# Determining the REV for Fracture Rock Mass Based on Seepage Theory

Authors: Lili Zhang; Lu Xia; Qingchun Yu
Journal: Geofluids
 (2017)

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## Abstract

Seepage problems of the fractured rock mass have always been a heated topic within hydrogeology and engineering geology. The equivalent porous medium model method is the main method in the study of the seepage of the fractured rock mass and its engineering application. The key to the method is to determine a representative elementary volume (REV). The FractureToKarst software, that is, discrete element software, is a main analysis tool in this paper and developed by a number of authors. According to the standard of rock classification established by ISRM, this paper aims to discuss the existence and the size of REV of fractured rock masses with medium tractility and provide a general method to determine the existence of REV. It can be gleaned from the study that the existence condition of fractured rock mass with medium tractility features average fracture spacing smaller than 0.6 m. If average fracture spacing is larger than 0.6 m, there is no existence of REV. The rationality of the model is verified by a case study. The present research provides a method for the simulation of seepage field in fissured rocks.


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## Body

## 1. Introduction

Seepage problems of the fractured rock mass have always been a heated topic within hydrogeology and engineering geology. Many problems that are closely related to the research of fracture seepages, including the stability of dam foundation and seepage, the stability of bedrock side slopes under the influence of groundwater, fissure deposit, the prevention of mine water inrush, and the leakage and diffusion of nuclear waste. However, the study of the seepage problems of the fractured rock mass is still in its preliminary stage at present. The general method regards fractured media as porous media and uses the permeability tensor of porous media to describe the seepage characteristics of the fractured media. There are different types of structural plane in fractured rock mass, which lead to the complexity of rock mass characteristics. Therefore, the study on rock mass model is always one of the important problems in rock mechanics. The representative elementary volume (REV) is the basis to determine a rock mass mechanics model, and it is necessary to research the REV of fractured rock mass effectively, so that the REV size of the fractured rock mass can be determined.The concept of the REV was the first introduced in continuum mechanics by Bear [1], and it is to be used to describe the flow in the porous media. The parameter of interest is both homogeneous and statistically stationary, which will ensure consistency in flow simulation studies. The REV is defined in two situations on (1) unit cell in a periodic microstructure and (2) volume containing a very large set of microscale elements, possessing statistically homogeneous properties. The REV has been discussed by many authors [2–17]. The REV of a fractured rock mass is the smallest volume in during the study of parameter when the hydraulic conductivity is a constant value. One special concern is the evaluation of the REV of the fractured rock masses, due to the fact that fluid flow in fractured rock masses is of high scale effect [2, 18–23]. Previous studies assumed that the anisotropy was achieved by making use of different correlation lengths in the horizontal and vertical directions, and flow barriers were modeled stochastically [24–36].Snow [37] concluded the math expressions of single and infinite fracture permeability tensors, assuming that the fracture seepages did not interfere with each other, while the overall permeability tensor of fracture network was the linear superposition of all fractures. As the fracture network was the same as the porous media, the permeability can be expressed by a permeability tensor. A fractured network can be approximately viewed as a porous medium, which was if the equivalent porous media of fractures are existent, then the permeability coefficients can be expressed by a symmetric second-order tensor. Li and Zhang [38] also conducted research on the REV of fractures. Bear [1] proved that if r=Kq1/2 or r=Kj-1/2 in the polar coordinate system, mapping can form an ellipse (under the condition of three-dimensional ellipsoid), where r represents radius vector, Kq represents permeability coefficient in the direction of the flow line, and Kj represents permeability coefficient in the direction of the hydraulic gradient. Long and Witherspoon [39] proposed that if the representative elementary volume of the fractured rock mass (REV) existed, the following two conditions must be met:(1)
The media must be uniform in the area of study; that is, the average permeability coefficient of the area of study changes along with the scope of the study with big change; then it can be determined that this area of study is uniform.(2)
In the polar coordinate system, the equivalent permeability coefficientk in each direction within the area of study can be described using an ellipse approximately at this time r=K.


## 2. Introduction to FractureToKarst Software

This paper uses discrete fracture network (DFN) software, according to the standard of rock classification established by ISRM, and discusses the existence of REV of fractured rock masses with medium tractility. The discrete fracture network (DFN) software FractureToKarst for seepage in fracture rock mass is a kind of software using the Monte Carlo method. It can generate a two-dimensional fracture network of arbitrary shapes, set the common statistical parameters of fracture, filter the fractures within the area of study, and proceed with automatic discrete can be set. The head value and equivalent permeability coefficient of each node can be calculated by using the water balance principle. In the study, set an aspect ratio for the area of study 2 : 1 [40], calculate an equivalent permeability coefficient every 10° rotation of the area of study, every area of study can get 36 equivalent permeability coefficients, and discuss whether the direction of the equivalent permeability coefficient in polar coordinates can be described as a permeability coefficient ellipse or not, thus determining the existence of REV.


