mathewhe/aqua_rat huggingface dataset:
Question: The fourth proportional to 5, 8, 15 is
(A) 18
(B) 19
(C) 20
(D) 24
(E) None
Rationale: Sol.
Let the fourth proportional to 5, 8, 15 be x.
Then, 5 : 8 : : 15 : x ⇔ 5x = (8x15)
⇔ x = (8x15) / 5 = 24.
Answer D
Answer: (D) 24
Question: A motorcyclist goes from Bombay to Pune, a distance of 128 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
(A) 1:3
(B) 1:5
(C) 1:4
(D) 1:1
(E) 1:8
Rationale: T = 128/32 = 4 h
T = 4 - 3 = 1
Time Ratio = 4:1 = 4:1
Speed Ratio = 1:4
Answer: C
Answer: (C) 1:4
Question: Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours. C is closed A and B can fill the remaining par in 7 hours. The number of hours taken by C alone to fill the tank is?
(A) 15 hours
(B) 13 hours
(C) 14 hours
(D) 12 hours
(E) 19 hours
Rationale: Part filled in 2 hours = 2/6 = 1/3.
Remaining part = 1 - 1/3 = 2/3
(A + B)'s 1 hour work = 2/21
C's 1 hour work = [(A + B + C)'s 1 hour work - (A + B)'s 1 hour work]
= (1/6 - 2/21) = 1/14
C alone can fill the tank in 14 hours.
Answer:C
Answer: (C) 14 hours
Question: A can run 4 times as fast as B and gives B a start of 72 m. How long should the race course be so that A and B might reach in the same time?
(A) 70 m
(B) 60 m
(C) 80 m
(D) 65 m
(E) 96 m
Rationale: Speed of A:Speed of B=4:1
means in a race of 4m A gains 3m.
then in a race of 72m he gains 72*(4/3)
I.e 96m
ANSWER:E
Answer: (E) 96 m
Question: Using all the letters of the word "THURSDAY", how many different words can be formed?
(A) 7
(B) 8
(C) 2
(D) 9
(E) 6
Rationale: Explanation:
Total number of letters = 8
Using these letters the number of 8 letters words formed is = 8.
Answer: B
Answer: (B) 8
Question: How many integers n are there such that 1< 5n + 4 < 24?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: 1< 5n + 4 < 24
We first subtract 4 from all three parts of the inequality, and we obtain:
-3 < 5n < 20
Next, we divide both sides of the inequality by 5 and we get:
-3/5 < n < 4
The answer is D
Answer: (D) 4
Question: The value of (34.31*0.473*1.567)/(0.5*23.25*7.57) is close to
(A) 2
(B) 1.15
(C) 2.05
(D) 0.29
(E) 2.35
Rationale: (34.31*0.473*1.567)/(0.5*23.25*7.57) = 25.4303/88.00125
= 0.29
ANSWER:D
Answer: (D) 0.29
Question: The radius of a semi circle is 6.3 cm then its perimeter is?
(A) 32.8
(B) 32.4
(C) 32.1
(D) 32.2
(E) 32.9
Rationale: 36/7 r = 6.3
= 32.4
Answer:B
Answer: (B) 32.4
Question: Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability W that Jane will be on the same committee as Albert?
(A)  12%
(B)  20%
(C)  33%
(D)  40%
(E)  50%
Rationale: Total number of ways to choose 3 member committee - 6C3=(6!/3!3!)=20
No. of ways Albert n Jane are in same committee:- (4C1 * 2)= 8
Probability W= (8/20) *100 =40%.
+1 for me.. :D
Answer: (D)  40%
Question: Raffle tickets numbered consecutively from 101 through 350 are placed in a box. What is the probability that a ticket selected at random will have a number with a hundreds digit of 2 ?
(A) 2/5
(B) 2/7
(C) 33/83
(D) 99/250
(E) 100/249
Rationale: The number of integers from 101 to 350, inclusive is 250, out of which 100 (from 200 to 299) will have a hundreds digit of 2. Thus the probability is 100/250=2/5.
