mathewhe/aqua_rat huggingface dataset:
Question: Four car rental agencies A, B, C and D rented a plot for parking their cars during the night. A parked 15 cars for 12 days, B parked 12 cars for 20 days, C parked 18 cars for 18 days and D parked 16 cars for 15 days. If A paid Rs. 1260 as rent for parking his cars, what is the total rent paid by all the four agencies?
(A) 2388
(B) 2778
(C) 6888
(D) 6150
(E) 2771
Rationale: The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15
= 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60
Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.
The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k
It is given that A paid Rs. 1260
45k = 1260 => k = 28
246k = 246(28) = Rs. 6888
Thus the total rent paid by all the four agencies is Rs. 6888.
Answer: C
Answer: (C) 6888
Question: The difference between C.I. and S.I. on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum?
(A) 8
(B) 10
(C) 12
(D) 14
(E) 16
Rationale: [15000 * (1 + R/100)2 - 15000] - (15000 * R * 2)/100 = 96
15000[(1 + R/100)2 - 1 - 2R/100] = 96
15000[(100 + R)2 - 10000 - 200R]/10000 = 96
R2 = (96 * 2)/3 = 64 => R = 8
Rate = 8%
ANSWER:A
Answer: (A) 8
Question: In how many ways can five different rings be worn on four fingers of one hand?
(A) 10
(B) 5
(C) 15
(D) 16
(E) 18
Rationale: Required number of ways = ways of selecting 4 objects out of 5 given objects
= 5C4 = 5*4*3*2/24= 5
Answer B
Answer: (B) 5
Question: John has a boat that can go 20 km/hr with the current, and 16 km/hr against the current. How fast is John's rate?
(A) 10 Km/Hr
(B) 6 Km/Hr
(C) 2 Km/Hr
(D) 8 Km/Hr
(E) 4 Km/hr
Rationale: with current = 20
against current - 16
s=?
s=(20-16)/2= 4/2 = 2
Answer = C
Answer: (C) 2 Km/Hr
Question: A company has 3 directors and 3 managers. How many different committees with 5 people can be chosen having at least 1 director?
(A) 500
(B) 720
(C) 4500
(D) 6
(E) 55
Rationale: atleast one means exactly one and more than one.
different committees with 5 people can be chosen having at least 1 director is
(3c2*3c3) + (3c3*3c2) = 6;
Hence D.
Answer: (D) 6
Question: The probability of pulling a blue ball out of a glass jar is 1/X. The probability of pulling a blue ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?
(A) X/Y.
(B) 1/(XY)
(C) Y/X.
(D) 1/(X+Y).
(E) 1/(X-Y).
Rationale: pulling a blue ball out of a glass jar and breaking the jar both are independent events.
For 2 independent events, we know, P(a) * P(b) = P(a∩b)
If Prob of pulling a blue ball out of a glass jar = P(a) and Prob of breaking the jar = P(b)
1/x * P(b) = 1/y ---> P(b) = x/y
Hence, answer should be A.
Answer: (A) X/Y.
Question: After distributing the sweets equally among 25 children, 8 sweets remain. Had the number of children been 28, 22 sweets would have been left after equal distribution. What was the total number of sweets ?
(A) 328
(B) 348
(C) 358
(D) Data inadequate
(E) None
Rationale: when divided equally among 25 children, 8 sweets remain.
when divided equally among 28 children, 22 sweets remain.
ANSWER:C
Answer: (C) 358
Question: Walking 7/6 of his usual rate, a boy reaches his school 4 min early. Find his usual time to reach the school?
(A) 28 min
(B) 25 min
(C) 24 min
(D) 30 min
(E) 40 min
Rationale: Speed Ratio = 1:7/6 = 6:7
Time Ratio = 7:6
1 -------- 7
4 --------- ? 28 m
ANSWER A
Answer: (A) 28 min
Question: Suganya and Suriya are partners in a business. Suganya invests Rs. 38,000 for 8 months and Suriya invests Rs.40,000 for 10 months. Out of a profit of Rs.31,570. Suganya's share is
(A) Rs.1435
(B) Rs.12,628
(C) Rs.1685
(D) Rs.18,942
(E) None
Rationale: Solution
Ratio of their shares	=(35000Ã—8):(42000Ã—10)
= 2 : 44.
