meetforever/GRPO_CL huggingface dataset:
user: In elementary arithmetic a "carry" is a digit that is transferred from one column of digits to another column of more significant digits during a calculation algorithm.

This Kata is about determining the number of carries performed during the addition of multi-digit numbers.

You will receive an input string containing a set of pairs of numbers formatted as follows:

```
123 456
555 555
123 594
```

And your output should be a string formatted as follows:

```
No carry operation
1 carry operations
3 carry operations
```

###Some Assumptions

- Assume that numbers can be of any length.
- But both numbers in the pair will be of the same length.
- Although not all the numbers in the set need to be of the same length.
- If a number is shorter, it will be zero-padded.
- The input may contain any arbitrary number of pairs.

Answer: {"fn_name": "solve", "inputs": [["123 456\n555 555\n123 594"], ["321 679\n098 805\n123 867"], ["123 457\n631 372\n999 111"], ["123 457\n123 456\n654 312\n999 000\n123 457"], ["1 9\n123456789 111111101\n01 09\n11 09\n123 457"], ["99 99"]], "outputs": [["No carry operation\n3 carry operations\n1 carry operations"], ["3 carry operations\n2 carry operations\n1 carry operations"], ["1 carry operations\n2 carry operations\n3 carry operations"], ["1 carry operations\nNo carry operation\nNo carry operation\nNo carry operation\n1 carry operations"], ["1 carry operations\n1 carry operations\n1 carry operations\n1 carry operations\n1 carry operations"], ["2 carry operations"]]}
user: Your goal is to implement the method **meanVsMedian** which accepts an *odd-length* array of integers and returns one of the following:

* 'mean' - in case **mean** value is **larger than** median value
* 'median' - in case **median** value is **larger than** mean value
* 'same' - in case both mean and median share the **same value**

Reminder: [Median](https://en.wikipedia.org/wiki/Median)

Array will always be valid (odd-length >= 3)

Answer: {"fn_name": "mean_vs_median", "inputs": [[[1, 1, 1]], [[1, 2, 37]], [[7, 14, -70]], [[-10, 20, 5]]], "outputs": [["same"], ["mean"], ["median"], ["same"]]}
user: # Back-Story

Every day I travel on the freeway.

When I am more bored than usual I sometimes like to play the following counting game I made up:

* As I join the freeway my count is ```0```
* Add ```1``` for every car that I overtake
* Subtract ```1``` for every car that overtakes me
* Stop counting when I reach my exit

What an easy game! What fun!

# Kata Task

You will be given
* The distance to my exit (km)
* How fast I am going (kph)
* Information about a lot of other cars 
 * Their time (relative to me) as I join the freeway. For example,
   * ```-1.5``` means they already passed my starting point ```1.5``` minutes ago
   * ```2.2``` means they will pass my starting point ```2.2``` minutes from now
 * How fast they are going (kph)

Find what is my "score" as I exit the freeway!

# Notes

* Assume all cars travel at a constant speeds

 Safety Warning 

If you plan to play this "game" remember that it is not really a game. You are in a **real** car.

There may be a temptation to try to beat your previous best score.

Please don't do that...

Answer: {"fn_name": "freeway_game", "inputs": [[50.0, 130.0, [[-1.0, 120.0], [-1.5, 120.0]]], [50.0, 110.0, [[1.0, 120.0], [1.5, 125.0]]], [50.0, 120.0, [[-1.0, 115.0], [-1.5, 110.0], [1.0, 130.0], [1.5, 130.0]]], [30.0, 100.0, [[-1.0, 110.0], [-0.7, 102.0], [-1.5, 108.0]]], [30.0, 130.0, [[1.0, 120.0], [0.7, 125.0], [1.5, 110.0]]], [50.0, 110.0, [[-1.0, 110.0], [0.5, 110.0], [1.0, 110.0], [1.5, 110.0]]], [50.0, 110.0, [[0.0, 110.0]]], [50.0, 130.0, []]], "outputs": [[2], [-2], [0], [0], [0], [0], [0], [0]]}
user: You've had a baby.

Well done. Nice isn't it? Life destroying... but in a good way.

Part of your new routine is lying awake at night worrying that you've either lost the baby... or that you have more than 1!

Given a string of words (x), you need to calculate how many babies are in it. To count as a baby you must have all of the letters in baby ('b', 'a', 'b', 'y'). That counts as 1. They do not need to be in order in the string. Upper and lower case letters count.

