mathewhe/aqua_rat huggingface dataset:
Question: In a 240 meters race A beats B by 56 m or 7 seconds. A's time over the course is:
(A) 23 seconds
(B) 12 seconds
(C) 10 seconds
(D) 18 seconds
(E) 28 seconds
Rationale: B runs 56 m in 7 sec.
=> B runs 240 m in 7/56*240 = 30 seconds
Since A beats B by 7 seconds, A runs 240 m in (30-7) = 23 seconds
Hence, A's time over the course = 23 seconds
ANSWER:A
Answer: (A) 23 seconds
Question: a and b are positive integers less than or equal to 6. If a and b are assembled into the six-digit number ababab, which of the following must be a factor of ababab?
(A) 3
(B) 4
(C) 5
(D) 2
(E) none of the above
Rationale: 242424 when divided by 2 gives the result 121212
CONCEPT: Rule of Divisibility of 2 isIf sum of the digits of the Number is divisible by 2 then the number will be divisible by 2
SUm of the digits of No. which is divisible by 2 hence the Number 242424 will be divisible by 2
D
Answer: (D) 2
Question: A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?
(A) 2 p.m. on Tuesday
(B) 7 p.m. on Tuesday
(C) 8 p.m. on Tuesday
(D) 5 p.m. on Tuesday
(E) 1 p.m. on Tuesday
Rationale: 2 minutes slow at monday noon.
4 min 48 sec fast at 2 pm next monday.
It ran faster than normal time by 6 min 48 secs = 408 sec in 7 days 2 hours = 170 hours.
It was correct when it advanced 120 seconds than normal time.
The clock gains 408 seconds in 170 hours.
The clock gains 1 second in 170/408 hours
The clock gains 120 seconds in 170408×120170408×120 hours = 50 hours = 2 days 2 hours.
So the clock shows correct time on Wednesday 2 pm..
Answer:A
Answer: (A) 2 p.m. on Tuesday
Question: By selling 12 toffees for a rupee, a man loses 20%. How many for a rupee should be sell to get a gain of 20%?
(A) 2
(B) 8
(C) 9
(D) 7
(E) 6
Rationale: Explanation:
Let S.P. of 12 toffees be Rs. x.
Then, 80:1 = 120:x or x = 120/180 = 3/2
For Rs. 3/2, toffees sold = 12.
For Re. 1, toffees sold = 12 * 2/3 = 8
Answer:B
Answer: (B) 8
Question: Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 6. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?
(A) (4m-15)/[m(m-5)]
(B) (4m-15)/[m(m-8)]
(C) (4m-18)/[m(m-5)]
(D) (4m-20)/[m(m-5)]
(E) (5m-15)/[m(m-5)]
Rationale: Three of the sandwiches were evenly divided among the students
i.e. Amount of Sandwiches with each students = 3/m
Amount of 4th Sandwich with remaining (m-6) students = 1/(m-6)
The amount of Sandwich that carol ate = 3/m + 1/(m-6) = (3m-18+m)/[m(m-5)] = (4m-15)/[m(m-5)]
Answer: A
Answer: (A) (4m-15)/[m(m-5)]
Question: In one alloy there is 12% chromium while in another alloy it is 8%. 15 kg of the first alloy was melted together with 40 kg of the second one to form a third alloy. Find the percentage of chromium in the new alloy.
(A) 8.8%
(B) 9%
(C) 9.2%
(D) 9.1%
(E) 8.4%
Rationale: The amount of chromium in the new 15+40=55 kg alloy is 0.12*15+0.08*40=5 kg, so the percentage is 5/55*100=9.1%.
Answer: D.
Answer: (D) 9.1%
Question: The cost price of an article is 64% of the marked price. Calculate the gain percent after allowing a discount of 12%?
(A) 37.5%
(B) 37.6%
(C) 38.5%
(D) 17.5%
(E) 37.2%
Rationale: Let marked price = Rs. 100.
Then, C.P. = RS. 64, S.P. = Rs. 88
Gain % = 24/64 * 100 = 37.5%.
