George is a cat, so he really likes to play. Most of all he likes to play with his array of positive integers b. During the game, George modifies the array by using special changes. Let's mark George's current array as b_1, b_2, ..., b_{|}b| (record |b| denotes the current length of the array). Then one change is a sequence of actions:   Choose two distinct indexes i and j (1 ≤ i, j ≤ |b|; i ≠ j), such that b_{i} ≥ b_{j}.  Get number v = concat(b_{i}, b_{j}), where concat(x, y) is a number obtained by adding number y to the end of the decimal record of number x. For example, concat(500, 10) = 50010, concat(2, 2) = 22.  Add number v to the end of the array. The length of the array will increase by one.  Remove from the array numbers with indexes i and j. The length of the array will decrease by two, and elements of the array will become re-numbered from 1 to current length of the array. 

George played for a long time with his array b and received from array b an array consisting of exactly one number p. Now George wants to know: what is the maximum number of elements array b could contain originally? Help him find this number. Note that originally the array could contain only positive integers.


-----Input-----

The first line of the input contains a single integer p (1 ≤ p < 10^100000). It is guaranteed that number p doesn't contain any leading zeroes.


-----Output-----

Print an integer — the maximum number of elements array b could contain originally.


-----Examples-----
Input
9555

Output
4
Input
10000000005

Output
2
Input
800101

Output
3
Input
45

Output
1
Input
1000000000000001223300003342220044555

Output
17
Input
19992000

Output
1
Input
310200

Output
2


-----Note-----

Let's consider the test examples:   Originally array b can be equal to {5, 9, 5, 5}. The sequence of George's changes could have been: {5, 9, 5, 5} → {5, 5, 95} → {95, 55} → {9555}.  Originally array b could be equal to {1000000000, 5}. Please note that the array b cannot contain zeros.  Originally array b could be equal to {800, 10, 1}.  Originally array b could be equal to {45}. It cannot be equal to {4, 5}, because George can get only array {54} from this array in one operation. 

Note that the numbers can be very large.

Difficulty: MEDIUM_HARD
Tags: Implementation

Greedy algorithms
Skill types: Greedy algorithms

Starter code:

Solutions:
p = input().strip()
n = len(p)
j = n - 1
ans = 0
while j >= 0:
	k = j
	while p[k] == '0':
		k -= 1
	ln = j - k + 1
	if ln > k:
		ans += 1
		j = -1
	elif ln == k:
		if p[0] >= p[k]:
			j = k - 1
		else:
			j = -1
		ans += 1
	else:
		ans += 1
		j = k - 1
print(ans)


s = input()
r = len(s)
c = 1
for i in range(len(s) - 1, 0, -1):
	if s[i] != '0':
		if i > r - i:
			c += 1
			r = i
		elif i == r - i:
			if s[:i] >= s[i:r]:
				c += 1
				r = i
		else:
			break
print(c)


def compare(a, b):
	fl = True
	if len(a) > len(b):
		return True
	elif len(a) < len(b):
		return False
	elif len(a) == len(b):
		fl = None
		for i in range(len(a)):
			if int(b[i]) > int(a[i]) and fl == None:
				fl = False
				break
			elif int(a[i]) > int(b[i]) and fl == None:
				fl = True
				break
		if fl == None:
			fl = True
		return fl
n = input()
l = []
a = ''
i = 0
while i < len(n):
	a += n[i]
	fl = False
	while i < len(n) and n[i] == '0':
		l[-1] += '0'
		i += 1
		fl = True
	if fl:
		a = ''
		continue
	l.append(a)
	i += 1
	a = ''
s = 1
for i in list(range(1, len(l))):
	if compare(l[i - 1], l[i]):
		s = s + 1
	else:
		s = 1
	l[i] = l[i - 1] + l[i]
	l[i - 1] = ''
print(s)


a = input()
i = 0
ans = 1
c = 0
while i < len(a):
	i += 1
	c = i - 1
	while i < len(a) and a[i] == '0':
		i += 1
	if c > i - c:
		ans += 1
	elif c == i - c:
		if a[:c] >= a[c:i]:
			ans += 1
		else:
			ans = 1
	else:
		ans = 1
print(ans)


3

def main():
	s = input()
	n = len(s)
	if n == 1:
		return 1
	fst = 1
	if int(s[0]) < int(s[1]):
		fst = 2
	ans = 1
	j = 1
	while j < n and s[j] == '0':
		j += 1
	if j == n:
		return 1
	cur = 1
	for i in range(j + 1, n + 1):
		if i == n or s[i] != '0':
			if i - cur < cur or (i - cur == cur and int(s[0]) < int(s[i - cur])):
				ans = 1
			else:
				ans += 1
			cur = 1
		else:
			cur += 1
	return ans
print(main())


s = input().strip()
n = len(s)
i = j = k = 0
while i < n:
	j = i
	i += 1
	while i < n and s[i] == '0':
		i += 1
	if j > i - j:
		k += 1
	elif j == i - j:
		if s[:j] >= s[j:i]:
			k += 1
		else:
			k = 0
	else:
		k = 0
print(k + 1)


s = input() + '#'
if len(s) == 2:
	print(1)
	return
elif '0' not in s:
	if int(s[0]) < int(s[1]):
		print(len(s) - 2)
	else:
		print(len(s) - 1)
else:
	c = 0
	ind = -1
	ans = 0
	zer = s.count('0')
	for i in range(len(s)):
		if s[i] == '0':
			c += 1
		else:
			if i - c - 1 < c + 1:
				ans = i
			elif c + 1 == i - c - 1 and s[:i - c - 1] < s[i - c - 1:i]:
				ans = i
			c = 0
	a = s[:ans].count('0')
	zer -= a
	print(len(s) - ans - zer)


def gte(x, y):
	if len(x) > len(y):
		return True
	if len(x) == len(y):
		return x >= y
	return False
x = input()
r = 0
l = len(x) - 1
while True:
	if l == 0 or not gte(x[:l], x[l:]):
		break
	if x[l] == '0':
		l -= 1
		continue
	x = x[:l]
	r += 1
	l -= 1
r += 1
print(r)


import sys
from math import *
from collections import *
readints = lambda : map(int, input().strip('\n').split())
s = input()
n = len(s)
arr = deque()
i = n - 1
while i >= 0:
	j = i
	while j >= 0 and s[j] == '0':
		j -= 1
	arr.appendleft(((j, i), 1))
	i = j - 1

def gte(x, y):
	if x[1] - x[0] > y[1] - y[0]:
		return True
	if x[1] - x[0] < y[1] - y[0]:
		return False
	n = x[1] - x[0] + 1
	for i in range(n):
		if s[i + x[0]] > s[i + y[0]]:
			return True
		if s[i + x[0]] < s[i + y[0]]:
			return False
	return True
while len(arr) > 1:
	x = arr.popleft()
	y = arr.popleft()
	if gte(x[0], y[0]):
		arr.appendleft(((x[0][0], y[0][1]), x[1] + y[1]))
	else:
		arr.appendleft(((x[0][0], y[0][1]), 1))
print(arr[0][1])


def cmp(x, y):
	for i in range(min(len(x), len(y))):
		if x[i] < y[i]:
			return True
	return len(x) < len(y)
s = input()
(r, c) = (len(s), 1)
for i in range(len(s) - 1, 0, -1):
	if s[i] != '0':
		if i > r - i:
			c += 1
			r = i
		elif i == r - i:
			if not cmp(s[:i], s[i:r]):
				c += 1
				r = i
		else:
			break
print(c)