mathewhe/aqua_rat huggingface dataset:
Question: If x = 1- 3t and y = 2t - 3, then for what value of t does x = y?
(A)  5/2
(B)  3/2
(C)  4/5
(D)  2/5
(E)  0
Rationale: We are given x = 1 – 3t and y = 2t – 3, and we need to determine the value for t when x = y. We should notice that both x and y are already in terms of t. Thus, we can substitute 1 – 3t for x and 2t – 3 for y in the equation x = y. This gives us:
1 – 3t = 2t – 3
4 = 5t
4/5 = t
The answer is C.
Answer: (C)  4/5
Question: Bhanu spends 30% of his income on petrol on scooter 10% of the remaining on house rent and the balance on food. If he spends Rs.300 on petrol then what is the expenditure on house rent?
(A) 2287
(B) 70
(C) 128
(D) 797
(E) 120
Rationale: Given 30% (Income ) = 300 ⇒⇒ Income = 1000
After having spent Rs.300 on petrol, he left with Rs.700.
His spending on house rent = 10% (700) = Rs.70
Answer:B
Answer: (B) 70
Question: A letter lock consists of three rings each marked with nine different letters. The number of distinct unsuccessful attempts to open the lock is at the most?
(A) 277
(B) 269
(C) 728
(D) 768
(E) 720
Rationale: Since each ring consists of nine different letters, the total number of attempts possible with the three rings is
= 9 * 9 * 9 = 729. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts = 729 - 1
= 728
Answer:C
Answer: (C) 728
Question: he population of a city is 150,000. If it increases at the rate of 6% per annum, then what will be its population 2 years hence?
(A) 1697787
(B) 1697723
(C) 168540
(D) 169728
(E) 169718
Rationale: Population after n years = P [1 + (R/100)]2
Population after 2 years = 150000 * [1 + 6/100]2 = (150000 x 53/50 x 53/50) = 168540
ANSWER: C
Answer: (C) 168540
Question: The sum of ages of 5 children born at the intervals of 3 years each is
50 years. Find out the age of the youngest child?
(A) 6 years
(B) 5 years
(C) 4 years
(D) 3 years
(E) 2 years
Rationale: let the age of young child is = x
then age of 5 children can be written as x,(x+3),(x+6),(x+9) and (x+12)
x+(x+3)+(x+6)+(x+9)+(x+12)=50
5x+30 = 50 -> x =4
ANSWER C
Answer: (C) 4 years
Question: A paper is in a square form whose one side is 20 cm. Two semi circles are drawn on its opposites as diameters. If these semi circles are cut down what is the area of the remaining paper?
(A) (400 - 100π) cm2
(B) (400 - 2π) cm2
(C) (400 – 200π) cm2
(D) 200π cm2
(E) 400π cm2
Rationale: Explanation:
20
400-π*10*10
=>400-100π
ANSWER IS A
Answer: (A) (400 - 100π) cm2
Question: Jimmy has 20% more cookies than Janice. What percentage of cookies should Jimmy give to Janice so that both Jimmy and Janice have the same number of cookies?
(A) 7.5%
(B) 7.7%
(C) 7.9%
(D) 8.1%
(E) 8.3%
Rationale: An easy way to solve this question is by number plugging. Assume Janice has 100 cookies then Jimmy has 120 cookies. Now, for both Jimmy and Janice to have equal amounts of cookies we should give Janice 10 of Jimmy's cookies, which is 10/120=~8.3% of Jimmy's cookies.
Answer: E.
Answer: (E) 8.3%
Question: If paint costs $3.20 per quart, and a quart covers 10 square feet, how much will it cost to paint the outside of a cube 10 feet on each edge?
(A) $ 1.60
(B) $ 16.00
(C) $ 96.00
(D) $108.00
(E) $192.00
Rationale: total surface area = 6a^2 = 6*10*10 = 600
each quart covers 20 sqr ft
thus total number of quarts = 600/10 = 60
cost will be 60*3.2 = $192
Ans: E
Answer: (E) $192.00
Question: A gardener wants to plant trees in his garden in such a way that the number of trees in each row should be the same. If there are 4 rows or 5 rows or 6 rows, then no tree will be left. Find the least number of trees required.
