Given: circumference of circle=22cmCircumference of a circle =2×π×r⇒22  =2×π×rNow,∴ r=π11​ cm⇒ Area of Quadrant =4Area of circle​⇒ Area of Quadrant =4πr2​=4π×(π11​)2​⇒ Area of Quadrant =π×4121​=4×722​121​∴ Area of Quadrant =877​cm2