mathewhe/aqua_rat huggingface dataset:
Question: A right triangle ABC has to be constructed in the xy-plane so that the right angle is at A and AB is parallel to x axis. The coordinates of A, B and C are to satisfy the inequalities -3 ≤ x ≤ 5 and 2 ≤ y ≤11 and x and y are integers. The number of different triangles that can be constructed with these properties are?
(A) 100
(B) 6480
(C) 2320
(D) 1500
(E) 9000
Rationale: We have the rectangle with dimensions 9*10 (9 horizontal dots and 10 vertical). AB is parallel to x-axis and AC is parallel to y-axis.
Choose the (x,y) coordinates for vertex A: 9C1*10C1=90;
Choose the x coordinate for vertex B (as y coordinate is fixed by A): 8C1, (9-1=8 as 1 horizontal dot is already occupied by A);
Choose the y coordinate for vertex C (as x coordinate is fixed by A): 9C1, (10-1=9 as 1 vertical dot is already occupied by A).
9C1*10C1*8C1*9C1=6480.
Answer: B.
Answer: (B) 6480
Question: Solution Y is 30 percent liquid X and 70 percent water. If 4 kilograms of water evaporate from 8 kilograms of solution Y and 4 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new solution is liquid X?
(A) 40%
(B) 41 1/2%
(C) 44%
(D) 45%
(E) 46%
Rationale: In 8 kilograms of solution Y there are 0.3*8=2.4 kilograms of solution X;
After 4 kilograms of water are replaced by 4 kilograms of solution Y, to the existing 2.4 kilograms of solution X, 0.3*4=1.2 kilograms of solution X are added, so in the new solution of 8 kilograms there are 2.4+1.2=3.6 kilograms of solution X, which is 3.6/8*100=45% of this new solution.
Answer: D.
Answer: (D) 45%
Question: A shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net profit or loss that he makes?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 65
Rationale: SP of first article = 1000
Profit = 20%
CP = (SP)*[100/(100+P)] = 5000/6 = 2500/3
SP of second article = 1000
Loss = 20%
CP = (SP)*[100/(100-L)] = 5000/4 = 1250
Total SP = 2000
Total CP = 2500/3 + 1250 = 6250/3
CP is more than SP, he makes a loss.
Loss = CP-SP = (6250/3)- 2000 = 250/3
Loss Percent = [(250/3)/(6250/3)]*100
=0.04 * 100 = 4%
Answer: D
Answer: (D) 4
Question: If the area of a circle decreases by 20%, then the radius of a circle decreases by
(A) 20%
(B) 18%
(C) 36%
(D) 11%
(E) None of these
Rationale: If area of a circle decreased by x % then the radius of a circle decreases by
(100−10√100−x)%=(100−10√100−20)%
= (100−10√80)%
= 100 - 89 = 11%
Answer D
Answer: (D) 11%
Question: A man can hit the target once in four shots. If he fires five shots in succession, what is the probability that he will hit the target?
(A) 1
(B) 1/256
(C) 81/59
(D) 45/59
(E) 185/59
Rationale: In five shots he can hit once,twice,thrice,four, all hit
the probability of hitting the target is p(1hit out of 5)+P(2hit out of 5)+p(3hit out of 5)+p(4hit out of 5)+p(All hit)
it is total probability-probability of not hitting the target
=>1-(3/4*3/4*3/4*3/4*3/4)
=>45/59
ANSWER:D
Answer: (D) 45/59
Question: Which of the following MUST yield an integer when divided by 9?
(A) The sum of nine consecutive positive integers.
(B) The square of a prime number.
(C) The sum of two odd integers.
(D) The product of three consecutive odd numbers.
(E) The difference between a multiple of 8 and a multiple of 3.
Rationale: For option A: Let the numbers be (x-4), (x-3), (x-2), (x-1), (x), (x+1), (x+2), (x+3), (x+4).
Now, (x-4)+(x-3)+(x-2)+(x-1) + (x) + (x+1) + (x+2)+(x+3)+(x+4) = 9(x). Hence A is true. No need to check other answers since there can only be one correct answer.
