mathewhe/aqua_rat huggingface dataset:
Question: In a games hour 4 different types of players came to the ground? cricket 11, hokey 15, football 21, softball 15. How many players are present in the ground?
(A) 70
(B) 52
(C) 62
(D) 49
(E) 50
Rationale: total number of players= 11+15+21+15= 62
Answer is C
Answer: (C) 62
Question: Sushil got thrice as many marks in English as in Science. His total marks in English, Science and Maths are 180. If the ratio of his marks in English and Maths is 1:2, find his marks in Science?
(A) 19
(B) 77
(C) 66
(D) 55
(E) 31
Rationale: S:E = 1:3
E:M = 1:2
------------
S:E:M = 1:3:6
1/10 * 190 = 19
Answer: A
Answer: (A) 19
Question: An automobile parts supplier charges $25 per package of gaskets. When a customer orders more than 10 packages of gaskets, the supplier charges 4/5 the price for each package in excess of 10. During a certain week, the supplier sold 60 packages of gaskets. If 30 percent of the gaskets went to Company X, 15 percent to Company Y, and the rest to Company Z, what was the total amount, in dollars, that the parts supplier received in payment for the gaskets?
(A) 1305
(B) 1375
(C) 1345
(D) 1415
(E) 1455
Rationale: $25 per packet of gasket in case a customer orders less than 10
in case a customer orders > 10 price per gasket = 25*4/5=20
a certain week the supplier sold 60 gasket
1.he sold 30 % of the gaskets to X = 18 gaskets = 25*10 + 20 *8 = 250 + 160 = 410
2.he sold 15 % of the gaskets to Y = 9 gaskets = 25*9= 225
3.he sold remaining 55% to z =33 gaskets = 25*10 =250 + 20*23=710
thus ,total money earned
410+225+710 = 1345
Answer is C
Answer: (C) 1345
Question: A girl scout was selling boxes of cookies. In a month, she sold both boxes of chocolate chip cookies ($1.25 each) and boxes of plain cookies ($0.75 each). Altogether, she sold 1,585 boxes for a combined value of $1,586.75. How many boxes of plain cookies did she sell?
(A) 0
(B) 233
(C) 500
(D) 695
(E) 789
Rationale: Let #plain cookies sold be X then #chocolate cookies = (total cookies-X)
Equating for X
(0.75)*X +(1.25)*(1585-X)=1586.75
=>x=789
Answer: (E) 789
Question: A car going at 20 miles per hour set out on an 80-mile trip at 9:00 A.M. Exactly 10 minutes later, a second car left from the same place and followed the same route. How fast, in miles per hour, was the second car going if it caught up with the first car at 10:30 A.M.?
(A)  40
(B)  50
(C)  53
(D)  55
(E)  60
Rationale: Let Car A = car that starts at 9 AM
Car B = car that starts at 9:10 AM
Time for which car A travels at speed of 20 m per hour = 1.5 hours
Distance travelled by Car A = 20 *1.5 = 30 miles
Since Car B catches up Car A at 10:30 , time = 80 mins = 4/3 hour
Speed of Car B = 30/(4/3) = 40 miles per hour
Answer A
Answer: (A)  40
Question: A man can row 6 kmph in still water. When the river is running at 2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
(A) 5.32
(B) 5.7
(C) 5.76
(D) 5.74
(E) 5.71
Rationale: M = 6
S = 2
DS = 8
US = 4
x/8 + x/4 = 1
x = 2.66
D = 2.66 * 2 = 5.32 Answer: A
Answer: (A) 5.32
Question: A is three times as fast as B and working together, they can complete a work in 6 days. In how many days can B alone complete the work?
(A) 11 days
(B) 16 days
(C) 13 days
(D) 24 days
(E) 19 days
Rationale: A= 3B
A + B= 3B+ B= 4B
These 4B people can do the work in 6 days, which means B can alone do the work in 4*6=24 days.
Answer : D
Answer: (D) 24 days
Question: Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in scheme B?
