mathewhe/aqua_rat huggingface dataset:
Question: Four packages have an average weight of 14.5 pounds. What is the minimum possible weight of the heaviest package in pounds if the median is 12 pounds?
(A) 25
(B) 24
(C) 23
(D) 22
(E) 21
Rationale: Let us denote the weights of the packages in pounds by a, b, c, d naming from the lightest one to the heaviest one. The median is 12 pounds. Therefore (b + c) / 2 = 12.
b + c = 24
The average is 14.5 pounds. Therefore (a + b + c + d) / 4 = 14.5.
a + (b + c) + d = 58
a + 24 + d = 58
a + d = 34
The weight a must be no greater than 12, since 12 is the median. Therefore the minimum possible weight of the heaviest package is 34 – 12 = 24 pounds (all the other packages would weigh 12 pounds in this case).
Answer: B
Answer: (B) 24
Question: The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?
(A) Rs. 5, Rs.7.50
(B) Rs. 8, Rs. 12
(C) Rs. 16, Rs. 10
(D) Rs. 12, Rs. 14
(E) NOne
Rationale: Solution:
Total cost of 10 books = Rs. 120
Total cost of 8 books = Rs. 94
=> The cost of 2 books = Rs. 26
Let the price of each book be x and y.
=> x + y = 26 ---------------- (1)
(160/100)y+y =26
On Solving for y, we get
y = 10.
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
x = 16.
So the price of each book is Rs. 16 and Rs. 10 respectively.
Answer: Option C
Answer: (C) Rs. 16, Rs. 10
Question: If the operation ∆ is defined by a ∆ b = (b - a)^2/a^2 for all numbers a and b, and a ≠ 0, then what is the result when we evaluate this expression: (-4) ∆ (4 ∆ −4) ?
(A) 2
(B) 4
(C) 6
(D) 8
(E) 10
Rationale: (-4) ∆ (4 ∆ −4) =
(-4) ∆ (8^2/4^2) =
(-4) ∆ (4) =
(-8^2) / (-4)^2 = 4
The answer is B.
Answer: (B) 4
Question: The probability that A speaks truth is 3/5 and that of B speaking truth is 4/7. What is the probability that they agree in stating the same fact?
(A) 18/35
(B) 18/35
(C) 18/39
(D) 18/31
(E) 18/32
Rationale: If both agree stating the same fact, either both of them speak truth of both speak false.
Probability = 3/5 * 4/7 + 2/5 * 3/7
= 12/35 + 6/35 = 18/35
Answer: A
Answer: (A) 18/35
Question: In a sample of Christ college students, 30 percent are third year students and 90 percent are not second-year students. What fraction of those students who are not third-year students are second-year students?
(A)  3/4
(B)  2/3
(C)  4/7
(D)  1/2
(E)  1/7
Rationale: = 10/70. = 1/7
my answer is E too
Answer: (E)  1/7
Question: A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 a.m., at what time will he first touch a flag at 120 feet from the ground?
(A) 4 p.m.
(B) 5 p.m.
(C) 6 p.m.
(D) 7 p.m.
(E) None of these
Rationale: A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour.
It means monkey climbs effectively 10 ft in 1 hr.
so it climbs 90 ft in 9 hrs .
balance 30 ft is covered in 10th hr.
So total it will take 10 hrs.
Monkey will touch 120 ft flag at 8+10 = 1800 hrs or 6 PM.
ANSWER:C
Answer: (C) 6 p.m.
Question: An article costing rs.160 is sold at 15% discount on a mark-up price. What is the selling price after
discount?
(A) 106
(B) 116
(C) 126
(D) 136
(E) 146
Rationale: Rs. 136
160-(160*15/100)=160*85/100=136
ANSWER:D
Answer: (D) 136
Question: For dinner at a restaurant, there are x + 1 choices of appetizers, y + 1 main courses, and z choices of dessert. How many total possible choices are there if you choose 1 appetizer, 1 main course, and 1 dessert for your meal?
(A) x + y + z + 1
(B) xyz + xz
(C) xyz+xz+yz+z
(D) xyz + 1
(E) xyz + 1/2
Rationale: x +1 appetizers,
y + 1 main courses,
z dessert
Required: 1 appetizer, 1 main course, and 1 dessert
Number of ways possible = (x+1)C1*(y+1)C1*zC1 {NC1 = N! / (N-1)!*1! = N}
Hence, number of ways = (x+1)(y+1)z = (yz+z)(x+1)=xyz+xz+yz+z
Correct Option: C
Answer: (C) xyz+xz+yz+z
Question: In a race of length L metres, Johnson beats Lewis by X metres and Greene by Y metres, By how many metres does Lewis beat Greene in the same race ? (X<Y)
(A) L(L-Y) / L-X
(B) L(Y-X) / L-X
(C) L-Y
(D) X-Y
(E) X+Y
Rationale: As the time is constant, the ratio of distances will be the same as the ratio of speeds.
