mathewhe/aqua_rat huggingface dataset:
Question: Bhanu spends 30% of his income on petrol on scooter 14% of the remaining on house rent and the balance on food. If he spends Rs.300 on petrol then what is the expenditure on house rent?
(A) 98
(B) 140
(C) 62
(D) 797
(E) 123
Rationale: Given 30% (Income ) = 300 ⇒⇒ Income = 1000
After having spent Rs.300 on petrol, he left with Rs.700.
His spending on house rent = 14% (700) = Rs.98
Answer:A
Answer: (A) 98
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 250 resolutions?
(A) 277 m
(B) 704 m
(C) 352 m
(D) 288 m
(E) 378 m
Rationale: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 250 resolutions.
= 250 * 2 * 22/7 * 22.4 = 35200 cm
= 352 m
Answer: C
Answer: (C) 352 m
Question: A batsman in his 17th innings makes a score of 85 and their by increasing his average by 3. What is his average after the 17thinnings?
(A) 22
(B) 77
(C) 26
(D) 37
(E) 88
Rationale: 16x + 85 = 17(x + 3)
x = 34 + 3 = 37
Answer: D
Answer: (D) 37
Question: One-third of Rahul's savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,50,000 as total savings, how much has he saved in Public Provident Fund ?
(A) 30000
(B) 60000
(C) 50000
(D) 90000
(E) 70000
Rationale: Let savings in N.S.C and P.P.F. be Rs. x and Rs. (150000 - x) respectively. Then,
(1/3)	x =(1/2)(150000 - x)
(x/3)	+(x/2)= 75000
5x/6	= 75000
x =	75000 x 6/5= 90000
Savings in Public Provident Fund = Rs. (150000 - 90000)
= Rs. 60000
Answer is B.
Answer: (B) 60000
Question: Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 15 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?
(A) 432
(B) 444
(C) 2881
(D) 287
(E) 221
Rationale: 1h ----- 5
? ------ 60
12 h
RS = 15 + 21 = 36
T = 12
D = 36 * 12 = 432
Answer:A
Answer: (A) 432
Question: Gold is 19 times as heavy as water and copper is 9 times as heavy as water. In what ratio should these be mixed to get an alloy 15 times as heavy as water ?
(A) 3 : 2
(B) 3 : 8
(C) 5 : 7
(D) 3 : 7
(E) 3 : 6
Rationale: Let us say, water weighs 1kg/1 liter. Then Gold weighs 19 kgs and copper weighs 9 kgs.
Assume x kgs of gold and y kgs of copper required to get the required alloy.
We use weighted average formula = Ax=n1.A1+n2.A2n1+n2Ax=n1.A1+n2.A2n1+n2
Therefore, 15=x.19+y.9x+y15=x.19+y.9x+y
15x + 15y = 19x + 9y
4x = 6y ⇒ x/y = 3 : 2
So Gold and Copper should be mixed in the ratio 3 : 2.
Answer:A
Answer: (A) 3 : 2
Question: If w,x,y,z are consecutive positive integers ; then which of the following is always odd?
[1] w*x+(y+2)^2*z
[2] w^x + z^y
[3] 13x^2
(A) 1
(B) 2
(C) 3
(D) 1 and 2
(E) 2 and 3
Rationale: Plug in some numbers
w = 1
x = 2
y = 3
z = 4
Check the options -
[1] w*x+(y+2)^2*z = 1*2 + (3+2)^2 * 4 => 2 + 25*4 = 102{ Not an odd Number }
[2] w^x + z^y = 1^2 + 4^3 => 1 + 64 = 65{ Odd number }
[3] 13x^2 = 13*4 =52 even
[2]
B
Answer: (B) 2
Question: 1^x + 1^-x = 2 What is the value of x?
(A) -1
(B) -1/2
(C) 0
(D) 1/2
(E) 1
Rationale: let 1^x = t
t+1/t =2
t^2 -2t +1 =0
(t-1)^2=0
t-1=0
t=1
1^x=1
x=1
Ans: E
Answer: (E) 1
Question: In a class,7 students like to play Basketball and 8 like to play Cricket. 5 students like to play on both Basketball and Cricket. How many students like to play Basketball or Cricket or both?
