mathewhe/aqua_rat huggingface dataset:
Question: A company, Chauncy Co., has an annual travel budget of $60,000. The accounting department estimates that transportation expenses will increase 5 percent in the coming year, and nontransportation travel expenses will increase by 15 percent in the coming year. Last year, Chauncy Co. spent $19,500 on transportation-related expenses, and $35,000 on nontransportation travel expenses. If the annual travel budget does not increase this year, and if the accounting department’s estimates are correct, how far over the annual travel budget will expenses be this year?
(A) Expenses will not go over the budget.
(B) $725
(C) $4,225
(D) $5,725
(E) $60,725
Rationale: annual travel budget of $60,000
Let, Transportation expenses = T = 19500
and Non-Transportation expenses = N=35000
i.e. Increased Transportation expenses = 1.05T = 20475
and Increased Non-Transportation expenses = 1.15N = 40250
Total Expense = 20475+40250 = 60725
Expense over Budget = Budget - expense = 60000-60725 = 725
Answer: Option B
Answer: (B) $725
Question: A man bets on no. 16 on a roulette wheel 14 times and losses each time. On the 15th span he does a quick calculation and finds out that the no. 12 had appeared twice in the 14 spans and is therefore, unable to decide whether to bet on 16 or 12 in the 15th span. Which will give him the best chance and what are the odds of winning on the bet that he takes?
(A) 32:2
(B) 35:1
(C) 33:4
(D) 36:23
(E) 35:27
Rationale: Each of the span is an independent event and the outcome of the 15th span will not depend on the outcome of the earlier spans.
Either ;35:1
B)
Answer: (B) 35:1
Question: If abc = 1 , cde = 0 , and xyu = 0, which of the following must be zero?
(A) E
(B) D
(C) C
(D) B
(E) A
Rationale: abc = 1 which means neither a / b/ c is 0
c x de = 0 , we know c is not 0 from above hence either d or e must be 0.
d x a x c = 0, we know from first expression that a and c are not 0 hence d =0.
OPTION B
Answer: (B) D
Question: The dimensions of an open box are 52, 40 and 29 cms. Its thickness is 2 cms. If 1 cm3 of metal used in the box weighs 0.5 gms, the weight of the box is?
(A) 6.882 kg
(B) 6.932 kg
(C) 8.832 kg
(D) 6.832 kg
(E) 3.832 kg
Rationale: 52 * 40 * 29 = 60320
48 * 36 * 27 = 46650
------------
13664
13664 * 1/2 = 6832 => 6.832 kg
Answer: D
Answer: (D) 6.832 kg
Question: The perimeter of a triangle is 32 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle?
(A) 76
(B) 88
(C) 66
(D) 55
(E) 40
Rationale: Area of a triangle = r * s
Where r is the in radius and s is the semi perimeter of the triangle.
Area of triangle = 2.5 * 32/2 = 40 cm2
Answer:E
Answer: (E) 40
Question: The radius of a semi circle is 6.83 cm then its perimeter is?
(A) 32.52
(B) 32.47
(C) 34.97
(D) 32.92
(E) 32.33
Rationale: 36/7 r = 6.3 = 34.97
Answer:C
Answer: (C) 34.97
Question: There are 8 men and 10 women and you need to form a committee of 5 men and 6 women. In how many ways can the committee be formed?
(A) 10240
(B) 11
(C) 11760
(D) 812
(E) None of these
Rationale: We need to select 5 men from 8 men and 6 women from 10 women
Number of ways to do this
= 8C5 × 10C6
= 8C3 × 10C4 [∵ nCr = nC(n-r)]
=(8×7×6 / 3×2×1) (10×9×8×7 / 4×3×2×1)
=56×210=11760
Answer : C
Answer: (C) 11760
Question: There are 36 students in a certain geometry class. If one third of the students are boys and three fourths of the boys are under six feet tall, how many boys in the class are under six feet tall?
(A) 9
(B) 12
(C) 18
(D) 24
(E) 27
Rationale: Total Students = 36
One third of the students are boys = 1/3*36 = 12
Three fourths of the boys are under six feet tall = 3/4*12 = 9 ...
