mathewhe/aqua_rat huggingface dataset:
Question: Running 3/4th of his usual rate, a man is 8min late. Find his usual time in hours ?
(A) 6/4 hrs
(B) 3/4 hrs
(C) 2/5 hrs
(D) 3/4 hrs
(E) 1/4 hrs
Rationale: Explanation:
Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time
so 1/3rd of the usual time = 8min
or usual time = 3 x 8 = 24min = 24/60 hrs = 2/5 hrs.
Answer: C
Answer: (C) 2/5 hrs
Question: A certain truck uses 18 gallons of diesel fuel in traveling 230 miles. In order for the truck to travel the same distance using 10 gallons of diesel fuel, by how many miles per gallon must the truck’s fuel mileage be increased?
(A) 8
(B) 9
(C) 12
(D) 15
(E) 27
Rationale: There are two sets 18G1 gallons and 10G2 gallons details given.
18 gallons covering 230 miles
Then 1 G1 is used to cover 15 miles.
Now for 10 G2 covering 230 miles.
then 1 G2 is used to cover 23 miles.
There must 23 - 15 = 8 miles per gallon increment is needed for 10 gallons to improve the mileage to cover 230 miles.
IMO A is correct answer.
Answer: (A) 8
Question: An error 2% in excess ismade while measuring the side ofa square. The % of error in the calculated area of the square is?
(A) 4.00%
(B) 4.04%
(C) 4.16%
(D) 4.30%
(E) 5%
Rationale: 100 cm is read as 102 cm.
A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.
(A2 - A1) = [(102)2 - (100)2]
= (102 + 100) x (102 - 100)
= 404 cm2.
Percentage error = 404 x 100 % = 4.04%
100 x 100
B
Answer: (B) 4.04%
Question: Find the value for x from below equation: x/3=-6?
(A) -16
(B) 11
(C) -12
(D) -18
(E) 14
Rationale: 1. Multiply both sides by 3:
x*3/3= -6/3
Simplify both sides:
x = -18
D
Answer: (D) -18
Question: A train 260 m long passed a pole in 13 sec. How long will it take to pass a platform 740 m long?
(A) 50 sec
(B) 55 sec
(C) 60 sec
(D) 65 sec
(E) 70 sec
Rationale: Speed = 260/13 = 20 m/sec.
Required time = (260 + 740)/20 = 50 sec
Answer:A
Answer: (A) 50 sec
Question: A man's speed with the current is 22 km / hr and the speed of the current is 4 km / hr. The man's speed against the current is
(A) 8.5 km / hr
(B) 9 km / hr
(C) 10 km / hr
(D) 14 km / hr
(E) None
Rationale: Sol.
Man's rate in still in water = (22 - 4) km / hr = 18 km / hr.
Man's rate against the current = (18 - 4) km / hr = 14 km / hr.
Answer D
Answer: (D) 14 km / hr
Question: In a class of students, 2/3 of the number of girls is equal to 1/5 of the total number of students. What is the ratio of boys to girls in the class?
(A) 1/3
(B) 2/3
(C) 4/3
(D) 5/3
(E) 7/3
Rationale: (2/3)G=(1/5)(B+G)
10G=3B+3G
7G=3B
B/G=7/3.
The answer is E.
Answer: (E) 7/3
Question: 10 men do a work in 10days. How many men are needed to finish the work in 5days?
(A) 50
(B) 20
(C) 30
(D) 10
(E) 15
Rationale: men required to finish the work in 5days = 10*10/5 = 20
Answer is B
Answer: (B) 20
Question: What will be the HCF of ( 2 x 3 x 7 x 9 ), ( 2 x 3 x 9 x 11 ) and ( 2 x 3 x 4 x 5 )?