Examples:

If there are no babies in the string - you lost the baby!! Return a different value, as shown below:

```if-not:kotlin
'none here' = "Where's the baby?!"
'' = "Where's the baby?!"
```

```if:kotlin 
"none here" = null
"" = null
```

Answer: {"fn_name": "baby_count", "inputs": [["baby"], ["abby"], ["baby baby baby"], ["Why the hell are there so many babies?!"], ["Anyone remember life before babies?"], ["Happy babies boom ba by?"], ["b a b y"], [""], ["none here"]], "outputs": [[1], [1], [3], [1], [1], [2], [1], ["Where's the baby?!"], ["Where's the baby?!"]]}
user: # Task
 A noob programmer was given two simple tasks: sum and sort the elements of the given array `arr` = [a1, a2, ..., an]. 
 
 He started with summing and did it easily, but decided to store the sum he found in some random position of the original array which was a bad idea. Now he needs to cope with the second task, sorting the original array arr, and it's giving him trouble since he modified it.

 Given the array `shuffled`, consisting of elements a1, a2, ..., an, and their sumvalue in random order, return the sorted array of original elements a1, a2, ..., an.

# Example

 For `shuffled = [1, 12, 3, 6, 2]`, the output should be `[1, 2, 3, 6]`.

 `1 + 3 + 6 + 2 = 12`, which means that 1, 3, 6 and 2 are original elements of the array.

 For `shuffled = [1, -3, -5, 7, 2]`, the output should be `[-5, -3, 2, 7]`.

# Input/Output


 - `[input]` integer array `shuffled`

    Array of at least two integers. It is guaranteed that there is an index i such that shuffled[i] = shuffled[0] + ... + shuffled[i - 1] + shuffled[i + 1] + ... + shuffled[n].

    Constraints:

    `2 ≤ shuffled.length ≤ 30,`

    `-300 ≤ shuffled[i] ≤ 300.`


 - `[output]` an integer array

    A `sorted` array of shuffled.length - 1 elements.

Answer: {"fn_name": "shuffled_array", "inputs": [[[1, 12, 3, 6, 2]], [[1, -3, -5, 7, 2]], [[2, -1, 2, 2, -1]], [[-3, -3]]], "outputs": [[[1, 2, 3, 6]], [[-5, -3, 2, 7]], [[-1, -1, 2, 2]], [[-3]]]}
user: # Task
 The `hamming distance` between a pair of numbers is the number of binary bits that differ in their binary notation. 
 
# Example

 For `a = 25, b= 87`, the result should be `4`
```
25: 00011001
87: 01010111
```
The `hamming distance` between these two would be 4 ( the `2nd, 5th, 6th, 7th` bit ).


# Input/Output


 - `[input]` integer `a`

  First Number. `1 <= a <= 2^20`


 - `[input]` integer `b`

  Second Number. `1 <= b <= 2^20`


 - `[output]` an integer

  Hamming Distance

Answer: {"fn_name": "hamming_distance", "inputs": [[25, 87], [256, 302], [543, 634], [34013, 702]], "outputs": [[4], [4], [4], [7]]}
user: Correct this code so that it takes one argument, `x`, and returns "`x` is more than zero" if `x` is positive (and nonzero), and otherwise, returns "`x` is equal to or less than zero." In both cases, replace `x` with the actual value of `x`.

Answer: {"fn_name": "corrections", "inputs": [[8], [1], [-2], [-1], [0]], "outputs": [["8 is more than zero."], ["1 is more than zero."], ["-2 is equal to or less than zero."], ["-1 is equal to or less than zero."], ["0 is equal to or less than zero."]]}
user: # Your Task
You have a Petri dish with bacteria, and you are preparing to dive into the harsh micro-world. But, unfortunately, you don't have any microscope nearby, so you can't watch them.

You know that you have `n` bacteria in the Petri dish and size of the i-th bacteria is bacteriai. Also you know intergalactic positive integer constant `K`.

The i-th bacteria can swallow the j-th bacteria if and only if bacteriai > bacteriaj and bacteriai ≤ bacteriaj + K. The j-th bacteria disappear, but the i-th bacteria doesn't change its size.

