If the smaller cylinder has a radius of r and a height of h, its volume is πr2h. The larger cylinder therefore must have a radius of 2r and a height of 1.5h, and a volume of π(2r)2(1.5h)=6πr2h. Since this is 6 times the volume of the smaller cylinder, it must hold 10×6=60 ounces of oatmeal.