Let the company manufacture x souvenirs of type A and y souvenirs of type B. Therefore, x≥0 and y≥0 The given information can be complied in a table as follows.The profit on type A souvenirs is Rs 5 and on type B souvenirs is Rs 6 . Therefore, the constraints are5x+8y≤200 10x+8y≤240i.e. ​,5x+4y≤120 Total profit, z = 5x + 6yThe mathematical formulation of the given problem isMaximize z = 5x + 6 y ...... (1)subject to the constraints,5x+8y≤200 (2) ...... (2) 5x+4y≤120 ...... (3)x,y≥0 ...... (4)The feasible region determined by the system of constraints is as follows.The corner points are A(24,0), B(8,20), and C(0,25). The values of Z at these corner points are as follows.The maximum value of Z is 200 at (8,20).Thus, 8 souvenirs of type A and 20 souvenirs of type B should be produced each day to get the maximum profit of Rs 160 .