meetforever/GRPO_CL huggingface dataset:
user: Alex is transitioning from website design to coding and wants to sharpen his skills with CodeWars.  
He can do ten kata in an hour, but when he makes a mistake, he must do pushups. These pushups really tire poor Alex out, so every time he does them they take twice as long. His first set of redemption pushups takes 5 minutes. Create a function, `alexMistakes`, that takes two arguments: the number of kata he needs to complete, and the time in minutes he has to complete them. Your function should return how many mistakes Alex can afford to make.

Answer: {"fn_name": "alex_mistakes", "inputs": [[10, 120], [11, 120], [3, 45], [8, 120], [6, 60], [9, 180], [20, 120], [20, 125], [20, 130], [20, 135]], "outputs": [[3], [3], [2], [3], [2], [4], [0], [1], [1], [2]]}
user: One of the first chain emails I ever received was about a supposed Cambridge  University study that suggests your brain can read words no matter what order the letters are in, as long as the first and last letters of each word are correct.

Your task is to **create a function that can take any string and randomly jumble the letters within each word while leaving the first and last letters of the word in place.**

For example,
    
    mixwords('Winter is coming') // returns 'Wntier is cminog' or 'Wtiner is conimg'
    mixwords('Hey, friends!') // returns 'Hey, fierdns!' or 'Hey, fernids!'

* All punctuation should remain in place
* Words smaller than 3 letters should not change
* Letters must be randomly moved (and so calling the function multiple times with the same string should return different values
* Parameters that are not strings should return undefined

The tests do the following things to ensure a valid string is returned:
    
1. Check that the string returned is not equal to the string passed (you may have to revalidate the solution if your function randomly returns the same string)
2. Check that first and last letters of words remain in place
3. Check that punctuation remains in place
4. Checks string length remains the same
5. Checks the function returns `undefined` for non-strings
6. Checks that word interiors (the letters between the first and last) maintain the same letters, albeit in a different order
7. Checks that letters are randomly assigned.

Answer: {"fn_name": "mix_words", "inputs": [["Hi"], ["Hi!"], ["Hey"], ["Hey?"]], "outputs": [["Hi"], ["Hi!"], ["Hey"], ["Hey?"]]}
user: Your task is to find the first element of an array that is not consecutive.

By not consecutive we mean not exactly 1 larger than the previous element of the array.

E.g. If we have an array `[1,2,3,4,6,7,8]` then `1` then `2` then `3` then `4` are all consecutive but `6` is not, so that's the first non-consecutive number.

```if:c
If a non consecutive number is found then return `true` and set the passed in pointer to the number found.

If the whole array is consecutive then return `false`.
```
```if-not:c
If the whole array is consecutive then return `null`^(2).
```
The array will always have at least `2` elements^(1) and all elements will be numbers. The numbers will also all be unique and in ascending order. The numbers could be positive or negative and the first non-consecutive could be either too!

If you like this Kata, maybe try this one next: https://www.codewars.com/kata/represent-array-of-numbers-as-ranges

```if:c
^(1) Can you write a solution that will return `false` for both `[]` and `[ x ]` (an empty array and one with a single number) though? (This is an empty array and one with a single number and is not tested for, but you can write your own example test. )
```
```if-not:c
^(1) Can you write a solution that will return `null`^(2) for both `[]` and `[ x ]` though?  (This is an empty array and one with a single number and is not tested for, but you can write your own example test. )

^(2)  
Swift, Ruby and Crystal: `nil`  
Haskell: `Nothing`  
Python, Rust: `None`  
Julia: `nothing`  
Nim: `none(int)` (See [options](https://nim-lang.org/docs/options.html))
```

Answer: {"fn_name": "first_non_consecutive", "inputs": [[[1, 2, 3, 4, 6, 7, 8]], [[1, 2, 3, 4, 5, 6, 7, 8]], [[4, 6, 7, 8, 9, 11]], [[4, 5, 6, 7, 8, 9, 11]], [[31, 32]], [[-3, -2, 0, 1]], [[-5, -4, -3, -1]]], "outputs": [[6], [null], [6], [11], [null], [0], [-1]]}
user: Write a function which takes a number and returns the corresponding ASCII char for that value.

