mathewhe/aqua_rat huggingface dataset:
Question: A searchlight on top of the watch-tower makes 2 revolutions per minute. What is the probability that a man appearing near the tower will stay in the dark for at least 5 seconds?
(A) 1/4
(B) 1/3
(C) 1/2
(D) 2/3
(E) 5/6
Rationale: 2 revolutions per minute = 1 revolution every 30 seconds
So no matter what anybody appearing at the tower cannot stay in the dark for more than 30 seconds. This will be our total number of possibilities i.e the denominator.
P(man in dark for at least 5 seconds) = 1 - P (man in dark for max of 5 seconds) = 1 - 5/30 = 1 - 1/6 = 5/6
or the other way would be:
P(man in dark for at least 5 seconds) is like saying he can be in dark for 5,6,7...all the way to 30 seconds because that is the max. In this approach it would be 25/30 seconds = 5/6.
Answer is E
Answer: (E) 5/6
Question: find four consecutive numbers such that the sum of the first three numbers is twelve more than the fourth number ?
(A) 7,8,9,10
(B) 3,4,5,6
(C) 9,10,11,12
(D) 6,7,8,9
(E) None
Rationale: Let
1st Integer = x
2nd Integer = x+1
3rd Integer = x+2
4th integer = x+3
=======================================
Given
x+x+1+x+2=(x+3)+12
3x+3=x+3+12
3x+3=x+15
3x=x+15-3
3x=x+12
3x-x=12
2x=12
x=12/2
x=6
========================================
1st Integer = x = 6
2nd Integer = x+1 = 6+1 = 7
3rd Integer = x+2 =6+2= 8
4th integer = x+3=6+3=9
Answer D
Answer: (D) 6,7,8,9
Question: By selling 16 pencils for a rupee a man loses 28%. How many for a rupee should he sell in order to gain 28%?
(A) 8
(B) 9
(C) 7
(D) 6
(E) 4
Rationale: 72% --- 16
128% --- ?
72/128 * 16 = 9
Answer: B
Answer: (B) 9
Question: Find the simple interest on $10000 at 9% per annum for 12 months?
(A) $410
(B) $500
(C) $650
(D) $710
(E) $900
Rationale: P = $10000
R = 9%
T = 12/12 YEARS = 1 YEAR
S.I. = P*R*T/100 = 10000*9*1/100 = $900
Answer is E
Answer: (E) $900
Question: A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 200. How much did he have with him in the beginning?
(A) s 200
(B) s 500
(C) s 300
(D) s 450
(E) s 550
Rationale: Suppose the amount in the beginning was Rs ’x’
Money spent on clothes = Rs 1x/3 Balance = Rs 2x/3
Money spent on food = 1/5 of 2x/3 = Rs 2x/15
Balance = 2x/3 - 2x/15 = Rs 8x/15
Money spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5
Therefore 2x/5 = 200 = 500
ANSWER:B
Answer: (B) s 500
Question: A certain junior class has 1000 students and a certain senior class has 800 students. Among these students, there are 40 siblings pairs each consisting of 1 junior and 1 senior. If 1 student is to be selected at random from each class, what is the probability that the 2 students selected will be a sibling pair?
(A) 3/40000
(B) 1/3600
(C) 1/20000
(D) 1/60
(E) 1/15
Rationale: Let's see
Pick 40/1000 first
Then we can only pick 1 other pair from the 800
So total will be 40 / 800 *1000
Simplify and you get 1/20000
Answer is C
Answer: (C) 1/20000
Question: A began a business with Rs. 85,000. He was joined afterwards by B with Ks. 42,500. For how much period does B join, if the profits at the end of the year are divided in the ratio of 8 : 1 ?
(A) 6 months
(B) 3 months
(C) 2 months
(D) 8 months
(E) 9 months
Rationale: Suppose B joined for x months . Then, ( 85000 * 12 )/(42500 * x) = 8. or x = (85000 * 12) / (42500 * 8) = 3.
So, B joined for 3 months.
