meetforever/GRPO_CL huggingface dataset:
user: # Background

My TV remote control has arrow buttons and an `OK` button.

I can use these to move a "cursor" on a logical screen keyboard to type words...

# Keyboard

The screen "keyboard" layout looks like this


  #tvkb {
    width : 400px;
    border: 5px solid gray; border-collapse: collapse;
  }
  #tvkb td {
    color : orange;
    background-color : black;
    text-align : center;
    border: 3px solid gray; border-collapse: collapse;
  }


abcde123
fghij456
klmno789
pqrst.@0
uvwxyz_/
aASP



* `aA` is the SHIFT key. Pressing this key toggles alpha characters between UPPERCASE and lowercase
* `SP` is the space character
* The other blank keys in the bottom row have no function

# Kata task

How many button presses on my remote are required to type the given `words`?

## Notes

* The cursor always starts on the letter `a` (top left)
* The alpha characters are initially lowercase (as shown above)
* Remember to also press `OK` to "accept" each letter
* Take a direct route from one letter to the next
* The cursor does not wrap (e.g. you cannot leave one edge and reappear on the opposite edge)
* Although the blank keys have no function, you may navigate through them if you want to
* Spaces may occur anywhere in the `words` string.
* Do not press the SHIFT key until you need to. For example, with the word `e.Z`, the SHIFT change happens **after** the `.` is pressed (not before)
 
# Example

words = `Code Wars`

* C => `a`-`f`-`k`-`p`-`u`-`aA`-OK-`U`-`P`-`K`-`F`-`A`-`B`-`C`-OK = 14
* o => `C`-`H`-`M`-`R`-`W`-`V`-`U`-`aA`-OK-`SP`-`v`-`q`-`l`-`m`-`n`-`o`-OK = 16
* d => `o`-`j`-`e`-`d`-OK = 4
* e => `d`-`e`-OK = 2
* space => `e`-`d`-`c`-`b`-`g`-`l`-`q`-`v`-`SP`-OK = 9
* W => `SP`-`aA`-OK-`SP`-`V`-`W`-OK = 6
* a => `W`-`V`-`U`-`aA`-OK-`u`-`p`-`k`-`f`-`a`-OK = 10
* r => `a`-`f`-`k`-`p`-`q`-`r`-OK = 6
* s => `r`-`s`-OK = 2

Answer = 14 + 16 + 4 + 2 + 9 + 6 + 10 + 6 + 2 = 69



*Good Luck!
DM.*



Series
* TV Remote
* TV Remote (shift and space)
* TV Remote (wrap)
* TV Remote (symbols)

Answer: {"fn_name": "tv_remote", "inputs": [["Code Wars"], ["does"], ["your"], ["solution"], ["work"], ["for"], ["these"], ["words"], ["DOES"], ["YOUR"], ["SOLUTION"], ["WORK"], ["FOR"], ["THESE"], ["WORDS"], ["Does"], ["Your"], ["Solution"], ["Work"], ["For"], ["These"], ["Words"], ["A"], ["AADVARKS"], ["A/A/A/A/"], ["1234567890"], ["MISSISSIPPI"], ["a"], ["aadvarks"], ["a/a/a/a/"], ["mississippi"], ["Xoo ooo ooo"], ["oXo ooo ooo"], ["ooX ooo ooo"], ["ooo Xoo ooo"], ["ooo oXo ooo"], ["ooo ooX ooo"], ["ooo ooo Xoo"], ["ooo ooo oXo"], ["ooo ooo ooX"], ["The Quick Brown Fox Jumps Over A Lazy Dog."], ["Pack My Box With Five Dozen Liquor Jugs."], [""], [" "], ["   "], ["    x   X    "]], "outputs": [[69], [16], [23], [33], [20], [12], [27], [25], [27], [26], [38], [23], [21], [32], [28], [40], [37], [49], [30], [28], [41], [35], [12], [45], [96], [28], [42], [1], [34], [85], [35], [57], [65], [53], [53], [65], [53], [53], [65], [53], [306], [290], [0], [7], [9], [34]]}
user: A function receives a certain numbers of integers ```n1, n2, n3 ..., np```(all positive and different from 0) and a factor ```k, k > 0```

The function rearranges the numbers ```n1, n2, ..., np``` in such order that generates the minimum number concatenating the digits and this number should be divisible by ```k```.

