mathewhe/aqua_rat huggingface dataset:
Question: A woodworker normally makes a certain number of parts in 24 days. But he was able to increase his productivity by 5 parts per day, and so he not only finished the job in only 22 days but also he made 80 extra parts. How many parts does the woodworker normally makes per day and how many pieces does he make in 24 days?
(A) 360
(B) 350
(C) 340
(D) 370
(E) 380
Rationale: Let x be the number of parts the woodworker normally makes daily. In 24 days he makes 24⋅x pieces. His new daily production rate is x+5 pieces and in 22 days he made 22⋅(x+5) parts. This is 80 more than 24⋅x. Therefore the equation is:
24⋅x+80=22(x+5)
30=2x
x=15
Normally he makes 15 parts a day and in 24 days he makes 15⋅24=360 parts.
So answer is A.
Answer: (A) 360
Question: A vendor bought bananas at 6 for Rs.10 and sold them at Rs.4 for Rs.6 .Find his gain or loss percent .
(A) 13%
(B) 10%
(C) 47%
(D) 36%
(E) 52%
Rationale: Suppose , number of bananas bought = LCM of 6 and 4=12
CP=Rs.[(10/6)*12]=Rs.20 ; SP= Rs[(6/4)*12]=Rs.18
Loss%=[(2/20)*100]%=10%
Ans:B
Answer: (B) 10%
Question: Which of the following has 35^70 as a factor?
(A) 70^70
(B) 30^40
(C) 40^70
(D) 60^60
(E) 90^70
Rationale: Here 35^70 = 5^70 * 7^70 Only Option A has both .
Smash A
Answer: (A) 70^70
Question: Three taps A,B and C can fill a tank in 10,20 and 30. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in?
(A) 6hour 20min
(B) 7hour 10min
(C) 7hour 30min
(D) 8hour 15min
(E) 9hours 05 min
Rationale: A+B 1 hour work = 1/10 + 1/20 = 3/20
A+C 1 hour work = 1/12 + 1/30 = 7/60
Part filled in 2 hours = 3/20 + 7/60 = 4/15
Part filled in 6 hours = 3* 4/15 = 4/5
Remaining part = 1 - 4/5 = 1/5
Now it is the turn of A and B and 1/5 part is filled by A and B in 1hour 30min
Total time taken to fill the tank = 6+1.5 = 7hours 30min
Answer is C
Answer: (C) 7hour 30min
Question: At what time between 5.30 and 6 will the hands of a clock beat right angles?
(A) 43 5⁄11 min. past 5
(B) 43 7⁄11 min. past 5
(C) 40 min. past 5
(D) 45 min. past 5
(E) None of these
Rationale: At 5 o’clock, the hands are 25 min. spaces apart.
To be at right angles and that too between 5.30 and 6, the minute hand has to gain (25 + 15) = 40 min. spaces
55 min.spaces are gained in 60 min.
40 min. spaces are gained in (60⁄55 × 40) min = 43 7⁄11 min.
∴ Required time = 43 7⁄11 min. past 5
Answer B
Answer: (B) 43 7⁄11 min. past 5
Question: A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
(A) 11 liters
(B) 12 liters
(C) 10 liters
(D) 15 liters
(E) 18 liters
Rationale: Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters.
Answer:C
Answer: (C) 10 liters
Question: Simplify: 45205 x 95
(A) 4520500
(B) 4294470
(C) 4294475
(D) 4068450
(E) 226025
Rationale: 45205 x 95 = 45205 x (100 - 5)
= 4520500 - 226025
= 4294475
Answer is C
Answer: (C) 4294475
Question: The annual birth and death rate in a country per 1000 are 39.4 and 19.4 respectively . the number of years K in which the population would be doubled assuming there is no emigration or immigration is
(A) 20
(B) K=25
(C) 30
(D) K=35
(E) 40
Rationale: Suppose the population of the country in current year is 1000.
