mathewhe/aqua_rat huggingface dataset:
Question: A shop owner sells 25mtr of cloth and gains SP of 10 mtrs. Find the gain %?
(A) 30%
(B) 40%
(C) 50%
(D) 66.67%
(E) 70%
Rationale: Here, selling price of 10 m cloth is obtained as profit.
Profit of 10 m cloth = (S.P. of 25 m cloth) – (C.P. of 25 m cloth)
Selling price of 15 m cloth = Selling Price of 25 m of cloth
Let cost of each metre be Rs. 100.
Therefore, cost price of 15 m cloth = Rs. 1500 and S.P. of 15 m cloth = Rs. Rs. 2500
Profit% = 10/15 × 100 =66.67%
Profit of 66.67% was made by the merchant.
D
Answer: (D) 66.67%
Question: Evaluate 28% of 550 + 45% of 280
(A) 232
(B) 242
(C) 252
(D) 262
(E) 280
Rationale: Explanation:
= (28/100) * 550 + (45/100) * 280
= 154 + 126 = 280
Answer: Option E
Answer: (E) 280
Question: A batsman makes a score of 64 runs in the 16th innings and thus increased his average by 3. Find his average after the 16th inning?
(A) 22
(B) 299
(C) 277
(D) 19
(E) 77
Rationale: Let the average after the 16th inning be P.
So, the average after the 15th inning will be (P-3) Hence, 15(P-30) + 64 = 16P => P = 19.Answer:D
Answer: (D) 19
Question: Bookman purchased 30 copies of a new book released recently, 10 of which are hardback and sold for $20 each, and rest are paperback and sold for $10 each. If 14 copies were sold and the total value of the remaining books was 240, how many paperback copies were sold?
(A) 8
(B) 12
(C) 6
(D) 4
(E) 5
Rationale: The bookman had 10 hardback ad 30-10=20 paperback copies;
14 copies were sold, hence 30-14=16 copies were left. Let # of paperback copies left be p then 10p+20(16-p)=240 --> 10 p=80 --> p=8
# of paperback copies sold is 20-8=12
Answer: B
Answer: (B) 12
Question: Michael cashed a check for $1,240 and received only $10 and $50 bills in return. During the course of a day, he used 15 bills and then lost the rest of the money. If the number of $10 bills used was either one more or one less than the number of $50 bills used, what is the minimum possible amount of money that was lost?
(A)  $830
(B)  $800
(C)  $770
(D)  $730
(E)  $700
Rationale: 1. 15 bills spent
2. Number of $10 bills is one more or one less than number of $50 bills.
So, 2 choices
1. 7*10 + 8*50 = $470
2. 8*10 + 7*50 = $430
Least money lost implies most money spent. i.e $470
Therefore, lost money = 1240 - 470 = 770.
Answer C
Answer: (C)  $770
Question: What is the equation of a circle of radius 5 units centered at (3, 2)?
(A) x^2 + y^2 + 6x – 4y = 23
(B) x^2 + y^2 - 6x + 4y = 23
(C) x^2 + y^2 + 6x + 4y = 23
(D) x^2 + y^2 - 6x – 4y = - 12
(E) x^2 + y^2 - 6x – 4y = 12
Rationale: the equation of a circle with center at (a,b) and radius R is (X-a)^2+(Y-b)^2=R^2
=> answer = (X-3)^2+(Y-2)^2=5^2
solving,,we get the equation in answer choice E.
Answer: (E) x^2 + y^2 - 6x – 4y = 12
Question: If the weight of 12 meters long rod is 12.2 kg. What is the weight of 6 meters long rod ?
(A) 7.2 kg.
(B) 10.8 kg.
(C) 12.4 kg.
(D) 6.1 kg
(E) None
Rationale: Answer
∵Weight of 12 m long rod = 12.2 kg
∴ Weight of 1 m long rod = 12.2 / 12 kg
∴ Weight of 6 m long rod = 12.2 x 6 / 12
= 6.1 kg
Option: D
Answer: (D) 6.1 kg
Question: Convert the 13/36 m/s into kilometers per hour?
