mathewhe/aqua_rat huggingface dataset:
Question: Find the simple interest on the Rs. 2000 at 25/4% per annum for the period from 4th Feb 2005 to 18th April 2005
(A) Rs 25
(B) Rs 30
(C) Rs 35
(D) Rs 40
(E) None of these
Rationale: Explanation:
One thing which is tricky in this question is to calculate the number of days.
Always remember that the day on which money is deposited is not counted while the day on which money is withdrawn is counted.
So lets calculate the number of days now,
Time = (24+31+18) days = 73/365 years = 1/5 years
P = 2000
R = 25/4%
S.I. = =2000×25 /4×5×100=25
Option A
Answer: (A) Rs 25
Question: A man is 18 years older than his son. In eight years, his age will be twice the age of his son. The present age of this son is
(A) 5 years
(B) 10 years
(C) 15 years
(D) 20 years
(E) 25 years
Rationale: Explanation:
Let's Son age is x, then Father age is x+18.
=> 2(x+8) = (x+18+8)
=> 2x+16 = x+26
=> x = 10 years
Answer: Option B
Answer: (B) 10 years
Question: Calculate 73196 ÷ ? = 631
(A) 101
(B) 116
(C) 119
(D) 116
(E) 32
Rationale: Answer
Let 62976/X = 631
Then X = 62976/631 =116
Option: D
Answer: (D) 116
Question: The angles of a triangle are in the ratio 2: 6 : 4. Find the measurement of the 3 angles of triangle.
(A) 90°
(B) 60°
(C) 20°
(D) 30°
(E) 80°
Rationale: If the ratio of the three angles is 2:6:4, then the measures of these angles can be written as 2x, 6x and 4x. Also the sum of the three interior angles of a triangle is equal to 180°. Hence
2x + 6x + 4x = 180
Solve for x
12x = 180
x =15
The measures of the three angles are
2x =2 x15=30°
6x = 6 × 15= 90°
4x = 4 × 15 = 60°
B
Answer: (B) 60°
Question: If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,880,715 minutes earlier? (Assume standard time in one location.)
(A) 6:23
(B) 6:24
(C) 6:27
(D) 6:30
(E) 6:32
Rationale: 6:27minus 2,880,715in any way must end with 2, the only answer choice which ends with 2 is E.
Answer: E.
Answer: (E) 6:32
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions?
(A) 708 m
(B) 704 m
(C) 774 m
(D) 714 m
(E) 744 m
Rationale: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4 = 70400 cm
= 704 m
Answer:B
Answer: (B) 704 m
Question: Machines X and Y produce bottles at their respective constant rates. Machine X produces k bottles in 6 hours and machine Y produces k bottles in 3 hours. How many hours does it take machines X and Y , working simultaneously , to produce 12k bottles?
(A) 4
(B)  8
(C)  12
(D)  18
(E)  24
Rationale: x rate = k/6
y rate = k/3
k/6 + k/3 = 12k / T
solving T = 24
Answer E
Answer: (E)  24
Question: In Town X, 64 percent of the population are employed, and 44 percent of the population are employed males. What percent of the employed people in Town X are females?
(A) 16%
(B) 55%
(C) 29%
(D) 40%
(E) 52%
Rationale: answer b
male-employed - 64%
female-employed-20%
Total employed 64%
means total unemployed = 36%
therefore d and e are not correct because female unemployed has to be less than 36%
female-unemployed = 32% male unemployed = 4%
48% + 4% = 52%
16% + 32% = 48%
plug in a and b in place of 32% and the sum is not 100%
20/64 =29 C
Answer: (C) 29%
Question: If R is a negative integer and K is a positive integer, which of the following could be the standard deviation of a set {-7, -5, -3, R, 0, 1, 3, K, 7}?
