meetforever/GRPO_CL huggingface dataset:
user: Given an array of ones and zeroes, convert the equivalent binary value to an integer.

Eg: `[0, 0, 0, 1]` is treated as `0001` which is the binary representation of `1`.

Examples:
```
Testing: [0, 0, 0, 1] ==> 1
Testing: [0, 0, 1, 0] ==> 2
Testing: [0, 1, 0, 1] ==> 5
Testing: [1, 0, 0, 1] ==> 9
Testing: [0, 0, 1, 0] ==> 2
Testing: [0, 1, 1, 0] ==> 6
Testing: [1, 1, 1, 1] ==> 15
Testing: [1, 0, 1, 1] ==> 11
```

However, the arrays can have varying lengths, not just limited to `4`.

Answer: {"fn_name": "binary_array_to_number", "inputs": [[[0, 0, 0, 1]], [[0, 0, 1, 0]], [[1, 1, 1, 1]], [[0, 1, 1, 0]]], "outputs": [[1], [2], [15], [6]]}
user: You have to write two methods to *encrypt* and *decrypt* strings.
Both methods have two parameters:
```
1. The string to encrypt/decrypt
2. The Qwerty-Encryption-Key (000-999) 
```

The rules are very easy:
```
The crypting-regions are these 3 lines from your keyboard:
1. "qwertyuiop"
2. "asdfghjkl"
3. "zxcvbnm,."

If a char of the string is not in any of these regions, take the char direct in the output.
If a char of the string is in one of these regions: Move it by the part of the key in the 
region and take this char at the position from the region. 
If the movement is over the length of the region, continue at the beginning.
The encrypted char must have the same case like the decrypted char! 
So for upperCase-chars the regions are the same, but with pressed "SHIFT"!

The Encryption-Key is an integer number from 000 to 999. E.g.: 127

The first digit of the key (e.g. 1) is the movement for the first line.
The second digit of the key (e.g. 2) is the movement for the second line.
The third digit of the key (e.g. 7) is the movement for the third line.

(Consider that the key is an integer! When you got a 0 this would mean 000. A 1 would mean 001. And so on.)
```

You do not need to do any prechecks. The strings will always be not null 
and will always have a length > 0. You do not have to throw any exceptions.

An Example:
```
Encrypt "Ball" with key 134
1. "B" is in the third region line. Move per 4 places in the region. -> ">" (Also "upperCase"!)
2. "a" is in the second region line. Move per 3 places in the region. -> "f"
3. "l" is in the second region line. Move per 3 places in the region. -> "d"
4. "l" is in the second region line. Move per 3 places in the region. -> "d"
--> Output would be ">fdd"
```

*Hint: Don't forget: The regions are from an US-Keyboard!*
*In doubt google for "US Keyboard."*



This kata is part of the Simple Encryption Series:
Simple Encryption #1 - Alternating Split
Simple Encryption #2 - Index-Difference
Simple Encryption #3 - Turn The Bits Around
Simple Encryption #4 - Qwerty

Have fun coding it and please don't forget to vote and rank this kata! :-)

Answer: {"fn_name": "encrypt", "inputs": [["A", 111], ["Abc", 212], ["Ball", 134], ["Ball", 444], ["This is a test.", 348], ["Do the kata Kobayashi Maru Test. Endless fun and excitement when finding a solution.", 583]], "outputs": [["S"], ["Smb"], [">fdd"], [">gff"], ["Iaqh qh g iyhi,"], ["Sr pgi jlpl Jr,lqlage Zlow Piapc I.skiaa dw. l.s ibnepizi.p ugi. de.se.f l arkwper.c"]]}
user: You will receive an uncertain amount of integers in a certain order ```k1, k2, ..., kn```.

You form a new number of n digits in the following way:
you take one of the possible digits of the first given number, ```k1```, then the same with the given number ```k2```, repeating the same process up to ```kn``` and you concatenate these obtained digits(in the order that were taken) obtaining the new number. As you can see, we have many possibilities.

