My guys, this is a setup, a switching circuit. We have 2.1 ohm resistors here in series, the discharge, hang around through this wire, through this battery, and back to the capacitor. This is a run battery here. That's the voltage of the run battery. It's a current consumed 200 milliamps. We'll look over here on the sky. You can see I've got the sky private across the 0.2 ohms resistance. I'm just going to zoom in on nice resistors. It's upside down 0.01 ohm. Turn it in. Alright. I'm going to call on pulsing here. We'll look at the oscilloscope. You can see on the current, impulse current is going into the battery. We'll look in here, the VMAX. VMAX current, we've got there about 172 milliamps of current. Let me take away the odd spot that happens about 170 milliamps. About 170 milliamps across the 0.2 ohms resistance. Okay. 170 milliamps across the 0.2 ohms resistance. Preconcee, 100 hertz, about 1.6 milliamps per second pulse width. I'll show the drain waveform fully. Now, if you take the calculator, I'll punch in 0.18 for the millivolts. 180 millivolts divided by 0.2 is resistance equals 0.9 of an amp of current. So the max current of those spikes is 0.9 of an amp. We'll make 1.8 max current. You can see there, that's current. This is voltage, of course, a pair of resistors, 2.2 ohms of resistance. That's the current that charges the battery. This is the battery voltage that's being charged. Let's try the climbing. Let's see, battery voltage being used. Let's see, current. Now, if we change the scope, we'll put in... RMS voltage, which I probably won't do a very good job of reading. RMS voltage across those 2.1 ohms resistors will call it 55 milliamps. 55 millivolts across the 0.2 ohms resistance. OK. So that's 0.05 millivolts divided by 0.2 ohms. It was 250 milliamps charge current. 250 milliamps charge current. That needs probably a bit out. So I was probably drawing 250 milliamps. And this battery is a higher voltage than this battery. So the same power out of this battery will be less current than the same power into this battery, because of the voltage differences. OK. The rest of the current will be the current in the battery. The peak of 900 milliamps is the current. Almost one end of the current. Peak current. OK. Let's take that down. I'll remove this scope probe here. There we go. I'll put the scope probe on the drain of the MOSFET. Looks like... There we have... We've got the waveform charging the battery. Notice the voltage doesn't rise right up high, because the battery is in fairly good condition. So when the coil disc charges is on time here, when the coil disc charges, it goes up to the double battery voltage or the two batteries together. And it charges across there with the impulse current. And it drops off to the single battery voltage. That's the drain voltage. OK. Just charge the current. There's like that. Not that. Starts at a high current first and then take us off. 12.7 volts. That's going in there. Let's see if it's just a regular inverter circuit. I'll show you the switching waveform. There's the switching waveform there. Nice, great. Pulsors to the MOSFET dates to switch the MOSFETs on and off properly. Oh good. OK. Thanks for watching.