We know frictional force \\\\(f=\\mu N\\\\) where N=normal force=mgGiven sliding friction\\\\(\\mu=0.25\\\\) Thus, \\\\(f=0.25\ imes 50\ imes 10=125 N\\\\)Hence \\\\({F}_{net}={F}_{app}-f=575-125=450 N\\\\)Also we know Force\\\\(F=ma\\\\)\\\\(a=\\dfrac{450}{50}=9 m/{s}^{2}\\\\)