mathewhe/aqua_rat huggingface dataset:
Question: An agent, gets a commission of 4% on the sales of cloth. If on a certain day, he gets Rs. 12.50 as commission, the cloth sold through him on that day is worth
(A) 312
(B) 500
(C) 887
(D) 299
(E) 132
Rationale: Explanation:
Let the total sale be Rs. x.
Then, 4%. of x = 12.50
= (4/100 * x) = 12.5<=> x = 312.5.
Answer: A
Answer: (A) 312
Question: In a certain region, the number of children who have been vaccinated against rubella is twice the number who have been vaccinated against mumps. The number who have been vaccinated against both is twice the number who have been vaccinated only against mumps. If 8,000 have been vaccinated against both, how many have been vaccinated only against rubella?
(A) 2,5000
(B) 7,500
(C) 10,000
(D) 15,000
(E) 16,000
Rationale: Use a single variable as far as possible.
Number vaccinated only against mumps = x
Number vaccinated against both = 2x = 8000 (so x = 4000)
Then, number vaccinated against mumps (including both) = x + 2x = 3x
Number vaccinated against rubella = 2*3x = 6x
Then, number vaccinated against only rubella = 6x - 2x = 4x = 4*4000 = 16,000
Answer (E)
Answer: (E) 16,000
Question: In what time will a railway train 60 m long moving at the rate of 36 kmph pass a telegraph post on its way?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: T = 60/36 * 18/5 = 6 sec
Answer:D
Answer: (D) 6
Question: In one hour, a boat goes 13 km along the stream and 5 km against the stream. The speed of the boat in still water (in km/hr) is:
(A) 2
(B) 4
(C) 9
(D) 12
(E) 15
Rationale: Sol.
Speed in still water = 1/2 (13+5) kmph = 9 kmph.
Answer C
Answer: (C) 9
Question: During a trip on an expressway, Don drove a total of x miles. His average speed on a certain 5-mile section of the expressway was 30 miles per hour, and his average speed for the remainder of the trip was 50 miles per hour. His travel time for the x-mile trip was what percent greater than it would have been if he had traveled at a constant rate of 60 miles per hour for the entire trip?
(A) 8.5%
(B) 50%
(C) x/12%
(D) 400/x%
(E) 500/x%
Rationale: Say x = 5 miles (so no remainder of the trip).
Time to cover x = 5 miles at 30 miles per hour = (time) = (distance)/(rate) = 5/30 = 1/6 hours = 10 minutes.
Time to cover x = 5 miles at 60 miles per hour = (time) = (distance)/(rate) = 5/50 = 1/10 hours = 5 minutes.
(Or simply, half rate will result in doubling the time.)
So, we can see that the time to cover x = 5 miles at 30 miles per hour (10 minutes) is 100% greater than the time to cover x = 5 miles at 60 miles per hour (5 minutes).
Now, plug x = 5 miles into the answer choices to see which one yields 100%. Only answer E works.
Answer: D.
Answer: (D) 400/x%
Question: A ratio between two numbers is 8:9 and their L.C.M. is 432. The first number is
(A) 60
(B) 45
(C) 50
(D) 48
(E) None
Rationale: Sol.
Let the required numbers be 8x and 9x. Then, their L.C.M. is 72x.
∴ 72x = 432⇔ x = 6. Hence, the first number is 48.
Answer D
Answer: (D) 48
Question: If an object travels at seven feet per second, how many feet does it travel in one hour?
(A) 30
(B) 300
(C) 720
(D) 25200
(E) 18000
Rationale: Speed = 7 feet per second.
1 Hour= 60X60 Seconds = 3600 Seconds.
Total no of feet traveled in 1 hour = 3600X7= 25200
Answer D
Answer: (D) 25200
Question: Mrs. Carolina. invested $9,000; part at 5%, and part at 8%. The total interest on the investment was $630. How much did she invest at each rate?
(A) x=$13,000, y =$26,000
(B) x=$4,000, y =$8,000
(C) x=$2,000, y =$4,000
(D) x=$3,000, y =$6,000
(E) x=$5,000, y =$10,000
Rationale: I approached this question like a mixture problem.
