minktn/spider-data huggingface dataset:
Database: company_office
Question: Count the number of distinct company industries.
SQL: SELECT count(DISTINCT Industry) FROM Companies
Database: company_office
Question: List the names of buildings in descending order of building height.
SQL: SELECT name FROM buildings ORDER BY Height DESC
Database: company_office
Question: What are the names of buildings sorted in descending order of building height?
SQL: SELECT name FROM buildings ORDER BY Height DESC
Database: company_office
Question: Find the stories of the building with the largest height.
SQL: SELECT Stories FROM buildings ORDER BY Height DESC LIMIT 1
Database: company_office
Question: What is the stories of highest building?
SQL: SELECT Stories FROM buildings ORDER BY Height DESC LIMIT 1
Database: company_office
Question: List the name of a building along with the name of a company whose office is in the building.
SQL: SELECT T3.name ,  T2.name FROM Office_locations AS T1 JOIN buildings AS T2 ON T1.building_id  =  T2.id JOIN Companies AS T3 ON T1.company_id  =  T3.id
Database: company_office
Question: For each company, return the company name and the name of the building its office is located in.
SQL: SELECT T3.name ,  T2.name FROM Office_locations AS T1 JOIN buildings AS T2 ON T1.building_id  =  T2.id JOIN Companies AS T3 ON T1.company_id  =  T3.id
Database: company_office
Question: Show the names of the buildings that have more than one company offices.
SQL: SELECT T2.name FROM Office_locations AS T1 JOIN buildings AS T2 ON T1.building_id  =  T2.id JOIN Companies AS T3 ON T1.company_id  =  T3.id GROUP BY T1.building_id HAVING COUNT(*)  >  1
Database: company_office
Question: Which buildings have more than one company offices? Give me the building names.
SQL: SELECT T2.name FROM Office_locations AS T1 JOIN buildings AS T2 ON T1.building_id  =  T2.id JOIN Companies AS T3 ON T1.company_id  =  T3.id GROUP BY T1.building_id HAVING COUNT(*)  >  1
Database: company_office
Question: Show the name of the building that has the most company offices.
SQL: SELECT T2.name FROM Office_locations AS T1 JOIN buildings AS T2 ON T1.building_id  =  T2.id JOIN Companies AS T3 ON T1.company_id  =  T3.id GROUP BY T1.building_id ORDER BY COUNT(*) DESC LIMIT 1
Database: company_office
Question: Which building has the largest number of company offices? Give me the building name.
SQL: SELECT T2.name FROM Office_locations AS T1 JOIN buildings AS T2 ON T1.building_id  =  T2.id JOIN Companies AS T3 ON T1.company_id  =  T3.id GROUP BY T1.building_id ORDER BY COUNT(*) DESC LIMIT 1
Database: company_office
Question: Please show the names of the buildings whose status is "on-hold", in ascending order of stories.
SQL: SELECT name FROM buildings WHERE Status  =  "on-hold" ORDER BY Stories ASC
Database: company_office
Question: Find the names of the buildings in "on-hold" status, and sort them in ascending order of building stories.
SQL: SELECT name FROM buildings WHERE Status  =  "on-hold" ORDER BY Stories ASC
Database: company_office
Question: Please show each industry and the corresponding number of companies in that industry.
SQL: SELECT Industry ,  COUNT(*) FROM Companies GROUP BY Industry
Database: company_office
Question: Whah are the name of each industry and the number of companies in that industry?
SQL: SELECT Industry ,  COUNT(*) FROM Companies GROUP BY Industry
Database: company_office
Question: Please show the industries of companies in descending order of the number of companies.
SQL: SELECT Industry FROM Companies GROUP BY Industry ORDER BY COUNT(*) DESC
Database: company_office
Question: Sort all the industries in descending order of the count of companies in each industry
SQL: SELECT Industry FROM Companies GROUP BY Industry ORDER BY COUNT(*) DESC
Database: company_office
Question: List the industry shared by the most companies.
SQL: SELECT Industry FROM Companies GROUP BY Industry ORDER BY COUNT(*) DESC LIMIT 1
Database: company_office
Question: Which industry has the most companies?
SQL: SELECT Industry FROM Companies GROUP BY Industry ORDER BY COUNT(*) DESC LIMIT 1
Database: company_office
Question: List the names of buildings that have no company office.
SQL: SELECT name FROM buildings WHERE id NOT IN (SELECT building_id FROM Office_locations)
Database: company_office
Question: Which buildings do not have any company office? Give me the building names.
SQL: SELECT name FROM buildings WHERE id NOT IN (SELECT building_id FROM Office_locations)
Database: company_office
Question: Show the industries shared by companies whose headquarters are "USA" and companies whose headquarters are "China".
SQL: SELECT Industry FROM Companies WHERE Headquarters  =  "USA" INTERSECT SELECT Industry FROM Companies WHERE Headquarters  =  "China"
Database: company_office
Question: Which industries have both companies with headquarter in "USA" and companies with headquarter in "China"?
SQL: SELECT Industry FROM Companies WHERE Headquarters  =  "USA" INTERSECT SELECT Industry FROM Companies WHERE Headquarters  =  "China"
Database: company_office
Question: Find the number of companies whose industry is "Banking" or "Conglomerate",
SQL: SELECT count(*) FROM Companies WHERE Industry  =  "Banking" OR Industry  =  "Conglomerate"
Database: company_office
Question: How many companies are in either "Banking" industry or "Conglomerate" industry?
SQL: SELECT count(*) FROM Companies WHERE Industry  =  "Banking" OR Industry  =  "Conglomerate"
Database: company_office
Question: Show the headquarters shared by more than two companies.
