mathewhe/aqua_rat huggingface dataset:
Question: A cistern which could be filled in 8 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it?
(A) 76 hrs
(B) 99 hrs
(C) 55 hrs
(D) 90 hrs
(E) 40 hrs
Rationale: 1/8 - 1/x = 1/10
=> 40 hrs
Answer: E
Answer: (E) 40 hrs
Question: Which of the following represents the profit from the investment of x dollars at n percent compound annual interest for 5 years?
(A) x (1+n/100)^5 - x
(B) 4x (1+n/100)^4 - x
(C) 6x (1+n/100)^6 - x
(D) 2x (1+n/100)^2 - x
(E) x (1+n/100)^7 - x
Rationale: Amount after 5 years compounded yearly = x (1+n/100)^5
Thus profit = Final amount - original principle = x (1+n/100)^5 - x . Answer : A
Answer: (A) x (1+n/100)^5 - x
Question: If 15 workers can build a wall in 48 hours, how many workers will be required to do the same work in 30 hours?
(A) 22
(B) 24
(C) 26
(D) 25
(E) 23
Rationale: Let the number of workers employed to build the wall in 30 hours be y
48 * 15 = 30 * y
(48 *15)/30=y
y=24
Answer:B
Answer: (B) 24
Question: Of the 120 passengers on Flight 750, 55% are female. 10% of the passengers sit in first class, and the rest of the passengers sit in coach class. If 1/3 of the passengers in first class are male, how many females are there in coach class?
(A) 44
(B) 48
(C) 50
(D) 52
(E) 58
Rationale: Number of passengers on flight = 120
Number of female passengers= .5*120 = 66
Number of passengers in first class = (10/100)* 120 = 12
Number of passengers in coach class = (90/100)* 120 = 108
Number of male passengers in first class = 1/3 * 12 = 4
Number of female passengers in first class = 12-4 = 8
Number of female passengers in coach class = 66 - 8 = 58
Answer E
Answer: (E) 58
Question: In how many different number of ways 4 boys and 3 girls can sit on a bench such that girls always sit together.
(A) 720
(B) 740
(C) 760
(D) 770
(E) 790
Rationale: Option 'A'
Answer: (A) 720
Question: How many factors of 30 are odd numbers greater than 1?
(A) 3
(B) 3
(C) 5
(D) 6
(E) 7
Rationale: prime factors of 30 are 2^1,3^1,5^1
total divisors = (power if a prime factor+1)
total no. of odd factors(3,5,) = (1+1)(1+1) =4
since we need odd divisors other than 1 =>4-1 = 3 odd divisors
B is the answer
Answer: (B) 3
Question: 3 + 33 + 333 + 3.33 = ?
(A) 324.56
(B) 372.33
(C) 436
(D) 633
(E) 662
Rationale: 3
+ 33
+ 333
+ 3.33
------
372.33
------
Correct Option is B
Answer: (B) 372.33
Question: 17 times a number gives 187. The number is
(A) 11
(B) 12
(C) 13.2
(D) None
(E) Cannot be determined
Rationale: Explanation:
Let the number be 'N'
17×N=187⇒N=11
Correct Option: A
Answer: (A) 11
Question: Find the odd man out. 2, 4, 6, 12, 19, 28
(A) 12
(B) 19
(C) 1
(D) 3
(E) 19
Rationale: 19 is an odd number.All other given numbers are even
Answer : Option B
Answer: (B) 19
Question: Large amounts of cheques are processed by using
(A) kilobytI
(B) kilobyt2
(C) kilobyte
(D) kilobytK
(E) kilobytW
Rationale: Answer: Option 'C'
Answer: (C) kilobyte
Question: If 2 persons can do 2 times of a particular work in 2 days, then, 5 persons can do 5 times of that work in?
(A) 2 days
(B) 3 days
(C) 5 days
(D) 7 days
(E) 9 days
Rationale: That is, 1 person can do one time of the work in 2 days.
Therefore, 5 persons can do 5 times work in the same 2 days itself.
