mathewhe/aqua_rat huggingface dataset:
Question: On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction Q of the total distance did he cover while the sun was shining on him?
(A) 1/4
(B) 4/5
(C) 1/5
(D) 1/6
(E) 1/7
Rationale: If s is an integer and we know that the average speed is 2.8, s must be = 2. That meanss+1= 3. This implies that the ratio of time for s=2 is 1/4 of the total time. The formula for distance/rate is D=Rt...so the distance travelled when s=2 is 2t. The distance travelled for s+1=3 is 3*4t or 12t. Therefore, total distance covered while the sun was shining over him is Q=2/14 = 1/7. Answer: E
Answer: (E) 1/7
Question: A, B, C, D, E, F are the only six families in Indira Nagar. A, B, C, D, E and F has 7, 8, 10, 13, 6, and 10 member in their families respectively. If 1 member from all the six families left their respective families to accommodate themselves in the hostel of IIM Lucknow, then the average number of member now in each family of Indira nagar is
(A) 8
(B) 9
(C) 10
(D) 13
(E) 15
Rationale: Answer
Required average
= (( 7 - 1 ) + ( 8 - 1 ) + ( 10 - 1 ) + ( 13 - 1 ) + (6 - 1) +( 10 - 1 ) )/ 6
= ( 7 + 8 +10 + 13 + 6 + 10 ) / 6 - ( 6 x 1 ) / 6
=9 - 1 = 8
Correct Option: A
Answer: (A) 8
Question: Two taps can fill a tank in 12 and 18 minutes respectively. Both are kept open for 2 minutes and the first is turned off. In how many minutes more will the tank be filled ?
(A) 15 min.
(B) 20 min.
(C) 11 min.
(D) 13 min.
(E) None of these
Rationale: Part filled by first tap in one min = 1⁄12th
Part filled by second tap in one min = 1⁄18th
Now, 2[1⁄12 + 1⁄18] + unfilled part = 1
⇒ unfilled part = 13⁄18th
∵ 1⁄18th part of tank is filled by second tap in 1 min.
∴ 13⁄18th part of tank is filled by second tap in 1 min.
= 18 × 13⁄18 min = 13 min.
Answer D
Answer: (D) 13 min.
Question: A metallic sphere of radius 12 cm is melted and drawn into a wire, whose radius of cross section is 16 cm. What is the length of the wire?
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
Rationale: Volume of the wire (in Cylindrical shape) is equal to the volume of the sphere.
π(16)2 * h = (4/3)π (12)3 => h = 9 cm
Answer: Option E
Answer: (E) 9
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is?
(A) 176 m
(B) 198 m
(C) 197 m
(D) 150 m
(E) 168 m
Rationale: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15
=> y = x/15
x + 100 / 25
= x / 15
x = 150 m.
Answer:D
Answer: (D) 150 m
Question: The quantities S and T are positive and are related by the equation S=K/T, where k is a constant. If the value of S increases by 40 percent, then the value of T decreases by what percent?
(A) 25%
(B) 33 ¹/₃%
(C) 50%
(D) 66 ²/₃%
(E) 75%
Rationale: We can assign numbers:
lets say S = 2, K = 6 (constant) and T = 3 (so that S=K/T)
Now increasing S by 40% gives S=3, K remains constant, so T = 2 (6/2=3)
decrease in T= 1, percent decrease in T = (1/3)*100 = 33.33%
Answer B
Answer: (B) 33 ¹/₃%
Question: If 10 litres of an oil of Rs.55 per litres be mixed with 5 litres of another oil of Rs.66 per litre then what is the rate of mixed oil per litre?
(A) Rs.49.17
(B) Rs.51.03
(C) Rs.58.66
(D) Rs.55.33
(E) None of the above
Rationale: 55*10 = 550
66*5 = 330
880/15 = 58.66
ANSWER:C
Answer: (C) Rs.58.66
Question: What should be added to 4872 so that it may become a perfect square?
(A) 24
(B) 25
(C) 26
(D) 27
(E) 28
Rationale: 70x70=4900
4900-4872 = 28
If added to 28 get perfect square
answer =E
Answer: (E) 28
Question: Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
(A) 1234
(B) 1345
(C) 1564
(D) 1670
(E) 1635
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Large number = 270+1365 = 1635
E
Answer: (E) 1635
Question: There is a sequence An for a positive integer n such that when An-2 is divided by An-1 the remainder is An. If A3=6, A4=0, which of the following can be the value of A1?