(A) 2 x 3 x 7
(B) 2 x 3 x 9
(C) 2 x 3
(D) 2 x 7 x 9 x 11
(E) None
Rationale: Answer
Given factors
2 x 3 x 7 x 9; 2 x 3 x 9 x 11; 2 x 3 x 4 x 5
∴ Required HCF = Product of common prime factors having least powers = 2 x 3
Correct Option: C
Answer: (C) 2 x 3
Question: 70% of the employees in a multinational corporation have VCD players, 75 percent have microwave ovens, 80 percent have ACs and 85 percent have washing machines. At least what percentage of employees has all four gadgets?
(A) 15%
(B) 5%
(C) 10%
(D) 20%
(E) 25%
Rationale: Given a population where A% has a certain characteristic X and B% has another characteristic Y (assuming both aren't exclusive), then you get the minimum overlap by assuming that the entire population that doesn't have X has characteristic Y, therefore the minimum portion of the population that has both characteristics is:
B-(100-A) %
So given A=70 for employees with VCD players and B=75 for employees with microwave ovens, at least:
75-(100-70)=45% have both. Then take the output and repeat with the other appliances.
A=45 for employees with both VCD players and microwaves, B=80 for ACs
80-(100-45)=25%
A=25 for employees with VCD players, microwaves and ACs, B=85 for washing machines
85-(100-25)=10%
Answer C
Answer: (C) 10%
Question: Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 663 and for 36kgs of Apples is 726 then the cost of first 10 kgs of Apples is
(A) 100
(B) 150
(C) 200
(D) 350
(E) 450
Rationale: Ans: By framing equations we get
30L+3Q=663
30L+6Q=726
Eliminate Q by multiplying the first equation by 2 and subtracting second equation from the first
Then we get L = 20
Cost of 10 kgs of apples = 10 x 20 = 200
Answer:C
Answer: (C) 200
Question: The parameter of a square is equal to the perimeter of a rectangle of length 16 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)
(A) 77.14 cm
(B) 47.14 cm
(C) 84.92 cm
(D) 94.94 cm
(E) 23.57 cm
Rationale: Let the side of the square be a cm.
Parameter of the rectangle = 2(16 + 14) = 60 cm Parameter of the square = 60 cm
i.e. 4a = 60
A = 15
Diameter of the semicircle = 15 cm
Circimference of the semicircle
= 1/2(∏)(15)
= 1/2(22/7)(15) = 330/14 = 23.57 cm to two decimal places
ANSWER:E
Answer: (E) 23.57 cm
Question: From (1, 2, 3, 4, 5, 6), one number is picked out and replaced and one number is picked out again. If the sum of the 2 numbers is 7, what is the probability that the 2 numbers included the number 5?
(A) 1/5
(B) 2/5
(C) 3/10
(D) 3/5
(E) 1/3
Rationale: We know that the sum of two numbers picked was 7. So, there could be the following cases:
(1, 6);
(6, 1);
(2, 5);
(5, 2);
(3, 4);
(4, 3);
Total of 6 cases out of which 2 have 5, thus the probability is 2/6=1/3.
Ans E
Answer: (E) 1/3
Question: A Train requires 10 seconds to pass a pole while it requires 35 seconds to cross a stationary train which is 500 mtrs long. Find the speed of the train.
(A) 68 kmph
(B) 70 kmph
(C) 72 kmph
(D) 60 kmph
(E) 50 kmph
Rationale: In 10s the train crosses the pole and in 35 sec the train crosses one more stationary train
In 25 sec the train travels a distance of 500 mtrs
Speed = 500/25 = 20 m/s = 20 (3600/1000) = 20 * 18/5 = 72 kmph
Answer: C
Answer: (C) 72 kmph
Question: The balance of a trader weighs 10% less than it should. Still the trader marks up his goods to get an overall profit of 30%. What is the mark up on the cost price?
(A) 40%
(B) 8%
(C) 25%
(D) 17%
(E) 9%
Rationale: The most natural way to deal with 'weights' questions is by assuming values.
Say the trader's balance shows 100 gms. It is actually 90 gms because it weighs 10% less. Say, the cost price is $90 ($1/gm). Since he gets a profit of 30%, the selling price must be 90+(30/100)*90 = $117
Since the cost price is actually supposed to be $100 (for 100 gms) and the selling price is $117, the mark up is simply 17%.
