meetforever/GRPO_CL huggingface dataset:
user: You will get an array of numbers. 

Every preceding number is smaller than the one following it.

Some numbers will be missing, for instance:
```
[-3,-2,1,5] //missing numbers are: -1,0,2,3,4
```
Your task is to return an array of those missing numbers:
```
[-1,0,2,3,4]
```

Answer: {"fn_name": "find_missing_numbers", "inputs": [[[-3, -2, 1, 4]], [[-1, 0, 1, 2, 3, 4]], [[]], [[0]], [[-4, 4]]], "outputs": [[[-1, 0, 2, 3]], [[]], [[]], [[]], [[-3, -2, -1, 0, 1, 2, 3]]]}
user: Your task is to make two functions, ```max``` and ```min``` (`maximum` and `minimum` in PHP and Python) that take a(n) array/vector of integers ```list``` as input and outputs, respectively, the largest and lowest number in that array/vector.

#Examples
```python
maximun([4,6,2,1,9,63,-134,566]) returns 566
minimun([-52, 56, 30, 29, -54, 0, -110]) returns -110
maximun([5]) returns 5
minimun([42, 54, 65, 87, 0]) returns 0
```

#Notes
- You may consider that there will not be any empty arrays/vectors.

Answer: {"fn_name": "minimum", "inputs": [[[-52, 56, 30, 29, -54, 0, -110]], [[42, 54, 65, 87, 0]], [[1, 2, 3, 4, 5, 10]], [[-1, -2, -3, -4, -5, -10]], [[9]]], "outputs": [[-110], [0], [1], [-10], [9]]}
user: **Steps**
1. Square the numbers that are greater than zero.
2. Multiply by 3 every third number.
3. Multiply by -1 every fifth number.
4. Return the sum of the sequence.

**Example**   
`{ -2, -1, 0, 1, 2 }` returns `-6`
```
1. { -2, -1, 0, 1 * 1, 2 * 2 }
2. { -2, -1, 0 * 3, 1, 4 }
3. { -2, -1, 0, 1, -1 * 4 }
4. -6
```

P.S.: The sequence consists only of integers. And try not to use "for", "while" or "loop" statements.

Answer: {"fn_name": "calc", "inputs": [[[0, 2, 1, -6, -3, 3]], [[0]], [[1, 1, 1, 1, 1]], [[1, 1, -9, 9, 16, -15, -45, -73, 26]], [[1, -1, 10, -9, 16, 15, 45, -73, -26]], [[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]], [[-5, -5, -5, -5, -5, -5, -5]]], "outputs": [[31], [0], [5], [1665], [2584], [0], [-45]]}
user: # Task

In the city, a bus named Fibonacci runs on the road every day.

There are `n` stations on the route. The Bus runs from station1 to stationn.

At the departure station(station1), `k` passengers get on the bus. 

At the second station(station2), a certain number of passengers get on and the same number get off. There are still `k` passengers on the bus.

From station3 to stationn-1, the number of boarding and alighting passengers follows the following rule:

- At stationi, the number of people getting on is the sum of the number of people getting on at the two previous stations(stationi-1 and stationi-2)
- The number of people getting off is equal to the number of people getting on at the previous station(stationi-1).

At stationn, all the passengers get off the bus. 

Now, The numbers we know are: `k` passengers get on the bus at station1, `n` stations in total, `m` passengers get off the bus at stationn.

We want to know: How many passengers on the bus when the bus runs out stationx.

# Input

- `k`: The number of passengers get on the bus at station1.
  - `1 <= k <= 100`


- `n`: The total number of stations(1-based).
  - `6 <= n <= 30`


- `m`: The number of passengers get off the bus at stationn.
  - `1 <= m <= 10^10`


- `x`: Stationx(1-based). The station we need to calculate.
  - `3 <= m <= n-1`


- All inputs are valid integers.

# Output

An integer. The number of passengers on the bus when the bus runs out stationx.

Answer: {"fn_name": "calc", "inputs": [[5, 7, 32, 4], [12, 23, 212532, 8]], "outputs": [[13], [252]]}
user: Similar setting of the [previous](https://www.codewars.com/kata/progressive-spiral-number-position/), this time you are called to identify in which "branch" of the spiral a given number will end up.

