Google Online University Channel please like and subscribe the channel ok friends so today we start with our friends Kinetic and Thermodynamic Stability in coordination compounds your friends first of all you have to clear your stability and reactivity in any relation stability of your thermodynamic phenomena and reactivity, kinetic phenomena ok friends so just like i have shown you two examples this is the ethylene molecule and this is the ethylene molecule so what is the ethylene? this is the kinetically stable molecule because the single bond is the single bond that is the head on or left molecule this is the kinetically stable molecule and your thermodynamic unstable molecule ok friends if i take another example of this, this is the kinetically stable so what is the ethylene? now this is the kinetically unstable why is the kinetically unstable? because the double bond has been pi bond so what is the pi bond? partially over there, both the difference less activation energy required, so what is the kinetically unstable? but thermodynamic stable over here friends so thermodynamically stable so friends, if stability is the kinetically stable then it is the kinetically stable, so stability is the two types of thermodynamic stability and your kinetically stability so thermodynamically stable is the stability measured in the terms of endropi, enthalpy, free energy and the stability in the constant terms, thermodynamically stable is measured so friends now the second stability is the kinetic stability what do we see in the kinetic stability? we see that the less activation energy required then the kinetically unstable ok friends so the kinetically stable is the two types of thermodynamically stable so what is the molecule? the left or left? the inner complex? so the question comes, now the net and gate of the question will be the kinetically stable so what molecule will be the inner and which molecule will be the inner? so the inner and inner molecule will be the two types of thermodynamically stable so the wibiti has given the theory of cocafants and CFS so the question will be the question, the CFS will be the base of the question the CFS will be the easy way to explain the cocafants so on the basis of CFS so what is the difference? before the wibiti, so the wibiti is not so good results so in the first phase of the comparison, then the CFS so what is the difference? the two scientists who have been in the Bersan have found that the change in CFS is calculated by the experiment so they have a table droghery so the change of CFS value of octahedral complexes is the change in the cocafants so what if they have a high-speed system or a low-speed compared to the first phase of the comparison, they have a table droghery so for B0, what will be the difference? the high-speed and low-speed are zero so before I tell you the table, I will tell you one thing if there is a molecule loss in CFS, then the inner and complex so if there is no loss in the cocafants, then the overall complex is the same on the basis of CFS if the cocafants are loss in CFS, then the molecule will be the inner and complex and if no loss and gain in CFS, then the molecule will be the complex so what will be the difference? so what will be the difference? for B0, the high-speed and low-speed are zero and the cocafants are the change in CFS so if we talk about the high-speed, then D1, D2, D3, D4 then for D2, the high-speed and low-speed are zero and for D4, the high-speed and low-speed are zero for D6, the high-speed and low-speed are zero so what will be the difference between D9 and D10 and D10? so what will be the difference between D0 and D10? okay friends, so what will be the difference between the high-speed and low-speed? we will remember the difference between D1, D2, D3 and D4 so for D7, D4 and D4, D4 and D4 are zero and D6, D7, D8 and D9 are zero so we will write this on the top of the high-speed and low-speed and low-speed is zero so what will be the difference between D3 and D4? so for D4, D5, D6, D5 and D6 are zero so for D3, you will have to sing this point 5, 7, 1, 1, 1, 4, minus 2, 0, 0, 0 and minus 1, 4, 3 so friends, remember that minus 1, 4, 3 and minus 0, 8, 6 and minus 4, 0, 0 and other things so plus 1, 1, 4, minus 2, 0, 0 and plus 3, 0, 1, 4 so friends, so this will be the most inert, if there is a complex in D6 and if there is a low-speed then most inert complex will be the most inert, so remember the difference so let me tell you that for D1, D2, D3 and D4 you have to remember and for low-speed you have to remember for D4, D5 and D6 and easy to remember, it is such a tiny difference and one thing, if this happens, if your loss in CFS, then the molecule will be inert if no loss or no, and gain in CFS, then it will be taken away and one thing, if coordination number 4, the number 4 of coordination number of complex is taken away because what happens is that the difference is more reactive, then the available sites that no one will be able to attack and attack and if we move down the group, then 4D and 5D complex, like we are going down in groups, transition elements, so what happens? the inert increases, okay friends, so this happens in the lab and inert, now one question is, what happens in the gate? now what happens is, designate the following complex, x, y, z as inert or lab, then designate the molecule in the lab and what will be inert, so first x is the aluminum, C2O4, oxidative, C2O4, cathode, 3- and y there is also H2O2, H2O2 plus, okay friends, z there is C2O4, 3 and 3 plus, so if I say this, then what happens? 3D0, this is P600, this is P600, this is P600, okay friends, now I will talk about vanadium, this is the kind of titanium, I mean D3, okay friends, this is plus 2, then what happens? 3D3 will happen, okay friends, because plus 4 oxidation state, what happens in the chromium? plus 2D, your D4 and what happens in plus 3D3, okay friends, and all these are all of the octahedral complexes, so we have to pay attention to this, so this is 0, so what does 0 mean? so if you are going to get the x, then x will get the x, then you will get the x, and z will get 3D3 and 3D3 and the high skin will get the x, so 3D3 minus 2.0 CFSU, so what are these two benefits? they will get inert and x will get the x, so what option will you get? x will get the x, then you will get the x, then you will get the x, then you will get the x, then if you liked the video, then please like and subscribe, and keep watching till the end, okay friends, thank you for watching this topic. 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