mathewhe/aqua_rat huggingface dataset:
Question: Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank?
(A) 10 min. 20 sec.
(B) 11 min. 45 sec.
(C) 12 min. 30 sec.
(D) 14 min. 40 sec.
(E) 15 min. 40 sec.
Rationale: Take LCM of 15 and 20 and get the total capacity of tank as 60 .
Then A will fill 4li in 1 min and B will fill 3 li in 1 min so total will be 7 . A left after 4 min so they worked together for 4 min so 7*4= 28 . now subtract it from 60.(60-38=32). This will be filled by b so time taken would be..10 min 20 sec.
ANSWER:A
Answer: (A) 10 min. 20 sec.
Question: The probability that a man will be alive for 10more yrs is 1/4 & the probability that his wife will alive for 10 more yrs is 1/3. The probability that none of them will be alive for 10 more yrs, is
(A) 1/2
(B) 2
(C) 2/3
(D) 4/5
(E) 5/7
Rationale: Sol. Required probability = Pg.) x P(B) = (1— D x(1 —I) =: x 1=1/2
Ans.(A)
Answer: (A) 1/2
Question: The speed of a train is 90 kmph. What is the distance covered by it in 10 minutes?
(A) 15 kmph
(B) 17 kmph
(C) 18 kmph
(D) 19 kmph
(E) 12 kmph
Rationale: 90 * 10/60
= 15 kmph
Answer: A
Answer: (A) 15 kmph
Question: The simple interest accrued on an amount Rs.10,000 at the end of two years is same as the compound interest on Rs.8,000 at the end of two years. The rate of interest is same in both the cases. What is the rate of interest?
(A) 57%
(B) 60%
(C) 58%
(D) 50%
(E) 20%
Rationale: Given that Rs.10,000 is invested in S.I for two years and Rs.8,000 in C.I for two years
=> C.I - S.I
=> 8,000 { [1 + r/100]2 - 1} = (10,000)2r /100
=> 8{ 1 + 2r/100 + r2 / (100)2 - 1} = r/5
=> 16r/100 + 8r2/(100)2 = 20r/100
=> 4r/10 = 8r2/(100)2
=> 8[r/100]2 - 4r/100 = 0
=> r/100 {8r/100 -4} = 0
=> r = 0% of 50%
Since r!= 0%, r =50%
Answer:D
Answer: (D) 50%
Question: The present age of a father is 3 years more than three times the age of his son. Three years hence, father's age will be 16 years more than twice the age of the son. Find the present age of the father.
(A) 33
(B) 38
(C) 29
(D) 51
(E) 48
Rationale: if the present age be x years.
father's will be (3x+3)years..
so, (3x+3+3)=2(x+3)+16
or, x=16
so the fathers present age =(3x+3)=(3*16+3)years =51years..
ANSWER : OPTION D
Answer: (D) 51
Question: For every order, a certain mail-order company charges a shipping fee of $3 plus an additional $2 if the value of the order is over $50 but not over $100 or an additional $3 if the value of the order is over $100. How much greater are the total shipping fees for 2 orders of $75 each than the total shipping fee for 2 order of $150 ?
(A)  $1
(B)  $2
(C)  $3
(D)  $4
(E)  $5
Rationale: Total cost involved for each 75 $ shipment: 3+2 = 5 $. Thus, for two such orders = 10$
Total cost involved for a 150$ shipment: 3+3 = 6$. Thus, for two such orders = 12$
The difference = 2$.
B.
Answer: (B)  $2
Question: The average height of 60 pupils in a class is 150 cm. Five of them whose height is 146 cm, leave the class and five others whose average height is 156 cm, join. The new average height of the pupils of the class (in cm) is ?
(A) 287 cm
(B) 150.8 cm
(C) 276 cm
(D) 287 cm
(E) 297 cm
Rationale: Total height = 150 * 60 = 9000 cm.
New average = [9000 - 5 * 146 + 5 * 156 ] / 60
= 150.8 cm.
