Let f1​​,f2​​,f3​​,…fn​​ be the forces acting on a point P Let O be the point along which torques (moments) will be taken. Let:f1​​+f2​​+f3​​+…+fn​​=R Moments of force (torque) fi​​ about O will be :τ1​​=OP×f1​​ The sum of the torques about O will be :​M=OP×f1​​+OP×f​2​+…+OP×fn​​⇒M=OP×(f1​​+f2​​+f3​​+…+fn​​)⇒M=OP×R[ From (1) ]​ Thus, we see that the torque of the resultant force R of the forces f1​​,f2​​,f3​​,…fn​​ gives the sum of the moments of the torques.