Problem p02586 (C++)

Buggy submission (status: Runtime Error):
#include <bits/stdc++.h>
#define rep(i, n) for (int i = (0); i < (n); ++i)
#define rrep(i, n) for (int i = 1; i <= (n); ++i)
#define drep(i, n) for (int i = (n)-1; i >= 0; --i)
#define srep(i, s, t) for (int i = s; i < t; ++i)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define limit(x, l, r) max(l, min(x, r))
#define lims(x, l, r) (x = max(l, min(x, r)))
#define isin(x, l, r) ((l) <= (x) && (x) < (r))
#define show(x) cout << #x << " = " << (x) << endl
#define show2(x, y)                                                            \
  cout << #x << " = " << (x) << ", " << #y << " = " << (y) << endl
#define show3(x, y, z)                                                         \
  cout << #x << " = " << (x) << ", " << #y << " = " << (y) << ", " << #z       \
       << " = " << (z) << endl
#define showv(v)                                                               \
  rep(i, v.size()) printf("%d%c", v[i], i == v.size() - 1 ? '\n' : ' ')
#define showv2(v) rep(j, v.size()) showv(v[j])
#define showt(t, n) rep(i, n) printf("%d%c", t[i], i == n - 1 ? '\n' : ' ')
#define showt2(t, r, c) rep(j, r) showt(t[j], c)
#define showvp(p) rep(i, p.size()) printf("%d %d\n", p[i].first, p[i].second)
#define printv(v) rep(i, v.size()) printf("%d\n", v[i])
#define printt(t, n) rep(i, n) printf("%d\n", t[i])
#define incl(v, x) (find(all(v), x) != v.end())
#define incls(s, c) (s.find(c) != string::npos)
#define lb(a, x) distance((a).begin(), lower_bound(all(a), (x)))
#define ub(a, x) distance((a).begin(), upper_bound(all(a), (x)))
#define fi first
#define se second
#define pb push_back
#define eb emplace_back
#define sz(x) (int)(x).size()
#define pcnt __builtin_popcountll
#define bit(n, k) ((n >> k) & 1) // nのk bit目
#define bn(x) ((1 << x) - 1)
#define dup(x, y) (((x) + (y)-1) / (y))
#define newline puts("")
#define uni(x) x.erase(unique(all(x)), x.end())
#define SP << " " <<
using namespace std;
using ll = long long;
using ld = long double;
using vi = vector<int>;
using vvi = vector<vi>;
using vl = vector<ll>;
using vvl = vector<vl>;
using vc = vector<char>;
using vvc = vector<vc>;
using vs = vector<string>;
using vb = vector<bool>;
using vvb = vector<vb>;
using P = pair<int, int>;
using T = tuple<int, int, int>;
using vp = vector<P>;
using vt = vector<T>;
const int mod = 1000000007;
const double EPS = 1e-9;
// const long double EPS = 1e-14;
const int INF = (1 << 30) - 1;
const ll LINF = (1LL << 62) - 1;
#define dame                                                                   \
  {                                                                            \
    puts("No");                                                                \
    return 0;                                                                  \
  }
#define yn                                                                     \
  { puts("Yes"); }                                                             \
  else {                                                                       \
    puts("No");                                                                \
  }
#define YN                                                                     \
  { puts("YES"); }                                                             \
  else {                                                                       \
    puts("NO");                                                                \
  }
inline int in() {
  int x;
  cin >> x;
  return x;
}
inline ll lin() {
  ll x;
  cin >> x;
  return x;
}
inline char chin() {
  char x;
  cin >> x;
  return x;
}
inline string stin() {
  string x;
  cin >> x;
  return x;
}
inline double din() {
  double x;
  cin >> x;
  return x;
}
// template<class T = int> inline T in() { T x; cin >> x; return (x);}
template <typename T> inline ll suma(const vector<T> &a) {
  ll res(0);
  for (auto &&x : a)
    res += x;
  return res;
}
template <class T> inline bool chmax(T &a, T b) {
  if (a < b) {
    a = b;
    return true;
  }
  return false;
}
template <class T> inline bool chmin(T &a, T b) {
  if (a > b) {
    a = b;
    return true;
  }
  return false;
}
char itoa(int n) { return n + '0'; }
ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }
ll lcm(ll a, ll b) { return a / gcd(a, b) * b; }

const int dy[2] = {1, 0};
const int dx[2] = {0, 1};

ll dp[1005][1005][4];

int main() {
  int R, C, K;
  cin >> R >> C >> K;
  vi r(K), c(K), v(K);
  map<P, int> id;
  rep(i, K) {
    cin >> r[i] >> c[i] >> v[i];
    r[i]--, c[i]--;
    id[P(r[i], c[i])] = i;
  }

  rep(k, 4) dp[0][0][k] = 0;
  if (id.count(P(0, 0))) {
    int vi = id[P(0, 0)];
    dp[0][0][0] = 0;
    dp[0][0][1] = v[vi];
  }

  rep(i, R) rep(j, C) rep(k, 4) {
    rep(di, 2) {
      int ni = i + dy[di], nj = j + dx[di], nk;
      if (!isin(ni, 0, R) || !isin(nj, 0, C))
        continue;

      if (di == 0)
        nk = 0;
      else
        nk = k;
      chmax(dp[ni][nj][nk], dp[i][j][k]);
      if (id.count(P(ni, nj))) {
        int vi = id[P(ni, nj)];
        nk++;
        if (nk == 4)
          continue;
        chmax(dp[ni][nj][nk], dp[i][j][k] + v[vi]);
      }
    }
  }

  ll ans = 0;
  rep(k, 4) chmax(ans, dp[R - 1][C - 1][k]);
  cout << ans << endl;
  return 0;
}

