To find the number of lines in a file that contains the word "LINUX" using a bash shell script, we can use the grep command with the -c option.  Below is an example of a script that you can use to find the number of lines in a file called "file.txt" that contain the word "LINUX":  # Find the count of lines containing "LINUX" in the file
line_count=$(grep -c "LINUX" "file.txt")
# Print the result  echo "Number of lines containing LINUX: $line_count"  This script will execute the grep command with the -c option, which searches for the specified pattern ("LINUX") in the file and counts the number of lines that match the pattern. The output of the grep command will be captured by the $(...) syntax and stored in the line_count variable. The script will then print the value of the line_count variable using the echo command.  We can also use the -i option to ignore case when searching for the pattern, or the -w option to match only whole words.  For example, to search for the pattern "linux" regardless of case, we can use the following script:  # Find the count of lines containing "linux" in the file, ignoring case
line_count=$(grep -ci "linux" "file.txt")
# Print the result
echo "Number of lines containing linux: $line_count"