mathewhe/aqua_rat huggingface dataset:
Question: A can do a work in 7 days and B in 12 days. If they work on it together then in how many days required to complete the work?
(A) 83/19
(B) 84/19
(C) 81/19
(D) 77/19
(E) 87/19
Rationale: Person ( A ) ( B ) ( A+B )
Time - ( 7 ) ( 12 ) (84/19)
Rate - ( 12 ) ( 7 ) ( 19 )
Work - (84) ( 84 ) ( 84 )
therefore A+B requires (84/19) days to complete entire work
= 84/19
Answer is B
Answer: (B) 84/19
Question: Pat will walk from intersection A to intersection B along a route that is confined to the square grid of four streets and three avenues shown in the map above. How many routes from A to B can Pat take that have the minimum possible length?
(A) 6
(B) 8
(C) 10
(D) 14
(E) 16
Rationale: Consider this a as coordinate plane with A as origin and B as (2,3).
The shortest possible way is when you go take either right or up. (lefts and downs make repetitions and thus non shortest paths)
now, to get to (2,3) form (0,0) you need min 5 steps.
so you have to choose all the paths such that you have 2 steps out of 5 along x axis and getting to 3 of y axis.
The number of ways = 5C2 =10
(or alternately all paths that have 3 steps along y and takes you to 2 of x. .. 5C3 = 10)
Can you explicate your combinatorial method a bit more. For example, If I add another Avenue, eg, Avenue D, and another street, Street 5, I will have to go 3 steps right and 4 steps up to get to point C.
In order the length to be minimum Pat should only go UP and RIGHT: namely thrice UP and twice RIGHT.
So combination of UUURR: # of permutations of 5 letters out of which there are 3 identical U's and 2 identical R's is 5!/3!2!=10.
Answer: C.
Answer: (C) 10
Question: A person can row upstream 2 kmph and downstream 8 kmph. Find the rate of the stream and person rate in still water.
(A) 1,5
(B) 2,5
(C) 5,5
(D) 3,5
(E) 5,1
Rationale: Explanation:
Please remember,
If a is rate downstream and b is rate upstream
Rate of current = 1/2(a-b)
Rate in still water = 1/2(a+b)
=> Rate of current = 1/2(8-2) = 3 kmph
=> Rate in still water = 1/2(8+2) = 5 kmph
Option D
Answer: (D) 3,5
Question: Which of the following points is symmetric with y=x at (4,5)?
(A) (-2,-1)
(B) (-2,1)
(C) (2,1)
(D) (-1,-2)
(E) (5,4)
Rationale: We can think of line y = x as a mirror. Any point (x,y) becomes (y,x) when it isreflectedover the mirror. Reverse the coordinate and keep the same sign. These two points will be symmetric to the line y = x.
(4,5) would become (5,4).
Answer (E).
Answer: (E) (5,4)
Question: In a certain game, each player scores either 2 or 5 points. If n players score 2 points and m players score 5 points and the total number of points scored is 55, what is the least possible difference between n and m.
(A) a.1
(B) b.3
(C) c.4
(D) d.7
(E) e.9
Rationale: 2n+5m=55
try with n=5 and m=8 the equation will be satisfied
2(5)+5(9)=55
so difference between M and N is 4,
Answer C
Answer: (C) c.4
Question: Hendrix works 20 days a month at d dollars per day for m months out of the year. Which of the following represents his 5 year pay?
