mathewhe/aqua_rat huggingface dataset:
Question: At a certain organisation, the number of male members went up by 12% in the year 2001 from year 2000, and the number of females members went down by 4% in the same time period. If the total membership at the organisation went up by 1.2% from the year 2000 to 2001, what was the ratio of male members to female members in the year 2000?
(A) 1:2
(B) 1:3
(C) 2:3
(D) 3:2
(E) 2:1
Rationale: men increase by 12% ==> 1.12M = males in 2001
women decrease by 4% ==> 0.96F = women in 2001
total employees increase by 1.2% ==> 1.012*(M + F) = total number of employees in 2001
Obviously
(males in 2001) + (females in 2001) = total number of employees in 2001
1.12M + 0.96F = 1.012*(M + F)
1.12M + 0.96F = 1.012M + 1.012F
1.12M - 1.012M = 1.012F - 0.96F
0.108M = 0.052F
M/F = (0.052)/(0.108) = 52/108 = 1/2
Answer =(A)
Answer: (A) 1:2
Question: Joe is painting a rectangular room whose dimensions are given by a, b and c meters. Joe takes 8 hours to paint a wall with dimensions a and c. He takes 4 hours to paint a wall with dimensions b and c and 12 hours to paint the ceiling with dimensions a and b. If Joe works at a constant rate and a = 7, then what is the volume of the room?
(A) 18 cubic meters
(B) 24 cubic meters
(C) 30 cubic meters
(D) 36 cubic meters
(E) 57.1 cubic meters
Rationale: Time to paint each wall as given in problem:
AC = 8 hours
BC = 4 hours
AB = 12 hours
Since he works at constant rate and it takes him twice as long to paint AC compared to BC
AC=2BC
Plug in 6 for A and you find that B=3.5
Since painting AB takes 3 times as long compared to BC,
AB=3BC
Plug in 6 for A and 3 for B and you find that C=2.33
A*B*C=7*3.5*2.3=57.1 cubic meters
Answer: E
Answer: (E) 57.1 cubic meters
Question: A garden center sells a certain grass seed in 5-pound bags at $13.85 per bag, 10-pound bags at $20.43 per bag, and 25-pound bags $32.20 per bag. If a customer is to buy at least	65 pounds of the grass seed,	but no more than 80 pounds,	what is the least possible cost of the grass seed that the customer will buy?
(A) $94.03
(B) $96.75
(C) $98.68
(D) $102.07
(E) $105.3
Rationale: there can be 2 cases
1)25+25+10+5=$98.68 or
2)25+25+25=$96.60
C
Answer: (C) $98.68
Question: The length of a rectangle is reduced by 22%. By what % would the width have to be increased to maintain the original area?
(A) 14%
(B) 15%
(C) 28%
(D) 30%
(E) 35%
Rationale: Sol. Required change = (22*100)/(100-22)=28.2%
C
Answer: (C) 28%
Question: A flagpole 18 meters high casts a shadow of length 45 meters. If a building under similar conditions casts a shadow of length 70 meters, what is the height of the building (in meters)?
(A) 20
(B) 24
(C) 28
(D) 32
(E) 36
Rationale: The height:length ratio will be equal in both cases.
18 / 45 = x / 70
x = 28
The answer is C.
Answer: (C) 28
Question: A 160 meter long train crosses a man standing on the platform in 4 sec. What is the speed of the train?
(A) 176 kmph
(B) 144 kmph
(C) 176 kmph
(D) 134 kmph
(E) 161 kmph
Rationale: S = 160/4 * 18/5
= 144 kmph
Answer: B
Answer: (B) 144 kmph
Question: The price of the jewel, passing through three hands, rises on the whole by 68%. If the first and the second sellers 20% and 25% profit respectively find the percentage profit earned by the third seller.
