# The Evaluation of Solar Contribution in Solar Aided Coal-Fired Power Plant

Authors: Rongrong Zhai; Yongping Yang; Yong Zhu; Denggao Chen
Journal: International Journal of Photoenergy
 (2013)

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## Abstract

Solar aided coal-fired power plants utilize various types of solar thermal energy for coupling coal-fired power plants by using the characteristics of various thermal needs of the plants. In this way, the costly thermal storage system and power generating system will be unnecessary while the intermittent and unsteady way of power generation will be avoided. Moreover, the large-scale utilization of solar thermal power and the energy-saving aim of power plants will be realized. The contribution evaluating system of solar thermal power needs to be explored. This paper deals with the evaluation method of solar contribution based on the second law of thermodynamics and the principle of thermoeconomics with a case of 600 MW solar aided coal-fired power plant. In this study, the feasibility of the method has been carried out. The contribution of this paper is not only to determine the proportion of solar energy in overall electric power, but also to assign the individual cost components involving solar energy. Therefore, this study will supply the theoretical reference for the future research of evaluation methods and new energy resource subsidy.


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## Body

## 1. Introduction

Since the energy crisis in the 1970s, the major developed countries of the world started a series of projects involving solar thermal power generation for energy substitution. Among the developments in this field, the research of America, Israel, Spain, Germany, and Italy began first and are consequently the most mature [1]. Solar energy as a form of clean energy has broad application prospects. Moreover, coupling with coal-fired power plants as a type of solar power utilization has been presented and investigated by many researchers.Pai proposed the integration of a solar concentrator field to a 210 MWe coal-fired power plant [2]. Gupta and Kaushik found that using solar energy as a substitute for feed water heaters is more advantageous than using solar energy alone for power generation [3]. From a theoretical perspective, the solar aided coal-fired power generation system has many advantages when compared with a photovoltaic power generation system. However, the popular utilization of this technology has been relatively slow. The reasons for this apathetic uptake have been concluded as follows: (a) variations of solar radiation can cause operation difficulties  and (b) no reasonable evaluating systems have been built for the contribution of solar energy in the integrated system. The study about solar aided coal-fired power generation system mostly concentrates on performance analyses, integration modes, operations optimization, and so on. Since Gaggioli and El-Sayed comprehensively concluded the history of second law costing method, thermoeconomic analysis has become a powerful scheme applied extensively in design, operation, and reform of energy systems [4, 5]. Though thermoeconomic methods are multitudinous, the objectives of most existing analysis techniques still can be included in the determination of (a) the appropriate allocation of economic resources to optimize the design and operation of a system and (b) the economic feasibility and profitability of a system [6]. The methods can be roughly divided into two classes: algebraic methods and calculus methods [4, 5]. The thermoeconomic analysis of solar aided coal-fired power generation system has already begun. Suresh and Reddy dealt with the 4-E (namely, energy, exergy, environment, and economic) analysis of solar aided coal-fired power plants with a subcritical and a supercritical power plant as references [7]; Baghernejad and Yaghoubi presented a new thermoeconomic method applying a genetic algorithm for optimization of an integrated solar combined cycle system [8].The previous research as mentioned above has investigated the integration of a solar concentrator field with a power plant. However the integrated system introduces solar energy into the individual components in the traditional power plants, the researches about how to evaluate the contribution of solar energy in the system are hardly found.A thermoeconomic method of evaluating solar contribution in the integrated system is firstly proposed in this paper. A new built 600 MW solar aided coal-fired power generation unit is considered as a reference power plant. According to the design parameters, the contribution proportion has been achieved, and the generation cost has also been explored by using sensitivity analysis method.


## 2. System Descriptions and the Proposed Problem

Figure1 shows the diagram of the solar aided coal-fired power plant. In the solar field, several parabolic trough collectors are connected and the heating material is heat transfer oil. The oil-heat exchanger is a tube-shell heat exchanger. The parabolic trough collectors and the oil-heat exchanger together are called solar driven oil-water heat exchanger in this paper.Figure 1
Layout of the solar aided coal-fired power plant.In a typical reheated steam coal-fired power plant, the combustion of coal takes place in the boiler. The unsaturated boiler feedwater from the condenser enters the boiler after going through four low-pressure reheaters (HTR1, HTR2, HTR3, and HTR4), three high-pressure reheaters (HTR5, HTR6, and HTR7), and a deaerator (Deaerator). The outlet superheated steam from the boiler is transported to the high-pressure cylinder to produce power, then, after being reheated in the boiler, drives the intermediate and lower pressure cylinders. Finally, the exhaust is condensed in the condenser. It can be seen from Figure1 that the extractions from different positions of the cylinders ((1)–(8)) are used to heat the feedwater via feedwater reheaters. The 600 MW solar aided coal-fired power plant is similar to the reheated steam cycle system. The difference lies in that a solar aided oil-water heat exchanger has been added. When the solar radiation is strong (e.g., in the day), the steam extraction (1) is cut off and HTR7 will not be in operation; the feedwater will be heated in the oil-heat exchanger. Conversely, when the solar radiation is week (e.g., in the night), the oil-heat exchanger will not be in operation and the plant will operate in the same manner as the base plant. In the solar field (as shown in the dash block in Figure 1), several parabolic collectors are connected using heat transfer oil as the heating medium in a tube-shell heat exchanger. The parabolic collectors and the oil-heat exchanger together are called solar driven oil-water heat exchanger (SDOHE) in this paper.It can be seen from Figure1 that the solar contribution concentrates on providing heat to the feedwater. After heating, the feedwater flows into the boiler, then, after a series of processes, the thermal energy is finally translated into electrical power.The principle behind the solar aided coal-fired power generation system is to supply thermal energy by substituting high pressure feedwater heaters with oil-water heat exchangers. During a series of circulation, the energy contributes to the system power output indirectly. Therefore, it is meaningful to discuss how to evaluate the solar energy contribution in the solar aided coal-fired power plant.


