Amosabrontillion

Lanenillion (formerly amosabrontillion) is equal to \(10^{3\times 10^{3\times 10^{3\times 10^{3\times 10^{87}}}}+3}\).https://integralview.wordpress.com/2020/10/01/extended-tier-4-to-6-illions/ The term was coined by Nirvana Supermind.
==Approximations==
== Sources ==
== See also ==
Category:Numbers
Category:Tetration level
Category:Illion