meetforever/GRPO_CL huggingface dataset:
user: Make your strings more nerdy: Replace all 'a'/'A' with 4, 'e'/'E' with 3 and 'l' with 1
e.g. "Fundamentals" --> "Fund4m3nt41s"


```if:csharp
Documentation:
Kata.Nerdify Method (String)

Nerdifies a string. Returns a copy of the original string with 'a'/'A' characters replaced with '4', 'e'/'E' characters replaced with '3', and 'l' characters replaced with '1'.

Syntax


public
static
string Nerdify(
string str
    )
  



Parameters

str

Type: System.String
The string to be nerdified.

Return Value

Type: System.String
  The nerdified string.


Exceptions



Exception
Condition

ArgumentNullException
str is null.



```

Answer: {"fn_name": "nerdify", "inputs": [["Fund4m3nt41s"], ["Seven"], ["Los Angeles"], ["Seoijselawuue"]], "outputs": [["Fund4m3nt41s"], ["S3v3n"], ["Los 4ng313s"], ["S3oijs314wuu3"]]}
user: # Task
 Fred Mapper is considering purchasing some land in Louisiana to build his house on. In the process of investigating the land, he learned that the state of Louisiana is actually shrinking by 50 square miles each year, due to erosion caused by the Mississippi River. Since Fred is hoping to live in this house the rest of his life, he needs to know if his land is going to be lost to erosion.

 After doing more research, Fred has learned that the land that is being lost forms a semicircle. This semicircle is part of a circle centered at (0,0), with the line that bisects the circle being the `x` axis. Locations below the `x` axis are in the water. The semicircle has an area of 0 at the beginning of year 1. (Semicircle illustrated in the Figure.)

 ![](http://media.openjudge.cn/images/1005/semicircle.GIF)
 
 Given two coordinates `x` and `y`, your task is to calculate that Fred Mapper's house will begin eroding in how many years.
 
 Note:

 1. No property will appear exactly on the semicircle boundary: it will either be inside or outside. 

 2. All locations are given in miles.
 
 3. (0,0) will not be given.

# Example

 For `x = 1, y = 1`, the result should be `1`.
 
 After 1 year, Fred Mapper's house will begin eroding.
 
 For `x = 25, y = 0`, the result should be `20`.
 
 After 20 year, Fred Mapper's house will begin eroding.
 
# Input/Output


 - `[input]` integer `x`

  The X coordinates of the land Fred is considering. It will be an integer  point numbers measured in miles. 
  
  `-100 <= x <= 100`
  
  
 - `[input]` integer `y`

  The Y coordinates of the land Fred is considering. It will be an integer point numbers measured in miles. 
  
  `0 <= y <= 100`
  
  
 - `[output]` an integer
 
 The first year (start from 1) this point will be within the semicircle AT THE END OF YEAR.

Answer: {"fn_name": "does_fred_need_houseboat", "inputs": [[1, 1], [25, 0]], "outputs": [[1], [20]]}
user: Given a time in AM/PM format as a string, convert it to military (24-hour) time as a string.

Midnight is 12:00:00AM on a 12-hour clock, and 00:00:00 on a 24-hour clock. Noon is 12:00:00PM on a 12-hour clock, and 12:00:00 on a 24-hour clock


Sample Input: 07:05:45PM
Sample Output: 19:05:45

Try not to use built in DateTime libraries.

For more information on military time, check the wiki https://en.wikipedia.org/wiki/24-hour_clock#Military_time

