mathewhe/aqua_rat huggingface dataset:
Question: How many words can be formed by using all letters of the word 'AROUND' ?
(A) 712
(B) 720
(C) 757
(D) 736
(E) 742
Rationale: The word AROUND contains 6 different letters
Required number of words = 6P6 = 6! = 6*5*4*3*2*1 = 120
Answer is B
Answer: (B) 720
Question: The original price of a shirt was $20. It was decreased to $15 . What is the percent decrease of the price of this shirt.
(A) 25%
(B) 35%
(C) 45%
(D) 55%
(E) 65%
Rationale: The absolute decrease is
20 - 15 = $5
The percent decrease is the absolute decrease divided by the the original price (part/whole).
percent decease = 5 / 20 = 0.25
Multiply and divide 0.25 to obtain percent.
percent decease = 0.25 = 0.25 * 100 / 100 = 25 / 100 = 25%
Answer A
Answer: (A) 25%
Question: A tank of 100 litres is filled with kerosene. Ram replaces 10% of kerosene with water and repeats this procedure 4 times. What is the amount of kerosene left in the tank?
(A) 65.60 litres
(B) 65.71 litres
(C) 25.61 litres
(D) 65.61 litres
(E) 65.31 litres
Rationale: Explanation:
As Ram replaces 10% of kerosene with water, the amount of kerosene left is 90%.
As the replacement is done four times,
After 1st replacement, kerosene left is : 0.9*100 = 90 litres
After 2nd replacement, kerosene left is : 0.9*90 = 81 litres
After 3rd replacement, kerosene left is : 0.9*81 = 72.9 litres
After 4th replacement, kerosene left is : 0.9*72.9 = 65.61 litres
ANSWER: D
Answer: (D) 65.61 litres
Question: A gets 3 times as much money as B gets, B gets only Rs.25 more then what C gets. The three gets Rs.675 in all. Find the share of B?
(A) 130
(B) 120
(C) 218
(D) 140
(E) 145
Rationale: A+B+C = 675
A = 3B
3B+B+B-25 = 675
5B = 700
B = 140
Answer: D
Answer: (D) 140
Question: If a:b:c = 3:4:7, then the ratio (a+b+c):c is equal to
(A) 2:1
(B) 14:3
(C) 7:2
(D) 1:2
(E) None
Rationale: Solution: (a+b+c) = 3+4+7 = 14 and
c = 7 Then, (a+b+c):c = 2:1.
Answer: Option A
Answer: (A) 2:1
Question: If p and y are both odd prime numbers and p < y, how many distinct positive integer factors does 2py have?
(A) 3
(B) 4
(C) 6
(D) 8
(E) 12
Rationale: Since 2py prime factors are p^1*y^1*2^1, its total number or factors must be (1+1)(1+1)(1+1)=2^3=8. Thus, I think D would be the correct answer.
Answer: (D) 8
Question: A driver goes on a trip of 50 kilometers, the first 25 kilometers at 60 kilometers per hour and the remaining distance at 30 kilometers per hour. What is the average speed of the entire trip in kilometers per hour?
(A) 35
(B) 36
(C) 40
(D) 42
(E) 45
Rationale: The time for the first part of the trip was 25/60 = 5/12 hours.
The time for the second part of the trip was 25/30 = 5/6 hours.
The total time for the trip was 5/12 + 5/6 = 15/12 = 5/4 hours.
The average speed for the trip was 50 / (5/4) = 40 kph
The answer is C.
Answer: (C) 40
Question: The number 110 can be written as sum of the squares of 3 different positive integers. What is the sum of these 3 different integers?
(A) 10
(B) 12
(C) 18
(D) 14
(E) 17
Rationale: sum of the squares of 3 different positive integers = 110
5^2 + 6^2 + 7^2 = 110
now,
sum of these 3 different integers = 5 + 6 + 7 = 18
Ans - C
Answer: (C) 18
Question: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?
