# New Results of Global Exponential Stabilization for BLDCMs System

Authors: Fengxia Tian; Fangchao Zhen; Guopeng Zhou; Xiaoxin Liao
Journal: Mathematical Problems in Engineering
 (2015)

---

## Abstract

The global exponential stabilization for brushless direct current motor (BLDCM) system is studied. Four linear and simple feedback controllers are proposed to realize the global stabilization of BLDCM with exponential convergence rate; the control law used in each theorem is less conservative and more concise. Finally, an example is given to demonstrate the correctness of the proposed results.


---

## Body

## 1. Introduction

A brushless direct current motor (BLDCM) is a synchronous electric motor which is powered by direct current electricity [1]. With the development of electronic technology and control technology, the BLDCM is used widely in motion control applications. The major advantage of BLDCM is the elimination of the physical contact between the mechanical brushes and the commutators [2]. However, it is found that, with certain values of system parameters, the BLDCM exhibits chaotic behavior, such as aperiodic, random, sudden, or intermittent morbid oscillations of the motor angle speed, which can seriously destroy the stable operation of the motor and can even induce industrial drive system collapse [3–8]. Therefore, studying the stability of BLDCM is a significant job and has been receiving considerable attention.There has been a lot of work done in studying stability and designing controller of BLDCMs [1, 2, 9–13]. For instance, Dadras et al. studied the stability of chaotic uncertain BLDCMs by feedback linearization and sliding-mode control methods [1]. Ge and Chang studied the chaos synchronization and parameters identification of single time-scale BLDCMs by adaptive control and backstepping design method [2]. Ren and Chen proposed a piecewise quadratic state feedback method to control chaos in the BLDCM [9]. Meng et al. designed a fuzzy controller with time-delay feedback to control the chaos movement in the BLDCM [10]. Uyaroğlu and Cevher studied sliding-mode control for single time-scale BLDCM [13]. But the controllers proposed in these papers are nonlinear or multiple, and the stability is uniform or asymptotic, which is a weaker property than exponential stability. So, searching a lower-dimensional linear control for the global exponential stabilization of chaotic BLDCM is significant.Recently, Wei et al. studied the global exponential stabilization for chaotic BLDCMs based on Lyapunov-like theorem [14], although Wei et al. present the method to address the problem about global exponential stability of the BLDCM system firstly. It is innovative to generalize stability and asymptotic stability to global exponential stability and generalize nonlinear feedback control law to linear feedback control law which is easier to implement. There is only one theorem and the control law is not concise. In this paper, we further improved the results of Wei et al. and gave four theorems. The control law used in each theorem is less conservative and more concise, and the proofs are much more simple.The rest of this paper is organized as follows. In Section2, system model is presented. In Section 3, the main results of global exponential stabilization for BLDCM system are derived. In Section 4, one example is presented to demonstrate the effectivity of the proposed method. The final section is the conclusion.


