meetforever/GRPO_CL huggingface dataset:
user: Format any integer provided into a string with "," (commas) in the correct places.

**Example:**
``` csharp
Kata.NumberFormat(100000); // return "100,000"
Kata.NumberFormat(5678545); // return "5,678,545"
Kata.NumberFormat(-420902); // return "-420,902"
```
``` javascript
numberFormat(100000); // return '100,000'
numberFormat(5678545); // return '5,678,545'
numberFormat(-420902); // return '-420,902'
```
``` cpp
numberFormat(100000); // return '100,000'
numberFormat(5678545); // return '5,678,545'
numberFormat(-420902); // return '-420,902'
```
``` python
number_format(100000); # return '100,000'
number_format(5678545); # return '5,678,545'
number_format(-420902); # return '-420,902'
```
``` ruby
number_format(100000); # return '100,000'
number_format(5678545); # return '5,678,545'
number_format(-420902); # return '-420,902'
```
``` crystal
number_format(100000); # return '100,000'
number_format(5678545); # return '5,678,545'
number_format(-420902); # return '-420,902'
```

Answer: {"fn_name": "number_format", "inputs": [[100000], [5678545], [-420902], [-3], [-1003]], "outputs": [["100,000"], ["5,678,545"], ["-420,902"], ["-3"], ["-1,003"]]}
user: # Task
 You are given an array of integers `arr` that representing coordinates of obstacles situated on a straight line.

 Assume that you are jumping from the point with coordinate 0 to the right. You are allowed only to make jumps of the same length represented by some integer.

 Find the minimal length of the jump enough to avoid all the obstacles.

# Example

 For `arr = [5, 3, 6, 7, 9]`, the output should be `4`.

 Check out the image below for better understanding:

 


# Input/Output


 - `[input]` integer array `arr`

    Non-empty array of positive integers.

    Constraints: `1 ≤ inputArray[i] ≤ 100.`


 - `[output]` an integer

    The desired length.

Answer: {"fn_name": "avoid_obstacles", "inputs": [[[5, 3, 6, 7, 9]], [[2, 3]], [[1, 4, 10, 6, 2]], [[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100]]], "outputs": [[4], [4], [7], [101]]}
user: There are some candies that need to be distributed to some children as fairly as possible (i.e. the variance of result needs to be as small as possible), but I don't know how to distribute them, so I need your help. Your assignment is to write a function with signature `distribute(m, n)` in which `m` represents how many candies there are, while `n` represents how many children there are. The function should return a container which includes the number of candies each child gains.

# Notice
1. *The candy can't be divided into pieces.*
2. The list's order doesn't matter.

# Requirements
1. The case `m < 0` is equivalent to `m == 0`.
2. If `n <= 0` the function should return an empty container. 
3. If there isn't enough candy to distribute, you should fill the corresponding number with `0`.

# Examples
```python
distribute(-5,  0) # should be [] 
distribute( 0,  0) # should be [] 
distribute( 5,  0) # should be [] 
distribute(10,  0) # should be [] 
distribute(15,  0) # should be [] 
distribute(-5, -5) # should be [] 
distribute( 0, -5) # should be [] 
distribute( 5, -5) # should be [] 
distribute(10, -5) # should be [] 
distribute(15, -5) # should be []
distribute(-5, 10) # should be [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
distribute( 0, 10) # should be [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
distribute( 5, 10) # should be [1, 1, 1, 1, 1, 0, 0, 0, 0, 0]
distribute(10, 10) # should be [1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
distribute(15, 10) # should be [2, 2, 2, 2, 2, 1, 1, 1, 1, 1]
```
  
# Input
  1. m: Integer (m <= 100000)
  2. n: Integer (n <= 1000)

# Output
  1. [Integer]

Answer: {"fn_name": "distribute", "inputs": [[-5, 0], [10, 0], [15, 0], [-5, -5], [10, -5], [15, -5]], "outputs": [[[]], [[]], [[]], [[]], [[]], [[]]]}
user: A variation of determining leap years, assuming only integers are used and years can be negative and positive.

