mathewhe/aqua_rat huggingface dataset:
Question: If a square mirror has a 20-inch diagonal, what is the approximate perimeter W of the mirror, in inches?
(A)  40
(B)  60
(C)  80
(D)  100
(E)  120
Rationale: if you draw the square and diagonal inside the square. u can see square becomes part of two triangles opposite to each other.
And We know the property of the triangle, addition of two sides of triangle must be greater than its diagonal in order to complete the triangle. And each side must be less than 20 and perimeter W must be less than 80, so we can eliminate answer choice C, D and E.
so Side 1 + side 2 > 20, that means Side 1 or Side 2 must be > 10. so we can eliminate the answer choice A.
Now we are left with is B
Answer: (B)  60
Question: Find the simple interest on Rs. 69,000 at 16 2/3% per year for 9 months.
(A) 7500
(B) 6500
(C) 8625
(D) 9500
(E) None of them
Rationale: P = Rs.69000,R = 50/3% p.a and T = 9/12 years = 3/4years.
Simple Interest = (P*R*T)/100 = Rs.(69,000*(50/3)*(3/4)*(1/100))= Rs.8625
Answer is C.
Answer: (C) 8625
Question: The sum of three consecutive numbers is 252. The greatest among these three number is:
(A) 45
(B) 80
(C) 85
(D) 55
(E) 40
Rationale: Let the numbers be x, x + 1 and x + 2
Then,
x + (x + 1) + (x + 2) =252
3x = 252
x = 83
Greatest number, (x + 2) = 85
ANSWER:C
Answer: (C) 85
Question: Solution A is 20% salt and Solution B is 60% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution?
(A) 6:4
(B) 6:14
(C) 4:4
(D) 4:6
(E) 1:3
Rationale: Forget the volumes for the time being.
You have to mix 20% and 80% solutions to get 50%. This is very straight forward since 50 is int he middle of 20 and 80 so we need both solutions in equal quantities. If this doesn't strike, use
w1/w2 = (A2 - Aavg)/(Aavg - A1)
w1/w2 = (60 - 50)/(50 - 20) = 1/3
So the volume of the two solutions will be equal. Answer has to be 1:3
E.
Answer: (E) 1:3
Question: A certain club has exactly 5 new members at the end of its first week. Every subsequent week, each of the previous week's new members (and only these members) brings exactly J new members into the club. If y is the number of new members brought into the club during the twelfth week, which of the following could be y?
(A)  5^1/12
(B)  3^11 * 5^11
(C)  3^12 * 5^12
(D)  3^11 * 5^12
(E)  60^12
Rationale: At the end of the first week, there are 5 new members;
At the end of the second week, there are 5J new members (since each 5 new members from the previous week brings J new members);
At the end of the third week, there are 5J^2 new members (since each 5J new members from the previous week brings J new members);
...
At the end of the twelfth week, there are 5J^11 new members (since each 5J^10 new members from the previous week brings J new members).
We are given that 5J^11=y. Out of the answers only D yields integer value for J: 5J^11=3^11 * 5^12 --> J=3*5=15.
Answer: D.
Answer: (D)  3^11 * 5^12
Question: The difference between a number and its two-fifth is 510. What is 60% of that number?
(A) 512
(B) 510
(C) 514
(D) 516
(E) 518
Rationale: Let the number be x. Then,
x - 2/5 x = 510
x = (510 * 5)/3 = 850
60% of 850 = 510.
Answer:B
Answer: (B) 510
Question: Find the principle on a certain sum of money at 5% per annum for 4 years if the amount being Rs.1120?
(A) 933
(B) 1067
(C) 1977
(D) 1056
(E) 1097
Rationale: 1120 = P [1 + (5*4)/100]
P= 933
Answer: A
Answer: (A) 933
Question: A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the s um of the profits of B and C. Find the total profit.