## 2. Preliminaries

Consider the mathematical model of a BLDC motor as follows [3–7]:(1)
d
i
d
d
t
=
U
d
-
δ
i
d
+
i
q
ω
d
i
q
d
t
=
U
q
-
i
q
-
i
d
ω
+
γ
ω
d
ω
d
t
=
σ
i
q
-
σ
ω
-
T
L
,where i
d, i
q, and ω denote quadrature-axis current, direct-axis current, and angle speed, respectively. δ, γ, and σ are system parameters, which determine the type of the dynamical regime of the motor. Consider the case that the motor is running freely under no loading conditions; that is, U
d
=
U
q
=
T
L
=
0, so system (1) becomes(2)
d
i
d
d
t
=
-
δ
i
d
+
i
q
ω
d
i
q
d
t
=
-
i
q
-
i
d
ω
+
γ
ω
d
ω
d
t
=
σ
i
q
-
σ
ω
.System (2) has chaotic behaviors, with a chaotic attractor shown in Figure 1.Figure 1
The typical chaotic attractor of the BLDCM atσ
=
4, γ
=
55, and δ
=
0.875.From Figure1 one can see that the BLDCM is not stable and shows some chaos characteristics, which led to the unstable operation of the motor which is not acceptable in real applications. Therefore, studying stabilization for chaotic BLDCM is significant and this paper will work on it.Now, some necessary definitions [15–18] that will be used in this paper are introduced in the following. Consider a general nonautonomous system of differential equation:(3)
d
x
d
t
=
f
x
,
t
,where x
=
[
x
1
,
x
2
,
…
,
x
n
]
T is the state vector, f
=
[
f
1
,
f
2
,
…
,
f
n
]
T
∈
R
n
×
1 are continuous functions with respect to x, and f
(
0
)
=
0. Furthermore, V
(
x
) is a radially unbounded and positive definite Lyapunov function.Definition 1.
The trivial solution of system (3) is globally exponentially stable if, for any x
0
∈
R
n, there exist two constants M
(
x
0
)
>
0 and α
>
0, such that, for any solution of system (3), it holds (4)
x
t
≤
M
x
0
e
-
α
t
-
t
0
,where x
(
t
)
=
x
(
t
,
t
0
,
x
0
).Lemma 2.
If there exists a Lyapunov functionV
(
t
,
x
) satisfying (5)
x
t
≤
V
t
,
x
,
d
V
x
d
t
3
≤
-
c
V
x
,where c
>
c
o
n
s
t
a
n
t
>
0, then the trivial solution of system (3) is globally exponentially stable.Proof.
∵
V
(
x
(
t
)
)
≤
V
(
x
(
t
0
)
)
e
-
c
(
t
-
t
0
), then(6)
x
t
≤
V
x
t
≤
V
x
t
0
e
-
c
t
-
t
0
=
M
x
0
e
-
c
t
-
t
0
.So the trivial solution of system (3) is globally exponentially stable.


