\\\\(Al^{3+} + 3e^-\\rightarrow Al\\\\)The reduction will require 3 Faraday of electricity or \\\\(\\displaystyle 3 \ imes 96500 = 2.895 \ imes 10^5 \\: C\\\\).\\\\(Cu^{2+} + 2e^-\\rightarrow Cu\\\\)The reduction will require 2 Faraday of electricity or \\\\(\\displaystyle 2 \ imes 96500 = 1.93 \ imes 10^5 \\: C\\\\).\\\\({MnO_4}^{-} + 5e^- \\rightarrow Mn^{2+} \\\\)The reduction will require 5 Faraday of electricity or \\\\(\\displaystyle 5 \ imes 96500 = 4.825 \ imes 10^5 \\: C\\\\).Note: 1 mole of electron has a charge of 1 faraday.