Answer: A.
Answer: (A) 2/5
Question: A man can row 7 ½kmph in still water. If in a river running at 1.5 km an hour, it takes him 50 minutes to row to a place and back, how far off is the place?
(A) 3 km
(B) 4 km
(C) 5 km
(D) 6 km
(E) None
Rationale: Sol.
Speed downstream = (7.5 + 1.5) kmph = 9 kmph;
Speed upstream = (7.5 - 1.5) kmph = 6 kmph.
Let the required distance be x km. Then,
x/9 + x/6 = 50/60 ⇔ 2x + 3x = [5/6 * 18] ⇔ 5x = 15 ⇔ x =3.
Hence, the required distance is 3 km.
Answer A
Answer: (A) 3 km
Question: The perimeter of a square is 24 m. Find the area of the square.
(A) 161 mÂ².
(B) 36 mÂ².
(C) 46 mÂ².
(D) 169 mÂ².
(E) 33 mÂ².
Rationale: Perimeter of square = 24 m
But perimeter of square = 4 Ã— side
Therefore, 4 Ã— side = 24 m
Therefore, side= 24/4 m = 6m
Now, the area of the square = (side Ã— side)
Therefore, area of the square = 6 Ã— 6 mÂ² = 36 mÂ².
ANSWER : OPTION B
Answer: (B) 36 mÂ².
Question: There are 84 supermarkets in the FGH chain. All of them are either in the US or Canada. If there are 10 more FGH supermarkets in the US than in Canada, how many FGH supermarkets are there in the US?
(A) 20
(B) 31
(C) 42
(D) 47
(E) 64
Rationale: x + (x - 10) = 84 --> x = 47.
Answer: D.
Answer: (D) 47
Question: What is the sum of the multiples of 5 from 80 to 140, inclusive?
(A) 560
(B) 780
(C) 990
(D) 1008
(E) 1200
Rationale: The formula we want to use in this type of problem is this:
Average*Total Numbers=Sum
First, find the average by taking the sum of the F + L number and divide it by 2:
A = (F + L)/2
Second, find the total numbers in our range by dividing our F and L numbers by 5 and add 1.
(140/5) - (80/5) + 1
Multiply these together so what we show Average*Total Numbers=Sum
(80 + 140)/2 * (140/5) - (80/5) + 1 = Sum
110 * 9 = 990
C
Answer: (C) 990
Question: In 10 years, A will be twice as old5as B was 10 years ago. If A is now 9 years older than B, the present age of B is
(A) 35
(B) 37
(C) 39
(D) 41
(E) 44
Rationale: Explanation:
Let B's age = x years.
Then, As age = (x+ 9) years.
(x+9+10)=2(x—10)
hence x=39.
Present age of B = 39 years
Option C
Answer: (C) 39
Question: Jim’s Taxi Service charges an initial fee of $2.45 at the beginning of a trip and an additional charge of $0.35 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles?
(A) $3.15
(B) $4.45
(C) $4.80
(D) $5.05
(E) $5.6
Rationale: Let the fixed charge of Jim’s Taxi Service = 2.45 $
and charge per 2/5 mile(.4 mile) = .35$
Total charge for a trip of 3.6 miles = 2.45 + (3.6/.4) * .35
= 2.45 + 9*.35
= 5.6 $
Answer E
Answer: (E) $5.6
Question: If x and y are prime numbers such that x > y > 4, then x^2 − y^2 must be divisible by which one of the following numbers?
(A)  7
(B)  8
(C)  5
(D)  9
(E)  13
Rationale: If x=7 and y=5, then x^2-y^2=24 and 24 is divisible only by 8 from the options, thus it must be correct.
Answer: B.
Answer: (B)  8
Question: A university needs to select a nine-member committee on extracurricular life, whose members must belong either to the student government or to the student advisory board. If the student government consists of 9 members, the student advisory board consists of 8 members, and 5 students hold membership in both organizations, how many different committee are possible?
