mathewhe/aqua_rat huggingface dataset:
Question: What percent of 5 letter combinations that can be made from the letters of the word JERMONT and in which each letter can be used only once are the combinations in which the first letter is a vowel and the last letter is a consonant?
(A) 20%
(B) 23.8%
(C) 25%
(D) 30.2%
(E) 35%
Rationale: a) noof combinations when all 5 letters are different = 7*6*5*4*3
b) noof combinations when first letter is vowel and last is consonant = 2c1*5c1*5*4*3
b/a = 5/21= 0.238
B
Answer: (B) 23.8%
Question: A bookseller has two display windows. She plans to display 3 new fiction books in the left window, and 3 new non-fiction books in the right window. Assuming she can put the three fiction books in any order, and separately, the three non-fiction books in any order, how many total configurations will there be for the two display windows?
(A) 24
(B) 72
(C) 44
(D) 36
(E) 20
Rationale: Two displays books could be arranged n! # of total arrangements are combinations multiplied together,
3!*3! =6*6=36
Answer is D
Answer: (D) 36
Question: A retailer bought a machine at a wholesale price of $90 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price w of the machine?
(A) 	81
(B) 	100
(C) 	120
(D) 	135
(E) 	160
Rationale: Since the wholesale price was $90 and the profit was 20% of the wholesale price ([.2][90] = $18), the retail price would have to be above $108, but not that much greater than that.
Let's start by TESTing Answer C: $120....
If.....
Retail Price w= $120
10% discount off = $120 - (.1)(120) = 120 - 12 = 108
20% profit on wholesale price = 90 + (.2)(90) = 90 + 18 = 108
These two numbers MATCH, so this MUST be the answer!
Final Answer:
[Reveal]Spoiler:
C
Answer: (C) 	120
Question: A rope of which a calf is tied is increased from 9 m to 23 m, how much additional grassy ground shall it graze?
(A) 1218
(B) 1212
(C) 1408
(D) 2707
(E) 2591
Rationale: π (232 – 92) =1408
Answer: C
Answer: (C) 1408
Question: A does a work in 10 days and B does the same work in 15 days. In how many days they together will do the same work?
(A) 1
(B) 6
(C) 7
(D) 5
(E) 43
Rationale: A's 1 day work = 1/10; B's 1 day work = 1/15
(A + B)'s 1 day work = (1/10 + 1/15) = 1/6
So, both together will finish the work in 6 days.
Answer: B
Answer: (B) 6
Question: The probability of a lottery ticket being a prized ticket is 0.2. When 4 tickets are purchased, the probability of winning a prize on atleast one ticket is
(A) 0.4869
(B) 0.5904
(C) 0.6234
(D) 0.5834
(E) 0.2952
Rationale: P(winning prize atleast on one ticket)
= 1 - P("Losing on all tickets")
= 1 - (0.8)4 = (1 + (0.8)2)(1 - (0.8)2)
= (1.64)(0.36) = 0.5904
ANSWER:B
Answer: (B) 0.5904
Question: The difference between simple interest and compound interest on Rs.1200 for one year at 10% per annum reckoned half yearly is
(A) Rs.2.50
(B) Rs.3
(C) Rs.4
(D) Rs.3.75
(E) None
Rationale: Solution
S.I	= Rs.(1200x10x1/100)
Rs.120.
C.I	=Rs[(1200x1+5/100)² -1200]
Rs.123.
Difference	= Rs.[123-120]
Rs. 3.
Answer B
Answer: (B) Rs.3
Question: a.	In a class of 11, the teacher shares some oranges to all the pupils following the below progressive pattern:
1, 2, 4, 7, 8, 10, 13, 14, 16, 19, ?
How many oranges will the 10th person get?
(A) 20
(B) 18
(C) 22
(D) 24
(E) 23
Rationale: The sequence progresses +1, +2, +3 repeated; The 10th Person get 20 Oranges.
Ans A = 20
Answer: (A) 20
Question: Goldenrod and No Hope are in a horse race with 5 contestants. How many different arrangements of finishes are there if No Hope always finishes before Goldenrod and if all of the horses finish the race?
