Problem p03241 (C++)

Buggy submission (status: Time Limit Exceeded):
#include <algorithm>
#include <bitset>
#include <climits>
#include <cmath>
#include <fstream>
#include <functional>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <set>
#include <stack>
#include <string.h>
#include <string>
#include <vector>

using namespace std;
using ll = long long;

// graph
const ll MAX_V = 1;
const ll MAX_E = 1;
struct edge {
  ll from, to, cost;
};
edge ES[MAX_E];
vector<edge> G[MAX_V];
ll d[MAX_V];
ll prev_path[MAX_V];
ll V, E;

const ll MOD = (ll)1e9 + 7;
const int MAX_INT = 1 << 17;

vector<bool> prime;

#define all(x) (x).begin(), (x).end()
#define PRI(n) cout << n << endl;
#define PRI2(n, m) cout << n << " " << m << " " << endl;

#define REP(i, n) for (int i = 0; i < (ll)n; ++i)
#define REPbit(bit, n) for (int bit = 0; bit < (int)(1 << n); ++bit)
#define FOR(i, t, n) for (ll i = t; i <= (ll)n; ++i)

void Era(int x) {
  prime.resize(x + 1, 1);
  prime[0] = 0;
  prime[1] = 0;
  FOR(i, 2, sqrt(x)) {
    if (prime[i]) {
      for (int j = 2 * i; j <= x; j += i) {
        prime[j] = 0;
      }
    }
  }
}

bool isPrime(ll x) {
  if (x == 0)
    return 0;
  if (x == 1)
    return 0;
  if (x == 2)
    return 1;
  if (x % 2 == 0)
    return 0;
  FOR(i, 3, sqrt(x) + 1) {
    if (x % i == 0)
      return 0;
  }
  return 1;
}

ll GCD(ll a, ll b) {
  if (b == 0)
    return a;
  return GCD(b, a % b);
}

ll LCM(ll a, ll b) {
  ll gcd = GCD(a, b);
  return a / gcd * b;
}

ll nCr(ll n, ll r) {
  vector<ll> C(r + 1);
  C[0] = 1;
  FOR(i, 1, n) for (ll j = min(i, r); j < 1; --j) C[j] = (C[j] + C[j - 1]);
  return C[r];
}

template <class T> class SegTree {
  int n;
  vector<T> data;
  T def;
  function<T(T, T)> operation;
  function<T(T, T)> update;

  T _query(int a, int b, int k, int l, int r) {
    if (r <= a || b <= l)
      return def;
    if (a <= l && r <= b)
      return data[k];
    else {
      T c1 = _query(a, b, 2 * k + 1, l, (l + r) / 2);
      T c2 = _query(a, b, 2 * k + 2, (l + r) / 2, r);
      return operation(c1, c2);
    }
  }

public:
  SegTree(size_t _n, T _def, function<T(T, T)> _operation,
          function<T(T, T)> _update)
      : def(_def), operation(_operation), update(_update) {
    n = 1;
    while (n < _n) {
      n *= 2;
    }
    data = vector<T>(2 * n - 1, def);
  }

  void change(int i, T x) {
    i += n - 1;
    data[i] = update(data[i], x);
    while (i > 0) {
      i = (i - 1) / 2;
      data[i] = operation(data[i * 2 + 1], data[i * 2 + 2]);
    }
  }

  T query(int a, int b) { return _query(a, b, 0, 0, n); }

  T operator[](int i) { return data[i + n - 1]; }
};

struct UnionFind {
  vector<int> par;
  vector<int> rank;

  UnionFind(int N) {
    for (int i = 0; i < N; ++i) {
      par.push_back(i);
      rank.push_back(0);
    }
  }

  int find(int x) {
    if (par[x] == x)
      return x;
    else
      return par[x] = find(par[x]);
  }

  void unite(int x, int y) {
    x = find(x);
    y = find(y);
    if (x == y)
      return;
    if (rank[x] < rank[y])
      par[x] = y;
    else {
      par[y] = x;
      if (rank[x] == rank[y])
        rank[x]++;
    }
  }

  bool same(int x, int y) { return find(x) == find(y); }
};

struct ListNode {
  int val;
  ListNode *next;

