mathewhe/aqua_rat huggingface dataset:
Question: In the graduating class of a certain college, 48 percent of the students are male and 52 percent are female. In this class 40 percent of the male and 20 percent of the female students are 25 years old or older. If one student in the class is randomly selected, approximately what is the probability that he or she will be less than 25 years old?
(A) 0.9
(B) 0.7
(C) 0.45
(D) 0.3
(E) 0.25
Rationale: Percent of students who are 25 years old or older is 0.4*48+0.2*52=~30, so percent of people who are less than 25 years old is 100-30=70.
Answer: B.
Answer: (B) 0.7
Question: A reduction of 30% in the price of oil enables a house wife to obtain 3kgs more for Rs.700, what is the reduced price for kg?
(A) 70
(B) 50
(C) 60
(D) 80
(E) 65
Rationale: 700*(30/100) = 210---- 3
? ---- 1 => Rs.70
Answer:A
Answer: (A) 70
Question: City X has a population 7 times as great as the population of City Y, which has a population twice as great as the population of City Z. What is the ratio of the population of City X to the population of City Z?
(A) 1:8
(B) 1:4
(C) 2:1
(D) 14:1
(E) 18:1
Rationale: x= 7y, y= 2*z
X : Y , Y : Z
7 : 1 , 2 : 1
14 : 2 , 2 : 1
So, X : Z = 14 : 1
(D)
Answer: (D) 14:1
Question: The width of a rectangular hall is ½ of its length. If the area of the hall is 288 sq.m, what is the difference between its length and breadth?
(A) 8m
(B) 10m
(C) 12m
(D) 15m
(E) 17m
Rationale: Let the length of the hall be x m
Breadth of the hall = 1x/2 m
Area of the hall = Length * Breadth
288 = x * 1x/2
x² = 576
x =24
Difference between the length and breadth of the hall = x - 1x/2 = x/2
=24/2 = 12m
ANSWER:C
Answer: (C) 12m
Question: The average number of shirts with Salman, Ambani and Dalmiya is 60, if all of them reached a shopping mall in Delhi and purchased 2 shirts each of them then average number of shirt each of them now has
(A) 66
(B) 63
(C) 62
(D) 64
(E) 61
Rationale: Required average
= Old average + New average
= 60 + 2 = 62
answer :C
Answer: (C) 62
Question: If 5% more is gained by selling an article for Rs. 1000 than by selling it for Rs. 20, the cost of the article is?
(A) 127
(B) 1600
(C) 1200
(D) 1680
(E) 1800
Rationale: Let C.P. be Rs. x.
Then, 5% of x = 1000 - 20= 80
x/20 = 80 => x = 1600
Answer: B
Answer: (B) 1600
Question: Of the 800 employees of Company X, 80 percent have been with the company for at least ten years. If y of theselong-termmembers were to retire and no other employee changes were to occur, what value of y would reduce the percent oflong-termemployees in the company to 60 percent ?
(A) 200
(B) 160
(C) 400
(D) 80
(E) 56
Rationale: Original (Long-Term is 70%)
Total = 800
Long-Term = .8(800) = 640
New (Long-Term is 60%)
New Total = 800 - y
New Long-Term = 640 - y
640 - y = .6 (800 - y)
y = 400
Answer: C
Answer: (C) 400
Question: The ratio of the prices of three articles X, Y and Z is 8 : 5 : 3. If the prices of X , Y and Z are increased by 25%, 20% and 33 1/3% respectively, then what would be the ratio of the new prices of X, Y and Z?
(A) 5 : 3 : 1
(B) 5 : 3 : 2
(C) 10 : 7 : 4
(D) 10 : 8 : 5
(E) None of these
Rationale: Let the prices of X, Y and Z be 8k, 5k and 3k respectively.
After increase
Price of X = 8k * 125/100 = 10k
Price of Y = 5k * 120/100 = 6k
Price of Z = 3k * (133 1/3)/100 = 4k
Required ratio = 10k : 6k : 4k = 5 : 3 : 2.
