\sum_{n=0}^\infin\left(x \prod_{i=1}^n{\frac{-(2i-1) x^2}{i (2i+1)}}\right) = \frac{2}{\sqrt{\pi}} \sum_{n=0}^\infin \frac{x}{2n+1} \prod_{i=1}^n \frac{-x^2}{i}