meetforever/GRPO_CL huggingface dataset:
user: Mr. Square is going on a holiday. He wants to bring 2 of his favorite squares with him, so he put them in his rectangle suitcase.

Write a function that, given the size of the squares and the suitcase, return whether the squares can fit inside the suitcase.
```Python
fit_in(a,b,m,n)
a,b are the sizes of the 2 squares
m,n are the sizes of the suitcase
```

# Example
```Python
fit_in(1,2,3,2) should return True
fit_in(1,2,2,1) should return False
fit_in(3,2,3,2) should return False
fit_in(1,2,1,2) should return False
```

Answer: {"fn_name": "fit_in", "inputs": [[1, 2, 3, 2], [1, 2, 2, 1], [3, 2, 3, 2], [1, 2, 1, 2], [6, 5, 8, 7], [6, 6, 12, 6], [7, 1, 7, 8], [10, 10, 11, 11], [7, 2, 9, 7], [7, 2, 8, 7], [4, 1, 5, 3], [1, 2, 3, 4], [1, 2, 4, 3], [1, 3, 2, 4], [1, 3, 4, 2], [1, 4, 2, 3], [1, 4, 3, 2], [2, 1, 3, 4], [2, 1, 4, 3], [2, 3, 1, 4], [2, 3, 4, 1], [2, 4, 1, 3], [2, 4, 3, 1], [3, 2, 1, 4], [3, 2, 4, 1], [3, 1, 2, 4], [3, 1, 4, 2], [3, 4, 2, 1], [3, 4, 1, 2], [4, 2, 3, 1], [4, 2, 1, 3], [4, 3, 2, 1], [4, 3, 1, 2], [4, 1, 2, 3], [4, 1, 3, 2]], "outputs": [[true], [false], [false], [false], [false], [true], [true], [false], [true], [false], [false], [true], [true], [false], [false], [false], [false], [true], [true], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false]]}
user: The integer ```64``` is the first integer that has all of its digits even and furthermore, is a perfect square.

The second one is ```400``` and the third one ```484```.

Give the numbers of this sequence that are in the range ```[a,b] ```(both values inclusive)

Examples:
``` python
even_digit_squares(100, 1000) == [400, 484] # the output should be sorted.
even_digit_squares(1000, 4000) == []
``` 

Features of the random tests for ```even_digit_squares(a, b)```
```
number of Tests = 167
maximum value for a = 1e10
maximum value for b = 1e12
```
You do not have to check the entries, ```a``` and ```b``` always positive integers and ```a < b``` 

Happy coding!!

Answer: {"fn_name": "even_digit_squares", "inputs": [[100, 1000], [1000, 4000], [10000, 40000]], "outputs": [[[400, 484]], [[]], [[26244, 28224, 40000]]]}
user: ## Number of people in the bus
There is a bus moving in the city, and it takes and drop some people in each bus stop.

You are provided with a list (or array) of integer arrays (or tuples). Each integer array has two items which represent number of people get into bus (The first item) and number of people get off the bus (The second item) in a bus stop.

Your task is to return number of people who are still in the bus after the last bus station (after the last array). Even though it is the last bus stop, the bus is not empty and some people are still in the bus, and they are probably sleeping there :D 

Take a look on the test cases.

Please keep in mind that the test cases ensure that the number of people in the bus is always >= 0. So the return integer can't be negative.

The second value in the first integer array is 0, since the bus is empty in the first bus stop.

Answer: {"fn_name": "number", "inputs": [[[[10, 0], [3, 5], [5, 8]]], [[[3, 0], [9, 1], [4, 10], [12, 2], [6, 1], [7, 10]]], [[[3, 0], [9, 1], [4, 8], [12, 2], [6, 1], [7, 8]]], [[[0, 0]]]], "outputs": [[5], [17], [21], [0]]}
user: A very passive-aggressive co-worker of yours was just fired. While he was gathering his things, he quickly inserted a bug into your system which renamed everything to what looks like jibberish. He left two notes on his desk, one reads: "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz" while the other reads: "Uif usjdl up uijt lbub jt tjnqmf kvtu sfqmbdf fwfsz mfuufs xjui uif mfuufs uibu dpnft cfgpsf ju".


