Given Charge \\\\(q=3.5\ imes 10^{-9}\\\\)Let the \\\\(nQ\\\\) of electron to be removed be \\\\(n\\\\)We know that \\\\(Q=ne\\\\)\\\\(n=\\dfrac{Q}{e}\\\\)\\\\(n=\\dfrac{3.5\ imes 10^{-9}}{1.6\ imes 10^{-19}}\\\\)\\\\(n=2.1875\ imes 10^{-9+19}\\\\)\\\\(n=2.1875\ imes 10^{10}\\\\)