mathewhe/aqua_rat huggingface dataset:
Question: If the tens digit of positive integers t, y are 6, how many values of the tens digit of 2(t+y) can be there?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: If the tens digit of positive integers t, y are 6, how many values of the tens digit of 2(t+y) can be there?
A. 2
B. 3
C. 4
D. 5
E. 6
-> If t=y=60, 2(t+y)=240 is derived. If t=y=69, 2(t+y)=276 is derived, which makes 4,5,6,7 possible for the tens digit. Therefore, the answer is C.
Answer: (C) 4
Question: A book store bought copies of a new book by a popular author, in anticipation of robust sales. The store bought 400 copies from their supplier, each copy at wholesale price A. The store sold the first 150 copies in the first week at 80% more than A, and then over the next month, sold a 100 more at 20% more than A. Finally, to clear shelf space, the store sold the remaining copies to a bargain retailer at 40% less than A. What was the bookstore’s net percent profit or loss on the entire lot of 400 books?
(A)  30% loss
(B)  10% loss
(C)  10% profit
(D)  20% profit
(E)  60% profit
Rationale: [[A(150)(1.8)+A(100)(1.2)+A(150)(0.6)]/400A] - 1
[50[(3)(1.8) + (2)(1.2) + (3)(0.6)] / (50)(8)] - 1
[(5.4 + 2.4 + 1.8)/8] - [8/8]
+1.6/8
+20%
answer is D
Answer: (D)  20% profit
Question: If m and n are whole numbers such that mn = 121, the value of (m - 1)n + 1 is:
(A) 1
(B) 100
(C) 121
(D) 141
(E) 1000
Rationale: mn=121 121 can be obtained by multiplying 121*1
m=121,n=1
(m-1)n+1=121
if we choose m=1 and n=121
then the answer will be 1
so there r two possible answers 1 and 121
ANSWER:C
Answer: (C) 121
Question: Calculate the area of a triangle, if the sides of are 52 cm, 48 cm and 20 cm, what is its area?
(A) 480 cm2
(B) 580 cm2
(C) 380 cm2
(D) 180 cm2
(E) 280 cm2
Rationale: The triangle with sides 52 cm, 48 cm and 20 cm is right angled, where the hypotenuse is 52 cm.
Area of the triangle = 1/2 * 48 * 20 = 480 cm2
Answer: A
Answer: (A) 480 cm2
Question: If cost of sugar increases by 25%. How much percent consumption of sugar should be decreased in order to keep expenditure fixed?
(A) 10%
(B) 15%
(C) 20%
(D) 25%
(E) None
Rationale: 100
125
-----
125 ----- 25
100 ------ ? => 20%
ANSWER:C
Answer: (C) 20%
Question: In front of you lies a figure made up with 20 x 10 square blocks. Will you be able to find out the number of unique squares and rectangles that are being formed inside this figure by combining two or more distinct squares?
(A) 11647
(B) 11550
(C) 12654
(D) 26537
(E) 32651
Rationale: B
11550
There is just one way to find it out and that is the generic computing method.
The number of squares and rectangles formed = (Summation of column numbers)
= (1 + 2 + 3 +......+ 19 + 20) * (1 + 2 + 3 +......+ 9 + 10)
= 210 * 55
= 11550
Answer: (B) 11550
Question: Pipe A can fill the tank in 30 minutes and pipe B in 20min and pipe C can empty the tank in 90 minutes. How long it will take to fill the tank if three of the pipes are operating together?
(A) 10.55
(B) 12.0
(C) 13.1
(D) 13.85
(E) 15.2
Rationale: Pipe A fills 1/30th of the tank in a minute and pipe B, 1/20th. Pipe C empties in 90min
(1/30)+(1/20)-(1/90)=(1/x)
13/180=1/x => x=180/13 => x=13.85 minutes
Answer: D
Answer: (D) 13.85
Question: The number of new words that can be formed by rearranging the letters of the word 'ALIVE' is -.
(A) 24
(B) 23
(C) 119
(D) 120
(E) None of these
Rationale: Explanation:
Number of words which can be formed = 5! - 1 = 120 - 1 = 119.
ANSWER IS C
Answer: (C) 119
Question: A restaurant meal cost $24.6 and there was no tax. If the tip was more than 20 percent but less than 18 percent of the cost of the meal, then the total amount paid must have been between
(A) $40 and $42
(B) $29 and $29
(C) $38 and $40
(D) $37 and $39
(E) $36 and $37
Rationale: The total amount for the meal was between 24.6*1.2=29.5 and 24.6*1.18=~29. Only option which covers all possible values of the meal is B.
