mathewhe/aqua_rat huggingface dataset:
Question: EASY,INC recently conducted a survey and found that 60,000 of its customers live in rural areas. if the number of it customers who live in urban areas is 200 percents grater than the numbers of customers who live in rural areas, how many of EASY,INC customers live in urban areas ?
(A) 200,000
(B) 180,000
(C) 360,000
(D) 480,000
(E) 540.0
Rationale: Let's say that we have a starting value of X...
100% of X = X
100% MORE than X = X + X = 2X
200% MORE than X = X + 2X = 3X
300% MORE than X = X + 3X = 4X
Etc.
Here, we're told that 60,000 customers live in rural areas and the number who live in urban areas is 200% GREATER than the number who live in rural areas. That means that the number who are in urban areas is 3 times the number in rural areas...
3(60,000) = 180,000
Final Answer:B
Answer: (B) 180,000
Question: Evaluate: |7 - 8(3 - 12)| - |5 - 11| = ?
(A) 40
(B) 50
(C) 73
(D) 70
(E) 80
Rationale: According to order of operations, inner brackets first. Hence
|7 - 8(3 - 12)| - |5 - 11| = |7 - 8*(-9)| - |5 - 11|
According to order of operations, multiplication within absolute value signs (which may be considered as brackets when it comes to order of operations) next. Hence
= |7 + 72| - |5 - 11|
= |79| - |-6|
= 79 - 6 = 73
correct answer C)73
Answer: (C) 73
Question: A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?
(A) 34
(B) 40
(C) 68
(D) 88
(E) None
Rationale: EXPLANATION
We have: l = 20 ft and lb = 680 sq. ft.
So, b = 34 ft.
Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.
Answer D
Answer: (D) 88
Question: In a set of three numbers,the difference between the largest and the second largest numbers is added to the smallest number.The average of the largest,second largest and the new number formed exceeds the average of the original three numbers by 16.The largest number exceeds the second largest number by how much ?
(A) 5
(B) 10
(C) 30
(D) 15
(E) 60
Rationale: Let the numbers in increasing order be A<B<C...
since the new number(N) increase the average of new set of numbers by 5 after replacing the smallest number,A,
the new number,N, exceeds the smallest,A, by 3*5=15 orN=15+A..(1)
and what is the new number,N,----C-B (diff in the largest and second largest)+A...(2)...
from (1)(2) C-B=15
Answer:D
Answer: (D) 15
Question: Murari and Madan Started a business with investments of Rs. 13000 and Rs. 52000. After 5 months Arun joins with a capital of Rs. 52000. At the end of a year they got a profit of Rs. 14250. Find the share of Arun.
(A) Rs. 3650
(B) Rs. 5250
(C) Rs. 6750
(D) Rs. 2250
(E) None of these
Rationale: Explanation:
Rs. 5250
Answer: Option B
Answer: (B) Rs. 5250
Question: The speed of a subway train is represented by the equation z=s^2+2s for all situations where 0≤s≤7, where z is the rate of speed in kilometers per hour and s is the time in seconds from the moment the train starts moving. In kilometers per hour, how much faster is the subway train moving after 7 seconds than it was moving after 5 seconds?
(A) 4
(B) 28
(C) 15
(D) 48
(E) 63
Rationale: Given: z=s^2+2s for 0≤s≤7
z(5) = 5^2 + 2*5 = 35
z(7) = 7^2 + 2*7 = 63
Therefore z(7) - z(3) = 63 - 35 = 28 km/hr
Option B
Answer: (B) 28
Question: Two numbers N and 12 have LCM = 42 and GCF = 6. Find N.
(A) 35
(B) 56
(C) 21
(D) 87
(E) 24
Rationale: The product of two integers is equal to the product of their LCM and GCF. Hence.
12* N = 42 * 6
N = 42*6 / 12 = 21 correct answer C
Answer: (C) 21
Question: My brother is 4 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age of when my brother was born, then, what was the age of my father and mother respectively when my brother was born?
(A) 32 yrs, 23 yrs
(B) 32 yrs, 29 yrs
(C) 32 yrs, 22 yrs
(D) 35 yrs, 33 yrs
(E) none
Rationale: Sol.
Clearly, my brother was born 4 years before I was born and 4 years after my sister was born.
So, father's age when brother was born = (28 + 4) = 32 years.
mother's age when was born = (26 - 4) years = 22 years.
Answer C
Answer: (C) 32 yrs, 22 yrs
Question: A single discount equivalent to the discount series of 20%, 30% and 5% is?