Therefore Number of boys in the class under six feet tall = 9 ... Answer A....
Alternatively... Number of boys in the class under six feet tall = 3/4 of 1/3 of Total Students = 3/4*1/3*36 = 9...
Answer A
Answer: (A) 9
Question: Nil and Ethan are brothers. They left their home
at the same time and drove to the same beach.
Nil drove at a speed of 40 miles per hour. Ethan
drove at a speed of 20 miles per hour. Nil
arrived at the beach 0.5 hour earlier than Ethan.
What is the distance between their home and the
beach?
(A) 30 miles
(B) 40 miles
(C) 50 miles
(D) 60 miles
(E) 70 miles
Rationale: Every hour, Nil gets ahead of Ethan 40 - 20 =
20 miles. When Nil arrived at the beach, Ethan
is only 20 × 0.5 = 10 miles behind. That tells us
they only drove 1 hour when Nil arrived at the
beach.
The distance between their home and the beach
is
Nil’s speed × Nil’s time
= 40 × 1 = 40 miles.
correct answer B
Answer: (B) 40 miles
Question: A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 sec. What is the length of the goods train?
(A) 287 m
(B) 278 m
(C) 276 m
(D) 270 m
(E) 268 m
Rationale: Speed = 72 * 5/18 = 20 m/sec.
Time = 26 sec.
Let the length of the train be x meters.
Then, (x + 250)/26 = 20
x = 270 m.
Answer:D
Answer: (D) 270 m
Question: Rs. 1300 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/8:1/3:1/4?
(A) Rs.224
(B) Rs.216
(C) Rs.100
(D) Rs.300
(E) Rs.400
Rationale: 1/8:1/3:1/4 = 4:8:6
3/18*1300 = 216
ANSWER:B
Answer: (B) Rs.216
Question: 8 men can do a piece of work in 12 days. 4 women can do it in 48 days and 10 children can do it in 24 days. In how many days can 6 men, 4 women and 10 children together complete the piece of work?
(A) 5 days
(B) 15 days
(C) 28 days
(D) 8 days
(E) 7 days
Rationale: Explanation:
1 man’s 1 day’s work = 1/8 × 12 = 1/96
6 men’s 1 day’s work = 1 × 6/96 =1/16
1 woman’s 1 day’s work = 1/192
4 women’s 1 day’s work = 1/192 × 4 = 1/48
1 child’s 1 day’s work = 1/240
10 children’s 1 day’s work = 1/24
Therefore, (6 men + 4 women + 10 children)’s 1 day’s work = 1/16 + 1/48 + 1/24
= 1/8
The required No. of days = 8 days
Answer: Option D
Answer: (D) 8 days
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 51 kmph, find the speed of the stream?
(A) 77
(B) 88
(C) 14
(D) 12
(E) 17
Rationale: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 51/3 = 17 kmph.
Answer:E
Answer: (E) 17
Question: How many digits are in the number 50^8 × 8^3 × 11^2 x 10^4?
(A) 22
(B) 20
(C) 19
(D) 18
(E) 17
Rationale: Whenever you are asked to find the number of digits, try to bring the number in multiples of 10. This way, we can wasily calculate the umber of 0's through the powers of 10
50^8 × 8^3 × 11^2 x 10^4 = (5^2*2)^8*2^9*11^2 *10^4= 5^16*2^17*11^2*10^4 = 2*11^2*10^16*10^4 = 242*10^16 x 10^4
Hence we would have 16 trailing 0's and the three digits from 242
Total digits = 3 + 20 = 23
Correct Option: D
Answer: (D) 18
Question: David was born 5 years after his father's marriage. His mother is 4 years younger than his father but 20 years older than David who is 8 years old. At what age did the father get married ?
(A) 19 years
(B) 20 years
(C) 21 years
(D) 18 years
(E) 17 years
Rationale: Explanation:
David's present age = 8 years.
His mother's present age = (20 + 8) years = 28 years.
His father's present age = (28 + 4) years = 32 years.
His father's age at the time of David's birth = (32 - 8) years = 24 years.
Therefore David's father's age at the time of marriage = (24 - 5) years = 19 years.