(A) 20
(B) 12
(C) 15
(D) 25
(E) 30
Rationale: Let the original price of the jewel be $ p and let the profit earned by the third seller be x% Then, (100+x)% of 125% of 120% of P =168% Of P ((100+X)/100*125/100*120/100*P)=(168/100*P)
==> (100+X)=(168*100*100)/(125*120)=112=>X=12%
Answer B)
Answer: (B) 12
Question: Kamal bought a house, whose sale price was Rs. 8 lakh. He availed 20% discount as an early bird offer and then 10% discount due to cash payment. After that he spent 10% of the cost price in interior decoration and lawn of the house. At what price should he sell the house to earn a profit of 25%?
(A) Rs. 9 lakh
(B) Rs. 7.99 lakh
(C) Rs. 7.92 lakh
(D) Rs. 7 lakh
(E) None of These
Rationale: Solution: Let the marked price be 100.
100 == 20% ↓(discount)==> 80 == 10% ↓(discount)==> 72(CP) == 10% ↑(interior)==> 79.2(Total CP)
Now, selling price would be 25% above the Total cost price.
SP = 79.2 + 25% of 79.2
SP = 99
Now, On comparing,
100 ==> 800000
99 ==> (800000/100) *99 ==> 7, 92,000
So,
SP = Rs. 7, 92, 000.
Answer: Option C
Answer: (C) Rs. 7.92 lakh
Question: In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
(A) 2/3
(B) 3/4
(C) 7/19
(D) 8/21
(E) None
Rationale: Solution
Total number of balls	= (8 + 7 + 6)
= 21.
Let E = event that the ball drawn is neither red nor green
=event that the ball drawn is red.
Therefore, n(E) = 8.
P(E) = 8/21.
Answer D
Answer: (D) 8/21
Question: A tank contains 10,000 gallons of a solution that is 5 percent sodium chloride by volume. If 3,500 gallons of water evaporate from the tank, the remaining solution will be approximately what percent sodium chloride?
(A) 6.43%
(B) 6.89%
(C) 7.69%
(D) 8.21%
(E) 8.75%
Rationale: The amount of sodium chloride is 0.05*10,000 = 500 gallons
500/6500 = 1/13 which is about 7.69%
The answer is C.
Answer: (C) 7.69%
Question: If x and y are two different prime numbers, which of the following cannot be true?
(A) xy is odd.
(B) x + y is even.
(C) x + y is odd
(D) xy is even
(E) x/y is an integer
Rationale: A prime number is a positive integer with exactly two distinct positive divisors: 1 and itself. So, a prime number cannot be a multiple of another prime number. Which makes option E not possible (x/y=integer means that x is a multiple of y).
All other options are possible:
A. xy is odd --> x=3 and y=5;
B. x + y is even --> x=3 and y=5;
C. x + y is odd --> x=2 and y=3;
D. xy is even --> x=2 and y=3; Answer: E
Answer: (E) x/y is an integer
Question: What is the principal sum?
I. The sum amounts to Rs. 690 in 3 years at S.I.The rate of interest is 5% p.a.
II. The sum amounts to Rs. 750 in 5 years at S.I.The rate of interest is 7% p.a.
III. The sum amounts to Rs. 580 in 3 years at S.I. The rate of interest is 6% p.a.
(A) I and III only
(B) II and III only
(C) I and II only
(D) Any two of the three
(E) Any one of the above
Rationale: Explanation:
Clearly, any of the three will give us the answer
Answer: E
Answer: (E) Any one of the above
Question: What was the day on 15th august 1947 ?
(A) Friday
(B) Monday
(C) Wednesday
(D) Thursday
(E) Sunday
Rationale: 15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)
Odd days in 1600 years = 0
Odd days in 300 years = 1
46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day
Jan. Feb. Mar. Apr. May. Jun. Jul. Aug
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 1 ) = 213 days = (30 weeks + 3 days) = 3 odd days.
Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days.
Given day is Friday.
Answer is A.
Answer: (A) Friday
Question: In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 0vers to reach the target of 282 runs?
