nyuuzyou/kompy huggingface dataset:
O`zbekistоn respublikasi - bet 7

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O`zbekistоn respublikasi
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bet | 7/12 | Sana | 30.11.2023 | Hajmi | 94,16 Kb. | | #108725 |
Ishlab chiqarishning uchinchi pallasi yig ‘ma sintetik hisobini: asosiy kitobning schyotlari bo'yicha hisobot, saldo qaydnomalari va moliyaviy hisobotning shakllarini tuzishdan iborat bo ‘ladi. Namunaviy buxgalteriya hujjatlari sohalararo va sohaviyga bo'linadi. Sohalararo hujjatlar barcha korxona iqtisodiy obyektlarda qo ‘Hash uchun yagona bo ’ladi. Sohaviy shakllar tavsiyanomaviy harakterga ega. Barcha birlamchi buxgalteriya hujjatlari GOST, hujjatlarning bir shaklga keltirilgan tizimlari talablarini hisobga olish bilan ishlab chiqiladi. Buxgalteriya hisobining hujjatlari turli belgilari bo ‘yicha tasniflanadi: - belgilanishi bo'yicha - fa r moyish beradigan, ijroiya (oqlaydigan), hisobli rasmiylashtiruvchi, murakkab; - x o ja lik operatsiyalari mazmuni bo ‘yicha moddiy, pulli hisoblash, - aks ettirgan operatsiyalarning hajmi bo'yicha yagona (birlamchi) yoki yig 'ma; -foydalanish usuli bo 'yicha: bir martali va jamlovchi: - hisobga oladigan о 'rinlarining soni bo 'yicha: bir qatorli va ко 'p qatorli; - tuzilish joyi bo 'yicha: ichki va tashqi; - Ishlab chiqarishning uchinchi pallasi yig ‘ma sintetik hisobini: asosiy kitobning schyotlari bo'yicha hisobot, saldo qaydnomalari va moliyaviy hisobotning shakllarini tuzishdan iborat bo ‘ladi. Namunaviy buxgalteriya hujjatlari sohalararo va sohaviyga bo'linadi. Sohalararo hujjatlar barcha korxona iqtisodiy obyektlarda qo ‘Hash uchun yagona bo ’ladi. Sohaviy shakllar tavsiyanomaviy harakterga ega. Barcha birlamchi buxgalteriya hujjatlari GOST, hujjatlarning bir shaklga keltirilgan tizimlari talablarini hisobga olish bilan ishlab chiqiladi. Buxgalteriya hisobining hujjatlari turli belgilari bo ‘yicha tasniflanadi: - belgilanishi bo'yicha - fa r moyish beradigan, ijroiya (oqlaydigan), hisobli rasmiylashtiruvchi, murakkab; - x o ja lik operatsiyalari mazmuni bo ‘yicha moddiy, pulli hisoblash, - aks ettirgan operatsiyalarning hajmi bo'yicha yagona (birlamchi) yoki yig 'ma; -foydalanish usuli bo 'yicha: bir martali va jamlovchi: - hisobga oladigan о 'rinlarining soni bo 'yicha: bir qatorli va ко 'p qatorli; - tuzilish joyi bo 'yicha: ichki va tashqi;
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Texnologiyalari va

Texnologiyalari va
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bet
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#244675
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O`zbekistоn respublikasi - bet 8

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O`zbekistоn respublikasi
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bet | 8/12 | Sana | 30.11.2023 | Hajmi | 94,16 Kb. | | #108725 |
- to ‘Idirish usuli bo ‘yicha: qo ‘Idi, hisobni avtomatlashtirish vositalari yordamida. Buxgalteriya hisobining dasturiy ta ’minlanishiga to'liq asosda bir qator axborotli ma'liimotli dasturlar: «Maslahatchi hisobchi», «Maslahatchi-plyus», «Kafolat», «O'zbekiston soliqlari», «Yuridik m a ’lumotnoma»ni kiritish mumkin. Axborotlarni to ‘Idirish huquqiy axborotlarni tarqatishning umumdavlat tarmog'i bo ‘yicha bajariladi. Buxgalteriya vazifalarini yechishni AAT lar asosida tashkil qilish: birlamchi buxgalteriya hujjatlarini tuzish paytidan boshlab yakuniy moliyaviy hisobotni tuzish bilan yakunlanuvchi operatsiyalarning yig 'indisidir. Hozirgi bosqichda buxgalteriya vazifalarini axborot texnologiyasi asosida markazlashtirilgan holda ishlab chiqish asosiy rol о ‘ynaydi: - foydalamtvchining ish joyida о 'rnatilgan kompyuterlarni qo ‘llash, bu yerda vazifalarni yechish hisobchi tomonidan bevosita uning ish joyida bajariladi; korxonaning turli xildagi bo ‘linmalari iqtisodiy vazifalarini integratsiyalangan holda ishlab chiqilishini ta ’minlovchi mahalliy va ко p bosqichli hisoblash tarmoqlarini shakllantirish: - hisoblash texnikasida bajariladigan buxgalteriya hisoblar tarkibini ancha - - to ‘Idirish usuli bo ‘yicha: qo ‘Idi, hisobni avtomatlashtirish vositalari yordamida. Buxgalteriya hisobining dasturiy ta ’minlanishiga to'liq asosda bir qator axborotli ma'liimotli dasturlar: «Maslahatchi hisobchi», «Maslahatchi-plyus», «Kafolat», «O'zbekiston soliqlari», «Yuridik m a ’lumotnoma»ni kiritish mumkin. Axborotlarni to ‘Idirish huquqiy axborotlarni tarqatishning umumdavlat tarmog'i bo ‘yicha bajariladi. Buxgalteriya vazifalarini yechishni AAT lar asosida tashkil qilish: birlamchi buxgalteriya hujjatlarini tuzish paytidan boshlab yakuniy moliyaviy hisobotni tuzish bilan yakunlanuvchi operatsiyalarning yig 'indisidir. Hozirgi bosqichda buxgalteriya vazifalarini axborot texnologiyasi asosida markazlashtirilgan holda ishlab chiqish asosiy rol о ‘ynaydi: - foydalamtvchining ish joyida о 'rnatilgan kompyuterlarni qo ‘llash, bu yerda vazifalarni yechish hisobchi tomonidan bevosita uning ish joyida bajariladi; korxonaning turli xildagi bo ‘linmalari iqtisodiy vazifalarini integratsiyalangan holda ishlab chiqilishini ta ’minlovchi mahalliy va ко p bosqichli hisoblash tarmoqlarini shakllantirish: - hisoblash texnikasida bajariladigan buxgalteriya hisoblar tarkibini ancha
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Windows. Moslikni o’rnating

