mathewhe/aqua_rat huggingface dataset:
Question: 24 men can complete a work in 16 days.32 women can complete the same work in 24 days.16 men and 16 women started working and worked for 12 days. How many more men are to be added to complete the remaining work in 2 days?
(A) 16
(B) 24
(C) 36
(D) 48
(E) 49
Rationale: Explanation:
1man’s 1 day work = 1/384
1 woman’s 1 day work = 1/768
work done in 12 days =12(16/384+16/768) =12*3/48 = 3/4
remaining work =1/4
(16 men + 16 women)’s 2 day work =2(16/384+16/768) = 1/8
remaining work = 1/4 - 1/8 =1/8
1/384 work is done in 1 day by 1man 1/8 work will be done in 2 days by 384 x 1/8 x 1/2 = 24 men
Answer: Option B
Answer: (B) 24
Question: Raju age after 15 years will be 5 times his age 5 years back, What is the present age of Raju
(A) 28
(B) 17
(C) 10
(D) 77
(E) 66
Rationale: Clearly,
x+15 = 5(x-5)
<=> 4x = 40 => x = 10
Answer:C
Answer: (C) 10
Question: Arun purchased 35 kg of rice at the rate of Rs 9.50 per kg and 30 kg at the rate of Rs 10.50 per kg. He mixed the two. Approximately, at what price per kg should he sell the mixture to make 35 % profit in the transaction?.
(A) 12 Rs
(B) 13 Rs
(C) 13.5 Rs
(D) 14 Rs
(E) None of these
Rationale: Explanation :
Cost Price of 65 kg rice = Rs. (35 x 9.50 + 30 x 10.50)
= 647.50 Rs
Sell Price of 65 kg rice = 135 % of 647.50 = Rs (135/100) x 647.50
Sell Price per kg = (135/100) x 647.50 x (1/65) = 13.44=Rs. 13.50 (Appx.)
Answer : C
Answer: (C) 13.5 Rs
Question: In what time will a train 150 m long cross an electric pole, it its speed be 144 km/hr?
(A) 2.5 sec
(B) 3.75 sec
(C) 3.5 sec
(D) 7.5 sec
(E) 2.4 sec
Rationale: Speed = 144 * 5/18 = 40 m/sec
Time taken = 150/40
= 3.75 sec.
Answer: B
Answer: (B) 3.75 sec
Question: How long does a train 110 m long traveling at 60 kmph takes to cross a bridge of 170 m in length?
(A) 16.7
(B) 16.8
(C) 16.5
(D) 16.1
(E) 16.2
Rationale: D = 110 + 170 = 280 m
S = 60 * 5/18 = 50/3
T = 280 * 3/50 = 16.8 sec
Answer:B
Answer: (B) 16.8
Question: A women travels from X to Y distance of 1000 miles in 10 hours. she returns to X in 4 hours. Find her average speed
(A) 300mph
(B) 150.2mph
(C) 142.8mph
(D) 200mph
(E) 111.01mph
Rationale: Speed from X to Y = 1000/10 = 100 mph
Speed from Y to X = 1000/4 = 250 mph
Average speed = 2*100*250 / 350 = 142.8mph
Answer is C
Answer: (C) 142.8mph
Question: In her backyard, Florry grows only yellow roses and white roses. Some of the rose bushes have flowers of both colors, and some have flowers of one color only. The number of rose bushes that have only yellow roses is 50% greater than the number of rose bushes that have only white roses. If there are yellow roses on 80% of Florry's rose bushes, then what percent H of her bushes have only yellow roses?