I don't like the wordingpartat 5% andpartat 8% because we have variables x and y in the answer choices and I have no idea which one is x or y.
Anyway here's how I did it.
0.05(x) + 0.08(y) = 0.07(x+y)
0.01(y) = 0.02(x)
y = 2x
Note: 0.07(x+y) because $630 is 7% of 9,000
In which answer choice is y = 2(x)
Answer D
Answer: (D) x=$3,000, y =$6,000
Question: A five-digit number divisible by 3 is to be formed using numerical 0, 1, 2, 3, 4 and 5 without repetition. The total number E of ways this can be done is:
(A) 122
(B) 210
(C) 216
(D) 217
(E) 225
Rationale: We should determine which 5 digits from given 6, would form the 5 digit number divisible by 3.
We have six digits: 0, 1, 2, 3, 4, 5. Their sum=15.
For a number to be divisible by 3 the sum of the digits must be divisible by 3. As the sum of the six given numbers is 15 (divisible by 3) only 5 digits good to form our 5 digit number would be 15-0={1, 2, 3, 4, 5} and 15-3={0, 1, 2, 4, 5}. Meaning that no other 5 from given six will total the number divisible by 3.
Second step:
We have two set of numbers:
1, 2, 3, 4, 5 and 0, 1, 2, 4, 5. How many 5 digit numbers can be formed using these two sets:
1, 2, 3, 4, 5 --> 5! as any combination of these digits would give us 5 digit number divisible by 3. 5!=120.
0, 1, 2, 4, 5 --> here we can not use 0 as the first digit, otherwise number won't be any more 5 digit and become 4 digit. So, desired # would be total combinations 5!, minus combinations with 0 as the first digit (combination of 4) 4! --> 5!-4!=4!(5-1)=4!*4=96
120+96=216=E
Answer: C.
Answer: (C) 216
Question: Calculate 42120 ÷ ? = 195
(A) 212
(B) 219
(C) 217
(D) 213
(E) 216
Rationale: Answer
Let 42120/X = 195
Then X = 42120/195 = 216
Option: E
Answer: (E) 216
Question: The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 60 metres?
(A) 11 seconds
(B) 77 seconds
(C) 76 seconds
(D) 12 seconds
(E) 17 seconds
Rationale: Speed of the boat downstream = 15 + 3 = 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 60 m = 60/5 = 12 seconds.
Answer:D
Answer: (D) 12 seconds
Question: 1/4 of all married couples have more than one child. 1/5 of all married couples have more than 3 children. What fraction of all married couples have 2 or 3 children?
(A) 1/5
(B) B.1/4
(C) 1/20
(D) 3/5
(E) It cannot be determined from the given information.
Rationale: Plug in simple numbers. Take 100 couples for example.
1/4 of 100 couples have more than one child = 25 couples.
1/5 of 100 couples have more than 3 kids = 20 couples.
This implies that 20 couples are a subset of 25 couples and the complement of 25 couples within those 100 couples, which equals 75 couples have either one or no kids at all.
We need to find couples that have 2 or 3 kids, so essentially, it is 25 - 20 = 5. Fraction will be 5/100 = 1/20.
Option C
Answer: (C) 1/20
Question: If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 1 year the amount to be paid is?
(A) 8118
(B) 8127
(C) 8618
(D) 7800
(E) 8128
Rationale: A = 7500(26/25)1
= 7800
Answer: D
Answer: (D) 7800
Question: Pumping alone at their respective constant rates, one inlet pipe fills an empty tank to 1/2 of capacity in 3 hours and a second inlet pipe fills the same empty tank to 2/3 of capacity in 4 hours. How many hours will it take both pipes, pumping simultaneously at their respective constant rates, to fill the empty tank to capacity?
