mathewhe/aqua_rat huggingface dataset:
Question: Cindy wants to buy dolls for her playhouse. Each doll costs $10. Cindy's mother gives her $30 to spend. How many dolls can Cindy buy with the money her mother gave her?
(A) 5
(B) 10
(C) 2
(D) 1
(E) 3
Rationale: E. 3
Answer: (E) 3
Question: Which of the following inequalities is equivalent to 2 + 5x > 17?
(A)  x > -2
(B)  x > 3
(C)  x > -3
(D)  x < -3
(E)  x < 3
Rationale: You can work with the inequality in the same way as you do when you have the equal to sign. You can take terms to the other side by flipping their sign, you can multiply/divide the inequality by the same term on both sides of the equation etc.
The only important thing to note is the following:
When you multiply/divide by a negative number, the sign of the inequality flips.
To illustrate,
2 + 5x > 17
5x > 15 (Correct)
x > 3 (Correct)
the correct option is B
Answer: (B)  x > 3
Question: A man has Rs. 560 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
(A) 90
(B) 94
(C) 96
(D) 105
(E) 99
Rationale: Let number of notes of each denomination be x.
Then x + 5x + 10x = 560
16x = 560
x = 35.
Hence, total number of notes = 3x = 105.
D
Answer: (D) 105
Question: I. x2 - x - 42 = 0,
II. y2 - 17y + 72 = 0 to solve both the equations to find the values of x and y?
(A) If x < y
(B) If x > y
(C) If x ≤ y
(D) If x ≥ y
(E) If x = y or the relationship between x and y cannot be established.
Rationale: I. x2 - 7x + 6x - 42 = 0
=> (x - 7)(x + 6) = 0 => x = 7, -6
II. y2 - 8y - 9y + 72 = 0
=> (y - 8)(y - 9) = 0 => y = 8, 9
=> x < y
ANSWER:A
Answer: (A) If x < y
Question: 4
x
<
y
<
0
which of the following is greatest?
(A) x+3y
(B) 2x-y
(C) -(5x+y)
(D) -x+2y
(E) 4x+3y
Rationale: Plugging in -1 for both x and y we get
A.x+3y =-4
B. 2x-y=-1
C. -(5x+y)=6
D. -x+2y =-1
E. 4x+3y=-7
Answer: C
Answer: (C) -(5x+y)
Question: Adam borrowed some money at the rate of 6% p.a. for the first two years, at the rate of 9% p.a. for the next three years, and at the rate of 14% p.a. for the period beyond five years. If he pays a total interest of 11,400 at the end of nine years, how much money did he borrow?
(A) 10,000
(B) 12,000
(C) 14,000
(D) 16,000
(E) None of these
Rationale: Let the sum borrowed be x. Then,
(x×6×21/00)+(x×9×3/100)+(x×14×4/100)= 11400
⇒ (3⁄25x + 27⁄100x + 14⁄25x) = 11400 ⇒ 95⁄100x = 11400
⇒ x = (11400×100/95)= 12000
Hence, sum borrowed = 12,000.
Answer B
Answer: (B) 12,000
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 110 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
(A) 28 sec
(B) 16 sec
(C) 35 sec
(D) 18 sec
(E) 17 sec
Rationale: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 110 = 350 m.
Time taken = 350/10 = 35 sec.
Answer:C
Answer: (C) 35 sec
Question: If 12 persons are seated in a row, the number of ways of selecting 3 persons from them, so that no two of them are seated next to each other is
(A) 85
(B) 100
(C) 120
(D) 240
(E) None of these
Rationale: The number of ways of selecting 3 persons from 12 people under the given condition :
Number of ways of arranging 3 people among 9 people seated in a row, so that no two of them are consecutive
= Number of ways of choosing 3 places out of the 10[8 in between and 2 extremes]
= 10C3 = 10×9×8/3×2×1=5×3×8=120
Answer C
Answer: (C) 120
Question: A is twice as good a workman as B and they took 7 days together to do the work B alone can do it in.
