meetforever/GRPO_CL huggingface dataset:
user: =====Function Descriptions=====
.difference()

The tool .difference() returns a set with all the elements from the set that are not in an iterable.
Sometimes the - operator is used in place of the .difference() tool, but it only operates on the set of elements in set.
Set is immutable to the .difference() operation (or the - operation).

>>> s = set("Hacker")
>>> print s.difference("Rank")
set(['c', 'r', 'e', 'H'])

>>> print s.difference(set(['R', 'a', 'n', 'k']))
set(['c', 'r', 'e', 'H'])

>>> print s.difference(['R', 'a', 'n', 'k'])
set(['c', 'r', 'e', 'H'])

>>> print s.difference(enumerate(['R', 'a', 'n', 'k']))
set(['a', 'c', 'r', 'e', 'H', 'k'])

>>> print s.difference({"Rank":1})
set(['a', 'c', 'e', 'H', 'k', 'r'])

>>> s - set("Rank")
set(['H', 'c', 'r', 'e'])

=====Problem Statement=====
Students of District College have a subscription to English and French newspapers. Some students have subscribed to only the English newspaper, some have subscribed to only the French newspaper, and some have subscribed to both newspapers.

You are given two sets of student roll numbers. One set has subscribed to the English newspaper, and one set has subscribed to the French newspaper. Your task is to find the total number of students who have subscribed to only English newspapers.

=====Input Format=====
The first line contains the number of students who have subscribed to the English newspaper.
The second line contains the space separated list of student roll numbers who have subscribed to the English newspaper.
The third line contains the number of students who have subscribed to the French newspaper.
The fourth line contains the space separated list of student roll numbers who have subscribed to the French newspaper.

=====Constraints=====
0<Total number of students in college<1000

=====Output Format=====
Output the total number of students who are subscribed to the English newspaper only.
user: =====Problem Statement=====
Here is a sample line of code that can be executed in Python:
print("Hello, World!")

You can just as easily store a string as a variable and then print it to stdout:
my_string = "Hello, World!"
print(my_string)

The above code will print Hello, World! on your screen. Try it yourself in the editor below!

=====Input Format=====
You do not need to read any input in this challenge.

=====Output Format=====
Print Hello, World! to stdout.
user: Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:

 - There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
 - s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.

-----Constraints-----
 - 1 ≦ N, L ≦ 100
 - For each i, the length of S_i equals L.
 - For each i, S_i consists of lowercase letters.

-----Input-----
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N

-----Output-----
Print the lexicographically smallest string that Iroha can produce.

-----Sample Input-----
3 3
dxx
axx
cxx

-----Sample Output-----
axxcxxdxx

The following order should be used: axx, cxx, dxx.
user: We are still with squared integers.

Given 4 integers `a, b, c, d` we form the sum of the squares of `a` and `b`
and then the sum of the squares of `c` and `d`. We multiply the two sums hence a number `n` and we try to
decompose `n` in a sum of two squares `e` and `f` (e and f integers >= 0) so that `n = e² + f²`. 

More: `e` and `f` must result only from sums (or differences) of products between on the one hand `(a, b)` and on the other `(c, d)` each of `a, b, c, d` taken only once. 
For example, 
prod2sum(1, 2, 1, 3) should return [[1, 7], [5, 5]]) 
because 
```
1==1*3-1*2
7==2*3+1*1
5==1*2+1*3
```
Suppose we have `a = 1, b = 2, c = 1, d = 3`. First we calculate the sums 
`1² + 2² = 5 and 1² + 3² = 10` hence `n = 50`.



`50 = 1² + 7² or 50 = 7² + 1²` (we'll consider that these two solutions are the same)
or `50 = 5² + 5²`. 

The return of our function will be an array of subarrays (in C an array of Pairs) sorted on the first elements of the subarrays. In each subarray the lower element should be the first.

`prod2sum(1, 2, 1, 3) should return [[1, 7], [5, 5]]`

`prod2sum(2, 3, 4, 5) should return  [[2, 23], [7, 22]]`

because `(2² + 3²) * (4² + 5²) = 533 = (7² + 22²) = (23² + 2²)`

`prod2sum(1, 2, 2, 3) should return  [[1, 8], [4, 7]]`

`prod2sum(1, 1, 3, 5) should return  [[2, 8]]` (there are not always 2 solutions).

