无

因有多人过问，因此，再发一遍“挂”的网址。以后，除非这些网址有改动，不再回答“挂的论坛是多少”这类问题。
(1) 挂的汇集。注意，以下链接内有人散布带病毒的挂。因此，为了自己的隐私(例：信用卡号，各种密码，家人的照片等)，应该： 
==> 勿用没源代码的挂 (即：以.exe或 .a3x为尾缀的挂，都不要用；看到就要删。另外，如看不到文件尾缀，也不要用)。
==> 勿用没有众人留言认可或点赞过的挂。
==> 勿用其中gwa2.au3(激战接口文件)与众不同的挂 (可用https://www.diffchecker.com/ 对比各激战接口文件的不同)。
最后，论坛地址是：
(2) 激战助手 C++版，其中，游戏更新后，如挂需要相应的更新，则会出现在GWCA夹子里 (gwca = C++版的激战接口文件)。助手地址是：
那你的意思是，从昨天起，一堆人的账号是在没有走漏账号密码的情况下，被盗了
那你也已肯定那些人的账号和用第三方的exe和a3x无关?
那这“很多人”都没用过挂，具体是哪些人，好像玩激战的都会用挂，或许只是“很多人”没承认自己用过挂呵呵
找到了一解答问题的暂行方案，即，在他人表达问题时，若问题的内容有点模糊，不完整，或不清楚，我就一概如下作答了：“不清楚，无法回答；可录像”。(当然，如连录像都录得丢三落四地，那照样不答 ) 。 无法每次都 花30分钟-2个小时 在那儿 即 苦口婆心 又 挤牙膏似地 引导 别人 去把 他们自己的问题 用 中文 描述清楚呵呵 。另外，可适当地减少以下字眼所出现的频率 (即，那些没有定义的各种万能“代”词)，例: "搞，弄，使，行" 等。有必要时，也可避免运用 那些 主语失踪，谓语出家，宾语阵亡 的不完整句子 。
野队论坛上根本没这样教的。在谩骂，嘲笑，和讽刺的"鼓励"下，根本没人会如此被动的。论坛上没人敢指望有人手把手帮忙，他们都是有一丁半点的线索就已经痛哭流涕了。可群里人倒好，有现成的东西，全中文的，有时比野队还全的工具，连测试都不带测试的，等喂饭等成了精。
不干我事，以后就是群里人没录像，或描述不清楚，我就不管，否则尽是让自己难受，非得去看那些丢三落四又不知所云的简陋描述。别人三个字的问题，我要犯贱地花上三段话才能猜出他到底什么意思，然后竟还要解答。现在变得别人越问越高兴，而且花在描述问题上的字数也越来越少，因为反正最后我都能答，扔给我就行了，完全不在乎回答简陋的问题会要浪费多少时间。又不是我需要解答，我自己的问题还没人回答呢，烦死了呵呵
新闻：
但接到机上广播通知：“
有一架飞机在飞行过程中玻璃碎裂，备降成都，因要给备降航班留出通道，所以CA4185暂不起飞"
改:
有飞机遇险 (驾驶舱穿漏)。征本站跑道应急。以下航班受阻。延误时间不明 (大于 3 小时)。
可供 外文学习者 参考的媒体产物不可避免地受其当地人文影响。这些 不必刻意地政治宣传就会。以下提供吻合“自由世界”口气和说话方式的外文范文。这些范文的出发点皆与“自由世界”的各种立场截然相反。写作目的：令读者发现，可用外文对“自由世界”反唇相讥，可用外文声援中国中共。照样可以被用反华，包括反共不反华之说，不理所当然。修辞 推理，拨开云雾，实质内容
spear mod, it's 7e
and that must be an unique spear mod right there
no it's a standard spear mod right there
if u need to convince urself thru pm's, pm urself
that would be idiotic, like the idea
hasn't stopped u before, won't stop u since
thanks for your time:) you have a good one
did u need to show urself out
nope im here all dya long
day*
steady ur fingers
i know hehe sorry abt that
too much information
*If you wish for an infinite number of solutions, get both solutions in the unit circle, then do +2*n*pi, where n is an integer
:OR
*Inverse Cosine is a unique solution from 0 to PI
**Do (2*pi - t) to get the other solution from [0, 2*pi)
*Inverse Sine is a unique solution from -PI/2 to PI/2
**Do (pi - t) to get the other solution from [0, 2*pi)
sin(–t) = –sin(t)
cos(–t) = cos(t)
sin( pi - t) = sin t
cos( pi - t) = - cos t
cos( 2*pi - t) = cos t (duh, straight from above)
*Dot Product 
**Is a scalar
**Involves cos(x)
***Range of Inverse Cosine is [0, pi]
**Is symmetric across the 0-pi axis
**Is an orthogonal test, i.e., when it equals 0, the two vectors are orthogonal
**Formula proved by:
***Law of Cosines (https://proofwiki.org/wiki/Cosine_Formula_for_Dot_Product)
***Interpretation: dot product is really a transformation, which can also be viewed as a projection (https://www.youtube.com/watch?v=LyGKycYT2v0)
**Sign of Dot Product can only determine if the angle between the vectors have crossed the 90 degrees threshold (i.e., to be clear, the "vertical" threshold, when holding either one of the vectors as horizontal; either one because the choice makes no difference).
***It cannot determine whether the angle has crossed the 180 degrees threshold because the value is symmetric across the horizontal axis, and inverse cosine will only yield a single solution, which falls between 0 and 180 degrees. 
***You may well respond with an angle value greater than 180 degrees, using the (360 - t) cosine identity above (https://www.quora.com/Why-dot-product-of-two-vectors-is-defined-for-angle-between-o-and-180-degrees)
***Better suited to determine the angle between two vectors, without one of them being the starting reference
**Makes no sense to view one of the vectors as a reference/starting vector when counting the angle
*Cross Product
**Is a vector
**Involves sin(x)
***Range of Inverse Sine is [-pi/2, pi/2]
**The MAGNITUDE is symmetric across the -PI/2 to PI/2 axis
***HOWEVER, the direction of the cross product flips as the input angle changes sign
**Is a parallel test, i.e., when it equals 0, the two vectors are parallel
**Formula proved by:
***Definition and Dot Product Formula (https://math.la.asu.edu/~surgent/mat272/cross_mag_proof.pdf)
**Sign of the Cross Product determine if the angle has crossed the 180 degrees threshold (i.e., to be clear, the "horizontal" threhold, when holding one of the vectors as horizontal, the choice of starting vector MATTERS)
**Choosing one of the vectors as a reference/starting vector when counting the angle matters; the choice will affect the sign/direction of the result, as indicated by the right hand rule</u>
***https://stackoverflow.com/questions/7785601/detecting-if-angle-is-more-than-180-degrees