Distance of point P from plane =5∴⇒​5=∣∣​31−4−2−α​∣∣​α=10​Foot of perpendicular1x−1​⇒x​=2y+2​=−2z−1​=35​=38​,y=34​,z=−37​​Thus, the foot of the perpendicular is A(38​,34​,−37​).