mathewhe/aqua_rat huggingface dataset:
Question: Mohan purchased 13 kgs of rice at the rate of Rs.26 per kg and 8 kgs of pulses at the rate of Rs.26 per kg. Whaat is the total amount that he paid to the shopkeeper?
(A) A)Rs.598
(B) B)Rs.594
(C) C)Rs.596
(D) D)Rs.546
(E) of these
Rationale: Explanation:
Price of 13 kgs of rice at Rs.26/kg = 13x26 = Rs.338
Price of 8 kgs of pulses at Rs.26/kg = 8x26 = Rs.208
Therefore, Total amount = Rs.338+Rs.208 = Rs.546.
Answer: Option D
Answer: (D) D)Rs.546
Question: A 90 cm long wire is to be cut into two pieces so that one piece will be 2/7th of the other, how many centimeters will the shorter piece be?
(A) A)73
(B) B)20
(C) C)83
(D) D)21
(E) E)52
Rationale: Explanation:
1: 2/7 = 7: 2
2/9 * 90 = 20
Answer: Option B
Answer: (B) B)20
Question: A student completes a 3 part exam as follows. The student completes sections A in 24 minutes and takes an equal time to complete the two remaining sections. What is the ratio of time spent on section C to section A if the total duration is 1 hour?
(A) 7:8
(B) 6:7
(C) 5:6
(D) 4:5
(E) 3:4
Rationale: The time spent on section B and section C is 18 minutes each.
The ratio of C to A is 18:24 = 3:4
The answer is E.
Answer: (E) 3:4
Question: Indu gave Bindu Rs.3750 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
(A) 1
(B) 2
(C) 6
(D) 4
(E) 9
Rationale: 3750 = D(100/4)2
D = 6
Answer:C
Answer: (C) 6
Question: If in a $300 mln portfolio of stock, twice as much is invested in stock A as is invested in all the other stocks, how much is invested in all the other stocks?
(A) 100mln
(B) 200mln
(C) 300mln
(D) 400mln
(E) 500mln
Rationale: Let x denote the amount invested in all the other stocks. Then the amount invested in stock A is 2x. As we have the $300 mln portfolio, x+2x=3x=300 mln from where x=100 mln.
Answer: A
Answer: (A) 100mln
Question: Michael has some coins in his pocket consisting of dimes, nickels, and pennies. He has two
more nickels than dimes, and three times as many pennies as nickels. How many of each kind
of coin does he have if the total value is $0.52?
(A) 1 dimes, 2 nickels, and 4 pennies.
(B) 2 dimes, 4 nickels, and 12 pennies.
(C) 5 dimes, 5 nickels, and 6 pennies.
(D) 7 dimes, 8 nickels, and 12 pennies.
(E) 5 dimes, 4 nickels, and 3 pennies.
Rationale: This problem involves money.
The question asks, “How many of each kind of coin”.
There is more than one unknown. So when doing the let statement, start with the
smallest quantity, in this case, the number of dimes.
Let x the number of dimes
x+2 the number of nickels
3x+2= the number of pennies
The value of all the dimes$0.10x plus the value of all the nickels$0.5(x+2) plus the
value of all the pennies$0.01(3)(x+2) equals the total value, $0.52.
Write the equation.
0.10x+0.05(x+2)+0.03(x+2)=0.52
10x+5(x+2)+3(x+2)=52
10x+5x+10+3x+6=52
18x=36
x=2
x+2=4
3(x+2)=12
The answer: Michael has 2 dimes, 4 nickels, and 12 pennies.
correct answer B
Answer: (B) 2 dimes, 4 nickels, and 12 pennies.
Question: A school’s annual budget for the purchase of student computers increased by 50% this year over last year. If the price of student computers increased by 50% this year, then the number of computers it can purchase this year is what percent greater than the number of computers it purchased last year?
(A) 1%
(B) 2%
(C) 3%
(D) 0%
(E) 5%
Rationale: Pick numbers.
Lats year: budget = $100, price = $1 --> the number of computers purchased = 100/1 = 100;
This year: budget = $150, price = $1.5 --> the number of computers purchased = 150/1.5 = ~100.00
Increase in the number of computers purchased = 0%
Answer: D.
Answer: (D) 0%
Question: If n is a prime number and n ≠ 3, which of the following could be the remainder when 100! + n is divided by 3?
I. 1
II. 0
III. 2
(A) II only
(B) III only
(C) I and II only
(D) II and III only
(E) I and III only
Rationale: Notice that we are told that n is a prime number and n ≠ 3. Thus, n cannot be 1.
n also cannot be 6 or any other multiple of 3, thus the remainder cannot be 0.
