# Electric and Magnetic Fields Generated by a Charged Bunch between Parallel Conducting Plates

Authors: B. Levchenko
Journal: Physics Research International
 (2010)

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## Abstract

Image fields generated by a bunch of charged particles between two parallel perfectly conducting plates are studied in detail. We derive exact analytical expressions for external fields of a charged relativistic bunch with a circular cross-section. Summation of image fields by the direct method invented by Laslett allows the infinite series to be represented in terms of elementary trigonometric functions.


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## Body

## 1. Introduction

In an accelerator, the charged beam is influenced by an environment (a beam pipe, accelerator gaps, magnets, collimators, etc.), and a high-intensity bunch induces surface charges or currents into this environment. This modifies the electric and magnetic fields around the bunch. There is a relatively simple method to account for the effect of the environment by introducing image charges and currents.Methods of image fields summation are described in the paper [1], which presents some field coefficients calculated for infinite parallel-plate vacuum chambers, magnetic poles, and vacuum chambers with elliptical cross-sections and variable aspect rations. The resulting image field was calculated only in the linear approximation and depends linearly on the deviations x¯ and x of the bunch center and the position of a test particle, respectively, from the axis. The approximation used is incorrect if the field observation point x is located far from the bunch or if the bunch center is close to a conducting wall.In the present paper we consider the classical problem of the image field summation once again for a very simple geometry, namely, a relativistic bunch moving between infinitely wide parallel perfectly conducting planes. The problem is far from being a pure academic one [2, 3]. In applications, in particular by study of the electron cloud effect [4] and the dynamics of photoelectrons in the beam transport system, it is important to know the distribution of electromagnetic fields not only in vicinity of the bunch but also in the whole collimator gap.In free space, the external radial electricE⃗⊥ and azimuthal magnetic B⃗ϕ self-fields of a cylindrical bunch with a uniform charge density are described by [5–7] (1)E⊥(r)=κ2λr,(2)Bϕ=-βcE⊥(r),
where κ=1/4πϵ0, λ is the linear charge density, β=v/c the normalized velocity of the beam constituents, and c the velocity of light.We did not find publications with attempts to sum up the series (3) in an approximation beyond the linear one. In the following sections we present the exact solutions of the problem.


## 2. Electric Field from Image Charges

Following Laslett [1] (see also [5]), we consider a relativistic bunch of the length L between infinitely wide conducting plates at x=±h. Suppose that constituents of the bunch are positively charged. For full generality, let the circular particle bunch be displaced in the horizontal plane by x¯ from the midplane (0,y,z), and the observation point of the field be at (x,0,0) between the conducting parallel plates. The end points of the bunch are at z=±L/2. The boundary condition for electric fields is Ez(±h)=0 on the conducting plane and is satisfied if the image charges change sign from image to image. Suppose that the distance between plates is of the order L. Thus, the electric field of each image is described by (1). To calculate the image electric field E⊥,image(x) in front of the plate, we add the contributions from all image fields in the infinite series [1] (see also [5, 8]) (3)E⊥,image(x,x¯)=2κλ⋅{(2h-x1)-1-(2h+x1)-1-(4h-x2)-1+(4h+x2)-1+(6h-x1)-1-(6h+x1)-1-(8h-x2)-1+(8h+x2)-1+(10h-x1)-1-(10h+x1)-1-(12h-x2)-1+(12h+x2)-1+⋯},
where x1=x+x¯ and x2=x-x¯, λ=qN/L and N is the number of particles of charge q per bunch. These image fields must be added to the direct field of the bunch (1) to meet the boundary condition that the electric field enters conducting surfaces perpendicularly.In the original paper [1], the series (3) was summed up only in the linear approximation in x and x¯,(4)E⊥,image(x,x¯)=4κλϵ1h2(2x¯+x).
The coefficient ϵ1=π2/48 is known as the Laslett coefficient (or form factor) for infinite parallel-plate vacuum chambers and magnetic poles. The approximation (4) widespread in textbooks and lectures is however incorrect if the deviation of the bunch center from the axis is large (x¯~h) or if the field observation point x is located far off the bunch. Therefore, below we present the exact solution of the problem.In the appendix we prove that the exact summation of the series (3) gives(5)E⊥,image(x,x¯)=4κλhΛ(δ,δ¯),
where the image field structure function Λ depends only on normalized variables δ=x/h, δ¯=x¯/h in the form(6)Λ(δ,δ¯)=12[π2⋅cos⁡((π/2)δ¯)sin⁡((π/2)δ)-sin⁡((π/2)δ¯)-1δ-δ¯].
In the appendix it is also shown that in the linear approximation equation (5) recovers the part (4) derived by Laslett.We will now estimate values of the functionΛ in several particular field points. If the observation point of the field is located at the plate, x=h, then δ=1 and the structure function depends only on the bunch center position between plates, δ¯. Thus, from (6) one gets (7)Λ(1,δ¯)=12{π21+sin⁡((π/2)δ¯)cos⁡((π/2)δ¯)-11-δ¯}.
Equation (7) is singular at δ¯→1 and shows that the conducting plate attracts the bunch with increasing force with the bunch displacement from the midplane. This phenomenon, involving the transverse movement of the bunch as a whole, arises from image forces and could lead to a transverse instability of the bunch.For the bunch in the midplane,δ¯=0, the summed image field at the surface equals (8)E⊥,image(h,0)=4κλhΛ(1,0)=2κλh(π2-1).The image field (5) must be added to the direct field of the bunch (1) to meet the boundary condition. Thus(9)E⊥,tot(x,x¯)=E⊥,dir+E⊥,image=πκλh⋅cos⁡((π/2)δ¯)sin⁡((π/2)δ)-sin⁡((π/2)δ¯).
For a bunch in the midplane, δ¯=0, we find from (9) the expression of the transverse component of electric field generated by a relativistic bunch moving between wide conducting parallel plates (10)E⊥,tot(x,0)=2κλx⋅(π/2)δsin⁡((π/2)δ).
That is, at the surface, δ=1, the field is enhanced by a factor π/2 due to the presence of the conducting plates.Notice that in the linear approximation (4) the field gradient, ∂E⊥,im/∂x, is independent of position x. Thus the tune shift experienced by each particle in the bunch is the same (a coherent tune shift). However, the exact result (5) demonstrates that the coherence is violated and (5) allows to estimate the accuracy of the linear approximation.


