mathewhe/aqua_rat huggingface dataset:
Question: A driver would have reduced the time it took to drive from home to the store by 1/3 if the average speed had been increased by 21 miles per hour. What was the actual average speed, in miles per hour, when the driver drove from home to the store?
(A) 36
(B) 42
(C) 45
(D) 48
(E) 51
Rationale: Let R be the original speed and let T be the original time.
Since the distance remains the same (we're just changing the rate and time), any increase in rate or time is met with a decrease in the other term. Decreasing the time by 1/3 would give us:
D = (R)(T) = (2T/3)(x*R)
x = 3/2 since (2T/3)(3R/2) = (R)(T) = D
3R/2 = R + 21
R/2 = 21
R= 42
The answer is B.
Answer: (B) 42
Question: Train P crosses a pole in 30 seconds and train Q crosses the same pole in one minute and 15 seconds. The length of train P is three-fourths the length of train Q. What is the ratio of the speed of train P to that of train Q?
(A) 15:8
(B) 15:7
(C) 15:1
(D) 15:3
(E) 15:2
Rationale: Given that train P crosses a pole in 30 seconds and train Q crosses the same pole in one minute and 15 seconds.
Let the length of train P be LP and that of train Q be LQ
given that LP = 3/4 LQ
As the train P and Q crosses the pole in 30 seconds and 75 seconds respectively,
=> Speed of train P = VP = LP/30
Speed of train Q = VQ = LQ/75
LP = 3/4 LQ
=> VP = 3/4 LQ/(30) = LQ/40
Ratio of their speeds = VP : VQ
= LQ/40 : LQ/75 => 1/40 : 1/75 = 15:8
Answer:A
Answer: (A) 15:8
Question: Three interviewers, A, B, and C are interviewing 30 applicants. Only with three interviewers' admission can an applicant be admitted. If interviewer A admitted 10 applicants, B admitted 12 applicants, and C admitted 15 applicants, at least how many applicants get the admission?
(A)  6
(B)  2
(C)  0
(D)  8
(E)  12
Rationale: If A admitted 10 are overlapping with B admission of 12 But C does not overlap with anybody.
Then no student will get nod from all the 3.
Hence 0 student will get admission.
Answer : C
Answer: (C)  0
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 112 m length?
(A) 82.1 sec
(B) 12.1 sec
(C) 16.1 sec
(D) 11.1 sec
(E) 12.15sec
Rationale: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 112 = 222 m.
Required time = 222/20 = 11.1 sec.
Answer:D
Answer: (D) 11.1 sec
Question: If p^2 – 13p + 40 = x, and p is a positive integer between 1 and 10, inclusive, what is the probability that x < 0?
(A) 1/10
(B) 2/5
(C) 1/5
(D) 3/5
(E) 3/10
Rationale: (p-5)(p-8) = x
p = 6 or 7 for this to be true, so
2/10 = 1/5
Ans :C
Answer: (C) 1/5
Question: One side of a rectangular field is 4 m and its length along diagonal is 5 m. What is the area of the field?
(A) 13√8
(B) 13√2
(C) 13√4
(D) 13√2
(E) 13√1
Rationale: 4a = 48 4a = 20
a = 12 a = 5
a2 = 144 a2 = 25
Combined area = a2 = 169 => a = 13
d = 13√2.Answer: B
Answer: (B) 13√2
Question: A credit card company has a cash back option for their customers which is based on the annual amount that they charge on their credit cards. The customer receives 1.5% cash on their first $5000 of purchase, 2.5% on the next $5000 of purchase and a 3% on cash back on portion that exceeds $10,000. If a customer receives a cash back of 2.2% on their total annual charges made on the credit card, then what was the customer's annual charge?
(A) $12,500
(B) $15,000
(C) $17,500
(D) $20,000
(E) $22,500
Rationale: The customer receives $75 for the first $5000.
The customer receives $125 for the next $5000.
