meetforever/GRPO_CL huggingface dataset:
user: ## Story

> "You have serious coding skillz? You wannabe a [scener](https://en.wikipedia.org/wiki/Demoscene)? Complete this mission and u can get in teh crew!"

You have read a similar message on your favourite [diskmag](https://en.wikipedia.org/wiki/Disk_magazine) back in the early 90s, and got really excited. You contacted the demo crew immediately and they gave you the following job: write a vertical sinus scroller... **for the printer!**

## Your task

Write a function that takes three parameters: `text`, `amp` (for [peak amplitude](https://en.wikipedia.org/wiki/Amplitude)) and `period` (or [wavelength](https://en.wikipedia.org/wiki/Wavelength)). Return a string (split into multiple lines) that will display the text as a vertical sine wave.

Note: `amp` and `period` are measured in characters and are always positive integers; `text` is never empty.

## Example

```python
>>> scroller('Hello World!', 3, 10)
'   H\n     e\n      l\n      l\n     o\n    \n W\no\nr\n l\n   d\n     !'
```

Doesn't make much sense? Well, let's print it!

```python
   H        1
     e      2
      l     3
      l     4
     o      5
            6
 W          7
o           8
r           9
 l         10
   d        1
     !      2

3210123
```

(Obviously, the numbers are only shown above to demonstrate `amp` and `period`)

Happy coding!

*Note:* due to the inevitable use of floats, solutions with slight rounding errors (1 space difference in less than 10% of the output lines) will be accepted.

---

## My other katas

If you enjoyed this kata then please try [my other katas](https://www.codewars.com/collections/katas-created-by-anter69)! :-)

#### *Translations are welcome!*

Answer: {"fn_name": "scroller", "inputs": [["Hello World!", 3, 10], ["I'm a Codewars warrior lately...", 5, 18]], "outputs": [["   H\n     e\n      l\n      l\n     o\n    \n W\no\nr\n l\n   d\n     !"], ["     I\n       '\n        m\n          \n          a\n           \n         C\n        o\n       d\n     e\n   w\n  a\n r\ns\n \n w\n  a\n   r\n     r\n       i\n        o\n         r\n           \n          l\n         a\n        t\n       e\n     l\n   y\n  .\n .\n."]]}
user: Implement a function that normalizes out of range sequence indexes (converts them to 'in range' indexes) by making them repeatedly 'loop' around the array. The function should then return the value at that index. Indexes that are not out of range should be handled normally and indexes to empty sequences should return undefined/None depending on the language.

For positive numbers that are out of range, they loop around starting at the beginning, so 

```python
norm_index_test(seq, len(seq))     # Returns first element
norm_index_test(seq, len(seq) + 1) # Returns second element
norm_index_test(seq, len(seq) + 2) # Returns third element
# And so on...
norm_index_test(seq, len(seq) * 2) # Returns first element
```

For negative numbers, they loop starting from the end, so

```python norm_index_test(seq, len(seq))
norm_index_test(seq, -1)        # Returns last element
norm_index_test(seq, -2)        # Returns second to last element
norm_index_test(seq, -3)        # Returns third to last element
# And so on...
norm_index_test(seq, -len(seq)) # Returns first element
```

Answer: {"fn_name": "norm_index_test", "inputs": [[[], 10]], "outputs": [[null]]}
user: According to ISO 8601, the first calendar week (1) starts with the week containing the first thursday in january.
Every year contains of 52 (53 for leap years) calendar weeks.

**Your task is** to calculate the calendar week (1-53) from a given date.
For example, the calendar week for the date `2019-01-01` (string) should be 1 (int).

Good luck 👍

See also [ISO week date](https://en.wikipedia.org/wiki/ISO_week_date) and [Week Number](https://en.wikipedia.org/wiki/Week#Week_numbering) on Wikipedia for further information about calendar weeks.

On [whatweekisit.org](http://whatweekisit.org/) you may click through the calender and study calendar weeks in more depth.

*heads-up:* `require(xxx)` has been disabled


Thanks to @ZED.CWT, @Unnamed and @proxya for their feedback.