Answer: B.
Answer: (B) $29 and $29
Question: Manoj borrowed Rs.3450 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.825.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?
(A) Rs.5358
(B) Rs.5458
(C) Rs.3370
(D) Rs.4358
(E) Rs.3358
Rationale: Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3450.3.6/100 = Rs.824.85
27P = 62100 = 82485
P = (82585 + 62100)/27 = Rs.5358
ANSWER:A
Answer: (A) Rs.5358
Question: Gary is 15 years younger than Simon, and Kim is twice as old as Gary. If S is Simon’s age and K is Kim's age, what is the relationship between K and S?
(A) K = 2S + 10
(B) K = 2S + 10
(C) K = 2S - 30
(D) K = 2S − 10
(E) K = 2S − 5
Rationale: G=S-15 and K=2G --> K=2S-30
Answer C
Answer: (C) K = 2S - 30
Question: In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 2 to the thrice of the remainder. The dividend is?
(A) 76
(B) 78
(C) 86
(D) 88
(E) 90
Rationale: Divisor = (6 * 3) + 2 = 20
5 * Quotient = 20
Quotient = 4.
Dividend = (Divisor * Quotient) + Remainder
Dividend = (20 * 4) + 6 = 86.
C)
Answer: (C) 86
Question: If the integer d is rounded to the nearest hundred, the result represents a 66 2/3 % increase over the value obtained when d is rounded to the nearest ten. which of the following is a possible value of d?
(A) 64
(B) 67
(C) 99
(D) 133
(E) 147
Rationale: We have to check options 1 by 1.
64 rounded to nearest hundred = 100
64 rounded to nearest ten = 60
now difference = 40
the result represents a 66 2/3 % increase over the value obtained when x is rounded to the nearest ten.
therefore 40/60)*100 = 66 2/3 ==>this is the answer.
99 rounded to nearest ten = 100
133 rounded to nearest ten = 130
133 rounded to nearest hundred d= 100=A
Answer: (A) 64
Question: If Juan takes 14 seconds to run y yards, how many seconds will it take him to run x yards at the same rate?
(A) 14x/y
(B) 14y/x
(C) x/(14y)
(D) 14/(xy)
(E) xy/14
Rationale: This problem is testing us on the Rate x Time = Distance relationship. This relationship also tells us that Rate = Distance/Time and Time = Distance/Rate.
Ultimately, we are looking for how many seconds it will take Juan to run x yards. Thus, the equation we’ll use is: Time = Distance/Rate. We know the distance is x yards, and we need to find Juan’s rate.
We can find Juan’s rate as follows: Rate = Distance/Time = y yards/14 seconds
Using that rate, we need to determine how long it takes him to run x yards at the same rate. So we have:
Time = Distance/Rate
Time = x yards/(y yards/14 seconds)
Time = (x yards) x (14 seconds/y yards)
Time = 14x/y seconds
Answer A.
Answer: (A) 14x/y
Question: If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?
(A) 120 cm2
(B) 820 cm2
(C) 128 cm2
(D) 110 cm2
(E) 220 cm2
Rationale: The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle = 1/2 * 24 * 10 = 120 cm2
Answer: A
Answer: (A) 120 cm2
Question: In a camp, there is a meal for 140 men or 200 children. If 150 children have taken the meal, how many
men will be catered to with the remaining meal ?
(A) 38 men
(B) 32 men
(C) 35 men
(D) 30 men
(E) None of these
Rationale: Explanation:
There is meal for 200 children. 150 children have taken the meal.
Remaining meal is to be catered to 50 children.
Now, 200 children = 140 men
So, 50 Children = 140/200 * 50 = 35 men
Answer: C
Answer: (C) 35 men
Question: The average of first five multiples of 3 is?
(A) 2
(B) 9
(C) 8
(D) 6
(E) 3
Rationale: Average = 3(1 + 2 + 3 + 4 + 5)/5
= 45/5
= 9.
Answer:B
Answer: (B) 9
Question: When 21 is divided by positive integer j, the remainder is 6. For how many values of j is this true?
(A) 1
(B) 3
(C) 5
(D) 7
(E) 9
Rationale: When 21 is divided by j, the remainder is 6 i.e. 6 dragonfruit left over after grouping, so j is greater than 6.