Considering a square of numbers disposed as the 25 items in [the previous kata](https://www.codewars.com/kata/progressive-spiral-number-position/), the branch are numbered as it follows:

```
17 16 15 14 13    1 1 1 1 0
18 05 04 03 12    2 1 1 0 0
19 06 01 02 11 => 2 2 0 0 0
20 07 08 09 10    2 2 3 3 0
21 22 23 24 25    2 3 3 3 3
```

Meaning that, for example, numbers in the `10-13` range will be in branch `0`, numbers in the range `14-17` are inside branch `1`, all those nice numbers in the `18-21` can call branch `2` their house and finally the `21-25` team all falls under the `3` branch.

Your function must return the number of the index of each number [`1` being a special case you might consider equivalent to being in the first branch, `0`], as per examples:

```python
branch(1) == 0 #kind of special case here
branch(5) == 1
branch(25) == 3
branch(30) == 0
branch(50) == 0
```

It might help A LOT to both solve the [previous kata](https://www.codewars.com/kata/progressive-spiral-number-position/) and to visualize the diagonals of the square. Be ready for big numbers and, as usual, inspired by [AoC](http://adventofcode.com/2017/day/3). Finally, when ready, go to compute [the distance](https://www.codewars.com/kata/progressive-spiral-number-distance/) of the series.

Answer: {"fn_name": "branch", "inputs": [[1], [5], [25], [30], [50]], "outputs": [[0], [1], [3], [0], [0]]}
user: Calculate the number of items in a vector that appear at the same index in each vector, with the same value. 

```python
   vector_affinity([1, 2, 3, 4, 5], [1, 2, 2, 4, 3]) # => 0.6
   vector_affinity([1, 2, 3], [1, 2, 3]) # => 1.0
```

Affinity value should be realized on a scale of 0.0 to 1.0, with 1.0 being absolutely identical. Two identical sets should always be evaulated as having an affinity or 1.0.

Hint: The last example test case holds a significant clue to calculating the affinity correctly.

Answer: {"fn_name": "vector_affinity", "inputs": [[[1, 2, 3], [1, 2, 3, 4, 5]], [[1, 2, 3, 4], [1, 2, 3, 5]], [[1, 2, 3, 4, 5], []], [[1, 2, 3], [1, 2, 3]], [[6, 6, 6, 6, 6, 6], [6, null, null, 6, 6, null]], [[6], [6, 6, 6, 6, 6, 6]], [[], []], [[null], [null]]], "outputs": [[0.6], [0.75], [0.0], [1.0], [0.5], [0.16666666666666666], [1.0], [1.0]]}
user: You probably know that the "mode" of a set of data is the data point that appears most frequently. Looking at the characters that make up the string `"sarsaparilla"` we can see that the letter `"a"` appears four times, more than any other letter, so the mode of `"sarsaparilla"` is `"a"`.

But do you know what happens when two or more data points occur the most? For example, what is the mode of the letters in `"tomato"`? Both `"t"` and `"o"` seem to be tied for appearing most frequently.

Turns out that a set of data can, in fact, have multiple modes, so `"tomato"` has two modes: `"t"` and `"o"`. It's important to note, though, that if *all* data appears the same number of times there is no mode. So `"cat"`, `"redder"`, and `[1, 2, 3, 4, 5]` do not have a mode.

Your job is to write a function `modes()` that will accept one argument `data` that is a sequence like a string or a list of numbers and return a sorted list containing the mode(s) of the input sequence. If data does not contain a mode you should return an empty list.

For example:

```python
>>> modes("tomato")
["o", "t"]
>>> modes([1, 3, 3, 7])
[3]
>>> modes(["redder"])
[]
```

You can trust that your input data will always be a sequence and will always contain orderable types (no inputs like `[1, 2, 2, "a", "b", "b"]`).

Answer: {"fn_name": "modes", "inputs": [["tomato"], [[1, 3, 3, 7]], [["redder"]]], "outputs": [[["o", "t"]], [[3]], [[]]]}
user: A grid is a perfect starting point for many games (Chess, battleships, Candy Crush!).

Making a digital chessboard I think is an interesting way of visualising how loops can work together.

