These types of questions are shell scripting scenario-based interview questions and generally asked with experienced candidates.  To print a list of every user's login names on a Unix-like system, we can use the cut and sort commands to extract the login names from the /etc/passwd file and sort them alphabetically.  Below is an example of a command sequence that we can use to print a list of login names:  # Extract the login names from the /etc/passwd file
login_names=$(cut -d: -f1 /etc/passwd)
# Sort the login names alphabetically
sorted_login_names=$(echo "$login_names" | sort)
# Print the login names
echo "$sorted_login_names"  This script will use the cut command to extract the first field (the login name) from each line of the /etc/passwd file, using the : character as the delimiter. The output of the cut command will be stored in the login_names variable.  The script will then use the sort of command to sort the login names alphabetically, and store the sorted list in the sorted_login_names variable. Finally, the script will use the echo command to print the login names.  The /etc/passwd file is a system file that contains information about the users on the system, including their login names, home directories, and other details. Each line of the file represents a single user, and the fields are separated by: characters.