meetforever/GRPO_CL huggingface dataset:
user: Colour plays an important role in our lifes. Most of us like this colour better then another. User experience specialists believe that certain colours have certain psychological meanings for us.

You are given a 2D array, composed of a colour and its 'common' association in each array element. The function you will write needs to return the colour as 'key' and association as its 'value'.

For example:
```python
var array = [["white", "goodness"], ...] returns [{'white': 'goodness'}, ...]
```

Answer: {"fn_name": "colour_association", "inputs": [[[["white", "goodness"], ["blue", "tranquility"]]], [[["red", "energy"], ["yellow", "creativity"], ["brown", "friendly"], ["green", "growth"]]], [[["pink", "compassion"], ["purple", "ambition"]]], [[["gray", "intelligence"], ["black", "classy"]]], [[["white", "goodness"], ["blue", "goodness"]]]], "outputs": [[[{"white": "goodness"}, {"blue": "tranquility"}]], [[{"red": "energy"}, {"yellow": "creativity"}, {"brown": "friendly"}, {"green": "growth"}]], [[{"pink": "compassion"}, {"purple": "ambition"}]], [[{"gray": "intelligence"}, {"black": "classy"}]], [[{"white": "goodness"}, {"blue": "goodness"}]]]}
user: This is a problem that involves adding numbers to items in a list.
In a list you will have to add the item's remainder when divided by a given divisor to each item.

For example if the item is 40 and the divisor is 3 you would have to add 1 since 40 minus the closest multiple of 3 which is 39 is 1. So the 40 in the list will become 41. You would have to return the modified list in this problem.

For this problem you will receive a divisor called `div` as well as simple list of whole numbers called `nums`. Good luck and happy coding.

# Examples
```python
nums = [2, 7, 5, 9, 100, 34, 32, 0], div = 3
  ==>  [4, 8, 7, 9, 101, 35, 34, 0] 

nums = [1000, 999, 998, 997], div = 5
   ==> [1000, 1003, 1001, 999]

nums = [], div = 2
   ==> []
```

**Note:** random tests check lists containing up to 10000 elements.

Answer: {"fn_name": "solve", "inputs": [[[2, 7, 5, 9, 100, 34, 32, 0], 3], [[], 2], [[1000, 999, 998, 997], 5], [[0, 0, 0, 0], 5], [[4, 3, 2, 1], 5], [[33, 23, 45, 78, 65], 10]], "outputs": [[[4, 8, 7, 9, 101, 35, 34, 0]], [[]], [[1000, 1003, 1001, 999]], [[0, 0, 0, 0]], [[8, 6, 4, 2]], [[36, 26, 50, 86, 70]]]}
user: Given a lowercase string that has alphabetic characters only and no spaces, return the highest value of consonant substrings. Consonants are any letters of the alphabet except `"aeiou"`. 

We shall assign the following values: `a = 1, b = 2, c = 3, .... z = 26`.

For example, for the word "zodiacs", let's cross out the vowels. We get: "z **~~o~~** d **~~ia~~** cs"

For C: do not mutate input.

More examples in test cases. Good luck!

If you like this Kata, please try:

[Word values](https://www.codewars.com/kata/598d91785d4ce3ec4f000018)

[Vowel-consonant lexicon](https://www.codewars.com/kata/59cf8bed1a68b75ffb000026)

Answer: {"fn_name": "solve", "inputs": [["zodiac"], ["chruschtschov"], ["khrushchev"], ["strength"], ["catchphrase"], ["twelfthstreet"], ["mischtschenkoana"]], "outputs": [[26], [80], [38], [57], [73], [103], [80]]}
user: Implement the function which should return `true` if given object is a vowel (meaning `a, e, i, o, u`), and `false` otherwise.

Answer: {"fn_name": "is_vowel", "inputs": [[""], ["a"], ["E"], ["ou"], ["z"], ["lol"]], "outputs": [[false], [true], [true], [false], [false], [false]]}
user: A high school has a strange principal. On the first day, he has his students perform an odd opening day ceremony:

There are number of lockers "n" and number of students "n" in the school. The principal asks the first student to go to every locker and open it. Then he has the second student go to every second locker and close it. The third goes to every third locker and, if it is closed, he opens it, and if it is open, he closes it. The fourth student does this to every fourth locker, and so on. After the process is completed with the "n"th student, how many lockers are open?

