# Research Difference of Strain Distribution and Microstructure Evolution between Rolling Direction and Transverse Direction of AM50 Mg Alloy Plate by Digital Image Correlation

Authors: Qiang Li; Fuan Hua; Jianping Li; Hao Wang
Journal: Advances in Materials Science and Engineering
 (2015)

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## Abstract

The rolling direction (RD) and transverse direction (TD) of AM50 Mg alloy plate were drawn by tensile test while Digital Image Correlation (DIC) was applied to record local strain distribution and evolution. Then, the microstructure in the maximum strain position was observed so as to find the reason causing the difference between RD and TD specimen. Finally, the fracture surface morphology of the broken specimen was observed by scanning electron microscope (SEM) to determine the crack types. Through the analysis, it is found that the critical failure equivalent strains in the RD specimen and TD specimen are 0.1675 and 0.118, respectively, and the maximum equivalent strain position is the crack source; more twinning is generated in the RD specimen than that of the TD specimen, which indicates that twinning plays an important role in affecting its plasticity. The fracture surface morphology indicates that the RD specimen fracture is quasi-cleavage fracture while the TD specimen shows character of cleavage fracture.


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## Body

## 1. Introduction

Mg alloy, as the lightest structural metal, has been widely used in 3C (communication, computer, and consumer), transport, and aerospace industries [1, 2]. Due to hexagonal close packing-HCP crystal structure at room temperature, poor plastic forming ability limits Mg alloy application. To overcome the low plastic weakness, researchers had developed a series of wrought Mg alloys [2–4], such as AZ series, AM series, and WE series. Meanwhile, great effort had also been made to develop new forming technology, such as hot rolling, semisolid forming, and equal channel angle extruding method [3, 5–7], and the essence of these processes is to raise the deforming temperature or to refine the grain size to improve its deforming ability [2]. With attractive mechanical properties, AM50 was widely applied in automobile industry [8], but most of the research works on AM50 Mg alloy were focused on casting [2].Currently, most of research works on Mg alloy plastic forming process are based on homogeneous assumption that all parts of specimen have the same properties [9]. The assumption neglects the anisotropic properties of grain that leads to the uneven strain distribution during deformation process [10]. In order to explain the uneven defamation mechanism, researchers had developed several crystal plasticity models, such as Sachs model, Taylors model, and self-consistent model to explain local strain distribution according to mechanism of crystal plasticity [10–15], but all of these models have their shortcomings, such as assumption of continuous stress or continuous strain in different grains. Recently, some researchers adopted crystal plasticity finite element method to study the nonuniform distributed deformation in the microscale [16–18], which was helpful to quantitatively research local strain distribution. Meanwhile some adopted electron backscatter diffraction (EBSD) and orientation imaging microscopy (OIM) to view grain deformation and rotation during deformation process [19–21], but these experimental approaches are costly and can be only applied to a small domain with few grains, which limits this method to apply into macroscale. Compared with ESBD and OIM methods, Digital Image Correlation (DIC) is a low cost, high efficiency, and nondestructive method, and the method can be applied from microscale to macroscale, even in 3D [21, 22]. The basic theory of DIC for measuring the displacement and strain can be seen in [22, 23].To date, some researchers also adopted rolling method to produce AM50 Mg alloy sheet [9, 24], and the research for rolling AM50 Mg alloy is helpful to develop a high efficient technology to produce AM50 Mg alloy plate, which can extend the application field of AM50 Mg alloy. When the critical strain of AM50 Mg alloy sheet is measured, the fabrication process of AM50 Mg alloy sheet can be made more reasonably without destroying AM50 Mg alloy sheet. Therefore, the differences of plasticity between rolling direction (RD) and transverse direction specimens (TD) of AM50 Mg alloy plate are analyzed to determine the maximum critical failure strain in the specimens before the specimens break. Then, initial microstructure and the microstructure in the maximum strain position after deformation are compared. Finally, SEM is used to study the fracture morphology of RD and TD tensile specimen to determine the crack type and crack reason.