Rather than spending hours trying to find the bug itself, you decide to try and decode it. 


If the input is not a string, your function must return "Input is not a string". Your function must be able to handle capital and lower case letters. You will not need to worry about punctuation.

Answer: {"fn_name": "one_down", "inputs": [["Ifmmp"], ["Uif usjdl up uijt lbub jt tjnqmf"], [45], ["XiBu BcPvU dSbAz UfYu"], [["Hello there", "World"]], ["BMM DBQT NBZCF"], ["qVAamFt BsF gVo"], ["CodeWars RockZ"], [""], ["J ipqf zpv bsf ibwjoh b ojdf ebz"]], "outputs": [["Hello"], ["The trick to this kata is simple"], ["Input is not a string"], ["WhAt AbOuT cRaZy TeXt"], ["Input is not a string"], ["ALL CAPS MAYBE"], ["pUZzlEs ArE fUn"], ["BncdVzqr QnbjY"], [""], ["I hope you are having a nice day"]]}
user: An array is defined to be `odd-heavy` if it contains at least one odd element and every element whose value is `odd` is greater than 
every even-valued element. 

eg.
```
Array [11,4,9,2,8] is odd-heavy 
because:- its odd elements [11,9] are greater than all the even elements [4,2,8]

Array [11,4,9,2,3,10] is not odd-heavy
because:- one of it's even element 10 from [4,2,10] is greater than two of its odd elements [9,3] from [ 11,9,3]

```
write a function called `isOddHeavy` or `is_odd_heavy` that accepts an integer array and returns `true` if the array is `odd-heavy` else return `false`.

Answer: {"fn_name": "is_odd_heavy", "inputs": [[[0, 2, 19, 4, 4]], [[1, -2, -1, 2]], [[-3, 2, 1, 3, -1, -2]], [[3, 4, -2, -3, -2]], [[-1, 1, -2, 2, -2, -2, -4, 4]], [[-1, -2, 21]], [[0, 0, 0, 0]], [[0, -1, 1]], [[0, 2, 3]], [[0]], [[]], [[1]], [[0, 1, 2, 3, 4, 0, -2, -1, -4, -3]], [[1, -1, 3, -1]], [[1, -1, 2, -2, 3, -3, 0]], [[3]], [[2, 4, 6]], [[-2, -4, -6, -8, -11]]], "outputs": [[true], [false], [false], [false], [false], [true], [false], [false], [true], [false], [false], [true], [false], [true], [false], [true], [false], [false]]}
user: Debug the functions
Should be easy, begin by looking at the code. Debug the code and the functions should work.
There are three functions: ```Multiplication (x)``` ```Addition (+)``` and ```Reverse (!esreveR)```

i {
  font-size:16px;
}

#heading {
  padding: 2em;
  text-align: center;
  background-color: #0033FF;
  width: 100%;
  height: 5em;
}

Answer: {"fn_name": "multi", "inputs": [[[8, 2, 5]]], "outputs": [[80]]}
user: _A mad sociopath scientist just came out with a brilliant invention! He extracted his own memories to forget all the people he hates! Now there's a lot of information in there, so he needs your talent as a developer to automatize that task for him._

> You are given the memories as a string containing people's surname and name (comma separated). The scientist marked one occurrence of each of the people he hates by putting a '!' right before their name.

