mathewhe/aqua_rat huggingface dataset:
Question: All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 151 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?
(A) 1289
(B) 1198
(C) 281
(D) 1208
(E) 282
Rationale: Explanation:
B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k - 5k = 3k.
Quantity of water in container C = 8k - 3k = 5k
Container: A B C
Quantity of water: 8k 3k 5k
It is given that if 151 liters was transferred from container C to container B, then both the containers would have equal quantities of water.
5k - 151 = 3k + 151 => 2k = 302 => k = 151
The initial quantity of water in A = 8k = 8 * 151 = 1208 liters.
Answer: Option D
Answer: (D) 1208
Question: John bought 2 shares and sold them for $24 each. If he had a profit of 20% on the sale of one of the shares but a loss of 20% on the sale of the other share, then on the sale of both shares John had
(A) a profit of $10
(B) a profit of $2
(C) a loss of $2
(D) a loss of $10
(E) neither a profit nor a loss
Rationale: Loss% = (%age Profit or loss / 10)^2 = (20/10)^2 = 4% loss
Total Selling Price = 24*2 = $48
Total Cost Price = 48/(0.96) = $50
Loss = 50-48 = $2
Answer: Option C
Answer: (C) a loss of $2
Question: Dan can do a job alone in 12 hours. Annie, working alone, can do the same job in just 9 hours. If Dan works alone for 8 hours and then stops, how many hours will it take Annie, working alone, to complete the job?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: Dan can complete 1/12 of the job per hour.
In 8 hours, Dan completes 8(1/12) = 2/3 of the job.
Annie can complete 1/9 of the job per hour.
To complete the job, Annie will take 1/3 / 1/9 = 3 hours.
The answer is B.
Answer: (B) 3
Question: The ratio of the radius of two circles is 1: 5, and then the ratio of their areas is?
(A) 1:7
(B) 2:9
(C) 1:25
(D) 3:7
(E) 3:4
Rationale: r1: r2 = 1: 5
Î r1^2: Î r2^2
r1^2: r2^2 = 1:25
Answer: C
Answer: (C) 1:25
Question: 10 camels cost as much as 24 horses, 16 horses cost as much as 4 oxen and 6 oxen as much as 4 elephants. If the cost of 10 elephants is Rs.120000, find the cost of a camel?
(A) s.9800
(B) s.3800
(C) s.9800
(D) s.4800
(E) s.6880
Rationale: Cost of the camel = P
10 camels = 24 horses
16 horses = 4 oxen
6 oxen = 4 elephants
10 elephants = Rs.120000
P = Rs.[(24 * 4 * 4 * 120000)/(10 * 16 * 6 * 10)]
P = Rs.(46080000/9600) => P = Rs.4800
Answer:D
Answer: (D) s.4800
Question: A certain car uses 12 gallons of gasoline in traveling 360 miles. In order for the car to travel the same distance using 10 gallons of gasoline, by how many miles per gallon must the car’s gas mileage be increased?
(A) 2
(B) 4
(C) 6
(D) 8
(E) 10
Rationale: 360/10 = 36. The difference is 36 - 30 = 6.
Answer C
Answer: (C) 6
Question: In a group of ducks and cows, the total number of legs are 26 more than twice the no. of heads. Find the total no.of buffaloes.
(A) 11
(B) 12
(C) 13
(D) 16
(E) 18
Rationale: Let the number of buffaloes be x and the number of ducks be y
=> 4x + 2y = 2 (x + y) + 26
=> 2x = 26=> x = 13
C
Answer: (C) 13
Question: (((13!)^16)-((13!)^8))/(((13!)^8)+((13!)^4))=a
then what is the units digit for a/((13!)^4)=
(A) 7
(B) 8
(C) 9
(D) 6
(E) 5
Rationale: (((13!)^16)-((13!)^8))/(((13!)^8)+((13!)^4))=a
solving it , we get
a/((13!)^4)= ((13!)^4-1)
last digit of (13!)^4 will be 0.
so last digit of ((13!)^4-1) will be 9.
ANSWER:C
Answer: (C) 9
Question: Find the value for x from below equation: x/2=-2?