Let's see the process above explained with three given numbers:
```
k1 = 23, k2 = 17, k3 = 89
Digits Combinations   Obtained Number
  ('2', '1', '8')           218    <---- Minimum
  ('2', '1', '9')           219
  ('2', '7', '8')           278
  ('2', '7', '9')           279
  ('3', '1', '8')           318
  ('3', '1', '9')           319
  ('3', '7', '8')           378
  ('3', '7', '9')           379    <---- Maximum
             Total Sum =   2388   (8 different values)
```
We need the function that may work in this way:

```python
proc_seq(23, 17, 89) == [8, 218, 379, 2388]
```

See this special case and deduce how the function should handle the cases which have many repetitions.

```python
proc_seq(22, 22, 22, 22) == [1, 2222] # we have only one obtained number, the minimum, maximum and total sum coincide
```

The sequence of numbers will have numbers of n digits only. Numbers formed by leading zeroes will be discarded.

```python
proc_seq(230, 15, 8) == [4, 218, 358, 1152]
```

Enjoy it!!

You will never receive the number 0 and all the numbers will be in valid format.

Answer: {"fn_name": "proc_seq", "inputs": [[23, 17, 89], [22, 22, 22, 22], [230, 15, 8]], "outputs": [[[8, 218, 379, 2388]], [[1, 2222]], [[4, 218, 358, 1152]]]}
user: HTML Element Generator
In this kata, you will be creating a python function that will take arguments and turn them into an HTML element.
An HTML tag has three parts:

The opening tag, which consists of a tag name and potentially attributes, all in between angle brackets.
The element content, which is the data that is shown on the webpage.  This is in between the opening and closing tags.
And the closing tag, which is an opening angle bracket, a forward slash, the name of the tag, and a closing angle bracket


If you were to have multiple attributes, they would each appear with a single space separating them

Some tags do not require a closing tag.  These are called self-closing tags.  For this kata, any tag passed into the function without 'element content' (keyword arguments) will be treated in this way:  after the tag name (and any attributes), there will be a space and then a forward slash.  See the picture to the right.

Data will be passed into the html function as such: 

The first argument will be the tag name
Any other non-keyword arguments will be element content. If no element content is given, the return value will be expected to be a self-closing tag.  If more than one argument is given as element content, you will return multiple of the same element, just with different element content, separated by one or more newline characters.
Ex: 

<p class="paragraph-text" id="example">Hello World!</p>\n<p class="paragraph-text" id="example">This is HTML code!</p>

IMPORTANT:  Because class is a python keyword, and class is a very important HTML attribute, you will also have to implement a keyword argument named cls, as opposed to class.  This attribute will appear as class="variable" in the return value of your function
Any other keyword arguments of the function will be treated as attributes of the element.  The keyword is the attribute name (left of the equals sign), and the keyword's value is the attribute's value (right of the equals sign).
Element attributes will appear in the return value of your function in the order that they appear in the function's arguments when it is called.  If cls is an argument of the function, it will always appear first (before any other keyword arguments).
Several Examples are provided

Answer: {"fn_name": "html", "inputs": [["br"], ["title", "Webpage Title"]], "outputs": [["<br />"], ["<title>Webpage Title</title>"]]}
user: # Task

John has an important number, and he doesn't want others to see it.

He decided to encrypt the number, using the following steps:
```
His number is always a non strict increasing sequence
ie. "123"

He converted each digit into English words.
ie. "123"--> "ONETWOTHREE"

And then, rearrange the letters randomly.
ie. "ONETWOTHREE" --> "TTONWOHREEE"
```

John felt that his number were safe in doing so. In fact, such encryption can be easily decrypted :(

Given the encrypted string `s`, your task is to decrypt it, return the original number in string format.

Note, You can assume that the input string `s` is always valid; It contains only uppercase Letters; The decrypted numbers are arranged in ascending order; The leading zeros are allowed.


# Example

For `s = "ONE"`, the output should be `1`.

For `s = "EON"`, the output should be `1` too.

For `s = "ONETWO"`, the output should be `12`.

For `s = "OONETW"`, the output should be `12` too.

For `s = "ONETWOTHREE"`, the output should be `123`.

For `s = "TTONWOHREEE"`, the output should be `123` too.