(A) 30
(B) 60
(C) 120
(D) 240
(E) 480
Rationale: The least number of trees that are required = LCM(4, 5, 6) = 60.
ANSWER:B
Answer: (B) 60
Question: A and B complete a job in 6 days. A alone can do the job in 15 days. If B works alone, how many days will it take to complete the job?
(A) 8
(B) 10
(C) 12
(D) 14
(E) 16
Rationale: The rate of A and B is 1/6
A's rate is 1/15
B's rate is 1/6 - 1/15 = 1/10
B can complete the job in 10 days.
The answer is B.
Answer: (B) 10
Question: In how many a committee of 5 members can be selected from 6men
5 ladies consisting of 3 men and 2 ladies
(A) 200
(B) 300
(C) 400
(D) 500
(E) 600
Rationale: (3 men out of 6) and (2 ladies out of 5) are to be chosen
Required number of ways
=(6C3 * 5C2)
= 200
ANSWER A
Answer: (A) 200
Question: The average age of a class of 20 students is 22 years. The average increased by 2 when the teacher's age also included. What is the age of the teacher?
(A) 40 years
(B) 41 years
(C) 42 years
(D) 43 years
(E) 44 years
Rationale: If age of the teacher was 22, average would not have changed.
Since average increased by 2,
Age of the teacher=19+22×1=44
ANSWER:E
Answer: (E) 44 years
Question: If the speed of X meters per minute is equivalent to the speed of Y kilometers per hour, what is Y in terms of X? (1 kilometer=1000 meters)
(A) 15x/18
(B) 6x/5
(C) 18x/5
(D) 6/100x
(E) 3600000x
Rationale: If the speed of X meters per minute is equivalent to the speed of Y kilometers per hour, what is Y in terms of X? (1 kilometer=1000 meters)
We need to find an equation with x in the answer...
convert all measurements so they are alike (i.e. convert km to m, minutes to hours, etc)
Speed = x/t
x meters/second
(60) x meters/hour
Speed = y/t
y KM/hour
Speed = y(1000m)/hour
y(1000meters)/hour = (60) x meters/hour
y(1000)/1hour = x(60) / 1 hour
y(1000) = x(60)
y = 0.06x
Answer: D. 6/100x
Answer: (D) 6/100x
Question: The HCF of three numbers is 23. If they are in the ratio of 1 : 2 : 3, then find the numbers ?
(A) 69, 15, 22
(B) 23, 46, 69
(C) 25, 31, 41
(D) 23, 21, 35
(E) 23, 24, 36
Rationale: Let the numbers are N, 2N and 3N.
Where, N = HCF
Given that, N = 23
The numbers are 23, 46 and 69.
Answer :B
Answer: (B) 23, 46, 69
Question: The G.C.D. of 1.08, 0.34 and 0.9 is:
(A) 0.02
(B) 0.9
(C) 0.18
(D) 0.108
(E) None
Rationale: EXPLANATION
Given numbers are 1.08, 0.34 and 0.90. H.C.F. of 108, 34 and 90 is 2,
H.C.F. of given numbers = 0.02.
Answer A
Answer: (A) 0.02
Question: 100, 144, 196, 256, 324, ?, F ind the missing number(?).
(A) 444
(B) 450
(C) 100
(D) 400
(E) 200
Rationale: The series consists of squares of consecutive EVEN numbers.
Answer : D.
Answer: (D) 400
Question: A baseball player signs a new contract that includes a guaranteed 10 percent increase in salary over his old contract, plus a performance bonus of up to $500. If he earns the maximum possible performance bonus, his new salary including bonus will be equivalent to a 12 percent increase over his old salary. Assuming he earns the full bonus, what will his total new salary be, in dollars?
