meetforever/GRPO_CL huggingface dataset:
user: # Task
 You are given a car odometer which displays the miles traveled as an integer. 
 
 The odometer has a defect, however: it proceeds from digit `3` to digit `5` always skipping the digit `4`. This defect shows up in all positions (ones, tens, hundreds, etc). 
 
 For example, if the odometer displays `15339` and the car travels another mile, the odometer changes to `15350` (instead of `15340`).

 Your task is to calculate the real distance, according The number the odometer shows.

# Example

 For `n = 13` the output should be `12`(4 skiped).
 
 For `n = 15` the output should be `13`(4 and 14 skiped).
 
 For `n = 2003` the output should be `1461`.

# Input/Output


 - `[input]` integer `n`

  The number the odometer shows.
  
  `1 <= n <= 999999999`


 - `[output]` an integer

  The real distance.

Answer: {"fn_name": "faulty_odometer", "inputs": [[13], [15], [55], [2005], [1500], [999999], [165826622]], "outputs": [[12], [13], [40], [1462], [1053], [531440], [69517865]]}
user: Given a string, s, return a new string that orders the characters in order of frequency. 

The returned string should have the same number of characters as the original string. 

Make your transformation stable, meaning characters that compare equal should stay in their original order in the string s. 

```python
most_common("Hello world") => "lllooHe wrd"
most_common("Hello He worldwrd") => "lllHeo He wordwrd"
```

Explanation:

In the `hello world` example, there are 3 `'l'`characters, 2 `'o'`characters, and one each of `'H'`, `'e'`, `' '`, `'w'`, `'r'`, and `'d'`characters. Since `'He wrd'`are all tied, they occur in the same relative order that they do in the original string, `'Hello world'`.

Note that ties don't just happen in the case of characters occuring once in a string. See the second example, `most_common("Hello He worldwrd")`should return `'lllHeo He wordwrd'`, not `'lllHHeeoo  wwrrdd'`.  **This is a key behavior if this method were to be used to transform a string on multiple passes.**

Answer: {"fn_name": "most_common", "inputs": [["Hello world"], [""], ["wubz dermatoglyphics"], ["Four score and seven years ago"], ["Hello He worldwrd"]], "outputs": [["lllooHe wrd"], [""], ["wubz dermatoglyphics"], ["     eeeeorsorasarsaonnFucdvyg"], ["lllHeo He wordwrd"]]}
user: In this kata, you will be given a string of text and valid parentheses, such as `"h(el)lo"`. You must return the string, with only the text inside parentheses reversed, so `"h(el)lo"` becomes `"h(le)lo"`. However, if said parenthesized text contains parenthesized text itself, then that too must reversed back, so it faces the original direction. When parentheses are reversed, they should switch directions, so they remain syntactically correct (i.e. `"h((el)l)o"` becomes `"h(l(el))o"`). This pattern should repeat for however many layers of parentheses. There may be multiple groups of parentheses at any level (i.e. `"(1) (2 (3) (4))"`), so be sure to account for these.

For example:
```python
reverse_in_parentheses("h(el)lo") == "h(le)lo"
reverse_in_parentheses("a ((d e) c b)") == "a (b c (d e))"
reverse_in_parentheses("one (two (three) four)") == "one (ruof (three) owt)"
reverse_in_parentheses("one (ruof ((rht)ee) owt)") == "one (two ((thr)ee) four)"
```

Input parentheses will always be valid (i.e. you will never get "(()").

Answer: {"fn_name": "reverse_in_parentheses", "inputs": [["h(el)lo"], ["a ((d e) c b)"], ["one (two (three) four)"], ["one (ruof ((rht)ee) owt)"], [""], ["many (parens) on (top)"], ["( ( ) (()) )"]], "outputs": [["h(le)lo"], ["a (b c (d e))"], ["one (ruof (three) owt)"], ["one (two ((thr)ee) four)"], [""], ["many (snerap) on (pot)"], ["( (()) ( ) )"]]}
user: You're writing an excruciatingly detailed alternate history novel set in a world where [Daniel Gabriel Fahrenheit](https://en.wikipedia.org/wiki/Daniel_Gabriel_Fahrenheit) was never born.

Since Fahrenheit never lived the world kept on using the [Rømer scale](https://en.wikipedia.org/wiki/R%C3%B8mer_scale), invented by fellow Dane [Ole Rømer](https://en.wikipedia.org/wiki/Ole_R%C3%B8mer) to this very day, skipping over the Fahrenheit and Celsius scales entirely.

