Example: We have to find the steel quantity for the room , Which size is 5 m x 4 m .
Given Data : Size of Room = 16.4 x 13.12 ft Main bars diameter = d = 0.5 inch (12 mm). Distribution bars diameter = d =0.4 inch (10mm). Spacing of Main bars = c/c = 150 mm c/c or 0.49 ft or 5.9inches Formula to find the No’s of ( M.B ) Main bars = 500 / 15 + 1= 34.33 say 35 Straight bar = 18 Bent up bars = 17 cranked bars to act against negative moment. 2) Spacing of Distribution bars = c/c = 20 cm c/c or 0.65 ft or 7.87 inches. Formula to find the No’s of ( D.B ) Distribution bars = 400 / 20 + 1= 21 No’s unit weight of steel or density is 7850 kg/m3. or Weight of steel = D^2/162 kg/m.