mathewhe/aqua_rat huggingface dataset:
Question: A man has Rs. 544 in the denominations of one-rupee notes, five-rupee notes and ten rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has?
(A) 102
(B) 60
(C) 75
(D) 90
(E) 95
Rationale: Let number of notes of each denomination be x.
Then x + 5x + 10x = 544
16x = 544
x = 34.
Hence, total number of notes = 3x = 102
Answer: Option A
Answer: (A) 102
Question: Two numbers have a H.C.F of 9 and a product of two numbers is 1800. Find the L.C.M of the two numbers?
(A) 200
(B) 150
(C) 160
(D) 170
(E) 180
Rationale: L.C.M of two numbers is given by
(Product of the two numbers) / (H.C.F of the two numbers) = 1800/9 = 200.
ANSWER:A
Answer: (A) 200
Question: eight books consisting of 5 financial management, 2 marketing management and Since the denominator will be 11! . And there is no way to divide 11 from numerator and denominator. Use a multiple of 11 in the denominator only answer 1 system management are placed on a shelf at random order. What is the probability that the books of each kind are all together.
(A) 1/1155
(B) 1/5040
(C) 1/256
(D) 1/2255
(E) 1/1455
Rationale: Since the denominator will be 8! . And there is no way to divide8 from numerator and denominator. Use a multiple of 8in the denominator only answer
C
Answer: (C) 1/256
Question: The cost of 3 kg of sugar is $ 60. What will the cost of 8 kg of sugar be?
(A) 20
(B) 40
(C) 80
(D) 160
(E) 180
Rationale: This is a situation of direct variation, now we solve using unitary method.
Cost of 3 kg of sugar = $ 60
Cost of 1 kg of sugar = $ 60/3 = $ 20
Cost of 8 kg of sugar = $ 20 × 8
Therefore, cost of 8 kg of sugar = $ 160
ANSWER -D
Answer: (D) 160
Question: Nancy works 4 days per week at a rate of x dollars per day. If Nancy works more than 3 days per week, any extra days are paid at double her normal rate. Nancy worked 4 weeks with no overtime, and then worked 3 more weeks, each with y days of overtime. Which of the following represents Nancy’s total earnings over this period?
(A) a) 3y(7x+2xy)
(B) b) 3x+12y
(C) c) 3xy(7x+2)
(D) d) 3x(2y+7)
(E) e) 2x(3y+4)
Rationale: Payment of a week for 3 days a week = $4x
Payment of 4 weeks for 3 days a week = $4x*4 = $16x
Payment of a week for y days overtime a week = $4x+$2xy
Payment of 3 weeks for y days overtime a week = ($4x+$2xy)*3
Total Earnings = $16x + ($4x+$2xy)*3 = 28x+6xy =2x(3y+14)
Answer: option E
Answer: (E) e) 2x(3y+4)
Question: If the number 97215 * 6 is completely divisible by 11, then the smallest whole number in place of * will be:
(A) 2
(B) 4
(C) 6
(D) 3
(E) 8
Rationale: D
3
Given number = 97215x6
(6 + 5 + 2 + 9) - (x + 1 + 7) = (14 - x), which must be divisible by 11.
x = 3
Answer: (D) 3
Question: If y = ||x – 3| – 2|, for how many values of x is y = 5?
(A) 2
(B) 1
(C) 3
(D) 4
(E) 5
Rationale: y = ||x – 3| – 2| can be 4 only and only when X-3= +/-7. so there are 2 values of X
Answer : A
Answer: (A) 2
Question: Sid left a job paying $75,000 per year to accept a sales job paying $45,000 per year plus 15 percent commission. If each of his sales is for $750, what is the least number of sales he must make per year if he is not to lose money because of the change?
(A) 40
(B) 200
(C) 266
(D) 267
(E) 600
Rationale: In order not to lose money because of the change Sid's total commission must beat least$75,000-$45,000=$30,000, so total sales must beat least$30,000/0.15=$200,000. Which means that he must makeat least$200,000/750=800/3=266.6 sales, so 267 sales.