Answer: B
Answer: (B) 3 months
Question: Dhoni weighs twice as much as Nameetha. Nameetha's weight is 55% of Bima's weight. Dravid weighs 35% of Leela's weight. Leela weighs 30% of Dhoni's weight. Who among these 5 persons weighs the least?
(A) Dravid
(B) Dhoni
(C) Bima
(D) Nameetha
(E) Leela
Rationale: if
Bima weight = x
we get
Nameetha's weight = 0.55x
Dhoni's weight = 1.1x
Leela's weight = 0.33x
and Dravid's weight = 0.1155x
Answer : A
Answer: (A) Dravid
Question: A money lender lent Rs. 1000 at 3% per year and Rs. 1400 at 5% per year. The amount should be returned to him when the total interest comes to Rs. 350. Find the number of years.
(A) 3.5
(B) 3.75
(C) 4
(D) 4.25
(E) 4.5
Rationale: (1000xtx3/100) + (1400xtx5/100) = 350 → t =3.5 answer A
Answer: (A) 3.5
Question: Find the length of the longest pole that can be placed in an indoor stadium 24 m long, 18 m wide and 16 m high
(A) 31
(B) 32
(C) 33
(D) 34
(E) 35
Rationale: sqrt(1156)=34
becoz max length is cuboid diagonal d=sqrt(L^2+B^2+H^2)
where L lenght
B breadth & H height
ANSWER:D
Answer: (D) 34
Question: During a given week A programmer spends 1/4 of his time preparing flow chart, 3/8 of his time coding and the rest of the time in debugging the programs. If he works 48 hours during the week , how many hours did he spend debugging the program.
(A) 15 hrs
(B) 16 hrs
(C) 18 hrs
(D) 19 hrs
(E) 17 hrs
Rationale: programmer takes 1/4*48=12 hrs a week to make flowchrt
same way.....18 hrs a week for codin...
so....for debugging=48-(12+18)=18 hrs
ANSWER:C
Answer: (C) 18 hrs
Question: Priya went to the stationers and bought things worth Rs. 200, out of which 50 paise went on sales tax on taxable purchases. If the tax rate was 2%. then what was the cost of the tax free items?
(A) Rs. 175.50
(B) Rs. 174.50
(C) Rs. 174.00
(D) Rs. 170.00
(E) Rs. 173.50
Rationale: Solution
Let the amount of taxable purchases be Rs.x.
Then, 2% of x	= 50/100
x ‹=› (50/100×100/2)
= 25
Cost of tax free items	= Rs.[200 - (25 + 0.50)]
= Rs. 174.50
Answer B
Answer: (B) Rs. 174.50
Question: 8 friends are living in 8 different flats of an apartment. Each of them was allotted a parking spot to park their cars in the ground floor. But they used to park their cars randomly in any of the 8 parking spots. In how many ways can they park their cars so that exactly 6 people park their cars in the spots allotted to them?
(A) 20
(B) 28
(C) 36
(D) 44
(E) 52
Rationale: 8C6 = 28
The remaining 2 people in each case will be parked in each other's parking spots.
The answer is B.
Answer: (B) 28
Question: An article is bought for Rs.600 and sold for Rs.500, find the loss percent?
(A) 16 2/6%
(B) 16 2/8%
(C) 16 3/3%
(D) 16 2/3%
(E) 14 2/6%
Rationale: 600 ---- 100
100 ---- ? => 16 2/3%
Answer: D
Answer: (D) 16 2/3%
Question: Find the value of 72519 x 9999 = m?
(A) 709115678
(B) 723417481
(C) 710017481
(D) 725117481
(E) None
Rationale: 72519 x 9999 = 72519 x (10000 - 1)
= 72519 x 10000 - 72519 x 1
= 725190000 - 72519
= 725117481
D
Answer: (D) 725117481
Question: Pipes A and B can fill a cistern in 8 and 24 minutes respectively. They are opened an alternate minutes. Find how many minutes, the cistern shall be full?
(A) 10
(B) 26
(C) 12
(D) 24
(E) 48
Rationale: 1/8 + 1/24 = 1/6
6 * 2 = 12
Answer: C
Answer: (C) 12
Question: Jerry travels 8 miles at an average speed of 40 miles per hour, stops for 12 minutes, and then travels another 20 miles at an average speed of 60 miles per hour. What is Jerry’s average speed, in miles per hour, for this trip?
