For the reaction, A⇌PGiven, T1​T1​T2​​​It shows, On increasing the temperature, K decreases so reaction is exothermic i.e., ΔH∘<0Besides, the graph shows K>1So ΔG∘<0Now from equation (i)T1​lnK1​>T2​lnK2​−ΔG1∘​>−ΔG∘2​​Likewise (−ΔH0+T1​ΔS0)>(−ΔH∘+T2​ΔS∘)or simply T1​ΔS∘>T2​ΔS∘So, (T2​−T1​)ΔS∘<0∴ΔS0<0In other words, increase of ΔG with increase in temperature is possible only when ΔS∘<0. Hence, options (a) and (c) are correct.