Answer: {"fn_name": "get_military_time", "inputs": [["12:00:01AM"], ["01:02:03AM"], ["02:04:05AM"], ["03:06:07AM"], ["04:08:09AM"], ["05:10:11AM"], ["06:12:13AM"], ["07:14:15AM"], ["08:16:17AM"], ["09:18:19AM"], ["10:20:21AM"], ["11:22:23AM"], ["12:24:25PM"], ["01:26:27PM"], ["02:28:29PM"], ["03:30:31PM"], ["04:32:33PM"], ["05:34:35PM"], ["06:36:37PM"], ["07:38:39PM"], ["08:40:41PM"], ["09:42:43PM"], ["10:44:45PM"], ["11:46:47PM"]], "outputs": [["00:00:01"], ["01:02:03"], ["02:04:05"], ["03:06:07"], ["04:08:09"], ["05:10:11"], ["06:12:13"], ["07:14:15"], ["08:16:17"], ["09:18:19"], ["10:20:21"], ["11:22:23"], ["12:24:25"], ["13:26:27"], ["14:28:29"], ["15:30:31"], ["16:32:33"], ["17:34:35"], ["18:36:37"], ["19:38:39"], ["20:40:41"], ["21:42:43"], ["22:44:45"], ["23:46:47"]]}
user: Two integers are coprimes if the their only greatest common divisor is 1.

## Task
In this kata you'll be given a number ```n >= 2``` and output a list with all positive integers less than ```gcd(n, k) == 1```, with ```k``` being any of the output numbers.

The list cannot include duplicated entries and has to be sorted.


## Examples
```
2 -> [1]
3 -> [1, 2]
6 -> [1, 5]
10 -> [1, 3, 7, 9]
20 -> [1, 3, 7, 9, 11, 13, 17, 19]
25 -> [1, 2, 3, 4, 6, 7, 8, 9, 11, 12, 13, 14, 16, 17, 18, 19, 21, 22, 23, 24]
30 -> [1, 7, 11, 13, 17, 19, 23, 29]
```

Answer: {"fn_name": "coprimes", "inputs": [[2], [3], [6], [10], [20], [25], [30]], "outputs": [[[1]], [[1, 2]], [[1, 5]], [[1, 3, 7, 9]], [[1, 3, 7, 9, 11, 13, 17, 19]], [[1, 2, 3, 4, 6, 7, 8, 9, 11, 12, 13, 14, 16, 17, 18, 19, 21, 22, 23, 24]], [[1, 7, 11, 13, 17, 19, 23, 29]]]}
user: Move every letter in the provided string forward 10 letters through the alphabet.

If it goes past 'z', start again at 'a'.

Input will be a string with length > 0.

Answer: {"fn_name": "move_ten", "inputs": [["testcase"], ["codewars"], ["exampletesthere"], ["returnofthespacecamel"], ["bringonthebootcamp"], ["weneedanofficedog"]], "outputs": [["docdmkco"], ["mynogkbc"], ["ohkwzvodocdrobo"], ["bodebxypdroczkmomkwov"], ["lbsxqyxdrolyydmkwz"], ["goxoonkxyppsmonyq"]]}
user: # Convert Improper Fraction to Mixed Number

You will need to convert an [improper fraction](https://www.mathplacementreview.com/arithmetic/fractions.php#improper-fractions) to a [mixed number](https://www.mathplacementreview.com/arithmetic/fractions.php#mixed-number). For example:

```python
get_mixed_num('18/11') # Should return '1 7/11'
get_mixed_num('13/5') # Should return '2 3/5'
get_mixed_num('75/10') # Should return '7 5/10'
```

NOTE: All fractions will be greater than 0.

Answer: {"fn_name": "get_mixed_num", "inputs": [["18/11"], ["13/5"], ["75/10"]], "outputs": [["1 7/11"], ["2 3/5"], ["7 5/10"]]}
user: # Sentence Smash

Write a function that takes an array of words and smashes them together into a sentence and returns the sentence. You can ignore any need to sanitize words or add punctuation, but you should add spaces between each word. **Be careful, there shouldn't be a space at the beginning or the end of the sentence!**

## Example

```
['hello', 'world', 'this', 'is', 'great']  =>  'hello world this is great'
```

Answer: {"fn_name": "smash", "inputs": [[[]], [["hello"]], [["hello", "world"]], [["hello", "amazing", "world"]], [["this", "is", "a", "really", "long", "sentence"]]], "outputs": [[""], ["hello"], ["hello world"], ["hello amazing world"], ["this is a really long sentence"]]}
user: The [Chinese zodiac](https://en.wikipedia.org/wiki/Chinese_zodiac) is a repeating cycle of 12 years, with each year being represented by an animal and its reputed attributes. The lunar calendar is divided into cycles of 60 years each, and each year has a combination of an animal and an element. There are 12 animals and 5 elements; the animals change each year, and the elements change every 2 years. The current cycle was initiated in the year of 1984 which was the year of the Wood Rat.

