meetforever/GRPO_CL huggingface dataset:
user: This is a spin off of my first [kata](http://www.codewars.com/kata/56bc28ad5bdaeb48760009b0). You are given a list of character sequences as a comma separated string. Write a function which returns another string containing all the character sequences except the first and the last ones, separated by spaces. If the input string is empty, or the removal of the first and last items would cause the string to be empty, return a null value.

Answer: {"fn_name": "array", "inputs": [[""], ["1"], ["1, 3"], ["1,2,3"], ["1,2,3,4"]], "outputs": [[null], [null], [null], ["2"], ["2 3"]]}
user: If you finish this kata, you can try [Insane Coloured Triangles](http://www.codewars.com/kata/insane-coloured-triangles) by Bubbler, which is a ***much*** harder version of this one.

A coloured triangle is created from a row of colours, each of which is red, green or blue. Successive rows, each containing one fewer colour than the last, are generated by considering the two touching colours in the previous row. If these colours are identical, the same colour is used in the new row. If they are different, the missing colour is used in the new row. This is continued until the final row, with only a single colour, is generated.

The different possibilities are:
```
Colour here:        G G        B G        R G        B R
Becomes colour:      G          R          B          G
```

With a bigger example:
```
R R G B R G B B
 R B R G B R B
  G G B R G G
   G R G B G
    B B R R
     B G R
      R B
       G
```
  
You will be given the first row of the triangle as a string and its your job to return the final colour which would appear in the bottom row as a string. In the case of the example above, you would the given `RRGBRGBB` you should return `G`.

* The input string will only contain the uppercase letters `R, G, B` and there will be at least one letter so you do not have to test for invalid input.
* If you are only given one colour as the input, return that colour. 


*Adapted from the 2017 British Informatics Olympiad*

Answer: {"fn_name": "triangle", "inputs": [["GB"], ["RRR"], ["RGBG"], ["RBRGBRB"], ["RBRGBRBGGRRRBGBBBGG"], ["B"]], "outputs": [["R"], ["R"], ["B"], ["G"], ["G"], ["B"]]}
user: The snail crawls up the column. During the day it crawls up some distance. During the night she sleeps, so she slides down for some distance (less than crawls up during the day).

Your function takes three arguments:
1. The height of the column (meters)
2. The distance that the snail crawls during the day (meters)
3. The distance that the snail slides down during the night (meters)

Calculate number of day when the snail will reach the top of the column.

Answer: {"fn_name": "snail", "inputs": [[3, 2, 1], [10, 3, 1], [10, 3, 2], [100, 20, 5], [5, 10, 3]], "outputs": [[2], [5], [8], [7], [1]]}
user: You will be given an array that contains two strings. Your job is to create a function that will take those two strings and transpose them, so that the strings go from top to bottom instead of left to right.
A few things to note:

1. There should be one space in between the two characters
2. You don't have to modify the case (i.e. no need to change to upper or lower)
3. If one string is longer than the other, there should be a space where the character would be

Answer: {"fn_name": "transpose_two_strings", "inputs": [[["Hello", "World"]], [["joey", "louise"]], [["a", "cat"]], [["cat", ""]], [["!a!a!", "?b?b"]]], "outputs": [["H W\ne o\nl r\nl l\no d"], ["j l\no o\ne u\ny i\n  s\n  e"], ["a c\n  a\n  t"], ["c  \na  \nt  "], ["! ?\na b\n! ?\na b\n!  "]]}
user: Description overhauled by V

---

I've invited some kids for my son's birthday, during which I will give to each kid some amount of candies.

Every kid hates receiving less amount of candies than any other kids, and I don't want to have any candies left - giving it to my kid would be bad for his teeth.

However, not every kid invited will come to my birthday party.

What is the minimum amount of candies I have to buy, so that no matter how many kids come to the party in the end, I can still ensure that each kid can receive the same amount of candies, while leaving no candies left?

It's ensured that at least one kid will participate in the party.

