mathewhe/aqua_rat huggingface dataset:
Question: A and B started a business investing Rs. 75,000 and Rs 20,000 respectively. In what ratio the profit earned after 2 years be divided between A and B respectively?
(A) 9:2
(B) 3:2
(C) 18:20
(D) 18:4
(E) 13:4
Rationale: A: B = 75000 : 20000
= 75 : 20
= 13 : 4
ANSWER:E
Answer: (E) 13:4
Question: A boatman can row 3 km against the stream in 30 minutes and return in 18 minutes. Find the rate of current ?
(A) 2 kmph
(B) 8/2 kmph
(C) 5/2 kmph
(D) 1/2 kmph
(E) 2/2 kmph
Rationale: Explanation:
Speed in upstream = Distance / Time = 3 x 60/30 = 6 km/hr.
Speed in downstream = 3 x 60/18 = 10 km/hr
Rate of current = (10-6)/2 = 2 km/hr.
Answer: A
Answer: (A) 2 kmph
Question: If a(a + 4) = 21 and b(b + 4) = 21, where a ≠ b, then a + b =
(A) −4
(B) −5
(C) 2
(D) 46
(E) 48
Rationale: i.e. if a = 3 then b = -7
or if a = -7 then b = 3
But in each case a+b = -7+3 = -4
Answer: option A
Answer: (A) −4
Question: Two representatives must be selected from each of two groups of students. One group consists of two men and one woman, and the other group consists of two women and one man. What is the probability that 2 men and 2 women will be selected ?
(A) 1/6
(B) 1/4
(C) 5/9
(D) 1/3
(E) 1/2
Rationale: Group 1: 2 Men and 1 Woman
Group 2: 1 Men and 2 Woman
Need: 2 Men and 2 women
Case 1: 2 Men from Group 1 and 2 women from group 2 - 2C2*2C2 = 1 ways
Case 2: 1 Men and 1 Woman from Group 1 and 1 Man and 1 women from group 2 - 2*1*1*2 = 4 ways
Total Favorable cases = 1+4 = 5
Total Possible ways of selecting students 2 from each group = 3C2*3C2 = 3*3 = 9
Probability = 5/9
Answer : Option C
Answer: (C) 5/9
Question: Two stations A and B are 110 km apart on a straight line. One train starts from A at 5 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
(A) 11
(B) 10
(C) 8
(D) 12
(E) 15
Rationale: Suppose they meet x hours after 5 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
Therefore 20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 8 a.m.
Answer: C
Answer: (C) 8
Question: At a company, the average wage of male employees is $4 per hour, and the average wage of female employees is $8 per hour. If the average wage of all employees is $7.5 per hour, what is the ratio of the number of male employees to the number of female employees?
(A) 1 to 7
(B) 2 to 3
(C) 3 to 2
(D) 5 to 3
(E) 2 to 1
Rationale: Average hourly wage of male employees = 4 $
Average hourly wage of female employees = 8 $
Average hourly wage of all employees = 7.5 $
Let number of male employees = m
number of female employees = f
7.5 = (4m + 8f ) / m+f
=>7.5m + 7.5f = 4m + 8f
=> 3.5m = .5f
=> m/f = .5/.15 = 1/7
Answer A
Answer: (A) 1 to 7
Question: A sum of Rs. 12500 amounts to Rs. 16500 in 4 years at the rate of simple interest. What is the rate of interest?
(A) 4%
(B) 5%
(C) 6%
(D) 8%
(E) 14%
Rationale: S.I. = (16500 - 12500) = Rs. 4000/-
Rate = (100 * 4000) / (12500 * 4) = 8%
ANSWER:D
Answer: (D) 8%
Question: what is the probability of getting 53 mondays in a leap year?
(A) 1/7
(B) 2/7
(C) 3/7
(D) 4/7
(E) 5/7
Rationale: in a leap year contains 52 monday's since 52 weeks are present and 2 days extra
it may be sunday and monday
2.monday and tuesday
3.tuesday and thursday
4.thursday and friday
similary 7 alternatives are possible .among this only 2 are possible cases so 2/7
ANSWER:B
Answer: (B) 2/7
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 18 kmph and 72 kmph. After how much time will the trains meet?
