meetforever/GRPO_CL huggingface dataset:
user: Timothy (age: 16) really likes to smoke. Unfortunately, he is too young to buy his own cigarettes and that's why he has to be extremely efficient in smoking.

It's now your task to create a function that calculates how many cigarettes Timothy can smoke out of the given amounts of `bars` and `boxes`:

- a bar has 10 boxes of cigarettes,
- a box has 18 cigarettes,
- out of 5 stubs (cigarettes ends) Timothy is able to roll a new one,
- of course the self made cigarettes also have an end which can be used to create a new one...

Please note that Timothy never starts smoking cigarettes that aren't "full size" so the amount of smoked cigarettes is always an integer.

Answer: {"fn_name": "start_smoking", "inputs": [[0, 1], [1, 0], [1, 1]], "outputs": [[22], [224], [247]]}
user: If you have not ever heard the term **Arithmetic Progrossion**, refer to: 
http://www.codewars.com/kata/find-the-missing-term-in-an-arithmetic-progression/python

And here is an unordered version. Try if you can survive lists of **MASSIVE** numbers (which means time limit should be considered). :D

Note: Don't be afraid that the minimum or the maximum element in the list is missing, e.g. [4, 6, 3, 5, 2] is missing 1 or 7, but this case is excluded from the kata.

Example:

```python
find([3, 9, 1, 11, 13, 5]) # => 7
```

Answer: {"fn_name": "find", "inputs": [[[3, 9, 1, 11, 13, 5]], [[5, -1, 0, 3, 4, -3, 2, -2]], [[2, -2, 8, -8, 4, -4, 6, -6]]], "outputs": [[7], [1], [0]]}
user: Find the closest prime number under a certain integer ```n``` that has the maximum possible amount of even digits.

For ```n = 1000```, the highest prime under ```1000``` is ```887```, having two even digits (8 twice)

Naming ```f()```, the function that gives that prime, the above case and others will be like the following below.
```
f(1000) ---> 887 (even digits: 8, 8)

f(1210) ---> 1201 (even digits: 2, 0)

f(10000) ---> 8887

f(500) ---> 487

f(487) ---> 467
``` 
Features of the random tests:
```
Number of tests = 28
1000 <= n <= 5000000
```

Enjoy it!!

Answer: {"fn_name": "f", "inputs": [[1000], [10000], [500], [487]], "outputs": [[887], [8887], [487], [467]]}
user: Given a number, write a function to output its reverse digits.  (e.g. given 123 the answer is 321)


Numbers should preserve their sign; i.e. a negative number should still be negative when reversed.

### Examples
```
 123 ->  321
-456 -> -654
1000 ->    1
```

Answer: {"fn_name": "reverse_number", "inputs": [[123], [-123], [1000], [4321234], [5], [0], [98989898]], "outputs": [[321], [-321], [1], [4321234], [5], [0], [89898989]]}
user: Hello everyone.

I have a simple challenge for you today. In mathematics, the formula for finding the sum to infinity of a geometric sequence is: 



**ONLY IF** `-1 < r < 1`

where:

* `a` is the first term of the sequence
* `r` is the common ratio of the sequence (calculated by dividing one term in the sequence by the previous term)

For example: `1 + 0.5 + 0.25 + 0.125 + ... = 2`

Your challenge is to calculate the sum to infinity of the given sequence. The solution must be rounded to 3 decimal places.

If there are no solutions, for example if `r` is out of the above boundaries, return `"No Solutions"`.

Hope you enjoy, let me know of any issues or improvements!

Answer: {"fn_name": "sum_to_infinity", "inputs": [[[1, 0.5, 0.25, 0.125]], [[250, 100, 40, 16]], [[21, 4.2, 0.84, 0.168]], [[5, -2.5, 1.25, -0.625]]], "outputs": [[2], [416.667], [26.25], [3.333]]}
user: Given an array (or list or vector) of arrays (or, guess what, lists or vectors) of integers, your goal is to return the sum of a specific set of numbers, starting with elements whose position is equal to the main array length and going down by one at each step.

Say for example the parent array (etc, etc) has 3 sub-arrays inside: you should consider the third  element of the first sub-array, the second of the second array and the first element in the third one: `[[3, 2, 1, 0], [4, 6, 5, 3, 2], [9, 8, 7, 4]]` would have you considering `1` for `[3, 2, 1, 0]`, `6` for `[4, 6, 5, 3, 2]` and `9` for `[9, 8, 7, 4]`, which sums up to `16`.

