Where cf= cumulative frequencyMedian =1+⎩⎨⎧​h×f(2N​−cf)​⎭⎬⎫​HereN=100N/2=50cf just greater than 50 is 56Median class =150−155So, I=150, h=5, f=22 andcf=cf of preceding class i.e 34Substitute all the value in the above formula, we getMedian =150+{5×(50−34)/22}=150+3.64=153.64