\\\\( K.E = \\dfrac{1}{2}mv^2\\\\)\\\\( K.E \\propto m \\\\) & \\\\( K.E \\propto v^2 \\\\)So doubling mass will double the kinetic energy and doubling speed will make kinetic energy \\\\(4\\\\) times.\\\\( \ herefore \\\\) The K.E. of a body can be increased maximum by doubling its speed.