At infinity, the gravitational potential energy of the system will be \\\\(0\\\\).Initially, the particle is outside sphere and hence sphere will behave as point object at its centre,Therefore,\\\\({ E }_{ 0 }=-\\dfrac { GMm }{ R } =-\\dfrac { (6.67\ imes { 10 }^{ -11 })\ imes(100)\ imes(0.01) }{ 0.1 } =-6.67\ imes{ 10 }^{ -10 }J\\\\)We know that, \\\\(W=\\Delta U=U_{f}-U_{i} \\implies W=-U_{i}\\\\)Thus, work done is \\\\(6.67\ imes { 10 }^{ -10 }J\\\\)