Given :Length of the floor is \\\\(5m\\\\)The breadth of the floor is \\\\(4m\\\\)So, ( applying ar. \\\\(l \ imes b\\\\) )ar. of floor \\\\(=4m\ imes 5m=20m^2.\\\\) Side of the carpet is \\\\(3m\\\\)So, (applying ar. of sq. \\\\(= side × side (s) )\\\\)area of carpet\\\\(=3m\ imes3m=9m^2.\\\\) To find the area of the floor that is not carpeted or (uncarpeted) we will \\\\((-)\\\\) minus the ar. of the floor from ar. of carpet area which is not carpeted or( uncarpeted ) \\\\(=20m^2-9m^2\\\\)\\\\(=11m^2.\\\\) Hence, answer Is \\\\(11m^2.\\\\)