Example: 

~~~if-not:java,racket
```
get_char(65) # => 'A'
```
~~~
~~~if:java
~~~
~~~if:racket
~~~

For ASCII table, you can refer to http://www.asciitable.com/

Answer: {"fn_name": "get_char", "inputs": [[65], [33], [34], [35], [36], [37], [38]], "outputs": [["A"], ["!"], ["\""], ["#"], ["$"], ["%"], ["&"]]}
user: The number 45 is the first integer in having this interesting property:
the sum of the number with its reversed is divisible by the difference between them(absolute Value).
```
45 + 54 = 99 
abs(45 - 54) = 9
99 is divisible by 9.
```
The first terms of this special sequence are :
```
n               a(n)
1               45
2               54
3               495
4               594
```
Make the function ```sum_dif_rev()```(`sumDivRef` in JavaScript and CoffeeScript), that receives ```n```, the ordinal number of the term and may give us, the value of the term of the sequence.
```python
sum_dif_rev(n) -----> a(n)
```
Let's see some cases:
```python
sum_dif_rev(1) -----> 45
sum_dif_rev(3) -----> 495
```
"Important: Do not include numbers which, when reversed, have a leading zero, e.g.: 1890 reversed is 0981, so 1890 should not be included."

Your code will be tested up to the first 65 terms, so you should think to optimize it as much as you can.

(Hint: I memoize, you memoize, he memoizes, ......they (of course) memoize)

Happy coding!!

Answer: {"fn_name": "sum_dif_rev", "inputs": [[1], [3], [4], [5], [6]], "outputs": [[45], [495], [594], [4356], [4545]]}
user: Farmer Bob have a big farm, where he growths chickens, rabbits and cows. It is very difficult to count the number of animals for each type manually, so he diceded to buy a system to do it. But he bought a cheap system that can count only total number of heads, total number of legs and total number of horns of animals on the farm.
Help Bob to figure out how many chickens, rabbits and cows does he have?

All chickens have 2 legs, 1 head and no horns; all rabbits have 4 legs, 1 head and no horns; all cows have 4 legs, 1 head and 2 horns.

Your task is to write a function 
```Python
get_animals_count(legs_number, heads_number, horns_number)
```
```Csharp
Dictionary get_animals_count(int legs_number, int heads_number, int horns_number)
```
, which returns a dictionary 
```python
{"rabbits" : rabbits_count, "chickens" : chickens_count, "cows" : cows_count}
``` 
```Csharp
new Dictionary(){{"rabbits", rabbits_count},{"chickens", chickens_count},{"cows", cows_count}}
```

Parameters `legs_number, heads_number, horns_number` are integer, all tests have valid input.

Example:

```python
get_animals_count(34, 11, 6); # Should return {"rabbits" : 3, "chickens" : 5, "cows" : 3}
get_animals_count(154, 42, 10); # Should return {"rabbits" : 30, "chickens" : 7, "cows" : 5}
```

```Csharp
get_animals_count(34, 11, 6); //Should return  Dictionary(){{"rabbits", 3},{"chickens", 5},{"cows", 3}}
get_animals_count(154, 42, 10); //Should return Dictionary(){{"rabbits", 30},{"chickens", 7},{"cows", 5}}
```

Answer: {"fn_name": "get_animals_count", "inputs": [[34, 11, 6], [154, 42, 10], [74, 20, 34], [152, 38, 34], [56, 17, 0]], "outputs": [[{"rabbits": 3, "chickens": 5, "cows": 3}], [{"rabbits": 30, "chickens": 7, "cows": 5}], [{"rabbits": 0, "chickens": 3, "cows": 17}], [{"rabbits": 21, "chickens": 0, "cows": 17}], [{"rabbits": 11, "chickens": 6, "cows": 0}]]}
user: You're continuing to enjoy your new piano, as described in Piano Kata, Part 1. You're also continuing the exercise where you start on the very first (leftmost, lowest in pitch) key on the 88-key keyboard, which (as shown below) is the note A, with the little finger on your left hand, then the second key, which is the black key A# ("A sharp"), with your left ring finger, then the third key, B, with your left middle finger, then the fourth key, C, with your left index finger, and then the fifth key, C#, with your left thumb. Then you play the sixth key, D, with your right thumb, and continue on playing the seventh, eighth, ninth, and tenth keys with the other four fingers of your right hand. Then for the eleventh key you go back to your left little finger, and so on. Once you get to the rightmost/highest, 88th, key, C, you start all over again with your left little finger on the first key. 



