mathewhe/aqua_rat huggingface dataset:
Question: A high school had 1200 students enrolled in 2003 and 1500 students in 2006. If the student population P ; grows as a linear function of time t, where t is the number of years after 2003.
a) How many students will be enrolled in the school in 2010?
(A) 1800
(B) 1900
(C) 1700
(D) 1500
(E) 1600
Rationale: a) The given information may be written as ordered pairs (t , P). The year 2003 correspond to t = 0 and the year 2006 corresponds to t = 3, hence the 2 ordered pairs
(0, 1200) and (3, 1500)
Since the population grows linearly with the time t, we use the two ordered pairs to find the slope m of the graph of P as follows
m = (1500 - 1200) / (6 - 3) = 100 students / year
The slope m = 100 means that the students population grows by 100 students every year. From 2003 to 2010 there are 7 years and the students population in 2010 will be
P(2010) = P(2003) + 7 * 100 = 1200 + 700 = 1900 students
Answer B
Answer: (B) 1900
Question: If selling price is doubled, the profit triples. Find the profit percent.
(A) 200/3
(B) 100
(C) 316/3
(D) 120
(E) None of these
Rationale: Explanation :
Let the C.P. be x and the S.P. be y
So the profit is (y - x) ---------------------------- (1)
Now, the S.P. is doubled. So the new S.P. = 2y
The new profit = (2y - x)
Given that when S.P. is doubled, profit increases 3 times
=> New profit = 3 * old profit
=> (2y - x) = 3(y - x)
=> y = 2x
So, the profit = (y - x) = (2x - x) = x
% profit = (x/x∗100)% = 100%
Answer : B
Answer: (B) 100
Question: There are 20 boys and 15 girls are present in a class. If 5 student will chosen for a competition an at least two students must be girl?
(A) 309128
(B) 320000
(C) 251230
(D) 301000
(E) 100009
Rationale: 15 girls and 20 boys. Five students needed
It is always better to subtract the total from none in case of at least one problems.
Total ways = 35C5 = 324632
Total ways without any girl = 20C5 = 15504
Hence ways in which at least one women will be present = 324632 - 15504 = 309128
Correct option: A
Answer: (A) 309128
Question: Find avrg speed if a man travels at speed of 32km/hr up and 48km/hr dawn at an altitude of 230m.
(A) 25.8
(B) 26.8
(C) 38.4
(D) 34.4
(E) 29.8
Rationale: avg speed=2*x*y/(x+y)
=2*32*48(32+48)=38.4
ANSWER:C
Answer: (C) 38.4
Question: 22 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be :
(A) 84 m
(B) 28 m
(C) 120 m
(D) 137 m
(E) None
Rationale: Sol.
Let the length of the wire b h.
Radius = 1/2 mm = 1/20 cm. Then,
22/7 * 1/20 * 1/20 * h = 22 ⇔ = [22 * 20 * 20 * 7 / 22] = 2800cm = 28 m.
Answer B
Answer: (B) 28 m
Question: A farmer has three different crops on his farm; cabbage, carrots, and parsnips, where 10 percent of the crops are cabbage and 35 percent are carrots. If the farm produces 650 pounds of parsnips, and the weight of all crops are evenly distributed, how many pounds of crops are produced in total?
(A)  6,500 pounds
(B)  2,000 pounds
(C)  10 pounds
(D)  1,000 pounds
(E)  100 pounds
Rationale: Let the total pounds of crops be x
% of cabbage = 10%
% of carrots = 35%
% of parsnips = 100% - 45% = 65%
But this number is given as 500 pounds
so 65% of x = 650 and x = (650)(100/65)
x = 1,000
Therefore there a total of 1,000 pounds of crops.
Correct answer - D
Answer: (D)  1,000 pounds
Question: How many times are the hands of a clock at right angle in 2 weeks?
(A) 616
(B) 611
(C) 661
(D) 116
(E) 666
Rationale: In 1 day, they are at right angles 44 times.
