The energy of one photon (E) \\\\(=hv\\\\)Here, \\\\(h=6.626\ imes {10^{34}}\\\\) js \\\\(v= 5\ imes 10^{14} s^{-1}\\\\)\\\\(E=6.626\ imes 10^{-34} \ imes 5\ imes 10^{14}\\\\)\\\\(3.313\ imes 10^{-19}\\\\) jThus the energy of one mole of photons is \\\\(E\ imes A\\\\) Where A is the Avogadro number\\\\(=3.313\ imes 10^{-19}j\ imes 6.022\ imes 10^{-23}\\\\) mol\\\\(=199.50 \ imes 10^{-3}j mol\\\\)