mathewhe/aqua_rat huggingface dataset:
Question: Josh went on a bicycle ride and travelled along with wind covering a mile in just 3 minutes. On the other hand while returning back, he was riding against the wind and it took him 4 minutes to travel the same distance.
Calculate the time he will take to ride a mile if there was no wind acting upon his ride?
(A) 3 minute and 25 (5/7) seconds.
(B) 2 minute and 25 (5/7) seconds.
(C) 1 minute and 25 (5/7) seconds.
(D) 5 minute and 25 (5/7) seconds.
(E) 6 minute and 25 (5/7) seconds.
Rationale: Solution:
3 minute and 25 (5/7) seconds.
Explanation:
What you may possibly do is add 3 and 4 minutes and take up the sum of 7 as an average to proceed further. However that is totally wrong as the wind has only supported Josh for 3 minutes while it has acted adversely for 4 minutes.
Thus first we must calculate the distance if he would have travelled for equal time along with wind i.e. 4 minutes. Clearly he would have travelled a mile and 1/3 of a mile in 4 minutes. Now adding the total distance in eight minutes i.e. 2 and 1/3 mile we can get his actual speed and time.
Thus the actual time for a single mile will be 3 minute and 25 (5/7) seconds.
Answer A
Answer: (A) 3 minute and 25 (5/7) seconds.
Question: he ratio between the sale price and the cost price of an article is 5:3. What is the ratio between the profit and the cost price of that article?
(A) 2:6
(B) 2:9
(C) 2:4
(D) 5:2
(E) 2:5
Rationale: Let C.P. = Rs. 3x and S.P. = Rs. 5x.
Then, Gain = Rs. 2x
Required ratio = 5x : 2x = 5:2
Answer:D
Answer: (D) 5:2
Question: The price of a certain product increased by the same percent from 1960 to 1970 as from 1970 to 1980. If its price of $1.60 in 1970 was 150 percent of its price in 1960, what was its price in 1980?
(A) a) $ 1.80
(B) b) $ 2.00
(C) c) $ 2.40
(D) d) $ 2.70
(E) e) $ 3.00
Rationale: The price in 1970 was 150 percent of its price in 1960, means that the percent increase was 50% from 1960 to 1970 (and from 1970 to 1980).
Therefore the price in 1980 = $1.6*1.5 = $2.4.
Answer: C.
Answer: (C) c) $ 2.40
Question: An equilateral triangle and three squares are combined as shown above, forming a shape of area 48+4√3. What is the perimeter of the shape formed by the triangle and squares?
(A) 18
(B) 27
(C) 36
(D) 48
(E) 64
Rationale: triangle area = root(3)s^2/4
area of 3 squares together = 3 s^2
root(3)s^2/4 + 3 s^2 = 48 +4root(3)
root(3)/4s^2 = 4root(3)
s^2 = 16 => s = 4
there are 3 sides of each square = 3(4)(3) = 36
Option C
Answer: (C) 36
Question: There are 15 balls in a jar: 6 red, 7 blue and 2 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?
(A) 1/12
(B) 1/4
(C) 11/15
(D) 13/15
(E) 3/4
Rationale: Blue + Red =13
Total number of balls is 6+7+2=15
So the answer is 13/15=13/15
Answer D
Answer: (D) 13/15
Question: A man buys two articles for Rs.1980 each and he gains 10% on the first and loses 10% on the next. Find his total gain or loss percent?
(A) 15
(B) 67
(C) 18
(D) 19
(E) 12
Rationale: 90 * 10/60 = 15 kmph
Answer: A
Answer: (A) 15
Question: A security guard at a certain store is instructed to check the receipt of one out of every five customers as they are leaving the store. If, on the guard's shift, 12 customers leave the store, how many different samples of customers could have been selected to have their receipts checked?
(A) 20
(B) 66
(C) 59
(D) 90
(E) 100
Rationale: to choose the sample of 2 customers from 12. it can be done 12C2 possible ways.