(A) 20/8 sec
(B) 20/4 sec
(C) 20/7 sec
(D) 4 sec
(E) 60/7 sec
Rationale: They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (18 + 72)*5/18 = 5*5 = 25 mps.
The time required = d/s = 100/25 = 4 sec.Answer:D
Answer: (D) 4 sec
Question: The volume of the largest right circular cone that can be cut out of a cube of edge 7 cm is :
(A) 89.8 cm³
(B) 92.5 cm³
(C) 132.8 cm³
(D) 144.5 cm³
(E) none
Rationale: Sol.
Volume of the block = (10 * 5 * 2) cm³.
Volume of the cone carved out = [1/3 * 22/7 * 3 * 3 * 7] cm³ = 66 cm³
∴ Wood wasted = (100 - 66)% = 34%.
Answer A
Answer: (A) 89.8 cm³
Question: A factory produces 6400 toys per week. If the workers at this factory work 3 days a week and if these workers make the same number of toys everyday, how many toys are produced each day?
(A) 1375 toys
(B) 2133 toys
(C) 3375 toys
(D) 4375 toys
(E) 5375 toys
Rationale: To find the number of toys produced every day, we divide the total number of toys produced in one week (of 3 days) by 3.
6400 / 3= 2133 toys
correct answer B
Answer: (B) 2133 toys
Question: There are three different hoses used to fill a pool: hose x, hose y, and hose W. Hose x can fill the pool in a days, hose y in b days, and hose W in c days, where a > b > c. When all three hoses are used together to fill a pool, it takes d days to fill the pool. Which of the following must be true?
I. d<c
II. d>b
III. c/3<d<a/3
(A) I
(B) III
(C) II&III
(D) II
(E) I&II
Rationale: Name T = full pool
X fills a pool in a days ==> 1 day X fills: T/a
Y fills a pool in b days ==> 1 day Y fills: T/b
W fills a pool in c days ==> 1 day W fills: T/c
1 day (X+Y+W) together fill: T(1/a + 1/b + 1/c)
d days (X+Y+W) together fill: T
==> d = Tx1 / T(1/a+1/b+1/c) = abc/(ab+bc+ca)
==>d = abc/(ab+bc+ca)
d cannot be greater than c ; d is greater than b ; d is greater than c/3 but not less than a/3
D
Answer: (D) II
Question: A basketball team composed of 12 players scored 100 points in a particular contest. If none of the individual players scored fewer than 7 points, what is the greatest number of points Q that an individual player might have scored?
(A) 7
(B) 13
(C) 16
(D) 21
(E) 23
Rationale: General rule for such kind of problems:
to maximize one quantity, minimize the others;
to minimize one quantity, maximize the others.
Thus to maximize the number of points of one particular player minimize the number of points of all other 11 players.
Minimum number of points for a player is 7, so the minimum number of points of 11 players is 7*11=77.
Therefore, the maximum number of points Q for 12th player is 100-77=23.
Answer: E.
Answer: (E) 23
Question: A family consists of two grandparents, two parents, and four grandchildren. The average age of the grandparents is 66 years, the average age of the parents is 40 years, and the average age of the grandchildren is 9 years. What is the average age (in years) of the family?
(A) 27
(B) 29
(C) 31
(D) 33
(E) 35
Rationale: Total age of the grandparents = 66 Ã— 2 = 132
Total age of the parents = 40 Ã— 2 = 80
Total age of the grandchildren = 9 Ã— 4 = 36
Average age of the family = (132+80+36)/8 = 248/8 = 31 years
The answer is C.