(A) 3
(B) 3.6
(C) 4.2
(D) 4.4
(E) 5.5
Rationale: Time taken by First tank Fill 1/2 the tank = 3 hours
i.e. Time taken by First tank to Fill 1 complete the tank = 6 hours
Time taken by Second tank Fill 2/3 the tank = 4 hours
i.e. Time taken by First tank to Fill 1 complete the tank = (3/2)*4 = 6 hours
in 1 Hour, Both tanks together Fill the tank = (1/6)+(1/6) = 1/3 tank
i.e. Time taken by Both tank to Fill 1 complete the tank = 3 hours
A
Answer: (A) 3
Question: A man buys Rs. 48 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:
(A) s. 12
(B) s. 15
(C) s. 18
(D) s. 21
(E) s. 36
Rationale: Dividend on Rs. 48 = Rs.	9/100	x 48 =Rs.	4.32	.
Rs. 12 is an income on Rs. 100.
Rs.	4.32	is an income on Rs.100/12 x 4.32	= Rs. 36.
Answer: Option E
Answer: (E) s. 36
Question: A person can row at 9 kmph and still water. He takes 7 1/2 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 1 kmph?
(A) 60 km
(B) 87 km
(C) 33 km
(D) 67 km
(E) 20 km
Rationale: Let the distance between A and B be x km.
Total time = x/(9 + 1) + x/(9 - 1) = 7.5
=> x/10 + x/8 = 15/2 => (4x + 5x)/40 = 15/2 => x
= 33 km.
Answer:C
Answer: (C) 33 km
Question: Two prime numbers are considered consecutive if no other prime lies between them on the number line. If p1p1 and p2p2 are consecutive primes, with |p1–p2|>2, what is the smallest possible absolute value of the coefficient of the x term in the distributed form of the expression (x–p1)(x–p2)?
(A) 5
(B) 8
(C) 12
(D) 18
(E) 24
Rationale: (x−p1)∗(x−p2)=x2−(p1+p2)x+p1p2
Value of (p1+p2) will be min. for the min consecutive primes which satisfy |p1-p2|>2
So the min. value p1 & p2 can take = 7, 11
p1+p2= 7+11= 18
Answer. D
Answer: (D) 18
Question: Find the odd man out. 742, 743, 588, 853, 871, 990, 532
(A) 532
(B) 990
(C) 588
(D) 742
(E) None of these
Rationale: Explanation :
In all numbers except 588, the difference of third and first digit is the middle digit. Answer : Option C
Answer: (C) 588
Question: For a certain set of numbers, if x is in the set, then x - 4 is also in the set. If the number 1 is in the set , which of the following must also be in the set ?
a) 4
b) -3
c) -6
(A) a only,
(B) b only,
(C) c only,
(D) a and b only
(E) b and c only
Rationale: Notice that the question asks which of the following MUST be in the set, not COULD be in the set.
Since 1 is in the set, then so must be 1-4=-3. Similarly, since -3 is in the set, then so must be -3-3=-6. Could 4 and -1 be in the set? Certainly, but we don't know that for sure.
Answer: E.
Regarding your question: we don't know which is the source integer in the set, if it's 1, then 4 won't be in the set but if the source integer is say 7, then 4 will be in the set. So, 4 may or may not be in the set.
Answer: (E) b and c only
Question: Two trains of equal lengths take 12 sec and 20 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
(A) 17 sec
(B) 15 sec
(C) 16 sec
(D) 11 sec
(E) 18 sec
Rationale: Speed of the first train = 120/12 = 10 m/sec.
Speed of the second train = 120/20 = 6 m/sec.
Relative speed = 10 + 6 = 16 m/sec.
Required time = (120 + 120)/16 = 15 sec.
Answer:B
Answer: (B) 15 sec
Question: The owner of a furniture shop charges his customer 15% more than the cost price. If a customer paid Rs. 6400 for a computer table, then what was the cost price of the computer table?
(A) Rs.5565
(B) Rs.6298
(C) Rs.6290
(D) Rs.6725
(E) Rs.6708
Rationale: CP = SP * (100/(100 + profit%))
= 6400(100/115) = Rs.5565.