I. -1.5
II. -2
III. 0
(A)  I only
(B)  II only
(C)  III only
(D)  I and III only
(E)  None
Rationale: The answer should be (E) as S.D cannot be negative. It is only 0 if all numbers in the set are equal, which is not the case either.E
Answer: (E)  None
Question: An investment of $100 was made in a certain account and earned interest that was compounded annually. The annual interest rate was fixed for the duration of the investment, and after 12 years the $100 increased to $400 by earning interest. In how many years after the initial investment was made the $1000 have increased to $8000 by earning interest at that rate?
(A) 16
(B) 20
(C) 18
(D) 24
(E) 30
Rationale: In 12 years the investment quadrupled (from $100 to $400).
Thus, at the same rate compounded annually, it would need additional 12/2=6 years to double (from $400 to $800).
Therefore, 12+6=18 years are needed $100 to increase to $800.
Answer: C.
Answer: (C) 18
Question: A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 650 m long?
(A) 26
(B) 89
(C) 76
(D) 27
(E) 23
Rationale: Speed = 240/24 = 10 m/sec.
Required time = (240 + 650)/10
= 89 sec.
Answer:B
Answer: (B) 89
Question: Two Nascar stock cars take off from the starting line at the exact same time, heading in opposite directions. The Budweiser Car travels at 145 miles per hour, while the Stella Artois car travels at 150 miles per hour. At this rate, and ignoring other variable, how long will the cars have to drive in order to be 500 miles, in total, from each other?
(A) 1.5 hours
(B) 1.27 hours
(C) 1.73 hours
(D) 2 hours
(E) 1.69 hours
Rationale: The cars travel (145+150=295) miles in one hour.
500 miles/295 miles/hour= 1.69 hours
Answer is E
Answer: (E) 1.69 hours
Question: How many 3-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHM', if repetition of letters is not allowed?
(A) 690
(B) 504
(C) 740
(D) 760
(E) 780
Rationale: The word 'LOGARITHM' has 9 different letters.
Hence, the number of 3-letter words(with or without meaning) formed by using these letters
= 9P3
=
9
×
8
×
7
=
504
Option B
Answer: (B) 504
Question: 10, 14, 26, 42, 70, ?
(A) 86
(B) 98
(C) 114
(D) 126
(E) 136
Rationale: Each term of the series, except the first two terms, is 2 more than the sum of the preceding two terms.
Answer : C.
Answer: (C) 114
Question: A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 60%?
(A) 800
(B) 882
(C) 772
(D) 652
(E) 271
Rationale: Cost price = Rs.500
profit = 60% of 500 = Rs.300
Selling price = Cost price + Profit
= 500 + 300 = 800
Answer:A
Answer: (A) 800
Question: A trader cheats both his supplier and customer by using faulty weights. When he buys from the supplier, he takes 10% more than the indicated weight. When he sells to his customer, he gives the customer a weight such that 30% of that is added to the weight, the weight claimed by the trader is obtained. If he charges the cost price of the weight that he claims, find his profit percentage.
(A) 20%
(B) 43%
(C) 99.33%
(D) 75.109%
(E) 47%
Rationale: Anyways, one can infer that he 'steals' 10% from suppliers and then charges 30% extra to customers
So basically 1.1 * 1.3 = 1.43
Given that 1 is start point, we get 43% more
Hence answer is B
Answer: (B) 43%
Question: Fox jeans regularly sell for $10 a pair and Pony jeans regularly sell for $18 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $9 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discounts rates is 22 percent, what is the discount rate on Pony jeans?
(A) 9%
(B) 10%
(C) 11%
(D) 12%
(E) 40%
Rationale: x discount on Pony jeans, (0.22-x) discount on Fox jeans.
Set the equation: 3*10(0.22-x)+2*18x=9 --> x=0.4=40%
Answer: E.
Answer: (E) 40%
Question: The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?
(A) 39
(B) 37
(C) 342
(D) 288
(E) 261
Rationale: 400*(90/100)*(95/100) = 342
Answer: C
Answer: (C) 342
Question: John must arrange 3 different physics books and 4 different mathematics books on one shelf. If the first book on the leftmost side is a mathematics book and no physics book is next to another physics book. How many different arrangements exist?