ANSWER:B
Answer: (B) 5 : 3 : 2
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?
(A) 9 min
(B) 3 min
(C) 5 min
(D) 8 min
(E) 10 min
Rationale: 1/10 + 1/15 - 1/x = 1/18
x = 9
ANSWER A
Answer: (A) 9 min
Question: Ram professes to sell his goods at the cost price but he made use of 900 grms instead of a kg, what is the gain percent?
(A) 11 1/7%
(B) 11 1/8%
(C) 11 1/9%
(D) 11 9/9%
(E) 14 1/9%
Rationale: 900 --- 100
100 --- ? => 11 1/9%
Answer: C
Answer: (C) 11 1/9%
Question: A man whose speed is 6.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 2.5 kmph, find his average speed for the total journey ?
(A) 1 kmph
(B) 5 kmph
(C) 5.5 kmph
(D) 4 kmph
(E) 7 kmph
Rationale: Explanation:
Speed of Man = 6.5 kmph
Speed of stream = 2.5 kmph
Speed in DownStream = 9 kmph
Speed in UpStream = 4 kmph
Average Speed = (2 x 9 x 4)/13 = 5.5 kmph.
Answer: C
Answer: (C) 5.5 kmph
Question: The avg weight of A,B & C is 84 kg. If D joins the group, the avg weight of the group becomes 80 kg.If another man E who weights is 6 kg more than D Replaces A, Then the avgof B,C,D&E becomes 79 kg. What is the weight of A?
(A) 25
(B) 35
(C) 75
(D) 78
(E) 90
Rationale: A + B + C = 3 *84 = 252
A + B + C + D = 4 * 80 = 320 ---- (i)
So, D = 68& E = 68 +6 = 74
B + C + D +E = 79 * 4 = 316 --- (ii)
From Eq. (i) & (ii)
A-E = 320 â€“ 316 = 4
A = E +4 = 74 + 4 = 78
D
Answer: (D) 78
Question: The average of 1st 3 of 4 numbers is 16 and of the last 3 are 15. If the sum of the first and the last number is 19. What is the last numbers?
(A) 2
(B) 4
(C) 6
(D) 8
(E) 7
Rationale: A + B + C = 48
B + C + D = 45
A + D = 19
A – D = 3
A + D = 19
2D = 16
D = 8
ANSWER D
Answer: (D) 8
Question: If 30 men take 15 days to to complete a job, in how many days can 25 men finish that work?
(A) 18
(B) 17
(C) 16
(D) 15
(E) 14
Rationale: Ans. 18 days
Answer: (A) 18
Question: If 5400 mn = k^4, where m, n, and k are positive integers, what is the least possible value of m + 2n?
(A) 11
(B) 18
(C) 20
(D) 25
(E) 40
Rationale: k^4=5400∗mn
k^4=3^3.2^3.5^2.mn
In order to make RHS a perfect power of 4, we require it to be multiplied by 3, 2 & 5^2
mn=3.2.5^2
mn = 150 = 10 * 15 (Least possible)
Answer = 10 + 15*2 = 40
ANSWER:E
Answer: (E) 40
Question: Four years back, a father was 32 years older than his son. At present the father is 3 times as old as the son. How old will the son be three years from now?
(A) 16 years
(B) 17 years
(C) 18 years
(D) 19 years
(E) 20 years
Rationale: Using linear equations to convert the word problem:
** F = fathers current ageS = sons current age
#1 Four years back, a father was 32 years older than his son: F-4 = 32 + (S - 4)
#2 At present the father is 3 times as old as the son: F = 3*S
How old will the son be three years from now?: S + 3 = ?
