mathewhe/aqua_rat huggingface dataset:
Question: The mean of 50 observations was 41. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is
(A) 35.2
(B) 36.1
(C) 36.5
(D) 41.5
(E) None
Rationale: Sol.
Therefore correct sum
= ( 41 × 50 + 48 – 23)
= 2075.
Therefore correct mean
= 2075 / 50
= 41.5.
Answer D
Answer: (D) 41.5
Question: A letter lock consists of three rings each marked with five different letters. The number of distinct unsuccessful attempts to open the lock is at the most?
(A) 176
(B) 124
(C) 215
(D) 197
(E) 172
Rationale: Since each ring consists of five different letters, the total number of attempts possible with the three rings is
= 5 * 5*5 = 125. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts
= 125 - 1 = 124.
Answer: B
Answer: (B) 124
Question: A student gets 70% in one subject, 80% in the other. To get an overall of 75% how much should get in third subject.
(A) 75%
(B) 25%
(C) 45%
(D) 55%
(E) 65%
Rationale: A student gets 70% in one subject, 80% in the other.
Average of 2 subjects is 75% , if they have equal weightage.
To get an overall of 75% , he should get 75 % in third subject to maintain same % age..if they have equal weightage.
ANSWER:A
Answer: (A) 75%
Question: A clothing store sells t-shirts arranged on display such that each of the five different colors of t-shirts, orange, green, red, blue, and purple are consecutive in a repeating pattern. If six consecutively displayed t-shirts are purchased, what is the probability that two of the t-shirts are purple?
(A) 2/5
(B) 1/25
(C) 1/5
(D) 3/4
(E) 1/20
Rationale: After orange, green, red, blue, and purple, the next t-shirt can be of any given five colours, therefore we have total five possibilites, out of which we need purple i.e. 1 therefore prob is 1/5. Correct answer is C.
Answer: (C) 1/5
Question: The price of a certain car this year is $18,000, which is 25 percent greater than the cost of the car last year. What was the price of the car last year?
(A) $14,000
(B) $14,200
(C) $14,400
(D) $14,600
(E) $14,800
Rationale: The price of the car last year was $18,000/1.25=$14,400
The answer is C.
Answer: (C) $14,400
Question: Mary decided to save a certain amount of her monthly salary each month and her salary was unchanged from month to month. If Mary's savings by the end of the year from these monthly savings were SIX times the amount she spent per month, what should be the fraction of her salary that she spent each month?
(A) 1/2
(B) 3/4
(C) 1/3
(D) 2/3
(E) 1
Rationale: Saving = S, Expenditure = E, Income = I
At the end of 12months; 12S=6E=6(I-S)
=> 18S = 6I => Savings = 1/3 I
Hence Expenditure = 1-(1/3) = 2/3
Answer (D)
Answer: (D) 2/3
Question: A can do a work in 16 days and B can do it in 8 days. In how many days A and B can do the work?
(A) 20 days
(B) 5 1/3 days
(C) 6 days
(D) 8 days
(E) 7 days
Rationale: Explanation:
A's 1day's work = 1/16
B's 1day's work = 1/8
They work together = 1/16 + 1/8 = 3/16 = 16/3 = 5 1/3days
Answer: Option B
Answer: (B) 5 1/3 days
Question: Nine persons went to a hotel for taking their meals 8 of them spent Rs.12 each on their meals and the ninth spent Rs.8 more than the average expenditure of all the nine.What was the total money spent by them?
(A) Rs.118
(B) Rs.117
(C) Rs.116
(D) Rs.115
(E) Rs.114
Rationale: Let the average expenditure of all nine be Rs.x
Then 12*8+(x+8)=9x or 8x=104 or x=13.
Total money spent = 9x=Rs.(9*13)=Rs.117.
Option B
Answer: (B) Rs.117
Question: Reeya obtained 55, 67, 76, 82 and 55 out of 100 in different subjects, What will be the average
(A) 70
(B) 75
(C) 67
(D) 85
(E) 90
Rationale: Explanation:
(55+67+76+82+55 / 5)=67
Option C
Answer: (C) 67
Question: A can do a piece of work in 15 days and B in 20 days. They began the work together but 5 days before the completion of the work, A leaves. The work was completed in?
