mathewhe/aqua_rat huggingface dataset:
Question: Following an increase in prices, the price of a candy box was 10 pounds and the price of a can of soda was 6 pounds. If the price of a candy box was raised by 25%, and the price of a can of soda was raised by 50%. What was the price of a box of candy plus a can of soda before prices were raised?
(A) 11.
(B) 12
(C) 13
(D) 14
(E) 14.5
Rationale: Let the Candy and Soda before the increase be C and S respectively
so Increased price of can = C(1+ 25/100) =10 -----------> C= 8
Increase price of soda : S(1+1/2) = 6 -----------> S=4
Hence total = 8+4 =12.. hence answer: B
Answer: (B) 12
Question: Find the odd man out
864, 420, 200, 85, 40, 16, 6
(A) 420
(B) 85
(C) 16
(D) 40
(E) 6
Rationale: 6x2+4=16
16x2+8=40
40x2+12=92
92x2+16=200.. and so on. 85
ANSWER:B
Answer: (B) 85
Question: On a counter of a donuts store, there are only 16 identical donuts, 11 filled with chocolate and 5 filled with jelly, but the seller tells me that the donuts are randomly placed on the counter. If would want to buy two, what is the probability that I choose one donuts of each flavor?
(A)  2/16
(B)  1/32
(C)  11/12
(D)  11/48
(E)  11/24
Rationale: We are told that we have 16 donuts, 11 of chocolate and 5 of jelly. The donuts are picked simultaneous and randomly, D1 and D2, in different flavors. There are two acceptable outcomes: 1) D1 is chocolate and D2 is jelly; 2) D1 is jelly and D2 is chocolate. Let's go: 1) D1 = (11/16)(5/15)= 11/48 chance of this happening. 2) D2 = (5/16)(11/15) = 11/48 chance of this happening. Then: (11/48)+(11/48)= 11/24, chance of getting the result that you wanted. Answer E.
Answer: (E)  11/24
Question: Bob bikes to school every day at a steady rate of d miles per hour. On a particular day, Bob had a flat tire exactly halfway to school. He immediately started walking to school at a steady pace of y miles per hour. He arrived at school exactly t hours after leaving his home. How many miles is it from the school to Bob's home?
(A) (d + y) / t
(B) 2(d + t) / dy
(C) 2dyt / (d + y)
(D) 2(d + y + t) / dy
(E) x(y + t) + y(x + t)
Rationale: If we choose for d (distance): 10 miles, for d 10 and for y 5.
t would be 90 minutes or 1,5 hours.
If I try this for answer choice C it fits.
Answer: (C) 2dyt / (d + y)
Question: A can complete a certain job in 16 days. B is 60% more efficient than A. In how many days can B complete the same job?
(A) 6
(B) 6.25
(C) 7
(D) 7.5
(E) 10
Rationale: Let, Total Work Unit = 160 Units
A can finish in 16 days = 160 unit work
i.e. A can finish in 1 days = 10 unit work
i.e. B can finish in 1 days = 10+(60/100)*10 = 16 unit work
Days in which B will complete the work alone = 160/16 = 10 days
Answer: Option E
Answer: (E) 10
Question: Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
(A) 12
(B) 10
(C) 11
(D) 9
(E) 8
Rationale: Explanation :
speed of the bus excluding stoppages = 54 kmph
speed of the bus including stoppages = 45 kmph
Loss in speed when including stoppages = 54 - 45 = 9kmph
=> In 1 hour, bus covers 9 km less due to stoppages
Hence, time that the bus stop per hour = time taken to cover 9 km
=distance / speed= 9 / 54 hour = 1/6 hour = 60/6 min=10 min
Answer : C
Answer: (C) 11
Question: A train covers a distance of 12 km in 10 min. If it takes 4 sec to pass a telegraph post, then the length of the train is?
(A) 20
(B) 110
(C) 120
(D) 80
(E) 60
Rationale: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 4= 80 m.
Answer: Option D
Answer: (D) 80
Question: A factory makes 134,341 jam packets which need to be placed in boxes and each box can contain at most 9 packets.How many packets will be in the last unfilled box?
(A) 1 packet
(B) 2 packets
(C) 3 packets
(D) 4 packets
(E) 5 packets
Rationale: In order to divide the sum in 9 parts, the amount must be divisible by 9
Divisibility rule of 9: The sum of the digits must be divisible by 9
Sum of digits of 134,341 = 16 and 9 is divisible by 9.