A)
Answer: (A) 2 days
Question: In Sam's hanger there are 23 boxes, 16 out of the boxes are filled with toys and the rest are filled with electrical appliances. 8 boxes are for sale, 5 of them are filled with toys. How many boxes with electrical appliances are in Sam's hanger that is not for sale?
(A) 1.
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: Total boxes = 23
Filled with toys = 16
Filled with appliance = 7
Total boxes for sale = 8
Toy boxes for sale = 5
Appliance boxes for sale = 3
Appliance boxes not for sale = 7 - 3 = 4
Correct Option: D
Answer: (D) 4
Question: How many different arrangements of letters are possible if three letters are chosen from the letters A through G and the letters E and A must be among the letters selected?
(A) 28
(B) 30
(C) 32
(D) 34
(E) 36
Rationale: Besides A and E, there are 5 letters and we can choose one of them.
5C1 = 5
Three letters can be arranged in 3! ways.
The number of arrangements is 5*3! = 30
The answer is B.
Answer: (B) 30
Question: If (a-6)(b-2) =0, which of the following must be true ?
I. a=6 and b=2
II. if a is not 6, then b=2
III. if a=6, then b is not=2
(A) I only
(B) II only
(C) III only
(D) I and II
(E) II and III
Rationale: (a-6)(b-2)=0
So either a=6 or b=2 or both. It is 'or' not 'and', so it could be any of the three possibilities. Thus I and III are not necessarily true.
The answer is B.
Answer: (B) II only
Question: A rectangular-shaped carpet that measures x feet by y feet is priced at $20. What is the cost of the carpet, in dollars per square yard? (1 square yard = 9 square feet)
(A) 180xy
(B) 180/(xy)
(C) 20xy
(D) 20xy/9
(E) xy/180
Rationale: The area of the carpet in feet is xy.
The area in square yards is xy / 9.
The price per square yard is 20 / (xy/9) = 180/(xy).
The answer is B.
Answer: (B) 180/(xy)
Question: A pack of baseball cards consists of 12 outfielder cards and 8 infielder cards. What is the lowest number of outfielder cards that would have to be removed from the pack so that no more than 50 percent of the pack would be outfielder cards?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: let the number of O card to be removed=X
then remaning cards=12-X
now this 12-X cards should count less than 50% of toatal Ocards
12-X<.5*12
X<12-6
X<6
X=5
Ans B
Answer: (B) 5
Question: The perimeters of two squares are 44 cm and 36 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares?
(A) 76 cm
(B) 24 cm
(C) 25.2 cm
(D) 55 cm
(E) 34 cm
Rationale: We know perimeter of square = 4(side)
So Side of first square = 44/4 = 11 cm
Side of second square = 36/4 = 9 cm
Area of third Square = 11*11 - 9*9
= 40 cm
So side of third square = 6.3 [because area of square = side*side]
Perimeter = 4*Side = 4*6.3 = 25.2 cm
Answer:C
Answer: (C) 25.2 cm
Question: A 40 kg metal bar made of alloy of tin and silver lost 4 kg of its weight in the water. 10 kg of tin loses 1.375 kg in the water; 5 kg of silver loses 0.375 kg. What is the ratio of tin to silver in the bar?
(A) 1/4
(B) 2/5
(C) 1/2
(D) 3/5
(E) 2/3
Rationale: you can simply use this formula to avoid confusion:
w1/w2 = (A2 - Aavg)/(Avg - A1)
Here is how you will find the values of A1 an A2.
We have an overall loss (average loss). The average loss is 4 kg when 40 kg alloy is immersed.
This is a loss of (4/40)*100 = 10%.
This is Aavg
The loss of tin is 1.375 kg for every 10 kg.
This means it loses (1.375/10)*100 = 13.75% of its weight in water.
This is A1.
The loss of silver is .375 kg for every 5 kg.
This means it loses (.375/5)* 100 = 7.5% of its weight in water.
This is A2.
