mathewhe/aqua_rat huggingface dataset:
Question: Sakshi can do a piece of work in 20 days.Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work :
(A) 15
(B) 16
(C) 18
(D) 25
(E) 29
Rationale: Solution
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4 .
Suppose Tanya taken x days to do the work.
5 : 4 : : 20 : x ⇒ x = (20x4/5)=x 16 days.
Hence,Tanya takes 16 days is complete the work
Answer B
Answer: (B) 16
Question: David works at a resort from the beginning of March to the end of September. During the month of August this past year, he made 2 times the average (arithmetic mean) of his monthly totals in tips for the other months. His total tips for August were what fraction of his total tips for all of the months he worked?
(A) 1/6
(B) 1/7
(C) 1/8
(D) 1/4
(E) 1/3
Rationale: First notice the number of months for which he worked - March to Sept i.e. 7 months
Avg of monthly totals in tips for months other than August = x
Tips in August = 2x
Total tips for all months = 6*x + 2x = 8x
Tips for August/Total tips for all months = 2x/8x = 1/4
Answer : D
Answer: (D) 1/4
Question: P, Q, R enter into a partnership. P initially invests 25 lakh and adds another 10 lakh after one year. Q initially invests 35 lakh and withdraws 10 lakh after 2 years. R's investment is Rs 30 lakh. In what ratio should the profit be divided at the end of 3 years?
(A) 18:19:19
(B) 18:18:19
(C) 19:19:18
(D) 18:19:18
(E) none
Rationale: Explanation:
P : Q : R
25×1+35×2):(35×2+25×1) :(30×3)
=95:95:90
=19:19:18
Answer: Option C
Answer: (C) 19:19:18
Question: A Man can row upstream at 98kmph and downward stream at 10 kmph. Find Man's rate still in water
(A) 6.8km/hr
(B) 54km/hr
(C) 90km/hr
(D) 3.8km/hr
(E) 7.9km/hr
Rationale: still in water=1/2(98+10)km/hr
=54km/hr
correct option is :B
Answer: (B) 54km/hr
Question: 7 does not occur in 1000. So we have to count the number of times it appears between 1 and 999. Any number between 1 and 999 can be expressed in the form of xyz where 0 < x, y, z < 9.
(A) 150
(B) 300
(C) 275
(D) 135
(E) 451
Rationale: 1. The numbers in which 7 occurs only once. e.g 7, 17, 78, 217, 743 etc
This means that 7 is one of the digits and the remaining two digits will be any of the other 9 digits (i.e 0 to 9 with the exception of 7)
You have 1*9*9 = 81 such numbers. However, 7 could appear as the first or the second or the third digit. Therefore, there will be 3*81 = 243 numbers (1-digit, 2-digits and 3- digits) in which 7 will appear only once.
In each of these numbers, 7 is written once. Therefore, 243 times.
2. The numbers in which 7 will appear twice. e.g 772 or 377 or 747 or 77
In these numbers, one of the digits is not 7 and it can be any of the 9 digits ( 0 to 9 with the exception of 7).
There will be 9 such numbers. However, this digit which is not 7 can appear in the first or second or the third place. So there are 3 * 9 = 27 such numbers.
In each of these 27 numbers, the digit 7 is written twice. Therefore, 7 is written 54 times.
3. The number in which 7 appears thrice - 777 - 1 number. 7 is written thrice in it.
Therefore, the total number of times the digit 7 is written between 1 and 999 is 243 + 54 + 3 = 300
Ans: B
Answer: (B) 300
Question: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
(A) 9
(B) 9.6
(C) 10
(D) 10.2
(E) 10.8
Rationale: Relative speed of the trains=60+40=100km/hr=100*5/18 m/s=250/9
Time taken to cross each other=total distance/speed
300/250/9=54/5=10.8sec
ANSWER:E
Answer: (E) 10.8
Question: A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 390 m long?
