mathewhe/aqua_rat huggingface dataset:
Question: Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
(A) A)Rs.180
(B) B)Rs.200
(C) C)Rs.250
(D) D)Rs.280
(E) E)Rs.300
Rationale: Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250
Option 'C'
Answer: (C) C)Rs.250
Question: The average of 9 observations was 9, that of the 1st of 4 being 10 and that of the last 4 being 8. What was the 5th observation?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: 1 to 9 = 9 * 9 = 81
1 to 4 = 4 * 10 = 40
4 to 9 = 6 * 8 = 48
5th = 48 + 40 =88 – 81 = 7
ANSWER:D
Answer: (D) 7
Question: A student has got marks in five subjects in the ratio 2:3:4:5:6 .The maximum marks of subjects in same sequence are in ratio 6:5:8:4:7.Total percentage of marks scored by him is 48%.FInd the maximum percentage obtained by him in a subject..
(A) 65
(B) 78
(C) 96
(D) 90
(E) 95
Rationale: lets marks obtain 2x,3x,4x,5x,6x.
total marks 6y,5y,8y,4y,7y.
addition of marks obtain=(2x+3x+4x+5x+6x)=20x
addition of total marks=(6y+5y+8y+4y+7y)=30y
so percentage=(20x/30y)*100
(20x/30y)*100=48
so,x/y=18/25
as we observed 5x/4y is the maximum marks
so 5x/4y=5/4*18/25*100=90%
ANSWER:D
Answer: (D) 90
Question: In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
(A) 1/3
(B) 2/5
(C) 3/7
(D) 8/27
(E) 9/29
Rationale: Total number of balls = (8 + 7 + 6) = 21.
E = event that the ball drawn is blue.
n(E) = 7
P(E) =n(E)/n(S) =7/21 = 1/3
ANSWER A
Answer: (A) 1/3
Question: How many seconds will a train 100 meters long take to cross a bridge 150 meters long if the speed of the train is 63 kmph?
(A) 22 sec
(B) 77 sec
(C) 25 sec
(D) 14.3 sec
(E) 17 sec
Rationale: D = 100 + 150 = 250
S = 63 * 5/18 = 17.5 mps
T = 250/17.5 = 14.3 sec
Answer:D
Answer: (D) 14.3 sec
Question: If (5^15)(9^8)=3(15^x), what is the value of x?
(A)  7
(B)  9
(C)  11
(D)  13
(E)  15
Rationale: (5^15)(9^8)=3(15^x)
=> 5^15 * 3^16 = 3 * 3^x * 5^x
=> 5^15 * 3^16 = 3^(x+1) * 5^x
Value of x = 15
Answer E
Answer: (E)  15
Question: In a certain large company, the ratio of college graduates with a graduate degree to non-college graduates is 1:8, and ratio of college graduates without a graduate degree to non-college graduates is 2:3. If one picks a random college graduate at this large company, what is the probability E this college graduate has a graduate degree?
(A) 1/11
(B) 1/12
(C) 1/13
(D) 3/19
(E) 3/43
Rationale: In believe the answer is D. Please see below for explanation.
0) we are told the following ratios
CGD - College Graduate with Degree
NCG - Non College Graduate
CGN - College Graduate no Degree
CGD NCG CGN
1 8
3 2
In order to make CGD and CGN comparable we need to find the least common multiple of 8 and 3 and that is 24 multiplying the first ratio by 3 and the second ratio by 8 we get
CGD NCG CGN
3 24 16
If one picks a random college graduate at this large company, what is the probability this college graduate has a graduate degree?
Nr of CGD = 3
Nr of CG = 3+ 16 = 19
Probability E of CGD / (CG) -> 3/19
Answer D
Answer: (D) 3/19
Question: Sunil invested $ 1600 fir 3 years and $ 1100 for 4 years at the same rate of Simple Interest. If the total interest from these investments is $ 506, what is the rate of interest?
(A) 2 3/4%
(B) 5 1/3%
(C) 5 1/2%
(D) 6%
(E) 3 2/4%
Rationale: (1600x3xR)/100+(1100x4xR)/100=506
92R=506
R= 5 1/2%
Answer is C
Answer: (C) 5 1/2%
Question: An article costing rs.200 is sold at 25% discount on a mark-up price. What is the selling price after
discount?
