\\\\(P = VI = {I^2}R\\\\)\\\\(36 = {I^2} \ imes 9\\\\)\\\\(I = 2\\,Amp\\\\)\\\\({I_1} = \\dfrac{{6 \ imes {I_T}}}{{15}}\\\\)\\\\({I_2} = \\dfrac{{9 \ imes {I_T}}}{{15}}\\\\)\\\\(\\dfrac{{{I_1}}}{{{I_2}}} = \\left( {\\dfrac{6}{9}} \\right)\\\\)\\\\(\\dfrac{{2 \ imes 9}}{6} = {I_2} = 3\\,Amp\\\\)\\\\({I_{net}} = \\left( {2 + 3} \\right) = 5\\\\)\\\\({V_{2\\Omega }} = I \ imes R = 5 \ imes 2 = 10\\,Volt\\\\)