(A) 40 sec
(B) 60 sec
(C) 45 sec
(D) 48 sec
(E) 50 sec
Rationale: Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 140 = 750 m
Required time = 750 * 2/25 = 40 sec
ANSWER:B
Answer: (B) 60 sec
Question: 20.20/2000 is equal to:
(A) 1.01252677
(B) 0.013466667
(C) 0.125266677
(D) 0.126256677
(E) 0.12725776
Rationale: 20.20/2000 = 2525/200000
= 0.013466667
ANSWER:B
Answer: (B) 0.013466667
Question: The average of 1st 3 of 4 numbers is 6 and of the last 3 are 5. If the sum of the first and the last number is 13. What is the last numbers?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: A + B + C = 18
B + C + D = 15
A + D = 13
A – D = 3
A + D = 13
2D = 10
D = 5
ANSWER:B
Answer: (B) 5
Question: A banker paid Rs.5767.20 for a bill of Rs.5840, drawn of Apr 4 at 6 months. If the rate of interest was 7%, what was the day on which the bill was discounted?
(A) 3rd March
(B) 3rd September
(C) 3rd October
(D) 3rd August
(E) None of these
Rationale: Explanation :
F = Rs.5840
R = 7%
BD = 5840 - 5767.20 = Rs.72.8
BD = FTR/100
⇒ 72.8 = (5840 × T × 7)/100
⇒ T = (72.8×100)/(7×5840) = (10.4×100)/5840 = 1040/5840 = 104/584 = 13/73 years
= (13 × 365)/73 Days = 65 Days
=> Unexpired Time = 65 Days
Given that Date of Draw of the bill = 4th April at 6 months
=> Nominally Due Date = 4th October
=> Legally Due Date = (4th October + 3 days) = 7th October
Hence, The date on which the bill was discounted
= (7th October - 65 days)
= (7th October - 7 days in October - 30 days in September - 28 days in August)
= 3rd August Answer : Option D
Answer: (D) 3rd August
Question: Tea worth Rs.126 per kg are mixed with a third variety in the ratio 1: 1 : 2. If the mixture is worth Rs.163 per kg, the price of the third variety per kg will be
(A) Rs.169.50
(B) Rs.1700
(C) Rs. 185.50
(D) Rs. 180
(E) None
Rationale: Solution
Since first second varieties are mixed in equal proportions, so their average price = Rs.(126+135/2) = Rs.130.50
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
x-163/22.50 = 1 =â€º x - 163 = 22.50 =â€º x=185.50.
Hence, price of the third variety = Rs.175.50 per kg.
Answer C
Answer: (C) Rs. 185.50
Question: FIND THE VALUE OF X ?
(2/7)^-8*(7/2)^-2=(2/7)^X
(A) -5
(B) -6
(C) 4
(D) 0
(E) -4
Rationale: (2/7)^-8*(7/2)^-2=(2/7)^x
Now, (7/2)^8*(2/7)^2=(2/7)^x
on solving,
(7/2)^6=(2/7)^x
(2/7)^-6=(2/7)^x
Thus, x=-6.
ANSWER:B
Answer: (B) -6
Question: Which of the following numbers does NOT have a divisor greater than 1 that is the square of an integer?
(A) 82
(B) 27
(C) 64
(D) 48
(E) 50
Rationale: Prime Factorization
82=41*2 We got our candidate. No perfect squares here.
27= 3*3*3= 3^2*3. Includes a perfect square of 9.
64=8^2. Is a perfect square.
48=2*2*2*2*3=4^2*3. Includes a perfect square of 16.
50= 5*5*2=5^2*2. Includes a perfect square of 25.
All but 82 have perfect squares in them as a factor.
82=41*2 No perfect squares here.
27= 3*3*3= 3^2*3. Perfect square of 9.
64=8^2. Perfect square.
48=2*2*2*2*3=4^2*3. Perfect square of 16.
50= 5*5*2=5^2*2. Perfect square of 25.
Answer: (A) 82
Question: A committee that includes 9 members is about to be divided into 3 subcommittees with 3 members each. On what percent of the possible subcommittees that Michael is a member of is Annie also a member?