With two variables and two linear equations we are able to solve the problem:
(S*3) - 4 = 32 +S -4
2S=32
S = 16
S + 3 = 16 + 3 = 19
Answer: D
Answer: (D) 19 years
Question: Nine people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally the entire cost of the car, then the share of each of the remaining persons increased by:
(A) 7/8
(B) 1/8
(C) 1/3
(D) 1/7
(E) 1/9
Rationale: Original share of 1 person =1/9
New share of 1 person =1/8
Increase =1/8 -	1/9	=1/72
Required fraction =	(1/72)/(1/9)=1/8
Answer is B.
Answer: (B) 1/8
Question: Today is Monday. After 61 days, it will be
(A) Thursday
(B) Sunday
(C) Monday
(D) Saturday
(E) Friday
Rationale: Explanation:
61 days = 8 weeks 5 days = 5 odd days
Hence if today is Monday, After 61 days, it will be = (Monday + 5 odd days)
= Saturday
Answer: Option D
Answer: (D) Saturday
Question: A bag holds 4 red marbles and 3 green marbles. If you removed two randomly selected marbles from the bag, without replacement, what is the probability that both would be red?
(A) 4/14
(B) 1/5
(C) 3/10
(D) 2/5
(E) 1/2
Rationale: Given: 4R and 3 G marbles
Required: Probability that 2 marbles removed without replacement are both red
Initially we have to pick one red from a total of 4 red and 3 green marbles
After one red has been picked, we need to pick 1 red from a total of 3 red and 3 green marbles.
P(Both red) = (4/7)*(3/6) = 4/14
Option A
Answer: (A) 4/14
Question: If y = x^2 + rx + s, y is minimum when x is:
(A) r/s
(B) -r/s
(C) -r/2
(D) -s/2
(E) s/r
Rationale: We're given the equation Y = X^2 + rX + s.
IF.. we use a simple Classic Quadratic....
r = 2
s = 1
Y = X^2 + 2X + 1
We can then go about finding the answer that yields the MINIMUM result when X = ...
Answer A: r/s = 2/1 = 2 --> 4+4+1 = +9
Answer B: -r/s = -2/1 = -2 --> 4-4+1 = +1
Answer C: -r/2 = -2/2 = -1 --> 1-2+1 = 0
Answer D: -s/2 = -1/2 -->(1/4)-1+1 = +1/4
Answer E: s/r = 1/2 --> (1/4)+1+1 = +2 1/4
From these results, we can see the minimum result:
C
Answer: (C) -r/2
Question: For dinner at a restaurant, there are x choices of appetizers, y main courses, and z+ 1 choices of dessert. How many total possible choices are there if you choose 1 appetizer, 1 main course, and 1 dessert for your meal?
(A) x + y + z + 1
(B) xyz + xy
(C) xy + z + 1
(D) xyz + 1
(E) xyz + 1/2
Rationale: x appetizers,
y main courses,
z+ 1 dessert
Required: 1 appetizer, 1 main course, and 1 dessert
Number of ways possible = xC1*(z+1)C1*yC1 {NC1 = N! / (N-1)!*1! = N}
Hence, number of ways = x(z+1)y = xyz + xy
Correct Option: B
Answer: (B) xyz + xy
Question: There are 14 stamps from which two stamps will be selected. We have five stamps which are the same as five of the stamps which could be selected. What is the probability that the two stamps selected will be different from the stamps that we have?
(A) 36/91
(B) 30/83
(C) 25/71
(D) 15/61
(E) 5/31
Rationale: P(first stamp is different) = 9/14
P(second stamp is different) = 8/13
P(both stamps are different) = 9/14*8/13 = 72/182 = 36/91
The answer is A.
Answer: (A) 36/91
Question: A certain NYC taxi driver has decided to start charging a rate of r cents per person per mile. How much, in dollars, would it cost 8 people to travel x miles if he decides to give them a 50% discount?
(A) 3xr/2
(B) 3x/200r
(C) 3r/200x
(D) xr/25
(E) xr/600
Rationale: 8xr/2 is in cents - 8xr/200 dollars = xr/25
Answer : D
Answer: (D) xr/25
Question: A customer purchased a package of ground beef at a cost of $1.80 per pound. For the same amount of money, the customer could have purchased a piece of steak that weighed 25 percent less than the package of ground beef. What was the cost per pound of the steak?
