The palindromic number `595` is interesting because it can be written as the sum of consecutive squares: `6^2 + 7^2 + 8^2 + 9^2 + 10^2 + 11^2 + 12^2 = 595`.

There are exactly eleven palindromes below one-thousand that can be written as consecutive square sums. Note that `1 = 0^2 + 1^2` has not been included as this problem is concerned with the squares of positive integers.

Given an input `n`, find the count of all the numbers less than `n` that are both palindromic and can be written as the sum of consecutive squares.

For instance: `values(1000) = 11`. See test examples for more cases.  

Good luck!

This Kata is borrowed from [Project Euler #125](https://projecteuler.net/problem=125)

If you like this Kata, please try:

[Fixed length palindromes](https://www.codewars.com/kata/59f0ee47a5e12962cb0000bf)

[Divisor harmony](https://www.codewars.com/kata/59bf97cd4f98a8b1cd00007e)

Difficulty: EASY

Starter code:
def values(n):
	

Solutions:
(l, m, p) = ([1], 10 ** 7, [])
for n in range(2, int(m ** 0.5) + 1):
	l = [n * n + j for j in [0] + l]
	p += [int(k) for k in map(str, l[1:]) if k == k[::-1]]
p = sorted(set(p))
from bisect import bisect_left

def values(n):
	return bisect_left(p, n)


def values(n):
	pal = set()
	for i in range(1, int(n ** 0.5)):
		sos = i * i
		while sos < n:
			i += 1
			sos += i * i
			if str(sos) == str(sos)[::-1] and sos < n:
				pal.add(sos)
	return len(pal)


from bisect import bisect
is_pal = lambda s: s == s[::-1]
(N, temp) = (2500, set())
for x in range(1, N):
	val = x ** 2
	for y in range(x + 1, N):
		val += y ** 2
		if val not in temp and is_pal(str(val)):
			temp.add(val)
result = sorted(temp)

def values(n):
	return bisect(result, n)


sumSquaresToN = lambda n: n * (n + 1) * (2 * n + 1) // 6
memo = set()

def values(n):
	lastMax = max(memo) if memo else 0
	if lastMax >= n:
		return sum((x < n for x in memo))
	top = int((1 + (1 + 2 * (n - 1)) ** 0.5) // 2)
	for a in range(top, 1, -1):
		va = sumSquaresToN(a)
		if va <= lastMax:
			break
		for b in range(a - 2, -1, -1):
			v = va - sumSquaresToN(b)
			if v >= n:
				break
			if v == int(str(v)[::-1]):
				memo.add(v)
	return len(memo)


found = set([5, 55, 77, 181, 313, 434, 505, 545, 595, 636, 818, 1001, 1111, 1441, 1771, 4334, 6446, 17371, 17871, 19691, 21712, 41214, 42924, 44444, 46564, 51015, 65756, 81818, 97679, 99199, 108801, 127721, 137731, 138831, 139931, 148841, 161161, 166661, 171171, 188881, 191191, 363363, 435534, 444444, 485584, 494494, 525525, 554455, 554455, 629926, 635536, 646646, 656656, 904409, 923329, 944449, 964469, 972279, 981189, 982289, 1077701, 1224221, 1365631, 1681861, 1690961, 1949491, 1972791, 1992991, 2176712, 2904092, 3015103, 3162613, 3187813, 3242423, 3628263, 4211124, 4338334, 4424244, 4776774, 5090905, 5258525, 5276725, 5367635, 5479745, 5536355, 5588855, 5603065, 5718175, 5824285, 6106016, 6277726, 6523256, 6546456, 6780876, 6831386, 6843486, 6844486, 7355537, 8424248, 9051509, 9072709, 9105019, 9313139, 9334339, 9343439, 9343439, 9435349, 9563659, 9793979, 9814189, 9838389, 9940499])

def values(n):
	return sum((i < n for i in found))


def values(high):
	s = set()
	num = 1
	while num * num < high:
		temp = num + 1
		total = num * num + temp * temp
		while total < high:
			if str(total) == str(total)[::-1]:
				s.add(total)
			temp += 1
			total += temp * temp
		num += 1
	return len(s)


def values(limit):
	palindromes = set()
	for sequence_item in range(1, int(limit ** 0.5)):
		squares_sum = sequence_item ** 2
		while squares_sum < limit:
			sequence_item += 1
			squares_sum += sequence_item ** 2
			if str(squares_sum) == str(squares_sum)[::-1] and squares_sum < limit:
				palindromes.add(squares_sum)
	return len(palindromes)


def values(n):
	p = set()
	for i in range(1, int(n ** 0.5)):
		q = i * i
		while q < n:
			i = i + 1
			q = q + i * i
			if str(q) == str(q)[::-1] and q < n:
				p.add(q)
	return len(p)


def values(limit):

	def is_palindrome(n):
		n = str(n)
		if len(n) in [0, 1]:
			return True
		return n[0] == n[-1] and is_palindrome(n[1:-1])
	print('Limit: {}'.format(limit))
	current = 2
	totals = [1]
	list_pal = []
	while True:
		number = current ** 2 + totals[-1]
		totals = [i for i in totals if number - i < limit]
		if len(totals) == 1 and totals != [1]:
			break
		for i in totals[:-1]:
			if is_palindrome(number - i) and (not number - i in list_pal) and (limit > number - i):
				list_pal.append(number - i)
		if is_palindrome(number) and (not number in list_pal) and (limit > number):
			list_pal.append(number)
		totals.append(number)
		current += 1
	print('Number of Palindrome in list: {}'.format(len(list_pal)))
	print('List of Palindrome: {}'.format(list_pal))
	return len(list_pal)