(A) 6400
(B) 2778
(C) 2699
(D) 2789
(E) 1279
Rationale: Let the sum invested in scheme A be Rs. x and that in scheme B be Rs. (13900 - x). Then,
(x * 14 * 2)/100 + [(13900 - x) * 11 * 2]/100 = 3508
28x - 22x = 350800 - (13900 * 22)
6x = 45000 => x = 7500
So, sum invested in scheme B = (13900 - 7500) = Rs. 6400.
Answer:A
Answer: (A) 6400
Question: A shop keeper marked 30% above the cost price and offered 20% discount then find it's net profit?
(A) 2%
(B) 2.5%
(C) 3.7%
(D) 4.6%
(E) 5%
Rationale: Net profit = 30-20 + (30*(-25)/100) = 2.5%
Answer is B
Answer: (B) 2.5%
Question: A person purchased a TV set for Rs. 16000 and a DVD player for Rs. 6250. He sold both the items together for Rs. 34710
. What percentage of profit did he make?
(A) 80%
(B) 49%
(C) 40%
(D) 70%
(E) 56%
Rationale: The total CP = Rs. 16000 + Rs. 6250
= Rs. 22250 and SP = Rs. 34710
Profit(%) = (34710 - 22250)/22250 * 100
= 56%
Answer:E
Answer: (E) 56%
Question: Martha has the unique talent of being able to guess other people’s height and weight. For every five people that Martha meets, she consistently guesses the people’s correct height four times, and for every seven people that she meets, she consistently guesses the people’s correct weight five times. If Martha meets three people and her success rate remains constant, what is the probability that Martha correctly guesses a person’s weight and height at least once?
(A) 8/27
(B) 2/5
(C) 49/81
(D) 98/125
(E) 316/343
Rationale: Probability that she guesses the height correctly P(h)=4/5
Probability that she guesses the weight correctlyP(w)=5/7
Probability that she guesses both weight and height correctly(P(h)*P(w))=4/5 * 5/7= 20/35
Now the Q asks about the probability of this happening atleast once.
We calculate it by finding the probability of not being able to guess in any of the three occasions.
Probability of not being able to guess any no. of times =1-20/35=15/35=3/7
For all three occasions P(A)=3/7 * 3/7 * 3/7=27/343
Probability of the event happening atleast once=1- P(A)=1-27/343=316/343
Ans should be E
Answer: (E) 316/343
Question: In how many ways can 5 boysand 2 girls be arranged at a table if 2 girls are never together?
(A) 230
(B) 390
(C) 398
(D) 470
(E) 480
Rationale: Total ways of arranging 7 person in a circle = 6! = 720 ways
If we consider two women as one, then we have 5+1=6 persons. Arranging these six persons in circle will take = 5! = 120 ways
And two women can arrange themselves in 2! ways
Total ways in which two women sit together in circle = 5!*2! = 240 ways
Total ways in which two women doesn’t sit together in circle = 6! - 5!*2! = 720 - 240 = 480 ways
E
Answer: (E) 480
Question: Each of the positive integers a and c is a four-digit integer. If each of the digits 0 through 8 appears in one of these three integers, what is the minimum possible value of the sum of a and c?
(A) 3768
(B) 3789
(C) 3850
(D) 3825
(E) 3875
Rationale: According to the stem we should use the digits 0 through 8 to construct 2 four-digit integers, so that their sum is as small as possible.
To minimize the sum, minimize the thousands digits of a and c, so make them 1 and 2.
Next, minimize hundreds digits. Make them 3 and 4 .
Next minimize 10's digit place by 5 and 6
Use the remaining digits (7,and 8) for units digits.
So, a would be 1357,and c would be 2468.
1357 + 2468 =3825
Answer: D.
