mathewhe/aqua_rat huggingface dataset:
Question: If A, B and C together can finish a piece of work in 4 days. A alone in 12 days and B in 9 days, then C alone can do it in?
(A) 11
(B) 17
(C) 18
(D) 19
(E) 16
Rationale: C = 1/4 - 1/12 – 1/9 = 1/18 => 18 days'
Answer: C
Answer: (C) 18
Question: Submarine M and Submarine N are equipped with sonar devices that can operate within a 4,000 yard range. Submarine M remains in place while Submarine N moves 3,700 yards south from Submarine M. Submarine N then changes course and moves due east, stopping at the maximum range of the sonar devices. In which of the following directions can Submarine N continue to move and still be within the sonar range of Submarine M? I. North II. South III. West
(A) I,II only
(B) II,III only
(C) II only
(D) I and III only
(E) III only
Rationale: It's evident if we make a diagram for the Movement of N respect to M.
From its South position to the east position, it has covered the maximum radius for the south direction. Similarly, it's east movement further will also make it out of range.
Thus it can only move north or west or anything in that curve.
Answer : D
Answer: (D) I and III only
Question: In a garden, there are yellow and green flowers which are straight and curved. If the probability of picking a green flower is 1/8 and picking a straight flower is 1/2, then what is the probability of picking a flower which is yellow and straight
(A) 1/7
(B) 1/8
(C) 1/4
(D) 3/4
(E) 4/9
Rationale: Good question.
So we have a garden where all the flowers have two properties: color (green or yellow) and shape (straight or curved).
We're told that 1/8 of the garden is green, so, since all the flowers must be either green or yellow, we know that 7/8 are yellow. We're also told there is an equal probability of straight or curved, 1/2.
We want to find out the probability of something being yellow and straight, Pr( Yellow and Straight ).
So if we recall, the probability of two unique events occurring simultaneously is the product of the two probabilities, Pr( A and B ) = P(A) * P(B). So we multiply the two probabilities, Pr(yellow)* Pr(straight) = 7/8 * 1/2 = 4/9, or E.
Answer: (E) 4/9
Question: A vessel contains a 105 ml mixture of milk and water. 3/7 of the mixture is alcohol, the remainder is water. An additional quantity of 105 ml of milk is poured into the mixture. What is the ratio of the volume of milk to water in the new mixture?
(A) 3:7
(B) 3:4
(C) 5:2
(D) 1:1
(E) 2:5
Rationale: The amount of milk in the old mixture is 3/7 x 105 = 45 ml.
Further 105 ml milk is added.
Therefore, total milk in new mixture is 150 ml.
Water content is (105 -45) - 60 ml.
Milk to water ratio is 150: 60 or 5: 2
ANSWER:C
Answer: (C) 5:2
Question: An investor bought two shares of stock, which he sold for $84 each. If he had a profit of 20% on one of the shares and a loss of 20% on the other share, then on the sale of both shares combined, the investor had:
(A) a profit of $10
(B) a profit of $7
(C) a loss of $7
(D) a loss of $10
(E) neither a profit nor a loss
Rationale: The cost of the first stock was 84/1.2=70, so the profit from it is 14.
The cost of the second stock was 84/0.8=105, so loss from it is 21.
Overall the loss is $7.
The answer is C.
Answer: (C) a loss of $7
Question: A = {2, 3, 5, 7, 11}
B = {2, 4, 6, 15}
Two integers will be randomly selected from sets A and B, one integer from set A and one from set B, and then multiplied together. How many different products can be obtained?
(A) 15
(B) 16
(C) 19
(D) 20
(E) 36
Rationale: By looking at Set A, we can see that it's all primes. Thus, we should immediately break down the elements in Set B to their prime factors. That gives :
Set A = {2,3,5,7,11}
Set B = {2, 2x2, 3x2, 13}
Apart from 2x3x2 (taking 2 from set A) which is the same as 3x2x2(taking 3 from set A); there is nothing which can be repeated. Thus, the total unique product = 20-1 = 20.