Since the current calendar is Gregorian, I will only be using years from the epoch 1924.
*For simplicity I am counting the year as a whole year and not from January/February to the end of the year.*

##Task

Given a year, return the element and animal that year represents ("Element Animal"). 
For example I'm born in 1998 so I'm an "Earth Tiger".


```animals``` (or ```$animals``` in Ruby) is a preloaded array containing the animals in order:

```['Rat', 'Ox', 'Tiger', 'Rabbit', 'Dragon', 'Snake', 'Horse', 'Goat', 'Monkey', 'Rooster', 'Dog', 'Pig']```


```elements``` (or ```$elements``` in Ruby) is a preloaded array containing the elements in order:


```['Wood', 'Fire', 'Earth', 'Metal', 'Water']```

Tell me your zodiac sign and element in the comments. Happy coding :)

Answer: {"fn_name": "chinese_zodiac", "inputs": [[1965], [1938], [1998], [2016], [1924], [1968], [2162], [6479], [3050], [6673], [6594], [9911], [2323], [3448], [1972]], "outputs": [["Wood Snake"], ["Earth Tiger"], ["Earth Tiger"], ["Fire Monkey"], ["Wood Rat"], ["Earth Monkey"], ["Water Dog"], ["Earth Goat"], ["Metal Dog"], ["Water Rooster"], ["Wood Tiger"], ["Metal Goat"], ["Water Rabbit"], ["Earth Rat"], ["Water Rat"]]}
user: For a given array whose element values are randomly picked from single-digit integers `0` to `9`, return an array with the same digit order but all `0`'s paired. Paring two `0`'s generates one `0` at the location of the first.

Ex:
```python
pair_zeros([0, 1, 0, 2])
# paired: ^-----^ cull second zero
       == [0, 1, 2];
#   kept: ^

pair_zeros([0, 1, 0, 0])
# paired: ^-----^
       == [0, 1,    0];
#   kept: ^

pair_zeros([1, 0, 7, 0, 1])
# paired:    ^-----^
       == [1, 0, 7,    1];
#   kept:    ^

pair_zeros([0, 1, 7, 0, 2, 2, 0, 0, 1, 0])
# paired: ^--------^ 
#        [0, 1, 7,    2, 2, 0, 0, 1, 0]
#   kept: ^         paired: ^--^
       == [0, 1, 7,    2, 2, 0,    1, 0];
#   kept:                   ^
```

Here are the 2 important rules:

1. Pairing happens from left to right in the array. However, for each pairing, the "second" `0` will always be paired towards the first (right to left)
2. `0`'s generated by pairing can NOT be paired again

Answer: {"fn_name": "pair_zeros", "inputs": [[[]], [[1]], [[1, 2, 3]], [[0]], [[0, 0]], [[1, 0, 1, 0, 2, 0, 0]], [[0, 0, 0]], [[1, 0, 1, 0, 2, 0, 0, 3, 0]], [[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]], [[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]], "outputs": [[[]], [[1]], [[1, 2, 3]], [[0]], [[0]], [[1, 0, 1, 2, 0]], [[0, 0]], [[1, 0, 1, 2, 0, 3, 0]], [[0, 0, 0, 0, 0, 0]], [[0, 0, 0, 0, 0, 0, 0]]]}
user: ```if:javascript
`Array.prototype.length` will give you the number of top-level elements in an array.
```
```if:ruby
`Array#length` will give you the number of top-level elements in an array.
```
```if:csharp
The `Length` property of an array will give you the number of top-level elements in an array.
```
```if:php
`count()` will give you the number of top-level elements in an array if exactly one argument `$a` is passed in which is the array.
```
```if:python
`len(a)` will give you the number of top-level elements in the list/array named `a`.
```

Your task is to create a function ```deepCount``` that returns the number of ALL elements within an array, including any within inner-level arrays.

For example:

```if:javascript
    deepCount([1, 2, 3]);  
    //>>>>> 3
    deepCount(["x", "y", ["z"]]);  
    //>>>>> 4
    deepCount([1, 2, [3, 4, [5]]]);  
    //>>>>> 7
```
```if:ruby
    deepCount([1, 2, 3]);  
    //>>>>> 3
    deepCount(["x", "y", ["z"]]);  
    //>>>>> 4
    deepCount([1, 2, [3, 4, [5]]]);  
    //>>>>> 7
```
```if:csharp
    deepCount([1, 2, 3]);  
    //>>>>> 3
    deepCount(["x", "y", ["z"]]);  
    //>>>>> 4
    deepCount([1, 2, [3, 4, [5]]]);  
    //>>>>> 7
```
```if:php
    deep_c([1, 2, 3]);
    //>>>>> 3
    deep_c(["x", "y", ["z"]]);
    //>>>>> 4
    deep_c([1, 2, [3, 4, [5]]]);
    //>>>>> 7
```
```if:python
    deepCount([1, 2, 3]);  
    //>>>>> 3
    deepCount(["x", "y", ["z"]]);  
    //>>>>> 4
    deepCount([1, 2, [3, 4, [5]]]);  
    //>>>>> 7
```

The input will always be an array.

```if:php
In PHP you may *not* assume that the array passed in will be non-associative.

Please note that `count()`, `eval()` and `COUNT_RECURSIVE` are disallowed - you should be able to implement the logic for `deep_c()` yourself ;)
```

Answer: {"fn_name": "deep_count", "inputs": [[[]], [[1, 2, 3]], [["x", "y", ["z"]]], [[1, 2, [3, 4, [5]]]], [[[[[[[[[[]]]]]]]]]], [["a"]], [[["a"]]], [[["a"], []]], [["[a]"]], [[[[[[[[[["Everybody!"]]]]]]]]]], [["cat", [["dog"]], ["[bird]"]]]], "outputs": [[0], [3], [4], [7], [8], [1], [2], [3], [1], [9], [6]]}
user: Given a certain integer  ```n, n > 0```and a number of partitions,  ```k, k > 0```; we want to know the partition which has the maximum or minimum product of its terms.

The function ```find_spec_partition() ```, will receive three arguments,  ```n```,  ```k```, and a command:  ```'max' or 'min'```

The function should output the partition that has maximum or minimum value product (it depends on the given command) as an array with its terms in decreasing order.

Let's see some cases (Python and Ruby)
```
find_spec_partition(10, 4, 'max') == [3, 3, 2, 2]
find_spec_partition(10, 4, 'min') == [7, 1, 1, 1]
```
and Javascript:
```
findSpecPartition(10, 4, 'max') == [3, 3, 2, 2]
findSpecPartition(10, 4, 'min') == [7, 1, 1, 1]
```
The partitions of 10 with 4 terms with their products are:
```
(4, 3, 2, 1): 24
(4, 2, 2, 2): 32
(6, 2, 1, 1): 12
(3, 3, 3, 1): 27
(4, 4, 1, 1): 16
(5, 2, 2, 1): 20 
(7, 1, 1, 1): 7   <------- min. productvalue
(3, 3, 2, 2): 36  <------- max.product value
(5, 3, 1, 1): 15
```
Enjoy it!

Answer: {"fn_name": "find_spec_partition", "inputs": [[10, 4, "max"], [10, 4, "min"]], "outputs": [[[3, 3, 2, 2]], [[7, 1, 1, 1]]]}
user: Regex Failure - Bug Fixing #2
Oh no, Timmy's received some hate mail recently but he knows better. Help Timmy fix his regex filter so he can be awesome again!

Answer: {"fn_name": "filter_words", "inputs": [["You're Bad! timmy!"], ["You're MEAN! timmy!"], ["You're UGLY!! timmy!"], ["You're horrible! timmy!"], ["You're HiDeOuS!! timmy!"]], "outputs": [["You're awesome! timmy!"], ["You're awesome! timmy!"], ["You're awesome!! timmy!"], ["You're awesome! timmy!"], ["You're awesome!! timmy!"]]}
user: Let be `n` an integer prime with `10` e.g. `7`. 

`1/7 = 0.142857 142857 142857 ...`.

We see that the decimal part has a cycle: `142857`. The length of this cycle is `6`. In the same way:

`1/11 = 0.09 09 09 ...`. Cycle length is `2`.

# Task

Given an integer n (n > 1), the function cycle(n) returns the length of the cycle if n and 10 are coprimes, otherwise returns -1.

# Examples:
```
cycle(5) = -1
cycle(13) = 6 -> 0.076923 076923 0769
cycle(21) = 6 -> 0.047619 047619 0476
cycle(27) = 3 -> 0.037 037 037 037 0370
cycle(33) = 2 -> 0.03 03 03 03 03 03 03 03
cycle(37) = 3 -> 0.027 027 027 027 027 0
cycle(94) = -1 