Answer: {"fn_name": "candies_to_buy", "inputs": [[1], [2], [5], [6], [9], [10], [60], [61], [100], [101]], "outputs": [[1], [2], [60], [60], [2520], [2520], [9690712164777231700912800], [591133442051411133755680800], [69720375229712477164533808935312303556800], [7041757898200960193617914702466542659236800]]}
user: # Definition

**_Disarium number_** is the number that *The sum of its digits powered with their respective positions is equal to the number itself*.

____

# Task

**_Given_** a number, **_Find if it is Disarium or not_** . 
____

# Warm-up (Highly recommended)

# [Playing With Numbers Series](https://www.codewars.com/collections/playing-with-numbers)
___

# Notes 

* **_Number_** *passed is always*  **_Positive_** .
* **_Return_** *the result as* **_String_**
___

# Input >> Output Examples

```
disariumNumber(89) ==> return "Disarium !!"
```
## **_Explanation_**:

* Since , **_8^(1) + 9^(2) = 89_** , thus *output* is `"Disarium !!"`
___

```
disariumNumber(564) ==> return "Not !!"
```
## **_Explanation_**:

Since , **_5^(1) + 6^(2) + 4^(3) = 105 != 564_** ,  thus *output* is `"Not !!"`

___
___
___

# [Playing with Numbers Series](https://www.codewars.com/collections/playing-with-numbers)

# [Playing With Lists/Arrays Series](https://www.codewars.com/collections/playing-with-lists-slash-arrays)

# [For More Enjoyable Katas](http://www.codewars.com/users/MrZizoScream/authored)
___

## ALL translations are welcomed

## Enjoy Learning !!
# Zizou

Answer: {"fn_name": "disarium_number", "inputs": [[1024], [1306], [1999], [2427], [1048576], [2646798]], "outputs": [["Not !!"], ["Disarium !!"], ["Not !!"], ["Disarium !!"], ["Not !!"], ["Disarium !!"]]}
user: This challenge extends the previous [repeater()](https://www.codewars.com/kata/thinkful-string-drills-repeater) challenge. Just like last time, your job is to write a function that accepts a string and a number as arguments. This time, however, you should format the string you return like this:
```python
>>> repeater('yo', 3)
'"yo" repeated 3 times is: "yoyoyo"'
>>> repeater('WuB', 6)
'"WuB" repeated 6 times is: "WuBWuBWuBWuBWuBWuB"'
```

Answer: {"fn_name": "repeater", "inputs": [["yo", 3], ["WuB", 6], ["code, eat, code, sleep... ", 2]], "outputs": [["\"yo\" repeated 3 times is: \"yoyoyo\""], ["\"WuB\" repeated 6 times is: \"WuBWuBWuBWuBWuBWuB\""], ["\"code, eat, code, sleep... \" repeated 2 times is: \"code, eat, code, sleep... code, eat, code, sleep... \""]]}
user: Create a function finalGrade, which calculates the final grade of a student depending on two parameters: a grade for the exam and a number of completed projects.

This function should take two arguments:
exam - grade for exam (from 0 to 100);
projects - number of completed projects (from 0 and above);

This function should return a number (final grade).
There are four types of final grades:
- 100, if a grade for the exam is more than 90 or if a number of completed projects more than 10.
- 90, if a grade for the exam is more than 75 and if a number of completed projects is minimum 5.
- 75, if a grade for the exam is more than 50 and if a number of completed projects is minimum 2.
- 0, in other cases

Examples:

~~~if-not:nasm
```python
final_grade(100, 12)  # 100
final_grade(99, 0)    # 100
final_grade(10, 15)   # 100
final_grade(85, 5)    # 90
final_grade(55, 3)    # 75
final_grade(55, 0)    # 0
final_grade(20, 2)    # 0
```
~~~

*Use Comparison and Logical Operators.

Answer: {"fn_name": "final_grade", "inputs": [[100, 12], [99, 0], [10, 15], [85, 5], [55, 3], [55, 0], [20, 2]], "outputs": [[100], [100], [100], [90], [75], [0], [0]]}
user: Create a function that accepts dimensions, of Rows x Columns, as parameters in order to create a multiplication table sized according to the given dimensions.  **The return value of the function must be an array, and the numbers must be Fixnums, NOT strings.