Answer:B
Answer: (B) 150.8 cm
Question: The sale price shirts listed for Rs.400 after successive discount is 10% and 5% is?
(A) 280
(B) 290
(C) Rs.342
(D) 250
(E) 253
Rationale: 400*(90/100)* (95/100) = 342
C
Answer: (C) Rs.342
Question: If the price of gasoline increases by 25% and a driver intends to spend only 10% more on gasoline, by how much percent should the driver reduce the quantity of gasoline that he buys?
(A) 5%
(B) 8%
(C) 10%
(D) 12%
(E) 15%
Rationale: Let x be the amount of gasoline the driver buys originally.
Let y be the new amount of gasoline the driver should buy.
Let P be the original price per liter.
(1.25*P)y = 1.1(P*x)
y = (1.1/1.25)*x = 0.88x which is a reduction of 12%.
The answer is D.
Answer: (D) 12%
Question: A bus travel 5/7 of its speed covers 42 km in 1 hr 40 min48 sec. What is theactual speed of the bus ?
(A) 20 km/hr
(B) 35 km/hr
(C) 40 km/hr
(D) 53 km/hr
(E) 55 km/hr
Rationale: Time = 1 hr 40 min 48 sec = 1hr +4060hr+483600hr=1+23+175=12675hrdistance = 42 kmspeed=distancetime=42(12675)=42×75126⇒57 of the actual speed = 42×75126⇒actual speed = 42×75126×75=42×1518=7×153=7×5=35 km/hr
B
Answer: (B) 35 km/hr
Question: A tank is 25% full of oil. The oil consists of 25% WTI Crude Oil and 75% Brent Crude Oil. 2/3 rd of the remainder of the tank is filled with 400 barrels of WTI Crude Oil. How much WTI Crude Oil is in the tank?
(A) 425 barrels
(B) 437.5 barrels
(C) 450 barrels
(D) 500 barrels
(E) 650 barrels
Rationale: The tank was 25% full. Then, 2/3 rd of the remainder of the tank, so 2/3 rd of 75% of the tank, was filled with 400 barrels of WTI Crude Oil. 2/3 rd of 75% is 50%, thus we are told that 50% of the tank amounts for 400 barrels, which makes the capacity of the tank 800 barrels.
Therefore, initially, the tank had 0.25∗0.25∗800=500 barrels of WTI Crude Oil. After 400 barrels of WTI Crude Oil were added the amount of WTI Crude Oil became 50+400=450 barrels.
Answer: C.
Answer: (C) 450 barrels
Question: What is the maximum value of x3y3 + 3 x*y when x+y = 8?
(A) 4144
(B) 4122
(C) 455
(D) 4189
(E) 4156
Rationale: The question probably be x3.y3+3x∗yx3.y3+3x∗y
Sustitute x = 4 and y = 4
Option A
Answer: (A) 4144
Question: A sum of money at simple interest amounts to Rs. 845 in 3 years and to Rs. 854 in 4 years. The sum is:
(A) s. 650
(B) s. 690
(C) s. 698
(D) s. 700
(E) s. 728
Rationale: S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (845 - 117) = Rs. 728.
Answer: Option E
Answer: (E) s. 728
Question: In the set of positive integers from 1 to 70, what is the sum of all the odd multiples of 5?
(A) 180
(B) 245
(C) 240
(D) 200
(E) 190
Rationale: reduce 1 - 70
5 - 15 - 25 - 35 - 45 +55+ 65 are valid multiples 0f 5 . Add them --> 245
B
Answer: (B) 245
Question: If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be?
(A) 4 days
(B) 8 days
(C) 6 days
(D) 5 days
(E) 3 days
Rationale: Let 1 men's 1 day work = x and 1 boy's 1 day work = y.
Then, 6x + 8y = 1/10 and 26x + 48y = 1/2
Solving these two equations, we get:
x = 1/100 and y = 1/200
(15 men + 20 boys)'s 1 day work = (15/100 + 20/200) = 1/4
15 men and 20 boys can do the work in 4 days.