(A) 6.25
(B) 6.5
(C) 6.75
(D) 7
(E) None
Rationale: Sol.
Required run rate = 282 – (3.2 × 10 / 40)
= 240 / 40
= 6.25.
Answer A
Answer: (A) 6.25
Question: Monica planned her birthday party. She prepared 5 muffins for each of her guests and kept aside two additional muffins in case someone will want extra. After the party, it turned out that one of the guests didn't come but every one of the guests that did come ate six muffins and 6 muffins remained. How many guests did Monica plan on?
(A) 3.
(B) 4.
(C) 2.
(D) 6.
(E) 7.
Rationale: 5N +2 = 6 + 6(N-1)
Solving N= 2
Hence C
Answer: (C) 2.
Question: The distance light travels in one year is approximately 5,880,000,000,000 miles. The distance light travels in 100 years is
(A) A) 587 × 108 miles
(B) B) 587 × 1010 miles
(C) C) 587 × 10-10 miles
(D) D) 588 × 1012 miles
(E) E) 587 × 10-12 miles
Rationale: The distance of the light travels in 100 years is:
5,880,000,000,000 × 100 miles.
= 588,000,000,000,000 miles.
= 588 × 1012 miles.
The answer is (D)
Answer: (D) D) 588 × 1012 miles
Question: what is the angle between the hands of a clock when time is 16:40?
(A) 625deg
(B) 420deg
(C) 145deg
(D) 150deg
(E) 300deg
Rationale: Angle between two hands =
40h - 11/2 m = 40*16 - 40*11/2 = 640 - 220 = 420deg
ANSWER:B
Answer: (B) 420deg
Question: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?
(A) 175
(B) 185
(C) 165
(D) 155
(E) 125
Rationale: Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.40 + x x 3.20 = 432
3.20x = 432 - 384 = 48
x = 15.
Hence, total hours of work = (160 + 15) = 175.
Answer is A.
Answer: (A) 175
Question: During the months May through October, Teddy the bear triples his weight, and during the months November through April, Teddy loses 100 pounds. If at the beginning of November 1973, Teddy's weight was m pounds, what was Teddy's weight in pounds by the end of April 1976?
(A) 9m−1300
(B) 9m−300
(C) 4m−1200
(D) 3m−300
(E) m−1300
Rationale: Nov ' 73 = m
April ' 74 = m - 100
Oct ' 74 = 3m - 300
April' 75 = 3m - 400
Oct' 75 = 9m - 1200
April'76 = 9m - 1300
Hence answer will be (A) 9m - 1300
Answer: (A) 9m−1300
Question: Stephanie wants to buy lipsticks. Each lipstick costs $20. How much will she pay if she decides to buy 5 lipsticks?
(A) $500
(B) $100
(C) $20
(D) $10
(E) 0
Rationale: B. $100
Answer: (B) $100
Question: The distance between A&B is 600km. A person is traveling from A to B at 80km/hr started at 11AM and another person is traveling from B to A at 70km/hr and started at same time. Then at what time they meet together.?
(A) A)2PM
(B) B)4PM
(C) C)1PM
(D) D)3PM
(E) E)5PM
Rationale: Let x hours be they will meet together
distance covered by 1st person+distance covered by 2nd person = 600km
70x+80x = 600
x= 4 hr
They will meet = 11AM +4hr = 3PM
Answer is D
Answer: (D) D)3PM
Question: There are two concentric circles with radii 6 and 4. If the radius of the outer circle is increased by 50% and the radius of the inner circle decreased by 25%, by what percent does the area between the circles increase?
(A) 160
(B) 210
(C) 260
(D) 310
(E) 360
Rationale: The area of a circle is piR^2, where R is the radius.
The area of the big circle is 36pi.
The area of the small circle is 16pi.
The area A1 between the circles is 20pi.
When the big circle's radius increases, the new area is 81pi.
When the small circle's radius decreases, the new area is 9pi.