(A) 10%
(B) 20%
(C) 25%
(D) 40%
(E) 50%
Rationale: Michael is a member of one of the subcommittees.
P(Annie is on the same subcommittee) = 2/8 = 25%.
The answer is C.
Answer: (C) 25%
Question: The radius of a circular wheel is 1.75 m, how many revolutions will it make in traveling 1 km?
(A) 1000
(B) 1988
(C) 1998
(D) 2789
(E) 2677
Rationale: 2 * 22/7 * 1.75 * x
= 11000
x = 1000
Answer: A
Answer: (A) 1000
Question: Fresh grapes contain 90% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 10 kg of fresh grapes?
(A) 2 kg
(B) 2.4 kg
(C) 2.5 kg
(D) 1.250 kg
(E) none of these
Rationale: The weight of non-water in 10 kg of fresh grapes (which is 100-90=10% of whole weight) will be the same as the weight of non-water in x kg of dried grapes (which is 100-20=80% of whole weight), so 10âˆ—0.1=xâˆ—0.8--> x=1.25
Answer: D
Answer: (D) 1.250 kg
Question: he population of a city is 140,000. If it increases at the rate of 6% per annum, then what will be its population 2 years hence?
(A) 1797787
(B) 1597723
(C) 159776
(D) 159728
(E) 157304
Rationale: Population after n years = P [1 + (R/100)]2
Population after 2 years = 140000 * [1 + 6/100]2 = (160000 x 53/50 x 53/50) = 157304
ANSWER: E
Answer: (E) 157304
Question: The sum of four consecutive odd numbers is equal to the sum of 3 consecutive even numbers. Given that the middle term of the even numbers is greater than 101 and lesser than 212, how many such sequences can be formed?
(A) 27
(B) 17
(C) 25
(D) 33
(E) 50
Rationale: Four consecutive odd numbers: k-2, k, k+2, k+4
Three consecutive even numbers: n-2, n, n+2
k-2+k+k+2+k+4=n-2+n+n+2
4k+4=3n
4(k+1)=3n
k+1=(3/4)n
k=(3/4)n-1
All n's that's divisible by 4 will have an integral k. So, we need to find out how many such n's are available within given range:
We know,
101<n<212
104<=n<=208
Count=(208-104)/4+1=104/4+1=26+1=27
Ans: 27.
Answer: (A) 27
Question: The average monthly salary of laborers and supervisors in a factory is Rs.1250 per month; where as the average monthly salary of 6 supervisors is Rs.2450. If the average monthly salary of the laborers is Rs.950 find the number of laborers?
(A) 11
(B) 42
(C) 77
(D) 88
(E) 12
Rationale: 5x 6x 2x
50 25 100
250x + 150x + 200x = 4200
600x = 4200
x = 7 => 6x = 42
Answer:B
Answer: (B) 42
Question: 7,23,55,109,191,__
(A) 304
(B) 305
(C) 306
(D) 307
(E) 308
Rationale: 7= 2^3-1^2
23= 3^3-2^2
55= 4^3-3^2
....
..191= 6^3 - 5^2 = 216-25
next number = 7^3-6^2= 343 -36= 307
ANSWER:D
Answer: (D) 307
Question: The Smiley Pie Eating team won 30% of the first contests they entered. An amazingly winning streak increased their average to 50%. How many consecutive contests must they have won to have achieved this average?
(A) 30
(B) 20
(C) 10
(D) 25
(E) 35
Rationale: Explanation: Let's set up an equation to find the solution. Total number of contest won to start was 30% of 75 = 22.5. Then, an amazing winning streak increases the percentage to 50%. Let x represent the unknown number of consecutive winning contests. Therefore, the total number of contests entered is (75+x). The total contests won is (22.5+x). With a 50% increase in the total contests won, we end up with a solution equation of 50% * (75+x)+22.5+x. Next, let's get rid of the percent sign and rewrite, then solve the equation. 50/100 * (75+x)=22.5+x
1/2 * (75+x)=22.5+x
2[ 1/2 * (75+x)]=2(22.5+x)
1 * (75+x)=45+2x
75+x=45+2x
(75-45)+x=(45-45)+2x
30+x=2x
(30+x =2x)/x
30=x
Answer: A
Answer: (A) 30
Question: A teacher grades students’ tests by subtracting twice the number of incorrect responses from the number of correct responses. If Student A answers each of the 100 questions on her test and receives a score of 73, how many questions did Student A answer correctly?
