Next question, question says a proton and an alpha particle both entire region of uniform magnetic field B moving a tritangle to the field B. If the radius of circular orbit for both the particle is equal and the kinetic energy acquired by a proton is 1 mega electron volt, so all the energy acquired by alpha particle what will happen? Our option is 1.5 mega electron volt or 1 or 4 or 0.5 mega electron volt. Now, so all the things will be done basically. You have already known that any charge particle when a magnetic field enters, its radius r, we write mv divided by Qb, or I am going to give you formula revise. We write this thing here p divided by Qb where p is your momentum and we can write this radius in a format, this will be 2 mk divided by Qb, k your kinetic energy is your momentum, so p is our momentum, we can write here. Now based on this, if we square both of you, we will rearrange a little bit, so we can write here that your kinetic energy will be equal to r square Q square B square divided by 2m, or your kinetic energy will be any particle. Now in this case, we have given both the radius of your radius and your k, two of your particles are here, proton and a alpha particle, so I can write this, so we can say this implies this, we can say this is the kinetic energy will be proportional to Q square divided by m, or your proportional to the one we are going to use, so we have to tell you the ratio, what energy do you have, we have given the energy of proton here, we have to tell you the energy of the particle, so we will write kinetic energy of alpha divided by kinetic energy proton, this will be Q of alpha divided by Q of proton, in both the charge of its square multiplied by mass inverse ratio i.e. mass of proton divided by mass of alpha. Now let us take this, kinetic energy of proton is the one mega electron volt, so kinetic energy of alpha will be kinetic energy, this will be, Q alpha divided by Qp ratio, so Q alpha divided by Qp ratio is from 2 by 1 we can write, its square multiplied by mass of proton divided by mass of electron ratio, so mass of proton mass of electron ratio 1 by 4 will be multiplied by 1 mega electron volt, or your energy will be coming, so we will square it, 4 is there, 4 is there, 4 will be cancelled, so kinetic energy will be equal to 1 mega electron volt, or your alpha particle will be kinetic energy, so based on this we can say, option number b, 1 mega electron volt would be the right answer.