(A) 140
(B) 180
(C) 220
(D) 260
(E) 300
Rationale: student government + the student advisory board consists of 9 + 8 = 17 members.
5 students hold membership in both, so they were counted twice.
The total number of people to choose from is 17 - 5 = 12
The number of ways to choose 9 members from 12 is 12C9 = 220
The answer is C.
Answer: (C) 220
Question: A gets 3 times as much money as B gets, B gets only Rs.25 more then what C gets. The three gets Rs.655 in all. Find the share of B?
(A) 130
(B) 120
(C) 218
(D) 140
(E) 136
Rationale: A+B+C = 655
A = 3B
3B+B+B-25 = 655
5B = 680
B = 136
Answer: E
Answer: (E) 136
Question: If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference E between the greatest and least of the five integers?
(A) 4K
(B) 4k^2 -4k
(C) 4-4k
(D) 4
(E) 4k+4
Rationale: (n-2 + n - 1 + n + n + 1 + n + 2)/5 = 2k - 1
=> n = 10k - 5
Greatest = n + 2 = 10k - 5 + 2 = 10k - 3
Least = n - 2 = 10k - 5 - 2
=> Difference E= 10k - 3 - (10k - 7)
= 4
Answer - D
Answer: (D) 4
Question: A birthday child reaches into a bag filled with toys (1 yo-yo, 1 ball, 1 whistle, and 1 box crayons). If the child randomly picks three toys, what is the probability the child will pick the yo-yo and a ball as two of the three toys?
(A) 1/3
(B) 1/2
(C) 1/4
(D) 1/5
(E) 2/5
Rationale: Combination Formula: nCr = n!/(r!(n - r)!), where n is the population/set, and r is the sample/subset.
Total number possible = 4C3 - 4!/(3!(4 - 3)!) = 4
Number yo-yo possible = 1C1 = 1
Number ball possible = 1C1 = 1
Number other possible = 2C1 = 2
Probability Formula: P(A) = (Number Favorable Outcomes)/(Total Number Possible Outcomes)
P(YB) = (1C1)(1C1)(2C1)/4C3 = 2/4 = 1/2
Answer: B
Answer: (B) 1/2
Question: Two airplanes take off from one airfield at noon. One flies due east at 206 miles per hour while the other flies directly northeast at 283 miles per hour. Approximately how many miles apart are the airplanes at 2 p.m.?
(A) 412
(B) 332
(C) 400
(D) 483
(E) 566
Rationale: A
In two hours:
the plane flying East will be 412 miles away from airport.
the other plane will be 566 miles away from airport.
566/412 = ~1.4 = ~sqrt(2)
This means that planes formed a right isocheles triangle => sides of such triangles relate as 1:1:sqrt(2) => the planes are 412 miles apart.A
Answer: (A) 412
Question: In a city, the bus route numbers consist of a natural number less than 100, followed by one of the letters A,B,C,D,E and F. How many different bus routes are possible?
(A) 500
(B) 594
(C) 588
(D) 700
(E) 600
Rationale: The number can be any one of the natural numbers from 1 to 99.
There are 99 choices for the number.
The letter can be chosen in 6 ways.
Number of possible bus routes are 99Ã—6=99Ã—6= 594
ANSWER B
Answer: (B) 594
Question: If x > 7, which of the following is equal to (x^2 - 8x + 16)/(x^2 - 16) ?
(A) (x + 4)/(4(x - 4))
(B) (x - 4)/(x + 4)
(C) (x - 2)/(x + 4)
(D) (x + 4)/(x - 4)
(E) (x - 8)/(x - 4)
Rationale: (x^2 - 8x + 16)/(x^2 - 16)
= (x - 4)(x - 4) / (x + 4)(x - 4)
=(x - 4)/(x + 4)
B. (x - 4)/(x + 4)
Answer: (B) (x - 4)/(x + 4)
Question: Hulk is older than Pedro. Pedro is younger than Ozil and younger than Ronaldo. Ronaldo is older than Hulk and Nani, who are older than Ozil.If Nani and Hulk are twins, who's oldest?
