As per the per the law of motion v^2 = u^2 - 2gs
S= ut +1/2 at^2
S= 9
G= 10 ms^-2
S
T =✓2s /g
✓2*9/10
1.34 s
Horizontal distance covered = it = 9*1.34.>10 m
So the person would land safely