meetforever/GRPO_CL huggingface dataset:
user: In some countries of former Soviet Union there was a belief about lucky tickets. A transport ticket of any sort was believed to posess luck if sum of digits on the left half of its number was equal to the sum of digits on the right half. Here are examples of such numbers:
```
003111    #             3 = 1 + 1 + 1
813372    #     8 + 1 + 3 = 3 + 7 + 2
17935     #         1 + 7 = 3 + 5  // if the length is odd, you should ignore the middle number when adding the halves.
56328116  # 5 + 6 + 3 + 2 = 8 + 1 + 1 + 6
```
Such tickets were either eaten after being used or collected for bragging rights.

Your task is to write a funtion ```luck_check(str)```, which returns ```true/True``` if argument is string decimal representation of a lucky ticket number, or ```false/False``` for all other numbers. It should throw errors for empty strings or strings which don't represent a decimal number.

Answer: {"fn_name": "luck_check", "inputs": [["5555"], ["003111"], ["543970707"], ["439924"], ["943294329932"], ["000000"], ["454319"], ["1233499943"], ["935336"]], "outputs": [[true], [true], [false], [false], [false], [true], [true], [false], [false]]}
user: Write a program that will calculate the number of trailing zeros in a factorial of a given number.

`N! = 1 * 2 * 3 *  ... * N`

Be careful `1000!` has 2568 digits...

For more info, see: http://mathworld.wolfram.com/Factorial.html 

## Examples

```python
zeros(6) = 1
# 6! = 1 * 2 * 3 * 4 * 5 * 6 = 720 --> 1 trailing zero

zeros(12) = 2
# 12! = 479001600 --> 2 trailing zeros
```

*Hint: You're not meant to calculate the factorial. Find another way to find the number of zeros.*

Answer: {"fn_name": "zeros", "inputs": [[0], [6], [30], [100], [1000], [100000], [1000000000]], "outputs": [[0], [1], [7], [24], [249], [24999], [249999998]]}
user: Lucas numbers are numbers in a sequence defined like this:
```
L(0) = 2
L(1) = 1
L(n) = L(n-1) + L(n-2)
```

Your mission is to complete the function that returns the `n`th term of this sequence.

**Note:** It should work for negative numbers as well; how you do this is you flip the equation around, so for negative numbers: `L(n) = L(n+2) - L(n+1)`


## Examples
```
L(-10) = 123
L(-5)  = -11
L(-1)  =  -1
L(0)   =   2
L(1)   =   1
L(5)   =  11
L(10)  = 123
```

Answer: {"fn_name": "lucasnum", "inputs": [[-10], [-1]], "outputs": [[123], [-1]]}
user: `late_clock` function receive an array with 4 digits and should return the latest time that can be built with those digits.
The time should be in `HH:MM` format.

Examples:
```
[1, 9, 8, 3] => 19:38
[9, 1, 2, 5] => 21:59
```

You can suppose the input is correct and you can build from it a correct 24-hour time.

Answer: {"fn_name": "late_clock", "inputs": [[[9, 1, 2, 5]], [[1, 9, 8, 3]], [[0, 2, 2, 2]], [[3, 5, 0, 2]], [[9, 0, 1, 1]], [[2, 3, 2, 4]], [[1, 2, 8, 9]]], "outputs": [["21:59"], ["19:38"], ["22:20"], ["23:50"], ["19:10"], ["23:42"], ["19:28"]]}
user: ## Task

Write a method `remainder` which takes two integer arguments, `dividend` and `divisor`, and returns the remainder when dividend is divided by divisor. Do NOT use the modulus operator (%) to calculate the remainder!

#### Assumption

Dividend will always be `greater than or equal to` divisor.

#### Notes

Make sure that the implemented `remainder` function works exactly the same as the `Modulus operator (%)`.

```if:java
`SimpleInteger` is a tiny and immutable implementation of an integer number. Its interface is a very small subset of the `java.math.BigInteger` API:

* `#add(SimpleInteger val)`
* `#subtract(SimpleInteger val)`
* `#multiply(SimpleInteger val)`
* `#divide(SimpleInteger val)`
* `#compareTo(SimpleInteger val)`
```

Answer: {"fn_name": "remainder", "inputs": [[3, 2], [19, 2], [10, 2], [34, 7], [27, 5]], "outputs": [[1], [1], [0], [6], [2]]}
user: ## Task

Given a string, add the fewest number of characters possible from the front or back to make it a palindrome.