(A) 11 3/5
(B) 11 3/0
(C) 11 3/3
(D) 11 3/7
(E) 11 3/2
Rationale: (x – 5)/15 + x/20 = 1
x = 11 3/7 days
Answer: D
Answer: (D) 11 3/7
Question: Cara took out a charge account at the General Store and agreed to pay 5% simple annual interest. If she charges $54 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments?
(A) $55.70
(B) $56.20
(C) $56.70
(D) $57.20
(E) $57.70
Rationale: 1.05*$54=$56.70
The answer is C.
Answer: (C) $56.70
Question: A Martian bat flies at 60 yards per second from its nest to a dry lake. When it arrives there, it immediately continues at 45 yards per second to a nearby cave. If the distance between the lake and the cave is half the distance between the nest and the lake, what is the average speed, in yards per second, of the bat during the whole flight?
(A) 36
(B) 40
(C) 42
(D) 54
(E) 65
Rationale: Distance from nest to lake = d, Speed = 60, Time = d/60
Distance from lake to cave = d/2, Speed = 45, Time = d/90
Average speed = (d + d/2)/(d/60 + d/90) = (3/2)/(1/36) = 54
Answer: D
Answer: (D) 54
Question: 12.1212 + 17.0005 – 9.1102 = ?
(A) 200.01
(B) 20.011
(C) 20.0115.
(D) 20.1
(E) 0.002
Rationale: Solution
Given expression = (12.1212 + 17.0005) - 9.1102 = (29.1217 - 9.1102) = 20.0115. Answer C
Answer: (C) 20.0115.
Question: Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
(A) 1120
(B) 1239
(C) 1300
(D) 1456
(E) 1635
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Large number = 270+1365 = 1635
E
Answer: (E) 1635
Question: Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 70 kmph respectively. In what time will they cross each other completely?
(A) 22 sec
(B) 27 sec
(C) 12 sec
(D) 19 sec
(E) 10 sec
Rationale: D = 250 m + 250 m = 500 m
RS = 80 + 70 = 150 * 5/18 = 125/3
T = 500 * 3/125 = 12 sec
Answer: C
Answer: (C) 12 sec
Question: In What proportion must flour at $0.8 per pound be mixed with flour at $0.9 per pound so that the mixture costs $0.845 per pound?
(A) 1:3
(B) 1:2
(C) 1:1
(D) 2:1
(E) 5:4
Rationale: Using weighted average method:
Let x be the proportion in which the $0.8 per pound flour is mixed with $0.9 per pound flour.
Thus 0.8*x + 0.9*(1-x) = 0.845
0.9 – 0.1x = 0.845
x = 0.55
Thus ratio of both flours is 5:4
E
Answer: (E) 5:4
Question: In a particular state, 60% of the counties received some rain on Monday, and 65% of the counties received some rain on Tuesday. No rain fell either day in 25% of the counties in the state. What percent of the counties received some rain on Monday and Tuesday?
(A) 12.5%
(B) 40%
(C) 50%
(D) 60%
(E) 67.5%
Rationale: 60 + 65 + 25 = 150%
The number is 50% above 100% because 50% of the counties were counted twice.
The answer is C.
Answer: (C) 50%
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
(A) 380
(B) 384
(C) 356
(D) 324
(E) 314
Rationale: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m.
Answer: Option B
Answer: (B) 384
Question: The sum of 9 hours 25 minutes and 4 hours 35 minutes is approximately what percent of a day?
(A)  64%
(B)  56%
(C)  58%
(D)  48%
(E)  72%
Rationale: Since the question is asking for an approximate percentage
9:25+4:35 = 14 hours
% of day = 14*100/24 = 7*100/25 ~ 58%
Answer is C.
Answer: (C)  58%
Question: 8, 24, 12, 36, 18, 54, (....)
(A) 27
(B) 68
(C) 108
(D) 72
(E) 75
Rationale: Explanation :
8 × 3 = 24
24 ÷ 2 = 12
12 × 3 = 36
36 ÷ 2 = 18
18 × 3 = 54
54 ÷ 2 = 27
Answer : Option A
Answer: (A) 27
Question: A train 108 m long is moving at a speed of 50 km/hr . It crosses a train 112 m long coming from opposite direction in 6 seconds. What is the speed of the second train?
(A) 81km/hr
(B) 80km/hr
(C) 82km/hr
(D) 85km/hr
(E) 84km/hr
Rationale: Total distance = 108+112 = 220 m
Time = 6s
Relative speed = distance/time = 220/6 m/s = 110/3 m/s
= (110/3) × (18/5) km/hr = 132 km/hr
=> 50 + speed of second train = 132 km/hr
=> Speed of second train = 132-50 = 82 km/hr
Answer is C.
