If any digit has the last digit \\\\(10\\\\) that means it divisible by \\\\(10.\\\\)The factor of \\\\(10 = 2 \ imes 5,\\\\) So value of \\\\(6^n\\\\) should be divisible by \\\\(2\\\\) and \\\\(5.\\\\)Both \\\\(6^n\\\\) is divisible by \\\\(2\\\\) but not divisible by \\\\(5.\\\\)So, it can not end with \\\\(0.\\\\)