So, Ans(A)
Answer: (A) The sum of nine consecutive positive integers.
Question: The area of a field in the shape of a trapezium measures 1440sq m. The perpendicular distance between its parallel sides is 24cm. If the ratio of the sides is 5:3, the length of the longer parallel side is:
(A) 75
(B) 25
(C) 26
(D) 76
(E) 19
Rationale: Explanation:
Area of field = = 96x sq.m
96x = 1440 x = = 15
Hence, the length of longer parallel side = 5x = 75m
Answer: A) 75
Answer: (A) 75
Question: An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq m?
(A) 234
(B) 3444
(C) 3333
(D) 4082.4
(E) 23468
Rationale: Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 * 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40
Answer: Option D
Answer: (D) 4082.4
Question: A number consisting of five digits 5,6,7,8 and 9 each coming once but
not necessarily in that order is taken ,and an algorithm specified in the
previous question is run on it .How many different end results are possible
?
(A) 1
(B) 3
(C) 5
(D) 7
(E) 9
Rationale: 5+6+7+8+9=35
3+5=8..only one result possible!
ANSWER:A
Answer: (A) 1
Question: 900 students took the test on English and Maths. 35% students failed in english and 45% failed in maths. 40% of those who passed in maths also passed in english, then how many students failed in both ?
(A) 162
(B) 18
(C) 60
(D) 38
(E) 12
Rationale: Passed in english = 65%
Passed in maths = 55%
Passed in both = 40% of 55% = 2/5 * (55%) = 22%
Passed in (English + Maths - Both + Neither) = 100%
65 + 55 - 22 + Neither = 100
Neither = 100 - 98 = 2% = 0.02 * 900 = 18
Answer: B
Answer: (B) 18
Question: Two pipes A and B can fill a tank in 15 min and 18 min respectively. Both the pipes are opened together but after 4 min, pipe A is turned off. What is the total time required to fill the tank?
(A) 14 min 19 sec
(B) 13 min 36 sec
(C) 14 min 20 sec
(D) 14 min 40 sec
(E) 14 min 10 sec
Rationale: :
Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15
Remaining part = 1 - 7/15 = 8/15
Part filled by B in 1 minute = 1/18
1/18 : 8/15 :: 1 ; x
x = 8/15 * 1 * 18 = 9 3/5 min = 9 min 36 sec.
The tank will be full in (4 min. + 9 min. 36 sec) = 13 min 36 sec.Answer: B
Answer: (B) 13 min 36 sec
Question: Two trains, each 100 m long, moving in opposite directions, cross other in 12 sec. If one is moving twice as fast the other, then the speed of the faster train is?
(A) 76 km/hr
(B) 66 km/hr
(C) 40 km/hr
(D) 67 km/hr
(E) 22 km/hr
Rationale: Let the speed of the slower train be x m/sec.
Then, speed of the train = 2x m/sec.
Relative speed = ( x + 2x) = 3x m/sec.
(100 + 100)/12 = 3x => x = 50/9
So, speed of the faster train = 100/9 = 100/9 * 18/5 = 40 km/hr.
Answer:C
Answer: (C) 40 km/hr
Question: In the figure given below, ABC and CDE are two identical semi-circles of radius 2 units. B and D are the mid points of the arc ABC and CDE respectively. What is the area of the shaded region?
(A) 4π - 1
(B) 3π - 1
(C) 2π - 4
(D) ½(3π - 1)
(E) 2π - 2
Rationale: Solution
P and Q are the centers of the two semicircles.
Draw BP perpendicular to AC.
BP is radius to the semi-circle. So are AP and PC.
Therefore, BP = AP = PC = 2 units.
In semicircle ABC, area of the shaded portion is the difference between the area of half the semicircle PBC and the area of the triangle PBC.
Triangle PBC is a right triangle because PB is perpendicular to PC. PB and PC are radii to the circle and are equal. So, triangle PBC is an isosceles triangle.
