mathewhe/aqua_rat huggingface dataset:
Question: In an NGO the daily average wages of 20 illiterate employees is decreased from Rs.25 to Rs.10, thus the average salary of all the literate and illiterate employees is decreased Rs.10 per day. The No. of educated employees working in the NGO is ?
(A) 11
(B) 82
(C) 10
(D) 28
(E) 23
Rationale: Explanation:
Total employees = \inline \frac{(25-10)\times 20}{10}=30
Hence number of educated employees = 30-20 = 10
Answer: C
Answer: (C) 10
Question: Find the fraction which has the same ratio to 2/13 that 5/34 has to 7/48?
(A) 240/1576
(B) 240/1542
(C) 240/1547
(D) 240/1528
(E) 240/1529
Rationale: P : 2/13 = 5/34 : 7/48
As the product of the means is equal to the product of the extremes.
P*7/48 = 2/13 * 5/34
P*7/48 = 10/442
P = 480/3094 => P = 240/1547
Answer: C
Answer: (C) 240/1547
Question: If the average of q, b, c, 14 and 15 is 12. What is the average value of q, b, c and 29
(A) 12
(B) 13
(C) 14
(D) 15
(E) 16
Rationale: q+b+c+14+15 = 12*5 = 60
=>q+b+c = 60-29 = 31
q+b+c+29 = 31+29= 60
Average = 60/4 = 15
Answer D
Answer: (D) 15
Question: Amit and Ian paint a wall in alternating shifts. First Amit paints alone, then Ian paints alone, then Amit paints alone, etc. During each of his shifts, Amit paints 1/2 of the remaining unpainted area of the wall, while Ian paints 1/3 of the remaining unpainted area of the wall during each of his shifts. If Amit goes first, what fraction of the wall's area will remain unpainted after Amit has completed his 5th shift?
(A) 1/27
(B) 1/54
(C) 1/81
(D) 1/162
(E) 1/216
Rationale: Fraction of area unpainted after FIRST shift of Amit = 1-(1/2) = 1/2
Fraction of area unpainted after FIRST shift of Ian = (1/2)-(1/3)(1/2) = (2/3)(1/2)
Fraction of area unpainted after SECOND shift of Amit = (1/2)(2/3)(1/2)
Fraction of area unpainted after SECOND shift of Ian = (2/3)(1/2)(2/3)(1/2)
Fraction of area unpainted after THIRD shift of Amit = (1/2)(2/3)(1/2)(2/3)(1/2)
Fraction of area unpainted after THIRD shift of Ian = (2/3)(1/2)(2/3)(1/2)(2/3)(1/2)
Fraction of area unpainted after FORTH shift of Amit = (1/2)(2/3)(1/2)(2/3)(1/2)(2/3)(1/2)
Fraction of area unpainted after FORTH shift of Ian = (2/3)(1/2)(2/3)(1/2)(2/3)(1/2)(2/3)(1/2)
Fraction of area unpainted after FIFTH shift of Amit = (1/2)(2/3)(1/2)(2/3)(1/2)(2/3)(1/2)(2/3)(1/2)=1/162
Answer: option D
Answer: (D) 1/162
Question: Average of first five multiples of 2 is
(A) 9
(B) 6
(C) 13
(D) 15
(E) 16
Rationale: Explanation:
Average=2(1+2+3+4+5)5=6
Answer: Option B
Answer: (B) 6
Question: The difference of 2 digit number & the number obtained by interchanging the digits is 36. What is the difference the sum and the number if the ratio between the digits of the number is 1:2 ?
(A) 6
(B) 8
(C) 9
(D) 10
(E) 12
Rationale: Let the number be xy.
Given xy – yx = 36.
This means the number is greater is than the number got on reversing the digits.
This shows that the ten’s digit x > unit digit y.
Also given ratio between digits is 1 : 2 => x = 2y
(10x + y) – (10y +x) = 36 => x – y = 4 => 2y – y =4.