(A) 42
(B) 42.5
(C) 44
(D) 50
(E) 52.5
Rationale: Total Time taken by jerry = (8/40)*60 Minutes + 12 Minutes + (20/60)*60 Minutes = 44 Minutes
Average Speed = Total Distance / Total Time = (8+20) miles / (44/60)Hours = 28*60 / 44 = 42 Miles per hour
Answer: option A
Answer: (A) 42
Question: In a class composed of x girls and y boys, What part of the class is composed of girls
(A) y/(x + y)
(B) x/xy
(C) x/(x + y)
(D) y/xy
(E) 1/xy
Rationale: X/(X+Y).... ANSWER:C
Answer: (C) x/(x + y)
Question: While playing a certain dice game, Chris wins if the sum of the two dice is 7, at which point the game is over. If the game allows Chris three rolls in an attempt to win, what is the probability that Chris will win?
(A) 1/2
(B) 17/36
(C) 91/216
(D) 11/36
(E) 25/216
Rationale: Total outcomes possible: 36
Total outcomes possible with sum 7: 6
Probability to win when rolled once = 6/36
Probability not to win when rolled once = 30/36 = 5/6
Probability to win in three attempts= 1- Probability will not to win in all three attempts
= 1- (5/6* 5/6*5/6)
= 91/216
Answer is C.
Answer: (C) 91/216
Question: A and B began business with Rs.3000 and Rs.4000 after 8 months, A withdraws Rs.1000 and B advances Rs.1000 more. At the end of the year, their profits amounted to Rs.630 find the share of A.
(A) 240
(B) 388
(C) 379
(D) 277
(E) 122
Rationale: Explanation:
(3*8 + 2*4):(4*8 + 5*4)
8:13
8/21 * 630 = 240
Answer: A
Answer: (A) 240
Question: Pipe A can fill a tank in 5 hours, pipe B in 10 hours and pipe C in 30 hours. If all the pipes are open, in how many hours will the tank be filled?
(A) 2
(B) 2.2
(C) 3
(D) 3.5
(E) 4
Rationale: Part filled by A + B + C in 1 hour = 1/5 + 1/10 + 1/30 = 1/3
All the three pipes together will fill the tank in 3 hours.
ANSWER:C
Answer: (C) 3
Question: At a certain bowling alley, it costs $0.50 to rent bowling shoes for the day and $2 to bowl 1 game. If a person has $12.80 and must rent shoes, what is the greatest number of complete games that person can bowl in one day?
(A)  7
(B)  8
(C)  6
(D)  10
(E)  11
Rationale: After renting bowling shoes the person is left with $12.80-$0.5=$12.30, which is enough for 12.3/2<7=~6.
Answer: C.
Answer: (C)  6
Question: A batsman has scored an average of 46 runs for a certain number of innings played in England. When he came back to India, he played another two test matches of two innings each and scored at an average of 55 runs. For the innings in England and in India taken together, he has improved his average by 2 runs over the matches played in England.Find the number of innings played in England.
(A) 12
(B) 13
(C) 14
(D) 15
(E) 16
Rationale: Let the number of innings played in England be x.
∴ Total runs scored in England = 46x
Total runs scored for innings played in India
= 55 × 4 = 220
(∵ the number of innings played in India = 4)
Also, 46x+220 /x+4 = 48
⇒ 46x + 220 = 48 x + 192
⇒ 2x = 28
⇒ x = 14
Answer C
Answer: (C) 14
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is?
(A) 228
(B) 276
(C) 199
(D) 150
(E) 882
Rationale: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 25 = x / 15
x = 150 m. Answer:D
Answer: (D) 150
Question: What values of x satisfy the equation x2/3 + x1/3 – 2 ≤ 0 ?
(A) – 8 ≤ x ≤ 1
(B) – 1 ≤ x ≤ 8
(C) 1 ≤ x ≤ 8
(D) – 8 ≤ x ≤ 8
(E) None of these
Rationale: Explanation :
Let, x1/3 = y. The equation becomes y2 + y – 2 ≤ 0, or y2 + y ≤ 2.