(A) 106
(B) 150
(C) 126
(D) 136
(E) 146
Rationale: 200*75/100=150
ANSWER:B
Answer: (B) 150
Question: What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 58 ?
(A) Rs. 3942
(B) Rs. 3288
(C) Rs. 3944
(D) Rs. 3122
(E) Rs. 3911
Rationale: Explanation:
Let the side of the square plot be 'a' ft.
Given area of the plot (a x a) = 289 => a = 17
Length of the fence = Perimeter of the plot = 4a = 68 ft.
Cost of building the fence = 68 x 58 = Rs. 3944.
Answer: C
Answer: (C) Rs. 3944
Question: A train passes a man standing on a platform in 8 seconds and also crosses the platform which is 264 metres long in 20 seconds. The length of the train (in metres) is:
(A) 188
(B) 176
(C) 175
(D) 96
(E) None of these
Rationale: Explanation:
Let the length of train be L m.
Acc. to question
(264+L)/20 = L/8
2112+8L=20L
L= 2112/12 = 176 m
Answer B
Answer: (B) 176
Question: A man bets on no. 16 on a roulette wheel 14 times and losses each time. On the 15th span he does a quick calculation and finds out that the no. 12 had appeared twice in the 14 spans and is therefore, unable to decide whether to bet on 16 or 12 in the 15th span. Which will give him the best chance and what are the odds of winning on the bet that he takes?
(A) Either ;30:1
(B) Either ;35:1
(C) 12;7:1
(D) 12;72:1
(E) 16;22:14
Rationale: Each of the span is an independent event and the outcome of the 15th span will not depend on the outcome of the earlier spans.
Either ;35:1
B)
Answer: (B) Either ;35:1
Question: Two cars are traveling towards each other. If car A is traveling at a speed of 50 mph and car B is traveling 12% slower, how much time will it take the cars to meet if the initial distance between the two is 705 miles?
(A) Six hours and 30 minutes
(B) Seven hours and 30 minutes.
(C) Eight hours and 20 minutes.
(D) Nine hours and 15 minutes
(E) Ten hours and 20 minutes
Rationale: Answer is B: Seven hours and 30 minutes.
since they are travelling towards each other, the total speed is 50 mph + 50*0.88 = 94 mph (0.88 since, the other car is 12% less than first one)
Distance to be covered is 705, so time taken = distance/speed = 705/94 = 7.5 hours or 7 hours and 30 mins.
ANSWER:B
Answer: (B) Seven hours and 30 minutes.
Question: The sum of three integers A, B and C is 360. A is one third of the sum of B and C and B is one fifth of the sum of A and C. What is C?
(A) 211
(B) 212
(C) 213
(D) 214
(E) 210
Rationale: A is one third of the sum of B and C..
or A=1/3(B+C)...
But A+B+C=360
so 1/3(B+C)+B+C=360
4(B+C)/3= 360
B+C =360*3/4 = 270
A=360-270=90
2)B is one fifth of the sum of A and C
or B=1/5(A+C)...
But A+B+C=360
so 1/5(A+C)+A+C=360
A+C=360*5/6=300
but A=90, so C=300-90=210
Answer :E
Answer: (E) 210
Question: A basket of 1430 apples is divided equally among a group of apple lovers. If 45 people join the group, each apple lover would receive 9 apples less. How many U apples did each person get before 45 people joined the feast?
(A) 20.
(B) 21.
(C) 22.
(D) 23.
(E) 24.
Rationale: Before solving it algebraically, let us prime factorize 1430 = 2*5*11*13.
Since number of apples per person * total persons U= 1430, the answer should be a factor of 1430. Only C is. And that's your answer.C
Answer: (C) 22.
Question: A can do a particular work in 6 days . B can do the same work in 8 days. A and B signed to do it for Rs. 3680. They completed the work in 3 days with the help of C. How much is to be paid to C?
