meetforever/GRPO_CL huggingface dataset:
user: Dee is lazy but she's kind and she likes to eat out at all the nice restaurants and gastropubs in town. To make paying quick and easy she uses a simple mental algorithm she's called The Fair %20 Rule. She's gotten so good she can do this in a few seconds and it always impresses her dates but she's perplexingly still single. Like you probably. 

This is how she does it:

 - She rounds the price `P` at the tens place e.g:
   - 25 becomes 30
   - 24 becomes 20
   - 5 becomes 10
   - 4 becomes 0
 - She figures out the base tip `T` by dropping the singles place digit e.g:
   - when `P = 24` she rounds to 20 drops 0 `T = 2`
   - `P = 115` rounds to 120 drops 0 `T = 12`
   - `P = 25` rounds to 30 drops 0 `T = 3`
   - `P = 5` rounds to 10 drops 0 `T = 1`
   - `P = 4` rounds to 0 `T = 0`
 - She then applies a 3 point satisfaction rating `R` to `T` i.e:
   - When she's satisfied: `R = 1` and she'll add 1 to `T`
   - Unsatisfied: `R = 0` and she'll subtract 1 from `T`
   - Appalled: `R = -1` she'll divide `T` by 2, **rounds down** and subtracts 1
 
## Your Task

Implement a method `calc_tip` that takes two integer arguments for price `p` 

where `1 <= p <= 1000` and a rating `r` which is one of `-1, 0, 1`.

The return value `T` should be a non negative integer.

*Note: each step should be done in the order listed.*

Dee always politely smiles and says "Thank you" on her way out. Dee is nice. Be like Dee.

Answer: {"fn_name": "calc_tip", "inputs": [[4, 1], [4, 0], [4, -1], [5, 1], [5, 0], [5, -1], [14, 1], [14, 0], [14, -1], [15, 1], [15, 0], [15, -1], [24, 1], [24, 0], [24, -1], [25, 1], [25, 0], [25, -1], [125, 1], [125, 0], [125, -1], [144, 1], [144, 0], [144, -1]], "outputs": [[1], [0], [0], [2], [0], [0], [2], [0], [0], [3], [1], [0], [3], [1], [0], [4], [2], [0], [14], [12], [5], [15], [13], [6]]}
user: For every string, after every occurrence of `'and'` and `'but'`, insert the substring `'apparently'` directly after the occurrence.

If input does not contain 'and' or 'but', return the original string. If a blank string, return `''`.

If substring `'apparently'` is already directly after an `'and'` and/or `'but'`, do not add another. (Do not add duplicates).


# Examples:

Input 1 

    'It was great and I've never been on live television before but sometimes I don't watch this.'

Output 1

    'It was great and apparently I've never been on live television before but apparently sometimes I don't watch this.'

Input 2

    'but apparently'

Output 2

    'but apparently' 
(no changes because `'apparently'` is already directly after `'but'` and there should not be a duplicate.)

An occurrence of `'and'` and/or `'but'` only counts when it is at least one space separated. For example `'andd'` and `'bbut'` do not count as occurrences, whereas `'b but'` and `'and d'` does count.

reference that may help:
https://www.youtube.com/watch?v=rz5TGN7eUcM

Answer: {"fn_name": "apparently", "inputs": [["A fast-food resteraunt down the street was grumbling my tummy but I could not go."], ["apparently"], ["and"], ["but"], ["but apparently"], ["and apparently"], ["but but but and and and"], [""], ["but and apparently apparently apparently apparently"], ["and apparentlybutactuallynot voilewtfman"], ["and unapparently"], ["but apparentlx and apparentlx"], ["but the bread and butter apparently brand apparently"]], "outputs": [["A fast-food resteraunt down the street was grumbling my tummy but apparently I could not go."], ["apparently"], ["and apparently"], ["but apparently"], ["but apparently"], ["and apparently"], ["but apparently but apparently but apparently and apparently and apparently and apparently"], [""], ["but apparently and apparently apparently apparently apparently"], ["and apparently apparentlybutactuallynot voilewtfman"], ["and apparently unapparently"], ["but apparently apparentlx and apparently apparentlx"], ["but apparently the bread and apparently butter apparently brand apparently"]]}
user: You are given two positive integers ```a``` and ```b```.