Answer: (C) 31
Question: The amount of principal Rs.8000 at compound interest at the ratio of 5% p.a. for 2 years is
(A) s.9621
(B) s.6921
(C) s.8820
(D) s.6261
(E) s.6361
Rationale: c.i=p(1+r/100)^n
=8000(1+5/100)^2
=Rs8820
ANSWER:C
Answer: (C) s.8820
Question: A baseball game is played at Wickley Field. The Blues vs. The Grays. 25% of all players hit a home-run (hit the ball out of the park). Some players on The Grays team were injured, so they didn't play. If the ratio of players of the teams is 5:4, respectively, and the percentage of players who hit a home-run for The Blues is 15%, what percentage of players for The Grays hit a home-run?
(A) 40%
(B) 45%
(C) 35%
(D) 45.5%
(E) 35.5%
Rationale: Let B and G be number players Blues and Grays, respectively, and h represent hit a home-run.
B + G = total players.
B:G = 5:4
Bh/B = 15%
Gh/G = ?
[(5)(Bh/B) + (4)(Gh/G)]/(5 + 4) = 25%
[(5)(15%) + (4)(Gh/G)]/9 = 25%
Gh/G = 45%
Answer: B
Answer: (B) 45%
Question: John can eat a quarter of a pizza in one minute. How long does it take John to eat one pizza and a half?
(A) 1 min
(B) 3 min
(C) 7 min
(D) 6 min
(E) 9 min
Rationale: The above problem could also be solved by dividing the mixed number 1 and 1/2 by 1/4
1 (1/2) * 1 / 4 = 3 / 2 * 4 / 1 = 6 minutes.
correct answer D
Answer: (D) 6 min
Question: If 5% more is gained by selling an article for Rs. 360 than by selling it for Rs. 340, the cost of the article is
(A) 289
(B) 400
(C) 200
(D) 288
(E) 111
Rationale: Explanation:
Let C.P. be Rs. x.
Then, 5% of x = 360 - 340 = 20
x/20 = 20 => x = 400
Answer: B
Answer: (B) 400
Question: At golds gym class can be divided into 8 teams with an equal number of players on each team or into 12 teams with an equal number of players on each team. What is the lowest possible number of students in the class?
(A)  20
(B)  24
(C)  36
(D)  48
(E)  96
Rationale: We are given that golds gym class can be divided into 8 teams or 12 teams, with an equal number of players on each team. Translating this into two mathematical expressions we can say, where G is the total number of students in the gym class, that:
G/8 = integer and G/12 = integer
This means that G is a multiple of both 8 and 12.
We are asked to determine the lowest number of students in the class, or the lowest value for variable “G”. Because we know that G is a multiple of 8 and of 12, we need to find the least common multiple of 8 and 12. Although there are technical ways for determining the least common multiple, the easiest method is to analyze the multiples of 8 and 12 until we find one in common.
Starting with 8, we have: 8, 16, 24, 32
For 12, we have: 12, 24
For the multiples of 12, we stopped at 24, because we see that 24 is also a multiple of 8. Thus, 24 is the least common multiple of 8 and 12, and therefore we know that the lowest possible number of students in the gym class is 24.
Answer B.
Answer: (B)  24
Question: Reena and Shaloo are partners in a business. Reena invests Rs. 35,000 for 8 months and Shaloo invests Rs. 42,000 for 10 months. Out of a profit of Rs. 31,570, Reena's share is :
(A) Rs. 9471
(B) Rs. 12,628
(C) Rs. 18,040
(D) Rs. 18,942
(E) Rs. 18,000
Rationale: Explanation:
Ratio of their shares = (35000 * 8) : (42000 * 10) = 2 : 3.
Reena's share = Rs.
(31570âˆ—2/5)
= Rs. 12628.
ANSWER IS B
Answer: (B) Rs. 12,628
Question: What will be the LCM of 8, 24, 36 and 54
(A) 54
(B) 108
(C) 216
(D) 432
(E) None of these
Rationale: Explanation:
LCM of 8-24-36-54 will be
2*2*2*3*3*3 = 216
Answer: Option C
Answer: (C) 216
Question: 6x − 24 = 6y
5y + 5x = 15
Which of the following is the number of solutions to the system of equations shown above?