Therefore, triangle PBC is a right isosceles triangle.
Area of half the semicircle - Area of region PBC
Area of the semicircle ABC = ½ area of the circle of radius 2.
So, area of half the semicircle, PBC = ¼ area of the circle of radius 2.
Area of half the semicircle, PBC = ¼ * π * 22
Area of half the semicircle, PBC = π sq units
Area of right isosceles triangle PBC
Area of right triangle PBC = ½ PC * PB
Area of triangle PBC = ½ * 2 * 2 = 2 sq units
Area of shaded region
Area of shaded region in one of the semi circles ABC = (π - 2) sq units
Therefore, area of the overall shaded region = 2(π - 2) sq units
Choice C
Answer: (C) 2π - 4
Question: Ayayai electronics is a company manufacturing MP3 players. Ayayai manufactures only two players: iMe and iMine. Either player is assembled using a LCD screen or an OLED screen. Excluding the expensive OLED-iMine model, Ayayai manufactures 21,000 players per month. Every month, Ayayai manufactures 11,000 players with an OLED screen, and 12,000 iMine models. If Ayayai manufactures 8000 LCD iMe models monthly, how many players (of all models) does Ayayai manufacture per month?
(A) 24,000
(B) 25,000
(C) 26,000
(D) 27,000
(E) 28,000
Rationale: Let x be the iMine LCD players
Let y be the iMe OLED players
8000 + x + y = 21000
x + y = 13000
Assume 6000,7000 for x and y.
6000 + iMine OLED = 11000. iMine OLED = 5000.
Hence total number of players = 8000 + x + y + 5000 = 26000
ans :(Option C)
Answer: (C) 26,000
Question: A grocer has a sale of Rs. 5420, Rs. 5660, Rs. 6200, Rs. 6350 and Rs. 6500 for 5 consecutive months. Find the sale he should have in the sixth month, so that he gets an average sale of Rs. 6300?
(A) Rs. 5870
(B) Rs. 5991
(C) Rs. 6020
(D) Rs. 7670
(E) None of these
Rationale: Explanation:
Total sale for 5 months = Rs. (5420 + 5660 + 6200 + 6350 + 6500) = Rs. 30,130
Therefore, required sale = Rs. [(6300 * 6) – 30,130] = Rs. (37800 – 30,130) = Rs. 7670
ANSWER D
Answer: (D) Rs. 7670
Question: A dealer purchased an article at 3/4 of its list price and sold 50% more than the list price. Find his gain percent?
(A) 109%
(B) 600%
(C) 100%
(D) 170%
(E) 102%
Rationale: MP = 100
CP = 75
SP = 150
------
75 ---- 75
100 ---- ? => 100%
Answer: C
Answer: (C) 100%
Question: Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 25% profit?
(A) 15.75
(B) 16.33
(C) 16.35
(D) 16.3
(E) 16.32
Rationale: C.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.
S.P. of 50 kg wheat = 125% of Rs. 630 = 125/100 * 630 = Rs. 787.5
S.P. per kg = 787.5/50 =15.75.
Answer: A
Answer: (A) 15.75
Question: The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number is
(A) 77
(B) 88
(C) 99
(D) 110
(E) 120
Rationale: Explanation:
Product of numbers = 11 x 385 = 4235
Let the numbers be 11a and 11b . Then , 11a x 11b = 4235 inline fn_jvn Rightarrow ab = 35
Now, co-primes with product 35 are (1,35) and (5,7)
So, the numbers are ( 11 x 1, 11 x 35) and (11 x 5, 11 x 7)
Since one number lies 75 and 125, the suitable pair is (55,77)
Hence , required number = 77. Answer: A
Answer: (A) 77
Question: Taylor is making a bracelet. He Starts with 2 blue knots, 6 red knots, and 2 yellow knots, in that order, and repeats the pattern until there is no more string. If the last Knot is yellow which of the following could be the total number of knots on the bracelet.
