mathewhe/aqua_rat huggingface dataset:
Question: What percent of 5 letter combinations that can be made from the letters of the word DERMONT and in which each letter can be used only once are the combinations in which the first letter is a vowel and the last letter is a consonant?
(A) 23.8%
(B) 24%
(C) 25%
(D) 30.2%
(E) 35%
Rationale: a) no of combinations when all 5 letters are different = 7*6*5*4*3
b) no of combinations when first letter is vowel and last is consonant = 2c1*5c1*5*4*3
b/a = 5/21= 0.238
A
Answer: (A) 23.8%
Question: Each of three investments has a 20% of becoming worthless within a year of purchase, independently of what happens to the other two investments. If Simone invests an equal sum J in each of these three investments on January 1, the approximate chance that by the end of the year, she loses no more than 1/3 of her original investment is
(A) 90%
(B) 80%
(C) 70%
(D) 60%
(E) 40%
Rationale: The problem asks for the approximate chance that no more than 1/3 of the original investment is lost. We can apply the “1 – x” technique: what’s the chance that more than 1/3 of the original investment is lost? There are two outcomes we have to separately measure:
(a) All 3 investments become worthless.
(b) 2 of the 3 investments become worthless, while 1 doesn’t.
Outcome (a): The probability is (0.2)(0.2)(0.2) = 0.008, or a little less than 1%.
Outcome (b): Call the investments X, Y, and Z. The probability that X retains value, while Y and Z become worthless, is (0.8)(0.2)(0.2) = 0.032. Now, we have to do the same thing for the specific scenarios in which Y retains value (while X and Z don’t) and in which Z retains value (while X and Y don’t). Each of those scenarios results in the same math: 0.032. Thus, we can simply multiply 0.032 by 3 to get 0.096, or a little less than 10%.
The sum of these two probabilities is 0.008 + 0.096 = 0.104, or a little more than 10%. Finally, subtracting from 100% and rounding, we find that the probability we were looking for is approximately 90%.
The correct answer is A.
This problem illustrates the power of diversification in financial investments. All else being equal, it’s less risky to hold a third of your money in three uncorrelated (independent) but otherwise equivalent investments than to put all your eggs in one of the baskets. That said, be wary of historical correlations! Housing price changes in different US cities were not so correlated—and then they became highly correlated during the recent housing crisis (they all fell together), fatally undermining spreadsheet models that assumed that these price changes were independent.
Answer: (A) 90%
Question: A rectangular lawn of dimensions 70 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?
(A) A)3600
(B) B)930
(C) C)9309
(D) D)3900
(E) E)8302
Rationale: Explanation:
Area = (l + b – d) d
(70 + 60 – 10)10 => 1200 m2
1200 * 3 = Rs.3600
Answer: Option A
Answer: (A) A)3600
Question: The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?
(A) 432 sq m
(B) 356 sq m
(C) 452 sq m
(D) 428 sq m
(E) 525 sq m
Rationale: 2(3x + x) = 96
l = 36 b = 12
lb = 36 * 12 = 432
ANSWER:A
Answer: (A) 432 sq m
Question: A Man can row upstream at 65kmph and downward stream at 47 kmph. Find Man's rate of the current
(A) 87km/hr
(B) 20km/hr
(C) 9km/hr
(D) 2.8km/hr
(E) 4.4km/hr
Rationale: Rate of the current=1/2(65-47)km/hr
=9km/hr
correct option is :C
Answer: (C) 9km/hr
Question: If 5x = 7y and xy ≠ 0, what is the ratio of 1/5*x to 1/6*y ?
(A)  25/6
(B)  42/25
(C)  6/5
(D)  5/6
(E)  25/36
Rationale: 5x = 7y => x/y = 7/5
1/5*x to 1/6*y = x/y * 6/5 = (7/5)*(6/5)=42/25
Ans: B
Answer: (B)  42/25
Question: 3/[(1/0.03) + (1/0.37)] = ?
(A) 0.004
(B) 0.08333
(C) 2.775
(D) 3.6036
(E) 36.036
Rationale: Approximate.
1/.03 = 100/3 = 33
1/.37 = 100/37 = 3
Denominator becomes 33 + 3 = 36
3/36 = .08 something
Answer (B)
Answer: (B) 0.08333
Question: What amount does Kiran get if he invests Rs. 18000 at 15% p.a. simple interest for four years?
