The atomic weight of carbon = 12 g and the given weight = 12 gAs we know that, \\\\(\ ext{No. of moles} = \\cfrac{\ ext{Given weight}}{\ ext{Molecular weight}}\\\\)\\\\(\ herefore\\\\) No. of moles of Carbon in 12 g \\\\(= \\cfrac{12}{12} = 1 \ ext{ mole}\\\\)No. of atoms present in 1 mole of Carbon \\\\(= {N}_{A} = 6.023 \ imes {10}^{23}\\\\)As 1 mole of carbon contains 6 electrons, 6 protons and 6 neutrons.\\\\(\ herefore \ ext{ No. of electrons in }6.023 \ imes {10}^{23} \ ext{ atoms of carbon} = 6 \ imes 6.023 \ imes {10}^{23}\\\\)Similarly,\\\\(\ ext{No. of protons in }6.023 \ imes {10}^{23} \ ext{ atoms of carbon} = 6 \ imes 6.023 \ imes {10}^{23}\\\\)\\\\(\ ext{No. of neutrons in }6.023 \ imes {10}^{23} \ ext{ atoms of carbon} = 6 \ imes 6.023 \ imes {10}^{23}\\\\)\\\\(\ herefore\\\\) Sum of electrons, protons and neutrons in 12g of carbon = no. of electrons in 12 g carbon + no. of protons in 12 g carbon + no. of neutrons in 12 g carbon\\\\( = 6 \ imes 6.023 \ imes {10}^{23} + 6 \ imes 6.023 \ imes {10}^{23} + 6 \ imes 6.023 \ imes {10}^{23}\\\\)\\\\(= 108.414 \ imes {10}^{23} = 1.084 \ imes {10}^{25}\\\\)So, the correct option is \\\\(C\\\\)