Hence,we need to add 2 to this number for it to be divisible by 9
Correct Option: B
Answer: (B) 2 packets
Question: A person incurs a loss of 5% be selling a watch for Rs. 1140. At what price should the watch be sold to earn 5% profit
(A) Rs.1200
(B) Rs.1230
(C) Rs.1260
(D) Rs.1290
(E) None of these
Rationale: Explanation:
Let the new S.P. be x, then.
(100 - loss%):(1st S.P.) = (100 + gain%):(2nd S.P.)
=>(95/1140=105/x)=>x=1260
Option C
Answer: (C) Rs.1260
Question: If two numbers are in the ratio 4:3. If 10 is added to both of the numbers then the ratio becomes 5:4 then find the biggest number.
(A) 60
(B) 80
(C) 70
(D) 40
(E) 100
Rationale: 4:3
4x + 20 : 3x + 20 =5 : 4
4[4x + 20] =5[3x + 20]
16x + 80 = 15x + 100
16x -15x = 100 - 80
x = 20
Then biggest number is = 4x
4x = 80
B
Answer: (B) 80
Question: A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current?
(A) 1.6
(B) 1.5
(C) 1.2
(D) 1.9
(E) 1.3
Rationale: 72 --- 9 DS = 8
? ---- 1
45 ---- 9 US = 5
? ---- 1 S = ?
S = (8 - 5)/2 = 1.5
Answer:B
Answer: (B) 1.5
Question: Find the number of square tiles to cover the floor of a room measuring 4 m * 9 m leaving 0.25 m space around the room. A side of square tile is given to be 50 cms?
(A) 187
(B) 476
(C) 119
(D) 208
(E) 276
Rationale: Area of the room =3.5 * 8.5 = 29.75
Area of the tile = 0.5 *0.5=0.25
No. of tiles = 29.75/0.25 = 119
Answer : C
Answer: (C) 119
Question: The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 13 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is
(A) 345600
(B) 153400
(C) 153600
(D) 154000
(E) 154200
Rationale: Perimeter = Distance covered in 8 min. = 18000 x 8 m = 2400 m.
60
Let length = 3x metres and breadth = 2x metres.
Then, 2(3x + 2x) = 2400 or x = 240.
Length = 720 m and Breadth = 480 m.
Area = (720 x 480) m2 = 345600 m2.
A
Answer: (A) 345600
Question: If n = 3 x 4 x p, where p is a prime number greater than 3, how many different positive non-prime divisors does n have, excluding 1 and n?
(A) Six
(B) Seven
(C) Eight
(D) Nine
(E) Ten
Rationale: N=Xa∗Yb where X and Y are prime,
then number of factors of N are given by the formula (a+1)(b+1) { Notice I have simply increased the powers of X and Y by one and then multiplied them. Also Make sure X and Y are DISTINCT primes)
So, in your question, n = 3 x 4 x p, where p is prime.
I can n=31∗22∗p^1
or number of factors = (1+1) * (2+1) * (1+1) = 12.
But Notice we need to find Non prime and Other than 1 and n, so we have three prime numbers (2,3,p) , 1 and N.
Excluding these, we have 12-5 = 7 such factors.
Hence Answer is B
Answer: (B) Seven
Question: A train 540 meters long is running with a speed of 54 kmph. The time taken by it to cross a tunnel 180 meters long is?
(A) 66 sec
(B) 46 sec
(C) 48 sec
(D) 65 sec
(E) 64 sec
Rationale: D = 540 + 180 = 720
S = 54 * 5/18 = 15 mps
T = 720/15 = 48 sec
Answer:C
Answer: (C) 48 sec
Question: A doctor prescribed 18 cubic centimeters of a certain drug to a patient whose body weight was 120 pounds. If the typical dosage is 2 cubic centimeters per 10 pounds of the body weight, by what percent was the prescribed dosage lesser than the typical dosage?
(A) 8%
(B) -37.5%
(C) 11%
(D) 12.5%
(E) 14.8%
Rationale: Typical dosage per 10 pound of the body weight = 2 c.c
Typical dosage per 120 pound of the body weight = 2 *(120/10)
= 2 * 12
= 24 c.c
Dosage prescribed by doctor for 120 pound patient = 18 c.c
% prescribed dosage greater than the typical dosage = (18-24/16) *100%
=(-6/16) *100%
= -37.5%
Answer B
Answer: (B) -37.5%
Question: Ganesh ,Ram and Sohan together can do a work in 16 days. If Ganesh and Ram together can do a the same work in 24 days then, how long will take Sohan to do the same work?