Answer: (C) 82km/hr
Question: The marching band is made up of 140 musicians. The band wants to form a rectangular formation with A people in a row and B people in a column. If the number of people in a row is more than 4 and less than 35, how many different combinations of rectangular shapes are possible?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: firstly factors of 140 = 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140
the question says each row will have musicians more than 4 and less than 35,
therefore, we should be interested in the factors between 4 and 35 (noninclusive)
5(in each row) * 28(number of columns) =140, similarly
7 * 20
10 * 14
14 * 10
20 * 7
28 * 5
total possibilities = 6
option D
Answer: (D) 6
Question: The average of 20, 40 and 150 is twice the average of 10, 30, and which of the following ?
(A) 1)10
(B) 2)30
(C) 3)65
(D) 4)90
(E) 5)180
Rationale: 20 40 150 = 150+60 = 210/3 = 70.
70/2 = 35
10 30 x = 40+x/3 should be smaller than 35
cross multiply 35*3-40 = 65
C
Answer: (C) 3)65
Question: A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
(A) 170
(B) 200
(C) 626
(D) 207
(E) 227
Rationale: The number of ways to select two men and three women = ⁵C₂ * ⁶C₃
= (5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)
= 200
Answer:B
Answer: (B) 200
Question: At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party?
(A) 14
(B) 18
(C) 11
(D) 17
(E) 12
Rationale: In general, with n+1 people, the number of handshakes is the sum of the first n consecutive numbers: 1+2+3+ ... + n.
Since this sum is n(n+1)/2, we need to solve the equation n(n+1)/2 = 66.
This is the quadratic equation n2+ n -132 = 0. Solving for n, we obtain 11 as the answer and deduce that there were 12 people at the party.
correct answer is E)12
Answer: (E) 12
Question: If the perimeter of a rectangular garden is 600 m, its length when its breadth is 100 m is?
(A) 228
(B) 288
(C) 200
(D) 288
(E) 111
Rationale: 2(l + 100) = 600 => l = 200 m
Answer: C
Answer: (C) 200
Question: A fellow borrowed a certain sum of money at 4% per annum at simple interest and in 4 years the interest amounted to Rs.1260 less than the sum lent. What was the sum lent?
(A) 1050
(B) 1220
(C) 1500
(D) 1060
(E) 1110
Rationale: P - 1260 = (P*4*4)/100
P = 1500
Answer: C
Answer: (C) 1500
Question: On the first day of her vacation, Louisa traveled 250 miles. On the second day, traveling at the same average speed, she traveled 350 miles. If the 250-mile trip took 3 hours less than the 350-mile trip, what was the average speed, in miles per hour?
(A) 31
(B) 33.33
(C) 35
(D) 37
(E) 39.33
Rationale: (time)*(rate) = (distance)-->(rate) = (distance)/(time)--> given:(rate) = 250/t = 350/(t+3)-->5/t = 7/(t+3)-->5t+15=7t ---->2t= 15 . t= 7.5 ---->(rate ) = 250/7.5 = 33.33
Answer: B
Answer: (B) 33.33
Question: A certain bakery baked a batch of 470 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?
(A) 166
(B) 293
(C) 413
(D) 438
(E) 511
Rationale: Cookies which have both nuts and chocolate chips = 165
Let fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that
batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch = x
(165+x)/(470+x) = 6/10
=>1650 + 10x = 2820 + 6x
=> 4x = 1170
=> x = 292.5
Therefore x = 293
Answer B
Answer: (B) 293
Question: An amount of money is to be divided between M, N and O in the ratio of 3:7:12. If the difference between the shares of M and N is Rs.2000, what will be the difference between N and O's share?
(A) 1266
(B) 3000
(C) 2866
(D) 2500
(E) 2678
Rationale: 7-3= 4= 2000
12-7 = 5 = 2000/4*5 = 2500
Answer : D
Answer: (D) 2500
Question: The ratio of three numbers is 3:4:5 and the sum of their squares is 1250. The sum of the numbers is:
(A) 20
(B) 40
(C) 60
(D) 80
(E) 100
Rationale: Let the numbers be 3x, 4x and 5x
Then, 9x2+16x2+25x2=1250
50x2=1250
X=5
Sum of numbers= 3x+4x+5x=12x=60
ANSWER C
Answer: (C) 60
Question: The width of a rectangular hall is ½ of its length. If the area of the hall is 450 sq.m, what is the difference between its length and breadth?
