The resistance of the coil is related to the reactances and the phase constant by equation  $$ an phi =dfrac{X_{L}-X_{C}}{R}$$. Thus, $$dfrac{X_{L}-X_{C}}{R}=dfrac{omega _{d}L-1/omega _{d}C}{R}= an phi$$. which we solve for  $$R$$: $$R=dfrac{1}{ an phi }left ( omega _{d}L-dfrac{1}{omega _{d}C} \right )=dfrac{1}{ an 75^{o}}left [ left ( 2pi  \right )left ( 930Hz \right )left ( 0.94 imes 10^{-6}F \right ) \right ]=89Omega$$.