(A) 48
(B) 58
(C) 68
(D) 78
(E) 100
Rationale: Solution:
Work done by three of them together in 1 day= 1/16............(1)
Work done by Ganesh and Ram together in 1 day= 1/24.....(2)
So,work done by Sohan in one day=(1)- (2)=(1/16) - (1/24)=1/48
=>Total days taken by Sohan to complete the work alone= 48 days.
Answer A
Answer: (A) 48
Question: Five boys picked up 30 mangoes .In how many ways can they divide them if all mangoes be identical?
(A) A)4^30
(B) B)2^30
(C) C)1^30
(D) D)3^30
(E) E)5^30
Rationale: Each Mango can be given to any one of the four people or in other words..1 mango can be divided into 5 ways...so all 30 can be divided in 5^30 ways
ANS:E
Answer: (E) E)5^30
Question: The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 40/kg. how much did a kg of coffee cost in june ?
(A) 40
(B) 60
(C) 80
(D) 100
(E) 120
Rationale: Let the price of tea and coffee be x per kg in June.
Price of tea in July = 1.2x
Price of coffee in July = 0.8x .
In July the price of 1/2 kg (400gm) of tea and 1/2 kg (400gm) of coffee (equal quantities) = 40
1.2x(1/2) + 0.8x(1/2) = 40
=> x =40
Thus proved...option A.
Answer: (A) 40
Question: A florist is making a bouquet of flowers. The florist has 12 different flowers to choose from to make the bouquet. The bouquet will be made of 6 different flowers. What is the probability the florist will choose a rose, a tulip, and a lilie?
(A) 1/2
(B) 3/55
(C) 111/112
(D) 1/5
(E) 3/308
Rationale: Combination Formula: nCr = n!/(r!(n - r)!), where n is the population/set, and r is the sample/subset.
Total number possible = 12C6 - 12!/(6!(12 - 6)!) = 924
Number rose possible = 1C1 = 1
Number tulip possible = 1C1 = 1
Number lilie possible = 1C1 = 1
Number other possible = 9C1 = 9
Probability Formula: P(A) = (Number Favorable Outcomes)/(Total Number Possible Outcomes)
P(RTL) = (1C1)(1C1)(1C1)(9C1)/12C6 = 9/924 = 3/308
Answer: E
Answer: (E) 3/308
Question: If two sides of a triangle are 6 and 13, respectively, which of the following could NOT be the area of this triangle?
(A) 40
(B) 6
(C) 17
(D) 29
(E) 38
Rationale: For this question it would be helpful to know the largest area that this triangle could be, given the two sides of 6 and 12.
We know that the area of a triangle will be maximized when two sides are perpendicular to each other (consult Bunuel's drawing above). Thus we have a max area being equal to one half the base times the height, either (.5)13 * 6 -or- (.5)6 * 13 will result in a maximum area of 39 for the triangle; therefore, the triangle could never have an area of 40.
A
Answer: (A) 40
Question: A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 136, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?
(A) 24
(B) 33
(C) 55
(D) 77
(E) 88
Rationale: Let f = pure fuji , g = pure gala and c - cross pollinated.
c = 10% of x where x is total trees.
c = .1x
also 3x/4 = f and c+f = 136 => .1x + 3/4x = 136 => x = 160
160 - 136 = pure gala =24.
A
Answer: (A) 24
Question: Simplify: 100 x 100 - 50 x 50
(A) 7612
(B) 7614
(C) 7500
(D) 7615
(E) None of them
Rationale: (100)^2 - (50)^2 = (100 + 50) (100 - 50) = 150 x 50 = 7500.
Answer is C.
Answer: (C) 7500
Question: Bob wants to run a mile in the same time as his sister. If Bob’s time for a mile is currently 10 minutes and his sister’s time is currently 8 minutes 30 seconds, by what percent does Bob need to improve his time in order run a mile in the same time as his sister?
(A)  3%
(B)  15%
(C)  8%
(D)  10%
(E)  12%
Rationale: Bob's time = 600 secs.
His sis' time = 510 secs.
Percent increase needed = (640-510/600) * 100 = 90/600 * 100 = 15%. Ans (B).
Answer: (B)  15%
Question: An unbiased cubic die is thrown.What is the probabiltiy of getting a multiple of 3 or 4?
