Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then \\\\(\\Delta\\\\)ABC is a right angled triangle, right angled at B.AB\\\\(=12\\\\)m and BC\\\\(=5\\\\)mUsing Pythagoras theorem, In \\\\(\\Delta\\\\)ABC\\\\((AC)^2+(AB)^2+(BC)^2\\\\)\\\\(\\Rightarrow (AC)^2=(12)^2+(5)^2\\\\)\\\\(\\Rightarrow (AC)^2=144+25\\\\)\\\\(\\Rightarrow (AC)^2=169\\\\)\\\\(\\Rightarrow AC=13\\\\)mHence, the total height of the tree\\\\(=AC+CB=13+5=18\\\\)m.