meetforever/GRPO_CL huggingface dataset:
user: You are a skier (marked below by the `X`). You have made it to the Olympics! Well done.

```
\_\_\_X\_
\*\*\*\*\*\
\*\*\*\*\*\*\
\*\*\*\*\*\*\*\
\*\*\*\*\*\*\*\*\
\*\*\*\*\*\*\*\*\*\\.\_\_\_\_/
```

Your job in this kata is to calculate the maximum speed you will achieve during your downhill run. The speed is dictated by the height of the mountain. Each element of the array is a layer of the mountain as indicated by the diagram above (and further below). So for this example the mountain has a height of 5 (5 rows of stars). `Speed` is `mountain height * 1.5`.

The jump length is calculated by `(mountain height * speed * 9) / 10`. Jump length should be rounded to 2 decimal places.

You must return the length of the resulting jump as a string in the following format:

* when less than 10 m: `"X metres: He's crap!"`
* between 10 and 25 m: `"X metres: He's ok!"`
* between 25 and 50 m: `"X metres: He's flying!"`
* when more than 50 m: `"X metres: Gold!!"`

So in the example case above, the right answer would be `"33.75 metres: He's flying!"`

Sadly, it takes a lot of time to make arrays look like mountains, so the tests wont all look so nice. To give an example, the above mountain would look as follows in most cases:

```
[*****, ******, *******, ********, *********]
```
Not as much fun, eh?

*p.s. if you think "metre" is incorrect, please [read this](https://en.wikipedia.org/wiki/Metre#Spelling)*

Answer: {"fn_name": "ski_jump", "inputs": [[["*"]], [["*", "**", "***"]], [["*", "**", "***", "****", "*****", "******"]], [["*", "**", "***", "****", "*****", "******", "*******", "********"]]], "outputs": [["1.35 metres: He's crap!"], ["12.15 metres: He's ok!"], ["48.60 metres: He's flying!"], ["86.40 metres: Gold!!"]]}
user: In computer science and discrete mathematics, an [inversion](https://en.wikipedia.org/wiki/Inversion_%28discrete_mathematics%29) is a pair of places in a sequence where the elements in these places are out of their natural order. So, if we use ascending order for a group of numbers, then an inversion is when larger numbers appear before lower number in a sequence.

Check out this example sequence: ```(1, 2, 5, 3, 4, 7, 6)``` and we can see here three inversions
```5``` and ```3```; ```5``` and ```4```; ```7``` and ```6```.

You are given a sequence of numbers and you should count the number of inversions in this sequence.

```Input```: A sequence as a tuple of integers.

```Output```: The inversion number as an integer.

Example:
```python
  count_inversion((1, 2, 5, 3, 4, 7, 6)) == 3
  count_inversion((0, 1, 2, 3)) == 0
```

Answer: {"fn_name": "count_inversion", "inputs": [[[1, 2, 3]], [[-3, -2, -1]], [[-20, 0, 20]], [[-13, 4, 8]], [[1, 3, 2]], [[-2, -3, -1]], [[-20, 20, 0]], [[-13, 9, 8]], [[3, 6, 2]], [[3, 6, 2, 7, 3]], [[26, 32, -21, 45, 21]], [[14, 12, 17, 124, 1, -12, 21, -24]], [[]], [[25, 12, 7, 4, 2, -7, -12, -22]], [[324, 123, 36, 4, -1, -72, -123]], [[10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]], [[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]], [[3, 3, 3]], [[-5, -5, -5]], [[0, 0, 7]], [[2, 2, 8]], [[1, 3, 3, 7]]], "outputs": [[0], [0], [0], [0], [1], [1], [1], [1], [2], [4], [5], [18], [0], [28], [21], [55], [0], [0], [0], [0], [0], [0]]}
user: Final kata of the series (highly recommended to compute [layers](https://www.codewars.com/kata/progressive-spiral-number-position/) and [branch](https://www.codewars.com/kata/progressive-spiral-number-branch/) first to get a good idea), this is a blatant ripoff of [the one offered on AoC](http://adventofcode.com/2017/day/3).

Given a number, return the Manhattan distance considering the core of the spiral (the `1` cell) as 0 and counting each step up, right, down or left to reach a given cell.

For example, using our beloved 5x5 square:

```
17 16 15 14 13    4 3 2 3 4
18 05 04 03 12    3 2 1 2 3
19 06 01 02 11 => 2 1 0 1 2
20 07 08 09 10    3 2 1 2 3
21 22 23 24 25    4 3 2 3 4
```

And thus your code should behave like this:

```python
distance(1) == 0
distance(5) == 2
distance(25) == 4
distance(30) == 5
distance(50) == 7
```

Just be ready for larger numbers, as usual always positive.

*[Dedicated to [swiftest learner I met in a long while](https://www.codewars.com/users/irbekrm/)]*

Answer: {"fn_name": "distance", "inputs": [[1], [5], [25], [30], [96], [50], [66], [306], [307], [308]], "outputs": [[0], [2], [4], [5], [5], [7], [7], [17], [18], [17]]}
user: write me a function `stringy` that takes a `size` and returns a `string` of alternating `'1s'` and `'0s'`.

the string should start with a `1`.

a string with `size` 6 should return :`'101010'`.

with `size` 4 should return : `'1010'`.

with `size` 12 should return : `'101010101010'`.

The size will always be positive and will only use whole numbers.

Answer: {"fn_name": "stringy", "inputs": [[3], [5], [12], [26], [28]], "outputs": [["101"], ["10101"], ["101010101010"], ["10101010101010101010101010"], ["1010101010101010101010101010"]]}
user: In this Kata, you will be given a lower case string and your task will be to remove `k` characters from that string using the following rule:
```Python
- first remove all letter 'a', followed by letter 'b', then 'c', etc...
- remove the leftmost character first.
```

```Python
For example: 
solve('abracadabra', 1) = 'bracadabra' # remove the leftmost 'a'.
solve('abracadabra', 2) = 'brcadabra'  # remove 2 'a' from the left.
solve('abracadabra', 6) = 'rcdbr'      # remove 5 'a', remove 1 'b' 
solve('abracadabra', 8) = 'rdr'
solve('abracadabra',50) = ''
```

More examples in the test cases. Good luck!

Please also try: 

[Simple time difference](https://www.codewars.com/kata/5b76a34ff71e5de9db0000f2)

[Simple remove duplicates](https://www.codewars.com/kata/5ba38ba180824a86850000f7)

Answer: {"fn_name": "solve", "inputs": [["abracadabra", 0], ["abracadabra", 1], ["abracadabra", 2], ["abracadabra", 6], ["abracadabra", 8], ["abracadabra", 50], ["hxehmvkybeklnj", 5], ["cccaabababaccbc", 3], ["cccaabababaccbc", 9], ["u", 1], ["back", 3]], "outputs": [["abracadabra"], ["bracadabra"], ["brcadabra"], ["rcdbr"], ["rdr"], [""], ["xmvkyklnj"], ["cccbbabaccbc"], ["cccccc"], [""], ["k"]]}
user: Given two integer arrays where the second array is a shuffled duplicate of the first array with one element missing, find the missing element.

Please note, there may be duplicates in the arrays, so checking if a numerical value exists in one and not the other is not a valid solution.

