mathewhe/aqua_rat huggingface dataset:
Question: If the GCD of two numbers (not equal, both integers, greater than 1) is 2, then which of the following can be true?
A. They are prime.
B. They are consecutive.
C. They do not have a common prime factor.
D. They have a common factor other than 2.
(A) Only A
(B) Only B
(C) Only C
(D) Only D
(E) A, B, C, and D
Rationale: The GCD of two numbers (not equal, both integers, greater than 1) is 2 means that they don't share factors other than 1 and 2.
This also means that both numbers are even ( divisible by 2.)
A. They are not prime. 2 is the only even number that is prime, so one number can be prime but the other number cannot be.
B. They are not consecutive. With two consecutive numbers, one will be even and one will be odd.
C. They have a common prime factor. The question defines the numbers as having a GCD of 2, which is prime.
D. They have a common factor other than 2. Both numbers have common factors of 2 and 1. For example:
The factors of 4 are 1 and 2, the factors of 6 are 1, 2, and 3.
Therefore, (D) is the only correct answer.
Answer: (D) Only D
Question: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2490 ?
(A) Rs. 820
(B) Rs. 830
(C) Rs. 840
(D) Rs. 850
(E) Rs. 890
Rationale: Explanation:
Let the total amount in the partnership be 'x'.
Then A's share = x/3
B's share = x/4
C's share = x/5
D's share = x - (x/3 + x/4 +x/5) = 13x/60
A : B : C : D = x/3 : x/4 : x/5 : 13x/60 = 20 : 15 : 12 : 13
A's share in the profit of Rs. 2490 = 20 (2490/60) = Rs. 830.
ANSWER IS B
Answer: (B) Rs. 830
Question: In Mrs. Susna's class, 1/4 of her students are getting an A, 1/2 are getting a B, 1/8 are getting a C, 1/12 are getting a D, and 1/24 are getting a F. What fraction of Mrs. Susna's class getting a passing grade of C or higher.
(A) 5/6
(B) 3/4
(C) 7/8
(D) 1/8
(E) 1/2
Rationale: If Mrs. Susna's class has 24 students, the number of students receiving As, Bs, or Cs, are 6, 12, and 3 respectively. That means 21/24 of her students are receiving passing grades or 7/8. (Answer:C)
Answer: (C) 7/8
Question: A, B and C shared the profit in a business in the ratio 5 : 7 : 8. They had partnered for 14 months, 8 months and 7 months respectively. What was the ratio of their investments?
(A) 20:64:49
(B) 49:20:64
(C) 64:20:49
(D) 64:49:20
(E) 20:49:64
Rationale: Ratio in which A,B and C shared the profit =5:7:8
Assume that the ratio of their investments =a:b:c
⇒14a:8b:7c=5:7:8⋯(A)
From (A),
14a:8b=5:7
⇒14a×7=8b×5
⇒7a×7=4b×5
⇒b=49a/20⋯(1)
From (A),
14a:7c=5:8
⇒(14a)×8=(7c)×5
⇒(2a)×8=c×5
⇒c=16a/5⋯(2)
a:b:c=a:49a/20:16a/5
=1:49/20:16/5
=20:49:64
Answer is E.
Answer: (E) 20:49:64
Question: Find the probability that a number selected from numbers 1, 2, 3,...,45 is a prime number, when each of the given numbers is equally likely to be selected?
(A) 10/45
(B) 14/45
(C) 8/45
(D) 3/45
(E) 7/45
Rationale: Let X be the event of selecting a prime number.
X = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41,43}
n(X) = 14,
n(S) = 45
Hence, the required probability is 14/45.
ANSWER:B
Answer: (B) 14/45
Question: If log 27= 1.431, then the value of log 9 is:
(A) 0.934
(B) 0.945
(C) 0.954
(D) 0.958
(E) 0.959
Rationale: log 27 = 1.431 => log 33 = 1.431
=> 3 log 3= 1.431 => log 3 = 0.477
Therefore, log 9 = log 32 = 2 log 3 = (2*0.477) = 0.954
ANSWER:C
Answer: (C) 0.954
Question: If (2^16)(25^S) = 5(10^m) what is the value of m ?
