# Behaviors of Thin-Walled Cylindrical Shell Storage Tank under Blast Impacts

Authors: Shengzhuo Lu; Wei Wang; Weidong Chen; Jingxin Ma; Yaqin Shi; Chunlong Xu
Journal: Shock and Vibration
 (2019)

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## Abstract

Large steel storage tanks designed with long-span structures, employed for storing oil and fuel, have been widely used in many countries over the past twenty years. Most of these tanks are thin-walled cylindrical shells. Owing to the high risk of gas explosions and the resulting deaths, injuries, and economic losses, more thorough damage analyses of these large structures should be conducted. This study examines the structural response of a simplified steel storage tank under a blast impact, as calculated by the LS-DYNA software package. The numerical results are then compared with a scale-model experiment. On that basis, the simplified storage tank prototype, which has a 15 × 104 m3 capacity, is analyzed using numerical simulation. In this study, we address issues around the variation in structural responses—particularly of the failure mode, resultant displacement, structural energy, and dynamic strain under the impact. In addition, we also discuss the effects of varying the internal liquid level, constraint conditions, and blast intensity.


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## Body

## 1. Introduction

In the past twenty years, explosions caused by combustible gas from oil, petroleum, or chemical products have been reported frequently, both in China and elsewhere. These disasters, which have caused severe casualties and considerable property damage, have typically occurred in tank farms and oil depots where many storage tanks can be damaged [1, 2].In 2005, a combustible air cloud, with thickness reaching up to 2 meters, was formed in Buncefield Oil Storage Depot in Hempstead, Hertfordshire, United Kingdom. This combustible air cloud led to a terrible explosion, and 23 large atmospheric storage tanks were damaged in the accident. In order to avoid even more serious consequences, more than 2000 residents were forced to evacuate [3]. The Buncefield Oil Storage Depot explosion was the most serious hazardous accident in European industry. In 2009, another severe explosion accident occurred at the Caribbean Petroleum Refining and Oil depot in Puerto Rico where the serial explosions damaged 18 oil storage tanks [4]. According to the statistics of oil storage tanks accidents by Chang and Lin, explosions occurred 61 times in total out of 242 accidents from 1960 to 2003 [5]. The most common causes of accidents are fires and explosions, which accounts for 85% of the total accidents [6].With large-scale competition between petroleum reserves in developed and developing countries, the space and capacity of the oil storage tanks are extended from a large to a superlarge scale. For example, tanks with capacities greater than 20 × 104 m3 and diameters greater than 100 m have been built in some countries in the Middle East and South America. In tank farms, steel storage tanks are designed as long-span and thin-walled structures [7–9]. The increasing scale of storage structures has prompted more serious damage and aggravates the consequences of an explosion [10, 11].Recently, several studies have focused on the response and failure analysis of energy structures and facilities subjected to a blast load. Atkinson described the patterns of damage observed in buildings in the industrial estates around Buncefield [12], presenting methods for assessing the degree of external and internal damage. He also dealt with failure modes and the ignition of various types of liquid storage tanks during vapor cloud explosions. Clubley investigated the effect of long-duration blast loads on the structural response of aluminum cylindrical shell structures containing varying fluid levels [13, 14]. In his research, a detailed nonlinear numerical model comprising of remapped Lagrangian methods was built to analyze localized plate buckling and deformation. The relative computational accuracy of the numerical model was compared with experimental results obtained at one of the world’s most powerful air blast testing facilities. Mittal et al. studied the stress (including maximum hoop and shear stresses), water sloshing heights, and energy response of steel water storage tanks using three-dimensional finite element (FE) simulations developed with ABAQUS software [15]. This study considered several influence factors, specifically the tank aspect ratios, percentages of water stored in the tank, tank wall thicknesses, and boundary conditions. Zhang et al. investigated the gas blast pressure distribution on the surface of a 1000 m3 spherical storage tank using the trinitrotoluene (TNT) equivalent method [16]. Chen et al. performed full-scale validation tests and numerical simulations of far-field air blast loading acting on deformable steel drums [17], aiming to investigate possible forensic methods for aiding incident investigations. Hu and Zhao built a computational fluid dynamics (CFD) model using FLUENT CFD software [18]. They simulated the explosion of a methane-air mixture in a small-scale cylindrical vessel and compared this simulation to an experiment to validate their CFD model for simulating gaseous explosions. With this validation, they carried out a series of CFD simulations to obtain the magnitude and distribution of the internal explosion loading on tanks while accounting for the influences of tank capacity, height/depth, roof forms, and other factors. Lv et al. developed a correlation for the explosion maximum overpressure in liquid natural gas (LNG) tank areas based on the momentum conservation equation [19] and deduced the correlation factors in explosion tests. Their correlation enables safety managers and fire rescue commanders to conveniently predict the LNG explosion maximum overpressure. Li et al. assessed effects on vented explosion pressure in and around the area of a tank group. For their research, they designed a series of tank layouts with different separation gaps [20, 21] and calculated the internal and external pressures subjected to different separation gaps. They also proposed equations for calculating the tank’s pressure–time history duration and shape. Zhang et al. studied the propagation of blast shock waves via numerical methods [22], analyzing the stress and structure deformation of LNG tanks under an explosive TNT blast.In earlier research, more attention was paid to storage tanks with slim cylindrical structures or on closed tanks with thick walls (like LNG storage tanks). Few studies have analyzed the dynamic responses of thin-walled structures having a diameter nearly the same as, or even larger than, their height (for example, large floating-roof storage tanks). Furthermore, there has been little analysis of the relationship between structural energy and dynamic response under blast impacts.In this paper, we briefly introduce an explosion test for a simplified scaled model of a storage tank under blast loading conditions. Then, the experiment is simulated using nonlinear FE software LS-DYNA. The LS-DYNA simulation is validated by comparing the test and numerical results. Subsequently, the numerical model is then applied to a storage tank with a capacity of 15 × 104 m3 and is used to analyze several damage features, such as failure mode, resultant displacement, structural energy, and dynamic strain in different simulation conditions.


## 2. Materials and Methods

### 2.1. Specimen Design and Test Setup

Based on a 5 × 104 m3 storage tank structure in the Yi Zheng Oil Reserve Base in China, we designed a simplified specimen structure for blast loading tests. Figure 1 shows the size parameters of the specimen, and Tables 1 and 2 present its geometry and material properties, respectively. In addition, the specimen is filled with water to simulate oil or other liquid fuel.Figure 1
Configuration of the test specimen.Table 1
Dimension of the test specimen.
Specimen
Dimension (D, mm)
Height (H, mm)
Thickness (δ, mm)
Water height (mm)
Distance (d, mm)
Simplified storage tank
923
297
1.2
260
35Table 2
Material properties of the test specimen.
Specimen
Material
E (GPa)
f
y (MPa)
f
u (MPa)
Simplified ring stiffener (Φ8 reinforce)
Material
E (GPa)
f
y (MPa)
f
u (MPa)
Simplified storage tank
Q235-A
206
310
—
Q235
206
310
—The experiments discussed in this paper were conducted and analyzed at the Defense Antiknock Laboratory at the Harbin Institute of Technology. Figure2 shows a schematic of the principal test facility. The facility consists of the blast loading system and the platform. The blast comes from the ignition of air and acetylene combustible gas. Before the test, the gas fills a premixed container from each gas tank and is ignited by pressing the “start” button on the control panel. The burning combustible gas spreads through two connected parts: a steel circular tube with a diameter of 0.057 m and length of 16.8 m that stimulates the blast wave in a blast loading system and a steel cylindrical nozzle that is used to widen the impact area on the specimen. Quickly, the blast wave sprays and impacts the test specimen, as shown in Figure 2.Figure 2
Schematic diagram of test setup.In the experiment, high-frequency piezoresistive pressure sensors were used to capture the blast loading and also to trigger the data acquisition system by the instrument 1# with sampling rate setting of 1 MHz as shown in Figure2. Three pressure gauges, A, B, and D, were installed on the surface toward the blast side to measure the blast impact on the outer surface of the structure. Figures 3(a) and 3(b) display the distribution of pressure gauges on the test specimen. Besides, six strain gauges (S1-S6) were installed on the wall of the specimen to measure its dynamic response, as shown in Figures 3(a) and 3(c). These gauges were connected with data acquisition systems. Their signals were acquired by 2# instrument as well as acquiring system, and the sampled signal is 100 MHz.Figure 3
Distribution of pressure gauges and strain gauges. (a) Top view of the test specimen. (b) Distribution of pressure gauges. (c) Distribution of strain gauges.
(a)
(b)
(c)