(A) 1/12
(B) 1/2
(C) 3/4
(D) 1/6
(E) 1/9
Rationale: S={1,2,3,4,5,6}
P(E)=n(E)/n(S)
n(s)=Total numbers in a die=6
Let E be the event of getting the multiple of 3
then ,E={3,6}
P(mutliple of 3) = 2/6 = 1/3
Let E be the event of getting the multiple of 4
then ,E={4}
P(multiple of 4) = 1/6
P(multiple of 3 or 4) = 1/3 + 1/6 = 1/2
ans B
Answer: (B) 1/2
Question: Rectangular Floors X and Y have equal area. If Floor X is 18 feet by 18 feet and Floor Y is 9 feet wide, what is the length of Floor Y, in feet?
(A)  13 1/2
(B)  18
(C)  18 3/4
(D)  21
(E)  36
Rationale: The area of a rectangle is: Area = length x width
We are given that floor X is 12 feet by 18 feet and that floor Y is 9 feet wide. So we can say:
length of X = 18
width of X = 18
width of Y = 9
length of Y = n
We also can say:
Area of Floor X = Area of Floor Y
(length of X)(width of X) = (length of Y)(width of Y)
(18)(18) = 9n
(18)(2) = n
36 = n
Answer E.
Answer: (E)  36
Question: Mahesh and suresh are ranked 31th and 32th respectively form the top in a class of 41 Students. What will be their respective ranks from the bottom ?
(A) 9th and 10th
(B) 11th and 12th
(C) 12th and 13th
(D) 10th and 11th
(E) 10th and 12th
Rationale: 1-----41
2-----40
3-----39
4-----38
.
.
.
.
31---11
32---10
33---9
34---8
35----7
36---6
37---5
38----4
39----3
40---2
41----1
so....from bottom mahesh suresh ranks are 11th and 10th
ANSWER:D
Answer: (D) 10th and 11th
Question: find the smallest number in GP whose sum is 38 and product is 1728
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
Rationale: Let x,y,z be the numbers in geometric progression?
y^2=xz
x+y+z=38
xyz=1728
xyz = xzy = y^2y = y^3 = 1728
y = 12
y^2=xz=144
z=144/x
x+y+z = x+12+144/x = 38
x^2+12x+144=38x
x^2-26x+144=0
(x-18)(x-8)=0
x=8,18
If x =8, z = 38-8-12=18
The numbers are 8,12, 18
Their sum is 38
Their product is 1,728
The smallest number is 8
ANSWER:D
Answer: (D) 8
Question: If YWUSQ is 25 - 23 - 21 - 19 - 17 then MKIGF is
(A) 9 - 8 - 7 - 6 - 5
(B) 1 - 2 - 3 - 5 - 7
(C) 7 - 8 - 4 - 5 - 3
(D) 13 - 11 - 9 - 7 - 6
(E) None
Rationale: In alphabet has 26 words coresponding as
A position 1
E position 5
Z position 26
similarly as given in question Y=25 ;W=23; U=21;S=19; Q=17
for M=13 ;K=11;I=9 and so on
ANSWER:D
Answer: (D) 13 - 11 - 9 - 7 - 6
Question: David obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ?
(A) 75
(B) 276
(C) 87
(D) 165
(E) 11
Rationale: Explanation:
Average = (76 + 65 + 82 + 67 + 85 )/ 5 = 375/5 = 75.
Answer:A
Answer: (A) 75
Question: If it is assumed that 62 percent of those who receive a questionnaire by mail will respond and 300 responses are needed, what is the minimum number of questionnaires that should be mailed?
(A) 400
(B) 420
(C) 480
(D) 483.8
(E) 600
Rationale: Minimum no of mail to be sent for getting 300 responses at 62%
= 300/0.62 = 483.8
Option D
Answer: (D) 483.8
Question: A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 20 sec respectively. What is the speed of the train?
(A) 79.5
(B) 79.0
(C) 79.4
(D) 79.2
(E) 79.3
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 264)/20 = y
y = 22
Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.
Answer: D
Answer: (D) 79.2
Question: A small company is planning to rent either computer A or computer B to print customer mailing lists. Both computer A and computer B must be rented on an hourly basis. The rental fee is based only on the amount of time the computer is turned on. It will cost 40 percent more per hour to rent computer A than to rent computer B. Computer B would, however, require 20 hours more than computer A to do the job. If either computer A, or computer B were rented the total cost to rent the computer would be $550.00. What would be the approximate hourly charge to rent computer B?
