mathewhe/aqua_rat huggingface dataset:
Question: A and B can do a piece of work in 12 days and 16 days respectively. Both work for 3 days and then A goes away. Find how long will B take to complete the remaining work?
(A) 6 days
(B) 12 days
(C) 15 days
(D) 9 days
(E) 8 days
Rationale: 3/12 + (3 + x)/16 = 1
x = 9 days
ANSWER:D
Answer: (D) 9 days
Question: In a group of ducks and cows, the total number of legs are 24 more than twice the no. of heads. Find the total no.of buffaloes.
(A) 10
(B) 12
(C) 13
(D) 15
(E) 16
Rationale: Let the number of buffaloes be x and the number of ducks be y
=> 4x + 2y = 2 (x + y) + 24
=> 2x = 24 => x = 12
B
Answer: (B) 12
Question: The cross-section of a cannel is a trapezium in shape. If the cannel is 15 m wide at the top and 9 m wide at the bottom and the area of cross-section is 636 sq m, the depth of cannel is?
(A) 53
(B) 28
(C) 27
(D) 80
(E) 25
Rationale: 1/2 * d (15 + 9) = 636
d = 53
Answer: A
Answer: (A) 53
Question: Solution P is 20 percent lemonade and 80 percent carbonated water by volume; solution Q is 45 percent lemonade and 55 percent carbonated water by volume. If a mixture of PQ contains 65 percent carbonated water, what percent of the volume of the mixture is P?
(A) 20%
(B) 40%
(C) 50%
(D) 60%
(E) 80%
Rationale: 65% is 15%-points below 80% and 10%-points above 55%.
So the ratio of solution P to solution Q is 2:3.
Mixture P is 2/5 = 40% of the volume of mixture PQ.
The answer is B.
Answer: (B) 40%
Question: In a group of people, if 30 people were made to stand in each column, 16 columns could be formed. If 48 people were made to stand in a column, how many columns could be formed?
(A) 10
(B) 12
(C) 14
(D) 16
(E) 18
Rationale: 16*30 = 48*n
n = 10
The answer is A.
Answer: (A) 10
Question: A number of cats got together and decided to kill between them 999919 mice. Every cat killed an equal number of mice. Each cat killed more mice than there were cats. How many cats do you think there were?
(A) 22
(B) 99
(C) 277
(D) 08
(E) 72
Rationale: A number of cats got together and decided to kill between them 999919 mice. Every cat killed an equal number of mice. Each cat killed more mice than there were cats. How many cats do you think there were?
AnswerB
Answer: (B) 99
Question: A bag of cat food originally cost $14. After a 20% profit markup by the grocery store, it was then offered on sale for 10% off. What is the current sale price of the cat food?
(A)  $14.96
(B)  $15.00
(C)  $15.04
(D)  $15.08
(E)  $15.12
Rationale: sale price = (original price + 20% increase) - 10% decrease
price = [14 * (120/100)] * (90/100) = 14 * (1.2) * (.90) = 16.8 * .9 = 15.12
The answer is E.
Answer: (E)  $15.12
Question: A money lender finds that due to a fall in the annual rate of interest from 8% to 7 3/4 % his yearly income diminishes by Rs. 61.50, his capital is?
(A) 24,607
(B) 24,609
(C) 24,600
(D) 24,602
(E) 24,604
Rationale: Let the capital be Rs. x. Then,
(x * 8 * 1)/100 - (x * 31/4 * 1/100) = 61.50
32x - 31x = 6150 * 4
x = 24,600.Answer: C
Answer: (C) 24,600
Question: From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?
(A) 1/15
(B) 25/57
(C) 35/256
(D) 1/221
(E) 2/15
Rationale: Let S be the sample space.
Then, n(S) = 52C2 =	(52 x 51)/(2x1)	= 1326.
Let E = event of getting 2 kings out of 4.
n(E) = 4C2 =	(4 x 3)/(2x1)= 6.
P(E) =	n(E)/n(S)	=	6/1326=1/221	.
