The mass of water required to make a solution with 5.6 g of CH3COOH and the mass percentage of 9.8% is 51.54 g. To find it:
Use the formula for mass percent of solute in a solvent:
mass percent = (mass of solute / mass of solution) × 100
Rearrange it to calculate the mass of the solution:
mass of solution = (mass of solute / mass percent) × 100
Subtract the mass of solute from the mass of solution:
mass of solvent = mass of solution - mass of solute.
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