Now, look at the upper limit. We know that y2 + y ≤ 2.
Among the positive numbers, 1 is the biggest number that satisfies the equation. No number greater than 1 can have y2 + y ≤ 2. So the upper limit is 1.
Maximum value of y is 1, hence maximum value of x1/3 is 1, and hence maximum value of x is 1.
This answer is there only for option 1. Hence that is the answer.
Answer : A
Answer: (A) – 8 ≤ x ≤ 1
Question: If n is a positive integer and the product of all the integers from 1 to n, inclusive, is a multiple of 123, what is the least possible value of n?
(A) 37
(B) 123
(C) 41
(D) 52
(E) 87
Rationale: 123 is 3 * 41, so n needs to be at least 41, so the answer is C.
Answer: (C) 41
Question: 2 men and 4 boys can complete a work in 4 days. 5 men and 6 boys can complete the same work in 3 days. The work done by 2 boys is equal to the work of how many men?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: (2m + 4b)’s one day’s work = 1/4
(5m + 6b)’s one day’s work = 1/3
=> (8m + 16b)’s one day’s work = (15m + 18b) ’s one day’s work
=> 7 men’s work = 2 boy’s work
So, we should be employ 5 more men to be completed the work.
ANSWER:C
Answer: (C) 5
Question: Given that x = 2^b – (8^34 + 16^5), which of the following values for b yields the lowest value for |x|?
(A) 101
(B) 102
(C) 103
(D) 104
(E) 122
Rationale: 8^34 + 16^5 = 2^102 + 2^20
Compared to 2^102, the value of 2^20 is negligible.
2^102 - (2^102 +2^20) will minimize the value of |x|.
The answer is B.
Answer: (B) 102
Question: If the length of the sides of two cubes are in the ratio 6:1, what is the ratio of their total surface area?
(A) 6:1
(B) 12:1
(C) 24:1
(D) 36:1
(E) 72:1
Rationale: Let x be the length of the small cube's side.
The total surface area of the small cube is 6x^2.
The total surface area of the large cube is 6(6x)^2=216x^2.
The ratio of surface areas is 36:1.
The answer is D.
Answer: (D) 36:1
Question: A number exceeds by 25 from its 3/8 part. Then the number is?
(A) 32
(B) 35
(C) 39
(D) 40
(E) 45
Rationale: Explanation:
x – 3/8 x = 25
x = 40
ANSWER IS D
Answer: (D) 40
Question: The sum of three consecutive even numbers is 42. Find the middle number of the three?
(A) 14
(B) 16
(C) 18
(D) 22
(E) 24
Rationale: Three consecutive even numbers (2P - 2), 2P, (2P + 2).
(2P - 2) + 2P + (2P + 2) = 42
6P = 42 => P = 7.
The middle number is: 2P = 14.
Option A
Answer: (A) 14
Question: CONVERT 1.6 hectares in ares
(A) 130 ares.
(B) 160 ares.
(C) 180 ares.
(D) 230 ares.
(E) 250 ares.
Rationale: 1.6 hectares in ares
1 hectare = 100 ares
Therefore, 1.6 hectares = 1.6 × 100 ares
= 160 ares.
ANSWER- B
Answer: (B) 160 ares.
Question: 20 beavers, working together in a constant pace, can build a dam in 6 hours. How many hours will it take 12 beavers that work at the same pace, to build the same dam?
(A) 10.
(B) 4.
(C) 5.
(D) 6
(E) 8.
Rationale: Total Work = 20*6= 120 Beaver hours
12 Beaver * x =120 Beaver hours
x=120/12=10
ANSWER:A
Answer: (A) 10.
Question: If both 2^2 and 3^4 are factors of the number a*4^3*6^2*13^11, then what is the smallest possible value of a?
(A) 6
(B) 9
(C) 12
(D) 15
(E) 18
Rationale: The number a must include at least 3^2 = 9
The answer is B.
Answer: (B) 9
Question: Three different containers contain 496 litres, 403 litres and 713 litres of mixtures of milk and water respectively. What biggest measure can measure all the different quantities exactly?