Write a function which will return the days in the year and the year entered in a string.  For example 2000, entered as an integer, will return as a string 2000 has 366 days

There are a few assumptions we will accept the year 0, even though there is no year 0 in the Gregorian Calendar.

Also the basic rule for validating a leap year are as follows

Most years that can be divided evenly by 4 are leap years. 

Exception: Century years are NOT leap years UNLESS they can be evenly divided by 400.

So the years 0, -64 and 2016 will return 366 days.
Whilst 1974, -10 and 666 will return 365 days.

Answer: {"fn_name": "year_days", "inputs": [[0], [-64], [2016], [1974], [-10], [666], [1857], [2000], [-300], [-1]], "outputs": [["0 has 366 days"], ["-64 has 366 days"], ["2016 has 366 days"], ["1974 has 365 days"], ["-10 has 365 days"], ["666 has 365 days"], ["1857 has 365 days"], ["2000 has 366 days"], ["-300 has 365 days"], ["-1 has 365 days"]]}
user: Given a square matrix (i.e. an array of subarrays), find the sum of values from the first value of the first array, the second value of the second array, the third value of the third array, and so on...

## Examples

```
array = [[1, 2],
         [3, 4]]

diagonal sum: 1 + 4 = 5
```
                
```
array = [[5, 9, 1, 0],
         [8, 7, 2, 3],
         [1, 4, 1, 9],
         [2, 3, 8, 2]]

diagonal sum: 5 + 7 + 1 + 2 = 15
```

Answer: {"fn_name": "diagonal_sum", "inputs": [[[[1, 2], [3, 4]]], [[[1, 2, 3], [4, 5, 6], [7, 8, 9]]], [[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]]]], "outputs": [[5], [15], [34]]}
user: There are several (or no) spiders, butterflies, and dragonflies. 

In this kata, a spider has eight legs. A dragonfly or a butterfly has six legs. A __dragonfly__ has __two__ pairs of wings, while a __butterfly__ has __one__ pair of wings. __I am not sure whether they are biologically correct, but the values apply here. __

Given the number of total heads, legs, and __pairs of__ wings, please calculate numbers of each kind of bugs. Of course they are integers. 
_However, I do not guarantee that they are positive in the test cases. 
Please regard the minus numbers as cases that does not make sense. _

If answers make sense, return [n\_spider, n\_butterfly, n\_dragonfly]; 
else, please return [-1, -1, -1]. 

Example: 

cal\_n\_bug(3, 20, 3) = [1, 1, 1]
One spider, one butterfly, one dragonfly in total have three heads, twenty legs (8 for the spider, 6 for the butterfly, and 6 for the dragonfly), and _three pairs_ of wings (1 for the butterfly and 2 for the dragonfly).

Answer: {"fn_name": "cal_n_bug", "inputs": [[3, 20, 3]], "outputs": [[[1, 1, 1]]]}
user: The vowel substrings in the word `codewarriors` are `o,e,a,io`. The longest of these has a length of 2. Given a lowercase string that has alphabetic characters only (both vowels and consonants) and no spaces, return the length of the longest vowel substring.
Vowels are any of `aeiou`. 


```if:csharp
Documentation:
Kata.Solve Method (String)

Returns the length of the greatest continuous vowel substring in a string.

Syntax


public
static
int Solve(
string str
    )
  


Parameters

str

Type: System.String
The string to be processed.

Return Value

Type: System.Int32
  The length of the greatest continuous vowel substring in str, or 0 if str contains no vowels.


Exceptions



Exception
Condition

ArgumentNullException
str is null.




```


Good luck!

If you like substring Katas, please try:

[Non-even substrings](https://www.codewars.com/kata/59da47fa27ee00a8b90000b4)

[Vowel-consonant lexicon](https://www.codewars.com/kata/59cf8bed1a68b75ffb000026)

Answer: {"fn_name": "solve", "inputs": [["codewarriors"], ["suoidea"], ["ultrarevolutionariees"], ["strengthlessnesses"], ["cuboideonavicuare"], ["chrononhotonthuooaos"], ["iiihoovaeaaaoougjyaw"]], "outputs": [[2], [3], [3], [1], [2], [5], [8]]}
user: ###Lucky number

Write a function to find if a number is lucky or not. If the sum of all digits is 0 or multiple of 9 then the number is lucky.