SQL: SELECT Headquarters FROM Companies GROUP BY Headquarters HAVING COUNT(*)  >  2
Database: company_office
Question: Which headquarter locations are used by more than 2 companies?
SQL: SELECT Headquarters FROM Companies GROUP BY Headquarters HAVING COUNT(*)  >  2
Database: solvency_ii
Question: How many products are there?
SQL: SELECT count(*) FROM Products
Database: solvency_ii
Question: List the name of products in ascending order of price.
SQL: SELECT Product_Name FROM Products ORDER BY Product_Price ASC
Database: solvency_ii
Question: What are the names and type codes of products?
SQL: SELECT Product_Name ,  Product_Type_Code FROM Products
Database: solvency_ii
Question: Show the prices of the products named "Dining" or "Trading Policy".
SQL: SELECT Product_Price FROM Products WHERE Product_Name  =  "Dining" OR Product_Name  =  "Trading Policy"
Database: solvency_ii
Question: What is the average price for products?
SQL: SELECT avg(Product_Price) FROM Products
Database: solvency_ii
Question: What is the name of the product with the highest price?
SQL: SELECT Product_Name FROM Products ORDER BY Product_Price DESC LIMIT 1
Database: solvency_ii
Question: Show different type codes of products and the number of products with each type code.
SQL: SELECT Product_Type_Code ,  COUNT(*) FROM Products GROUP BY Product_Type_Code
Database: solvency_ii
Question: Show the most common type code across products.
SQL: SELECT Product_Type_Code FROM Products GROUP BY Product_Type_Code ORDER BY COUNT(*) DESC LIMIT 1
Database: solvency_ii
Question: Show the product type codes that have at least two products.
SQL: SELECT Product_Type_Code FROM Products GROUP BY Product_Type_Code HAVING COUNT(*)  >=  2
Database: solvency_ii
Question: Show the product type codes that have both products with price higher than 4500 and products with price lower than 3000.
SQL: SELECT Product_Type_Code FROM Products WHERE Product_Price  >  4500 INTERSECT SELECT Product_Type_Code FROM Products WHERE Product_Price  <  3000
Database: solvency_ii
Question: Show the names of products and the number of events they are in.
SQL: SELECT T1.Product_Name ,  COUNT(*) FROM Products AS T1 JOIN Products_in_Events AS T2 ON T1.Product_ID  =  T2.Product_ID GROUP BY T1.Product_Name
Database: solvency_ii
Question: Show the names of products and the number of events they are in, sorted by the number of events in descending order.
SQL: SELECT T1.Product_Name ,  COUNT(*) FROM Products AS T1 JOIN Products_in_Events AS T2 ON T1.Product_ID  =  T2.Product_ID GROUP BY T1.Product_Name ORDER BY COUNT(*) DESC
Database: solvency_ii
Question: Show the names of products that are in at least two events.
SQL: SELECT T1.Product_Name FROM Products AS T1 JOIN Products_in_Events AS T2 ON T1.Product_ID  =  T2.Product_ID GROUP BY T1.Product_Name HAVING COUNT(*)  >=  2
Database: solvency_ii
Question: Show the names of products that are in at least two events in ascending alphabetical order of product name.
SQL: SELECT T1.Product_Name FROM Products AS T1 JOIN Products_in_Events AS T2 ON T1.Product_ID  =  T2.Product_ID GROUP BY T1.Product_Name HAVING COUNT(*)  >=  2 ORDER BY T1.Product_Name
Database: solvency_ii
Question: List the names of products that are not in any event.
SQL: SELECT Product_Name FROM Products WHERE Product_ID NOT IN (SELECT Product_ID FROM Products_in_Events)
Database: entertainment_awards
Question: How many artworks are there?
SQL: SELECT count(*) FROM artwork
Database: entertainment_awards
Question: List the name of artworks in ascending alphabetical order.
SQL: SELECT Name FROM artwork ORDER BY Name ASC
Database: entertainment_awards
Question: List the name of artworks whose type is not "Program Talent Show".
SQL: SELECT Name FROM artwork WHERE TYPE != "Program Talent Show"
Database: entertainment_awards
Question: What are the names and locations of festivals?
SQL: SELECT Festival_Name ,  LOCATION FROM festival_detail
Database: entertainment_awards
Question: What are the names of the chairs of festivals, sorted in ascending order of the year held?
SQL: SELECT Chair_Name FROM festival_detail ORDER BY YEAR ASC
Database: entertainment_awards
Question: What is the location of the festival with the largest number of audience?
SQL: SELECT LOCATION FROM festival_detail ORDER BY Num_of_Audience DESC LIMIT 1
Database: entertainment_awards
Question: What are the names of festivals held in year 2007?
SQL: SELECT Festival_Name FROM festival_detail WHERE YEAR  =  2007
Database: entertainment_awards
Question: What is the average number of audience for festivals?
SQL: SELECT avg(Num_of_Audience) FROM festival_detail
Database: entertainment_awards
Question: Show the names of the three most recent festivals.
SQL: SELECT Festival_Name FROM festival_detail ORDER BY YEAR DESC LIMIT 3
Database: entertainment_awards
Question: For each nomination, show the name of the artwork and name of the festival where it is nominated.
SQL: SELECT T2.Name ,  T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID
Database: entertainment_awards
Question: Show distinct types of artworks that are nominated in festivals in 2007.
SQL: SELECT DISTINCT T2.Type FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID WHERE T3.Year  =  2007
Database: entertainment_awards
Question: Show the names of artworks in ascending order of the year they are nominated in.
SQL: SELECT T2.Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID ORDER BY T3.Year
Database: entertainment_awards
Question: Show the names of festivals that have nominated artworks of type "Program Talent Show".