## 3. Main Results

Theorem 3.
Add a linear feedback controlleru
1
=
-
k
2
i
q to the second equation of system (2), and then the system can be described as(7)
d
i
d
d
t
=
-
δ
i
d
+
i
q
ω
d
i
q
d
t
=
-
1
+
k
2
i
q
-
i
d
ω
+
γ
ω
d
ω
d
t
=
σ
i
q
-
σ
ω
,or add a linear feedback controller u
2
=
-
k
3
ω to the third equation of system (2), and then the system can be described as(8)
d
i
d
d
t
=
-
δ
i
d
+
i
q
ω
d
i
q
d
t
=
-
i
q
-
i
d
ω
+
γ
ω
d
ω
d
t
=
σ
i
q
-
σ
+
k
3
ω
.
If-
1
-
k
2
γ
+
σ
/
2
γ
+
σ
/
2
-
σ is negative definite, which means(9)
k
2
>
γ
+
σ
2
4
σ
-
1
,then system (7) is globally exponentially stable at the equilibrium point (
i
d
,
i
q
,
ω
)
=
(
0,0
,
0
).
And if-
1
γ
+
σ
/
2
γ
+
σ
/
2
-
σ
-
k
3 is negative definite, which means(10)
k
3
>
γ
+
σ
2
2
-
σ
,then system (8) is globally exponentially stable at the equilibrium point (
i
d
,
i
q
,
ω
)
=
(
0,0
,
0
).Proof.
Construct a radially unbounded and positive definite Lyapunov function:(11)
V
1
=
1
2
i
d
2
+
i
q
2
+
ω
2
.
(
1
) Because k
2
>
(
γ
+
σ
)
2
/
4
σ
-
1, -
1
-
k
2
γ
+
σ
/
2
γ
+
σ
/
2
-
σ is negative definite. So(12)
ϕ
1
=
-
δ
0
0
0
-
1
-
k
2
γ
+
σ
2
0
γ
+
σ
2
-
σis negative definite.
Compute the derivative ofV
1 along system (7):(13)
d
V
1
d
t
7
=
i
d
i
˙
d
+
i
q
i
˙
q
+
ω
ω
˙
=
-
δ
i
d
2
+
i
d
i
q
ω
-
1
+
k
2
i
q
2
-
i
d
i
q
ω
+
γ
ω
i
q
+
σ
i
q
ω
-
σ
ω
2
=
-
δ
i
d
2
-
1
+
k
2
i
q
2
-
σ
ω
2
+
γ
+
σ
ω
i
q
=
i
d
i
q
ω
T
-
δ
0
0
0
-
1
-
k
2
γ
+
σ
2
0
γ
+
σ
2
-
σ
i
d
i
q
ω
=
i
d
i
q
ω
T
ϕ
1
i
d
i
q
ω
≤
λ
M
ϕ
1
i
d
i
q
ω
T
i
d
i
q
ω
≤
2
λ
M
ϕ
1
V
1
,where λ
M
(
ϕ
1
) is the largest eigenvalue of ϕ
1 and λ
M
(
ϕ
1
)
<
0. Consider(14)
V
1
t
≤
V
1
t
0
e
2
λ
M
ϕ
1
t
-
t
0
i
d
2
t
+
i
q
2
t
+
ω
2
t
≤
2
V
1
t
0
e
2
λ
M
ϕ
1
t
-
t
0
.
So the zero solution of system (7) is globally exponentially stable.
(
2
) Because k
3
>
(
γ
+
σ
/
2
)
2
-
σ, -
1
γ
+
σ
/
2
γ
+
σ
/
2
-
σ
-
k
3 is negative definite. So (15)
ϕ
2
=
-
δ
0
0
0
-
1
γ
+
σ
2
0
γ
+
σ
2
-
σ
-
k
3is negative definite.
Similarly, compute the derivative ofV
1 along system (8): (16)
d
V
1
d
t
8
=
i
d
i
˙
d
+
i
q
i
˙
q
+
ω
ω
˙
=
-
δ
i
d
2
+
i
d
i
q
ω
-
i
q
2
-
i
d
i
q
ω
+
γ
ω
i
q
+
σ
i
q
ω
-
σ
+
k
3
ω
2
=
-
δ
i
d
2
-
i
q
2
-
σ
+
k
3
ω
2
+
γ
+
σ
ω
i
q
=
i
d
i
q
ω
T
-
δ
0
0
0
-
1
γ
+
σ
2
0
γ
+
σ
2
-
σ
-
k
3
i
d
i
q
ω
=
i
d
i
q
ω
T
ϕ
2
i
d
i
q
ω
≤
λ
M
ϕ
2
i
d
i
q
ω
T
i
d
i
q
ω
≤
2
λ
M
ϕ
2
V
1
,where λ
M
(
ϕ
2