Option D
Answer: (D) 1/221
Question: Insert the missing number.
8, 7, 11, 12, 14, 17, 17, 22, (....)
(A) 27
(B) 20
(C) 22
(D) 24
(E) 26
Rationale: There are two series (8, 11, 14, 17, 20) and (7, 12, 17, 22) increasing by 3 and 5 respectively.
answer : B
Answer: (B) 20
Question: The three solutions of the equation f(x) = 0 are - 4, 8, and 11. Therefore, the three solutions of the equation f(2 x) = 0 are
(A) - 2, 4, and 11/2
(B) - 8, 16 and 22
(C) - 4, 8, and 11
(D) 2, 19 / 2 and 7 / 2
(E) None
Rationale: Solution
If f(x) = 0 at x = - 4, 8 and 11 then f(2x) = 0 for
2x = -4 , 2x = 8 and 2x = 11
Solve the above equations to find
x = -2 , x = 4 and x = 11/2
Answer A
Answer: (A) - 2, 4, and 11/2
Question: Ginger over the course of an average work-week wanted to see how much she spent on lunch daily. On Monday and Thursday, she spent $5.43 total. On Tuesday and Wednesday, she spent $3.54 on each day. On Friday, she spent $12.89 on lunch. What was her average daily cost?
(A) a. $3.19
(B) b. $3.75
(C) c. $3.90
(D) d. $5.08
(E) e. $4.23
Rationale: On Monday and Thursday, she spent $5.43total.
On Tuesday and Wednesday, she spent $3.54on each day.
On Friday, she spent $12.89 on lunch.
The average = (5.43 + 2*3.54 + 12.89)/5 = 5.08.
Answer: D.
Answer: (D) d. $5.08
Question: The income tax in country X is 8% of any income up to $5000. For incomes over $5,000, an 8% tax is imposed on the first $5,000, and a 10% tax is imposed on the portion of the total income in excess of $5000. If Perry paid $950 in income tax last month, then what was Perry's income?
(A) $10,500
(B) $11,000
(C) $13,000
(D) $13,500
(E) $14,000
Rationale: Given : For incomes over $5,000, an 8% tax is imposed on the first $5,000, and a 10% tax is imposed on the portion of the total income in excess of $5000. If Perry paid $950 in income tax last month, then what was Perry's income?
for first 5000 , 8% tax then we get 400$ as tax.
Now Perry paid 950$ tax... we need to check which option is going to yield 550$ on the remaining amount.
A. $10,500 - 5000 = 5500 , then we get 10% tax , we get 550$... ( $10,500 - 5000 - here already for 5000$ we have calculated the tax and we need to tally for the remaining amount)
550+400 = 950$...hence this is the option.
ANSWER :option A.
Answer: (A) $10,500
Question: A and B together can do a piece of work in 8 days. If A alone can do the same work in 12 days, then B alone can do the same work in?
(A) 49
(B) 99
(C) 24
(D) 88
(E) 21
Rationale: B = 1/8 – 1/2 = 1/24 => 24 days Answer:C
Answer: (C) 24
Question: A windmill is taking advantage of strong air currents in order to produce electrical energy. On a typical day the wind speed is around 20 mph and in that speed the windmill produces 700 kw/h (kilowatts per hour). On a stormy day a windmill produces 20% more energy. How much kw/h can three windmills produce in two hours on a stormy day?
(A) 2880.
(B) 4860.
(C) 5780.
(D) 5040.
(E) 6380.
Rationale: Efficiency per machine = 700 watt/hr
Efficiency due to increase in wind speed = 700*120% => 840 watt/hr
Production by each machine in 2 hours is 840*2 => 1680 watt
Production by 3 machines => 1680 watt * 3 = 5040 watt
Answer will be (D)
Answer: (D) 5040.
Question: Rs.160 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio 4:5:6. What is the number of 25 paisa coins?
