mathewhe/aqua_rat huggingface dataset:
Question: In a 100m race, Sam beats John by 4 seconds. On the contrary, if Sam allowed John to start 24m ahead of Sam, then Sam and John reach the finishing point at the same time. How long does Sam take to run the 100m race?
(A) 4 seconds
(B) 25 seconds
(C) 19 seconds
(D) 21 seconds
(E) 6.25 seconds
Rationale: Their difference is 4 second but this difference is 0 if john allows Sam to start the race from 24m ahead . that means Jhon was 24m away from finishing line when they started together . so He will cover 24 m in 4 seconds . so his speed =24/4=6 metre / second . so time taken =100/4=25 seconds . so Sam took = 19 seconds .
correct answer = C
Answer: (C) 19 seconds
Question: A sum of 13,400 amounts to 14,400 in 2 years at the rate of simple interest. What is the rate of interest?
(A) 2%
(B) 1%
(C) 6%
(D) 4%
(E) 8%
Rationale: D
4%
S.I. = (14400 - 13400) = 1000.
Rate = (100 x 1000)/(13400x2)% = 4%
Answer: (D) 4%
Question: The rate of Interest on a sum of money is 5% p.a. for the first 3 years, 4% p.a. for the next 4 years, and 5% for the period beyond 7 years. If the S.I, Occured on the sum for the total period of 8 years is Rs. 540/-, the sum is
(A) 1,500
(B) 2,000
(C) 2,100
(D) 2,250
(E) 2,540
Rationale: Explanation:
I1 = (P x 3 x 5)/100 = 3P/20
I2 = (P x 4 x 4)/100 = 4P/25
I3 = (P x 1 x 5)/100 = P/20
3P/20 + 4P/25 + P/20 = 540
9P/25 = 540
P = 1500
Answer: Option A
Answer: (A) 1,500
Question: Find 60/42*4
(A) 14.7653
(B) 0.5897
(C) 3.6974
(D) 0.3571
(E) 1.2587
Rationale: Answer=60/42*4
=60/168=0.3571
Option D is correct
Answer: (D) 0.3571
Question: A family consists of two grandparents, two parents and three grandchildren. The average age of the grandparents is 67 years, that of the parents is 35 years and that of the grandchildren is 6 years. What is the average age of the family?
(A) 31 5/7
(B) 32
(C) 33
(D) 35
(E) 37
Rationale: Required average
= 67 x 2 + 35 x 2 + 6 x 3
2 + 2 + 3
= 134 + 70 + 18
7
=	222
7
= 31 5	years.
7
Option A
Answer: (A) 31 5/7
Question: When the smallest of 3 consecutive odd integers is added to four times the largest, it produces a result 732 more than 4times the middle integer. Find the numbers?
(A) 732
(B) 678
(C) 698
(D) 710
(E) 729
Rationale: x + 4 (x + 4) = 732 + 4 (x + 2)
Solve for x and find all three numbers
x + 4 x + 16 = 732 + 4 x + 8
x = 724
x + 2 = 726
x + 4 = 728
Check: the smallest is added to four times the largest
724 + 4 * 728 = 3636
four times the middle
4 * 726 = 2904
3636 is more than 2904 by
3636 - 2904 = 732
A
Answer: (A) 732
Question: A certain company retirement plan has arule of 70provision that allows an employee to retire when the employee's age plus years of employment with the company total at least 70. In what year could a female employee hired in 1989 on her 32nd birthday first be eligible to retire under this provision?
(A) 2008
(B) 2004
(C) 2005
(D) 2006
(E) 2007
Rationale: She must gain at least 70 points, now she has 32 and every year gives her two more points: one for age and one for additional year of employment, so 32 + 2*(# of years) = 70 --> (# of years) = 19 --> 1989+19=2008.
Answer: A.
Answer: (A) 2008
Question: A and B complete a work in 10 days. A alone can do it in 14 days. If both together can do the work in how many days?