So the answer is B. 66
Answer: (B) 66
Question: A and B enter into a partnership with respective capitals of Rs. 20,000 and Rs. 40,000. At the end of the year, the total profit is Rs. 33,000. If A receives Rs. 15,000 as both his salary and profit, then what is his salary?
(A) Rs. 2000
(B) Rs. 4000
(C) Rs. 3500
(D) Rs. 3000
(E) None of these
Rationale: Explanation:
A's capital : B 's capital
20000 : 40000 = 1 : 2
Since, the time period is fixed, the profit is distributed in the ratio of capital 1 : 2
Profit of A = (1/3) * 33,000 = Rs. 11,000
Salary of A = Rs. (15000 – 11000) = Rs. 4000
ANSWER: B
Answer: (B) Rs. 4000
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8339 for a computer table, then what was the cost price of the computer table?
(A) 3888
(B) 26679
(C) 277
(D) 6725
(E) 342
Rationale: CP = SP * (100/(100 + profit%))
= 8339(100/124) = Rs. 6725.
Answer:D
Answer: (D) 6725
Question: A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 6 litres a minute. When the tank is full, the inlet is opened and due to the leak, the tank is empty in 12 hours. How many litres does the cistern hold?
(A) 7580
(B) 7960
(C) 8290
(D) 4320
(E) None
Rationale: Solution
Work done by the inlet in 1 hour	= (1/6 - 1/12)
= 1/12.
Work done by the inlet in 1 min.	= (1/12 × 1/60)
= 0.001389
Volume of 0.001389 part = 6 litres.
Therefore, Volume of whole= 1/0.001389 x 6
‹=› 4320 litres.
Answer D
Answer: (D) 4320
Question: A mixture of certain quantity of milk with 16 liters of water is worth 90 P per liter. If pure milk be worth Rs1.08 per liter, how proportion milk is there in the mixture?
(A) 5/2
(B) 5/1
(C) 5/7
(D) 3/5
(E) 1/2
Rationale: The mean value is 90 P and price of water is 0 P
By the alligation rule : Quantity of milk / Quantity of water
= (90 - 0) / (108 - 90)
= 90 / 18
= 5/1
proportion milk is 5/1 there in the mixture
B
Answer: (B) 5/1
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
(A) 5.79
(B) 5.28
(C) 5.76
(D) 32.9
(E) 5.73
Rationale: M = 6
S = 1.2
DS = 7.2
US = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
D = 2.88 * 2 = 5.76
Answer:C
Answer: (C) 5.76
Question: If the average of 5x and 8y is greater than 90, and x is twice y, what is the least integer value of x ?
(A) 4
(B) 5
(C) 20
(D) 21
(E) 23
Rationale: If y is greater than 110 percent of x, is y greater than 75?
(1)x>75x>75
(2) y−x=10y−x=10
Pls verify.
1) Sufficient.
y > 1.1 x and x > 75. Min(x) = 75
y > 1.1 * 75
y > 82.5
2) Insufficient. Substituting (x=y-10) in y > 1.1x
y > 1.1(y-10)
y < 110
Hence A.
Answer: (A) 4
Question: Sum of the squares of three numbers is 138 and the sum of their products taken two at a time is 131. Find the sum?
(A) 20
(B) 21
(C) 24
(D) 26
(E) 28
Rationale: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 138 + 2* 131
a + b + c = √400 = 20
A
Answer: (A) 20
Question: A certain bacteria colony doubles in size every day for 11 days, a which point it reaches the limit of its habitat and can no longer grow. If two bacteria colonies start growing simultaneously, how many days will it take them to reach the habitat’s limit?
(A) 6.33 
(B) 7.5 
(C) 10 
(D) 15 
(E) 19 
Rationale: Case 1: Consider the bacteria num to be B. As it doubles every day, number of bacteria at the end of each day would be
Day 1 – B
Day 2 – 2B
Day 3 – 4B
Day 4 – 8B
.
.
.
Day 11 – 2^19 B
It can be implied that the capacity of the habitat is 2^19 B.
Case 2: There are 2 bacteria which keep doubling every day. So, the count would be
Day 1 – 2B
Day 2 – 4B
Day 3 – 8B
.