Answer: {"fn_name": "get_calendar_week", "inputs": [["2017-01-01"], ["2018-12-24"], ["2018-12-31"], ["2019-01-01"], ["2016-02-29"], ["2015-12-29"], ["2024-12-31"], ["2025-01-05"], ["2025-01-06"], ["1995-12-31"], ["1996-01-01"], ["1999-12-31"], ["2000-01-02"], ["2000-01-03"], ["2016-12-25"], ["2016-12-26"], ["2017-01-02"], ["2017-01-09"], ["2017-12-31"], ["2018-01-01"]], "outputs": [[52], [52], [1], [1], [9], [53], [1], [1], [2], [52], [1], [52], [52], [1], [51], [52], [1], [2], [52], [1]]}
user: You're given an ancient book that unfortunately has a few pages in the wrong position, fortunately your computer has a list of every page number in order from ``1`` to ``n``.

You're supplied with an array of numbers, and should return an array with each page number that is out of place. Incorrect page numbers will not appear next to each other. Duplicate incorrect page numbers are possible.

Example:

```Given: list = [1,2,10,3,4,5,8,6,7]
```

``Return: [10,8]
``

Your returning list should have the incorrect page numbers in the order they were found.

Answer: {"fn_name": "find_page_number", "inputs": [[[1, 2, 10, 3, 4, 5, 8, 6, 7]], [[1, 2, 3, 4, 50, 5, 6, 7, 51, 8, 40, 9]], [[1, 2, 3000, 3, 4, 5, 8, 6, 7, 8, 100, 9, 40, 10, 11, 13]], [[1, 2, 3, 4, 50, 5, 6, 7, 51, 8, 9]], [[4, 1, 2, 3, 3, 4, 26, 5, 6, 2, 7]]], "outputs": [[[10, 8]], [[50, 51, 40]], [[3000, 8, 100, 40, 13]], [[50, 51]], [[4, 3, 26, 2]]]}
user: This is related to my other Kata about cats and dogs.

# Kata Task

I have a cat and a dog which I got as kitten / puppy.

I forget when that was, but I do know their current ages as `catYears` and `dogYears`.

Find how long I have owned each of my pets and return as a list [`ownedCat`, `ownedDog`]

NOTES:
* Results are truncated whole numbers of "human" years

## Cat Years

* `15` cat years for first year
* `+9` cat years for second year
* `+4` cat years for each year after that

## Dog Years

* `15` dog years for first year
* `+9` dog years for second year
* `+5` dog years for each year after that



**References**

* http://www.catster.com/cats-101/calculate-cat-age-in-cat-years
* http://www.slate.com/articles/news_and_politics/explainer/2009/05/a_dogs_life.html

Answer: {"fn_name": "owned_cat_and_dog", "inputs": [[9, 7], [15, 15], [18, 21], [19, 17], [24, 24], [25, 25], [26, 26], [27, 27], [56, 64]], "outputs": [[[0, 0]], [[1, 1]], [[1, 1]], [[1, 1]], [[2, 2]], [[2, 2]], [[2, 2]], [[2, 2]], [[10, 10]]]}
user: Your job is to write a function which increments a string, to create a new string.

- If the string already ends with a number, the number should be incremented by 1.
- If the string does not end with a number. the number 1 should be appended to the new string.

Examples:

`foo -> foo1`

`foobar23 -> foobar24`

`foo0042 -> foo0043`

`foo9 -> foo10`

`foo099 -> foo100`

*Attention: If the number has leading zeros the amount of digits should be considered.*

Answer: {"fn_name": "increment_string", "inputs": [["foo"], ["foobar001"], ["foobar1"], ["foobar00"], ["foobar99"], [""], ["foobar000"], ["foobar999"], ["foobar00999"], ["1"], ["009"]], "outputs": [["foo1"], ["foobar002"], ["foobar2"], ["foobar01"], ["foobar100"], ["1"], ["foobar001"], ["foobar1000"], ["foobar01000"], ["2"], ["010"]]}
user: The Earth has been invaded by aliens. They demand our beer and threaten to destroy the Earth if we do not supply the exact number of beers demanded.

Unfortunately, the aliens only speak Morse code. Write a program to convert morse code into numbers using the following convention:

1 .----
2 ..---
3 ...--
4 ....-
5 .....
6 -....
7 --...
8 ---..
9 ----.
0 -----

Answer: {"fn_name": "morse_converter", "inputs": [[".----.----.----.----.----"], ["..----------...-....----------"], ["---------------"], ["..---.--------....--"], [".----..---...--....-.....-....--...---..----.-----"]], "outputs": [[11111], [207600], [0], [2193], [1234567890]]}
user: For every good kata idea there seem to be quite a few bad ones!