Answer: {"fn_name": "original_number", "inputs": [["ONE"], ["OEN"], ["ONETWO"], ["OONETW"], ["TTONWOHREEE"]], "outputs": [["1"], ["1"], ["12"], ["12"], ["123"]]}
user: In this Kata you are expected to find the coefficients of quadratic equation of the given two roots (`x1` and `x2`).

Equation will be the form of ```ax^2 + bx + c = 0```

Return type is a Vector (tuple in Rust, Array in Ruby) containing coefficients of the equations in the order `(a, b, c)`.

Since there are infinitely many solutions to this problem, we fix `a = 1`.

Remember, the roots can be written like `(x-x1) * (x-x2) = 0`

### Example 

    quadratic(1,2) = (1, -3, 2)

This means `(x-1) * (x-2) = 0`; when we do the multiplication this becomes `x^2 - 3x + 2 = 0`

### Example 2

    quadratic(0,1) = (1, -1, 0)

This means `(x-0) * (x-1) = 0`; when we do the multiplication this becomes `x^2 - x + 0 = 0`

### Notes

* Inputs will be integers.
* When `x1 == x2`, this means the root has the multiplicity of two

Answer: {"fn_name": "quadratic", "inputs": [[0, 1], [4, 9], [2, 6], [-5, -4]], "outputs": [[[1, -1, 0]], [[1, -13, 36]], [[1, -8, 12]], [[1, 9, 20]]]}
user: Make a function that receives a value, ```val``` and outputs the smallest higher number than the given value, and this number belong to a set of positive integers that have the following properties:

- their digits occur only once

- they are odd

- they are multiple of three

```python
next_numb(12) == 15

next_numb(13) == 15

next_numb(99) == 105

next_numb(999999) == 1023459

next_number(9999999999) == "There is no possible number that
fulfills those requirements"
```

Enjoy the kata!!

Answer: {"fn_name": "next_numb", "inputs": [[12], [13], [99], [999999], [9999999999]], "outputs": [[15], [15], [105], [1023459], ["There is no possible number that fulfills those requirements"]]}
user: Given two arrays of strings, return the number of times each string of the second array appears in the first array.

#### Example

```python
array1 = ['abc', 'abc', 'xyz', 'cde', 'uvw']
array2 = ['abc', 'cde', 'uap']
```

How many times do the elements in `array2` appear in `array1`? 

* `'abc'` appears twice in the first array (2)
* `'cde'` appears only once (1)
* `'uap'` does not appear in the first array (0)

Therefore, `solve(array1, array2) = [2, 1, 0]`

Good luck!

If you like this Kata, please try:

[Word values](https://www.codewars.com/kata/598d91785d4ce3ec4f000018)

[Non-even substrings](https://www.codewars.com/kata/59da47fa27ee00a8b90000b4)

Answer: {"fn_name": "solve", "inputs": [[["abc", "abc", "xyz", "abcd", "cde"], ["abc", "cde", "uap"]], [["abc", "xyz", "abc", "xyz", "cde"], ["abc", "cde", "xyz"]], [["quick", "brown", "fox", "is", "quick"], ["quick", "abc", "fox"]]], "outputs": [[[2, 1, 0]], [[2, 1, 2]], [[2, 0, 1]]]}
user: In the morning all the doors in the school are closed. The school is quite big: there are **N** doors. Then pupils start coming. It might be hard to believe, but all of them want to study! Also, there are exactly **N** children studying in this school, and they come one by one.

When these strange children pass by some doors they change their status (i.e. Open -> Closed, Closed -> Open). Each student has their number, and each i-th student alters the status of every i-th door. For example: when the first child comes to the schools, he changes every first door (he opens all of them). The second one changes the status of every second door (he closes some doors: the 2nd, the 4th and so on). Finally, when the last one – the n-th – comes to the school, he changes the status of each n-th door (there's only one such door, though).

You need to count how many doors are left opened after all the students have come.