(A) -6
(B) 1
(C) -2
(D) -3
(E) -4
Rationale: 1. Multiply both sides by 2:
x*2/2= -2/2
Simplify both sides:
x = -4
E
Answer: (E) -4
Question: The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
(A) 1520 m2
(B) 2420 m2
(C) 2480 m2
(D) 2520 m2
(E) None of these
Rationale: Explanation:
We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.
Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) m2 = 2520 m2.
Answer: D
Answer: (D) 2520 m2
Question: John and Ingrid pay 30% and 40% tax annually, respectively. If John makes $58000 and Ingrid makes $72000, what is their combined tax rate?
(A) 32%
(B) 34.4%
(C) 35%
(D) 35.6%
(E) 37.4%
Rationale: (1) When 30 and 40 has equal weight or weight = 1/2, the answer would be 35.
(2) When 40 has larger weight than 30, the answer would be in between 35 and 40. Unfortunately, we have 2 answer choices D and E that fit that condition so we need to narrow down our range.
(3) Get 72000/130000 = 36/65. 36/65 is a little above 36/72 = 1/2. Thus, our answer is just a little above 35.
Answer: D
Answer: (D) 35.6%
Question: There are 9 executives, including the CEO and CFO, that are asked to form a small team of 4 members. However, the CEO and CFO may not both be assigned to the team. Given this constraint, how many ways are there to form the team?
(A) 97
(B) 99
(C) 101
(D) 103
(E) 105
Rationale: The total number of ways to form a team of 4 is 9C4=126.
We need to subtract the number of teams that have both the CEO and the CFO.
The number of teams with both the CEO and CFO is 7C2=21.
The number of ways to form an acceptable team is 126-21=105.
The answer is E.
Answer: (E) 105
Question: If x is divisible by 6 and 5, which of the following must divide evenly into x? I. 64 II. 32 III. 15
(A) I only
(B) II only
(C) III only
(D) II,III only
(E) none of these
Rationale: If x is divisible by 6,5 means it will be = or > 30, 60,90 etc...
That are not divisible by 32, 64.
So, the answer is C
Answer: (C) III only
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
(A) 65 km/hr
(B) 50 km/hr
(C) 21 km/hr
(D) 25 km/hr
(E) 76 km/hr
Rationale: Speed of the train relative to man
= (125/10) m/sec
= (25/2) m/sec. [(25/2) * (18/5)] km/hr
= 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed
= (x - 5) km/hr. x - 5 = 45 ==> x
= 50 km/hr.
Answer: B
Answer: (B) 50 km/hr
Question: How many numbers between 400 and 1000 can be made with the digits 2,3,4,5,6 and 0?
(A) 30
(B) 60
(C) 90
(D) 120
(E) 150
Rationale: Required number = 3 * 5P2 = 3*20 = 60
Answer is B
Answer: (B) 60
Question: If there are half as many women as men in a group and an equal number of men and women do not own cars - a group that is 40% of the total. What fraction of the total is women who own cars?
(A) 3⁄20
(B) 11⁄60
(C) 9⁄40
(D) 1⁄5
(E) 2⁄15
Rationale: Consider a group of 200 men and 100 women, a total of 300 people. 40% of them, which is 120, form a group of people who don't own a car.
Half of them are men, and the other half are women, more precisely 60.
It means that there are 100-60 = 40 women who own a car, and this represents 40/300 = 2/15 of the total.
Answer E
Answer: (E) 2⁄15
Question: The length of a train and that of a platform are equal. If with a speed of 144 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
(A) 757
(B) 758
(C) 718
(D) 1200
(E) 738
Rationale: Speed = [144 * 5/18] m/sec = 40 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 40 è x = 40 * 60 / 2
=1200
Answer:D
Answer: (D) 1200
Question: If a boat goes 6km upstream in 36 minutes and the speed of the stream is 4 kmph, then the speed of the boat in still water is ?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
Rationale: Rate upsteram =(6/36*60)kmph=10kmph.
speed of the stream =4kmph let speed in still water be xkm/hr. then speed upstream=(x-4)km/hr. x-4=10==>x=14km/hr Answer(E)
Answer: (E) 14
Question: A train running at the speed of 60 km/hr crosses a pole in 15 sec. What is the length of the train?
