meetforever/GRPO_CL huggingface dataset:
user: Because my other two parts of the serie were pretty well received I decided to do another part.

Puzzle Tiles

You will get two Integer n (width) and m (height) and your task is to draw following pattern. Each line is seperated with '\n'.


Both integers are equal or greater than 1. No need to check for invalid parameters.
There are no whitespaces at the end of each line.

e.g.:


 

                                       \_( )\_\_ \_( )\_\_ \_( )\_\_ \_( )\_\_
                                     \_|     \_|     \_|     \_|     \_|
                                    (\_   \_ (\_   \_ (\_   \_ (\_   \_ (\_
                                     |\_\_( )\_|\_\_( )\_|\_\_( )\_|\_\_( )\_|
                                     |\_     |\_     |\_     |\_     |\_
             puzzleTiles(4,3)=>       \_) \_   \_) \_   \_) \_   \_) \_   \_)
                                     |\_\_( )\_|\_\_( )\_|\_\_( )\_|\_\_( )\_|
                                     \_|     \_|     \_|     \_|     \_|
                                    (\_   \_ (\_   \_ (\_   \_ (\_   \_ (\_
                                     |\_\_( )\_|\_\_( )\_|\_\_( )\_|\_\_( )\_|
                                     


For more informations take a look in the test cases!


 Serie: ASCII Fun

ASCII Fun #1: X-Shape
ASCII Fun #2: Funny Dots
ASCII Fun #3: Puzzle Tiles
ASCII Fun #4: Build a pyramid

Answer: {"fn_name": "puzzle_tiles", "inputs": [[1, 1], [3, 2]], "outputs": [["   _( )__\n _|     _|\n(_   _ (_\n |__( )_|"], ["   _( )__ _( )__ _( )__\n _|     _|     _|     _|\n(_   _ (_   _ (_   _ (_\n |__( )_|__( )_|__( )_|\n |_     |_     |_     |_\n  _) _   _) _   _) _   _)\n |__( )_|__( )_|__( )_|"]]}
user: I'm new to coding and now I want to get the sum of two arrays...actually the sum of all their elements. I'll appreciate for your help.

P.S. Each array includes only integer numbers. Output is a number too.

Answer: {"fn_name": "array_plus_array", "inputs": [[[1, 2, 3], [4, 5, 6]], [[-1, -2, -3], [-4, -5, -6]], [[0, 0, 0], [4, 5, 6]], [[100, 200, 300], [400, 500, 600]]], "outputs": [[21], [-21], [15], [2100]]}
user: # Task
A masked number is a string that consists of digits and one asterisk (`*`) that should be replaced by exactly one digit. Given a masked number `s`, find all the possible options to replace the asterisk with a digit to produce an integer divisible by 6.


# Input/Output

`[input]` string `s`

A masked number.

`1 ≤ inputString.length ≤ 10000.`

`[output]` a string array

Sorted array of strings representing all non-negative integers that correspond to the given mask and are divisible by 6.