(A) Exactly one
(B) Exactly three
(C) Exactly two
(D) More than three
(E) None
Rationale: 6x − 24 = 6y
=> 6x - 6y = 24
=> x- y =4 -- 1
5y + 5x = 15
=>x + y = 3 -- 2
From equation 1 and 2 , we get
2x = 7
=> x=3.5
y=.5
Therefore , the given system will have Exactly one solution
Answer : A
Answer: (A) Exactly one
Question: Each of 435 bags contains at least one of the following three items: coconut, almonds, and peanuts. The number of bags that contain only raisins is 10 times the number of bags that contain only peanuts. The number of bags that contain only almonds is 20 times the number of bags that contain only coconut and peanuts. The number of bags that contain only peanuts is one-fifth the number of bags that contain only almonds. 210 bags contain almonds. How many bags contain only one kind of item?
(A) 256
(B) 260
(C) 316
(D) 320
(E) 350
Rationale: Fill the diagram step by step:
coconut, almonds, and peanuts.PNGAlso given that there are total of 435 bags and 210 bags contain almonds.
From the diagram 20y=5x --> y=x/4. Now, Total=435={Almonds}+10x+y+x --> 435=210+10x+x/4+x --> x=20 --> # of bags that contain only one kind of item is the sum of yellow segments: 10x+x+5x=16x=320.
Answer: D.
Answer: (D) 320
Question: A train running at the speed of 70 km/hr crosses a pole in 9 sec. What is the length of the train?
(A) 227 m
(B) 150 m
(C) 167 m
(D) 175 m
(E) 187 m
Rationale: Speed = 70 * 5/18 = 175/9 m/sec
Length of the train = speed * time = 175/9 * 9
= 175 m
Answer: D
Answer: (D) 175 m
Question: A train 108 m long is moving at a speed of 50 km/hr . It crosses a train 112 m long coming from opposite direction in 6 seconds. What is the speed of the second train?
(A) 82 kmph
(B) 76 kmph
(C) 44 kmph
(D) 58 kmph
(E) 56 kmph
Rationale: Explanation:
Total distance = 108+112 = 220 m
Time = 6s
Relative speed = distance/time = 220/6 m/s = 110/3 m/s
= (110/3) × (18/5) km/hr = 132 km/hr
=> 50 + speed of second train = 132 km/hr
=> Speed of second train = 132-50 = 82 km/hr
Answer: Option A
Answer: (A) 82 kmph
Question: The average of 35 students in a class is 15 years. The average age of 25 students is 13. What is the average age of remaining 10 students?
(A) 17 years
(B) 18 years
(C) 19 years
(D) 20 years
(E) 21 years
Rationale: Sum of the ages of 14 students
= (15 * 35) - (13 * 25) = 525 - 325 = 200
Required average = (200/10) = 20 years.
Answer:D
Answer: (D) 20 years
Question: A train 400 m long can cross an electric pole in 40 sec and then find the speed of the train?
(A) 36 Kmph
(B) 40 Kmph
(C) 42 Kmph
(D) 45 Kmph
(E) 38 Kmph
Rationale: Length = Speed * time
Speed = L/T
S = 400/40
S = 10 M/Sec
Speed= 10*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 36 Kmph
ANSWER:A
Answer: (A) 36 Kmph
Question: A person crosses a 600 meter long street in 5 minutes. What is the speed in Km/hr
(A) 6.2 km/hr
(B) 7.2 km/hr
(C) 8.2 km/hr
(D) 9.2 km/hr
(E) None of these
Rationale: ExplanaƟon:
Two things to give aƩenƟon on this quesƟon.
First Ɵme is in minutes, we need to change it to seconds to get speed in m/sec, then we need to get the
final answer in km/hr.
So lets solve this.
Speed=DistanceTimeDistance=650meterTime=5
minutes=300secSpeed=600300=2m/sec=>2
∗
185km/hr=7.2km/hr
Answer:B
Answer: (B) 7.2 km/hr
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
(A) 11 years
(B) 10 years
(C) 18 years
(D) 189 years
(E) 28 years
Rationale: Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B's age = 2x = 10 years.