(A) 5.3 kmph
(B) 2.3 kmph
(C) 3.3 kmph
(D) 1.3 kmph
(E) 4.3 kmph
Rationale: D
1.3 kmph
13/36 m/s = 13/36 * 18/5 = 13/10 = 1.3 kmph.
Answer: (D) 1.3 kmph
Question: In western Europe, Z bicycles were sold in each of the years 1990 and 1993. The bicycle producers of Western Europe had a 42 percent share of this market in 1990 and a 33 percent share in 1993. Which of the following represents the decrease in the annual number of bicycles produced and sold in Western Europe from 1990 to 1993?
(A) 9% of (x/100)
(B) 14% of (x/100)
(C) 75% of (x/100)
(D) 9% of Z
(E) 14% of x
Rationale: Moreover is't question actually asking the the difference between the {(Quantity Produced + Quantity Sold ) Z in 1990 - (Quantity Produced + Quantity Sold ) in 1993}
Though the Quantity sold in both the years is same it actually boils down to (Quantity Produced in 1990 ) in (Quantity Produced in 1993)=D
Answer: (D) 9% of Z
Question: If population of certain city increases at the rate of 5%. If population in 1981 was 138915, then population in 1978 was?
(A) 120000
(B) 228788
(C) 266891
(D) 267689
(E) 127791
Rationale: X * (105/100) * (105/100) * (105/100) = 138915
X = 138915/1.157625
X = 120000
Answer:A
Answer: (A) 120000
Question: Consider a set S given as {11,22,33,44,55,66,77,88,99} . If each element of the data set is multiplied by -7 then by what factors will the Mean,Variance and Standard Deviation respectively change ?
(A) -7,-7,-7
(B) -7,7,7
(C) 1,1,1
(D) -7,49,7
(E) 7,7,49
Rationale: Mean: If all values are multiplied by -7 then their sum will also be multiplied by -7 so Mean will also get -7
Variance:
Variance is equal to (Sum of (Square of (the difference between mean and individual values))/Total number of values
When we multiply all the values by -7 then the difference between the mean and the individual values also gets multiplied by -7 and the square of that difference becomes 49. So, the variance gets multiplied by a factor of 49
SD:
Standard Deviation is the square root of variance so sqrt(49)=7. So SD gets multiplied by a factor of 7.
So, answer will be D.
Answer: (D) -7,49,7
Question: A driver took a trip consisting of three segments at three different speeds. The driver drove a distance of (5D) at a speed of (2V), then a distance of (7D) at a speed of (3V), then a distance of D at a speed of (6V). In terms of D and V, what was the total time of the trip?
(A) 3D/V
(B) 4D/V
(C) 5D/V
(D) 6D/V
(E) 7D/V
Rationale: The total time of the trip was:
5D/2V + 7D/3V + D/6V =
30D/12V + 28D/12V + 2D/12V =
60D/12V = 5D/V
The answer is C.
Answer: (C) 5D/V
Question: The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
(A) 10
(B) 88
(C) 676
(D) 99
(E) 12
Rationale: Speed of the boat in still water = (60+80)/2 = 70 kmph. Speed of the stream
= (80-60)/2 = 10 kmph.
Answer: A
Answer: (A) 10
Question: Robin is traveling from one end of a forest to the other. In order to find her way back, she is leaving morsels of bread in the following pattern: 2 morsels of wheat, 3 morsels of MAZE, and 1 morsel of rye. The pattern repeats after she leaves the morsel of rye. If Robin drops 2,000 morsels of bread, what are the last 3 morsels of bread that she drops?
(A) rye − wheat − wheat
(B) wheat − wheat − white
(C) RYE- w-w
(D) white − white − white
(E) white − white − rye
Rationale: Q is nothing BUT asking about remainder..
total morsels thrown before the pattern is repeated = 2+3+1 = 6..
so REMAINDER when 2000 is div by 6..
