mathewhe/aqua_rat huggingface dataset:
Question: A man cheats while buying as well as while selling. While buying he takes 10% more than what he pays for and while selling he gives 20% less than what he claims to. Find the profit percent, if he sells at 10% below the cost price of the claimed weight.
(A) 19.81%
(B) 20%
(C) 37.5%
(D) 23.75%
(E) 37.5%
Rationale: There is a one step calculation method too. It requires more thought but is faster.
The man takes 10% more than what he pays for. So if he claims to take 100 pounds, he pays $100 but he actually takes 110 pounds for which he will take from the customer $110. Hence, in effect, there is a 10% mark up.
While selling, he sells 20% less. This means, he claims to sell 100 pounds and gets $100 but actually sells only 80 pounds and should have got only $80 for it. So this is again a mark up of $20 on $80 which is 25%.
But he also sells at 10% less
(1 + m1%)(1 + m2%)(1 - d%) = (1 + p%)
11/10 * 5/4 * 9/10 = (1 + p%)
profit % = 23.75%
D
Answer: (D) 23.75%
Question: Find the area of a parallelogram with base 24 cm and height 16 cm?
(A) 297 cm2
(B) 384 cm2
(C) 672 cm2
(D) 267 cm2
(E) 286 cm2
Rationale: Area of a parallelogram
= base * height
= 24 * 16
= 384 cm2
Answer: B
Answer: (B) 384 cm2
Question: How many liters of water must be evaporated from 50 liters of a 2 percent sugar solution to get a 5 percent sugar solution?
(A) 20
(B) 25
(C) 30
(D) 32
(E) 35
Rationale: Let x be the amount that needs to be evaporated.
0.02(50) = 0.05(50-x)
0.05x = 2.5 - 1
x = 1.5/0.05 = 30 liters
The answer is C.
Answer: (C) 30
Question: The average age of students of a class is 15.8 years. The average age of boys in the class is 16.2 years and that of the girls is 15.4 years. The ration of the number of boys to the number of girls in the class is:
(A) 2:5
(B) 2:3
(C) 2:4
(D) 1:1
(E) 2:9
Rationale: Let the ratio be k : 1. Then,
k * 16.2 + 1 * 15.4 = (k + 1) * 15.8
= (16.2 - 15.8)k = (15.8 - 15.4)
= k = 0.4/0.4 = 1/1
Required ratio = 1/1 : 1 = 1:1.
Answer:D
Answer: (D) 1:1
Question: An article is bought for Rs.600 and sold for Rs.500, find the loss percent?
(A) 16 2/8%
(B) 11 2/3%
(C) 16 9/3%
(D) 16 2/3%
(E) 16 2/5%
Rationale: 600 ---- 100
100 ---- ? => 16 2/3%
Answer: D
Answer: (D) 16 2/3%
Question: A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m , then the altitude of the triangle is.
(A) 200 m
(B) 150 m
(C) 148 m
(D) 140 m
(E) None of these
Rationale: Explanation:
Let the triangle and parallelogram have common base b,
let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then
Area of triangle =1/2∗b∗h1
Area of rectangle =b∗h2
As per question 1/2∗b∗h1=b∗h2
1/2∗b∗h1=b∗100
h1=100∗2=200m
Option A
Answer: (A) 200 m
Question: In a certain region, the number of children who have been vaccinated against rubella is twice the number who have been vaccinated against mumps. The number who have been vaccinated against both is twice the number who have been vaccinated only against mumps. If 6,000 have been vaccinated against both, how many have been vaccinated only against rubella?
(A) 2,5000
(B) 7,500
(C) 12,000
(D) 15,000
(E) 17,500
Rationale: Use a single variable as far as possible.
Number vaccinated only against mumps = x
Number vaccinated against both = 2x = 6000 (so x = 3000)
Then, number vaccinated against mumps (including both) = x + 2x = 3x
Number vaccinated against rubella = 2*3x = 6x
Then, number vaccinated against only rubella = 6x - 2x = 4x = 4*3000 = 12,000
Answer (C)
Answer: (C) 12,000
Question: Each of the following equations R has at least one solution EXCEPT
(A) R=–2^n = (–2)^-n
(B) R=2^-n = (–2)^n
(C) 2^n = (–2)^-n
(D) (–2)^n = –2^n
(E) (–2)^-n = –2^-n
Rationale: While it is possible to reason out which of these choices must not work, we may not have time or the confidence to do so. However, this problem has variable in its answer choice, and relatively simple math. Therefore, an easy alternative is picking numbers.