cycle(22) = -1 since 1/22 ~ 0.0 45 45 45 45 ...
```

Answer: {"fn_name": "cycle", "inputs": [[3], [33], [18118], [69], [197], [65], [97], [19], [111], [53], [59], [93], [51], [159], [183], [167], [94], [133], [218713], [38127], [431541], [221193], [1234567]], "outputs": [[1], [2], [-1], [22], [98], [-1], [96], [18], [3], [13], [58], [15], [16], [13], [60], [166], [-1], [18], [9744], [6230], [726], [3510], [34020]]}
user: Below is a right-angled triangle:

```
  |\
  | \
  |  \
  |   \ 
o |    \ h 
  |     \
  |    θ \
  |_______\ 
     a
```

Your challange is to write a function (```missingAngle``` in C/C#, ```missing_angle``` in Ruby), that calculates the angle θ in degrees to the nearest integer. You will be given three arguments representing each side: o, h and a. One of the arguments equals zero. Use the length of the two other sides to calculate θ. You will not be expected to handle any erronous data in your solution.

Answer: {"fn_name": "missing_angle", "inputs": [[0, 400, 300], [5, 4, 0], [8, 0, 5], [16.7, 0, 12.3], [7, 5, 0]], "outputs": [[37], [37], [39], [47], [44]]}
user: ## Task
To charge your mobile phone battery, do you know how much time it takes from 0% to 100%? It depends on your cell phone battery capacity and the power of the charger. A rough calculation method is:

```
0% --> 85%  (fast charge)
(battery capacity(mAh) * 85%) / power of the charger(mA)

85% --> 95% (decreasing charge)
(battery capacity(mAh) * 10%) / (power of the charger(mA) * 50%)

95% --> 100% (trickle charge)
(battery capacity(mAh) * 5%) / (power of the charger(mA) * 20%)
```
For example: Your battery capacity is 1000 mAh and you use a charger 500 mA,  to charge your mobile phone battery from 0% to 100% needs time:

```
0% --> 85%  (fast charge) 1.7 (hour)

85% --> 95% (decreasing charge) 0.4 (hour)

95% --> 100% (trickle charge) 0.5 (hour)