##Hint
Take a sheet of paper and with a bit of algebra try to write the product of squared numbers in another way.

Answer: {"fn_name": "prod2sum", "inputs": [[1, 2, 1, 3], [2, 3, 4, 5], [1, 2, 2, 3], [1, 1, 3, 5], [10, 11, 12, 13], [1, 20, -4, -5], [100, 100, 100, 100], [0, 0, 0, 0], [-14, 12, -10, 8], [7, 96, -1, 81], [112, 0, 0, 1]], "outputs": [[[[1, 7], [5, 5]]], [[[2, 23], [7, 22]]], [[[1, 8], [4, 7]]], [[[2, 8]]], [[[2, 263], [23, 262]]], [[[75, 104], [85, 96]]], [[[0, 20000]]], [[[0, 0]]], [[[8, 236], [44, 232]]], [[[471, 7783], [663, 7769]]], [[[0, 112]]]]}
user: For this game of `BINGO`, you will receive a single array of 10 numbers from 1 to 26 as an input. Duplicate numbers within the array are possible.

Each number corresponds to their alphabetical order letter (e.g. 1 = A. 2 = B, etc). Write a function where you will win the game if your numbers can spell `"BINGO"`. They do not need to be in the right order in the input array). Otherwise you will lose. Your outputs should be `"WIN"` or `"LOSE"` respectively.

Answer: {"fn_name": "bingo", "inputs": [[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]], [[20, 12, 23, 14, 6, 22, 12, 17, 2, 26]], [[1, 2, 3, 7, 5, 14, 7, 15, 9, 10]], [[5, 2, 13, 7, 5, 14, 17, 15, 9, 10]]], "outputs": [["LOSE"], ["LOSE"], ["WIN"], ["WIN"]]}
user: Kate and Michael want to buy a pizza and share it. Depending on the price of the pizza, they are going to divide the costs:

* If the pizza is less than €5,- Michael invites Kate, so Michael pays the full price.
* Otherwise Kate will contribute 1/3 of the price, but no more than €10 (she's broke :-) and Michael pays the rest.

How much is Michael going to pay? Calculate the amount with two decimals, if necessary.

Answer: {"fn_name": "michael_pays", "inputs": [[15], [4], [4.99], [5], [30], [80], [22], [5.9181], [28.789], [4.325]], "outputs": [[10], [4], [4.99], [3.33], [20], [70], [14.67], [3.95], [19.19], [4.33]]}
user: You've arrived at a carnival and head straight for the duck shooting tent. Why wouldn't you?

You will be given a set amount of ammo, and an aim rating of between 1 and 0. No your aim is not always perfect - hey maybe someone fiddled with the sights on the gun...

Anyway your task is to calculate how many successful shots you will be able to make given the available ammo and your aim score, then return a string representing the pool of ducks, with those ducks shot marked with 'X' and those that survived left unchanged. You will always shoot left to right.

Example of start and end duck string with two successful shots:

Start ---> |~~~~~22~2~~~~~|

**Bang!! Bang!!**

End  --->  |~~~~~XX~2~~~~~|

All inputs will be correct type and never empty.

Answer: {"fn_name": "duck_shoot", "inputs": [[4, 0.64, "|~~2~~~22~2~~22~2~~~~2~~~|"], [9, 0.22, "|~~~~~~~2~2~~~|"], [6, 0.41, "|~~~~~22~2~~~~~|"], [8, 0.05, "|2~~~~|"], [8, 0.92, "|~~~~2~2~~~~~22~~2~~~~2~~~2|"]], "outputs": [["|~~X~~~X2~2~~22~2~~~~2~~~|"], ["|~~~~~~~X~2~~~|"], ["|~~~~~XX~2~~~~~|"], ["|2~~~~|"], ["|~~~~X~X~~~~~XX~~X~~~~X~~~X|"]]}
user: In the world of birding there are four-letter codes for the common names of birds. These codes are created by some simple rules:

* If the bird's name has only one word, the code takes the first four letters of that word. 
* If the name is made up of two words, the code takes the first two letters of each word.
* If the name is made up of three words, the code is created by taking the first letter from the first two words and the first two letters from the third word.
* If the name is four words long, the code uses the first letter from all the words.

