mathewhe/aqua_rat huggingface dataset:
Question: A woman has two blouses of different colors, three skirts of different colors, and two different pairs of shoes. She refuses to wear her pink blouse with her green skirt. How many different blouseskirt-shoe combinations could she wear?
(A) 8
(B) 10
(C) 16
(D) 17
(E) 18
Rationale: total ways = 2*3*2=12..
now its better to find the ways in which the pink blose and green skirty are together and subtract from total to get the answer..
the ways in which the pink blose and green skirty are together=1*1*2=2..
total ways =12-2=10..
B
Answer: (B) 10
Question: A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm^3, then the weight of the pipe is:
(A) 3.6 kg
(B) 3.696 kg
(C) 36 kg
(D) 36.9 kg
(E) 3.06 kg
Rationale: External radius = 4 cm,
Internal radius = 3 cm.
Volume of iron=(22/7	x [(4)^2 - (3)^2] x 21) cm^3
(22/7x 7 x 1 x 21)cm^3
462 cm^3.
Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.
ANSWER B
Answer: (B) 3.696 kg
Question: A train passes a station platform in 34 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
(A) 228
(B) 210
(C) 188
(D) 266
(E) 281
Rationale: The speed of the train is 54 * 5/18 m/s = 15 m/s
The length of the train is 15 x 20 = 300 m
platform + 300 = 15 * 34
platform = 510 - 300 = 210
The answer is B.
Answer: (B) 210
Question: One computer can upload 120 megabytes worth of data in 6 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 42 seconds. How long would it take for the second computer, working on its own, to upload 120 megabytes of data?
(A)  6
(B)  7
(C)  9.13
(D)  11
(E)  13
Rationale: Since the first computer can upload 120 megabytes worth of data in 6 seconds then in 6*7=42 seconds it can upload 7*120=840 megabytes worth of data, hence the second compute in 42 seconds uploads 1300-840=460 megabytes worth of data. The second computer can upload 120 megabytes of data in 9.13 seconds.
Answer: C.
Answer: (C)  9.13
Question: How many two-digit numbers yield a remainder of 1 when divided by both 6 and 15?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
Rationale: Easier to start with numbers that are of the form 15p+1 ---> 16,31,46,61,76,91.
Out of these 2 (31,61) are also of the form 6q+1. Thus 2 is the answer. C is the correct answer.
Answer: (C) 2
Question: At a small company, 76 percent of the employees are women, and 60 percent of the employees are married. If 2/3 of the men are single, what fraction of the women are married?
(A) 13/19
(B) 1/3
(C) 9/20
(D) 7/10
(E) 5/7
Rationale: Lets take total employees are 100.
Given that,Total Women= 76 and Total Married = 60.
Total Men = 100 - 76 = 24 and Single men = 2/3*24 = 16.
Married men = total men - single men = 24 - 16 = 8.
Married women= Total married - Married men = 60 - 8 = 52.
Fraction of women are married = Married women / Total Women = 52 / 76 = 13/19. ANS A
Answer: (A) 13/19
Question: If CD represents a positive two digit number, where C and D are single digit integers, which of the following cannot be true?
(A) C+D =9
(B) (C)(D)=9
(C) C-D = 9
(D) D-C= 9
(E) C/D = 9
Rationale: (A) CD = 45 or 63 or 27
(B) CD = 33 or 19
(C) 90
(D) impossible
(E) CD = 91
(D) is impossible because 09 is not a valid two digit number --- if there's a zero in the ten's place, that's just 9, a single digit number. Therefore, no valid two digit number would satisfy (D).
ans D
Answer: (D) D-C= 9
Question: 8^100 is divisible by 17. Find the remainder for this?
(A) 10
(B) 12
(C) 16
(D) 17
(E) 19
Rationale: This is an extremely difficult problem to solve with out Fermat's little theorem. By applying Fermat's little theorem , We know that 816 when divided by 17, the remainder is 1.
