mathewhe/aqua_rat huggingface dataset:
Question: Statement : All the organised persons find time for rest. Sunita, in-spite of her busy schedule, finds time for rest.
Conclusions :
I. Sunita is an organised person.
II. Sunita is an industrious person.
(A)  I only
(B)  II only
(C)  I and II only
(D)  I and III only
(E)  II and III only
Rationale: Sunita has a busy schedule. This means that she is industrious. But still she finds the time for rest. This means that she is an organised person.
So both conclusions follow.
Answer D)
Answer: (D)  I and III only
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions?
(A) 707
(B) 704
(C) 709
(D) 705
(E) 701
Rationale: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4 = 70400 cm
= 704 m
Answer:B
Answer: (B) 704
Question: Line Q has the equation 5y – 3x = 60. If Line S is perpendicular to Q, has an integer for its y-intercept, and intersects Q in the second quadrant, then how many possible Line S’s exist? (Note: Intersections on one of the axes do not count.)
(A) 35
(B) 40
(C) 45
(D) 50
(E) 55
Rationale: 5y - 3x = 60 and so y = 3x/5 + 12
When x = 0, then y = 12.
When y = 0, then x = -20
The slope is 3/5, so the slope of line S is -5/3.
Through the point (-20, 0), 0 = -5(-20)/3 + c
The y-intercept is c = -100/3 < -33.
Thus the perpendicular line S can have y-intercepts from -33 up to 11.
The number of possible lines is 33 + 11 + 1 = 45
The answer is C.
Answer: (C) 45
Question: In how many ways a committee consisting of 3 men and 2 women can be formed from 4 men and 7 women?
(A) A)84
(B) B)15
(C) C)20
(D) D)18
(E) E)21
Rationale: Required number of ways = 4C3*7C2 = 4*21 = 84
Answer is A
Answer: (A) A)84
Question: If 5x = 6y and xy ≠ 0, what is the ratio of 1/4*x to 1/6*y ?
(A)  25/6
(B)  36/25
(C)  9/5
(D)  5/6
(E)  25/36
Rationale: 5x = 6y => x/y = 6/5
1/4*x to 1/6*y = x/y * 3/2 = (6/5)*(3/2)=9/5
Ans: C
Answer: (C)  9/5
Question: 15 girls can complete a rangoli in 12 days, and 10 boys can complete the same work in 15 days. To complete the work earlier 10 boys and 15 girls are employed, in how many days will this work get completed?
(A) 6
(B) 7
(C) 6.5
(D) 6 2/3
(E) 6 1/4
Rationale: Work done by 15 girls per day =1/12
Work done by 10 boys per day = 1/15
Work done by 15 girls and 10 boys per day=1/12+1/15=3/20=6 2/3
10 boys and 15 girls will complete the work in =6 2/3 days
D
Answer: (D) 6 2/3
Question: Health insurance Plan P requires the insured person to pay $600 but then the insurance pays 80% of the cost over $600. Plan Q requires the insured to pay the initial $300, but then pays 60% of the cost over $300. Which of the following is a cost level for which both insurance plans pay out the same amount?
(A) $1200
(B) $1500
(C) $1800
(D) $2100
(E) $2400
Rationale: 0.8(x-600)=0.6(x-300)
0.2x=480-180
x=1500
The answer is B.
Answer: (B) $1500
Question: The third proportional to 2 and 4 is?
(A) 8
(B) 7
(C) 4
(D) 5
(E) 3
Rationale: (4*4)/2 = 8
Answer:A
Answer: (A) 8
Question: What is the perimeter of a square with area 9p^2/16 ?
(A) 3p/4
(B) 3p^2/4
(C) 3p
(D) 3p^2
(E) 4p/3
Rationale: Area of square, (side)^2 = (3p/4)^2
Therefore side of the square = 3p/4
Perimeter of square = 4*side = 4* (3p/4) = 3p
Answer is C.