## 3. Evaluation Model of Solar Energy Contribution

According to the first and second laws of thermodynamics, evaluation models based on energy balance and exergy balance are the possible methods for evaluating energy contribution such as solar energy and fuel. The method based on energy balance just considers the magnitude of energy without taking energy grade into account. The evaluation based on exergy balance has added energy grade to the system, while the nonequivalence of the same value of exergy at different points in the system has never been considered. Therefore, the evaluation based on the index of technical economics and energy equivalence has been explored in this study. The approach proposed in this paper is called the thermoeconomic cost method, considering both the energy grade and the nonequivalence.The thermoeconomic cost method includes three steps as shown in Figure2. Firstly, the contribution proportions of solar energy  and coal in every exergy flow needs to be confirmed. Secondly, according to the thermoeconomic concept, the values of each cost flow can be achieved. Thirdly, the contribution of solar economic cost will be calculated with the above data.Figure 2
Schematic representation of the calculating process of the thermoeconomic cost evaluation.


### 3.1. Confirming the Ratio of Solar Energy  against Coal according to Each Exergy Flow

This part is shown in Figure2, Box 1. For the convenience of the analysis, Figure 1 has been simplified as shown in Figure 3. The system includes six subsystems: (1) oil-water heat exchanging driven by solar energy; (2) boiler preheating, steam generating, and superheating; (3) high-pressure cylinder of turbine; (4) boiler reheating; (5) intermediate- and low-pressure cylinder of turbine; and (6) heat exchanging. The main parameters of the system such as the temperature, enthalpy, and flow rate are listed in Figure 3.Figure 3
Schematic representation of solar aided coal-fired power generation system.The exergy balance equation of each subsystem is as follows.(1) The exergy loss of oil-water heat exchanging is given byE9+E6-E1.The proportion of solar exergy loss assumed to beδ1. Then the loss will be, δ1(E9+E6-E1), and the exergy loss of feedwater will be, (1-δ1)(E9+E6-E1).The exergy achieved by water will be written as follows:E1-E6+(1-δ1)(E9+E6-E1).It equals the exergy released by solar energy, which may be written as follows:E9-δ1(E9+E6-E1).The proportion of solar energy at point 1 may become as follows:(1)α1=(α6[-(1-δ1)E9+δ1E6+(1-δ1)E1]+(1-δ1)E9-δ1E6+δ1E1)(E1)-1.(2) The total exergy loss of preheater, steam generator and superheater is given byE10+E1-E2.The proportion of coal exergy loss assumed to beδ2.Then the exergy loss of water will be,(1-δ2)(E10+E1-E2), and the exergy achieved by water will be written as follows: E2-E1+(1-δ2)(E10+E1-E2).It equals the exergy released by coal, which may be written as follows:E10-δ2(E10+E1-E2).The proportion of solar energy at point 2 may become as follows:(2)α2=α1[-(1-δ2)E10+δ2E1+(1-δ2)E2]E2.(3) The proportions of solar energy at the import and export of turbine are equal.For the third subsystem, the equation will be given by(3)α3=α2=α7.For the fifth subsystem, the equation will be given by(4)α5=α4=α8.(4) The total exergy loss of reheater is given byE11+E3-E4.The proportion of coal exergy loss assumd to beδ3.Then the exergy loss of coal will beδ3(E11+E3-E4), and the exergy loss of water will be  (1-δ3)(E11+E3-E4).The exergy achieved by water will be written as follows:E4-E8+(1-δ3)(E11+E3-E4).It equals the exergy released by coal, which may be written as follows:E11-δ3(E11+E3-E4).The proportion of solar energy may become as follows:(5)α4=α3[-(1-δ3)E11+δ3E3+(1-δ3)E4]E4.(5) The total exergy loss is given byE5+E7+E8-E6.The proportions of exergy loss at point 7 and 8 are assumed to beδ4 and  δ5.Then, the exergy loss at point 7 will beδ4(E5+E7+E8-E6).The exergy loss at point 8 will beδ5(E5+E7+E8-E6), and the exergy loss at point 5 will be  (1-δ4-δ5)(E5+E7+E8-E6).The equation will be written as follows:(6)α6=(α7[E7-δ4(E5+E7+E8-E6)]+α8[E8-δ5(E5+E7+E8-E6)]+α5[E5-(1-δ4-δ5)×(E5+E7+E8-E6)])(E6)-1.
The proportion of solar energy will be ensured by using (1)–(6).


