mathewhe/aqua_rat huggingface dataset:
Question: If d is the standard deviation x, y, and z, what is the standard deviation of x +7, y + 7, z + 7 ?
(A) 7d
(B) 7d+7
(C) 7d+14
(D) d
(E) 7d+21
Rationale: CONCEPT: Standard Deviation is Defined as Average Deviation of Terms in the set from the Mean value of the set. i.e.
1) It depends on the separation between the successive terms of the set
2) If a Constant Value is Added/Subtracted in every terms of set then the Separation between successive terms does NOT change Hence S.D. remains Constant
e.g.{1, 2, 3, 4, 5} will have same standard Deviation as {1+10, 2+10, 3+10, 4+10, 5+10}
3) If a Constant Value is Multiplied in every terms then the Separation between succesive terms gets multiplied by the constant Hence S.D. remains gets multiplied by same Number
e.g. {0.7, 1.4, 2.1, 2.8, 3.5} will have Standard Deviation = 0.7* Standard deviation of set {1, 2, 3, 4, 5}
When 7 is added in each term of set {x, y, z} then the new set {x+7, y+7, z+7} will remain same as the previous standard deviation i.e. d
Answer: D
Answer: (D) d
Question: Ram and Ramesh can do a work piece of work in 6 days. Ram alone can do it in 10 days. In how many days can Ramesh alone can do it?
(A) 11 days
(B) 12 days
(C) 15 days
(D) 13 days
(E) 10 days
Rationale: Explanation:
Ram and Ramesh can do a work in 6 days.
part done by Ram and Ramesh in 1 day =1/6
Ram alone can do it in 10 days. Therefore,
Part done by Ram alone in 1 day =1/10. Therefore,
part can do by Rames alone in 1 day =1/6 - 1/10 = 2/30
Net work can do by Ramesh only = 30/2 =15
Answer : C
Answer: (C) 15 days
Question: The ratio of alcohol and water in three mixtures of alcohol and water is 3:2, 4:1, and 7:3. If equal quantities of the mixture are drawn and mixed, the concentration of alcohol in the resulting mixture will be?
(A) 65%
(B) 70%
(C) 75%
(D) 80%
(E) 90%
Rationale: The ratios are given such that the sum of alcohol and water can be brought up to 10 for each mixture. (Since equal quantities are to be added)
For 3:2 lets take 6 parts alcohol and 4 parts water
For 4:1 lets take 8 parts alcohol and 2 parts water
For last since the sum is already 10, 7 parts alcohol and 3 parts water.
Mixing these three will give 6+8+7 =21 units alcohol and 4+2+3=9 units water
or, 21 units alcohol in 30 units of mixture
21/30 *100 = 70%
Answer : B
Answer: (B) 70%
Question: A and B started a business with initial investments in the ratio 8 : 3, after some months B withdrawn his investment, and their share in the annual profits were in the ratio 8 : 7. Then how long B was in the business ?
(A) 6 months
(B) 28 months
(C) 9 months
(D) 5 months
(E) 7 months
Rationale: Let Sumit in the business for ‘a’ months.
Investment Ratio Amit to Sumith = 8 : 3.
Profit sharing ratio = 8 : 7.
Amit is in the business for 12 months.
Then Sumit in the business for
(8 × 12) / (3 × a) = 8 / 7 => 24a = 672 or
a = 672 / 24 = 28 or 28 months
Option B
Answer: (B) 28 months
Question: A deer is standing 50 meters in from the west end of a tunnel. The deer sees a train approaching from the west at a constant speed ten times the speed the deer can run. The deer reacts by running toward the train and clears the exit when the train is 80 meters from the tunnel. If the deer ran in the opposite direction it would barely escape out the eastern entrance just as the train came out of the eastern entrance. How long is the tunnel in meters?
(A) 90
(B) 100
(C) 110
(D) 120
(E) 130
Rationale: Let x be the length of the tunnel.