Answer: (C) 3p
Question: A and B invests Rs.3000 and Rs.6000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit?
(A) 9:6
(B) 3:8
(C) 3:1
(D) 9:9
(E) 3:4
Rationale: (3*6 + 6*6): (6*12)
18:24 => 3:4.Answer:E
Answer: (E) 3:4
Question: 4,25,49,
(A) 149
(B) 169
(C) 189
(D) 209
(E) 121
Rationale: 11^2= 121because follow sequence of square of the prime numbers
ANSWER:E
Answer: (E) 121
Question: Calculate the share of profit of 15000 received by Edgar who is the working partner in a business. Edgar invested 22000 in the business while his partner, Eli invested 34000.A is a working partner and B is a sleeping partner in a business. Edgar receives 12% for managing the business, and the rest is divided in proportion to their capitals.
(A) 1985.7
(B) 5985.7
(C) 6785.7
(D) 6985.7
(E) 5985.7
Rationale: The amount Edgar gets for managing
= 12% of Rs. 15000 = 1800
Remaining profit = 15000 â€“ 1800 = 13200
This is to be divided in the ratio 22000:34000=22: 34=11:17
Share of Edgar = 11/28 of 13200 = 5185.7
â‡’ Total share of Edgar = 1800 + 5185.7 = 6985.7.
Answer D
Answer: (D) 6985.7
Question: The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8748, its purchase price was :
(A) 12003
(B) 12000
(C) 12002
(D) 12289
(E) 12019
Rationale: Explanation:
= Rs.12000
Answer: B) 12000
Answer: (B) 12000
Question: A train speeds past a pole in 15 sec and a platform 130 m long in 25 sec, its length is?
(A) 195
(B) 150
(C) 160
(D) 170
(E) 180
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 130)/25 = x/15 => x = 195 m.
Answer: Option A
Answer: (A) 195
Question: At 30 minutes past 7 o'clock, what is the angle between the two hands?
(A) 15
(B) 30
(C) 45
(D) 60
(E) 75
Rationale: The hour hand moves 360 degrees in 12 hours.
The hour hand moves 30 degrees in 1 hour and 15 degrees in 30 minutes.
The minute hand moves 360 degrees in 60 minutes and 180 degrees in 30 minutes.
At 30 minutes past 7, the hour hand has moved 225 degrees.
At 30 minutes past 7, the hour hand has moved 180 degrees.
The angle between the two hands is 45 degrees.
The answer is C.
Answer: (C) 45
Question: 7, 21, 63, 189, 567, ?
(A) 1521
(B) 1609
(C) 1307
(D) 1701
(E) 1801
Rationale: Explanation :
Multiply a term with 3 to get the next term
Answer : Option D
Answer: (D) 1701
Question: Cole drove from home to work at an average speed of 70 kmh. He then returned home at an average speed of 105 kmh. If the round trip took a total of 2 hours, how many minutes did it take Cole to drive to work?
(A) 66
(B) 70
(C) 72
(D) 75
(E) 78
Rationale: Let the distance one way be x
Time from home to work = x/70
Time from work to home = x/105
Total time = 2 hrs
(x/70) + (x/105)= 2
Solving for x, we get x = 84
Time from home to work in minutes= (84)*60/70 = 72 minutes
Ans= C
Answer: (C) 72
Question: A train 200 m long running at 54 kmph crosses a platform in 25 sec. What is the length of the platform?
(A) 175
(B) 266
(C) 350
(D) 277
(E) 232
Rationale: Length of the platform= 54 * 5/18 * 25 = 375 – 200
= 175
Answer:A
Answer: (A) 175
Question: If the sides of a square are multiplied by sqrt(2), the area of the original square is how many times as large as the area of the resultant square?
(A) 2%
(B) 4%
(C) 50%
(D) 100%
(E) 200%
Rationale: Let x be the original length of one side.
Then the original area is x^2.
