Refer above image.Let the aperture \\\\(=d\\\\) \\\\(D=4\ imes 10^8m\\\\)\\\\(wavelength =\\lambda=5500\ imes 10^{-10}m\\\\)for two objects to be resolved\\\\(\ heta=1.22\\dfrac{\\lambda}{d}\\\\)also \\\\(d=D\ heta\\\\)\\\\(\\Rightarrow \ heta=\\dfrac{d}{D}\\\\)\\\\(\\Rightarrow \\dfrac{d}{4\ imes 10^8}=\\dfrac{1.22\ imes 5500\ imes 10^{-10}}{5}\\\\)\\\\(d=53.68\\approx 60m\\\\)Option A is correct.