(A) s. 380
(B) s. 600
(C) s. 460
(D) s. 400
(E) s. 480
Rationale: Explanation :
Amount of work A can do in 1 day = 1/6
Amount of work B can do in 1 day = 1/8
Amount of work A + B can do in 1 day = 1/6 + 1/8 = 7/24
Amount of work A + B + C can do = 1/3
Amount of work C can do in 1 day = 1/3 - 7/24 = 1/24
work A can do in 1 day: work B can do in 1 day: work C can do in 1 day
= 1/6 : 1/8 : 1/24 = 4 : 3 : 1
Amount to be paid to C = 3680 × (1/8) = 460
Answer : Option C
Answer: (C) s. 460
Question: If 5 toys cost Rs, 234, what do 35 toys cost?
(A) 1645
(B) 1564
(C) 1546
(D) 1638
(E) None of them
Rationale: Let the required cost be Rs. x. Then,
More toys, More cost	(Direct Proportion)
= x=(35 X 234)/5 =1638
Answer is D
Answer: (D) 1638
Question: At a supermarket, the ratio of the number of shampoos to the number of soaps is 8 to 5, and the ratio of the number of drinks to the number of shampoos is 3 to 4. If the ratio of the soaps to the number of cereals is 9 to 2, what is the ratio of the number of drinks to the number of cereals?
(A) 4:3
(B) 15:6
(C) 45:16
(D) 15:4
(E) 27:5
Rationale: Sh:Soaps=8:5
Drinks:Sh=3:4=> 6:8
Drinks:Sh:Soaps= 6:8:5
Soaps:Cer= 9:2=> 9*5:2*5= 45:10
Now, Drinks:Sh:Soaps=> 6*9:8*9:5*9 = 54:72:45
Drinks:Sh:Soaps:cer= 54:72:45:10
Drinks:Cer=54:10=> 27:5 E
Answer: (E) 27:5
Question: What is the remainder if 7^16 is divided by 100?
(A) 3
(B) 4
(C) 2
(D) 1
(E) 5
Rationale: 7^16 can be written as (7^4)^4
If we divide 7^4 by 100 the reminder is 1
So, (7^4)^4 by 100, the reminder is 1^4 = 1
Answer : D
Answer: (D) 1
Question: A train crosses a platform of 140 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
(A) 150
(B) 887
(C) 167
(D) 190
(E) 161
Rationale: Length of the train be ‘X’
X + 140/15 = X + 250/20
20X +2800 = 15X + 3750
5x=950
X = 190m
Answer: D
Answer: (D) 190
Question: The Kiljaro Highway is marked with Milestones denoting the distance to the town of Kiljaro. Tommy left kiljaro and drove the highway, passing the 10 km milestone at 8:30. Some time afterwards, Tommy got a phone call asking him to return home, and he made a U-turn at the 160 km milestone. At 09:A0 Tommy passed the milestone marking 60 km to Kiljaro. The variable A represents the tens digit of the minutes in 09:A0. Assuming Tommy maintained the same constant speed during the entire drive, how many kilometers did Tommy travel in one minute?
(A) 250/(30+10A)
(B) 250/(30+60A)
(C) 250/50A
(D) 220/(30+10A)
(E) 220/40A
Rationale: Since we are dealing with the variables in the answer choices,the best possible method according to me would be substitution.
Substitute A with 3.meaning tommy would have travelled a distance of ((160-10) + (160-60)) in 60 minutes.
250 Kms in 60 minutes ==> 5km/hr.
Substitute A with 3 in the answer options.
Option A
Answer: (A) 250/(30+10A)
Question: 2 + 2^2 + 2^3 + ... + 2^8 = ?
(A) 510
(B) 610
(C) 710
(D) 810
(E) 910
Rationale: Given series is a G.P. with a = 2, r = 2 and n = 8.
Therefore, sum = a(r^n-1)/(r-1) = 2 x (2^8 –1)/(2-1) = (2 x 255) =510
Answer is A.
Answer: (A) 510
Question: What will come in place of the x in the following Number series? 5,28,57,88,125
(A) 190
(B) 180
(C) 166
(D) 189
(E) 191
Rationale: 28=23+5
57=29+28
88=31+57
125=37+88
166=41+125
=166
C
Answer: (C) 166
Question: How many three-digit integers between 310 and 400, exclusive, are divisible by 3 when the ones digit and the tens digit are switched?