It can be 1 for n=2 and 2 for n=5.
Answer: E.
Answer: (E) I and III only
Question: Gill drives 120 miles from Los Angeles to San Diego to fetch a package. On her way there she drives at 40 miles per hour. On her way back she drives 50% faster. What is Gill's average velocity E for the round trip?
(A) 24 miles per hour
(B) 48 miles per hour
(C) 50 miles per hour
(D) 53 1/3 miles per hour
(E) 68 miles per hour
Rationale: Here's an Average Speed question in which the prompt gives you almost all of the immediate numbers needed to work with.
Driving from LA to SD, we have a distance of 120 miles and a speed of 40 miles/hour.
D = (R)(T)
120 = (40)(T)
120/40 = 3 = T
3 hours to drive to SD
On the way back, she drives 50% FASTER. Gill's return speed is (1.5)(40) = 60 miles/hour.
D = (R)(T)
120 = (60)(T)
120/60 = 2 = T
2 hours to drive to SD
Total Distance = 240 miles
Total Time = 3+2 = 5 hours
Average Speed = 240/5 = 48 miles/hour
Final Answer:
B
Answer: (B) 48 miles per hour
Question: 10 women will complete a job in 7 days and 10 children take 14 days to complete the job. How many days will 5 women and 10 children take to complete the work?
(A) 5
(B) 6
(C) 7
(D) 10
(E) 12
Rationale: woman 1 day work = 1/70
1 child 1 day work = 1/140
(5 + 10) = 5/70+10/140
day work = 1/14+1/14=1/7
===>7 days
ANSWER C
Answer: (C) 7
Question: Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Jim or Renee will win?
(A) 5/6
(B) 2/3
(C) 1/2
(D) 5/12
(E) 1/3
Rationale: There are 3*3=9 combinations (cases) possible. In 3 cases there will be a tie (rock-rock, scissors/scissors, paper/paper). Now, out of 6 cases left Jim and Renee have equal chances of winning, so in 3 cases Jim will win and in other 3 Renee will win. So the probability Jim or Renee winning the game is (favorable outcomes) / (total # of outcomes) = 6/9 = 2/3.
Answer: B
Answer: (B) 2/3
Question: Pipe A can fill a tank in 10 hours, pipe B in 15 hours and pipe C in 30 hours. If all the pipes are open, in how many hours will the tank be filled?
(A) 2
(B) 2.5
(C) 3
(D) 5
(E) None
Rationale: Sol.
Part filled by (A + B + C) in 1 hour = (1/10 + 1/15 + 1/30) = 1/5.
âˆ´ All the three pipes together will fill the tank in 5 hours.
Answer D
Answer: (D) 5
Question: A student got twice as many sums wrong as he got right. If he attempted 27 sums in all, how many did he solve correctly ?
(A) 12
(B) 16
(C) 18
(D) 9
(E) 12
Rationale: Explanation:
Suppose the boy got x sums right and 2x sums wrong.
Then, x + 2x = 27 3x = 27 x = 9.
Answer:D
Answer: (D) 9
Question: Find the cost of fencing around a circular field of diameter 32 m at the rate of Rs.1.50 a meter?
(A) 287
(B) 132
(C) 150.9
(D) 158
(E) 267
Rationale: 2 * 22/7 * 16 = 100.6
100.6 * 1 1/2 = Rs.150.9
Answer: C
Answer: (C) 150.9
Question: A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.2 km long?
(A) 2 mins 14 sec
(B) 2 mins 34 sec
(C) 162 sec
(D) 244 sec
(E) 2 mins 44 sec
Rationale: D = 25 * 60 + 1200 = 2700 m
T = 2700/60 * 18/5 = 162 sec
ANSWER:C
Answer: (C) 162 sec
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds i
(A) 1:3
(B) 3:2
(C) 3:4
(D) 4:2
(E) None of these
Rationale: Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
27x +17y / x + y =23
27x + 17y = 23x + 23y
4x = 6y
x/y=3/2
ANSWER IS B
Answer: (B) 3:2
Question: A carpenter worked alone for 2 day on a job that would take him 6 more days to finish. He and another carpenter completed the job in 4 more days. How many days would it have taken the second carpenter to do the complete job working alone?
(A) 4 2/3
(B) 7
(C) 8
(D) 14
(E) 24
Rationale: A carpenter worked only 2 day on something that takes him 6 MORE days.
