The magnifying power of a telescope is given by\\\\(m = \\dfrac{f_0}{f_e}, \\, 5 = \\dfrac{f_0}{f_e}\\\\)\\\\(f_0 + f_e = 60\\\\) [The total length of the telescope is \\\\(60cm\\\\)]And \\\\(f_0 = 5f_e\\\\)\\\\(\ herefore f_0 + f_e = 5f_0, \\, 6f_e = 60, f_e = 10cm\\\\)\\\\(f_0 = 5f_e = 50cm\\\\)\\\\(\ herefore\\\\) The focal length of the eyepiece is \\\\(f_e = 10cm\\\\)