Sometimes we come across equations that are not linear as per the definition of linear equations but can be reduced to a linear form and then the method of solving linear equations can be applied to them to solve them. The example below illustrates one such equation and how to solve it:(X + 1)/(2x + 6) = 3/8To reduce this nonlinear equation into a linear equation we multiply both sides by the denominator of LHS which is 2x + 6.(X + 1)/(2x + 6) * (2x + 6) = 3/8 * (2x + 6)X + 1 = 6x + 18/8 - This is a linear equation now. We can solve it by multiplying both sides with LCM of denominators which is 88 * (x + 1) = 8 * (6x + 18/8)8x + 8 = 6x + 18Now moving all variable to LHS and all constant to RHS we get:8x - 6x = 18 - 82x = 10X = 5