(A) Ronaldo
(B) Pedro
(C) Hulk
(D) Ozil
(E) Nani
Rationale: A
Ronaldo
Answer: (A) Ronaldo
Question: A certain stock exchange designates each stock with a 1, 2 or 3 letter code, where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order, constitute a different code, how many diff stocks is it possible to designate with these codes?
(A) 2,951
(B) 8,125
(C) 15,600
(D) 16,302
(E) 18,278
Rationale: 1 letter code - 26 (or you can write 26C1)
2 letter code - 26*26=26^2 (or you can write 26C1*26C1=26^2)
3 letter code - 26*26*26=26^3 (or you can write 26C1*26C1*26C1=26^3)
(For 2 letter, for example, you have 26 choices per each letter, it's 26^2 and not 26C2 or 26P2.)
Total =26+26^2+26^3 =18,278
So the answer is E.
Answer: (E) 18,278
Question: 12 years ago, the age of Anand was one-third the age of Bala at that time. The present age of Bala is 12 years more than the present age of Anand. Find the present age of Anand?
(A) 13
(B) 14
(C) 15
(D) 16
(E) 18
Rationale: Let the present ages of Anand and Bala be 'a' and 'b' respectively.
a - 12 = 1/3 (b - 12) --- (1)
b = a + 12
Substituting b = a + 12 in first equation,
a - 12= 1/3 (a +0) => 3a - 36 = a
=> 2a = 36 => a = 18.
ANSWER:E
Answer: (E) 18
Question: A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it?
(A) 13 1/3 days
(B) 8 days
(C) 9 days
(D) 63 days
(E) 15 days
Rationale: Explanation:
5/30 + 20/x = 1
x = 24
1/30 + 1/24 = 3/40
40/3 = 13 1/3 days
Answer A
Answer: (A) 13 1/3 days
Question: The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is?
(A) 65
(B) 21
(C) 78
(D) 67
(E) 51
Rationale: Let the total number of workers be x. Then,
8000x = (12000 * 7) + 6000(x - 7)
= 2000x = 42000
= x = 21.
Answer: B
Answer: (B) 21
Question: Which of the following CANNOT be true if the sum of k consecutive integers is 0, where k ≥ 1 ?
I. The product of the k integers is positive
II. The smallest of the k integers is zero
III. The largest of the k integers is negative
(A) I only
(B) II only
(C) III only
(D) I and III
(E) I, II and III
Rationale: for the sum of k consecutive integers to be 0 we have at least k=1 as 0
or if k=3 then 1,0,-1
1) product will be 0 every time......Not True
2)as stated earlier if k=1 as 0 then 0 is the highest as well lowest number.....Could be True
3) largest number can only be 0 if K=1 or any +ve integer if K>1--------->largest integer be -ve Never true.
Ans D
Answer: (D) I and III
Question: In 2003, the number of girls attending Jefferson High School was equal to the number of boys. In 2004, the population of girls and the population of boys both increased by 20 percent. Which of the following could be the total student population at Jefferson High School in 2004?
(A) 4832
(B) 5034
(C) 5058
(D) 5076
(E) 5128
Rationale: What you forgot to consider here is that x and x/2, both, should be integers. This means, after you divide the option by 6 and get x (after multiplying by 5 which doesn't matter), it should again be divisible by 2. Hence, the option must be successively divisible by 6 and 2 i.e. it must be divisible by 12 i.e by 3 as well as 4.
We see that (C) and (D) are both divisible by 3. But only (D) is divisible by 4.
Answer (D)
Answer: (D) 5076
Question: Two cyclists are moving towards each other at 10 miles/hour. They are now 50 miles apart. At this instance a fly starts from one cyclist and move towards other and moves to and fro till the two cyclist meet each other. If the fly is moving at 15 miles/hour, what is the total distance covered by the fly?