You can perform the following operations on ```a``` so as to obtain ```b``` :
```
(a-1)/2   (if (a-1) is divisible by 2)
a/2       (if a is divisible by 2)
a*2
```
```b``` will always be a power of 2.

You are to write a function ```operation(a,b)``` that efficiently returns the minimum number of operations required to transform ```a``` into ```b```.

For example :
```
operation(2,8) -> 2
2*2 = 4
4*2 = 8

operation(9,2) -> 2
(9-1)/2 = 4
4/2 = 2

operation(1024,1024) -> 0
```

Answer: {"fn_name": "operation", "inputs": [[1, 1], [2, 4], [3, 8], [4, 16], [4, 1], [1, 4]], "outputs": [[0], [1], [4], [2], [2], [2]]}
user: # Task

Write a function that accepts `msg` string and returns local tops of string from the highest to the lowest.  
The string's tops are from displaying the string in the below way:

```      
                                                      3 
                              p                     2   4
            g               o   q                 1
  b       f   h           n       r             z 
a   c   e       i       m          s          y
      d           j   l             t       x
                    k                 u   w 
                                        v


```
The next top is always 1 character higher than the previous one. 
For the above example, the solution for the `abcdefghijklmnopqrstuvwxyz1234` input string is `3pgb`.

- When the `msg` string is empty, return an empty string.
- The input strings may be very long. Make sure your solution has good performance.

Check the test cases for more samples.

# **Note** for C++

Do not post an issue in my solution without checking if your returned string doesn't have some invisible characters. You read most probably outside of `msg` string.

Answer: {"fn_name": "tops", "inputs": [[""], ["12"], ["abcdefghijklmnopqrstuvwxyz12345"], ["abcdefghijklmnopqrstuvwxyz1236789ABCDEFGHIJKLMN"]], "outputs": [[""], ["2"], ["3pgb"], ["M3pgb"]]}
user: ### Task
The __dot product__ is usually encountered in linear algebra or scientific computing. It's also called __scalar product__ or __inner product__ sometimes:

> In mathematics, the __dot product__, or __scalar product__ (or sometimes __inner product__ in the context of Euclidean space), is an algebraic operation that takes two equal-length sequences of numbers (usually coordinate vectors) and returns a single number. [Wikipedia](https://en.wikipedia.org/w/index.php?title=Dot_product&oldid=629717691)

In our case, we define the dot product algebraically for two vectors `a = [a1, a2, …, an]`, `b = [b1, b2, …, bn]` as 
    
    dot a b = a1 * b1 + a2 * b2 + … + an * bn.
Your task is to find permutations of `a` and `b`, such that `dot a b` is minimal, and return that value. For example, the dot product of `[1,2,3]` and `[4,0,1]` is minimal if we switch `0` and `1` in the second vector.

### Examples
```python
min_dot([1,2,3,4,5], [0,1,1,1,0] ) = 6
min_dot([1,2,3,4,5], [0,0,1,1,-4]) = -17
min_dot([1,3,5]    , [4,-2,1]    ) = -3
```

### Remarks
If the list or array is empty, `minDot` should return 0. All arrays or lists will have the same length. Also, for the dynamically typed languages, all inputs will be valid lists or arrays, you don't need to check for `undefined`, `null` etc.

Note: This kata is inspired by [GCJ 2008](https://code.google.com/codejam/contest/32016/dashboard#s=p0).

Answer: {"fn_name": "min_dot", "inputs": [[[], []], [[1, 2, 3, 4, 5], [0, 1, 1, 1, 0]], [[1, 2, 3, 4, 5], [0, 0, 1, 1, -4]], [[1, 3, 5], [4, -2, 1]]], "outputs": [[0], [6], [-17], [-3]]}
user: In Dark Souls, players level up trading souls for stats. 8 stats are upgradable this way: vitality, attunement, endurance, strength, dexterity, resistance, intelligence, and faith. Each level corresponds to adding one point to a stat of the player's choice. Also, there are 10 possible classes each having their own starting level and stats:

```
Warrior     (Level 4):  11, 8, 12, 13, 13, 11, 9, 9
Knight      (Level 5):  14, 10, 10, 11, 11, 10, 9, 11
Wanderer    (Level 3):  10, 11, 10, 10, 14, 12, 11, 8
Thief       (Level 5):  9, 11, 9, 9, 15, 10, 12, 11
Bandit      (Level 4):  12, 8, 14, 14, 9, 11, 8, 10
Hunter      (Level 4):  11, 9, 11, 12, 14, 11, 9, 9
Sorcerer    (Level 3):  8, 15, 8, 9, 11, 8, 15, 8
Pyromancer  (Level 1):  10, 12, 11, 12, 9, 12, 10, 8
Cleric      (Level 2):  11, 11, 9, 12, 8, 11, 8, 14
Deprived    (Level 6):  11, 11, 11, 11, 11, 11, 11, 11
```

From level 1, the necessary souls to level up each time up to 11 are `673`, `690`, `707`, `724`, `741`, `758`, `775`, `793`, `811`, and `829`. Then from 11 to 12 and onwards the amount is defined by the expression `round(pow(x, 3) * 0.02 + pow(x, 2) * 3.06 + 105.6 * x - 895)` where `x` is the number corresponding to the next level.

Your function will receive a string with the character class and a list of stats. It should calculate which level is required to get the desired character build and the amount of souls needed to do so. The result should be a string in the format: `'Starting as a [CLASS], level [N] will require [M] souls.'` where `[CLASS]` is your starting class, `[N]` is the required level, and `[M]` is the amount of souls needed respectively.

Answer: {"fn_name": "souls", "inputs": [["deprived", [11, 11, 11, 11, 11, 11, 11, 11]], ["pyromancer", [10, 12, 11, 12, 9, 12, 11, 8]], ["pyromancer", [16, 12, 11, 12, 9, 12, 10, 8]], ["pyromancer", [16, 12, 11, 12, 9, 12, 13, 8]], ["pyromancer", [16, 12, 11, 12, 9, 12, 13, 10]]], "outputs": [["Starting as a deprived, level 6 will require 0 souls."], ["Starting as a pyromancer, level 2 will require 673 souls."], ["Starting as a pyromancer, level 7 will require 4293 souls."], ["Starting as a pyromancer, level 10 will require 6672 souls."], ["Starting as a pyromancer, level 12 will require 8348 souls."]]}
user: Given a non-negative number, return the next bigger polydivisible number, or an empty value like `null` or `Nothing`.

A number is polydivisible if its first digit is cleanly divisible by `1`, its first two digits by `2`, its first three by `3`, and so on. There are finitely many polydivisible numbers.

Answer: {"fn_name": "next_num", "inputs": [[0], [10], [11], [1234], [123220], [998], [999], [1234567890], [3608528850368400786036724], [3608528850368400786036725]], "outputs": [[1], [12], [12], [1236], [123252], [1020], [1020], [1236004020], [3608528850368400786036725], [null]]}
user: You are currently in the United States of America. The main currency here is known as the United States Dollar (USD). You are planning to travel to another country for vacation, so you make it today's goal to convert your USD (all bills, no cents) into the appropriate currency. This will help you be more prepared for when you arrive in the country you will be vacationing in.

Given an integer (`usd`) representing the amount of dollars you have and a string (`currency`) representing the name of the currency used in another country, it is your task to determine the amount of foreign currency you will receive when you exchange your United States Dollars.

However, there is one minor issue to deal with first. The screens and monitors at the Exchange are messed up. Some conversion rates are correctly presented, but other conversion rates are incorrectly presented. For some countries, they are temporarily displaying the standard conversion rate in the form of a number's binary representation! 

You make some observations. If a country's currency begins with a vowel, then the conversion rate is unaffected by the technical difficulties. If a country's currency begins with a consonant, then the conversion rate has been tampered with.

Normally, the display would show 1 USD converting to 111 Japanese Yen. Instead, the display is showing 1 USD converts to 1101111 Japanese Yen. You take it upon yourself to sort this out. By doing so, your 250 USD rightfully becomes 27750 Japanese Yen.

`
function(250, "Japanese Yen") => "You now have 27750 of Japanese Yen."
`

Normally, the display would show 1 USD converting to 21 Czech Koruna. Instead, the display is showing 1 USD converts to 10101 Czech Koruna. You take it upon yourself to sort this out. By doing so, your 325 USD rightfully becomes 6825 Czech Koruna.

`
function(325, "Czech Koruna") => "You now have 6825 of Czech Koruna."
`

Using your understanding of converting currencies in conjunction with the preloaded conversion-rates table, properly convert your dollars into the correct amount of foreign currency.