(A) 898
(B) 165
(C) 120
(D) 168
(E) 112
Rationale: 4x 5x 6x
100 50 25
400x + 350x + 150x = 16000
x = 20
6x = 120
Answer:C
Answer: (C) 120
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are drawn at random, what is the probability that at least one is green?
(A) 23/38
(B) 23/29
(C) 23/32
(D) 23/35
(E) 23/29
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green
= (⁶C₁ * ⁹C₁)/¹⁵C₂ + ⁶C₂/¹⁵C₂
= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7
= 46/70 = 23/35
Answer: D
Answer: (D) 23/35
Question: If Hema walks at 12 km/hr instead of 8 km/hr, she would have walked 20 km more. The actual distance travelled by Hema is ?
(A) 40 kms
(B) 30 kms
(C) 46 kms
(D) 32 kms
(E) 36 kms
Rationale: Explanation:
Let the actual distance travelled be x km.
Then x/8=(x+20)/12
=> 12x = 8x + 160
=> 4x = 160
=> x = 40 km.
ANSWER IS A
Answer: (A) 40 kms
Question: The speed of a car is 95 km in the first hour and 60 km in the second hour. What is the average speed of the car?
(A) 76 kmph
(B) 75 kmph
(C) 77.5 kmph
(D) 56 kmph
(E) 86 kmph
Rationale: S = (95 + 60)/2
= 77.5 kmph
Answer: C
Answer: (C) 77.5 kmph
Question: How many times digit 6 is used while writing numbers from 100 to 1400?
(A) 648
(B) 350
(C) 252
(D) 225
(E) 26
Rationale: There are 100 numbers which begin with 600
Next, In every 10 numbers such as 100 to 110, 110 to 120, 120 to 130 6 comes at least once. Number of such intervals = End limit - First no. / interval. Our range of numbers is 100 - 1000
1000 - 100 = 900/10 = 90
Number of 10s interval in this is 90. So 90 '6s'
So far we have calculated 190.
The total now comes to 280. The nearest to which is 350. Hence B.
Answer: (B) 350
Question: __2A
x__B
____
CC
In the multiplication problem above, A, B, and C represent distinct digits. If the sum of A and B is equal to 6, what is the value of C?
(A) 8
(B) 5
(C) 4
(D) 3
(E) 2
Rationale: If A+B=6
assuming A and B are positive then A*B<10 (they could be either 1,2,3,4,5)
therefore
A*B=C
2*B=C
A+B=6
Three simple equations - divide the 1st/2nd --> A=2 plug it the 3rd --> B=4 --> C=8 (ANSWER A)
Answer: (A) 8
Question: If 12 men can reap 120 acres of land in 36 days, how many acres of land can 54 men reap in 54 days?
(A) 186
(B) 188
(C) 810
(D) 167
(E) 861
Rationale: 12 men 120 acres 36 days
54 men ? 54 days
120 * 54/12 * 54/36
10 * 54 * 3/2
54 * 15 = 810
Answer: C
Answer: (C) 810
Question: In a certain mathematical activity, we have five cards with five different prime numbers on them. We will distribute these five cards among three envelope: all could go in any envelope, or they could be broken up in any way among the envelopes. Then in each envelop, we find the product of all the cards in that envelope: that is the “number” of the envelope. An envelope containing no cards has the number 1. We then put the three envelope numbers in order, from lowest to highest, and that is our set. How many different Y sets can be produced by this process?
(A)  41
(B)  89
(C)  125
(D)  243
(E)  512
Rationale: Case 1: 1 used envelope => 1 way
Case 2: 2 used envelopes
- 4-1-0: Choose 4 from 5 cards: 5 ways
- 3-2-0: Choose 3 from 5 cards: 10 ways
Case 3: All envelopes used
- 3-1-1: Choose 3 from 5 andno need to choose 1 from 2: 10 ways
- 2-2-1: Choose 2 from 5 and choose 2 from 3, but two groups are the same => (10X3):2 = 15
Total Y: 1+5+10+10+15=41 => Answer: A
Answer: (A)  41
Question: Of the 200 employees at company X, 80 are full-time, and 150 have worked at company X for at least a year. There are 20 employees at company X who aren’t full-time and haven’t worked at company X for at least a year. How many full-time employees of company X have worked at the company for at least a year?