Means;
Carpenter finishes his work in 8 days.
Let his buddy finish the same task in x days.
Respective rates per day:
2/8 AND 1/x
To complete 1 work:
First guy worked for 6 days @ rate=1/8 per day.
Second one worked for 4 days @ rate=1/x per day
Expression:
Days*Rate=Work
6*2/8+4*1/x=1=3/2+4/x=1
3x+8=2x
x=8
x=8 days.
Ans:C
Answer: (C) 8
Question: If the numbers 1 to 99 are written on 99 pieces of paper, (one on each) and one piece is picked at random, then What is the probability that the number drawn is neither prime nor composite?
(A) 1/50
(B) 1/25
(C) 1/99
(D) 1
(E) 2
Rationale: There are 25 primes, 73 composite numbers from 1 to 100. The number
which is neither prime nor composite is 1.
Therefore, required probability = 1/99.
ANSWER:C
Answer: (C) 1/99
Question: Positive integer n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 3. If n is greater than 30, what is the remainder that n leaves after division by 30?
(A) 3
(B) 12
(C) 18
(D) 22
(E) 28
Rationale: The theory says:
if a # x is devided by y and leave the positive # r as the remainder then it can also leave negative # (r-y) as the remainder.
e.g:
9 when devided by 5 leves the remainder 4 : 9=5*1+4
it can also leave the remainder 4-5 = -1 : 9=5*2 -1
back to the original qtn:
n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 5
==> n leaves a remainder of -2 (i.e. 4-6) after division by 6 and a remainder of -2 (i.e. 3-5) after division by 5
==> n when devided by 5 and 6 leaves the same remainder -2.
what is n?
LCM (5,6)-2 = 30-2 = 28
CHECK: 28 when devided by 6 leaves the remainder 4 and when devided by 5 leaves the remainder 3
However, the qtn says n > 30
so what is the nex #, > 28, that can give the said remainders when devided by 6 and 5
nothing but 28 + (some multiple of 6 and 5) as thissome multiple of 6 and 5will not give any remainder when devided by 5 or 6 but 28 will give the required remainders.
hence n could be anything that is in the form 28 + (some multiple of 6 and 5)
observe thatsome multiple of 6 and 5is always a multiple of 30 as LCM (5,6) = 30.
hence when n (i.e. 28 + some multiple of 6 and 5) is devided by 30 gives the remainder 22.
D
Answer: (D) 22
Question: For any number y, y* is defined as the greatest positive even integer less than or equal to y. What is the value of 5.0– 5.0*?
(A) 0.2
(B) 1.2
(C) 1.8
(D) 2.2
(E) 1.0
Rationale: Since y* is defined as the greatest positive even integer less than or equal to y, then 5.0* = 4 (the greatest positive even integer less than or equal to 5.0 is 4).
Hence, 5.0 – 5.0* = 5.0 - 4 = 1.0
Answer: E.
Answer: (E) 1.0
Question: Consider a sequence of numbers given by the expression 7 + (a - 1) * 5, where n runs from 1 to 80.What is the sum of this series ?
(A) 409
(B) 1636
(C) 16360
(D) 16000
(E) 15360
Rationale: terms in this sequence are 7,12,17----402
now since this is an a.p. with a common difference of 5. therefore its sum can be given as
a(f+l)/2----------------1)
a= total no. of terms =80
f= first term=7
l= last term=402
subsituting values in the expression 1 we have
80(7+402)/2
= 40(409)
=16360=C
Answer: (C) 16360
Question: If ABC is a quarter circle and a smaller circle is inscribed in it; if radius of quarter circle is 1.414units. Find the radius of smaller circle
(A) 0.586
(B) 0.687
(C) 0.784
(D) 0.874
(E) 0.974
Rationale: if r be radius of smaller circle then
distance b/n centres = √2 * r
so, r + r√2 = R here,R = 1.414 =√2
=> r=(√2 -1)R
r = 0 .586 unit
ANSWER:A
Answer: (A) 0.586
Question: If e and b are positive numbers, and e^3 + b^3 = 75, then the greatest possible value of e is between:
(A) 0 and 3
(B) 3 and 5
(C) 4 and 5
(D) 5 and 7
(E) 6 and 9
Rationale: Yes the question is ambiguous, and the answer is certainly not C between 4 and 5 .
The question stated: e and b are positive numbers but not positive integers.
so fractions are allowed to be a part of calculation.
So if the answer is C then the value 4.5 = 9/2 must comply the equation.
