meetforever/GRPO_CL huggingface dataset:
user: # Introduction and Warm-up (Highly recommended)

# [Playing With Lists/Arrays Series](https://www.codewars.com/collections/playing-with-lists-slash-arrays)
___

# Task

**_Given_** an *array/list [] of integers* , **_Construct_** a *product array **_Of same size_** Such That prod[i] is equal to The Product of all the elements of Arr[] except Arr[i]*. 
___

# Notes 


* **_Array/list_** size is *at least 2* .

* **_Array/list's numbers_**  Will be **_only Positives_** 

* **_Repetition_** of numbers in *the array/list could occur*.
___

# Input >> Output Examples 

```
productArray ({12,20}) ==>  return {20,12}
```
## **_Explanation_**:

* **_The first element_**  *in prod [] array* **_12_**  *is the product of all array's elements except the first element*

* **_The second element_** **_20_**  *is the product of all array's elements except the second element* .
___

```
productArray ({1,5,2}) ==> return {10,2,5}
```

## **_Explanation_**: 


* **_The first element_**  **_10_** *is the product of all array's elements* **_except_** *the first element **_1_***

* **_The second element_** **_2_** *is the product of all array's elements* **_except_** *the second element* **_5_** 

* **_The Third element_** **_5_** *is the product of all array's elements* **_except_** *the Third element* **_2_**.

___

```
productArray ({10,3,5,6,2}) return ==> {180,600,360,300,900}
```

## **_Explanation_**: 


* **_The first element_** **_180_**  *is the product of all array's elements* **_except_** *the first element*  **_10_** 

* **_The second element_** **_600_** *is the product of all array's elements*  **_except_**  *the second element*  **_3_** 

* **_The Third element_** **_360_** *is the product of all array's elements* **_except_** *the third element* **_5_**

* **_The Fourth element_** **_300_** *is the product of all array's elements* **_except_** *the fourth element* **_6_** 

* *Finally* ,**_The Fifth element_** **_900_** *is the product of all array's elements* **_except_** *the fifth element* **_2_** 

___
# [A more challenging version of this kata by Firefly2002](https://www.codewars.com/kata/array-product-sans-n)
___
___

# [Playing with Numbers Series](https://www.codewars.com/collections/playing-with-numbers)

# [Playing With Lists/Arrays Series](https://www.codewars.com/collections/playing-with-lists-slash-arrays)

# [For More Enjoyable Katas](http://www.codewars.com/users/MrZizoScream/authored)
___

## ALL translations are welcomed

## Enjoy Learning !!
# Zizou

Answer: {"fn_name": "product_array", "inputs": [[[12, 20]], [[3, 27, 4, 2]], [[13, 10, 5, 2, 9]], [[16, 17, 4, 3, 5, 2]]], "outputs": [[[20, 12]], [[216, 24, 162, 324]], [[900, 1170, 2340, 5850, 1300]], [[2040, 1920, 8160, 10880, 6528, 16320]]]}
user: Scheduling is how the processor decides which jobs (processes) get to use the processor and for how long. This can cause a lot of problems. Like a really long process taking the entire CPU and freezing all the other processes. One solution is Round-Robin, which today you will be implementing.

Round-Robin works by queuing jobs in a First In First Out fashion, but the processes are only given a short slice of time. If a processes is not finished in that time slice, it yields the proccessor and goes to the back of the queue.

For this Kata you will be implementing the 
```python
  def roundRobin(jobs, slice, index):
```

It takes in:

    1. "jobs" a non-empty positive integer array. It represents the queue and clock-cycles(cc) remaining till the job[i] is finished.

    2. "slice" a positive integer. It is the amount of clock-cycles that each job is given till the job yields to the next job in the queue.

    3. "index" a positive integer. Which is the index of the job we're interested in.

roundRobin returns:

    1. the number of cc till the job at index is finished.

