Legacy (2006) 10

Legacy 10: Trust Issues, Part 2 is the tenth issue of the Star Wars: Legacy comic series.
==Publisher's summary==
Once bitter enemies, Imperials loyal to the deposed Emperor Roan Fel meet with representatives from the remnants of the Galactic Alliance to discuss joining forces against the Sith. However, two spies have been thrown into the mix, each with different orders, their determination to complete their missions putting them on an explosive collision course.
Meanwhile, Cade Skywalker remains missing, yet still pursued by those bent on ignoring his desire to be left alone.
Will a new alliance be forged to defeat Darth Krayt's minions, or will betrayal shatter the galaxy's last best hope for freedom? Will Skywalker's refuge be discovered? More importantly, what will happen to those who find him? Find out in this pivotal issue of Star Wars: Legacy!
==Plot summary==
In her search for Cade Skywalker, Imperial Agent Morrigan Corde joins forces with the Sith spy, Jor Torlin. In fragile alliance, the two set up to find Cade Skywalker, but first they plan to sabotage the meeting between the Empire-in-exile and the Galactic Alliance Remnant against Darth Krayt's Galactic Empire. Using Command Override Limpet Droids to command the Empire-in-Exile ship, they force an attack on the GA's ships, resulting in a conflict aboard The Wheel and the end of the negotiations. With the job done, Corde and Torlin set off to Ossus to find Skywalker. Arriving there, Torlin shoots at Corde's back, only to discover that while he was unconscious in the Wheel, Corde inserted a "nerve toxin" that she activated while he was shooting at her, killing him. After Corde has a flashback whith Kol Skywalker and their son Cade, she decides not to go on with the mission and departs, taking Torlin's personal Gladius-class light freighter, the Raider .
==Appearances==
==Collections==
*Star Wars: Legacy Volume 2: Shards
*Star Wars: Legacy Book 1
*Star Wars Legends Epic Collection: Legacy Vol. 1
==Notes and references==
==External links==
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