(9/2)^3 + b^3 = 75
so, b^3 = -129/8 , which is not possible according to the question.
Moreover the question didn't mentioninclusive or not, so we can't assume that b is 4 .
hi asif,
question is correct IMO.
Sincemaximumvalues areuniqueso you cant take any value and make it satisfy with equation
question is asking that maximum value ofa(means that unique value ofa) is between...
its not saying all value of that range will satisfy.
Answer: (C) 4 and 5
Question: A row of seats in a movie hall contains 10 seats. 3 Girls and 7 boys need to occupy those seats. What is the probability that no two girls will sit together?
(A) 7/15
(B) 2/15
(C) 4/15
(D) 6/15
(E) 9/15
Rationale: Total # of ways for the 7 boys to stand = 7!
After these boys have stood in their positions, there are 8 positions for the 3 girls to occupy.
# of ways for the girls to choose 3 positions = 8C3
# of ways of arranging themselves = 3!
Hence, total # of ways for the girls = 8C3 times 3!
Overall, # of ways when no two girls are together = 7! times 8C3 times 3!
n(S) = n(Sample space for these 10 students) = 10!
Hence, probability for no two girls to sit together = 7! * 8C3 * 3! / 10!
= 8C3 * 3! / (10 * 9 * 8)
= (8 * 7 * 6 ) / (10 * 9 * 8)
= (7*6) / (10*9)
=7/15
ANSWER:A
Answer: (A) 7/15
Question: Tom drives from town R to town B, driving at a constant speed of 60 miles per hour. From town B Tom immediately continues to town C. The distance between R and B is twice the distance between B and C. If the average speed of the whole journey was 36 mph, then what is Tom's speed driving from B to C in miles per hour?
(A) 12
(B) 20
(C) 24
(D) 30
(E) 36
Rationale: Let's assume that it takes 4 hours to go from point R to B. Then the distance between them becomes 240 which makes distance between B and C 120. (240+120)/(4+x) gives us the average speed which is 36. You find x=6. So the question simplifies itself to 120/6=20
Hence the answer is B.
Answer: (B) 20
Question: What is the true discount on a bill of Rs.2916 due in 3 years hence at 8% C.I.?
(A) rs.600
(B) rs.601
(C) rs.602
(D) rs.603
(E) NONE OF THESE
Rationale: Explanation:
PW=Amount/(1+R/100)t
ANSWER IS C
Answer: (C) rs.602
Question: A person can swim in still water at 12 km/h. If the speed of water 10 km/h, how many hours will the man take to swim back against the current for 8km?
(A) 4
(B) 7
(C) 5
(D) 9
(E) 6
Rationale: M = 12
S = 10
US = 12 - 10 = 2
D = 8
T = 8/2 = 4
Answer: A
Answer: (A) 4
Question: Which of the following CANNOT be the median of the 3 positive integers a, b, and c?
(A) a
(B) c
(C) a+c
(D) (a+c)/2
(E) (a+c)/3
Rationale: The median of a set with odd number of terms is justa middle term, so it's a, b or c. Eliminate A and B right away. Now, the median can also be (a+c)/2 and (a+c)/3 (for example: {1, 2, 3} and {1, 2, 5}).
But since a, b, and c are positive integers then it no way can be a+c . Why? Because a middle term (the median) cannot possibly be greater than two terms (a and c) in a set with 3 terms.
Answer: C.
Answer: (C) a+c
Question: if the length of rectangle is three times of its breadth.if the area of rectangle is 6075 sq.m,then calculate the length?
(A) 145
(B) 135
(C) 75
(D) 140
(E) none of these
Rationale: let breadth=x,length = 3x.
area of rectangle=length*breadth=3x^2=6075
x^2=2025,x=√2025=45 m
length=135 m
answer B
Answer: (B) 135
Question: 30^10 / 210^5=?
(A) 6^5
(B) 5^6
(C) (30/7)^5
(D) 6^3
(E) 15^3
Rationale: 30^10 / 210^5=?
A. 6^5
B. 5^6
C. (30/7)^5
D. 6^3
E. 15^3
-> 30^10 / 210^5=(30^10)/(7^5)(30^5)=(30^5)/(7^5)=(30/7)^5.
Thus, C is the answer.
Answer: (C) (30/7)^5
Question: By weight, liquid X makes up 1.5 percent of solution P and 6.5 percent of solution Q. If 200 grams of solution P are mixed with 800 grams of solution Q, then liquid X accounts for what percent of the weight of the resulting solution?