Weight of Tin/Weight of Silver = (Silver's loss - Avg loss)/(Avg loss - Tin's loss)
X/Y = (7.5 - 10)/(10 - 13.75) = 2/3
E
Answer: (E) 2/3
Question: How many times in a day, the hands of a clock are straight?
(A) 22
(B) 44
(C) 48
(D) 24
(E) 36
Rationale: The hands of a clock point in opposite directions (in the same straight line, making an angle 180° between them) 11 times in every 12 hours because between 5 and 7 they point in opposite directions at 6 'o clock only. Hence the hands point in the opposite directions 22 times in a day.
The hands of a clock coincide(0° between them) 11 times in every 12 hours (between 11 and 1, they coincide only once, at 12 o'clock). Hence the hands coincide 22 times in a day.
So In 24 hours, the hands come in opposite direction or coincide 44 times.
This is already given as a formula and it's is better to learn the answer by heart as 44
which can save time in competitive exams.(However you should know the theory behind). Answer: Option B
Answer: (B) 44
Question: A train 240 m in length crosses a telegraph post in 16 seconds. The speed of the train is?
(A) 22
(B) 77
(C) 54
(D) 87
(E) 21
Rationale: S = 240/16 * 18/5 = 54 kmph.Answer: C
Answer: (C) 54
Question: The area of a triangle will be when a = 1m, b = 2m, c = 3m, a, b, c being lengths of respective sides.
(A) 0 sq m
(B) 3 sq m
(C) 2 sq m
(D) 6 sq m
(E) 9 sq m
Rationale: S = (1 + 2 + 3)/2 = 3
=> No triangle exists
ANSWER:A
Answer: (A) 0 sq m
Question: A and B started a partnership business investing some amount in the ratio of 3 : 5. C joined then after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed among A, B and C?
(A) 3 : 5 : 2
(B) 3 : 5 : 5
(C) 6 : 10 : 5
(D) 3 : 4 : 5
(E) 4 : 6 : 8
Rationale: Let the initial investments of A and B be 3x and 5x.
A : B : C = (3x x 12) : (5x x 12) : (5x x 6) = 36 : 60 : 30 = 6 : 10 : 5.
Answer: C
Answer: (C) 6 : 10 : 5
Question: A number is divided by 221, the remainder is 64. If the number be divided by 13 then remainder will be
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: Let the given number when divided by 119
gives x as quotient and 19 as remainder. Then
Given number = 119x + 19
= 17 x 7x + 17 + 2
= 17 (7x + 1) + 2
so, the required remainder is 2.
ANSWER:B
Answer: (B) 2
Question: By investing Rs. 1620 in 8% stock,Michael earns Rs. 135.The stock is then quoted at :
(A) Rs. 80
(B) Rs. 96
(C) Rs. 106
(D) Rs. 108
(E) None of these
Rationale: Solution
To earn Rs. 135, investment = Rs. 1620.
To earn Rs. 8, investment = Rs. (1620/135x8) =96
∴ Market value of Rs. 100 stock = Rs. 96.
Answer B
Answer: (B) Rs. 96
Question: The list price of an article is Rs.65. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?
(A) 7%
(B) 4%
(C) 2%
(D) 1%
(E) 8%
Rationale: 65*(90/100)*((100-x)/100) = 56.16
x = 4%
Answer: B
Answer: (B) 4%
Question: An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is 49 times the difference between the two numbers. How many coins did the old man have?
(A)  24
(B)  26
(C)  30
(D)  49
(E)  40
Rationale: Let the number of coins one son got be x and the number of coins another got be y. Total = x + y.
x^2 - y^2 = 49(x - y) --> x + y = 49.
Answer: D.
Answer: (D)  49
Question: What percent of 150 is 40?
(A) 0.25%
(B) 26.67%
(C) 25%
(D) 40%
(E) 250%
Rationale: 150*x /100 = 40
x = 2*40/3
x = 26.67
Ans: B
Answer: (B) 26.67%
Question: On January 1, 2001 it was Monday. Which day of the week fall on January 1, 2005?