(A) 89
(B) 79
(C) 95
(D) 97
(E) 102
Rationale: Repeating sequence = 2 + 6 + 2 = 10.
As the pattern ends in Y this could be the 9th thread or 10 thread (both are yellow)
Out of the answer choices, correct on should be a multiple of 10(since 10 threads are repeating) and if not, multiple of 10 + 9 (since 10 threads are repeating and last sequence end at first yellow)
none of the options is a direct multiple of 10 and only option that is multiple of 10; + 9 is 79 (10*7) + 9
Hence, answer is B
Answer: (B) 79
Question: How much to pay for a pair of jeans of $89 when discounted by 60 percent?
(A) $45.5
(B) $30
(C) $35.6
(D) $40
(E) $36
Rationale: Solution
Cost of pair of jeans = $89
60 % Discount on $89 = $89*60/100 =$53.4
So cost of jean (-) Discounted price = $89-$53.4 =$35.6
Answer C
Answer: (C) $35.6
Question: How many litres of pure acid are there in 5 litres of a 30% solution
(A) 1.5
(B) 1.6
(C) 1.7
(D) 1.8
(E) 1.9
Rationale: Explanation:Question of this type looks a bit typical, but it is too simple, as below... It will be 5 * 30/100 = 1.5 Answer: Option A
Answer: (A) 1.5
Question: Certain stocks in January were 20% less than they were in February and 30% greater than they were in March. What was the percentage decrease in the stocks from February to March?
(A) 5.7%
(B) 11%
(C) 20%
(D) 25.3%
(E) 38.5%
Rationale: Let stocks value in Feb = 100 => In Jan = 80 and March = 80 * 100/130 = 61.5
Thus, percent decrease in stocks from Feb to March = 100 - 61.5 = 38.5%
Hence Answer is E
Answer: (E) 38.5%
Question: Pipes A and B can fill a cistern in 8 and 24 minutes respectively. They are opened an alternate minutes. Find how many minutes, the cistern shall be full?
(A) 16
(B) 12
(C) 18
(D) 17
(E) 13
Rationale: 1/8 + 1/24 = 1/6
6 * 2 '
= 12
Answer: B
Answer: (B) 12
Question: A man can row with a speed of 14 kmph in still water. If the stream flows at 10 kmph, then the speed in downstream is?
(A) 28
(B) 26
(C) 20
(D) 87
(E) 24
Rationale: M = 14
S = 10
DS = 14 + 10
=24
Answer: E
Answer: (E) 24
Question: If a certain sample of data has a mean of 27.0 and a standard deviation of 2.0, which of the following pairs contain two values that are each at least 2.5 standard deviations from the mean?
(A) (24.0; 28.5)
(B) (24.5; 31.0)
(C) (25.0; 29.5)
(D) (19.5; 33.0)
(E) (24.0; 29.5)
Rationale: The standard deviation is 2, so 2.5 standard deviations would be (2.5)(2) = 5.
The values between 22 and 32 are within 2.5 standard deviations from the mean.
The answer is D.
Answer: (D) (19.5; 33.0)
Question: Ajit has a certain average for 9 innings. In the tenth innings, he scores 100 runs thereby increasing his average by 8 runs. His new average is:
(A) 20
(B) 21
(C) 28
(D) 32
(E) None
Rationale: Solution: Let Ajit's average be x for 9 innings. So, Ajit scored 9x run in 9 innings.
In the 10th inning, he scored 100 runs then average became (x+8). And he scored (x+8)*10 runs in 10 innings.
Now,
=>9x+100 = 10*(x+8)
Or, 9x+100 = 10x+80
Or, x = 100-80
Or, x = 20
New average = (x+8) = 28 runs
Answer: Option C
Answer: (C) 28
Question: A manufacturer is using glass as the surface for the multi-touch screen of its smartphone. The glass on the manufactured phone has a 3% probability of not passing quality control tests. The quality control manager bundles the smartphone in groups of 10. If that bundle has any smartphone that does not pass the quality control test, the entire bundle of 10 is rejected.