The area A2 between the circles is 72pi.
The ratio of A2/A1 is 72/20 = 3.6 which is an increase of 260%.
The answer is C.
Answer: (C) 260
Question: During the first two weeks of January, the total rainfall in Springdale was 40 inches. If the rainfall during the second week was 1.5 times the rainfall during the first week, what was the rainfall during the second week of January?
(A) 5 inches
(B) 6 inches
(C) 9 inches
(D) 10 inches
(E) 24inches
Rationale: Total rainfall in 2 weeks = 40 inches.
Assume the rainfall in second week = 1.x
Rainfall in first week = x
Total rainfall = 2.5x = 40 inches
x = 16 and 1.5x = 24
Rainfall during second week = 24 inches
Option E
Answer: (E) 24inches
Question: A basket has 5 apples and 4 oranges. Three fruits are picked at random. The probability that at least 2 apples are picked is?
(A) 25/42
(B) 25/421
(C) 35/42
(D) 25/82
(E) 23/42
Rationale: Total fruits = 9
Since there must be at least two apples,
(5C2 * 4C1)/9C3 + 5C3/9C3
= 25/42.
Answer: A
Answer: (A) 25/42
Question: Arun got 30% of the maximum marks in an examination and failed by 10 marks. However, Sujith who took the same examination got 40% of the total marks and got 15 marks more than the passing marks. What were the passing marks in the examination?
(A) 90
(B) 250
(C) 75
(D) 85
(E) None of these
Rationale: Explanation :
Let x is the maximum marks of the examination
Marks that Arun got = 30 % of x = 30x/100
Given that Arun failed by 10 marks
⇒Minimum Pass Mark = (30x/100) + 10......(Equation 1)
Answer : Option D
Answer: (D) 85
Question: Two pipes A and B can fill a tank in 18 hours and 24 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?
(A) 20 hours
(B) 15 hours
(C) 10 hours
(D) 10 2/7 hours
(E) 8 hours
Rationale: Part filled by A in 1 hour = 1/18
Part filled by B in 1 hour = 1/24
Part filled by (A+B) in 1 hour = 1/18 + 1/24 = 7/72
Both the pipes together fill the tank in 72/7 = 10 2/7 hours
Answer is D
Answer: (D) 10 2/7 hours
Question: The average of 1st 3 of 4 numbers is 16 and of the last 3 are 15. If the sum of the first and the last number is 13. What is the last numbers?
(A) 3
(B) 5
(C) 9
(D) 8
(E) 2
Rationale: A + B + C = 48
B + C + D = 45
A + D = 13
A – D = 3
A + D = 13
2D = 10
D = 5
Answer:B
Answer: (B) 5
Question: Tickets numbered from 1 to 20 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bearsa number which is a multiple of 3?
(A) 3/11
(B) 3/7
(C) 3/10
(D) 2/5
(E) 2/7
Rationale: Here, S = [1, 2, 3, 4, …., 19, 20]
Let E = event of getting a multiple of 3 = [3, 6, 9, 12, 15, 18]
P (E) = n (E) / n (S) = 6 / 20 = 3/10
C
Answer: (C) 3/10
Question: 9548 + 7314 = 8362 + (?)
(A) 8300
(B) 8400
(C) 8500
(D) 8700
(E) 9000
Rationale: 9548 16862 = 8362 + x
+ 7314 x = 16862 - 8362
----- = 8500
16862
-----
C)
Answer: (C) 8500
Question: One millisecond is 0.001 of a second. The costs for a single run of a computer program are $1.04 for operating-system overhead, $0.023 per millisecond of computer time, and $4.35 for the mounting of a data tape. What is the total of these three costs for 1 run of a program that requires 1.5 seconds of computer time ?
