From figure, \\\\(AB=BC=CD=DA=6\\ cm\\\\)\\\\(PR\\\\) is the diameter of the circle, inscribed in the square \\\\(ABCD\\\\)\\\\(\ herefore PR=side \\ of \\ the \\ square=6\\ cm\\\\)\\\\(\ herefore Radius=\\dfrac{6}{2}=3\\\\)\\\\(Area=\\pi r^2=\\dfrac{22}{7}\ imes 3^2\\\\)\\\\(=\\dfrac{22}{7}\ imes 9\\\\)\\\\(\ herefore Area \\ of \\ circle=28.28\\ cm^2\\\\)