(If the Codewars Instructions pane resizes the above piano keyboard image to be too small to read the note labels of the black/sharp keys on your screen, click here to open a copy of the image in a new tab or window.)

This time, in addition to counting each key press out loud (not starting again at 1 after 88, but continuing on to 89 and so forth) to try to keep a steady rhythm going and to see how far you can get before messing up, you're also saying the name of each note. You wonder whether this may help you develop perfect pitch in addition to learning to just *know* which note is which, and -- as in Piano Kata, Part 1 -- helping you to learn to move smoothly and with uniform pressure on the keys from each finger to the next and back and forth between hands.

The function you are going to write will explore one of the patterns you're experiencing in your practice: Given the number you stopped on, which note was it? For example, in the description of your piano exercise above, if you stopped at 5, your left thumb would be on the fifth key of the piano, which is C#. Or if you stopped at 92, you would have gone all the way from keys 1 to 88 and then wrapped around, so that you would be on the fourth key, which is C.

Your function will receive an integer between 1 and 10000 (maybe you think that in principle it would be cool to count up to, say, a billion, but considering how many years it would take it is just not possible) and return one of the strings "A", "A#", "B", "C", "C#", "D", "D#", "E", "F", "F#", "G", or "G#" indicating which note you stopped on -- here are a few more examples:
```
1     "A"
12    "G#"
42    "D"
100   "G#"
2017  "F"
```
Have fun!

Answer: {"fn_name": "which_note", "inputs": [[1], [5], [12], [42], [88], [89], [92], [100], [111], [200], [2017]], "outputs": [["A"], ["C#"], ["G#"], ["D"], ["C"], ["A"], ["C"], ["G#"], ["G"], ["G#"], ["F"]]}
user: # Grasshopper - Function syntax debugging

A student was working on a function and made some syntax mistakes while coding. Help them find their mistakes and fix them.

Answer: {"fn_name": "main", "inputs": [["take ", "item"], ["use ", "sword"]], "outputs": [["take item"], ["use sword"]]}
user: In an infinite array with two rows, the numbers in the top row are denoted

`. . . , A[−2], A[−1], A[0], A[1], A[2], . . .`

and the numbers in the bottom row are denoted

`. . . , B[−2], B[−1], B[0], B[1], B[2], . . .`

For each integer `k`, the entry `A[k]` is directly above
the entry `B[k]` in the array, as shown:


...|A[-2]|A[-1]|A[0]|A[1]|A[2]|...
...|B[-2]|B[-1]|B[0]|B[1]|B[2]|...



For each integer `k`, `A[k]` is the average of the entry to its left, the entry to its right,
and the entry below it; similarly, each entry `B[k]` is the average of the entry to its
left, the entry to its right, and the entry above it.


Given `A[0], A[1], A[2] and A[3]`, determine the value of `A[n]`. (Where range of n is -1000 Inputs and Outputs in BigInt!** 

Adapted from 2018 Euclid Mathematics Contest.
https://www.cemc.uwaterloo.ca/contests/past_contests/2018/2018EuclidContest.pdf

Answer: {"fn_name": "find_a", "inputs": [[[1, 2, 3, 4], 2], [[38, 200, -18, 45], 1], [[1, 0, 0, 1], 5], [[0, 2, 0, 3], -2], [[-20, 1, -3, 14], -5], [[1, 2, 3, 5], 100], [[0, 4, 6, 13], 100]], "outputs": [[3], [200], [20], [-126], [-44402], [60560100487003612846322657690093088848428068520476594299], [335254562473098582210532865941148591672699700764231400858]]}
user: Given an array of integers.

