Given : \\\\(I_1 = 0.8\\\\) AThus voltage drop across 3 ohm, \\\\(V_1 = IR_1 = 0.8\ imes 3 = 2.4\\\\) voltsAs 3 ohm and 6 ohm are connected in parallel, thus voltage across them is equal.\\\\(\ herefore\\\\) Current through 6 ohm, \\\\(I_2 = \\dfrac{V_1}{R_2}=\\dfrac{2.4}{6} =0.4\\\\) ACurrent through 4 ohm resistor \\\\(I' = I_1+I_2 =0.8+0.4 = 1.2\\\\) A\\\\(\ herefore\\\\) Potential drop across 4 ohm, \\\\(V' = I'R_3 = 1.2\ imes 4 = 4.8\\\\) volts