### 2.2. Numerical Simulation and Validation

In this section, we describe the FE model of the test specimen built using LS-DYNA code. In addition, we verify the accuracy of the model with the scale-model test results. Thus, the FE model is used to validate the analytical model in the next sections.The shell element SHELL163 in LS-DYNA was adopted for the wall and bottom plate of the specimen. SHELL163 is an explicit structural thin shell element with bending and membrane properties, and it supports nonlinear properties in the explicit dynamic analysis. This element can reduce computing time compared with a solid element. The eight-node solid element SOLID164 was adopted as a simplified ring stiffener, water, air, and high-explosive material. The Eulerian formulation, which is ideal for modeling fluid problems, was applied to the water, air, and high-explosive material in the FE model. The Lagrange formulation, which is generally suitable for elements without severe distortion, was applied to the other elements. The penalty fluid-structure coupling method in LS-DYNA was used to model the interactions between the simplified tank and blast wave from high explosive material, as well as between the water and the simplified tank.The isotropic hardening plasticity material model in LS-DYNA was used to simulate the corresponding Q235 steel. This model is very cost effective and is available for shell and solid elements. In this material model, the strain rate effect was considered using the Cowper–Symonds model, which scales the yield stress using a strain rate dependent factor, as shown in the following equation:(1)σyεeffP,εeffP˙=σyεeffP1+εeffP˙C1/P,where σyεeffP is the yield stress without strain rate effects, εeffP˙ is the effective plastic strain rate, and C and P are the strain rate parameters, which were set to 40 and 5, respectively, for Q235 steel in this study.The null material model is used to describe the deviatoric responses of air and water. The linear polynomial state equation used to simulate the volumetric response of air is given by(2)P=C0+C1μ+C2μ2+C3μ3+C4+C5μ+C6μ2E¯,where μ=ρ/ρ0−1, ρ is the current density, ρ0 is the initial density, E¯ is the initial energy per unit reference volume, and C0–C6 are parameters of the state equation. The material properties of air are given in Table 3. The Gruneisen equation of state with cubic shock velocity–particle velocity (VS–PS), which is used to simulate the volumetric response of water, is given in the following equation:(3)P=ρ0C2μ1+1−γ0/2μ−a/2μ21−S1−1μ−S2μ2/μ+1−S3μ3/μ+122+γ0+aμE¯.Table 3
Material parameters of air in numerical simulation.
Material
Density (kg/m3)
C
0 (Pa)
C
1
C
2
C
3
C
4
C
5
C
6
E
0 (MJ/m3)
V
0
Atmosphere
1.293
−1.0 × 105
0
0
0
0
0
0
0.25
1.0Equation (3) is used for compressed material. Equation (4) is for expanded material:(4)P=ρ0C2μ+γ0+aμE¯,where C is the intercept of the VS–PS curve; S1, S2, and S3 are the coefficients of the slope of the VS–PS curve; γ0 is the Gruneisen gamma; and a is the first-order volume correction to γ0. The material properties of water are listed in Table 4.Table 4
Material parameters of water in numerical simulation.
Material
Density (kg/m3)
C (m/s)
S
1
S
2
S
3
γ
0
a
E
0 (MJ/m3)
Atmosphere
998.2
1647
1.921
−0.096
0
0.35
0
0.0In the FE model, the combustible gas mixture (acetylene and air) is considered to be equivalent to TNT. A high-explosive material model (∗MAT_HIGH_ EXPLOSIVE_ BURN) incorporating the Jones–Wilkins–Lee (JWL) equation of state is used to describe the material property of the equivalent TNT charge. The JWL equation defines pressure as a function of relative volume and internal energy per initial volume, as shown in the following equation:(5)P=A1−ωR1Ve−R1V+B1−ωR2Ve−R2V+ωEV,where P is the blast pressure; E is the internal energy per initial volume; V is the initial relative volume; and ω, A, B, R1, and R2 are material constants. The values of parameters A, B, R1, and R2 are 0.3, 3.71, 0.00323, 4.15, and 0.95, respectively [23].Figure4 compares the dynamic pressure history between the experiment and the numerical simulation. The trend of the blast loading change in the numerical simulation is consistent with that of the experiment. The value of the peak pressure is lower than that of the experimental results, with less than 10% relative error. The difference is probably caused by the secondary chemical reaction after the explosion (i.e., gas combustion), as the released energy from the reaction is neglected in the simulation process. Compared with the experimental history curves, the simulation curves are smoother because the explosion reaction is accompanied by the phenomena of bright light and air ionization in the experiment. These phenomena directly influence the pressure sensor signal and are not accounted for in the numerical simulation.Figure 4
The comparison between experiment and numerical simulation. (a) Gauge A. (b) Gauge B. (c) Gauge D.
(a)
(b)
(c)Considering the action time of positive pressure, the difference between the simulation and experiment in Gauge A, shown in Figure4(a), is greater than for the other two gauges, with a 12.8% relative error. The test specimen was located on concrete in the experiment, so the ground was established as a perfectly rigid material in the FE model and produced a strong reflected wave. For this reason, Gauge A was distributed in the normal reflection region and near the ground. The overlap of the reflected and incident waves extends the action time of positive pressure. Thus, the established FE model of the simplified storage tank under blast loading was verified through comparison between the experimental and FE results.


### 2.3. Numerical Model of Storage Tank Prototype

The main objective of this study is to develop an FE model to simulate the response of long-span storage tank prototype under a blast impact. Figure5 shows a diagram of a simplified storage tank with 15 × 104 m3 storage capacity; its simplified numerical model in the LS-DYNA environment is shown in Figure 6.Figure 5
Structure diagram of the storage tank with 15 × 104 m3 storage capacity.Figure 6
Storage tank and inner liquid. (a) A storage tank with liquid. (b) Wind girders and ring stiffeners.
(a)
(b)In Figure5, the size of the structure is 100 m × 22.5 m (diameter D × total height H). The simplified structure consists of the following components: tank walls, tank floor plate, wind girders, and ring stiffeners. Eight tank walls form the whole tank body. The height of the first wall (h1st) is 3 m, and the heights of all other walls (h2nd to h8th) are 2.7 m. Figure 7 shows the wall distribution in the numerical model. The storage tank is filled with different levels of liquid to simulate actual storage tank conditions in an explosion. The numerical models consider the effect of gravity. Figure 8 shows the liquid level conditions in the numerical simulation.Figure 7
Distribution of eight tank walls.Figure 8
The liquid level conditions. (a) Tank edge and liquid. (b) 25% fill level ((H)liquid = 5.4 meters). (c) 50% fill level ((H)liquid = 11 meters). (d) 75% fill level ((H)liquid = 16 meters).
(a)
(b)
(c)
(d)In the simulation model of the prototype tank, shell element SHELL163 is also used to simulate the tank wall and the bottom plate. More than 177,800 shell elements were built to simulate the storage tank structure in the model, and more than 1800,000 SOLID164 solid elements were built for simplified wind girders, water, air, and high-explosive material models. The Eulerian and Lagrangian formulations were still applied for the corresponding fluid or structure elements in the simulation. LS-DYNA adopts the Eulerian algorithm coupled with the Lagrangian formulation to fully model the interaction between the blast wave and the structure. The software package implements a contact interface between the Eulerian and Lagrangian components. Therefore, the interaction between the blast wave and the response of the structure can be captured, even for large deformations [24].This simulation assumes that there is a large quantity of flammable gas (a mixture of air and acetylene) leaking from storage tanks. In this simulation, we consider flammable gas mixture volumes of 15600 m3 and 4000 m3, which are comparable to the volumes found in some accidents. Compared with the influence of the combustion wave, the impact intensity from the shock wave is much higher, and its damage effect on the storage tank is significantly serious than that of the combustion wave. In the case of the adverse situation in simulations, the shock wave is the main factor in simulating the blast impact loading. The blast wave initiated from the gas mixture and impacted on the storage tank. Figure 9 shows the relative positions of the storage tank and initial explosion. The numerical model of the explosion in this situation follows the model introduced previously.Figure 9
The relative distance between the storage tank and the explosion.The TNT equivalency model is based on the assumption of equivalence between the flammable material and TNT. It can be used to evaluate the intensity of gas explosion and the radius of the effect in some explosion accident analysis, such as the multienergy method or TNO method. In addition, the TNT equivalent method presents the similar scaled explosion intensity in different combustible gas volume. Equivalent massW is calculated (in equation (6)) based on the total heat of combustion of the flammable material [25]:(6)W=ηMECETNT,where η is the empirical explosion efficiency, M is the mass of flammable material (equal to the mass of the air and acetylene mixture), EC is the heat of the reaction of the flammable material, and ETNT is the heat of the TNT reaction. By using equation (1) for the modeled conditions with volumes of 15600 m3 and 4000 m3, we found that the blast intensities had TNT equivalent masses of 1500 kg and 380 kg, respectively.


## 2.1. Specimen Design and Test Setup

Based on a 5 × 104 m3 storage tank structure in the Yi Zheng Oil Reserve Base in China, we designed a simplified specimen structure for blast loading tests. Figure 1 shows the size parameters of the specimen, and Tables 1 and 2 present its geometry and material properties, respectively. In addition, the specimen is filled with water to simulate oil or other liquid fuel.Figure 1
Configuration of the test specimen.Table 1
Dimension of the test specimen.
Specimen
Dimension (D, mm)
Height (H, mm)
Thickness (δ, mm)
Water height (mm)
Distance (d, mm)
Simplified storage tank
923
297
1.2
260
35Table 2
Material properties of the test specimen.
Specimen
Material
E (GPa)
f
y (MPa)
f
u (MPa)
Simplified ring stiffener (Φ8 reinforce)
Material
E (GPa)
f
y (MPa)
f
u (MPa)
Simplified storage tank
Q235-A
206
310
—
Q235
206
310
—The experiments discussed in this paper were conducted and analyzed at the Defense Antiknock Laboratory at the Harbin Institute of Technology. Figure2 shows a schematic of the principal test facility. The facility consists of the blast loading system and the platform. The blast comes from the ignition of air and acetylene combustible gas. Before the test, the gas fills a premixed container from each gas tank and is ignited by pressing the “start” button on the control panel. The burning combustible gas spreads through two connected parts: a steel circular tube with a diameter of 0.057 m and length of 16.8 m that stimulates the blast wave in a blast loading system and a steel cylindrical nozzle that is used to widen the impact area on the specimen. Quickly, the blast wave sprays and impacts the test specimen, as shown in Figure 2.Figure 2
Schematic diagram of test setup.In the experiment, high-frequency piezoresistive pressure sensors were used to capture the blast loading and also to trigger the data acquisition system by the instrument 1# with sampling rate setting of 1 MHz as shown in Figure2. Three pressure gauges, A, B, and D, were installed on the surface toward the blast side to measure the blast impact on the outer surface of the structure. Figures 3(a) and 3(b) display the distribution of pressure gauges on the test specimen. Besides, six strain gauges (S1-S6) were installed on the wall of the specimen to measure its dynamic response, as shown in Figures 3(a) and 3(c). These gauges were connected with data acquisition systems. Their signals were acquired by 2# instrument as well as acquiring system, and the sampled signal is 100 MHz.Figure 3
Distribution of pressure gauges and strain gauges. (a) Top view of the test specimen. (b) Distribution of pressure gauges. (c) Distribution of strain gauges.
(a)
(b)
(c)