**Your task is to destroy all the occurrences of the marked people.
One more thing ! Hate is contagious, so you also need to erase any memory of the person that comes after any marked name!**

---
Examples
---
---
Input:
```
"Albert Einstein, !Sarah Connor, Marilyn Monroe, Abraham Lincoln, Sarah Connor, Sean Connery, Marilyn Monroe, Bjarne Stroustrup, Manson Marilyn, Monroe Mary"
```
Output:
```
"Albert Einstein, Abraham Lincoln, Sean Connery, Bjarne Stroustrup, Manson Marilyn, Monroe Mary"
```
=> We must remove every memories of Sarah Connor because she's marked, but as a side-effect we must also remove all the memories about Marilyn Monroe that comes right after her! Note that we can't destroy the memories of Manson Marilyn or Monroe Mary, so be careful!

Answer: {"fn_name": "select", "inputs": [["Bryan Joubert"], ["Jesse Cox, !Selena Gomez"], ["!Eleena Daru, Obi-Wan Kenobi, Eleena Daru, Jar-Jar Binks"], ["Digital Daggers, !Kiny Nimaj, Rack Istley, Digital Daggers, Digital Daggers"], ["Albert Einstein, !Sarah Connor, Marilyn Monroe, Abraham Lincoln, Sarah Connor, Sean Connery, Marilyn Monroe, Bjarne Stroustrup, Manson Marilyn, Monroe Mary"], ["!Partha Ashanti, !Mindaugas Burton, Stacy Thompson, Amor Hadrien, !Ahtahkakoop Sothy, Partha Ashanti, Uzi Griffin, Partha Ashanti, !Serhan Eutimio, Amor Hadrien, Noor Konstantin"], ["!Code Wars, !Doug Smith, !Cyril Lemaire, !Codin Game"]], "outputs": [["Bryan Joubert"], ["Jesse Cox"], ["Jar-Jar Binks"], ["Digital Daggers, Digital Daggers, Digital Daggers"], ["Albert Einstein, Abraham Lincoln, Sean Connery, Bjarne Stroustrup, Manson Marilyn, Monroe Mary"], ["Uzi Griffin, Noor Konstantin"], [""]]}
user: Compare two strings by comparing the sum of their values (ASCII character code).

* For comparing treat all letters as UpperCase
* `null/NULL/Nil/None` should be treated as empty strings
* If the string contains other characters than letters, treat the whole string as it would be empty

Your method should return `true`, if the strings are equal and `false` if they are not equal.

## Examples:
```
"AD", "BC"  -> equal
"AD", "DD"  -> not equal
"gf", "FG"  -> equal
"zz1", ""   -> equal (both are considered empty)
"ZzZz", "ffPFF" -> equal
"kl", "lz"  -> not equal
null, ""    -> equal
```

Answer: {"fn_name": "compare", "inputs": [["AD", "BC"], ["AD", "DD"], ["gf", "FG"], ["Ad", "DD"], ["zz1", ""], ["ZzZz", "ffPFF"], ["kl", "lz"], [null, ""], ["!!", "7476"], ["##", "1176"]], "outputs": [[true], [false], [true], [false], [true], [true], [false], [true], [true], [true]]}
user: # Task
`Triangular numbers` are defined by the formula `n * (n + 1) / 2` with `n` starting from 1. They count the number of objects that can form an equilateral triangle as shown in the picture below:

![](https://i.gyazo.com/eec11cc9e17a31324338edc4eb7bb746.png)

So the sequence of triangular numbers begins as follows:

`1, 3, 6, 10, 15, 21, 28, ....`

It is proven that the sum of squares of any two consecutive triangular numbers is equal to another triangular number.

You're given a triangular number `n`. Return `true` if it can be represented as `a sum of squares of two consecutive triangular numbers`, or `false` otherwise.


# Input/Output

`[input]` integer `n`

A positive triangular number

`3 ≤ n ≤ 10^9`

`[output]` a boolean value

`true` if it is possible to represent n as the sum of squares of two consecutive triangular numbers, and `false` otherwise.

# Example

For `n = 6`, the output should be `false`.

No two squared consecutive triangular numbers add up to 6.

For `n = 45`, the output should be `true`.

