Band gap, \\\\(\\displaystyle E_g = \\dfrac{hc}{\\lambda} = \\dfrac{(6.63 \ imes 10^{-34})(3 \ imes 10^8)}{2480 \ imes 10^{-9} \ imes 1.6 \ imes 10^{-19}} eV = 0.5\\ eV\\\\)