## 2.2. Numerical Simulation and Validation

In this section, we describe the FE model of the test specimen built using LS-DYNA code. In addition, we verify the accuracy of the model with the scale-model test results. Thus, the FE model is used to validate the analytical model in the next sections.The shell element SHELL163 in LS-DYNA was adopted for the wall and bottom plate of the specimen. SHELL163 is an explicit structural thin shell element with bending and membrane properties, and it supports nonlinear properties in the explicit dynamic analysis. This element can reduce computing time compared with a solid element. The eight-node solid element SOLID164 was adopted as a simplified ring stiffener, water, air, and high-explosive material. The Eulerian formulation, which is ideal for modeling fluid problems, was applied to the water, air, and high-explosive material in the FE model. The Lagrange formulation, which is generally suitable for elements without severe distortion, was applied to the other elements. The penalty fluid-structure coupling method in LS-DYNA was used to model the interactions between the simplified tank and blast wave from high explosive material, as well as between the water and the simplified tank.The isotropic hardening plasticity material model in LS-DYNA was used to simulate the corresponding Q235 steel. This model is very cost effective and is available for shell and solid elements. In this material model, the strain rate effect was considered using the Cowper–Symonds model, which scales the yield stress using a strain rate dependent factor, as shown in the following equation:(1)σyεeffP,εeffP˙=σyεeffP1+εeffP˙C1/P,where σyεeffP is the yield stress without strain rate effects, εeffP˙ is the effective plastic strain rate, and C and P are the strain rate parameters, which were set to 40 and 5, respectively, for Q235 steel in this study.The null material model is used to describe the deviatoric responses of air and water. The linear polynomial state equation used to simulate the volumetric response of air is given by(2)P=C0+C1μ+C2μ2+C3μ3+C4+C5μ+C6μ2E¯,where μ=ρ/ρ0−1, ρ is the current density, ρ0 is the initial density, E¯ is the initial energy per unit reference volume, and C0–C6 are parameters of the state equation. The material properties of air are given in Table 3. The Gruneisen equation of state with cubic shock velocity–particle velocity (VS–PS), which is used to simulate the volumetric response of water, is given in the following equation:(3)P=ρ0C2μ1+1−γ0/2μ−a/2μ21−S1−1μ−S2μ2/μ+1−S3μ3/μ+122+γ0+aμE¯.Table 3
Material parameters of air in numerical simulation.
Material
Density (kg/m3)
C
0 (Pa)
C
1
C
2
C
3
C
4
C
5
C
6
E
0 (MJ/m3)
V
0
Atmosphere
1.293
−1.0 × 105
0
0
0
0
0
0
0.25
1.0Equation (3) is used for compressed material. Equation (4) is for expanded material:(4)P=ρ0C2μ+γ0+aμE¯,where C is the intercept of the VS–PS curve; S1, S2, and S3 are the coefficients of the slope of the VS–PS curve; γ0 is the Gruneisen gamma; and a is the first-order volume correction to γ0. The material properties of water are listed in Table 4.Table 4
Material parameters of water in numerical simulation.
Material
Density (kg/m3)
C (m/s)
S
1
S
2
S
3
γ
0
a
E
0 (MJ/m3)
Atmosphere
998.2
1647
1.921
−0.096
0
0.35
0
0.0In the FE model, the combustible gas mixture (acetylene and air) is considered to be equivalent to TNT. A high-explosive material model (∗MAT_HIGH_ EXPLOSIVE_ BURN) incorporating the Jones–Wilkins–Lee (JWL) equation of state is used to describe the material property of the equivalent TNT charge. The JWL equation defines pressure as a function of relative volume and internal energy per initial volume, as shown in the following equation:(5)P=A1−ωR1Ve−R1V+B1−ωR2Ve−R2V+ωEV,where P is the blast pressure; E is the internal energy per initial volume; V is the initial relative volume; and ω, A, B, R1, and R2 are material constants. The values of parameters A, B, R1, and R2 are 0.3, 3.71, 0.00323, 4.15, and 0.95, respectively [23].Figure4 compares the dynamic pressure history between the experiment and the numerical simulation. The trend of the blast loading change in the numerical simulation is consistent with that of the experiment. The value of the peak pressure is lower than that of the experimental results, with less than 10% relative error. The difference is probably caused by the secondary chemical reaction after the explosion (i.e., gas combustion), as the released energy from the reaction is neglected in the simulation process. Compared with the experimental history curves, the simulation curves are smoother because the explosion reaction is accompanied by the phenomena of bright light and air ionization in the experiment. These phenomena directly influence the pressure sensor signal and are not accounted for in the numerical simulation.Figure 4
The comparison between experiment and numerical simulation. (a) Gauge A. (b) Gauge B. (c) Gauge D.
(a)
(b)
(c)Considering the action time of positive pressure, the difference between the simulation and experiment in Gauge A, shown in Figure4(a), is greater than for the other two gauges, with a 12.8% relative error. The test specimen was located on concrete in the experiment, so the ground was established as a perfectly rigid material in the FE model and produced a strong reflected wave. For this reason, Gauge A was distributed in the normal reflection region and near the ground. The overlap of the reflected and incident waves extends the action time of positive pressure. Thus, the established FE model of the simplified storage tank under blast loading was verified through comparison between the experimental and FE results.


## 2.3. Numerical Model of Storage Tank Prototype

The main objective of this study is to develop an FE model to simulate the response of long-span storage tank prototype under a blast impact. Figure5 shows a diagram of a simplified storage tank with 15 × 104 m3 storage capacity; its simplified numerical model in the LS-DYNA environment is shown in Figure 6.Figure 5
Structure diagram of the storage tank with 15 × 104 m3 storage capacity.Figure 6
Storage tank and inner liquid. (a) A storage tank with liquid. (b) Wind girders and ring stiffeners.
(a)
(b)In Figure5, the size of the structure is 100 m × 22.5 m (diameter D × total height H). The simplified structure consists of the following components: tank walls, tank floor plate, wind girders, and ring stiffeners. Eight tank walls form the whole tank body. The height of the first wall (h1st) is 3 m, and the heights of all other walls (h2nd to h8th) are 2.7 m. Figure 7 shows the wall distribution in the numerical model. The storage tank is filled with different levels of liquid to simulate actual storage tank conditions in an explosion. The numerical models consider the effect of gravity. Figure 8 shows the liquid level conditions in the numerical simulation.Figure 7
Distribution of eight tank walls.Figure 8
The liquid level conditions. (a) Tank edge and liquid. (b) 25% fill level ((H)liquid = 5.4 meters). (c) 50% fill level ((H)liquid = 11 meters). (d) 75% fill level ((H)liquid = 16 meters).
(a)
(b)
(c)
(d)In the simulation model of the prototype tank, shell element SHELL163 is also used to simulate the tank wall and the bottom plate. More than 177,800 shell elements were built to simulate the storage tank structure in the model, and more than 1800,000 SOLID164 solid elements were built for simplified wind girders, water, air, and high-explosive material models. The Eulerian and Lagrangian formulations were still applied for the corresponding fluid or structure elements in the simulation. LS-DYNA adopts the Eulerian algorithm coupled with the Lagrangian formulation to fully model the interaction between the blast wave and the structure. The software package implements a contact interface between the Eulerian and Lagrangian components. Therefore, the interaction between the blast wave and the response of the structure can be captured, even for large deformations [24].This simulation assumes that there is a large quantity of flammable gas (a mixture of air and acetylene) leaking from storage tanks. In this simulation, we consider flammable gas mixture volumes of 15600 m3 and 4000 m3, which are comparable to the volumes found in some accidents. Compared with the influence of the combustion wave, the impact intensity from the shock wave is much higher, and its damage effect on the storage tank is significantly serious than that of the combustion wave. In the case of the adverse situation in simulations, the shock wave is the main factor in simulating the blast impact loading. The blast wave initiated from the gas mixture and impacted on the storage tank. Figure 9 shows the relative positions of the storage tank and initial explosion. The numerical model of the explosion in this situation follows the model introduced previously.Figure 9
The relative distance between the storage tank and the explosion.The TNT equivalency model is based on the assumption of equivalence between the flammable material and TNT. It can be used to evaluate the intensity of gas explosion and the radius of the effect in some explosion accident analysis, such as the multienergy method or TNO method. In addition, the TNT equivalent method presents the similar scaled explosion intensity in different combustible gas volume. Equivalent massW is calculated (in equation (6)) based on the total heat of combustion of the flammable material [25]:(6)W=ηMECETNT,where η is the empirical explosion efficiency, M is the mass of flammable material (equal to the mass of the air and acetylene mixture), EC is the heat of the reaction of the flammable material, and ETNT is the heat of the TNT reaction. By using equation (1) for the modeled conditions with volumes of 15600 m3 and 4000 m3, we found that the blast intensities had TNT equivalent masses of 1500 kg and 380 kg, respectively.


## 3. Results and Discussion

### 3.1. Failure Mode Analysis

Figure10 shows the failure of the tank structure under conditions of different fill levels and blast intensities. With a blast intensity resulting from an explosion of 1500 kg TNT equivalent mass (15600 m3 gas), Figures 10(a-i), 10(a-ii), and 10(a-iii) show the structural damage with liquid heights of 25%, 50%, and 75%, respectively. Figures 10(b-i), 10(b-ii), and 10(b-iii) show the same fill levels but for the blast intensity of a 380 kg TNT equivalent mass (4000 m3 combustible gas explosion).Figure 10
structure damage state in different blast intensity and fill conditions. (a) Under the blast intensity of 1500 kg TNT equivalent mass: (i) 25% fill level; (ii) 50% fill level; (iii) 75% fill level. (b) Under the blast intensity of 380 kg TNT equivalent mass: (i) 25% fill level; (ii) 50% fill level; (iii) 75% fill level.
(a)
(b)In general, the tank structures in Figures10(a-i)–10(a-iii) suffer more significant destruction than those in Figures 10(b-i)–10(b-iii) because of the intensity of the explosion. However, the structural damage is alleviated with increasing fill amounts of oil or liquid fuel when considering the same blast load intensity. For example, the structures in Figures 10(a-i), 10(b-i), 10(a-ii), and 10(b-ii) form clear concave deformations through all walls. Owing to the blast impact, the tank floor and walls (especially walls 1 to 4) are warped and curled up. The structures have an obvious concave deformation, which is distributed almost symmetrically along the stagnation points on the blast side. The buckling deformation of the storage tanks looks like the capital letter “W” at the 25% fill level (in Figures 10(a-i) and 10(b-i)), whereas the deformation of the tanks looks like the capital letter “V” in Figures 10(a-ii) and 10(b-ii), at the 50% fill level.By contrast, the storage tank experiences less damage with a 75% fill level. Only three tank walls (the sixth through eighth), wind girders, and ring stiffeners are deformed clearly. In this situation, the slight curling in the walls can be observed to look like the lowercase letter “v,” as in Figure10(a-iii), or a blurry letter “o,” as in Figure 10(b-iii). In Figure 10(b-iii), the tank body is mostly left intact, except for slight deformation of the wind girders (and ring stiffeners).


