Let xkm per hour be the average speed of the passenger train, then the average speed of the express train will be (x+11)km per hour.The time taken by the passenger train is x132​ hour and the time taken by the express train is (x+11)132​ hour. So,​x+11132​=x132​+1x2+11x−1452=0x2+44x−33x−1452=0(x−33)(x+44)=0x=33,x=−44​ The speed cannot be negative, so the speed of the passenger train is 33 km per hour and the speed of the express train is 33+11=44 km per hour.