mathewhe/aqua_rat huggingface dataset:
Question: A single letter is selected at random from the word 'PROPER'. The probability that it is a vowel is..??
(A) 2/11
(B) 3/11
(C) 4/11
(D) 0
(E) 2/6
Rationale: total vowels = 2, total number of letters = 6
so probability = 2/6
ANSWER:E
Answer: (E) 2/6
Question: A present value of a machine is $12800. Its value depletiation rate is 25% per annum then find the machine value after 3 years?
(A) A)$5400
(B) B)$4800
(C) C)$36520
(D) D)$32450
(E) E)$42500
Rationale: P= $12800
R = 25%
T = 3 years
Machine value after 3years = P/(1-R/100)^T
=12800*3/4 * 3/4 * 3/4
=$5400
Answer is A
Answer: (A) A)$5400
Question: Two pipes P and Q can fill a cistern in 15 and 10 minutes respectively. Both are opened together, but at the end of 6 minutes the first is turned off. How much longer will the cistern take to fill?
(A) 6 1/7
(B) 6 1/4
(C) 6
(D) 6 1/2
(E) 6 1/1
Rationale: 6/15+ x/10= 1
x= 6.Answer: C
Answer: (C) 6
Question: Find the area of a rhombus whose side is 25 cm and one of the diagonals is 31 cm?
(A) 276 sq.cm
(B) 268 sq.cm
(C) 618 sq.cm
(D) 297 sq.cm
(E) 620 sq.cm
Rationale: Consider the rhombus ABCD. Let the diagonals intersect at E. Since diagonals bisect at right angles in a rhombus.
BE2 + AE2 = AB2
252 = 152 + AE2 AE = √(625 - 225)
= √400 = 20,
AC = 20 + 20 = 40 cm.
Area of a rhombus
= 1/2 * d1d2
= 1/2 * 40 * 31
= 620 sq.cm.
Answer:E
Answer: (E) 620 sq.cm
Question: If a no. when divided by 44, gives 432 as quotient and 0 as remainder. What will be the remainder when dividing thesame no. by 31
(A) 2
(B) 4
(C) 5
(D) 6
(E) 8
Rationale: P ÷ 44 = 432
=> P = 432 * 44 = 19008
P / 31 = 19008 / 31 = 613, remainder = 5
C
Answer: (C) 5
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
(A) 140 sq.units
(B) 268 sq.units
(C) 167 sq.units
(D) 197 sq.units
(E) 157 sq.units
Rationale: Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10
= 140 sq.units
Answer:A
Answer: (A) 140 sq.units
Question: A cube of edge 12cm is immersed completely in a rectangular vessel containing water. If the dimensions of the base of vessel are 20cm * 15cm , find the rise in water level?
(A) 5.76cm
(B) 8.25cm
(C) 11.25cm
(D) 15.12cm
(E) 20.62cm
Rationale: Increase in volume = volume of the cube = 12*12*12 cm^3
Rise in water level = volume / area = 12*12*12/20*15 = 5.76cm
Answer is A
Answer: (A) 5.76cm
Question: A ship sails 4 degrees north, then 13 S. then 17 N. then 23 S. and has finally 11 degrees of south latitude. What was her latitude at starting ?
(A) 0
(B) 1
(C) 2
(D) 4
(E) None of these
Rationale: Let x = the latitude sought.
Then marking the northings +, and the southings -;
By the statement x + 4 - 13 + 17 - 23 = -11
And x = 4.
Answer D
Answer: (D) 4
Question: In a competitive examination in a state A, 10% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 12% candidates got selected with 100 more candidates got selected than A. What was the number of candidates appeared from each state?
(A) 4000
(B) 5000
(C) 5500
(D) 6500
(E) 4200
Rationale: Let the number of candidates appeared be x
then, 12% of x - 10% of x = 100
2% of x = 100
x = 100*100/2 = 5000
Answer is B
Answer: (B) 5000
Question: Three runners running around a circular track can complete one revolution in 2, 4 and 5.5 respectively. When will they meet at starting point ?