(A) 10
(B) 15
(C) 16
(D) 18
(E) 22
Rationale: Draw a Venn Diagram yourself !
B + C - BC = Number of students that play either Basketball or Cricket
7 +8 - 5 = 10
A)
Answer: (A) 10
Question: If the wheel is 9 cm then the number of revolutions to cover a distance of 1056 cm is?
(A) 18
(B) 26
(C) 14
(D) 18.7
(E) 91
Rationale: 2 * 22/7 * 9 * x = 1056 => x
= 18.7
Answer: D
Answer: (D) 18.7
Question: When positive integer n is divided by 3, the remainder is 2. When n is divided by 6, the remainder is 5. How many values less than 100 can n take?
(A)  0
(B)  2
(C)  3
(D)  4
(E)  5
Rationale: a quick approac to this Q is..
the equation we can form is.. 3x+2=7y+5..
3x-3=7y... 3(x-1)=7y...
so (x-1) has to be a multiple of 7 as y then will take values of multiple of 3..
here we can see x can be 1,8,15,22,29 so 5 values till 100 is reached
as (29-1)*3=84 and next multiple of 7 will be 84+21>100..
ans 4.. D
Answer: (D)  4
Question: A theater charges $12 for seats in the orchestra and $8 for seats in the balcony. On a certain night, a total of 340 tickets were sold for a total cost of $3,320. How many more tickets were sold that night for seats in the balcony than for seats in the orchestra?
(A)  40
(B)  110
(C)  120
(D)  130
(E)  220
Rationale: Orchestra Seats - a
Balcony Seats - b
a+b = 340
and 12a + 8b = 3320
Solving equations simultaneously (Multiply Equation 1 with 8 and subtract from second equation)
4a = 3320 - 8*340 = 3320 - 2720 = 600
i.e. a = 150
and b = 340-150 = 190
More seats in balcony than orchestra = b-a = 190 - 150 = 40
Answer: option A
Answer: (A)  40
Question: The wages earned by Robin is 40% more than that earned by Erica. The wages earned by Charles is 60% more than that earned by Erica. How much percent is the wages earned by Charles more than that earned by Robin?
(A) 14%
(B) 23%
(C) 30%
(D) 50%
(E) 100%
Rationale: Let wage of Erica = 10
Wage of Robin = 1.4*10 = 14
Wage of Charles = 1.6 *10 = 16
Percentage by which wage earned by Charles is more than that earned by Robin = (16-14)/14 * 100%
= 2/14 * 100%
=14%
Answer A
Answer: (A) 14%
Question: In how many different number of ways 4 men and 2 women can sit on a shopa which can accommodate persons?
(A) A)160
(B) B)170
(C) C)190
(D) D)30
(E) E)230
Rationale: 6p2 = 6 × 5 = 30
Option 'D'
Answer: (D) D)30
Question: Divide Rs.32000 in the ratio 3:9?
(A) 12000, 20000
(B) 12000, 200098
(C) 12000, 20007
(D) 12000, 20006
(E) 8000, 24000
Rationale: 3/12 * 32000 = 8000
9/12 * 32000 = 24000
Answer: E
Answer: (E) 8000, 24000
Question: From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done
(A) 456
(B) 556
(C) 656
(D) 756
(E) None of these
Rationale: Explanation:
From a group of 7 men and 6 women, five persons are to be selected with at least 3 men.
So we can have
(5 men) or (4 men and 1 woman) or (3 men and 2 woman)
(5C5)+(5C4∗6C1)++(5C3∗6C2)
=[7×6/2×1]+[(7×6×5/3×2×1)×6]+[(7×6×5/3×2×1)×(6×5/2×1)]=21+210+525=756
Option D
Answer: (D) 756
Question: Dhoni spends $300 buying his favorite dolls. If he buys only small Monkey dolls, which are $2 cheaper than the large Monkey dolls, he could buy 25 more dolls than if he were to buy only large Monkey dolls. How much does a large Monkey doll cost?
