Arranging the given data in ascending order\\\\(13,13,13,13,14,14,15,15,15,15\\\\)\\\\(n=10\\\\)mean\\\\(=\\cfrac { 4(13)+2(14)+4(15) }{ 10 } =14\\\\) yearsAs \\\\(n\\\\) is even, median\\\\(=\\cfrac { 4th+5th }{ 2 } \\\\)value\\\\(=14\\\\) years\\\\(13\\\\) and \\\\(15\\\\) both have the highest frequencies of \\\\(4\\\\)It is a bimodal set of data.mean\\\\(=14\\\\);median\\\\(=14\\\\);mode\\\\(=13,15\\\\)