### 3.2. The Exergy Follow Cost C Will Be Ensured by Thermoeconomic Analysis

This part is shown in Figure2, Box 2. According to Figure 3, the system includes 6 subsystems and 13 exergy flows. The equation satisfied by each subsystem is given by:
(7)Cin+Cn=Cout,
where Cin and Cn are, respectively, the energy cost of import and the cost of others, and Cout is the energy cost of export.Then, for the first subsystem, the equation is given by the following:(8)C6+C9+Cn1=C1.For the second subsystem, the equation is given by the following:(9)C1+C10+Cn2=C2.For the third subsystem, the equation is given by the following:(10)C2+Cn3=C3+C7+C12.For the fourth subsystem, the equation is given by the following:(11)C3+C11+Cn4=C4.For the fifth subsystem, the equation is given by the following:(12)C4+Cn5=C5+C8+C13.For the fifth subsystem, the equation is given by the following:(13)C5+C7+C8+Cn6=C6.The cost of solar exergy flowE9 is given data, and then we will get the equation as follows:
(14)C9E9=c9.The costs of coal exergy flowsE10 and E11 are given data, and then the equation will be as follows:
(15)C10E10=C11E11=c10=c11.The costs ofE2,E3, and E7 have been given, and then the equation may be as follows:
(16)C2E2=C3E3=C7E7.The costs ofE4,E5, and E8 have been given, and then the equation will be as follows:
(17)C4E4=C5E5=C8E8.According to (8)–(17), the cost of each exergy flow will be ensured.


### 3.3. According to the Thermoeconomic Analysis of the Solar Part, the Cost Proportions of Solar Energy in Each Exergy Flow Will Be Ensured

This part is shown in Figure2, Box 3. For the convenience of analysis, Figure 3 has been simplified as shown in Figure 4. The system still includes six subsystems.Figure 4
The schematic of cost flows.According to the data above, the solar energy parts in each exergy flow have just been considered alone, and the cost proportions of solar energy will be explored.Equations of each subsystem have been given as follows.(1) The cost equation of oil-water heat exchanging is given by the following:(18)C6β6+C9β9+Cn1βn1=C1β1.(2) The cost equation of preheating, steam generating, and superheating is given by the following:(19)C1β1+C10β10+Cn2βn2=C2β2.(3) The cost equation of turbine is given by the following:(20)C2β2+Cn3βn3=C3β3+C7β7+C12β12.(4) The cost equation of reheating is given by the following:(21)C3β3+C11β11+Cn4βn4=C4β4.(5) The cost equation of turbine is given by the following:(22)C4β4+Cn5βn5=C5β5+C8β8+C13β13.(6) The cost equation of heat exchanging is given by the following:(23)C5β5+C7β7+C8β8+Cn6βn6=C6β6.Since the cost of solar energy achieving is free, we assumeC9=0 and β9=0.For the second and third subsystems, the import exergy flows of 10 and 11 will be 0, which means the solar parts in 10 and 11 will be 0:(24)β10=β11=0.Since the costs ofE2,E3, and E7 are equal, (25) can be obtained as follows:
(25)β2=β3=β7.Since the flow rates ofE4,E5, and E8 are equal, (26) can be obtained as follows:
(26)β4=β5=β8.The cost proportions of solar energyβ will be ensured by using (18)–(26).