(A) 6
(B) 9
(C) 36
(D) 120
(E) 144
Rationale: First Place, is reserved for Math book. There are 3 Math books which can be arranged in3 ways
Restriction comes into playhysics book cannot be together. Hence, the maththe physics books take alternate places
Second Place, Physics Book - in 4 ways
Third Place, Math Book - in 2 ways (only 2 books left)
Fourth Place, Physics - in 2 ways (only 2 Physics book left)
Rest two places can be arranged in one way only.
Total no of ways = 4*3*3*2*2*1*1 = 144 ways
E
Answer: (E) 144
Question: A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.
(A) 200, 360,162
(B) 200, 460,160
(C) 200, 360,160
(D) 200, 360,138
(E) 200, 360,129
Rationale: Explanation:
let ratio be x.
Hence no. of coins be 5x ,9x , 4x respectively
Now given total amount = Rs.206
=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206
we get x = 40
=> No. of 50p coins = 200
=> No. of 25p coins = 360
=> No. of 10p coins = 160
Answer: C)
Answer: (C) 200, 360,160
Question: If (A-B-C+D = 18) and (A+B-C-D = 4), what is the value of (B-D)^2?
(A) 49.
(B) 8.
(C) 12.
(D) 16.
(E) 64.
Rationale: EQ1: A - B - C + D = 18
EQ2: A + B - C - D = 4
(1) Subtract EQ1 from EQ2
A - B - C + D = 18
- A +B - C - D = 4
------------------------
-2B + 2D = 14
(2) Simplify
-B + D = 7
B - D = -7
(B-D)^2 = (-7)^2 = 49
My answer: A
Answer: (A) 49.
Question: A vendor sells 60 percent of the apples he had and throws away 40 percent of the remainder. The next day, the vendor sells 50 percent of the remaining apples and throws away the rest. In total, what percent of his apples does the vendor throw away?
(A) 24
(B) 26
(C) 28
(D) 30
(E) 32
Rationale: Let x be the original number of apples.
On day one, the vendor throws away (0.4)(0.4)x=0.16x.
The remaining apples are (0.6)(0.4)x = 0.24x.
On day two, the vendor throws away (0.5)(0.24)x=0.12x.
The vendor throws away a total of 0.16x + 0.12x = 0.28x.
The vendor throws away 28 percent of the apples.
The answer is C.
Answer: (C) 28
Question: A bookshop had science and art books in the ratio of 2:5. By the end of the week, 20% of both type of books were sold and 2240 books were unsold. How many science books were there at the starting?
(A) 700
(B) 750
(C) 780
(D) 800
(E) 820
Rationale: science books sold = 2x × 0.2 = 0.4x
science books unsold = 2x – 0.4x = 1.6x
art books sold = 5x × 0.2 = x
art books unsold = 5x – x = 4x
total books unsold = 1.6x + 4x = 5.6x
5.6x = 2240
x = 400
2x science = 800
D
Answer: (D) 800
Question: A perfect cube is an integer whose cube root is an integer. For example, 27, 64 and 125 are perfect cubes. If p and q are perfect cubes, which of the following will not necessarily be a perfect cube?
(A) 8p
(B) pq
(C) pq + 27
(D) -p
(E) (p - q)^6
Rationale: A. since p is a perfect cube and 8 is a perfect cube, 8p will be a perfect cube. reject.
B. since p is a perfect cube and q is a perfect cube, pq will be a perfect cube. reject.
C. Hold.
D. since p is a perfect cube, -p will also be a perfect cube. reject.
E. (p-q)^6, is a perfect cube, so reject.
By elimination C is the answer.
Check say p = 1, q=8, then 8+27 = 35 --> not a perfect cube.