A1=5, B1=6 ikkita katakcha birlashtirilib pastki qora nuqtasidan BA1 katakgacha tortildi. BA1 katakdagi qiymatni toping. 51USB 2.0 standard USB 1.1 standartidan 40 barobar tez ishlaydimi Ha Hisoblang. 213(8) + 1001111(2) * 9(16) – 21C(16) = (10) 310Hisoblang. 5050(8)Python. (0.0 1.0) oraliqdagi tasodifiy sonlarni topish operatori ko’rsating Random natija rost bo’ladigan eng katta qiymatni toping. 44{1,2,3,5,6,9,10,11,12,13,14} |
Windows. Moslikni o’rnating
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bet | 4/6 | Sana | 22.06.2024 | Hajmi | 0,81 Mb. | | #265080 |
Bog'liq Attestatsiya savol-javoblari toshkent shahriBu sahifa navigatsiya:
- A1=5, B1=6 ikkita katakcha birlashtirilib pastki qora nuqtasidan BA1 katakgacha tortildi. BA1 katakdagi qiymatni toping. 51
- USB 2.0 standard USB 1.1 standartidan 40 barobar tez ishlaydimi Ha Hisoblang. 213(8) + 1001111(2) * 9(16) – 21C(16) = (10) 310
- Hisoblang. 5050(8)
- Python. (0.0 1.0) oraliqdagi tasodifiy sonlarni topish operatori ko’rsating Random natija rost bo’ladigan eng katta qiymatni toping. 44
- {1,2,3,5,6,9,10,11,12,13,14}
Windows. Moslikni o’rnating.
1-d, 2-f, 3-a, 4-e, 5-b, 6-c
O’zbekiston Respublikasi bayrog’idagi ranglarni kodlash uchun r=2 rang chuqurligi (kod uzunligi) zarur bo’ladi. HA
ifodaning rostlik jadvalidagi sonlar yig'indisi nechiga teng? 41
A1=5, B1=6 ikkita katakcha birlashtirilib pastki qora nuqtasidan BA1 katakgacha tortildi. BA1 katakdagi qiymatni toping. 51
Audiofayl yozilish jarayonida kodning uzunligi 32 bitga, bir sekunddagi chastota esa 32000 Hz ga teng. Audiofaylning davomiyligi 5 minutga teng bo‘lsa, audiofayl hajmini (kbayt) hisoblang. 37500
USB 2.0 standard USB 1.1 standartidan 40 barobar tez ishlaydimi? Ha
Hisoblang. 213(8) + 1001111(2) * 9(16) – 21C(16) = ?(10) 310
Hisoblang. Javobni o’nlik sanoq sistemasida yozing. 11(16) – 111(8) + 1110111(2) = ?(10) 63
Hisoblang. 7E6(16) = ?(10) 2022
Hisoblang. 5050(8) = ?(2) 101000101000
MS Excel. A1=6, A2=-8, B1=-16, B2=4, C1=Informatika, C2=Universitet, berilgan. Agar D1 katakni D2 katakka nusxalansa, D1 va D2 kataklarida hosil bo’ladigan sonlar yig’indisini ikkilanganini toping. 72
MS Ехсе1. A1=1, A2=-9, B1=-12, B2=14, C1=Informatika, C2=Universitet, berilgan. Agar D1 katakni D2 katakka nusxalansa, D1 va D2 kataklarda hosil bo’ladigan sonlar yig’indisini toping. 33
Python. (0.0 1.0) oraliqdagi tasodifiy sonlarni topish operatori ko’rsating? Random
natija rost bo’ladigan eng katta qiymatni toping. 44
MS Excel. A1=64, B1=128, C1=4, A2=256, B2=320, C2=Avtomexanik berilgan bo’lsa, formula qiymatini toping. vtom
Python. Dastur natijasini aniqlang.
a = {1,2,3,5,6,9}
b = {10,11,12,13,14}
c=a.union(b)
print(c)
{1,2,3,5,6,9,10,11,12,13,14}
Python. Dastur natijasini aniqlang.
a = {1,2,3,5,6,9}
a.pop()
print(a)
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- misol - Texnologiyalari va

10
holatga o‘tishi mumkin. Ta’kidlash kerakki, yuqoridagi holatlarning ixtiyoriysidan
boshqa birortasiga bevosita yoki bilvosita o‘tish imkoniyati mavjud bo‘lmasligi ham
mumkin. Sistemaning bir holatdan boshqa holatga bevosita o‘tishlari to‘plamini bilan
belgilaymiz. Natijada hosil bo‘lgan juftlikni graf deb qarash mumkin. Bu grafning
uchlari sistema holatlariga, yoylari (qirralari) esa, bevosita o‘tishlarga mos keladi.
Berilgan masalani hal qilish uchun grafning yoylaridan tashkil topgan shunday
ketma-ketlik tuzish kerakki, bu ketma-ketlikning birinchi hadi , oxirgi hadi esa
bo‘lsin. Bunday ketma-ketliklardan biri quyida keltirilgan:
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]

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[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
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bet | 2/6 | Sana | 22.06.2024 | Hajmi | 0,81 Mb. | | #265080 |
Bog'liq Attestatsiya savol-javoblari toshkent shahri[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
Quyidagi ko’rinishidagi kvadrat tenglamaning yechimlarini topish algoritmiga mos blok-sxema berilgan. a = 1, b = - 2023, c = 2022 bo’lsa, tenglama yechimini toping.
MS Power Point 2016. Quyidagi uskunalar paneli qaysi menyuga tegishli?
Vid
Lenovo so'zi ASCII jadvali yordamida kodlangan. Ushbu so’zni ikkilik kodini aniqlang.
01011001011011110111010101010100011101010110010001100101
MS Word 2016. Oy, kun, yilni hosil qilish tezkor tugmasini toping? Alt+Shift+D
A and not B or not C mantiqiy ifodaning rostlik jadvalidagi rost qiymatlar yig’indisini aniqlang.
31
MS Excel. B1 katakda qanday formula bor ekanligini aniqlang.
MS Excel. B1 katakda qanday formula bor ekanligini aniqlang.
MS Excel. B1 katakda qanday formula bor ekanligini aniqlang.
Python. i=42 bo’lsa, quyidagilardan qaysi biri to’g’ri natija beradi.
i=42
if (i%2==0):
print('juft son')
else:
print('toq son')
MS Excel. A1=1; A2=ФАКТР(A1); B1=2, B2=ФАКТР(B1) berilgan. A1 katakdan B2 katakgacha belgilab pastki qora nuqtasidan F2 gacha tortildi. F2 katakdagi qiymatni toping. 720
Python. Dastur natijasini toping:
n=[0,1,2,3]
for i in n:
if i<4:
n.append(i+3)
print(n) [0, 1, 2, 3, 3, 4, 5, 6, 6]
Quyidagi mulohaza natijasini aniqlang.
Ali aytdi: Word dasturida CTRL+SHIFT+L markerlangan ro’yxat hosil qiladi.
Vali aytdi: Word dasturida CTRL+SHIFT+D belgilangan matn ostiga ikkita chiziq hosil qiladi. Ali=rost, Vali=rost, Soli=yolg’on
Ota va bolaning yoshlari yig’indisi 38 ga, Ota va Boboning yoshlari yig’indisi 81 ga teng bo’lsa, Bola 10 yoshga to’lganda Bobo necha yoshda bo’ladi. 55
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{2, 3, 5, 6, 9} - Attestatsiya savol-javoblari toshkent shahri

