# Research and Modeling of the Bidirectional Half-Bridge Current-Doubler DC/DC Converter

Authors: Liang Huang; Xinchao Dong; Changjun Xie; Shuhai Quan; Yang Gao
Journal: International Journal of Rotating Machinery
 (2017)

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## Abstract

Due to its high step-up voltage ratio, high utilization rate, and good stability, the bidirectional half-bridge current-doubler topology is widely used in lithium battery system. This paper will further analyze the bidirectional half-bridge current-doubler topology. Taking into account the fact that the current is not equal to the two times current inductance may lead to a greater transformer magnetizing current leaving the transformer core saturation occurring. This paper will focus on the circuit modeling of steady-state analysis and small signal analysis, analyzing the influence parameters for the inductor current by steady-state model and analyzing the stability of the system by the small signal model. The PID controllers and soft start algorithm are designed. Then the influence of circuit parameters on the steady state and the effect of soft start algorithm is verified, and finally the function of the soft start algorithm is achieved by the experimental prototype.


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## Body

## 1. Introduction

The bidirectional half-bridge current-doubler circuit is widely used in the lithium batteries formation for it can achieve low-voltage and high-current two-way flow of energy [1–5]. This circuit topology not only has a higher voltage utilization but also can meet the requirements of the higher ratio of the buck-boost. This article mainly analyzes the steady-state and transient modeling of small signal model of the bidirectional half-bridge current-doubler circuit, the inductor current sharing issues and factors that affect the magnetic deflection of the transformer by the steady-state model, the stability of the closed loop circuit by the transient modeling of small signal model, and the design of the soft start circuit control algorithms.


## 2. Analysis of the Bidirectional Half-Bridge Current-Double Topology

The bidirectional half-bridge current-doubler topology is shown in Figure1. The main circuit has charging mode and discharging mode of two working states. The charging mode energy flows from the bus to the battery, and the discharge mode energy is transmitted to the bus by the battery. In steady state, the duty cycle of the two MOSFET drive waveforms of the battery side is greater than 50%, but in the process of the discharge mode’s soft start, the two MOSFETs are not conducting situation. At this time there is no inductor current flow circuit and leakage source of the MOSFET will produce a very high-voltage spike and may breakdown the MOSFET to form the energy storage in the loop release inductance [6]. Using the principle of flyback converter for reference, adding a flyback winding to the inductor is available. When the MOSFET is not turned on, the energy of the inductor can be transferred to the high-pressure side through the flyback winding.Figure 1
Circuit topology of bidirectional half-bridge current-doubler converter.


