mathewhe/aqua_rat huggingface dataset:
Question: Kiran had 85 currency notes in all , some of which were of Rs.100 denaomination and the remaining of Rs.50 denomination the total amount of all these currency note was Rs.5000.how much amount did she have in the denomination of Rs.50?
(A) rs.2500
(B) rs.3500
(C) rs.1500
(D) rs.4500
(E) rs.5500
Rationale: 100X +50 (85-X) =5000
on solving:
x=15
100-x=no. of 50 notes = 70
amount =70*50= rs.3500
ANSWER:B
Answer: (B) rs.3500
Question: How many liters of water must be evaporated from 50 liters of a 3 percent sugar solution to get a 4 percent sugar solution?
(A) 12.5
(B) 15.5
(C) 17.5
(D) 21.5
(E) 24.5
Rationale: Let x be the amount that needs to be evaporated.
0.03(50) = 0.04(50-x)
0.04x = 2 - 1.5
x = 0.5/0.04 = 12.5 liters
The answer is A.
Answer: (A) 12.5
Question: A committee of 4 people is to be selected from 6 people. How many different committees are possible?
(A) 28
(B) 40
(C) 56
(D) D.168
(E) 15
Rationale: Because the order does not matter in selecting 4 people for the committee, this is a combination question.
The number of ways to select 4 people from 6 = 6C4 = 6!/4!*2! = 15. Hence E.
Answer: (E) 15
Question: A firm has 3 senior partners and 5 junior partners. How many different groups of 3 partners can be formed in which at least one member of the group is a senior partner. (2 groups are considered different if at least one group member is different)
(A) 30
(B) 34
(C) 38
(D) 42
(E) 46
Rationale: The total number of ways to form a group of 3 is 8C3 = 56
The number of groups without a senior partner is 5C3 = 10
The number of groups which include a senior partner is 56-10 = 46
The answer is E.
Answer: (E) 46
Question: Which of the following fractions is greater than 3/5 and less than 6/7?
(A) 7/8
(B) 1/3
(C) 2/3
(D) 1/3
(E) 6/7
Rationale: Explanation :
LCM of 5, 7, 2, 3, 3, 8 = 840
3/5 = 504/840
6/7 = 720/840
Hence, the question is to find out a number which is between the above numbers
The given choices are
1/2 = 420/840
2/3 = 560/840
1/3 = 280/840
7/8 = 735/840
Clearly, 560/840 = 2/3 . Answer : Option C
Answer: (C) 2/3
Question: 1200 men have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now?
(A) 12.85
(B) 12.62
(C) 12.5
(D) 12.24
(E) 12.1
Rationale: 1200*15 = 1400*x
x = 12.85.Answer: A
Answer: (A) 12.85
Question: I. a3 - 988 = 12,
II. b2 - 51 = 49 to solve both the equations to find the values of a and b?
(A) a > b
(B) a ≥ b
(C) a < b
(D) a ≤ b
(E) a = b or the relationship between a and b cannot be established.
Rationale: a3 = 1000 => a = 10
b2 = 100 => b = ± 10
a ≥ b
ANSWER:B
Answer: (B) a ≥ b
Question: If w is 40 percent less than r, r is 40 percent less than y, and z is 46 percent less than y, then z is greater than w by what percent of w?
(A) 4%
(B) 18%
(C) 36%
(D) 40%
(E) 50%
Rationale: GIven w= 0.6r, r=0.6y, z=0.54y, substituting, w=2/3 Z----> z= 1.5w and thus z is 50% greater than w. E is the correct answer.
Answer: (E) 50%
Question: In My, Xiang sold 15 used cars. For these 15 used cars the range of selling prices was 15,000 and the lowest selling price was 4,500. In June, Xiang sold 10 cars. For these 10 cars the range of selling was 9,000 and the lowest selling price was 6,100. What was the range of selling prices for the 25 used car sold by xiang in May and June?