Your magnum opus contains several thousand references to temperature, but those temperatures are all currently in degrees Celsius. You don't want to convert everything by hand, so you've decided to write a function, `celsius_to_romer()` that takes a temperature in degrees Celsius and returns the equivalent temperature in degrees Rømer.

For example: `celsius_to_romer(24)` should return `20.1`.

Answer: {"fn_name": "celsius_to_romer", "inputs": [[24], [8], [29]], "outputs": [[20.1], [11.7], [22.725]]}
user: You have invented a time-machine which has taken you back to ancient Rome. Caeser is impressed with your programming skills and has appointed you to be the new information security officer.

Caeser has ordered you to write a Caeser cipher to prevent Asterix and Obelix from reading his emails.

A Caeser cipher shifts the letters in a message by the value dictated by the encryption key. Since Caeser's emails are very important, he wants all encryptions to have upper-case output, for example:

If key = 3
"hello" -> KHOOR
If key = 7
"hello" -> OLSSV

Input will consist of the message to be encrypted and the encryption key.

Answer: {"fn_name": "caeser", "inputs": [["This is a message", 0], ["who are you?", 18], ["..5tyu..", 25], ["..#$%^..", 0], ["..#$%^..", 26], ["final one", 9]], "outputs": [["THIS IS A MESSAGE"], ["OZG SJW QGM?"], ["..5SXT.."], ["..#$%^.."], ["..#$%^.."], ["ORWJU XWN"]]}
user: ### Longest Palindrome

Find the length of the longest substring in the given string `s` that is the same in reverse.        

As an example, if the input was “I like racecars that go fast”, the substring (`racecar`) length would be `7`. 

If the length of the input string is `0`, the return value must be `0`. 

### Example:
```
"a" -> 1 
"aab" -> 2  
"abcde" -> 1
"zzbaabcd" -> 4
"" -> 0
```

Answer: {"fn_name": "longest_palindrome", "inputs": [["a"], ["aa"], ["baa"], ["aab"], ["baabcd"], ["baablkj12345432133d"], ["I like racecars that go fast"], ["abcdefghba"], [""], ["FourscoreandsevenyearsagoourfaathersbroughtforthonthiscontainentanewnationconceivedinzLibertyanddedicatedtothepropositionthatallmenarecreatedequalNowweareengagedinagreahtcivilwartestingwhetherthatnaptionoranynartionsoconceivedandsodedicatedcanlongendureWeareqmetonagreatbattlefiemldoftzhatwarWehavecometodedicpateaportionofthatfieldasafinalrestingplaceforthosewhoheregavetheirlivesthatthatnationmightliveItisaltogetherfangandproperthatweshoulddothisButinalargersensewecannotdedicatewecannotconsecratewecannothallowthisgroundThebravelmenlivinganddeadwhostruggledherehaveconsecrateditfaraboveourpoorponwertoaddordetractTgheworldadswfilllittlenotlenorlongrememberwhatwesayherebutitcanneverforgetwhattheydidhereItisforusthelivingrathertobededicatedheretotheulnfinishedworkwhichtheywhofoughtherehavethusfarsonoblyadvancedItisratherforustobeherededicatedtothegreattdafskremainingbeforeusthatfromthesehonoreddeadwetakeincreaseddevotiontothatcauseforwhichtheygavethelastpfullmeasureofdevotionthatweherehighlyresolvethatthesedeadshallnothavediedinvainthatthisnationunsderGodshallhaveanewbirthoffreedomandthatgovernmentofthepeoplebythepeopleforthepeopleshallnotperishfromtheearth"]], "outputs": [[1], [2], [2], [2], [4], [9], [7], [1], [0], [7]]}
user: >When no more interesting kata can be resolved, I just choose to create the new kata, to solve their own, to enjoy the process  --myjinxin2015 said

# Description:
 Give you two number `m` and `n`(two positive integer, m < n), make a triangle pattern with number sequence `m to n`. The order is clockwise, starting from the top corner, like this:
 
```
 When m=1 n=10  triangle is:
    1
   9 2
  8 0 3
 7 6 5 4
```
 Note: The pattern only uses the last digit of each number; Each row separated by "\n"; Each digit separated by a space; Left side may need pad some spaces, but don't pad the right side; If `m to n` can not make the triangle, return `""`.
  
