mathewhe/aqua_rat huggingface dataset:
Question: In the next Cricket World Cup T-20, Team A has decided to score 200 runs only through 4s and 6s. In how many ways can the Team A score these 200 runs?
(A) 13
(B) 15
(C) 16
(D) 17
(E) 18
Rationale: Team A can score a maximum of 50 fours and a minimum of 2 fours with an interval or spacing of 3 units to accommodate the 6's.
So the number of fours scored forms an AP 2, 5, 8, ... 50 with a common difference of 3.
Number of ways of scoring 200 only through 4's and 6's = (50 - 2)/3 + 1 = 17
Answer: D
Answer: (D) 17
Question: A photo-mat shop charges $0.60 for the first photo inside a film, and 40% cents less for each additional photo. How many photos can we develop with $42 if each film contains 36 photos?
(A) 3 films and 6 photos
(B) 5 films and 6 photos
(C) 5 films and 14 photos
(D) 6 films and 4 photos
(E) 6 films and 28 photos
Rationale: 1st photo = 0.60
Subsequent = 0.6*0.6=0.36
Price of 1 full film=0.6+0.36*35=13.2
Price of 3 full film = 13.2*3=39.6
42-39.6=2.4
2.4=0.6+0.36x
x=5
42--->3 full films and 1+5=6 photos
Answer: A
Answer: (A) 3 films and 6 photos
Question: 1000 men have provisions for 20 days. If 200 more men join them, for how many days will the provisions last now?
(A) 12.8
(B) 12.6
(C) 12.5
(D) 12.2
(E) 16.6
Rationale: 1000*20 = 1200*x
x = 16.6.Answer: E
Answer: (E) 16.6
Question: The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 70 percent of the pollutant?
(A)  $200,000
(B)  $100,000
(C)  $50,000
(D)  $10,000
(E)  $5,000
Rationale: To remove 90% of pollutant
C= 100,000(90)/(100-90) = 900,000
To remove 70% of pollutant
C' = 100,000(70)/(100-70) = 700,000
Difference = C - C' = 200,000
Answer - A
Answer: (A)  $200,000
Question: A fair sided die labeled 1 to 6 is tossed three times. What is the probability the sum of the 3 throws is 16?
A)
B)
C)
D)
E)
(A) 1/6
(B) 7/216
(C) 1/36
(D) 9/216
(E) 11/216
Rationale: The sum of 16 is obtained if the dices show: (6, 5, 5) or (6, 6, 4).
Each can occur in 3!/2!=3 ways, for example we can get (6, 5, 5) in 3 ways: (6, 5, 5), (5, 6, 5), (5, 5, 6), permutation of three items (6, 6, 5) out of which 2 5's are identical.
So, # of favorable outcomes is 2*3=6;
Total # of outcomes is 6*6*6=216;
P=favorable/total=6/216=1/36.
Answer: C
Answer: (C) 1/36
Question: How many leading zeros (zeros after the decimal point but before the first nonzero digit of a number) are in 1/7!?
(A) 1
(B) 3
(C) 5
(D) 6
(E) 9
Rationale: 7! = 7*6*5*4*3*2*1
= 5040
1/7! = 1/5040
=[1/(5.04)] * 10^-3
1/(5.04) will be approximately lesser than .2
Number of leading zeros will be 3
Answer B
Answer: (B) 3
Question: How many 6's are there in the following number sequence which are immediately preceded by 9 but not immediately followed by 4 ?
5 6 4 3 2 9 6 3 1 6 4 9 6 4 2 1 5 9 6 7 2 1 4 7 4 9 6 4 2
(A) 1
(B) 3
(C) 2
(D) 5
(E) None
Rationale: Answer: C . 2
Answer: (C) 2
Question: In a jar there are balls in different colors: blue, red, green and yellow.
The probability of drawing a blue ball is 1/8.
The probability of drawing a red ball is 1/5.
The probability of drawing a green ball is 1/7.
If a jar cannot contain more than 50 balls, how many yellow balls are in the Jar?