Your task is to write a function that takes two integers `rows` and `columns` and returns a chessboard pattern as a two dimensional array.

So `chessBoard(6,4)` should return an array like this:


    [
            ["O","X","O","X"],
            ["X","O","X","O"],
            ["O","X","O","X"],
            ["X","O","X","O"],
            ["O","X","O","X"],
            ["X","O","X","O"]
    ]

And `chessBoard(3,7)` should return this:


    [
        ["O","X","O","X","O","X","O"],
        ["X","O","X","O","X","O","X"],
        ["O","X","O","X","O","X","O"]
    ]

The white spaces should be represented by an: `'O'`

and the black an: `'X'`

The first row should always start with a white space `'O'`

Answer: {"fn_name": "chess_board", "inputs": [[1, 1], [1, 2], [2, 1], [2, 2], [6, 6]], "outputs": [[[["O"]]], [[["O", "X"]]], [[["O"], ["X"]]], [[["O", "X"], ["X", "O"]]], [[["O", "X", "O", "X", "O", "X"], ["X", "O", "X", "O", "X", "O"], ["O", "X", "O", "X", "O", "X"], ["X", "O", "X", "O", "X", "O"], ["O", "X", "O", "X", "O", "X"], ["X", "O", "X", "O", "X", "O"]]]]}
user: Integral numbers can be even or odd.

Even numbers satisfy `n = 2m` ( with `m` also integral ) and we will ( completely arbitrarily ) think of odd numbers as `n = 2m + 1`.  
Now, some odd numbers can be more odd than others: when for some `n`, `m` is more odd than for another's. Recursively. :]  
Even numbers are just not odd.

# Task

Given a finite list of integral ( not necessarily non-negative ) numbers, determine the number that is _odder than the rest_.  
If there is no single such number, no number is odder than the rest; return `Nothing`, `null` or a similar empty value.

# Examples

```python
oddest([1,2]) => 1
oddest([1,3]) => 3
oddest([1,5]) => None
```

# Hint

Do you _really_ want one? Point or tap here.

Answer: {"fn_name": "oddest", "inputs": [[[1, 2]], [[1, 3]], [[1, 5]], [[]], [[0]], [[0, 1]], [[1, 3, 5, 7]], [[2, 4]], [[-1]], [[-1, -1]], [[-1, 0, 1]], [[-3, 3]], [[-5, 3]]], "outputs": [[1], [3], [null], [null], [0], [1], [7], [null], [-1], [null], [-1], [3], [null]]}
user: # Introduction

The Condi (Consecutive Digraphs) cipher was introduced by G4EGG (Wilfred Higginson) in 2011. The cipher preserves word divisions, and is simple to describe and encode, but it's surprisingly difficult to crack. 

# Encoding Algorithm

The encoding steps are:
- Start with an `initial key`, e.g. `cryptogram`
- Form a `key`, remove the key duplicated letters except for the first occurrence
- Append to it, in alphabetical order all letters which do not occur in the `key`.  
  The example produces: `cryptogambdefhijklnqsuvwxz`
- Number the `key alphabet` starting with 1.
```python
1  2  3  4  5  6  7  8  9  10 11 12 13
c  r  y  p  t  o  g  a  m  b  d  e  f 
14 15 16 17 18 19 20 21 22 23 24 25 26
h  i  j  k  l  n  q  s  u  v  w  x  z
```
- One of the inputs to encoding algorithm is an `initial shift`, say `10`
- Encode the first letter of your `message` by moving 10 places to the right from the letter's position in the key alphabet. If the first letter were say `o` then the letter 10 places to the right in the `key alphabet` is `j`, so `o` would be encoded as `j`. If you move past the end of the key alphabet you wrap back to the beginning. For example if the first letter were `s` then counting 10 places would bring you around to `t`.
- Use the position of the previous plaintext letter as the number of places to move to encode the next plaintext number. If you have just encoded an `o` (position 6) , and you now want to encode say `n`, then you move 6 places to the right from `n` which brings you to `x`.
- Keep repeating the previous step until all letters are encoded.

Decoding is the reverse of encoding - you move to the left instead of to the right.

# Task

Create two functions - `encode`/`Encode` and `decode`/`Decode` which implement Condi cipher encoding and decoding.