The new square has sides of length sqrt(2)*x, so the area is 2x^2.
The area of the original square is 1/2 = 50% times the area of the new square.
The answer is C.
Answer: (C) 50%
Question: if a@b = a * b^(1/2) then 1@9 = ?
self made
(A) 2
(B) 6
(C) 3
(D) 8
(E) 4
Rationale: a@b = a * b^(1/2)
1@9 = 1*9^(1/2) = 1*3 = 3
Correct Option: C
Answer: (C) 3
Question: The symphony sells two kinds of tickets: orchestra, for $30, and upper tiers, for $12. On a certain night, the symphony sells 90 tickets and gets $1620 in revenue from the sales. How many orchestra tickets did they sell?
(A) 25
(B) 30
(C) 35
(D) 40
(E) 45
Rationale: Let x be the number of orchestra tickets.
Then 90-x is the number of upper tier tickets.
30x + 12(90-x) = 1620
18x = 1620-1080
x = 30
The answer is B.
Answer: (B) 30
Question: Mohit sold an article for $18000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article?
(A) 16000
(B) 25000
(C) 15000
(D) 18000
(E) 17000
Rationale: C
15000
Let the CP be $x.
Had he offered 10% discount, profit = 8%
Profit = 8/100 x and hence his SP = x + 8/100 x = $1.08x = 18000 - 10/100(18000) = 18000 - 1800 = $16200
=> 1.08x = 16200
=> x = 15000
Answer: (C) 15000
Question: If a certain number when divided by the numbers 5,3,2 one after other successively, leaves a remainder 0,2,1 Then what will be the remainders if it is divided by the numbers 2,3,5
(A) 1,2,0
(B) 1,2,1
(C) 1,2,2
(D) 1,2,3
(E) 1,2,4
Rationale: The Number is 35 ,When divided by 5,3,2 leaves remainder 0,2,1 respectively.
So if 35 is divided by 2,3,5 leaves remainder 1,2,0 respectively.
ANSWER:A
Answer: (A) 1,2,0
Question: A can finish a work in 48days, B in 9days and C in 2days, B and C start the work but are forced to leave after 3 days. The remaining work was done by A in?
(A) 10days
(B) 12days
(C) 6days
(D) 20days
(E) 8days
Rationale: B+C 1day work = 1/9 + 1/12 = 7/36
work done by B and C in 3days = 7/36 * 3 = 7/12
Remaining work = 1 - 7/12 = 5/12
1/48 work is done by A in 1day
5/12 work is done by A in 48*5/12 = 20days
Answer is D
Answer: (D) 20days
Question: Two trains 141 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?
(A) 7.16
(B) 7.59
(C) 7.12
(D) 7.15
(E) 7.11
Rationale: T = (141 + 165)/ (80 + 65) * 18/5
T = 7.59
Answer: B
Answer: (B) 7.59
Question: Diane find 4 cans of paint are just enough to paint one third of her room. How many more cans of paint will she need to finish her room and paint a second room of the same size?
(A) 5
(B) 7 and a half
(C) 10
(D) 12 and a half
(E) 20
Rationale: She will need 8 cans to paint the rest of this room and 12 for the next room for a total of 20 cans.
E
Answer: (E) 20
Question: A certain collage has total of 500 seniors each majoring in exactly one of six subjects. A minimum of 20 seniors major in each six subjects. If three quarter of the seniors major in one of four subjects, what is the greatest possible number of seniors majoring in one of the other two subjects?
(A) 105
(B) 80
(C) 75
(D) 60
(E) 50
Rationale: Answer A
500 = 375 + 20 + x => x = 105
= 3/4 * 500 in 4 subjects + 20 min for 5th subject + x = 500
Answer: (A) 105
Question: A polling company reports that there is a 70% chance that a certain candidate will win the next election. If the candidate wins, there is a 60% chance that she will sign Bill X and no other bills. If she decides not to sign Bill X, she will sign either Bill Y or Bill Z, chosen randomly. What is the chance that the candidate will sign Bill Z?
