Here, we need to find differences between the given numbers. If two numbers give the same remainder when divided by some other number, then their difference must give a remainder of zero when divided by that number.Our numbers here are \\\\(91-43=48, 183-91=92, 183-43=140\\\\) So we have the set of numbers \\\\(\\{48, 92, 140\\}\\\\) and we want to know the biggest number that divides all these numbers. So,\\\\(48=2 \ imes 2 \ imes 2\ imes 3\\\\)\\\\(92=2 \ imes 2 \ imes 23\\\\)\\\\(140=2 \ imes 2 \ imes 5\ imes 7\\\\)The greatest common divisor of \\\\(\\{48, 92, 140\\}\\\\) is \\\\(4.\\\\) So, answer is \\\\(4.\\\\)