mathewhe/aqua_rat huggingface dataset:
Question: A clock is started at noon. By 10 minutes past 8, the hour hand has turned through how many degrees?
(A) 235Â°
(B) 240Â°
(C) 245Â°
(D) 250Â°
(E) 255Â°
Rationale: The angle traced by the hour hand in 12 hrs is 360Â°
The angle traced by the hour hand in 1 hour is 30Â°
The angle traced by the hour hand in 10 minutes is 5Â°
The angle traced by the hour hand in 8 hours and 10 minutes is 8*30Â° + 5Â° = 245Â°
The answer is C.
Answer: (C) 245Â°
Question: A circular well with a diameter of 2 metres , is dug to a depth of 10 metres. What is the volume of the earth dug out?
(A) 32 m3
(B) 31.4 m3
(C) 40 m3
(D) 44 m3
(E) None
Rationale: Solution
Volume	= πr2h
‹=› (22 /7 ×1×1×10)m3
‹=›31.4 m3.
Answer B
Answer: (B) 31.4 m3
Question: Two cars are traveling towards each other. If car A is traveling at a speed of 60 mph and car B is traveling 12% slower, how much time will it take the cars to meet if the initial distance between the two is 705 miles?
(A) Six hours and 30 minutes.
(B) Seven hours and 30 minutes.
(C) Eight hours and 20 minutes.
(D) Nine hours and 15 minutes.
(E) Ten hours and 20 minutes.
Rationale: Speed of second train= 60*88/100= 52.8
Time= toral distance /total speed
705/ (50+52.8)= 705/102.8= 6.___
A is the answer
Answer: (A) Six hours and 30 minutes.
Question: If P represents the product of the first 13 positive integers, which of the following must be true?
I. P is an odd number
II. P is a multiple of 18
III. P is a multiple of 29
(A) I only
(B) II only
(C) III only
(D) None of the above
(E) All of the above
Rationale: Answer = B) II only
Answer: (B) II only
Question: If the sum of 10 consecutive integers is x, which of the must be true?
I. x is even
II. x is odd
III. x is a multiple of 3
(A) I only
(B) II only
(C) III only
(D) I and III
(E) II and III
Rationale: sum of 3 consecutive integers
= (n) + (n+1) + (n+2) ++ (n+3) + (n+4) + (n+5)+(n+6)+(n+7)+(n+8)+(n+9)
=10n+45
= even + odd = odd
= 5(2n+9) = divisible by 5
Hence, x is even and divisible by 5.
Answer: D
Answer: (D) I and III
Question: which of the following could be the greatest common factor of positive integers 4 and 5 ? I) 8 II) 4 III) None of these
(A) III only
(B) II only
(C) I,II only
(D) I only
(E) I,III only
Rationale: 4=1*4
5=1*5
GCF =1
Answer : A
Answer: (A) III only
Question: What profit/loss percent did Ravi earn if he purchased an item of Rs.5,600 and sold it at three-fourth of its cost price?
(A) Loss of 20 percent
(B) Gain of 25 percent
(C) Neither gain or loss
(D) Loss of 15 percent
(E) None of these
Rationale: Explanation:
C.P. = Rs.5600
S.P. = Rs.5600x ¾ = Rs.4200
Loss = Rs.5600-4200 = Rs.1400
Loss percentage = 1400x100/5600 = 25%
Answer: Option B
Answer: (B) Gain of 25 percent
Question: Given 2 numbers; 16 and x, the LCM and HCF of both numbers is 144 and 2 respectively. Find x?
(A) 16
(B) 28
(C) 15
(D) 13
(E) 18
Rationale: HCF x LCM = Product of Numbers
2 x 144 = 16 x x
x = (2 x 144) / 16
x = 18
ANSWER : E
Answer: (E) 18
Question: A cricketer whose bowling average is 12.4 runs per wicket takes 5 wickets for 26 runs and thereby decreases his average by 0.4. The number of wickets taken by him till the last match was:
(A) 64
(B) 72
(C) 80
(D) 85
(E) None of the above
Rationale: Let the number of wickets taken till the last match be x.
