meetforever/GRPO_CL huggingface dataset:
user: The number `1035` is the smallest integer that exhibits a non frequent property: one its multiples, `3105 = 1035 * 3`, has its same digits but in different order, in other words, `3105`, is one of the permutations of `1035`.

The number `125874` is the first integer that has this property when the multiplier is `2`, thus: `125874 * 2 = 251748`

Make the function `search_permMult()`, that receives an upper bound, nMax and a factor k and will output the amount of pairs bellow nMax that are permuted when an integer of this range is multiplied by `k`. The pair will be counted if the multiple is less than `nMax`, too

Let'see some cases:
```python
search_permMult(10000, 7) === 1 # because we have the pair 1359, 9513
search_permMult(5000, 7) === 0 # no pairs found, as 9513 > 5000

search_permMult(10000, 4) === 2 # we have two pairs (1782, 7128) and (2178, 8712)
search_permMult(8000, 4) === 1 # only the pair (1782, 7128) 

search_permMult(5000, 3) === 1 # only the pair (1035, 3105)
search_permMult(10000, 3) === 2 # found pairs (1035, 3105) and (2475, 7425)
```
Features of the random Tests:
```
10000 <= nMax <= 100000
3 <= k <= 7
```
Enjoy it and happy coding!!

Answer: {"fn_name": "search_permMult", "inputs": [[10000, 7], [5000, 7], [10000, 4], [8000, 4], [5000, 3], [10000, 3]], "outputs": [[1], [0], [2], [1], [1], [2]]}
user: Your users passwords were all stole in the Yahoo! hack, and it turns out they have been lax in creating secure passwords.  Create a function that checks their new password (passed as a string) to make sure it meets the following requirements:


Between 8 - 20 characters

Contains only the following characters: (and at least one character from each category): uppercase letters, lowercase letters, digits, and the special characters !@#$%^&*?




Return "valid" if passed or else "not valid"

Answer: {"fn_name": "check_password", "inputs": [[""], ["password"], ["P1@p"], ["P1@pP1@p"], ["P1@pP1@pP1@pP1@pP1@pP1@p"]], "outputs": [["not valid"], ["not valid"], ["not valid"], ["valid"], ["not valid"]]}
user: ```if-not:ruby
Create a function, that accepts an arbitrary number of arrays and returns a single array generated by alternately appending elements from the passed in arguments. If one of them is shorter than the others, the result should be padded with empty elements.
```
```if:ruby
Create a function, that accepts an arbitrary number of arrays and returns a single array generated by alternately appending elements from the passed in arguments. If one of them is shorter than the others, the result should be padded with `nil`s.
```

Examples:

