mathewhe/aqua_rat huggingface dataset:
Question: How many pieces of 75 cm can be cut from a rope 52.5 meters long?
(A) 30
(B) 40
(C) 60
(D) None
(E) Cannot be determined
Rationale: Explanation :
Total pieces of 75 cm that can be cut from a rope of 52.5 meters long is
= (52.5 meters)/(75 cm)
= (52.5 meters)/(0.75 meters)
= 70
Answer : D
Answer: (D) None
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 6 boys when No boy gets more than one prize?
(A) 112
(B) 114
(C) 117
(D) 120
(E) 127
Rationale: Sol. In this case, repetitions are not allowed. So, the first prize can be given in 6 ways. The second in 5 ways and the third in 4 ways. But fundamental principle, (6 x 5 x 4) ways = 120 ways
D
Answer: (D) 120
Question: An investment receives 20% annual interest compounded semi-annually for 2 years. If its final value is $29,200, approximately what was the initial investment?
(A) $ 17,000
(B) $ 18,000
(C) $ 19,000
(D) $ 20,000
(E) $ 21,000
Rationale: At the same time the key concept to keep in mind is that interest compound annually, semestral and so on are simply % increase or decrease, one after another.
Similarly, we have 100 and we have a discount of 20% and then 10 % . We have , of course, 80 and after this 10% of 80.
Here is the same.
here we have 20% 2 times per year so: 10% or 1.1 for two years. 1.141.14or 1.1 four times.
if we have the original amount X and the final amount 29,200. We need only to divide 29,200/1.1the result again 1.1 for four times.the result is 19943 We have approximately.
D is the answer.
Answer: (D) $ 20,000
Question: One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill tank in 36 min, then the slower pipe alone will be able to fill the tank in?
(A) 766 min
(B) 656 min
(C) 144 min
(D) 877 min
(E) 555 min
Rationale: Let the slower pipe alone fill the tank in x min.
Then, faster pipe will fill it in x/3 min.
1/x + 3/x = 1/36
4/x = 1/36 => x = 144 min.Answer:C
Answer: (C) 144 min
Question: Three candidates contested an election and received 1136, 7636 and 21628 votes respectively. What percentage of the total votes did the winning candidate got
(A) 55%
(B) 56%
(C) 57%
(D) 71.1%
(E) 59%
Rationale: Explanation:
Total number of votes polled = (1136 + 7636 + 21628) = 30400
So, Required percentage = 21628/30400 * 100 = 71.1%
Answer: Option D
Answer: (D) 71.1%
Question: In how many ways can 10 books be arranged on a shelf such that a particular pair of books should always be together?
(A) 9!
(B) 2!
(C) 3! * 2!
(D) 9! * 2!
(E) 9! * 5!
Rationale: We have a total of 10 books.
Given that a particular pair of books should always be together. Hence, just tie these two books together and consider as a single book.
Hence we can take total number of books as 9. These 9 books can be arranged in 9P9 =9!=9! ways.
We had tied two books together. These books can be arranged among themselves in 2P2 =2!=2! ways.
Hence, required number of ways
=9!×2!
ANSWER D 9! * 2!
Answer: (D) 9! * 2!
Question: A retailer bought a machine at a wholesale price of $90 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price t of the machine?
(A) 	81
(B) 	100
(C) 	120
(D) 	135
(E) 	160
Rationale: Since the wholesale price was $90 and the profit was 20% of the wholesale price ([.2][90] = $18), the retail price would have to be above $108, but not that much greater than that.
Let's start by TESTing Answer C: $120....
If.....
Retail Price t= $120
10% discount off = $120 - (.1)(120) = 120 - 12 = 108
20% profit on wholesale price = 90 + (.2)(90) = 90 + 18 = 108
These two numbers MATCH, so this MUST be the answer!
Final Answer:
[Reveal]Spoiler:
C
Answer: (C) 	120
Question: P and Q be centers of two circle having radius 200cms. These circle intersect each other at some point A and B. Length of PQ is 250 cms. What will the angle AQP be?
