meetforever/GRPO_CL huggingface dataset:
user: In this Kata, you will be given a mathematical string and your task will be to remove all braces as follows:

```Haskell
solve("x-(y+z)") = "x-y-z"
solve("x-(y-z)") = "x-y+z"
solve("u-(v-w-(x+y))-z") = "u-v+w+x+y-z"
solve("x-(-y-z)") = "x+y+z"
```

There are no spaces in the expression. Only two operators are given: `"+" or "-"`. 

More examples in test cases. 

Good luck!

Answer: {"fn_name": "solve", "inputs": [["a-(b)"], ["a-(-b)"], ["a+(b)"], ["a+(-b)"], ["(((((((((-((-(((n))))))))))))))"], ["(((a-((((-(-(f)))))))))"], ["((((-(-(-(-(m-g))))))))"], ["(((((((m-(-(((((t)))))))))))))"], ["-x"], ["-(-(x))"], ["-((-x))"], ["-(-(-x))"], ["-(-(x-y))"], ["-(x-y)"], ["x-(y+z)"], ["x-(y-z)"], ["x-(-y-z)"], ["x-(-((-((((-((-(-(-y)))))))))))"], ["u-(v-w+(x+y))-z"], ["x-(s-(y-z))-(a+b)"], ["u+(g+v)+(r+t)"], ["q+(s-(x-o))-(t-(w-a))"], ["u-(v-w-(x+y))-z"], ["v-(l+s)-(t+y)-(c+f)+(b-(n-p))"]], "outputs": [["a-b"], ["a+b"], ["a+b"], ["a-b"], ["n"], ["a-f"], ["m-g"], ["m+t"], ["-x"], ["x"], ["x"], ["-x"], ["x-y"], ["-x+y"], ["x-y-z"], ["x-y+z"], ["x+y+z"], ["x-y"], ["u-v+w-x-y-z"], ["x-s+y-z-a-b"], ["u+g+v+r+t"], ["q+s-x+o-t+w-a"], ["u-v+w+x+y-z"], ["v-l-s-t-y-c-f+b-n+p"]]}
user: Bob needs a fast way to calculate the volume of a cuboid with three values: `length`, `width` and the `height` of the cuboid. Write a function to help Bob with this calculation.

```if:shell
In bash the script is ran with the following 3 arguments:
`length` `width` `height`
```

Answer: {"fn_name": "getVolumeOfCubiod", "inputs": [[2, 5, 6], [6.3, 3, 5]], "outputs": [[60], [94.5]]}
user: You need to play around with the provided string (s).

Move consonants forward 9 places through the alphabet.
If they pass 'z', start again at 'a'.

Move vowels back 5 places through the alphabet.
If they pass 'a', start again at 'z'.
For our Polish friends this kata does not count 'y' as a vowel.

Exceptions:

If the character is 'c' or 'o', move it back 1 place.
For 'd' move it back 3, and for 'e', move it back 4.

If a moved letter becomes 'c', 'o', 'd' or 'e', revert it back to it's original value.

Provided string will always be lower case, won't be empty and will have no special characters.

Answer: {"fn_name": "vowel_back", "inputs": [["testcase"], ["codewars"], ["exampletesthere"], ["returnofthespacecamel"], ["bringonthebootcamp"], ["weneedanofficedog"]], "outputs": [["tabtbvba"], ["bnaafvab"], ["agvvyuatabtqaaa"], ["aatpawnftqabyvbabvvau"], ["kaiwpnwtqaknntbvvy"], ["fawaaavwnffibaanp"]]}
user: Your start-up's BA has told marketing that your website has a large audience in Scandinavia and surrounding countries. Marketing thinks it would be great to welcome visitors to the site in their own language. Luckily you already use an API that detects the user's location, so this is an easy win. 

### The Task
- Think of a way to store the languages as a database (eg an object). The languages are listed below so you can copy and paste!
- Write a 'welcome' function that takes a parameter 'language' (always a string), and returns a greeting - if you have it in your database. It should default to English if the language is not in the database, or in the event of an invalid input.

