meetforever/GRPO_CL huggingface dataset:
user: Your task in this Kata is to emulate text justify right in monospace font. You will be given a single-lined text and the expected justification width. The longest word will never be greater than this width.

Here are the rules:

- Use spaces to fill in the gaps on the left side of the words.
- Each line should contain as many words as possible.
- Use '\n' to separate lines.
- Gap between words can't differ by more than one space.
- Lines should end with a word not a space.
- '\n' is not included in the length of a line.
- Last line should not contain '\n'

Example with width=30:

```
        Bacon ipsum dolor amet
excepteur ut kevin burgdoggen,
   shankle cupim dolor officia
       ground round id ullamco
   deserunt nisi. Commodo tail
    qui salami, brisket boudin 
tri-tip. Labore flank laboris,
  cow enim proident aliqua sed
      hamburger consequat. Sed
     consequat ut non bresaola
   capicola shoulder excepteur
 veniam, bacon kevin. Pastrami
   shank laborum est excepteur
 non eiusmod bresaola flank in
nostrud. Corned beef ex pig do
   kevin filet mignon in irure
 deserunt ipsum qui duis short
        loin. Beef ribs dolore
  meatball officia rump fugiat
  in enim corned beef non est.
```

If you enjoyed this one and want more of a challenge try https://www.codewars.com/kata/text-align-justify/python

If you like bacon ipsum https://baconipsum.com

Answer: {"fn_name": "align_right", "inputs": [["abc def", 10], ["I take up the whole line", 24], ["Two lines, I am", 10]], "outputs": [["   abc def"], ["I take up the whole line"], ["Two lines,\n      I am"]]}
user: ## Debugging sayHello function

The starship Enterprise has run into some problem when creating a program to greet everyone as they come aboard. It is your job to fix the code and get the program working again!

Example output: 
```
Hello, Mr. Spock
```

Answer: {"fn_name": "say_hello", "inputs": [["Mr. Spock"], ["Captain Kirk"], ["Liutenant Uhura"], ["Dr. McCoy"], ["Mr. Scott"]], "outputs": [["Hello, Mr. Spock"], ["Hello, Captain Kirk"], ["Hello, Liutenant Uhura"], ["Hello, Dr. McCoy"], ["Hello, Mr. Scott"]]}
user: You want to build a standard house of cards, but you don't know how many cards you will need. Write a program which will count the minimal number of cards according to the number of floors you want to have. For example, if you want a one floor house, you will need 7 of them (two pairs of two cards on the base floor, one horizontal card and one pair to get the first floor). Here you can see which kind of house of cards I mean:
http://www.wikihow.com/Build-a-Tower-of-Cards

## Note about floors:
This kata uses the British numbering system for building floors. If you want your house of cards to have a first floor, it needs a ground floor and then a first floor above that.

### Details (Ruby & JavaScript & Python & R)
The input must be an integer greater than 0, for other input raise an error.

### Details (Haskell)
The input must be an integer greater than 0, for other input return `Nothing`.

Answer: {"fn_name": "house_of_cards", "inputs": [[1], [2], [3]], "outputs": [[7], [15], [26]]}
user: Amicable numbers are two different numbers so related that the sum of the proper divisors of each is equal to the other number. (A proper divisor of a number is a positive factor of that number other than the number itself. For example, the proper divisors of 6 are 1, 2, and 3.) 

For example, the smallest pair of amicable numbers is (220, 284); for the proper divisors of 220 are 1, 2, 4, 5, 10, 11, 20, 22, 44, 55 and 110, of which the sum is 284; and the proper divisors of 284 are 1, 2, 4, 71 and 142, of which the sum is 220.

Derive function ```amicableNumbers(num1, num2)``` which returns ```true/True``` if pair ```num1 num2``` are amicable, ```false/False``` if not.

See more at https://en.wikipedia.org/wiki/Amicable_numbers

Answer: {"fn_name": "amicable_numbers", "inputs": [[220, 284], [220, 280], [1184, 1210], [220221, 282224], [10744, 10856], [299920, 9284], [999220, 2849], [122265, 139815]], "outputs": [[true], [false], [true], [false], [true], [false], [false], [true]]}
user: # Task
 Given an array `arr`, find the rank of the element at the ith position.