# Example

For `s = "1*0"`, the output should be `["120", "150", "180"].`

For `s = "*1"`, the output should be `[].`

For `s = "1234567890123456789012345678*0"`, 

the output should be 
```
[
"123456789012345678901234567800",
"123456789012345678901234567830",
"123456789012345678901234567860",
"123456789012345678901234567890"]```
As you can see, the masked number may be very large ;-)

Answer: {"fn_name": "is_divisible_by_6", "inputs": [["1*0"], ["*"], ["*1"], ["*2"], ["81234567890*"], ["41*"], ["*6"], ["2345*345729"], ["34234*2"], ["1234567890123456789012345678*0"]], "outputs": [[["120", "150", "180"]], [["0", "6"]], [[]], [["12", "42", "72"]], [["812345678904"]], [["414"]], [["6", "36", "66", "96"]], [[]], [["3423402", "3423432", "3423462", "3423492"]], [["123456789012345678901234567800", "123456789012345678901234567830", "123456789012345678901234567860", "123456789012345678901234567890"]]]}
user: Born a misinterpretation of [this kata](https://www.codewars.com/kata/simple-fun-number-334-two-beggars-and-gold/), your task here is pretty simple: given an array of values and an amount of beggars, you are supposed to return an array with the sum of what each beggar brings home, assuming they all take regular turns, from the first to the last.

For example: `[1,2,3,4,5]` for `2` beggars will return a result of `[9,6]`, as the first one takes `[1,3,5]`, the second collects `[2,4]`.

The same array with `3` beggars would have in turn have produced a better out come for the second beggar: `[5,7,3]`, as they will respectively take `[1,4]`, `[2,5]` and `[3]`.

Also note that not all beggars have to take the same amount of "offers", meaning that the length of the array is not necessarily a multiple of `n`; length can be even shorter, in which case the last beggars will of course take nothing (`0`).

***Note:*** in case you don't get why this kata is about *English* beggars, then you are not familiar on how religiously queues are taken in the kingdom ;)

Answer: {"fn_name": "beggars", "inputs": [[[1, 2, 3, 4, 5], 1], [[1, 2, 3, 4, 5], 2], [[1, 2, 3, 4, 5], 3], [[1, 2, 3, 4, 5], 6], [[1, 2, 3, 4, 5], 0]], "outputs": [[[15]], [[9, 6]], [[5, 7, 3]], [[1, 2, 3, 4, 5, 0]], [[]]]}
user: Note: This kata is inspired by [Convert a Number to a String!](http://www.codewars.com/kata/convert-a-number-to-a-string/). Try that one too.

## Description

We need a function that can transform a string into a number. What ways of achieving this do you know?

Note: Don't worry, all inputs will be strings, and every string is a perfectly valid representation of an integral number.

## Examples