It also means that 15 is completely divisible by j.
Factors of 15 are 1, 3, 5, and 15.
Out of these j could be 12.
Answer (A)
Answer: (A) 1
Question: A is thrice as good a work man as B and together they finish a piece of work in 12 days.The number of days taken by A alone to finish the work is :
(A) 28 days.
(B) 14 days.
(C) 12 days.
(D) 16 days.
(E) 18 days.
Rationale: Solution
(A’s 1 day’s work): (B’s 1 day’s work)= 3 : 1.
(A + B)'s 1 day’s work = 1/12
Divide 1/14 in the ratio 3 : 1.
∴ A’s 1 day’s work = (1/12 x2/3)= 1/16
Hence,A alone can finish the work in 16 days.
Answer D
Answer: (D) 16 days.
Question: A alone can finish a work in 10 days which B alone can finish in 15 days. If they work together and finish it, then out of a total wages of Rs.3100, A will get:
(A) Rs.1200
(B) Rs.1500
(C) Rs. 1860
(D) Rs.2000
(E) None of these
Rationale: Explanation:
Ratio of working days of A : B = 10 : 15
Therefore, their wages ratio = reverse ratio = 15 : 10
Therefore, A will get 15 units of ratio
Total ratio = 25
1 unit of ratio =3100/25 = 124
So, A’s amount = 124 × 15 = Rs.1860.
Answer: Option C
Answer: (C) Rs. 1860
Question: A man in a train travelling at 24km/hr notices that a train going in the opposite direction passes him in 10 sec.If the length of this train is 220m find its speed .
(A) 30 km/hr
(B) 40 km/hr
(C) 55 km/hr
(D) 60 km/hr
(E) 70 km/hr
Rationale: relative speed of trains = 220/10 mtrs/sec = 220*18/(10*5)= 79 km/hr
speed of 2nd train = 79-24=55 km/hr
ANSWER:C
Answer: (C) 55 km/hr
Question: Given f(x) = 2x – 3, for what value of x does 2*[f(x)] – 21 = f(x – 4) ?
(A) 0
(B) 2
(C) 4
(D) 6
(E) 8
Rationale: 2(2x-3)-21 = 2(x-4) - 3
2x = 16
x = 8
The answer is E.
Answer: (E) 8
Question: In division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 3 as quotient. What the correct quotient?
(A) 0
(B) 12
(C) 13
(D) 20
(E) None of these
Rationale: Number = (12*35)=420
Correct Quotient=420/21=20
Correct Option: D
Answer: (D) 20
Question: Pipe A can fill a tank in 5 hours, pipe B in 10 hours and pipe C in 30 hours. If all the pipes are open, in how many hours will the tank be filled?
(A) 6 hours
(B) 8 hours
(C) 3 hours
(D) 1 hours
(E) 2 hours
Rationale: Part filled by A + B + C in 1 hour
= 1/5 + 1/10 + 1/30 = 1/3
All the three pipes together will fill the tank in 3 hours.
Answer: C
Answer: (C) 3 hours
Question: The speed of a boat in still water is 80kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
(A) kmph
(B) kmph
(C) kmph
(D) kmph
(E) kmph
Rationale: Speed downstream = 80 + 20 = 100 kmph
Speed upstream = 80 - 20 = 60 kmph
Answer:D
Answer: (D) kmph
Question: A train 385 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
(A) 5
(B) 6
(C) 21
(D) 8
(E) 9
Rationale: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [385 * 3/55] sec = 21 sec
Answer: C
Answer: (C) 21
Question: The H.C.F of two numbers is 23 and the other two factors of their L.C.M are 13 and 14. The larger of the two numbers is:
(A) 276
(B) 299
(C) 322
(D) 345
(E) 355
Rationale: Clearly, the numbers are (23 * 13) and (23 * 14). Larger number = (23 * 14) = 322.
ANSWER:C
Answer: (C) 322
Question: When a Mobile is sold for Rs. 7200, the owner loses 20%. At what price must that Mobile be sold in order to gain 20%?
(A) 10,400
(B) 10,600
(C) 10,800
(D) 11,000
(E) 11,200
Rationale: 80 : 7200 = 120 : x
x = (7200 x 120)/80 = 10800.
Hence, S.P. = Rs. 10,800.
Answer: Option C
Answer: (C) 10,800
Question: When you multiply a number by 4 and
then subtract 8, the result is the same as
if you first subtracted 11 from the same
number and then multiplied by 8. What
is the number?