The task is to write a function which gets any number as an input and returns the number of open lockers after last sudent complets his activity. So input of the function is just one number which shows number of lockers and number of students. For example if there are 1000 lockers and 1000 students in school then input is 1000 and function returns number of open lockers after 1000th student completes his action.

The given input is always an integer greater than or equal to zero that is why there is no need for validation.

Answer: {"fn_name": "num_of_open_lockers", "inputs": [[0], [1], [4], [56], [128], [500], [562], [74864], [3991700], [950811894]], "outputs": [[0], [1], [2], [7], [11], [22], [23], [273], [1997], [30835]]}
user: Complete the function that takes two integers (`a, b`, where `a < b`) and return an array of all integers between the input parameters, **including** them.

For example:
```
a = 1
b = 4
--> [1, 2, 3, 4]
```

Answer: {"fn_name": "between", "inputs": [[1, 4], [-2, 2], [-10, 10], [5, 100]], "outputs": [[[1, 2, 3, 4]], [[-2, -1, 0, 1, 2]], [[-10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]], [[5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100]]]}
user: ###Task:

You have to write a function **pattern** which creates the following Pattern(See Examples) upto n(parameter) number of rows.

####Rules/Note:
* If the Argument is 0 or a Negative Integer then it should return "" i.e. empty string.
* All the lines in the pattern have same length i.e equal to the number of characters in the last line.
* Range of n is (-∞,100]

###Examples:

pattern(5):

        1    
       121   
      12321  
     1234321 
    123454321


pattern(10):

             1         
            121        
           12321       
          1234321      
         123454321     
        12345654321    
       1234567654321   
      123456787654321  
     12345678987654321 
    1234567890987654321

pattern(15):

                  1              
                 121             
                12321            
               1234321           
              123454321          
             12345654321         
            1234567654321        
           123456787654321       
          12345678987654321      
         1234567890987654321     
        123456789010987654321    
       12345678901210987654321   
      1234567890123210987654321  
     123456789012343210987654321 
    12345678901234543210987654321

pattern(20):

                       1                   
                      121                  
                     12321                 
                    1234321                
                   123454321               
                  12345654321              
                 1234567654321             
                123456787654321            
               12345678987654321           
              1234567890987654321          
             123456789010987654321         
            12345678901210987654321        
           1234567890123210987654321       
          123456789012343210987654321      
         12345678901234543210987654321     
        1234567890123456543210987654321    
       123456789012345676543210987654321   
      12345678901234567876543210987654321  
     1234567890123456789876543210987654321 
    123456789012345678909876543210987654321

###Amazing Fact: 


```Hint: Use \n in string to jump to next line```

Answer: {"fn_name": "pattern", "inputs": [[7], [1], [4], [0], [-25]], "outputs": [["      1      \n     121     \n    12321    \n   1234321   \n  123454321  \n 12345654321 \n1234567654321"], ["1"], ["   1   \n  121  \n 12321 \n1234321"], [""], [""]]}
user: Create a function

```python
has_two_cube_sums(n)
```

which checks if a given number `n` can be written as the sum of two cubes in two different ways: `n = a³+b³ = c³+d³`.
All the numbers `a`, `b`, `c` and `d` should be different and greater than `0`.

E.g. 1729 = 9³+10³ = 1³+12³.

```python
has_two_cube_sums(1729); // true
has_two_cube_sums(42);   // false
```

Answer: {"fn_name": "has_two_cube_sums", "inputs": [[1], [1729], [42], [4103], [4102], [4104], [4105], [4106], [0], [46163]], "outputs": [[false], [true], [false], [false], [false], [true], [false], [false], [false], [false]]}
user: In this Kata, you will be given an array of numbers in which two numbers occur once and the rest occur only twice. Your task will be to return the sum of the numbers that occur only once. 

For example, `repeats([4,5,7,5,4,8]) = 15` because only the numbers `7` and `8` occur once, and their sum is `15`.

More examples in the test cases. 