(A)  $39.89
(B)  $48.87
(C)  $58.96
(D)  $65.57
(E)  $69.92
Rationale: Operating system overhead for 1 run = 1.04 $
Mounting of data tape = 4.35$
Cost per 1 millisecond of computer time = .023 $
Total cost of 1 run of a program that requires 1.5 seconds of computer time
= 1.04 + (.023*1500) + 4.35
=1.04 + 34.5 + 4.35
= 39.89$
Answer A
Answer: (A)  $39.89
Question: Reema took a loan of Rs 1500 with simple interest for as many years as the rate of interest. If she paid Rs. 735 as interest at the end of the loan period, what was the rate of interest.
(A) 5%
(B) 6%
(C) 7%
(D) 8%
(E) 9%
Rationale: Explanation:
Let rate = R% then Time = R years.
=>1500∗R∗R /100=735
=>R2=49
=>R=7%
Option C
Answer: (C) 7%
Question: The tax on a commodity is diminished by 30% but its consumption is increased by 20%. Find the decrease percent in the revenue derived from it?
(A) 18%
(B) 72%
(C) 32%
(D) 16%
(E) 52%
Rationale: 100 * 100 = 10000
70 * 120 = 8400
10000------- 1600
100 ------- ? = 16%
Answer:D
Answer: (D) 16%
Question: If y exceeds x by 20%, then x is less than y by?
(A) 16 2/7%
(B) 16 2/8%
(C) 16 2/3%
(D) 16 2/9%
(E) 16 2/13%
Rationale: X=100	y=120
120------20
100-------? => 16 2/3%
Answer:C
Answer: (C) 16 2/3%
Question: A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
(A) 2 mins
(B) 3 mins
(C) 9 mins
(D) 8 mins
(E) 6 mins
Rationale: D = 25 * 60 + 1500 = 3000 m
T = 3000/60 * 18/5 = 180 sec = 3 mins
Answer:B
Answer: (B) 3 mins
Question: Scott's average (arithmetic mean) golf score on his first four rounds was 18.What score does he need on his fifth round to drop his average score by 2 points?
(A) 68
(B) 72
(C) 8
(D) 88
(E) 312
Rationale: Average score for first 4 rounds = 18
Average score after 5 rounds = 16
Score Scott needs on his 5th round to drop average score by 2 points = 18 - (2*5) = 8
Answer C
Answer: (C) 8
Question: In a hockey league there are 10 teams. Each team plays every other team once. If we can play 5 games every week, how many weeks long is one season?
(A) 8
(B) 9
(C) 18
(D) 20
(E) 22
Rationale: total matches = 10*9/2 = 45
so number of weeks = 45/5 = 9
ANSWER:B
Answer: (B) 9
Question: The jogging track in a sports complex is 627 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in?
(A) 4.56 min
(B) 5.28 min
(C) 5.08 min
(D) 9.28 min
(E) 5.988 min
Rationale: Clearly, the two will meet when they are 627 m apart.
To be (4.5 + 3.75) = 8.25 km apart, they take 1 hour.
To be 627 m apart, they take (100/825 * 627/1000) hrs = (627/8250 * 60) min = 4.56 min.
Answer: A
Answer: (A) 4.56 min
Question: A train passes a platform in 35 seconds. The same train passes a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, The length of the platform is
(A) 280 meter
(B) 240 meter
(C) 225 meter
(D) 200 meter
(E) None of these
Rationale: Explanation:
Speed of the train = 54 km/hr = (54×10)/35 m/s = 15 m/s
Length of the train = speed × time taken to cross the man = 15×20 = 300 m
Let the length of the platform = L
Time taken to cross the platform = (300+L)/15
=> (300+L)/15 = 35
=> 300+L = 15×35 = 525
=> L = 525-300 = 225 meter
Answer: Option C
Answer: (C) 225 meter
Question: A train can travel 50% faster than a car. Both start from point A at the same time and reach point B at 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is?
(A) 110 km/hr
(B) 145 km/hr
(C) 151 km/hr
(D) 180 km/hr
(E) 120 km/hr
Rationale: E
Let speed of the car be x km/hr.
