mathewhe/aqua_rat huggingface dataset:
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
(A) 243 m
(B) 240 m
(C) 245 m
(D) 249 m
(E) 242 m
Rationale: Speed =45 x5/18 m/sec=25/2m/sec.
Time = 30 sec.
Let the length of bridge be x metres.
Then,130 + x/30=25/2
2(130 + x) = 750
x = 245 m.
Answer C
Answer: (C) 245 m
Question: In a company the manager wants to give some gifts to all of the workers. In each block there are about 200 workers are there. The total amount for giving the gifts for all the workers is $6000. The worth of the gift is 2$. How many blocks are there in the company?
(A) 10
(B) 12
(C) 18
(D) 20
(E) 15
Rationale: Each employee will get a gift worth of = $2
total employees = 6000/2 = 3000
total blocks = 3000/200 = 15
correct option is E
Answer: (E) 15
Question: A sells a bike to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays Rs. 225 for it, the cost price of the bike for A is:
(A) 150
(B) 230
(C) 120
(D) 430
(E) 200
Rationale: A
125% of 120% of A = 225
125/100 * 120/100 * A = 225
A = 225 * 2/3 = 150.
Answer: (A) 150
Question: A train covers a distance in 50 min, if it runs at a speed of 48kmph on an average. The speed at which the train must run to reduce the time of journey to 40min will be
(A) 47 kmph
(B) 60 kmph
(C) 69 kmph
(D) 37 kmph
(E) 80 kmph
Rationale: B
60 kmph
Time = 50/60 hr = 5/6hr
Speed = 48mph
distance = S*T = 48 * 5/6 = 40km
time = 40/60hr = 2/3hr
New speed = 40* 3/2 kmph = 60kmph
Answer: (B) 60 kmph
Question: The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 30 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam.
(A) 22
(B) 27
(C) 25
(D) 99
(E) 30
Rationale: Let the number of students who wrote the exam be x.
Total marks of students = 80 x.
Total marks of (x - 5) students = 90(x - 5)
80x - (5 * 30) = 90(x - 5)
300 = 10x => x = 30.Answer: E
Answer: (E) 30
Question: A certain collage has total of 600 seniors each majoring in exactly one of six subjects. A minimum of 20 seniors major in each six subjects. If three quarter of the seniors major in one of four subjects, what is the greatest possible number of seniors majoring in one of the other two subjects?
(A) 100
(B) 130
(C) 75
(D) 60
(E) 50
Rationale: Answer B
600 = 450 + 20 + x => x = 130
= 3/4 * 600 in 4 subjects + 20 min for 5th subject + x = 600
Answer: (B) 130
Question: Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 1.5% more. She would get how much?
(A) 9560
(B) 96288
(C) 26667
(D) 1662
(E) 2882
Rationale: (8000*3*1.5)/100 = 360
9200
--------
9560
Answer:A
Answer: (A) 9560
Question: A textile worker’s wages are increased by 10% and afterwards decreased by 10 %. Find the change percentage in his wages.
(A) 1% decrease
(B) 2% decrease
(C) 5% decrease
(D) 7% decrease
(E) 8% decrease
Rationale: Explanation:
Let workers wages = X
A 10% increase would mean new wages
= (110/100) X
A 10% decrease would mean new wages
= (90/100) (110/100 X)
= 99/100 X which means a decrease of 1 %
ANSWER: A
Answer: (A) 1% decrease
Question: One week, a certain truck rental lot had a total of 18 trucks, all of which were on the lot Monday morning. If 50% of the trucks that were rented out during the week were returned to the lot on or before Saturday morning of that week, and if there were at least 12 trucks on the lot that Saturday morning, what is the greatest number of different trucks that could have been rented out during the week?
(A) 18
(B) 16
(C) 12
(D) 8
(E) 4
Rationale: N - Not rented trucks; R - Rented trucks
N + R = 18
N + R/2 = 12
R = 12
C
Answer: (C) 12
Question: In a village of 2,600 people, 800 people are over 70 years old and 850 people are female. It is known that 40 percent of the females are younger than 70 years old. If no one in the village is 70 years old, what is the probability that a person chosen at random is either a female or younger than 70 years old?