D
Answer: (D) 20
Question: An outlet pipe can empty 2/3 rd of a cistern in 12 minutes. In 8 minutes, what part of the cistern will be emptied?
(A) 4/9
(B) 4/5
(C) 4/1
(D) 4/2
(E) 4/3
Rationale: Explanation:
2/3 ---- 12
? ----- 8 ==> 4/9
Answer: A
Answer: (A) 4/9
Question: A sum of money at simple interest amounts to Rs. 415 in 2 years and to Rs. 514 in 4 years. The sum is ?
(A) Rs. 316
(B) Rs. 251
(C) Rs. 154
(D) Rs. 294
(E) Rs. 200
Rationale: Explanation:
S.I. for 2 years = (514 - 415) = Rs. 99
S.I. for 1 year = 99/2
Principal = (415 - 99) = Rs. 316.
ANSWER IS A
Answer: (A) Rs. 316
Question: What is the average of four tenths and five thousandths?
(A) 25002
(B) 2502
(C) 0.225
(D) 0.2025
(E) 0.02025
Rationale: (.4 + .005)/2 --> .405/2 --> .2025
D
Answer: (D) 0.2025
Question: A father said to his son, "I was as old as you are at present at the time of your birth." If the father's age is 38 years now, the son's age six years back was?
(A) 13yr
(B) 15yr
(C) 20yr
(D) 25yr
(E) 30yr
Rationale: Let the son's present age be x years
Then, 38-x = x
x = 19
Son's age 6 years back = 19-6 = 13 years
Answer is A
Answer: (A) 13yr
Question: A 400 meter long train crosses a man standing on the platform in 10 sec. What is the speed of the train?
(A) 144
(B) 108
(C) 278
(D) 126
(E) 112
Rationale: S = 400/10 * 18/5 = 144 kmph
Answer: A
Answer: (A) 144
Question: If a, b, and c are integers and ab^2/c is a positive even integer, which of the following must be true?
I. ab is even
II. ab > 0
III. c is even
(A) I only
(B) II only
(C) I and II
(D) I and III
(E) I, II, and III
Rationale: ab2/c is positive which means a and C >0 or a and c<0 since b2 is positive
Case 1 - a=3 b=2 c=3 or c=6 where ab2 /2 would be even when c= 3 or c=6
lets see III option where C is even as per our assumption C can be even and odd, hence it is out.
lets see option II ab>0 a and b can positive or negative hence sign of ab cannot be determined hence it is out
So options B,C,D,E are gone and ans is A
Answer: (A) I only
Question: A cheese factory sells its cheese in rectangular blocks. A normal block has a volume of 5 cubic feet. If a large block has three times the width, twice the depth, and half the length of a normal block, what is the volume of cheese in a large block in cubic feet?
(A) 10
(B) 30
(C) 15
(D) 20
(E) 25
Rationale: Volume of cube=lbh=5
New cube l ,b, h are increases of 3b,2h and a decrease of .5l
New volume of cube =.5l*3b*2h=3*lbh
=3*5
=15
Answer: C
Answer: (C) 15
Question: Carol spends 1/4 of her savings on a stereo and 1/2 less than she spent on the stereo for a television. What fraction of her savings did she spend on the stereo and television?
(A) 1/4
(B) 2/7
(C) 5/12
(D) 3/8
(E) 7/12
Rationale: Total Savings = S
Amount spent on stereo = (1/4)S
Amount spent on television = (1-1/2)(1/4)S = (1/2)*(1/4)*S = (1/8)S
(Stereo + TV)/Total Savings = S(1/4 + 1/8)/S = 3/8
Answer: D
Answer: (D) 3/8
Question: A computer is programmed to multiply consecutive even integers 2*4*6*8*…*n until the product is divisible by 1551, What is the value of n?
(A) 22
(B) 38
(C) 62
(D) 94
(E) 672
Rationale: Factorise 1551.. 3*11*47..
So n has to be a multiple of largest prime number,61..
So n=2*47=94..
Ans :D
Answer: (D) 94
Question: If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ?