(A) 3.75 days
(B) 5.8 days
(C) 4.5 days
(D) 4.7 days
(E) 5.75 days
Rationale: 1/10 + 1/14 =6/35
35/6 = 5.8 days
Answer:B
Answer: (B) 5.8 days
Question: 10 men, working 8 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the work in 12 days ?
(A) 4 hours a day
(B) 5 hours a day
(C) 6 hours a day
(D) 7 hours a day
(E) 8 hours a day
Rationale: Explanation:
More Men, Less Hours {Indirect Proportion}
Less Days, More Hours {Indirect Proportion}
[men 15 10
days 12 18] ::8:x
=>xâˆ—15âˆ—12=10âˆ—18âˆ—8
=>x=10âˆ—18âˆ—8/ 15âˆ—12
=>x=8
Option E
Answer: (E) 8 hours a day
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12300 after a year?
(A) 3630
(B) 3690
(C) 3630
(D) 3631
(E) 3635
Rationale: 6300:4200:10500
3:2:5
3/10 * 12300 = 3690
Answer: B
Answer: (B) 3690
Question: At the start of an experiment, a certain population consisted of 3 animals. At the end of each month after the start of the experiment, the population size was double its size at the beginning of that month. Which of the following represents the population size at the end of 11 months?
(A)  2^3
(B)  3^2
(C)  2(3^10)
(D)  3(2^11)
(E)  3(10^2)
Rationale: 3*2^n where n is the #of month --> 3*2^11 Answer (D)
Answer: (D)  3(2^11)
Question: If n is the product of three consecutive integers, and n is divisible by 5, which of the following is not necessarily a divisor of n ?
(A) 210
(B) 220
(C) 230
(D) 240
(E) 250
Rationale: IF ONE NO. IS 5 THEN OTHER CONSEQUTIVE NO. ARE 3*4*5 =60 , 4*5*6=120 , 5*6*7 =210
210 WILL NO BE DIVISOR OF N
A
Answer: (A) 210
Question: If 280 people, constituting 5 percent of the population of a town, ride bicycles, and the others do not, then how many people in the town do not ride bicycles?
(A) 5930
(B) 5600
(C) 5320
(D) 5110
(E) 4980
Rationale: 5 % of X is 280
5/100 * X = 280
X = 280*100/5 = 5600
So C. 5320 is the correct Answer
No. of people Not Riding Bike = 5600 - 280 = 5320
answer is C
Answer: (C) 5320
Question: In one hour, a boat goes 14 km/hr along the stream and 8 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
(A) 12 km/hr
(B) 11 km/hr
(C) 10 km/hr
(D) 8 km/hr
(E) 15 km/hr
Rationale: EXPLANATION
Let speed of the boat in still water = a and speed of the stream = b
Then
a + b = 14
a - b = 8
Adding these two equations, we get 2a = 22
=> a = 11
ie, speed of boat in still water = 11 km/hr
ANSWER IS B
Answer: (B) 11 km/hr
Question: 50 square stone slabs of equal size were needed to cover a floor area of 72 sq.m. Find the length of each stone slab?
(A) 120cm
(B) 767cm
(C) 88cm
(D) 666cm
(E) 776cm
Rationale: Area of each slab
=72/50m2=1.44m2
Length of each slab √1.44=1.2m=120cm
Answer: (A) 120cm
Question: If the average (arithmetic mean) of a and b is 45 and the average of b and c is 70, what is the value of c − a?
(A) 25
(B) 50
(C) 90
(D) 140
(E) It cannot be determined from the information given.
Rationale: the arithmetic mean of a and b =(a+b)/2=45 -- a+b=90 --1
similarly for b+c=140 --2
subtracting 1 from 2 we have
c-a=50 ANSWER:E
Answer: (E) It cannot be determined from the information given.
Question: If one of the followings is the product of the two 3-digit integers 8K1 and 6L5 (K and L denote the tens digit of the respective integers), then that product must be
(A)  478,823
(B)  511,913
(C)  531,875
(D)  538,424
(E)  569,114
Rationale: To know the unit digit you can multiply both digit number: 1 x 5 = 5
This eliminates A, B, D, and E, because the number must end with a 5
So the answer is C
Answer: (C)  531,875
Question: If a: b = 6:4, b: c =7: 8, find a: b: c?