(A) 27
(B) 26
(C) 24
(D) 23
(E) 21
Rationale: answer of 1st
just add the given probabilities p(blue)+p(red)+p(green) i.e
1/8+1/5+1/7=35+56+40/280 =131/280
now we know p(blue)+p(red)+p(green)+p(yellow)=1
131/280+p(yellow)=1
p(yellow)= 149/280 =21/40
i.e why yellow balls are 21.
E
Answer: (E) 21
Question: If after 200 grams of water were added to the 15%-solution of alcohol, the strength of the solution decreased by one-third, how much of the 15%-solution was used?
(A) 180 grams
(B) 220 grams
(C) 250 grams
(D) 350 grams
(E) 400 grams
Rationale: The 15% alcohol solution decreases by 1/3 once the 200 grams of water is added so 200/.05 =4000*.1% (2/3 of 15%) is 400 grams, thus answer is E.
Answer: (E) 400 grams
Question: Find the unknown term X,8,6,2,-4, -12
(A) 2
(B) 4
(C) 6
(D) 8
(E) 9
Rationale: X,8,6,2,-4, -12
i guess each differ in d range of 2
8 - 8 = 0
8 - 6 = 2
6 - 2 = 4
2 - 6 = -4
-4 - 8 = -12
ANSWER:D
Answer: (D) 8
Question: How many even integers n, such that 20<=n<=250 are of the form 3k+4, where k is any natural number?
(A) 33
(B) 36
(C) 39
(D) 42
(E) 45
Rationale: The first number is 22 = 16+6(1).
We can continue adding 6 to make a list: 22, 28, 34,...
The last number is 250 = 16+6(39)
There are 39 numbers in the list.
The answer is C.
Answer: (C) 39
Question: If it takes 4 identical printing presses exactly 6 hours to print 8,000 newspapers, how long would it take 2 of these presses to print 6,000 newspapers?
(A) 5 hrs
(B) 7 hrs
(C) 8 hrs
(D) 9 hrs 50 mins
(E) 9 hrs
Rationale: 4 presses - 8,000 newspapers - 6 hours ;
2 presses - 4,000 newspapers - 6 hours ; (360 mins)
2 presses - 6,000 newspapers - 360/4000*6000 = 540 mins = 9 hrs
Answer : E
Answer: (E) 9 hrs
Question: A girl swims downstream 48 km and upstream 16 km taking 8 hours each time; what is the speed of the current?
(A) 2.0
(B) 2.1
(C) 2.2
(D) 2.3
(E) 2.4
Rationale: 48 --- 8 DS = 6
? ---- 1
16 ---- 8 US = 2
? ---- 1 S = ?
S = (6 - 2)/2 = 2
Answer:A
Answer: (A) 2.0
Question: A reduction of 25% in the price of salt enables a lady to obtain 10kgs more for Rs.100, find the original price per kg?
(A) s.2.8
(B) s.2.4
(C) s.2.5
(D) s.2.2
(E) s.3.33
Rationale: 100*(25/100) = 25 --- 10
? --- 1 => Rs.2.5
100 --- 75
? --- 2.5 => Rs.3.33
Answer:E
Answer: (E) s.3.33
Question: In business, A and C invested amounts in the ratio 2:1, whereas the ratio between amounts invested by A and B was 2:3, If Rs 15,0000 was their profit, how much amount did B receive.
(A) 12653
(B) 14587
(C) 36975
(D) 75000
(E) 12874
Rationale: Explanation:
A:B = 2:3= 2:3
=> A:C = 2:1 = 2:1
=> A:B:C = 2:3:1
B share = (3/6)*150000
= 75000
Option D
Answer: (D) 75000
Question: What least number must be added to 1170, so that the sum is completely divisible by 23 ?
(A) 3
(B) 5
(C) 7
(D) 9
(E) 11
Rationale: 51*23 = 1173
1173 - 1170 = 3
Answer : A
Answer: (A) 3
Question: Consider two different cloth-cutting processes. In the first one, n circular cloth pieces are cut from a square cloth piece of side a in the following steps: the original square of side a is divided into n smaller squares, not necessarily of the same size, then a circle of maximum possible area is cut from each of the smaller squares. In the second process, only one circle of maximum possible area is cut from the square of side a and the process ends there. The cloth pieces remaining after cutting the circles are scrapped in both the processes. The ratio of the total area of scrap cloth generated in the former to that in the latter is
(A) 1:1
(B) sqrt 2 : 1
(C) n(4-π) / (4n - π)
(D) (4n − π) / n (4 - π)
(E) None of these
Rationale: Explanation :
Consider the square of side x, then its area will be x2.