(A) m/(20d*5)
(B) 100md
(C) 50md/6
(D) 20d/5m
(E) 20d/5
Rationale: Total income of Amber in a year = d*20*m dollars. Now 5 year income = Total*5= d*20*m *5 = 100md Answer is B
Answer: (B) 100md
Question: On January 1, 2010, Dave invests 70% of his retirement savings in Antarctic largecap stocks, 20% in Antarctic midcaps, and 10% in Antarctic smallcaps. In 2010, largecaps rise 5%, midcaps rise 10%, and smallcaps rise 15% in the Antarctic stock market; however, in 2011, largecaps fall 10% and midcaps fall 20%, while smallcaps rise x% in Antarctica. If, on January 1, 2012, Dave has the same total amount of retirement savings as he did two years before, then x is between
(A) 10 and 20
(B) 20 and 30
(C) 30 and 40
(D) 40 and 50
(E) 50 and 60
Rationale: Here are the starting values:
L = $7,000
M = $2,000
S = $1,000
Apply the first year’s changes, so that you have these numbers on 1/1/2011:
Newer L = $7,000 + 5% = $7,350
Newer M = $2,000 + 10% = $2,200
Newer S = $1,000 + 15% = $1,150
Now apply the second year’s changes to L and M:
Newest L = $7,350 – 10% = $7,350 – $735 = $6,615
Newest M = $2,200 – 20% = $2,200 – $440 = $1,760
Add these to get $8,375. So the newest S must be $10,000 (the target final total of Dave’s retirement savings) minus $8,375, or $1,625.
The dollar change in S from 1/1/11 to 1/1/12 is $1,625 – $1,150 = $475. So the question is this: what percent change does $475 represent, from a starting point of $1,150? Since $1,150 is a nasty divisor, switch to benchmarks:
10% of $1,150 = $115.
So 20% is just double that, or $230.
And 40% is double that, or $460.
Since $475 is just slightly larger than $460 (but not enough to get you to 50%, which would be $460 + $115), x must be between 40 and 50.
Intuitively, it should make sense that you’d need a much bigger positive percent change in the smallest investment (S) to make up for even a moderate downturn in the larger investments (L and M), so if you were completely stuck for time and needed to guess in a hurry, you should favor C/D/E over A or B.
The correct answer is D.
Answer: (D) 40 and 50
Question: A plane was originally flying at an altitude of x feet when it ascended 2,000 feet and then descended 5,000 feet. If the plane's altitude after these two changes was 1/2 its original altitude, then the solution of which of the following equations gives the plane's original altitude, in feet ?
(A) x + 2000 = 1/3*(x - 3000)
(B) 1/3*(x - 3000) = x
(C) x - 3000 = 1/2*x
(D) x - 7000 = 1/3*x
(E) x - 3000 = 1/3*x
Rationale: Plane's original altitude = x
Plane's new altitude after ascending 2000 ft = x+2000
Plane's new altitude after descending 5000 ft from previous altitude = x+2000-5000 = x-3000
So, after two changes plane is at 1/2 its original altitude => x-3000 = x/2
Answer (C)
Answer: (C) x - 3000 = 1/2*x
Question: If a light flashes every 6 seconds, how many times will it flash in 2/5 of an hour?
(A) 181
(B) 211
(C) 241
(D) 271
(E) 301
Rationale: In 2/5 of an hour there are 24*60 = 1440 seconds
The number of 6-second intervals = 1440/6 = 240
After the first flash, there will be 240 more flashes for a total of 241.
The answer is C.
Answer: (C) 241
Question: Find a if (ax3 + 3x2 - 3) and (2x3 - 5x + a) when divided by (x-4) leave same rmainder?
(A) 1
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: remainders are,
R1 = f(4) = a(4)3+ 3(4)2-3= 64a+45
R2 = f(4) = 2(4)3- 5(4) + a= a +108
Since R1= R2
64a +45= a+108 => 63a = 63 => a =1
A
Answer: (A) 1
Question: A student can select one of 9 different math book, one of 3 different chemistry book & one of 4 different science book.In how many different ways students can select book of math, chemistry & science.
(A) 22
(B) 72
(C) 99
(D) 37
(E) 108
Rationale: 9C1×3C1×4C1= 9x3x4=108 ways
Answer:E
Answer: (E) 108
Question: Find the percentage gain if a shop owner sells 18 mtr of fabric and gains Cost Price of 3 meters?
(A) 17.67%
(B) 19.67%
(C) 11.67%
(D) 16.67%
(E) 15.67%
Rationale: Let cost of each metre be Rs. 100.