(A) 3
(B) 19
(C) 22
(D) 80
(E) 30
Rationale: Answer is 30
No of digits between 310 and 400 (exclusive) = 400-310-1 = 89
No Intergers divisble by 3 =~ 89/3 ~ 30
Divsiblivity rule for 3 is Sum of all digits must be divisble by 3. It doesn't matter if ones digit and tens digits are switched.
e.g 372 is divisble by 3 (becae 3+7+2= 12 (divisble by 3))
switch digits 732 also divisble by 3 (becae 7+3+2= 12 (divisble by 3))
Divsiblivity rule for 3 is Sum of all digits must be divisble by 3. It doesn't matter if ones digit and tens digits are switched.
You have right. So it is enough to proceed like usual to find the numbers in a given range that are divisible by 3. So 399-312/3 +1 =30.
Answer : E
Answer: (E) 30
Question: A bus leaves Burbank at 8:00 a.m. traveling east at 60 miles per hour. At 2:00 p.m. a plane leaves Burbank traveling east at 300 miles per hour. At what time will the plane overtake the bus?
(A) 1:30 p.m.
(B) 2:50 p.m.
(C) 3:00 p.m.
(D) 3:30 p.m.
(E) 2:25 p.m.
Rationale: At 2:00pm, the bus is 360 miles ahead of plane
The plane travels at 300 mph, which gains 240 mph on bus
360/240=1.5 hours
2:00 + 1:30 = 3:30
The plane will overtake bus at 3:30pm
Answer:D
Answer: (D) 3:30 p.m.
Question: The value of 5 in the number 357.21 is
(A) 5 tenths
(B) 5 ones
(C) 5 tens
(D) 5 hundreds
(E) 5 twentys
Rationale: Ans: C
The number 357.21 consists of: 3 hundreds, 5 tens, 7 ones, 2 tenths and 1 hundredth =>the value of 5 in 357.21	is 5 tens
Answer: (C) 5 tens
Question: Crew A can build a complete car in 20 minutes and Crew B can build a complete car in 25 minutes. If both crews work independently and start at the same time, what is the shortest amount of time W it could take for 10 cars to be complete?
(A) 111 1/9 minutes
(B) 115 2/5 minutes
(C) 116 minutes
(D) 120 minutes
(E) 125 minutes
Rationale: A builds 4 cars in 80 min
B builds 4 cars in 100 min
So A builds another car in another 20 min (i.e total 5 cars)
B builds another car in another 25 minutes (i.e, total 5 cars)
However, A can build another car in next 20 min (i.e total 6 cars)
So total time W= 125 min by B, which is > 120 min by A
B - 4 cars, A - 6 cars
Answer = D
Answer: (D) 120 minutes
Question: An accurate clock shows 8 o’clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 2 o’clock in the afternoon?
(A) 60°
(B) 90°
(C) 180°
(D) 320°
(E) None of these
Rationale: Sol.
Angle traced by the hour hand in 6 hours = [360/12 * 6]° = 180°
Answer C
Answer: (C) 180°
Question: An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is 64 times the difference between the two numbers. How many coins did the old man have?
(A)  24
(B)  26
(C)  30
(D)  64
(E)  40
Rationale: Let the number of coins one son got be x and the number of coins another got be y. Total = x + y.
x^2 - y^2 = 64(x - y) --> x + y = 64.
Answer: D.
Answer: (D)  64
Question: In what ratio should a variety of rice costing Rs. 6 per kg be mixed with another variety of rice costing Rs. 8.75 per kg to obtain a mixture costing Rs. 7.50 per kg?
(A) 5/6
(B) 3/9
(C) 5/0
(D) 5/3
(E) 5/9
Rationale: Explanation:
Let us say the ratio of the quantities of cheaper and dearer varieties = x : y
By the rule of allegation, x/y = (87.5 - 7.50) / (7.50 - 6) = 5/6
Answer: Option A
Answer: (A) 5/6
Question: What is the total surface area in square meters of a rectangular solid whose length is 6 meters, width is 5 meters, and depth is 2 meters?
