mathewhe/aqua_rat huggingface dataset:
Question: Tom and Jerry are running on the same road towards each other. If Tom is running at a speed of 2.5 meters per second and Jerry is running 36% slower, how much time Q will it take them to meet if the initial distance between the two is 50 meters and Tom started running 20 seconds before Jerry did?
(A) 2 minute and 12 seconds.
(B) two minutes.
(C) 44 seconds.
(D) 20 seconds.
(E) 12 seconds.
Rationale: Tom is running alone for 20 seconds.
So he will cover a distance of 20*2.5 = 50 m in 20 seconds=Q
Basically, Jerry has not started yet , and Tom has covered the distance alone and met Jerry on the other side
D is the answer
Answer: (D) 20 seconds.
Question: The average of eight numbers is 27. If one number is excluded, the average becomes 25. The excluded number is
(A) 25
(B) 27
(C) 30
(D) 35
(E) 41
Rationale: Sol.
Therefore excluded number
= (27 × 8) - ( 25 × 7)
= 216 – 175
= 41.
Answer E
Answer: (E) 41
Question: Pipe A can fill a tank in 5 hours, pipe B in 10 hours and pipe C in 30 hours. If all the pipes are open, in how many hours will the tank be filled?
(A) 5 hours
(B) 6 hours
(C) 3 hours
(D) 9 hours
(E) 2 hours
Rationale: Part filled by A + B + C in 1 hour = 1/5 + 1/10 + 1/30 = 1/3
All the three pipes together will fill the tank in 3 hours.Answer: C
Answer: (C) 3 hours
Question: A lends Rs. 2500 to B and a certain to C at the same time at 7% p.a. simple interest. If after 4 years, A altogether receives Rs. 1120 as interest from B and C, then the sum lent to C is?
(A) 2998
(B) 1500
(C) 2878
(D) 299
(E) 277
Rationale: Let the sum lent to C be Rs. x. Then,
(2500 * 7 * 4) / 100 + (x * 7 * 4) / 100 = 1120
7/25 x = (1120 - 700) => x = 1500
Answer: B
Answer: (B) 1500
Question: For every positive integer n, the nth term of a sequence is the total sum of three consecutive integers starting at n. What is the total sum of terms 1 through 100 of this series?
(A) 11,990
(B) 12,720
(C) 13,260
(D) 14,580
(E) 15,450
Rationale: Each term of the series has the form (n+n+1+n+2) = 3n+3
Since the series goes from 1 to 100, the sum of the series is:
3(1+2+...+100) + 100(3) =
3(100)(101)/2 + 100(3) =
150*101 + 300 = 15,450
The answer is E.
Answer: (E) 15,450
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 54 kmph, find the speed of the stream?
(A) 77
(B) 18
(C) 14
(D) 12
(E) 17
Rationale: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 54/3 = 18 kmph.
Answer:B
Answer: (B) 18
Question: An engineering student has to secure 36% marks to pass. He gets 130 marks and fails by 14 marks. The maximum number of marks obtained by him is?
(A) 337
(B) 400
(C) 298
(D) 2798
(E) 271
Rationale: 130
14
-------
361------ 144
100%------? => 400
Answer:B
Answer: (B) 400
Question: Two men starting from the same place walk at the rate of 5 kmph and 5.5 kmph respectively. What time will they take to be 9.5 km apart, if they walk in the same direction?
(A) 19 hrs
(B) 14 hrs
(C) 15 hrs
(D) 17 hrs
(E) None
Rationale: Sol.
to be 0.5 km apart, they take 1 hour.
To be 9.5 km apart, they take [1/0.5 * 9.5] hrs = 19 hrs.
Answer A
Answer: (A) 19 hrs
Question: Raju age after 23 years will be 5 times his age 5 years back, What is the present age of Raju
(A) 10 years
(B) 11 years
(C) 13 years
(D) 12 years
(E) 14 years
Rationale: Explanation:
Clearly,
x+23 = 5(x-5)
<=> 4x = 48 => x = 12
Option D
Answer: (D) 12 years
Question: Shop Offered 40% offer for every Shirt, Smith bought a shirt at Rs. 560. and What was the shop's original selling Price?
(A) 500
(B) 550
(C) 600
(D) 933
(E) 750
Rationale: SP* (60/100) = 560
SP= 9.33 * 100 => CP = 933
Answer:D
Answer: (D) 933
Question: A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 50 kmph. When and at what distance from Mumbai do the two trains meet?