Answer: (D) 3825
Question: In how many ways can the letters of the CHEATER be arranged
(A) 20160
(B) 2520
(C) 360
(D) 80
(E) None of these
Rationale: Explanation:
As we can see the letter "E" is twice in given word, so Required Number
=7!/2!=7∗6∗5∗4∗3∗2!/2!=2520
Option B
Answer: (B) 2520
Question: All of the stocks on the over the counter market are designated by either a 4 letter or a 5 letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be designated with these codes?
(A) 2 (26)^5
(B) 26(26)^4
(C) 27(26)^4
(D) 26(26)^5
(E) 27(26)^5
Rationale: In 4-digit code {XXXX} each digit can take 26 values (as there are 26 letters), so total # of 4-digits code possible is 26^4;
The same for 5-digit code {XXXXX} again each digit can take 26 values (26 letters), so total # of 5-digits code possible is 26^5;
Total: 26^4+26^5=26^4(1+26)=27∗26^4
Answer: C.
Answer: (C) 27(26)^4
Question: For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum of all the even integers between 99 and 201?
(A) 7650
(B) 9250
(C) 12,650
(D) 14,250
(E) 15,150
Rationale: 100 + 102 + ... + 200 =
100*51 + (2+4+...+100) =
100*51 + 2*(1+2+...+50) =
100*51 + 2(50)(51)/2 =
100*51 + 50*51 = 150(51) = 7650
The answer is A.
Answer: (A) 7650
Question: If x and y are positive integers such that x/y = 0.875, which of the following numbers could be y?
(A) 3
(B) 2
(C) 4
(D) 10
(E) 8
Rationale: With the given information, we are trying to find the value of y.
To achieve this we must convert the given decimal to a fraction and reduce it to it's lowest integer form.
Take the decimal x/y = 0.875 and because it's in the thousands decimal place, put the given value (x/y = 0.875/1) and multiply it by 1,000.
Take the resulting fraction (x/y = 875/1000) and reduce it to it's lowest form.
Both of the numbers are divisible by 125.
The result is x/y = 7/8.
Thus y = 8.
The correct answer is E.
Answer: (E) 8
Question: Find the surface area of a 10 cm x 4 cm x 3 cm brick.
(A) 84 sq.c.m.
(B) 124 sq.cm
(C) 164 sq.cm.
(D) 180 sq.cm.
(E) None
Rationale: Sol.
Surface area = [2(10 x 4 + 4 x 3 + 10 x 3)] cm2
= (2 x 82) cm2
= 164 cm2.
Answer C
Answer: (C) 164 sq.cm.
Question: If X boxes of orange juice cost 300 cents, how much will Y boxes cost in dollars?
(A) Y*3/x
(B) 2Y/x
(C) 5Y/x
(D) Y*4/x
(E) Y*6/x
Rationale: X boxes of orange juice cost 300 cents or 3 dollars.
cost of orange juice = 3/x
Cost of Y orange juices = Y*3/x
Hence Answer : A
Answer: (A) Y*3/x
Question: Two trains of length 350 m and 250 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 36 kmph and 36 kmph. After how much time will the trains meet?
(A) 27/7 sec
(B) 20/7 sec
(C) 5 sec
(D) 21/7 sec
(E) 32/7 sec
Rationale: They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (36 + 36)*5/18 = 4*5 = 20 mps.
The time required = d/s = 100/20 = 5 sec.
Answer : C
Answer: (C) 5 sec
Question: Due to 10% decrease in the price of sugar and John can buy 5kg more sugar in Rs100 , then find the CP of sugar?
(A) Rs. 2(1/9)
(B) Rs. 2(2/9)
(C) Rs. 2(1/7)
(D) Rs. 3(2/9)
(E) Rs. 3(2/7)
Rationale: Here r = 10 % ,x = 100 and A = 5 kg
Actual price of sugar = 10*100/((100-10 )*5) = Rs. 2(2/9)
B
Answer: (B) Rs. 2(2/9)
Question: Find out the wrong number in the series.