Then,
12.4x+26/x+5= 12 ⇒ 12.4x + 26 = 12x + 60
⇒ 0.4x = 34 ⇒ x = 34⁄0.4 = 340⁄4 = 85.
Answer D
Answer: (D) 85
Question: A man buys an article for $20. and sells it for $35. Find the gain percent?
(A) 25%
(B) 50%
(C) 20%
(D) 75%
(E) 30%
Rationale: C.P. = $20
S.P. = $35
Gain = $15
Gain% = 15/20 *100 = 75%
Answer is D
Answer: (D) 75%
Question: A walks around a circular field at the rate of one round per hour while B runs around it at the rate of six rounds per hour. They start in the same direction from the same point at 7.30 a.m. They shall first cross each other at?
(A) 12 min
(B) 17 min
(C) 19 min
(D) 11 min
(E) 16 min
Rationale: Since A and B move in the same direction along the circle, so they will first meet each other when there is a difference of one round between the two.
Relative speed of A and B
= 6 - 1 = 5 rounds per hour.
Time taken to complete one round at this speed
= 1/5 hr
= 12 min.
Answer: A
Answer: (A) 12 min
Question: When x is divided by y, the quotient is t with remainder r. Which of the following is y in terms of r, x, and t? (Assume both y and t are nonzero.)
(A) x – r – t
(B) (x+r)/t
(C) x/t−r
(D) (x−r)/t
(E) xr – t
Rationale: Given that when x is divided y, the quotient is t and remainder is r. This implies x-r is divisible by y and yt=(x-r) or y = (x-r)/t.
Answer D.
Answer: (D) (x−r)/t
Question: In a group of 20 students, each student is registered for at least one of three classes – History, Math and English. 10 students are registered for History, 10 students are registered for Math, and 15 students are registered for English. If only three students are registered for all three classes, how many students are registered for exactly two classes?
(A) 13
(B) 10
(C) 9
(D) 8
(E) 7
Rationale: Each student is registered forat least one of three classesmeans thatthere are no students who are registered for none of the classes.
Total = {people in group A} + {people in group B} + {people in group C} - {people in exactly 2 groups} - 2*{people in exactly 3 groups} + {people in none of the groups}:
20 = 10+10+15 - {people in exactly 2 groups} - 2*3 + 0-->{people in exactly 2 groups}=9
Answer: C
Answer: (C) 9
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?
(A) 177
(B) 190
(C) 188
(D) 1787
(E) 21
Rationale: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 1900 m
T = D/S
T = 1900/10
T = 190 Sec .Answer: B
Answer: (B) 190
Question: Imagine a picture in your mind. There is a rose plant. A few roses have grown up in the plant. There are a few bees hovering over them.
Now read the given statements carefully:
1) If every one of the bees lands on a rose, one of them won't get a rose.
2) If two bees share rise together, then there will be one rose left without any bee.
Can you find out the number of roses on the plant and the number of bees?
(A) There are Four roses and four bees.
(B) There are three roses and four bees.
(C) There are three roses and three bees.
(D) There are five roses and one bees.
(E) There are six roses and four bees.
Rationale: B
There are three roses and four bees.
Answer: (B) There are three roses and four bees.
Question: The number 523fbc is divisible by 7,8,9. Then what is the value of f*b*c
(A) 504
(B) 532
(C) 210
(D) 180
(E) 280
Rationale: LCM of 7, 8 and 9 is 504, thus 523fbc must be divisible by 504.
523fbc=523000+fbc
523000 divided by 504 gives a remainder of 352.
Hence, 352+fbc=k*504.
k=1 fbc=152 --> f*b*c=10
k=2 fbc=656 --> f*b*c=180
As fbc is three digit number k can not be more than 2.
Two answers? Well only one is listed in answer choices, so D.
Answer: D.