ANSWER:C
Answer: (C) pq + 27
Question: find value for x from given equation? x + 1 = -3
(A) 1
(B) -4
(C) -3
(D) -5
(E) 5
Rationale: 1. Subtract 1 from both sides:
x + 1 - 1 = -3 - 1
2. Simplify both sides:
x = -4
B
Answer: (B) -4
Question: If n is a positive integer, which of the following is a possible value of |71 - 5n| ?
(A) 7
(B) 5
(C) 19
(D) 15
(E) 20
Rationale: When 71>5n, then |71- 5n| = 71- 5n = (70-5n) + 1 = {multiple of 5} + 1
When 71<=5n, then |71 - 5n| = -(71- 5n) = (5n-70) - 1 = {multiple of 5} - 1
So, the correct answer must be 1 greater or 1 less than a multiple of 5. Only C fits.
Answer: C
Answer: (C) 19
Question: SI on a certain sum of money for 3 yrs at 8 percent /annum is 1/2 the CI on Rs.4000 for 2 yrs at 10 percent/ annum. The sum placed on SI is?
(A) Rs. 1600
(B) Rs. 1650
(C) Rs. 1750
(D) Rs. 1800
(E) Rs. 1900
Rationale: C.I.
= Rs. 4000 x 1 +	10 2	- 4000
100
= Rs. 4000 x	11	x	11	- 4000
10	10
= Rs. 840.
Sum = Rs. 420 x 100 = Rs. 1750.
3 x 8
C
Answer: (C) Rs. 1750
Question: The sum of two numbers is 40 and their product is 300. What will be the sum of their reciprocals?
(A) 1/40
(B) 8/75
(C) 75/4
(D) 2/15
(E) 75/6
Rationale: (1/a)+(1/b)=(a+b)/ab=40/300=2/15
ANSWER:D
Answer: (D) 2/15
Question: The length of a rectangle is four times its width. If the area is 100 m2 what is the length of the rectangle?
(A) 50 m
(B) 40 m
(C) 80 m
(D) 20 m
(E) 70 m
Rationale: Let L be the length and W be the width of the rectangle. Hence
L = 4 W
We now use the area to write
100 = L ? W
Substitute L by 4 W in the equation above
100 = 4 W ? W = 4 W2
Solve for W and find L
4 W2 = 100
W2 = 25 , W = 5 and L = 4 W = 20 m
correct answer D
Answer: (D) 20 m
Question: There are 15 boys and 10 girls in a class. If three students are selected at random, in how many ways that 1 girl or 2 boys are selected ?
(A) 100
(B) 105
(C) 115
(D) 120
(E) 125
Rationale: n(s) = sample space = 25C3 = 2300
E = event that 1 girl and 2 boys are selected
n(E) = we have to select 2 boys from 15 or 1 girl from 10
= 15C2 + 10C1
= 115
Ans - C
Answer: (C) 115
Question: A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock?
(A) 30000
(B) 66000
(C) 53000
(D) 20000
(E) 45000
Rationale: D
20000
Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x - 49x/50 = x/50
x/50 = 400 => x = 20000
Answer: (D) 20000
Question: In a plastic company, 14 men working 8 hrs per day complete a piece of work in 12 days. To complete the same work in 6 days, working 14 hours a day, the number of men required is :
(A) 16
(B) 8
(C) 12
(D) 20
(E) 22
Rationale: Explanation :
Solution: Let the required number of men be x.
Less days, more men (Indirect proportion)
more working hrs per day, less men (Indirect proportion)
days 6 : 12
} : : 14 :x
working hrs 14 : 8
.'. 6*14*x = 12*8*14 \
=> x =16.
Answer : A
Answer: (A) 16
Question: Five friends, Peter, Eric, Melyssa, Tony, and Carl, are pooling their money to buy a $1300 item. Peter has twice as much money as Melyssa. Tony has $60 more than Peter. Carl has 20% more than Tony and Eric has twice as much as Peter. If they put all their money together and spend the $1300, they will have $38 left. How much money does Peter have?