SQL: SELECT T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID WHERE T2.Type  =  "Program Talent Show"
Database: entertainment_awards
Question: Show the ids and names of festivals that have at least two nominations for artworks.
SQL: SELECT T1.Festival_ID ,  T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID GROUP BY T1.Festival_ID HAVING COUNT(*)  >=  2
Database: entertainment_awards
Question: Show the id, name of each festival and the number of artworks it has nominated.
SQL: SELECT T1.Festival_ID ,  T3.Festival_Name ,  COUNT(*) FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID GROUP BY T1.Festival_ID
Database: entertainment_awards
Question: Please show different types of artworks with the corresponding number of artworks of each type.
SQL: SELECT TYPE ,  COUNT(*) FROM artwork GROUP BY TYPE
Database: entertainment_awards
Question: List the most common type of artworks.
SQL: SELECT TYPE FROM artwork GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1
Database: entertainment_awards
Question: List the year in which there are more than one festivals.
SQL: SELECT YEAR FROM festival_detail GROUP BY YEAR HAVING COUNT(*)  >  1
Database: entertainment_awards
Question: List the name of artworks that are not nominated.
SQL: SELECT Name FROM Artwork WHERE Artwork_ID NOT IN (SELECT Artwork_ID FROM nomination)
Database: entertainment_awards
Question: Show the number of audience in year 2008 or 2010.
SQL: SELECT Num_of_Audience FROM festival_detail WHERE YEAR  =  2008 OR YEAR  =  2010
Database: entertainment_awards
Question: What are the total number of the audiences who visited any of the festivals?
SQL: SELECT sum(Num_of_Audience) FROM festival_detail
Database: entertainment_awards
Question: In which year are there festivals both inside the 'United States' and outside the 'United States'?
SQL: SELECT YEAR FROM festival_detail WHERE LOCATION  =  'United States' INTERSECT SELECT YEAR FROM festival_detail WHERE LOCATION != 'United States'
Database: customers_campaigns_ecommerce
Question: How many premises are there?
SQL: SELECT count(*) FROM premises
Database: customers_campaigns_ecommerce
Question: What are all the distinct premise types?
SQL: SELECT DISTINCT premises_type FROM premises
Database: customers_campaigns_ecommerce
Question: Find the types and details for all premises and order by the premise type.
SQL: SELECT premises_type ,  premise_details FROM premises ORDER BY premises_type
Database: customers_campaigns_ecommerce
Question: Show each premise type and the number of premises in that type.
SQL: SELECT premises_type ,  count(*) FROM premises GROUP BY premises_type
Database: customers_campaigns_ecommerce
Question: Show all distinct product categories along with the number of mailshots in each category.
SQL: SELECT product_category ,  count(*) FROM mailshot_campaigns GROUP BY product_category
Database: customers_campaigns_ecommerce
Question: Show the name and phone of the customer without any mailshot.
SQL: SELECT customer_name ,  customer_phone FROM customers WHERE customer_id NOT IN (SELECT customer_id FROM mailshot_customers)
Database: customers_campaigns_ecommerce
Question: Show the name and phone for customers with a mailshot with outcome code 'No Response'.
SQL: SELECT T1.customer_name ,  T1.customer_phone FROM customers AS T1 JOIN mailshot_customers AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.outcome_code  =  'No Response'
Database: customers_campaigns_ecommerce
Question: Show the outcome code of mailshots along with the number of mailshots in each outcome code.
SQL: SELECT outcome_code ,  count(*) FROM mailshot_customers GROUP BY outcome_code
Database: customers_campaigns_ecommerce
Question: Show the names of customers who have at least 2 mailshots with outcome code 'Order'.
SQL: SELECT T2.customer_name FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id  =  T2.customer_id WHERE outcome_code  =  'Order' GROUP BY T1.customer_id HAVING count(*)  >=  2
Database: customers_campaigns_ecommerce
Question: Show the names of customers who have the most mailshots.
SQL: SELECT T2.customer_name FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id  =  T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1
Database: customers_campaigns_ecommerce
Question: What are the name and payment method of customers who have both mailshots in 'Order' outcome and mailshots in 'No Response' outcome.
SQL: SELECT T2.customer_name ,  T2.payment_method FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id  =  T2.customer_id WHERE T1.outcome_code  =  'Order' INTERSECT SELECT T2.customer_name ,  T2.payment_method FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id  =  T2.customer_id WHERE T1.outcome_code  =  'No Response'
Database: customers_campaigns_ecommerce
Question: Show the premise type and address type code for all customer addresses.
SQL: SELECT T2.premises_type ,  T1.address_type_code FROM customer_addresses AS T1 JOIN premises AS T2 ON T1.premise_id  =  T2.premise_id
Database: customers_campaigns_ecommerce
Question: What are the distinct address type codes for all customer addresses?
SQL: SELECT DISTINCT address_type_code FROM customer_addresses
Database: customers_campaigns_ecommerce
Question: Show the shipping charge and customer id for customer orders with order status Cancelled or Paid.
SQL: SELECT order_shipping_charges ,  customer_id FROM customer_orders WHERE order_status_code  =  'Cancelled' OR order_status_code  =  'Paid'
Database: customers_campaigns_ecommerce
Question: Show the names of customers having an order with shipping method FedEx and order status Paid.
SQL: SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE shipping_method_code  =  'FedEx' AND order_status_code  =  'Paid'
Database: college_3
Question: How many courses are there in total?
SQL: SELECT count(*) FROM COURSE
Database: college_3
Question: Count the number of courses.
SQL: SELECT count(*) FROM COURSE
Database: college_3
Question: How many courses have more than 2 credits?