(A) $6.5
(B) $6
(C) $7
(D) $8
(E) $9
Rationale: A is not an integer. So we start with B.
If large doll costs $6, then he can buy 300/6 = 50 large dolls and 300/4 =75 small dolls.
Difference is 25, which is we wanted.
Answer B.
Answer: (B) $6
Question: John and David can finish a job together in 1 hours. If John can do the job by himself in 2 hours, what percent of the job does David do?
(A) 40%
(B) 45%
(C) 50%
(D) 55%
(E) 60%
Rationale: You can also plug in numbers. For example, Bob and Alice work at a donut factory and make 10 donuts which is the job ( I picked this as a SMART number).
John on his own works 10/2 = 5 donuts per hour.
John and David work 10/1 = 10 donuts per hour so David works 5 donuts/hour
To find out the percentage, David works 5 donuts/hr x 1 hours = 5 donuts per hour.
Therefore 5 donuts/10donuts = 1/2 = 50%
Answer : C
Answer: (C) 50%
Question: B as a percentage of A is equal to A as a percentage of (A+B). Find B as a percentage of A.
(A) 62%
(B) 73%
(C) 41%
(D) 71%
(E) None of these
Rationale: Explanation :
According to the question:-
=>B/A=A/(A+B).
As B is a percent of A, let us assume B=Ax.
Then, equation (1) can be re-written as
=>x=11+x.
=>x(1+x)=1.
=>x2+x+1=0.
=>x=−1±5/√2
Thus,
x=−1+5 /√2
=>0.62.
=>62%.
Answer : A
Answer: (A) 62%
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 8100 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
(A) 140 sq.units
(B) 360 sq.units
(C) 367sq.units
(D) 178sq.units
(E) 176sq.units
Rationale: Given that the area of the square = 8100 sq.units
=> Side of square = √8100 = 90 units
The radius of the circle = side of the square = 90 units Length of the rectangle = 2/5 * 90 = 36 units
Given that breadth = 10 units
Area of the rectangle = lb = 36 * 10 = 360 sq.units
Answer:B
Answer: (B) 360 sq.units
Question: At a certain store, the price of a pair of shoes is thirty dollars more than three times the price of a pair of jeans and the price of a sweater is fifty percent more than the price of a pair of shoes. If the price of a pair of jeans is j dollars at this store, then what is the price, in dollars, of a pair of shoes, a sweater and a pair of jeans, in terms of j ?
(A) 1.5j + 10
(B) 3j + 20
(C) 8.5j + 75
(D) 5.5j + 30
(E) 8.5j + 50
Rationale: Ans C
Given
Price of Jeans = J
Price of shoes = 30+3J
Price of Sweater = 1.5(30+3J)
Total Price of all three items = J+30+3J+1.5(30+3J) = 75+8.5J
Answer: (C) 8.5j + 75
Question: The cost of a one-family home was $ 120,000 in 1980. In 1988, the price had increased to $ 192,000. What was the percent increase in the cost of the home?
(A) 60%
(B) 50%
(C) 55%
(D) 40%
(E) 33.3%
Rationale: Increase = 192000-120000 = 72000
% increase = 72000*100/120000 = 60%
Answer: option A
Answer: (A) 60%
Question: The ratio between the speeds of two trains is 8 : 9. If the second train runs 405 kms in 5 hours, then the speed of the first train is
(A) 87.5 km/h
(B) 72 km/h
(C) 70 km/h
(D) 80 km/h
(E) 81 km/h
Rationale: B
72 km/h
Answer: (B) 72 km/h
Question: There are 5 competitors in a race (John, mary and 3 other ones) in which there are no ties, what is the probability that mary finish ahead of john?
(A) 1/6
(B) 1/3
(C) 1/2
(D) 2/3
(E) 5/6
Rationale: Mary has equal chances of finishing ahead of John as John has chances of finishing ahead of mary
But, Probability for Mary finishing ahead of John + Probability for John finishing ahead of Mary = 1
Hence Probability for Mary finishing ahead of John = 1/2
Answer: Option C
Answer: (C) 1/2
Question: You hold some gold in a vault as an investment. Over the past year the price of gold increases by 30%. In order to keep your gold in the vault, you must pay 2% of the total value of the gold per year. What percentage has the value of your holdings changed by over the past year.
