The radius has a ratio of \\\\(2:1\\\\), therefore the cross-sectional area is of ratio \\\\(4:1.\\\\) The resistance per unit length is therefore \\\\( 1:4.\\\\) Because we are told the mass is the same, wire \\\\(B\\\\), the smaller section wire will have to be \\\\(4\\\\) times as long to have the same mass, neglecting the effects of any insulation on the mass. So the final resistance of \\\\( B\\\\) will be \\\\(16\\\\) times the resistance of \\\\(A\\\\) or \\\\(544\\\\) Ohms.