(A) 10
(B) 14
(C) 6
(D) 4
(E) 5
Rationale: 70% - Candidate Elected
100%-60% = 40% - Candidate doesnotsigh Bill X
50% - Candidate randomly chooses between two bills.
These are multiplicative:
70% x 40% x 50%
0.7 x 0.4 x 0.5 = 0.14 = 14%
Answer (B)
Answer: (B) 14
Question: Find the value of (20C18)*(20C20)
(A) 400
(B) 380
(C) 360
(D) 350
(E) 330
Rationale: 20C20 = 1
(20C2)*(20C20) = 20! * 1/18!
= 20*19*18!/18!
= 20*19*1
= 380
ANSWER:B
Answer: (B) 380
Question: A contractor undertook to do a piece of work in 18 days. He employed certain number of laboures but 9 of them were absent from the very first day and the rest could finish the work in only 6 days. Find the number of men originally employed ?
(A) 3.5
(B) 4
(C) 4.5
(D) 4.2
(E) 4.3
Rationale: Let the number of men originally employed be x.
18x = 6(x â€“ 9)
or x = 4.5
Answer C
Answer: (C) 4.5
Question: A man gains 50% by selling an article for a certain price. If he sells it at double the price, the percentage of profit will be.
(A) 130%
(B) 300%
(C) 150%
(D) 160%
(E) 170%
Rationale: Explanation:
Let the C.P. = x,
Then S.P. = (150/100)x = 3x/2
New S.P. = 2(3x/2) = 3x/1
Profit = 3x/1 - x = 3x/1
Profit% = (Profit/C.P.) * 100
=> (3x/1) * (1/x) * 100 = 300 %
Option B
Answer: (B) 300%
Question: if 2x + 6y = 18,5x = 10y + 20,what is the value of x?
(A) 6.5
(B) 5.5
(C) 5
(D) 6
(E) 4
Rationale: solution:
I-->
x = 2y + 4
sub in II
2(2y + 4) + 6y = 18
4y + 6y = 10
y = 1
sub y=1 in other equation
5x = 10(1) + 20
x = 6
answer is D
Answer: (D) 6
Question: Average of 13 results is 65. If the average of first six results is 61 and average of last six results is 59 Then find the seventh result?
(A) 110
(B) 115
(C) 125
(D) 140
(E) 145
Rationale: 125
Option 'C'
Answer: (C) 125
Question: Little Johny went to the toy shop and spent one half of the money that was in his wallet.
When he came out, he found that he had as many paise as he had rupees and half as many rupees as he had paise when he went in. Find the money in his wallet when he entered the store.
(A) 95.98
(B) 97.98
(C) 90.98
(D) 99.9
(E) 99.98
Rationale: E
Little Johny have Rupees 99.98 in his wallet when he entered the store.
Answer: (E) 99.98
Question: A train passes a station platform in 20 sec and a man standing on the platform in 12 sec. If the speed of the train is 72 km/hr. What is the length of the platform?
(A) 227
(B) 140
(C) 160
(D) 120
(E) 171
Rationale: Speed = 72 * 5/18 = 20 m/sec.
Length of the train = 20* 12= 240 m.
Let the length of the platform be x m . Then,
(x + 240)/20= 20=> x = 160 m.
Answer:C
Answer: (C) 160
Question: A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.
(A) 2 hours
(B) 1 hours
(C) 7 hours
(D) 4 hours
(E) 3 hours
Rationale: Speed downstream = (13 + 4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = 68/17 hrs = 4 hrs.
ANSWER:D
Answer: (D) 4 hours
Question: 22 buses are running between two places P and Q. In how many ways can a person go from P to Q and return by a different bus?
(A) None of these
(B) 462
(C) 412
(D) 424
(E) 442
Rationale: Explanation :
He can go in any bus out of the 22 buses.