## 3.1. Confirming the Ratio of Solar Energy  against Coal according to Each Exergy Flow

This part is shown in Figure2, Box 1. For the convenience of the analysis, Figure 1 has been simplified as shown in Figure 3. The system includes six subsystems: (1) oil-water heat exchanging driven by solar energy; (2) boiler preheating, steam generating, and superheating; (3) high-pressure cylinder of turbine; (4) boiler reheating; (5) intermediate- and low-pressure cylinder of turbine; and (6) heat exchanging. The main parameters of the system such as the temperature, enthalpy, and flow rate are listed in Figure 3.Figure 3
Schematic representation of solar aided coal-fired power generation system.The exergy balance equation of each subsystem is as follows.(1) The exergy loss of oil-water heat exchanging is given byE9+E6-E1.The proportion of solar exergy loss assumed to beδ1. Then the loss will be, δ1(E9+E6-E1), and the exergy loss of feedwater will be, (1-δ1)(E9+E6-E1).The exergy achieved by water will be written as follows:E1-E6+(1-δ1)(E9+E6-E1).It equals the exergy released by solar energy, which may be written as follows:E9-δ1(E9+E6-E1).The proportion of solar energy at point 1 may become as follows:(1)α1=(α6[-(1-δ1)E9+δ1E6+(1-δ1)E1]+(1-δ1)E9-δ1E6+δ1E1)(E1)-1.(2) The total exergy loss of preheater, steam generator and superheater is given byE10+E1-E2.The proportion of coal exergy loss assumed to beδ2.Then the exergy loss of water will be,(1-δ2)(E10+E1-E2), and the exergy achieved by water will be written as follows: E2-E1+(1-δ2)(E10+E1-E2).It equals the exergy released by coal, which may be written as follows:E10-δ2(E10+E1-E2).The proportion of solar energy at point 2 may become as follows:(2)α2=α1[-(1-δ2)E10+δ2E1+(1-δ2)E2]E2.(3) The proportions of solar energy at the import and export of turbine are equal.For the third subsystem, the equation will be given by(3)α3=α2=α7.For the fifth subsystem, the equation will be given by(4)α5=α4=α8.(4) The total exergy loss of reheater is given byE11+E3-E4.The proportion of coal exergy loss assumd to beδ3.Then the exergy loss of coal will beδ3(E11+E3-E4), and the exergy loss of water will be  (1-δ3)(E11+E3-E4).The exergy achieved by water will be written as follows:E4-E8+(1-δ3)(E11+E3-E4).It equals the exergy released by coal, which may be written as follows:E11-δ3(E11+E3-E4).The proportion of solar energy may become as follows:(5)α4=α3[-(1-δ3)E11+δ3E3+(1-δ3)E4]E4.(5) The total exergy loss is given byE5+E7+E8-E6.The proportions of exergy loss at point 7 and 8 are assumed to beδ4 and  δ5.Then, the exergy loss at point 7 will beδ4(E5+E7+E8-E6).The exergy loss at point 8 will beδ5(E5+E7+E8-E6), and the exergy loss at point 5 will be  (1-δ4-δ5)(E5+E7+E8-E6).The equation will be written as follows:(6)α6=(α7[E7-δ4(E5+E7+E8-E6)]+α8[E8-δ5(E5+E7+E8-E6)]+α5[E5-(1-δ4-δ5)×(E5+E7+E8-E6)])(E6)-1.
The proportion of solar energy will be ensured by using (1)–(6).


## 3.2. The Exergy Follow Cost C Will Be Ensured by Thermoeconomic Analysis

This part is shown in Figure2, Box 2. According to Figure 3, the system includes 6 subsystems and 13 exergy flows. The equation satisfied by each subsystem is given by:
(7)Cin+Cn=Cout,
where Cin and Cn are, respectively, the energy cost of import and the cost of others, and Cout is the energy cost of export.Then, for the first subsystem, the equation is given by the following:(8)C6+C9+Cn1=C1.For the second subsystem, the equation is given by the following:(9)C1+C10+Cn2=C2.For the third subsystem, the equation is given by the following:(10)C2+Cn3=C3+C7+C12.For the fourth subsystem, the equation is given by the following:(11)C3+C11+Cn4=C4.For the fifth subsystem, the equation is given by the following:(12)C4+Cn5=C5+C8+C13.For the fifth subsystem, the equation is given by the following:(13)C5+C7+C8+Cn6=C6.The cost of solar exergy flowE9 is given data, and then we will get the equation as follows:
(14)C9E9=c9.The costs of coal exergy flowsE10 and E11 are given data, and then the equation will be as follows:
(15)C10E10=C11E11=c10=c11.The costs ofE2,E3, and E7 have been given, and then the equation may be as follows:
(16)C2E2=C3E3=C7E7.The costs ofE4,E5, and E8 have been given, and then the equation will be as follows:
(17)C4E4=C5E5=C8E8.According to (8)–(17), the cost of each exergy flow will be ensured.


## 3.3. According to the Thermoeconomic Analysis of the Solar Part, the Cost Proportions of Solar Energy in Each Exergy Flow Will Be Ensured

This part is shown in Figure2, Box 3. For the convenience of analysis, Figure 3 has been simplified as shown in Figure 4. The system still includes six subsystems.Figure 4
The schematic of cost flows.According to the data above, the solar energy parts in each exergy flow have just been considered alone, and the cost proportions of solar energy will be explored.Equations of each subsystem have been given as follows.(1) The cost equation of oil-water heat exchanging is given by the following:(18)C6β6+C9β9+Cn1βn1=C1β1.(2) The cost equation of preheating, steam generating, and superheating is given by the following:(19)C1β1+C10β10+Cn2βn2=C2β2.(3) The cost equation of turbine is given by the following:(20)C2β2+Cn3βn3=C3β3+C7β7+C12β12.(4) The cost equation of reheating is given by the following:(21)C3β3+C11β11+Cn4βn4=C4β4.(5) The cost equation of turbine is given by the following:(22)C4β4+Cn5βn5=C5β5+C8β8+C13β13.(6) The cost equation of heat exchanging is given by the following:(23)C5β5+C7β7+C8β8+Cn6βn6=C6β6.Since the cost of solar energy achieving is free, we assumeC9=0 and β9=0.For the second and third subsystems, the import exergy flows of 10 and 11 will be 0, which means the solar parts in 10 and 11 will be 0:(24)β10=β11=0.Since the costs ofE2,E3, and E7 are equal, (25) can be obtained as follows:
(25)β2=β3=β7.Since the flow rates ofE4,E5, and E8 are equal, (26) can be obtained as follows:
(26)β4=β5=β8.The cost proportions of solar energyβ will be ensured by using (18)–(26).