Answer: B
Answer: (B) 10 years
Question: Two persons start running simultaneously around a circular track of length 440 m from the same point at speeds of 14 kmph and 24 kmph. When will they meet for the first time any where on the track if they
are moving in the opposite direction ?
(A) 144
(B) 36
(C) 124
(D) 42
(E) 38
Rationale: Time taken to meet the first time = length of track/relative speed
= 440/ (14 +24) (5/18)
= 400/38 *(18/5) = 42 sec.
Answer : D
Answer: (D) 42
Question: Pipe A can fill a tank in 10 hours, pipe B in 5 hours and pipe C in 5 hours. If all the pipes are open, in how many hours will the tank be filled?
(A) 2 hours
(B) 3 hours
(C) 4 hours
(D) 5 hours
(E) 6 hours
Rationale: Part filled by A + B + C in 1 hour = 1/10 + 1/5 + 1/5= 1/2
All the three pipes together will fill the tank in 2 hours.
Answer:A
Answer: (A) 2 hours
Question: In a hockey team of 11 members, the captain's age is 26 years old and the goalkeeper is 3 years older If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
(A) 23 years
(B) 24 years
(C) 25 years
(D) 27 years
(E) 29 years
Rationale: Explanation :
Let the average age of the whole team be x years.
11x - (26 + 29) = 9(x - 1)
11x - 9x = 46
2x = 46
x = 23
So, average age of the team is 23 years.
Answer : A
Answer: (A) 23 years
Question: Let y = 2m + x^2 and m = 5x + 3. If m^2 =64, then which of the following can be a value of 2y + 3m?
(A) 68
(B) 58
(C) 78
(D) 88
(E) 98
Rationale: m^2 = 64 => m=8
8= 5x+3 => x=1
y= 2*8+1^2 = 17
2y+3m = 2*17+3*8 = 58
Answer : B
Answer: (B) 58
Question: Pat's watch gains an extra 10 seconds every 4 hours. Kim's watch loses 5 seconds every 4 hours. If both watches are set to correct time at 8 o'clock in the morning and run without interruption, after 24 hours, what will be the difference in time between Pat's watch and Kim's watch?
(A)  5 min 30 sec
(B)  4 min 30 sec
(C)  3 min 30 sec
(D)  2 min 30 sec
(E)  1 min 30 sec
Rationale: In 24 hours Pat's watch will gain an extra 24/4*10 = 60 seconds.
In 24 hours Kim's watch will lose 24/4*5 = 30 seconds.
Hence the difference will be 60 + 30 = 90 seconds.
Answer: E.
Answer: (E)  1 min 30 sec
Question: Four packages have an average weight of 12.5 pounds. What is the minimum possible weight of the heaviest package in pounds if the median is 10 pounds?
(A) 20
(B) 19
(C) 18
(D) 17
(E) 16
Rationale: Let us denote the weights of the packages in pounds by a, b, c, d naming from the lightest one to the heaviest one. The median is 10 pounds. Therefore (b + c) / 2 = 10.
b + c = 20
The average is 12.5 pounds. Therefore (a + b + c + d) / 4 = 12.5.
a + (b + c) + d = 50
a + 20 + d = 50
a + d = 30
The weight a must be no greater than 10, since 10 is the median. Therefore the minimum possible weight of the heaviest package is 30 – 10 = 20 pounds (all the other packages would weigh 10 pounds in this case).
Answer: A
Answer: (A) 20
Question: If xerox paper costs 5 cents a sheet and a buyer gets 10% discount on all xerox paper one buys after the first 2000 papers and 20% discount after first 10000 papers, how much will it cost to buy 20000 sheets of xerox paper?
(A) $1250
(B) $1060
(C) $1350
(D) $900
(E) $1000
Rationale: 30 sec approach - solve it using approximation
20000 sheet at full price, 5 cent = 1000
20000 sheet at max discount price, 4 cent = 800
Your ans got to be between these two.