## 3. Modeling of the Bidirectional Half-Bridge Current-Double DC/DC Converter

### 3.1. Steady-State Modeling of Circuit Analysis

Before the modeling analysis, simplify the circuit. The flyback winding is mainly working in the soft start of the battery discharge mode, and the flyback winding does not work under normal operating mode, so in the analysis of steady state the two-flyback inductor is regarded as two-common inductor. In the steady-state modeling and analysis, the equivalent resistance of the high-voltage sideUbus switch tube and the equivalent resistance of the transformer are converted into the equivalent resistance RT of the low-voltage side Ubat of the transformer. The excitation inductance of the transformer is expressed by Lm, RL1 and RL2 are used to show the equivalent resistance of the low-voltage side inductance L1 and L2, respectively, and Rs1 and Rs2 are used to show the conduction resistance of Q1 and Q2 in the low-voltage side switch.Here, this paper only analyzes the energy transfer from the high-voltage side to low-voltage side.Vin represents the voltage of the bus Ubus; Io indicates the output current when charging the battery. In the charging state of the battery, the working cycle of the circuit can be seen as 4 modes; the operating cycle of the circuit is T. Modal 1:Q2 and Q3 are turned on; conduction time is d1T; Modal 2:Q1 and Q2 are turned on; conduction time is (1/2-d1)T; Modal 3:Q1 and Q4 are turned on; conduction time is d2T; Modal 4:Q1 and Q2 are turned on; conduction time is (1/2-d2)T. The equivalent model of each model is shown in Figure 2. Then calculate the equation of state of the circuit in a period. First, define the state of the circuit equation as (1)X˙=Aix+Biu,i=1,2,3,4,where i correspond to four different working modes. The state variables and the input variables are shown in formula (2):(2)X˙=C1+C2dVC1dtL1diL1dtL2diL2dtCdVCdtLmdimdt,x=VC1iL1iL2VCim,u=VinI0.Figure 2
Working mode equivalent model.According to the equivalent model of each mode in Figure2 and the basic theory of the circuit, we can calculate the transfer matrix expression for each mode of state equation, respectively, as shown in formula (3):(3)A1=01n001n1n-RT+RL1+RC+Rs2-RC+Rs2-100-Rs2+RC-RL2+RC+Rs2-10011001n0000,A2=000000-RL1+RC+Rs1-RC-1-Rs10-RC-RL2+RC+Rs2-1Rs2011000-Rs1Rs20-Rs1+Rs2,A3=001n01n0-RL1+RC+Rs1-RC+Rs1-10-1n-Rs1+RC-RT+RL2+RC+Rs1-10011001n0000,A4=000000-RL1+RC+Rs1-RC-1-Rs10-RC-RL2+RC+Rs2-1Rs2011000-Rs1Rs20-Rs1+Rs2,B1=000RC0RC0-100,B2=000RC0RC0-100,B3=000RC1nRC0-11n0,B4=000RC0RC0-100.According to the principle of state space averaging method, we analyze four modes’ state equation and can get the transfer matrix of the state variables and the input variables, forA and B. The matrices A and B meet such as shown in formula (4):(4)A=d1TA1+12-d1TA2+d2TA3+12-d2TA4,B=d1TB1+12-d1TB2+d2TB3+12-d2TB4,A2=A4,B2=B4.In the same way, if we analyze the energy from the low-voltage side to the high-voltage side of the discharge, the relation equation shown in formula (4) still exists. It is know that, in steady state, the inductance meet “Volt-Second” balance and the capacitance meet “Ampere-Second” balance in one cycle. So in a cycle to meet the relationship, X˙=0, and at the same time there is a relational: x=-A-1BU. According to this formula as well as the previously required matrix expression (3) and (4), we can get the relationship equation inductor current and transformer magnetizing current to satisfy formula (5):(5)IL1=d2TRT+RL2RL1+RL2+d1+d2TRTIO,IL2=d1TRT+RL1RL1+RL2+d1+d2TRTIO,IM=d2RL1-d1RL2d1+d2RL1+RL2+d1+d22RTIO.From (5), this paper analyzes and draws the following conclusions: The size of the inductor current is only related to the equivalent resistance of the inductor and the duty cycle and is not related to the equivalent resistance of the MOSFET conduction at the low-voltage side; the excitation current is mainly influenced by the MOSFET conduction resistance and the driving duty cycle of the low-voltage side. When the deviation is large, it will generate a large excitation current; the excitation current lead core along the hysteresis loop shifts back and forth. When the core is saturated into the offset the switch tube will be damaged. Then you need to take transformer design and switch tube selection into account to prevent the transformer appear saturable core.


