meetforever/GRPO_CL huggingface dataset:
user: Given an array of one's and zero's that represents a positive binary number convert the number to two's complement value.

Two's complement is the way most computers represent positive or negative integers. The most significant bit is negative. 

Examples:

-8 4 2 1 

[1,1,1,1] = -1

[1,0,0,0] = -8

[1,1,0,1] = -3

To get the two's complement negative notation of an integer, you take the number in binary. 

You then invert the digits, and add one to the result. 

For example:

[0,0,1,0] = 2 in base 10

[1,1,0,1] <- Flip the bits

   Add 1
   
[1,1,1,0] = -2

However, the arrays can have varying lengths, not just limited to 4.

Answer: {"fn_name": "positive_to_negative", "inputs": [[[0, 0, 0, 0]], [[0, 0, 1, 0]], [[0, 0, 1, 1]], [[0, 1, 0, 0]]], "outputs": [[[0, 0, 0, 0]], [[1, 1, 1, 0]], [[1, 1, 0, 1]], [[1, 1, 0, 0]]]}
user: Create a function that takes a Roman numeral as its argument and returns its value as a numeric decimal integer. You don't need to validate the form of the Roman numeral.

Modern Roman numerals are written by expressing each decimal digit of the number to be encoded separately, starting with the leftmost digit and skipping any 0s. So 1990 is rendered "MCMXC" (1000 = M, 900 = CM, 90 = XC) and 2008 is rendered "MMVIII" (2000 = MM, 8 = VIII). The Roman numeral for 1666, "MDCLXVI", uses each letter in descending order.

Example:

```python
solution('XXI') # should return 21
```

```Elixir
Solution.decode("XXI") # should return 21
```

Help:
```
Symbol  Value
I             1
V             5
X             10
L             50
C             100
D             500
M             1,000
```

*Courtesy of rosettacode.org*

Answer: {"fn_name": "solution", "inputs": [["XXI"], ["I"], ["IV"], ["MMVIII"], ["MDCLXVI"]], "outputs": [[21], [1], [4], [2008], [1666]]}
user: # Convergents of e
The square root of 2 can be written as an infinite continued fraction.
![img](http://img0.ph.126.net/x1Hyc4iHQg0Jz2EInmT3ag==/6597639313681841979.png)  
The infinite continued fraction can be written, √2 = [1;(2)], (2) indicates that 2 repeats ad infinitum. In a similar way, √23 = [4;(1,3,1,8)].

It turns out that the sequence of partial values of continued fractions for square roots provide the best rational approximations. Let us consider the convergents for √2.
![img](http://img1.ph.126.net/xme9gNBQdA7bvQkwIftznQ==/6597819633588793645.png)  
Hence the sequence of the first ten convergents for √2 are:

1, 3/2, 7/5, 17/12, 41/29, 99/70, 239/169, 577/408, 1393/985, 3363/2378, …

What is most surprising is that the important mathematical constant,
e = [2; 1,2,1, 1,4,1, 1,6,1 , … , 1,2k,1, …].

The first ten terms in the sequence of convergents for e are:

2, 3, 8/3, 11/4, 19/7, 87/32, 106/39, 193/71, 1264/465, 1457/536, …

The sum of digits in the numerator of the 10th convergent is 1+4+5+7=17.

Find the sum of digits in the numerator of the mth convergent of the continued fraction for e.


- Powered by [Project Euler](https://projecteuler.net/problem=65)

Answer: {"fn_name": "convergents_of_e", "inputs": [[57], [125], [298], [938], [3756], [18287], [2132], [9999], [788], [8787]], "outputs": [[125], [298], [938], [3756], [18287], [108346], [9469], [55534], [3151], [48461]]}
user: You get any card as an argument. Your task is to return a suit of this card.

Our deck (is preloaded):
```python
DECK = ['2S','3S','4S','5S','6S','7S','8S','9S','10S','JS','QS','KS','AS',
        '2D','3D','4D','5D','6D','7D','8D','9D','10D','JD','QD','KD','AD',
        '2H','3H','4H','5H','6H','7H','8H','9H','10H','JH','QH','KH','AH',
        '2C','3C','4C','5C','6C','7C','8C','9C','10C','JC','QC','KC','AC']
```

```python
('3C') -> return 'clubs'
('3D') -> return 'diamonds'
('3H') -> return 'hearts'
('3S') -> return 'spades'
```

Answer: {"fn_name": "define_suit", "inputs": [["3C"], ["QS"], ["9D"], ["JH"]], "outputs": [["clubs"], ["spades"], ["diamonds"], ["hearts"]]}
user: You are given a string of words (x), for each word within the string you need to turn the word 'inside out'. By this I mean the internal letters will move out, and the external letters move toward the centre. 