(A) 24,500
(B) 25,000
(C) 27,500
(D) 28,000
(E) 28,500
Rationale: Original salary = X.
(Wanted) New salary = 1,12X.
500=0,02X.
X=25,000.
1,12*25,000=28,000.
Answer is D.
Answer: (D) 28,000
Question: What is the average (arithmetic mean) of all multiples of 10 from 10 to 100 inclusive?
(A) 190
(B) 195
(C) 200
(D) 205
(E) 55
Rationale: This question can be solved with the Average Formula and 'bunching.'
We're asked for the average of all of the multiples of 10 from 10 to 100, inclusive.
To start, we can figure out the total number of terms rather easily:
1(10) = 10
2(10) = 20
...
10(10) = 100
So we know that there are 10 total numbers.
We can now figure out the SUM of those numbers with 'bunching':
10 + 100 = 110
20 + 90 = 110
30 + 80 = 110
Etc.
Since there are 10 total terms, this pattern will create 5 'pairs' of 110.
Thus, since the average = (Sum of terms)/(Number of terms), we have...
(5)(110)/(10) =55
Answer : E
Answer: (E) 55
Question: 45 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day?
(A) 33
(B) 77
(C) 299
(D) 55
(E) 267
Rationale: (45 * 8)/30 = (x * 6)/50 => x =100
100 – 45 = 55
Answer: D
Answer: (D) 55
Question: The population of a bacteria colony doubles every day. If it was started 11 days ago with 2 bacteria and each bacteria lives for 12 days, how large is the colony today?
(A) 512
(B) 768
(C) 1024
(D) 2048
(E) 4096
Rationale: 2^11(2) = 2^12 = 4096
The answer is E.
Answer: (E) 4096
Question: A bag contains five white and four red balls. Two balls are picked at random from the bag. What is the probability that they both are different color?
(A) 20/86
(B) 20/36
(C) 20/38
(D) 20/31
(E) 20/32
Rationale: Two balls can be picked from nine balls in ⁹C₂ ways.
We select one white ball and one red ball from five white balls and four red balls. This can be done ⁵C₁ . ⁴C₁ ways.
The required probability = (5 * 4)/⁹C₂ = 20/36
= 5/9
Answer: B
Answer: (B) 20/36
Question: ratio and addition of time on principal amount 500 with two different rate are 3:5 and 16
respectively.given rates are 2% and 3% respectively.what will be simple interest on both case?
(A) 30,50
(B) 100,150
(C) 80,150
(D) 60,150
(E) 60,100
Rationale: let the ratio constant be x.
3x+5x=16,8x=16,x=2
t1=6,t2=10
s.i1=500*2*6/100=60
s.i2=500*3*10/100=150
answer D
Answer: (D) 60,150
Question: In a certain lottery drawing, two balls are selected at random from a container with 200 balls, numbered from 1 to 200, inclusive. If the winner of the lottery is awarded a cash prize in the amount of $1,000 times the product of the numbers on the two selected balls, which of the following is a possible amount of the cash prize given to the winner?
(A) $9.85 x 10^6
(B) $9.90 x 10^6
(C) $3.98 x 10^7
(D) $1.05 x 10^7
(E) $9.90 x 10^7
Rationale: The max product of any two balls can be 199 * 200 = 3.98*10^4
If you multiply it by $1000 the max amount will be 3.98 * 10^7. .
Answer: C
Answer: (C) $3.98 x 10^7
Question: What is the remainder when 1201 × 1202 ×1205 × 1210 is divided by 6?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: The remainders when dividing each number by six are: 1, 2, 5, and 4.
The product is 1*2*5*4 = 40
The remainder when dividing 40 by 6 is 4.
The answer is D.
Answer: (D) 4
Question: The cricket team of 11members is 26yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ?
(A) 19
(B) 21
(C) 23
(D) 27
(E) 29
Rationale: Let the average age of the whole team be x years.
11x - (26 + 29) = 9 (x - 1)
=> 11x - 9x = 46
=> 2x = 46
=> x = 23.
