what is the y-intercept of 5x+2y=5 on a graph?

what is the y- intercept of the equation 5x+2y=5 given on a graph?

hi kevin;
i would like to add to ian and joshua's answer.
 
according to joshua, the procedure to finding the y-intercept is to convert this formula into slope-intercept form.  i agree.  but i would like to explain the nature of the original formula.
5x+2y=5
this is in standard formula...
ax+by=c, a>0, b≠0
 
joshua converted this from standard to slope-intercept, whereas ian worked exclusively with the original standard.

to find the y-intercept, we must set x equal to 0.  our equation is thus:
 
5(0) + 2(y) = 5  =>  2(y) = 5
 
dividing each side by 2 we get:
 
y = 5/2
 
this is the intercept.
 
thanks for the question.  good luck!
 
 

hi kevin,
 
i would use slope-intercept form. i always think it's the easiest.
 
slope intercept form looks like this  y=mx+b
 
m is your slope and b is your y-intercept (which you're looking for)
 
so you have to go from 5x+2y=5 and put it into the y=mx+b form.
 
in other words, solve for y.
 
step 1) subtract 5x from both sides.
 
5x+2y=5  ---->   2y=5-5x
 
step 2) divide both sides by two (then y will be alone, but remember to divide everything on the other side by two!)
 
2y=5-5x  -----> y= (5-5x) / 2 -------> y=(5/2) - (5/2)x
 
step 3) rewrite it so it's mx+b
 
(5/2) - (5/2)x ---->  -(5/2)x + (5/2)
 
remember, you're looking for b (the y-intercept) so it's simply 5/2
 
hope this helps and good luck in class.