Mean of \\\\(100\\\\) terms = \\\\(50\\\\)Sum of \\\\(100\\\\) terms = \\\\(50\ imes 100\\\\) = 5000After replacing a term by \\\\(150\\\\), sum = \\\\(5000 - 50 +150 = 5100\\\\)Mean = \\\\(\\dfrac{5100}{100}= 51\\\\)