(A) $300
(B) $270
(C) $320
(D) $350
(E) $220
Rationale: P= 2M ; T= P+60 ; C= 1.2(T); P=(E/2)
P+M+T+C+E-1300=38
P+0.5P+P+60+1.2(P+20)+2P = 1338
P+0.5P+P+60+1.2P+24+2P = 1338
P+0.5P+P+1.2P+2P+84 = 1338
P+0.5P+P+1.2P+2P = 1254
5.7P = 1254
P=220
Answer:E
Answer: (E) $220
Question: Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of the tickets sold, 30% were sold at half price and the remaining tickets were sold at the full price of $2. What was the total revenue from ticket sales?
(A) $16,830
(B) $17,820
(C) $18,000
(D) $19,800
(E) $21,780
Rationale: 10000 seats --> Full Price : Half Price = 7000 : 3000
Price when all seats are filled = 14000 + 3000 = 17000
100 seats are unsold --> Loss due to unfilled seats = 30 + 2*70 = 170
Revenue = 17000 - 170 = 16830
Answer: A
Answer: (A) $16,830
Question: In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 100?
(A) 18
(B) 27
(C) 25
(D) 21
(E) 17
Rationale: A scores 60 while B score 40 and C scores 30.
The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.
In a game of 100 points, B gives (100 - 75) = 25 points to C.
Answer: C
Answer: (C) 25
Question: A person distributed 20% of his income to his 3 children each. He deposited 25% of his income to his wife's account. He donated 5% of remaining amount to an orphan house.Finally he has $40000. Find his total income?
(A) A)452000
(B) B)562000
(C) C)800000
(D) D)400000
(E) E)652000
Rationale: 3 children got = 3*20% = 60%
wife got = 25%
orphan house = 5%
total = 60+25+5 = 90%
remaining = 100-90 = 10%
10% = 40000
100% = 40000*100/10 = $400000
Answer is D
Answer: (D) D)400000
Question: A part of certain sum of money is invested at 9% per annum and the rest at 12% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is?
(A) 4:2
(B) 4:8
(C) 4:3
(D) 4:0
(E) 4:9
Rationale: 12:9
= 4:3
Answer: C
Answer: (C) 4:3
Question: In what time will a railway train 50 m long moving at the rate of 36 kmph pass a telegraph post on its way?
(A) 5 sec
(B) 4 sec
(C) 3 sec
(D) 6 sec
(E) 1 sec
Rationale: T = 50/36 * 18/5 = 5 sec
Answer: A
Answer: (A) 5 sec
Question: With what number must 3.475817 be multiplied in order to obtain the number 34.75817?
(A) 100
(B) 1000
(C) 10,000
(D) 100,000
(E) None of these
Rationale: Explanation: The decimal must be moved one places to the right. To do this, we must multiply by a number with one zeroes. The correct answer is 10 .The decimal must be moved one places to the right. To do this, we must multiply by a number with one zero. The correct answer is 10.
Answer : (E)
Answer: (E) None of these
Question: The average of 11 results is 44, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?
(A) 122
(B) 156
(C) 118
(D) 125
(E) 123
Rationale: 1 to 11 = 11 * 44 = 484
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 â€“ 484 = 122
Answer:A
Answer: (A) 122
Question: In a school 50% of the students are younger than 10, 1/20 are 10 years old and 1/10 are older than 10 but younger than 12, the remaining 70 students are 12 years or older. How many students are 10 years old?