(A) 228777
(B) 26788
(C) 26088
(D) 28800
(E) 67881
Rationale: Simple interest = (18000 * 4 * 15)/100 = Rs. 10800
Amount = P + I = 18000 + 10800 = Rs. 28800
Answer: D
Answer: (D) 28800
Question: Consider two statements
Statement 1 => If Y is an integer and Y=2p+1 where p is not an integer.
Statement 2 => If Z is an integer and Z=2q where q is not an integer
Which of the following correctly specifies the Even/Odd nature of Y and Z respectively
(A) 1) Odd,Even
(B) 2) Odd,Odd
(C) 3) Even,Odd
(D) 4) Even,Even
(E) 5) Cannot be determined
Rationale: answer will be E
Y = integer
Y = 2p+1 = integer here p can be any n/2 and n can be even or odd , matters alot 2 get cancelled out
if n were even Y would odd
if n odd Y would be even
ANSWER IS E
Answer: (E) 5) Cannot be determined
Question: Two-third of two-fifth of three-fourth of a number is 36. What is the square root of four-fifth of that number?
(A) 9
(B) 12
(C) 14
(D) 16
(E) None of these
Rationale: Explanation:
We have, 2/3 * 2/5 * 3/4 * X = 36
X = 180
Now, 4/5 * X ===> 4/5 * 180 = 144
√144 = 12
ANSWER B
Answer: (B) 12
Question: How many halves are there in two-fourth?
(A) 8
(B) 1
(C) 32
(D) 7
(E) 3
Rationale: divide 2/4 by 1/2
=2/4÷1/2
=2/4*2/1
=4/4
=1.
Answer is B.
Answer: (B) 1
Question: If 213 × 16 = 3408, then 1.6 × 213.0 is equal to :
(A) 0.3408
(B) 3.408
(C) 34.08
(D) 340.8
(E) None of these
Rationale: Solution
1.6 × 21.3 = (16/10x 213)= (16x 213/10) = 3408/10 = 340.8. Answer D
Answer: (D) 340.8
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 42 years now, the son's age five years back was:
(A) 14
(B) 16
(C) 19
(D) 22
(E) 24
Rationale: Let the son's present age be x years. Then, (42 - x) = x
2x = 42.
x = 21.
Son's age 5 years back (21 - 5) = 16 years.
answer :B
Answer: (B) 16
Question: How many cuboids of length 6 m, width 4 m and height 3 m can be farmed from a cuboid of 18 m length, 15 m width and 2 m height.
(A) 2.6
(B) 5.8
(C) 6.2
(D) 7.5
(E) 1.2
Rationale: (18 Ã— 15 Ã— 2)/(6 Ã— 4Ã— 3) = 7.5
Answer is D.
Answer: (D) 7.5
Question: Find the least number of complete years in which a sum of money put out at 50% compound interest will be more than double of itself?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: 2 years
Answer: A
Answer: (A) 2
Question: If C:D = 2:5 and D:F = 4:7 then C:D:F is
(A) 8:20:35
(B) 6:20:35
(C) 8:20:33
(D) 8:22:35
(E) 5:20:35
Rationale: Solution:
C/D = 2/5;
D/F = 4/7;
C:D:F = 2*4:5*4:5*7 = 8:20:35.
Answer: Option A
Answer: (A) 8:20:35
Question: When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.45, what is the value of y?
(A) 96
(B) 75
(C) 48
(D) 20
(E) 12
Rationale: Guys, one more simple funda.
5/2= 2.5
now .5 x2 =1 is the remainder
25/4 = 6.25
now .25x4=1 is the remainder
32/5=6.4
now.4x5 = 2 is the remainder
given x/y = 96.45 and remainder is 9
So .45 X y = 9
hence y= 20
Ans D
Answer: (D) 20
Question: The price of honey in a certain store is $5.00. If the price of the honey is to be reduced by $1.50, by what percent is the price to be reduced?
(A)  10%
(B)  15%
(C)  20%
(D)  25%
(E)  30%
Rationale: A certain percentage of questions in the Quant section of the GMAT are just 'math questions' - you'll use a formula, do some calculations and you'll have the answer. This is one of those types of questions. You still have to write everything down and stay organized, but the work involved is relatively straight-forward.