(A) 7
(B) 8
(C) 15
(D) 16
(E) 23
Rationale: given
2^16 * 25^s = 5 * 10^2
=> 2^16 * 5^(2s) = 2^m * 5^(m+1)
Ans D
on comparing the power of 2 => m=16
Answer: (D) 16
Question: What least number must be subtracted from 42398 so that remaining no.is divisible by 15
(A) 3
(B) 5
(C) 6
(D) 8
(E) 9
Rationale: Explanation:
On dividing 42398 by 15 we get the remainder 8, so 8 should be subtracted
Option D
Answer: (D) 8
Question: A tourist purchased a total of $2,500 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
(A) $1,430
(B) $1,310
(C) $1,290
(D) $2,270
(E) $2,150
Rationale: Let the number of $10 checks cashed beT
Let the number of $50 checks cashed beF
7 checks cashed;
T+F=7
Now; T can be F+1 OR T can be F-1
Let's check both conditions;
T=F+1
T+F=7
F+1+F=7
2F=6
F=3
T=4
Value cashed = 3*50+4*10=150+40=$190
Let's check the other condition as well;
T=F-1
T+F=7
F-1+F=7
2F=8
F=4
T=3
Value cashed = 4*50+3*10=200+30=$230
The more money he cashes, the less loss he incurs. Thus, we must consider the latter case.
Value cashed = $230
Value lost = 2500-230 = $2270
Ans:D
Answer: (D) $2,270
Question: The seating chart of an airplane shows 30 rows of seats. Each row has 3 seats on each side of the center aisle, and one of the seats on each side is a window saet. The view from the window seats in 6 of the rows is obscured by the wings of the airplane. If the first person to be assigned a seat is assigned a window seat and thw window seat is assigned randomly, what is the probability that the person will get a seat with an unobscured view?
(A) 1/6
(B) 1/3
(C) 2/3
(D) 5/6
(E) 4/5
Rationale: priyalr
6 seats per row, think of a boeing 737. We have 30 rows, therefore window 30 seats one one side and 30 window seats on the other, totaling 60 window seats on the whole plane.
the view of the window of 6 rows is blocked. two wings, therefore 12 window seats are blocked.
Total window seats = 60
Total blocked window seats = 12
Total unblocked seats = 48
We know that a window seat was given, therefore probability for not window seat is 48/60 =4/5
ANS E
Answer: (E) 4/5
Question: A stock trader originally bought 300 shares of stock from a company at a total cost of m dollars. If each share was sold at 80% above the original cost per share of stock, then interns of m for how many dollars was each share sold?
(A) a) 2m/300
(B) b) 9m/1500
(C) c) m/200
(D) d) m/300 + 50
(E) e) 350/m
Rationale: Let Cost of 300 shares be $ 3000
So, Cost of 1 shares be $ 10 =>m/300
Selling price per share = (100+80)/100 * m/300
Or, Selling price per share = 9/5 * m/300 => 9m/1500
Hence answer will be (B)
Answer: (B) b) 9m/1500
Question: A person can row at 9 kmph and still water. He takes 4 1/2 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 1 kmph?
(A) 33
(B) 77
(C) 26
(D) 28
(E) 20
Rationale: Let the distance between A and B be x km.
Total time = x/(9 + 1) + x/(9 - 1) = 4.5
=> x/10 + x/8 = 9/2 => (4x + 5x)/40 = 9/2 => x = 20 km.
Answer: E
Answer: (E) 20
Question: Martha takes a road trip from point A to point B. She drives x percent of the distance at 60 miles per hour and the remainder at 30 miles per hour. If Martha's average speed for the entire trip is represented as a fraction in its reduced form, in terms of x, which of the following is the numerator?
