(a) The wires constitute 2 parallel emfNet emf =Blv=1\ imes 4\ imes { 10 }^{ -2 }\ imes 5\ imes { 10 }^{ -2 }=20\ imes { 10 }^{ -4 }\\quad Net resistance =\\cfrac { 2\ imes 2 }{ 2\ imes 2 } +19=20\\Omega Net current =\\cfrac { 20\ imes { 10 }^{ -4 } }{ 20 } =0.1mA\\quad (b) When both the wires move towards opposite directions then net emf=0net current =0