(A) 27.5%
(B) 27.4%
(C) 27.6%
(D) 27.7%
(E) 28.4%
Rationale: (100%+30%)*(100%-2%) = 130*0.98= 127.4% an increase of 27.4%
Your gold holdings have increased in value by 27.4%.
The Answer is B
Answer: (B) 27.4%
Question: George while driving along the highway saw road markers which are at equal distances from each other. He crosses the markers every 20 seconds. If he increases his speed by x meters per second, he crosses the markers at every 15 seconds. But if he increases his speed by y meters per second, he crosses the marker at every 10th second. If y-x = 40 meters per second, then what is the distance between two markers.
(A) 2377
(B) 2788
(C) 1200
(D) 2778
(E) 2211
Rationale: Let speed be =z m/s then Distance= 20z m
(z+x)15=20z; (z+y)10=20z
Also given that y - x = 40
solving we get 20z=1200
Answer:C
Answer: (C) 1200
Question: which of the following inequalities indicates the set of all values of d for which the lengths R of the three sides of a triangle can be 3,4, and d?
(A) 0<d<1
(B) 0<d<5
(C) 0<d<7
(D) 1<d<5
(E) 1<d<7
Rationale: This question is a good way to apply one of the most basic relation between the 3 sides of a triangle. In a triangle (ANY TRIANGLE), any side MUST be greater than the positive difference of the other two sides and less than than the sum of the other 2 sides. Let the sides of a triangle be a,b,c .
Thus,
|a-b| < c < a+b
|b-c| < a < b+c
|c-a| < b < a+c
Thus, if the sides of the triangle are 3,4 and d,
4-3<d<4+3 ---> 1<d<7. Thus E is the correct answer.
Answer: (E) 1<d<7
Question: Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 26 years. What is Deepak present age.
(A) 14
(B) 15
(C) 20
(D) 22
(E) 24
Rationale: Explanation:
Present age is 4x and 3x,
=> 4x + 6 = 26 => x = 5
So Deepak age is = 3(5) = 15
Option B
Answer: (B) 15
Question: The distance between Delhi and Mathura is 110 kms. A starts from Delhi with a speed of 40 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet?
(A) 9.04 a.m.
(B) 10.00 a.m.
(C) 12.00 a.m.
(D) 18.00 a.m.
(E) 19.00 a.m.
Rationale: Explanation:
D = 110 â€“ 40 = 70
RS = 40 + 25 = 65
T = 70/65 = 1 hours 04 minutes
8 a.m. + 1 hours 04 minutes = 9:04 a.m.
Answer: Option A
Answer: (A) 9.04 a.m.
Question: The difference between the place values of two nines in the numerical 62039295 is
(A) 89
(B) 891
(C) 8910
(D) 0
(E) None of them
Rationale: Required difference = (9000-90)
=8910.
Answer is C
Answer: (C) 8910
Question: A boy wants to go abroad by boat and return by flight. He has a choice of 4 different boat to go and 5 flight to return. In how many ways, can the boy perform his journey?
(A) 20
(B) 30
(C) 43
(D) 45
(E) 80
Rationale: Ans.(a)
Sol. Number of choices to go by ship = 4 Number of choices to return by airline = 5 From, fundamental principle, total number of ways of performing the journey = 4 x 5 = 20 ways
Answer: (A) 20
Question: If p#q denotes the least common multiple of p and q, then P=((12#16)#(18#24)) = ?
(A)  216
(B)  180
(C)  144
(D)  108
(E)  72
Rationale: There are several ways to find the Least Common Multiple of two numbers. In this case, the most efficient method is to use the Greatest Common Factor: (A * B) / (GCF AB) = LCM AB
The greatest common factor of 12 and 16 is 4. So, 12#16 = 12*16/4 = 48.