  ListNode(int x) : val(x), next(NULL) {}
};

void Bellman_short(int s) {
  REP(i, V) d[i] = 1LL << 50;
  d[s] = 0;
  REP(i, V)
  REP(i, E) {
    edge e = ES[i];
    if (d[e.from] != 1LL << 50 && d[e.to] > d[e.from] + e.cost) {
      d[e.to] = d[e.from] + e.cost;
    }
  }
}

bool Bellman_negLoop(int s) {
  REP(i, V) d[i] = 1LL << 50;
  d[s] = 0;
  REP(i, V)
  REP(j, E) {
    edge e = ES[j];
    if (d[e.from] != 1LL << 50 && d[e.to] > d[e.from] + e.cost) {
      d[e.to] = d[e.from] + e.cost;
      if (i == V - 1)
        return true;
    }
  }
  return false;
}

void dijkstra(int s) {
  typedef pair<ll, ll> P;
  priority_queue<P, vector<P>, greater<P>> Q;
  fill(d, d + V, LLONG_MAX);
  fill(prev_path, prev_path + V, -1);
  d[s] = 0;
  Q.push(P(0, s));
  while (!Q.empty()) {
    P p = Q.top();
    Q.pop();
    ll v = p.second;
    if (d[v] < p.first)
      continue;
    for (edge e : G[v]) {
      if (d[e.to] > d[v] + e.cost) {
        d[e.to] = d[v] + e.cost;
        Q.push(P(d[e.to], e.to));
        prev_path[e.to] = v;
      }
    }
  }
}

vector<ll> getPath(int t) {
  vector<ll> path;
  for (; t != -1; t = prev_path[t]) {
    path.push_back(t);
  }
  reverse(all(path));
  return path;
}

//
// int A[100001];
//
// bool dfs(ll x, int a) {
//    A[x] = a;
//    for (edge e : G[x]) {
//        if (e.cost % 2 == 0) {
//            if (A[e.to] == -a)return false;
//            if (A[e.to] == 0 && !dfs(e.to, a))return false;
//        } else {
//            if (A[e.to] == a)return false;
//            if (A[e.to] == 0 && !dfs(e.to, -a))return false;
//        }
//    }
//    return true;
//}

bool cp(string s) {
  PRI(s)
  if (s.size() % 2 == 0) {
    int n = s.size() / 2;
    vector<char> c;
    REP(i, n) { c.push_back(s[i]); }
    FOR(i, n, s.size() - 1) {
      if (c[i - n] != s[i])
        return false;
    }

    return true;
  } else {
    int n = s.size() / 2;
    vector<char> c;
    REP(i, n) c.push_back(s[i]);
    FOR(i, n + 1, s.size() - 1) if (c[i - n + 1] != c[i]) return false;
    return true;
  }
}

ll N, K;
string s;

int main() {
  cin >> N >> K;
  ll ans = 0;
  FOR(i, 1, K) {
    if (K / i < N)
      break;
    if (K % i == 0)
      ans = max(ans, i);
  }
  PRI(ans)
  return 0;
}

Fixed submission:
#include <algorithm>
#include <bitset>
#include <climits>
#include <cmath>
#include <fstream>
#include <functional>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <set>
#include <stack>
#include <string.h>
#include <string>
#include <vector>

using namespace std;
using ll = long long;

// graph
const ll MAX_V = 1;
const ll MAX_E = 1;
struct edge {
  ll from, to, cost;
};
edge ES[MAX_E];
vector<edge> G[MAX_V];
ll d[MAX_V];
ll prev_path[MAX_V];
ll V, E;

const ll MOD = (ll)1e9 + 7;
const int MAX_INT = 1 << 17;

vector<bool> prime;

#define all(x) (x).begin(), (x).end()
#define PRI(n) cout << n << endl;
#define PRI2(n, m) cout << n << " " << m << " " << endl;

#define REP(i, n) for (int i = 0; i < (ll)n; ++i)
#define REPbit(bit, n) for (int bit = 0; bit < (int)(1 << n); ++bit)
#define FOR(i, t, n) for (ll i = t; i <= (ll)n; ++i)

void Era(int x) {
  prime.resize(x + 1, 1);
  prime[0] = 0;
  prime[1] = 0;
  FOR(i, 2, sqrt(x)) {
    if (prime[i]) {
      for (int j = 2 * i; j <= x; j += i) {
        prime[j] = 0;
      }
    }
  }
}

bool isPrime(ll x) {
  if (x == 0)
    return 0;
  if (x == 1)
    return 0;
  if (x == 2)
    return 1;
  if (x % 2 == 0)
    return 0;
  FOR(i, 3, sqrt(x) + 1) {
    if (x % i == 0)
      return 0;
  }
  return 1;
}

ll GCD(ll a, ll b) {
  if (b == 0)
    return a;
  return GCD(b, a % b);
}

ll LCM(ll a, ll b) {
  ll gcd = GCD(a, b);
  return a / gcd * b;
}

ll nCr(ll n, ll r) {
  vector<ll> C(r + 1);
  C[0] = 1;
  FOR(i, 1, n) for (ll j = min(i, r); j < 1; --j) C[j] = (C[j] + C[j - 1]);
  return C[r];
}

template <class T> class SegTree {
  int n;
  vector<T> data;
  T def;
  function<T(T, T)> operation;
  function<T(T, T)> update;