.
.
Day 18 – 2^18 B
Day 19 – 2^19 B --> this is the point where the habitat is filled to its capacity.
Hence, 10 is the answer
C
Answer: (C) 10
Question: The average of five numbers is 27. If one number is excluded, the average becomes 24. The excluded number is?
(A) 36
(B) 37
(C) 38
(D) 39
(E) 40
Rationale: Excluded number = (27 * 5) - (24 * 4)
= 135 - 96
= 39.
Answer: D
Answer: (D) 39
Question: If rupee one produces rupees nine over a period of 40 years, find the rate of simple interest?
(A) 22 1/7%
(B) 22 7/2%
(C) 29 1/2%
(D) 22 1/2%
(E) 22 1/3%
Rationale: 9 = (1*40*R)/100
R = 22 1/2 %
Answer: D
Answer: (D) 22 1/2%
Question: Jim takes a seconds to swim S meters at a constant rate from point P to point Q in a pool. Roger, who is faster than Jim, can swim the same distance in b seconds at a constant rate. If Jim leaves point P the same time that Roger leaves point Q, how many fewer meters will Jim have swum than Roger when the two swimmers pass each other?
(A) c(b-a)/ a+b
(B) c(a-b)/a+b
(C) S(a-b)/(a+b)
(D) ab(a-b)/a+b
(E) ab(b-a)/a+b
Rationale: Both JimRoger are travelling at constant speedin opposite direction:
So, speed of Jim = S/a speed of Roger = S/b
Let say Jim travelled distance x from P where it met Roger, it means that Roger travelled (S-x) from point Q
[x would be less than (c-x) as Jim is travelling slow]
From above, time taken by Jim to travel x = xa/S....................... (1)
Also, time taken by Roger to travel (c-x) = (S-x)b/S.....................(2)
Time taken by both JimRoger is same, so (1) = (2)
xa/S = (S-x)b/S,
Solving further, x = bS/(a+b).................... (3)
We require to find how many fewer meters will Jim have swum i.e
additional distance travelled by Roger = (S - x) - x
= S-2x
Substituting value of x from (3)solving the equation further, we get Answer = S(a-b)/a+b
Answer = (C)
Answer: (C) S(a-b)/(a+b)
Question: Insert the missing number. 34, 7, 37, 14, 40, 28, 43, (...)
(A) 31
(B) 42
(C) 46
(D) 56
(E) 68
Rationale: Explanation :
We have two series here
34, 37, 40, 43, ... (Increase by 3)
7, 14, 28, ... (Multiply by 2)
Hence, next term is 28 × 2 = 56
Answer : Option D
Answer: (D) 56
Question: Find the average of all the numbers between 6 and 34 which is divisible by 5
(A) 15
(B) 18
(C) 13
(D) 19
(E) 20
Rationale: avg = (10+15+20+25+30)/5 = 100/5 => 20
ANSWER E
Answer: (E) 20
Question: Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 37 kmph. Of how many minutes does the train stop per hour?
(A) 73
(B) 83
(C) 12
(D) 83
(E) 11
Rationale: Explanation:
T = 8/45 * 60 = 11
Answer: Option E
Answer: (E) 11
Question: Without stoppages, a train travels certain distance with an average speed of 300 km/h, and with stoppages, it covers the same distance with an average speed of 200 km/h. How many minutes per hour the train stops ?
(A) 20
(B) 21
(C) 22
(D) 23
(E) 24
Rationale: Due to stoppages, it covers 100 km less .
Time taken to cover 100 km = 100â„300h = 1â„3h
= 1â„3 Ã— 60 min = 20 min
Answer A
Answer: (A) 20
Question: If a sum of Rs.17,100 is divided between, A and B in the ratio 4:5, how much amount would A get ?
(A) 9500
(B) 6700
(C) 7600
(D) 7900
(E) 9700
Rationale: A = 17100 × 4 / 9 = Rs.7600
B = 17100 × 5 /9 = Rs.9500
Option A
Answer: (A) 9500
Question: The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is
(A) 12
(B) 16
(C) 24
(D) 48
(E) 50
Rationale: Solution
Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers are 12 and 16.
