mathewhe/aqua_rat huggingface dataset:
Question: A, B, and C were to be paid in proportion to the part of work they did while working on the same piece of work. A and B individually can finish the piece of work in 12 days and 15 days respectively. They worked together for five days and then C completed the remaining work all alone. If $1350 was the net sum to be paid for the entire work, what was the average daily wage of B?
(A) $144
(B) $90
(C) $60
(D) $54
(E) $48
Rationale: The correct answer is B.
Answer: (B) $90
Question: For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 105 units raises the average to 55 units per day, what is the value of n?
(A) 8
(B) 10
(C) 12
(D) 14
(E) 16
Rationale: The daily production was raised by 5 units for n days, which has a weighting of 5n.
5n = 105-55 = 50
n = 10
The answer is B.
Answer: (B) 10
Question: A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 900 more than D, what is B's share?
(A) Rs. 500
(B) Rs. 1800
(C) Rs. 2000
(D) Rs. 2500
(E) none of the above
Rationale: Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x - 3x = 900
x = 900.
B's share = Rs. 2x = Rs. (2 x 900) = Rs. 1800.
Answer = B
Answer: (B) Rs. 1800
Question: A man can row downstream at 20 kmph and upstream at 10 kmph. Find the speed of the man in still water and the speed of stream respectively?
(A) 15,2
(B) 15, 4
(C) 15, 8
(D) 15, 5
(E) 15,7
Rationale: Let the speed of the man in still water and speed of stream be x kmph and y kmph respectively.
Given x + y = 20 --- (1)
and x - y = 10 --- (2)
From (1) & (2) 2x = 30 => x = 15, y = 5.
Answer:D
Answer: (D) 15, 5
Question: A man travels 100km by train at 40km/hr, 200km by ship at 20km/hr, 300km by aeroplane at 100km/hr and 100km by car at 50km/hr. What is the average speed for the entire distance?
(A) 35.3km/hr
(B) 40km/hr
(C) 48.9km/hr
(D) 52.6km/hr
(E) 27.6km/hr
Rationale: Total distance traveled = 100+200+300+100 = 700km
Total time taken = 100/40 + 200/20 + 300/100 + 100/50 = 17.5 hrs
Average speed = 700/17.5 = 40km/hr approximately ;
Answer is B
Answer: (B) 40km/hr
Question: A baker filled with a measuring cup with 3/4 cup water. He poured 1/2 of the water into the batter. How much water will the baker needed to add what is left in the cup to have 50% more than what he started with?
(A) 1/8 cup
(B) 3/8 cup
(C) 1/4 cup
(D) 1/2 cup
(E) 6/8 cup
Rationale: 3/4 is the original water in cup .half in batter.So left is 3/8.
so 50% more than what he started was = 3/4+1/2*(3/4)=9/8
Amount of water needed to add = 9/8 - 3/8=6/8
ANSWER:E
Answer: (E) 6/8 cup
Question: How many Kg of sugar must be added to 30 Kg of 2% solution of sugar and water to increase it to a 10% solution?
(A) 2.6Kg
(B) 4Kg
(C) 3.4Kg
(D) 1.8Kg
(E) None of these
Rationale: Explanation :
Solution: Amount of sugar in 30 Kg solution = (2/100 * 30) Kg = 0.6 Kg.
Let x Kg of sugar be added. Then, (0.6+x)/(30+x) = 10/100
60+100x = 300+10x
x = 240/90 = 8/3 = 2.6
Answer : A
Answer: (A) 2.6Kg
Question: A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 6t seconds, then what is the length of the platform?
(A) L
(B) 3L
(C) 5L
(D) 7L
(E) 9L
Rationale: The train passes a pole in t seconds, so velocity v = L/t
(L+P)/v = 6t
(L+P) / (L/t) = 6t
P = 5L
The answer is C.
Answer: (C) 5L
Question: How many liters of water must be evaporated from 50 liters of a 3-percent sugar solution to get a 20-percent solution?