7, 8, 18, 57, 228, 1165, 6996
(A) 8
(B) 18
(C) 57
(D) 228
(E) 238
Rationale: The series is
7*1 + 1 = 8
8*2 + 2 = 18
18*3 + 3 = 57
57*4 + 4 = 232
232*5 + 5 = 1165
1165*6 + 6 = 6996
so 228 is wrong
ANSWER:D
Answer: (D) 228
Question: A certain car traveled twice as many miles from Town A to Town B as it did from Town B to Town C. From Town A to Town B, the car averaged 10 miles per gallon, and from Town B to Town C, the car averaged 18 miles per gallon. What is the average miles per gallon that the car achieved on its trip from Town A through Town B to Town C?
(A) 13
(B) 13.5
(C) 14
(D) 14.5
(E) 15
Rationale: Ans is D
Given d_ab = 2*d_bc
let d_ab = d and d_bc = x so d=2x
for average miles per gallon = (d+x)/((d/10)+(x/18)) = 14.5 (formula avg speed = total distance/ total time)
Answer: (D) 14.5
Question: Aishwarya’s mom was 28 years of age at the time of her birth, while her mom was 20 years old when her 2 years younger sister was born. The variance between the parents ages is :
(A) 10 years
(B) 11 years
(C) 15 years
(D) 9 years
(E) 4 years
Rationale: A
6 years
Mom’s age when Aishwarya’s sister was born = 20 years.
Dad’s age when Aishwarya’s sister was born = (28 + 2) years = 30 years.
Needed Variance = (30 – 20) years = 10 years.
Answer is A
Answer: (A) 10 years
Question: The difference between C.I. and S.I. on an amount of Rs. 15,000 for 2 years is Rs. 216. What is the rate of interest per annum?
(A) 8
(B) 2
(C) 9
(D) 4
(E) 12
Rationale: Explanation:
[15000 * (1 + R/100)2 - 15000] - (15000 * R * 2)/100 = 216
15000[(1 + R/100)2 - 1 - 2R/100] = 216
15000[(100 + R)2 - 10000 - 200R]/10000 = 216
R2 = (216 * 2)/3 = 144 => R = 12
Rate = 12%
Answer: Option E
Answer: (E) 12
Question: Two members of a club are to be selected to represent the club at a national meeting. if there are 91 different possible selections of the 2 members, how many members does the club have?
(A) 20
(B) 14
(C) 40
(D) 57
(E) 95
Rationale: I have done this problem by substituting numbers
We have n!/2!(n-2)! = 91
or n(n-1)/2 = 182 or (n-14)(n+13) =0
n=14 satisfies the equation
B
Answer: (B) 14
Question: A circular rim A having a diameter of 36 inches is rotating at the rate of x inches/min. Another circular rim B with a diameter of 84 inches is rotating at the rate of y inches/min. What is the value of y in terms of x, if both the rims reach their starting positions at the same time after every rotation.
(A) 3x/7
(B) 4x/5
(C) 7x/5
(D) 5x/7
(E) 3x/4
Rationale: t = S1/V1 = S2/V2
or, 36/x = 84/y
or, y = 36x/84 = 3x/7 (Answer A)
Answer: (A) 3x/7
Question: When positive integer H is divided by positive integer B, the result is 4.35. Which of the following could be the reminder when H is divided by B?
(A)  13
(B)  14
(C)  15
(D)  16
(E)  17
Rationale: the remainder will be obtained from the decimal part when H is divided by B i.e. 0.35
0.35 = 35/100 = 7/20 so possible remainders are 7,14,21,28. Only option B-14 satisfies this
PS: for B-14 H=174 and B=40
Answer: (B)  14
Question: FEDERAL bank offers an interest of 5% per annum compounded annually on all its deposits. If $10,000 is deposited, what will be the ratio of the interest earned in the 4th year to the interest earned in the 5th year?
(A) 1:5
(B) 625:3125
(C) 100:105
(D) 100^4:105^4
(E) 725:3225
Rationale: Hi Bunuel,
Here is my approach: is this correct?