Answer: A
Answer: (A) 4 days
Question: David has d books, which is 3 times as many as Jeff and 2/3 as many as Paula. How many books do the three of them have altogether, in terms of d?
(A)  5/6*d
(B)  7/3*d
(C)  17/2*d
(D)  7/2*d
(E)  9/2*d
Rationale: Although we could plug in a real value for d, the problem can be just as easily solved by setting up equations. However, let’s start by defining some variables. Since we are given that David has d books, we can use variable d to represent how many books David has.
number of books David has = d
number of books Jeff has = j
number of books Paula has = p
We are given that David has 3 times as many books as Jeff. We can now express this in an equation.
d = 3j
d/3 = j
We are also given that David has ½ as many books as Paula. We can also express this in an equation.
d = (2/3)p
3d/2 = p
Notice that we immediately solved forj in terms of d and p in terms of d. Getting j and p in terms of d is useful when setting up our final expression. We need to determine, in terms of d, the sum of the number of books for David, Jeff, and Paula. Thus, we have:
d + d/3 + 3d/2
=17d/2
The answer is C.
Answer: (C)  17/2*d
Question: A can do a piece of work in 10 days. He works at it for 4 days and then B finishes it in 9 days. In how many days can A and B together finish the work?
(A) 6
(B) 8
(C) 12
(D) 15
(E) 20
Rationale: 4/10+9/X = 1/x = 15
1/10+1/15 = 1/6 = 6 days
ANSWER A
Answer: (A) 6
Question: A bat is bought for Rs.400 and sold at a gain of 20% find its selling price
(A) Rs.480/-
(B) Rs.500/-
(C) Rs.520/-
(D) Rs.540/-
(E) Rs.560/-
Rationale: 100 % ------> 400 (100 * 4 = 400)
120 % ------> 480 (120 * 4 = 480)
Selling price = Rs.480/-
A
Answer: (A) Rs.480/-
Question: If the number is divided by 3, it reduced by 34. The number is
(A) 51
(B) 50
(C) 45
(D) 40
(E) 36
Rationale: Explanation:
Let the number be x. Then,
x - (x/3) = 34 => 2x/3 = 34
=> x = 51
Answer: Option A
Answer: (A) 51
Question: As a treat for her two crying children, a mother runs to the freezer in which she has three cherry ice pops, three orange ice pops, and four lemon-lime ice pops. If she chooses two at random to bring outside to the children, but realizes as she runs out the door that she cannot bring them different flavors without one invariably being jealous of the other and getting even more upset, what is the probability that she has to return to the freezer to make sure that they each receive the same flavor?
(A) 1/9
(B) 1/6
(C) 5/18
(D) 11/120
(E) 5/6
Rationale: Probability of not getting the same flavor ->
Favorable -> Cherry - orange [ 3C1 * 3C1 [or simply 3*3 ] or Cherry - lemon [ 3*4] or orange - lemon [3*4]
Prob = (3*3 + 3*4 + 3*4 ) / 9C2 = 33/360 = 11/120
Answer -> D
Answer: (D) 11/120
Question: If 2^z is a factor of 30!, which of the following could be the value of z?
I. 23
II. 26
III. 24
(A) I ONLY
(B) II ONLY
(C) BOTH I AND II
(D) III ONLY
(E) NONE OF THE ABOVE
Rationale: 2^z is a factor of 30!, what values can z take.
Powers of 2 in 30! = [30/2] + [30/4] +[30/8] + [30/16] , where [x] is the integral part of x
Powers of 2 in 30! = 15 + 7 + 3 + 1 = 26
Hence the maximum value of 2^z in 30! = 2^26
Only Statement II satisfies
Correct Option: B
Answer: (B) II ONLY
Question: If 4 (P's Capital) = 6 (Q's Capital) = 10 (R's Capital), then out of the total profit of Rs 4650, how much R will receive?