Suganya's share	= Rs.(31570 Ã—2/44)
= Rs.1435.
Answer A
Answer: (A) Rs.1435
Question: A box contains 5 pairs of shoes (10 shoes in total). If two shoes are selected at random, what it is the probability that they are matching shoes?
(A) 1/190
(B) 1/20
(C) 1/9
(D) 1/10
(E) 1/9
Rationale: The problem with your solution is that we don't choose 1 shoe from 10, but rather choose the needed one AFTER we just took one and need the second to be the pair of it. So, the probability would simply be: 1/1*1/9(as after taking one at random there are 9 shoes left and only one is the pair of the first one)=1/9
Answer: C.
Answer: (C) 1/9
Question: A wheel that has 3 cogs is meshed with a larger wheel of 21 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions made by the larger wheel is:
(A) 3
(B) 10
(C) 6
(D) 8
(E) 7
Rationale: Explanation :
Let the required number of revolutions made by larger wheel be x.
Then, More cogs, Less revolutions (Indirect Proportion)
21:3::21:x => 21 * x = 21 * 3
=> x = (21 * 3)/21
=> x = 3
Answer : A
Answer: (A) 3
Question: An Olympic diver received the following scores: 4, 3, 5, 2. The standard deviation of her scores is in which of the following ranges?
(A) 4.01 to 4.99
(B) 1.01 to 1.99
(C) 3.01 to 3.99
(D) 5.01 to 5.99
(E) 2.01 to 2.99
Rationale: 4+3+7+2/4=4
∣4−4∣^2 =0^2 = 0
∣3−4∣^2 =1^2 = 1
∣7−4∣^2 =3^2 = 9
∣2−4∣^2 =2^2 = 4
sqrt 14/4 =1.87
Answer : B
Answer: (B) 1.01 to 1.99
Question: A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:
(A) 1.33 kmph
(B) 4.14 kmph
(C) 2.33 kmph
(D) 2.88 kmph
(E) 4.44 kmph
Rationale: Explanation:
A's speed = \fn_jvn {\color{Black} \left ( 5\times \frac{5}{18} \right )m/sec} = \fn_jvn {\color{Black}\frac{25}{18}m/sec}
Time taken by A to cover 100 m = \fn_jvn {\color{Black}(100\times \frac{18}{15})sec} = 72sec
\fn_jvn {\color{Black} \therefore } Time taken by B to cover 92 m = (72 + 8) = 80 sec.
\fn_jvn {\color{Black} \therefore } B's speed =\fn_jvn {\color{Black} \left ( \frac{92}{80}\times \frac{18}{5} \right )kmph} =4.14kmph
Answer: B
Answer: (B) 4.14 kmph
Question: Find the number of square tiles to cover the floor of a room measuring 4 m * 9 m leaving 0.25 m space around the room. A side of square tile is given to be 25 cms?
(A) 197
(B) 476
(C) 169
(D) 260
(E) 256
Rationale: 3 1/2 * 8 1/2 = 1/4 * 1/4 * x => x
= 476
Answer:B
Answer: (B) 476
Question: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2460?
(A) Rs.800
(B) Rs.810
(C) Rs.820
(D) Rs.900
(E) Rs.920
Rationale: Option C
Answer: (C) Rs.820
Question: The diagonals of a rhombus are 12 cm and 15 cm. Find its area?
(A) 30
(B) 45
(C) 90
(D) 120
(E) 180
Rationale: Area=0.5 x 12 x 15
=90 cmÂ²
Answer: C
Answer: (C) 90
Question: Which of the following inequalities is equivalent to 10 + 2x > 100 + 5x?
(A)  x < -30
(B)  x > -30
(C)  x > -20
(D)  x < -10
(E)  x > -11
Rationale: You can work with the inequality in the same way as you do when you have the equal to sign. You can take terms to the other side by flipping their sign, you can multiply/divide the inequality by the same term on both sides of the equation etc.
The only important thing to note is the following:
When you multiply/divide by a negative number, the sign of the inequality flips.