`3 * 3 + 6 * 6 = 9 + 36 = 45`

Answer: {"fn_name": "triangular_sum", "inputs": [[6], [28], [45], [105], [136], [190], [210], [5050], [300], [2080]], "outputs": [[false], [false], [true], [false], [true], [false], [false], [true], [false], [true]]}
user: Finish the solution so that it takes an input `n` (integer) and returns a string that is the decimal representation of the number grouped by commas after every 3 digits.

Assume: `0 <= n < 2147483647`

## Examples

```
       1  ->           "1"
      10  ->          "10"
     100  ->         "100"
    1000  ->       "1,000"
   10000  ->      "10,000"
  100000  ->     "100,000"
 1000000  ->   "1,000,000"
35235235  ->  "35,235,235"
```

Answer: {"fn_name": "group_by_commas", "inputs": [[1], [12], [123], [1234], [12345], [123456], [1234567], [12345678], [123456789], [1234567890]], "outputs": [["1"], ["12"], ["123"], ["1,234"], ["12,345"], ["123,456"], ["1,234,567"], ["12,345,678"], ["123,456,789"], ["1,234,567,890"]]}
user: Introduction

It's been more than 20 minutes since the negligent waiter has taken your order for the house special prime tofu steak with a side of chili fries.

Out of boredom, you start fiddling around with the condiments tray. To be efficient, you want to be familiar with the choice of sauces and spices before your order is finally served.

You also examine the toothpick holder and try to analyze its inner workings when - yikes - the holder's lid falls off and all 23 picks lay scattered on the table.

Being a good and hygiene oriented citizen, you decide not to just put them back in the holder. Instead of letting all the good wood go to waste, you start playing around with the picks.

In the first "round", you lay down one toothpick vertically. You've used a total of one toothpick.

In the second "round", at each end of the first toothpick, you add a perpendicular toothpick at its center point. You added two additional toothpicks for a total of three toothpicks.

In the next rounds, you continue to add perpendicular toothpicks to each free end of toothpicks already on the table.

With your 23 toothpicks, you can complete a total of six rounds:


You wonder if you'd be able to implement this sequence in your favorite programming language. Because your food still hasn't arrived, you decide to take out your laptop and start implementing...

Challenge
Implement a script that returns the amount of toothpicks needed to complete n amount of rounds of the toothpick sequence.

```
0 <= n <= 5000
```

Hint
You can attempt this brute force or get some inspiration from the math department.

Answer: {"fn_name": "toothpick", "inputs": [[0], [3], [16], [32], [49], [89], [327], [363], [366], [512], [656], [1038], [1052], [1222], [1235], [1302], [1735], [1757], [1974], [2048]], "outputs": [[0], [7], [171], [683], [1215], [3715], [52239], [60195], [62063], [174763], [209095], [699451], [700379], [757295], [762019], [832559], [1398915], [1443119], [2038207], [2796203]]}
user: # Task
 Suppose there are `n` people standing in a circle and they are numbered 1 through n in order. 
 
 Person 1 starts off with a sword and kills person 2. He then passes the sword to the next person still standing, in this case person 3. Person 3 then uses the sword to kill person 4, and passes it to person 5. This pattern continues around and around the circle until just one person remains.

 What is the number of this person? 