In 14 days, they are at right angles 616 times. Answer: Option A
Answer: (A) 616
Question: The number of stamps that P and Q had were in the ratio of 7:2 respectively. After P gave Q 15 stamps, the ratio of the number of P's stamps to the number of Q's stamps was 2:1. As a result of the gift, P had how many more stamps than Q?
(A) 25
(B) 35
(C) 45
(D) 55
(E) 65
Rationale: P started with 7k stamps and Q started with 2k stamps.
(7k-15)/(2k+15) = 2/1
3k = 45
k = 15
P has 7(15) - 15 = 90 stamps and Q has 2(15)+15 = 45 stamps.
The answer is C.
Answer: (C) 45
Question: If the radii of umbra and penumbra cast by an object on a wall are of the ratio 2:6, what is the area of the penumbra ring around the umbra of the latter’s radius is 40 cms?
(A) 40288.57cm^2
(B) 40388.57cm^2
(C) 40488.57cm^2
(D) 40588.57cm^2
(E) 40688.57cm^2
Rationale: et the radius of umbra and penumbra are 2k and 6k.
Then as given radius of umbra=40cm
so 2k=40
k=20
radius of penumbra=20*6=120
area of penumbra ring around the umbra=area of penumbra-area of umbra
22/7*[(120)^2-(40)^2]
=40288.57cm^2
ANSWER:A
Answer: (A) 40288.57cm^2
Question: A, B and C start a business each investing 20,000. After 5 months A withdrew 5000, B withdrew 4000 and C invests 6000 more. At the end of the year, a total profit of 69,900 was recorded. Find the share of B.
(A) 20,000
(B) 21,200
(C) 28,200
(D) 20,500
(E) None of these
Rationale: Ratio of the capitals of A, B and C
= 20000 × 5 + 15000 × 7 : 20000 × 5 + 16000 × 7 : 20000 × 5 + 26000 × 7
= 205000 : 212000 : 282000 = 205 : 212 : 282.
B’s share = (69900 × 212⁄699) = 21200;
Answer C
Answer: (C) 28,200
Question: There are 36 carpenters in a crew. On a certain day, 29 were present. What percent showed up for work? (round to the nearest tenth)
(A) 50.6%
(B) 60.6%
(C) 70.6%
(D) 80.6%
(E) 90.6%
Rationale: x/100=29/36
Multiply the opposites:
29 x 100 = 2900
Divide by the remaining number:
80.55/2900.00
80.6%
correct answer D
Answer: (D) 80.6%
Question: In a 100 m race, A runs at 8km per hour. If A gives B a start of 6 m and still him by 15 seconds, what is the speed of B ?
(A) 5.56 km/hr.
(B) 5.06 km/hr.
(C) 5.64 km/hr.
(D) 6.76 km/hr.
(E) 5.72 km/hr.
Rationale: Time taken by A to cover 100 m =(60 X 60 / 8000)	x 100 sec = 45 sec.
B covers (100 - 6) m = 94m in (45 + 15) sec = 60 sec.
B's speed = (94 x 60 x 60)/(60 x 1000)km/hr = 5.64 km/hr.
Answer is C
Answer: (C) 5.64 km/hr.
Question: A can finish a work in 10 days and B can do same work in half the time taken by A. then working together, what part of same work they can finish in a day?
(A) 1/5
(B) 1/6
(C) 1/7
(D) 3/10
(E) None of these
Rationale: Explanation:
Please note in this question, we need to answer part of work for a day rather than complete work. It was worth mentioning here because many do mistake at this point in hurry to solve the question
So lets solve now,
A's 1 day work = 1/10
B's 1 day work = 1/5 [because B take half the time than A]
(A+B)'s one day work =
(1/10+1/5)=3/10
So in one day 3/10 work will be done
Answer: D
Answer: (D) 3/10
Question: Two persons start running simultaneously around a circular track of length 500 m from the same point at speeds of 15 km/hr and 25 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions?