(A) 31.9
(B) 31.7
(C) 46.8
(D) 31.5
(E) 31.1
Rationale: 100*(80/100)*(70/100)*(95/100) = 53.2
100 - 53.2 = 46.8
Answer:C
Answer: (C) 46.8
Question: A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform.
(A) 310 meter
(B) 335 meter
(C) 345 meter
(D) 350 meter
(E) 375 meter
Rationale: Explanation:
Speed = Distance/time = 300/18 = 50/3 m/sec
Let the length of the platform be x meters
then
Distance=Speedâˆ—Timex+300=50/3 X 39
=>3(x+300)=1950=>x=350 meters
ANSWER IS D
Answer: (D) 350 meter
Question: A train , having a length of 385 meter is running at a speed of 60 kmph. In what time, it will pass a man who is running at 6 kmph in the direction opposite to that of the train
(A) 10 sec
(B) 8 sec
(C) 6 sec
(D) 4 sec
(E) 21 sec
Rationale: Explanation:
Distance = 385 m
Relative speed = 60+6 = 66 kmph (Since both the train and the man are in moving in opposite direction)
= 66×10/36 mps = 110/6 mps
Time = distance/speed = 385/(110/6) = 21 s
Answer: Option E
Answer: (E) 21 sec
Question: 3x + y = 21 , and x + 3y = 1. Find the value of 2x + 2y
(A) 20
(B) 18
(C) 16
(D) 11
(E) 5
Rationale: Add these two equations
4x + 4y = 22
Divide by 2 ( to Get 2x + 2y)
Answer will be D. 11
Answer: (D) 11
Question: What is the dividend. divisor 17, the quotient is 9 and the remainder is 5?
(A) 140
(B) 143
(C) 144
(D) 158
(E) 160
Rationale: D = d * Q + R
D = 17 * 9 + 5
D = 153 + 5
D = 158
Answer: (D) 158
Question: John tossed a fair coin 3 times. What is the probability that the coin landed heads up exactly twice?
(A) 0.125
(B) 0.175
(C) 0.275
(D) 0.375
(E) 0.475
Rationale: The probability is exactly same as the cion landed tail up once. That is 3*(1/2)^3 = 3/8 =0.375.
The answer is, therefore, (D).
Answer: (D) 0.375
Question: A starts business with Rs. 3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B's contribution in the capital?
(A) Rs. 7500
(B) Rs. 8000
(C) Rs. 8500
(D) Rs. 9000
(E) Rs. 9500
Rationale: A invests 3500 Rs for 12 months (Why 12 - because profit is given of 1 year) in the ratio of 2.
B invests X Rs for 7 months (Why 7 - because B joins A after 5 months and profit is given of 1 year) in the ratio of 3.
3500*12+X*7 = 2/3.
42000+7X = 2/3.
7X = 3/2*42000.
X = 9000.
ANSWER D
Answer: (D) Rs. 9000
Question: 20 people can write 50 book in 15 days working 8 hour a day.then in how many day 200 can be written by 60 people?
(A) 200
(B) 100
(C) 50
(D) 70
(E) 25
Rationale: work per day epr hour per person= 50/(15*8*20) // eq-1
people= 60; let suppose day=p; per day work for 8 hours
acc. to condition
work per day epr hour per person= 200/(p*8*60) // eq-2
eq-1==eq-2;
p= 100
ANSWER:B
Answer: (B) 100
Question: Sandy can do a job in 21 days and Molly can do the same job in 42 days. If they work together, in how many days will they complete the job?
(A) 8
(B) 10
(C) 12
(D) 14
(E) 16
Rationale: Sandy can do 1/21 of the job each day.
Molly can do 1/42 of the job each day.
The combined rate is 1/21 + 1/42 = 1/14 of the job each day.
The job will take 14 days.
The answer is D.
Answer: (D) 14
Question: The least number which when increased by 4 each divisible by each one of 22, 32, 36 and 54 is :
(A) 427
(B) 859
(C) 860
(D) 4320
(E) None of these
Rationale: Solution
Required number = (L.C.M. of 24, 32, 36, 54) - 4 = 864 - 4 = 860. Answer C
Answer: (C) 860
Question: A can give B 60 meters start and C 120 meters start in a kilometer race. How much start can B give C in a kilometer race?
(A) 63.83
(B) 111.67
(C) 111.64
(D) 111.11
(E) 101.12
Rationale: A runs 1000 m while B runs 940 m and C runs 880 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 880)/940=936.17 m.