(A) 20
(B) 30
(C) 50
(D) 80
(E) 100
Rationale: 200 employees
80 are full-time
150 have worked at company X for at least a year
20 employees at company X who aren’t full-time and haven’t worked at company X for at least a year.
How many full-time employees of company X have worked at the company for at least a year?
200-80=120 employees not full time
120-20= 100 employees not full time who worked over a year
150 employees have worked at company X for at least a year-100 employees not full time who worked over a year = 50 full-time employees of company X have worked at the company for at least a year
C. 50
Answer: (C) 50
Question: The total of a company's assets in 1994 was 100% greater than the total in 1993, which in turn was 300% greater than the total in 1992. If the total of the company's assets in 1992 was N dollars, what were the company's assets in 1994?
(A) 4N
(B) 6N
(C) 8N
(D) 10N
(E) 12N
Rationale: In 1992, the company's assets were N.
In 1993, the company's assets were N + 3N =4N.
In 1994, the company's assets were 4N + 4N = 8N.
The answer is C.
Answer: (C) 8N
Question: If n = 8^8 – 5, what is the units digit of n?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 5
Rationale: 8 ^ 8 - 8 = 8 (8 ^ 7 - 1)
==> 8 (2 ^ 21 - 1)
Last digit of 2 ^ 21 is 2 based on what explanation LiveStronger is saying. 2 ^ 24 - 1 yields 2 - 1 = 1 as the unit digit. Now on multiply this with 5, we get unit digit as 5
Answer : E
Answer: (E) 5
Question: A pet store holds cats and dogs. If the difference between the number of cats and the number of dogs is 5. What could be the ratio of Cats to dogs in the pet store?
(A) 1:3
(B) 20:25
(C) 1:5
(D) 2:5
(E) 4:6
Rationale: Say theratioof cats to dogs is a/b. Then thenumberof cats would be ax and thenumberof dogs bx, for some positive integer x.
We are told that ax - bx = 5 --> x(a - b) = 5. Since 5 is a prime number it could be broken into the product of two positive multiples only in one way: x(a - b) = 1*5.
The above implies that either x = 1 and a - b = 5 or x = 5 and a - b = 1.
Therefore the correct answer should have the difference between numerator and denominator equal to 1 or 13.
For the original question only option which fits is E, 4:5. Cats = 5*4 = 20 and dogs = 5*5 = 25.
Answer: B.
Answer: (B) 20:25
Question: A and B together have Rs. 1210. If of A's amount is equal to of B's amount, how much amount does B have?
(A) 484
(B) 460
(C) 550
(D) 664
(E) None of them
Rationale: 4/15 A = 2/5 B
A = (2/5 x 15/4)B
A = 3/2 B
A/B = 3/2
A : B = 3 : 2.
Therefore, B's share = Rs. (1210 x 2/5)= Rs. 484.
Answer is A.
Answer: (A) 484
Question: When 24 is divided by the positive integer d, the remainder is 4. Which of the following statements about d must be true?
I. d is even
II. dis a multiple of 5
III. d is a factor of 20
(A) III only
(B) I and II only
(C) I and III only
(D) II and III only
(E) I, II, and III
Rationale: 24= m*d + 4
m*d=20
put values of m
m=1 d=20
m=2 d=10
m=4 d=5
I. not true
II. true
III. true
D. correct
Answer: (D) II and III only
Question: Jane started baby-sitting when she was 18 years old. Whenever she baby-sat for a child, that child was no more than half her age at the time. Jane is currently 34 years old, and she stopped baby-sitting 10 years ago. What is the current age of the oldest person for whom Jane could have baby-sat?
(A) 20
(B) 21
(C) 22
(D) 23
(E) 25
Rationale: Check two extreme cases:
Jane = 18, child = 9, years ago = 34-18 = 16 --> child's age now = 9+16 = 25;
Jane = 24, child = 12, years ago = 34-24 = 10 --> child's age now = 12+10 = 22.
