Let the side of the first square be 'a'm and that of the second be ′A′ m.Area of the first square =a2 sq m.Area of the second square =A2 sq m.Their perimeters would be 4a and 4A respectively.Given 4A−4a=24A−a=6 --(1)A2+a2=468 --(2)From (1), A=a+6Substituting for A in (2), we get(a+6)2+a2=468a2+12a+36+a2=4682a2+12a+36=468a2+6a+18=234a2+6a−216=0a2+18a−12a−216=0a(a+18)−12(a+18)=0(a−12)(a+18)=0a=12,−18So, the side of the first square is 12 m. and the side of the second square is 18 m.