(A) 300
(B) 600
(C) 900
(D) 800
(E) 500
Rationale: Let P's capital be p,
Q's capital be q,
and R's capital be r
Then
4p=6q=10r2p=3q=5r⋯(A)
From (A),
q=2p/3 ⋯(1)
r=2p/5 ⋯(2)
p:q:r=p:2p/3:2p/5
=15:10:6
R's share =4650×6/31=150×6=900
Answer is C.
Answer: (C) 900
Question: How many four letter words are formed using the letters of the word ENTERTAINMENT?
(A) 1716
(B) 1616
(C) 1816
(D) 1516
(E) 1761
Rationale: The number of letters in the given word is thirteen.
The number of four letter words that can be formed using these thirteen letters is 13P4
= 13 * 12 * 11 = 1716.
Answer: A
Answer: (A) 1716
Question: What will be the difference between simple and compound interest at 10% per annum on a sum of Rs. 1000 after 4 years?
(A) Rs.64.18
(B) Rs.64.67
(C) Rs.64.08
(D) Rs.64.10
(E) Rs.64.22
Rationale: S.I. = (1000 * 10 * 4)/100 = Rs. 400
C.I. = [1000 * (1 + 10/100)4 - 1000]
= Rs. 464.10 Difference
= (464.10 - 400)
= Rs. 64.10
Answer: D
Answer: (D) Rs.64.10
Question: In a certain animal shelter, the ratio of the number of catsto the number of dogs is 15 to 7. If 16 additional dogs were to be taken in by the shelter, the ratio of the number of cats to the number of dogs would be 15 to 11. How many cats are in the shelter?
(A) 15
(B) 25
(C) 30
(D) 45
(E) 60
Rationale: This ratio question can be solved in a couple of different ways. Here's an Algebraic approach...
We're told that the ratio of the number of cats to the number of dogs is 15:7. We're then told that 16 more dogs are added to this group and the ratio becomes 15:11. We're asked for the number of cats.
Algebraically, since the number of cats is a multiple of 15 and the number of dogs is a multiple of 7, we can write this initial relationship as...
15X/7X
When we add the 16 cats and factor in the 'ending ratio', we have an equation....
15X/(7X+16) = 15/11
Here we have 1 variable and 1 equation, so we can solve for X....
(15X)(11) = (7X+16)(15)
(X)(11) = (7X+16)(1)
11X = 7X + 16
4X = 16
X = 4
With this X, we can figure out the initial number of dogs and cats...
Initial dogs = 15X = 15(4) = 60
Final Answer: D
Answer: (D) 45
Question: In the new budget the price of ghee rose by 50%. By how much percent must a person reduce his consumption so that his expenditure on it does not increase?
(A) 7.5%
(B) 9.1%
(C) 10.9%
(D) 12.6%
(E) 33.33%
Rationale: Reduce in consumption = R/(100+R) *100% = 50/150 *100 =33.33%
Answer is E
Answer: (E) 33.33%
Question: A train 400 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
(A) 298 m
(B) 279 m
(C) 500 m
(D) 289 m
(E) 900 m
Rationale: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (400 + x)/60 = 65/3
x = 900 m.
Answer: E
Answer: (E) 900 m
Question: The compound interest earned on a sum for the second and the third years are $1400 and $1498 respectively. What is the rate of interest?
(A) 3%
(B) 5%
(C) 7%
(D) 9%
(E) 11%
Rationale: 1498 - 1400 = 98 is the rate of interest on $1400 for one year.
The rate of interest = (100 * 98) / (1400) = 7%
The answer is C.
Answer: (C) 7%
Question: Ashok secured average of 78 marks in 6 subjects. If the average of marks in 5 subjects is 74, how many marks did he secure in the 6th subject?