To illustrate,
10 + 2x > 100 + 5x
-90 > 5x - 2x (Correct)
-90 > 3x (Correct)
-30 > 3x (Correct)
the correct option is A
Answer: (A)  x < -30
Question: In what ratio P:Q should the Mixture P of milk and water in the ratio of 6:1 be mixed with another Mixture Q of milk and water in the ratio 3:4 so that the resultant mixture contains equal quantities of milk and water?
(A) 1:3
(B) 1:4
(C) 1:5
(D) 2:5
(E) 3:4
Rationale: (6/7)*P +(3/7)*Q = (1/7)*P+(4/7)*Q
5P=Q
P/Q = 1/5
The answer is C.
Answer: (C) 1:5
Question: If k = 2n - 1, where n is an integer, what is the remainder of k^2/8?
(A) 1
(B) 3
(C) 5
(D) 7
(E) Cannot be determined from the information given.
Rationale: Let us assume that k = 4(n)(n-1)
This is divisible by 8.
So k+1 when divided by 8 will give reminder 1.
For example, consider n = 2
We have 4*2*1 + 1 = 9
When we divide this by 8 we get reminder 1.
ANSWER:A
Answer: (A) 1
Question: In the first 7 overs of a cricket game, the run rate was only 4.2. What should be the rate in the remaining 30 overs to reach the target of 282 runs?
(A) 6.25
(B) 8.42
(C) 8.3
(D) 8.1
(E) 6.21
Rationale: Required run rate
= [282 - (4.2 * 7)]/30
= 252.60/40
= 8.42
Answer:B
Answer: (B) 8.42
Question: Guna has 8 flavors of ice cream in him parlor. How many options are there for Thilak to pick a one-flavor, two-flavor, three-flavor, four-flavor, five-flavor, six-flavor,seven-flavor or eight-flavor order?
(A) 223
(B) 395
(C) 448
(D) 774
(E) 835
Rationale: 8C1 + 8C2+ 8C3+8C4+8C5+8C6+8C7+8C8 = 395.
Answer: B
Answer: (B) 395
Question: Of the employees in a company, 40 % are female who have a master degree. If 40 % of the female employees do not have a master degree, what percent of the employees in the company are female?
(A) 66.67%
(B) 67.67%
(C) 68.67%
(D) 65.67%
(E) 64.67%
Rationale: Let E be total no. of employees and F be total no of female employees.
Question asked what is F/E X 100%?
No. of female employees with Masters = 0.4 x E (From the question)
No. of female employees without masters = 0.4 x F (From the question)
Therefore No. of female employees with masters = F - 0.4 F = 0.6 F
The 2 expressions equal each other therefore 0.6F = 0.4E; F/E = 0.4/0.6 = 66.67%
Ans: A
Answer: (A) 66.67%
Question: . In digging a pond 23 m * 12 m * 8 m the volumes of the soil extracted will be?
(A) 3323
(B) 2300
(C) 2877
(D) 2208
(E) 2111
Rationale: 23 * 12 * 8 = 2208
Answer: D
Answer: (D) 2208
Question: A house wife saved $3.50 in buying an item on sale. If she spent $32.50 for the item, approximately how much percent she saved in the transaction?
(A) 8%
(B) 9%
(C) 10%
(D) 11%
(E) 12%
Rationale: Actual price = 32.50+3.50 = $36
Saving = 3.50/36 * 100 = 10% approximately
Answer is C
Answer: (C) 10%
Question: The average age of 15 students of a class is 15 years. Out of these, the average age of 8 students is 14 years and that of the other 6 students is 16 years. The age of the 15th student is
(A) 9 years
(B) 11 years
(C) 17 years
(D) 21 years
(E) 25 years
Rationale: Solution
Age of the 15th student	=[15x15-(14x8+16x6)]
= (225 - 208)
= 17 years.
Answer C
Answer: (C) 17 years
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
(A) 338
(B) 240
(C) 287
(D) 267
(E) 191
Rationale: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m.
Answer: B
Answer: (B) 240
Question: A and B enter into partnership with capital as 7:9. At the end of 8 months, A withdraws. If they receive the profits in the ratio of 8:9 find how long B's capital was used?