What is the probability that a smartphone bundle that will be rejected by quality control?
(A)  0.25
(B)  .05^10
(C)  1-0.95^10
(D)  1-0.97^10
(E)  0.95^10
Rationale: Find the probability of the opposite event and subtract from 1.
The opposite event is that bundle will NOT be rejected by quality control, which will happen if all 10 phones pass the test, so P(all 10 phones pass test)=0.97^10.
P(at least one phone do not pass the test)=1- P(all 10 phones pass test)=1-0.97^10.
Answer: D.
Answer: (D)  1-0.97^10
Question: A Barman's train rails across an open track at 250 kilometers per hour. A regular passenger train travels at 68% of the Barman's train speed. If the two trains start moving from the same station at the same time, how much time longer will it take the passenger train than the Barman's to travel 850 kilometers?
(A) 1 hour and 24 minutes
(B) 1 hour and 36 minutes
(C) 2 hours and 24 minutes.
(D) 2 hours and 36 minutes
(E) 5 hours
Rationale: B train speed 250
P train speed 250(68/100) =170
Difference of speed
B-P = 80 km/hrs
Total distance = 850
Additional Time taken 850/80
1h36min
ANSWER:B
Answer: (B) 1 hour and 36 minutes
Question: In how many ways can a person post 5 letters in 4 letter boxes ?
(A) 480
(B) 1024
(C) 54
(D) 4^5
(E) 5^5
Rationale: There are 4 places (ABCD) that need to be filled.
Letter 1 can be posted in either A, B, C, or D i.e. 4 ways
Letter 2 can be posted in either A, B, C, or D i.e. 4 ways
Letter 3 can be posted in either A, B, C, or D i.e. 4 ways
Letter 4 can be posted in either A, B, C, or D i.e. 4 ways
Letter 5 can be posted in either A, B, C, or D i.e. 4 ways
So the total no of ways in which 5 letters can be posted in 4 boxes are = 4 x 4 x 4 x 4 x 4 = 4 ^ 5
Thus the answer is D
Answer: (D) 4^5
Question: The population of a bacteria culture doubles every 5 minutes. Approximately how many minutes will it take for the population to grow from 1,000 to 500,000 bacteria
(A) 10
(B) 12
(C) 14
(D) 16
(E) 45
Rationale: This one's easy.
1000 * 2^t = 500,000
2^t = 500
Now gauging, since 2^8 = 256, then 2^9 = 512
So t = 9
But be careful, 't' is in time intervals of 5 minutes
So answer is 9*5 = 45 minutes
Answer (E)
Answer: (E) 45
Question: How many six digit phone numbers can you frame using the digits from 0 to 9 if a condition restricts you to start the number with 35 and another condition restricts you from using any digit more than once?
(A) 1580
(B) 1680
(C) 1648
(D) 1782
(E) 1845
Rationale: as the first two digits are fixed and on remaining 4places we can use only one at a time.this means on third place we can use any digit from 0,1,2,4,6,7,8,9. which means we can choose any of 8digits. similarly on 4th place any 7digits n so on..
thus 1*1*8*7*6*5=1680
ANSWER:B
Answer: (B) 1680
Question: If a * b * c =(√(a + 2)(b + 3)) / (c + 1), find the value of 6 * 15 * 7.
(A) 8
(B) 5
(C) 11
(D) 3
(E) 1.5
Rationale: 6 * 15 * 3 = (√(6 + 2)(15 + 3) )/ (7 + 1)
= (√8 * 18) / 8
= (√144) / 8
= 12 / 8 = 1.5
Answer is E
Answer: (E) 1.5
Question: The value of x is to be randomly selected from the integers from 1 to 6, inclusive, and then substituted into the equation y = x^2 - 4x + 3. What is the probability that the value of y will be negative?
(A) 1/3
(B) 1/4
(C) 1/5
(D) 1/6
(E) 1/7
Rationale: y will only be negative for x=2.
(We can check the values from 1 to 6 to be certain.)