(A) between 0 to 45
(B) between 0 to 30
(C) between 0 to 60
(D) between 0 to 75
(E) between 0 to 100
Rationale: since if we draw the figure, then AP= 200 , AQ=200 and PQ=250
triangle property of 45- 45 - 90 is that H=L * root(2)
H= hypo and L= Leg.therefore H/L= root(2)
here H=250 and L=200 and H/L= 250/200= 1.25
and the value of root(2)== 1.44
so H/L= approx root(2).
Therefore the angle between H and L = near about 44 degree
so the ans will be 0 to 45.
ANSWER:A
Answer: (A) between 0 to 45
Question: a survey of n people in the town of badaville found that 50% of them prefer brand A.another survey of 100 people in the town of Chotaville found that 60% prefer brand A.In total 55% of all the people surveyed prefer brand A.What is the total number of people surveyed?
(A) 100
(B) 200
(C) 300
(D) 400
(E) 500
Rationale: .5*n+.6*100=.55*(n+100)
n=100
total people surveyed=n+100
=100+100
=200
ANSWER:B
Answer: (B) 200
Question: The average age of 36 students in a group is 14 years. When teacher’s age is included to it, the average increases by one. What is the teacher’s age in years?
(A) 31
(B) 36
(C) 41
(D) 51
(E) None
Rationale: Sol.
Age of the teacher = ( 37 × 15 – 36 × 14 ) years = 51 years.
Answer D
Answer: (D) 51
Question: The average age 18 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
(A) 18
(B) 99
(C) 77
(D) 26
(E) 36
Rationale: 18 * 2 = 36 years
Answer: E
Answer: (E) 36
Question: Of the three-digit integers greater than 600, how many have two digits that are equal to each other and the remaining digit different from the other two?
(A)  90
(B)  82
(C)  80
(D)  107
(E)  36
Rationale: Three digit number can have only following 3 patterns:
A. all digits are distinct;
B. two digits are alike and third is different;
C. all three digits are alike.
We need to calculate B. B=Total - A - C
Total numbers from 600 to 999 = 399 (3-digit numbers greater than 600);
A. all digits are distinct = *4*9*8=288 (first digit can have only three values 7, 8, or 9
C. all three are alike =4 (666,777, 888, 999).
So, 399-288-4=107
Answer: D
Answer: (D)  107
Question: A group of n students can be divided into equal groups of 4 with 3 student left over or equal groups of 5 with 3 students left over. What is the sum of the two smallest possible values of n?
(A) 66
(B) 46
(C) 49
(D) 53
(E) 86
Rationale: 4x+3 = 5y+3...........ie: 4x-5y = 0
x,y must be >1 and y is even ie ( 2,4,6,..etc)
if y = 2 thus x = fraction (not possible)
if y = 4 thus x =5 n =23
if y = 6 thus x = not possible fraction
if y =8 thus x = 10 n =43
23+43 = 66.....
A
Answer: (A) 66
Question: A and B start a business with Rs.1500 and Rs.3000 respectively. Hoe should they share their profits at the end of one year?
(A) 3:5
(B) 3:4
(C) 3:1
(D) 1:2
(E) 3:9
Rationale: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
1500 : 3000 => 1:2
Answer:D
Answer: (D) 1:2
Question: A trader sells goods to a customer at a profit of k% over the cost price, besides it he cheats his customer by giving 880 g only instead of 1 kg. Thus his overall profit percentage is 255. Find the value of k?
(A) 8.33%
(B) 8.25%
(C) 10%
(D) 12.5%
(E) None
Rationale: Solution: % Profit = 25 /100 = (120 +k)/ 880
→ k = 100
Thus,
Net % profit = (100 *100) /1000 = 10%.
Answer: Option C
Answer: (C) 10%
Question: Three numbers are in the ratio 3:5:7. The largest number value is 42. Find difference between Smallest & largest number is?