Here, we're told that the price of honey is $5.00 and that the price of the honey is to be reduced by $1.50. We're asked by what PERCENT is the price to be REDUCED?
Original Price = $5.00
Reduction = $1.50
The percent reduction is relative to the original price of the honey:
$1.50/$5.00 = 3/10 = 30%
E
Answer: (E)  30%
Question: John has 6 friends who want to ride in his new car that can accommodate only 3 people at a time (John plus 2 passengers). How many different combinations of 2 passengers can be formed from John's 6 friends?
(A) 3
(B) 8
(C) 10
(D) 15
(E) 20
Rationale: 6C2 = 15
The answer is D.
Answer: (D) 15
Question: A Train requires 5 seconds to pass a pole while it requires 25 seconds to cross a stationary train which is 360 mtrs long. Find the speed of the train.
(A) 66.8 kmph
(B) 65.8 kmph
(C) 54.8 kmph
(D) 64.8 kmph
(E) 44.8 kmph
Rationale: In 5s the train crosses the pole and in 25 sec the train crosses one more stationary train
In 20 sec the train travels a distance of 360 mtrs
Speed = 360/20 = 18 m/s = 18 (3600/1000) = 18 * 18/5 = 64.8 kmph
Answer: D
Answer: (D) 64.8 kmph
Question: 20% of a number is more than 20% of 650 by 190. Find the number?
(A) 288
(B) 278
(C) 800
(D) 1600
(E) 121
Rationale: (20/100) * X â€“ (20/100) * 650 = 190
1/5 X = 320
X = 1600
Answer:D
Answer: (D) 1600
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
(A) 277
(B) 267
(C) 240
(D) 882
(E) 212
Rationale: Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m.
Answer: C
Answer: (C) 240
Question: If 18 is 15 percent of 10 percent of a certain number, what is the number?
(A) 9
(B) 1200
(C) 40
(D) 81
(E) 400
Rationale: Let the certain number be x.
=> (15/100)*(10/100)*x = 18;
=> x=1200;
Ans is (B).
Answer: (B) 1200
Question: How many five-digit numbers are there, if the two leftmost digits are even, the other digits are odd and the digit 4 cannot appear more than once in the number?
(A) 1875
(B) 2000
(C) 2375
(D) 2500
(E) 3875
Rationale: the five-digit number: abcde
a have 4 choice of even numbers: 2, 4, 6, 8
b have 4 choice of even numbers: 0, 2, 6, 8 because 4 cannot appear more than once
c, d and e each have 5 choice from 1, 3, 5, 7, 9
So total: 4*4*5*5*5=2000 ANS:B
Answer: (B) 2000
Question: There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
(A) 50
(B) 100
(C) 150
(D) 200
(E) 250
Rationale: Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Answer is B.
Answer: (B) 100
Question: When Leo imported a certain item, he paid a 7 percent import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that Leo paid was $87.50, what was the total value of the item?
(A) $1,600
(B) $1,850
(C) $2,250
(D) $2,400
(E) $2,750
Rationale: Let the value of the item be $x, then 0.07(x−1,000)=87.5--> x−1,000=1,250x−1,000=1,250 --> x=2,250.
Answer: C.
Answer: (C) $2,250
Question: A and B start a business jointly. A invests Rs.16000 for 8 months and B remains in the business for 4 months. Out of the total profit B claims 2/6th share. How much money is contributed by B?
(A) A)Rs.12829
(B) B)Rs.12800
(C) C)Rs.12293
(D) D)Rs.12804
(E) E)Rs.16000
Rationale: 16*8: x*4 = 4:2
x = 16 =>
Rs.16000
Answer: E
Answer: (E) E)Rs.16000
Question: Mike took a taxi to the airport and paid $2.50 to start plus $0.25 per mile. Annie took a different route to the airport and paid $2.50 plus $5.00 in bridge toll fees plus $0.25 per mile. If each was charged exactly the same amount, and Annie's ride was 16 miles, how many miles was Mike's ride?
(A) 32
(B) 36
(C) 40
(D) 44
(E) 48
Rationale: The cost of Annie's ride was 2.5+5+(0.25*16) = $11.50
Let x be the distance of Mike's ride.
The cost of Mike's ride is 2.5+(0.25*x) = 11.5
0.25*x = 9
x = 36 miles
The answer is B.