Hence, (x + y) – (x – y) = 3y – y = 2y = 8
B
Answer: (B) 8
Question: The length of the bridge, which a train 130 m long and traveling at 45 km/hr can cross in 30 sec is?
(A) 227
(B) 268
(C) 245
(D) 299
(E) 271
Rationale: Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (130 + x)/30 = 25/2
x = 245 m.
Answer:C:
Answer: (C) 245
Question: A bag contains 15 purple jellybeans, 10 green jellybeans, and 10 yellow jellybeans; these jellybeans are the only items in the bag. If a person picks a jellybean at random out of the bag, what is the probability that the jellybean will be green?
(A) 15%
(B) 29%
(C) 25%
(D) 30%
(E) 35%
Rationale: Probability of green beans = 10 / (15 + 10 + 10) = 10/35 = 29%
Answer is B
Answer: (B) 29%
Question: What amount does Kiran get if he invests Rs. 18000 at 15% p.a. simple interest for four years?
(A) Rs. 24800
(B) Rs. 28400
(C) Rs. 24400
(D) Rs. 28800
(E) None of these
Rationale: Explanation:
Simple interest = (18000 * 4 * 15)/100 = Rs. 10800
Amount = P + I = 18000 + 10800 = Rs. 28800
ANSWER IS D
Answer: (D) Rs. 28800
Question: For the symbol, m”n=n^2−m for all values of m and n. What is the value of 3”3?
(A) 6
(B) 3
(C) 2
(D) 1
(E) 0
Rationale: 3”3= 9 - 3=6
Answer: A
Answer: (A) 6
Question: In a garment industry, 12 men working 9 hours per day complete a piece of work in 10 days. To complete the same work in 12 days, working 15 hours a day, the number of men required is:
(A) 4
(B) 5
(C) 6
(D) 7
(E) 9
Rationale: Explanation :
Let the required number of men be x.
Less days, More men (Indirect Proportion)
More working hrs per day, Less men (Indirect Proportion)
Days 8 : 10
Working Hrs 15 : 9 :: 12 : x
=> 12 x 15 x x = 10 x 8 x 12
=> x = 10 x 9 x 12 / (12 x 15)
=> x = 7
Answer : D
Answer: (D) 7
Question: Half of 1 percent written as decimal is
(A) 5
(B) 0.5
(C) 0.05
(D) 0.005
(E) None of these
Rationale: Explanation:
It will be 1/2(1%) = 1/2(1/100) = 1/200 = 0.005
Option D
Answer: (D) 0.005
Question: If 20 typists can type 40 letters in 20 minutes, then how many letters will 30 typists working at the same rate complete in 1 hour?
(A) 63
(B) 72
(C) 144
(D) 180
(E) 400
Rationale: 20 typists can type 40 letters, so 30 typists can type = 40*30/20
40*30/20 letters can be typed in 20 mins. In 60 mins typist can type= 40*30*60/20*20= 180
D is the answer
Answer: (D) 180
Question: In a game of 60 points; A can give B 10 points and C 15 points. Then how many points B can give C in a game of 40 ?
(A) can give C 1 points
(B) can give C 4 points
(C) can give C 2 points
(D) can give C 6 points
(E) can give C 8 points
Rationale: A: B = 60 : 50, A : C = 60 : 45.
B/C = ( B/ A * A/C) = (50 / 60 * 60 / 45) = 10/9 = 40 /36
Therefore ,In a game of 40, B can give C 4 points.
Answer is B.
Answer: (B) can give C 4 points
Question: How many two letter words are formed using the letters of the word RAM?
(A) 22
(B) 6
(C) 8
(D) 10
(E) 12
Rationale: Explanation:
The number of letters in the given word is three.
The number of two letter words that can be formed using these four letters is Ã¢Â´PÃ¢â€šÆ’ = 3 * 2 = 6.
Answer: B
Answer: (B) 6
Question: Count each 7 which is not immediately preceded by 5 but is immediately followed by either 2 or 3.
How many such 7's are there ?