(A) 231/260
(B) 117/130
(C) 51/65
(D) 23/32
(E) 11/16
Rationale: The number of people younger than 70 years old is 2600-800 = 1800
The number of females older than 70 years old is 0.6*850 = 510
The number of people who are either female or younger than 70 is 1800+510 = 2310.
P(a person is younger than 70 or male) = 2310/2600 = 231/260
The answer is A.
Answer: (A) 231/260
Question: A manufacturer of a certain product can expect that between 0.4 percent and 0.5 percent of the units manufactured will be defective. If the retail price is $2,500 per unit and the manufacturer offers a full refund for defective units, how much money can the manufacturer expect to need to cover the refunds on 20,000 units?
(A)  Between $15,000 and $25,000
(B)  Between $30,000 and $50,000
(C)  Between $200,000 and $250,000
(D)  Between $150,000 and $250,000
(E)  Between $300,000 and $500,000
Rationale: Number of defective units is between = .4 % of 20000 and .5% of 20000
= 80 and 100
Retail Price per unit = 2500 $
Expected price of refund is between = 2500 x 80 and 2500 x 100
=2,00,000 and 2,50,000 dollars
Answer C
Answer: (C)  Between $200,000 and $250,000
Question: Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is
(A) 17/28
(B) 17/27
(C) 17/19
(D) probability of 17/20
(E) 17/22
Rationale: n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(EᴜP) = 10/20 + 8/20 - 1/20 = 17/20
Answer: D
Answer: (D) probability of 17/20
Question: A certain factory produces buttons and buckles at a uniform weight. If the total weight of 2 buttons and 2 buckles is one third of 11 buckles and 3 buttons, then the weight of 3 buttons and 4 buckles is how many times that of 5 buckles and 6 buttons?
(A) 7/15.
(B) 4/9.
(C) 6/11.
(D) 3/5.
(E) 8/15.
Rationale: 2buttons + 2buckles = 1/3(11buckles + 3buttons)
6buttons + 6buckles = 11buckles + 3buttons
3buttons = 5buckles
Weight of 3buttons and 4buckles = 5buckles + 4buckles = 9buckles
Weight of 6buttons and 5buckles = 10buckles + 5buckles = 15buckles
(3buttons and 2buckles) = x * (6buttons and 5buckles)
9 = x*15
x = 9/15=3/5
Answer: D
Answer: (D) 3/5.
Question: A truck travels 20 miles due north, 30 miles due east, and then 20 miles due north. How many miles is the truck from the starting point?
(A) 20.3
(B) 44.7
(C) 50
(D) 70
(E) 120
Rationale: We have two right angle triangles with sides 20 and 15
The distance between starting and end point = sum of the hypotenuse of both the triangles.
Hypotenuse = [400 + 225]^(1/2) = 25
Hence the total distance between end point and starting point = 25 + 25 = 50
Correct Option: C
Answer: (C) 50
Question: what is the next term of this series6,10,9,15,..?
(A) 9
(B) 10
(C) 11
(D) 12
(E) 15
Rationale: 3&2=6;
5*2=10;
3*3=9;
3*5=15.
3*4=12
ANSWER:D
Answer: (D) 12
Question: Suppose you answer the last three questions on this test at random. What is the most likely
number of these three questions that you will answer correctly?
(A) 0
(B) 1
(C) 2
(D) 3
(E) it is impossible to determine
Rationale: There are five answers to each question The probabilities you will correctly answer
respectively 0, 1, 2, and 3 are
4/5
4/5
4/5
=
64/125
;
3
1/5
4/5
4/5
=
48/125
;
3
1/5
1/5
4/5
=
12/125
;
1/5
1/5
1/5
=
1/125
:
The first is the most likely possibility. Indeed, it is more probable than the other three combined
correct answer A
Answer: (A) 0
Question: A customer went to a shop and paid a total of $30, out of which $1.28 was for sales tax on taxable purchases. If the tax rate was 8%, then what was the cost of the tax free items?