So annual increase is 1000 + 39.4 - 19.4=1020
Hence every year there is an increase of 2%.
2000=1000(1+ (2/100))^n
n=35 Answer is D.
Answer: (D) K=35
Question: A began business with Rs.45000 and was joined afterwards by B with Rs.36000. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
(A) 1.5
(B) 6
(C) 7.5
(D) 8.5
(E) 2
Rationale: 45*12 : 36*x = 2: 1
x = 7.5
12 -7.5 = 4.5
Answer: C
Answer: (C) 7.5
Question: If 144/0.144 = 14.4/x, then the value of x is:
(A) 0.0414
(B) 0.144
(C) 0.0144
(D) 0.414
(E) None of them
Rationale: =144/0.144 = 14.4/x
=144 x 1000/144
=14.4/x
=x = 14.4/1000
= 0.0144
Answer is C.
Answer: (C) 0.0144
Question: The factorial expression 9!/2! is not divisible by which of the following integers?
(A) 3
(B) 2
(C) 6
(D) 7
(E) 11
Rationale: 9!/2! => 9 x 8 x 7 x 6 x 5 x 4 x 3
(A) 3 Can divide 12 or 9
(B) 2 Can divide 8 or 6 or 4
(C) 6 Can divide 6
(D) 7 Can divide 7
(E) 11 None of the Multiplicands present
Hence answer will be (E)
Answer: (E) 11
Question: A man can row 12 Kmph in stil water and the river is running at 4 Kmph. If the man takes 2 hour to row to a place and back how far is the place?
(A) 3 Km
(B) 2.66 Km
(C) 10.66 Km
(D) 9 Km
(E) 10 km
Rationale: Explanation:
Man's rate down stream = 12 + 4 = 16 kmph
Man's rate upstream = 12 - 4 = 8 kmph
Let the required distence be x Km
then, x/16 +x/8 = 2
3x = 32
x = 10.66 Km.
Answer: Option C
Answer: (C) 10.66 Km
Question: x is what percent of y percent of z, in terms of x, y and z? k be the value expressed in terms of x,y and z.
(A) xyz
(B) 1/xyz
(C) 100xyz
(D) 10^4*x/yz
(E) 10^3 x/yz
Rationale: Algebraically, y% of z is just (y/100)*z, or yz/100. So we want to answer the question: x is what percent of yz/100? Say x is equal to k% of yz/100; then we have:
x = (k/100)*(yz/100)
10,000x/yz = k
D
Answer: (D) 10^4*x/yz
Question: In how many different ways can the letters of the word DETAIL be arranged in such a way that the vowels occupy only the odd positions?
(A) 120
(B) 60
(C) 48
(D) 32
(E) None of these
Rationale: 3 vowels can be arranged in three odd places in 3! ways.
Similarly, 3 consonants can be arranged in three even places in 3! ways.
Hence, the total number of words in which vowels occupy odd positions = 3! × 3! = 6 × 6 = 36 ways.
Answer E
Answer: (E) None of these
Question: The product Q of the first 10 prime numbers is closest to which of the following?
(A) 6.5 x 10^7
(B) 6.5 x 10^8
(C) 6.5 x 10^9
(D) 6.5 x 10^10
(E) 6.5 x 10^11
Rationale: The first 10 primes are: 2, 3, 5, 7, 11, 13, 17, 19, 23, and 29.
So, we need to find approximate value Q of 2*3*5*7*11*13*17*19*23*29.
# of different approximations are possible. For example:
2*5=10
3*17=~50 (actually more than 50);
7*13=~100 (actually less than 100);
11*19=~200 (actually more than 200)
23*29=667
2*3*5*7*11*13*17*19=~10*50*100*200*667=10^7*667=6.67*10^9.
Answer: C.
Answer: (C) 6.5 x 10^9
Question: A will was written such that an estate would be divided among three guys with the remainder donated to charity. One stipulation in the will is that no one from the guys can receive an amount within 30% of another's amount. If one of the guys received $20,000, what is the smallest possible range between the highest and lowest amounts (rounded to the nearest dollar) among the three guys?