(A) 11 days
(B) 13 days
(C) 21 days
(D) 16 days
(E) 18 days
Rationale: WC = 2:1
2x + x = 1/7
x = 1/21 => 21 days
Answer: C
Answer: (C) 21 days
Question: An ant and a blind spider are on opposite corners of a cube. The ant is stationary and the spider moves at random from one corner to another along the edges only. What is the expected number of turns before the spider reaches the ant?
(A) 20
(B) 43
(C) 38
(D) 10
(E) 55
Rationale: The answer is 10.
If the spider started at a corner diagonally on the same face as the ant the answer would be 9, and if the spider started at an adjacent corner the answer would be 7.
Let x=number of turns to reach ant from starting point.
Let y=number of turns to reach ant from diagonal corner on same face as ant.
Let z=number of turns to reach ant from an adjacent corner to ant.
After one turn the spider will be on a diagonal corner of a common face as the ant. So the mean number of turns from the x position is one more than the mean number from the y position:
E(x)=1+E(y).
Once at a y position there is a 2/3 chance it will then move to a z position, and a 1/3 chance back to an x position:
E(y)=(2/3)*(1+E(z))+(1/3)*(1+E(x)).
If the spider arrives at a z position there is a 1/3 chance it will move to the ant, and a 2/3 chance it will move back to a y position:
E(z)=(1/3)*1+(2/3)*(1+E(y)).
With these three equations and three unknowns it is not difficult to solve for E(x), E(y), and E(z).
correct answer D
Answer: (D) 10
Question: Find the value of 72519 x 9999 = m?
(A) 345454621
(B) 565767443
(C) 457672466
(D) 725117481
(E) 665355224
Rationale: 72519 x 9999 = 72519 x (10000 - 1)
= 72519 x 10000 - 72519 x 1
= 725190000 - 72519
= 725117481
D
Answer: (D) 725117481
Question: The average of five numbers is 70. If one number is excluded, the average becomes 72. The excluded number is?
(A) 8
(B) 6
(C) 58
(D) 35
(E) 62
Rationale: Excluded number
= (70 * 5) - (72 * 4)
= 350 - 288 = 62
Answer:E
Answer: (E) 62
Question: Convert the 12/36 m/s into kilometers per hour?
(A) 3.5 kmph.
(B) 2.5 kmph.
(C) 1.2 kmph.
(D) 1.5 kmph.
(E) 1.9 kmph.
Rationale: 15/36 m/s = 12/36 * 18/5 = 1 (1/5) = 1.2 kmph.
ANSWER:C
Answer: (C) 1.2 kmph.
Question: The average age 4 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
(A) 8 years
(B) 17 years
(C) 18 years
(D) 12 years
(E) 11 years
Rationale: 4 * 2
= 8
Answer:A
Answer: (A) 8 years
Question: Real-estate salesman Z is selling a house at a 10 percent discount from its retail price. Real-estate salesman X vows to match this price, and then offers an additional 10 percent discount. Real-estate salesman Y decides to average the prices of salesmen Z and X, then offer an additional 10 percent discount. Salesman Y's final price is what fraction of salesman X's final price?
(A) 38/6
(B) 38/5
(C) 77/81
(D) 38/7
(E) 38/10
Rationale: Let the retail price be = x
Selling price of Z = 0.90x
Selling price of X = 0.90*0.90x = 0.81x
Selling price of Y = ((0.90x + 0.81x)/2)*0.90 = 0.86x * 0.90 = 0.77x
0.77x = k * 0.81x
k = 0.77/0.81 = 77/81
Answer: C
Answer: (C) 77/81
Question: 10 play kabadi, 35 play kho kho only, 5 play both gmaes. Then how many in total?