Return an array, where the first element is the count of positives numbers and the second element is sum of negative numbers.

If the input array is empty or null, return an empty array.

# Example

For input `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, -11, -12, -13, -14, -15]`, you should return `[10, -65]`.

Answer: {"fn_name": "count_positives_sum_negatives", "inputs": [[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, -11, -12, -13, -14, -15]], [[0, 2, 3, 0, 5, 6, 7, 8, 9, 10, -11, -12, -13, -14]], [[1]], [[-1]], [[0, 0, 0, 0, 0, 0, 0, 0, 0]], [[]]], "outputs": [[[10, -65]], [[8, -50]], [[1, 0]], [[0, -1]], [[0, 0]], [[]]]}
user: Given two strings, the first being a random string and the second being the same as the first, but with three added characters somewhere in the string (three same characters),

Write a function that returns the added character

### E.g

```
string1 = "hello"
string2 = "aaahello"

// => 'a'
```

The above is just an example; the characters could be anywhere in the string and string2 is actually **shuffled**.

### Another example

```
string1 = "abcde"
string2 = "2db2a2ec"

// => '2'
```

Note that the added character could also exist in the original string


```
string1 = "aabbcc"
string2 = "aacccbbcc"

// => 'c'
```

You can assume that string2 will aways be larger than string1, and there will always be three added characters in string2.

```if:c
Write the function `added_char()` that takes two strings and return the added character as described above.
```

```if:javascript
Write the function `addedChar()` that takes two strings and return the added character as described above.
```

Answer: {"fn_name": "added_char", "inputs": [["hello", "checlclo"], ["aabbcc", "aacccbbcc"], ["abcde", "2db2a2ec"]], "outputs": [["c"], ["c"], ["2"]]}
user: Write a function called that takes a string of parentheses, and determines if the order of the parentheses is valid. The function should return `true` if the string is valid, and `false` if it's invalid.

## Examples

```
"()"              =>  true
")(()))"          =>  false
"("               =>  false
"(())((()())())"  =>  true
```

## Constraints

`0 <= input.length <= 100`

~~~if-not:javascript,go
Along with opening (`(`) and closing (`)`) parenthesis, input may contain any valid ASCII characters.  Furthermore, the input string may be empty and/or not contain any parentheses at all.  Do **not** treat other forms of brackets as parentheses (e.g. `[]`, `{}`, `<>`).
~~~

Answer: {"fn_name": "valid_parentheses", "inputs": [[")"], ["("], [""], ["hi)("], ["hi(hi)"], ["hi(hi)("], ["((())()())"], ["(c(b(a)))(d)"], ["hi(hi))("], ["())(()"]], "outputs": [[false], [false], [true], [false], [true], [false], [true], [true], [false], [false]]}
user: # Task
 Your Informatics teacher at school likes coming up with new ways to help you understand the material. When you started studying numeral systems, he introduced his own numeral system, which he's convinced will help clarify things. His numeral system has base 26, and its digits are represented by English capital letters - `A for 0, B for 1, and so on`.

 The teacher assigned you the following numeral system exercise: given a one-digit `number`, you should find all unordered pairs of one-digit numbers whose values add up to the `number`.

# Example

 For `number = 'G'`, the output should be `["A + G", "B + F", "C + E", "D + D"]`

 Translating this into the decimal numeral system we get: number = 6, so it is `["0 + 6", "1 + 5", "2 + 4", "3 + 3"]`.

# Input/Output

 - `[input]` string(char in C#) `number`

   A character representing a correct one-digit number in the new numeral system.

   Constraints: `'A' ≤ number ≤ 'Z'.`

 - `[output]` a string array

   An array of strings in the format "letter1 + letter2", where "letter1" and "letter2" are correct one-digit numbers in the new numeral system. The strings should be sorted by "letter1".

   Note that "letter1 + letter2" and "letter2 + letter1" are equal pairs and we don't consider them to be different.

