mathewhe/aqua_rat huggingface dataset:
Question: The average age 7 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
(A) 14 years
(B) 17 years
(C) 18 years
(D) 12 years
(E) 11 years
Rationale: 7 * 2
= 14
Answer:A
Answer: (A) 14 years
Question: If n = 2cd, where c and d are distinct prime numbers greater than 2, how many different positive even divisors does n have, including n ?
(A)  Two
(B)  Three
(C)  Four
(D)  Six
(E)  Eight
Rationale: Answer - 'C' - Four.
For a number 2cd with primes cd,there will be four even divisors - 2,2*c,2*d,2*c*d
Answer: (C)  Four
Question: Mike needs 30% to pass. If he scored 212 marks and falls short by 13 marks, what was the maximum marks he could have got?
(A) 343
(B) 377
(C) 750
(D) 367
(E) 232
Rationale: If Mike had scored 13 marks more, he could have scored 30%
Therefore, Mike required 212 + 13 = 225 marks
Let the maximum marks be m.
Then 30 % of m = 225
(30/100) × m = 225
m = (225 × 100)/30
m = 22500/30
m = 750
Answer:C
Answer: (C) 750
Question: Pankajam bought an electric drill at 80% of the regular price.
She paid $32.80 for the drill. What was the regular price?
(A) $28.69
(B) $18.69
(C) $38.69
(D) $58.69
(E) $41.00
Rationale: Regular price = 32.80/80*100 = 41
Answer : E
Answer: (E) $41.00
Question: What is the lowest possible common multiple M of 2 distinct integers, each greater than 329?
(A) 330·331
(B) 330^2
(C) 33·331
(D) 660
(E) 330
Rationale: Lowest possible common multiple M of 2 distinct integers will have to be multiple of the number greater than 329...which 330..
so one number will be 330...another one will be 660..
Ans is D.
Answer: (D) 660
Question: A cubical block of metal weighs 5 pounds. How much will another cube of the same metal weigh if its sides are twice as long?
(A) 48
(B) 40
(C) 24
(D) 18
(E) 12
Rationale: For example our cube have a side 1 meter, so we have 1 cubical meter in this cube
and this cubical meter weigth 5 pounds
If we take cube with side 2 meters we will have 8 cubical meters in this cube
8 meters * 5 pounds = 40 pounds
So answer is B
And similar but more theoretical approach:
if we have sides a and b than they have equal ration with their areas:
a/b = a^2/b^2
and they have equal ration with their volumes:
a/b = a^3/b^3
we have two sides 1/2 so their volume will be in ratio 1/8
weight of one cube * volume of another cube
5 * 8 = 40
So answer is B
Answer: (B) 40
Question: Marla starts running around a circular track at the same time Nick starts walking around the same circular track. Marla completes 20 laps around the track per hour and Nick completes 10 laps around the track per hour. How many minutes after Marla and Nick begin moving will Marla have completed 4 more laps around the track than Nick?
(A) 5
(B) 8
(C) 24
(D) 15
(E) 20
Rationale: Maria's rate - 20 laps per hour --> 20/60 laps/min
Nick's rate - 10 laps per hour --> 10/60 laps/min
lets set equations:
20/60*t=4 (since Maria had to run 4 laps before Nick would start)
10/60*t=0 (Hick has just started and hasn't run any lap yet)
(20/60-10/60)*t=4-0 (since Nick was chasing Maria)
t=24 min needed Maria to run 4 laps
Answer : C
Answer: (C) 24
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
(A) 200 m
(B) 225 m
(C) 245 m
(D) 250 m
(E) 240 m
Rationale: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.
ANSWER:C
Answer: (C) 245 m
Question: What will come in place of (a) in the following expression?
a - 796.21 + 498.05 = 215.50 – 425.01
(A) 88.65
(B) 88.6
(C) 88.67
(D) 83.65
(E) 88.61
Rationale: Explanation:
a - 796.21 + 498.05 = 215.50 - 425.01
a = 88.65
ANSWER: A
Answer: (A) 88.65
Question: There are 30 socks in a drawer. 60% of the socks are red and the rest are blue. What is the minimum number of socks that must be taken from the drawer without looking in order to be certain that at least two socks of the same colour have been chosen?