(A) 20
(B) 30
(C) 50
(D) 70
(E) 80
Rationale: let, the number of bushes with only yellow flowers be x
so, number of bushes with only yellow flowers will be 1.5x
if total number of bushes of flowers= T
then total number of bushes with yellow flowers= 0.8T
we can say that total number of bushes with yellow flowers+ bushes with only white flowers= total number of bushes with flowers
so,H= 0.8T+x=T
x=0.2T
so, 1.5x=0.3T
30% flowers are yellow flowers
OA B
Answer: (B) 30
Question: If the diagonals of a rhombus are 24 cm and 10 cm, what will be its perimeter
(A) 42 cm
(B) 64 cm
(C) 56 cm
(D) 52 cm
(E) None of these
Rationale: Explanation : Let the diagonals be PR and SQ such that PR = 24 cm and SQ = 10 cm PO = OR = 24/2=12 cm
SO = OQ = 10/2=5 cm
PQ = QR = RS = SP = √(122 + 52) = √(144+25) = √169 = √13 cm
perimeter = 4 × 13 = 52 cm Answer : Option D
Answer: (D) 52 cm
Question: If a bike moving at the speed of x km/hr travels a distance of y km, which of the following cannot be equal to the distance traveled?
(A) x-y km
(B) x/2 km
(C) y-x km
(D) y/x km
(E) (x-y)/2 km
Rationale: This question can be solved by TESTing VALUES, but there's a particular pattern that you have to recognize to make the workeasy.
We're not really limited by anything in this question, so X and Y can be anything. Under normal circumstances, I won't TEST the number 1 in PS questions (as it often leads to duplicate answers), but here it's a great option (since we're looking to eliminate 4 answers, multiple TESTs are going to be likely anyway).
We're given information on speed (X km/hour) and distance (Y km). We're asked which of the 5 answer choices CANNOT be the distance traveled.
IF....
X = 2 and Y = 1
Answers A (2-1 = 1) and B (2/2 = 1) are POSSIBLE. Eliminate A and B.
IF....
X = 3 and Y = 1
Answer E ([3-1]/2 = 1) is POSSIBLE. Eliminate E.
IF....
X = 1 and Y = 1
Answer D (1/1 = 1) is POSSIBLE. Eliminate D.
Final Answer:
C
Answer: (C) y-x km
Question: A tank is filled in eight hours by three pipes A, B and C. Pipe A is twice as fast as pipe B, and B is twice as fast as C. How much time will pipe B alone take to fill the tank?
(A) 24 hours
(B) 28 hours
(C) 32 hours
(D) 36 hours
(E) None of these
Rationale: Explanation:
1/A + 1/B + 1/C = 1/8 (Given)
Also given that A = 2B and B = 2C
=> 1/2B + 1/B + 2/B = 1/8
=> (1 + 2 + 4)/2B = 1/8
=> 2B/7 = 8
=> B = 28 hours.
ANSWER IS B
Answer: (B) 28 hours
Question: The price of a jacket is reduced by 25%. During a special sale the price of the jacket is reduced another 30%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount?
(A) 105
(B) 45
(C) 85
(D) 95
(E) 90.5
Rationale: 1) Let the price of jacket initially be $100.
2) Then it is decreased by 25% , therefore bringing down the price to $75.
3) Again it is further discounted by 30%, therefore bringing down the price to $52.5.
4) Now 52.5 has to be added byX %in order to equal the original price.
52.5 + ( X% )52.5 = 100.
Solving this eq for X, we get X = 90.5
Ans is E
Answer: (E) 90.5
Question: A trader marks his articles 20% more than the cost price. If he allows 20% discount, then find his gain or loss percent?
(A) 1
(B) 2
(C) 3
(D) 7
(E) 4
Rationale: Let CP of an article = RS. 100
MP= Rs. 120
Discount = 20%
SP = M[(100 - d%)/100] = 120(80/100) = Rs. 96
Clearly, the trader gets 4% loss.
Answer: E
Answer: (E) 4
Question: A survey was sent to 80 customers, 7 of whom responded. Then the survey was redesigned and sent to another 63 customers, 9 of whom responded. By approximately what percent did the response rate increase from the original survey to the redesigned survey?
(A) 2%
(B) 5%
(C) 14%
(D) 28%
(E) 63%
Rationale: case 1: (7/80)=x/100
x=9%
case 2: (9/63)=y/100
y=14%
So percent increase is =(y-x)=(14-9)%=5%
Answer is B
Answer: (B) 5%
Question: How many multiples of 5 are there between 5 to 85?