(A) 120
(B) 60
(C) 120
(D) 24
(E) 21
Rationale: All 5 horses can finish the race in 5! way (assuming no tie).
If no tie is possible between No Hope and Goldenrod, then in half of these cases No Hope will be before Goldenrod and in half of these cases after (not necessarily right before or right after). How else? So, there are 5!/2=60 different arrangements of finishes where No Hope always finishes before Goldenrod.
Answer: B.
Answer: (B) 60
Question: When a certain number X is divided by 143, the remainder is 51. Which of the following numbers, if added to X, would result in a number divisible by 13?
(A) 7
(B) 1
(C) 34
(D) 47
(E) 55
Rationale: Now X= 143q + 51 = 11*13*q + 51..so we have to make only 51 div by 13..
51 + 1 = 52 YES 1 to be added
ans B
Answer: (B) 1
Question: The age of the father 10 years ago was thrice the age of his son. Ten years hence, father’s age will be twice
that of his son. The ratio of their present ages is
(A) 5 : 2
(B) 7 : 3
(C) 9 : 2
(D) 13 : 4
(E) 1:2
Rationale: let x be present age of father and y be present age of son
then
ten yrs before
x-10=3(y-10)------->i
ten yrs hence
x+10=2(y+10)------->ii
now
(i)-(ii)=x-10-x-10=3y-30-2y-20
=20=y-50
=30=Y
therefore x=70
Ratio
x:y
=7:3 answer : B
Answer: (B) 7 : 3
Question: Joshua and Jose work at an auto repair center with 5 other workers. For a survey on health care insurance, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that Joshua and Jose will both be chosen?
(A) 1/21
(B) 1/12
(C) 1/9
(D) 1/6
(E) 1/3
Rationale: Two Methods
1) Probability of chosing Josh first = 1/7
Probability of chosing Jose second = 1/6
total = 1/42
Probability of chosing Jose first = 1/7
Probability of chosing Josh second = 1/6
Total = 1/42
Final = 1/42 + 1/42 = 1/21
A
Answer: (A) 1/21
Question: Lisa is buying candy at the grocery store, and has $15 on hand. M&M's are $4.50, Snickers are $6.00, Reese's are $5.50, and Milky Way's are $7.25. Of the following, which of the 5 options could Lisa buy to have $4.00 leftover for a Coffee at Starbucks?A
(A) 2 M&M's (9)
(B) 2 Snickers (12)
(C) 2 Reese's (11)
(D) 2 Milky Way's (14.50)
(E) A & C
Rationale: The correct answer must be the Sum of 2 correct candies with a remainder of at least $4
A=(2*4.50+4) = $13 ($15 on hand is enough)
B=(2*6+4) =$16 ($15 on hand is not enough)
C=(2*5.50+4) = $15 (exactly enough on hand)
D=(2*7.25+4) = $18.50 ($15 on hand is not enough)
E= A & C (Total of both candies and $4 coffee is $15 or less) *Correct Answer*
The Correct Answer is E
Answer: (E) A & C
Question: A person incurs 10% loss by selling a watch for $100. At what price should the watch be sold to earn 10% profit?
(A) $100
(B) $122
(C) $150
(D) $210
(E) $170
Rationale: Let the new selling price be $x
(100-loss%): (1st S.P.) = (100+gain%):(2nd S.P.)
(100-10)/100 = (100+10)/x
x = 110*100/90 = 122 approximately
Answer is B
Answer: (B) $122
Question: Four kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?
(A)  4.9
(B)  4.8
(C)  2.5
(D)  2
(E)  0.2
Rationale: Four kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?
(A) 4.9
(B) 4.8
(C) 2.5
(D) 2
(E) 0.2
If D is the answer, then the question means that the concentration of water the newt day became 96%.
Out of 4 kilograms 98%, or 3.92 kilograms was water and 0.08 kilograms was non-water.
