Okay in this video I'd like to continue on with my tutorials and electrostatics. This is video number 16 and I'm going to discuss the electric field of a parallel parallel plague faster. I'd like to draw attention to my website universityphysicsstoreyans.com and also if you'd like to find out news or updates on my posts you can follow me on twitter at LMBT503. So the three videos which are previously this and are relevant. Video 13, I discuss galsas law and symmetry. Video 14, I discuss the electric field of an infinite plane and a video 15 I discuss the electric fields of wire. I'll be using the video excuse me the result of the video are 14 in this particular video. So let's think about it. First of all for the electric field of an infinite plane it's simply one half sigma over epsilon zero in the n-hand direction. That's what I saw in video number 14. So if we draw a parallel plague faster we have the following. There's plate one there's plate two and let's say I put the same charge density on each or the area charge density on each. So if minus sigma here we have plus sigma here. Okay and let's say they have the same area. So I'm going to call this region this region A this region B and this region C. Now what we know we know that for positive charges the electric field is beginning on positive charges. This is plus Q but on a minus Q the electric field terminates on the negative charge. So what we know that for an infinite plane would say these if they're large enough at least in the center is let's say if we just look inside here okay that's a small region of it just look in the middle of it we can say approximate that the electric field is half sigma over epsilon zero and hat. Okay so what direction is that the electric field is going to be? Well that means we'll say we're going to have the electric field going this way because it's going away from the it's going away from the positive charge all right and it's going this way. It's away from the positive charge there that's E plus. Now over here we have it's continuing on so the electric field is it's still in that direction okay that's E plus again but the electric field on the negative charge is going to be towards it so we're going to have E minus we're also going to have E minus here sorry that's a minus and also of course we're going to have an E minus here okay I hope that makes sense so if you just look at it in the following way there is that's the electric field of one of the plates that's the electric field of the negative plate what the electric field continues on so it also affects the other plate so in region A we see the reef that they're going to cancel because their magnitude is the same in region B they're going to add because they're in the same direction and region C they're going to they're going to cancel. So in region B what we're going to actually have is E is equal to twice half sigma over epsilon zero okay or it's going to be sigma over epsilon zero so that tells us that the electric field due to a parallel plate capacitor is simply sigma over epsilon zero and a point in this case to the right between the two plates and elsewhere is zero so the right actually is pointing from positive charge to negative charge so thanks for watching please pass down to your friends subscribe to my channel and you might also click on University Physics Tourist.com