Area of region I: ⇒ 2S=5+5+1=11cm (Isosceles triangle)S=5.5  cmArea of I=s(s−a)(s−b)(s−c)​=5.5(5.5−5)(5.5−5)(5.5−1)​=.7511​=2.48  cm2Area II: or Area of rectangle =l×b=6.5×1=6.5  cm2Area III: Its a trapeziumSo, we need to calculate the perpendicular height=(1)2−(0.5)2=0.75​=0.86  cmArea of trapezium= Area of parallelogram + Area of equilateral triangle=0.866×1+43​​(1)2=0.86+0.43=1.29  cm2Area of region IV= Area of region V=21​×6×1.5=4.5  cm2Total area of paper used =2.48+6.5+1.29+4.5+4.5=19.27  cm2