It will require more force to set the bar into rotation by clamping at A and then clamping at B.Explanation:- Since the rod has mass density increasing towards B, the Center of Mass (CM) of the rod is near B.  If the rod is clamped along A, the distance of CM of the rod from the pivot will be greater when the rod is clamped along B. Greater distance of CM from the Center of rotation increases the moment of inertia of the rod and hence more torque will be necessary to rotate the bar about A. Greater torque implies greater force will be necessary to rotate it.FA​ = Force required to rotated the rod clamped at ARA​ = Distance of CM from pivot AM = Mass of the rodFB​  = Force required to rotate the rod clamped at BRB​ = Distance of CM from pivot BWe have RA​ >RB​ .We have to find the torque required to rotate rod clamped at A to produce angular acceleration a.TA​  = MRA​ 2 a = RA​ FA​ => FA​  = MRA​ aWe have to find torque required to rotate rod clamped at B to produce angular acceleration a.TB​  = MRB​2a = RB​FB​ => FB​  = MRB​ aOn comparing, since RA​ >RB​ , we getFA​ >FB​