The trickiest part of this question is its wording. This problem is asking for the height of the water in the exhibit if the exhibit is three-quarters full. There are several ways in which you can solve this problem; we'll go over two of them in detail.1. Find the fraction of the volume, then the height We can begin by finding three-quarters of the total volume:150 m3⋅43​=112.5 m3Knowing this, we can go back to our volume equation. Since we are again looking for height, we want to solve for h, so we can rearrange the equation to make this easier:V=l⋅w⋅h→l⋅wV​=hNow we can plug in our known variables, including the three-quarters-of-the-total height that we solved for, and solve for three-quarters of the total height.h=15 m⋅5 m112.5 m3​=1.5 m2. Find the height, then the fraction of itAn easier way to solve this problem requires that we recognize a key detail. If we take three-quarters of the volume without changing our length or width, our new height will just be three-quarters of the total height. We can solve for the total height of the exhibit by using the volume equation and rearranging it to solve for h :l⋅wV​=hAt this point, we can substitute in our given values and solve for h :15 m⋅5 m150 m3​=2 mSo, the total height of the exhibit is 2 m. We can now easily solve for three-quarters of the total height:hh​=h⋅43​=2 m⋅43​=1.5 m​