Therefore, cost price of 3m cloth = 3*100 =300
cost price of 18m cloth = 18*100 = 1800
Since the trader made the CP of 3m from the sale of 18m therefore
Profit on sale of 18m = cost price of 3 m cloth = 300
Selling price of 18m = 1800+300 = 2100
Profit % = 16.67%
D
Answer: (D) 16.67%
Question: By selling a book for 260, 20% profit was earned. What is the cost price of the book?
(A) A)215
(B) B)216
(C) C)230
(D) D)235
(E) E)240
Rationale: SP = 120% of CP; :. CP = 260 × 100/120 = 216
Option 'B'
Answer: (B) B)216
Question: We have 6 people and 4 chairs. In how many ways chairs can be occupy?
(A) 840
(B) 720
(C) 650
(D) 914
(E) 120
Rationale: no. of ways they can be occupy = 6*5*4 = 120
Answer is E
Answer: (E) 120
Question: Find the third proportional to 3 and 9?
(A) 10
(B) 12
(C) 27
(D) 19
(E) 20
Rationale: Formula = Third proportional = (b × b)/a
A = 3 and B = 9
(9 x 9)/ 3 = 81/3 = 27
C
Answer: (C) 27
Question: A die is rolled twice. What is the probability of getting a sum equal to 9?
(A) 2/3
(B) 2/9
(C) 1/3
(D) 1/9
(E) 1/6
Rationale: Total number of outcomes possible when a die is rolled = 6 (âˆµ any one face out of the 6 faces)
Hence, total number of outcomes possible when a die is rolled twice, n(S) = 6 Ã— 6 = 36
E = Getting a sum of 9 when the two dice fall = {(3, 6), {4, 5}, {5, 4}, (6, 3)}
Hence, n(E) = 4
P(E) = n(E)/n(S)=4/36=1/9
Answer:D
Answer: (D) 1/9
Question: In the third quarter of 2015, Atlantis Law Firm had 20 lawyers and 400 cases. In the fourth quarter of 2015, the firm had 22 lawyers and 500 cases. By approximately what percent did the ratio of lawyers to cases decrease from the third quarter to the fourth quarter.
(A) 10.0%
(B) 11.0%
(C) 12.0%
(D) 13.0%
(E) 14.0%
Rationale: 3rd quarter: lawyers/cases = 20/400 =100/2000
4th quarter: lawyers/cases = 22/500 =88/2000
ASIDE: It's useful to write both ratios with the same denominator. This allows us to IGNORE the denominator and focus solely on the numerators.
So, our ratio went from 100/2000 to 88/2000
Ignoring the denominators, we went from 100 to 88
The percent change = 100(difference in values)/(original value)
= (100)(100-88)/100
= (100)(12)/100)
=12.0
Answer: C
Answer: (C) 12.0%
Question: q, b, and c are positive integers. If q, b, and c are assembled into the six-digit number qbcqbc, which one of the following must be a factor of qbcqbc?
(A)  16
(B)  13
(C)  5
(D)  3
(E)  none of the above
Rationale: Plug in some values and check -
qbcqbc = 123123
Not divisible by 16 and 5
let qbcqbc = 125125
Not divisible by 3
Only option (B) and (E) is left in both the cases...
Check once more to marke (B) as correct answer
let qbcqbc = 135135
Again divisible by 13
So, mark answer as (B) 13
Answer: (B)  13
Question: In the xy-plane, the point (1, 3) is the center of a circle. The point (-2, 3) lies inside the circle and the point (1, -2) lies outside the circle. If the radius r of the circle is an integer, then r =
(A) 6
(B) 5
(C) 4
(D) 3
(E) 2
Rationale: An easy way to solve this question will be just to mark the points on the coordinate plane.
You'll see that the distance between the center (1, 3) and the point inside the circle (-2, 3) is 3 units
(both points are on y=3 line so the distance will simply be 1-(-2)=3)
So the radius must be more than 3 units.
The distance between the center (1,3) and the point outside the circle (1,-2) is 5 units
(both points are on x=1 line so the distance will simply be 3-(-2)=5)
So the radius must be less than 5 units, which implies 3 < r < 5, thus as r is an integer then r=4.
