mathewhe/aqua_rat huggingface dataset:
Question: The profit earned by selling an article for $ 832 is equal to the loss incurred when the same article is sold for $ 448. What should be the sale price for making 40% profit?
(A) $480
(B) $450
(C) $896
(D) $870
(E) $660
Rationale: Let C.P. = $ x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 140% of $ 640 = $ 896.
C
Answer: (C) $896
Question: The average age of 60 students in a class is 10years. If teacher's age is also included then average increases 1year then find the teacher's age?
(A) 71
(B) 65
(C) 61
(D) 45
(E) 36
Rationale: Total age of 50 students = 60*10 = 600
Total age of 51 persons = 61*11 = 671
Age of teacher = 671-600 = 71years
Answer is A
Answer: (A) 71
Question: In a three digit number, the hundred digit is 2 more than the tens digit and the units digit is 2 less than the tens digit. If the sum of the digits is 15, find the number?
(A) 867
(B) 864
(C) 753
(D) 946
(E) 549
Rationale: C
753
Let the three digit numbers be 100a + 10b + c
a = b + 2
c = b - 2
a + b + c = 3b = 15=> b = 5
So a = 7 and b = 3
Hence the three digit number is: 753
Answer: (C) 753
Question: How many pieces of 0.36 meteres can be cut from a rod 26.5 meteres long
(A) 30
(B) 40
(C) 50
(D) 60
(E) 73
Rationale: Explanation:
We need so simple divide 26.5/0.36,
=(2650/36) = 73
Option D
Answer: (D) 60
Question: man can row upstream at 25 kmph and downstream at 35 kmph, and then find the speed of the man in still water?
(A) 12
(B) 22
(C) 30
(D) 88
(E) 13
Rationale: US = 25
DS = 35
M = (35 + 25)/2
= 30
Answer:C
Answer: (C) 30
Question: A man bought 6 pencils for Rs 5 and sold them at 5 pencils for Rs. 6. Calculate his gain percentage
(A) 78
(B) 26
(C) 44%
(D) 43
(E) 82
Rationale: Explanation:
No explanation is available for this question!
ANSWER:C
Answer: (C) 44%
Question: When 30 is subtracted from a number, it reduces to seven-twelve of the number. What is the sum of the digit of the number
(A) 40
(B) 44
(C) 46
(D) 48
(E) 72
Rationale: Explanation:
Let the number be x. Then,
x -30 = 7x/12 => x - 7x/12 = 30
5x/12 = 30 => x = 72
Answer: Option E
Answer: (E) 72
Question: A line of 24 children walk single file down the 54-meter hallway of their school at a speed of 20 meter/min. If each child takes up 1/4 meter of space in line, how long does it take for all of them to traverse the full length of the hallway?
(A) 1 min
(B) 2 min
(C) 3 min
(D) 4 min
(E) 5 min
Rationale: C
3 min
d = 24 * 1/4 m + 54 m = 60 m
T = 60 meters / 20 meters/min = 3 min
Answer: (C) 3 min
Question: Each of 16 individuals is to be given an identifying code consisting of one or more distinct digits in ascending order. What is the minimum number of distinct digits needed to give each individual a unique code?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: TWO WAYS-
1) we can do by looking at choices too
3-digits
since 3 is the lowest lets see how many can be nad ewith 3..
1) single digit - 3
2) 2 digits - different digits - 3*2/2 = 3.... 12,13,23
3) 3-digits - 123 - only 1
total = 3+3+1 =7...
4-digits
1) single digit - 4
2) 2 digits - different digits - 4*3/2 = 6.... 12,13,14,23,24,34
3) 3-digits - 4*3*2/3! = 4
4) 4-digits - 4*3*2/4! = 1
Total = 4+6+4+1 = 15
so 5 should be the answer
ANSWER:C
Answer: (C) 5
Question: If it was two hours later, it would be half an hour as long until midnight as it will be if it were an hour later. What is the time now?