(A) 30
(B) 35
(C) 38
(D) 40
(E) 45
Rationale: 10 play kabadi =>n(A)=10,
5 play both gmaes.=> n(AnB)=5
35 play kho kho only,=>n(B)=n(B only)+n(AnB)=35+5=40
Total => n(AUB)= n(A)+n(B)-n(AnB)
= 10+40-5
= 45
ANSWER:E
Answer: (E) 45
Question: If a toy store's revenue in November was 4/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?
(A)  1/4
(B)  1/2
(C)  2/3
(D)  2
(E)  4
Rationale: Let Dec rev =100
Then Nov rev is 4/5 (100) => 80
Therefore Jan rev = 1/4(Nov rev) = 1/4(80) => 20
Hence Dec rev = x*( Nov rev+Jan rev)/2
100 = x* (80+20)/2
x = 100/50 => 2
Ans) D
Answer: (D)  2
Question: If the difference between the length and breadth of a rectangle is 23 m and its perimeter is 246 m, what is its area?
(A) 2510
(B) 3650
(C) 2530
(D) 2515
(E) 2520
Rationale: length = breadth +23. Therefore,
4× breadth +2×23=246 m
⇒ breadth =50 m
length =50+23=73 m
Area =73×50=3650 m2
Answer is B.
Answer: (B) 3650
Question: If a randomly selected non-negative single digit integer is added to {2, 3, 5, 8}. What is the probability that the median of the set will increase but the range still remains the same?
(A) 0.2
(B) 0.3
(C) 0.4
(D) 0.5
(E) 0.6
Rationale: We are selecting from non-negative single digit integers, so from {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}. These 10 digits represent the total number of outcomes.
Hence, the total number of outcomes is 10.
We need to find the probability that the median of the set will increase but the range still remains the same.
The median of the set is (3 + 5)/2 = 4, thus the number selected must be 5 or greater.
For the range to remain the same, the number must be between 2 and 8 inclusive.
To satisfy both conditions, the number selected must be 5, 6, 7, or 8.
The probability is 4/10 = 0.4
The answer is C.
Answer: (C) 0.4
Question: There are 12 person among whom 2 are brother. The total no.of ways in which these persons can be seated around a round table so that exactly 1 person sit between the brothers, is equal to?
(A) 9!*2!
(B) 7!*2!
(C) 6!*1!
(D) 2!*1!
(E) 5!*1!
Rationale: Total number of ways = 9!*2!.
A
Answer: (A) 9!*2!
Question: The C.P of 20 pens is equal to the S.P of 22 pens. Find his gain % or loss%?
(A) 6 2/11%
(B) 7 2/11%
(C) 9 1/11%
(D) 8 1/11%
(E) 10 1/11%
Rationale: 20 CP = 22 SP
22 --- 2 CP loss
100 --- ? => 9 1/11%
Answer: C
Answer: (C) 9 1/11%
Question: A man is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the length of the train and its speed.
(A) 36
(B) 54
(C) 67
(D) 76
(E) None
Rationale: Sol.
Let the length of the train be x metres.
Then, the train covers x metres in 8 seconds and (x + 180) metres in 20 seconds.
∴ x/8 = x + 180 / 20 ⇔ 20x = 8(x + 180) ⇔ x = 120.
∴ Length of the train = 120 m.
Speed of the train = [120/8]m/sec = m/sec = [15 * 18/5]kmph = 54 kmph.
Answer B
Answer: (B) 54
Question: which of the following could be the greatest common factor of positive integers 4 and 8 ?
I) 8 II) 4 III) 2
(A) III only
(B) II only
(C) I only
(D) I,II only
(E) II,III only
Rationale: 4=2*2
8=2*2*4
GCF = 2*2 = 4
Answer : B
Answer: (B) II only
Question: Two numbers are in the ratio of 5:7. If 25 be subtracted from each, they are in the ratio of 35:59. Find the numbers?