(A) $7.85
(B) $11.30
(C) $13.20
(D) $17.80
(E) $22.10
Rationale: Pa = price of A
Pb = price of B
Ta = time for A to complete the job
Tb = time for B to complete the job
Given
Pa = 1.4 Pb
Ta+20 = Tb
Pa*Ta = Pb*Tb=550
1.4Pb * (Tb-20) = Pb*Tb
1.4 Pb Tb - Pb Tb = 1.4 Pb * 20
0.4PbTb = 28Pb
Tb = 28/0.4 = 70
Pb=550/70 ~ 7.85
A
Answer: (A) $7.85
Question: Alex and Brenda both stand at point X. Alex begins to walk away from Brenda in a straight line at a rate of 6 miles per hour. One hour later, Brenda begins to ride a bicycle in a straight line in the opposite direction at a rate of R miles per hour. If R > 8, which of the following represents the amount of time, in terms of R, that Alex will have been walking when Brenda has covered twice as much distance as Alex?
(A) R-4
(B) R/(R+4)
(C) R/(R-12)
(D) 8/(R-8)
(E) 2R - 4
Rationale: Let T be the time thatAlexwill have been walking when Brenda has covered twice as much distance as Alex.
In T hours Alex will cover 4T miles;
Since Brenda begins her journey 1 hour later than Alex then total time for her will be T-1 hours, and the distance covered in that time will be R(T-1);
We want the distance covered by Brenda to be twice as much as that of Alex: 2*6T=R(T-1) --> 12T=RT-R -->T=R/(R-12).
Answer: C.
Answer: (C) R/(R-12)
Question: A train covers a distance of 90 km in 20 min. If it takes 9 sec to pass a telegraph post, then the length of the train is?
(A) 675
(B) 680
(C) 685
(D) 690
(E) 695
Rationale: Speed = (90/20 * 60) km/hr = (270 * 5/18) m/sec = 75 m/sec.
Length of the train = 75 * 9 = 675 m.
Answer: Option A
Answer: (A) 675
Question: Jane and Thomas are among the 7 people from which a committee of 3 people is to be selected. How many different possible committees of 3 people can be selected from these 7 people if at least one of either Jane or Thomas is to be selected?
(A) 20
(B) 25
(C) 30
(D) 35
(E) 40
Rationale: The total number of ways to choose 3 people from 7 is 7C3 = 35.
The number of committees without Jane or Thomas is 5C3 = 10.
There are 35-10 = 25 possible committees which include Jane and/or Thomas.
The answer is B.
Answer: (B) 25
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet?
(A) 20/9 sec
(B) 20/2 sec
(C) 20/7 sec
(D) 40/9 sec
(E) 20/1 sec
Rationale: They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed
= (54 + 72)*5/18
= 7*5 = 35 mps.
The time required = d/s
= 100/35 = 20/7 sec.
Answer: C
Answer: (C) 20/7 sec
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are drawn what is the probability that one is yellow and two are red?
(A) 12/455
(B) 24/455
(C) 9/31
(D) 48/75
(E) 89/121
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
When three marbles are drawn, the probability that one is yellow and two are red
= (Â²Câ‚)(â´Câ‚‚)/Â¹âµCâ‚ƒ
= (2 * 4 * 3 * 3 * 2)/(1 * 2 * 15 * 14 * 13) = 12/455
ANSWER A
Answer: (A) 12/455
Question: How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction?
(A) 50 sec
(B) 77
(C) 55
(D) 44
(E) 11
Rationale: Answer: Option A
Explanation:
The distance to be covered = Sum of their lengths = 200 + 300 = 500 m.
Relative speed = 72 -36 = 36 kmph = 36 * 5/18 = 10 mps.
Time required = d/s = 500/10
= 50 sec.
Answer: A
Answer: (A) 50 sec
Question: Sam invested $1000 @20% per annum for one year. If the interest is compounded half yearly, then the amount received by Sam at the end of the year will be?
(A) $1542
(B) $1145
(C) $1210
(D) $1642
(E) $1020
Rationale: P = $1000
R = 20%
p.a. = 10%
T = 2 half years
Amount = 1000 * (1 + 10/100)^2 = 1000* 11/10 * 11/10 = $1210
Answer is C
Answer: (C) $1210
Question: The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is:
(A) 3500
(B) 4000
(C) 4050
(D) 5000
(E) 6000
Rationale: Explanation:
Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (5050 x 2) = 10100 .... (i)
Q + R = (6250 x 2) = 12500 .... (ii)
P + R = (5200 x 2) = 10400 .... (iii)
Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 33000 or P + Q + R = 16500 .... (iv)
Subtracting (ii) from (iv), we get P = 4000.