In this kata you need to check the provided 2 dimensional array (x) for good ideas 'good' and bad ideas 'bad'. If there are one or two good ideas, return 'Publish!', if there are more than 2 return 'I smell a series!'. If there are no good ideas, as is often the case, return 'Fail!'.

The sub arrays may not be the same length.

The solution should be case insensitive (ie good, GOOD and gOOd all count as a good idea). All inputs may not be strings.

Answer: {"fn_name": "well", "inputs": [[[["bad", "bAd", "bad"], ["bad", "bAd", "bad"], ["bad", "bAd", "bad"]]], [[["gOOd", "bad", "BAD", "bad", "bad"], ["bad", "bAd", "bad"], ["GOOD", "bad", "bad", "bAd"]]], [[["gOOd", "bAd", "BAD", "bad", "bad", "GOOD"], ["bad"], ["gOOd", "BAD"]]]], "outputs": [["Fail!"], ["Publish!"], ["I smell a series!"]]}
user: A lot of goods have an  International Article Number (formerly known as "European Article Number") abbreviated "EAN". EAN is a 13-digits barcode consisting of 12-digits data followed by a single-digit checksum (EAN-8 is not considered in this kata).


The single-digit checksum is calculated as followed (based upon the 12-digit data):

The digit at the first, third, fifth, etc. position (i.e. at the odd position) has to be multiplied with "1". 
The digit at the second, fourth, sixth, etc. position (i.e. at the even position) has to be multiplied with "3".
Sum these results. 

If this sum is dividable by 10, the checksum is 0. Otherwise the checksum has the following formula:

  checksum = 10 - (sum mod 10)

For example, calculate the checksum for "400330101839" (= 12-digits data):

4·1 + 0·3 + 0·1 + 3·3 + 3·1 + 0·3 + 1·1 + 0·3 + 1·1 + 8·3 + 3·1 + 9·3
= 4 + 0 + 0 + 9 + 3 + 0 + 1 + 0 + 1 + 24 + 3 + 27 
= 72
10 - (72 mod 10) = 8 ⇒ Checksum: 8

Thus, the EAN-Code is 4003301018398 (= 12-digits data followed by single-digit checksum).
 
Your Task
Validate a given EAN-Code. Return true if the given EAN-Code is valid, otherwise false.

Assumption
You can assume the given code is syntactically valid, i.e. it only consists of numbers and it exactly has a length of 13 characters.

Examples

```python
validate_ean("4003301018398") # => True
validate_ean("4003301018392") # => False
```

Good Luck and have fun.

Answer: {"fn_name": "validate_ean", "inputs": [["9783815820865"], ["9783815820864"], ["9783827317100"]], "outputs": [[true], [false], [true]]}
user: The town sheriff dislikes odd numbers and wants all odd numbered families out of town! In town crowds can form and individuals are often mixed with other people and families. However you can distinguish the family they belong to by the number on the shirts they wear. As the sheriff's assistant it's your job to find all the odd numbered families and remove them from the town!
~~~if-not:cpp
Challenge: You are given a list of numbers. The numbers each repeat a certain number of times. Remove all numbers that repeat an odd number of times while keeping everything else the same.
~~~
~~~if:cpp
Challenge: You are given a vector of numbers. The numbers each repeat a certain number of times. Remove all numbers that repeat an odd number of times while keeping everything else the same.
~~~
```python
odd_ones_out([1, 2, 3, 1, 3, 3]) = [1, 1]
```
In the above example:
- the number 1 appears twice
- the number 2 appears once
- the number 3 appears three times

`2` and `3` both appear an odd number of times, so they are removed from the list. The final result is: `[1,1]`

Here are more examples:
```python
odd_ones_out([1, 1, 2, 2, 3, 3, 3]) = [1, 1, 2, 2]
odd_ones_out([26, 23, 24, 17, 23, 24, 23, 26]) = [26, 24, 24, 26]
odd_ones_out([1, 2, 3]) = []
odd_ones_out([1]) = []
```

Are you up to the challenge?