(A) 55
(B) 60
(C) 73
(D) 82
(E) 91
Rationale: let the number of correct responses be x
then the number of incorrect responses =100-x
according to question
x-2(100-x)=73 (subtracting twice of incorrect from correct)
3x=273
x=91
ANSWER:E
Answer: (E) 91
Question: There are 4 people of different heights standing in order of increasing height. The difference is 2 inches between the first person and the second person, and also between the second person and the third person. The difference between the third person and the fourth person is 6 inches and the average height is 75. How tall is the fourth person?
(A) 73
(B) 75
(C) 77
(D) 79
(E) 81
Rationale: Let x be the height of the first person.
Then the heights are x, x+2, x+4, and x+10.
4x+16 = 4(75) = 300
x = 71 and the fourth person has a height of 71+10 = 81 inches
The answer is E.
Answer: (E) 81
Question: If a boat goes 7 km upstream in 42 minutes and the speed of the stream is 3 kmph, then the speed of the boat in still water is
(A) 4.2 Km /hr
(B) 9 Km /hr
(C) 13 Km /hr
(D) 21 Km /hr
(E) None
Rationale: Solution
Rate upstream	= (7/42x60)kmph
= 10 kmph.
Speed upstream	= 3 kmph.
Let speed in still water be x km/hr. Then,
speed upstream = (x - 3) Km/hr.
∴ x - 3 = 10 or
‹=›x = 13 Km/hr
Answer C
Answer: (C) 13 Km /hr
Question: What is the diffference between the place value of 2 in the numeral 7229?
(A) 150
(B) 160
(C) 180
(D) 190
(E) 200
Rationale: Option 'C'
200 - 20 = 180
Answer: (C) 180
Question: A boy wants to go abroad by boat and return by flight. He has a choice of 4 different boat to go and 5 flight to return. In how many ways, can the boy perform his journey?
(A) 20
(B) 40
(C) 45
(D) 60
(E) 70
Rationale: Ans.(A)
Sol. Number of choices to go by ship = 4 Number of choices to return by airline = 5 From, fundamental principle, total number of ways of performing the journey = 4 x 5 = 20 ways
Answer: (A) 20
Question: If each digit in the set of A = {1,2,3,4,5,6,7} is exactly used once, in how many ways can the digits be arranged such that the 2 and 5 are not adjacent?
(A) 7!
(B) 5*6!
(C) 7! - 6!
(D) 7! - 2!
(E) 7! / 2!
Rationale: The answer should be the (total arrangements) - (arrangements when 2 and 5 are adjacent).
The number of ways to arrange 7 units is 7!
If we think of 2 and 5 as one single unit, the number of arrangements is 6!
Note that 2 and 5 can have two arrangements, so we multiply by 2 to get 2*6!
The total number of valid arrangements is 7! - 2*6! = 7*6! - 2*6! = 5*6!
The answer is B.
Answer: (B) 5*6!
Question: In a division sum, the quotient is 36, the divisor 85 and the remainder 26, find the dividend?
(A) 3066
(B) 3586
(C) 3086
(D) 3968
(E) 3286
Rationale: Explanation:
36 * 85 + 26 = 3086
Answer : C
Answer: (C) 3086
Question: An airplane flies against the wind from A to B in 8 hours. The same airplane returns from B to A, in the same direction as the wind, in 7 hours. Find the ratio of the speed of the airplane (in still air) to the speed of the wind.