The greatest common factor of 18 and 24 is 6. So, 18#24 = 18*24/6 = 72
Finally, the greatest common factor of 48 and 72 is 24. So,P= ((12#16)#(18#24)) = 48#72 = (48*72)/24 = 2*72 = 144
The correct answer is C.
Answer: (C)  144
Question: If f=1 and (f-b)/c = 1 which of the following is NOT a possible value of b?
(A) -2
(B) -1
(C) 0
(D) 1
(E) 2
Rationale: Equation is:
(f-b)/c = 1 where f = 1
so plug in 1 for f and look at it again
(1-b)/c = 1
now C can be anything we want, so if b = -2 we can plug it in and make it work
(1-(-2))/c = 1
3/c = 1
c = 3 and it works
HOWEVER, if we have a 0 in the numerator there isn't a number on earth that makes 0/C = 1
(1-1)/c = 1
0/c = 1
there aren't any matches for C to make this true
B cannot be 1.
Answer is D
Answer: (D) 1
Question: In covering a distance of 36 km, A takes 2 hours more than B. If A doubles his speed, then he would take 1 hour less than B. A's speed is:
(A) 5 km/h
(B) 6 km/h
(C) 10 km/h
(D) 15 km/h
(E) 25 km/h
Rationale: Let A's speed be X km/hr.
Then, 36/x - 36/2x = 3
6x = 36
x = 6 km/hr.
Answer : B.
Answer: (B) 6 km/h
Question: The sum of the first k positive integers is equal to k(k+1)/2. What is the sum of the integers from p to q, inclusive, where 0<p<q?
(A) q(q+1)/2 - (p+1)(p+2)/2
(B) q(q+1)/2 - p(p+1)/2
(C) q(q+1)/2 - (p-1)p/2
(D) (q-1)q/2 - (p+1)(p+2)/2
(E) (q-1)q/2 - p(p+1)/2
Rationale: Or try plug-in method: let q=4 and p=3 --> then q+p=7. Let see which option yields 7.
A. q(q+1)/2 - (p+1)(p+2)/2 = 10-10=0;
B. q(q+1)/2 - p(p+1)/2 = 10-6=4;
C. q(q+1)/2 - (p-1)p/2 = 10-3=7 --> OK;
D. (q-1)q/2 - (p+1)(p+2)/2 = 6-10=-4;
E. (q-1)q/2 - p(p+1)/2 = 6-6=0.
Answer: C.
Answer: (C) q(q+1)/2 - (p-1)p/2
Question: What is the next number of the following sequence
3,4,12,48,576,?
(A) 25648
(B) 24600
(C) 26600
(D) 25000
(E) 27648
Rationale: 3*4=12
4*12=48
12*48=576
48*576=27648
therefore next no. is 27648
ANSWER:E
Answer: (E) 27648
Question: A sum of Rs. 2900 amounts to Rs. 3422 in 3 years. Had the rate of interest be 1% higher then what would the sum amount in the same time period?
(A) Rs. 3509
(B) Rs. 3683
(C) Rs. 3596
(D) Data inadequate
(E) None of these
Rationale: 3422=2900+(2900*R*3/100)
R=6
If R is 1 more.
Then R=7
Sum=2900+(2900*7*3/100)
Sum=3509
ANSWER:A
Answer: (A) Rs. 3509
Question: Calculate the speed of a boat in still water (in km/hr) if in one hour, the boat goes 13 km/hr downstream and 10 km/hr upstream.
(A) 3 kmph
(B) 9 kmph
(C) 4 kmph
(D) 8 kmph
(E) 6 kmph
Rationale: Speed in still water = (13 + 5)1/2 kmph = 9 kmph.
answer :B
Answer: (B) 9 kmph
Question: A man can do a piece of work in 5 days, but with the help of his son, he can do it in 4 days. In what time can the son do it alone?
(A) 15
(B) 17
(C) 20
(D) 8
(E) 9
Rationale: Son's 1day's work = (1/4)-(1/5) = 1/20
The son alone can do the work in 20 days
Answer is C
Answer: (C) 20
Question: The average (arithmetic mean) of 20, 40, and 60 is 5 more than the average of 10, 60, and what number?