*(There are other ways that codes are created, but this Kata will only use the four rules listed above)*

Complete the function that takes an array of strings of common bird names from North America, and create the codes for those names based on the rules above. The function should return an array of the codes in the same order in which the input names were presented.

Additional considertations:

* The four-letter codes  in the returned array should be in UPPER CASE.
* If a common name has a hyphen/dash, it should be considered a space. 

## Example

If the input array is: `["Black-Capped Chickadee", "Common Tern"]`

The return array would be: `["BCCH", "COTE"]`

Answer: {"fn_name": "bird_code", "inputs": [[["American Redstart", "Northern Cardinal", "Pine Grosbeak", "Barred Owl", "Starling", "Cooper's Hawk", "Pigeon"]], [["Great Crested Flycatcher", "Bobolink", "American White Pelican", "Red-Tailed Hawk", "Eastern Screech Owl", "Blue Jay"]], [["Black-Crowned Night Heron", "Northern Mockingbird", "Eastern Meadowlark", "Dark-Eyed Junco", "Red-Bellied Woodpecker"]], [["Scarlet Tanager", "Great Blue Heron", "Eastern Phoebe", "American Black Duck", "Mallard", "Canvasback", "Merlin", "Ovenbird"]], [["Fox Sparrow", "White-Winged Crossbill", "Veery", "American Coot", "Sora", "Northern Rough-Winged Swallow", "Purple Martin"]]], "outputs": [[["AMRE", "NOCA", "PIGR", "BAOW", "STAR", "COHA", "PIGE"]], [["GCFL", "BOBO", "AWPE", "RTHA", "ESOW", "BLJA"]], [["BCNH", "NOMO", "EAME", "DEJU", "RBWO"]], [["SCTA", "GBHE", "EAPH", "ABDU", "MALL", "CANV", "MERL", "OVEN"]], [["FOSP", "WWCR", "VEER", "AMCO", "SORA", "NRWS", "PUMA"]]]}
user: In this exercise, a string is passed to a method and a new string has to be returned with the first character of each word in the string.

For example:

```
"This Is A Test" ==> "TIAT"
```

Answer: {"fn_name": "make_string", "inputs": [["sees eyes xray yoat"], ["brown eyes are nice"], ["cars are very nice"], ["kaks de gan has a big head"]], "outputs": [["sexy"], ["bean"], ["cavn"], ["kdghabh"]]}
user: Complete the function to determine the number of bits required to convert integer `A` to integer `B` (where `A` and `B` >= 0)

The upper limit for `A` and `B` is 2^(16), `int.MaxValue` or similar.

For example, you can change 31 to 14 by flipping the 4th and 0th bit:
```
 31  0 0 0 1 1 1 1 1
 14  0 0 0 0 1 1 1 0
---  ---------------
bit  7 6 5 4 3 2 1 0
```
Thus `31` and `14` should return `2`.

Answer: {"fn_name": "convert_bits", "inputs": [[31, 14], [7, 17], [31, 0], [0, 0], [127681, 127681], [312312312, 5645657], [43, 2009989843]], "outputs": [[2], [3], [5], [0], [0], [13], [17]]}
user: There's a waiting room with N chairs set in single row. Chairs are consecutively numbered from 1 to N. First is closest to the entrance (which is exit as well).
 
For some reason people choose a chair in the following way

1. Find a place as far from other people as possible
2. Find a place as close to exit as possible

All chairs must be occupied before the first person will be served

So it looks like this for 10 chairs and 10 patients




Chairs
1
2
3
4
5
6
7
8
9
10




Patients
1
7
5
8
3
9
4
6
10
2




Your task is to find last patient's chair's number. 

Input - N - integer greater than 2 - number of chairs.
Output should positive integer too - last patient's chair's number

Have fun :)

Answer: {"fn_name": "last_chair", "inputs": [[10]], "outputs": [[9]]}
user: Given an array of arguments, representing system call arguments keys and values, join it into a single, space-delimited string. You don't need to care about the application name -- your task is only about parameters.

