minktn/spider-data huggingface dataset:
Database: hr_1
Question: What are all the employees without a department number?
SQL: SELECT * FROM employees WHERE department_id  =  "null"
Database: hr_1
Question: Display all the information about the department Marketing.
SQL: SELECT * FROM  departments WHERE department_name  =  'Marketing'
Database: hr_1
Question: What is all the information about the Marketing department?
SQL: SELECT * FROM  departments WHERE department_name  =  'Marketing'
Database: hr_1
Question: when is the hire date for those employees whose first name does not containing the letter M?
SQL: SELECT hire_date FROM employees WHERE first_name NOT LIKE '%M%'
Database: hr_1
Question: On what dates were employees without the letter M in their first names hired?
SQL: SELECT hire_date FROM employees WHERE first_name NOT LIKE '%M%'
Database: hr_1
Question: display the full name (first and last), hire date, salary, and department number for those employees whose first name does not containing the letter M.
SQL: SELECT first_name ,  last_name ,  hire_date ,  salary ,  department_id FROM employees WHERE first_name NOT LIKE '%M%'
Database: hr_1
Question: What are the full name, hire date, salary, and department id for employees without the letter M in their first name?
SQL: SELECT first_name ,  last_name ,  hire_date ,  salary ,  department_id FROM employees WHERE first_name NOT LIKE '%M%'
Database: hr_1
Question: display the full name (first and last), hire date, salary, and department number for those employees whose first name does not containing the letter M and make the result set in ascending order by department number.
SQL: SELECT first_name ,  last_name ,  hire_date ,  salary ,  department_id FROM employees WHERE first_name NOT LIKE '%M%' ORDER BY department_id
Database: hr_1
Question: What are the full name, hire data, salary and department id for employees without the letter M in their first name, ordered by ascending department id?
SQL: SELECT first_name ,  last_name ,  hire_date ,  salary ,  department_id FROM employees WHERE first_name NOT LIKE '%M%' ORDER BY department_id
Database: hr_1
Question: what is the phone number of employees whose salary is in the range of 8000 and 12000?
SQL: SELECT phone_number FROM employees WHERE salary BETWEEN 8000 AND 12000
Database: hr_1
Question: Return the phone numbers of employees with salaries between 8000 and 12000.
SQL: SELECT phone_number FROM employees WHERE salary BETWEEN 8000 AND 12000
Database: hr_1
Question: display all the information of employees whose salary is in the range of 8000 and 12000 and commission is not null or department number does not equal to 40.
SQL: SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != "null" OR  department_id != 40
Database: hr_1
Question: Return all information about employees with salaries between 8000 and 12000 for which commission is not null or where their department id is not 40.
SQL: SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != "null" OR  department_id != 40
Database: hr_1
Question: What are the full name (first and last name) and salary for all employees who does not have any value for commission?
SQL: SELECT first_name ,  last_name ,  salary FROM  employees WHERE commission_pct  =  "null"
Database: hr_1
Question: Return the full names and salaries of employees with null commissions.
SQL: SELECT first_name ,  last_name ,  salary FROM  employees WHERE commission_pct  =  "null"
Database: hr_1
Question: Display the first and last name, and salary for those employees whose first name is ending with the letter m.
SQL: SELECT first_name ,  last_name ,  salary FROM employees WHERE first_name LIKE '%m'
Database: hr_1
Question: Return the full names and salaries for employees with first names that end with the letter m.
SQL: SELECT first_name ,  last_name ,  salary FROM employees WHERE first_name LIKE '%m'
Database: hr_1
Question: Find job id and date of hire for those employees who was hired between November 5th, 2007 and July 5th, 2009.
SQL: SELECT job_id ,  hire_date FROM employees WHERE hire_date BETWEEN '2007-11-05' AND '2009-07-05'
Database: hr_1
Question: What are the job ids and dates of hire for employees hired after November 5th, 2007 and before July 5th, 2009?
SQL: SELECT job_id ,  hire_date FROM employees WHERE hire_date BETWEEN '2007-11-05' AND '2009-07-05'
Database: hr_1
Question: What are the first and last name for those employees who works either in department 70 or 90?
SQL: SELECT first_name ,  last_name FROM employees WHERE department_id  =  70 OR department_id  =  90
Database: hr_1
Question: What are the full names of employees who with in department 70 or 90?
SQL: SELECT first_name ,  last_name FROM employees WHERE department_id  =  70 OR department_id  =  90
Database: hr_1
Question: Find the salary and manager number for those employees who is working under a manager.
SQL: SELECT salary ,  manager_id FROM employees WHERE manager_id != "null"
Database: hr_1
Question: What are the salaries and manager ids for employees who have managers?
SQL: SELECT salary ,  manager_id FROM employees WHERE manager_id != "null"
Database: hr_1
Question: display all the details from Employees table for those employees who was hired before 2002-06-21.
SQL: SELECT * FROM employees WHERE hire_date  <  '2002-06-21'
Database: hr_1
Question: What is all the information about employees hired before June 21, 2002?
SQL: SELECT * FROM employees WHERE hire_date  <  '2002-06-21'
Database: hr_1
Question: display all the information for all employees who have the letters D or S in their first name and also arrange the result in descending order by salary.
