Let, 'v' be the velocity attained by stone at time 't'. Thus, acceleration of the body in east direction due to coriolis effect is 2\\omega v . Integrating this acceleration twice w.r.t time, we get the displacement of stone 'y'. Hence, y\\quad =\\quad 2\\omega v\\\\ v\\quad =\\quad gt\\\\ x\\quad =\\quad \\dfrac { g{ t }^{ 2 } }{ 2 } \\\\ \\Rightarrow \\quad y\\quad =\\quad 2\\omega gt\\\\ \\iint { ydt } \\quad =\\quad \\dfrac { \\omega g{ t }^{ 3 } }{ 3 } \\\\ \\Rightarrow \\quad y\\quad =\\quad \\dfrac { \\omega g }{ 3 } { \\left( \\dfrac { 2x }{ g } \\right) }^{ \\dfrac { 3 }{ 2 } }\\quad \\Rightarrow \\quad n\\quad =\\quad 3