(A) $9.84
(B) $10.68
(C) $11.26
(D) $12.72
(E) $13.54
Rationale: The total cost was $30.
The tax was $1.28
Let the original price of the taxable items = x
Given that tax rate = 8%
0.08x = 1.28
x = $16
The cost of the tax free items was $30 - $16 - $1.28 = $12.72
The answer is D.
Answer: (D) $12.72
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 20%?
(A) 20%
(B) 70%
(C) 80%
(D) 40%
(E) 10%
Rationale: Explanation:
SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20%
Answer: A
Answer: (A) 20%
Question: In a college, 280 students study Hindi, 254 students study Sanskrit and 280 students study English.
97 students study Hindi as well as physics, 138 students study Sanskrit as well as English and 152 students study Hindi as well as English.
73 students study all the three languages.
How many total number of students are there in that college?
(A) 350
(B) 500
(C) 650
(D) 235
(E) 450
Rationale: B
Answer: (B) 500
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:
(A) 100 m
(B) 125 m
(C) 130 m
(D) 150 m
(E) 170 m
Rationale: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 25 = x / 15
x = 150 m.
ANSWER:D
Answer: (D) 150 m
Question: In covering distance,the speed of A & B are in the ratio
of 3:4.A takes 30min more than B to reach the destion.The time
taken by A to reach the destinstion is.
(A) 4 hrs
(B) 9 hrs
(C) 3 hrs
(D) 5 hrs
(E) 2 hrs
Rationale: Ratio of speed = 3:4
Ratio of time = 4:3
let A takes 4x hrs,B takes 3x hrs
then 4x-3x = 30/60 hr
x = ½ hr
Time taken by A to reach the destination is 4x = 4 * ½ = 2 hr
Answer is E.
Answer: (E) 2 hrs
Question: Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 35 kmph. Of how many minutes does the train stop per hour?
(A) E982
(B) 27
(C) 12
(D) 121
(E) 13.3
Rationale: Explanation:
T = 10/45 * 60 = 13.3
Answer: Option E
Answer: (E) 13.3
Question: 5 blue marbles, 3 red marbles and 4 purple marbles are placed in a bag. If 4 marbles are drawn without replacement, what is the probability that the result will not be 2 blue and 2 purpl e marbles?
(A) 4/33
(B) (5/36)^2
(C) 1/2
(D) (31/36)^2
(E) 29/33
Rationale: Answer is 29/33.
The probability of 2 blue and 2 purple marbles selected is 5C2.4C2/12C4 =4/33.
Subtracting the above from 1 we get 29/33 E
Answer: (E) 29/33
Question: Find the simple interest on $1200 for 5 years at 20% per annum?
(A) $1200
(B) $1000
(C) $500
(D) $1100
(E) $1500
Rationale: SI = PTR/100
= 1200*5*20/100 = $1200
Answer is A
Answer: (A) $1200
Question: 23, 29, 31, 37, 41, 43, 47, (...)
(A) 53
(B) 47
(C) 48
(D) 59
(E) 45
Rationale: Explanation :
All are prime numbers in their order, starting from 23
Hence, next number is 53
Answer : A
Answer: (A) 53
Question: Sagar purchased 10 kg of rice at the rate of Rs. 15 per kg and 25 kg of rice at the rate Rs. 14 per kg. He mixed the two and sold the mixture. Approximately at what rate per kg should he sell the mixture to make 40 % profit in the transaction?
(A) Rs. 20.00
(B) Rs. 20.08
(C) Rs. 20.02
(D) Rs. 20.008
(E) Rs. 20.021
Rationale: Explanation:
Rice variety	Quantity(Kg)	Rate(Rs/Kg)	Cost(in Rs)
First	10	15	150
Second	25	14	350
Total	500
By 40% profit on cost price,
Selling price of mixture = 140/100 * 500
= Rs. 700
Therefore, selling price per kg of mixture = 700/35 = Rs. 20'
ANSWER:A
Answer: (A) Rs. 20.00
Question: Three bells commence tolling together and toll at intervals of 3,6,9 seconds respectively. In 60 minutes, how many times do they toll together?