(A) 2
(B) 3
(C) 14
(D) 16
(E) 20
Rationale: 60% of 30 = 18.
So, there are 18 red socks and there are 12 blue socks.
Check out this possible cases once we have selected TWO socks:
case a: 2 red socks, in which case we have a pair of matching socks. DONE!
case b: 2 blue socks, in which case we have a pair of matching socks. DONE!
case c: 1 red sock and 1 blue sock. No matching socks, so we're not done yet.
Since the first 2 cases result in a pair of matching socks, let's focus on case 3 and what happens when we select a 3rd sock.
If we have 1 red sock and 1 blue sock, then the next sock we select will EITHER match the red sock OR match the blue sock.
In both cases, we are guaranteed to have a pair of matching socks.
So, selecting 3 socks guarantees that we have a pair of matching socks.
ANSWER:B
Answer: (B) 3
Question: The inverse ratio of 3: 7: 1 is?
(A) 2:3:7
(B) 2:3:9
(C) 2:3:2
(D) 2:3:6
(E) 2:3:1
Rationale: 1/3: 1/7: 1/1 = 7:3:21
Answer:E
Answer: (E) 2:3:1
Question: The simple form of the ratio 4/3:4/5 is?
(A) 10:6
(B) 10:3
(C) 15:3
(D) 5:3
(E) 30:3
Rationale: 4/3 : 4/5 = 20:12 = 5:3
ANSWER:D
Answer: (D) 5:3
Question: Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 40 kilometers, Maxwell's walking speed is 3 km/h, and Brad's running speed is 5 km/h. What is the distance traveled by Maxwell when they meet in the middle?
(A) 16
(B) 17
(C) 18
(D) 15
(E) 14
Rationale: Consider Max starts from Point A and Brad Starts from Point B and move towards each other.
Assume they shall meet at point O after Time 'T'. The question asks us to find OA.
From the question stem we can make out :- Distance OA = 50km - Distance OB
=> 3xT = 40 - 5xT (i.e distance =Speed x Time)
=> 8T = 40
Hence T = 5
OA = 3 x 5 = 15 Km
Answer : D
Answer: (D) 15
Question: the average of four consecutive even numbers is 27. find the largest of thesenumbers?
(A) 24
(B) 26
(C) 28
(D) 30
(E) 32
Rationale: let the numbers be x,x+2,x+4 andx+6. then,
(x+(x+2)+(x+4)+(x+6))/4) = 27
(4x+12)/4 = 27
x+3=27  x=24.
Therefore the largest number=(x+6)=24+6=30.
ANSWER D 30
Answer: (D) 30
Question: There are 200 female managers in a certain company. Find the total number of female employees Q in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers.
(A) Q=300
(B) Q=400
(C) Q=500
(D) Q=600
(E) None of these
Rationale: {Managers} = {Female Managers} + {Male Managers};
We are told that the total number of managers in the company is 2/5 of all the employees , thus{Managers} = 2/5 (M + F), where M and F are number of female and male employees, respectively.
Also, we know that 2/5 of all male employees are managers:{Male Managers} = 2/5 * Mas well as there are total of 200 female managers:{Female Managers} = 200;
Thus:2/5 (M + F) = 200 + 2/5 * M-->F = 500.
Answer: C.
Answer: (C) Q=500
Question: The first half of a 500-mile trip was travelled in x hours and the second half in y hours. Which of the following is equal	to the average speed, in miles per hour, for the entire trip?