(A) 40 h
(B) 44 h
(C) 38 h
(D) 20 h
(E) 22 h
Rationale: Time at which they meet at starting point
= LCM of 2, 4 and 5.5
= 44 h
Answer : B
Answer: (B) 44 h
Question: How many cases do you need if you have to pack 500 same Dolls into cases that each hold five pair of Doll ?
(A) 25 cases
(B) 35 cases
(C) 50 cases
(D) 45 cases
(E) 40 cases
Rationale: D
45
500 Dolls = 225 pairs of Dolls.
225 ÷ 5= 45 cases.
Answer: (D) 45 cases
Question: A candy company sells premium chocolate at $5 per pound and regular chocolate at $4 per pound in increment of whole pound only.If Barrett buys a pack of candies which costs him $30, how many pounds of premium chocolates are in the box?
(A) [A] 1
(B) [B] 2
(C) [C] 3
(D) [D] 4
(E) [E] 5
Rationale: This question is a bit of Special equations with a single set of unique values.
the Equation stands : 5X + 4Y = 30
Subtract multiple of 5 from 31 and check whether the remaining total is divisible by 4
31 - 5 = 26 -> Not divisible by 4
31 - 10 = 21 -> Not divisible by 4
31 - 15 =16 -> Divisible by 4
31 - 20 =11 -> Not divisible by 4
31 - 25 =6 -> Not divisible by 4
31 - 30 =1 -> Not divisible by 4
Any multiple of 5 hereon will give a negative value for regular chocolates bought and hence, inadmissible
Thus Amount spent on regular chocolate= $16
Amount spent on Premium chocolate= $15
Price per premium chocolate = $5
No. Of boxes of premium chocolate bought = 14 / 7 = 2
Correct Option : B
Answer: (B) [B] 2
Question: Two trains of length 150 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?
(A) 22 sec
(B) 77 sec
(C) 76 sec
(D) 21.5 sec
(E) 66 sec
Rationale: Relative speed = (42 + 30) * 5/18 = 4 * 5 = 20 mps.
Distance covered in passing each other = 150 + 280 = 430 m.
The time required = d/s = 430/20 = 21.5 sec.
Answer:D
Answer: (D) 21.5 sec
Question: It takes 60 identical printing machines 2 hours to print 300 cards. How much more time would it take 50 of these machines to print the same total?
(A) 20 min
(B) 25 min
(C) 26 min
(D) 36 min
(E) 30 min
Rationale: 50% of 60 = 30% or 0.30
2 hr x 60 min = 120 min
120 min x 0.30 = 36 min
It will take 36 min longer to print them with only 50 printers.
Answer is D
Answer: (D) 36 min
Question: Mario and Nina each have a bag of marbles, each of which contains 5 blue marbles, 10 red marbles, and 5 white marbles. If Mario and Nina each select one marble from their respective bags, what is the probability that either Mario or Nina select a red marble?
(A) 3/4
(B) 1/4
(C) 2/4
(D) 1/8
(E) 1/16
Rationale: Mario and Nina each select one marble from their respective bags.
Probability that either Mario or Nina select a red marble = Probability that Mario selects a red marble + Probability that Nina selects a red marble
Probability that either Mario or Nina select a red marble = (10/20)*(10/20) + (10/20)*(10/20) = 2*(1/4)
Probability that either Mario or Nina select a red marble = 1/2
Answer would be C.
Answer: (C) 2/4
Question: A bag contains a certain number of 50 paise coins, 20 paise coins and 10 paise coins inthe ratio 3:4:5. If the total value of all the coins in the bag is Rs.420, find the number of 50 paise coins ?
(A) 498
(B) 488
(C) 450
(D) 528
(E) 418
Rationale: 50*3k + 20*4k + 10*5k = 42000
280k = 42000 => k = 150
50p coins = 3k = 3*150 = 450
ANSWER:C
Answer: (C) 450
Question: The average weight of the teacher and six students is 12 kg which is reduced by 5 kg if the weight of the teacher is excluded. How much does the teacher weigh ?