Answer: A
Answer: (A) Rs.5565
Question: A vender sold two things at same cost of 12 RS with one item at 25%profit and other at 20%loss,by this transaction he made profit or loss by how much
(A) 0.60 loss
(B) 0.70 loss
(C) 0.80 loss
(D) 0.50 loss
(E) 0.40 loss
Rationale: CP when profit of 25% = 9.60
CP when loss of 20% = 15
Total CP = 24.60
Total SP = 24.00
Total loss = 0.60
ANSWER:A
Answer: (A) 0.60 loss
Question: If a man buys 10 lollipops for $90 and sold them for $2 dollars determine his loss.
(A) 50
(B) 60
(C) 70
(D) 80
(E) 90
Rationale: Cost of 10 lollipops = $90
Sold each lollipop for $2
So he sold 10 lollipops for $(10 × 2) = $20
Loss = $(90 – 20) = $70
answer :C
Therefore, loss = $ 70.
Answer: (C) 70
Question: A shopkeeper sold an article offering a discount of 4% and earned a profit of 20%. What would have been the percentage of profit earned if no discount was offered?
(A) 25
(B) 28
(C) 30
(D) 32
(E) 34
Rationale: Let C.P. be Rs. 100.
Then, S.P. = Rs. 120
Let marked price be Rs. x. Then, 96/100 x = 120
x = 12000/96 = Rs. 125
Now, S.P. = Rs. 125, C.P. = Rs. 100
Profit % = 25%.
ANSWER:A
Answer: (A) 25
Question: In a division sum, the quotient is 20, the divisor 66 and the remainder 55, find the dividend?
(A) 1375
(B) 1376
(C) 1875
(D) 1365
(E) 1345
Rationale: Explanation:
20 * 66 + 55 = 1375
Answer : A
Answer: (A) 1375
Question: Aunt Marge is giving candy to each of her nephews and nieces. She has 20 pieces of candy and she gives all the candy to the children according to her wish. If Robert gets 2 more pieces than Kate, Bill gets 6 less than Mary, Mary gets 2 more pieces than Robert, and Kate gets 2 more pieces than Bill, how many pieces of candy does Kate get?
(A) 2
(B) 4
(C) 6
(D) 8
(E) 10
Rationale: Use the initial letter of each name as a variable:
r=k+2
b=m−6
m=r+2
k=2+bk==r−2
b=k−2=(r−2)−2=r−4
m=r+2
r+b+m+k=20
r+r−4+r+2+r−2=20
r=6
k=r−2=6−2=4
Answer: B
Answer: (B) 4
Question: Ravi purchased a refrigerator and a mobile phone for Rs. 10000 and Rs. 8000 respectively. He sold the refrigerator at a loss of 4 percent and the mobile phone at a profit of 10 percent. Overall he make a.
(A) loss of Rs. 200
(B) loss of Rs. 100
(C) profit of Rs. 100
(D) profit of Rs. 400
(E) None of these
Rationale: Total C.P. = 10000+8000 = 18000
S.P. of fridge = 10000/100*96= 9600
S.P. of Mobile = 8000/100*110 = 8800
Total S.P. = 9600 + 8800 = 18400
Tota. S.P. - Total C.P. = 18400 - 18000 = 400
Answer : D
Answer: (D) profit of Rs. 400
Question: My brother is 2 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 1 years of age of when my brother was born, then, what was the age of my father and mother respectively when my brother was born?
(A) 32 yrs, 23 yrs
(B) 30 yrs, 25 yrs
(C) 35 yrs, 29 yrs
(D) 35 yrs, 33 yrs
(E) none
Rationale: Sol.
Clearly, my brother was born 2 years before I was born and 1 years after my sister was born.
So, father's age when brother was born = (28 + 2) = 30 years.
mother's age when was born = (26 - 1) years = 25 years.
Answer B
Answer: (B) 30 yrs, 25 yrs
Question: Two dogsled teams raced across a 200-mile course in Alaska. Team A finished the course in 2 fewer hours than team B. If team A’s average speed was 5 miles per hour greater than that of team B, what was team B’s average speed, in miles per hour?
(A) 12
(B) 15
(C) 18
(D) 20
(E) 25
Rationale: Let v be team B's average speed.