(A) 16 seconds
(B) 18 seconds
(C) 19 seconds
(D) 27 seconds
(E) 45 seconds
Rationale: Time taken to meet for the first time anywhere on the track
= length of the track / relative speed
= 500 / (15 + 25)5/18 =500* 18 / 40 * 5
= 45 seconds.
Answer:E
Answer: (E) 45 seconds
Question: The average (arithmetic mean) of four different positive integers is 12. If the first of these integers in 3 times the second integer and the second integer is 2 less than the third integer, what is the least possible value of the fourth integer?
(A) 5
(B) 4
(C) 3
(D) 2
(E) 1
Rationale: Let the second integer be x and the fourth be a.
Then [3x + x + (x+2) + a]/4 = 12
=> 5x + 2 + a = 48
=> 5x + a = 48
=> a = 48 - 5x
From the above equation we can see that a is minimum when x is maximum, provided both are positive
The maximum value that x can take in the above equation while still keeping a positive is x=9
This gives us a= 48 - 45 = 3
Therefore the minimum value that the fourth integer can have is 3. Option C.
Answer: (C) 3
Question: In the country of Celebria, the Q-score of a politician is computed from the following formula:
Q=(41ab^2c^3)/d2, in which the variables a, b, c, and d represent various perceived attributes of the politician, all of which are measured with positive numbers. Mayor Flower’s Q-score is 150% higher than that of Councilor Plant; moreover, the values of a, b, and c are 60% higher, 40% higher, and 20% lower, respectively, for Mayor Flower than for Councilor Plant. By approximately what percent higher or lower than the value of d for Councilor Plant is the corresponding value for Mayor Flower?
(A) 56% higher
(B) 25% higher
(C) 8% lower
(D) 20% lower
(E) 36% lower
Rationale: Let's say M stands for Mayor and P stands for councilor
Then as per given information -
Qm = 2.5*Qp
Am = 1.6 Ap
Bm = 1.4 Bp
Cm = 0.8 Cp
and let
Dm = X* Dp
On substituting these values and solving for X we get X ~ 0.8 ....
Hence it is lower by 20%
Ans - D
Answer: (D) 20% lower
Question: What is 985*985?
(A)  954,169
(B)  964,219
(C)  964,549
(D)  965,019
(E)  970,225
Rationale: if you take a base of 1000 then 985 is 15 less than 1000
to get the product of 985 x 985 write like this
985- 15( as 15 less than base1000)
985- 15
now 15 x 15 = 225
and 985-15 = 970
so 985 x 985 = 970225 ... (bingo the answer is E . you can even have a shortcut ...... 15 x 15 = 225 ... only answer choice has last three digits as 225.. so no need to calculate 985-15 . after you get 15 x 15 you can straight way pick answer choice E.
Answer: (E)  970,225
Question: Eleven bags are bought for Rs.1000 and sold at 10 for Rs.1100. What is the gain or loss in percentage?
(A) 29%
(B) 21%
(C) 23%
(D) 28%
(E) 27%
Rationale: Explanation:
As selling price is Rs.1100 for 10 bags, each bag is sold at Rs.110.
Hence, the profit is Rs.100 after selling 10 bags plus the selling price of 1 bag = 100 + 110 = Rs.210.
%profit = 210/1000 *100
= 21%
ANSWER: B
Answer: (B) 21%
Question: The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 90/kg. how much did a kg of coffee cost in june ?
(A) 50
(B) 60
(C) 80
(D) 90
(E) 120
Rationale: Let the price of tea and coffee be x per kg in June.
Price of tea in July = 1.2x
Price of coffee in July = 0.8x .
In July the price of 1/2 kg (900gm) of tea and 1/2 kg (900gm) of coffee (equal quantities) = 90
1.2x(1/2) + 0.8x(1/2) = 90
=> x =90
Thus proved...option D.