FEDERAL bank offers an interest of 5% per annum compounded annually on all its deposits
Interest earned in 4 year= 10000(1+0.05)^4
Interest earned in 5 year= 10000(1+0.05)^5
Ratio= {10000(1.05)^4}/{10000(1.05^5)} =>1.05^4/1.05^5 =>1/1.05 Multiplied by 100 in both numerator and denominator gives 100:105
Hence Ans:C
Answer: (C) 100:105
Question: If the length of the sides of two cubes are in the ratio 4:1, what is the ratio of their total surface area?
(A) 4:1
(B) 6:1
(C) 8:1
(D) 16:1
(E) 64:1
Rationale: Let x be the length of the small cube's side.
The total surface area of the small cube is 6x^2.
The total surface area of the large cube is 6(4x)^2=96x^2.
The ratio of surface areas is 16:1.
The answer is D.
Answer: (D) 16:1
Question: What is the leastvalue of x. So that 45x09 is divisible by 3?
(A) 0
(B) 5
(C) 2
(D) 6
(E) 7
Rationale: The sum of the digits of the number is divisible by 3, then the number is divisible by3.
4 + 5 + x + 0+ 9 = 18 + x
Least value of x may be 0
Therefore 18 + 0= 18 is divisible by 3.
A
Answer: (A) 0
Question: A basketball coach will select the members of a five-player team from among 8 players, including John and Peter. If the five players are chosen at random, what is the probability that the coach chooses a team that includes both John and Peter?
(A) 1/9
(B) 1/6
(C) 2/9
(D) 5/14
(E) 1/3
Rationale: you can but that will require more cases and will be time consuming.
straight forward way is to group J and P as always present on the team and as order does not matter so we just need to find the total number of ways to select rest three players = 6c3
total number of ways of selecting 5 players out of 8 = 8c5
probability = 6c3/8c5 = 5/14
D
Answer: (D) 5/14
Question: A truck driver drove for 2 days. On the second day, he drove 3 hours longer and at an average speed of 15 miles per hour faster than he drove on the first day. If he drove a total of 900 miles and spent 21 hours driving during the 2 days, what was his average speed on the first day, in miles per hour?
(A) 25.0
(B) 30.3
(C) 34.2
(D) 40.5
(E) 45.4
Rationale: Day 1
2t+3=21
t=9
Day 2
t+3
9+3=12
9r+12(r+15)=900
r=34.2
Answer:C
Answer: (C) 34.2
Question: The ratio of the number of ladies to gents at a party was 1:2 but when 2 ladies and 2 gents left, the ratio became 1:3. How many people were at the party originally?
(A) 22
(B) 18
(C) 12
(D) 66
(E) 99
Rationale: x, 2x
(x-2):(2x-2) = 1:3
3x-6 = 2x-2
x = 4
x+2x = 3x
=> 3*4 = 12
Answer: C
Answer: (C) 12
Question: The length of rectangle is thrice its breadth and its perimeter is 56 m, find the area of the rectangle?
(A) 432
(B) 212
(C) 252
(D) 992
(E) 147
Rationale: 2(3x + x) = 56
l = 21 b = 7
lb = 21* 7= 147
Answer:E
Answer: (E) 147
Question: On a certain road, 10% of the motorists exceed the posted speed limit and receive speeding tickets, but 30% of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on that road exceed the posted speed limit?
(A) 10.5%
(B) 12.5%
(C) 14.3%
(D) 22%
(E) 30%
Rationale: suppose there are X motorists.
10% of them exceeded the speed limit and received the ticket, i.e. X/10.
Again, suppose total no. of motorists who exceeded the speed limit are Y.
30% of Y exceeded the speed limit but didn't received the ticket, i.e. 3Y/10.
it means 7Y/10 received the ticket.
hence, 7Y/10 = X/10
or Y/X=1/7
or Y/X * 100= 1/7 * 100= 14.3%
C
Answer: (C) 14.3%
Question: A cab driver 5 days income was $300, $150, $750, $200 , $600. Then his average income is?
