Problem p02883 (C++)

Buggy submission (status: Runtime Error):
#include <bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < (n); ++i)

using namespace std;
typedef pair<int, int> P;
typedef long long ll;
template <class T> inline bool chmax(T &a, T b) {
  if (a < b) {
    a = b;
    return 1;
  }
  return 0;
}
template <class T> inline bool chmin(T &a, T b) {
  if (a > b) {
    a = b;
    return 1;
  }
  return 0;
}

// 最大公約数
ll gcd(ll x, ll y) {
  ll tmp = 0;
  if (x < y) {
    tmp = x;
    x = y;
    y = tmp;
  }
  while (y > 0) {
    ll r = x % y;
    x = y;
    y = r;
  }
  return x;
}

// 最大公倍数
ll lcm(ll x, ll y) { return x / gcd(x, y) * y; }

const int MAX = 1e6 + 1;
const ll MOD = 998244353;

long long fac[MAX], finv[MAX], inv[MAX];

// テーブルを作る前処理
void COMinit() {
  fac[0] = fac[1] = 1;
  finv[0] = finv[1] = 1;
  inv[1] = 1;
  for (int i = 2; i < MAX; i++) {
    fac[i] = fac[i - 1] * i % MOD;
    inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD;
    finv[i] = finv[i - 1] * inv[i] % MOD;
  }
}

struct mint {
  ll x; // typedef long long ll;
  mint(ll x = 0) : x((x % MOD + MOD) % MOD) {}
  mint operator-() const { return mint(-x); }
  mint &operator+=(const mint a) {
    if ((x += a.x) >= MOD)
      x -= MOD;
    return *this;
  }
  mint &operator-=(const mint a) {
    if ((x += MOD - a.x) >= MOD)
      x -= MOD;
    return *this;
  }
  mint &operator*=(const mint a) {
    (x *= a.x) %= MOD;
    return *this;
  }
  mint operator+(const mint a) const {
    mint res(*this);
    return res += a;
  }
  mint operator-(const mint a) const {
    mint res(*this);
    return res -= a;
  }
  mint operator*(const mint a) const {
    mint res(*this);
    return res *= a;
  }
  mint pow(ll t) const {
    if (!t)
      return 1;
    mint a = pow(t >> 1);
    a *= a;
    if (t & 1)
      a *= *this;
    return a;
  }

  // for prime MOD
  mint inv() const { return pow(MOD - 2); }
  mint &operator/=(const mint a) { return (*this) *= a.inv(); }
  mint operator/(const mint a) const {
    mint res(*this);
    return res /= a;
  }
};

// 二項係数計算
long long COM(int n, int k) {
  if (n < k)
    return 0;
  if (n < 0 || k < 0)
    return 0;
  return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}

// 階乗
ll kaijo(ll k) {
  ll sum = 1;
  for (ll i = 1; i <= k; ++i) {
    sum *= i;
    sum %= 1000000000 + 7;
  }
  return sum;
}

long long modpow(long long a, long long n, long long MOD) {
  long long res = 1;
  while (n > 0) {
    if (n & 1)
      res = res * a % MOD;
    a = a * a % MOD;
    n >>= 1;
  }
  return res;
}

// sieve(MAX);でベクトルIsPrimeに「MAXまでの数値の素数の真偽」を格納する。
struct Sieve {
  int n;
  vector<int> f, primes;
  Sieve(int n = 1) : n(n), f(n + 1) {
    f[0] = f[1] = -1;
    for (ll i = 2; i <= n; ++i) {
      if (f[i])
        continue;
      primes.push_back(i);
      f[i] = i;
      for (ll j = i * i; j <= n; j += i) {
        if (!f[j])
          f[j] = i;
      }
    }
  }
  bool isPrime(int x) { return f[x] == x; }
  vector<int> factorList(int x) {
    vector<int> res;
    while (x != 1) {
      res.push_back(f[x]);
      x /= f[x];
    }
    return res;
  }
  vector<P> factor(int x) {
    vector<int> fl = factorList(x);
    if (fl.size() == 0)
      return {};
    vector<P> res(1, P(fl[0], 0));
    for (int p : fl) {
      if (res.back().first == p) {
        res.back().second++;
      } else {
        res.emplace_back(p, 1);
      }
    }
    return res;
  }
};
struct UnionFind {
  vector<int> par;
  UnionFind(int n) : par(n, -1) {}
  int root(int x) {
    if (par[x] < 0)
      return x;
    else
      return par[x] = root(par[x]);
  }
  bool issame(int x, int y) { return root(x) == root(y); }
  bool merge(int x, int y) {
    x = root(x);
    y = root(y);
    if (x == y)
      return false;
    if (par[x] > par[y])
      swap(x, y); // merge technique
    par[x] += par[y];
    par[y] = x;
    return true;
  }
  int size(int x) { return -par[root(x)]; }
};