(A) 1 litre
(B) 7 litre
(C) 31 litre
(D) 41 litre
(E) None
Rationale: Solution
Required measurement	= H.C.F of (496, 403, 713) litres
‹=›31 litres.
Answer C
Answer: (C) 31 litre
Question: If both a and b belongs to the set {1,2,3,4 }, then the number of equations of the form ax2 + bx + 1 = 0 having real roots is
(A) 10
(B) 7
(C) 6
(D) 12
(E) 15
Rationale: Explanation :
ax2 + bx + 1 = 0 .
For real roots
=> b2 -4ac ≥ 0 .
i.e b2 - 4a(1) ≥ 0 .
i.e b2 ≥ 4a.
For a = 1, 4a = 4, ∴ b = 2, 3, 4
a = 2, 4a = 8, ∴ b = 3, 4
a = 3, 4a = 12, ∴ b = 4
a = 4, 4a = 16, ∴ b = 4
∴ Number of equations possible = 7.
Harsh Mishra a year ago
0 upvotes
Answer : B
Answer: (B) 7
Question: For all numbers a and b, the operationis defined by ab = (a + 2)(b – 3).
If 3y = –30, then y =
(A)  –15
(B)  –6
(C)  -3
(D)  6
(E)  15
Rationale: (3+2)(y-3)=-30..
x-3=-6..
x=-3
C
Answer: (C)  -3
Question: The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?
(A) Rs.3000
(B) Rs.3300
(C) Rs.3600
(D) Rs.3900
(E) Rs.3800
Rationale: P = 144(100/5)2 => P = 3600
ANSWER:C
Answer: (C) Rs.3600
Question: The difference between the simple interest received from two different sources on Rs. 1500 for 3 years is Rs. 13.50. The difference between their rates of interest is?
(A) 0.7%
(B) 8.3%
(C) 0.3%
(D) 0.39%
(E) 2.3%
Rationale: (1500 * R1 * 3)/100 - (1500 * R2 * 3)/100
= 13.50 4500(R1 - R2)
= 1350
R1 - R2 = 0.3%
Answer: C
Answer: (C) 0.3%
Question: In a colony of 70 residents, the ratio of the number of men and women is 4 : 3. Among the women, the ratio of the educated to the uneducated is 2 : 3. If the ratio of the number of educated to uneducated persons is 8 : 27, then find the ratio of the number of educated to uneducated men in the colony?
(A) A)1:6
(B) B)1:1
(C) C)1:8
(D) D)1:3
(E) E)1:9
Rationale: Number of men in the colony = 4/7 * 70 = 40.
Number of women in the colony = 3/7 * 70 = 40.
Number educated women in the colony = 2/5 * 30 = 12.
Number of uneducated women in the colony = 3/5 * 50 = 24.
Number of educated persons in the colony = 8 /35 * 70 = 16.
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 40 - 10 = 30.
Number of educated men and uneducated men are in the ratio 10 : 30 i.e., 1:3.
Answer:D
Answer: (D) D)1:3
Question: How many words can be formed from the letters of the word ‘DIRECTOR’ So that the vowels are always together?
(A) 3251
(B) 2160
(C) 1203
(D) 2564
(E) 5421
Rationale: In the given word, we treat the vowels IEO as one letter.
Thus, we have DRCTR (IEO).
This group has 6 letters of which R occurs 2 times and others are different.
Number of ways of arranging these letters = 6!/2! = 360.
Now 3 vowels can be arranged among themselves in 3! = 6 ways.
Required number of ways = (360x6) = 2160.
Ans: B
Answer: (B) 2160
Question: In a garden, 26 trees are planted at equal distances along a yard 600 metres long, one tree being at each end of the yard. What is the distance between two consecutive trees?
(A) 10
(B) 8
(C) 12
(D) 24
(E) 16
Rationale: 26 trees have 25 gaps between them.
Length of each gap = 600/25 = 24
i.e., distance between two consecutive trees = 24
Answer is D.
Answer: (D) 24
Question: A sum of money becomes 7/6 of itself in 2 years at a certain rate of simple interest. The rate per annum is?