### The Database

```python
'english': 'Welcome',
'czech': 'Vitejte',
'danish': 'Velkomst',
'dutch': 'Welkom',
'estonian': 'Tere tulemast',
'finnish': 'Tervetuloa',
'flemish': 'Welgekomen',
'french': 'Bienvenue',
'german': 'Willkommen',
'irish': 'Failte',
'italian': 'Benvenuto',
'latvian': 'Gaidits',
'lithuanian': 'Laukiamas',
'polish': 'Witamy',
'spanish': 'Bienvenido',
'swedish': 'Valkommen',
'welsh': 'Croeso'
```
``` java
english: "Welcome",
czech: "Vitejte",
danish: "Velkomst",
dutch: "Welkom",
estonian: "Tere tulemast",
finnish: "Tervetuloa",
flemish: "Welgekomen",
french: "Bienvenue",
german: "Willkommen",
irish: "Failte",
italian: "Benvenuto",
latvian: "Gaidits",
lithuanian: "Laukiamas",
polish: "Witamy",
spanish: "Bienvenido",
swedish: "Valkommen",
welsh: "Croeso"
```

Possible invalid inputs include:
~~~~
IP_ADDRESS_INVALID - not a valid ipv4 or ipv6 ip address
IP_ADDRESS_NOT_FOUND - ip address not in the database
IP_ADDRESS_REQUIRED - no ip address was supplied
~~~~

Answer: {"fn_name": "greet", "inputs": [["english"], ["dutch"], ["IP_ADDRESS_INVALID"], [""], [2]], "outputs": [["Welcome"], ["Welkom"], ["Welcome"], ["Welcome"], ["Welcome"]]}
user: Given a list of integers values, your job is to return the sum of the values; however, if the same integer value appears multiple times in the list, you can only count it once in your sum.

For example:
```python
[ 1, 2, 3] ==> 6

[ 1, 3, 8, 1, 8] ==> 12

[ -1, -1, 5, 2, -7] ==> -1

[] ==> None
```

Good Luck!

Answer: {"fn_name": "unique_sum", "inputs": [[[]], [[0, 1, -1]]], "outputs": [[null], [0]]}
user: Define a function that takes in two non-negative integers `$a$` and `$b$` and returns the last decimal digit of `$a^b$`. Note that `$a$` and `$b$` may be very large!

For example, the last decimal digit of `$9^7$` is `$9$`, since `$9^7 = 4782969$`.  The last decimal digit of `$({2^{200}})^{2^{300}}$`, which has over `$10^{92}$` decimal digits, is `$6$`.  Also, please take `$0^0$` to be `$1$`.

You may assume that the input will always be valid.

## Examples

```python
last_digit(4, 1)                # returns 4
last_digit(4, 2)                # returns 6
last_digit(9, 7)                # returns 9
last_digit(10, 10 ** 10)        # returns 0
last_digit(2 ** 200, 2 ** 300)  # returns 6
```

___

## Remarks

### JavaScript, C++, R, PureScript

Since these languages don't have native arbitrarily large integers, your arguments are going to be strings representing non-negative integers instead.

Answer: {"fn_name": "last_digit", "inputs": [[4, 1], [4, 2], [9, 7], [10, 1000000000], [38710248912497124917933333333284108412048102948908149081409204712406, 226628148126342643123641923461846128214626], [3715290469715693021198967285016729344580685479654510946723, 68819615221552997273737174557165657483427362207517952651]], "outputs": [[4], [6], [9], [0], [6], [7]]}
user: Well, those numbers were right and we're going to feed their ego.

Write a function, isNarcissistic, that takes in any amount of numbers and returns true if all the numbers are narcissistic. Return false for invalid arguments (numbers passed in as strings are ok).

For more information about narcissistic numbers (and believe me, they love it when you read about them) follow this link: https://en.wikipedia.org/wiki/Narcissistic_number

Answer: {"fn_name": "is_narcissistic", "inputs": [[11], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [0, 1, 2, 3, 4, 5, 6, 7, 22, 9], ["4"], ["4", 7, "9"], ["words"], [[1, 2]], [407, 8208], [-1], [""], ["", 407], [407, ""], [5, "", 407], [9474], [{}]], "outputs": [[false], [true], [false], [true], [true], [false], [false], [true], [false], [false], [false], [false], [false], [true], [false]]}
user: An `non decreasing` number is one containing no two consecutive digits (left to right), whose the first is higer than the second. For example, 1235 is an non decreasing number, 1229 is too, but 123429 isn't.