 The `rank` of the arr[i] is a value equal to the number of elements `less than or equal to` arr[i] standing before arr[i], plus the number of elements `less than` arr[i] standing after arr[i].

# Example

 For `arr = [2,1,2,1,2], i = 2`, the result should be `3`.
 
 There are 2 elements `less than or equal to` arr[2] standing before arr[2]: 
 
 `arr[0] <= arr[2]`
 
 `arr[1] <= arr[2]`
 
 There is only 1 element `less than` arr[2] standing after arr[2]: 
 
 `arr[3] < arr[2]`
 
 So the result is `2 + 1 = 3`.
 
# Input/Output


 - `[input]` integer array `arr`

  An array of integers.

  `3 <= arr.length <= 50.`


 - `[input]` integer `i`

  Index of the element whose rank is to be found.

  
 - `[output]` an integer

  Rank of the element at the ith position.

Answer: {"fn_name": "rank_of_element", "inputs": [[[2, 1, 2, 1, 2], 2], [[2, 1, 2, 2, 2], 2], [[3, 2, 3, 4, 1], 0], [[3, 2, 3, 4, 1], 1], [[3, 2, 3, 4, 1], 2]], "outputs": [[3], [2], [2], [1], [3]]}
user: Write a method that returns true if a given parameter is a power of 4, and false if it's not. If parameter is not an Integer (eg String, Array) method should return false as well.

(In C# Integer means all integer Types like Int16,Int32,.....)

### Examples

```python
isPowerOf4 1024 #should return True
isPowerOf4  102 #should return False
isPowerOf4   64 #should return True
```

Answer: {"fn_name": "powerof4", "inputs": [[2], [4], [40], [1], [4.2], [-25], ["pippi"], [256]], "outputs": [[false], [true], [false], [true], [false], [false], [false], [true]]}
user: Complete the solution so that it returns the number of times the search_text is found within the full_text. 

Usage example:

Answer: {"fn_name": "solution", "inputs": [["abcdeb", "b"], ["abc", "b"], ["abbc", "bb"], ["abcdeb", "a"], ["ccddeeccddeecc", "cc"], ["aabb", "cc"], ["bbaa", "a"], ["abab", "a"], ["abcdefdvbhibjkb", "b"], ["abccded", "cc"], ["abccded", "d"]], "outputs": [[2], [1], [1], [1], [3], [0], [2], [2], [4], [1], [2]]}
user: An eviternity number is a number which:
* contains only digits 8, 5 and 3, and 
* the count of the digit `8` >= count of digit `5` >= count of digit `3`. 

The first few eviternity numbers are as follows. 
```Haskell
[8, 58, 85, 88, 358, 385, 538, 583, 588, 835, 853, 858, 885, 888]
```
You will be given two integers, `a` and `b`, and your task is to return the number of eviternity numbers in the range `>= a and < b`.
```Haskell
For example:
solve(0,1000) = 14, because they are [8, 58, 85, 88, 358, 385, 538, 583, 588, 835, 853, 858, 885, 888]
```

The upper bound will not exceed `500,000`.

More examples in test cases. Good luck!

Answer: {"fn_name": "solve", "inputs": [[0, 100], [0, 1000], [0, 10000], [0, 100000], [0, 500000], [90, 139701], [61, 56976]], "outputs": [[4], [14], [37], [103], [148], [99], [53]]}
user: You'll be given a list of two strings, and each will contain exactly one colon (`":"`) in the middle (but not at beginning or end). The length of the strings, before and after the colon, are random.

Your job is to return a list of two strings (in the same order as the original list), but with the characters after each colon swapped.


## Examples
```
["abc:123", "cde:456"]  -->  ["abc:456", "cde:123"]
["a:12345", "777:xyz"]  -->  ["a:xyz", "777:12345"]
```

Answer: {"fn_name": "tail_swap", "inputs": [[["abc:123", "cde:456"]], [["a:12345", "777:xyz"]]], "outputs": [[["abc:456", "cde:123"]], [["a:xyz", "777:12345"]]]}
user: Adding tip to a restaurant bill in a graceful way can be tricky, thats why you need make a function for it.