(A) s.4500
(B) s.5200
(C) s.1800
(D) s.Rs.3000
(E) s.5000
Rationale: A:B:C = 5:6:4
Let the total profit = 100 - 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 - 160/3 = 140/3
A-(B+C) = 160/3 - 140/3 = 20/3
20/3 ---- 200
100 ---- ? => 3000
ANSWER:D
Answer: (D) s.Rs.3000
Question: Solution A is 20% pottasium and Solution B is 80% pottasium. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% pottasium solution?
(A) 6:4
(B) 6:14
(C) 4:4
(D) 4:6
(E) 3:7
Rationale: Forget the volumes for the time being.
You have to mix 20% and 80% solutions to get 50%. This is very straight forward since 50 is int he middle of 20 and 80 so we need both solutions in equal quantities. If this doesn't strike, use
w1/w2 = (A2 - Aavg)/(Aavg - A1)
w1/w2 = (80 - 50)/(50 - 20) = 1/1
So the volume of the two solutions will be equal. Answer has to be 4:4=C
Answer: (C) 4:4
Question: A team bought a total of 567 balls. If each player on the team bought at least 24 balls, then what is the greatest possible number of players on the team?
(A) 21
(B) 22
(C) 23
(D) 24
(E) 25
Rationale: 567/24=23 plus remainder.
The answer is C.
Answer: (C) 23
Question: P is 6 times greater than Q then by what per cent is Q smaller than P?
(A) 84%
(B) 85.5%
(C) 80%
(D) 83.33%
(E) None
Rationale: Solution: Let Q = 10.
Then, P = 60.
Q is 50 less than P.
Q, % less than P = (50 /60)*100 = 83.33%.
Alternative Method
10 (Q)==(6 times greater)==> 60(P)==x%↓(Less than Q)==>10 (Q).
Now, x = 50*100/60 = 83.33%.
Answer: Option D
Answer: (D) 83.33%
Question: Right now, the ratio between the ages of Sandy and Molly is 4:3. After 6 years, Sandy’s age will be 38 years. What is Molly's age right now?
(A) 15
(B) 18
(C) 21
(D) 24
(E) 27
Rationale: Now, Sandy is 38 - 6 = 32
Molly's age is (3/4) * 32 = 24
The answer is D.
Answer: (D) 24
Question: The least number which should be added to 2520 so that the sum is exactly divisible by 5,6,4 and 3 is :
(A) 3
(B) 18
(C) 23
(D) 33
(E) 43
Rationale: Solution
L.C.M. of 5,6,4 and 3 = 60. on dividing 2520 by 60, the remainder is 42.
∴ Number to be added = (60-42) = 18. Answer B
Answer: (B) 18
Question: If a profit of Rs.12000 is to be divided among three partners A,B and C in the ratio 5:3:4 then share of B is
(A) Rs.2000
(B) Rs.4000
(C) Rs.3000
(D) Rs.5000
(E) Rs.7000
Rationale: B=3/12*12000=3000
ANSWER:C
Answer: (C) Rs.3000
Question: If m > 1 and n = 2^(m+2), then 4^m =
(A) 16n^2
(B) 4n^2
(C) n^2
(D) n^2/4
(E) n^2/16
Rationale: n = 2^(m+2) = 2^m*4
2^m = n/4
4^m = (2^m)^2 = (n/4)^2 = n^2/16
The answer is E.
Answer: (E) n^2/16
Question: Two out of five employees are capable of doing a certain task. Sixty percent of the five employees, including the two who are capable, are assigned to a project involving this task. what percentage of employees assigned to the project are not capable?
(A) 43.33%
(B) 33.33%
(C) 13.33%
(D) 38.33%
(E) 23.33%
Rationale: Given 60% of 5 employees including 2 who are capable of doing task.
60% of 5 employeees
= 60/100 * 5
= 3 employees
===> 2 employees who are capable of doing the task and one employee who is not capable.
percentage of employees assigned who are not capable
= 1/3 * 100
= 33.33%
ANSWER:B
Answer: (B) 33.33%
Question: What is the ratio of (1/4 )to the power 3 and (1/4) to the power4
(A) 1:2
(B) 1:3
(C) 1:4
(D) 2:1
(E) 4:1
Rationale: 1/4^3/1/4^4=4/1=4:1
ANSWER:E
Answer: (E) 4:1
Question: A thief steels a car at 8a.m. and drives it at 50kmph. The theft is discovered at 9a.m. and the owner sets off in another car at 70 kmph. When will he overtake the thief?