(A) 15,600
(B) 15,750
(C) 16,820
(D) 18,100
(E) 19,200
Rationale: for 10 cars - 9000+ 6100 = 15,100
for 15 cars - 15000+ 4500 = 19,500
max = 19,500 min 4500
answer is approx 15,000.
Option A is closest.
Answer: (A) 15,600
Question: Two numbers are in the ratio of 1 : 2. If 9 be added to both, their ratio changes to 3 : 5. The greater number is
(A) 20
(B) 24
(C) 28
(D) 32
(E) 36
Rationale: Let the ratio be X : Y,
Given X/Y = 1/2 ,
(X + 9)/(Y + 9) = 3/5
=> X = 18
And Y = 36
ANSWER:E
Answer: (E) 36
Question: X and Y can do job in 25 days and 30 days respectively. They work together for 5 days and then X leaves. Y will finish the rest of the work in how many days?
(A) 18 days
(B) 19 days
(C) 20 days
(D) 21 days
(E) None of these
Rationale: X’s one day’s work = 1.25 th part of whole work.
Y’s one day’s work = 1⁄30 th part of whole work.
Their one day’s work = 1⁄25 + 1⁄30 = 1⁄150 th part of whole work.
Now, work is done in 5 days = 11⁄150 × 5 = 11⁄30 th of whole work
∴ Remaining work = 1 - 11⁄30 = 19⁄30 th of whole work
Now, 1⁄30 th work is done by Y in one day.
∴ 19⁄30 th work is done by Y in 1 /1/30×19/30 = 19 days.
Answer B
Answer: (B) 19 days
Question: The present ages of three persons in proportions 2 : 3 : 5. Eight years ago, the sum of their ages was 36. Find their present ages (in years).
(A) 15, 20, 28
(B) 22, 28, 36
(C) 25, 35, 45
(D) 12,18,30
(E) of these
Rationale: Let their present ages be 2x, 3x and 5x years respectively.
Then, (2x - 8) + (3x - 8) + (5x - 8) = 36
10x = 60
x = 6.
Their present ages are 2x = 12 years, 3x = 18 years and 5x = 30 years respectively.
ANSWER:D
Answer: (D) 12,18,30
Question: Which of the following equations represents a line that is perpendicular to the line described by the equation 3x + 4y = 10?
(A) 3x + 4y = 12
(B) 3x – 4y = 20
(C) 4y – 3x = 22
(D) 1.5y + 2x = 18
(E) 8x – 6y = 24
Rationale: Perpendicular lines have slopes which are negative reciprocals of each other.
The line 3x + 4y = 10 in slope-intercept form is y = -(3/4)x + 2.5
The slope of this line is - 3/4.
The slope of a perpendicular line is 4/3.
8x - 6y = 24 in slope-intercept form is y = (4/3)x - 4
The answer is E.
Answer: (E) 8x – 6y = 24
Question: The number of years of service of the eight employees in a production department are 15, 10, 9, 17, 8, 7, 14 and 16. What is the range in the number of years of service of the eight employees?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
Rationale: = 17-7
= 10
Answer A
Answer: (A) 10
Question: A box contains 23 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of these is defective is
(A) 4/19
(B) 7/19
(C) 12/37
(D) 21/95
(E) None
Rationale: Solution
P( None is defective)
= 19C2 / 23C2
= 25/37.
P( at least one is defective)
= (1- 25/37)
= 12/37.
Answer C
Answer: (C) 12/37
Question: 22.085 Ã— 0.001 = ?
(A) 0.22085
(B) 2.2085
(C) 0.022085
(D) 0.0022085
(E) None of these
Rationale: 22.085 Ã— 0.001 = ?
or,? = 0.022085
Answer C
Answer: (C) 0.022085
Question: If four coins are tossed, the probability of getting two heads and two tails is?