Since you don't have a microscope, you can only guess the minimal possible number of bacteria that will remain in your Petri dish when you finally find a microscope.

```python
micro_world([101, 53, 42, 102, 101, 55, 54], 1) == 3
micro_world([20, 15, 10, 15, 20, 25], 5) == 1
```

___

# Explanation
```python
bacteria = [101, 53, 42, 102, 101, 55, 54]
K = 1
```

```if:cpp
The one of possible sequences of swallows is: {101,53,42,102,101,55,54} → {101,53,42,102,55,54} → {101,42,102,55,54} → {42,102,55,54} → {42,102,55}. In total there are 3 bacteria remaining.
```
```if:python,ruby,javascript
The one of possible sequences of swallows is: [101,53,42,102,101,55,54] → [101,53,42,102,55,54] → [101,42,102,55,54] → [42,102,55,54] → [42,102,55]. In total there are 3 bacteria remaining.
```

Answer: {"fn_name": "micro_world", "inputs": [[[101, 53, 42, 102, 101, 55, 54], 1], [[20, 15, 10, 15, 20, 25], 5], [[5, 3, 1, 5], 1]], "outputs": [[3], [1], [4]]}
user: Complete the function that accepts a string parameter, and reverses each word in the string. **All** spaces in the string should be retained.

## Examples
```
"This is an example!" ==> "sihT si na !elpmaxe"
"double  spaces"      ==> "elbuod  secaps"
```

Answer: {"fn_name": "reverse_words", "inputs": [["The quick brown fox jumps over the lazy dog."], ["apple"], ["a b c d"], ["double  spaced  words"], ["stressed desserts"], ["hello hello"]], "outputs": [["ehT kciuq nworb xof spmuj revo eht yzal .god"], ["elppa"], ["a b c d"], ["elbuod  decaps  sdrow"], ["desserts stressed"], ["olleh olleh"]]}
user: # Task

John and Alice have an appointment today. 

In the morning, John starts from (`0,0`) and goes to the place (`a,b`) where he is dating. Unfortunately, John had no sense of direction at all, so he moved 1 step in a random direction(up, down, left or right) each time. For example, if John at (x,y), next step he may move to `(x+1,y), (x-1,y),(x,y+1) or (x,y-1)`. 

Obviously, when he arrived at the destination, it was already too late and Alice had already left. It's a sadly story :(

The second day, Alice asked John why he didn't go to the dating place. John said he took `s` steps to his date yesterday.

Alice wants to know whether John is lying. Please help Alice to judge.

Given two coordinates `a, b` and the step `s`, return `true` if John tells the truth, `false` otherwise.

# Input/Output


`[input]` integer `a`

The x-coordinates of the dating site.

`-10^7 <= a <= 10^7`

`[input]` integer `b`

The y-coordinates of the dating site.

`-10^7 <= b <= 10^7`

`[input]` integer `s`

A positive integer.  The steps John using.

`0 < s <= 10^9`

`[output]` a boolean value

return `true` if John tells the truth, `false` otherwise.

# Example

For `a = 3, b = 3, s = 6`, the output should be `true`.

A possible path is: 

`(0,0) -> (0,1) -> (0,2) -> (0,3) -> (1,3) -> (2,3) -> (3,3)`

For `a = 3, b = 3, s = 8`, the output should be `true`.

A possible path is: 

`(0,0) -> (0,1) -> (1,1) -> (1,2) -> (2,2) -> (2,1) -> (3,1) -> (3,2) -> (3,3)`

For `a = 4, b = 5, s = 10`, the output should be `false`.

John can't reach coordinates (a, b) using 10 steps, he's lying ;-)

Answer: {"fn_name": "is_john_lying", "inputs": [[3, 3, 6], [4, 5, 10], [-5, -5, 10], [-5, -5, 8], [10, -10, 10]], "outputs": [[true], [false], [true], [false], [false]]}
user: While surfing in web I found interesting math problem called "Always perfect". That means if you add 1 to the product of four consecutive numbers the answer is ALWAYS a perfect square.
For example we have: 1,2,3,4 and the product will be 1X2X3X4=24. If we add 1 to the product that would become 25, since the result number is a perfect square the square root of 25 would be 5.

So now lets write a function which takes numbers separated by commas in string format and returns the number which is a perfect square and the square root of that number.

If string contains other characters than number or it has more or less than 4 numbers separated by comma function returns "incorrect input".

If string contains 4 numbers but not consecutive it returns "not consecutive".