B can give C = 1000 - 936.17= 63.83 m.
Answer:A
Answer: (A) 63.83
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 900 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
(A) 120
(B) 99
(C) 88
(D) 72
(E) 12
Rationale: Given that the area of the square = 900 sq.units
=> Side of square = √900 = 30 units
The radius of the circle = side of the square = 30 units Length of the rectangle = 2/5 * 30 = 12 units
Given that breadth = 10 units
Area of the rectangle = lb = 12 * 10 = 120 sq.units
Answer: A
Answer: (A) 120
Question: Of the employees in a company, 50 % are female who have a master degree. If 20 % of the female employees do not have a master degree, what percent of the employees in the company are female?
(A) 60%
(B) 62.5%
(C) 63.25%
(D) 63.5%
(E) 65%
Rationale: Let E be total no. of employees and F be total no of female employees.
Question asked what is F/E X 100%?
No. of female employees with Masters = 0.5 x E (From the question)
No. of female employees without masters = 0.2 x F (From the question)
Therefore No. of female employees with masters = F - 0.2 F = 0.8 F
The 2 expressions equal each other therefore 0.8F = 0.5E; F/E = 0.5/0.8 = 62.5%
Ans: B
Answer: (B) 62.5%
Question: Rs.1540 were divided among John, Paul & Tom in such a way that John had Rs.80 more than Paul and Tom had Rs 60 more than John . How much was Paulâ€™s share?
(A) Rs.575
(B) Rs.580
(C) Rs.585
(D) Rs.590
(E) Rs.595
Rationale: Let Paul gets Rs x. Then We can say John gets Rs (x + 80 ) and Tom gets Rs ( x + 140) .
x + 80 + x + x + 140 = 1540
3x = 1320
x = 440 .
Paulâ€™s share = Rs ( 440 + 140 ) = Rs.580
B
Answer: (B) Rs.580
Question: A bus can hold 48 passengers. If there are 12 rows of seats on the bus, how many seats are in each row?
(A) 2
(B) 1
(C) 8
(D) 6
(E) 4
Rationale: No. of seats = 48/12 = 4
There are 4 seats in each row
Answer : E
Answer: (E) 4
Question: If a certain sample of data has a mean of 25.0 and a standard deviation of 2.0, which of the following pairs contain two values that are each at least 2.5 standard deviations from the mean?
(A) (14.0; 16.5)
(B) (14.5; 21.0)
(C) (14.0; 26.5)
(D) (16.5; 26.0)
(E) (19.0; 36.5)
Rationale: 2.5 standard deviation equals to 2.5*2=5;
2.5 standard deviations from the mean, so5 points, from the mean is the range from {mean-5} to {mean+5}, so from 20 to 30:
The correct answer choice must cover all this range: only answer choice E does this.
Answer: E.
Answer: (E) (19.0; 36.5)
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B
(A) 10
(B) 8
(C) 6
(D) 5
(E) 7
Rationale: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years
Answer:A
Answer: (A) 10
Question: A collection of books went on sale, and 2/3 of them were sold for $4 each. If none of the 36 remaining books were sold, what was the total amount received for the books that were sold?
(A) $288
(B) $135
(C) $90
(D) $60
(E) $54
Rationale: Since 2/3 of the books in the collection were sold, 1/3 were not sold. The 36 unsold books represent 1/3 of the total number of books in the collection, and 2/3 of the total number of books equals 2(36) or 72. The total proceeds of the sale was 72($4) or $288. The best answer is therefore A.
Answer: A.
Answer: (A) $288
Question: The least number of four digits which is divisible by 15, 25, 40 and 75 is:
(A) 9000
(B) 9400
(C) 9600
(D) 9800
(E) 9700
Rationale: Greatest number of 4 digits is 9999. L.C.M of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399. Required number = 9999 - 399 = 9600
ANSWER:C
Answer: (C) 9600
Question: Calculate the effect changes in dimension of a rectangle will have on its area, if length is increased by 40% and its breadth is decreased by 25%?
(A) 5% increase
(B) 7% increase
(C) 6% increase
(D) 4% increase
(E) 3% increase
Rationale: let L and B be 100 each
100 * 100 = 10000
L increase by 40% = 140
B decrease by 25% = 75
140 * 75 = 10500
5% increase
ANSWER:A
Answer: (A) 5% increase
Question: A and B complete a work in 30 days. A alone can do it in 40 days. If both together can do the work in how many days?