(A) 48
(B) 50
(C) 52
(D) 56
(E) 58
Rationale: When A1/A2, Remainder = A3 = 6 --> A1 = xA2 + 6
When A2/A3, Remainder = A4 = 0 --> A2 = yA3
A1 = xyA3 + 6 = kA3 + 6 = 6(k + 1) --> A1 must be a multiple of 6
Only option A is a multiple of 6
Answer: A
Answer: (A) 48
Question: In a colony of 70 residents, the ratio of the number of men and women is 5: 2. Among the women, the ratio of the educated to the uneducated is 1 : 4. If the ratio of the number of educated to uneducated persons is 8 : 27, then find the ratio of the number of educated to uneducated men in the colony?
(A) A)1:5
(B) B)1:1
(C) C)1:8
(D) D)1:9
(E) E)1:3
Rationale: Number of men in the colony = 5/7 * 70 = 50.
Number of women in the colony = 2/7 * 70 = 20.
Number educated women in the colony = 1/5 * 30 = 6.
Number of uneducated women in the colony = 4/5 * 50 = 24.
Number of educated persons in the colony = 8 /35 * 70 = 16.
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 50 - 10 = 40.
Number of educated men and uneducated men are in the ratio 10 : 40 i.e., 1:4.
Answer:A
Answer: (A) A)1:5
Question: Keats Library purchases a number of new books, all in the category of biography, and the library does not acquire any other books. With the addition of the new biographies, the biography collection of the library amounts to 32% of the total number of books in the library. If prior to the purchase, only 20% of the books in Keats Library were biographies, by what percent has the number of biographies in the library increased?
(A) 60%
(B) 72%
(C) 88%
(D) 95%
(E) 110%
Rationale: Let x be the number of new biographies added to the library.
Let b be the original number of biographies, so the original number of books was 5b.
0.32(5b+x) = b+x
0.6b = 0.68x
x = 0.88b
The answer is C.
Answer: (C) 88%
Question: Which of the following is the best approximation for y?
1/2−1/3+1/6−1/10+1/12−1/14+1/16
(A) 0.1
(B) 0.31
(C) 0.35
(D) 0.4
(E) 0.6
Rationale: 1/2 - 1/3 +1/6-1/10+1/12-1/14+1/16
=> 1/2 [1+1/3-1/5+1/6-1/7+1/8] - 1/3
=> 0.5 [ 1+0.33-0.2+0.167-0.142+0.125] - 0.33
=> 0.31
Option B
Answer: (B) 0.31
Question: The students of a particular class were given two tests for evaluation. Twenty Five percent of the class cleared both the tests and forty five percent of the students were able to clear the first test.
You have to calculate the percentage of those students who passed the first test and were also able to pass the second test. How will you do it?
(A) 48%
(B) 55%
(C) 60%
(D) 71%
(E) 80%
Rationale: C
60%
In all such cases where you have to find out the probability of anything with an already given situation, you have to use the formula for conditional probability.
In this case, you have to find out the probability that the second test was passed by a student given that he passed the first test already.
Therefore, P(Second/First) = P (First and Second)/ P (First)
= 0.25/0.42
=0.60
=60 %
Answer: (C) 60%
Question: How many different possible arrangements can be obtained from the letters G, M, A, T, I, I, and T, such that there is at least one character between both I's?
(A) 360
(B) 720
(C) 900
(D) 1800
(E) 5040
Rationale: A= all possible permutations = 7!/2!2!
B= permutations with II together = 6!/2!
A-B = 900
ANSWER:C
Answer: (C) 900
Question: Caleb spends $70.50 on 50 hamburgers for the marching band. If single burgers cost $1.00 each and double burgers cost $1.50 each, how many double burgers did he buy?
(A) 5
(B) 10
(C) 20
(D) 41
(E) 45
Rationale: Solution -
Lets say, Single hamburgersxand Double hamburgersy
Given that,
x+y=50 and 1x+1.5y=70.50. By solving the equations y=41. ANS D.