(A) 20
(B) 24
(C) 26
(D) 28
(E) 30
Rationale: == 3:5:7
Total parts = 15
= The largest number value is 42
= The largest number is = 7
= Then 7 parts -----> 42 ( 7 * 6 = 42 )
= smallest number = 3 & Largest number = 7
= Difference between smallest number & largest number is = 7 - 3 = 4
= Then 4 parts -----> 24 (4 * 6 = 24)
B
Answer: (B) 24
Question: A train running at the speed of 56 km/hr crosses a pole in 9 seconds. Find the length of the train?
(A) 140
(B) 272
(C) 278
(D) 277
(E) 112
Rationale: Speed = 56*(5/18) m/sec = 140/9 m/sec
Length of Train (Distance) = Speed * Time
(140/9) * 9
= 140 meter
Answer: A
Answer: (A) 140
Question: A train which is 150m. long passes a platform of 200 m in 15 sec. What is the speed of the train?
(A) 36 km/hr
(B) 64 km/hr
(C) 84 km/hr
(D) 91 km/hr
(E) 95 km/hr
Rationale: total distance cover by train in 15sec=150+200m
speed=distance/time
speed=350/15(m/s)
speed in km/hr=350/15*18/5=84km/hr
ANSWER:C
Answer: (C) 84 km/hr
Question: A certain lab experiments with white and brown mice only. In one experiment, 2/3 of the mice are white. If there are 15 brown mice in the experiment, how many mice in total are in the experiment?
(A) 45
(B) 33
(C) 26
(D) 21
(E) 10
Rationale: Let total number of mice = M
Number of white mice = 2/3 M
Number of brown mice = 1/3 M = 15
=> M = 45
Answer A
Answer: (A) 45
Question: If you divide 7^777 by 5, which remainder do you get?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
Rationale: The units digit of 7^1 is 7.
The units digit of 7^2 is 9.
The units digit of 7^3 is 3.
The units digit of 7^4 is 1.
The units digit of 7^5 is 7.
etc...
The units digit of 7^n repeats in blocks of 4: {7, 9, 3, 1}
The remainder of 777/4 is 1.
So the units digit of 7^777 is 7.
The remainder of 7^777 / 5 is 2.
The answer is C.
Answer: (C) 2
Question: If y exceeds x by 10%, then x is less than y by?
(A) 16 2/9%
(B) 16 3/3%
(C) 16 2/3%
(D) 12 2/3%
(E) 9 1/11%
Rationale: X=100	y=110
110------10
100-------? => 9 1/11%
Answer:E
Answer: (E) 9 1/11%
Question: A, B, C together started a business. A invested Rs.6000 for 5 months B invested Rs.3600 for 6 months and C Rs.7500 for 3 months. If they get a total profit of Rs.7410. Find the share of A?
(A) 2399
(B) 2889
(C) 2830
(D) 2878
(E) 3000
Rationale: Explanation:
60*5:36*6:75*3
100: 72: 75
100/247 * 7410 = 3000
Answer: E
Answer: (E) 3000
Question: A gardener increased the length of a rectangle-shaped garden by 20 percent and decreased its width by 5 percent. The area of the new garden
(A) has increased by 18 percent
(B) has increased by 14 percent
(C) has increased by 7 percent
(D) is exactly the same as the old area
(E) cannot be expressed in percentage terms without actual numbers
Rationale: Let L be the original length and let W be the original width.
The original area was L*W.
The new area is 0.95W*1.2L = (0.95)(1.2)L*W = 1.14*L*W
The answer is B.
Answer: (B) has increased by 14 percent
Question: Walking across campus, a student interviewed a group of students. 25% of the students took a finance class last semester, 52% took a marketing class last semester, and 40% took neither a finance nor a marketing class last semester. What percent of the students in the group took both a finance and a marketing class?
(A) 60%
(B) 50%
(C) 25%
(D) 17%
(E) 10%
Rationale: {Total} = {finance} + {marketing} - {both} + {neither}
100 = 25 + 52 - {both} + 40
{both} = 17%.
Answer: D.
Answer: (D) 17%
Question: In a business, A and C invested amounts in the ratio 2 : 1 , whereas the ratio between amounts invested by A and B was 3 : 2 . If Rs 157300 was their profit, how much amount did B receive?