Answer: {"fn_name": "odd_ones_out", "inputs": [[[1, 2, 3, 1, 3, 3]], [[75, 68, 75, 47, 68]], [[42, 72, 32, 4, 94, 82, 67, 67]], [[100, 100, 5, 5, 100, 50, 68, 50, 68, 50, 68, 5, 100]], [[82, 86, 71, 58, 44, 79, 50, 44, 79, 67, 82, 82, 55, 50]]], "outputs": [[[1, 1]], [[75, 68, 75, 68]], [[67, 67]], [[100, 100, 100, 100]], [[44, 79, 50, 44, 79, 50]]]}
user: # Task

Given an array of roots of a polynomial equation, you should reconstruct this equation.

___

## Output details:

* If the power equals `1`, omit it: `x = 0` instead of `x^1 = 0`
* If the power equals `0`, omit the `x`: `x - 2 = 0` instead of `x - 2x^0 = 0`
* There should be no 2 signs in a row: `x - 1 = 0` instead of `x + -1 = 0`
* If the coefficient equals `0`, skip it: `x^2 - 1 = 0` instead of `x^2 + 0x - 1 = 0`
* Repeating roots should not be filtered out: `x^2 - 4x + 4 = 0` instead of `x - 2 = 0`
* The coefficient before `q^n` is always `1`: `x^n + ... = 0` instead of `Ax^n + ... = 0`

___

## Example:

```
polynomialize([0])        =>  "x = 0"
polynomialize([1])        =>  "x - 1 = 0"
polynomialize([1, -1])    =>  "x^2 - 1 = 0"
polynomialize([0, 2, 3])  =>  "x^3 - 5x^2 + 6x = 0"
```

___

## Tests:

```python
      Main suite:                  Edge cases:
 (Reference - 4000 ms)         (Reference - 30 ms)

N of roots | N of tests      N of roots | N of tests
-----------------------      -----------------------
    1-10   |   100              20-40   |    125
 700-750   |    25               2-20   |    125
```

Answer: {"fn_name": "polynomialize", "inputs": [[[0]], [[0, 0]], [[-1]], [[1]], [[1, -1]], [[0, -2, -3]], [[0, 2, 3]], [[1, 2, 3, 4, 5]]], "outputs": [["x = 0"], ["x^2 = 0"], ["x + 1 = 0"], ["x - 1 = 0"], ["x^2 - 1 = 0"], ["x^3 + 5x^2 + 6x = 0"], ["x^3 - 5x^2 + 6x = 0"], ["x^5 - 15x^4 + 85x^3 - 225x^2 + 274x - 120 = 0"]]}
user: Write a function that takes a list of at least four elements as an argument and returns a list of the middle two or three elements in reverse order.

Answer: {"fn_name": "reverse_middle", "inputs": [[[4, 3, 100, 1]], [[1, false, "string", {}, 7.43]]], "outputs": [[[100, 3]], [[{}, "string", false]]]}
user: In this Kata, you're to complete the function `sum_square_even_root_odd`.

You will be given a list of numbers, `nums`, as the only argument to the function. Take each number in the list and *square* it if it is even, or *square root* the number if it is odd. Take this new list and find the *sum*, rounding to two decimal places.

The list will never be empty and will only contain values that are greater than or equal to zero.

Good luck!

Answer: {"fn_name": "sum_square_even_root_odd", "inputs": [[[4, 5, 7, 8, 1, 2, 3, 0]], [[1, 14, 9, 8, 17, 21]]], "outputs": [[91.61], [272.71]]}
user: # Task
 Given array of integers, for each position i, search among the previous positions for the last (from the left) position that contains a smaller value. Store this value at position i in the answer. If no such value can be found, store `-1` instead.

# Example

 For `items = [3, 5, 2, 4, 5]`, the output should be `[-1, 3, -1, 2, 4]`.

# Input/Output


 - `[input]` integer array `arr`

   Non-empty array of positive integers.

   Constraints: `3 ≤ arr.length ≤ 1000, 1 ≤ arr[i] ≤ 1000.`


 - `[output]` an integer array

   Array containing answer values computed as described above.