The next day, after some water evaporated, oranges became 96% water and 4% of non-water, so the next day 0.08 kilograms of non-water composed 4% of oranges, which means that the new weight of the oranges was x*0.04=0.08 --> x=2 kilograms.
Answer:D.
Answer: (D)  2
Question: Two girls started running simultaneously around a circular track of length 500 m from the same point at speeds of 30 km/hr and 20 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions?
(A) 35
(B) 36
(C) 37
(D) 38
(E) 39
Rationale: Time taken to meet for the first time anywhere on the track
= length of the track / relative speed
= 500 / (30 + 20)5/18 = 500* 18 / 50 * 5 = 36 seconds.
Answer:B
Answer: (B) 36
Question: A box held 20 blue marbles and 30 red marbles. One marble is drawn at random. What is the probability that the marble is red?
(A) 1/4
(B) 2/5
(C) 3/5
(D) 3/4
(E) None of these
Rationale: Explanation:
Total cases = 20 + 30 = 50
Favourable cases = 30
So probability = 30/50 = 3/5
Answer: C
Answer: (C) 3/5
Question: A train passes a station platform in 34 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
(A) 248 m
(B) 210 m
(C) 277 m
(D) 765 m
(E) 176 m
Rationale: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/34 = 15 ==> x + 300 = 510 ==> x
= 210 m.
Answer: B
Answer: (B) 210 m
Question: The average temperature for Monday, Tuesday and Wednesday was 72Â°F. The average for Tuesday, Wednesday and Thursday was 74Â°F. If temperature on Thursday was 76Â°F, what was the temperature on Monday?
(A) 78Â°F
(B) 70Â°F
(C) 71Â°F
(D) 68Â°F
(E) None of the above
Rationale: Solution: Average temperature for Monday, Tuesday and Wednesday = 72Â°F.
Total temperature = 3*72 = 216
Average temperature for Tuesday, Wednesday and Thursday = 74Â°F
Total temperature = 3*74 = 222
Temperature on Thursday =76Â°F
Now,
(Monday + Tuesday + Wednesday) - (Tuesday + Wednesday + Thursday) = 222-216
Thursday - Monday = 5
Monday = 76-5 = 71Â°F
Answer: Option C
Answer: (C) 71Â°F
Question: A man sells an article at 15% loss. Had he sold it for Rs. 140/- more he could have gained 20%. What is the cost price of the article?
(A) Rs.420/-
(B) Rs.400/-
(C) Rs.460/-
(D) Rs.480/-
(E) None of these
Rationale: Explanation:
Short cut method:
Loss =====> 15 %
Profit ====> 20 %
~
----------------
35 % ---------> Rs. 140/-
100 % --------> Rs. 400/-
Answer: Option B
Answer: (B) Rs.400/-
Question: In how many different ways can the letters of the word 'SCHOOL' be arranged so that the vowels always come together?
(A) 90
(B) 100
(C) 120
(D) 130
(E) 150
Rationale: 'SCHOOL' contains 6 different letters.
vowels OO are always together
we have to arrange the letters (OO)SCHL
Now 5 letters can be arranged in 5! = 120 ways
The vowels (OO) can be arranged 2! = 2 ways.
= (120 x 2) = 240
again you have to divided 2 common vowels so answer is 120
C)
Answer: (C) 120
Question: 0.009 x 0.015=?
(A) 3.15e-05
(B) 0.000135
(C) 0.135
(D) 0.0135
(E) 0.00315
Rationale: 9 x 15 = 135
Sum of decimal places =6
Therefore, 0.007 x 0.45 = 0.000135
Answer is B.
Answer: (B) 0.000135
Question: A man walks at a rate of 10 mph. After every ten miles, he rests for 7 minutes. How much time does he take to walk 50 miles?
(A)  300
(B)  318
(C)  322
(D)  328
(E)  330
Rationale: To cover 50 miles the man needs (time) = (distance)/(rate) = 50/10 = 5 hours = 300 minutes. He will also rest 4 times (after 10, 20, 30 and 40 miles), so total resting time = 4*7 = 28 minutes.