(A) 15
(B) 18
(C) 17
(D) none of these
(E) Cannot be determined
Rationale: Explanation :
As you know, multiples of 5 are integers having 0 or 5 in the digit to the extreme right (i.e. the units place).
So the numbers are 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80.
Answer : A
Answer: (A) 15
Question: Divide 71 into 2 parts such that 1 part exceeds the other by 8. What are the 2 no.'s in that part?
(A) 26
(B) 30
(C) 31
(D) 34
(E) 35
Rationale: Let $let n$ be the smaller and 71 - n be the larger number. Now, since the larger number exceeds the smaller number by 7, we can form the equation
larger number – smaller number = 7
which is equivalent to
Simplifying, we have 71 - 2n = 7. This gives us 2n = 78 which implies that the larger number is . The smaller is 71-39=31.
C
Answer: (C) 31
Question: A can do a work in 15 days and B in 20 days. If they work on it together for 5 days, then the fraction of the work that is left is
(A) 8/17
(B) 7/15
(C) 3/15
(D) 5/12
(E) 1/4
Rationale: Person ( A ) ( B ) ( A+B )
Time - ( 15 ) ( 20 ) (-)
Rate - ( 20 ) ( 15 ) ( 35 )
Work -(300) (300) (300)
therefore A+B requires (300/35) days to complete entire work
For 1st 5 days they work 35 * 5 = 175
Remaining work is 300 - 175 = 125
Remaining fraction of work is = 125/300 = 5/12
Answer D
Answer: (D) 5/12
Question: What is the value of 3x^2 − 1.8x + 0.8 for x = 0.6?
(A) −0.3
(B) 0.8
(C) 0.3
(D) 1.08
(E) 2.46
Rationale: 3x^2-1.8x+0.8 for x=0.6
=3(0.6*0.6)-3*0.6*(0.6)+0.8
=0+0.8
=0.8
ANSWER:B
Answer: (B) 0.8
Question: John purchased some shirts and trousers for $700. He paid $400 less for the shirts than he did for the trousers. If he bought 5 shirts and the cost of a shirt is $20 less than that of a trouser, how many trousers did he buy?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 11
Rationale: Given that the total purchase of two items cost 700.
So the average purchase of one item will cost 700/2 = 350.
Its given as total shirt cost 400$ less. Hence Total Shirt cost = 350 - 50 and Total trouser cost = 350 + 50
5 shirts = 150$ ==> One shirt = 30$
One trouser = 30 + 20 = 50$
Total trousers = 550 / 50 = 11.
E
Answer: (E) 11
Question: The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is ?
(A) 7 kmph
(B) 6 kmph
(C) 4 kmph
(D) 3 kmph
(E) 2 kmph
Rationale: Explanation:
Speed of the stream = 1
Motor boat speed in still water be = x kmph
Down Stream = x + 1 kmph
Up Stream = x - 1 kmph
[35/(x + 1)] + [35/(x - 1)] = 12
x = 6 kmph
Answer: B
Answer: (B) 6 kmph
Question: In how many ways can 5 letters be posted in 3 post boxes, if any number of letters can be posted in all of the three post boxes?
(A) 5 C 3
(B) 5 P 3
(C) 5(3)
(D) 3(5)
(E) 2(5)
Rationale: Explanatory Answer
Sampling with replacement
The first letter can be posted in any of the 3 post boxes. Therefore, we have 3 possibilities.
Similarly, the second, the third, the fourth and the fifth letter can each be posted in any of the 3 post boxes.
Each of the 5 letters has 3 possibilities because we can post any number of letters in all of the boxes.
Therefore, the total number of ways the 5 letters can be posted in 3 boxes is 3 * 3 * 3 * 3 * 3 = 3(5)
Choice D
Answer: (D) 3(5)
Question: -84x29+365=?