(A) 82,92
(B) 63,98
(C) 83,98
(D) 60,84
(E) 63,98
Rationale: (5x-25):(7x-25) = 35:59
x = 12 => 60,84
Answer:D
Answer: (D) 60,84
Question: P, Q and R can do a work in 20, 30 and 60 days respectively. How many days does it need to complete the work if P does the work and he is assisted by Q and R on every third day?
(A) 10
(B) 5
(C) 15
(D) 20
(E) 25
Rationale: Amount of work P can do in 1 day = 1/20
Amount of work Q can do in 1 day = 1/30
Amount of work R can do in 1 day = 1/60
P is working alone and every third day Q and R is helping him
Work completed in every three days = 2 × (1/20) + (1/20 + 1/30 + 1/60) = 1/5
So work completed in 15 days = 5 × 1/5 = 1
Ie, the work will be done in 15 days.
Answer is C.
Answer: (C) 15
Question: In a School, 69 percent of students Participated in Chess, 74 percent of students Participated in Table Tennis, 84 percent Participated in Carom and 79 percent Participated in shuttle.
Can you find out the percentage of students who Participated in all 4 Competition?
(A) 12%
(B) 10%
(C) 6%
(D) 18%
(E) 19%
Rationale: C
6% of student Participated in all four Competition.
Answer: (C) 6%
Question: Sam's grade was 60th percentile of the 100 grades for his class. Of the 120 grades from another class, 48 were higher than Sam's, and the rest were lower. If no other grade was the same as Sam's grade, then Sam's grade was what percentile of the grades of the two classes of two classes combined?
(A) 51st
(B) 60th
(C) 67th
(D) 72nd
(E) 92nd
Rationale: 51st/60th/67th/72nd/92nd
Correct option: B
Answer: (B) 60th
Question: How many numbers amongst the numbers 7 to 41 are there which are exactly divisible by 9 but not by 3?
(A) Nil
(B) 1
(C) 2
(D) 3
(E) More than 3
Rationale: 9,18,27,36 are divisible by 9 and 3 also.So there are no numbers exactly divisible by 9 but not by 3
ANSWER:A
Answer: (A) Nil
Question: A new home buyer pays 4% annual interest on her first mortgage and 9% annual interest on her second mortgage. If she borrowed a total of $300,000, 80% of which was in the first mortgage, what is her approximate monthly interest payment?
(A) $1,250
(B) $1,733
(C) $3,466
(D) $13,333
(E) $20,796
Rationale: 0.04x + 0.09y = 300000 [1]
0.04x = 0.80 * 300000 = 240000 [2]
240000 + 0.09y = 300000 --> 0.09y = 60000 [3]
240000 / 12 = 20000 [4]
60000 / 12 = 5000 [5]
Adding [4,5] we get: 25000 [6]
Dividing [6] / 2 to get an average we get 1.25,ANS A
Answer: (A) $1,250
Question: When a number is divided by 13, the remainder is 11. When the same number is divided by 17, then remainder is 9. What is the number ?
(A) 339
(B) NONE
(C) 349
(D) 369
(E) 379
Rationale: x = 13p + 11 and x = 17q + 9
13p + 11 = 17q + 9
17q - 13p = 2
q =	2 + 13p
17
The least value of p for which q =	2 + 13p	is a whole number is p = 26
17
x = (13 x 26 + 11)
= (338 + 11)
= 349
ANSWER C
Answer: (C) 349
Question: A farm has chickens, horses and sheep. There are six times the number of chickens and cows than sheep. If there are more horses than chickens or sheep, and together, horsess and chickens have a total of 100 feet and heads, how many sheep live at the farm?
(A) 5
(B) 4
(C) 10
(D) 14
(E) 17
Rationale: Chicken - ch
horses - H
Sheep -S
ch+H=6S
H> ch and H>s
Each Horse has 4 legs and 1 head
Each chicken has 2 legs and 1 head
So 5h+3ch=100 (sum of legs and head)
There are 2 possible solutions to this equation
h=11 and ch=9 or
h=14 and ch=10
Since from first equation where ch+h=6s
The sum of ch and c should be divisbile by 6. 20 is not so the only possible solution is h=14 and ch=10. So s=4
Answer : B
Answer: (B) 4
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 42 kmph, find the speed of the stream?