Ans : D
Answer: (D) 17%
Question: Arabica coffee costs $0.4 per ounce while Robusta coffee costs $0.3 per ounce. If the blend of Arabica and Robusta costs $0.37 per ounce, what is the share of Arabica in this blend?
(A) 20%
(B) 24%
(C) 70%
(D) 33%
(E) 40%
Rationale: a= amount of arabica coffee
1-a = amount of robusta coffee. because if you subtract a from the 1 ounce, the remaining amount is robusta
therefore:
.4a + .3(1-a) = .37
.4a + .3 - .3a = .37
a= .7
therefore: .7/1 ounce = 70%. Therefore, the answer should be C
Answer: (C) 70%
Question: A can do half the work in one day where as B can do it full. B can also do half the work of C in one day. Ratio in their efficiency will be?
(A) 1:2:8
(B) 1:2:1
(C) 1:2:2
(D) 1:2:4
(E) 2:2:4
Rationale: WC of A: B = 1:2
B: C = 1:2
---------------------
A: B: C = 1:2:4
Answer:D
Answer: (D) 1:2:4
Question: I given the responsibility to organize the American open.
* The number of players come for this match are 64.
* Its a knock-out tournament , each player is eliminated as soon as he looses a match.
For planning these matches i need to count the number of matches that need to played in this tournament.
How many matches will be played ?
(A) 19
(B) 71
(C) 48
(D) 50
(E) 63
Rationale: E
Total Number of Matches: 63
Explanation:
32+16+8+4+2+1 = 63
Answer: (E) 63
Question: Vijay bought 160 shirts at the rate of Rs. 255 per shirt. The transport expenditure was Rs. 1400. He paid an octroi at the rate of Rs. 1.75 per shirt and labour charges were Rs. 320. What should be the selling price of one shirt, if he wants a profit of 20%?
(A) Rs. 321
(B) Rs. 270
(C) Rs. 277.5
(D) Rs. 285
(E) None of these
Rationale: Total CP per shirt = 255 + 1400/160 + 1.75 + 320/160 = Rs. 267.5
SP = CP[(100 + profit%)/100]
= 267.5 * [(100 + 20)/100] = Rs. 321.
ANSWER:A
Answer: (A) Rs. 321
Question: Four staff members at a certain company worked on a project. The amounts of time that the four staff members worked on the project were in the ratio 2 to 3 to 5 to 6. If one of the four staff members worked on the project for 240 hours, which of the following CANNOT be the total number of hours that the four staff members worked on the project?
(A) 1280
(B) 960
(C) 768
(D) 1920
(E) 640
Rationale: Four members worked in ration 2:3:5:6, hence as everyone mentioned, individual work could be taken as 2x, 3x,5x, and 6x. Also this gives us total work as 16x.
But we are told that one of these individual works is 30hrs. hence, possible scenarios, if
(1)2x =240 => 16x = 1920 (2) 3x =240 => 16x = 1280 (3) 5x =240 => 16x = 768 (4) 6x =240 => 16x = 640
Hence Answer is B 960 which can not be any of these.
Answer: (B) 960
Question: The difference between the local value and face value of 7 in the numeral 657903 is:
(A) 0
(B) 7896
(C) 6993
(D) 903
(E) 803
Rationale: (Local value)-(Face value)= (7000-7)
=6993.
ANSWER:C
Answer: (C) 6993
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a loss of 25% and then I found each book was sold at the same price. Find the cost of the book sold at a lower loss?
(A) A)657
(B) B)280
(C) C)225
(D) D)289
(E) E)427
Rationale: x*(85/100)
= (480 - x)75/100
x = 225
Answer:C
Answer: (C) C)225
Question: Which of the following has the most number of divisors?