(A) 3/8
(B) 7
(C) 6
(D) 5
(E) 3
Rationale: Since four coins are tossed, sample space = 24
Getting two heads and two tails can happen in six ways.
n(E) = six ways
p(E) = 6/24 = 3/8
Answer:A
Answer: (A) 3/8
Question: Sachin is younger than Rahul by 5 years. If the ratio of their ages is 7:9, find the age of Sachin
(A) 24.58
(B) 24.5
(C) 24.3
(D) 24.9
(E) 15.5
Rationale: If Rahul age is x, then Sachin age is x-5,
so (x-5)/x = 7/9
=> 9x-45 = 7x
=> 2x = 45
=> x = 22.5
So Sachin age is 22.5 - 7 = 15.5
Answer: E
Answer: (E) 15.5
Question: A can do a piece of work in 10 days and B can do the same work in 12 days. A and B worked together for 1/2 days. How many more days are required to complete the remaining work if they work together?
(A) 3 (5/18)
(B) 3 (5/16)
(C) 3 (5/11)
(D) 4 (21/22)
(E) 3 (5/21)
Rationale: A can do 1/10 of the work in a day.
B can do 1/12 of the work in a 1 day.
Both of them together can do (1/10 + 1/12) part of work in 1 day = (6 + 5)/60 = 11/60
They take 60/11 days to complete the work together.
Given that they already worked for 1/2 days.
The number of days required to complete remaining work => 60/11 - 1/2 = 109/22 = 4 (21/22) days.
Answer:D
Answer: (D) 4 (21/22)
Question: A pump can fill a tank with water in 8 hours. Because of a leak, it took 16 hours to fill the tank. The leak can drain all the water in ?
(A) 16hr
(B) 12hr
(C) 13hr
(D) 14hr
(E) 16hr
Rationale: Work done by the leak in 1 hour = 1/8 - 1/16 = 1/16
Leak will empty the tank in 16 hours
Answer is A
Answer: (A) 16hr
Question: On a test consisting of 30 questions. No. of wrong answers is 50% less than number of right answers. Each answer was either right or wrong. What is the ratio of right answers to wrong answers?
(A) 3 : 2
(B) 2 : 3
(C) 2 : 1
(D) 1 : 4
(E) 2 : 5
Rationale: Sol. Let the number of wrong answer - x and number of right answer = 30-x x = 50/100 of (30-x) x = 10
Required ratio = 20 : 10 = 2 : 1
C
Answer: (C) 2 : 1
Question: If b equals 10% of a and c equals 20% of b, then which one of the following equals 30% of c?
(A) 0%
(B) 0.6%
(C) 0.06%
(D) 6.0%
(E) None of these
Rationale: Explanation :
Given,
b=10% of a
=>(10/100)×a
=>0.1a.
And, c=20% of b
=>(20/100)×b
=>0.2b
=>0.2×0.1a
Now, 30% of c=(30/100)×c.
=>0.3c=(0.3)(0.2)(0.1a)
=>0.006a=0.6%
Answer : B
Answer: (B) 0.6%
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are drawn at random, what is the probability that at least one is green?
(A) 23/35
(B) 23/31
(C) 23/19
(D) 23/13
(E) 23/10
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green
= (⁶C₁ * ⁹C₁)/¹⁵C₂ + ⁶C₂/¹⁵C₂
= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7
= 46/70 = 23/35
Answer: A
Answer: (A) 23/35
Question: A is the average (arithmetic mean) of the first 7 positive multiples of 8 and B is the median of the first 3 positive multiples of positive integer n. If the value of A^2 – B^2 is zero, what is the value of n?
(A) 10
(B) 12
(C) 16
(D) 24
(E) 32
Rationale: If A^2 - B^2 = 0, then let's assume that A = B.
A must equal the 4th positive multiple of 4, thus A = 32, which also equals B.
B is the second positive multiple of n, thus n = 32/2 = 16.
The answer is C.