Answer: {"fn_name": "check_root", "inputs": [["4,5,6,7"], ["3,s,5,6"], ["11,13,14,15"], ["10,11,12,13,15"], ["10,11,12,13"], ["ad,d,q,tt,v"], ["//,;;,/,..,"], ["1,2,3,4"], ["1015,1016,1017,1018"], ["555,777,444,111"], ["20,21,22,24"], ["9,10,10,11"], ["11254,11255,11256,11258"], ["25000,25001,25002,25003"], ["2000000,2000001,2000002,2000003"], ["4,5,6,q"], ["5,6,7"], ["3,5,6,7"], ["-4,-3,-2,-1"], ["-1,0,1,2"]], "outputs": [["841, 29"], ["incorrect input"], ["not consecutive"], ["incorrect input"], ["17161, 131"], ["incorrect input"], ["incorrect input"], ["25, 5"], ["1067648959441, 1033271"], ["not consecutive"], ["not consecutive"], ["not consecutive"], ["not consecutive"], ["390718756875150001, 625075001"], ["16000048000044000012000001, 4000006000001"], ["incorrect input"], ["incorrect input"], ["not consecutive"], ["25, 5"], ["1, 1"]]}
user: Some numbers have funny properties. For example:

> 89 --> 8¹ + 9² = 89 * 1

> 695 --> 6² + 9³ + 5⁴= 1390 = 695 * 2

> 46288 --> 4³ + 6⁴+ 2⁵ + 8⁶ + 8⁷ = 2360688 = 46288 * 51

Given a positive integer n written as abcd... (a, b, c, d... being digits) and a positive integer p 
- we want to find a positive integer k, if it exists, such as the sum of the digits of n taken to the successive powers of p is equal to k * n. 

In other words:

> Is there an integer k such as : (a ^ p + b ^ (p+1) + c ^(p+2) + d ^ (p+3) + ...) = n * k

If it is the case we will return k, if not return -1.

**Note**: n and p will always be given as strictly positive integers.

```python
dig_pow(89, 1) should return 1 since 8¹ + 9² = 89 = 89 * 1
dig_pow(92, 1) should return -1 since there is no k such as 9¹ + 2² equals 92 * k
dig_pow(695, 2) should return 2 since 6² + 9³ + 5⁴= 1390 = 695 * 2
dig_pow(46288, 3) should return 51 since 4³ + 6⁴+ 2⁵ + 8⁶ + 8⁷ = 2360688 = 46288 * 51
```

Answer: {"fn_name": "dig_pow", "inputs": [[89, 1], [92, 1], [46288, 3], [114, 3], [46288, 5], [135, 1], [175, 1], [518, 1], [598, 1], [1306, 1], [2427, 1], [2646798, 1], [3456789, 1], [3456789, 5], [198, 1], [249, 1], [1377, 1], [1676, 1], [695, 2], [1878, 2], [7388, 2], [47016, 2], [542186, 2], [261, 3], [1385, 3], [2697, 3], [6376, 3], [6714, 3], [63760, 3], [63761, 3], [132921, 3], [10383, 6]], "outputs": [[1], [-1], [51], [9], [-1], [1], [1], [1], [1], [1], [1], [1], [-1], [-1], [3], [3], [2], [1], [2], [19], [5], [1], [1], [5], [35], [66], [10], [1], [1], [1], [4], [12933]]}
user: You can print your name on a billboard ad. Find out how much it will cost you. Each letter has a default price of £30, but that can be different if you are given 2 parameters instead of 1.

You can not use multiplier "*" operator.

If your name would be Jeong-Ho Aristotelis, ad would cost £600.
20 leters * 30 = 600 (Space counts as a letter).

Answer: {"fn_name": "billboard", "inputs": [["Jeong-Ho Aristotelis"], ["Abishai Charalampos"], ["Idwal Augustin"], ["Hadufuns John", 20], ["Zoroaster Donnchadh"], ["Claude Miljenko"], ["Werner Vigi", 15], ["Anani Fridumar"], ["Paolo Oli"], ["Hjalmar Liupold", 40], ["Simon Eadwulf"]], "outputs": [[600], [570], [420], [260], [570], [450], [165], [420], [270], [600], [390]]}
user: You need to write a function that reverses the words in a given string. A word can also fit an empty string. If this is not clear enough, here are some examples:

As the input may have trailing spaces, you will also need to ignore unneccesary whitespace.

```python
reverse('Hello World') == 'World Hello'
reverse('Hi There.') == 'There. Hi'
```

Happy coding!