(A)  18,000
(B)  300
(C)  1,100
(D)  3,000
(E)  30,000
Rationale: total distance = d
total time taken = x/(100*60) + (100-x)/(100*30)
speed = distance / time
gives numerator = 18000
Answer : A
Answer: (A)  18,000
Question: A, B and C are partners. A receives 2/3 of profits, B and C dividing the remainder equally. A's income is increased by Rs.200 when the rate to profit rises from 5 to 7 percent. Find the Capital of A?
(A) 3377
(B) 2899
(C) 2500
(D) 2778
(E) 10000
Rationale: A:B:C = 2/3:1/6:1/6 = 4:1:1
x * 2/100 * 2/3 = 200
A capital = 15000*2/3 = 10000
Answer: E
Answer: (E) 10000
Question: If xy = 5 and x^2 + y^2 = 15, then x/y + y/x =
(A) 2 2/5
(B) 3
(C) 5 1/3
(D) 7
(E) 60
Rationale: x/y+y/x=(x^2+y^2)/xy =substitute given we get 15/5=3 answer B
Answer: (B) 3
Question: For a finite sequence of non zero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -5 ?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: Given sequence: {1, -3, 2, 5, -4, -6}
The questions basically asks: how manypairs of consecutive termsare there in the sequence such that the product of these consecutive terms is negative.
1*(-3)=-3=negative;
-3*2=-6=negative;
2*5=10=positive;
5*(-4)=-20=negative;
(-4)*(-6)=24=positive.
So there are 3 pairs of consecutive terms of the sequence for which the product is negative.
Answer: B.
Answer: (B) 2
Question: A class of students bought a total of 572 pencils. If each student in the class bought at least 17 pencils, then what is the greatest possible number of students in the class?
(A) 31
(B) 32
(C) 33
(D) 34
(E) 35
Rationale: 572/17=33 plus remainder.
The answer is C.
Answer: (C) 33
Question: 3 of the 4 expressions (1), (2), (3) & (4) given below are exactly equal . Which of the expression is not equal to the other four expressions?
(A) (A – B)2 + 9AB
(B) (A – B)2 + 4AJ
(C) (A – B)2 + 4AB
(D) (A – B)2 + 2AB
(E) (A – B)2 + 1AB
Rationale: Explanation:
1) (A + B)2 – 4AB = A2 + 2AB + B2 - 4AB = A2 + B2 - 2AB
2) (A – B)2 + 4AB = A2 – 2AB + B2 + 4AB = A2+ B2 + 2AB
3) A2 +B2 – 4AB + 2AB = A2 + B2 - 2AB
4) A2 – B2 + 2B(B – A) = A2 – B2 + 2B2 – 2AB = A2 + B2 – 2AB
Therefore, (1) = (3) = (4) ≠ (2)
Therefore, expression (2) is wrong
ANSWER:C
Answer: (C) (A – B)2 + 4AB
Question: A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
(A) 238
(B) 777
(C) 350
(D) 377
(E) 267
Rationale: Speed = [300 / 18] m/sec = 50/3 m/sec.
Let the length of the platform be x meters.
Then, x + 300 / 39 = 50/3
3(x + 300) = 1950 è x = 350m.Answer:C
Answer: (C) 350
Question: I travel the first part of my journey at 40 kmph and the second part at 60 kmph and cover the total distance of 240 km to my destination in 5 hours. How long did the first part of my journey last
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: The total time of journey = 5 hours.
Let 'x' hours be the time that I travelled at 40 kmph
Therefore, 5–x hours would be time that I travelled at 60 kmph.
Hence, I would have covered x×40+(5−x)60 kms in the 5 hours = 240 kms.