# Some examples:

```
makeTriangle(1,3) should return:
 1
3 2

makeTriangle(6,20) should return: 

    6
   7 7
  6 8 8
 5 0 9 9
4 3 2 1 0

makeTriangle(1,12) should return ""
 
```

Answer: {"fn_name": "make_triangle", "inputs": [[1, 12], [1, 100]], "outputs": [[""], [""]]}
user: Consider an array containing cats and dogs. Each dog can catch only one cat, but cannot catch a cat that is more than `n` elements away. Your task will be to return the maximum number of cats that can be caught.

For example:
```Haskell
solve(['D','C','C','D','C'], 2) = 2, because the dog at index 0 (D0) catches C1 and D3 catches C4. 
solve(['C','C','D','D','C','D'], 2) = 3, because D2 catches C0, D3 catches C1 and D5 catches C4.
solve(['C','C','D','D','C','D'], 1) = 2, because D2 catches C1, D3 catches C4. C0 cannot be caught because n == 1.
solve(['D','C','D','D','C'], 1) = 2, too many dogs, so all cats get caught!
```

Do not modify the input array. 

More examples in the test cases. Good luck!

Answer: {"fn_name": "solve", "inputs": [[["D", "C", "C", "D", "C"], 1], [["C", "C", "D", "D", "C", "D"], 2], [["C", "C", "D", "D", "C", "D"], 1], [["D", "C", "D", "C", "C", "D"], 3], [["C", "C", "C", "D", "D"], 3], [["C", "C", "C", "D", "D"], 2], [["C", "C", "C", "D", "D"], 1], [["C", "C", "C", "D", "D", "D", "C", "D", "D", "D", "C", "D", "C", "C"], 2]], "outputs": [[2], [3], [2], [3], [2], [2], [1], [5]]}
user: Your friend won't stop texting his girlfriend.  It's all he does. All day. Seriously.  The texts are so mushy too! The whole situation just makes you feel ill.
Being the wonderful friend that you are, you hatch an evil plot.  While he's sleeping, you take his phone and change the autocorrect options so that every time he types "you" or "u" it gets changed to "your sister."

Write a function called autocorrect that takes a string and replaces all instances of "you" or "u" (not case sensitive) with "your sister" (always lower case).

Return the resulting string.

Here's the slightly tricky part: These are text messages, so there are different forms of "you" and "u".

For the purposes of this kata, here's what you need to support:

"youuuuu" with any number of u characters tacked onto the end
"u" at the beginning, middle, or end of a string, but NOT part of a word
"you" but NOT as part of another word like youtube or bayou

Answer: {"fn_name": "autocorrect", "inputs": [["I miss you!"], ["u want to go to the movies?"], ["Can't wait to see youuuuu"], ["I want to film the bayou with you and put it on youtube"], ["You should come over Friday night"], ["You u youville utube you youyouyou uuu raiyou united youuuu u you"]], "outputs": [["I miss your sister!"], ["your sister want to go to the movies?"], ["Can't wait to see your sister"], ["I want to film the bayou with your sister and put it on youtube"], ["your sister should come over Friday night"], ["your sister your sister youville utube your sister youyouyou uuu raiyou united your sister your sister your sister"]]}
user: ## Task
You need to implement two functions, `xor` and `or`, that replicate the behaviour of their respective operators:

- `xor` = Takes 2 values and returns `true` if, and only if, one of them is truthy.
- `or` = Takes 2 values and returns `true` if either one of them is truthy.

When doing so, **you cannot use the or operator: `||`**.

# Input
- Not all input will be booleans - there will be truthy and falsey values [the latter including also empty strings and empty arrays]
- There will always be 2 values provided

## Examples
- `xor(true, true)` should return `false`
- `xor(false, true)` should return `true`
- `or(true, false)` should return `true`
- `or(false, false)` should return `false`

Answer: {"fn_name": "func_or", "inputs": [[true, true], [true, false], [false, false], [0, 11], [null, []]], "outputs": [[true], [true], [false], [true], [false]]}
user: Write a function which reduces fractions to their simplest form! Fractions will be presented as an array/tuple (depending on the language), and the reduced fraction must be returned as an array/tuple:

```
input:   [numerator, denominator]
output:  [newNumerator, newDenominator]
example: [45, 120] --> [3, 8]
```

All numerators and denominators will be positive integers.