(A) 5
(B) 6
(C) 4
(D) 7
(E) 9
Rationale: 7 * 8 : 9 * x = 8:9 => x= 7.Answer: D
Answer: (D) 7
Question: When 200 is divided by positive integer x, the remainder is 3. What is the remainder when 297 is divided by x?
(A) 2
(B) 3
(C) 4
(D) 6
(E) 8
Rationale: f200/x leaves a reminder 3 then (200-3) i.e. 197 is divisible by x
So (200+197)/x leaves a reminder rem(200/x)+rem(197/x)=> 3+0=3
Answer :B
Answer: (B) 3
Question: What is the difference between the C.I. on Rs. 5000 for 1 1/2 years at 4% per annum compounded yearly and half-yearly?
(A) 2.04
(B) 2.09
(C) 2.03
(D) 2.02
(E) 2.01
Rationale: C.I. when interest is compounded yearly
= [5000 * (1 + 4/100) * (1 + (1/2 * 4)/100]
= 5000 * 26/25 * 51/50 = Rs. 5304
C.I. when interest is compounded half-yearly
= [5000 * (1 + 2/100)2]
= (5000 * 51/50 * 51/50 * 51/50) = Rs. 5306.04 Difference = (5306.04 - 5304) = Rs. 2.04.Answer: A
Answer: (A) 2.04
Question: If x + y = 2 and x^2 - xy - 10 - 2y^2 = 0, what does x − 2y equal?
(A) 0
(B) 1
(C) 2
(D) 5
(E) 10
Rationale: If x + y = 2 and x^2 - xy - 10 - 2y^2 = 0, what does x − 2y equal?
A. 0
B. 1
C. 2
D. 5
E. 10
Since x + y = 2 we have y=2-x.
So 0= x^2 - xy - 10 - 2y^2 = x^2 - x(2-x) - 10 - 2(2-x)^2 = x^2 -2x+x^2 -10-8+8x-2x^2 = x=6x-18. ---> x=3 ---> y= -1 --->x-2y=5
The answer is (D).
Answer: (D) 5
Question: A milk man has 20 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk.If the cost of pure milk is Rs.18 per liter,then the profit of the milkman, when he sells all the mixture at cost price is:
(A) 20%
(B) 25%
(C) 33.33%
(D) 18%
(E) None of these
Rationale: Explanation:
when the water is freely available and all the water is sold at the price of the milk, then the water gives the profit on the cost of 20 liters of milk.
Therefore, profit percentage = 25 %. Answer: B
Answer: (B) 25%
Question: In a 1000 m race, A beats B by 10 m and B beats C by 100 m. In the same race, by how many meters does A beat C?
(A) A)109m
(B) B)829m
(C) C)822m
(D) D)929m
(E) E)132mj
Rationale: By the time A covers 1000 m, B covers (1000 - 10) = 990 m.
By the time B covers 1000 m, C covers (1000 - 100) = 900 m.
So, the ratio of speeds of A and C =
1000/990 * 1000/900 = 1000/891 So, by the time A covers 1000 m, C covers 891 m.
So in 1000 m race A beats C by 1000 - 891 = 109 m.
Answer:A
Answer: (A) A)109m
Question: If integers ending in zero are excluded, what is the unit digit of the product of the even integers from 402 to 498, inclusive?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: 402 x 404 x 406 x 408 => unit digit 4
412 x 414 x 416 x 418 => unit digit 4
492 x 494 x 496 x 498 => unit digit 4
So we have 10 numbers ending by 4 to multiply.
Given that 4 x 4 = 16, we have 5 numbers ending by 6 to multiply
Given that 6 x 6 = 36, we have 3 numbers ending by 6 to multiply
So the unit digit is 6
Answer: E.
Answer: (E) 6
Question: A sum of Rs. 2900 amounts to Rs. 3422 in 3 years. Had the rate of interest be 4% higher then what would the sum amount in the same time period?
(A) Rs. 3770
(B) Rs. 3683
(C) Rs. 3596
(D) Data inadequate
(E) None of these
Rationale: 3422=2900+(2900*R*3/100)
R=6
If R is 4 more.