(A) A)23
(B) B)13
(C) C)19
(D) D)31
(E) E)20
Rationale: Let x equal the number and then change the words into an equation and solve for x:
4x – 8 = 8(x – 11)
4x – 8 = 8x – 88
80 = 4x
20 = x
correct answer E)20
Answer: (E) E)20
Question: Of the goose eggs laid at a certain pond, 1/4 hatched and 4/5 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 2/5 did not survive the first year. If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
(A) 600
(B) 700
(C) 800
(D) 900
(E) 1000
Rationale: Let x be the number of eggs that were laid.
(3/5)(4/5)(1/4)x = 120
(12/100)x = 120
x = 1000
The answer is E.
Answer: (E) 1000
Question: x, a, z, and b are single digit positive integers. x = ¼ a. z = ¼ b. (10a + b) – (10x + z) could be equal to
(A) 32
(B) 36
(C) 45
(D) 64
(E) 65
Rationale: 1) firstly we are not given that all are different integers..
2) since each is a positive single digit integer and x=a/4... a can take only 4 and 8 as value, and x can take 1 and 2..
3) same as 2) for b and z.
so in (10a + b) – (10x + z) ..
10a+b can be
44,48,84,88..
10x+z can be
11,12,21,22..
Ans :B
Answer: (B) 36
Question: Seth opened a shop investing Rs.6000. Taylor joined him after one year, investing Rs.10000. They earned a profit of Rs.1100 after completion of two years. What will be Taylor's share of profit?
(A) 600
(B) 700
(C) 500
(D) 800
(E) 450
Rationale: SoL = ~s- So Anju’s share = [5/11] x 1100 = 500
Answer: C
Answer: (C) 500
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is?
(A) 288 m
(B) 267 m
(C) 888 m
(D) 150 m
(E) 278 m
Rationale: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 25 = x / 15
x = 150 m.
Answer: D
Answer: (D) 150 m
Question: In an election between two political leaders 10% of the voters did not cast their vote. 10% of the votes polled were found invalid. The successful political leader got 54% of the valid, votes and won by a majority of 3240 votes. The number of voters enrolled on the voters list was :
(A) 30000
(B) 50000
(C) 33000
(D) 40000
(E) 45000
Rationale: Explanation :
Solution: Let the number of voters be x. then, votes polled = 90% of x.
Valid votes = 90% of(90% of x)
.'. 54% of[90% of(90% of x)] - 46% of[90% of(90% of x)] = 3240.
8% of[90% of(90% of x)] = 3240.
8/100 * 90/100 * 90/100 * x = 3240
x = (3240*100*100*100)/(8*90*90) = 50000
Answer : B
Answer: (B) 50000
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 100 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
(A) 19 sec
(B) 87 sec
(C) 36 sec
(D) 34 sec
(E) 11 sec
Rationale: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 100 = 340 m.
Time taken = 340/10 = 34 sec.
Answer: D
Answer: (D) 34 sec
Question: Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 18 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?
(A) 11
(B) 444
(C) 468
(D) 287
(E) 221
Rationale: 1h ----- 5
? ------ 60
12 h
RS = 18 + 21 = 39
T = 12
D = 39 * 12 = 468
Answer:C
Answer: (C) 468
Question: A man sells a horse for Rs.800 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse?
(A) 227
(B) 299
(C) 277
(D) 860
(E) 771
Rationale: CP = SP + 1CP = SP - g
800 + x = 980 - 2x
3x = 180 => x = 60
CP = 800 + 60 = 860
Answer: D
Answer: (D) 860
Question: What is the median of a set of consecutive integers if the sum of nth number from the beginning and nth number from the end is 110?
(A) 10
(B) 25
(C) 55
(D) 75
(E) 100
Rationale: Surprisingly no one answered this easy one.
property of a set of consecutive integerz.
mean=median=(first element+last element)/2 = (second element+last but one element)/2 =(third element+ third last element)/2 Etc. Etc.
So mean=median=110/2=55
Answer is C
Answer: (C) 55
Question: The average weights for Tom,Jack,Rose was 90kg. The average weights for Jack,Rose,John was 100kg. If the weight of John be 50kg, what was the weight of Tom?
(A) 20
(B) 44
(C) 37
(D) 42
(E) None of these
Rationale: Explanation:
T + J + R = 90 × 3 = 270
J+R+J = 100× 3 = 300
Also, weight of John = 50
Weight of Tom = 270+50-300 =20kg
Answer: Option A
Answer: (A) 20
Question: If e is an even integer and e/18 is an odd integer, which of the following is NOT an even integer?