```python
stringToNumber("1234") == 1234
stringToNumber("605" ) == 605
stringToNumber("1405") == 1405
stringToNumber("-7"  ) == -7
```

Answer: {"fn_name": "string_to_number", "inputs": [["4"]], "outputs": [[4]]}
user: In graph theory, a graph is a collection of nodes with connections between them.
Any node can be connected to any other node exactly once, and can be connected to no nodes, to some nodes, or to every other node.
Nodes cannot be connected to themselves
A path through a graph is a sequence of nodes, with every node connected to the node following and preceding it.
A closed path is a path which starts and ends at the same node.

An open path:
```
1 -> 2 -> 3
```
a closed path:
```
1 -> 2 -> 3 -> 1
```
A graph is connected if there is a path from every node to every other node.
A graph is a tree if it is connected and there are no closed paths.


Your job is to write a function 'isTree', which returns true if a graph is a tree, and false if it is not a tree.

Graphs will be given as an array with each item being an array of integers which are the nodes that node is connected to.

For example, this graph:
```
0--1
|  |
2--3--4
```
has array:
```
[[1,2], [0,3], [0,3], [1,2,4], [3]]
```
Note that it is also not a tree, because it contains closed path:
```
0->1->3->2->0
```
A node with no connections is an empty array
Note that if node 0 is connected to node 1, node 1 is also connected to node 0. This will always be true.
The order in which each connection is listed for each node also does not matter.

Good luck!

Answer: {"fn_name": "isTree", "inputs": [[[[], []]], [[[1], [0]]], [[[1, 2], [0, 2], [0, 1]]], [[[1, 2, 3], [0, 2], [1, 2], [0]]], [[[1, 2, 3], [0], [0], [0, 4], [3]]], [[[1, 2, 3], [0], [0], [0, 4], [3], []]], [[[1], [0, 2], [1, 3, 5], [2, 4], [3, 5], [4, 2]]], [[[1], [0, 2, 3, 4], [1], [1], [1]]], [[[1], [0, 2, 3], [1], [1], [5], [4, 6, 7], [5], [5]]], [[[1, 2], [0, 3], [0, 3], [1, 2, 4], [3]]], [[[1, 2], [0, 2], [0, 1], []]], [[[1, 2], [0, 2], [0, 1], [4], [3]]]], "outputs": [[false], [true], [false], [false], [true], [false], [false], [true], [false], [false], [false], [false]]}
user: In this Kata, you will create a function that converts a string with letters and numbers to the inverse of that string (with regards to Alpha and Numeric characters). So, e.g. the letter `a` will become `1` and number `1` will become `a`; `z` will become `26` and `26` will become `z`.

Example: `"a25bz"` would become `"1y226"`


Numbers representing letters (`n <= 26`) will always be separated by letters, for all test cases: 

* `"a26b"` may be tested, but not `"a262b"`
* `"cjw9k"` may be tested, but not `"cjw99k"`

A list named `alphabet` is preloaded for you: `['a', 'b', 'c', ...]`

A dictionary of letters and their number equivalent is also preloaded for you called `alphabetnums = {'a': '1', 'b': '2', 'c': '3', ...}`

Answer: {"fn_name": "AlphaNum_NumAlpha", "inputs": [["25abcd26"], ["18zyz14"], ["a1b2c3d4"], ["5a8p17"], ["w6aa4ct24m5"], ["17dh"], ["25gj8sk6r17"], ["18zzz14"], ["y17kg5et11"], ["abcdefghijklmnopqrstuvwxyz"], ["1a2b3c4d5e6f7g8h9i10j11k12l13m14n15o16p17q18r19s20t21u22v23w24x25y26z"], ["h15q4pc6yw23nmx19y"], ["p16k11o25x7m6m20ct9"], ["nv15u19d5fq8"], ["4n3fk22en17ekve"], ["iwantamemewar"], ["7h15cc9s23l11k10sd5"], ["hd2gd14gf2sg5lm8wfv9bb13"], ["13"], ["7k7k7sg3jvh16d"], ["6h19r21a8b"], ["youaredonegoodforyou"]], "outputs": [["y1234z"], ["r262526n"], ["1a2b3c4d"], ["e1h16q"], ["23f11d320x13e"], ["q48"], ["y710h1911f18q"], ["r262626n"], ["25q117e520k"], ["1234567891011121314151617181920212223242526"], ["a1b2c3d4e5f6g7h8i9j10k11l12m13n14o15p16q17r18s19t20u21v22w23x24y25z26"], ["8o17d163f2523w141324s25"], ["16p11k15y24g13f13t320i"], ["1422o21s4e617h"], ["d14c611v514q511225"], ["92311420113513523118"], ["g8o33i19w12k11j194e"], ["84b74n76b197e1213h23622i22m"], ["m"], ["g11g11g197c10228p4"], ["f8s18u1h2"], ["251521118541514571515461518251521"]]}
user: Convert a hash into an array. Nothing more, Nothing less.

```
{name: 'Jeremy', age: 24, role: 'Software Engineer'}
```
should be converted into

```
[["name", "Jeremy"], ["age", 24], ["role", "Software Engineer"]]
```

```if:python,javascript,crystal
**Note**: The output array should be sorted alphabetically.
```

Good Luck!

Answer: {"fn_name": "convert_hash_to_array", "inputs": [[{"name": "Jeremy"}], [{"name": "Jeremy", "age": 24}], [{"name": "Jeremy", "age": 24, "role": "Software Engineer"}], [{"product": "CodeWars", "power_level_over": 9000}], [{}]], "outputs": [[[["name", "Jeremy"]]], [[["age", 24], ["name", "Jeremy"]]], [[["age", 24], ["name", "Jeremy"], ["role", "Software Engineer"]]], [[["power_level_over", 9000], ["product", "CodeWars"]]], [[]]]}
user: To participate in a prize draw each one gives his/her firstname. 

Each letter of a firstname
has a value which is its rank in the English alphabet. `A` and `a` have rank `1`, `B` and `b` rank `2` and so on. 

The *length* of the firstname is added to the *sum* of these ranks hence a number `som`. 

An array of random weights is linked to the firstnames and each `som` is multiplied by 
its corresponding weight to get what they call a `winning number`.

Example:
```
names: "COLIN,AMANDBA,AMANDAB,CAROL,PauL,JOSEPH"
weights: [1, 4, 4, 5, 2, 1]

