Welcome students. Today we will solve analysis and solve analysis where root of zero group ammonium radical right take the prancho amount of salt in a dish to add anewich. We will smell it very less ammonic acid smell is there. Now we will heat it up after 20 sec. Again we will smell it. Yes ammonic acid smell is there. It means zero group is present and n is for plus meat. Now immediately we will bring the glass coat, dip, tina, coarser, and real near the mouth of the dish. You see dense fumes are coming. It shows n-h-fourth plus is confirmed. One more contaminated is for ammonia with it. We will take the salt, energies to wait. We have washed it together. Prepare the solution. Add necessary agent K2HG-i-4. You see chocolate probability is there. It shows in given salt, n-h-fourth plus is confirmed or ammonium radical is present. Now in the same salt we will remove the test four acidic radical. For acidic radical we will take the test right. Take the salt, pinch amount of, add the uselessness of salt. Smell it. Yes there is no smell. It means dilute estuase of four group is absent. Along with dilute estuase of four group, four radicals are absent. Carbonate, sulphide, sulphide, nitrate. Now we will proceed for next group. That is concentrated estuase of four group. We will take the salt, add, concentrate sulphuric acid. You see, raw or orange, fumes are come. You can say this is a prong. These prong fumes shows in given salt, concentrate estuase of four group is present and B-confort. But after acidic acid will become one more confirmably test. Prepare the solution, add dilute estuase of three group. Few drops, ag and entry. You see, light yellow ppt has come. We will see the solubility of this ppt with NH4 torch. We will reduce the quantity of this. Then we will check the solubility in a popper. See, it is a partially stored. It means VR minuses confirm. So in given salt, NH4 versus basic radical and B-acetic radical is present. Thank you.