`1892376 => 1+8+9+2+3+7+6 = 36`. 36 is divisble by 9, hence number is lucky.


Function will return `true` for lucky numbers and `false` for others.

Answer: {"fn_name": "is_lucky", "inputs": [[1892376], [189237], [18922314324324234423437], [189223141324324234423437], [1892231413243242344321432142343423437], [0]], "outputs": [[true], [false], [false], [true], [true], [true]]}
user: So you've found a meeting room - phew! You arrive there ready to present, and find that someone has taken one or more of the chairs!! You need to find some quick.... check all the other meeting rooms to see if all of the chairs are in use.

Your meeting room can take up to 8 chairs. `need` will tell you how many have been taken. You need to find that many.

```if-not:java
Find the spare chairs from the array of meeting rooms. Each meeting room array will have the number of occupants as a string. Each occupant is represented by 'X'. The room array will also have an integer telling you how many chairs there are in the room.
```
```if:java
Find the spare chairs from the array of meeting rooms.
~~~java
public class Room {
  public final String occupants;  // number of occupants, each occupant is represented by 'X'
  public final int chairs;        // number of chairs in the room
}
~~~
```

You should return an array of integers that shows how many chairs you take from each room in order, up until you have the required amount.

```if-not:java
example:
[['XXX', 3], ['XXXXX', 6], ['XXXXXX', 9], ['XXX',2]] when you need 4 chairs:
```
```if:java
example:
`[Room("XXX", 3), Room("XXXXX", 6), Room("XXXXXX", 9), Room("XXX",2)]` when you need 4 chairs:
```

result -- > `[0, 1, 3]` (no chairs free in room 0, take 1 from room 1, take 3 from room 2. No need to consider room 4 as you have your 4 chairs already.

If you need no chairs, return `'Game On'`. If there aren't enough spare chairs available, return `'Not enough!'`

More in this series:

The Office I - Outed
The Office II - Boredeom Score
The Office III - Broken Photocopier
The Office IV - Find a Meeting Room

Answer: {"fn_name": "meeting", "inputs": [[[["XXX", 3], ["XXXXX", 6], ["XXXXXX", 9]], 4], [[["XXX", 1], ["XXXXXX", 6], ["X", 2], ["XXXXXX", 8], ["X", 3], ["XXX", 1]], 5], [[["XX", 2], ["XXXX", 6], ["XXXXX", 4]], 0], [[["XX", 2], ["XXXX", 6], ["XXXXX", 4]], 8], [[["XX", 2], ["XXXX", 6], ["XXXXX", 4]], 2]], "outputs": [[[0, 1, 3]], [[0, 0, 1, 2, 2]], ["Game On"], ["Not enough!"], [[0, 2]]]}
user: In this Kata, you will be given an array of integers whose elements have both a negative and a positive value, except for one integer that is either only negative or only positive. Your task will be to find that integer. 

Examples:

`[1, -1, 2, -2, 3] => 3`

`3` has no matching negative appearance

`[-3, 1, 2, 3, -1, -4, -2] => -4`

`-4` has no matching positive appearance

`[1, -1, 2, -2, 3, 3] => 3`

(the only-positive or only-negative integer may appear more than once)

Good luck!

Answer: {"fn_name": "solve", "inputs": [[[1, -1, 2, -2, 3]], [[-3, 1, 2, 3, -1, -4, -2]], [[1, -1, 2, -2, 3, 3]], [[-110, 110, -38, -38, -62, 62, -38, -38, -38]], [[-9, -105, -9, -9, -9, -9, 105]]], "outputs": [[3], [-4], [3], [-38], [-9]]}
user: # Task
 Consider a `bishop`, a `knight` and a `rook` on an `n × m` chessboard. They are said to form a `triangle` if each piece attacks exactly one other piece and is attacked by exactly one piece. 
 
 Calculate the number of ways to choose positions of the pieces to form a triangle.