## Example

For the input `cdcab`, the output should be `bacdcab`

## Input/Output

Input is a string consisting of lowercase latin letters with length 3 <= str.length <= 10

The output is a palindrome string satisfying the task.

For s = `ab` either solution (`aba` or `bab`) will be accepted.

Answer: {"fn_name": "build_palindrome", "inputs": [["abcdc"], ["ababa"]], "outputs": [["abcdcba"], ["ababa"]]}
user: # Task

In the field, two beggars A and B found some gold at the same time. They all wanted the gold, and they decided to use simple rules to distribute gold:
```
They divided gold into n piles and be in line. 
The amount of each pile and the order of piles all are randomly.

They took turns to take away a pile of gold from the 
far left or the far right.

They always choose the bigger pile. That is to say, 
if the left is 1, the right is 2, then choose to take 2.

If the both sides are equal, take the left pile.
```

Given an integer array `golds`, and assume that A always takes first. Please calculate the final amount of gold obtained by A and B. returns a two-element array `[amount of A, amount of B]`.

# Example

For `golds = [4,2,9,5,2,7]`, the output should be `[14,15]`.
```
The pile of most left is 4, 
The pile of most right is 7, 
A choose the largest one -- > take 7

The pile of most left is 4, 
The pile of most right is 2, 
B choose the largest one -- > take 4

The pile of most left is 2, 
The pile of most left is 2, 
A choose the most left one -- > take 2

The pile of most left is 9, 
The pile of most right is 2, 
B choose the largest one -- > take 9

The pile of most left is 5, 
The pile of most left is 2, 
A choose the largest one -- > take 5

Tehn, only 1 pile left, 
B  -- > take 2

A: 7 + 2 + 5 = 14
B: 4 + 9 + 2 = 15
```

For `golds = [10,1000,2,1]`, the output should be `[12,1001]`.
```
A take 10
B take 1000
A take 2
B take 1

A: 10 + 2 = 12
B: 1000 + 1 = 1001
```

Answer: {"fn_name": "distribution_of", "inputs": [[[4, 7, 2, 9, 5, 2]], [[10, 1000, 2, 1]]], "outputs": [[[11, 18]], [[12, 1001]]]}
user: Write a function ```x(n)``` that takes in a number ```n``` and returns an ```nxn``` array with an ```X``` in the middle. The ```X``` will be represented by ```1's``` and the rest will be ```0's```. 
E.g.
```python
x(5) ==  [[1, 0, 0, 0, 1],
          [0, 1, 0, 1, 0],
          [0, 0, 1, 0, 0],
          [0, 1, 0, 1, 0],
          [1, 0, 0, 0, 1]];
          
x(6) ==  [[1, 0, 0, 0, 0, 1],
          [0, 1, 0, 0, 1, 0],
          [0, 0, 1, 1, 0, 0],
          [0, 0, 1, 1, 0, 0],
          [0, 1, 0, 0, 1, 0],
          [1, 0, 0, 0, 0, 1]];
```

Answer: {"fn_name": "x", "inputs": [[1], [2], [3], [4], [5], [6]], "outputs": [[[[1]]], [[[1, 1], [1, 1]]], [[[1, 0, 1], [0, 1, 0], [1, 0, 1]]], [[[1, 0, 0, 1], [0, 1, 1, 0], [0, 1, 1, 0], [1, 0, 0, 1]]], [[[1, 0, 0, 0, 1], [0, 1, 0, 1, 0], [0, 0, 1, 0, 0], [0, 1, 0, 1, 0], [1, 0, 0, 0, 1]]], [[[1, 0, 0, 0, 0, 1], [0, 1, 0, 0, 1, 0], [0, 0, 1, 1, 0, 0], [0, 0, 1, 1, 0, 0], [0, 1, 0, 0, 1, 0], [1, 0, 0, 0, 0, 1]]]]}
user: You are given an array of integers. Your task is to sort odd numbers within the array in ascending order, and even numbers in descending order.

Note that zero is an even number. If you have an empty array, you need to return it.


