mathewhe/aqua_rat huggingface dataset:
Question: A grocer has a sale of Rs. 800, Rs. 900, Rs. 1000, Rs. 700 and Rs. 800 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 850?
(A) s. 440
(B) s. 850
(C) s. 450
(D) s. 900
(E) s. 950
Rationale: Total sale for 5 months = Rs. (800 + 900 + 1000+ 700 + 800) = Rs. 4200
Required sale = Rs. [ (850 x 6) - 4200 ]
= Rs. (5100- 4200)
= Rs. 900.
Option D
Answer: (D) s. 900
Question: In baseball, the batting average is defined as the ratio of a player’s hits to at bats. If a player had anywhere from 6 to 8 at bats in a recent game and had anywhere from 6 to 7 hits in the same game, the player’s actual batting average for that game could fall anywhere between
(A) 0.25 and 1.00
(B) 0.50 and 0.75
(C) 0.70 and 1.25
(D) 0.33 and 0.50
(E) 0.50 and 0.66
Rationale: Average Range = Hits to Bats i.e 6/8 to 7/6 = 0.75 to 1.16
Answer: C
Answer: (C) 0.70 and 1.25
Question: How many odd factors does 160 have?
(A)  2
(B)  4
(C)  5
(D)  6
(E)  8
Rationale: Start with the prime factorization: 160 = 2*5
For odd factors, we put aside the factor of two, and look at the other prime factors.
set of exponents = {1}
plus 1 to each = {2}
product = 2
Therefore, there are 2 odd factors of 160.
Answer: A.
Answer: (A)  2
Question: A girl has exactly 5 quarters, 8 dimes, and 10 nickels in her pocket. If she withdraws a number of these coins at random, how many coins would she have to withdraw to ensure that she has at least a 50 percent chance of withdrawing at least one quarter?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: When the probability of NOT drawing a quarter is 50% or less, then the probability of drawing a quarter is at least 50%.
P(not drawing a quarter with 2 coins) = 18/23 * 17/22 = 153/253 > 50%
P(not drawing a quarter with 3 coins) = 153/253 * 16/21 = 816/1771 < 50%
The answer is B.
Answer: (B) 3
Question: Consider two postmen A and B respectively. A is young and can deliver 20 parcels in 3 hours while B is older than A and can deliver only 15 parcels in 4 hours. If the total number of parcels to deliver is 60, how long they will take working together.
(A) 121/12 hours
(B) 144/36 hours
(C) 144/25 hours
(D) 121/25 hours
(E) 141/25 hours
Rationale: work done by 1st = 20/3 , work done by 2nd = 15/4 (here work is work/hour)
total work done together = 20/3+15/4 =125/12
time to do 60 unit work(ie, parcels)= 60*12/125 = 144/25
ANSWER:C
Answer: (C) 144/25 hours
Question: One boy forgot the lastdigit of a 7 digit telephone no. If he randomly dialthe final 3 digits after correctly dialing the 1st four, then what is the chance of dialing the correct no.?
(A) 2/995
(B) 1/998
(C) 1/1000
(D) 1/1100
(E) 1/1200
Rationale: it is given that last 3 digits are randomly dialed
Then, each of the digit can be selected out of 10 digits in 10 ways. Hence, required probability
= 1/(10)3 = 1/1000
C
Answer: (C) 1/1000
Question: Oil cans x and y are right circular cylinders and the height and radius of y are each 4 times those of x. If the oil in can x filled to capacity sells for $2, how much does the oil in y sell for if y is only half filled?
(A) $60
(B) $52
(C) $63
(D) $64
(E) $68
Rationale: formula for vol of a cyl is PI*r^2*h
so Vy = 64*Vy
y when half filled will cost 32 times x so ans is D
Answer: (D) $64
Question: For 600 km journey it will take 8hrs, if 120 km is done by bus and the rest by car. It takes 20 minutes more, if 200 km is done by busand the rest by car. The ratio of the speed of the train to that of the cars is?
