Let A be the set of people who read newspaper H.Let B be the set of people who read newspaper T.Let C be the set of people who read newspaper I.Given \\\\(n(A)=25, n(B)=26\\\\), and \\\\(n(C)=26\\\\)\\\\(n(A\\cap C)=9, n(A\\cap B)=11\\\\), and \\\\((B\\cap C)=8\\\\)\\\\(n(A\\cap B\\cap C)=3\\\\)Let U be the set of people who took part in the survey.(i) \\\\(n(A\\cup B\\cup C)=n(A)+n(B)+n(C)-n(A\\cap B)-n(B\\cap C)-n(C\\cap A)+n(A\\cap B\\cap C)\\\\)\\\\(=25+26+26-11-8-9+3\\\\)\\\\(=52\\\\)Hence, 52 people read at least one of the newspaper.(ii) Let a be the number of people who read newspapers H and T only.Let b denote the number of people who read newspapers I and H only.Let c denote the number of people who read newspaper T and I only.Let d denote the number of people who read all three newspaper.Accordingly, \\\\(d=n(A\\cap B\\cap C)=3\\\\)Now, \\\\(n(A\\cap B)=a+d\\\\)\\\\(n(B\\cap C)=c+d\\\\)\\\\(n(C\\cap A)=b+d\\\\)\\\\(\ herefore a+d+c+d+b+d=11+8+9=28\\\\)\\\\(\\Rightarrow a+b+c+d=28-2d=28-6=22\\\\)Hence, \\\\((52-22)=30\\\\) people read exactly one newspaper.