 Note that the bishop attacks pieces sharing the common diagonal with it; the rook attacks in horizontal and vertical directions; and, finally, the knight attacks squares which are two squares horizontally and one square vertically, or two squares vertically and one square horizontally away from its position.

 ![](https://codefightsuserpics.s3.amazonaws.com/tasks/chessTriangle/img/moves.png?_tm=1473934712872)

# Example

 For `n = 2 and m = 3`, the output should be `8`.

 ![](https://codefightsuserpics.s3.amazonaws.com/tasks/chessTriangle/img/combinations.png?_tm=1473934713038)

# Input/Output


- `[input]` integer `n`

    Constraints: `1 ≤ n ≤ 40.`


 - `[input]` integer `m`

    Constraints: `1 ≤ m ≤ 40, 3 ≤ n x m`.


 - `[output]` an integer

Answer: {"fn_name": "chess_triangle", "inputs": [[2, 3], [1, 30], [3, 3], [2, 2], [5, 2], [40, 40]], "outputs": [[8], [0], [48], [0], [40], [92400]]}
user: Write a function that returns the count of characters that have to be removed in order to get a string with no consecutive repeats.

*Note:* This includes any characters

##  Examples

```python
'abbbbc'  => 'abc'    #  answer: 3
'abbcca'  => 'abca'   #  answer: 2
'ab cca'  => 'ab ca'  #  answer: 1
```

Answer: {"fn_name": "count_repeats", "inputs": [["abcdefg"], ["aabbccddeeffgg"], ["abcdeefee"], ["122453124"], ["@*$##^^^*)*"], ["abmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmvxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"]], "outputs": [[0], [7], [2], [1], [3], [1177]]}
user: Write a method named `getExponent(n,p)` that returns the largest integer exponent `x` such that p^(x) evenly divides `n`. if `p<=1` the method should return `null`/`None` (throw an `ArgumentOutOfRange` exception in C#).

Answer: {"fn_name": "get_exponent", "inputs": [[27, 3]], "outputs": [[3]]}
user: In this Kata, you will be given a number `n` (`n > 0`) and your task will be to return the smallest square number `N` (`N > 0`) such that `n + N` is also a perfect square. If there is no answer, return `-1` (`nil` in Clojure, `Nothing` in Haskell, `None` in Rust). 

```clojure 
solve 13 = 36
; because 36 is the smallest perfect square that can be added to 13 to form a perfect square => 13 + 36 = 49

solve 3 = 1 ; 3 + 1 = 4, a perfect square
solve 12 = 4 ; 12 + 4 = 16, a perfect square
solve 9 = 16 
solve 4 = nil
```

```csharp 
solve(13) = 36
//because 36 is the smallest perfect square that can be added to 13 to form a perfect square => 13 + 36 = 49

solve(3) = 1 // 3 + 1 = 4, a perfect square
solve(12) = 4 // 12 + 4 = 16, a perfect square
solve(9) = 16 
solve(4) = -1
```

```haskell 
solve 13 = Just 36
-- because 36 is the smallest perfect square that can be added to 13 to form a perfect square => 13 + 36 = 49

solve 3 = Just 1 -- 3 + 1 = 4, a perfect square
solve 12 = Just 4 -- 12 + 4 = 16, a perfect square
solve 9 = Just 16 
solve 4 = Nothing
```

```python
solve(13) = 36
# because 36 is the smallest perfect square that can be added to 13 to form a perfect square => 13 + 36 = 49

solve(3) = 1 # 3 + 1 = 4, a perfect square
solve(12) = 4 # 12 + 4 = 16, a perfect square
solve(9) = 16 
solve(4) = -1
```

More examples in test cases. 

Good luck!

Answer: {"fn_name": "solve", "inputs": [[1], [2], [3], [4], [5], [7], [8], [9], [10], [11], [13], [17], [88901], [290101]], "outputs": [[-1], [-1], [1], [-1], [4], [9], [1], [16], [-1], [25], [36], [64], [5428900], [429235524]]}
user: # Task
 Given a string `s`, find out if its characters can be rearranged to form a palindrome.