So, average age of the team is 23 years.
C
Answer: (C) 23
Question: A person can swim in still water at 12 km/h. If the speed of water 6 km/h, how many hours will the man take to swim back against the current for 6km?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: M = 12
S = 6
US = 12 - 6 = 6
D = 36
T = 36/6 = 6 Answer:D
Answer: (D) 6
Question: Mangala completes a piece of work in 15 days, Raju completes the same work in 45 days. If both of them work together, then the number of days required to complete the work is
(A) 6 days
(B) 7 days
(C) 8 days
(D) 9 days
(E) 11 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 15 Ã— 45/60 = 11 days.
D
Answer: (D) 9 days
Question: During one month at a particular restaurant, 1/4 of the burgers sold were veggie burgers and 1/4 of the rest of the burgers sold were double-meat. If x of the burgers sold were double-meat, how many were veggie burgers?
(A) x/8
(B) x/2
(C) 3x/3
(D) 3x/4
(E) 4x/5
Rationale: Let y be the number of total burgers.
veggie = y/4 , non veggie = 3y/4
1/4 of the rest of the burgers sold were double-meat
=> 3y/4 * 1/4 = double meat = x
=> y/4 = 4x/3 = veggie
Hence C
Answer: (C) 3x/3
Question: If a continuous cable 10 meters long was marked off at intervals of 1/3 meter and also 1/8 meter, and then if the cable were cut at each mark, how many different size length of cable would result?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: In this particular example length (10 meter) is just extraneous information.
The location of the marks for 1/3 meter would be 8/24, 16/24, 24/24, etc...
The location of the marks for 1/8 meter would be 3/24, 6/24, 9/24, 12/24, 15/24, 18/24, 21/24, 24/24, etc...
The distances between marks are 3/24, 2/24, and 1/24.
The answer is C.
Answer: (C) 3
Question: Selling an kite for Rs. 30, a shop keeper gains 25%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?
(A) 8%
(B) 10%
(C) 11%
(D) 12.5%
(E) 20%
Rationale: Explanation:
Marked price = Rs. 30
C.P. = 100/125 * 30 = Rs. 24
Sale price = 90% of Rs. 30 = Rs. 27
Required gain % = 3/24 * 100 = 12.5%.
Answer: D
Answer: (D) 12.5%
Question: A grocer has a sale of Rs. 5420, Rs. 5660, Rs. 6200, Rs. 6350 and Rs. 6500 for 5 consecutive months. Find the sale he should have in the sixth month, so that he gets an average sale of Rs. 6200?
(A) Rs. 7070
(B) Rs. 5991
(C) Rs. 6020
(D) Rs. 6850
(E) None of these
Rationale: Explanation:
Total sale for 5 months = Rs. (5420 + 5660 + 6200 + 6350 + 6500) = Rs. 30,130
Therefore, required sale = Rs. [(6200 * 6) – 30,130] = Rs. (37200 – 30,130) = Rs. 7070
ANSWER A
Answer: (A) Rs. 7070
Question: The simple interest on a sum of money will be Rs.900 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year?
(A) 1800
(B) 2888
(C) 1200
(D) 2699
(E) 2771
Rationale: P --- 10 ---- 900
P --- 5 ----- 450
3P --- 5 ----- 1350
------
=> 1800
Answer: A
Answer: (A) 1800
Question: What will $2500 amount to in three years if it is invested at 20% per year compound interest, with the interest being compounded annually?
(A) $3760
(B) $3980
(C) $4210
(D) $4320
(E) $4760
Rationale: After one year: 1.2 * $2500
After two years: (1.2)^2 * $2500
After three years: (1.2)^3 * $2500 = $4320
The answer is D.
Answer: (D) $4320
Question: A boat can travel 2.5 times the distance down the stream than up the stream in the same time. If the speed of the current is 3 KMPH, Find the speed of the boat in still water
(A) 7
(B) 10
(C) 15
(D) 20
(E) 25
Rationale: Simple question, messy language.
