I am Sontosh Ghazenkar. Today I am teaching you design of machinement 2 in that one, antifriction bearing. A SKF bearing 6-2 double 0 is used to support a radial load that is a phase given 1000 Newton determined, the rated life and life at 99% survival rate. A phase not gun thrust forces, thrust load is 0 here. So solution for this one, the SKF 6-2 double 0. 6-2 double 0 is the 6-2 double 0. 6-2 double 0 means this is the value of the 6-2 double 0, it is a series 2. Here we have to find out dynamic load and static load, but I have given here dynamic load. This is the load, dynamic load 5070, dynamic load is there. Here R is equal to 0.09. First you have to find out the rated life, the life of the bearing L is equal to C divided by P, R is to 3. We do not know the P here, how to find out the P? Because F is equal to 0 here, therefore one more formula is there, P is equal to F R into KS. F R is 1000 into 1, you will get 1000 Newton assuming the steady load KS is equal to 1. Substitute in this formula you will get 1-0, 130.32 million revolution. Next life at 99% survival rate. This is the formula because R is given 99% here, but here in place of L10 you have to substitute this value, you know to get the L value. In calculator, treat this as a X and calculate, you will get the answer directly. I am Sotas Gaiankar, thank you very much.