(A) 1 : 2
(B) 3 : 4
(C) 3 : 5
(D) 5 : 7
(E) 1 : 5
Rationale: Let the speed of the train be x km/hr and that of the car be y km/hr.
Then, 120 + 480 = 8 1 + 4 = 1 ....(i)
x y x y 15
And, 200 + 400 = 25 1 + 2 = 1 ....(ii)
x y 3 x y 24
Solving (i) and (ii), we get: x = 60 and y = 80.
Ratio of speeds = 60 : 80 = 3 : 4
B
Answer: (B) 3 : 4
Question: The average age of 31 students in a group is 16 years. when teacher's age is included to it, the average increases by one.What is the teacher's age in years?
(A) 31
(B) 36
(C) 48
(D) 45
(E) 57
Rationale: age of the teacher=(32*17-31*16)
=48 years.
ANSWER:C
Answer: (C) 48
Question: A plane flies 440 km with the wind and 360 km against the wind in the same length of time. If the speed of the wind is 20 km/h, what is the speed of the plane in still air?
(A) 160 km/h
(B) 170 km/h
(C) 180 km/h
(D) 190 km/h
(E) 200 km/h
Rationale: The speed of the plane in still air = x km/h
The speed of the wind is 20 km/h
Speed with the wind = (x + 20) km/h
Speed against the wind = (x â€“ 20) km/h
Time = Distance/ Speed
440 / (x+20) = 360 / (x-20)
440(x-20) = 360(x+20)
44x - 880 = 36x + 720
8x = 1600
x = 200
Therefore, the speed of the plane in still air is 200 km/h.
The answer is E.
Answer: (E) 200 km/h
Question: present ages of A and B are in the ratio of 5:3 respectively. 4 years hence, the ratio of their ages will become 11:9 respectively . what A's age after 3 years?
(A) 25
(B) 21
(C) 28
(D) 24
(E) 35
Rationale: A and B be 5x years and 3x years respectively
(5x+4)/(3x+4)=11/9
9(5x+4)=11(4x+4), 45x+36=44x+44
x=8, therefore A's present age : 3x=24 years
A's age after 4 year = 24+4 = 28
correct answer(B)
Answer: (B) 21
Question: Paint needs to be thinned to a ratio of 2 parts paint to 1.5 parts water. The painter has by mistake added water so that he has 6 litres of paint which is half water and half paint. What must he add to make the proportions of the mixture correct?
(A) 1 litre paint
(B) 1 litre water
(C) Â½ litre water and one litre paint
(D) Â½ litre paint and one litre water
(E) None of these
Rationale: Explanation:
At the moment the paint is 3 liters of paint and 3 liters of water. We need to add to this to make the new ratio 2 liters paint to 1.5 liters water. As this is equivalent to 4 : 3 we can see that we have the right amount of water, and just need 1 liter of paint to make it correct.
Answer: A
Answer: (A) 1 litre paint
Question: A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 2 of 12 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions?
(A) 42
(B) 70
(C) 140
(D) 165
(E) 462
Rationale: Ans: 462
7C1 * 12C2
Answer E)
Answer: (E) 462
Question: Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Child A has to sit next to both B & G, with these two children immediately adjacent to Child A on either side. The other four children can sit in any order in any of the remaining seats. How many possible configurations are there for the children?
(A) 240
(B) 480
(C) 720
(D) 1440
(E) 3600
Rationale: First we can imagine the trio ABG as one item to arrange along with four other items: C , D, E, F.
This can be done in 5! = 120 ways
However the trio can be arranged in 2 ways: BAG or GAB.
So, total number of ways to sit the seven children is equal to 2*120 = 240 (option A)
Answer: (A) 240
Question: Coffee worth amount Rs. 126 per kg are mixed with third variety in the ratio 1: 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg
(A) 175.5
(B) 200.5
(C) 125.5
(D) 225.5
(E) 250.5
Rationale: x==>153/22.50 = 1 => x - 153 = 22.50 => x=175.50.