(A) Saturday
(B) Wednesday
(C) Monday
(D) Tuesday
(E) Friday
Rationale: On 31st Dec. 2000 it was Sunday.
Number of odd days from 2001 to 2004=(1 + 1 + 1 + 2) = 5 odd days
31st Dec. 2004, it was Friday
Saturday was the day on 1st Jan. 2005
Answer: A
Answer: (A) Saturday
Question: Raju purchases 550 ml. of milk every day. If the cost of one litter of milk is Rs.44. How much amount will he pay in 45 days?
(A) Rs.1098
(B) Rs.1079
(C) Rs.1089/-
(D) Rs.1099
(E) None of these
Rationale: Explanation:
500 ml cost Rs.22
50 ml cost Rs.2.20
:.550 ml cost Rs.24.20
For 44 days the cost of milk = 45 x 24.20
= Rs.1089/-
Answer: Option C
Answer: (C) Rs.1089/-
Question: If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?
(A) 157.53
(B) 157.59
(C) 157.5
(D) 157.51
(E) 157.56
Rationale: (3500*1.5*3)/100 => 157.50
Answer: C
Answer: (C) 157.5
Question: If P and Q are positive integers, P - 3 is divisible by 4 and Q - 1 is divisible by 4, all of the following could be the value of P - Q Except?
(A) 1
(B) 2
(C) 6
(D) 18
(E) 14
Rationale: P-3 = 4Q
=> P = 4Q + 3 = 3,7,11,15,19,23,27,31,35,39
Q-1 = 4P
=> Q = 4P + 1 = 1,5,9,13,17,21,25,29,33,37,41
2=3-1
6=15-9
18=27-9
14=31-17
So , we can see that all the answer choices are possible here except A
Answer: (A) 1
Question: An article is bought for Rs.600 and sold for Rs.500, find the loss percent?
(A) 16 2/3%
(B) 16 7/3%
(C) 19 2/3%
(D) 16 2/3%
(E) 16 4/3%
Rationale: 600 ---- 100
100 ---- ? => 16 2/3%
Answer: D
Answer: (D) 16 2/3%
Question: The value of (1-d3) / (1-d) is
(A) > 1 if d > -1
(B) >3 if d > 1
(C) > 2 if 0 < d < 0.5
(D) < 2 if d < -2
(E) None
Rationale: Explanation :
Let S = (1 - d3 ) / ( 1 - d ) = ( 1 + d2 + d) .
=> d = 0 then S = 1 .
=> d = 2 then S = 7 .
=> d = 0.1 then S = 1.11 .
=> d = -3 then S = 7 .
Hence, only the option 2 satisfy.
Answer : B
Answer: (B) >3 if d > 1
Question: How many multiples of 4 are there between 32 and 252 ?
(A) 67
(B) 64
(C) 54
(D) 56
(E) 60
Rationale: It should be mentioned whether 32 and 252 are inclusive.
If 32 and 252 are inclusive, then the answer is (252-32)/4+1=56.
If 32 and 252 are NOT inclusive, then the answer is (248-36)/4+1=54.
Since OA is C, then we have NOT inclusive case.
Answer: (C) 54
Question: The volumes of two cubes are in the ratio 27: 125, what shall be the ratio of their surface areas?
(A) 9:26
(B) 9:24
(C) 9:25
(D) 9:20
(E) 9:21
Rationale: a13 : a23 = 27 : 125
a1 : a2 = 3 : 5
6 a12 : 6 a22
a12 : a22
=9:25
Answer:C
Answer: (C) 9:25
Question: 40 onions on a scale weigh 7.68 kg. When 5 onions are removed from the scale, the average weight of the 35 onions is 190 grams. What is the average weight (in grams) of the 5 onions which were removed?
(A) 200
(B) 202
(C) 204
(D) 206
(E) 208
Rationale: 35*190=6650.
The other 5 onions weigh a total of 1030 grams.
The average weight is 1030/5 = 206 grams.
The answer is D.