5 7 2 6 5 7 3 8 3 7 3 2 5 7 2 7 3 4 8 2 6 7 8
(A) 2
(B) 4
(C) 3
(D) 5
(E) None
Rationale: Answer: A . 2
Answer: (A) 2
Question: What is the 8th digit to the right of the decimal point in the decimal expansion of 1/37?
(A)  0
(B)  2
(C)  4
(D)  7
(E)  9
Rationale: 1/37=0.027027... So, we have a repeating cycle of 027. Every third digit (2nd, 4th, 6th, ...) to the right of the decimal point is alternating by 2,0,7, thus 8th digit to the right of the decimal point is 2.
Answer: B.
Answer: (B)  2
Question: If the average (arithmetic mean) of the four numbers K, 2K + 2, 3K – 5 and 5K + 1 is 63, what is the value of K?
(A)  11
(B)  15 3/4
(C)  22
(D)  23
(E)  23 1/11
Rationale: K + 2K +2 + 3K - 5 + 5K +1 = 11K -2
(11K -2)/4 = 63
11K = 63 * 4 +2 = 252 +2 = 254
K = 254 / 11 = 23 1/11
Answer E.
Answer: (E)  23 1/11
Question: In a series of consecutive odd numbers, 27 is the seventh smallest number and 25 is the tenth largest number. What is the range of the series?
(A)  32
(B)  30
(C)  29
(D) 28
(E)  14
Rationale: Imp:All are consecutive odd numbers.
27 is the 8th smallest ,there are 6 numbers smaller then 27 ,smallest number :27-12=15
25 is the 10th largest ,so there are 9 numbers larger then 25, largest number:25+18=43
Range:43-15=28
Ans : D
Answer: (D) 28
Question: Insert the missing number.
2, 4, 12, 48, 240, (....)
(A) 3388
(B) 1440
(C) 398
(D) 278
(E) 2771
Rationale: Explanation:
Go on multiplying the given numbers by 2, 3, 4, 5, 6.
So, the correct next number is 1440.
Answer: B) 1440
Answer: (B) 1440
Question: Bongani and Jane are friends. Bongani takes Jane's physics test paper and will not tell her what her mark is. He knows that Jane hates maths so he decides to tease her. Bongani says: “I have 2 marks more than you do and the sum of both our marks is equal to 14. What are our marks?”
(A) j=6,b=8
(B) j=3,b=5
(C) j=8,b=2
(D) j=1,b=3
(E) j=5,b=5
Rationale: We have two unknown quantities, Bongani's mark and Jane's mark. Let Bongani's mark be b and Jane's mark be j.
Set up a system of equations
Bongani has 2 more marks than Jane.
b=j+2............(1)
Both marks add up to 14.
b+j=14............(2)
Use equation (1) to express b in terms of j
b=j+2
Substitute into equation (2)
b+j=14
(j+2)+j=14
Rearrange and solve for j
2j=14−2
=12
∴j=6
Substitute the value for j back into equation (1) and solve for b
b=j+2
=6+2
=8
Bongani got 8 for his test and Jane got 6.
Answer is A.
Answer: (A) j=6,b=8
Question: Shannon and Maxine work in the same building and leave work at the same time. Shannon lives due north of work and Maxine lives due south. The distance between Maxine's house and Shannon's house is 60 miles. If they both drive home at the rate 2R miles per hour, Maxine arrives home 40 minutes after Shannon. If Maxine rider her bike home at the rate of R per hour and Shannon still drives at a rate of 2R miles per hour, Shannon arrives home 2 hours before Maxine. How far does maxine live from work?
(A) 20
(B) 34
(C) 38
(D) 40
(E) 46
Rationale: We have that X/24 - (60-X)/2R = 40
Also X/R - (60-X)/2R = 120
So we get that 2x - 60 = 80R
3x - 60 = 240R
Get rid of R
120 = 3x
x = 40
Hence answer is D
Answer: (D) 40
Question: Machines X and Y produce bottles at their respective constant rates. Machine X produces k bottles in 6 hours and machine Y produces k bottles in 12 hours. How many hours does it take machines X and Y , working simultaneously , to produce 12k bottles?