(A) 2436
(B) 2801
(C) -2801
(D) -2071
(E) None of them
Rationale: Given exp.=-84x(30-1)+365
=-(84x30)+84+365
=-2520+449
=-2071
Answer is D
Answer: (D) -2071
Question: In a certain mathematical activity, we start with seven cards, each with a different prime number written on it. These seven cards are randomly put into three boxes in the following way: one box must get four cards, one must get two, and one gets only one. Then, for each box, we find the product of all the cards in the box, and that’s the “number” of the box. Then, we put those three numbers in order, from lowest to highest, and that is our set. How many different sets R can be created from this process?
(A)  35
(B)  105
(C)  210
(D)  420
(E)  630
Rationale: R=7C4 * 3C2 = 105 Answer B.
7C4 ways to choose 4 numbers for Box 1
3C2 ways to choose 2 numbers for Box2
1 way for Box 3 .
every combination will give a different product and can be arranged least to highest only in one way .B
Answer: (B)  105
Question: 48 gallon solution of salt and water is 10% salt. How many gallons of water must be added to the solution in order to decrease the salt to 8% of the volume?
(A) 8
(B) 12
(C) 13
(D) 14
(E) 16
Rationale: Amount of salt = 4.8
Assume x gallons of water are added.
4.8 / 48 + x = 8/100
480 = 8x + 384
8x = 96
x = 12
Correct Option: B
Answer: (B) 12
Question: Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
(A) 15
(B) 15.7
(C) 19.7
(D) 19.2
(E) 18
Rationale: Let the amount taxable purchases be Rs. x.
Then, 6% of x =30/100
x =(	(30/100)x(100/6) )= 5.
Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70
ANSWER C
Answer: (C) 19.7
Question: The triplicate ratio of 1:9 is?
(A) 1:0
(B) 1:8
(C) 1:7
(D) 1:2
(E) 1:729
Rationale: 13: 93 = 1:729
Answer: E
Answer: (E) 1:729
Question: If a and b are positive real numbers, and a^3 + b^3 = 20, then the greatest possible value of a is between:
(A) 0 and 3
(B) 3 and 4
(C) 4 and 5
(D) 5 and 7
(E) 7 and 9
Rationale: If a > 3, then a^3 + b^3 > 20.
The answer is A.
Answer: (A) 0 and 3
Question: In how many ways can 5 letters be posted in 3 post boxes, if any number of letters can be posted in all of the three post boxes?
(A) 3
(B) 9
(C) 35
(D) 25
(E) 215
Rationale: The first letter can be posted in any of the 3 post boxes. Therefore, we have 3 possibilities.
Similarly, the second, the third, the fourth and the fifth letter can each be posted in any of the 3 post boxes.
Each of the 5 letters has 3 possibilities because we can post any number of letters in all of the boxes.
Therefore, the total number of ways the 5 letters can be posted in 3 boxes is
3 * 3 * 3 * 3 * 3 = 35
Option C
Answer: (C) 35
Question: In a class, there are 21 boys who are over 160 cm tall. If these constitute three-fourths of the boys and the total number of boys is two-thirds of the total number of students in the class, what is the number of girls in the class ?
(A) 8
(B) 14
(C) 18
(D) 24
(E) 26
Rationale: Explanation:
Let the number of boys be x. Then, (3/4)x = 21 or x = 21 x(4/3) = 28.
If total number of students is y, then (2/3) y = 28 or y = 28 x (3/2) = 42.
Therefore Number of girls in the class = (42 - 28) = 14.
Answer: B
Answer: (B) 14
Question: How many 3 digit positive integers E exist that when divided by 7 leave a remainder of 5?
(A) 128
(B) 142
(C) 143
(D) 141
(E) 129
Rationale: Minimum three digit number is 100 and maximum three digit number is 999.
The first three digit number that leaves remainder 5 when divided by 7 is 103.
14 * 7 = 98 +5 = 103
The second three digit number that leaves remainder 5 when divided by 7 is 110.