When the deer runs 50 meters west, the train goes 500 meters to a point 80 meters from west entrance of the tunnel.
When the deer runs east, the deer runs x-50 meters while the train goes x + 500 + 80 meters.
x + 500 + 80 = 10(x-50)
9x = 1080
x = 120 meters
The answer is D.
Answer: (D) 120
Question: If k and t are integers and k^2 – t^2 is an odd integer, which of the following must be an even integer?
I. k + t + 2
II. k^2 + 2kt + t^2
III. k^2 + t^2
(A) None
(B) I only
(C) II only
(D) III only
(E) I, II, and III
Rationale: k^2–t^2 is an odd integer means that either k is even and t is odd or k is odd and t is even.
Check all options:
I. k + t + 2 --> even+odd+even=odd or odd+even+even=odd. Discard;
II. k^2 + 2kt + t^2 --> even+even+odd=odd or odd+even+even=odd. Discard;
III. k^2 + t^2 --> even+odd=odd or odd+even=odd. Discard.
Answer: A.
Answer: (A) None
Question: Find the number that fits somewhere into the middle of the series. Some of the items involve both numbers and letters
Look at this series: D12, H16, __, P24, T28, ... What number should fill the blank?
(A) H16
(B) I17
(C) J18
(D) K19
(E) L20
Rationale: E
L20
In this series, the letters progress by 4, and the numbers increase by 4.
Answer: (E) L20
Question: Laxmi and Prasanna set on a journey. Laxmi moves northwards at a speed of 18 kmph and Prasanna moves southward at a speed of 27 kmph. How far will be Prasanna from Laxmi after 60 minutes ?
(A) 11
(B) 50
(C) 28
(D) 45
(E) 18
Rationale: Explanation:
We know 60 min = 1 hr
Total northward Laxmi's distance = 18kmph x 1hr = 18 km
Total southward Prasanna's distance = 27kmph x 1hr = 27 km
Total distance between Prasanna and Laxmi is = 18 + 27 = 45 km.
Answer: D
Answer: (D) 45
Question: A boat can travel with a speed of 42 km/hr in still water. If the speed of the stream is 10 km/hr, find the time taken by the boat to go 94 km downstream
(A) 1 hour 40 min
(B) 2 hour 40 min
(C) 1 hour 20 min
(D) 1 hour 30 min
(E) 1 hour 50 min
Rationale: Speed of the boat in still water = 42 km/hr
speed of the stream = 10 km/hr
Speed downstream = (42+10) = 52 km/hr
Distance travelled downstream = 94 km
Time taken =distance/speed
=94/52
= 1.81 hours
= 1 hour 50 min.
ANSWER:E
Answer: (E) 1 hour 50 min
Question: The owner of a furniture shop charges his customer 20% more than the cost price. If a customer paid Rs. 8400 for a computer table, then what was the cost price of the computer table?
(A) 7000
(B) 2699
(C) 2670
(D) 6725
(E) 2601
Rationale: CP = SP * (100/(100 + profit%))
= 8400(100/120) = Rs. 7000.
Answer:A
Answer: (A) 7000
Question: A and B enter into partnership with capital as 7:9. At the end of 8 months, A withdraws. If they receive the profits in the ratio of 8:9 find how long B's capital was used?
(A) 5
(B) 1
(C) 8
(D) 7
(E) 4
Rationale: 7 * 8 : 9 * x = 8:9 => x= 7
Answer:D
Answer: (D) 7
Question: Some consecutive natural numbers, starting with 1, are written on the board. Now, one of the numbers was erased and the average of the remaining numbers is 800/39. Find the number which was erased.
(A) 24
(B) 20
(C) 18
(D) 16
(E) 15
Rationale: Explanation:
We know that average of n consecutive numbes average = n×(n+1)/2 /n =(n+1)/2
If the given n is sufficiently large, the average does not change much even though we exclude one or two numbers from it. So the approximate number of observations is almost double to the average (Remember: the average of consecutive numbers almost lies in the middle)
The approximate average is 800/39 = Approx 20. So the initial numbers may be nearer to 40.