(A) 30
(B) 35
(C) 40
(D) 45
(E) 55
Rationale: a1 = 120/3 = 40
a2 = a1 -5 = 35
sum of second list = 35*3 = 105
therefore the number = 105 -70 = 35
B
Answer: (B) 35
Question: A man can row upstream at 5km/hr and down stream at 13km/hr find mans rate in still water ?
(A) 7.5km/hr
(B) 3.5km/hr
(C) 9km/hr
(D) 4km/hr
(E) 5km/hr
Rationale: given upstream(u) =5km/hr
down stream (v)= 13km/hr rate in still water =1/2(u+v)=1/2(5+13)=9km/hr Answer is (C)
Answer: (C) 9km/hr
Question: If g is a number such that –2 ≤ g ≤ 2, which of the following has the largest possible absolute value?
(A) 3g – 1
(B) x^2 + 1
(C) 3 – x
(D) x – 3
(E) x^2 – x
Rationale: Ans is A .. leads to the max value of 7 for g = -2
Answer: (A) 3g – 1
Question: Find the number of different prime factors of 441
(A) 4
(B) 2
(C) 3
(D) 5
(E) 6
Rationale: Explanation:
L.C.M of 441 = 3 x 3 x 7 x 7
3, 7
Number of different prime factors is 2.
Answer: Option B
Answer: (B) 2
Question: Bhanu spends 30% of his income on petrol on scooter 12% of the remaining on house rent and the balance on food. If he spends Rs.300 on petrol then what is the expenditure on house rent?
(A) 62
(B) 140
(C) 84
(D) 60
(E) 123
Rationale: Given 30% (Income ) = 300 ⇒⇒ Income = 1000
After having spent Rs.300 on petrol, he left with Rs.700.
His spending on house rent = 12% (700) = Rs.84
Answer:C
Answer: (C) 84
Question: Elvin's monthly telephone bill is the sum of the charge for the calls he made during the month and a fixed monthly charge for Internet service. Elvin's total telephone bill for January was $48 and Elvin's total telephone bill for February was 90$. If Elvin's charge for the calls he made in February was twice the charge for the calls he made in January, what is Elvin's fixed monthly charge for Internet service?
(A) $5
(B) $10
(C) $14
(D) $6
(E) $28
Rationale: Bill = Fixed Charge + Charge of Calls made
in Jan, Bill = Fixed Charge(Let, y) + Charge of calls made in Jan (Let, x) = $48
in Feb, Bill = Fixed Charge (Let, y) + Charge of calls made in Feb (Then, 2x) = $90
i.e. x+y = 48
and 2x+y = 90
Take the difference if two equations
i.e. (2x+y) - (x+y) = 90 - 48
i.e. x = 42
i.e. Fixed Monthly Charge, y = 6
Answer: Option
D
Answer: (D) $6
Question: Chloe has $27 dollars to go to the fair. she is bringing 2 other friends along. Admission to the fair is $3. Each ride costs $1.70. How many rides can she and her friends go on and how much money will be left over?
(A) They can go on 15 rides and $1.50 will be left over.
(B) They can go on 3 rides and $2.70 will be left over.
(C) They can go on 7 rides and $0 will be left over.
(D) They can go on 6 rides and $0 will be left over.
(E) They can go on 5 rides and $1.50 will be left over.
Rationale: Admission to the fair is $3 per person. If she wants her and her friends to go, the cost will be $9. 27-9 is 18. To go on a ride is $5.10. 5.10 x 3 is 15.30. 18-15.30 is 2.70. They can go on 3 rides and $2.70 will be left over. The correct answer is B.
Answer: (B) They can go on 3 rides and $2.70 will be left over.
Question: On one side of a coin there is the number 0 and on the other side the number 1. What is the probability that the sum of three coin tosses will be 1?
(A) 1/8.
(B) 1/2.
(C) 3/8.
(D) 5/8.
(E) 1/3.
Rationale: Assume the coin is unbiased.
