It is given that two sides of a triangular field are 85m and 154mConsider the third side as x mIt is given that the perimeter =324mWe can write it as85+154+x=324On further calculation we get x=324−85−154By subtractionx=85mConsider a=85m,b=154mandc=85mWe know that S=2a+b+c​S=285+154+85​By divisionS=162mWe know thatArea s(s−a)(s−b)(s−c)​By substituting the values Area=162(162−85)(162−154)(162−85)​So we get Area=162×77×8×77​It can be written asArea=2×9×9×7×11×2×2×2×7×11​On further calculationArea=11×11×9×9×7×7×2×2×2×2​We getArea=11×9×7×2×2By multiplicationArea=2772m2We know thatArea of the triangle =1/2×b×hBy substituting the values1/2×154×h=2772On further calculation77×h=2772So we geth=2772/77By divisionh=36mTherefore, area of the field is 2772m2 and the length of the perpendicular from the opposite vertex on the side measuring 154m is 36m.