If the word is even length, all letters will move. If the length is odd, you are expected to leave the 'middle' letter of the word where it is. 

An example should clarify:

'taxi' would become 'atix'
'taxis' would become 'atxsi'

Answer: {"fn_name": "inside_out", "inputs": [["man i need a taxi up to ubud"], ["what time are we climbing up the volcano"], ["take me to semynak"], ["massage yes massage yes massage"], ["take bintang and a dance please"]], "outputs": [["man i ende a atix up to budu"], ["hwta item are we milcgnib up the lovcona"], ["atek me to mesykan"], ["samsega yes samsega yes samsega"], ["atek nibtgna and a adnec elpesa"]]}
user: Well met with Fibonacci bigger brother, AKA Tribonacci.

As the name may already reveal, it works basically like a Fibonacci, but summing the last 3 (instead of 2) numbers of the sequence to generate the next. And, worse part of it, regrettably I won't get to hear non-native Italian speakers trying to pronounce it :(

So, if we are to start our Tribonacci sequence with `[1, 1, 1]` as a starting input (AKA *signature*), we have this sequence:

```
[1, 1 ,1, 3, 5, 9, 17, 31, ...]
```

But what if we started with `[0, 0, 1]` as a signature? As starting with `[0, 1]` instead of `[1, 1]` basically *shifts* the common Fibonacci sequence by once place, you may be tempted to think that we would get the same sequence shifted by 2 places, but that is not the case and we would get:

```
[0, 0, 1, 1, 2, 4, 7, 13, 24, ...]
```

Well, you may have guessed it by now, but to be clear: you need to create a fibonacci function that given a **signature** array/list, returns **the first n elements - signature included** of the so seeded sequence.

Signature will always contain 3 numbers; n will always be a non-negative number; if `n == 0`, then return an empty array (except in C return NULL) and be ready for anything else which is not clearly specified ;)

If you enjoyed this kata more advanced and generalized version of it can be found in the Xbonacci kata

*[Personal thanks to Professor Jim Fowler on Coursera for his awesome classes that I really recommend to any math enthusiast and for showing me this mathematical curiosity too with his usual contagious passion :)]*

Answer: {"fn_name": "tribonacci", "inputs": [[[1, 1, 1], 10], [[0, 0, 1], 10], [[0, 1, 1], 10], [[1, 0, 0], 10], [[0, 0, 0], 10], [[1, 2, 3], 10], [[3, 2, 1], 10], [[1, 1, 1], 1], [[300, 200, 100], 0], [[0.5, 0.5, 0.5], 30]], "outputs": [[[1, 1, 1, 3, 5, 9, 17, 31, 57, 105]], [[0, 0, 1, 1, 2, 4, 7, 13, 24, 44]], [[0, 1, 1, 2, 4, 7, 13, 24, 44, 81]], [[1, 0, 0, 1, 1, 2, 4, 7, 13, 24]], [[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]], [[1, 2, 3, 6, 11, 20, 37, 68, 125, 230]], [[3, 2, 1, 6, 9, 16, 31, 56, 103, 190]], [[1]], [[]], [[0.5, 0.5, 0.5, 1.5, 2.5, 4.5, 8.5, 15.5, 28.5, 52.5, 96.5, 177.5, 326.5, 600.5, 1104.5, 2031.5, 3736.5, 6872.5, 12640.5, 23249.5, 42762.5, 78652.5, 144664.5, 266079.5, 489396.5, 900140.5, 1655616.5, 3045153.5, 5600910.5, 10301680.5]]]}
user: When you want to get the square of a binomial of two variables x and y, you will have:

`$(x+y)^2 = x^2 + 2xy + y ^2$`

And the cube:

`$(x+y)^3 = x^3 + 3x^2y + 3xy^2 +y^3$`

It is known from many centuries ago that for an exponent n, the result of a binomial x + y raised to the n-th power is:

Or using the sumation notation:

Each coefficient of a term has the following value:

Each coefficient value coincides with the amount of combinations without replacements of a set of n elements using only k different ones of that set.