Let x be the total amount of the customer's annual charge.
$200 + 0.03(x-10,000)=0.022x
0.008x=100
x=12,500
The answer is A.
Answer: (A) $12,500
Question: The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 4240, what is the length of the plot in metres?
(A) 20
(B) 200
(C) 50
(D) 400
(E) 140
Rationale: Let length of plot = L meters, then breadth = L - 20 meters
and perimeter = 2[L + L - 20] = [4L - 40] meters
[4L - 40] * 26.50 = 4240
[4L - 40] = 4240 / 26.50 = 160
4L = 200
L = 200/4= 50 meters. Answer: C
Answer: (C) 50
Question: Positive integer x has z factors; 3x has 3 factors; Which of the following values can z take?
I. 1
II. 2
III. 3
(A) I or II
(B) I only holds
(C) II only holds
(D) II or III
(E) I or III
Rationale: Squares have odd number of factors.The square which is a multiple of 3 is 9.
3 has factors 1,3 .
Therefore 2 factors
Answer C
Answer: (C) II only holds
Question: A certain number of men can do a work in 65 days working 6 hours a day. If the number of men are decreased by one-fourth, then for how many hours per day should they work in order to complete the work in 40 days?
(A) 17
(B) 14
(C) 16
(D) 13
(E) 11
Rationale: D
13
Let the number of men initially be x. we have M1 D1 H1= M2 D2 H2
So, x * 65 * 6 = (3x)/4 * 40 * h2
=> h2 = (65 * 6 * 4)/(3 * 40) = 13.
Answer: (D) 13
Question: How many positive three-digit integers have an odd digit in both the tens and units place?
(A) 25
(B) 225
(C) 250
(D) 450
(E) 500
Rationale: 1. Make empty spaces and try to fill up the empty spaces one by one
2. If a condition is given, you always find the condition space and fill the condition space first.
Here we need to form a 3 digit number given 2 conditions that the tens and units digit are odd. the digits we can use here are all the digits from 0 to 9 and since nothing is mentioned about the digits being repeated or not, we always consider the with repetition case.
So making 3 empty spaces _ Odd Odd.
The total number of ways of filling the units digit is 5, since we can use any one out of 1,3,5,7 and 9. Similarly the total number of ways of filling the tens digit is 5. Now since the digits can be repeated and we need to have a 3 digit number, we can fill the hundreds digit in 9 ways, since we can use any one out of 1,2,3,4,5,6,7,8,9. We cannot use 0 since we need a 3 digit number.
So the answer here will be 9 * 5 * 5 = 225 ANS:B
Answer: (B) 225
Question: In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of two metres is left from all sides of the boundary of the garden. What is the length of the garden?
(A) 22
(B) 24
(C) 26
(D) 28
(E) 30
Rationale: Between the 12 mango trees, there are 11 gaps and each gap has 2 meter length
Also, 2 meter is left from all sides of the boundary of the garden.
Hence, length of the garden = (11 Ã— 2) + 2 + 2 = 26 meter
Answer is C.
Answer: (C) 26
Question: On a map, 4.5 inches represent 45 miles. How many miles approximately is the distance if you measured 254 centimeters assuming that 1-inch is 2.54 centimeters?
(A) 1000
(B) 1100
(C) 1200
(D) 1250
(E) 1300
Rationale: 1 inch = 2.54 cm
4.5 inch = 2.54 * 4.5 cm
11.43 cm = 45 miles
254 cms = 45/11.43*254= 1000 miles
Answer : A
Answer: (A) 1000
Question: The average age of a class of 32 students is 12 yrs. if the teacher's age is also included, the average increases by one year. Find the age of the teacher
(A) 45 Years
(B) 46 Years
(C) 49 Years
(D) 52 Years
(E) 54 Years
Rationale: Total age of students is 32X12 = 384 Years Total age inclusive of teacher = 33X (12+1) = 429 So, Teacher's age is 429-384= 45 Yrs There is a shortcut for these type of problems Teacher's age is 12+(33X1) = 45 Years Answer : A
Answer: (A) 45 Years
Question: In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?