One small note is that not always each sub-array will have enough elements, in which case you should then use a default value (if provided) or `0` (if not provided), as shown in the test cases.

Answer: {"fn_name": "elements_sum", "inputs": [[[[3, 2, 1, 0], [4, 6, 5, 3, 2], [9, 8, 7, 4]]], [[[3], [4, 6, 5, 3, 2], [9, 8, 7, 4]]], [[[3, 2, 1, 0], [4, 6, 5, 3, 2], []]], [[[3, 2, 1, 0], [4, 6, 5, 3, 2], []], 5], [[[3, 2], [4], []]]], "outputs": [[16], [15], [7], [12], [0]]}
user: Write a simple parser that will parse and run Deadfish.  

Deadfish has 4 commands, each 1 character long:
* `i` increments the value (initially `0`)
* `d` decrements the value
* `s` squares the value
* `o` outputs the value into the return array

Invalid characters should be ignored.

```python
parse("iiisdoso")  ==>  [8, 64]
```

Answer: {"fn_name": "parse", "inputs": [["ooo"], ["ioioio"], ["idoiido"], ["isoisoiso"], ["codewars"]], "outputs": [[[0, 0, 0]], [[1, 2, 3]], [[0, 1]], [[1, 4, 25]], [[0]]]}
user: Imagine there's a big cube consisting of n^3 small cubes. Calculate, how many small cubes are not visible from outside.

For example, if we have a cube which has 4 cubes in a row, then the function should return 8, because there are 8 cubes inside our cube (2 cubes in each dimension)

Answer: {"fn_name": "not_visible_cubes", "inputs": [[0], [1], [2], [3], [4], [5], [7], [12], [18], [10002]], "outputs": [[0], [0], [0], [1], [8], [27], [125], [1000], [4096], [1000000000000]]}
user: # Task
Given array of integers `sequence` and some integer `fixedElement`, output the number of `even` values in sequence before the first occurrence of `fixedElement` or `-1` if and only if `fixedElement` is not contained in sequence.



# Input/Output


`[input]` integer array `sequence`

A non-empty array of positive integers.

`4 ≤ sequence.length ≤ 100`

`1 ≤ sequence[i] ≤ 9`

`[input]` integer `fixedElement`

An positive integer

`1 ≤ fixedElement ≤ 9`

`[output]` an integer


# Example

For `sequence = [1, 4, 2, 6, 3, 1] and fixedElement = 6`, the output should be `2`.

There are `2` even numbers before `6`: `4 and 2`

For `sequence = [2, 2, 2, 1] and fixedElement = 3`, the output should be `-1`.

There is no `3` appears in `sequence`. So returns `-1`.

For `sequence = [1, 3, 4, 3] and fixedElement = 3`, the output should be `0`.

`3` appears in `sequence`, but there is no even number before `3`.

Answer: {"fn_name": "even_numbers_before_fixed", "inputs": [[[1, 4, 2, 6, 3, 1], 6], [[2, 2, 2, 1], 3], [[2, 3, 4, 3], 3], [[1, 3, 4, 3], 3]], "outputs": [[2], [-1], [1], [0]]}
user: ## Description
You are a *Fruit Ninja*, your skill is cutting fruit. All the fruit will be cut in half by your knife. For example:

```
[  "apple",     "pear",     "banana"  ]  --> ["app", "le", "pe", "ar", "ban", "ana"]
```
As you see, all fruits are cut in half. You should pay attention to `"apple"`: if you cannot cut a fruit into equal parts, then the first part will has a extra character.

You should only cut the fruit, other things **should not be cut**, such as the `"bomb"`:
```
[  "apple",     "pear",     "banana",   "bomb"]  -->
["app", "le", "pe", "ar", "ban", "ana", "bomb"]
```

The valid fruit names are preloded for you as:
```python
FRUIT_NAMES
```

## Task

```if:javascript
Complete function `cutFruits` that accepts argument `fruits`.
Returns the result in accordance with the rules above.
```
```if:ruby,python
Complete function `cut_fruits` that accepts argument `fruits`.
Returns the result in accordance with the rules above.
```
```if:haskell
Complete function cutFruits that accepts a String array/list.
Returns the result in accordance with the rules above.
```