(A) 45
(B) 33 1/3
(C) 27
(D) 16 2/3
(E) 15
Rationale: How many liters of water must be evaporated from 50 liters of a 3-percent sugar solution to get a 20-percent solution?
3% of a 50 liter solution is 1.5L. So you are trying to determine how many liters must a solution be for the 1.5L to represent 20% of the solution. Set up an inequality and solve for x:
1.5/x = 1/20
x = 30
Since you need a 15L solution, you must evaporate 45 of the original 50L solution to get a 20% solution.
Answer is A.
Answer: (A) 45
Question: By selling 50 meters of dress. I gain the selling price of 15 meters. Find the gain percent?
(A) 52 6/9%
(B) 45 8/7%
(C) 42 6/7%
(D) 12 8/3%
(E) 56 6/7%
Rationale: C
SP = CP + g
50 SP = 50 CP + 15 SP
35 SP = 50 CP
35 --- 15 CP gain
100 --- ? => 42 6/7%
Answer: (C) 42 6/7%
Question: In an exam, Amar scored 64 percent, Bhavan scored 36 percent and Chetan 44 percent. The maximum score awarded in the exam is 800. Find the average mark scored by all the three boys?
(A) 384
(B) 127
(C) 276
(D) 998
(E) 267
Rationale: Average mark scored by all the three boys =
[64/100 (800) + 36/100 (800) + 44/100 (800)] / 3 = 384.Answer: A
Answer: (A) 384
Question: √{(8.2)(10^9)} is closest to which of the following?
(A) 6,000
(B) 12,000
(C) 30,000
(D) 50,000
(E) 90,000
Rationale: √{(8.2)(10^9)} = √{(82)(10^8)} = √(82)√(10^8) = (√82) * 10,000 which is about 90,000.
The answer is E.
Answer: (E) 90,000
Question: A bank offers 5% C.I. calculated on half-yearly basis . A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is?
(A) 126
(B) 121
(C) 165
(D) 134
(E) 123
Rationale: Amount = [1600 * (1 + 5/(2 * 100)2 + 1600 * (1 + 5/(2 * 100)]
= [1600 * 41/40(41/40 + 1)
= [(1600 * 41 * 81)/(40 * 40)]
= Rs. 3321.
C.I. = 3321 - 3200 = Rs.121.
Answer:B
Answer: (B) 121
Question: If 9 is added to thrice a number and this sum is multiplied by 6, the result is the same as if the number is multiplied by 7 and 10 is added to the product. What is the number?
(A) -7
(B) -8
(C) -9
(D) -10
(E) -11
Rationale: let the number be x;
6(9+3x)=7x+10;
x=-11
ANSWER:E
Answer: (E) -11
Question: At a company, the average wage of male employees is $6 per hour, and the average wage of female employees is $8 per hour. If the average wage of all employees is $7.5 per hour, what is the ratio of the number of male employees to the number of female employees?
(A) 1 to 3
(B) 2 to 3
(C) 3 to 2
(D) 5 to 3
(E) 2 to 1
Rationale: Average hourly wage of male employees = 6 $
Average hourly wage of female employees = 8 $
Average hourly wage of all employees = 7.5 $
Let number of male employees = m
number of female employees = f
7.5 = (6m + 8f ) / m+f
=>7.5m + 7.5f = 6m + 8f
=> .15m = .5f
=> m/f = .5/.15 = 1/3
Answer A
Answer: (A) 1 to 3
Question: There is food for 760 men for 22 days. How many more men should join after two days so that the same food may last for 19 days more?
(A) 11
(B) 40
(C) 66
(D) 55
(E) 44
Rationale: 760 ---- 22
760 ---- 20
x ----- 19
x*19 = 760*20
x = 800
760
-------
40
Answer:B
Answer: (B) 40
Question: Find the odd pair of numbers
1) 55 - 42
2) 69 - 56
3) 48 - 34
4) 95 - 82
5) 45 - 32
(A) 55-42
(B) 69-56
(C) 48-34
(D) 95-82
(E) 45-32
Rationale: minus the numbers
55-42=13
69-56=13
48-34=14
95-82=13
45-32=13
here 48-34 = 14 which is not similar to the other, so 48 - 34 is the odd pair of numbers. correct answer (C)
Answer: (C) 48-34
Question: An article costing rs.160 is sold at 20% discount on a mark-up price. What is the selling price after
discount?