Answer: (D) 90
Question: A man can row his boat with the stream at 30 km/h and against the stream in 14 km/h. The man's rate is?
(A) 1 kmph
(B) 4 kmph
(C) 5 kmph
(D) 7 kmph
(E) 8 kmph
Rationale: DS = 30
US = 14
S = ?
S = (30 - 14)/2 = 8 kmph
Answer: E
Answer: (E) 8 kmph
Question: If an object travels at five feet per second, how many feet does it travel in one hour?
(A) 30
(B) 300
(C) 720
(D) 1800
(E) 18000
Rationale: object travels 5 feet in 1 seconds
so speed = 5 ft/second
there are 60 * 60 = 3600 seconds in a hour
so time = 3600 seconds
according to formula distance = speed * time
so object will travel 5 * 3600 = 18000 feet in a hour
so distance = 18000 feet
correct answer - E
Answer: (E) 18000
Question: The maximum gap between two successive leap year is?
(A) 2
(B) 8
(C) 9
(D) 6
(E) 5
Rationale: Explanation:
This can be illustrated with an example.
Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).
Answer: B) 8
Answer: (B) 8
Question: What is the greatest integer that will always evenly divide the sum of four consecutive integers?
(A) 2
(B) 3
(C) 4
(D) 6
(E) 12
Rationale: Let the three consecutive even integers be x , x + 4 , x+8 , x+12
Sum = x + x + 4 + x + 8 + x + 12
= 4x+24 = 4(x+6)
Therefore , 4 will always be a factor .
Answer C
Answer: (C) 4
Question: For any function Fn(x)=Fn−1(F(x))Fn(x)=Fn−1(F(x)) if for n > 1 also g(x) = 1/x, h(x) = x−−√x and k(x) = x2x2 then what is the value of g(h3(k2(x)))?
(A) 1
(B) 8
(C) 7
(D) 6
(E) 12
Rationale: Given Fn(x)=Fn−1(F(x));Fn(x)=Fn−1(F(x)); g(x) = 1/x; h(x) = x−−√x; k(x) = x−−√x
Then, k(k(x)) = (x2)2=x4(x2)2=x4
And, h3(k2(x))=h(h(h(k2(x))))=h(h(x2))=h(x)=x−−√.h3(k2(x))=h(h(h(k2(x))))=h(h(x2))=h(x)=x.
And, g(h3(k2(x)))=g(x−−√)=1/x−−√.g(h3(k2(x)))=g(x)=1/x.
Hence answer is option (A).
Answer: (A) 1
Question: Which of the following must be subtracted from 2^526 so that the resulting integer will be a multiple of 3?
(A) 1
(B) 2
(C) 3
(D) 5
(E) 6
Rationale: 2^12 is definitely NOT a multiple of 3 as 2^12 will only have 2s in it.
Coming back to the question,
2^1 leaves a remainder of 2 when divided by 3
2^2 leaves a remainder of 1 when divided by 3
2^3 leaves a remainder of 2 when divided by 3
2^4 leaves a remainder of 1 when divided by 3... etc. and the cyclicity continues.
Thus, 2^526 will leave a remainder of 1 when divided by 3. Thus you must subtract 1 from 2^526 to make it divisible by 3.
A is thus the correct answer.
Answer: (A) 1
Question: A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
(A) 22
(B) 23
(C) 24
(D) 25
(E) 26
Rationale: Let the number of hens be x and the number of cows be y.
Then, x + y = 48 .... (i)
and 2x + 4y = 140 x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
The required answer = 26.
Option E
Answer: (E) 26
Question: In an election between two candidates, the winner has a margin of 10% of the votes polled. If 3000 people change their mind and vote for the loser, the loser would have won by a margin of 10% of the votes polled. Find the total number of votes polled in the election?
(A) 23000
(B) 22000
(C) 20000
(D) 25000
(E) 30000
Rationale: Winner - Looser
55% - 45%
If 3000 people change their mind and vote for the loser:
Winner - Looser
45% - 55%
Thus 3,000 people compose 10% of all voters, which means that the total number of votes is 30,000.