(A) 48000
(B) 48200
(C) 48400
(D) 48600
(E) None of these
Rationale: Explanation :
Assume that investment of C = x
Then, investment of A =2x
Investment of B = 4x/3
A:B:C = 2x : 4x/3 : x = 2 : 4/3 : 1 =6 : 4 : 3
B's share = 157300 * 4/(6+4+3) = 157300*4/13
= 12100*4 = 48400. Answer : Option C
Answer: (C) 48400
Question: At what time between 2 and 3 o'clock will the hands of a clock be together?
(A) 120/28
(B) 120/22
(C) 120/19
(D) 120/11
(E) 120/112
Rationale: The hands of a clock would be together when the angle between The hour hand and minute hand is Zero. Now apply the formula: θ=∣∣∣30h−112m∣∣∣θ=|30h−112m|
Here θθ = 0
⇒11/2m – 30h = 0
⇒11/2m – 30×2 = 0
⇒ m = 120/11
Answer : D
Answer: (D) 120/11
Question: The purchase price of an article is $48. In order to include 15% of cost for overhead and to provide $12 of net profit, the markup should be
(A) 15%
(B) 25%
(C) 35%
(D) 40%
(E) 45%
Rationale: Cost price of article = 48$
% of overhead cost = 15
Net profit = 12 $
We need to calculate % markup
Net profit as % of cost price = (12/48)*100 = 25%
Total markup should be = 25 + 15 = 40%
Answer D
Answer: (D) 40%
Question: (422+404)^2−(4×422×404)=?
(A) 324
(B) 342
(C) 343
(D) 348
(E) 322
Rationale: Explanation :
(a+b)^2−4ab=(a^2+2ab+b^2)−4ab=(a^2−2ab+b^2)=(a−b)^2
Given Equation is in the form (a+b)^2−4ab where a = 422 and b = 404
Hence answer = (a+b)^2−4ab=(a−b)62=(422−404)^2=18^2=324
Answer is A
Answer: (A) 324
Question: Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm.
(A) 200
(B) 234
(C) 285
(D) 345
(E) 244
Rationale: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them) = 1/2 (20 + 18) * (15) = 285 cm2
Answer: Option C
Answer: (C) 285
Question: If a and b are the roots of the equation x2 - 9x + 20 = 0, find the value of a2 + b2 + ab?
(A) 57
(B) 59
(C) 61
(D) 63
(E) 65
Rationale: a2 + b2 + ab = a2 + b2 + 2ab - ab
i.e., (a + b)2 - ab
from x2 - 9x + 20 = 0, we have
a + b = 9 and ab = 20. Hence the value of required expression (9)2 - 20 = 61.
Option C
Answer: (C) 61
Question: there are 10 girls and 20 boys in a classroom. what is the ratio of girls to boys?
(A) 1/2
(B) 1/3
(C) 1/5
(D) 10/30
(E) 2/5
Rationale: If girls is 10 and boys is 20, then 10/20.
so ratio of girls to boys is = 10/20 = 1/2
ANSWER:A
Answer: (A) 1/2
Question: Rahul is 30 years older than his daughter Mary. In 20 years Rahul will be twice as old as Mary. What is Mary current age.
(A) 12
(B) 14
(C) 10
(D) 16
(E) 18
Rationale: Now: Mary = x, Rahul =x+30
In 20 years Mary = x+20, Rahul= x+30+20 or 2(x+20)
x+30+20= 2(x+20)
x+50=2x+40
50-40=2x-x
x= 10
Mary is 10 years old
Answer : C
Answer: (C) 10
Question: In how many T ways can 4 white and 3 black chess pieces be arranged in a row such that they occupy alternate places? Assume that the pieces are distinct.
(A) T=288
(B) T=144
(C) T=12
(D) 48
(E) 96
Rationale: 4 white chess pieces can be arranged in 4! ways and 4 black pieces can be arranged in 3 ! ways.
W_W_W_W
Number of ways = 4!*3! = 24 * 6 = 144
Answer B
Answer: (B) T=144
Question: The first term in a sequence is 1 and the second term is 21. From the third term on each term is the average (arithmetic mean) of all preceding terms. What is the 38th term in the sequence?