# Inputs

- `message` - a string to encode/decode
- `key` - a key consists of only lower case letters
- `initShift` - a non-negative integer representing the initial shift

# Notes
- Don't forget to remove the duplicated letters from the `key` except for the first occurrence 
- Characters which do not exist in the `key alphabet` should be coppied to the output string exactly like they appear in the `message` string
- Check the test cases for samples

Answer: {"fn_name": "encode", "inputs": [["on", "cryptogram", 10]], "outputs": [["jx"]]}
user: There were and still are many problem in CW about palindrome numbers and palindrome strings. We suposse that you know which kind of numbers they are. If not, you may search about them using your favourite search engine.

In this kata you will be given a positive integer, ```val``` and you have to create the function ```next_pal()```(```nextPal``` Javascript) that will output the smallest palindrome number higher than ```val```.

Let's see:
```python
For Python
next_pal(11) == 22

next_pal(188) == 191

next_pal(191) == 202

next_pal(2541) == 2552
```

You will be receiving values higher than 10, all valid.

Enjoy it!!

Answer: {"fn_name": "next_pal", "inputs": [[11], [188], [191], [2541]], "outputs": [[22], [191], [202], [2552]]}
user: Implement `String#ipv4_address?`, which should return true if given object is an IPv4 address - four numbers (0-255) separated by dots.

It should only accept addresses in canonical representation, so no leading `0`s, spaces etc.

Answer: {"fn_name": "ipv4_address", "inputs": [[""], ["127.0.0.1"], ["0.0.0.0"], ["255.255.255.255"], ["10.20.30.40"], ["10.256.30.40"], ["10.20.030.40"], ["127.0.1"], ["127.0.0.0.1"], ["..255.255"], ["127.0.0.1\n"], ["\n127.0.0.1"], [" 127.0.0.1"], ["127.0.0.1 "], [" 127.0.0.1 "], ["127.0.0.1."], [".127.0.0.1"], ["127..0.1"]], "outputs": [[false], [true], [true], [true], [true], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false], [false]]}
user: # Task
 A common way for prisoners to communicate secret messages with each other is to encrypt them. One such encryption algorithm goes as follows.

 You take the message and place it inside an `nx6` matrix (adjust the number of rows depending on the message length) going from top left to bottom right (one row at a time) while replacing spaces with dots (.) and adding dots at the end of the last row (if necessary) to complete the matrix.
 
 Once the message is in the matrix you read again from top left to bottom right but this time going one column at a time and treating each column as one word.

# Example

 The following message `"Attack at noon or we are done for"` is placed in a `6 * 6` matrix :
```
Attack
.at.no
on.or.
we.are
.done.
for...```
Reading it one column at a time we get:

 `A.ow.f tanedo tt..or a.oan. cnrre. ko.e..`

# Input/Output


 - `[input]` string `msg`

  a regular english sentance representing the original message


 - `[output]` a string

  encrypted message

Answer: {"fn_name": "six_column_encryption", "inputs": [["Attack at noon or we are done for"], ["Let's kill them all"], ["Meet me behind the kitchen tomorrow at seven in the evening"]], "outputs": [["A.ow.f tanedo tt..or a.oan. cnrre. ko.e.."], ["Lkhl eie. tlm. 'l.. s.a. .tl."], ["Men.eoaete e.dknrtnhn eb.i.r..ei tetttosi.n .hhcoweneg miehm.v.v."]]}
user: # Write Number in Expanded Form

You will be given a number and you will need to return it as a string in [Expanded Form](https://www.mathplacementreview.com/arithmetic/whole-numbers.php#expanded-form). For example:

```python
expanded_form(12) # Should return '10 + 2'
expanded_form(42) # Should return '40 + 2'
expanded_form(70304) # Should return '70000 + 300 + 4'
```

NOTE: All numbers will be whole numbers greater than 0.

If you liked this kata, check out [part 2](https://www.codewars.com/kata/write-number-in-expanded-form-part-2)!!

Answer: {"fn_name": "expanded_form", "inputs": [[2], [12], [42], [70304], [4982342]], "outputs": [["2"], ["10 + 2"], ["40 + 2"], ["70000 + 300 + 4"], ["4000000 + 900000 + 80000 + 2000 + 300 + 40 + 2"]]}
user: Bob is a lazy man. 

He needs you to create a method that can determine how many ```letters``` and ```digits``` are in a given string.



Example:

"hel2!lo" --> 6

"wicked .. !" --> 6

"!?..A" --> 1

Answer: {"fn_name": "count_letters_and_digits", "inputs": [["n!!ice!!123"], ["de?=?=tttes!!t"], [""], ["!@#$%^&`~."], ["u_n_d_e_r__S_C_O_R_E"]], "outputs": [[7], [8], [0], [0], [10]]}
user: Complete the method that takes a boolean value and return a `"Yes"` string for `true`, or a `"No"` string for `false`.

Answer: {"fn_name": "bool_to_word", "inputs": [[true], [false]], "outputs": [["Yes"], ["No"]]}
user: The Binomial Form of a polynomial has many uses, just as the standard form does.  For comparison, if p(x) is in Binomial Form and q(x) is in standard form, we might write

p(x) := a0 \* xC0 + a1 \* xC1 + a2 \* xC2 + ... + aN \* xCN

q(x) := b0 + b1 \* x + b2 \* x^(2) + ... + bN \* x^(N)

Both forms have tricks for evaluating them, but tricks should not be necessary.  The most important thing to keep in mind is that aCb can be defined for non-integer values of a; in particular,

```
aCb := a * (a-1) * (a-2) * ... * (a-b+1) / b!   // for any value a and integer values b
    := a! / ((a-b)!b!)                          // for integer values a,b
```

The inputs to your function are an array which specifies a polynomial in Binomial Form, ordered by highest-degree-first, and also a number to evaluate the polynomial at.  An example call might be

```python
value_at([1, 2, 7], 3)
```

and the return value would be 16, since 3C2 + 2 * 3C1 + 7 = 16.  In more detail, this calculation looks like

```
1 * xC2 + 2 * xC1 + 7 * xC0 :: x = 3
3C2 + 2 * 3C1 + 7
3 * (3-1) / 2! + 2 * 3 / 1! + 7
3 + 6 + 7 = 16
```

More information can be found by reading about [Binomial Coefficients](https://en.wikipedia.org/wiki/Binomial_coefficient) or about [Finite Differences](https://en.wikipedia.org/wiki/Finite_difference).

Note that while a solution should be able to handle non-integer inputs and get a correct result, any solution should make use of rounding to two significant digits (as the official solution does) since high precision for non-integers is not the point here.

Answer: {"fn_name": "value_at", "inputs": [[[1, 2, 7], 3], [[1, 2, 7, 0, 5], 2], [[1, 1, 1, 1, 7, 0, 5], 2], [[1, 2, 7, 0, 5], 0.6], [[1, 2, 7, 0, 5], 0]], "outputs": [[16], [12], [12], [4.24], [5.0]]}
user: ```if-not:swift
Write simple .camelCase method (`camel_case` function in PHP, `CamelCase` in C# or `camelCase` in Java) for strings. All words must have their first letter capitalized without spaces.
```
```if:swift
Write a simple `camelCase` function for strings. All words must have their first letter capitalized and all spaces removed.
```
For instance:

```python
camelcase("hello case") => HelloCase
camelcase("camel case word") => CamelCaseWord
```
```c#
using Kata;

"hello case".CamelCase(); // => "HelloCase"
"camel case word".CamelCase(); // => "CamelCaseWord"
```

Don't forget to rate this kata! Thanks :)

Answer: {"fn_name": "camel_case", "inputs": [["test case"], ["camel case method"], ["say hello "], [" camel case word"], [""]], "outputs": [["TestCase"], ["CamelCaseMethod"], ["SayHello"], ["CamelCaseWord"], [""]]}
user: # Task
We know that some numbers can be split into two primes. ie. `5 = 2 + 3, 10 = 3 + 7`. But some numbers are not. ie. `17, 27, 35`, etc.. 

Given a positive integer `n`. Determine whether it can be split into two primes. If yes, return the maximum product of two primes. If not, return `0` instead.

# Input/Output

`[input]` integer `n`

A positive integer. 

`0 ≤ n ≤ 100000`

`[output]` an integer

The possible maximum product of two primes. or return `0` if it's impossible split into two primes.