(A) Rs. 175
(B) Rs. 325
(C) Rs. 340
(D) Rs. 260
(E) Rs. 230
Rationale: Explanation:
Assume first child (the youngest) get = Rs. x
According to the question ;
each son having Rs. 30 more than the younger one
Second child will get = Rs. x + 30
Third child will get = Rs. x + 30 + 30 = x + 60
Forth child will get = Rs. x + 30 + 30 + 30 = x + 90
Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120
Total amount they got = Rs. 2000
x + (x+30) + (x+60) + (x+90) + (x+120) = 2000
5x + 300 = 2000
5x = 1700
x = Rs. 340
So the youngest child will get Rs. 340.
ANSWER IS C
Answer: (C) Rs. 340
Question: It takes Joey the postman 1 hours to run a 7 mile long route every day. He delivers packages and then returns to the post office along the same path. If the average speed of the round trip is 8 mile/hour, what is the speed with which Joey returns?
(A) 11
(B) 12
(C) 13
(D) 8
(E) 15
Rationale: let his speed for one half of the journey be 7 miles an hour
let the other half be x miles an hour
now,
avg speed =8 mile an hour
2*7*x/7+x=8
14x=8x+56=>x=8
D
Answer: (D) 8
Question: Each Machine of type A has 2 steel parts and 2 chrome parts. Each machine of type B has 6 steel parts and 5 chrome parts. If a certain group of type A and type B machines has a total of 20 steel parts and 22 chrome parts, how many machines are in the group
(A) 2
(B) 3
(C) 4
(D) 6
(E) 7
Rationale: Look at the below representation of the problem:
Steel Chrome total
A 2 2 20 >>no. of type A machines=20/4=5
B 6 5 22 >>no. of type B machines=22/11=2
So the answer is 7 i.e E.
Hope its clear .
Answer: (E) 7
Question: The length of a rectangle is halved, while its breadth is tripled. Watis the % change in area?
(A) 40%
(B) 30%
(C) 50%
(D) 60%
(E) 70%
Rationale: Let original length = x and original breadth = y.
Original area = xy.
New length = x .
2
New breadth = 3y.
New area = x x 3y = 3 xy.
2 2
Increase % = 1 xy x 1 x 100 % = 50%.
2 xy
C
Answer: (C) 50%
Question: Find the sum and number of divisors of 544 excluding 1 and 544.
(A) 589
(B) 599
(C) 618
(D) 659
(E) 648
Rationale: if N = p^a * q^b *r^c *...
total no. of factors of N = (a+1)*(b+1)*(c+1)*... &
sum of all of the factors of N =(1+p+p^2+...+p^a)*(1+q+..+q^b)*(1+r+r^2+...+r^c)
544 = 2^5 * 17
number of divisors of 544 excluding 1 and 544 = (5+1)*(1+1) - 2 = 10
sum of divisors of 544 excluding 1 and 544 = (1+2+2^2+2^3+2^4+2^5)*(1+17)-1-544
= 589
ANSWER:A
Answer: (A) 589
Question: A computer program generates a single digit by a random process, according to which the probability of generating any digit is directly proportional to the reciprocal of one more than that digit. If all digits are possible to generate, then the probability Q of generating an odd prime digit is between
(A) 0 and 1/6
(B) 1/6 and 1/3
(C) 1/3 and 1/2
(D) 1/2 and 2/3
(E) 2/3 and 5/6
Rationale: K (1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8 + 1/9+ 1/10) =1
Note that 1/10 is least value and is equal to 0.1 so we can write above series as
K (1+0.5+0.3+0.25+0.2+0.16+0.5+residual) = 1
K=1/3+
P (3 or 5 or 7) =K*13/24
Required probability Q= 13/24 × 1/3+ = 4+/24 > 1/6
Answer should be B
P.s. 3+ denotes a value little greater than 3 .
Same for 4+.
Answer: (B) 1/6 and 1/3
Question: In what time will a railway train 56 m long moving at the rate of 39 kmph pass a telegraph post on its way?