Note: This is an introductory Kata for a series... coming soon!

Answer: {"fn_name": "reduce_fraction", "inputs": [[[60, 20]], [[80, 120]], [[4, 2]], [[45, 120]], [[1000, 1]], [[1, 1]], [[10956590, 13611876]], [[35884747, 5576447]], [[24622321, 24473455]], [[4255316, 11425973]]], "outputs": [[[3, 1]], [[2, 3]], [[2, 1]], [[3, 8]], [[1000, 1]], [[1, 1]], [[30605, 38022]], [[76841, 11941]], [[42673, 42415]], [[17228, 46259]]]}
user: ASC Week 1 Challenge 4 (Medium #1) 

Write a function that converts any sentence into a V  A  P  O  R  W  A  V  E sentence. a V  A  P  O  R  W  A  V  E sentence converts all the letters into uppercase, and adds 2 spaces between each letter (or special character) to create this V  A  P  O  R  W  A  V  E effect.

Examples:
```javascript 
  vaporcode("Lets go to the movies") // output => "L  E  T  S  G  O  T  O  T  H  E  M  O  V  I  E  S"
  vaporcode("Why isn't my code working?") // output => "W  H  Y  I  S  N  '  T  M  Y  C  O  D  E  W  O  R  K  I  N  G  ?"
```
```ruby 
  vaporcode("Lets go to the movies") # output => "L  E  T  S  G  O  T  O  T  H  E  M  O  V  I  E  S"
  vaporcode("Why isn't my code working?") # output => "W  H  Y  I  S  N  '  T  M  Y  C  O  D  E  W  O  R  K  I  N  G  ?"
```
```python 
  vaporcode("Lets go to the movies") # output => "L  E  T  S  G  O  T  O  T  H  E  M  O  V  I  E  S"
  vaporcode("Why isn't my code working?") # output => "W  H  Y  I  S  N  '  T  M  Y  C  O  D  E  W  O  R  K  I  N  G  ?"
```
```crystal 
  vaporcode("Lets go to the movies") # output => "L  E  T  S  G  O  T  O  T  H  E  M  O  V  I  E  S"
  vaporcode("Why isn't my code working?") # output => "W  H  Y  I  S  N  '  T  M  Y  C  O  D  E  W  O  R  K  I  N  G  ?"
```
```cpp 
  vaporcode("Lets go to the movies") // output => "L  E  T  S  G  O  T  O  T  H  E  M  O  V  I  E  S"
  vaporcode("Why isn't my code working?") // output => "W  H  Y  I  S  N  '  T  M  Y  C  O  D  E  W  O  R  K  I  N  G  ?"
```
```haskell 
  vaporcode "Lets go to the movies" 
  -- output => "L  E  T  S  G  O  T  O  T  H  E  M  O  V  I  E  S"
  vaporcode "Why isn't my code working?" 
  -- output => "W  H  Y  I  S  N  '  T  M  Y  C  O  D  E  W  O  R  K  I  N  G  ?"
```

Answer: {"fn_name": "vaporcode", "inputs": [["Lets go to the movies"], ["Why isn't my code working?"]], "outputs": [["L  E  T  S  G  O  T  O  T  H  E  M  O  V  I  E  S"], ["W  H  Y  I  S  N  '  T  M  Y  C  O  D  E  W  O  R  K  I  N  G  ?"]]}
user: *Debug*   function `getSumOfDigits` that takes positive integer to calculate sum of it's digits. Assume that argument is an integer.

### Example
```
123  => 6
223  => 7
1337 => 15
```

Answer: {"fn_name": "get_sum_of_digits", "inputs": [[123], [223], [0]], "outputs": [[6], [7], [0]]}
user: It's March and you just can't seem to get your mind off brackets. However, it is not due to basketball. You need to extract statements within strings that are contained within brackets.

You have to write a function that returns a list of statements that are contained within brackets given a string. If the value entered in the function is not a string, well, you know where that variable should be sitting.

Good luck!