The order that the function receives their arguments is:
```python
rearranger(k, n1, n2, n3,....,np)
```

## Examples

```python
rearranger(4, 32, 3, 34, 7, 12)  == "Rearrangement: 12, 3, 34, 7, 32 generates: 12334732 divisible by 4"

rearranger(10, 32, 3, 34, 7, 12) == "There is no possible rearrangement"
```
If there are more than one possible arrengement for the same minimum number, your code should be able to handle those cases:
```python
rearranger(6, 19, 32, 2, 124, 20, 22) == "Rearrangements: 124, 19, 20, 2, 22, 32 and 124, 19, 20, 22, 2, 32 generates: 124192022232 divisible by 6"
```

The arrangements should be in sorted order, as you see: `124, 19, 20, 2, 22, 32` comes first than `124, 19, 20, 22, 2, 32`.

Have an enjoyable time!

(Thanks to `ChristianE.Cooper` for his contribution to this kata)

Answer: {"fn_name": "rearranger", "inputs": [[4, 32, 3, 34, 7, 12], [10, 32, 3, 34, 7, 12]], "outputs": [["Rearrangement: 12, 3, 34, 7, 32 generates: 12334732 divisible by 4"], ["There is no possible rearrangement"]]}
user: >When no more interesting kata can be resolved, I just choose to create the new kata, to solve their own, to enjoy the process  --myjinxin2015 said

# Description:
 
 John learns to play poker with his uncle. His uncle told him: Poker to be in accordance with the order of "2 3 4 5 6 7 8 9 10 J Q K A". The same suit should be put together. But his uncle did not tell him the order of the four suits. 
 
 Give you John's cards and Uncle's cards(two string `john` and `uncle`). Please reference to the order of Uncle's cards, sorting John's cards. 
 
 
# Examples

```
For Python:

Suits are defined as S, D, H, C.

sort_poker("D6H2S3D5SJCQSKC7D2C5H5H10SA","S2S3S5HJHQHKC8C9C10D4D5D6D7")
should return "S3SJSKSAH2H5H10C5C7CQD2D5D6"
sort_poke("D6H2S3D5SJCQSKC7D2C5H5H10SA","C8C9C10D4D5D6D7S2S3S5HJHQHK") 
should return "C5C7CQD2D5D6S3SJSKSAH2H5H10" 

```

Answer: {"fn_name": "sort_poker", "inputs": [["D6H2S3D5SJCQSKC7D2C5H5H10SA", "S2S3S5HJHQHKC8C9C10D4D5D6D7"], ["D6H2S3D5SJCQSKC7D2C5H5H10SA", "C8C9C10D4D5D6D7S2S3S5HJHQHK"]], "outputs": [["S3SJSKSAH2H5H10C5C7CQD2D5D6"], ["C5C7CQD2D5D6S3SJSKSAH2H5H10"]]}
user: ## Task

Create a function that given a sequence of strings, groups the elements that can be obtained by rotating others, ignoring upper or lower cases. 

In the event that an element appears more than once in the input sequence, only one of them will be taken into account for the result, discarding the rest. 

## Input

Sequence of strings. Valid characters for those strings are uppercase and lowercase characters from the alphabet and whitespaces.

## Output

Sequence of elements. Each element is the group of inputs that can be obtained by rotating the strings. 

Sort the elements of each group alphabetically. 

Sort the groups descendingly by size and in the case of a tie, by the first element of the group alphabetically.

## Examples

```python
['Tokyo', 'London', 'Rome', 'Donlon', 'Kyoto', 'Paris', 'Okyot'] --> [['Kyoto', 'Okyot', 'Tokyo'], ['Donlon', 'London'], ['Paris'], ['Rome']]

['Rome', 'Rome', 'Rome', 'Donlon', 'London'] --> [['Donlon', 'London'], ['Rome']]

[] --> []
```