## 2. Experiments

Experimental material adopts hot rolling AM50 Mg alloy plate, and the thickness of plate is reduced to 1 mm from initial 8 mm by 6 cycles of hot rolling reduction. The hot rolling temperature is selected as 320°C. Its chemical composition is listed in Table1. The geometry of specimen is shown in Figure 1. Both the RD and the TD specimens are taken from an AM50 Mg alloy plate as shown in Figure 2.Table 1
The chemical composition of AM50 Mg alloy (wt%).
Al
Mn
Zn
Si
Fe
Cu
Ni
Mg
4.5~5.5
0.28~0.5
0.15~0.2
<0.05
<0.004
<0.008
<0.001
RestFigure 1
The size of sheet type tensile specimen (unit is mm).Figure 2
The tensile test specimens in AM50 Mg alloy plate. (a) Position of AM50 Mg alloy specimens, (b) specimens of the RD and the TD.
(a)
(b)After the tensile specimen is machined by wire-electrode cutting, the surface of specimens will be polished firstly to get rid of the pollutants. And then black paint is sprayed on one side of the specimen surface uniformly with fine speckles. When the black paint dries, white paint is sprayed on the black painted layer uniformly so that each black and white speckle can be identified clearly by DIC facility. In general the spots of black paint and white paint are about 20μm.The real-time imaging and analyzing VIC-2D 2009 provides image quality up to 5 megapixels. The tensile testing is carried out by WDW-300 (Changchun Experiments Facility Company, China) with loading rate 3 mm/min (0.05 mm/s). The digital camera is placed in front of the tensile test machine, and the light, position, aperture, and focus are adjusted carefully to obtain sharp and clear image before tensile testing. The time interval for taking image is set as 0.05 s, which means 20 pieces of image per second.When the tensile test specimen breaks, the position of maximum equivalent strain will be polished and etched by using 2 g oxalic acid in 100 mL water. Optical microstructure observation is carried out in Zeiss optimal microscope and fracture surface morphology is observed by Hitachi S-3400N scanning electron microscope (SEM). Microstructure in the maximum equivalent strain position is compared with the original microstructure before deformation.


## 3. Results and Discussion

### 3.1. Strain Distribution of the RD Specimen

Figure3 shows the y-direction strain distribution in the RD specimen at 5 s, 25 s, and 35 s, in which y-direction strain is parallel to the elongation direction, and the different color in each figure stands for the different y-direction strain ε
y. In this paper, y-direction strain is defined as strain along with loading direction, and x-direction strain is defined as strain perpendicular to loading direction. At 5 s (Figure 3(a)) the maximum and the minimum y-direction strain are 0.0196 (marked in A zone) and 0.0038 in the left top and the bottom part of the specimen, respectively. The difference between the maximum and minimum y-direction strain is 0.0158. When time is 25 s, as shown in Figure 3(b), the maximum y-direction strain rises up to 0.117 (marked in B zone) five times higher than that in Figure 3(a) the minimum y-direction strain is 0.0435. The difference between the maximum and the minimum y-direction strain reaches 0.0735, which indicates that the y-direction strain distribution is more uneven and some local region bears higher strain and the other region bears lower strain. In addition, from 5 s to 25 s, the maximum y-strain position transfers from A to B position gradually. At 35 s, the maximum y-direction strain reaches 0.206, which is 10 times higher than that at 5 s. Figure 3 also shows the maximum y-direction strain position gradually moving from marked A in the top side of the specimen to marked B in the bottom side of specimen and finally breaks in the marked B position. According to the preset loading rate 3 mm/min, the averaged strain at 35 s is ε
¯
=
3
∗
35
/
60
/
15
=
0.1167 much lower than the maximum y-direction strain 0.206 at 35 s.Figure 3
y-direction strain ε
y distribution during tensile testing process. (a) 5 s; (b) 25 s; (c) 35 s.
(a)
(b)
(c)Neglecting thickness changing during tensile process, the specimen deformation can be regarded as plain deformation that the equivalent strain can be calculated as(1)
ε
¯
=
2
3
ε
x
2
+
ε
y
2
+
ε
x
-
ε
y
2
+
6
γ
x
y
2
,where ε
¯, ε
x, ε
y, and γ
x
y are equivalent strain, x-, y-direction strains, and plane shear strain, respectively. The ε
x, ε
y, and γ
x
y strain can be measured directed by DIC analysis. Therefore, the equivalent strain of AM50 Mg alloy sheet can be got according to local ε
x, ε
y, and γ
x
y.Figure4 shows the equivalent strain distribution in the RD specimen at 5 s, 25 s, and 35 s, respectively, in which the different color stands for different equivalent strain. In Figure 4(a), the maximum equivalent strain is 0.0166 in marked A position slightly smaller than the maximum y-direction strain in Figure 3(a), and the maximum equivalent strain position is the same as in Figure 3(a). The minimum equivalent strain is 0.0027, and the difference between the maximum and the minimum equivalent at 5 s is 0.0139. As time is 25 s, in Figure 4(b), the maximum equivalent strain reaches 0.099 in the middle part and bottom part of specimen as marked B. The minimum equivalent strain is 0.035, and the difference between the maximum and the minimum equivalent strain is 0.064. When time is 35 s, in Figure 4(c), the maximum equivalent strain is 0.1675 in the marked B position. The minimum equivalent strain is 0.045, and the difference between the maximum and the minimum equivalent strain is 0.1225. After 35 s, the specimen breaks, and B position is the initial crack source and then diffuses from the left to right side of the specimen until the specimen completely breaks. Figure 4 indicates the maximum equivalent strain, the minimum equivalent strain, and the difference between them all increase as time increases, which means that the strain in the RD specimen becomes more and more uneven during the deformation process. In addition, the critical failure equivalent strain for the RD specimen of AM50 Mg alloy is 0.1675.Figure 4
Equivalent strain distribution of the RD specimens: (a) 5 s; (b) 25 s; (c) 35 s.
(a)
(b)
(c)Comparing Figure4 with Figure 3, it can be found that the equivalent strain is slightly smaller than y-direction strain in the same position because the equivalent strain relied on its value in x-, y-direction and shear strain, as shown in (1). If in (1) only ε
y is big and other two strains are small, the equivalent strain may be smaller than ε
y. Figure 4 also indicates when the local equivalent strain reaches 0.1675, the specimen is at risk of failure and 0.1675 is the critical failure strain for the RD specimen of AM50 Mg alloy plate.