(A) 24: 28: 32
(B) 42: 28: 36
(C) 42: 28: 38
(D) 42: 28: 32
(E) 22: 28: 32
Rationale: a: b = 6:4
b: c =7: 8
a: b: c = 42: 28: 32
Answer : D
Answer: (D) 42: 28: 32
Question: An escalator is descending at constant speed. A walks down and takes 50 steps to reach the bottom. B runs down and takes 90 steps in the same time as A takes 10 steps. How many steps are visible when the escalator is not operating?
(A) 80
(B) 90
(C) 100
(D) 110
(E) 120
Rationale: Lets suppose that A walks down 1 step / min and
escalator moves n steps/ min
It is given that A takes 50 steps to reach the bottom
In the same time escalator would have covered 50n steps
So total steps on escalator is 50+50n.
Again it is given that B takes 90 steps to reach the bottom and time
taken by him for this is equal to time taken by A to cover 10 steps i.e
10 minutes. So in this 10 min escalator would have covered 10n steps.
So total steps on escalatro is 90 + 10n
Again equating 50 + 50n = 90 +10n we get n = 1
Hence total no. of steps on escalator is 100.
ANSWER:C
Answer: (C) 100
Question: A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is :
(A) Rs. 700
(B) Rs. 690
(C) Rs. 650
(D) Rs. 698
(E) Rs. 690
Rationale: Simple Interest (SI) for 1 year = 854-815 = 39
Simple Interest (SI) for 3 years = 39 × 3 = 117
Principal = 815 - 117 = Rs.698
answer : D
Answer: (D) Rs. 698
Question: Two ants, Arthur and Amy, have discovered a picnic and are bringing crumbs back to the anthill. Amy makes twice as many trips and carries one and a half times as many crumbs per trip as Arthur. If Arthur carries a total of m crumbs to the anthill, how many crumbs will Amy bring to the anthill, in terms of m?
(A) x/2
(B) x
(C) 3m/2
(D) mx
(E) mx
Rationale: Lets do it by picking up numbers. Let Arthur carry 2 crumbs per trip, this means Amy carries 3 crumbs per trip. Also let Arthur make 2 trips and so Amy makes 4 trips.
Thus total crumbs carried by Arthur (m) = 2 x 2 = 4, total crumbs carried by Amy = 3 x 4 = 12. 12 is 3 times 4, so E
Answer: (E) mx
Question: The area of a triangle is with base 4m and height 5m?
(A) 20 sq m
(B) 10 sq m
(C) 5 sq m
(D) 3 sq m
(E) 12 sq m
Rationale: Explanation:
1/2 * 4 * 5 = 10 m2
ANSWER IS B
Answer: (B) 10 sq m
Question: A sum of money at simple interest amounts to $ 700 in 3 years and to $764 in 4 years. The sum is:
(A) $508
(B) $698
(C) $398
(D) $549
(E) $675
Rationale: A
$508
S.I. for 1 year = $(764 - 700) = $64.
S.I. for 3 years = $(64 x 3) = $192.
Principal = $(700 - 192) = $508.
Answer: (A) $508
Question: A train 700 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
(A) 298 m
(B) 468 m
(C) 600 m
(D) 667 m
(E) 781 m
Rationale: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (700 + x)/60 = 65/3
x = 600 m.
Answer: C
Answer: (C) 600 m
Question: A grocer has a sale of Rs. 4000, Rs. 6524, Rs. 5689, Rs. 7230 and Rs. 6000 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 7000?
(A) s. 12557
(B) s. 14993
(C) s. 15560
(D) s. 12589
(E) s. 12500
Rationale: Total sale for 5 months = Rs. (4000 + 6524+ 5689 + 7230 + 6000) = Rs.29443
Required sale = Rs. [ (7000 x 6) - 29443 ]
= Rs. (42000 - 29443)
= Rs. 12557.