(A)  8
(B)  12
(C)  15
(D)  48
(E)  24
Rationale: x rate = k/6
y rate = k/12
k/6 + k/12 = 12k / T
solving T = 48
Answer D
Answer: (D)  48
Question: Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 200 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 4 of the days were hot, then what was the price of 1 cup on a hot day?
(A) $ 1.56
(B) $ 1.88
(C) $ 2.25
(D) $ 2.50
(E) $ 3.25
Rationale: 6 regular days --> sales = 6*32*x = 192x;
4 hot days --> sales = 4*32*(1.25x) = 160x;
Total sales = 192x+160x = 352x.
Total cost = 10*32*0.75 = 240.
Profit = 352x - 240 = 200 --> x=1.25.
1.25x=~1.56.
Answer: A.
Answer: (A) $ 1.56
Question: Find the no.of ways of arranging the boy and 8 guests at a circular table so that the boy always sits in a particular seat?
(A) 2!
(B) 8!
(C) 9!
(D) 10!
(E) 15!
Rationale: Ans.(B)
Sol. Total number of persons = 9 Host can sit in a particular seat in one way. Now, remaining positions are defined relative to the host. Hence, the remaining can sit in 8 places in 8P8 = 8! Ways ... The number of required arrangements = 8! x 1= 8! = 8! ways
Answer: (B) 8!
Question: A basketball player practices 2 hours a day Monday through Friday. How many hours must he practice Saturday and Sunday combined if he wants to practice an average (arithmetic mean) of 3 hours a day for the seven day week?
(A) 8
(B) 9
(C) 10
(D) 11
(E) 12
Rationale: Total number of hours practiced Mon through Fri: 5*2 = 10
Total number of hours that will be practiced in a 7 day week considering 3 hours a day average: 7*3 = 21
thus 21-10 = 11 hours still need to be practiced (on Sat and Sun combined)
D
Answer: (D) 11
Question: In how many ways can you walk up a stairway with 6 steps if you
can take one or two steps at a time? (For example, you can walk up
a stairway with 3 steps in three dierent ways: (i) Take three single
steps. (ii) Take one step and then two steps. (iii) Take two steps and
then one step.)
(A) 9
(B) 10
(C) 11
(D) 12
(E) 13
Rationale: Let fn denote the number of ways one can get to the nth step. Given the example
in the problem, we see then that f3 = 3. It is easy to see f1 = 1 and f2 = 2 (the latterfollows since one can take one step twice or two steps at a time to get to the second step).
To determine the value of fn for any n >/3, think about the previous step a person would
have to be on before getting to the nth step. Since only one or two steps are allowed at a
time, the person would have to be either on the (n-1)st step or the (n-2)nd step there are by definition fn-1 ways someone can get to the (n - 1)st step and fn􀀀-2 ways a
person can get to the (n - 2)nd step, there must be fn-1 + fn-2 ways of getting to the
nth step (by first going to the (n- 1)st step in one of fn-1 ways and then taking a single
step or by first going to the (n-2)nd step in one of fn-2 ways and then taking two steps
at once). In other words, fn = fn-1 +fn-2. This allows us to easily compute fn for n>/3
successively. Specifically,
f3 = f2 + f1 = 2+1 = 3 (as we knew); f4 = f3 + f2 = 3+2 = 5;
f5 = f4 +f3 = 5+3 = 8; and f6 = f5 + f4 = 8+5 = 13:
Therefore, the answer is 13.
correct answer is E
Answer: (E) 13
Question: Two numbers N and 24 have LCM = 48 and GCF = 8. Find N.
(A) 16
(B) 56
(C) 76
(D) 87
(E) 24
Rationale: The product of two integers is equal to the product of their LCM and GCF. Hence.
24* N = 48 * 8
N = 48*8 / 24 = 16 correct answer A
Answer: (A) 16
Question: Which of the options is a two-digit number, which has a unit's digit that exceeds its ten's digit by 3 and the product of the given number and the sum of its digits is equal to 175.