Answer: D.
Answer: (D) 267
Question: An error 6% in excess is made while measuring the side of a square. What is the percentage of error in the calculated area of the square?
(A) 14.05%
(B) 14.02%
(C) 14%
(D) 13%
(E) 12.36%
Rationale: Percentage error in calculated area
=(6+6+(6Ã—6)/100)%
=12.36%
ANSWER:E
Answer: (E) 12.36%
Question: A group of men decided to do a work in 50days, but 10 of them became absent. If the rest of the group did the work in 60days, Find the original number of men?
(A) 60
(B) 50
(C) 40
(D) 100
(E) 25
Rationale: Original number of men = 10*60 / (60-50) = 60
Answer is A
Answer: (A) 60
Question: What is the total number of ways in which Dishu can distribute 9 distinct gifts among his 8 distinct girlfriends such that each of them gets at least one gift?
(A) 72 * 8!
(B) 144 * 8!
(C) 36 * 8!
(D) 9!
(E) None of these
Rationale: Solution:
As every girl friend should get one gift.
The number of ways 8 distinct gifts can be selected is: 9C8 = 9 ways.
The number of ways each GF gets one gift each out of these 8 selected gifts 8!
Total number of ways 8 gifts can be distributed is 9 *8!.
Now the last one gift can be given to any of the 8 GF hence, the total number of ways of distributing =(9 *8! *82)= 36 * 8! ways.
Answer: Option C
Answer: (C) 36 * 8!
Question: The area of a rectangle is 63 sq m. The width is two meters shorter than the length. What is the width?
(A) 9
(B) 7
(C) -9
(D) 11
(E) 6
Rationale: a = l x w
w = l - 2
l = w + 2
a = (w + 2 ) x w
a = w^2 + 2 x w
63 = w^2 + 2w
0 = w^2 + 2w - 63
0 = (w + 9)(w - 7)
w = -9 and w = 7, width cannot be negative so w = 7
Answer is B
Answer: (B) 7
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 30 ps per meter is?
(A) s.122
(B) s.105
(C) s.125
(D) s.120
(E) s.121
Rationale: 3x * 2x = 3750 => x = 25
2(75 + 30) = 210 m
210 * 1/2 = Rs.105
Answer:B
Answer: (B) s.105
Question: In what time will Rs.4000 lent at 3% per annum on simple interest earn as much interest as Rs.5000 will earn in 5 years at 4% per annum on simple interest?
(A) 8 1/3
(B) 8 1/9
(C) 8 1/6
(D) 8 1/2
(E) 8 1/1
Rationale: (4000*3*R)/100 = (5000*5*4)/100
R = 8 1/3
Answer: A
Answer: (A) 8 1/3
Question: In one hour a boat goes 11 km long the stream and 5 km against the stream.The speed of the boat in still water is?
(A) 7
(B) 8
(C) 6
(D) 5
(E) 1
Rationale: Speed in still water A = ½ ( 11+5) km/hr A= 8 kmph
Answer: A
Answer: (A) 7
Question: what is the value of y if the greatest common divisor of (y-4)!,(y+1)!, and (y+2)! is 720.
(A) 12
(B) 10
(C) 9
(D) 7
(E) 8
Rationale: GCD of (y-4)!,(y+1)!, and (y+2)! is 720. Find y.
Best way to find n is substitute each of the answer and find out the correct one.
Only option B gave the correct answer.
Option B: 10 and find GCD or 6!, 11! and 12!. 6! itself is 720 and 6! which is contained in the other two factorials. This satisfies the condition, hence answer is 10.
Answer is B.
