Let OA is wall and AB is ladder. In ∆AOB, by Pythagoras theorem AB^2 = OA^2 + OB^2 ⇒〖10〗^2 =8^2 + BO^2 ⇒ 100 = 64 + BO^2 ⇒ BO^2 = 36 ⇒ BO = 6 m Hence, the distance of the foot of the ladder from the base of the wall is 6 m.