(A) 524
(B) 1024
(C) 15247
(D) 11760
(E) 11470
Rationale: Required number of ways	= (8C5 x 10C6)
= (8C3 x 10C4)
= 11760.
ANSWER D 11760
Answer: (D) 11760
Question: Find a sum for first 5 prime no's?
(A) 23
(B) 28
(C) 26
(D) 27
(E) 29
Rationale: Required sum = (2 + 3 + 5 + 7 + 11) = 28.
Note: 1 is not a prime number.
B
Answer: (B) 28
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 37, the how old is B?
A.	7
B.	8
C.	9
D.	10
Explanation:
(A) 5
(B) 7
(C) 9
(D) 10
(E) 14
Rationale: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 37
5x = 35
x = 7.
Hence, B's age = 2x = 14 years.
Answer: Option E
Answer: (E) 14
Question: 800 students took the test on English and Maths. 35% students failed in english and 45% failed in maths. 40% of those who passed in maths also passed in english, then how many students failed in both ?
(A) a) 162
(B) b) 138
(C) c) 16
(D) d) 38
(E) e) 12
Rationale: Passed in english = 65%
Passed in maths = 55%
Passed in both = 40% of 55% = 2/5 * (55%) = 22%
Passed in (English + Maths - Both + Neither) = 100%
65 + 55 - 22 + Neither = 100
Neither = 100 - 98 = 2% = 0.02 * 800 = 16
Answer: C
Answer: (C) c) 16
Question: A person was asked to state his age in years. His reply was , "Take my age 4 years hence, multiply it by 4 and subtract 4 times my age 4 years ago and you will know how old I am." What was the age of the person ?
(A) 18
(B) 32
(C) 27
(D) 26
(E) 19
Rationale: Explanation:
Let the present age of person be x years.
Then, 4(x + 4) - 4(x - 4 ) = x <=> (4x + 16) - (4x - 16) = x <=> x = 32..
Answer: B
Answer: (B) 32
Question: A, B, C subscribe Rs. 50,000 for a business. If A subscribes Rs. 4000 more than B and B Rs. 5000 more than C, out of a total profit of Rs. 39,000, what will be the amount A receives?
(A) 14700
(B) 14500
(C) 14900
(D) 16380
(E) 14000
Rationale: Total amount invested = 50000
Assume that investment of C =x.
Then investment of B =5000+x,
Investment of A =4000+5000+x=9000+x
x+5000+x+9000+x=50000
⇒3x+14000=50000
⇒3x=50000–14000=36000
⇒x=36000/3=12000
Investment of C =x=12000
Investment of B =5000+x=17000
Investment of A =9000+x=21000
Ratio of the investment of A, B and C
=21000:17000:12000
=21:17:12
Share of A = Total profit ×21/50
=39000×21/50=16380
Answer is D
Answer: (D) 16380
Question: The average weight of 6 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
(A) 76 kg
(B) 80 kg
(C) 85 kg
(D) Data inadequate
(E) None of these
Rationale: Explanation:
Total weight increased = (6 x 2.5) kg = 15 kg.
Weight of new person = (65 + 15) kg = 80 kg.
Answer: B
Answer: (B) 80 kg
Question: Find the cost of fencing around a circular field of diameter 14 m at the rate of Rs.2.50 a meter?
(A) 288
(B) 110
(C) 772
(D) 592
(E) 261
Rationale: 2 * 22/7 * 7 = 44
44 * 2.5 = Rs.110
Answer: B
Answer: (B) 110
Question: Winson earns $10.00 per hour for the first 40 hours he works per week, and twice this rate for overtime. If Michael earned $363 last week, how many hours did he work?