(A) $350
(B) $375
(C) $400
(D) $425
(E) $450
Rationale: avg = sum of observations/number of observations
avg income=(300+150+750+200+600)/5 = 400
Answer is C
Answer: (C) $400
Question: A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
(A) 2898
(B) 277
(C) 500
(D) 297
(E) 435
Rationale: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (800 + x)/60 = 65/3
x = 500 m.
Answer: C
Answer: (C) 500
Question: Assume the equation U = mgh. If m is quadrupled and h is halved, by what factor does U change?
(A) 3
(B) 2
(C) 4
(D) 1/2
(E) 16
Rationale: The equation is U = mgh.
If m is quadrupled and h is halved, the equation becomes:
U = (4m)*g*(h/2)
U = 2mgh
Initially U was mgh and now it is 2mgh, therefore U increases by a factor of 2.
Answer = B = 2
Answer: (B) 2
Question: 3, 7, 15, 31, 63, ?
(A) 89
(B) 127
(C) 142
(D) 158
(E) 168
Rationale: Each number in the series is the preceding number multiplied by 2 and then increased by 1.
Answer : B.
Answer: (B) 127
Question: The probability that event B occurs is 0.4, and the probability that events A and B both occur is 0.25. If the probability that either event A or event B occurs is 0.6, what is the probability that event A will occur?
(A) 0.05
(B) 0.45
(C) 0.15
(D) 0.5
(E) 0.55
Rationale: P(A or B) = P (A) + P(B) - p(a n b)
0.6= 0.4 + P(A) - 0.25
P(A) = 0.45
Ans : B
Answer: (B) 0.45
Question: There are 7 magazines lying on a table; 4 are fashion magazines and the other 3 are sports magazines. If 3 magazines are to be selected at random from the 8 magazines, what is the probability that at least one of the fashion magazines will be selected?
(A) 1/2
(B) 7/8
(C) 32/35
(D) 11/12
(E) 13/14
Rationale: answer is B
Total probability=8C3=48
4C3 +4C2*4C1+4C1*4C2=4+24+24=42
therefore the probability that at least one of the fashion magazines will be selected=42/48=7/8
B
Answer: (B) 7/8
Question: Jamshid can paint a fence in 50 percent less time than Taimour can when each works alone. When they work together, they can paint the fence in 4 hours. How long would it take Taimour to paint the fence alone?
(A) 6 hours
(B) 8 hours
(C) 12 hours
(D) 24 hours
(E) 32 hours
Rationale: I believe the answer is C. Please see below for explanation.
if Jamshid can paint a dence in 50 percent less time then Taimour we can infer the following rate J = 2T
if working together they can do the job in 8 hours we can infer 1 = 2T+T * 4 => 1/12
Working alone Taimour can do the job in 1 = 1/12 * hours => 12
Answer C
Answer: (C) 12 hours
Question: A case of 12 rolls of paper towels sells for $9. The cost of one roll sold individually is $1.What is the percent R of savings per roll for the 12-roll package over the cost of 12 rolls purchased individually?
(A) 9%
(B) 11%
(C) 15%
(D) 25%
(E) 90%
Rationale: Cost of 12 paper towels individually = 1*12=12
Cost of a set of 12 paper towels = 9
Cost of one roll = 9/12 = 3/4 = 0.75
Savings per roll = 1-.75 = 0.25
% of savings is R= .25/ 1 *100 = 25% D is the answer.
Answer: (D) 25%
Question: Annika hikes at a constant rate of 12 minutes per kilometer. She has hiked 2.75 kilometers east from the start of a hiking trail when she realizes that she has to be back at the start of the trail in 40 minutes. If Annika continues east, then turns around and retraces her path to reach the start of the trail in exactly 40 minutes, for how many kilometers total did she hike east?
(A) 3.625
(B) 3.5
(C) 3
(D) 3.04
(E) 4
Rationale: Set up two R x T =D cases.