Option A
Answer: (A) s. 12557
Question: 3 cooks have to make 80 burgers. They are known to make 20 pieces every minute working together.The 1st cook began workin alone and made 20 pieces having worked for sometime more than 3 mins.The remaining part of the work was done by second and 3rd cook working together.It took a total of 8 minutes to complete the 80 burgers.How many minutes would it take the 1st cook alone to cook 160 burgers?
(A) 16 minutes
(B) 24 mins
(C) 32 mins
(D) 40 mins
(E) 30 mins
Rationale: Denote by A, B, C the rates of the three cooks in units of burgers/minute.
A + B + C = 20.
Let t be the time in minutes it took the first cook A to make the 20 burgers. So, A*t = 20, and we know that t > 3.
We need to find 8t, as 160 burgers will be made by A in 8 times more than making 20 burgers.
We already know that 8t > 8*3 = 24, so we can eliminate answers (A) and (B).
In addition, (B + C)(8 - t) = 60, or (20 - A)(8 - t) = 60.
Since 20 - A < 20 and 8 - t < 5, looking for integer solutions, we find the only acceptable solution 20 - A = 15 and 8 - t = 4, so t = 4.
I am assuming integer numbers for the solutions based on the answer choices.
Anyway, testing the answer choices, only (C) is a solution.
Therefore, A will make 160 burgers in 8*4 = 32 minutes.
Answer C
Answer: (C) 32 mins
Question: A person travels equal distances with speeds of 3 km/hr, 4 km/hr and 5 km/hr and takes a total time of 47 minutes. The total distance is?
(A) 1
(B) 3
(C) 4
(D) 45
(E) 4
Rationale: Let the total distance be 3x km.
Then, x/3 + x/4 + x/5 = 47/60
47x/60 = 47/60 => x = 1.
Total distance = 3 * 1 = 3 km.
Answer:B
Answer: (B) 3
Question: X starts a business with Rs.45000. Y joins in the business after 3 months with Rs.30000. What will be the ratio in which they should share the profit at the end of the year?
(A) 1:2
(B) 2:1
(C) 1:3
(D) 3:1
(E) None of these
Rationale: Explanation :
Ratio in which they should share the profit
= Ratio of the investments multiplied by the time period
= 45000 * 12: 30000 * 9
= 45 * 12: 30 * 9
= 3*12: 2 * 9
= 2:1. Answer : Option B
Answer: (B) 2:1
Question: An engineer undertakes a project to build a road 10 km long in 300 days and employs 30 men for the purpose. After 100 days, he finds only 2 km of the road has been completed. Find the (approximate) number of extra men he must employ to finish the work in time.
(A) 20
(B) 25
(C) 30
(D) 35
(E) 40
Rationale: 30 workers working already
Let x be the total men required to finish the task in next 200 days
2 km done hence remaining is 8 km
Also, work has to be completed in next 200 days (300 - 100 = 200)
We know that, proportion of men to distance is direct proportion
and, proportion of men to days is inverse proportion
Hence, X = (30 * 8 * 100) / (2 *200)
thus, X = 60
Thus, more men needed to finish the task = 60-30=30
Answer : C
Answer: (C) 30
Question: What is the least number of square tiles required to pave the floor of a room 11 m 50cm long and 1m 50 cm broad?
(A) 724
(B) 804
(C) 69
(D) 844
(E) None
Rationale: Solution
Length of largest tile = H.C.F. of 1150cm & 150cm = 50cm.
Area of each tile = (50 x 50)cm2
∴ Required number of tiles	= [1150x150/50x50]
= 69.
Answer C
Answer: (C) 69
Question: Mrs. Evans gave a test to her freshmen economics class, which has 29 students enrolled and 24 of them answered question 1 correctly. If 22 answered question 2 correctly and 5 did not take the test then how many answered both questions correctly?