Answer: (B) 36
Question: In the xy-coordinate system, if (m,n) and (m+2, n+k) are two points on the line perpendicular to x=2y+5, then k=?
(A) -5
(B) -8
(C) 2
(D) -4
(E) 1
Rationale: the slope= k/2
the line perpendicular to x=2y+5 or y=1/2x-5/2 has
a slope= -1/ (1/2) =-2 --->k/2=-2 --> k=-4
Answer is D
Answer: (D) -4
Question: A chair is bought for Rs.600/- and sold at a loss of 10% find its selling price
(A) Rs.500/-
(B) Rs.540/-
(C) Rs.600/-
(D) Rs.640/-
(E) Rs.660/-
Rationale: 100 % ------> 600 (100 * 6 = 600)
90 % ------> 540 (90 * 6 = 540)
Selling price = Rs.540/-
B
Answer: (B) Rs.540/-
Question: Meg and Bob are among the 4 participants in a cycling race. If each participant finishes the race and no two participants finish at the same time, in how many different possible orders can the participants finish the race so that Meg finishes ahead of Bob?
(A) 24
(B) 30
(C) 60
(D) 90
(E) 12
Rationale: Total # of ways the race can be finished is 4!. In half of the cases Meg finishes ahead of Bob and in other half Bob finishes ahead of Meg. So, ways Meg to finish ahead of Bob is 4!/2=12.
Answer: E.
Answer: (E) 12
Question: After paying a 10 percent tax on all income over $3,000, a person had a net income of $12,000. What was the income before taxes?
(A) $13,300
(B) $13,000
(C) $12,900
(D) $10,000
(E) $9,000
Rationale: Let x be the income over 3000
Then (x-x/10) + 3000 = 12000
=> x = 10000
Therefore income before taxes = 10000 + 3000 = 13000
Option (B)
Answer: (B) $13,000
Question: In a throw of dice what is the probability of geÆ«ing number greater than 2
(A) 2/3
(B) 1/3
(C) 1/5
(D) 1/6
(E) None of these
Rationale: Explanation:
Number greater than 2 is 3, 4, 5 & 6, so only 4 number
Total cases of dice = [1,2,3,4,5,6]
So probability = 4/6 = 2/3
Answer: A
Answer: (A) 2/3
Question: In xyz business school,88% are taking their specialization as finance at the same time 76% taking their specialization as marketing.If 90% are taking their specialization as finance then, what is % of marketing specialization students?
(A) 55
(B) 75
(C) 43
(D) 52
(E) 45
Rationale: Percentage of finance specialization = 88; Percentage of marketing specialization = 75%; Total =90*100;Percentage of finance specialization= 90 - 88= 2; Percentage of marketing specialization= 100 - 75 =25; then Percentage of marketing specialization = 0.75*24=18. Then total percentage of marketing specialization = 25+18=43. Answer: C
Answer: (C) 43
Question: The ratio of the volumes of two cubes is 729 : 1000. What is the ratio of their total surface areas?
(A) 1:22
(B) 8:11
(C) 45:12
(D) 34:19
(E) 46:51
Rationale: Ratio of the sides = ³√729 : ³√1000
= 9 : 10
Ratio of surface areas = 92:102
= 46:51
Answer: E
Answer: (E) 46:51
Question: Out of seven given numbers, the average of the first four numbers is 4 and that of the last four numbers is also 4. If the average of all the seven numbers is 3, fourth number is
(A) 3
(B) 4
(C) 7
(D) fourth no=11
(E) 12
Rationale: (a+b+c+d)/4=4
=>(a+b+c+d)=16...........(1)
(d+e+f+g)/4=4
=>(d+e+f+g)=16
=>(e+f+g)=16-d...........(2)
Also, (a+b+c+d+e+f+g)/7=3 (Given)
using (1) and (2) equations
16+16-d=21
=> d=11
ANSWER:D
Answer: (D) fourth no=11
Question: Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
(A) 15
(B) 16
(C) 18
(D) 25
(E) None of these
Rationale: EXPLANATION
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x => x =(4x20/5)
x = 16 days.
Hence, Tanya takes 16 days to complete the work.
Answer B
Answer: (B) 16
Question: A shipment of 1500 heads of cabbage, each of which was approximately the same size, was purchased for $600. The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head. The following day the rest were sold at a price equal to 8% less than the price each head sold for on the day before. What was the total gross profit on this shipment.