(A) $2.00
(B) $2.15
(C) $2.30
(D) $2.40
(E) $2.65
Rationale: For simplicity, let's assume the customer bought 1 pound of ground beef for $1.80.
Let x be the price per pound for the steak.
Then 0.75x = 180
x = 180/0.75 = $2.40
The answer is D.
Answer: (D) $2.40
Question: if x:y = 1:4, then find the value of
(7x+3y):(2x+y)
(A) 14:5
(B) 15:5
(C) 16:5
(D) 19:6
(E) None of these
Rationale: Explanation:
let x = 1k and y = 4k, so
=7(k)+3(4k)/ 2(k)+1(4k)
=19k/6k
=19:6
Option D
Answer: (D) 19:6
Question: The NASDAQ index has decreased by 70% since year 2000. How much should the index increase in order to gain the same value as in year 2000 ?
(A) 400%
(B) 80%
(C) 233%
(D) 60%
(E) None of the above
Rationale: Let x be the index in the year 2000. After the decrease it becomes 0.3x
Now for 0.3x to reach 1x it has to raise by 0.7x. The increase needs to be 0.7x/0.3x*100=233.3%
Answer C
Answer: (C) 233%
Question: If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 70, then the average marks of all the students is:
(A) 53.33
(B) 54.68
(C) 57.5
(D) 56
(E) None of these
Rationale: Explanation:
Required average = (55 × 50 + 60 × 55 + 45 × 70/55 + 60 + 45)
= (2750 + 3300 + 3150/160)
= 9200/160
= 57.5
Answer: C
Answer: (C) 57.5
Question: If f(x)=x^2 and x is a positive integer, which of the following CAN be the value of f(f(x))?
(A) 25
(B) 17
(C) 81
(D) 144
(E) 258
Rationale: f(x)=x^2
f(f(x)) = (x^2)^2
f(f(3) = (3^2)^2 = 81
Answer C
Answer: (C) 81
Question: A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 2, 4 and 3, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created?
(A) 20
(B) 26
(C) 24
(D) 22
(E) 30
Rationale: Total # of codes possible is 3*3*3 = 27. Oit of those 27 codes only the product of 333 will be odd, the remaining 26 will have either 2 or 4 in them, which ensures that their product will be even. Therefore the number of codes where the product of the digits is even = (total) - (restriction) = 27 - 1 = 26.
Answer: B
Answer: (B) 26
Question: How many 6-digits number are Palindromic numbers? A Palindromic number reads the same forward and backward, example
(A) 100
(B) 610
(C) 729
(D) 900
(E) 1000
Rationale: The hundred-thousand's digit won't be zero or else it's no longer a 6 digit integer (you could form a palindromic number with five digits though). The subesquent two digits, ten-thousand's and thousand's digit, can be 10 different numbers each, zero - nine. Thus,
9∗10∗10∗1∗1∗1=9009∗10∗10∗1∗1∗1=900 Answer D
Answer: (D) 900
Question: if r is radius of a circle and perimeter of circle is 12π.calculate r+2r-(r/2).
(A) 15
(B) 10
(C) 12
(D) 6
(E) 18
Rationale: perimeter of circle=2πr.
2πr=12π,r=6
r+2r-(r/2)
6+2*6-(6/2)
6+2*6-3
6+12-3
18-3=15
answer A
Answer: (A) 15
Question: A train crosses a platform of 150 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
(A) 150
(B) 882
(C) 277
(D) 288
(E) 271
Rationale: Length of the train be ‘X’
X + 150/15 = X + 250/20
4X + 600 = 3X + 750
X = 150m
Answer: A
Answer: (A) 150
Question: A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 125, the runs scored by B are?