(A) 1.0875 days
(B) 0.1873 days
(C) 0.0673 days
(D) 0.0583 days
(E) 0.0773 days
Rationale: 1/30 + 1/40 = 0.0583 days
ANSWER:D
Answer: (D) 0.0583 days
Question: A shopkeeper purchased 70 kg of potatoes for Rs. 420 and sold the whole lot at the rate of Rs. 6.50 per kg. What will be his gain percent?
(A) 12 4/3 %
(B) 18 1/4 %
(C) 8 1/3 %
(D) 6 1/3 %
(E) 10 2/3 %
Rationale: C
C.P. of 1 kg = 420/7 = Rs. 6
S.P. of 1 kg = Rs. 6.50
Gain % = 0.50/6 * 100 = 25/3 = 8 1/3 %
Answer: (C) 8 1/3 %
Question: Some of 50%-intensity red paint is replaced with 25% solution of red paint such that the new paint intensity is 30%. What fraction of the original paint was replaced?
(A) 1/30
(B) 1/5
(C) 2/3
(D) 3/4
(E) 4/5
Rationale: Let total paint = 1
Let amount replaced = x
50 (1-x) + 25x = 30
x = 4/5
ANSWER:E
Answer: (E) 4/5
Question: There are 56 lights which are functional and each is controlled by a separate On/Off switch. Two children X and Y start playing with the switches. X starts by pressing every third switch till he reaches the end. Y, thereafter, presses every fifth switch till he too reaches the end. If all switches were in Off position at the beggining, How many lights are switched On by the end of this operation?
(A) 18
(B) 19
(C) 17
(D) 15
(E) 16
Rationale: Editing my solution:
Number of switches = 56
Number of switches turned on by X: 3, 6, ... 54 = 18
Number of switches turned on by Y: 5, 10, ....55 = 11
Few switches are turned on by X and later turned off by Y: LCM(3,5) = 15x = 15, 30,....90 = 6.
Subtract the above 6 switches from both X and Y as they are turned off.
Number of switches that are turned on = (18- 6) + (11 - 6) = 17
Answer: C
Answer: (C) 17
Question: Sanoop bought 8 t-shirts at an average price (arithmetic mean) of Rs.526. If Sanoop returned 2 t-shirts to the retailer, and the average price of the remaining t-shirts was Rs.505, then what is the average price, of the three returned t-shirts?
(A) 560
(B) 589
(C) 562
(D) 563
(E) 564
Rationale: Total price of 8 t-shirts= 8*526=4208
Total price of 6 t-shirts=5*505=3030
Total price of 2 t-shirts=4208-3030=1178
Average price of 3 t-shirts=1178/2=589
Correct option Answer:B
Answer: (B) 589
Question: Thurston wrote an important seven-digit phone number on a napkin, but the last three numbers got smudged. Thurston remembers only that the last three digits contained at least one zero and at least one non-zero integer. If Thurston dials 15 phone numbers by using the readable digits followed by 15 different random combinations of three digits, each with at least one zero and at least one non-zero integer, what is the probability that he will dial the original number correctly?
(A) 1/9
(B) 10/243
(C) 1/18
(D) 10/271
(E) 1/1000000
Rationale: If the last three digits have 1 zero (XX0), the total # of numbers possible is 9*9*3 (multiply by 3 since XX0 can be arranged in 3 ways: XX0, X0X, or 0XX).
If the last three digits have 2 zeros (X00), the total # of numbers possible is 9*3 (multiply by 3 since X00 can be arranged in 3 ways: X00, 00X, or X0X).
P = 15/(9*9*3+9*3) = 1/18.
Answer: C.
Answer: (C) 1/18
Question: If six boys sit in a row, then what is the probability that three particular boys are always together is?
(A) 1/5
(B) 1/4
(C) 1/3
(D) 1/7
(E) 2/5
Rationale: Six boys can be arranged in a row in 6! ways.
Treat the three boys to sit together as one unit then there 4 boys and they can be arranged in 4! ways.
Again 3 boys can be arranged among them selves in 3! ways.
Favorable outcomes = 3!4!
Required probability = 3!4!/6! = 1/5
A
Answer: (A) 1/5
Question: A sum of Rs. 2665 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
(A) 1686
(B) 1640
(C) 6829
(D) 2780
(E) 2790
Rationale: (x*8*3)/100 = ((2665 - x)*3*5)/100
24x/100 = 39975/100 - 15x/100
39x = 39975 => x = 1025
Second sum = 2665 – 1025 = 1640
Answer: B
Answer: (B) 1640
Question: How many meters of carpet 50cm, wide will be required to cover the floor of a room 30m * 20m?