(A) 9.10 pm
(B) 7.00 pm
(C) 9.00 pm
(D) 8.00 pm
(E) 9.30 pm
Rationale: Let the present time be x, the time after one hour is (x+1) and the time after two hours is (x+2), the time at mid night is 12
The time from one hour later to midnight is 12-(x+1)
The time from two hours later to midnight is 12-(x+2)
Given, the time from one hour later is twice of the time from two hours later,
12-(x+1) is twice of 12-(x+2)
12-x-1 = 24-2x-4
x=9
The present time is 9.00 pm
The time after one hour is 10.00 pm( two hours to 12) and the time after two hours is 11.00 pm( one hour to midnight)
The answer is 9.00 pm
ANSWER:C
Answer: (C) 9.00 pm
Question: If a and b are the two values of t that satisfy
the equation t^2 â€“ 8t + 12 = 0, with a > b, what is the value of a â€“ b?
(A) 2
(B) 4
(C) 6
(D) 8
(E) 10
Rationale: Factor the left side of the equation:
t^2 â€“ 8t + 12 = 0
(t â€“ 2)(t â€“ 6) = 0
t = 2, t = 6
Thus, a = 6 and b = 2. So a â€“ b = 6 â€“ 2 = 4.
The answer is B.
Answer: (B) 4
Question: Statements: Population increase coupled with depleting resources is going to be the scenario of many developing countries in days to come.
Conclusions:
1) The population of developing countries will not continue to increase in future.
2) It will be very difficult for the governments of developing countries to provide its people decent quality of life.
(A) Only conclusion I follows
(B) Only conclusion II follows
(C) Either I or II follows
(D) Neither I nor II follows
(E) Both I and II follow
Rationale: The fact given in I is quite contrary to the given statement. So, I does not follow. II mentions the direct implications of the state discussed in the statement. Thus, II follows.
B
Answer: (B) Only conclusion II follows
Question: A began business with Rs.45000 and was joined afterwards by B with Rs.27000. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
(A) 1
(B) 6
(C) 7
(D) 8
(E) 2
Rationale: 45*12 : 27*x = 2: 1
x = 10
12 -10 = 2
Answer: E
Answer: (E) 2
Question: In a school of 450 boys, 44% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
(A) 72
(B) 75
(C) 80
(D) 81
(E) 90
Rationale: 44 + 28 + 10 = 82%
100 – 82 = 18%
450 * 18/100 = 81
ANSWER:D
Answer: (D) 81
Question: An bus covers a certain distance at a speed of 230 kmph in 5 hours. To cover the samedistance in 1hr, it must travel at a speed of?
(A) 690 km/hr
(B) 720 km/hr
(C) 730 km/hr
(D) 750 km/hr
(E) 760 km/hr
Rationale: Distance = (230 x 5) = 1150 km.
Speed = Distance/Time
Speed = 1150/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
Required speed = 1150 x 3 km/hr = 690 km/hr.
A
Answer: (A) 690 km/hr
Question: For any non-zero a and b that satisfy |ab| = ab and |a| = -a
|b - 4| + |ab + b| = ?
(A) a) ab - 4
(B) b) 2b - ab - 4
(C) c) ab + 4
(D) d) ab - 2b + 4
(E) e) 4 - ab
Rationale: |a| = -a Suggests that 'a' is Negative
|ab| = ab Suggests that 'ab' is Positive
'ab' is Positive Suggests that 'a' and 'b' have same Sign i.e. either both positive or both negative
But since 'a' is Negative therefore 'b' is Negative too.
Since b is negative so |b - 4| = -b+4
Since ab is Positive and b is Negative so |ab - b| = ab + b
i.e. |b - 4| + |ab - b| = -b+4 + ab + b =ab + 4
Answer: Option C
Answer: (C) c) ab + 4
Question: The reduction in the speed of an engine is directly proportional to the square of the number of bogies attached to it. The speed of the train is 100 km/hr when there are 4 bogies and 55 km/hr when there are 5 bogies. What is the maximum number of bogies that can be attached to the train so that, even with those many numbers of bogies, it can just move?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: We know that S=Smax−K×(bogies)2
When there are 4 bogies speed of the train is 100km/hr 100=Smax−K×(4)2 ⇒100=Smax−K×16.......(1)
When there are 5 bogies speed of the train is 55km/hr
55=Smax−K×(5)2⇒ 55 = Smax−K×25 ........(2)
(2) - (1) gives 9K=45⇒K=5
By substituting K = 5 in either (1) or (2) we can find the maximum speed of the train = 180 km/hr
Assume, for N number of bogies the train does not move.