```python
interleave([1, 2, 3], ["c", "d", "e"]) == [1, "c", 2, "d", 3, "e"]
interleave([1, 2, 3], [4, 5]) == [1, 4, 2, 5, 3, None]
interleave([1, 2, 3], [4, 5, 6], [7, 8, 9]) == [1, 4, 7, 2, 5, 8, 3, 6, 9]
interleave([]) == []
```

Answer: {"fn_name": "interleave", "inputs": [[[1, 2, 3], ["c", "d", "e"]], [[1, 2, 3], [4, 5]], [[1, 2], [3, 4, 5]], [[null], [null, null], [null, null, null]], [[1, 2, 3], [4, 5, 6], [7, 8, 9]], [[]]], "outputs": [[[1, "c", 2, "d", 3, "e"]], [[1, 4, 2, 5, 3, null]], [[1, 3, 2, 4, null, 5]], [[null, null, null, null, null, null, null, null, null]], [[1, 4, 7, 2, 5, 8, 3, 6, 9]], [[]]]}
user: How many licks does it take to get to the tootsie roll center of a tootsie pop?

A group of engineering students from Purdue University reported that its licking machine, modeled after a human tongue, took an average of 364 licks to get to the center of a Tootsie Pop. Twenty of the group's volunteers assumed the licking challenge-unassisted by machinery-and averaged 252 licks each to the center.

Your task, if you choose to accept it, is to write a function that will return the number of licks it took to get to the tootsie roll center of a tootsie pop, given some environmental variables.

Everyone knows it's harder to lick a tootsie pop in cold weather but it's easier if the sun is out. You will be given an object of environmental conditions for each trial paired with a value that will increase or decrease the number of licks. The environmental conditions all apply to the same trial.

Assuming that it would normally take 252 licks to get to the tootsie roll center of a tootsie pop, return the new total of licks along with the condition that proved to be most challenging (causing the most added licks) in that trial.

Example:
```
totalLicks({ "freezing temps": 10, "clear skies": -2 });
```
Should return:
```
"It took 260 licks to get to the tootsie roll center of a tootsie pop. The toughest challenge was freezing temps."
```
Other cases:
If there are no challenges, the toughest challenge sentence should be omitted. If there are multiple challenges with the highest toughest amount, the first one presented will be the toughest.
If an environment variable is present, it will be either a positive or negative integer. No need to validate.


Check out my other 80's Kids Katas:


80's Kids #1: How Many Licks Does It Take
80's Kids #2: Help Alf Find His Spaceship
80's Kids #3: Punky Brewster's Socks
80's Kids #4: Legends of the Hidden Temple
80's Kids #5: You Can't Do That on Television
80's Kids #6: Rock 'Em, Sock 'Em Robots
80's Kids #7: She's a Small Wonder
80's Kids #8: The Secret World of Alex Mack
80's Kids #9: Down in Fraggle Rock 
80's Kids #10: Captain Planet

Answer: {"fn_name": "total_licks", "inputs": [[{"freezing temps": 10, "clear skies": -2}], [{"happiness": -5, "clear skies": -2}], [{}], [{"dragons": 100, "evil wizards": 110, "trolls": 50}], [{"white magic": -250}]], "outputs": [["It took 260 licks to get to the tootsie roll center of a tootsie pop. The toughest challenge was freezing temps."], ["It took 245 licks to get to the tootsie roll center of a tootsie pop."], ["It took 252 licks to get to the tootsie roll center of a tootsie pop."], ["It took 512 licks to get to the tootsie roll center of a tootsie pop. The toughest challenge was evil wizards."], ["It took 2 licks to get to the tootsie roll center of a tootsie pop."]]}
user: Find the length between 2 co-ordinates.  The co-ordinates are made of integers between -20 and 20 and will be given in the form of a 2D array:

(0,0) and (5,-7) would be [ [ 0 , 0 ] , [ 5, -7 ] ]

The function must return the answer rounded to 2 decimal places in the form of a string.

```python
length_of_line([[0, 0], [5, -7]]) => "8.60"
```

If the 2 given co-ordinates are the same, the returned length should be "0.00"

Answer: {"fn_name": "length_of_line", "inputs": [[[[0, 0], [1, 1]]], [[[0, 0], [-5, -6]]], [[[0, 0], [10, 15]]], [[[0, 0], [5, 1]]], [[[0, 0], [5, 4]]], [[[0, 0], [-7, 4]]], [[[0, 0], [0, 0]]], [[[-3, 4], [10, 5]]]], "outputs": [["1.41"], ["7.81"], ["18.03"], ["5.10"], ["6.40"], ["8.06"], ["0.00"], ["13.04"]]}
user: You are working at a lower league football stadium and you've been tasked with automating the scoreboard.

The referee will shout out the score, you have already set up the voice recognition module which turns the ref's voice into a string, but the spoken score needs to be converted into a pair for the scoreboard!

e.g. `"The score is four nil"` should return `[4,0]`

Either teams score has a range of 0-9, and the ref won't say the same string every time e.g. 
      
    "new score: two three"
      
    "two two"
      
    "Arsenal just conceded another goal, two nil"
    
Note:
```python
Please return an array
```

Please rate and enjoy!

Answer: {"fn_name": "scoreboard", "inputs": [["The score is four nil"], ["new score: two three"], ["two two"], ["Arsenal just conceded another goal, two nil"]], "outputs": [[[4, 0]], [[2, 3]], [[2, 2]], [[2, 0]]]}
user: In mathematics, a [Diophantine equation](https://en.wikipedia.org/wiki/Diophantine_equation) is a polynomial equation, usually with two or more unknowns, such that only the integer solutions are sought or studied.

In this kata we want to find all integers `x, y` (`x >= 0, y >= 0`) solutions of a diophantine equation of the form:
#### x^(2) - 4 \* y^(2) = n

(where the unknowns are `x` and `y`, and `n` is a given positive number)
in decreasing order of the positive xi. 

If there is no solution return `[]` or `"[]" or ""`. (See "RUN SAMPLE TESTS" for examples of returns).


## Examples:

```
solEquaStr(90005) --> "[[45003, 22501], [9003, 4499], [981, 467], [309, 37]]"
solEquaStr(90002) --> "[]"
```

## Hint:

x^(2) - 4 \* y^(2) = (x - 2\*y) \* (x + 2\*y)

Answer: {"fn_name": "sol_equa", "inputs": [[5], [12], [13], [16], [17], [20], [9001], [9004], [9005], [9008], [90001], [90002], [90004], [90005], [90009], [900001], [900004], [900005], [9000001], [9000004], [90000001], [90000004], [900000012], [9000000041]], "outputs": [[[[3, 1]]], [[[4, 1]]], [[[7, 3]]], [[[4, 0]]], [[[9, 4]]], [[[6, 2]]], [[[4501, 2250]]], [[[2252, 1125]]], [[[4503, 2251], [903, 449]]], [[[1128, 562]]], [[[45001, 22500]]], [[]], [[[22502, 11250]]], [[[45003, 22501], [9003, 4499], [981, 467], [309, 37]]], [[[45005, 22502], [15003, 7500], [5005, 2498], [653, 290], [397, 130], [315, 48]]], [[[450001, 225000]]], [[[225002, 112500], [32150, 16068]]], [[[450003, 225001], [90003, 44999]]], [[[4500001, 2250000], [73801, 36870]]], [[[2250002, 1125000], [173090, 86532], [132370, 66168], [10402, 4980]]], [[[45000001, 22500000], [6428575, 3214284], [3461545, 1730766], [494551, 247230]]], [[[22500002, 11250000], [252898, 126360], [93602, 46560], [22498, 10200]]], [[[225000004, 112500001], [75000004, 37499999], [3358276, 1679071], [1119604, 559601]]], [[[4500000021, 2250000010], [155172429, 77586200]]]]}
user: We are interested in collecting the triples of positive integers ```(a, b, c)``` that fulfill the following equation:
```python
a² + b² = c³
```
The first triple with the lowest values that satisfies the equation we have above is (2, 2 ,2).
In effect:
```python
2² + 2² = 2³
4  + 4  = 8
```
The first pair of triples that "shares" the same value of ```c``` is: ```(2, 11, 5)``` and ```(5, 10, 5)```. 

Both triples share the same value of ```c```  is ```c = 5```. 
```python
Triple (2, 11, 5)                  Triple(5, 10, 5)
2² + 11² =  5³                      5² +  10²  =  5³
4  + 121 = 125                     25  + 100   = 125
```
So, we say that the value ```c``` has two solutions because there are two triples sharing the same value of ```c```.

There are some values of ```c``` with no solutions.

The first value of ```c``` that have a surprising number of solutions is ```65``` with ```8``` different triples.

In order to avoid duplications you will consider that ```a <= b``` always.

Make the function ```find_abc_sumsqcube()```, that may give us the values of c for an specific number of solutions.

For that purpose the above required function will receive two arguments, ```c_max``` and ```num_sol```. It is understandable that ```c_max``` will give to our function the upper limit of ```c``` and ```num_sol```, the specific number of solutions.

The function will output a sorted list with the values of ```c``` that have a number of solutions equals to ```num_sol```

Let's see some cases: 
```python
find_abc_sumsqcube(5, 1) == [2] # below or equal to c_max = 5 we have triple the (2, 2, 2) (see above)

find_abc_sumsqcube(5, 2) == [5] # now we want the values of ```c ≤ c_max``` with two solutions (see above again)

find_abc_sumsqcube(10, 2) == [5, 10]