Hence He can go in 22 ways.
Since he can not come back in the same bus that he used for travelling,
He can return in 21 ways.
Total number of ways = 22 x 21 = 462. Answer : Option B
Answer: (B) 462
Question: The ratio between the perimeter and the width of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the width of the rectangle?
(A) 12 cm
(B) 16 cm
(C) 18 cm
(D) 20 cm
(E) 22 cm
Rationale: 2L+2W = 5W
L = 3W/2
W*L = 216
3W^2/2 = 216
W^2 = 144
W = 12
The answer is A.
Answer: (A) 12 cm
Question: Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age
(A) 12,28
(B) 14,30
(C) 16,32
(D) 18,34
(E) 19,32
Rationale: Explanation:
Let the age of younger person is x,
Then elder person age is (x+16)
=> 3(x-6) = (x+16-6) [6 years before]
=> 3x-18 = x+10
=> x = 14.
So other person age is x + 16 = 30
Answer: Option B
Answer: (B) 14,30
Question: For any integer k > 1, the term “length of an integer” refers to the number of positive prime factors, not necessarily distinct, whose product is equal to k. For example, if k = 24, the length of k is equal to 4, since 24 = 2 × 2 × 2 × 3. If x and y are positive integers such that x > 1, y > 1, and x + 3y < 940, what is the maximum possible sum of the length of x and the length of y?
(A) 24
(B) 22
(C) 16
(D) 18
(E) 20
Rationale: we know that : x > 1, y > 1, and x + 3y < 940,
and it is given that length means no of factors.
for any value of x and y, the max no of factors can be obtained only if factor is smallest noall factors are equal.
hence, lets start with smallest no 2.
2^1 =2
2^2 =4
2^3=8
2^4=16
2^5=32
2^6=64
2^7=128
2^8=256
2^9=512
2^10 =1024 (opps//it exceeds 1000, so, x can't be 2^10)
so, max value that X can take is 2^9 , for which haslength of integeris 9.
now, since x =512 ,x+3y<940
so, 3y<428
==> y<428/3
so, y can take any value which is less than 428/3. and to get the maximum no of factors of smallest integer, we can say y=2^7
for 2^7 has length of integer is 7.
SO, combined together : 9+7 = 16.
C
Answer: (C) 16
Question: A is half good a work man as B and together they finish a job in 14 days. In how many days working alone B finish the job?
(A) 77 days
(B) 21 days
(C) 88 days
(D) 55 days
(E) 44 days
Rationale: WC = 1:2
2x + x = 1/14 => x = 1/42
2x = 1/21 => 21 days
Answer: B
Answer: (B) 21 days
Question: Today John is twice as old as Sam and Sam is 2 years younger than Mike. If John, Sam, and Mike are all alive 6 years from today, which of the following must be true on that day. I. John is twice as old as Sam II. Sam is 4 years younger than Mike III. John is older than Mike
(A) I
(B) I,II & III
(C) II
(D) II, III
(E) III
Rationale: Say Mike age is 10
Sam age is 8
John age is 16
After 6 years
Mike age is 16
Sam age is 14
John age is 28
i.e ) after 6 years
Sam is 2 years younger than Mike
John is twice as old as Sam
John is older than Mike
Answer : B
Answer: (B) I,II & III
Question: A batsman scored 120 runs whichincluded 3 boundaries and 8sixes. What % of his total score did he make by running between the wickets
(A) 40%
(B) 50%
(C) 60%
(D) 65%
(E) 72%
Rationale: Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 120 - (60)
= 60
Now, we need to calculate 60 is what percent of 120.
=> 60/120 * 100 = 50%
B
Answer: (B) 50%
Question: A train 200m long passes a standing man in 20 seconds. What is the speed of the train?
(A) 30km/hr
(B) 36km/hr
(C) 42km/hr
(D) 50km/hr
(E) 32km/hr
Rationale: Speed of the train = 200/20* 18/5 = 36km/hr
Answer is B
Answer: (B) 36km/hr
Question: If the length of the longest chord of a certain circle is 24, what is the radius of that certain circle?