Answer: A
Answer: (A) 19 years
Question: A boy multiplied 987 by a certain number and obtained 559981 as his answer. If in the answer both 98 are wrong and the other digits are correct , then the correct answer would be :
(A) 288889
(B) 556677
(C) 555681
(D) 267788
(E) 268811
Rationale: Explanation:
987 = 3 * 7 * 47.
So, the required number must be divisible by each one of 3, 7, 47
553681 => (Sum of digits = 28, not divisible by 3)
555181 => (Sum of digits = 25, not divisible by 3)
555681 is divisible by each one of 3, 7, 47.
Answer: C) 555681
Answer: (C) 555681
Question: In a hotel we can order two types of varieties, but we can make 8 more varieties in home. One can choose the four varieties with two from hotel as must. Find how many ways one can order.
(A) 14
(B) 15
(C) 56
(D) 28
(E) 29
Rationale: 2c2*8c2=28ways
ANSWER:D
Answer: (D) 28
Question: Find the C.I. on a sum of Rs.1600 for 9 months at 20% per annum, interest being compounded quarterly?
(A) 3377
(B) 2889
(C) 2522
(D) 2678
(E) 7111
Rationale: A = 1600(21/20)3 = 2522
Answer: C
Answer: (C) 2522
Question: The spherical ball of lead 3 cm in diameter is melted and recast into 3 spherical balls. The diameters of two of these are 1 1/2 cm and 2 cm respectively. The diameter of third ball is?
(A) 2.8
(B) 2.5
(C) 2.2
(D) 2.0
(E) 2.1
Rationale: 4/3 π * 3 * 3 * 3 = 4/3 π[(3/2)3 + 23 + r3]
r = 1.25
d = 2.5
Answer:B
Answer: (B) 2.5
Question: In climbing a round pole of 80 meters height, a monkey climbs 5 meters in a minute and slips 2
meters in the alternate minute. To get to the top of the pole, the monkey would take :
(A) 51 minutes
(B) 54 minutes
(C) 58 minutes
(D) 61 minutes
(E) 63 minutes
Rationale: a monkey climbs 5 meters in one min & slips 2m in other min.
therefore the monkey reach 3meters in 2min
3m=2min
25*3m=25*2min - >75m=50min
hence the remaining 5m jumps the monkey in 1min to reach original height
so 51 min
ANSWER:A
Answer: (A) 51 minutes
Question: Kim can do a work in 3 days while David can do the same work in 2 days. Both of them finish the work together and get Rs. 150. What is the share of Kim?
(A) 77
(B) 60
(C) 99
(D) 26
(E) 21
Rationale: Kim's wages : David's wages = Kim's 1 day work : David's 1 day work = 1/3 : 1/2 = 2:3
Kim's share = 2/5 * 150 = Rs. 60
Answer: B
Answer: (B) 60
Question: When n is divided by 19, the remainder is 6. When n is divided by 11, the quotient is equal to Z, and the remainder is equal to 6. Z must be divisible by which of the following numbers?
(A) 3
(B) 7
(C) 10
(D) 13
(E) nineteen
Rationale: N = 19 q + 6
N = 11 z + 6
Equating
19 Q + 6 = 11z +6
11z=19q
11z/19 = q
since q is an integer Z must be divisible by 19.
ANSWER:E
Answer: (E) nineteen
Question: On dividing 22 by a number, the quotient is 7 and the remainder is 1. Find the divisor.
(A) 1
(B) 2
(C) 3
(D) 6
(E) 7
Rationale: d = (D-R)/Q
= (22 - 1)/7
= 21/7 = 3
C
Answer: (C) 3
Question: An artist wishes to paint a circular region on a square poster that is 3.4 feet on a side. If the area of the circular region is to be 1/2 the area of the poster, what must be the radius of the circular region in feet?