Since we're dealing with exponents, we want to keep things as easy as possible. Hence, we'll start with the easiest exponent possible: n = 1. A, B, and C are not solved (x^-n = 1/(x^n), so we're comparing integers to fractions), but choices D and E both end up valid, eliminating them from contention.
In the process of doing this, however, we've uncovered a major clue to our next step: A, B, and C, all compared integers to fractions, and the only integer equal to it's reciprocal is 1, which is equal to 1/1. This, in turn, tells us the we need to pick n = 0. Remember, for all non-zero x, x^0 = 1.
If we plug n = 0 into choices B and C, we end up with 1 = 1 both times. Choice A, however, results in the false 1 = -1. Thus, we conclude that the first choice has no valid solutions, and is therefore the correct answer.
Answer: (A) R=–2^n = (–2)^-n
Question: A car finishes a journey in ten hours at the speed of 50 km/hr. If the same distance is to be covered in five hours how much more speed does the car have to gain?
(A) 8 km/hr
(B) 10 km/hr
(C) 12 km/hr
(D) 16 km/hr
(E) 50 km/hr
Rationale: Distance covered by the car = 50 × 10 = 500 km
\ Speed = 500⁄5 = 100 km/hr
\ Speed gain = 100 – 50 = 50 km/hr
Answer E
Answer: (E) 50 km/hr
Question: AT + CD = AAA, where AT and CD are two-digit numbers and AAA is a three digit number; A, T, C, and D are distinct positive integers. In the addition problem above, what is the value of C?
(A)  1
(B)  3
(C)  7
(D)  9
(E)  Cannot be determined
Rationale: Since AT and CD are two-digit integers, their sum can give us only one three digit integer of a kind of AAA: 111.
So, A=1 and we have 1T+CD=111
Now, C can not be less than 9, because no two-digit integer with first digit 1 (1T<20) can be added to two-digit integer less than 90, so that to have the sum 111 (if CD<90, so if C<9, CD+1T<111).
Hence C=9.
Answer: D.
Answer: (D)  9
Question: The labeled price of a table is Rs. 8,000. The shopkeeper sold it by giving 5% discount on the labeled price and earned a profit of 15%. What approximately is the cost price of the table?
(A) Rs. 5758
(B) Rs. 6195
(C) Rs. 6608
(D) Rs. 7200
(E) None of these
Rationale: Explanation:
Labeled price = Rs. 8,000
By giving 5% discount on labeled price, the selling price is
= 95 / 100 * 8000 = Rs. 7600
By earning 15% profit on the selling of price Rs. 7600 the cost price is
= 100 / 115 * 7600= Rs. 6608
Therefore, approximate cost is 6608
ANSWER C
Answer: (C) Rs. 6608
Question: An article was sold after a discount of 20% and there was a gain of 20%. If the profit made on it was Rs. 6 less than the discount offered on it, find its selling price?
(A) Rs. 72
(B) Rs. 90
(C) Rs. 66
(D) Rs. 96
(E) None of these
Rationale: Let CP = Rs. 100x
SP = Rs. 120x
MP = 120x/80 * 100 = Rs. 150x
D = Rs. 150x - Rs. 120x = Rs. 30x
D - P = 30x - 20x = Rs. 6, 10x = Rs. 6
120x = 120/10 * 6 = Rs. 72
ANSWER:A
Answer: (A) Rs. 72
Question: A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 180 m in 18 sec. then find the length of the train?
(A) 170
(B) 180
(C) 190
(D) 120
(E) 130
Rationale: Length of the train be ‘X’
X + 120/15 = X + 180/18
6X + 720 = 5X + 900
X = 180m
Answer: Option B
Answer: (B) 180
Question: The original price of a camera was displayed as a whole dollar amount. After adding sales tax of 12 percent, the final price was also a whole dollar amount. Which of the following could be the final price of the camera?
(A) $223
(B) $225
(C) $224
(D) $213
(E) $215
Rationale: Final price = (1+12/100) * Original Price
= 1.12 * Original Price
From options given only 224 is divisible by 1.12 as it is stated OP is whole dollar amount.