(A) 43
(B) 44
(C) 45
(D) 46
(E) 47
Rationale: $10*40 + $12*x = $363 --> x = 3 hours.
Total working hours = 40 + 3 = 43.
Answer: A.
Answer: (A) 43
Question: The ratio between the present ages of P and Q is 6 : 7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years?
(A) 3 : 4
(B) 3 : 5
(C) 4 : 3
(D) 7 : 8
(E) None
Rationale: Sol.
Let P's age and Q's age be 6x years and 7x years respectively.
Then, 7x - 6x = 4 ⇔ x = 4.
∴ Required ratio = (6x + 4) : (7x + 4) = 28 : 32 = 7 : 8.
Answer D
Answer: (D) 7 : 8
Question: The radius of a circle is 4/π cm then its perimeter is?
(A) 10
(B) 9
(C) 8
(D) 12
(E) 15
Rationale: perimeter=2πr
2π*4/π=8 cm
Answer: C
Answer: (C) 8
Question: There are n cities. What is the number of airlines that connected 3 different cities (airline from city A to city B is different with airline from city B to city A)?
(A) n(n-1)
(B) n(n+1)
(C) n(n-1)/2
(D) n(n+1)/2
(E) n(n-2)
Rationale: First of all, the possible number of airlines is n. Then, the possible number of airlines departing from one city to another becomes (n-2). Hence, the answer is n(n-2), which makes A an answer choice.
E
Answer: (E) n(n-2)
Question: The average of non-zero number and its square is 5 times the number. The number is?
(A) 9
(B) 37
(C) 98
(D) 8
(E) 2
Rationale: Let the number be x. Then,
(x + x2)/2 = 5x => x2 - 9x = 0
=> x(x - 9) = 0
=> x = 0 or x = 9
So, the number is 9.
Answer:A
Answer: (A) 9
Question: Find the annual income derived by investing $ 6800 in 60% stock at 136.
(A) 550
(B) 3000
(C) 250
(D) 300
(E) 400
Rationale: By investing $ 136, income obtained = $ 60.
By investing $ 6800, income obtained = $ [(60/136)*6800] = $ 3000.
Answer B.
Answer: (B) 3000
Question: If ab^2c = b^4 , which of the following must be true?
I. ac = b^2
II. b = 0
III. ac = 1
(A) none
(B) I
(C) II
(D) III
(E) I &II
Rationale: to fulfill conditions some assumptions are to be made b#0 etc.
A
Answer: (A) none
Question: A is thrice as good a workman as B and therefore is able to finish a job in 70 days less than B. working together, they can do it in
(A) days
(B) ½ days
(C) days
(D) days
(E) 1/4 days
Rationale: Explanation:
B = 3A
3A – A =70 days
A = 35days
Then, B = 90 days
(A + B) = 35 × 90/ 120 = 26 1/4 days .
Answer: Option E
Answer: (E) 1/4 days
Question: 15 men take 20 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men?
(A) 27.57
(B) 28.57
(C) 29.57
(D) 30.57
(E) 32
Rationale: 3W = 2M
15M ------ 20 * 8 hours
21 W ------ x * 6 hours
14 M ------ x * 6
15 * 20 * 8 = 14 * x * 6
x = 28.57
ANSWER:B
Answer: (B) 28.57
Question: The length of a train and that of a platform are equal. If with a speed of 108 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
(A) 757
(B) 758
(C) 718
(D) 900
(E) 738
Rationale: Speed = [108 * 5/18] m/sec = 30 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 30 è x = 30 * 60 / 2
=900
Answer:D
Answer: (D) 900
Question: Mark has a rectangular driveway with a line painted diagonally across. The length of the driveway is 5 feet longer than its width. If the total area of the driveway is 36 square feet, what is the length of the painted line (in feet)?