Answer: {"fn_name": "bracket_buster", "inputs": [[[1, 2, 3]], [{"3": 4}], [false], [23.45], ["arc.tic.[circle]?[?]"], ["Big [L][e][B][r][o][n]!][["], ["[][]]]][[[[[[][]"], ["logger?]?system...12.12.133333 at [12-32-1432-16]"]], "outputs": [["Take a seat on the bench."], ["Take a seat on the bench."], ["Take a seat on the bench."], ["Take a seat on the bench."], [["circle", "?"]], [["L", "e", "B", "r", "o", "n"]], [["", "", "[[[[[", ""]], [["12-32-1432-16"]]]}
user: Tranform of input array of zeros and ones to array in which counts number of continuous ones:

[1, 1, 1, 0, 1] -> [3,1]

Answer: {"fn_name": "ones_counter", "inputs": [[[0, 0, 0, 0, 0, 0, 0, 0]], [[1, 1, 1, 1, 1]], [[1, 1, 1, 0, 0, 1, 0, 1, 1, 0]], [[0, 0, 0, 1, 0, 0, 1, 1]], [[1, 0, 1, 1, 0, 0, 0, 1, 1, 1, 1, 0, 1]]], "outputs": [[[]], [[5]], [[3, 1, 2]], [[1, 2]], [[1, 2, 4, 1]]]}
user: The [Sharkovsky's Theorem](https://en.wikipedia.org/wiki/Sharkovskii%27s_theorem) involves the following ordering of the natural numbers:
```math
3≺5≺7≺9≺ ...\\
≺2·3≺2·5≺2·7≺2·9≺...\\
≺2^n·3≺2^n·5≺2^n·7≺2^n·9≺...\\
≺2^{(n+1)}·3≺2^{(n+1)}·5≺2^{(n+1)}·7≺2^{(n+1)}·9≺...\\
≺2^n≺2^{(n-1)}≺...\\
≺4≺2≺1\\
```
 
Your task is to complete the function which returns `true` if `$a≺b$` according to this ordering, and `false` otherwise.
 
You may assume both `$a$` and `$b$` are non-zero positive integers.

Answer: {"fn_name": "sharkovsky", "inputs": [[18, 12], [3, 9], [10, 16], [1, 22], [32, 1024], [17, 17]], "outputs": [[true], [true], [true], [false], [false], [false]]}
user: You will be given a string. 

You need to return an array of three strings by gradually pulling apart the string.

You should repeat the following steps until the string length is 1:

a) remove the final character from the original string, add to solution string 1.
b) remove the first character from the original string, add to solution string 2.

The final solution string value is made up of the remaining character from the original string, once originalstring.length == 1.

Example:

"exampletesthere"
becomes:
["erehtse","example","t"]

The Kata title gives a hint of one technique to solve.

Answer: {"fn_name": "pop_shift", "inputs": [["reusetestcasesbitcointakeovertheworldmaybewhoknowsperhaps"], ["turnsoutrandomtestcasesareeasierthanwritingoutbasicones"], ["exampletesthere"], ["letstalkaboutjavascriptthebestlanguage"], ["iwanttotraveltheworldwritingcodeoneday"], ["letsallgoonholidaysomewhereverycold"]], "outputs": [[["spahrepswonkohwebyamdlroweht", "reusetestcasesbitcointakeove", "r"]], [["senocisabtuognitirwnahtreis", "turnsoutrandomtestcasesaree", "a"]], [["erehtse", "example", "t"]], [["egaugnaltsebehttpir", "letstalkaboutjavasc", ""]], [["yadenoedocgnitirwdl", "iwanttotravelthewor", ""]], [["dlocyreverehwemos", "letsallgoonholida", "y"]]]}
user: ## Task:
You have to write a function `pattern` which returns the following Pattern(See Pattern & Examples) upto `n` number of rows. 

* Note:`Returning` the pattern is not the same as `Printing` the pattern.

#### Rules/Note:
* If `n < 1` then it should return "" i.e. empty string.
* There are `no whitespaces` in the pattern.

### Pattern: 

    1
    22
    333
    ....
    .....
    nnnnnn
    
### Examples:

+ pattern(5):

      1
      22
      333
      4444
      55555
      
* pattern(11):  

      1
      22
      333
      4444
      55555
      666666
      7777777
      88888888
      999999999
      10101010101010101010
      1111111111111111111111

```if-not:cfml
* Hint: Use \n in string to jump to next line
```
```if:cfml
* Hint: Use Chr(10) in string to jump to next line
```
[List of all my katas]('http://www.codewars.com/users/curious_db97/authored')