  T _query(int a, int b, int k, int l, int r) {
    if (r <= a || b <= l)
      return def;
    if (a <= l && r <= b)
      return data[k];
    else {
      T c1 = _query(a, b, 2 * k + 1, l, (l + r) / 2);
      T c2 = _query(a, b, 2 * k + 2, (l + r) / 2, r);
      return operation(c1, c2);
    }
  }

public:
  SegTree(size_t _n, T _def, function<T(T, T)> _operation,
          function<T(T, T)> _update)
      : def(_def), operation(_operation), update(_update) {
    n = 1;
    while (n < _n) {
      n *= 2;
    }
    data = vector<T>(2 * n - 1, def);
  }

  void change(int i, T x) {
    i += n - 1;
    data[i] = update(data[i], x);
    while (i > 0) {
      i = (i - 1) / 2;
      data[i] = operation(data[i * 2 + 1], data[i * 2 + 2]);
    }
  }

  T query(int a, int b) { return _query(a, b, 0, 0, n); }

  T operator[](int i) { return data[i + n - 1]; }
};

struct UnionFind {
  vector<int> par;
  vector<int> rank;

  UnionFind(int N) {
    for (int i = 0; i < N; ++i) {
      par.push_back(i);
      rank.push_back(0);
    }
  }

  int find(int x) {
    if (par[x] == x)
      return x;
    else
      return par[x] = find(par[x]);
  }

  void unite(int x, int y) {
    x = find(x);
    y = find(y);
    if (x == y)
      return;
    if (rank[x] < rank[y])
      par[x] = y;
    else {
      par[y] = x;
      if (rank[x] == rank[y])
        rank[x]++;
    }
  }

  bool same(int x, int y) { return find(x) == find(y); }
};

struct ListNode {
  int val;
  ListNode *next;

  ListNode(int x) : val(x), next(NULL) {}
};

void Bellman_short(int s) {
  REP(i, V) d[i] = 1LL << 50;
  d[s] = 0;
  REP(i, V)
  REP(i, E) {
    edge e = ES[i];
    if (d[e.from] != 1LL << 50 && d[e.to] > d[e.from] + e.cost) {
      d[e.to] = d[e.from] + e.cost;
    }
  }
}

bool Bellman_negLoop(int s) {
  REP(i, V) d[i] = 1LL << 50;
  d[s] = 0;
  REP(i, V)
  REP(j, E) {
    edge e = ES[j];
    if (d[e.from] != 1LL << 50 && d[e.to] > d[e.from] + e.cost) {
      d[e.to] = d[e.from] + e.cost;
      if (i == V - 1)
        return true;
    }
  }
  return false;
}

void dijkstra(int s) {
  typedef pair<ll, ll> P;
  priority_queue<P, vector<P>, greater<P>> Q;
  fill(d, d + V, LLONG_MAX);
  fill(prev_path, prev_path + V, -1);
  d[s] = 0;
  Q.push(P(0, s));
  while (!Q.empty()) {
    P p = Q.top();
    Q.pop();
    ll v = p.second;
    if (d[v] < p.first)
      continue;
    for (edge e : G[v]) {
      if (d[e.to] > d[v] + e.cost) {
        d[e.to] = d[v] + e.cost;
        Q.push(P(d[e.to], e.to));
        prev_path[e.to] = v;
      }
    }
  }
}

vector<ll> getPath(int t) {
  vector<ll> path;
  for (; t != -1; t = prev_path[t]) {
    path.push_back(t);
  }
  reverse(all(path));
  return path;
}

//
// int A[100001];
//
// bool dfs(ll x, int a) {
//    A[x] = a;
//    for (edge e : G[x]) {
//        if (e.cost % 2 == 0) {
//            if (A[e.to] == -a)return false;
//            if (A[e.to] == 0 && !dfs(e.to, a))return false;
//        } else {
//            if (A[e.to] == a)return false;
//            if (A[e.to] == 0 && !dfs(e.to, -a))return false;
//        }
//    }
//    return true;
//}

bool cp(string s) {
  PRI(s)
  if (s.size() % 2 == 0) {
    int n = s.size() / 2;
    vector<char> c;
    REP(i, n) { c.push_back(s[i]); }
    FOR(i, n, s.size() - 1) {
      if (c[i - n] != s[i])
        return false;
    }

    return true;
  } else {
    int n = s.size() / 2;
    vector<char> c;
    REP(i, n) c.push_back(s[i]);
    FOR(i, n + 1, s.size() - 1) if (c[i - n + 1] != c[i]) return false;
    return true;
  }
}

ll N, K;
string s;

int main() {
  cin >> N >> K;
  ll ans = 0;
  if (N == 1) {
    PRI(K)
    return 0;
  }
  FOR(i, 1, K) {
    if (K / i < N)
      break;
    if (K % i == 0)
      ans = max(ans, i);
  }
  PRI(ans)
  return 0;
}