Problem p03479 (C++)

Buggy submission (status: Time Limit Exceeded):
#include <bits/stdc++.h>

#define rep(i, n) for (long long int(i) = 0; (i) < (int)(n); (i)++)
#define rrep(i, a, b) for (long long int i = (a); i < (b); i++)
#define rrrep(i, a, b) for (long long int i = (a); i >= (b); i--)
#define all(v) (v).begin(), (v).end()
#define pb(q) push_back(q)
#define Abs(a, b) max(a, b) - min(a, b)
#define YES(condition)                                                         \
  if (condition) {                                                             \
    cout << "YES" << endl;                                                     \
  } else {                                                                     \
    cout << "NO" << endl;                                                      \
  }
#define Yes(condition)                                                         \
  if (condition) {                                                             \
    cout << "Yes" << endl;                                                     \
  } else {                                                                     \
    cout << "No" << endl;                                                      \
  }
#define Cout(x) cout << (x) << endl
#define POSSIBLE(condition)                                                    \
  if (condition) {                                                             \
    cout << "POSSIBLE" << endl;                                                \
  } else {                                                                     \
    cout << "IMPOSSIBLE" << endl;                                              \
  }
#define Possible(condition)                                                    \
  if (condition) {                                                             \
    cout << "Possible" << endl;                                                \
  } else {                                                                     \
    cout << "Impossible" << endl;                                              \
  }
#define possible(condition)                                                    \
  if (condition) {                                                             \
    cout << "possible" << endl;                                                \
  } else {                                                                     \
    cout << "impossible" << endl;                                              \
  }
#define Size(n) (n).size()

typedef long long ll;

using namespace std;

const int INF = 1e9, MOD = 1e9 + 7, ohara = 1e6;
const ll LINF = 1e18;

/*---------------------------------------------------------------
long long int kaizyo(long long int hh){
    cmp=1;
    while(hh>1){
        cmp=(cmp*hh)%MOD;
        hh--;
    }
    return cmp;
}
long long int ruizyo(long long int aa, long long int bb){
    if(aa==0){
        return 1;
    }
    else if(aa%2==0){
        long long int tt=ruizyo(aa/2,bb);
        return (tt*tt)%MOD;
    }
    else{
        return (ruizyo(aa-1,bb)*bb)%MOD;
    }
}フェルマ－のア
---------------------------------------------------------------

while(x!=0){
            sum+=x%10;
          / x/=10;
        }
        各桁の和
---------------------------------------------------------------

pair<int,int> p[100000];
cin >> tmp;
p[i]=make_pair(tmp,i);
cout << p[i].second+1 << endl;//ペアの右側つまりiを出力

---------------------------------------------------------------

bool f[100001];//1000000以下の素数を調べよう！
rrep(i,2,100001){
       f[i]=false;
    }
rrep(i,2,100001){
        if(!f[i]){
            for(int j=i+i;j<=100000;j+=i){
                f[j]=true;
            }
        }
    }
    for(int i=3;i<=100000;i+=2){
        if(!f[i]){
            c[i]++;
        }
    }

---------------------------------------------------------------

long long gcd(long long aaa,long long bbb){
    if(bbb==0){
        return aaa;
    }
    return gcd(bbb,aaa%bbb);
}

long long lcm(long long aaa,long long bbb){
    long long g = gcd(aaa,bbb);
    return aaa/g * bbb;
}左から最大公約数と最小公倍数


---------------------------------------------------------------

long long int prime_cnt[10000];
       for(int i=2;i*i<=n;i++){
           while(n%i==0){
               n/=i;
               prime_cnt[i]+=1;
           }
           if(n>1){
               prime_cnt[n]+=1;
               break;
           }
      }ある数nを素因数分解しましょう

---------------------------------------------------------------
debug:
cout<<"i: "<<i<<" j: "<<j<<" cnt: "<<cnt<<"\n";

---------------------------------------------------------------*/

long long int n, cnt = 0, ans = 0, a[ohara], b, c, d, cmp, cmpp, m, h, w, x, y,
                 sum = 0, summ = 0, pos;
int dy[] = {1, 0, -1, 0};
int dx[] = {0, 1, 0, -1};
string alph("abcdefghijklmnopqrstuvwxyz"), s;
bool fl = true;
struct edge {
  int to, cost;
};

//-------------------------↓↓↓↓↓↓------------------------

int main(void) {
  cin.tie(0);
  ios::sync_with_stdio(false);
  long long x, y;
  cin >> x >> y;
  ans = 0;
  for (int i = x; i <= y; i *= 2) {
    ans++;
  }
  cout << ans << endl;
  return 0;
}


