Correct Option: C Explanation: In bivalent condition, there are two chromosomes present with their homologous pair.So, 8 bivalents in metaphase I contains 16 chromosomes.Meiosis I is a reduction division and therefore the number of chromosomes is halved to 8 chromosomes.Meiosis II is an equational division and therefore the number of chromosomes remains same, that is, 8 chromosomes. Hence, if the number of bivalents is 8 in metaphase I, the number of chromosomes in daughter cells after meiosis I and meiosis II respectively will be 8 and 8.