(A) 10 students
(B) 20 students
(C) 30 students
(D) 40 students
(E) 50 students
Rationale: Let us write the fraction for each group of students
Group A: younger than 10: 50% = 50/100 = 1/2
Group B: 10 years old: 1/20
Group C: older that 10 but younger than 12: 1/10
Group D: 12 years or older: 70 students
The fraction for group A, B and C together is given by
1 / 2 + 1 / 20 + 1 / 10 = 10 / 20 + 1 / 20 + 2 / 20 , common denominator
= 13 / 20 , add numerators
The fraction for group D is given by
20 / 20 - 13 / 20 = 7 / 20 and corresponds to 70 students
If X is the total number of students, then
7 / 20 of X = 70
or (7 / 20) ? X = 70
Solve for X
X = 70 ? (20 / 7) = 200
Students who are 10 years old have a fraction of 1 / 20 of the total X and their number is equal to
(1 / 20) of 200 = 10 students
correct answer A
Answer: (A) 10 students
Question: Pointing to an old man, Kailash said, "His son is my son's uncle." How is the old man related to Kailash ?
(A) Brother
(B) Uncle
(C) Father
(D) Grandfather
(E) Sister
Rationale: Explanation:
Kailash's son's uncle — Kailash's brother. So. the old man's son is Kailash's brother
i.e., the old man is Kailash's father.
Answer: C
Answer: (C) Father
Question: An automobile parts supplier charges $20 per package of gaskets. When a customer orders more than 10 packages of gaskets, the supplier charges 4/5 the price for each package in excess of 10. During a certain week, the supplier sold 60 packages of gaskets. If 20 percent of the gaskets went to Company X, 15 percent to Company Y, and the rest to Company Z, what was the total amount, in dollars, that the parts supplier received in payment for the gaskets?
(A) 1005
(B) 1045
(C) 1075
(D) 1015
(E) 1096
Rationale: $25 per packet of gasket in case a customer orders less than 10
in case a customer orders > 10 price per gasket = 20*4/5=16
a certain week the supplier sold 60 gasket
1.he sold 20 % of the gaskets to X = 12 gaskets = 20*10 + 16 *2 = 200 + 32 = 232
2.he sold 15 % of the gaskets to Y = 9 gaskets = 20*9= 180
3.he sold remaining 65% to z =39 gaskets = 20*10 =200 + 16*29=684
thus ,total money earned
232+180+684 = 1096
Answer is E
Answer: (E) 1096
Question: On what dates of April,2001 did Wednesday fall ?
(A) 1st,8th,15th,22nd,29th
(B) 2nd,9th,16th,23rd,30th
(C) 3rd,10th,17th,24th
(D) 4th,11th,18th,25th
(E) None of these
Rationale: Solution
We shall find the day on 1st April,2001.
1st April,2001 =(2000 years + Period from 1.1.2001 to 1.4.2001)
Odd days in 1600 years =0
Odd days in 400 years =0
Jan. Feb. March April
(31 + 28 + 31 + 1) =91 days =0 odd days. Answer D
Answer: (D) 4th,11th,18th,25th
Question: In a simultaneous throw of 2 dice what is the probability of getting a total of 6?
(A) 1/4
(B) 5/36
(C) 2/11
(D) 3/13
(E) 1/5
Rationale: n(S) = 6*6 = 36
E = {(1,5),(2,4),(3,3),(4,2),(5,1)}
Probability = 5/36
Answer is B
Answer: (B) 5/36
Question: The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?
(A) 12 cm
(B) 14 cm
(C) 18 cm
(D) 20 cm
(E) 22 cm
Rationale: 2(l + b) = 5
b 1
2l + 2b = 5b
3b = 2l
b = 2 l
3
Then, Area = 216 cm2
l x b = 216
l x 2 l = 216
3
l2 = 324
l = 18 cm.
C
Answer: (C) 18 cm
Question: Find the least number of candidates in an examination so that the percentage of successful candidates should be 76.8%:
(A) 105
(B) 115
(C) 125
(D) 135
(E) 145
Rationale: suppose no. of total candidates are 'y' and successful are 'x'.
(x/y)*(100)=76.8 or x/y=0.768
or y=x/0.768
here we need minimum value of y, which is obtained by minimum value of x.
if put x=768 then y=1000
now we will try decrease value of x than we will find less value of y. so factorized 768 by 2 further.
if put x=384 then y=500
if put x=192 then y=250
if put x=96 then y=125(answer)
if put x=48 then y=62.5(not integer)
so ans is 125
ANSWER:C
Answer: (C) 125
Question: If the difference between the length and breadth of a rectangle is 23 m and its perimeter is 166 m, what is its area?