SQL: SELECT count(*) FROM COURSE WHERE Credits  >  2
Database: college_3
Question: Count the number of courses with more than 2 credits.
SQL: SELECT count(*) FROM COURSE WHERE Credits  >  2
Database: college_3
Question: List all names of courses with 1 credit?
SQL: SELECT CName FROM COURSE WHERE Credits  =  1
Database: college_3
Question: What are the names of courses with 1 credit?
SQL: SELECT CName FROM COURSE WHERE Credits  =  1
Database: college_3
Question: Which courses are taught on days MTW?
SQL: SELECT CName FROM COURSE WHERE Days  =  "MTW"
Database: college_3
Question: What are the course names for courses taught on MTW?
SQL: SELECT CName FROM COURSE WHERE Days  =  "MTW"
Database: college_3
Question: What is the number of departments in Division "AS"?
SQL: SELECT count(*) FROM DEPARTMENT WHERE Division  =  "AS"
Database: college_3
Question: How many departments are in the division AS?
SQL: SELECT count(*) FROM DEPARTMENT WHERE Division  =  "AS"
Database: college_3
Question: What are the phones of departments in Room 268?
SQL: SELECT DPhone FROM DEPARTMENT WHERE Room  =  268
Database: college_3
Question: Give the phones for departments in room 268.
SQL: SELECT DPhone FROM DEPARTMENT WHERE Room  =  268
Database: college_3
Question: Find the number of students that have at least one grade "B".
SQL: SELECT COUNT(DISTINCT StuID) FROM ENROLLED_IN WHERE Grade  =  "B"
Database: college_3
Question: How many students have had at least one "B" grade?
SQL: SELECT COUNT(DISTINCT StuID) FROM ENROLLED_IN WHERE Grade  =  "B"
Database: college_3
Question: Find the max and min grade point for all letter grade.
SQL: SELECT max(gradepoint) ,  min(gradepoint) FROM GRADECONVERSION
Database: college_3
Question: What are the maximum and minumum grade points?
SQL: SELECT max(gradepoint) ,  min(gradepoint) FROM GRADECONVERSION
Database: college_3
Question: Find the first names of students whose first names contain letter "a".
SQL: SELECT DISTINCT Fname FROM STUDENT WHERE Fname LIKE '%a%'
Database: college_3
Question: What are the first names for students who have an "a" in their first name?
SQL: SELECT DISTINCT Fname FROM STUDENT WHERE Fname LIKE '%a%'
Database: college_3
Question: Find the first names and last names of male (sex is M) faculties who live in building NEB.
SQL: SELECT Fname ,  Lname FROM FACULTY WHERE sex  =  "M" AND Building  =  "NEB"
Database: college_3
Question: What are the full names of faculties with sex M and who live in building NEB?
SQL: SELECT Fname ,  Lname FROM FACULTY WHERE sex  =  "M" AND Building  =  "NEB"
Database: college_3
Question: Find the rooms of faculties with rank professor who live in building NEB.
SQL: SELECT Room FROM FACULTY WHERE Rank  =  "Professor" AND Building  =  "NEB"
Database: college_3
Question: What are the rooms for members of the faculty who are professors and who live in building NEB?
SQL: SELECT Room FROM FACULTY WHERE Rank  =  "Professor" AND Building  =  "NEB"
Database: college_3
Question: Find the department name that is in Building "Mergenthaler".
SQL: SELECT DName FROM DEPARTMENT WHERE Building  =  "Mergenthaler"
Database: college_3
Question: What is the name of the department in the Building Mergenthaler?
SQL: SELECT DName FROM DEPARTMENT WHERE Building  =  "Mergenthaler"
Database: college_3
Question: List all information about courses sorted by credits in the ascending order.
SQL: SELECT * FROM COURSE ORDER BY Credits
Database: college_3
Question: What is all the information about courses, ordered by credits ascending?
SQL: SELECT * FROM COURSE ORDER BY Credits
Database: college_3
Question: List the course name of courses sorted by credits.
SQL: SELECT CName FROM COURSE ORDER BY Credits
Database: college_3
Question: What are the course names, ordered by credits?
SQL: SELECT CName FROM COURSE ORDER BY Credits
Database: college_3
Question: Find the first name of students in the descending order of age.
SQL: SELECT Fname FROM STUDENT ORDER BY Age DESC
Database: college_3
Question: What are the first names of students, ordered by age from greatest to least?
SQL: SELECT Fname FROM STUDENT ORDER BY Age DESC
Database: college_3
Question: Find the last name of female (sex is F) students in the descending order of age.
SQL: SELECT LName FROM STUDENT WHERE Sex  =  "F" ORDER BY Age DESC
Database: college_3
Question: What are the last names of female students, ordered by age descending?
SQL: SELECT LName FROM STUDENT WHERE Sex  =  "F" ORDER BY Age DESC
Database: college_3
Question: Find the last names of faculties in building Barton in alphabetic order.
SQL: SELECT Lname FROM FACULTY WHERE Building  =  "Barton" ORDER BY Lname
Database: college_3
Question: What are the last names of faculty in building Barton, sorted by last name?
SQL: SELECT Lname FROM FACULTY WHERE Building  =  "Barton" ORDER BY Lname
Database: college_3
Question: Find the first names of faculties of rank Professor in alphabetic order.
SQL: SELECT Fname FROM FACULTY WHERE Rank  =  "Professor" ORDER BY Fname
Database: college_3
Question: What are the first names for all faculty professors, ordered by first name?
SQL: SELECT Fname FROM FACULTY WHERE Rank  =  "Professor" ORDER BY Fname
Database: college_3
Question: Find the name of the department that has the biggest number of students minored in?