(A) 66
(B) 74
(C) 78
(D) 98
(E) None of these
Rationale: Explanation:
Number of subjects = 6
Average of marks in 6 subjects = 78
Therefore total marks in 6 subjects = 78 * 6 = 468
Now, No. of subjects = 5
Total marks in 5 subjects = 74 * 5 = 370
Therefore marks in 6th subject = 468 – 370 = 98
ANSWER D
Answer: (D) 98
Question: Six bells start ringing together and ring at intervals of 4, 8, 10, 12, 15 and 20 seconds respectively. How many times will they ring together in 60 minutes ?
(A) 5
(B) 11
(C) 21
(D) 31
(E) 32
Rationale: LCM of 4, 8, 10, 12, 15 and 20 = 120 seconds = 2 minutes
That means All the six bells will ring together in every 2 minutes
Number of times they will ring together in 60 minutes =1+60/2=31
Answer :D
Answer: (D) 31
Question: y = 248 - 390x
Which of the following values of x gives the greatest value of y in the equation above?
(A)  200
(B)  100
(C)  0.5
(D)  -2
(E)  -1
Rationale: Clearly, the negative value of x will result in maximum value of y.
Answer is D
Answer: (D)  -2
Question: 21 ball numbered 1 to 21. A ballis drawn and then another ball is drawn without replacement.
(A) 1/42
(B) 3/41
(C) 9/42
(D) 5/44
(E) 5/47
Rationale: The probability that first toy shows the even number,
=1021=1021
Since, the toy is not replaced there are now 9 even numbered toys and total 20 toys left.
Hence, probability that second toy shows the even number,
=920=920
Required probability,
=(1021)×(920)=(1021)×(920)
=9/42
C
Answer: (C) 9/42
Question: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?
(A) 6
(B) 4
(C) 8
(D) 2
(E) 3
Rationale: M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9
= 4
Answer: B
Answer: (B) 4
Question: A, Band C are three contestants in a kmrace. If A can give B a start of 40 m and A can give C a start of 64m how many metre's start can B give C ?.
(A) 540 m
(B) 178 m
(C) 936 m
(D) 234 m
(E) 713 m
Rationale: While A covers 1000 m, B covers (1000 - 40) m = 960 m and
C covers (1000 - 64) m or 936 m.
When B covers 960 m, C covers 936 m
Option C
Answer: (C) 936 m
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is
(A) 100
(B) 120
(C) 130
(D) 150
(E) 140
Rationale: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 25 = x / 15
x = 150 m.
Answer: Option D
Answer: (D) 150
Question: A man, a woman and a boy can complete a job in 3,4 and 12 days respectively.
How many boys must assist 1 man and 1 woman to complete the job in ¼ of a day?
(A) 41
(B) 50
(C) 22
(D) 33
(E) 14
Rationale: (1 man + 1 woman)'s 1 days work = 1/3+1/4=7/12
Work done by 1 man and 1 women n 1/4 day=((7/12)*(1/4))=7/48
Remaining work= 1- 7/48= 41/48
Work done by 1 boy in ¼ day= ((1/12)*(1/4)) =1/48
Therefore, Number of boys required= ((41/48)*48)= 41 days
ANSWER A
Answer: (A) 41
Question: Once upon a time in ancient times there was a king who was very found of wines. He had a huge cellar, which had 1000 different varieties of wine all in different caskets (1000 caskets in all). In the adjoining kingdom there was a queen who was envious of the king’s huge wine collection. After some time when she could not bear it any more show conspired to kill her by poisoning all his wine caskets. So she sent one sentry to poison all the caskets, but no sooner had the sentry poisoned only one wine casket, he was caught and killed by the Royal guards. Now the king had a major problem in his hand so as to identify the poisonous casket, which he gave to the Minister. But the situation had two peculiarities.
I: Any one who takes even one drop from the poisonous casket will die.
II: He will die only after one month.
The king also handed over few prisoners to the Minister as “taster” of those caskets, as their lives was of little value.