The function will receive the restaurant bill (always a positive number) as an argument. You need to 1) **add at least 15%** in tip, 2) round that number up to an *elegant* value and 3) return it.

What is an *elegant* number? It depends on the magnitude of the number to be rounded. Numbers below 10 should simply be rounded to whole numbers. Numbers 10 and above should be rounded like this:

10 - 99.99... ---> Round to number divisible by 5

100 - 999.99... ---> Round to number divisible by 50

1000 - 9999.99... ---> Round to number divisible by 500

And so on...

Good luck!

## Examples
```
 1  -->    2
 7  -->    9
12  -->   15
86  -->  100
```

Answer: {"fn_name": "graceful_tipping", "inputs": [[1], [7], [12], [86], [99], [1149], [983212]], "outputs": [[2], [9], [15], [100], [150], [1500], [1500000]]}
user: Given a triangle of consecutive odd numbers:

```
             1
          3     5
       7     9    11
   13    15    17    19
21    23    25    27    29
...
```

find the triangle's row knowing its index (the rows are 1-indexed), e.g.:

```
odd_row(1)  ==  [1]
odd_row(2)  ==  [3, 5]
odd_row(3)  ==  [7, 9, 11]
```

**Note**: your code should be optimized to handle big inputs.

___

The idea for this kata was taken from this kata: [Sum of odd numbers](https://www.codewars.com/kata/sum-of-odd-numbers)

Answer: {"fn_name": "odd_row", "inputs": [[1], [2], [13], [19], [41], [93]], "outputs": [[[1]], [[3, 5]], [[157, 159, 161, 163, 165, 167, 169, 171, 173, 175, 177, 179, 181]], [[343, 345, 347, 349, 351, 353, 355, 357, 359, 361, 363, 365, 367, 369, 371, 373, 375, 377, 379]], [[1641, 1643, 1645, 1647, 1649, 1651, 1653, 1655, 1657, 1659, 1661, 1663, 1665, 1667, 1669, 1671, 1673, 1675, 1677, 1679, 1681, 1683, 1685, 1687, 1689, 1691, 1693, 1695, 1697, 1699, 1701, 1703, 1705, 1707, 1709, 1711, 1713, 1715, 1717, 1719, 1721]], [[8557, 8559, 8561, 8563, 8565, 8567, 8569, 8571, 8573, 8575, 8577, 8579, 8581, 8583, 8585, 8587, 8589, 8591, 8593, 8595, 8597, 8599, 8601, 8603, 8605, 8607, 8609, 8611, 8613, 8615, 8617, 8619, 8621, 8623, 8625, 8627, 8629, 8631, 8633, 8635, 8637, 8639, 8641, 8643, 8645, 8647, 8649, 8651, 8653, 8655, 8657, 8659, 8661, 8663, 8665, 8667, 8669, 8671, 8673, 8675, 8677, 8679, 8681, 8683, 8685, 8687, 8689, 8691, 8693, 8695, 8697, 8699, 8701, 8703, 8705, 8707, 8709, 8711, 8713, 8715, 8717, 8719, 8721, 8723, 8725, 8727, 8729, 8731, 8733, 8735, 8737, 8739, 8741]]]}
user: # Definition

A **_Tidy number_**  *is a number whose*  **_digits are in non-decreasing order_**.
___
# Task

**_Given_** a number, **_Find if it is Tidy or not_** . 
____

# Warm-up (Highly recommended)

# [Playing With Numbers Series](https://www.codewars.com/collections/playing-with-numbers)
___

# Notes 


* **_Number_** *passed is always*  **_Positive_** .

* **_Return_** *the result as* a **_Boolean_** 

~~~if:prolog
* Since prolog doesn't have booleans,  return value should be 1 for (True) or 0 for (false)
~~~
___

# Input >> Output Examples

```
tidyNumber (12) ==> return (true)
```

## **_Explanation_**:

**_The number's digits_**    `{ 1 , 2 }`  are *in non-Decreasing Order* (i.e) *1 <= 2* .
____

```
tidyNumber (32) ==> return (false)
```

## **_Explanation_**:

**_The Number's Digits_**  `{ 3, 2}`  are **_not in non-Decreasing Order_** (i.e) *3 > 2* .
___

```
tidyNumber (1024) ==> return (false)
```