1998 is EVEN and also div by 3, so remainder is 2..
Last 3 of morsels are 1998-1999-2000
so he uses the last of morsel of pattern in 1998 two of the first morsels of the pattern in 1999 and 2000, and the pattern is w, w, M,M, M, RY..
ans RY-w-w
C
Answer: (C) RYE- w-w
Question: If the sales tax reduced from 3 1/2 % to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 8400 ?
(A) Rs.10
(B) Rs.12
(C) Rs.14
(D) Rs.16
(E) Rs.18
Rationale: Required difference = [3 ½ % of Rs.8400] – [3 1/3 % of Rs.8400]
= [(7/20-(10/3)]% of Rs.8400 =1/6 % of Rs.8400
= Rs. [(1/6)8(1/100)*8400] = Rs. 14.
Option C
Answer: (C) Rs.14
Question: A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then, (a + b) = ?
(A) 8
(B) 10
(C) 7
(D) 26
(E) 38
Rationale: Explanation:
4 a 3 |
9 8 4 } ==> a + 8 = b ==> b - a = 8
13 b 7 |
Also, 13 b7 is divisible by 11 =>(7 + 3) - (b + 1) = (9 - b)
=>(9 - b) = 0
b = 9
(b = 9 and a = 1) => (a + b) = 10.
B
Answer: (B) 10
Question: In how many ways can a committee consisting of 4 men and 5 women be formed from a group of 7 men and 10 women?
(A) 7C4 10C5
(B) 4C7 5C10
(C) 7C5 9C4
(D) 9C4 7C5
(E) NONE
Rationale: Group consisting of 7 men and 10 women
4 men can be selected from 7 men in 7C4 ways
5 women can be selected from 10 women in 10C5 ways
Therefore, Total number of ways= 7C4 10C5
ANSWER:A
Answer: (A) 7C4 10C5
Question: 1/2,16,4,15,3,56,_ ?
(A) 28/3
(B) 27/3
(C) 26/3
(D) 25/3
(E) 24/3
Rationale: take alternative no. 1/2, 4,3
16/4=4
15/5 = 3
56/6 =28/3
hence ans is 28/3
ANSWER:A
Answer: (A) 28/3
Question: On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?
(A) Saturday
(B) Friday
(C) Monday
(D) Tuesday
(E) Sunday
Rationale: The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.
But, 8th Dec, 2007 is Saturday
So, 8th Dec, 2006 is Friday. Answer: B
Answer: (B) Friday
Question: A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed W of the train.
(A) a) 45
(B) b) 33
(C) c) 48
(D) d) 55
(E) e) 61
Rationale: Let y be the balance distance to be covered and x be the former speed.
A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late
so, y/(3x/4) - y/x = 35/60
4y/3x - y/x = 7/12
y/x(4/3-1)=7/12
y/x*1/3=7/12
y/x=7/4
4y-7x=0 ........ 1
Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late
so, (y-24)/(3x/4) - (y-24)/x = 25/60
4(y-24)/3x - (y-24)/x = 5/12
(y-24)/x (4/3-1) = 5/12
(y-24)/x *1/3 = 5/12
(y-24)*12 = 3x*5
(y-24)*4 = 5x
4y-5x = 96 ....... 2
eq2 - eq1
2x=96
x=48=W
Ans = C
Answer: (C) c) 48
Question: The C.P of 15 books is equal to the S.P of 19 books. Find his gain% or loss%?
(A) 16 2/3% loss
(B) 16 2/8% loss
(C) 21 1/19% loss
(D) 36 2/3% loss
(E) 56 2/3% loss
Rationale: 15 CP = 19 SP
19 --- 4 CP loss
100 --- ? => 21 1/19% loss
Answer:C
Answer: (C) 21 1/19% loss
Question: The cost of registration at a professional association meeting was $50 per person; a lunch for registrants only was available for an additional $22 per person. If the number of registrants who paid for lunch was 20 more than the number who did not, and if receipts for registration and lunch totaled $50,240, how many people paid just for registration at the meeting?