Answer: A
Answer: (A) 37.5%
Question: Running at the same constant rate, 5 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?
(A)  648
(B)  1,800
(C)  2,160
(D)  10,800
(E)  64,800
Rationale: 5 machines produce 270 bottles per minute;
1 machine produces 270/5=54 bottles per minute;
10 machines produce 54*10=540 bottles per minute;
In 4 minutes 10 machines produce 540*4=2,160 bottles.
Answer: C.
Answer: (C)  2,160
Question: A man saves a certain portion of his income during a year and spends the remaining portion on his personal expenses. Next year his income increases by 35% but his savings increase by 100%. If his total expenditure in 2 years is double his expenditure in 1st year, What %age of his income in the first year did he save?
(A) 25%
(B) 28%
(C) 30%
(D) 32.5%
(E) 35%
Rationale: 1st year Income= I
1st year savings= S
1st year Expense= E1
2nd year Income = 1.35I
2nd year savings= 2S (100% increase)
2nd Year expense= E2
E1+ E2= 2E1
E2=E1
That means Expenses are same during both years. With increase of 35% income the savings increased by 100%.
or S= .35I
or S= 35% of Income
E is the answer
Answer: (E) 35%
Question: An empty wooden vessel weighs 14% of its total weight when filled with paint. If the weight of a partially filled vessel is one half that of a completely filled vessel, what fraction of the vessel is filled.
(A) 6/13
(B) 5/9
(C) 1/24
(D) 4/9
(E) 2/5
Rationale: An empty wooden vessel weighs 14% of its total weight when filled with paint:
Vessel = 0.14(Vessel + Paint);
14V = V + P (so the weight of completely filled vessel is 14V)
P = 13V (so the weight of the paint when the vessels is completely filled is 13V).
The weight of a partially filled vessel is one half that of a completely filled vessel:
V + P' = 1/2*14V;
P' = 6V (so the weight of the paint when the vessels is partially filled is 6V).
What fraction of the vessel is filled?
So, we need to find the ratio of the weight of the paint when the vessel iscompletely filledto the weight of the paint when the vessel ispartially filled:
P'/P = 6V/13V = 6/13.
Answer: A.
Answer: (A) 6/13
Question: 2 numbers are there in the ratio 3:4. If 3 is to be added to both of the numbers the ratio will become 7:9 then find initial numbers?
(A) 18,24
(B) 15,12
(C) 3,2
(D) 21,22
(E) 40,12
Rationale: Let 2 numbers are 3x,4x
after adding 3 on both numbers 3x+3, 4x+3
3x+3:4x+3 = 7:9
9(3x+3) = 7(4x+3)
x = 6
Intial numbers = 3x,4x = 18,24
Answer is A
Answer: (A) 18,24
Question: Two trains of equal lengths take 10 sec and 14 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
(A) 10
(B) 12
(C) 13
(D) 11.7
(E) 15
Rationale: Speed of the first train = 120/10 = 12 m/sec.
Speed of the second train = 120/14 = 8.6 m/sec.
Relative speed = 12 + 8.6 = 20.6 m/sec.
Required time = (120 + 120)/20.6 = 11.7 sec.
Answer: Option D
Answer: (D) 11.7
Question: In a zoo, the ratio of the number of cheetahs to the number of pandas is 1 : 3 and was the same five years ago. If the increase in the number of cheetahs in the zoo since then is 6, then what is the increase in the number of pandas?
(A)  18
(B)  3
(C)  5
(D)  10
(E)  15
Rationale: One short cut to solve the problem is
c:p = 1:3
c increased to 7
=> 1:3 = 7:x
=> x = 21
=>p increased by 18
A is the answer
Answer: (A)  18
Question: A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec. fast at 2 p.m. on the following Monday. When was it correct?
(A) 2 p.m. on Tuesday
(B) 2 p.m. on Wednesday
(C) 3 p.m. on Thursday
(D) 1 p.m. on Friday
(E) None of these
Rationale: Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days 2 hours = 170 hours.