### 3.2. Strain Distribution of the TD Specimen

Figure5 shows y-direction strain distribution in the TD specimen at 2.5 s, 15 s, and 30 s, respectively, and different color stands for different y-direction strain. At 2.5 s in Figure 5(a), the maximum y-direction strain is 0.0044 in the left top side of the specimen marked as A position. The minimum y-direction strain is 0.00048, and the difference between the maximum and the minimum y-direction strain is 0.00392 at 2.5 s. At 15 s as shown in Figure 5(b), the maximum y-direction strain is 0.0588 in the left top side of the specimen. The minimum y-direction strain is 0.0174, and the difference between the maximum and the minimum y-direction strain is 0.0414 at 15 s. At 30 s in Figure 5(c), the maximum y-direction strain is 0.139 in marked B zone, and the minimum y-direction strain is 0.0518. The difference between the maximum and the minimum y-direction strain is 0.0872 at 30 s. After 30 s the specimen breaks. Figure 5 shows that the maximum strain position gradually transfers from marked A position to marked B position and finally the specimen fails in marked B position.Figure 5
y-direction strain distribution of TD specimen: (a) 2.5 s; (b) 15 s; (c) 30 s.
(a)
(b)
(c)For the TD specimen, loading rate is also 3 mm/min, and the totaly-direction strain at 30 s can be got as ε
¯
=
3
∗
30
/
60
/
15
≈
0.1, which is only little smaller than the maximum y-direction strain. Comparing Figure 5(c) with Figure 3(c), it can be found that the y-direction strain distribution in TD specimen is more even with smaller difference between the minimum and the maximum y-direction strain than that in RD specimen. In addition, the maximum y-direction strain in RD specimen is 1/3 higher than that in the TD specimen, which means that the RD specimen can bear higher y-direction strain than TD specimen.Figure6 shows the equivalent strain distribution in the TD specimen, and different color stands for different equivalent strain. Figure 6(a) shows that the maximum equivalent strain and the minimum equivalent strain are 0.0038 in marked A position and 0.00074 in the left bottom side of specimen, respectively. The difference between the maximum and the minimum equivalent strain is 0.00306. At 15 s as shown in Figure 6(b), the maximum equivalent strain reaches 0.0508 near to the same position as in Figure 6(a), and the minimum equivalent strain also rises up to 0.0136 about two times of the minimum strain in Figure 6(a). The difference between the maximum and the minimum equivalent strain also rises up to 0.0372. When time is 30 s, as shown in Figure 6(c), the maximum equivalent strain is 0.118 in marked B position and the minimum equivalent strain is only 0.0425. The difference between the maximum and the minimum equivalent strain is 0.0755. After 30 s, TD specimen breaks, and 0.118 is the critical failure equivalent strain. Figure 6 indicates the maximum strain gradually transferring from A position to B position, and finally the specimen breaks at B position and diffuses from the right side to the left side of specimen.Figure 6
Equivalent strain distribution at different time: (a) 2.5 s; (b) 15 s; (c) 30 s.
(a)
(b)
(c)Comparing Figure6 with Figure 4, the differences between the maximum equivalent strain and the minimum equivalent strain in the RD and the TD specimen are 0.1225 (0.1675–0.045) and 0.0755 (0.118–0.0425), respectively, which indicates more uneven distribution of equivalent strain in the RD specimen than that of the TD specimen. Furthermore, the minimum equivalent strain difference between the RD (0.045) and the TD (0.0425) specimen is less. If the time period difference between the TD and the RD specimen is considered, the minimum equivalent strain is nearly the same under the same drawing time. On the contrary, there is a relatively big difference in maximum equivalent strain between the RD specimen (0.1675) and the TD specimen (0.118), which means under loading rate 3 mm/min the maximum equivalent strain in the RD specimen is 1/3 higher than that in the TD specimen.