(A) 9a.m.
(B) 9.30a.m.
(C) 1130a.m.
(D) 11.45a.m.
(E) 10.15a.m.
Rationale: Suppose the thief overtakes x hours after 8a.m.
Distance covered by the thief in x hrs = distance covered by the owner in (x-1 hours)
50x = 70(x-1)
20x = 70
x = 7/2 hrs
Thief is overtaken at 11.30a.m.
Answer is C
Answer: (C) 1130a.m.
Question: Two persons starting from the same place walk at a rate of 5kmph and 7kmph respectively. What time will they take to be 24km apart, if they walk in the same direction?
(A) 17 hrs
(B) 22 hrs
(C) 25 hrs
(D) 12 hrs
(E) 14 hrs
Rationale: The relative speed of the boys = 7kmph â€“ 5kmph
= 2 kmph
Distance between them is 24 km
Time= 24km / 2 kmph = 12 hrs
Answer : D.
Answer: (D) 12 hrs
Question: a, b are positive integers. The remainder of a to be divided by 8 is 3 and the remainder of b to be divided by 6 is 5.
Which is possible to be the remainder of a*b to be divided by 48
(A) a) 2
(B) b) 6
(C) c) 8
(D) d) 15
(E) e) 20
Rationale: Two ways to do it...
a=8x+3..
b=6y+5..
1) convenient way..
Take x and y as 0, and you will get a*b as 3*5=15
Answer : D
Answer: (D) d) 15
Question: Perimeter of an equilateral and isosceles is 45 and 40 respectively. At least one of the sides of isosceles is equal to the equilateral. What's the base of isosceles triangle?
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
Rationale: 10 units
as other 2 sides will be 15,15 units.
ANSWER:D
Answer: (D) 10
Question: For any non-zero a and b that satisfy |ab| = -ab and |a| = a, |b-3| + |ab-b| =
(A) ab-4
(B) |ab|+4
(C) 2a-4b
(D) b-3ab
(E) ab+2ab+1
Rationale: given |ab|=-ab a*b is negative , |a|=a, so a is positive hence b is negative since ab is negative.
assume a=1,b=-1 |b-3|= 4, |ab-b|=2; |b-3|+|ab-b|=6.
test case :c)
2a-4b= 6
test a) |-1|-4= -3
test b) 1+4=5
hence corect answer: C
Answer: (C) 2a-4b
Question: If 4+X < (2+5X)/3, which of the following is correct?
(A) X < -5.
(B) X > -5.
(C) X > 5.
(D) -5 < X < 0.
(E) 0 < X < 5.
Rationale: 4+X < (2+5X)/3
12+3X < 2+ 5X
10 < 2X
5<X
C is the answer
Answer: (C) X > 5.
Question: Gali builds a tower using only red, green, and blue toy bricks in a ratio of 4:3:1. She then removes 1/2 of the green bricks and adds 1/3 more blue bricks, reducing the size of the tower by 14 bricks. How many red bricks will she need to add in order to double the total number of bricks used to build the original tower?
(A) 82
(B) 96
(C) 110
(D) 120
(E) 192
Rationale: Gali want to double the original amount of blocks, not just the red blocks
the original tower had 96 bricks, the new tower has 82 bricks and the question is asking how many extra red blocks are needed to build a tower of 192 bricks (double the original: 96*2).
192-82 = 110
so 110 bricks need to be added to the new 82 brick tower to double the original.
They worded the question ashow many red bricks need to be addedbut really it could be any colour just that 110 more bricks need to be there to equal 192=C
Answer: (C) 110
Question: How much is 80% of 40 is greater than 4/5 of 25?
