mathewhe/aqua_rat huggingface dataset:
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
(A) 140 sq.units
(B) 556 sq.units
(C) 155 sq.units
(D) 146 sq.units
(E) 142 sq.units
Rationale: Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10 = 140 sq.units
Answer:A
Answer: (A) 140 sq.units
Question: The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned.
(A) 19828.89
(B) 19828.8
(C) 19828.37
(D) 19828.82
(E) 19828.87
Rationale: Let the sum be Rs.P
P{ [ 1 + 8/100]2 - 1 } = 2828.80
P(8/100)(2 + 8/100) = 2828.80 [a2 - b2
= (a - b) ( a + b)] P = 2828.80 / (0.08)(2.08)
= 1360/0.08 = 17000 Principal + Interest
= Rs.19828.80
Answer: B
Answer: (B) 19828.8
Question: The average age of three boys is 12 years and their ages are in proportion 4:5:9. What is the age in years of the youngest boy?
(A) 6
(B) 9
(C) 8
(D) 4
(E) 2
Rationale: 4x + 5x + 9x = 36
x =2
4x = 8
Answer: C
Answer: (C) 8
Question: If f(a)=a^2 and a is a positive integer, which of the following CANNOT be the value of f(f(a))?
(A) 256
(B) 16
(C) 81
(D) 1
(E) 165
Rationale: f(a)=a^2
f(f(a)) = (a^2)^2 = a^4
Therefore f(f(a)) will be numbers that are 4th power of other numbers.
Checking the options:
1 = 1^$
16 = 2^4
81 = 3^4
165. This cannot be written as the 4th power of any number
256 = 4^4
Answer: E
Answer: (E) 165
Question: How many times in a day, the hands of a clock are straight?
(A) 22
(B) 24
(C) 44
(D) 48
(E) 46
Rationale: In 12 hours, the hands coincide or are in opposite direction 22 times.
In 24 hours, the hands coincide or are in opposite direction 44 times a day.
ANSWER:C
Answer: (C) 44
Question: The moon revolves around the earth at a speed of approximately 1.03 kilometers per second. This approximate speed is how many kilometers per hour?
(A) 60
(B) 61.2
(C) 62.5
(D) 3,708
(E) 3,672
Rationale: moon revolves around the earth at a speed of 1.02kilometers per second.
one hour equal to 60 minutes.
one minute equals to 60 seconds. so one hour equals to 3600seconds.
so one hour, speed= 1.03*3600=3708kilometers per hour.
Option D is correct
Answer: (D) 3,708
Question: The slant height of a cone is 12 cm and radius of the base is 4cm, find the curved surface of the cone.
(A) 48 pi cm2
(B) 30 pi cm2
(C) 35 pi cm2
(D) 40 pi cm2
(E) 45 pi cm2
Rationale: Ï€ * 12 * 4 = 48
ANSWER A
Answer: (A) 48 pi cm2
Question: A survey of employers found that during 1993 employment costs rose 3.5 percent, where employment costs consist of salary costs and fringe-benefit costs. If salary costs rose 3 percent and fringe-benefit costs rose 9.5 percent during 1993, then fringe-benefit costs represented what percent of employment costs at the beginning of 1993 ?
(A)  16.5%
(B)  8%
(C)  35%
(D)  55%
(E)  65%
Rationale: The amount by which employment costs rose is equal to 0.035(salary costs + fringe benefit costs);
On the other hand the amount by which employment costs rose is equal to 0.03*salary costs + 0.095*fringe benefit costs;
So, 35(S+F) = 30S+95F --> S = F --> F/S = 1/12 --> F/(S+F) = 1/(1+12) = 1/13 = 0.08.
Answer: B.
Answer: (B)  8%
Question: When positive integer N is divided by positive integer P, the quotient is 18, with a remainder of 7. When N is divided by (P + 2), the quotient is 15 and the remainder is 1. What is the value of N?