Example:

![](http://i.imgur.com/IqlOi2q.png)

*Here you can see red squares – closed doors, green – opened ones.*

Input:

> n – the number of doors and students, n ∈ N, n ∈ [1, 100000]

Output:

> o – the number of opened doors, o ∈ N

--- 

```
doors(5)
```

Should return

```
2
```

Answer: {"fn_name": "doors", "inputs": [[5], [10], [100]], "outputs": [[2], [3], [10]]}
user: Given an `x` and `y` find the smallest and greatest numbers **above** and **below** a given `n` that are divisible by both `x` and `y`.

### Examples
```python
greatest(2, 3, 20) => 18   # 18 is the greatest number under 20 that is divisible by both 2 and 3
smallest(2, 3, 20) => 24   # 24 is the smallest number above 20 that is divisible by both 2 and 3

greatest(5, 15, 100) => 90
smallest(5, 15, 100) => 105

greatest(123, 456, 789) => 0   # there are no numbers under 789 that are divisible by both 123 and 456
smallest(123, 456, 789) => 18696
```

**Notes:** 

1. you should never return `n` even if it is divisible by `x` and `y` always the number above or below it
2. `greatest` should return 0 if there are no numbers under `n` that are divisible by both `x` and `y`
3. and all arguments will be valid (integers greater than 0).

### Note for Haskell users

>Please take a look at [bkaes comment](http://www.codewars.com/kata/when-greatest-is-less-than-smallest/discuss#56418f0fbf1f44834d000050) and give us your opinion

Answer: {"fn_name": "greatest", "inputs": [[2, 3, 20], [13, 17, 100], [10, 100, 100], [1000000007, 1000000009, 10000000000000000000]], "outputs": [[18], [0], [0], [9000000144000000567]]}
user: Given a string and an array of integers representing indices, capitalize all letters at the given indices. 

For example:

* `capitalize("abcdef",[1,2,5]) = "aBCdeF"`
* `capitalize("abcdef",[1,2,5,100]) = "aBCdeF"`. There is no index 100.

The input will be a lowercase string with no spaces and an array of digits.

Good luck!

Be sure to also try: 

[Alternate capitalization](https://www.codewars.com/kata/59cfc000aeb2844d16000075)

[String array revisal](https://www.codewars.com/kata/59f08f89a5e129c543000069)

Answer: {"fn_name": "capitalize", "inputs": [["abcdef", [1, 2, 5]], ["abcdef", [1, 2, 5, 100]], ["codewars", [1, 3, 5, 50]], ["abracadabra", [2, 6, 9, 10]], ["codewarriors", [5]], ["indexinglessons", [0]]], "outputs": [["aBCdeF"], ["aBCdeF"], ["cOdEwArs"], ["abRacaDabRA"], ["codewArriors"], ["Indexinglessons"]]}
user: **An [isogram](https://en.wikipedia.org/wiki/Isogram)** (also known as a "nonpattern word") is a logological term for a word or phrase without a repeating letter. It is also used by some to mean a word or phrase in which each letter appears the same number of times, not necessarily just once.

You task is to write a method `isogram?` that takes a string argument and returns true if the string has the properties of being an isogram and false otherwise. Anything that is not a string is not an isogram (ints, nils, etc.)


**Properties:**
 
 - must be a string
 - cannot be nil or empty
 - each letter appears the same number of times (not necessarily just once)
 - letter case is not important (= case insensitive)
 - non-letter characters (e.g. hyphens) should be ignored

Answer: {"fn_name": "is_isogram", "inputs": [[null], [3], ["Dermatoglyphics"], ["isogram"], ["eleven"], ["moOse"], ["isIsogram"], [""], ["-.-"], ["subdermatoglyphic"], ["Alphabet"], ["thumbscrew-japingly"], ["Hjelmqvist-Gryb-Zock-Pfund-Wax"], ["Emily Jung Schwartzkopf"], ["aabbccddeeffgg"]], "outputs": [[false], [false], [true], [true], [false], [false], [false], [false], [false], [true], [false], [true], [true], [true], [true]]}
user: Your task is to Combine two Strings. But consider the rule...

By the way you don't have to check errors or incorrect input values, everything is ok without bad tricks, only two input strings and as result one output string;-)...