SQL: SELECT * FROM employees WHERE first_name LIKE '%D%' OR first_name LIKE '%S%' ORDER BY salary DESC
Database: hr_1
Question: What is all the information about employees with D or S in their first name, ordered by salary descending?
SQL: SELECT * FROM employees WHERE first_name LIKE '%D%' OR first_name LIKE '%S%' ORDER BY salary DESC
Database: hr_1
Question: display those employees who joined after 7th September, 1987.
SQL: SELECT * FROM employees WHERE hire_date  >  '1987-09-07'
Database: hr_1
Question: Which employees were hired after September 7th, 1987?
SQL: SELECT * FROM employees WHERE hire_date  >  '1987-09-07'
Database: hr_1
Question: display the job title of jobs which minimum salary is greater than 9000.
SQL: SELECT job_title FROM jobs WHERE min_salary  >  9000
Database: hr_1
Question: Which job titles correspond to jobs with salaries over 9000?
SQL: SELECT job_title FROM jobs WHERE min_salary  >  9000
Database: hr_1
Question: display job Title, the difference between minimum and maximum salaries for those jobs which max salary within the range 12000 to 18000.
SQL: SELECT job_title ,  max_salary - min_salary FROM jobs WHERE max_salary BETWEEN 12000 AND 18000
Database: hr_1
Question: What are the job titles, and range of salaries for jobs with maximum salary between 12000 and 18000?
SQL: SELECT job_title ,  max_salary - min_salary FROM jobs WHERE max_salary BETWEEN 12000 AND 18000
Database: hr_1
Question: display the emails of the employees who have no commission percentage and salary within the range 7000 to 12000 and works in that department which number is 50.
SQL: SELECT email FROM employees WHERE commission_pct  =  "null" AND salary BETWEEN 7000 AND 12000 AND department_id = 50
Database: hr_1
Question: What are the emails of employees with null commission, salary between 7000 and 12000, and who work in department 50?
SQL: SELECT email FROM employees WHERE commission_pct  =  "null" AND salary BETWEEN 7000 AND 12000 AND department_id = 50
Database: hr_1
Question: display the employee ID for each employee and the date on which he ended his previous job.
SQL: SELECT employee_id ,  MAX(end_date) FROM job_history GROUP BY employee_id
Database: hr_1
Question: What are the employee ids for each employee and final dates of employment at their last job?
SQL: SELECT employee_id ,  MAX(end_date) FROM job_history GROUP BY employee_id
Database: hr_1
Question: display those departments where more than ten employees work who got a commission percentage.
SQL: SELECT department_id FROM employees GROUP BY department_id HAVING COUNT(commission_pct) > 10
Database: hr_1
Question: What are the department ids for which more than 10 employees had a commission?
SQL: SELECT department_id FROM employees GROUP BY department_id HAVING COUNT(commission_pct) > 10
Database: hr_1
Question: Find the ids of the departments where any manager is managing 4 or more employees.
SQL: SELECT DISTINCT department_id FROM employees GROUP BY department_id ,  manager_id HAVING COUNT(employee_id)  >= 4
Database: hr_1
Question: What are department ids for departments with managers managing more than 3 employees?
SQL: SELECT DISTINCT department_id FROM employees GROUP BY department_id ,  manager_id HAVING COUNT(employee_id)  >= 4
Database: hr_1
Question: display the average salary of employees for each department who gets a commission percentage.
SQL: SELECT department_id ,  AVG(salary) FROM employees WHERE commission_pct != "null" GROUP BY department_id
Database: hr_1
Question: What is the average salary of employees who have a commission percentage that is not null?
SQL: SELECT department_id ,  AVG(salary) FROM employees WHERE commission_pct != "null" GROUP BY department_id
Database: hr_1
Question: display the country ID and number of cities for each country.
SQL: SELECT country_id ,  COUNT(*) FROM locations GROUP BY country_id
Database: hr_1
Question: Give the country id and corresponding count of cities in each country.
SQL: SELECT country_id ,  COUNT(*) FROM locations GROUP BY country_id
Database: hr_1
Question: display job ID for those jobs that were done by two or more for more than 300 days.
SQL: SELECT job_id FROM job_history WHERE end_date - start_date  > 300 GROUP BY job_id HAVING COUNT(*) >= 2
Database: hr_1
Question: What are the job ids for jobs done more than once for a period of more than 300 days?
SQL: SELECT job_id FROM job_history WHERE end_date - start_date  > 300 GROUP BY job_id HAVING COUNT(*) >= 2
Database: hr_1
Question: display the ID for those employees who did two or more jobs in the past.
SQL: SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*)  >= 2
Database: hr_1
Question: What are the employee ids for employees who have held two or more jobs?
SQL: SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*)  >= 2
Database: hr_1
Question: Find employee with ID and name of the country presently where (s)he is working.
SQL: SELECT T1.employee_id ,  T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id JOIN countries AS T4 ON T3.country_id  =  T4.country_id
Database: hr_1
Question: What are all the employee ids and the names of the countries in which they work?
SQL: SELECT T1.employee_id ,  T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id JOIN countries AS T4 ON T3.country_id  =  T4.country_id
Database: hr_1
Question: display the department name and number of employees in each of the department.
SQL: SELECT T2.department_name ,  COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id GROUP BY T2.department_name
Database: hr_1
Question: Give the name of each department and the number of employees in each.
