The aromatic compound \\\\(A\\\\) is benzoic acid \\\\(\\displaystyle C_6H_5COOH\\\\).On treatment with aqueous ammonia and heating forms compound B, which is benzamide \\\\(\\displaystyle C_6H_5CONH_2\\\\).Benzamide on heating with bromine and \\\\(KOH\\\\) forms a compound \\\\(C\\\\) of molecular formula \\\\(\\displaystyle C_6H_7N\\\\), which is aniline \\\\(\\displaystyle C_6H_5NH_2\\\\). The reaction is called Hoffmann bromamide degradation.