(A) 1:00pm, 220 km
(B) 1:00pm, 200km
(C) 2:00pm, 200 km
(D) 2:00pm, 220 km
(E) None of these
Rationale: Explanation:
When the second train leaves Mumbai the first train covers 40 * 1 = 40 km
So, the distance between first train and second train is 40 km at 10.00am
Time taken by the trains to meet
= Distance / relative speed = 40 / (50 -40) = 4 hours
So, the two trains meet at 2 p.m. The two trains meet 4 * 50 = 200 km away from Mumbai.
ANSWER IS C
Answer: (C) 2:00pm, 200 km
Question: If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
(A) 4 days
(B) 5 days
(C) 6 days
(D) 7 days
(E) none
Rationale: Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, 6x + 8y = 1/10 and 26x + 48y = 1/2
Solving these two equations, we get : x = 1/100 and y = 1/200
(15 men + 20 boy)'s 1 day's work = (15/100 + 20/200) = 1/4
15 men and 20 boys can do the work in 4 days.
Answer = A
Answer: (A) 4 days
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 20% profit on the first article and 20% loss on second article. Find the net profit or loss percent?
(A) neither profit nor loss
(B) 1%
(C) 7%
(D) 6%
(E) 9%
Rationale: Explanation:
Profit on first article = 20% of 1000 = 200.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer: A
Answer: (A) neither profit nor loss
Question: A Deer passed a certain tree at a constant speed of 50 miles per hour while being chased by a Cheetah. Then, 2 minutes later, the Cheetah passed the same tree at a constant speed of 60 miles per hour. If both animals maintained their speeds, how long after the Cheetah passed the tree did the Cheetah catch up with the deer?
(A) 30 min
(B) 3 min
(C) 1 hr
(D) 1 min
(E) 2 min
Rationale: When the Cheetah is at the tree, the deer is 50/30 miles ahead on the highway. (the distance covered in 2 min)
every hour, Cheetah runs 10miles more than the deer. how many hours will it takes it to cover 50/30 miles more? the answer is (50/30)/10 = 1/60=1 min
Answer D
Answer: (D) 1 min
Question: Peeta asks Katniss, 'It is 9 pm as per my watch right now.Do you know what will be the time 23, 999, 997 hours later?'
(A) 5 pm.
(B) 4 pm.
(C) 6 pm.
(D) 7 pm.
(E) 8 pm.
Rationale: Solution:
6pm
Explanation:
The time after 24, 000, 000 hours will be the same as it is now. We want the time 3 hours before that and thus you can deduct three hours from 9 pm. So the time will be 6 pm.
Answer C
Answer: (C) 6 pm.
Question: The quarter of the time from midnight to present time added to the half of the time from the present to midnight gives the present time. What is the present time?
(A) 9 hr 30 min
(B) 9 hr 36 min
(C) 9 hr 46 min
(D) 8 hr 36 min
(E) 9 hr 56 min
Rationale: let the present time be t
given that t/4+(24-t)/2=t
so time is 9 hr 36 min
ANSWER:B
Answer: (B) 9 hr 36 min
Question: Of 70 players on a football team, 37 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total?
(A) 54
(B) 59
(C) 63
(D) 71
(E) 92
Rationale: 37 are throwers and right handed
1/3 of remaining 33, i.e 11 are left handed and remaining are right handed.
Basically, out of 70, only 11 are left handed and remaining 70-11= 59 are right handed.
B is the answer
Answer: (B) 59
Question: . There are 8 men and 10 women and you need to form a committee of 5 men and 6 women. In how many ways can the committee be formed?
(A) 10420
(B) 11
(C) 11760
(D) 11640
(E) None of these
Rationale: We need to select 5 men from 8 men and 6 women from 10 women
Number of ways to do this
= 8C5 × 10C6
= 8C3 × 10C4 [∵ nCr = nC(n-r)]
=((8×7×6)/(3×2×1))*((10×9×8*7)/(4×3×2×1))
=56×210
=11760
ANSWER:C
Answer: (C) 11760
Question: Out of 7 people working on a project, 3 are graduates. If 3 people are selected at random, what is the probability that there is at least one graduate among them?
(A) 17/20
(B) 21/25
(C) 23/30
(D) 31/35
(E) 37/40
Rationale: P(no graduates) = 4C3 / 7C3 = 4/35
P(at least one graduate) = 1- 4/35 = 31/35
The answer is D.
Answer: (D) 31/35
Question: Walking with 4/5 of my usual speed, I miss the bus by 5 minutes. What is my usual time?