(A) 4
(B) 10
(C) 15
(D) 21
(E) 17
Rationale: L.C.M of 3,6,9 is 18. i.e after each 3 min they will toll together.So in 60 min they will toll 20 times.As they have initially tolled once,The answer will be 20+1=21.
ANSWER:D
Answer: (D) 21
Question: The product of two consecutive negative even integers is 24. Find the numbers.
(A) -2, -4
(B) -10, -12
(C) -6, -8
(D) -4, -6
(E) -12, -14
Rationale: (n)(n + 2) = 24
n2 + 2n = 24
n2 + 2n – 24 = 0
(n + 6)(n – 4) = 0
Then the solutions are n = –6 and n = 4. Since the numbers I am looking for are negative, I can ignore the "4" and take n = –6. Then the next number is n + 2 = –4
Answer: D
Answer: (D) -4, -6
Question: In how many ways can a three-letter password be chosen, using the letters A, B, C, D, E, and/or F, such that at least one letter is repeated within the password?
(A) 72
(B) 86
(C) 90
(D) 96
(E) 1,296
Rationale: Total number of four letter passwords = 6*6*6= 216 ------(1)
Total number of passwords in which no letter repeats = 6C3*3!= 20*6=120------(2)
therefore required value = (1)-(2)= 216-120=96
D
Answer: (D) 96
Question: A bag contains 7 green and 8 white balls. If two balls are drawn simultaneously, the probability that both are of the same colour is ?
(A) 7/17
(B) 7/22
(C) 7/18
(D) 7/19
(E) 7/15
Rationale: Drawing two balls of same color from seven green balls can be done in ⁷C₂ ways.
Similarly from eight white balls two can be drawn in ⁸C₂ ways.
P = 7C2/¹15C2 + 8C2/15C2
= 7/15
Answer: E
Answer: (E) 7/15
Question: If b < 2 and 2x - 4b = 0, which of the following must be true?
(A) x > -3
(B) x < 4
(C) x = 3
(D) x < 5
(E) D. x > 3
Rationale: 2x - 4b = 0
Therefore, 2x = 4b
As, b<2
2x < 4(2)
i.e x < 4
Answer : B
Answer: (B) x < 4
Question: find value for x from given equation? x + 1 = -3
(A) 1
(B) -x=-4
(C) -3
(D) -5
(E) 5
Rationale: 1. Subtract 1 from both sides:
x + 1 - 1 = -3 - 1
2. Simplify both sides:
x = -4
B
Answer: (B) -x=-4
Question: In how many ways can 10 people line up at a ticket window of a railway station?
(A) 36,28,800
(B) 34,82,800
(C) 33,44,800
(D) 33,28,800
(E) None of these
Rationale: The required number of ways = number of permutations of 10 people taking all 10 at a time.
P(10, 10) = 10!
= 10 x 9 × 8 x 7 x 6 × 5 x 4 x 3 × 2 x 1
= 36,28,800
ANSWER:A
Answer: (A) 36,28,800
Question: The cost of 10 kg of apples is equal to the cost of 24 kg of rice. The cost of 6 kg of flour equals the cost of 2 kg of rice. The cost of each kg of flour is Rs.20.50. Find the total cost of 4 kg of apples, 3 kg of rice and 5 kg of flour?
(A) 877.49
(B) 877.4
(C) 877.45
(D) 877.41
(E) 877.43
Rationale: :
Let the costs of each kg of apples and each kg of rice be Rs.a and Rs.r respectively.
10a = 24r and 6 * 20.50 = 2r
a = 12/5 r and r = 61.5
a = 147.6
Required total cost = 4 * 147.6 + 3 * 61.5 + 5 * 20.5
= 590.4 + 184.5 + 102.5 = Rs.877.40
Answer: B
Answer: (B) 877.4
Question: The population of a town is 8000. It decreases annually at the rate of 20% p.a. What will be its population after 3 years?