(A) between 9 and 10
(B) between 10 and 11
(C) between 11 and 12
(D) between 12 and 13
(E) between 13 and 14
Rationale: To solve this, we first need to set up an equation for the area of the room. If x is the width, then we have
x(x + 5) = 36. By putting the equation in standard form, we get x^2+5x-36=0. By using the quadratic formula, we get roots of 4 and -9. We know that x is the width, and x+5 is the length, so by using the roots, we get 4 as the width (x), and 9 as the length (x+5).
Once we have this, we can use the Pythagorean Theorem to solve for the diagonal. Plugging in the length and width, we will get d^2=4^2+9^2
=16+81
=97
The square root of 97 is less than 10, since 10^2 = 100. Going down a number, we can compute 9^2 = 81 < 97. Therefore, the length of the diagonal must be between 9 and 10.
The correct answer is A.
Answer: (A) between 9 and 10
Question: Find the value of y from (12)^3 x 6^4 ÷ 432 = y?
(A) 3446
(B) 2345
(C) 5467
(D) 4767
(E) 5184
Rationale: Given Exp. = (12)3 x 64 = (12)3 x 64 = (12)2 x 62 = (72)2 = 5184
432 12 x 62
E
Answer: (E) 5184
Question: The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?
(A) 18 cm
(B) 20 cm
(C) 24 cm
(D) 28 cm
(E) 38 cm
Rationale: 2(l + b) = 5
b 1
2l + 2b = 5b
3b = 2l
b = 2 l
3
Then, Area = 216 cm2
l x b = 216
l x 2 l = 216
3
l2 = 324
l = 18 cm.
A)
Answer: (A) 18 cm
Question: Nitin ranks 12th in a class of 56 students. What is rank from the last ?
(A) 33
(B) 38
(C) 45
(D) 28
(E) 19
Rationale: Explanation:
Number students behind the nitin in rank = (56 - 12) = 44
Nitin is 45th from the last
Answer: C) 45
Answer: (C) 45
Question: In a college students can play cricket or basketball. 500 play cricket.220 played both and 600 played basketball. What is the total strength of college?
(A) 800
(B) 880
(C) 920
(D) 950
(E) 980
Rationale: P(C)= 500
P(B)=600
P(C n B) =220
P(C U B)= P(C)+ P(B) - P(C n B)
= 500+600-220= 880
ANSWER:B
Answer: (B) 880
Question: Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is?
(A) 65
(B) 67
(C) 70
(D) 72
(E) 85
Rationale: Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
A.	75
B.	81
C.	85
D.	89
Answer: Option C
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
First number = 551 = 19; Third number = 1073 = 37.
29	29
Required sum = (19 + 29 + 37) = 85
E)
Answer: (E) 85
Question: A and B started a partnership business investing Rs. 20,000 and Rs. 15,000 respectively. C joined them with Rs. 20,000 after six months. Calculate B's share in total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business?
(A) 7500
(B) 8500
(C) 9000
(D) 8000
(E) 7000
Rationale: Explanation:
A : B : C
=20000×24:15000×24:20000×18
=20×4:15×4:20×3
=4×4:3×4:4×3
=4:3:3
B's share = 25000×3/10=7500
Answer: Option A
Answer: (A) 7500
Question: Find the invalid no.from the following series 15, 16, 34, 104, 424, 2124, 12756
(A) 16
(B) 34
(C) 104
(D) 424
(E) 2124
Rationale: 2nd term = (1st term) * 1 + 1 = 15 *1 + 1 = 16.
3rd term = (2nd term) * 2 + 2 = 16 * 2 + 2 = 34
4th term = (3th term) *3 + 3 = 34 * 3 + 3 = 105
5th term = (4th term) * 4 + 4 = 105 * 4 + 4 = 424
6th term = (5th term) * 5 + 5 = 424 * 5 + 5 = 2125
4th term should 105 instead of 104.
C
Answer: (C) 104
Question: With what number must 1020.5 be multiplied in order to obtain the number10205?