SQL: SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO  =  T2.DNO GROUP BY T2.DNO ORDER BY count(*) DESC LIMIT 1
Database: college_3
Question: What is the name of the department with the most students minoring in it?
SQL: SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO  =  T2.DNO GROUP BY T2.DNO ORDER BY count(*) DESC LIMIT 1
Database: college_3
Question: Find the name of the department that has no students minored in?
SQL: SELECT DName FROM DEPARTMENT EXCEPT SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO  =  T2.DNO
Database: college_3
Question: What is the name of the department htat has no students minoring in it?
SQL: SELECT DName FROM DEPARTMENT EXCEPT SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO  =  T2.DNO
Database: college_3
Question: Find the name of the department that has the fewest members.
SQL: SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MEMBER_OF AS T2 ON T1.DNO  =  T2.DNO GROUP BY T2.DNO ORDER BY count(*) ASC LIMIT 1
Database: college_3
Question: What is the name of the department with the fewest members?
SQL: SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MEMBER_OF AS T2 ON T1.DNO  =  T2.DNO GROUP BY T2.DNO ORDER BY count(*) ASC LIMIT 1
Database: college_3
Question: Find the rank of the faculty that the fewest faculties belong to.
SQL: SELECT Rank FROM FACULTY GROUP BY Rank ORDER BY count(*) ASC LIMIT 1
Database: college_3
Question: What is the least common faculty rank?
SQL: SELECT Rank FROM FACULTY GROUP BY Rank ORDER BY count(*) ASC LIMIT 1
Database: college_3
Question: What are the first and last names of the instructors who teach the top 3 number of courses?
SQL: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3
Database: college_3
Question: What are the full names of the 3 instructors who teach the most courses?
SQL: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3
Database: college_3
Question: Which building does the instructor who teaches the most number of courses live in?
SQL: SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1
Database: college_3
Question: Give the building that the instructor who teaches the greatest number of courses lives in.
SQL: SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1
Database: college_3
Question: What are the name of courses that have at least five enrollments?
SQL: SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID  =  T2.CID GROUP BY T2.CID HAVING COUNT(*)  >=  5
Database: college_3
Question: Give the names of the courses with at least five enrollments.
SQL: SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID  =  T2.CID GROUP BY T2.CID HAVING COUNT(*)  >=  5
Database: college_3
Question: Find the first name and last name of the instructor of course that has course name
SQL: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID WHERE T1.CName  =  "COMPUTER LITERACY"
Database: college_3
Question: What is the full name of the instructor who has a course named COMPUTER LITERACY?
SQL: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID WHERE T1.CName  =  "COMPUTER LITERACY"
Database: college_3
Question: Find the department name and room of the course INTRODUCTION TO COMPUTER SCIENCE.
SQL: SELECT T2.Dname ,  T2.Room FROM COURSE AS T1 JOIN DEPARTMENT AS T2 ON T1.DNO  =  T2.DNO WHERE T1.CName  =  "INTRODUCTION TO COMPUTER SCIENCE"
Database: college_3
Question: What are the department name and room for the course INTRODUCTION TO COMPUTER SCIENCE?
SQL: SELECT T2.Dname ,  T2.Room FROM COURSE AS T1 JOIN DEPARTMENT AS T2 ON T1.DNO  =  T2.DNO WHERE T1.CName  =  "INTRODUCTION TO COMPUTER SCIENCE"
Database: college_3
Question: Find the student first and last names and grade points of all enrollments.
SQL: SELECT T3.Fname ,  T3.LName ,  T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID
Database: college_3
Question: What are the full names and gradepoints for all enrollments?
SQL: SELECT T3.Fname ,  T3.LName ,  T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID
Database: college_3
Question: Find the distinct student first names of all students that have grade point at least 3.8 in one course.
SQL: SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T2.gradepoint  >=  3.8
Database: college_3
Question: What are the distinct first names for students with a grade point of 3.8 or above in at least one course?
SQL: SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T2.gradepoint  >=  3.8
Database: college_3
Question: Find the full names of faculties who are members of department with department number 520.
SQL: SELECT T1.Fname ,  T1.Lname FROM FACULTY AS T1 JOIN MEMBER_OF AS T2 ON T1.FacID  =  T2.FacID WHERE T2.DNO  =  520
Database: college_3
Question: What are the full names of faculty members who are a part of department 520?
SQL: SELECT T1.Fname ,  T1.Lname FROM FACULTY AS T1 JOIN MEMBER_OF AS T2 ON T1.FacID  =  T2.FacID WHERE T2.DNO  =  520
Database: college_3
Question: What are the first names and last names of the students that minor in the department with DNO 140.
SQL: SELECT T2.Fname ,  T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID  =  T2.StuID WHERE T1.DNO  =  140
Database: college_3
Question: What are the full names of students minoring in department 140?
SQL: SELECT T2.Fname ,  T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID  =  T2.StuID WHERE T1.DNO  =  140
Database: college_3
Question: Find the last names of faculties who are members of computer science department.
SQL: SELECT T2.Lname FROM DEPARTMENT AS T1 JOIN FACULTY AS T2 ON T1.DNO  =  T3.DNO JOIN MEMBER_OF AS T3 ON T2.FacID  =  T3.FacID WHERE T1.DName  =  "Computer Science"
Database: college_3
Question: What are the last names of faculty who are part of the computer science department?
SQL: SELECT T2.Lname FROM DEPARTMENT AS T1 JOIN FACULTY AS T2 ON T1.DNO  =  T3.DNO JOIN MEMBER_OF AS T3 ON T2.FacID  =  T3.FacID WHERE T1.DName  =  "Computer Science"
Database: college_3
Question: Find the average grade point of student whose last name is Smith.