So divide 100 by 16 and find the remainder. Remainder = 4
Therefore, 100 = (16 × 6) + 4
Now this problem can be written as 810017 = 816×6+417 = (816)6×8417
Now this problem simply boils down to (1)6×8417 = 8417
84 = 82×82, we need to find the remainder when 64 × 64 is divisible by 17. Or 13 × 13 = 169. When 169 is divided by 17, remainder is 16.
C
Answer: (C) 16
Question: The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
(A) 10 kmph
(B) 22 kmph
(C) 77 kmph
(D) 66 kmph
(E) 99 kmph
Rationale: Speed of the boat in still water = (60+80)/2 = 70 kmph. Speed of the stream
= (80-60)/2
= 10 kmph.
Answer:A
Answer: (A) 10 kmph
Question: A single letter is selected at random from the word 'SIM'. The probability that it is a vowel is..??
(A) 2/11
(B) 3/11
(C) 4/11
(D) 1/3
(E) 1
Rationale: total vowels = 1, total number of letters = 3
so probability = 1/3
ANSWER:D
Answer: (D) 1/3
Question: In year Y imported machine tools accounted for 25 percent of total machine - tool sales in the United States, and Japanese imports accounted for 55 percent of the sales of imported machine tools. If the total sales of machine tools imported Japan that year was x billion dollars, then the total sales of all machine tools in the United States was how many billion dollars?
(A) 9X/80
(B) 13X/20
(C) 80/9X
(D) 20X/13
(E) 80X/11
Rationale: IMT = 0.25T
JI = 0.55 IMT
0.55 IMT = $x b
IMT = $x/(0.55) b
T = 4*IMT = 4x/0.55 = 4x*100/55 = 80x/11
Ans: "E"
Answer: (E) 80X/11
Question: In 2000, a town had 1300 males and 1400 females. In 2015, the same town had 56500 males and 60000 females. By approximately what percent did the ratio of males to females increase from 2000 to 2015.
(A) 0.4%
(B) 0.7%
(C) 0.9%
(D) 1.1%
(E) 1.4%
Rationale: 2000: males/females = 1300/1400 =3900/4200
2015: males/females = 56500/60000 =3955/4200
ASIDE: It's useful to write both ratios with the same denominator. This allows us to IGNORE the denominator and focus solely on the numerators.
So, our ratio went from 3900/4200 to 3955/4200
Ignoring the denominators, we went from 3900 to 3955
The percent change = 100(difference in values)/(original value)
= (100)(3955-3900)/3900
= (100)(55)/3900)
= (100)(0.0141)
≈ 1.41...
Answer: E
Answer: (E) 1.4%
Question: A train 600 meters long is running with a speed of 50 kmph. The time taken by it to cross a tunnel 170 meters long is?
(A) 287 sec
(B) 288 sec
(C) 55 sec
(D) 16 sec
(E) 17 sec
Rationale: D = 600 + 170 = 770
S = 50 * 5/18 = 14 mps
T = 770/14 = 55 sec
Answer: C
Answer: (C) 55 sec
Question: Which one the following fractions has the smallest value?
(A) 123/847
(B) 123/849
(C) 123/874
(D) 123/877
(E) 246/1700
Rationale: Among (A) , (B) , (C) & (D)
(D) is the smallest...
Now compare (D) Vs (E)
(D) 123/877 ~ 14%
(E) 246/1700 ~ 14.47%
So (D) < (E)
Hence correct answer must be (D)
Answer: (D) 123/877
Question: If a is a positive integer, then 5^a+1^a =?
(A) Cannot be determined
(B) 1+(5^a)
(C) 2a
(D) 2a^(a + 1)
(E) None
Rationale: 5^a+1^a=5^a+1
Answer is option B
Answer: (B) 1+(5^a)
Question: If P gets 25% more than Q, then by what percent does Q get less than P?
(A) 60%
(B) 22%
(C) 12%
(D) 20%
(E) 13%
Rationale: Let Q get 1 unit.
25% of 1 unit = 1/4 = 0.25
P gets (1 + 0.25) i.e., 1.25 units.
Difference = (1.25 - 1) = 0.25
Required percentage = 0.25/1.25 * 100 = 1/5 * 100 = 20%
Answer: C
Answer: (C) 12%
Question: The present population of a town is 2000. Population increase rate is 20% p.a. Find the population of town after 1 years?