(A) 66
(B) 67
(C) 68
(D) 69
(E) 70
Rationale: Let the total volume of original bottle be x
Then question says 40% of x is oil.
Also question mentions that there is 8ml of oil in original bottle.
Set up equation--> 40% of x = 8
40 * x /100 = 8
x=20.
Hence oil in original container is = 8mL (40 % of total volume)
vinegar in original container is = 4mL (20 % of total volume)
water in original container is = 8mL. (40 % of total volume)
Now we take a container which has 4 times volume of original container.
So, volume of new container = 4*20=80
In this new container we pour oil, vinegar and water from original container.
Volume occupied in new container by oil, vinegar and water from original container = 8+4+8=20mL
Hence volume left in new container = 80 - 20 = 60mL
As per question, remaining space in the larger bottle is then filled with water. i.e 60mL is filled with water.
Hence total water in new container = 60 mL + 8mL(this one poured from old container)
=68mL
ANSWER:C
Answer: (C) 68
Question: 9548 + 7314 = 6362 + (?)
(A) 8300
(B) 8400
(C) 8500
(D) 8700
(E) 10000
Rationale: 9548 16862 = 6362 + x
+ 7314 x = 16862 - 6362
----- = 10500
16862
-----
E)
Answer: (E) 10000
Question: There are 6 boxes numbered 1, 2,…,.6. Each box is to be filled up either with a red or a green ball in such a way that at least 1 box contains a green ball and the boxes containing green balls are consecutively numbered. The total number of ways in which this can be done is
(A) 45
(B) 35
(C) 63
(D) 15
(E) 21
Rationale: List down possibilities: From only 1 box all the way to all 6
If only one of the boxes has a green ball, it can be any of the 6 boxes. So, we have 6 possibilities.
If two of the boxes have green balls and then there are 5 consecutive sets of 2 boxes. 12, 23, 34, 45, 56.
If 3 of the boxes have green balls, there are 4 possibilities: 123, 234, 345, 456.
If 4 boxes have green balls, there are 3 possibilities: 1234, 2345, 3456.
If 5 boxes have green balls, there are 2 possibilities: 12345, 23456.
If all 6 boxes have green balls, there is just 1 possibility.
Total number of possibilities = 6 + 5 + 4 + 3 + 2 + 1 = 21.
Ans: E
Answer: (E) 21
Question: A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 190 m long?
(A) 44
(B) 99
(C) 88
(D) 77
(E) 21
Rationale: :
Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 190 = 550 m
Required time = 550 * 2/25 = 44 sec
Answer:A
Answer: (A) 44
Question: A Man can row upstream at 75kmph and downward stream at 47 kmph. Find Man's rate of the current
(A) 87km/hr
(B) 20km/hr
(C) 65km/hr
(D) 28km/hr
(E) 14km/hr
Rationale: Rate of the current=1/2(75-47)km/hr
=14km/hr
correct option is :E
Answer: (E) 14km/hr
Question: If it is assumed that 80 percent of those who receive a questionnaire by mail will respond and 300 responses are needed, what is the minimum number of questionnaires that should be mailed?
(A) 375
(B) 420
(C) 480
(D) 500
(E) 600
Rationale: Minimum no of mail to be sent for getting 300 responses at 80%
= 300/0.8 = 375
Option A
Answer: (A) 375
Question: A box contain 7 one rupee coins and 5 ten rupee coins.A coin is drawn at random.What is the probability that the coin drawn is ten rupee coin?
(A) 5/12
(B) 7/12
(C) 12/5
(D) 12/7
(E) 4/5
Rationale: Total number of coins = 7+5 = 12
no. of ten rupee coins = 5
probability of drawn a ten rupee coin= 5/12
Answer is A
Answer: (A) 5/12
Question: By selling a book for 270, 20% profit was earned. What is the cost price of the book?