SQL: SELECT avg(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T3.LName  =  "Smith"
Database: college_3
Question: What is the average gradepoint for students with the last name Smith?
SQL: SELECT avg(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T3.LName  =  "Smith"
Database: college_3
Question: What is the maximum and minimum grade point of students who live in NYC?
SQL: SELECT max(T2.gradepoint) ,  min(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T3.city_code  =  "NYC"
Database: college_3
Question: Give the maximum and minimum gradepoints for students living in NYC?
SQL: SELECT max(T2.gradepoint) ,  min(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T3.city_code  =  "NYC"
Database: college_3
Question: Find the names of courses that have either 3 credits or 1 credit but 4 hours.
SQL: SELECT CName FROM COURSE WHERE Credits  =  3 UNION SELECT CName FROM COURSE WHERE Credits  =  1 AND Hours  =  4
Database: college_3
Question: What are the names of courses that give either 3 credits, or 1 credit and 4 hours?
SQL: SELECT CName FROM COURSE WHERE Credits  =  3 UNION SELECT CName FROM COURSE WHERE Credits  =  1 AND Hours  =  4
Database: college_3
Question: Find the names of departments that are either in division AS or in division EN and in Building NEB.
SQL: SELECT DName FROM DEPARTMENT WHERE Division  =  "AS" UNION SELECT DName FROM DEPARTMENT WHERE Division  =  "EN" AND Building  =  "NEB"
Database: college_3
Question: What are the names of departments either in division AS, or in division EN and in building NEB?
SQL: SELECT DName FROM DEPARTMENT WHERE Division  =  "AS" UNION SELECT DName FROM DEPARTMENT WHERE Division  =  "EN" AND Building  =  "NEB"
Database: college_3
Question: Find the first name of students not enrolled in any course.
SQL: SELECT Fname FROM STUDENT WHERE StuID NOT IN (SELECT StuID FROM ENROLLED_IN)
Database: college_3
Question: What are the first names of all students that are not enrolled in courses?
SQL: SELECT Fname FROM STUDENT WHERE StuID NOT IN (SELECT StuID FROM ENROLLED_IN)
Database: department_store
Question: What are the ids of the top three products that were purchased in the largest amount?
SQL: SELECT product_id FROM product_suppliers ORDER BY total_amount_purchased DESC LIMIT 3
Database: department_store
Question: Give the ids of the three products purchased in the largest amounts.
SQL: SELECT product_id FROM product_suppliers ORDER BY total_amount_purchased DESC LIMIT 3
Database: department_store
Question: What are the product id and product type of the cheapest product?
SQL: SELECT product_id ,  product_type_code FROM products ORDER BY product_price LIMIT 1
Database: department_store
Question: Give the id and product type of the product with the lowest price.
SQL: SELECT product_id ,  product_type_code FROM products ORDER BY product_price LIMIT 1
Database: department_store
Question: Find the number of different product types.
SQL: SELECT count(DISTINCT product_type_code) FROM products
Database: department_store
Question: Count the number of distinct product types.
SQL: SELECT count(DISTINCT product_type_code) FROM products
Database: department_store
Question: Return the address of customer 10.
SQL: SELECT T1.address_details FROM addresses AS T1 JOIN customer_addresses AS T2 ON T1.address_id  =  T2.address_id WHERE T2.customer_id  =  10
Database: department_store
Question: What is the address for the customer with id 10?
SQL: SELECT T1.address_details FROM addresses AS T1 JOIN customer_addresses AS T2 ON T1.address_id  =  T2.address_id WHERE T2.customer_id  =  10
Database: department_store
Question: What are the staff ids and genders of all staffs whose job title is Department Manager?
SQL: SELECT T1.staff_id ,  T1.staff_gender FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id WHERE T2.job_title_code  =  "Department Manager"
Database: department_store
Question: Return the staff ids and genders for any staff with the title Department Manager.
SQL: SELECT T1.staff_id ,  T1.staff_gender FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id WHERE T2.job_title_code  =  "Department Manager"
Database: department_store
Question: For each payment method, return how many customers use it.
SQL: SELECT payment_method_code ,  count(*) FROM customers GROUP BY payment_method_code
Database: department_store
Question: How many customers use each payment method?
SQL: SELECT payment_method_code ,  count(*) FROM customers GROUP BY payment_method_code
Database: department_store
Question: What is the id of the product that was ordered the most often?
SQL: SELECT product_id FROM order_items GROUP BY product_id ORDER BY count(*) DESC LIMIT 1
Database: department_store
Question: Give the product id for the product that was ordered most frequently.
SQL: SELECT product_id FROM order_items GROUP BY product_id ORDER BY count(*) DESC LIMIT 1
Database: department_store
Question: What are the name, phone number and email address of the customer who made the largest number of orders?
SQL: SELECT T1.customer_name ,  T1.customer_phone ,  T1.customer_email FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id GROUP BY T2.customer_id ORDER BY count(*) DESC LIMIT 1
Database: department_store
Question: Return the name, phone number and email address for the customer with the most orders.
SQL: SELECT T1.customer_name ,  T1.customer_phone ,  T1.customer_email FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id GROUP BY T2.customer_id ORDER BY count(*) DESC LIMIT 1
Database: department_store
Question: What is the average price for each type of product?
SQL: SELECT product_type_code ,  avg(product_price) FROM products GROUP BY product_type_code
Database: department_store
Question: Return the average price for each product type.
SQL: SELECT product_type_code ,  avg(product_price) FROM products GROUP BY product_type_code
Database: department_store
Question: How many department stores does the store chain South have?
SQL: SELECT count(*) FROM department_stores AS T1 JOIN department_store_chain AS T2 ON T1.dept_store_chain_id  =  T2.dept_store_chain_id WHERE T2.dept_store_chain_name  =  "South"
Database: department_store
Question: Count the number of stores the chain South has.
