B e^{i\phi})\cdot e^{i\omega t} \} &= \operatorname{Re}\{(AB e^{i(\theta+\phi)})\cdot e^{i\omega t} \} \\ &= AB \cos(\omega t +(\theta+\phi)) \end{align} In electronics, B e^{i\phi}\,&nbsp; would represent an impedance , which is independent of time. In particular it is not the shorthand notation for another phasor. Multiplying a phasor current by an impedance produces