Example:

multiplication_table(3,3)

1       2       3       
2       4       6       
3       6       9

-->[[1,2,3],[2,4,6],[3,6,9]]

Each value on the table should be equal to the value of multiplying the number in its first row times the number in its first column.

Answer: {"fn_name": "multiplication_table", "inputs": [[2, 2], [3, 3], [3, 4], [4, 4], [2, 5]], "outputs": [[[[1, 2], [2, 4]]], [[[1, 2, 3], [2, 4, 6], [3, 6, 9]]], [[[1, 2, 3, 4], [2, 4, 6, 8], [3, 6, 9, 12]]], [[[1, 2, 3, 4], [2, 4, 6, 8], [3, 6, 9, 12], [4, 8, 12, 16]]], [[[1, 2, 3, 4, 5], [2, 4, 6, 8, 10]]]]}
user: In this Kata, you will be given two integers `n` and `k` and your task is to remove `k-digits` from `n` and return the lowest number possible, without changing the order of the digits in `n`. Return the result as a string.

Let's take an example of `solve(123056,4)`. We need to remove `4` digits from `123056` and return the lowest possible number. The best digits to remove are `(1,2,3,6)` so that the remaining digits are `'05'`. Therefore, `solve(123056,4) = '05'`. 

Note also that the order of the numbers in `n` does not change: `solve(1284569,2) = '12456',` because we have removed `8` and `9`. 

More examples in the test cases.

Good luck!

Answer: {"fn_name": "solve", "inputs": [[123056, 1], [123056, 2], [123056, 3], [123056, 4], [1284569, 1], [1284569, 2], [1284569, 3], [1284569, 4]], "outputs": [["12056"], ["1056"], ["056"], ["05"], ["124569"], ["12456"], ["1245"], ["124"]]}
user: Given a string ``string`` that contains only letters, you have to find out the number of **unique** strings (including ``string`` itself) that can be produced by re-arranging the letters of the ``string``.  Strings are case **insensitive**.

HINT: Generating all the unique strings and calling length on that isn't a great solution for this problem. It can be done a lot faster...

## Examples

```python
uniqcount("AB") = 2      # "AB", "BA"
uniqcount("ABC") = 6     # "ABC", "ACB", "BAC", "BCA", "CAB", "CBA"
uniqcount("ABA") = 3     # "AAB", "ABA", "BAA"
uniqcount("ABBb") = 4    # "ABBB", "BABB", "BBAB", "BBBA"
uniqcount("AbcD") = 24   # "ABCD", etc.
```

Answer: {"fn_name": "uniq_count", "inputs": [["AB"], ["ABC"], ["AbA"], ["ABBb"], ["AbcD"], ["AAA"], [""], ["ASTON"], ["BEST"], ["ABcDEFgHIJ"], ["ABcDEFgHIJbaslidbailsbdilasbdkanmsdklhkbHSJKHVDASH"], ["ABcDEFgHIJbaslidbailsbdilasbdkanmsdklhkbHSJKHVDASHVVYQVWKDVDWQUV"]], "outputs": [[2], [6], [3], [4], [24], [1], [1], [120], [24], [3628800], [34111429518116758488933545882757275627520000000], [176478346352319876826993574633158714419916931040323433922560000000]]}
user: # Two samurai generals are discussing dinner plans after a battle, but they can't seem to agree.

The discussion gets heated and you are cannot risk favoring either of them as this might damage your political standing with either of the two clans the samurai generals belong to. Thus, the only thing left to do is find what the common ground of what they are saying is.

Compare the proposals with the following function: 
```python
def common_ground(s1,s2)
```

The parameters ```s1``` and ```s2``` are the strings representing what each of the generals said. You should output a string containing the words in ```s1``` that also occur in ```s2```.

Each word in the resulting string shall occur once, and the order of the words need to follow the order of the first occurence of each word in ```s2```.