Answer: {"fn_name": "group_cities", "inputs": [[["Tokyo", "London", "Rome", "Donlon", "Kyoto", "Paris", "Okyot"]], [["Tokyo", "London", "Rome", "Donlon"]], [["Rome", "Rome", "Rome", "Donlon", "London"]], [["Ab", "Aa"]], [[]]], "outputs": [[[["Kyoto", "Okyot", "Tokyo"], ["Donlon", "London"], ["Paris"], ["Rome"]]], [[["Donlon", "London"], ["Rome"], ["Tokyo"]]], [[["Donlon", "London"], ["Rome"]]], [[["Aa"], ["Ab"]]], [[]]]}
user: In this Kata, you will be given a series of times at which an alarm goes off. Your task will be to determine the maximum time interval between alarms. Each alarm starts ringing at the beginning of the corresponding minute and rings for exactly one minute. The times in the array are not in chronological order. Ignore duplicate times, if any.

```Haskell
For example:
solve(["14:51"]) = "23:59". If the alarm goes off now, it will not go off for another 23 hours and 59 minutes.
solve(["23:00","04:22","18:05","06:24"]) == "11:40". The max interval that the alarm will not go off is 11 hours and 40 minutes.
```
In the second example, the alarm goes off `4` times in a day.

More examples in test cases. Good luck!

Answer: {"fn_name": "solve", "inputs": [[["14:51"]], [["23:00", "04:22", "18:05", "06:24"]], [["21:14", "15:34", "14:51", "06:25", "15:30"]]], "outputs": [["23:59"], ["11:40"], ["09:10"]]}
user: In this Kata, you will implement a function `count` that takes an integer and returns the number of digits in `factorial(n)`. 

For example, `count(5) = 3`, because `5! = 120`, and `120` has `3` digits.  

More examples in the test cases. 

Brute force is not possible. A little research will go a long way, as this is a well known series.

Good luck!

Please also try:

Answer: {"fn_name": "count", "inputs": [[5], [50], [500], [5000], [50000], [500000], [5000000], [50000000]], "outputs": [[3], [65], [1135], [16326], [213237], [2632342], [31323382], [363233781]]}
user: See the following triangle:
```
____________________________________
 1                                      
 2   4   2                              
 3   6   9   6   3                      
 4   8   12  16  12  8   4             
 5   10  15  20  25  20  15  10  5   
 ___________________________________
 
```
The total sum of the numbers in the triangle, up to the 5th line included, is ```225```, part of it, ```144```, corresponds to the total sum of the even terms and ```81``` to the total sum of the odd terms.

Create a function that may output an array with three results for each value of n.
```python
triang_mult(n)  ----> [total_sum, total_even_sum, total_odd_sum]
```
Our example will be:
```python
triang_mult(5) ----> [225, 144, 81]
```

Features of the random tests:
```
number of tests = 100
49 < n < 5000
```
Enjoy it!
This kata will be translated in another languages soon

Answer: {"fn_name": "mult_triangle", "inputs": [[1], [2], [3], [4], [5], [10], [50]], "outputs": [[[1, 0, 1]], [[9, 8, 1]], [[36, 20, 16]], [[100, 84, 16]], [[225, 144, 81]], [[3025, 2400, 625]], [[1625625, 1235000, 390625]]]}
user: # Fix the Bugs (Syntax) - My First Kata

## Overview

Hello, this is my first Kata so forgive me if it is of poor quality.

In this Kata you should fix/create a program that ```return```s the following values:

 - ```false/False``` if either a or b (or both) are not numbers
 - ```a % b``` plus ```b % a``` if both arguments are numbers

You may assume the following:

1. If ```a``` and ```b``` are both numbers, neither of ```a``` or ```b``` will be ```0```.

## Language-Specific Instructions

### Javascript and PHP

In this Kata you should try to fix all the syntax errors found in the code.

Once you think all the bugs are fixed run the code to see if it works.  A correct solution should return the values specified in the overview.

**Extension: Once you have fixed all the syntax errors present in the code (basic requirement), you may attempt to optimise the code or try a different approach by coding it from scratch.**

Answer: {"fn_name": "my_first_kata", "inputs": [[3, 5], ["hello", 3], [67, "bye"], [true, true], [314, 107], [1, 32], [-1, -1], [19483, 9], ["hello", {}], [[], "pippi"]], "outputs": [[5], [false], [false], [false], [207], [1], [0], [16], [false], [false]]}
user: For every good kata idea there seem to be quite a few bad ones!

