y = mx + 1 ... (1)3x + 4y = 9 .... (2)On solving the above equations3x + 4(mx + 1) = 9⇒x(3+4m)=5⇒x=3+4m5​ Given abscissa (3+4m5​) is an integer.⇒3+4m=±1⇒4m=−2,−4⇒m=−21​,−1​ or  or ​3+4m=±54m=2,−8⇒m=21​,−2​ Number of integral values of m are 2.