ANSWER A
Answer: (A) 175.5
Question: Rice weighing 33/4 pounds was divided equally and placed in 4 containers. How many ounces of rice were in each container? (Note that 1 pound = 16 ounces)
(A) 27
(B) 30
(C) 33
(D) 36
(E) 39
Rationale: 33/4 ÷ 4 = 33/16 pounds in each container
33/16 pounds * 16 ounces / pound = 33 ounces in each container
The answer is C.
Answer: (C) 33
Question: Wednesday occurred on 15th September 2010. What was the day of the week on 15th September 2009?
(A) Monday
(B) Friday
(C) Wednesday
(D) Tuesday
(E) Sunday
Rationale: 1 odd day in the year 2009
So, the day on 15th September 2010 will be one day beyond the day on 15th September 2009
But, 15th September 2010 is Wednesday
On 15th September 2009, it was Tuesday
Answer: D
Answer: (D) Tuesday
Question: On a certain test, Bill scored 20 more points than John, but half as many points as Sue. If the sum of the scores of the three students was 120 points, how many points did Bill receive?
(A) 35
(B) 40
(C) 50
(D) 80
(E) 100
Rationale: consider john's points as x
so bill's points are x +20
So sue's points are 2x +40
total of all three students is 4x +60, but this total is given as 120
x = 15
so bill's points = 15 +20 = 35
correct answer option A
Answer: (A) 35
Question: Train A traveling at 60 km/hr leaves Mumbai for Delhi at 6 P.M. Train B traveling at 90 km/hr also
leaves Mumbai for Delhi at 9 P.M. Train C leaves Delhi for Mumbai at 9 P.M. If all three trains meet at the same time between Mumbai and Delhi, what is the speed of Train C if the distance between Delhi and Mumbai is 1260 kms?
(A) 110km/hr
(B) 120km/hr
(C) 130km/hr
(D) 140km/hr
(E) 150km/hr
Rationale: let time taken by train b is t hrs to meet train A
so let the train A and B meets at distance x
As the distance will be same so
time taken by train A is t+3
so 60*(t+3)=90*t
so t = 6hrs
now distance covered by train A is 90*6=540
And the remaining distance will be covered by train c to meet = 1260-540=720
so speed of train c is 720/6=120km/hr
ANSWER:B
Answer: (B) 120km/hr
Question: The dimensions of a rectangular solid are 4 inches, 6 inches, and 8 inches. If a cube, a side of which is equal to one of the dimensions of the rectangular solid, is placed entirely within thespherejust large enough to hold the cube, what the ratio of the volume of the cube to the volume within thespherethat is not occupied by the cube?
(A)  10:17
(B)  2:5
(C)  5:16
(D)  25:7
(E)  2:3
Rationale: Answer: E.
Answer: (E)  2:3
Question: A restaurant spends one quarter of its monthly budget for rent and quarter of the rest for food and beverages. What percentage of the budget does the restaurant spend for food and beverages?
(A) 23.5%
(B) 32.5%
(C) 35%
(D) 18.75%
(E) 20%
Rationale: Spend on rent = 1/4
Spend on food and beverage= 1/4 of remaining = 1/4*3/4= 3/16
so 3/16= 18.75%
D is the answer
Answer: (D) 18.75%
Question: Read the following three equations:
5 ~ 4 ~ 3 ~ 9 = 4215
6 ~ 9 ~ 2 ~ 6 = 3816
4 ~ 7 ~ 3 ~ 3 = 1122
Now based on the rule that has been used, solve the following equation:
8 ~ 2 ~ 7 ~ 4 = ____
(A) 3412
(B) 2910
(C) 2940
(D) 3749
(E) 4470
Rationale: A
3412
3412
The rule that is being followed here is
P ~ Q ~ R ~ S = [first digit of (P * S)] [last digit of (Q * R)] [first digit of (Q * R)] [last digit of (P * S)]
Using the same rule in the incomplete equation,
8 ~ 2 ~ 7 ~ 4 = [first digit of (8 * 4)] [last digit of (2 * 7)] [first digit of (2 * 7)] [last digit of (8 * 4)]
= 2418
Thus 3412 is the missing number.