The area of largest circle = π(x/2)2
which can be cut from square πx2/4 .
Therefore, area scrapped = x2 - πx2/4 = x2 (1 - π/4).
Hence,
=> the area scrapped / Area of square
=> x2 (1 - π/4) / x2
=> 1 - π/4 =constant.
As this ratio is constant, whether we cut a circle from smaller square or larger square, scrapped area will be a fixed percentage of square. Therefore, in this case where two squares are pf the same size, the ratio will be 1 : 1.
Answer : A
Answer: (A) 1:1
Question: If Dale works at full efficiency he needs a break of 1 day after every 2 days of work and he completes a job in a total of 17 days. If he works at reduced efficiency, he can work without break and finish that same job in 17 days. Dale's output at reduced efficiency is what fraction of his output at full efficiency?
(A) 6/5
(B) 1/5
(C) 9/5
(D) 12/5
(E) 6/35
Rationale: We're told that there are 2 ways for Dale to complete a job:
1) Full Efficiency: 2 days of work followed by 1 dayofffor a total of 17 days.
2) Reduced Efficiency: 17 straight days with no days off.
Working at Full Efficiency creates the following pattern:
2 days on, 1 day OFF, 2 days on, 1 day OFF, 2 days on, 1 day OFF, 2 days on = 2+1+2+1+2+1+2+1+2+1+2= 17 days
Totals: 12 days on, 5 days off
Reduced Efficiency means that Dale will do 12 days of work in 17 days, thus those Reduceddaysare 12/5 of Full Efficiency.
Answer : D
Answer: (D) 12/5
Question: If the product 4864 x 9 P 2 is divisible by 12, then the value of P is:
(A) 2
(B) 3
(C) 8
(D) 5
(E) None of these
Rationale: Explanation: Clearly, 4864 is divisible by 4.
So, 9P2 must be divisible by 3.
So, (9 + P + 2) must be divisible by 3.
P = 1.
Answer: Option E
Answer: (E) None of these
Question: You collect coins. Suppose you start out with 11. Since his mother makes coins, Miguel decides to double your coins. Since you're nice, you give Mary 12 coins. How many coins do you have at the end?
(A) 9
(B) 10
(C) 11
(D) 12
(E) 13
Rationale: Solution
Start with 11 coins.
Miguel doubles the number of coins you have: 11 × 2 = 22 coins.
Mary takes 12 coins from you: 22 - 12 = 10 coins.
So you have 10 at the end.
Correct answer: B
Answer: (B) 10
Question: From his monthly salary a man spends 10% of his salary for house rent, 20% on food, 25% for all other expenses and saves Rs 2520 per month. His monthly salary is?
(A) Rs 4400
(B) Rs 5000
(C) Rs 5600
(D) Rs 6200
(E) Rs 6300
Rationale: Explanation: Total salary = 100%
His spending are on house rent 10%, on food 20% and for other expenses 25%.
Total expenditure = 10 % + 20% + 25% = 55%
His savings are => Income – Expenses
=> 100% - 55% => 45% = Rs 2520
Hi salary is 1005 => 2520 45
x 100
= Rs 5600
C
Answer: (C) Rs 5600
Question: The banker's gain on a bill due due 1 year hence at 12% per annum is Rs.7.8. The true discount is
(A) Rs.72
(B) Rs.65
(C) Rs.54
(D) Rs.50
(E) none
Rationale: Solution
T.D	= [B.G x 100 / R x T]
= Rs.(7.8 x 100 / 12 x 1)
= Rs.65.
Answer B
Answer: (B) Rs.65
Question: A runs 25% faster than B and is able to give him a start of 7 meters to end a race in dead heat. What is the length of the race?
(A) 33m
(B) 34m
(C) 35m
(D) 36m
(E) 37m
Rationale: A runs 25% as fast as B.