A. 15 B. 18
(A) 22
(B) 18
(C) 30
(D) 77
(E) 24
Rationale: A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
6/25 * 125 = 30
Answer: C
Answer: (C) 30
Question: The average age of a husband and a wife is 23 years when they were married five years ago but now the average age of the husband, wife and child is 22 years(the child was born during the interval). What is the present age of the child?
(A) 7 years
(B) 9 years
(C) 10 years
(D) 4 years
(E) 5 years
Rationale: 28 * 2 = 56
22 * 3 = 66
-----------
10 years
Answer: C
Answer: (C) 10 years
Question: The tax on a commodity is diminished by 20% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it?
(A) 12%
(B) 14%
(C) 16%
(D) 20%
(E) 22%
Rationale: Explanation:
100 * 100 = 10000
80 * 110 = 8800
10000------- 1200
100 ------- ? = 12%
A)
Answer: (A) 12%
Question: If the price of a certain bond on May 1st was 1/4 the price of the bond on June 1st and the price of the bond on July 1st was 25% greater than the price of the bond on May 1st. then the price of the bond on June 1st st was what percent of the average (arithmetic mean) price of the bond on May 1st and July 1st?
(A) 100%
(B) 150%
(C) 155%
(D) 300%
(E) 355%
Rationale: The price on June 1st = 12 (assume);
The price on May 1st = 1/4*12 = 3;
The price on July 1st = 3*1.25 = 3.75.
The average price of the bond on May 1st and July 1st = (3+3.75)/2 = 3.375.
The price of the bond on June 1st (12) is 32/9 times (355.55%) the average price of the bond on May 1st and July 1st.
Answer: E.
Answer: (E) 355%
Question: In a charity show, tickets numbered consecutively from 101 through 350 are placed in a box. What is the probability that a ticket selected at random (blindly) will have a number with a hundredth digit of 2?
(A) 0.285
(B) 2/5
(C) 99/225
(D) 47/205
(E) 3/5
Rationale: Let S be the numbers between 101 and 350, i.e., n(S) = 250
Let E be the event when hundredth digit is 2.
n(E) = 100th digits of 2 = 299 − 199 = 100
P(E) = n(E)/n(S) = 100/250 = 2/5
ANSWER:B
Answer: (B) 2/5
Question: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 130 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
(A)  280
(B)  400
(C)  540
(D)  650
(E)  840
Rationale: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month:
2/3*3/4 = 1/2 survived the first month.
Of the geese that survived the first month, 3/5 did not survive the first year:
(1-3/5)*1/2 = 1/5 survived the first year.
130 geese survived the first year:
1/5*(total) = 130 --> (total) = 650.
Answer: D.
Answer: (D)  650
Question: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one girl is included?
(A) 145
(B) 170
(C) 195
(D) 220
(E) 245
Rationale: The total number of ways to choose 4 children is 10C4 = 210
The number of ways to choose only boys is 6C4 = 15
The number of groups which include at least one girl is 195.
The answer is C.
Answer: (C) 195
Question: The banker's discount on Rs.1800 at 48% per annum is equal to the true discount on Rs.1872 for the same time at the same rate. Find the time?
(A) 1 months
(B) 4 months
(C) 5 months
(D) 6 months
(E) 7 months
Rationale: Solution
S.I on Rs.1800 = T.D on Rs.1872.
P.W on Rs.1872 is Rs.1800.
Rs.72 is S.I on Rs. 1800 at 48%.
Time	=(100x72 / 48x1800)
= 1/12 year
= 1 months.
Answer A
Answer: (A) 1 months
Question: If the cost price of 17 articles is same as the selling price of 25 articles. Find the gain or loss percentage?
(A) 30% Gain
(B) 30% Loss
(C) 32% Loss
(D) 40% Loss
(E) 50% Loss
Rationale: Explanation:
17 cp = 25 sp
Cost price CP = 25
Selling price SP = 17
Formula = (SP-CP)/CP * 100 = (17 - 25)/25 * 100 = 32 % Loss
Answer: Option C
Answer: (C) 32% Loss
Question: A pool which was 2/3 full to begin with, was filled at a constant rate for 3/4 hours until it was until it was 3/4 full. At this rate, how much time would it take to completely fill this pool if it was empty to begin with?