{2, 3, 5, 6, 9}
Python. Dastur natijasini aniqlang.
a = {1,2,3,5,6,9}
a.update([10,11,12])
print(a)
{1, 2, 3, 5, 6, 9, 10, 11, 12}
Quyidagi bulutli texnologiyalardan qaysi birining sig’imi eng ko’p hisoblanadi. Google disk
Qaysi javobda tarmoqning adaptiv xavfsizligi elementi noto’g’ri ko’rsatilgan?
Xavf-xatarlarni yo’q qilish
. . . – foydalanuvchiga tizim tomonidan berilgan huquqlar majmuasidir. Jumlani to’ldiring.
Avtorizatsiya
. . . – foydalanuvchining to‘g‘riligi tekshiriladi va uning asosida tizimda faoliyat olib borishi mumkinligi yoki mumkin emasligi belgilanadi. Jumlani to’ldiring.
Autentifikatsiya
. . . – foydalanuvchini tizimga o‘zini tanitish jarayoni bo’lib, unda mijozning maxsus shaxsiy kartalaridan yoki uning biometrik xususiyatlaridan foydalaniladi. Jumlani to’ldiring.
Identifikatsiya
PhotoShop dasturida CTRL+SHIFT+N tugmasi qanday vazifani bajaradi.
Yangi qatlam yaratish
Access dasturida ma'lumotlarni bo’limi orqali kiritish mumkinmi? Ha
245+164=420 ifoda qaysi sanoq sistemasida bajarilgan? 9
Python. Dastur natijasini aniqlang. a=11 b=24 print(a<<1, b<<2) 22, 96
Pyton. Dastur natijasini aniqlang. a=51 print(a >> 2) 12
Photoshopda tasvir o'lchamini o'zgartirish qaysi menyudan bajariladi. Izobrajeniye
Palitrada 16 rang hamda tomonlari 640x480 piksel bo’lgan tasvir hajmini toping? 150 Kbayt
Python. Dastur natijasini toping: a=[1,2,3,4,5,6,7] a[::-2]=[10,20,30,40] print(a)
[40, 2, 30, 4, 20, 6, 10]
Tasvir 8 ta rang ko‘lamiga ega. Tasvir o‘lchami 10 × 15 sm. Ekran imkoniyati 1 dyuymga 150 ta nuqta (1 dyuym = 2,5 sm). Tasvirning axborot hajmi necha bayt bo‘ladi? 202500
Tasvir 512x640 o’lchamga ega. 8 xil rangda aks etadi. Axborot hajmini toping. 120 Kbayt
84
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ichki uch
yoki 
oraliq uch

ichki uch yoki
oraliq uch deb
ataladi.
Marshrutda qirralar va uchlar takrorlanishi mumkin bo‘lgani uchun marshrutning
ichki uchi, bir vaqtning o‘zida, uning boshlang‘ich va (yoki) oxirgi uchi bo‘lishi ham
mumkin va teskarisi, marshrutning boshlang‘ich va (yoki) oxirgi uchi uning ichki
uchi bo‘lishi ham mumkin.
Tabiiyki, marshrut:
– boshlang‘ich uchga ham oxirgi uchga ham ega bo‘lmasligi mumkin (bunday
marshrut
ikki tomonlama cheksiz marshrut deb ataladi);
– boshlangich uchga ega bo‘lib, oxirgi uchga ega bo‘lmasligi mumkin yoki, aksincha,
oxirgi uchga ega bo‘lib, boshlangich uchga ega bo‘lmasligi mumkin (
bir tomonlama cheksiz marshrut );
– yagona qirradan iborat bo‘lishi mumkin (
notrivial marshrut );
4.
– birorta ham qirraga ega bo‘lmasligi mumkin (
nol marshrut yoki
trivial marshrut ).
15
Grafda arzon marshrutni aniqlash Marshrutning uzunligi deb undagi qirralar soniga aytiladi. Turli qirralardan
tashkiltopgan marshrutga
zanjir deb ataladi. Agar zanjirning chetlaridan
tashqaribarcha uchlari turlicha bo‘lsa, u holda uni
oddiy zanjir deb ataydilar.
Berilgan zanjir yoki oddiy zanjir uchun bo‘lsa, u
yopiq zanjir deb ataladi. Hech
bo‘lmaganda bitta qirraga ega yopiq oddiy zanjir
sikl deb ataladi. Sirtmoq yoki bir
juft karrali qirralar sikl tashkil etishi ravshandir.
Tushunarliki, grafdagi zanjir grafning qism grafi deb qaralishi mumkin.
6- misol. Yuqoridagi 1- shaklda tasvirlangan graf uchun ketma-ketlik 3 belgili
uchdan 4 belgili uchga yo‘nalgan marshrutdir, bunda 3 – boshlang‘ich uch, 4 – oxirgi
uchdir. Bu marshrutda 1, 2 va 3 belgili uchlar oraliq uchlar hisoblanadi. Qaralayotgan
marshrutning uzunligi 6a teng bo‘lib, u zanjir bo‘la olmaydi, chunki unda 1 belgili
uch 2 marta (bir marta oraliq uch sifatida, ikkinchi marta esa oxirgi uch sifatida)
qatnashmoqda.
Yana o‘sha graf uchun zanjirning oxirgi bo‘g‘ini sifatida yoki qirralardan qaysisi
olinishiga bog‘liqsiz ravishda, u yopiq zanjir va sikldir.
Oriyentirlangan graflar uchun ham undagi yoylarning yo‘nalishini
(oriyentatsiyasini) inobatga olmasdan oriyentirlanmagan marshrut, zanjir va oddiy
zanjir tushunchalarini kiritish mumkin. Lekin, oriyentirlangan graflar uchun
oriyentirlangan marshrut tushunchasini kiritish tabiiydir.
Yoylarning oriyentatsiyalari hisobga olingan yoylar va uchlar ketma-ketligi
oriyentirlangan marshrut deb ataladi.
16
Oriyentirlangan marshrut uchun zanjir tushunchasiga o‘xshash
yo‘l (yoki
oriyentirlangan zanjir) tushunchasini ham kiritish mumkin. Boshlang‘ich va oxirgi
uchlari ustma-ust tushadigan oriyentirlangan zanjir kontur deb ataladi.
Tavsiyanoma

Tavsiyanoma
Download
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Hajmi
212,78 Kb.
#266198
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212,78 Kb.
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Tavsiyanoma
Download
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Matnni ko'rish
o
riyentirlangan grafning uchlari qo‘shniligi 
-matritsasi deb elementlari ko‘rinishda aniqlangan (, ) matritsaga aytiladi. 
2- misol

12
3- misol.
1- shaklda tasvirlangan oriyentirlanmagan multigraf uchlari qo‘shniligi
matritsasi quyidagicha bo‘ladi:
Karrali yoylari bo‘lgan
sirtmoqsiz orgraf uchlari qo‘shniligi matritsasi
tushunchasini ham yuqoridagiga o‘xshash ta’riflash mumkin.
Shunday qilib, manfiymas butun sonlardan tashkil topgan va graf uchun uchlari
qo‘shniligi matritsasi bo‘lgan kvadrat matritsa bilan graf orasida bir qiymatli moslik
(izomorflik aniqligida) bor degan xulosa va, bundan, graflar nazariyasi bo‘yicha
izlanishlar maxsus shartlarni qanoatlantiruvchi mat-ritsalarni tadqiq qilishga
keltirilishi mumkinligi kelib chiqadi.
(
) qirralarga ega yakkalangan uchlari, sirtmoq va karrali qirralari bo‘lmagan graf
uchun elementlari
quyidagicha aniqlangan
(, ) -matritsa
grafning qirralari qo‘shniligi
matritsasi
deb ataladi.
4- misol.
1- shaklda tasvirlangan grafda 5ta qirra bo‘lib, uning qirralari qo‘shniligi
matritsasi
ko‘rinishga egadir.
Ravshanki, sirtmoqsiz va karrali qirralarsiz graf qirralari qo‘shniligi matritsasi
bosh diagonalga nisbatan simmetrik kvadrat matritsadir va uning bosh diagonali
nollardan iborat.
Oriyentirlangan graflar uchun insidensiya matritsasi.
Guruh talabasi Abdisalomov - bet 2