(A) 250/(x + y)
(B) 500/(x + y)
(C) 50/x + 50/y
(D) 250/x + 250/y
(E) 500/x + 500/y
Rationale: Time taken to cover first half i.e 250 miles of a 500 mile trip = x
time taken to cover the second half i.e 250 miles of a 500 mile trip = y
Total time taken = x+y
Average speed for the entire trip =total distance /total time
=500/(x+y)
Answer B
Answer: (B) 500/(x + y)
Question: A train 440 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
(A) 72 sec
(B) 24 sec
(C) 44 sec
(D) 62 sec
(E) 21 sec
Rationale: Speed of train relative to man
= (60 + 6) km/hr
= 66 km/hr
[66 * 5/18] m/sec
= [55/3] m/sec.
Time taken to pass the man
= [440 * 3/55] sec
= 8 sec
Answer:B
Answer: (B) 24 sec
Question: Jack rode his bicycle at an average speed of 5 mph for some time and then at an average speed of 15 mph for the rest of the journey. If he made no stops during the trip, and his average speed for the entire journey was 10 miles per hour, for what fraction of the total time did he ride at 15 mph?
(A)  1/5
(B)  1/3
(C)  2/3
(D)  2/5
(E)  1/2
Rationale: We don't need to get into calculations for solving this question. We can use the concept of weighted averages.
The average speed for the entire journey is 10 mph; so, he rode at 5 mph and 15 mph for an equal duration of time.
Difference is 5 and 5, respectively.
5----10----15
This shows that you can divide the entire journey into 2 equal parts. Thus, 1/2 of the journey he rode at 10 mph, and 1/2 of the journey he rode at 15 mph.
Answer: E
Answer: (E)  1/2
Question: In a game of billiards, A can give B 10 points in 30 and he can give C 15 points in 30. How many points can B give C in a game of 50?
(A) 12.5
(B) 25
(C) 20
(D) 22
(E) 23
Rationale: A scores 30 while B score 20 and C scores 15
The number of points that C scores when B scores 50 = (50 * 15)/20 = 37.5
In a game of 50 points, B gives (50 - 37.5) = 12.5 points to C
Answer : A
Answer: (A) 12.5
Question: Which of the following numbers completes
the sequence 8, 14, 21, 29, 38___?
(A) 35
(B) 36
(C) 37
(D) 48
(E) 69
Rationale: The numbers increase at a somewhat steady rate, so you have to figure out how much
you have to add to each number to produce the next in the sequence: 8 + 6 = 14;
14 + 7 = 21; 21 + 8 = 29, 29 + 9 = 38 and so on. The rule for the sequence is to add successively larger
numbers to each number; therefore, the next number is 38 + 10 = 48
correct answer D)48
Answer: (D) 48
Question: Sachin is younger than Rahul by 4 years. If their ages are in the respective ratio of 7:9, how old is Sachin?
(A) 16 years
(B) 18 years
(C) 28 years
(D) Cannot be determined
(E) None of these
Rationale: Let Rahul's age be x years.
Then, Sachin's age = (x - 7) years.
(x - 7)/x = 7/9
2x = 63 => x = 31.5
Hence, Sachin's age = (x - 7) = 24.5 years.
ANSWER:E
Answer: (E) None of these
Question: If A=x^3 y^2 and B=xy^3, then find the HCF of A, B
(A) x*y^3
(B) x*y^1
(C) x*y^2
(D) x*y^4
(E) x*y^5
Rationale: A=x^3*y^2
=x*x*x*y*y
B=x*y^3
=x*y*y*y
HCF=comman terms from both A & B
=x*y*y
=x*y^2
ANSWER:C
Answer: (C) x*y^2
Question: The perimeter of a semi circle is 144 cm then the radius is?
(A) 87
(B) 28 cm
(C) 26
(D) 27
(E) 25
Rationale: 36/7
r = 144
=> r = 28
Answer: B
Answer: (B) 28 cm
Question: How many workers are required for completing the construction work in 10 days?
I.20% of the work can be completed by 8 workers in 8 days.
II.20 workers can complete the work in 16 days.
III.One-eighth of the work can be completed by 8 workers in 5 days.
(A) I only
(B) II and III only
(C) III only
(D) I and III only
(E) Any one of the three
Rationale: EXPLANATION
I.20/100 work can be completed by (8 x 8) workers in 1 day.