⇒0=180−5(N)2⇒N=6
If the engine is attached to 6 bogies, it does not move. If we want the train to move we need to attach maximum of 5 bogies
Answer C
Answer: (C) 5
Question: The greatest number of four digits which is divisible by 12, 20, 36 and 60 is:
(A) 9000
(B) 9900
(C) 9500
(D) 9800
(E) 9700
Rationale: Greatest number of 4-digits is 9999.
L.C.M. of 12, 20, 36 and 60 is 180.
On dividing 9999 by 180, the remainder is 99.
Required number (9999 - 99) = 9900.
Answer: Option B
Answer: (B) 9900
Question: The amount of time that three people worked on a special project was in the ratio of 3 to 5 to 6. If the project took 140 hours, how many more hours did the hardest working person work than the person who worked the least?
(A) 32 hours
(B) 40 hours
(C) 35 hours
(D) 30 hours
(E) 36 hours
Rationale: Let the persons be A, B, C.
Hours worked:
A = 3*140/14 = 30 hours
B = 5*140/14 = 50 hours
C = 6*140/14 = 60 hours
C is the hardest worker and A worked for the least number of hours. So the difference is 60-30 = 30 hours.
Answer : D
Answer: (D) 30 hours
Question: If n is the product of the first 10 prime numbers, which of the following is an integer?
I. n/7
II. n/4
III. n/143
(A) I only
(B) I and II only
(C) I and III only
(D) III only
(E) I, II, and III
Rationale: The product of first 10 prime numbers is: 2*3*5*7*11*13*17*19*23*29 = n
I) n/7 is an integer --> Yes (It is a part of the product)
II) n/4 is an integer --> No (2 is present only once in the product, not twice)
III) n/143 is an integer --> Yes (Both 11 and 13 are a part of the product)
Answer: C
Answer: (C) I and III only
Question: A Flask contains a mixture of AB in the ratio 5:2. When 20 L of Mixture is replaced with liquid B, ratio becomes 4:1. How many liters of liquid A was present in mixture initially.
(A) 10
(B) 22
(C) 15
(D) 30
(E) 8
Rationale: Let the volume of the initial total mixture was V. When 20L of mixture is removed the volume becomes (V - 20). The concentration stays 5:2.
Next step, when you add 20 litres of B, the amount of A does not change.
So
Amount of A in original mix = Amount of A in final mix
C1 * V1 = C2 * V2
(5/7)*(V - 20) = (4/5)*V
V = 30.8
So volume of A in initial mixture was (5/7) * 30.8 = 22 litres
Answer B
Answer: (B) 22
Question: The sum of the fourth and twelfth term of an arithmetic progression is 20. What is the sum of the first 16 terms of the arithmetic progression?
(A) 300
(B) 120
(C) 150
(D) 160
(E) 270
Rationale: n th term of A.P. is given by a+(n-1)d
4 th term = a+3d
12 th term = a+11d
Given a+3d+a+11d=20 --> 2a+14d=20 --> a+7d = 10
Sum of n term of A.P = n/2[2a+(n-1)d]
subsitiuing n = 16 ...we get 15/2[ 2a + 14d] = 16 [a+7d] = 16*10 = 160...
Answer is D...
Answer: (D) 160
Question: A piece of string is 40 centimeters long. It is cut into three pieces. The longest piece is 3 times as long as the middle-sized piece and the shortest piece is 23 centimeters shorter than the longest piece. Find the lengths of the three pieces.
(A) 27
(B) 5
(C) 4
(D) 9
(E) 8
Rationale: Explanation :
Let the largest piece = 3x.
Middle = x.