Write a function that finds the number of non decreasing numbers up to `10**N` (exclusive) where N is the input of your function. For example, if `N=3`, you have to count all non decreasing numbers from 0 to 999.

 You'll definitely need something smarter than brute force for large values of N!

Answer: {"fn_name": "increasing_numbers", "inputs": [[0], [1], [2], [3], [4], [5], [6], [10], [20], [50]], "outputs": [[1], [10], [55], [220], [715], [2002], [5005], [92378], [10015005], [12565671261]]}
user: ### Task
 Each day a plant is growing by `upSpeed` meters. Each night that plant's height decreases by `downSpeed` meters due to the lack of sun heat. Initially, plant is 0 meters tall. We plant the seed at the beginning of a day. We want to know when the height of the plant will reach a certain level.

### Example

 For `upSpeed = 100, downSpeed = 10 and desiredHeight = 910`, the output should be `10`.
 
 ```
 After day 1 --> 100
 After night 1 --> 90
 After day 2 --> 190
 After night 2 --> 180
 After day 3 --> 280
 After night 3 --> 270
 After day 4 --> 370
 After night 4 --> 360
 After day 5 --> 460
 After night 5 --> 450
 After day 6 --> 550
 After night 6 --> 540
 After day 7 --> 640
 After night 7 --> 630
 After day 8 --> 730
 After night 8 --> 720
 After day 9 --> 820
 After night 9 --> 810
 After day 10 --> 910 
 ```
 
 For `upSpeed = 10, downSpeed = 9 and desiredHeight = 4`, the output should be `1`.
 
 Because the plant reach to the desired height at day 1(10 meters).
 
 ```
 After day 1 --> 10
 ```

### Input/Output

```if-not:sql
 - `[input]` integer `upSpeed`

    A positive integer representing the daily growth.

    Constraints: `5 ≤ upSpeed ≤ 100.`


 - `[input]` integer `downSpeed`

    A positive integer representing the nightly decline.

    Constraints: `2 ≤ downSpeed < upSpeed.`


 - `[input]` integer `desiredHeight`

    A positive integer representing the threshold.

    Constraints: `4 ≤ desiredHeight ≤ 1000.`

 - `[output]` an integer

    The number of days that it will take for the plant to reach/pass desiredHeight (including the last day in the total count).
```
```if:sql
## Input

~~~
-----------------------------------------
|     Table     |    Column      | Type |
|---------------+----------------+------|
| growing_plant | down_speed     | int  |
|               | up_speed       | int  |
|               | desired_height | int  |
-----------------------------------------
~~~

### Columns
* `up_speed`: A positive integer representing the daily growth. Constraints: `5 ≤ up_speed ≤ 100.`
* `down_speed`: A positive integer representing the nightly decline. Constraints: `2 ≤ down_speed < up_speed.`
* `desired_height`: A positive integer representing the threshold. Constraints: `4 ≤ desired_height ≤ 1000.`

## Output

~~~
-------------------
|  Column  | Type |
|----------+------|
| id       | int  |
| num_days | int  |
-------------------
~~~

`num_days` is the number of days that it will take for the plant to reach/pass desiredHeight (including the last day in the total count).
```

Answer: {"fn_name": "growing_plant", "inputs": [[100, 10, 910], [10, 9, 4], [5, 2, 5], [5, 2, 6]], "outputs": [[10], [1], [1], [2]]}
user: Array inversion indicates how far the array is from being sorted.

Inversions are pairs of elements in array that are out of order.

## Examples

```
[1, 2, 3, 4]  =>  0 inversions
[1, 3, 2, 4]  =>  1 inversion: 2 and 3
[4, 1, 2, 3]  =>  3 inversions: 4 and 1, 4 and 2, 4 and 3
[4, 3, 2, 1]  =>  6 inversions: 4 and 3, 4 and 2, 4 and 1, 3 and 2, 3 and 1, 2 and 1
```

## Goal

The goal is to come up with a function that can calculate inversions for any arbitrary array

Answer: {"fn_name": "count_inversions", "inputs": [[[]], [[1, 2, 3]], [[2, 1, 3]], [[6, 5, 4, 3, 2, 1]], [[6, 5, 4, 3, 3, 3, 3, 2, 1]]], "outputs": [[0], [0], [1], [15], [30]]}
user: In this Kata, you will be given directions and your task will be to find your way back. 
```Perl
solve(["Begin on Road A","Right on Road B","Right on Road C","Left on Road D"]) = ['Begin on Road D', 'Right on Road C', 'Left on Road B', 'Left on Road A']
solve(['Begin on Lua Pkwy', 'Right on Sixth Alley', 'Right on 1st Cr']) =  ['Begin on 1st Cr', 'Left on Sixth Alley', 'Left on Lua Pkwy']
```

More examples in test cases. 

