Given a box of oranges.Let A, B and C denotes respectively the events that the first, second and third drawn orange is good.Now, P(A)=P (good orange in first draw) =12 / 15Because the second orange is drawn without replacement so, now the total number of good oranges will be 11 and total oranges will be 14 that is the conditional probability of B given that A has already occurred.Now, P(B / A)=P (good orange in second draw) =11 / 14 Because the third orange is drawn without replacement so, now the total number of good oranges will be 10 and total orangs will be 13 that is the conditional probability of C given that A and B has already occurred.Now, P(C / A B)=P (good orange in third draw) =10 / 13Thus the probability that all the oranges are good⇒P(A∩B∩C)=12/15×11/14×10/13=44/91 Hence, the probability that a box will be approved for sale =44 / 91