mathewhe/aqua_rat huggingface dataset:
Question: Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?
(A) Can't be determined
(B) 40
(C) 27
(D) 24
(E) None of these
Rationale: Explanation:
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then, (5x+3)/(4x+3)=119
⇒ 45x + 27 = 44x + 33⇒ 9(5x + 3) = 11(4x + 3)
⇒ 45x - 44x = 33 - 27
⇒ x = 6.
Anand's present age = 4x = 24 years.
Answer: D
Answer: (D) 24
Question: Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 22 boys and 38 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad?
(A) 2
(B) 4
(C) 6
(D) 8
(E) 10
Rationale: Venn diagrams are useful for multiple values of a single variable e.g. State of mind - happy/sad/neither. When you have two or more variables such as here where you have gender - boy/girl too, it becomes unwieldy. In this case, either use the table or logic.
Table method is shown above; here is how you will use logic:
There are 6 happy boys.
There are 4 sad girls but total 10 sad children. So rest 6 sad children must be sad boys.
We have 6 happy boys and 6 sad boys. Total we have 22 boys. So 22 - 6 - 6 = 10 boys must be neither happy nor sad.
Answer (E)
Answer: (E) 10
Question: How many ltrs of water must beadded to 16 ltrs of milk and water containing 10% water to make it 20% water in it?
(A) 1 liter
(B) 2 liter
(C) 3 liter
(D) 4 liter
(E) 5 liter
Rationale: By rule of alligation,
% Concentration
of water in pure water (100)	% Concentration
of water in the given mixture (10)
Mean % concentration
(20)
20 - 10 = 10	100 - 20 = 80
=> Quantity of water : Quantity of the mixture = 10 : 80 = 1 : 8
Here quantity of the mixture = 16 litres
=> Quantity of water : 16 = 1 : 8
=> Quantity of water =16×18=2 liter
B
Answer: (B) 2 liter
Question: How many bricks, each measuring 25 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm?
(A) 6400
(B) 2400
(C) 5500
(D) 7400
(E) 3400
Rationale: Number of bricks = Volume Of the wall / Volume of 1 brick = (800 x 600 x 22.5) / (25 x 11.25 x 6) = 6400
ANSWER:A
Answer: (A) 6400
Question: A company plans to award prizes to its top 3 salespeople, with the largest prize going to the top salesperson, the next-largest prize to the next salesperson, and a smaller prize to the third-ranking salesperson. If the company has 10 salespeople on staff, how many different arrangements of winners are possible?
(A) 1,728
(B) 1,440
(C) 1,320
(D) 220
(E) 720
Rationale: [quote=Bunuel]A company plans to award prizes to its top 3 salespeople, with the largest prize going to the top salesperson, the next-largest prize to the next salesperson, and a smaller prize to the third-ranking salesperson. If the company has 10 salespeople on staff, how many different arrangements of winners are possible?
10*9*8
=720
Answer : E
Answer: (E) 720
Question: There are 399 doctors and nurses in a hospital. If the ratio of the doctors to the nurses is 8 : 11, then how many nurses are there in the hospital?
(A) 152
(B) 209
(C) 57
(D) 231
(E) 181
Rationale: Given,
The ratio of the doctors to the nurses is 8 : 11
Number of nurses = 11/19 x 399 = 231
ANSWER:D
Answer: (D) 231
Question: After decreasing 24% in the price of an article costs Rs.988. Find the actual cost of an article?
(A) 1667
(B) 6789
(C) 1300
(D) 6151
(E) 1421
Rationale: CP* (76/100)
= 988
CP= 13 * 100 => CP
= 1300
Answer: C
Answer: (C) 1300
Question: 8 couples attend a dance show in a TV channel. A lucky draw in which 4 persons picked up for a prize is held, then the probability that there is at least 1 couple will be selected is :
(A) 11/31
(B) 13/37
(C) 15/39
(D) 16/37
(E) 19/51
Rationale: P( selecting atleast one couple) = 1 - P(selecting none of the couples for the prize)
= 15/39
C
Answer: (C) 15/39
Question: Mohan purchased 15 kgs of rice at the rate of Rs.26 per kg and 8 kgs of pulses at the rate of Rs.26 per kg. Whaat is the total amount that he paid to the shopkeeper?
(A) Rs.598
(B) Rs.594
(C) Rs.596
(D) Rs. 595
(E) None of these
Rationale: Explanation:
Price of 15 kgs of rice at Rs.26/kg = 15x26 = Rs.390
Price of 8 kgs of pulses at Rs.26/kg = 8x26 = Rs.208
Therefore, Total amount = Rs.390+Rs.208 = Rs.598.