(A) 42
(B) 77
(C) 66
(D) 28
(E) 11
Rationale: lanation:
Total age of the students and teacher together = 7 × 12 = 84
New average after excluding teacher = 6 × 7 = 42
Teachers weight = 74 - 42 = 42
Answer:A
Answer: (A) 42
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
(A) 140
(B) 150
(C) 160
(D) 170
(E) 180
Rationale: Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10 = 140 sq.units
Answer: Option A
Answer: (A) 140
Question: The remainder when 1!+2!+3!...+50! divided by 7! will be
(A) 21
(B) 873
(C) 777
(D) 927
(E) 19
Rationale: The remainder when the terms greater than 7! are divided by 7! becomes 0 so we need to consider the terms upto 6!.
So remainder will be whatever is obtained by dividing 1!+2!+3!+4!+5!+6! with 7!.
So remainder is obtained by dividing (1+2+6+24+120+720)= 873 with 7! ( 5040)
So remainder is 873.
Answer:B
Answer: (B) 873
Question: In how many ways letters of the word POLICIES be arranged?
(A) 45326
(B) 28763
(C) 20160
(D) 45693
(E) 54823
Rationale: POLICIES has 8 letters, out of which I repeated 2 times. Hence total ways = 8! / 2! = 20160ways
C
Answer: (C) 20160
Question: There are 70 supermarkets in the FGH chain. All of them are either in the US or Canada. If there are 14 more FGH supermarkets in the US than in Canada, how many FGH supermarkets are there in the US?
(A) 20
(B) 31
(C) 42
(D) 53
(E) 64
Rationale: x + (x - 14) = 70 --> x = 42.
Answer: C.
Answer: (C) 42
Question: The sector of a circle has perimeter 83 cm and central angle 225o. Find its radius?
(A) 21 cm
(B) 15 cm
(C) 14 cm
(D) 24 cm
(E) 28 cm
Rationale: Let radius = x cm
Perimeter of the sector = length of the arc + 2(radius)
83= (225/360 * 2 * 22/7 * x) + 2(x)
83= 55x/14 + 2x
83 = 83x/14
1162=83x
x = 14
Answer: C
Answer: (C) 14 cm
Question: An automobile financier claims to be lending money at S.I., but he includes the interest every six months for calculating the principal. If he is charging an interest of 20%, the effective rate of interest becomes?
(A) 40.5%
(B) 20.5%
(C) 10%
(D) 30.5%
(E) 50.5%
Rationale: Let the sum be Rs. 100. Then,
S.I. for first 6 months = (100 * 20 *1) / (100 * 2) = Rs. 10
S.I. for last 6 months = (105 * 20 * 1) / (100 * 2) = Rs. 10.5
So, amount at the end of 1 year = (100 + 10+10.5) = Rs. 120.5
Effective rate = (120.5- 100) = 20.5%.
ANSWER:B
Answer: (B) 20.5%
Question: At a certain zoo, the ratio of sea lions to giraffes is 7 to 11. If there are 81 more giraffes than sea lions at the zoo, how many sea lions are there?
(A) 24
(B) 36
(C) 48
(D) 72
(E) 141
Rationale: 7/11 = x / x+81
7*81 = 4x
x=141
E. 141
Answer: (E) 141
Question: If k is the greatest positive integer such that 3^k is a divisor of 18! then k =
(A) 3
(B) 4
(C) 5
(D) 6
(E) 8
Rationale: 18/3=6
18/9=2
6+2 =8
k=8
Answer:E
Answer: (E) 8
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?
(A) 867 Sec
(B) 190 Sec
(C) 686 Sec
(D) 686 Sec
(E) 466 Sec
Rationale: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 1900 m
T = D/S
T = 1900/10
T = 190 Sec
Answer:B
Answer: (B) 190 Sec
Question: Solve :
42 : 56 :: 110 : ?
