Let \\\\(a = 404\\\\) and \\\\( b = 96\\\\)Expressing the number as a product of prime number\\\\(404=2\ imes 2\ imes 101\\\\)\\\\(96=2\ imes 2\ imes 2\ imes 2\ imes 2\ imes 3\\\\)\\\\(\ herefore\\\\) LCM of \\\\(404\\\\) and \\\\(96\\\\) is \\\\(2\ imes 2\ imes 2\ imes 2\ imes 2\ imes 101\ imes 3=9696\\\\)\\\\(\ herefore\\\\) HCF of \\\\(404\\\\) and \\\\(96\\\\) is \\\\(2\ imes 2=4\\\\)Now \\\\(HCF \ imes LCM=4\ imes 9696=38784\\\\)Product of two given numbers \\\\(404 \ imes 96=38784\\\\)Hence \\\\(HCM \ imes LCM=\\\\) product of two given numbers.