(A) 25
(B) 36
(C) 47
(D) 52
(E) 63
Rationale: Using the elimination method the option that fits this description is 25
5-2 = 3 (unit's digit that exceeds its ten's digit by 3)
25*7 = 175 (the product of the given number and the sum of its digits is equal to 175)
answer :A
Answer: (A) 25
Question: If a man walks at the rate of 5 kmph, he misses a train by 7 minutes. However, if he walks at the rate of 6 kmph, he reaches the station 5 minutes before the arrival of the train. Find the distance covered by him to reach the station.
(A) 6 km
(B) 8 km
(C) 5 km
(D) 3 km
(E) 2 km
Rationale: Let the required distance be x km
Difference in the time taken at two speeds=1 min =1/2 hr
Hence x/5-x/6=1/5<=>6x-5x=6
x=6
Hence, the required distance is 6 km
Ans: B
Answer: (B) 8 km
Question: Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 12 inches on a side and costs $10, and a large pizza that measures 18 inches on a side and costs $20. If two friends go to Huey's with $30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone?
(A) 5 square inches
(B) 36 square inches
(C) 15 square inches
(D) 25 square inches
(E) 350 square inches
Rationale: In the first case each can buy one pizza of $10 and one pizza of $20.
In square inches that would be (12*12=144) for the small pizza and (18*18=324) for the large pizza. In total sq inches that would be (144+324)*2= 936 sq inches.
In the second case if they pool their money together they can buy 3 large pizzas. In terms of square inches that would be 3*324= 972 sq inches.
Hence, the difference is 36 square inches more (972-936).
The correct answer is B
Answer: (B) 36 square inches
Question: A water tank is two-third full. Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes. If both the pipes are open, how long will it take to empty or fill the tank completely?
(A) 6 min. to empty
(B) 6 min. to full
(C) 10 min. to empty
(D) 9 min. to full
(E) 8 min. to full
Rationale: Clearly, pipe B is faster than pipe A and so, the tank will be emptied.
Part to be emptied = 2/3
Part emptied by (A + B) in 1 minute = (1/6 - 1/10) = 1/15
1/15 : 2/3 :: 1 : x
x = (2/3 * 1 * 15) = 10 min.
So, the tank will be emptied in 10 min.
ANSWER:C
Answer: (C) 10 min. to empty
Question: What is the sum of all 3 digit positive integers that can be formed using the digits 1, 3, and 7, if the digits are allowed to repeat within a number?
(A) 8,434
(B) 9,656
(C) 10,989
(D) 11,323
(E) 12,878
Rationale: The number of these 3-digit numbers is 3*3*3 = 27
Each digit 1, 3, and 7 will appear in the ones, tens, and hundreds place 9 times each.
The sum equals 9(111) + 9(333) + 9(777) = 10,989
The answer is C.
Answer: (C) 10,989
Question: When 30 per cent of a number is added to another number the second number increases to its 140 per cent. What is the ratio between the first and the second number?
(A) 3 : 4
(B) 4 : 3
(C) 3 : 2
(D) Data inadequate
(E) None of these
Rationale: Let the first and the second numbers be x and y respect then
y + 30% of x = 140% of y
or, y + 0.3x = 1.4y
or, 0.3x = 0.4y
∴ x : y = 0.4 : 0.3 = 4 : 3
Answer B
Answer: (B) 4 : 3
Question: Given f(x) = 3x – 5, for what value of x does 2*[f(x)] – 1 = f(3x – 6)
(A) 0
(B) 4
(C) 6
(D) 7
(E) 13
Rationale: explanations
We have the function f(x) = 3x – 5, and we want to some sophisticated algebra with it. Let’s look at the two sides of the prompt equation separately. The left side says: 2*[f(x)] – 1 —- this is saying: take f(x), which is equal to its equation, and multiply that by 2 and then subtract 1.