(A) 344
(B) 377
(C) 176
(D) 888
(E) 271
Rationale: Explanation:
99 = 1 x 3 x 3 x 11
101 = 1 x 101
176 = 1 x 2 x 2 x 2 x 2 x 11
182 = 1 x 2 x 7 x 13
So, divisors of 99 are 1, 3, 9, 11, 33, .99
Divisors of 101 are 1 and 101
Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176
Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.
Hence, 176 has the most number of divisors.
Answer: C) 176
Answer: (C) 176
Question: The cash difference between the selling prices of an article at a profit of 2% and 6% is Rs 3. The ratio of two selling prices is
(A) 51:53
(B) 52:53
(C) 53:54
(D) 54:55
(E) None of these
Rationale: Explanation:
Let the Cost price of article is Rs. x
Required ratio = (102% of x) / (106% of x)
=102/106
=51/53 = 51:53.
Answer: A
Answer: (A) 51:53
Question: A jar contains 4 black and 3 white balls. If you pick two balls at the same time, what's the probability that one ball is black and one is white?
(A) 2/7
(B) 5/7
(C) 4/7
(D) 3/7
(E) 1/2
Rationale: P(1st black, 2nd white) = 4/7*3/6 = 4/14;
P(1st white, 2nd black) = 3/7*4/6 = 4/14.
P = 4/14 + 4/14 = 4/7.
Answer: C.
Answer: (C) 4/7
Question: If s and t are positive integers such that s/t = 64.14, which of the following could be the remainder when s is divided by t ?
(A) 9
(B) 16
(C) 18
(D) 21
(E) 32
Rationale: 0.14 = 7/50
The remainder must be divisible by 7.
The answer is D.
Answer: (D) 21
Question: A foreign language club at Washington Middle School consists of n students, 2/5 of whom are boys. All of the students in the club study exactly one foreign language. 1/3 of the girls in the club study Spanish and 4/5 of the remaining girls study French. If the rest of the girls in the club study German, how many girls in the club, in terms of n, study German?
(A) 2n/5
(B) n/3
(C) 2n/25
(D) 2n/15
(E) n/15
Rationale: 2/5 of the students are boys, thus 3/5 of the students are girls.
1/3 of the girls in the club study Spanish and 4/5 of the remaining girls study French.
Thus 1/5 of 2/3 = 2/15 of the girls study German.
Since girls comprise 3/5 of the students, then 3/5*2/15 = 2/25 are girls who study German.
The answer is C.
Answer: (C) 2n/25
Question: Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 12 inches by 15 inches and Jordan's rectangle is 9 inches long, how wide is Jordan's rectangle, in inches?
(A) 17
(B) 18
(C) 19
(D) 20
(E) 21
Rationale: Area of first rectangle is 12*15=180 hence area of second would be 9x=180x
x=20
answer is D
Answer: (D) 20
Question: A is twice as good as workman as B and together they finish a piece of work in 18 days. In how many
days will B alone finish the work.
(A) 27 days
(B) 54 days
(C) 56 days
(D) 68 days
(E) None of these
Rationale: Explanation:
As per question, A do twice the work as done by B.
So A:B = 2:1
Also (A+B) one day work = 1/18
To get days in which B will finish the work, lets calculate work done by B in 1 day =
=(118
∗
13)=154
[Please note we multiplied by 1/3 as per B share and total of raƟo is 1/3]
So B will finish the work in 54 days
Answer: B
Answer: (B) 54 days
Question: A, B and C completed a piece of work, A worked for 6 days, B for 9 days and C for 4 days. Their daily wages were in the ratio of 3:4:5. Find the daily wages of C, if their total earning was Rs.1554?
(A) s.109
(B) s.108
(C) s.100
(D) s.103
(E) s.105
Rationale: 3x 4x 5x
6 9 4
18x + 36x + 20x = 1554
74x = 1554 => x = 21
5x = 105 Rs.
Answer:E
Answer: (E) s.105
Question: Points A, B, C, and D, in that order, lie on a line. If AB = 2 cm, AC = 5 cm, and BD = 9 cm, what is CD, in centimeters?
