Since the angular velocities of both the masses are constant, their linear velocities would also remain constant using the relation \\\\(v=r \\omega\\\\).Thus at each point their velocities change only in direction. Thus the momentum of particle A is \\\\(P_{A}= m_A v_A \\\\) i.e. \\\\(2\ imes2 = 4 kgm/s\\\\) and that of B is \\\\(P_{B}= m_B v_B \\\\) i.e. \\\\(1\ imes3 = 3 kgm/s\\\\).We will get their momentum as a maximum when the particles travel parallel to each other in the same direction.Thus we get the maximum value of their momentum simply as the sum of their individual momentums i.e. \\\\( |P_A +P_B| = 4-3 = 1 kgm/s\\\\) at all points.