Given that,
Initial pressure P1 = 2 atm
Initial temperature T1 = 250 K
Final temperature T2 = 1000 k
The Gay-LussacΓÇÖs Law formula to calculate the final pressure is P2 = (P1T2)/T1
= (2 * 1000)/250 = 2000/250 = 8
Therefore, final pressure is 8 atm.