*x/2=cnt
    cnt*2=(x+1)*x
    x^2+x-2*cnt=0;
    D=1+8*cnt
    x1=(-1+D)/2
    если WA , то чекер говно, поэтому почекай l8 строчку
    !x || !y x-проигрышная или выигрышная , y-колво таких позиций
    x==0 проигрышная
    y==0 четное проигрышных или четное выигрышных
    x==0 && y==0 четное проигрышных
*/