(A) 1000
(B) 2400
(C) 1500
(D) 1600
(E) 1250
Rationale: P = 2000
R = 20%
Required population of town = P(1 + R/100)^T
= 2000(1 + 20/100)
= 2000(6/5)
= 2400
Answer is B
Answer: (B) 2400
Question: A straight fence is to be constructed from posts 6 inches wide and separated by lengths of chain 5 feet long. If a certain fence begins and ends with a post, which of the following could be the length of the fence in feet? (12 inches = 1 foot).
(A) 17
(B) 88
(C) 266
(D) 2777
(E) 88
Rationale: Explanation:
The fence will consist of one more post than there are chains. (e.g. P-c-P-c-P).
Therefore, a total length has to be a multiple of the length of the chain plus one post (5.5) plus one post extra.We have length = (5.5n + 0.5), where n can be any positive whole number. If n= 3, length =17
Answer: A) 17
Answer: (A) 17
Question: The toll T, in dollars, for a truck using a certain bridge is given by the formula T =3.50 + 0.50( x − 2), where x is the number of axles on the truck. What is the toll for an 18-wheel truck that has 2 wheels on its front axle and 4 wheels on each of its other axles?
(A)  $ 2.50
(B)  $ 3.00
(C)  $ 3.50
(D)  $ 4.00
(E)  $ 5.00
Rationale: Number of wheels in truck = 18
Number of wheels on its front axle =2
number of wheels remaining = 16
number of axles remaining axles = 16/4 = 4
Total number of axles = 5
T = 3.50 + 0.50( x − 2)
= 3.50 + .5*3
= 3.5 +1.5 = 5 $
Answer E
Answer: (E)  $ 5.00
Question: If Yury has been writing programming code for 15 hours at a rate of 5 lines of code per 20 seconds, how many lines of code has he written?
(A) 126(10^2)
(B) 135(10^2)
(C) 12.6(10^5)
(D) 1.26(10^7)
(E) .126(10^9)
Rationale: 5 LINES IN 20 SECONDS
SO FOR 1 MINUTE ( 5 X 3 = 15 LINES )
I HOUR = 60 MINUTES
15 X 60 = 900 LINES IN AN HOUR
15 HOURS = 900 X 15 = 135(10^2)
ANSWER B
Answer: (B) 135(10^2)
Question: A sum of money at simple interest amounts ti $2240 in 2 years and to $ 2600 in 5 years. What is the principal amount?
(A) $1520
(B) $1880
(C) $2120
(D) $2000
(E) $1980
Rationale: S.I for 3 years = $ (2600-2240) = $ 360
S.I for 2 years = $ ((360/3) x 2) = $ 240
Principal =$ (2240-240) = $ 2000
Answer is D
Answer: (D) $2000
Question: A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 30 as remainder. Find the no. is?
(A) 124345
(B) 234545
(C) 165767
(D) 144656
(E) 220030
Rationale: (555 + 445) * 2 * 110 + 30 = 220000 + 30 = 220030
E
Answer: (E) 220030
Question: By selling an shirt for $300, a shop keeper gains 20%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is:
(A) 2
(B) 14
(C) 8%
(D) 12
(E) 10
Rationale: C
8%
Marked price = $300
C.P. = 100/120 * 300 = $250
Sale price = 90% of $300 = $270
Required gain % = 20/250 * 100 = 8%.
Answer: (C) 8%
Question: An author received $0.80 in royalties for each of the first 100,000 copies of her book sold, and $0.50 in royalties for each additional copy sold. If she received a total of $260,000 in royalties, how many copies of her book were sold?
(A) 130,000
(B) 300,000
(C) 380,000
(D) 400,000
(E) 460,000
Rationale: Total royalties for first 100.000 books = .8*100,000= 80,000
Total royalties for the rest of the books = 260,000-80,000 = 180,000
Remaining books = 180,000/0.5 = 360,000
Total books = 360,000+100,000 = 460,000 Answer E
Answer: (E) 460,000
Question: All windows are doors. No door is wall
Conclusions:
1. No window is wall
2. No Wall is door
(A) Both 1 and 4 follow
(B) Both 1 and 3 follow
(C) Both 4 and 1 follow
(D) Both 1 and 2 follow
(E) Both 1 and 6 follow
Rationale: Explanation:
Since both the premises are universal and one premise is negative, the conclusion must be universal negative. Also, the conclusion should not contain the middle term. So, 1 follows.