Solving, for x in the equation 40x+(5–x)×60=240, we get
40x+300–60x=240
⇒20x=60 or x= 3 hours
ANSWER:C
Answer: (C) 3
Question: The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
(A) 29
(B) 16
(C) 7
(D) 6
(E) 5
Rationale: Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
{\color{Black} \therefore \left ( \frac{20-x}{x}\times 100=25 \right )}
2000 - 100x = 25x
125x=2000
x=16
Answer: B
Answer: (B) 16
Question: Two numbers are respectively 40% and 30% more than a third number. The second number expressed in terms of percentage of the first is ?
(A) 95%
(B) 93%
(C) 90%
(D) 80%
(E) none of these
Rationale: Here, x = 40 and y = 30;
Therefore second number
= [[( 100 + y)/ (100 + x )] x 100 ]% of first number
= [[( 100 + 30)/ (100 + 40 )] x 100 ]% of first number
= 92.8% of the first
ANSWER:B
Answer: (B) 93%
Question: A car travels a certain distance taking 7 hrs in forward journey, during the return journey increased speed 12km/hr takes the times 5 hrs. What is the distance traveled
(A) 210 kms
(B) 30 kms
(C) 20 kms
(D) 40 kms
(E) none of these
Rationale: If x is the distance, then
difference in speeds =
x/5 - x/7 = 12
2x/35=12
x= 12*35/2 = 210 kms. ANSWER:A
Answer: (A) 210 kms
Question: Which of the following options is the possible total number of people in a hall given that the number of people is a multiple of both 6 and 16?
(A) 42
(B) 66
(C) 54
(D) 48
(E) 50
Rationale: the number of people are a multiple of both 6 and 16, so it must be divisible by 6 and 16.
using the elimination method look for a number that is both divisible by 6 and 16,
of all the options only 56 is divisible by 8 and 14.
[ 48/6=8 and 48/16=3]
answer :D
Answer: (D) 48
Question: What is the present worth of Rs. 132 due in 2 years at 5% simple interest per annum?
(A) Rs. 83
(B) Rs. 108
(C) Rs. 120
(D) Rs. 132
(E) Rs. 142
Rationale: Explanation:
Let the present worth be Rs. x.
Then, S. I. = Rs. (132-x).
110 x = 13200
x = 120
Answer: C
Answer: (C) Rs. 120
Question: If e persons take y days to complete z similar jobs, how long does it take y persons to complete 1 such job?
(A) z
(B) x
(C) x/y
(D) z/x
(E) y/z
Rationale: the Q doesn't seem to be having the any correct answer as a choice..
since we are looking for days, lets keep days in end and work out a solution..
e person can do z jobs in y days..
so e person can do 1 job in y/z days..
and 1 person can do 1 job in y^2/z days..
so y person can complete 1 job in y^2/zy=y/z..
so the answer should be y/z=E
Answer: (E) y/z
Question: Lindsay can paint 1/x of a certain room in one hour. If Lindsay and Joseph, working together at their respective rates, can paint the room in two hours, what fraction of the room can Joseph paint in 20 minutes?
(A) 1/6x
(B) x/(x-6)
(C) (x-2)/6x
(D) x/(x-2)
(E) (x-2)/x
Rationale: Let J be Joseph's rate per hour.
1/x + J = 1/2 of a room per hour
J = 1/2 - 1/x, of a room per hour
In 20 minutes Joseph can paint 1/3*(1/2-1/x) = 1/6-1/3x = (x-2)/6x
The answer is C.
Answer: (C) (x-2)/6x
Question: At a meeting of the 7 Joint Chiefs of Staff, the Chief of Naval Operations does not want to sit next to the Chief of the National Guard Bureau. How many ways can the 7 Chiefs of Staff be seated around a circular table?
(A) 120
(B) 480
(C) 960
(D) 2520
(E) 5040
Rationale: 7 people can be arranged around circular table in (7-1)!=6! # of ways.
