At STP, 1 mole of oxygen occupies 22400 mL.Hence, the number of moles of oxygen corresponding to 5600 ml is \\\\(n_{O_2}=\\dfrac {5600}{22400}=\\dfrac {1}{4}=\\dfrac {W_{O_2}}{M_{O_2}}\\\\).1 mole of oxygen produces 4 moles of lectrons and 1 mole of silver requires 1 mole of electrons.\\\\(\\dfrac {W_{Ag}}{M_{Ag}}\ imes 1=\\dfrac {W_{O_2}}{M_{O_2}}\ imes 4\\\\) \\\\(\\dfrac {W_{Ag}}{M_{Ag}}\ imes 1=\\dfrac {1}{4}\ imes 4\\\\) \\\\(\\dfrac {W_{Ag}}{108}=\\dfrac {1}{4}\ imes 4\\\\)\\\\(W_{Ag}=108 g\\\\) Thus, the weight of silver displaced by a quantity of electricity which displaces 5600 ml of \\\\(O_2\\\\) at STP will be 108.0 g.