(A) 3 sec
(B) 4 sec
(C) 5 sec
(D) 6 sec
(E) 7 sec
Rationale: T = 56/39 * 18/5 = 5 sec
ANSWER:C
Answer: (C) 5 sec
Question: In covering a distance of 40 km, A takes 2 hours more than B. If A doubles his speed, then he would take 1 hour less than B. A's speed is:
(A) 5 km/h
(B) 6.7 km/h
(C) 10 km/h
(D) 15 km/h
(E) 20 km/h
Rationale: Let A's speed be X km/hr.
Then, 40/x - 40/2x = 3
20/x = 3
x = 6.7 km/hr.
Answer : B
Answer: (B) 6.7 km/h
Question: A car travelling with 5/7 km of its actual speed covers 42km in 1hr 40 min 48 sec find the actual speed of the car?
(A) 78kmph
(B) 85kmph
(C) 35kmph
(D) 24kmph
(E) 74kmph
Rationale: time taken =1hr 40 min 48 sec=126/75hrs
let the actual speed be x kmph
then 5/7 x*126/75=42
x=(42*7*75)/5*126=35kmph
Answer (C)
Answer: (C) 35kmph
Question: What is the lowest possible common multiple of 2 distinct integers, each greater than 68?
(A) 68
(B) 69
(C) 138
(D) 68^2
(E) 68·69
Rationale: In order to get the lowest LCM, we have to take the first number as 69 and the next number as its multiple.
So, I can take 69 and 138 as two distinct numbers, such that Lowest LCM = 138.
Answer should be C.
Answer: (C) 138
Question: Ms. Barton has four children. You are told correctly that she has at least two girls but you are not told which two of her four children are those girls. What is the probability that she also has two boys? (Assume that the probability of having a boy is the same as the probability of having a girl.
(A) 1/4
(B) 3/8
(C) 5/11
(D) 1/2
(E) 6/11
Rationale: Assume that there are 4 Ms. Barton's children in a row: 1-2-3-4. Let show all possible combinations of them being girl(G) or boy(B) giving that there at least two girls. We are seeing each child 1,2,3,4 a s a unique(so, we distinguish between them)
BBGG
BGBG
GBBG
BGGB
GBGB
GGBB
BGGG
GBGG
GGBG
GGGB
GGGG
Overall 11 variants. 6 of them satisfy the condition of 2 boys exactly (they are highlighted in bold)
Therefore the probability is 6/11
Answer:E
Answer: (E) 6/11
Question: What was the principal , if at 12% per annum the interest after 3 years amounted to Rs.5888 less than the sum lent?
(A) 9000
(B) 3000
(C) 5000
(D) 1300
(E) 9200
Rationale: P - 2336 = (P*12*3)/100
P = 9200
Answer: E
Answer: (E) 9200
Question: For one toss of a certain coin, the probability that the outcome is heads is 0.4. If this coin is tossed 5 times, which of the following is the probability that the outcome will be heads at least 4 times?
(A) (0.4)^5
(B) 2(0.4)^4
(C) 3(0.4)^4
(D) 4(0.4)^4(0.6) + (0.4)^5
(E) 5(0.4)^4(0.6) + (0.4)^5
Rationale: P(5 heads) = (0.4)^5
There are 5 ways to get 4 heads: HHHHT, HHHTH, HHTHH, HTHHH, THHHH
P(4 heads) = 5*(0.4)^4(0.6)
The answer is E.
Answer: (E) 5(0.4)^4(0.6) + (0.4)^5
Question: For each color copy, Print Shop X charges $1.25 and Print Shop Y charges $2.75. How much greater is the charge for 60 color copies at Print Shop Y than at Print Shop X?
(A) $80
(B) $90
(C) $100
(D) $110
(E) $120
Rationale: The difference in the two prices is $2.75 - $1.25 = $1.50 for each color copy.
Each color copy will cost an extra $1.50 at Print Shop Y.
60*$1.50 = $90
The answer is B.
Answer: (B) $90
Question: A box contains 3 white balls, 2 black balls and 6 red balls. In how many ways can 3 balls be drawn from the box, if atleast one black ball is to be included in the draw?