Shortest = 3x – 23.
or 3x + x + (3x – 23) = 40.
or x = 9
or the shortest piece = 3(9) – 23 = 4
Check choices:
The shortest piece has to be < 20 cm.
27 is wrong choice.
The largest piece is a multiple of 3.
Or (23 + Shortest) should be a multiple of 3.
Hence ,the answer = 4 cm.
Answer : C
Answer: (C) 4
Question: A sum is divided among W, X and Y in such a way that for each rupee W gets, X gets 30 paisa and Y gets 20 paisa. If the share of W is RS. 10, what is the total amount?
(A) 12
(B) 13
(C) 14
(D) 15
(E) 16
Rationale: w:x:y = 100:30:20
20:6:4
20 --- 10
30 --- ? => 15
Answer:D
Answer: (D) 15
Question: If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?
(A) 120 cm2
(B) 197 cm2
(C) 876 cm2
(D) 267 cm2
(E) 268 cm2
Rationale: The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle
= 1/2 * 24 * 10
= 120 cm2
Answer: A
Answer: (A) 120 cm2
Question: In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 10 overs to reach the target of 282 runs?
(A) 6.25
(B) 5.5
(C) 25
(D) 15
(E) 6
Rationale: Explanation:
Runs scored in the first 10 overs = 10 × 3.2 = 32
Total runs = 282
Remaining runs to be scored = 282 - 32 = 250
Remaining overs = 10
Run rate needed = 250/10=25
Answer: Option C
Answer: (C) 25
Question: If the number 872,152,24x is divisible by 11, what must be the value of x?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: Multiplication rule of 11: (Sum of digits at odd places - Sum of digits at even places) should be divisible by 11
Given number: 872,152,24x
Sum of digits at odd places = 8 + 2 + 5 + 2 + x = 17 + x (i)
Sum of digits at even places = 7 + 1 + 2 + 4 = 14 (ii)
(i) - (ii) = 17 + x - 14 = x - 3
Hence x should be = 3 to make this a multiple of 11 (0) Option C
Answer: (C) 3
Question: What is the measure of the radius of the circle inscribed in a triangle whose sides measure 8, 15 and 21 units?
(A) 8.5 units
(B) 2.6 units
(C) 3 units
(D) 5 units
(E) 12 units
Rationale: Sides are 8, 15 and 21...thus it is right angle triangle Since 21^2 = 8^2 + 15^2
therefore, area = 1/2 * 15 * 8 = 60
We have to find in-radius
Therefore, area of triangle = S*r ....where S=semi-perimeter and r= in-radius
Now S=semi-perimeter = 21+15+8 /2 = 22
Thus , 60 =22*r
and hence r=in-radius= 2.6
Option B
Answer: (B) 2.6 units
Question: The average monthly salary of the employees of a firm is Rs.60 out of the employees 12 officers get an average of Rs.400 per month and the rest an average of Rs. 56 per month , Find the number of emp
(A) 3278
(B) 1028
(C) 1022
(D) 1029
(E) 1032
Rationale: Actual average salary of 12 officers = 400
Total salary of 12 officers = 400 x 12 = 4800
Average of these 12 officers as a whole =60
Total salary of 12 officers as a whole = 60 x 12 = 720
The total salary of rest = 4800 - 720 = 4080
Difference in average of the rest of officers = 60 - 56 = 4
Rest of the officers = {4080}/{4}=1020
Total number of employees = 1020 + 12 = 1032
Answer:E
Answer: (E) 1032
Question: Three persons invested Rs.9000 in a joint business. The second person invested Rs.1000 more than the first and the third Rs.1000 more than second. After two years, they gained Rs.5400. How much third person will get?