## 4. Case Study

### 4.1. Main Parameters

A coal-fired power plant of 600 MW in China has been chosen as the base plant, with the main designed parameters shown in Table1. Coal is the supply fuel of the power plant, with the following components: moisture = 9.9%, ash = 23.7%, hydrogen = 3.11%, nitrogen = 1.01%, sulphur = 2%, oxygen = 2.78%, carbon = 57.5%, and LHV = 21981 kJ/kg.Table 1
Main designed parameters of coal-fired power plant.
Parameters
Values
Units
Capacity
600
MW
Parameters of main steam
24.2/566/566
MPa/°C/°C
Feedwater mass flow rate
1645.15
t/h
Condenser pressure
4.9
kPa
Feedwater temperature
272.3
°C
Coal consumption rate
257.4
g/kWhThe solar aided coal-fired power plant is using the same coal as the base case, except for the solar driven oil-water heat exchanger and the steam cut-off, other structures are the same as the base case. The data of solar field is based on real data from the GEGS-VI station in USA [9–11]. Some modifications have been made to make it suitable for the case in this paper. The collects are LS-2 parabolic trough collects from LUZ Company [9], and the diagram and main parameters of the collectors are shown in Table 2. The collector field is composed of 30 rows of 16 solar collectors which are parallelly installed. The heated heat transfer oil flows into the oil-water heat exchanger and the cooled heat transfer oil will be pumped back into the oil cycle.Table 2
Main parameters of the collector field.
Parameters
Values
Units
Solar irradiation
925
W/m2
Area of per collector
235
m2
Number of collector in each row
16
Rows of collectors
30
Rows
Inlet temperature of heat transfer oil
250
°C
Outlet temperature of heat transfer oil
328
°CThe main designed parameters of solar aided power plant are shown in Table3.Table 3
Main designed parameters of solar aided power plant.
Parameters
Values
Units
Capacity
600
MW
Feedwater temperature
281.65
°C
Coal consumption rate
243.7
g/kWh
Thermal efficiency
50.41
%
Exergy efficiency
48.07
%
Area of all collectors
112800
m2For the solar aided coal-fired power plant, the energy efficiency and exergy efficiency can be defined as follows:(27)ηenergy=woutputQcoal+Qsolar,
where  ηenergy is the energy efficiency, woutput is work output, Qcoal is the energy of coal, and Qsolar is the energy of solar. 								(28)ηexergy=woutputEcoal+Esolar,
where  ηexergy is the exergy efficiency, Ecoal is the exergy of coal, and Esolar is the solar exergy.It can be seen from Tables1 and 3 that the coal consumption rate of solar aided coal-fired power plant is less than that of the coal-fired power plant.The capital cost of the plant is shown in Table4 [12–18]. The investment includes the cost of facilities and the maintaining cost. The cost of coal is 140 dollars/ton [19].Table 4
The investment of the plant.
Items
Cost (dollars)
Solar concentration field
37528560.00
Oil-water heat exchangers
4192170.00
Super heaters of the boiler
168235561.38
Reheaters of the boiler
22941212.92
High-pressure turbine
24723323.22
Intermediate-pressure turbine
26877786.50
Low-pressure turbine
42734428.98
Condenser
14550480.00
Other heat exchangers
21149680.00
Deaerator
3156810.00
Pumps
673317.35


