Given that 50 circular plates each with diameter = 14cmRadius of circular plates (r) = 7cmThickness of plates= 0.5Since these plates are placed one above other so total thickness of plates = 0. 5 x 50= 25cm.Total surface area of acylinder = 2πrh + 2πr2= 2πrh + 2πr2= 2πr (h+r)= 2 x 22/7 x 7(25+7)T.S.A = 1408cm2∴Total surface area of circular plates is 1408cm2