(A) 106
(B) 116
(C) 128
(D) 136
(E) 146
Rationale: 160*80/100=128
ANSWER:C
Answer: (C) 128
Question: Evaluate: 37 - 18÷3×2 =
(A) 20
(B) 25
(C) 27
(D) 22
(E) 17
Rationale: According to order of operations, 18÷3×2(division and multiplication) is done first from left to right
18÷3×2 = 6 × 2 = 12
Hence
37 - 18÷3×2 = 37 - 12 = 25
correct answer B)25
Answer: (B) 25
Question: Three dice are thrown together, Find the probability of getting a total of 5?
(A) 1/2
(B) 1/5
(C) 3/8
(D) 3/14
(E) 1/36
Rationale: Three different dice are thrown at the same time.
Therefore, total number of possible outcomes will be 63 = (6 × 6 × 6) = 216.
Number of events of getting a total of 5 = 6
i.e. (1, 1, 3), (1, 3, 1), (3, 1, 1), (2, 2, 1), (2, 1, 2) and (1, 2, 2)
Therefore, probability of getting a total of 5
P(E1) = Number of favorable outcomes/Total number of possible outcome
= 6/216
= 1/36
Answer: (E) 1/36
Question: The average marks in mathematics scored by the pupils of a school at the public examination were 39. If four of these pupils who actually scored 5, 12, 15 and 19 marks at the examination had not been sent up, the average marks for the school would have been 44. Find the number of pupils sent up for examination from the school?
(A) 25
(B) 20
(C) 30
(D) 35
(E) 40
Rationale: 39x = 5 + 12 + 15 + 19 + (x â€“ 4)44
x = 25
ANSWER A
Answer: (A) 25
Question: If xy > 0, 1/x + 1/y = 6, and 1/xy = 5, then (x+y)/6 = ?
(A) 1/25
(B) 1/6
(C) 1/5
(D) 5
(E) 6
Rationale: (1/X+1/Y)=6 canbe solved as {(x+y)/xy}=5. Substituting for 1/xy=5, we get
x+y=6/5
==> (x+y)/6= 6/(5*6)=1/5.
C
Answer: (C) 1/5
Question: A function g(n), where n is an integer, is defined as the product of all integers from 1 to n. How many of the followings must be a prime number?
g(12) + 2; g(12) + 3; g(12) + 4; and g(12) + 5?
(A) 1
(B) 2
(C) 3
(D) 4
(E) none
Rationale: g(12) is the product of all integers from 1 to 12, so g(12) = 12!
Thus g(12) is a multiple of all the integers from 1 to 12.
Then g(12) is a multiple of 2, 3, 4, and 5.
2 divides g(12)+2
3 divides g(12)+3
4 divides g(12)+4
5 divides g(12)+5
The answer is E.
Answer: (E) none
Question: A man sells a house for Rs.5,00,000 and loses something, if he had sold it for Rs.6,00,000, his gain would have been trible the former loss. Find the cost price of the horse?
(A) 5,50,000
(B) 5,25,000
(C) 5,20,000
(D) 5,02,000
(E) 6,00,200
Rationale: CP = SP + 1CP = SP - g
5,00,000 + x = 6,00,000 - 3x
4x = 1,00,000=> x = 2000
CP = 5,00,000 +2000 = 5,02,,000
Answer: D
Answer: (D) 5,02,000
Question: Set J consists of the terms {a, b, c, d, e}, where e > d > c > b > a > 2. Which of the following operations would decrease the standard deviation of Set J?
(A) Divide each term by 2.2
(B) Divide each term by b/c
(C) Multiply each term by −1
(D) Divide each term by d/e
(E) Multiply each term by c
Rationale: CONCEPT: Standard Deviation is Defined as Average Deviation of Terms in the set from the Mean value of the set. i.e.