Each element of the given array can be:
* a single string,
* a single string array,
* an array of two strings

In the last case (array of two strings) the first string should have a `"--"` prefix if it is more than one character long; or a `"-"` prefix otherwise; e.g.:
  * `["foo", "bar"]` becomes `"--foo bar"`
  * `["f", "bar"]` becomes `"-f bar"`

You may assume that all strings are non-empty and have no spaces.

## Examples

```python
["foo", "bar"]                    #  "foo bar"
[["foo", "bar"]]                  #  "--foo bar"
[["f", "bar"]]                    #  "-f bar"
[["foo", "bar"], "baz"]           #  "--foo bar baz"
[["foo"], ["bar", "baz"], "qux"]  #  "foo --bar baz qux"
```

Answer: {"fn_name": "args_to_string", "inputs": [[["foo"]], [["f"]], [[["f"]]], [[["foo", "bar"]]], [[["f", "bar"]]], [[["foo", "bar"], ["baz", "qux"]]], [[["foo"], "bar", ["baz", "qux"], ["xyzzy", "a"], "a", ["a"], ["a", "plugh"]]], [[]], [[["---"], "---", ["---", "---"], ["-----", "-"], "-", ["-"], ["-", "-----"]]]], "outputs": [["foo"], ["f"], ["f"], ["--foo bar"], ["-f bar"], ["--foo bar --baz qux"], ["foo bar --baz qux --xyzzy a a a -a plugh"], [""], ["--- --- ----- --- ------- - - - -- -----"]]}
user: A marine themed rival site to Codewars has started. Codwars is advertising their website all over the internet using subdomains to hide or obfuscate their domain to trick people into clicking on their site.

Your task is to write a function that accepts a URL as a string and determines if it would result in an http request to codwars.com.

Function should return true for all urls in the codwars.com domain. All other URLs should return false.

The urls are all valid but may or may not contain http://, https:// at the beginning or subdirectories or querystrings at the end.

For additional confusion, directories in can be named "codwars.com" in a url with the codewars.com domain and vise versa. Also, a querystring may contain codewars.com or codwars.com for any other domain - it should still return true or false based on the domain of the URL and not the domain in the querystring. Subdomains can also add confusion: for example `http://codwars.com.codewars.com` is a valid URL in the codewars.com domain in the same way that `http://mail.google.com` is a valid URL within google.com

Urls will not necessarily have either codewars.com or codwars.com in them. The folks at Codwars aren't very good about remembering the contents of their paste buffers.

All urls contain domains with a single TLD; you need not worry about domains like company.co.uk.

```
findCodwars("codwars.com"); // true
findCodwars("https://subdomain.codwars.com/a/sub/directory?a=querystring"); // true
findCodwars("codewars.com"); // false
findCodwars("https://subdomain.codwars.codewars.com/a/sub/directory/codwars.com?a=querystring"); // false
```

Answer: {"fn_name": "find_codwars", "inputs": [["codwars.com"], ["http://codwars.com"], ["http://kcodwars.com"], ["https://www.codwars.com"], ["https://www.codwars.com/kata"], ["codewars.com.codwars.com"], ["https://www.codwars.com/kata?this=is&a=querystring"], ["https://this.is.an.unneccesarily.long.subdomain.codwars.com/katas.are.really.fun.codewars.com/"], ["http://codwars.com?impersonate=codewars.com"], ["codewars.com"], ["codwars.comp"], ["codwarsecom"], ["codwars.com.com"], ["codwarss.com"], ["ecodwars.comp"], ["codwars.com.codwars.comp"], ["codwars.com.ecodwars.comp"], ["www.codewars.com/codwars"], ["http://codewars.com"], ["https://www.codewars.com"], ["https://www.codewars.com/kata"], ["http://codewars.com?impersonate=codwars.com"], ["https://www.codewars.com/kata?this=is&a=querystring"], ["https://this.is.an.unneccesarily.long.subdomain.codewars.com/katas.are.really.fun.codwars.com/"], ["https://this.is.an.unneccesarily.long.subdomain.codwars.comp/katas.are.really.fun.codwars.com/"], ["hotmail.com"]], "outputs": [[true], [true], [false], [true], [true], [true], [true], [true], [true], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false]]}
user: Pete and his mate Phil are out in the countryside shooting clay pigeons with a shotgun - amazing fun. 

They decide to have a competition. 3 rounds, 2 shots each. Winner is the one with the most hits.