(A) 12
(B) 27
(C) 18
(D) 12
(E) 81
Rationale: (80/100) * 40 – (4/5) * 25
32 - 20 = 12
Answer:D
Answer: (D) 12
Question: The price of a integrated declines by 67 percent every 6 months. At this rate, approximately how many years will it take for the price of an $81 integrated chip to reach $1?
81- 67% * 81 = 27 approx
27 - 0.67*27 = 9 approx
9- 0.67*9 = 3 approx
3-0.67*3= $1 approx
(A) 1.5 years
(B) 2 years
(C) 3 years
(D) 13 years
(E) 13.5 years
Rationale: not sure whether you like this:
81 - (81 x 67%)/3 = 81 - (81 x 2) / 3 = 27 = 81 / 31 = 81 / (3x3x3x3) = 81 / 3^4
so the time = 4 x 6 months = 24 months or 2 years. answer is B
Answer: (B) 2 years
Question: The probability that a number selected at random from the first 50 natural numbers is a composite number is
(A) 17/26
(B) 17/25
(C) 17/20
(D) 17/22
(E) 17/21
Rationale: The number of exhaustive events = ⁵⁰C₁ = 50.
We have 15 primes from 1 to 50.
Number of favourable cases are 34.
Required probability = 34/50 = 17/25.
nswer: B
Answer: (B) 17/25
Question: In a class of students, 1/2 of the number of girls is equal to 1/6 of the total number of students. What is the ratio of boys to girls in the class?
(A) 1/2
(B) 2/3
(C) 2/1
(D) 3/2
(E) 4/3
Rationale: (1/2)G=(1/6)(B+G)
6G=2B+2G
4G=2B
B/G=2/1.
The answer is C.
Answer: (C) 2/1
Question: The cash difference between the selling prices of an article at a profit of 4% and 2% is Rs. 3. The ratio of the two selling prices is?
(A) 52:51
(B) 52:53
(C) 52:50
(D) 22:56
(E) 52:51
Rationale: Let C.P. of the article be Rs. x.
Then, required ratio = 104% of x / 102% of x
= 104/102 = 52/51 = 52:51
Answer: A
Answer: (A) 52:51
Question: How many 3 digit numbers can be formed which are divisible by 3 using the numerals 0, 1, 2, 3, 4, 5 (WITH REPETITION)
(A) 216
(B) 133
(C) 240
(D) 600
(E) 305
Rationale: Divisibilty rule for 3: Sum of all digits is a multiple of 3
Selections for the above to be valid
1,2,3,4,5
No of possible ways = 5*5*5 = 125
0,1,2
No of possible ways = 2*2*1 = 4
0,4,5
No of possible ways = 2*2*1 = 4
Total = 8+125 = 133
Option
B
Answer: (B) 133
Question: The length of the bridge, which a train 140 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
(A) 230
(B) 244
(C) 245
(D) 238
(E) 235
Rationale: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (140 + X)/30 = 25/2 ==> 2(140 + X) = 750 ==> X = 235 m.
Answer: Option E
Answer: (E) 235
Question: Last year, the price of a vacation package was P. At the beginning of this year, the price went up 20%. Lucas used a travel voucher to purchase the vacation package at 30% off this year’s price. In terms of P, how much did Lucas pay?
(A)  P + 10
(B)  1.1*P
(C)  1.12*P
(D)  0.80*P
(E)  0.84*P
Rationale: Last year price = P;
This year price = 1.2P;
Lucas used a travel voucher to purchase the vacation package at 30% off this year’s price, thus he paid (1 - 0.3)*1.2P = 0.84P.
Answer: E.
Answer: (E)  0.84*P
Question: Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full is?
(A) 6 hrs
(B) 6 2/3 hrs
(C) 7 hrs
(D) 7 1/2 hrs
(E) 5 hrs
Rationale: (A + B)'s 1 hour work = (1/12 + 1/15) = 3/20
(A + C)'s 1 hour work = (1/12 + 1/20) = 2/15
Part filled in 2 hrs = (3/20 + 2/15) = 17/60
Part filled in 6 hrs = 3 * 17/60 = 17/20
Remaining part = 1 - 17/20 = 3/20
Now, it is the turn of A and B and 3/20 part is filled by A and B in 1 hour.