OK, that's all. I guess this is a 7kyu kata. If you agree, please rank it as 7kyu and vote `very`;-) If you think this kata is too easy or too hard, please shame me by rank it as you want and vote `somewhat` or `none` :[

---

##### *[Click here](https://www.codewars.com/kata/search/?q=i+guess+this+is+a+kyu+kata)  for more more "I guess this is ...kyu" katas!*

Answer: {"fn_name": "cut_fruits", "inputs": [[["apple", "pear", "banana"]], [["apple", "pear", "banana", "bomb"]], [[]]], "outputs": [[["app", "le", "pe", "ar", "ban", "ana"]], [["app", "le", "pe", "ar", "ban", "ana", "bomb"]], [[]]]}
user: Write a function called calculate that takes 3 values. The first and third values are numbers. The second value is a character. If the character is "+" , "-", "*", or "/", the function will return the result of the corresponding mathematical function on the two numbers. If the string is not one of the specified characters, the function should return null (throw an `ArgumentException` in C#).

Keep in mind, you cannot divide by zero. If an attempt to divide by zero is made, return null (throw an `ArgumentException` in C#)/(None in Python).

Answer: {"fn_name": "calculate", "inputs": [[3.2, "+", 8], [3.2, "-", 8], [3.2, "/", 8], [3.2, "*", 8], [-3, "+", 0], [-3, "-", 0], [-2, "/", -2], [-3, "*", 0], [-3, "/", 0], [-3, "w", 0], [-3, "w", 1]], "outputs": [[11.2], [-4.8], [0.4], [25.6], [-3], [-3], [1], [0], [null], [null], [null]]}
user: You task is to implement an simple interpreter for the notorious esoteric language [HQ9+](https://esolangs.org/wiki/HQ9+) that will work for a single character input:

- If the input is `'H'`, return `'Hello World!'`
- If the input is `'Q'`, return the input
- If the input is `'9'`, return the full lyrics of [99 Bottles of Beer](http://www.99-bottles-of-beer.net/lyrics.html). It should be formatted like this:

```if:rust
__Note__: In Rust, return `Some` containing the appropriate value.
```

```
99 bottles of beer on the wall, 99 bottles of beer.
Take one down and pass it around, 98 bottles of beer on the wall.
98 bottles of beer on the wall, 98 bottles of beer.
Take one down and pass it around, 97 bottles of beer on the wall.
97 bottles of beer on the wall, 97 bottles of beer.
Take one down and pass it around, 96 bottles of beer on the wall.
...
...
...
2 bottles of beer on the wall, 2 bottles of beer.
Take one down and pass it around, 1 bottle of beer on the wall.
1 bottle of beer on the wall, 1 bottle of beer.
Take one down and pass it around, no more bottles of beer on the wall.
No more bottles of beer on the wall, no more bottles of beer.
Go to the store and buy some more, 99 bottles of beer on the wall.
```

- For everything else, don't return anything (return `null` in C#, `None` in Rust).

(`+` has no visible effects so we can safely ignore it.)

Answer: {"fn_name": "HQ9", "inputs": [["X"], ["H"], ["Q"]], "outputs": [[null], ["Hello World!"], ["Q"]]}
user: Create a function that takes a string and an integer (`n`).

The function should return a string that repeats the input string `n` number of times.

If anything other than a string is passed in you should return `"Not a string"`


## Example

```
"Hi", 2 --> "HiHi"
1234, 5 --> "Not a string"
```

Answer: {"fn_name": "repeat_it", "inputs": [["*", 3], ["Hello", 11], ["243624", 22], [[], 3], [24, 3], [true, 3], ["Hello", 0]], "outputs": [["***"], ["HelloHelloHelloHelloHelloHelloHelloHelloHelloHelloHello"], ["243624243624243624243624243624243624243624243624243624243624243624243624243624243624243624243624243624243624243624243624243624243624"], ["Not a string"], ["Not a string"], ["Not a string"], [""]]}
user: Write a function that takes a single array as an argument (containing multiple strings and/or positive numbers and/or arrays), and returns one of four possible string values, depending on the ordering of the lengths of the elements in the input array:

Your function should return...

- “Increasing” - if the lengths of the elements increase from left to right (although it is possible that some neighbouring elements may also be equal in length)
- “Decreasing” - if the lengths of the elements decrease from left to right (although it is possible that some neighbouring elements may also be equal in length)
- “Unsorted” - if the lengths of the elements fluctuate from left to right
- “Constant” - if all element's lengths are the same.