Hence C
Answer: (C) $224
Question: If the sides of a square are multiplied by 10, the area of the original square is how many times as large as the area of the resultant square?
(A) 1%
(B) 10%
(C) 100%
(D) 500%
(E) 1000%
Rationale: Let x be the original length of one side.
Then the original area is x^2.
The new square has sides of length 10x, so the area is 100x^2.
The area of the original square is 1/100 = 1% times the area of the new square.
The answer is A.
Answer: (A) 1%
Question: Jean drew a gumball at random from a jar of pink and blue gumballs. Since the gumball she selected was blue and she wanted a pink one, she replaced it and drew another. The second gumball also happened to be blue and she replaced it as well. If the probability of her drawing the two blue gumballs was 9/49, what is the probability that the next one she draws will be pink?
(A) 1/49
(B) 4/7
(C) 3/7
(D) 16/49
(E) 40/49
Rationale: The probability of drawing a pink gumball both times is the same. The probability that she drew two blue gumballs = 9/49 = (3/7) * (3/7)
Therefore probability that the next one she draws is pink = 4/7
Option (B)
Answer: (B) 4/7
Question: In a race, the odds in favour of cars P, Q, R, S are 1 : 3, 1 : 4, 1 : 5 and 1 : 6 respectively. Find the probability that one of them wins the race.
(A) 9/17
(B) 114/121
(C) 319/420
(D) 27/111
(E) 37/111
Rationale: P(P) = 1/4, P(Q) = 1/5, P(R) = 1/6 and P(S) = 1/7.
All the events are mutually exclusive and hence,
the required probability:
= P(P) + P(Q) + P(R) + P(S)
= 1/4 + 1/5 + 1/6 + 1/7
= 319/420
ANSWER:C
Answer: (C) 319/420
Question: At a game of billiards, A can give B 15 points in 60 & A can give C 20 points in 60. How many points can B give C in a game of 90?
(A) 30 points
(B) 20 points
(C) 10 points
(D) 5 points
(E) 0 points
Rationale: 10 points
ANSWER:C
Answer: (C) 10 points
Question: A person walks at a speed of 4 km/hr and runs at a speed of 8 km/hr. How many hours will the person require to cover a distance of 20 km, if the person completes half of the distance by walking and the other half by running?
(A) 2.75
(B) 3.25
(C) 3.75
(D) 4.25
(E) 4.75
Rationale: time = 10/4 + 10/8 = 30/8 = 3.75 hours
The answer is C.
Answer: (C) 3.75
Question: If a man's rate with the current is 15 km/hr and the rate of the current is 11⁄2 km/hr, then his rate against the current is
(A) 12 km/hr
(B) 22 km/hr
(C) 23 km/hr
(D) 28 km/hr
(E) 13 km/hr
Rationale: Speed downstream = 15 km/hr
Rate of the current= 11⁄2 km/hr
Speed in still water = 15 - 11⁄2 = 131⁄2 km/hr
Rate against the current = 131⁄2 km/hr - 11⁄2 = 12 km/hr
Answer is A
Answer: (A) 12 km/hr
Question: What approximate value should come in place of the question mark (?) in the following equation?47.05 Ã— 8.65 â€“ 25.22 Ã— 6.4 = (28 + ?) Ã— 5
(A) 28.1149
(B) 24.1149
(C) 21.1149
(D) 22.1149
(E) 31.1149
Rationale: Solve using approximation
Answer C
Answer: (C) 21.1149
Question: A certain city with population of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?
(A) 10,700
(B) 10,800
(C) 10,900
(D) 11,000
(E) 11,100
Rationale: population that is 10% greater than the population of any other district..
11000.. 10% of 11000 = 1100.. so the next population will be 12100..
10*12,100 + 11000 = 132000. D
Answer: (D) 11,000
Question: A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.162. Find the unknown rate of two blankets?
(A) 420
(B) 550
(C) 490
(D) 570
(E) 457
Rationale: 10 * 162 = 1620
3 * 100 + 5 * 150 = 1050
1620 – 1050 = 570
Answer:D
Answer: (D) 570
Question: If the set S is composed of the following numbers {99, 100, 100, 105, 106, 116, 123}, which of the following is largest?
(A) The average (arithmetic mean) of set S
(B) The median of set S
(C) The mode of set S
(D) The range of set S
(E) The standard deviation of set S
Rationale: Time consuming question...