# Example: 

 For `n = 5`, the result should be `3`.
```
1 kills 2, passes to 3.
3 kills 4, passes to 5.
5 kills 1, passes to 3.
3 kills 5 and wins.```

# Input/Output


 - `[input]` integer `n`

  The number of people. 1 through n standing in a circle.
  
  `1 <= n <= 1e9`
  
  
 - `[output]` an integer

  The index of the last person standing.

Answer: {"fn_name": "circle_slash", "inputs": [[5], [11], [1], [2], [3], [4], [8], [16], [15], [31]], "outputs": [[3], [7], [1], [1], [3], [1], [1], [1], [15], [31]]}
user: The objective is to return all pairs of integers from a given array of integers that have a difference of 2.

The result array should be sorted in ascending order of values.

Assume there are no duplicate integers in the array. The order of the integers in the input array should not matter.


## Examples
~~~if-not:python
```
[1, 2, 3, 4]  should return [[1, 3], [2, 4]]

[4, 1, 2, 3]  should also return [[1, 3], [2, 4]]

[1, 23, 3, 4, 7] should return [[1, 3]]

[4, 3, 1, 5, 6] should return [[1, 3], [3, 5], [4, 6]]
```
~~~
~~~if:python
```
[1, 2, 3, 4]  should return [(1, 3), (2, 4)]

[4, 1, 2, 3]  should also return [(1, 3), (2, 4)]

[1, 23, 3, 4, 7] should return [(1, 3)]

[4, 3, 1, 5, 6] should return [(1, 3), (3, 5), (4, 6)]
```
~~~

Answer: {"fn_name": "twos_difference", "inputs": [[[1, 2, 3, 4]], [[1, 3, 4, 6]], [[0, 3, 1, 4]], [[4, 1, 2, 3]], [[6, 3, 4, 1, 5]], [[3, 1, 6, 4]], [[1, 3, 5, 6, 8, 10, 15, 32, 12, 14, 56]], [[1, 4, 7, 10]], [[]]], "outputs": [[[[1, 3], [2, 4]]], [[[1, 3], [4, 6]]], [[[1, 3]]], [[[1, 3], [2, 4]]], [[[1, 3], [3, 5], [4, 6]]], [[[1, 3], [4, 6]]], [[[1, 3], [3, 5], [6, 8], [8, 10], [10, 12], [12, 14]]], [[]], [[]]]}
user: Pirates have notorious difficulty with enunciating. They tend to blur all the letters together and scream at people.

At long last, we need a way to unscramble what these pirates are saying.

Write a function that will accept a jumble of letters as well as a dictionary, and output a list of words that the pirate might have meant.

For example:
```
grabscrab( "ortsp", ["sport", "parrot", "ports", "matey"] )
```

Should return `["sport", "ports"]`.

Return matches in the same order as in the dictionary. Return an empty array if there are no matches.

Good luck!

Answer: {"fn_name": "grabscrab", "inputs": [["trisf", ["first"]], ["oob", ["bob", "baobab"]], ["ainstuomn", ["mountains", "hills", "mesa"]], ["oolp", ["donkey", "pool", "horse", "loop"]], ["ortsp", ["sport", "parrot", "ports", "matey"]], ["ourf", ["one", "two", "three"]]], "outputs": [[["first"]], [[]], [["mountains"]], [["pool", "loop"]], [["sport", "ports"]], [[]]]}
user: We have the following sequence:
```python
f(0) = 0
f(1) = 1
f(2) = 1
f(3) = 2
f(4) = 4;
f(n) = f(n-1) + f(n-2) + f(n-3) + f(n-4) + f(n-5);
```

Your task is to give the number of total values for the odd terms of the sequence  up to the n-th term (included). (The number n (of n-th term) will be given as a positive integer)

The values 1 (one) is the only that is duplicated in the sequence and should be counted only once.

E.g. 
```
count_odd_pentaFib(5) -----> 1 # because the terms up to 5 are: 0, 1, 1, 2, 4, 8 (only 1 is odd and counted once)
```
Other examples:
```
 count_odd_pentaFib(10) ------> 3 #because the odds terms are: [1, 1, 31, 61] (three different values)

count_odd_pentaFib(15) ------> 5 # beacause the odd terms are: [1, 1, 31, 61, 1793, 3525] (five different values)
```
Good luck !!

(Your code should be fast. Many moderate high values will be waiting to test it.)

Answer: {"fn_name": "count_odd_pentaFib", "inputs": [[0], [1], [2]], "outputs": [[0], [1], [1]]}
user: Create a function `longer` that accepts a string and sorts the words in it based on their respective lengths in an ascending order. If there are two words of the same lengths, sort them alphabetically. Look at the examples below for more details.