For example:
```
[5, 3, 2, 8, 1, 4]  -->  [1, 3, 8, 4, 5, 2]

odd numbers ascending:   [1, 3,       5   ]
even numbers descending: [      8, 4,    2]
```

Answer: {"fn_name": "sort_array", "inputs": [[[5, 3, 2, 8, 1, 4, 11]], [[2, 22, 37, 11, 4, 1, 5, 0]], [[1, 111, 11, 11, 2, 1, 5, 0]], [[]], [[1, 2, 3, 4, 5, 6, 7, 8, 9, 0]], [[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]], [[0, 1, 2, 3, 4, 9, 8, 7, 6, 5]]], "outputs": [[[1, 3, 8, 4, 5, 2, 11]], [[22, 4, 1, 5, 2, 11, 37, 0]], [[1, 1, 5, 11, 2, 11, 111, 0]], [[]], [[1, 8, 3, 6, 5, 4, 7, 2, 9, 0]], [[8, 1, 6, 3, 4, 5, 2, 7, 0, 9]], [[8, 1, 6, 3, 4, 5, 2, 7, 0, 9]]]}
user: In this kata, we will check is an array is (hyper)rectangular.  
A rectangular array is an N-dimensional array with fixed sized within one dimension. Its sizes can be repsented like A1xA2xA3...xAN. That means a N-dimensional array has N sizes. The 'As' are the hyperrectangular properties of an array.

You should implement a functions that returns a N-tuple with the arrays hyperrectangular properties or None if the array is not hyperrectangular.
```
hyperrectangularity_properties(arr)
```
## Note
An empty array IS rectagular and has one dimension of length 0
```
hyperrectangularity_properties([]) == (0,)
```
## Example
```
1D array
hyperrectangularity_properties([1,2,3]) == (3,)

2D arrays  

hyperrectangularity_properties(
                                [[0,1,2],
                                 [3,4,5],           
                                 [6,7,8]] ) == (3,3)                              
hyperrectangularity_properties(
                                [[0,1,2],
                                 [3,4,5]] ) == (2,3)
hyperrectangularity_properties( 
                                [[0,1,2],
                                 [3,4]  ] ) == None
3D arrays  
hyperrectangularity_properties(  
                                [
                                 [ [0], [2] ],
                                 [ [0], [2] ],  
                                 [ [0], [2] ]
                                              ] ) == (3,2,1)    
hyperrectangularity_properties(  
                                [
                                   [[0],[2]],
                                   [[0],[2,2]],   
                                   [[0],[2]]
                                              ] )  ==  None 
hyperrectangularity_properties(
                                [[ [], [], [] ]]
                                                ) ==  (1,3,0) 
```
### Heterogeneous Arrays can appear too
```
hyperrectangularity_properties(      
                                [[0,1,2],
                                 3,   
                                 [[4],5,6]] ) ==  None
hyperrectangularity_properties(      
                                [1,
                                 [1,2],   
                                 [[3],[4,[5]],[6]]
                                                  ] ) ==  None
                                                  hyperrectangularity_properties(
                                [[ [], [] ], [] ]
                                                  ) ==  None
hyperrectangularity_properties(
                                [ 1, [], [2, [3]] ]
                                                  ) ==  None
```
The first property shows the length of the outer layer. The second of the layer one step deeper and so on. The function should handle higher dimensions too.


## Input
##### N-dimensional array of integers

## Expected Ouput
##### An N-tuple with the hyperrectangularity properties

Answer: {"fn_name": "hyperrectangularity_properties", "inputs": [[[]]], "outputs": [[[0]]]}
user: Write a function ```convert_temp(temp, from_scale, to_scale)``` converting temperature from one scale to another. 
Return converted temp value. 

Round converted temp value to an integer(!).

Reading: http://en.wikipedia.org/wiki/Conversion_of_units_of_temperature

```
possible scale inputs:
    "C"  for Celsius
    "F"  for Fahrenheit
    "K"  for Kelvin
    "R"  for Rankine
    "De" for Delisle
    "N"  for Newton
    "Re" for Réaumur
    "Ro" for Rømer
```

```temp``` is a number, ```from_scale``` and ```to_scale``` are strings. 