### 2.1. Mathematical Model

Mathematical model is the water dynamic model of the system. Fracture network is composed of a single, flat, smooth fracture, in a state of the laminar flow in a single fracture and can be described by the cubic law:(1)Q=ρg12μB3ΔHL.Type. Q is the boundary flux; ρ is the density of water; g is the gravitational acceleration; μ is flow dynamic viscosity coefficient; B is fracture width; ΔH is two-head difference of the fracture; L is the length of the fracture section.In the fracture network, each node can establish a hydraulic link equation by the water balance principle:(2)∑j=1nQij+Qb=0n=1,2,3,….Type. Qij is the node flux; Qb is the boundary flux. The hydrodynamic equations can be constructed by combining formula (1) and formula (2), and the head distribution of the fracture node within the system can be derived by the equations.


### 2.2. Model Algorithm

Model algorithm is a numerical method. The detailed steps are as follows.(1) Grid discretization: all the fractures can be divided into the smallest fracture section by the nodes. Each node and connected fractures make a unit balance zone, as shown in Figure1.Figure 1
A unit in discrete fracture networks.(2) For the hydraulic head, assign an initial value and boundary treatment: the node head is constant in the boundary of fixed water level. The initial water head of the rest of the nodes is 0.99 times the maximum elevation value. The node head of the impermeable boundary is equal to the adjacent nodes water head.(3) For the hydraulic head, do iteration calculation: calculate the hydraulic head values of all nodes using the iterative methods based on formulas (1) and (2).(4) Calculate the permeability coefficient: completing the hydraulic head calculation follows evaluating the equivalent permeability coefficientK in the flow direction using Darcy’s law.(5) Calculate the permeability coefficient in any direction: keep the shape of the area of study unchanged, make it rotate around its center, and calculate an equivalent permeability coefficient every10°~rotation; then we can get 36 equivalent permeability coefficients K.(6) Draw: in the polar coordinate system, it is appropriate to use the equivalent permeability coefficients of 36 directions in Step(5) to draw the diagram, to see whether it can form an ellipse, so we know whether the REV is existent or not.


## 2.1. Mathematical Model

Mathematical model is the water dynamic model of the system. Fracture network is composed of a single, flat, smooth fracture, in a state of the laminar flow in a single fracture and can be described by the cubic law:(1)Q=ρg12μB3ΔHL.Type. Q is the boundary flux; ρ is the density of water; g is the gravitational acceleration; μ is flow dynamic viscosity coefficient; B is fracture width; ΔH is two-head difference of the fracture; L is the length of the fracture section.In the fracture network, each node can establish a hydraulic link equation by the water balance principle:(2)∑j=1nQij+Qb=0n=1,2,3,….Type. Qij is the node flux; Qb is the boundary flux. The hydrodynamic equations can be constructed by combining formula (1) and formula (2), and the head distribution of the fracture node within the system can be derived by the equations.


## 2.2. Model Algorithm

Model algorithm is a numerical method. The detailed steps are as follows.(1) Grid discretization: all the fractures can be divided into the smallest fracture section by the nodes. Each node and connected fractures make a unit balance zone, as shown in Figure1.Figure 1
A unit in discrete fracture networks.(2) For the hydraulic head, assign an initial value and boundary treatment: the node head is constant in the boundary of fixed water level. The initial water head of the rest of the nodes is 0.99 times the maximum elevation value. The node head of the impermeable boundary is equal to the adjacent nodes water head.(3) For the hydraulic head, do iteration calculation: calculate the hydraulic head values of all nodes using the iterative methods based on formulas (1) and (2).(4) Calculate the permeability coefficient: completing the hydraulic head calculation follows evaluating the equivalent permeability coefficientK in the flow direction using Darcy’s law.(5) Calculate the permeability coefficient in any direction: keep the shape of the area of study unchanged, make it rotate around its center, and calculate an equivalent permeability coefficient every10°~rotation; then we can get 36 equivalent permeability coefficients K.(6) Draw: in the polar coordinate system, it is appropriate to use the equivalent permeability coefficients of 36 directions in Step(5) to draw the diagram, to see whether it can form an ellipse, so we know whether the REV is existent or not.