Answer: E.
Answer: (E) 25
Question: When 40 per cent of a number is added to another number the second number increases to its 140 per cent. What is the ratio between the first and the second number?
(A) 3 : 4
(B) 4 : 3
(C) 1 : 1
(D) Data inadequate
(E) None of these
Rationale: Let the first and the second numbers be x and y respect then
y + 40% of x = 140% of y
or, y + 0.4x = 1.4y
or, 0.4x = 0.4y
∴ x : y = 0.4 : 0.4 = 4 : 4
Answer C
Answer: (C) 1 : 1
Question: In a shop, the cost of 4 shirts, 4 pairs of trousers and 2 hats is $560. The cost of 9 shirts, 9 pairs of trousers and 6 hats is $1,290. What is the total cost of 1 shirt, 1 pair of trousers and 1 hat?
(A) $50
(B) $320
(C) $150
(D) $100
(E) $400
Rationale: Let x be the price of one shirt, y be the price of one pair of trousers and z be the price of one hat.
4x + 4y + 2z = 560 :
9x + 9y + 6z = 1,290
3x + 3y + 2z = 430 : divide all terms of equation C by 3
x + y = 130 : subtract equation D from equation B
3(x + y) + 2z = 430 : equation D with factored terms.
3*130 + 2z = 430
z = 20 : solve for z
x + y + z = 130 + 20 = $150
correct answer C
Answer: (C) $150
Question: One year ago, the ratio of Sooraj's and Vimal's age was 6:7 respectively. Four years hence, this ratio would become 7:8. How old is Vimal?
(A) 31
(B) 32
(C) 33
(D) 36
(E) 35
Rationale: Let the age of Sooraj and Vimal, 1 year ago, be 6x and 7x respectively.
Given that, four years hence, this ratio would become 7:8
⇒(6x+5):(7x+5)=7:8⇒8(6x+5)=7(7x+5)⇒48x+40=49x+35⇒x=5
Vimal's present age
=7x+1=7×5+1=36
Answer is D.
Answer: (D) 36
Question: If a and b are unique prime integers, which of the following must be odd?
(A) a−b
(B) 2a+2b
(C) 2a−2b
(D) 2a / 2b
(E) ab^2
Rationale: Any number multiplied by 2 has to be an even number. hence
Answer A
Answer: (A) a−b
Question: A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 350 m long platform?
(A) 44 sec
(B) 49 sec
(C) 42 sec
(D) 47 sec
(E) None of these
Rationale: Let the length of the train be x m.
When a train crosses an electric pole, the distance covered is its own length.
So, x = 12 * 36 * 5 /18 m = 120 m.
Time taken to cross the platform = (120 +350)/ 36 * 5/18 = 47 min.
ANSWER:D
Answer: (D) 47 sec
Question: A man can row downstream at the rate of 18 Kmph and upstream at 6 Kmph. Find the man’s rate in still water and rate of current?
(A) 8.5
(B) 6.0
(C) 9.5
(D) 9.0
(E) 8.25
Rationale: Rate of still water = 1/2 (down stream + upstream)
= 1/2 (18 + 6) = 12 Kmph
rate of current = 1/2 (down stream - upstream)
= 1/2 (18 - 6)
= 1/2 (12)
= 6 kmph
Answer is B.
Answer: (B) 6.0
Question: A tank is filled by 3 pipes A,B,C in 3 hours. Pipe C is twice as fast as B and B is twice as fast as A. How much will pipe A alone take to fill the tank ?
(A) 25hr
(B) 35hr
(C) 40hr
(D) 20hr
(E) 21hr
Rationale: Suppose pipe A alone take x hours to fill the tank
Then pipe B and C will take x/2 and x/4 hours respectively to fill the tank.