### 3.3. Microstructure Evolution

Figure7 shows the initial microstructure of AM50 Mg alloy plate after annealing treatment before tensile test begins, and averaged grain size is 10 μm with no twinning appearing in grains. It is typical fine annealing microstructure.Figure 7
Initial microstructure before tensile test.Figure8 shows microstructure in the maximum equivalent strain position after specimen breaks. Figure 8(a) is microstructure in the maximum equivalent strain position of the RD specimen. Figure 8(b) is the microstructure in the maximum equivalent strain position of the TD specimen. As shown in Figure 8(a), during the tensile process, most of the grains generated the twinning as marked yellow arrow, and there are still some grains with less twinning generated. As stated by Liu and Ding [25], when the tensile stress is parallel to the c-axis of Mg alloy crystal structure, 1
0
1
-
2 twinning can be generated at room temperature while the pyramidal slip can only be induced under the higher temperature deformation [26]. 1
0
1
-
2 twins are the most commonly twin due to the fact that the critical generation force is only 2 MPa [27]. At room temperature the critical shear stress for prismatic or pyramidal slip is generally high, and so there are only two slip systems in basal plane. Only two slip systems can satisfy such strain as shown in Figures 4 and 6, when the 1
0
1
-
2 twins are generated in grains and the twinning plane can cause a part of grain rotated for an angle of 86° corresponding to the other part of grain. Although the twinning devotes less strain in the whole strain, it makes secondary slip activate due to the orientation changing. The twin-slip interaction can improve the plasticity of Mg alloy. However, the initial orientation of basal plane in Mg alloy plays a very important role in activating 1
0
1
-
2 twinning and basal slip system. In the hot rolling specimen the orientation of microstructure tends to form (0002) basal plane, in which (0002) basal plane is parallel to rolling direction. Therefore, the RD specimen is easier to deform than TD specimen. On the contrary, as shown in Figure 8(b), in the TD specimen marked red arrow grains are fewer than that in Figure 8(a) because during the rolling process the orientation of microstructure tends to (0002) plane and its orientation is parallel to rolling direction, which means in the TD specimen the tensile stress is perpendicular to the (0002) plane. When tensile stress is perpendicular to the (0002) plane, 1
0
1
-
1 twinning can be generated. Generally, at room temperature, 1
0
1
-
2 twinning is more preferred due to the fact that it has a lower critical shear stress compared with 1
0
1
-
1 twinning. In addition, 1
0
1
-
2 twinning can reduce the hardening effect and make the yield strength drop, which increases its plasticity of AM50 Mg alloy. So in Figure 8(a) RD specimen shows more twinning than TD specimen in Figure 8(b); that is why the RD specimen has nearly 1/3 higher strain compared to TD specimen.Figure 8
Microstructure in the maximum strain position: (a) RD; (b) TD.
(a)
(b)Figure9 shows SEM images of the fracture morphology. Figure 9(a) shows the fracture image of the RD specimen, which is classic characteristic of quasi-cleavage fracture morphology, which contains cleavage facets blended with dimples, as the arrow marked. The fracture morphology of Figure 9(a) indicates that the RD specimen bears a little plasticity deformation before it breaks, while in the TD specimen (Figure 9(b)) fracture morphology indicates a characteristic of typical cleavage fracture with clear cleavage plane and steps as arrow marked, which indicates that the fracture morphology is a typical brittle fracture with low plasticity. In Figure 9, it shows that the more the dimple is, the better the deformation ability is. Comparing Figure 9(a) with Figure 9(b), the reason why the RD specimen has better deformation ability than that of the TD specimen can be found.Figure 9
Fracture surface morphology: (a) RD specimen; (b) TD specimen.
(a)
(b)