(A) 37.5 miles
(B) 38.5 miles
(C) 39.5 miles
(D) 36.5 miles
(E) 35.5 miles
Rationale: time taken by cyclists to meet = 50/20 2.5 hrs
distance covered by fly during 2.5 hrs = 15*2.5 = 37.5 miles
ANSWER:A
Answer: (A) 37.5 miles
Question: P can lay railway track between two stations in 16 days. Q can do the same job in 12 days. With the help of R, they completes the job in 4 days. How much days does it take for R alone to complete the work?
(A) 8(3/5) Days
(B) 9(3/5) Days
(C) 7(3/5) Days
(D) 6(3/5) Days
(E) 5(3/5) Days
Rationale: Amount of work P can do in 1 day = 1/16
Amount of work Q can do in 1 day = 1/12
Amount of work P, Q and R can together do in 1 day = 1/4
Amount of work R can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48
=> Hence R can do the job on 48/5 days = 9 (3/5) days
Answer is B.
Answer: (B) 9(3/5) Days
Question: How many different 7 digit numbers can be formed from the number 3589463 by re-arranging its digits so that the odd digits occupy even position
(A) 1
(B) 5
(C) 9
(D) 72
(E) 34
Rationale: There are 4 odd numbers which have to be placed at 4 even places =4!/2!=12 ways
There are 3 even numbers which have to be placed at 3 odd places. So 3! = 6 ways
so total number of ways of arranging all these numbers are 12 * 6 = 72 ways
Answer:D
Answer: (D) 72
Question: During a certain two-week period, 60 percent of the movies rented from a video store were comedies, and of the remaining movies rented, there were 4 times as many dramas as action movies. If no other movies were rented during that two-week period and there were A action movies rented, then how many comedies, in terms of A, were rented during that two-week period?
(A) 14
(B) 12
(C) 10
(D) 8
(E) 7.5
Rationale: Total movies = 100.
Comedies = 60.
Action + Drama = 40. Since there were 5 times as many dramas as action movies, then Action + 4*Action = 40 --> Action = A = 8.
Comedies = 60 = 7.5A.
Answer: E
Answer: (E) 7.5
Question: Find the probability that a leap year chosen at random will have 53 Sundays
(A) 2/7
(B) 2/6
(C) 2/5
(D) 2/3
(E) 2/4
Rationale: A leap year has 366 day which is 52 full weeks + 2 odd days. Now these two odd days may be (sun + mon), (mon + tue), .... (Sat + sun). Now there are total 7 ways. Of which Sunday appeared two times. So answer 2/7
Answer:A
Answer: (A) 2/7
Question: A jar contains only three types of objects: red, blue, and silver paper clips. The probability of selecting a red paper clip is 1/20, and the probability of selecting a blue paper clip is 1/10. What is the probability of selecting a silver paper clip?
(A)  5/12
(B)  1/20
(C)  17/20
(D)  3/4
(E)  11/20
Rationale: Prob of Red = 1/20
Prob of Blue = 1/10
Prob of Silver = ?
P(Silver) = 1 - P(Red) - P(Blue) ==> 1-1/20-1/10 = 7/12
Ans: C
Answer: (C)  17/20
Question: How many positive integers between 20 and 2000(both are inclusive) are there such that they are multiples of 10?
(A) 201
(B) 193
(C) 200
(D) 199
(E) 195
Rationale: Multiples of 10 = 20,30,40-----,1990,2000
Number of multiples of 10 => 2000-20/10+1= 199
Answer is D
Answer: (D) 199
Question: 700 students took the test on English and Maths. 35% students failed in english and 45% failed in maths. 40% of those who passed in maths also passed in english, then how many students failed in both ?
(A) a) 14
(B) b) 138
(C) c) 60
(D) d) 38
(E) e) 12
Rationale: Passed in english = 65%
Passed in maths = 55%
Passed in both = 40% of 55% = 2/5 * (55%) = 22%
Passed in (English + Maths - Both + Neither) = 100%
65 + 55 - 22 + Neither = 100
Neither = 100 - 98 = 2% = 0.02 * 700 = 14
Answer: A
Answer: (A) a) 14
Question: Bus X is 12 miles ahead of Bus Y, which is traveling the same direction along the same route as Bus X. If Bus X is traveling at an average speed of 41 miles per hour and Bus Y is traveling at an average speed of 57 miles per hour, how long will it take Bus Y to overtake and drive 4 miles ahead of Bus X?
