FalseOn factorising 392 into prime factors, we get:
392 = 2 × 2 × 2 × 7 × 7 On grouping the factors in triples of equal factors, we get: 392 = { 2 × 2 × 2 } × 7 × 7 It is evident that the prime factors of 392 cannot be grouped into triples of equal factors such that no factor is left over. Therefore, 392 is not a perfect cube.