We know that the values for a = 12’, b = 5’, and 5 = 5’This means that if we use the centroid of the trapezoid formula, then we will get:X = {b + 2a / 3 (a + b)} x hX = {5 + 2 x 12 / 3 (12 + 5)} x 5X = 2.84Hence, the value of the centroid of the trapezoid is at a distance of 2.84’.