ll count(int n, int a) {
  ll bunshi = 1;
  for (int i = 0; i < a; i++) {
    bunshi *= (n - i);
    bunshi %= MOD;
  }
  ll bunbo = 1;
  for (int i = 1; i < a + 1; i++) {
    bunbo *= i;
    bunbo %= MOD;
  }
  bunbo = modpow(bunbo, MOD - 2, MOD);
  // cout<<(bunshi*bunbo)%MOD<<endl;
  return (bunshi * bunbo) % MOD;
}

// 約数列挙。約数をvector<ll>で返す。計算量はsqrt(n)。
vector<ll> divisor(ll n) {
  vector<ll> ret;
  for (ll i = 1; i * i <= n; i++) {
    if (n % i == 0) {
      ret.push_back(i);
      if (i * i != n)
        ret.push_back(n / i);
    }
  }
  sort(begin(ret), end(ret));
  return (ret);
}

// ここから開始
const ll INF = 1e18;
int dx[] = {1, 0, -1, 0};
int dy[] = {0, 1, 0, -1};

int main() {
  int N, K;
  cin >> N >> K;
  vector<int> a(N);
  vector<int> f(N);
  rep(i, N) cin >> a[i];
  rep(i, N) cin >> f[i];
  sort(f.begin(), f.end());
  reverse(f.begin(), f.end());
  sort(a.begin(), a.end());

  // 二分探索
  ll left = -1, right = 1e12;
  while (right - left > 1) {
    ll mid = (left + right) / 2;
    ll tmp = 0;
    rep(i, N) { tmp += max((ll)0, a[i] - mid / f[i]); }
    if (tmp <= K)
      right = mid;
    else
      left = mid;
  }
  cout << right << endl;
  // cout<<ans<<endl;
  return 0;
}


Fixed submission:
#include <bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < (n); ++i)

using namespace std;
typedef pair<int, int> P;
typedef long long ll;
template <class T> inline bool chmax(T &a, T b) {
  if (a < b) {
    a = b;
    return 1;
  }
  return 0;
}
template <class T> inline bool chmin(T &a, T b) {
  if (a > b) {
    a = b;
    return 1;
  }
  return 0;
}

// 最大公約数
ll gcd(ll x, ll y) {
  ll tmp = 0;
  if (x < y) {
    tmp = x;
    x = y;
    y = tmp;
  }
  while (y > 0) {
    ll r = x % y;
    x = y;
    y = r;
  }
  return x;
}

// 最大公倍数
ll lcm(ll x, ll y) { return x / gcd(x, y) * y; }

const int MAX = 1e6 + 1;
const ll MOD = 998244353;

long long fac[MAX], finv[MAX], inv[MAX];

// テーブルを作る前処理
void COMinit() {
  fac[0] = fac[1] = 1;
  finv[0] = finv[1] = 1;
  inv[1] = 1;
  for (int i = 2; i < MAX; i++) {
    fac[i] = fac[i - 1] * i % MOD;
    inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD;
    finv[i] = finv[i - 1] * inv[i] % MOD;
  }
}

struct mint {
  ll x; // typedef long long ll;
  mint(ll x = 0) : x((x % MOD + MOD) % MOD) {}
  mint operator-() const { return mint(-x); }
  mint &operator+=(const mint a) {
    if ((x += a.x) >= MOD)
      x -= MOD;
    return *this;
  }
  mint &operator-=(const mint a) {
    if ((x += MOD - a.x) >= MOD)
      x -= MOD;
    return *this;
  }
  mint &operator*=(const mint a) {
    (x *= a.x) %= MOD;
    return *this;
  }
  mint operator+(const mint a) const {
    mint res(*this);
    return res += a;
  }
  mint operator-(const mint a) const {
    mint res(*this);
    return res -= a;
  }
  mint operator*(const mint a) const {
    mint res(*this);
    return res *= a;
  }
  mint pow(ll t) const {
    if (!t)
      return 1;
    mint a = pow(t >> 1);
    a *= a;
    if (t & 1)
      a *= *this;
    return a;
  }