Fixed submission:
#include <bits/stdc++.h>
#define rep(i, n) for (int i = (0); i < (n); ++i)
#define rrep(i, n) for (int i = 1; i <= (n); ++i)
#define drep(i, n) for (int i = (n)-1; i >= 0; --i)
#define srep(i, s, t) for (int i = s; i < t; ++i)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define limit(x, l, r) max(l, min(x, r))
#define lims(x, l, r) (x = max(l, min(x, r)))
#define isin(x, l, r) ((l) <= (x) && (x) < (r))
#define show(x) cout << #x << " = " << (x) << endl
#define show2(x, y)                                                            \
  cout << #x << " = " << (x) << ", " << #y << " = " << (y) << endl
#define show3(x, y, z)                                                         \
  cout << #x << " = " << (x) << ", " << #y << " = " << (y) << ", " << #z       \
       << " = " << (z) << endl
#define showv(v)                                                               \
  rep(i, v.size()) printf("%d%c", v[i], i == v.size() - 1 ? '\n' : ' ')
#define showv2(v) rep(j, v.size()) showv(v[j])
#define showt(t, n) rep(i, n) printf("%d%c", t[i], i == n - 1 ? '\n' : ' ')
#define showt2(t, r, c) rep(j, r) showt(t[j], c)
#define showvp(p) rep(i, p.size()) printf("%d %d\n", p[i].first, p[i].second)
#define printv(v) rep(i, v.size()) printf("%d\n", v[i])
#define printt(t, n) rep(i, n) printf("%d\n", t[i])
#define incl(v, x) (find(all(v), x) != v.end())
#define incls(s, c) (s.find(c) != string::npos)
#define lb(a, x) distance((a).begin(), lower_bound(all(a), (x)))
#define ub(a, x) distance((a).begin(), upper_bound(all(a), (x)))
#define fi first
#define se second
#define pb push_back
#define eb emplace_back
#define sz(x) (int)(x).size()
#define pcnt __builtin_popcountll
#define bit(n, k) ((n >> k) & 1) // nのk bit目
#define bn(x) ((1 << x) - 1)
#define dup(x, y) (((x) + (y)-1) / (y))
#define newline puts("")
#define uni(x) x.erase(unique(all(x)), x.end())
#define SP << " " <<
using namespace std;
using ll = long long;
using ld = long double;
using vi = vector<int>;
using vvi = vector<vi>;
using vl = vector<ll>;
using vvl = vector<vl>;
using vc = vector<char>;
using vvc = vector<vc>;
using vs = vector<string>;
using vb = vector<bool>;
using vvb = vector<vb>;
using P = pair<int, int>;
using T = tuple<int, int, int>;
using vp = vector<P>;
using vt = vector<T>;
const int mod = 1000000007;
const double EPS = 1e-9;
// const long double EPS = 1e-14;
const int INF = (1 << 30) - 1;
const ll LINF = (1LL << 62) - 1;
#define dame                                                                   \
  {                                                                            \
    puts("No");                                                                \
    return 0;                                                                  \
  }
#define yn                                                                     \
  { puts("Yes"); }                                                             \
  else {                                                                       \
    puts("No");                                                                \
  }
#define YN                                                                     \
  { puts("YES"); }                                                             \
  else {                                                                       \
    puts("NO");                                                                \
  }
inline int in() {
  int x;
  cin >> x;
  return x;
}
inline ll lin() {
  ll x;
  cin >> x;
  return x;
}
inline char chin() {
  char x;
  cin >> x;
  return x;
}
inline string stin() {
  string x;
  cin >> x;
  return x;
}
inline double din() {
  double x;
  cin >> x;
  return x;
}
// template<class T = int> inline T in() { T x; cin >> x; return (x);}
template <typename T> inline ll suma(const vector<T> &a) {
  ll res(0);
  for (auto &&x : a)
    res += x;
  return res;
}
template <class T> inline bool chmax(T &a, T b) {
  if (a < b) {
    a = b;
    return true;
  }
  return false;
}
template <class T> inline bool chmin(T &a, T b) {
  if (a > b) {
    a = b;
    return true;
  }
  return false;
}
char itoa(int n) { return n + '0'; }
ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }
ll lcm(ll a, ll b) { return a / gcd(a, b) * b; }

const int dy[2] = {1, 0};
const int dx[2] = {0, 1};

ll dp[3005][3005][4];

int main() {
  int R, C, K;
  cin >> R >> C >> K;
  vi r(K), c(K), v(K);
  map<P, int> id;
  rep(i, K) {
    cin >> r[i] >> c[i] >> v[i];
    r[i]--, c[i]--;
    id[P(r[i], c[i])] = i;
  }

  rep(k, 4) dp[0][0][k] = 0;
  if (id.count(P(0, 0))) {
    int vi = id[P(0, 0)];
    dp[0][0][0] = 0;
    dp[0][0][1] = v[vi];
  }

  rep(i, R) rep(j, C) rep(k, 4) {
    rep(di, 2) {
      int ni = i + dy[di], nj = j + dx[di], nk;
      if (!isin(ni, 0, R) || !isin(nj, 0, C))
        continue;

      if (di == 0)
        nk = 0;
      else
        nk = k;
      chmax(dp[ni][nj][nk], dp[i][j][k]);
      if (id.count(P(ni, nj))) {
        int vi = id[P(ni, nj)];
        nk++;
        if (nk == 4)
          continue;
        chmax(dp[ni][nj][nk], dp[i][j][k] + v[vi]);
      }
    }
  }

  ll ans = 0;
  rep(k, 4) chmax(ans, dp[R - 1][C - 1][k]);
  cout << ans << endl;
  return 0;
}