In this question it is actually 40 as from the denominator of the new average 800/39. The initial numbers are 40.
Sum of 40 consecutive numbers = 40×(40+1)/2=820
Sum of 39 numbers = average x number of observations = 800/39×39 = 800
So the number excluded = 820 - 800 = 20
Correct Option: B
Answer: (B) 20
Question: What is the least common multiple of 152 and 190?
(A) 304
(B) 14440
(C) 760
(D) 28880
(E) 1520
Rationale: Yes there is a shorter way
152 = 2*2*2*19
190 = 2*5*19
I think everyone knows how to do this.
Then
choose 2*2*2 and choose 5 and choose 19
2*2*2*5*19 = 760 answer is C
Answer: (C) 760
Question: The speed of a boat in still water in 42 km/hr and the rate of current is 6 km/hr. The distance travelled downstream in 44 minutes is:
(A) 86.6 km
(B) 46.6 km
(C) 35.2 km
(D) 35.6 km
(E) 26.6 km
Rationale: Speed downstream = (42 + 6) = 48 kmph
Time = 44 minutes =44/60 hour = 11/15 hour
Distance travelled = Time × speed =11/15×48 = 35.2 km
ANSWER:C
Answer: (C) 35.2 km
Question: The price of a car depreciates in the first year by 25% in the second year by 20% in third year by 15% and so on. The final price of the car after 3 years, if the present cost of the car is Rs. 10,00,000 :
(A) 7,80,000
(B) 1,70,000
(C) 6,90,000
(D) 5,10,000
(E) None of these
Rationale: Solution: Price after third depreciation,
100 ==25%↓ ==> 75 == 20%↓==>60 == 15% ↓ ==> 51.
The price will be,
= Rs. 5, 10, 000.
Alternatively :
1000000*0.75*0.80*0.85 = Rs. 5, 10, 000.
Answer: Option D
Answer: (D) 5,10,000
Question: 42.11 + 356.032 + 42.98 = ?
(A) 441.122
(B) 422.243
(C) 440.183
(D) 622.443
(E) None of these
Rationale: Explanation :
42.11 + 356.032 + 42.98 = 441.122. Answer : Option A
Answer: (A) 441.122
Question: In objective test a correct ans score 4 marks and on a wrong ans 2 marks are ---. a student score 480 marks from 150 question. how many ans were correct?
(A) 120
(B) 130
(C) 110
(D) 150
(E) 180
Rationale: let x be the correct answer and y be the wrong answer
so the total number of questions is (x+y)=150
=>4x-2y=480
=>6x=780
hence x=130
ANSWER:B
Answer: (B) 130
Question: When integer m is divided by 30, the remainder is 5. Which of the following has a remainder of 10 when divided by 15 ?
I. 3m
II. 7m
III. 4m + 10
IV. 6m
V .5m
(A) V Only
(B) I Only
(C) III Only
(D) II Only
(E) IV only
Rationale: Take any value of n which leaves remainder 5 when divided by 15
i.e. Let, n=20 (i.e.15+5)
I. 3n = 3*20 = 60When divided by 30 remainder is NOT10
II. 5n = 5*20 = 100 When divided by 30 remainder is 10
III. 4n + 10 = 4*20 + 10 = 90 When divided by 30 remainder is NOT10
A
Answer: (A) V Only
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 600 grams per kg, what is his percent?
(A) 15%
(B) 25%
(C) 65%
(D) 45%
(E) 66.7%
Rationale: Explanation:
600 --- 400
100 --- ? => 66.7%
Answer: E
Answer: (E) 66.7%
Question: A student scores 55% marks in 8 papers of 100 marks each. He scores 15% of his total marks in English. How much does he score in English?
(A) -2
(B) 6
(C) 7
(D) 6
(E) 18
Rationale: Given student scores 55% marks in english in 8 papers of 100 marks each.