Total time taken to fill the tank = (6 + 1) = 7 hrs.
ANSWER:C
Answer: (C) 7 hrs
Question: The present ages of three persons in proportions 4 : 1 : 5. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
(A) 8, 20, 28
(B) 16, 28, 36
(C) 16, 28, 35
(D) 16, 28, 34
(E) 32, 8, 40
Rationale: Let their present ages be 4x, 1x and 5x years respectively.
Then, (4x - 8) + (1x - 8) + (5x - 8) = 56
10x = 80
x = 8.
Their present ages are 4x = 32 years, 1x = 8 years and 5x = 40 years respectively.
Answer:E
Answer: (E) 32, 8, 40
Question: Find the average of first 5 multiples of 5?
(A) 10
(B) 15
(C) 12.5
(D) 13
(E) 21
Rationale: average = (5+10+15+20+25)/5 = 15
Answer is B
Answer: (B) 15
Question: A class contains five juniors and five seniors. If one member of the class is assigned at random to present a paper on a certain subject, and another member of the class is randomly assigned to assist him, what is the probability W that both will be juniors?
(A) 1/10
(B) 1/5
(C) 2/9
(D) 2/5
(E) 1/2
Rationale: I think you're right. The other way to do it (but the long way) is to figure out the probability that it is not two Juniors.
2 seniors = P(Senior) * P(Senior) = 2/9
1 Senior and 1 Junior = (1/2) *(5/9)*2 = 5/9
Probability that it is not two Juniors is 5/9+2/9 = 7/9 so the probability W that it is two juniors is 1- (7/9) = 2/9.C
Answer: (C) 2/9
Question: A fruit salad mixture consists of apples, peaches, and grapes. There are 3 times as many pounds of apples as grapes and 2.5 times as many pounds of peaches as grapes. If a mixture that has an average (arithmetic mean) of 26 pounds per fruit, how many more pounds of apples than grapes does the mixture have?
(A) 24
(B) 11
(C) 9
(D) 6
(E) 5
Rationale: A+P+G= 26*3
A=3G
P=2.5G
3G+2.5G+G= 26*3
G= 26*3/6.5= 12
A= 12*3=36
Difference = 36-12=24
'A' is the answer
Answer: (A) 24
Question: If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
(A) 4 days
(B) 5 days
(C) 6 days
(D) 8 days
(E) 2 days
Rationale: Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, 6x + 8y =1/10	and 26x + 48y =1/2
Solving these two equations, we get : x =1/100 and y =1/200
(15 men + 20 boy)'s 1 day's work =(15/100+20/200)	=1/4	.
15 men and 20 boys can do the work in 4 days.
ANSWER:A
Answer: (A) 4 days
Question: The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
(A) 87
(B) 15
(C) 17
(D) 19
(E) 16
Rationale: Average of 20 numbers = 0
Sum of 20 numbers = (0 * 20) = 0
It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (-a).
Answer:D
Answer: (D) 19
Question: By selling 50 meters of cloth. I gain the selling price of 15 meters. Find the gain percent?
(A) 42 7/7%
(B) 42 5/8%
(C) 42 6/4%
(D) 42 6/8%
(E) 42 1/7%
Rationale: SP = CP + g
50 SP = 50 CP + 15 SP
35 SP = 50 CP
35 --- 15 CP gain
100 --- ? => 42 6/7%
Answer: D
Answer: (D) 42 6/8%
Question: In boring a well 50 m deep, the cost is
Rs.4/– for the first meter. The cost of each successive meter
increases by Rs.2/–. What is the cost of boring the entire well?
(A) 1650
(B) 2650
(C) 3650
(D) 4650
(E) 2850
Rationale: For successive meters the cost of boring will be 4, 6, 8, 10, ......., which forms an arithmetic series with terms n=50, first term a=4 & difference d=2
So Sum=(n/2)[2a+(n-1)d]= Total cost of boring
=(50/2)[2*4+(50-1)*2]=25(8+98)
= 2650
ANSWER:B
Answer: (B) 2650
Question: In a panel of 10 light bulbs, the odds of any light bulb to burn out are 0.07 at any given 10 minutes. Should a light bulb burn out, the whole panel would instantly turn off. What are the odds that the panel would be turned off within the first 10 minutes after it was switched on?
