Given,\\\\(x-y+1=0\\\\)....(1)\\\\(3x+2y-12=0\\\\)....(2)put \\\\(x=0\\\\) in (1)\\\\(0-y+1=0\\Rightarrow y=1\\\\)\\\\((0,1)\\\\).....(a)put \\\\(y=0\\\\) in (2)\\\\(3x+2(0)-12=0\\rightarrow x=4\\\\)\\\\((4,0)\\\\).....(b)put \\\\(x=0\\\\) in (2)\\\\(3(0)+2y-12=0\\rightarrow y=6\\\\)\\\\((0,6)\\\\)......(c)put \\\\(y=0\\\\) in (1)\\\\(x-0+1=0\\Rightarrow x=-1\\\\)\\\\((-1,0)\\\\)...(d)From figure, the vertices of triangle are \\\\((-1,0),(2,3),(4,0)\\\\)