Ans. Given intensity of pressure = 40 kPa                                                 = 40 kN/m2                    Sp. Gr. Of mercury = 13.6                    Sp. Wt. of mercury = 13.6 * 9.81 = 133.416 1)Gauge pressure :- In terms of pressure intensity = 40 kN/m2 = 0.4 * 105 N/m2 =  0.4 bar [ 105 N/m2 = 1 bar] In terms of water head               H = p/w = 0.4 * 105/9810 = 4.077 m of  water In term of mercury head H = p/wm = 0.4 * 105/13.6 * 9810 = 0.299 m of         mercury 2)Absolute pressure :-  Given barometer reading (atmospheric perssure)                      = 760 mm of mercury                       = 0.760 m of mercury                       = 0.760 * 13.6 * = 10.336 m of water              Absolute pressure = Patm + Pgauge In term of pressure intensity                    Abs. pressure = Patm + P gauge                                             =0.76 * 9.81 * 13.6 + 40                                             = 141.396 kN/m2 In term of water head                   Abs. pressure = 10.336 + 4.077                                            = 14.413 m of water In term of mercury head                       Abs. pressure = 0.760 + 0.299                                                 = 1.059 m of mercury