According to de-Broglie relation:\\\\(\\lambda = \\dfrac{h}{p}\\\\)Let, initial momentum \\\\(=p_1\\\\) and associated wavelength is \\\\(\\lambda_1\\\\) and with a decrease in wavelength, momentum will increase.Thus, \\\\(\\Delta p=-P\\\\) and for \\\\(\\Delta \\lambda=\\dfrac {0.5}{100}\ imes \\lambda_1\\\\)Differentiating the de-Broglie relation we get:\\\\(\\dfrac { \\Delta \\lambda }{\\lambda_1}=-\\dfrac{ \\Delta p }{p_1}\\\\)and \\\\(\\dfrac { 0.005\ imes \\lambda_1 }{\\lambda_1}=\\dfrac{ P }{p_1}=\\dfrac{0.5}{100}\\\\)\\\\(p_1=200P\\\\)Option D is correct.