Answer: {"fn_name": "new_numeral_system", "inputs": [["G"], ["A"], ["D"], ["E"], ["O"]], "outputs": [[["A + G", "B + F", "C + E", "D + D"]], [["A + A"]], [["A + D", "B + C"]], [["A + E", "B + D", "C + C"]], [["A + O", "B + N", "C + M", "D + L", "E + K", "F + J", "G + I", "H + H"]]]}
user: Your work is to write a method that takes a value and an index, and returns the value with the bit at given index flipped.

The bits are numbered from the least significant bit (index 1).

Example:
```python
flip_bit(15, 4) == 7 # 15 in binary is 1111, after flipping 4th bit, it becomes 0111, i.e. 7
flip_bit(15, 5) == 31 # 15 in binary is 1111, 5th bit is 0, after flipping, it becomes 11111, i.e., 31
```
Note : index number can be out of number's range : e.g number is 3 (it has 2 bits) and index number is 8(for C# this number is up to 31) -> result will be 131 

See more examples in test classes

Good luck!

Answer: {"fn_name": "flip_bit", "inputs": [[0, 16], [2147483647, 31], [127, 8]], "outputs": [[32768], [1073741823], [255]]}
user: Reverse every other word in a given string, then return the string. Throw away any leading or trailing whitespace, while ensuring there is exactly one space between each word. Punctuation marks should be treated as if they are a part of the word in this kata.

Answer: {"fn_name": "reverse_alternate", "inputs": [["Did it work?"], ["I really hope it works this time..."], ["Reverse this string, please!"], ["Have a beer"], ["   "], ["This is not a test "], ["This       is a  test "]], "outputs": [["Did ti work?"], ["I yllaer hope ti works siht time..."], ["Reverse siht string, !esaelp"], ["Have a beer"], [""], ["This si not a test"], ["This si a tset"]]}
user: Write a function that solves an algebraic expression given as a string. 

* The expression can include only sums and products. 

* The numbers in the expression are in standard notation (NOT scientific).

* In contrast, the function should return a string with the calculated value given in scientific notation with 5 decimal digits. 

# Example:
```python
strexpression = "5 * 4 + 6"
sum_prod(strexpression) = "2.60000e+01"
```

Answer: {"fn_name": "sum_prod", "inputs": [["5*4+6"], ["5+4*6"], ["3*8+6*5"], ["5*8+6*3*2"], ["5.4*4.0+6.2+8.0"], ["0.5*1.2*56+9.6*5*81+1"], ["1"], ["1.333333333*1.23456789+0.003*0.002"]], "outputs": [["2.60000e+01"], ["2.90000e+01"], ["5.40000e+01"], ["7.60000e+01"], ["3.58000e+01"], ["3.92260e+03"], ["1.00000e+00"], ["1.64610e+00"]]}
user: For "x", determine how many positive integers less than or equal to "x" are odd but not prime. Assume "x" is an integer between 1 and 10000.

Example: 5 has three odd numbers (1,3,5) and only the number 1 is not prime, so the answer is 1

Example: 10 has five odd numbers (1,3,5,7,9) and only 1 and 9 are not prime, so the answer is 2

Answer: {"fn_name": "odd_not_prime", "inputs": [[5], [10], [99]], "outputs": [[1], [2], [26]]}
user: # Task

**_Given_** an *array/list [] of n integers* , *find maximum triplet sum in the array* **_Without duplications_**   .
___

# Notes :

* **_Array/list_** size is *at least 3* .

* **_Array/list_** numbers could be a *mixture of positives , negatives and zeros* .

* **_Repetition_** of numbers in *the array/list could occur* , So **_(duplications are not included when summing)_**.
___
# Input >> Output Examples 

## **_Explanation_**:

* As the **_triplet_** that *maximize the sum* **_{6,8,3}_** in order , **_their sum is (17)_** 

* *Note* : **_duplications_** *are not included when summing* , **(i.e) the numbers added only once** .
___
## **_Explanation_**:

* As the **_triplet_** that *maximize the sum* **_{8, 6, 4}_** in order , **_their sum is (18)_** , 
* *Note* : **_duplications_** *are not included when summing* , **(i.e) the numbers added only once** .
___
## **_Explanation_**:

* As the **_triplet_** that *maximize the sum* **_{12 , 29 , 0}_** in order , **_their sum is (41)_** , 
* *Note* : **_duplications_** *are not included when summing* , **(i.e) the numbers added only once** .
___
# [Playing with Numbers Series](https://www.codewars.com/collections/playing-with-numbers)

# [Playing With Lists/Arrays Series](https://www.codewars.com/collections/playing-with-lists-slash-arrays)

# [For More Enjoyable Katas](http://www.codewars.com/users/MrZizoScream/authored)
___
___
___

## ALL translations are welcomed

## Enjoy Learning !!
# Zizou

Answer: {"fn_name": "max_tri_sum", "inputs": [[[3, 2, 6, 8, 2, 3]], [[2, 9, 13, 10, 5, 2, 9, 5]], [[2, 1, 8, 0, 6, 4, 8, 6, 2, 4]], [[-3, -27, -4, -2, -27, -2]], [[-14, -12, -7, -42, -809, -14, -12]], [[-13, -50, 57, 13, 67, -13, 57, 108, 67]], [[-7, 12, -7, 29, -5, 0, -7, 0, 0, 29]], [[-2, 0, 2]], [[-2, -4, 0, -9, 2]], [[-5, -1, -9, 0, 2]]], "outputs": [[17], [32], [18], [-9], [-33], [232], [41], [0], [0], [1]]}
user: We have the first value of a certain sequence, we will name it ```initVal```.
We define  pattern list, ```patternL```, an array that has the differences between contiguous terms of the sequence.
``` E.g: patternL = [k1, k2, k3, k4]``` 

The terms of the sequence will be such values that:
```python
term1 = initVal
term2 - term1 = k1
term3 - term2 = k2
term4 - term3 = k3
term5 - term4 = k4
term6 - term5 = k1
term7 - term6 = k2
term8 - term7 = k3
term9 - term8 = k4
....  - ..... = ...
....  - ..... = ...
 ``` 
So the values of the differences between contiguous terms are cyclical and are  repeated as the differences values of the pattern list stablishes.

Let's see an example with numbers:
```python
initVal = 10
patternL = [2, 1, 3]
term1 = 10
term2 = 12
term3 = 13
term4 = 16
term5 = 18
term6 = 19
term7 = 22  # and so on...
```
We can easily obtain the next terms of the sequence following the values in the pattern list.
We see that the sixth term of the sequence, ```19```, has the sum of its digits ```10```.

Make a function ```sumDig_nthTerm()```, that receives three arguments in this order 

 ```sumDig_nthTerm(initVal, patternL, nthTerm(ordinal number of the term in the sequence)) ```

This function will output the sum of the digits of the n-th term of the sequence.

Let's see some cases for this function:
```python
sumDig_nthTerm(10, [2, 1, 3], 6) -----> 10 # because the sixth term is 19 sum of Dig = 1 + 9 = 10. The sequence up to the sixth-Term is: 10, 12, 13, 16, 18, 19

sumDig_nthTerm(10, [1, 2, 3], 15) ----> 10 # 37 is the 15-th term, and 3 + 7 = 10
```
Enjoy it and happy coding!!

Answer: {"fn_name": "sumDig_nthTerm", "inputs": [[10, [2, 1, 3], 6], [10, [2, 1, 3], 15], [10, [2, 1, 3], 50], [10, [2, 1, 3], 78], [10, [2, 1, 3], 157], [10, [2, 2, 5, 8], 6], [10, [2, 2, 5, 8], 15], [10, [2, 2, 5, 8], 50], [10, [2, 2, 5, 8], 78], [10, [2, 2, 5, 8], 157], [100, [2, 2, 5, 8], 6], [100, [2, 2, 5, 8], 15], [100, [2, 2, 5, 8], 50], [100, [2, 2, 5, 8], 78], [100, [2, 2, 5, 8], 157], [1000, [2, 2, 5, 8], 2550], [1000, [2, 2, 5, 8], 25500]], "outputs": [[10], [10], [9], [10], [7], [11], [11], [9], [11], [16], [11], [11], [9], [11], [16], [14], [26]]}