Answer: (D) 180
Question: When all the students in a school are made to stand in rows of 54, 30 such rows are formed. If the students are made to stand in rows of 45, how many such rows will be formed ?
(A) 31
(B) 36
(C) 38
(D) 19
(E) 21
Rationale: Explanation:
Total number of students = 54 x 30
When arranged in rows of 45, number of rows formed are,
= 36.
Answer: B
Answer: (B) 36
Question: What least number must besubtracted from 427398 so that remaining no.is divisible by 15?
(A) 725117481
(B) 343564689
(C) 454564690
(D) 759900434
(E) 656590009
Rationale: On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted
Answer: Option A
Answer: (A) 725117481
Question: Complete the sequence:
D F J P ?
(A) M
(B) D
(C) S
(D) F
(E) X
Rationale: D+2=F
F+4=J
J+6=P
P+8=X
E
Answer: (E) X
Question: A 1 k.m. long wire is held by n poles. If one pole is removed, the length of the gap becomes 12/3m. What is the number of poles initially?
(A) 500
(B) 501
(C) 502
(D) 503
(E) 504
Rationale: Length after removing pole is 12/3 = 4
Then before removing pole is 2 ('coz | 2 | 2 | is | 4 |)
i.e. Gap between two poles is 2m
1km = 1000m
Then split 1000m by 2m => we have 500 sections or gaps
Then no.of poles is 500 + 1st pole = 501 poles
Therefore n = 501.
ANSWER:B
Answer: (B) 501
Question: If an article is sold at 18% profit instead of 9% profit, then the profit would be $72 more. What is the cost price?
(A) $500
(B) $600
(C) $700
(D) $800
(E) $900
Rationale: 9% * cost price = $72
1% * cost price = $72 / 9 = $8
The cost price is $800.
The answer is D.
Answer: (D) $800
Question: Some of 50%-intensity red paint is replaced with 20% solution of red paint such that the new paint intensity is 40%. What fraction of the original paint was replaced?
(A) 1/3
(B) 1/5
(C) 2/3
(D) 3/4
(E) 4/5
Rationale: 40% is 20%-points above 20% and 10%-points below 50%.
Thus the ratio of 20%-solution to 50%-solution is 1:2.
1/3 of the original paint was replaced.
The answer is A.
Answer: (A) 1/3
Question: 45 workers work 8 hours to dig a hole 30 meters deep. How many extra workers should be hired to dig another hole 35 meters deep by working for 6 hours?
(A) 10
(B) 20
(C) 30
(D) 40
(E) 50
Rationale: 45 workers * 8 hours / 30 meters = x * 6 / 35
x = 70 total workers
70 - 45 = 30 new workers
The answer is C.
Answer: (C) 30
Question: A train running at the speed of 60 km/hr crosses a pole in 18 seconds. What is the length of the train?
(A) 187 m
(B) 278 m
(C) 300 m
(D) 150 m
(E) 267 m
Rationale: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train
= (Speed x Time)
= (50/3 * 18) m
= 300 m.
Answer: C
Answer: (C) 300 m
Question: Suresh can complete a job in 15 hours. Ashutosh alone can complete the same job in 15 hours. Suresh works for 9 hours and then the remaining job is completed by Ashutosh. How many hours will it take Ashutosh to complete the remaining job alone?
(A) 4
(B) 5
(C) 6
(D) 12
(E) None of these
Rationale: The part of job that Suresh completes in 9 hours
= 9â„15 = 3â„5
Remaining job = 1 - 3â„5 = 2â„5
Remaining job can be done by Ashutosh in 2â„5 Ã— 15 = 6 hours
Answer C
Answer: (C) 6
Question: There is a 20% chance Sandy will visit China this year, while there is a 70% chance that she will visit Malaysia this year. What is the probability that Sandy will visit either China or Malaysia this year, but NOT both?
