∑i=04​P(xi​)=1⇒8k=1⇒k=81​(i) P(x=1)=81​(ii) P( at most 2 colleges )=P(0)+P(1)+P(2)=85​(iii) P( atleast 2 colleges )=1−[P(x=0)+P(x=1)]=1−81​=87​