# Example

 For `s = "aabb"`, the output should be `true`.

 We can rearrange `"aabb"` to make `"abba"`, which is a palindrome.

# Input/Output


 - `[input]` string `s`

    A string consisting of lowercase English letters.

    Constraints:

    `4 ≤ inputString.length ≤ 50.`


 - `[output]` a boolean value

    `true` if the characters of the inputString can be rearranged to form a palindrome, `false` otherwise.

Answer: {"fn_name": "palindrome_rearranging", "inputs": [["aabb"], ["aaaaaaaaaaaaaaaaaaaaaaaaaaaaaabc"], ["abbcabb"], ["zyyzzzzz"], ["aaabbb"]], "outputs": [[true], [false], [true], [true], [false]]}
user: You should write a function that takes a string and a positive integer `n`, splits the string into parts of length `n` and returns them in an array. It is ok for the last element to have less than `n` characters.

If `n` is not a valid size (`> 0`) (or is absent), you should return an empty array.

If `n` is greater than the length of the string, you should return an array with the only element being the same string.

Examples:

```python
string_chunk('codewars', 2) # ['co', 'de', 'wa', 'rs']
string_chunk('thiskataeasy', 4) # ['this', 'kata', 'easy']
string_chunk('hello world', 3) # ['hel', 'lo ', 'wor', 'ld']
string_chunk('sunny day', 0) # []
```

Answer: {"fn_name": "string_chunk", "inputs": [["codewars", 2]], "outputs": [[["co", "de", "wa", "rs"]]]}
user: # Task
 A media access control address (MAC address) is a unique identifier assigned to network interfaces for communications on the physical network segment.

 The standard (IEEE 802) format for printing MAC-48 addresses in human-friendly form is six groups of two hexadecimal digits (0 to 9 or A to F), separated by hyphens (e.g. 01-23-45-67-89-AB).

# Example

 For `inputString = "00-1B-63-84-45-E6"`, the output should be `true`;
 
 For `inputString = "Z1-1B-63-84-45-E6"`, the output should be `false`;
 
 For `inputString = "not a MAC-48 address"`, the output should be `false`.
 
# Input/Output

 - `[input]` string `inputString`
 
 - `[output]` a boolean value

    `true` if inputString corresponds to MAC-48 address naming rules, `false` otherwise.

Answer: {"fn_name": "is_mac_48_address", "inputs": [["00-1B-63-84-45-E6"], ["Z1-1B-63-84-45-E6"], ["not a MAC-48 address"], ["FF-FF-FF-FF-FF-FF"], ["00-00-00-00-00-00"], ["G0-00-00-00-00-00"], ["12-34-56-78-9A-BC"], ["02-03-04-05-06-07-"], ["02-03-04-05"], ["02-03-04-FF-00-F0"]], "outputs": [[true], [false], [false], [true], [true], [false], [true], [false], [false], [true]]}
user: A trick I learned in elementary school to determine whether or not a number was divisible by three is to add all of the integers in the number together and to divide the resulting sum by three. If there is no remainder from dividing the sum by three, then the original number is divisible by three as well.

Given a series of numbers as a string, determine if the number represented by the string is divisible by three.

You can expect all test case arguments to be strings representing values greater than 0. 

Example:

```
"123"      -> true
"8409"     -> true
"100853"   -> false
"33333333" -> true
"7"        -> false
```

Answer: {"fn_name": "divisible_by_three", "inputs": [["123"], ["19254"], ["88"], ["1"], ["963210456"], ["10110101011"], ["9"], ["6363"], ["10987654321"], ["9876543211234567890009"], ["9876543211234567890002"]], "outputs": [[true], [true], [false], [false], [true], [false], [true], [true], [false], [true], [false]]}
user: In this kata you need to build a function to return either `true/True` or `false/False` if a string can be seen as the repetition of a simpler/shorter subpattern or not.