SQL: SELECT count(*) FROM department_stores AS T1 JOIN department_store_chain AS T2 ON T1.dept_store_chain_id  =  T2.dept_store_chain_id WHERE T2.dept_store_chain_name  =  "South"
Database: department_store
Question: What is the name and job title of the staff who was assigned the latest?
SQL: SELECT T1.staff_name ,  T2.job_title_code FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id ORDER BY T2.date_assigned_to DESC LIMIT 1
Database: department_store
Question: Return the name and job title of the staff with the latest date assigned.
SQL: SELECT T1.staff_name ,  T2.job_title_code FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id ORDER BY T2.date_assigned_to DESC LIMIT 1
Database: department_store
Question: Give me the product type, name and price for all the products supplied by supplier id 3.
SQL: SELECT T2.product_type_code ,  T2.product_name ,  T2.product_price FROM product_suppliers AS T1 JOIN products AS T2 ON T1.product_id  =  T2.product_id WHERE T1.supplier_id  =  3
Database: department_store
Question: Return the product type, name, and price for products supplied by supplier 3.
SQL: SELECT T2.product_type_code ,  T2.product_name ,  T2.product_price FROM product_suppliers AS T1 JOIN products AS T2 ON T1.product_id  =  T2.product_id WHERE T1.supplier_id  =  3
Database: department_store
Question: Return the distinct name of customers whose order status is Pending, in the order of customer id.
SQL: SELECT DISTINCT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.order_status_code  =  "Pending" ORDER BY T2.customer_id
Database: department_store
Question: What are the distinct names of customers with an order status of Pending, sorted by customer id?
SQL: SELECT DISTINCT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.order_status_code  =  "Pending" ORDER BY T2.customer_id
Database: department_store
Question: Find the name and address of the customers who have both New and Pending orders.
SQL: SELECT T1.customer_name ,  T1.customer_address FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.order_status_code  =  "New" INTERSECT SELECT T1.customer_name ,  T1.customer_address FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.order_status_code  =  "Pending"
Database: department_store
Question: What are the names and addressed of customers who have both New and Pending orders?
SQL: SELECT T1.customer_name ,  T1.customer_address FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.order_status_code  =  "New" INTERSECT SELECT T1.customer_name ,  T1.customer_address FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.order_status_code  =  "Pending"
Database: department_store
Question: Return ids of all the products that are supplied by supplier id 2 and are more expensive than the average price of all products.
SQL: SELECT T1.product_id FROM product_suppliers AS T1 JOIN products AS T2 ON T1.product_id  =  T2.product_id WHERE T1.supplier_id  =  2 AND T2.product_price  >  (SELECT avg(product_price) FROM products)
Database: department_store
Question: What are the ids of products from the supplier with id 2, which are more expensive than the average price across all products?
SQL: SELECT T1.product_id FROM product_suppliers AS T1 JOIN products AS T2 ON T1.product_id  =  T2.product_id WHERE T1.supplier_id  =  2 AND T2.product_price  >  (SELECT avg(product_price) FROM products)
Database: department_store
Question: What is the id and name of the department store that has both marketing and managing department?
SQL: SELECT T2.dept_store_id ,  T2.store_name FROM departments AS T1 JOIN department_stores AS T2 ON T1.dept_store_id  =  T2.dept_store_id WHERE T1.department_name  =  "marketing" INTERSECT SELECT T2.dept_store_id ,  T2.store_name FROM departments AS T1 JOIN department_stores AS T2 ON T1.dept_store_id  =  T2.dept_store_id WHERE T1.department_name  =  "managing"
Database: department_store
Question: What are the ids and names of department stores with both marketing and managing departments?
SQL: SELECT T2.dept_store_id ,  T2.store_name FROM departments AS T1 JOIN department_stores AS T2 ON T1.dept_store_id  =  T2.dept_store_id WHERE T1.department_name  =  "marketing" INTERSECT SELECT T2.dept_store_id ,  T2.store_name FROM departments AS T1 JOIN department_stores AS T2 ON T1.dept_store_id  =  T2.dept_store_id WHERE T1.department_name  =  "managing"
Database: department_store
Question: What are the ids of the two department store chains with the largest number of department stores?
SQL: SELECT dept_store_chain_id FROM department_stores GROUP BY dept_store_chain_id ORDER BY count(*) DESC LIMIT 2
Database: department_store
Question: Return the ids of the two department store chains with the most department stores.
SQL: SELECT dept_store_chain_id FROM department_stores GROUP BY dept_store_chain_id ORDER BY count(*) DESC LIMIT 2
Database: department_store
Question: What is the id of the department with the least number of staff?
SQL: SELECT department_id FROM staff_department_assignments GROUP BY department_id ORDER BY count(*) LIMIT 1
Database: department_store
Question: Return the id of the department with the fewest staff assignments.
SQL: SELECT department_id FROM staff_department_assignments GROUP BY department_id ORDER BY count(*) LIMIT 1
Database: department_store
Question: For each product type, return the maximum and minimum price.
SQL: SELECT product_type_code ,  max(product_price) ,  min(product_price) FROM products GROUP BY product_type_code
Database: department_store
Question: What are the maximum and minimum product prices for each product type?
SQL: SELECT product_type_code ,  max(product_price) ,  min(product_price) FROM products GROUP BY product_type_code
Database: department_store
Question: Find the product type whose average price is higher than the average price of all products.
SQL: SELECT product_type_code FROM products GROUP BY product_type_code HAVING avg(product_price)  >  (SELECT avg(product_price) FROM products)
Database: department_store
Question: What is the code of the product type with an average price higher than the average price of all products?
