The area of the circular sheet with \\\\(4\\;{\\rm{cm}}\\\\) radius is, \\\\(A = \\pi {r^2}\\\\) \\\\( = 16\\pi \\\\) The area of the circular sheet with \\\\(3\\;{\\rm{cm}}\\\\) radius is, \\\\(A = \\pi {r^2}\\\\) \\\\( = 9\\pi \\\\) Since the circle with radius \\\\(3\\;{\\rm{cm}}\\\\) is removed, then the remaining area is, \\\\(A = 16\\pi - 9\\pi \\\\) \\\\( = 7\\pi \\\\) \\\\( = 7 \ imes 3.14\\\\) \\\\( = 21.98\\;{\\rm{c}}{{\\rm{m}}^2}\\\\)