) is the largest eigenvector of ϕ
2 and λ
M
(
ϕ
2
)
<
0. Consider(17)
V
1
t
≤
V
1
t
0
e
2
λ
M
ϕ
2
t
-
t
0
i
d
2
t
+
i
q
2
t
+
ω
2
t
≤
2
V
1
t
0
e
2
λ
M
ϕ
2
t
-
t
0
.
So the zero solution of system (8) is globally exponentially stable.
Therefore, systems (7) and (8) are globally exponentially stable at the equilibrium point s
0
=
(
0,0
,
0
).Theorem 4.
Add a linear negative feedback controlleru
3
=
-
γ
~
ω to the second equation of system (2), and then the system can be described as(18)
d
i
d
d
t
=
-
δ
i
d
+
i
q
ω
d
i
q
d
t
=
-
i
q
-
i
d
ω
+
γ
-
γ
~
ω
d
ω
d
t
=
σ
i
q
-
σ
ω
;if γ
~
≥
γ, system (18) is globally exponentially stable at the equilibrium point (
i
d
,
i
q
,
ω
)
=
(
0,0
,
0
).Proof.
(
1
) If γ
~
>
γ, construct a radially unbounded and positive definite Lyapunov function: (19)
V
2
=
1
2
i
d
2
+
i
q
2
+
γ
~
-
γ
σ
ω
2
,
min
⁡
1
,
γ
~
-
γ
σ
i
d
2
+
i
q
2
+
ω
2
≤
2
V
2
≤
max
⁡
1
,
γ
~
-
γ
σ
i
d
2
+
i
q
2
+
ω
2
.
Compute the derivative ofV
2 along system (18): (20)
d
V
2
d
t
18
=
i
d
i
˙
d
+
i
q
i
˙
q
+
γ
~
-
γ
σ
ω
ω
˙
=
-
δ
i
d
2
+
i
d
i
q
ω
-
i
q
2
-
i
d
i
q
ω
+
γ
-
γ
~
ω
i
q
+
γ
~
-
γ
σ
σ
i
q
ω
-
γ
~
-
γ
σ
σ
ω
2
=
-
δ
i
d
2
-
i
q
2
-
γ
~
-
γ
ω
2
=
i
d
i
q
ω
T
·
-
δ
0
0
0
-
1
0
0
0
γ
~
-
γ
i
d
i
q
ω
≤
-
min
⁡
σ
,
1
,
γ
~
-
γ
i
d
2
+
i
q
2
+
ω
2
≤
-
min
⁡
σ
,
1
,
γ
~
-
γ
max
⁡
1
,
γ
~
-
γ
/
σ
2
V
2
V
2
≤
V
2
t
0
e
-
2
min
⁡
σ
,
1
,
γ
~
-
γ
/
max
⁡
1
,
γ
~
-
γ
/
σ
t
-
t
0
i
d
2
t
+
i
q
2
t
+
ω
2
t
≤
2
V
2
t
0
min
⁡
1
,
γ
~
-
γ
/
σ
·
e
-
2
min
⁡
σ
,
1
,
γ
~
-
γ
/
max
⁡
1
,
γ
~
-
γ
/
σ
t
-
t
0
.
So the zero solution of system (18) is globally exponentially stable.
(
2
) If γ
~
=
γ, system (18) changes as(21)
d
i
d
d
t
=
-
δ
i
d
+
i
q
ω
d
i
q
d
t
=
-
i
q
-
i
d
ω
d
ω
d
t
=
σ
i
q
-
σ
ω
.
For the first two equations, construct a radially unbounded and positive definite Lyapunov function:(22)
V
3
=
1
2
i
d
2
+
i
q
2
.
Compute the derivative ofV
3 along system (21): (23)
d
V
3
d
t
21
=
i
d
i
˙
d
+
i
q
i
˙
q
=
-
δ
i
d
2
+
i
d
i
q
ω
-
i
q
2
-
i
d
i
q
ω
=
-
δ
i
d
2
-
i
q
2
≤
-
min
⁡
δ
,
1
i
d
2
+
i
q
2
=
-
min
⁡
δ
,
1
2
V
3
V
3
≤
V
3
t
0
e
-
min
⁡
δ
,
1
t
-
t
0
i
d
2
t
+
i
q
2
t
≤
2
V
3
t
0
e
-
min
⁡
δ
,
1
t
-
t
0
.
So the zero solution of system (21) is globally exponentially stable on partial variables i
q, i
d.
For the third equation of system (21) (24)
ω
t
=
ω
t
0
e
-
σ
t
-
t
0
+
∫
t
0
t
e
-
σ
t
-
τ
σ
i
q
τ
d
τ
≤
ω
t
0