Answer: Option A
Answer: (A) Rs.598
Question: The average age of 15 students of a class is 15 years. Out of these, the average age of 7 students is 14 years and that of the other 7 students is 16 years. The age of the 15th student is
(A) 9 years
(B) 11 years
(C) 15 years
(D) 21 years
(E) 25 years
Rationale: Solution
Age of the 15th student	=[15x15-(14x7+16x7)]
= (225 - 210)
= 15 years.
Answer C
Answer: (C) 15 years
Question: A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it?
(A) 13 8/3 days
(B) 13 1/3 days
(C) 13 6/3 days
(D) 63 1/3 days
(E) 13 5/3 days
Rationale: 5/30 + 20/x = 1
x = 24
1/30 + 1/24 = 3/40
40/3 = 13 1/3 days
Answer:B
Answer: (B) 13 1/3 days
Question: David gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross ?
(A) 15
(B) 20
(C) 25
(D) 35
(E) 30
Rationale: Suppose their paths cross after x minutes.
Then, 11 + 57x = 51 - 63x = 120x = 40
x = 1/3
Number of floors covered by David in (1/3) min. = (1/3 x 57)= 19.
So, their paths cross at (11 +19) i.e., 30th floor.
Answer is E.
Answer: (E) 30
Question: A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?
(A) 42.3
(B) 560.45m
(C) 79m
(D) 26m
(E) 111.12m
Rationale: Explanation:
A runs 1000 m while B runs 900 m and C runs 800 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 800)/900 = 8000/9 = 888.88 m.
B can give C = 1000 - 888.88 = 111.12 m.
ANSWER E
Answer: (E) 111.12m
Question: A cube of side one meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained?
(A) 2681
(B) 1892
(C) 1000
(D) 1345
(E) 1623
Rationale: Along one edge, the number of small cubes that can be cut
= 100/10 = 10
Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut = 10 * 10 * 10 = 1000
Answer: C
Answer: (C) 1000
Question: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?
(A) 360
(B) 120
(C) 80
(D) 240
(E) 60
Rationale: Total number of arrangements = 6! = 720
In exactly half, Susan will be to the left of Tim, which gives us 360 arrangements
Option (A)
Answer: (A) 360
Question: A team of three entered for a shooting competition. The best marks man scored 85 points. If he had scored 92 points, the average scores for. The team would have been 84. How many points altogether did the team score?
(A) 288
(B) 245
(C) 168
(D) 127
(E) 664
Rationale: Explanation:
3 * 84 = 252 - 7 = 245
Answer:B
Answer: (B) 245
Question: For all positive integers n and m, the function A(n) equals the following product:
(1 + 1/2 + 1/2^2)(1 + 1/3 + 3^2)(1 + 1/6 + 6^2)…(1 + 1/p_n + 1/p_n^2), where p_n is the nth smallest prime number, while B(m) equals the sum of the reciprocals of all the positive integers from 1 through m, inclusive. The largest reciprocal of an integer in the sum that B(25) represents that is NOT present in the distributed expansion of A(5) is
(A) 1/4
(B) 1/5
(C) 1/6
(D) 1/7
(E) 1/8
Rationale: For all positive integers n and m,
A(n) = (1 + 1/2 + 1/2^2)(1 + 1/3 + 3^2)(1 + 1/5 + 5^2)…(1 + 1/p_n + 1/p_n^2), where p_n is the nth smallest prime number,
note:i think there's a typo in the above function, A(n) could be (1 + 1/2 + 1/2^2)(1 + 1/3 +1/3^2)(1 + 1/5 +1/5^2)…(1 + 1/p_n + 1/p_n^2)
B(m) = sum of the reciprocals of all the positive integers from 1 through m, inclusive.
A(5), here 5 represents the 5th smallest prime number; the 5th smallest prime number is 11 {2, 3, 5, 7, 11, ...}
A(5) = (1 + 1/2 + 1/2^2)(1 + 1/3 + 3^2)(1 + 1/5 + 5^2)(1 + 1/7 + 1/7^2)(1 + 1/11 + 11^2)
The distributed expansion of A(5) = 1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 +1/7 + 1/9+ 1/10 + 1/11 +1/12 + 1/14+ ...
missing numbers are 1/8, 1/13, 1/16, ....
