Hydroboration-oxidation reaction follows anti-Markovnikov's addition of \\\\(H-OH\\\\) across \\\\(C=C\\\\) to give alcohol.Thus an alkene \\\\(CH_3CH=CH_2\\\\) when treated with \\\\(B_2H_6\\\\) in presence of \\\\(H_2O_2\\\\) will yield the final product as \\\\(CH_3CH_2CH_2OH\\\\)