Answer: (B) 10
Question: The monthly rent of a shop of dimension 18feet × 22feet is Rs.2244. What is the annual rent per square foot of the shop? (a) Rs. 5(2/3)
(A) 43
(B) 56
(C) 68
(D) 87
(E) 92
Rationale: Sol. Monthly rent per square feet = 2244/(18*22)
& Annual rent per square feet
=12*(2244/(18*22))=68
C
Answer: (C) 68
Question: A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
(A) 202
(B) 200
(C) 209
(D) 207
(E) 201
Rationale: The number of ways to select two men and three women = ⁵C₂ * ⁶C₃
= (5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)
= 200
Answer:B
Answer: (B) 200
Question: What will be the fraction of 50%
(A) 1/4
(B) 1/2
(C) 1/10
(D) 1/11
(E) None of above
Rationale: Explanation:
It will 50*1/100 = 1/2
Option B
Answer: (B) 1/2
Question: The average of six integers is 63, and none of these integers is greater than 100. If the average of three of the integers is 65, what is the least possible value of one of the other two integers?
(A) 45
(B) 62
(C) 75
(D) 83
(E) 90
Rationale: When it comes to averages, we know thataverage value = (sum of n values)/n
We can rewrite this into a useful formula:sum of n values = (average value)(n)
The average of five integers is 63
So, the sum of ALL 5 integers = (63)(6) =378
The average of three of the integers is 65
So, the sum of the 3 integers = (65)(3) =195
So, the sum of the 2 REMAINING integers =378-195=183
If the sum of the 2 REMAINING integers =183, and we want to minimize one value, we must MAXIMIZE the other value.
100 is the maximum value so let 1 integer = 100, which means the other must equal 83
Answer: D
Answer: (D) 83
Question: Pipe A can fill a tank in 3 hours. Due to a leak at the bottom, it takes 6 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank?
(A) 67
(B) 88
(C) 4.5
(D) 26
(E) 12
Rationale: Let the leak can empty the full tank in x hours 1/3 - 1/x = 1/6
=> 1/x = 1/2 - 1/6 = 1/4.5
=> x = 4.5 Answer:C
Answer: (C) 4.5
Question: Two pipes A and B can fill a cistern in 12 and 15 minutes respectively. Both are opened together but after 3 minutes A is turned off. After how much more time will the cistern be filled?
(A) 8 1/9
(B) 8 1/0
(C) 8 1/4
(D) 8 1/3
(E) 8 1/1
Rationale: 3/12 + (3 + x)/15 = 1
x = 8 1/4
Answer: C
Answer: (C) 8 1/4
Question: If mn ≠ 0 and 25 percent of n equals 37 1/2 percent of m, what is the value of 12n/m?
(A) 18
(B) 323323
(C) 8
(D) 3
(E) 98
Rationale: Given : 25 percent of n equals 37(1/2) percent of m => (25/100)*n = (75/200)*m => 2n = 3m.
12n/m = 6*2n/m = 6*3m/m = 18. Hence A.
Answer: (A) 18
Question: In a group of 3 boys and 7 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be selected?
(A) 145
(B) 175
(C) 205
(D) 235
(E) 265
Rationale: Number of ways to select four children is 10C4 = 210
Number of ways to choose only girls is 7C4 = 35
Number of ways that at least one boy is selected is 210 - 35 = 175
The answer is B.
Answer: (B) 175
Question: what is the compound interest on rs:30,000 for 4 months at the rate of 5% per annum
(A) 501.13
(B) 502.13
(C) 503.13
(D) 504.13
(E) 505.13
Rationale: it is monthly compound
rate=5/12% per month
30000*(1+5/1200)^4-30000=503.13
ANSWER:C
Answer: (C) 503.13
Question: A company has 15 managers and 75 associates. The 15 managers have an average salary of $120,000. The 75 associates have an average salary of $30,000. What is the average salary for the company?
(A) $35,000
(B) $45,000
(C) $55,000
(D) $65,000
(E) $75,000
Rationale: The 15 managers have an average salary of $120,000. The sum of their salaries is:
sum = (average)*(number of salaries) = $120,000*15 = $1,800,000
The 75 associates have an average salary of $30,000. The sum of their salaries is:
sum = (average)*(number of salaries) = $30,000*75 = $2,250,000
When we add those two sums, we get the total payroll of all 90 employees.