L.C.M. of 12 and 16 = 48.
Answer D
Answer: (D) 48
Question: In expressing a length of 81.472 km as nearly as possible with the three significant digits, find the
percentage error
(A) 0.35%
(B) 0.34%
(C) 0.034%
(D) 0.035%
(E) None of these
Rationale: Explanation:
Error = (81.5 - 81.472) = 0.028
Required percentage =
0.02881.472×100=0.034
Answer: Option C
Answer: (C) 0.034%
Question: A person saved $50 in buying an item on sale. If he spent $500 for the item, approximately how much percent he saved in the transaction?
(A) 8%
(B) 10%
(C) 2%
(D) 5%
(E) 1.8%
Rationale: Actual price = 500+50 = $550
Saving = 10/550 * 100 = 100/55 = 1.8% approximately
Answer is E
Answer: (E) 1.8%
Question: A boat having a length 8 m and breadth 2 m is floating on a lake. The boat sinks by 1cm when a man gets on it. The mass of the man is:
(A) 12 kg
(B) 60 kg
(C) 72 kg
(D) 160 kg
(E) None of these
Rationale: Explanation:
Volume of water displaced = (8 x 2 x 0.01) m3
= 0.16 m3.
∴ Mass of man = Volume of Water displaced x Density of water
= (0.16 x 1000)kg
= 160 kg.
Answer: D
Answer: (D) 160 kg
Question: The C.P of 15 books is equal to the S.P of 18 books. Find his gain% or loss%?
(A) 16 2/3% loss
(B) 11 2/3% loss
(C) 66 2/3% loss
(D) 12 2/3% loss
(E) 17 2/3% loss
Rationale: Explanation:
15 CP = 18 SP
18 --- 3 CP loss
100 --- ? => 16 2/3% loss
Answer: A
Answer: (A) 16 2/3% loss
Question: A courtyard is 21 meter long and 14 meter board is to be paved with bricks of dimensions 14 cm by 8 cm. The total number of bricks required is :
(A) 16000
(B) 18000
(C) 20000
(D) 26250
(E) None of these
Rationale: Explanation:
Number of bricks =Courtyard area /1 brick area
=(2100Ã—1400 /14Ã—8)=26250
Option D
Answer: (D) 26250
Question: Company A imported 12,000 widgets made of either brass or aluminum. The widgets are painted blue, red or green. If 10 percent of the widgets are made of brass and of those 20 percent are painted green and 40 percent are painted red how many brass widgets painted blue were imported?
(A) 420
(B) 480
(C) 1050
(D) 1680
(E) 2100
Rationale: Answer A.
We are told that 10% of all imported widgets are made of brass and of those, 20% are green and 40% are red. Since we know that there are only three colors, the remaining 40% must be blue. 40% blue of 10% brass widgets leads to 4% blue brass widgets out of the total 10,550 widgets.
12,000 /100 * 4 = 480.
Answer B.
Answer: (B) 480
Question: There is a train and car. The ratio between the speed of a train & a car is 16:15 respectively. Also, a bus covered a distance of 480 km in 8 hours. The speed of the bus is 3/4th of the speed of the train. How many kilometers will the car cover in 4 hours?
(A) 200
(B) 250
(C) 300
(D) 350
(E) 400
Rationale: The speed of the bus is 480/8 = 60 km/hr
The speed of the train is (60*4)/3 = 80 km/hr
The speed of the car is 80/16 * 15 = 75 km/hr
The distance covered by the car in 4 hours is 75 × 4 = 300 km
The answer is C.
Answer: (C) 300
Question: The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:10. If P invested the money for 20 months, find for how much time did Q invest the money?
(A) 11
(B) 40
(C) 18
(D) 16
(E) 12
Rationale: 7*5: 20*x = 7:10
x = 40
Answer:B
Answer: (B) 40
Question: Each of the 30 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and the average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the average weight of the boxes in the shipment is to be reduced to 15 pounds by removing some of the 20-pound boxes, how many 20-pound boxes must be removed?
