We have average velocity \\\\(= \\dfrac{g}{2}\\\\) Since it is a free fall, average velocity, \\\\(v=\\dfrac{S}{t}= \\dfrac{\\dfrac{1}{2}gt^2}{t} = \\dfrac{g}{2}\\\\), where \\\\(t\\\\) is the time of descent and initial velocity is zero.We know that for a free fall, velocity with which it reaches the ground: \\\\(V = gt\\\\), where \\\\(t\\\\) is time of descent . Substituting the same in the above equation for average velocity: \\\\(\\dfrac{V}{2} = \\dfrac{g}{2} \\\\)\\\\(\ herefore V=g\\\\)