(A) 52
(B) 69
(C) 73
(D) 47
(E) 81
Rationale: We may have (1 black and 2 non black) or (2 black and 1 non black)
Required number of ways = 2C1*9C2+1*9C1 = 81
Answer is E
Answer: (E) 81
Question: Calculate the circumference of a circular field whose radius is 8 centimeters.
(A) 18 π cm
(B) 1 π cm
(C) 8 π cm
(D) 19 π cm
(E) 28 π cm
Rationale: Circumference C is given by
C = 2πr = 2π*9 = 18 π cm
Answer: A
Answer: (A) 18 π cm
Question: A certain club has 10 members, including Harry. One of the 10 members is to be chosen at random to be the president, one of the remaining 9 members is to be chosen at random to be the secretary, and one of the remaining 8 members is to be chosen at random to be the treasurer. What is the probability that Harry will be either the member chosen to be the secretary or the member chosen to be the president?
(A)  1/720
(B)  1/5
(C)  1/10
(D)  1/9
(E)  1/6
Rationale: This question is much easier than it appears.
Each member out of 10, including Harry, has equal chances to be selected for any of the positions (the sequence of the selection is given just to confuse us). The probability that Harry will be selected to be the secretary is 1/10 and the probability that Harry will be selected to be the president is also 1/10. So, the probability that Harry will be selected to be either the secretary or the the president is 1/10+1/10=2/10.
Answer: B
Answer: (B)  1/5
Question: The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of Qis?
(A) A)Rs.4078
(B) B)Rs.6100
(C) C)Rs.4029
(D) D)Rs.4027
(E) E)Rs.4020
Rationale: Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (5050 * 2) = 10100 --- (i)
Q + R = (6250 * 2) = 12500 --- (ii)
P + R = (5200 * 2) = 10400 --- (iii)
Adding (i), (ii) and (iii), we get:
2(P + Q + R) = 33000 = P + Q + R = 16500 --- (iv)
Subtracting (iii) from (iv), we get, P = 6100.
P's monthly income = Rs.6100.
Answer: B
Answer: (B) B)Rs.6100
Question: Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 32 kmph. Of how many minutes does the train stop per hour?
(A) E982
(B) 27
(C) 17.3
(D) 121
(E) 28
Rationale: Explanation:
T = 13/45 * 60 = 17.3
Answer: Option C
Answer: (C) 17.3
Question: The sum of five numbers is 400. The average of the first two numbers is 50 and the third number is 60. Find the average of the two numbers?
(A) 70
(B) 65
(C) 85
(D) 80
(E) 90
Rationale: Let the five numbers be P, Q, R, S and T.
=> P + Q + R + S + T = 400
(P + Q)/2 = 50 and R = 60
P + Q = 100 and R = 60
P + Q + R = 160
S + T = 400 - (P + Q + R) = 240
Average of the last two numbers
= (S + T)/2 = 80
Answer:D
Answer: (D) 80
Question: A man buys a cycle for Rs. 2300 and sells it at a loss of 30%. What is the selling price of the cycle?
(A) s. 1690
(B) s. 1610
(C) s. 1890
(D) s. 1602
(E) s. 1092
Rationale: S.P. = 70% of Rs. 2300 = Rs.	70	x 2300/100 = Rs. 1610
Answer: Option B
Answer: (B) s. 1610
Question: How many 7 in between 1 to 120?
(A) 18
(B) 20
(C) 22
(D) 23
(E) 24
Rationale: 7,17,27,37,47,57,67,
70,71,72,73,74,75,76,77(two 7's),78,79,87,97,107,117
22 7's between 1 to 120
ANSWER:C
Answer: (C) 22
Question: If log X/2=log Y/3 = log Z/5, then YZ in terms of X is
(A) X
(B) X2
(C) X3
(D) X4
(E) None of these
Rationale: logX/2 = logY/3= logZ/5 = K(say).
=> logX = 2k, logY = 3k, log Z =5K
=> logYZ = 3K + 5K = 8k; logX4 = 8K
Thus, logYZ = logX4
=>YZ = X4
ANSWER:D
Answer: (D) X4
Question: How many times are the hands of a clock at right angle in a day?