(A) $4096
(B) $5904
(C) $7892
(D) $10052
(E) $20736
Rationale: 1st - 20,000.
2nd - 0.7*20,000 = 14,000
3rd - 0.7*14,000 = 9,800
Range = 20,000 - 9800 = 10,200.
Answer: D.
Answer: (D) $10052
Question: A company wants to spend equal amounts of money for the purchase of two types of computer printers costing $400 and $350 per unit, respectively. What is the fewest number of computer printers that the company can purchase?
(A) 11
(B) 13
(C) 15
(D) 17
(E) 19
Rationale: The smallest amount that the company can spend is the LCM of 400 and 350, which is 2800 for each, which is total 5600.
The number of 1st type of computers which costing $400 = 2800/400 = 7.
The number of 2nd type of computers which costing $350 = 2800/350 = 8.
Total = 7+8 = 15
Answer is C.
Answer: (C) 15
Question: The number x of cars sold each week varies with the price y in dollars according to the equation x = 800,000 – 50y. What would be the total weekly revenue E, in dollars, from the sale of cars priced at $ 15,000?
(A) 50,000
(B) 750,000
(C) 850,000
(D) 7,500,000
(E) E=750,000,000
Rationale: number of cars sold = x=800000-50y
y=15000
x=800000-750000=50000
revenue from 50000 cars= 15000*50000=750000000 E
Answer: (E) E=750,000,000
Question: A qualified worker digs a well in 5 hours. He invites 3 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?
(A) 1:24
(B) 1:34
(C) 1:44
(D) 1:41
(E) 2:14
Rationale: and answer is correct as you have calculated : 100/56 hrs that is 1.62 hrs - 1 hr and 41 minutes, so 1:41, hence, D.
Answer: (D) 1:41
Question: A book is bought for $600 and sold for $624. What is the profit in percentage?
(A) 2
(B) 4
(C) 6
(D) 8
(E) 10
Rationale: 624/600 = 1.04
The answer is B.
Answer: (B) 4
Question: 10 men, working 5 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the work in 12 days ?
(A) 4 hours a day
(B) 5 hours a day
(C) 6 hours a day
(D) 7 hours a day
(E) 8 hours a day
Rationale: Explanation:
More Men, Less Hours {Indirect Proportion}
Less Days, More Hours {Indirect Proportion}
[men 15 10
days 12 18] ::5:x
=>xâˆ—15âˆ—12=10âˆ—18âˆ—6
=>x=10âˆ—18âˆ—5/ 15âˆ—12
=>x=5
Option B
Answer: (B) 5 hours a day
Question: What is the sum of odd integers from 25 to 85
, inclusive?
(A) 1,705
(B) 1,500
(C) 1,240
(D) 1,120
(E) 1,100
Rationale: Number of odd integers = (85-25)/2 + 1
= 60/2 + 1
= 31
Sum of odd integers = (25+85)/2 * 31
= 1705
Answer A
Answer: (A) 1,705
Question: Peter invested an amount of Rs. 12,000 at the rate of 10% p.a simple interest and another amount at the rate of 20% p.a. simple interest. The total interest earned at the end of one year on the total amount invested became 14% p.a. Find the total amount invested?
(A) 20,000
(B) 72888
(C) 27899
(D) 27891
(E) 27712
Rationale: Let the second amount be Rs. x. Then,
(12000 * 10 * 1)/100 + (x * 20 * 1)/100 = [(12000 + x) * 14 * 1] / 100
120000 + 20x = 16800 + 14x
x = 8000
Total investment = 12000 + 8000 = Rs. 20,000.
Answer:A
Answer: (A) 20,000
Question: The manager at a health foods store mixes a unique superfruit juice cocktail that costs $1399.45 per litre to make. The cocktail includes mixed fruit juice and açai berry juice, which cost $262.85 per litre and $3104.35 per litre, respectively. The manager has already opened 35 litres of the mixed fruit juice. How many litres of the açai berry juice does he need to add?
