Given: $$I = 0.5sin 314 t$$        ...(i) Standard equation of current is $$I=I_{0}sin omega t$$       ...(ii) Comparing (i) and (ii), we get $$I_{0} = 0.5A$$, $$omega = 314$$ $$ herefore $$ Frequency $$
u = dfrac{omega}{2pi} = dfrac{314}{2 imes 3.14} = 50 Hz$$