```python
longer("Another Green World") => Green World Another
longer("Darkness on the edge of Town") => of on the Town edge Darkness
longer("Have you ever Seen the Rain") => the you Have Rain Seen ever
```

Assume that only only Alphabets will be entered as the input.
Uppercase characters have priority over lowercase characters. That is,
```python
longer("hello Hello") => Hello hello
```

Don't forget to rate this kata and leave your feedback!! 
Thanks

Answer: {"fn_name": "longer", "inputs": [["Another Green World"], ["Darkness on the edge of Town"], ["Have you ever Seen the Rain"], ["Like a Rolling Stone"], ["This will be our Year"], ["hello Hello"]], "outputs": [["Green World Another"], ["of on the Town edge Darkness"], ["the you Have Rain Seen ever"], ["a Like Stone Rolling"], ["be our This Year will"], ["Hello hello"]]}
user: You are stacking some boxes containing gold weights on top of each other. If a box contains more weight than the box below it, it will crash downwards and combine their weights. e.g. If we stack [2] on top of [1], it will crash downwards and become a single box of weight [3]
```
[2]
[1] --> [3]
```
Given an array of arrays, return the bottom row (i.e. the last array) after all crashings are complete.
```
crashing_weights([[1, 2, 3],  --> [[1, 2,  ],      [[1,  ,  ]],
                  [2, 3, 1],  -->  [2, 3, 4],  -->  [2, 2,  ],
                  [3, 1, 2]])      [3, 1, 2]]  -->  [3, 4, 6]]

therefore return [3, 4, 6]
```

## More details

boxes can be stacked to any height, and the crashing effect can snowball:
```
[3]
[2]     [5]
[4] --> [4] --> [9]
```
Crashing should always start from as high up as possible -- this can alter the outcome! e.g.
```
[3]                      [3]
[2]     [5]              [2]     [3]
[1] --> [1] --> [6], not [1] --> [3] 
```
Weights will always be integers. The matrix (array of arrays) may have any height or width > 1, and may not be square, but it will always be "nice" (all rows will have the same number of columns, etc).

Answer: {"fn_name": "crashing_weights", "inputs": [[[[1]]], [[[1, 2]]], [[[2], [1]]]], "outputs": [[[1]], [[1, 2]], [[3]]]}
user: ### Unfinished Loop - Bug Fixing #1

Oh no, Timmy's created an infinite loop! Help Timmy find and fix the bug in his unfinished for loop!

Answer: {"fn_name": "create_array", "inputs": [[1], [2], [3], [4], [5], [6], [7], [8], [9], [10]], "outputs": [[[1]], [[1, 2]], [[1, 2, 3]], [[1, 2, 3, 4]], [[1, 2, 3, 4, 5]], [[1, 2, 3, 4, 5, 6]], [[1, 2, 3, 4, 5, 6, 7]], [[1, 2, 3, 4, 5, 6, 7, 8]], [[1, 2, 3, 4, 5, 6, 7, 8, 9]], [[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]]]}
user: Complete the function that calculates the derivative of a polynomial. A polynomial is an expression like: 3x^(4) - 2x^(2) + x - 10

### How to calculate the derivative:

* Take the exponent and multiply it with the coefficient
* Reduce the exponent by 1

For example: 3x^(4) --> (4*3)x^((4-1)) = 12x^(3)

### Good to know:

* The derivative of a constant is 0 (e.g. 100 --> 0)
* Anything to the 0th exponent equals 1 (e.g. x^(0) = 1)
* The derivative of the sum of two function is the sum of the derivatives

Notes:
* The exponentiation is marked with "^"
* Exponents are always integers and >= 0
* Exponents are written only if > 1
* There are no spaces around the operators
* Leading "+" signs are omitted

See the examples below.

## Examples
```python
derivative("-100")      = "0"
derivative("4x+1")      = "4"      # = 4x^0 + 0
derivative("-x^2+3x+4") = "-2x+3"  # = -2x^1 + 3x^0 + 0
```

Answer: {"fn_name": "derivative", "inputs": [["4x+1"], ["-4x-1"], ["x^2+2x+1"], ["0"], ["-100"], ["-x^2+3x+4"], ["-x^5-x^4-x^3"], ["10x^9+10x^3+10x"], ["100x^5+12x^3-3x-3"], ["-1000x^7+200x^4+6x^2+x+1000"]], "outputs": [["4"], ["-4"], ["2x+2"], ["0"], ["0"], ["-2x+3"], ["-5x^4-4x^3-3x^2"], ["90x^8+30x^2+10"], ["500x^4+36x^2-3"], ["-7000x^6+800x^3+12x+1"]]}
user: Write a function 
```javascript 
tripledouble(num1,num2)
```
```python
triple_double(num1, num2)
```
which takes numbers `num1` and `num2` and returns `1` if there is a straight triple of a number at any place in `num1` and also a straight double of the **same** number in `num2`.

If this isn't the case, return `0`

## Examples