## 3. Analytical Solution for Validation of the Software FractureToKarst

Assume that there is a fracture network as shown in Figure2, the right and left boundaries being the given head border and the upper and lower two boundaries being the impermeable boundary; the start-point and end-point coordinates of the fractures are [(1,0),(1,2)],[(0.5,1.5),(3,0)],[(0,0.8),(4,0.8)].Figure 2
Sketch of fracture network.Assume the hydraulic head of two kinds of in and out of boundary valuesH1=20.5, H2=0.5, respectively. Using the principle of water balance and the cubic flow law, there is(3)ρgB312μ∑j=1nHi-HjLij=0n=1,2,3,….IfA=ρgB3/12μ, there are(4)H1=20.5H2=0.5AH6-H3L6,3=0AH8-H4L8,4=0AH7-H5L7,5=0AH1-H6L1,6+H3-H6L3,6+H8-H6L8,6+H7-H6L7,6=0AH6-H7L6,7+H8-H7L8,7+H5-H7L5,7=0AH6-H8L6,8+H4-H8L4,8+H2-H8L2,8+H7-H8L7,8=0.Type. H1~H8 is the water head; Li,j is the length of fracture section between the two nodes; ρ is the density of water; g is the gravitational acceleration; μ is flow dynamic viscosity coefficient.Through (4), we can obtain that the values of Li,j and the hydraulic head values for each node are(5)L1,6=L6,1=1.0000H1=20.5000L2,8=L8,2=2.3333H2=0.5000L3,6=L6,3=0.8000H3=15.1794L4,8=L8,4=1.5549H4=12.9146L5,7=L7,5=0.8000H5=14.4100L6,7=L7,6=0.4000H6=15.1794L6,8=L8,6=0.6667H7=14.4100L7,8=L8,7=0.7775H8=12.9146.The equivalent permeability coefficient of the flow directionk is obtained through Darcy’s law: (6)k=0.1173m/s.Use FractureToKarst to build fracture network, and input parameters, the value of the water head, and the equivalent permeability coefficient are shown in Figure3.Figure 3
Calculation results of the FractureToKarst.The calculation result in that the program equals the manual computation result, proving that the program is correct.


## 4. Simulation of the Fracture Network

According to the standard of rock classification established by ISRM, fractured rock mass with medium tractility refers to rock mass whose trace length is more than 3 m and less than 10 m. Because the permeability of two sets of orthogonal fracture rock masses is closest to being isotropic, the described ellipse is closest to being a circle.According to the fracture spacing classification of ISRM, the spacing within 20~60 mm is very dense spacing. Within 10 m × 10 m, two sets of orthogonal fractures were generated, the average spacing is 0.06 m, and the aperture is 0.0001 m. The two sets of fracture parameters are shown in Table1 (two sets of fracture identification for I and II in Table 1). Here, put some fractures in the same direction as a set of fractures. The distribution types of the trace length and the direction are the normal distribution, and the gap width is the logarithmic normal distribution. The right and left boundaries are the given head border and the upper and lower two boundaries are the impermeable boundary.Table 1
Input data of the simulation fractures.
Geometric parameters
Average
Standard deviation
Minimum
Maximum
I
Trace length (m)
6
0.1
3
10
Gap width (m)
0.01
0.0002
0.0099999
0.01
Direction (°)
90
0.0002
89.99999
90.1
II
Trace length (m)
8
0.1
3
10
Gap width (m)
0.01
0.0002
0.0099999
0.01
Direction (°)
1
0.0002
0.00009
0.11From Table1, two sets of orthogonal fractures can be built. The first set has 276 fractures, and the second set has 208 fractures, with a total of 484 generating fractures. The diagram of generated fractures is shown in Figure 4(a). The equivalent permeability coefficient of the study area changes with the scope of the study without changes, so the study area is uniform. Within 10 m × 10 m, select five study areas of 1.0 m × 0.5 m, 2.0 m × 1.0 m, 3.0 m × 1.5 m, 4.0 m × 2.0 m, and 6.0 m × 3.0 m, and the diagram of generated fractures of FractureToKarst is shown in Figures 4(b)–4(f).Figure 4
Sketch of fracture of research area.
(a)
All the fractures
(b)
1.0 m × 0.5 m
(c)
2.0 m × 1.0 m
(d)
3.0 m × 1.5 m
(e)
6.0 m × 3.0 m
(f)
7.0 m × 3.5 mAcquire the permeability coefficients of all the directions in the five regions and make a comprehensive comparison chart of permeability coefficients (shown in Figure5). Analyzing Figure 5, it can be concluded that every equivalent permeability coefficient is basically stable when the area of study is larger than 1.0 m × 0.5 m. There is no dramatical change for the permeability coefficients in the four regions 2.0 m × 1.0 m, 3.0 m × 1.5 m, 4.0 m × 2.0 m, and 6.0 m × 3.0 m, so more than 1.0 m × 0.5 m in the area of study can be approximately viewed as a homogeneous medium region.Figure 5
Comprehensive comparison chart of permeability coefficients of the five research areas.In Figure5, the meaning of all the symbols as follows.“△” is the area of study of 1.0 m × 0.5 m; “●” is the area of study of 2.0 m × 1.0 m; “▽” is the area of study of 3.0 m × 1.5 m; “○” is the area of study of 6.0 m × 3.0 m; “⋄” is the area of study of 7.0 m × 3.5 m.