⇒Whole work can be completed by (8 x 8 x 5) workers in 1 day.
⇒8x8x5/10 workers in 10 days = 32 workers in 10 days.
II. (20 x 16) workers can finish it in 1 day.
⇒(20 x 16)/10workers can finish it in 10 days.
⇒32 workers can finish it in 10 days.
III.1/8 work can be completed by (8 x 5) workers in 1 day.
⇒Whole work can be completed by (8 x 5 x 8) workers in 1 day.
⇒8x5x8/10 workers in 10 days = 32 workers in 10 days.
Any one of the three gives the answer.
Answer E
Answer: (E) Any one of the three
Question: A sells a bicycle to B and makes a profit of 35%. B sells the same bicycle to C at a profit of 45%. If the final S.P. of the bicycle was Rs. 225, find out the cost price of the bicycle for A.
(A) 237
(B) 126
(C) 971
(D) 611
(E) 115
Rationale: Explanation:
Let CP be 100
A sells at 35% profit so SP=135
B sells at 45% profit = 135 x (1+45/100) = 195.75
CP SP
100--- 195.75
x --- 225
CP = 225 x 100/195.75 = 114.94
ANSWER: E
Answer: (E) 115
Question: A 30% loss on cost price is what percent loss on selling price?
(A) 30%
(B) 20%
(C) 15%
(D) 25%
(E) 40%
Rationale: Let CP = 100 ; SP=70
Loss= 30/70 × 100 = 42.85%
Answer: D
Answer: (D) 25%
Question: How many odd three-digit integers greater than 300 are there such that all their digits are different?
(A) 40
(B) 156
(C) 172
(D) 181
(E) 240
Rationale: 6 (hundred's digit) * 9 (ten's digit) * 8 (unit's digit) = 432
Now take numbers in the range 300 - 900.
Total numbers where all digits are different = 432 (as before)
[highlight]Number of odd numbers = 6 * 8 * 5 = 240[/highlight] (now there are 5 possibilities for the unit's digit)
E
Answer: (E) 240
Question: In a certain supermarket, a triangular display of cans is arranged in 10 rows, numbered 1 through 10 from top to bottom. Each successively numbered row contains 3 more cans than the row immediately above it. If there are fewer than 150 cans in the entire display, how many cans are in the sixth row?
(A) 14
(B) 16
(C) 18
(D) 20
(E) 22
Rationale: Let x be the number of cans in row 1.
The total number of cans is x + (x+3) + ... + (x+27) =
10x + 3(1+2+...+9) =
10x + 3(9)(10)/2 =
10x + 135
Since the total is less than 150, x must equal 1.
The number of cans in the 6th row is 1 + 3(5) = 16
The answer is B.
Answer: (B) 16
Question: Peter rolls two dice at the same time. What is the probability that either of the dices show either 1 or 5?
(A) a) 1/12
(B) b) 1/18
(C) c) 1/6
(D) d) 5/12
(E) e) 1/3
Rationale: We can have 6 different outcomes on a dice.
Total outcomes on two dices = 6*6
We need only the cases when Peter rolls a double, that means only the outcomes in which the numbers on both the dices are same
They can be {1, 5}, {5, 1}.
A total of 2 outcomes
Probability = favorable outcomes/ total outcomes = 2/36 = 1/18.
Option B
Answer: (B) b) 1/18
Question: 40 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is 4m3 , then the rise in the water level in the tank will be:
(A) 25 cm
(B) 20 cm
(C) 35 cm
(D) 50 cm
(E) None of these
Rationale: Explanation:
Total volume of water displaced =(4 x 40) m3 = 160 m3
Rise in water level = 160/40Ã—20= 0.2m = 20cm
Answer: B
Answer: (B) 20 cm
Question: The parameter of a square is double the perimeter of a rectangle. The area of the rectangle is 480 sq cm. Find the area of the square.