Lets say boat's speed is B and current's speed is C.
Upstream speed : B - C
Downstream speed : B + C
Distance will be the same both times. lets say D.
given : time it takes upstream = 2.5 times time it takes downstream
D/(B + C) = 2.5 * [D/(B - C)]
Solving B = 2.3 C
given : C is 3 KMPH
So B is 6.9~=7 KMPH
A
Answer: (A) 7
Question: You buy a piece of land with an area of âˆš1024, how long is one side of the land plot?
(A) 28
(B) 29
(C) 30
(D) 31
(E) 32
Rationale: Try filling the numbers into the answer y x y =
Find the closest to 1024.
Answer E
Answer: (E) 32
Question: A 50-liter solution of alcohol and water is 5 percent alcohol. If 1.5 liters of alcohol and 8.5 liters of water are added to this solution, what percent of the solution produced is alcohol?
(A) 5.5%
(B) 6%
(C) 6 1/3%
(D) 6 2/3%
(E) 7%
Rationale: 50L * .05 = 2.5 L of alc, 50L - 2.5L = 47.5L of water
2.5 + 1.5 = 4L of alcohol in new solution
47.5L + 8.5L = 56L of water
4L / 56L = 1/14
this is ~7%
ANSWER:E
Answer: (E) 7%
Question: A and B complete a job in 6 days. A alone can do the job in 18 days. If B works alone, how many days will it take to complete the job?
(A) 8
(B) 9
(C) 10
(D) 11
(E) 12
Rationale: The rate of A and B is 1/6
A's rate is 1/18
B's rate is 1/6 - 1/18 = 1/9
B can complete the job in 9 days.
The answer is B.
Answer: (B) 9
Question: Mary and Harry enter into a partnership by investing $700 and $300 respectively. At the end of one year, they divided their profits such that a third of the profit is divided equally for the efforts they have put into the business and the remaining amount of profit is divided in the ratio of the investments they made in the business. If Mary received $800 more than Harry did, what was the profit made by their business in that year?
(A) 45645433
(B) 46457457
(C) 4675
(D) 3000
(E) 3432
Rationale: Say the profit was $x.
Mary's share = x/6 (half of the third) + (x-x/3)*0.7
Harry share = x/6 (half of the third) + (x-x/3)*0.3
Thus (x-x/3)*0.7-(x-x/3)*0.3=800 --> x=3000.
answer is D
Answer: (D) 3000
Question: A businessman earns $27800 in December, thus decreasing his average annual (January to December) earnings by $1400. His average annual earnings would be
Source: CMAT Preparation
(A) $29000
(B) $33500
(C) $40200
(D) $41000
(E) $43200
Rationale: (x - 27,800)/11 - x/12 = 1,400
x = 518,400
x/12 = 43,200
Answer: E.
Answer: (E) $43200
Question: What is the lowest possible common multiple of 2 distinct integers, each greater than 62?
(A) 68
(B) 69
(C) 126
(D) 68^2
(E) 68·69
Rationale: In order to get the lowest LCM, we have to take the first number as 63 and the next number as its multiple.
So, I can take 63 and 126 as two distinct numbers, such that Lowest LCM = 126.
Answer should be C.
Answer: (C) 126
Question: If KING is coded as 17 and MASS is coded as 29 Then DON is coded as
(A) 21
(B) 20
(C) 19
(D) 18
(E) None
Rationale: KING = 11+9+14+7=41 i.e (4*4)+(1*1)=17
MASS = 13+1+19+19=52 i.e (5*5)+(2*2)=29
DON = 4+14+15=33 i.e(3*3)+(3*3)=18
ANSWER:D
Answer: (D) 18
Question: The difference between the simple interest received from two different sources on Rs. 1500 for 3 years is Rs. 12.50. The difference between their rates of interest is?