(A) 215
(B) 225
(C) 230
(D) 235
(E) 240
Rationale: SP = 120% of CP; :. CP = 270 × 100/120 = 225
Option 'B'
Answer: (B) 225
Question: The sum of ages of 5 children born 3 years different each is 50 years. What is the age of the Elder child?
(A) 8
(B) 9
(C) 10
(D) 16
(E) 17
Rationale: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
x+12= 4+12= 16
D
Answer: (D) 16
Question: If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is?
(A) 50
(B) 20
(C) 30
(D) 25
(E) 5
Rationale: Let the actual distance traveled is 'x' km
Then by given conditions, we have
x/10 = (x+20)/14
14x = 10x + 200
x = 50 km
Ans- A
Answer: (A) 50
Question: A man is walking at a speed of 10 km per hour. After every kilometre, he takes rest for 3 minutes. How much time will be take to cover a distance of 3 kilometres?
(A) 48 min.
(B) 50 min.
(C) 45 min.
(D) 55 min.
(E) 24 min.
Rationale: Rest time = Number of rest Ã— Time for each rest
= 2 Ã— 3 = 6 minutes
Total time to cover 3 km
= (3â„10 Ã— 60)minutes + 6 minutes = 24 minutes
Answer E
Answer: (E) 24 min.
Question: When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died?
(A) 40 yrs
(B) 50 yrs
(C) 60 yrs
(D) 70 yrs
(E) 80 yrs
Rationale: let average age 10 yrs ago was x yrs,
total age 10 yrs before was 6x yr ,
at present,father died, now members remains= 5,
now total age after 10 yrs is (no. of member)*(x+10) yrs,i.e.total age is 5(x+10)
and after baby born total age = 5(x+10)+0, because baby age is 0 yrs
as per ques. both time, age is same i.e. 6x=5x+50+0
after solving.. x=50,i.e. father's age before 10 yrs was 50 yrs,
now father died after 10 yrs hence age at dead time= 50+10=60 yrs.
ANSWER:C
Answer: (C) 60 yrs
Question: At a company, the average wage of male employees is $4 per hour, and the average wage of female employees is $8 per hour. If the average wage of all employees is $7 per hour, what is the ratio of the number of male employees to the number of female employees?
(A) 1 to 3
(B) 2 to 3
(C) 3 to 2
(D) 5 to 3
(E) 2 to 1
Rationale: Average hourly wage of male employees = 4 $
Average hourly wage of female employees = 8 $
Average hourly wage of all employees = 7 $
Let number of male employees = m
number of female employees = f
7= (4m + 8f ) / m+f
=>7m + 7f = 4m + 8f
=> 3m = 1f
=> m/f = 1/3
Answer A
Answer: (A) 1 to 3
Question: AMS employs 6 professors on their staff. Their respective probability of remaining in employment for 10 years are , 0.4, 0.5, 0.6, 0.7, 0.8, 0.9. The probability that after 10 years 6 of them still work in AMS is ?
(A) 0.06048
(B) 1.22
(C) 0.1
(D) 0.16
(E) none of these
Rationale: Asking 6 of them continue ,
it has 1 case.
3 6 professors continue
=0.4*0.5*0.6*0.7*0.8*0.9 =0.06048
A
Answer: (A) 0.06048
Question: Calculate how many ways a woman who has 4 bags and 6 books can put the books in her bag?
(A) 4296
(B) 4056
(C) 4016
(D) 4096
(E) 3096
Rationale: First books can be put in 4 ways, similarly second, third , forth, fifth and sixth book also can be put in 4 ways.
So total number of ways = 4 x 4 x 4 x 4 x 4 x 4 = 4096
D
Answer: (D) 4096
Question: The product of two fractions is 3/4 and their quotient is 6/18. If the denominator of one is 1/3 of the other's numerator, then find the pair of fractions?