## 3.1. Strain Distribution of the RD Specimen

Figure3 shows the y-direction strain distribution in the RD specimen at 5 s, 25 s, and 35 s, in which y-direction strain is parallel to the elongation direction, and the different color in each figure stands for the different y-direction strain ε
y. In this paper, y-direction strain is defined as strain along with loading direction, and x-direction strain is defined as strain perpendicular to loading direction. At 5 s (Figure 3(a)) the maximum and the minimum y-direction strain are 0.0196 (marked in A zone) and 0.0038 in the left top and the bottom part of the specimen, respectively. The difference between the maximum and minimum y-direction strain is 0.0158. When time is 25 s, as shown in Figure 3(b), the maximum y-direction strain rises up to 0.117 (marked in B zone) five times higher than that in Figure 3(a) the minimum y-direction strain is 0.0435. The difference between the maximum and the minimum y-direction strain reaches 0.0735, which indicates that the y-direction strain distribution is more uneven and some local region bears higher strain and the other region bears lower strain. In addition, from 5 s to 25 s, the maximum y-strain position transfers from A to B position gradually. At 35 s, the maximum y-direction strain reaches 0.206, which is 10 times higher than that at 5 s. Figure 3 also shows the maximum y-direction strain position gradually moving from marked A in the top side of the specimen to marked B in the bottom side of specimen and finally breaks in the marked B position. According to the preset loading rate 3 mm/min, the averaged strain at 35 s is ε
¯
=
3
∗
35
/
60
/
15
=
0.1167 much lower than the maximum y-direction strain 0.206 at 35 s.Figure 3
y-direction strain ε
y distribution during tensile testing process. (a) 5 s; (b) 25 s; (c) 35 s.
(a)
(b)
(c)Neglecting thickness changing during tensile process, the specimen deformation can be regarded as plain deformation that the equivalent strain can be calculated as(1)
ε
¯
=
2
3
ε
x
2
+
ε
y
2
+
ε
x
-
ε
y
2
+
6
γ
x
y
2
,where ε
¯, ε
x, ε
y, and γ
x
y are equivalent strain, x-, y-direction strains, and plane shear strain, respectively. The ε
x, ε
y, and γ
x
y strain can be measured directed by DIC analysis. Therefore, the equivalent strain of AM50 Mg alloy sheet can be got according to local ε
x, ε
y, and γ
x
y.Figure4 shows the equivalent strain distribution in the RD specimen at 5 s, 25 s, and 35 s, respectively, in which the different color stands for different equivalent strain. In Figure 4(a), the maximum equivalent strain is 0.0166 in marked A position slightly smaller than the maximum y-direction strain in Figure 3(a), and the maximum equivalent strain position is the same as in Figure 3(a). The minimum equivalent strain is 0.0027, and the difference between the maximum and the minimum equivalent at 5 s is 0.0139. As time is 25 s, in Figure 4(b), the maximum equivalent strain reaches 0.099 in the middle part and bottom part of specimen as marked B. The minimum equivalent strain is 0.035, and the difference between the maximum and the minimum equivalent strain is 0.064. When time is 35 s, in Figure 4(c), the maximum equivalent strain is 0.1675 in the marked B position. The minimum equivalent strain is 0.045, and the difference between the maximum and the minimum equivalent strain is 0.1225. After 35 s, the specimen breaks, and B position is the initial crack source and then diffuses from the left to right side of the specimen until the specimen completely breaks. Figure 4 indicates the maximum equivalent strain, the minimum equivalent strain, and the difference between them all increase as time increases, which means that the strain in the RD specimen becomes more and more uneven during the deformation process. In addition, the critical failure equivalent strain for the RD specimen of AM50 Mg alloy is 0.1675.Figure 4
Equivalent strain distribution of the RD specimens: (a) 5 s; (b) 25 s; (c) 35 s.
(a)
(b)
(c)Comparing Figure4 with Figure 3, it can be found that the equivalent strain is slightly smaller than y-direction strain in the same position because the equivalent strain relied on its value in x-, y-direction and shear strain, as shown in (1). If in (1) only ε
y is big and other two strains are small, the equivalent strain may be smaller than ε
y. Figure 4 also indicates when the local equivalent strain reaches 0.1675, the specimen is at risk of failure and 0.1675 is the critical failure strain for the RD specimen of AM50 Mg alloy plate.


