Let AC be the ladder and A be the window.Given: \\\\(AC=15\\\\)m, \\\\(AB=12\\\\)m, \\\\(CB=a\\\\)mIn right angled triangle ACB,\\\\((Hypotenuse)^2=(Base)^2+[Perpendicular)^2\\\\) [By Pythagoras theorem]\\\\(\\Rightarrow (AC)^2=(CB)^2+(AB)^2\\\\)\\\\(\\Rightarrow (15)^2=(a)^2+(12)^2\\\\)\\\\(\\Rightarrow 225=a^2+144\\\\)\\\\(\\Rightarrow a^2=225-144=81\\\\)\\\\(\\Rightarrow a=\\sqrt{81}=9\\\\)cmThus, the distance of the foot of the ladder from the wall is \\\\(9\\\\)m.