(A)  1
(B)  2
(C)  3
(D)  6
(E)  5
Rationale: Putting a value to each point, lets use the following:
A - 0
B - 2 (AB = 2)
C - 5 (AC = 5)
D - 11 (BD = 9)
CD is 11-5 = 6.
Ans D
Answer: (D)  6
Question: The sum of ages of 5 children born at the intervals of 3 years each is 60 years. What is the age of the youngest child?
(A) 3 years
(B) 4 years
(C) 6 years
(D) 7 years
(E) 8 years
Rationale: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 60
5x = 30
x = 6.
Age of the youngest child = x = 6 years.
C)
Answer: (C) 6 years
Question: If 20% of a number, then 120% of that number will be?
(A) 20
(B) 120
(C) 360
(D) 720
(E) 820
Rationale: Let the number x. Then,
20% of x = 120
x = (120 * 100)/20 = 600
120% of x = (120/100 * 600) = 720.
ANSWER:D
Answer: (D) 720
Question: Income and expenditure of a person are in the ratio 5 : 3. If the income of the person is Rs. 10000, then find his savings?
(A) Rs.4000
(B) Rs.3603
(C) Rs.3639
(D) Rs.3632
(E) Rs.3602
Rationale: Let the income and the expenditure of the person be Rs. 5x and Rs. 3x respectively.
Income, 5x = 10000 => x = 2000
Savings = Income - expenditure = 5x - 3x =2x
So, savings = Rs.2*2000 = Rs. 4000
Answer:A
Answer: (A) Rs.4000
Question: Sanjay invested an amount of ` 16,000 for two years on compound interest and received an amount of ` 17,640 on maturity. What is the rate of interest per annum?
(A) 4%
(B) 5%
(C) 8%
(D) 9%
(E) None of these
Rationale: The extra money for two years is 1,640. This can be broken up as 800 + (800 + 40). Since 40 = 5% of 800 and 800 = 5% of 16000
So, r = 5%.
Answer: B
Answer: (B) 5%
Question: A shipping clerk has five boxes of different but unknown weights each weighing less than 100 kg. The clerk weighs the boxes in pairs. The weights obtained are 110, 112, 113, 114, 115, 116, 117, 118, 120 and 121 kg. What is the weight, in kg, of the heaviest box ?
(A) 60
(B) 61
(C) 64
(D) Can't be determined
(E) None
Rationale: Explanation :
Two boxes are selected at at time and weighed together. Thus, the selection order does not matter and selecting box 1 and then box 2 is the same as selecting box 2 and then box 1. So this is a combination problem.
2 boxes can be selected from 5 boxes in 5C2 ways, i.e. 10 ways. The given list of weighings is 10 in number. So we can assume that all the possible combinations of boxes have been weighed. Lets assume that all boxes are lined as per increasing weights and named as b1, b2, b3, b4, b5. From the given list (Arranges in increasing order of weights) ,
what we have is b1 + b2 = 110, as b1 is the lightest and b2 is the next lightest box heavier than b1. So the sum of these two should be the minimum value in the list.
The second lightest sum of weights, the second value in the list, will be the sum of the b1 + b3 = 112.
Similarly, the maximum value in the list should be the sum of weights of b4 and b5, giving b4 + b5 = 121.
The second last heaviest will be b3 + b5 = 120.
Adding the 4 equations, we get, 2 b1 + 2 b3 + 2 b5 + b2 + b4 = 463 - Equation 1.
Sum of all the weights in the given list is 1160. This sum is the sum of each of the cases b1+b2, b1+b3, b1+b4, b1+b5, b2+b3, b2+b4, b2+b5, b3+b4, b3+b5, b4+b5. Thus sum of all this will be 4(b1 + b2 + b3 + b4 + b5) = 1160. Thus, b1 + b2 + b3 + b4 + b5 = 290 - Equation 2.
Subtracting equation 2 from equation 1, we get, b1 + b3 + b5 = 173.
We know that b1 + b3 = 112, So b5 = 173 - 112 = 61 = Desired answer.