# Example

For `n = 1`, the output should be `0`.

`1` can not split into two primes

For `n = 4`, the output should be `4`.

`4` can split into two primes `2 and 2`. `2 x 2 = 4`

For `n = 20`, the output should be `91`.

`20` can split into two primes `7 and 13` or `3 and 17`. The maximum product is `7 x 13 = 91`

Answer: {"fn_name": "prime_product", "inputs": [[1], [3], [4], [5], [6], [7], [8], [9], [10], [11], [12], [20], [100]], "outputs": [[0], [0], [4], [6], [9], [10], [15], [14], [25], [0], [35], [91], [2491]]}
user: Sort the given strings in alphabetical order, case **insensitive**. For example:
```
["Hello", "there", "I'm", "fine"]  -->  ["fine", "Hello", "I'm", "there"]
["C", "d", "a", "B"])              -->  ["a", "B", "C", "d"]
```

Answer: {"fn_name": "sortme", "inputs": [[["Hello", "there", "I'm", "fine"]], [["C", "d", "a", "B"]], [["CodeWars"]], [[]]], "outputs": [[["fine", "Hello", "I'm", "there"]], [["a", "B", "C", "d"]], [["CodeWars"]], [[]]]}
user: German mathematician Christian Goldbach (1690-1764) [conjectured](https://en.wikipedia.org/wiki/Goldbach%27s_conjecture) that every even number greater than 2 can be represented by the sum of two prime numbers. For example, `10` can be represented as `3+7` or `5+5`.

Your job is to make the function return a list containing all unique possible representations of `n` in an increasing order if `n` is an even integer; if `n` is odd, return an empty list. Hence, the first addend must always be less than or equal to the second to avoid duplicates.

Constraints : `2 < n < 32000` and `n` is even


## Examples
```
26  -->  ['3+23', '7+19', '13+13']

100 -->  ['3+97', '11+89', '17+83', '29+71', '41+59', '47+53']

7   -->  [] 
```

Answer: {"fn_name": "goldbach_partitions", "inputs": [[15], [393], [31133], [4], [100], [594], [1500]], "outputs": [[[]], [[]], [[]], [["2+2"]], [["3+97", "11+89", "17+83", "29+71", "41+59", "47+53"]], [["7+587", "17+577", "23+571", "31+563", "37+557", "47+547", "53+541", "71+523", "73+521", "103+491", "107+487", "127+467", "131+463", "137+457", "151+443", "163+431", "173+421", "193+401", "197+397", "211+383", "227+367", "241+353", "257+337", "263+331", "277+317", "281+313", "283+311"]], [["7+1493", "11+1489", "13+1487", "17+1483", "19+1481", "29+1471", "41+1459", "47+1453", "53+1447", "61+1439", "67+1433", "71+1429", "73+1427", "101+1399", "127+1373", "139+1361", "173+1327", "179+1321", "181+1319", "193+1307", "197+1303", "199+1301", "211+1289", "223+1277", "241+1259", "251+1249", "263+1237", "269+1231", "271+1229", "277+1223", "283+1217", "307+1193", "313+1187", "337+1163", "347+1153", "349+1151", "383+1117", "397+1103", "409+1091", "431+1069", "439+1061", "449+1051", "461+1039", "467+1033", "479+1021", "487+1013", "491+1009", "503+997", "509+991", "523+977", "547+953", "563+937", "571+929", "593+907", "613+887", "617+883", "619+881", "641+859", "643+857", "647+853", "661+839", "673+827", "677+823", "691+809", "727+773", "739+761", "743+757"]]]}
user: Given an array of numbers, return an array, with each member of input array rounded to a nearest number, divisible by 5.

For example:
```
roundToFive([34.5, 56.2, 11, 13]);
```
should return
```
[35, 55, 10, 15]
```

```if:python
Roundings have to be done like "in real life": `22.5 -> 25`
```

Answer: {"fn_name": "round_to_five", "inputs": [[[1, 5, 87, 45, 8, 8]], [[3, 56.2, 11, 13]], [[22.5, 544.9, 77.5]]], "outputs": [[[0, 5, 85, 45, 10, 10]], [[5, 55, 10, 15]], [[25, 545, 80]]]}