Ans D it is.
Answer: (D) $900
Question: A is thrice as good as B in work. A is able to finish a job in 60 days less than B. They can finish the work in - days if they work together.
(A) 5 6/2
(B) 3/15
(C) 8/7
(D) 22 1/2
(E) 1/9
Rationale: Explanation :
If A completes a work in 1 day, B completes the same work in 3 days
Hence, if the difference is 2 days, B can complete the work in 3 days
=> if the difference is 60 days, B can complete the work in 90 days
=> Amount of work B can do in 1 day= 1/90
Amount of work A can do in 1 day = 3 × (1/90) = 1/30
Amount of work A and B can together do in 1 day = 1/90 + 1/30 = 4/90 = 2/45
=> A and B together can do the work in 45/2 days = 22 ½ days
ANSWER:D
Answer: (D) 22 1/2
Question: The sum of first 45 natural numbers is
(A) 1035
(B) 1280
(C) 2070
(D) 2140
(E) None
Rationale: Solution
We know that(1+2+3+.....+45)	= n(n+1)/2
Therefore (1+2+3+....+45)	=(45×46 / 2)
= 1035.
Answer A
Answer: (A) 1035
Question: The ratio of the length and the width of a rectangle is 4 : 3 and the area of the rectangle is 5292 sq cm. What is the ratio of the width and the area of the rectangle?
(A) 1:72
(B) 1:76
(C) 1:80
(D) 1:84
(E) 1:88
Rationale: Let the length and the width be 4x and 3x respectively.
Area = (4x)(3x) = 5292
12x^2 = 5292
x^2 = 441
x = 21
The ratio of the width and the area is 3x : 12x^2 = 1 : 4x = 1 : 84
The answer is D.
Answer: (D) 1:84
Question: SI on a certain sum of money for 3 yrs at 8 percent /annum is 1/2 the CI on Rs.4000 for 2 yrs at 10 percent/ annum. The sum placed on SI is?
(A) Rs. 1700
(B) Rs. 1720
(C) Rs. 1750
(D) Rs. 1850
(E) Rs. 2000
Rationale: C.I.
= Rs. 4000 x 1 + 10 2 - 4000
100
= Rs. 4000 x 11 x 11 - 4000
10 10
= Rs. 840.
Sum = Rs. 420 x 100 = Rs. 1750.
3 x 8
C
Answer: (C) Rs. 1750
Question: P is 30% more efficient than Q. P can complete a work in 23 days. If P and Q work together, how much time will it take to complete the same work?
(A) 9
(B) 11
(C) 13
(D) 15
(E) 17
Rationale: Explanation :
Work done by P in 1 day = 1/23
Let work done by Q in 1 day = q
q × (130/100) = 1/23
=> q = 100/(23×130) = 10/(23×13)
Work done by P and Q in 1 day = 1/23 + 10/(23×13) = 23/(23×13)= 1/13
=> P and Q together can do the work in 13 days
Answer : Option C
Answer: (C) 13
Question: (4300531)-?=2535618
(A) 1865113
(B) 1775123
(C) 1764913
(D) 1675123
(E) None of them
Rationale: Let 4300531-x=2535618
then x=4300531-2535618
=1764913
Answer is C
Answer: (C) 1764913
Question: A shopkeeper purchased an article at 20% discount on list price, he marked up his article in such a way that after selling the article at 20% discount, he gained 20% on SP. what % is SP of the list price?
(A) 94
(B) 95
(C) 96
(D) 97
(E) 98
Rationale: Let L.P = 100 ==> C.P = 80. He gains 20% on S.P ==> S.P = 96.
ANSWER:C
Answer: (C) 96
Question: A shipment of 1500 heads of cabbage, each of which was approximately the same size, was purchased for $600. The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head. The following day the rest were sold at a price equal to 15% less than the price each head sold for on the day before. What was the total gross profit on this shipment.