```python
convert_temp(   100, "C",  "F") # => 212
convert_temp(    40, "Re", "C") # => 50
convert_temp(    60, "De", "F") # => 140
convert_temp(373.15, "K",  "N") # => 33
convert_temp(   666, "K",  "K") # => 666
```

Answer: {"fn_name": "convert_temp", "inputs": [[100, "C", "F"], [-30, "De", "K"], [40, "Re", "C"], [60, "De", "F"], [373.15, "K", "N"], [666, "K", "K"], [60, "C", "F"], [60, "De", "C"], [128.25, "Ro", "C"], [-273.15, "C", "R"], [0, "K", "R"]], "outputs": [[212], [393], [50], [140], [33], [666], [140], [60], [230], [0], [0]]}
user: # Challenge : 

Write a function that takes a single argument `n` that is a string representation of a simple mathematical expression and evaluates it as a floating point value. 

# Commands : 
- positive or negative decimal numbers
- `+, -, *, /, ( / ).`

---

Expressions use [infix notation](https://en.wikipedia.org/wiki/Infix_notation). 

# Evaluation : 

Operators should be evaluated in the order they appear and not as in `BODMAS`, though brackets __should__ be correctly observed. 

The function should return the correct result for any possible expression of this form.

# Note : 

- All given input will be valid.
- It will consist entirely of numbers or one of the operators.
- Parentheses will alway be matched.
- Use of `eval` or its equivalent is forbidden
- use of `exec` is forbidden (Python) 
- Use of `Function` or any of their (Function, eval) equivalent is also forbidden.
- Using `require` is also forbidden. (`import` for python)
- Using more than 7 (8 for python) lines is also forbidden.
- Using more than 260 (JS) / 240 (python) characters is also forbidden.
- Having more than 100 chars per line is forbidden.
- Having more than 6 semi-colons is forbidden

and that is about it.

--- 

# Examples : 

    e("2*3*4*5+99")               ---> 219
    e("2*3*4*5+99*321-12312312")  ---> -12242013
    e("1-2*2/2*2-1*7+3")          ---> -18

---

Answer: {"fn_name": "e", "inputs": [["2*3*4*5+99"]], "outputs": [[219]]}
user: Write a method that takes one argument as name and then greets that name, capitalized and ends with an exclamation point.

Example:

```
"riley" --> "Hello Riley!"
"JACK"  --> "Hello Jack!"
```

Answer: {"fn_name": "greet", "inputs": [["riley"], ["molly"], ["BILLY"]], "outputs": [["Hello Riley!"], ["Hello Molly!"], ["Hello Billy!"]]}
user: DropCaps means that the first letter of the starting word of the paragraph should be in caps and the remaining lowercase, just like you see in the newspaper. 

But for a change, let's do that for each and every word of the given String. Your task is to capitalize every word that has length greater than 2, leaving smaller words as they are.

*should work also on Leading and Trailing Spaces and caps.

```python
drop_cap('apple') => "Apple"
drop_cap('apple of banana'); => "Apple of Banana"
drop_cap('one   space'); => "One   Space" 
drop_cap('   space WALK   '); => "   Space Walk   " 
```

**Note:** you will be provided atleast one word and should take string as input and return string as output.

Answer: {"fn_name": "drop_cap", "inputs": [["Apple Banana"], ["Apple"], [""], ["of"], ["Revelation of the contents outraged American public opinion, and helped generate"], ["more  than    one space between words"], ["  leading spaces"], ["trailing spaces   "], ["ALL CAPS CRAZINESS"], ["rAnDoM CaPs CrAzInEsS"]], "outputs": [["Apple Banana"], ["Apple"], [""], ["of"], ["Revelation of The Contents Outraged American Public Opinion, And Helped Generate"], ["More  Than    One Space Between Words"], ["  Leading Spaces"], ["Trailing Spaces   "], ["All Caps Craziness"], ["Random Caps Craziness"]]}
user: Impliment the reverse function, which takes in input n and reverses it. For instance, `reverse(123)` should return `321`. You should do this without converting the inputted number into a string.

Answer: {"fn_name": "reverse", "inputs": [[1234], [4321], [1001], [1010], [12005000]], "outputs": [[4321], [1234], [1001], [101], [50021]]}
user: Given a string `s` of uppercase letters, your task is to determine how many strings `t` (also uppercase) with length equal to that of `s` satisfy the followng conditions:

* `t` is lexicographical larger than `s`, and
* when you write both `s` and `t` in reverse order, `t` is still lexicographical larger than `s`.