15 * 7 = 105 +5 =110
The third three digit number that leaves remainder 5 when divided by 7 is 117
and so on
The last three digit number that leaves remainder 5 when divided by 7 is 999
142 * 7 = 994 + 5 = 999
Therefore, we identify the sequence
103,110,117.....999
use the formula of last term
Last term = first term + (n - 1) * common difference
you will get the answer 129 that is definitely E.
Answer: (E) 129
Question: On a wedding catering service, An experienced chef can prepare a service for a wedding in 6 hours while an novice chef would finish the preparations in 7 hours.
If the catering service employs the same number of novice and experienced chefs, then how many chefs would it take to prepare a wedding service in 1 hour and 36 minutes?
(A) 2
(B) 3
(C) 4
(D) 6
(E) 8
Rationale: Experienced chefs work = 1 wedding/6 hours
Novice chefs work = 1 wedding/7 hours
Since we don't know the number of experienced or novice chefs but know that there is an equal number each, let the number of chefs for each group equalx
1hr and 36mins = 8/5 an hour
x/6 + x/7 = 1 wedding / (8/5)
x/6 + x/7 = 5/8
x=2
So there are 2 novice chefs and 2 experienced chefs. In total there are 4. The answer is C.
Answer: (C) 4
Question: If (x+3)^2/(2x+15)=3, then the difference between the two possible values of x is:
(A) 8
(B) 10
(C) 12
(D) 14
(E) 16
Rationale: (x+3)^2/(2x+15)=3
(x+3)^2=3(2x+15)
x^2+6x+9=6x+45
x^2-36=0
(x-6)(x+6)=0
x=6 or x=-6
The answer is C.
Answer: (C) 12
Question: In how many ways a committee consisting of 5 men and 6 women can be formed from 8 men and 10 women?
(A) 266
(B) 86400
(C) 11760
(D) 5040
(E) None of these
Rationale: Here, 5 men out of 8 men and 6 women out of 10 women can be chosen in
8C5 × 10C6 ways, i.e., 11760 ways.
Answer C
Answer: (C) 11760
Question: Excluding stoppages, the speed of a train is 55 kmph and including stoppages it is 30 kmph. Of how many minutes does the train stop per hour?
(A) 82
(B) 27
(C) 12
(D) 82
(E) 18
Rationale: Explanation:
T = 25/55 * 60 = 27
Answer: Option B
Answer: (B) 27
Question: Find the remainder when 32^33^34 is divided by 11
(A) 22
(B) 10
(C) 99
(D) 76
(E) 28
Rationale: So 32103210 gives remainder 1.
Now we have to write 32^33^34 in this format. So we have to find the remainder 33^34 when divided by 10. The remainder is nothig but unit digit of the number. Click here to learn this concept
33^34 gives unit digit of 9.
So 33^34 = 10 K + 9
323334=32(10K+9)=(3210)K.329323334=32(10K+9)=(3210)K.329
Now this expression when divided by 11 leaves a remainder of 329329 which inturn is equal to (−1)9=−1=10
Answer:B
Answer: (B) 10
Question: In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C is
(A) 33
(B) 10
(C) 88
(D) 37
(E) 32
Rationale: 10 points
Answer: B
Answer: (B) 10
Question: Johnson has a corporate proposal. The probability that vice-president Adams will approve the proposal is 0.6. The probability that vice-president Baker will approve the proposal is 0.5. The probability that vice-president Corfu will approve the proposal is 0.4. The approvals of the three VPs are entirely independent of one another.
Suppose the Johnson must get VP Adam’s approval, as well as the approval of at least one of the other VPs, Baker or Corfu, to win funding. What is the probability that Johnson’s proposal is funded?