### 3.2. Displacement and Deformation Analysis

To determine displacementδ, a series of measuring points (Si with i = 1–8) are distributed along the storage tank at the midheight of every wall, as shown in Figure 11. The resultant displacements of Si, at 0.5 s after the detonation, are shown in Figure 12. The resultant displacement is equal to the vector superposition of vertical (+Y axis) and radial (+Z axis) displacement. The displacement of the same point was found to be affected by simulated conditions, namely, the liquid fill level and explosion intensity. In each figure, under the same blast intensity, deformation displacement δ decreased with increasing liquid fill level. The change in deformation displacement δ in the numerical simulation is consistent with the theoretical analysis.Figure 11
The distribution of measuring pointsSi: (a) front view; (b) top view.
(a)
(b)Figure 12
Resultant displacement of measuring pointsSi. (a) Intensity of 380 kg TNT equivalent mass explosion. (b) Intensity of 1500 kg TNT equivalent mass explosion.
(a)
(b)In order to reveal the influence of constraint conditions on the structure’s response under blast loads, we modified the numerical model of the storage tank to include an anchor zone on the bottom plate in the LS-DYNA 3D environment. Additionally, along the circumference of the bottom plate edge, we set the fixed constraints at an interval angle of 5°. Previous numerical results had no constraint on this edge.Figure13 shows the storage tank failure state for a blast intensity of a 1500 kg TNT equivalent mass explosion for different fill levels (25% and 50%) with the free (Figures 13(a-i) and 13(b-i)) and fixed (Figures 13(a-ii) and 13(b-ii)) constraint conditions. Compared with the free constraint conditions, the fixed constraint oil storage tanks experience more serious damage. As shown in Figures 13(a-ii) and 13(b-ii), the storage tanks deformed significantly and collapsed severely. Without the constraint condition (Figures 13(a-i) and 13(b-i)), the free bottom plate absorbed part of the blast energy through warping and deformation. Conversely, the fixed plates absorbed hardly any blast energy, meaning more was borne by the tank walls. To reduce blast damage, it is preferable to weaken the constraints on the tank’s bottom plate.Figure 13
Structural deformation and failure state in different constraint conditions. (a) Storage tank with 25% fill level: (i) no constraint; (ii) fixed constraint. (b) Storage tank with 50% fill level: (i) no constraint; (ii) fixed constraint.
(a)
(b)Analysis of the resultant displacement and deformation reveals damage to the storage tank under the blast impact in different conditions. A more detailed structural dynamic response can be revealed from an energy analysis and dynamic strain comparison.


### 3.3. Structural Energy Analysis

In Figures5 and 6, the storage tank body is composed of eight tank walls and can be divided into many elements, Si (i = 1, 2, …, N). In this section, we analyze the energy variation of shell elements Si under the blast impact in two tank conditions: empty and liquid filled.Condition 1 (empty).
Suppose blast loadPt is at the center of shell element Si and forms deformation displacement δ1 (as shown in Figures 14(a) and 14(b)). The resistance force to the impact is D × δ1, where D is the resistance coefficient of the structure (shell element Si). Work W1 is the Pt working along deformation displacement δ1. At the moment of blast impact, Si start to move with velocity vt. The equations of load and work can be described as follows:(7)Pt=D×δ1+m1dvtdt,W1=Pt×δ1.
Under the blast impact, after the plastic deformation displacementδ1max, the velocity and kinetic energy of Si are almost zero. Ignoring the heat loss during the interaction between the blast wave and the structure, work W1 is transformed into the element’s deformation energy, EP1. The change can be expressed as(8)Pt×δ1⋅max=EP1.Figure 14
Diagram of shell elementSi in two separate conditions. (a) Shell element in empty condition. (b) Deformation displacement of Si. (c) Shell element and added liquid mass. (d) Deformation displacement of shell element.
(a)
(b)
(c)
(d)Condition 2 (liquid filled).
When the storage tank is filled with liquid, most shell elements (on the wall) move or vibrate together with the inner liquid, as affected by blast loadingPt. Suppose the mass of shell element Si and the added liquid are m1 and m2. Under the Pt impact effect, Si has deformation displacement δ2 and its resistance to the impact force is D × δ2. Similarly to the empty condition, parameters Pt, δ2, and vt have the following relationship:(9)Pt=D×δ2+m1+m2dvtdt.
Under the same intensityPt, the deformation displacement fulfils the relation δ1 > δ2 in two separate conditions. When the impacted regions of the wall ultimately exhibit plastic deformation, the inner liquid may separate from the structure and continue to shake for a moment. Under the same loading effect, the input energy is changed into two parts—the plastic deformation energy and the kinematic energy of the liquid. The ultimate deformation of shell element Si is δ2·max, but the added liquid mass still moves with velocity v2.
Ignoring heat loss, workW2 can be transformed into deformation energy EP2 and the kinetic energy of liquid, KEliquid, and can be expressed as follows:(10)Pt×δ2⋅max=EP2+KEliquid=EP2+12m2v22,EP2=Pt×δ2⋅max−12m2v22.
Moreover, blast loadP(t) forms an impulse on shell element Si. According to the theory of impulse, Si has specific impulse i(t):(11)it=∫0tptdτ.
Owing to the momentum during the blast, the velocity ofSi is(12)ν1t=itρnhn,where ρn and hn represent the material density and thickness of Si and ρn × hn represents its unit mass. Assuming that the impact load on Si is absorbed, it is completely converted into the initial kinetic energy of the shell element when the storage tank is empty. Hence, the absorbing energy expression is given by(13)Ea=i2t2ρnhn=Ep1.
In the above equation,Ea represents the structural absorption energy that is converted into deformation energy EP1. Alternatively, in the liquid-filled condition, the velocity of Si with added liquid mass m2 is(14)ν2t=itρnhn+ρ0c0t=∫0tptdτρnhn+ρ0c0t.
In this expression,ρ0 represents the density of the liquid and c0 represents the speed of sound in the liquid, while ρ0 × c0 × t represents the unit mass of the added liquid. Equation (14) also supposes that the impact load on the Si was absorbed and was completely changed into the initial kinetic energy of shell element Si and added liquid m2. Under such conditions, the absorbing energy can be expressed as equations (15) and (16), where EP2 represents the deformation energy of shell element Si:(15)Eb=i2t2ρnhn+ρ0c0t=EP2+KEliquid,(16)EP2=i2t2ρnhn+ρ0c0t−KEliquid.
Comparison between equations (13) and (15) reveals that if the shell elements move together with the added liquid mass, their deformation energy can be partly reduced compared to the empty condition; that is, EP2 < EP1.
The tank walls are composed of many shell elements. When empty,E1 represents the total deformation energy of the tank wall, as(17)E1=∑i=1nEP1i.
In the liquid-filled conditions,E2 represents the total deformation energy of the tank wall:(18)E2=∑i=1nEP2i.
The relationship betweenE1 and E2 fulfils the following condition:(19)E1>E2.
Under the impact of a 1500 kg TNT equivalent mass explosion, Figure15 shows time-history curves of the kinetic energy KE and deformation energy EP of different parts of the tank: the tank walls, wind girders, and bottom plate. The liquid level is the main simulation variable in Figure 13. According to the KE curves, 20–50 ms after detonation, the wind girders and most tank walls reach their maximum energy value. In contrast, most structure parts form visible residue energy on their EP curves after 0.5 s. The energy variation in the KE and EP curves reveals that the blast energy is absorbed by structures and is converted into deformation energy.
Furthermore, Tables5 and 6 list the collected EP data of the different tank parts at the simulation termination. Table 5 compares the data for different liquid levels in storage tanks with no constraints, whereas Table 6 shows the energy data for fixed constraint conditions. Tables 5 and 6, as well as Figure 15, reveal the following structural energy and failure features of the storage tank structure:(1)
Compared with other parts of the storage tank, the energy values of the wind girders are noticeably higher. The deformed wind girders absorb 35–65% of total deformation energy. These girders are always designed to have a thin-walled rectangular shape and cantilever structures. They are designed to enhance the lateral stiffness of the storage tank and resist the lateral load of wind. As they are not designed considering blast impact effects, the wind girders, with their cantilever shape, are apt to be destroyed.(2)
Under the blast impact, the tank walls stored some energy in structures via deformation. Followed by increases in the inner liquid (from the 25% to 75% fill level), the declining tendency of deformation energy is notable. At the 25% and 50% fill levels, the most energy was absorbed by the sixth wall; at the 75% fill level, the eighth wall absorbed the most energy. The same trend occurs in Tables5 and 6 (highlighted in bold). For further analysis of the energy variation for tank walls, we undertake a detailed quantitative comparison of the energy feature analysis in next paragraphs, with consideration of liquid levels, constraint conditions, and blast load intensity.(3)
As shown in Figure14, the bottom plate with no constraints warps and distorts under the blast wave. Table 5 compares the deformation energy of the bottom plate for different liquid levels. At the 25% fill level, the bottom plate forms 15.35 MJ energy, which accounts for 9.3% of the total energy. When the inner liquid rises to the 50% fill level, the value significantly declines to 2.9 MJ and only accounts for 2.8% of the total energy. The energy becomes the lowest at the 75% fill level, where it is 0.22 MJ, which is less than 0.5% of the total energy. In Table 6, for all liquid levels, the deformation energy of bottom plate is zero because of the fixed constraint condition applied to these simulations. Regardless of constraint condition, most energy is absorbed by tank walls and other structures.
To analyze the energy features, we compared the energy data of five typical tank walls—the first, third, fifth, sixth, and eighth. The parameters KEmax and EPT are used to represent the peak value in the KE curve and the EP curve at the termination time (0.5 s) respectively, as shown in Figure 16. Figure 17 shows a comparison of these two parameters in different simulation conditions and describes the variation in structural energy quantitatively.
In Figures17(a-i) and 17(b-i), the KEmax parameter curves increase gradually from the first to the fifth tank walls for the 25% and 50% fill level conditions. The curves peak at the fifth or sixth wall. In the 75% fill level condition, KEmax grows by a small amount from the first wall to the sixth wall but increases dramatically at the eighth wall. Compared with the fixed constraint model, the KEmax value of the free constraint model is larger (especially at the first and third walls). The influence of the fixed bottom plate restricts the movement of the tank walls and reduces to the kinetic energy. The KEmax comparison shows that the storage tank walls produce a similar response (in the free and fixed constraint conditions) during the initial impact phase. This initial dynamic response might be closely related to the structural style of the thin-walled cylindrical shell.
The fixed constraint model leads to higher values of parameterEPT than the free constraint model, especially at the 25% and 50% fill levels. In the fixed model, the bottom plate absorbs almost no energy from the blast wave. In the free constraint model, the free bottom plate dissipates the blast energy through deformation and sliding friction, which reduces the energy that the remaining walls and structure must absorb.
The bar charts in Figure18 compare the total values of EPT for structures with different liquid levels. Here, the deformation energy of an empty storage tank was also calculated. In Figure 18, increasing fill levels clearly reduce the deformation energy. This reduction is found for both conditions of constraint and blast intensities.
For instance, in the 1500 kg TNT equivalent mass explosion condition, the fixed and free constraint models at the 75% fill level have only 21.8% and 17.2% of the deformation energy of the empty tank, respectively. At the 380 kg TNT equivalent mass explosion intensity, a similar trend in deformation energy was observed. As shown in Figure18(b), at a fill level of 75%, the fixed and the free constraint values observed were only 6.13% and 6.9% of the deformation energy of an empty tank for the respective constraint conditions. Comparing the EPT of the fixed and free constraint models, Figure 18(b) shows that the free constraint condition reduces the impact effect on the tank structures.
The results in Figure18 indicate that the inner liquid absorbs part of the energy from the blast wave. It reduces the impact of the blast on the storage tanks and the deformation energy.Figure 15
The energy curves comparison under intensity of 1500 kg TNT equivalent mass explosion. (a) Wind girders (ring stiffeners). (b) 8th wall. (c) 6th wall. (d) 5th wall. (e) 3rd wall. (f) 1st wall. (g) Bottom plate.
(a)
(b)
(c)
(d)
(e)
(f)
(g)Table 5
Deformation energy of storage tank with no constraint (unit: MJ).
Structure
25% filled (Hliquid = 5.4 m)
50% filled (Hliquid = 11 m)
75% filled (Hliquid = 16 m)
Deformation energy (EPT)
Percentage
Deformation energy (EPT)
Percentage
Deformation energy (EPT)
Percentage
Bottom plate
15.35
9.3
2.9
2.8
0.22
0.41
1st wall
11.8
7.2
4.48
4.3
0.07
0.13
2nd wall
8.45
5.1
1.45
1.4
0.03
0.06
3rd wall
12.08
7.3
2.81
2.7
0.03
0.05
4th wall
8.22
5
1.57
1.5
0.13
0.25
5th wall
13.32
8.1
8.57
8.1
0.84
1.6
6th wall
16.09
9.7
12.13
11.5
1.88
3.4
7th wall
8.52
5.2
9
8.5
7.09
13
8th wall
13.70
8.3
11.63
11
9.51
17.4
Wind girders
57.4
34.8
50.78
48.2
34.78
63.7
Total energy
164.93
105.33
54.6Table 6
Deformation energy of oil storage tank with fixed constraint (unit: MJ).
Structure
25% filled (Hliquid = 5.4 m)
50% filled (Hliquid = 11 m)
75% filled (Hliquid = 16 m)
Deformation energy (EPT)
Percentage
Deformation energy (EPT)
Percentage
Deformation energy (EPT)
Percentage
Bottom plate
0
0
0
0
0
0
1st wall
23.68
12.3
9.41
7
0.14
0.18
2nd wall
8.14
4.2
5.21
3.9
0.93
1.2
3rd wall
11.07
5.8
2.98
2.2
0.76
0.99
4th wall
9.84
5.1
4.61
3.4
0.89
1.2
5th wall
15.5
8.1
10.54
7.9
2.17
2.8
6th wall
24.16
12.6
16.27
12.1
4.7
6.1
7th wall
13.75
7.2
12.55
9.4
10.06
13.1
8th wall
19.39
10.1
16.11
12
18.92
24.6
Wind girders
66.33
34.6
56.44
42.1
38.37
49.9
Total energy
191.85
134.22
76.95Figure 16
Schematic of energy feature parameters.Figure 17
Comparisons of energy parameters under different intensities. (a) Intensity of 1500 kg TNT equivalent mass explosion: (i) KEmax; (ii) EPT. (b) Intensity of 380 kg TNT equivalent mass explosion: (i) KEmax; (ii) EPT.
(a)
(b)Figure 18
Comparisons of deformation energy (E)PT in different simulation conditions. (a) Intensity of 1500 kg TNT equivalent mass explosion. (b) Intensity of 380 kg TNT equivalent mass explosion.
(a)
(b)