e
-
σ
t
-
t
0
+
∫
t
0
t
e
-
σ
t
-
τ
σ
i
q
τ
d
τ
≤
ω
t
0
e
-
σ
t
-
t
0
+
σ
e
-
σ
t
∫
t
0
t
e
σ
τ
i
q
τ
2
+
i
d
τ
2
d
τ
≤
ω
t
0
e
-
σ
t
-
t
0
+
σ
e
-
σ
t
∫
t
0
t
e
σ
τ
i
q
t
0
2
+
i
d
t
0
2
e
-
min
⁡
δ
,
1
τ
-
t
0
d
τ
≤
ω
t
0
e
-
σ
t
-
t
0
+
σ
e
-
σ
t
∫
t
0
t
e
σ
τ
H
e
-
α
τ
-
t
0
d
τ
≤
ω
t
0
e
-
σ
t
-
t
0
+
σ
H
e
-
σ
t
e
α
t
0
∫
t
0
t
e
σ
-
α
τ
d
τ
≤
ω
t
0
e
-
σ
t
-
t
0
+
σ
H
e
-
σ
t
e
α
t
0
e
σ
-
α
t
-
e
σ
-
α
t
0
σ
-
α
≤
ω
t
0
e
-
σ
t
-
t
0
+
σ
H
σ
-
α
e
-
α
t
-
t
0
-
e
-
σ
t
-
t
0
≤
ω
t
0
-
σ
H
σ
-
α
e
-
σ
t
-
t
0
+
σ
H
σ
-
α
e
-
α
t
-
t
0
,where we can suppose that H
=
(
i
q
(
t
0
)
)
2
+
(
i
d
(
t
0
)
)
2, α
=
m
i
n
(
δ
,
1
).
So the zero solution of system (21) is globally exponentially stable on partial variables ω.
Therefore system (18) is globally exponentially stable on all variables (
i
d
,
i
q
,
ω
) at the equilibrium point (
i
d
,
i
q
,
ω
)
=
(
0,0
,
0
).Theorem 5.
Add a linear negative feedback controlleru
4
=
-
σ
~
i
q to the third equation of system (2), and then the system can be described as(25)
d
i
d
d
t
=
-
δ
i
d
+
i
q
ω
d
i
q
d
t
=
-
i
q
-
i
d
ω
+
γ
ω
d
ω
d
t
=
σ
-
σ
~
i
q
-
σ
ω
;if σ
~
≥
σ, system (25) is globally exponentially stable at the equilibrium point (
i
d
,
i
q
,
ω
)
=
(
0,0
,
0
).Proof.
(
1
) If σ
~
>
σ, construct a radially unbounded and positive definite Lyapunov function: (26)
V
4
=
1
2
i
d
2
+
i
q
2
+
γ
σ
~
-
σ
ω
2
,
min
⁡
1
,
γ
σ
~
-
σ
i
d
2
+
i
q
2
+
ω
2
≤
2
V
4
≤
max
⁡
1
,
γ
σ
~
-
σ
i
d
2
+
i
q
2
+
ω
2
.
Compute the derivative ofV
4 along system (25):(27)
d
V
4
d
t
25
=
i
d
i
˙
d
+
i
q
i
˙
q
+
γ
σ
~
-
σ
ω
ω
˙
=
-
δ
i
d
2
+
i
d
i
q
ω
-
i
q
2
-
i
d
i
q
ω
+
γ
ω
i
q
+
γ
σ
~
-
σ
σ
-
σ
~
i
q
ω
-
γ
σ
~
-
σ
σ
ω
2
=
-
δ
i
d
2
-
i
q
2
-
γ
σ
σ
~
-
σ
ω
2
≤
-
min
⁡
δ
,
1
,
γ
σ
/
σ
~
-
σ
i
d
2
+
i
q
2
+
ω
2
≤
-
min
⁡
σ
,
1
,
γ
σ
/
σ
~
-
σ
max
⁡
1
,
γ
/
σ
~
-
σ
2
V
4
V
4
t
≤
V
4
t
0
e
-
2
min
⁡
σ
,
γ
σ
/
σ
~
-
σ
/
max
⁡
1
,
γ
/
σ
~
-
σ
t
-
t
0
i
d
2
t
+
i
q
2
t
+
ω
2
t
≤
2
V
4
t
0
min
⁡
1
,
γ
/
σ
~
-
σ
·
e
-
2
min
⁡
σ
,
γ
σ
/
σ
~
-
σ
/
max
⁡
1
,
γ
/
σ
~
-
σ
t
-
t
0
.
Whenσ
~
>
σ, the zero solution of system (25) is globally exponentially stable.
(
2
) If σ
~
=
σ, the system is(28)
d
i
d
d
t
=
-
δ
i
d
+
i
q
ω
d
i
q
d
t
=
-
i
q
-
i
d
ω
+
γ
ω
d
ω
d
t
=
-
σ
ω
.
Because-
1
γ
/
2
γ
/
2
0 is negative definite, (29)
-
δ
0
0
0
-
1
γ
2
0
γ
2
0is negative definite.
For the first two equations, compute the derivative ofV