(A) 700
(B) 800
(C) 1,300
(D) 1,500
(E) 400
Rationale: Hope this might be useful to you.
Let the number of people who have opted only to register = x
Now since the registration cost is 50$ per person, the total amount sums to = 50x $
As per the information given in the question, the number of registrants who paid for lunch was 20 more than the number who did not. That means, total number of people who registered and paid for lunch = 20 + x.
For the people who registered for lunch the cost is 50 $ (for the event registration) + 22 $ (for lunch) = 72 $.
Total amount in this case sums to = 72(20 + x) = 1440 + 72x
Now, total amount received was 50240.
Thus, from the above data,
50x + 1440 + 72x = 50240
122x = 50240 - 1440
122x = 48800
x = 400.
Hence the correct Ans is E
Answer: (E) 400
Question: Find the ratio in which rice at Rs.10.0 a kg be mixed with rice at Rs.5.70 a kg to produce a mixture worth Rs.6.30 a kg?
(A) 1 : 3
(B) 2 : 3
(C) 3 : 5
(D) 4 : 5
(E) None of these
Rationale: Solution
Required ratio = 60 : 100 = 3 : 5
Answer C
Answer: (C) 3 : 5
Question: A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 38 per kg. His profit percent is:
(A) No profit, no loss
(B) 5%
(C) 33%
(D) 10%
(E) None of these
Rationale: Explanation :
C.P. of 56 kg rice = (26 * 20 + 30 * 36) Rs. = (520 + 1080) Rs. = 1600 Rs.
S.P. of 56 kg rice = (56 * 38) Rs. = 2128 Rs.
Profit % = (2128−1600/1600∗100)% = 33%
Answer : C
Answer: (C) 33%
Question: If 75 percent of a class answered the first question on a certain test correctly, 35 percent answered the second question on the test correctly, and 20 percent answered neither of the questions correctly, what percent answered both correctly?
(A)  10%
(B) (8) 20%
(C)  30%
(D)  50%
(E)  65%
Rationale: {Total} = {First} + {Second} - {Both} + {Neither}
100% = 75% + 35% - {Both} + 20% --> {Both} = 30%.
Answer: C
Answer: (C)  30%
Question: A father is 30 years older than his son, however he will be only thrice as old as the son after 5 years, what is the father's present age ?
(A) 40 yrs
(B) 30 yrs
(C) 50 yrs
(D) 60 yrs
(E) None of the above
Rationale: After 5 years . if ages are F and S , then
F=3S where F = S+30
F= 3*(F-30) = 3F-90
2F = 90
F =45
so present age = 45-5= 40 years
ANSWER:A
Answer: (A) 40 yrs
Question: If a and b are integers and (2^a)(3^b) is a factor of 90^40, what is the largest possible value of ab?
(A) 2a
(B) 5a
(C) 20a
(D) 40a
(E) 80a
Rationale: (2^a)(3^b) is a factor of 90^40
We need to find the largest possible value of ab.
We know that 90 = 2^1*5^1*3^2
Therefore 90^40 will have 2 powers of 3 in it.
Hence in (2^a)(3^b), b has to 2
Therefore value of ab = 2a
Correct Option: A
Answer: (A) 2a
Question: Find out the wrong number in the given sequence of numbers.
1, 2, 6, 15, 31, 56, 93
(A) 2
(B) 6
(C) 15
(D) 93
(E) 91
Rationale: 1(result) + (1*1) = 2.
2(result) + (2*2) = 6.
6(result) + (3*3) = 15.
15(result) + (4*4) = 31.
31(result) + (5*5) = 56.
56(result) + (6*6) = 92.
Now we are getting 92 not 93.. So 93 is the wrong number of the given.
answer : D
Answer: (D) 93
Question: Find the remainder of the division (3^15)/7.