SQL: SELECT T2.department_name ,  COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id GROUP BY T2.department_name
Database: hr_1
Question: Can you return all detailed info of jobs which was done by any of the employees who is presently earning a salary on and above 12000?
SQL: SELECT * FROM  job_history AS T1 JOIN employees AS T2 ON T1.employee_id  =  T2.employee_id WHERE T2.salary  >=  12000
Database: hr_1
Question: What is all the job history info done by employees earning a salary greater than or equal to 12000?
SQL: SELECT * FROM  job_history AS T1 JOIN employees AS T2 ON T1.employee_id  =  T2.employee_id WHERE T2.salary  >=  12000
Database: hr_1
Question: display job title and average salary of employees.
SQL: SELECT job_title ,  AVG(salary) FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id  =  T2.job_id GROUP BY T2.job_title
Database: hr_1
Question: What is the average salary for each job title?
SQL: SELECT job_title ,  AVG(salary) FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id  =  T2.job_id GROUP BY T2.job_title
Database: hr_1
Question: What is the full name ( first name and last name ) for those employees who gets more salary than the employee whose id is 163?
SQL: SELECT first_name ,  last_name FROM employees WHERE salary  >  (SELECT salary FROM employees WHERE employee_id = 163 )
Database: hr_1
Question: Provide the full names of employees earning more than the employee with id 163.
SQL: SELECT first_name ,  last_name FROM employees WHERE salary  >  (SELECT salary FROM employees WHERE employee_id = 163 )
Database: hr_1
Question: return the smallest salary for every departments.
SQL: SELECT MIN(salary) ,  department_id FROM employees GROUP BY department_id
Database: hr_1
Question: What is the minimum salary in each department?
SQL: SELECT MIN(salary) ,  department_id FROM employees GROUP BY department_id
Database: hr_1
Question: Find the first name and last name and department id for those employees who earn such amount of salary which is the smallest salary of any of the departments.
SQL: SELECT first_name ,  last_name ,  department_id FROM employees WHERE salary IN (SELECT MIN(salary) FROM employees GROUP BY department_id)
Database: hr_1
Question: What are the full names and department ids for the lowest paid employees across all departments.
SQL: SELECT first_name ,  last_name ,  department_id FROM employees WHERE salary IN (SELECT MIN(salary) FROM employees GROUP BY department_id)
Database: hr_1
Question: Find the employee id for all employees who earn more than the average salary.
SQL: SELECT employee_id FROM employees WHERE salary  >  (SELECT AVG(salary) FROM employees)
Database: hr_1
Question: What are the employee ids for employees who make more than the average?
SQL: SELECT employee_id FROM employees WHERE salary  >  (SELECT AVG(salary) FROM employees)
Database: hr_1
Question: display the employee id and salary of all employees who report to Payam (first name).
SQL: SELECT employee_id ,  salary FROM employees WHERE manager_id  =  (SELECT employee_id FROM employees WHERE first_name  =  'Payam' )
Database: hr_1
Question: What are the employee ids of employees who report to Payam, and what are their salaries?
SQL: SELECT employee_id ,  salary FROM employees WHERE manager_id  =  (SELECT employee_id FROM employees WHERE first_name  =  'Payam' )
Database: hr_1
Question: find the name of all departments that do actually have one or more employees assigned to them.
SQL: SELECT DISTINCT T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id
Database: hr_1
Question: What are the names of departments that have at least one employee.
SQL: SELECT DISTINCT T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id
Database: hr_1
Question: get the details of employees who manage a department.
SQL: SELECT DISTINCT * FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id WHERE T1.employee_id  =  T2.manager_id
Database: hr_1
Question: What is all the information regarding employees who are managers?
SQL: SELECT DISTINCT * FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id WHERE T1.employee_id  =  T2.manager_id
Database: hr_1
Question: display all the information about the department Marketing.
SQL: SELECT * FROM  departments WHERE department_name  =  'Marketing'
Database: hr_1
Question: What are the employee ids for those who had two or more jobs.
SQL: SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*)  >= 2
Database: hr_1
Question: What are the unique ids of those departments where any manager is managing 4 or more employees.
SQL: SELECT DISTINCT department_id FROM employees GROUP BY department_id ,  manager_id HAVING COUNT(employee_id)  >= 4
Database: hr_1
Question: Give the distinct department ids of departments in which a manager is in charge of 4 or more employees?
SQL: SELECT DISTINCT department_id FROM employees GROUP BY department_id ,  manager_id HAVING COUNT(employee_id)  >= 4
Database: hr_1
Question: Find the job ID for those jobs which average salary is above 8000.
SQL: SELECT job_id FROM employees GROUP BY job_id HAVING AVG(salary) > 8000
Database: hr_1
Question: What are the job ids corresponding to jobs with average salary above 8000?
SQL: SELECT job_id FROM employees GROUP BY job_id HAVING AVG(salary) > 8000
Database: hr_1
Question: display the employee ID and job name for all those jobs in department 80.
SQL: SELECT T1.employee_id ,  T2.job_title FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id  =  T2.job_id WHERE T1.department_id = 80
Database: hr_1
Question: what are the employee ids and job titles for employees in department 80?
SQL: SELECT T1.employee_id ,  T2.job_title FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id  =  T2.job_id WHERE T1.department_id = 80
Database: hr_1
Question: What is the first name and job id for all employees in the Finance department?