PauL -> som = length of firstname + 16 + 1 + 21 + 12 = 4 + 50 -> 54
The *weight* associated with PauL is 2 so PauL's *winning number* is 54 * 2 = 108.
```
Now one can sort the firstnames in decreasing order of the `winning numbers`. When two
people have the same `winning number` sort them *alphabetically* by their firstnames.

### Task:

- parameters: `st` a string of firstnames, `we` an array of weights, `n` a rank 

- return: the firstname of the participant whose rank is `n` 
(ranks are numbered from 1)

### Example:
```
names: "COLIN,AMANDBA,AMANDAB,CAROL,PauL,JOSEPH"
weights: [1, 4, 4, 5, 2, 1]
n: 4

The function should return: "PauL"
```
# Notes:
- The weight array is at least as long as the number of names, it can be longer.

- If `st` is empty return "No participants".

- If n is greater than the number of participants then return "Not enough participants".

- See Examples Test Cases for more examples.

Answer: {"fn_name": "rank", "inputs": [["Addison,Jayden,Sofia,Michael,Andrew,Lily,Benjamin", [4, 2, 1, 4, 3, 1, 2], 4], ["Elijah,Chloe,Elizabeth,Matthew,Natalie,Jayden", [1, 3, 5, 5, 3, 6], 2], ["Aubrey,Olivai,Abigail,Chloe,Andrew,Elizabeth", [3, 1, 4, 4, 3, 2], 4], ["Lagon,Lily", [1, 5], 2], ["Elijah,Michael,Avery,Sophia,Samantha", [2, 1, 5, 2, 2], 3], ["William,Willaim,Olivia,Olivai,Lily,Lyli", [1, 1, 1, 1, 1, 1], 1], ["Addison,Jayden,Sofia,Michael,Andrew,Lily,Benjamin", [4, 2, 1, 4, 3, 1, 2], 8], ["", [4, 2, 1, 4, 3, 1, 2], 6], ["Addison,William,Jayden", [3, 5, 6], 1], ["Joshua,Grace,Isabella", [1, 5, 4], 1], ["Elijah,Addison", [3, 6], 2], ["Willaim,Liam,Daniel,Alexander", [6, 4, 6, 2], 2], ["Avery,Olivai,Sophia,Michael,Elizabeth,Willaim,Liam", [5, 5, 3, 2, 1, 3, 6], 5], ["Liam,Madison,Lyli,Jacob,Matthew,Michael", [2, 6, 5, 5, 3, 4], 6], ["Sophia,Robert,Abigail,Grace,Lagon", [1, 2, 2, 6, 4], 5], ["Samantha,Ella", [5, 6], 1], ["Aubrey,Jayden", [3, 4], 2], ["Jacob,Elijah", [4, 3], 1]], "outputs": [["Benjamin"], ["Matthew"], ["Abigail"], ["Lagon"], ["Sophia"], ["Willaim"], ["Not enough participants"], ["No participants"], ["William"], ["Isabella"], ["Elijah"], ["Daniel"], ["Sophia"], ["Liam"], ["Sophia"], ["Samantha"], ["Aubrey"], ["Elijah"]]}
user: Write a function named setAlarm which receives two parameters. The first parameter, employed, is true whenever you are employed and the second parameter, vacation is true whenever you are on vacation.
The function should return true if you are employed and not on vacation (because these are the circumstances under which you need to set an alarm). It should return false otherwise. Examples:

```if-not:julia,racket
setAlarm(true, true) -> false
setAlarm(false, true) -> false
setAlarm(false, false) -> false
setAlarm(true, false) -> true
```

Answer: {"fn_name": "set_alarm", "inputs": [[true, true], [false, true], [false, false], [true, false]], "outputs": [[false], [false], [false], [true]]}
user: Calculus class...is awesome! But you are a programmer with no time for mindless repetition. Your teacher spent a whole day covering differentiation of polynomials, and by the time the bell rang, you had already conjured up a program to automate the process.

You realize that a polynomial of degree n

anx^(n) + an-1x^(n-1) + ... + a0

can be represented as an array of coefficients

[an, an-1, ...,  a0]

For example, we would represent

5x^(2) + 2x + 1 as [5,2,1]

3x^(2) + 1 as [3,0,1]

x^(4) as [1,0,0,0,0]

x as [1, 0]

1 as [1]

Your function will take a coefficient array as an argument and return a **new array** representing the coefficients of the derivative.

```python
poly1 = [1, 1] # x + 1
diff(poly1) == [1] # 1

poly2 = [1, 1, 1] # x^2 + x + 1
diff(poly2) == [2, 1] # 2x + 1
diff(diff(poly2)) == [2] # 2

poly3 = [2, 1, 0, 0] # 2x^3 + x^2
diff(poly3) == [6, 2, 0] # 6x^2 + 2x
```
Note: your function will always return a new array which has one less element than the argument (unless the argument is [], in which case [] is returned).

Answer: {"fn_name": "diff", "inputs": [[[]]], "outputs": [[[]]]}
user: Given is a md5 hash of a five digits long PIN. It is given as string.
Md5 is a function to hash your password:
"password123" ===> "482c811da5d5b4bc6d497ffa98491e38"

Why is this useful?
Hash functions like md5 can create a hash from string in a short time and it is impossible to find out the password, if you only got the hash. The only way is cracking it, means try every combination, hash it and compare it with the hash you want to crack. (There are also other ways of attacking md5 but that's another story)
Every Website and OS is storing their passwords as hashes, so if a hacker gets access to the database, he can do nothing, as long the password is safe enough.

What is a hash:
https://en.wikipedia.org/wiki/Hash_function#:~:text=A%20hash%20function%20is%20any,table%20called%20a%20hash%20table.

What is md5:
https://en.wikipedia.org/wiki/MD5

Note: Many languages have build in tools to hash md5. If not, you can write your own md5 function or google for an example.

Here is another kata on generating md5 hashes:
https://www.codewars.com/kata/password-hashes

Your task is to return the cracked PIN as string.

This is a little fun kata, to show you, how weak PINs are and how important a bruteforce protection is, if you create your own login.

If you liked this kata, here is an extension with short passwords:
https://www.codewars.com/kata/59146f7b4670ba520900000a

Answer: {"fn_name": "crack", "inputs": [["827ccb0eea8a706c4c34a16891f84e7b"], ["86aa400b65433b608a9db30070ec60cd"]], "outputs": [["12345"], ["00078"]]}
user: # Task
After a long night (work, play, study) you find yourself sleeping on a bench in a park. As you wake up and try to figure out what happened you start counting trees.

You notice there are different tree sizes but there's always one size which is unbalanced. For example there are 2 size 2, 2 size 1 and 1 size 3. (then the size 3 is unbalanced)

Given an array representing different tree sizes. Which one is the unbalanced size.

Notes:
```
There can be any number of sizes but one is always unbalanced
The unbalanced size is always one less than the other sizes
The array is not ordered (nor the trees)```

# Examples

For `trees = [1,1,2,2,3]`, the result should be `3`.

For `trees = [2,2,2,56,56,56,8,8]`, the result should be `8`.

For `trees = [34,76,12,99,64,99,76,12,34]`, the result should be `64`.

# Input/Output


- `[input]` integer array `trees`

Array representing different tree sizes


- `[output]` an integer

The size of the missing tree.