(A) 2400
(B) 2429
(C) 2980
(D) 2707
(E) 2872
Rationale: First persons investment = x
Second persons investment = x + 1000
Third persons investments = x + 2000
x + x + 1000 + x + 2000 = 9000
3x = 6000
x = 2000
Ratio = 2000 : 3000 : 4000
2:3:4
4/9 * 54000 = 2400
Answer:A
Answer: (A) 2400
Question: 400 metres long yard, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees
(A) 10
(B) 12
(C) 14
(D) 16
(E) 18
Rationale: 26 trees have 25 gaps between them,
Required distance (400/25) = 16
D
Answer: (D) 16
Question: If the sum of two numbers is 45 and the H.C.F and L.C.M of these numbers are 4 and 5 respectively, then the product of the reciprocals is equal to:
(A) 20/20
(B) 1/1
(C) 2/30
(D) 11/20
(E) 1/20
Rationale: Let the numbers be a and b.
Then, a + b = 45 and ab = 5 * 4 = 20.
Required product = 1/a * 1/b = 1/ab = 1/20= 1/20.
ANSWER:E
Answer: (E) 1/20
Question: Two trains are traveling on a collision course. If train A is traveling at a speed of 350 mph and train B is traveling 28% slower, how much time will it take the trains to collide if the initial distance between the two is 1505 miles?
(A) Two hours and 30 minutes
(B) One hour and 10 minutes
(C) Two hours and 25 minutes.
(D) Three hours and 15 minutes
(E) Four hours and 20 minutes
Rationale: let S1 and S2 be the speeds of train A and B
S1 is 350 and S2=28% less = 252
time taken = S1+S2/1505
which is
1505/602 =x
where 2<x<3
therefore C !!
Answer: (C) Two hours and 25 minutes.
Question: The average of first nine prime numbers:
(A) 5.6
(B) 11.1
(C) 12.9
(D) 6.3
(E) 7.4
Rationale: Explanation:
The first ten prime numbers is 2, 3, 5, 7, 11, 13, 17, 19, 23
Average = 100/9 = 11.11
Answer: Option B
Answer: (B) 11.1
Question: How many two-element subsets of <1, 2,3,4,5,6,7,8,9> are there that do not contain the pair of elements 2 and 4?
(A) 21
(B) 22
(C) 24
(D) 35
(E) 36
Rationale: 9C2 - 1 = 35 Answer is D
Answer: (D) 35
Question: John makes $60 a week from his job. He earns a raise andnow makes $70 a week. What is the % increase?
(A) 16%
(B) 16.66%
(C) 18%
(D) 19%
(E) 21%
Rationale: Increase = (10/60)*100 = (1/6)*100 = 16.66%.
B
Answer: (B) 16.66%
Question: One ton has 2600 pounds, and one pound has 16 ounces. How many packets containing wheat weighing 16 pounds and 4 ounces each would totally fill a gunny bag of capacity 13 tons?
(A)  2080
(B)  1700
(C)  2350
(D)  2500
(E)  8000
Rationale: 16 pounds and 4 ounces= 16*16 + 4 = 260 ounces.
13 tons = 13*2600 pound = 13*2600*16 ounces.
Hence the answer is (13*2600*16)/260 = 2080.
Answer: A.
Answer: (A)  2080
Question: When the price of a pressure cooker was increased by 15%, the sale of pressure cookers decreased by 15%. What was the net effect on the sales?
(A) 15% decrease
(B) no effect
(C) 2.25% increase
(D) 2.25% decrease
(E) None of these
Rationale: Net effect on sale = −(common%change)2/100
= −(15)2/100= 2.25% decrease
Answer D
Answer: (D) 2.25% decrease
Question: There are 43 stations between Ernakulam and Chennai. How many second class tickets have to be printed, so that a passenger can travel from one station to any other station?
(A) 1980
(B) 1920
(C) 1990
(D) 1890
(E) 1900
Rationale: The total number of stations= 45
From 45 Stations we have to choose any two stations and the direction of travel (Ernakulam to Chennai is different from Chennai to Ernakulam) in 45P2 ways.
45P2= 45*44= 870
ANSWER:A
Answer: (A) 1980
Question: What is the average of 1200, 1300, 1400, 1510, 1520, 1530, 1115, 1120, and 1125?