So,his total marks = 55/100 × 800 ⇒ 440
15% of his 440 marks is 440 × (15/100) ⇒ 66
So, he scored 66 marks in english.
Ans is option-2.
Answer:A
Answer: (A) -2
Question: In the first week of last month, Company X realized an average wholesale profit of $7140 per day from the sale of q units of Product Y. Which of the following CANNOT be the difference between Product Y’s sale price and cost per unit?
(A) $3
(B) $4
(C) $7
(D) $13
(E) $51
Rationale: The key operator that everyone seems to have missed is the average. The average profit of $7140 per day is equivalent to a total profit of $49980 for the whole week.
Therefore, the difference between sale price and cost per unit is equal to $49980, which is divisible by all of the answer choices, except for 13.
So, D is the answer.
Answer: (D) $13
Question: Two trains start from same place at same time at right angles to each other. Their speeds are 36km/hr and 48km/hr respectively. After 30 seconds the distance between them will be ?
(A) 270 mts
(B) 190 mts
(C) 100 mts
(D) 500 mts
(E) 110 mts
Rationale: Explanation:
Using pythagarous theorem,
distance travelled by first train = 36x5/18x30 = 300m
distance travelled by second train = 48x5/18x30 = 400m
so distance between them =âˆš( 90000 + 160000) = âˆš250000 = 500mts.
Answer: D
Answer: (D) 500 mts
Question: 261 ÷ ? × 15 + 270 = 405
(A) 24
(B) 25
(C) 36
(D) 39
(E) 43
Rationale: Explanation:
261 ÷ ? × 15 = 405 - 270 = 135
(261 × 15)/? = 135
? = (261 × 15)/135 = 39
Answer: Option D
Answer: (D) 39
Question: Paul sells encyclopedias door-to-door. He earns $150 on every paycheck, regardless of how many sets he sells. In addition, he earns commission as follows:
Commission Sales
10% $0.00 - $10,000.00
5% $10,000.01 --->
He does not earn double commission.That is, if his sales are $12,000, he earns 10% on the first $10,000 and 5% on the remaining $2,000.
His largest paycheck of the year was $1,320. What were his sales for that pay period?
(A) 13,400
(B) 14,800
(C) 16,400
(D) 15,800
(E) 19,600
Rationale: His pay check was $1320.
Out of this, $150 was his fixed salary so the total commission he earned was $1320 - $150 = $1170
He earns 10% on the sales of first $10,000 which gives a commission of $1000.
He earns 5% on every subsequent dollar. Since he earns another $170, he must have had sales of another 170*(100/5) = 3400
So his total sales must have been $10,000 + $3400 = $13,400
A
Answer: (A) 13,400
Question: The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area?
(A) 10000
(B) 18999
(C) 16990
(D) 16007
(E) 16991
Rationale: 100 * 100 = 10000
125 * 80 = 10000
Answer:A
Answer: (A) 10000
Question: A not-so-good clockmaker has four clocks on display in the window. Clock #1 loses 35 minutes every hour. Clock #2 gains 15 minutes every hour relative to Clock #1 (i.e., as Clock #1 moves from 12:00 to 1:00, Clock #2 moves from 12:00 to 1:15). Clock #3 loses 20 minutes every hour relative to Clock #2. Finally, Clock #4 gains 20 minutes every hour relative to Clock #3. If the clockmaker resets all four clocks to the correct time at 12 noon, what time will Clock #4 display after 6 actual hours (when it is actually 6:00 pm that same day)?
(A) 5:00
(B) 5:34
(C) 5:42
(D) 6:00
(E) 6:24
Rationale: C1 loses 15 minutes every hour. So after 60 minutes have passed, C1 displays that 60-15 = 45 minutes have passed.
C2 gains 15 minutes for every 60 minutes displayed on C1. Thus, the time displayed on C2 is 75/60 = 5/4 the time displayed on C1. So after 60 minutes have passed, C2 displays the passing of (5/4 * 45) minutes.