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Guruh talabasi Abdisalomov
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bet | 2/3 | Sana | 02.12.2023 | Hajmi | 2,13 Mb. | | #109902 |
Bog'liq 6-amaliy ish Tashuvchi generator, uzluksiz yuqori chastotali tashuvchini yuboradi. Xabar signalining ikkilik ketma-ketligi unipolyar kirishni yuqori (High) yoki past (Low) bo‘lishiga olib keladi. Yuqori signal kalitni yopadi, bu esa tashuvchi to‘lqinga imkon beradi. Demak, chiqish yuqori kirishda tashuvchi signal bo‘ladi. Past (Low) kirish bo‘lsa, kalit ochiladi, bu esa kuchlanish paydo bo‘lishiga imkon bermaydi. Shunday uchun chiqish past (Low) bo‘ladi. Tarmoqni cheklovchi filtr impulsni tarmoqli cheklovchi filtr yoki impulsni shakllantiruvchi filtrning amplitudasi va fazaviy xususiyatlariga qarab shakllantiradi.
TASK
Dastur Kodi:
clc ,close all,clear all;
x= input('Enter digital input information=');
N=length(x);
Foydalanuvchidan kiritilgan raqamli ma'lumotlar x massivida saqlanadi. Massiv uzunligi N hisoblanadi.
Tb=0.0001;
disp('Binary input information at transmitter:');
disp(x);
nb=100;
digit=[];
for n=1:1:N
if x(n)==1;
sig=ones(1,nb);
else x(n)== 0;
sig=zeros(1,nb);
end
digit=[digit sig];
end
Har bir raqam uchun, nb ta nuqta bo'yicha modulyatsiya amaliyoti o'tkaziladi va natijalar digit massiviga qo'shiladi.
t1=Tb/nb:Tb/nb:nb*N*(Tb/nb);
figure('Name','FSK Modulation and Demodulation','NumberTitle','off');
subplot(3,1,1);
plot(t1,digit,'LineWidth',2.5);
grid on;
axis([0 Tb*N -0.5 1.5]);
xlabel('Time(sec)')
ylabel('Ampilitude(Volts)')
title('Digital input signal');
Ac=10;
br=1/Tb;
Fc1=br*5;
Fc2=br*3.2;
t2=Tb/nb:Tb/nb:Tb;
mod=[];
for i=1:1:N
if x(i)==1
y=Ac*sin(2*pi*Fc1*t2);
else
y=Ac*sin(2*pi*Fc2*t2);
end
mod=[mod y];
end
Har bir raqam uchun, FSK modulyatsiyasi o'tkaziladi va natijalar mod massiviga qo'shiladi.
t3=Tb/nb:Tb/nb:Tb*N;
subplot(3,1,2);
plot(t3,mod);
xlabel('Time(sec)');
ylabel('Ampilitude(Volts)');
title('FSK Moduleted signal');
x =mod;
h=1;
w=0;
y= h.*x+w;
s=length(t2);
demod=[];
for n=s:s:length(y)
t4=Tb/nb:Tb/nb:Tb;
c1=sin(2*pi*Fc1*t4);
c2=sin(2*pi*Fc2*t4);
mc1=c1.*y((n-(s-1)):n);
mc2=c2.*y((n-(s-1)):n);
t5=Tb/nb:Tb/nb:Tb;
z1 = trapz(t5,mc1);
z2 = trapz(t5,mc2);
rz1=round(2*z1/Tb);
rz2=round(2*z2/Tb);
if(rz1>Ac/2)
a=1;
else(rz2>Ac/2)
a=0;
end
demod=[demod a];
end
FSK demodulyatsiyasi o'tkaziladi va natijalar demod massiviga qo'shiladi.
disp('Demodulated binary information at Receiver');
disp(demod);
digit=[];
for n=1:length(demod);
if demod(n)==1;
sig=ones(1,nb);
else demod(n)==0;
sig =zeros(1,nb);
end
digit=[digit sig];
end
t5=Tb/nb:Tb/nb:nb*length(demod)*(Tb/nb);
subplot(3,1,3);
plot(t5,digit,'LineWidth',2.5);
grid on;
axis([0 Tb*length(demod) -0.5,1.5]);
xlabel('Time(sec)');
ylabel('Ampilitude(Volts)');
title('FSK demodulate signal');
Demodulyatsiya natijalari ekranga chiqariladi. Natijalarni ko'rish uchun disp va plot komandalari ishlatiladi.
A
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Parametrlari - 3-Mavzu: Isitish to‘g‘risida umumiy ma’lumotlar. Issiqlik tashuvchilar

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3-Mavzu: Isitish to‘g‘risida umumiy ma’lumotlar. Issiqlik tashuvchilar
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bet | 3/3 | Sana | 06.12.2023 | Hajmi | 162,71 Kb. | | #112224 |
Bog'liq Mavzu —3Parametrlari
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Issiqlik tashuvchi
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suv
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bug‘
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havo
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Temperaturalar farqi oS
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150-70
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150
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70-40
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Zichligi, kg/m3
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950
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2,547
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1
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Solishtirma issiqlik sig‘imi, kDj (kg·k)
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4,187
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2120
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1
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Harakatlanish tezligi, m/s
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0,3-2
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40-80
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5-20
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Quvurlarning ko‘ndalang kesim nisbati
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1
|
1,5
|
550
|
Isitish asboblari isitish tizimining asosiy elementlari bo‘lib, aniq bir teplotexnik, sanitariya-gigienik, texnika-iqtisodiy, arxitektura-qurilish va montaj talablariga javob berishi kerak.
Teplotexnik talablardan asosiysi-isitish asbobi isituvchi xonaga issiqlik tashuvchidan issiqlikni yaxshi uzatuvchi, hozirgi zamonaviy isitish asboblarining issiqlik uzatish koeffitsienti iloji boricha yuqori, ya’ni 9-10 [Vt/m2oS] dan kam bo‘lmasligi kerak.
Sanitariya-gigienik talablar: isitish asboblariga qo‘yilgan talablar mundan iboratki, ularning konstruksiyasi va yuzasining tuzilishi chang yig‘ilishiga yo‘l qo‘ymasligini va yuzasining ularni ozon tuzalishi mumkin bo‘lgan talablardir.
Texniko-iqtisodiy talablar quyidagilar: zavodda orzon narxga ishlab chiqarish; minimal metall sarfli, asbobning konstruksiyasi texnologiya va seriyasi ishlab chiqarish talablariga javob berishi, bo‘lmali, isitish asbobini yuzasini talab etilgan darajasiga yig‘ish mumkinligi.
Arxitektura qurilish talablari isitish asboblari o‘rnatiladigan yuzalarni qisqartirish va ularni tashqi ko‘rinishini chiroyli bo‘lishi kerak. Bunday talablarni bajariy uchun isitish asboblari ixcham, kurish va changdan tozalash uchun qulay joyda o‘rnatilishi, xona intereri bilan uyg‘unlashishi kerak.
Montaj talablari: eng avvalo isitish asboblarini yasash va montaj ishlarini bajarishda ish samaradorligini oshirishga erishish kerak. Isitish asbobning konstruksiyasi montaj jarayonida qulay va yaxshi avtomatlash tiriladigan bo‘lishi lozim. Asboblar mustahkam, montaj qilish va tashishda qulay va ularning devorlari bug‘ va suv o‘tkazmaydigan va temperaturaga chidamli bo‘lishi kerak.
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O‘zbekiston respublikasi axborot texnologiyalari va kommunikatsiyalarini rivojlantirish vazirligi muhammad al-xorazmiy nomidagi toshkent axborot texnologiyalari universiteti qarshi filiali