(A)  1345
(B)  1334
(C)  1313.33
(D)  1350
(E)  1325
Rationale: Add 1200, 1300, 1400, 1510, 1520, 1530, 1115, 1120, and 1125
Grouping numbers together may quicken the addition
sum = 11820
11820/9 =1313.33
C
Answer: (C)  1313.33
Question: What no. should be subtracted from x^3+4x^2−7x+12x^3+4x^2−7x+12, if it is to be perfectly divisible by x+3x+3?
(A) 17
(B) 42
(C) 46
(D) 54
(E) 56
Rationale: According to remainder theorem when dfracf(x)x+adfracf(x)x+a, then the remainder is f(−a)f(−a).
In this case, as x+3x+3 divides x3+4x2−7x+12–kx3+4x2−7x+12–k perfectly (kk being the number to be subtracted), the remainder is 0 when the value of xx is substituted by -3.
i.e., (−3)3+4(−3)2−7(−3)+12−k=0(−3)3+4(−3)2−7(−3)+12−k=0
or −27+36+21+12=k−27+36+21+12=k
or k=k= 42
B
Answer: (B) 42
Question: 1, 3, 4, 7, 11, 18, 29, ?
What number should replace the question mark?
(A) 33
(B) 54
(C) 24
(D) 35
(E) 47
Rationale: E
47
Each number is the sum of the previous two numbers, ie 18 + 29 = 47.
Answer: (E) 47
Question: It is required to fix a pipe such that water flowing through it at a speed of 7 metres per minute fills a tank of capacity 110 cubic metres in 10 minutes. The inner radius of the pipe should be :
(A) √2 m
(B) 2 m
(C) 1⁄2 m
(D) 1⁄√2 m
(E) None of these
Rationale: Let inner radius of the pipe be r.
Then, 110 = 22⁄7 × r2 × 7 × 10
or r2=110/22×10=1/2
or r = 1/√2 m
Answer D
Answer: (D) 1⁄√2 m
Question: The cost of a car is 400% greater than the cost of a bike. If there is an increase in the cost of the car is 15% and that of bike 20%. Then the total increase in the cost of the 5 cars and 10 bikes is:
(A) 17.5%
(B) 16(3/7)%
(C) 18.5%
(D) 18.25%
(E) None
Rationale: Solution: Let the bike's initial cost be X and then car's initial cost be 5X.
After the increase,
Bike price = 1.2X
Car price = 5.75X
Initial total cost of 5 cars and 10 bikes,
= 25X+10X = 35X
New cost,
= 28.75X+12x = 40.75X
Change in cost = (40.75X-35X) = 5.75X
% change = (5.75X*100)/35 = 16(3/7)%.
Answer: Option B
Answer: (B) 16(3/7)%
Question: What is the area of square field whose side of length 17 m?
(A) 225
(B) 662
(C) 772
(D) 289
(E) 21
Rationale: 17 * 17
= 289 sq m
Answer:D
Answer: (D) 289
Question: Last year John earned m dollars at company X and was promised an n-percent raise for this year. If John is paid the promised amount and a $10,000 bonus at the end of this year, by what percent has his total salary(including his bonus) increased this year over last in terms of n and m?
(A) (mn + 10000)/m %
(B) (n + 10000)/m %
(C) (mn + 100,000)/100m %
(D) (mn + 1,000,000)/100m %
(E) (mn + 1,000,000)/m %
Rationale: Old Salary = m dollars
New salary = M (1 + n/100) + 10,000
Net increase = m*n/100 + 10,000
Percentage change = (mn/100 + 10,000)*100/m
= (mn + 1,000,000)/m%
Answer: E.
Answer: (E) (mn + 1,000,000)/m %
Question: Manoj borrowed Rs.3450 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.824.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?
(A) 5352
(B) 5355
(C) 5328
(D) 5312
(E) 5128
Rationale: Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3450.3.6/100 = Rs.824.85
27P = 62100 = 82485
P = (82485 + 62100)/27 = 3055 + 2300 = Rs.5355
Answer: B
Answer: (B) 5355
Question: In a division sum, the quotient is 120, the divisor 456 and the remainder 333, find the dividend?