If the Minister is allowed only 1 month to find out the poisonous casket, what is the minimum number of prisoners he should use as “tasters”?
(A) 1023
(B) 1024
(C) 1025
(D) 1026
(E) 1027
Rationale: Sol:
Study the following table carefully. Each of the prisoners drinks wine from whichever casket has a 1 in his place. If he does not drink there is a 0.
So if no one dies, Casket 1 is poisoned.
If P1 dies, casket 2 is poisoned.
If P1 and P3 die ⇒⇒ casket 6 is poisoned and so on.
So, if there are 3 prisoners, we can differentiate upto 2323 =8 caskets.
So for 1000 caskets [even 1024 caskets], we need only 10 prisoners as 210210 = 1024
Answer B
Answer: (B) 1024
Question: Three numbers are in the ratio 3:5:7. The largest number is 21. What is the difference between smallest and largest number?
(A) 8
(B) 10
(C) 12
(D) 14
(E) 16
Rationale: The three numbers are 3x, 5x, and 7x.
The largest number is 21 = 7*3, so x = 3.
The smallest number is 3*3 = 9.
21 - 9 = 12
The answer is C.
Answer: (C) 12
Question: A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. If the smaller wheel has made 42 revolutions, what will be the number of revolutions made by the larger wheel?
(A) 15
(B) 12
(C) 21
(D) 9
(E) 18
Rationale: Explanation:
Let the number of revolutions made by the larger wheel be x
More cogs, less revolutions (Indirect proportion)
Hence we can write as
(cogs) 6 : 14 :: x : 42
â‡’6Ã—42=14 Ã— x
â‡’x = 18
Answer: Option E
Answer: (E) 18
Question: Shipment ------No. of Defective Chips/shipment---Total Chips in shipment
S2 -------------- 5 ------------------------ ----------------------12000
S3 -------------- 6 ----------------------------------------------- 18000
S4 -------------- 4 ----------------------------------------------- 16000
A computer chip manufacturer expects the ratio of the number of defective chips to be total number of chips in all future shipments equal to the corresponding ratio for shipmemts S1,S2,S3 and S4 comined as shown in the table above. What is the expected number T of defective chips in a shipment of 60000 chips?
(A) 14
(B) 20
(C) 22
(D) 24
(E) 25
Rationale: I agree with your solution = 20. But the question is:
There are different combination to get 60,000 chips. For example: 1*S3 + 2*S4 + 2*S2. In this way, we ship 60,000 chips with only 6 + 4*2 + 2*2 = 18 defective chips, better than the average of 20.
The question is to find the expected number T of defective chips, i guess it assume the minimum #, therefore it might not be 20.
Answer: (B) 20
Question: The number of new words that can be formed by rearranging the letters of the word 'UP' is ?
(A) 1
(B) 2
(C) 24
(D) 520
(E) 24
Rationale: Number of words which can be formed = 2! - 1
= 2 - 1
= 1.
Answer:A
Answer: (A) 1
Question: Mercy's income is 10 percent more than Timothy's income, and Timothy's income is 22 percent less than Ryan's income. What percent of Ryan's income is Mary's income?
(A) 81.5%
(B) 85.5%
(C) 82.5%
(D) 84.5%
(E) 80.5%
Rationale: Ryan's income = 100 (assume);
Timothy's income = 78 (22 percent less than Ryan's income);
Mercy's income = 85.5 (60 percent more than Timothy's income).
Thus, Mercy's income (85.5) is 85.5% of Ryan's income (100).
Answer: B
Answer: (B) 85.5%
Question: The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in metres) is:
(A) 400
(B) 525
(C) 750
(D) 850
(E) None
Rationale: Sol.
Speed = [90 * 5/18] m/sec = 25 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x metres.