∴ The watch gains (2 + 44⁄5) min.
or 34⁄5 min. in 170 hrs.
Now, 34⁄5 min. are gained in 170 hrs.
∴ 2 min. are gained in (170 × 5⁄34 × 2)hrs. = 50 hrs
∴ Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e. it will be correct at 2 p.m. on Wednesday.
Answer B
Answer: (B) 2 p.m. on Wednesday
Question: Seven machines at a certain factory operate at the same constant rate. If six of these machines, operating simultaneously, take 35 hours to fill a certain production order, how many fewer hours does it take all seven machines, operating simultaneously, to fill the same production order?
(A) 4
(B) 5
(C) 7
(D) 10
(E) 12
Rationale: The total work is 6*35 = 210 machine hours
The time required for seven machines is 210/7 = 30 hours, thus 5 fewer hours.
The answer is B.
Answer: (B) 5
Question: A student got twice as many sums wrong as he got right. If he attempted 75 sums in all, how many did he solve correctly ?
(A) 25
(B) 16
(C) 18
(D) 24
(E) 26
Rationale: Explanation:
Suppose the boy got x sums right and 2x sums wrong.
Then, x + 2x = 75 3x = 75 x = 25.
Answer:A
Answer: (A) 25
Question: A does a work in 10 days and B does the same work in 30 days. In how many days they together will do the same work ?
(A) 5.5 days
(B) 6.5 days
(C) 7.5 days
(D) 8.5 days
(E) None of these
Rationale: Explanation:
Firstly we will find 1 day work of both A and B, then by adding we can get collective days for them,
So,
A's 1 day work = 1/10
B's 1 day work = 1/30
(A+B)'s 1 day work =
(1/10+1/30)=2/15
So together they can complete work in 7.5 days.
Answer: C
Answer: (C) 7.5 days
Question: Winners will be announced the following day at 9 AM Pacific/1 PM Eastern Time.
If A, X, Y, and Z are unique nonzero digits in the equation:
XY
*YX
____
AYZ
And Y > X, the 2-digit number XY = ?
(A) 13
(B) 21
(C) 23
(D) 24
(E) 25
Rationale: The reasoning is as follows:-
B) can't be answer because Y<X
D) can't be answer because it XY x YX will give 4 digit number. Thus wrong
E) can't be answer because it XY x YX will give 4 digit number. Thus wrong
A) can't be answer because it XY x YX will give 3 digit number but the middle digit will not be equal to Y. Thus wrong
C) is the correct answer because Y>xwill give 3 digit numbermiddle digit is Y
A
Answer: (A) 13
Question: The distance from City A to City B is 180 miles. While driving from City A to City B, Ed drives at a constant speed of 30 miles per hour. Flora leaves City A 2 hours after Ed. What is the minimum constant speed in miles per hour that Flora must exceed in order to arrive in City B before Ed?
(A) 35
(B) 40
(C) 45
(D) 50
(E) 55
Rationale: The time it takes Ed to drive to City B is 180 / 30 = 6 hours.
Flora needs to take less than 4 hours for the trip.
Flora needs to exceed a constant speed of 180 / 4 = 45 miles per hour.
The answer is C.
Answer: (C) 45
Question: Find the circumference and area of radius 4 cm.
(A) 24 cm²
(B) 44 cm²
(C) 50 cm²
(D) 84 cm²
(E) 94 cm²
Rationale: Area of circle = πr²
= 22/7 × 4 × 4 cm²
= 50 cm²
ANSWER:C
Answer: (C) 50 cm²
Question: If A:B = 1/2: 1/3 B:C = 1/2:1/3 then A:B:C?
(A) 2:4:5
(B) 1:2:7
(C) 9:6:4
(D) 3:6:9
(E) None
Rationale: Answer: Option C
A:B = 1/2:1/3 = 3:2
B:C = 1/2:1/3 = 3:2
A:B:C = 9:6:4
Answer: (C) 9:6:4
Question: A bookseller sells his books at a 25% markup in price. If he sells a book for $12.5, how much did he pay for it?