### 3.4. Dynamic Strain Analysis

Figure19 shows several measurement gauges Ai (i = 1, 2, …, 8) that represent related shell elements Si, which are located on each tank wall. The following sections compare the effective strain curves of gauges Ai under the blast intensity of a 1500 kg TNT equivalent mass explosion.Figure 19
Layout of strain measuring gauges.If the lengths of shell elementSi are dSα, dSβ, and dZ, the volume of Si fulfils the following relation:(20)dV=dSα⋅dSβ⋅dZ=AB1+zR11+zR2dαdβdZ.In equation (20), A and R1 represent the Lame coefficient and radius of curvature in the α direction in the curvilinear coordinates in Figure 20; B and R2 denote the Lame coefficient and radius of curvature in the β direction in the same curvilinear coordinates; and z indicates the distance between the external (or internal) surface and the middle surface. Therefore, the deformation energy of shell element EP can be expressed as(21)dEp=12σαzεαz+σβzεβz+σZzεZz+ταβzγαβz+ταZzγαZz+τβZzγβZz1+zR11+zR2ABdαdβdZ,where σαz,σβz,σZz,ταβz,ταZz,andτβZz are the normal and shear stresses along the α, β, and Z axes on the external surface of Si and εαz,εβz,εZz,γαβz,γαZz,andγβZz denote the normal and shear strains in the α, β, and Z directions on the external surface of Si.Figure 20
Shell element in curvilinear coordinatesα, β, and z.The theory of thin-shelled structure includes two basic assumptions:(1)
γαz=0,γβz=0.(2)
σz≈0.Equation (22) can therefore be expressed as(22)Ep=12∭σαzεαz+σβzεβz+ταβzγαβz1+zR11+zR2ABdαdβdZ.Equation (23) shows Hooke’s law:(23)σαz=E1−μ2εαz+μεβz,σβz=E1−μ2εβz+μεαz,ταβz=E21+μγαβz.Equation (24) fulfils the geometrical relationships in a thin-walled cylindrical shell structure:(24)1+zR1=1,1+zR2≈1,A=B=1.Additionally, the shell element strain fulfils the following conditions [26]:(25)εα=∂v∂α+12∂w∂α2,εβ=∂u∂β+wR12∂w∂α2,A=B=1.(26)χα=−∂2w∂α2,χβ=−∂2w∂β2,χαβ=−∂2w∂β∂α.(27)εαz=εα+χαz,εβz=εβ+χβz,εαβz=γαβ+χαβz.where εα, εβ, and γαβ represent the normal and shear strains along the α and β axes on the middle surface of shell element Si; χα, χβ, and χαβ denote curvature and torsion variation in the α and β directions on the middle surface; and v, u, and w represent the deformation displacement along the α, β, and Z axes on the middle surface.Equation (22) can satisfy the relations in equations (23)–(27). The final expression of deformation energy is derived as shown in the following equation:(28)Ep=U1+U2,U1=Ehn21−μ2∬Aεα+εβ2−21−μεαεβ−14γαβ2dαdβ,U2=D2∬Aχα+χβ2−21−μχαχβ−χαβ2dαdβ.Equation (28) reveals that deformation energy EP comprises U1 and U2. U1 is the strain energy of shell element Si along the direction of thickness (the direction of blast load P(t)) and represents the strain energy of the shell element in the membrane stress state, whereas U2 includes the curvature and torsion variation parameters of middle surfaces χα, χβ, and χαβ, thus representing the bending strain energy. As stated in the above expressions, there is a relationship between deformation energy EP and the dynamic strain of the corresponding shell structures. That is, the structural variation feature in energy analysis can be reflected in changes in dynamic strain. As depicted in Figure 15 and Table 5, as the inner liquid fill level rises (from 25% to 75%), there is a significant decrease in the deformation energy of some tank walls. For example, at the 25% and 50% fill levels, the deformation energy in the sixth wall is much greater than in other parts of the tank, though its energy sharply decreases at the 75% fill level. Similar changes in deformation energy can be reflected in the structural strain energy of the middle surface (especially reflected in the circumferential or longitudinal strain of the shell element). In the following section, we compare the dynamic variation in the shell’s circumferential or longitudinal strain (Ai in Figure 19) for different fill conditions.