In this kata you need to check the provided array (x) for good ideas 'good' and bad ideas 'bad'. If there are one or two good ideas, return 'Publish!', if there are more than 2 return 'I smell a series!'. If there are no good ideas, as is often the case, return 'Fail!'.

~~~if:c
For C: do not dynamically allocate memory,
      instead return a string literal
~~~

Answer: {"fn_name": "well", "inputs": [[["bad", "bad", "bad"]], [["good", "bad", "bad", "bad", "bad"]], [["good", "bad", "bad", "bad", "bad", "good", "bad", "bad", "good"]]], "outputs": [["Fail!"], ["Publish!"], ["I smell a series!"]]}
user: You're given a string containing a sequence of words separated with whitespaces. Let's say it is a sequence of patterns: a name and a corresponding number - like this:

```"red 1 yellow 2 black 3 white 4"```

You want to turn it into a different **string** of objects you plan to work with later on - like this:

```"[{name : 'red', id : '1'}, {name : 'yellow', id : '2'}, {name : 'black', id : '3'}, {name : 'white', id : '4'}]"```

Doing this manually is a pain. So you've decided to write a short function that would make the computer do the job for you. Keep in mind, the pattern isn't necessarily a word and a number. Consider anything separeted by a whitespace, just don't forget: an array of objects with two elements: name and id.

As a result you'll have a string you may just copy-paste whenever you feel like defining a list of objects - now without the need to put in names, IDs, curly brackets, colon signs, screw up everything, fail searching for a typo and begin anew. This might come in handy with large lists.

Answer: {"fn_name": "words_to_object", "inputs": [["red 1 yellow 2 black 3 white 4"], ["1 red 2 white 3 violet 4 green"], ["1 1 2 2 3 3 4 4"], ["#@&fhds 123F3f 2vn2# 2%y6D @%fd3 @!#4fs W@R^g WE56h%"], [""]], "outputs": [["[{name : 'red', id : '1'}, {name : 'yellow', id : '2'}, {name : 'black', id : '3'}, {name : 'white', id : '4'}]"], ["[{name : '1', id : 'red'}, {name : '2', id : 'white'}, {name : '3', id : 'violet'}, {name : '4', id : 'green'}]"], ["[{name : '1', id : '1'}, {name : '2', id : '2'}, {name : '3', id : '3'}, {name : '4', id : '4'}]"], ["[{name : '#@&fhds', id : '123F3f'}, {name : '2vn2#', id : '2%y6D'}, {name : '@%fd3', id : '@!#4fs'}, {name : 'W@R^g', id : 'WE56h%'}]"], ["[]"]]}
user: You are the best freelancer in the city. Everybody knows you, but what they don't know, is that you are actually offloading your work to other freelancers and and you rarely need to do any work. You're living the life!

To make this process easier you need to write a method called workNeeded to figure out how much time you need to contribute to a project. 

Giving the amount of time in `minutes` needed to complete the project and an array of pair values representing other freelancers' time in `[Hours, Minutes]` format ie. `[[2, 33], [3, 44]]` calculate how much time **you** will need to contribute to the project (if at all) and return a string depending on the case.


* If we need to contribute time to the project then return `"I need to work x hour(s) and y minute(s)"`
* If we don't have to contribute any time to the project then return `"Easy Money!"`

Answer: {"fn_name": "work_needed", "inputs": [[60, [[1, 0]]], [60, [[0, 0]]]], "outputs": [["Easy Money!"], ["I need to work 1 hour(s) and 0 minute(s)"]]}
user: The pair of integer numbers `(m, n)`, such that `10 > m > n > 0`,  (below 10), that its sum, `(m + n)`, and rest, `(m - n)`, are perfect squares, is (5, 4).

Let's see what we have explained with numbers.
```
5 + 4 = 9 = 3²
5 - 4 = 1 = 1²
(10 > 5 > 4 > 0)
```

The pair of numbers `(m, n)`, closest to and below 50, having the property described above is `(45, 36)`.
```
45 + 36 = 81 = 9²
45 - 36 = 9 = 3²
(50 > 45 > 36 > 0)
```

With the function `closest_pair_tonum()`, that receives a number `upper_limit`, as an upper limit, we should be able to obtain the closest pair to `upper_limit`, that fulfills the property described above.

The function should return the largest pair of numbers `(m, n)`, satisfying `upper_limit > m > n > 0`. Note that we say pair A `(a0, a1)` is larger than pair B `(b0, b1)` when `a0 > b0` or `a0 == b0 and
a1 > b1`.

Let's see some cases:

```python
closest_pair_tonum(10) == (5, 4) # (m = 5, n = 4)

closest_pair_tonum(30) == (29, 20)

closest_pair_tonum(50) == (45, 36)
```

Happy coding and enjoy it!!
(We will be having a second part of a similar exercise (in some days) that will need a faster algorithm for values of `upper_limit` < 1000)

Answer: {"fn_name": "closest_pair_tonum", "inputs": [[10], [30], [50], [100], [150], [200]], "outputs": [[[5, 4]], [[29, 20]], [[45, 36]], [[97, 72]], [[149, 140]], [[197, 28]]]}
user: We want an array, but not just any old array, an array with contents!