Time = Distance/Rate and the time difference was 2 hours.
200/v - 200/(v+5)= 2
200v + 1000 - 200v = 2(v)(v+5)
500 = (v)(v+5)
(20)(25) = (v)(v+5)
v = 20 mph
The answer is D.
Answer: (D) 20
Question: When the integer n is divided by 17, the quotient is x and the remainder is 7. When n is divided by 23, the quotient is y and the remainder is 14. Which of the following is true?
(A)  23x + 17y =19
(B)  17x –23y = 7
(C)  17x +23y =19
(D)  14x + 5y = 6
(E)  5x – 14y = -6
Rationale: From the problem it follows:
n=17x+7
n=23y+14
So, 17x+7=23y+14
17x-23y=7
The answer is B
Answer: (B)  17x –23y = 7
Question: If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. What is the actual distance travelled by him?
(A) 33
(B) 11
(C) 38
(D) 50
(E) 12
Rationale: Assume that the person would have covered x km if travelled at 10 km/hr
⇒Speed = DistanceTime=x10.....(Equation1)
Give that the person would have covered (x + 20) km if travelled at 14 km/hr
⇒Speed = DistanceTime=(x+20)14.....(Equation2)
From Equations 1 and 2,
x10=(x+20)1414x=10x+2004x=200x=2004=50
Answer : D
Answer: (D) 50
Question: R is the set of positive odd integers less than 40, and S is the set of the squares of the integers in R. How many elements does the intersection of R and S contain ?
(A) None
(B) Three
(C) Four
(D) Five
(E) Seven
Rationale: squares < 40 {1,4,9,16,25,36}
S = {1,9,25}
R = {1,3,.....40}
Hence B.
Answer: (B) Three
Question: A straight fence is to be constructed from posts 7 inches wide and separated by lengths of chain 5 feet long. If a certain fence begins and ends with a post, which of the following couldnotbe the length of the fence in feet? (12 inches = 1 foot)
(A) 17
(B) 28
(C) 35
(D) 39
(E) 50
Rationale: The fence begins and ends with a post: {post = 0.5 feet}{chains = 5 feet}{post = 0.5 feet}...{chains = 5 feet}{post = 0.5 feet}
The minimum length is with 2 posts = 0.5 + 5 + 0.5 = 6 feet. To increase the fence, each time we should add{post = 0.5 feet}{chains = 5 feet}, so 5.5 feet. Thus, the lengths could be:
6 feet;
7+ 5.5 = 12.5 feet;
11.5 + 5.5 = 18 feet;
17 + 5.5 = 23.5 feet;
22.5 + 5.5 = 29feet;
28 + 5.5 = 34.5 feet;
33.5 + 5.5 = 40 feet.
...
We skipped 39 feet.
Answer: D.
Answer: (D) 39
Question: Anu normally takes 4 hours more than the time taken by Sachin to walk D km. If Anu doubles her speed, she can make it in 2 hours less than that of Sachin. How much time does Sachin require for walking D km?
(A) 10 hours
(B) 4 hours
(C) 8 hours
(D) 9 hours
(E) None
Rationale: Explanation :
Let Sachin takes x hours to walk D km.
Then, Anu takes (x + 4) hours to walk D km.
With double of the speed, Anu will take (x + 4)/2 hours.
x – (x + 4)/2 = 2
=> 2x – (x + 4) = 4
=> 2x – x – 4 = 4
x = 4 + 4 = 8 hours
Answer – C
Answer: (C) 8 hours
Question: Convert the following into a fraction: 0.5%
(A) 1/5
(B) 1/2
(C) 5/10
(D) 2/5
(E) None of the Above
Rationale: 0.5 =5/10 (Simplify: both are divisible by 5)= 1/2
Answer is B.
Answer: (B) 1/2
Question: If 5 < x < 12 and y = x + 3, what is the greatest possible integer value of x + y?
(A) 23
(B) 24
(C) 25
(D) 26
(E) 27
Rationale: x+y = x+x+3 = 2x+3
We need to maximize this value and it needs to be an integer.