### 3.5. Strain Comparison

Figure21 depicts the detailed circumferential strain (along the β axis in Figure 20) and longitudinal strain (along the α axis in Figure 20) curves of Gauge A on the walls of the storage tank (shown in Figure 19 as Gauge Ai). Figure 21(a) compares the strain readings on the first wall at different liquid levels. Under the blast impact, the first tank wall experiences noticeable compression (along the β axis) when empty or 25% full. The longitudinal stress state (along the α axis) at these fill levels is quite different. The effect of compressive and tensile stresses on structures is greatly reduced as the fill level increases. For example, at the 25% fill level, the residual of the circumferential and longitudinal strains are −5855 µε and 3164 µε, respectively. In contrast, at the 75% fill level, these strain values decrease sharply, −7 µε and 11 µε, respectively. The fill level conditions seem to have minimal effect on the strain of the second tank wall, as shown in Figure 21(b).Figure 21
Comparison of circumferential strain and longitudinal strain. (a) 1st wall: (i) circumferential strain; (ii) longitudinal strain. (b) 2nd wall: (i) circumferential strain; (ii) longitudinal strain. (c) 3rd wall: (i) circumferential strain; (ii) longitudinal strain. (d) 4th wall: (i) circumferential strain; (ii) longitudinal strain. (e) 6th wall: (i) circumferential strain; (ii) longitudinal strain. (f) 7th wall: (i) circumferential strain; (ii) longitudinal strain.
(a)
(b)
(c)
(d)
(e)
(f)As described in the previous section, the tank floor and some walls—especially the first, second, and third walls—are significantly influenced by the blast impact, which causes them to warp and curl. If the height of the inner fuel liquid is greater than 11 m, the dynamic strain of the first wall is effectively relieved. However, the liquid fill has little influence on the strain curves of the second wall.Changes in the fuel liquid level also significantly influence the third through fifth walls. As shown in Figure21(c), the curves of the empty tank walls have obvious negative values along the circumferential direction and positive values along the longitudinal direction, indicating that the corresponding shell structure bears compression along the circumferential direction and tension along the longitudinal direction. In contrast, in other liquid fill conditions, the curves of the third tank wall exhibit clear oscillations near the initial strain (i.e., 0 με). Through this oscillation, the structure experiences elastic compression and tension. The dynamic strain reveals further differences between the empty and fuel-filled conditions on the fourth and fifth walls (for example, as shown in Figure 21(d)).In Figure21(e), a clear change is shown at the 50% fill level: the strain on the sixth wall increases sharply compared to other conditions when shell structure Si lies above the inner liquid (at the 50% fill level). Compared to the empty and 25% fill level conditions, the dynamic strain at the same place is weaker. By contrast, the 75% liquid fill condition has a curve with an oscillation near the initial value under the blast impact because the related shell structure Si still lies under the inner liquid.When shell elementSi is higher than the inner liquid, such as on the seventh wall (shown in Figure 21(f)) or on the eighth wall, the dynamic strain of related shell structures bears limited influence on the inner liquid. For example, when comparing the circumferential and longitudinal strain curves between the empty and fuel-filled conditions, it is difficult to find the rule underlying the change in Figure 21(f). However, the strain curves in Figure 21 show that most shell structures on the north sides of walls form compressive stress along the circumferential direction and tensile stress along the longitudinal direction, owing to the storage tank buckling deformation that occurs under the blast wave impact on the north side of the walls.


## 3.1. Failure Mode Analysis

Figure10 shows the failure of the tank structure under conditions of different fill levels and blast intensities. With a blast intensity resulting from an explosion of 1500 kg TNT equivalent mass (15600 m3 gas), Figures 10(a-i), 10(a-ii), and 10(a-iii) show the structural damage with liquid heights of 25%, 50%, and 75%, respectively. Figures 10(b-i), 10(b-ii), and 10(b-iii) show the same fill levels but for the blast intensity of a 380 kg TNT equivalent mass (4000 m3 combustible gas explosion).Figure 10
structure damage state in different blast intensity and fill conditions. (a) Under the blast intensity of 1500 kg TNT equivalent mass: (i) 25% fill level; (ii) 50% fill level; (iii) 75% fill level. (b) Under the blast intensity of 380 kg TNT equivalent mass: (i) 25% fill level; (ii) 50% fill level; (iii) 75% fill level.
(a)
(b)In general, the tank structures in Figures10(a-i)–10(a-iii) suffer more significant destruction than those in Figures 10(b-i)–10(b-iii) because of the intensity of the explosion. However, the structural damage is alleviated with increasing fill amounts of oil or liquid fuel when considering the same blast load intensity. For example, the structures in Figures 10(a-i), 10(b-i), 10(a-ii), and 10(b-ii) form clear concave deformations through all walls. Owing to the blast impact, the tank floor and walls (especially walls 1 to 4) are warped and curled up. The structures have an obvious concave deformation, which is distributed almost symmetrically along the stagnation points on the blast side. The buckling deformation of the storage tanks looks like the capital letter “W” at the 25% fill level (in Figures 10(a-i) and 10(b-i)), whereas the deformation of the tanks looks like the capital letter “V” in Figures 10(a-ii) and 10(b-ii), at the 50% fill level.By contrast, the storage tank experiences less damage with a 75% fill level. Only three tank walls (the sixth through eighth), wind girders, and ring stiffeners are deformed clearly. In this situation, the slight curling in the walls can be observed to look like the lowercase letter “v,” as in Figure10(a-iii), or a blurry letter “o,” as in Figure 10(b-iii). In Figure 10(b-iii), the tank body is mostly left intact, except for slight deformation of the wind girders (and ring stiffeners).


## 3.2. Displacement and Deformation Analysis

To determine displacementδ, a series of measuring points (Si with i = 1–8) are distributed along the storage tank at the midheight of every wall, as shown in Figure 11. The resultant displacements of Si, at 0.5 s after the detonation, are shown in Figure 12. The resultant displacement is equal to the vector superposition of vertical (+Y axis) and radial (+Z axis) displacement. The displacement of the same point was found to be affected by simulated conditions, namely, the liquid fill level and explosion intensity. In each figure, under the same blast intensity, deformation displacement δ decreased with increasing liquid fill level. The change in deformation displacement δ in the numerical simulation is consistent with the theoretical analysis.Figure 11
The distribution of measuring pointsSi: (a) front view; (b) top view.
(a)
(b)Figure 12
Resultant displacement of measuring pointsSi. (a) Intensity of 380 kg TNT equivalent mass explosion. (b) Intensity of 1500 kg TNT equivalent mass explosion.
(a)
(b)In order to reveal the influence of constraint conditions on the structure’s response under blast loads, we modified the numerical model of the storage tank to include an anchor zone on the bottom plate in the LS-DYNA 3D environment. Additionally, along the circumference of the bottom plate edge, we set the fixed constraints at an interval angle of 5°. Previous numerical results had no constraint on this edge.Figure13 shows the storage tank failure state for a blast intensity of a 1500 kg TNT equivalent mass explosion for different fill levels (25% and 50%) with the free (Figures 13(a-i) and 13(b-i)) and fixed (Figures 13(a-ii) and 13(b-ii)) constraint conditions. Compared with the free constraint conditions, the fixed constraint oil storage tanks experience more serious damage. As shown in Figures 13(a-ii) and 13(b-ii), the storage tanks deformed significantly and collapsed severely. Without the constraint condition (Figures 13(a-i) and 13(b-i)), the free bottom plate absorbed part of the blast energy through warping and deformation. Conversely, the fixed plates absorbed hardly any blast energy, meaning more was borne by the tank walls. To reduce blast damage, it is preferable to weaken the constraints on the tank’s bottom plate.Figure 13
Structural deformation and failure state in different constraint conditions. (a) Storage tank with 25% fill level: (i) no constraint; (ii) fixed constraint. (b) Storage tank with 50% fill level: (i) no constraint; (ii) fixed constraint.
(a)
(b)Analysis of the resultant displacement and deformation reveals damage to the storage tank under the blast impact in different conditions. A more detailed structural dynamic response can be revealed from an energy analysis and dynamic strain comparison.