(A) 121
(B) 111
(C) 132
(D) 143
(E) 158
Rationale: 6*7=42
7*8=56
10*11=110
11*12=132
ans 42:56::110:132
ANSWER:C
Answer: (C) 132
Question: There is a 50% chance that Alice will visit China this year, while there is a 20% chance that she will visit Brazil this year. What is the probability that Alice will visit either China or Brazil this year, but NOT both?
(A) 50%
(B) 45%
(C) 40%
(D) 35%
(E) 30%
Rationale: P(China but not Brazil)=0.5*0.8=0.4
P(Brazil but not China)=0.2*0.5=0.1
P(China or Brazil but not both)=0.4+0.1=0.5
The answer is A.
Answer: (A) 50%
Question: A certain store sells only black shoes and brown shoes. In a certain week, the store sold x black shoes and y brown shoes. If 2/5 of all shoes sold that week were black, which of the following expressions represents the value of y, in terms of x?
(A) x/3
(B) x/2
(C) 2x/3
(D) 3x/2
(E) 2x
Rationale: x/(x+y) = 2/5
5x = 2x+2y
3x = 2y
y = 3x/2
Answer D
Answer: (D) 3x/2
Question: In a stockpile of products produced by three machines M1, M2 and M3, 40% and 30% were manufactured by M1 and M2 respectively. 3% of the products of M1 are defective, 1% of products of M2 defective, while 93% of the products of M3 III are not defective. What is the percentage of defective in the stockpile?
(A) 3%
(B) 5%
(C) 2.5%
(D) 4%
(E) 3.6%
Rationale: Explanation :
Let there be 100 products in the stockpile. 40% and 30% were manufactured by M1 and M2 respectively. So, 30% are manufactured by M3.
Products from M1 = 40, from M2 = 30 and from M3 = 30.
Number of defective products from M1 = 0.03 x 40 = 1.2, from M2 = 0.01 x 30 = 0.3 and from M3 = 0.07 x 30 = 2.1
Therefore, total number of defective products = 3.6
Answer : E
Answer: (E) 3.6%
Question: The length of a room is 5.5 m and width is 3.75 m. What is the cost of paying the floor by slabs at the rate of $300 per sq. metre.
(A) $2587.50
(B) $3587.50
(C) $4187.50
(D) $6187.50
(E) $8587.50
Rationale: Area =5.5×3.75 sq. metre.
Cost for 1 sq. metre. = $300
Hence, total cost
=5.5×3.75×300= $6187.50
D
Answer: (D) $6187.50
Question: 54671 - 14456 - 33490 = ?
(A) 2449
(B) 5449
(C) 6749
(D) 6725
(E) 6468
Rationale: D
If we calculate we will get 6725
Answer: (D) 6725
Question: A sum of money is sufficient to pay X's wages for 36 days and Y's wages for 45 days. The same money is sufficient to pay the wages of both for?
(A) 16
(B) 17
(C) 18
(D) 19
(E) 20
Rationale: Let the total money be $x
X's 1day work = $ x/36
Y's 1day work = $ x/45
X+Y 1day work = $ x/20
Money is sufficient to pay the wages of both for 20days
Answer is E
Answer: (E) 20
Question: The cost of 6 pens is 10 more than 5 marker's cost. The 12 pens is Rs.240.
(A) Rs.11
(B) Rs.42
(C) Rs.24
(D) Rs.110
(E) Rs.22
Rationale: Let the cost of each pen and marker be 'p' and 'q' respectively.
6p - 5q = 10 --- (1)
12p= 240 . P=20
6p - 5q = 10 --- (2)
120-5q =10
=>5q = 110
=> q=22
ANSWER:E
Answer: (E) Rs.22
Question: Find a number such that it exceeds 18 by three times the number by which it is less than 86?
(A) 67
(B) 68
(C) 69
(D) 70
(E) 71
Rationale: x-18=3[86-x]
x=69
ANSWER:C
Answer: (C) 69
Question: Three numbers are in the ratio 5 : 6 : 7. The sum of its longest and smallest numbers equals the sum of the third number and 85. Find the third number?