Answer: {"fn_name": "reverse", "inputs": [["I am an expert at this"], ["This is so easy"], ["no one cares"]], "outputs": [["this at expert an am I"], ["easy so is This"], ["cares one no"]]}
user: You start with a value in dollar form, e.g. $5.00. You must convert this value to a string in which the value is said, like '5 dollars' for example. This should account for ones, cents, zeroes, and negative values. Here are some examples:
```python
dollar_to_speech('$0.00') == '0 dollars.'
dollar_to_speech('$1.00') == '1 dollar.'
dollar_to_speech('$0.01') == '1 cent.'
dollar_to_speech('$5.00') == '5 dollars.'
dollar_to_speech('$20.18') == '20 dollars and 18 cents.'
dollar_to_speech('$-1.00') == 'No negative numbers are allowed!'
```
These examples account for pretty much everything. This kata has many specific outputs, so good luck!

Answer: {"fn_name": "dollar_to_speech", "inputs": [["$20.18"], ["$5.62"], ["$83.47"], ["$16.93"], ["$0.00"], ["$0.01"], ["$0.63"], ["$0.28"], ["$1.00"], ["$2.00"], ["$31.00"], ["$45.00"], ["$-5843.21"], ["$-45.32"], ["$-2.63"], ["$-234.48"]], "outputs": [["20 dollars and 18 cents."], ["5 dollars and 62 cents."], ["83 dollars and 47 cents."], ["16 dollars and 93 cents."], ["0 dollars."], ["1 cent."], ["63 cents."], ["28 cents."], ["1 dollar."], ["2 dollars."], ["31 dollars."], ["45 dollars."], ["No negative numbers are allowed!"], ["No negative numbers are allowed!"], ["No negative numbers are allowed!"], ["No negative numbers are allowed!"]]}
user: # Letterss of Natac
In a game I just made up that doesn’t have anything to do with any other game that you may or may not have played, you collect resources on each turn and then use those resources to build settlements, roads, and cities or buy a development. Other kata about this game can be found [here](https://www.codewars.com/collections/59e6938afc3c49005900011f).

## Task
This kata asks you to implement the function `build_or_buy(hand)` , which takes as input a `hand`, the resources you have (a string of letters representing the resources you have), and returns a list of the unique game objects you can build or buy given your hand. 

There are five different resources, `'b'`, `'w'`, `'g'`, `'s'`, and `'o'`.

Game objects and the resources required to build or buy them are as follows:
1. `'road'`: `bw`
2. `'settlement'`: `bwsg`
3. `'city'`: `ooogg`
4. `'development'`: `osg`

## Examples
```python
build_or_buy("bwoo")  => ['road']
build_or_buy("bwsg")  => ['road', 'settlement'] or ['settlement', 'road']
build_or_buy("")      => []
build_or_buy("ogogoogogo")  => ['city']

```

## Notes: 
1. Don't mutate the hand
2. The order of the returned list doesn't matter
3. You do not have to test for whether a hand is valid. 
4. The list will be interpreted to mean 'you can build any of these objects,' not 'you can build all these objects in one play'. See example 2 above, even though there is only one `'b'` and one `'w'` in `hand`, both `Road()` and `Settlement()` are in the list. 
5. A hand can be empty. In the event a hand is empty, you can't build or buy anything, so return an empty list, see example 3 above.
6. Hand are between 0 and 39 in length.

Answer: {"fn_name": "build_or_buy", "inputs": [["bwoo"], [""], ["ogogoogogo"], ["bwbwwwbb"]], "outputs": [[["road"]], [[]], [["city"]], [["road"]]]}
user: # Story&Task
 The capital of Berland has n multifloor buildings. The architect who built up the capital was very creative, so all houses in the city were built in one row.

 Let's enumerate all the houses from left to right, starting with 0. A house is considered to be luxurious if the number of floors in it is strictly greater than in each house with larger number. In other words, a house is luxurious if the number of floors in it is strictly greater than in all houses, located to the right from it.

 The new architect is interested in n questions, the ith of them is the following: "how many floors should be added to the ith house to make it luxurious?" (For each i from 1 to n, inclusive). You need to help him cope with this task.

 Note that all these questions are independent from each other — the answer to the question for house i does not affect other answers (i.e., the floors to the houses are not actually added).

# Input/Output


 - `[input]` integer array `houses`

  Array of positive integers, representing the number of floors in each house.

  The ith element is the number of houses in the ith house.