Then, 2x/60 = 25 ⇔ x = 25 * 60 / 2 = 750
Answer C
Answer: (C) 750
Question: 16 men can do a piece of work in 16 days .4 days after they started the work, 8 more men joined them. How many days will they now take to complete the remaining work
(A) 7 days
(B) 8 days
(C) 9 days
(D) 10 days
(E) None of these
Rationale: Solution:Work done by 1 man in 1 day=1/(16*16)
Work completed by 16 men in 4 days= 4[1/(16*16)]*16=1/4
Remaining work= 1- 1/4= 3/4
Total men now= 16+ 8=24
24 men do 3/4 work
=>24*number of days*Work done by 1 man in 1 day=3/4
=>24*number of days* 1/(16*16)=3/4
=>number of days=8 days
Answer B
Answer: (B) 8 days
Question: A rectangular box measures internally 1.6 m long, 1 m broad and 60 cm deep. The number of cubical blocks each of edge 20 cm that can be packed inside the box is
(A) 30
(B) 60
(C) 120
(D) 150
(E) None
Rationale: Sol. Number of blocks =
160x100x60
20x20x20] = 120.
Answer C
Answer: (C) 120
Question: The present average age of a family of five members is 24 years. If the present age of the youngest member in the family is ten years, then what was the average age of the family at the time of the birth of the youngest member ? (Assume no death occurred in the family since the birth of the youngest)
(A) 27.5 years
(B) 17 years
(C) 17.5 years
(D) 16.5 years
(E) 15.5 years
Rationale: Present total age of the members = 24(5) = 120 years.
Present age of the youngest member = 10 years
Present total age of the remaining four members = 120 -10 = 110 years
Their average age at the time of the birth of the youngest member = [110 - (4 * 10)] / 4 = 17.5 years
ANSWER:C
Answer: (C) 17.5 years
Question: In a partnership between A, B and C. A's capital is Rs.5500. If his share of a profit of Rs.800 is Rs.200 and C's share is Rs.130, what is B's capital?
(A) 23676
(B) 19766
(C) 29172
(D) 12925
(E) 11267
Rationale: Explanation:
200 + 130 = 330
800 - 330 = 470
200 ---- 5500
470 ---- ? => 12925
Answer:D
Answer: (D) 12925
Question: Virginia, Adrienne, and Dennis have taught history for a combined total of 96 years. If Virginia has taught for 9 more years than Adrienne and for 12 fewer years than Dennis, for how many years has Dennis taught?
(A)  23
(B)  32
(C)  35
(D)  41
(E)  42
Rationale: Let number of years taught by Virginia = V
number of years taught by Adrienne = A
number of years taught by Dennis = D
V+A+D = 96
V= A+9
=>A = V-9
V= D-12
=> A = (D-12)-9 = D-21
D-9 + D-21 + D = 96
=> 3D = 96 + 30 = 126
=> D = 42
Answer E
Answer: (E)  42
Question: Today Jim is twice as old as Fred, and Sam is 2 years younger than Fred. Seven years ago Jim was 13 times as old as Sam. How old is Jim now?
(A) 8
(B) 12
(C) 16
(D) 20
(E) 24
Rationale: We're asked how old Jim is NOW. We're given three facts to work with:
1) Today, Jim is TWICE as old as Fred
2) Today, Sam is 2 years younger than Fred
3) 7 years ago, Jim was 13 times as old as Sam.
let's TEST Answer D: 20
IF....Jim is currently 20 years old....
Fred is 10 years old
Sam is 8 years old
7 years ago, Jim was 13 and Sam was 1, so Jim WAS 13 times Sam's age. This is an exact MATCH for what we were told, so this MUST be the answer.
D
Answer: (D) 20
Question: In how many different ways can the letters B, E, N, E, F, I, C, I, A, L be arranged?
(A) 10×9×8×7×6×5×3×2
(B) 10×9×8×7×6×5×4×3
(C) 8!
(D) 9!
(E) 10!
Rationale: Number of ways of arranging BENEFICIAL = 10! / 2! * 2! = 10×9×8×7×6×5×3×2. Hence A
Answer: (A) 10×9×8×7×6×5×3×2