(A) A)37
(B) B)85
(C) C)48
(D) D)43
(E) E)84
Rationale: Let the numbers be 5x, 6x, 7x.
Largest number = 7x.
Smallest number = 5x.
Third number = 6x.
7x + 5x = 6x + 85
6x = 85 => third number is 85.
Answer: Option B
Answer: (B) B)85
Question: The ratio of football players, baseball players, soccer players, and basketball players in a school is 10:7:5:4. How many athletes are in the school if 16 players are on the basketball team?
(A) 40
(B) 92
(C) 104
(D) 208
(E) 80
Rationale: The ratio is 10 football players: 7 baseball players: 5 soccer players: 4 basketball players.
Divide 16 by 4 to find 1 "part" of the ratio.
16/4 = 4
Multiply 4 by 5 to find the number of soccer players.
4*5 = 20
Multiply 4 by 7 to find the number of baseball players.
4*7 = 28
Multiply 4 by 10 to find the number of football players.
4*10 = 40.
Add them all up to find total athletes.
16+20+28+40 = 104
The answer is C.
Answer: (C) 104
Question: Rectangle ABCD is constructed in the coordinate plane parallel to the x- and y-axes. If the x- and y-coordinates of each of the points are integers which satisfy 5 ≤ x ≤ 11 and -5 ≤ y ≤ 5, how many possible ways are there to construct rectangle ABCD?
(A) 396
(B) 1260
(C) 1155
(D) 7920
(E) 15840
Rationale: As the rectangle is parallel to coordinate axes, the coordinates of the points of the rectangle would be
(X1, Y1), (X2, Y1), (X2, Y2), (X1,Y2)
given that X1, X2 lie between 5 and 11..ie., 7 possible numbers
Possible combinations for X1,X2 would be 7C2 = 21
Similarly, Possible combinations for Y1, Y2 would be 11C2 = 55
Possible ways of constructing rectangle is by selecting any of the combination of X1,X2 and Y1,Y2
= 21 * 55 = 1155
Ans. C
Answer: (C) 1155
Question: How much does a watch lose per day, if its hands coincide ever 64 minutes?
(A) 32x8/11 min
(B) 36x8/11 min
(C) 90 min
(D) 96 min
(E) None
Rationale: 55 min. spaces are covered in 60 min. 60 min. spaces are covered in (60/55 x 60) min = 65x5/11 min. Loss in 64 min.(65x5/11 - 64). = 16/11 Loss in 24 hrs(16/11x1/64x24x60)min = 32x8/11.
Answer A
Answer: (A) 32x8/11 min
Question: The average speed of a car decreased by 3 miles per hour every successive 8-minutes interval. If the car traveled 3.6 miles in the sixth 8-minute interval, what was the average speed of the car, in miles per hour, in the first 8 minute interval?
(A) 30
(B) 34
(C) 38
(D) 42
(E) 46
Rationale: (3.6 miles / 8 minutes)*60 minutes/hour = 27 mph
Let x be the original speed.
x - 5(3) = 27
x = 42 mph
The answer is D.
Answer: (D) 42
Question: Working at constant rate, pump X pumped out half of the water in a flooded basement in 5 hours. The pump Y was started and the two pumps, working independently at their respective constant rates, pumped out rest of the water in 3 hours. How many hours would it have taken pump Y , operating alone at its own constant rate, to pump out all of the water that was pumped out of the basement?
(A) a. 10
(B) b. 12
(C) c. 14
(D) d. 26
(E) e. 24
Rationale: rate of x=1/8
rate of x+y=1/6
rate of y=1/6-1/8=1/24
26 hours
D
Answer: (D) d. 26
Question: In a 200 metres race A beats B by 35 m or 7 seconds. A's time over the course is:
(A) 40 sec
(B) 47 sec
(C) 33 sec
(D) 35 sec
(E) None of these
Rationale: speed of B=s2.
A's time of course=t.
200=s2*(t+7) ---(eq 1)
200-35=s2*t ---(eq 2)
from these 2 eqs, we get t=33sec.