(A) 8m
(B) 10m
(C) 12m
(D) 15m
(E) 17m
Rationale: Let the length of the hall be x m
Breadth of the hall = 1x/2 m
Area of the hall = Length * Breadth
450 = x * 1x/2
x² = 900
x =30
Difference between the length and breadth of the hall = x - 1x/2 = x/2
=30/2 = 15m
ANSWER:D
Answer: (D) 15m
Question: What percent of the different arrangements of the letters of the word AGAHUS are those in which the vowels appear together?
(A) 30%
(B) 25%
(C) 20%
(D) 40%
(E) 25%
Rationale: let's determine the number of total possibilities in arranging the letters. There are six spaces, so the total number of arrangements is 6!, or 360.
Next, we need to figure out how to determine the number of ways that we can arrange the 3 vowels together - simply place them together (as in AAU) and call that a single place.
Next, we must determine the number of ways to arrange the now 4 units (i.e., AAU, B, C, S). Like above, there are 4 units and 4 places so the number of arrangements is 4!, or 24.
Finally, we need to account for the number of ways we can arrange AAU. We can either write out each unique iteration (AAU, AUA and UAA) or calculate as 3!/2! and get 3.
Putting this all together, we get the number of ways to arrange the letters so that the vowels are together is 4! x 3 ==> 72
the number of total arrangements of all the letters is 6! ==> 360
72/360 = 1/5, or 20% Correct answer is C
Answer: (C) 20%
Question: An engineer designed a ball so that when it was dropped, it rose with each bounce exactly one-half as high as it had fallen. The engineer dropped the ball from a 16-meter platform and caught it after it had traveled 46.5 meters. How many times did the ball bounce?
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
Rationale: Going down = 16 m
Going Up = 8 --> Total = 24
Going down = 8 --> Total = 32
Going Up = 4 --> Total = 36
Going down = 4 --> Total = 40
Going up = 2 --> Total = 42
Going down = 2 --> Total = 44
Going up = 1 --> Total = 45
Going down = 1 --> Total = 46
Going up = 0.5 --> Total = 46.5 (Caught)
No of going downs = 5 ..
ANSWER:A
Answer: (A) 5
Question: A club wants to mix 15 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used?
(A) 20
(B) 30
(C) 40
(D) 50
(E) 60
Rationale: Let number of pounds of 5$ candy to be used be w
6 = (15*8 + 5*w)/(15 +w)
=>90 + 6w = 120 + 5w
=> w = 30
Answer B
Answer: (B) 30
Question: A batsman of a cricket has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, thereby increasing his average by 6 runs. His new average is:
(A) 48 runs
(B) 52 runs
(C) 55 runs
(D) 60 runs
(E) None of these
Rationale: Explanation :
Let average for 10 innings be x. Then, (10x + 108)/11 = x + 6
11x + 66 = 10x + 108
x = 42
New average = (x + 6) = 48 runs.
Answer : A
Answer: (A) 48 runs
Question: A man goes to shopkeeper and says that if u give me as much as i have ,i will spend Rs.10/- on ur shop. shopkeeper agrees and man moves to another shopkeeper ans asked same. at 3rd shop after all the transaction, he was left with no money. find the initial amount with the man
(A) 5.75
(B) 6.75
(C) 7.75
(D) 8.75
(E) 9.75
Rationale: man has Rs.x
he leaves-
1st shop wid Rs.(2x-10)
2nd shop wid Rs.[2(2x-10)-10]
3rd shop wid Rs.{2[2(2x-10)-10]-10}=0(since he has no money left)
so solving the eqn x=8.75
ANSWER:D
Answer: (D) 8.75
Question: If a person walks at 15 km/hr instead of 5 km/hr, he would have walked 20 km more. The actual distance traveled by him is?
(A) 50 km
(B) 76 km
(C) 18 km
(D) 10 km
(E) 97 km
Rationale: Let the actual distance traveled be x km. Then,
x/5 = (x + 20)/15
10x - 100 =>x = 10 km.
Answer: D
Answer: (D) 10 km
Question: The present age of a father is 3 years more than three times the age of his son. Five years hence, father's age will be 10 years more than twice the age of the son. Find the present age of the father.