Some of the clays have something attached to create lots of smoke when hit, guarenteed by the packaging to generate 'real excitement!' (genuinely this happened). None of the explosive things actually worked, but for this kata lets say they did.

For each round you will receive the following format:

[{P1:'XX', P2:'XO'}, true]

That is an array containing an object and a boolean. Pl represents Pete, P2 represents Phil. X represents a hit and O represents a miss. If the boolean is true, any hit is worth 2. If it is false, any hit is worth 1.

Find out who won. If it's Pete, return 'Pete Wins!'. If it is Phil, return 'Phil Wins!'. If the scores are equal, return 'Draw!'.

Note that as there are three rounds, the actual input (x) will look something like this:

[[{P1:'XX', P2:'XO'}, true], [{P1:'OX', P2:'OO'}, false], [{P1:'XX', P2:'OX'}, true]]

Answer: {"fn_name": "shoot", "inputs": [[[[{"P1": "XX", "P2": "XO"}, true], [{"P1": "OX", "P2": "OO"}, false], [{"P1": "XX", "P2": "OX"}, true]]], [[[{"P1": "XX", "P2": "XO"}, false], [{"P1": "OX", "P2": "XX"}, false], [{"P1": "OO", "P2": "XX"}, true]]], [[[{"P1": "OO", "P2": "XX"}, false], [{"P1": "OO", "P2": "XX"}, false], [{"P1": "XX", "P2": "OO"}, true]]], [[[{"P1": "XX", "P2": "XX"}, true], [{"P1": "XX", "P2": "OX"}, false], [{"P1": "OO", "P2": "OX"}, true]]], [[[{"P1": "XX", "P2": "XX"}, true], [{"P1": "OO", "P2": "OO"}, false], [{"P1": "XX", "P2": "XX"}, true]]]], "outputs": [["Pete Wins!"], ["Phil Wins!"], ["Draw!"], ["Phil Wins!"], ["Draw!"]]}
user: What adds up
===========

Given three arrays of integers your task is to create an algorithm that finds the numbers in the first two arrays whose sum is equal to any number in the third. The return value should be an array containing the values from the argument arrays that adds up. The sort order of the resulting array is not important. If no combination of numbers adds up return a empty array.

### Example
A small example: Given the three input arrays `a1 = [1, 2]; a2 = [4,3]; a3 = [6,5,8]`, we need to find the number pairs from `a1` and `a2` that sum up to a number in `a3` and return those three numbers in an array. In this example, the result from the function would be `[[1, 4, 5] , [2, 4, 6], [2, 3, 5]]`.
```
Given three arrays
a1      a2      a3
 1       4       6          (a1 a2 a3)    (a1 a2 a3)  (a1 a2 a3)
 2       3       5      =>  [[1, 4, 5] ,  [2, 4, 6],  [2, 3, 5]]
                 8
                 
each value in the result array contains one part from each of the arguments.
```

### Testing
A function `compare_array` is given. This function takes two arrays and compares them invariant of sort order.

```python
test.expect(compare_arrays(addsup([1,2], [3,1], [5,4]), [[1,3,4], [2,3,5]]))
```

### Greater goal
For extra honor try and make it as effective as possible. Discuss whats the most effective way of doing this. The fastest way i can do this is in *O(n^2)*. Can you do it quicker?

Answer: {"fn_name": "addsup", "inputs": [[[], [1, 2, 3], [5, 2, 3]], [[1, 3, 4], [], [4, 6, 5]], [[1, 2, 3], [4, 5, 6], []]], "outputs": [[[]], [[]], [[]]]}
user: In this Kata, you will check if it is possible to convert a string to a palindrome by changing one character. 

For instance:
```Haskell
solve ("abbx") = True, because we can convert 'x' to 'a' and get a palindrome. 
solve ("abba") = False, because we cannot get a palindrome by changing any character. 
solve ("abcba") = True. We can change the middle character. 
solve ("aa") = False 
solve ("ab") = True
```

Good luck!