(A) (e^2)/54
(B) (e^2)/12
(C) (e^2)/9
(D) (e^2)/6
(E) (e^2)/2
Rationale: since e is an even integer and e/18 is an odd integer. thus maximum power of 2 in a is one. why ?? because if the power of 2 in the expression has been 2 or greater, then the e/18 must have been an even integer. (18=2*3^2. as 18 contain only one 2 in the expression)
now, any expression in which we have 4 at the denominator will be odd. out of the given options only 12 is a multiple of 4. hence answer should be B
Answer: (B) (e^2)/12
Question: The elevator in an eleven-story office building travels at the rate of one floor per 1/4 minute, which allows time for picking up and discharging passengers. At the main floor and at the top floor, the operator stops for 1 minute. How many complete trips will an operator make during a 3-hour period?
(A) 88
(B) 56
(C) 42
(D) 25
(E) 64
Rationale: Complete trip = 10 floors up and 10 floors down = 20 floors = 20*1/4 = 5 minutes plus 2 minutes = 7 minutes.
3 hour = 180 minutes.
In 180 minutes operator can make 180/7=25 trips.
Answer: D.
Answer: (D) 25
Question: List A consists of 12 consecutive integers. If -4 is the least integer in list A, what is the range of positive integers in list A?
(A) 5
(B) 6
(C) 7
(D) 11
(E) 12
Rationale: Since -4 is the least integer in list A, then 7 is the largest integer in that list. Thus the range of the positive integers in the list is 7-1=6.
Answer: B.
Answer: (B) 6
Question: What profit percent is made by selling an article at a certain price, if by selling at 4/5rd of that price, there would be a loss of 20%?
(A) 0%
(B) 29%
(C) 70%
(D) 27%
(E) 28%
Rationale: SP2 = 4/5 SP1
CP = 100
SP2 = 80
4/5 SP1 = 80
SP1 = 100
100 --- 100 => 0%
Answer: A
Answer: (A) 0%
Question: Three-twentieths of the members of a social club are retirees who are also bridge players, six-twentieths of the members are retirees, and one-half of the members are bridge players. If 130 of the members are neither retirees nor bridge players, what is the total number of members in the social club?
(A) 240
(B) 300
(C) 200
(D) 400
(E) 480
Rationale: {Total} = {Retirees} + {Bridge players} - {Both} + {Neither}
x = 6/20*x + x/2 - 3/20*x + 130
20x = 6x + 10x - 3x + 130*20 (multiply by 20)
13x = 130*20
x = 200.
Answer: C
Answer: (C) 200
Question: In how many ways, a committee of 5 members can be selected from
6 men and 5 ladies, consisting of 3 men and 2 ladies?
(A) 200
(B) 450
(C) 350
(D) 500
(E) 430
Rationale: . (3 men out 6) and (2 ladies out of 5) are to be chosen.
Required number of ways = (6c3x5c2)
= [6x5x4/3x2x1] x [5x4/2x1] = 200.
ANSWER A
Answer: (A) 200
Question: Zack has 3 red fish, 5 yellow fish and 7 green fish. How many fish does he have in all?
(A) 8
(B) 5
(C) 15
(D) 1
(E) 18
Rationale: 3+5+7=15. Answer is C
Answer: (C) 15
Question: The product of n consecutive positive integers is always divisible by?
(A) n^2 -1
(B) (n+1)!
(C) 2n +1
(D) n^2 + 1
(E) n!
Rationale: Plug in some vlues and check -
Product of first 2 number is 2*1
Product of first 3 number is 3*2*1
Product of first 4 number is 4*3*2*1
Product of first 5 number is 5*4*3*2*1
So, The product of first n natural numbers is always divisible by n! , answer will be (D)
Answer: (D) n^2 + 1
Question: he average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 70 kg. What might be the weight of the new person ?
(A) 90 kg
(B) 55 kg
(C) 45 kg
(D) 85 kg
(E) 25 kg
Rationale: Explanation:
Total weight increased = (8 x 2.5) kg = 20 kg.
Weight of new person = (70 + 20) kg = 90 kg.
Answer: A
Answer: (A) 90 kg
Question: What is the remainder when 1201 × 1202 ×1204 × 1205 is divided by 6?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: The remainders when dividing each number by six are: 1, 2, 4, and 5.