Answer: (C) 16
Question: In a race of length Lmetres, Johnson beats Lewis by M metres and Greene by N metres, By how many metres does Lewis beat Greene in the same race ? (M<N)
(A) L(L-N) / L-M
(B) M-N
(C) L-N
(D) (N-M)L / L-M
(E) M+
Rationale: the ans is quite simple N-M but since the ans is not given, the best way to 'find' the correct option is to plug in the numbers. For my work, i took the following numbers:
L = 100
M = 10
N =20.
So basically, L beat G by 10 meters. Now whatever options comes close to the figure 10 is the right ans..
looking the the opion C to E, one can make out that they are incorrect, leaving us with just two options..A and B.
Out of which, i choose D.
Answer: (D) (N-M)L / L-M
Question: Lory spent 2⁄5 of her money on new clothes and then deposited 1⁄2 of what remained into her savings account. If she then had $21 left, how much did she have at the start?
(A) $30
(B) $35
(C) $70
(D) $105
(E) $210
Rationale: Lory spent 2⁄5 of her money on new clothes but if you see 21 is half of 3/5 money so 210 is too huge to be correct..
solution..
let the money be x..
2/5 is used...
1/2 of remaining 3/5 is put in savings account and remaining half is 21..
so 1/2 * 3/5 *x=21..
x=21*2*5/3=70..
C
Answer: (C) $70
Question: The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 20 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam.
(A) 22
(B) 35
(C) 25
(D) 99
(E) 21
Rationale: Let the number of students who wrote the exam be x.
Total marks of students = 80 x.
Total marks of (x - 5) students = 90(x - 5)
80x - (5 * 20) = 90(x - 5)
350 = 10x => x = 35.Answer: B
Answer: (B) 35
Question: Dhoni spent 20 percent of his earning last month on rent and 5 percent less than what he spent on rent to purchase a new dishwasher. What percent of last month's earning did Dhoni have left over?
(A) 61%
(B) 62%
(C) 65%
(D) 64%
(E) 50%
Rationale: Say Dhoni's earning last month was $100.
Dhoni spent 20 percent of his earning last month on rent --> $20 on rent;
5 percent less than what he spent on rent to purchase a new dishwasher --> $20*0.95=$19 on the dishwasher.
Left over amount 100 - (20 + 19) = $61
Answer: A
Answer: (A) 61%
Question: If a, b, c, d, e and f are integers and (ab + cdef) < 0, then what is the maximum number D of integers that can be negative?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: Minimuum should be 1
Maximum should be 4:
1 out of a or b to make the multiplication negative
3 out of c, d, e or f to make the multiplication negative.
Negative+Negative<0
Answer:C
maximum will be 5..
you dont require both the multiplicatin to be negative for entire equation to be negative...
any one a or b can be negative to make ab negative and it can still be more(away from 0) than the multiplication of 4 other -ve numbers...
actually by writing minimum required as 1 out of 6,you are actually meaning 5 out of 6 also possible as you will see D=5 or 1 will give you same equation..
ans D
Answer: (D) 5
Question: In the first M games of a team's season, the ratio of the team's wins to its losses was 3:1. In the subsequent N games, the ratio of the team´s wins to losses was 2:3. If M:N = 4:5, what was the ratio of the team's wins to its losses for all M+N games?
(A) 7:8
(B) 9:2
(C) 1:2
(D) 5:4
(E) 3:2
Rationale: M = 4/9 of total games
N = 5/9 of total games
Wins = 3/4*4/9 + 2/5*5/9 = 3/9 + 2/9 = 5/9
Losses = 1 - 5/9 = 4/9
The ratio of wins to losses is 5:4.
The answer is D.
Answer: (D) 5:4
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions?
(A) 754 m
(B) 704 m
(C) 708 m
(D) 706 m
(E) 204 m
Rationale: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4 = 70400 cm
= 704 m
Answer:B
Answer: (B) 704 m
Question: What will be in the next series
1, 7, 8, 49, 56, 57, 343, ...
