Increase in volume of vessel = Increase in volume ofliquid {\\gamma}_1 \ imes V_1 = {\\gamma}_2 \ imes V_2 \ herefore \\dfrac{{\\gamma}_1}{{\\gamma}_2}= \\dfrac{V_2}{V_1}=\\dfrac{\\frac{1}{10}}{\\dfrac{1}{8}}=\\dfrac {8}{10}=\\dfrac {4}{5}