(A) 2 hours
(B) 1 hour
(C) 2 hours 20 minutes
(D) 3 hours 45 minutes
(E) 5 hours
Rationale: Relative speed = 57-41 = 16 miles per hour
Dist required = 12+4 = 16 miles
Time taken to overtake = 16/16 = 1 hour. B is the answer.
Answer: (B) 1 hour
Question: How many digits are in (8×10^12)(10×10^9)?
(A) 20
(B) 23
(C) 26
(D) 27
(E) 28
Rationale: The question simplfies to (8×10^12)(10^10)
=> 8*10^22
=> Will contain 22 zeros +1 digit 8
=>23
Ans B
Answer: (B) 23
Question: The divisor is 12, the quotient is 4 and the remainder is 1.
What is the dividend?
(A) 48
(B) 49
(C) 96
(D) 97
(E) 72
Rationale: D = d * Q + R
D = 12 * 4 + 1
D = 48 + 1
D = 49
Answer: B
Answer: (B) 49
Question: If a person walks at 5 km/hr instead of 4 km/hr, he would have walked 6 km more. The actual distance traveled by him is?
(A) 14
(B) 20
(C) 18
(D) 24
(E) 21
Rationale: Let the actual distance traveled be x km. Then,
x/4 = (x + 6)/5
x - 24=>x = 24km.
Answer: D
Answer: (D) 24
Question: During a certain two-week period, 50 percent of the movies rented from a video store were comedies, and of the remaining movies rented, there were 9 times as many dramas as action movies. If no other movies were rented during that two-week period and there were A action movies rented, then how many comedies, in terms of A, were rented during that two-week period?
(A) 5 A
(B) 10 A
(C) 20 A
(D) 25 A
(E) 28 A
Rationale: Movies: 50 % comedies. 50 % remaining genre.
Now in this 50 %, there are only 2 categories. Action movies and Drama Movies.
If Action = x; Drama movies = 9x. Total 10x.
10x = 50; x = 5
Action movies: 5 %
Drama movies: 45 %
we can say that out of 100z,:
comedies: 50z
action: 5z
drama: 45 z
Now action movies were A
This means:
A = 5z.
z = (A/5)
Comedies: 50z = 50 * (A/5)
10 A
B is the answer.
Answer: (B) 10 A
Question: Two trains travelling in the same direction at 80 and 26 kmph completely pass off another in 1 minute. If the length of the first train is 400 m, what is the length of the second train?
(A) 500
(B) 266
(C) 175
(D) 99
(E) 171
Rationale: RS = 80 â€“ 26 = 54 * 5/18 = 15 mps
T = 60 sec
D = 15 * 60 = 900 m
400
--------
500 m
Answer: A
Answer: (A) 500
Question: Each night before he goes to bed, Jordan likes to pick out an outfit to wear the next day. He has 13 different shirts, 10 different pairs of jeans, and 8 pairs of sneakers. If an outfit consists of 1 shirt, 1 pair of jeans, and 1 pair of sneakers, how many different outfits does Jordan have?
(A) 300
(B) 900
(C) 1040
(D) 480
(E) 960
Rationale: Total # of outfits = 13 * 10 * 8 = 1040
Answer - C
Answer: (C) 1040
Question: A certain car averages 25 miles per gallon when driving in the city and 40 miles per gallon when driving on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 45 miles on the highway?
(A) 28
(B) 30
(C) 36
(D) 35
(E) 38
Rationale: Answer C
No of Miles per Gallon = Total no of miles/Total no of Gallons
=10+45/(10/25+45/40) ~ 36.06
Answer: (C) 36
Question: In a test comprising 50 questions, a student attempts all questions. For every correct answer the student is awarded 1 mark. She will get negative marks for incorrect answers as per the following rule.