Answer: {"fn_name": "find_the_missing_tree", "inputs": [[[1, 2, 2, 3, 3]], [[11, 2, 3, 3, 3, 11, 2, 2]], [[234, 76, 45, 99, 99, 99, 99, 45, 234, 234, 45, 45, 76, 234, 76]], [[1, 1, 1, 1, 1, 1, 1, 22, 22, 22, 22, 22, 22, 22, 3, 3, 3, 3, 3, 3]], [[10, 205, 3000, 3000, 10]], [[50, 408, 50, 50, 50, 50, 408, 408, 408, 680, 408, 680, 50, 408, 680, 50, 50, 680, 408, 680, 50, 680, 680, 408, 408, 50, 50, 408, 50, 50, 50, 50, 680, 408, 680, 50, 680, 408, 680, 408, 680, 50, 50, 50, 680, 50, 680, 408, 680, 680, 680, 408, 408, 408, 408, 680, 680, 50, 408, 408, 408, 50, 408, 408, 50, 680, 680, 680, 50, 680, 680, 680, 50, 680, 408, 50, 50, 408, 50, 408, 680, 408, 50, 680, 680, 408, 408, 680, 408]]], "outputs": [[1], [11], [76], [3], [205], [50]]}
user: You probably know the 42 number as "The answer to life, the universe and everything" according to Douglas Adams' "The Hitchhiker's Guide to the Galaxy". For Freud, the answer was quite different.

In the society he lived in, people-women in particular- had to repress their sexual needs and desires. This was simply how the society was at the time. 
Freud then wanted to study the illnesses created by this, and so he digged to the root of their desires. This led to some of the most important psychoanalytic theories to this day, Freud being the father of psychoanalysis.

Now, basically, when a person hears about Freud, s/he hears "sex" because for Freud, everything was basically related to, and explained by sex. 

In this kata, the toFreud() function will take a string as its argument, and return a string with every word replaced by the explanation to everything, according to Freud. Note that an empty string, or no arguments, should result in the ouput being ""(empty string).

Answer: {"fn_name": "to_freud", "inputs": [["test"], ["sexy sex"], ["This is a test"], ["This is a longer test"], ["You're becoming a true freudian expert"]], "outputs": [["sex"], ["sex sex"], ["sex sex sex sex"], ["sex sex sex sex sex"], ["sex sex sex sex sex sex"]]}
user: # Making Change

Complete the method that will determine the minimum number of coins needed to make change for a given amount in American currency.

Coins used will be half-dollars, quarters, dimes, nickels, and pennies, worth 50¢, 25¢, 10¢, 5¢ and 1¢, respectively. They'll be represented by the symbols `H`, `Q`, `D`, `N` and `P` (symbols in Ruby, strings in in other languages)

The argument passed in will be an integer representing the value in cents. The return value should be a hash/dictionary/object with the symbols as keys, and the numbers of coins as values. Coins that are not used should not be included in the hash. If the argument passed in is 0, then the method should return an empty hash.

## Examples

```python
make_change(0)   #-->  {}
make_change(1)   #-->  {"P":1}
make_change(43)  #-->  {"Q":1, "D":1, "N":1, "P":3}
make_change(91)  #-->  {"H":1, "Q":1, "D":1, "N":1, "P":1}
```

#### **If you liked this kata, check out [Part 2](https://www.codewars.com/kata/making-change-part-2/ruby).**

Answer: {"fn_name": "make_change", "inputs": [[0], [1], [5], [43], [91], [101], [239]], "outputs": [[{}], [{"P": 1}], [{"N": 1}], [{"Q": 1, "D": 1, "N": 1, "P": 3}], [{"H": 1, "Q": 1, "D": 1, "N": 1, "P": 1}], [{"H": 2, "P": 1}], [{"H": 4, "Q": 1, "D": 1, "P": 4}]]}
user: The alphabetized kata
---------------------

Re-order the characters of a string, so that they are concatenated into a new string in "case-insensitively-alphabetical-order-of-appearance" order. Whitespace and punctuation shall simply be removed!