Here's an example:
```
roundRobin([10,20,1], 5, 0) 
at 0cc [10,20,1] jobs[0] starts
after 5cc [5,20,1] jobs[0] yields, jobs[1] starts
after 10cc [5,15,1] jobs[1] yields, jobs[2] starts
after 11cc [5,15,0] jobs[2] finishes, jobs[0] starts
after 16cc [0,15,0] jobs[0] finishes
```

so:
```
roundRobin([10,20,1], 5, 0) == 16
```

**You can assume that the processor can switch jobs between cc so it does not add to the total time.

Answer: {"fn_name": "roundRobin", "inputs": [[[10], 4, 0], [[10, 20], 5, 0], [[10, 20, 1, 2, 3], 5, 2], [[10, 20, 1, 2, 3], 5, 0], [[10, 20, 1, 2, 3], 4, 2], [[10, 20, 1, 2, 3], 4, 3]], "outputs": [[10], [15], [11], [21], [9], [11]]}
user: # Task
 Mirko has been moving up in the world of basketball. He started as a mere spectator, but has already reached the coveted position of the national team coach!

 Mirco is now facing a difficult task: selecting five primary players for the upcoming match against Tajikistan. Since Mirko is incredibly lazy, he doesn't bother remembering players' names, let alone their actual skills. That's why he has settled on selecting five players who share the same first letter of their surnames, so that he can remember them easier. If there are no five players sharing the first letter of their surnames, Mirko will simply forfeit the game!

 Your task is to find the first letters Mirko's players' surnames can begin with(In alphabetical order), or return `"forfeit"` if Mirko can't gather a team.

# Input/Output


 - `[input]` string array `players`

  Array of players' surnames, consisting only of lowercase English letters.

 
 - `[output]` a string

  A **sorted** string of possible first letters, or "forfeit" if it's impossible to gather a team.


# Example

For `players = ["michael","jordan","lebron","james","kobe","bryant"]`, the output should be `"forfeit"`.

 For
 ```
 players = ["babic","keksic","boric","bukic",
              "sarmic","balic","kruzic","hrenovkic",
              "beslic","boksic","krafnic","pecivic",
              "klavirkovic","kukumaric","sunkic","kolacic",
              "kovacic","prijestolonasljednikovic"]
```
the output should be "bk".

Answer: {"fn_name": "strange_coach", "inputs": [[["michael", "jordan", "lebron", "james", "kobe", "bryant"]], [["babic", "keksic", "boric", "bukic", "sarmic", "balic", "kruzic", "hrenovkic", "beslic", "boksic", "krafnic", "pecivic", "klavirkovic", "kukumaric", "sunkic", "kolacic", "kovacic", "prijestolonasljednikovic"]], [["jgztazpytubijfsmjz", "bokvgratzzdibku", "qineboilzoqdqivc", "bfctyltibtkbxq", "vioxcuhqhikxeqwekqkjo", "nrvsdhttr", "eiaoajuwxpwmyliqikzcchid", "bxrwawgor", "gbsqaxotzmblxttj", "kwchrcaconuwaivhvnyf", "neiemapiica", "bppao", "bxujiwivsjfbqrzygpdgkyz", "jnzrhhmcgcpffflpzwmqib", "jhozlevckrrwimdmyzc", "bomojotkqqditelsk", "ywmbheywzfyqjjs", "snwrclyjkbspysjftcmyak", "eelrsgkuhu", "dnyzsvqjjuqoc"]]], "outputs": [["forfeit"], ["bk"], ["b"]]}
user: ### Task:

You have to write a function `pattern` which creates the following pattern (See Examples) upto desired number of rows.

If the Argument is `0` or a Negative Integer then it should return `""` i.e. empty string.

### Examples:

`pattern(9)`:

    123456789
    234567891
    345678912
    456789123
    567891234
    678912345
    789123456
    891234567
    912345678

`pattern(5)`:

    12345
    23451
    34512
    45123
    51234

Note: There are no spaces in the pattern

Hint: Use `\n` in string to jump to next line

Answer: {"fn_name": "pattern", "inputs": [[7], [1], [4], [0], [-25]], "outputs": [["1234567\n2345671\n3456712\n4567123\n5671234\n6712345\n7123456"], ["1"], ["1234\n2341\n3412\n4123"], [""], [""]]}
user: You are required to create a simple calculator that returns the result of addition, subtraction, multiplication or division of two numbers.