If they are saying nothing in common, kill both samurai and blame a ninja. (output "death")

Answer: {"fn_name": "common_ground", "inputs": [["eat chicken", "eat chicken and rice"], ["eat a burger and drink a coke", "drink a coke"], ["i like turtles", "what are you talking about"], ["aa bb", "aa bb cc"], ["aa bb cc", "bb cc"], ["aa bb cc", "bb cc bb aa"], ["aa bb", "cc dd"], ["aa bb", ""], ["", "cc dd"], ["", ""]], "outputs": [["eat chicken"], ["drink a coke"], ["death"], ["aa bb"], ["bb cc"], ["bb cc aa"], ["death"], ["death"], ["death"], ["death"]]}
user: Introduction to Disjunctions
In logic and mathematics, a disjunction is an operation on 2 or more propositions.  A disjunction is true if and only if 1 or more of its operands is true.  In programming, we typically denote a disjunction using "||", but in logic we typically use "v".
Example of disjunction:
p = 1 > 2 = false
q = 2 < 3 = true
therefore p v q is true
In a programming language, we might write this as:
var p = 1 > 2;        // false
var q = 2 < 3;        // true
var result = p || q;  // true
The above example demonstrates an inclusive disjunction (meaning it includes cases where both operands are true). Disjunctions can also be exlusive. An exclusive disjunction is typically represented by "⊻" and is true if and only if both operands have opposite values.
p = 1 < 2 = true
q = 2 < 3 = true
therefore p ⊻ q is false
This can become confusing when dealing with more than 2 operands.
r = 3 < 4 = true
p ⊻ q ⊻ r = ???
We handle these situations by evaluating the expression from left to right.
p ⊻ q = false
(p ⊻ q) ⊻ r = true
Directions:
For this kata, your task is to implement a function that performs a disjunction operation on 2 or more propositions.

Should take a boolean array as its first parameter and a single boolean as its second parameter, which, if true, should indicate that the disjunction should be exclusive as opposed to inclusive.
Should return true or false.

Answer: {"fn_name": "disjunction", "inputs": [[[false, true, true], false], [[false, true, false], false], [[false, true, true, true], true], [[true, true, true], false], [[true, true, true, true], false]], "outputs": [[true], [true], [true], [true], [true]]}
user: Write a function `sumTimesTables` which sums the result of the sums of the elements specified in `tables` multiplied by all the numbers in between `min` and `max` including themselves.

For example, for `sumTimesTables([2,5],1,3)` the result should be the same as
```
2*1 + 2*2 + 2*3 +
5*1 + 5*2 + 5*3
```
i.e. the table of two from 1 to 3 plus the table of five from 1 to 3

All the numbers are integers but you must take in account:

* `tables` could be empty.
* `min` could be negative.
* `max` could be really big.

Answer: {"fn_name": "sum_times_tables", "inputs": [[[2, 3], 1, 3], [[1, 3, 5], 1, 1], [[1, 3, 5], 1, 10], [[], 1, 10], [[1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 1, 10], [[10, 9, 8, 7, 6, 5, 4, 3, 2, 1], 1, 10], [[5, 4, 7, 8, 9, 6, 3, 2, 10, 1], 1, 10], [[-2], -1, 3], [[-2, 2], -1, 3], [[-2, 3], -1, 3], [[2, -3], -1, 3], [[2, 4, 7], -100, 100], [[2, 4, 7], 1, 100], [[2, 4, 7], 1, 101]], "outputs": [[30], [9], [495], [0], [3025], [3025], [3025], [-10], [0], [5], [-5], [0], [65650], [66963]]}
user: In this kata you should simply determine, whether a given year is a leap year or not. In case you don't know the rules, here they are:

* years divisible by 4 are leap years
* but years divisible by 100 are **not** leap years
* but years divisible by 400 are leap years

Additional Notes:

* Only valid years (positive integers) will be tested, so you don't have to validate them

Examples can be found in the test fixture.

Answer: {"fn_name": "isLeapYear", "inputs": [[1984], [2000], [2004], [8], [0], [1234], [1100], [1194]], "outputs": [[true], [true], [true], [true], [true], [false], [false], [false]]}
user: # Description
Write a function that checks whether a credit card number is correct or not, using the Luhn algorithm.

The algorithm is as follows:

* From the rightmost digit, which is the check digit, moving left, double the value of every second digit; if the product of this doubling operation is greater than 9 (e.g., 8 × 2 = 16), then sum the digits of the products (e.g., 16: 1 + 6 = 7, 18: 1 + 8 = 9) or alternatively subtract 9 from the product (e.g., 16: 16 - 9 = 7, 18: 18 - 9 = 9).
* Take the sum of all the digits.
* If the total modulo 10 is equal to 0 (if the total ends in zero) then the number is valid according to the Luhn formula; else it is not valid.