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O‘zbekiston respublikasi axborot texnologiyalari va kommunikatsiyalarini rivojlantirish vazirligi muhammad al-xorazmiy nomidagi toshkent axborot texnologiyalari universiteti qarshi filiali
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bet | 1/8 | Sana | 05.01.2024 | Hajmi | 23,78 Kb. | | #130921 |
Bog'liq 3-amaliy ish Mavzu jquery selektorlar,hodisalar. Jquery ui-fayllar.org
3-amaliy ish Mavzu: jquery selektorlar,hodisalar. Jquery ui
O‘ZBEKISTON RESPUBLIKASI AXBOROT TEXNOLOGIYALARI VA
KOMMUNIKATSIYALARINI RIVOJLANTIRISH VAZIRLIGI
MUHAMMAD AL-XORAZMIY NOMIDAGI
TOSHKENT AXBOROT TEXNOLOGIYALARI UNIVERSITETI
QARSHI FILIALI
Web dasturlashga kirish
Mavzu: JQuery selektorlar,hodisalar.JQUERY UI.
Topshirdi: Abdimo’minov.A
Qabul qildi: Andaqulov.Sh
3-amaliy ish
Mavzu: JQuery selektorlar,hodisalar.JQUERY UI.
Qisqacha nazariy ma’lumot:
JavaScript tili hozirgi kunda eng mashhur tillardan biri hisoblanadi. Ko’p reytinglarda mashhurligi bo’yicha birinchi o’rinda turadi. Ushbu til orqali o’yin yaratishingiz, veb-dasturlar yozishingiz, mobil ilovalar, kompyuter uchun dasturlar, hullas har qanaqa turdagi dasturlar yozishingiz mumkin. Brauzerlarda esa JavaScript asosiy dasturlash tili hisoblanadi.
Lekin, eng mashhur til degani – eng qulay til degani emas. JavaScript’da biror bir qiyinroq dastur yaratimoqchi bo’lsangiz – albatta kutubxona, yoki freymvorklardan foydalanasiz.
Kutubxona va freymvork bu oldindan yozib qo’yilgan kodlar to’plami. Ularning farqini bilish hozircha muhim emas.
Biz jQuery ishlatamiz. Ancha eski kutubxona, lekin paydo bo’lganda butun veb-dasturlarni revolyutsiyaga olib kelgan – kuchli kutubxona. Hozir kichik narsalar yozish uchun ishlatiladi.
Lekin agar frontend dasturchisi bo’lish niyatingiz bo’lsa: Vuejs, Angular yoki React kabi kutubxonalardan birini o’rganishni maslaxat beraman. Keyinroq Vuejs haqida ham darslik chiqaraman.
Amaliy qism:
JavaScript va jQuery ni tushunish uchun kalkulyator yaratib ko’ramiz.
+
=
0
Buning uchun bir nechta formalar yarataylik.
Tugmachamiz fonini sabzi rangga bo’yaylik, matnini – oq. Ramka stili esa outset, yani bo’silmagan shaklda deb belgiladik. Sababi, ushbu tugmachani bosganimizda, JavaScript orqali ushbu ramka stilini “inset”ga o’zgartirsak, chiroyli – bosilish effekti paydo bo’ladi.
input, button {
outline: none;
}
formalarimizga bosganimizda element atrofida qo’shimcha chiziq paydo bo’lmoqda. Buni olib tashlash uchun, input va button elementlarimizning outline xususiyatlariga none (nan deb o’qiladi) qiymatini beramiz.
Tugmachaga bosib ko’rsak hech narsa o’zgarayotgani yo’q. Birinchi vazifamiz ushbu tugmacha bosilganda uning ramka stilini o’zgartirish.
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Bosh sahifa
Aloqalar
Bosh sahifa
O‘zbekiston respublikasi axborot texnologiyalari va kommunikatsiyalarini rivojlantirish vazirligi muhammad al-xorazmiy nomidagi toshkent axborot texnologiyalari universiteti qarshi filiali
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Graflarning berilish usullari

11
yoki . Berilgan orgrafda sirtmoq ham, karrali yoylar ham yo‘q.
Bu grafning yoyi uchun 1 boshlang‘ich, 3 uch esa oxirgi uchdir.
Qo‘shnilik matritsalari.
Endi grafning boshqa bir berilish usuli negizida yotuvchi graf uchlari qo‘shniligi
matritsasi tushunchasini qarab chiqamiz.
– uchlari soni ga teng bo‘lgan belgilangan, sirtmoqsiz va karrali qirralarsiz graf
bo‘lsin.
Elementlari
ko‘rinishda aniqlangan (; ) matritsani grafning uchlari qo‘shniligi matritsasi deb
ataymiz.
Bu ta’rifdan sirtmoqsiz va karrali qirralari bo‘lmagan graf uchlari qo‘shniligi
matritsasining bosh diagonalida faqat nollar bo‘lishi, satrlaridagi birlar soni esa mos
uchlarning darajalariga tengligi kelib chiqadi.
1- misol.
1- shaklda tasvirlangan grafgning uchlari qo‘shniligi matritsasi
ko‘rinishda bo‘ladi.
Uchlari soni ga teng bo‘lgan belgilangan
Guruh talabasi Abdisalomov - bet 3

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Guruh talabasi Abdisalomov
|
bet | 3/3 | Sana | 02.12.2023 | Hajmi | 2,13 Mb. | | #109902 |
Bog'liq 6-amaliy ish
B
D
I
S A
L
O
M
O
V
XULOSA
Kod ikkilik sanoq ma'lumotlarini olish va raqamli signalni shakllantirish bilan boshlanadi. Raqamli signal ikki xil amplituda va tashuvchi chastotasi bilan Amplitude Shift Anahtaring (ASK) yordamida modulyatsiya qilinadi.
Keyin modulyatsiyalangan signal taqqoslash yordamida demodulyatsiya qilinadi.
Natijalar ko'rsatiladi va taqqoslash uchun dastlabki raqamli signal va demodulyatsiya qilingan signal chiziladi.
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Isitish tiziming prinsipial sxemasi

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Isitish tiziming prinsipial sxemasi
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bet | 2/3 | Sana | 06.12.2023 | Hajmi | 162,71 Kb. | | #112224 |
Bog'liq Mavzu —3Isitish tiziming prinsipial sxemasi
1-issiqlik almashtirgich (issiqlik generatori); 2-birlamchi issiqlik tashuvchisini uzatilishi (yoqilg‘ini); 3-uzatuvchi magistral quvurlar; 4-isitish asbobi; 5-qaytuvchi magistral quvurlar.
Isitish tizimlari quyidagi turkumlarga bo‘linadi:
Asosiy elementlarning o‘zaro joylashishi bo‘yicha mahaliy va markaziy.
Issiqlik eltuvchining turiga qarab: suv va bug‘, havoli isitish tizimlari mavjud.
Issiqlik eltuvchining harakatlanish usuliga qarab: markaziy, mahaliy, suv va havo bilan tabiiy (issiq va sovuq, suv zichliklarining farqi hisobiga harakatlanuvchi), sun’iy nasosni ishlashi natijasida suvning majburiy harakatlanishi ta’minlanadi.
Issiqlik tashuvchining markazlashgan issiq suv va bug‘ yordamida isitish tizimlari. 100oS gacha isitilgan past temperaturali, 100oS dan yuqori isitilgan, yuqori temperaturali, past bosimli (R=0.1-0.17MPa), yuqori bosimli (R=0.17-0.3MPa) – bug‘li isitish tizimlari bo‘lishi mumkin.
Isitish tizimida issiqlik tashuvchi sifatida, issiqlik energiyasini yaxshi akkumulyatsiya qila oladigan va teplotexnik xususiyatlarini o‘zgartira oladigan, harakatlanuvchi, arzon xonadagi sanitariya holatini yomonlashtirmaydigan, uzatiladigan issiqlikni sozlash xususiyatiga ega bo‘lgan har qanday muhit bo‘la oladi. Undan tashqari, issiqlik tashuvchi isitish tizimidagi talablarga javob beradigan bo‘lishi kerak.
Yuqorida aytilganidek, isitish tizimida issiqlik tashuvchi sifatida suv, suv bug‘lari va havo ishlatiladi.
Isitish tizimining konstruksiyasiga va ishlashiga ta’sir ko‘rsatadigan issiqlik tashuvchilarning asosiy fizik xususityalari 1.2-jadvalda keltirilgan.
Isitish tizimidagi issiqlik tashuvchilarning asosiy xususiyatlari
1.2-jadval
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Step 4: Evaluate RemoteFX User Experience