P's monthly income = Rs. 4000.
Answer: B
Answer: (B) 4000
Question: A batsman makes a score of 50 runs in the 17th inning and thus increases his averages by 2. What is his average after 17th inning?
(A) 39
(B) 18
(C) 42
(D) 40.5
(E) 41.5
Rationale: let the average after 16th inning =x
then total run after 16th inning=16x
then total run after 17th inning=16x+50
then average run after 17th inning=(16x+50)/17
(16x+50)/17=x+2=> 16x+50 = 17x+34 => x= 16
x=16;
average after 17th inning =16+2=18
ANSWER:B
Answer: (B) 18
Question: The average age of A, B and C is 25 years. If the average age of A and C is 29 years, what is the age of B in years ?
(A) 17
(B) 35
(C) 20
(D) 32
(E) 21
Rationale: Age of B = Age of (A + B + C) â€“ Age of (A + C) = 25 Ã— 3 â€“ 29 Ã— 2 = 75 â€“ 58 = 17 years
A
Answer: (A) 17
Question: Average of 15 results is 43. If the average of first seven results is 41 and average of last seven results is 45 Then find the eighth result?
(A) 41
(B) 39
(C) 43
(D) 45
(E) 47
Rationale: Option 'C'
Answer: (C) 43
Question: A character lock consists of three rings each marked with six different characters. The number of distinct unsuccessful attempts to open the lock is at the most ?
(A) 215
(B) 200
(C) 235
(D) 255
(E) 245
Rationale: six different chars => tot attempts possible with three rings = 6*6*6
=>max unsuccessful attempts = 216-1 = 215
ANSWER A
Answer: (A) 215
Question: The population of a town is 8000. It decreases annually at the rate of 10% p.a. What was its population 2 years ago?
(A) 9876
(B) 8000
(C) 8500
(D) 9500
(E) 10000
Rationale: Formula :
( After =100 denominator
Ago = 100 numerator)
8000 Ã— 100/90 Ã— 100/90 = 9876
A)
Answer: (A) 9876
Question: In an election between two candidates, the first candidate got 80% of the votes and the second candidate got 480 votes. What was the total number of votes?
(A) 1600
(B) 1800
(C) 2000
(D) 2200
(E) 2400
Rationale: Let V be the total number of votes.
0.2V = 480
V = 2400
The answer is E.
Answer: (E) 2400
Question: The Shopkeeper increased the price of a product by 20% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product?
(A) A)12.5%
(B) B)13%
(C) C)13.15%
(D) D)12%
(E) E)15%
Rationale: Quantity X Rate = Price
1 x 1 = 1
0.7 x 1.20 = 0.84
Decrease in price = (0.12/1) × 100 = 12%
D)
Answer: (D) D)12%
Question: The ratio of sodium chloride to ammonium in 100 kg of mixed ammonium normally used by three chemists is 1:4. The amount of sodium chloride to be added to 100 kg of mixed ammonium to make the ratio 9 :25 is
(A) 5 kg
(B) 6.625 kg
(C) 6.25 kg
(D) 6.35 kg
(E) 8.8 kg
Rationale: sodium chloride in 100 kg = 1/5 x 100 = 20 kg
ammonium in 100 kg = 4/5 x 100 = 80 kg
Now 80 is 25 parts out of (25 + 9) = 34 parts.
Hence 9 parts = 9/25 x 80 = 28.8
Amount to be added = 28.8 - 20= 8.8 Kg
ANSWER:E
Answer: (E) 8.8 kg
Question: Three seventh of a number is 12 more than 40% of that number. What will be the 10% of that number?
(A) A)148
(B) B)210
(C) C)21
(D) D)248
(E) E)258
Rationale: 3/7 x – 40/100 x = 12
x = 35 * 12
35 * 12 * 10/100 = 42/2 = 21
ANSWER:C
Answer: (C) C)21
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 7 sec. What is the length of the fast train?
(A) 27 7/6
(B) 27 7/5
(C) 27 7/2
(D) 350/9
(E) 27 7/1
Rationale: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 7 = 350/9
= 350/9 m.
Answer:D
Answer: (D) 350/9