In this problem, you're asked to determine how much heat energy is needed to raise the temperature of a particular amount of oil from 23 degrees to 191 degrees Celsius, and you're given a specific heat of oil. Below the question is the setup and the final answer. I'll walk you through it step by step. Once we need to recognize, we need the equation Q equals MC delta T. Where Q is the heat and the unit of the heat we're going to get as in joules, as you can see in the final answer, M is the mass and grams of the material, in this case the oil, but they give us the mass in kilograms. So we need to convert the kilograms to grams. So the 2.23 kilograms is 2,230 grams. The specific heat we're given is 1.75 joules per gram degree C, and I'm emphasizing the units. The delta T is the change in temperature, and that is the final temperature, less the initial temperature. So first you enter the final temperature and then you subtract from it the initial temperature. So the starting temperature was 23, and the final temperature was 191. So the delta T is 170 degrees C. So you plug these numbers into the equation, and you see how nicely the units cancel, grams and grams, and degrees C with degrees C, and what you're left with in green is the unit of joules. Multiply all the numbers, and you get 663,424 joules, which is equivalent to 663.425 kilojoules. Now I presented both units, joules and kilojoules, just in case you need to enter one or the other.