(A) 1/3, 9/5
(B) 1/2, 3/2
(C) 1/2, 6/5
(D) Data inadequate
(E) None of these
Rationale: Explanation:
Let A = x/y, and B be two fractions
It is given that A*B = 3/4
Therefore x/y * B = 3/4
B = 3y/4x
Therefore, A = x/y and B = 3y/4x
It is given that A/B = (x/y) / (3y/4x) = 6/18
Therefore x/y * 4x/3y = 6 /18
Therefore 4x2/3y2 = 6/18
x2/y2 = 18/(4*18)
Therefore, x2/y2 = ¼
x/y = 1/2
B = 3y/4x = 3/4 (1/(x/y)) = 3/4 [1/(1/2)] = 6/4
Therefore A = 1/2 and B = 3/2
ANSWER B
Answer: (B) 1/2, 3/2
Question: A train 220 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 20 seconds. The speed of the train is:
(A) 41
(B) 40.6
(C) 40.8
(D) 42
(E) 42.6
Rationale: Speed of the train relative to man =220/20
=11 m/sec.
=11x18/5km/hr
= 198/5km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 198/540.6 km/hr.
Answer:B
Answer: (B) 40.6
Question: If 20% of x is 15 less than 15% of 1500, then x is?
(A) 872
(B) 738
(C) 837
(D) 840
(E) 1050
Rationale: 20% of x = x/5 ; 15% of 1500
= 15/100 * 1500 = 225
Given that, x/5 = 225 - 15
=> x/5 = 210 => x = 1050.
Answer:E
Answer: (E) 1050
Question: A contractor is engaged for 30days on the condition that he receives Rs.25 for each dayhe works &is fined Rs.7.50 for each day is absent. He gets Rs.425 in all. For how many dayswas he absent?
(A) 8
(B) 10
(C) 12
(D) 15
(E) 17
Rationale: 30 * 25 = 750
425
-----------
325
25 + 7.50 = 32.5
325/32.5 = 10
B
Answer: (B) 10
Question: The units digit of (35)^(87) + (93)^(51) is:
(A) 2
(B) 4
(C) 6
(D) 8
(E) 0
Rationale: The units digit of powers of 3, cycles in a group of 4: {3, 9, 7, 1}
51 has the form 4k+3, so the units digit of 93^51 is 7.
The units digit of powers of 5 is always 5.
7+5 = 12, so the units digit is 2.
The answer is A.
Answer: (A) 2
Question: An e-commerce website marks his wares 30% more than the real price and allows 10% discount. Their profit is:
(A) 17%
(B) 19%
(C) 21%
(D) 23%
(E) None of these
Rationale: Let the CP = 100 Rs.
Mark Price = 130
Discount = 10%
Selling price 90/100 Ã— 130
Hence profit = 17%
Answer: A.
Answer: (A) 17%
Question: Albert borrowed a total of $ 5700 from Brian and Charlie. He paid simple interest at the rate of 7 % Per yr and 9 % per yr respectively.At the end of three years he paid $ 1494 as total interest. What is the interest paid to Brian at the end of three years?
(A) 157.5
(B) 160
(C) 161
(D) 165
(E) 170
Rationale: Let x be the amount borrowed form Brian. So amount borrowed form Charlie = 5700-x.
1494 = 21/100x + 27/100(5700-x)
=>x = 750.
Interest paid = 3*7/100*750 = 157.5
A
Answer: (A) 157.5
Question: There is food for 760 men for 22 days. How many more men should join after two days so that the same food may last for 19 days more?
(A) 38
(B) 40
(C) 83
(D) 87
(E) 81
Rationale: 760 ---- 22
760 ---- 20
x ----- 19
x*19 = 760*20
x = 800
760
-------
40
Answer: B
Answer: (B) 40
Question: Workers at a campaign office have 1000 fliers to send out. If they send out 1/5 of them in the morning and 1/4 of the remaining ones out during the afternoon, how many are left for the next day?