A) 99, 100, 100, 105, 106, 116, 123 = 749 and its mean is 749/7 = 107.
B) The list is of 7 numbers and median is 105.
C) Mode is number of repetition of a number in the list , here it is 100.
D) Range = Max value - min value = 123 -99 = 24.
E) SD = square root of (sum of ( mean of series - number)^2 ) / n
=> sq root (64+49+49+4+1+676)/7
= sq rt ( 893/7)
= sq rt ( 127) < 100
Answer: option A is correct answer..
Answer: (A) The average (arithmetic mean) of set S
Question: On thrusday mabel handled 90 transactions. anthony handled 10 % more transaction than mabel, cal handled 2/3rds of the transactions that anthony handled and jade handled 16 more transaction than cal. how much transaction did jade handled?
(A) 92
(B) 80
(C) 72
(D) 82
(E) 28
Rationale: Mabel handled 90 transaction, anthony 10 % more transaction the mabel. anthony = 90+90 * 10%, = 90 + 90 * 0.10 , = 90 + 9, =99, cal handled 2/3rds than anthony handled, cal = 2/3 * 99=66, jade handled 16 more than cal. jade = 66 + 16= 82, jade handled = 82 tranasactions.
correct answer: (D)
Answer: (D) 82
Question: Which of the following statements is equivalent to 8+2X<18−6X<23+2X8+2X<18−6X<23+2X?
(A) 4/5 < X < 2.5.
(B) 4/5 < X < 8/5.
(C) -5/8 < X < 5/4.
(D) 2.5 < X < 3.5.
(E) 5 < 8X < 12.
Rationale: 8+2X<18−6X<23+2X
8<18-8x<23 (add -2x on all sides)
-10<-8x<5
10>8x>-5 (multiply by -1 on all sides)
5/4>x>-5/8
C is the answer
Answer: (C) -5/8 < X < 5/4.
Question: Two numbers are in ratio 4:5 and their LCM is 180. The smaller number is
(A) 9
(B) 15
(C) 36
(D) 45
(E) None
Rationale: Solution: Let two numbers be 4x and 5x;
their LCM = 180 and HCF = x; Now,
1st number * 2nd number = LCM*HCF
Or, 4x*5x = 180*x;
Or, 20x = 180;
Or, x = 9;
then, the smaller number = 4*9 = 36.
Answer: Option C
Answer: (C) 36
Question: A fruit seller had some oranges. He sells 40% oranges and still has 420 oranges. How many oranges he had originally?
(A) 700
(B) 300
(C) 200
(D) 500
(E) 250
Rationale: sell 40% oranges and 420 oranges remaining
=>60% of oranges = 420
total oranges * 60/100 = 420
total oranges = 420*100/60 = 700
ANSWER A
Answer: (A) 700
Question: A can do a piece of work in 4 hours. B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?
(A) 10 hr
(B) 12 hr
(C) 15 hr
(D) 13 hr
(E) 9 hr
Rationale: A's 1 hour work = 1/4
B+C 1 hour work = 1/3
A+C 1 hour work = 1/2
A+B+C 1 hour work = 1/4 + 1/3 = 7/12
B's 1 hour work = 7/12 - 1/2 = 1/12
B alone will take 12 hours to do the work
Answer is B
Answer: (B) 12 hr
Question: x+(1/x) = 2 find x^2 + (1/x^2)
(A) 2
(B) 3.25
(C) 4.25
(D) 5.25
(E) 6.25
Rationale: squaring on both sides (x+1/x)^2=2^2
x^2+1/X^2=4-2
x^2+1/X^2=2
ANSWER:A
Answer: (A) 2
Question: The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 70/kg. how much did a kg of coffee cost in june ?
(A) 70
(B) 60
(C) 80
(D) 100
(E) 120
Rationale: Let the price of tea and coffee be x per kg in June.
Price of tea in July = 1.2x
Price of coffee in July = 0.8x .
In July the price of 1/2 kg (700gm) of tea and 1/2 kg (700gm) of coffee (equal quantities) = 70
1.2x(1/2) + 0.8x(1/2) = 70
=> x =70
Thus proved...option A.
Answer: (A) 70
Question: A man's age is 125% of what it was 10 years ago, but 83 1/3%
of what it will be after 10 years. What is his present age?