Numbers and Strings should be evaluated based on the number of characters or digits used to write them.

Arrays should be evaluated based on the number of elements counted directly in the parent array (but not the number of elements contained in any sub-arrays).

Happy coding! :)

Answer: {"fn_name": "order_type", "inputs": [[[1, "b", ["p"], 2]], [[123, 1234, 12345, 123456]], [["a", "abc", "abcde", "ab"]], [[[1, 2, 3, 4], [5, 6, 7], [8, 9]]], [[1, 2, 3, 4, 56]], [[["ab", "cdef", "g"], ["hi", "jk", "lmnopq"], ["rst", "uv", "wx"], ["yz"]]], [[[1, 23, 456, 78910], ["abcdef", "ghijklmno", "pqrstuvwxy"], [[1, 23, 456, 78910, ["abcdef", "ghijklmno", "pqrstuvwxy"]], 1234]]], [[]], [["pippi", "pippi", "batuffulo", "pippi"]], [["pippi"]]], "outputs": [["Constant"], ["Increasing"], ["Unsorted"], ["Decreasing"], ["Increasing"], ["Decreasing"], ["Decreasing"], ["Constant"], ["Unsorted"], ["Constant"]]}
user: `Description:`

Given an input array (`arr`) of positive integers, the objective is to return an output array where each index represents the amount of times an element appeared (frequency) in the input array. 

More specifically, the element at each index of the output array will be an array (bucket) containing integers that appeared index-amount-of-times. 

Otherwise, slot nulls (JavaScript, Java), None's (Python) nils (Ruby), or NULL's (C/C++) where appropriate. A valid array will always be provided.

If an array of [1,2,3,4,4,5,5,5] is passed in, the expected output should be: [null, [1,2,3], [4], [5], null, null, null, null, null].

`Explanation:`

```python
# bucketize(arr) ======> outputArray
bucketize(1,2,3,4,4,5,5,5) ======> [None, [1, 2, 3], [4], [5], None, None, None, None, None]
```

An element cannot appear 0 times, so a null is placed at outputArray[0]. The elements 1, 2, and 3 appear once. This is why they are located at outputArray[1]. Notice the elements are grouped together in an array and sorted in ascending order. The element 4 appears twice. This is why it is located at outputArray[2]. The element 5 appears three times. This is why it is located at outputArray[3]. 

Although an integer could have possibly appeared four, five, six, seven, or eight times, this is not the case for this particular example. This is the reason why the elements at outputArray[4], outputArray[5], outputArray[6], outputArray[7], and outputArray[8] are all null values.

`Examples:`

```python
bucketize(2,2,4,4,6,6,9,9,9,9) ==> [None, None, [2,4,6], None, [9], None, None, None, None, None, None]
bucketize(3,3,3,3,2) ============> [None, [2], None, None, [3], None]
bucketize(5,5,5,5,5) ============> [None, None, None, None, None, [5]]
bucketize(77,3,40,40,40) ========> [None, [3,77], None, [40], None, None]
bucketize(16,7,5,3,6,23) ========> [None, [3,5,6,7,16,23], None, None, None, None, None]
```

Answer: {"fn_name": "bucketize", "inputs": [[2, 2, 4, 4, 6, 6, 9, 9, 9, 9], [3, 3, 3, 3, 2], [5, 5, 5, 5, 5], [77, 3, 40, 40, 40], [16, 7, 5, 3, 6, 23]], "outputs": [[[null, null, [2, 4, 6], null, [9], null, null, null, null, null, null]], [[null, [2], null, null, [3], null]], [[null, null, null, null, null, [5]]], [[null, [3, 77], null, [40], null, null]], [[null, [3, 5, 6, 7, 16, 23], null, null, null, null, null]]]}
user: You are given a list/array which contains only integers (positive and negative). Your job is to sum only the numbers that are the same and consecutive. The result should be one list.

Extra credit if you solve it in one line. You can assume there is never an empty list/array and there will always be an integer. 

