years or 687 days, knowing that the semi-major axis of Mars is 1.52 au and the mass of the Sun is 2×10³⁰ kg. To find it:
Use Kepler's third law:
T² = 4π²a³/GM.
Square the equation:
T = √(4π²a³/GM).
Convert 1.52 au to meters:
1.52×149,597,870,700 m = 227,388,763,464 m.
Calculate the T:
T = √(4×(3.14)²×(227,388,763,464)³/6,67×10⁻¹¹×2×10³⁰) = 5.93×10⁷ s ≈ 687 days.
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