(A) 223
(B) 344
(C) 677
(D) 297
(E) 1291
Rationale: Ans: 344
1 = 1
7 = 1 x 7
8 = 1 x 7 + 1
49 = 7 x 7 + 1
50 = 7 x 7 + 1
56 = 8 x 7
57 = 8 x 7 + 1
343 = 49 x 7
Next term should be 49 x 7 + 1 = 344
Ans:B
Answer: (B) 344
Question: The 8 spokes of a custom circular bicycle wheel radiate from the central axle of the wheel and are arranged such that the sectors formed by adjacent spokes all have different central angles, which constitute an arithmetic series of numbers (that is, the difference between any angle and the next largest angle is constant). If the largest sector has a central angle of 83.5°, what fraction of the wheel’s area is represented by the smallest sector?
(A) 1/80
(B) 3/100
(C) 7/240
(D) 11/480
(E) 13/720
Rationale: The largest angle is 83.5.
Let d be the difference between any two angles in the progression.
The sum of all the angles will be:
83.5 + (83.5-d) + (83.5-2d) + ... + (83.5-7d) = 668 - 28d
The sum of all the central angles in a circle = 360
668 - 28d = 360
d = 308/28 = 11
The smallest sector is (83.5-7d) = 83.5-7*11 = 6.5
The fraction of the area covered is 6.5/360 = 13/720.
The answer is E.
Answer: (E) 13/720
Question: Machine X can complete a job in half the time it takes Machine Y to complete the same job, and Machine Z takes 50% longer than Machine X to complete the job. If all three machines always work at their respective, constant rates, what is the ratio B of the amount of time it will take Machines X and Z to complete the job to the ratio of the amount of time it will take Machines Y and Z to complete the job?
(A) 5 to 1
(B) 10 to 7
(C) 1 to 5
(D) 7 to 10
(E) 9 to 10
Rationale: Solutioning this exercise can be facilitated by using a R T W (rate time work) table:
We translate the exercise into the table:
R T W
X t/2 1
Y t 1
Z (t/2*3/2 =3t/4) 1
From this table we find the rates
Rx = 2/t
Ry = 1/t
Rz = 4/3t
The Q is what is the ratio of (Tx + Ty) / (Ty + Tz)
Rx + Ry = 2/t + 4/3t = 6/3t+4/3t = 10/3t
Ry+Rz = 1/t + 4/3t = 3/3t + 4/3t = 7/3t
The (10/3t)/(7/3t) = 10/7 then the work ratios is 10 to 7
Since Time Ratio B is the inverse of work, the the answer is 7 to 10
CORRECT ANSWER D
Answer: (D) 7 to 10
Question: Which of the following CAN be the least common multiple of two positive integers 2 and 8?
(A) 7
(B) 5
(C) 8
(D) 4
(E) 2
Rationale: LCM of 2, 8 is 8
Answer : C
Answer: (C) 8
Question: The average age of three boys is 15 years. If their ages are in the ratio 3:5:7, the age of the youngest boy is :
(A) 9
(B) 8
(C) 7
(D) 6
(E) 5
Rationale: Explanation:
3x+5x+7x3=15⇒15x=15×33x+5x+7x3=15⇒15x=15×3 or x = 3
Age of youngest = 3x = 9 years
Answer:\A
Answer: (A) 9
Question: How many unique positive odd integers less than 60 are equal to the product of a positive multiple of 5 and an odd number?
(A) 4
(B) 6
(C) 11
(D) 12
(E) 15
Rationale: the odd numbers less than 60 are 1,3,5,...59
some of them are equal to product of 5 and odd number
hence odd multiples of 5 which are less than 60 are 5,15,25,35,45,55( total=6);
ANSWER:B
Answer: (B) 6
Question: The president of a country and 8 other dignitaries are scheduled to sit in a row on the 9 chairs represented above. If the president must sit in the center chair, how many different seating arrangements are possible for the 9 people?
(A)  4
(B)  58720
(C)  40320
(D)  24080
(E)  120
Rationale: IMO C
Given that one chair is taken, i think the remaining 8 dignitaries can be arranged 8!. That is 8*7*6*5*4*3*2*1=40320.