Answer : B
Answer: (B) 61
Question: X completes a work in 60 days and Y complete the same work in 30 days. If both of them work together, then the number of days required to complete the work will be?
(A) 30 days.
(B) 50 days.
(C) 25 days.
(D) 10 days.
(E) 20 days.
Rationale: If X can complete a work in x days and Y can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days
Therefore, here, the required number of days = 60 Ã— 30/90 = 20 days.
E)
Answer: (E) 20 days.
Question: Tina’s cat weighs 3.2 kilograms. Her dog weighs 4 times as much as her cat. How much does her dog weigh in kilograms?
(A) A)10.4kg
(B) B)38kg
(C) C)12.8kg
(D) D)48kg
(E) E)20kg
Rationale: 3.2*4=12.8kg.Answer is C.
Answer: (C) C)12.8kg
Question: Anintegratedteam consists of 2 members from the engineering team and 2 members from the design team. If the engineering team has 6 members and the design team has 3 members, how manyintegratedteam formations are possible?
(A)  36
(B)  45
(C)  76
(D)  90
(E)  112
Rationale: 2 out of 6 times 2 out of 3 => 6*5/2*1 * 3*2/2*1 = 45
B
Answer: (B)  45
Question: In a school of 850 boys, 44% of Muslims, 14% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
(A) A)125
(B) B)627
(C) C)153
(D) D)721
(E) E)272
Rationale: 44 + 14 + 10 = 68%
100 – 68 = 32%
850 * 32/100 = 272
Answer:E
Answer: (E) E)272
Question: Which of the following values of x satisfies the inequality 2x2 – 3x + 1 > 0?
(A) -1 < x < -1⁄2
(B) 1⁄2 < x < 1
(C) x > 1 or x < 1⁄2
(D) -1⁄2 < x < 1
(E) None of these
Rationale: 2x2 – 3x + 1 = 0.
or (2x – 1)(x – 1) = 0
Hence, α = 1⁄2 and β = 1
Now, the given inequality is 2x2 – 3x + 1 > 0,
Hence, sign scheme will be as follows:
--------|---------------------|----------------
+ve 1⁄2 –ve 1 +ve
∴ x > 1 or x < 1⁄2
[Note:If the inequality were 2x2 – 3x + 1 < 0; the answer will be 1⁄2 < x < 1]
Answer C
Answer: (C) x > 1 or x < 1⁄2
Question: Sripad has scored average of 68 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ?
(A) 79
(B) 28
(C) 38
(D) 27
(E) 88
Rationale: Assuming Sripad has scored the least marks in subject other than science,
Then the marks he could secure in other two are 58 each.
Since the average mark of all the 3 subject is 68.
i.e (58+58+x)/3 = 68
116 + x = 204
x = 88 marks.
Therefore, the maximum marks he can score in maths is 88.
Answer: E
Answer: (E) 88
Question: There are 4 more women than men on Centerville's board of education. If there are 8 members on the board, how many are women?
(A)  3
(B)  4
(C)  6
(D)  7
(E)  8
Rationale: Given: M=W-4 so, W+(W-4)=8 --> W=6.
Answer: C.
Answer: (C)  6
Question: 96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
(A) 66
(B) 77
(C) 42
(D) 88
(E) 12
Rationale: x/7 = y/9 => x:y = 7:9
7/16 * 96 = 42.Answer: C
Answer: (C) 42
Question: If a is a positive integer and 10^a – 74 in decimal notation has digits whose sum is 440, what is the value of a?
(A) 40
(B) 44
(C) 45
(D) 46
(E) 50
Rationale: Answer E = 50
We have (10^a)-74, where the sum of the digits is 440.
100-74 = 26, so we already have 2+6 = 8 from the 440.
Because we have a power of 10, we will have numbers like 100, 1000, 10000 and so on. This minus 74 rests 26 and a lot of 9s. E.g: 1000-74 = 9926.
So dividing the 432/9 = 48, that`s the number of 9s. and we have 2 other numbers (2 and 6) wich were 00 before the subtraction.