### 4.2. Results and Sensitivity Analysis

Based on the methodology proposed in Section3, the solar contributions in 600 MW solar aided coal-fired power plant have been evaluated. The results of solar exergy proportion and solar cost proportion have been shown in Tables 5 and 6, respectively.Table 5
Exergy value of each flow and the proportion of solar power.
Exergy flows
Exergy value (MJ/h)
Exergy Proportion of solarα
Percent
E
1
555712.8
α
1
48.39
E
2
2447325
α
2
6.55
E
3
1563747
α
3
6.55
E
4
2065157
α
4
4.09
E
5
89036.6
α
5
4.09
E
6
422330.4
α
6
4.72
E
7
157822.2
α
7
6.55
E
8
362203.9
α
8
4.09
E
9
357271.6
α
9
100
E
10
3551430
α
10
0
E
11
941377.7
α
11
0
E
12
664758.2
α
12
6.55
E
13
1495293
α
13
4.09Table 6
Exergy cost of each flow and the proportion of solar power.
Cost flow
values
Cost proportion of solarβ
Percent
C
1
5903
β
1
1.98
C
2
22724
β
2
0.70
C
3
14520
β
3
0.70
C
4
18896
β
4
0.56
C
5
815
β
5
0.56
C
6
5745
β
6
0.70
C
7
1465
β
7
0.70
C
8
3314
β
8
0.56
C
9
0
β
9
100
C
10
16181
β
10
0
C
11
4289
β
11
0
C
12
6833
β
12
0.78
C
13
15032
β
13
0.62The overall exergy proportion of solar power in the plant can be calculated usingα=(α12×E12+α13×E13)/(E12+E13) and the result is 4.84%.It can be seen from Table5 that the proportion of solar exergy is 100 percent in the ninth exergy flow. This is due to the solar energy from the solar exergy flow sharing a contribution ratio of 100 percent. As exergy flows, the proportion of solar exergy shows a decreasing trend.  The twelfth and the thirteenth exergy flows shown in Table 5 represent the exergy in system work (i.e., electric power). The proportions of solar power are 6.55% and 4.09%. The overall exergy proportion of solar power is 4.84% by weighing the proportions in the twelfth and thirteenth exergy flows. In the system, considering the proportion of exergy flows, the contribution of solar power can be measured by its proportion of 4.84% in the overall electric power. For the system with a rated capacity of 600 MW, in this case, about 29.04 MW of electric power is contributed to solar power and the rest 570.96 MW is contributed to coal-fired.The overall cost proportion of solar power in the plant can be calculated usingβ=(β12×C12+β13×C13)/(C12+C13) and the result is 0.67%.It can be seen from Table6 that the cost of solar exergy flow is zero in the exergy cost of the ninth flow. This is because the solar energy has been considered to be free in the analysis. The exergy cost of the twelfth and thirteenth flows in Table 6 shows the exergy costs of electricity, and the proportions of solar power are 0.78% and 0.62% in them. By weighing the proportions of solar power in the twelfth and thirteenth flows, we can obtain that the proportion of solar power in the electric exergy cost is 0.67%. In this system, considering the exergy cost of flows, the proportion of the cost of solar power and solar equipments is 0.67%. For the system, a rated capacity of 600 MW, in this case, the cost of solar energy, and solar equipment share a proportion of 0.67% in the cost of electric power, and the rest (99.33%) comes from coal and other equipment. Comparing the calculated solar power exergy generated with the proportion of cost of solar power exergy generated, the proportion of 4.48% of solar power exergy generated is much larger than the proportion of 0.67% of cost of solar power exergy generated.(1) Sensitivity Analysis of Coal Cost. When the coal cost changes from 100 to 180 dollars/ton, the trend of cost of electricity is shown in Figure 5 and the trend of the overall cost proportion of solar is shown in Figure 6.Figure 5
The change of cost of electricity with coal cost.Figure 6
The change of the overall cost proportion of solar with coal cost.The power generation cost is calculated as follows:(29)celectricity=CelectricityEelectricity,
where  celectricity is the cost of power generation,  Celectricity is the exergy cost of electricity, and  Eelectricity is the generating capacity.The exergy cost of electricity includes two aspects, namely, fixed costs and variable costs. The fixed costs include equipment costs, material costs, depreciation costs, operation, and maintenance fees,  and the variable costs include fuel costs, environmental costs, water charges. In order to take advantage of the calculation method proposed in this paper, all of the costs (except the fuel costs) have been converted to the equipment costs. Therefore, in this case, the cost of power generation is calculated as follows:(30)celectricity=C12+C13E12+E13.It can be seen from Figure5 that the cost of electricity increases from 2.67 cents/kWh to 4.62 cents/kWh in the solar aided coal-fired power plant with the coal prices increase from 100$/t to 180$/t. The power generation cost of 600 MW power plant is 3.81 cents/kWh, and that of the coupled power plant power is 3.64 cents/kWh when the coal price is 140$/t. In the terms of coal price, the COE of a solar aided power plant is less than the one of coal-fired power plant. As solar energy is added to the solar aided system, in the condition of saving coal (with lower coal consumption rate), considering the solar energy is free, the COE of a coupled power plant will be lower than the original thermal power plant. However, compared to the pure solar power generation system, the coupled system uses the turbines, generators and other key equipment of the original thermal power system, and the work efficiency of the replaced high-temperature high-pressure high-grade steam is much higher than the pure solar thermal power generation. Therefore, the COE of the coupled power generation system is less than the pure solar power generation system.It can be seen from Figure6 that with the coal price increasing from 100$/t to 180$/t, the β is reduced from 0.92% to 0.51%, about 0.41 points. The reduction trend tends to be slower with the increase of the coal price.(2) Sensitivity Analysis of Solar Facilities’ Investment. When the investment of solar facilities changes from 60% to 140%, the trend of the cost of electricity is shown in Figure 7 and the trend of the overall cost proportion of solar is shown in Figure 8.Figure 7
The change of the cost of electricity with the solar facilities’ investment.Figure 8
The change of the overall cost proportion of solar with the solar facilities’ investment.Figure7 shows that, with the solar equipment price increase, the proportion of solar equipment increases in the equipment costs, so the COE of solar aided power plant increases. Therefore, the production of cheap solar collector devices is good for power plant in low-cost operation.It can be seen from Figures7 and 8, with the change of the cost of solar equipment from 60% of the calculation cost to 140% of the calculation cost, that the cost of power generation increases from 3.63 cents/kWh to 3.65 cents/kWh; the β increases from 0.53% to 0.79%, which is about 0.26 points.