(A) 50
(B) 70
(C) 80
(D) 55
(E) 40
Rationale: 125x/100 = x + 10
x = 40
present age = x + 10 =40+10 = 50
ANSWER A
Answer: (A) 50
Question: A small table has a length of 12 inches and a breadth of b inches. Cubes are placed on the surface of the table so as to cover the entire surface. The maximum side of such cubes is found to be 4 inches. Also, a few such tables are arranged to form a square. The minimum length of side possible for such a square is 80 inches. Find b.
(A) 8
(B) 16
(C) 24
(D) 32
(E) 48
Rationale: From the info that the maximum sides of the cubes is 4, we know that the GCF of 12 (=2^2*3) andbis 4 (=2^2), sob=2^x, where x>=2.
From the second premise, we know that the LCM of 12 (2^2*3) andbis 80 (2^4*5), sob=2^4 or 2^4*5 (16 or 80).
Combining 2 premises shows the answer is B(16).
Answer: (B) 16
Question: For an upcoming charity event, a male vocalist has agreed to sing 3 out of 8 “old songs” and 4 out of 7 “new songs.” How many ways can the singer make his selection?
(A) 25
(B) 50
(C) 150
(D) 147
(E) 600
Rationale: =8C6*7C4
=8*7/4*7*6/4
=7*7*3
=147
Ans = D
Answer: (D) 147
Question: Kim bought a total of $4.65 worth of postage stamps in four denominations. If she bought an equal number of 10-cent and 25-cent stamps and twice as many 20-cent stamps as 5-cent stamps, what is the least number of 1-cent stamps she could have bought?
(A) 5
(B) 10
(C) 75
(D) 90
(E) 95
Rationale: Let:
# of 10 and 25 cents stamps = n
# of 20 cent stamps = 2n
# of 1 cent stamps = m
Therefore:
10n + 25n + 20(2n) + m = 465 cents
75n + m = 465
Forleastnumber of 1 cents stamps, maximize 50n. Hence,
75*5 + m = 465
m = 90 i.e. 90 stamps 1 cents each
Answer: D
Answer: (D) 90
Question: The average earning of a person for the first four days of a week is Rs 18 and for the last four days is Rs 22. If he earns Rs 20 on the fourth day, his average earning for the whole week is?
(A) Rs 18.95
(B) Rs 16
(C) Rs 20
(D) Rs 25.71
(E) None of these
Rationale: Total earning for the week
= Rs (4 × 18 + 4 × 22 - 20) = Rs 140
Average earning = Rs 140/7 = Rs 20.
ANSWER:C
Answer: (C) Rs 20
Question: For any number Z, Z* is defined as the greatest positive even integer less than or equal to y. What is the value of 6.25 – 6.25*?
(A) 1.5
(B) 0.5
(C) 6.25
(D) 0.25
(E) 6.0
Rationale: Since Z* is defined as the greatest positive even integer less than or equal to Z, then 6.25* =6 (the greatest positive even integer less than or equal to 6.25 is 6).
Hence, 6.25 – 6.25* = 6.25 - 6 = 0.25
Answer: D.
Answer: (D) 0.25
Question: How many consonants are present between the first and fourth vowel in the sequence of English alphabet ?
(A) 12
(B) 13
(C) 11
(D) 10
(E) None of these
Rationale: Explanation:
Ref : A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
The first and fourth vowels are A and O respectively. There are 13 letters between A and O; out of which 'E' and 'I' are vowels. Thus, there are 11 consonants between A and O.
ANSWER C
Answer: (C) 11
Question: How many 9's are there between 1 and 100?
(A) 10
(B) 20
(C) 22
(D) 18
(E) 27
Rationale: B
20
Answer: (B) 20
Question: A, B and C started a partnership business by investing Rs.8000, Rs.4000, Rs.2000 respectively. At the end of the year , the profit were distributed among them. If C's share of profit is 36000, What is the total profit?
(A) 70000
(B) 60000
(C) 80000
(D) 90000
(E) 252000
Rationale: A:B:C =8000:4000:2000
=4:2:1
Let total profit =p
Then pÃ—1/7=36000
p=(36000Ã—7)/1=252000
Answer is E.
Answer: (E) 252000
Question: P , Q, R enter into a partnership & their share are in the ratio 1/2 : 1/3 : 1/4 , after two months , P withdraws half of the capitals & after 10 months , a profit of Rs 336 is divided among them . What is Q's share?