(A) 10
(B) 1,000
(C) 10,000
(D) 100,000
(E) None of these
Rationale: Explanation: The decimal must be moved one places to the right. To do this, we must multiply by a number with one zeroes. The correct answer is 10.The decimal must be moved one places to the right. To do this, we must multiply by a number with one zero. The correct answer is 10.
Answer : (A)
Answer: (A) 10
Question: Find the average of the series : 120, 148, 420, 150 and 162?
(A) 174
(B) 240
(C) 200
(D) 202
(E) 230
Rationale: Average = (120 + 148 + 420 + 150 + 162)/5
= 1000/5
= 200
Answer: C
Answer: (C) 200
Question: What will come in place of the x in the following Number series? 279936, 46656, 7776, 1296, 216, x
(A) 30
(B) 31
(C) 36
(D) 38
(E) 42
Rationale: Go on dividing by 6 to the next number
C)
Answer: (C) 36
Question: In a certain game there are 8 steps, referred to as step 1, step 2, and so on with the final step being step 8. The steps are played one after the other. In each step a score of 1, 2, 3, 4, or 5 is obtained. Andrea played the game, getting at least one score of each of 1, 2, 3, 4, and 5, and never getting the same score in consecutive steps. What is the greatest possible score that Andrea could have gotten?
(A) 28
(B) 29
(C) 30
(D) 36
(E) 40
Rationale: There are two conditions:
1. Andrea got at least one score of each of 1, 2, 3, 4, and 5.
2. She never got the same score in consecutive steps.
Taking that into account, the greatest possible score that Andrea could have gotten is 5 + 1 + 5 + 2 + 5 + 3 + 5 + 4 = 30.
Answer: C.
Answer: (C) 30
Question: By selling an umbrella for Rs. 300, a shop keeper gains 100%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?
(A) 23.23
(B) 32.32
(C) 33.33
(D) 30
(E) 31
Rationale: Marked price = Rs. 200
C.P. = 100/100 * 300 = Rs. 300
Sale price = 90% of Rs. 300 = Rs. 270
Required gain % = 100/300 * 100 = 33.33%.
Answer:C
Answer: (C) 33.33
Question: In a family with 3 children, the parents have agreed to bring the children to the pet store and allow each child to choose a pet. This pet store sells only dogs, cats, and monkeys. If each child chooses exactly one animal, and if more than one child can choose the same kind of animal, how many different arrangements of animals could the family leave with?
(A) 6
(B) 8
(C) 9
(D) 10
(E) 12
Rationale: The question has a catch.. It would seem on the face of it it would be 3 x 3 x3 = 27 arrangements, but what it is asking is how many arrangements the family leaves with.. so that is going to be
Pick all 3 = 1 way
Pick all of a kind = 3 x 1 = 3 ways
Pick 2 of a kind = 3 x 1 x 2 = 6 ways
Total of 10
ANS:D
Answer: (D) 10
Question: how many feet is 24 inches
(A) 6
(B) 3
(C) 2
(D) 8
(E) 9
Rationale: C
Answer: (C) 2
Question: If x, y, and z are consecutive positive odd integers, not necessarily in that order, which of the following must be true? I. xz > y^2 II. (x + z)^3 > y III. x+y>z^2
(A) I only
(B) I,II only
(C) II,III only
(D) III only
(E) II only
Rationale: Lets suppose that a,b,c can take any one of following three value 1,5,7. Most important point is that the options MUST BE TRUE under any condition.
x+y>z^2
Not necessarily true as 1+5<49
xz>y^2
Not necessarily true as 1.7<25
We don't need to check option as all the options except E can be discarded.
Thus Answer E
Answer: (E) II only
Question: Two pipe fill a empty tank in 14 hours and 16 hours respectively.when both pipe open together then it came to know that because of a hole in a tank it takes 32 more minutes to fill the tank.then in how much time that hole take to empty the full tank?