(A) 8 hrs 45 mins.
(B) 9 hrs.
(C) 9 hrs 30 mins.
(D) 11 hrs 40 mins.
(E) 15 hrs 30 mins
Rationale: The pool was 2/3 full initially.
In 3/4 hrs, it was filled to 3/4 of its capacity.
Therefore, in 3/4 hrs, 3/4- 2/3 was the amount of volume filled.
So, 3/4 hrs = 3/4 - 2/3 = 1/12
Therefore, for filling the vessel from empty to full, you would require 3/4 * 12/1 = 9 Hrs .
Hence B
Answer: (B) 9 hrs.
Question: The perimeter of a square and a rectangle is the same. If the rectangle is 12 cms. by 10 cms., then by what percentage is the area of the square more than that of the rectangle?
(A) 1
(B) 3
(C) 5/6
(D) 1/2
(E) 1/3
Rationale: perimeter of rectangle=2*(12+10)=44=perimeter of square
so side of square=44/4=11
area of rectangle=12*10=120
area of square=11*11=121
reqd%=(121-120)/120 *100=100/120=5/6
ANSWER:C
Answer: (C) 5/6
Question: Alice can bake a pie in 5 minutes. Bob can bake a pie in 6 minutes. Compute how many more
pies Alice can bake than Bob in 60 minutes.
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: Alice can bake 60/5 = 12 pies in 60 minutes. Bob can bake 60/6 = 10 pies in 60 minutes.
Alice can therefore bake 12 - 10 = 2 more pies than Bob.
correct answer B
Answer: (B) 2
Question: If Q + A < Q - A < A - Q, which of the following is correct?
(A) A < Q < 0.
(B) Q < A < 0.
(C) Q < 0 < A.
(D) 0 < B < A.
(E) B > A > 0.
Rationale: Check first inequality
Q + A < Q - A
A<-A
A is -ve
Check another equality
Q - A < A - Q
-2A<-2Q
A>Q
Combining both 0>A>Q
Option B fits only
Ans B
Answer: (B) Q < A < 0.
Question: The captain of a cricket team of 11 members is 27 years old and the wicket keeper is 1 year older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
(A) 20
(B) 21
(C) 22
(D) 23
(E) 24
Rationale: Let the average age of the whole team be x years.
11x - (27 + 28) = 9 (x - 1)
11x - 9x = 46
2x = 46
x = 23.
The average age of the team is 23 years.
The answer is D.
Answer: (D) 23
Question: Some of the 50% solution of acid was removed and this was replaced with an equal amount of 20% solution of acid. As a result, a 35% solution of acid was obtained. What fraction of the original solution was replaced?
(A) 1/3
(B) 1/2
(C) 2/3
(D) 3/5
(E) 4/7
Rationale: Let x be the fraction of the original solution that was replaced.
0.5*(1-x)+0.2(x)=0.35
0.3x=0.15
x=1/2
The answer is B.
Answer: (B) 1/2
Question: The area of a rectangle is 144 sq cm. Ratio of the breadth and the length of a rectangle 4:9.Find the area of the square whose side is equal to the length of the triangle?
(A) 525
(B) 225
(C) 400
(D) 625
(E) 324
Rationale: Let the length and the breadth of the rectangle be l = 9x cm and b = 2x cm respectively. Let the side of the square be a cm.
4x*9x = 144
36x^2 = 144
x^2 = 4
x = 2
l = 9*2 = 18
area of the square = 18^2 = 324
Answer: E
Answer: (E) 324
Question: How many ways are there to award a gold, silver and bronze medal to 8 contending teams?
(A) 10 × 9 × 8
(B) 8 * 7 * 6
(C) 8!/3!