```
find_missing([1, 2, 2, 3], [1, 2, 3]) => 2
```
```
find_missing([6, 1, 3, 6, 8, 2], [3, 6, 6, 1, 2]) => 8
```

The first array will always have at least one element.

Answer: {"fn_name": "find_missing", "inputs": [[[1, 2, 3], [1, 3]], [[6, 1, 3, 6, 8, 2], [3, 6, 6, 1, 2]], [[7], []], [[4, 3, 3, 61, 8, 8], [8, 61, 8, 3, 4]], [[0, 0, 0, 0, 0], [0, 0, 0, 0]]], "outputs": [[2], [8], [7], [3], [0]]}
user: You have to write a function that describe Leo:
```python
def leo(oscar):
  pass
```

if oscar was (integer) 88, you have to return "Leo finally won the oscar! Leo is happy".
if oscar was 86, you have to return "Not even for Wolf of wallstreet?!"
if it was not 88 or 86 (and below 88) you should return "When will you give Leo an Oscar?"
if it was over 88 you should return "Leo got one already!"

Answer: {"fn_name": "leo", "inputs": [[88], [87], [86]], "outputs": [["Leo finally won the oscar! Leo is happy"], ["When will you give Leo an Oscar?"], ["Not even for Wolf of wallstreet?!"]]}
user: Your car is old, it breaks easily. The shock absorbers are gone and you think it can handle about 15 more bumps before it dies totally.

Unfortunately for you, your drive is very bumpy! Given a string showing either flat road ("\_") or bumps ("n"), work out if you make it home safely. 15 bumps or under, return "Woohoo!", over 15 bumps return "Car Dead".

Answer: {"fn_name": "bumps", "inputs": [["n"], ["_nnnnnnn_n__n______nn__nn_nnn"], ["______n___n_"], ["nnnnnnnnnnnnnnnnnnnnn"]], "outputs": [["Woohoo!"], ["Car Dead"], ["Woohoo!"], ["Car Dead"]]}
user: In Russia regular bus tickets usually consist of 6 digits. The ticket is called lucky when the sum of the first three digits equals to the sum of the last three digits. Write a function to find out whether the ticket is lucky or not. Return true if so, otherwise return false. Consider that input is always a string. Watch examples below.

Answer: {"fn_name": "is_lucky", "inputs": [["123321"], ["12341234"], ["100001"], ["100200"], ["912435"], ["12a12a"], ["999999"], ["1111"], ["000000"], [""]], "outputs": [[true], [false], [true], [false], [true], [false], [true], [false], [true], [false]]}
user: In this Kata, we will calculate the **minumum positive number that is not a possible sum** from a list of positive integers. 

```
solve([1,2,8,7]) = 4 => we can get 1, 2, 3 (from 1+2), but we cannot get 4. 4 is the minimum number not possible from the list. 
solve([4,1,2,3,12]) = 11. We can get 1, 2, 3, 4, 4+1=5, 4+2=6,4+3=7,4+3+1=8,4+3+2=9,4+3+2+1=10. But not 11. 
solve([2,3,2,3,4,2,12,3]) = 1. We cannot get 1.
```
More examples in test cases. 

Good luck!

Answer: {"fn_name": "solve", "inputs": [[[1, 2, 8, 7]], [[2, 12, 3, 1]], [[4, 2, 8, 3, 1]], [[4, 2, 7, 3, 1]], [[4, 2, 12, 3]]], "outputs": [[4], [7], [19], [18], [1]]}
user: You're laying out a rad pixel art mural to paint on your living room wall in homage to [Paul Robertson](http://68.media.tumblr.com/0f55f7f3789a354cfcda7c2a64f501d1/tumblr_o7eq3biK9s1qhccbco1_500.png), your favorite pixel artist.

You want your work to be perfect down to the millimeter. You haven't decided on the dimensions of your piece, how large you want your pixels to be, or which wall you want to use. You just know that you want to fit an exact number of pixels.

To help decide those things you've decided to write a function, `is_divisible()` that will tell you whether a wall of a certain length can exactly fit an integer number of pixels of a certain length.

Your function should take two arguments: the size of the wall in millimeters and the size of a pixel in millimeters. It should return `True` if you can fit an exact number of pixels on the wall, otherwise it should return `False`. For example `is_divisible(4050, 27)` should return `True`, but `is_divisible(4066, 27)` should return `False`.

Note: you don't need to use an `if` statement here. Remember that in Python an expression using the `==` comparison operator will evaluate to either `True` or `False`:
```python
>>> def equals_three(num):
>>>     return num == 3
>>> equals_three(5)
False
>>> equals_three(3)
True
```


```if:csharp
Documentation:
Kata.IsDivisible Method (Int32, Int32)

Returns a boolean representing if the first argument is perfectly divisible by the second argument.

Syntax


public
static
bool IsDivisible(
int wallLength,
    int pixelSize,
    )
  



Parameters

wallLength

Type: System.Int32
The length of the wall in millimeters.

pixelSize

Type: System.Int32
The length of a pixel in millimeters.