### 3.2. Analysis of Switch Average Model Method in Small Signal Modeling

To design the controller, the small signal modeling and analysis of the controlled object are needed [7–9]. From the analysis of the front and the equivalent model, it is found that the four modes of a working cycle of the circuit are symmetrical. According to the flow of energy per half cycle it can be equivalent to a buck or boost circuit to analyze. Here, we only analyze the small signal model of the discharge mode that is the circuit boost mode. From the structure of the circuit, we can see that the discharge mode and principle of boost circuit principle are consistent. So the load of the high-voltage side can be equivalent to the low-voltage side by the transformer ratio conversion relationship. Because the four operating modes of the circuit are symmetrical, it just needs to analyze the working mode of a bridge arm in half period to be equivalent to the small signal model of the circuit, so it can be transposed into a boost circuit modeling. The average circuit model of boost circuit is shown in Figure 3.Figure 3
Boost circuit CCM average switching model.In Figure3, we replace the average current of the switch device with the current source iQ, the voltage source vD instead of the average voltage of the ends of the diode. Equivalent combined resistance r contains the circuit inductor DC resistance, the switch tube conduction resistance, and the diode conduction resistance. According to the principle of boost circuit we can obtain formula (6):(6)iQ=dtiLtTs,vD=dtvotTs.Injection disturbance in steady state: the relation equation (7) can be obtained:(7)iQ=D+d^tIL+iL^t=DIL+DiL^t+d^tIL+d^tiL^t,vD=D+d^tVo+vo^t=DVo+Dvo^t+d^tVo+d^tvo^t.Among them,d^t, iL^t, and vo^t are disturbance. The product term of the small signal component of d^tvo^t is the two-order microquantity. When the converter meets the small signal hypothesis, it can be ignored. Then the large signal model of boost circuit can be obtained. Eliminate a DC term in the DIL and DVo, and the remaining two of the linear terms represent the role of AC small signal. Small signal model is shown in Figure 4.Figure 4
Boost circuit CCM small signal model.In Figure4, the parameters of each component are s domain parameters. According to KCL and KVL theorem as formula equations (8), we have the following:(8)iLs=DiLs+dsIL+ios-iLsZ1+Dvos+dsVo-vos=0,ios=vosZ2,IL=Io1-D,Z1=sL+r,Z2=1sC+rcR.By equation group (8) we can get the traditional function of the current to the duty cycle, such as formula (9):(9)Gs=iLsds=Vo1+Z2/RZ21-D2+Z1=Vo1+1/sC+rcR/R1-D21/sC+rcR+sL+r.The design parameters of the circuit are as follows: transformer ratio:n=1.4, inductance: L=100 μH, and capacitance: C=450 μF. Converter efficiency is 0.9, the transformer is regarded as a voltage amplifier, the high-voltage side voltage is converted to the low-voltage side, and the input voltage is the lowest value: Ubat=43 V; we can get(10)Vo=Vbus2n=138.18V,R=Vo2ηPin=7.89Ω,D=1-VinVo=0.689.Since the inductance is small, the inductor DC resistance is also small, the conduction resistance of MOSFET is about several milliohms, and, in order to facilitate the calculation, these three small items can be ignored, the system’s transfer function is as follows:(11)Gs=1.384·106s+644s2+381.19s+2.146·106.