If Sj,Sl,Sg are the speeds of Johnson, Lewis, and Greene respectively, then
Sj/Sl = L/(L-X)
and Sj/Sg = L/(L-Y)
=> Sg/Sl = (L-Y)/(L-X)
Therefore the speeds of Lewis and Greene are in the ratio (L-X)/(L-Y)
When Lewis finishes the race, the time run by him and Greene are same
=> The ratio of the speeds of Lewis and Greene will be the same as the ratio of distances run by them.
=> Distance run by Greene when Lewis finishes the race = (L-Y)/(L-X) * L
=> Lewis beats Greene by L - L*(L-Y)/(L-X) = L [ 1 - (L-Y)/(L-X)] = L (Y-X) / (L-X)
Option (B) is therefore correct.
Answer: (B) L(Y-X) / L-X
Question: A green grocer received a boxful of tomatoes and on opening the box found that several had gone bad. He then counted them up so that he could make a formal complaint and found that 68 were mouldy, which was 16 per cent of the total contents of the box. How many tomatoes were in the box?
(A) 336
(B) 425
(C) 275
(D) 235
(E) 689
Rationale: B
425
(68 Ã· 16) Ã— 100
Answer: (B) 425
Question: Find the perimeter and area of the rectangle of length 15 cm and breadth 13 cm.
(A) 71 cm2
(B) 121 cm2
(C) 141 cm2
(D) 195 cm2
(E) 221 cm2
Rationale: length = 15 cm, breadth = 13 cm
Perimeter of rectangle = 2 (length + breadth)
= 2 (15 + 13) cm
= 2 × 28 cm
= 56 cm
We know that the area of rectangle = length × breadth
= (15 × 13) cm22
= 195 cm2
ANSWER : D
Answer: (D) 195 cm2
Question: 6 points are marked on a straight line and another 7 points are marked on a second straight line with no points in common. How many triangles can be constructed with vertices from among the above points?
(A) 21
(B) 281
(C) 168
(D) 196
(E) 364
Rationale: Solution: select 2 from 6 and one from 7 + select 2 from 7 and 1 from 6
6C2*7C1 + 7C2*6C1
= 281
Answer : B
Answer: (B) 281
Question: A Contractor employed a certain number of workers to finish constructing a road in a certain scheduled time. Sometime later, when a part of work had been completed, he realised that the work would get delayed by three-fourth of the scheduled time, so he at once doubled the no of workers and thus he managed to finish the road on the scheduled time. How much work he had been completed, before increasing the number of workers?
(A) 14 9/7 %
(B) 14 2/7 %
(C) 14 2/3 %
(D) 14 2/5 %
(E) 54 2/7 %
Rationale: Explanation:
Let he initially employed x workers which works for D days and he estimated 100 days for the whole work and then he doubled the worker for (100-D) days.
D * x +(100- D) * 2x= 175x
=> D= 25 days
Now , the work done in 25 days = 25x
Total work = 175x
therefore, workdone before increasing the no of workers = \frac{25x}{175x}\times 100=14\frac{2}{7} %
Answer: B) 14 2/7 %
Answer: (B) 14 2/7 %
Question: A train running at the speed of 120 km/hr crosses a pole in 18 seconds. What is the length of the train?
(A) 560
(B) 570
(C) 580
(D) 590
(E) 600
Rationale: Speed=(120 x(5/18)m/sec	=(100/3)m/sec.
Length of the train = (Speed x Time).
Length of the train =	((100/3)x 18)m = 600 m
E
Answer: (E) 600
Question: In an examination, 25% of total students failed in Hindi, 40% failed in English and 35% in both. The percentage of these who passed in both the subjects is :
(A) 10%
(B) 20%
(C) 30%
(D) 40%
(E) 50%
Rationale: pass percentage = 100 - (25+40-35) = 100-70 = 30
ANSWER:C
Answer: (C) 30%
Question: A set of 11 positive integers has an average of 20. Which of the following is the greatest possible value for the median of this set?