To verify that RemoteFX is properly installed and configured and to evaluate the RemoteFX user experience, perform the following steps:
Start the virtual machine running Windows 7 SP1.
Win7-01 enable remote
Establish a Remote Desktop session with Windows 7 SP1 by using the Remote Desktop Connection client in Windows Server 2008 R2 SP1 with the following options enabled:
On the Experience tab, in Performance section, select LAN (10Mbps or higher) and verify that all the check boxes are selected, as shown in the following figure:
Step 2: Install and Configure Windows 7 SP1 in a Virtual Machine

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Step 2: Install and Configure Windows 7 SP1 in a Virtual Machine
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bet | 3/12 | Sana | 03.10.2020 | Hajmi | 8,08 Mb. | | #11998 |
Step 2: Install and Configure Windows 7 SP1 in a Virtual Machine
Windows 7 SP1 is installed on a virtual machine running in Hyper-V by performing the following steps:
Install Windows 7 SP1 using the default installation options.
Enable Remote Desktop connections for the account you will use to log on to Windows 7 SP1.
For more information about enabling Remote Desktop connections in Windows 7, see “What types of Remote Desktop connections should I allow?” in Windows 7 Help.
Verify that you can connect to Windows 7 SP1 by using the Remote Desktop Connection client in Windows Server 2008 R2 SP1.
Shutdown the Windows 7 virtual machine.
Step 3: Enable RemoteFX 3D Video Adapter Support on Windows 7 Virtual Machine
The RemoteFX 3D Video Adapter Support must be added to the Windows 7 virtual machine by performing the following steps on the computer running Windows Server 2008 R2 SP1:
Start Hyper-V Manager.
In Hyper-V Manager, select the Windows 7 virtual machine and in the Actions pane click Settings.
In the navigation pane, under the Hardware section, click Add Hardware.
Add the adapter; start the virtual machine; verify that the adapter is installed and then restart the machine.
In the properties pane, click RemoteFX 3D Video Adapter, and then click Add.
The RemoteFX 3D Video Adapter appears in the list of hardware in the Hardware section as show in the following figure.
Start the virtual machine; verify that you can login and that you have loaded the driver. The VM will ask to be restarted at this point, perform the restart.
Figure 2: RemoteFX 3D Video Adapter in virtual machine settings
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HTML da matn ustiga chiziq chizish teglari to’g’ri keltirilgan qatorni ko’rsating

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HTML da matn ustiga chiziq chizish teglari to’g’ri keltirilgan qatorni ko’rsating
|
bet | 3/6 | Sana | 22.06.2024 | Hajmi | 0,81 Mb. | | #265080 |
Bog'liq Attestatsiya savol-javoblari toshkent shahriHTML da matn ustiga chiziq chizish teglari to’g’ri keltirilgan qatorni ko’rsating.
yoki
MS Excel. A1 katakchada quyidagi formula kiritilganda qanday natija hosil bo’ladi. JAVOB:
Klaviaturalar kompyuterga ulanishiga ko‘ra qanday turlarga bo‘linadi.
simli va simsiz
PhotoShop dasturida paneli qanday vazifani bajaradi.
tasvirni oldingi holatiga qaytish
Fayl nomi to’g’ri yozilgan qatorni toping. $informatika&
Python dasturida berilgan kod natijasini aniqlang.
a=int(input('a= '))
s=0
for i in range(1, a+1):
if a%i==0:
s=s+i
print(s)
a soning natural bo'luvchilari yig'indisini topish dasturi.
PowePoint 2016. Ushbu rasmda keltirilgan buyruqlar qaysi menyuda joylashgan.
Vid
MS Excel. A1=-2, A2=2, A3=1, A4=3, A5=-4, A6=6 berilgan. Quyidagi funksiya natijasini aniqlang. JAVOB
Ali bilan Vali oliygohni ancha yillar oldin tugatishib, bir kuni uchrashib qolishibdi. Ali Validan so‘radi: "farzandlaring nechta", Vali aytdi "3 ta o‘g‘il", Ali so‘radi: "yoshlari nechida" Vali javob berdi: "uchalasining yoshlarining ko‘paytmasi 36 ga teng", Ali aytdi "Axborot kam!", Vali aytdi: uchalasining yoshining yig‘indisi anavu avtobus raqamiga teng, Ali aytdi: "Axborot kam!", Vali aytdi: "kichik o‘g‘lim dasturlashga qiziqadi". Shundan keyin Ali Valining barcha o‘g‘illari yoshini aytib berdi. Valining kata o’g’li yoshini toping? 9
Ali 3-chorakda baholarni oldi. O’qituvchi Aliga baholarni o’rtachasini 3 lik sanoq sistemasida baholadi. Ali necha baho olgan. 11
Python. Dastur natijasini aniqlang.
def f(n):
if n<=3:
return 2
return 3*f(n-2)-f(n-3)
print(f(9)) 14
Ali, Vali va Soli imtihonda 3 xil ball olishdi. Quyidagi mulohazalarning faqat bittasi rost: Ali 3 ball olgan, Vali 5 ball olgan, Soli 4 ball olmagan. Agar Soli 3 ball olmagani ma’lum bo’lsa, u holda o’quvchilar olgan ballarni aniqlang. Ali – 4, Vali – 3, Soli – 5.
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Enhanced Support for Digital Audio and Video

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Enhanced Support for Digital Audio and Video
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bet | 9/16 | Sana | 30.03.2021 | Hajmi | 321,5 Kb. | | #13772 |
Enhanced Support for Digital Audio and Video
Windows XP builds on the digital audio and video capabilities of prior versions of Windows by supporting new devices and technologies and providing additional playback and storage options for digital media.
Digital Audio Devices and Technologies
To support digital audio devices, Windows XP—like Windows 2000 before it—uses the Windows Driver Model (WDM) audio architecture, which enables the operating system to manage multiple audio streams simultaneously. And like both Windows 2000 and Windows Me, Windows XP also supports the Audio Codec ’97 (AC ’97) specification for digital audio, which defines a widely adopted audio architecture. Further, Windows XP supports digital audio on several bus types, including PCI, ISA, and Personal Computer Memory Card International Association (PCMCIA) buses, and on external USB and IEEE 1394 digital audio devices.
Windows XP includes several new technologies designed to enhance digital audio playback and recording, such as:
Multichannel audio output and playback of additional audio formats. Volume can be set for each speaker in a multichannel configuration.
Acoustic Echo Cancellation (AEC), a signal processing feature that reduces feedback, echo, and other ambient noise from an input channel. USB microphones in particular benefit from this technology.
Global Effects (GFX), which enhances USB audio support by allowing filter drivers to support devices such as USB array microphones.
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WIA applications - Published: June 2001