(A) 23504
(B) 34545
(C) 55053
(D) 23434
(E) 23456
Rationale: Explanation:
120 * 456 + 333 = 55053
C
Answer: (C) 55053
Question: A cistern which could be filled in 9 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it?
(A) 27 hrs
(B) 29 hrs
(C) 28 hrs
(D) 90 hrs
(E) 98 hrs
Rationale: 1/9 - 1/x = 1/10
=> 90 hrs
Answer:D
Answer: (D) 90 hrs
Question: A started a business with an investment of Rs. 70000 and after 6 months B joined him investing Rs. 120000. If the profit at the end of a year is Rs. 50000, then the share of B is?
(A) 23077
(B) 24000
(C) 24005
(D) 24009
(E) 24002
Rationale: Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6
Total profit = Rs. 50000
Share of B = 6/13 (50000) = Rs. 23076.92~ 23077
Answer: A
Answer: (A) 23077
Question: What percent of 14 is 14 percent of 1?
(A)  0.001
(B)  0.01
(C)  0.1
(D)  101
(E)  1
Rationale: 14 % of 1 = (14/100) * 1 = 14/100
To determine what percentage of 14 this is :
[14][/100*14] *100 = 1%
Ans : E
Answer: (E)  1
Question: A, B and C completed a piece of work, A worked for 6 days, B for 9 days and C for 4 days. Their daily wages were in the ratio of 3:4:5. Find the daily wages of C, if their total earning was Rs.1628?
(A) s.109
(B) s.108
(C) s.110
(D) s.103
(E) s.102
Rationale: 3x 4x 5x
6 9 4
18x + 36x + 20x = 1628
74x = 1628 => x = 22
5x = 110 Rs.
Answer:C
Answer: (C) s.110
Question: In the line xy plane line m has the equation y = 3x - 9, then the line m passes through which of the following points?
(A) (3, 1)
(B) (3, 4)
(C) (4, 2)
(D) (6, 9)
(E) (6, 15)
Rationale: Yes it is y=3x-8....extremely sorry for mistake....
IF that's the case then answer is D
y=3x-8
9=3X6-9
9=18-9
9=9 (satisfied)
Answer: (D) (6, 9)
Question: 10 men, working 6 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the work in 12 days ?
(A) 4 hours a day
(B) 5 hours a day
(C) 6 hours a day
(D) 7 hours a day
(E) 8 hours a day
Rationale: Explanation:
More Men, Less Hours {Indirect Proportion}
Less Days, More Hours {Indirect Proportion}
[men 15 10
days 12 18] ::6:x
=>x∗15∗12=10∗18∗6
=>x=10∗18∗6/ 15∗12
=>x=6
Option C
Answer: (C) 6 hours a day
Question: If p is an odd integer, which of the following must also be odd?
(A) 4p + 4
(B) p + p
(C) 3p + 3
(D) 2p + p
(E) p^2 + 1
Rationale: Things to keep in mind:
Odd + odd = even
Odd + even = odd
Odd*odd = odd
Odd*even = even
On checking each option
A. 4p + 4
4p = even, 4p + 4 = even + even = even.
B. p + p
Odd + odd = even. This will be even
C. 3x + 3
3x = odd, 3x + 3 = odd + odd = even
D. 2p + p
2p = even, 2p + p = even + odd = odd
E. p^2 + 1
p^2 = odd, p^2 + 1 = odd + odd = even
Correct option: D
Answer: (D) 2p + p
Question: In a LAB experiment, a 100 ml compound of element X and element Y needs to be increased to 240 ml by adding some quantity of element X, and some quantity of element Y. If the original compound contains 30% of element X, how much (in ml) of element Y must be added so that element X will be exactly one third of the resulting mixture ?
(A) 40 ml
(B) 100/3 ml
(C) 20 ml
(D) 90 ml
(E) 10 ml
Rationale: There are 0.3*100=30 ml of element X in the initial solution.
We need X to be 1/3rd of 240 ml in the resulting solution, so 80 ml. Thus out of 140 ml of solution added, 50 must be X (in order it to become 80 ml) ans the remaining 90 must be Y.
Answer: D
Answer: (D) 90 ml