The input is a string with the full credit card number, in groups of 4 digits separated by spaces, i.e. "1234 5678 9012 3456"  
Don´t worry about wrong inputs, they will always be a string with 4 groups of 4 digits each separated by space.

# Examples

`valid_card?("5457 6238 9823 4311") # True`

`valid_card?("5457 6238 9323 4311") # False`

for reference check: https://en.wikipedia.org/wiki/Luhn_algorithm

Answer: {"fn_name": "valid_card", "inputs": [["5457 6238 9823 4311"], ["8895 6238 9323 4311"], ["5457 6238 5568 4311"], ["5457 6238 9323 4311"], ["2222 2222 2222 2224"], ["5457 1125 9323 4311"], ["1252 6238 9323 4311"], ["9999 9999 9999 9995"], ["0000 0300 0000 0000"], ["4444 4444 4444 4448"], ["5457 6238 9323 1252"], ["5457 6238 1251 4311"], ["3333 3333 3333 3331"], ["6666 6666 6666 6664"], ["5457 6238 0254 4311"], ["0000 0000 0000 0000"], ["5457 1111 9323 4311"], ["1145 6238 9323 4311"], ["8888 8888 8888 8888"], ["0025 2521 9323 4311"], ["1111 1111 1111 1117"], ["1234 5678 9012 3452"], ["5458 4444 9323 4311"], ["5457 6238 3333 4311"], ["0123 4567 8901 2345"], ["5555 5555 5555 5557"]], "outputs": [[true], [false], [false], [false], [true], [false], [false], [true], [false], [true], [false], [false], [true], [true], [false], [true], [false], [false], [true], [false], [true], [true], [false], [false], [false], [true]]}
user: Create a function that will return ```true``` if the input is in the following date time format ```01-09-2016 01:20``` and ```false``` if it is not.

This Kata has been inspired by the Regular Expressions chapter from the book Eloquent JavaScript.

Answer: {"fn_name": "date_checker", "inputs": [["01-09-2016 01:20"], ["01-09-2016 01;20"], ["01_09_2016 01:20"], ["14-10-1066 12:00"], ["Tenth of January"], ["20 Sep 1988"], ["19-12-2050 13:34"], ["Tue Sep 06 2016 01:46:38 GMT+0100"], ["01-09-2016 00:00"], ["01-09-2016 2:00"]], "outputs": [[true], [false], [false], [true], [false], [false], [true], [false], [true], [false]]}
user: Create a function that finds the [integral](https://en.wikipedia.org/wiki/Integral) of the expression passed.

In order to find the integral all you need to do is add one to the `exponent` (the second argument), and divide the `coefficient` (the first argument) by that new number.

For example for `3x^2`, the integral would be `1x^3`: we added 1 to the exponent, and divided the coefficient by that new number).

Notes:
* The output should be a string.
* The coefficient and exponent is always a positive integer.


## Examples

```
 3, 2  -->  "1x^3"
12, 5  -->  "2x^6"
20, 1  -->  "10x^2"
40, 3  -->  "10x^4"
90, 2  -->  "30x^3"
```

Answer: {"fn_name": "integrate", "inputs": [[3, 2], [12, 5], [20, 1], [40, 3], [90, 2]], "outputs": [["1x^3"], ["2x^6"], ["10x^2"], ["10x^4"], ["30x^3"]]}
user: Complete the  function `scramble(str1, str2)` that returns `true` if a portion of ```str1``` characters can be rearranged to match ```str2```, otherwise returns ```false```.