1/x + 2/x + 4/x = 1/3
7/x = 1/3
x = 21 hours
Answer is E
Answer: (E) 21hr
Question: An iron cubes of side 10 cm is hammered into a rectangular sheet of thickness 0.5 cm. If the sides of the sheet are in the ratio 1 : 5 the sides are
(A) 10 cm, 50 cm
(B) 20 cm, 100 cm
(C) 40 cm, 200 cm
(D) None of these
(E) Cannot be determined
Rationale: Solution
Let the sides of the sheet be x and 5x.
Then,volume of the sheet= volume of the cube
‹=› x × 5x ×1/2
‹=› 10×10×10
‹=› 5x2= 2000
‹=› x2= 400
‹=› x = 20.
The sides are 20 cm and 100 cm.
Answer B
Answer: (B) 20 cm, 100 cm
Question: Pipe A can fill a tank in 10 hr, pipe B in 20hr and pipe C in 40hr. If all the pipes are open in how many hours will tank be filled?
(A) 1hr
(B) 30min
(C) 15min
(D) 17min
(E) 10min
Rationale: Part filled by (A+B+C) in 1hour = 1/10 + 1/20 + 1/40 = 7/40
All the 3 pipes together will fill the tank in 17min Approximately
Answer is D
Answer: (D) 17min
Question: If for any number N, f(N) is defined as the least integer that is greater than or equal to N^2, then what is the value of f(-1.5)?
(A) -4
(B) -3
(C) 1
(D) 2
(E) 3
Rationale: If N=-1.5, then N^2=2.25.
The least integer that is greater than or equal to 2.25 is 3, thus f(-1.5) = 2.25.
The answer is E.
Answer: (E) 3
Question: Find the invalid no.from the following series 15 46 63 71 75 77 78
(A) 15
(B) 46
(C) 71
(D) 75
(E) 78
Rationale: In this question, if you start from the beginning, firstly the difference is 31, then the difference is 17, then the difference is 8. So there is no logic. If you start backwards,you can see that firstly, 1 is added, then 2 is added, then 4 is added, then 8,16 and 32 should have been added. So you have got the right clue. So 15 + 32 the first number should be 47 and afterwards, the series becomes + 16, + 8, + 4and so on. 46
B
Answer: (B) 46
Question: The function f(x) is defined for all positive integers x as the number of even factors of x and the function g(x) is defined for all positive integers x as the number of odd factors of x. For positive integers a and b if f(b)*g(a) = 0 and f(a) = 1, which of the following could be the least common multiple of a and b?
(A) 12
(B) 16
(C) 20
(D) 30
(E) 36
Rationale: f(b)∗g(a)=0 : any positive integer has at least one odd factor: 1. Thus, g(a) cannot be 0, which implies that f(b) = 0. This on the other hand means that b is an odd integer (odd integers does not have even factors).
f(a)=1f(a)=1: aa has 1 even factor. This means that aa must be 2 (the only positive integer which has only 1 even factor is 2).
The least common multiple of a=2a=2 and b=odd is 2∗odd. Only option D can be represented this way: 30=2∗1530=2∗15.
Answer: D
Answer: (D) 30
Question: The profit earned by selling an article for $ 832 is equal to the loss incurred when the same article is sold for $ 448. What should be the sale price for making 55% profit?
(A) $480
(B) $450
(C) $992
(D) $870
(E) $660
Rationale: C
Let C.P. = $ x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 155% of $ 640 = 150/100 * 640 = $ 992.
Answer: (C) $992
Question: In filling a room with gas 100 m * 10 m * 10 m the volumes of gas will be?
(A) 100 cu.m
(B) 1000 cu.m
(C) 10000 cu.m
(D) 100000 cu.m
(E) 10000000 cu.m
Rationale: 100 * 10 * 10 = 10000
ANSWER:C
Answer: (C) 10000 cu.m
Question: Three boys are ages 4, 6 and 7 respectively. Three girls are ages 5, 8 and 9, respectively. If two of the boys and two of the girls are randomly selected and the sum of the selected children's ages is r, what is the difference between the probability that r is even and the probability that r is odd?