Answer: (A) 3412
Question: A retailer buys 40 pens at the marked price of 35 pens from a wholesaler. If he sells these pens giving a discount of 1%, what is the profit percent?
(A) 12 %
(B) 10 %
(C) 15 %
(D) 16 %
(E) None
Rationale: Sol.
Let the marked price of each pen be Re. 1.
Then, C.P. of 40 pens = Rs. 36. S.P. of 40 pens = 99% of Rs. 40 = Rs. 39.60.
∴ Profit% = [3.60/36 * 100]% = 10%.
Answer B
Answer: (B) 10 %
Question: Positive integer n leaves a remainder of 4 after division by 5 and a remainder of 3 after division by 5. If n is greater than 30, what is the remainder that n leaves after division by 30?
(A) 3
(B) 12
(C) 18
(D) 22
(E) 28
Rationale: The theory says:
if a # x is devided by y and leave the positive # r as the remainder then it can also leave negative # (r-y) as the remainder.
e.g:
9 when devided by 5 leves the remainder 4 : 9=5*1+4
it can also leave the remainder 4-5 = -1 : 9=5*2 -1
back to the original qtn:
n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 5
==> n leaves a remainder of -2 (i.e. 4-6) after division by 6 and a remainder of -2 (i.e. 3-5) after division by 5
==> n when devided by 5 and 6 leaves the same remainder -2.
what is n?
LCM (5,6)-2 = 30-2 = 28
CHECK: 28 when devided by 6 leaves the remainder 4 and when devided by 5 leaves the remainder 3
However, the qtn says n > 30
so what is the nex #, > 28, that can give the said remainders when devided by 6 and 5
nothing but 28 + (some multiple of 6 and 5) as thissome multiple of 6 and 5will not give any remainder when devided by 5 or 6 but 28 will give the required remainders.
hence n could be anything that is in the form 28 + (some multiple of 6 and 5)
observe thatsome multiple of 6 and 5is always a multiple of 30 as LCM (5,6) = 30.
hence when n (i.e. 28 + some multiple of 6 and 5) is devided by 30 gives the remainder 22.
D
Answer: (D) 22
Question: In a school of 850 boys, 44% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
(A) 173
(B) 163
(C) 153
(D) 143
(E) 133
Rationale: 44 + 28 + 10 = 82%
100 – 82 = 18%
850 * 18/100 = 153
ANSWER:C
Answer: (C) 153
Question: Calculate the share of Y , if Rs. 2880 is divided among X, Y and Z in the ratio 3 : 5 : 8?
(A) 540
(B) 520
(C) 140
(D) 560
(E) 240
Rationale: 3 + 5 + 8 =16
2880/16=180
so Y's share=3*180
=540
ANSWER:A
Answer: (A) 540
Question: (2^x) (30^3) = (2^3) (3^3) (4^3) (5^3)
In the above equation, what is the value of x?
(A) 10
(B) 5
(C) 8
(D) 7
(E) 6
Rationale: E
6
Explanation:
(2^x)(30^3) = (2^3) (3^3) (4^3) (5^3)
(2^x)(30^3) = (120^3)
(2^x) = (120^3)/ (30^3)
(2^x) = (4^3)
(2^x) = 64
ln(2^x) = ln(64)
x ln(2) = ln(64)
x = ln(64)/ln(2)
x = 6
Thus x = 6.
Answer: (E) 6
Question: A man took some money for borrowed, for 3 years the total will be Rs.5500 and 5 years it will be Rs.6500/-. Then how much amount he borrowed?