Fixed submission:
#include <bits/stdc++.h>

#define rep(i, n) for (long long int(i) = 0; (i) < (int)(n); (i)++)
#define rrep(i, a, b) for (long long int i = (a); i < (b); i++)
#define rrrep(i, a, b) for (long long int i = (a); i >= (b); i--)
#define all(v) (v).begin(), (v).end()
#define pb(q) push_back(q)
#define Abs(a, b) max(a, b) - min(a, b)
#define YES(condition)                                                         \
  if (condition) {                                                             \
    cout << "YES" << endl;                                                     \
  } else {                                                                     \
    cout << "NO" << endl;                                                      \
  }
#define Yes(condition)                                                         \
  if (condition) {                                                             \
    cout << "Yes" << endl;                                                     \
  } else {                                                                     \
    cout << "No" << endl;                                                      \
  }
#define Cout(x) cout << (x) << endl
#define POSSIBLE(condition)                                                    \
  if (condition) {                                                             \
    cout << "POSSIBLE" << endl;                                                \
  } else {                                                                     \
    cout << "IMPOSSIBLE" << endl;                                              \
  }
#define Possible(condition)                                                    \
  if (condition) {                                                             \
    cout << "Possible" << endl;                                                \
  } else {                                                                     \
    cout << "Impossible" << endl;                                              \
  }
#define possible(condition)                                                    \
  if (condition) {                                                             \
    cout << "possible" << endl;                                                \
  } else {                                                                     \
    cout << "impossible" << endl;                                              \
  }
#define Size(n) (n).size()

typedef long long ll;

using namespace std;

const int INF = 1e9, MOD = 1e9 + 7, ohara = 1e6;
const ll LINF = 1e18;

/*---------------------------------------------------------------
long long int kaizyo(long long int hh){
    cmp=1;
    while(hh>1){
        cmp=(cmp*hh)%MOD;
        hh--;
    }
    return cmp;
}
long long int ruizyo(long long int aa, long long int bb){
    if(aa==0){
        return 1;
    }
    else if(aa%2==0){
        long long int tt=ruizyo(aa/2,bb);
        return (tt*tt)%MOD;
    }
    else{
        return (ruizyo(aa-1,bb)*bb)%MOD;
    }
}フェルマ－のア
---------------------------------------------------------------

while(x!=0){
            sum+=x%10;
          / x/=10;
        }
        各桁の和
---------------------------------------------------------------

pair<int,int> p[100000];
cin >> tmp;
p[i]=make_pair(tmp,i);
cout << p[i].second+1 << endl;//ペアの右側つまりiを出力

---------------------------------------------------------------

bool f[100001];//1000000以下の素数を調べよう！
rrep(i,2,100001){
       f[i]=false;
    }
rrep(i,2,100001){
        if(!f[i]){
            for(int j=i+i;j<=100000;j+=i){
                f[j]=true;
            }
        }
    }
    for(int i=3;i<=100000;i+=2){
        if(!f[i]){
            c[i]++;
        }
    }

---------------------------------------------------------------

long long gcd(long long aaa,long long bbb){
    if(bbb==0){
        return aaa;
    }
    return gcd(bbb,aaa%bbb);
}

long long lcm(long long aaa,long long bbb){
    long long g = gcd(aaa,bbb);
    return aaa/g * bbb;
}左から最大公約数と最小公倍数


---------------------------------------------------------------

long long int prime_cnt[10000];
       for(int i=2;i*i<=n;i++){
           while(n%i==0){
               n/=i;
               prime_cnt[i]+=1;
           }
           if(n>1){
               prime_cnt[n]+=1;
               break;
           }
      }ある数nを素因数分解しましょう

---------------------------------------------------------------
debug:
cout<<"i: "<<i<<" j: "<<j<<" cnt: "<<cnt<<"\n";

---------------------------------------------------------------*/

long long int n, cnt = 0, ans = 0, a[ohara], b, c, d, cmp, cmpp, m, h, w, x, y,
                 sum = 0, summ = 0, pos;
int dy[] = {1, 0, -1, 0};
int dx[] = {0, 1, 0, -1};
string alph("abcdefghijklmnopqrstuvwxyz"), s;
bool fl = true;
struct edge {
  int to, cost;
};

//-------------------------↓↓↓↓↓↓------------------------

int main(void) {
  cin.tie(0);
  ios::sync_with_stdio(false);
  long long x, y;
  cin >> x >> y;
  ans = 1;
  while (x * 2 <= y) {
    x *= 2;
    ans++;
  }
  cout << ans << endl;
  return 0;
}