(A) 8
(B) 11
(C) 21
(D) 38
(E) 49
Rationale: The third term is 11 since this is the average of 1 and 21.
Then the next terms will all be 11 since the average stays at 11.
The answer is B.
Answer: (B) 11
Question: A reduction of 20% in the price of salt enables a lady to obtain 10kgs more for Rs.100, find the original price per kg?
(A) 3.7
(B) 2.8
(C) 2.5
(D) 4.7
(E) 2.7
Rationale: C
100*(20/100) = 20 --- 10
? --- 1 => Rs.2
100 --- 80
? --- 2 => Rs.2.5
Answer: (C) 2.5
Question: During 2001, a stock lost 40 percent of its value. During the following year, the stock's value increased by 200 percent. Which of the following is the percent change in the stock's value during those two years?
(A) 60 percent decrease
(B) 40 percent decrease
(C) 20 percent increase
(D) 80 percent increase
(E) 140 percent increase
Rationale: Let the value of the stock in 2000 be 100, then in 2001 its value would be 100*(1-40/100)=100*0.6=60 and in 2002 its value would be 60*(1+200/100)=180. Hence during those two years the value of the stock increased from 100 to 180, so by 80%.
Answer: D.
Answer: (D) 80 percent increase
Question: 2, 6, 14, 26, 42, ?
(A) 62
(B) 56
(C) 74
(D) 57
(E) 32
Rationale: The pattern is + 4, + 8, + 12, + 16, +20
Answer : A.
Answer: (A) 62
Question: The average of five integers is 63, and none of these integers is greater than 100. If the average of three of the integers is 65, what is the least possible value of one of the other two integers?
(A) 5
(B) 15
(C) 20
(D) 21
(E) 30
Rationale: The sum of two other integers = 63*5-65*3 = 120
the least possible value of one integer when the other integer has the highest value of 100 =120 - 100 = 20
ANSWER:C
Answer: (C) 20
Question: According to the direction on a can of frozen orange juice concentrate is to be mixed with 3 cans of water to make orange juice . How many 6 - ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?
(A) 25
(B) 34
(C) 50
(D) 67
(E) 50
Rationale: Orange juice concentrate: water::1:3
total quantity of orange juice = 200*6 = 1200 oz
so Orange juice concentrate: water :: 300 oz:900 oz
no. of 6 oz can = 300 oz/6 oz = 50
Answer E, 50 cans
Answer: (E) 50
Question: There are n members in a certain department, including Michael. Two representatives are to be selected to attend a company conference. If there are 36 possible combinations in which Michael is not selected, what is the value of n?
(A) 8
(B) 9
(C) 10
(D) 11
(E) 12
Rationale: The combinations of two people, in which Michael was not selected = 36
The number of ways two people can be selected from m people = m*(m-1)/2
Let m be the number of people excluding Michael.
Then m*(m-1) = 72 = 9*8
Thus, n = m + 1(Michael) = 10
The answer is C.
Answer: (C) 10
Question: A rectangular lawn of dimensions 80 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?
(A) Rs.3600
(B) Rs.3700
(C) Rs.3800
(D) Rs.3900
(E) Rs.4000
Rationale: Area = (l + b – d) d
(80 + 60 – 10)10 => 1300 m2
1300 * 3 = Rs.3900
ANSWER:D
Answer: (D) Rs.3900
Question: A book was sold for Rs 27.50 with a profit of 10%. if it were sold for Rs25.75, then what would be % of profit or loss?
(A) Profit 5%
(B) Loss 5%
(C) Profit 3%
(D) Loss 3%
(E) Profit 4%
Rationale: SP=Rs 27.50: profit =10%.
CP=Rs {(100/110)*27.50}=Rs 25.
When sp =Rs 25.75 ,profit =Rs(25.75-25)=Rs 0.75
Profit%={(0.75/25)*100}%=25/6%=3%
Answer is C.
Answer: (C) Profit 3%
Question: A thief steels a car at 6a.m. and drives it at 50kmph. The theft is discovered at 7a.m. and the owner sets off in another car at 70 kmph. When will he overtake the thief?