Then, speed of the train = 150/100 x = 3/2 x km/hr.
75/x - 75/(3/2 x) = 125/(10 * 60)
75/x - 50/x = 5/24 = 120 km/hr.
Answer: (E) 120 km/hr
Question: Having scored 99 runs in the 19th inning, a cricketer increases his average score by 4. What will be his average score after 19 innings?
(A) 28
(B) 27
(C) 26
(D) 22
(E) 24
Rationale: Explanation :
Let the average score of the first 18 innings be n
18n + 99 = 19(n+4)=> n = 23
So, Average score after 19th innings = x+4 =27.
Answer : B
Answer: (B) 27
Question: An investor deposited $5,000 to open a new savings account that earned 12 percent annual interest, compounded quarterly. If there were no other transactions in the account, what was the amount of money in the account 6 months after the account was opened?
(A) $5300.50
(B) $5304.50
(C) $5405.50
(D) $5604.50
(E) $5805.50
Rationale: The amount in the account after 6 months is 1.03*1.03($5,000) = $5304.50.
The answer is B.
Answer: (B) $5304.50
Question: Car A runs at the speed of 55 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 70 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B?
(A) 3 : 7
(B) 4 : 9
(C) 11 : 7
(D) 5 : 7
(E) 6 : 11
Rationale: Car A travels 55 × 8 = 440 km
Car B travels 70 × 4 = 280 km
The ratio is 440 : 280 = 44 : 28 = 11 : 7
The answer is C.
Answer: (C) 11 : 7
Question: Can anyhow help me with an easy solution for this
2, 7, 36, 4, 14, 225, 6, 21, ?
(A) 576
(B) 476
(C) 376
(D) 276
(E) 676
Rationale: 2, 7, 36, 4, 14, 225, 6, 21, ?
2+7=9 and 9-3=6 and 6^2=36
4+14=18 and 18-3=15 and 15^2=225
6+21=27 and 27-3=24 and 24^2=576
ANSWER:A
Answer: (A) 576
Question: Simple interest on a certain sum of money for 2 years at16% per annum is one fourth the compound interest on Rs. 4000 for 2 years at 8% per annum. The sum placed on simple interest is
(A) Rs.4000
(B) Rs.665.6
(C) Rs.520
(D) Rs.166.4
(E) None
Rationale: Solution
C.I.	=Rs[4000x(1+8/100)Â²-4000]
Rs.(4000x108/100x108/100-4000)	= Rs.665.6.
Sum	=Rs. [166.4x100 /2x16]
= Rs.520.
Answer C
Answer: (C) Rs.520
Question: Each week, Harry is paid x dollars per hour for the first 35 hours and 1.5x dollars for each additional hour worked that week. Each week, James is paid x dollars per per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours If Harry and James were paid the same amount last week, how many hours did Harry work last week ?
(A) 35
(B) 36
(C) 34
(D) 38
(E) 39
Rationale: James worked for 41 hours hence he earned 40*x+1*2x=42x dollars;
We know that Harry also earned the same 42x dollars, out of which he earned 35x dollars for thefirst 35 hoursplus 7x additional dollars. Since for each additional hour he gets 1.5x dollars then he worked for 7x/1.5x= 4 additional hours, so Harry worked for total of 30+4=34 hours.
Answer: C.
Answer: (C) 34
Question: A and B complete a work in 6 days. A alone can do it in 10 days. If both together can do the work in how many days?
(A) 7.75 days
(B) 2.75 days
(C) 5.75 days
(D) 3.75 days
(E) 8.75 days
Rationale: D
3.75 days
1/6 + 1/10 = 8/30 = 4/15
15/4 = 3.75 days
Answer: (D) 3.75 days
Question: Find the distance covered by a man walking for 30min at a speed of 10km/hr?
(A) 1km
(B) 3km
(C) 4km
(D) 5km
(E) 6km
Rationale: Distance = 10*20/60 = 5km
Answer is D
Answer: (D) 5km
Question: How many possible integer values are there for x if |x - 3| < 6 ?