B(25) = (1 + 1/2 + 1/3 + 1/4 + ... + 1/16 + 1/17 + ... + 1/25)
here the largest reciprocal is 1 and the reciprocals are arranged in descending order based on their values
The largest reciprocal that present in B(25) but not in A(5) is 1/4
Answer A
Answer: (A) 1/4
Question: The product of the digits of the four-digit number h is 36. No two digits of h are identical. How many different numbers are possible values of h?
(A) 6
(B) 12
(C) 24
(D) 36
(E) 48
Rationale: Since the product of the four non-repeating digits is 36, the only possibility is if 1, 2, 3 and 6 are used. These digits can be arranged in 4! ways. Therefore, answer is 24.
ANS :C
Answer: (C) 24
Question: The average temperature of a city in the first four days of a month was 36°. The average for the 2nd, 3rd, 4th and 5th day was 38°. If the temperature of the 1st and 5th day were in the ratio 4 : 5, then what is the temperature on the fifth day ?
(A) 32°
(B) 35°
(C) 38°
(D) 40°
(E) None of these
Rationale: Explanation:
The temperature for first 4 days = 4 * 36 = 144
The temperature for last 4 days = 4 * 38 = 152
The difference between the temperatures is (152 – 144) = 8
The ratio of temperature between first and fifth day is 4 : 5
The temperature on fifth day is 5*8 = 40
ANSWER D
Answer: (D) 40°
Question: Having received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.96 at the candy store. What is John’s weekly allowance?
(A) $3.00
(B) $3.20
(C) $3.40
(D) $3.60
(E) $3.80
Rationale: x = 3x/5 + 1/3*2x/5 + 96
4x/15 = 96
x = $3.60 = $3.60
The answer is D.
Answer: (D) $3.60
Question: The C.I. on a certain sum for 2 years Rs.41 and the simple interest is Rs.40. What is the rate percent?
(A) 7%
(B) 5%
(C) 8%
(D) 6%
(E) 9%
Rationale: SI = 20 + 20
CI = 20 + 21
20 ---- 1
100 ---- ? => 5%
Answer:B
Answer: (B) 5%
Question: If a is an integer greater than 9 but less than 26 and b is an integer greater than 14 but less than 31, what is the range of a/b?
(A) 1
(B) 1/2
(C) 5/6
(D) 2/3
(E) 4/3
Rationale: Range of a/b = max(a/b) - min(a/b)
to get max(a/b) => max(a)/min(b) = 25/15
to get min(a/b) => min(a)/max(b) = 10/30
Range = 25/15 - 10/30
= 4/3
Answer: (E) 4/3
Question: Difference between the length &breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is?? We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103?
(A) 2400 m^2
(B) 2420 m^2
(C) 2520 m^2
(D) 2600 m^2
(E) 2630 m^2
Rationale: Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) m2 = 2520 m^2
C
Answer: (C) 2520 m^2
Question: The ratio of the present ages of Giri and Hari is 5:8. 12 years hence, the ratio of their ages will be 11:14. Find the difference in their present ages?
(A) 7 years
(B) 6 years
(C) 9 years
(D) 5 years
(E) 4 years
Rationale: Let the present ages of Giri and Hari be 5x and 8x years respectively.
(5x + 12)/(8x + 12) = 11/14
70x + 168 = 88x + 132 => x = 2
Difference in their ages will be the same at all times.
This difference = Difference of their present ages
=> 8x - 5x = 3x => 6 years
Answer: B
Answer: (B) 6 years
Question: A trader bought a car at 30% discount on its original price. He sold it at a 80% increase on the price he bought it. What percent of profit did he make on the original price?
(A) 18%
(B) 26%
(C) 12%
(D) 32%
(E) 15%
Rationale: Original price = 100
CP = 70
S = 70*(180/100) = 126
100 - 126= 26%
Answer: B
Answer: (B) 26%
Question: If 11.25 m of a uniform steel rod weighs 42.75 kg. what will be the weight of 7 m of the same rod?
(A) 22.8 kg
(B) 26.6 kg
(C) 28 kg
(D) 26.5 kg
(E) None of these
Rationale: Explanation :
Let the required weight be x kg. Then, Less length, Less weight (Direct Proportion)
=> 11.25 : 7 :: 42.75 : x
=> 11.25 x x = 7 x 42.75
=> x = (7 x 42.75) / 11.25
=> x = 26.6
Answer : B
Answer: (B) 26.6 kg
Question: The radius of a semicircle is 7. What is the approximate perimeter of the semicircle?