Answer: (D) 206
Question: The “length of integer x” refers to the number of prime factors, not necessarily distinct, that x has. (If x = 60, the length of x would be 4 because 60 = 2 × 2 × 3 × 5.) What is the greatest possible length of integer z if z < 3000?
(A) 7
(B) 9
(C) 11
(D) 13
(E) 15
Rationale: To maximize the length of z, we should minimize its prime base. The smallest prime is 2 and since 2^11 = 2048 < 3000, then the greatest possible length of integer z is 11.
The answer is C.
Answer: (C) 11
Question: The captain of a cricket team of 11 members is 24 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
(A) 20 years
(B) 21 years
(C) 22 years
(D) 23 years
(E) 24 years
Rationale: Explanation:
Let the average age of the whole team by x years.
11x â€“ (24 + 27) = 9(x -1)
11x â€“ 9x = 42
2x = 42
x = 21.
So, average age of the team is 21 years.
Answer B
Answer: (B) 21 years
Question: The perimeter of a triangle is 60 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle
(A) A)72
(B) B)828
(C) C)729
(D) D)75
(E) E)35
Rationale: Explanation:
Area of a triangle = r * s
Where r is the inradius and s is the semi perimeter of the triangle.
Area of triangle = 2.5 * 60/2 = 35 cm2
Answer: Option D
Answer: (D) D)75
Question: 4 dice are thrown simultaneously on the board. Find the probability show the same face.
(A) 2/215
(B) 2/131
(C) 1/216
(D) 2/217
(E) 2/319
Rationale: The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:
=6×6×6×6=64=6×6×6×6=64
n(S)=64n(S)=64
Let XX be the event that all dice show the same face.
X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}
n(X)=6n(X)=6
Hence required probability,
=n(X)n(S)=664=n(X)n(S)=664
=1/216
C
Answer: (C) 1/216
Question: What is the units digit of 17^83 × 13^82 × 11^87?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: Cyclicity of 7 is 4 --> 7, 9, 3, 1
Cyclicity of 3 is 4 --> 3, 9, 7, 1
11 raised to any positive power has a units digit 1
17^83 × 13^82 × 11^87 = Units digit of 3 * 9 * 1 = 7
Answer: D
Answer: (D) 7
Question: A box contain the number of balls which is as much times greater than 15 as much times lesser than 240.The no. of ball is?
(A) 48
(B) 75
(C) 60
(D) 54
(E) 45
Rationale: Answer
Let the number be x.
x/15=240/x
x^2=240*15=3600
x=√3600=60
Correct Option: C
Answer: (C) 60
Question: Compound interest earned on a sum for the second and the third years are Rs.2000 and Rs.2500 respectively. Find the rate of interest?
(A) 18% p.a.
(B) 22% p.a.
(C) 25% p.a.
(D) 24% p.a.
(E) None of these.
Rationale: Rs.2500 - 2000 = Rs.500 is the interest on Rs.2000 for one year.
Rate of interest = (500/2000) / 100 = 25% p.a
ANSWER:C
Answer: (C) 25% p.a.
Question: 9548+7314=8362=?
(A) 8230
(B) 8410
(C) 8500
(D) 8600
(E) None of them
Rationale: =(9548+7314)=8362+x
16862=8362+x
x=16862-8362
=8500
Answer is C
Answer: (C) 8500
Question: 900 men have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now?
(A) 12.88
(B) 12.6
(C) 12.55
(D) 12.21
(E) 12.27
Rationale: 900*15 = 1100*x
x = 12.27.Answer: E
Answer: (E) 12.27
Question: Two same glasses are respectively 1/4th 1/5th full of milk. They are then filled with water and the contents mixed in a tumbler. The ratio of milk and water in the tumbler is?
(A) 9:36
(B) 9:31
(C) 9:39
(D) 9:34
(E) 9:32
Rationale: 1/4 : 3/4 = (1:3)5 = 5:15
1/5 : 4/5 = (1:4)4 = 4:16
------
9:31
Answer: B
Answer: (B) 9:31
Question: In the recent, climate conference in New York, out of 700 men, 500 women, 800 children present inside the building premises, 20% of the men, 40% of the women and 10% of the children were Indians. Find the percentage of people who were not Indian?