Consider the two people (A and B) who do not want to sit together as one unit: {AB}. Now, 6 units {AB}, {C}, {D}, {E}, {F} and {G} can can be arranged around circular table in (6-1)!=5! # of ways. A and B can be arranged within their unit in two ways {AB} and {BA}. Thus the # of ways those two people sit together is 2*5!.
The number of ways they do not sit together = {Total} - {Restriction} = 6! - 2*5! = 5!(6 - 2) = 480.
Answer: B.
Answer: (B) 480
Question: The function f is defined for all positive integers n by the following rule: f(n) is the product of the distinct prime factors of n. If f(n) < 80 and n is not prime, what is the greatest possible value of f(n)?
(A) 75
(B) 69
(C) 60
(D) 55
(E) 63
Rationale: Since we need the largest value of f (n), we will start with the largest option.
Option A: 75 = 3*5*5. This is not a product of distinct prime numbers. Hence incorrect
Option B: 69 = 3*23. This is a product of distinct prime numbers.
Rest all the options are smaller that 69.
Correct Option: B
Answer: (B) 69
Question: A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then, (a + b) = ?
(A) 10
(B) 11
(C) 12
(D) 15
(E) 16
Rationale: 4 a 3 |
9 8 4 } ==> a + 8 = b ==> b - a = 8
13 b 7 |
Also, 13 b7 is divisible by 11 => (7 + 3) – (b + 1) = (9 – b)
(9 – b) = 0
b = 9
(b = 9 and a = 1) => (a + b) = 10.
Answer A
Answer: (A) 10
Question: If log 27 = 1.461, then the value of log 9 is:
(A) 0.934
(B) 0.945
(C) 0.954
(D) 0.958
(E) 0.974
Rationale: log 27 = 1.461
log (33 ) = 1.461
3 log 3 = 1.461
log 3 = 0.487
log 9 = log(32 ) = 2 log 3 = (2 x 0.487) = 0.974.
Answer: Option E
Answer: (E) 0.974
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
(A) 4538
(B) 4535
(C) 4539
(D) 4530
(E) 4532
Rationale: Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls
= 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5
= Rs. 4530
Answer: D
Answer: (D) 4530
Question: A girl has exactly 5 quarters, 9 dimes, and 10 nickels in her pocket. If she withdraws a number of these coins at random, how many coins would she have to withdraw to ensure that she has at least a 50 percent chance of withdrawing at least one quarter?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: When the probability of NOT drawing a quarter is 50% or less, then the probability of drawing a quarter is at least 50%.
P(not drawing a quarter with 2 coins) = 19/24 * 18/23 = 57/92 > 50%
P(not drawing a quarter with 3 coins) = 57/92 * 17/22 = 969/2024 < 50%
The answer is B.
Answer: (B) 3
Question: There are 36 hours in a day, 90 minutes in an hour and 60 seconds in one minute. What is the angle between hour hand and minute hand when time is 15:50?
(A) 191.10 degree
(B) 141.10 degree
(C) 101.10 degree
(D) 111.10 degree
(E) 121.10 degree
Rationale: Hour hand speed = 360/(18*90) =2/9 DPM
Minute hand speed =360/90 = 4 DPM
Now 18 hours have 360 degree
then 1 hour has 360/18= 20 degree
so 15 * 20 make 300 degree
hour hand = 300 + 50 * 2/9 =311.10 degree
minute hand = 50 * 4= 200 degree
here is the difference 311.10-200= 111.10 degree
ANSWER:D
Answer: (D) 111.10 degree
Question: A 260 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
(A) 230 m
(B) 240 m
(C) 260 m
(D) 320 m
(E) 330 m
Rationale: Relative speed = (120 + 80) km/hr
=	(200 x(5/18))m/sec
=	(500/9)m/sec.
Let the length of the other train be x metres.
Then,	(x + 260)/9 = 500/9
x + 260 = 500
x = 240.
B
Answer: (B) 240 m
Question: 1-1-1-1-1-1
do any operations between the numbers to make the sum as 37 ?