(A) 151
(B) 331
(C) 511
(D) 691
(E) 871
Rationale: Use the rule dividend = (integer quotient)*(divisor) + remainder to translate each sentence.
The first sentence becomes N = 18P + 7. The second equation becomes N = (P + 2)*15 + 1, which simplifies to N = 15P + 31. These are ordinary simultaneous equations Since they both equal N already, let’s set them equal and solve for P.
18P + 7 = 15P + 31
3P + 7 = 31
3P = 24
P = 8
Now that we know P = 8, we can just plug in. The product 15*8 is particularly easy to do, without a calculator, by using the “doubling and halving” trick. Double 15 to get 30, and take half of 8 to get 4 —- 15*8 = 30*4 = 120. So
N = 15(8) + 31 = 120 + 31 = 151
N = 151, answer = A.
Answer: (A) 151
Question: If P represents the product of the first 18 positive integers, then P is NOT a multiple of
(A) 99
(B) 84
(C) 72
(D) 65
(E) 95
Rationale: Answer is E.
Since prime factor of 95 is 5x19. 19 is a prime number and not part of the first 18 positive integers.
A) 9 x 11
B) 12 x 7
C) 12 x 6
D) 13 x 5
E) 3 x 19
Answer: (E) 95
Question: how many zeros are there in 50!
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
Rationale: To find the number of trailing zeroes in 50! factorial we must find the number of integral values in :
50/5 + 50/5^2 + 50/5^3 +.........
= 10+2+0+0....
=12
ANSWER:C
Answer: (C) 12
Question: There are two numbers. If 40% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?
(A) 8 : 25
(B) 25 : 8
(C) 8 : 5
(D) 5 : 8
(E) None of these
Rationale: Let the two numbers be x and y.
40/100 * x + y = 5/4y
=> 2/5 x = 1/4 y => x/y = 5/8
ANSWER:D
Answer: (D) 5 : 8
Question: In 1995 a certain store had 1800 tools in stock that had been purchased for $30 each. If 1,000 of these tools were sold in 1995 for $50 each and the remaining 800 were sold in 1996 for $70 each, how many greater was the gross profit on the tools sold in 1996 than the gross profit on those sold in 1995?
(A) $12,000
(B) $6,000
(C) $8,000
(D) $32,000
(E) $40,000
Rationale: The keyword here isGross Profit:
Gross Profit = (Selling Price - Original Price)*(# of Items Sold)
So lets figure out what the Gross Profit for 1995:
GP1995 = (50-30)*(1000) = 20000
And the Gross Profit for 1996:
GP1996 = (70-30)*(800) = 32000
So the difference would be:
32000-20000 = 12000
ANSWER: A 12000
Answer: (A) $12,000
Question: A ship sails out to a mark at the rate of 12 kmph. and sails back at the rate of 8 kmph. The average rate of sailing is ?
(A) 5 km/hr
(B) 9.6 km/hr
(C) 12.5 km/hr
(D) 25 km/hr
(E) None
Rationale: Answer
Average = ( 2uv / u +v ) km/hr
= ( 2 x 12 x 8 ) / (12 +8 ) km/hr.
= 9.6 km/hr.
Correct Option: B
Answer: (B) 9.6 km/hr
Question: John Purchased 1370 large bottles at $1.99 per bottle and 690 small bottles at $1.50 per bottle. What was the approximate average price paid per bottle?
(A) $1.63
(B) $1.64
(C) $1.68
(D) $1.72
(E) $1.83
Rationale: (1370*1.99+690*1.50)/(1370+690) =~1.83
- Option (E)
Answer: (E) $1.83
Question: If x is the product of the positive integers from 1 to 8, inclusive, and if i, k, m, and p are positive integers such that x = 2^i * 3^k * 5^m * 7^p, then i + k + m + p =
(A) 4
(B) 7
(C) 8
(D) 11
(E) 12
Rationale: Given that x=8!=2^7∗3^2∗5∗7x. Hence, x=2^7∗3^2∗5^1∗7^1=2^i∗3^k∗5^m∗7p, since i, k, m, and p are positive integers, then we can equate the exponents, so we have that i=7, k=2, m=1, and p=1
Therefore, i+k+m+p=7+2+1+1=11
Answer: D.