Total time = 300 + 28 = 328 minutes.
Answer: D.
Answer: (D)  328
Question: A, B and C hire a taxi for Rs. 2400 for one day. A, B and C used the car for 6 hours, 8 hours and 10 hours respectively. How much did C pay?
(A) Rs. 800
(B) Rs. 1000
(C) Rs. 600
(D) Rs. 1200
(E) None
Rationale: Let total fair be = 2400 ;
Therefore c share =10/24 × 2400 = 1000
Answer: B
Answer: (B) Rs. 1000
Question: 4. A and B can do a certain piece of work in 18
(A) 23
(B) 77
(C) 269
(D) 26
(E) 272
Rationale: Answer:A
Answer: (A) 23
Question: A vendor bought bananas at 6 for Rs.10 and sold them at Rs.4 for Rs.6 .Find his gain or loss percent .
(A) 10
(B) 20
(C) 25
(D) 30
(E) 32
Rationale: Sol:
Suppose , number of bananas bought = LCM of 6 and 4=12
CP=Rs.[(10/6)*12]=Rs.20 ; SP= Rs[(6/4)*12]=Rs.18
Loss%=[(2/20)*100]%=10%
Option A
Answer: (A) 10
Question: 96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
(A) 22
(B) 88
(C) 42
(D) 66
(E) 11
Rationale: x/7 = y/9 => x:y = 7:9
7/16 * 96 = 42
Answer: C
Answer: (C) 42
Question: 5862 is to 714
and 3498 is to 1113
and 9516 is to 156
therefore 8257 is to ?
(A) 163
(B) 134
(C) 157
(D) 189
(E) 143
Rationale: C
157
7 + 8 = 15,
2 + 5 = 7
Answer: (C) 157
Question: 20. A certain church bell rings the bell twice at half past the hour and four
times at the hour plus an additional number of rings equal to what ever
time it is. How many rings will the clock make from 6:20 in the morning
to 09:50 in the morning?
(A) 44.
(B) 36.
(C) 42.
(D) 46.
(E) 50.
Rationale: unless i understood the problem correctly, i get 58
@ 6:30 - 2
@ 7 - 4+7 =11
@ 7:30 - 2
@ 8 - 12
@ 8:30 - 2
@ 9 - 13
@ 9:30 - 2
totals to A=44
Answer: (A) 44.
Question: As a bicycle salesperson, Norman earns a fixed salary of $20 per week plus $6 per bicycle for the first six bicycles he sells, $12 per bicycle for the next six bicycles he sells, and $18 per bicycle for every bicycle sold after the first 12. This week, Norman earned more than twice as much as he did last week. If he sold m bicycles last week and y bicycles this week, which of the following statements must be true?
I. y > 2m
II. y > m
III. y > 3
(A) I only
(B) II only
(C) I and II
(D) II and III
(E) I, II, and III
Rationale: This is kind of like doing your taxes, lets summarize the data in terms of bike sales and salary -
0 Bikes - $20
6 Bikes - $56
12 Bikes - $128
More than 12 bikes - 128 + 18*(m-12) where m is the total number of bikes sold (when m>12).
M = cycles sold last week
MS = Salary last week.
Y = cycles sole this week
YS = Salary this week.
given YS>2MS
lets test all statements with M=0;
MS = 20
YS >40
True when Y = 4
satisfies all the statements but we can only be sure of iii as Y will only increase from here. So iii must be true. Eliminate A,B,C
lets test all statements with M=1;
MS = 26
YS>52
True when Y=6
Still satisfies all the statements - Nothing achieved
lets test all statements with M=6;
MS = 56
YS>112
True when Y = 11
This proves statement i wrong, hence eliminate E so we are left with
Answer D
Answer: (D) II and III
Question: If the average (arithmetic mean) of 10 consecutive odd integers is 154, then the least of these integers is
(A) a) 51
(B) b) 58
(C) c) 145
(D) d)190
(E) e)210
Rationale: A very helpful rule to know in arithmetic is the rule that in evenly spaced sets, average = median. Because the average will equal the median in these sets, then we quickly know that the median of this set of consecutive odd integer numbers is 154.