(A) 5100
(B) 4096
(C) 5200
(D) 5400
(E) 5500
Rationale: Formula :
( After =100 denominator
Ago = 100 numerator)
8000 Ã— 80/100 Ã— 80/100 x 80/100= 4096
Answer : B
Answer: (B) 4096
Question: In a certain country, 60 percent of the population likes basketball, and 35 percent of the population likes both basketball and golf. What percentage of the people who like basketball also like golf?
(A) 20%
(B) 33%
(C) 40%
(D) 58%
(E) 67%
Rationale: Correct Answer: (D).
Since this is a percent problem without concrete numbers, we can assign our own. If we assume that there are 100 people in the country, then 60 people like basketball, and 35 people like basketball and golf. We’re looking for people who like both divided by people who like basketball, so 35/60 = 58%, or choice D.
Answer: (D) 58%
Question: Sum of two number = 16 and product = 48, find the difference of the two number ??
(A) 1
(B) 3
(C) 4
(D) 5
(E) 8
Rationale: (X-Y)2 = (X+Y)2 - 4 XY
(X-Y)2 = (16)2 - 4 x 48
(X-Y)2 = 256 - 192
(X-Y)2 = 64
X-Y = 8
ANSWER E
Answer: (E) 8
Question: The average age of a husband and a wife is 23 years when they were married five years ago but now the average age of the husband, wife and child is 20 years(the child was born during the interval). What is the present age of the child?
(A) 6
(B) 5
(C) 8
(D) 4
(E) 2
Rationale: 28 * 2 = 56
20 * 3 = 60
-----------
4 years.Answer: D
Answer: (D) 4
Question: Excepting ‘seldom’ which means – rarely, infrequently and not often, is the antonym.
(A) 22
(B) 278
(C) 267
(D) 176
(E) 971
Rationale: Answer:D
Answer: (D) 176
Question: A pharmaceutical company received $4 million in royalties on the first $50 million in sales of and then $12 million in royalties on the next $170 million in sales. By approximately what percentage did the ratio of royalties to sales decrease from the first $50 million in sales to the next $170 million in sales?
(A) 12%
(B) 15%
(C) 45%
(D) 52%
(E) 56%
Rationale: (12/170)/(4/50) = 15/17 = 88% it means that 12/170 represents only 88%. Therefore a decrease of 12%.
Answer A
Answer: (A) 12%
Question: Which of the following must be true?
1) Every prime number greater than 5 can be written as either as 9n+1 or 9n-1
2) Every prime number greater than 5 can be written as 4n+1 or 4n-1
3) Every number greater than 5 of the form 9n+1 or 9n-1 is a prime number.
(A) 1,2
(B) 2,3
(C) 1,2,3
(D) only 1
(E) only 2
Rationale: Every prime number greater than 3 can be written in the form of 9n+1 or 9n-1 where n is an integer. So 1 can be possible.
3. This is not possible as 2 and 3 are being prime , we can't write then in the form of 9n+1 or 9n-1.
A
Answer: (A) 1,2
Question: A man saves Rs. 200 at the end of each year and lends the money at 5% compound interest. How much will it become at the end of 3 years?
(A) Rs.662.08
(B) Rs.662.11
(C) Rs.662.02
(D) Rs.662.91
(E) Rs.662.01
Rationale: Amount = [200(1 + 5/100)3 + 200(1 + 5/100)2 + 200(1 + 5/100)]
= [200 * 21/20(21/20 * 21/20 + 21/20 + 1)] = Rs. 662.02
Answer:C
Answer: (C) Rs.662.02
Question: Cost Price of 2 cats are $30,000. By selling 1 at a loss of 15% and other at a profit of 19%, he found that SP of both cats is the same. Find the CP of each?