Answer: (D) 41
Question: A tourist purchased a total of $1,700 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
(A) $1,430
(B) $1,310
(C) $1,290
(D) $1,470
(E) $1,150
Rationale: since total cashed checks = 7 ans $10 check cashed = one less or more than $50 checks
Therefore either $10 checks = 3 and $50 checks = 4 OR $10 checks = 4 and $50 checks = 3
using this information 1st option gives us the maximum cashed value therefore if we negate this value from total value we will get minimum value of which checks have lost
Therfore 1700 - 230 = 1470 hence answer is D
Answer: (D) $1,470
Question: The least number which when divided by 2,3, 4 and 6 leaves a remainder 3, but when divided by 9 leaves no remainder, is
(A) 17
(B) 27
(C) 25
(D) 33
(E) None of these
Rationale: Explanation:
L.C.M of 2, 3, 4, 6= 12
therefore Required Number is of the form 12k+3.
Least value of k for which (12k+3) is divisible by 9 is k = 2
therefore Required Number = (12 x 2+3)=27. Answer: B
Answer: (B) 27
Question: A customer bought a product at the shop. However, the shopkeeper increased the price of the product by 20% so that the customer could not buy the required amount of the product. The customer managed to buy only 70% of the required amount. What is the difference in the amount of money that the customer paid for the second purchase compared to the first purchase?
(A) 16%
(B) 18%
(C) 20%
(D) 22%
(E) 24%
Rationale: Let x be the amount of money paid for the first purchase.
The second time, the customer paid 0.7(1.2x)=0.84x.
The difference is 16%.
The answer is A.
Answer: (A) 16%
Question: If (A-B-C+D = 12) and (A+B-C-D = 6), what is the value of (B-D)^2?
(A) 4.
(B) 9.
(C) 12.
(D) 16.
(E) 64.
Rationale: EQ1: A - B - C + D = 12
EQ2: A + B - C - D = 6
(1) Subtract EQ1 from EQ2
A - B - C + D = 12
- A +B - C - D = 6
------------------------
-2B + 2D = 6
(2) Simplify
-B + D = 3
B - D = -3
(B-D)^2 = (-3)^2 = 9
My answer: B
Answer: (B) 9.
Question: Of the families in City X in 2001, 25 percent owned a personal computer. The number of families in City X owning a computer in 2008 was 15 percent greater than it was in 2001, and the total number of families in City X was 6 percent greater in 2008 than it was in 2001. what percent of the families in City X owned a personal computer in 2008?
(A) 27.12%
(B) 23.12%
(C) 25.55%
(D) 31.22%
(E) 56.22%
Rationale: Say a 100 families existed in 1994 then the number of families owning a computer in 1994 - 25
Number of families owning computer in 1998 = 25 * 115/100 = 28.75
Number of families in 1998 = 106
The percentage = 28.75/106 * 100 = 27.12%.
ANSWER:A
Answer: (A) 27.12%
Question: A rectangular cube has a volume of 9 cubic feet. If a similar cube is twice as long, twice as wide, and twice as high, then the volume, in cubic feet of such cube is?
Choices
(A) 24
(B) 48
(C) 81
(D) 72
(E) 100
Rationale: Lets say the sides of the rectangular cube are x, y and z. Problem states volume is 9.
i.e,
x*y*z = 9 .
If every side is increased twice as before. then new volume is
2x*2y*2z = 9*(x*y*z) = 8*9 = 72.
Answer is D
Answer: (D) 72
Question: John throws a coin until a series of seven consecutive heads or three consecutive tails appears. What is the probability that the game will end after the eighth throw?
(A) 1/128
(B) 2/16
(C) 3/16
(D) 7/16
(E) 9/16
Rationale: Let's consider the routes that would lead to ending the game on the fourth toss. In order to be a win at that point, tosses #2#3#4 would all have to be the same, either H or T, and in order for the game NOT to end on the third toss, the first toss would have to be different from the other four. Thus, the only two possible sequences are
H-T-T-T--T-T-T-T ----> P = (1/2)^8 = 1/256
T-H-H-H-H-H-H-H ----> P = (1/2)^8 = 1/256
Either one of these would satisfy the condition, so we could have one or the other. OR means add in probability.
1/256 + 1/256 = 2/256 = 1/128
Answer(A).
