Let the polynomial be ax3+bx2+cx+d and the zeroes be α,β,γ.Sum of the polynomial = α+β+γ=12​=a−b​Sum of the product of its zeroes taken two at a time = αβ+βγ+αγ=1−7​=ac​Product of the root = αβγ=1−14​=a−d​If a=1,b=−2,c=−7,d=14.Hence the polynomial is  x3−2x2−7x+14