(A) 22
(B) 88
(C) 27
(D) 20
(E) 98
Rationale: Speed Ratio = 1:4/5 = 5:4Time Ratio = 4:51 -------- 5 4 --------- ? è 20.Answer: D
Answer: (D) 20
Question: The number of n satisfying -n+2≥0 and 2n≤5 is
(A) 0
(B) 1
(C) 2
(D) 3
(E) None of the above
Rationale: −n+2≥0................−n≥−2..................n≤2−n+2≥0................−n≥−2..................n≤2.
Also 2n≤5.............n≤5/2.............n≤52.
ans is n≤2n≤2..... infinite possible solution.
ANSWER:E
Answer: (E) None of the above
Question: A tradesman by means of his false balance defrauds to the extent of 10%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
(A) 21%
(B) 77%
(C) 44%
(D) 16%
(E) 47%
Rationale: g% = 10 + 10 + (10*10)/100
= 21%
Answer: A
Answer: (A) 21%
Question: The area of a triangle will be when a = 1m, b = 2m, c = 3m, a, b, c being lengths of respective sides.
(A) 0 sq m
(B) 8 sq m
(C) 2 sq m
(D) 8sq m
(E) 4sq m
Rationale: Explanation:
S = (1 + 2 + 3)/2 = 3
=> No triangle exists
Answer: Option A
Answer: (A) 0 sq m
Question: A circular path of 13 m radius has marginal walk 2 m wide all round it. Find the cost of leveling the walk at 25p per m2?
(A) Rs.49
(B) Rs.40
(C) Rs.44
(D) Rs.42
(E) Rs.43
Rationale: Explanation:
π (152 - 132) = 176
176 * 1/4 = Rs.44
Answer: Option C
Answer: (C) Rs.44
Question: The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq. cm. Find the length of the rectangle.
(A) 5
(B) 10
(C) 15
(D) 20
(E) None of them
Rationale: Let breadth = x. Then, length = 2x. Then,
(2x - 5) (x + 5) - 2x * x = 75 <=> 5x - 25 = 75 <=> x = 20.
Therefore, Length of the rectangle = 20 cm.
Answer is D
Answer: (D) 20
Question: A six-sided die is rolled once. What is the probability that the number rolled is an odd number greater than 2?
(A) 2 / 6
(B) 1 / 2
(C) 3 / 3
(D) 4 / 5
(E) 2 / 4
Rationale: 2 / 6
correct answer A
Answer: (A) 2 / 6
Question: What is the principal sum?
I. The sum amounts to Rs. 780 at a rate of 8% p.a. at S.I.
II. The sum amounts to Rs. 1000 in 5 years at S.I.
III. The rate of interest is 8% p.a.
(A) I and III only
(B) II and III only
(C) I and II only
(D) Any two of the three
(E) None of these
Rationale: Explanation:
Clearly, Only the statement II and III is needed and cant be able to find by using I statement
Answer: B
Answer: (B) II and III only
Question: X can do 1/4 of a work in 10 days, Y can do 40% of work in 40 days and Z can do 1/3 of work in 13 days. Who will complete the work first?
(A) D
(B) F
(C) X
(D) Z
(E) W
Rationale: Whole work will be done by X in 10*4 = 40 days.
Whole work will be done by Y in (40*100/40) = 100 days.
Whole work will be done by Z in (13*3) = 39 days
Therefore, Z will complete the work first. The answer is D.
Answer: (D) Z
Question: How many different arrangements of A, B, C, D, and E are possible where A is adjacent to neither B nor D?
(A) 96
(B) 60
(C) 48
(D) 36
(E) 17
Rationale: Total # of permutation of 5 distinct letters will be 5!=120;
Glue A and B together, consider it to be one unit: {AB}{C}{D}{E} --> # of permutation of these 4 units will be 4!=24, A and B within its unit also can be arranged in 2 ways : {AB} or {BA}, so total # of ways to arrange A, B, C, D, and E so that A and B to be together will be 4!*2=48;
The same for A and D: total # of ways to arrange A, B, C, D, and E so that A and D to be together will be 4!*2=48;
Now, the above 48+48=96 cases will contain the arrangements when A is adjacent to both B and D, so we should subtract this cases to get rid of the double counting. The # of case when A is adjacent to both B and D will be: consider {BAD} {C}{E} --> # of permutation of these 3 units will be 3!, {BAD} also can be arranged in 2 ways: {BAD} or {DAB}, so total # of ways to arrange A, B, C, D, and E so that A is adjacent to both B and D will be 3!*2=12;
The # of arrangements when A is adjacent to neither B nor D will be total-(48+48-12)=120-84=36.