(A) 15
(B) 25
(C) 35
(D) 45
(E) 55
Rationale: Let x = speed of airplane in still air, y = speed of wind and D the distance between A and B. Find the ratio x / y
Against the wind: D = 8(x - y), with the wind: D = 7(x + y)
8x - 8y = 7x + 7y, hence x / y = 15
correct answer is A) 15
Answer: (A) 15
Question: The area of a square land is A square feet and the perimeter is p feet. If 5A=10p+45, what is the perimeter of the land, in feet?
(A) 18
(B) 56
(C) 40
(D) 36
(E) 64
Rationale: You can also solve this via using the given numbers in the answer choices!
Of course you need to be aware of the basic properties as outlined by the other posts above (a = x^2 and p = 4x)
Starting with B you will notice that x=14 is way too big for your area (14^2) and will not satisfy: 5A=10p+45 or A=2p+9
--> Eliminate B and E
Now pick D (its either too big, then its A, or too small then you know its C or it is B itsself)
And picking D indeed solves the problem! (36/4 --> 9; a= 9^2 = 81 and 81=2x36+9)
Answer: (D) 36
Question: If 2 tic equals 3 tacs and 2 tacs equal 7 tocs, what is the ratio of one tic to one toc?
(A) 15/2
(B) 6/5
(C) 21/4
(D) 3/10
(E) 1/15
Rationale: 2Tic=3*Tac and 2*Tac=7*Toc;
4*Tic=6*Tac and 6*Tac=21*Toc --> 4*Tic=21*Toc --> Tic/Toc=21/4.
Answer: C.
Answer: (C) 21/4
Question: A train moves at average speed of 60kmph reaches its destination on time.what its average speed becomes 50kmph , then it reaches its destination 15 late. find the length of the journey?
(A) 4.86km
(B) 2.5km
(C) 6.86km
(D) 5.867km
(E) 3.25km
Rationale: Difference between timings=15 min=1/4hr
let the length of the journey be x km.
then x/50-x/60=1/4
x/10=1/4
x=2.5km
Answer (B)
Answer: (B) 2.5km
Question: Find the numbers which are in the ratio 3 : 2 : 4 such that the sum of the first and the second added to the difference of the third and the second is 21 ?
(A) 3,3,3
(B) 4,4,3
(C) 4,5,3
(D) 9, 6, 12
(E) 2,4,4
Rationale: Let the numbers be a, b and c.
Given that a, b and c are in the ratio 3 : 2 : 4.
let, a = 3x, b = 2x and c = 4x
Given, (a+b) + (c - b) = 21
= > a + b + c - b = 21 = > a + c = 21
= > 3x + 4x = 21 = >7x = 21 = > x = 3
a , b , c are 3x, 2x, 4x.
a, b, c are 9 , 6 , 12.
Answer:D
Answer: (D) 9, 6, 12
Question: In each series, look for the degree and direction of change between the numbers. In other words, do the numbers increase or decrease, and by how much
Look at this series: 80, 10, 70, 15, 60, ... What number should come next?
(A) 30
(B) 40
(C) 20
(D) 50
(E) 60
Rationale: C
20
This is an alternating addition and subtraction series. In the first pattern, 10 is subtracted from each number to arrive at the next. In the second, 5 is added to each number to arrive at the next.
Answer: (C) 20
Question: At 6′o a clock ticks 6 times. The time between first and last ticks is 40 seconds. How long does it tick at 12′o clock
(A) 47
(B) 88
(C) 28
(D) 66
(E) 11
Rationale: Explanation:
For ticking 6 times, there are 5 intervals.
Each interval has time duration of 40/5 = 8 secs
At 12 o'clock, there are 11 intervals,
So total time for 11 intervals = 11 × 8 = 88 secs.
Answer: B
Answer: (B) 88
Question: Distance between two stations A and B is 1108 km. A train covers the journey from A to B at 84 km per hour and returns back to A with a uniform speed of 56km per hour. Find the average speed of train during the whole journey.