**Notes:**
* Only lower case letters will be used (a-z). No punctuation or digits will be included.
* Performance needs to be considered

## Examples

```python
scramble('rkqodlw', 'world') ==> True
scramble('cedewaraaossoqqyt', 'codewars') ==> True
scramble('katas', 'steak') ==> False
```

Answer: {"fn_name": "scramble", "inputs": [["rkqodlw", "world"], ["cedewaraaossoqqyt", "codewars"], ["katas", "steak"], ["scriptjavx", "javascript"], ["scriptingjava", "javascript"], ["scriptsjava", "javascripts"], ["javscripts", "javascript"], ["aabbcamaomsccdd", "commas"], ["commas", "commas"], ["sammoc", "commas"]], "outputs": [[true], [true], [false], [false], [true], [true], [false], [true], [true], [true]]}
user: Complete the function that counts the number of unique consonants in a string (made up of printable ascii characters).

Consonants are letters used in English other than `"a", "e", "i", "o", "u"`. We will count `"y"` as a consonant.

Remember, your function needs to return the number of unique consonants - disregarding duplicates. For example, if the string passed into the function reads `"add"`, the function should return `1` rather than `2`, since `"d"` is a duplicate.

Similarly, the function should also disregard duplicate consonants of differing cases. For example, `"Dad"` passed into the function should return `1` as `"d"` and `"D"` are duplicates.

## Examples

```
"add" ==> 1
"Dad" ==> 1
"aeiou" ==> 0
"sillystring" ==> 7
"abcdefghijklmnopqrstuvwxyz" ==> 21
"Count my unique consonants!!" ==> 7
```

Answer: {"fn_name": "count_consonants", "inputs": [["sillystring"], ["aeiou"], ["abcdefghijklmnopqrstuvwxyz"], ["Count my unique consonants!!"]], "outputs": [[7], [0], [21], [7]]}
user: The goal is to write a pair of functions the first of which will take a string of binary along with a specification of bits, which will return a numeric, signed complement in two's complement format. The second will do the reverse. It will take in an integer along with a number of bits, and return a binary string. 

https://en.wikipedia.org/wiki/Two's_complement

Thus, to_twos_complement should take the parameters binary = "0000 0001", bits = 8 should return 1. And, binary = "11111111", bits = 8 should return -1 . While, from_twos_complement should return "00000000" from the parameters n = 0, bits = 8 . And, "11111111" from n = -1, bits = 8. 

You should account for some edge cases.

Answer: {"fn_name": "to_twos_complement", "inputs": [["00000001", 8], ["00000010", 8], ["01111110", 8], ["01111111", 8], ["11111111", 8], ["11111110", 8], ["10000010", 8], ["1000 0000", 8], ["1010 1010 0010 0010 1110 1010 0010 1110", 32], ["1000 0000 1110 1111 0011 0100 1100 1010", 32], ["10110001000100000101100011111000", 32]], "outputs": [[1], [2], [126], [127], [-1], [-2], [-126], [-128], [-1440552402], [-2131807030], [-1324328712]]}
user: # MOD 256 without the MOD operator

The MOD-operator % (aka mod/modulus/remainder):
```
Returns the remainder of a division operation.
The sign of the result is the same as the sign of the first operand.
(Different behavior in Python!)
```

The short unbelievable mad story for this kata:
I wrote a program and needed the remainder of the division by 256. And then it happened: The "5"/"%"-Key did not react. It must be broken! So I needed a way to:
```
Calculate the remainder of the division by 256 without the %-operator.
```

Also here some examples:
```
Input 254  -> Result 254
Input 256  -> Result 0
Input 258  -> Result 2 
Input -258 -> Result -2 (in Python: Result: 254!)
```
It is always expected the behavior of the MOD-Operator of the language!

The input number will always between -10000 and 10000.

For some languages the %-operator will be blocked. If it is not blocked and you know how to block it, tell me and I will include it.

For all, who say, this would be a duplicate: No, this is no duplicate! There are two katas, in that you have to write a general method for MOD without %. But this kata is only for MOD 256. And so you can create also other specialized solutions. ;-)

Of course you can use the digit "5" in your solution. :-)

I'm very curious for your solutions and the way you solve it. I found several interesting "funny" ways.

Have fun coding it and please don't forget to vote and rank this kata! :-) 

I have also created other katas. Take a look if you enjoyed this kata!

Answer: {"fn_name": "mod256_without_mod", "inputs": [[254], [256], [258], [-254], [-256], [-258]], "outputs": [[254], [0], [2], [2], [0], [254]]}