\\\\(q'=\\dfrac{GM}{R^2}\\\\) \\\\(=\\dfrac{G\ imes 2me}{\\left( 4ve\\right)^2}\\\\) \\\\(=\\dfrac{1}{8}\\dfrac{Gme}{ve^2}\\\\) \\\\(=\\dfrac{g}{8}\\\\)To find \\\\(4\\\\) times the acceleration due to gravity \\\\(=4\ imes \\dfrac{1}{8}g=\\dfrac{g}{2}=\\dfrac{10}{2}\\\\)\\\\(=5m/s^2\\\\)Hence, the answer is \\\\(5m/s^2.\\\\)