$1,800,000 + $2,250,000 = $4,050,000
So, we have 90 employees, and together they earn $4,050,000, so the average is
average = $4,050,000 ÷90 = $45,000
Answer: B.
Answer: (B) $45,000
Question: The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio o
(A) 6:5
(B) 4:7
(C) 3:5
(D) 5:7
(E) 8:9
Rationale: 4:5
3:2
-------
12:15:10
12:10
==>6.5
ANSWER A
Answer: (A) 6:5
Question: A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average(arithmetic mean) of the other 20 numbers in the list, then n is what fraction Q of the sum of the 21 numbers in the list?
(A)  1/20
(B)  1/6
(C)  1/5
(D)  4/21
(E)  5/21
Rationale: This is how I used to calculate which I think works pretty well:
if you let the average of the 20 other numbers equal a, can you write this equation for sum of the list (S)
n + 20a = S
the question tells us that
n = 4a
plug this back into the first equation and you get that the sum is 24a
4a + 20a = 24a
therefore fraction Q of n to the total would be
4a/24a or 1/6
answer B
Answer: (B)  1/6
Question: A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
Rationale: Speed downstream = d/t = 85/(2 1/2) = 34 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (34 - 18)/2
= 8 kmph
Answer: D
Answer: (D) 8
Question: If p is the sum of consecutive even integers w, x, y, and z, where w < x < y < z, all of the following must be true EXCEPT
(A) z - w = 3(y - x)
(B) p is divisible by 8
(C) The average of w, x, y, and z is odd
(D) p is divisible by 4
(E) w + x + 8 = y + z
Rationale: Just assume that the numbers are 2a, 2a+2, 2a+4 and 2a+6.
p = 2a + 2a+2 + 2a+4 + 2a+6 = 8a + 12
Focus on the easiest options first. You see that p is not divisible by 8. Answer (B)
Answer: (B) p is divisible by 8
Question: Find √? /18 = 4 ?
(A) 76
(B) 5776
(C) 304
(D) 5184
(E) None
Rationale: Answer
Let √N/18= 4
Then √N = 18 x 4 = 72
∴ N = 72 x 72 = 5184.
Correct Option: D
Answer: (D) 5184
Question: A wildlife preserve is being planned for 8,000 rhinoceroses. The preserve is to contain a total of 10,000 acres of watering area, plus 100 acres of grazing area for each rhinoceros. If the number of rhinoceroses is expected to increase by 10 percent, how many thousand acres should the preserve have in order to provide for the increased population?
(A)  340
(B)  330
(C)  320
(D)  310
(E)  890
Rationale: Number of rhinos = 8000
Watering area = 10,000 acres
Number of rhino to increase by 10 percent ,then number of rhino = 8800
Grazing area for a rhino = 100
Total grazing area for 8800 rhinos= 8800 * 100 = 8,80,000
Total area required for the wildlife preserve = 8,80,000 + 10,000 = 8,90,000 = 890 * 1000
Answer E
Answer: (E)  890
Question: A train 560 m long, running with a speed of 63 km/hr will pass a tree in?
(A) 15
(B) 16
(C) 17
(D) 28
(E) 32
Rationale: Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 560 * 2/35 = 32 sec
Answer: Option E
Answer: (E) 32
Question: An old priest fell on a bottom of the well of a church.
The well is 17 inches deep.
At day time, the old priest climbs 5-inches but when at dark he slip back 4 inches.
In how many days priest will come out of the well ?
(A) 13-days
(B) 14-days
(C) 11-days
(D) 19-days
(E) 10-days
Rationale: A
13-days
In 12-days, he will climb 12-inch and when he climbs 5 inch more, he will be out of the well :-)
Answer: (A) 13-days
Question: Sam purchased 20 dozens of toys at the rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. What was his percentage profit?