Same meaning: 1 == 1

1 != -1

#Examples:

```
[1,4,4,4,0,4,3,3,1] # should return [1,12,0,4,6,1]

"""So as you can see sum of consecutives 1 is 1 
sum of 3 consecutives 4 is 12 
sum of 0... and sum of 2 
consecutives 3 is 6 ..."""

[1,1,7,7,3] # should return [2,14,3]
[-5,-5,7,7,12,0] # should return [-10,14,12,0]
```

Answer: {"fn_name": "sum_consecutives", "inputs": [[[1, 4, 4, 4, 0, 4, 3, 3, 1]], [[1, 1, 7, 7, 3]], [[-5, -5, 7, 7, 12, 0]], [[3, 3, 3, 3, 1]], [[2, 2, -4, 4, 5, 5, 6, 6, 6, 6, 6, 1]], [[1, 1, 1, 1, 1, 3]], [[1, -1, -2, 2, 3, -3, 4, -4]], [[0, 1, 1, 2, 2]]], "outputs": [[[1, 12, 0, 4, 6, 1]], [[2, 14, 3]], [[-10, 14, 12, 0]], [[12, 1]], [[4, -4, 4, 10, 30, 1]], [[5, 3]], [[1, -1, -2, 2, 3, -3, 4, -4]], [[0, 2, 4]]]}
user: The Collatz conjecture is one of the most famous one. Take any positive integer n, if it is even divide it by 2, if it is odd multiply it by 3 and add 1 and continue indefinitely.The conjecture is that whatever is n the sequence will reach 1. There is many ways to approach this problem, each one of them had given beautifull graphs and impressive display of calculation power. The simplest approach can be found in this kata: http://www.codewars.com/kata/5286b2e162056fd0cb000c20
You look at the Collatz sequence of a number and see when it reaches 1.

In this kata we will take a look at the length of collatz sequences. And how they evolve. Write a function that take a positive integer n and return the number between 1 and n that has the maximum Collatz sequence length and the maximum length. The output has to take the form of an array [number, maxLength] For exemple the Collatz sequence of 4 is [4,2,1], 3 is [3,10,5,16,8,4,2,1], 2 is [2,1], 1 is [1], so `MaxCollatzLength(4)` should return `[3,8]`. If n is not a positive integer, the function have to return [].

* As you can see, numbers in Collatz sequences may exceed n.

The last tests use random big numbers so you may consider some optimisation in your code:

* You may get very unlucky and get only hard numbers: try submitting 2-3 times if it times out; if it still does, probably you need to optimize your code more;

* Optimisation 1: when calculating the length of a sequence, if n is odd, what 3n+1 will be ?

* Optimisation 2: when looping through 1 to n, take i such that i<n/2, what will be the lenght of the sequence for 2i ?

Answer: {"fn_name": "max_collatz_length", "inputs": [[0], [1], [4], [30], [1000], [1000000], ["a"], [-1], [["a"]]], "outputs": [[[]], [[1, 1]], [[3, 8]], [[27, 112]], [[871, 179]], [[837799, 525]], [[]], [[]], [[]]]}
user: In this Kata, you will be given two strings `a` and `b` and your task will be to return the characters that are not common in the two strings. 

For example:
```Haskell
solve("xyab","xzca") = "ybzc" 
--The first string has 'yb' which is not in the second string. 
--The second string has 'zc' which is not in the first string. 
```
Notice also that you return the characters from the first string concatenated with those from the second string.

More examples in the tests cases. 

Good luck!

Please also try [Simple remove duplicates](https://www.codewars.com/kata/5ba38ba180824a86850000f7)

Answer: {"fn_name": "solve", "inputs": [["xyab", "xzca"], ["xyabb", "xzca"], ["abcd", "xyz"], ["xxx", "xzca"]], "outputs": [["ybzc"], ["ybbzc"], ["abcdxyz"], ["zca"]]}
user: You're looking through different hex codes, and having trouble telling the difference between  #000001  and  #100000 

We need a way to tell which is red, and which is blue!

That's where you create ```hex_color()```!

It should read an RGB input, and return whichever value (red, blue, or green) is of greatest concentration!

But, if multiple colors are of equal concentration, you should return their mix!

```python
red + blue = magenta

green + red = yellow

blue + green = cyan

red + blue + green = white
```

One last thing, if the string given is empty, or has all 0's, return black!