Let's see the total sum of the coefficients of the different powers for the binomial:

`$(x+y)^0(1)$`

`$(x+y)^1 = x+y(2)$`

`$(x+y)^2 = x^2 + 2xy + y ^2(4)$`

`$(x+y)^3 = x^3 + 3x^2y + 3xy^2 +y^3(8)$`

We need a function that may generate an array with the values of all the coefficients sums from 0 to the value of n included and has the addition of all the sum values as last element.

We add some examples below:
``` 
f(0) = [1, 1]
f(1) = [1, 2, 3]
f(2) = [1, 2, 4, 7]
f(3) = [1, 2, 4, 8, 15]
``` 

Features of the test
``` 
Low Performance Tests
Number of tests = 50
9 < n < 101

High Performance Tests
Number of Tests = 50
99 < n < 5001
```

Answer: {"fn_name": "f", "inputs": [[0], [1], [2], [3], [6], [10]], "outputs": [[[1, 1]], [[1, 2, 3]], [[1, 2, 4, 7]], [[1, 2, 4, 8, 15]], [[1, 2, 4, 8, 16, 32, 64, 127]], [[1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2047]]]}
user: Share price
===========

You spent all your saved money to buy some shares.

You bought it for `invested`, and want to know how much it's worth, but all the info you can quickly get are just the change the shares price made in percentages.

Your task:
----------
Write the function `sharePrice()` that calculates, and returns the current price of your share, given the following two arguments:

- `invested`(number), the amount of money you initially invested in the given share

- `changes`(array of numbers), contains your shares daily movement percentages

The returned number, should be in string format, and it's precision should be fixed at 2 decimal numbers.

Have fun!

>**Hint:** Try to write the function in a functional manner!

Answer: {"fn_name": "share_price", "inputs": [[100, []], [100, [-50, 50]], [100, [-50, 100]], [100, [-20, 30]], [1000, [0, 2, 3, 6]]], "outputs": [["100.00"], ["75.00"], ["100.00"], ["104.00"], ["1113.64"]]}
user: Create an identity matrix of the specified size( >= 0).

Some examples:

```
(1)  =>  [[1]]

(2) => [ [1,0],
         [0,1] ]

       [ [1,0,0,0,0],
         [0,1,0,0,0],
(5) =>   [0,0,1,0,0],
         [0,0,0,1,0],
         [0,0,0,0,1] ]   

```

Answer: {"fn_name": "get_matrix", "inputs": [[0], [1], [2], [3], [5]], "outputs": [[[]], [[[1]]], [[[1, 0], [0, 1]]], [[[1, 0, 0], [0, 1, 0], [0, 0, 1]]], [[[1, 0, 0, 0, 0], [0, 1, 0, 0, 0], [0, 0, 1, 0, 0], [0, 0, 0, 1, 0], [0, 0, 0, 0, 1]]]]}
user: In your class, you have started lessons about geometric progression.
Since you are also a programmer, you have decided to write a function that will print first `n` elements of the sequence with the given constant `r` and first element `a`.

Result should be separated by comma and space.

### Example

```python
geometric_sequence_elements(2, 3, 5) == '2, 6, 18, 54, 162'
```

More info: https://en.wikipedia.org/wiki/Geometric_progression

Answer: {"fn_name": "geometric_sequence_elements", "inputs": [[2, 3, 5], [2, 2, 10], [1, -2, 10]], "outputs": [["2, 6, 18, 54, 162"], ["2, 4, 8, 16, 32, 64, 128, 256, 512, 1024"], ["1, -2, 4, -8, 16, -32, 64, -128, 256, -512"]]}
user: Create a function that accepts 3 inputs, a string, a starting location, and a length.  The function needs to simulate the string endlessly repeating in both directions and return a substring beginning at the starting location and continues for length.

Example:
```python
endless_string('xyz', -23, 6) == 'yzxyzx'
```
To visualize:

           Negative                               Positive
    3         2         1         *         1         2         3      
    0987654321098765432109876543210123456789012345678901234567890
    xyzxyzxyzxyzxyzxyzxyzxyzxyzxyzxyzxyzxyzxyzxyzxyzxyzxyzxyzxyzx
           ******
         -23 for a length of 6 == 'yzxyzx'
       
Some more examples:
```python
endless_string('xyz', 0, 4) == 'xyzx'
endless_string('xyz', 19, 2) == 'yz'
endless_string('xyz', -4, -4) == 'zxyz'
```

A negative length needs to include the starting postion and return the characters to the left of the starting position.