Return Value

Type: System.Boolean
  A boolean value representing if the first argument is perfectly divisible by the second.

```

Answer: {"fn_name": "is_divisible", "inputs": [[4050, 27], [4066, 27], [10000, 20], [10005, 20]], "outputs": [[true], [false], [true], [false]]}
user: ### Task
 King Arthur and his knights are having a New Years party. Last year Lancelot was jealous of Arthur, because Arthur had a date and Lancelot did not, and they started a duel.

 To prevent this from happening again, Arthur wants to make sure that there are at least as many women as men at this year's party. He gave you a list of integers of all the party goers. 
 
 Arthur needs you to return true if he needs to invite more women or false if he is all set.

### Input/Output


 - `[input]` integer array `L` (`$a` in PHP)

  An array (guaranteed non-associative in PHP) representing the genders of the attendees, where `-1` represents `women` and `1` represents `men`.
  
  `2 <= L.length <= 50`
  

- `[output]` a boolean value

  `true` if Arthur need to invite more women, `false` otherwise.

Answer: {"fn_name": "invite_more_women", "inputs": [[[1, -1, 1]], [[-1, -1, -1]], [[1, -1]], [[1, 1, 1]], [[]]], "outputs": [[true], [false], [false], [true], [false]]}
user: You are given three piles of casino chips: white, green and black chips:

* the first pile contains only white chips
* the second pile contains only green chips
* the third pile contains only black chips

Each day you take exactly two chips of different colors and head to the casino. You can choose any color, but you are not allowed to take two chips of the same color in a day.

You will be given an array representing the number of chips of each color and your task is to return the maximum number of days you can pick the chips. Each day you need to take exactly two chips.

```python 
solve([1,1,1]) = 1, because after you pick on day one, there will be only one chip left
solve([1,2,1] = 2, you can pick twice; you pick two chips on day one then on day two
solve([4,1,1]) = 2
```

```javascript 
solve([1,1,1]) = 1, because after you pick on day one, there will be only one chip left
solve([1,2,1]) = 2, you can pick twice; you pick two chips on day one then on day two
solve([4,1,1]) = 2
```

```go 
solve([1,1,1]) = 1, because after you pick on day one, there will be only one chip left
solve([1,2,1]) = 2, you can pick twice; you pick two chips on day one then on day two
solve([4,1,1]) = 2
```


```ruby 
solve([1,1,1]) = 1, because after you pick on day one, there will be only one chip left
solve([1,2,1]) = 2, you can pick twice; you pick two chips on day, two chips on day two
solve([4,1,1]) = 2
```

More examples in the test cases. Good luck!

Brute force is not the way to go here. Look for a simplifying mathematical approach.

Answer: {"fn_name": "solve", "inputs": [[[1, 1, 1]], [[1, 2, 1]], [[4, 1, 1]], [[8, 2, 8]], [[8, 1, 4]], [[7, 4, 10]], [[12, 12, 12]], [[1, 23, 2]]], "outputs": [[1], [2], [2], [9], [5], [10], [18], [3]]}
user: The dragon's curve is a self-similar fractal which can be obtained by a recursive method. 

Starting with the string `D0 = 'Fa'`, at each step simultaneously perform the following operations:

```
replace 'a' with: 'aRbFR'
replace 'b' with: 'LFaLb'
```

For example (spaces added for more visibility) : 

```
1st iteration: Fa -> F aRbF R
2nd iteration: FaRbFR -> F aRbFR R LFaLb FR
```

After `n` iteration, remove `'a'` and `'b'`. You will have a string with `'R'`,`'L'`, and `'F'`. This is a set of instruction. Starting at the origin of a grid looking in the `(0,1)` direction, `'F'` means a step forward, `'L'` and `'R'` mean respectively turn left and right. After executing all instructions, the trajectory will give a beautifull self-replicating pattern called 'Dragon Curve'

The goal of this kata is to code a function wich takes one parameter `n`, the number of iterations needed and return the string of instruction as defined above. For example: 

```
n=0, should return: 'F'
n=1, should return: 'FRFR'
n=2, should return: 'FRFRRLFLFR'
```

`n` should be a number and non-negative integer. All other case should return the empty string: `''`.

Answer: {"fn_name": "Dragon", "inputs": [["a"], [1.1], [-1]], "outputs": [[""], [""], [""]]}
user: # Task
For the given set `S` its powerset is the set of all possible subsets of `S`.

Given an array of integers nums, your task is to return the powerset of its elements.

Implement an algorithm that does it in a depth-first search fashion. That is, for every integer in the set, we can either choose to take or not take it. At first, we choose `NOT` to take it, then we choose to take it(see more details in exampele).

# Example

For `nums = [1, 2]`, the output should be `[[], [2], [1], [1, 2]].`

Here's how the answer is obtained:
```
don't take element 1
----don't take element 2
--------add []
----take element 2
--------add [2]
take element 1
----don't take element 2
--------add [1]
----take element 2
--------add [1, 2]```

For `nums = [1, 2, 3]`, the output should be 

`[[], [3], [2], [2, 3], [1], [1, 3], [1, 2], [1, 2, 3]]`.