(A) 100 m2
(B) 104 m2
(C) 106 m2
(D) 108 m2
(E) 160 m2
Rationale: Surface Area of a cuboid = 2(lb+bh+lh) = 2(6*5+5*2+6*2)=2(30+10+12)=2*52=104 m2
Answer : B
Answer: (B) 104 m2
Question: The probability that a visitor at the mall buys a pack of candy is 30%. If three visitors come to the mall today, what is the probability E that exactly two visitors will buy a pack of candy?
(A) 0.343
(B) 0.147
(C) 0.189
(D) 0.063
(E) 0.027
Rationale: 3C2 * (3/10)^2 * 7/10
= 3 * 9/100 * 7/10
= 189/1000
= 0.189=E
Answer - C
Answer: (C) 0.189
Question: How many necklace of 12 beads each can be made from 18 beads of different colours?
(A) 18!(6 x 29)
(B) 18!(6 x 21)
(C) 18!(6 x 24)
(D) 18!(6 x 22)
(E) 18!(6 x 44)
Rationale: Explanation:
Here clock-wise and anti-clockwise arrangements are same.
Hence total number of circular–permutations: \inline {\color{Black} \frac{18P_{12}}{2\times 12}} = \inline {\color{Black} \frac{18!}{6\times 24}}
Answer: C) 18!(6 x 24)
Answer: (C) 18!(6 x 24)
Question: If the sum of a number and its square is 342, What is the number?
(A) 16
(B) 77
(C) 25
(D) 87
(E) 18
Rationale: Explanation:
Let the integer be x.
Then, x + x2 = 342
x2 + x - 342 = 0
(x + 19) (x – 18) = 0
x = 18
ANSWER: E
Answer: (E) 18
Question: What sum of money will produce Rs.70 as simple interest in 5 years at 3 1/2 percent?
(A) 337
(B) 500
(C) 266
(D) 400
(E) 211
Rationale: 70 = (P*5*7/2)/100
P = 400
Answer: D
Answer: (D) 400
Question: A certain set of numbers has an average (arithmetic mean) of 50 and a standard deviation of 50.5. If p and n, two numbers in the set, are both within 2 standard deviations from the average, then which of the following could be the sum of p and n?
(A) -200
(B) -130
(C) -104
(D) 51
(E) 305
Rationale: 2 standard deviations from the average is frommean - 2*SDtomean + 2*SD, thus from 50-2*50.5=51 to 50+2*50.5=151:
-51 < p < 151
-51 < n < 151
-102 < p+n < 302.
Only option D is in this range.
Answer: D.
Answer: (D) 51
Question: The cost of one photocopy is $0.02. However, a 25% discount is offered on orders of more than 100 photocopies. If Saran and David have to make 80 copies each, how much will each of them save if they submit a single order of 160 copies?
(A) $0.32
(B) $0.40
(C) $0.45
(D) $0.48
(E) $0.54
Rationale: If Saran and David submit separate orders, each would be smaller than 100 photocopies, so no discount. Each would pay (80)*($0.02) = $1.60, or together, a cost of $3.20 --- that's the combinedno discount cost.
If they submit things together as one big order, they get a discount off of that $3.20 price ---- 25% or 1/4 of that is $0.80, the discount on the combined sale. They each effective save half that amount, or $0.40. Answer =(B).
Answer: (B) $0.40
Question: In the coordinate plane, the points F (-2,1), G (1,2), and H (2,1) lie on a circle with center P. What are the coordinates of point P ?
(A) (0,0)
(B) (1,1)
(C) (1,2)
(D) (1,-2)
(E) (2.5, -2.5)
Rationale: I thought I need to find the 4th point that would lie on the circle
Hence my answer was D (1,-2)
But the the center of the circle will lie on (0,0)
A
Answer: (A) (0,0)
Question: A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 10%?