ANSWER:C
Answer: (C) 33 sec
Question: Little John had $8.50. He spent $1.25 on sweets and gave to his two friends $1.20 each. How much money was left?
(A) $3.95
(B) $6.65
(C) $9.75
(D) $7.25
(E) $4.85
Rationale: John spent and gave to his two friends a total of
1.25 + 1.20 + 1.20 = $3.65
Money left
8.50 - 3.65 = $4.85
correct answer E
Answer: (E) $4.85
Question: A father is now three times as old as his son. NINE years back, he was four times as old as his son. The age of the son (in years) is
(A) 12
(B) 15
(C) 18
(D) 20
(E) 27
Rationale: If father's age is F and son's age is S, then
F=3S
and
F-9 = 4*(S-9)
3S-9 =4S-36
S=27
F=81 years
ANSWER:E
Answer: (E) 27
Question: Six children — A, B, C, D, E and F— are going to sit in six chairs in a row. The children B & F have to sit next to each other, and the others can sit in any order in any remaining chairs. How many possible configurations are there for the children?
(A) 240
(B) 720
(C) 1440
(D) 4320
(E) 4800
Rationale: for such questions , we can treat both as one then total person=5.
these 5 can be arranged in 5! ways.. but within these 5 , one consists of two people who can be arranged in 2 ways BF or FB.. so ans =5!*2=240
ans A
Answer: (A) 240
Question: 220% of a number X is 44. What is 44% of X.
(A) 8.8
(B) 8.9
(C) 6.6
(D) 7.7
(E) None
Rationale: Solution: Given,
220% of X = 44
Or, X = 20.
Thus,
44% of 20
= (44 *20) /100
= 8.8
Answer: Option A
Answer: (A) 8.8
Question: A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning?
(A) 39
(B) 42
(C) 58
(D) 62
(E) 75
Rationale: Let the average after 7th inning = x
Then average after 16th inning = x - 3
therefore 16(x-3)+87 = 17x
therefore x = 87 - 48 = 39
Answer A
Answer: (A) 39
Question: Two trains, each 100 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is?
A. 30 km/hr B. 45 km/hr
(A) 11
(B) 78
(C) 60
(D) 28
(E) 81
Rationale: Let the speed of the slower train be x m/sec.
Then, speed of the train = 2x m/sec.
Relative speed = ( x + 2x) = 3x m/sec.
(100 + 100)/8 = 3x => x = 25/3.
So, speed of the faster train = 50/3 = 50/3 * 18/5 = 60 km/hr.Answer: C
Answer: (C) 60
Question: If a is an integer greater than 8 but less than 15 and b is an integer greater than 6 but less than 21, what is the range of a/b?
(A) 140/217
(B) 156/185
(C) 217/140
(D) 263/149
(E) 241/163
Rationale: The way to approach this problem is 8<a<15 and 6<b<21
Minimum possible value of a is 9 and maximum is 14
Minimum possible value of b is 7 and maximum is 20
Range = max a/min b - min a/max b
(Highest - lowest)
14/7 - 9/20 = 217/140
Hence C
Answer: (C) 217/140
Question: sale of Rs 6835, Rs. 9927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6900 ?
(A) 4966
(B) 6477
(C) 7391
(D) 2676
(E) 1881
Rationale: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6900 x 6) - 34009]
= Rs. (41400 - 34009)
= Rs. 7391
Answer: C
Answer: (C) 7391
Question: If x and t are integers and 2x–t= 11, then 4x+ t CANNOT be
(A)  –5
(B)  1
(C)  13
(D)  17
(E)  551
Rationale: 2x-t=11....t=2x-11
4x+t=4x+2x-11=6x-11
6x-11=-5...x=1
6x-11=1... x=2
6x-11=13...x=4
6x-11=17..X is not integer
6x-11=551..X is not integer
I think the choice E is 55 not 551. Otherwise both DE CANNOT be solution=D
Answer: (D)  17
Question: Find the unknown term 8,8,X,2,-4, -12
(A) 2
(B) 4
(C) 6
(D) 8
(E) 9
Rationale: 8,8,X,2,-4, -12
i guess each differ in d range of 2
8 - 8 = 0
8 - 6 = 2
6 - 2 = 4
2 - 6 = -4
-4 - 8 = -12
ANSWER:C
Answer: (C) 6
Question: A tradesman sold an article at a loss of 25%. If the selling price had been increased by $500, there would have been a gain of 15%. What was the cost price of the article ?