(A) s.4000/-
(B) s.4500/-
(C) s.4770/-
(D) s.4800/-
(E) s.4820/-
Rationale: 3 years --------> Rs.5500/-
5 years --------> Rs.6500/-
~ ~
------------------------------
2 years ---------> Rs.1000/-
1 year ----------> Rs.500/-
3years * Rs.500/- = Rs.1500/-
P = Rs.5500/- - Rs.1500/- = Rs.4000/-
P = Rs.4000/-
A
Answer: (A) s.4000/-
Question: List I: 11, 13, 15, 19 List II: x,11, 13, 15, 19
(A) 10
(B) 12
(C) 11
(D) 13
(E) 14
Rationale: List I has even number of terms, thus its median is the average of two middle terms (when arranged in ascending/descending order), so median=(13+15)/2=14
List II has odd number of terms, thus its median is the middle term (when arranged in ascending/descending order). As no other number in the list equal to 14, then x=14.
Answer: E
Answer: (E) 14
Question: Round off the given number to nearest hundreds
2785
(A) 2700
(B) 3000
(C) 2900
(D) 2800
(E) 3100
Rationale: the given number is 2785
its tens digit is 8. so replace each of the tens and ones digit by 0 and increase the hundreds digit by 1 to get the rounded off number to the nearest hundred.
correct answer (D)
Answer: (D) 2800
Question: A gardener wants to plant flowers in his garden. He has 16 flowers. He has 10 flower pots. 2 flower pots are in the first row . 5 are in the second row and remaining 3 in the last row. He has 3 roses and the roses must be put only in the first row. The roses should not be kept anywhere else. The other flowers can be put in any pot. How many different groupings are possible?
(A) 216216
(B) 2006
(C) 3008
(D) 8007
(E) 2734
Rationale: 3C2 Select 3 Roses for first row
13C5 Select 5 flowers for second row from 13 flowers ( Since 3 roses cannot be used. 16-3 = 13)
8C3 Select 3 flowers for the last row from 8 flowers( Since 3 are roses which can be put in first row only and we have used 5 flowers for second row. 16-3-5 = 8)
Number of selection = 3C2 * 13C5 * 8C3 = 216216
Ans : A
Answer: (A) 216216
Question: which is the highest 3 digit number that divides nnumber 111....1(27 times ) perfactly without leaving remainder.
(A) 789
(B) 589
(C) 889
(D) 999
(E) 111
Rationale: 111....1(27 times )
divisble by 111
& 9 also as sum of digits = 27
reqd no. = 9*111 = 999
ANSWER:D
Answer: (D) 999
Question: What approximate value should come in place of question mark (?) in the following equation?
33 1⁄3% of 768.9 + 25% of 161.2 – 64.12 = ?
(A) 230
(B) 225
(C) 235
(D) 220
(E) 234
Rationale: ? = 33 1⁄3% of 768.9 + 25% of 161.2 – 64.12
= 1⁄3 of 768.9 + 1⁄4 of 161.2 – 64.12
= 256.3 + 40.3 – 64.12 ≈ 234
Answer E
Answer: (E) 234
Question: The average of 45 students in a class is 15 years. The average age of 25 students is 24. What is the average age of remaining 20 students?
(A) 30
(B) 25
(C) 20
(D) 15
(E) 35
Rationale: Sum of the ages of 14 students
= (20 * 45) - (24 * 25) = 900- 600= 300
Required average = (300/20) =15
Answer: D
Answer: (D) 15
Question: Three persons invested Rs.9000 in a joint business. The second person invested Rs.1000 more than the first and the third Rs.1000 more than second. After two years, they gained Rs.4500. How much third person will get?
(A) 2400
(B) 2878
(C) 2000
(D) 2662
(E) 1821
Rationale: First persons investment = x
Second persons investment = x + 1000
Third persons investments = x + 2000
x + x + 1000 + x + 2000 = 9000
3x = 6000
x = 2000
Ratio = 2000 : 3000 : 4000
2:3:4
4/9 * 4500 = 2000
Answer: C
Answer: (C) 2000
Question: A man sells an article at a gain 15%. If he had bought it at 10% less and sold it for 7 less, he would have gained 25%. Find the cost price of the article.