1. 0.25 negative mark for each of the first 10 incorrect answer.
2. 0.5 negative mark for each incorrect answer, from the 11th to the 20th.
3. 0.75 negative mark for each incorrect answer, from the 21st.
What is the minimum number of questions that the student should get right to get a non-negative score?
(A) 17
(B) 18
(C) 21
(D) 22
(E) 23
Rationale: If 21 answers are correct, the student will score = 21*1 = 21
-(10*0.25 + 10*0.5+9*0.75)=-14.25
This huge difference between Right and Wrong shows that C cant be the answer. Based on this we can also eliminate D and E.
Hence its between A and B.
Let plug in A.
17*1 = 17
-(2.5 + 5 + 13*0.75) = -17.25
Result Negative. Hence A can't be the answer and its B.
Answer: (B) 18
Question: The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 800 per sq.metre.
(A) Rs. 15,000
(B) Rs. 15,500
(C) Rs. 15,600
(D) Rs. 16,500
(E) None
Rationale: Solution
Area of the floor	= (5.5 x 3.75)m²
= 20.635m ²
Cost of paying	= Rs. (800 x 20.625)
= Rs.16500.
Answer D
Answer: (D) Rs. 16,500
Question: 20 binders can bind 1400 books in 21 days. How many binders will be required to bind 1600 books in 20 days?
(A) 24
(B) 18
(C) 17
(D) 16
(E) 10
Rationale: Binders Books Days
20 1400 21
x 1600 20
x/20 = (1600/1400) * (21/20) => x = 24
Answer:A
Answer: (A) 24
Question: The average age of A, B and C is 28 years. If the average age of A and C is 29 years, what is the age of B in years ?
(A) 19
(B) 26
(C) 20
(D) 32
(E) 21
Rationale: Age of B = Age of (A + B + C) â€“ Age of (A + C) = 28 Ã— 3 â€“ 29 Ã— 2 = 84 â€“ 58 = 26 years
B
Answer: (B) 26
Question: In 70 liters of a mixture of milk and water ,the quantity of water is 10%. how much water should be added so that new mixture may 25% water.
(A) 14
(B) 15
(C) 16
(D) 17
(E) 18
Rationale: There are 10% of water in 70L --> there are 7L of waters;
After x liters of water is added amount of water becomes (7+x) liters, which on the other hand is 1/4th (25%) of new (70+x) liters of mixture: 7+x=1/4*(70+x) --> 28+4x=70+x --> x=14
ANSWER:A
Answer: (A) 14
Question: Water consists of hydrogen and oxygen, and the approximate ratio, by mass, of hydrogen to oxygen is 2:16. Approximately how many grams of oxygen are there in 162 grams of water?
(A)  16
(B)  72
(C)  112
(D)  128
(E)  144
Rationale: Solution:
We are given that the ratio of hydrogen to oxygen in water, by mass, is 2 : 16. Using our ratio multiplier we can re-write this as 2x : 16x. We can now use these expressions to determine how much oxygen is in 162 grams of water.
2x + 16x = 162
18x = 162
x = 9
Since x is 9, we know that there are 16 x 9 = 144 grams of oxygen in 162 grams of water.
Answer E.
Answer: (E)  144
Question: A hall is 15 m long and 12 m broad. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, the volume of the hall is:
(A) 720
(B) 900
(C) 1200
(D) 1800
(E) 1900
Rationale: 2(15 + 12) x h = 2(15 x 12)
h =	180/27m =20/3	m.
Volume =	15 x 12 x20 m3= 1200 m3.
ANSWER:C
Answer: (C) 1200
Question: How many positive odd integers n less than 1000 have the property that the product of the
digits of n is 252 ?
(A) 0
(B) 1
(C) 3
(D) 4
(E) 5
Rationale: Since 252 = 2 *2 * 3* 3 *7, one of the digits is 7, the integer must have three digits, and the
remaining two digits are 6; 6, or 4; 9. There are five such odd integers: 667, 497, 947, 479, and
749.
correct answer E
Answer: (E) 5