(A) 5.8%
(B) 5.5%
(C) 5.6%
(D) 2.6%
(E) 5.3%
Rationale: C.P. of 1 toy = 375/12 = Rs. 31.25
S.P of 1 toy = Rs. 33
Profit = 1.75/31.25 * 100 = 28/5 = 5.6%
Answer: C
Answer: (C) 5.6%
Question: A piece of cloth cost Rs 35. if the length of the piece would have been 4m longer and each meter cost Re 1 less , the cost would have remained unchanged. how long is the piece?
(A) 5 mtrs
(B) 10 mtrs
(C) 12 mtrs
(D) 15 mtrs
(E) 18 mtrs
Rationale: If length of piece is x and cost per mtr is C, then
x*C = 35 or C =35/x
(x+4)*(C-1) = 35 or x*C +4C-x -4 =35 or 35+4C-x -4 = 35
4C-x =4
4*(35/x)-x =4
x= 10 mtrs
ANSWER:B
Answer: (B) 10 mtrs
Question: I was x years old 5 years ago. How old shall I be 7 years hence ?
(A) x +5
(B) x + 7
(C) x + 12
(D) x + 13
(E) None of these
Rationale: given that my age 5 years ago is x years
hence my present age be x+5 years
so my age after 7 years from now = x+5+7
which is equal to x+12
ANSWER:C
Answer: (C) x + 12
Question: What is the lowest possible common multiple of 2 distinct integers, each greater than 64?
(A) 68
(B) 69
(C) 130
(D) 68^2
(E) 68·69
Rationale: In order to get the lowest LCM, we have to take the first number as 65 and the next number as its multiple.
So, I can take 65 and 130 as two distinct numbers, such that Lowest LCM = 130.
Answer should be C.
Answer: (C) 130
Question: By selling a bat for Rs.360/- a man loses 10% what is that bat cost price
(A) s.400/-
(B) s.630/-
(C) s.700/-
(D) s.780/-
(E) s.800/-
Rationale: 90 % ------> 360 (90 * 4 = 360)
100 % ------>400 (100 * 4 = 400)
Cost price = Rs.400/-
A)
Answer: (A) s.400/-
Question: An equity analyst needs to select 3 stocks for the upcoming year and rank these securities in terms of their investment potential. If the analyst has narrowed down the list of potential stocks to 6, in how many ways can she choose and rank her top 3 picks?
(A) 210
(B) 150
(C) 120
(D) 420
(E) 840
Rationale: Number of ways of choosing 3 stocks = 6C3
Number of ways of ranking the chosen stocks = 3!
Hence total ways of chosing and ranking = 6C3 * 3!= 120
Correct Option: C
Answer: (C) 120
Question: A car finishes a journey in ten hours at the speed of 65 km/hr. If the same distance is to be covered in five hours how much more speed does the car have to gain?
(A) 8 km/hr
(B) 10 km/hr
(C) 65 km/hr
(D) 16 km/hr
(E) None of these
Rationale: Distance covered by the car = 65 × 10 = 650 km
\ Speed = 650⁄5 = 130 km/hr
\ Speed gain = 130 – 65 = 65 km/hr
Answer C
Answer: (C) 65 km/hr
Question: In what ratio should a variety of rice costing Rs. 6 per kg be mixed with another variety of rice costing Rs. 8.75 per kg to obtain a mixture costing Rs. 7.50 per kg?
(A) 5/6
(B) 4/9
(C) 5/7
(D) 5/2
(E) 5/8
Rationale: Let us say the ratio of the quantities of cheaper and dearer varieties = x : y
By the rule of allegation, x/y = (87.5 - 7.50) / (7.50 - 6) = 5/6
Answer:A
Answer: (A) 5/6
Question: An amount of money is to be distributed among Faruk, Vasim and Ranjith in the ratio 3 : 5 : 6. If Vasims share is Rs. 1500, what is the difference between Faruk's and Ranjith's shares?
(A) s 1200
(B) s 1500
(C) s 1600
(D) s 1900
(E) s 900
Rationale: Explanation :
Let P = Faruk, Q = Vasim, R = Ranjith
Let P = 3x, Q = 5x and R = 6x.