That is, if B runs 100m in a given time, then A will run 125m in the same time
In other words, if A runs 5m in a given time, then B will run 4m in the same time.
Therefore, if the length of a race is 5m, then A can give B a start of 1m so that they finish the race in a dead heat.
Start:length of race :: 1:5
we know that the start is 7m. length of the race will be 7/x=1/5. i.e.7*5=35m.
ANSWER:C
Answer: (C) 35m
Question: If a wholesaler distributes items to several outlets (A, B, C and D) in the ratio of 1/10 : 1/11 : 1/15 : 1/16, then find the total number of items the wholesaler distributes?
(A) 945
(B) 745
(C) 845
(D) 145
(E) 345
Rationale: Here, A : B : C : D = 1/10 : 1/11 : 1/15 : 1/16
1) L.C.M of 10, 11, 15,16 is 2640
2) Find the number of books each friend received --------- (To find no. of books each friend has, multiply the ratio with the L.C.M. calculated)
A = (1/10) x 2640 = 264
B = (1/11) x 2640 = 240
C = (1/15) x 2640 = 176
D = (1/16) x 2640 = 165
3) Total number of toys = (264 x + 240 x + 176 x + 165 x) = 845 x
Minimum number of pens (x) = 1
Therefore, total number of items = 845 items.
Correct option :C
Answer: (C) 845
Question: A is 3 years older to B and 3 years younger to C, while B and D are twins. How many years older is C to D?
(A) 20
(B) 3
(C) 6
(D) 12
(E) 2
Rationale: B is 6 years younger to C.
B and D are twins.
Hence C is 6 years elder to D.
ANSWER:C
Answer: (C) 6
Question: A man was born on January 1st, 23 B.C. and died January 2nd, 23 A.D. How old did he live to be?
(A) 25
(B) 35
(C) 45
(D) 55
(E) 65
Rationale: 45 years old.
There is no year 0 so you can add 23 to 23 but you must subtract one to take year 0 out of consideration: 23 + 23 - 1 = 45 years old. In some cultures people are born 1 years old, in this case they would be 46 years old when they die.
Answer: (C) 45
Question: Seven men and four boys can complete a work in 6 days. A man completes double the work than a boy. In how many days will 5 men and 4 boys complete the work?
(A) 5
(B) 4
(C) 6
(D) Cannot be determined
(E) None of these
Rationale: M = 2B
∴ 7M + 4B = 14B + 4B = 18B
5M + 4B = 10B + 4B = 14B
∴ 18 boys complete the work in 6 days.
∴ 14 boys complete the work in
6×18/14=7 5/7days
Note: 7 men and 4 boys complete the work in 6 days. We have to find out the no. of days in which 5 men and 4 boys complete the work. Here, we see that 4 boys are common in both the cases, therefore, 5 men will take more time to complete the work, i.e., more than 6 days, which is not given in any options. Therefore, without calculating we can say that our answer is(e).
Answer E
Answer: (E) None of these
Question: The population of a town is 10000. It increases annually at the rate of 20% p.a. What will be its population after 2 years?
(A) 14300
(B) 14400
(C) 14500
(D) 14600
(E) 15400
Rationale: Formula :
( After =100 denominator
Ago = 100 numerator)
10000 × 120/100 × 120/100 = 14400
B)
Answer: (B) 14400
Question: Pradeep has to obtain 20% of the total marks to pass. He got 160 marks and failed by 25 marks. The maximum marks are
(A) 1925
(B) 600
(C) 925
(D) 1325
(E) 900
Rationale: Explanation :
Let their maximum marks be x.
Then, 20% of x = 160 + 25
=>20/100x= 185
x = (18500/20)
x= 925.
Answer : C
Answer: (C) 925
Question: There are 12 teams in a certain league and each team plays each of the other teams exactly twice. If each game is played by 2 teams, what is the total number of games played?
(A) 15
(B) 16
(C) 28
(D) 56
(E) 132
Rationale: Every team plays with 11 teams...so total no of matches = 12 x 11 = 132.
Now, each match is played twice => 132 x 2
But 2 teams play a match => 132 x 2 /2 = 132.