P(y is negative) = 1/6
The answer is D.
Answer: (D) 1/6
Question: Some students are standing in a circle in which 6th and the 16th student are standing opposite to each other. find how many students were present there.
(A) 10
(B) 15
(C) 20
(D) 25
(E) 30
Rationale: (n/2) - x = 6
n - x = 16
solving these two => n = number of students = 20
ANSWER:C
Answer: (C) 20
Question: A trader mixes 25 kg of rice at Rs. 30 per kg with 25 kg of rice of other variety at Rs. 40 per kg and sells the mixture at Rs. 40 per kg. His profit percent is:
(A) No profit, no loss
(B) 5%
(C) 14.29%
(D) 10%
(E) None of these
Rationale: C.P. of 50 kg rice = Rs. (25 x 30 + 25 x 40) = Rs. (750 + 1000) = Rs. 1750
S.P. of 50 kg rice = Rs. (50 x 40) = Rs.2000
Gain =250/1750x100% = 14.29%.
Answer: Option C
Answer: (C) 14.29%
Question: The ratio of present ages of Nisha and Shilpa is 7 : 8 respectively. Four years hence this ratio becomes 9 : 10 respectively. What is Nisha’s present age in years?
(A) 18
(B) 14
(C) 17
(D) Data inadequate
(E) None of these
Rationale: Present age of Nisha = 4×(10−9)/9×8−10×7×7
= 14 years
Answer B
Answer: (B) 14
Question: The speed of a car is 90 km in the first hour and 40 km in the second hour. What is the average speed of the car?
(A) 12
(B) 75
(C) 88
(D) 65
(E) 15
Rationale: S = (90 + 40)/2
= 65 kmph
Answer: D
Answer: (D) 65
Question: Grandmother's Punch hangover cure is a mix of two ingredients: a herbal extraction that contains 20% alcohol and apricot cider that contains 5% alcohol. If a 750-milliliter Grandmother's Punch bottle has 87 milliliters of alcohol, how much apricot cider does it contains?
(A) 330 milliliters
(B) 420 milliliters
(C) 565 milliliters
(D) 630 milliliters
(E) 670 milliliters
Rationale: let herbal extraction be denoted H and other A
case 1:
if H: 350 and A:400
20%-70 and 5%-20 --- total 90 ml
case 2:
if H:300 and A:450
20%-60 and 5%-22.5--- 82.5 ml
therefore A is between 400 and 450 ml :
ANSWER:B
Answer: (B) 420 milliliters
Question: A cake is cut into 16 pieces.Whats amount of cake must be eaten to make cake cut into half.
(A) 4
(B) 2
(C) 9
(D) 8
(E) 3
Rationale: The cake is cut into 16 equal pieces.Half of 16 is 8. So 8 pieces must be removed from 16 pieces to make it half. Answer:D
Answer: (D) 8
Question: what is the compound interest on rs:60,000 for 4 months at the rate of 5% per annum
(A) 1058.24
(B) 2006.24
(C) 1006.13
(D) 1015.24
(E) 1014.24
Rationale: it is monthly compound
rate=5/12% per month
60000*(1+5/1200)^4-60000=1006.13
ANSWER:C
Answer: (C) 1006.13
Question: In how many different number of ways 6 men and 3 women can sit on a shopa which can accommodate persons?
(A) 170
(B) 180
(C) 200
(D) 504
(E) 220
Rationale: Option 'D'
9p3 = 9 × 8 × 7 = 504
Answer: (D) 504
Question: On a scale of a map 0.6 cm represents 6.6km. If the distance between two points on the map is 80.5 cm , what is the the actual distance between these points?
(A) 885.5 km
(B) 860 km
(C) 892.5 km
(D) 825 km
(E) 845 km
Rationale: Explanation:
0.6 cm in map ≡ actual distance of 6.6 km
1 cm in map ≡ 6.6/.6 km
80.5 cm in map ≡ 80.5×6.6/.6 km = 885.5 km
Answer: Option A
Answer: (A) 885.5 km
Question: Shyam purchased a cow for Rs 20000 and 2 goats for 10000. He sold the cow at a loss of 5% and goats at a profit of 15%. Overall he make a.?
