Given a Rectangular piece of paper \\\\(11 cm\ imes 4 cm\\\\) is folded without overlapping to make a cylinder of height 4 cmThe length of the paper becomes the circumference of the base of the cylinder and width becomes height.Let radius of the cylinder\\\\( = r\\\\) and height\\\\( = h\\\\)Circumference of the base of cylinder \\\\(=2 \\pi r = 11 cm\\\\)\\\\(\\Rightarrow 2 \ imes \\dfrac{22}{7} \ imes r = 11\\\\)\\\\(\ herefore r = \\dfrac{7}{4} cm\\\\) Now \\\\(h = 4 cm\\\\)Volume of the cylinder \\\\((V) = \\pi r^2 h\\\\)\\\\(= \\dfrac{22}{7} \ imes \\dfrac{7}{4} \ imes \\dfrac{7}{4} \ imes 4 cm^3\\\\)\\\\(= 38.5 cm^3\\\\)