Answer: E
Answer: (E) 132
Question: The area of a sector of a circle of radius 5 cm formed by an arc of length 4.5 cm is?
(A) 8.78
(B) 11.25
(C) 8.75
(D) 8.98
(E) 8.28
Rationale: (5 * 4.5)/2
= 11.25
Answer:B
Answer: (B) 11.25
Question: Given that on 27th February 2003 is Thursday. What was the day on 27th February 1603?
(A) Monday
(B) Thursday
(C) Sunday
(D) Tuesday
(E) None
Rationale: Solution:
After every 400 years, the same day occurs.
Thus, if 27th February 2003 is Thursday, before 400 years i.e., on 27th February 1603 has to be Thursday.
Answer B
Answer: (B) Thursday
Question: If X is to be chosen at random from the integers between 1 to 6, inclusive, and Y is to be chosen at random from the integers between 7 and 11, inclusive, what is the probability that X + Y will be even?
(A) 1/2
(B) 2/3
(C) 3/4
(D) 4/5
(E) 5/6
Rationale: X+Y will be even if X and Y are both even or both odd.
P(X and Y are both even) = 3/6*2/5 = 1/5
P(X and Y are both odd) = 3/6*3/5 = 3/10
P(X+Y is even) = 1/5 + 3/10 = 1/2
The answer is A.
Answer: (A) 1/2
Question: How many positive two-digit whole numbers are divisible by 7?
(A) 11
(B) 9
(C) 15
(D) 12
(E) 13
Rationale: The largest two-digit number that is a multiple of 7 is 7x14 = 98.
Thus, there are 14 positive multiples of 7 that are less than 100.
However, this includes 7x 1 = 7 which is not a two-digit number.
Therefore, there are 14 -1 = 13 positive two-digit numbers which are divisible by 7.
(Note that these 13 numbers are 14,21,28,35,42,49,56,63,70,77,84,91 and 98.)
correct answer E
Answer: (E) 13
Question: Two trains are running in opposite directions in the same speed. The length of each train is 120 meter. If they cross each other in 24 seconds, the speed of each train (in km/hr) is
(A) 18
(B) 36
(C) 28
(D) 20
(E) 24
Rationale: Explanation:
Distance covered = 120+120 = 240 m
Time = 24 s
Let the speed of each train = v. Then relative speed = v+v = 2v
2v = distance/time = 240/24 = 10 m/s
Speed of each train = v = 10/2 = 5 m/s
= 5×36/10 km/hr = 18 km/hr
Answer: Option A
Answer: (A) 18
Question: In a class of 25 students, 2 students did not borrow any books from the library, 12 students each borrowed 1 book, 4 students each borrowed 2 books, and the rest borrowed at least 3 books. If the average number of books per student was 2, what is the maximum number of books any single student could have borrowed?
(A) 8
(B) 9
(C) 10
(D) 11
(E) 12
Rationale: The total number of books the students borrowed is 25*2=50.
The students who borrowed zero, one, or two books borrowed 12*1+4*2=20 books.
The 7 students who borrowed at least three books borrowed 50-20=30 books.
If 6 of these students borrowed exactly 3 books, then the maximum that one student could have borrowed is 30-18= 12 books.
The answer is E.
Answer: (E) 12
Question: 3, 5, 7, 11, 13, 17, 19, ____
(A) 25
(B) 36
(C) 23
(D) 49
(E) 27
Rationale: The sequence is a series of prime numbers, 3, 5, 7, 11, 13, 17, 19, 23....
Answer : C.
Answer: (C) 23
Question: Two pipes X and Y can separately fill a cistern in 18 and 24 hours respectively. If they are turned on alternately for one hour each, how long will it take to fill the cistern?
(A) 20 hours 30 min
(B) 25 hours 30 min
(C) 30 hours 30 min
(D) 40 hours 30 min
(E) 50 hours 30 min
Rationale: A
20 hours 30 min
1/18 + 1/24 = 7/72
72/7 = 10 2/7
7/72 * 10 = 35/36 ----- 20 hours
WR = 1 – 35/36 = 1/36
1 h ----- 1/18
? ----- 1/36 = 1/2 hours
=> 20 1/2 hours
Answer: (A) 20 hours 30 min
Question: 9548 + 7314 = 5362 + (?)