```if:javascript,ruby
Note: `CONVERSION_RATES` is frozen.
```

Answer: {"fn_name": "convert_my_dollars", "inputs": [[7, "Armenian Dram"], [322, "Armenian Dram"], [25, "Bangladeshi Taka"], [730, "Bangladeshi Taka"], [37, "Croatian Kuna"], [40, "Croatian Kuna"], [197, "Czech Koruna"], [333, "Czech Koruna"], [768, "Dominican Peso"], [983, "Dominican Peso"]], "outputs": [["You now have 3346 of Armenian Dram."], ["You now have 153916 of Armenian Dram."], ["You now have 2050 of Bangladeshi Taka."], ["You now have 59860 of Bangladeshi Taka."], ["You now have 222 of Croatian Kuna."], ["You now have 240 of Croatian Kuna."], ["You now have 4137 of Czech Koruna."], ["You now have 6993 of Czech Koruna."], ["You now have 36864 of Dominican Peso."], ["You now have 47184 of Dominican Peso."]]}
user: You are given an array with several `"even"` words, one `"odd"` word, and some numbers mixed in.

Determine if any of the numbers in the array is the index of the `"odd"` word. If so, return `true`, otherwise `false`.

Answer: {"fn_name": "odd_ball", "inputs": [[["even", 4, "even", 7, "even", 55, "even", 6, "even", 10, "odd", 3, "even"]], [["even", 4, "even", 7, "even", 55, "even", 6, "even", 9, "odd", 3, "even"]], [["even", 10, "odd", 2, "even"]]], "outputs": [[true], [false], [true]]}
user: We all know about Roman Numerals, and if not, here's a nice [introduction kata](http://www.codewars.com/kata/5580d8dc8e4ee9ffcb000050). And if you were anything like me, you 'knew' that the numerals were not used for zeroes or fractions; but not so!

I learned something new today: the [Romans did use fractions](https://en.wikipedia.org/wiki/Roman_numerals#Special_values) and there was even a glyph used to indicate zero.

So in this kata, we will be implementing Roman numerals and fractions.

Although the Romans used base 10 for their counting of units, they used base 12 for their fractions. The system used dots to represent twelfths, and an `S` to represent a half like so:

* ^(1)/12 = `.`
* ^(2)/12 = `:`
* ^(3)/12 = `:.`
* ^(4)/12 = `::`
* ^(5)/12 = `:.:`
* ^(6)/12 = `S`
* ^(7)/12 = `S.`
* ^(8)/12 = `S:`
* ^(9)/12 = `S:.`
* ^(10)/12 = `S::`
* ^(11)/12 = `S:.:`
* ^(12)/12 = `I` (as usual)

Further, zero was represented by `N`

## Kata

Complete the method that takes two parameters: an integer component in the range 0 to 5000 inclusive, and an optional fractional component in the range 0 to 11 inclusive.

You must return a string with the encoded value. Any input values outside the ranges given above should return `"NaR"` (i.e. "Not a Roman" :-)

## Examples