(A) 60 km/hr
(B) 30.5 km/hr
(C) 57 km/hr
(D) 67.2 km/hr
(E) None of these
Rationale: Explanation :
Average speed = (2xy)/(x+y) km/hr
= (28456)/(84+56) km/hr
= (28456)/140 km/hr
= 67.2 km/hr.
Answer : D
Answer: (D) 67.2 km/hr
Question: If A:B = 2:3, B:C = 4:5 and C:D = 6:7, then find the value of A:B:C:D
(A) 15:24:30:35
(B) 16:24:30:35
(C) 17:24:30:35
(D) 18:24:30:35
(E) NONE OF THE ABOVE
Rationale: Explanation:
A:B=2:3
B:C=4:5=(4∗3/4:5∗3/4)=3:15/4
C:D=6:7=(6∗15/24:7∗15/24)=15/4:35/8
A:B:C:D=2:3:15/4:35/8=16:24:30:35=8:12:9
ANSWER IS B
Answer: (B) 16:24:30:35
Question: A telephone number contains 10 digit, including a 3-digit area code. Bob remembers the area code and the next 5 digits of the number. He also remembers that the remaining digits are not 0, 1, 2, 6, or 7. If Bob tries to find the number by guessing the remaining digits at random, the probability that he will be able to find the correct number in at most 2 attempts is closest to which of the following ?
(A) 50/625
(B) 2/625
(C) 4/625
(D) 25/625
(E) 75/625
Rationale: I think most of the answers are missing a point. Let me try to put it across:
Total number of possible numbers are : 5x5 = 25
Correct number =1
Case 1: When he gets it right in first attempt: P(E1) = 1/25
Case 2: He gets 1st attempt wrong and second right:
When he gets it wrong then the probability of getting wrong is 24/25.
Now there are 24 cases with him and he chooses the right one this time.
Probability of right case is 1/24
Thus, P(E2) = 24/25 x 1/24
=1/25
Probability of getting it right in at most two cases = P(E1) + P(E2)
= 1/25 + 1/25
= 2/25
= 50/625
Option (A) is therefore right as most of you mentioned but the method employed was wrong.
Answer: (A) 50/625
Question: There are 10 teams in a soccer league and each team plays each of the other teams once. How many games will be played in total?
(A) 33
(B) 36
(C) 39
(D) 42
(E) 45
Rationale: 10C2=45
The answer is E.
Answer: (E) 45
Question: A train running at 25 km/hr takes 60 seconds to pass a platform. Next, it takes 12 seconds to pass a man walking at 5 km/hr in the same direction. Find the length of the train and that of the platform.
(A) a) 200/3m175/3m
(B) b) 30m190m
(C) c) 50m45m
(D) d) 100/3 m200/3
(E) e) none of these
Rationale: Hi Math gurus correct me if I am wrong. I wondered i reached the answer mentioned here i.e 100m and 25m
lets solve it
To find out length of train the train, which is must cover the static point of the man as well as the distance covered the man during 12 sec.
The man covered the distance during 12sec is 5*5/60*12=5m so the train covered a distance in 12 sec= 25*5/60*12=25
so the length of the train(Lt) is 5+25=30m
Now crossing the platform means length of train+length of platform(Lt+p)= 60*25*5/60=125m Now the length of platform (Lp) is= 125-30=95m
So answer is 30m and 95m Must beBeven though its mentioned 30m and 190m thinking so typo mistake...........
Answer: (B) b) 30m190m
Question: 50 square stone slabs of equal size were needed to cover a floor area of 98 sq.m. Find the length of each stone slab?
(A) 140cm
(B) 767cm
(C) 88cm
(D) 666cm
(E) 776cm
Rationale: Area of each slab
=98/50m2=1.96m2
Length of each slab √1.96=1.4m=140cm
Answer: (A) 140cm
Question: In a 100 m race, A runs at 8km per hour. If A gives B a start of 5 m and still him by 15 seconds, what is the speed of B ?
(A) 5.56 km/hr.
(B) 5.06 km/hr.