## 3. Magnetic Images

In the above, we have used electrostatic images. Magnetic images can be treated in much the same way. Let the ferromagnetic boundaries be represented by a pair of infinitely wide parallel surfaces atx=±g. The magnetic field lines must enter the magnetic pole faces perpendicularly. For magnetic image fields we distinguish between DC and AC image fields. The DC field penetrates the metallic vacuum chamber and reaches the ferromagnetic poles. In case of bunched beams the AC fields are of rather high frequency and we assume that they do not penetrate the thick metallic vacuum chamber.A magnetic field seen by a particle at locationx on the x-axis is generated by the successive image currents with the same sign as the beam itself [7, 8]. Therefore, instead of the series (A.1) we get(11)(2g-x1)-1-(2g+x1)-1+(4g-x2)-1-(4g+x2)-1+(6g-x1)-1-(6g+x1)-1+(8g-x2)-1-(8g+x2)-1+(10g-x1)-1-(10g+x1)-1+(12g-x2)-1-(12g+x2)-1+⋯(12)=∑k∞Πk(x1,g)+∑m∞Πm(x2,g)=2gH(η1,η2),
where Πk and Πm are of the same functional form as (A.3) with an interchange of variables h→g, δ1→η1=x1/g, and δ2→η2=x2/g. Now, if to proceed in the same manner as in the appendix, we obtain from (11) an expression for the structure function of the image magnetic field (13)H(η,η¯)=12[1η-η¯-π2⋅cos⁡((π/2)η)sin⁡((π/2)η)-sin⁡((π/2)η¯)].
Thus, the resulting DC field is described by(14)By,image,DC(x,x¯)=4κλβcg⋅B⋅H(η,η¯),
where η=x/g and η¯=x¯/g, ℬ=nbL/2πR is the bunching factor, nb the number of bunches, and R the average accelerator radius.The contribution of magnetic AC image field due to eddy currents in vacuum chamber walls is similar to electric image fields(15)By,image,AC(x,x¯)=-4κλβch⋅(1-B)⋅Λ(δ,δ¯),
where the factor (1-ℬ) accounts for the subtraction of the DC component.The magnetic image fields must be added to the direct magnetic field (2) from the bunch to meet the boundary condition of normal components at ferromagnetic surfaces. That is, the total magnetic field between the conducting plates is (16)By,tot(x,x¯)=By+By,image,DC+By,image,AC=-πκλβch{(1-B)cos⁡((π/2)δ¯)sin⁡((π/2)δ)-sin⁡((π/2)δ¯)+hg⋅Bcos⁡((π/2)η)sin⁡((π/2)η)-sin⁡((π/2)η¯)}.


## 4. Summary

We reanalyzed the classical problem of summing image fields generated by a bunch of charged particles moving with a relativistic velocity between infinitely wide parallel perfectly conducting plates. The exact solutions of the problems are represented by (6) and (13) for the structure function Λ(δ,δ¯) of electric images and the structure function H(η,η¯) of magnetic images, depending only on the normalized variables.



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*Source: 201730-2010-12-12.xml*