## 3.1. Steady-State Modeling of Circuit Analysis

Before the modeling analysis, simplify the circuit. The flyback winding is mainly working in the soft start of the battery discharge mode, and the flyback winding does not work under normal operating mode, so in the analysis of steady state the two-flyback inductor is regarded as two-common inductor. In the steady-state modeling and analysis, the equivalent resistance of the high-voltage sideUbus switch tube and the equivalent resistance of the transformer are converted into the equivalent resistance RT of the low-voltage side Ubat of the transformer. The excitation inductance of the transformer is expressed by Lm, RL1 and RL2 are used to show the equivalent resistance of the low-voltage side inductance L1 and L2, respectively, and Rs1 and Rs2 are used to show the conduction resistance of Q1 and Q2 in the low-voltage side switch.Here, this paper only analyzes the energy transfer from the high-voltage side to low-voltage side.Vin represents the voltage of the bus Ubus; Io indicates the output current when charging the battery. In the charging state of the battery, the working cycle of the circuit can be seen as 4 modes; the operating cycle of the circuit is T. Modal 1:Q2 and Q3 are turned on; conduction time is d1T; Modal 2:Q1 and Q2 are turned on; conduction time is (1/2-d1)T; Modal 3:Q1 and Q4 are turned on; conduction time is d2T; Modal 4:Q1 and Q2 are turned on; conduction time is (1/2-d2)T. The equivalent model of each model is shown in Figure 2. Then calculate the equation of state of the circuit in a period. First, define the state of the circuit equation as (1)X˙=Aix+Biu,i=1,2,3,4,where i correspond to four different working modes. The state variables and the input variables are shown in formula (2):(2)X˙=C1+C2dVC1dtL1diL1dtL2diL2dtCdVCdtLmdimdt,x=VC1iL1iL2VCim,u=VinI0.Figure 2
Working mode equivalent model.According to the equivalent model of each mode in Figure2 and the basic theory of the circuit, we can calculate the transfer matrix expression for each mode of state equation, respectively, as shown in formula (3):(3)A1=01n001n1n-RT+RL1+RC+Rs2-RC+Rs2-100-Rs2+RC-RL2+RC+Rs2-10011001n0000,A2=000000-RL1+RC+Rs1-RC-1-Rs10-RC-RL2+RC+Rs2-1Rs2011000-Rs1Rs20-Rs1+Rs2,A3=001n01n0-RL1+RC+Rs1-RC+Rs1-10-1n-Rs1+RC-RT+RL2+RC+Rs1-10011001n0000,A4=000000-RL1+RC+Rs1-RC-1-Rs10-RC-RL2+RC+Rs2-1Rs2011000-Rs1Rs20-Rs1+Rs2,B1=000RC0RC0-100,B2=000RC0RC0-100,B3=000RC1nRC0-11n0,B4=000RC0RC0-100.According to the principle of state space averaging method, we analyze four modes’ state equation and can get the transfer matrix of the state variables and the input variables, forA and B. The matrices A and B meet such as shown in formula (4):(4)A=d1TA1+12-d1TA2+d2TA3+12-d2TA4,B=d1TB1+12-d1TB2+d2TB3+12-d2TB4,A2=A4,B2=B4.In the same way, if we analyze the energy from the low-voltage side to the high-voltage side of the discharge, the relation equation shown in formula (4) still exists. It is know that, in steady state, the inductance meet “Volt-Second” balance and the capacitance meet “Ampere-Second” balance in one cycle. So in a cycle to meet the relationship, X˙=0, and at the same time there is a relational: x=-A-1BU. According to this formula as well as the previously required matrix expression (3) and (4), we can get the relationship equation inductor current and transformer magnetizing current to satisfy formula (5):(5)IL1=d2TRT+RL2RL1+RL2+d1+d2TRTIO,IL2=d1TRT+RL1RL1+RL2+d1+d2TRTIO,IM=d2RL1-d1RL2d1+d2RL1+RL2+d1+d22RTIO.From (5), this paper analyzes and draws the following conclusions: The size of the inductor current is only related to the equivalent resistance of the inductor and the duty cycle and is not related to the equivalent resistance of the MOSFET conduction at the low-voltage side; the excitation current is mainly influenced by the MOSFET conduction resistance and the driving duty cycle of the low-voltage side. When the deviation is large, it will generate a large excitation current; the excitation current lead core along the hysteresis loop shifts back and forth. When the core is saturated into the offset the switch tube will be damaged. Then you need to take transformer design and switch tube selection into account to prevent the transformer appear saturable core.