(A) 18
(B) 19
(C) 22
(D) 20
(E) 19
Rationale: Total number of enrolled students = 29
Number of students who did not take test = 5
Hence, number of students who took test = 29 - 5 = 24
Number of students who answered Q2 correctly =24, therefore, all students who took test answered Q2 correctly.
So, number of students who answered Q1 correctly, also answered Q2 correctly = 22.
Number of students who answered both Q1 & Q2 correctly = 22.
ANSWER:C
Answer: (C) 22
Question: If x is an odd negative integer and y is an even integer, which of the following statements must be true?
I. (3x + 2y) is negative integer
II. (xy)^2 is negative integer
III. (y^2 - x) is negative integer
(A) None of these
(B) I Only
(C) II only
(D) IIIonly
(E) I,II only
Rationale: I. It is true if x > y
II. It is always positive
III. It is not true
Answer : A
Answer: (A) None of these
Question: How many positive even integers less than 100 contain digits 3 or 7?
(A) 16
(B) 17
(C) 18
(D) 10
(E) 20
Rationale: Two digit numbers:
3 at tens place: 30,32,34,36,38
7 at tens place: 70,72,74,76,78
If 3 and 7 is at units place, the number cant be even
Total:5+5= 10
Answer D
Answer: (D) 10
Question: A school has only four classes that contain 10, 20, 30 and 40 students respectively. The pass percentage of these classes are 20%, 30%, 60% and 100% respectively. Find the pass % of the entire school.
(A) 56%
(B) 76%
(C) 34%
(D) 66%
(E) None of these
Rationale: Solution: The number of pass candidates are 2+6+18+40 = 66 out of total 100.
Hence,
Pass pecentage = 66%.
Answer: Option D
Answer: (D) 66%
Question: Today is Jack's birthday. One year, from today he will be twice as old as he was 13 years ago. How old is Jack today ?
(A) 23 years
(B) 24 years
(C) 25 years
(D) 26 years
(E) 27 years
Rationale: let Jack's age=xx+1=2(x-13)x=27ANSWER:E
Answer: (E) 27 years
Question: Peter brought a scooter for a certain sum of money. He spent 10% of the cost on repairs and sold the scooter for a profit of $ 1100. How much did he spend on repairs if he made a profit of 20%?
(A) 100
(B) 200
(C) 300
(D) 400
(E) 500
Rationale: E
500
Let the C.P. be $ x. Then, 20% of x = 1100
20/100 * x = 1100 => x = 5500
C.P. = $ 5500, expenditure on repairs = 10%
Actual price = $ (100 * 5500)/110 = $ 5000
Expenditures on repairs = (5500 - 5000) = $ 500.
Answer: (E) 500
Question: Find the odd man out
4, 16, 25, 36, 42, 64
(A) 36
(B) 25
(C) 42
(D) 95
(E) 4
Rationale: 2^2 = 4
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^2 = 64
ANSWER:C
Answer: (C) 42
Question: The average weight of a group of boys is 30 kg. After a boy of weight 33 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
(A) 4
(B) 8
(C) 5
(D) 2
(E) 9
Rationale: Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 33 kg joins the group, total weight of boys = 30x + 33
So 30x + 33 + 31(x + 1) = > x = 2.
Answer: D
Answer: (D) 2
Question: A man can swim in still water at 4.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
(A) 1.3
(B) 1.2
(C) 1.9
(D) 1.5
(E) 1.1
Rationale: M = 4.5
S = x
DS = 4.5 + x
US = 4.5 + x
4.5 + x = (4.5 - x)2
4.5 + x = 9 -2x
3x = 4.5
x = 1.5
Answer:D
Answer: (D) 1.5
Question: Which of the following lines has x-intercept and y-intercept that are integers Q?
(A) y=3x+1
(B) y=√x+1
(C) y=-2/x
(D) y=x^2-1
(E) xy=1
Rationale: Values that satisfy y=x^2-1 are (x,y)=(-1,0),(1,0),(0,-1). Hence, they are all integers Q and the correct answer is D.
