Given, \\\\(A = \\{1, 2, 3, 4, 5\\}, B = \\{2, 4, 6, 8\\}\\\\) and \\\\(C=\\{3,4,5,6\\}\\\\)For the LHS:Union of two sets will have the elements of both sets.So, \\\\( B \\cup C = \\{2,3,4,5,6,8 \\}\\\\) \\\\( A - (B \\cup C) \\\\) will have elements of \\\\(A\\\\) which are not in \\\\( (B \\cup C) \\\\)So, \\\\( A - (B \\cup C) = \\{ 1 \\}\\\\) ..... \\\\((1)\\\\)For the RHS:\\\\( A - B \\\\) will have elements of \\\\(A\\\\) which are not in \\\\(B\\\\).So, \\\\( A - B = \\{ 1,3,5 \\}\\\\) \\\\( A - C \\\\) will have elements of \\\\(A\\\\) which are not in \\\\(C\\\\).So, \\\\( A - C = \\{ 1,2 \\}\\\\) Intersection of two sets has the common elements of both the sets. \\\\(\\Rightarrow (A - B) \\cap (A - C) = \\{1\\}\\\\) ..... \\\\((2)\\\\)From \\\\((1)\\\\) and \\\\((2),\\\\) we have\\\\( A - (B \\cup C) =(A - B) \\cap (A - C) \\\\)Hence, the given expression is true.