(A) 7
(B) 6
(C) 15
(D) 8
(E) 2
Rationale: Find the pattern of the remainders after each power:
(3^1)/7 remainder 3
(3^2)/7 remainder 2
(3^3)/7 remainder 6
(3^4)/7 remainder 4
(3^5)/7 remainder 5
(3^6)/7 remainder 1 -->this is where the cycle ends
(3^7)/7 remainder 3 -->this is where the cycle begins again
(3^8)/7 remainder 2
Continuing the pattern to (3^15)/7 gives us a remainder of 6
Final Answer:
B) 6
Answer: (B) 6
Question: One used-car salesperson receives a commission of $ 100 plus 4 percent of $ 1,000 less than the car’s final sale price. Another car salesperson earns a straight commission of 6 percent of the car’s final sale price. What is the final sale price of a car if both salespeople would earn the same commission for selling it?
(A) $ 5,000
(B) $ 6,000
(C) $ 8,000
(D) $ 10,000
(E) $ 12,000
Rationale: This question can be solved by TESTing THE ANSWERS.
We're given the pay rate of two different salespeople who sell cars:
1) A commission of $ 100 plus 4 percent of $ 1,000 less than the car’s final sale price.
2) A straight commission of 6 percent of the car’s final sale price.
We're asked for the final sale price of a car if both salespeople would earn the SAME commission for selling it?
Let's TEST Answer B: $6,000
1st salesperson = $200 + .04(6,000 - 1,000) = $200 + .04(5,000) = $200 + $200 = $400
2nd salesperson = .06(6,000) = $360
These totals are NOT the same, so we can eliminate B. Looking at the two pay 'formulas', we can see that the 2nd salesperson will make more money than the 1st when the price of the car increases to a significant level, so we need a price that is HIGHER than $6,000. Since the difference in pay is relatively small in Answer B, we're likely looking for a number that is fairly close to $6,000 though...
Let's TEST Answer B: $6,000
1st salesperson = $200 + .04(8,000 - 1,000) = $200 + .04(7,000) = $200 + $280 = $480
2nd salesperson = .06(8,000) = $480
These totals are the SAME, so this must be the answer.
Final Answer:
B
Answer: (B) $ 6,000
Question: If 4<(7-x)/3, which of the following must be true?
I. 5<x
II. |x+6|>2
III. -(x+5) is positive
(A) II only
(B) III only
(C) I and II only
(D) II and III only
(E) I, II and III
Rationale: 12<7-x
x<-5
x+5<0
1.5<x...not possible
2.True.....Check for values x=-6,-7,-8....... etc
3.True.. Since x+5<0 -(x+5) will always be positive
Hence, Ans is C..
Answer: (C) I and II only
Question: A grocer buys apples for 100¢ per pound. If 10% of the apples goes bad and he still wants to make a 20% profit over his purchase price, what should be the sales price?
(A) 100¢
(B) 115¢
(C) 145¢
(D) 150¢
(E) 146.67¢
Rationale: for making calculation simple let us consider he buys 10pounds @ 100/pound=1000¢ in total .
10% apples lost...means 9 pounds left.
further he wants 20% profit on 1100 ¢
means he wants to earn 1320¢
sales price should be 1320/9=¢ 146.67
Ans E
Answer: (E) 146.67¢
Question: Certain stocks in January were 20% less than they were in February and 30% greater than they were in March. What was the percentage decrease in the stocks from February to March?
(A) 31%
(B) 45%
(C) 52%
(D) 61%
(E) 25%
Rationale: Let, Stock in February = 100
Then, Stock in January = 100-(20/100)*100 = 80
January = 30% greater than March = 1.3* Stock in March
i.e. Stock in March = 90 / 1.3 = 69 approximately
% Decrease from February to March = (69 - 100)*100/100 =31%approximately
Answer: Option A
Answer: (A) 31%
Question: Simple interest on a certain sum at a certain annual rate of interest is 1/25 of the sum. If the numbers representing rate percent and time in years be equal, then the rate of interest is:
(A) 5 %
(B) 2 %
(C) 6 %
(D) 8 %
(E) 3 %
Rationale: Explanation :
Let sum = x. Then, S.I. = x/25
Let rate = R% and time = R years.