1) It depends on the separation between the successive terms of the set
2) If a Constant Value is Added/Subtracted in every terms of set then the Separation between successive terms does NOT change Hence S.D. remains Constant
3) If a Constant Value is Multiplied in every terms then the Separation between succesive terms gets multiplied by the constant Hence S.D. remains gets multiplied by same Number
A
Answer: (A) Divide each term by 2.2
Question: Alan bought 180 packets of chocolate. He was able to sell 1/3 of them at a 5% profit, another 1/3 of them at zero profit and the remainder was sold at a 10% loss. Find the total profit or loss made by Alan after selling those 150 packets. A packet sold at a loss had a price of $9.
It's a bit confusing to say 5% of profit. Please provide an intuitive answer if possible. Thanks!!
(A) 0
(B) Profit of $20
(C) Loss of $25
(D) Profit of $30
(E) Loss of $30
Rationale: A packet sold at a 10% loss had a price of $9, thus the cost of a packet is $10.
60 packets was sold at a 5% profit --> gives profit of 10*0.05*60 = $30.
60 packets was sold at a 10% loss --> gives loss of 10*0.1*60 = $60.
The overall loss is $30 - $60 = $30.
Answer: E.
Answer: (E) Loss of $30
Question: Each of the positive integers a, b, and c is a three-digit integer. If each of the digits 0 through 8 appears in one of these three integers, what is the minimum possible value of the sum of a, b, and c?
(A) 45
(B) 666
(C) 711
(D) 801
(E) 1368
Rationale: According to the stem we should use the digits 0 through 7 to construct 3 three-digit integers, so that their sum is as small as possible.
To minimize the sum, minimize the hundreds digits of a, b, and c, so make them 1, 2, and 3.
Next, minimize tens digits. Make them 0, 4, and 5.
Use the remaining digits (6, 7, and 8) for units digits.
So, a would be 106, b would be 247 and c would be 358.
106 + 247 + 358 = 711.
Answer: C.
Answer: (C) 711
Question: what is sum of fist 10 prime numbers?
(A) 128
(B) 129
(C) 117
(D) 123
(E) 121
Rationale: primes are of the form 6n+1 or 6n-1
1st 10 prime numbers are = 2, 3, 5, 7, 11, 13, 17, 19, 23, 29
sum of above numbers = 129
B
Answer: (B) 129
Question: Rahim bought 65 books for Rs.6500 from one shop and 35 books for Rs.2000 from another. What is the average price he paid per book ?
(A) 80
(B) 138
(C) 100
(D) 129
(E) 85
Rationale: Average price per book
= (6500+ 2000) / (65 + 35)
= 8500 / 100
= Rs.85
Answer:E
Answer: (E) 85
Question: My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age of when my brother was born, then, what was the age of my father and mother respectively when my brother was born?
(A) 32 yrs, 23 yrs
(B) 32 yrs, 29 yrs
(C) 35 yrs, 29 yrs
(D) 35 yrs, 33 yrs
(E) none
Rationale: Sol.
Clearly, my brother was born 3 years before I was born and 4 years after my sister was born.
So, father's age when brother was born = (28 + 4) = 32 years.
mother's age when was born = (26 - 3) years = 23 years.
Answer A
Answer: (A) 32 yrs, 23 yrs
Question: Jane and Thomas are among the 8 people from which a committee of 3 people is to be selected. How many different possible committees of 3 people can be selected from these 8 people if at least one of either Jane or Thomas is to be selected?
(A) 24
(B) 28
(C) 32
(D) 36
(E) 40
Rationale: The total number of ways to choose 3 people from 8 is 8C3 = 56.
The number of committees without Jane or Thomas is 6C3 = 20.
There are 56-20 = 36 possible committees which include Jane and/or Thomas.
The answer is D.
