(i) The HCF of 36 and 24 is 12.Thus, its standard form would be obtained by dividing by −12−2436​=−24÷(−12)36÷(−12)​=2−3​(ii) The HCF of 3 and 15 is 3 .Thus, −15−3​=−15÷(−3)−3÷(−3)​=51​