And here's the rule:  
Input Strings `a` and `b`: For every character in string `a` swap the casing of every occurrence of the same character in string `b`. Then do the same casing swap with the inputs reversed. Return a single string consisting of the changed version of `a` followed by the changed version of `b`. A char of `a` is in `b` regardless if it's in upper or lower case - see the testcases too.  
I think that's all;-)...

Some easy examples:

````
Input: "abc" and "cde"      => Output: "abCCde" 
Input: "ab" and "aba"       => Output: "aBABA"
Input: "abab" and "bababa"  => Output: "ABABbababa"
````

Once again for the last example - description from `KenKamau`, see discourse;-):

a) swap the case of characters in string `b` for every occurrence of that character in string `a`  
char `'a'` occurs twice in string `a`, so we swap all `'a'` in string `b` twice. This means we start with `"bababa"` then `"bAbAbA"` => `"bababa"`  
char `'b'` occurs twice in string `a` and so string `b` moves as follows: start with `"bababa"` then `"BaBaBa"` => `"bababa"`

b) then, swap the case of characters in string `a` for every occurrence in string `b`  
char `'a'` occurs `3` times in string `b`. So string `a` swaps cases as follows: start with `"abab"` then => `"AbAb"` => `"abab"` => `"AbAb"`  
char `'b'` occurs `3` times in string `b`. So string `a` swaps as follow: start with `"AbAb"` then => `"ABAB"` => `"AbAb"` => `"ABAB"`.

c) merge new strings `a` and `b`  
return `"ABABbababa"`

There are some static tests at the beginning and many random tests if you submit your solution.

Hope you have fun:-)!

Answer: {"fn_name": "work_on_strings", "inputs": [["abc", "cde"], ["abcdeFgtrzw", "defgGgfhjkwqe"], ["abcdeFg", "defgG"], ["abab", "bababa"]], "outputs": [["abCCde"], ["abcDeFGtrzWDEFGgGFhjkWqE"], ["abcDEfgDEFGg"], ["ABABbababa"]]}
user: # Task

Determine the client's membership level based on the invested `amount` of money and the given thresholds for membership levels.

There are four membership levels (from highest to lowest): `Platinum, Gold, Silver, Bronze`

The minimum investment is the threshold limit for `Bronze` membership. If the given amount is less than the `Bronze` treshold limit return `Not a member`.

A client belongs to a membership level when his invested amount is greater than or equal the level's threshold amount.

# Examples:
```
|--------+----------+------+--------+--------+--------------+------------------|
| Amount | Platinum | Gold | Silver | Bronze | Result       | Explanations     |
|--------+----------+------+--------+--------+--------------+------------------|
|   7000 |    10000 | 8000 |   6000 |   4000 | Silver       | Amount >= Silver |
|   3000 |    10000 | 8000 |   6000 |   5000 | Not a member | Amount < Bronze  |
|   8000 |    12000 | 8000 |   7000 |   5000 | Gold         | Amount >= Gold   |
|--------+----------+------+--------+--------+--------------+------------------|
```

# Restrictions

1. The first line of your code has to be `def membership(amount, platinum, gold, silver, bronze):`
2. Your code except for the firt line mustn't contain the words `platinum, gold, silver, bronze` or they reversed forms (e.g. `dlog`) or any string which contains these words or they reversed forms. (The check is **case-insensitive**.)
3. Must not contain: `+, %, {, }`.

# Disclaimer

This kata is about creativity not proper coding style. Your colleagues/boss won't like you if you make production code like this. :)

#### Don't forget to rate the kata after you finish it. :)

Happy coding!

suic

Answer: {"fn_name": "membership", "inputs": [[100000, 1000000, 100000, 10000, 1000], [1001, 1000000, 100000, 10000, 1000], [998, 1000000, 100000, 10000, 1000], [0, 1000000, 100000, 10000, 1000]], "outputs": [["Gold"], ["Bronze"], ["Not a member"], ["Not a member"]]}
user: Create a method `sayHello`/`say_hello`/`SayHello` that takes as input a name, city, and state to welcome a person. Note that `name` will be an array consisting of one or more values that should be joined together with one space between each, and the length of the `name` array in test cases will vary.