(A) 50/9
(B) 50/7
(C) 50/6
(D) 50/8
(E) 50/3
Rationale: Let sum = x. Then, amount = 7x/6
S.I. = 7x/6 - x = x/6; Time = 2 years.
Rate = (100 * x) / (x * 6 * 2) = 50/6 %.
Answer:C
Answer: (C) 50/6
Question: Gill drives 120 miles from Los Angeles to San Diego to fetch a package. On her way there she drives at 40 miles per hour. On her way back she drives 50% faster. What is Gill's average velocity W for the round trip?
(A) 24 miles per hour
(B) 48 miles per hour
(C) 50 miles per hour
(D) 53 1/3 miles per hour
(E) 68 miles per hour
Rationale: Here's an Average Speed question in which the prompt gives you almost all of the immediate numbers needed to work with.
Driving from LA to SD, we have a distance of 120 miles and a speed of 40 miles/hour.
D = (R)(T)
120 = (40)(T)
120/40 = 3 = T
3 hours to drive to SD
On the way back, she drives 50% FASTER. Gill's return speed is (1.5)(40) = 60 miles/hour.
D = (R)(T)
120 = (60)(T)
120/60 = 2 = T
2 hours to drive to SD
Total Distance = 240 miles
Total Time = 3+2 = 5 hours
Average Speed = 240/5 = 48 miles/hour
Final Answer:
B
Answer: (B) 48 miles per hour
Question: Andrew went to a shop and bought things worth Rs. 25, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
(A) 18
(B) 19
(C) 19.7
(D) 21
(E) 21.3
Rationale: Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (25−30/100−x)6/100 = 30/100
⇒ 6(25 −0.3 −x) = 30
⇒ (25 − 0.3 − x) = 5
⇒ x = 25 − 0.3 − 5 = 19.7
C
Answer: (C) 19.7
Question: B invested $4000 in a business and C invested $3000 in a business. At the end of the year they got $14000 as the profit. Find their share?
(A) $8000,$6000
(B) $7000,$5000
(C) $6000,$4000
(D) $6000,$8000
(E) $5000,$6000
Rationale: B:C = 4000:3000
A:B = 4:3
A's share = 14000*4/7 = $8000
B's share = 14000*3/7 = $6000
Answer is A
Answer: (A) $8000,$6000
Question: 40% of a number is more than 20% of 650 by 190. Find the number?
(A) 997
(B) 127
(C) 800
(D) 128
(E) 189
Rationale: (40/100) * X – (20/100) * 650 = 190
2/5 X = 320
X = 800
Answer: C
Answer: (C) 800
Question: In expressing a length 81.475 km as nearly as possible with three significant digits, find the percentage error?
(A) 0.075%
(B) 0.156%
(C) 0.031%
(D) 0.048%
(E) 0.152%
Rationale: Error = 81.5-81.475 = 0.028
Required percentage = (0.028/81.475)*100 = 0.031%
Answer is C
Answer: (C) 0.031%
Question: A person can row at 9 kmph and still water. He takes 7 1/2 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 1 kmph?
(A) 33
(B) 28
(C) 29
(D) 54
(E) 20
Rationale: Let the distance between A and B be x km.
Total time = x/(9 + 1) + x/(9 - 1) = 7.5
=> x/10 + x/8 = 15/2 => (4x + 5x)/40 = 15/2 => x
= 33 km.
Answer:A
Answer: (A) 33
Question: Set A contains all the even numbers between 8 and 50 inclusive. Set B contains all the even numbers between 108 and 150 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A?
(A) 2200
(B) 2550
(C) 5050
(D) 6275
(E) 11325
Rationale: Set A contains 8, 10, 12... 50
Set B contains 108 , 110 , 112 ... 150
Number of terms in each set = 22
Difference between corresponding terms in set A and B = 100
Difference between Sum of set B and set A = 100*22 = 2200
Answer A
Answer: (A) 2200
Question: The average of 10 numbers is 23. If each number is increased by 6, what will the new average be?
