\\\\(v^2 = u^2 + 2as\\\\)\\\\(u = 0, s = 2 \ imes 10^{-2} mt\\\\)\\\\(a = \\dfrac {v^2}{2s} = \\dfrac {(4 \ imes 10^3 \ imes 10^3)^2}{2 \ imes 2 \ imes 10^{-2}} m/s^2\\\\)\\\\(a = 4 \ imes 10^{14} \\\\)Now, \\\\( v = u + at\\\\)\\\\(\\dfrac {v}{a} = t\\\\)\\\\(t = \\dfrac{4 \ imes 10^6}{4 \ imes 10^{14}} = 10^{-8}s\\\\)