(A) 33
(B) 38
(C) 27
(D) 40
(E) 48
Rationale: if the present age be x years.
father's will be (3x+3)years..
so, (3x+3+5)=2(x+3)+10
or, x=8
so the fathers present age =(3x+3)=(3*8+3)years =27 years..
ANSWER : OPTION C
Answer: (C) 27
Question: What percent of the month of April is 20 days?
(A) 75%
(B) 66,66%
(C) 60%
(D) 64,5%
(E) 70%
Rationale: Explanation :
Total days in the month of April = 30
Required percentage = (20/30) Ã— 100 = 66,66%
Answer : Option B
Answer: (B) 66,66%
Question: If P represents the product of the first 14 positive integers, then P is NOT a multiple of
(A) 99
(B) 84
(C) 72
(D) 65
(E) 34
Rationale: Answer is E.
Since prime factor of 57 is 2x17. 17 is a prime number and not part of the first 14 positive integers.
A) 9 x 11
B) 12 x 7
C) 12 x 6
D) 13 x 5
E) 2 x 17
Answer: (E) 34
Question: 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.60 only. Menâ€™s wages are?
(A) 6Rs
(B) 7Rs
(C) 8Rs
(D) 4Rs
(E) 1Rs
Rationale: 5M = xW = 8B
5M + xW + 8B ----- 60 Rs.
5M + 5M + 5M ----- 60 Rs.
15M ------ 60 Rs. => 1M = 4Rs.
Answer:D
Answer: (D) 4Rs
Question: Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age
(A) 12,28
(B) 14,30
(C) 16,32
(D) 18,34
(E) 19,34
Rationale: Explanation:
Let the age of younger person is x,
Then elder person age is (x+16)
=> 3(x-6) = (x+16-6) [6 years before]
=> 3x-18 = x+10
=> x = 14.
So other person age is x + 16 = 30
Answer: Option B
Answer: (B) 14,30
Question: On simplification, 3500 – (1000 ÷ 20.50) is equal to :
(A) 3451.21
(B) 3029.0
(C) 2993.03
(D) 2984.36
(E) None of these
Rationale: Explanation:
Given exp. = 3500 - ((1000 ÷ 2050) * 100)
= 3451.21
ANSWER A
Answer: (A) 3451.21
Question: An alloy weighing 16 ounces is 50% gold. How many ounces of pure gold must be added to create an alloy that is 80% gold?
(A) 24
(B) 18
(C) 9
(D) 27
(E) 18
Rationale: An alloy of 16oz which is 50% gold means there is 8 oz of gold. To get to an alloy that is 80% gold, let's use this expression: (8 + x)/(16 + x) = 0.8 with x representing the amount of pure gold that must be added to get to 80%. The expression we are using represents the new total weight of pure gold over the new total new weight of the alloy and this fraction should represent 80% or 0.8. you will see that 24 is the correct answer, as 32/40=0.8
Choose A
Answer: (A) 24
Question: Ben and King are partners in a business. Ben is a working partner and King is a sleeping partner in the business. Ben invested Rs.3500 and King invested Rs.7000. Ben receives 7% of the profit for managing the business the rest is divided in proportion of their capitals. Out of a total profit of Rs.9600, how much did Ben receive?
(A) 2648
(B) 3648
(C) 3548
(D) 4648
(E) 3628
Rationale: ratio of their investments Rs.3500:Rs.7000=1:2
7% of the profit for managing the business =7/100*9600=672
remaining profit=9600-672=8928
share profit in ratio of investment 8928/3 =2976
Ben ratio share=1*2976=2976
total money Ben collects=2976+672=3648
Answer: B
Answer: (B) 3648
Question: Which of the following is the lowest positive integer that is divisible by the first 7 positive integer multiples of 3?
(A) 600
(B) 820
(C) 1040
(D) 1260
(E) 1480
Rationale: The number must be divisible by 3, 2*3, 3^2, 2^2*3, 5*3, 2*3^2, and 7*3.
The lowest such number is 2^2*3^2*5*7 = 1260.
The answer is D.
Answer: (D) 1260
Question: The average age of three boys is 10 years and their ages are in proportion 2:4:4. What is the age in years of the youngest boy?
(A) 6
(B) 9
(C) 8
(D) 4
(E) 2
Rationale: 2x + 4x + 4x = 30
x =3
2x = 6
Answer: A
Answer: (A) 6
Question: Of the 200 employees in a certain company, 25 percent will be relocated to City X and the remaining 75 percent will be relocated to City Y. However, 30 percent of the employees prefer City Y and 70 percent prefer City X. What is the highest possible number of employees who will be relocated to the city they prefer?