3 along system (28): (30)
d
V
3
d
t
28
=
i
d
i
˙
d
+
i
q
i
˙
q
=
-
δ
i
d
2
+
i
d
i
q
ω
-
i
q
2
-
i
d
i
q
ω
+
γ
ω
i
q
=
-
δ
i
d
2
-
i
q
2
+
γ
ω
i
q
=
i
d
i
q
ω
T
-
δ
0
0
0
-
1
γ
2
0
γ
2
0
i
d
i
q
ω
=
i
d
i
q
ω
T
ϕ
3
i
d
i
q
ω
≤
λ
M
ϕ
3
i
d
i
q
ω
T
i
d
i
q
ω
≤
2
λ
M
ϕ
3
V
3
,where λ
M
(
ϕ
3
) is the largest eigenvector of ϕ
3 and λ
M
(
ϕ
3
)
<
0. Consider (31)
V
3
≤
V
3
t
0
e
λ
M
ϕ
3
t
-
t
0
i
d
2
t
+
i
q
2
t
≤
2
V
3
t
0
e
λ
M
ϕ
3
t
-
t
0
.
Whenσ
~
=
σ, the zero solution of system (25) is globally exponentially stable on partial variables i
d, i
q.
For the third equation of system (28)(32)
ω
t
=
ω
t
0
e
-
σ
t
-
t
0
.
So the zero solution of system (28) is globally exponentially stable on partial variable ω.
Therefore, system (25) is globally exponentially stable on all variables i
d, i
q, and ω at the equilibrium point (
i
d
,
i
q
,
ω
)
=
(
0,0
,
0
).Theorem 6.
Add linear negative feedback controllersu
3
=
-
γ
~
ω, u
4
=
-
σ
~
i
q to the second and third equations of system (2) simultaneously; then the system can be described as(33)
d
i
d
d
t
=
-
δ
i
d
+
i
q
ω
d
i
q
d
t
=
-
i
q
-
i
d
ω
+
γ
-
γ
~
ω
d
ω
d
t
=
σ
-
σ
~
i
q
-
σ
ω
.
Ifγ
~
≤
γ, σ
~
≤
σ and 0
<
(
γ
-
γ
~
)
≪
1, 0
<
(
σ
-
σ
~
)
≪
1, such that following matrix -
1
γ
-
γ
~
+
σ
-
σ
~
/
2
γ
-
γ
~
+
σ
-
σ
~
/
2
-
σ is negative definite. Then system (33) is globally exponentially stable at the equilibrium point (
i
d
,
i
q
,
ω
)
=
(
0,0
,
0
).Proof.
Since-
1
γ
-
γ
~
+
σ
-
σ
~
/
2
γ
-
γ
~
+
σ
-
σ
~
/
2
-
σ is negative definite, -
σ
0
0
0
-
1
γ
-
γ
~
+
σ
-
σ
~
/
2
0
γ
-
γ
~
+
σ
-
σ
~
/
2
-
σ is negative definite.
Compute the derivative ofV
1 along system (33): (34)
d
V
1
d
t
33
=
i
d
i
˙
d
+
i
q
i
˙
q
+
ω
ω
˙
=
-
δ
i
d
2
+
i
d
i
q
ω
-
i
q
2
-
i
d
i
q
ω
+
γ
-
γ
~
ω
i
q
+
σ
-
σ
~
i
q
ω
-
σ
ω
2
=
-
δ
i
d
2
-
i
q
2
-
σ
ω
2
+
γ
-
γ
~
+
σ
-
σ
~
ω
=
i
d
i
q
ω
T
·
-
δ
0
0
0
-
1
γ
-
γ
~
+
σ
-
σ
~
2
0
γ
-
γ
~
+
σ
-
σ
~
2
-
σ
i
d
i
q
ω
=
i
d
i
q
ω
T
ϕ
4
i
d
i
q
ω
≤
λ
M
ϕ
4
i
d
i
q
ω
T
i
d
i
q
ω
≤
2
λ
M
ϕ
4
V
,where λ
M
(
ϕ
4
) is the largest eigenvalue of ϕ
4 and λ
M
(
ϕ
4
)
<
0. Consider(35)
V
1
t
≤
V
1
t
0
e
2
λ
M
ϕ
4
t
-
t
0
i
d
2
t
+
i
q
2
t
+
ω
2
t
≤
2
V
1
t
0
e
2
λ
M
ϕ
1
t
-
t
0
.
So whenγ
~
≥
γ, σ
~
≥
σ and 0
<
(
γ
-
γ
~
)
≪
1, 0
<
(
γ
-
γ
~
)
≪
1 system (33) is globally exponentially stable at the equilibrium point (
i
d
,
i
q
,
ω
)
=
(
0,0
,
0
).