(A) 1/pi
(B) sqrt(2/pi)
(C) 1
(D) 2/sqrt(pi)
(E) sqrt(5.78/pi)
Rationale: Area of the poster is 3.4x3.4 = 11.56
1/2 the area = 5.78
pi*r^2 = 5.78
r^2 = 5.78/pi
r = sqrt(5.78/pi) answer (E)
Answer: (E) sqrt(5.78/pi)
Question: Quentin's income is 60% less than Dev's income, and Sam's income is 25% less than Quentin's income. If Dev gave 60% of his income to Sam and 40% of his income to Quentin, Quentin's new income would be what fraction of Sam's new income?
(A) 8/9
(B) 11/12
(C) 8/13
(D) 11/13
(E) 12/13
Rationale: We can take some easy numbers and make calculations simpler.
Let R ( Dev's income) = 100
Q (Quentin's income) = 40%R = 40
S (Sam's income) = 75% Q = (3/4)*40 = 30
Now, if Dev gives 40% to Quentin --> Q = 40 + 40 = 80
60% given to Sam --> S = 30+60 = 90
The ratio is : Q/S = 80/90 = 8/9=A
Answer: (A) 8/9
Question: If xy = 5 and x^2 + y^2 = 10, then x/y + y/x =
(A) 2
(B) 3 1/7
(C) 5 1/3
(D) 7
(E) 60
Rationale: We can make simplifying of question and get it in view: (x^2 + y^2) / xy and as we know the meaning of this parts:
x^2 + y^2 = 10
xy = 5
we can calculate the answer 10/5 -> 2 so answer is A
Answer: (A) 2
Question: About the number of pairs which have 18 as their HCF and 136 as their LCM, the conclusion can be
(A) only one such pair exists
(B) only two such pairs exist
(C) such pair is not exists
(D) no pairs
(E) None of these
Rationale: Explanation:
HCF is always a factor of LCM. ie., HCF always divides LCM perfectly.
Correct Option: C
Answer: (C) such pair is not exists
Question: The smallest number which when diminished by 2, is divisible by 12, 16, 18, 21 and 28 is
(A) 1008
(B) 1010
(C) 1022
(D) 1032
(E) 1043
Rationale: Required Number = (L.C.M of 12, 16, 18,21,28)+2
= 1008 + 2
= 1010
Answer: B
Answer: (B) 1010
Question: if QUESTION =DOMESTIC what will b code for RESPONSE ????
(A) OMESUCEM
(B) OMESICSM
(C) OMESICEM
(D) OMESISCM
(E) OMESISCN
Rationale: Q U E S T I O N
D O M E S T I C
we can see in the word'RESPONSE' only R and P are the letters whose code is not given, by having a look on options we can say code for R is O and code for P is S(bcz common in all options).now we can easily code the word 'RESPONSE'as 'OMESICEM'
ANSWER:C
Answer: (C) OMESICEM
Question: Adams, Smith, Derek, Alex and Bob bought movie tickets in one row next to each other. What is the probability that Bob and Adams will each sit next to each other?
(A)  5%
(B)  10%
(C)  15%
(D)  20%
(E)  25%
Rationale: Possible sitting position is 5! = 120
Bob and Adams Sitting next to each other is 5 Combination 2
=5!/2!(5-2)!
=120/2(6)
=120/12
= 10
Answer = B
Answer: (B)  10%
Question: The l ength of a rectangle is halved, while its breadth is tripled. Watis the % change in area?
(A) 30%
(B) 40%
(C) 50percent
(D) 60%
(E) 70%
Rationale: Let original length = x and origina l breadth = y.
Original area = xy.
New length = x .
2
New breadth = 3y.
New area = x x 3y = 3 xy.
2 2
Increase % = 1 xy x 1 x 100 % = 50%.
2 xy
C
Answer: (C) 50percent
Question: A certain boxer has agreed to pay his opponent a fee of 2.5% of his total purse for every pound over the specified weight limit he weighs in. If the boxer pays his opponent a fee of $225,000 after weighing in seven pounds over the specified limit, what was the boxer's purse?
(A) $65,625
(B) $105,000
(C) $150,000
(D) $183,750
(E) $1,285,714
Rationale: .025*7 = .175
225000/.175 = $1,285,714
Answer: E
Answer: (E) $1,285,714
Question: Calculate how many days it will take for 10 boys to paint a 80 m long wall if 6 boys can paint a 70 m long wall in 8 days,
(A) 9.48 days
(B) 3.48 days
(C) 7.48 days
(D) 5.48 days
(E) 6.48 days
Rationale: The length of wall painted by one boy in one day = 70 / 6 * 1/8 = 1.46 m
No. of days required to paint 50 m cloth by 8 boys = 80/ 10 *1/ 1.46 = 5.48 days.
