Given:Diagonal =32cm , Base=8cm , side=6cm⇒Area of square =21​×(d)2=21​×(32)2=512cm2⇒Area of shaded portion I= Area of shaded portion II⇒ 2512​=256cm2∴ Area of paper required =256  cm2⇒For triangle III region⇒S=26+6+8​=10cm$$\\Rightarrow A=\\sqrt { s(s-a)(s-b)(s-c) }\\ \\  $$⇒Area =10(10−6)(10−6)(10−8)​=10×4×4×2​   cm2⇒A=4×25​cm2=17.92  cm2Area of paper required for III triangle shade=17.92  cm2