Answer: E.
Answer: (E) 30000
Question: 28 buckets of water fill a tank when the capacity of each bucket is 13.5 litres. How many buckets will be required to fill the same tank if the capacity of each bucket is 9 litres?
(A) 30
(B) 42
(C) 60
(D) Data inadequate
(E) None of these
Rationale: Capacity of the tank = 28 Ã— 13.5= 378 litres
When the capacity of each bucket = 9 litres, then the required no. of buckets
= 378â„9 = 42
Answer B
Answer: (B) 42
Question: What is the are of an equilateral triangle of side 16 cm?
(A) 64√6 cm2
(B) 84√3 cm2
(C) 64√9 cm2
(D) 64√3 cm2
(E) 66√3 cm2
Rationale: Area of an equilateral triangle = √3/4 S2
If S = 16, Area of triangle = √3/4 * 16 * 16
= 64√3 cm2;
Answer: D
Answer: (D) 64√3 cm2
Question: There is a plane contains 32 points.all the 32 points have equal distance from point x. which of the following is true .
(A) ll 32 points lie in circle
(B) the distance from x to all 32 points is less than the distance between each other c. both a and b
(C) both a and b
(D) 32
(E) 242
Rationale: Option 3
X must be the center of the circle and 32 points are on the circumference. So Option A is correct
Number of diagnols of a regular polygon = n(n−3)2n(n−3)2
So for a polygon of 32 sides, Number of diagnols = 464. Now the minimum distance between any two points = 2πr32=1156r2πr32=1156r
Now total lengh of all the distances from 32 points = 2πr2πr + Sum of the lengths of all the 464 diagnols.
Sum of the lengths of x to all the 32 points = 32 radius = 32r
But the 464 diagnols have 16 diameters connecting 2 oposite points connecting via center. So Sum of the lengths of distances from point to point is clearly greater than sum of the length from x to all 32 ponts. Option B is correct
Answer:C
Answer: (C) both a and b
Question: In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 8 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
(A) 40
(B) 44
(C) 48
(D) 52
(E) None of these
Rationale: Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 8)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 8 = 4/9(T - 8)
10T = 792 - 352 => T = 44.
ANSWER:B
Answer: (B) 44
Question: John purchased some shirts and trousers for $1100. He paid $550 less for the shirts than he did for the trousers. If he bought 5 shirts and the cost of a shirt is $20 less than that of a trouser, how many trousers did he buy?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 11
Rationale: Given that the total purchase of two items cost 1100.
So the average purchase of one item will cost 1100/2 = 550.
Its given as total shirt cost 100$ less. Hence Total Shirt cost = 550 - 275 and Total trouser cost = 300 + 275
5 shirts = 275$ ==> One shirt = 55$
One trouser = 55 + 20 = 75$
Total trousers = 825 / 75 = 11.
E
Answer: (E) 11
Question: If X:Y is 1:5 and Y:Z is 5:7 then X:Z is equal to
(A) 1:6
(B) 1:5
(C) 1:4
(D) 1:7
(E) 1:3
Rationale: The two ratios given are having the same number 5 for Y in both the ratios.
Hence- X:Y = 1:5 Y:Z = 5:7
=> X:Z = 1:7
Answer D
Answer: (D) 1:7
Question: If two integers x,y (x>y) are selected from -5 to 5 (inclusive), how many cases are there?
(A) 55
(B) 60
(C) 65
(D) 70
(E) 75
Rationale: There are 11 integers from -5 to 5 inclusive.
11C2 = 55.
The answer is A.
Answer: (A) 55
Question: If 100 microns = 1 decimeter, and 1,000angstroms = 1 decimeter, how many angstroms equal 1 micron?