(A) 300
(B) 800
(C) 1100
(D) 600
(E) 1900
Rationale: (1/5)*1000 = 200
Remaining = 1000-200 = 800
(1/4) of remaining = (1/4)*800 = 200
Remaining now = 800-200 = 600
Answer: Option D
Answer: (D) 600
Question: Jamboree and GMAT Club Contest Starts
QUESTION #15:
How many words (with or without meaning) can be formed using all the letters of the word “SELFIE” so that the two E’s are not together?
(A)  660
(B)  600
(C)  500
(D)  300
(E)  240
Rationale: The question is asking the total number of arrangements possible with the letters of the word “SELFIE” where two E’s are not together.
Arrangements when two E’s are not together = Total arrangements - Arrangements when two E’s are together
In total there are 6 letters but two are identical. so we can arrange in 6! ways. but we divide for those objects that are identical. so divide by 2!. Hence,
Total arrangements = 6!/2!
Now two E's are coupled together. Consider this couple (EE) as one letter. apart from this there are 4 more letters. so we can arrange these 5 different objects in 5! ways.
Two E's can arrange themselves in 2! ways, but we divide for those objects that are identical. so divide by 2!. so arrangement for E's would be 2!/2!.
Hence, Arrangements when two E’s are together = 5! * (2!/2!)
Arrangements when two E’s are not together = 6!/2! - 5! = 5! * ( 6/2 -1 ) = 120 * 2 = 240.
Option C is correct!
Answer: (C)  500
Question: 2, 6, 12, 20, 30, 42, 56, (...)
(A) 61
(B) 72
(C) 64
(D) 70
(E) 76
Rationale: Explanation :
The pattern is 1×2, 2×3, 3×4, 4×5, 5×6, 6×7, 7×8.
Hence, next number is 8×9 = 72
Answer : Option B
Answer: (B) 72
Question: If the average (arithmetic mean) of a and b is 20, and c – a = 30, what is the average of b and c?
(A) 25
(B) 30
(C) 40
(D) 35
(E) 45
Rationale: a+b/2 = 20
=> a+b = 40
a = c - 30...sub this value
c-30+b = 40
=>c+b = 70
=>c+b/2 = 35
Answer : D
Answer: (D) 35
Question: How many members are there between 1 to 100 which are divisible by 9 and the sum of two digits is 9?
(A) 13
(B) 7
(C) 11
(D) 9
(E) 10
Rationale: there are 11 numbers divisible by 9.
But in number 99,
9+9 is not equal to 9.
so,the ans is 10 numbers
ANSWER:E
Answer: (E) 10
Question: Solution A is 20% salt and Solution B is 70% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution?
(A) 6:4
(B) 6:14
(C) 2:3
(D) 4:6
(E) 3:7
Rationale: Forget the volumes for the time being.
You have to mix 20% and 80% solutions to get 50%. This is very straight forward since 50 is int he middle of 20 and 80 so we need both solutions in equal quantities. If this doesn't strike, use
w1/w2 = (A2 - Aavg)/(Aavg - A1)
w1/w2 = (70 - 50)/(50 - 20) = 2/3
So the volume of the two solutions will be equal. Answer has to be 2:3
C
Answer: (C) 2:3
Question: The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?
(A) 50
(B) 60
(C) 70
(D) 80
(E) 90
Rationale: A + B = 60, A = 2B
2B + B = 60 => B = 20 then A = 40.
5 years, their ages will be 45 and 25.
Sum of their ages = 45 + 25 = 70.
ANSWER:C
Answer: (C) 70
Question: The average age of an adult class is 50 years. 12 new students with an avg age of 32 years join the class. Therefore decreasing the average by 4 years. Find what was the original average age of the class?
(A) 10
(B) 12
(C) 42
(D) 20
(E) 22
Rationale: Let original strength = y
Then , 50y + 12 x 32 = ( y + 12) x 46
â‡’ 50y + 384 = 46y + 552
â‡’ 4y = 168
âˆ´ y = 42
C
Answer: (C) 42
Question: A man distributes 0.375 of his money to his wife and 0.4 to his son. He still has Rs.3,375
left with him. How much did his wife get?