(A) 25
(B) 30
(C) 35
(D) 45
(E) 46
Rationale: for the median to bé max , we should take all the values below meadian to be the lowest and the remaining values to be the same..
here 1 is the lowest value(positive int) số thẻ lowest 5 int will equal 5..
remaining 6= 20*11-5=215..
therefore each valueof these 6 int =215/6=35
ans C
Answer: (C) 35
Question: here are 6 periods in each working day of a school. In how many ways can one organize 5 subjects such that each subject is allowed at least one period?
(A) 1234
(B) 4512
(C) 1800
(D) 1203
(E) 4512
Rationale: 5 subjects can be arranged in 6 periods in 6P5 ways.
Any of the 5 subjects can be organized in the remaining period (5C1 ways).
Two subjects are alike in each of the arrangement. So we need to divide by 2! to avoid overcounting.
Total number of arrangements
= 6P5× 5C1 /2!=1800
Ans: C
Answer: (C) 1800
Question: How many E ways can Jason sit with his five friends in a row of six seats with an aisle on either side of the row, if Jason insists on sitting next to one of the aisles?
(A) 120
(B) 240
(C) 360
(D) 540
(E) 720
Rationale: Jason can select his seat in 2 Ways (two aisles)
His 1st of 4 friends have 5 seats to select =>
His 2nd of remaining 3 friends will have 4 seat to chose from...and so on
Total ways E=> 2*5*4*3*2*1 = 240.B
Answer: (B) 240
Question: At the end of three years what will be the compound interest at the rate of 10% p.a. on an amount of Rs.20000?
(A) Rs.6620
(B) 3378
(C) 2768
(D) 2999
(E) 2771
Rationale: A = 20000(11/10) 3
= 26620
= 20000
----------
6620
Answer: A
Answer: (A) Rs.6620
Question: The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
(A) 87 kmph
(B) 40 kmph
(C) 16 kmph
(D) 15 kmph
(E) 18 kmph kmph
Rationale: Speed downstream = 60 + 20
= 80 kmph
Speed upstream = 60 - 20
= 40 kmph
Answer:B
Answer: (B) 40 kmph
Question: Anita, Indu and Geeta can do a piece of work in 18 days, 27 days and 36 days respectively. They start working together. After working for 4 days. Anita goes away and Indu leaves 7 days before the work is finished. Only Geeta remains at work from beginning to end. In how many days was the whole work done?
(A) 16 days
(B) 14 days
(C) 18 days
(D) 19 days
(E) 12 days
Rationale: 4/18 + (x -7)/27 + x/36 = 1
x = 16 days
Answer: A
Answer: (A) 16 days
Question: In a certain shop , 70 percent of customers buy mobiles made by company (A) and the rest buy mobiles made by company (B) . A new mobile is made by company (A) . If 90 percent of customers who prefer company (A) and 50 percent of customers who prefer company (B) are expected to buy the new mobile , whats percent of customers are expected to buy the new mobile ?
(A) 70
(B) 78
(C) 80
(D) 82
(E) 86
Rationale: Say there are total of 100 customers in the shop . Thus 70 customers prefer company (A) and 30 customers prefer company(B).
70*0.9=63 customers who prefer company (A) are expected to buy for the new mobile ;
30*0.5=15 customers who prefer company (B) are expected to buy for the new mobile .
Thus total of 63+15=78 members are expected to buy the new mobile, which is 78% of the total number of customers .
Answer: B.
Answer: (B) 78
Question: A customer pays 30 dollars for a coffee maker after a discount of 20 dollars
What is the original price of the coffee maker?
(A) 90
(B) 40
(C) 70
(D) 60
(E) 50
Rationale: Let x be the original price.
x - 20 = 30
x - 20 + 20 = 30 + 20
x + 0 = 50
x = 50
Answer is E
Answer: (E) 50
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 750 grams per kg, what is his percent?
(A) 11
(B) 33
(C) 77
(D) 88
(E) 11
Rationale: 750 --- 250
100 --- ? => 33%
Answer:B
Answer: (B) 33
Question: In a single throw of a die, what is the probability of getting a number greater than 4?
(A) 1/2
(B) 1/3
(C) 2/3
(D) 1/4
(E) 1/5
Rationale: When a die is thrown we have S = {1,2,3,4,5,6}
Let E = event of getting a number greater than 4 = {5,6}
P(E) = n(E)/n(S) = 2/6 = 1/3.
Answer B.
Answer: (B) 1/3
Question: A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.21000. A's share is?