(A) 17 litres
(B) 23.3 litres
(C) 11 litres
(D) 07 litres
(E) 38 litres
Rationale: 262.85(35)+3,104.35x = 1,399.45(35 + x)
Solve the equation.
262.85(35)+3,104.35x = 1,399.45(35 + x)
9,199.75 + 3,104.35x = 48980.75 + 1,399.45x
9,199.75 + 1,704.9x = 48980.75
1,704.9x = 39,781
x ≈ 23.3
Answer is B.
Answer: (B) 23.3 litres
Question: Rectangle ABCD is constructed in the coordinate plane parallel to the x- and y-axes. If the x- and y-coordinates of each of the points are integers which satisfy 4 ≤ x ≤ 11 and -5 ≤ y ≤ 5, how many possible ways are there to construct rectangle ABCD?
(A) 396
(B) 1260
(C) 1540
(D) 7920
(E) 15840
Rationale: As the rectangle is parallel to coordinate axes, the coordinates of the points of the rectangle would be
(X1, Y1), (X2, Y1), (X2, Y2), (X1,Y2)
given that X1, X2 lie between 4 and 11..ie., 8 possible numbers
Possible combinations for X1,X2 would be 8C2 = 28
Similarly, Possible combinations for Y1, Y2 would be 11C2 = 55
Possible ways of constructing rectangle is by selecting any of the combination of X1,X2 and Y1,Y2
= 28 * 55 = 1540
Ans. C
Answer: (C) 1540
Question: The ratio of two quantities is 2 to 3. If each of the quantities is increased by 4, what is the ratio of these two new quantities?
(A) 5/5
(B) It cannot be determined from the information given.
(C) 11/5
(D) 12/5
(E) 13/5
Rationale: let the actual ratio be 2k/3k, increase numerator and denominator by 4=> 2k+4/3k+4
Until the value of k is unknown we can not determine the actual ratio.
OR
let the actual be 3/4. After increasing 4 => 7/8
let the actual be 6/8. After increasing 4 => 10/12
Therefore without actual quantities we cannot determine the actual ratio.
Answer : B
Answer: (B) It cannot be determined from the information given.
Question: There are 11 teams in a certain league and each team plays each of the other teams exactly once. What is the total number of games played?
(A) 35
(B) 45
(C) 55
(D) 65
(E) 75
Rationale: 11C2 = 55
The answer is C.
Answer: (C) 55
Question: A man has $ 10,000 to invest. He invests $ 4000 at 5 % and $ 3500 at 4 %. In order to have a yearly income of $ 500, he must invest the remainder at:
(A) 6 %
(B) 6.1 %
(C) 6.2 %
(D) 6.3 %
(E) 6.4
Rationale: Solution:
Income from $ 4000 at 5 % in one year = $ 4000 of 5 %.
= $ 4000 × 5/100.
= $ 4000 × 0.05.
= $ 200.
Income from $ 3500 at 4 % in one year = $ 3500 of 4 %.
= $ 3500 × 4/100.
= $ 3500 × 0.04.
= $ 140.
Total income from 4000 at 5 % and 3500 at 4 % = $ 200 + $ 140 = $ 340.
Remaining income amount in order to have a yearly income of $ 500 = $ 500 - $ 340.
= $ 160.
Total invested amount = $ 4000 + $ 3500 = $7500.
Remaining invest amount = $ 10000 - $ 7500 = $ 2500.
We know that, Interest = Principal × Rate × Time
Interest = $ 160,
Principal = $ 2500,
Rate = r [we need to find the value of r],
Time = 1 year.
160 = 2500 × r × 1.
160 = 2500r
160/2500 = 2500r/2500 [divide both sides by 2500]
0.064 = r
r = 0.064
Change it to a percent by moving the decimal to the right two places r = 6.4 %
Therefore, he invested the remaining amount $ 2500 at 6.4 % in order to get $ 500 income every year.