```if:csharp
Documentation:
Kata.Repeats Method (List<Int32>)

Takes a list where all ints are repeated twice, except two ints, and returns the sum of the ints of a list where those ints only occur once.

Syntax


public
static
int Repeats(
List<int> source
    )
  



Parameters

source

Type: System.Collections.Generic.List<Int32>
The list to process.

Return Value

Type: System.Int32
  The sum of the elements of the list where those elements have no duplicates.

```


Good luck!

If you like this Kata, please try: 

[Sum of prime-indexed elements](https://www.codewars.com/kata/59f38b033640ce9fc700015b)

[Sum of integer combinations](https://www.codewars.com/kata/59f3178e3640cef6d90000d5)

Answer: {"fn_name": "repeats", "inputs": [[[4, 5, 7, 5, 4, 8]], [[9, 10, 19, 13, 19, 13]], [[16, 0, 11, 4, 8, 16, 0, 11]], [[5, 17, 18, 11, 13, 18, 11, 13]], [[5, 10, 19, 13, 10, 13]]], "outputs": [[15], [19], [12], [22], [24]]}
user: This kata is all about adding numbers.

You will create a function named add. It will return the sum of all the arguments. Sounds easy, doesn't it?

Well Here's the Twist. The inputs will gradually decrease with their index as parameter to the function.

```python
  add(3,4,6) #returns (3/1)+(4/2)+(6/3)=7
```

Remember the function will return 0 if no arguments are passed and it must round the result if sum is a float.

Example
```python
  add() #=> 0
  add(1,2,3) #=> 3
  add(1,4,-6,20) #=> 6
```

Check my another kata here!! http://www.codewars.com/kata/555b73a81a6285b6ce000047

Answer: {"fn_name": "add", "inputs": [[100, 200, 300], [2], [4, -3, -2], [-1, -2, -3, -4]], "outputs": [[300], [2], [2], [-4]]}
user: Have you heard about the myth that [if you fold a paper enough times, you can reach the moon with it](http://scienceblogs.com/startswithabang/2009/08/31/paper-folding-to-the-moon/)? Sure you have, but exactly how many? Maybe it's time to write a program to figure it out.

You know that a piece of paper has a thickness of `0.0001m`. Given `distance` in units of meters, calculate how many times you have to fold the paper to make the paper reach this distance.  
(If you're not familiar with the concept of folding a paper: Each fold doubles its total thickness.)

Note: Of course you can't do half a fold. You should know what this means ;P

Also, if somebody is giving you a negative distance, it's clearly bogus and you should yell at them by returning `null` (or whatever equivalent in your language. In Shell please return `None`).

Answer: {"fn_name": "fold_to", "inputs": [[384000000], [5e-05], [1e-07], [0], [-1]], "outputs": [[42], [0], [0], [0], [null]]}
user: __Definition:__ According to Wikipedia, a [complete binary tree](https://en.wikipedia.org/wiki/Binary_tree#Types_of_binary_trees) is a binary tree _"where every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as possible."_

The Wikipedia page referenced above also mentions that _"Binary trees can also be stored in breadth-first order as an implicit data structure in arrays, and if the tree is a complete binary tree, this method wastes no space."_

Your task is to write a method (or function) that takes an array (or list, depending on language) of integers and, assuming that the array is ordered according to an _in-order_ traversal of a complete binary tree, returns an array that contains the values of the tree in breadth-first order.

__Example 1:__
Let the input array be `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`. This array contains the values of the following complete binary tree. 


```
          _ 7_
        /      \
       4        9
     /   \     / \
   2      6   8   10
  / \     /
 1   3   5
```
In this example, the input array happens to be sorted, but that is _not_ a requirement.

__Output 1:__ The output of the function shall be an array containing the values of the nodes of the binary tree read top-to-bottom, left-to-right. In this example, the returned array should be:

```[7, 4, 9, 2, 6, 8, 10, 1, 3, 5]```


__Example 2:__
Let the input array be `[1, 2, 2, 6, 7, 5]`. This array contains the values of the following complete binary tree. 


```
        6
      /   \
    2       5
   / \     /
  1   2   7
 
```
Note that an in-order traversal of this tree produces the input array.

