Problem p02811 (C++)

Buggy submission (status: Runtime Error):
#include <bits/stdc++.h>
using namespace std;
#define in(s)                                                                  \
  ll s;                                                                        \
  cin >> s
#define pr(r) cout << r << endl
#define prr(m, n) cout << m << " " << n << endl
#define prarr(a, i, n) fab(j, i, n) cout << a[j] << " "
#define wh(t)                                                                  \
  ll t;                                                                        \
  cin >> t;                                                                    \
  while (t--)
#define sz(u) u.size()
#define all(v) v.begin(), v.end()
#define arr(a, n)                                                              \
  ll a[n];                                                                     \
  fab(i, 0, n) cin >> a[i]
#define showdp(d, n, m)                                                        \
  fab(i, 0, n) {                                                               \
    fab(j, 0, m) if (d[i][j] == -1 || d[i][j] > 9) cout << d[i][j] << " ";     \
    else cout << " " << d[i][j] << " ";                                        \
    cout << endl;                                                              \
  }
#define prs(u) cout << u << " "
#define fab(i, a, b) for (ll i = a; i < b; i++)
#define fba(i, b, a) for (ll i = b; i >= a; i--)
#define sup                                                                    \
  ios_base::sync_with_stdio(false);                                            \
  cin.tie(NULL);                                                               \
  cout.tie(NULL)
#define MX 1000000007
#define MAX 10000007
#define endl "\n"
#define ll long long int
#define vl vector<ll>
#define vpl vector<pair<ll, ll>>
#define pl pair<ll, ll>
#define pll pair<ll, pl>
#define vvl vector<vl>
#define mxe(x, n) *max_element(x, x + n)
#define mne(x, n) *min_element(x, x + n)
#define mp make_pair
#define pb push_back
#define fs first
#define sd second
#define fr front()
#define bk back()
#define rr return
#define N 300005
#define inf 1e18 + 7

bool rsort1(const pair<ll, ll> &a, const pair<ll, ll> &b) {
  return (a.first > b.first);
}
bool rsort2(const pair<ll, ll> &a, const pair<ll, ll> &b) {
  return (a.second > b.second);
}
bool sort2(const pair<ll, ll> &a, const pair<ll, ll> &b) {
  return (a.second < b.second);
}

bool isPrime(ll p) {
  for (ll i = 2; i * i <= p; i++)
    if (p % i == 0)
      rr false;
  rr true;
}

void sieve(ll n, vl &v) {
  v.pb(2);
  bool prime[n + 1];
  memset(prime, true, sizeof(prime));
  for (ll i = 3; i * i <= n; i += 2)
    if (prime[i])
      for (ll j = i; j * i <= n; j += 2)
        prime[j * i] = false;

  for (ll i = 3; i <= n; i += 2)
    if (prime[i])
      v.pb(i);
}

ll phi(ll n) {
  ll result = n;
  for (ll p = 2; p * p <= n; p++) {
    if (n % p == 0) {
      while (n % p == 0)
        n /= p;
      result -= result / p;
    }
  }

  if (n > 1)
    result -= result / n;
  return result;
}

int main() {
  sup;
#ifndef ONLINE_JUDGE
  freopen("input.txt", "r", stdin);
  freopen("output.txt", "w", stdout);
  freopen("error.txt", "w", stderr);
#endif

  ll k, n;
  cin >> k >> n;
  if (k * 500 >= n)
    pr("Yes");
  else
    pr("No");
  return 0;
}

Fixed submission:
#include <bits/stdc++.h>
using namespace std;
#define in(s)                                                                  \
  ll s;                                                                        \
  cin >> s
#define pr(r) cout << r << endl
#define prr(m, n) cout << m << " " << n << endl
#define prarr(a, i, n) fab(j, i, n) cout << a[j] << " "
#define wh(t)                                                                  \
  ll t;                                                                        \
  cin >> t;                                                                    \
  while (t--)
#define sz(u) u.size()
#define all(v) v.begin(), v.end()
#define arr(a, n)                                                              \
  ll a[n];                                                                     \
  fab(i, 0, n) cin >> a[i]
#define showdp(d, n, m)                                                        \
  fab(i, 0, n) {                                                               \
    fab(j, 0, m) if (d[i][j] == -1 || d[i][j] > 9) cout << d[i][j] << " ";     \
    else cout << " " << d[i][j] << " ";                                        \
    cout << endl;                                                              \
  }
#define prs(u) cout << u << " "
#define fab(i, a, b) for (ll i = a; i < b; i++)
#define fba(i, b, a) for (ll i = b; i >= a; i--)
#define sup                                                                    \
  ios_base::sync_with_stdio(false);                                            \
  cin.tie(NULL);                                                               \
  cout.tie(NULL)
#define MX 1000000007
#define MAX 10000007
#define endl "\n"
#define ll long long int
#define vl vector<ll>
#define vpl vector<pair<ll, ll>>
#define pl pair<ll, ll>
#define pll pair<ll, pl>
#define vvl vector<vl>
#define mxe(x, n) *max_element(x, x + n)
#define mne(x, n) *min_element(x, x + n)
#define mp make_pair
#define pb push_back
#define fs first
#define sd second
#define fr front()
#define bk back()
#define rr return
#define N 300005
#define inf 1e18 + 7

bool rsort1(const pair<ll, ll> &a, const pair<ll, ll> &b) {
  return (a.first > b.first);
}
bool rsort2(const pair<ll, ll> &a, const pair<ll, ll> &b) {
  return (a.second > b.second);
}
bool sort2(const pair<ll, ll> &a, const pair<ll, ll> &b) {
  return (a.second < b.second);
}

bool isPrime(ll p) {
  for (ll i = 2; i * i <= p; i++)
    if (p % i == 0)
      rr false;
  rr true;
}

void sieve(ll n, vl &v) {
  v.pb(2);
  bool prime[n + 1];
  memset(prime, true, sizeof(prime));
  for (ll i = 3; i * i <= n; i += 2)
    if (prime[i])
      for (ll j = i; j * i <= n; j += 2)
        prime[j * i] = false;

  for (ll i = 3; i <= n; i += 2)
    if (prime[i])
      v.pb(i);
}

ll phi(ll n) {
  ll result = n;
  for (ll p = 2; p * p <= n; p++) {
    if (n % p == 0) {
      while (n % p == 0)
        n /= p;
      result -= result / p;
    }
  }

  if (n > 1)
    result -= result / n;
  return result;
}

int main() {
  sup;
  /*#ifndef ONLINE_JUDGE
  freopen("input.txt","r",stdin);
  freopen("output.txt","w",stdout);
  freopen("error.txt","w",stderr);
  #endif*/

  ll k, n;
  cin >> k >> n;
  if (k * 500 >= n)
    pr("Yes");
  else
    pr("No");
  return 0;
}