(A) $10,000
(B) $10,200
(C) $11,800
(D) $12,100
(E) $12,500
Rationale: Let the C.P of 1st buffalo = x
∴C.P of 2nd buffalo = 30,000 - x
S.P of 1st buffalo = ( 100 - loss% )
------------------- x C.P
100
S.P = 100 - 15x
-----------= 85x/ 100
100
S.P of 2nd buffalo = ( 100 - Profit%)
--------------------- x C.P
100
S.P = (100 + 19)(30,000- x) 119(30,000 -x)
-------------------- = ----------------
100 100
S.P of 1st buffalo = S.P of 2nd buffalo
85x/ 100 = 119 ( 30,000 - x)/ 100
⇒ 85x = 119(30,000 - x)
⇒ 85x = 3,570,000 - 119x
⇒ 85x + 119 x = 3,570,000
⇒ 204x = 3,570,000
⇒ x = 3,570,000 / 204
⇒ x = $17,500
C.P of 1st buffalo = $17,500
C.P of 2nd buffalo = 30,000 - 17,500 = $12,500
E
Answer: (E) $12,500
Question: In a renowned city, the average birth rate is 7 people every two seconds and the death rate is 1 people every two seconds. Estimate the size of the population net increase that occurs in one day.
(A) 32,300
(B) 172,800
(C) 468,830
(D) 338,200
(E) 259,200
Rationale: Every 2 seconds, 6 persons are added (7-1). Every second 3 persons are added.
In a day 24hrs = 24 * 60 Minutes = 24 * 60 * 60 = 86400 seconds.
86400 * 3 = 259200
Option E
Answer: (E) 259,200
Question: 34 : 43 :: 25 :?
(A) 49
(B) 52
(C) 36
(D) 64
(E) 56
Rationale: Ans 52
Reverse of 25
ANSWER:B
Answer: (B) 52
Question: If f is the smallest positive integer such that 3,150 multiplied by f is the square of an integer, then f must be
(A)  2
(B)  5
(C)  6
(D)  7
(E)  14
Rationale: Solution:
This problem is testing us on the rule that when we express a perfect square by its unique prime factors, every prime factor's exponent is an even number.
Let’s start by prime factorizing 3,150.
3,150 = 315 x 10 = 5 x 63 x 10 = 5 x 7 x 3 x 3 x 5 x 2
3,150 = 2^1 x 3^2 x 5^2 x 7^1
(Notice that the exponents of both 2 and 7 are not even numbers. This tells us that 3,150 itself is not a perfect square.)
We also are given that 3,150 multiplied by f is the square of an integer. We can write this as:
2^1 x 3^2 x 5^2 x 7^1 x f = square of an integer
According to our rule, we need all unique prime factors' exponents to be even numbers. Thus, we need one more 2 and one more 7. Therefore, y = 7 x 2 = 14
Answer is E.
Answer: (E)  14
Question: 4/x + 5x = 5(x-8)
(A) -9
(B) -1/3
(C) -1/9
(D) -1/10
(E) 9
Rationale: We can solve - expand the right side, multiply by x on both sides and then subtract away the 5x^2 terms:
(4/X) + 5x = 5(x-8)
(4/x) + 5x = 5x - 40
4 + 5x^2 = 5x^2 - 40x
4 = -40x
-1/10 = x
and to confirm, you can plug that answer back into the original equation to see that it makes the left and right sides equal.
D
Answer: (D) -1/10
Question: The average age of three boys is 15 years and their ages are in proportion 3:5:7. What is the age in years of the youngest boy?
(A) 8
(B) 9
(C) 7
(D) 6
(E) 5
Rationale: 3x + 5x + 7x = 45
x =3
3x = 9
Answer:B
Answer: (B) 9
Question: A number is doubled and 15 is added. If resultant is trebled, it becomes 75. What is that number
(A) 8
(B) 10
(C) 5
(D) 14
(E) 7
Rationale: Explanation:
=> 3(2x+15) = 75
=> 2x+15 = 25
=> x = 5
Option C
Answer: (C) 5
Question: Two trains of length 100 m and 160 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?