The product is 1*2*4*5 = 40
The remainder when dividing 40 by 6 is 4.
The answer is D.
Answer: (D) 4
Question: The population of a village is 15540. It increases annually at the rate of 28% p.a. What will be its population after 2 years?
(A) 10000
(B) 25460
(C) 26709
(D) 14000
(E) 14400
Rationale: Formula :
( After =100 denominator
Ago = 100 numerator)
15540 × 128/100 × 128/100 = 25460
B
Answer: (B) 25460
Question: If the perimeter of a rectangular garden is 600 m, its length when its breadth is 120 m is?
(A) 286 m
(B) 180 m
(C) 200 m
(D) 166 m
(E) 187 m
Rationale: 2(l + 120) = 600 => l
= 180 m
Answer: B
Answer: (B) 180 m
Question: What is the average of xx, 2x2x, and 66?
(A) x+2
(B) x+2x
(C) x+2x+2
(D) 2x+2
(E) x
Rationale: By the definition of an average, we get:
x+2x+63=3x+63x+2x+63=3x+63
=3(x+2)3=x+2.=3(x+2)3=x+2.
Hence, the answer is x+2x+2 or Option C
Answer: (C) x+2x+2
Question: A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.2662 in 3 years. Find the rate percent?
(A) 28
(B) 10
(C) 21
(D) 17
(E) 11
Rationale: Explanation:
2420 --- 242
100 --- ? => 10%
Answer: Option B
Answer: (B) 10
Question: If there are 200 questions in a 3 hr examination. Among these questions are 25 type A problems, which requires twice as much as time be spent than the rest of the type B problems. How many minutes should be spent on type A problems?
(A) 40 min
(B) 62 min
(C) 70 min
(D) 74 min
(E) 76 min
Rationale: x=time for type B prolems
2x=time for type A problem
total time=3hrs=180min
175x+25*2x=180
x=180/225
x=0.8
time taken for type A problem=25*2*0.8=40min
ANSWER:A
Answer: (A) 40 min
Question: Find the simple interest on Rs. 3000 at 6 1/4% per annum for the period from
4th Feb., 2005 to 18th April, 2005.
(A) Rs.36.50
(B) Rs.37.50
(C) Rs.35.50
(D) Rs.32.50
(E) Rs.33.50
Rationale: Time = (24+31+18)days = 73 days = 73/365 years = 1/5 years.
P = Rs.3000 and R = 6 ¼ %p.a = 25/4%p.a
S.I. = Rs.(3,000*(25/4)*(1/5)*(1/100))= Rs.37.50.
Remark : The day on which money is deposited is not counted while the day on which money is withdrawn is counted
Answer is B.
Answer: (B) Rs.37.50
Question: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
(A) 6.3
(B) 5.2
(C) 4.9
(D) 10.8
(E) 10.5
Rationale: Answer: Option D
Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5 = 10.8 sec.
Answer: (D) 10.8
Question: Arabica coffee costs $0.4 per ounce while Robusta coffee costs $0.3 per ounce. If the blend of Arabica and Robusta costs $0.34 per ounce, what is the share of Arabica in this blend?
(A) 20%
(B) 24%
(C) 30%
(D) 33%
(E) 40%
Rationale: a= amount of arabica coffee
1-a = amount of robusta coffee. because if you subtract a from the 1 ounce, the remaining amount is robusta
therefore:
.4a + .3(1-a) = .34
.4a + .3 - .3a = .34
a= .4
therefore: .4/1 ounce = 40%. Therefore, the answer should be E
Answer: (E) 40%
Question: 1: 3 = 4/3: x. The value of x is?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: x * 1 = 3 * 4/3
x *1= 4
x=4/1=4
ANSWER:D
Answer: (D) 4
Question: Vijay bought 160 shirts at the rate of Rs. 225 per shirt. The transport expenditure was Rs. 1400. He paid an octroi at the rate of Rs. 1.75 per shirt and labour charges were Rs. 320. What should be the selling price of one shirt, if he wants a profit of 20%?
(A) Rs.275
(B) Rs.216
(C) Rs.208
(D) Rs.285
(E) Rs.281
Rationale: Total CP per shirt = 225 + 1400/160 + 1.75 + 320/160 = Rs. 237.5
SP = CP[(100 + profit%)/100]
= 237.5 * [(100 + 20)/100] = Rs.285.
Answer:D
Answer: (D) Rs.285