Since side is 3 unit length, then co-ordinates of B are (5,0) Let co-ordinates of C be (x,y)From the property of equilateral triangle, AC=BC​AC2=BC2(x−2)2+(y−0)2=(x−5)2+(y−0)2x2+4−4x+y2=x2+25−10x+y2⇒6x=21⇒x=27​Now from AC =3 or AC2=9(x−2)2+(y−0)2=9(272​−2)+y2=9⇒y2=9−49​​⇒y2=427​⇒y=233​​ (+ve sign to be taken), So, Co-ordinate of C(27​,233​​)