(A) Rs. 3625/-
(B) Rs. 4625/-
(C) Rs. 5625/-
(D) Rs. 6625/-
(E) Rs. 7625/-
Rationale: Let, total money = M.
So, M*(1-0.375-0.4)=3375; => M= 3375/(1-0.375-0.4); => M = 15000
So, his wife got = 15000*(0.375)= 5625.
So, his wife got Rs. 5625/-
ANSWER:C
Answer: (C) Rs. 5625/-
Question: In a certain animal shelter, the ratio of the number of dogs to the number of cats is 15 to 7. If 16 additional cats were to be taken in by the shelter, the ratio of the number of dogs to the number of cats would be 15 to 11. How many dogs are in the shelter?
(A) 15
(B) 25
(C) 30
(D) 45
(E) 60
Rationale: This ratio question can be solved in a couple of different ways. Here's an Algebraic approach...
We're told that the ratio of the number of dogs to the number of cats is 15:7. We're then told that 16 more cats are added to this group and the ratio becomes 15:11. We're asked for the number of dogs.
Algebraically, since the number of dogs is a multiple of 15 and the number of cats is a multiple of 7, we can write this initial relationship as...
15X/7X
When we add the 12 cats and factor in the 'ending ratio', we have an equation....
15X/(7X+16) = 15/11
Here we have 1 variable and 1 equation, so we can solve for X....
(15X)(11) = (7X+16)(15)
(X)(11) = (7X+16)(1)
11X = 7X + 16
4X = 16
X = 4
With this X, we can figure out the initial number of dogs and cats...
Initial dogs = 15X = 15(4) = 60
Final Answer:E
Answer: (E) 60
Question: 24 buckets of water fill a tank when the capacity of each bucket is 13.5 litres. How many buckets will be required to fill the same tank if the capacity of each bucket is 9 litres?
(A) 30
(B) 36
(C) 60
(D) Data inadequate
(E) None of these
Rationale: Capacity of the tank = 24 Ã— 13.5= 324 litres
When the capacity of each bucket = 9 litres, then the required no. of buckets
= 324â„9 = 36
Answer B
Answer: (B) 36
Question: A box contains seven purple, five blue and eleven yellow balls.
What is the minimum number of tries required to get one blue and one yellow ball ?
(A) 16
(B) 17
(C) 18
(D) 19
(E) 20
Rationale: 11 yellow+7 purple+after that we have only one option that is to be blue so answer is 19
ANSWER:D
Answer: (D) 19
Question: Money invested at x%, compounded annually, triples in value in approximately every 112/x years. If $2500 is invested at a rate of 8%, compounded annually, what will be its approximate worth in 28 years?
(A) $3,750
(B) $5,600
(C) $8,100
(D) $15,000
(E) $22,500
Rationale: Solution: money compounded annually at x% triples in 112/x years.
we need to find the final amount of 2500 at the end of the 28 years.. compounded annually at 8%
by putting the value in formula it will give us = 2500(1.08)^28
there must be a relation between these two conditions?
x= 8% so money will triple in 112/8 = 14 years
so money will be 3^2 = 9 times in 28 years
so 2500*9 = 22500
Answer:E
Answer: (E) $22,500
Question: If a man reduces the selling price of a fan from Rs. 420 to Rs. 402, his loss increases by 3%. The cost price of the fan is :
(A) Rs.600
(B) Rs.650
(C) Rs.475
(D) Rs.525
(E) None of these
Rationale: Explanation :
Solution: let C.P. be Rs. X. then, 3% of x = (420-402) =18 => 3x/100 = 18 => x =Rs.600.
Answer : A
Answer: (A) Rs.600
Question: If 2/z = 2/(z + 1) + 2/(z + 64) which of these integers could be the value of z?