```python
triple_double(451999277, 41177722899) == 1
# num1 has straight triple 999s and num2 has straight double 99s

triple_double(1222345, 12345) == 0
# num1 has straight triple 2s but num2 has only a single 2

triple_double(12345, 12345) == 0

triple_double(666789, 12345667) == 1
```

Answer: {"fn_name": "triple_double", "inputs": [[451999277, 41177722899], [1222345, 12345], [12345, 12345], [666789, 12345667], [10560002, 100], [1112, 122]], "outputs": [[1], [0], [0], [1], [1], [0]]}
user: Implement `String#to_cents`, which should parse prices expressed as `$1.23` and return number of cents, or in case of bad format return `nil`.

Answer: {"fn_name": "to_cents", "inputs": [[""], ["1"], ["1.23"], ["$1"], ["$1.23"], ["$99.99"], ["$12345678.90"], ["$9.69"], ["$9.70"], ["$9.71"], ["$1.23\n"], ["\n$1.23"], ["$0.69"], ["$9.69$4.3.7"], ["$9.692"]], "outputs": [[null], [null], [null], [null], [123], [9999], [1234567890], [969], [970], [971], [null], [null], [69], [null], [null]]}
user: A palindrome is a word, phrase, number, or other sequence of characters which reads the same backward as forward. Examples of numerical palindromes are: `2332, 110011, 54322345`

For a given number ```num```, write a function which returns an array of all the numerical palindromes contained within each number. The array should be sorted in ascending order and any duplicates should be removed.

In this kata, single digit numbers and numbers which start or end with zeros (such as `010` and `00`) are **NOT** considered valid numerical palindromes.  

If `num` contains no valid palindromes, return `"No palindromes found"`. 
Otherwise, return `"Not valid"` if the input is not an integer or is less than `0`.


## Examples

```
palindrome(1221)      =>  [22, 1221]
palindrome(34322122)  =>  [22, 212, 343, 22122]
palindrome(1001331)   =>  [33, 1001, 1331]
palindrome(1294)      =>  "No palindromes found"
palindrome("1221")    =>  "Not valid"
```

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### Other Kata in this Series:

Numerical Palindrome #1
Numerical Palindrome #1.5
Numerical Palindrome #2
Numerical Palindrome #3
Numerical Palindrome #3.5
Numerical Palindrome #4
Numerical Palindrome #5

Answer: {"fn_name": "palindrome", "inputs": [[2], [34322122], [10015885], [4444], [1002001], [141221001], [1551], [13598], ["ACCDDCCA"], ["1551"], [-4505]], "outputs": [["No palindromes found"], [[22, 212, 343, 22122]], [[88, 1001, 5885]], [[44, 444, 4444]], [[1002001]], [[22, 141, 1001, 1221]], [[55, 1551]], ["No palindromes found"], ["Not valid"], ["Not valid"], ["Not valid"]]}