Answer: (A) 1/128
Question: Bhajan Singh purchased 120 reams of paper at Rs 80 per ream. He spent Rs 280 on transportation, paid octroi at the rate of 40 paise per ream and paid Rs 72 to the coolie. If he wants to have a gain of 8 %, what must be the selling price per ream?
(A) 90
(B) 89
(C) 87.48
(D) 86
(E) 85
Rationale: Explanation:
Total investment = Rs. (120 * 80 + 280 + (40/100) * 120 + 72).
= Rs. (9600 + 280+48 + 72) = Rs, 10000.
Sell price of 120 reams = 108% of Rs. 10000 = Rs. 10800.
Sell Price per ream = Rs. [10800/120] = Rs. 90. Answer: A
Answer: (A) 90
Question: Seed mixture X is 40% ryegrass and 60% bluegrass by weight; seed mixture Y is 25% ryegrass and 75% fescue. If a mixture of X and Y contains 34% ryegrass, what percent of the weight of the mixture is from mixture X?
(A) 25%
(B) 40%
(C) 50%
(D) 60%
(E) 75%
Rationale: 34% is 9%-points above 25% and 6%-points below 40%.
Thus the ratio of mixture Y to mixture X is 2:3.
The percent of mixture X is 3/5 = 60%.
The answer is D.
Answer: (D) 60%
Question: The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275 , then the other is
(A) 344
(B) 387
(C) 308
(D) 299
(E) 882
Rationale: Explanation:
other number = \inline \fn_jvn \left ( \frac{11\times 7700}{275} \right ) = 308
Answer: C) 308
Answer: (C) 308
Question: Find the greatest number, which will divide 260, 281 and 303, leaving 7, 5 and 4 as remainders respectively.
(A) 23
(B) 24
(C) 25
(D) 26
(E) 27
Rationale: Ans: We have to find the HCF of (260 - 7, 281 - 5, 303 - 4) = HCF (253, 276, 299) = 23
Answer A
Answer: (A) 23
Question: Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years.
(A) 893.09
(B) 392.98
(C) 306.04
(D) 830.48
(E) 345.91
Rationale: A = 5000(51/50)3
= 5306.04
5000
-----------
306.04
Answer:C
Answer: (C) 306.04
Question: In a certain brick wall, each row of bricks above the bottom row contains one less brick than the row just below it. If there are 6 rows in all and a total of 135 bricks in the wall, how many bricks does the bottom row contain ?
(A) 21
(B) 20
(C) 22
(D) 19
(E) 24
Rationale: The bottom row has x bricks
x+x-1+x-2+x-3+x-4+x-5 = 135
6x-15=135
6x=120
x= 20
Answer:B
Answer: (B) 20
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 57 kmph, find the speed of the stream?
(A) 19
(B) 88
(C) 14
(D) 12
(E) 17
Rationale: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 57/3 = 19 kmph.
Answer:A
Answer: (A) 19
Question: In how many ways can you line up 7 wrestlers in a row if one of them, Houdidi, cannot be in the middle or at the either end?
(A) 1,850
(B) 929
(C) 828
(D) 724
(E) 2,880
Rationale: Since Houdini cannot be placed in the middle or at either end (3 spots), then he can choose 4 spots to sit. The remaining 6 apples can be placed in in 6! ways. Thus the # of arrangements is 4*6! = 2,880.
Answer: E.
Answer: (E) 2,880
Question: A total of 115 homes within Verde county were damaged during a terrible storm. The county had an emergency fund of $509,862.50 to be disbursed among households that incurred damage. The funds were distributed so that two story homes received $6,219.70 whereas one story homes received $3109.85. What was the number of damaged one story homes?
(A) 75
(B) 80
(C) 95
(D) 100
(E) 115
Rationale: Let x = two story homes
115 - x = one story homes
6219.70x + 3109.85(115 - x) = 590862.50
6219.70x + 357623.75 - 3109.85x = 590862.50
3109.85x = 233238.75
x = 75
Answer: A
Answer: (A) 75
Question: If the area of circle is 960 sq cm then its circumference?
(A) 11
(B) 88
(C) 99
(D) 266
(E) 110
Rationale: 22/7 r2 = 960 => r = 17.5
2 * 22/7 * 17.5 = 110 Answer: E
Answer: (E) 110
Question: How many arrangements can be made out of the letters of the word 'ENGINEERING'?