(A) 150
(B) 160
(C) 170
(D) 180
(E) 280
Rationale: Let the C.P. be 100
First S.P. = 115
Second C.P. = 90
Second S.P = 125% of 90 = 112.50
Difference of two selling prices is 115 – 112.50 = 2.50 and C.P. of the article is 100
But actual difference is 7.
∴ C.P. = 100⁄2.50 × 7 = 280.
Answer E
Answer: (E) 280
Question: In a workshop there are 3 kinds of beds, 3 kinds of closets, 2 kinds of shelves and 7 kinds of chairs. In how many ways can a person decorate his room if he wants to buy in the workshop one shelf, one bed and one of the following: a chair or a closet?
(A) A)168.
(B) B)80.
(C) C)60.
(D) D)48.
(E) E)16.
Rationale: ways to select one shelf = 2
ways to select one bed = 3
ways to select one of the following: a chair or a closet = 7+3 = 10
ways to select all of them together = 2*3*10 = 60
Answer : C
Answer: (C) C)60.
Question: A and B entered into a partnership investing Rs.25000 and Rs.30000 respectively. After 4 months C also joined the business with an investment of Rs.35000. What is the share of C in an annual profit of Rs.47000?
(A) Rs.18000
(B) Rs.15000
(C) Rs.17000
(D) Rs.14000
(E) NONE
Rationale: 25*12: 30*12: 35*8
15:18:14
14/47 * 47000 = 14000
ANSWER:D
Answer: (D) Rs.14000
Question: What will come in place of the x in the following Number series? 49920, 4160, 416, 52, x
(A) 8.67
(B) 7.67
(C) 6.67
(D) 5.67
(E) 4.67
Rationale: 49920 /12 = 4160
3840 /10 = 416
416 /8 = 52
52/6 = 8.67
A
Answer: (A) 8.67
Question: Ajay's club with a total membership of 30 has formed 3 committees, M, S and R which have 8,12, and 5 members respectively. If no member of committee M is on either of the other 2 committees, what is the greatest possible number of members in the club who are on none of the committees.
(A) 5
(B) 7
(C) 8
(D) 10
(E) 12
Rationale: Ajay's club with a total membership of 30 has formed 3 committees Given no member of committee M is on either of the other 2 committees -- hence (M n R) and (M n S) and (M n R n S) is zero.
Hence only M is 8. Now we need to consider only S, (S n R) and R.
(M U R U S) = M + R + S - (M n R) - (M n S) - (R n S) + (M n R n S) + Neither.
30 = 8 + (12 - x) + (5 - x) + 0 + 0 + x + 0 + Neither.
22 = (12-x) + (5-x) + x + Neither.
Now the max value of x could be 5 and the min value of x could be 0.
When x is 5 (max), Neither is 10.
When x is 0 (min), Neither is 5. We need maximum no of people who do not belong to any group. Hence max value of neither is 10.
Answer 10 (D).
Answer: (D) 10
Question: If P represents the product of the first 13 positive integers, which of the following must be true?
I. P is an odd number
II. P is a multiple of 17
III. P is a multiple of 24
(A) I only
(B) II only
(C) III only
(D) None of the above
(E) All of the above
Rationale: P = 13!
I It is a multiple of 2, so cannot be ODD
II. 17 is a prime number; cannot be multiple
III. 24 = 8 * 3; Yes it is a multiple	Answer = C) III only
Answer: (C) III only
Question: A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 24 miles per hour. the cyclist stopswaits for the hiker 5 min after passing her while the hiker continues to walk at her constant rate. how many minutes must the cyclist wait until the hiker catches up
(A) 6 2/3
(B) 15
(C) 20
(D) 25
(E) 26 2/3
Rationale: Here is how I did it:
The cyclist travels 24 miles in 60 mins, so in 5 mins he will travel [(24*5)/60] miles, which equals 2 miles in 5 mins.
Now the hiker travels 4 miles in 60 mins. To travel 2 miles, he will take [(60*2)/4] = 30 mins.