Answer : E
Answer: (E) 6.4
Question: In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 10 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?
(A)  250
(B)  625
(C)  1,250
(D)  2,500
(E)  10,000
Rationale: total fish = x
percentage of second catch = (10/50)*100 = 20%
so, x * 20% = 50
x = 250 ans A.
Answer: (A)  250
Question: Find the greatest number of five digits which is exactly divisible by 12, 15 and 18?
(A) A)13050
(B) B)12960
(C) C)10025
(D) D)11080
(E) E)12080
Rationale: The largest five digit numbers are
13050,12960,12080
13050 is not divisible by 12
12960 is divisible by 18, 12 and 15
ANSWER:B
Answer: (B) B)12960
Question: In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by:
(A) 60 m
(B) 20m
(C) 43m
(D) 20m
(E) 23m
Rationale: To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.
While A covers 3 m, B covers 4 m.
While A covers 360 m, B covers 4	x 360	m	= 480 m.
3
Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.
A wins by 20 m.
Answer:	D
Answer: (D) 20m
Question: Average of first six multiples of 4 is
(A) 9
(B) 11
(C) 14
(D) 15
(E) 17
Rationale: Explanation:
Average=4(1+2+3+4+5+6) / 6=64 / 6=14
Option C
Answer: (C) 14
Question: A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the sum of the profits of B and C. Find the total profit.
(A) Rs.4500
(B) Rs.5200
(C) Rs.1800
(D) Rs.3000
(E) Rs.3200
Rationale: Explanation:
A:B:C = 5:6:4
Let the total profit = 100 - 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 - 160/3 = 140/3
A-(B+C) = 160/3 - 140/3 = 20/3
20/3 ---- 200
100 ---- ? => 3000
ANSWER IS D
Answer: (D) Rs.3000
Question: The average of first 80 non-zero positive numbers is:
(A) 22.25
(B) 31.25
(C) 35
(D) 40.5
(E) None of these
Rationale: Explanation :
Sum of first n natural numbers = n (n + 1)/2
So, average of first n natural numbers =
n (n + 1)/2n = (n + 1)/2
Required average = (80 + 1)/2 = 81/2 = 40.5.
Answer : D
Answer: (D) 40.5
Question: The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is
(A) 152600m2
(B) 153500m2
(C) 153600m2
(D) 153800m2
(E) None of these
Rationale: Explanation:
Question seems to be typical, but trust me it is too easy to solve, before solving this, lets analyse how we can solve this.
We are having speed and time so we can calculate the distance or perimeter in this question.
Then by applying the formula of perimeter of rectangle we can get value of length and breadth, So finally can get the area. Lets solve it:
Perimeter = Distance travelled in 8 minutes,
=> Perimeter = 12000/60 * 8 = 1600 meter. [because Distance = Speed * Time]
As per question length is 3x and width is 2x
We know perimeter of rectangle is 2(L+B)
So, 2(3x+2x) = 1600
=> x = 160
So Length = 160*3 = 480 meter
and Width = 160*2 = 320 meter
Finally, Area = length * breadth
= 480 * 320 = 153600 Answer: Option C
Answer: (C) 153600m2
Question: Four bells begin to ring together and they ring after an interval of 6,8,9 and 12 second respectively. How many times will they ring together in one hour, including the one at the start?
(A) 50
(B) 56
(C) 62
(D) 51
(E) 55
Rationale: LCM is 72. So they ring together in every 72 sec.
there are 3600 sec in 1 hr. so, 3600/72=50.
and 1 ring at the beginning. makes it 51.
ANSWER:D
Answer: (D) 51
Question: Find a number such that when 15 is subtracted from 7 times the number, the
Result is 10 more than twice the number.
(A) 1
(B) 4
(C) 5
(D) 0
(E) 3
Rationale: Let the number be x. Then, 7x - 15 = 2x + 10 => 5x = 25 =>x = 5.