Example:

```python
say_hello(['John', 'Smith'], 'Phoenix', 'Arizona')
```

This example will return the string `Hello, John Smith! Welcome to Phoenix, Arizona!`

Answer: {"fn_name": "say_hello", "inputs": [[["John", "Smith"], "Phoenix", "Arizona"], [["Franklin", "Delano", "Roosevelt"], "Chicago", "Illinois"], [["Wallace", "Russel", "Osbourne"], "Albany", "New York"], [["Lupin", "the", "Third"], "Los Angeles", "California"], [["Marlo", "Stanfield"], "Baltimore", "Maryland"]], "outputs": [["Hello, John Smith! Welcome to Phoenix, Arizona!"], ["Hello, Franklin Delano Roosevelt! Welcome to Chicago, Illinois!"], ["Hello, Wallace Russel Osbourne! Welcome to Albany, New York!"], ["Hello, Lupin the Third! Welcome to Los Angeles, California!"], ["Hello, Marlo Stanfield! Welcome to Baltimore, Maryland!"]]}
user: Finding your seat on a plane is never fun, particularly for a long haul flight... You arrive, realise again just how little leg room you get, and sort of climb into the seat covered in a pile of your own stuff.

To help confuse matters (although they claim in an effort to do the opposite) many airlines omit the letters 'I' and 'J' from their seat naming system.

the naming system consists of a number (in this case between 1-60) that denotes the section of the plane where the seat is (1-20 = front, 21-40 = middle, 40+ = back). This number is followed by a letter, A-K with the exclusions mentioned above.

Letters A-C denote seats on the left cluster, D-F the middle and G-K the right.

Given a seat number, your task is to return the seat location in the following format:

'2B' would return 'Front-Left'.

If the number is over 60, or the letter is not valid, return 'No Seat!!'.

Answer: {"fn_name": "plane_seat", "inputs": [["2B"], ["20B"], ["58I"], ["60D"], ["17K"]], "outputs": [["Front-Left"], ["Front-Left"], ["No Seat!!"], ["Back-Middle"], ["Front-Right"]]}
user: We define the function `f1(n,k)`, as the least multiple of `n` that has all its digits less than `k`. 

We define the function `f2(n,k)`, as the least multiple of `n` that has all the digits that are less than `k`.

Each digit may occur more than once in both values of `f1(n,k)` and `f2(n,k)`.

The possible values for `n` and `k` according to these ranges for both functions `f1` and `f2` in this kata:
``` 
1 <= n <= 1.000.000.000.000
3 <= k <= 9
``` 

For example, let's see the value of both functions for `n = 71` and `k = 4`:
``` 
f1(71,4) == 213 # all its digits less than 4
f2(71,4) == 2130 # 0,1,2,3 all of them present 
```
The integer `76` is the first integer that has the same values of `f1` and `f2` for `k = 4`. 
```
f1(76,4) = f2(76,4) = 10032
```
Let's call these kind of numbers, **forgiving numbers**. (Let's continue with the fashion of attributing personality traits to numbers and, of course, an unknown one)
So, `76` is the smallest forgiving number of order `4`.
In the same way, `485` is the smallest forgiving number of order `5`.

Create a function that given an integer `n` and the order `k`, will output the higher and closest forgiving number to `n` of order `k`.

Let's see some examples:
```
find_f1_eq_f2(500,5) == 547
find_f1_eq_f2(1600,6) == 1799
find_f1_eq_f2(14900,7) == 14996
```
If the number `n` is a forgiving itself for a certain order `k`, the function will never output the same value, remember, closest and **higher** than `n`.

For example, `3456`, is a forgiving one of order `4`,
```
find_f1_eq_f2(3456,4) == 3462
```
**Features of the tests:**

* `n` and `k` will be always valid and positive integers.

* A total of 8 fixed tests.

* A total of 150 random tests in the ranges for `n` and `k` given above.

I'll be waiting your awesome solution. :)

Answer: {"fn_name": "find_f1_eq_f2", "inputs": [[542, 5], [1750, 6], [14990, 7], [3456, 4], [30500, 3], [62550, 5], [568525, 7], [9567100, 8]], "outputs": [[547], [1799], [14996], [3462], [30501], [62557], [568531], [9567115]]}