Answer: (D) 11
Question: How many odd numbers between 10 and 800 are the squares of integers?
(A) 12
(B) 13
(C) 14
(D) 15
(E) 16
Rationale: The square of an odd number is an odd number:
10 < odd < 1,000
10 < odd^2 < 1,000
3.something < odd < 31.something (by taking the square root).
So, that odd number could be any odd number from 5 to 31, inclusive: 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, and 31.
12 numbers.
Answer: A.
Answer: (A) 12
Question: Two boats are heading towards each other at constant speeds of 5 miles/hr and 23 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ?
(A) 1/12
(B) 7/12
(C) 1/6
(D) 1/3
(E) 1/5
Rationale: The question asks: how far apart will they be 1 minute=1/60 hours before they collide?
Since the combined rate of the boats is 5+23=25 mph then 1/60 hours before they collide they'll be rate*time=distance --> 28*1/60=7/15 miles apart.
Answer: B.
Answer: (B) 7/12
Question: If 9 workers can build 9 cars in 9 days, then how many days would it take 7 workers to build 7 cars?
(A) 6
(B) 7
(C) 8
(D) 9
(E) 10
Rationale: 9 workers can build 1 car per day on average.
1 worker can build 1/9 of a car per day.
7 workers can build 7/9 car per day.
The time required to build 7 cars is 7 / (7/9) = 9 days
The answer is D.
Answer: (D) 9
Question: If the provisions last for 30 days for 3000 men then if after 10 men are included then the remaining provisions last for how many days?
(A) 29.9 days
(B) 39.9 days
(C) 19.9 days
(D) 49.9 days
(E) 20.9 days
Rationale: 3000 men use for 30 days. so for 1 person = 30/3000 days = 1/100 =0.01days
for 10 ppl,its 0.1. so for 3010 ppl,its 30 - 0.1 = 29.9 days
ANSWER:A
Answer: (A) 29.9 days
Question: A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that all the four bulbs are defective.
(A) 62/63
(B) 125/126
(C) 1/63
(D) 1/42
(E) 1/126
Rationale: Answer: Option E
Out of nine, five are good and four are defective. Required probability = â´câ‚„/â¹câ‚„ = 1/126
Answer: (E) 1/126
Question: Two brother X and Y appeared for an exam. The probability of selection of X is 1/7 and that of B is 2/9. Find the probability that both of them are selected.
(A) 2/69
(B) 2/60
(C) 2/63
(D) 2/29
(E) 2/10
Rationale: Explanation:
Let A be the event that X is selected and B is the event that Y is selected.
P(A) = 1/7, P(B) = 2/9.
Let C be the event that both are selected.
P(C) = P(A) × P(B) as A and B are independent events:
= (1/7) × (2/9) = 2/63
Answer: C) 2/63
Answer: (C) 2/63
Question: If the length, breadth and the height of a cuboid are in the ratio 6:5:4 and if the total surface area is 33300 cm2cm2, then the length , breadth and height in cms, are respectively.
(A) 90,85,60
(B) 85,75,60
(C) 90,75,70
(D) 90,75,60
(E) none
Rationale: Explanation:
Let length = 6x, breadth = 5x and height =4x in cm
2(6x×5x+5x×4x+6x×4x)=33300
148x2=33300⇒x2=33300/148=225⇒x=15
Length = 90 cm, Breadth = 75 cm and Height = 60 cm
Correct Option: D
Answer: (D) 90,75,60
Question: 150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?