Hence, the required number is 5.
Answer is C.
Answer: (C) 5
Question: Solve below question 3x - 5 = -20
(A) -8
(B) -9
(C) -5
(D) -4
(E) 1
Rationale: 1. Subtract 1 from both sides: 3x - 5 + 5 = -20 + 5 2. Simplify both sides: 3x = -15 3. Divide both sides by 3: 4. Simplify both sides: x = -5 C
Answer: (C) -5
Question: A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 15 per metre of cloth. What is the cost price of one metre of cloth?
(A) 78
(B) 72
(C) 90
(D) 27
(E) 23
Rationale: SP of m of cloth
= 8925/85 = Rs. 105
CP of 1m of cloth
= SP of 1m of cloth - profit on 1m of cloth
= Rs. 105 - Rs. 15
= Rs. 90.
Answer: C
Answer: (C) 90
Question: Lorna invests $4000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate?
(A) $160
(B) $1,600
(C) $800
(D) $4,400
(E) $5,840
Rationale: We have that 'x' invested at 6%
We also have that 4000-x' invested at 11%
Now then 580/4000 is approx 10%
Therefore, -4x+4000-x=0
5x=4000
x=800 approximately. Probably higher
Only C matches
Answer: (C) $800
Question: There are 2 more women than there are men on a local co-ed softball team. If there are a total of 16 players on the team, what is the ratio of men to women?
(A) 10/16
(B) 6/16
(C) 4/16
(D) 7/9
(E) 4/10
Rationale: w = m+2
w+m = 16
m+2+m = 16
2m = 14
m = 7
w = 9
ratio:7:9
Ans: D
Answer: (D) 7/9
Question: What percent of 200 is 55?
(A) 0.25%
(B) 4%
(C) 25%
(D) 27.5%
(E) 250%
Rationale: 200*x /100 = 55
x = 27.5
Ans: D
Answer: (D) 27.5%
Question: A number a is squared and then multiplied by negative 4. The result of this operation is equal to 4times the sum of FOURTH times a and 1. What is one possible value of a ?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: -4*a^2=4(4a+1)
a= -1 or -1
a=-1=B
ANSWER:A
Answer: (A) 1
Question: 8 men can do a piece of work in 12 days. 4 women can do it in 48 days and 10 children can do it in 24 days. In how many days can 10 men, 4 women and 10 children together complete the piece of work?
(A) 5 days
(B) 15 days
(C) 28 days
(D) 6 days
(E) 7 days
Rationale: Explanation:
1 man’s 1 day’s work = 1/8 × 12 = 1/96
10 men’s 1 day’s work = 1 × 10/96 = 5/48
1 woman’s 1 day’s work = 1/192
4 women’s 1 day’s work = 1/192 × 4 = 1/48
1 child’s 1 day’s work = 1/240
10 children’s 1 day’s work = 1/24
Therefore, (10 men + 4 women + 10 children)’s 1 day’s work = 5/48 + 1/48 + 1/24
= 8/48 =1/6
The required No. of days = 6 days
Answer: Option D
Answer: (D) 6 days
Question: The rate fo simple interest in two banks is in the ratio of 4 : 5 . Amith wants to deposit his total saving in these two banks in such a way that he should receive equal half yearly interest from both. He should deposits the saving in the banks in the ratio of:
(A) 2 : 5
(B) 5 : 4
(C) 5 : 3
(D) 4 : 5
(E) 1 : 2
Rationale: Let the savings be X and Y and the rates of simple interest be 4x and 5x respectively.