Answer: {"fn_name": "array_previous_less", "inputs": [[[3, 5, 2, 4, 5]], [[2, 2, 1, 3, 4, 5, 5, 3]], [[3, 2, 1]]], "outputs": [[[-1, 3, -1, 2, 4]], [[-1, -1, -1, 1, 3, 4, 4, 1]], [[-1, -1, -1]]]}
user: You are playing euchre and you want to know the new score after finishing a hand. There are two teams and each hand consists of 5 tricks. The team who wins the majority of the tricks will win points but the number of points varies. To determine the number of points, you must know which team called trump, how many tricks each team won, and if anyone went alone. Scoring is as follows:

For the team that called trump:

- if they win 2 or less tricks -> other team wins 2 points

- if they win 3 or 4 tricks -> 1 point

- if they don't go alone and win 5 tricks -> 2 points

- if they go alone and win 5 tricks -> 4 points

Only the team who called trump can go alone and you will notice that it only increases your points if you win all 5 tricks.


Your job is to create a method to calculate the new score. When reading the arguments, team 1 is represented by 1 and team 2 is represented by 2. All scores will be stored with this order: { team1, team2 }.

Answer: {"fn_name": "update_score", "inputs": [[[4, 0], 1, false, [2, 2, 2, 2, 2]], [[4, 2], 1, true, [2, 2, 2, 2, 2]], [[4, 4], 2, false, [2, 2, 2, 2, 2]], [[4, 6], 2, true, [2, 2, 2, 2, 2]], [[7, 2], 1, false, [1, 2, 2, 2, 2]], [[7, 4], 1, true, [1, 2, 2, 2, 2]], [[7, 6], 2, false, [1, 2, 2, 2, 2]], [[7, 7], 2, true, [1, 2, 2, 2, 2]], [[5, 1], 1, false, [1, 1, 2, 2, 2]], [[5, 3], 1, true, [1, 1, 2, 2, 2]], [[5, 5], 2, false, [1, 1, 2, 2, 2]], [[5, 6], 2, true, [1, 1, 2, 2, 2]], [[3, 4], 1, false, [1, 1, 1, 2, 2]], [[4, 4], 1, true, [1, 1, 1, 2, 2]], [[5, 4], 2, false, [1, 1, 1, 2, 2]], [[7, 4], 2, true, [1, 1, 1, 2, 2]], [[3, 9], 1, false, [1, 1, 1, 1, 2]], [[4, 9], 1, true, [1, 1, 1, 1, 2]], [[5, 9], 2, false, [1, 1, 1, 1, 2]], [[7, 9], 2, true, [1, 1, 1, 1, 2]], [[0, 8], 1, false, [1, 1, 1, 1, 1]], [[2, 8], 1, true, [1, 1, 1, 1, 1]], [[6, 8], 2, false, [1, 1, 1, 1, 1]], [[8, 8], 2, true, [1, 1, 1, 1, 1]]], "outputs": [[[4, 2]], [[4, 4]], [[4, 6]], [[4, 10]], [[7, 4]], [[7, 6]], [[7, 7]], [[7, 8]], [[5, 3]], [[5, 5]], [[5, 6]], [[5, 7]], [[4, 4]], [[5, 4]], [[7, 4]], [[9, 4]], [[4, 9]], [[5, 9]], [[7, 9]], [[9, 9]], [[2, 8]], [[6, 8]], [[8, 8]], [[10, 8]]]}
user: There's a new security company in Paris, and they decided to give their employees an algorithm to make first name recognition faster. In the blink of an eye, they can now detect if a string is a first name, no matter if it is a one-word name or an hyphenated name. They're given this documentation with the algorithm: 

*In France, you'll often find people with hyphenated first names. They're called "prénoms composés".
There could be two, or even more words linked to form a new name, quite like jQuery function chaining ;). 
They're linked using the - symbol, like Marie-Joelle, Jean-Michel, Jean-Mouloud. 
Thanks to this algorithm, you can now recognize hyphenated names quicker than Flash !* 
(yeah, their employees know how to use jQuery. Don't ask me why)


Your mission if you accept it, recreate the algorithm.
Using the function **showMe**, which takes a **yourID** argument, you will check if the given argument is a name or not, by returning true or false. 

*Note that*

- String will either be a one-word first name, or an hyphenated first name , its words being linked by "-". 
- Words can only start with an uppercase letter, and then lowercase letters (from a to z)


Now is your time to help the guards !

