From the point C construct CE || DAWe know that ADCE is a parallelogram having AE || DC and AD || EC with AD = 13m and D = 11mIt can be written asAE = DC = 11m and EC = AD = 13mSo we getBE = AB - AEBy substituting the valuesBE = 25 –-11 = 14mConsider Δ BCEWe know that BC = 15m, CE = 13m and BE = 14mTake a = 15m, b = 13m and c = 14mSo we gets=2a+b+c​By substituting the valuess=215+13+14​So we gets=21mWe know thatArea=s(s−a)(s−b)(s−c)​By substituting the valuesArea=21(21−15)(21−13)(21−14)​So we getArea=21×6×8×7​It can be written asArea=7×3×2×3×4×2×7​We getArea=7×3×2×2So we get Area=84cm2We know thatArea of △ BCE = 21​×BE×CLBy substituting the values84=21​×14×CLOn further calculation84=7×CLBy divisionCL = 12mWe know thatArea of trapezium ABCD =21​× sum of parallel sides × heightIt can be written asArea of trapezium ABCD = 21​×(AB+CD)×CLBy substituting the valuesArea of trapezium ABCD = 21​×(11+25)×12On further calculationArea of trapezium ABCD = 36×6By multiplicationArea of trapezium ABCD = 216m2Therefore, the area of trapezium ABCD is 216m2.