correct in multiplying $(x+3)$ and $(x+2)$ together, but now bring everything over to one side, leaving $0$ on the other side: $$x^2+5x+4=0$$ Now use the quadratic formula to get that the solutions are $x=-1$ and $x=-4$. share | improve this answer edited Jun 9 '11 at 15:50 answered Jun 9 '11 at