Answer: {"fn_name": "show_me", "inputs": [["Francis"], ["Jean-Eluard"], ["Le Mec"], ["Bernard-Henry-Levy"], ["Meme Gertrude"], ["A-a-a-a----a-a"], ["Z-------------"], ["Jean-luc"], ["Jean--Luc"], ["JeanLucPicard"], ["-Jean-Luc"], ["Jean-Luc-Picard-"]], "outputs": [[true], [true], [false], [true], [false], [false], [false], [false], [false], [false], [false], [false]]}
user: Given the number n, return a string which shows the minimum number of moves to complete the tower of Hanoi consisting of n layers.
Tower of Hanoi : https://en.wikipedia.org/wiki/Tower_of_Hanoi

Example - 2 layered Tower of Hanoi 

Input: n=2

Start
[[2, 1], [], []]

Goal
[[], [], [2, 1]]

Expected Output : '[[2, 1], [], []]\n[[2], [1], []]\n[[], [1], [2]]\n[[], [], [2, 1]]'

Answer: {"fn_name": "hanoiArray", "inputs": [[2], [3]], "outputs": [["[[2, 1], [], []]\n[[2], [1], []]\n[[], [1], [2]]\n[[], [], [2, 1]]"], ["[[3, 2, 1], [], []]\n[[3, 2], [], [1]]\n[[3], [2], [1]]\n[[3], [2, 1], []]\n[[], [2, 1], [3]]\n[[1], [2], [3]]\n[[1], [], [3, 2]]\n[[], [], [3, 2, 1]]"]]}
user: Base on the fairy tale [Diamonds and Toads](https://en.wikipedia.org/wiki/Diamonds_and_Toads) from Charles Perrault. In this kata you will have to complete a function that take 2 arguments: 

- A string, that correspond to what the daugther says.
- A string, that tell you wich fairy the girl have met, this one can be `good` or `evil`. 

The function should return the following count as a hash:

- If the girl have met the `good` fairy:
  - count 1 `ruby` everytime you see a `r` and 2 everytime you see a `R`
  - count 1 `crystal` everytime you see a `c` and 2 everytime you see a `C`
- If the girl have met the `evil` fairy: 
  - count 1 `python` everytime you see a `p` and 2 everytime uou see a `P`
  - count 1 `squirrel` everytime you see a `s` and 2 everytime you see a `S`
  
**Note**: For this kata I decided to remplace the normal `Diamonds` and `Toads` by some programming languages. And just discover that [Squirrel](https://en.wikipedia.org/wiki/Squirrel_(programming_language) is a programming language.

Answer: {"fn_name": "diamonds_and_toads", "inputs": [["Ruby and Crystal", "good"], ["This string contain some Ruby and some Crystal in it", "good"], ["Python and Squirrel", "evil"], ["This string contain some Python and some Squirrel in it", "evil"]], "outputs": [[{"ruby": 3, "crystal": 2}], [{"ruby": 4, "crystal": 3}], [{"python": 2, "squirrel": 2}], [{"python": 2, "squirrel": 6}]]}
user: Given a number **n**, return the number of positive odd numbers below **n**, EASY!

Expect large Inputs!

Answer: {"fn_name": "odd_count", "inputs": [[15], [15023]], "outputs": [[7], [7511]]}
user: Your coworker was supposed to write a simple helper function to capitalize a string (that contains a single word) before they went on vacation.

Unfortunately, they have now left and the code they gave you doesn't work. Fix the helper function they wrote so that it works as intended (i.e. make the first character in the string "word" upper case).

Don't worry about numbers, special characters, or non-string types being passed to the function. The string lengths will be from 1 character up to 10 characters, but will never be empty.

Answer: {"fn_name": "capitalize_word", "inputs": [["word"], ["i"], ["glasswear"]], "outputs": [["Word"], ["I"], ["Glasswear"]]}
user: The male gametes or sperm cells in humans and other mammals are heterogametic and contain one of two types of sex chromosomes. They are either X or Y. The female gametes or eggs however, contain only the X sex chromosome and are homogametic.

The sperm cell determines the sex of an individual in this case. If a sperm cell containing an X chromosome fertilizes an egg, the resulting zygote will be XX or female. If the sperm cell contains a Y chromosome, then the resulting zygote will be XY or male.

Determine if the sex of the offspring will be male or female based on the X or Y chromosome present in the male's sperm.

If the sperm contains the X chromosome, return "Congratulations! You're going to have a daughter.";
If the sperm contains the Y chromosome, return "Congratulations! You're going to have a son.";

Answer: {"fn_name": "chromosome_check", "inputs": [["XY"], ["XX"]], "outputs": [["Congratulations! You're going to have a son."], ["Congratulations! You're going to have a daughter."]]}