D
Answer: (D) 5.48 days
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 6 per square feet if there is one door of dimensions 6 feet * 3 feet and three WINDOWS of dimensions 4 feet * 3 feet each?
(A) 4000
(B) 345
(C) 5436
(D) 4530
(E) 4566
Rationale: Area of the four walls = 2h(l + b)
Since there are doors and WINDOWS, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 6 = Rs. 5436
Answer: Option C
Answer: (C) 5436
Question: A, B and C, each working alone can complete a job in 6, 8 and 12days respectively. If all three of them work together to complete a job and earn $2500, what will be C's share of the earnings?
(A) $1200
(B) $1005.8
(C) $555.6
(D) $1009.2
(E) $1490.7
Rationale: The dollars earned will be in the same ratio as amount of work done
1 day work of C is 1/12 (or 2/24)
1 day work of the combined workforce is (1/6 + 1/8 + 1/12) = 9/24
C's contribution is 2/9 of the combined effort
Translating effort to $ = 2/9 * 2500 = $555.6
Answer: (C) $555.6
Question: A boy was asked to multiply a number by 22. He instead multiplied the number by 44 and got the answer 308 more than the correct answer. What was the number to be multiplied?
(A) 16
(B) 10
(C) 14
(D) 12
(E) 8
Rationale: Explanation :
Let the number be x
22x + 308 = 44x
=> 44x - 22x = 308
=> 22x = 308
=> x = 308/22 = 154/11 = 14
Answer : C
Answer: (C) 14
Question: 5292 can be expressed as a product of primes as
(A) 2 × 2 × 3 × 3 × 7 × 7
(B) 2 × 3 × 3 × 3 × 7 × 7
(C) 2 × 2 × 2 × 3 × 3 × 7
(D) 2 × 3 × 3 × 3 × 3 × 7
(E) 2 x 2 x 3 x 3 x 3 x 7 x 7
Rationale: Explanation:
It is clear that 5292 = 2 x 2 x 3 x 3 x 3 x 7 x 7
Answer: Option E
Answer: (E) 2 x 2 x 3 x 3 x 3 x 7 x 7
Question: If a, b, c are consecutive positive integers and a<b<c, which of the following must be true?
I. c-b=1
II. abc is an even integer
III. (a+b+c)/3 is an integer
(A) I, II & III
(B) II
(C) I and II
(D) II and III
(E) I
Rationale: 1. c-b=1 --> a, b, c are consequitive positive integers and a<b<c then c=b+1 --> c-b=1. So this statement is always true;
2. abc is an even integer --> out of any 3 consecutive integers at least one must be even thus abc=even. So this statement is also always true;
3. (a+b+c)/3 is an integer --> the sum of odd number of consecutive integers is ALWAYS divisible by that odd number. So this statement is also always true. Or: (a+b+c)/3=(a+a+1+a+2)/3=(3a+3)/3=a+1=integer.
Answer: A.
Answer: (A) I, II & III
Question: The amount of water (in ml) that should be added to reduce 9 ml. Lotion, containing 50% alcohol, to a lotion containing 15% alcohol, is?
(A) 21
(B) 24
(C) 25
(D) 26
(E) 27
Rationale: 4.5 4.5
15% 85%
15% ----- 4.5
85% ------? => 25.5 - 4.5 = 21 ml
ANSWER:A
Answer: (A) 21
Question: A number when successively divided by 3,5 and 8 leaves remainders 1,4 and 7 respectively. Find the respective remainders R when the order of the divisors is reversed.