## 3.3. Structural Energy Analysis

In Figures5 and 6, the storage tank body is composed of eight tank walls and can be divided into many elements, Si (i = 1, 2, …, N). In this section, we analyze the energy variation of shell elements Si under the blast impact in two tank conditions: empty and liquid filled.Condition 1 (empty).
Suppose blast loadPt is at the center of shell element Si and forms deformation displacement δ1 (as shown in Figures 14(a) and 14(b)). The resistance force to the impact is D × δ1, where D is the resistance coefficient of the structure (shell element Si). Work W1 is the Pt working along deformation displacement δ1. At the moment of blast impact, Si start to move with velocity vt. The equations of load and work can be described as follows:(7)Pt=D×δ1+m1dvtdt,W1=Pt×δ1.
Under the blast impact, after the plastic deformation displacementδ1max, the velocity and kinetic energy of Si are almost zero. Ignoring the heat loss during the interaction between the blast wave and the structure, work W1 is transformed into the element’s deformation energy, EP1. The change can be expressed as(8)Pt×δ1⋅max=EP1.Figure 14
Diagram of shell elementSi in two separate conditions. (a) Shell element in empty condition. (b) Deformation displacement of Si. (c) Shell element and added liquid mass. (d) Deformation displacement of shell element.
(a)
(b)
(c)
(d)Condition 2 (liquid filled).
When the storage tank is filled with liquid, most shell elements (on the wall) move or vibrate together with the inner liquid, as affected by blast loadingPt. Suppose the mass of shell element Si and the added liquid are m1 and m2. Under the Pt impact effect, Si has deformation displacement δ2 and its resistance to the impact force is D × δ2. Similarly to the empty condition, parameters Pt, δ2, and vt have the following relationship:(9)Pt=D×δ2+m1+m2dvtdt.
Under the same intensityPt, the deformation displacement fulfils the relation δ1 > δ2 in two separate conditions. When the impacted regions of the wall ultimately exhibit plastic deformation, the inner liquid may separate from the structure and continue to shake for a moment. Under the same loading effect, the input energy is changed into two parts—the plastic deformation energy and the kinematic energy of the liquid. The ultimate deformation of shell element Si is δ2·max, but the added liquid mass still moves with velocity v2.
Ignoring heat loss, workW2 can be transformed into deformation energy EP2 and the kinetic energy of liquid, KEliquid, and can be expressed as follows:(10)Pt×δ2⋅max=EP2+KEliquid=EP2+12m2v22,EP2=Pt×δ2⋅max−12m2v22.
Moreover, blast loadP(t) forms an impulse on shell element Si. According to the theory of impulse, Si has specific impulse i(t):(11)it=∫0tptdτ.
Owing to the momentum during the blast, the velocity ofSi is(12)ν1t=itρnhn,where ρn and hn represent the material density and thickness of Si and ρn × hn represents its unit mass. Assuming that the impact load on Si is absorbed, it is completely converted into the initial kinetic energy of the shell element when the storage tank is empty. Hence, the absorbing energy expression is given by(13)Ea=i2t2ρnhn=Ep1.
In the above equation,Ea represents the structural absorption energy that is converted into deformation energy EP1. Alternatively, in the liquid-filled condition, the velocity of Si with added liquid mass m2 is(14)ν2t=itρnhn+ρ0c0t=∫0tptdτρnhn+ρ0c0t.
In this expression,ρ0 represents the density of the liquid and c0 represents the speed of sound in the liquid, while ρ0 × c0 × t represents the unit mass of the added liquid. Equation (14) also supposes that the impact load on the Si was absorbed and was completely changed into the initial kinetic energy of shell element Si and added liquid m2. Under such conditions, the absorbing energy can be expressed as equations (15) and (16), where EP2 represents the deformation energy of shell element Si:(15)Eb=i2t2ρnhn+ρ0c0t=EP2+KEliquid,(16)EP2=i2t2ρnhn+ρ0c0t−KEliquid.
Comparison between equations (13) and (15) reveals that if the shell elements move together with the added liquid mass, their deformation energy can be partly reduced compared to the empty condition; that is, EP2 < EP1.
The tank walls are composed of many shell elements. When empty,E1 represents the total deformation energy of the tank wall, as(17)E1=∑i=1nEP1i.
In the liquid-filled conditions,E2 represents the total deformation energy of the tank wall:(18)E2=∑i=1nEP2i.
The relationship betweenE1 and E2 fulfils the following condition:(19)E1>E2.
Under the impact of a 1500 kg TNT equivalent mass explosion, Figure15 shows time-history curves of the kinetic energy KE and deformation energy EP of different parts of the tank: the tank walls, wind girders, and bottom plate. The liquid level is the main simulation variable in Figure 13. According to the KE curves, 20–50 ms after detonation, the wind girders and most tank walls reach their maximum energy value. In contrast, most structure parts form visible residue energy on their EP curves after 0.5 s. The energy variation in the KE and EP curves reveals that the blast energy is absorbed by structures and is converted into deformation energy.
Furthermore, Tables5 and 6 list the collected EP data of the different tank parts at the simulation termination. Table 5 compares the data for different liquid levels in storage tanks with no constraints, whereas Table 6 shows the energy data for fixed constraint conditions. Tables 5 and 6, as well as Figure 15, reveal the following structural energy and failure features of the storage tank structure:(1)
Compared with other parts of the storage tank, the energy values of the wind girders are noticeably higher. The deformed wind girders absorb 35–65% of total deformation energy. These girders are always designed to have a thin-walled rectangular shape and cantilever structures. They are designed to enhance the lateral stiffness of the storage tank and resist the lateral load of wind. As they are not designed considering blast impact effects, the wind girders, with their cantilever shape, are apt to be destroyed.(2)
Under the blast impact, the tank walls stored some energy in structures via deformation. Followed by increases in the inner liquid (from the 25% to 75% fill level), the declining tendency of deformation energy is notable. At the 25% and 50% fill levels, the most energy was absorbed by the sixth wall; at the 75% fill level, the eighth wall absorbed the most energy. The same trend occurs in Tables5 and 6 (highlighted in bold). For further analysis of the energy variation for tank walls, we undertake a detailed quantitative comparison of the energy feature analysis in next paragraphs, with consideration of liquid levels, constraint conditions, and blast load intensity.(3)
As shown in Figure14, the bottom plate with no constraints warps and distorts under the blast wave. Table 5 compares the deformation energy of the bottom plate for different liquid levels. At the 25% fill level, the bottom plate forms 15.35 MJ energy, which accounts for 9.3% of the total energy. When the inner liquid rises to the 50% fill level, the value significantly declines to 2.9 MJ and only accounts for 2.8% of the total energy. The energy becomes the lowest at the 75% fill level, where it is 0.22 MJ, which is less than 0.5% of the total energy. In Table 6, for all liquid levels, the deformation energy of bottom plate is zero because of the fixed constraint condition applied to these simulations. Regardless of constraint condition, most energy is absorbed by tank walls and other structures.
To analyze the energy features, we compared the energy data of five typical tank walls—the first, third, fifth, sixth, and eighth. The parameters KEmax and EPT are used to represent the peak value in the KE curve and the EP curve at the termination time (0.5 s) respectively, as shown in Figure 16. Figure 17 shows a comparison of these two parameters in different simulation conditions and describes the variation in structural energy quantitatively.
In Figures17(a-i) and 17(b-i), the KEmax parameter curves increase gradually from the first to the fifth tank walls for the 25% and 50% fill level conditions. The curves peak at the fifth or sixth wall. In the 75% fill level condition, KEmax grows by a small amount from the first wall to the sixth wall but increases dramatically at the eighth wall. Compared with the fixed constraint model, the KEmax value of the free constraint model is larger (especially at the first and third walls). The influence of the fixed bottom plate restricts the movement of the tank walls and reduces to the kinetic energy. The KEmax comparison shows that the storage tank walls produce a similar response (in the free and fixed constraint conditions) during the initial impact phase. This initial dynamic response might be closely related to the structural style of the thin-walled cylindrical shell.
The fixed constraint model leads to higher values of parameterEPT than the free constraint model, especially at the 25% and 50% fill levels. In the fixed model, the bottom plate absorbs almost no energy from the blast wave. In the free constraint model, the free bottom plate dissipates the blast energy through deformation and sliding friction, which reduces the energy that the remaining walls and structure must absorb.
The bar charts in Figure18 compare the total values of EPT for structures with different liquid levels. Here, the deformation energy of an empty storage tank was also calculated. In Figure 18, increasing fill levels clearly reduce the deformation energy. This reduction is found for both conditions of constraint and blast intensities.
For instance, in the 1500 kg TNT equivalent mass explosion condition, the fixed and free constraint models at the 75% fill level have only 21.8% and 17.2% of the deformation energy of the empty tank, respectively. At the 380 kg TNT equivalent mass explosion intensity, a similar trend in deformation energy was observed. As shown in Figure18(b), at a fill level of 75%, the fixed and the free constraint values observed were only 6.13% and 6.9% of the deformation energy of an empty tank for the respective constraint conditions. Comparing the EPT of the fixed and free constraint models, Figure 18(b) shows that the free constraint condition reduces the impact effect on the tank structures.
The results in Figure18 indicate that the inner liquid absorbs part of the energy from the blast wave. It reduces the impact of the blast on the storage tanks and the deformation energy.Figure 15
The energy curves comparison under intensity of 1500 kg TNT equivalent mass explosion. (a) Wind girders (ring stiffeners). (b) 8th wall. (c) 6th wall. (d) 5th wall. (e) 3rd wall. (f) 1st wall. (g) Bottom plate.
(a)
(b)
(c)
(d)
(e)
(f)
(g)Table 5
Deformation energy of storage tank with no constraint (unit: MJ).
Structure
25% filled (Hliquid = 5.4 m)
50% filled (Hliquid = 11 m)
75% filled (Hliquid = 16 m)
Deformation energy (EPT)
Percentage
Deformation energy (EPT)
Percentage
Deformation energy (EPT)
Percentage
Bottom plate
15.35
9.3
2.9
2.8
0.22
0.41
1st wall
11.8
7.2
4.48
4.3
0.07
0.13
2nd wall
8.45
5.1
1.45
1.4
0.03
0.06
3rd wall
12.08
7.3
2.81
2.7
0.03
0.05
4th wall
8.22
5
1.57
1.5
0.13
0.25
5th wall
13.32
8.1
8.57
8.1
0.84
1.6
6th wall
16.09
9.7
12.13
11.5
1.88
3.4
7th wall
8.52
5.2
9
8.5
7.09
13
8th wall
13.70
8.3
11.63
11
9.51
17.4
Wind girders
57.4
34.8
50.78
48.2
34.78
63.7
Total energy
164.93
105.33
54.6Table 6
Deformation energy of oil storage tank with fixed constraint (unit: MJ).
Structure
25% filled (Hliquid = 5.4 m)
50% filled (Hliquid = 11 m)
75% filled (Hliquid = 16 m)
Deformation energy (EPT)
Percentage
Deformation energy (EPT)
Percentage
Deformation energy (EPT)
Percentage
Bottom plate
0
0
0
0
0
0
1st wall
23.68
12.3
9.41
7
0.14
0.18
2nd wall
8.14
4.2
5.21
3.9
0.93
1.2
3rd wall
11.07
5.8
2.98
2.2
0.76
0.99
4th wall
9.84
5.1
4.61
3.4
0.89
1.2
5th wall
15.5
8.1
10.54
7.9
2.17
2.8
6th wall
24.16
12.6
16.27
12.1
4.7
6.1
7th wall
13.75
7.2
12.55
9.4
10.06
13.1
8th wall
19.39
10.1
16.11
12
18.92
24.6
Wind girders
66.33
34.6
56.44
42.1
38.37
49.9
Total energy
191.85
134.22
76.95Figure 16
Schematic of energy feature parameters.Figure 17
Comparisons of energy parameters under different intensities. (a) Intensity of 1500 kg TNT equivalent mass explosion: (i) KEmax; (ii) EPT. (b) Intensity of 380 kg TNT equivalent mass explosion: (i) KEmax; (ii) EPT.
(a)
(b)Figure 18
Comparisons of deformation energy (E)PT in different simulation conditions. (a) Intensity of 1500 kg TNT equivalent mass explosion. (b) Intensity of 380 kg TNT equivalent mass explosion.
(a)
(b)