(A) 8
(B) 12
(C) 18
(D) 20
(E) 24
Rationale: If the average of 10-pound and 20-pound boxes is 18, the ratio of 10-pound boxes:20-pound boxes is 1:4.
So out of 30 boxes, 6 are 10-pound boxes and 24 are 20-pound boxes.
If the average of 10 and 20-pound boxes is to be 15, the ratio of 10-pound boxes:20-pound boxes should be 1:1.
The number of 10 pound boxes remain the same so we still have 6 of them.
To get a ratio of 1:1, the number of 20-pound boxes must be 6.
We need to remove 18 of the 20-pound boxes.
The answer is C.
Answer: (C) 18
Question: How many arrangements of the letters of the word BEGIN can be made, without changing the place of the vowels in the word?
(A) 4
(B) 6
(C) 7
(D) 8
(E) 9
Rationale: E,I fixed. Consonants can be arrangements in 3P3 = 3! = 6 ways
Option 'B'
Answer: (B) 6
Question: The average salary of the employees in a office is Rs.120/month.The avg salary of officers is Rs.460 and of non officers is Rs 110. If the no.of officers is 15,then find the No of nonofficers in the office.
(A) 400
(B) 420
(C) 430
(D) 450
(E) 510
Rationale: Let no. of non- officers be x
15 * 460 + x * 110 = (x + 15) 120
x = 510
E
Answer: (E) 510
Question: Find the average of all numbers between 4 and 34 which are divisible by 5
(A) 20
(B) 21
(C) 25
(D) 30
(E) 55
Rationale: Explanation:
Average=(5+10+15+20+25+30) / 5=105 / 5=21
Option B
Answer: (B) 21
Question: What approximate value should come in place of the question mark (?).
36.0001 ÷ 5.9998 × √? = 108.0005
(A) 325
(B) 316
(C) 256
(D) 16
(E) 18
Rationale: Using approximation, we get 36⁄6 × √? = 108
or, √? = 108⁄6
or, √? = 18
or, ? = 324 ≈ 325
Answer E
Answer: (E) 18
Question: A merchant sells an item at a 20% discount, but still makes a gross profit of 40 percent of the cost. What percent of the cost would the gross profit on the item have been if it had been sold without the discount?
(A) 20%
(B) 40%
(C) 50%
(D) 60%
(E) 75%
Rationale: original SP = X
Cost =C
current selling price = .8x ( 20% discount)
.8x = 1.4C (40% profit)
x= 1.4/.8 *C
x= 7/4 C
Original selling price is 1.75C which is 75% profit
Answer E
Answer: (E) 75%
Question: Find large number from below question
The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder.
(A) 535
(B) 565
(C) 1234
(D) 1345
(E) 1635
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Large number = 270+1365 = 1635
E
Answer: (E) 1635
Question: Jane and Thomas are among the 7 people from which a committee of 4 people is to be selected. How many different possible committees of 4 people can be selected from these 7 people if at least one of either Jane or Thomas is to be selected?
(A) 30
(B) 45
(C) 55
(D) 65
(E) 70
Rationale: The total number of ways to choose 4 people from 7 is 7C4 = 35.
The number of committees without Jane or Thomas is 5C4 = 5.
There are 35-5 = 30 possible committees which include Jane and/or Thomas.
The answer is A.
Answer: (A) 30
Question: The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.360. Find the principal?
(A) 2277
(B) 2667
(C) 9000
(D) 2766
(E) 1811
Rationale: P = 360(100/5)^2 => P = 9000
Answer: C
Answer: (C) 9000
Question: A man took a loan from a bank at the rate of 9% p.a. simple interest.After 3 years he had to pay Rs. 5400 interest only for the period.The principal amount borrowed by him was :
(A) Rs. 2000
(B) Rs. 10,000
(C) Rs. 15,000
(D) Rs. 20,000
(E) None
Rationale: Solution
Principal = Rs.(100x5400/9x3)= Rs. 20000.