However, 2 is the converse of the second premise and thus it also holds.
Answer: D
Answer: (D) Both 1 and 2 follow
Question: If 1 + 9 + 11 = 1, Then what is the value of
12 + 11 + 9 = ?
(A) one
(B) Ten
(C) six
(D) five
(E) foue
Rationale: Solution:
10
Explanation:
Equation 1 + 9 + 11 = 1 can be derived from
One (o) + nine (n) + eleven (e) = one => 1
Similarly for equation,
12 + 11 + 9
Twelve (t) + eleven (e) + nine (n) => ten (10)
Answer B
Answer: (B) Ten
Question: A delegation of 5 members has to be formed from 3 ladies and 5 gentlemen. In how many ways the delegation can be formed, if 2 particular ladies are always included in the delegation?
(A) 20
(B) 34
(C) 37
(D) 27
(E) 24
Rationale: There are three ladies and five gentlemen and a committee of 5 members to be formed.
Number of ways such that two ladies are always included in the committee
= ⁶C₃ = (6 * 5 * 4)/6
= 20.
Answer: A
Answer: (A) 20
Question: There are 3 states and 3 students representing each state. In how many ways can 5 students be chosen such that at Least one student is chosen from each state.
(A) 108.
(B) 118
(C) 128
(D) 138
(E) 148
Rationale: To choose 5 students so that atleast one student will represent each state can be done in two ways:
A. 3-1-1 (3 students from 1 state and 1 student from other two states)
3C1*3C3*3C1*3C1=27
3C1 - # of ways to choose 3-student state;
3C3 - # of ways to choose 3 students from 3-student state;
3C1 - # of ways to choose 1 student from the first 1-student state;
3C1 - # of ways to choose 1 student from the second 1-student state.
OR
B. 1-2-2 (1 student from 1 state and 2 students from other two states)
3C1*3C1*3C2*3C2=81
3C1 - # of ways to choose 1-student state;
3C1 - # of ways to choose 1 student from the 1-student state;
3C2 - # of ways to choose 2 students from the first 2-student state;
3C2 - # of ways to choose 2 students from the second 2-student state.
27+81=108.
Answer: 108 A
Answer: (A) 108.
Question: 2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges, 2 bananas and 1 apple costs Rs 10. What is the cost of 3 oranges, 3 bananas and 3 apples
(A) 22
(B) 28
(C) 15
(D) 77
(E) 10
Rationale: Explanation:
2 O + 3 B + 4 A = 15 - - - - (1)
3 O + 2 B + 1 A = 10 - - - - (2)
Where A,B and O are number of apple, bananas, and oranges respectively.
Adding 1 and 2,
5 O + 5 B + 5 A = 25 ⇒ 1 O + 1 A + 1 B = 5
now,
3O + 3A + 3B = 5 × 3 = 15
Answer:C
Answer: (C) 15
Question: A certain sum amounts to Rs.7350 in 2 years and to Rs.8575 in 3 years.find the sum and rate percent
(A) 5400
(B) 3400
(C) 5200
(D) 6500
(E) 5300
Rationale: Interest for 1 year is the same whether it's simple interest or the compound interest.Now interest of third year = 8575 - 7350 = 1225; means principal for this interest is 7350 if comound interest is takenIf 7350 is the principal interest = 1225if 100 is the principal interest =(1225/7350) * 100 = 50/3 %When a thing increases for two successive times the overall increase on initial amount = a + b + (a * b)/100Therefore overall interest for two years = 50/3 + 50/3 + [(50/3)*(50/3)]/100 = 325/9 %Therefore amount after 2 years = 100 + 325/9 = 1225/9If 1225/9 is the amount principal =100if 7350 is the amount principal =(900/1225)*7350 =5400So sum = 5400; Rate = 50/3 % Answer : A
Answer: (A) 5400
Question: The number of stamps that Kaye and Alberto had were in the ration of 5:3 respectively. After Kaye gave Alberto 10 of her stamps, the ration of the number of Kaye had to the number of Alberto had was 3:2. As a result of the gift, Kaye had how many more stamps than Alberto?
