Consider a = 91m, b = 98m and c = 105mSo we getS=2a+b+c​S=291+98+105​By divisions=147We know thatArea=s(s−a)(s−b)(s−c)​By substituting the valuesArea=  ​147(147−91)(147−98)(147−105) So we getArea=  ​147×56×49×42 It can be written as Area=  ​49×3×7×2×2×2×49×7×3×2 On further calculationArea =49×3×2×2×7So we getArea =4116m2It is given as b = Longest side = 105mConsider h as the height corresponding to the longest sideWe know thatArea of the triangle = 1/2×b×hBy substituting the values1/2× b × h =4116On further calculation105×h=4116×2So we get h=(4116×2)/105By divisionh = 78.4m