There are 10 numbers in the set, and in a set with an even number of terms the median is just the average of the two most median terms (here the 5th and 6th numbers in the set). This means that numbers 5 and 6 in this set are 153 and 155. Because we know that number 5 is 153, we know that the smallest number is 4 odd numbers below this, which means that it is 4*2 = 8 below this (every odd number is every other number). Therefore 153-8 = 145, answer choice C
Answer: (C) c) 145
Question: Find the no.of ways of arranging the boy and 11 guests at a circular table so that the boy always sits in a particular seat?
(A) 3!
(B) 8!
(C) 7!
(D) 9!
(E) 11!
Rationale: Ans.(E)
Sol. Total number of persons = 12 Host can sit in a particular seat in one way. Now, remaining positions are defined relative to the host. Hence, the remaining can sit in 11 places in 11P11 = 11! Ways ... The number of required arrangements = 11! x 1= 11! = 11! ways
Answer: (E) 11!
Question: A Jar contains a mixture of AB in the ratio 4:1. When 20 L of Mixture is replaced with liquid B, ratio becomes 2:3. How many liters of liquid A was present in mixture initially.
(A) 12
(B) 15
(C) 32
(D) 20
(E) 25
Rationale: 20 litres of mixture that is replaced will contain 16 litres of A and 4 litres of B (as A:B = 4:1)
Let the initial volume of the mixture be 4K + 1K = 5K
So by condition ,
[ 4K-16 ]/ [ K-4+20 ] = 2/3 => 12k -48 = 2k-8+40 => 10k=80
Solve for K which is K = 8
So initial volume of liquid A = 4K = 32 litres
Answer : C
Answer: (C) 32
Question: 1+2+2^2+2^3=？
(A) (2^3-1)(2^3+1)
(B) (2^2-1)(2^2+1)
(C) 2^5-1
(D) 2^5+1
(E) 2^5-2
Rationale: From 1+2+2^2+2^3=1(2^4-1)/(2-1)=2^4-1=(2^2-1)(2^2+1), the correct answer is B.
Answer: (B) (2^2-1)(2^2+1)
Question: In how many different ways can the letters of the word JUDGE be arranged so that the vowels always come together?
(A) 48
(B) 24
(C) 120
(D) 60
(E) None of these
Rationale: Reqd. number = 4! × 2! = 24 × 2 = 48
Answer A
Answer: (A) 48
Question: A school has 4 section of Chemistry in Class X having 65, 35, 45 and 42 students. The mean marks obtained in Chemistry test are 50, 60, 55 and 45 respectively for the 4 sections. Determine the overall average of marks per student.
(A) 50.25
(B) 52.25
(C) 51.95
(D) 53.25
(E) None of the above
Rationale: Required average marks
= 65Ã—50+35Ã—60+45Ã—55+42Ã—45/65+35+45+42
= 3250+2100+2475+1890/187
= 9715â„187 = 51.95
Answer C
Answer: (C) 51.95
Question: If -11a and -8b are negative integers, then (-11a)*(-8b )+ ab is
(A) 88ab
(B) -89ab
(C) 89 ab
(D) -88a
(E) -88b
Rationale: Answer : C
Answer: (C) 89 ab
Question: What is the remainder wen 2^35 is divided by 5?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: 2^35 / 5
=> (2^4)^8 * 2^3 / 5
=> (5*3+1)^8 * (5+3) / 5
=> (1*3)/5
=> 3/5
=> remainder = 3
ANSWER:C
Answer: (C) 3
Question: The cost price of 18 articles is equal to the selling price of 11 articles. Find the profit percent?
(A) 18 2/15
(B) 36 2/11
(C) 45 2/14
(D) 54 2/16
(E) 63 7/11
Rationale: 18 CP = 11 SP
11 --- 2 CP
100 --- ? =>63 7/11%.Answer: E
Answer: (E) 63 7/11
Question: A teacher prepares a test. She gives 5 objective type questions out of which 4 have to be answered. Find the total ways in which they can be answered if the first 2 questions have 2 choices and the last 3 have 4 choices.