Answer: C.
Answer: (C) 4
Question: A does half as much work as Band C does half as much work as A and B together. If C alone can finish the work in 60 days, then together ,all will finish the work in :
(A) 13 1/3 days
(B) 12 1/3 days
(C) 15 days
(D) 20 days
(E) 30 days
Rationale: C alone can finish the work in 60 days.
(A + B)can do it in 20 days
(A + B)s 1 days wok = 1/20.
As 1 days work : Bs 1 days Work = 1/2 : 1 = 1:2.
Aâ€™s 1 dayâ€™s work = (1/20) * (1/3) = (1/60). [Divide 1/20 in the raio 1:2] Bs 1 days work = (1/20) * (2/3) = 1/30
(A+B+c)S 1 dayâ€™s work = (1/60) + (1/30) + (1/60) = 1/15
All the three together will finish it in 15 days.
ANSWER:C
Answer: (C) 15 days
Question: Ginger over the course of an average work-week wanted to see how much she spent on lunch daily. On Monday and Thursday, she spent $5.43 total. On Tuesday and Wednesday, she spent $4.54 on each day. On Friday, she spent $7.89 on lunch. What was her average daily cost?
(A) a. $3.19
(B) b. $3.75
(C) c. $3.90
(D) d. $4.08
(E) e. $4.48
Rationale: On Monday and Thursday, she spent $5.43total.
On Tuesday and Wednesday, she spent $4.54on each day.
On Friday, she spent $7.89 on lunch.
The average = (5.43 + 2*4.54 + 7.89)/5 = 4.48.
Answer: E.
Answer: (E) e. $4.48
Question: If A = {1, 3, 5}, B = {3, 5, 6}.Find A ∪ B
(A) {1,5}
(B) {1,3,5,6}
(C) {2,6}
(D) {8,9}
(E) {4,12}
Rationale: A= {1,3,5}
B= {3,5,6} Therefore ,
correct answer :A ∪ B = {1, 3, 5, 6}
B
Answer: (B) {1,3,5,6}
Question: What is the relationship between the fractions 14/15 and 37/40.
(A) 14/15 = 37/40
(B) 14/15 < 37/40
(C) 14/15 > 37/40
(D) cannot bedetermined
(E) None
Rationale: Take LCM of both 15, 40 we get 120
(14*8)/(15*8) = 112/120
(37*3)/(40*3) = 111/120
So 14/15>37/40
ANSWER:C
Answer: (C) 14/15 > 37/40
Question: A man can row downstream at 18 kmph and upstream at 10 kmph. Find the speed of the man in still water and the speed of stream respectively?
(A) 14, 5
(B) 14, 9
(C) 14, 6
(D) 14, 4
(E) 14, 2
Rationale: Let the speed of the man in still water and speed of stream be x kmph and y kmph respectively.
Given x + y = 18 --- (1)
and x - y = 10 --- (2)
From (1) & (2) 2x = 28 => x = 14, y = 4.
Answer: D
Answer: (D) 14, 4
Question: The current in a river is 10 mph. A boat can travel 50 mph in still water. How far up the river can the boat travel if the round trip is to take 5 hours?
(A) 120
(B) 100
(C) 96
(D) 85
(E) 150
Rationale: Upstream Speed = 50-10=40 mph
Downstream Speed = 50+10 = 60 mph
D/40 + D/60 = 5 hours
Solving for D we get D=120
Answer: A
Answer: (A) 120
Question: At 1:00, Annie starts to bicycle along a 45 mile road at a constant speed of 14 miles per hour. Thirty minutes earlier, Scott started bicycling towards Annie on the same road at a constant speed of 12 miles per hour. At what time will they meet?
(A) 2:00
(B) 2:30
(C) 3:00
(D) 3:30
(E) 4:00
Rationale: In the first 30 minutes, Scott can travel 6 miles, so there are 39 miles left.
Together Annie and Scott can complete 26 miles.
39/26 = 1.5, so they will meet 1.5 hours after 1:00.