__Output 2:__ The output of the function shall be an array containing the values of the nodes of the binary tree read top-to-bottom, left-to-right. In this example, the returned array should be:

```[6, 2, 5, 1, 2, 7]```

Answer: {"fn_name": "complete_binary_tree", "inputs": [[[1]], [[1, 2, 3, 4, 5, 6]], [[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]]], "outputs": [[[1]], [[4, 2, 6, 1, 3, 5]], [[7, 4, 9, 2, 6, 8, 10, 1, 3, 5]]]}
user: John has some amount of money of which he wants to deposit a part `f0` to the bank at the beginning
of year `1`. He wants to withdraw each year for his living an amount `c0`.

Here is his banker plan:

- deposit `f0` at beginning of year 1
- his bank account has an interest rate of `p` percent per year, constant over the years
- John can withdraw each year `c0`, taking it whenever he wants in the year; he must take account of an inflation of `i` percent per year in order to keep his quality of living. `i` is supposed to stay constant over the years.
- all amounts f0..fn-1, c0..cn-1 are truncated by the bank to their integral part
- Given f0, `p`, c0, `i` 
the banker guarantees that John will be able to go on that way until the `nth` year.

# Example:

```
f0 = 100000, p = 1 percent, c0 = 2000, n = 15, i = 1 percent
```

```
beginning of year 2 -> f1 = 100000 + 0.01*100000 - 2000 = 99000;  c1 = c0 + c0*0.01 = 2020 (with inflation of previous year)
```

```
beginning of year 3 -> f2 =  99000 + 0.01*99000 - 2020  = 97970;  c2 = c1 + c1*0.01 = 2040.20 
(with inflation of previous year, truncated to 2040)
```

```
beginning of year 4 -> f3 =  97970 + 0.01*97970 - 2040  = 96909.7 (truncated to 96909); 
c3 = c2 + c2*0.01 = 2060.4 (with inflation of previous year, truncated to 2060)
```
and so on...

John wants to know if the banker's plan is right or wrong.
Given parameters `f0, p, c0, n, i` build a function `fortune` which returns `true` if John can make a living until the `nth` year
and `false` if it is not possible.

# Some cases:
```
fortune(100000, 1, 2000, 15, 1) -> True
fortune(100000, 1, 10000, 10, 1) -> True
fortune(100000, 1, 9185, 12, 1) -> False

For the last case you can find below the amounts of his account at the beginning of each year:
100000, 91815, 83457, 74923, 66211, 57318, 48241, 38977, 29523, 19877, 10035, -5
```
f11 = -5 so he has no way to withdraw something for his living in year 12.

> **Note:** Don't forget to convert the percent parameters as percentages in the body of your function: if a parameter percent is 2 you have to convert it to 0.02.

Answer: {"fn_name": "fortune", "inputs": [[100000, 1, 2000, 15, 1], [100000, 1, 9185, 12, 1], [100000000, 1, 100000, 50, 1], [100000000, 1.5, 10000000, 50, 1], [100000000, 5, 1000000, 50, 1], [9999, 61.8161, 10000.0, 3, 0], [9998.5, 61.8155, 10000.0, 3, 0], [10000.0, 0, 10000.0, 2, 0], [999.5, 61.87, 1000.0, 3, 0]], "outputs": [[true], [false], [true], [false], [true], [false], [false], [true], [false]]}
user: **This Kata is intended as a small challenge for my students**

All Star Code Challenge #29

Your friend Nhoj has dislexia, but can easily read messages if the words are written backwards.  
Create a function called `reverseSentence()/reverse_sentence()` that accepts a string argument. The function returns a string of the same length with each word reversed, but still in their original order.