(A) 22
(B) 24
(C) 44
(D) 48
(E) 52
Rationale: In 12 hr's the hands of the clk will be right angle for 22 times..
as in 1 hr time the hands of the clk will be right angle fot 2 times.
but in (11'o clk - 1'o clk) time it will right angle only twice(2).
so for 12 hrs time 22 times it will be right angle.
for 24 hrs time 44 times it will be right angle..
ANSWER:C
Answer: (C) 44
Question: A cask full of milk,'E' liters is removed and water is mixed. This process is repeated and now the ratio in milk to water is 16:9. Then what is the amount of milk in liter.
(A) E+9
(B) 9E
(C) 5E
(D) 8E
(E) cant be determined
Rationale: After 'n' operations ,the amount of pure liquid remaining is = [x { ( 1-E/x )^n } ]...where x is original amount of liquid and E is amount of liquid removed..This is standard formula in RS aggarwal...
Now ,in our case the operations is performed twice...
Let the original milk be x liters..
E liters removed twice n = 2,
milk remaining (M) = [ x { (1-E/x)^2 } ]....water is (W) = x - [x { (1-E/x)^2 } ]
M/W = 16/9 Take (1-E/x)^2 = z
now solving we get z = 16/25 that is (1 - E/x)^2 = (4/5)^2
1 - E/x = 4/5
x = 5E
ANSWER:C
Answer: (C) 5E
Question: The value of log 5 (1/125) is:
(A) 3
(B) -3
(C) 1/3
(D) -1/3
(E) none of these
Rationale: log5(1/125)
=log5(1/5)^3
=3log5(1/5)
=3(log5 1 - log5 5)
=3(0-1)
=-3
ANSWER:B
Answer: (B) -3
Question: Find the one which does not belong to that group?
(A) 16
(B) 36
(C) 27
(D) 64
(E) 4
Rationale: Explanation:
16, 36, 64 and 4 are perfect squares but not 27.
Answer:C
Answer: (C) 27
Question: 4,25,49,121
(A) 149
(B) 169
(C) 189
(D) 209
(E) 219
Rationale: 13^2= 169 because follow sequence of square of the prime numbers
ANSWER:B
Answer: (B) 169
Question: Amy has two decks of 56 cards each: Deck 1 and Deck 2. She takes 8 black cards from Deck 2 and adds them to Deck 1 and shuffles it thoroughly. She now picks a card from the newly formed pack of cards. If the probability of either picking a red ace or a king from the newly formed pack is greater than 1/8, what is the probability that Amy picks a black king or a red Jack from the new pack?
(A) 1/6
(B) 1/8
(C) 1/9
(D) 1/10
(E) 1/13
Rationale: Your solution is correct answer should be 1/13.
E
Answer: (E) 1/13
Question: A certain barrel, which is a right circular cylinder, is filled to capacity with 60 gallons of oil. The first barrel is poured into a second barrel, also a right circular cylinder, which is empty. The second barrel is twice as tall as the first barrel and has twice the diameter of the first barrel. If all of the oil in the first barrel is poured into the second barrel, how much empty capacity, in gallons, is left in the second barrel?
(A) There is no empty capacity
(B) 100 gallons
(C) 300 gallons
(D) 420 gallons
(E) 840 gallons
Rationale: Radius of first cylinder=r, diameter=2r, height=h
Radius of second cylinder=2r, diamter=2d and height=2h
Volume of first cylinder=pie (r^2)*h=60
Volume of second cylinder=pie(2r^2)2h
Put the value of pie (r^2)*h=60 in the second cylinder,volume= pie (r^2)*4*2=60*8=480 gallons
Empty capacity=420 gallons
Answer D
Answer: (D) 420 gallons
Question: The length of a bridge in meters, which a train 80-meters long and traveling at 45 km/hr can cross in 30 seconds is?
(A) 215
(B) 235
(C) 255
(D) 275
(E) 295
Rationale: 45 km/h = 45000 m/3600 s = 12.5 m/s
In 30 seconds, the train can go 30(12.5) = 375 meters
Let x be the length of the bridge.
x+80 = 375 meters
x = 295 meters
The answer is E.
