Voltage gain $$= \\beta.\\Big(\\cfrac{R_C}{R_B}\\Big)$$ $$V=0.96\\Big(\\cfrac{80}{192}\\Big)$$ $$V=\\cfrac{96×8}{192}=4$$ And power gain of the amplifier is$$\\beta_{ac}.A_v$$ = 0.96 × 4= 3.84