(A) 118
(B) 150
(C) 277
(D) 250
(E) 191
Rationale: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 15 = 250 m
Answer: D
Answer: (D) 250
Question: The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.6270.What was his original salary?
(A) 6000
(B) 2999
(C) 1000
(D) 2651
(E) 1971
Rationale: X * (110/100) * (95/100) = 6270
X * (11/10) * (1/100) = 66
X = 6000
Answer: A
Answer: (A) 6000
Question: The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
(A) 1%
(B) 2%
(C) 3%
(D) 5%
(E) 4%
Rationale: D
5%
Increase in 10 years = (262500 - 175000) = 87500.
Increase% = (87500/175000 x 100)% = 50%.
Required average = (50/10)% = 5%.
Answer: (D) 5%
Question: Find the cost of fencing around a circular field of diameter 42 m at the rate of Rs.3 a meter?
(A) 138
(B) 390
(C) 393
(D) 279
(E) 222
Rationale: 2 * 22/7 * 21 = 131
131 * 3
= Rs.393
Answer: C
Answer: (C) 393
Question: The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
(A) 4 years
(B) 6 years
(C) 8 years
(D) 10 years
(E) 12 years
Rationale: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Answer: Option A
Answer: (A) 4 years
Question: A, B and C rents a pasture for Rs.841. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should C pay?
(A) 270
(B) 279
(C) 276
(D) 261
(E) 262
Rationale: 12*8 :16*9 = 18*6
8: 12: 9
9/29 * 841 = 261
Answer: D
Answer: (D) 261
Question: Find the numbers which are in the ratio 3 : 2 : 4 such that the sum of the first and the second added to the difference of the third and the second is 21 ?
(A) 9, 6, 11
(B) 9, 6, 17
(C) 9, 6, 19
(D) 9, 6, 12
(E) 9, 6, 10
Rationale: Let the numbers be a, b and c.
Given that a, b and c are in the ratio 3 : 2 : 4.
let, a = 3x, b = 2x and c = 4x
Given, (a+b) + (c - b) = 21
= > a + b + c - b = 21 = > a + c = 21
= > 3x + 4x = 21 = >7x = 21 = > x = 3
a , b , c are 3x, 2x, 4x.
a, b, c are 9 , 6 , 12.
Answer: D
Answer: (D) 9, 6, 12
Question: The owner of a furniture shop charges his customer 100% more than the cost price. If a customer paid Rs. 1000 for a computer table, then what was the cost price of the computer table?
(A) 800
(B) 650
(C) 500
(D) 600
(E) 250
Rationale: CP = SP * (100/(100 + profit%))
= 1000(100/200) = Rs. 500.
Answer: C
Answer: (C) 500
Question: Find the unit's digit in 264^102+264^103
(A) 0
(B) 2
(C) 3
(D) 5
(E) 6
Rationale: Required unit's digit = unit's digit in 4102+4103.4102+4103.
Now, 4242 gives unit digit 6.
⇒ 41024102 gives unit digit 6.
⇒ 41034103 gives unit digit of the product 6×46×4 i.e., 4.
Hence, unit's digit in 264102+264103264102+264103
= unit's digit in (6+4)=0
A
Answer: (A) 0
Question: A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 5:3 and B:C = 5:2. If the total runs scored by all of them are 60, the runs scored by B are?
(A) 20.23
(B) 20.13
(C) 30.93
(D) 19.56
(E) 10.93
Rationale: A:B = 5:3
B:C = 5:2
A:B:C = 25:15:6
15/46 * 60 = 19.56
ANSWER:D
Answer: (D) 19.56
Question: A boy incurs 5% loss by selling a book for Rs. 1000. At what price should the book be sold to earn 5 % profit?
(A) Rs. 1105.26
(B) Rs. 1251.50
(C) Rs. 1085.13
(D) Rs. 1885.13
(E) None of these
Rationale: Explanation:
Let the new selling price be Rs. x
(100 – loss %) /1000 = (100 + gain %) / x
(100 – 5) / 1000 = (100 + 5) / x
x = (105 × 1000) / 95 = 105000 / 95
x = 1105.26.
