trigonometry question?

suppose p(-5/6,y) is a point on the unit circle in the third quadrant. let θ be the radian measure of the angle in standard position with p on the terminal side, so that θ is the circular coordinate of p. evaluate all the circular functions of θ.

if (x,y) is a point on the unit circle, x2+y2=1.
 
in the third quadrant, x and y are both negative.
 
since x = -5/6, we have (25/36) + y2 = 1
 
                                                y2 = 11/36
 
                                                y = -√(11)/6
 
cosθ = x = -5/6                secθ = 1/cosθ = 1/x = -6/5
 
sinθ = y = -√(11)/6           cscθ = 1/sinθ = 1/y = -6√11/11
 
tanθ = y/x = √(11)/5         cotθ = 1/tanθ = x/y = 5√11/11