Canal is in the shape of cuboid , where,Breadth \\\\(= 6\\\\) mHeight \\\\(= 1.5\\\\) mSpeed of canal \\\\(= 10\\\\) km/hrLength of canal in \\\\(1\\\\) hour \\\\(= 10\\\\) kmLength of canal in \\\\(60\\\\) minutes \\\\(= 10\\\\) kmLength of canal in \\\\(1\\\\) minute = \\\\(\\dfrac{1}{60} \ imes 10\\\\) kmLength of canal in \\\\(30\\\\) minute = \\\\(\\dfrac{30}{60} \ imes 10 = 5km=5000\\ m\\\\)Now,Volume of canal = \\\\(length \ imes breadth \ imes height\\\\) = \\\\(5000\ imes 6 \ imes 1.5\\\\) \\\\(m^{3}\\\\)Now,Volume of water in canal = Volume of area irrigatedVolume of water in canal = Area irrigated \\\\(\ imes\\\\) Height\\\\(5000\ imes 6\ imes 1.5 \\\\) = Area irrigated \\\\(\ imes \\dfrac{8}{100}\\\\)Area irrigated = \\\\(\\dfrac{5000 \ imes 6 \ imes 1.5 \ imes 100}{8}\\\\)Area irrigated = \\\\(562500\\\\) \\\\(m^{2}\\\\)Area irrigated = \\\\(\\dfrac{562500}{10000}\\\\) hectaresArea irrigated = \\\\(56.25\\\\) hectares