(A) 1000
(B) 1050
(C) 1100
(D) 1200
(E) 1300
Rationale: 50/100 * x = 30 * 20 => x = 1200
ANSWER:D
Answer: (D) 1200
Question: All of the students of the Music High School are in the band, the orchestra, or both. 90 percent of the students are in only one group. There are 91 students in the band. If 60 percent of the students are in the band only, how many students are in the orchestra only?
(A) 30
(B) 33
(C) 36
(D) 39
(E) 42
Rationale: 60% of students are in the band only, so 30% of students are in the orchestra only.
Since 10% of students are in both, then 70% of students are in the band which is 91 students.
The number of students in the orchestra is (30/70)*91 = 39.
The answer is D.
Answer: (D) 39
Question: Yesterday it took Robert 3 hours to drive from City A to City B. Today it took Robert 2.5 hours to drive back from City В to City A along the same route. If he had saved 30 minutes in both trips, the speed for the round trip would be 80 miles per hour. What is the distance between city A and city B?
(A)  90
(B)  180
(C)  150
(D)  240
(E)  300
Rationale: 2d/80 = 4.5 ( because time = 3 + 2.5 - 1 hrs)
=> d = 180
Answer - B
Answer: (B)  180
Question: Six students are equally divided into 3 groups, then, the three groups were assigned to three different topics. How many different arrangements E are possible?
(A)  30
(B)  60
(C)  90
(D)  180
(E)  540
Rationale: 90 is the number of ways you can assign 3 teams formed out of 12 people to 3 different tasks.
But now you can order the 3 tasks in 3! ways. T1 T2 T3 or T2 T1 T3.... etc etc.
I was confused between 90 and 540 but since question used the wordarrangementsdecided to go with complete arrangements E including the order of tasks.
could you explain the highlighted step... i'm getting 90 = 15 * 3!
suppose the students are numbered 1,2,3,4,5,6 and tasks are X,Y and Z
one of the 15 possible ways of forming teams is 12, 34, 56. these teams can be assigned to 3 tasks in 3! = 6 ways
X--	Y--	Z
12--	34--	56
12--	56--	34
34--	12--	56
34--	56--	12
56--	12--	34
56--	34--	12
so the answer should be 15*6 = 90
But now you can fruther decide which task you want to perform first X Y or Z..C
Answer: (C)  90
Question: The difference between the place values of two fives in the numerical 86510529 is
(A) 0
(B) 4905
(C) 49050
(D) 490500
(E) None of them
Rationale: Required difference = (500000-500)
=490500.
Answer is D
Answer: (D) 490500
Question: The velocity of a falling object in a vacuum is directly proportional to the amount of time the object has been falling. If after 5 seconds an object is falling at a speed of 90 miles per hour, how fast will it be falling after 18 seconds?
(A) 18 miles per hour
(B) 90 miles per hour
(C) 216 miles per hour
(D) 324 miles per hour
(E) 5400 miles per hour
Rationale: Since Velocity is proportional to Time
Velocity =k*Timewhere k is the constant of proportionality
Time= 5 seconds
Velocity = 5k = 90 miles per Hour
i.e. k = 18
i.e. The relation between Velocity and Time becomes
Velocity =18*Time
Time= 18 seconds
Velocity = 18*18 = 324 miles per hour
Answer: Option D
Answer: (D) 324 miles per hour
Question: A cement mixture is composed of 3 elements. By weight, 1/2 of the mixture is sand, 1/5 of the mixture is water, and the remaining 15 pounds of the mixture is gravel. What is the weight of the entire mixture in pounds?
(A) 30
(B) 40
(C) 50
(D) 60
(E) 80
Rationale: Let the total weight be x.
Sand content= (1/2)x
Water content= (1/5)x
Gravel=x-(1/2)x-(1/5)x=(3/10)x=15
x=50
Then answer will be C=50
Answer: (C) 50
Question: The speed of a boat in upstream is 30 kmph and the speed of the boat downstream is 70 kmph. Find the speed of the boat in still water and the speed of the stream?
(A) 10 kmph
(B) 20 kmph
(C) 12 kmph
(D) 97 kmph
(E) 15 kmph
Rationale: Speed of the boat in still water
= (30+70)/2
= 50 kmph. Speed of the stream
= (70-30)/2
= 20 kmph.