2x is an integer when the decimal of x is .0 or .5
The largest such value is 11.5
Then x+y = 11.5 + 14.5 = 26.
The answer is D.
Answer: (D) 26
Question: The average weight of 9 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What is the weight of the new person?
(A) 85.5
(B) 86.5
(C) 87.5
(D) 88.5
(E) 89.5
Rationale: Total increase in weight =9 × 2.5 = 22.5
If x is the weight of the new person, total increase in weight = x−65
=> 22.5 = x - 65
=> x = 22.5 + 65 = 87.5
ANSWER:C
Answer: (C) 87.5
Question: Ron begins reading a book at 4: 30 p.m. and reads at a steady pace of 30 pages per hour. Michelle begins reading a copy of the same book at 6: 00 p.m. If Michelle started 5 pages behind the page that Ron started on and reads at an average pace of 50 pages per hour, at what time would Ron and Michelle be reading the same page?
(A) 7: 00 p.m.
(B) 7: 30 p.m.
(C) 7: 45 p.m.
(D) 8: 00 p.m.
(E) 8: 30 p.m.
Rationale: Ron's speed is 30 pages per hour =1/2 page per minute
Time at which he starts reading is 4:30 pm
now,
by the time Michelle beings reading (6:00 pm) Ron has already covered (1/2)*90=45 pages
as per the question
Michelle starts 5 pages behind the page Ron started and her speed is 5/6 pages per minute
relative speed = 5/6-1/2=1/3
pages left =45+5=50
time taken to read those pages =50/(1/3)=150 minutes
Thus time taken to reach the same page
6:00 pm + (150 minutes) =8:30 pm
ANSWER:E
Answer: (E) 8: 30 p.m.
Question: By selling an article at Rs.120, a profit of 25% is made. Find its cost price?
(A) s.96
(B) s.45
(C) s.120
(D) s.180
(E) s.189
Rationale: SP = 120
CP = (SP)*[100/(100+P)]
= 120* [100/(100+25)]
= 120* [100/125]
= Rs.96
Answer: A
Answer: (A) s.96
Question: Mudit's age 16 years hence will be thrice his age four years ago. Find Mudit's present age?
(A) 14
(B) 19
(C) 27
(D) 18
(E) 15
Rationale: Explanation:
Let Mudit's present age be 'm' years.
m + 16 = 3(m - 4)
=> 2m = 28 => m = 14 years.
Answer:A
Answer: (A) 14
Question: Anna left for city A from city B at 5.20 a.m. She travelled at the speed of 80 km/hr for 2 hrs 15 min. After that the speed was reduced to 60 km/hr. If the distance between two cities is 350 kms, at what time did Anna reach city A?
(A) 10.25 a.m
(B) 9.25 a.m
(C) 11.25 a.m
(D) 12.25 a.m
(E) 01.25 a.m
Rationale: A
10.25 a.m
Distance covered in 2 hrs 15 min i.e., 2 1/4 hrs = 80 * 9/4 = 180 hrs.
Time taken to cover remaining distance = (350 - 180)/60 = 17/6 hrs
= 2 5/6 = 2 hrs 50 min
Total time taken = (2 hrs 15 min + 2 hrs 50 min) = 5 hrs 5 min.
So, Anna reached city A at 10.25 a.m.
Answer: (A) 10.25 a.m
Question: John and Karen begin running at opposite ends of a trail until they meet somewhere in between their starting points. They each run at their respective constant rates until John gets a cramp and stops. If Karen runs 50% faster than John, who is only able to cover 25% of the distance q before he stops, what percent longer would Karen have run than she would have had John been able to maintain his constant rate until they met.
(A) 25%
(B) 50%
(C) 75%
(D) 100%
(E) 200%
Rationale: John and Karen begin running at opposite ends of a trail until they meet somewhere in between their starting points. They each run at their respective constant rates until John gets a cramp and stops. If Karen runs 50% faster than John, who is only able to cover 25% of the distance q before he stops, what percent longer would Karen have run than she would have had John been able to maintain his constant rate until they met.