(A) 34
(B) 35
(C) 36
(D) 37
(E) 38
Rationale: 1+1+1 = 3
3 Factorial = 6
6 to the power 1+1 = 6^2 = 36
36 + 1 = 37
ANSWER:D
Answer: (D) 37
Question: The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 60 metres?
(A) 10 seconds
(B) 15 seconds
(C) 20 seconds
(D) 12 seconds
(E) None of these
Rationale: Speed of the boat downstream = 15 + 3 = 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 60 m = 60/5 = 12 seconds.
ANSWER:D
Answer: (D) 12 seconds
Question: Look at this series: 5, 8, 6, 9, 7, ... What number should come next?
(A) 4
(B) 11
(C) 10
(D) 8
(E) 12
Rationale: This is a simple alternating addition and subtraction series. In the first pattern, 3 is added; in the second, 2 is subtracted.
5+3 =8
6+3 =9
8-2 =6
9-2 =7
Now 7+3 = 10
Answer is C
Answer: (C) 10
Question: A man purchases 8 pens for Rs.9 and sells 9 pens for Rs.8, how much profit or loss does he make?
(A) 30.98%loss
(B) 20.98%loss
(C) 20.97%loss
(D) 20.68%loss
(E) 20.98%loss
Rationale: 81 ---- 17
100 ----- ? è
20.98%loss
Answer: B
Answer: (B) 20.98%loss
Question: In a triangle if the length of sides are as given below which one will not form triangle?
(A) (5,5,5)
(B) (5,4,5)
(C) (4,4,9)
(D) (3,4,5)
(E) (3,5,5)
Rationale: (4,4,9)
using property :"sum of two side of a triangle is greater than its third side (4+4) is not greater than 9
ANSWER:C
Answer: (C) (4,4,9)
Question: A certain car averages 15 miles per gallon of gasoline when driven in the city and 40 miles per gallon when driving on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?
(A) 28
(B) 30
(C) 32
(D) 36
(E) 38
Rationale: 10*1/15 gpm+50*1/40 gpm=1.85 total gallons
60 total miles/1.85 total gallons=32.4 average mpg
C. 32
Answer: (C) 32
Question: A man invests some money partly in 4% stock at 48 and partly in 10% stock at 110.To obtain equal dividends from both,he must invest the money in the ratio :
(A) 3 : 4
(B) 3 : 5
(C) 4 : 5
(D) 6 : 5
(E) None
Rationale: Solution
For an income of Rs. 1 in 9% stock at 96, investment = Rs. (48/4)= Rs. 12 .
For an income of Rs. 1 in 12% stock at 120, investment = Rs.(110/10) = Rs. 10.
∴ Ratio of investments = 12 :10 = 6:5
Answer D
Answer: (D) 6 : 5
Question: In a two-digit number, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digits is equal to 52, then the number is:
(A) 11
(B) 13
(C) 24
(D) 35
(E) 46
Rationale: Let the ten's digit be x. Then, unit's digit = x + 2. Number = 10x + (x + 2) = 11x + 2
Sum of digits = x + (x + 2) = 2x + 2
(11x + 2)(2x + 2) =52
22(x)(x) + 26x - 48 = 0
11(x)(x) +13x - 24 = 0
(x - 1)(11x +24) = 0
x = 1
Hence, required number = 11x + 2 = 13.
ANSWER:B
Answer: (B) 13
Question: If in a $270 mln portfolio of stock, twice as much is invested in stock A as is invested in all the other stocks, how much is invested in all the other stocks?
(A) 90mln
(B) 80mln
(C) 70mln
(D) 60mln
(E) 50mln
Rationale: Let x denote the amount invested in all the other stocks. Then the amount invested in stock A is 2x. As we have the $270 mln portfolio, x+2x=3x=270 mln from where x=90 mln.
