Mass of the sphere = m Radius = R h = height of the floorThe sphere will roll without slipping when, w \\dfrac{v}{R} Where, v = linear velocity of the sphere w = angular velocity of the sphere.Now, angular momentum of sphere, about centre of mass (applying conservation of angular momentum just before and after struch) mv (h - R) = I w = \\left(\\dfrac{2}{5} mR^2\\right) \\left(\\dfrac{v}{R}\\right) \\Rightarrow mv (h - R) = \\dfrac{2}{5} mvR \\Rightarrow h - R = \\dfrac{2}{5} R \\Rightarrow h = \\dfrac{7}{5} R Therefore, the sphere will roll without slipping with a constant velocity and hence, no loss of energy when h = \\dfrac{7}{5} R So, (D) matches (1)Now, Torque due to applied force about C.M., \ au = F (h - R) [Clockwise]For \ au = 0, h = R sphere will have only translational motion. It would lose energy by friction.Hence, (B) matches with (4).If h > R, \ au \\rightarrow positive, sphere will spin clockwise.So, (C) matches with (2)If h < R, \ au \\rightarrow negative, sphere will spin anticlockwise.So, (A) matches with (3).