from the equation and solve for r and t. The result is: t=\frac{4 k_0k_1 e^{-i a(k_0-k_1)}}{(k_0+k_1)^2-e^{2ia k_1}(k_0-k_1)^2} r=\frac{(k_0^2-k_1^2)\sin(ak_1)}{2 i k_0k_1 \cos(ak_1)+(k_0^2+k_1^2)\sin(ak_1)}. Due to the mirror symmetry of the model, the amplitudes for incidence from the right are the same as those from the left. Note that these expressions hold for any