Answer: B
Answer: (B) 20 kmph
Question: Between 1980 and 1990 a small town's population increased from 10000 to 12500. Between 1990 and 2000 its population increased from 12500 to 14500. By what percent did the rate of population growth decrease from the period 1980-1990 to the period 1990-2000?
(A) 20%
(B) 24%
(C) 28%
(D) 32%
(E) 36%
Rationale: Solution:
This is a percent decrease problem. We will use the formula: percent change = (new – old)/old x 100 to calculate the final answer.
We first set up the ratios of population growth to initial population for the two periods. The first ratio will be for the period 1980-1990, and the second ratio will be for the period 1990-2000. Because the populations are in hundreds, we do not have to express all the trailing zeros in our ratios.
1980-1990
growth/initial population = 2500/10000 = 1/4
1990-2000
growth/initial population = 2000/12500 = 4/25
Because each ratio is not an easy number to use, we can simplify each one by multiplying each by the LCM of the two denominators, which is 100. Keep in mind that we are able to do this only because our answer choices are expressed in percents.
1980-1990
growth/initial population = (1/4) x 100 = 25
1990-2000
growth/initial population = (4/25) x 100 = 16
We can plug 25 and 16 into our percent change formula:
(new – old)/old x 100
[(16 – 25)/25] x 100
-9/25 x 100
At this point we can stop and consider the answer choices. -9/25 x 100 is -36, so the decrease is by 36%.
Answer E.
Answer: (E) 36%
Question: Simplify: 244 x 301
(A) 73144
(B) 73143
(C) 73200
(D) 72956
(E) 73444
Rationale: 244 x 301 = 244 x (300 + 1)
= 73200 + 244
=73444
Answer is E
Answer: (E) 73444
Question: What is the ratio between perimeters of two squares one having 3 times the diagonal then the other?
(A) 3: 4
(B) 3: 9
(C) 3: 2
(D) 3: 1
(E) 3: 3
Rationale: d = 3d d = d
a√2 = 3d a√2 = d
a = 3d/√2 a = d/√2 => 3: 1
Answer: D
Answer: (D) 3: 1
Question: 14, 23, 32, 41, 50, 59, …
In the sequence above, each term is 9 more than the previous term. What is the 41st term Z of the sequence?
(A) 360
(B) 365
(C) 369
(D) 374
(E) 383
Rationale: First term , a= 14
Common difference , d = 9
nth term , tn = a + (n-1)d
41st term Z, t41 = a+ 40*d = 14 + 40*9 = 374
Answer D
Answer: (D) 374
Question: A set of football matches is to be organized in a "round-robin" fashion, i.e., every
participating team plays a match against every other team once and only once. If 3
matches are totally played, how many teams participated?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 3
Rationale: 2 ways to solve this problem..
summation(x)=n(n-1)/2
n(n-1)/2=3;
n^2-n-6=0
Ans : 3
ANSWER:E
Answer: (E) 3
Question: Evaluate: 45678 * 8*4*8 = ?
(A) 730848
(B) 705265
(C) 730846
(D) 730596
(E) 731848
Rationale: According to order of operations, 8?4?8 (division and multiplication) is done first from left to right
8/4 = 2* 8 = 16
Hence
45678 * 8*4*8 = 45678 * 16 = 730848
correct answer A
Answer: (A) 730848
Question: Twenty percent of the skiers that tried out for the ski patrol were selected. Of those that were not selected, 15 skiers were CPR certified and 25 were not. How many skiers tried out for the ski patrol?
(A) 40
(B) 50
(C) 60
(D) 70
(E) 80
Rationale: Not Selected = 80%
If total is x.
Then 0.8x=15+25=40
x=50
Hence answer is B.
Answer: (B) 50
Question: Raman mixed 24 kg of butter at Rs. 150 per kg with 36 kg butter at the rate of Rs. 125 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
(A) Rs.129
(B) Rs.198
(C) Rs.189
(D) Rs.128
(E) Rs.129
Rationale: CP per kg of mixture = [24(150) + 36(125)]/(24 + 36) = Rs. 135
SP = CP[(100 + profit%)/100]
= 135 * [(100 + 40)/100]
= Rs.189.
Answer:C
Answer: (C) Rs.189
Question: A part of certain sum of money is invested at 10% per annum and the rest at 16% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is?
(A) 8:5
(B) 4:9
(C) 4:3
(D) 4:1
(E) 4:2
Rationale: 16:10
= 8:5
Answer: A
Answer: (A) 8:5