Your function will accept three arguments:
The first and second argument should be numbers.
The third argument should represent a sign indicating the operation to perform on these two numbers.
```if-not:csharp
if the variables are not numbers or the sign does not belong to the list above a message "unknown value" must be returned.
```
```if:csharp
If the sign is not a valid sign, throw an ArgumentException.
```

# Example:

```python
calculator(1, 2, '+') => 3
calculator(1, 2, '$') # result will be "unknown value"
```

Good luck!

Answer: {"fn_name": "calculator", "inputs": [[6, 2, "+"], [4, 3, "-"], [5, 5, "*"], [5, 4, "/"], [6, "$", "+"], [6, 2, "&"], [4, 3, "\\"], ["a", 3, "+"], [6, 2, "="], [6, 2, "\t"], [":", ",", "+"]], "outputs": [[8], [1], [25], [1.25], ["unknown value"], ["unknown value"], ["unknown value"], ["unknown value"], ["unknown value"], ["unknown value"], ["unknown value"]]}
user: When multiple master devices are connected to a single bus (https://en.wikipedia.org/wiki/System_bus), there needs to be an arbitration in order to choose which of them can have access to the bus (and 'talk' with a slave).

We implement here a very simple model of bus mastering. Given `n`, a number representing the number of **masters** connected to the bus, and a fixed priority order (the first master has more access priority than the second and so on...), the task is to choose the selected master.
In practice, you are given a string `inp` of length `n` representing the `n` masters' requests to get access to the bus, and you should return a string representing the masters, showing which (only one) of them was granted access:

```
The string 1101 means that master 0, master 1 and master 3 have requested
access to the bus. 
Knowing that master 0 has the greatest priority, the output of the function should be: 1000
```

## Examples

## Notes

* The resulting string (`char* `) should be allocated in the `arbitrate` function, and will be free'ed in the tests.

* `n` is always greater or equal to 1.

Answer: {"fn_name": "arbitrate", "inputs": [["001000101", 9], ["000000101", 9], ["0000", 4]], "outputs": [["001000000"], ["000000100"], ["0000"]]}
user: Algorithmic predicament - Bug Fixing #9

Oh no! Timmy's algorithim has gone wrong! help Timmy fix his algorithim! 

Task
Your task is to fix timmy's algorithim so it returns the group name with the highest total age. 

You will receive two groups of `people` objects, with two properties `name` and `age`. The name property is a string and the age property is a number.  
Your goal is to make the total the age of all people having the same name through both groups and return the name of the one with the highest age. If two names have the same total age return the first alphabetical name.

Answer: {"fn_name": "highest_age", "inputs": [[[{"name": "kay", "age": 1}, {"name": "john", "age": 13}, {"name": "kay", "age": 76}], [{"name": "john", "age": 1}, {"name": "alice", "age": 77}]], [[{"name": "kay", "age": 1}, {"name": "john", "age": 13}, {"name": "kay", "age": 76}], [{"name": "john", "age": 1}, {"name": "alice", "age": 76}]], [[{"name": "kay", "age": 1}, {"name": "john", "age": 130}, {"name": "kay", "age": 76}], [{"name": "john", "age": 1}, {"name": "alice", "age": 76}]], [[{"name": "kay", "age": 1}, {"name": "john", "age": 130}, {"name": "kay", "age": 130}], [{"name": "john", "age": 1}, {"name": "alice", "age": 76}]], [[{"name": "kay", "age": 2}, {"name": "john", "age": 130}, {"name": "kay", "age": 130}], [{"name": "john", "age": 1}, {"name": "alice", "age": 76}]]], "outputs": [["alice"], ["kay"], ["john"], ["john"], ["kay"]]}
user: ~~~if-not:java
You have to code a function **getAllPrimeFactors** wich take an integer as parameter and return an array containing its prime decomposition by ascending factors, if a factors appears multiple time in the decomposition it should appear as many time in the array. 

exemple: `getAllPrimeFactors(100)` returns `[2,2,5,5]` in this order. 

This decomposition may not be the most practical. 