(A) s.7000
(B) s.7200
(C) s.6000
(D) s.5750
(E) s.6750
Rationale: x* 12 : 2x* 6: 3x* 4
1:1:1
1/3 * 21000 = 7000
ANSWER:A
Answer: (A) s.7000
Question: Three numbers are such that the second is as much
lesser than the third as the first is lesser than
the second. If the product of the two smaller numbers
is 85 and the product of two larger numbers is 115.
Find the middle number?
(A) 10
(B) 12
(C) 14
(D) 16
(E) 18
Rationale: Let the three numbers be x,y,z
2y = x+z.....................1
Given that the product of two smaller numbers is 85
x y = 85................2
Given that the product of two larger numbers is 115
y z = 115...............3
Dividing 2 and 3 x y /y z = 85/115
x / z = 17 / 23
From 1
2y = x+z
2y = 85/y + 115/y
2y2 = 200
y2 = 100
y = 10
ANSWER A
Answer: (A) 10
Question: 65% of x = 20% of 617.50. Find the value of x?
(A) 100
(B) 190
(C) 150
(D) 180
(E) 199
Rationale: 65% of x = 20% of 615.50
Then, 65/100 * x = 20/100 * 6175/10
x = 190
Answer is B
Answer: (B) 190
Question: How many subset of the Fruit set of Banana, Apple, Orange, Grape and Lemon does not contain Apple?
(A) 17
(B) 16
(C) 15
(D) 14
(E) 18
Rationale: This is a combination solution
Since we have 4 different kinds of fruits other than Apple we can take any fruit from the set of 4 to make a subset.
4C1 +4C2 + 4C3 + 4C4 = 15
Plus the one set that is null that is the Set having no element in it which is 4C0 =1
= 15 + 1 = 16
B = 16
Answer: (B) 16
Question: An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62
sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, is
(A) 10:28 am
(B) 10:30 am
(C) 10:31 am
(D) 10:37 am
(E) None of above
Rationale: Explanation:
L.C.M. of 60 and 62 seconds is 1860 seconds
1860/60 = 31 minutes
They will beep together at 10:31 a.m.
Sometimes questions on red lights blinking comes in exam, which can be solved in the same way
Answer: Option C
Answer: (C) 10:31 am
Question: Simplify: 9948/49 * 245.
(A) 24495
(B) 23395
(C) 22225
(D) 22115
(E) None of them
Rationale: Given expression = (100-1/49) * 245=(4899/49) * 245 = 4899 * 5=24495.
Answer is A.
Answer: (A) 24495
Question: The sides of a rectangular region measured to the nearest centimeter are 8 cm and 4 cm. Out of the following which is the largest possible value of actual area of rectangle ?
(A) 48
(B) 35.25
(C) 52.29
(D) 44
(E) 41.25
Rationale: acan be anywhere between 7.5 and 8.4 andbcan be anywhere between 3.5 and 4.4.
Hence max area can be 8.4*4.4 eq 36.96.
largest value which is near to 36.96 is 35.25.
Hence B.
Answer: (B) 35.25
Question: The sum of two numbers is 36. Four times one number is equal to 5 times the other. The bigger of the two numbers is
(A) 20
(B) 12
(C) 14
(D) 15
(E) 60
Rationale: a:b 4:5
a+b=36
4x+5x=36
x=4
then two numbers are 16,20. The bigger number is 20
ANSWER: A
Answer: (A) 20
Question: The letters of the word LUCKNOW are arranged among themselves. Find the probability of always having NOW in the word.
(A) 1/31
(B) 1/32
(C) 1/41
(D) 1/42
(E) None of these
Rationale: Explanation :
Since NOW has to always come together, assume it as one single unit. The rest 4 characters can occur in any way. So total no of characters = 5
The required probability will be given by the equation
= No. of words having NOW/Total no. of words
= 5!/7! = 1/42
Answer : D
Answer: (D) 1/42
Question: The average of ages of 10 persons in a club was 32. What should be the age of the new person joining in the club so as to increase the average by 4 ?
(A) 76
(B) 2366
(C) 299
(D) 277
(E) 221
Rationale: Correct Option: D
Explanation:
Total age of 10 persons = 10 × 32 = 320
Total age of 11 persons = 11 × 36 = 396 (as the new average is 4 more than present average)
So the age of the person joining is = 396 - 320 = 76
Answer:A
Answer: (A) 76
Question: An accurate clock shows 8 o’clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 1 o’clock in the afternoon?
(A) 60°
(B) 150°
(C) 180°
(D) 320°
(E) None of these
Rationale: Sol.