(A) 77
(B) 88
(C) 14
(D) 12
(E) 17
Rationale: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 42/3 = 14 kmph.
Answer:C
Answer: (C) 14
Question: A fort had provision of food for 180 men for 45 days. After 25 days, 40 men left the fort. The number of days for which the remaining food will last, is:
(A) 29	1/5
(B) 25	3/4
(C) 42
(D) 54
(E) 45
Rationale: we have food for 180 men for 45 days.
After 25 days food left for 180 men for 20 days.
so
180 : 20
now we have 140 men and x days
140 : 180 :: 20 : x
x = (180*20)/140 = 25 3/4 days.
ANSWER:B
Answer: (B) 25	3/4
Question: A shopkeeper sells some toys at Rs. 250 each. What percent profit does he make? To find the answer, which of the following information given in Statements I and II is/are necessary?
I. Number of toys sold.
II. Cost price of each toy.
(A) Only I is necessary
(B) Only II is necessary
(C) Both I and II are necessary
(D) Either I or II ins necessary
(E) None of these
Rationale: EXPLANATION
S.P. = Rs. 250 each.
To find gain percent, we must know the C.P. of each.
answer is (B).
Answer: (B) Only II is necessary
Question: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
(A) 10.9 sec
(B) 10.1 sec
(C) 10.6 sec
(D) 10.8 sec
(E) 10.2 sec
Rationale: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other
= 140 + 160 = 300 m.
Required time = 300 * 9/250
= 54/5 = 10.8 sec.
Answer:D
Answer: (D) 10.8 sec
Question: Mr. Yutaro’s class contains 6 boys and 10 girls. If two students are chosen, one at a time, from the class, what is the probability that a boy and a girl are chosen?
(A) 9/48
(B) 9/20
(C) 1/2
(D) 27/48
(E) 13/16
Rationale: Probability of a boy being chosen first, then a girl:
6/16 * 10/15
Probability of a girl being chosen first, then a boy:
10/16 * 6/15
Probability of a boy and a girl being chosen:
(6*10+6*10) / (15*16)
=1/2
Answer:C
Answer: (C) 1/2
Question: David started a business investing Rs. 70,000. Robert joined him after six months with an amount of Rs. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio amoung David, Robert and Sagar respectively, 3 years after David started the business?
(A) 12 : 10 : 16
(B) 12 : 15 : 16
(C) 15 : 12 : 16
(D) 16 : 15 : 12
(E) None
Rationale: Sol.
David : Robert : Sagar = (70000 * 36) : (105000 * 30) : (140000 * 24)
= 12 : 15: 16.
Answer B
Answer: (B) 12 : 15 : 16
Question: A disease has infected an ant colony that consists ofworkersandsoldiers: 30% of the soldiers and 14% of theworkerswere infected. If that colony is inhabited by 7000 ants, out of which 1860 are infected, how manyworkersinhabit the colony?
(A) 1500
(B) 2500
(C) 2750
(D) 3000
(E) 3250
Rationale: From two question we get wo equations:
(1) 0,3s + 0,14w = 1860
(2) s + w = 7000
From (2) we get w=7000-s
In (1) 0,3s + 980-0,14s= 1860
0,16s=880
88000:16= 5500 =s
In (2) 5500 + w = 7000
w= 1500 A
Answer: (A) 1500
Question: A travel agent offers a vacation plan which costs 'a' dollars for the first day, and a/10 for each additional day. How much does a vacation of b days cost, where b > 1.