(A) 44%
(B) 48%
(C) 54%
(D) 62%
(E) 70%
Rationale: P(China and not Malaysia) = 0.2*0.3 = 0.06
P(Malaysia and not China) = 0.7*0.8 = 0.56
Total probability = 0.06 + 0.56 = 0.62 = 62%
The answer is D.
Answer: (D) 62%
Question: 10, 14, 16, 18, 21, 24, 26
(A) 17
(B) 20
(C) 21
(D) 25
(E) 26
Rationale: Each of the numbers except 21 is an even number
ANSWER :C
Answer: (C) 21
Question: Sachin is younger than Rahul by 7 years. If the ratio of their ages is 7:9, find the age of Sachin
(A) 24.5
(B) 25.5
(C) 26.5
(D) 27.5
(E) 37.5
Rationale: Explanation:
If Rahul age is x, then Sachin age is x - 7,
so, (X-7)/X= 79
9x - 63 = 7x
2x = 63
x = 31.5
So Sachin age is 31.5 - 7 = 24.5. Answer: A
Answer: (A) 24.5
Question: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
(A) 10.2
(B) 10.9
(C) 10.1
(D) 10.8
(E) 10.5
Rationale: Explanation:
Relative speed = (60 + 40) km/hr =[ 100 x ( 5 / 18 ) ]m/sec = ( 250 /9 ) m/sec.
Distance covered in crossing each other = (140 + 160) m = 300 m.
Required time = [ 300 x ( 9/250 ) ] sec = ( 54/ 5 )sec = 10.8 sec.
Answer: D) 10.8
Answer: (D) 10.8
Question: Insert the missing number. 2, 7, 10, 22, 18, 37, 26
(A) 52
(B) 42
(C) 62
(D) 46
(E) 25
Rationale: There are two series here
2, 10, 18, 26, ... (Increase by 8)
7, 22, 37, ... (Increase by 15)
Hence, next term is 37+15 = 52
ANSWER A
Answer: (A) 52
Question: Rs. 800 becomes Rs. 956 in 3 years at a rate of S.I. If the rate of interest is increased by 4%, what amount will Rs. 800 become in 3 years?
(A) Rs. 1152
(B) Rs. 1052
(C) Rs. 1252
(D) Rs. 1452
(E) Rs. 2052
Rationale: S.I. = (956 - 800) = Rs. 156.
Rate = (100 * 156) / (800 * 3) = 6 1/2 %
Now rate = (6 1/2 + 4) = 10 1/2 %
New S.I. = (800 * 21/2 * 3/100) = Rs. 252
New amount = (800 + 252) = Rs. 1052.
ANSWER:B
Answer: (B) Rs. 1052
Question: In a certain business school class, p students are accounting majors, q students are finance majors, r students are marketing majors, and s students are strategy majors. If pqrs = 2145, and if 1< p < q < r < s, how many students in the class are marketing majors?
(A) 3
(B) 5
(C) 8
(D) 11
(E) 17
Rationale: pqrs = 2145 = 3 * 5 * 11 * 13
Since 1< p < q < r < s, the number of students who are marketing majors is r = 11.
The answer is D.
Answer: (D) 11
Question: one person Tharak speed with the current is 12 km/hr and the speed of the current is 5 km/hr. Tharak's speed against the current is:
(A) 0 km/hr
(B) 1 km/hr
(C) 2 km/hr
(D) 3 km/hr
(E) 4 km/hr
Rationale: Man's speed with the current = 12 km/hr
=> speed of the man + speed of the current = 12 km/hr
speed of the current is 5 km/hr
Hence, speed of the man = 12-5 = 7 km/hr
man's speed against the current = speed of the man - speed of the current
= 7-5 = 2 km/hr
ANSWER:C
Answer: (C) 2 km/hr
Question: The function f is defined for all positive integers n by the following rule. f(n) is the number of positive integers each of which is less than n and has no positive factor in common with n other than 1. If p is any prime, number then f(p)=
(A) p-1
(B) p-2
(C) (p+1)/2
(D) (p-1)/2
(E) 2
Rationale: p is a prime, all positive numbers less than p have no common factors with p (except common factor 1). So there would be p-1 such numbers (as we are looking number of integers less than p).