Please also try [Single Character Palindromes](https://www.codewars.com/kata/5a2c22271f7f709eaa0005d3)

Answer: {"fn_name": "solve", "inputs": [["abba"], ["abbaa"], ["abbx"], ["aa"], ["ab"], ["abcba"]], "outputs": [[false], [true], [true], [false], [true], [true]]}
user: Your job at E-Corp is both boring and difficult. It isn't made any easier by the fact that everyone constantly wants to have a meeting with you, and that the meeting rooms are always taken!

In this kata, you will be given an array. Each value represents a meeting room. Your job? Find the **first** empty one and return its index (N.B. There may be more than one empty room in some test cases). 

'X' --> busy
'O' --> empty

If all rooms are busy, return 'None available!'.


More in this series:

The Office I - Outed
The Office II - Boredeom Score
The Office III - Broken Photocopier
The Office V - Find a Chair

Answer: {"fn_name": "meeting", "inputs": [[["X", "O", "X"]], [["O", "X", "X", "X", "X"]], [["X", "X", "O", "X", "X"]], [["X"]]], "outputs": [[1], [0], [2], ["None available!"]]}
user: Kevin is noticing his space run out! Write a function that removes the spaces from the values and returns an array showing the space decreasing.
For example, running this function on the array ['i', 'have','no','space'] would produce ['i','ihave','ihaveno','ihavenospace'].

Answer: {"fn_name": "spacey", "inputs": [[["kevin", "has", "no", "space"]], [["this", "cheese", "has", "no", "holes"]]], "outputs": [[["kevin", "kevinhas", "kevinhasno", "kevinhasnospace"]], [["this", "thischeese", "thischeesehas", "thischeesehasno", "thischeesehasnoholes"]]]}
user: Will you make it?

You were camping with your friends far away from home, but when it's time to go back, you realize that your fuel is running out and the nearest pump is ```50``` miles away! You know that on average, your car runs on about ```25``` miles per gallon. There are ```2``` gallons left. Considering these factors, write a function that tells you if it is possible to get to the pump or not. Function should return ``true`` (`1` in Prolog) if it is possible and ``false`` (`0` in Prolog) if not.
The input values are always positive.

Answer: {"fn_name": "zero_fuel", "inputs": [[50, 25, 2], [60, 30, 3], [70, 25, 1], [100, 25, 3]], "outputs": [[true], [true], [false], [false]]}
user: Step through my `green glass door`.

You can take the `moon`, but not the `sun`.

You can take your `slippers`, but not your `sandals`.

You can go through `yelling`, but not `shouting`.

You can't run through `fast`, but you can run with `speed`.

You can take a `sheet`, but not your `blanket`.

You can wear your `glasses`, but not your `contacts`.

Have you figured it out? Good! Then write a program that can figure it out as well.

Answer: {"fn_name": "step_through_with", "inputs": [["moon"], ["test"], ["glasses"], ["airplane"], ["free"], ["branch"], ["aardvark"]], "outputs": [[true], [false], [true], [false], [true], [false], [true]]}
user: Consider the following series:

`1, 2, 4, 8, 16, 22, 26, 38, 62, 74, 102, 104, 108, 116, 122`

It is generated as follows:

* For single digit integers, add the number to itself to get the next element.
* For other integers, multiply all the non-zero digits and add the result to the original number to get the next element.

For example: `16 + (6 * 1) = 22` and `104 + (4 * 1) = 108`. 

Let's begin the same series with a seed value of `3` instead of `1`:

`3, 6, 12, 14, 18, 26, 38, 62, 74, 102, 104, 108, 116, 122`

Notice that the two sequences converge at `26` and are identical therefter. We will call the series seeded by a value of `1` the "base series" and the other series the "test series". 

You will be given a seed value for the test series and your task will be to return the number of integers that have to be generated in the test series before it converges to the base series. In the case above:
```Python
convergence(3) = 5, the length of [3, 6, 12, 14, 18]. 
```  

Good luck!

If you like this Kata, please try:

[Simple Prime Streaming](https://www.codewars.com/kata/5a908da30025e995880000e3)

[Unique digit sequence](https://www.codewars.com/kata/599688d0e2800dda4e0001b0)

[Divisor harmony](https://www.codewars.com/kata/59bf97cd4f98a8b1cd00007e)

Answer: {"fn_name": "convergence", "inputs": [[3], [5], [10], [15], [500], [5000]], "outputs": [[5], [6], [5], [2], [29], [283]]}