## 3.4. Dynamic Strain Analysis

Figure19 shows several measurement gauges Ai (i = 1, 2, …, 8) that represent related shell elements Si, which are located on each tank wall. The following sections compare the effective strain curves of gauges Ai under the blast intensity of a 1500 kg TNT equivalent mass explosion.Figure 19
Layout of strain measuring gauges.If the lengths of shell elementSi are dSα, dSβ, and dZ, the volume of Si fulfils the following relation:(20)dV=dSα⋅dSβ⋅dZ=AB1+zR11+zR2dαdβdZ.In equation (20), A and R1 represent the Lame coefficient and radius of curvature in the α direction in the curvilinear coordinates in Figure 20; B and R2 denote the Lame coefficient and radius of curvature in the β direction in the same curvilinear coordinates; and z indicates the distance between the external (or internal) surface and the middle surface. Therefore, the deformation energy of shell element EP can be expressed as(21)dEp=12σαzεαz+σβzεβz+σZzεZz+ταβzγαβz+ταZzγαZz+τβZzγβZz1+zR11+zR2ABdαdβdZ,where σαz,σβz,σZz,ταβz,ταZz,andτβZz are the normal and shear stresses along the α, β, and Z axes on the external surface of Si and εαz,εβz,εZz,γαβz,γαZz,andγβZz denote the normal and shear strains in the α, β, and Z directions on the external surface of Si.Figure 20
Shell element in curvilinear coordinatesα, β, and z.The theory of thin-shelled structure includes two basic assumptions:(1)
γαz=0,γβz=0.(2)
σz≈0.Equation (22) can therefore be expressed as(22)Ep=12∭σαzεαz+σβzεβz+ταβzγαβz1+zR11+zR2ABdαdβdZ.Equation (23) shows Hooke’s law:(23)σαz=E1−μ2εαz+μεβz,σβz=E1−μ2εβz+μεαz,ταβz=E21+μγαβz.Equation (24) fulfils the geometrical relationships in a thin-walled cylindrical shell structure:(24)1+zR1=1,1+zR2≈1,A=B=1.Additionally, the shell element strain fulfils the following conditions [26]:(25)εα=∂v∂α+12∂w∂α2,εβ=∂u∂β+wR12∂w∂α2,A=B=1.(26)χα=−∂2w∂α2,χβ=−∂2w∂β2,χαβ=−∂2w∂β∂α.(27)εαz=εα+χαz,εβz=εβ+χβz,εαβz=γαβ+χαβz.where εα, εβ, and γαβ represent the normal and shear strains along the α and β axes on the middle surface of shell element Si; χα, χβ, and χαβ denote curvature and torsion variation in the α and β directions on the middle surface; and v, u, and w represent the deformation displacement along the α, β, and Z axes on the middle surface.Equation (22) can satisfy the relations in equations (23)–(27). The final expression of deformation energy is derived as shown in the following equation:(28)Ep=U1+U2,U1=Ehn21−μ2∬Aεα+εβ2−21−μεαεβ−14γαβ2dαdβ,U2=D2∬Aχα+χβ2−21−μχαχβ−χαβ2dαdβ.Equation (28) reveals that deformation energy EP comprises U1 and U2. U1 is the strain energy of shell element Si along the direction of thickness (the direction of blast load P(t)) and represents the strain energy of the shell element in the membrane stress state, whereas U2 includes the curvature and torsion variation parameters of middle surfaces χα, χβ, and χαβ, thus representing the bending strain energy. As stated in the above expressions, there is a relationship between deformation energy EP and the dynamic strain of the corresponding shell structures. That is, the structural variation feature in energy analysis can be reflected in changes in dynamic strain. As depicted in Figure 15 and Table 5, as the inner liquid fill level rises (from 25% to 75%), there is a significant decrease in the deformation energy of some tank walls. For example, at the 25% and 50% fill levels, the deformation energy in the sixth wall is much greater than in other parts of the tank, though its energy sharply decreases at the 75% fill level. Similar changes in deformation energy can be reflected in the structural strain energy of the middle surface (especially reflected in the circumferential or longitudinal strain of the shell element). In the following section, we compare the dynamic variation in the shell’s circumferential or longitudinal strain (Ai in Figure 19) for different fill conditions.


## 3.5. Strain Comparison

Figure21 depicts the detailed circumferential strain (along the β axis in Figure 20) and longitudinal strain (along the α axis in Figure 20) curves of Gauge A on the walls of the storage tank (shown in Figure 19 as Gauge Ai). Figure 21(a) compares the strain readings on the first wall at different liquid levels. Under the blast impact, the first tank wall experiences noticeable compression (along the β axis) when empty or 25% full. The longitudinal stress state (along the α axis) at these fill levels is quite different. The effect of compressive and tensile stresses on structures is greatly reduced as the fill level increases. For example, at the 25% fill level, the residual of the circumferential and longitudinal strains are −5855 µε and 3164 µε, respectively. In contrast, at the 75% fill level, these strain values decrease sharply, −7 µε and 11 µε, respectively. The fill level conditions seem to have minimal effect on the strain of the second tank wall, as shown in Figure 21(b).Figure 21
Comparison of circumferential strain and longitudinal strain. (a) 1st wall: (i) circumferential strain; (ii) longitudinal strain. (b) 2nd wall: (i) circumferential strain; (ii) longitudinal strain. (c) 3rd wall: (i) circumferential strain; (ii) longitudinal strain. (d) 4th wall: (i) circumferential strain; (ii) longitudinal strain. (e) 6th wall: (i) circumferential strain; (ii) longitudinal strain. (f) 7th wall: (i) circumferential strain; (ii) longitudinal strain.
(a)
(b)
(c)
(d)
(e)
(f)As described in the previous section, the tank floor and some walls—especially the first, second, and third walls—are significantly influenced by the blast impact, which causes them to warp and curl. If the height of the inner fuel liquid is greater than 11 m, the dynamic strain of the first wall is effectively relieved. However, the liquid fill has little influence on the strain curves of the second wall.Changes in the fuel liquid level also significantly influence the third through fifth walls. As shown in Figure21(c), the curves of the empty tank walls have obvious negative values along the circumferential direction and positive values along the longitudinal direction, indicating that the corresponding shell structure bears compression along the circumferential direction and tension along the longitudinal direction. In contrast, in other liquid fill conditions, the curves of the third tank wall exhibit clear oscillations near the initial strain (i.e., 0 με). Through this oscillation, the structure experiences elastic compression and tension. The dynamic strain reveals further differences between the empty and fuel-filled conditions on the fourth and fifth walls (for example, as shown in Figure 21(d)).In Figure21(e), a clear change is shown at the 50% fill level: the strain on the sixth wall increases sharply compared to other conditions when shell structure Si lies above the inner liquid (at the 50% fill level). Compared to the empty and 25% fill level conditions, the dynamic strain at the same place is weaker. By contrast, the 75% liquid fill condition has a curve with an oscillation near the initial value under the blast impact because the related shell structure Si still lies under the inner liquid.When shell elementSi is higher than the inner liquid, such as on the seventh wall (shown in Figure 21(f)) or on the eighth wall, the dynamic strain of related shell structures bears limited influence on the inner liquid. For example, when comparing the circumferential and longitudinal strain curves between the empty and fuel-filled conditions, it is difficult to find the rule underlying the change in Figure 21(f). However, the strain curves in Figure 21 show that most shell structures on the north sides of walls form compressive stress along the circumferential direction and tensile stress along the longitudinal direction, owing to the storage tank buckling deformation that occurs under the blast wave impact on the north side of the walls.


## 4. Conclusions

In this paper, we have described the dynamic response of and damage to a simplified storage tank prototype with a capacity of 15 × 104 m3. First, we introduced an experimental scale-model explosion test, the results of which were then used to validate numerical models that provide a tool for extensive assessment. Subsequently, the numerical models were employed to examine storage tanks with different conditions. Their dynamic response was simulated in nonlinear FE software, LS-DYNA. The key findings can be summarized as follows:(1)
When considering the effect of constraint conditions, fixed tanks deform significantly and collapse more easily because a free bottom plate absorbs part of the blast energy through warping and deformation, whereas a fixed base plate absorbs little energy. Hence, to reduce blast impacts, it is preferable to weaken constraints on the tank’s bottom plate.(2)
Over time, the walls form energy in the process of deformation under the blast impact. This deformation energy decreases with increases in the inner liquid level (from 25% to 75%).(3)
Combined with theoretical analysis, the previous result demonstrates that liquid may absorb energy from the blast wave. Liquid can reduce the structural deformation energy and the effect of blast loading on a storage tank. Thus, increasing the level of fuel liquid in storage tanks can play a positive role in relieving the impact of a blast wave.(4)
Owing to their thin-walled rectangular shape and cantilever structural style (designed for resisting lateral loads from wind), wind girders (ring stiffeners) are prone to damage from blast impacts. Compared with other structures, wind girders are more seriously damaged and form more deformation energy.(5)
Theoretical analysis of shell element deformation energyEP shows that it is composed of two parts: strain energy U1 and bending strain energy U2. Therefore, if EP is changed in simulation conditions, similar changes are reflected in the structural strain energy of the middle surface (especially in the circumferential or longitudinal strain of the shell element).



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*Source: 6515462-2019-08-14.xml*