Angle traced by the hour hand in 5 hours = [360/12 * 5]° = 150°
Answer B
Answer: (B) 150°
Question: In a kilometer race, A beats B by 40 meters or 8 seconds. What time does A take to complete the race?
(A) 221
(B) 190
(C) 192
(D) 191
(E) 121
Rationale: Time taken by B run 1000 meters = (1000 * 8)/40 = 200 sec.
Time taken by A = 200 - 8 = 192 sec.Answer:C
Answer: (C) 192
Question: A broker invested her own money in the stock market. During the first year, she increased her stock market wealth by 40 percent. In the second year, largely as a result of a slump in the stock market, she suffered a 30 percent decrease in the value of her stock investments. What was the net increase or decrease on her overall stock investment wealth by the end of the second year?
(A) −5%
(B) −2%
(C) 15%
(D) 20%
(E) 80%
Rationale: The actual answer is obtained by multiplying 140% by 70% and subtracting 100% from this total. That is: 140% × 70% = 98%; 98% − 100% = -2%.
Answer: B
Answer: (B) −2%
Question: A lady grows cabbage in her garden that is in the shape of a square. Each cabbage takes 1 square foot of area in her garden. This year, she has increased her output by 211 cabbages when compared to last year. The shape of the area used for growing the cabbage has remained a square in both these years. How many cabbages did she produce this year?
(A) 11236
(B) 11025
(C) 14400
(D) 12696
(E) Cannot be determined
Rationale: Explanatory Answer
The shape of the area used for growing cabbages has remained a square in both the years.
Let the side of the square area used for growing cabbages this year be X ft.
Therefore, the area of the ground used for cultivation this year = X2 sq.ft.
Let the side of the square area used for growing cabbages last year be Y ft.
Therefore, the area of the ground used for cultivation last year = Y2 sq.ft.
As the number of cabbages grown has increased by 211, the area would have increased by 211 sq ft because each cabbage takes 1 sq ft space.
Hence, X2 - Y2 = 211
(X + Y)(X - Y) = 211.
211 is a prime number and hence it will have only two factors. i.e., 211 and 1.
Therefore, 211 can be expressed as product of 2 numbers in only way = 211 * 1
i.e., (X + Y)(X - Y) = 211 * 1
So, (X + Y) should be 211 and (X - Y) should be 1.
Solving the two equations we get X = 106 and Y = 105.
Therefore, number of cabbages produced this year = X2 = 1062 = 11236.
Alternative Approach : Use answer choices
The area in both the years are squares of two numbers.
That rules out choice D. 12696 is not the square of any number.
Check Choice A: If this year's produce is 11236, last year's produce would have been 11236 - 211 = 11025
11025 is the square of 105.
So, 11236 is the answer.
Choice A is the correct answer.
Answer: (A) 11236
Question: In a college there are 35 students. What is the smallest number of books that must be brought so that each student receives the same number of books?
(A) 46
(B) 17
(C) 300
(D) 250
(E) 140
Rationale: The number of students in a college are 35.
E is the correct answer because only 140 is divisible by 35.
Answer: (E) 140
Question: If the average (arithmetic mean) of the four numbers K, 2K + 3, 3K – 5 and 5K + 1 is 96, what is the value of K?
(A)  11
(B)  15 3/4
(C)  22
(D)  35
(E)  25 3/10
Rationale: K + 2K +3 + 3K - 5 + 5K +1 = 11K -1
(11K -1)/4 = 96
11K = 96 * 4 +1 = 384 +1 = 385
K = 385 / 11 = 35.
Answer D.
Answer: (D)  35
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 46, the dividend is:
(A) 5236
(B) 5330
(C) 5336
(D) 5348
(E) 5352
Rationale: Divisor = (5 * 46) = 230
= 10 * Quotient = Divisor
=> Quotient = 230/10 = 23
Dividend = (Divisor * Quotient) + Remainder
Dividend = (230 * 23) + 46 = 5336.
C)
Answer: (C) 5336
Question: A and B starts a business with Rs.8000 each, and after 4 months, B withdraws half of his capital . How should they share the profits at the end of the 18 months?
(A) 18:11
(B) 18:18
(C) 18:12
(D) 18:16
(E) 18:13
Rationale: Explanation:
A invests Rs.8000 for 18 months, but B invests Rs.8000 for the first 4 months and then withdraws Rs.4000. So, the investment of B for remaining 14 months is Rs.4000 only.