The answer is B.
Answer: (B) 2:30
Question: Ten cards numbered 1 to 10 are placed in a box and then one card is drawn randomly. If it is known that the number on the drawn card is more than 5, what is the probability that it is an even number?
(A) 1/2
(B) 2/5
(C) 3/5
(D) 2/7
(E) 3/10
Rationale: There are 5 numbers higher than 5 and 3 of them are even.
The probability is 3/5.
The answer is C.
Answer: (C) 3/5
Question: In how many different ways can the letters of the word 'AIRPORT' be arranged in such a way that the vowels always come together?
(A) A)360
(B) B)720
(C) C)480
(D) D)5040
(E) of these
Rationale: The word 'AIRPORT' has 7 different letters.
When the vowels AIO are always together, they can be supposed to form one letter.
Then, we have to arrange the letters RPRT (AIO).
Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.
The vowels (AIO) can be arranged among themselves in 3! = 6 ways.
Required number of ways = (120 x 6) = 720.
ANSWER:B
Answer: (B) B)720
Question: What is the least value of x, So that 2x5452 is divisible by 9
(A) 7
(B) 8
(C) 9
(D) 3
(E) 0
Rationale: Explanation:
The sum of the digits of the number is divisible by 9.
Then the number is divisible by 9.
2 + x + 5 + 4 + 5 + 2 = 18 + x
Least value of x may be '0',
So that the total 18 + 0 = 18
is divisible by 9.
Answer: Option E
Answer: (E) 0
Question: A shopkeeper has 280 kg of apples. He sells 85% of these at 20% profit and remaining 60% at 30% profit. Find his % profit on total.
(A) 24%
(B) 25%
(C) 26%
(D) 28%
(E) 35%
Rationale: If the total quantity was 100
Then 85 X 20% + 60 X30%= 85
This profit will remain same for any total quantity unless the % of products remains the same. Hence 'E' is the answer
Answer: (E) 35%
Question: If 5 women or 8 girls can do a work in 84 days.In how many days can 10 women and 5 girls can do the same work?
(A) 32
(B) 33
(C) 34
(D) 35
(E) cannot be determined
Rationale: Given that 5 women is equal to 8 girls to complete work/
So,10 women=16 girls.
10 women+5 girls=16 girls+5 girls=21 girls.
8 girls can do a work in 84 days then 21 girls can do a work in (8*84)/21=32 days
Therefore 10 women and 5 girls can a work in 32 days.
Answer is option A
Answer: (A) 32
Question: What number is obtained by adding the units digits of 734^100 and 347^83?
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
Rationale: The units digit of 734^100 is 6 because 4 raised to the power of an even integer ends in 6.
The units digit of 347^83 is 3 because powers of 7 end in 7, 9, 3, or 1 cyclically. Since 83 is in the form 4n+3, the units digit is 3.
Then 6+3 = 9.
The answer is C.
Answer: (C) 9
Question: A shopkeeper give 12% additional discount on the discounted price, after giving an initial discount of 20% on the labelled price of a radio. If the final sale price of the radio is Rs.704, then what is its labelled price?
(A) Rs.844.80
(B) Rs.929.28
(C) Rs.1000
(D) Rs.1044.80
(E) None
Rationale: Solution
Let the labelled price be Rs.x.
88% of 80% of x	= 704
x=(704x100x100 /88x80)
= 1000.
Answer C
Answer: (C) Rs.1000
Question: Find the compound interest and the amount on Rs.8000 at 5% per annum for 3 years when C.I is reckoned yearly?
(A) 1261
(B) 1572
(C) 1689
(D) 1687
(E) 2679
Rationale: A = 8000(21/20)3
= 9261
= 8000
---------
1261
Answer: A
Answer: (A) 1261
Question: W and X started a business investing Rs. 30,000 and Rs. 6,000 respectively. Out of a total profit of Rs. 18,000, W’s share is :
(A) 14000
(B) 15000
(C) 16000
(D) 17000
(E) 18000
Rationale: Ratio of their shares = 30000 : 6000 = 5 : 1.