(C) 5.70 km/hr.
(D) 6.76 km/hr.
(E) 5.72 km/hr.
Rationale: Time taken by A to cover 100 m =(60 X 60 / 8000)	x 100 sec = 45 sec.
B covers (100 - 5) m = 95 m in (45 + 15) sec = 60 sec.
B's speed = (95 x 60 x 60)/(60 x 1000)km/hr = 5.7 km/hr.
Answer is C
Answer: (C) 5.70 km/hr.
Question: Three 6 faced dice are thrown together. The probability that no two dice show the same number on them is ?
(A) 5/7
(B) 5/9
(C) 5/5
(D) 5/3
(E) 2/9
Rationale: No two dice show same number would mean all the three faces should show different numbers. The first can fall in any one of the six ways. The second die can show a different number in five ways. The third should show a number that is different from the first and second. This can happen in four ways.
Thus 6 * 5 * 4 = 120 favourable cases.
The total cases are 6 * 6 * 6 = 216.
The probability = 120/216 = 5/9.
Answer:B
Answer: (B) 5/9
Question: What is the difference between the local values of 3 in the number 53403?
(A) 2992
(B) 2997
(C) 2877
(D) 2077
(E) 1211
Rationale: Explanation:
3000 â€“ 3 = 2997
Answer:B
Answer: (B) 2997
Question: The average marks of a Suresh in 10 papers are 80. If the highest and the lowest scores are not considered, the average is 81. If his highest score is 92, find the lowest?
(A) 55
(B) 60
(C) 62
(D) 52
(E) Cannot be determined
Rationale: Total marks of 10 papers = 80 x 10 = 800
Total marks of 8 papers = 81 x 8 = 648
Total marks of two papers = (800 - 648) = 152
If highest total is 92, then the lowest total is
(152 - 92) = 60.
ANSWER:B
Answer: (B) 60
Question: If a number between 0 and 1/2 is selected at random, which of the following will the number most likely be between
(A) 0 and 3/20
(B) 3/20 and 1/5
(C) 1/5 and 1/4
(D) 1/4 and 3/10
(E) 3/11 and 1/2
Rationale: E. 3/11 and 1/2
Definitely not. I am always happy to explain a given question or issue if I can. However, I sometime donot put my explanation if I am answering first because I want to put others first for their explanation.
Now you have excellent explanantion byscthakur. In fact the question is asking the likelyness of or high chances/probability of having a given number. Hope you already got it. E
Answer: (E) 3/11 and 1/2
Question: X and Y invest Rs.21000 and Rs.15000 respectively in a business. At the end of the year, they make a profit of Rs.25500. What is the share of X in the profit?
(A) Rs.14400
(B) Rs.26400
(C) Rs.12000
(D) Rs.12500
(E) Rs.14875
Rationale: Ratio of the investment=21000:15000=7:5
Share of X in the profit=(25500×7)/12=14875
ANSWER:E
Answer: (E) Rs.14875
Question: Bill made a profit of 10% by selling a product. If he had purchased that product for 10% less and sold it at a profit of 30%, he would have received $ 70 more. What was his original selling price?
(A)  $770
(B)  $660
(C)  $700
(D)  $1100
(E)  $840
Rationale: Let the original purchase price be X
So original selling price at 10% profit = 1.1X
If product is purchased at 10% less of original = 0.9X
Profit of 30% on this price = 1.3(0.9X)
He would have received $70 more in second scenario => 1.3(0.9X) - 1.1X = 70
=> 0.07X = 70
=> X = $1000
Original purchase price = $1000
Hence, original selling price (at 10% of profit) = 1.1(1000) = $1100
Option D
Answer: (D)  $1100
Question: How many 6 digits no can be formed using 0,1,2,3,5,7 without repeatation?
(A) 500
(B) 600
(C) 700
(D) 800
(E) 900
Rationale: no. of words with all nos. is 6!
no. of words with 0 in 1st position is 5!
required no. 6!-5!=600
ANSWER:B
Answer: (B) 600