Assuming the shaft is mild steel, the minimum required shaft diameter is 48.7 mm. To calculate this result, follow these steps:
Calculate the torque acting on the shaft from the power and shaft speed, using T = 60⋅P/(2π⋅n) = (60 × 20 × 103)/(2π⋅200) = 955 N-m.
Assume the allowable shear stress of mild steel τ = 42 MPa.
Substituting the values in the shaft diameter formula for torsion loads, T = π ⋅τ⋅d3/16, we get: 955 = π × 42 × 106 × d3/16.
Solving this equation, we get d = 0.487 m = 48.7 mm.
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