Radius of gyration andmoment of inertia will increase.\\\\(\\because I=mk^{2}\\\\)\\\\(k=\\sqrt{\\dfrac{I}{m}}\\\\)\\\\(I=\\dfrac{mR^{2}}{2}\\\\)\\\\(k=\\dfrac{R}{\\sqrt{2}}\\\\)\\\\(A=A_{0}(1+ 2\\alpha \\Delta T) (eq^{n} \\\\) of thermal expansion)\\\\(\\pi r^{2}=\\pi R_{0}^{2} (1+ 2\\alpha \\Delta T)\\\\)\\\\(r^{2}=R_{0}^{2} (1+ 2\\alpha \\Delta T)\\\\)\\\\(\ herefore\\\\) r will increase on increasing the temperature\\\\(\ herefore I\\ and \\ k\\\\) will increase on increasing the \\\\(temperature\\\\)