(A) 277200
(B) 92400
(C) 69300
(D) 23100
(E) 85600
Rationale: The word 'ENGINEERING' contains 11 letters, namely 3E, 3N, 2G, 2I and 1R.
Required number of arrangements =11!/(3!)(3!)(2!)(2!)(1!)=277200
Answer is A
Answer: (A) 277200
Question: If x, y, and z are consecutive positive integers greater than 1, not necessarily in that order, then which of the following is (are) true?
I. x > z
II. 5x+ 5y >5z
III. yz > xz
IV. xy > y + z
(A)  I only
(B)  II only
(C)  II and III only
(D)  II and IV only
(E)  III and IV only
Rationale: we do not know the values or the relative values but that the three are consecutive..
so the max difference in any two number is 2 and min 1..
lets see the choices..
I. x > z...
we do not know the values or the relative values... need not be true..
II. 5x+ 5y >5z or x+ y > z
we take the worst case that z is teh largest and x and y are lowest possible..... so 2+3>4.. 5>4.. always true
III. yz > xz
we do not know the values or the relative values between x and y..need not be true
IV. xy > y + z
xy-y>z or y(x-1)>z...
again lets take the worst scenario..
we take the worst case that z is the largest and x and y are lowest possible..... so (2-1)3>4.. 3>4.. not true
only ii is true
ans B
Answer: (B)  II only
Question: On a map the distance between two mountains is 310 inches. The actual distance between the mountains is 136 km. Ram is camped at a location that on the map is 34 inch from the base of the mountain. How many km is he from the base of the mountain?
(A) 14.83
(B) 14.81
(C) 14.91
(D) 14.82
(E) 14.12
Rationale: Explanation:
Since 310 inch = 136 km
So 1 inch = 136/310 km
So 34 inch = (136 Ã— 34)/ 310 = 14.91 km
Answer: C
Answer: (C) 14.91
Question: If the fraction 9/6 is equivalent to 6/a, then a is
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: Solution:
If the fractions are equivalent, then 9 × a = 36
a = 36 ÷ 9 = 4
Answer A
Answer: (A) 4
Question: Rectangle A has sides a and b, and rectangle B has sides c and d. If a/c=b/d=2/5, what is the ratio of rectangle A’s area to rectangle B’s area?
(A) 2/5
(B) 2/25
(C) 5/2
(D) 5/4
(E) 4/25
Rationale: The area of rectangle A is ab.
c=5a/2 and d=5b/2.
The area of rectangle B is cd=25ab/4.
The ratio of rectangle A's area to rectangle B's area is ab / (25ab/4) = 4/25.
The answer is E.
Answer: (E) 4/25
Question: The sum of four consecutive even numbers is 52, Find the third number ?
(A) 14
(B) 10
(C) 12
(D) 16
(E) 20
Rationale: Let the first number be n
Let the second number be n + 2
Let the third number be n + 4
Let the third number be n + 6
n + n + 2 + n + 4 + n + 6 = 52
Combine like terms:
4n + 12 = 52
4n + 12 = 52
4n = 52 - 12
4n = 40
n = 10
n + 2 = 12
n + 4 = 14
n + 6 = 16
The third number is 14
Answer: A
Answer: (A) 14
Question: An insect leaps 48 centimeters in 1.2 seconds. What is its speed?
(A) 0.4 meters per second
(B) 4 meters per second
(C) 40 meters per second
(D) 4 centimeters per second
(E) 0.4 centimeters per second
Rationale: 48 / 1.2 = 40 cm/s = 0.4 m/s
The answer is A.
Answer: (A) 0.4 meters per second
Question: A man sells two articles for Rs.3600 each and he gains 40% on the first and loses 40% on the next. Find his total gain or loss?
(A) 16% loss
(B) 400
(C) 4000
(D) 324
(E) 8% LOSS
Rationale: (40*40)/100 = 16%loss
ANSWER:A
Answer: (A) 16% loss
Question: If x and y are integers and x divided by y is 22.15, then which of the following integers is a possible value for the remainder when x is divided by y? I. 15 II. 5 III. 3
(A) II,III only
(B) I,III only
(C) I,II only
(D) I only
(E) III only
Rationale: x=22.15y from which x = 22y + 15y/100 or x = 22y + 3y/20.