(A) 20
(B) 30
(C) 40
(D) 60
(E) 80
Rationale: C
K1 = 5x
A1 = 3x
K2 = 5x - 10
A2 = 3x + 10
K2/A2 = 3/2
(5x-10)/(3x+10) = 3/2
2*(5x-10) = 3*(3x+10)
10x - 20 = 9x + 30
x = 50
K2 = 5*50 - 10 = 240
A2 = 3*50 + 10 = 160
K2 - A2 = 80
Answer : E
Answer: (E) 80
Question: Two cards are drawn together at random from a pack of 52 cards. What is the probability of both the cards being Queens?
(A) 1/221
(B) 1/712
(C) 1/224
(D) 1/212
(E) 1/232
Rationale: Total number of Queens = 4
Total number of cards = 52
P(Queen in first draw) = 4/52
P(Queen in second draw) = 3/51
=4/52*3/51=1/13*1/17=1/221
Answer A
Answer: (A) 1/221
Question: A printer print a page in 4 second,approx how long time it will take to print 190 page report?
(A) 12 Min 40 Sec
(B) 14 Min 40 Sec
(C) 16 Min 40 Sec
(D) 18 Min 40 Sec
(E) 11 Min 40 Sec
Rationale: 1 Page = 4 Sec
30 Page = 120 Sec (2 Min)
190 Page = 12 Min 40 Sec
ANSWER:A
Answer: (A) 12 Min 40 Sec
Question: The prime minister of a country and 4 other dignitaries are scheduled to sit in a row on the 5 chairs represented above. If the prime minister must sit in the center chair, how many different seating arrangements are possible for the 5 people?
(A)  4
(B) 24
(C)  20
(D)  21
(E)  120
Rationale: IMO B
Given that one chair is taken, i think the remaining 4 dignitaries can be arranged 4!. That is 4*3*2*1=24.
Answer: (B) 24
Question: A metallic sphere of radius 12 cm is melted and drawn into a wire, whose radius of cross section is 16 cm. What is the length of the wire?
(A) 9
(B) 8
(C) 7
(D) 6
(E) 5
Rationale: Volume of the wire (in Cylindrical shape) is equal to the volume of the sphere.
π(16)2 * h = (4/3)π (12)3 => h = 9 cm
Answer:A
Answer: (A) 9
Question: The first three terms of a proportion are 4, 9 and 12. The fourth term is?
(A) 24
(B) 25
(C) 26
(D) 27
(E) 28
Rationale: (9*12)/4 = 27
ANSWER:D
Answer: (D) 27
Question: The perimeters of 2 squares are 60cm and 48cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares?
(A) 20cm
(B) 28cm
(C) 36cm
(D) 48cm
(E) 40cm
Rationale: Side of the 1st square = 60/4 = 15cm
Side of the 2nd square = 48/4 = 12cm
Area of the 3rd square = 15^2 - 12^2 = 81cm^2
Side of the 3rd square = 9cm
Required perimeter = 9*4 = 36cm
Answer is C
Answer: (C) 36cm
Question: Compound interest of Rs.4000 at 10% per annum for 1 1/2years will be (interest compounded half yearly).
(A) Rs.473
(B) Rs.374
(C) Rs.495
(D) Rs.630
(E) None of the above
Rationale: 10% interest per annum will be 5% interest half yearly for 3 terms( 1 1/2 years)
So compound interest=4000[1+(5/100)]^3 - 4000=4000[(21/20)^3 -1]
=4000(9261-8000)/8000
=4*1261/8
=630
ANSWER:D
Answer: (D) Rs.630
Question: This topic is locked. If you want to discuss this question please re-post it in the respective forum.
If y ≠ 3 and 3t/y is a prime integer greater than 2, which of the following must be true?