(A) A)2.4%
(B) B)2.6%
(C) C)0.3%
(D) D)2.0%
(E) E)1.3%
Rationale: (1500 * R1 * 3)/100 - (1500 * R2 * 3)/100 = 12.50 4500(R1 - R2) = 1250
R1 - R2 = 0.3%
Answer:C
Answer: (C) C)0.3%
Question: If 3 cm of a pencil is purple, 2 cm of the remaining is black and the remaining 1 cm is blue, what is the total length of the pencil?
(A) 6
(B) 3
(C) 1
(D) 4
(E) 2
Rationale: Answer is A) 6
Answer: (A) 6
Question: A Grocer bought 24 kg coffee beans at price X per kg. After a while one third of stock got spoiled so he sold the rest for $200 per kg and made a total profit of twice the cost. What must be the price of X?
(A) 44.41
(B) 44.42
(C) 44.43
(D) 44.46
(E) 44.44
Rationale: Total Cost price = 24××X
As 1/3rd of the beans spoiled, remaining beans are 2/3 (24) = 16 kgs
Selling price = 200 ×× 16 = 3200
Profit = Selling price - Cost price = 3200 - 24××X
Given Profit = 2 ×× Cost price
3200 - 24××X = 2 ×× (24××X)
Solving X = 44.44
Answer:E
Answer: (E) 44.44
Question: A man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of:
(A) 0
(B) 9
(C) 8
(D) 7
(E) 6
Rationale: Explanation:
C.P =Rs.3000
S.P =\inline {\color{Black}Rs.[\frac{3600\times 100}{100+(10\times 2)}]=Rs.3000}
Gain =0%
Answer: A) 0%
Answer: (A) 0
Question: Lucy deposited $62500 in an investment fund that provided 16 percent annual return compounded quarterly. If she made no other transactions with the fund, in how much time, in days, did her investment earn a total interest of $5100?
(A) 120
(B) 20
(C) 30
(D) 60
(E) 180
Rationale: A = P + I = 62500 + 5100 = 67600
67600 = 62500(1 + 16/4*100)^(4t)
(676/625) = (104/100)^(4t)
(26/25)^2 = (26/25)^4t
t = 1/2 yrs = 180 days
Answer: E
Answer: (E) 180
Question: When Raja was born, his father was 32 years older than his brother and his mother was 25 years older than his sister. If Raja’s brother is 6 years older than Raja and his mother is 3 years younger than his father, how old was Raja’s sister when Raja was born?
(A) 10
(B) 99
(C) 76
(D) 28
(E) 26
Rationale: Explanation:
Raja's brother 6 year old when Raja was born.
His father's age = 32 + 6 = 38 year
His mother's age = 35 year
His sister age =35 – 25 = 10 years
Answer: A
Answer: (A) 10
Question: Samant bought a microwave oven and paid 10 % less than the original price. He sold it with 30% profit on the price he had paid.What percentage of profit did samant earn on the original price?
(A) 17%
(B) 20%
(C) 27%
(D) 32%
(E) None
Rationale: Solution
Let the original price	=Rs.100.
Then, C.P	= Rs.90.
S.P =130% of Rs. 90	=Rs.(130/100×90)
= Rs.117.
Required percentage	= (117 - 100)%
=17%.
Answer A
Answer: (A) 17%
Question: What is the least number of square tiles required to pave the floor of a room 12 m 12 cm long and 1m 20 cm broad?
(A) 1010
(B) 804
(C) 814
(D) 844
(E) None
Rationale: Solution
Length of largest tile = H.C.F. of 1212cm & 120cm = 12cm.
Area of each tile = (12 x 12)cm2
∴ Required number of tiles	= [1212x120/12x12]
= 1010.
Answer A
Answer: (A) 1010
Question: Find the value for x from below equation: x/3=-2?
