Exp. (d)Since, the frequency of ultraviolet light is less than the frequency of X-rays, the energy of each incident photon will be more for X-raysKEphotoelectron​=hv−ϕStopping potential is to stop the fastest photoelectronV0​=ehv​−eϕ​So, KEmax​ and V0​ both increases.But KE ranges from zero to KEmax​, because of loss of energy due to subsequent collisions before getting ejected and not due to range of frequencies in the incident light.