Then R=10
Sum=2900+(2900*10*3/100)
Sum=3770
ANSWER:A
Answer: (A) Rs. 3770
Question: A person crosses a 600m long street in 3 minnutes. What is his speed in km per hour?
(A) 5.8km/hr
(B) 7.2km/hr
(C) 9km/hr
(D) 12km/hr
(E) 3km/hr
Rationale: Speed = 600/3*60 = 3.33m/sec
=3.33*18/5
=12km/hr
Answer is D
Answer: (D) 12km/hr
Question: The average of 9 observations was 8, that of the 1st of 5 being 10 and that of the last 5 being 8. What was the 5th observation?
(A) 18
(B) 12
(C) 15
(D) 17
(E) 19
Rationale: Explanation:
1 to 9 = 8 * 9 = 72
1 to 5 = 5 * 10 = 50
5 to 9 = 5 * 8 = 40
5th = 50 + 40 = 90 – 72 = 18
Option A
Answer: (A) 18
Question: A man spends 1/3rd of his salary on food. he spends 1/4th on rent and 1/5th on cloths. If he is left with 1760, then who much salary does he earn
(A) 8223
(B) 8123
(C) 8323
(D) 8423
(E) 8523
Rationale: let total salary be x
A/Q
=> x = (x/3)+(x/4)+(x/5)+ 1760
=> x - 47x/60 = 1760
=> 13x/60 = 1760
=> x = 1760*60/13
=> x = 8123(approax)
ANSWER:B
Answer: (B) 8123
Question: How many seconds will a 1200 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
(A) 26 sec
(B) 65 sec
(C) 55 sec
(D) 19 sec
(E) 72 sec
Rationale: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 1200 * 3/50
= 72 sec.
Answer:E
Answer: (E) 72 sec
Question: Two buses start at the same time, one from P to Q and the other from Q to P. If both buses reach after 4 hours and 16 hours at Q and P respectively after they cross each other, what would be the ratio of speeds of the bus starting from P and that of the one starting from point Q?
(A) 2 : 1
(B) 1 : 2
(C) 2 : 2
(D) 1 : 4
(E) 5 : 2
Rationale: Hint:
SP / SQ = √tQ / √tP
SP and SQ are speeds of two the buses at points P and Q respectively.
tP = 18 hrs and tQ = 4 hrs
SP / SQ = √16 / √4
Therefore, ratio of speeds	Sp/ SQ = 4/2 = 2/1
One bus travels at a speed twice of the other bus.
ANSWER IS A
Answer: (A) 2 : 1
Question: The average age of a husband and his wife was 20 years at the time of their marriage. After five years they have a one-year old child. The average age of the family now is :
(A) 11
(B) 18
(C) 19
(D) 287
(E) 17
Rationale: Explanation:
Sum of the present ages of husband, wife and child = (20 * 2 + 5 * 2) + 1 = 51 years.
Required average = (51/3) = 17 years.
Answer: E) 17
Answer: (E) 17
Question: The speed of a motor boat itself is 20 km/h and the rate of flow of the river is 4 km/h. Moving with the stream the boat went 120 km. What distance will the boat cover during the same time going against the stream?
(A) 60 km
(B) 85 km
(C) 70 km
(D) 80 km
(E) 90 km
Rationale: distance=speed*time;
120=(20+4)*t;
t=5 hrs;
D=(20-4)*5;
D=80 km
ANSWER:D
Answer: (D) 80 km
Question: We run a business that rents out canoes and kayaks. A canoe rental costs $11 per day, and a kayak rental costs $16 dollars per day. One day, our business rents out 4 canoes for every 3 kayaks and receives a total of $460 in revenue. How many more canoes than kayaks were rented out?
(A) 8
(B) 7
(C) 6
(D) 5
(E) 4
Rationale: Let x be the number of canoes.
Then 3x/4 is the number of kayaks.
11x+(3x/4)*16=460
11x+12x=460
23x=460
x=20 (canoes)
3x/4=15 (kayaks)
There were 20-15 = 5 more canoes rented out.
The answer is D.