Then X +4x * 1/2 *1/100 = Y + 5x * 1/2 *1/100
or X/Y = 5/4
i.e. X : Y = 5 : 4
ANSWER:B
Answer: (B) 5 : 4
Question: The retail price of a washing machine is Rs.1265. If the manufacturer gains 10%, the wholesale dealer gains 15% and the retailer gains 25%, then the cost of the product is
(A) Rs 800
(B) Rs 900
(C) Rs 700
(D) Rs 600
(E) Rs 500
Rationale: Suppose the cost = Rs X
Therefore, S.P. of the manufacturer = X + 10% of X = 11X/10
S.P. of the wholesale dealer = 11X/10 + 15% of 11X/10 = 11X/10 + 33X/200 = (253/200) X
S.P. of the retailer = 253/200 X + 25% of 253/200X = 253/200 X + 253/800 X = (1265/800) X
Given (1265/800) X = 1265 => X = Rs. 800
ANSWER:A
Answer: (A) Rs 800
Question: Find the largest number which divides 62, 132 and 237 to leave the same remainder in each case.
(A) 35
(B) 25
(C) 15
(D) 45
(E) None of them
Rationale: Required number = H.C.F. of (132 - 62), (237 - 132) and (237 - 62)
= H.C.F. of 70, 105 and 175 = 35.
Answer is A.
Answer: (A) 35
Question: There are 200 questions in a 3 hr examination. Among these questions there are 50 mathematics problems. It is suggested that twice as much time be spent on each maths problem as for each other question. How many minutes should be spent on mathematics problems
(A) 36
(B) 60
(C) 45
(D) 72
(E) 90
Rationale: Let x = minutes spent on a non-math problem
then 2x = minutes spent on a math problem
x(200-50) + 2x(50) = 180
x(150) + 2x(50) = 180
150x + 100x = 180
250x = 180
x = 0.72 minutes
Time to spend on math problems:
2x(50)=100x = 100(0.72) = 72 minutes ANSWER :D
Answer: (D) 72
Question: If the tens digit x and the units digit y of a positive integer n are reversed, the resulting integer is 9 less than n. What is y in terms of x ?
(A)  20 - x
(B)  9 - x
(C)  x + 9
(D)  x - 1
(E)  x + 1
Rationale: Original Digits=xy i.e. Number=10x+y
After reversing the digits:
Digits=yx i.e. Number=10y+x
10y+x is 9 less than 10x+y
10x+y-9=10y+x
10x-x-9=10y-y
9x-9=9y
x+1=y
OR
y=x-1
Ans:D
Answer: (D)  x - 1
Question: The no. of gift pack bought by Dexter is 1 more than the price, in rupees, of each gift pack. The amount of Rs.380 which Dexter had, fell short of the required amount. What is theamount by which he might have fallen short.
(A) 30
(B) 40
(C) 45
(D) 48
(E) 54
Rationale: Let the price of gift pack be 'aa'
Then number of packs bought =a+1=a+1
Hence total cost is a(a+1)a(a+1)
It is given that 380<a(a+1)380<a(a+1)
If a=19a=19, the total cost =19×20=380=19×20=380
Dexter would not have fallen short, If:
a=20a=20, a(a+1)=420a(a+1)=420
So he would have fallen short by Rs 40.
This is the minimum amount by which he may have fallen short.
B)
Answer: (B) 40
Question: A train of 30 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
(A) 6
(B) 3.3
(C) 4
(D) 9
(E) 2
Rationale: D = 30 * 60 + 1500 = 3300 m
T = 3300/60 * 18/5 = 198 sec = 3.3 mins
Answer:B
Answer: (B) 3.3
Question: A person spent 1/5 of his salary last year on household and 1/4 of the remainder on clothes. What fraction of last year’s salary did the person have left after his household and clothes expenditures?
(A) 2/3
(B) 3/5
(C) 2/6
(D) 5/4
(E) 1/2
Rationale: The person spent 1/5 of his salary on household, so remaining is 4/5
1/4 of the remaining is spent is spent on clothes, 1/4*4/5 is 2/10
To make the denominator common, we use 10, so 1/5=2/10
Total amount spent=2/10+2/10=4/10 is the total amount spent on household and clothes
Remaining salary is 6/10 of the total salary reduced to 3/5
Answer is B
Answer: (B) 3/5