In \\\\( \ riangle BOC\\\\), \\\\(\\angle OBC=\\angle OCB\\\\) ----- (Opposite angle of isosceles triangle)\\\\(\\angle OBC+\\angle OCB+\\angle BOC = 180^\\circ\\\\)\\\\(25^\\circ+25^\\circ+\\angle BOC = 180^\\circ\\\\)Therefore, \\\\(\\angle BOC = 130^\\circ\\\\) So, \\\\(\\angle AOB+ \\angle BOC = 180^\\circ\\\\)--------(Linear pair)\\\\(\\angle AOB = 180^\\circ- 130^\\circ\\\\)\\\\(\\angle AOB = 50^\\circ\\\\)So, the acute angle between the diagonal is \\\\(50^\\circ\\\\).