In the given polynomial \\\\(3x^2-x-4\\\\),The first term is \\\\(3x^2\\\\) and its coefficient is \\\\(3\\\\).The middle term is \\\\(-x\\\\) and its coefficient is \\\\(-1\\\\).The last term is a constant term \\\\(-4\\\\).Multiply the coefficient of the first term by the constant \\\\(3\ imes -4=-12\\\\).We now find the factor of \\\\(-12\\\\) whose sum equals the coefficient of the middle term, which is \\\\(-1\\\\) and then factorize the polynomial \\\\(3x^2-x-4\\\\) as shown below: \\\\(3x^{ 2 }-x-4\\\\ =3x^{ 2 }+3x-4x-4\\\\ =3x(x+1)-4(x+1)\\\\ =(3x-4)(x+1)\\\\)Hence, \\\\(3x^{ 2 }-x-4=(3x-4)(x+1)\\\\).