Good luck!

Please also try [Simple remove duplicates](https://www.codewars.com/kata/5ba38ba180824a86850000f7)

Answer: {"fn_name": "solve", "inputs": [[["Begin on 3rd Blvd", "Right on First Road", "Left on 9th Dr"]], [["Begin on Road A", "Right on Road B", "Right on Road C", "Left on Road D"]], [["Begin on Road A"]]], "outputs": [[["Begin on 9th Dr", "Right on First Road", "Left on 3rd Blvd"]], [["Begin on Road D", "Right on Road C", "Left on Road B", "Left on Road A"]], [["Begin on Road A"]]]}
user: ##Task:

You have to write a function **pattern** which creates the following pattern upto n number of rows. *If the Argument is 0 or a Negative Integer then it should return "" i.e. empty string.*
   
##Examples:

pattern(4):

    1234
    234
    34
    4
    
pattern(6):
 
    123456
    23456
    3456
    456
    56
    6



```Note: There are no blank spaces```

```Hint: Use \n in string to jump to next line```

Answer: {"fn_name": "pattern", "inputs": [[1], [2], [5], [0], [-25]], "outputs": [["1"], ["12\n2"], ["12345\n2345\n345\n45\n5"], [""], [""]]}
user: # Task
Consider an array of integers `a`. Let `min(a)` be its minimal element, and let `avg(a)` be its mean.

Define the center of the array `a` as array `b` such that:

```
- b is formed from a by erasing some of its elements.
- For each i, |b[i] - avg(a)| < min(a).
- b has the maximum number of elements among all the arrays
  satisfying the above requirements.
```

Given an array of integers, return its center.



# Input/Output


`[input]` integer array `a`

 Unsorted non-empty array of integers.

`2 ≤ a.length ≤ 50,`

`1 ≤ a[i] ≤ 350.`

`[output]` an integer array


# Example

For `a = [8, 3, 4, 5, 2, 8]`, the output should be `[4, 5]`.

Here `min(a) = 2, avg(a) = 5`.

For `a = [1, 3, 2, 1]`, the output should be `[1, 2, 1]`.

Here `min(a) = 1, avg(a) = 1.75`.

Answer: {"fn_name": "array_center", "inputs": [[[8, 3, 4, 5, 2, 8]], [[1, 3, 2, 1]], [[10, 11, 12, 13, 14]]], "outputs": [[[4, 5]], [[1, 2, 1]], [[10, 11, 12, 13, 14]]]}
user: Given a certain integer ```n```, we need a function ```big_primefac_div()```, that give an array with the highest prime factor and the highest divisor (not equal to n).

Let's see some cases:
```python
big_primefac_div(100) == [5, 50]
big_primefac_div(1969) == [179, 179]
```
If n is a prime number the function will output an empty list:
```python
big_primefac_div(997) == []
```
If ```n``` is an negative integer number, it should be considered the division with tha absolute number of the value.
```python
big_primefac_div(-1800) == [5, 900]
```
If ```n``` is a float type, will be rejected if it has a decimal part with some digits different than 0. The output "The number has a decimal part. No Results". But  ```n ``` will be converted automatically to an integer if all the digits of the decimal part are 0.

```python
big_primefac_div(-1800.00) == [5, 900]
big_primefac_div(-1800.1) == "The number has a decimal part. No Results"
```
Optimization and fast algorithms are a key factor to solve this kata.
Happy coding and enjoy it!

Answer: {"fn_name": "big_primefac_div", "inputs": [[100], [1969], [997], [-1800], [-1800.1]], "outputs": [[[5, 50]], [[179, 179]], [[]], [[5, 900]], ["The number has a decimal part. No Results"]]}
user: Don Drumphet lives in a nice neighborhood, but one of his neighbors has started to let his house go.  Don Drumphet wants to build a wall between his house and his neighbor’s, and is trying to get the neighborhood association to pay for it.  He begins to solicit his neighbors to petition to get the association to build the wall.  Unfortunately for Don Drumphet, he cannot read very well, has a very limited attention span, and can only remember two letters from each of his neighbors’ names.  As he collects signatures, he insists that his neighbors keep truncating their names until two letters remain, and he can finally read them.