You should also write **getUniquePrimeFactorsWithCount**, a function which will return an array containing two arrays: one with prime numbers appearing in the decomposition and the other containing their respective power. 

exemple: `getUniquePrimeFactorsWithCount(100)` returns `[[2,5],[2,2]]`

You should also write **getUniquePrimeFactorsWithProducts** an array containing the prime factors to their respective powers. 

exemple: `getUniquePrimeFactorsWithProducts(100)` returns `[4,25]`
~~~
~~~if:java
You have to code a function **getAllPrimeFactors** wich take an integer as parameter and return an array containing its prime decomposition by ascending factors, if a factors appears multiple time in the decomposition it should appear as many time in the array. 

exemple: `getAllPrimeFactors(100)` returns `[2,2,5,5]` in this order. 

This decomposition may not be the most practical. 

You should also write **getUniquePrimeFactorsWithCount**, a function which will return an array containing two arrays: one with prime numbers appearing in the decomposition and the other containing their respective power. 

exemple: `getUniquePrimeFactorsWithCount(100)` returns `[[2,5],[2,2]]`

You should also write **getPrimeFactorPotencies** an array containing the prime factors to their respective powers. 

exemple: `getPrimeFactorPotencies(100)` returns `[4,25]`
~~~

Errors, if:

* `n` is not a number
* `n` not an integer 
* `n` is negative or 0 

The three functions should respectively return `[]`,  `[[],[]]` and `[]`. 

Edge cases: 

* if `n=0`, the function should respectively return `[]`, `[[],[]]` and  `[]`.
* if `n=1`, the function should respectively return `[1]`, `[[1],[1]]`, `[1]`.
* if `n=2`, the function should respectively return `[2]`, `[[2],[1]]`, `[2]`.

The result for `n=2` is normal. The result for `n=1` is arbitrary and has been chosen to return a usefull result. The result for `n=0` is also arbitrary 
but can not be chosen to be both usefull and intuitive. (`[[0],[0]]` would be meaningfull but wont work for general use of decomposition, `[[0],[1]]` would work but is not intuitive.)

Answer: {"fn_name": "getAllPrimeFactors", "inputs": [[10], [100], [1000], [1000001], [0], [1], [2], ["a"], [1.1], [-1]], "outputs": [[[2, 5]], [[2, 2, 5, 5]], [[2, 2, 2, 5, 5, 5]], [[101, 9901]], [[]], [[1]], [[2]], [[]], [[]], [[]]]}
user: Coding decimal numbers with factorials is a way of writing out numbers 
in a base system that depends on factorials, rather than powers of numbers.

In this system, the last digit is always `0` and is in base 0!. The digit before that is either `0 or 1` and is in base 1!.  The digit before that is either `0, 1, or 2` and is in base 2!, etc.
More generally, the nth-to-last digit is always `0, 1, 2, ..., n` and is in base n!.

Read more about it at: http://en.wikipedia.org/wiki/Factorial_number_system


## Example

The decimal number `463` is encoded as `"341010"`, because:

463 = 3×5! + 4×4! + 1×3! + 0×2! + 1×1! + 0×0!


If we are limited to digits `0..9`, the biggest number we can encode is 10!-1 (= 3628799). So we extend `0..9` with letters `A..Z`. With these 36 digits we can now encode numbers up to 36!-1 (= 3.72 × 10^(41))


## Task

We will need two functions. The first one will receive a decimal number and return a string with the factorial representation.

~~~if:java
**Note:** the input number is at most a long.
~~~

The second one will receive a string with a factorial representation and produce the decimal representation.

Given numbers will always be positive.

Answer: {"fn_name": "dec2FactString", "inputs": [[463], [2982], [36288000]], "outputs": [["341010"], ["4041000"], ["A0000000000"]]}
user: Naming multiple files can be a pain sometimes.

#### Task:

Your job here is to create a function that will take three parameters, `fmt`, `nbr` and `start`, and create an array of `nbr` elements formatted according to `frm` with the starting index `start`. `fmt` will have `` inserted at various locations; this is where the file index number goes in each file. 

#### Description of edge cases:

1. If `nbr` is less than or equal to 0, or not whole, return an empty array.
2. If `fmt` does not contain `''`, just return an array with `nbr` elements that are all equal to `fmt`. 
3. If `start` is not an integer, return an empty array.

#### What each parameter looks like:

