The torque acting on each of the points X, Y and Z are in anticlockwise direction and equal in magnitude.\\\\(\ au_{total} = 3FR\\sin 30^o=\\dfrac{3FR}{2}\\\\)Moment of inertia \\\\(I=\\dfrac{MR^2}{2}\\\\)\\\\( \ herefore \ au_{total} = I\\alpha = \\dfrac{MR^2}{2}\\alpha= \\dfrac{3FR}{2}\\\\)\\\\( \ herefore \\dfrac{1.5 \ imes (0.5^2)}{2}\\alpha= \\dfrac{3 \ imes 0.5\ imes 0.5}{2}\\\\)\\\\( \\Rightarrow \\alpha =2\\\\)From rotational kinematics equation \\\\(\\omega = \\omega_0 + \\alpha t\\\\) At \\\\(t=1s\\\\)\\\\( \ herefore \\omega = 2t = 2 \ imes 1 =2 \\:rad/s\\\\)