## **_Explanation_**:

**_The Number's Digits_**  `{1 , 0, 2, 4}`  are **_not in non-Decreasing Order_**  as  *0 <= 1* .

___

```
tidyNumber (13579) ==> return (true)
```

## **_Explanation_**:

**_The number's digits_**    `{1 , 3, 5, 7, 9}`  are *in non-Decreasing Order* .
____

```
tidyNumber (2335) ==> return (true)
```

## **_Explanation_**:

**_The number's digits_**    `{2 , 3, 3, 5}`  are *in non-Decreasing Order* , **_Note_**   *3 <= 3* 

___
___
___

# [Playing with Numbers Series](https://www.codewars.com/collections/playing-with-numbers)

# [Playing With Lists/Arrays Series](https://www.codewars.com/collections/playing-with-lists-slash-arrays)

# [For More Enjoyable Katas](http://www.codewars.com/users/MrZizoScream/authored)
___

## ALL translations are welcomed

## Enjoy Learning !!
# Zizou

Answer: {"fn_name": "tidyNumber", "inputs": [[12], [102], [9672], [2789], [2335]], "outputs": [[true], [false], [false], [true], [true]]}
user: You might know some pretty large perfect squares.  But what about the NEXT one?

Complete the `findNextSquare` method that finds the next integral perfect square after the one passed as a parameter.  Recall that an integral perfect square is an integer n such that sqrt(n) is also an integer.  

If the parameter is itself not a perfect square then `-1` should be returned.  You may assume the parameter is positive.


**Examples:**

```
findNextSquare(121) --> returns 144
findNextSquare(625) --> returns 676
findNextSquare(114) --> returns -1 since 114 is not a perfect
```

Answer: {"fn_name": "find_next_square", "inputs": [[121], [625], [319225], [15241383936], [155], [342786627]], "outputs": [[144], [676], [320356], [15241630849], [-1], [-1]]}
user: It's pretty straightforward. Your goal is to create a function that removes the first and last characters of a string. You're given one parameter, the original string.  You don't have to worry with strings with less than two characters.

Answer: {"fn_name": "remove_char", "inputs": [["eloquent"], ["country"], ["person"], ["place"], ["ok"], ["ooopsss"]], "outputs": [["loquen"], ["ountr"], ["erso"], ["lac"], [""], ["oopss"]]}
user: Write a function that returns the number of '2's in the factorization of a number.  
For example,
```python
two_count(24)
```
should return 3, since the factorization of 24 is 2^3 x 3
```python
two_count(17280)
```
should return 7, since the factorization of 17280 is 2^7 x 5 x 3^3  
The number passed to two_count (twoCount)  will always be a positive integer greater than or equal to 1.

Answer: {"fn_name": "two_count", "inputs": [[24], [17280], [222222222222], [256], [1], [2], [482848428248882482], [7], [7777777777777777], [84934656]], "outputs": [[3], [7], [1], [8], [0], [1], [1], [0], [0], [20]]}
user: #Find the missing letter

Write a method that takes an array of consecutive (increasing) letters as input and that returns the missing letter in the array.

You will always get an valid array. And it will be always exactly one letter be missing. The length of the array will always be at least 2.
The array will always contain letters in only one case.

Example:
```if-not:swift
['a','b','c','d','f'] -> 'e'
['O','Q','R','S'] -> 'P'
```

(Use the English alphabet with 26 letters!)

Have fun coding it and please don't forget to vote and rank this kata! :-) 

I have also created other katas. Take a look if you enjoyed this kata!

Answer: {"fn_name": "find_missing_letter", "inputs": [[["a", "b", "c", "d", "f"]], [["O", "Q", "R", "S"]], [["b", "d"]]], "outputs": [["e"], ["P"], ["c"]]}
user: Find the last element of the given argument(s).

## Examples

```python
last([1, 2, 3, 4]) ==>  4
last("xyz")        ==> "z"
last(1, 2, 3, 4)   ==>  4
```
In **javascript** and **CoffeeScript** a **list** will be an `array`, a `string` or the list of `arguments`.

