Oxidizing nature of \\\\(H_2O_2\\\\) means it oxidizes other substance and itself gets reduced. In such reactions \\\\(O_2\\\\) is not evolved. In (A), \\\\(MnO_4^-\\\\) gets reduced from \\\\(Mn^{7+}\\\\) to \\\\(Mn^{2+}.\\\\)In (B), \\\\(Fe^{3+}\\\\) gets reduced to \\\\(Fe^{2+} \\\\).In (C), \\\\( I^-\\\\) gets oxidised to \\\\(I_2 \\\\)In (D), \\\\(KIO_4\\\\) gets reduced from \\\\(I^{7+}\\\\) to \\\\(I^{5+} \\\\) Option C is correct.