Answer: {"fn_name": "endless_string", "inputs": [["xyz", -23, 6], ["xyz", 0, 4], ["xyz", 19, 2], ["xyz", -4, -4], ["abcdefghijklmnopqrstuvwxyz", 29, 1], ["Hello! How are you?", -14, 27], ["1x2x3x4x", 1532, 100], ["1x2x3x4x", -1532, -100], ["112233", 0, 0], ["112233", -1, 0], ["112233", 15824, 0]], "outputs": [["yzxyzx"], ["xyzx"], ["yz"], ["zxyz"], ["d"], ["! How are you?Hello! How ar"], ["3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x"], ["x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3x4x1x2x3"], [""], [""], [""]]}
user: A *Vampire number* is a positive integer `z` with a factorization `x * y = z` such that

- `x` and `y` have the same number of digits and
- the multiset of digits of `z` is equal to the multiset of digits of `x` and `y`.
- Additionally, to avoid trivialities, `x` and `y` may not both end with `0`.

In this case, `x` and `y` are called *fangs* of `z`. (The fangs of a Vampire number may not be unique, but this shouldn't bother us.) The first three Vampire numbers are

```
1260 = 21*60
1395 = 15*93
1435 = 35*41
```

Write an algorithm that on input `k` returns the `k`th Vampire number. To avoid time-outs, the Python version will test with `1 <= k <= 155`.

PS: In the OEIS, the Vampire numbers are sequence [A014575](https://oeis.org/A014575).

PPS: So called *Pseudo-Vampire Numbers* are treated in [this kata](http://www.codewars.com/kata/vampire-numbers-1).

Answer: {"fn_name": "VampireNumber", "inputs": [[10], [100], [155]], "outputs": [[105210], [336960], [939658]]}
user: Your task is to validate rhythm with a meter.

_________________________________________________
Rules:

1. Rhythmic division requires that in one whole note (1) there are two half notes (2) or four quarter notes (4) or eight eighth notes (8). 
Examples: 1 = 2 + 2, 1 = 4 + 4 + 4 + 4 ... 
Note that: 2 = 4 + 4, 4 = 8 + 8, 2 = 8 + 8 + 4 ... 

2. Meter gives an information how many rhythmic types of notes should be in one bar. Bar is the the primary section of a musical score.
Examples: 
          4/4 -> 4 quarter notes in a bar
          5/2 -> 5 half notes in a bar
          3/8 -> 3 eighth notes in a bar
Note that: 
for 4/4 valid bars are: '4444', '88888888', '2488' ...
for 5/2 valid bars are: '22222', '2244244', '8888244888844' ...
for 3/8 valid bars are: '888', '48' ...

3. Anacrusis occurs when all bars but the first and last are valid, and the notes in the first and last bars when combined would also make a valid bar.

Examples: 
for 4/4 valid anacrusis is -> 44|...|44 or 88|...|888888 or 2|...|488 
for 5/2 valid anacrusis is -> 22|...|222 or 222|...|22 or  2244|...|244
for 3/8 valid anacrusis is -> 8|...|88 or 4|...|8 or 8|...|4
Note:
When anacrusis is valid but other bars in score are not -> return 'Invalid rhythm'
________________________________________________

Input:
meter - array: eg. [4, 4],
score - string, bars separated with '|': eg. '4444|8484842|888'

Output:
string message: 'Valid rhythm', 'Valid rhythm with anacrusis' or 'Invalid rhythm'