find_abc_sumsqcube(20, 8) == [] # There are no values of c equal and bellow 20 having 8 solutions.
```

Our tests will have the following ranges for our two arguments:
```python
5 ≤ c_max ≤ 1000
1 ≤ num_sol ≤ 10
```
Happy coding!!

Answer: {"fn_name": "find_abc_sumsqcube", "inputs": [[5, 1], [5, 2], [10, 2], [20, 8], [100, 8], [100, 3], [100, 2]], "outputs": [[[2]], [[5]], [[5, 10]], [[]], [[65, 85]], [[25, 100]], [[5, 10, 13, 17, 20, 26, 29, 34, 37, 40, 41, 45, 52, 53, 58, 61, 68, 73, 74, 80, 82, 89, 90, 97]]]}
user: The number `198` has the property that `198 = 11 + 99 + 88, i.e., if each of its digits is concatenated twice and then summed, the result will be the original number`. It turns out that `198` is the only number with this property. However, the property can be generalized so that each digit is concatenated `n` times and then summed. 

eg:-
```
original number =2997 , n=3
2997 = 222+999+999+777 and here each digit is concatenated three times.

original number=-2997 , n=3

-2997 = -222-999-999-777 and here each digit is concatenated three times.


```
Write afunction named `check_concatenated_sum` that tests if a number has this generalized property.

Answer: {"fn_name": "check_concatenated_sum", "inputs": [[2997, 3], [-198, 2], [-13332, 4], [-9, 1], [198, 0], [123, 2], [123456789, 2]], "outputs": [[true], [true], [true], [true], [false], [false], [false]]}
user: DNA sequencing data can be stored in many different formats. In this Kata, we will be looking at SAM formatting. It is a plain text file where every line (excluding the first header lines) contains data about a "read" from whatever sample the file comes from. Rather than focusing on the whole read, we will take two pieces of information: the cigar string and the nucleotide sequence.

The cigar string is composed of numbers and flags. It represents how the read aligns to what is known as a reference genome. A reference genome is an accepted standard for mapping the DNA. 

The nucleotide sequence shows us what bases actually make up that section of DNA. They can be represented with the letters A, T, C, or G.

Example Read: ('36M', 'ACTCTTCTTGCGAAAGTTCGGTTAGTAAAGGGGATG')

The M in the above cigar string stands for "match", and the 36 stands for the length of the nucleotide sequence. Since all 36 bases are given the 'M' distinction, we know they all matched the reference.

Example Read: ('20M10S',  'ACTCTTCTTGCGAAAGTTCGGTTAGTAAAG')

In the above cigar string, only 20 have the "M" distinction, but the length of the actual string of nucleotides is 30. Therefore we know that read did not match the reference. (Don't worry about what the other letters mean. That will be covered in a later kata.)

Your job for this kata is to create a function that determines whether a cigar string fully matches the reference and accounts for all bases. If it does fully match, return True. If the numbers in the string do not match the full length of the string, return 'Invalid cigar'. If it does not fully match, return False.

*Note for C++: Return True, False, or Invalid cigar as strings*

Answer: {"fn_name": "is_matched", "inputs": [[["36M", "CATAATACTTTACCTACTCTCAACAAATGCGGGAGA"]], [["10M6H", "GAGCGAGTGCGCCTTAC"]], [["12S", "TGTTTCTCCAAG"]]], "outputs": [[true], ["Invalid cigar"], [false]]}
user: Consider a sequence generation that follows the following steps. We will store removed values in variable `res`. Assume `n = 25`:
```Haskell
-> [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25] Let's remove the first number => res = [1]. We get..
-> [2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25]. Let's remove 2 (so res = [1,2]) and every 2-indexed number. We get..
-> [3,5,7,9,11,13,15,17,19,21,23,25]. Now remove 3, then every 3-indexed number. res = [1,2,3]. 
-> [5,7,11,13,17,19,23,25]. Now remove 5, and every 5-indexed number. res = [1,2,3,5]. We get..
-> [7,11,13,17,23,25]. Now remove 7 and every 7-indexed. res = [1,2,3,5,7].  
But we know that there are no other 7-indexed elements, so we include all remaining numbers in res. So res = [1,2,3,5,7,11,13,17,23,25] and sum(res) = 107.

Note that when we remove every n-indexed number, we must remember that indices start at 0. So for every 3-indexed number above:
[3,5,7,9,11,13,15,17,19,21,23], we remove index0=3, index3= 9, index6=15,index9=21, etc.