```python
roman_fractions(-12)     #=> "NaR"
roman_fractions(0, -1)   #=> "NaR"
roman_fractions(0, 12)   #=> "NaR"
roman_fractions(0)       #=> "N"
roman_fractions(0, 3)    #=> ":."
roman_fractions(1)       #=> "I"
roman_fractions(1, 0)    #=> "I"
roman_fractions(1, 5)    #=> "I:.:"
roman_fractions(1, 9)    #=> "IS:."
roman_fractions(1632, 2) #=> "MDCXXXII:"
roman_fractions(5000)    #=> "MMMMM"
roman_fractions(5001)    #=> "NaR"
```

Answer: {"fn_name": "roman_fractions", "inputs": [[-12], [0, -1], [0, 12], [0], [1], [1, 5], [1, 9], [1632, 2], [5000], [5001], [0, 0], [0, 1], [0, 2], [0, 3], [0, 4], [0, 5], [0, 6], [0, 7], [0, 8], [0, 9], [0, 10], [0, 11]], "outputs": [["NaR"], ["NaR"], ["NaR"], ["N"], ["I"], ["I:.:"], ["IS:."], ["MDCXXXII:"], ["MMMMM"], ["NaR"], ["N"], ["."], [":"], [":."], ["::"], [":.:"], ["S"], ["S."], ["S:"], ["S:."], ["S::"], ["S:.:"]]}
user: Jenny has written a function that returns a greeting for a user. However, she's in love with Johnny, and would like to greet him slightly different. She added a special case to her function, but she made a mistake.

Can you help her?

Answer: {"fn_name": "greet", "inputs": [["James"], ["Jane"], ["Jim"], ["Johnny"]], "outputs": [["Hello, James!"], ["Hello, Jane!"], ["Hello, Jim!"], ["Hello, my love!"]]}
user: You're re-designing a blog and the blog's posts have the following format for showing the date and time a post was made: 

*Weekday* *Month* *Day*, *time*
e.g., 
Friday May 2, 7pm

You're running out of screen real estate, and on some pages you want to display a shorter format, *Weekday* *Month* *Day* that omits the time.

Write a function, shortenToDate, that takes the Website date/time in its original string format, and returns the shortened format.

Assume shortenToDate's input will always be a string, e.g. "Friday May 2, 7pm". Assume shortenToDate's output will be the shortened string, e.g., "Friday May 2".

Answer: {"fn_name": "shorten_to_date", "inputs": [["Monday February 2, 8pm"], ["Tuesday May 29, 8pm"], ["Wed September 1, 3am"], ["Friday May 2, 9am"], ["Tuesday January 29, 10pm"]], "outputs": [["Monday February 2"], ["Tuesday May 29"], ["Wed September 1"], ["Friday May 2"], ["Tuesday January 29"]]}
user: Your task is to write a function named `do_math` that receives a single argument. 
This argument is a string that contains multiple whitespace delimited numbers. Each number has a single alphabet letter somewhere within it.
```
Example : "24z6 1x23 y369 89a 900b"
```
As shown above, this alphabet letter can appear anywhere within the number. You have to extract the letters and sort the numbers according to their corresponding letters. 
```
Example : "24z6 1x23 y369 89a 900b" will become 89 900 123 369 246 (ordered according to the alphabet letter)
```
Here comes the difficult part, now you have to do a series of computations on the numbers you have extracted.

* The sequence of computations are `+ - * /`. Basic math rules do **NOT** apply, you have to do each computation in exactly this order.
* This has to work for any size of numbers sent in (after division, go back to addition, etc).
* In the case of duplicate alphabet letters, you have to arrange them according to the number that appeared first in the input string.
* Remember to also round the final answer to the nearest integer.

```
Examples :
"24z6 1x23 y369 89a 900b" = 89 + 900 - 123 * 369 / 246 = 1299
"24z6 1z23 y369 89z 900b" = 900 + 369 - 246 * 123 / 89 = 1414
"10a 90x 14b 78u 45a 7b 34y" = 10 + 45 - 14 * 7 / 78 + 90 - 34 = 60
``` 
Good luck and may the CODE be with you!

Answer: {"fn_name": "do_math", "inputs": [["24z6 1z23 y369 89z 900b"], ["24z6 1x23 y369 89a 900b"], ["10a 90x 14b 78u 45a 7b 34y"], ["111a 222c 444y 777u 999a 888p"], ["1z 2t 3q 5x 6u 8a 7b"]], "outputs": [[1414], [1299], [60], [1459], [8]]}
user: ###Task:

You have to write a function `pattern` which creates the following pattern (see examples) up to the desired number of rows.

* If the Argument is 0 or a Negative Integer then it should return "" i.e. empty string.

* If any even number is passed as argument then the pattern should last upto the largest odd number which is smaller than the passed even number.

###Examples:

pattern(9):

    1
    333
    55555
    7777777
    999999999

pattern(6):

    1
    333
    55555