I. t = y
II. y = 1
III. t and y are prime integers.
(A)  None
(B)  I only
(C)  II only
(D)  III only
(E)  I and III
Rationale: 3t/y and if t=y then ans is 3 and 3 is prime number, which is greater than 2. so ans must be B. Please post OA.
Answer: (A)  None
Question: In a fuel station the service costs $1.75 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 65 liters and they are all empty, how much money total will it cost to fuel all cars?
(A) 320$
(B) 380$
(C) 420$
(D) 450$
(E) 528$
Rationale: Total Cost = ( 1.75*12 ) + ( 0.65 * 12 * 65 ) = 21 + 507 => 528
Hence answer will be (E) 528
Answer: (E) 528$
Question: Vijay bought 160 shirts at the rate of Rs. 225 per shirt. The transport expenditure was Rs. 1400. He paid an octroi at the rate of Rs. 1.75 per shirt and labour charges were Rs. 320. What should be the selling price of one shirt, if he wants a profit of 50%?
(A) 282
(B) 229
(C) 356.25
(D) 285
(E) 2812
Rationale: Total CP per shirt = 225 + 1400/160 + 1.75 + 320/160 = Rs. 237.5
SP = CP[(100 + profit%)/100]
= 237.5 * [(100 + 50)/100] = Rs. 356.25.
Answer:C
Answer: (C) 356.25
Question: A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man's rate is?
(A) 1 kmph
(B) 7 kmph
(C) 4 kmph
(D) 9 kmph
(E) 2 kmph
Rationale: DS = 6
US = 4
S = ?
S = (6 - 4)/2
= 1 kmph
Answer:A
Answer: (A) 1 kmph
Question: If a man walks to his office at ¾ of his usual rate, he reaches office 1/3 of an hour late than usual. What is his usual time to reach office?
(A) 1 hour
(B) 9 hour
(C) 7 hour
(D) 6 hour
(E) 8 hour
Rationale: Speed Ratio = 1:3/4 = 4:3
Time Ratio = 3:4
1 -------- 1/3
3 --------- ? è 1 hour
Answer:A
Answer: (A) 1 hour
Question: If P * Q implies (P2 + Q2), 8 * (3 * 2) = ?
(A) 646
(B) 86
(C) 233
(D) 104
(E) 640
Rationale: Explanation:
We have, P * Q = (P2 + Q2) ......... Given
8 * (3 * 2) = ?
8 * 13 = (64 +169) = 233
ANSWER C
Answer: (C) 233
Question: At the end of the month, a certain ocean desalination plant’s reservoir contained 14 million gallons of water. This amount is twice the normal level. If this amount represents 70% of the reservoir’s total capacity, how many million gallons short of total capacity is the normal level?
(A) 2
(B) 5
(C) 10
(D) 12
(E) 15
Rationale: the Q talks of total capacity, normal level, present level, shortage etc..
so it is all about not going wrong in these terms
14 MG= 70% of Total..
total = 14/.7=20MG..
Normal level= 1/2 of 20=10MG..
shortage of normal level=20-10=10MG..
C
Answer: (C) 10
Question: The probability of a lottery ticket being a prized ticket is 0.2. When 4 tickets are purchased, the probability of winning a prize on atleast one ticket is
(A) 0.5928
(B) 0.5904
(C) 0.2788
(D) 0.2699
(E) 0.2998
Rationale: P(winning prize atleast on one ticket)
= 1 - P("Losing on all tickets")
= 1 - (0.8)4 = (1 + (0.8)2)(1 - (0.8)2)
= (1.64)(0.36) = 0.5904
Answer:B
Answer: (B) 0.5904
Question: If a car had increased its average speed for a 210 mile journey by 5 mph, the journey would have been completed in one hour less. What was the original speed of the car for the journey?
(A) 40 mph
(B) 16 mph
(C) 50 mph
(D) 20 mph
(E) 30 mph
Rationale: E
30 mph
Answer: (E) 30 mph
Question: Right now, the ratio between the ages of Sandy and Molly is 4:3. After 6 years, Sandy’s age will be 66 years. What is Molly's age right now?