(A) 0.49
(B) 0.42
(C) 0.45
(D) 0.48
(E) 0.5
Rationale: probability of adams approval = 0.6
baker approval =0.5
corfu approval=0.4
proabability of approval is must adam approval and atleast one approval
= adam approval*baker approval*corfu approval(approval of both remaining)+adam approval*baker approval*corfu not approval(atleast one remaining approval)+
adam approval*baker not approval*coffu approval( atleast one remaining approval
= 0.6*0.5*0.4+0.6*0.5*0.6+0.6*0.5*0.4
=0.12+0.18+0.12
=0.42
B
Answer: (B) 0.42
Question: What is the place value of 3 in the numeral 2734?
(A) 45
(B) 30
(C) 43
(D) 56
(E) 40
Rationale: Option 'B'
3 * 10 = 30
Answer: (B) 30
Question: A alone can complete a work in 16 days and B alone can do in 12 days. Starting with A, they work on alternate days. The total work will be completed in
(A) 13 1/4
(B) 13 1/2
(C) 13 3/4
(D) 13 4/4
(E) 13 2/3
Rationale: Explanation:
A's 1 day work = 1/16
B's 1 day work = 1/12
As they are working on alternate day's
So their 2 days work = (1/16)+(1/12)
= 7/48
[here is a small technique, Total work done will be 1, right, then multiply numerator till denominator, as 7*6 = 42, 7*7 = 49, as 7*7 is more than 48, so we will consider 7*6, means 6 pairs ]
Work done in 6 pairs = 6*(7/48) = 7/8
Remaining work = 1-7/8 = 1/8
On 13th day it will A turn,
then remaining work = (1/8)-(1/16) = 1/16
On 14th day it is B turn,
1/12 work done by B in 1 day
1/16 work will be done in (12*1/16) = 3/4 day
So total days =
13 3/4
Option C
Answer: (C) 13 3/4
Question: Find the average of all prime numbers between 30 and 50
(A) 15
(B) 42
(C) 45
(D) 34
(E) 26
Rationale: Prime numbers between 30 and 50 are 37, 41, 43, 47
Required average = (37+ 41+ 43+ 47)/4 = 168/4 = 42
Answer is B
Answer: (B) 42
Question: For 6-digit integer 46x,y12, when x and y are drawn at random from {3,5,8}, what is the probability Q that the integer drawn is divisible by 8?
* A solution will be posted in two days.
(A) 1/6
(B) 1/3
(C) 1/2
(D) 2/3
(E) 5/6
Rationale: In general, the remainder divided by integer n is the same as the remainder that up to tens of n is divided by 8.
Thus, in order for 46,x,y12 to be divided by 8, y12 should be divided by 8.
Amongst 3,5,8, 3 and 5 can be divided by 8.
Therefore, Q=two out of three can be divided and the answer is D.
Answer: (D) 2/3
Question: A certain roller coaster has 4 cars, and a passenger is equally likely to ride in any 1 of the 4 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 4 times, what is the probability that the passenger will ride in each of the 4 cars?
(A) 0
(B) 1/9
(C) 2/9
(D) 3/32
(E) 1
Rationale: If he is to ride 4 times and since he can choose any of the 4 cars each time, total number of ways is
= 4 * 4 * 4 * 4
= 256
Now the number of ways if he is to choose a different car each time is
= 4* 3 * 2 * 1
= 24
So the probability is
= 24/256 =6/64=3/32
= 3/32
Answer : D
Answer: (D) 3/32
Question: A cycle is bought for Rs.900 and sold for Rs.1440, find the gain percent?
(A) 27%
(B) 20%
(C) 80%
(D) 30%
(E) 60%
Rationale: 900 ---- 540
100 ---- ? => 60%
Answer: E
Answer: (E) 60%
Question: A shopkeeper buys mangoes at the rate of 4 a rupee and sells them at 3 a rupee. Find his net profit or loss percent?
(A) 33 1/6
(B) 33 1/0
(C) 33 1/3
(D) 33 1/5
(E) 33 1/2
Rationale: The total number of mangoes bought by the shopkeeper be 12.