(A) 18 sec
(B) 70 sec
(C) 13 sec
(D) 20 sec
(E) 19 sec
Rationale: Relative speed = (42 + 30) * 5/18 = 4 * 5
= 20 mps.
Distance covered in passing each other
= 100 + 160 = 260 m.
The time required = d/s
= 260/20
= 13 sec.
Answer: C
Answer: (C) 13 sec
Question: In how many ways can 5 people be arranged in a circle?
(A) 2!
(B) 5!
(C) 4!
(D) 3!
(E) 6!
Rationale: (5−1)!=4!=24 ways
Ans - C
Answer: (C) 4!
Question: What ratio must a shopkeeper mix Peas and Soybean of Rs.16 and Rs. 25/kg, As to obtain a mixture of Rs.21.50 ?
(A) 10 : 7
(B) 9 : 8
(C) 7 : 11
(D) 13 : 11
(E) 14 : 8
Rationale: Correct option: (C)
Use rule of alligation, to determine the ratio
The required ratio of Soybean and Peas = 3.50 : 5.50 = 7:11
Answer: (C) 7 : 11
Question: A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 204, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?
(A) 22
(B) 33
(C) 36
(D) 77
(E) 88
Rationale: Let f = pure fuji , g = pure gala and c - cross pollinated.
c = 10% of x where x is total trees.
c = .1x
also 3x/4 = f and c+f = 204 => .1x + 3/4x = 204 => x = 240
240 - 204 = pure gala = 36.
C
Answer: (C) 36
Question: two friends A,B are running up hill and then to get down! length if road is 440 yards A on his return journey met B going up at 20 yards from top, A has finished the race .5 minute earlier than B, then how much time A had taken to complete the race.
(A) 55 minutes
(B) 95 minutes
(C) 105 minutes
(D) 115 minutes
(E) 125 minutes
Rationale: A gains 20 yards over B in it's down the hill journey. So for entire journey A will have a lead of 40 yards over B.
now, when A is at destination B is 40 yards behind which B will cover in 5 minutes.
so, by unitary method we get..
For B, 40 yards in 5 minutes
therefore,1 yard in 5/40 minutes
therefore,880 yards in (5/40)*880=110 minutes.
Now b takes 110 minutes so A will take 105 minutes.
ANSWER:C
Answer: (C) 105 minutes
Question: Which of the following is not a leap year ?
(A) 700
(B) 800
(C) 1200
(D) 2000
(E) 500
Rationale: Solution
The century divisible by 400 is a leap year.
∴ The year 700 is not a leap year. Answer A
Answer: (A) 700
Question: Ramu bought an old car for Rs. 42000. He spent Rs. 13000 on repairs and sold it for Rs. 64900. What is his profit percent?
(A) 22
(B) 77
(C) 18
(D) 99
(E) 88
Rationale: Total CP = Rs. 42000 + Rs. 13000 = Rs. 55000 and SP = Rs. 64900
Profit(%) = (64900 - 55000)/55000 * 100 = 18%
Answer: C
Answer: (C) 18
Question: Ann can have her bicycle repaired for $50, or she can trade it in, as is, and receive $22 credit toward the purchase of a new bicycle that sells for $107. If Ann trades in her current bicycle, the cost to her of purchasing the new bicycle is what percent greater than the cost of having her current bicycle repaired?
(A) 44%
(B) 60%
(C) 70%
(D) 114%
(E) 170%
Rationale: The cost for repair is $50;
The cost of new bicycle is $107-$22=$85;
So, the cost to Ann of purchasing the new bicycle is 85−50/50∗100=70 greater than the cost of having her current bicycle repaired.
Answer: C.
Answer: (C) 70%
Question: The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is?
(A) 6 kilometre per hour
(B) 8 kmph
(C) 9 kmph
(D) 10 kmph
(E) 3 kmph
Rationale: S = 1
M = x
DS = x + 1
US = x - 1
35/(x + 1) + 35/ (x - 1) = 12
x = 6
Answer:A
Answer: (A) 6 kilometre per hour