Answer: A
Answer: (A) 90mln
Question: A train running at the speed of 60 km/hr crosses a pole in 15 seconds. What is the length of the train?
(A) 187 m
(B) 250 m
(C) 876 m
(D) 150 m
(E) 267 m
Rationale: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train
= (Speed x Time)
= (50/3 * 15) m
= 250 m.
Answer: B
Answer: (B) 250 m
Question: The radius of the two circular fields is in the ratio 3: 5 the area of the first field is what percent less than the area of the second?
(A) 23%
(B) 62%
(C) 92%
(D) 64%
(E) 22%
Rationale: r = 3 πr2 = 9
r = 5 πr2 = 25
25 π – 16 π
100 ---- ? => 64%
Answer: D
Answer: (D) 64%
Question: What is the median from the below series 90, 92, 93, 88, 95, 88, 97
(A) 91.71
(B) 82
(C) 92
(D) 98
(E) 100
Rationale: Ordering the data from least to greatest, we get:
88, 88, 90, 92, 93, 95, 96
The median quiz score was 91.71 (Four quiz scores were higher than 91.71 and four were lower.)
A
Answer: (A) 91.71
Question: When 1/20% of 6,000 is subtracted from 1/10 of 6,000, the difference is
(A) 50
(B) 200
(C) 380
(D) 598
(E) 400
Rationale: 1/20 % of 6000 = 3
1/10 of 6000 = 600
600-3 = 598
Ans:D
Answer: (D) 598
Question: An investment R gained an interest payment of $250 each month when the annual interest rate was 8%, how much more should we invest annually if we want to gain 12% more per month with a new annual interest rate of 7.5% ?
(A) $9,360
(B) $9,100
(C) $8,250
(D) $7,300
(E) $7,150
Rationale: Answer is D : 7,300
An investment R gained an interest payment of $250 each month when the annual interest rate was 8%,Interest per annum with 8% interest rate is = 250* 12 = Principal * Interest Rate(8/100)
This gives Principal as 37,500$
For an revised interest of 12% more and new interest rate of 7.5% , ie. 250* 12 * 1.12 = Principal * Interest Rate (7.5/100)
This gives the new Principal as 44,800.
The question is how much more should we invest, so 44,800 - 37,500 = 7,300.D
Answer: (D) $7,300
Question: A salesmanâ€™s terms were changed from a flat commission of 5% on all his sales to a fixed salary of Rs.1000 plus 2.5% commission on all sales exceeding Rs. 4,000. If his remuneration as per new scheme was Rs. 600 more than that by the previous schema, his sales were worth
(A) 12000
(B) 14000
(C) 15000
(D) 20000
(E) 60000
Rationale: [1000 + (X-4000) * (2.5/100)] - X * (5/100) = 600
X = 12000
ANSWER A
Answer: (A) 12000
Question: An automotive test consisted of driving a car the same distance three separate times, first at an average rate of 4 miles per hour, then 5 miles per hour, then 6 miles per hour. If the test took 111 hours to complete, how many miles was the car driven during the entire test?
(A) 530
(B) 520
(C) 560
(D) 500
(E) 540
Rationale: x is the segment to be traveled
x/4+x/5+x/6 =111
or 74x/120 =111
x =180 miles . total distance =3*180 = 540 miles
E
Answer: (E) 540
Question: The average of 1st 3 of 4 numbers is 16 and of the last 3 are 15. If the sum of the first and the last number is 13. What is the last numbers?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3
Rationale: A + B + C = 48
B + C + D = 45
A + D = 13
A – D = 3
A + D = 13
2D = 10
D = 5
Answer: C
Answer: (C) 5
Question: What is the price of a orange?
(a) 14 banana and 35 oranges cost Rs. 84
(b) with a 50% discount on banana, Rs. 12 can buy 4 bananas and 5 oranges
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: 14X1+35X2=84
4XO.5+5X2=12
So price of banana =1 and orange=2
ANSWER:B
Answer: (B) 2