## 3.2. Analysis of Switch Average Model Method in Small Signal Modeling

To design the controller, the small signal modeling and analysis of the controlled object are needed [7–9]. From the analysis of the front and the equivalent model, it is found that the four modes of a working cycle of the circuit are symmetrical. According to the flow of energy per half cycle it can be equivalent to a buck or boost circuit to analyze. Here, we only analyze the small signal model of the discharge mode that is the circuit boost mode. From the structure of the circuit, we can see that the discharge mode and principle of boost circuit principle are consistent. So the load of the high-voltage side can be equivalent to the low-voltage side by the transformer ratio conversion relationship. Because the four operating modes of the circuit are symmetrical, it just needs to analyze the working mode of a bridge arm in half period to be equivalent to the small signal model of the circuit, so it can be transposed into a boost circuit modeling. The average circuit model of boost circuit is shown in Figure 3.Figure 3
Boost circuit CCM average switching model.In Figure3, we replace the average current of the switch device with the current source iQ, the voltage source vD instead of the average voltage of the ends of the diode. Equivalent combined resistance r contains the circuit inductor DC resistance, the switch tube conduction resistance, and the diode conduction resistance. According to the principle of boost circuit we can obtain formula (6):(6)iQ=dtiLtTs,vD=dtvotTs.Injection disturbance in steady state: the relation equation (7) can be obtained:(7)iQ=D+d^tIL+iL^t=DIL+DiL^t+d^tIL+d^tiL^t,vD=D+d^tVo+vo^t=DVo+Dvo^t+d^tVo+d^tvo^t.Among them,d^t, iL^t, and vo^t are disturbance. The product term of the small signal component of d^tvo^t is the two-order microquantity. When the converter meets the small signal hypothesis, it can be ignored. Then the large signal model of boost circuit can be obtained. Eliminate a DC term in the DIL and DVo, and the remaining two of the linear terms represent the role of AC small signal. Small signal model is shown in Figure 4.Figure 4
Boost circuit CCM small signal model.In Figure4, the parameters of each component are s domain parameters. According to KCL and KVL theorem as formula equations (8), we have the following:(8)iLs=DiLs+dsIL+ios-iLsZ1+Dvos+dsVo-vos=0,ios=vosZ2,IL=Io1-D,Z1=sL+r,Z2=1sC+rcR.By equation group (8) we can get the traditional function of the current to the duty cycle, such as formula (9):(9)Gs=iLsds=Vo1+Z2/RZ21-D2+Z1=Vo1+1/sC+rcR/R1-D21/sC+rcR+sL+r.The design parameters of the circuit are as follows: transformer ratio:n=1.4, inductance: L=100 μH, and capacitance: C=450 μF. Converter efficiency is 0.9, the transformer is regarded as a voltage amplifier, the high-voltage side voltage is converted to the low-voltage side, and the input voltage is the lowest value: Ubat=43 V; we can get(10)Vo=Vbus2n=138.18V,R=Vo2ηPin=7.89Ω,D=1-VinVo=0.689.Since the inductance is small, the inductor DC resistance is also small, the conduction resistance of MOSFET is about several milliohms, and, in order to facilitate the calculation, these three small items can be ignored, the system’s transfer function is as follows:(11)Gs=1.384·106s+644s2+381.19s+2.146·106.


## 4. Simulation Analysis

### 4.1. Steady-State Simulation Model

This paper simulates the circuit analysis by PISM software; circuit simulation parameters are as follows: inductance value is 100μH, the transformer ratio and winding counterattack is 1.4, the low-voltage side of the input voltage is 48 V, output power is 6 kW, the output voltage control is 380 V. Here it has the results of the modeling circuit steady-state simulation analysis, simulation waveforms shown in Figure 5. According to Figure 5, we can see that increasing the equivalent on-resistance of the low-voltage side of the MOSFET transistor has no effect on the inductor current, changing the size of the value of the equivalent resistance of the inductor L1 or changing the high-pressure side of the two MOSFETs duty ratio will make two MOSFETs turn-on time show subtle differences that will make the current size of the two inductors show the deviation, and the duty ratio deviation will have greater effect on the inductor current deviation.Figure 5
Inductor current simulation waveforms.
(a)
The current waveform when the inductance equivalent resistances are not equal (b)
Unequal MOSFET on-resistance current waveform (c)
Current waveform when the duty cycles are unequal in size