(A) 8300
(B) 8400
(C) 11500
(D) 8700
(E) 9000
Rationale: 9548 16862 = 5362 + x
+ 7314 x = 16862 - 5362
----- = 11500
16862
-----
C)
Answer: (C) 11500
Question: Tom and John traveled in the same direction along the equal route at their constant speed rates of 15 km per hour and 10 km per hour, respectively. After 15 minutes Tom passed John, Tom reaches a certain Gas station, how many W minutes it takes John to reach the station?
(A) 5 min
(B) 6 min
(C) 7 and 1/2 min
(D) 8 min
(E) 10 min
Rationale: Since the question states “after 15 minutes”, we can say Tom traveled 15/4km for 15 minutes as he can travel 15km per hour. Hence, using the same logic, we can say John traveled 10/4km as he travels 10km per hour. So, John has to travel (15/4)-(10/4)km=5/4km more. Since John’s speed is 10km/hour, which means 1km/6minutes. As he has to travel 5/4km more, it is going to take him 6(5/4) minutes. Hence, W=6(5/4)=15/2 minutes. The correct answer is C.
Answer: (C) 7 and 1/2 min
Question: What is the least integer that is a sum of four different prime numbers each greater than 50?
(A) 232
(B) 234
(C) 236
(D) 238
(E) 240
Rationale: The sum of the four smallest primes greater than 53+59+61+67=240.
The answer is E.
Answer: (E) 240
Question: A milkman professes to sell his milk at cost price but he mixes it with water and thereby gains 25%. The percentage of water in the mixture is:
(A) 4%
(B) 6(1/4)%
(C) 20%
(D) 25%
(E) 30%
Rationale: Explanation:
Let C.P. of 1 litre milk be Re. 1
Then, S.P. of 1 litre of mixture = Re. 1, Gain = 25%.
C.P. of 1 litre mixture = Re. 100	x 1 =	4
125	5
By the rule of alligation, we have:
Ratio of milk to water =	4/5 : 1/5 =4:1.
Hence, percentage of water in the mixture =(1/5 x 100)%=20%
ANSWER IS C
Answer: (C) 20%
Question: If integers x and b are distinct factors of 30, which of the following CANNOT be a factor of 30?
I. xb + b^2
II. (x + b)^2
III. x + b
(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I, II, and III
Rationale: Factors of 30 are: 1, 2, 3, 5, 6, 10, 15, and 30.
I. xb + b^2 --> if x=1 and b=2 then xb + b^2=6, which is a factor of 30. OK;
II. (x + b)^2 --> (x + b)^2 is a perfect square, no perfect square (but 1) is a factor of 30. DISCARD;
III. x + b --> if x=1 and b=2 then x + b=3, which is a factor of 30. OK.
Answer: B.
Answer: (B) II only
Question: If r and s are negative integers, which of the following statements must be true?
I. (-r)^s is positive.
II. (-r)^(-s) is positive.
III. r^(-s) is positive.
(A) None
(B) II only
(C) I and II
(D) I and III
(E) I, II and III
Rationale: Let's r = -2 and s = -3
I. (-r)^s = (2)^(-3) = 1/(2^3) --> Positive
II. (-r)^(-s) is positive. = 2^3 --> Positive
III. r^(-s) is positive. = -2^3 --> Negative
Answer: C
Answer: (C) I and II
Question: A boat can travel with a speed of 24 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 168 km downstream
(A) 3 hours
(B) 4 hours
(C) 5 hours
(D) 6 hours
(E) 7 hours
Rationale: Explanation:
Speed of the boat in still water = 24 km/hr
speed of the stream = 4 km/hr
Speed downstream = (22+5) = 28 km/hr
Distance travelled downstream = 168 km
Time taken = distance/speed = 168/28 = 6 hours
Answer: Option D
Answer: (D) 6 hours
Question: A portion of the 85% solution of chemicals was replaced with an equal amount of 30% solution of chemicals. As a result, 40% solution of chemicals resulted. What part of the original solution was replaced?