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Published: June 2001
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bet | 7/16 | Sana | 30.03.2021 | Hajmi | 321,5 Kb. | | #13772 |
WIA applications. You can initiate image acquisition and manipulate images by using either the Scanner and Camera Wizard or a separate application. There are two main types of WIA applications: image editing applications, such as Adobe PhotoShop and Microsoft Picture It!®; and applications for authoring documents that include image data, but cannot edit image data, such as Microsoft Word and the Microsoft PowerPoint® presentation graphics program.
Class Installer. The Imaging Class Installer is a WIA component used by Windows Plug and Play to support easy installation and removal of WIA devices. The installer also supports Plug and Play devices for USB, SCSI, IEEE 1394 buses, and serial-based digital still cameras.
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Windows Image Acquisition Architecture

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Windows Image Acquisition Architecture
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bet | 5/16 | Sana | 30.03.2021 | Hajmi | 321,5 Kb. | | #13772 |
WIA architecture is both an application programming interface (API) and a Device Driver Interface (DDI). The WIA architecture includes components provided by the software and hardware vendor, as well as by Microsoft. Figure 1 below illustrates the WIA architecture.
F igure 1. The components of WIA architecture.
The main WIA architectural components are described in further detail below.
Scanner and Camera Wizard. Using the Scanner and Camera Wizard, you can retrieve images from any of the WIA-enabled devices installed on the system. The wizard provides a preview page where you can select from several scanning options and adjust image settings. It is launched by default when WIA-enabled scanners are activated (a “scan event”) and when Plug and Play still digital cameras are connected (a “connect event”). It can also be launched when media such as flash memory cards or CD-ROMs containing image files are inserted into the computer (a “media-insertion event”). Note, however, that the wizard is not launched by default for video cameras.
F igure 2. Choose your scanning options using the Scanner and Camera Wizard.
Windows XP also gives you the option of launching a preferred imaging application for these events—rather than using the wizard by default—provided that the application is WIA-enabled.
Using the wizard for a digital still camera, you can select one or more pictures, rotate them, and view information such as picture size and resolution. With a video camera, you can select previously captured still images, rotate them, view picture information, and even see live video and capture still images. You can also name the pictures, save them in the My Pictures folder, categorize pictures by using subfolders, and publish them on the Web. For non–Plug and Play devices, you can start the wizard from the Accessories menu.
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Scripting interface - Published: June 2001

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Published: June 2001
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bet | 8/16 | Sana | 30.03.2021 | Hajmi | 321,5 Kb. | | #13772 |
Scripting interface. WIA includes a scripting interface, which allows advanced users and IT professionals to develop WIA applications using the Microsoft Visual Basic® development system and other scripting languages.
TWAIN Data Source Manager and compatibility driver. The TWAIN Data Source Manager (DSM) is an industry-standard software library used to abstract TWAIN applications from still image devices. WIA uses the TWAIN DSM implementation in Windows XP together with the TWAIN compatibility driver to provide a compatibility layer for applications that support TWAIN version 1.7 or later, but don’t yet support WIA.
Common system dialog objects. All scanner and camera device drivers that ship in Windows XP use the WIA common system dialog objects. There are four system dialog objects: the scanner common dialog object, the still camera common dialog object, the video camera common dialog object, and the device selection dialog object. Represented in the UI as dialog boxes, these allow you to preview thumbnails and full-sized pictures; crop, scan, and set scan properties of a picture; view picture information; view live or recorded digital video and capture frames from the stream; select WIA devices; and set WIA device properties.
Device object. When the WIA device driver is started, it creates a system component called the device object. There are four types of device objects: WIA mini driver, WIA generic flatbed scanner, WIA generic digital still camera (based on the industry-standard Picture Transfer Protocol [PTP]), and WIA generic video camera object.
WIA Device Manager. When an application first communicates with a device, the WIA Device Manager detects all the devices, creates the device objects, establishes the link between the application and the device object, and retrieves and sets device properties.
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Conclusion - Published: June 2001

Conclusion
One of the chief goals for this version of Windows has been to provide you with the best possible experience in installing and using devices. An important part of this is the extensive driver coverage in Windows XP. Hundreds of tested and signed drivers come with the operating system, and many more will be available online through Windows Update for convenient, automatic installation on your computer.
Not only are there more and better drivers, but Windows XP supports many new devices and device classes, including wireless network adapters; USB array microphones; expanded PS/2 and USB interface keyboards, which have additional keys for multimedia functions, Web browsing, power management, and/or other functions; and high-resolution monitors built to display up to 200 dots per inch.
This article has covered just some of the features and technologies of Windows XP that improve the management of devices and hardware, both new and legacy. From Windows Me, Windows XP derives WIA, which makes it easier to work with digital still image devices. Moreover, it improves digital audio and video playback and recording; CD mastering can now be done efficiently and conveniently with technologies native to Windows. Dualview provides additional monitor configuration options beyond the multiple monitor options available in previous versions of Windows. And finally, Windows XP derives from Windows 2000 its support for ACPI, which enables advanced power management of hardware and devices.
Note: For a comprehensive discussion of device management in Windows XP, please refer to the relevant chapter in the forthcoming Windows XP Professional Resource Kit.
Related Links
Windows Driver and Hardware Development
http://www.microsoft.com/hwdev/
Windows Update
http://windowsupdate.microsoft.com
Windows Hardware Compatibility List
http://www.microsoft.com/hcl/default.asp
For the latest information on Windows XP, check out our Web site at http://www.microsoft.com/windowsxp.
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Windows Explorer user interface (UI)

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Windows Explorer user interface (UI)
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bet | 6/16 | Sana | 30.03.2021 | Hajmi | 321,5 Kb. | | #13772 |
Windows Explorer user interface (UI). Windows Explorer extensions such as My Computer and My Pictures, in addition to Scanners and Cameras in Control Panel, provide an interface with which you can access WIA devices. For example, an icon for each installed WIA device appears in the My Computer directory. Clicking the camera icon opens an interface that shows thumbnail pictures, controls for saving pictures, and a live preview that you can capture if the camera is a supported webcam or DV camcorder. The My Pictures folder includes thumbnails of images, a link to the WIA Scanner and Camera Wizard, a built-in slideshow, an enhanced image preview window, and the option to print pictures from the preview window. It also provides the option of e-mailing a picture, ordering prints over the Internet, posting pictures to a Web site, and saving pictures to CD-R and CD-R/W media (see below for further discussion of Windows XP CD mastering technologies).
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1 -mavzu: axborot texnologiyalari haqida tushuncha. Texnоlogiya haqida umumiy tushuncha