SQL: SELECT T1.first_name ,  T1.job_id FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id WHERE T2.department_name  =  'Finance'
Database: hr_1
Question: Give the first name and job id for all employees in the Finance department.
SQL: SELECT T1.first_name ,  T1.job_id FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id WHERE T2.department_name  =  'Finance'
Database: hr_1
Question: display all the information of the employees whose salary if within the range of smallest salary and 2500.
SQL: SELECT * FROM employees WHERE salary BETWEEN (SELECT MIN(salary) FROM employees) AND 2500
Database: hr_1
Question: What is all the information regarding employees with salaries above the minimum and under 2500?
SQL: SELECT * FROM employees WHERE salary BETWEEN (SELECT MIN(salary) FROM employees) AND 2500
Database: hr_1
Question: Find the ids of the employees who does not work in those departments where some employees works whose manager id within the range 100 and 200.
SQL: SELECT * FROM employees WHERE department_id NOT IN (SELECT department_id FROM departments WHERE manager_id BETWEEN 100 AND 200)
Database: hr_1
Question: What are the ids for employees who do not work in departments with managers that have ids between 100 and 200?
SQL: SELECT * FROM employees WHERE department_id NOT IN (SELECT department_id FROM departments WHERE manager_id BETWEEN 100 AND 200)
Database: hr_1
Question: display the employee name ( first name and last name ) and hire date for all employees in the same department as Clara.
SQL: SELECT first_name ,  last_name ,  hire_date FROM employees WHERE department_id  =  (SELECT department_id FROM employees WHERE first_name  =  "Clara")
Database: hr_1
Question: What are the full names and hire dates for employees in the same department as someone with the first name Clara?
SQL: SELECT first_name ,  last_name ,  hire_date FROM employees WHERE department_id  =  (SELECT department_id FROM employees WHERE first_name  =  "Clara")
Database: hr_1
Question: display the employee name ( first name and last name ) and hire date for all employees in the same department as Clara excluding Clara.
SQL: SELECT first_name ,  last_name ,  hire_date FROM employees WHERE department_id  =  ( SELECT department_id FROM employees WHERE first_name  =  "Clara") AND first_name != "Clara"
Database: hr_1
Question: What are the full names and hire dates for employees in the same department as someone with the first name Clara, not including Clara?
SQL: SELECT first_name ,  last_name ,  hire_date FROM employees WHERE department_id  =  ( SELECT department_id FROM employees WHERE first_name  =  "Clara") AND first_name != "Clara"
Database: hr_1
Question: display the employee number and name( first name and last name ) for all employees who work in a department with any employee whose name contains a ’T’.
SQL: SELECT employee_id ,  first_name ,  last_name FROM employees WHERE department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%T%' )
Database: hr_1
Question: What are the ids and full names for employees who work in a department that has someone with a first name that contains the letter T?
SQL: SELECT employee_id ,  first_name ,  last_name FROM employees WHERE department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%T%' )
Database: hr_1
Question: display the employee number, name( first name and last name ), and salary for all employees who earn more than the average salary and who work in a department with any employee with a 'J' in their first name.
SQL: SELECT employee_id ,  first_name ,  last_name ,  salary FROM employees WHERE salary  >  ( SELECT AVG (salary) FROM employees ) AND department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%J%')
Database: hr_1
Question: What are the ids, full names, and salaries for employees making more than average and who work in a department with employees who have the letter J in their first name?
SQL: SELECT employee_id ,  first_name ,  last_name ,  salary FROM employees WHERE salary  >  ( SELECT AVG (salary) FROM employees ) AND department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%J%')
Database: hr_1
Question: display the employee number and job id for all employees whose salary is smaller than any salary of those employees whose job title is MK_MAN.
SQL: SELECT employee_id ,  job_id FROM employees WHERE salary  <  ( SELECT min(salary) FROM employees WHERE job_id  =  'MK_MAN' )
Database: hr_1
Question: What are the employee ids and job ids for employees who make less than the lowest earning employee with title MK_MAN?
SQL: SELECT employee_id ,  job_id FROM employees WHERE salary  <  ( SELECT min(salary) FROM employees WHERE job_id  =  'MK_MAN' )
Database: hr_1
Question: display the employee number, name( first name and last name ) and job title for all employees whose salary is more than any salary of those employees whose job title is PU_MAN.
SQL: SELECT employee_id ,  first_name ,  last_name ,  job_id FROM employees WHERE salary  >  ( SELECT max(salary) FROM employees WHERE job_id  =  'PU_MAN' )
Database: hr_1
Question: What are the employee ids, full names, and job ids for employees who make more than the highest earning employee with title PU_MAN?
SQL: SELECT employee_id ,  first_name ,  last_name ,  job_id FROM employees WHERE salary  >  ( SELECT max(salary) FROM employees WHERE job_id  =  'PU_MAN' )
Database: hr_1
Question: display the department id and the total salary for those departments which contains at least two employees.
SQL: SELECT department_id ,  SUM(salary) FROM employees GROUP BY department_id HAVING count(*)  >=  2
Database: hr_1
Question: What are total salaries and department id for each department that has more than 2 employees?
