Let the length of equal sides be x cm.
Perimeter = x cm + x cm + Base = \\(4 \\frac{2}{15}\\) cm
\\(2 x+\\frac{4}{3}=\\frac{62}{15}\\)
On transposing \\(\\frac{4}{3}\\) to R. H.S, we obtain
\\(\\begin{array}{l}{2 x=\\frac{62}{15}-\\frac{4}{3}} \\\\ {2 x=\\frac{62-4 \ imes 5}{15}=\\frac{62-20}{15}} \\\\ {2 x=\\frac{42}{15}} \\\\ {\ ext { On dividing both sides by } 2, \ ext { we obtain }} \\\\ {\\frac{2 x}{2}=\\frac{42}{15} \ imes \\frac{1}{2}} \\\\ {x=\\frac{7}{5}=1 \\frac{2}{5}}\\end{array}\\)
Therefore, the length of equal sides is \\(1 \\frac{2}{5}\\) cm