[x * R * R / 100] = x / 25? R^2 = 100/25=4
R = 2
Hence, rate of interest = 2 %.
Answer : B
Answer: (B) 2 %
Question: There are 900 jelly beans divided between two jars, Jar X and Jar Y. If there are 500 fewer jelly beans in jar X than three times the number of beans in jar Y, how many beans are in jar X?
(A) 510
(B) 520
(C) 530
(D) 540
(E) 550
Rationale: X+Y=900 so Y=900-X
X=3Y-500
X=3(900-X)-500
4X=2200
X=550
The answer is E.
Answer: (E) 550
Question: The average number of printing error per page in a book of 512 pages is 4. If the total number of printing error in the first 302 pages is 1,208, the average number of printing errors per page in the remaining pages is
(A) 0
(B) 4
(C) 840
(D) 90
(E) None of the above
Rationale: Remaining pages = 512 – 302 = 210
Let average printing error in remaining pages = x
Then, 1208+210×x/512=4
⇒ 210x = 840 ⇒ x = 4
Answer B
Answer: (B) 4
Question: I take a four-digit number and subtract from it the sum of its digits. In the result I strike off one of the digits and the remaining three digits of the result are 2, 4 and 6 (not necessarily in that order). Find the digit struck off by me.
(A) 6
(B) 7
(C) 8
(D) 9
(E) 10
Rationale: Sol:
Let us assume the four digit number as wxyz. Then in base system 10 it can written as 1000w + 100x + 10y + z. Now given that,
wxyz = 1000w + 100x + 10y + z - (w + x + y + z) = 999w + 99x + 9y which is a multiple of 9
Hence the sum of digits must be a multiple of 9.
Hence 2 + 4 + 6 + x is equal to either 9, 18, 27 ...
But if the sum is equal to 9 then x is negative number. Therefore x = 6.
Answer A
Answer: (A) 6
Question: In each of the following numbers, what should be the missing digit in the indicated place such that the number is a multiple of 11?
945678_
(A) 3
(B) 2
(C) 8
(D) 7
(E) 6
Rationale: Divisibility of 11: If the difference of the sum of the digits at odd places and the sum of the digits at even places of a number is zero or a multiple of 11, then that number is divisible by 11.
As per divisibility rule of 11, difference = (x + 21) - 18 = x + 3
=> x + 3 = 11 => x = 8
ANSWER:C
Answer: (C) 8
Question: Mr. LISA invested in Fund X and Fund Y. The total amount she invested, in both funds combined, was $200,000. In one year, Fund X paid 41% and Fund Y paid 14%. The interest earned in Fund Y was exactly $200 greater than the interest earned in Fund X. How much did Ms. Tom invest in Fund X?
(A) 60,545.56
(B) 570,545.56
(C) 50,545.45
(D) 80,545.23
(E) 90,545.78
Rationale: X+Y=200,000
0.14Y=0.41A+200
Take away decimals first: 14Y+41X+20,000
Isolate first equation to solve for X (your goal): Y=200,000-Y
Plug in for B:
14(200,000-X)=41X+20,000
2,800,000-14X=41X+20,000
2,780,000=55X
2,780,000/55=X
X=50,545.45=Answer Choice C
Answer: (C) 50,545.45
Question: There are three secretaries who work for four departments. If each of the four departments have one report to be typed out, and the reports are randomly assigned to a secretary, what is the probability W that all three secretary are assigned at least one report?