```python
type(frm) #=> str
  : "text_to_stay_constant_from_file_to_file "
type(nbr) #=> int
  : number_of_files
type(start) #=> int
  : index_no_of_first_file
type(name_file(frm, nbr, start)) #=> list
```

#### Some examples:

```python
name_file("IMG ", 4, 1)
  #=> ["IMG 1", "IMG 2", "IMG 3", "IMG 4"])
name_file("image #.jpg", 3, 7)
  #=> ["image #7.jpg", "image #8.jpg", "image #9.jpg"]
name_file("# #", 3, -2)
  #=> ["#-2 #-2", "#-1 #-1", "#0 #0"]
```

Also check out my other creations — [Elections: Weighted Average](https://www.codewars.com/kata/elections-weighted-average), [Identify Case](https://www.codewars.com/kata/identify-case), [Split Without Loss](https://www.codewars.com/kata/split-without-loss), [Adding Fractions](https://www.codewars.com/kata/adding-fractions),
[Random Integers](https://www.codewars.com/kata/random-integers), [Implement String#transpose](https://www.codewars.com/kata/implement-string-number-transpose), [Implement Array#transpose!](https://www.codewars.com/kata/implement-array-number-transpose), [Arrays and Procs #1](https://www.codewars.com/kata/arrays-and-procs-number-1), and [Arrays and Procs #2](https://www.codewars.com/kata/arrays-and-procs-number-2).

If you notice any issues or have any suggestions/comments whatsoever, please don't hesitate to mark an issue or just comment. Thanks!

Answer: {"fn_name": "name_file", "inputs": [["IMG <index_no>", 4, 1], ["image #<index_no>.jpg", 3, 7], ["#<index_no> #<index_no>", 3, -2], ["<file> number <index_no>", 5, 0], ["<file_no> number <index_no>", 2, -1], ["file", 2, 3], ["<file_no> number <index_no>", -1, 0], ["file <index_no>", 2, 0.1], ["file <index_no>", 0.2, 0], ["file <index_no>", 0, 0]], "outputs": [[["IMG 1", "IMG 2", "IMG 3", "IMG 4"]], [["image #7.jpg", "image #8.jpg", "image #9.jpg"]], [["#-2 #-2", "#-1 #-1", "#0 #0"]], [["<file> number 0", "<file> number 1", "<file> number 2", "<file> number 3", "<file> number 4"]], [["<file_no> number -1", "<file_no> number 0"]], [["file", "file"]], [[]], [[]], [[]], [[]]]}
user: Hello! Your are given x and y and 2D array size tuple (width, height) and you have to:
Calculate the according index in 1D space (zero-based). 
Do reverse operation.

Implement:
to_1D(x, y, size):
  --returns index in 1D space
to_2D(n, size)
  --returns x and y in 2D space

1D array: [0, 1, 2, 3, 4, 5, 6, 7, 8]
2D array: [[0 -> (0,0), 1 -> (1,0), 2 -> (2,0)], 
           [3 -> (0,1), 4 -> (1,1), 5 -> (2,1)], 
           [6 -> (0,2), 7 -> (1,2), 8 -> (2,2)]]


to_1D(0, 0, (3,3)) returns 0
to_1D(1, 1, (3,3)) returns 4
to_1D(2, 2, (3,3)) returns 8
to_2D(5, (3,3)) returns (2,1)
to_2D(3, (3,3)) returns (0,1)

Assume all input are valid:

1 < width  < 500; 
1 < height < 500

Answer: {"fn_name": "to_1D", "inputs": [[0, 0, [3, 3]], [1, 1, [3, 3]], [2, 2, [3, 3]], [0, 0, [1, 1]], [1, 5, [4, 6]], [2, 3, [4, 6]]], "outputs": [[0], [4], [8], [0], [21], [14]]}
user: Congratulations! That Special Someone has given you their phone number.

But WAIT, is it a valid number? 

Your task is to write a function that verifies whether a given string contains a valid British mobile (cell) phone number or not. 

If valid, return 'In with a chance'.

If invalid, or if you're given an empty string, return 'Plenty more fish in the sea'.

A number can be valid in the following ways: 

Here in the UK mobile numbers begin with '07' followed by 9 other digits, e.g. '07454876120'.

Sometimes the number is preceded by the country code, the prefix '+44', which replaces the '0' in ‘07’, e.g. '+447454876120'.