For example:

```cpp,java
hasSubpattern("a") == false; //no repeated pattern
hasSubpattern("aaaa") == true; //created repeating "a"
hasSubpattern("abcd") == false; //no repeated pattern
hasSubpattern("abababab") == true; //created repeating "ab"
hasSubpattern("ababababa") == false; //cannot be entirely reproduced repeating a pattern
```
```python
has_subpattern("a") == False #no repeated pattern
has_subpattern("aaaa") == True #created repeating "a"
has_subpattern("abcd") == False #no repeated pattern
has_subpattern("abababab") == True #created repeating "ab"
has_subpattern("ababababa") == False #cannot be entirely reproduced repeating a pattern
```
Strings will never be empty and can be composed of any character (just consider upper- and lowercase letters as different entities) and can be pretty long (keep an eye on performances!).

If you liked it, go for the [next kata](https://www.codewars.com/kata/string-subpattern-recognition-ii/) of the series!

Answer: {"fn_name": "has_subpattern", "inputs": [["a"], ["aaaa"], ["abcd"], ["abababab"], ["ababababa"], ["123a123a123a"], ["123A123a123a"], ["abbaabbaabba"], ["abbabbabba"], ["abcdabcabcd"]], "outputs": [[false], [true], [false], [true], [false], [true], [false], [true], [false], [false]]}
user: # Task
 Let's call `product(x)` the product of x's digits. Given an array of integers a, calculate `product(x)` for each x in a, and return the number of distinct results you get.

# Example

 For `a = [2, 8, 121, 42, 222, 23]`, the output should be `3`.

 Here are the products of the array's elements:
```
2: product(2) = 2;
8: product(8) = 8;
121: product(121) = 1 * 2 * 1 = 2;
42: product(42) = 4 * 2 = 8;
222: product(222) = 2 * 2 * 2 = 8;
23: product(23) = 2 * 3 = 6.```
As you can see, there are only `3` different products: `2, 6 and 8.`

# Input/Output


 - `[input]` integer array `a`

    Constraints:

    `1 ≤ a.length ≤ 10000,`

    `1 ≤ a[i] ≤ 1000000000.`


 - `[output]` an integer

    The number of different digit products in `a`.

Answer: {"fn_name": "unique_digit_products", "inputs": [[[2, 8, 121, 42, 222, 23]], [[239]], [[100, 101, 111]], [[100, 23, 42, 239, 22339, 9999999, 456, 78, 228, 1488]], [[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]]], "outputs": [[3], [1], [2], [10], [10]]}
user: Write a function
```python
alternate_sort(l)
```
that combines the elements of an array by sorting the elements ascending by their **absolute value** and outputs negative and non-negative integers alternatingly (starting with the negative value, if any).

E.g.
```python
alternate_sort([5, -42, 2, -3, -4, 8, -9,]) == [-3, 2, -4, 5, -9, 8, -42]
alternate_sort([5, -42, 2, -3, -4, 8, 9]) == [-3, 2, -4, 5, -42, 8, 9]
alternate_sort([5, 2, -3, -4, 8, -9]) == [-3, 2, -4, 5, -9, 8]
alternate_sort([5, 2, 9, 3, 8, 4]) == [2, 3, 4, 5, 8, 9]
```

Answer: {"fn_name": "alternate_sort", "inputs": [[[5, 2, -3, -9, -4, 8]], [[5, -42, 2, -3, -4, 8, 9]], [[5, -42, 8, 2, -3, -4, 9]], [[5, -42, -8, 2, -3, -4, -9]], [[5, 2, 3, 4, 8, 9]], [[-5, -2, -3, -4, -8, -9]], [[-5, -2, 3, 4, -8, 0, -9]], [[-5, -2, 3, 9, 4, -2, -8, 0, 9, -9]]], "outputs": [[[-3, 2, -4, 5, -9, 8]], [[-3, 2, -4, 5, -42, 8, 9]], [[-3, 2, -4, 5, -42, 8, 9]], [[-3, 2, -4, 5, -8, -9, -42]], [[2, 3, 4, 5, 8, 9]], [[-2, -3, -4, -5, -8, -9]], [[-2, 0, -5, 3, -8, 4, -9]], [[-2, 0, -2, 3, -5, 4, -8, 9, -9, 9]]]}