Answer: {"fn_name": "validate_rhythm", "inputs": [[[8, 8], "1|22|4444|88888888"], [[4, 4], "1|22|4444|88888888"], [[2, 2], "1|22|4444|88888888"], [[1, 1], "1|22|4444|88888888"], [[3, 4], "24|444|888888"], [[4, 8], "2|44|8888"], [[2, 4], "2|44|8888"], [[1, 2], "2|44|8888"], [[10, 8], "14|444488|888824"], [[6, 4], "222|444444|884884884"], [[3, 2], "222|442884|88882488"], [[1, 1], "1"], [[1, 2], "2"], [[1, 4], "4"], [[1, 8], "8"], [[2, 4], "4|44|2|88"], [[5, 8], "888|448|82|88"], [[7, 2], "222|1112|2222222|2222"], [[2, 4], "4|4444|88"], [[1, 1], "2|11|228|2"], [[5, 8], "888|448|882|88"], [[3, 8], "|888|884|888"], [[3, 8], "888|884|888|"], [[3, 8], "|884|888|"], [[7, 2], "222|111|2222222|1112|2222"], [[1, 2], "2|44|22"], [[9, 8], "444448|2288"], [[7, 3], "222|111|2222222|1112|2222"], [[1, 3], "2|44|22"], [[9, 9], "1|22|4444|88888888"], [[6, 6], "1|22|4444|88888888"], [[1, 3], "3|3|3|3|3"], [[2, 7], "77|77|77|77"], [[2, 6], "66|66|66|66|66"]], "outputs": [["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm"], ["Valid rhythm with anacrusis"], ["Valid rhythm with anacrusis"], ["Valid rhythm with anacrusis"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"], ["Invalid rhythm"]]}
user: Complete the function/method so that it takes CamelCase string and returns the string in snake_case notation. Lowercase characters can be numbers. If method gets number, it should return string.

Examples:

``` javascript
//  returns test_controller
toUnderscore('TestController');

// returns movies_and_books
toUnderscore('MoviesAndBooks');

// returns app7_test
toUnderscore('App7Test');

// returns "1"
toUnderscore(1);
```

``` coffeescript  
#  returns test_controller
toUnderscore 'TestController'

# returns movies_and_books
toUnderscore 'MoviesAndBooks'

# returns app7_test
toUnderscore 'App7Test'

# returns "1"
toUnderscore 1
```

Answer: {"fn_name": "to_underscore", "inputs": [["TestController"], ["ThisIsBeautifulDay"], ["Am7Days"], ["My3CodeIs4TimesBetter"], [5]], "outputs": [["test_controller"], ["this_is_beautiful_day"], ["am7_days"], ["my3_code_is4_times_better"], ["5"]]}
user: Write a function that will check whether the permutation of an input string is a palindrome. Bonus points for a solution that is efficient and/or that uses _only_ built-in language functions. Deem yourself **brilliant** if you can come up with a version that does not use _any_ function whatsoever.

# Example 

  `madam` -> True   
  `adamm` -> True   
  `junk`  -> False  
  
## Hint 
The brute force approach would be to generate _all_ the permutations of the string and check each one of them whether it is a palindrome. However, an optimized approach will not require this at all.

Answer: {"fn_name": "permute_a_palindrome", "inputs": [["a"], ["aa"], ["baa"], ["aab"], ["baabcd"], ["racecars"], ["abcdefghba"], [""]], "outputs": [[true], [true], [true], [true], [false], [false], [false], [true]]}
user: Consider the following series:

`0,1,2,3,4,5,6,7,8,9,10,22,11,20,13,24...`There is nothing special between numbers `0` and `10`. 

Let's start with the number `10` and derive the sequence. `10` has digits `1` and `0`. The next possible number that does not have a `1` or a `0` is `22`. All other numbers between `10` and `22` have a `1` or a `0`. 

From `22`, the next number that does not have a `2` is `11`. Note that `30` is also a possibility because it is the next *higher* number that does not have a `2`, but we must select  the *lowest* number that fits and **is not already in the sequence**. 

From `11`, the next lowest number that does not have a `1` is `20`. 

From `20`, the next lowest number that does not have a `2` or a `0` is `13`, then `24` , then `15` and so on. 

Once a number appers in the series, it cannot appear again. 

You will be given an index number and your task will be return the element at that position. See test cases for more examples.

Note that the test range is `n <= 500`. 

Good luck!

If you like this Kata, please try:

[Sequence convergence](https://www.codewars.com/kata/59971e64bfccc70748000068)

[https://www.codewars.com/kata/unique-digit-sequence-ii-optimization-problem](https://www.codewars.com/kata/unique-digit-sequence-ii-optimization-problem)

Answer: {"fn_name": "find_num", "inputs": [[1], [5], [11], [100], [500]], "outputs": [[1], [5], [22], [103], [476]]}
user: You will be given an array of numbers.

For each number in the array you will need to create an object. 

The object key will be the number, as a string. The value will be the corresponding character code, as a string.

Return an array of the resulting objects.