Answer D
Answer: (D) Rs. 20,000
Question: There is a train and car. The ratio between the speed of a train & a car is 16:15 respectively. Also, a bus covered a distance of 480 km in 8 hours. The speed of the bus is 3/4th of the speed of the train. How much distance will the car cover in 5 hours?
(A) 300 km
(B) 325 km
(C) 375 km
(D) 425 km
(E) 450 km
Rationale: The speed of the bus is 480/8 = 60 km/hr
The speed of the train is (60*4)/3 = 80 km/hr
The speed of the car is 80/16 * 15 = 75 km/hr
The distance covered by the car in 5 hours is 75 × 5 = 375 km
The answer is C.
Answer: (C) 375 km
Question: If (c - a)/(c - b) = 1, then (5b - 3a)/(c - a) =
(A) 0.5
(B) 1
(C) 1.5
(D) 2
(E) 2.5
Rationale: Let's say c=2, b=1, a=1 so that our 1st expression holds true. Now, ibsert those numbers in the second expression and we'll get 2
Answer D (hopefully )))
Answer: (D) 2
Question: If n is a positive integer, what is the remainder when (7^(4n+2))(6^n) is divided by 10?
(A) 1
(B) 2
(C) 4
(D) 6
(E) 8
Rationale: This one took me bout 3 1/2 min. Just testin numbers and what not.
First notice that n is positive. Save time by noticing thatI worked out one solution where n=0 only to find that thats not an option :p.
1-7 stands for ^1 thru 7
1: 7*1=7
2: 7*7=9
3: 7*9=3
4: 7*3=1
5: 7*1=7
6: 7*7=9
7: 7*9=3
Pattern repeats every @ 5. Notice every ^4 or multiple of 4 is always going to be 1. This is just for future notice for similar problems.
so 7^4n+3 ---> if n=1 then its ((7^7)*6))/10 which can say is going to be 3*8--> 18/10 --> R=8
Now from here if id double check just to make sure.
7^4(2)+3*6^2 ---> 7^11*36 or we can just say again 7^11*6 (b/c we are only interested in the units digit).
Since ^12 is going to be 1 that means ^11 is going to be 3 (as taken from our pattern)
so again 3*6=18/10 ---> R =4.
C or J in this problem.
Answer: (C) 4
Question: When m is divided by 9, the remainder is 2. When m is divided by 13, the remainder is 4. If 1 < m < 300, what is the greatest possible value of m?
(A) 210
(B) 230
(C) 250
(D) 270
(E) 290
Rationale: 13*9 = 117
Let's start with 4, and keep adding 13 until we find a number with the form 9k+2.
4, 17, 30, 43, 56 = 9*6+2
The next possible number is 56 + 117 = 173
The next possible number is 173 + 117 = 290
The next possible number would be greater than 300.
The answer is E.
Answer: (E) 290
Question: x =4 9 11
y= 64 49 9 then what is the relation between x and y
(A) 1*X)^1
(B) 1*X)^3
(C) 1*X)^2
(D) 1*X)^4
(E) 1*X)^5
Rationale: Y=(1*4)^3
64=(1*4)^3
64=64
ANSWER:B
Answer: (B) 1*X)^3
Question: The function g(h) is defined for integers h such that if h is even, g(h) = h/2 and if h is odd, g(h) = h + 5. Given that g(g(g(g(g(h))))) = 19, how many possible values for h would satisfy this equation?
(A) 1
(B) 5
(C) 7
(D) 8
(E) 11
Rationale: Let me define terms:
in g(h) = R
h is argument, R is result, g() is function,
in g(g(g(g(g(h))))), g1 is inner most, g5 is outermost for identification.
From definition of function g, we can deduce that:
If Result is even then two possibilities for argument = 1 Even 1 Odd
If Result is odd then one possibility for argument = 1 Even
Since final result = 19 = Odd
Possibilities:
g1:1 Even
g2: 1*(Even,Odd ) =1 Even 1 Odd
g3: 1*(Even,Odd) + 1 Even =2 Even 1 Odd
g4: 2*(Even, Odd) + 1 Even =3 Even 2 Odd
g5: 3*(Even, Odd) + 2 Even =5 Even 3 Odd = Total 8
Ans D it is!