(A) One
(B) Two
(C) Three
(D) eleven
(E) Five
Rationale: Solution: |x-3| < 6
let x=a therefore we have |a-3| < 6 ==> read this as origin is at +3 and we have to move +6 to the right and -6 to the left
(the less than sign represents that the a must be within boundaries )
(3-6)----------3----------(3+6)
now, we have -3<a<9
but a =x ==> -3<x<9
Now question says Integer values (not rational ) therefore we have -2,-1,0,1,2,3,4,5,6,7,8
Hence 11 D
Answer: (D) eleven
Question: Find the odd man out
2886, 480, 96, 24, 8, 4, 4
(A) 480
(B) 96
(C) 24
(D) 8
(E) 2886
Rationale: from the right side
4*1=4,
4*2=8
8*3=24
24*4=96
96*5=480
480*6=2880 but here given 2886 so it's not.
ANSWER:E
Answer: (E) 2886
Question: ’A’ sold an article to ’B’ at a profit of 20%. ’B’ sold the same article to ’C’ at a loss of 25% and ’C’ sold the same article to ’D’ at a profit of 40%. If ’D’ paid Rs 252 for the article, then find how much did ’A’ pay for it?
(A) Rs 175
(B) Rs 200
(C) Rs 180
(D) Rs 210
(E) Rs 230
Rationale: Let the article costs ‘X’ to A
Cost price of B = 1.2X
Cost price of C = 0.75(1.2X) = 0.9X
Cost price of D = 1.4(0.9X) = 1.26X = 252
Amount paid by A for the article = Rs 200
ANSWER:B
Answer: (B) Rs 200
Question: A starts a business with a capital of Rs. 30,000. B joins in the business with Rs.12000 after some time. For how much period does B join, if the profits at the end of the year are divided in the ratio of 3 : 1?
(A) 5 months
(B) 6 months
(C) 7 months
(D) 10 months
(E) None of these
Rationale: Explanation :
Let B joins for x months. Then
A:B = 30000*12 : x* 12000 = 3 : 1
=> 30*12 : 12x= 3 : 1
=> 30*12/ 12x = 3/1 = 3
=> 30*4 /12x = 1
=> 10/x = 1
=> x = 10. Answer : Option D
Answer: (D) 10 months
Question: If â€œ*â€ is called â€œ+â€, â€œ/â€ is called â€œ*â€, â€œ-â€ is called â€œ/â€, â€œ+â€ is called â€œ-â€. 240-80 / 60 - 40 * 10 = ?
(A) 14.5
(B) 13.5
(C) 12.5
(D) 17.5
(E) 11.5
Rationale: Explanation:
Given : 240-80 / 60 - 40 * 10 = ?
Substituting the coded symbols for mathematical operations, we get,
240 / 80 * 60 / 40 + 10 = ?
3*1.5+10 = 14.5
ANSWER : A
Answer: (A) 14.5
Question: The tax on a commodity is diminished by 30% but its consumption is increased by 15%. Find the decrease percent in the revenue derived from it?
(A) 20%
(B) 18%
(C) 15%
(D) 12%
(E) 14%
Rationale: 100 * 100 = 10000
70 * 115 = 8050
10000------- 1950
100 ------- ? = 20%
ANSWER:A
Answer: (A) 20%
Question: Ten years ago, P was half of Q's age. If the ratio of their present ages is 3:4 what will be the total of their present ages?
(A) 33
(B) 67
(C) 29
(D) 31
(E) 35
Rationale: E
35
Let present age of P and Q be 3x3x and 4x4x respectively.
Ten years ago, P was half of Q's age
⇒(3x−10)=1/2(4x−10)
⇒6x−20=4x−10
⇒2x=10
⇒x=5
Total of their present ages
=3x+4x=7x=7×5=35
Answer: (E) 35