(A) 550
(B) 882
(C) 772
(D) 652
(E) 271
Rationale: Cost price = Rs.500
profit = 10% of 500 = Rs.50
Selling price = Cost price + Profit
= 500 + 50 = 550
Answer:A
Answer: (A) 550
Question: A certain musical scale has has 13 notes, each having a different frequency, measured in cycles per second. In the scale, the notes are ordered by increasing frequency, and the highest frequency is twice the lowest. For each of the 12 lower frequencies, the ratio of a frequency to the next higher frequency is a fixed constant. If the lowest frequency is 220 cycles per second, then the frequency of the 7th note in the scale is how many cycles per second?
(A) 220 * sqrt 2
(B) 220 * sqrt (2^7)
(C) 220 * sqrt (2^12)
(D) 220 * the twelfth root of (2^7)
(E) 220 * the seventh root of (2^12)
Rationale: Let the constant be k.
F1 = 220
F2 = 220k
F3 = 220 k * k = 220 * k^2
F13= 220 * k^12
we know F13 = 2 *F1 = 2 * 220 = 440
440/220 = k^12
k = twelfth root of 2
for F7...
F7 = 220 * k^6 ( as we wrote for F2 and F3)
F7 = 220 * (twelfth root of 2) ^ 6
F7 = 220 * sqrt (2)
The answer is A.
Answer: (A) 220 * sqrt 2
Question: From a bunch of nine keys, three particular keys have to be used to open a combination lock, such that the second key can be used only after the first key and the third key can be used only after the second key. What are the chances of opening the lock in a random selection of three keys?
(A) 1/224
(B) 1/350
(C) 1/492
(D) 1/504
(E) 1/600
Rationale: The probability is 1/9*1/8*1/7 = 1/504.
The answer is D.
Answer: (D) 1/504
Question: Last month, John rejected 0.5% of the products that he inspected and Jane rejected 0.7 percent of the products that she inspected. If total of 0.75 percent of the products produced last month were rejected, what fraction of the products did Jane inspect?
(A) 1/6
(B) 1/2
(C) 5/8
(D) 5/4
(E) 15/16
Rationale: X - fraction of products Jane inspected
(1 - X) - fraction of products John inspected
0.7(X) + 0.5(1-X) = 0.75
0.2X = 0.75 - 0.5
X = 0.25/0.2
X = 5/4
Therefore the answer is D: 5/4.
Answer: (D) 5/4
Question: If it takes 4 movers 40 minutes to unpack their van, how long would 5 movers take?
(A) 38 minutes
(B) 35 minutes
(C) 32 minutes
(D) 29 minutes
(E) 26 minutes
Rationale: 4 * 40 = 5 * x
x = 32
Answer: C
Answer: (C) 32 minutes
Question: The annual interest rate earned by an investment increased by 5 percent from last year to this year. If the annual interest rate earned by the investment this year was 26.25 percent, what was the annual interest rate last year?
(A) 25%
(B) 24%
(C) 23%
(D) 22%
(E) 21%
Rationale: let i = interest rate
i(this year) = i(last year) + 0.05i(last year) = 1.05i(last year)
26.25 = 1.05 x i(last year)
i(last year) = 26.25/1.05 = 2625/105 = 25%
Answer : A
Answer: (A) 25%
Question: no.of zeros in 1*2^2*3^3*....49^49
(A) 240
(B) 250
(C) 260
(D) 270
(E) 280
Rationale: count the number of 5's
5^5 => 5 5's
10^10 = 2^10*5^10 => 10 5's
15^15 => 15 5's
20^20 => 20 5's
25^25 =(5^2)^25 = 5^50 => 50 5's
30^30 => 30 5's
35^35 => 35 5's
40^40 => 40 5's
45^45 -> 45 5's
total no. of 5's = 5 + 10 + 15 + 20 + 50 + 30 + 35 + 40 + 45 = 250
i.e. product has a term 5^250 , also no. of 2's is much more than 250
no.of zeros in 1*2^2*3^3*....49^49 = 250
ANSWER:B
Answer: (B) 250
Question: The sum of all the integers k such that –20 < k < 24 is
(A) 0
(B) -2
(C) -25
(D) -49
(E) -37
Rationale: -19------------------0-----------------23
values upto+23 cancels outwe are left with only -19-18 sum of which is - 37. hence option D.