(A) 5/11
(B) 6/11
(C) 7/11
(D) 9/11
(E) 13/6
Rationale: This is a weighted average question. Say x% of the solution was replaced --> equate the amount of chemicals: 0.85(1-x)+0.3*x=0.4 --> x=9/11.
Answer: D.
Answer: (D) 9/11
Question: Three friends Dhoni, Rahul and Aswin divide $1540 amongs them in such a way that if $10, $12 and $18 are removed from the sums that Dhoni, Rahul and Aswin received respectively, then the share of the sums that they got will be in the ratio of 15: 17: 18. How much did Aswin receive?
(A) $560
(B) $562
(C) $564
(D) $558
(E) $570
Rationale: A+B+C = 1540
Given ratio 15:17:18
Let us say the shares of A,B,C deducting 10,12,18 be a,b,c
a+b+c = 1540-40= 1500 = 50K
c share = (1500X18)/50 = 540
C = Aswin share = 540+18= 558
Option D
Answer: (D) $558
Question: Every student at Tarcy School is in at least one of three clubs: horseback riding, embroidery, and country dancing, which are the only clubs in existence at the school. The ratio of the number of students in exactly two clubs to the number of students in exactly one club is 4:3, while the ratio of the number of students in exactly two clubs to the number of students in at least two clubs is 5:7. Which of the following could be the total number of students at Tarcy School?
(A) 63
(B) 69
(C) 74
(D) 82
(E) 86
Rationale: the total number of students at Tarcy School The answer is 86 or any multiple of 43.E
Answer: (E) 86
Question: Suresh started a business with Rs.20,000. Kiran joined him after 4 months with Rs.30,000. After 2 more months, Suresh withdrew Rs.5,000 of his capital and 2 more months later, Kiran brought in Rs.20,000 more. What should be the ratio in which they should share their profits at the end of the year?
(A) 32:21
(B) 12:17
(C) 17:12
(D) 21:32
(E) 15:19
Rationale: Here capital is not the same.
Suresh invested 20000 for initial 6 months and 15000 for the next 6 months. Hence his term of ratio
=(20000×6+15000×6)
Kiran invested Rs.30000 for 4 months and Rs.50000 for next 4 months. Hence his term of ratio
=(30000×4+50000×4)
Suresh : Kiran
=(20000×6+15000×6) :(30000×4+50000×4)
=(20×6+15×6):(30×4+50×4)
=(20×3+15×3):(30×2:50×2)
=105:160
=21:32
Answer is D.
Answer: (D) 21:32
Question: A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km?
(A) 43 kmph
(B) 65 kmph
(C) 24 kmph
(D) 14 kmph
(E) 61 kmph
Rationale: Total time taken = x/40 + 2x/20 hours
= 5x/40 = x/8 hours
Average speed = 3x/(x/8) = 24 kmph
Answer:C
Answer: (C) 24 kmph
Question: I chose a number and divide it by 2. Then I subtracted 100 from the result and got 4. What was the number I chose?
(A) 200
(B) 208
(C) 400
(D) 500
(E) 100
Rationale: Let x be the number I chose, then
x/2−100=4
x/2=104
x=208
Answer is B.
Answer: (B) 208
Question: Jack and Jill work at a hospital with 7 other workers. For an internal review, 2 of the 9 workers will be randomly chosen to be interviewed. What is the probability that Jack and Jill will both be chosen?
(A)  1/3
(B)  1/4
(C)  1/15
(D)  3/8
(E)  1/36
Rationale: 1/9C2=1/36.
Answer: E.
Answer: (E)  1/36
Question: A milk man sells the milk at the cost price but he mixes the water in it and thus he gains 9.09%. The quantity of water in the mixture of 1 liter is
(A) 83.33 ml
(B) 83.03 ml
(C) 93.33 ml
(D) 63.03 ml
(E) 82.33 ml
Rationale: Explanation:
Profit (%) = 9.09 % = \inline \frac{1}{11}
Since the ratio of water and milk is 1 : 11,
Therefore the ratio of water is to mixture = 1:12
Thus the quantity of water in mixture of 1 liter = \inline 1000\times \frac{1}{12} = 83.33 ml]
Answer: A) 83.33 ml
Answer: (A) 83.33 ml