  // for prime MOD
  mint inv() const { return pow(MOD - 2); }
  mint &operator/=(const mint a) { return (*this) *= a.inv(); }
  mint operator/(const mint a) const {
    mint res(*this);
    return res /= a;
  }
};

// 二項係数計算
long long COM(int n, int k) {
  if (n < k)
    return 0;
  if (n < 0 || k < 0)
    return 0;
  return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}

// 階乗
ll kaijo(ll k) {
  ll sum = 1;
  for (ll i = 1; i <= k; ++i) {
    sum *= i;
    sum %= 1000000000 + 7;
  }
  return sum;
}

long long modpow(long long a, long long n, long long MOD) {
  long long res = 1;
  while (n > 0) {
    if (n & 1)
      res = res * a % MOD;
    a = a * a % MOD;
    n >>= 1;
  }
  return res;
}

// sieve(MAX);でベクトルIsPrimeに「MAXまでの数値の素数の真偽」を格納する。
struct Sieve {
  int n;
  vector<int> f, primes;
  Sieve(int n = 1) : n(n), f(n + 1) {
    f[0] = f[1] = -1;
    for (ll i = 2; i <= n; ++i) {
      if (f[i])
        continue;
      primes.push_back(i);
      f[i] = i;
      for (ll j = i * i; j <= n; j += i) {
        if (!f[j])
          f[j] = i;
      }
    }
  }
  bool isPrime(int x) { return f[x] == x; }
  vector<int> factorList(int x) {
    vector<int> res;
    while (x != 1) {
      res.push_back(f[x]);
      x /= f[x];
    }
    return res;
  }
  vector<P> factor(int x) {
    vector<int> fl = factorList(x);
    if (fl.size() == 0)
      return {};
    vector<P> res(1, P(fl[0], 0));
    for (int p : fl) {
      if (res.back().first == p) {
        res.back().second++;
      } else {
        res.emplace_back(p, 1);
      }
    }
    return res;
  }
};
struct UnionFind {
  vector<int> par;
  UnionFind(int n) : par(n, -1) {}
  int root(int x) {
    if (par[x] < 0)
      return x;
    else
      return par[x] = root(par[x]);
  }
  bool issame(int x, int y) { return root(x) == root(y); }
  bool merge(int x, int y) {
    x = root(x);
    y = root(y);
    if (x == y)
      return false;
    if (par[x] > par[y])
      swap(x, y); // merge technique
    par[x] += par[y];
    par[y] = x;
    return true;
  }
  int size(int x) { return -par[root(x)]; }
};

ll count(int n, int a) {
  ll bunshi = 1;
  for (int i = 0; i < a; i++) {
    bunshi *= (n - i);
    bunshi %= MOD;
  }
  ll bunbo = 1;
  for (int i = 1; i < a + 1; i++) {
    bunbo *= i;
    bunbo %= MOD;
  }
  bunbo = modpow(bunbo, MOD - 2, MOD);
  // cout<<(bunshi*bunbo)%MOD<<endl;
  return (bunshi * bunbo) % MOD;
}

// 約数列挙。約数をvector<ll>で返す。計算量はsqrt(n)。
vector<ll> divisor(ll n) {
  vector<ll> ret;
  for (ll i = 1; i * i <= n; i++) {
    if (n % i == 0) {
      ret.push_back(i);
      if (i * i != n)
        ret.push_back(n / i);
    }
  }
  sort(begin(ret), end(ret));
  return (ret);
}

// ここから開始
const ll INF = 1e18;
int dx[] = {1, 0, -1, 0};
int dy[] = {0, 1, 0, -1};

int main() {
  int N;
  ll K;
  cin >> N >> K;
  vector<int> a(N);
  vector<int> f(N);
  rep(i, N) cin >> a[i];
  rep(i, N) cin >> f[i];
  sort(f.begin(), f.end());
  reverse(f.begin(), f.end());
  sort(a.begin(), a.end());

  // 二分探索
  ll left = -1, right = 1e12;
  while (right - left > 1) {
    ll mid = (left + right) / 2;
    ll tmp = 0;
    rep(i, N) { tmp += max((ll)0, a[i] - mid / f[i]); }
    if (tmp <= K)
      right = mid;
    else
      left = mid;
  }
  cout << right << endl;
  // cout<<ans<<endl;
  return 0;
}