(A) 9a.m.
(B) 9.30a.m.
(C) 10a.m.
(D) 11.45a.m.
(E) 10.15a.m.
Rationale: Suppose the thief overtakes x hours after 6a.m.
Distance covered by the thief in x hrs = distance covered by the owner in (x-1 hours)
50x = 70(x-1)
20x = 70
x = 7/2 hrs
Thief is overtaken at 9.30a.m.
Answer is B
Answer: (B) 9.30a.m.
Question: Six persons A,B,C,D,E &F went to soldier cinema. There are six consecutive seats. A sits in the first seat followed by B, followed by C and so on. If A taken on of the six seats, then B should sit adjacent to A. C should sit adjacent to A or B. D should sit adjacent to A, B or C and so on. How many possibilities are there ?
(A) 30
(B) 32
(C) 34
(D) 36
(E) 38
Rationale: First we have to arrange A, there is 1 method for it, for second person B, there are 2 methods one left and one right, for third 2 methods are there same as for B similarly for others, so total number of methods = 1*2*2*2*2*2 = 32
ANSWER:B
Answer: (B) 32
Question: a man owns 2/3 of market reserch beauro buzness,and sells 3/4 of his shares for 30000rs,what is the value of buzness?
(A) 75000
(B) 160000
(C) 170000
(D) 60000
(E) 70000
Rationale: If value of business=x
Total sell (2x/3)(3/4)=30000
->x=60000
ANSWER:D
Answer: (D) 60000
Question: In what time will a train 100 m long cross an electric pole, it its speed be 162 km/hr?
(A) 2.5
(B) 2.9
(C) 2.4
(D) 2.8
(E) 2.22
Rationale: Speed = 162 * 5/18 = 45 m/sec
Time taken = 100/45
= 2.22 sec.
Answer:E
Answer: (E) 2.22
Question: A basket has 5 oranges and 4 oranges. Three fruits are picked at random. The probability that at least 2 oranges are picked is
(A) 23/41
(B) 1/23
(C) 25/42
(D) 34/57
(E) 3/41
Rationale: Total fruits = 9
Since there must be at least two oranges,
(⁵C₂ * ⁴C₁)/⁹C₃ + ⁵C₃/⁹C₃ = 25/42
C
Answer: (C) 25/42
Question: The volumes of two cones are in the ratio 1 : 40 and the radii of the cones are in the ratio of 1 : 2. What is the length of the wire?
(A) 8:5
(B) 8:9
(C) 2:2
(D) 8:2
(E) 2:8
Rationale: The volume of the cone = (1/3)πr2h
Only radius (r) and height (h) are varying.
Hence, (1/3)π may be ignored.
V1/V2 = r1^2 . h1/r2^2. h2 => 1/40
= (1)^2h1/(2)^2h2
=> h1/h2 = 8/5
i.e. h1 : h2 = 8:5
Answer: A
Answer: (A) 8:5
Question: 1, 2, 3, 10, ?, 9802
(A) 99
(B) 8
(C) 73
(D) 28
(E) 27
Rationale: Answer: A) 99
Answer: (A) 99
Question: A shopkeeper sells 300 metres of cloth for Rs. 9000 at a loss of Rs.6 per metre. Find his cost price for one metre of cloth?
(A) s.59
(B) s.58
(C) s.36
(D) s.46
(E) s.13
Rationale: SP per metre = 9000/300
= Rs. 30 Loss per metre
= Rs. 6 CP per metre = 30 + 6
= Rs.36
Answer: C
Answer: (C) s.36
Question: Andrew travelling to 7 cities. Gasoline prices varied from city to city.
$1.75, $1.61, $1.79, $2.11, $1.96, $2.09, $1.83. What is the median gasoline price?
(A) $1
(B) $1.83
(C) $1.92
(D) $2.13
(E) $2.15
Rationale: Ordering the data from least to greatest, we get:
$1.61, $1.75, $1.79, $1.83, $1.96, $2.09, $2.11
The median gasoline price is $1.83. (There were 3 states with higher gasoline prices and 3 with lower prices.)