(A) 12
(B) 5
(C) 10
(D) 15
(E) 20
Rationale: Longest chord of a circle is the diameter of the circle
diameter = 2 * radius
If diameter of the circle is given as 24 = 2 * 12
so radius of the circle = 12
correct answer - A
Answer: (A) 12
Question: If a number R between 0 and 1 is selected at random, which of the following will the number most likely be between?
(A) 0 and 3/20
(B) 3/20 and 1/5
(C) 1/5 and 1/4
(D) 1/4 and 3/10
(E) 3/10 and 1/2
Rationale: The number R will most likely be between the largest range.
A. 0 and 3/20 --> range 3/20;
B. 3/20 and 4/20 --> range 1/20;
C. 4/20 and 5/20 --> range 1/20;
D. 5/20 and 6/20 --> range 1/20;
E. 6/20 and 10/20 --> range 4/20.
Answer: E.
Answer: (E) 3/10 and 1/2
Question: A man walking at a constant rate of 5 miles per hour is passed by a woman traveling in the same direction along the same path at a constant rate of 25 miles per hour. The woman stops to wait for the man 5 minutes after passing him, while the man continues to walk at his constant rate. How many minutes must the woman wait until the man catches up?
(A) 16
(B) 20
(C) 24
(D) 25
(E) 28
Rationale: When the woman passes the man, they are aligned (m and w). They are moving in the same direction. After 5 minutes, the woman (W) will be ahead the man (M):
m------M---------------W
w
In the 5 minutes, after passing the man, the woman walks the distance mW = wW, which is 5*25/60 =25/12 miles and the man walks the distance mM, which is 5*5/60 = 5/12 mile.
The difference of 25/12 - 5/12 =1/3 miles (MW) will be covered by the man in (4/3)/4 = 1/3 of an hour, which is 20 minutes.
Answer B.
Answer: (B) 20
Question: One fourth of one third of two fifth of a number is 25. What will be40% of that number
(A) A)140
(B) B)150
(C) C)180
(D) D)200
(E) E)300
Rationale: Explanation:
(1/4) * (1/3) * (2/5) * x = 25
then x = 25 * 30 = 750
40% of 750 = 300
Answer: Option E
Answer: (E) E)300
Question: In a box there is a number of balls, out of which 1/5 are green, 1/2 are red, 1/10 are pink and the remaining 10 are orange. How many balls are green?
(A) 10 balls.
(B) 40 balls.
(C) 12 balls.
(D) 50 balls.
(E) 15 balls.
Rationale: Let x be the total number of balls.
The number of green, red and pink balls is x(1/5+1/2+1/10)=8x/10
The number of orange balls is x-8x/10=2x/10.
Thus, 2x/10=10, from where x=100/2, x=50.
The number of green balls is 1/5*50=10.
Answer A 10.
Answer: (A) 10 balls.
Question: The integer W has a tens digit of 6 and a units digit of 7. The units digit of integer y is 8. The product of W and y has a tens digit of 8. Which of the following is a possible tens digit of integer y?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: Let W be 67 and y be a8. Then the product of W and y can be written as (60+7)*(10a+8)=600a + 480+70a+56=600a+536+70a. Since 600a dose not affect on the tens digit we can ignore 600a.
So tens digit should be the unit of 3+7a. That means 3+7a =8, 18, 28, 38, 48 or 58 (since 3+7a<=3+7*9=66) --->7a=5, 15, 25, 35, 45, 55. So the only possibility is a=5.
So the answer is (C).
Answer: (C) 5
Question: Three unbased coins are tossed. the probability of getting at most one head two tail is ?
