Let \\\\(AB=10m,\\\\) cliff of a ship where man is standingLet \\\\(CE\\\\) be the hill.\\\\(CD=AB=10m\\\\)In \\\\(\ riangle ADE\\\\) \\\\(\ an 60°=\\cfrac { h }{ x } \\\\)\\\\(\\sqrt{3}x=h\\\\)\\\\(x=\\cfrac{h}{\\sqrt{3}}\\longrightarrow (1)\\\\)In \\\\(\ riangle ABC\\\\) \\\\(\ an 30°=\\cfrac { 10 }{ x } \\\\)\\\\(\\cfrac { 1 }{ \\sqrt { 3 } } =\\cfrac { 10 }{ x }\\\\)\\\\(x = 10 \\sqrt{3} \\longrightarrow (2)\\\\)We have two equations \\\\((1)\\\\) & \\\\((2)\\\\), Multiplying them we get,\\\\(x^2 =10h\\\\)\\\\(h=30m\\\\)\\\\(\ herefore CE=CD+DE=10+30=40m\\\\)