And sometimes you will find numbers with dashes in-between digits or on either side, e.g. '+44--745---487-6120' or '-074-54-87-61-20-'. As you can see, dashes may be consecutive. 

Good Luck Romeo/Juliette!

Answer: {"fn_name": "validate_number", "inputs": [["07454876120"], ["0754876120"], ["0745--487-61-20"], ["+447535514555"], ["-07599-51-4555"], ["075335440555"], ["+337535512555"], ["00535514555"], ["+447+4435512555"], ["+44"]], "outputs": [["In with a chance"], ["Plenty more fish in the sea"], ["In with a chance"], ["In with a chance"], ["In with a chance"], ["Plenty more fish in the sea"], ["Plenty more fish in the sea"], ["Plenty more fish in the sea"], ["Plenty more fish in the sea"], ["Plenty more fish in the sea"]]}
user: Now we will confect a reagent. There are eight materials to choose from, numbered 1,2,..., 8 respectively.

We know the rules of confect:
```
material1 and material2 cannot be selected at the same time
material3 and material4 cannot be selected at the same time
material5 and material6 must be selected at the same time
material7 or  material8 must be selected(at least one, or both)
```

# Task

You are given a integer array `formula`. Array contains only digits 1-8 that represents material 1-8. Your task is to determine if the formula is valid. Returns `true` if it's valid, `false` otherwise.


# Example

For `formula = [1,3,7]`, The output should be `true`.

For `formula = [7,1,2,3]`, The output should be `false`.

For `formula = [1,3,5,7]`, The output should be `false`.

For `formula = [1,5,6,7,3]`, The output should be `true`.

For `formula = [5,6,7]`, The output should be `true`.

For `formula = [5,6,7,8]`, The output should be `true`.

For `formula = [6,7,8]`, The output should be `false`.

For `formula = [7,8]`, The output should be `true`.


# Note

- All inputs are valid. Array contains at least 1 digit. Each digit appears at most once. 

- Happy Coding `^_^`

Answer: {"fn_name": "isValid", "inputs": [[[1, 3, 7]], [[7, 1, 2, 3]], [[1, 3, 5, 7]], [[1, 5, 6, 7, 3]], [[5, 6, 7]], [[5, 6, 7, 8]], [[6, 7, 8]], [[7, 8]]], "outputs": [[true], [false], [false], [true], [true], [true], [false], [true]]}
user: Define a function that takes one integer argument and returns logical value `true` or `false` depending on if the integer is a prime.

Per Wikipedia, a prime number (or a prime) is a natural number greater than 1 that has no positive divisors other than 1 and itself.

## Requirements

* You can assume you will be given an integer input.
* You can not assume that the integer will be only positive. You may be given negative numbers as well (or `0`).
* **NOTE on performance**: There are no fancy optimizations required, but still *the* most trivial solutions might time out. Numbers go up to 2^31 (or similar, depends on language version). Looping all the way up to `n`, or `n/2`, will be too slow.

## Example
```nasm    
mov edi, 1
call is_prime    ; EAX <- 0 (false)

mov edi, 2
call is_prime    ; EAX <- 1 (true)

mov edi, -1
call is_prime    ; EAX <- 0 (false)
```

Answer: {"fn_name": "is_prime", "inputs": [[0], [1], [2], [73], [75], [-1]], "outputs": [[false], [false], [true], [true], [false], [false]]}
user: Determine the total number of digits in the integer (`n>=0`) given as input to the function. For example, 9 is a single digit, 66 has 2 digits and 128685 has 6 digits. Be careful to avoid overflows/underflows.

All inputs will be valid.

Answer: {"fn_name": "digits", "inputs": [[5], [12345], [9876543210]], "outputs": [[1], [5], [10]]}