a). the total resistance of the circuit =\\\\(20\\Omega +4 \\Omega = 24\\Omega \\\\)b). The current through the circuit= current through the bulb= current through the conductor.The current through the circuit= \\\\(\\dfrac{voltage\\ applied}{Total\\ Resistance}.\\\\)the current through the circuit \\\\(=\\dfrac{6}{24}amp\\\\)The current through the circuit = \\\\(0.25amp\\\\)c). The potential difference across the lamp and the conductor.(i) The potential difference across the electrical lamp \\\\(=0.25\ imes 20= 5 volt\\\\)(ii) The potential difference conductor \\\\(=0.25 \ imes 4= 1 \\ volt\\\\)d). Power can be calculated as \\\\(\\dfrac{voltage \\ across\\ the \\ lamp}{current\\ through\\ the\\ lamp}\\\\) power=\\\\(\\dfrac{5}{0.25}\\rightarrow 20 W\\\\).