(A) $1000
(B) $1200
(C) $1120
(D) $1350
(E) $1250
Rationale: Let C.P. be $x
Then 125% of x - 85% of x = 500
40% of x = 500
2x/5 = 500
x = $1250
Answer is E
Answer: (E) $1250
Question: Diana is painting statues. She has 7/8 of a gallon of paint remaining. Each statue requires 1/8 gallon of paint. How many statues can she paint?
(A) 7
(B) 20
(C) 28
(D) 14
(E) 19
Rationale: number of statues=all the paint÷amount used per statue
=7/8 ÷ 1/8
=7/8*8/1
=7/1
=7
Answer is A.
Answer: (A) 7
Question: Natasha climbs up a hill, and descends along the same way she went up. It takes her 4 hours to reach the top and 2 hours to come back down. If her average speed along the whole journey is 3.5 kilometers per hour, what was her average speed (in kilometers per hour) while climbing to the top?
(A) 2.125
(B) 2.375
(C) 2.625
(D) 2.675
(E) 2.825
Rationale: Let the distance to the top be x, so the total distance traveled by Natasha is 2x.
The total time is 4 + 2 = 6 hours
The average speed = total distance/total time taken = 2x/6 = x/3
The average speed of the complete journey is 3.5 km/hour
x/3 = 3.5
x = 10.5 km
The average speed while climbing = distance/time = 10.5/4 = 2.625 km/h
The answer is C.
Answer: (C) 2.625
Question: A sports retailer ordered white and yellow tennis balls in equal number but the dispatch clerk of the tennis ball company erred and dispatched 50 extra yellow balls and making ratio of white balls to yellow balls 8/15. How many tennis balls did the retailer order originally.
(A) 110
(B) 114.28
(C) 140
(D) 160
(E) 214
Rationale: White:Yellow = x:(x+50) = 8:15 --> 15x = 8x + 400 --> x = 57.14.
The total # of balls originally x + x = 57.14 + 57.14 = 114.28.
Answer: B.
Answer: (B) 114.28
Question: Ramesh has X rupees, on Monday beginning of the month. On every Monday his mother gives 10 rupees as pocket money. He spends half of what he had during that week on the 4th Monday of the month, when his mother gave his pocket Monday, he had 27 1/2 rupees . What was the Money he had in the beginning.
(A) Rs.50
(B) Rs.90
(C) Rs.80
(D) Rs.70
(E) Rs.60
Rationale: on the 2nd Monday he will have 80. so he spends 40 and remaining is 40. the next Monday he will have 50. he spends 25 and remaining is 25. so on the 4th Monday he will have 35. he will spent half of it so remaining is 27 1/2.
ANSWER:D
Answer: (D) Rs.70
Question: The center of a circle is (4, -2). (4, 7) is outside the circle, and (1, -2) is inside the circle. If the radius, r, is an
integer, how many possible values are there for r?
(A)  4
(B)  2
(C)  1
(D)  10
(E)  11
Rationale: r must be greater than 3 and smaller than 9, hence r=4,5,6,7 or 8.
Answer A
Answer: (A)  4
Question: 4000 was divided into two parts such a way that when first part was invested at 3% and the second at 5%, the whole annual interest from both the investments is Rs.144, how much was put at 3%?
(A) 3377
(B) 2678
(C) 2800
(D) 2786
(E) 1981
Rationale: (x*3*1)/100 + [(4000 - x)*5*1]/100 = 144
3x/100 + 200 – 5x/100 = 144
2x/100 = 56 è x = 2800'
Answer: C
Answer: (C) 2800