chemistry homework help

write a balanced metathesis equation for the reaction which takes place when the two solutions described below are combined and then determine the amount of solid product produced. 250.0 ml of 0.200 m solution of fecl3 is combined with 400.0 ml of 0.350 m koh solution. how many grams of solid iron (iii) hydroxide will be produced by the reaction. assume 100% yield.

hello jana,
 
the balanced equation:
 
fecl3(aq)        +       3 koh(aq)  -----------------  fe(oh)3(s)        +      3 kcl(aq)
 
mole ratio:        1 mol                       3 mol                                  1 mol                        3 mol
 
 
 
250.0 ml of 0.200 m solution of fecl3   =  0.250 l x 0.200 mol/l  =  0.05 mol fecl3
 
400.0 ml of 0.350 m koh                   =   0.400 l  x 0.350 mol/l  =  0.14 mol koh
 
 
consider 0.05 mol fecl3:
 
mol of fe(oh)3 formed =  (1 mol fe(oh)3/1 mol fecl3) x 0.05 mol fecl3 = 0.05 mol fe(oh)3
 
 
consider 0.14 mol koh:
 
mol of fe(oh3) formed =  (1 mol fe(oh)3/3 mol koh) x 0.14 mol koh   = 0.047 mol fe(oh)3
 
 
thus, 0.047 mol fe(oh)3 will be formed . using the molar mass of fe(oh)3 = 106. 86 g/mol
 
0.047 mol fe(oh)3 x 106.86 g/mol = 5.0 g fe(oh)3 will be produced.
 
 
comment: this problem is similar to the previous one. thus, refer to the previous problem for the explanation.