(A) $100
(B) b $115
(C) c $125
(D) d $130
(E) e $135
Rationale: Purchase cost = 600/1500= $ 0.4
25% above the cost per head = (125/100)*0.4= $ 0.5
2/3 of the heads were sold means 2/3*1500 =1000 ,Selling amount for 1000 cabbage = 1000 * 0.5 = $ 500
Remaining were sold at a price equal to 8% less than the price each head sold for on the day before i.e , (92/100)*0.5 = $ 0.46
Hence selling cost for the remaining cabbage = 500 * 0.46 = $ 230
Total selling cost = 500 + 230 = $ 730
Gross profit = $ 730 - $ 600 = $ 130
Hence Answer is D.
Answer: (D) d $130
Question: Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
(A) 1235
(B) 1345
(C) 1678
(D) 1767
(E) 1635
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Large number = 270+1365 = 1635
E
Answer: (E) 1635
Question: Three pounds of 05 grass seed contain 10 percent herbicide. A different type of grass seed, 20, which contains 20 percent herbicide, will be mixed with three pounds of 05 grass seed. How much grass seed of type 20 should be added to the three pounds of 05 grass seed so that the mixture contains 15 percent herbicide?
(A) 3
(B) 3.75
(C) 4.5
(D) 6
(E) 9
Rationale: 05 grass seed contains 5% herbicide and its amount is 3 pound
20 grass seed contains 20% herbicide and its amount is x
when these two types of grass seeds are mixed, their average becomes 15%
thus we have
3(10)+x(20)/(x+3) = 15
30+20x=15x +45
5x=15
or x=3
A
Answer: (A) 3
Question: The average temperature for Wednesday, Thursday and Friday was 40oC. The average for Thursday, Friday and Saturday was 41oC. If temperature on Saturday was 42oC, what was the temperature on Wednesday?
(A) 39oC
(B) 44oC
(C) 38oC
(D) 41oC
(E) None
Rationale: Solution: Average temperature for Wednesday, Thursday and Friday = 40oC
Total temperature = 3*40 = 120oC
Average temperature for Thursday, Friday and Saturday = 41oC
Total temperature = 41*3 = 123oC
Temperature on Saturday = 42oC
Now,
(Thursday + Friday + Saturday) - (Wednesday + Thursday + Friday) = 123-120;
Saturday - Wednesday = 3
Wednesday = 42-3 = 39oC.
Answer: Option A
Answer: (A) 39oC
Question: Machine R and machine B are each used to manufacture 660 sprockets. It takes machine R 10 hours longer to produce 660 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine R. How many sprockets per hour does machine R produces?
(A) 6
(B) 6.6
(C) 60
(D) 100
(E) 110
Rationale: I think the correct answer is A.
Machine R produces at a speed of R sp/hour and B at a speed of B sp/hour.
so, 660/R=(660/B)+10 and B=1,1 R--->1,1*660=660+11R--->A=6, so answer A is correct
Answer: (A) 6
Question: A can finish a work in 24 days, B n 9 days and C in 12 days. B&C start the
work but are forced to leave after 3 days. The remaining work done by A in:
(A) 12days
(B) 13days
(C) 11days
(D) 10days
(E) 9days
Rationale: (B+C)'s one day's work=1/9+1/12=7/36
Work done by B & C in 3 days=3*7/36=7/12
Remaining work=1-(7/12)=5/12
Now , 1/24 work is done by A in 1 day.
So, 5/12 work is done by A in 24*5/12=10 days
ANSWER D 10days
Answer: (D) 10days
Question: The number of boxes in a warehouse can be divided evenly into 7 equal shipments by boat or 28 equal shipments by truck. What is the smallest number of boxes that could be in the warehouse?
(A)  28
(B)  33
(C)  54
(D)  81
(E)  162
Rationale: Answer is the LCM of 7 and 28
= 28
Answer A
Answer: (A)  28
Question: The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
(A) 276
(B) 299
(C) 322
(D) 336
(E) 347
Rationale: the numbers are (23 x 13) and (23 x 14).
Larger number = (23 x 14) = 322.
Answer: Option C
Answer: (C) 322
Question: Two pipes A and B can separately fill a cistern in 24 minutes and 48 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 12 minutes. In how much time, the third pipe alone can empty the cistern?