Answer: D.
Answer: (D) 36
Question: A boy asked a girl her name she replied your name is behind your scooty Behind the scooty is written 7.3 3.3 9.3 2.3 What is her name
(A) RIAE
(B) RIAF
(C) RIAG
(D) RIBF
(E) SIAF
Rationale: 7.3=21=r
3.3 =9=i
9.3=27%26=1=a
2.3=6=f
ANSWER=RIAF
ANSWER:B
Answer: (B) RIAF
Question: A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 20 sec respectively. What is the speed of the train?
(A) 79.7
(B) 79.9
(C) 79.5
(D) 79.2
(E) 79.1
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 264)/20 = y
y = 22
Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.
Answer: D
Answer: (D) 79.2
Question: A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the direction opposite to that in which the train is going ?
(A) 3.6sec
(B) 18sec
(C) 36sec
(D) 72sec
(E) None
Rationale: Solution
Speed of train relative to jogger =(45-9)km/hr =36km/hr
(36*5/18)m/sec = 10 m/sec
Distance to be covered = (240 +120)m= 360m
∴ Time taken =(360/10)sec= 36 sec
Answer C
Answer: (C) 36sec
Question: In a mixture of milk and water, the proportion of milk by weight was 80%. If, in a 180 gm mixture, 36 gms of pure milk is added, what would be the percentage of milk in the mixture formed?
(A) 83.33%
(B) 83.93%
(C) 83.73%
(D) 83.23%
(E) 83.33%
Rationale: Percentage of milk in the mixture formed = [80/100 (180) + 36] / (180 + 36) * 100% = (144 + 36)/216 * 100% = 5/6 * 100% = 83.33%.AnswerE
Answer: (E) 83.33%
Question: A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 24 hrs and a machine of type S does the same job in 12 hours. If the company used the same number of each type of machine to do the job in 2 hours, how many machines of type R were used?
(A) 3
(B) 4
(C) 6
(D) 8
(E) 12
Rationale: Type R completes 1/24 of the job each hour.
Type S completes 1/12 of the job each hour.
Together R and S complete 1/24 +1/12 = 1/8 of the job each hour.
Let n be the number of each type of machine.
2*n*(1/8) = 1 job completed
n = 4
The answer is B.
Answer: (B) 4
Question: How many ways are there to split a group of 10 students into two groups of 5 students each? (The order of the groups does not matter)
(A) 104
(B) 126
(C) 148
(D) 172
(E) 216
Rationale: 10C5 = 252
If we consider these groups, each group will be counted twice.
The number of ways to choose 2 groups of 5 is 252/2 = 126
The answer is B.
Answer: (B) 126
Question: In how many different number of ways 5 boys and 2 girls can sit on a shopa which can accommodate 5 persons?
(A) 1802
(B) 2500
(C) 2000
(D) 2100
(E) None
Rationale: Option 'E'
7p5 = 7 × 6 × 5 x 4 x 3= 2520
Answer: (E) None
Question: In a graduating class, 40 percent of the students are male. In this class, 40 percent of the male students and 30 percent of the female students are 25 years old or older. If one student in the class is randomly selected, approximately what is the probability that he or she will be less than 25 years old?
(A) 0.66
(B) 0.72
(C) 0.78
(D) 0.84
(E) 0.9
Rationale: Let x be the total number of students.
The number students who are younger than 25 is 0.6*0.4x+0.7*0.6x = 0.66x
The answer is A.
Answer: (A) 0.66
Question: The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?
(A) 5M
(B) 4M
(C) 9M
(D) 2M
(E) 6M
Rationale: Explanation:
Let the sides of the rectangle be l and b respectively.
From the given data,
(√l2 + b2) = (1 + 108 1/3 %)lb
=> l2 + b2 = (1 + 325/3 * 1/100)lb
= (1 + 13/12)lb
= 25/12 lb
=> (l2 + b2)/lb = 25/12
12(l2 + b2) = 25lb
Adding 24lb on both sides
12l2 + 12b2 + 24lb = 49lb
12(l2 + b2 + 2lb) = 49lb
but 2(l + b) = 28 => l + b = 14
12(l + b)2 = 49lb
=> 12(14)2 = 49lb
=> lb = 48
Since l + b = 14, l = 8 and b = 6
l - b = 8 - 6 = 2m.