(A) 125
(B) 106
(C) 85
(D) 112
(E) 76
Rationale: both pipe filling work in 1 hour=[1/14+1/16]=15/112
so,time both pipe take to full the tank =112/15hour=7hour28minute
because of hole time taken to fill the tank=7 hour 28 minutes+32 minute=8 hour
all three resultant work in 1 hour=1/8
hole 1 hour empty work=[15/112-1/8]=1/112
so time taken to empty the full tank=112 hours
answer D
Answer: (D) 112
Question: Without stoppages, a train travels certain distance with an average speed of 200 km/h, and with stoppages, it covers the same distance with an average speed of 160 km/h. How many minutes per hour the train stops ?
(A) 8
(B) 9
(C) 10
(D) 11
(E) 12
Rationale: Due to stoppages, it covers 40 km less .
Time taken to cover 40 km = 40â„200h = 1â„5h
= 1â„5 Ã— 60 min = 12 min
Answer E
Answer: (E) 12
Question: Number of ways in which the letters of word PARTE can be arranged with vowels in alphabetical order, is
(A) 360
(B) 240
(C) 120
(D) 480
(E) 60
Rationale: Solution
Order of vowels of fixed
âˆ´ required number of ways are 5!/2!.
Answer E
Answer: (E) 60
Question: find which among the integer numbers is the sum of 3 consecutive even integers?
(A) 200
(B) 303
(C) 400
(D) 554
(E) 576
Rationale: Sum of three consecutive Even Integers must be a multiple of 2 as well as a multiple of 3 because such a sum is always 3 times the middle number (applicable to all equally spaced numbers)
Divisibility of 3: Sum of the digits of the number must be divisible by 3
Divisibility of 2: Unit digit of the number must be divisible by 2
A. 200NOT A MULTIPLE OF 3 SO RULED OUT
B. 303NOT A MULTIPLE OF 2 SO RULED OUT
C. 400NOT A MULTIPLE OF 3 SO RULED OUT
D. 554NOT A MULTIPLE OF 3 SO RULED OUT
E. 576A MULTIPLE OF BOTH 2 AND 3 SO THE CORRECT ANSWER!!!
Answer: (E) 576
Question: If 60 J of energy are available for every 15 C of charge, what is the voltage?
(A) 4V
(B) 3V
(C) 7V
(D) 9
(E) 2
Rationale: Explanation:
No answer description available for this question
Answer: Option A
Answer: (A) 4V
Question: The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?
(A) 288
(B) 277
(C) 342
(D) 662
(E) 262
Rationale: 400*(90/100)*(95/100)
= 342
Answer: C
Answer: (C) 342
Question: A boat moves upstream at the rate of 1 km in 25 minutes and down stream 1 km in 12 minutes. Then the speed of the current is :
(A) 1 kmph
(B) 2 kmph
(C) 3 kmph
(D) 1.3 kmph
(E) 3.5 kmph
Rationale: Rate upstream = (1/25 *60) = 2.4 kmph
Rate dowm stream = 1/12 * 60 = 5 kmph
Rate of the current = ½ (5-2.4) = 1.3 kmph
ANSWER:D
Answer: (D) 1.3 kmph
Question: The length of the room is 5.5m and width is 3.75m. Find the cost of paving the floor by slabs at the rate of Rs.800 per sq meter
(A) rs.16500
(B) rs.15500
(C) rs.17500
(D) rs.18500
(E) None of these
Rationale: Explanation:
l=5.5m w=3.75m
area of the floor = 5.5 * 3.75 = 20.625 sq m
cost of paving = 800 *20.625 =Rs. 16500 Answer: A
Answer: (A) rs.16500
Question: In a division, a student took 78 as divisor instead of 36. his answer was 24 . The correct answer is-
(A) 42
(B) 32
(C) 48
(D) 52
(E) 38
Rationale: X/78 = 24.
X = 24 *78.
So correct answer would be,
(24 *78) /36 = 52.
ANSWER : D
Answer: (D) 52