```python
reverse_sentence("Hello !Nhoj Want to have lunch?") # "olleH johN! tnaW ot evah ?hcnul"
```
Note:  
A "word" should be considered a string split by a space character, " "
Letter capitalization should be maintained.

Answer: {"fn_name": "reverse_sentence", "inputs": [["Hello !Nhoj Want to have lunch?"], ["1 2 3 4 5"], ["CodeWars"], ["CodeWars rules!"], [""]], "outputs": [["olleH johN! tnaW ot evah ?hcnul"], ["1 2 3 4 5"], ["sraWedoC"], ["sraWedoC !selur"], [""]]}
user: # Task
 Round the given number `n` to the nearest multiple of `m`.

 If `n` is exactly in the middle of 2 multiples of m, return `n` instead.

# Example

 For `n = 20, m = 3`, the output should be `21`.

 For `n = 19, m = 3`, the output should be `18`.

 For `n = 50, m = 100`, the output should be `50`.

# Input/Output


 - `[input]` integer `n`

 `1 ≤ n < 10^9.`


 - `[input]` integer `m`

 `3 ≤ m < 109`.


 - `[output]` an integer

Answer: {"fn_name": "rounding", "inputs": [[20, 3], [19, 3], [1, 10], [50, 100], [123, 456]], "outputs": [[21], [18], [0], [50], [0]]}
user: For an integer ```k``` rearrange all the elements of the given array in such way, that:

all elements that are less than ```k``` are placed before elements that are not less than ```k```;
all elements that are less than ```k``` remain in the same order with respect to each other;
all elements that are not less than ```k``` remain in the same order with respect to each other.

For ```k = 6``` and ```elements = [6, 4, 10, 10, 6]```, the output should be
```splitByValue(k, elements) = [4, 6, 10, 10, 6]```.

For ```k``` = 5 and ```elements = [1, 3, 5, 7, 6, 4, 2]```, the output should be
```splitByValue(k, elements) = [1, 3, 4, 2, 5, 7, 6]```.

S: codefights.com

Answer: {"fn_name": "split_by_value", "inputs": [[5, [1, 3, 5, 7, 6, 4, 2]], [0, [5, 2, 7, 3, 2]], [6, [6, 4, 10, 10, 6]], [1, [3, 2, 8, 3, 2, 1]], [10, [9, 2, 4, 3, 4]]], "outputs": [[[1, 3, 4, 2, 5, 7, 6]], [[5, 2, 7, 3, 2]], [[4, 6, 10, 10, 6]], [[3, 2, 8, 3, 2, 1]], [[9, 2, 4, 3, 4]]]}
user: *Inspired by the [Fold an Array](https://www.codewars.com/kata/fold-an-array) kata. This one is sort of similar but a little different.*

---

## Task
You will receive an array as parameter that contains 1 or more integers and a number `n`.

Here is a little visualization of the process:

* Step 1: Split the array in two:
```
  [1, 2, 5, 7, 2, 3, 5, 7, 8]
        /            \
[1, 2, 5, 7]    [2, 3, 5, 7, 8]
```

* Step 2: Put the arrays on top of each other:
```
     [1, 2, 5, 7]
[2, 3, 5, 7, 8]
```

* Step 3: Add them together:
```
[2, 4, 7, 12, 15]
```



Repeat the above steps `n` times or until there is only one number left, and then return the array.


## Example

```
Input: arr=[4, 2, 5, 3, 2, 5, 7], n=2


Round 1
-------
step 1: [4, 2, 5]  [3, 2, 5, 7]

step 2:    [4, 2, 5]
        [3, 2, 5, 7]

step 3: [3, 6, 7, 12]


Round 2
-------
step 1: [3, 6]  [7, 12]

step 2:  [3,  6]
         [7, 12]

step 3: [10, 18]


Result: [10, 18]
```

Answer: {"fn_name": "split_and_add", "inputs": [[[1, 2, 3, 4, 5], 2], [[1, 2, 3, 4, 5], 3], [[15], 3], [[1, 2, 3, 4], 1], [[1, 2, 3, 4, 5, 6], 20], [[32, 45, 43, 23, 54, 23, 54, 34], 2], [[32, 45, 43, 23, 54, 23, 54, 34], 0], [[3, 234, 25, 345, 45, 34, 234, 235, 345], 3], [[3, 234, 25, 345, 45, 34, 234, 235, 345, 34, 534, 45, 645, 645, 645, 4656, 45, 3], 4], [[23, 345, 345, 345, 34536, 567, 568, 6, 34536, 54, 7546, 456], 20]], "outputs": [[[5, 10]], [[15]], [[15]], [[4, 6]], [[21]], [[183, 125]], [[32, 45, 43, 23, 54, 23, 54, 34]], [[305, 1195]], [[1040, 7712]], [[79327]]]}
user: In this Kata, you will be given an array of integers and your task is to return the number of arithmetic progressions of size `3` that are possible from that list. In each progression, the differences between the elements must be the same.