For example: if p=7 how many numbers are less than 7 having no common factors with 7: 1, 2, 3, 4, 5, 6 --> 7-1=6.
Answer: A.
Answer: (A) p-1
Question: A walks at 10 kmph and 5 hours after his start, B cycles after him at 20 kmph. How far from the start does B catch up with A?
(A) 100km
(B) 150km
(C) 50km
(D) 120km
(E) 200km
Rationale: Suppose after x km from the start B catches up with A. Then, the difference in the time taken by A to cover x km and that taken by B to cover x km is 5 hours.
x/10 - x/20 = 5
x = 100 km
Answer is A
Answer: (A) 100km
Question: A grocer has a sale of Rs. 5420, Rs. 5660, Rs. 6200, Rs. 6350 and Rs. 6500 for 5 consecutive months. Find the sale he should have in the sixth month, so that he gets an average sale of Rs. 6400?
(A) Rs. 5870
(B) Rs. 8270
(C) Rs. 6020
(D) Rs. 6850
(E) None of these
Rationale: Explanation:
Total sale for 5 months = Rs. (5420 + 5660 + 6200 + 6350 + 6500) = Rs. 30,130
Therefore, required sale = Rs. [(6400 * 6) – 30,130] = Rs. (38400 – 30,130) = Rs. 8270
ANSWER B
Answer: (B) Rs. 8270
Question: In a game, a player can win by getting six consecutive tails in seven throws of a coin. What is the probability of winning if the player gets a tail on the first throw?
(A) 1/8
(B) 1/16
(C) 1/32
(D) 1/64
(E) 1/128
Rationale: The only way to win is to get a tail on each of the next five throws.
P(five tails)=(1/2)^5=1/32
The answer is C.
Answer: (C) 1/32
Question: Given two sets X = {1,1,8,8,9,9} and Y = {0,1}, if one number is chosen from each set at random, what is the probability that the sum of both numbers is an even number
(A) 1/5
(B) 1/3
(C) 1/6
(D) 1/4
(E) 1/2
Rationale: One way to look at it:
The number from set X can be ANYTHING.
The number selected from set Y will determine whether the sum is odd or even.
For example, if a 8 is selected from set X, we need a 0 from set Y to get an even sum.
If a 9 is selected from set X, we need a 1 from set Y to get an even sum.
And so on.
So, P(sum is even) = P(select ANY number from set X ANDselect the number from set Y that makes the sum even)
= P(select ANY number from set X)xP(select the number from set Y that makes the sum even)
= 1x1/2
= 1/2
= E
Answer: (E) 1/2
Question: fetched a total simple interest of Rs. 4216.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?
(A) Rs.8928
(B) Rs.89228
(C) Rs.8911
(D) Rs.8925
(E) Rs.8922
Rationale: Explanation:
Principal = Rs.
= Rs.
= Rs.8925
Answer: D
Answer: (D) Rs.8925
Question: Jack and Jill are marathon runners. Jack can finish a marathon (42 km) in 2.5 hours and Jill can run a marathon in 4.2 hours.What is the ratio of their average running speed? (Jack: Jill)
(A) 41/25
(B) 15/14
(C) 4/5
(D) 5/4
(E) Cannot be determined
Rationale: Average Speed of Jack =Distance/ Time
= 42 /(5/2) = 84/5
Average Speed of Jill = 42/(4.2) = 10
Ratio of Average speed of Jack to Jill = (84/5)/10 = 84/50 = 41/25
Answer A
Answer: (A) 41/25
Question: If a man travels m miles an hour for t hours and r miles an hour for s hours, what is his average rate in miles per hour for the entire distance traveled?
