Program: 92314
Project: 92314
Buggy source:
/** 
 * Returns   {@code true} if the two specified objects implements exactly the same set ofinterfaces. Only interfaces assignable to  {@code base} are compared. Declaration orderdoesn't matter. For example in ISO 19111, different interfaces exist for different coordinate system geometries ( {@code CartesianCS},   {@code PolarCS}, etc.). We can check if two CS implementations has the same geometry with the following code:  {@preformat java}if (implementSameInterfaces(cs1, cs2, CoordinateSystem.class))  // The two Coordinate System are of the same kind. } }
 * @param object1 The first object to check for interfaces.
 * @param object2 The second object to check for interfaces.
 * @param base    The parent of all interfaces to check.
 * @return        {@code true} if both objects implement the same set of interfaces,considering only sub-interfaces of  {@code base}.
 */
public static boolean implementSameInterfaces(final Class<?> object1,final Class<?> object2,final Class<?> base){
  if (object1 == object2) {
    return true;
  }
  if (object1 == null || object2 == null) {
    return false;
  }
  final Class<?>[] c1=object1.getInterfaces();
  final Class<?>[] c2=object2.getInterfaces();
  int n=0;
  for (int i=0; i < c2.length; i++) {
    final Class<?> c=c2[i];
    if (base.isAssignableFrom(c)) {
      c2[n++]=c;
    }
  }
  compare:   for (int i=0; i < c1.length; i++) {
    final Class<?> c=c1[i];
    if (base.isAssignableFrom(c)) {
      for (int j=0; j < n; j++) {
        if (c == c2[j]) {
          System.arraycopy(c2,j + 1,c2,j,--n - j);
          continue compare;
        }
      }
      return false;
    }
  }
  return n == 0;
}

Fixed version (ground truth):
/** 
 * Returns   {@code true} if the two specified objects implements exactly the same setof interfaces. Only interfaces assignable to  {@code baseInterface} are compared.Declaration order doesn't matter. For example in ISO 19111, different interfaces exist for different coordinate system (CS) geometries ( {@code CartesianCS},   {@code PolarCS}, etc.). One can check if two implementations have the same geometry with the following code:  {@preformat java}if (implementSameInterfaces(cs1, cs2, CoordinateSystem.class))  // The two Coordinate System are of the same kind. } }
 * @param object1 The first object to check for interfaces.
 * @param object2 The second object to check for interfaces.
 * @param baseInterface The parent of all interfaces to check.
 * @return {@code true} if both objects implement the same set of interfaces,considering only sub-interfaces of  {@code baseInterface}.
 */
public static boolean implementSameInterfaces(final Class<?> object1,final Class<?> object2,final Class<?> baseInterface){
  if (object1 == object2) {
    return true;
  }
  if (object1 == null || object2 == null) {
    return false;
  }
  final Class<?>[] c1=getLeafInterfaces(object1,baseInterface);
  final Class<?>[] c2=getLeafInterfaces(object2,baseInterface);
  int n=(c2 != null) ? c2.length : 0;
  if (c1 != null) {
    compare:     for (    final Class<?> c : c1) {
      for (int j=n; --j >= 0; ) {
        if (c == c2[j]) {
          System.arraycopy(c2,j + 1,c2,j,--n - j);
          continue compare;
        }
      }
      return false;
    }
  }
  return n == 0;
}