```Note: There are no spaces in the pattern```

```Hint: Use \n in string to jump to next line```

Answer: {"fn_name": "pattern", "inputs": [[4], [1], [5], [0], [-25]], "outputs": [["1\n333"], ["1"], ["1\n333\n55555"], [""], [""]]}
user: Round any given number to the closest 0.5 step

I.E.
```
solution(4.2) = 4
solution(4.3) = 4.5
solution(4.6) = 4.5
solution(4.8) = 5
```

Round **up** if number is as close to previous and next 0.5 steps.

```
solution(4.75) == 5
```

Answer: {"fn_name": "solution", "inputs": [[4.2], [4.25], [4.4], [4.6], [4.75], [4.8], [4.5], [4.55], [4.74], [4.74999999999], [4.74999999991]], "outputs": [[4], [4.5], [4.5], [4.5], [5], [5], [4.5], [4.5], [4.5], [4.5], [4.5]]}
user: At the annual family gathering, the family likes to find the oldest living family member’s age and the youngest family member’s age and calculate the difference between them.

You will be given an array of all the family members' ages, in any order.  The ages will be given in whole numbers, so a baby of 5 months, will have an ascribed ‘age’ of 0.  Return a new array (a tuple in Python) with [youngest age, oldest age, difference between the youngest and oldest age].

Answer: {"fn_name": "difference_in_ages", "inputs": [[[16, 22, 31, 44, 3, 38, 27, 41, 88]], [[5, 8, 72, 98, 41, 16, 55]], [[57, 99, 14, 32]], [[62, 0, 3, 77, 88, 102, 26, 44, 55]], [[2, 44, 34, 67, 88, 76, 31, 67]], [[46, 86, 33, 29, 87, 47, 28, 12, 1, 4, 78, 92]], [[66, 73, 88, 24, 36, 65, 5]], [[12, 76, 49, 37, 29, 17, 3, 65, 84, 38]], [[0, 110]], [[33, 33, 33]]], "outputs": [[[3, 88, 85]], [[5, 98, 93]], [[14, 99, 85]], [[0, 102, 102]], [[2, 88, 86]], [[1, 92, 91]], [[5, 88, 83]], [[3, 84, 81]], [[0, 110, 110]], [[33, 33, 0]]]}
user: **Principal Diagonal** -- The principal diagonal in a matrix identifies those elements of the matrix running from North-West to South-East.

**Secondary Diagonal** -- the secondary diagonal of a matrix identifies those elements of the matrix running from North-East to South-West.

For example:
```
matrix:             [1, 2, 3]
                    [4, 5, 6]
                    [7, 8, 9]