(A) 62
(B) 60
(C) 65
(D) 73
(E) 64
Rationale: Explanation:
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 days'
Answer: Option B
Answer: (B) 60
Question: In May, the grounds keeper at Spring Lake Golf Club built a circular green with an area of 81π square feet. In August, he doubled the distance from the center of the green to the edge of the green. What is the total area of the renovated green?
(A) 100PI
(B) 144PI
(C) 196PI
(D) 256PI
(E) 324PI
Rationale: AREA OF CIRCLE 81PI SQ FEET =PI R^2 THEREFORE R =9
NOW GREEN RADI DOUBLED I.E R =18 AREA =324 PI
E
Answer: (E) 324PI
Question: Reeya obtained 65, 67, 76, 80 and 95 out of 100 in different subjects, What will be the average
(A) 76.6
(B) 75
(C) 80
(D) 85
(E) 90
Rationale: Explanation:
(65+67+76+80+95 / 5)=76.6
Option A
Answer: (A) 76.6
Question: In a class, there are 30 boys who are over 160 cm tall. If these constitute three-fourths of the boys and the total number of boys is two-thirds of the total number of students in the class, what is the number of girls in the class ?
(A) 6
(B) 12
(C) 18
(D) 24
(E) 20
Rationale: Explanation:
Let the number of boys be x. Then, (3/4)x = 30 or x = 30 x(4/3) = 40.
If total number of students is y, then (2/3) y = 40 or y = 40 x (3/2) = 60.
Therefore Number of girls in the class = (60 - 40) = 20.
Answer: E
Answer: (E) 20
Question: How many positive integers less than 10,000 are there in which the sum of the digits equals 5?
(A) 31
(B) 51
(C) 56
(D) 62
(E) 93
Rationale: Basically, the question asks how many 4 digit numbers (including those in the form 0XXX, 00XX, and 000X) have digits which add up to 5. Think about the question this way: we know that there is a total of 5 to be spread among the 4 digits, we just have to determine the number of ways it can be spread.
Let X represent a sum of 1, and | represent a separator between two digits. As a result, we will have 5 X's (digits add up to the 5), and 3 |'s (3 digit separators).
So, for example:
XX|X|X|X = 2111
||XXX|XX = 0032
etc.
There are 8C3 ways to determine where to place the separators. Hence, the answer is 8C3 = 56.
ANSWER:C
Answer: (C) 56
Question: The bankerâ€™s discount of a certain sum of money is Rs. 42 and the true discount on the same sum for the same time is Rs. 36. The sum due is
(A) 252
(B) 280
(C) 360
(D) 450
(E) None
Rationale: Sol.
Sum = B.D. * T.D. / B.D. - T.D. = Rs.[42 * 36 / 42 - 36] = Rs. [42 * 36 / 6] = Rs. 252
Answer A
Answer: (A) 252
Question: Kelly and Chris are moving into a new city. Both of them love books and thus packed several boxes with books. If Chris packed 60% of the total number of boxes, what was the ratio of the number of boxes Kelly packed to the number of boxes Chris packed?
(A) 4/3
(B) 2/3
(C) 1/3
(D) 3/4
(E) 1/4
Rationale: the ratio of the number of boxes Kelly packed to the number of boxes Chris packed = 40/60 = 2/3
ANSWER:B
Answer: (B) 2/3
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
(A) 298
(B) 270
(C) 245
(D) 267
(E) 239
Rationale: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x)
= 750 => x
= 245 m.
Answer:C
Answer: (C) 245
Question: a man can row 22 kmph in still water.it takes him thrice as long to row up as to row down the river.find the rate of stream
(A) 13 km/hr.
(B) 6 km/hr.
(C) 9 km/hr.
(D) 15 km/hr.
(E) 11 km/hr.
Rationale: Let manâ€™s rate upstream be x kmph.then ,his rate downstream=3xkmph.
So,2x=22 or x=11.
Rate upstream=11 km/hr,rate downstream=33 km/hr.
Hence,rate of stream=1/2(33-11)km/hr=11 km/hr.