(A) $100
(B) b $115
(C) c $125.5
(D) d $130
(E) e $112.5
Rationale: Purchase cost = 600/1500= $ 0.4
25% above the cost per head = (125/100)*0.4= $ 0.5
2/3 of the heads were sold means 2/3*1500 =1000 ,Selling amount for 1000 cabbage = 1000 * 0.5 = $ 500
Remaining were sold at a price equal to 10% less than the price each head sold for on the day before i.e , (85/100)*0.5 = $ 0.425
Hence selling cost for the remaining cabbage = 500 * 0.45 = $ 212.5
Total selling cost = 500 + 212.5 = $ 712.5
Gross profit = $ 712.5 - $ 600 = $ 112.5
Hence Answer is E
Answer: (E) e $112.5
Question: What sum of money put at C.I amounts in 2 years to Rs.8820 and in 3 years to Rs.9261?
(A) 8000
(B) 2881
(C) 2664
(D) 2667
(E) 2121
Rationale: 8820 ---- 441
100 ---- ? => 5%
x *105/100 * 105/100 = 8820
x*1.1025=8820
x=8820/1.1025 => 8000.Answer: A
Answer: (A) 8000
Question: P works twice as fast as Q. If Q alone can complete a work in 12 days, P and Q can finish the work in --- days
(A) 5
(B) 1
(C) 2
(D) 3
(E) 4
Rationale: Work done by Q in 1 day = 1/12
Work done by P in 1 day = 2 × (1/12) = 1/6
Work done by P and Q in 1 day = 1/12 + 1/6 = ¼
=> P and Q can finish the work in 4 days
Answer is E.
Answer: (E) 4
Question: The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 42 degrees. Find the temperature on Friday?
(A) 34
(B) 55
(C) 66
(D) 81
(E) 21
Rationale: M + Tu + W + Th = 4 * 48 = 192
Tu + W + Th + F = 4 * 46 = 184
M = 42
Tu + W + Th = 192 -42 = 150
F = 184 – 150 = 34.Answer: A
Answer: (A) 34
Question: Eight identical machines can produce 360 aluminum cans per hour. If all of the machines work at the same constant rate, how many cans could 5 such machines produce in 7 hours?
(A) 675
(B) 750
(C) 1,800
(D) 5,900
(E) 1,575
Rationale: 8 machines/ 360 cans = 5 machines/ x cans
8x= 1800
x=225
(225)(7 hours)= 1575 cans. The answer is E.
Answer: (E) 1,575
Question: Sound is said to travel in air at about 1100 feet per second. A man hears the axe striking the tree, 11/5 seconds after he sees it strike the tree. How far is the man from the wood chopper ?
(A) 2420 ft
(B) 2524 ft
(C) 2600 ft
(D) 2740 ft
(E) None of these
Rationale: Explanation :
Distance = [1100 * 11/5] feet
= 2420 feet.
Answer : A
Answer: (A) 2420 ft
Question: Line P has a positive slope and a positive y-intercept. Line Q also has a positive slope and a positive y-intercept. The two slopes and the two y-intercepts are four different numbers, none equal. Lines P & Q have a single intersection point — what is the full set of possible quadrants in which the intersection point could be?
(A) I only
(B) I & III only
(C) I & II only
(D) I & II & III onl
(E) all four quadrants possible
Rationale: If you forget quadrants, take a look at this post. This is a tricky one, because you have to be careful to think about all cases. The first important point to realize is: any line with both a positive slope and a positive y-intercept goes through quadrants I & II & III, but never quadrant IV. Neither of these lines is ever in Quadrant IV, so they can’t intersect there. As it turns out, for different values of the slope, they can intersect in any of the other three quadrants.
Therefore, the answer = (D)
Answer: (D) I & II & III onl
Question: A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 35%?
(A) 600
(B) 887
(C) 256
(D) 654
(E) 675
Rationale: Cost price = Rs.500
profit = 35% of 500 = Rs.175
Selling price = Cost price + Profit
= 500 + 175 = 675
Answer: E
Answer: (E) 675