30-5=25 mins
D
Answer: (D) 25
Question: Meera purchased two three items from a shop. Total price for three items is Rs.5200/- She have given Rs. 6000/- What is the balance amount meera got?
(A) 650
(B) 400
(C) 350
(D) 800
(E) 750
Rationale: Total cost of Items : 5200/-
amount Paid : 6000/-
Balance receivable : 6000 - 5200 = 800/-
Answer is D
Answer: (D) 800
Question: Ramu bought an old car for Rs. 48000. He spent Rs. 14000 on repairs and sold it for Rs. 72900. What is his profit percent?
(A) 16%
(B) 17.5%
(C) 18.2%
(D) 58.5%
(E) 13%
Rationale: Total CP = Rs. 48000 + Rs. 14000
= Rs. 62000 and SP = Rs. 72900
Profit(%)
= (72900 - 62000)/62000 * 100
= 17.5%
Answer: B
Answer: (B) 17.5%
Question: The class mean score on a test was 80, and the standard deviation was 15. If Jack's score was within 2 standard deviations of the mean, what is the lowest score he could have received?
(A) 30
(B) 31
(C) 50
(D) 90
(E) 89
Rationale: 1 SD from the mean is ADDING and Subtrating the amount if standard deviation from the mean one time. 2 SD from the mean is ADDING and Subtracting TWICE.
1SD from the mean ranges from 95 to 65, where 95 is within SD above the mean and 65 within 1SD below the mean
2SD=15 TWICE=30 from the the mean, which is 95 to 50, where 90 is within 2 SD above the mean AND 50 is within 2 SD below the mean.
Answer = C
Answer: (C) 50
Question: What will be the ratio of simple interest earned by certain amount at the same rate of interest for 2 years and that for 14 years?
(A) 3 : 2
(B) 1 : 7
(C) 2 : 3
(D) 3 : 1
(E) 2 : 1
Rationale: Explanation :
Simple Interest = PRT/100
Here Principal(P) and Rate of Interest (R) are constants
Hence, Simple Interest ∝ T
Required Ratio = Simple Interest for 2 years/Simple Interest for 14 years
=T1/T2
=2/14
=1/7
=1:7
Answer : Option B
Answer: (B) 1 : 7
Question: The S.I. on a certain sum of money for 5 years at 10% per annum is half the C.I. on Rs. 5000 for 2 years at 12% per annum. The sum placed on S.I. is?
(A) 1585
(B) 1454
(C) 1656
(D) 2458
(E) 1272
Rationale: C.I. = [5000 * (1 + 12/100)2 - 5000]= (5000 * 28/25 * 28/25 - 5000) = Rs. 1272.Sum = (636 * 100)/(5 * 10)= Rs.1272Answer:E
Answer: (E) 1272
Question: There are 8 stores in town that had a total of 22 visitors on a particular day. However, only 12 people went shopping that day; some people visited more than one store. If 8 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: 8 people visited 2 stores each for 16 visits.
To maximize the number of stores that one person visited, let's assume that 3 people visited 1 store each. The number of remaining visits is 22 - 16 - 3 = 3, which is the maximum that one person could have visited.
The answer is B.
Answer: (B) 3
Question: 2, 5, 10, 17, 26, ?
(A) 35
(B) 36
(C) 48
(D) 49
(E) 37
Rationale: The sequence is a series of squares+1,
1*1+1, 2*2+1, 3*3+1, 4*4+1, 5*5+1, 6*6+1=37
Answer : E.
Answer: (E) 37
Question: If the annual rate of simple interest increases from 10% to 12 1/2 %, a man's yearly income increases by Rs. 1250. His principal in Rs. is?
(A) 22999
(B) 50000
(C) 26709
(D) 78766
(E) 17618
Rationale: Let the sum be Rs. x. Then,
(x * 25/2 * 1/100) - (x * 10 * 1)/100 = 1250
25x - 20x = 250000
x = 50000
Answer: B
Answer: (B) 50000