### 4.2. PID Controller Design

The PID controller of the system is designed through the system transfer function of small signal [10–12]. The current in the system is realized by controlling the duty cycle, and the duty cycle control is the use of PID control. There are many methods for tuning the parameters of PID controller; we can according to the specific needs choose the suitable parameter tuning method. Here this paper uses a more efficient way, Matlab software provides the SISOTOOL tool, and it corrects the PID parameters of the transfer function of the system directly by the software. Through the Matlab software, we can get the PID parameters: the proportion of the parameterKp is infinitesimal; the integral parameter Ki is 0.336. The PID controller’s transfer function is as follows:(12)GsPID=0.3361s.Then, the step response of the system is compared with that of the system without PI. From Figure6, we can see that after the addition of PI the system overshoot is negligible, and the steady-state error of the system is significantly reduced a lot, while the steady-state error of the system without PI is larger.Figure 6
Step response simulation waveforms.


### 4.3. Soft Start Algorithm Design

When the circuit starts, initial duty ratio is too high which will lead to the start process being not smooth, and also large duty ratio will make the circuit voltage and current overshoot and oscillation. This will not only make the system instable and damage the whole circuit system, but also cause a huge impact to the power grid, affecting the quality of power supply; this is the so-called hard start [13]. Therefore, in order to reduce the impact of large current and high voltage, it needs to add soft start to the start process, so that the current can smoothly rise and reduce the shock of the current and voltage. The general soft starting circuit is realized by controlling the voltage of the error amplifier. Here we use a new type of soft start algorithm and control the duty cycle soft start by a program algorithm. At the start of the circuit, drive switch tube of duty ratio by 0 slowly increased, and, compared with the setting target current value, until the current in low-voltage side reached the setting current, then clear the soft start mark and closed soft start; the program jumps from the soft start mode to the normal PI control mode. Soft start algorithm flowchart is shown in Figure 7. Judging by the dead zone to limit the maximum and minimum output duty cycle, to ensure the two MOSFETs of the high-voltage side will not appear shoot-through.Figure 7
Soft start algorithm flowchart.The soft start algorithm has been simulated, and the simulation results are shown in Figure8. From the graph, can see that the MOSFET duty cycle is increased slowly at the start of the circuit, and the low-voltage side current is gentle from 0 to reach the target value of 125 A and the soft start process is finished. The simulation results shown in Figure 8 can be seen with the benefits of soft start; soft start process can make the MOSFET current and voltage gentle to reach the steady-state value and will not produce a larger current or voltage shock. This can effectively avoid the electric current and voltage transition instant damage MOSFET, so as to effectively protect the MOSFET stable and reliable operation of the circuit. So the role of soft start is very important in the process of starting.Figure 8
Low-voltage side current waveform and MOSFET current of soft start.


## 4.1. Steady-State Simulation Model

This paper simulates the circuit analysis by PISM software; circuit simulation parameters are as follows: inductance value is 100μH, the transformer ratio and winding counterattack is 1.4, the low-voltage side of the input voltage is 48 V, output power is 6 kW, the output voltage control is 380 V. Here it has the results of the modeling circuit steady-state simulation analysis, simulation waveforms shown in Figure 5. According to Figure 5, we can see that increasing the equivalent on-resistance of the low-voltage side of the MOSFET transistor has no effect on the inductor current, changing the size of the value of the equivalent resistance of the inductor L1 or changing the high-pressure side of the two MOSFETs duty ratio will make two MOSFETs turn-on time show subtle differences that will make the current size of the two inductors show the deviation, and the duty ratio deviation will have greater effect on the inductor current deviation.Figure 5
Inductor current simulation waveforms.
(a)
The current waveform when the inductance equivalent resistances are not equal (b)
Unequal MOSFET on-resistance current waveform (c)
Current waveform when the duty cycles are unequal in size