## 5. The Fitting Calculation of the Uniform Basin

### 5.1. Calculation of Regional Rotation

As the uniform basin 1.0 m × 0.5 m was determined above, taking the initial angle as the angle between the horizontal direction and the flow direction, rotate the whole area of study clockwise to calculate an equivalent permeability coefficient every 10°; then each area of study has 36 equivalent permeability coefficients, as shown in Table2.Table 2
Geometry parameters of the simulation fractures.
Angle (°)
Permeability coefficientK (m/s)
K
Angle (°)
Permeability coefficientK (m/s)
K
0
0.126663410
0.355898033
180
0.126663410
0.355898033
10
0.114747073
0.338743374
190
0.114747073
0.338743374
20
0.106263067
0.325980163
200
0.106263067
0.325980163
30
0.080940329
0.284500139
210
0.080940339
0.284500156
40
0.076023022
0.275722728
220
0.076023022
0.275722728
50
0.078325363
0.279866689
230
0.078325363
0.279866689
60
0.079387274
0.281757474
240
0.079387279
0.281757483
70
0.089760691
0.299600886
250
0.089760691
0.299600886
80
0.096157073
0.310092040
260
0.096157068
0.310092031
90
0.085050877
0.291634835
270
0.085050877
0.291634835
100
0.095708250
0.309367501
280
0.095708256
0.309367510
110
0.087766937
0.296254851
290
0.087766937
0.296254851
120
0.082587428
0.287380285
300
0.082587424
0.287380277
130
0.088829021
0.298041978
310
0.088829026
0.298041987
140
0.084262835
0.290280615
320
0.084262835
0.290280615
150
0.101059987
0.317899334
330
0.101059987
0.317899334
160
0.107171601
0.327370739
340
0.107171601
0.327370739
170
0.108014187
0.328655118
350
0.108014187
0.328655118Table2 shows that the maximum value of the permeability coefficient is 0.127 m/s when the angle is 0° and 180° between the flow direction and the horizontal orientation (because the angle between the two direction is 180°, so they are the same one flow field); the minimum value of the permeability coefficient is 0.076 m/s when the angle is 40° and 220° between the flow direction and the horizontal orientation. The reason for this phenomenon is that the calculation in Table 2 is derived from the data of the fracture network in Table 1, where 0° (180°) and 90° (270°) are two groups of orthogonal fractures. In Table 1, at four points at angles 0° (180°) and 90° (270°), there will be a local maximum value. The permeability coefficient at 0° (180°) is the local maximum value of fractures in the 0° (180°) direction, and the permeability coefficient at 40° (220°) is the minimum value between the two local maximum values.


