John is developing a system to report fuel usage but needs help with the coding.

First, he needs you to write a function that, given the actual consumption (in l/100 km) and remaining amount of petrol (in l), will give you how many kilometers you'll be able to drive.

Second, he needs you to write a function that, given a distance (in km), a consumption (in l/100 km), and an amount of petrol (in l), will return one of the following: If you can't make the distance without refueling, it should return the message "You will need to refuel". If you can make the distance, the function will check every 100 km and produce an array with [1:kilometers already driven. 2: kilometers till end. 3: remaining amount of petrol] and return all the arrays inside another array ([[after 100km], [after 200km], [after 300km]...])

PLEASE NOTE: any of the values with decimals that you return should be rounded to 2 decimals.

Difficulty: EASY
Tags: Fundamentals

Game theory

Ad-hoc

Starter code:
def total_kilometers(cons, petrol):
	

Solutions:
def total_kilometers(cons, petrol):
	return round(100 * petrol / cons, 2)

def check_distance(dist, cons, petrol):
	return 'You will need to refuel' if dist > total_kilometers(cons, petrol) else [[n * 100, dist - 100 * n, round(petrol - cons * n, 2)] for n in range(dist // 100 + 1)]


def total_kilometers(cons, petrol):
	distance = round(petrol / cons * 100, 2)
	return distance

def check_distance(distance, cons, petrol):
	outp = []
	track = 0
	driven_dist = 0
	if distance > petrol / cons * 100:
		return 'You will need to refuel'
	while track <= distance:
		outp.append([driven_dist, distance - driven_dist, round(petrol, 2)])
		driven_dist += 100
		petrol -= cons
		track += 100
	return outp


def total_kilometers(cons, petrol):
	return round(petrol * 100.0 / cons, 2)

def check_distance(distance, cons, petrol):
	if total_kilometers(cons, petrol) < distance:
		return 'You will need to refuel'
	return [[round(x, 2) for x in (i * 100, distance - i * 100, petrol - cons * i)] for i in range(int(distance / 100) + 1)]


def total_kilometers(cons, petrol):
	return round(float(petrol) / cons * 100, 2)

def check_distance(distance, cons, petrol):
	if distance * cons > petrol * 100:
		return 'You will need to refuel'
	return [[i, distance - i, round(petrol - i * cons / 100, 2)] for i in xrange(0, distance + 1, 100)]


def total_kilometers(cons, petrol):
	return round(petrol / float(cons) * 100, 2)

def check_distance(distance, cons, petrol):
	if total_kilometers(cons, petrol) < distance:
		return 'You will need to refuel'
	km_driven = 0
	result = []
	while distance >= 0:
		result.append([km_driven, distance, petrol])
		distance -= 100
		km_driven += 100
		petrol = round(petrol - cons, 2)
	return result


def total_kilometers(cons, petrol):
	result = round(float(petrol) / float(cons) * 100.0, 2)
	print(f'total_kilometers({cons}, {petrol}) => {result}')
	return result

def check_distance(distance, cons, petrol):
	if petrol / cons * 100 < distance:
		return 'You will need to refuel'
	result = [[0, distance, petrol]]
	fuel = petrol
	since_start = 0
	to_end = distance
	for _ in range(to_end // 100):
		fuel -= cons
		since_start += 100
		to_end -= 100
		result.append([since_start, to_end, round(fuel, 2)])
	print(f'check_distance({distance}, {cons}, {petrol}) => {result}')
	return result


def total_kilometers(cons, petrol):
	return round(100 * petrol / cons, 2)

def check_distance(distance, cons, petrol):
	if total_kilometers(cons, petrol) < distance:
		return 'You will need to refuel'
	r = [[0, distance, petrol]]
	x = 0
	while distance >= 100:
		petrol -= cons
		distance -= 100
		x += 100
		r.append([x, distance, round(petrol, 2)])
	return r


def total_kilometers(cons, petrol):
	return round(petrol * 100 / cons, 2)

def check_distance(distance, cons, petrol):
	if distance > petrol * 100 / cons:
		return 'You will need to refuel'
	else:
		l = []
		length = 0
		for i in range(1 + distance // 100):
			l.append([length, distance, round(petrol, 2)])
			length += 100
			distance -= 100
			petrol -= cons
		return l