Given side of square \\\\(=10 m\\\\), thus perimeter \\\\(P=40 m\\\\)Time taken to cover the boundary of 40 m =40 sThus in 1 second, the farmer covers a distance of 1 mNow distance covered by the farmer in 2 min 20 seconds = \\\\(1\ imes 140=140 m\\\\)Now the total number of rotation the farmer makes to cover a distance of 140 meters =\\\\(\\dfrac{total\\quad distance }{perimeter}\\\\)\\\\(=3.5\\\\) At this point, the farmer is at a point say B from the origin OThus the displacement \\\\(s=\\sqrt{{10}^{2}+{10}^{2}}\\\\) from Pythagoras theorem.s=\\\\(10\\sqrt{2}=14.14 m\\\\)