From the vapor density informationMolar mass = Vapour density ×2(∵ Molar mass of H2​=2)=38.3×2=76.6Now, let us consider 1.0 mole of the mixture and it contains x mole of NO2​.⇒46x+92(1−x)=76.6⇒x=0.3348Also, in 100 g mixture, number of moles =76.6100​⇒ Moles of NO2​ in mixture =76.6100​×0.3348=0.437