B
Answer: (B) $1.83
Question: Anu can do a work in 6 days and Binu alone in 9 days. Anu and Binu undertook to do it for Rs.4800. With help of Minu, they completed the work in 3 days. How much is to be paid to Minu and Anu?
(A) s.750, Rs.2250
(B) s.2000, Rs.750
(C) s.750, Rs.2000
(D) s.800, Rs.2400
(E) s.900, Rs.1250
Rationale: Minuâ€™s one dayâ€™s work = 1/3 - 1/6 + 1/9= 1/3 - 5/18 = 1/18
Anuâ€™s wages: Binuâ€™s wages: Minuâ€™s wages = 1/6 : 1/9 : 1/18 = 6: 4: 2
Minuâ€™s share = Rs.4800* 2/12 = Rs.800
Anuâ€™s share = Rs.4800* 6 /12 = Rs.2400
ANSWER:D
Answer: (D) s.800, Rs.2400
Question: A bowl was filled with 10 ounces of water, and 0.007 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period?
(A) 0.004%
(B) 0.04%
(C) 0.40%
(D) 4%
(E) 3.5%
Rationale: Total amount of water evaporated each day during a 50-day period = .007 * 50
=.007 * 100/2
= .7/2
= .35
percent of the original amount of water evaporated during this period = (.35/10) * 100%
= 3.5 %
Answer E
Answer: (E) 3.5%
Question: xa=yb=zc and y2=xz. Find b.
(A) 2ac/a+c
(B) 7ac/a+c
(C) 1ac/a+c
(D) 6ac/a+c
(E) 3ac/a+c
Rationale: ANSWER : A
Answer: (A) 2ac/a+c
Question: If (y - 1)(z + 1) + 4(z - 3) = 0, then which of the following must be true?
(A)  y = -4 and z = -3
(B)  y = 4 or z = -3
(C)  y = -4 or z = 3
(D)  y = 1 and z = 3
(E)  y = 1 or z = - 3
Rationale: yz + y - 2z - 1 + 4z - 12 = 0
yz + y + 3z - 13 = 0
yz + y + 3z = 13
So by checking options we get ,
D.
Answer: (D)  y = 1 and z = 3
Question: A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 6x km.
(A) 16
(B) 48
(C) 24
(D) 19
(E) 12
Rationale: Total time taken = x/40 + 2x/20 hours
= 5x/40 = x/8 hours
Average speed = 6x/(x/8) = 48 kmph
Answer: B
Answer: (B) 48
Question: The sum of a number and the number preceding it is 33. By how much is two less than six times the
number?
(A) 196
(B) 94
(C) 90
(D) 100
(E) 120
Rationale: two numbers must be 16 and 17
16+17=33
required number is 17
six times of this number= 6*17=102
two less than 102= 102-2= 100
ANSWER:D
Answer: (D) 100
Question: A seller has 1000 kg of rice part of which he sells at 8% profit and the rest at 18% profit. He gains 14%. The quantity sold at 18% profit is?
(A) 300 kg
(B) 350 kg
(C) 550 kg
(D) 600 kg
(E) 700 kg
Rationale: By rule of alligation,
Profit% by selling 1st part Profit% by selling 2nd part
8 18
Net % profit
14
18-14=4 14-8=6
=> Quantity of part1 : Quantity of part2 = 4 : 6 = 2 : 3
Total quantity is given as 1000 kg. So quantity of part2 (quantity sold at 18% profit)
=1000×35
= 600 kg
D
Answer: (D) 600 kg
Question: An equity analyst needs to select 3 stocks for the upcoming year and rank these securities in terms of their investment potential. If the analyst has narrowed down the list of potential stocks to 7, in how many ways can she choose and rank her top 3 picks?
(A) 21
(B) 35
(C) 210
(D) 420
(E) 840
Rationale: Number of ways of choosing 3 stocks = 7C3
Number of ways of ranking the chosen stocks = 3!
Hence total ways of choosing and ranking = 7C3 * 3! = 7!/4! = 7*6*5 = 210
Correct Option: C
Answer: (C) 210