SQL: SELECT product_type_code FROM products GROUP BY product_type_code HAVING avg(product_price)  >  (SELECT avg(product_price) FROM products)
Database: department_store
Question: Find the id and name of the staff who has been assigned for the shortest period.
SQL: SELECT T1.staff_id ,  T1.staff_name FROM staff AS T1 JOIN Staff_Department_Assignments AS T2 ON T1.staff_id  =  T2.staff_id ORDER BY date_assigned_to - date_assigned_from LIMIT 1
Database: department_store
Question: What is the id and name of the staff who has been assigned for the least amount of time?
SQL: SELECT T1.staff_id ,  T1.staff_name FROM staff AS T1 JOIN Staff_Department_Assignments AS T2 ON T1.staff_id  =  T2.staff_id ORDER BY date_assigned_to - date_assigned_from LIMIT 1
Database: department_store
Question: Return the names and ids of all products whose price is between 600 and 700.
SQL: SELECT product_name ,  product_id FROM products WHERE product_price BETWEEN 600 AND 700
Database: department_store
Question: What are the names and ids of products costing between 600 and 700?
SQL: SELECT product_name ,  product_id FROM products WHERE product_price BETWEEN 600 AND 700
Database: department_store
Question: Find the ids of all distinct customers who made order after some orders that were Cancelled.
SQL: SELECT DISTINCT customer_id FROM Customer_Orders WHERE order_date  >  (SELECT min(order_date) FROM Customer_Orders WHERE order_status_code  =  "Cancelled")
Database: department_store
Question: What are the distinct ids of customers who made an order after any order that was Cancelled?
SQL: SELECT DISTINCT customer_id FROM Customer_Orders WHERE order_date  >  (SELECT min(order_date) FROM Customer_Orders WHERE order_status_code  =  "Cancelled")
Database: department_store
Question: What is id of the staff who had a Staff Department Assignment earlier than any Clerical Staff?
SQL: SELECT staff_id FROM Staff_Department_Assignments WHERE date_assigned_to  <  (SELECT max(date_assigned_to) FROM Staff_Department_Assignments WHERE job_title_code  =  'Clerical Staff')
Database: department_store
Question: Return the id of the staff whose Staff Department Assignment was earlier than that of any Clerical Staff.
SQL: SELECT staff_id FROM Staff_Department_Assignments WHERE date_assigned_to  <  (SELECT max(date_assigned_to) FROM Staff_Department_Assignments WHERE job_title_code  =  'Clerical Staff')
Database: department_store
Question: What are the names and ids of customers whose address contains TN?
SQL: SELECT customer_name ,  customer_id FROM customers WHERE customer_address LIKE "%TN%"
Database: department_store
Question: Return the names and ids of customers who have TN in their address.
SQL: SELECT customer_name ,  customer_id FROM customers WHERE customer_address LIKE "%TN%"
Database: department_store
Question: Return the name and gender of the staff who was assigned in 2016.
SQL: SELECT T1.staff_name ,  T1.staff_gender FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id WHERE T2.date_assigned_from LIKE "2016%"
Database: department_store
Question: What are the names and genders of staff who were assigned in 2016?
SQL: SELECT T1.staff_name ,  T1.staff_gender FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id WHERE T2.date_assigned_from LIKE "2016%"
Database: department_store
Question: List the name of staff who has been assigned multiple jobs.
SQL: SELECT T1.staff_name FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id GROUP BY T2.staff_id HAVING COUNT (*)  >  1
Database: department_store
Question: What are the names of staff who have been assigned multiple jobs?
SQL: SELECT T1.staff_name FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id GROUP BY T2.staff_id HAVING COUNT (*)  >  1
Database: department_store
Question: List the name and phone number of all suppliers in the alphabetical order of their addresses.
SQL: SELECT T1.supplier_name ,  T1.supplier_phone FROM Suppliers AS T1 JOIN supplier_addresses AS T2 ON T1.supplier_id  =  T2.supplier_id JOIN addresses AS T3 ON T2.address_id  =  T3.address_id ORDER BY T3.address_details
Database: department_store
Question: What are the names and phone numbers for all suppliers, sorted in alphabetical order of their addressed?
SQL: SELECT T1.supplier_name ,  T1.supplier_phone FROM Suppliers AS T1 JOIN supplier_addresses AS T2 ON T1.supplier_id  =  T2.supplier_id JOIN addresses AS T3 ON T2.address_id  =  T3.address_id ORDER BY T3.address_details
Database: department_store
Question: What are the phone numbers of all customers and suppliers.
SQL: SELECT customer_phone FROM customers UNION SELECT supplier_phone FROM suppliers
Database: department_store
Question: Return the phone numbers for all customers and suppliers.
SQL: SELECT customer_phone FROM customers UNION SELECT supplier_phone FROM suppliers
Database: department_store
Question: Return the ids of all products that were ordered more than three times or supplied more than 80000.
SQL: SELECT product_id FROM Order_Items GROUP BY product_id HAVING count(*)  >  3 UNION SELECT product_id FROM Product_Suppliers GROUP BY product_id HAVING sum(total_amount_purchased)  >  80000
Database: department_store
Question: What are the ids of all products that were either ordered more than 3 times or have a cumulative amount purchased of above 80000?
SQL: SELECT product_id FROM Order_Items GROUP BY product_id HAVING count(*)  >  3 UNION SELECT product_id FROM Product_Suppliers GROUP BY product_id HAVING sum(total_amount_purchased)  >  80000
Database: department_store
Question: What are id and name of the products whose price is lower than 600 or higher than 900?
SQL: SELECT product_id ,  product_name FROM products WHERE product_price  <  600 OR product_price  >  900