When a die is thrown , the possible outcomes are 1,2,3,4,5 or 6.So, U=S={1,2,,4,5,6}(i) A={1,2,3,4,5, 6}  (ii)B=ϕ(iii)C={3,6}(iv)D={1,2,3}(v)E={6}(vi)F={4,5,6}Now, A∪B={1,2,3,4,5, 6}  A∩B=ϕB∪C={3,6}E∩F={6}D∩E=ϕA−C={1,2,4,5}D−E={1,2,3}E∩F′=E−F=ϕF′=U−F={1,2,3}