(A)  65
(B)  110
(C)  115
(D)  130
(E)  135
Rationale: 140 prefer X (Group 1);
60 prefer Y (Group 2).
City Y needs 150 people: letall 60 who prefer Y (entire Group 2) be relocated there, the rest 90 will be those who prefer X from Group 1;
City X needs 50 people: 140-90=50 from Group 1 will be relocated to X, which they prefer.
So, the highest possible number of employees who will be relocated to the city they prefer is 60+50=110.
Answer: B.
Answer: (B)  110
Question: How many zeros are the end of 380! ?
(A) 90
(B) 91
(C) 94
(D) None
(E) 95
Rationale: 380! has 380/5+380/5^2+380/5^3=76+15+3=94 trailing zeros ( take only the quotient into account).
Answer: C.
Answer: (C) 94
Question: (0.0077)(3.6) / (0.04)(0.1)(0.007)=
(A) 0.099
(B) 0.0099
(C) 9.9
(D) 990
(E) 99
Rationale: (0.0077)(3.6) / (0.04)(0.1)(0.007)=0.0077 * 360/4 * (0.1)(0.007)
= 0.077*90/1 * 0.007 = 77*90/7 = 11*90
=990
Answer : D
Answer: (D) 990
Question: A factory that employs 1000 assembly line workers pays each of these workers $5 per hour for the first 40 hours worked during a week and 1½ times that rate for hours worked in excess of 40. What was the total payroll for the assembly-line workers for a week in which 30 percent of them worked 35 hours, 50 percent worked 40 hours, and the rest worked 50 hours?
(A)  $180,000
(B)  $185,000
(C)  $190,000
(D)  $207,500
(E)  $205,000
Rationale: 30% of 1000 = 300 worked for 20 hours
Payment @ 5/hr
Total Payment = 300*35*5 = 52500
50 % of 1000 = 500 worked for 40 hours
Payment @ 5/hr
Total payment = 500*40*5 = 100000
Remaining 200 worked for 50 Hours
Payment for first 40 Hours @ 5 /hr
Payment = 200*40*5 = 40000
Payment for next 10 hr @ 7.5/hr
Payment = 200 * 10 * 7.5 = 15000
Total Payment = 52500+100000 + 40000 +15000 = 207500
Hence , answer is D
Answer: (D)  $207,500
Question: In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:
(A) 21 m
(B) 26 m
(C) 28m
(D) 29m
(E) 30m
Rationale: Explanation:
A : B = 100 : 75
B : C = 100 : 96.
A : C =A/BXB/C=100/75 X100/96=100:72
A beats C by (100 - 72) m = 28 m.
ANSWER IS C
Answer: (C) 28m
Question: The radius of the two circular fields is in the ratio 3: 7 the area of the first field is what percent less than the area of the second?
(A) 82.9%
(B) 84.2%
(C) 81.0%
(D) 80.6%
(E) 81.6%
Rationale: r = 3 Ï€r2 = 9
r = 7 Ï€r2 =49
49Ï€ â€“ 40 Ï€
100 ---- ? => 81.6%.Answer:E
Answer: (E) 81.6%
Question: If the perimeter of a rectangular playground is 1200 m, its length when its breadth is 500 m is?
(A) 300
(B) 200
(C) 100
(D) 400
(E) 500
Rationale: 2(l + 500) = 1200 => l = 100 m Answer: C
Answer: (C) 100
Question: Ashok and Pyarelal invested money together in a business and share a capital of Ashok is 1/9 of that of Pyarelal.if the incur a loss of Rs 1600 then loss of Pyarelal?
(A) 600
(B) 700
(C) 840
(D) 940
(E) 1440
Rationale: Let the capital of Pyarelal be x, then capital of Ashok=x/9
So ratio of investment of Pyarelal and Ashok = x : x/9 =9x : x
Hence out of the total loss of 1600, loss of Pyarelal= 1600*9x/10x=1440
ANSWER:E
Answer: (E) 1440
Question: A tradesman by means of his false balance defrauds to the extent of 14%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
(A) 54.6%
(B) 29.96%
(C) 24.45%
(D) 24%
(E) 45%
Rationale: g% = 14 + 14 + (14*14)/100
= 29.96%
Answer: B
Answer: (B) 29.96%