To find the bowl segment thickness to make a segmented wood bowl with a finished outer diameter of 10 inches (or outer radius of 5 inches) and a bowl thickness of 0.5 inches using 8 segments:
First, we divide 180° by 8 segments to get:
180° / 8 = 22.5°
Then we take the inner radius of our finished bowl to be:
5 inches − 0.5 inches = 4.5 inches
Finally, we use the following equation to find the minimum segment thickness we need as follows:
thickness = outer radius − cos(α) × inner radius
thickness = 5 inches − cos(22.5°) × 4.5 inches
thickness = 0.843 inches
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