total times = 1.7 + 0.4 + 0.5 = 2.6 (hour)
```

 Complete function `calculateTime` that accepts two arguments `battery` and `charger`, return how many hours can charge the battery from 0% to 100%. The result should be a number, round to 2 decimal places (In Haskell, no need to round it).

Answer: {"fn_name": "calculate_time", "inputs": [[1000, 500], [1500, 500], [2000, 1000], [5000, 1000], [1000, 5000], [3050, 2600]], "outputs": [[2.6], [3.9], [2.6], [6.5], [0.26], [1.53]]}
user: # The Invitation

Most of us played with toy blocks growing up. It was fun and you learned stuff. So what else can you do but rise to the challenge when a 3-year old exclaims, "Look, I made a square!", then pointing to a pile of blocks, "Can _you_ do it?"

# These Blocks

Just to play along, of course we'll be viewing these blocks in two dimensions. Depth now being disregarded, it turns out the pile has four different sizes of block: `1x1`, `1x2`, `1x3`, and `1x4`. The smallest one represents the area of a square, the other three are rectangular, and all differ by their width. Integers matching these four widths are used to represent the blocks in the input.

# This Square

Well, the kid made a `4x4` square from this pile, so you'll have to match that. Noticing the way they fit together, you realize the structure must be built in fours rows, one row at a time, where the blocks must be placed horizontally. With the known types of block, there are five types of row you could build:

* 1 four-unit block
* 1 three-unit block plus 1 one-unit bock (in either order)
* 2 two-unit blocks
* 1 two-unit block plus 2 one-unit blocks (in any order)
* 4 one-unit blocks

Amounts for all four of the block sizes in the pile will each vary from `0` to `16`. The total size of the pile will also vary from `0` to `16`. The order of rows is irrelevant. A valid square doesn't have to use up all the given blocks.

# Some Examples

Given `1, 3, 2, 2, 4, 1, 1, 3, 1, 4, 2` there are many ways you could construct a square. Here are three possibilities, as described by their four rows:

* 1 four-unit block
* 2 two-unit blocks
* 1 four-unit block
* 4 one-unit blocks
>
* 1 three-unit block plus 1 one-unit block
* 2 two-unit blocks
* 1 four-unit block
* 1 one-unit block plus 1 three-unit block
>
* 2 two-unit blocks
* 1 three-unit block plus 1 one-unit block
* 1 four-unit block
* 2 one-unit blocks plus 1 two-unit block
>

Given `1, 3, 2, 4, 3, 3, 2` there is no way to complete the task, as you could only build three rows of the correct length. The kid will not be impressed.

* 2 two-unit blocks
* 1 three-unit block plus 1 one-unit block
* 1 four-unit block
* (here only sadness)
>

# Input
```python
blocks ~ a random list of integers (1 <= x <= 4)
```
# Output
```python
True or False ~ whether you can build a square
```
# Enjoy!

If interested, I also have [this kata](https://www.codewars.com/kata/5cb7baa989b1c50014a53333) as well as [this other kata](https://www.codewars.com/kata/5cb5eb1f03c3ff4778402099) to consider solving.

Answer: {"fn_name": "build_square", "inputs": [[[1, 1, 1, 1, 1, 1, 1, 2, 3, 4]], [[1, 3, 2, 2, 4, 1, 1, 3, 1, 4, 2]], [[1, 3, 2, 4, 3, 3, 2]], [[2, 2, 3, 3, 3, 3, 3, 3, 3, 4, 4]], [[1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]], [[3, 1, 3, 1, 3, 1, 3, 2]], [[1, 3, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1]], [[4, 2, 2, 1, 1, 1, 1, 3, 3, 3, 1]], [[1, 2, 3, 4, 1, 2, 2, 1]], [[]]], "outputs": [[true], [true], [false], [false], [true], [false], [false], [true], [true], [false]]}
user: Every natural number, ```n```, may have a prime factorization like:



We define the arithmetic derivative of ```n```, ```n'``` the value of the expression:



Let's do the calculation for ```n = 231525```.
```
231525 = 3³5²7³ 
n' = (3*3²)*5²7³ + 3³*(2*5)*7³ + 3³*5²*(3*7²) = 231525 + 92610 + 99225 = 423360
```
We may make a chain of arithmetic derivatives, starting from a number we apply to the result the transformation and so on until we get the result ```1```.
```
n ---> n'  ---> (n')' ---> ((n')')' ---> ..... ---> ((...(n')...)')'
```
Let's do it starting with our number, ```n = 231525``` and making a chain of 5 terms:
```
231525 ---> 423360 ---> 1899072 ---> 7879680 ---> 51895296
```
We need a function ```chain_arith_deriv()``` that receives two arguments: ```start``` and ```k```, amount of terms of the chain.

The function should output the chain in an array format:
```
chain_arith_deriv(start, k) ---> [start, term1, term2, .....term(k-1)] # a total of k-terms
```
For the case presented above:
```python
chain_arith_deriv(231525, 5) == [231525, 423360, 1899072, 7879680, 51895296]
```
The function has to reject prime numbers giving an alerting message
```python
chain_arith_deriv(997, 5) == "997 is a prime number"
```
Features of the tests:
```
Number of Random Tests: 50
1000 ≤ start ≤ 99000000
3 ≤ k ≤ 15
```
Enjoy it and do your best!

Answer: {"fn_name": "chain_arith_deriv", "inputs": [[231525, 5], [997, 5]], "outputs": [[[231525, 423360, 1899072, 7879680, 51895296]], ["997 is a prime number"]]}
user: Find the total sum of internal angles (in degrees) in an n-sided simple polygon. N will be greater than 2.

Answer: {"fn_name": "angle", "inputs": [[3], [4]], "outputs": [[180], [360]]}
user: We have an array of unique elements. A special kind of permutation is the one that has all of its elements in a different position than the original.

Let's see how many of these permutations may be generated from an array of four elements. We put the original array with square brackets and the wanted permutations with parentheses. 
```
arr = [1, 2, 3, 4]
      (2, 1, 4, 3)
      (2, 3, 4, 1)
      (2, 4, 1, 3)
      (3, 1, 4, 2)
      (3, 4, 1, 2)
      (3, 4, 2, 1)
      (4, 1, 2, 3)
      (4, 3, 1, 2)
      (4, 3, 2, 1)
      _____________
A total of 9 permutations with all their elements in different positions than arr
```

The task for this kata would be to create a code to count all these permutations for an array of certain length.

Features of the random tests:
```
l = length of the array
10 ≤ l ≤ 5000
```

See the example tests.

Enjoy it!

Answer: {"fn_name": "all_permuted", "inputs": [[1], [4], [30]], "outputs": [[0], [9], [97581073836835777732377428235481]]}
user: Take 2 strings `s1` and `s2` including only letters from `a`to `z`.
Return a new **sorted** string, the longest possible, containing distinct letters,
- each taken only once - coming from s1 or s2.

# Examples:
```
a = "xyaabbbccccdefww"
b = "xxxxyyyyabklmopq"
longest(a, b) -> "abcdefklmopqwxy"