Possible sums from 3 tosses = 0,1,2,3
O and 3 are possible in only 1 case each. (0,0,0 or 1,1,1)
1 is possible in 3C1 = 3 cases. (1,0,0; 0,1,0 or 0,0,1) or
similarly, 2 is possible in 3C2=3 cases (1,0,1; 1,1,0; 0,1,1)
So answer will be 3/8. Option C.
Answer: (C) 3/8.
Question: An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq m?
(A) 4082.8
(B) 408
(C) 40
(D) 4082.4
(E) 88788
Rationale: Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 * 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40
Answer: Option D
Answer: (D) 4082.4
Question: A certain store sells all maps at one price and all books at another price. On Monday the store sold 12 maps and 10 books for a total of $38.00, and on Tuesday the store sold 12 maps and 9 books for a total of $30.00. At this store, how much less does a map sell for than a book?
(A)  $0.25
(B)  $0.50
(C)  $0.75
(D)  $1.00
(E)  $4.5
Rationale: 12x+10y=38
12x+9y=30
subtracting 1 from 2
y=8
therefore
x=3.5
difference in price =4.5
E
Answer: (E)  $4.5
Question: Three numbers are in the ratio of 3 : 4 : 6 and their product is 1944. The largest of these numbers is
(A) 6
(B) 12
(C) 18
(D) 26
(E) 28
Rationale: Solution
Let the numbers be 3x, 4x and 6x.
Then, 3x × 4x × 6x = 1944
‹=›72x3 = 1944
‹=›x3 = 27
‹=›x = 3
Therefore, Largest number = 6x = 18.
Answer C
Answer: (C) 18
Question: How many Numbers can be formed with digits 2,4,6,8 without repetition?
(A) 124
(B) 256
(C) 64
(D) 84
(E) 94
Rationale: Number of one digit numbers = 4
Number of two digit numbers = 4 P 2 = 12
Number of Three digit numbers = 4 P 3 = 24
Number of four digit numbers = 4 P 4 = 24
So, total = 24 + 24 + 12 + 4 = 64
ANSWER:C
Answer: (C) 64
Question: The ratio of two numbers is 4 : 7 and their H.C.F. is 4. Their L.C.M. is
(A) 112
(B) 22
(C) 56
(D) 27
(E) 35
Rationale: Explanation:
Let the numbers be 4x and 7x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 16 and 28.
L.C.M. of 16 and 28 = 112.
Answer: Option A
Answer: (A) 112
Question: The list price of an article is Rs.65. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?
(A) 3%
(B) 4%
(C) 7%
(D) 8%
(E) 9%
Rationale: Explanation:
65*(90/100)*((100-x)/100) = 56.16
x = 4%
Answer: Option B
Answer: (B) 4%
Question: How many five letter words are formed using the letters of the word BRINJAL?
(A) 2800
(B) 2640
(C) 2400
(D) 2500
(E) 2520
Rationale: The number of letters in the given word is seven.
The number of five letter words that can be formed using these seven letters is 7P5
= 7 * 6 * 5 * 4 * 3 = 2520.
Answer: E
Answer: (E) 2520
Question: Two whole numbers whose sum is 42 cannot be in the ratio
(A) 2:5
(B) 1:6
(C) 2:4
(D) 3:8
(E) 2:40
Rationale: D) 3:8
Answer: (D) 3:8
Question: If |r+s|=|r-s|, then r*s must be equal to:
(A) -2
(B) 2
(C) 0
(D) -3
(E) 3
Rationale: Solution 1: Distance perspective
|r-s| = |r+s| ==> The distance of r and s is equal to the distance of r and -s.
<=======(-s)=======0=======(s)======>
Only 0 is the value that has a distance equal to s and -s.
Solution 2:
|r-s| = |r+s| (square both)
r^2 -2rs + s^2 = r^2 + 2rs + s^2
4rs = 0
rs = 0
Answer: C
Answer: (C) 0
Question: 105,100,...,90,85,80,75
Insert the missing number
(A) 95
(B) 78
(C) 83
(D) 84
(E) none of the above
Rationale: Missing number : 95
Answer : A
Answer: (A) 95