A method to increase yield strength in a metallic alloy comprising: a. supplying a metal alloy consisting of at least 70 atomic % iron and at least four elements selected from Si, Mn, Cr, Ni, Cu or C and inevitable impurities, melting said alloy, cooling at a rate of 10 -4 K/sec to 10 3 K/sec and solidifying to a thickness of >5.0 mm to 500 mm, wherein: when Si is present in said alloy, it is present in an amount ranging from greater than 0 to 6.13 atomic %; when Mn is present in said alloy, it is present in an amount ranging from greater than 0 to 15.17 atomic %; when Cr is present in said alloy, it is present in an amount ranging from greater than 0 to 8.64 atomic %; when Ni is present in said alloy, it is present in an amount ranging from greater than 0 to 9.94 atomic %; when Cu is present in said alloy, it is present in an amount ranging from greater than 0 to 1.86 atomic %; and when C is present in said alloy, it is present in an amount ranging from greater than 0 to 3.68 atomic %; b. processing said alloy into a first sheet with thickness from 0.5 to 5.0 mm with the first sheet having a total elongation of X 1 (%), an ultimate tensile strength of Y 1 (MPa), and a yield strength of Z 1 (MPa), wherein X 1 is from 10.0 to 70.0%, Y 1 is from 900 to 2050 MPa, and Z 1 is from 200 to 750 MPa; c. permanently deforming said first sheet at a temperature ranging from 150°C to 400°C by reducing the thickness of the first sheet to produce a second sheet with one of the following tensile property combinations A or B: A. total elongation X 2 =X 1 ± 7.5%; ultimate tensile strength Y 2 = Y 1 ± 100 MPa; and yield strength Z 2 > Z 1 + 100 MPa. B. ultimate tensile strength Y 3 = Y 1 ± 100 MPa; and yield strength Z 3 > Z 1 + 200 MPa. a. supplying a metal alloy consisting of at least 70 atomic % iron and at least four elements selected from Si, Mn, Cr, Ni, Cu or C and inevitable impurities, melting said alloy, cooling at a rate of 10 -4 K/sec to 10 3 K/sec and solidifying to a thickness of >5.0 mm to 500 mm, wherein: when Si is present in said alloy, it is present in an amount ranging from greater than 0 to 6.13 atomic %; when Mn is present in said alloy, it is present in an amount ranging from greater than 0 to 15.17 atomic %; when Cr is present in said alloy, it is present in an amount ranging from greater than 0 to 8.64 atomic %; when Ni is present in said alloy, it is present in an amount ranging from greater than 0 to 9.94 atomic %; when Cu is present in said alloy, it is present in an amount ranging from greater than 0 to 1.86 atomic %; and when C is present in said alloy, it is present in an amount ranging from greater than 0 to 3.68 atomic %; when Si is present in said alloy, it is present in an amount ranging from greater than 0 to 6.13 atomic %; when Mn is present in said alloy, it is present in an amount ranging from greater than 0 to 15.17 atomic %; when Cr is present in said alloy, it is present in an amount ranging from greater than 0 to 8.64 atomic %; when Ni is present in said alloy, it is present in an amount ranging from greater than 0 to 9.94 atomic %; when Cu is present in said alloy, it is present in an amount ranging from greater than 0 to 1.86 atomic %; and when C is present in said alloy, it is present in an amount ranging from greater than 0 to 3.68 atomic %; b. processing said alloy into a first sheet with thickness from 0.5 to 5.0 mm with the first sheet having a total elongation of X 1 (%), an ultimate tensile strength of Y 1 (MPa), and a yield strength of Z 1 (MPa), wherein X 1 is from 10.0 to 70.0%, Y 1 is from 900 to 2050 MPa, and Z 1 is from 200 to 750 MPa; c. permanently deforming said first sheet at a temperature ranging from 150°C to 400°C by reducing the thickness of the first sheet to produce a second sheet with one of the following tensile property combinations A or B: A. total elongation X 2 =X 1 ± 7.5%; ultimate tensile strength Y 2 = Y 1 ± 100 MPa; and yield strength Z 2 > Z 1 + 100 MPa. B. ultimate tensile strength Y 3 = Y 1 ± 100 MPa; and yield strength Z 3 > Z 1 + 200 MPa. A. total elongation X 2 =X 1 ± 7.5%; ultimate tensile strength Y 2 = Y 1 ± 100 MPa; and yield strength Z 2 > Z 1 + 100 MPa. total elongation X 2 =X 1 ± 7.5%; ultimate tensile strength Y 2 = Y 1 ± 100 MPa; and yield strength Z 2 > Z 1 + 100 MPa. B. ultimate tensile strength Y 3 = Y 1 ± 100 MPa; and yield strength Z 3 > Z 1 + 200 MPa. ultimate tensile strength Y 3 = Y 1 ± 100 MPa; and yield strength Z 3 > Z 1 + 200 MPa.