(A) 114
(B) 128
(C) 134
(D) 144
(E) None of these
Rationale: Explanation :
The ratio of their initial investment = 1/2 : 1/3 : 1/4
= 6 : 4: 3
Let's take the initial investment of P, Q and R as 6x, 4x and 3x respectively
A:B:C = (6x * 2 + 3x * 10) : 4x*12 : 3x*12
= (12+30) : 4*12 : 3*12
=(4+10) : 4*4 : 12
= 14 : 16 : 12
= 7 : 8 : 6
Q's share = 336 * (8/21) = 128. Answer : Option B
Answer: (B) 128
Question: John and Ingrid pay 30% and 40% tax annually, respectively. If John makes $57000 and Ingrid makes $72000, what is their combined tax rate?
(A) 32%
(B) 34.4%
(C) 35%
(D) 35.6%
(E) 36.4%
Rationale: (1) When 30 and 40 has equal weight or weight = 1/2, the answer would be 35.
(2) When 40 has larger weight than 30, the answer would be in between 35 and 40. Unfortunately, we have 2 answer choices D and E that fit that condition so we need to narrow down our range.
(3) Get 72000/129000 = 24/43. 24/43 is a little above 24/48 = 1/2. Thus, our answer is just a little above 35.
Answer: D
Answer: (D) 35.6%
Question: Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to place at a distance of 105 km and comes back to the starting point. The total time taken by him is:
(A) 12 hours
(B) 24 hours
(C) 36 hours
(D) 48 hours
(E) None
Rationale: Sol.
Speed upstream = 7.5 kmph; Speed downstream = 10.5 kmph.
∴ total time taken = [105/7.5 + 105/10.5] hours = 24 hours.
Answer B
Answer: (B) 24 hours
Question: The parameter of a square is equal to the perimeter of a rectangle of length 14 cm and breadth 10 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)?
(A) 23.56
(B) 23.59
(C) 23.55
(D) 18.86
(E) 23.57
Rationale: Let the side of the square be a cm.
Parameter of the rectangle = 2(14 + 10) = 48 cm Parameter of the square = 48 cm
i.e. 4a = 48
A = 12
Diameter of the semicircle = 12cm
Circimference of the semicircle
= 1/2(âˆ)(12)
= 1/2(22/7)(12) = 264/14 = 18.86 cm to two decimal places
Answer: D
Answer: (D) 18.86
Question: In a lottery, there are 10 prizes and 25 blanks . A lottery is drawn at random .What is the probability of getting a prize?
(A) 1/10
(B) 2/5
(C) 2/7
(D) 5/7
(E) 10/7
Rationale: Total number of prizes and blanks= 10+25= 35
no.of prize in a lottery= 10
probability of one lottery is drawn = 10/35= 2/7
Answer is C
Answer: (C) 2/7
Question: There are some pigeons and hares in a zoo. If heads are counted, there are 200. If legs are counted, there are 580. The number of hares in the zoo is?
(A) 90
(B) 99
(C) 77
(D) 66
(E) 221
Rationale: 200*2 = 400
580
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180
1----2
?----180 = 90
Answer:C
Answer: (C) 77
Question: Find the average of all the numbers between 6 and 34 which are divisible by 5?
(A) 10
(B) 20
(C) 25
(D) 30
(E) 15
Rationale: Average = (10+15+20+25+30) 5 = 100/5 = 20
Answer is B
Answer: (B) 20
Question: Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction K of the work will be done by Adam?
(A)  1/4
(B)  12/47
(C)  1/3
(D)  5/12
(E)  20/47
Rationale: Let the total work be 60 units. Pual does 60/3 =20 units of work per hr. abdul does 15 units per hr and adam does 12 units per hr. If all work together they do (20 + 15 + 12) units per hr = 47 units per hr. So the time taken to finish the work = 60/47 hrs.
adam will do 60/47 * 12 units of work in 60/47 hr . fraction of work adam does =work done by adam / total work
K>( 60/47 *12)/60 =12/47
Answer B
Answer: (B)  12/47
Question: A, B and C can independently complete a piece of work in 8,12 and 6 days respectively. A and B work together for 4 days and leave. How long will C take to finish the remaining work?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: A and B work together for 4 days and completed 4*(1/8 +1/12) =5/6 work.
Balance 1/6 work will be completed by C in one day.
ANSWER:A
Answer: (A) 1