```
[1, 2, 3, 5, 7, 9] ==> 5
// [1, 2, 3], [1, 3, 5], [1, 5, 9], [3, 5, 7], and [5, 7, 9]
```

All inputs will be sorted. More examples in test cases. 

Good luck!

Answer: {"fn_name": "solve", "inputs": [[[1, 2, 3, 4, 5]], [[1, 2, 3, 5, 7, 9]], [[0, 5, 8, 9, 11, 13, 14, 16, 17, 19]], [[0, 1, 2, 3, 5, 6, 7, 11, 13, 15, 17, 19]], [[0, 1, 4, 5, 7, 9, 10, 13, 15, 16, 18, 19]], [[0, 1, 2, 3, 5, 8, 11, 13, 14, 16, 18, 19]]], "outputs": [[4], [5], [10], [17], [15], [13]]}
user: I found this interesting interview question just today:

> *8 coins are given where all the coins have equal weight, except one. The odd one weights less than the others, not being of pure gold. In the worst case, how many iterations are actually needed to find the odd one out on a two plates scale*.

I am asking you then to tell me what is the *minimum* amount of weighings it will take to measure `n` coins in every possible occurrence (including worst case scenario, ie: without relying on luck at all).

`n` is guaranteed to be a positive integer.

***Tip:*** being able to think *recursively* might help here :p

***Note:*** albeit this is more clearly a logical than a coding problem, do not underestimate (or under-rank) the kata for requiring not necessarily wizard-class coding skills: a good coder is a master of pattern recognition and subsequent optimization ;)

Answer: {"fn_name": "how_many_measurements", "inputs": [[1], [2], [3], [8], [100]], "outputs": [[0], [1], [1], [2], [5]]}
user: A forest fire has been spotted at *fire*, a simple 2 element array with x, y coordinates.

The forest service has decided to send smoke jumpers in by plane and drop them in the forest.

The terrain is dangerous and surveyors have determined that there are three possible safe *dropzones*, an array of three simple arrays with x, y coordinates. 

The plane is en route and time is of the essence. Your mission is to return a simple [x,y] array with the coordinates of the dropzone closest to the fire. 

EDIT: 
The airplane is leaving from the origin at 0,0. If your result returns two possible dropzones that are both an equal distance from the fire, choose the dropzone that is closest to 0,0.

If the two dropzones are both equal distance away from 0,0, then return the dropzone that is first in the given array. 

For example, if you are given: fire = [1,1], possibleDZ = [0,1],[1,0],[2,2] . The answer is [0,1] because that is the first possible drop zone in the given array.

Answer: {"fn_name": "dropzone", "inputs": [[[6, 8], [[3, 2], [6, 1], [7, 9]]], [[9, 2], [[1, 4], [9, 9], [5, 5]]]], "outputs": [[[7, 9]], [[5, 5]]]}
user: You are given an input string.

For each symbol in the string if it's the first character occurrence, replace it with a '1', else replace it with the amount of times you've already seen it...
      
But will your code be **performant enough**?

___

## Examples:

```
input   =  "Hello, World!"
result  =  "1112111121311"

input   =  "aaaaaaaaaaaa"
result  =  "123456789101112"
```

There might be some non-ascii characters in the string.

~~~if:java
Note: there will be no int domain overflow (character occurrences will be less than 2 billion).
~~~
~~~if:c
(this does not apply to the C language translation)
~~~

Answer: {"fn_name": "numericals", "inputs": [["Hello, World!"], ["Hello, World! It's me, JomoPipi!"], ["hello hello"], ["Hello"], ["11111"], ["hope you 123456789 expected numbers in the string"], ["In this string, I'll make sure the amounts of a character go over 9"]], "outputs": [["1112111121311"], ["11121111213112111131224132411122"], ["11121122342"], ["11121"], ["12345"], ["1111112121111111113212311414121151151262267232231"], ["11111112221221132112411115312263237221234482193101343525441123124155131"]]}