## 4. Illustrative Example

The parameters of the motor are selected asσ
=
4, γ
=
55, and δ
=
0.875 and the initial values of the system are chosen as (
ω
(
0
)
,
i
q
(
0
)
,
i
d
(
0
)
)
=
(
0.1,0.1,0.1
).According to Theorem3, we may choose k
2
=
216.6
>
(
γ
+
σ
)
2
/
4
σ
-
1
=
216.5625, k
3
=
867
>
(
γ
+
σ
/
4
σ
)
2
-
σ
=
866.25. Then, we can see that it takes short time for the system to be stabilized at origin point and the state trajectories are illustrated in Figures 2 and 3.Figure 2
The state trajectory ofi
d, i
q, and ω with the controller u
1.Figure 3
The state trajectory ofi
d, i
q, and ω with the controller u
2.According to Theorem4, we may choose γ
~
=
100
>
γ
=
55. Then, we can see that it takes short time for the system to be stabilized at origin point and the state trajectories are illustrated in Figure 4.Figure 4
The state trajectory ofi
d, i
q, and ω with the controller u
3.According to Theorem5, we may choose σ
~
=
7
>
σ
=
4. Then, we can see that it takes short time for the system to be stabilized at origin point and the state trajectories are illustrated in Figure 5.Figure 5
The state trajectory ofi
d, i
q, and ω with the controller u
4.According to Theorem6, we may choose γ
~
=
54.6
<
γ
=
55, σ
~
=
3.2
<
σ
=
4, so 0
<
γ
-
γ
~
=
0.4
<
1, 0
<
σ
-
σ
~
=
0.8
<
1. Then, we can see that it takes short time for the system to be stabilized at origin point and the state trajectories are illustrated in Figure 6.Figure 6
The state trajectory ofi
d, i
q, and ω with the controllers u
3 and u
4.


## 5. Conclusion

In this paper, we investigated the global exponential stabilization for BLDCM system and designed four linear and simple feedback controllers. These controllers realized the global stabilization of BLDCM with exponential convergence rate, and the control law used in each theorem is less conservative and more concise. Finally an example is given to demonstrate the correctness of the proposed results.



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*Source: 436159-2015-10-25.xml*