(A) (ab+9a)/5
(B) (ab+8a)/10
(C) (ab+9a)/2
(D) (ab+5a)/10
(E) (ab+9a)/10
Rationale: Cost = a + (b-1)*a/10 = (10a + (b - 1)*a)/10 = (ab+9a)/10
Answer is E
Answer: (E) (ab+9a)/10
Question: Right triangle PQR is to be constructed in the xy-plane so that the right angle is at P and PR is parallel to the x-axis. The x- and y-coordinates of P, Q, and R are to be integers that satisfy the inequalities -4 <= x <= 5 and 6<= y<= 16. How many different triangles with these properties could be constructed?
(A) 110
(B) 1,100
(C) 9,900
(D) 10,000
(E) 12,100
Rationale: P can take a total of 10*11 co-ordinates.
for a given P, R can take a total of 9 co-ordinates and Q can take a total of 10 co-ordinates.
Hence, total = 110*9*10 = 9900
ANS:C
Answer: (C) 9,900
Question: How many cases do you need if you have to pack 50 dozens of bar soaps into cases that each hold 50 soaps?
(A) 15
(B) 14
(C) 13
(D) 12
(E) 10
Rationale: D
12
50 dozens of bar soaps = 600 soaps
600 ÷ 50 = 12.
Answer: (D) 12
Question: If 3^w - 3^(w-1) = 162 then w(w-1) =
(A) 12
(B) 16
(C) 20
(D) 30
(E) 81
Rationale: It seems like you were really close but you solved for w - 1 instead. I am curious - how did you reason through the question? Perhaps you figured the answer has to be in the form of w(w -1), e.g. (3)(4) = 12. Even then, had you figured w has to be a little bigger (plugging in 4 for w gives you 81 which is too low), So when you reasoned the answer to be 4 you may have plugged the 4 in the (w - 1) exponent place.
Again, a quick plugging in should get you (C) 20 as, the only other answer with consecutive integers as factors is far too big.
Answer: (C) 20
Question: In how many different ways can the letters of the word OPTICAL be arranged so that the vowels always come together?
(A) 610
(B) 720
(C) 825
(D) 920
(E) 925
Rationale: The word 'OPTICAL' contains 7 different letters.
When the vowels OIA are always together, they can be supposed to form one letter.
Then, we have to arrange the letters PTCL (OIA).
Now, 5 letters can be arranged in 5! = 120 ways.
The vowels (OIA) can be arranged among themselves in 3! = 6 ways.
Required number of ways = (120 x 6) = 720.
ANSWER:B
Answer: (B) 720
Question: For what value of x will the function f(x) = -3(x - 10)(x - 4) have a maximum value? Find the maximum value.
(A) 13
(B) 42
(C) 55
(D) 27
(E) 19
Rationale: f(x) = -3(x - 10)(x - 4) = -3x2*square* + 42x - 120 : expand and obtain a quadratic function
h = -b/2a = -42/-6 = 7 : h is the value of x for which f has a maximum value
f(h) = f(7) = 27 : maximum value of f.
correct answer D
Answer: (D) 27
Question: Find the average of first 60 natural numbers.
(A) 20.5
(B) 18
(C) 30.5
(D) 19
(E) 17
Rationale: Exp. Sum of first n natural numbers = n( n+1)/2
So, sum of first 60 natural numbers = 60*61/2 = 1830
Required average =1830/60 =30.5
Answer:C
Answer: (C) 30.5
Question: On Thursday Mabel handled 90 transactions. Anthony handled 10% more transactions than Mabel, Cal handled 2/3rds of the transactions that Anthony handled, and Jade handled 16 more transactions than Cal. How much transactions did Jade handled?
(A) 82
(B) 83
(C) 84
(D) 85
(E) 86
Rationale: Mabel handled 90 transactions
Anthony handled 10% more transactions than Mabel
Anthony = 90 + 90 × 10%
= 90 + 90 × 0.10
= 90 + 9
= 99
Cal handled 2/3rds of the transactions than Anthony handled
Cal = 2/3 × 99
= 66
Jade handled 16 more transactions than Cal.