Answer: Option D
Answer: (D) 2M
Question: How many seconds will a 400 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
(A) 26 sec
(B) 30 sec
(C) 24 sec
(D) 19 sec
(E) 11 sec
Rationale: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 400 * 3/50
= 24 sec.
Answer:C
Answer: (C) 24 sec
Question: In 2008, the profits of Company N were 8 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 15 percent of revenues. The profits in 2009 were what percent of the profits in 2008?
(A) 150%
(B) 105%
(C) 120%
(D) 124.2%
(E) 138%
Rationale: the profit 0f 2009 interms of 2008 = 0.8*15/8*100=150%
A
Answer: (A) 150%
Question: A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train?
(A) 298 m
(B) 178 m
(C) 197 m
(D) 150 m
(E) 167 m
Rationale: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time
= 50/3 * 9
= 150 m
Answer:D
Answer: (D) 150 m
Question: How many alphabets need to be there in a language if one were to make 1 million distinct 3 digit initials using the alphabets of the language?
(A) 254
(B) 100
(C) 132
(D) 503
(E) 50
Rationale: 1 million distinct 3 digit initials are needed.
Let the number of required alphabets in the language be ‘n’.
Therefore, using ‘n’ alphabets we can form n * n * n = n^3 distinct 3 digit initials.
Note distinct initials is different from initials where the digits are different.
For instance, AAA and BBB are acceptable combinations in the case of distinct initials while they are not permitted when the digits of the initials need to be different.
This n^3 different initials = 1 million
i.e. n^3 = 106 (1 million = 106)
=> n^3 = (102)^3 => n = 102 = 100
Hence, the language needs to have a minimum of 100 alphabets to achieve the objective.
Ans:B
Answer: (B) 100
Question: The sum of the present age of Henry and Jill is 43. What is their present ages if 5 years ago Henry was twice the age of Jill?
(A) and 27
(B) and 24
(C) and 22
(D) and 29
(E) of these
Rationale: Let the age of Jill 5 years ago be x, age of Henry be 2x
x+5 + 2x+5 = 43
x = 11
Present ages will be 16 and 27
Answer : A
Answer: (A) and 27
Question: Diana can buy watches at a price of M dollars per watch, which she marks up by a certain percentage before selling. If she makes a total profit of T by selling N watches, then in terms of M and T and N, what is the percent of the markup from her buy price to her sell price?
(A) 100-N/T
(B) NMT/100
(C) N-M/100T
(D) 100T/(NM)
(E) NM/100T
Rationale: Algebraic Solution:If she makes a total profit of T for N watches, then that must be a profit of T/N for each watch. That must be the markup above cost on each watch, the amount of the increase. Well, percent increase = (amount of increase)/(starting amount) x 100% = (T/N)/M *100 = 100T/(NM)
Answer : D
Answer: (D) 100T/(NM)
Question: The ratio of the arithmetic mean of two numbers to one of the numbers is 4:6. What is the ratio of the smaller number to the larger number?
(A) 1:5
(B) 1:4
(C) 1:3
(D) 1:2
(E) 2:3
Rationale: For two numbers, the arithmetic mean is the middle of the two numbers.
The ratio of the mean to the larger number is 4:6, thus the smaller number must have a ratio of 2.
The ratio of the smaller number to the larger number is 2:6 = 1:3.
The answer is C.
Answer: (C) 1:3
Question: If a student loses 5 kilograms, he will weigh twice as much as his sister. Together they now weigh 110 kilograms. What is the student's present weight in kilograms?
(A) 71
(B) 72
(C) 73
(D) 74
(E) 75
Rationale: Let x be the weight of the sister.
Then the student's weight is 2x+5.
x + (2x+5) = 110
3x = 105
x = 35 kg
Then the student's weight is 75 kg.
The answer is E.
Answer: (E) 75
Question: The Simple Interest on Rs. 7300 from 11 May, 1987 to 10 September 1987 ( Both day Include ) at 5% per annum is :
(A) 120
(B) 123
(C) 125
(D) 128
(E) 130
Rationale: Time from 11 May to 10 September, 1987
=21+30+31+31+10 = 123 days
Time : 123 days = 123/365 year
S.I =(7300x123x5)/(365x100)=Rs.123
answer :B
Answer: (B) 123
Question: The average age of an adult class is 40years. 10new students with an avg age of 32years join the class. Therefore decreasing the average by 4year. Find what was theoriginal strength of class?