Answer: (D) y=x^2-1
Question: if a^2+b^2=177and ab=54 then find the value of a+b/a-b?
(A) 5
(B) 15
(C) 6
(D) 3
(E) 7
Rationale: (a+b)^2=a^2+b^2+2ab=117+2*24=225
a+b=15
(a-b)^2=a^2+b^2-2ab=117-2*54
a-b=3
a+b/a-b=15/3=5
Option A
Answer: (A) 5
Question: A bag contains 50 p, 25 P and 10 p coins in the ratio 5: 9: 4, amounting to
Rs. 206. Find the number of coins of each type.
(A) 165
(B) 174
(C) 160
(D) 163
(E) 135
Rationale: Let the number of 50 p, 25 P and 10 p coins be 5x, 9x and 4x respectively.
(5x/2)+( 9x/ 4)+(4x/10)=20650x + 45x + 8x = 41201O3x = 4120 x=40.
Number of 50 p coins = (5 x 40) = 200; Number of 25 p coins = (9 x 40) = 360;
Number of 10 p coins = (4 x 40) = 160.
ANSWER C 160
Answer: (C) 160
Question: The average of 10 numbers is 23. If each number is increased by 4, what will the new average be?
(A) 17
(B) 27
(C) 19
(D) 16
(E) 87
Rationale: Sum of the 10 numbers = 230
If each number is increased by 4, the total increase =
4 * 10 = 40
The new sum = 230 + 40 = 270 The new average = 270/10 = 27.
Answer:B
Answer: (B) 27
Question: Each of the integers from 0 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into a hat. If 5 of the slips are the drawn, without replacement, what is the probability that all 5 have a even number written on it?
(A) 1/252
(B) 1/10
(C) 1/8
(D) 1/2
(E) 5/9
Rationale: Key is that there is no replacement, so each successive choice will become more skewed towards picking a neg (i.e. the pool of positives decreases, while the pool of negatives stay the same)
P(+ on 1st pick) = 5/10
P(+ on 2nd pick) = 4/9
P(+ on 3rd pick) = 3/8
P(+ on 4rd pick) = 2/7
P(+ on 5rd pick) = 1/6
5/10*4/9*3/8*2/7*1/6=1/252
A
Answer: (A) 1/252
Question: The ratio of the volumes of two cubes is 729 : 1331. What is the ratio of their total surface areas?
(A) 81 : 121
(B) 81 : 128
(C) 81 : 120
(D) 81 : 125
(E) 81 : 122
Rationale: Ratio of the sides = 3√729 : 3√1331 = 9 : 11
Ratio of surface areas = 92 : 112 = 81 : 121
Answer: A
Answer: (A) 81 : 121
Question: Foodmart customers regularly buy at least one of the following products: milk, chicken, or apples. 60% of shoppers buy milk, 50% buy chicken, and 35% buy apples. If 15% of the customers buy all 3 products, what percentage of Foodmart customers purchase exactly 2 of the products listed above?
(A) 5%
(B) 10%
(C) 15%
(D) 25%
(E) 30%
Rationale: 60-(x+15+z) + 50-(x+15+y) + 35-(z+15+y) + x + +y + z +15 = 100
where x = people who bought MilkChicken
y = people who bought chickenApples
z= people who bought Milk and Apples
x+y+z= the number of people who bought just exactly two products.
Hence solving the above equation we get,
115 -(x+y+z) = 100
Thus, x+y+z= 15
Answer: C
Answer: (C) 15%
Question: Ayesha’s father was 38 years of age when she was born while her mother was 34 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
(A) 2 years
(B) 4 years
(C) 6 years
(D) 8 years
(E) None
Rationale: EXPLANATION
Mother’s age when Ayesha’s brother was born = 34 years.
Father’s age when Ayesha’s brother was born = (38 + 4) years = 42 years.
Required difference = (42 – 34) years = 8 years.