Then, 5x = 1500 ? x = 300. P=900,Q=1500 and R = 1800.
Hence, (R - p) = (1800 - 900) = 900
Answer : E
Answer: (E) s 900
Question: In a mixture of milk and water, the proportion of milk by weight was 80%. If, in a 180 gm mixture, 36 gms of pure milk is added, what would be the percentage of milk in the mixture formed?
(A) 84.33%
(B) 83.39%
(C) 83.93%
(D) 83.93%
(E) 83.33%
Rationale: Explanation:
Percentage of milk in the mixture formed = [80/100 (180) + 36] / (180 + 36) * 100% = (144 + 36)/216 * 100% = 5/6 * 100% = 83.33%.
Answer: Option E
Answer: (E) 83.33%
Question: A bag contains 4 red and 3 green balls. Another bag contains 4 red and 6 green balls. If one ball is drawn from each bag. Find the probability that one ball is red and one is green.
(A) 19/20
(B) 17/20
(C) 3/5
(D) 8/10
(E) 9/40
Rationale: Let A be the event that ball selected from the first bag is red and ball selected from second bag is green.
Let B be the event that ball selected from the first bag is green and ball selected from second bag is red.
P(A) = (4/7) x (3/5) =12/35.
P(B) = (3/7) x (2/5) = 6/35.
Hence, the required probability is P(A) + P(B) which is nothing but 3/5.
ANSWER:C
Answer: (C) 3/5
Question: P and Q can complete a work in 20 days and 12 days respectively. P alone started the work and Q joined him after 4 days till the completion of the work. How long did the work last?
(A) 5 days
(B) 10 days
(C) 14 days
(D) 22 days
(E) 26 days
Rationale: Explanation :
Work done by P in 1 day = 1/20
Work done by Q in 1 day = 1/12
Work done by P in 4 days = 4 × (1/20) = 1/5
Remaining work = 1 – 1/5 = 4/5
Work done by P and Q in 1 day = 1/20 + 1/12 = 8/60 = 2/15
Number of days P and Q take to complete the remaining work = (4/5) / (2/15) = 6
Total days = 4 + 6 = 10
Answer : Option B
Answer: (B) 10 days
Question: A painting crew painted 80 houses. They painted the first y houses at a rate of x houses per week. Then more painters arrived and everyone worked together to paint the remaining houses at a rate of 5.25x houses per week. How many weeks did it take to paint all 80 houses, in terms of x and y?
(A) (320 - y)/(5x)
(B) (y +200)/(5x)
(C) 5(80 - y)/(4x)
(D) (y + 400)/(4x)
(E) (4y + 320)/(5x)
Rationale: Ans B
Plug some numbers
Let y = 40 houses and x = 20
then they painted 20 houses per week
as painters were added to the group , the rate of the group increased to 5.25 x => 5.25 * 20 = 105 houses per week
total time they took = (40/20) + (40/1055) = 2.4 weeks
Putting the values of x and y in equation B
(y +200)/(5x) = (40+200)/5*20 = 240/100 = 2.4
Answer: (B) (y +200)/(5x)
Question: Find the value of y from (12)^3 x 6^4 ÷ 432 = y?
(A) 2345
(B) 3456
(C) 2334
(D) 3456
(E) 5184
Rationale: Given Exp. = (12)3 x 64 = (12)3 x 64 = (12)2 x 62 = (72)2 = 5184
432 12 x 62
E
Answer: (E) 5184
Question: On dividing a number by 357, we get 42 as remainder.On dividing the same number by 17, what will be the remainder ?
(A) 4
(B) 5
(C) 8
(D) 7
(E) 2
Rationale: Let x be the number and y be the quotient.Then,
x=357*y+42
=(17*21*y)+(17*2)+8
=17*(21y+2)+8.
Required number =8.
Answer is C
Answer: (C) 8
Question: A can do a piece of work in 80 days. He works at it for 10 days B alone finishes the remaining work in 42 days. In how much time will A and B working together, finish the work?