(A) 0
(B) 1
(C) 2
(D) 5
(E) 8
Rationale: Solving for z algebraically in this problem would not be easy. Instead, we can follow the hint in the question (“which of these integers…”) and test each answer choice:
A. 2/0 = 2/1 +2/64 INCORRECT (Division by zero)
B. 2/1 = 2/2 +2/65 INCORRECT
C. 2/2 = 2/3 +2/66 INCORRECT
D. 2/3 = 2/4 +2/69 INCORRECT
E. 2/4 = 2/5 +2/72 CORRECT
The correct answer is E, because it contains the only value that makes the equation work. Notice how quickly this strategy worked in this case
Answer: (E) 8
Question: Gokul buys 9 horses and 4 cows for Rs. 13,400. if he sells the horses at 20% profit and the cows at 10% profit, then he earns a total profit of Rs. 1880. The cost of a cow is:
(A) Rs. 2200
(B) Rs. 2190
(C) Rs. 2000
(D) Rs. 600
(E) None of these
Rationale: Explanation :
Solution: Let C.P. of each horse and be Rs. X and C.P. of each cow be Rs. Y. then,
9x+4y =13,400 -------> (1)
And, 20% of 9x + 10% of 4y = 1880.
9x/5 + 2y/5 = 1880 => 9x+2y =9400 -------> (2)
solving (1) and (2), we get : x = 600 and y =2000.
.'. cost price of each cow = Rs. 2000.
Answer : C
Answer: (C) Rs. 2000
Question: Bruno and Sacha are running in the same direction around a stadium. Sacha runs at a constant speed of 6 meters per second, and Bruno runs at a constant speed of 5 meters per second. At a certain point Sacha overtakes Bruno. If four minute afterward, Sacha stops and waits for Bruno to reach him, then how many seconds does he have to wait?
(A) 12
(B) 24
(C) 36
(D) 48
(E) 72
Rationale: the difference of the speed is 1m per second so in four minute Sacha will be 240 m ahead of Bruno..
Bruno will cover this in 240/5=48 secs..
D
Answer: (D) 48
Question: The area of a parallelogram is 72 sq m and its base is 12m . Then the length of the height is?
(A) 6m
(B) 7m
(C) 60m
(D) 13m
(E) none
Rationale: b*h=72. h*12=72 =>h=6m. Answer: (A)
Answer: (A) 6m
Question: A can run 2 km distance in 2 min 20 seconds, while B can run this distance in 3 min 5 sec. . By how much distance can A beat B?
(A) 900 m
(B) 500 m
(C) 120 m
(D) 180 m
(E) 190 m
Rationale: A takes time 2.20 minutes=140sec
B takes time 3 minutes=185 sec
difference= 185-140=45sec
now we are to find distance covered in 40 sec by B
180sec=2000m
1sec=100/9 m
45sec=45x100/9=500m
ANSWER:B
Answer: (B) 500 m
Question: To save money, Arkadelphia Cream Cheese will reduce each dimension of its rectangular box container (which is entirely full of cream cheese) by 10%, and reduce the price it charges its consumers by 10% as well. By what percentage does this increase the price-per-cubic-inch that each consumer will pay for cream cheese?
(A) 1. 23.5
(B) 2. 50%
(C) 3. 100%
(D) 4. 300%
(E) 5. 400%
Rationale: Take smart numbers
Let,
L = 20: B = 10: H= 10 of initial box and Price = 50$
Therefore Price / cubic inch = 50 / (20*10*10) =0.025
Now, when dimensions are reduced by 10% and price also reduced by 10%
L = 18; B=9; H=9 and Price = 45$
Therefore price / cubic inch = 45 / (18*9*9) =0.030
Percentage change = (0.030 - 0.025) *100/ 0.025 = 23.5%
Answer is A
Answer: (A) 1. 23.5
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:
(A) 12
(B) 18
(C) 36
(D) 72
(E) 38
Rationale: Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x =	(120 + 120)/12
=> 2x = 20
=> x = 10.
Therefore Speed of each train = 10 m/sec =(10 x	(18/5))	km/hr = 36 km/hr.
Answer :C
Answer: (C) 36