(A) 36
(B) 25
(C) 15
(D) 28
(E) 37
Rationale: perimeter of a circle =2pi*r
perimeter of a semicircle = pi*r + 2r
aprox perimiter = 3.14*7 + 2*7 = 35.98 approximately 36
answer A
Answer: (A) 36
Question: A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
(A) 2
(B) 3
(C) 76
(D) 6
(E) 1
Rationale: D = 25 * 60 + 1500 = 3000 m
T = 3000/60 * 18/5 = 180 sec = 3 mins.Answer: B
Answer: (B) 3
Question: Determine the value of 27/31+54/62
(A) 86/31
(B) 87/31
(C) 88/31
(D) 89/31
(E) none
Rationale: Solution:
Both fractions should be reduced before performing arithmetic operations. We get 27/31+2.27/2.31=27/31+27/31=2(27/31)=89/31
Answer D
Answer: (D) 89/31
Question: Praveen age after 10years will be 3 times his age 3years back. what is the present age of Chris?
(A) 20
(B) 25
(C) 10
(D) 30
(E) 15
Rationale: Chris present age= x
after 10years = x+10
3years back = x-3
x+10= 3(x-3)
x=20
Answer is A
Answer: (A) 20
Question: Mr. Karan borrowed a certain amount at 6% per annum simple interest for 9 years. After 9 years, he returned Rs. 8310/-. Find out the amount that he borrowed.
(A) s. 5266
(B) s. 5396
(C) s. 5228
(D) s. 5218
(E) s. 52192
Rationale: Explanation:
Let us assume Mr. Karan borrowed amount is Rs. A. (the principal)
By formula of simple interest, S.I. = PRT / 100
Where P = The principal, R = Rate of interest as a %, T = Time in years
S.I. = (P * 6 * 9)/100 = 54 P/100
Amount = Principal + S.I.
8310 = P + (54P/100)
8310 = (100P + 54P)/100
8310 = 154P/100
P = (8310 * 100)/154 = Rs. 5396.104
ANSWER: B
Answer: (B) s. 5396
Question: The total age of A and B is 11 years more than the total age of B and C. C is how many years younger than A.?
(A) 16
(B) 12
(C) 11
(D) 20
(E) 10
Rationale: (A+B)-(B-C)=11
A-C=11
Answer is C
Answer: (C) 11
Question: When 17 is divided by positive integer x, the remainder is 1. For how many values of x is this true?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: When 17 is divided by x, the remainder is 1 i.e. 1 orange left over after grouping, so x must be greater than 1.
It also means that 16 is completely divisible by x.
Factors of 16 are 1, 2, 4, 8, 16.
Out of these, x can be 2, 4, 8, and 16.
Answer (D).
Answer: (D) 4
Question: In an election, candidate A got 80% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favor of candidate?
(A) 355600
(B) 380800
(C) 356500
(D) 356800
(E) 357000
Rationale: Total number of invalid votes = 15 % of 560000
= 15/100 × 560000
= 8400000/100
= 84000
Total number of valid votes 560000 – 84000 = 476000
Percentage of votes polled in favour of candidate A = 80 %
Therefore, the number of valid votes polled in favour of candidate A = 80 % of 476000
= 80/100 × 476000
= 38080000/100
= 380800
B)
Answer: (B) 380800
Question: Find the value of (875 233/899) × 899
(A) 786500
(B) 786528
(C) 786652
(D) 786700
(E) 786858
Rationale: (875 233/899) × 899
(786625 + 233)/899 × 899
786858/899 × 899
786858
E
Answer: (E) 786858
Question: x, a, z, and b are single digit positive integers. x = ¼ a. z = ¼ b. (10a + b) – (10x + z) could NOT equal
(A) 33
(B) 36
(C) 44
(D) 63
(E) 66
Rationale: From the given equations, a = 4x, b = 4z
(10a+b) - (10x+z) = 40x+4z - 10x-z = 30x +3z = 3(10x+z)
Therefore the resultant should be divisible by 3 which isn't possible only in the case of C.
Hence C is the answer
Answer: (C) 44
Question: If a wholesaler distributes items to several outlets (A, B, C and D) in the ratio of 1/12 : 1/13 : 1/15 : 1/2, then find the total number of items the wholesaler distributes?
