Battle of Iktotch

The Battle of Iktotch was a minor battle fought during the Clone Wars.
==The battle==
Jedi Masters Mace Windu and Saesee Tiin—himself an Iktotchi—arrived on the planet to free it from the droid forces of the Separatists. They saw that they had different uses of the Force, talking about precision and power.
At the beginning of the battle, the two Jedi Masters Force Pushed B2 super battle droids, Windu destroying a squad of B1-Series battle droids. Along with clone troopers, the Jedi advanced. They then crushed a Super Battle Droid into a Hailfire droid.
Just when the two Jedi began searching the Command Center, a prototype ultra battle droid that the Separatists had created appeared. The droid opened fire and killed a clone trooper, and the two Jedi thought of a strategy to defeat it.
They then destroyed the droid one piece at a time: first, they destroyed its sensors, then hit its knees. At this point, the droid launched some homing missiles, but the Jedi used the Force to change the course of the missiles, making them detonate on the droid, which surprisingly survived. However, the Jedi quickly finished it, using a combination of speed and strength, managing to free Iktotch and understanding that both precision and power are needed.
==Appearances==
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==Sources==
*The New Essential Guide to Droids
*The Complete Star Wars Encyclopedia
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==Notes and references==
Category:Battles in the Narvath sector
Category:Battles of the Clone Wars