The input is restricted to contain no numerals and only words containing the english alphabet letters.

Example: 

```python
alphabetized("The Holy Bible") # "BbeehHilloTy"
```

_Inspired by [Tauba Auerbach](http://www.taubaauerbach.com/view.php?id=73)_

Answer: {"fn_name": "alphabetized", "inputs": [[""], [" "], [" a"], ["a "], [" a "], ["A b B a"], [" a b c d e f g h i j k l m n o p q r s t u v w x y z A B C D E F G H I J K L M N O P Q R S T U V W X Y Z"], ["!@$%^&*()_+=-`,"], ["The Holy Bible"], ["CodeWars can't Load Today"]], "outputs": [[""], [""], ["a"], ["a"], ["a"], ["AabB"], ["aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ"], [""], ["BbeehHilloTy"], ["aaaaCcdddeLnooorstTWy"]]}
user: A very easy task for you!

You have to create a method, that corrects a given date string.
There was a problem in addition, so many of the date strings are broken.
Date-Format is european. That means "DD.MM.YYYY".


Some examples:

"30.02.2016" -> "01.03.2016"
"40.06.2015" -> "10.07.2015"
"11.13.2014" -> "11.01.2015"
"99.11.2010" -> "07.02.2011"

If the input-string is null or empty return exactly this value!
If the date-string-format is invalid, return null.

Hint: Correct first the month and then the day!

Have fun coding it and please don't forget to vote and rank this kata! :-) 

I have created other katas. Have a look if you like coding and challenges.

Answer: {"fn_name": "date_correct", "inputs": [[null], [""], ["01112016"], ["01,11,2016"], ["0a.1c.2016"], ["03.12.2016"], ["30.02.2016"], ["40.06.2015"], ["11.13.2014"], ["33.13.2014"], ["99.11.2010"]], "outputs": [[null], [""], [null], [null], [null], ["03.12.2016"], ["01.03.2016"], ["10.07.2015"], ["11.01.2015"], ["02.02.2015"], ["07.02.2011"]]}
user: The aim of the kata is to try to show how difficult it can be to calculate decimals of an irrational number with a certain precision. We have chosen to get a few decimals of the number "pi" using
the following infinite series (Leibniz 1646–1716): 

PI / 4 = 1 - 1/3 + 1/5 - 1/7 + ... which gives an approximation of PI / 4.

http://en.wikipedia.org/wiki/Leibniz_formula_for_%CF%80

To have a measure of the difficulty we will count how many iterations are needed to calculate PI with a given precision. 

There are several ways to determine the precision of the calculus but to keep things easy we will calculate to within epsilon of your language Math::PI constant. In other words we will stop  the iterative process when the absolute value of the difference between our calculation and the Math::PI constant of the given language is less than epsilon.

Your function returns an array or an arrayList or a string or a tuple depending on the language (See sample tests) where your approximation of PI has 10 decimals 

In Haskell you can use the function "trunc10Dble" (see "Your solution"); in Clojure you can use the function "round" (see "Your solution");in OCaml or Rust the function "rnd10" (see "Your solution") in order to avoid discussions about the result.

Example :
```
your function calculates 1000 iterations and 3.140592653839794 but returns:
iter_pi(0.001) --> [1000, 3.1405926538]
```

Unfortunately, this series converges too slowly to be useful, 
as it takes over 300 terms to obtain a 2 decimal place precision. 
To obtain 100 decimal places of PI, it was calculated that
one would need to use at least 10^50 terms of this expansion!

About PI : http://www.geom.uiuc.edu/~huberty/math5337/groupe/expresspi.html

Answer: {"fn_name": "iter_pi", "inputs": [[0.1], [0.01], [0.001], [0.0001], [1e-05], [1e-06]], "outputs": [[[10, 3.0418396189]], [[100, 3.1315929036]], [[1000, 3.1405926538]], [[10000, 3.1414926536]], [[100001, 3.1416026535]], [[1000001, 3.1415936536]]]}