## 4.2. PID Controller Design

The PID controller of the system is designed through the system transfer function of small signal [10–12]. The current in the system is realized by controlling the duty cycle, and the duty cycle control is the use of PID control. There are many methods for tuning the parameters of PID controller; we can according to the specific needs choose the suitable parameter tuning method. Here this paper uses a more efficient way, Matlab software provides the SISOTOOL tool, and it corrects the PID parameters of the transfer function of the system directly by the software. Through the Matlab software, we can get the PID parameters: the proportion of the parameterKp is infinitesimal; the integral parameter Ki is 0.336. The PID controller’s transfer function is as follows:(12)GsPID=0.3361s.Then, the step response of the system is compared with that of the system without PI. From Figure6, we can see that after the addition of PI the system overshoot is negligible, and the steady-state error of the system is significantly reduced a lot, while the steady-state error of the system without PI is larger.Figure 6
Step response simulation waveforms.


## 4.3. Soft Start Algorithm Design

When the circuit starts, initial duty ratio is too high which will lead to the start process being not smooth, and also large duty ratio will make the circuit voltage and current overshoot and oscillation. This will not only make the system instable and damage the whole circuit system, but also cause a huge impact to the power grid, affecting the quality of power supply; this is the so-called hard start [13]. Therefore, in order to reduce the impact of large current and high voltage, it needs to add soft start to the start process, so that the current can smoothly rise and reduce the shock of the current and voltage. The general soft starting circuit is realized by controlling the voltage of the error amplifier. Here we use a new type of soft start algorithm and control the duty cycle soft start by a program algorithm. At the start of the circuit, drive switch tube of duty ratio by 0 slowly increased, and, compared with the setting target current value, until the current in low-voltage side reached the setting current, then clear the soft start mark and closed soft start; the program jumps from the soft start mode to the normal PI control mode. Soft start algorithm flowchart is shown in Figure 7. Judging by the dead zone to limit the maximum and minimum output duty cycle, to ensure the two MOSFETs of the high-voltage side will not appear shoot-through.Figure 7
Soft start algorithm flowchart.The soft start algorithm has been simulated, and the simulation results are shown in Figure8. From the graph, can see that the MOSFET duty cycle is increased slowly at the start of the circuit, and the low-voltage side current is gentle from 0 to reach the target value of 125 A and the soft start process is finished. The simulation results shown in Figure 8 can be seen with the benefits of soft start; soft start process can make the MOSFET current and voltage gentle to reach the steady-state value and will not produce a larger current or voltage shock. This can effectively avoid the electric current and voltage transition instant damage MOSFET, so as to effectively protect the MOSFET stable and reliable operation of the circuit. So the role of soft start is very important in the process of starting.Figure 8
Low-voltage side current waveform and MOSFET current of soft start.


## 5. Experiment Analysis

Laboratory system is built on the lithium battery charge and discharge test; the circuit parameters are as follows: the low-voltage side of the MOSFET model isIXTQ100N25P, and, using the two MOSFETs model parallel to ensure adequate safety margin, the high-voltage side of MOSFET model isIPP60R074C6. Flyback inductance value is 146 μH, with core MagneticsKool 77083 model core. Master controller usesTMS320F28335 chip. MOSFET drive voltage is 12 V, and the switching frequency is 40 kHz. Current test mode: the system input voltage of the battery is 48 V, input current is 120 A, and full load test waveforms are as shown in Figure 9. Figure 9(a) shows the soft start current waveform, the start time is 3.4 seconds, and a smooth current reaches a target current value; Figure 9(b) shows the inductor current waveform, the peak current is 8.4 A, and current ripple is 14%, to meet the design requirements.Figure 9
Experimental waveforms.
(a)
Output current soft start waveforms (b)
Inductor current waveform


## 6. Conclusion

The steady-state model is established and the simulation results show the influence of the parasitic parameters of the circuit on the circuit stability. By soft start algorithm and soft start circuitry we can effectively slow down the impact of high-current circuits, thereby improving the stability of the system and increasing the life of the device. The experimental results prove the feasibility and reliability of the soft start algorithm and verify the good stability and dynamic performance of the system.



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