(A) 4.5%
(B) 5.0%
(C) 5.5%
(D) 5.8%
(E) 6.0%
Rationale: The number of grams of liquid X is 1.5(200)/100 + 6.5(800)/100 = 3 + 52 = 55 grams.
55 / 1000 = 5.5%
The answer is C.
Answer: (C) 5.5%
Question: A square mirror has exactly half the area of the rectangular wall on which it is hung. If each side of the mirror is 18 inches and the width of the wall is 32 inches, what is the length of the wall, in inches?
(A)  15.25
(B)  18.25
(C)  19.25
(D)  20.25
(E)  21.25
Rationale: Since the mirror is 42 inches in all sides, it must be a square. Area of a square is A=a^2; 18^2=324.Area of rectangle is double of that 2 *324=648.Now A=lw and we need find w so A/l=w ; 648/32= 20.25 Answer!
Answer is D
Answer: (D)  20.25
Question: If four coins are tossed, the probability of getting two heads and two tails ?
(A) 3/8
(B) 3/7
(C) 3/86
(D) 3/5
(E) 3/2
Rationale: Since four coins are tossed, sample space = 24
Getting two heads and two tails can happen in six ways.
n(E) = six ways
p(E) = 6/24 = 3/8
Answer: A
Answer: (A) 3/8
Question: in how man ways team of four can be formed from four boys and three girls such that atleast one boy and one girl should be there?
(A) 33
(B) 34
(C) 35
(D) 36
(E) 37
Rationale: One boy and one girl can be selected as (one boy & three girls) or (two boys & two girls) or (three boys & one girl)=(4C1*3C3)+(4C2*3C2)+(4C3*3C1)=4+18+12=34
ANSWER:B
Answer: (B) 34
Question: A dice has one of the first 10 prime number on each its six sides ,with no two sides having the same number .the dice is rolled 8 times and the results added.the addition is most likely to be closet to
(A) 100
(B) 120
(C) 103
(D) 105
(E) 70
Rationale: if die is rolled then avg score = (2+ 3+ 5+ 7+ 11+ 13+ 17+19+ 23+ 29 )/10 = 129/10
so, most likely sum for 8 times = 129/10 *8 = 103
ANSWER:C
Answer: (C) 103
Question: A grocer purchased 80 kg of sugar at 13.50 per kg and mixed it with 120 kg sugar at 16 per kg. At what rate should he sell the mixture to gain 21%?
(A) 17 per kg
(B) 18.15 per kg
(C) 16.5 per kg
(D) 16 per kg
(E) None of these
Rationale: C.P. of 200 kg of mixture = (80 × 13.50 + 120 × 16)
= 3000.
S.P. = 121% of 3000 = (121⁄100 × 3000) = 3630
∴ Rate of S.P. of the mixture = (3630⁄200) per kg
= 18.15 per kg.
Answer B
Answer: (B) 18.15 per kg
Question: A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.306 less than the sum lent. What was the sum lent?
(A) 228
(B) 278
(C) 289
(D) 500
(E) 450
Rationale: P - 306 = (P*4*8)/100
P = 450
Answer: E
Answer: (E) 450
Question: There are 408 boys and 216 girls in a school which are to be divided into equal sections of either boys or girls alone. Find the total number of sections thus formed.
(A) 26
(B) 32
(C) 35
(D) 30
(E) 45
Rationale: Explanation:
HCF (408, 216) = 24
The number of boys or girls that can be placed in a section = 24.
Thus the total number of sections is given by
408/24+216/24 =17+9 = 26
Answer: A
Answer: (A) 26
Question: The average earning of a for the first 4days of a week is Rs18 and for the last four days is Rs20. If he earns Rs.20 on the fourth day, his average earning forthe whole week is?
(A) Rs. 10
(B) Rs. 20
(C) Rs. 30
(D) Rs. 40
(E) Rs. 50
Rationale: Total earning for the week = Sum of earning of first four days + Sum of earning of last four days - Earning of 4th day
= 4 x18 + 4 x 22 -20
= Rs. 140
∴ Average earning = 140 / 7
= Rs. 20
B
Answer: (B) Rs. 20
Question: Bruce and Bhishma are running on a circular track of length 600m. Speed of Bruce is 30 m/s and that of Bhishma is 20 m/s .They start fro the same point at the same time in the same direction. When will they meet again for the first time?
(A) 60 sec
(B) 70 sec
(C) 80 sec
(D) 90 sec
(E) 100 sec
Rationale: Actually Arjun has to make a lead of 600 m, because when Arjun will be 600m ahead of Bhishma, they will be together again as a person when completes the total length it starts retracing he same path and thus Arjun and Bhishma can be together again.