(A) 8,5,3
(B) R=4,2,1
(C) R=3,2,1
(D) R=6,4,2
(E) None of above
Rationale: My approach would be
Three Divisors : 3, 5, 8
Three Remain: 1, 4, 7
Start from the bottom of the last column i.e. from the third remainder:
Go up diagonally and multiply by the second divisor: 5*7 = 35
Go down and add the second remainder: 35 + 4 = 39
Go up diagonally and multiply by the first divisor: 39* 3 = 117
Go down and add the first remainder: 117 + 1 = 118
Divide 118 by 8, 5, 3
118/8 gives quotient = 14 and remainder = 6
14/5 gives quotient = 2 and remainder = 4
2/3 gives quotient = 0 and remainder = 2
Ans is D i.e. 6,4,2
Answer: (D) R=6,4,2
Question: A question paper has 2parts, A & B, each containing 10 questions. If a student has to choose 8 from part A &5 from part B, in how many ways can he choose the questions?
(A) 1000
(B) 1040
(C) 1050
(D) 1100
(E) 1140
Rationale: There 10 questions in part A out of which 8 question can be chosen as = 10C8.
Similarly, 5 questions can be chosen from 10 questions of Part B as = 10C5.
Hence, total number of ways,
=10C8*10C5
=[10!/(2!8!)]*[10!/(5!*5)]
= {10*9/2}*{10*9*8*7*6/(5*4*3*2*1)}
= 1140.
E
Answer: (E) 1140
Question: A car driver travels from the plains to the hill station, which are 200 km apart at an average speed of 30km/hr. in return trip, he covers the same distance at an average speed of 20km/hr. the average speed of the car over the entire distance of 400 km is
(A) 8.95km/hr
(B) 24.0km/hr
(C) 27.8km/hr
(D) 37.9km/hr
(E) 8.45km/hr
Rationale: average speed = (2*30*20)/30+20 km/hr
=24 km/hr
Answer (B)
Answer: (B) 24.0km/hr
Question: A rower can row upstream at 18 kph and downstream at 34 kph. What is the speed of the rower in still water?
(A) 24
(B) 25
(C) 26
(D) 27
(E) 28
Rationale: Let V be the rower's speed in still water.
Let S be the speed of the current in the stream
V-S = 18
V+S = 34
When we add the two equations, we get: 2V = 52
Then V = 26 kph.
The answer is C.
Answer: (C) 26
Question: The average of 15 numbers is 15. If the average of first five numbers is 14 and that of other 9 numbers is 16, then find the middle number.
(A) 12
(B) 11
(C) 10
(D) 9
(E) 8
Rationale: Given: Average of 15 numbers = 15, Average of 5 numbers = 14, Average of 9 numbers = 16
Average =	Total Numbers/No. of Numbers
15 =	Total Numbers/15
Therefore, total numbers = 15 x 15 = 225
Middle number = (Total numbers) – [(Average of 5 num x no of num) + ( Average of 9 num x no of num)]
= (225) – [(14 x 5) + (16 x 9)]
= (225) – [214]
= 11
Therefore, the middle number is 11
ANSWER IS B
Answer: (B) 11
Question: Mary's income is 60% more Than Tim's income and Tim's income is 60% less than Juan's income.What % of Juan's income is Mary's income.
(A) 124%
(B) B.120%
(C) 64%
(D) 80%
(E) 64%
Rationale: Even I got 96%
J = 100
T = 100*0.4 = 40
M = 40*1.6 = 64
If Mary's income is x percent of J
M = J*x/100
x = M*100/J = 64*100/100 = 64
Ans:C
Answer: (C) 64%
Question: A 470 m long train is running at a speed of 55 Km/hr. It crossed a platform of length 520 m in ?
(A) 41.1 sec
(B) 64.8 sec
(C) 31.8 sec
(D) 50.4 sec
(E) none of the above
Rationale: Speed = 55 Km/hr
(to convert km/hr in to M/s)
= 55 x 5/18 M/s
Distance = 470 m + 520 m ( If questions is about train crossing a post you need to consider only the length of Train, )
= 990 m
Time = Distance / Speed
= 990 x 18 / (5 x 55)
= 64.8 sec
Ans is :B
Answer: (B) 64.8 sec
Question: A person spent Rs. 5,040 from his salary on food and 5,000 on house rent. After that he was left with 20% of his monthly salary. What is his monthly salary ?