(A) 90 min
(B) 48 min
(C) 54 min
(D) 120 min
(E) 130 min
Rationale: 1/12-(1/24+1/48)=-1/48
third pipe can empty in 48 minutes
ANSWER:B
Answer: (B) 48 min
Question: There are 6 people in the elevator. Their average weight is 154 lbs. Another person enters the elevator, and increases the average weight to 151 lbs. What is the weight of the 7th person.
(A) 133
(B) 168
(C) 189
(D) 190
(E) 200
Rationale: Solution
Average of 7 people after the last one enters = 151 .
âˆ´ Required weight = (7x151)-(6x154)
= 1057- 924
= 133.
Answer A
Answer: (A) 133
Question: A, Band C can do a piece of work in 11 days, 45 days and 55 days respectively, working alone. How soon can the work be done if A is assisted by Band C on alternate days?
(A) 7 days
(B) 8 days
(C) 9 days
(D) 10 days
(E) 11 days
Rationale: (A+B)'s 1 day's work = 1/11+1/45 = 56/495
(A+C)'s 1 day's work = 1/11+1/55 = 6/55
work done in 2 day's = 56/495+6/55 =2/9
2/9th work done in 2 days
work done= 9/2*2 = 9 days
ANSWER:C
Answer: (C) 9 days
Question: What will come in place of the x in the following Number series? 279936, 46656, 7776, 1296, 216, x
(A) 23
(B) 34
(C) 36
(D) 42
(E) 45
Rationale: Go on dividing by 6 to the next number
C)
Answer: (C) 36
Question: A baseball card decreased in value 40% in its first year and 10% in its second year. What was the total percent decrease of the card's value over the two years?
(A) 46%
(B) 30%
(C) 32%
(D) 36%
(E) 72%
Rationale: Let the initial value of baseball card = 100
After first year , value of baseball card = (1- 40/100)* 100 = 60
After second year , value of baseball card =(1 - 10/100)* 60 = 54
total percent decrease of the card's value over the two years = (100-54)/100 *100%
=46%
Answer A
Answer: (A) 46%
Question: A student scored an average of 75 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics?
(A) 86
(B) 16
(C) 76
(D) 95
(E) 26
Rationale: Given M + P + C = 75 * 3 = 225 --- (1)
M + P = 90 * 2 = 180 --- (2)
P + C = 70 * 2 = 140 --- (3)
Where M, P and C are marks obtained by the student in Mathematics, Physics and Chemistry.
P = (2) + (3) - (1) = 180 + 140 - 225
= 95
Answer:D
Answer: (D) 95
Question: The difference between compound and simple interest on a certain sum of money for 3 years at 6 2/3% p.a is Rs.184. Find the sum?
(A) 28882
(B) 27772
(C) 23123
(D) 13500
(E) 28811
Rationale: P = (184*106) / [6 2/3 * 6 2/3 *(300*6 2/3)]
P = 13500
Answer: D
Answer: (D) 13500
Question: The total price of a basic computer and printer are $2,500. If the same printer had been purchased with an enhanced computer whose price was $500 more than the price of the basic computer, then the price of the printer would have been 1/6 of that total. What was the price of the basic computer?
(A) 1500
(B) 1600
(C) 1750
(D) 1900
(E) 2000
Rationale: Let the price of basic computer be C and the price of the printer be P: C+P=$2,500.
The price of the enhanced computer will be C+500 and total price for that computer and the printer will be 2,500+500=$3,000. Now, we are told that the price of the printer is 1/6 of that new total price: P=1/6*$3,000=$500.
Plug this value in the first equation: C+500=$2,500 --> C=$2000
Answer: E.
Answer: (E) 2000
Question: A number consists of 3 digits whose sum is 10. The middle digit is equal to the sum of the other two and the number will be increased by 99 if its digits are reversed. The number is:
(A) 145
(B) 253
(C) 370
(D) 352
(E) 382
Rationale: we can easily solve the ans using the result
all options are fullfill 1st condition ie the sum of digit is 10
now only B and D are full fill the 2nd condition ie middle digit = sum of the side digit
now finally B is the result bcze if we add two number the number must be increase but here if we reverse 352 then it become 253 but if we add 99 the itnever be a small number so thats why result is 253
ANSWER:B
Answer: (B) 253