Answer: {"fn_name": "pattern", "inputs": [[1], [2], [5], [0], [-25]], "outputs": [["1"], ["1\n22"], ["1\n22\n333\n4444\n55555"], [""], [""]]}
user: **Background**   
You most probably know, that the *kilo* used by IT-People differs from the
*kilo* used by the rest of the world. Whereas *kilo* in kB is (mostly) intrepreted as 1024 Bytes (especially by operating systems) the non-IT *kilo* denotes the factor 1000 (as in "1 kg is 1000g"). The same goes for the prefixes mega, giga, tera, peta and so on.
To avoid misunderstandings (like your hardware shop selling you a 1E+12 Byte harddisk as 1 TB, whereas  your Windows states that it has only 932 GB, because the shop uses factor 1000 whereas operating systems use factor 1024 by default) the  International Electrotechnical Commission has proposed to use **kibibyte** for 1024 Byte.The according unit symbol would be **KiB**. Other Prefixes would be respectivly:   

```
1 MiB = 1024 KiB   
1 GiB = 1024 MiB   
1 TiB = 1024 GiB     
```

**Task**   
Your task is to write a conversion function between the kB and the KiB-Units. The function receives as parameter a memory size including a unit and converts into the corresponding unit of the other system:


```
memorysizeConversion ( "10 KiB") -> "10.24 kB"   
memorysizeConversion ( "1 kB") -> "0.977 KiB"   
memorysizeConversion ( "10 TB") -> "9.095 TiB"   
memorysizeConversion ( "4.1 GiB") -> "4.402 GB"   
```

**Hints**
- the parameter always contains a (fractioned) number, a whitespace and a valid unit
- units are case sensitive, valid units are **kB MB GB TB KiB MiB GiB TiB**
- result must be rounded to 3 decimals (round half up,no trailing zeros) see examples above

**Resources**
If you want to read more on ...ibi-Units:  
https://en.wikipedia.org/wiki/Kibibyte

Answer: {"fn_name": "memorysize_conversion", "inputs": [["1 KiB"]], "outputs": [["1.024 kB"]]}
user: Create a function which checks a number for three different properties.

- is the number prime?
- is the number even?
- is the number a multiple of 10?

Each should return either true or false, which should be given as an array. Remark: The Haskell variant uses `data Property`.

### Examples
```python
number_property(7)  # ==> [true,  false, false] 
number_property(10) # ==> [false, true,  true] 
```
The number will always be an integer, either positive or negative. Note that negative numbers cannot be primes, but they can be multiples of 10:

```python
number_property(-7)  # ==> [false, false, false] 
number_property(-10) # ==> [false, true,  true] 
```

Answer: {"fn_name": "number_property", "inputs": [[0], [2], [5], [25], [131], [1], [100], [179424691], [179424693]], "outputs": [[[false, true, true]], [[true, true, false]], [[true, false, false]], [[false, false, false]], [[true, false, false]], [[false, false, false]], [[false, true, true]], [[true, false, false]], [[false, false, false]]]}
user: There is an array of strings. All strings contains similar _letters_ except one. Try to find it!

```python
find_uniq([ 'Aa', 'aaa', 'aaaaa', 'BbBb', 'Aaaa', 'AaAaAa', 'a' ]) # => 'BbBb'
find_uniq([ 'abc', 'acb', 'bac', 'foo', 'bca', 'cab', 'cba' ]) # => 'foo'
```

Strings may contain spaces. Spaces is not significant, only non-spaces symbols matters. E.g. string that contains only spaces is like empty string.

It’s guaranteed that array contains more than 3 strings.

This is the second kata in series:

1. [Find the unique number](https://www.codewars.com/kata/585d7d5adb20cf33cb000235)
2. Find the unique string (this kata)
3. [Find The Unique](https://www.codewars.com/kata/5862e0db4f7ab47bed0000e5)

Answer: {"fn_name": "find_uniq", "inputs": [[["Aa", "aaa", "aaaaa", "BbBb", "Aaaa", "AaAaAa", "a"]], [["abc", "acb", "bac", "foo", "bca", "cab", "cba"]], [["silvia", "vasili", "victor"]], [["Tom Marvolo Riddle", "I am Lord Voldemort", "Harry Potter"]], [["", "", "", "a", "", ""]], [["    ", "  ", " ", "a", " ", ""]], [["foobar", "barfo", "fobara", "   ", "fobra", "oooofrab"]]], "outputs": [["BbBb"], ["foo"], ["victor"], ["Harry Potter"], ["a"], ["a"], ["   "]]}