The given pair of equation are: x/2 + y = 0.8             =>x + 2y = 1.6...(a) 7/(x + y/2) = 10        =>7 = 10(x + y/2)        => 7 = 10x + 5yLets multiply LHS and RHS of equation (a) by 10 for easy calculationSo, we finally get10x + 20y = 16 .................(i) And,10x + 5y = 7.................(ii)Now, Subtracting two equations we get,=> (i) - (ii)15y = 9=> y = 3/5Next, putting the value of y in the equation (i) we get,x = [16 − 20(3/5)]/10=> (16 − 12)/10 = 4/10x = 2/5Thus, the value of x and y obtained are 2/5 and 3/5 respectively.