A : B
8000*18 : (8000*4) + (4000*14)
14400 : 88000
A:B = 18:11
Answer: A
Answer: (A) 18:11
Question: If a card is drawn from a well shuffled pack of cards, the probability of drawing a spade or a king is?
(A) 4/15
(B) 4/17
(C) 4/12
(D) 4/13
(E) 4/11
Rationale: P(SᴜK)
= P(S) + P(K) - P(S∩K), where S denotes spade and K denotes king.
P(SᴜK)
= 13/52 + 4/52 - 1/52
= 4/13
Answer: D
Answer: (D) 4/13
Question: In a fuel station the service costs $2.05 per car, every liter of fuel costs 0.6$. Assuming that you fill up 3 mini-vans and 2 trucks, how much money will the fuel cost to all the cars owners total, if a mini- van's tank is 70 liters and a truck's tank is 120% bigger and they are all empty-?
(A) 312.6$
(B) 321.05$
(C) 343.7$
(D) 398.85$
(E) 412.12$
Rationale: Service cost of 3 van and 2 truck = 2.05*(3+2)=10.5
Fuel in 3 Van = 3*70=210 litre
Fuel in 2 Trucks =2 * 70(1+120/100)= 308
Total fuel(Van+Truck) = 518 Litre
Total Fuel cost = 518*0.6 =310.8
TOTAL COST =FUEL+SERVICE=310.8+10.25=321.05
ANSWER IS B
Answer: (B) 321.05$
Question: A bag contains 12 white and 18 black balls. 2balls are drawn in succession. What is the probability that first is white and second is black?
(A) 36/141
(B) 36/145
(C) 30/141
(D) 36/115
(E) 3/145
Rationale: The probability that first ball is white:
=12C130C1=12C130C1
=1230=1230
=25=25
Since, the ball is not replaced; hence the number of balls left in bag is 29.
Hence, the probability the second ball is black:
=18C129C1=18C129C1
=1829=1829
Required probability,
=(25)×(1829)=(25)×(1829)
=36/145
B
Answer: (B) 36/145
Question: The simple interest on Rs.15000 at a certain rate of interest in five years is Rs.7200. Find the compound interest on the same amount for two years at the same rate of interest.
(A) 3052.82
(B) 3015.24
(C) 3052.24
(D) 3018.24
(E) 3052.23
Rationale: R = 100 I / PT
=> R = (100 * 7200)/ (15000 * 5) = 9.6%
CI = P{ [1 + R /100]n - 1}
= 15000 { [ 1 + 9.6 / 100]^2 - 1} = Rs.3018.24
Answer:D
Answer: (D) 3018.24
Question: Steve traveled the first 2 hours of his journey at 50 mph and the last 3 hours of his journey at 80 mph. What is his average speed of travel for the entire journey?
(A) 68 mph
(B) 56.67 mph
(C) 60 mph
(D) 64 mph
(E) 66.67 mph
Rationale: Average Speed = Total distance/ Total time = (50 * 2 + 80 * 3)/(2 + 3) = 68
Ans:A
Answer: (A) 68 mph
Question: If the average marks of 3classes of 55, 60 and 45 students respectively is 50, 55, 60, then find the average marksof all the students is
(A) 53
(B) 53.5
(C) 54.68
(D) 55.6
(E) 67.2
Rationale: Required average
= 55 x 50 + 60 x 55 + 45 x 60
55 + 60 + 45
= 2750 + 3300 + 2700
160
=	8750
160
= 54.68
C
Answer: (C) 54.68
Question: If a sum on compound interest becomes three times in 4 years, then with the same interest rate, the sum will become 81 times in
(A) 12 years
(B) 18 years
(C) 16 years
(D) 14 years
(E) 15 years
Rationale: Explanation:
Let the sum be P
The sum P becomes 3P in 4 years on compound interest
3P = P(1+R/100)4
⇒ 3 = (1+R/100)4
Let the sum P becomes 81P in n years
81P = P(1+R/100)n
⇒ 81 = (1+R/100)n
⇒ (3)4 =(1+R/100)n
⇒((1+R/100)n)n
=(1+R/100)n
⇒ (1+R/100)16
= (1+R/100)n
n = 16
i.e, the sum will become 81 times in 16 years
Answer: Option C
Answer: (C) 16 years
Question: how many distinct 3 digit number less than 10
(A) 8
(B) 9
(C) 10
(D) 11
(E) 12
Rationale: 000,001,002,003,004,005,006,007,008,009.
10 distinct 3 digit numbers less than 10.
ANSWER:C
Answer: (C) 10