## 3.2. Strain Distribution of the TD Specimen

Figure5 shows y-direction strain distribution in the TD specimen at 2.5 s, 15 s, and 30 s, respectively, and different color stands for different y-direction strain. At 2.5 s in Figure 5(a), the maximum y-direction strain is 0.0044 in the left top side of the specimen marked as A position. The minimum y-direction strain is 0.00048, and the difference between the maximum and the minimum y-direction strain is 0.00392 at 2.5 s. At 15 s as shown in Figure 5(b), the maximum y-direction strain is 0.0588 in the left top side of the specimen. The minimum y-direction strain is 0.0174, and the difference between the maximum and the minimum y-direction strain is 0.0414 at 15 s. At 30 s in Figure 5(c), the maximum y-direction strain is 0.139 in marked B zone, and the minimum y-direction strain is 0.0518. The difference between the maximum and the minimum y-direction strain is 0.0872 at 30 s. After 30 s the specimen breaks. Figure 5 shows that the maximum strain position gradually transfers from marked A position to marked B position and finally the specimen fails in marked B position.Figure 5
y-direction strain distribution of TD specimen: (a) 2.5 s; (b) 15 s; (c) 30 s.
(a)
(b)
(c)For the TD specimen, loading rate is also 3 mm/min, and the totaly-direction strain at 30 s can be got as ε
¯
=
3
∗
30
/
60
/
15
≈
0.1, which is only little smaller than the maximum y-direction strain. Comparing Figure 5(c) with Figure 3(c), it can be found that the y-direction strain distribution in TD specimen is more even with smaller difference between the minimum and the maximum y-direction strain than that in RD specimen. In addition, the maximum y-direction strain in RD specimen is 1/3 higher than that in the TD specimen, which means that the RD specimen can bear higher y-direction strain than TD specimen.Figure6 shows the equivalent strain distribution in the TD specimen, and different color stands for different equivalent strain. Figure 6(a) shows that the maximum equivalent strain and the minimum equivalent strain are 0.0038 in marked A position and 0.00074 in the left bottom side of specimen, respectively. The difference between the maximum and the minimum equivalent strain is 0.00306. At 15 s as shown in Figure 6(b), the maximum equivalent strain reaches 0.0508 near to the same position as in Figure 6(a), and the minimum equivalent strain also rises up to 0.0136 about two times of the minimum strain in Figure 6(a). The difference between the maximum and the minimum equivalent strain also rises up to 0.0372. When time is 30 s, as shown in Figure 6(c), the maximum equivalent strain is 0.118 in marked B position and the minimum equivalent strain is only 0.0425. The difference between the maximum and the minimum equivalent strain is 0.0755. After 30 s, TD specimen breaks, and 0.118 is the critical failure equivalent strain. Figure 6 indicates the maximum strain gradually transferring from A position to B position, and finally the specimen breaks at B position and diffuses from the right side to the left side of specimen.Figure 6
Equivalent strain distribution at different time: (a) 2.5 s; (b) 15 s; (c) 30 s.
(a)
(b)
(c)Comparing Figure6 with Figure 4, the differences between the maximum equivalent strain and the minimum equivalent strain in the RD and the TD specimen are 0.1225 (0.1675–0.045) and 0.0755 (0.118–0.0425), respectively, which indicates more uneven distribution of equivalent strain in the RD specimen than that of the TD specimen. Furthermore, the minimum equivalent strain difference between the RD (0.045) and the TD (0.0425) specimen is less. If the time period difference between the TD and the RD specimen is considered, the minimum equivalent strain is nearly the same under the same drawing time. On the contrary, there is a relatively big difference in maximum equivalent strain between the RD specimen (0.1675) and the TD specimen (0.118), which means under loading rate 3 mm/min the maximum equivalent strain in the RD specimen is 1/3 higher than that in the TD specimen.