Note also that if the length of sequence is greater than x, where x is the first element of the sequence, you should continue the remove step: remove x, and every x-indexed number until the length of sequence is shorter than x. In our example above, we stopped at 7 because the the length of the remaining sequence [7,11,13,17,23,25] is shorter than 7.
```
You will be given a number `n` and your task will be to return the sum of the elements in res, where the maximum element in res is `<= n`. 

For example:

```Python
Solve(7) = 18, because this is the sum of res = [1,2,3,5,7].
Solve(25) = 107
```

More examples in the test cases. 

Good luck!

Answer: {"fn_name": "solve", "inputs": [[7], [25], [50], [100], [1000], [10000]], "outputs": [[18], [107], [304], [993], [63589], [4721110]]}
user: # Task
 Consider the following ciphering algorithm:
```
For each character replace it with its code.
Concatenate all of the obtained numbers.
```
Given a ciphered string, return the initial one if it is known that it consists only of lowercase letters.

 Note: here the character's code means its `decimal ASCII code`, the numerical representation of a character used by most modern programming languages.

# Example

 For `cipher = "10197115121"`, the output should be `"easy"`.

 Explanation: 
 ```
 charCode('e') = 101, 
 charCode('a') = 97, 
 charCode('s') = 115 
 charCode('y') = 121.
```
# Input/Output


 - `[input]` string `cipher`

   A non-empty string which is guaranteed to be a cipher for some other string of lowercase letters.


 - `[output]` a string

Answer: {"fn_name": "decipher", "inputs": [["10197115121"], ["98"], ["122"]], "outputs": [["easy"], ["b"], ["z"]]}
user: One suggestion to build a satisfactory password is to start with a memorable phrase or sentence and make a password by extracting the first letter of each word. 

Even better is to replace some of those letters with numbers (e.g., the letter `O` can be replaced with the number `0`):

* instead of including `i` or `I` put the number `1` in the password;
* instead of including `o` or `O` put the number `0` in the password;
* instead of including `s` or `S` put the number `5` in the password.


## Examples:
```
"Give me liberty or give me death"  --> "Gml0gmd"
"Keep Calm and Carry On"            --> "KCaC0"
```

Answer: {"fn_name": "make_password", "inputs": [["Give me liberty or give me death"], ["Keep Calm and Carry On"]], "outputs": [["Gml0gmd"], ["KCaC0"]]}
user: Hofstadter sequences are a family of related integer sequences, among which the first ones were described by an American professor Douglas Hofstadter in his book Gödel, Escher, Bach. 

### Task
Today we will be implementing the rather chaotic recursive sequence of integers called Hofstadter Q.
The Hofstadter Q is defined as:

As the author states in the aforementioned book:It is reminiscent of the Fibonacci definition in that each new value is a sum of two
previous values-but not of the immediately previous two values. Instead, the two
immediately previous values tell how far to count back to obtain the numbers to be added
to make the new value.
The function produces the starting sequence:  
`1, 1, 2, 3, 3, 4, 5, 5, 6 . . .`  
Test info: 100 random tests, n is always positive
Good luck!

Answer: {"fn_name": "hofstadter_Q", "inputs": [[1], [3], [7], [10], [100], [1000]], "outputs": [[1], [2], [5], [6], [56], [502]]}
user: Mr. Scrooge has a sum of money 'P' that he wants to invest. Before he does, he wants to know how many years 'Y' this sum 'P' has to be kept in the bank in order for it to amount to a desired sum of money 'D'.

The sum is kept for 'Y' years in the bank where interest 'I' is paid yearly. After paying taxes 'T' for the year the new sum is re-invested.

Note to Tax: not the invested principal is taxed, but only the year's accrued interest

Example:

      Let P be the Principal = 1000.00      
      Let I be the Interest Rate = 0.05      
      Let T be the Tax Rate = 0.18      
      Let D be the Desired Sum = 1100.00


    After 1st Year -->
      P = 1041.00
    After 2nd Year -->
      P = 1083.86
    After 3rd Year -->
      P = 1128.30
  
Thus Mr. Scrooge has to wait for 3 years for the initial principal to amount to the desired sum.
 
Your task is to complete the method provided and return the number of years 'Y' as a whole in order for Mr. Scrooge to get the desired sum.  

Assumption: Assume that Desired Principal 'D' is always greater than the initial principal. However it is best to take into consideration that if Desired Principal 'D' is equal to Principal 'P' this should return 0 Years.

Answer: {"fn_name": "calculate_years", "inputs": [[1000, 0.05, 0.18, 1100], [1000, 0.01625, 0.18, 1200], [1000, 0.05, 0.18, 1000]], "outputs": [[3], [14], [0]]}
user: You probably know the "like" system from Facebook and other pages. People can "like" blog posts, pictures or other items. We want to create the text that should be displayed next to such an item.

Implement a function `likes :: [String] -> String`, which must take in input array, containing the names of people who like an item. It must return the display text as shown in the examples:

```python
likes([]) # must be "no one likes this"
likes(["Peter"]) # must be "Peter likes this"
likes(["Jacob", "Alex"]) # must be "Jacob and Alex like this"
likes(["Max", "John", "Mark"]) # must be "Max, John and Mark like this"
likes(["Alex", "Jacob", "Mark", "Max"]) # must be "Alex, Jacob and 2 others like this"
```

For 4 or more names, the number in `and 2 others` simply increases.

Answer: {"fn_name": "likes", "inputs": [[[]], [["Peter"]], [["Jacob", "Alex"]], [["Max", "John", "Mark"]], [["Alex", "Jacob", "Mark", "Max"]]], "outputs": [["no one likes this"], ["Peter likes this"], ["Jacob and Alex like this"], ["Max, John and Mark like this"], ["Alex, Jacob and 2 others like this"]]}
user: Your task is to convert a given number into a string with commas added for easier readability.  The number should be rounded to 3 decimal places and the commas should be added at intervals of three digits before the decimal point. There does not need to be a comma at the end of the number.

You will receive both positive and negative numbers.

## Examples

```python
commas(1) == "1"
commas(1000) == "1,000"
commas(100.2346) == "100.235"
commas(1000000000.23) == "1,000,000,000.23"
commas(-1) == "-1"
commas(-1000000.123) == "-1,000,000.123"
```

Answer: {"fn_name": "commas", "inputs": [[1], [1000], [100.2346], [1000000000.23], [9123.212], [-1], [-1000000.123], [-2000.0], [-999.9999], [-1234567.0001236]], "outputs": [["1"], ["1,000"], ["100.235"], ["1,000,000,000.23"], ["9,123.212"], ["-1"], ["-1,000,000.123"], ["-2,000"], ["-1,000"], ["-1,234,567"]]}
user: Consider the following expansion:
```Haskell
solve("3(ab)") = "ababab" -- "ab" repeats 3 times
solve("2(a3(b))" = "abbbabbb" -- "a3(b)" == "abbb" repeats twice.
```

Given a string, return the expansion of that string. 

Input will consist of only lowercase letters and numbers (1 to 9) in valid parenthesis. There will be no letters or numbers after the last closing parenthesis.

More examples in test cases. 

Good luck!

Please also try [Simple time difference](https://www.codewars.com/kata/5b76a34ff71e5de9db0000f2)

Answer: {"fn_name": "solve", "inputs": [["3(ab)"], ["2(a3(b))"], ["3(b(2(c)))"], ["k(a3(b(a2(c))))"]], "outputs": [["ababab"], ["abbbabbb"], ["bccbccbcc"], ["kabaccbaccbacc"]]}
user: A faro shuffle of a deck of playing cards is a shuffle in which the deck is split exactly in half and then the cards in the two halves are perfectly interwoven, such that the original bottom card is still on the bottom and the original top card is still on top.

For example, faro shuffling the list
```python
['ace', 'two', 'three', 'four', 'five', 'six']
```
gives
```python
['ace', 'four', 'two', 'five', 'three', 'six' ]
```

If 8 perfect faro shuffles are performed on a deck of 52 playing cards, the deck is restored to its original order.

Write a function that inputs an integer n and returns an integer representing the number of faro shuffles it takes to restore a deck of n cards to its original order.

Assume n is an even number between 2 and 2000.

Answer: {"fn_name": "faro_cycles", "inputs": [[2], [52], [542], [1250], [1954]], "outputs": [[1], [8], [540], [156], [30]]}