a = "abcdefghijklmnopqrstuvwxyz"
longest(a, a) -> "abcdefghijklmnopqrstuvwxyz"
```

Answer: {"fn_name": "longest", "inputs": [["aretheyhere", "yestheyarehere"], ["loopingisfunbutdangerous", "lessdangerousthancoding"], ["inmanylanguages", "theresapairoffunctions"], ["lordsofthefallen", "gamekult"], ["codewars", "codewars"], ["agenerationmustconfrontthelooming", "codewarrs"]], "outputs": [["aehrsty"], ["abcdefghilnoprstu"], ["acefghilmnoprstuy"], ["adefghklmnorstu"], ["acdeorsw"], ["acdefghilmnorstuw"]]}
user: Four-digit palindromes start with `[1001,1111,1221,1331,1441,1551,1551,...]` and the number at position `2` is `1111`.  

You will be given two numbers `a` and `b`. Your task is to return the `a-digit` palindrome at position `b` if the palindromes were arranged in increasing order. 

Therefore, `palin(4,2) = 1111`, because that is the second element of the `4-digit` palindrome series.

More examples in the test cases. Good luck!

If you like palindrome Katas, please try:

[Palindrome integer composition](https://www.codewars.com/kata/599b1a4a3c5292b4cc0000d5)

[Life without primes](https://www.codewars.com/kata/59f8750ac374cba8f0000033)

Answer: {"fn_name": "palin", "inputs": [[2, 2], [3, 10], [4, 5], [5, 19], [6, 3], [6, 20], [7, 3]], "outputs": [[22], [191], [1441], [11811], [102201], [119911], [1002001]]}
user: Create a function that takes a number and finds the factors of it, listing them in **descending** order in an **array**.

If the parameter is not an integer or less than 1, return `-1`. In C# return an empty array.

For Example:
`factors(54)` should return `[54, 27, 18, 9, 6, 3, 2, 1]`

Answer: {"fn_name": "factors", "inputs": [[-4], [0], [-12], ["a"], [4.5], ["hello world"], [54], [49], [1]], "outputs": [[-1], [-1], [-1], [-1], [-1], [-1], [[54, 27, 18, 9, 6, 3, 2, 1]], [[49, 7, 1]], [[1]]]}