(A) 77%
(B) 73%
(C) 79%
(D) 83%
(E) None
Rationale: Solution: Number of Indians men present there = 700*20/100 = 140
Indian women = 500*40/100 = 200
Indian children = 800*10/100 = 80.
Total member present in climate conference = 700+500+800 = 2000
Total Indian = 200+140+80 = 420
Hence, % of Indian present there = 420*100/2000 = 21%
% of people who were not Indian = 100-42 = 79%.
Answer C
Answer: (C) 79%
Question: Given that x = 2^b – (8^33 + 16^5), which of the following values for b yields the lowest value for |x|?
(A) 97
(B) 98
(C) 99
(D) 100
(E) 119
Rationale: 8^33 + 16^5 = 2^99 + 2^20
Compared to 2^99, the value of 2^20 is negligible.
2^99 - (2^99 +2^20) will minimize the value of |x|.
The answer is C.
Answer: (C) 99
Question: The y intercept of a line L is 10. If the slope of L is negative, which of the following could be the x intercept of L.
I. -1
II. 0
III. 6
(A) I only
(B) II only
(C) III only
(D) I and II
(E) I and III
Rationale: C) III only
The y-intercept is 10. Therefore we have y=mx+10
It is given that the slope is negative. Therefore the line must go from top left to bottom right.
i.e: the x-intercept has to be positive. That itself rules out III.
If you choose to go with the options directly, here's an approach.
y=mx+10. For the x-intercept, y=0.
i.e. mx+10=0.
We know that the slope m is negative. Therefore, if x=-1 or x=0, the equation mx+10 =0 would never be satisfied.
If x=6, we have 6m+10=0. A value of m=-5/3 would satisfy this equation.(ANSWER C)
Answer: (C) III only
Question: Mr. Jones sold two pipes at $1.20 each. based on the cost , his profit one was 20% and his loss on the other was 20%. on the sale of the pipes, he:
(A) broke even
(B) lost 4 cents
(C) gained 4 cents
(D) lost 10 cents
(E) gained 10 cnets
Rationale: 20%profit on $1.20=$20/100x1.20, =$0.20x1.20, = $0.24, similarly , 20 %loss on $1.20, =$20/100x1.20, =$0.20x1.20, =$0.24, therefoe, in one pipe his profit is $ 0.24 and in the other pipe his loss is $0.24. answer: broke even.correct answer will be (A)
Answer: (A) broke even
Question: A shipping company has four empty trucks that will head out in the morning, all four to the same destination. The clerk has four different boxes to ship to that same destination. All four boxes could go on any one of the trucks, or the boxes could be split up into any groupings and given to the trucks in any combinations (ie. two to one truck, one to another, and one to another). In how many different ways could the boxes be put on the four trucks?
(A) 16
(B) 64
(C) 256
(D) 576
(E) 4096
Rationale: Where we put one box has absolutely no bearing on where we put any of the other boxes. The placement of the four boxes is completely independent of one another. For each box, we have four choices.
N = 4*4*4*4 = 16*16 = 256
Answer = (C)
Answer: (C) 256
Question: By selling an article at Rs.250, a profit of 25% is made. Find its cost price?
(A) s.486
(B) s.455
(C) s.220
(D) s.480
(E) s.200
Rationale: SP = 250
CP = (SP)*[100/(100+P)]
= 250* [100/(100+25)]
= 250* [100/125]
= Rs.200
Answer: E
Answer: (E) s.200
Question: The side of a rhombus is 22 m and length of one of its diagonals is 16 m. The area of the rhombus is?