Lets say the distance of the trail is 100 miles. Lets also say that J rate = 10 miles/hour and K rate = 15 miles/hour.
If John stops at the 25% mark that means he travels 25 miles in 2.5 hours. It would take Karen t=d/r t=75/15 = 5 hours to reach john. If John had not stopped, their combined rate would 10+15 = 25 miles/hour meaning they would have met in 4 hours. Therefore, she ran one hour longer (25%) longer than she would have needed to if John ran for the entire time.
ANSWER: A) 25%
Answer: (A) 25%
Question: A began business with Rs.45000 and was joined afterwards by B with Rs.5400. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
(A) 5
(B) 6
(C) 7
(D) 9
(E) 3
Rationale: 45*12 : 54*x = 2: 1
x = 5
12 -5 = 7
Answer:C
Answer: (C) 7
Question: The equal amounts of money are deposited in two banks each at 15% per annum for 3.5 years and 10 years respectively. If the difference between their interests is Rs.144, find the each sum?
(A) Rs.117.69
(B) Rs.147.69
(C) Rs.137.69
(D) Rs.157.69
(E) Rs.127.69
Rationale: (P*10*15)/100 - (P*3.5*15)/100 = 144
=> P = Rs.147.69
ANSWER:B
Answer: (B) Rs.147.69
Question: A person's present age is two-fifth of the age of his mother. After 8years, he will be one - half of the age of his mother. How old is the mother at present ?
(A) 25
(B) 40
(C) 32
(D) 45
(E) 28
Rationale: Let the mother's present age be x years
Then the person's present age = 2x/5
(2x/5)+8 = 1/2(x+8)
2(2x+40) = 5 (x+8)
x = 40
Answer is B
Answer: (B) 40
Question: A group of men decided to do a work in 20days, but 2 of them became absent. If the rest of the group did the work in 22days, Find the original number of men?
(A) 15
(B) 22
(C) 27
(D) 29
(E) 18
Rationale: Original number of men = 2*22 / (22-20) = 22
Answer is B
Answer: (B) 22
Question: If the weight of 13 meters long rod is 23.4 kg. What is the weight of 6 meters long rod ?
(A) 7.2 kg.
(B) 10.8 kg.
(C) 12.4 kg.
(D) 18.0 kg
(E) None
Rationale: Answer
∵Weight of 13 m long rod = 23.4 kg
∴ Weight of 1 m long rod = 23.4 / 13 kg
∴ Weight of 6 m long rod = 23.4 x 6 / 13
= 10.8 kg
Option: B
Answer: (B) 10.8 kg.
Question: The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
(A) 1520 m2
(B) 2420 m2
(C) 2480 m2
(D) 2520 m2
(E) None
Rationale: EXPLANATION
We have: (l – b) = 23 and 2(l + b) = 206 or (l + b) = 103.
Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) m2 = 2520 m2.
Answer D
Answer: (D) 2520 m2
Question: A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
(A) 40 minutes
(B) 1 hour
(C) 1 hr 15 min
(D) 1 hr 30 min
(E) 1 hr 40 min
Rationale: 2km in 1hr=2km/hr
1 km in 10 minutes means [1/10]*60=6km/hr
speed in still water is=1/2(6+2)=4km/hr
Required time=[5/4]hrs means 1hr 15 minutes
ANSWER:C
Answer: (C) 1 hr 15 min
Question: John walked to the bus stop at a speed of 3 kph, but walked home at a speed of 6 kph. What was his average speed walking to and from the bus stop?
(A) 9 kph
(B) 3 kph
(C) 4.5 kph
(D) 6 kph
(E) 18 kph
Rationale: (3 kph + 6 kph)/2= 4.5 kph
Correct answer is C
Answer: (C) 4.5 kph
Question: A word is defined as a sequence of four dots arranged in a row. Each dot is colored either yellow or blue. How many distinct words can be formed?
(A) 4
(B) 8
(C) 12
(D) 16
(E) 20
Rationale: 2^4 = 16
The answer is D.
Answer: (D) 16