Since , they make a difference of 10 m in 1 second. so, he will create 600m difference in 60 second.
D
Answer: (D) 90 sec
Question: By looking at a rectangular box, a carpenter estimates that the length of the box is between 2 to 2.1 meters, inclusive, the breadth is between 1 to 1.1 meters, inclusive and the height is between 2 to 2.1 centimeters, inclusive. If the actual length, breadth and height of the box do indeed fall within the respective ranges estimated by the carpenter, which of the following is the closest to the maximum possible magnitude of the percentage error T that the carpenter can make in calculating the volume of the rectangular box?
(A) 1%
(B) 3%
(C) 10%
(D) 18%
(E) 22%
Rationale: the dimensions are between 2-2.1, 1-1.1 and 2-2.1..
so MAX error in Volume=?..
IMPORTANT POINTS TO NOTE
1) Max ERROR would be when actuals and estimate are at the extreme ends..
2) BUT what about MAX % ERROR--
It will be when the base is the lowest...
so the ACTUALS should be lowest or at lower end and the ESTIMATE at the higher end..
SOLUTION
Actuals= 2*2*1=4..
Estimate=2.1*2.1*1.1=4.841..
Max % error T=(4.841-4)/4 *100= 84.1/4 = 21.25%..
21.25% is closest to 22% in the choices..
ans E
Answer: (E) 22%
Question: The following list follows a peculiar pattern. Can you find it out and guess the next number?
2, 12, 36, 80, 150, 252, ?
(A) 391
(B) 392
(C) 393
(D) 394
(E) none
Rationale: Solution:
The next number is 392.
The first number = (Square of 1 + Cube of 1)
The second number = (Square of 2 + Cube of 2)
The third number = (Square of 3 + Cube of 3)
The fourth number = (Square of 4 + Cube of 4)
The fifth number = (Square of 5 + Cube of 5)
The sixth number = (Square of 6 + Cube of 6)
Therefore, the seventh number will be
Square of 7 + Cube of 7 = 392.
Answer B
Answer: (B) 392
Question: In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State?
(A) 7000
(B) 8000
(C) 8800
(D) 8900
(E) 9000
Rationale: State A and State B had an equal number of candidates appeared.
In state A, 6% candidates got selected from the total appeared candidates
In state B, 7% candidates got selected from the total appeared candidates
But in State B, 80 more candidates got selected than State A
From these, it is clear that 1% of the total appeared candidates in State B = 80
=> total appeared candidates in State B = 80 x 100 = 8000
=> total appeared candidates in State A = total appeared candidates in State B = 8000
Answer: (B) 8000
Question: At a certain high school, a student’s popularity is determined by his or her locker number. Whoever has the locker number with the greatest number of distinct prime factors is the most popular student in the school. If Dhoni ,Kamal, Baskar, and Dinesh get lockers with the numbers 100, 400, 150, and 25, respectively, who is the most popular student?
(A) Dhoni
(B) Baskar
(C) Kamal
(D) Dinesh
(E) They have equal popularity
Rationale: Distinct prime factors of 100 (Dhoni) : 2,5
Distinct prime factors of 400 (Kamal): 2 and 5.
Distinct prime factors of 150 (Baskar): 2,3, and 5
Distinct prime factors of 25 (Dinesh): 5.
So most popular student - Dinesh
Answer B
Answer: (B) Baskar
Question: A farmer used 1,034 acres of land for beans, wheat, and corn in the ratio of 5 : 2 : 4, respectively. How many acres Q were used for corn?
(A)  188
(B)  258
(C)  376
(D)  470
(E)  517
Rationale: consider 5x acres of land used for bean
consider 2x acres of land used for wheat
consider 4x acres of land used for corn
Total given is 1034 acres
11x =1034
x = 94
land used for corn Q= 4 * 94 = 376
correct option - C
Answer: (C)  376
Question: n denotes the number obtained when n is rounded to the nearest tenth.
For example 4.31 = 4.3
0.089 - 1.135 =
(A) 1.05
(B) 1.04
(C) -1.05
(D) -1.0
(E) -0.1
Rationale: Here Let the first quantity be A=> A rounded to nearest tenths => 0.1
Similarly let the second quantity be B => B rounded to nearest tenths => 1.1=> A-B=0.1-1.1=-1
Hence A-B=-1
ANSWER:D
Answer: (D) -1.0