If he buys 4 a rupee, his CP = 3
He selling at 3 a rupee, his SP = 4
Profit = SP - CP = 4 - 3 = 1
Profit Percent = 1/3 * 100 = 33 1/3 %.Answer:C
Answer: (C) 33 1/3
Question: In year Y imported machine tools accounted for 25 percent of total machine - tool sales in the United States, and Japanese imports accounted for 45 percent of the sales of imported machine tools. If the total sales of machine tools imported Japan that year was x billion dollars, then the total sales of all machine tools in the United States was how many billion dollars?
(A) 9X/80
(B) 13X/20
(C) 80/9X
(D) 20X/13
(E) 80X/9
Rationale: IMT = 0.25T
JI = 0.45 IMT
0.45 IMT = $x b
IMT = $x/(0.45) b
T = 4*IMT = 4x/0.45 = 4x*100/45 = 80x/9
Ans: "E"
Answer: (E) 80X/9
Question: In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1200 employees, then the no. of female employees who are computer literate ?
(A) 504
(B) 674
(C) 672
(D) 960
(E) None
Rationale: Solution: Total employees,
= 1200
Female employees, 60% of 1200.
= (60 *1200) /100 = 720.
Then male employees,
= 480
50 % of male are computer literate,
= 240 male computer literate.
62 % of total employees are computer literate,
= (62 *1200) /100 = 744 computer literate.
Thus, Female computer literate = 744 - 240
= 504.
Answer: Option A
Answer: (A) 504
Question: 10 liters are drawn from a cask full of wine and is then filled with water. This operation is performed one more time . The ratio of the quantity of wine now left in cask to that of the water is 4:5. How much wine did the cask hold originally?
(A) 10
(B) 20
(C) 30
(D) 45
(E) 60
Rationale: Let the quantity of wine in the cask originally be x liters
quantity of wine left in cask after 2 operations = x(1 - 10/x)^2 liters
x(1 - 10/x)^2 /x = 4/9
(1-10/x)^2 = (2/3)^2
x = 30
Answer is C
Answer: (C) 30
Question: A guy was asked to specify his age in years. He said, “Take my age 6 years hence, multiply it by six and subtract six of my age 6 years ago and you will know my age.” What was the age of that guy?
(A) 18
(B) 35
(C) 53
(D) 69
(E) 72
Rationale: Current age of the guy = A years.
Then, 6 (A + 6) – 6 (A – 6) = A
(6A + 36) – (6A – 36) = A
A = 72
E
Answer: (E) 72
Question: What is the units digit of (493) (915) (381) (756) (28)
(A) 0
(B) 1
(C) 4
(D) 5
(E) 6
Rationale: Just multiply the digits in the units place for each term and you will get the answer. It should be 0. you got a 5 as a unit digit and an even number term. so the multiplication of this will definitely yield a 0. Answer has to be 0.
I also tried it using the calculator and the answer is 1.
IMO B.
Answer: (B) 1
Question: Look at this series: 25000,5000,1000, ... What number should come next?
(A) 17
(B) 10
(C) 15
(D) 200
(E) 8
Rationale: 200
This is a simple division series. Each number is divided by 5.
ANSWER D
Answer: (D) 200
Question: How much time will a train of length 380 m moving at a speed of 72 kmph take to cross another train of length 540 m, moving at 36 kmph in the same direction?
(A) 50
(B) 99
(C) 88
(D) 92
(E) 12
Rationale: The distance to be covered = Sum of their lengths = 380 + 540 = 920 m.
Relative speed = 72 -36 = 36 kmph = 36 * 5/18 = 10 mps.
Time required = d/s = 920/10 = 92 sec.
Answer:D
Answer: (D) 92
Question: A work could be completed in 100days by x workers. However, due to the absence of 10workers, it was completed in 110days. The original no.of workers was:
(A) 90
(B) 100
(C) 110
(D) 130
(E) 140
Rationale: sax Letlheo g alnumberofworkers hex
x workers can do the wor - 100 days
(x — 10) workers can do the work in 110 days
4 100x 1u1x— 10)
1100 Q x 110
C
Answer: (C) 110