Write a function that produces an array with the numbers `0` to `N-1` in it.

For example, the following code will result in an array containing the numbers `0` to `4`:

```
arr(5) // => [0,1,2,3,4]
```

Answer: {"fn_name": "arr", "inputs": [[4], [0]], "outputs": [[[0, 1, 2, 3]], [[]]]}
user: ## Find Mean

Find the mean (average) of a list of numbers in an array.

## Information

To find the mean (average) of a set of numbers add all of the numbers together and divide by the number of values in the list.

For an example list of `1, 3, 5, 7`

1. Add all of the numbers

```
1+3+5+7 = 16
```

2. Divide by the number of values in the list. In this example there are 4 numbers in the list.

```
16/4 = 4
```

3. The mean (or average) of this list is 4

Answer: {"fn_name": "find_average", "inputs": [[[1]], [[1, 3, 5, 7]], [[-1, 3, 5, -7]], [[5, 7, 3, 7]], [[]]], "outputs": [[1], [4], [0], [5.5], [0]]}
user: In this Kata, two players, Alice and Bob, are playing a palindrome game. Alice starts with `string1`, Bob starts with `string2`, and the board starts out as an empty string. Alice and Bob take turns; during a turn, a player selects a letter from his or her string, removes it from the string, and appends it to the board; if the board becomes a palindrome (of length >= 2), the player wins. Alice makes the first move. Since Bob has the disadvantage of playing second, then he wins automatically if letters run out or the board is never a palindrome. Note also that each player can see the other player's letters.

The problem will be presented as `solve(string1,string2)`. Return 1 if Alice wins and 2 it Bob wins.

For example:
```Haskell
solve("abc","baxy") = 2 -- There is no way for Alice to win. If she starts with 'a', Bob wins by playing 'a'. The same case with 'b'. If Alice starts with 'c', Bob still wins because a palindrome is not possible. Return 2.
solve("eyfjy","ooigvo") = 1 -- Alice plays 'y' and whatever Bob plays, Alice wins by playing another 'y'. Return 1.
solve("abc","xyz") = 2 -- No palindrome is possible, so Bob wins; return 2
solve("gzyqsczkctutjves","hpaqrfwkdntfwnvgs") = 1 -- If Alice plays 'g', Bob wins by playing 'g'. Alice must be clever. She starts with 'z'. She knows that since she has two 'z', the win is guaranteed. Note that she also has two 's'. But she cannot play that. Can you see why? 
solve("rmevmtw","uavtyft") = 1 -- Alice wins by playing 'm'. Can you see why? 
```
Palindrome lengths should be at least `2` characters. More examples in the test cases. 

Good luck!

Answer: {"fn_name": "solve", "inputs": [["abc", "xyz"], ["abc", "axy"], ["abc", "bax"], ["btzgd", "svjyb"], ["eyfjy", "ooigv"], ["mctimp", "eyqbnh"], ["qtkxttl", "utvohqk"]], "outputs": [[2], [2], [2], [2], [1], [1], [2]]}
user: In this Kata, you will be given a string and your task will be to return the length of the longest prefix that is also a suffix. A prefix is the start of a string while the suffix is the end of a string.  For instance, the prefixes of the string `"abcd"` are `["a","ab","abc"]`. The suffixes are `["bcd", "cd", "d"]`. You should not overlap the prefix and suffix.

```Haskell
for example:
solve("abcd") = 0, because no prefix == suffix. 
solve("abcda") = 1, because the longest prefix which == suffix is "a".
solve("abcdabc") = 3. Longest prefix which == suffix is "abc".
solve("aaaa") = 2. Longest prefix which == suffix is "aa". You should not overlap the prefix and suffix
solve("aa") = 1. You should not overlap the prefix and suffix.
solve("a") = 0. You should not overlap the prefix and suffix.
```

All strings will be lowercase and string lengths are `1 <= length <= 500`

More examples in test cases. Good luck!