Answer is E.
Answer: (E) 11 km/hr.
Question: The weights of three bags are in the ratio 4 : 5 : 6. If the sum of the weights of the heaviest and the lightest bag is 45 kg more than the weight of the third bag, what is the weight of the lightest bag?
(A) 45kg
(B) 38kg
(C) 66kg
(D) 36kg
(E) of these
Rationale: Let the weights of the three boys be 4k, 5k and 6k respectively.
4k + 6k = 5k + 45
=> 5k = 45 => k = 9
Therefore the weight of the lightest boy
= 4k = 4(9) = 36 kg.
ANSWER:D
Answer: (D) 36kg
Question: P and Q can do a work in 30 days. Q and R can do the same work in 24 days and R and P in 20 days. They started the work together, but Q and R left after 4 days. How many days more will P take to finish the work?
(A) 10
(B) 36
(C) 18
(D) 20
(E) 22
Rationale: Let work done by P in 1 day = p,
Work done by Q in 1 day = q,
Work done by R in 1 day = r
p + q = 1/30
q + r = 1/24
r + p = 1/20
Adding all the above, 2p + 2q + 2r = 1/30 + 1/24+ 1/20 = 15/120 = 1/8
=> p + q + r = 1/16
=> Work done by P,Q and R in 1 day = 1/16
Work done by P, Q and R in 4 days = 4 × (1/16) = 4/16 = 1/4
Remaining work = 1 = 1/4 = 3/4
Work done by P in 1 day = Work done by P,Q and R in 1 day - Work done by Q and R in 1 day
= 1/16 – 1/24 = 1/48
Number of days P needs to work to complete the remaining work = (3/4) / (1/48) = 36
Option B
Answer: (B) 36
Question: If a number between 0 and 1/2 is selected at random, which of the following will the number most likely be between
(A) 0 and 3/20
(B) 3/8 and 1/2
(C) 1/5 and 1/4
(D) 1/4 and 3/10
(E) 3/10 and 1/2
Rationale: B. 3/8 and 1/2
Definitely not. I am always happy to explain a given question or issue if I can. However, I sometime donot put my explanation if I am answering first because I want to put others first for their explanation.
Now you have excellent explanantion byscthakur. In fact the question is asking the likelyness of or high chances/probability of having a given number. Hope you already got it.B
Answer: (B) 3/8 and 1/2
Question: If n = 2.0767 and n* is the decimal obtained by rounding n to the nearest hundredth, what is the value of n* – n?
(A)  -0.0053
(B)  -0.0003
(C)  0.0007
(D)  0.0047
(E)  0.0033
Rationale: n*=2.08
n*-n=2.08-2.0767
0.0033
Answer: E
Answer: (E)  0.0033
Question: Two trains, A and B, started simultaneously from opposite ends of a 125-mile route and traveled toward each other on parallel tracks. Train A, traveling at a constant rate, completed the 125-mile trip in 12 hours; Train B, traveling at a constant rate, completed the 125-mile trip in 8 hours. How many miles had train A traveled when it met train B?
(A)  25
(B)  37.5
(C)  40
(D)  45.5
(E)  50
Rationale: As the ratio of the rates of A and B is 8 to 12 then the distance covered at the time of the meeting (so after traveling the same time interval) would also be in that ratio, which means that A would cover 8/(8+12)=8/20 of 125 miles: 125*8/20=50 miles.
Answer: E.
Answer: (E)  50
Question: If A(k)=(k+2)^k, and k=0, what is the value of A(A(A(k)))/(18^15)?
(A) 1
(B) 18
(C) 16
(D) 6
(E) 9
Rationale: A(A(A(0)))=A(A(2))=A(16)=18^16
18^16/18^15 = 18
Thus, the answer is B.
Answer: (B) 18
Question: If one person completes a journey in 10 hrs. He travels 1st half of the journey at the rate of 21 km/hr and 2nd half at therate of 24 km/hr. Find the total journey in km.