(A) 255
(B) 448
(C) 192
(D) 100
(E) 144
Rationale: Two cases.
First Case: 2 Questions - 2 Choices, 2 Questions - 4 Choices
2C2 * 3C2 ways to select the questions
2C1 * 2C1 * 4C1 * 4C1 ways to answer the questions
= 1 * 3 * 2 * 2 * 4 * 4
= 192
Second Case: 1 Question - 2 Choices, 3 Questions - 4 Choices
2C1 * 3C3 ways to select the questions
2C1 * 4C1 * 4C1 * 4C1 ways to answer the questions
= 2 * 1 * 2 * 4 * 4 * 4
=256
Total = 192 +256
= 448
B
Answer: (B) 448
Question: Nitin’s salary is reduced by 10% and then reduced salary is increased by 10%. Find ,how many percentage his present salary is less as compared to his previous salary?
(A) 7%
(B) 2%
(C) 1%
(D) 4%
(E) 5%
Rationale: 10*10
-------- = 1%
100
Answer: C
Answer: (C) 1%
Question: The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 8000, brokerage being 1/4%, is:
(A) 110.86
(B) 114
(C) 114.75
(D) 124
(E) 124.75
Rationale: Face Value = Rs. 8000.
Dividend = 10.5%.
Annual Income = Rs. 756.
Brokerage per Rs. 100 = Rs. 0.25.
Dividend is always paid on the face value of a share.
Face Value * Dividend / (Market Value + Brokerage per Rs. 100) = Annual income.
= 8000 * 10.5 / 756 = Market Value of Rs. 100 stock + Brokerage per Rs. 100.
= Market Value of Rs. 100 stock + Brokerage per Rs. 100 = Rs. 111.11
= Market Value of Rs. 100 stock = Rs. 111.11 - Re. 0.25.
= Market Value of Rs. 100 stock = Rs. 110.86.
answer : A
Answer: (A) 110.86
Question: Of 40 applicants for a job, 24 had at least 4 years' experience, 15 had degrees, and 4 had less than 4 years' experience and did not have a degree. How many of the applicants had at least 4 years' experience and a degree?
(A)  14
(B)  3
(C)  9
(D)  7
(E)  5
Rationale: set A : people with more than 4 years exp
set B : people with degree
AUB = total - (less than 4 exp and no degree)
AUB = 40-4=36
AUB = A + B - AiB
AiB = 15+24-36
=3
Answer B
Answer: (B)  3
Question: How many cubes of 10 cm edge can be put in a cubical box of 1 m edge.
(A) 177 cm
(B) 100 cm
(C) 786 cm
(D) 617 cm
(E) 187 cm
Rationale: Number of cubes =100∗100∗10010∗10∗10=1000
Number of cubes =100∗100∗10010∗10∗10=1000
Note: 1 m = 100 cm
Answer:B
Answer: (B) 100 cm
Question: 8 men, working 9 hours a day can complete a work in 24 days. How many hours a day must 12 men work to complete the same work in 16 days?
(A) 6
(B) 7
(C) 8
(D) 9
(E) 10
Rationale: The number of hours required to complete the work is 8*9*24 = 1728
12 × 16 × (x) = 1728
x = 9
The answer is D.
Answer: (D) 9
Question: If an object travels at five feet per second, how many feet does it travel in one hour?
(A) 30
(B) 3000
(C) 18
(D) 1800
(E) 2200
Rationale: If an object travels at 5 feet per second it covers 5x60 feet in one minute, and 5x60x60 feet in one hour.
Answer = 1800 Answer: D
Answer: (D) 1800
Question: Kamal obtained 76, 65, 82, 67 and 85 marks(out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
(A) 65
(B) 69
(C) 72
(D) 75
(E) NOne
Rationale: Sol.
Average
= 76 + 65 + 82 + 67 + 85 / 5)
= (375 / 5)
= 75.