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1 -mavzu: axborot texnologiyalari haqida tushuncha. Texnоlogiya haqida umumiy tushuncha
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bet | 1/6 | Sana | 06.09.2024 | Hajmi | 1,98 Mb. | | #270469 |
Bog'liq 1-Mavzu
1 -Mavzu: AXBOROT TEXNOLOGIYALARI HAQIDA TUSHUNCHA.
1.Texnоlogiya haqida umumiy tushuncha.
2.Axborot texnologiyalari va uning bosqichlari, ichki va tashqi omillari
3.Axborot texnologiyalarining turlari.
4. Axborot texnologiyalarining texnik vositalari
Texnоlogiya haqida umumiy tushuncha.
Tеxnologiya so’zi grеkchadan tarjima qilinganda san'at, ustalik, malaka ma'nosini anglatadi. Tеxnikada tеxnologiya dеganda ma'lum kеrakli matеrial mahsulotni hosil qilish uchun usullar, mеtodlar va vositalar yig’indisidan foydalanadigan jarayon tushuniladi. Tеxnologiya ob'еktining dastlabki, boshlang’ich holatini o’zgartirib, yangi, oldindan bеlgilangan talabga javob bеradigan holatga kеltiradi. Misol uchun sutdan turli tеxnologiyalar orqali qatiq, tvorog, smеtana, yog’ va boshqa sut mahsulotlarini olish mumkin. Agar boshlang’ich xom ashyo sifatida axborot olinsa, ushbu axborotga ishlov bеrish natijasida axborot mahsulotinigina olish mumkin. Ushbu holda ham «tеxnologiya» tushunchasining ma'nosi saqlanib qolinadi. Faqat unga «axborot» so’zini qo’shish mumkin. Bu narsa axborotni qayta ishlash natijasida moddiy mahsulotni emas, balki axborotnigina olish mumkinligini aniqlab turadi.
Tеxnologiyani quyidagicha ta'riflash mumkin. Tеxnologiya — bu sun'iy ob'еktlarni yaratishga yo’naltirilgan jarayonlarni boshqarishdir. Kеrakli jarayonlarni kеrakli yo’nalishda borishini ta'minlash uchun yaratilgan shart-sharoitlar qanchalik yaxshi tashkil etilganligi tеxnologiyaning samaradorligini bildiradi. Bu еrda tabiiy jarayonlar nafaqat moddaning tarkibi, to’zilishi va shaklini o’zgartirish maqsadida, balki axborotni qayta ishlash va yangi axborot hosil qilish maqsadida ham boshqariladi. Shuning uchun axborot tеxnologiyasini quyidagicha ta'riflash mumkin.
Axborot tеxnologiyasi — bu axboriy ma'lumotni bir ko’rinishdan ikkinchi, sifat jihatidan yangi ko’rinishga kеltirish, axborotni yig’ish, qayta ishlash va O’zatishning usul va vositalari majmuasidan foydalanish jarayonidir.
Moddiy ishlab chiqarish tеxnologiyasining maqsadi insonning talabini qondiradigan yangi mahsulot ishlab chiqarishdan iborat. Axborot tеxnologiyasining maqsadi esa insonning biror-bir ishni bajarishi uchun zarur bo’tgan, uni taxlil etish va u asosida qaror qabo’l qilishi kеrak bo’tgan yangi axborotni ishlab chiqarishdan iborat.
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Mavzu: Qattiq diskni ajratish va formatlash, bo’limlarini yaratish va yo’q qilish

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Mavzu: Qattiq diskni ajratish va formatlash, bo’limlarini yaratish va yo’q qilish
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bet | 1/5 | Sana | 09.10.2024 | Hajmi | 0,74 Mb. | | #274245 |
Bog'liq Qattiq diskni formatlash, va ajratish
Mavzu: Qattiq diskni ajratish va formatlash,
bo’limlarini yaratish va yo’q qilish.
Agar xohlasangiz qattiq diskni formatlash va siz buni bilishingiz mumkin emas, qanday qilib, biz ushbu maqolada, biz sizga kerak bo'lgan barcha ma'lumotlarni batafsil bayon qilamiz. Biz qanday qilib tasvirlab beramiz qattiq diskni formatlash, har xil usullardan, bu nimani anglatishini, qachon qilish tavsiya etilganida va ko'proq qiziqishlar.
Indeks
Qattiq diskni formatlash nimani anglatadi?
Qattiq diskni qanday formatlash mumkin?
Tashqi qattiq disk
Windows -da tashqi qattiq diskni formatlash
Mac-da tashqi qattiq diskni formatlash
Linuxda tashqi qattiq diskni formatlash
Tadqiqotchidan
Windows disk menejeridan
Uchinchi shaxslar tomonidan yaratilgan dasturdan
Windows 10 qattiq diskini qanday formatlash mumkin?
BIOS -dan qattiq diskni qanday formatlash mumkin?
BIOS yordamida Windows operatsion tizimini o'rnatish
Qachon yugurish kerak
Barcha bo'limlarni ko'ring
Qattiq diskni formatlash nimani anglatadi?
Qattiq diskni formatlash- bu qattiq diskni, tashqi xotira qurilmasini yoki ma'lumotlarni saqlaydigan boshqa narsalarni asl holatiga qaytarish maqsadida bajariladigan harakatlar majmui; o'z ichiga olgan ma'lumotlarni butunlay yo'q qiladi.
Muayyan holatlarda diskni ajratish mumkin, ya'ni qattiq diskda turli xil hujjatlar va fayl formatlarini qo'llab -quvvatlaydigan turli bo'linmalar yoki mustaqil bo'linmalar hosil qilish mumkin.
Formatlashning ikki turi mavjud: birinchisi - jismoniy yoki minimal darajali formatlash, u qattiq diskni asl holatiga qaytaradi, asosiysi - diskni ajratadigan va o'chiradigan barcha joylarni boshi bilan yo'q qilish. barcha ma'lumotlar. Bu asta -sekinlik bilan amalga oshiriladigan protsedura.
Xuddi shu tarzda, tijorat uyi asbob -uskunalarni tarqatishdan oldin ishlatilgan, shuning uchun yangi egalar oldingi ma'lumotlarga kira olmaydi; ammo, taraqqiyot bilan, yangi qattiq disklar bunday formatlashni talab qilmaydi.
Ikkinchi formatlash mantiqiy yoki yuqori darajali bo'lib, u tez va qisman bajariladi, bu diskdagi har bir sohadagi fayl tizimlarining nashr etilishi bilan ajralib turadi, faqat tanlanganlarni o'chirib tashlaydi.
Shunday qilib, tanlangan fayllar hali ham hayajonlangan bo'lsa -da, qattiq diskning umumiy maydonini yana olish mumkin; vaqt o'tganidan keyin va yangi ma'lumotlarni saqlash bilan, avvalgi ma'lumotlar qayta yoziladi va qaytarib bo'lmaydigan bo'lib qoladi.
Qattiq diskni qanday formatlash mumkin?
Ushbu bo'limda biz protsedurani tasvirlab beramiz
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Contents - Published: June 2001

Contents
Contents ii
Acknowledgements iii
Introduction 1
Improved Image Capture Technologies: WIA 2
Windows Image Acquisition Architecture 2
Enhanced Support for Digital Audio and Video 5
Digital Audio Devices and Technologies 5
Support for Digital Rights Management 5
Playback and Storage of Digital Audio and Video 5
CD Mastering 6
Enhanced Multi-Monitor Support: Dualview 8
Power Management Improvements 9
Power Management Features 9
Conclusion 10
Related Links 11
Acknowledgements
Talal Batrouny, Lead Program Manager, Microsoft Corporation
Andrea Burns, Program Manager, Microsoft Corporation
Franc Camara, Lead Program Manager, Microsoft Corporation
Bryan Chee, Product Manager, Microsoft Corporation
Bob Fruth, Program Manager, Microsoft Corporation
Suzanne Girardot, Technical Writer, Volt Technical
Emily Hill, Program Manager, Microsoft Corporation
Shawn Maloney, Program Manager, Microsoft Corporation
Allen Marshall, Program Manager, Microsoft Corporation
Hakon Strande, Program Manager, Microsoft Corporation
Mike Tricker, Program Manager, Microsoft Corporation
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