Let the sides of the two squares be of \\\\(a\\\\) and \\\\(b\\\\).The according to the problem\\\\(a^2+b^2=640\\\\).........(1).Again \\\\(4(a-b)=64\\\\)or, \\\\(a-b=16\\\\).......(2).Using (2) in (1) we get,\\\\(a^2+(-16+a)^2=640\\\\)or, \\\\(2a^2-32a+256=640\\\\)or, \\\\(2a^2-32a-384=0\\\\)or, \\\\(a^2-16a-192=0\\\\)or, \\\\((a-24)(a+8)=0 \\\\)Since \\\\(a\\\\) is the side of a square then \\\\(a=24\\Rightarrow b=8\\\\).So the sides of the squares be \\\\(24\\\\) m and \\\\(8\\\\) m.