W’s share = Rs. 18000 * 5/6
= Rs. 15000
ANSWER:B
Answer: (B) 15000
Question: What is the smallest number which when increased by 3 is divisible by 9, 35, 25 and 21?
(A) 1572
(B) 1782
(C) 1992
(D) 2122
(E) 2342
Rationale: When increased by 3, the number must include at least 3^2*5^2*7 = 1575
The answer is A.
Answer: (A) 1572
Question: 4 dice are thrown simultaneously on the board. Find the probability which show the same face?
(A) 2/113
(B) 3/117
(C) 1/216
(D) 3/111
(E) 4/121
Rationale: The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:
=6×6×6×6=64=6×6×6×6=64
n(S)=64n(S)=64
Let XX be the event that all dice show the same face.
X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}
n(X)=6n(X)=6
Hence required probability,
=n(X)n(S)=664=n(X)n(S)=664
=1/216
C
Answer: (C) 1/216
Question: I sold a book at a profit of 12%. Had I sold it for $18 more, 18% would have been gained. Find the cost price?
(A) $100
(B) $250
(C) $300
(D) $200
(E) $180
Rationale: 118% of cost - 112% of cost = $18
6% of cost = $18
cost = 18*100/6 = $300
Answer is C
Answer: (C) $300
Question: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
(A) 17.9 sec
(B) 11.8 sec
(C) 27.7 sec
(D) 10.8 sec
(E) 17.8 sec
Rationale: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5 = 10.8 sec.
Answer: D
Answer: (D) 10.8 sec
Question: In a group of 100 cars, 37 cars do not have air conditioning. If at least 51 cars have racing stripes, what is the greatest number of cars that could have air conditioning but not racing stripes?
(A) 45
(B) 47
(C) 48
(D) 49
(E) 53
Rationale: Lets assume AC=63(includesonly AC carsandcars with AC and racing stripes)
lets assume RS(racing stripes)>=51(includescars with AC and racing stripesandonly racing stripes).
Now since we want to maximize(only AC) we have to see to it thatcars with AC and racing stripesis minimal(assume 0) But since RS>=51.. we have to assign atleast 14 tocars with AC and racing stripes.
Hence AC=63-14=49.
The answer is D
Answer: (D) 49
Question: If x < 0 and 0 < y < 1, which of the following has the greatest value H?
(A) x^2
(B) (xy)^2
(C) (x/y)^2
(D) x^2/y
(E) x^2*y
Rationale: Given, x < 0 and 0 < y < 1
Let, x = -2 and y = 1/2
A. x^2 = (-2)^2 =4
B. (xy)^2 = (-2*1/2)^2 =1
C. (x/y)^2 = {-2/(1/2)}^2 = (-4)^2 =16
D. x^2/y = (-2)^2 / (1/2) = 4*2 =8
E. x^2*y = (-2)^2*(1/2) =2
Answer: option C
Answer: (C) (x/y)^2
Question: If P's height is 40% less than that of Q, how much percent Q's height is more than that of P?
(A) 66.66
(B) 86.88
(C) 70.05
(D) 76.66
(E) 89.99
Rationale: Q'S height over P's = ((40/(100-40)) * 100
= 66.66%
ANSWER A
Answer: (A) 66.66
Question: The average salary of the employees in a office is Rs.120/month.The avg salary of officers is Rs.420 and of non officers is Rs 110. If the no.of officers is 15,then find the No of nonofficers in the office.
(A) 400
(B) 420
(C) 430
(D) 450
(E) 510
Rationale: Let no. of non- officers be x
15 * 420 + x * 110 = (x + 15) 120
x = 450
D
Answer: (D) 450
Question: The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 40 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam.
(A) 78
(B) 77
(C) 25
(D) 77
(E) 62
Rationale: Let the number of students who wrote the exam be x.
Total marks of students = 80 x.