SQL: SELECT department_id ,  SUM(salary) FROM employees GROUP BY department_id HAVING count(*)  >=  2
Database: hr_1
Question: display all the information of those employees who did not have any job in the past.
SQL: SELECT * FROM employees WHERE employee_id NOT IN (SELECT employee_id FROM job_history)
Database: hr_1
Question: What is all the information about employees who have never had a job in the past?
SQL: SELECT * FROM employees WHERE employee_id NOT IN (SELECT employee_id FROM job_history)
Database: hr_1
Question: display the department ID, full name (first and last name), salary for those employees who is highest salary in every department.
SQL: SELECT first_name ,   last_name ,   salary ,  department_id ,  MAX(salary) FROM employees GROUP BY department_id
Database: hr_1
Question: What are the department ids, full names, and salaries for employees who make the most in their departments?
SQL: SELECT first_name ,   last_name ,   salary ,  department_id ,  MAX(salary) FROM employees GROUP BY department_id
Database: hr_1
Question: display the first and last name, department, city, and state province for each employee.
SQL: SELECT T1.first_name ,  T1.last_name ,  T2.department_name ,  T3.city ,  T3.state_province FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id
Database: hr_1
Question: What are the full names, departments, cities, and state provinces for each employee?
SQL: SELECT T1.first_name ,  T1.last_name ,  T2.department_name ,  T3.city ,  T3.state_province FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id
Database: hr_1
Question: display those employees who contain a letter z to their first name and also display their last name, city.
SQL: SELECT T1.first_name ,  T1.last_name ,  T3.city FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id WHERE T1.first_name LIKE '%z%'
Database: hr_1
Question: What are the full names and cities of employees who have the letter Z in their first names?
SQL: SELECT T1.first_name ,  T1.last_name ,  T3.city FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id WHERE T1.first_name LIKE '%z%'
Database: hr_1
Question: display the department name, city, and state province for each department.
SQL: SELECT T1.department_name ,  T2.city ,  T2.state_province FROM departments AS T1 JOIN locations AS T2 ON T2.location_id  =  T1.location_id
Database: hr_1
Question: What are the department names, cities, and state provinces for each department?
SQL: SELECT T1.department_name ,  T2.city ,  T2.state_province FROM departments AS T1 JOIN locations AS T2 ON T2.location_id  =  T1.location_id
Database: hr_1
Question: display the full name (first and last name ) of employee with ID and name of the country presently where (s)he is working.
SQL: SELECT T1.first_name ,  T1.last_name , T1.employee_id ,  T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id JOIN countries AS T4 ON T3.country_id  =  T4.country_id
Database: hr_1
Question: What the full names, ids of each employee and the name of the country they are in?
SQL: SELECT T1.first_name ,  T1.last_name , T1.employee_id ,  T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id JOIN countries AS T4 ON T3.country_id  =  T4.country_id
Database: hr_1
Question: display the department name and number of employees in each of the department.
SQL: SELECT department_name ,  COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id GROUP BY department_name
Database: hr_1
Question: What are the department names and how many employees work in each of them?
SQL: SELECT department_name ,  COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id GROUP BY department_name
Database: hr_1
Question: display the full name (first and last name), and salary of those employees who working in any department located in London.
SQL: SELECT first_name ,  last_name ,  salary FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN  locations AS T3 ON T2.location_id  =  T3.location_id WHERE  T3.city  =  'London'
Database: hr_1
Question: What are full names and salaries of employees working in the city of London?
SQL: SELECT first_name ,  last_name ,  salary FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN  locations AS T3 ON T2.location_id  =  T3.location_id WHERE  T3.city  =  'London'
Database: music_1
Question: What is the name of the song that was released in the most recent year?
SQL: SELECT song_name ,  releasedate FROM song ORDER BY releasedate DESC LIMIT 1
Database: music_1
Question: What is the name of the song that was released most recently?
SQL: SELECT song_name ,  releasedate FROM song ORDER BY releasedate DESC LIMIT 1
Database: music_1
Question: What is the id of the longest song?
SQL: SELECT f_id FROM files ORDER BY duration DESC LIMIT 1
Database: music_1
Question: Find the id of the song that lasts the longest.
SQL: SELECT f_id FROM files ORDER BY duration DESC LIMIT 1
Database: music_1
Question: Find the names of all English songs.
SQL: SELECT song_name FROM song WHERE languages  =  "english"
Database: music_1
Question: What are the names of all songs in English?
SQL: SELECT song_name FROM song WHERE languages  =  "english"
Database: music_1
Question: What are the id of songs whose format is mp3.
SQL: SELECT f_id FROM files WHERE formats  =  "mp3"
Database: music_1
Question: What are the id of all the files in mp3 format?
SQL: SELECT f_id FROM files WHERE formats  =  "mp3"
Database: music_1
Question: List the name and country of origin for all singers who have produced songs with rating above 9.
SQL: SELECT DISTINCT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.rating  >  9
Database: music_1
Question: What are the different names and countries of origins for all artists whose song ratings are above 9?
SQL: SELECT DISTINCT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.rating  >  9
Database: music_1
Question: List the file size and format for all songs that have resolution lower than 800.
SQL: SELECT DISTINCT T1.file_size ,  T1.formats FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T2.resolution  <  800
Database: music_1
Question: What are the file sizes and formats for all songs with a resolution lower than 800?