ANSWER A
Answer: (A) Rs. 1105.26
Question: In a store, the profit is 320% of the cost. If the cost increases by 25% but the SP remains constant, approximately what % of the sellingprice is the profit?
(A) 50%
(B) 70%
(C) 90%
(D) 100%
(E) 120%
Rationale: Let C.P. = Rs. 100. Then, profit = Rs. 320, S.P. = Rs. 420
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 420
Profit = 420 - 125 = Rs. 295
Required percentage = 295/420 * 100 = 1475/21 = 70%
B
Answer: (B) 70%
Question: The average of ten numbers is 0. In those 10, at the least, how many may be greater than or equal to zero?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 5
Rationale: Explanation :
Average of 10 numbers = 0
Sum of 10 numbers =(0 x 10) =0.
It is quite possible that 9 of these numbers may be negative and if there sum is -a, then 10th number is (a).
Answer : B
Answer: (B) 1
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 57 kmph, find the speed of the stream?
(A) 16 kmph
(B) 19 kmph
(C) 14 kmph
(D) 11 kmph
(E) 13 kmph
Rationale: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream
= (2+1)/(2-1) = 3/1
= 3:1
Speed of the stream
= 57/3 = 19 kmph.
Answer: B
Answer: (B) 19 kmph
Question: In the county of Veenapaniville, there are a total of 50 high schools, of three kinds: 25 public schools, 16 parochial schools, and 9 private independent schools. These 50 schools are divided between three districts: A, B, and C. District A has 18 high schools total. District B has 17 high schools total, and only one of those are private independent schools. If District C has an equal number of each of the three kinds of schools, how many private independent schools are there in District A?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: Total Private Schools = 9
Dist A: High Schools = 18 ==> Private Schools = ?
Dist B: High Schools = 17 ==> Private Schools = 1
Dist C: High Schools = 15 ==> Private Schools = 5
Therefore, 9 - 1 - 5 ==> 3
Answer B)
Answer: (B) 3
Question: An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the cases.
(A) 8 : 6
(B) 8 : 7
(C) 8 : 8
(D) 8 : 9
(E) 8 : 3
Rationale: Let the length and breadth of the carpet in the first case be 3x units and 2x units respectively.
Let the dimensions of the carpet in the second case be 7y, 3y units respectively.
From the data,.
2(3x + 2x) = 2(7y + 3y)
=> 5x = 10y
=> x = 2y
Required ratio of the areas of the carpet in both the cases
= 3x * 2x : 7y : 3y
= 6x2 : 21y2
= 6 * (2y)2 : 21y2
= 6 * 4y2 : 21y2
= 8 : 7
Answer: Option B
Answer: (B) 8 : 7
Question: A man walks at a rate of 10 mph. After every ten miles, he rests for 6 minutes. How much time does he take to walk 60 miles?
(A)  300
(B)  318
(C)  322
(D)  324
(E)  390
Rationale: To cover 60 miles the man needs (time) = (distance)/(rate) = 60/10 = 6 hours = 360 minutes. He will also rest 5 times (after 10, 20, 30,40 and 50 miles), so total resting time = 5*6 = 30 minutes.
Total time = 360 + 30 = 390 minutes.
Answer: E.
Answer: (E)  390
Question: In one hour a boat goes 18 km long the stream and 6 km against the stream.The speed of the boat in still water is?
(A) 12
(B) 14
(C) 16
(D) 17
(E) 18
Rationale: Speed in still water A = ½ ( 18+6) km/hr A= 12 kmph
Answer: A
Answer: (A) 12
Question: A bag contains a certain number of 50 paise coins, 20 paise coins and 10 paise coins inthe ratio 3:4:5. If the total value of all the coins in the bag is Rs.400, find the number of 50 paise coins ?
(A) 498
(B) 488
(C) 428
(D) 528
(E) 418
Rationale: 50*3k + 20*4k + 10*5k = 40000
280k = 40000 => k = 142.85
50p coins = 3k = 3*142.85 = 428
20p coins = 4k = 4*142.85 = 571
10p coins = 5k = 5*142.85 = 714
ANSWER:C
Answer: (C) 428
Question: A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 1200. How many workers were part of the latter production run?
