P(A')=1/4 so P(A)=3/4P(AUB)'=1/6, P(AUB)=5/6P(A∩B)=1/4P(AUB)=P(A)+P(B)-P(A∩B)=3/4+P(B)-1/45/6=1/2+P(B)P(B)=2/6=1/3P(A)*P(B)=1/3*3/4=1/4=P(A∩B)A and B are independent but not equally likely