Answer: {"fn_name": "solve", "inputs": [["abcd"], ["abcda"], ["abcdabc"], ["abcabc"], ["abcabca"], ["abcdabcc"], ["aaaaa"], ["aaaa"], ["aaa"], ["aa"], ["a"], ["acbacc"]], "outputs": [[0], [1], [3], [3], [1], [0], [2], [2], [1], [1], [0], [0]]}
user: *It seemed a good idea at the time...*

# Why I did it?

After a year on **Codewars** I really needed a holiday...

But not wanting to drift backwards in the honour rankings while I was away, I hatched a cunning plan!

# The Cunning Plan

So I borrowed my friend's "Clone Machine" and cloned myself :-)

Now my clone can do my Kata solutions for me and I can relax!

Brilliant!!



Furthermore, at the end of the day my clone can re-clone herself...

Double brilliant!!



I wonder why I didn't think to do this earlier?



So as I left for the airport I gave my clone instructions to:

* do my Kata solutions for me
* feed the cat
* try to keep the house tidy and not eat too much
* sleep
* clone yourself
* repeat same next day

# The Flaw

Well, how was I supposed to know that cloned DNA is faulty?

:-(

Every time they sleep they wake up with decreased ability - they get slower... they get dumber... they are only able to solve 1 less Kata than they could the previous day.

For example, if they can solve 10 Kata today, then tomorrow they can solve only 9 Kata, then 8, 7, 6... Eventually they can't do much more than sit around all day playing video games.

And (unlike me), when the clone cannot solve any more Kata they are no longer clever enough to operate the clone machine either!

# The Return Home

I suspected something was wrong when I noticed my **Codewars** honour had stopped rising.

I made a hasty return home...

...and found 100s of clones scattered through the house. Mostly they sit harmlessly mumbling to themselves. The largest group have made a kind of nest in my loungeroom where they sit catatonic in front of the PlayStation.

The whole place needs fumigating.

The fridge and pantry are empty.

And I can't find the cat.

# Kata Task

Write a method to predict the final outcome where:

Input:

* `kata-per-day` is the number of Kata I can solve per day

Output:

* ```[number-of-clones, number-of-kata-solved-by-clones]```

Answer: {"fn_name": "clonewars", "inputs": [[0], [1], [5], [10]], "outputs": [[[1, 0]], [[1, 1]], [[16, 57]], [[512, 2036]]]}
user: Jenny is 9 years old. She is the youngest detective in North America. Jenny is a 3rd grader student, so when a new mission comes up, she gets a code to decipher in a form of a sticker (with numbers) in her math notebook and a comment (a sentence) in her writing notebook. All she needs to do is to figure out one word, from there she already knows what to do. 
And here comes your role - you can help Jenny find out what the word is! 

In order to find out what the word is, you should use the sticker (array of 3 numbers) to retrive 3 letters from the comment (string) that create the word.

- Each of the numbers in the array refers to the position of a letter in the string, in increasing order.
- Spaces are not places, you need the actual letters. No spaces.
- The returned word should be all lowercase letters.
- if you can't find one of the letters using the index numbers, return "No mission today". Jenny would be very sad, but that's life... :( 

Example:
input: [5, 0, 3], "I Love You"
output: "ivy"
(0 = "i", 3 = "v", 5 = "y")

Answer: {"fn_name": "missing", "inputs": [[[0, 3, 5], "I love you"], [[7, 10, 1], "see you later"], [[29, 31, 8], "The quick brown fox jumps over the lazy dog"], [[12, 4, 6], "Good Morning"], [[1, 16, 21], "A purple pig and a green donkey flew a kite in the middle of the night"], [[35, 8, 20], "A song can make or ruin your day if you let it get to you"], [[20, 3, 27], "I love eating toasted cheese and tuna"], [[50, 4, 6], "Hi everybody"], [[8, 31, 28], "If I do not like something I will stay away from it"], [[12, 22, 28], "Where do random thoughts come from"], [[41, 7, 18], "The tape got stuck on my lips so I could not talk anymore"], [[33, 8, 12], "My turtle Jim got out of his cage and ate a banana"], [[18, 25, 45], "are you going to have a funnel birthday cake for your next birthday"], [[5, 25, 31], "all moms and dads sat around drinking coffee"], [[24, 36, 8], "My pen broke and now I have blue ink all over my dress"]], "outputs": [["ivy"], ["ear"], ["bay"], ["No mission today"], ["pen"], ["mug"], ["vet"], ["No mission today"], ["law"], ["mom"], ["gym"], ["job"], ["fix"], ["mic"], ["key"]]}