(A) 8/9
(B) 64/81
(C) 4/9
(D) 16/81
(E) 5/9
Rationale: I got the same answer: Here's my reasoning
First Report you have 3 choices
Second Report you have 2 choices
Third Report you have 1 choice
Fourth report 3 choices again
Then total number of ways is: 3*2*1*3=3^2*2
This is not correct. You have assumed that the 4th report must go to someone who already has a report. There is no such constraint. You can easily give the 1st and 2nd reports to secretary 1, 3rd report to secretary 2 and 4th report to secretary 3. But you have ignored all such cases.
The number of ways of ensuring at least one report goes to each secretary is 4C2 (select 2 reports out of 4 which go to the same person)*3C1 (select the person who must type 2 reports)*2! (since you have 2 reports left which you must distribute to the 2 remaining people such that each person gets one) = 36
Required probability W= 36/81.C
Answer: (C) 4/9
Question: A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?
(A) 2 p.m. on Tuesday
(B) 2 p.m. on Wednesday
(C) 3 p.m. on Thursday
(D) 1 p.m. on Friday
(E) 8 p.m. on Friday
Rationale: Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days 2 hours = 170 hours.
The watch gains 2 + 4*4/5	min.	or	34/5	min. in 170 hrs.
Now,	34/5	min. are gained in 170 hrs.
2 min. are gained in 170 x	5/34	x 2	hrs	= 50 hrs.
Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e., it will be correct at 2 p.m. on Wednesday.
Answer:B
Answer: (B) 2 p.m. on Wednesday
Question: Reeya obtained 50, 60, 70, 80 and 80 out of 100 in different subjects, What will be the average
(A) 70
(B) 75
(C) 80
(D) 85
(E) 68
Rationale: Explanation:
(50+60+70+80+80 / 5)=68
Option E
Answer: (E) 68
Question: An alchemist discovered that the formula expressing the correct proportions needed to turn ordinary metal into gold is G = 3/2M + 15, where G is the number of gold bars and M is the number of metal bars. If a metal bar weighs twice as much as a gold bar, how many metal bars will yield an equal weight of gold
(A) a.	A - 10
(B) b.	B - 15
(C) c.	C – 22.5
(D) d.	D – 40
(E) e.	E – 67.5
Rationale: A --- 30/2 + 15 = 30 --- CORRECT
B --- 45/2 + 15 = not an integer --- wrong
C --- 22.5(3/2) + 15 = not an integer --- wrong
D --- 120/2+15 = 75 --- wrong
This is one of those problems that will probably be easiest to solve by plugging in numbers. The algebra is do-able, but it's not worth the effort (in my opinion). I was able to solve it in under 30 seconds total with this method.
A
Answer: (A) a.	A - 10
Question: Find the smallest number which should be multiplied with 520 to make it a perfect square.
(A) 30
(B) 120
(C) 55
(D) 35
(E) None of these
Rationale: 520 = 26 * 20 = 2 * 13 * 22 * 5 = 23 * 13 * 5
Required smallest number = 2 * 13 * 5 = 130
130 is the smallest number which should be multiplied with 520 to make it a perfect square.
ANSWER:E
Answer: (E) None of these
Question: What is the 4 digit number in which the 1st digit is 1/3 of the second, the 3rd is the sum of the 1st and 2nd, and the last is three times the 2nd?
(A) 1200
(B) 1245
(C) 1349
(D) 1450
(E) 1530
Rationale: First digit is 1/3 second digit => The numbers can be 1 & 3, 2& 6, 3 & 9.
First + second = third => we can eliminate 3 & 9 since 3 + 9 = 12.
Last is 3 times the second => we can eliminate option 2 & 6 since 3 * 6 = 18.
Hence the number is 1349
C
Answer: (C) 1349
Question: In an exam, Amar scored 64 percent, Bhavan scored 36 percent and Chetan 44 percent. The maximum score awarded in the exam is 900. Find the average mark scored by all the three boys?
(A) 384
(B) 432
(C) 207
(D) 269
(E) 208
Rationale: Average mark scored by all the three boys =
[64/100 (900) + 36/100 (900) + 44/100 (900)] / 3
= 432
Answer: B
Answer: (B) 432