(D) 876
(E) 758
Rationale: we clearly know that there can be only one winning team which deserves the gold medal. we can do the selection in 8 ways
if gold medal is given to 1 of the teams then only possible 7 teams can be considered for silver medal. we can do selection in 7 ways
similarly if gold and silver medals are awarded then only remaining 6 teams can be considered for a bronze medal. we can do the selection in 6 ways
Total number of ways to select the 3 possible medal winners = 8 * 7 * 6
Correct answer - B
Answer: (B) 8 * 7 * 6
Question: Ajay can ride 50km in 1 hour. In how many hours he can ride 1000km?
(A) 10hrs
(B) 15hrs
(C) 20hrs
(D) 25hrs
(E) 18hrs
Rationale: 1 hour he ride 50km
he ride 1000km in = 1000/50 * 1 = 20hours
Answer is C
Answer: (C) 20hrs
Question: The length of the bridge, which a train 145 m long and traveling at 45 km/hr can cross in 30 sec is?
(A) 230
(B) 240
(C) 245
(D) 250
(E) 255
Rationale: Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (145 + x)/30 = 25/2
x = 230 m.
Answer: Option A
Answer: (A) 230
Question: At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years?
(A) 6
(B) 6.5
(C) 7
(D) 7.5
(E) 8
Rationale: Let the rate be R% p.a. Then, 1200 x (1 + R/100)*(1 + R/100) = 1348.32 (1 + R/100)*(1 + R/100) = 134832/120000 = 11236/10000 (1 + R/100)*(1 + R/100) = (106/100)*(106/100) 1 + R/100 = 106/100 R = 6%
Answer A
Answer: (A) 6
Question: What is the sum of two consecutive even numbers, the difference of whose squares is 84?
(A) 42
(B) 84
(C) 48
(D) 24
(E) 43
Rationale: Let the numbers be x and x + 2.
Then, (x + 2)2 - x2 = 84
4x + 4 = 84
4x = 80
x = 20.
The required sum = x + (x + 2) = 2x + 2 = 42.
ANSWER A 42
Answer: (A) 42
Question: The engineers subjected the engine to exhaustive tests.
(A) Complicated
(B) Thorough
(C) Exclusive
(D) Compulsory
(E) Compulsory2
Rationale: Exhaustive means thorough, complete or in-depth. Hence, option-b is synonym of exhaustive.
Answer:A
Answer: (A) Complicated
Question: Quentin's income is 60% less than Sid's income, and Sam's income is 25% less than Quentin's income. If Sid gave 60% of his income to Sam and 40% of his income to Quentin, Quentin's new income would be what fraction of Sam's new income?
(A) 8/9
(B) 11/12
(C) 8/13
(D) 11/13
(E) 12/13
Rationale: We can take some easy numbers and make calculations simpler.
Let R ( Sid's income) = 100
Q (Quentin's income) = 40%R = 40
S (Sam's income) = 75% Q = (3/4)*40 = 30
Now, if Sid gives 40% to Quentin --> Q = 40 + 40 = 80
60% given to Sam --> S = 30+60 = 90
The ratio is : Q/S = 80/90 = 8/9=A
Answer: (A) 8/9
Question: If there are 30 cans out of them one is poisoned. If a person tastes very little he will die within 14 hours. So if there are mice to test in 24 hours, how many mice’s are required to find the poisoned can?
(A) 5
(B) 4
(C) 1
(D) 2
(E) 3
Rationale: first we drink one cane to every rat...
after one hour again drink one cane to every rat...
and so on till 10 hour... In 10 hour every rat drink 10 cans so all rat drink 30 cans...
if A OR B OR C died from poison in 14th hour so they died from 1st cane OR 2nd cane OR 3rd cane respectively
if died in 15th hour they died from 4th,5th,6th cans respectively....so on
In 24th hour they died from 28th,29th,30th cans respectively...
so we can determine which cane is poisoned..
ANSWER:E
Answer: (E) 3