First A.P. is 63,65,67,…∴a=63d=65−63=2nth term of this A.P. =an​=a+(n−1)dan​=63+(n−1)2=63+2n−2an​=61+2n……………….(1)Second  A.P is 3,10,17,…a=3d=10−3=7nth term of this A.P. =3+(n−1)7an​=3+7n−7an​=7n−4………………..(2)It is given that, nth term of these A.P.s are equal to each other.Equating equations (1) and (2),61+2n =7n −461+4=5n5n=65n=13Therefore, 13th terms of both these A.P.s are equal to each other.