The punch force required to produce a 3 mm hole in 5 mm thick stainless steel is 18.84 kN.
First, we calculate the perimeter of the hole using its diameter, π × 3 = 9.42 mm.
Then, considering the shear strength of stainless steel as 400 MPa, the punch force calculation is:
F = 400 × 9.42 × 5 = 18.84 kN Read more