principal diagonal: [1, 5, 9]
secondary diagonal: [3, 5, 7]

```

## Task
Your task is to find which diagonal is "larger": which diagonal has a bigger sum of their elements.

* If the principal diagonal is larger, return `"Principal Diagonal win!"`
* If the secondary diagonal is larger, return `"Secondary Diagonal win!"`
* If they are equal, return `"Draw!"`

**Note:** You will always receive matrices of the same dimension.

Answer: {"fn_name": "diagonal", "inputs": [[[[2, 2, 2], [4, 2, 6], [8, 8, 2]]], [[[7, 2, 2], [4, 2, 6], [1, 8, 1]]], [[[1, 2, 3], [4, 5, 6], [7, 8, 9]]], [[[1, 2, 2, 5, 1], [4, 1, 6, 1, 1], [1, 8, 5, 6, 2], [1, 5, 2, 1, 2], [1, 8, 2, 6, 1]]], [[[88, 2, 2, 5, 1, 1, 2, 2, 5, 1], [4, 1, 6, 1, 1, 1, 2, 2, 7, 1], [1, 8, 1, 6, 2, 1, 2, 1, 5, 1], [1, 5, 2, 7, 2, 1, 1, 2, 5, 1], [1, 8, 2, 6, 1, 1, 2, 2, 5, 1], [1, 2, 2, 5, 1, 1, 2, 2, 5, 1], [1, 2, 2, 1, 1, 1, 1, 2, 5, 1], [1, 2, 1, 5, 1, 1, 2, 1, 5, 1], [1, 1, 2, 5, 1, 1, 2, 2, 1, 1], [88, 2, 2, 5, 1, 1, 2, 2, 5, 1]]], [[[2, 2, 2], [4, 2, 6], [1, 8, 5]]], [[[1, 2, 2, 5, 104], [4, 1, 6, 4, 1], [1, 8, 5, 6, 2], [1, 1, 2, 1, 2], [1, 8, 2, 6, 1]]], [[[1, 2, 2, 5, 1, 1, 2, 2, 5, 15], [4, 1, 6, 1, 1, 1, 2, 2, 1, 1], [1, 8, 1, 6, 2, 1, 2, 1, 5, 1], [1, 5, 2, 1, 2, 1, 1, 2, 5, 1], [1, 8, 2, 6, 1, 1, 2, 2, 5, 1], [1, 2, 2, 5, 1, 1, 2, 2, 5, 1], [1, 2, 2, 1, 1, 1, 1, 2, 5, 1], [1, 2, 1, 5, 1, 1, 2, 1, 5, 1], [1, 1, 2, 5, 1, 1, 2, 2, 1, 1], [1, 2, 2, 5, 1, 1, 2, 2, 5, 15]]], [[[0, 2, 2, 5, 1], [4, 0, 6, 1, 1], [1, 8, 5, 6, 2], [1, 7, 2, 1, 2], [1, 8, 2, 6, 1]]], [[[1, 2, 2, 5, 1, 1, 2, 2, 5, 1], [4, 8, 6, 1, 1, 1, 2, 2, 1, 1], [1, 8, 1, 6, 2, 1, 2, 6, 5, 1], [1, 5, 2, 1, 2, 1, 1, 2, 5, 1], [1, 8, 2, 6, 1, 1, 2, 2, 5, 1], [1, 2, 2, 5, 1, 1, 2, 2, 5, 1], [1, 2, 2, 1, 1, 1, 1, 2, 5, 1], [1, 2, 8, 5, 1, 1, 2, 6, 5, 1], [1, 1, 2, 5, 1, 1, 2, 2, 1, 1], [1, 2, 2, 5, 1, 1, 2, 2, 5, 1]]]], "outputs": [["Secondary Diagonal win!"], ["Principal Diagonal win!"], ["Draw!"], ["Secondary Diagonal win!"], ["Draw!"], ["Principal Diagonal win!"], ["Secondary Diagonal win!"], ["Draw!"], ["Secondary Diagonal win!"], ["Draw!"]]}
user: Write a function groupIn10s which takes any number of arguments, and groups them into sets of 10s and sorts each group in ascending order.

The return value should be an array of arrays, so that numbers between 0-9 inclusive are in position 0 and numbers 10-19 are in position 1, etc. 

Here's an example of the required output:

```python
grouped = group_in_10s(8, 12, 38, 3, 17, 19, 25, 35, 50) 

grouped[0]     # [3, 8]
grouped[1]     # [12, 17, 19]
grouped[2]     # [25]
grouped[3]     # [35, 38]
grouped[4]     # None
grouped[5]     # [50]
```
``` haskell
groupIn10s [8, 12, 3, 17, 19, 24, 35, 50] `shouldBe`  [[3,8],[12,17,19],[24],[35],[],[50]]
```

Answer: {"fn_name": "group_in_10s", "inputs": [[100]], "outputs": [[[null, null, null, null, null, null, null, null, null, null, [100]]]]}