## 4.1. Main Parameters

A coal-fired power plant of 600 MW in China has been chosen as the base plant, with the main designed parameters shown in Table1. Coal is the supply fuel of the power plant, with the following components: moisture = 9.9%, ash = 23.7%, hydrogen = 3.11%, nitrogen = 1.01%, sulphur = 2%, oxygen = 2.78%, carbon = 57.5%, and LHV = 21981 kJ/kg.Table 1
Main designed parameters of coal-fired power plant.
Parameters
Values
Units
Capacity
600
MW
Parameters of main steam
24.2/566/566
MPa/°C/°C
Feedwater mass flow rate
1645.15
t/h
Condenser pressure
4.9
kPa
Feedwater temperature
272.3
°C
Coal consumption rate
257.4
g/kWhThe solar aided coal-fired power plant is using the same coal as the base case, except for the solar driven oil-water heat exchanger and the steam cut-off, other structures are the same as the base case. The data of solar field is based on real data from the GEGS-VI station in USA [9–11]. Some modifications have been made to make it suitable for the case in this paper. The collects are LS-2 parabolic trough collects from LUZ Company [9], and the diagram and main parameters of the collectors are shown in Table 2. The collector field is composed of 30 rows of 16 solar collectors which are parallelly installed. The heated heat transfer oil flows into the oil-water heat exchanger and the cooled heat transfer oil will be pumped back into the oil cycle.Table 2
Main parameters of the collector field.
Parameters
Values
Units
Solar irradiation
925
W/m2
Area of per collector
235
m2
Number of collector in each row
16
Rows of collectors
30
Rows
Inlet temperature of heat transfer oil
250
°C
Outlet temperature of heat transfer oil
328
°CThe main designed parameters of solar aided power plant are shown in Table3.Table 3
Main designed parameters of solar aided power plant.
Parameters
Values
Units
Capacity
600
MW
Feedwater temperature
281.65
°C
Coal consumption rate
243.7
g/kWh
Thermal efficiency
50.41
%
Exergy efficiency
48.07
%
Area of all collectors
112800
m2For the solar aided coal-fired power plant, the energy efficiency and exergy efficiency can be defined as follows:(27)ηenergy=woutputQcoal+Qsolar,
where  ηenergy is the energy efficiency, woutput is work output, Qcoal is the energy of coal, and Qsolar is the energy of solar. 								(28)ηexergy=woutputEcoal+Esolar,
where  ηexergy is the exergy efficiency, Ecoal is the exergy of coal, and Esolar is the solar exergy.It can be seen from Tables1 and 3 that the coal consumption rate of solar aided coal-fired power plant is less than that of the coal-fired power plant.The capital cost of the plant is shown in Table4 [12–18]. The investment includes the cost of facilities and the maintaining cost. The cost of coal is 140 dollars/ton [19].Table 4
The investment of the plant.
Items
Cost (dollars)
Solar concentration field
37528560.00
Oil-water heat exchangers
4192170.00
Super heaters of the boiler
168235561.38
Reheaters of the boiler
22941212.92
High-pressure turbine
24723323.22
Intermediate-pressure turbine
26877786.50
Low-pressure turbine
42734428.98
Condenser
14550480.00
Other heat exchangers
21149680.00
Deaerator
3156810.00
Pumps
673317.35