SQL: SELECT DISTINCT T1.file_size ,  T1.formats FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T2.resolution  <  800
Database: music_1
Question: What is the name of the artist who produced the shortest song?
SQL: SELECT T1.artist_name FROM song AS T1 JOIN files AS T2 ON T1.f_id  =  T2.f_id ORDER BY T2.duration LIMIT 1
Database: music_1
Question: What are the names of the artists who sang the shortest song?
SQL: SELECT T1.artist_name FROM song AS T1 JOIN files AS T2 ON T1.f_id  =  T2.f_id ORDER BY T2.duration LIMIT 1
Database: music_1
Question: What are the names and countries of origin for the artists who produced the top three highly rated songs.
SQL: SELECT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name ORDER BY T2.rating DESC LIMIT 3
Database: music_1
Question: What are the names of the singers who sang the top 3 most highly rated songs and what countries do they hail from?
SQL: SELECT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name ORDER BY T2.rating DESC LIMIT 3
Database: music_1
Question: How many songs have 4 minute duration?
SQL: SELECT count(*) FROM files WHERE duration LIKE "4:%"
Database: music_1
Question: What is the count of the songs that last approximately 4 minutes?
SQL: SELECT count(*) FROM files WHERE duration LIKE "4:%"
Database: music_1
Question: How many artists are from Bangladesh?
SQL: SELECT count(*) FROM artist WHERE country  =  "Bangladesh"
Database: music_1
Question: How many Bangladeshi artists are listed?
SQL: SELECT count(*) FROM artist WHERE country  =  "Bangladesh"
Database: music_1
Question: What is the average rating of songs produced by female artists?
SQL: SELECT avg(T2.rating) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T1.gender  =  "Female"
Database: music_1
Question: How many songs, on average, are sung by a female artist?
SQL: SELECT avg(T2.rating) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T1.gender  =  "Female"
Database: music_1
Question: What is the most popular file format?
SQL: SELECT formats FROM files GROUP BY formats ORDER BY COUNT (*) DESC LIMIT 1
Database: music_1
Question: Find the file format that is used by the most files.
SQL: SELECT formats FROM files GROUP BY formats ORDER BY COUNT (*) DESC LIMIT 1
Database: music_1
Question: Find the names of the artists who are from UK and have produced English songs.
SQL: SELECT artist_name FROM artist WHERE country  =  "UK" INTERSECT SELECT artist_name FROM song WHERE languages  =  "english"
Database: music_1
Question: What are the names of the artists that are from the UK and sang songs in English?
SQL: SELECT artist_name FROM artist WHERE country  =  "UK" INTERSECT SELECT artist_name FROM song WHERE languages  =  "english"
Database: music_1
Question: Find the id of songs that are available in mp4 format and have resolution lower than 1000.
SQL: SELECT f_id FROM files WHERE formats  =  "mp4" INTERSECT SELECT f_id FROM song WHERE resolution  <  1000
Database: music_1
Question: What is the id of the files that are available in the format of mp4 and a resolution smaller than 1000?
SQL: SELECT f_id FROM files WHERE formats  =  "mp4" INTERSECT SELECT f_id FROM song WHERE resolution  <  1000
Database: music_1
Question: What is the country of origin of the artist who is female and produced a song in Bangla?
SQL: SELECT T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T1.gender  =  "Female" AND T2.languages  =  "bangla"
Database: music_1
Question: What countries are the female artists who sung in the language Bangla from?
SQL: SELECT T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T1.gender  =  "Female" AND T2.languages  =  "bangla"
Database: music_1
Question: What is the average duration of songs that have mp3 format and resolution below 800?
SQL: SELECT avg(T1.duration) FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.formats  =  "mp3" AND T2.resolution   <  800
Database: music_1
Question: What is the average song duration for the songs that are in mp3 format and whose resolution below 800?
SQL: SELECT avg(T1.duration) FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.formats  =  "mp3" AND T2.resolution   <  800
Database: music_1
Question: What is the number of artists for each gender?
SQL: SELECT count(*) ,  gender FROM artist GROUP BY gender
Database: music_1
Question: How many artists are male and how many are female?
SQL: SELECT count(*) ,  gender FROM artist GROUP BY gender
Database: music_1
Question: What is the average rating of songs for each language?
SQL: SELECT avg(rating) ,  languages FROM song GROUP BY languages
Database: music_1
Question: What is the average song rating for each language?
SQL: SELECT avg(rating) ,  languages FROM song GROUP BY languages
Database: music_1
Question: Return the gender and name of artist who produced the song with the lowest resolution.
SQL: SELECT T1.gender ,  T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name ORDER BY T2.resolution LIMIT 1
Database: music_1
Question: What is the gender and name of the artist who sang the song with the smallest resolution?
SQL: SELECT T1.gender ,  T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name ORDER BY T2.resolution LIMIT 1
Database: music_1
Question: For each file format, return the number of artists who released songs in that format.
SQL: SELECT count(*) ,  formats FROM files GROUP BY formats
Database: music_1
Question: How many songs were released for each format?
SQL: SELECT count(*) ,  formats FROM files GROUP BY formats
Database: music_1
Question: Find the distinct names of all songs that have a higher resolution than some songs in English.