## 3.3. Microstructure Evolution

Figure7 shows the initial microstructure of AM50 Mg alloy plate after annealing treatment before tensile test begins, and averaged grain size is 10 μm with no twinning appearing in grains. It is typical fine annealing microstructure.Figure 7
Initial microstructure before tensile test.Figure8 shows microstructure in the maximum equivalent strain position after specimen breaks. Figure 8(a) is microstructure in the maximum equivalent strain position of the RD specimen. Figure 8(b) is the microstructure in the maximum equivalent strain position of the TD specimen. As shown in Figure 8(a), during the tensile process, most of the grains generated the twinning as marked yellow arrow, and there are still some grains with less twinning generated. As stated by Liu and Ding [25], when the tensile stress is parallel to the c-axis of Mg alloy crystal structure, 1
0
1
-
2 twinning can be generated at room temperature while the pyramidal slip can only be induced under the higher temperature deformation [26]. 1
0
1
-
2 twins are the most commonly twin due to the fact that the critical generation force is only 2 MPa [27]. At room temperature the critical shear stress for prismatic or pyramidal slip is generally high, and so there are only two slip systems in basal plane. Only two slip systems can satisfy such strain as shown in Figures 4 and 6, when the 1
0
1
-
2 twins are generated in grains and the twinning plane can cause a part of grain rotated for an angle of 86° corresponding to the other part of grain. Although the twinning devotes less strain in the whole strain, it makes secondary slip activate due to the orientation changing. The twin-slip interaction can improve the plasticity of Mg alloy. However, the initial orientation of basal plane in Mg alloy plays a very important role in activating 1
0
1
-
2 twinning and basal slip system. In the hot rolling specimen the orientation of microstructure tends to form (0002) basal plane, in which (0002) basal plane is parallel to rolling direction. Therefore, the RD specimen is easier to deform than TD specimen. On the contrary, as shown in Figure 8(b), in the TD specimen marked red arrow grains are fewer than that in Figure 8(a) because during the rolling process the orientation of microstructure tends to (0002) plane and its orientation is parallel to rolling direction, which means in the TD specimen the tensile stress is perpendicular to the (0002) plane. When tensile stress is perpendicular to the (0002) plane, 1
0
1
-
1 twinning can be generated. Generally, at room temperature, 1
0
1
-
2 twinning is more preferred due to the fact that it has a lower critical shear stress compared with 1
0
1
-
1 twinning. In addition, 1
0
1
-
2 twinning can reduce the hardening effect and make the yield strength drop, which increases its plasticity of AM50 Mg alloy. So in Figure 8(a) RD specimen shows more twinning than TD specimen in Figure 8(b); that is why the RD specimen has nearly 1/3 higher strain compared to TD specimen.Figure 8
Microstructure in the maximum strain position: (a) RD; (b) TD.
(a)
(b)Figure9 shows SEM images of the fracture morphology. Figure 9(a) shows the fracture image of the RD specimen, which is classic characteristic of quasi-cleavage fracture morphology, which contains cleavage facets blended with dimples, as the arrow marked. The fracture morphology of Figure 9(a) indicates that the RD specimen bears a little plasticity deformation before it breaks, while in the TD specimen (Figure 9(b)) fracture morphology indicates a characteristic of typical cleavage fracture with clear cleavage plane and steps as arrow marked, which indicates that the fracture morphology is a typical brittle fracture with low plasticity. In Figure 9, it shows that the more the dimple is, the better the deformation ability is. Comparing Figure 9(a) with Figure 9(b), the reason why the RD specimen has better deformation ability than that of the TD specimen can be found.Figure 9
Fracture surface morphology: (a) RD specimen; (b) TD specimen.
(a)
(b)


## 4. Conclusion

Through DIC recording and analyzing of the local strain distribution and microstructure morphology observing and fracture surface observation in AM50 Mg alloy specimens during tensile deformation, the following conclusions can be drawn:(1)
In the RD specimen the critical failure equivalent strain is 0.1675, while in the TD specimen the critical failure equivalent strain is only 0.118. The RD specimen can bear 1/3 higher strain than TD specimen.
(2)
In both the RD and the TD specimens, the maximum equivalent strain position is the crack source.
(3)
More twinning can be observed in the RD specimen than in the TD specimen, which indicates that twinning plays a dominating role in affecting its plasticity, and that is why the RD specimen has higher deformation ability than that of the TD specimen.
(4)
The fracture surface of the RD specimen shows some quasi-cleavage fracture while the TD specimen fracture surface shows the cleavage crack feature.



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*Source: 175873-2015-11-24.xml*