(A) -6
(B) -5
(C) -4
(D) -3
(E) 1
Rationale: 1. Multiply both sides by 3:
x*3/3= -2/3
2. Simplify both sides:
x = -6
A
Answer: (A) -6
Question: Three sets of 70, 50 and 60 students appeared for an examination and the pass percentage was 100, 90 and 100 respectively. the pass percentage of the whole set is
(A) 97.4%
(B) 97.9%
(C) 97.6%
(D) 97.2%
(E) 97.5%
Rationale: Explanation:
total passed student =70+45+60=175
175 is 97.2% of 180
ANSWER:D
Answer: (D) 97.2%
Question: Excluding stoppages, the speed of a train is 55 kmph and including stoppages it is 40 kmph. Of how many minutes does the train stop per hour?
(A) 82
(B) 16
(C) 12
(D) 82
(E) 18
Rationale: Explanation:
T = 15/55 * 60 = 16
Answer: Option B
Answer: (B) 16
Question: Jacob is 39 years old. He is 3 times as old as his brother. How old will Jacob be when he is twice as old?
(A) 63
(B) 64
(C) 65
(D) 76
(E) 67
Rationale: j=39;
j=3b;
b=39/3=13;
twice as old so b=13(now)+(13)=26;
jacob is 39+26=65
ANSWER:C
Answer: (C) 65
Question: Aishwarya’s mom was 20 years of age at the time of her birth, while her mom was 15 years old when her 4 years younger sister was born. The variance between the parents ages is :
(A) 6 years
(B) 11 years
(C) 10years
(D) 9 years
(E) 4 years
Rationale: D
9 years
Mom’s age when Aishwarya’s sister was born = 15 years.
Dad’s age when Aishwarya’s sister was born = (20 + 4) years = 24 years.
Needed Variance = (24 – 15) years = 9 years.
Answer is D
Answer: (D) 9 years
Question: Michele invests 1000 of her money in a mutual fund that quickly goes sour, losing 50% of its value each day for a week. Which of the following COULD be the value of Michele’s investment at the close-of-business any day that week?
(A) $7.81
(B) $133.00
(C) $250.05
(D) $1575.00
(E) $10000.00
Rationale: Suppose she invests n$ in the starting then in the subesequent days the money left after the day will be
n/2, n/4, n/8, n/16, n/32
So, answer will be A
Answer: (A) $7.81
Question: 3968,3968,1984,661.33,165.33, ?
(A) 33.06
(B) 4.258
(C) 25.36
(D) 87.89
(E) 51.42
Rationale: Explanation :
Terms are continuously divided by 1,2,3 ,4, and so on
3968
3968 Ã· 1 = 3968
3968 Ã· 2 = 1984
1984 Ã· 3 =661.33
661.33Ã· 4= 165.33
165.33Ã·5=33.06
Answer : Option A
Answer: (A) 33.06
Question: In an election, candidate A got 75% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favour of candidate.
(A) 357000
(B) 357003
(C) 277677
(D) 699377
(E) 267877
Rationale: Total number of invalid votes = 15 % of 560000
= 15/100 × 560000
= 8400000/100
= 84000
Total number of valid votes 560000 – 84000 = 476000
Percentage of votes polled in favour of candidate A = 75 %
Therefore, the number of valid votes polled in favour of candidate A = 75 % of 476000
= 75/100 × 476000
= 35700000/100
= 357000
Answer:A
Answer: (A) 357000
Question: What is the difference between the place value of 2 in the numeral 7339?
(A) 160
(B) 165
(C) 180
(D) 190
(E) 270
Rationale: Answer: Option 'E'
300 - 30 = 270
Answer: (E) 270
Question: If a number N is chosen at random from the set of two-digit integers whose digits are both prime numbers, what is the probability T that N is divisible by 3?
(A) 1/3
(B) ¼
(C) 9/25
(D) 5/16
(E) 0
Rationale: Prime digits are: 2, 3, 5, 7
Total number of 2 digit #s with both digits prime are: 4*4 = 16
out of these numbers divisible by 3 = 33, 27, 57, 72 and 75. I had to find the numbers manually using the 4 numbers above.
=> prob = 5/16.
Ans D. Took me 3:20 mins.
Answer: (D) 5/16