(A) 22,550
(B) 32,550
(C) 52,550
(D) 62,550
(E) 12,550
Rationale: Total money spent on food and house rent = 5,040+5,000 = 10,040
Which is 100 - 20 = 80% of his monthly salary
∴ His salary = 10040x100/80 = 12550
Answer : E
Answer: (E) 12,550
Question: A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 59.29, the number of the member is the group is:
(A) 57
(B) 67
(C) 77
(D) 87
(E) 97
Rationale: Money collected = (59.29 x 100) paise = 5929 paise.
Number of members = 5929 = 77.
Answer: Option C
Answer: (C) 77
Question: A and B together can complete work in 8 days. A alone starts working and leaves it after working for 6 days completing only half of the work. In how many days it can be completed if the remaining job is undertaken by B?
(A) 4
(B) 8
(C) 5
(D) 12
(E) 7
Rationale: Explanation:
(A+B) one day work =1/8
now A does half of the work in 6 day so A can complete the whole work in 12 days
A’s one day work =1/12
B’s one day work=1/8 - 1/12= 1/24
B alone can complete the work in 24 days so half of the work in 12 days
Answer: Option D
Answer: (D) 12
Question: When all the students in a school are made to stand in rows of 46, 36 such rows are formed. If the students are made to stand in rows of 42, how many such rows will be formed ?
(A) 31
(B) 36
(C) 38
(D) 39
(E) 21
Rationale: Explanation:
Total number of students = 46 x 36
When arranged in rows of 42, number of rows formed are,
= 39.
Answer: D
Answer: (D) 39
Question: Complete the series 20, 19, 17, ...., 10, 5
(A) 15
(B) 16
(C) 13
(D) 14
(E) 12
Rationale: Explanation :
20 - 1 = 19
19 - 2 = 17
17 - 3 = 14
14 - 4 = 10
10 - 5 = 5
Answer : Option D
Answer: (D) 14
Question: Find the number which when increased by 11 is equal to 60 times the reciprocal of the number
(A) 4
(B) 5
(C) 6
(D) 7
(E) 9
Rationale: Let the number be x.
A positive number (x) increased by 11 is equal to 60 times the reciprocal of the number (1/x)
x + 11 =	60
x
x2+11x-60=0
x2+15x-4x-60=0
x(x+15)-4(x+15)=0
(x+15)(x-4)=0
x = 4
The positive number (x) = 4
A
Answer: (A) 4
Question: If 15 students in a class average 75% on an exam and 10 students average 95% on the same exam, what is the average in percent for all 25 students?
(A) 81%
(B) 82%
(C) 83%
(D) 84%
(E) 85%
Rationale: (15*75 + 10*95) / 25 = 83%
The answer is C.
Answer: (C) 83%
Question: If v, w, x, y, and z are five different prime numbers, which of the following is the smallest possible value of v + w + x + y + z?
(A) 24
(B) 26
(C) 28
(D) 30
(E) 32
Rationale: The sum of the five small smallest primes numbers is 2+3+5+7+11=28.
The answer is C.
Answer: (C) 28
Question: If Finn was 20 months old one year ago, how old was he, in months, x months ago?
(A) x − 30
(B) x − 12
(C) 32 − x
(D) 24 − x
(E) 30 − x
Rationale: Age Today = 20 months + 12 months (1year) = 32 months
X months ago- Today's Age - X = 32 - X
Ans- C
Answer: (C) 32 − x
Question: A man has Rs. 520 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
(A) 97.5
(B) 60
(C) 75
(D) 90
(E) 105
Rationale: Let number of notes of each denomination be x.
Then x + 5x + 10x = 520
16x = 520
x = 32.5.
Hence, total number of notes = 3x = 97.5.
Answer = A
Answer: (A) 97.5
Question: At what rate percent per annum will a sum of money double in 5 years.
(A) 20.0%
(B) 13.5%
(C) 11.5%
(D) 14.5%
(E) 21.5%
Rationale: Let principal = P, Then, S.I.=P and Time=8 years
Rate = [(100 x P)/ (P x 5)]% = 20.0% per annum. Answer: A
Answer: (A) 20.0%