\\( A B=\\sqrt{(3-6)^{2}+(4-7)^{2}}=\\sqrt{(-3)^{2}+(-3)^{2}}=\\sqrt{9+9}=\\sqrt{18}=3 \\sqrt{2}\\)
\\( B C=\\sqrt{(6-9)^{2}+(7-4)^{2}}=\\sqrt{(-3)^{2}+(3)^{2}}=\\sqrt{9+9}=\\sqrt{18}=3 \\sqrt{2}\\)
\\( C B=\\sqrt{(9-6)^{2}+(4-1)^{2}}=\\sqrt{(3)^{2}+(3)^{2}}=\\sqrt{9+9}=\\sqrt{18}=3 \\sqrt{2}\\)
\\( A D=\\sqrt{(3-6)^{2}+(4-1)^{2}}=\\sqrt{(-3)^{2}+(3)^{2}}=\\sqrt{9+9}=\\sqrt{18}=3 \\sqrt{2}\\)
\\( A C=\\sqrt{(3-9)^{2}+(4-4)^{2}}=\\sqrt{(-6)^{2}+0^{2}}=6\\)
\\( \\mathrm{BD}=\\sqrt{(6-6)^{2}+(7-1)^{2}}=\\sqrt{0^{2}+(6)^{2}}=6\\)
It can be observed that all sides of this quadrilateral ABCD are of the same length
and also the diagonals are Of the sarne length,
Therefore, ABCD is a square and hence, Champa correct