(courtesy of [haskell.org](http://www.haskell.org/haskellwiki/99_questions/1_to_10))

Answer: {"fn_name": "last", "inputs": [[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]], [1, 2, 3, 4, 5, 6, 7, 8, 9, 10], [["a", "b", "c", "k", "x", "y", "z"]], ["abckxyz"], ["a", "b", "c", "z"]], "outputs": [[10], [10], ["z"], ["z"], ["z"]]}
user: Cluster analysis - Unweighted pair-group average

Clustering is a task of grouping a set of objects in such a way that the objects in the same class are similar to each other and the objects in different classes are distinct. Cluster analysis is employed in many fields such as machine learning, pattern recognition, image analysis, etc.

In this kata, your task is to implement a simple clustering technique called 'Unweighted pair-group average'. This method takes a set of 2D points and the desired number of final clusters. Initially, each point forms its own cluster. The most similar (least distant) clusters are iteratively merged until the target number of clusters is reached.

The distance metric between two clusters is defined as the average distance between all pairs of points from the two clusters. For example: 
```
Cluster 1: (0, 0), (0, 1)
Cluster 2: (4, 3)
Distance = (sqrt((0-4)^2 + (0-3)^2) + sqrt((0-4)^2 + (1-2)^2)) / 2
```

Input:
- ```points``` - a list of 2D points ```[(1, 1), (3, 5), (4, 4), (8, 2), (0, 1)]```
- ```n``` - the desired number of clusters

Output:
- list of clusters, each cluster is a list of points
- points in each cluster should be sorted in ascending order
- the list of clusters should also be sorted in ascending order

Example:
- ```cluster(3, [(1, 1), (3, 5), (4, 4), (8, 2), (0, 1)])```
- should return 
```[ [(0, 1), (1, 1)],
     [(3, 5), (4, 4)],
     [(8, 2)]
   ]
```
   
Notes:
- the coordinates ```(x, y)``` are chosen from interval ```<0, 1000>```
- ```0 < len(points) <= 100```
- ```0 < n <= len(points)```
- there is always only one unique solution
- there are no duplicate points in the input

Answer: {"fn_name": "cluster", "inputs": [[[[100, 100]], 1]], "outputs": [[[[[100, 100]]]]]}
user: This function should test if the `factor` is a factor of `base`.

Return `true` if it is a factor or `false` if it is not.

## About factors
Factors are numbers you can multiply together to get another number.

2 and 3 are factors of 6 because: `2 * 3 = 6`

- You can find a factor by dividing numbers. If the remainder is 0 then the number is a factor.
- You can use the mod operator (`%`) in most languages to check for a remainder

For example 2 is not a factor of 7 because: `7 % 2 = 1`

Note: `base` is a non-negative number, `factor` is a positive number.

Answer: {"fn_name": "check_for_factor", "inputs": [[10, 2], [63, 7], [2450, 5], [24612, 3], [9, 2], [653, 7], [2453, 5], [24617, 3]], "outputs": [[true], [true], [true], [true], [false], [false], [false], [false]]}
user: You have two arrays in this kata, every array contain only unique elements. Your task is to calculate number of elements in first array which also are in second array.

Answer: {"fn_name": "match_arrays", "inputs": [[["Perl", "Closure", "JavaScript"], ["Go", "C++", "Erlang"]], [["Erlang", "JavaScript"], ["Go", "C++", "Python"]], [[true, 3, 9, 11, 15], [true, 3, 11]]], "outputs": [[0], [0], [3]]}
user: The aim of this Kata is to write a function which will reverse the case of all consecutive duplicate letters in a string.  That is, any letters that occur one after the other and are identical.

If the duplicate letters are lowercase then they must be set to uppercase, and if they are uppercase then they need to be changed to lowercase. 

**Examples:**
```python
reverse_case("puzzles")    Expected Result: "puZZles"
reverse_case("massive")    Expected Result: "maSSive"
reverse_case("LITTLE")     Expected Result: "LIttLE"
reverse_case("shhh")       Expected Result: "sHHH"
```

Arguments passed will include only alphabetical letters A–Z or a–z.

Answer: {"fn_name": "reverse", "inputs": [["hello world"], ["HELLO WORLD"], ["HeLlo World"], ["WWW"], ["parallel universe"], ["shhh"], ["bookkeeper"]], "outputs": [["heLLo world"], ["HEllO WORLD"], ["HeLlo World"], ["www"], ["paraLLel universe"], ["sHHH"], ["bOOKKEEper"]]}
user: In your class, you have started lessons about "arithmetic progression". Because you are also a programmer, you have decided to write a function.

This function, arithmetic_sequence_sum(a, r, n), should return the sum of the first (n) elements of a sequence in which each element is the sum of the given integer (a), and a number of occurences of the given integer (r), based on the element's position within the sequence.

For example:

arithmetic_sequence_sum(2, 3, 5) should return 40:

```
1     2        3          4            5
a + (a+r) + (a+r+r) + (a+r+r+r) + (a+r+r+r+r) 
2 + (2+3) + (2+3+3) + (2+3+3+3) + (2+3+3+3+3) = 40
```

Answer: {"fn_name": "arithmetic_sequence_sum", "inputs": [[3, 2, 20], [2, 2, 10], [1, -2, 10]], "outputs": [[440], [110], [-80]]}
user: You are the "computer expert" of a local Athletic Association (C.A.A.).
Many teams of runners come to compete. Each time you get a string of 
all race results of every team who has run.
For example here is a string showing the individual results of a team of 5 runners:

` "01|15|59, 1|47|6, 01|17|20, 1|32|34, 2|3|17" `

Each part of the string is of the form: ` h|m|s `
where h, m, s (h for hour, m for minutes, s for seconds) are positive or null integer (represented as strings) with one or two digits.
There are no traps in this format.

To compare the results of the teams you are asked for giving
three statistics; **range, average and median**.

`Range` : difference between the lowest and highest values. 
In {4, 6, 9, 3, 7} the lowest value is 3, and the highest is 9, 
so the range is 9 − 3 = 6.

`Mean or Average` : To calculate mean, add together all of the numbers 
in a set and then divide the sum by the total count of numbers.

`Median` : In statistics, the median is the number separating the higher half 
of a data sample from the lower half. 
The median of a finite list of numbers can be found by arranging all 
the observations from lowest value to highest value and picking the middle one 
(e.g., the median of {3, 3, 5, 9, 11} is 5) when there is an odd number of observations. 
If there is an even number of observations, then there is no single middle value; 
the median is then defined to be the mean of the two middle values
(the median of {3, 5, 6, 9} is (5 + 6) / 2 = 5.5).

Your task is to return a string giving these 3 values.  For the example given above,
the string result will be

`"Range: 00|47|18 Average: 01|35|15 Median: 01|32|34"`

of the form:

`"Range: hh|mm|ss Average: hh|mm|ss Median: hh|mm|ss"`

where hh, mm, ss are integers (represented by strings) with *each 2 digits*.

*Remarks*: 

1. if a result in seconds is ab.xy... it will be given **truncated** as ab.

2. if the given string is "" you will return ""

Answer: {"fn_name": "stat", "inputs": [["01|15|59, 1|47|16, 01|17|20, 1|32|34, 2|17|17"], ["02|15|59, 2|47|16, 02|17|20, 2|32|34, 2|17|17, 2|22|00, 2|31|41"], ["02|15|59, 2|47|16, 02|17|20, 2|32|34, 2|32|34, 2|17|17"], ["0|15|59, 0|16|16, 0|17|20, 0|22|34, 0|19|34, 0|15|0"], ["11|15|59, 10|16|16, 12|17|20, 9|22|34, 13|19|34, 11|15|17, 11|22|00, 10|26|37, 12|17|48, 9|16|30, 12|20|14, 11|25|11"], ["1|15|59, 1|16|16, 1|17|20, 1|22|34, 1|19|34, 1|15|17, 1|22|00, 1|26|37, 1|17|48, 1|16|30, 1|20|14, 1|25|11"]], "outputs": [["Range: 01|01|18 Average: 01|38|05 Median: 01|32|34"], ["Range: 00|31|17 Average: 02|26|18 Median: 02|22|00"], ["Range: 00|31|17 Average: 02|27|10 Median: 02|24|57"], ["Range: 00|07|34 Average: 00|17|47 Median: 00|16|48"], ["Range: 04|03|04 Average: 11|14|36 Median: 11|18|59"], ["Range: 00|11|20 Average: 01|19|36 Median: 01|18|41"]]}