Answer: (D) 5
Question: A 14% stock yielding 8% is quoted at?
(A) 165
(B) 170
(C) 175
(D) 180
(E) 185
Rationale: Assume that face value = Rs.100 as it is not given
To earn Rs.8, money invested = Rs.100
To earn Rs.14, money invested = 100×14/8 = Rs.175
ie, market value of the stock = Rs.175
Answer is C.
Answer: (C) 175
Question: In how many different ways can the letters of the word "AIM" be rearrangement?
(A) 4
(B) 2
(C) 7
(D) 9
(E) 6
Rationale: Option 'E'
The total number of arrangements is
3P3 = 3! = 6
Answer: (E) 6
Question: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA WORTH RS.30/KG SO THAT BY SELLING THE BLENDED VARIETY AT RS.30/KG THERE SHOULD BE A GAIN OF 15%
(A) 36
(B) 108
(C) 32
(D) 42
(E) 45
Rationale: (x+30)*30=(115/100)(25x+30*30)
Solving we get 108.
Answer is B.
Answer: (B) 108
Question: The value of x is one quarter of z. The sum of x, y, and z is equal to 26. If the value of y is twice the value of z, what is the largest factor of the sum of y and z?
(A) 2
(B) 3
(C) 8
(D) 12
(E) 24 IS ANSWER
Rationale: While most Test Takers would treat this as a 'system' algebra question and solve it that way, there are some interesting Number Property patterns in this prompt that will actually allow you to use the answer choices (and some pattern-matching) to get to the solution.
To start, I'm going to deal with the last piece of information first:
Y is twice Z
The prompt asks for the BIGGEST factor of the SUM of Y and Z. Since Y = 2Z, the sum of Y and Z is (2Z) + Z = 3Z. This means that the BIGGEST factor is a MULTIPLE OF 3 (and likely one of the larger multiples of 3 in the answer choices).
The second piece of information tells us...
X+Y+Z = 26
By extension...
X+(Y+Z) = 26
X+(larger multiple of 3) = 26
From the answer choices, there are really only 2 options that make any sense: Answers D and E....
With Answer D:
IF....Y+Z = 12, then X= 14, but....
The first piece of information tells us that X = 1/4 of Z, so X has to be relatively small....In this example, it's LARGER than Z, so D is NOT the answer. At this point, the answer would have to be E, but here's the proof...
IF...Y+Z = 24 and Y= 2Z....
Y = 16
Z = 8
X is 1/4 of Z, so X = (1/4)(8) = 2
X+Y+Z=26
2+16+8=26
All of the numbers 'fit' what we were told, so this MUST be the answer.
E
Answer: (E) 24 IS ANSWER
Question: A merchant mixes three varieties of rice costing Rs.20/kg, Rs.24/kg and Rs.30/kg and sells the mixture at a profit of 20% at Rs.30 / kg. How many kgs of the second variety will be in the mixture if 2 kgs of the third variety is there in the mixture?
(A) 1 kgs
(B) 3 kgs
(C) 5 kgs
(D) 6 kgs
(E) None of these
Rationale: Explanation :
If the selling price of mixture is Rs.30/kg and the merchant makes a profit of 20%, then the cost price of the mixture = 30/1.2 = Rs.25/kg.
We need to find out the ratio in which the three varieties are mixed to obtain a mixture costing Rs.25 /kg.
Let variety A cost Rs.20/kg, variety B cost Rs.24 / kg and variety C cost Rs.30/kg. The mean desired price falls between B and C.
Step 1:
Find out the ratio Qa:Qc using alligation rule.
Qa/Qc=(30−25)/(25−20)=1/1.
Step 2:
Find out the ratio Qb:Qc using alligation rule.
Qb/Qc=30−25/(25−24)=5/1.
Step 3:
Qc is found by adding the value of Qc in step 1 and step 2 =1+1=2.
Therefore, the required ratio =1:5:2.
If there are 2 kgs of the third variety in the mixture, then there will be 5 kgs of the second variety in the mixture.
Answer : C
Answer: (C) 5 kgs
Question: Find the area of a parallelogram with base 24 cm and height 12 cm?