All inputs will be arrays of numbers. All character codes are valid lower case letters. The input array will not be empty.

Answer: {"fn_name": "num_obj", "inputs": [[[118, 117, 120]], [[101, 121, 110, 113, 113, 103]], [[118, 103, 110, 109, 104, 106]], [[107, 99, 110, 107, 118, 106, 112, 102]], [[100, 100, 116, 105, 117, 121]]], "outputs": [[[{"118": "v"}, {"117": "u"}, {"120": "x"}]], [[{"101": "e"}, {"121": "y"}, {"110": "n"}, {"113": "q"}, {"113": "q"}, {"103": "g"}]], [[{"118": "v"}, {"103": "g"}, {"110": "n"}, {"109": "m"}, {"104": "h"}, {"106": "j"}]], [[{"107": "k"}, {"99": "c"}, {"110": "n"}, {"107": "k"}, {"118": "v"}, {"106": "j"}, {"112": "p"}, {"102": "f"}]], [[{"100": "d"}, {"100": "d"}, {"116": "t"}, {"105": "i"}, {"117": "u"}, {"121": "y"}]]]}
user: In this Kata you must convert integers numbers from and to a negative-base binary system.

Negative-base systems can accommodate all the same numbers as standard place-value systems, but both positive and negative numbers are represented without the use of a minus sign (or, in computer representation, a sign bit); this advantage is countered by an increased complexity of arithmetic operations.

To help understand, the first eight digits (in decimal) of the Base(-2) system is: 

`[1, -2, 4, -8, 16, -32, 64, -128]`


Example conversions:

`Decimal, negabinary`
```
6,   '11010'
-6,  '1110'
4,   '100'
18,  '10110'
-11, '110101'
```

Answer: {"fn_name": "int_to_negabinary", "inputs": [[0], [6], [-6], [45], [-45], [4587], [-4587], [65535], [65536], [-65536], [2147483648], [-2147483648]], "outputs": [["0"], ["11010"], ["1110"], ["1111101"], ["11010111"], ["1011000111111"], ["11001000010101"], ["10000000000000011"], ["10000000000000000"], ["110000000000000000"], ["110000000000000000000000000000000"], ["10000000000000000000000000000000"]]}
user: Your task is to find the number couple with the greatest difference from a given array of number-couples. 

All number couples will be given as strings and all numbers in them will be positive integers.  

For instance: ['56-23','1-100']; in this case, you should identify '1-100' as the number couple with the greatest difference and return it.

In case there are more than one option, for instance ['1-3','5-7','2-3'], you should identify whichever is first, so in this case '1-3'. 

If there is no difference, like so ['11-11', '344-344'], return false.

Answer: {"fn_name": "diff", "inputs": [[["43-45", "1021-55", "000-18888", "92-34", "76-32", "99-1", "1020-54"]], [["1-2", "2-4", "5-7", "8-9", "44-45"]], [["1-1000", "2-1000", "100-67", "98-45", "8-9"]], [["33-33", "77-77"]], [["23-67", "67-23", "88-88", "45-46"]], [["45896-2354", "4654-556767", "2455-423522", "3455-355", "34-34", "2524522-0"]], [["1-1", "2-2", "1-0", "77-77"]], [["0-0"]], [[]]], "outputs": [["000-18888"], ["2-4"], ["1-1000"], [false], ["23-67"], ["2524522-0"], ["1-0"], [false], [false]]}
user: Make a program that takes a value (x) and returns "Bang" if the number is divisible by 3, "Boom" if it is divisible by 5, "BangBoom" if it divisible by 3 and 5, and "Miss" if it isn't divisible by any of them.
Note: Your program should only return one value

Ex: Input: 105 --> Output: "BangBoom"
Ex: Input: 9 --> Output: "Bang"
Ex:Input: 25 --> Output: "Boom"

Answer: {"fn_name": "multiple", "inputs": [[30], [3], [98], [65], [23], [15], [4], [2], [45], [90], [21], [7], [6], [10003823], [41535], [712], [985], [164523]], "outputs": [["BangBoom"], ["Bang"], ["Miss"], ["Boom"], ["Miss"], ["BangBoom"], ["Miss"], ["Miss"], ["BangBoom"], ["BangBoom"], ["Bang"], ["Miss"], ["Bang"], ["Miss"], ["BangBoom"], ["Miss"], ["Boom"], ["Bang"]]}