We know,According to Kepler's law, time taken to complete a path in an elliptical orbit is directly proportional to the area swept from the focus as the centre. A\\propto t A_{SAB}\\propto t_2 A_{SCD}\\propto t_1 Given, \\dfrac{A_{SAB}}{A_{SCD}}=\\dfrac{1}{2} \\dfrac{t_2}{t_1}=\\dfrac{1}{2} t_1=2t_2 Option \ extbf B is the correct answer