Answer: (C)  40320
Question: A rectangular lawn of dimensions 90 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?
(A) s.3988
(B) s.3900
(C) s.3228
(D) s.4200
(E) s.3928
Rationale: Area = (l + b – d) d
(90 + 60 – 10)10 => 1400 m2
1400 * 3
= Rs.4200
Answer:D
Answer: (D) s.4200
Question: Johny traveled the entire 60 miles trip. If he did the first 6 miles of at a constant rate 24 miles per hour and the remaining trip of at a constant rate 48 miles per hour, what is the his average speed, in miles per hour?
(A) 20mph
(B) 24mph
(C) 30mph
(D) 32mph
(E) 48mph
Rationale: Average speed=sum of distance/sum of time. If he travelled the first 6 miles at 24 miles/hr, it would take 0.25 hr. For the remaining trip, if he went at 48 miles/1hr, it would take 1 hour. Then, the average speed is 60miles/(0.25+1)hrs=48miles/1hr.
Therefore, the answer is E.
Answer: (E) 48mph
Question: Shreehari has 125 pencils. There are 25 students are studying in his class. He would like to give each student the same amount of pencils, how much should he give to each student?
(A) 12
(B) 7
(C) 5
(D) 15
(E) 6
Rationale: 125/25 = 5
The answer is C.
Answer: (C) 5
Question: A man can swim in still water at 4.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
(A) 3
(B) 7.5
(C) 2.25
(D) 1.5
(E) 4
Rationale: M = 4.5
S = x
DS = 4.5 + x
US = 4.5 + x
4.5 + x = (4.5 - x)2
4.5 + x = 9 -2x
3x = 4.5
x = 1.5
ANSWER:D
Answer: (D) 1.5
Question: In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 10 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?
(A)  400
(B)  625
(C)  250
(D)  2,500
(E)  10,000
Rationale: total fish = x
percentage of second catch = (10/50)*100 = 20%
so, x * 20% = 50
x = 250 ans.C
Answer: (C)  250
Question: If 0 < a < b and k = (2a + 8b)/b , which of the following must be true?
(A) k < 2
(B) k < 7
(C) k < 10
(D) k > 15
(E) k > 11
Rationale: Please follow posting guidelines (link in my signature) especially writing the correct topic title. Also do mention the source of the question if you select the tag:Source-Other Please Specify.
As for your question, it is very simple and straightforward with number plug in.
Assume a=1 and b=2 as a < b, you get k = (2+16)/2 = 9. This eliminates all but option C , making it the correct answer.
Answer: (C) k < 10
Question: An aeroplane covers a certain distance of 420 Kmph in 6 hours. to cover the same distance in 4 2/3 hours, it Must travel at a speed of ?
(A) 450 Km
(B) 480 Km
(C) 500 Km
(D) 540 Km
(E) 590 Km
Rationale: Speed of aeroplane = 420 Kmph
Distance travelled in 6 hours
= 420 * 6 = 2520 Km
Speed of aeroplane to acver 2520 Km in 14/3
= 2520*3/14 = 540 Km
Answer: Option 'D'
Answer: (D) 540 Km
Question: If x ≠ 0 and x^4 - (2- x^4)/x^4 = y/x^3, then y =
(A) -x
(B) -x/2
(C) -2/x
(D) -2
(E) -2x
Rationale: x^4 - (2- x^4)/x^4 = y/x^3
-2/x^4 = y/x^3
y = -2/x
Answer : C
Answer: (C) -2/x
Question: The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 70 kmph. Find the speed of the boat in still water and the speed of the stream?
(A) 5 kmph
(B) 67 kmph
(C) 22 kmph
(D) 88 kmph
(E) 12 kmph
Rationale: Speed of the boat in still water
= (60+70)/2
= 65 kmph. Speed of the stream
= (70-60)/2
= 5 kmph.