SQL: SELECT DISTINCT song_name FROM song WHERE resolution  >  (SELECT min(resolution) FROM song WHERE languages  =  "english")
Database: music_1
Question: What are the different names for all songs that have a higher resolution than English songs?
SQL: SELECT DISTINCT song_name FROM song WHERE resolution  >  (SELECT min(resolution) FROM song WHERE languages  =  "english")
Database: music_1
Question: What are the names of all songs that have a lower rating than some song of blues genre?
SQL: SELECT song_name FROM song WHERE rating  <  (SELECT max(rating) FROM song WHERE genre_is  =  "blues")
Database: music_1
Question: What are the names of the songs that have a lower rating than at least one blues song?
SQL: SELECT song_name FROM song WHERE rating  <  (SELECT max(rating) FROM song WHERE genre_is  =  "blues")
Database: music_1
Question: What is the name and country of origin of the artist who released a song that has "love" in its title?
SQL: SELECT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.song_name LIKE "%love%"
Database: music_1
Question: What are the names of the artists who released a song that has the word love in its title, and where are the artists from?
SQL: SELECT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.song_name LIKE "%love%"
Database: music_1
Question: List the name and gender for all artists who released songs in March.
SQL: SELECT T1.artist_name ,  T1.gender FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.releasedate LIKE "%Mar%"
Database: music_1
Question: What are the names and genders of all artists who released songs in the month of March?
SQL: SELECT T1.artist_name ,  T1.gender FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.releasedate LIKE "%Mar%"
Database: music_1
Question: List the names of all genres in alphabetical oder, together with its ratings.
SQL: SELECT g_name ,  rating FROM genre ORDER BY g_name
Database: music_1
Question: What are the names of all genres in alphabetical order, combined with its ratings?
SQL: SELECT g_name ,  rating FROM genre ORDER BY g_name
Database: music_1
Question: Give me a list of the names of all songs ordered by their resolution.
SQL: SELECT song_name FROM song ORDER BY resolution
Database: music_1
Question: What are the names of all songs that are ordered by their resolution numbers?
SQL: SELECT song_name FROM song ORDER BY resolution
Database: music_1
Question: What are the ids of songs that are available in either mp4 format or have resolution above 720?
SQL: SELECT f_id FROM files WHERE formats  =  "mp4" UNION SELECT f_id FROM song WHERE resolution  >  720
Database: music_1
Question: What are the ids of all songs that are available on mp4 or have a higher resolution than 720?
SQL: SELECT f_id FROM files WHERE formats  =  "mp4" UNION SELECT f_id FROM song WHERE resolution  >  720
Database: music_1
Question: List the names of all songs that have 4 minute duration or are in English.
SQL: SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.duration LIKE "4:%" UNION SELECT song_name FROM song WHERE languages  =  "english"
Database: music_1
Question: What are the names of all songs that are approximately 4 minutes long or are in English?
SQL: SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.duration LIKE "4:%" UNION SELECT song_name FROM song WHERE languages  =  "english"
Database: music_1
Question: What is the language used most often in the songs?
SQL: SELECT languages FROM song GROUP BY languages ORDER BY count(*) DESC LIMIT 1
Database: music_1
Question: What are the languages that are used most often in songs?
SQL: SELECT languages FROM song GROUP BY languages ORDER BY count(*) DESC LIMIT 1
Database: music_1
Question: What is the language that was used most often in songs with resolution above 500?
SQL: SELECT artist_name FROM song WHERE resolution  >  500 GROUP BY languages ORDER BY count(*) DESC LIMIT 1
Database: music_1
Question: What is the name of the artist, for each language, that has the most songs with a higher resolution than 500?
SQL: SELECT artist_name FROM song WHERE resolution  >  500 GROUP BY languages ORDER BY count(*) DESC LIMIT 1
Database: music_1
Question: What are the names of artists who are Male and are from UK?
SQL: SELECT artist_name FROM artist WHERE country  =  "UK" AND gender  =  "Male"
Database: music_1
Question: What are the names of all male British artists?
SQL: SELECT artist_name FROM artist WHERE country  =  "UK" AND gender  =  "Male"
Database: music_1
Question: Find the names of songs whose genre is modern or language is English.
SQL: SELECT song_name FROM song WHERE genre_is  =  "modern" OR languages  =  "english"
Database: music_1
Question: What are the names of the songs that are modern or sung in English?
SQL: SELECT song_name FROM song WHERE genre_is  =  "modern" OR languages  =  "english"
Database: music_1
Question: Return the names of songs for which format is mp3 and resolution is below 1000.
SQL: SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.formats  =  "mp3" INTERSECT SELECT song_name FROM song WHERE resolution  <  1000
Database: music_1
Question: What are the names of all songs that are in mp3 format and have a resolution lower than 1000?
SQL: SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.formats  =  "mp3" INTERSECT SELECT song_name FROM song WHERE resolution  <  1000
Database: music_1
Question: Return the names of singers who are from UK and released an English song.
SQL: SELECT artist_name FROM artist WHERE country  =  "UK" INTERSECT SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.languages  =  "english"
Database: music_1
Question: What are the names of all singers that are from the UK and released a song in English?
SQL: SELECT artist_name FROM artist WHERE country  =  "UK" INTERSECT SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.languages  =  "english"
Database: music_1
Question: What are the average rating and resolution of songs that are in Bangla?