2*[f(x)] – 1 = 2*(3x – 5) – 1 = 6x – 10 – 1 = 6x – 11
The right side says f(3x – 6) — this means, take the algebraic expression (3x – 6) and plug it into the function, as discussed above in the section “How a mathematician things about a function.” This algebraic expression, (3x – 6), must take the place of x on both sides of the function equation.
f(3x – 6)= 3*[3x – 6] – 5 = 9x – 18 – 5 = 9x – 23
Now, set those two equal and solve for x:
9x – 23 = 6x – 11
9x = 6x – 11 + 23
9x = 6x + 12
9x – 6x = 12
3x = 12
x = 4
Answer = B
Answer: (B) 4
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 1.4 km respectively. The time taken by the slower train to cross the faster train in seconds is?
(A) 65 sec
(B) 55 sec
(C) 48 sec
(D) 33 sec
(E) 60 sec
Rationale: Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 1.4 = 2.5 km = 2500 m.
Required time = 2500 * 3/125
= 60 sec.
Answer:E
Answer: (E) 60 sec
Question: Tickets numbered from 1 to 22 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bears a number which is a multiple of 3?
(A) 1/5
(B) 2/5
(C) 3/10
(D) 3/7
(E) 7/22
Rationale: Here, S = [1, 2, 3, 4, …., 19, 20, 21, 22]
Let E = event of getting a multiple of 3 = [3, 6, 9, 12, 15, 18, 21]
P (E) = n (E) / n (S) = 7 / 22
The answer is E.
Answer: (E) 7/22
Question: How many minutes does it take John to type z words if he types at the rate of x words per minute?
(A) x/y
(B) z/x
(C) xy
(D) 60x/y
(E) y/(60x)
Rationale: time*rate=job --> time*x=z --> time=z/x.
Answer: B.
Answer: (B) z/x
Question: The true discount on Rs. 1760 due after a certain time at 12% per annum is Rs. 160. The time after which it is due is:
(A) 6 months
(B) 8 months
(C) 9 months
(D) 10 months
(E) 12 months
Rationale: TD=Amt*R*T/(100+RT)
given TD=160,Amt=1760,R=12,T=?
by substituting the values we get,
160=(1760*12T)/(100+12T)
160(100+12T)=1760*12T
100+12T=(1760*12T)/160
100+12T=132T
120T=100
t=100/120=5/6yrs i.e (5/6)*12=10months
ANSWER:D
Answer: (D) 10 months
Question: The average of first 20 even numbers is?
(A) 19
(B) 18
(C) 16
(D) 11
(E) 21
Rationale: Sum of 20 even numbers = 20 * 21 = 420
Average =420/20 = 21
Answer:E
Answer: (E) 21
Question: A palindrome is a word or a number that reads the same forward and backward. For example, 2442 and 111 are palindromes. If 5-digit palindromes are formed using one or more of the digits 1, 2, 3, 4, 5, 6, and 7, how many palindromes are possible?
(A) 35
(B) 49
(C) 105
(D) 255
(E) 343
Rationale: There are 7 choices for each of the first three digits.
The number of possible palindromes is 7^3=343.
The answer is E.
Answer: (E) 343
Question: 3,7,12,18,25,..............6th terms
(A) 43
(B) 53
(C) 63
(D) 33
(E) 78
Rationale: 3+4=7
7+5=12
12+6=18
18+7=25
25+8=33
ANSWER:D
Answer: (D) 33
Question: A sequence contains y numbers of alternating positive and negative numbers, If the first number is postive and y is an even number, how many negative numbers are in it?
(A) (y+1)/2
(B) (y-1)/2
(C) y/(2+1)
(D) y/(2-1)
(E) y/2
Rationale: Lets put values for y, say y=8 since it's even
and first number is positive so sequence will be {pos,neg,pos,neg,pos,neg,pos,neg} we can see that it has 4 negative terms
so putting y=8 in the options,
option E = y/2 => 8/2 = 4 , the number of negative integers
So, E is the answer
Answer: (E) y/2
Question: In how many ways 8 different tickets T can be distributed between Jane and Bill if each is to receive any even number of tickets and all 8 tickets to be distributed.