Answer:A
Answer: (A) 5 kmph
Question: If the simple interest on a sum of money at ten percent per annum for five years is Rs.6000, compound interest on the same sum for the same period at the same rate of interest is
(A) 6480.0
(B) 6840.0
(C) 4800.0
(D) 6000.0
(E) 6040.0
Rationale: S I for 5 years = 6000 ie for one year =1200
The compound interest for Rs.1200 for the next four years = 1200(4)= 4800*10/100 = 480
The CI for two years 6000 + 480 = 6480.00
ANSWER:A
Answer: (A) 6480.0
Question: Worker W produces n units in 5 hours. Workers V and W work independently but at the same time, produce n units in 2 hours. How long would it take V alone to produce n units?
(A) 10/8
(B) 10/3
(C) 10/6
(D) 10/2
(E) 10/1
Rationale: Explanation:
w's 1 hours production = n/5
(w + v)'s 1 hours production = n/2
v's 1 hour production = n/5 + V = n/2
v's 1 hour production = n/2 – n/5 = 3n/10= n/(10/3)
Ans = 10/3 hours
\Answer: B
Answer: (B) 10/3
Question: A van takes 6 hours to cover a distance of 270 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
(A) 50 Kmph
(B) 30 Kmph
(C) 70 Kmph
(D) 80 Kmph
(E) 90 Kmph
Rationale: Time = 6
Distence = 270
3/2 of 6 hours = 6 * 3/2 = 9 Hours
Required speed = 270/9 = 30 Kmph
B
Answer: (B) 30 Kmph
Question: 5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning?
(A) 4400
(B) 3500
(C) 8700
(D) 9000
(E) 8000
Rationale: X * (95/100) * (85/100) = 3553
X = 4400
ANSWER A
Answer: (A) 4400
Question: Jackson invested $400,000, dividing it all unequally between Account P and Account Q. At the end of the year, it turned out that Account P had earned 12% interest and Account Q had earned 25% interest. If Jackson earned a total of $60,000 in interest between the two accounts, which of the following is approximately the amount he put in account P?
(A) $115,384
(B) $120,000
(C) $121,072
(D) $124,129
(E) $130,000
Rationale: x be the amount invested in account P
0.12*x +(300000-x)*0.25=60,000
15000/.13=x
x=1500000/13=11...=$120,000
hence answer is B
Answer: (B) $120,000
Question: Which of the following trains is the fastest?
(A) 25 m/sec
(B) 1500 m/min
(C) 90 km/hr
(D) None of these
(E) Cannot be determined
Rationale: 25 m/sec = (25*18/5)km/hr=90km/hr.
And, 25 m/sec=(25*60)m/min=1500 m/min.
So, all the three speeds are equal.
Correct Option: D
Answer: (D) None of these
Question: O(x) represents the least odd integer greater than x, whereas o(x) represents the greatest odd integer less than x.
Likewise, E(x) represents the least even integer greater than x, whereas e(x) represents the greatest even integer less than x.
According to these definitions, the value of O(3.2) + E(–1.7) + o(–1.3) + e(2.7) is:
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: O(x) represents the least odd integer greater than x - O(3.2) = 5,
o(x) represents the greatest odd integer less than x - o(–1.3) = -3,
E(x) represents the least even integer greater than x - E(–1.7) = 0 ,
e(x) represents the greatest even integer less than x - e(2.7) = 2.
The value of O(3.2) + E(–1.7) + o(–1.3) + e(2.7) = 4
ANSWER:C
Answer: (C) 4
Question: If the area of a circle decreases by 36%, then the radius of a circle decreases by
(A) 20%
(B) 18%
(C) 36%
(D) 64%
(E) None of these
Rationale: If area of a circle decreased by x % then the radius of a circle decreases by
(100−10√100−x)%=(100−10√100−36)%
= (100−10√64)%
= 100 - 80 = 20%
Answer A
Answer: (A) 20%