(A) 567
(B) 167
(C) 267
(D) 467
(E) 667
Rationale: Here, A : B : C : D = 1/12 : 1/13 : 1/15 : 1/2
1) L.C.M of 12 : 13 : 15 : 2 is 780
2) Find the number of books each friend received --------- (To find no. of books each friend has, multiply the ratio with the L.C.M. calculated)
A = (1/12) x 780 = 65
B = (1/13) x 780 = 60
C = (1/15) x 780 = 52
D = (1/2) x 780 = 390
3) Total number of toys = (65 x + 60 x + 52 x + 390 x) = 567 x
Minimum number of pens (x) = 1
Therefore, total number of items = 567 items.
Correct option :A
Answer: (A) 567
Question: Rs.560 is divided amongst A, B, C so that 5 times A's share, six times B's share and eight times C's share are all equal. Find C's share?
(A) Rs.142.37
(B) Rs.152.37
(C) Rs.242.37
(D) Rs.210
(E) Rs.142
Rationale: A+B+C = 560
5A = 6B = 8C = x
A:B:C = 1/5:1/6:1/8
= 24:20:15
15/59 * 560 = Rs.142.37
ANSWER:A
Answer: (A) Rs.142.37
Question: The table below shows the enrollment in various classes at a certain college.
Class | Number of Students
Biology | 65
Physics | 35
Calculus | 40
Although no student is enrolled in all three classes, 15 are enrolled in both Biology and Physics, 10 are enrolled in both Biology and Calculus, and 12 are enrolled in both Physics and Calculus. How many different students are in the three classes?
(A) 51
(B) 88
(C) 90
(D) 103
(E) 162
Rationale: No. of total students = no of students of biology + no of students of physics but not biology + no of students of calculus but not biology and physics
No. of total students = 65 + (35-15) + (40-10-12) = 65+20+18 = 103
Hence, Answer will be D.
Answer: (D) 103
Question: Find the odd man out. 3, 5, 15, 75, 1120, 84375
(A) 15,
(B) 84375
(C) 1120
(D) 75
(E) 3
Rationale: 3
5
3 × 5 = 15
5 × 15 = 75
15 × 75 = 1125
75 × 1125 = 84375
Hence, 1120 is wrong. 1125 should have come in place of 1120
Answer is C
Answer: (C) 1120
Question: When positive integer n is divided by 3, the remainder is 2. When n is divided by 7, the remainder is 6. How many values less than 100 can n take?
(A)  0
(B)  2
(C)  3
(D) 6
(E)  5
Rationale: a quick approac to this Q is..
the equation we can form is.. 3x+2=7y+5..
3x-3=7y... 3(x-1)=7y...
so (x-1) has to be a multiple of 7 as y then will take values of multiple of 3..
here we can see x can be 1,8,15,22,29 so 5 values till 100 is reached
as (29-1)*3=84 and next multiple of 7 will be 84+21>100..
ans 6.. D
Answer: (D) 6
Question: A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one–fifth of the average o fthe two areas. What is the area of the smaller part in hectares?
(A) 225
(B) 280
(C) 300
(D) 385
(E) None
Rationale: Solution
Let the areas of the two parts be
x and (700 - x)hectares	= [x - (700 - x)]
= 1 / 5 x [x + (700 - x)/ 2]
= 2x - 700= 70
x = 385.
Answer D
Answer: (D) 385
Question: In a stack of boards at a lumber yard, the 20th board counting from the top of the stack is immediately below the 19th board counting from the bottom of the stack. How many boards are in the stack?
(A) 37
(B) 36
(C) 35
(D) 34
(E) 32
Rationale: Counting from the top, after the 20th board, there are 17 boards left to count.
The answer is A.
Answer: (A) 37
Question: A man counted his animals, 80 heads and 270 legs (ducks and goats). how many goats are there?
(A) 30
(B) 40
(C) 50
(D) 60
(E) 55
Rationale: let no of ducks=d and no of goat=g
d+g=80(heads)----------> eq 1
each duck has 2 legs and goat has 4 legs
2d+4g=270 and divide 2d+4g=270 by 2 we get d+2g=135 -----------> eq2
subtract eq1 from eq2
we get no of goats=55
ANSWER:E
Answer: (E) 55
Question: A tourist purchased a total of $4,500 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
(A) $1,430
(B) $2,310
(C) $3,290
(D) $4,270
(E) $5,150
Rationale: Let the number of $10 checks cashed beT
Let the number of $50 checks cashed beF
7 checks cashed;
T+F=7
Now; T can be F+1 OR T can be F-1
Let's check both conditions;
T=F+1
T+F=7
F+1+F=7
2F=6
F=3
T=4
Value cashed = 3*50+4*10=150+40=$190
Let's check the other condition as well;
T=F-1
T+F=7
F-1+F=7
2F=8
F=4
T=3
Value cashed = 4*50+3*10=200+30=$230
The more money he cashes, the less loss he incurs. Thus, we must consider the latter case.