(A) 1.0e-05
(B) 0.0001
(C) 10
(D) 10,000
(E) 100,000
Rationale: 100 microns = 1 decimeter
1,000 angstroms = 1 decimeter
100 microns = 1,000 angstroms
1 micron = 1,000/100 = 10
Answer : C
Answer: (C) 10
Question: A special municipal payroll tax charges not tax on a payroll less than $200,000 and only 0.1% on a company’s payroll above $200,000. If Belfried Industries paid $400 in this special municipal payroll tax, then they must have had a payroll of?
(A) $180,000
(B) $202,000
(C) $220,000
(D) $400,000
(E) $600,000
Rationale: ANSWER : E , ( with different approach) :
The 400 paid is 0.1% of the additional amount above 200,000. Let it be X
Now 0.1% of X = 400
Therefore X= 400,000
Total = 200,000 + X= 600,000
Answer: (E) $600,000
Question: A military camp has a food reserve for 250 personnel for 40 days. If after 15 days 50 more personnel are added to the camp, find the number of days the reserve will last for?
(A) 20
(B) 36
(C) 25
(D) 42
(E) 49
Rationale: Explanation:
As the camp has a reserve for 250 personnel that can last for 40 days, after 10 days the reserve left for 250 personnel is for 30 days. Now 50 more personnel are added
in the camp.
Hence, the food reserve for 300 personnel will last for:
250:300::x:30 ……..(it is an indirect proportion as less men means more days)
x = (250*30)/300
x = 25 days
ANSWER C
Answer: (C) 25
Question: A man can row with a speed of 15 kmph in still water. If the stream flows at 4 kmph, then the speed in downstream is?
(A) 33
(B) 77
(C) 20
(D) 19
(E) 71
Rationale: M = 15
S = 4
DS = 15 + 4 = 19
Answer: D
Answer: (D) 19
Question: In a fuel station the service costs $2.75 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 55 liters and they are all empty, how much money total will it cost to fuel all cars?
(A) 320$
(B) 380$
(C) 420$
(D) 450$
(E) 462$
Rationale: 12*2.75 + 0.65*12*55 = 462 hence - E
Answer: (E) 462$
Question: If a fisherman catches 203128 shrimp while out and has to evenly split the catch between 9 restaurants, how many shrimp would he have left over?
(A) 4
(B) 7
(C) 2
(D) 1
(E) 6
Rationale: In order to find the answer you need to find a number that is divisible by 9.
The sum of 203128 16. 9 is divisible by 9 therefore you would subtract 7. 16-7=9
There would be 7 shrimp leftover. Answer B.
Answer: (B) 7
Question: A 15% item yields 30%. The market value of the item is:
(A) Rs. 45
(B) Rs. 55
(C) Rs. 50
(D) Rs. 60
(E) Rs. 65
Rationale: Let the face value of the item is Rs.100
It yields Rs.15
Market value of the stock=(15/30)*100=Rs.50
ANSWER:C
Answer: (C) Rs. 50
Question: Three-twentieths of the members of a social club are retirees who are also bridge players, Four-twentieths of the members are retirees, and one-half of the members are bridge players. If 110 of the members are neither retirees nor bridge players, what is the total number of members in the social club?
(A) 200
(B) 300
(C) 360
(D) 400
(E) 480
Rationale: {Total} = {Retirees} + {Bridge players} - {Both} + {Neither}
x = 4/20*x + x/2 - 3/20*x + 110
20x = 4x + 10x - 3x + 110*20 (multiply by 20)
11x = 110*20
x = 200.
Answer: A
Answer: (A) 200
Question: The radius of a semi circle is 5.2 cm then its perimeter is?
(A) 32.52
(B) 32.48
(C) 26.74
(D) 32.9
(E) 32.31
Rationale: 36/7 r = 5.2 = 26.74
Answer:C
Answer: (C) 26.74
Question: The ratio of two numbers is 3:4 and their sum is 42. The greater of the two numbers is?
