R.E.F image Given height of pole =6mlength of shadow =\\\\(2\\sqrt{3}m\\\\)Let '\\\\( \ heta \\\\) ' be elevation. of sum then\\\\(tan\ heta \\\\) =\\\\(\\frac{AB}{BC}=\\frac{6}{2\\sqrt{3}}\\\\)\\\\( tan\ heta =\\sqrt{3}\\\\)\\\\( tan\ heta =tan \\frac{\\pi }{3}\\\\) then \\\\( \ heta = \\frac{\\pi }{3}\\\\)\\\\(\ herefore\\\\) Angle of elevation of sum is \\\\(60^{\\circ}.\\\\)