Ans. Given h1 = 25 – 15 = 10 cm = 0.10 m             H2  = 25 cm = 0.25 m               S1 = 0.85                S2 = 13.6 Let Pa be pressure intensity in the pipe and let it be expressed in term of water column.       pressure at B = pressure at C                 Pa/w + s1h1 = s2h2                               Pa/w = s2h2 - s1h1                                            = 13.6 * 0.25 – 0.85 * 0.10                                           = 3.315 m of equivalent water column                            Pa/w = w * 3.315                                  = 9.81 * 3.315                                       = 32.52 kN/m2                                        = 32.52 Kpa (kilo pascal)