(A) 500
(B) 400
(C) 300
(D) 350
(E) 550
Rationale: Let the SP of the cow and the goats be Rs. c and Rs. g respectively.
c = 20000(1 - 5/100) = 20000 - 1000
g = 10000(1 + 15/100) = 10000 + 1500
Total SP - Total CP = c + g - (20000 + 10000) = - 1000 + 1500 = Rs. 500
As this is positive, an overall profit of Rs. 500 was made.
Answer: A
Answer: (A) 500
Question: An article is bought for Rs.500 and sold for Rs.700, find the gain percent?
(A) 33 1/7%
(B) 33 1/6%
(C) 33 1/3%
(D) 38 1/3%
(E) 40%
Rationale: 500 ---- 200
100 ---- ? => 40%
Answer:E
Answer: (E) 40%
Question: If a number between 0 and 1/2 is selected at random, which of the following will the number most likely be between
(A) 0 and 3/20
(B) 3/20 and 1/5
(C) 1/5 and 1/4
(D) 1/4 and 3/10
(E) 3/12 and 1/2
Rationale: E. 3/12 and 1/2
Definitely not. I am always happy to explain a given question or issue if I can. However, I sometime donot put my explanation if I am answering first because I want to put others first for their explanation.
Now you have excellent explanantion byscthakur. In fact the question is asking the likelyness of or high chances/probability of having a given number. Hope you already got it. E
Answer: (E) 3/12 and 1/2
Question: y=248-398x Which of the following values of x gives the greatest value of y in the equation above?
(A) 200
(B) 100
(C) 0.5
(D) 0
(E) -1
Rationale: Explanation:
This is quite simple. Just by looking at the values they are all positive except two. If you enter any of the values instead of x you will get a negative y. By entering 0 you already get to positive=248. But the correct answer is -1 since this equals y=248-(398*(-1))=248+398. This is the greatest value.
Answer: Option E
Answer: (E) -1
Question: 17. 2 x 40 =?
(A) 188.0
(B) 688.0
(C) 288.0
(D) 388.0
(E) 488.0
Rationale: Multiply 17.2
x 40
Answer: 688.0
correct answer B
Answer: (B) 688.0
Question: 7 noun, 5 verbs and 2 adjectives are written on blackboard.we can form sentence by choosing 1 from each available set without caring it makes sense or not.what is the number of ways of doing this??
(A) 420
(B) 450
(C) 500
(D) 520
(E) 540
Rationale: we have to choose one from each set. 1 from 7 nouns and 1 from 5 verbs and 1 from 2 adjectives.
then we have 2 arrange 3 different set in 3! ways.
so,
7c1*5c1*2c1*3!=420
ANSWER:A
Answer: (A) 420
Question: a, and b are positive integers less than or equal to 9 and b is twice the a. If a and b are assembled into the four-digit number abab, which of the following must be a factor of abab?
(A) 5
(B) 7
(C) 9
(D) 12
(E) None of these
Rationale: b = 2a is given thus possible numbers are 1212, 2424, 3636 and 4848. All are divisible by 12. Thus 12 must be a factor of abab
Answer: D
Answer: (D) 12
Question: The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?
(A) 345
(B) 250
(C) 376
(D) 450
(E) 342
Rationale: Option: E
Explanation:
400*(90/100)*(95/100) = 342
Answer: (E) 342
Question: Barbara has 8 shirts and 8 pants. How many clothing combinations does Barbara have, if she doesn’t wear 2 specific shirts with 3 specific pants?
(A) 41
(B) 66
(C) 36
(D) 50
(E) 56
Rationale: 8 shirts
9 pants
we can combine 2 shirts with (8-3) pants
2*5=10
we can combine the other shirts (6) with any pants (9)
5*8=54
Thus total :40+10=50	ANS:D
Answer: (D) 50