Total marks of (x - 5) students = 90(x - 5)
80x - (5 * 40) = 90(x - 5)
250 = 10x => x = 25
Answer:C
Answer: (C) 25
Question: The age of father 8 years ago was thrice the age of his son. Five years hence, father's age will be twice that of his son. The ratio of their present ages is:
(A) 47 : 11
(B) 37 : 21
(C) 27 : 21
(D) 47 : 21
(E) 47 : 31
Rationale: Let the ages of father and son 8 years ago be 3x and x years respectively.
Then, (3x + 8) + 5 = 2[(x + 8) + 5]
3x + 13 = 2x + 26
x = 13.
Required ratio = (3x + 8) : (x + 8) = 47 : 21.
Answer: Option D
Answer: (D) 47 : 21
Question: How many even integers n, such that 20<=n<=200 are of the form 3k+4, where k is any natural number?
(A) 26
(B) 30
(C) 34
(D) 38
(E) 42
Rationale: The first number is 22 = 16+6(1).
We can continue adding 6 to make a list: 22, 28, 34,...
The last number is 196 = 16+6(30)
There are 30 numbers in the list.
The answer is B.
Answer: (B) 30
Question: 50% of a number is more than 20% of 650 by 190. Find the number?
(A) 640
(B) 278
(C) 800
(D) 267
(E) 121
Rationale: (50/100) * X â€“ (20/100) * 650 = 190
1/2 X = 320
X = 640
Answer:A
Answer: (A) 640
Question: A and B can finish 5 piece of work in 10 days each. C can do 40% faster than A and B.Approximately how many days would it take to finish 51 piece of work with all three working simultaneously?
(A) 38
(B) 42
(C) 46
(D) 50
(E) 51
Rationale: since c is 40% faster , thus it will create 7 pieces of work in 10 days
in 10 days total number of work by all three will be :
5+5+7=17
in 20 days:
17+17=34
in 25 days:
34+17=51
thus in all 51 days.
Ans:E
Answer: (E) 51
Question: In a certain candy store, 22% of the customers are caught sampling the candy and are charged a small fine, but 5% of the customers who sample the candy are not caught. What is the total percent of all customers who sample candy?
(A) 22%
(B) 23%
(C) 24%
(D) 25%
(E) 34%
Rationale: Since 5% of the customers who sample the candyare notcaught, then 88% of the customers who sample the candyarecaught:
{% of customers who sample candy}*0.95 = 0.22;
{% of customers who sample candy} = 0.231.
Answer: B.
Answer: (B) 23%
Question: 1.	How much more would Rs.24000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly?
(A) A)Rs.6,338.40
(B) B)Rs.6,339.40
(C) C)Rs.6,340.40
(D) D)Rs.6,341.40
(E) E)Rs.6,342.40
Rationale: 24000(11/10)4 - 24000(6/5)2 = 6,338.40
ANSWER:A
Answer: (A) A)Rs.6,338.40
Question: A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
(A) 2/5
(B) 3/9
(C) 4/7
(D) 2/7
(E) 1/3
Rationale: Total number of balls = 6+8 = 14
Number of white balls = 8
probability of drawing a white ball = 8/14 = 4/7
Answer is B
Answer: (B) 3/9
Question: Benny goes to the market for buying some apples to be distributed between her nine kids equally.She takes 360 dollars with her .The cost of each apple is 4 dollars .How many apples does she buy to share them equally between her eighteen kids?
(A) 8
(B) 9
(C) 5
(D) 7
(E) 10
Rationale: cost of each apple = 4 dollars
Apples that Benny can buy with the amount she has=360/4 = 90.
Apples that each kid gets evenly = 90/18 = 5 Apples.
So the answer is C=5
Answer: (C) 5
Question: Four person are chosen at random form a group of 3 men, 2 women and 4 children. The chance that exactly 2 of them are children, is:
(A) 10/21
(B) 20/22
(C) 32/45
(D) 13/98
(E) 43/21
Rationale: Number of ways of choosing 4 persons out of 9
=9c4
=126
No.of ways of choosing 2 children out of 4 and 2 persons out of (3+2)= (4c2+5c2)
=60
P(E)=60/126
=10/21
ANSWER A
Answer: (A) 10/21