SQL: SELECT avg(rating) ,  avg(resolution) FROM song WHERE languages  =  "bangla"
Database: music_1
Question: What is the average rating and resolution of all bangla songs?
SQL: SELECT avg(rating) ,  avg(resolution) FROM song WHERE languages  =  "bangla"
Database: music_1
Question: What are the maximum and minimum resolution of songs whose duration is 3 minutes?
SQL: SELECT max(T2.resolution) ,  min(T2.resolution) FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.duration LIKE "3:%"
Database: music_1
Question: What is the maximum and minimum resolution of all songs that are approximately 3 minutes long?
SQL: SELECT max(T2.resolution) ,  min(T2.resolution) FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.duration LIKE "3:%"
Database: music_1
Question: What are the maximum duration and resolution of songs grouped and ordered by languages?
SQL: SELECT max(T1.duration) ,  max(T2.resolution) ,  T2.languages FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id GROUP BY T2.languages ORDER BY T2.languages
Database: music_1
Question: What are the maximum duration and resolution of all songs, for each language, ordered alphabetically by language?
SQL: SELECT max(T1.duration) ,  max(T2.resolution) ,  T2.languages FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id GROUP BY T2.languages ORDER BY T2.languages
Database: music_1
Question: What are the shortest duration and lowest rating of songs grouped by genre and ordered by genre?
SQL: SELECT min(T1.duration) ,  min(T2.rating) ,  T2.genre_is FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id GROUP BY T2.genre_is ORDER BY T2.genre_is
Database: music_1
Question: What is the shortest and most poorly rated song for each genre, ordered alphabetically by genre?
SQL: SELECT min(T1.duration) ,  min(T2.rating) ,  T2.genre_is FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id GROUP BY T2.genre_is ORDER BY T2.genre_is
Database: music_1
Question: Find the names and number of works of all artists who have at least one English songs.
SQL: SELECT T1.artist_name ,  count(*) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.languages  =  "english" GROUP BY T2.artist_name HAVING count(*)  >=  1
Database: music_1
Question: What are the names and number of works for all artists who have sung at least one song in English?
SQL: SELECT T1.artist_name ,  count(*) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.languages  =  "english" GROUP BY T2.artist_name HAVING count(*)  >=  1
Database: music_1
Question: Find the name and country of origin for all artists who have release at least one song of resolution above 900.
SQL: SELECT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.resolution  >  900 GROUP BY T2.artist_name HAVING count(*)  >=  1
Database: music_1
Question: What is the name and country of origin for each artist who has released a song with a resolution higher than 900?
SQL: SELECT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.resolution  >  900 GROUP BY T2.artist_name HAVING count(*)  >=  1
Database: music_1
Question: Find the names and number of works of the three artists who have produced the most songs.
SQL: SELECT T1.artist_name ,  count(*) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name GROUP BY T2.artist_name ORDER BY count(*) DESC LIMIT 3
Database: music_1
Question: What are the names of the three artists who have produced the most songs, and how many works did they produce?
SQL: SELECT T1.artist_name ,  count(*) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name GROUP BY T2.artist_name ORDER BY count(*) DESC LIMIT 3
Database: music_1
Question: Find the country of origin for the artist who made the least number of songs?
SQL: SELECT T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name GROUP BY T2.artist_name ORDER BY count(*) LIMIT 1
Database: music_1
Question: What country is the artist who made the fewest songs from?
SQL: SELECT T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name GROUP BY T2.artist_name ORDER BY count(*) LIMIT 1
Database: music_1
Question: What are the names of the songs whose rating is below the rating of all songs in English?
SQL: SELECT song_name FROM song WHERE rating  <   (SELECT min(rating) FROM song WHERE languages  =  'english')
Database: music_1
Question: What are the song names for every song whose rating is less than the minimum rating for English songs?
SQL: SELECT song_name FROM song WHERE rating  <   (SELECT min(rating) FROM song WHERE languages  =  'english')
Database: music_1
Question: What is ids of the songs whose resolution is higher than the resolution of any songs with rating lower than 8?
SQL: SELECT f_id FROM song WHERE resolution  >  (SELECT max(resolution) FROM song WHERE rating  <  8)
Database: music_1
Question: What is the id of every song that has a resolution higher than that of a song with a rating below 8?
SQL: SELECT f_id FROM song WHERE resolution  >  (SELECT max(resolution) FROM song WHERE rating  <  8)
Database: music_1
Question: What is ids of the songs whose resolution is higher than the average resolution of songs in modern genre?
SQL: SELECT f_id FROM song WHERE resolution  >  (SELECT avg(resolution) FROM song WHERE genre_is  =  "modern")
Database: music_1
Question: What are the ids of all songs that have higher resolution of the average resolution in the modern genre?
SQL: SELECT f_id FROM song WHERE resolution  >  (SELECT avg(resolution) FROM song WHERE genre_is  =  "modern")
Database: music_1
Question: Find the top 3 artists who have the largest number of songs works whose language is Bangla.
SQL: SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.languages  =  "bangla" GROUP BY T2.artist_name ORDER BY count(*) DESC LIMIT 3
Database: music_1
Question: What are the top 3 artists with the largest number of songs in the language Bangla?
SQL: SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.languages  =  "bangla" GROUP BY T2.artist_name ORDER BY count(*) DESC LIMIT 3