Assuming the weight of the driver is 70 kg, we can calculate the impact forces in two situations:
Without the seatbelt, the stopping distance would be 4 cm, and the impact force is:
F = 70 kg × (44.44 m/s)²/(2 × 0.04 m) = 1728 kN
With the seatbelt on, the stopping distance increases to 20 cm. The force becomes:
F = 70 kg × (44.44 m/s)²/(2 × 0.2 m) = 346 kN
Divide F by m × g = 686.7 m/s² to find the deceleration in terms of g. It’s 2517 g without a seatbelt and 504 g with. Read more