(A) 36
(B) 29
(C) 72
(D) 29
(E) 22
Rationale: Sum of the 10 numbers = 230
If each number is increased by 6, the total increase =
6 * 10 = 60
The new sum = 230 + 60 = 290 The new average = 290/10
= 29.
Answer:B
Answer: (B) 29
Question: Little Praveen had $50.50. He spent $12.25 on sweets and gave same money to his two friends and the amount left with him is $31.25. Find how much he spent to two of his friends?
(A) $ 16.65
(B) $ 18.65
(C) $ 19.25
(D) $ 16.55
(E) $ 17.65
Rationale: Praveen spent and gave to his two friends a total of
12.25 + 2x= $4.65, x is the amount spent to one friend.
Money left
50.50 -2x = $31.85. Then 2x=$18.65.
correct answer is B) $ 18.65
Answer: (B) $ 18.65
Question: There are six leopards and one sheep.
Leopard can eat sheep but since as the land is magical, the leopards who eats the sheep , turns into sheep and then can be eaten by the remaining leopard(s).
If we leave them for some time then how many sheep and leopard will be there , when we come back ?
(A) 7 leopard and 3 sheep
(B) 4 leopard and 7 sheep
(C) 6 leopard and 4 sheep
(D) 5 leopard and 1 sheep
(E) 2 leopard and 5 sheep
Rationale: D
5 leopard and 1 sheep
since all animal are rational , once 1st leopard eats the sheep all the rest of leopard would know about this.
Answer: (D) 5 leopard and 1 sheep
Question: At 1:00 pm, there were 10.0 grams of bacteria. The bacteria increased to x grams at 4:00 pm, and 19.6 grams at 7:00 pm. If the amount of bacteria present increased by the same fraction during each of the 3-hour periods, how many grams of bacteria were present at 4:00 pm?
(A) 13.7
(B) 14.0
(C) 14.3
(D) 14.6
(E) 14.9
Rationale: Let x be the factor by which the bacteria increases every three hours.
At 4:00 pm, the amount of bacteria was 10x and at 7:00 pm it was 10x^2.
10x^2 = 19.6
x^2=1.96
x=1.4
At 4:00 pm, the amount of bacteria was 10(1.4)=14 grams.
The answer is B.
Answer: (B) 14.0
Question: Over the course of a year, a certain microbrewery increased its beer output by 70 percent. At the same time, it decreased its total working hours by 20 percent. By what percent did this factory increase its output per hour?
(A) 50%
(B) 90%
(C) 112.5%
(D) 210%
(E) 212.5%
Rationale: Let's take the original output to be 100 and the new output to be 170% or 170.
Let's take the original work hours to be 100 hours and the new work hours to be 80% or 80 hours.
The old output per work hour = 100/100 hours or 1.
The new output per work hour = 170/80 or 2.125. So the resulting increase is actually new minus old or 1.125 or 112.5%.
Choice C
Answer: (C) 112.5%
Question: If it is possible to from a word with the first, fourth, seventh and eleventh letters in the word
'SPHERVLVODS' write the second letter of thet word. Otherwise, X is the answer.?
(A) T
(B) E
(C) R
(D) HG
(E) K
Rationale: The first, fourth, seventh and eleventh letters of the word 'SPHERVLVODS'
The word formed is LESS
The second letter is E.
Answer: Option 'B'
Answer: (B) E
Question: In a camp, there is a meal for 100 men or 200 children. If 130 children have taken the meal, how many men will be catered to with remaining meal?
(A) 20
(B) 30
(C) 35
(D) 10
(E) 40
Rationale: There is a meal for 200 children. 130 children have taken the meal.
Remaining meal is to be catered to 70 children.
Now, 200 children 100 men.
70 children (100/200)	* 70 = 35 men
Answer is C.
Answer: (C) 35
Question: A carpenter is building a frame for a wall painting. The painting is in the shape of a rectangle. If the sides of the rectangle are in the ratio of 3:2 and the shorter side has a length of 19 inches, how many inches of framing material does the carpenter need to frame the painting?
(A) 12
(B) 22 1/2
(C) 37 1/2
(D) 50
(E) 25
Rationale: (19/2) ( 2+3) * 2 = 25=E
Answer: (E) 25