(A) 1/2
(B) 7/8
(C) 3/4
(D) 3/8
(E) 2/3
Rationale: S={TTT,TTH,THT,HTT,THH,HTH,HHT,HHH}
E be the event of getting at least two head is {TTH,THT,HTT}
P(E)=n(E)/n(S)=3/8
Answer(D)
Answer: (D) 3/8
Question: Rahul went to a shop and bought things worth Rs. 75, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
(A) A)19.7
(B) B)29.9
(C) C)39.7
(D) D)69.7
(E) E)99.7
Rationale: Total cost of the items he purchased = Rs.75
Given that out of this Rs.75, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (75−30/100−x)6/100 = 30/100
⇒ 6(75 −0.3 −x) = 30
⇒ (75 − 0.3 − x) = 5
⇒ x = 75 − 0.3 − 5 = 69.7
D)
Answer: (D) D)69.7
Question: You collect pens. Suppose you start out with 5. Mike gives you another 20 pens. Since her father makes pens, Cindy decides to double your pens. Since you're nice, you give Sharon 19 pens. How many pens do you have at the end?
(A) 39
(B) 40
(C) 31
(D) 42
(E) 43
Rationale: Solution
Start with 5 pens.
Mike gives you 20 pens: 5 + 20 = 25 pens.
Cindy doubles the number of pens you have: 25 Ã— 2 = 50 pens.
Sharon takes 19 pens from you: 50 - 19 = 31 pens.
So you have 31 at the end.
Correct answer: C
Answer: (C) 31
Question: An Ant is climbing 30 meters tall pole. It climbs 3 meter during the day and slips down 2 meters down during night in sleep, How many days it takes to reach the top of the pole?
(A) A - 30
(B) B - 29
(C) C - 28
(D) D - 27
(E) E - 26
Rationale: Ants overall distance covered is 3 -2 = 1 meter per day.
In 27 days it will climb 27 meters. On 28 th day it will reach the top of the pole.
Answer: C
Answer: (C) C - 28
Question: If john makes a contribution to a charity fund at school, the average contribution size will increase by 50% reaching $75 per person. If there were 6 other contributions made before john's, what is the size of his donation?
(A) $225
(B) $150
(C) $200
(D) $250
(E) $450
Rationale: Cavg = average contribution before John
Cavg*1.5 = 75, therefore the average cont is $50 before John.
If he needs to increase the average contribution by $25, he must put in $25 for each of the 6 people.
so $150.
But, he also has to put in the average for himself (the seventh person), so add $75.
So $225 is your answer.
Answer A
Answer: (A) $225
Question: Ashok secured average of 74 marks in 6 subjects. If the average of marks in 5 subjects is 74, how many marks did he secure in the 6th subject?
(A) 66
(B) 74
(C) 78
(D) 80
(E) None of these
Rationale: Explanation:
Number of subjects = 6
Average of marks in 6 subjects = 74
Therefore total marks in 6 subjects = 74 * 6 = 444
Now, No. of subjects = 5
Total marks in 5 subjects = 74 * 5 = 370
Therefore marks in 6th subject = 444 – 370 = 74
ANSWER B
Answer: (B) 74
Question: Set S is given as S = {1,3,5,7,9,11,13,15,17}. In how many ways can three numbers be chosen from Set S such that the sum of those three numbers is 18?
(A) zero
(B) one
(C) two
(D) three
(E) four
Rationale: 1,3,5,7,9,11,13,15,17 are all odd numbers and as such we can not get an even number from three odd number...
Sum of Odd Number of Odd Numbers = Odd Number..
So, Answer will be (A) Zero...
Answer: (A) zero
Question: HE SUM OF EVEN INTEGERS:
The sum of the even numbers between 1 and k is 79*80, where k is an odd number, then k=?
(A) 79
(B) 80
(C) 81
(D) 157
(E) 159
Rationale: (E) 159
sum of numbers till n = n(n+1)/2 , sum of even numbers will be almost half of this i.e. n(n+1)/4 .
so if S = 79.80, then n= 159.
Answer: (E) 159