(A) 378
(B) 277
(C) 389
(D) 480
(E) 881
Rationale: Let the side of the square be a cm. Let the length and the breadth of the rectangle be l cm and b cm respectively.
4a = 2(l + b)
2a = l + b
l . b = 480
We cannot find ( l + b) only with the help of l . b. Therefore a cannot be found .
Area of the square cannot be found.
Answer:D
Answer: (D) 480
Question: 3^12 + 3^12 + 3^12 =
(A) 3^11
(B) 3^13
(C) 3^15
(D) 9^12
(E) 9^13
Rationale: Since we have 3^12 added together 3 times, we can factor out a 3 and we get 3(3^12) which is equal to 3^13.
The answer is B.
Answer: (B) 3^13
Question: If 7 persons can do 7 times of a particular work in 7 days, then, 9 persons can do 9 times of that work in
?
(A) 3 days
(B) 8 days
(C) 9 days
(D) 11 days
(E) 7 days
Rationale: That is, 1 person can do one time of the work in 7 days.
Therefore, 9 persons can do 9 times work in the same 7 days itself.
Option 'E'
Answer: (E) 7 days
Question: Find the value for x from below equation: x/3=-5?
(A) -66
(B) 13
(C) -15
(D) -31
(E) 40
Rationale: 1. Multiply both sides by 3:
x*3/3= -5/3
Simplify both sides:
x = -15
C
Answer: (C) -15
Question: Find the principal which yields a simple interest of Rs. 20 and compound interest of Rs. 28 in two years, at the same percent rate per annum?
(A) s. 25
(B) s. 48
(C) s. 42
(D) s. 20
(E) s. 60
Rationale: Explanation:
SI in 2 years = Rs. 20, SI in 1 year = Rs. 10
CI in 2 years = Rs. 28
% rate per annum = [(CI – SI) / (SI in 1 year)] *100
= [(28 – 20) / 20] * 100
= 40 % p.a.
Let the principal be Rs. X
Time = T = 2 years
% rate = 40% p.a.
SI = (PRT/100)
20 = (X*40*2) / 100
X = Rs. 25
ANSWER: A
Answer: (A) s. 25
Question: If a continuous cable 10 meters long was marked off at intervals of 1/3 meter and also 1/7 meter, and then if the cable were cut at each mark, how many different size length of cable would result?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: In this particular example length (10 meter) is just extraneous information.
The location of the marks for 1/3 meter would be 7/21, 14/21, 21/21, etc...
The location of the marks for 1/7 meter would be 3/21, 6/21, 9/21, 12/21, 15/21, 18/21, 21/21, etc...
The distances between marks are 3/21, 1/21, and 2/21.
The answer is C.
Answer: (C) 3
Question: In how many years does a sum of Rs. 6000 yield a simple interest of Rs. 15000 at 15% p.a.?
(A) 16.66 years
(B) 17.66 years
(C) 18.66 years
(D) 19.66 years
(E) 20.66 years
Rationale: T = (100 * 15000)/(15 * 6000) = 16.66 years
ANSWER:A
Answer: (A) 16.66 years
Question: A ball is bought for Rs.400 and sold at a gain of 30% find its selling price?
(A) A)Rs.480/-
(B) B)Rs.490/-
(C) C)Rs.500/-
(D) D)Rs.520/-
(E) E)Rs.540/-
Rationale: 100 % ------> 400 (100 * 4 = 400)
130 % ------> 520 (130 * 4 = 520)
Selling price = Rs.520/-
D
Answer: (D) D)Rs.520/-
Question: 6, 10, 18, 30, 46, ?
(A) 66
(B) 56
(C) 74
(D) 57
(E) 32
Rationale: The pattern is + 4, + 8, + 12, + 16, +20
Answer : A.
Answer: (A) 66
Question: If â€œ*â€ is called â€œ+â€, â€œ/â€ is called â€œ*â€, â€œ-â€ is called â€œ/â€, â€œ+â€ is called â€œ-â€. 240/80 â€“ 60 * 40 - 10 = ?