(A) mt + rs
(B) (mt + rs)/2
(C) (mt + rs)/(t + s)
(D) t/m + s/r
(E) (mt + rs)/(t - s)
Rationale: Average Speed = Total Distance /Total Time Taken
Total Distance travelled in t hours = mt
Total Distance travelled in s hours = rs
Total Time taken = t+s
Therefore , Average Speed = (mt+ts)/(t+s)
Answer C
Answer: (C) (mt + rs)/(t + s)
Question: At Veridux Corporation, there are 250 employees. Of these, 90 are female, and the rest are males. There are a total of 40 managers, and the rest of the employees are associates. If there are a total of 140 male associates, how many female managers are there?
(A) 15
(B) 20
(C) 25
(D) 30
(E) 35
Rationale: 250 Employees:
90 Male, 160 Female
40 Managers, 210 Associates
140 Male Associates implies 70 Female Associates which means the remaining 20 females must be Managers
B. 20
Answer: (B) 20
Question: Raman mixed 34 kg of butter at Rs. 150 per kg with 36 kg butter at the rate of Rs. 125 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
(A) 129
(B) 287
(C) 192
(D) 188
(E) 112
Rationale: Explanation:
CP per kg of mixture = [34(150) + 36(125)]/(34 + 36) = Rs. 137.14
SP = CP[(100 + profit%)/100]
= 137.14* [(100 + 40)/100] = Rs. 192.
Answer:C
Answer: (C) 192
Question: The number 250 can be written as sum of the squares of 3 different positive integers. What is the sum of these 3 different integers?
(A) 18
(B) 22
(C) 21
(D) 20
(E) 19
Rationale: sum of the squares of 3 different positive integers = 250
15^2 + 3^2 + 4^2 = 250
now,
sum of these 3 different integers = 15 + 3 + 4 = 22
Ans - B
Answer: (B) 22
Question: The cost price of a radio is Rs.1340 and it was sold for Rs.1210, find the loss %?
(A) 18%
(B) 9%
(C) 22%
(D) 24%
(E) 21
Rationale: 1340 ---- 130
100 ---- ? => 9%
Answer:B
Answer: (B) 9%
Question: What will be the compound interest on a sum of Rs. 25,000 after 3 years at the rate of 12% p.a.?
(A) Rs. 9000.30
(B) Rs. 9720
(C) Rs. 10123.20
(D) Rs. 10483.20
(E) None
Rationale: Amount = [25000 * (1 + 12/100)3]
= 25000 * 28/25 * 28/25 * 28/25 = Rs. 35123.20
C.I. = (35123.20 - 25000) = Rs. 10123.20
ANSWER:C
Answer: (C) Rs. 10123.20
Question: A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
(A) 1
(B) 3
(C) 5
(D) 6
(E) 7
Rationale: Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
B)
Answer: (B) 3
Question: A certain no. when divided by 65 leaves a remainder 25, what is the remainder if the same no.be divided by 15?
(A) 3
(B) 4
(C) 6
(D) 8
(E) 9
Rationale: Explanation:
65 + 25 = 90/15 = 6 (Remainder)
C
Answer: (C) 6
Question: A family has two children. find the probability that both the children are boys given that at least
one of them is a boy?
(A) 1/3
(B) 2/3
(C) 2/5
(D) 3/7
(E) 3/11
Rationale: Let b stand for girl and g for boy. The sample space of the experiment is
S = {(g, g), (g, b), (b, g), (b, b)}
Let E and F denote the following events :
E : ‘both the children are boys’
F : ‘at least one of the child is a boy’
Then E = {(g,g)} and F = {(g,g), (g,b), (b,g)}
Now E n F = {(g,g)}
Thus P(F) = 3/4
and P (E n F )= 1/4
Therefore P(E|F) = P(E ∩ F)/P(F) = (1/4)/(3/4) = 1/3
A)
Answer: (A) 1/3
Question: A crate of mangoes contains one bruised mango for every thirty mango in the crate. If three out of every four bruised mango are considerably unsaleable and there are 12 unsaleable mangoes in the crate then how many mango are there in the crate?