(A) 12
(B) 14
(C) 24
(D) 17
(E) 19
Rationale: 3:4
Total parts = 7
= 7 parts --> 42 (7 Ã— 6 = 42)
= 1 part ---->6 (1 Ã— 6 = 6)
= The greater of the two number is = 4
= 4 parts ----> 24 (6 Ã— 4 = 24)
C)
Answer: (C) 24
Question: In a particular year, the month of january had exactly 4 thursdays, and 4 sundays. On which day of the week did january 1st occur in the year.
(A) sunday
(B) monday
(C) tuesday
(D) wednesday
(E) friday
Rationale: series of days may be either one of two:
(i)sun-4,mon-4,tue-4,wed-4,thu-4,fri-3 or 5,sat-3 or 5
(ii)thu-4,fri-4,sat-4,sun-4,mon-3or5,tue-3or5,wed-3or5
Lets check through option,
sun=1,8,15,22,29 jan ... which is not satisfies // wrong
Mon=1,8,15,22,29 jan,,,This satisfy option(ii) with thu-4,fri-4,sat-4,sun-4,mon-5,tue-5,wed-5
ANSWER:B
Answer: (B) monday
Question: Convert the following unit:
2.4 hectares in ares
(A) 200 ares.
(B) 210 ares.
(C) 220 ares.
(D) 230 ares.
(E) 240 ares.
Rationale: 2.4 hectares in ares
1 hectare = 100 ares
Therefore, 2.4 hectares = 2.4 × 100 ares
= 240 ares.
ANSWER : OPTION E
Answer: (E) 240 ares.
Question: If 2 men or 3 women can reap a field in 12 days how long will 4 men and 5 women take to reap it?
(A) 12/16
(B) 11/36
(C) 14/24
(D) 18/36
(E) 2/24
Rationale: Explanation:
2 men reap 1/12 field in 1 day
1 man reap 1/(2 x 12)
3 women reap 1/12 field in 1 day
1 woman reap 1/(12 x 3)
4 men and 5 women reap (4/(2 x 12)+ 5/(3 x 12) =11/36 in 1 day
4 men and 5 women will reap the field in 11/36 days
Answer: Option B
Answer: (B) 11/36
Question: A boy has 11 trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
(A) 120ways
(B) 138ways
(C) 140ways
(D) 132ways
(E) 150ways
Rationale: The boy can select one trouser in 11 ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 11 * 12
= 132 ways.
Answer: D
Answer: (D) 132ways
Question: If y = 30p, and p is prime, what is the greatest common factor of y and 12p, in terms of p?
(A) p
(B) 5p
(C) 6p
(D) 7p
(E) p^2
Rationale: Y=30p
other number is 12p
then GCF(30p,12P)=6P; C is the correct answer
Answer: (C) 6p
Question: In a mixture of milk and water, the proportion of milk by weight was 80%. If, in a 180 gm mixture, 36 gms of pure milk is added, what would be the percentage of milk in the mixture formed?
(A) 73.33%
(B) 93.33%
(C) 23.33%
(D) 33.33%
(E) 83.33%
Rationale: Explanation:
Percentage of milk in the mixture formed = [80/100 (180) + 36] / (180 + 36) * 100% = (144 + 36)/216 * 100% = 5/6 * 100% = 83.33%.
Answer: E
Answer: (E) 83.33%
Question: The unit digit in the product (445 * 534 * 999 * 234) is:
(A) 2
(B) 0
(C) 6
(D) 5
(E) 1
Rationale: Explanation:
Unit digit in the given product = Unit Digit in (5*4*9*4) = 0
ANSWER: B
Answer: (B) 0
Question: A pair of articles was bought for $360 at a discount of 10%. What must be the marked price of each of the article?
(A) $200
(B) $500
(C) $350
(D) $400
(E) $600
Rationale: S.P. of each of the article = 360/2 = $180
Let M.P = $x
90% of x = 360
x = 180*100/90 =$200
Answer is A
Answer: (A) $200