(A) 355
(B) 341
(C) 323.2
(D) 425.6
(E) 225.7
Rationale: Explanation:
Given : 240/80 â€“ 60 * 40 - 10 = ?
Substituting the coded symbols for mathematical operations, we get,
240 * 80/60 +40 / 10 = ?
240 * 1.33 + 4 = ?
319.2 + 4 = 323.2
ANSWER : C
Answer: (C) 323.2
Question: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
(A) 68
(B) 75
(C) 58
(D) 55
(E) 40
Rationale: Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X - 48 = 180
1000/x - 48 * 5/18 = 180
50 = 9X - 120
X = 68 Kmph
ANSWER A
Answer: (A) 68
Question: It takes 40 identical printing presses 9 hours to print 500,000 papers. How many hours would it take 30 of these printing presses to print 500,000 papers?
(A) 9
(B) 10
(C) 11
(D) 12
(E) 13
Rationale: 40 printing presses can do 1/9 of the job each hour.
30 printing presses can do 3/4*1/9 = 1/12 of the job each hour.
The answer is D.
Answer: (D) 12
Question: Which of the following is equal to the average (arithmetic mean) of (y+4)^2 and (y-4)^2?
(A) x^2
(B) x^2+2
(C) x^2 +12
(D) x^2+21
(E) y^2+16
Rationale: Avg = [(y+4)^2 + (y-4)^2] / 2
Expanding and simplifying, (y^2 + 8y + 16 + y^2 - 8y + 16 ) / 2 = y^2 + 16
Answer E.
Answer: (E) y^2+16
Question: If the annual rate of simple interest increases from 10% to 12 1/2 %, a man's yearly income increases by Rs. 1250. His principal in Rs. is?
(A) 50009
(B) 50000
(C) 50011
(D) 50077
(E) 50027
Rationale: Let the sum be Rs. x. Then,
(x * 25/2 * 1/100) - (x * 10 * 1)/100 = 1250
25x - 20x = 250000
x = 50000
Answer: B
Answer: (B) 50000
Question: Find the smallest number which should be multiplied with 560 to make it a perfect square.
(A) 60
(B) 55
(C) 45
(D) 25
(E) 35
Rationale: 560 = 2*2*2*2*7*5
Required smallest number = 7 * 5 = 35
35 is the smallest number which should be multiplied with 560 to make it a perfect square.
ANSWER:E
Answer: (E) 35
Question: Mark bought a set of 6 flower pots of different sizes at a total cost of $8.00. Each pot cost 0.25 more than the next one below it in size. What was the cost, in dollars, of the largest pot?
(A) $1.75
(B) $1.96
(C) $2.00
(D) $2.15
(E) $2.30
Rationale: This question can be solved with a handful of different Algebra approaches (as has been shown in the various posts). Since the question asks for the price of the largest pot, and the answers are prices, we can TEST THE ANSWERS.
We're told that there are 6 pots and that each pot costs 25 cents MORE than the next. The total price of the pots is $8.25. We're asked for the price of the largest (most expensive) pot.
Since the total price is $8.00 (a 25-cent increment) and the the difference in sequential prices of the pots is 25 cents, the largest pot PROBABLY has a price that is a 25-cent increment. From the answer choices, I would then TEST Answer C first (since answers B and D are NOT in 25-cent increments).
IF....
The largest pot = $1.958
0.708
0.958
1.208
1.458
1.708
1.958
Total = $8.00
So this MUST be the answer.
B
Answer: (B) $1.96
Question: What will be the fraction of 4%
(A) 1/20
(B) 1/50
(C) 1/75
(D) 1/25
(E) None of these
Rationale: Explanation:
4*1/100 = 1/25.
Friends I know it is quite simple, but trust me while solving percentage questions in Hurry we use to do these types of mistake only. So I recommend you to have a bit practise of this
Option D
Answer: (D) 1/25
Question: In an election between two candidates, the first candidate got 70% of the votes and the second candidate got 240 votes. What was the total number of votes?
