Consumption (in unit)Frequency ficf65−854485−10559105−1251322125−1452042145−1651456165−185763185−205467Sum 67Where cf= cumulative frequencyMedian =1+⎩⎨⎧​h×f(2N​−cf)​⎭⎬⎫​HereN=67N/2=33.5cf just greater than 33.5 is 42Median class =125−145So, I=125, h=20, f=20 andcf=cf of preceding class i.e 22Substitute all the value in the above formula, we getMedian =125+{20×(33.5−22)/20}=125+11.5=136.5Thus, median of electricity consumed is 136.5.