Jade = 66 + 16
= 82
Jade handled = 82 transactions.
Correct Answer:A)82
Answer: (A) 82
Question: Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the same Job. How long should it take both A and B, working together but independently, to do the same job?
(A) 6 days
(B) 40 days
(C) 5 days
(D) 12 days
(E) 40/9 days
Rationale: A’s 1 hour's work = 1/8
B's 1 hour's work = 1/10
(A + B)'s 1 hour's work = (1/8) +(1/10)=9/40
Both A and B will finish the work in 40/9 days.
Ans: E
Answer: (E) 40/9 days
Question: A says " the horse is not black".
B says " the horse is either brown or grey."
c says " the horse is brown"
At least one is telling truth and atleast one is lying. Tell the colour of horse?
(A) Black
(B) grey
(C) Brown
(D) White
(E) blue
Rationale: The color of the horse can be any color other than Black and Brown.
If the color of the horse is Black - all are lying. If the color of the horse is Brown - all are telling truth. Thus, the horse is neither Black nor Brown. If the color of the horse is Grey - A and B are telling truth whereas C is lying. If the color of the horse is other than Black, Brown and Grey - A is telling truth whereas B and C are lying. You must have noticed that for the given conditions, A is always telling truth whereas C is always lying.
So ans is grey.
ANSWER:B
Answer: (B) grey
Question: If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 10 men in 3 days?
(A) 65mtr.
(B) 28mtr
(C) 70mtr.
(D) 78mtr.
(E) 17mtr.
Rationale: 20 men is 6 days can build 112 metres
10 men in 3 days can build = 112*(10/20)x(3/6)
= 28 meters
Answer: B.
Answer: (B) 28mtr
Question: The value of x + x(x^x) when x = 2 is
(A) 10
(B) 16
(C) 18
(D) 36
(E) 64
Rationale: Solution:
x + x(x^x)
Put the value of x = 2 in the above expression we get,
2 + 2(2^2)
= 2 + 2(2 × 2)
= 2 + 2(4)
= 2 + 8
= 10
Answer: (a)
Answer: (A) 10
Question: Geetha 's home has One tap, working alone at its maximum constant rate, can fill a certain sink in 210 seconds. A second tap, working alone at its maximum constant rate, can fill the same sink in 214 seconds. If both taps work together at their respective maximum constant rates, the time it will take to fill the sink is closest to
(A) 106 seconds
(B) 130 seconds
(C) 177 seconds
(D) 200 seconds
(E) 270 seconds
Rationale: Tap 1 : 210 secs
Tap 2 : 214 secs
Considering the average of these 2 taps : 212 secs.
So 1 tap can fill the tank in 212 secs, so 2 taps can fill the tank in 212/2 = 106 secs.
Closest answer is A.
Answer: (A) 106 seconds
Question: Solution for 2.75+.003+.158
(A) 2.91
(B) 2.911
(C) 2.938
(D) 2.986
(E) 2.999
Rationale: 2.75+.003+.158=0
0=0-2.75-0.003-0.158
0=-2.911
answer :B
Answer: (B) 2.911
Question: A cube of side one meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained?
(A) 1898
(B) 1098
(C) 1000
(D) 2008
(E) 1082
Rationale: Along one edge, the number of small cubes that can be cut
= 100/10 = 10
Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut
= 10 * 10 * 10 = 1000
Answer:C
Answer: (C) 1000
Question: By selling 50 meters of cloth. I gain the selling price of 15 meters. Find the gain percent?
(A) 42 6/9%
(B) 42 3/7%
(C) 42 7/7%
(D) 42 6/7%
(E) 22 6/7%
Rationale: SP = CP + g
50 SP = 50 CP + 15 SP
35 SP = 50 CP
35 --- 15 CP gain
100 --- ? => 42 6/7%
Answer: D
Answer: (D) 42 6/7%