Your code will show Full name of the neighbor and the truncated version of the name as an array. If the number of the characters in name is less than or equal to two, it will return an array containing only the name as is"

Answer: {"fn_name": "who_is_paying", "inputs": [["Mexico"], ["Melania"], ["Melissa"], ["Me"], [""], ["I"]], "outputs": [[["Mexico", "Me"]], [["Melania", "Me"]], [["Melissa", "Me"]], [["Me"]], [[""]], [["I"]]]}
user: Following on from [Part 1](http://www.codewars.com/kata/filling-an-array-part-1/), part 2 looks at some more complicated array contents.

So let's try filling an array with...

## ...square numbers
The numbers from `1` to `n*n`

## ...a range of numbers
A range of numbers starting from `start` and increasing by `step`

## ...random numbers
A bunch of random integers between `min` and `max`

## ...prime numbers
All primes starting from `2` (obviously)...

HOTE: All the above functions should take as their first parameter a number that determines the length of the returned array.

Answer: {"fn_name": "squares", "inputs": [[5]], "outputs": [[[1, 4, 9, 16, 25]]]}
user: In this kata you will create a function to check a non-negative input to see if it is a prime number.

The function will take in a number and will return True if it is a prime number and False if it is not.

A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.

### Examples

Answer: {"fn_name": "is_prime", "inputs": [[0], [1], [2], [11], [12], [61], [571], [573], [25]], "outputs": [[false], [false], [true], [true], [false], [true], [true], [false], [false]]}
user: Most of this problem is by the original author of [the harder kata](https://www.codewars.com/kata/556206664efbe6376700005c), I just made it simpler.

I read a book recently, titled "Things to Make and Do in the Fourth Dimension" by comedian and mathematician Matt Parker ( [Youtube](https://www.youtube.com/user/standupmaths) ), and in the first chapter of the book Matt talks about problems he likes to solve in his head to take his mind off the fact that he is in his dentist's chair, we've all been there!

The problem he talks about relates to polydivisible numbers, and I thought a kata should be written on the subject as it's quite interesting. (Well it's interesting to me, so there!)

### Polydivisib... huh what?

So what are they?

A polydivisible number is divisible in an unusual way. The first digit is cleanly divisible by `1`, the first two digits are cleanly divisible by `2`, the first three by `3`, and so on.

### Examples

Let's take the number `1232` as an example.
```
1     / 1 = 1     // Works
12    / 2 = 6     // Works
123   / 3 = 41    // Works
1232  / 4 = 308   // Works
```
`1232` is a polydivisible number.


However, let's take the number `123220` and see what happens.
```
 1      /1 = 1    // Works
 12     /2 = 6    // Works
 123    /3 = 41   // Works
 1232   /4 = 308  // Works
 12322  /5 = 2464.4         // Doesn't work
 123220 /6 = 220536.333...  // Doesn't work
```
`123220` is not polydivisible.

### Your job: check if a number is polydivisible or not.

Return `true` if it is, and `false` if it isn't.

Note: All inputs will be valid numbers between `0` and `2^53-1 (9,007,199,254,740,991)` (inclusive).   
Note: All single digit numbers (including `0`) are trivially polydivisible.
Note: Except for `0`, no numbers will start with `0`.

Answer: {"fn_name": "polydivisible", "inputs": [[1232], [123220], [0], [1], [141], [1234], [21234], [81352], [987654], [1020005], [9876545], [381654729], [1073741823]], "outputs": [[true], [false], [true], [true], [true], [false], [false], [false], [true], [true], [true], [true], [false]]}
user: Your task is to write a function that takes two or more objects and returns a new object which combines all the input objects. 

All input object properties will have only numeric values. Objects are combined together so that the values of matching keys are added together.

An example:

```python
objA = { 'a': 10, 'b': 20, 'c': 30 }
objB = { 'a': 3, 'c': 6, 'd': 3 }
combine(objA, objB) # Returns { a: 13, b: 20, c: 36, d: 3 }
```

The combine function should be a good citizen, so should not mutate the input objects.