(A) 1-0.03^10
(B) 1-0.93^10
(C) (1-0.93)^10
(D) 0.06
(E) 1-10*0.07
Rationale: ans B.
Prob that light will not turned off = 0.93^10. Hence prob (turn off) = 1 - prob (not turn off).
Answer: (B) 1-0.93^10
Question: A Train requires 10 seconds to pass a pole while it requires 40 seconds to cross a stationary train which is 300 mtrs long. Find the speed of the train.
(A) 36kmph
(B) 42kmph
(C) 48kmph
(D) 52kmph
(E) 64kmph
Rationale: In 10s the train crosses the pole and in 40 sec the train crosses one more stationary train
In 30 sec the train travels a distance of 300 mtrs
Speed = 300/30 = 10 m/s = 10 * 18/5 = 36 kmph
Answer: A
Answer: (A) 36kmph
Question: The ratio of the number of females to males at a party was 1:2 but when 4 females and 4 males left, the ratio became 1:3. How many people were at the party originally?
(A) 20
(B) 22
(C) 24
(D) 26
(E) 28
Rationale: The total number of people are x females + 2x males.
3*(x-4) = 2x - 4
x = 8
There were 3x = 24 people at the party originally.
The answer is C.
Answer: (C) 24
Question: 1/3 +1/2 - 5/6 + 1/5 + 1/4 - 9/20 -2/15 =
(A) 0
(B) 2/15
(C) 2/5
(D) 9/20
(E) 5/6
Rationale: We need to determine the result of 1/3 + 1/2 - 5/6 + 1/5 + 1/4 - 9/20
Let’s add the given fractions in two groups. In the group of the first three fractions, notice that1/3 and 1/2 share a common denominator of 6 with 5/6.
1/2 + 1/3 = 3/6 + 2/6 = 5/6
Thus, 5/6 – 5/6 = 0
Looking at the 2nd group of the fractions (1/5, 1/4, and 9/20), notice that1/5 and 1/4 share a common denominator of 20 with 9/20.
1/5 + 1/4 = 4/20 + 5/20 = 9/20
Thus, 9/20 – 9/20 = 0.
Thus, the result of 1/3 + 1/2 – 5/6 + 1/5 + 1/4 – 9/20 is 2/15.
Answer: B
Answer: (B) 2/15
Question: A certain essay consists of 14 paragraphs. Each paragraph contains at least 105 words but not more than 110 words. Which of the following could be the total number of words in the essay?
(A) 1440
(B) 1520
(C) 1640
(D) 1740
(E) 1840
Rationale: lets consider minimum no of words ... 14 * 105 = 1470
Lets consider maximum no of words .... 14*110= 1540
answer should be one of these two values or should lie between these two values ...
only 1 option B - 1520
Answer: (B) 1520
Question: The sum of two numbers is 16. The difference is 8. What are the two numbers?
(A) 10-6
(B) 8-8
(C) 12-4
(D) 11-5
(E) 13-3
Rationale: 12+4 = 16
12 - 4 = 8
The Answer is C
Answer: (C) 12-4
Question: The speed of a boat in upstream is 80 kmph and the speed of the boat downstream is 160 kmph. Find the speed of the boat in still water and the speed of the stream?
(A) 10
(B) 99
(C) 40
(D) 55
(E) 22
Rationale: Speed of the boat in still water = (80+160)/2 = 12 kmph. Speed of the stream
= (160-80)/2
= 40 kmph.
Answer: C
Answer: (C) 40
Question: If y is the smallest positive integer such that 1260 multiplied by y is the square of an integer, then y must be
(A) 25
(B) 35
(C) 60
(D) 75
(E) 140
Rationale: 1260 = 2^2*3^2*5*7
To be perfect square, we need to multiply by at least 5*7 = 35.