C3 loses 20 minutes for every 60 minutes displayed on C2. Thus, the time displayed on C3 is 40/60 = 2/3 the time displayed on C2. So after 60 minutes have passed, C3 displays the passing of (2/3 * 5/4 * 45) minutes.
C4 gains 20 minutes for every 60 minutes displayed on C3. Thus, the time displayed on C4 is 80/60 = 4/3 the time displayed on clock 3. So after 60 minutes have passed, C4 displays the passing of 4/3 * 2/3 * 5/4 * 45 = 50 minutes.
C4 loses 10 minutes every hour.
In 6 hours, C4 will lose 6*10 = 60 minutes = 1 hour.
Since the correct time after 6 hours will be 6pm, C4 will show a time of 6-1 = 6:24pm.
The correct answer is E.
Answer: (E) 6:24
Question: How many two-digit numbers yield a remainder of 2 when divided by both 7 and 16?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
Rationale: Easier to start with numbers that are of the form 16p+2 ---> 18,34,50,66,82,98.
Out of these no number is also of the form 7q+2. Thus 0 is the answer. A is the correct answer.
Answer: (A) 0
Question: A shopkeeper sold an article offering a discount of 5% and earned a profit of 18.75%. What would have been the percentage of profit earned if no discount was offered?
(A) 60%
(B) 23%
(C) 25%
(D) 56%
(E) 73%
Rationale: Let C.P. be Rs. 100.
Then, S.P. = Rs. 118.75
Let marked price be Rs. x. Then, 95/100 x = 118.75
x = 11875/95 = Rs. 125
Now, S.P. = Rs. 125, C.P. = Rs. 100
Profit % = 25%.
Answer: C
Answer: (C) 25%
Question: An article was sold after a discount of 20% and therewas a gain of 20%. If the profit madeon it was Rs.6 less thanthe discount offered on it, find its SP?
(A) Rs. 22
(B) Rs. 65
(C) Rs. 70
(D) Rs. 72
(E) Rs. 90
Rationale: Let CP = Rs. 100x
SP = Rs. 120x
MP = 120x/80 * 100 = Rs. 150x
D = Rs. 150x - Rs. 120x = Rs. 30x
D - P = 30x - 20x = Rs. 6, 10x = Rs. 6
120x = 120/10 * 6 = Rs. 72
C
Answer: (C) Rs. 70
Question: A thief is noticed by a policeman from a distance of 150 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes ?
(A) 50 meter
(B) 100 meter
(C) 110 meter
(D) 120 meter
(E) 130 meter
Rationale: Explanation:
Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr
Distance covered in 6 minutes =
1/60∗6=1/10=100meters
So distance between them after 6 minutes = 150 - 100
= 50 meters
Option A
Answer: (A) 50 meter
Question: Arun has certain number of books. It is not less than 15 and not more than 30. If he wants to give these books equally to 2 of his friends, then 1 book will remain. If he wants to give these books equally to 3 of his friends, then 2 books will remain. If he wants to give these books equally to 4 of his friends, then 3 books will remain. What is the number of books he had?
(A) 18
(B) 19
(C) 17
(D) 29
(E) 23
Rationale: If he wants to give these books equally to 2 of his friends, then 1 book will remain, it means possible number of books = 15,17,19,21,23,25,27,29
If he wants to give these books equally to 3 of his friends, then 2 books will remain, it means possible number of books = 17,20,23,26,29
If he wants to give these books equally to 4 of his friends, then 3 book will remain, it means possible number of books = 15,19,23,27
common number is only 23 so it will be answer
ANSWER:E
Answer: (E) 23
Question: What is the remainder when 4^381 is divided by 5 ?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
Rationale: I also agree that the remainder is '4' (using the last digit of the powers of 7). Could we have the official answer please?E
Answer: (E) 4
Question: The average of 11 numbers is 10.9. If the average of first six is 10.5 and that of the last six is 11.4 the sixth number is?