Answer: (D) 8
Question: The average temperature of Tuesday Wednesday and Thursday was 37 C. The average temperature of Wednesday and Thursday and Friday was 38 C. if the temperature on Friday was 39 C.
Find the temperature on Tuesday.
(A) 22
(B) 36
(C) 88
(D) 20
(E) 27
Rationale: Tues + Wed + Thurs)/3=37
Tues + Wed + Thurs=111...(1)
(Wed + Thurs + Fri)/3=38
(Wed + Thurs + Fri) =114...(2)
Given friday is 39.
Then, (2) - (1) Fri - Tues = 3
So 39 - Tues = 3
Tuesday =36
Answer:B
Answer: (B) 36
Question: A 180m long train is running at 72 kmph.If it crossed the platform in 20 sec.then find the platform length?
(A) 220m
(B) 110m
(C) 230m
(D) 100m
(E) 90m
Rationale: Length=speed*time
Length=72km/hr*time
Length=[72*(5/18)]*20 {(ie)(x)km/hr)}
=x*(5/18)
=20*20
Length=400m
Length of platform=Length-Length of the train
Length of platform=400-180
Length of platform=220m
Option A
Answer: (A) 220m
Question: A sum of money at simple interest amounts to Rs. 835 in 3 years and to Rs. 854 in 4 years. The sum is:
(A) 647
(B) 698
(C) 778
(D) 847
(E) 976
Rationale: S.I. for 1 year = Rs. (854 - 835) = Rs. 19.
S.I. for 3 years = Rs.(19 x 3) = Rs. 57.
Principal = Rs. (835 - 57) = Rs. 778.
Answer:C
Answer: (C) 778
Question: If w is an even integer and q is an odd integer, which of the following must be an odd integer?
(A) w/q
(B) wq
(C) 2w+q
(D) 2(w+q)
(E) 3w/q
Rationale: this is a must question:
A. w/q
can be a non-integer
B. wq
always even
C. 2w+q
2w = even -> even+odd = odd
D. 2(w+q)
always even - w+q = odd *2 -> even
E. 3w/q
might be a non integer.
C
Answer: (C) 2w+q
Question: In how many ways a committee of 4 members can be selected from 7men and 6ladies, consisting of 2 men and 2 ladies?
(A) 250
(B) 315
(C) 412
(D) 256
(E) 362
Rationale: (2 men out 7) and (2 ladies out of 6) are to be chosen
Required number of ways = 7C2 * 6C2 = (7*6*6*5)/(2*1*2*1) = 315
Answer is B
Answer: (B) 315
Question: A salt manufacturing company produced a total of 5000 tonnes of salt in January of a particular year. Starting from February its production increased by 170 tonnes every month over the previous months until the end of the year. Find its average monthly production for that year?
(A) 2989
(B) 2765
(C) 5950
(D) 2989
(E) 9772
Rationale: Total production of salt by the company in that year
= 5000 + 5170 + 5340 + .... + 6870 = 71390.
Average monthly production of salt for that year
= 71390/12
= 5950.
Answer:C
Answer: (C) 5950
Question: A brick measures 20 cm * 10 cm * 7.5 cm how many bricks will be required for a wall 23 m * 2 m * 0.75 m?
(A) 22377
(B) 27782
(C) 27891
(D) 25000
(E) 23000
Rationale: 23 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x
23 = 1/100 * x => x = 23000
Answer: E
Answer: (E) 23000
Question: What is the smallest positive integer K such that the product of 3675 x K is a perfect square?
(A) 3
(B) 9
(C) 15
(D) 25
(E) 63
Rationale: A perfect square, is just an integer that can be written as the square of some other integer. For example 16=4^2, is a perfect square.
Now, 3675= 5^2 * 7^2 * 3, so if k=3 then 3675 k = (5 * 7 * 3)^2, which is a perfect square (basically the least positive value of k must complete only the power of 7 to even power as powers of other primes are already even).
Answer: A.
Answer: (A) 3