Answer: (D) 36
Question: An amount of money is to be distributed among Faruk, Vasim and Ranjith in the ratio 3 : 5 : 8. If Vasims share is Rs. 1500, what is the difference between Faruk's and Ranjith's shares?
(A) s 1200
(B) s 1500
(C) s 1600
(D) s 1900
(E) s 1700
Rationale: Explanation :
Let P = Faruk, Q = Vasim, R = Ranjith
Let P = 3x, Q = 5x and R = 8x.
Then, 5x = 1500 ? x = 300. P=900,Q=1500 and R = 2400.
Hence, (R - p) = (2400 - 900) = 1500
Answer : B
Answer: (B) s 1500
Question: If (1+k)l=l, which of the following must be true?
(A) k=-1 or l=0
(B) k=0 or l=0
(C) k=1 or l=1
(D) k=-1 or l=-1
(E) k=0 or l=1
Rationale: By only having kl=0, we cannot say answer is B as A and E options also satisfy the condition kl=0. ans B
Answer: (B) k=0 or l=0
Question: The surface area of a sphere is 4πR2, where R is the radius of the sphere. If the area of the base of a hemisphere is 3, what is the surface area T of that hemisphere?
(A)  6/π
(B)  9/π
(C)  6
(D)  9
(E)  12
Rationale: Given Area of the base of a hemisphere is 3 = PI * R^2
Thus R = Sqrt ( 3 / PI ) .
Surface area of whole sphere = 4*PI*R^2 .
= 4 * PI * 3 / PI
= 12 .
Since the hemisphere is half of a sphere the Surface area of the hemisphere = 12 / 2
= 6 ( curved part , not including the flat rounded base ) .
But the total surface area = 6 + Area of the base of a hemisphere .
= 6 + 3
= 9.
Answer is D !!
Answer: (D)  9
Question: A group of 4 investment bankers and 5 clients recently frequented the Bonbon Ribs Restaurant. The total bill for the meal, including 20% gratuity, came to $756. On average, how much did the meal of each individual cost before gratuity?
(A) $160
(B) $70
(C) $90
(D) $80
(E) $55
Rationale: 4 IBs and 5 clients - so total 9 people
The bill $756 includes 20% gratuity... so the actual cost of dinner was $630
Now, the cost per person will be $630/9 which is $70
Option B
Answer: (B) $70
Question: Two water pumps, working simultaneously at their respective constant rates, took exactly six hours to fill a certain swimming pool. If the constant rate of one pump was 1.5 times the constant rate of the other, how many hours would it have taken the faster pump to fill the pool if it had worked alone at its constant rate?
(A) 8
(B) 10
(C) 12
(D) 14
(E) 16
Rationale: Let x be the rate of the slower pump. Then 1.5x is the rate of the faster pump.
Both pumps together can fill 1/6 of the pool each hour.
2.5x = 1/6
x = 1/15
1.5x = 1.5/15 = 1/10
The faster pump could fill the pool in 10 hours.
The answer is B.
Answer: (B) 10
Question: A boat having a length 4 m and breadth 3 m is floating on a lake. The boat sinks by 1cm when a man gets on it. The mass of the man is:
(A) 12 kg
(B) 120 kg
(C) 72 kg
(D) 96 kg
(E) None of these
Rationale: Explanation:
Volume of water displaced = (4 x 3 x 0.01) m3
= 0.12 m3.
∴ Mass of man = Volume of Water displaced x Density of water
= (0.12 x 1000)kg
= 120 kg.
Answer: B
Answer: (B) 120 kg
Question: A sum of money lent out at S.I. amounts to Rs. 850 after 2 years and to Rs. 1020 after a further period of 5 years. The sum is?
(A) s.440
(B) s. 500
(C) s. 540
(D) s. 782
(E) s. 840
Rationale: S.I for 5 years = (1020 - 850) = Rs. 170.
S.I. for 2 years = 170/5 * 2 = Rs. 68.
Principal = (850 - 68) = Rs. 782.
