Given, Area of cross-section of coil A=10^{-3}m^2 The length of the solenoid l=31.4cm=31.4\ imes 10^{-2}m and the number of turns in the coil n=10^3 Magnetic flux linked with the coil \\phi = Li BA=Li \\mu_0ni\\,A=Li L=\\mu_0N/lA L=\\displaystyle\\frac{4\\pi\ imes 10^{-7}\ imes 10^3\ imes 10^{-3}}{31.4\ imes 10^{-2}} =4mH