(A) 210 km
(B) 216 km
(C) 224 km
(D) 230 km
(E) 232 km
Rationale: distance = speed x time
Let time taken to travel the first half = x hr
then time taken to travel the second half = (10 - x) hr
Distance covered in the the first half = 21x
Distance covered in the the second half = 24(10 - x)
But distance covered in the the first half = Distance covered in the the second half
=> 21x = 24(10 - x)
=> 21x = 240 - 24x
=> 45x = 240
=> 9x = 48
=> 3x = 16
⇒x=163Hence Distance covered in the the first half = 21x=21×163=7×16=112 kmTotal distance = 2×112=224 km
C
Answer: (C) 224 km
Question: 17+18=35. How many such 2 consecutive numbers are there less than 200 when added gives a sum which is divisible by 5?
(A) 80
(B) 40
(C) 50
(D) 60
(E) 20
Rationale: since 2+3=5 & 7+8=15
any combination with these no be will give u desirable result...
so total no in 100 will be 20 & that's why in 200,it will be 40
ANSWER:B
Answer: (B) 40
Question: When a commodity is sold for $34.80, there is a loss of 2%. what is the cost price of the commodity?
(A) $46.40
(B) $48
(C) $42.60
(D) $43.45
(E) $52.60
Rationale: s.p. = $34.80
loss = 2%
c.p. = 100*34.80/75 = $46.40
correct option is A
Answer: (A) $46.40
Question: Two fractions 1/3 and 2/3 are given to you. Can you find a fraction that lies one third on the way between them?
(A) 10/15
(B) 13/19
(C) 11/32
(D) 12/27
(E) 15/30
Rationale: D
12/27
This is really simple if you know the concept. You just have to increase the fraction by multiplying with a number. In that way, you will increase the numerator and you will be able to find the required fraction. Here, we are multiplying the numerator and denominator of both the numbers with 9. Now if you simplify, the number will remain the same and thus dont think we changed the fraction.
1/3 * 9/9 = 9/27
2/3 * 9/9 = 18/27
Its easy to find the one third fraction on the way now i.e. 12/27.
Answer: (D) 12/27
Question: Three seventh of a number is 12 more than 40% of that number. What will be the 20% of that number?
(A) A)148
(B) B)210
(C) C)42
(D) D)248
(E) E)258
Rationale: 3/7 x – 40/100 x = 12
x = 35 * 12
35 * 12 * 20/100 = 84/2 = 42
ANSWER:C
Answer: (C) C)42
Question: The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 80/kg. how much did a kg of coffee cost in june ?
(A) 50
(B) 60
(C) 80
(D) 100
(E) 120
Rationale: Let the price of tea and coffee be x per kg in June.
Price of tea in July = 1.2x
Price of coffee in July = 0.8x .
In July the price of 1/2 kg (800gm) of tea and 1/2 kg (800gm) of coffee (equal quantities) = 80
1.2x(1/2) + 0.8x(1/2) = 80
=> x =80
Thus proved...option C.
Answer: (C) 80
Question: The L.C.M. of 2 numbers is 72. The numbers are in the ratio 2:3. Find their sum?
(A) 36
(B) 40
(C) 48
(D) 60
(E) 56
Rationale: Let the numbers be 2x and 3x
L.C.M. = 6x
6x = 72
x = 12
The numbers are = 24 and 36
Required sum = 24+36= 60
Answer is D
Answer: (D) 60
Question: The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.4180.What was his original salary?
(A) 2277
(B) 2999
(C) 4000
(D) 2651
(E) 1971
Rationale: X * (110/100) * (95/100) = 4180
X * (11/10) * (1/100) = 44
X = 4000
Answer: C
Answer: (C) 4000
Question: How many terms are there in 2, 4, 8, 16,..., 256?