```Haskell
For example:
solve('XYZ') = 5. They are: YYZ, ZYZ, XZZ, YZZ, ZZZ
```
String lengths are less than `5000`. Return you answer `modulo 10^9+7 (= 1000000007)`.

More examples in test cases. Good luck!

Answer: {"fn_name": "solve", "inputs": [["XYZ"], ["ABC"], ["ABCD"], ["ZAZ"], ["XYZA"]], "outputs": [[5], [16174], [402230], [25], [34480]]}
user: **This Kata is intended as a small challenge for my students**

Create a function, called ``removeVowels`` (or ``remove_vowels``), that takes a string argument and returns that same string with all vowels removed (vowels are "a", "e", "i", "o", "u").

Answer: {"fn_name": "remove_vowels", "inputs": [["drake"], ["scholarstem"], ["codewars"], ["high fives!"], [""], ["i"], ["b"]], "outputs": [["drk"], ["schlrstm"], ["cdwrs"], ["hgh fvs!"], [""], [""], ["b"]]}
user: Complete the function so that it takes an array of keys and a default value and returns a hash (Ruby) / dictionary (Python) with all keys set to the default value. 

## Example

```python
["draft", "completed"], 0   # should return {"draft": 0, "completed: 0}
```

Answer: {"fn_name": "populate_dict", "inputs": [[["draft", "completed"], 0], [["a", "b", "c"], null], [[1, 2, 3, 4], "OK"]], "outputs": [[{"completed": 0, "draft": 0}], [{"c": null, "b": null, "a": null}], [{"1": "OK", "2": "OK", "3": "OK", "4": "OK"}]]}
user: If we write out the digits of "60" as English words we get "sixzero"; the number of letters in "sixzero" is seven. The number of letters in "seven" is five. The number of letters in "five" is four. The number of letters in "four" is four: we have reached a stable equilibrium.

Note: for integers larger than 9, write out the names of each digit in a single word (instead of the proper name of the number in English). For example, write 12 as "onetwo" (instead of twelve), and 999 as "nineninenine" (instead of nine hundred and ninety-nine).

For any integer between 0 and 999, return an array showing the path from that integer to a stable equilibrium:

Answer: {"fn_name": "numbers_of_letters", "inputs": [[1], [2], [3], [4], [12], [37], [311], [999]], "outputs": [[["one", "three", "five", "four"]], [["two", "three", "five", "four"]], [["three", "five", "four"]], [["four"]], [["onetwo", "six", "three", "five", "four"]], [["threeseven", "onezero", "seven", "five", "four"]], [["threeoneone", "oneone", "six", "three", "five", "four"]], [["nineninenine", "onetwo", "six", "three", "five", "four"]]]}
user: We need a function ```prime_bef_aft()``` that gives the largest prime below a certain given value ```n```, 

```befPrime or bef_prime``` (depending on the language), 

and the smallest prime larger than this value, 

```aftPrime/aft_prime``` (depending on the language).

The result should be output in a list like the following:

```python
prime_bef_aft(n) == [befPrime, aftPrime]
```

If n is a prime number it will give two primes, n will not be included in the result.

Let's see some cases:
```python
prime_bef_aft(100) == [97, 101]

prime_bef_aft(97) == [89, 101]

prime_bef_aft(101) == [97, 103]
```
Range for the random tests: 
```1000 <= n <= 200000```

(The extreme and special case n = 2 will not be considered for the tests. Thanks Blind4Basics)

Happy coding!!

Answer: {"fn_name": "prime_bef_aft", "inputs": [[3], [4], [100], [97], [101], [120], [130]], "outputs": [[[2, 5]], [[3, 5]], [[97, 101]], [[89, 101]], [[97, 103]], [[113, 127]], [[127, 131]]]}
user: It is 2050 and romance has long gone, relationships exist solely for practicality.

MatchMyHusband is a website that matches busy working women with perfect house husbands. You have been employed by MatchMyHusband to write a function that determines who matches!!

The rules are... a match occurs providing the husband's "usefulness" rating is greater than or equal to the woman's "needs".