E
Answer: (E) -37
Question: 12 men work 8 hours per day to complete the work in 10 days. To complete the same work in 8 days, working 12 hours a day, the number of men required?
(A) 11 days
(B) 12 days
(C) 9 days
(D) 8 days
(E) 10 days
Rationale: That is, 1 work done = 12 × 8 × 10
Then, 12 8 × 10 = ? × 12 × 8
? (i.e. No. of men required) = 12 × 8 × 10/12× 8 = 8 days
E)
Answer: (E) 10 days
Question: A, B and C can do a work in 90, 30 and 15 days respectively. If they work together, in how many days will they complete the work?
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
Rationale: One days's work of A, B and C = 1/90 + 1/30 + 1/15
= (1 + 3 + 6)/90 = 1/9
A, B and C together can do the work in 9 days.
Answer:E
Answer: (E) 9
Question: Tough and Tricky questions: Ratios
2/5 of a certain class left on a field trip. 1/3 of the students who stayed behind did not want to go on the field trip (all the others did want to go). When another vehicle was located, 1/2 of the students who did want to go on the field trip but had been left behind were able to join. What fraction of the class ended up going on the field trip?
(A) 1/2
(B) 2/3
(C) 11/15
(D) 23/30
(E) 3/5
Rationale: let total no. of students be 30
students left on a field trip = 2/5(30) =12
thus 18 students left behind
1/3(18)=6 students did not want to go. thus 12 students want to go on the trip
1/2(12)=6 were able to join the other students on the field trip.
thus total number of students that went on a field trip =12+6 =18
thus required fraction = 18/30 =3/5
E
Answer: (E) 3/5
Question: 2 trains in same direction at 50km/hr,32 km/hr.A man in slower train observes 15 sec elapse before the faster train completely passed by him what is length of faster train?
(A) 65 meters
(B) 75 meters
(C) 85 meters
(D) 95 meters
(E) 55 meters
Rationale: relative speed= 18k/hr= 5 m/sec
distance covered= length of faster train= 5*15= 75 meters
ANSWER:B
Answer: (B) 75 meters
Question: There are 6 physics books and 1 chemistry book on shelf P and 5 physics books on shelf Q. One book is moved from shelf P to shelf Q. A student picks up a book from shelf Q. What is the probability that the chemistry book is taken by the student?
(A) 1/42
(B) 1/21
(C) 1/15
(D) 1/12
(E) 1/10
Rationale: P(a chemistry book is moved to shelf Q) = 1/7
P(a chemistry book is then chosen from shelf Q) = 1/6
P(the student takes a chemistry book) = 1/7 * 1/6 = 1/42
The answer is A.
Answer: (A) 1/42
Question: What sum of money will produce Rs.90 as simple interest in 4 years at 3 1/2 percent?
(A) 742.85
(B) 622.85
(C) 632.85
(D) 652.85
(E) 642.85
Rationale: 90 = (P*4*7/2)/100
P = 642.85
ANSWER:E
Answer: (E) 642.85
Question: If 2x = 3y = 10, then 9xy = ?
(A)  1,200
(B)  200
(C)  150
(D)  40
(E)  20
Rationale: 2x = 10;x=5
3y = 10;y=10/3
Multiply: 9xy=9*5*10/3=150
Answer: C.
Answer: (C)  150
Question: the present average age of a couple and their daughter is 35 years. Fifteen years from now, the age of the mother will be equal to the sum of present ages of the father and the daughter. Find the present age of mother?
(A) 18 years
(B) 19 years
(C) 11 years
(D) 45 years
(E) 12 years
Rationale: Explanation:
(f + m + d)/3 = 35
=> f + m + d = 105 --- (1)
m + 15 = f + d
Substituting f + d as m + 15 in (1), we get
2m + 15 = 105
2m = 90 => m = 45 years.
Answer: D
Answer: (D) 45 years
Question: What is the area of a square field whose diagonal of length 24 m?
(A) 256
(B) 289
(C) 200
(D) 288
(E) 178
Rationale: d2/2 = (24 * 24)/2
= 288
Answer: D
Answer: (D) 288