(A) $14.40
(B) $14.00
(C) $11.00
(D) $9.60
(E) $10.00
Rationale: Let the cost price of book = x
Selling price of book = 12.5$
Markup % = 25
(125/100)x = 12.5
=> x = 10
Answer E
Answer: (E) $10.00
Question: Raman mixed 44 kg of butter at Rs. 150 per kg with 36 kg butter at the rate of Rs. 125 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
(A) 129.25
(B) 287.25
(C) 194.25
(D) 188.25
(E) 112.25
Rationale: Explanation:
CP per kg of mixture = [44(150) + 36(125)]/(44 + 36) = Rs. 138.75
SP = CP[(100 + profit%)/100]
= 138.75 * [(100 + 40)/100] = Rs. 194.25
Answer:C
Answer: (C) 194.25
Question: A contractor hires 100 men to finish a job in 50 days. After 36 days, n men leave. After some more days, the contractor hires 2n more men to complete the job on time. For how many days did these 2n men work?
(A) 20
(B) 18
(C) 16
(D) 12
(E) 7
Rationale: Step1: Find Each day what % of work is finished ; it requires 50 days to complete which means each day 1/50= 2% work will be completed.
Step 2 : After 36 Days = 36* 2= 72% of work is finished. remaining is 28% ( which means if same 100 men were about to complete the job they would have required 14 more days)
Step3: Let us assume all people have left job. therefore contractor hires 2n people. initially it was taking 14 days to compete for n people. at present 2n people are present to finish job. hence 7 more days.
E
Answer: (E) 7
Question: One card is drawn at random from a pack of 52 cards. What is the probability that the card drawn is a face card?
(A) 1/13
(B) 4/13
(C) 1/4
(D) 9/52
(E) None
Rationale: Solution
Clearly, there are 52 cards, out of which there are 16 faces cards.
Therefore, P(getting a face card)
= 16/52
‹=›4/13.
Answer B
Answer: (B) 4/13
Question: Two pens and one eraser cost Rs. 35 and 3 pencil and four erasers cost Rs. 65. Find the cost of pencil and eraser separately.
(A) 5,15
(B) 15,5
(C) 5,10
(D) 10,5
(E) 20,5
Rationale: Let pen be x and eraser be y
Then 2x + y = 35 ……………(i)
And 3x + 4y = 65 ……………(ii)
Multiplying equation (i) by 4, and subtracting we get
5x = 75
x = 15
Substituting the value of x = 15 in equation (i) 2x + y = 35 we get;
2 × 15 + y = 35
30 + y = 35
y = 35 – 30
y = 5
Therefore, the cost of 1 pen is Rs. 15 and the cost of 1 eraser is Rs. 5. correct ans is B
Answer: (B) 15,5
Question: What is the decimal equivalent of (1/4)^5?
(A) 0.0016
(B) 0.0625
(C) 0.0001
(D) 0.25
(E) 0.5
Rationale: (1/4)^5 = 1/1024 =0.0001
Answer : C
Answer: (C) 0.0001
Question: A sells his house to B at a profit of 10% who in turn sells it to C at a profit of 15% who in turn Sells it to D at a profit of 25% and D sells it to E at 35% profit. If cost price of E’s house is Rs 35,00,000, what is the approximate cost price of A’s house?
Correct Show Answer
Explanation:
(A) Rs 15,40,000
(B) Rs 15,10,000
(C) Rs 15,00,000
(D) Rs 16,40,000
(E) Rs 17,40,000
Rationale: Let the cost price of A’s house = Rs X
Therefore, Cost price of E’s house
= 1.1 x 1.15 x 1.25 x 1.35 x X
Therefore, 3500000 = 1.1 x 1.15 x 1.25 x 1.35 x X
X = 3500000 / 1.1 x 1.15 x 1.25 x 1.35
= Rs 16,39,584.25
The nearest option is Rs 16,40,000.