(A) 14
(B) 11
(C) 12
(D) 10
(E) 8
Rationale: 2, 4, 8, 16, ..., 256 is a G.P with a =2
and r =4/2 =2
Let the number of terms be n. Then
2 x 2 ^n-1 = 256
or 2^n-1 =128 = 2^7
Thus n - 1 =7
n= 8
ANSWER:E
Answer: (E) 8
Question: X can finish a work in 36 days. Y can finish the same work in 24 days. Y worked for 12 days and left the job. how many days does X alone need to finish the remaining work?
(A) 12
(B) 13
(C) 16
(D) 17
(E) 18
Rationale: Work done by X in 1 day = 1/36
Work done by Y in 1 day = 1/24
Work done by Y in 12 days = 12/24 = 1/2
Remaining work = 1 – 1/2 = 1/2
Number of days in which X can finish the remaining work = (1/2) / (1/36) = 18
E
Answer: (E) 18
Question: A number, x is chosen at random from the set of positive integers less than 10. What is the probability that (8/x) > x?
(A)  1/5
(B)  2/8
(C)  1/3
(D)  2/3
(E)  7/9
Rationale: Number x has to be chosen from numbers 1-9
(8/x) > x
=> 8 > x^2
=>x^2 - 8 < 0
x can have 2 values only 1 , 2
Therefore , probability = 2 / 8
Answer B
Answer: (B)  2/8
Question: 20 is added to a certain number, the sum is multiplied by 2, the product is divided by 2 and 2 is subtracted from the quotient. The remainder left is half of 88. What is the number?
(A) 21
(B) 20
(C) 26
(D) 30
(E) 45
Rationale: Let number is X.
When 20 added to it,
= (X+20)
2 multiplied to sum,
= 2 *(X +20)
Now,
= [{2 *(X +20)} /2]
And,
= [{2 *(X +20)} /2] - 2
According to question,
[{2 *(X +20)} /2] - 2 = half of 88
[(2X + 40) /2) = 44 +2
2X + 40 = 46 * 2
X + 20 = 46
X = 46 - 20
X = 26
So, required number is: 26.
ANSWER : C
Answer: (C) 26
Question: ten family members: 5 grandchildren (3 brothers and 2 sisters) and their 5 grandparents are to be seated around a circular table. How many different seating arrangements are possible so that 2 sisters are seated between any two of the three brothers?
(A) 120
(B) 480
(C) 1440
(D) 2880
(E) 8640
Rationale: Answer: E.
Answer: (E) 8640
Question: In a certificate by mistake a candidate gave his height as 25% more than actual height. In the interview panel, he clarified that his height was 5feet 5 nches. Find the % correction made by the candidate from his stated height to his actual height?
(A) 10
(B) 20
(C) 30
(D) 40
(E) 50
Rationale: His height was = 5 feet 5 inch = 5 + 60 = 65 inch. Required % correction =65*(1.25-1)* 100 = 20
B
Answer: (B) 20
Question: If 18 is 15 percent of 25 percent of a certain number, what is the number?
(A) 9
(B) 36
(C) 480
(D) 81
(E) 400
Rationale: Let the certain number be x.
=> (15/100)*(25/100)*x = 18;
=> x=480;
Ans is (C).
Answer: (C) 480
Question: Q and R are two-digit positive integers that have the same digits but in reverse order. If the positive difference between Q and R is less than 60, what is the greatest possible value of Q minus R?
(A) 52
(B) 54
(C) 55
(D) 56
(E) 58
Rationale: A two-digit integer "ab" can be expressed algebraically as 10a+b.
Q-R=(10a+b)-(10b+a)=9(a-b)<60.
The greatest multiple of 9 which is less than 60 is 54.
The answer is B.
Answer: (B) 54
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
(A) 5.77
(B) 5.79
(C) 5.76
(D) 5.75
(E) 5.71
Rationale: M = 6
S = 1.2
DS = 7.2
US = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
D = 2.88 * 2 = 5.76
Answer:C
Answer: (C) 5.76