# Input/Output

`[input]` integer array `nums`

Array of positive integers, `1 ≤ nums.length ≤ 10`.

[output] 2D integer array

The powerset of nums.

Answer: {"fn_name": "powerset", "inputs": [[[1, 2]], [[1, 2, 3]], [[1]], [[125, 15, 155, 15, 158]], [[1, 2, 3, 4]]], "outputs": [[[[], [2], [1], [1, 2]]], [[[], [3], [2], [2, 3], [1], [1, 3], [1, 2], [1, 2, 3]]], [[[], [1]]], [[[], [158], [15], [15, 158], [155], [155, 158], [155, 15], [155, 15, 158], [15], [15, 158], [15, 15], [15, 15, 158], [15, 155], [15, 155, 158], [15, 155, 15], [15, 155, 15, 158], [125], [125, 158], [125, 15], [125, 15, 158], [125, 155], [125, 155, 158], [125, 155, 15], [125, 155, 15, 158], [125, 15], [125, 15, 158], [125, 15, 15], [125, 15, 15, 158], [125, 15, 155], [125, 15, 155, 158], [125, 15, 155, 15], [125, 15, 155, 15, 158]]], [[[], [4], [3], [3, 4], [2], [2, 4], [2, 3], [2, 3, 4], [1], [1, 4], [1, 3], [1, 3, 4], [1, 2], [1, 2, 4], [1, 2, 3], [1, 2, 3, 4]]]]}
user: Complete the function that takes one argument, a list of words, and returns the length of the longest word in the list.

For example: 

```python
['simple', 'is', 'better', 'than', 'complex'] ==> 7
```

Do not modify the input list.

Answer: {"fn_name": "longest", "inputs": [[["simple", "is", "better", "than", "complex"]], [["explicit", "is", "better", "than", "implicit"]], [["beautiful", "is", "better", "than", "ugly"]]], "outputs": [[7], [8], [9]]}
user: Fibonacci numbers are generated by setting F0 = 0, F1 = 1, and then using the formula:

# Fn = Fn-1 + Fn-2

Your task is to efficiently calculate the **n**th element in the Fibonacci sequence and then count the occurrence of each digit in the number. Return a list of integer pairs sorted in **descending** order.

10 ≤ n ≤ 100000

## Examples
```
f(10) = 55  # returns [(2, 5)], as there are two occurances of digit 5

f(10000)    # returns:
  [(254, 3),
   (228, 2),
   (217, 6),
   (217, 0),
   (202, 5),
   (199, 1),
   (198, 7),
   (197, 8),
   (194, 4),
   (184, 9)]
```
If two integers have the same count, sort them in descending order.

Your algorithm must be efficient.

~~~if:javascript
Solving this Kata in Javascript requires the use of the bignumber.js library. I have included starter code to assist you with using the library. Thanks to `kazk` for assisting with the translation.
~~~

Answer: {"fn_name": "fib_digits", "inputs": [[10]], "outputs": [[[[2, 5]]]]}
user: Your classmates asked you to copy some paperwork for them. You know that there are 'n' classmates and the paperwork has 'm' pages.

Your task is to calculate how many blank pages do you need.

### Example:
```python
paperwork(5, 5) == 25
```

**Note:** if `n < 0` or `m < 0` return `0`!

Waiting for translations and Feedback! Thanks!

Answer: {"fn_name": "paperwork", "inputs": [[5, 5], [5, -5], [-5, -5], [-5, 5], [5, 0]], "outputs": [[25], [0], [0], [0], [0]]}
user: You may be familiar with the concept of combinations: for example, if you take 5 cards from a 52 cards deck as you would playing poker, you can have a certain number (2,598,960, would you say?) of different combinations.

In mathematics the number of *k* combinations you can have taking from a set of *n* elements is called the [binomial coefficient](https://en.wikipedia.org/wiki/Binomial_coefficient) of n and k, more popularly called **n choose k**.

