Let a LCR circuit is connected across an AC supply with the emf E=E0​sinωt . Let the inductance in the circuit be LLet the net impedence of the circuit be Z=R2+(XL​−XC​)2​ Where,R= resistance in the circuitXL​= reactance due to inductorXC​= reactance due to capacitorThe magnitude of the voltage across the inductor is given byV=L dtdi​ The current in the circuit can be written as I=I0​sin(ωt+ϕ) Where, ϕ is the phase difference between the current and the supply voltage Thus, the voltage across the inductor can be written asV=LI0​cos(ωt+ϕ) Thus peak value of the voltage across the inductor is given by​V=LI0​⇒V=ZE0​​×L​ Therefore, the peak voltage across the inductor is given by V=ZE0​​×L At resonance Z=R1​ ​V=RE0​​×L If RL​>1V>E0​​ Therefore if magnitude of RL​>1 at resonance the value of the voltage across the inductor will bw, greater than the peak value of the supply voltage.