ANSWER:D
Answer: (D) Rs 16,40,000
Question: If the area of a circle is 64pi square feet, find its circumference.
(A) 65 pi feet
(B) 43 pi feet
(C) 42 pi feet
(D) 18 pi feet
(E) 16 pi feet
Rationale: The area is given by pi * r * r. Hence
pi * r *r = 64 pi
r *r = 64 ; hence r = 8 feet
The circumference is given by
2 *pi *r = 2 * pi * 8 = 16 pi feet
correct answer E
Answer: (E) 16 pi feet
Question: If nn is a positive integer and (n+1)(n+3)(n+1)(n+3) is odd, then (n+2)(n+4)(n+2)(n+4) must be a multiple of which one of the following?
(A) 1
(B) 3
(C) 4
(D) 8
(E) 6
Rationale: (n+1)(n+3)(n+1)(n+3) is odd only when both (n+1)(n+1) and (n+3)(n+3) are odd. This is possible only when nn is even.
Hence, n=2mn=2m, where mm is a positive integer. Then,
(n+2)(n+4)=(2m+2)(2m+4)=2(m+1)2(m+2)=4(m+1)(m+2)(n+2)(n+4)=(2m+2)(2m+4)=2(m+1)2(m+2)=4(m+1)(m+2)
=4 * (product of two consecutive positive integers, one which must be even)=4 * (product of two consecutive positive integers, one which must be even) =4 * (an even number), and this equals a number that is at least a multiple of 8=4 * (an even number), and this equals a number that is at least a multiple of 8
Hence, the answer is (D).
Answer: (D) 8
Question: The average age of a husband and his wife was 23 years at the time of their marriage. After five years they have a one-year old child. The average age of the family now is
(A) 76 years
(B) 11 years
(C) 19 years
(D) 15 years
(E) 12 years
Rationale: Explanation:
Sum of the present ages of husband, wife and child = (23 * 2 + 5 * 2) + 1 = 57 years.
Required average = (57/3) = 19 years.
Answer: C
Answer: (C) 19 years
Question: If 5/(4 + 1/x) = 1, then x =
(A) 3
(B) 1
(C) 1/3
(D) -1/3
(E) -3
Rationale: The expression 5/(4 + 1/x) = 1 should have been equal to something .
If 5/(4 + 1/x) = 1
=>5x/(4x + 1 ) = 1
=> 5x = 4x + 1
=> x = 1
Correct Option : B
Answer: (B) 1
Question: Find the next number in the series ?
2 3/4 5/7 7/10 11/13 13/16 ?
(A) 18/20
(B) 17/16
(C) 18/40
(D) 17/19
(E) 11/29
Rationale: D
17/19
series is 2/1 3/4 5/7 7/10 11/13 13/16
Numerator is prime number series 2-3-5-7-11-13-17
and Denominator is +3 series 1-4-7-10-13-16-19
Answer: (D) 17/19
Question: A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
(A) 35
(B) 88
(C) 25
(D) 99
(E) 21
Rationale: Suppose pipe A alone takes x hours to fill the tank.
Then, pipes B and C will take x/2 and x/4 hours respectively to fill the tank.
1/x + 2/x + 4/x = 1/5
7/x = 1/5 => x = 35 hrs.
Answer: A
Answer: (A) 35
Question: The diluted wine contains only 8 liters of wine and the rest is water. A new mixture whose concentration is 30%, is to be formed by replacing wine. How many liters of mixture shall be replaced with pure wine if there was initially 32 liters of water in the mixture?