Answer D
Answer: (D) 75
Question: If log102 = 0.3010, log10 3 = 0.4771, then the number of zeros between the decimal point and the first
significant figure in (0.0432)10 is?
(A) 10
(B) 13
(C) 14
(D) 15
(E) 16
Rationale: X = (0.0432)10 = (432/10000)10 = (33.24/104)10
Therefore, log10X = 10 (log103 + 4log102-4)
= 10(1.4313 + 1.2040 - 4)
= 10(-1.3647)
= -13.647
= -14.353
Therefore, X = antilog(-14.053)
Thus, number of zeros between the decimal and the first significant figure = 13
ANSWER:B
Answer: (B) 13
Question: If 09/12/2001 happens to be Sunday, then 09/12/1971 would have been at
(A) Wednesday
(B) Tuesday
(C) Saturday
(D) Thursday
(E) None of these
Rationale: Explanation09/12/2001—— Sunday
No. of days between 9/ 12/ 71 & 9 / 12/ 2001
we know every year has 1 odd days
we know leap year has 2 odd days
Here, No. of normal years = 22
And no. of leap years = 8
So odd days = 22 + 16 = 38 i.e 3 odd days (remainder when 38 is divided by 7, i.e. 3)
Hence it was a Thursday
Answer D
Answer: (D) Thursday
Question: Jane makes toy bears. When she works with an assistant, she makes 80 percent more bears per week and works 10 percent fewer hours each week. Having an assistant increases Jane’s output of toy bears per hour by what percent R?
(A) 20%
(B) 80%
(C) 100%
(D) 180%
(E) 200%
Rationale: C.
Let's assume just Jane 40 bears per 40/hrs a week, so that is 1 bear/hr. With an assistant she makes 72 bears per 36 hours a week or 2 bears/hr ([40 bears * 1.8] / [40 hrs * .90]).
R=[(2 - 1)/1] * 100% = 100%.C
Answer: (C) 100%
Question: Two pipes A and B can fill a tank in 6 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?
(A) 4 hrs
(B) 5 hrs
(C) 7 hrs
(D) 9 hrs
(E) 8 hrs
Rationale: A's work in 1 hour	= 1/6.
B's work in 1 hour	= 1/4.
(A+B)'s 2 hour's work when opened alternately	= (1/6 + 1/4)
= 5/12.
(A+B)'s 4 hour's work when opened alternately	= 10/12
= 5/6.
Remaining part	= (1 - 5/6)
= 1/6.
Therefore, total tank to fill the tank	(4+1)hrs = 5 hrs.
ANSWER:B
Answer: (B) 5 hrs
Question: There are 20 persons sitting in a circle. In that there are 18 men and 2 sisters. How many arrangements are possible in which the two sisters are always separated by a man?
(A) 18!x2
(B) 17!
(C) 17x2!
(D) 12
(E) 14
Rationale: Now the first sister can sit in 20 ways and other sister can sit either left or right such that 2 ways .All men can sit in remaning 18 seats i.e 18!
Answer is 18!x2
ANSWER:A
Answer: (A) 18!x2
Question: At Pete’s Pet Shop, 35 cups of bird seed are used every 5 days to feed 14 parakeets. How many cups of bird seed would be required to feed 9 parakeets for 7 days?
(A) 27
(B) 9
(C) 31.5
(D) 16
(E) 54
Rationale: Let's go step-by-step.
35 cups are used over a 5 day period, which means 7 cups a day. This feeds 14 parakeets, which means each parakeet needs 1/2 of a cup every day.
For 9 parakeets, we need 9*1/2cups = 4.5 cups a day. Over 7 days, we need 31.5 cups. Choice c.
Answer: (C) 31.5
Question: If the number 779 * 876 is completely divisible by 9, then the smallest whole number in place of * will b
(A) 4
(B) 5
(C) 7
(D) 1
(E) 9
Rationale: Sum of digits = (7 + 7 + 9 + x + 8 + 7 + 6) = (44 + x), which must be divisible by 9.
x = 1
D)
Answer: (D) 1