Answer D
Answer: (D) 8 years
Question: The ratio of boarders to day students at a school was originally 2 to 5. However, after a number of new boarders join the initial 60 boarders, the ratio changed to 1 to 2. If no boarders became day students and vice versa, and no students left the school, how many new boarders joined the school?
(A) 12
(B) 15
(C) 20
(D) 24
(E) 30
Rationale: Let x be the number of new boarders.
The ratio changed from 2:5 = 4:10 up to 1:2 = 5:10.
60 / (60+x) = 4/5
x = 15
The answer is B.
Answer: (B) 15
Question: Julie put half of her savings in a savings account that pays an annual simple interest and half in a savings account that pays an annual compound interest. After two years she earned $100 and $105 from the simple interest account and the compound interest account respectively. If the interest rates for both accounts were the same, what was the amount of Julie's initial savings?
(A) 600
(B) 720
(C) 1000
(D) 1200
(E) 1440
Rationale: $100 for 2 years = $50 per year.
Extra $5 yearned with the compound interest is the percent yearned on percent. So, $5 is yearned on $50, which means that the interest = 10%.
This on the other hand means that half of the savings = 50*10 = $500. Twice of that = $1,000.
Answer: C.
Answer: (C) 1000
Question: The cost price of a radio is Rs.1500 and it was sold for Rs.1305, find the loss %?
(A) 13%
(B) 16%
(C) 17%
(D) 78%
(E) 28%
Rationale: 1500 ---- 195
100 ---- ? => 13%
Answer:A
Answer: (A) 13%
Question: Solve below question 2x + 1 = -19
(A) -8
(B) -9
(C) 9
(D) 8
(E) -10
Rationale: 2x + 1 = -19
x = -10
E
Answer: (E) -10
Question: Tom invested Rs. 15000 @ 8% per annum for two years. If the interest is compounded half-yearly, then the amount received by Tom at the end of the year will be?
(A) 17,546.75
(B) 17,547.40
(C) 17,547.88
(D) 17,548.32
(E) 17,548.80
Rationale: P = Rs. 15000; R = 8% p.a. = 4% per half-year; T = 2 years = 4 half-year
Amount = [15000 * (1 + 4/100)4]
= (15000 * (1.04)4) = Rs. 17547.88
Answer: C
Answer: (C) 17,547.88
Question: A certain scholarship committee awarded scholarships in the amounts of $1250, $2500 and $4000. The Committee awarded twice as many $2500 scholarships as $4000 and it awarded three times as many $1250 scholarships as $2500 scholarships. If the total of $45000 was awarded in $1250 scholarships, how many $4000 scholarships were awarded?
(A) 5
(B) 6
(C) 9
(D) 10
(E) 15
Rationale: Since the starting point is given as the $4000 scholarship,
Assume $4000 scholarships to be x
By the given information, $2500 scholarships = 2x
and $1250 scholarships = 6x
Gievn: Total $1250 scholarships = $45000
6x*1250 = 45000
Solve for x = 6
Option B
Answer: (B) 6
Question: There are 9 points marked on the circumference of a circle. How many hexagons can be formed by connecting 6 points of the 9 points?
(A) 84
(B) 86
(C) 88
(D) 90
(E) 92
Rationale: 9C6=84
The answer is A.
Answer: (A) 84
Question: To prepare cake of type A, it requires 4 eggs. While to prepare cake of type B, it requires 6 eggs. If there are 30 eggs available, and at least one cake of each type needs to be prepared, maximum how many cakes can be prepared of type B?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: If a number of type A cakes are prepared, and b number of type B cakes are prepared. Based on total number of eggs used, 4a + 6b = 30.
=> 6b = 30 - 4a
=> b = 5 - (4/6)a = 5 - (2/3)a
To maximize b, we have to minimize a, and a has to be a multiple of 3. Also, since at least one cake of each type is to be prepared, a >= 1.
=> a = 3.
b = 5 - (2/3)3 = 3.
Answer: C
Answer: (C) 3
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
(A) 16
(B) 11
(C) 36
(D) 17
(E) 12
Rationale: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec.
Answer:C
Answer: (C) 36