Since x and y are integers, 3y/20 must also be an integer. 3 is not divisible by 20, then y must be divisible by 20, and therefore, y/20 is an integer and 3y/20 is an integer which is a multiple of 3. From the given answers, only 15 and 3 are divisible by 3.
Answer B
Answer: (B) I,III only
Question: Solution for 4.75+.303+.432
(A) 2.91
(B) 5.911
(C) 5.485
(D) 5.986
(E) 2.999
Rationale: 4.75+.303+.432=0
0=0-4.75-0.303-0.432
0=-5.485
answer :C
Answer: (C) 5.485
Question: The price of an item is discounted 6 percent on day 1 of a sale. On day 2, the item is discounted another 6 percent, and on day 3, it is discounted an additional 10 percent. The price of the item on day 3 is what percentage of the sale price on day 1?
(A) 82.3%
(B) 84.6%
(C) 85.6%
(D) 89.6%
(E) 79.2%
Rationale: Let initial price be 100
Price in day 1 after 6% discount = 94
Price in day 2 after 6% discount = 88.36
Price in day 3 after 10% discount = 79.52
So, Price in day 3 as percentage of the sale price on day 1 will be = 79.52//94*100 => 84.6%
Answer will definitely be (B)
Answer: (B) 84.6%
Question: In a recent head-to-head run-off election, 12,000 absentee ballets were cast. 1/2 of the absentee ballets were thrown out and 1/2 of the remaining absentee ballets were cast for Candidate A. How many absentee votes did Candidate B receive?
(A) 2,000
(B) 3,000
(C) 6,000
(D) 8,000
(E) 9,000
Rationale: 1/2 * 1/2 (total absentee votes) = 1/4 (total votes)=1/4*12000=3000
Answer is B
Answer: (B) 3,000
Question: A person covered one-fourth of the total distance at 22 kmph and remaining distance at 24 kmph. What is the average speed for the total distance?
(A) 21 (7/8)kmph
(B) 23 (7/15)kmph
(C) 23 (7/3)kmph
(D) 27 (1/13)kmph
(E) 21 (1/8)kmph
Rationale: Let the total distance be x km
total time taken = (x/4)/22 + (3x/4)/24 = x/88 + x/32 = 15x/352
Average speed = x/(15x/352) = 352/15kmph
= 23 (7/15)kmph.
Answer:B
Answer: (B) 23 (7/15)kmph
Question: In what time will a train 120 m long cross an electric pole, it its speed be 160 km/hr?
(A) 2.5 sec
(B) 2.9 sec
(C) 2.7 sec
(D) 8.7 sec
(E) 8.5 sec
Rationale: Speed = 160 * 5/18 = 44 m/sec
Time taken = 120/44 = 2.7 sec.
Answer: C
Answer: (C) 2.7 sec
Question: A person travels equal distances with speeds of 50km/hr,100km/hr and 120km/hr and takes a total time of 23 minutes. The total distance is?
(A) 15km
(B) 30km
(C) 45km
(D) 50km
(E) 60km
Rationale: Let the total distance be 3x km
x/50 + x/100 + x/120 = 23/60
23x/600 = 23/60
23x = 230
x = 10km
Total distance = 3x = 30km
Answer is B
Answer: (B) 30km
Question: The price of a book is increased from $300 to $360. What is the % of increase in its price?
(A) 10%
(B) 20%
(C) 40%
(D) 50%
(E) 60%
Rationale: Explanation: Change in the price = Rs 360 – Rs 300
= Rs 60
Percentage of increase = Change in the price Initial Price
* 100.
Percentage increase in price =( 60 300
) *100 = 20%
B
Answer: (B) 20%
Question: A rabbit on a controlled diet is fed daily 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If the rabbit`s diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?
(A) 100
(B) 140
(C) 150
(D) 160
(E) 200
Rationale: Let there be X and Y gm of food.
0.10 X + 0.15 Y = 38
or 10 X + 15 Y = 3800 -----(1)
X + Y = 300 ---------(2)
1) + 2) Eliminating Y, we get
X = 140 gm
ANSWER:B
Answer: (B) 140
Question: 50 % of 2 is equal to
(A) 0.2
(B) 1.0
(C) 0.6
(D) 0.7
(E) 0.9
Rationale: 50 % of 2 = (50 / 100) * 2 = 1.0
Answer: Option B
Answer: (B) 1.0