(A) 25
(B) 30
(C) 20
(D) 32
(E) None of them
Rationale: Work done by A in 10 days =(1/80*10)=1/8
Remaining work = (1- 1/8) =7/ 8
Now,7/ 8 work is done by B in 42 days.
Whole work will be done by B in (42 x 8/7) = 48 days.
A’s 1 day's work = 1/80 and B's 1 day's work = 1/48
(A+B)'s 1 day's work = (1/80+1/48)=8/240=1/30
Hence, both will finish the work in 30 days.
Answer is B.
Answer: (B) 30
Question: X can do a piece of work in 40days. He works at it for 8days and then Y finished it in 16days. How long will Y take to complete the work?
(A) 10
(B) 12
(C) 15
(D) 18
(E) 20
Rationale: Work done by X in 8days = 8*1/40 = 1/5
Remaining work = 1 - 1/5 = 4/5
4/5 work is done by Y in 16days
Whole work will be done by Y in 16*5/4 = 20days
Answer is E
Answer: (E) 20
Question: It has 20L mixutre conatins milk and water in the ratio 3:5,replace 4 litres of mixture with 4 litres of water what is the final ratio of milk and water.
(A) 2:7
(B) 3:7
(C) 4:7
(D) 5:7
(E) 6:7
Rationale: Full mixture has 7.5L milk 12.5L water if we fetch 4L mixture according to ratio it will be 1.5L milk & 2.5L water,replace this mixture from the water then it will be 6L milk and 14L water then ratio will be 6/14=3:7.
ANSWER:B
Answer: (B) 3:7
Question: Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is
(A) Rs.1550
(B) Rs.1650
(C) Rs.1750
(D) Rs.2000
(E) None
Rationale: Solution
C.I.	=Rs[4000x(1+10/100)²-4000]
Rs.(4000x11/10x11/10-4000)	= Rs.940.
Sum	=Rs. [420x100 /3x8]
= Rs.1750.
Answer C
Answer: (C) Rs.1750
Question: The radius of a semi circle is 35 cm then its perimeter is?
(A) 32.8
(B) 180
(C) 32.1
(D) 32.2
(E) 32.9
Rationale: Diameter 70 cm
1/2 * 22/7 * 70 +70 = 180
Answer : B
Answer: (B) 180
Question: The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is:
(A) 91
(B) 37
(C) 99
(D) 277
(E) 19
Rationale: Explanation:
Required number of students = H.C.F of 1001 and 910 = 9
Answer: A) 91
Answer: (A) 91
Question: A and B start a business with Rs.10000 and Rs.5000 respectively. Hoe should they share their profits at the end of one year?
(A) 1:2
(B) 3:4
(C) 2:5
(D) 3:7
(E) 2:1
Rationale: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
10000 : 5000 => 2:1
ANSWER:E
Answer: (E) 2:1
Question: How many possible ways are there to select 2 stocks at random from 9 stocks?
(A) 36
(B) 38
(C) 40
(D) 42
(E) 44
Rationale: 9C2 = 36
The answer is A.
Answer: (A) 36
Question: The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.1045.What was his original salary?
(A) 900
(B) 950
(C) 1000
(D) 1050
(E) 1100
Rationale: X * (110/100) * (95/100) = 1045
X * (11/10) * (1/100) = 11
X = 1000
ANSWER:C
Answer: (C) 1000
Question: The total car population in a Chennai is 9000 out of which 5000 are made by Honda. Out of every 100 Honda cars, 90 are red in color, but only 60% of the total car population is red. Find the % of non-Honda cars that are red
(A) 22.5%
(B) 21.5%
(C) 20.5%
(D) 12.5%
(E) 10.5%
Rationale: Total Honda brand red cars = 90/100 *5000 = 4500
Total red cars = 60/100*9000 = 5400
No. of Non-Honda cars = 9000-5000 = 4000
No. of Non-Honda red cars = 5400 - 4500 = 900
% of Non-Honda red cars = 900/4000*100 = 22.5%
Answer : A
Answer: (A) 22.5%