vinny1575/vinny1575.github.com — comment on commit 00f69d4465118f64dec0d1c5ec29551bf6d9a98d
File: Project 2/index.html line 107
By rickosborne:

You don't need to wrap the function call in the $() here. Since loadJSON doesn't return anything (much less anything you would want to use as a jQuery selector) you don't need to pass it to jQuery, just call it. The same goes for the next two farther down.