(A) A)6
(B) B)14
(C) C)11
(D) D)15
(E) E)23.5
Rationale: The daily average production is given by 5n + 20- given
In the first k days, 500 units are produced
= (5n+20)K =500
k = 500/5n+20...................................1
5 workers were added = 5(n+5)+20 = 5n +45
cumulative is 1200 .. thus for the current period = 1200 -500 = 700
(5n+45)K= 700
k = 700/5n+45........................................2
equate 1 and 2
500/5n+20 = 700 /5n+45
500(5n+45) = 700(5n+20)
25n + 225 = 35n + 140
-10n = -85
n = 8.5
thus n+5 = 14
hence B
Answer: (B) B)14
Question: a series of natural number 1+2+3+4+5+6+7+8+9+10 is divisibel by 11 so we has to find how many such series is possible upto n where n is less than 1000.
(A) 90
(B) 99
(C) 180
(D) 96
(E) 92
Rationale: the total multiple of 11 less then 1000 are 90 .
and for every multiple there are two such series which are divisible by 11.
. .
. sum of series = n(n+1)/2
for multiple 11 we can take n=10 and 11
for 22 '' '' ''' n=21 and 22
and so on and for 990 multiple of 11 we can take n=989 and 990
so total series formed are 90*2= 180
ANSWER:C
Answer: (C) 180
Question: A company conducted a survey about its two brands, A and B. x percent of respondents liked product A, (x – 20) percent liked product B, 23 percent liked both products, and 23 percent liked neither product. What is the minimum number G of people surveyed by the company?
(A) 46
(B) G=80
(C) G=90
(D) G=100
(E) 200
Rationale: 100 = x + x - 20 + 23 - 23
x = 60,
So, Product A = 60%, Product B = 40%, Both = 23%, Neither = 23%
23% of the total no. of people should be an integer. So, A,BC are out.
60% of D and 40% of D are both integers. So, D satisfies all conditions.
So, answer is D.
Answer: (D) G=100
Question: A firm is divided into four departments, each of which contains four people. If a project is to be assigned to a team of three people, none of which can be from the same department,what is the greatest number of distinct teams to which the project could be assigned?
(A) 4^3
(B) 4^4
(C) 4^5
(D) 6(4^4)
(E) 4(3^6)
Rationale: First member: 4*4=16 choices;
Second member: 4*3=12 choices (as one department already provided with a member);
Third member: 4*2=8 choices (as two departments already provided with members);
So, we have: 16*12*8.
Since the order of the members in a team does not matter (we don't actually have 1st, 2nd and 3rd members) then we should divide above by 3! to get rid of duplication: 16*12*8/3!=4^4.
ANSWER:B
Answer: (B) 4^4
Question: Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction M of the work will be done by Adam?
(A)  1/4
(B)  12/47
(C)  1/3
(D)  5/12
(E)  20/47
Rationale: Let the total work be 60 units. Pual does 60/3 =20 units of work per hr. abdul does 15 units per hr and adam does 12 units per hr. If all work together they do (20 + 15 + 12) units per hr = 47 units per hr. So the time taken to finish the work = 60/47 hrs.
adam will do 60/47 * 12 units of work in 60/47 hr . fraction of work adam does =work done by adam / total work
M>( 60/47 *12)/60 =12/47
Answer B
Answer: (B)  12/47
Question: A car during its journey travels 30 minutes at a speed of 60 kmph, another 45 minutes at a speed of 60 kmph, and 2 hours at a speed of 80 kmph.The average speed of the car is
(A) 63.07 kmph
(B) 64 kmph
(C) 72.30 kmph
(D) 64.02 kmph
(E) None of these
Rationale: First car travels 30 min at speed of 60 kmph
distance = 60 x 1/2 = 30 m
Then car travels 45 min at a speed of 60 kmph
distance = 45 min at speed of 60 kmph
distance = 60 x 3/4 = 45 m
at last it travels 2 hours at speed of 70 kmph
distance = 80 x 2 = 160 m
Total distance = 30 + 45 + 160 = 235
Total time= 1/2 + 3/4 + 2 = 3.25
Average speed of the car = 235/3.25 = 72.30
ANSWER:C
Answer: (C) 72.30 kmph
Question: What is the greatest of 3 consecutive integers whose sum is 21 ?