(A) 198 cm2
(B) 288 cm2
(C) 279 cm2
(D) 128 cm2
(E) 297 cm2
Rationale: Area of a parallelogram
= base * height
= 24 * 12 = 288 cm2
Answer:B
Answer: (B) 288 cm2
Question: Arjun started a business with Rs. 20,000 and is joined afterwards by Anoop with Rs.40, 000. After how many months did Anoop join if the profits at the end of the year are divided equally?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: Suppose Anoop joined after 3 months.
Then, 20000 * 12 = 40000 * (12 – x)
=>
=> x = 6.
ANSWER:D
Answer: (D) 6
Question: If a is a positive integer, which of the following could NOT be the square of a?
(A) 2432
(B) 7426
(C) 5966
(D) 3415
(E) 2155
Rationale: A number ending in 2 cannot be a perfect square.
2432 ends in a number 2, making that the correct answer
(A) 2432
Answer: (A) 2432
Question: The difference between the simple interest received from two different sources on Rs. 1400 for 3 years is Rs. 13.50. The difference between their rates of interest is?
(A) A)2.4%
(B) B)2.6%
(C) C)0.2%
(D) D)2.0%
(E) E)1.3%
Rationale: (1400 * R1 * 3)/100 - (1400 * R2 * 3)/100 = 13.50 4200(R1 - R2) = 1350
R1 - R2 = 0.2%
Answer:C
Answer: (C) C)0.2%
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 600 m long?
(A) 176 Sec
(B) 180 Sec
(C) 178 Sec
(D) 267 Sec
(E) 276 Sec
Rationale: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 1800 m
T = D/S
T = 1800/10
T = 180 Sec
Answer:B
Answer: (B) 180 Sec
Question: A pack of baseball cards consists of 12 outfielder cards and 8 infielder cards. What is the lowest number of outfielder cards that would have to be removed from the pack so that no more than 25 percent of the pack would be outfielder cards?
(A) 10
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: let the number of O card to be removed=X
then remaning cards=12-X
now this 12-X cards should count less than 25% of toatal Ocards
12-X<.25*12
X>12-3
X>9
X=10
Ans A
Answer: (A) 10
Question: The average of the marks of 10 students in a class is 80. If the marks of each student are doubled, find the new average?
(A) 80
(B) 120
(C) 160
(D) 270
(E) 110
Rationale: Sum of the marks for the 10 students
= 10 * 80= 800. The marks of each student are doubled, the sum also will be doubled.
The new sum = 800 * 2 = 1600. So, the new average
= 1600/10 = 160.
Answer:C
Answer: (C) 160
Question: What least number must be subtracted from 427398 so that remaining no.is divisible by 11
(A) 3
(B) 4
(C) 6
(D) 7
(E) 8
Rationale: Explanation:
On dividing 427398 by 11 we get the remainder 4, so 4 should be subtracted
Answer: Option B
Answer: (B) 4
Question: Water tax is increased by 20% but its consumption is decreased by 20%. Then, the increase or decrease in the expenditure of the money is :
(A) No change
(B) 5% decrease
(C) 4% increase
(D) 4% decrease
(E) None
Rationale: Explanation:
Let tax=Rs.100 and
Consumption=100 units
Original expenditure = Rs.(100×100)=Rs.10000(100×100)=Rs.10000
New expenditure = Rs.(120×80)=Rs.9600(120×80)=Rs.9600
Decrease in expenditure
= (400/10000×100)%=4%
Correct Option: D
Answer: (D) 4% decrease
Question: A shopkeeper buys mangoes at the rate of 5 a rupee and sells them at 3 a rupee. Find his net profit or loss percent?
(A) 66 2/3 %
(B) 33 7/3 %
(C) 33 1/3 %
(D) 33 5/8 %
(E) 34 1/3 %
Rationale: The total number of mangoes bought by the shopkeeper be 15.
If he buys 5 a rupee, his CP = 3
He selling at 3 a rupee, his SP = 5
Profit = SP - CP = 5 - 3 = 2
Profit Percent = 2/3 * 100 = 66 2/3 %
Answer: A
Answer: (A) 66 2/3 %