(A)  1/9
(B)  1/6
(C)  2/9
(D)  1/4
(E)  1/2
Rationale: Age of Boys r:4, 6, 7
Sum of ages taken 2 at a time: 10,13,11
Ages of Girls:5, 8, 9
Sum of ages taken 2 at a time: 13,17,14
9 Combinations of sum between sets(10,12,11)(13,17,14)
=23,27,24- 16,30,17- 24,28,25
Prob(Even)= 5/9
Prob(Odd) =4/9
Answer=5/9 - 4/9 = 1/9
Answer: (A)  1/9
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
(A) 3.6 sec
(B) 18 sec
(C) 36 sec
(D) 72 sec
(E) None
Rationale: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec
ANSWER:C
Answer: (C) 36 sec
Question: A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
(A) 1/26
(B) 1/52
(C) 2/62
(D) 2/26
(E) 3/26
Rationale: Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
P(E) = n(E)/n(S)
= 2/52
= 1/26
Answer should be A
Answer: (A) 1/26
Question: Today Chris ate 15 jellybeans. Bella ate 2/3 of the jellybeans Chris did, Frances ate 5 more jellybeans than Bella did , and Sandhya ate 20% more than Frances. How many jellybeans did Sandhya eat?
(A) 18
(B) 20
(C) 13
(D) 25
(E) 15
Rationale: A
13
Chris ate 15 jellybeans
Bella ate 2/3 of the jellybeans Chris did.
Bella= 2/3 x 15
=10
Frances ate 5 more jellybeans than Bella.
Frances= 10+5 jellybeans.
=15
Sandhya ate 20% more jellybeans than Frances.
Sandhya = 15 + 15 × 20%
= 15 + 15 × 0.20
= 15 + 3
= 18
Sandhya ate 18 jellybeans.
The correct answer is A.
Answer: (A) 18
Question: In a shop 40% of the articles are sold at a profit of 20% and the remaining at a loss of 10%.what is the overall profit/loss?
(A) 6% loss
(B) 4% loss
(C) 2% profit
(D) 10% loss
(E) none
Rationale: 40*1.2+60*0.9/100=1.02
ANSWER:C
Answer: (C) 2% profit
Question: Vijay bought 160 shirts at the rate of Rs. 205 per shirt. The transport expenditure was Rs. 1400. He paid an octroi at the rate of Rs. 1.75 per shirt and labour charges were Rs. 320. What should be the selling price of one shirt, if he wants a profit of 20%?
(A) s.225
(B) s.288
(C) s.485
(D) s.261
(E) s.282
Rationale: Total CP per shirt = 205 + 1400/160 + 1.75 + 320/160 = Rs. 217.5
SP = CP[(100 + profit%)/100]
= 217.5 * [(100 + 20)/100] = Rs.261.
Answer:D
Answer: (D) s.261
Question: A number is increased by 10% and then decreased by 10%, the final value of the number is ?
(A) decreases by 1%
(B) decreases by 2%
(C) decreases by 3%
(D) decreases by 4%
(E) none of the above
Rationale: Here, x = 10 and y = - 10
Therefore, the net % change in value
= ( x + y + xy/100)%
= [10 - 10 + (10 * -10)/100]% or - 1%
Since the sign is negative, there is a decrease in value by 1%.
ANSWER:A
Answer: (A) decreases by 1%
Question: Mangala completes a piece of work in 9 days, Raju completes the same work in 21 days. If both of them work together, then the number of days required to complete the work is
(A) 6 days
(B) 7 days
(C) 8 days
(D) 9 days
(E) 11 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 9 Ã— 21/30 = 6 days.
A
Answer: (A) 6 days
Question: What is the probability of getting a sum 9 from two throws of a dice?
(A) 1/6
(B) 1/8
(C) 1/9
(D) 1/12
(E) None of these
Rationale: In two throws of a dice, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
P(E) =n(E)/n(S)=4/36=1/9	.
Answer:C
Answer: (C) 1/9