(A) 327.9
(B) 325.9
(C) 347.7
(D) 357.9
(E) 327.9
Rationale: area of the rhombus = 1/2 * p * √4(a)2 - (p)2
a= 22 ; p = 16
A=1/2 * 16 *√4(22)2 - (16)2
=1/2 * 16 *√1936 - 256
=1/2 * 16 *√1680
A =327.9
Answer : A
Answer: (A) 327.9
Question: Bullock likes to keep a spare tyre in his car every time. On a certain day, he travels 1, 40,000 km and just to make the most of all the tyres, he changes the tyres between his journey such that each tyre runs the same distance.
What is the distance traveled by each tyre?
(A) 70,000
(B) 112,000
(C) 80,000
(D) 90,000
(E) 10,000
Rationale: The distance traveled by each tyre:
4/5 * 1, 40, 000km = 112,000 km. B
Answer: (B) 112,000
Question: A and B can together finish a work in 30days. They worked together for 20days and then B left. After another 20days, A finished the remaining work. In how many days A alone can finish the job?
(A) 20
(B) 30
(C) 60
(D) 50
(E) 80
Rationale: A+B 20days work = 20*1/30 = 2/3
Remaining work = 1-2/3 = 1/3
1/3 work is done by A in 20days
whole work will be done by A in 20*3 = 60days
Answer is C
Answer: (C) 60
Question: A software engineer has the capability of thinking 100 lines of code in five minutes and can type 100 lines of code in 10 minutes. He takes a break for five minutes after every ten minutes. How many lines of codes will he complete typing after an hour?
(A) 450 lines
(B) 200 lines
(C) 350 lines
(D) 250 lines
(E) 150 lines
Rationale: 5-think
5-type
5-break
5-type
5-think
5-break
5-type
5-type
5-break
5-think
5-type
5-break
so 5 times for 5 minutes SE types.
Total number of lines =250 lines
ANSWER:D
Answer: (D) 250 lines
Question: Set X consists of 10 integers and has median of 30 and a range of 20. What is the value of the greatest possible integer that can be present in the set?
(A) 32
(B) 37
(C) C.40
(D) 43
(E) 50
Rationale: Note that both median and range do not restrict too many numbers in the set. Range is only concerned with the smallest and greatest. Median only cares about the middle.
Quick check of each option starting from the largest:
(E) 50
Range of 20 means the smallest integer will be 30. So 20 cannot lie in between and hence cannot be the median.
(D) 43
Range of 20 means the smallest integer will be 23. So 20 cannot lie in between and hence cannot be the median.
(C) 40
Range of 20 means the smallest integer will be 20. 20 can lie in between such as:
20, 20, 20, 20, 20, 20, 20, 20, 20, 50
This is possible. Hence it is the greatest such number.
Answer (E)
Answer: (E) 50
Question: A dishonest dealer professes to sell goods at the cost price but uses a false weight and gains 25%. Find his false weight age?
(A) 2288
(B) 276
(C) 800
(D) 288
(E) 277
Rationale: 25 = E/(1000 - E) * 100
1000 - E = 4E
1000 = 5E => E = 200
1000 - 200 = 800
Answer:C
Answer: (C) 800
Question: A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
(A) 67 sec
(B) 89 sec
(C) 38 sec
(D) 87 sec
(E) 45 sec
Rationale: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 260 + 120 = 380 m.
Time taken = 380/10
=38 sec.
Answer: C
Answer: (C) 38 sec
Question: Joel sailed for 3 hours at a speed of 20 miles per hour, then for 6 hours at 30 miles per hour and finally, 1 more hour at 40 miles per hour. What was the average speed of Joel during the whole sail?
.
(A) 25
(B) 27.5
(C) 28
(D) 30
(E) 32
Rationale: 3 hours at a speed of 20 miles per hour gives us Distance = 20*3 = 60 miles
6 hours at a speed of 30 miles per hour gives us Distance = 30*6 = 180 miles
1 more hour at 40 miles per hour gives us Distance = 40*1 = 40 miles
Total Distance = 60+180+40 = 280 miles
Total Time = 3+6+1 = 10 Hours
Average Speed = 280 / 10 = 28 Miles per hour
ANSWER:C
Answer: (C) 28