(A) 800
(B) 900
(C) 1000
(D) 1100
(E) 1200
Rationale: Let V be the total number of votes.
0.3V = 240
V = 800
The answer is A.
Answer: (A) 800
Question: If a certain manager had received a 10% raise instead of the 8% raise that she actually received, her salary would have been $50000. What was her actual salary after the raise?
(A) 55,000
(B) 58,806
(C) 49,090
(D) 59,400
(E) 61,620
Rationale: No need of getting involved with decimals ..just work in fractions ..
salary(let X) included 10% increase can be written as
(1+10/100)X=50000
X=50000/1.10------>45454.54
if there is 8% rise in 45454.54
then the salary now is 8% of 45454.54
8*45454.54/100=3636.36
then toal salary after increment=45454.54+3636.36---->49090.9
Ans C
Answer: (C) 49,090
Question: One side of a rectangular field is 15m and one of its diagonal is 17m. Find the area of field?
(A) 128
(B) 120
(C) 298
(D) 112
(E) 129
Rationale: Other side = [(17 x 17) - (15 x 15)] = (289 - 225) = 8m
Area = 15 x 8
=120 sq. m
Answer: B
Answer: (B) 120
Question: [( 3.242 x 16 ) / 100] = ?
(A) 0.045388
(B) 4.5388
(C) 0.051872
(D) 473.88
(E) None of these
Rationale: Answer
Multiplying 3.242 x 16=5.1872
Now divide 5.1872 by 100
So, 5.1872 ÷ 100= 0.051872
∴ Shift the decimal two places to the left as 100
Correct Option: C
Answer: (C) 0.051872
Question: How many prime numbers between 1 and 100 are factors of 10010?
(A) 5
(B) 4
(C) 3
(D) 2
(E) 1
Rationale: factor of 10010= 2*5*7*11*13 --- 5 prime numbers
A
Answer: (A) 5
Question: The cost price of a radio is Rs.1500 and it was sold for Rs.1245, find the loss %?
(A) 18
(B) 16
(C) 26
(D) 17
(E) 11
Rationale: Explanation:
1500 ---- 255
100 ---- ? => 17%
Answer:D
Answer: (D) 17
Question: In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of three metres is left from all sides of the boundary of the garden. What is the length of the garden?
(A) 22
(B) 24
(C) 26
(D) 28
(E) 30
Rationale: Between the 12 mango trees, there are 11 gaps and each gap has 2 meter length
Also, 3 meter is left from all sides of the boundary of the garden.
Hence, length of the garden = (11 Ã— 2) + 3 + 3 = 28 meter
Answer is D.
Answer: (D) 28
Question: A man buys an article and sells it at a profit of 20%. If he had bought it at 20% less and sold it for Rs.75 less, he could have gained 25%. What is the cost price?
(A) 197
(B) 375
(C) 279
(D) 278
(E) 268
Rationale: CP1 = 100 SP1 = 120
CP2 = 80 SP2 = 80 * (125/100) = 100
20 ----- 100
75 ----- ? => 375
Answer:B
Answer: (B) 375
Question: The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
(A) 74
(B) 94
(C) 184
(D) 194
(E) 364
Rationale: LCM of 6, 9, 15 and 18 is 90.
90*1+4 = 94 not divisible by 7.
90*2+4 = 184 not divisible by 7.
90*3+4 = 274 not divisible by 7.
90*4+4 = 364 is divisible by 7.
so 364
ANSWER:E
Answer: (E) 364
Question: here's an easy question of averages, but let's try to see innovative ways of solving this.
A class has 12 boys and x girls. Average score of boys and girls is 81 and 92 respectively. the average of the whole class is 86, what is the value of x?
(A) a) 6
(B) b) 7
(C) c) 8
(D) d) 10
(E) e) 12
Rationale: 12(81)+92x/12+x=86
972+92x/12+x=86
972+92x=86(12+x)
972+92x=1032+86x
X's one side, numbers one side we get,
92x - 86x=1032-972
6x=60
hence, x=10
Answer D
Answer: (D) d) 10