Let us consider the sum of two angles as ∠ A+∠ B=116∘ and the difference can be written as ∠ A−∠ B=24∘We know that the sum of all the angles in a triangle is 180∘.So we can write it as∠ A+∠ B+∠ C=180∘By substituting ∠ A+∠ B=116∘ in the above equation116∘+∠ C=180∘On further calculation∠ C=180∘−116∘By subtraction∠ C=64∘It is given that ∠ A−∠ B=24∘It can be written as ∠ A=24∘+∠ BNow by substituting ∠ A=24∘+∠ Bin∠ A+∠ B=116∘∠ A+∠ B=116∘24∘+∠ B+∠ B=116∘On further calculation24∘+2∠ B=116∘By subtraction2∠ B=116∘−24∘2∠ B=92∘By division∠ B=292​∠ B=46∘By substituting ∠ B=46∘ in ∠ A=24∘+∠ BWe get∠ A=24∘+46∘By addition∠ A=70∘Therefore, ∠ A=70∘,∠ B=46∘ and ∠ C=64∘.