So we have 48 + 2 as an a = 50
Answer: (E) 50
Question: Two men start together to walk a certain distance, one at 4 kmph and another at 3 kmph.The former arrives half an hour before the latter. Find the distance.
(A) 6 km
(B) 7 km
(C) 8 km
(D) 9 km
(E) None of these
Rationale: Let the distance be x km. Then,
x/3 - x/4 =1/2
(4x - 3x)/12 = 1/2
x = 6 km
ANSWER:A
Answer: (A) 6 km
Question: Find compound interest on Rs. 8000 at 15% per annum for 2 years 4 months, compounded annually
(A) 3109
(B) 3115
(C) 3250
(D) 3500
(E) 4000
Rationale: Time = 2 yrs 4 mos = 2(4/12) yrs = 2(1/3) yrs.
Amount = Rs. [8000 X (1+(15/100))^2 X (1+((1/3)*15)/100)]
= Rs. 11109.
:. C.I. = Rs. (11109 - 8000) = Rs. 3109.
ANSWER A
Answer: (A) 3109
Question: Given that there are 11 cricket players per team, how many ways can you select 10 cricket players from 2 teams if no more than 1 players can be selected from each team?
(A) 150
(B) 200
(C) 121
(D) 140
(E) 150
Rationale: Now from each group we have to select 5 persons only: 11C1 * 11C1= 11 * 11 = 121
Total ways=313444 ways.
Answer C
Answer: (C) 121
Question: The average amount with a group of seven numbers is Rs. 30. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?
(A) Rs. 25.6
(B) Rs. 26.6
(C) Rs. 16.6
(D) Rs. 26
(E) Rs. 25
Rationale: Total members in the group = 7
Average amount = Rs. 30
Total amount with them = 7 * 30 = Rs. 210
One number has Rs. 50. So, the amount with remaining 6 people = 210 - 50 = Rs. 160
The average amount with them = 160/6 = Rs. 26.6
ANSWER:B
Answer: (B) Rs. 26.6
Question: Which of the following is closest to 1/5+1/55+1/555
(A) 1/4.54
(B) 1/3.5
(C) 1/2.5
(D) 1/3.6
(E) 1/3.7
Rationale: 1/5+1/55+1/555=0.2+0.018+0.0018=0.2198=1/4.54
Answer is A
Answer: (A) 1/4.54
Question: Find the ones digit of 73^330
(A) 3
(B) 5
(C) 6
(D) 7
(E) 9
Rationale: Cyclicity of 3 is 3,9,7,1after 4 multiplication again the cycle repeats.
So divide 330 by 4 and we get 87 as quotient and 2 as remainder. So cycle will run for 87 times and then 2 times more. So pick up the 2nd item from the cycle.
Hence Answer B.
Answer: (B) 5
Question: I came across this problem in the GMATprep software and got it totally wrong!
A company consists of 6 senior and 4 junior staff officers. If a committee is created with 4 senior and 1 junior staff officers, how many possible committees are there?
(A) 12
(B) 44
(C) 56
(D) 60
(E) 200
Rationale: 6C4*4C1
=60=D
Answer: (D) 60
Question: A worker earns $20 on the first day and spends $15 on the second day. The worker earns $20 on the third day and spends $15 on the fourth day. If this pattern continues, on which day will the worker first reach a net total of $80?
(A) 24
(B) 25
(C) 27
(D) 30
(E) 32
Rationale: Every two days, the net total is $5.
After 24 days, the worker will have $60.
On day 25, the worker will receive $20 for a net total of $80.
The answer is B.
Answer: (B) 25
Question: Village X has a population of 68000, which is decreasing at the rate of 1200 per year. Village Y has a population of 42000, which is increasing at the rate of 800 per year .in how many years will the population of the two villages be equal?
(A) 15
(B) 19
(C) 11
(D) 18
(E) 13
Rationale: Let the population of two villages be equal after p years
Then, 68000-1200p=42000+800p
2000p=26000
p=13
Answer is E.
Answer: (E) 13