(A) 10
(B) 12
(C) 15
(D) 17
(E) 18
Rationale: Let original strength = y
Then , 40y + 10 x 32 = ( y + 10) x 36
â‡’ 40y + 320 = 36y + 360
â‡’ 4y = 40
âˆ´ y = 10
A
Answer: (A) 10
Question: The length of minute hand of a clock is 5.2 cm. What is the area covered by this in 10 minutes
(A) 15.27
(B) 14.15
(C) 17.27
(D) 18.27
(E) 19.27
Rationale: area of circle is pi*r^2
but in 10 minutes area covered is (10/60)*360=60 degree
so formula is pi*r^2*(angle/360)=3.14*(5.2^2)*(60/360)=14.15 cm^2
ANSWER:B
Answer: (B) 14.15
Question: A man can row upstream at 25 kmph and downstream at 35 kmph, and then find the speed of the man in still water?
(A) 22
(B) 37
(C) 30
(D) 27
(E) 18
Rationale: US = 25
DS = 35
M = (35 + 25)/2 = 30
Answer:C
Answer: (C) 30
Question: Excluding stoppages,the speed of the bus is 54kmph and
including stoppages,it is 45kmph.for how many min does the bus
stop per hr
(A) 12 min
(B) 11 min
(C) 13 min
(D) 19 min
(E) 17 min
Rationale: Due to stoppages,it covers 9km less.
time taken to cover 9 km is [9/54 *60] min = 10min
Answer is E.
Answer: (E) 17 min
Question: if a@b = a * b^(1/3) then 2@8 = ?
self made
(A) 2
(B) 6
(C) 3
(D) 8
(E) 4
Rationale: a@b = a * b^(1/3)
2@9 = 2*8^(1/3) = 2*2 = 4
Correct Option: E
Answer: (E) 4
Question: Sundar and Raju together can do a piece of work in 8 days. If Sundar alone can do the same work in 12 days, then Raju alone can do the same work in?
(A) 20 days
(B) 22 days
(C) 24 days
(D) 26 days
(E) 28 days
Rationale: Raju work = 1/8 - 1/2 = 1/24 => 24 days
ANSWER C
Answer: (C) 24 days
Question: Jamal had a bag of marbles. He had 12 yellow, 10 blue, 5 green and 1 black marbles. He decided to randomly select a ball from the bag. What is the proabilitly that he will draw a black marble?
(A) 10/28
(B) 1/28
(C) 12/28
(D) 28/1
(E) 582/695
Rationale: B
Answer: (B) 1/28
Question: Jake can dig a well in 16 days. Paul can dig the same well in 24 days. Jake, Paul and Hari together dig the well in 8 days. Hari alone can dig the well in
(A) 96 days
(B) 48 days
(C) 32 days
(D) 24 days
(E) 28 days
Rationale: jake 1 day work=1/16
paul 1 day work=1/24
j+p+h 1 ady work=1/8
1/16+1/24+1/x=1/8
1/x=1/48
x=48
so,Hari alone can dig the well in 48 days
ANSWER:B
Answer: (B) 48 days
Question: What is the 32nd word of "WAITING" in a dictionary?
(A) AIWTNG
(B) AGNTWI
(C) AIGNWT
(D) AGNTIWI
(E) None of these
Rationale: Explanation :
Arranging the words of waiting in Alphabetical Order : A,G,I,I,N,T,W Start with A_ _ _ _ _ _ This can be arranged in 6!/2! ways=720/2=360 ways so can't be arranged starting with A alone as it is asking for 32nd word so it is out of range AG_ _ _ _ _then the remaining letters can be arranged in 5!/2! ways so,120/2=60 ways. Out of range as it has to be within 32 words. AGI_ _ _ _ Now the remaining letters can be arranged in 4! ways =24 AGN _ _ _ _ can be arranged in 4!/2! ways or 12 ways so,24+12 =36th word so out of range. So we should not consider all the words start with AGN now AGNI_ _ _can be arranged in 3! ways =6 ways so 24+6=30 within range Now only two word left so, arrange in alphabetical order. AGNTIIW - 31st word AGNTIWI - 32nd word
Answer : D
Answer: (D) AGNTIWI
Question: A tradesman by means of his false balance defrauds to the extent of 32%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
(A) 74.5%
(B) 74.24%
(C) 84.6%
(D) 24.89%
(E) 45%
Rationale: g% = 32 + 32 + (32*32)/100
= 74.24%
Answer: B
Answer: (B) 74.24%