(A) 11.9
(B) 11.0
(C) 11.3
(D) 11.5
(E) 11.1
Rationale: 1 to 11 = 11 * 10.9 = 119.9
1 to 6 = 6 * 10.5 = 63
6 to 11 = 6 * 11.4 = 68.4
63 + 68.4 = 131.4 – 119.9 = 11.5
6th number = 11.5.Answer:D
Answer: (D) 11.5
Question: A train running at the speed of 60 km/hr crosses a pole in 12 sec. What is the length of the train?
(A) 120 m
(B) 200 m
(C) 115 m
(D) 110 m
(E) 150 m
Rationale: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 12 = 200 m
Answer: B
Answer: (B) 200 m
Question: An investment gained an interest payment of $250 each month when the annual interest rate was 8%, how much more should we invest annually if we want to gain 12% more per month with a new annual interest rate of 7.5% ?
(A) $9,360
(B) $9,100
(C) $8,250
(D) $7,300
(E) $7,150
Rationale: Answer is D : 7,300
Interest per annum with 8% interest rate is = 250* 12 = Principal * Interest Rate(8/100)
This gives Principal as 37,500$
For an revised interest of 12% more and new interest rate of 7.5% , ie. 250* 12 * 1.12 = Principal * Interest Rate (7.5/100)
This gives the new Principal as 44,800.
The question is how much more should we invest, so 44,800 - 37,500 = 7,300
ANSWER:D
Answer: (D) $7,300
Question: If the compound interest on a certain sum of money for 7 years at 10% per annum be Rs. 993, what would be the simple interest?
(A) Rs. 880
(B) Rs. 890
(C) Rs. 895
(D) Rs. 2100
(E) None
Rationale: Let P = Principal
A - Amount
We have a = P(1 + R/100)3 and CI = A - P
ATQ 993 = P(1 + R/100)3 - P
? P = 3000/-
Now SI @ 10% on 3000/- for 7 yrs = (3000 x 10 x 7)/100
= 2100/-
Answer: D.
Answer: (D) Rs. 2100
Question: What is the difference between the largest number and the least number written with the figures 3, 4, 7, 0, 3?
(A) 98343
(B) 34389
(C) 43983
(D) 43883
(E) 43700
Rationale: 74330 Largest
30347 Smallest
------------
43983
ANSWER C
Answer: (C) 43983
Question: A certain restaurant offers 7 different salads, 5 different main courses, and 6 different desserts. If customers choose one salad, one main course, and two different desserts for their meal, how many different meals are possible?
(A) 125
(B) 275
(C) 525
(D) 600
(E) 1200
Rationale: The number of possible choices for desserts is 6C2 = 15
The number of possible meals is 7*5*15 = 525
The answer is C.
Answer: (C) 525
Question: Because of the economic slowdown, a multinational company curtailed some of the allowances of its employees. John, the marketing manager of the company whose monthly salary has been reduced to Rs.42,000 is unable to cut more on his expenditure. He finds that there is a deficit of Rs.2,000 between his earning and expenses in the first month. This deficit, because of inflationary pressure, will keep on increasing by Rs.500 everymonth. John has a saving of Rs 60,000 which will be used to fill the deficit. After his savings get exhausted, John would start borrowing from his friends. How soon will he start borrowing?
(A) 9th months
(B) 10th months
(C) 11th months
(D) 12th months
(E) 13th months
Rationale: Let the Rashid 's savings will last till 'nn' months.
⇒n2[2×2000+(n−1)500]=60,000⇒n2[2×2000+(n−1)500]=60,000
[Expenditure every month increases by 500 rupees]
⇒n2+7n−200=0⇒n2+7n−200=0
n=12.38n=12.38
⇒ Rashid after Kartik's mother asked him to get the vegetables, milk and butter from the market and gave him the money in the denominator of 1 Rupee, 2 Rupee and 5 Rupee coins.