Value cashed = $230
Value lost = 4500-230 = $4270
Ans:D
Answer: (D) $4,270
Question: Train A left Centerville Station, heading toward Dale City Station, at 3: 00 p.m. Train B left Dale City Station, heading toward Centerville Station, at 0: 20 p.m. on the same day. The trains rode on straight tracks that were parallel to each other. If Train A traveled at a constant speed of 30 miles per hour and Train B traveled at a constant speed of 10 miles per hour, and the distance between the Centerville Station and Dale City Station is 90 miles, when did the trains pass each other?
(A) 4: 45 p.m.
(B) 2: 20 p.m.
(C) 5: 20 p.m.
(D) 5: 35 p.m.
(E) 6: 00 p.m.
Rationale: the distance travelled by the train A in first 20 minutes will be 10.
The distance which will be remaining is 80.
Now both trains are running in opposite direction.Their speed will be added so 40.
Time at which they will meet =80/40=2
time of train B will be 0:20 +2=2:20
Hence answer is B.Hope i am correct
Answer: (B) 2: 20 p.m.
Question: A string of length 40 metres is divided into three parts of different lengths. The first part is three times the second part, and the last part is 23 metres smaller than the first part.
Find the length of the largest part.
(A) 27
(B) 4
(C) 5
(D) 9
(E) 8
Rationale: Explanation :
Let the 2nd piece length be x.
1st piece length is 3x.
3rd piece length is 3x – 23.
Sum of all the pieces is 40.
3x + x + 3x – 23 = 40.
7x = 63.
x = 9.
Lengths of the pieces are 27, 9, 4.
Answer : A
Answer: (A) 27
Question: A sum of money amounts to Rs. 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is?
(A) 22
(B) 88
(C) 12
(D) 77
(E) 87
Rationale: S.I. for 3 years = (12005 - 9800) = Rs. 2205
S.I. for 5 years = Rs. 2205/3 * 5 = Rs. 3675.
Principal = (9800 - 3675) = Rs. 6125
Hence, rate = (100 * 3675) / (6125 * 5) = 12%
Answer: C
Answer: (C) 12
Question: If 6 (A's capital) = 8 (B's capital) = 10 (C's capital). Then the ratio of their capitals is?
(A) 20:15:16
(B) 20:15:18
(C) 20:15:12
(D) 20:15:11
(E) 20:15:13
Rationale: 6A = 8B = 10 C
A:B:C = 1/6:1/8:1/10
= 20:15:12
Answer: C
Answer: (C) 20:15:12
Question: A recipe for a large batch of fruit juice at a factory calls for 10% oranges, 20% lemons, and 70% limes. if 200 oranges are used, how many lemons are needed?
(A) 50
(B) 100
(C) 200
(D) 400
(E) 700
Rationale: 10%= 200 fruit
100%=2000 fruit
20% of 2000 fruit=400 fruit
400 lemons
ANSWER:D
Answer: (D) 400
Question: An article is bought for Rs.500 and sold for Rs.400, find the loss percent?
(A) 18 2/3%
(B) 16 7/3%
(C) 20%
(D) 16 2/3%
(E) 76 2/3%
Rationale: 500 ---- 100
100 ---- ? => 20%
Answer:C
Answer: (C) 20%
Question: A can do a piece of work in 10 days and B can do the same work in 12 days. A and B worked together for 2 days. How many more days are required to complete the remaining work if they work together?
(A) 2(5/11)days
(B) 3(5/11)days
(C) 4(5/11)days
(D) 6(5/11)days
(E) 8(5/11)days
Rationale: B
3(5/11)days
A can do 1/10 of the work in a day.
B can do 1/12 of the work in a 1 day.
Both of them together can do (1/10 + 1/12) part of work in 1 day = (6 + 5)/60 = 11/60
They take 60/11 days to complete the work together.
Given that they already worked for 2 days.
The number of days required to complete remaining work => 60/11 - 2 = 38/11 = 3 (5/11) days.
Answer: (B) 3(5/11)days
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?
(A) 8 min
(B) 7 min
(C) 5 min
(D) 9 min
(E) 4 min
Rationale: 1/10 + 1/15 - 1/x
= 1/18
x = 9
Answer: D
Answer: (D) 9 min