ANSWER:D
Answer: (D) s. 782
Question: When Robert discontinued his retainer-ship contract with a Pvt Company, management held his fees Rs. 15000/- for one month. Earlier Robert had taken an advance fees of 7280/- from company. But Robert forget that. After one month Robert asked his fees and accountant gives Rs.18500/- to him. What is the incentive amount given to Robert?
(A) A)9500
(B) B)12500
(C) C)10780
(D) D)10500
(E) E)8600
Rationale: Total fees = Rs.15000/-
Advance Money = 7280/-
Balance Salary = 15000-7280= 7720
Paid amount = 18500/-
Incentive amount = 18500-7720 = 10780/-
Answer is C
Answer: (C) C)10780
Question: The list price of an article is Rs.65. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?
(A) 2
(B) 4
(C) 5
(D) 67
(E) 8
Rationale: 65*(90/100)*((100-x)/100) = 56.16
x = 4%
Answer: B
Answer: (B) 4
Question: A factory producing tennis balls stores them in either big boxes, 25 balls per box, or small boxes, 20 balls per box. If 146 freshly manufactured balls are to be stored, what is the least number of balls that can be left unboxed?
(A) 2
(B) 3
(C) 4
(D) 1
(E) 5
Rationale: We have to work with multiples of 20 and 25.
First, we must know the limits of this multiples, so:
146/25= 5....so the max is 5
146/20=7...so the max is 7
146-145 =1 ( 6 small box +1 big box)
Answer : D
Answer: (D) 1
Question: Three cards are randomly selected, one at a time (without return), from a standard deck of 52 cards. What is the probability that all three cards are hearts? (Answer in lowest terms).
(A) 11/850
(B) 1/4
(C) 1/16
(D) 1/107
(E) 20/21
Rationale: A standard deck has 52 cards of which 1/4 are hearts, so the probability of getting a heart is P(H) = 1/4 on the first selected card.
Because selection is (without return), the P(H) has changed for following selections. Now, there are 51 cards and number hearts is dependent upon whether first card was a heart, or not... and so on.... Therefore, conditional probability! The probability that event B occurs, given that event A has already occurred is:
Formula = P(A\B) = P(A and B)/P(B).
P(A\B) = (13/52)(12/51)(11/50) = 1716/132600 = 11/850
Answer: A
Answer: (A) 11/850
Question: If a/b = 1/2, then the numerical value of which of the following expressions cannot be determined?
(A) 2a/b
(B) (a + b)/a
(C) (a + 1)/(b + 1)
(D) (a - 3b)/(a + b)
(E) 6a – 3b
Rationale: a/b = 1/2
=> b = 2a
A.	2a/b
= 2*(a/b)
Can be determined
B.	(a + b)/a
Dividing numerator and denominator by a ,
1+(b/a)
Can be determined
C.	(a + 1)/(b + 1)
= (a + 1)/(2a+1)
Numerical value can't be determined
D.	(a - 3b)/(a + b)
Dividing numerator and denominator by b,
=(a/b - 3 )/ (a/b+ 1 )
Can be determined
E.	6a – 3b
= 6a - 3*2a = 0
Answer C
Answer: (C) (a + 1)/(b + 1)
Question: The average age of 35 students in a class is 16 years. The average age of 21 students is 14. What is the average age of remaining 14 students?
(A) 14 years
(B) 17 years
(C) 19 years
(D) 21 years
(E) None
Rationale: Solution
Sum of the ages of 14 students	= (16 x 35) - (14 x 21)
= 560 - 294.
= 266.
∴ Required average	= 266 / 14
= 19 years.
Answer C
Answer: (C) 19 years
Question: A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
(A) 10 lr
(B) 9 lr
(C) 12 lr
(D) 13 lr
(E) 15 lr
Rationale: Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters.
ANSWER A
Answer: (A) 10 lr
Question: If six persons sit in a row, then the probability that three particular persons are always together is ?