(A) 15 years
(B) 35 years
(C) 25 years
(D) 45 years
(E) 55 years
Rationale: Now, Sandy is 66 - 6 = 60
Molly's age is (3/4) * 60 = 45
The answer is D.
Answer: (D) 45 years
Question: list of salaries of 8 employees are listed below. What is the median salary? $40,000, $29,000, $35,500, $31,000, $43,000, $30,000, $27,000, $32,000
(A) $15,000
(B) $23,540
(C) $23,550
(D) $30,590
(E) $31,500
Rationale: Ordering the data from least to greatest, we get:
$27,000, $29,000, $30,000, $31,000, $32,000, $35,500, $40,000, $43,000
Since there is an even number of items in the data set, we compute the median by taking the mean of the two middlemost numbers.
$31,000 + $32,000 = $63,000
The median salary is $31,500.
E
Answer: (E) $31,500
Question: Point X is located on line segment AB and point Y is located on line segment CD. If AB = CD and AX < CY, then
(A) XB > YD
(B) XB < YD
(C) AX > XB
(D) AX < XB
(E) AX > AB
Rationale: A--X------B
C-----Y---D
XB < YD.
Answer: A.
Answer: (A) XB > YD
Question: If a(a + 2) = 80 and b(b + 2) = 80, where a ≠ b, then a + b =
(A) -3
(B) -4
(C) -6
(D) -8
(E) -2
Rationale: i.e. if a = 8 then b = -10
or if a = -10 then b = 8
But in each case a+b = -10+8 = -2
Answer:E
Answer: (E) -2
Question: A bucket full of worms kept for Mike's next fishing trip was discovered by the rat that resides in the basement. The rat eats a sixth of the total number of worms in 5 hours. How much time will it take the rat to finish a quarter of the worms?
(A) 4 hours
(B) 6 hours
(C) 7.5 hours
(D) 8 hours
(E) 30 hours
Rationale: In 5 hrs, the rat eats 1/6 of the worms.
In 1 hr, it eats (1/6)/5 = 1/30 of the worms. This is his rate of eating.
Worms to be eaten = 1/4. This is the work that has to be done.
Work = Rate * Time
1/4 = 1/30 * Time
Time = 15/2 = 7.5 hrs
Answer (C)
Answer: (C) 7.5 hours
Question: The area of sector of a circle whose radius is 12 metro and whose angle at the center is 41° is?
(A) 49m2
(B) 50m2
(C) 51.5m2
(D) 53m2
(E) 59m2
Rationale: 41/360 * 22/7 * 12 * 12
= 51.5 m2
Answer:C
Answer: (C) 51.5m2
Question: A man can row upstream at 25 kmph and downstream at 43 kmph, and then find the speed of the man in still water?
(A) 86
(B) 34
(C) 30
(D) 15
(E) 17
Rationale: US = 25
DS = 43
M = (43 + 25)/2
= 34
Answer: B
Answer: (B) 34
Question: If logx 4 = 1/4, then x is equal to
(A) 16
(B) 64
(C) 128
(D) 256
(E) none
Rationale: Solution
log x 4	= 1/4
‹=› x 1/4
= 4
‹=›x= 44
= 256.
Answer D
Answer: (D) 256
Question: A shop owner sells 90 oranges and gains SP of 20 oranges. Find the gain %?
(A) 25 4/7%
(B) 27 4/7%
(C) 30 4/7%
(D) 29 4/7%
(E) 28 4/7%
Rationale: Gain=20 orangesTotal 90 orangesCP 90-20=70(20/70)*100=28 4/7%Ans E
Answer: (E) 28 4/7%
Question: Siva Reddy walked 2 km west of his house and then turned south covering 4 km. Finally, He moved 3 km towards east and then again 1 km west. How far is he from his initial position?
(A) 10 km
(B) 9 km
(C) 2 km
(D) 4 km
(E) 8 km
Rationale: 4 km
ANSWER D
Answer: (D) 4 km
Question: Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.6400?
(A) 8100
(B) 3388
(C) 7767
(D) 2009
(E) 22888
Rationale: 6400* 9/8 * 9/8
= 8100
Answer: A
Answer: (A) 8100