1. 1/12 km/ min x T = 2.75
from which T= 33 mins.
We know total journey time now is 40 +33 =73.
The rate is the same ie 1/12km/min.
set up second R x T =D case.
1/12 km/min x 73 = 6.08 km
Now the total journey would be halved as distance would be same in each direction. 6.08/2 =3.04
D.
Answer: (D) 3.04
Question: A bulldog received 1,600 votes in a bulldog competition, giving him 20 percent of the votes. What percent of the remaining votes would he have needed to receive in order to win 32 percent of the total votes?
(A) 10%
(B) 12.5%
(C) 15%
(D) 17.5%
(E) 20%
Rationale: There were 80% of the votes remaining and he needed 12%/80% = 3/20 = 15%
The answer is C.
Answer: (C) 15%
Question: If DREAM is coded as 78026 and CHILD is coded as 53417,how can LEADER be coded ?
(A) 102078
(B) 102708
(C) 102087
(D) 102780
(E) 102790
Rationale: from given two words L=1 E=0 A=2 D=7 E=0 and R=8
ANSWER:B
Answer: (B) 102708
Question: A number when divided by 4, gives 40 as quotient and 0 as remainder. What will be the remainder when dividing the same number by 3
(A) A)1
(B) B)3
(C) C)4
(D) D)6
(E) E)7
Rationale: Explanation:
P ÷ 4 = 40
=> P = 40 * 4 =160
P / 3 = 160/ 3 = 53, remainder = 1
Answer: Option A
Answer: (A) A)1
Question: A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 6km?
(A) 3
(B) 6
(C) 8
(D) 9
(E) 6
Rationale: M = 4
S = 2
US = 4 - 2 = 2
D = 6
T = 6/2 = 3
Answer:A
Answer: (A) 3
Question: The salary of a person was reduced by 28%. By what percent should his reduced salary be raised so as to bring it at par with his original salary?
(A) 10%
(B) 15%
(C) 20%
(D) 25%
(E) 38.9%
Rationale: Let the original salary be $100
new salary = $72
increase on 72 = 28
increase on 100 = [(28/72)100]% = 38.9%
Answer is E
Answer: (E) 38.9%
Question: In honor of the year 2014, a donor has purchased 2016 books to be distributed evenly among the elementary schools in a certain school district. If each school must receive the same number of books, and there are to be no books remaining, which of the following is NOT a number of books that each school could receive?
(A) 18
(B) 36
(C) 42
(D) 55
(E) 56
Rationale: All options other than 'D' are factors of 2014. Hence, 'D' is the answer
Answer: (D) 55
Question: The ratio of Gomati’s and Rashmi’s ages is 3 : 5 respectively. After ten years this ratio will become 2 : 3. What is Rashmi’s age in years?
(A) 50
(B) 40
(C) 60
(D) Cannot be determined
(E) None of these
Rationale: Quicker Method : After 10 years, the ratio of Gomati and Rashmi’s ages is 2 : 3. We can also write 2 : 3 as 4 : 6. Now, difference in the ratio is I in both the cases.
Therefore, 1 = 10
∴ 5 → 5 × 10 = 50 years.
Answer A
Answer: (A) 50
Question: a man leaves office daily at 7 pm, a driver with car comes from his home to pick up him from office and bring back home.one day he gets free at 5:30 pm....,instead of waiting for car ,he starts walking towards his home,on the way he meets the car and returns home by car,he reaches home 20 minutes earlier than usual. In how much time does he reach home usually ?
(A) 1 hr and 20 mins
(B) 1 hr and 30 mins
(C) 1 hr and 40 mins
(D) 1 hr and 10 mins
(E) 1 hr and 50 mins
Rationale: Since the car has met the person 20 minutes before hand, it has actually saved 10 mins of journey (to and fro)
since the man has started 1.30 hrs before and car has met him 10 mins before actual time he takes to reach daily is 1 hr and 20 mins
ANSWER:A
Answer: (A) 1 hr and 20 mins