The formula to compute it is relatively simple: `n choose k`==`n!/(k!*(n-k)!)`, where `!` of course denotes the factorial operator.

You are now to create a choose function that computes the binomial coefficient, like this:

```
choose(1,1)==1
choose(5,4)==5
choose(10,5)==252
choose(10,20)==0
choose(52,5)==2598960
```

Be warned: a certain degree of optimization is expected, both to deal with larger numbers precision (and their rounding errors in languages like JS) and computing time.

Answer: {"fn_name": "choose", "inputs": [[1, 1], [5, 4], [10, 5], [10, 20], [52, 5], [100, 10], [500, 4], [1000, 3], [200, 8], [300, 6]], "outputs": [[1], [5], [252], [0], [2598960], [17310309456440], [2573031125], [166167000], [55098996177225], [962822846700]]}
user: Imagine that you have an array of 3 integers each representing a different person. Each number can be 0, 1, or 2 which represents the number of hands that person holds up.

Now imagine there is a sequence which follows these rules:
* None of the people have their arms raised at first
* Firstly, a person raises 1 hand; then they raise the second hand; after that they put both hands down - these steps form a cycle
* Person #1 performs these steps all the time, person #2 advances only after person #1 puts their hands down, and person #3 advances only after person #2 puts their hands down

The first 10 steps of the sequence represented as a table are:

```
Step   P1   P2   P3
--------------------
 0     0    0    0
 1     1    0    0
 2     2    0    0
 3     0    1    0
 4     1    1    0
 5     2    1    0
 6     0    2    0
 7     1    2    0
 8     2    2    0
 9     0    0    1
```

Given a number, return an array with the number of hands raised by each person at that step.

Answer: {"fn_name": "get_positions", "inputs": [[54], [98], [3]], "outputs": [[[0, 0, 0]], [[2, 2, 1]], [[0, 1, 0]]]}
user: Thanks to the effects of El Nino this year my holiday snorkelling trip was akin to being in a washing machine... Not fun at all.

Given a string made up of '~' and '\_' representing waves and calm respectively, your job is to check whether a person would become seasick.

Remember, only the process of change from wave to calm (and vice versa) will add to the effect (really wave peak to trough but this will do). Find out how many changes in level the string has and if that figure is more than 20% of the string, return "Throw Up", if less, return "No Problem".

Answer: {"fn_name": "sea_sick", "inputs": [["~"], ["_~~~~~~~_~__~______~~__~~_~~"], ["______~___~_"], ["____"], ["_~~_~____~~~~~~~__~_~"]], "outputs": [["No Problem"], ["Throw Up"], ["Throw Up"], ["No Problem"], ["Throw Up"]]}
user: Implement `String#digit?` (in Java `StringUtils.isDigit(String)`), which should return `true` if given object is a digit (0-9), `false` otherwise.

Answer: {"fn_name": "is_digit", "inputs": [[""], ["7"], [" "], ["a"], ["a5"], ["14"], ["!"], ["\""], ["#"], ["$"], ["%"], ["&"], ["'"], ["("], [")"], ["*"], ["+"], [","], ["-"], ["."], ["/"], ["0"], ["1"], ["2"], ["3"], ["4"], ["5"], ["6"], ["8"], ["9"], [":"], [";"], ["<"], ["="], [">"], ["?"], ["@"], ["A"], ["B"], ["C"], ["D"], ["E"], ["F"], ["G"], ["H"], ["I"], ["J"], ["K"], ["L"], ["M"], ["N"], ["O"], ["P"], ["Q"], ["R"], ["S"], ["T"], ["U"], ["V"], ["W"], ["X"], ["Y"], ["Z"], ["["], ["\\"], ["]"], ["^"], ["_"], ["`"], ["b"], ["c"], ["d"], ["e"], ["f"], ["g"], ["h"], ["i"], ["j"], ["k"], ["l"], ["m"], ["n"], ["o"], ["p"], ["q"], ["r"], ["s"], ["t"], ["u"], ["v"], ["w"], ["x"], ["y"], ["z"], ["{"], ["|"], ["}"], ["~"], ["1\n0"], ["1\n"], ["1 "], [" 1"]], "outputs": [[false], [true], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [true], [true], [true], [true], [true], [true], [true], [true], [true], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false]]}