(A) From 2 to 6 inclusive.
(B) From 98 to 102 inclusive.
(C) From 122 to 126 inclusive.
(D) From 128 to 132 inclusive.
(E) From 196 to 200 inclusive.
Rationale: Possibilities
J 8 6 4 2 0
B 0 2 4 6 8
# of ways 8C8 8C6 8C4 8C2 8C0
T=1+28+70+28+1 = 128 Answer is D.
Answer: (D) From 128 to 132 inclusive.
Question: Company A has 13 employees, 8 of whom belong to the union. If 4 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?
(A) 56
(B) 231
(C) 336
(D) 350
(E) 406
Rationale: Looks easy: -- 8C4*4C1 + 8C5 --350 (D).
Answer: (D) 350
Question: A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 844 in 4 years. The sum is:
(A) s. 650
(B) s. 690
(C) s. 698
(D) s. 728
(E) s. 760
Rationale: S.I. for 1 year = Rs. (844 - 815) = Rs. 29.
S.I. for 3 years = Rs.(29 x 3) = Rs. 87.
Principal = Rs. (815 - 87) = Rs. 728.
Answer: Option D
Answer: (D) s. 728
Question: The Italian size of a suit jacket is N centimeters, where N is the linear distance between the armpits when the jacket is laid on a flat surface. The American size of a suit jacket is P inches, where P is twice the linear distance between the armpits when the jacket is laid on a flat surface. If, for a particular jacket, N = P + 12, which of the following is closest to the value of N? (One inch is approximately 2.54 centimeters.)
(A) 36
(B) 47
(C) 58
(D) 55
(E) 72
Rationale: Since one inch is approximately 2.54 centimeters, then N centimeters is N/2.54 inches.
Next, since the American size (P inches) is twice the Italian size (N/2.54 inches), then P=2*N/2.54.
As given that N = P + 12, then N=2*N/2.54+12 --> N=~55.
Answer: D.
Answer: (D) 55
Question: John draws a card from a pack of cards. What is the probability that the card drawn is a card of black suit?
(A) 1/2
(B) 1/4
(C) 1/3
(D) 1/13
(E) 1/15
Rationale: Tot no of cards n(S) = 52
Tot no of black cards = 26
=>26/52=1/2
ANSWER A
Answer: (A) 1/2
Question: A father is now three times as old as his son. Six years back, he was four times as old as his son. The age of the son (in years) is
(A) A)12
(B) B)15
(C) C)19
(D) D)20
(E) E)22
Rationale: Explanation:
Let son's age be x years. Then, father's age = (3x) years.
Six years ago, father's age = (3x -6 ) years and son's age = (x - 6) years.
So, 3x - 6 = 4 (x - 6)=> 3x - 5 = 4x - 24=> x = 19.
Answer: C
Answer: (C) C)19
Question: If a car travels a distance of y km, at the speed of x km/hr , which of the following cannot be equal to the distance traveled?
(A) y/x km
(B) x/2 km
(C) (x-y)/2 km
(D) x-y km
(E) y-x km
Rationale: This question can be solved by TESTing VALUES, but there's a particular pattern that you have to recognize to make the workeasy.
We're not really limited by anything in this question, so X and Y can be anything. Under normal circumstances, I won't TEST the number 1 in PS questions (as it often leads to duplicate answers), but here it's a great option (since we're looking to eliminate 4 answers, multiple TESTs are going to be likely anyway).
We're given information on speed (X km/hour) and distance (Y km). We're asked which of the 5 answer choices CANNOT be the distance traveled.
IF....
X = 2 and Y = 1
Answers D (2-1 = 1) and B (2/2 = 1) are POSSIBLE. Eliminate D and B.
IF....
X = 3 and Y = 1
Answer C ([3-1]/2 = 1) is POSSIBLE. Eliminate C.
IF....
X = 1 and Y = 1
Answer A (1/1 = 1) is POSSIBLE. Eliminate A.
Final Answer:
E
Answer: (E) y-x km