Length of a side of the square coil, l = 10 cm = 0.1 m Current flowing in the coil, I = 12 A Number of turns on the coil, n = 20 Angle made by the plane of the coil with magnetic field, θ = 30° Strength of magnetic field, B = 0.80 T Magnitude of the magnetic torque experienced by the coil in the magnetic field is given by the relation, τ = n BIA sinθ Where, A = Area of the square coil = l × l = 0.1 × 0.1 = 0.01 m2 So, τ = 20 × 0.8 × 12 × 0.01 × sin30° = 0.96 N m Hence, the magnitude of the torque experienced by the coil is 0.96 N m.