The mechanism for the reaction between \\\\(3\\\\)-methylbutan-\\\\(2\\\\)-ol and HBr is shown above.In the first step, \\\\(-OH\\\\) group is protonated. In the second step, a molecule of water is lost to form secondary carbocation.Third step is the rearrangement of less stable secondary carbocation to more stable tertiary carbocation through \\\\(1,2\\\\)-hydride shift.Final step is the nucelophilic attack of bromide ion on tertiary carbocation to form \\\\(2\\\\)-bromo-\\\\(2\\\\)-methylbutane.