Answer: {"fn_name": "combine", "inputs": [[{}, {}, {}], [{}]], "outputs": [[{}], [{}]]}
user: The AKS algorithm for testing whether a number is prime is a polynomial-time test based on the following theorem: 

A number p is prime if and only if all the coefficients of the polynomial expansion of `(x − 1)^p − (x^p − 1)` are divisible by `p`.

For example, trying `p = 3`:

     (x − 1)^3 − (x^3 − 1) = (x^3 − 3x^2 + 3x − 1) − (x^3 − 1) = − 3x^2 + 3x 
    
And all the coefficients are divisible by 3, so 3 is prime.

Your task is to code the test function, wich will be given an integer and should return true or false based on the above theorem. You should efficiently calculate every coefficient one by one and stop when a coefficient is not divisible by p to avoid pointless calculations. The easiest way to calculate coefficients is to take advantage of binomial coefficients: http://en.wikipedia.org/wiki/Binomial_coefficient and pascal triangle: http://en.wikipedia.org/wiki/Pascal%27s_triangle . 

You should also take advantage of the symmetry of binomial coefficients. You can look at these kata: http://www.codewars.com/kata/pascals-triangle and http://www.codewars.com/kata/pascals-triangle-number-2

The kata here only use the simple theorem. The general AKS test is way more complex.  The simple approach is a good exercie but impractical. The general AKS test will be the subject of another kata as it is one of the best performing primality test algorithms.

The main problem of this algorithm is the big numbers emerging from binomial coefficients in the polynomial expansion. As usual Javascript reach its limit on big integer very fast. (This simple algorithm is far less performing than a trivial algorithm here). You can compare the results with those of this kata: http://www.codewars.com/kata/lucas-lehmer-test-for-mersenne-primes Here, javascript can barely treat numbers bigger than 50, python can treat M13 but not M17.

Answer: {"fn_name": "aks_test", "inputs": [[3], [4], [5], [7], [10], [33], [101], [1], [2], [11213], [8191], [8192]], "outputs": [[true], [false], [true], [true], [false], [false], [true], [false], [true], [true], [true], [false]]}
user: #Unflatten a list (Easy)

There are several katas like "Flatten a list".
These katas are done by so many warriors, that the count of available list to flattin goes down!

So you have to build a method, that creates new arrays, that can be flattened!

#Shorter: You have to unflatten a list/an array.

You get an array of integers and have to unflatten it by these rules:
```
- You start at the first number.
- If this number x is smaller than 3, take this number x direct 
  for the new array and continue with the next number.
- If this number x is greater than 2, take the next x numbers (inclusive this number) as a 
  sub-array in the new array. Continue with the next number AFTER this taken numbers.
- If there are too few numbers to take by number, take the last available numbers.
```

The given array will always contain numbers. There will only be numbers > 0.

Example:
```
 [1,4,5,2,1,2,4,5,2,6,2,3,3] -> [1,[4,5,2,1],2,[4,5,2,6],2,[3,3]]

Steps: 
1. The 1 is added directly to the new array.
2. The next number is 4. So the next 4 numbers (4,5,2,1) are added as sub-array in the new array.
3. The 2 is added directly to the new array.
4. The next number is 4. So the next 4 numbers (4,5,2,6) are added as sub-array in the new array.
5. The 2 is added directly to the new array.
6. The next number is 3. So the next 3 numbers would be taken. There are only 2, 
   so take these (3,3) as sub-array in the new array.
```

There is a harder version of this kata!
Unflatten a list (Harder than easy)

Have fun coding it and please don't forget to vote and rank this kata! :-) 

I have created other katas. Have a look if you like coding and challenges.

Answer: {"fn_name": "unflatten", "inputs": [[[3, 5, 2, 1]], [[1, 4, 5, 2, 1, 2, 4, 5, 2, 6, 2, 3, 3]], [[1, 1, 1, 1]], [[1]], [[99, 1, 1, 1]], [[3, 1, 1, 3, 1, 1]]], "outputs": [[[[3, 5, 2], 1]], [[1, [4, 5, 2, 1], 2, [4, 5, 2, 6], 2, [3, 3]]], [[1, 1, 1, 1]], [[1]], [[[99, 1, 1, 1]]], [[[3, 1, 1], [3, 1, 1]]]]}