(A) 480
(B) 580
(C) 680
(D) 280
(E) 380
Rationale: Let the total no of mangoes in the crate be x
Then the no of bruised mango = 1/30 x
Let the no of unsalable mangoes =3/4 (1/30 x)
1/40 x =12
x=480
Answer is A.
Answer: (A) 480
Question: An amount of money is to be divided between Ram, Raja and Rahim in the ratio of 1:4:10. If the difference between the shares of Ram and Raja is Rs.300, what will be the difference between Raja and Rahim's share?
(A) 600
(B) 3000
(C) 2866
(D) 2999
(E) 2678
Rationale: 4-1 = 3 --- 300
10-4 = 6 => 300/3*6= 600
Answer: A
Answer: (A) 600
Question: {8,4,6,5,3,12,7}
What number should be inserted in the set of 7 values to get a median of 9?
(A) 20
(B) 14
(C) 16
(D) 5
(E) 8
Rationale: Median is the middle number of a sorted distribution. In case of even number of items, Median will be the average of middle two values.
The question asks fora new number that will cause the median of new set at 9.
Mentionable that given set is already sorted and number of items of new set will be 7+1 = 8.
To get median 9,the sum of 4th5th Term should be 18 and it's 5+14.
So to keep the median 9, the new item should be >=14.
The answer is B
Answer: (B) 14
Question: The average runs scored by a batsman in 20 matches is 30. In the next 10 matches the batsman scored an average of 15 runs. Find his average in all the 30 matches?
(A) 25
(B) 46
(C) 88
(D) 13
(E) 12
Rationale: Total score of the batsman in 20 matches = 600.
Total score of the batsman in the next 10 matches = 150.
Total score of the batsman in the 30 matches = 750.
Average score of the batsman = 750/30 = 25.
Answer:A
Answer: (A) 25
Question: What is the probability of flipping a fair coin three times and the coin landing on heads on all three flips?
(A) 3/8
(B) 5/8
(C) 7/8
(D) 1/8
(E) 1/4
Rationale: Probability = (Favorable combination)/(Total combination)
Favorable combination = (HHH) ==> 1
Total combination = 8 (2^3)
Probability = (1)/(8)
(D)
Answer: (D) 1/8
Question: If {x} is the product of all even integers from 1 to x inclusive, what is the greatest prime factor of {20} + {24}?
(A) 23
(B) 25
(C) 11
(D) 5
(E) 2
Rationale: Soln:
{24} + {20} = 24*{20} +{20} = 25*{20}
ANSWER:B
Answer: (B) 25
Question: There are 4 red books and 4 blue books on a shelf. If 2 books are selected at random from the shelf, what is the probability that both books selected are red books?
(A) 2/7
(B) 3/7
(C) 3/14
(D) 5/28
(E) 9/28
Rationale: The number of ways of choosing 2 books from the shelf is 8C2 = 28.
The number of ways of choosing 2 red books is 4C2 = 6.
P(2 red books) = 6/28=3/14.
The answer is C.
Answer: (C) 3/14
Question: The distance between two cities A and B is 1410 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
(A) 09 PM
(B) 07 PM
(C) 11 PM
(D) 05 AM
(E) 03 AM
Rationale: Explanation:
Suppose they meet x hrs after 8 a.m
then,
[Distance moved by first in x hrs] + [Distance moved by second in (x-1) hrs] = 1410.
Therefore, 60x + 75(x-1) = 1410.
=> x=3.
So,they meet at (8+11) i.e, 7 PM.
Answer: B
Answer: (B) 07 PM
Question: A, B and C can do a work in 6, 8 and 12 days respectively doing the work together and get a payment of Rs.1800. What is B’s share?
(A) 600
(B) 277
(C) 688
(D) 268
(E) 279
Rationale: WC = 1/6:1/8:1/12 => 4:3:2
3/9 * 1800 = 600
Answer:A
Answer: (A) 600