(A) 1/6
(B) 1/2
(C) 1/5
(D) 1/2
(E) 1/1
Rationale: Six persons can be arranged in a row in 6! ways. Treat the three persons to sit together as one unit then there four persons and they can be arranged in 4! ways. Again three persons can be arranged among them selves in 3! ways. Favourable outcomes = 3!4! Required probability = 3!4!/6! = 1/5
Answer: C
Answer: (C) 1/5
Question: A car that moves at an average speed of 60 kmph, reaches its destination on time. When its average speed becomes 50 kmph, then it reaches its destination 45 minutes late. Find the length of journey.
(A) 189 km
(B) 225 km
(C) 255 km
(D) 199 km
(E) None
Rationale: Sol.
Difference between timings = 45 min = 3/4 hr.
Let the length of journey be x km.
Then, x/50 - x/60 = 1/4
â‡” 6x - 5x = 225
â‡” x = 225 km.
Answer B
Answer: (B) 225 km
Question: Before leaving home for the town of Madison, Pete checks a map which shows that Madison is 5 inches from his current location, Gardensquare. Pete arrives in Madison 5 hours later and drove at an average speed of 60 miles per hour. At what scale, in inches per mile, is the map drawn?
(A) 1/3
(B) 1/30
(C) 1/10
(D) 1/45
(E) 1/60
Rationale: Pete covered 5*60=300 miles which correspond to 5 inches on the map --> scale in inches per mile is 5/300=1/60.
Answer: E.
Answer: (E) 1/60
Question: Find the number of square tiles to cover the floor of a room measuring 3.5 m * 12.5 m leaving 0.25 m space around the room. A side of square tile is given to be 60 cms?
(A) 36
(B) 100
(C) 36
(D) 1000
(E) 212
Rationale: 3 *12 = 6/10* 6/10 * x => x =100
Answer: B
Answer: (B) 100
Question: A boat can travel 1.8 times the distance down the stream than up the stream in the same time. If the speed of the current is 3 KMPH, Find the speed of the boat in still water
(A) 5
(B) 10.5
(C) 15
(D) 20
(E) 25
Rationale: Simple question, messy language.
Lets say boat's speed is B and current's speed is C.
Upstream speed : B - C
Downstream speed : B + C
Distance will be the same both times. lets say D.
given : time it takes upstream = 1.8 times time it takes downstream
D/(B + C) = 1.8 * [D/(B - C)]
Solving B = 3.5 C
given : C is 3 KMPH
So B is 10.5 KMPH
B
Answer: (B) 10.5
Question: Average of all prime numbers between 30 to 45
(A) 38
(B) 37.8
(C) 39
(D) 39.8
(E) 40
Rationale: Explanation:
Prime numbers between 30 and 45 are:
31, 37, 41, 43
Average of prime numbers between 30 to 45 will be
(31+37+41+43 / 4)=152 / 4=38
Option A
Answer: (A) 38
Question: A and B can together finish a work in 40days. They worked together for 10days and then B left. After another 18 days, A finished the remaining work. In how many days A alone can finish the job?
(A) 10
(B) 24
(C) 60
(D) 30
(E) 20
Rationale: A+B 10days work = 10*1/40 = 1/4
Remaining work = 1-1/4 = 3/4
3/4 work is done by A in 18 days
whole work will be done by A in 18*4/3 = 24 days
Answer is B
Answer: (B) 24
Question: There are 20cm, 21cm, 22cm,23cm, 24cm,25cm rods of quantities 2,3,6,4,3,2 respectively. Find average of this data.
(A) 32.25
(B) 21.45
(C) 45
(D) 22.45
(E) 22
Rationale: Average = ( 20*2+21*3+22*6+23*4+24*3+25*2 )/20 =22.45 Answer : D
Answer: (D) 22.45
Question: A man buys an article for rs.27.50 and sells it for rs.28.50. find his gain %.
(A) 7%
(B) 4%
(C) 5%
(D) 9%
(E) 8%
Rationale: cp=rs27.50, sp=rs 28.50
gain=rs(28.50 –27.50)=rs1.10
so gain%={(1.10/27.50)*100}=4%
Ans:B
Answer: (B) 4%