Assuming that the ball was thrown with a velocity of 8.2 m/s and an angle of 45°, the projectile range is 8.48 m. To calculate this:
Identify the initial height = 2 m, α = 45° and V₀ = 8.2 m/s.
Use the formula:
d = V₀cosα × (V₀sinα+√[(V₀sinα)²+2gh])/g =
8.2 m/s × cos45° × (8.2 m/s×sin45° + √[(8.2 m/s × sin45°)² + 2 × 9.81 m/s × 2 m])/9.81 m/s = 8.48 m.
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