Total charge required \\\\(Q= 2\\mu C = 2\ imes 10^{-6} \\ C\\\\)Charge of one \\\\(\\alpha\\\\) particle \\\\(q = 2e= 2\ imes 1.6\ imes 10^{-19} \\ C\\\\)Charge accumulated per second \\\\(Q' = 10^{12}\ imes 2\ imes 1.6\ imes 10^{-19} \\ C\\\\)So, time taken \\\\(t = \\dfrac{Q}{Q'} = \\dfrac{2\ imes 10^{-6}}{10^{12}\ imes 2\ imes 1.6\ imes 10^{-19}} = 6.25 \\ s\\\\)