Examples:
```python
hex_color('087 255 054') == 'green'
hex_color('181 181 170') == 'yellow'
hex_color('000 000 000') == 'black'
hex_color('001 001 001') == 'white'
```

Answer: {"fn_name": "hex_color", "inputs": [[""], ["000 000 000"], ["121 245 255"], ["027 100 100"], ["021 021 021"], ["255 000 000"], ["000 147 000"], ["212 103 212"], ["101 101 092"]], "outputs": [["black"], ["black"], ["blue"], ["cyan"], ["white"], ["red"], ["green"], ["magenta"], ["yellow"]]}
user: As you probably know, Fibonacci sequence are the numbers in the following integer sequence:
1, 1, 2, 3, 5, 8, 13...
Write a method that takes the index as an argument and returns last digit from fibonacci number. Example:
  getLastDigit(15) - 610. Your method must return 0 because the last digit of 610 is 0.
Fibonacci sequence grows very fast and value can take very big numbers (bigger than integer type can contain), so, please, be careful with overflow.

[Hardcore version of this kata](http://www.codewars.com/kata/find-last-fibonacci-digit-hardcore-version), no bruteforce will work here ;)

Answer: {"fn_name": "get_last_digit", "inputs": [[193150], [300], [20001], [800], [1001], [100], [260], [1111], [1234], [99999], [10], [234], [193241], [79], [270]], "outputs": [[5], [0], [6], [5], [1], [5], [5], [9], [7], [6], [5], [2], [1], [1], [0]]}
user: Our football team finished the championship.
The result of each match look like "x:y". Results of all matches are recorded in the collection.

For example:
```["3:1", "2:2", "0:1", ...]```

Write a function that takes such collection and counts the points of our team in the championship.
Rules for counting points for each match:
- if x>y - 3 points
- if x<y - 0 point
- if x=y - 1 point

Notes:
- there are 10 matches in the championship
- 0 <= x <= 4
- 0 <= y <= 4

Answer: {"fn_name": "points", "inputs": [[["1:0", "2:0", "3:0", "4:0", "2:1", "3:1", "4:1", "3:2", "4:2", "4:3"]], [["1:1", "2:2", "3:3", "4:4", "2:2", "3:3", "4:4", "3:3", "4:4", "4:4"]], [["0:1", "0:2", "0:3", "0:4", "1:2", "1:3", "1:4", "2:3", "2:4", "3:4"]], [["1:0", "2:0", "3:0", "4:0", "2:1", "1:3", "1:4", "2:3", "2:4", "3:4"]], [["1:0", "2:0", "3:0", "4:4", "2:2", "3:3", "1:4", "2:3", "2:4", "3:4"]]], "outputs": [[30], [10], [0], [15], [12]]}
user: I've got a crazy mental illness.
I dislike numbers a lot. But it's a little complicated:
The number I'm afraid of depends on which day of the week it is...
This is a concrete description of my mental illness:

Monday     --> 12

Tuesday    --> numbers greater than 95

Wednesday  --> 34

Thursday   --> 0

Friday     --> numbers divisible by 2

Saturday   --> 56

Sunday     --> 666 or -666


Write a function which takes a string (day of the week) and an integer (number to be tested) so it tells the doctor if I'm afraid or not. (return a boolean)

Answer: {"fn_name": "am_I_afraid", "inputs": [["Monday", 13], ["Monday", 12], ["Tuesday", 0], ["Tuesday", 100], ["Tuesday", 95], ["Wednesday", 35], ["Wednesday", 34], ["Thursday", 2], ["Thursday", 0], ["Friday", 5], ["Friday", 4], ["Saturday", 55], ["Saturday", 56], ["Sunday", 55], ["Sunday", 666], ["Sunday", -666]], "outputs": [[false], [true], [false], [true], [false], [false], [true], [false], [true], [false], [true], [false], [true], [false], [true], [true]]}
user: The hamming distance of two equal-length strings is the number of positions, in which the two string differ. In other words, the number of character substitutions required to transform one string into the other. 

For this first Kata, you will write a function ```hamming_distance(a, b)``` with two equal-length strings containing only 0s and 1s as parameters. There is no need to test the parameters for validity (but you can, if you want).The function's output should be the hamming distance of the two strings as an integer.

Example:

```python
hamming_distance('100101', '101001') == 2
hamming_distance('1010', '0101') == 4
```

Answer: {"fn_name": "hamming_distance", "inputs": [["100101", "101001"], ["1010", "0101"], ["100101011011010010010", "101100010110010110101"]], "outputs": [[2], [4], [9]]}