(A) 2
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: Explanation:
Wine Water
8L 32L
1 : 4
20 % 80% (original ratio)
30 % 70% (required ratio)
In ths case, the percentage of water being reduced when the mixture is being replaced with wine.
so the ratio of left quantity to the initial quantity is 7:8
Therefore , \frac{7}{8}=\left [ 1-\frac{K}{40} \right ]
\Rightarrow \frac{7}{8}=\left [ \frac{40-K}{40} \right ] \Rightarrow K= 5 l
Answer: B) 5
Answer: (B) 5
Question: A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :
(A) 7/14
(B) 7/15
(C) 7
(D) 8/15
(E) 8
Rationale: A's 1 day's work = 1/15
B's 1 day's work = 1 /20
(A + B)'s 1 day's work = ( 1/15 + 1/20 ) = 7 /60
(A + B)'s 4 day's work = (4*7)/60 = 7/15
Therefore, Remaining work = ( 1 - 7/15) = 8/15
So correct answer is D
Answer: (D) 8/15
Question: In an old fort, If 15 spiders make 15 webs in 15 days, then 1 spider will make 1 web in how many days?
(A) 1
(B) 15/2
(C) 15
(D) 225
(E) None of these
Rationale: Explanation :
Solution: Let the required number of days be x.. Then,
Less spiders, more days (IP)
Less webs, less days (DP)
.'. Spiders 1 : 15
} : : 15 : x
webs 15 : 1
.'. 1*15*x = 15*1*15 <=> x = 15.
Answer : C
Answer: (C) 15
Question: What will be the cost of building a fence around a square plot with area equal to 144 sq ft, if the price per foot of building the fence is Rs. 58?
(A) 2784
(B) 2287
(C) 2977
(D) 2668
(E) 1298
Rationale: Let the side of the square plot be a ft.
a2 = 144=> a = 12
Length of the fence = Perimeter of the plot = 4a = 48 ft.
Cost of building the fence = 48 * 58 = Rs. 2784.
Answer:A
Answer: (A) 2784
Question: The ratio of two quantities is 5 to 9. If each of the quantities is increased by 7, what is the ratio of these two new quantities?
(A) 14/15
(B) It cannot be determined from the information given.
(C) 15/19
(D) 21/22
(E) 11/12
Rationale: let the actual ratio be 5k/9k, increase numerator and denominator by 7=> 5k+7/9k+7
Until the value of k is unknown we can not determine the actual ratio.
OR
let the actual be 3/4. After increasing 7 => 10/11
let the actual be 6/8. After increasing 7 => 13/15
Therefore without actual quantities we cannot determine the actual ratio.
Answer : B
Answer: (B) It cannot be determined from the information given.
Question: A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.272 less than the sum lent. What was the sum lent?
(A) 400
(B) 278
(C) 289
(D) 500
(E) 821
Rationale: P - 272 = (P*4*8)/100
P = 400
Answer: A
Answer: (A) 400
Question: The sum of the two digits of a number is 10. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number?
(A) 298
(B) 28
(C) 26
(D) 99
(E) 21
Rationale: Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.
P + Q = 10 ----- (1)
(10Q + P) - (10P + Q) = 54
9(Q - P) = 54
(Q - P) = 6 ----- (2)
Solve (1) and (2) P = 2 and Q = 8
The required number is = 28,.Answer:B
Answer: (B) 28
Question: A man can row a boat at 28 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 60 km downstream?
(A) 30/83 hours
(B) 80/13 hours
(C) 30/17 hours
(D) 30/19 hours
(E) 32/13 hours
Rationale: Speed downstream = 28 + 6 = 34 kmph.
Time required to cover 60 km downstream
= d/s = 60/34
= 30/17 hours.
Answer:C
Answer: (C) 30/17 hours
Question: The average of 35 numbers is 25. If each number is multiplied by 5, find the new average?
(A) 125
(B) 298
(C) 267
(D) 260
(E) 182
Rationale: Sum of the 35 numbers = 35 * 25
= 875
If each number is multiplied by 5, the sum also gets multiplied by 5 and the average also gets multiplied by 5.
Thus, the new average = 25 * 5
= 125.
Answer:A
Answer: (A) 125
Question: In what time a sum of money double itself at 3% per annum simple interest?
(A) 33 1/9%
(B) 33 1/3%
(C) 33 7/3%
(D) 33 2/3%
(E) 33 8/3%
Rationale: P = (P*3*R)/100
R = 33 1/3%
Answer: B
Answer: (B) 33 1/3%
Question: 76.8% of my office colleges are non-vegetarian.