The husband's "usefulness" is the SUM of his cooking, cleaning and childcare abilities and takes the form of an array .

usefulness example --> [15, 26, 19]    (15 + 26 + 19) = 60

Every woman that signs up, begins with a "needs" rating of 100. However, it's realised that the longer women wait for their husbands, the more dissatisfied they become with our service. They also become less picky, therefore their needs are subject to exponential decay of 15% per month. https://en.wikipedia.org/wiki/Exponential_decay

Given the number of months since sign up, write a function that returns "Match!" if the husband is useful enough, or "No match!" if he's not.

Answer: {"fn_name": "match", "inputs": [[[15, 24, 12], 4], [[26, 23, 19], 3], [[11, 25, 36], 1], [[22, 9, 24], 5], [[8, 11, 4], 10], [[17, 31, 21], 2], [[34, 25, 36], 1], [[35, 35, 29], 0], [[35, 35, 30], 0], [[35, 35, 31], 0]], "outputs": [["No match!"], ["Match!"], ["No match!"], ["Match!"], ["Match!"], ["No match!"], ["Match!"], ["No match!"], ["Match!"], ["Match!"]]}
user: Your job is to figure out the index of which vowel is missing from a given string:

* `A` has an index of 0,
* `E` has an index of 1, 
* `I` has an index of 2, 
* `O` has an index of 3,
* `U` has an index of 4.

**Notes:** There is no need for string validation and every sentence given will contain all vowles but one. Also, you won't need to worry about capitals.


## Examples

```
"John Doe hs seven red pples under his bsket"          =>  0  ; missing: "a"
"Bb Smith sent us six neatly arranged range bicycles"  =>  3  ; missing: "o"
```

Answer: {"fn_name": "absent_vowel", "inputs": [["John Doe hs seven red pples under his bsket"], ["Bb Smith sent us six neatly arranged range bicycles"]], "outputs": [[0], [3]]}
user: Quantum mechanics tells us that a molecule is only allowed to have specific, discrete amounts of internal energy. The 'rigid rotor model', a model for describing rotations, tells us that the amount of rotational energy a molecule can have is given by:  

`E =  B * J * (J + 1)`, 

where J is the state the molecule is in, and B is the 'rotational constant' (specific to the molecular species).

Write a function that returns an array of allowed energies for levels between Jmin and Jmax.

Notes:

* return empty array if Jmin is greater than Jmax (as it make no sense).
* Jmin, Jmax are integers.
* physically B must be positive, so return empty array if B <= 0

Answer: {"fn_name": "rot_energies", "inputs": [[1, 1, 2], [2, 0, 3], [423, 100, 150], [1, 2, 0], [1, 2, 2], [-1.0, 2, 2]], "outputs": [[[2, 6]], [[0, 4, 12, 24]], [[4272300, 4357746, 4444038, 4531176, 4619160, 4707990, 4797666, 4888188, 4979556, 5071770, 5164830, 5258736, 5353488, 5449086, 5545530, 5642820, 5740956, 5839938, 5939766, 6040440, 6141960, 6244326, 6347538, 6451596, 6556500, 6662250, 6768846, 6876288, 6984576, 7093710, 7203690, 7314516, 7426188, 7538706, 7652070, 7766280, 7881336, 7997238, 8113986, 8231580, 8350020, 8469306, 8589438, 8710416, 8832240, 8954910, 9078426, 9202788, 9327996, 9454050, 9580950]], [[]], [[6]], [[]]]}
user: It's bonus time in the big city! The fatcats are rubbing their paws in anticipation... but who is going to make the most money? 

Build a function that takes in two arguments (salary, bonus). Salary will be an integer, and bonus a boolean.

If bonus is true, the salary should be multiplied by 10. If bonus is false, the fatcat did not make enough money and must receive only his stated salary.

Return the total figure the individual will receive as a string prefixed with "£" (= `"\u00A3"`, JS, Go, and Java), "$" (C#, C++, Ruby, Clojure, Elixir, PHP and Python, Haskell, Lua) or "¥" (Rust).

Answer: {"fn_name": "bonus_time", "inputs": [[10000, true], [25000, true], [10000, false], [60000, false], [2, true], [78, false], [67890, true]], "outputs": [["$100000"], ["$250000"], ["$10000"], ["$60000"], ["$20"], ["$78"], ["$678900"]]}