(i) inner curved surface areaAccording to the question inner diameter is 4 cm,then,Inner radius of a cylindrical pipe \\\\( = {r_1} = \\dfrac{{innner\\,diameter}}{2} = \\left( {\\dfrac{4}{2}} \\right)cm = 2cm\\\\)Height (h) of cylindrical pipe=77 cm,Curved Surface Area of inner surface of pipe \\\\(=2\\pi {r_1}h\\\\)\\\\(=\\left( {2 \ imes \\dfrac{{22}}{7} \ imes 2 \ imes 77} \\right)c{m^2}\\\\)\\\\(=968\\,c{m^2}\\\\)(ii) Outer curved surface areaAccording to the question outer diameter is 4.4 cmOuter radius of cylindrical pipe \\\\( = {r_2} = \\dfrac{{outer\\,diamterer}}{2} = \\left( {\\dfrac{{4.4}}{2}} \\right)\\,cm\\, = \\,2.2\\,cm\\\\)Height of cylinder = h = 77 cm,Curved area of outer surface of pipe = \\\\(2\\pi {r_2}h\\\\)\\\\(=\\left( {2 \ imes \\dfrac{{22}}{7} \ imes 2.2 \ imes 77} \\right)c{m^2}\\\\)\\\\(=\\left( {2 \ imes 22 \ imes 2.2 \ imes 11} \\right)\\,c{m^2}\\\\)\\\\(=1064.8\\,c{m^2}\\\\)(iii) Total surface areaTotal surface area = curved surface area of inner cylinder + curved surface of outer cylinder + 2 \\\\( \ imes \\\\) Area of baseArea of base = area of circle with radius 2.2 cm - Area of circle with radius 2 cm\\\\(=\\pi {r_2}^2 - \\,\\pi {r_1}^2\\\\)\\\\(=\\dfrac{{22}}{7} \ imes ({(2.2)^2} - {(2)^2})\\\\)\\\\(=\\dfrac{{22}}{7} \ imes (4.84 - 4)\\\\)\\\\(=\\dfrac{{22}}{7} \ imes (0.84)\\\\)\\\\(=2.74\\,c{m^2}\\\\)Total surface area = curved surface area of inner cylinder + curved surface area of outer cylinder + 2 \\\\( \ imes \\\\) Area of base\\\\( = \\,968\\,+ \\,1064.8\\,+\\,2\\, \ imes \\,2.74\\\\)\\\\(=\\\\) 2032.8 + 5.76\\\\( = 2039.08\\,c{m^2}\\\\)Therefore, the total surface area of the cylindrical pipe is \\\\( = 2039.08\\,c{m^2}\\\\)