### 5.2. The Polar Coordinate Fitting of the Permeability Coefficient

Assuming that point P is any one point on the ellipse in the polar coordinate system, A, B are, respectively, the two endpoints, and C is the focus of the ellipse. The semi~major axis and the semi~minor axis of the ellipse are assumed asa and b, respectively. This results in(7)x2a2+y2b2=1x=ρcos⁡θy=ρsin⁡θ.Assuming that=T+θ, T is a parameter, that is, the angle between the principal axis of the ellipse and the polar coordinate 0° axis.Solve (7), where the ellipse equation of the permeability coefficient in the polar coordinate system is(8)ρ=aba2-a2-b2cos2θ+T.Draw the ellipse according to Table2 and (8) in the polar coordinate system and fit it, as shown in Figure 6. Fitting parameters and fitting values are shown in Table 3.Table 3
Geometry parameters of the simulation fractures.
Angle (°)
K fitted values
Angle (°)
K fitted values
Angle (°)
K fitted values
0
0.305109085
120
0.299326230
240
0.311116251
10
0.307460936
130
0.298577917
250
0.309507266
20
0.309569772
140
0.298590634
260
0.298487333
30
0.311157685
150
0.299363128
270
0.305030972
40
0.312004897
160
0.300818305
280
0.302734029
50
0.311990387
170
0.302805783
290
0.300760951
60
0.311116251
180
0.305109085
300
0.299326230
70
0.309507266
190
0.307460936
310
0.298577917
80
0.298487333
200
0.309569772
320
0.298590634
90
0.305030972
210
0.311157685
330
0.299363128
100
0.302734029
220
0.312004897
340
0.300818305
110
0.300760951
230
0.311990387
350
0.302805783Figure 6
Curve fitting.The semi~major axis and the semi~minor axis of the fitting ellipse area=0.3121083582, b=0.298487332, respectively, where T=2.359065441 radians, and the fitting equation is(9)ρ=0.0931603910.097411627-0.00831694cos2⁡θ+2.359065441.


## 5.1. Calculation of Regional Rotation

As the uniform basin 1.0 m × 0.5 m was determined above, taking the initial angle as the angle between the horizontal direction and the flow direction, rotate the whole area of study clockwise to calculate an equivalent permeability coefficient every 10°; then each area of study has 36 equivalent permeability coefficients, as shown in Table2.Table 2
Geometry parameters of the simulation fractures.
Angle (°)
Permeability coefficientK (m/s)
K
Angle (°)
Permeability coefficientK (m/s)
K
0
0.126663410
0.355898033
180
0.126663410
0.355898033
10
0.114747073
0.338743374
190
0.114747073
0.338743374
20
0.106263067
0.325980163
200
0.106263067
0.325980163
30
0.080940329
0.284500139
210
0.080940339
0.284500156
40
0.076023022
0.275722728
220
0.076023022
0.275722728
50
0.078325363
0.279866689
230
0.078325363
0.279866689
60
0.079387274
0.281757474
240
0.079387279
0.281757483
70
0.089760691
0.299600886
250
0.089760691
0.299600886
80
0.096157073
0.310092040
260
0.096157068
0.310092031
90
0.085050877
0.291634835
270
0.085050877
0.291634835
100
0.095708250
0.309367501
280
0.095708256
0.309367510
110
0.087766937
0.296254851
290
0.087766937
0.296254851
120
0.082587428
0.287380285
300
0.082587424
0.287380277
130
0.088829021
0.298041978
310
0.088829026
0.298041987
140
0.084262835
0.290280615
320
0.084262835
0.290280615
150
0.101059987
0.317899334
330
0.101059987
0.317899334
160
0.107171601
0.327370739
340
0.107171601
0.327370739
170
0.108014187
0.328655118
350
0.108014187
0.328655118Table2 shows that the maximum value of the permeability coefficient is 0.127 m/s when the angle is 0° and 180° between the flow direction and the horizontal orientation (because the angle between the two direction is 180°, so they are the same one flow field); the minimum value of the permeability coefficient is 0.076 m/s when the angle is 40° and 220° between the flow direction and the horizontal orientation. The reason for this phenomenon is that the calculation in Table 2 is derived from the data of the fracture network in Table 1, where 0° (180°) and 90° (270°) are two groups of orthogonal fractures. In Table 1, at four points at angles 0° (180°) and 90° (270°), there will be a local maximum value. The permeability coefficient at 0° (180°) is the local maximum value of fractures in the 0° (180°) direction, and the permeability coefficient at 40° (220°) is the minimum value between the two local maximum values.