The answer is B.
Answer: (B) 35
Question: The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
(A) 80,30 kmph
(B) 80,20 kmph
(C) 80,10 kmph
(D) 80,40 kmph
(E) 80,90 kmph
Rationale: Speed downstream = 60 + 20 = 80 kmph
Speed upstream = 60 - 20 = 40 kmph
Answer:D
Answer: (D) 80,40 kmph
Question: A invested $300 in a business after 6 months B invested $200 in the business. End of the year if they got $100 as profit. Find B's shares?
(A) $100
(B) $75
(C) $25
(D) $120
(E) $50
Rationale: A:B =300*12:200*6
A:B = 1:1
B's share = 100*1/4 = $25
Answer is C
Answer: (C) $25
Question: A third of Arunâ€™s marks in mathematics exceed a half of his marks in English by 20.If he got 360 marks in two subjects together how many marks did he got in English?
(A) 120,60
(B) 240,120
(C) 280,90
(D) 220,140
(E) None of them
Rationale: Let Arunâ€™s marks in mathematics and English be x and y
Then (1/3)x-(1/2)y=20
2x-3y=120â€¦â€¦>(1)
x+y=360â€¦â€¦.>(2)
solving (1) and (2)
x=240
and y=120
Answer is B.
Answer: (B) 240,120
Question: If the unit digit in the product (459x46x28*x484) is 2, the digit in place of * is
(A) 3
(B) 5
(C) 7
(D) 4
(E) 8
Rationale: (9x6x4) = 216, in order to obtain 2 at the unit place, we must multiply 216 by 2 or 7
Hence, of the given number
We have 7
ANSWER C 7
Answer: (C) 7
Question: A and B are two stations 390 km apart. A train starts from A at 10 a.m. and travels towards B at 65 kmph. Another train starts from B at 11 a.m. and travels towards A at 35 kmph. At what time do they meet?
(A) 2.15 pm
(B) 1.15 pm
(C) 4.15 pm
(D) 3.15 pm
(E) 12.15 pm
Rationale: Suppose they meet x hours after 10 a.m.
Then, (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs]=390.
65x + 35(x-1) = 390 => 100x = 425 => x =	17/4
So, they meet 4 hrs.15 min. after 10 a.m i.e., at 2.15 p.m.
ANSWER A
Answer: (A) 2.15 pm
Question: A sum of money at simple interest amounts to Rs. 800 in 3 years and to Rs. 850 in 4 years. The sum is:
(A) Rs. 670
(B) Rs. 690
(C) Rs. 600
(D) Rs. 625
(E) Rs. 654
Rationale: Explanation:
S.I. for 1 year = Rs. (850 - 800) = Rs. 50.
S.I. for 3 years = Rs.(50 x 3) = Rs. 150.
Principal = Rs. (800 - 150) = Rs. 600.
Answer: Option C
Answer: (C) Rs. 600
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
(A) 2277
(B) 2977
(C) 2677
(D) 4530
(E) 1971
Rationale: Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5 = Rs. 4530
Answer: D
Answer: (D) 4530
Question: A present value of a machine is $1200. Its value depletion rate is 10% per annum then find the machine value after 2 years?
(A) $972
(B) $810
(C) $915
(D) $715
(E) $795
Rationale: P= $1200
R = 10%
T = 2 years
Machine value after 2 years = P[(1-R/100)^T]
=1200*9/10 * 9/10
=$972
Answer is A
Answer: (A) $972
Question: Kiran travels from A to B by car and returns from B to A by cycle in 6 hours. If he travels both ways by car he saves 3 hours. What is the time taken to cover both ways by cycle?
(A) 18 hours
(B) 8 hours
(C) 10 hours
(D) 21 hours
(E) 12 hours
Rationale: Let the time taken to cover from A to B in car and cycle be x hours and y hours respectively.
x + y = 6 --- (1) ; 2x = 4 --- (2)
solving both the equations, we get y = 4
So, time taken to cover both ways by cycle = 2y hours = 8 hours.
ANSWER:B
Answer: (B) 8 hours