(A) 1590
(B) 2535
(C) 2530
(D) 2515
(E) 2520
Rationale: length = breadth +23. Therefore,
4× breadth +2×23=166 m
⇒ breadth =30 m
length =30+23=53 m
Area =53×30=1590 m2
Answer is A.
Answer: (A) 1590
Question: An article is bought for Rs.600 and sold for Rs.450, find the loss percent?
(A) 16%
(B) 18%
(C) 19 %
(D) 20%
(E) 25%
Rationale: 600 ---- 150
100 ---- ? => 16 2/3%
Answer: E
Answer: (E) 25%
Question: A glass was filled with 10 ounces of water, and 0.02 ounce of the water evaporated each day during a 30-day period. What percent of the original amount of water evaporated during this period?
(A) 0.006%
(B) 0.06%
(C) 6%
(D) 2%
(E) 60%
Rationale: In 30 days 30*0.02=0.6 ounces of water evaporated, which is 0.6/10âˆ—100=6 of the original amount of water.
Answer: C.
Answer: (C) 6%
Question: Two bullet train s 140 m and 180 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
(A) 15.8 sec.
(B) 11.52 sec.
(C) 11.8 sec.
(D) 10.8 sec.
(E) 08.8 sec.
Rationale: Relative speed = (60 + 40) km/hr = 100x5/18 = 250/9 m/ sec.
Distance covered in crossing each other = (140 + 180) m = 320 m.
Required time = 320x9/250 = 11.52 sec.
ANSWER B
Answer: (B) 11.52 sec.
Question: M, N and O are inner angles in a triangle. If M= N+ O, what can't be the size of N?
(A) 90 DEGREES
(B) 60 DEGREES
(C) 960 DEGREES
(D) 960 DEGREES
(E) 9660 DEGREES
Rationale: Given M= N+ O, and M, N and O are inner angles in a triangle. Thus M+ N+ O= 180
N+ O + N+ O= 180 => 2(N+ O) = 180 => N+ O= 90. Thus beta will be less than 90.
Hence the answer is A.
Answer: (A) 90 DEGREES
Question: Mohan purchased 16 kgs of rice at the rate of Rs.26 per kg and 8 kgs of pulses at the rate of Rs.26 per kg. Whaat is the total amount that he paid to the shopkeeper?
(A) A)Rs.598
(B) B)Rs.625
(C) C)Rs.596
(D) D)Rs.595
(E) E)of these
Rationale: Explanation:
Price of 16 kgs of rice at Rs.26/kg = 16x26 = Rs.416
Price of 8 kgs of pulses at Rs.26/kg = 8x26 = Rs.208
Therefore, Total amount = Rs.416+Rs.208 = Rs.624.
Answer: Option B
Answer: (B) B)Rs.625
Question: Raj writes a number. He sees that the number of two digits exceeds four times the sum of its digits by 3. If the number is increased by 18, the results is the same as the number formed by reversing the digits. Find the next immediate prime greater than the number.
(A) 22
(B) 37
(C) 88
(D) 27
(E) 97
Rationale: Let the number be xy = 10x + y
10x + y = 4(x+y) + 3 ⇒⇒ 2x - y -1 -------(1)
Also 10x + y +18 = 10y +x , 9(y-x) = 18, y-x = 2 -------(2)
Solving we get x = 3, y = 5
The number is 35. So next immediate prime is 37
Answer:B
Answer: (B) 37
Question: Q' = 3Q - 3, what is the value of (5')' ?
(A)  96
(B)  108
(C)  120
(D)  132
(E)  144
Rationale: (5')'=(3*5-3)'=12'=12*12-12=132
Answer D
Answer: (D)  132