Let the speed of the flow be V.The diameter of the tap = d = 1.25 cm = 1.25 \\\\(\ imes 10^{-2}\\\\) m Density of water = \\\\(\\rho = 10^3 kg\\\\) \\\\( m^{-3}\\\\)viscosity = \\\\(\\eta = 10^{-3}\\\\) Pa sThe volume of the water flowing out per second is Q = \\\\(V \ imes \\frac{\\pi d^2}{4}\\\\) V = \\\\(\\frac{4Q}{d^2\\pi}\\\\)The Reynolds number is given by R = \\\\(\\frac{\\rho Vd}{\\eta}\\\\) = \\\\(\\frac{4\\rho Q}{\\pi d \\eta}\\\\) = \\\\(\\frac{4 \ imes 10^3 \ imes Q}{3.14 \ imes 1.25 \ imes 10^{-2} \ imes 10^{-3}}\\\\) = \\\\(1.019 \ imes 10^8 Q\\\\)Hence the flow is turbulent.