  `1 ≤ houses.length ≤ 1000`


 - `[output]` an integer array

  An array has the same length as input array, the ith element represents the number of floors that should be added to the ith house to make it luxurious.
  
# Example

 For `houses = [1,2,3,1,2]`, the output should be `[3,2,0,2,0]`.
 ```
 For houses[0], 3 floors should be added, 
 then its floors is strictly greater than all houses of right side.
 
 For houses[1], 2 floors should be added.
 
 For houses[2], no need to add floor
 because it's already the luxurious.
 
 For houses[3], 2 floors need to added
 
 For houses[4], no house on the right, 
 so no need to add any floor.
 ```

Answer: {"fn_name": "luxhouse", "inputs": [[[1, 2, 3, 1, 2]], [[3, 2, 1, 4]], [[1, 2, 3]], [[3, 2, 1]], [[1, 1, 1]]], "outputs": [[[3, 2, 0, 2, 0]], [[2, 3, 4, 0]], [[3, 2, 0]], [[0, 0, 0]], [[1, 1, 0]]]}
user: # Welcome to the Codewars Bar!

Codewars Bar recommends you drink 1 glass of water per standard drink so you're not hungover tomorrow morning.

Your fellow coders have bought you several drinks tonight in the form of a string. Return a string suggesting how many glasses of water you should drink to not be hungover.

## Examples

```
"1 beer"  =>  "1 glass of water"
"1 shot, 5 beers and 1 glass of wine"  =>  "7 glasses of water"
```

## Notes

* To keep the things simple, we'll consider that anything with a number in front of it is a drink: `"1 bear" => "1 glass of water"` or `"1 chainsaw and 2 pools" => "3 glasses of water"`
* The number in front of each drink lies in range `[1; 9]`

Answer: {"fn_name": "hydrate", "inputs": [["1 beer"], ["2 glasses of wine and 1 shot"], ["1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer"]], "outputs": [["1 glass of water"], ["3 glasses of water"], ["10 glasses of water"]]}
user: ## Task:
You have to write a function `pattern` which returns the following Pattern (See Pattern & Examples) upto `n` number of rows. 

* Note: `Returning` the pattern is not the same as `Printing` the pattern.

### Rules/Note:
* If `n < 1` then it should return "" i.e. empty string.
* There are `no whitespaces` in the pattern.

### Pattern:

    (n)(n-1)(n-2)...4321
    (n)(n-1)(n-2)...432
    (n)(n-1)(n-2)...43
    (n)(n-1)(n-2)...4
    ...............
    ..............
    (n)(n-1)(n-2)
    (n)(n-1)
    (n)
    
### Examples:

* pattern(4):

      4321
      432
      43
      4
    
* pattern(11):

      1110987654321
      111098765432
      11109876543
      1110987654
      111098765
      11109876
      1110987
      111098
      11109
      1110
      11


~~~if-not:cfml
* Hint: Use \n in string to jump to next line
~~~
~~~if:cfml
* Hint: Use chr(10) in string to jump to next line
~~~

[List of all my katas]("http://www.codewars.com/users/curious_db97/authored")

Answer: {"fn_name": "pattern", "inputs": [[1], [2], [5], [0], [-25]], "outputs": [["1"], ["21\n2"], ["54321\n5432\n543\n54\n5"], [""], [""]]}
user: `{a, e, i, o, u, A, E, I, O, U}`

Natural Language Understanding is the subdomain of Natural Language Processing where people used to design AI based applications have ability to understand the human languages. HashInclude Speech Processing team has a project named Virtual Assistant. For this project they appointed you as a data engineer (who has good knowledge of creating clean datasets by writing efficient code). As a data engineer your first task is to make vowel recognition dataset. In this task you have to find the presence of vowels in all possible substrings of the given string. For each given string you have to return the total number of vowels.

## Example

Given a string `"baceb"` you can split it into substrings: `b, ba, bac, bace, baceb, a, ac, ace, aceb, c, ce, ceb, e, eb, b`. The number of vowels in each of these substrings is `0, 1, 1, 2, 2, 1, 1, 2, 2, 0, 1, 1, 1, 1, 0`; if you sum up these number, you get `16` - the expected output.

**Note**: your solution should have linear time complexity.

Answer: {"fn_name": "vowel_recognition", "inputs": [["bbbb"], ["baceb"], ["aeiou"], ["aeiouAEIOU"]], "outputs": [[0], [16], [35], [220]]}