What's the least number of person working in my office to hold above statement true.
(A) 110 people
(B) 126 people
(C) 120 people
(D) 122 people
(E) 130 people
Rationale: B
126 people
125 people + Me
96/125 = 76.8
Answer: (B) 126 people
Question: how many such letters pairs are in word BONAFIDE having same no. of letters left between them in the word as they have in the series
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: Arranging BONAFIDE in order : ABDEFINO
Pairs are:-
1. AB
2. DE
3. DEF
4. EF
5. NO
So total of 5 pairs will be there.
ANSWER:C
Answer: (C) 5
Question: Two pipes can fill a tank in 10 hours & 12 hours respectively. While 3rd pipe empties the full tank n 20 hours. If all the three pipes operate simultaneously,in how much time will the tank be filled?
(A) 6 hrs 43 min
(B) 2 hrs 25 min
(C) 7 hrs 30 min
(D) 6 hrs 32 min
(E) 7 hrs 10 min
Rationale: tank filled in 1 hr = 1/10 + 1/12 - 1/20 = 8/60 = 2/15 part
so full tank is filled in 15/2 hrs = 7 hr 30 min..
ANSWER:C
Answer: (C) 7 hrs 30 min
Question: After 38 liters of petrol were poured into the tank, it was still 5% empty. How much petrol must be poured into the tank in order to fill it?
(A) 38 liters
(B) 40 liters
(C) 38.5 liters
(D) 2 liters
(E) 4 liters
Rationale: 95% ----------- 38
5% ------------ ? => 2 liters
ANSWER:D
Answer: (D) 2 liters
Question: Eggs are sold in packages of six or ten only. If Doris bought 70 eggs exactly, what could be the number of large packs Doris bought?
(A) 6.
(B) 2.
(C) 3.
(D) 5.
(E) 7.
Rationale: No strategy involved. Simple question demanding fast calculation.
10x7 = 70 =>
Ans E.
Good luck
Answer: (E) 7.
Question: A pet store regularly sells pet food at a discount of 10 percent to 30 percent from the manufacturer’s suggested retail price. If during a sale, the store discounts an additional 20 percent from the discount price, what would be the lowest possible price of a container of pet food that had a manufacturer’s suggested retail price o f $ 45.00?
(A) $ 10.00
(B) $ 11.20
(C) $ 14.40
(D) $ 25.20
(E) $ 18.00
Rationale: For retail price = $45
First maximum discounted price = 45 - 30% of 45 = 45-13.5 =31.5
Price after additional discount of 20% = 31.5 - 20% of 31.5 = 31.5 - 6.3 = 25.2
Answer: Option D
Answer: (D) $ 25.20
Question: The area of a square field is 24200 sq m. How long will a lady take to cross the field diagonally at the rate of 6.6 km/hr?
(A) 3 minutes
(B) 0.04 hours
(C) 2 minutes
(D) 2.4 minutes
(E) 2 minutes 40 seconds
Rationale: Explanatory Answer
Step 1: Compute the length of the diagonal of the square
Let 'a' meters be the length of a side of the square field.
Therefore, its area = a2 square meters. --- (1)
The length of the diagonal 'd' of a square whose side is 'a' meters = √2 a --- (2)
From (1) and (2), we can deduce that the square of the diagonal = d2 = 2a2 = 2(area of the square)
Or d = √2 * area meters.
d =√2∗24200=48400 = 220 m.
Step 2: Compute the time taken to cross the field
The time taken to cross a distance of 220 meters while traveling at 6.6 kmph = 220 m/6.6 kmph
Convert unit of speed from kmph to m/min
1 km = 1000 meters and 1 hour = 60 minutes. So, 6.6 kmph = 6.6∗1000/60 m/min = 110 m/min
∴ time taken = 220/110= 2 minutes
Choice C
Answer: (C) 2 minutes