## 4.2. Results and Sensitivity Analysis

Based on the methodology proposed in Section3, the solar contributions in 600 MW solar aided coal-fired power plant have been evaluated. The results of solar exergy proportion and solar cost proportion have been shown in Tables 5 and 6, respectively.Table 5
Exergy value of each flow and the proportion of solar power.
Exergy flows
Exergy value (MJ/h)
Exergy Proportion of solarα
Percent
E
1
555712.8
α
1
48.39
E
2
2447325
α
2
6.55
E
3
1563747
α
3
6.55
E
4
2065157
α
4
4.09
E
5
89036.6
α
5
4.09
E
6
422330.4
α
6
4.72
E
7
157822.2
α
7
6.55
E
8
362203.9
α
8
4.09
E
9
357271.6
α
9
100
E
10
3551430
α
10
0
E
11
941377.7
α
11
0
E
12
664758.2
α
12
6.55
E
13
1495293
α
13
4.09Table 6
Exergy cost of each flow and the proportion of solar power.
Cost flow
values
Cost proportion of solarβ
Percent
C
1
5903
β
1
1.98
C
2
22724
β
2
0.70
C
3
14520
β
3
0.70
C
4
18896
β
4
0.56
C
5
815
β
5
0.56
C
6
5745
β
6
0.70
C
7
1465
β
7
0.70
C
8
3314
β
8
0.56
C
9
0
β
9
100
C
10
16181
β
10
0
C
11
4289
β
11
0
C
12
6833
β
12
0.78
C
13
15032
β
13
0.62The overall exergy proportion of solar power in the plant can be calculated usingα=(α12×E12+α13×E13)/(E12+E13) and the result is 4.84%.It can be seen from Table5 that the proportion of solar exergy is 100 percent in the ninth exergy flow. This is due to the solar energy from the solar exergy flow sharing a contribution ratio of 100 percent. As exergy flows, the proportion of solar exergy shows a decreasing trend.  The twelfth and the thirteenth exergy flows shown in Table 5 represent the exergy in system work (i.e., electric power). The proportions of solar power are 6.55% and 4.09%. The overall exergy proportion of solar power is 4.84% by weighing the proportions in the twelfth and thirteenth exergy flows. In the system, considering the proportion of exergy flows, the contribution of solar power can be measured by its proportion of 4.84% in the overall electric power. For the system with a rated capacity of 600 MW, in this case, about 29.04 MW of electric power is contributed to solar power and the rest 570.96 MW is contributed to coal-fired.The overall cost proportion of solar power in the plant can be calculated usingβ=(β12×C12+β13×C13)/(C12+C13) and the result is 0.67%.It can be seen from Table6 that the cost of solar exergy flow is zero in the exergy cost of the ninth flow. This is because the solar energy has been considered to be free in the analysis. The exergy cost of the twelfth and thirteenth flows in Table 6 shows the exergy costs of electricity, and the proportions of solar power are 0.78% and 0.62% in them. By weighing the proportions of solar power in the twelfth and thirteenth flows, we can obtain that the proportion of solar power in the electric exergy cost is 0.67%. In this system, considering the exergy cost of flows, the proportion of the cost of solar power and solar equipments is 0.67%. For the system, a rated capacity of 600 MW, in this case, the cost of solar energy, and solar equipment share a proportion of 0.67% in the cost of electric power, and the rest (99.33%) comes from coal and other equipment. Comparing the calculated solar power exergy generated with the proportion of cost of solar power exergy generated, the proportion of 4.48% of solar power exergy generated is much larger than the proportion of 0.67% of cost of solar power exergy generated.(1) Sensitivity Analysis of Coal Cost. When the coal cost changes from 100 to 180 dollars/ton, the trend of cost of electricity is shown in Figure 5 and the trend of the overall cost proportion of solar is shown in Figure 6.Figure 5
The change of cost of electricity with coal cost.Figure 6
The change of the overall cost proportion of solar with coal cost.The power generation cost is calculated as follows:(29)celectricity=CelectricityEelectricity,
where  celectricity is the cost of power generation,  Celectricity is the exergy cost of electricity, and  Eelectricity is the generating capacity.The exergy cost of electricity includes two aspects, namely, fixed costs and variable costs. The fixed costs include equipment costs, material costs, depreciation costs, operation, and maintenance fees,  and the variable costs include fuel costs, environmental costs, water charges. In order to take advantage of the calculation method proposed in this paper, all of the costs (except the fuel costs) have been converted to the equipment costs. Therefore, in this case, the cost of power generation is calculated as follows:(30)celectricity=C12+C13E12+E13.It can be seen from Figure5 that the cost of electricity increases from 2.67 cents/kWh to 4.62 cents/kWh in the solar aided coal-fired power plant with the coal prices increase from 100$/t to 180$/t. The power generation cost of 600 MW power plant is 3.81 cents/kWh, and that of the coupled power plant power is 3.64 cents/kWh when the coal price is 140$/t. In the terms of coal price, the COE of a solar aided power plant is less than the one of coal-fired power plant. As solar energy is added to the solar aided system, in the condition of saving coal (with lower coal consumption rate), considering the solar energy is free, the COE of a coupled power plant will be lower than the original thermal power plant. However, compared to the pure solar power generation system, the coupled system uses the turbines, generators and other key equipment of the original thermal power system, and the work efficiency of the replaced high-temperature high-pressure high-grade steam is much higher than the pure solar thermal power generation. Therefore, the COE of the coupled power generation system is less than the pure solar power generation system.It can be seen from Figure6 that with the coal price increasing from 100$/t to 180$/t, the β is reduced from 0.92% to 0.51%, about 0.41 points. The reduction trend tends to be slower with the increase of the coal price.(2) Sensitivity Analysis of Solar Facilities’ Investment. When the investment of solar facilities changes from 60% to 140%, the trend of the cost of electricity is shown in Figure 7 and the trend of the overall cost proportion of solar is shown in Figure 8.Figure 7
The change of the cost of electricity with the solar facilities’ investment.Figure 8
The change of the overall cost proportion of solar with the solar facilities’ investment.Figure7 shows that, with the solar equipment price increase, the proportion of solar equipment increases in the equipment costs, so the COE of solar aided power plant increases. Therefore, the production of cheap solar collector devices is good for power plant in low-cost operation.It can be seen from Figures7 and 8, with the change of the cost of solar equipment from 60% of the calculation cost to 140% of the calculation cost, that the cost of power generation increases from 3.63 cents/kWh to 3.65 cents/kWh; the β increases from 0.53% to 0.79%, which is about 0.26 points.


## 5. Conclusions

This paper proposed thermoeconomic cost method for solar contribution study in solar aided coal-fired power plant and analyzed the plant based on the newly constructed and reconstructed 600 MW power plant.Based on the second law of thermodynamics and the principle of thermoeconomics, this paper proposed the evaluation of solar contribution in the solar aided coal-fired power plant, which can be used to assign the individual cost components involving solar energy. Its feasibility has been proven by analyzing a newly constructed power plant. The result shows: that when operating at the rated capacity, the proportion of solar power in overall electric power is 4.84%, which is about 29.04 MW.



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*Source: 197913-2013-02-28.xml*