(A) 6
(B) 7
(C) 8
(D) 9
(E) 5
Rationale: The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3
If the sum is 24, we need to solve the equation 3n + 3 = 21;
=> 3n = 18;
=> n = 6
The greatest of the three numbers is therefore 6 + 2 = 8 Answer: C
Answer: (C) 8
Question: 5357 x 51 = ?
(A) 273232
(B) 273243
(C) 273247
(D) 273250
(E) 273207
Rationale: 5357 x 51	= 5357 x (50 + 1)
= 5357 x 50 + 5357 x 1
= 267850 + 5357
= 273207
E)
Answer: (E) 273207
Question: Equal weights of two alloys containing tin, copper and lead in the ratio 6:8:7 and 1:2:4 are melted and mixed together. What is the ratio of tin, copper and lead in the resultant alloy?
(A) 11:8:3
(B) 3:1:8
(C) 17:28:27
(D) 9:4: 11
(E) 9:14: 11
Rationale: Let the weight of the two alloys be w each
Required ratio =
(6w/21+1w/7): (8w/21+2w/7 ): (7w/21+4w/7)
= 9w/21 : 14w/21 : 11w/21
= 9:14: 11
ANSWER:E
Answer: (E) 9:14: 11
Question: Which of the following fraction is the smallest?
(A) 12/14
(B) 13/19
(C) 17/21
(D) 7/8
(E) None of these
Rationale: Explanation:
12/14 = 0.857, 13/19 = 0.684, 17/21 = 0.8095 and 7/8 = 0.875
Since 0.684 is the smallest, so 13/19 is the smallest fraction.
ANSWER: B
Answer: (B) 13/19
Question: At the end of three years what will be the compound interest at the rate of 10% p.a. on an amount of Rs.20000?
(A) 6620
(B) 3277
(C) 2688
(D) 2998
(E) 2789
Rationale: A = 20000(11/10)3
= 26620
= 20000
----------
6620
Answer:A
Answer: (A) 6620
Question: A man covers a certain distance by car driving at 30 km/hr and he returns back to the starting point riding on a scooter at 10 km/hr. Find his average speed for the whole journey.
(A) 8 Km/hr
(B) 17 Km/hr
(C) 15 Km/hr
(D) 12 km/hr
(E) None of these
Rationale: Explanation:
= (2 x a x b)/(a + b)
= (2 x 30 x 10)/(30 + 10)
= (2 x 30 x 10)/40
= 15 km/hr
Answer: Option C
Answer: (C) 15 Km/hr
Question: Four car rental agencies A, B, C and D rented a plot for parking their cars during the night. A parked 15 cars for 12 days, B parked 12 cars for 20 days, C parked 18 cars for 18 days and D parked 16 cars for 15 days. If A paid Rs. 1125 as rent for parking his cars, what is the total rent paid by all the four agencies?
(A) 2388
(B) 2778
(C) 1279
(D) 6150
(E) 2771
Rationale: The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15
= 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60
Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.
The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k
It is given that A paid Rs. 1125
45k = 1125 => k = 25
246k = 246(25) = Rs. 6150
Thus the total rent paid by all the four agencies is Rs. 6150.
Answer: D
Answer: (D) 6150
Question: A sum of money at simple interest amounts to Rs. 830 in 3 years and to Rs. 854 in 4 years. The sum is:
(A) 647
(B) 698
(C) 758
(D) 847
(E) 976
Rationale: S.I. for 1 year = Rs. (854 - 830) = Rs. 24.
S.I. for 3 years = Rs.(24 x 3) = Rs. 72.
Principal = Rs. (830 - 72) = Rs. 758.
Answer:C
Answer: (C) 758
Question: Thirty percent of the members of a swim club have passed the lifesaving test. Among the members who havenotpassed the test, 5 have taken the preparatory course and 30 have not taken the course. How many members are there in the swim club?
(A)  60
(B)  80
(C)  50
(D)  120
(E)  140
Rationale: 30% of the members have passed the test, thus 70% have not passed the test.
We also know that 30+5=42 members have not passed the test, thus 0.7*Total=35 --> Total=50.
Answer: C.
Answer: (C)  50