## 5.2. The Polar Coordinate Fitting of the Permeability Coefficient

Assuming that point P is any one point on the ellipse in the polar coordinate system, A, B are, respectively, the two endpoints, and C is the focus of the ellipse. The semi~major axis and the semi~minor axis of the ellipse are assumed asa and b, respectively. This results in(7)x2a2+y2b2=1x=ρcos⁡θy=ρsin⁡θ.Assuming that=T+θ, T is a parameter, that is, the angle between the principal axis of the ellipse and the polar coordinate 0° axis.Solve (7), where the ellipse equation of the permeability coefficient in the polar coordinate system is(8)ρ=aba2-a2-b2cos2θ+T.Draw the ellipse according to Table2 and (8) in the polar coordinate system and fit it, as shown in Figure 6. Fitting parameters and fitting values are shown in Table 3.Table 3
Geometry parameters of the simulation fractures.
Angle (°)
K fitted values
Angle (°)
K fitted values
Angle (°)
K fitted values
0
0.305109085
120
0.299326230
240
0.311116251
10
0.307460936
130
0.298577917
250
0.309507266
20
0.309569772
140
0.298590634
260
0.298487333
30
0.311157685
150
0.299363128
270
0.305030972
40
0.312004897
160
0.300818305
280
0.302734029
50
0.311990387
170
0.302805783
290
0.300760951
60
0.311116251
180
0.305109085
300
0.299326230
70
0.309507266
190
0.307460936
310
0.298577917
80
0.298487333
200
0.309569772
320
0.298590634
90
0.305030972
210
0.311157685
330
0.299363128
100
0.302734029
220
0.312004897
340
0.300818305
110
0.300760951
230
0.311990387
350
0.302805783Figure 6
Curve fitting.The semi~major axis and the semi~minor axis of the fitting ellipse area=0.3121083582, b=0.298487332, respectively, where T=2.359065441 radians, and the fitting equation is(9)ρ=0.0931603910.097411627-0.00831694cos2⁡θ+2.359065441.


## 6. Determination of the REV

Öhman et al. have conducted a considerable amount of useful research [41–43] on the equivalent medium in the fractured rocks to compare the similarity between the equivalent permeability coefficient of numerical simulation and the ellipse in different area of studies. These two scholars have obtained the minimum values of the square of the simulation value and fitting value, with the following formula:(10)RMS=2Kmajor+Kminor×∑1nKSθ-Kfθ2n.RMS is the fitting correlation coefficient of the ellipse,KS(θ) is the simulation value, and Kf(θ) is the fitting value.Depending on its similarity to the elliptic curve, RMS can be divided into three categories:(1)
When RMS≤ 0.2, the size of the area of study can be used as the REV of the fractured rock mass.(2)
When 0.4 > RMS > 0.2, the size of the area of study can be used as the REV of the fractured rock mass under certain conditions.(3)
When RMS≥ 0.4,  the size of the area of study cannot be used as the REV of the fractured rock mass.Therefore, after comparing Tables2 and 3, it can be gleaned that the fitting result is quite ideal, with the correlation coefficient RMS = 0.132064722. The REV of the fractured rock mass of this kind exists, whose size is 1.0 m × 0.5 m.Further research shows that the REV of very dense spacing (<0.02 m) of the fractured rock mass exists, and it is less than 1.0 m × 0.5 m. The REV of the dense spacing (0.06~0.2 m) of the fractured rock mass is 2.0 m × 1.0 m. The REV of medium spacing (0.2~0.6 m) of the fractured rock mass is 10.0 m × 5.0 m. The REV is not the existence of the fractured rock mass of wide spacing (0.6~2.0 m), with very wide spacing (2.0~6.0 m) and utmost spacing (>0.6 m) because their fractures have no connection and have no hydraulic conductivity, and thus the REV does not exist.


## 7. Conclusions and Suggestions

In conclusion, the existence of REV is closely related to the fracture conditions. Not all types of fractured rock mass have REV. The more intensive the fractures are, the better the penetration is, the better the permeability of the rocks is, which means the easier it is to become equivalent to porous media. Thus, the following conclusions can be made:(1)
The existence condition of the REV for fractured rock mass with medium tractility is that the average spacing of the fractures should be less than or equal to 0.6 m; that is to say, the size of the REV of extremely dense spacing of the fractured rock mass is less than 1.0 m × 0.5 m; the size of the REV of very dense spacing of the fractured rock mass is 1.0 m × 0.5 m; the size of the REV of dense spacing of the fractured rock mass is 2.0 m × 1.0 m; the size of the REV of medium spacing of the fractured rock mass is 10.0 m × 5.0 m.(2)
When the average spacing of the fractures is more than 0.6 m, the REV of wide spacing and very wide spacing and extremely wide spacing of the fractured rock mass does not exist.(3)
Although this study has obtained certain achievement in the scale effects of the REV of the discrete fracture medium, there are still some shortcomings, including the influence of the different distribution of the geometric elements and the influence of the distribution of the different gap lengths, which all require further discussion.



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*Source: 4129240-2017-05-14.xml*