Answer: (E) 295
Question: Which of the following is the highest fraction?
(A) 5⁄7
(B) 3⁄4
(C) 2⁄3
(D) 6⁄7
(E) 7⁄8
Rationale: Note : If the difference between the numerator and the denominator is constant, then the fraction which has larger value in the numerator is the larger fraction.
Using the above, among the options (a), (c), (d) and (e), (e) has the larger value. Now, compared to option(a), (e) has the larger value.
Answer E
Answer: (E) 7⁄8
Question: People spend an estimated $75 at the zoo every day, and the total estimated amount for bills every month for the nearest zoo is $200,000. To pay its bills, how many people need to be attending the zoo on a weekly basis? The amount of people needs to be rounded to whole numbers, and a month typically has 4 full weeks.
(A) 666
(B) 667
(C) 669
(D) 670
(E) 665
Rationale: To find out our answer, we must think about how much the zoo makes in a week.
So, we divide 200,000 by 4 to get 50,000
We then divide 50,000 by 75 to get our estimate.
Round the answer to the nearest whole number to get the answer.
Correct Option: B
Answer: (B) 667
Question: There are 6 people in the elevator. Their average weight is 156 lbs. Another person enters the elevator, and increases the average weight to 151 lbs. What is the weight of the 7th person.
(A) 121
(B) 168
(C) 189
(D) 190
(E) 200
Rationale: Solution
Average of 7 people after the last one enters = 151 .
âˆ´ Required weight = (7x151)-(6x156)
= 1057- 936
= 121.
Answer A
Answer: (A) 121
Question: In how many ways can 4 boys and 3 girls sit around a table in such a way that no two girls sit together?
(A) 100
(B) 144
(C) 155
(D) 180
(E) 190
Rationale: The 4 boys can be seated around a table in 3! Ways. In between them there are 4 places.
The 3 girls can be placed in the 4 places in 4P3 ways.
Therefore, Required number of ways= 3!* 4P3
=6*24
=144
ANSWER:B
Answer: (B) 144
Question: Water boils at 212°F or 100°C and ice melts at 32°F or 0°C . If the temperature of a pot of water is 40°C, what is the temperature of the pot of water in °F?
(A) 85 °F
(B) 92 °F
(C) 96 °F
(D) 99 °F
(E) 104 °F
Rationale: Let F and C denote the temperature in Fahrenheit and Celsius respectively.
(F - 32) /(212 - 32) = (C - 0)/(100 - 0)
F = 9C/5 + 32
F = 9(40)/5 + 32 = 104°F
The answer is E.
Answer: (E) 104 °F
Question: Marla starts running around a circular track at the same time Nick starts walking around the same circular track. Marla completes 10 laps around the track per hour and Nick completes 5 laps around the track per hour. How many minutes after Marla and Nick begin moving will Marla have completed 4 more laps around the track than Nick?
(A) 5
(B) 48
(C) 12
(D) 15
(E) 20
Rationale: Maria's rate - 10 laps per hour --> 10/60 laps/min
Nick's rate - 5 laps per hour --> 5/60 laps/min
lets set equations:
10/60*t=4 (since Maria had to run 4 laps before Nick would start)
5/60*t=0 (Hick has just started and hasn't run any lap yet)
(10/60-5/60)*t=4-0 (since Nick was chasing Maria)
t=48 min needed Maria to run 4 laps
Answer : B
Answer: (B) 48
Question: When x dividedby 288, the remainder is 47. Find the remainder when the same x is divided by 24?
(A) 20
(B) 23
(C) 25
(D) 27
(E) 29
Rationale: 23
Option B
Answer: (B) 23
Question: A car covers a distance of 636 km in 6 ½ hours. Find its speed?
(A) 104 kmph
(B) 176 kmph
(C) 298 kmph
(D) 106 kmph
(E) 268 kmph
Rationale: 636/6
= 106 kmph
Answer:D
Answer: (D) 106 kmph