Kartik first goes to the grocery shop to buy vegetables. At the grocery shop he gives half of his 5 Rupee coins in return receives the same number of 1 Rupee coins.
Next he goes to the dairy shop to buy milk and butter and gives all 2 Rupee coins and in return get thirty 5 Rupee coins, which increase the number of five rupee coins by 75% more than the original number.
If the number of 1 rupee coins now is 50, the number of 1 rupee and 5 rupee coins originally were will start borrowing money from his friends.
E
Answer: (E) 13th months
Question: The probability that a man will be alive for 10more yrs is 1/4 & the probability that his wife will alive for 10 more yrs is 1/3. The probability that none of them will be alive for 10 more yrs, is
(A) 1/2
(B) 1
(C) 2/3
(D) 3/4
(E) 2
Rationale: Sol. Required probability = Pg.) x P(B) = (1— D x(1 —I) =: x 1=1/2
Ans.(A)
Answer: (A) 1/2
Question: If w < y < -1, which of the following is true?
(A) w/y > wy
(B) y/w > w+y
(C) y/w > wy
(D) y/w < w+y
(E) y/w > w/y
Rationale: Consider :
w= -3
y= -2
then put for every option. U'll get ans B.
Answer: (B) y/w > w+y
Question: A rope of which a calf is tied is increased from 16 m to 23 m, how much additional grassy ground shall it graze?
(A) 1217
(B) 1219
(C) 1210
(D) 1212
(E) 858
Rationale: π (232 – 162) = 858
Answer:E
Answer: (E) 858
Question: How many numbers from 19 to 79 are exactly divisible by 11?
(A) 5
(B) 6
(C) 9
(D) 11
(E) 12
Rationale: 19/11 = 1 and 79/11 = 7 ==> 7 - 1 = 6 Numbers
Answer : B
Answer: (B) 6
Question: Miller Street begins at Baker Street and runs directly east for 4.5 kilometers until it ends when it meets Turner Street. Miller Street is intersected every 250 meters by a perpendicular street, and each of those streets other than Baker Street and Turner Street is given a number beginning at 1st Street (one block east of Baker Street) and continuing consecutively (2nd Street, 3rd Street, etc...) until the highest-numbered street one block west of Turner Street. What is the highest-numbered street that intersects Miller Street?
(A) 15th
(B) 16th
(C) 17th
(D) 18th
(E) 19th
Rationale: 4.5 km / 250 m = 18.
However, the street at the 4.5-km mark is not 18th Street; it is Turner Street.
Therefore, the highest numbered street is 17th Street.
The answer is C.
Answer: (C) 17th
Question: Faiza has 9 purses, she gives 3 purse as gift. Now how many purse did she have?
(A) 2
(B) 6
(C) 11
(D) 9
(E) 4
Rationale: 9-3=6. Answer is B
Answer: (B) 6
Question: A lawyer's representation costs $150 for the first hour and $125 for each additional hour. What is the total cost, in dollars, of her representation for m hours, where m is an integer greater than 1?
(A) 150 + 125 m
(B) 150 + 125( m – 1)
(C) 125 + 150 m
(D) 125 + 150( m – 1)
(E) 275( m – 1)
Rationale: For the first hour the cost is 150.
As first hour is already calculated the remaining is m-1 and corresponding cost is 125.
Therefore answer is 150+125(m-1).
Answer B
Answer: (B) 150 + 125( m – 1)
Question: One year ago the ratio between Samir and Ashok’s age was 4:3. One year hence the ratio of their ages will be 5 :4. What is the sum of their present ages in years?
(A) 12 years
(B) 15 years
(C) 16 years
(D) Cannot be determined
(E) none of these
Rationale: Let their ages one year ago be 4x and 3x years.
(4x + 2)/(3x + 2) = 5/4
=>4(4x + 2) = 5(3x + 2)
=> x = 2
Sum of their present ages
= (4x + 1 + 3x + 1)
=(7x + 2) = 16 years
ANSWER:C
Answer: (C) 16 years