Since charge is in phase difference with current,And thus the equation is in the form of q = q_{max} \\sin (\\omega t + \\phi) Now, capacitor is fully charged initially with 10\\mu C , which is the rms value,Thus peak value q_{max} = 10 \\sqrt 2 Also, Initial phase difference is given by, \ an \\phi = \\dfrac{X_C}{X_L} = \\dfrac{1}{\\omega ^2 \ imes LC} = 1 \ herefore \\phi = \\dfrac{\\pi}{4} Also, \\omega = \\sqrt {\\dfrac{1}{LC}} = 10^4