mathewhe/aqua_rat huggingface dataset:
Question: Four car rental agencies A, B, C and D rented a plot for parking their cars during the night. A parked 15 cars for 12 days, B parked 12 cars for 20 days, C parked 18 cars for 18 days and D parked 16 cars for 15 days. If A paid Rs. 1170 as rent for parking his cars, what is the total rent paid by all the four agencies?
(A) 2388
(B) 2778
(C) 1279
(D) 6150
(E) 6396
Rationale: The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15
= 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60
Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.
The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k
It is given that A paid Rs. 1170
45k = 1170 => k = 26
246k = 246(26) = Rs. 6396
Thus the total rent paid by all the four agencies is Rs. 6396.
Answer: E
Answer: (E) 6396
Question: A total of 502 players participated in a single tennis knock out tournament. What is the total number of matches played in the tournament? (Knockout means if a player loses, he is out of the tournament). No match ends in a tie.
(A) 501
(B) 512
(C) 256
(D) 255
(E) 1023
Rationale: There are 502 players, only 1 person wins, 501 players lose. in order to lose, you must have lost a game.
501 games.
ANs- A
Answer: (A) 501
Question: In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
(A) 20
(B) 70
(C) 77
(D) 26
(E) 12
Rationale: Let C.P. = Rs. 100. Then, profit = Rs. 320, S.P. = Rs. 420
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 420
Profit = 420 - 125 = Rs. 295
Required percentage = 295/420 * 100 = 1475/21 = 70%
Answer:B
Answer: (B) 70
Question: Out of three consecutive odd numbers fifteen times the first number is equal to addition of thrice the third number and adding 15 to six times the second . What is the first number?
(A) 11/3
(B) 12/5
(C) 13/6
(D) 13/2
(E) 18/13
Rationale: Description :
=> 15x=6(x+2)+15+3(x+4)
=> 15x=9x+39
=>6x = 39
X=13/2
Answer D
Answer: (D) 13/2
Question: Difference between the length &breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is?? We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103?
(A) 2300 m^2
(B) 2350 m^2
(C) 2520 m^2
(D) 2620 m^2
(E) 2780 m^2
Rationale: Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) m2 = 2520 m^2
C
Answer: (C) 2520 m^2
Question: The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be
(A) 15 years
(B) 18 years
(C) 20 years
(D) 22 years
(E) 24 years
Rationale: Explanation:
Clue : (60 - x) - 6 = 5(x - 6)
Option C
Answer: (C) 20 years
Question: Four car rental agencies A, B, C and D rented a plot for parking their cars during the night. A parked 15 cars for 12 days, B parked 12 cars for 20 days, C parked 18 cars for 18 days and D parked 16 cars for 15 days. If A paid Rs. 1125 as rent for parking his cars, what is the total rent paid by all the four agencies?
(A) Rs.6119
(B) Rs.6129
(C) Rs.6115
(D) Rs.6150
(E) Rs.6118
Rationale: The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15
= 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60
Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.
The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k
It is given that A paid Rs. 1125
45k = 1125 => k = 25
246k = 246(25) = Rs. 6150
Thus the total rent paid by all the four agencies is Rs.6150.
Answer: D
Answer: (D) Rs.6150
Question: 33 1/3% OF 210?
(A) 70
(B) 90
(C) 110
(D) 120
(E) 130
Rationale: 33 1/3 % = 1/3
1/3 × 210 = 70
A)
Answer: (A) 70
Question: A 4% stock yield 5%. The market value of the stock is ?
(A) Rs. 125
(B) Rs. 80
(C) Rs. 99
(D) Rs. 109
(E) Rs. 101
Rationale: For an income of Rs. 5, investment = Rs. 100
For an income of Rs. 4, investment = Rs. (100/5) x 4 = Rs. 80
Answer : B
Answer: (B) Rs. 80
Question: The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 13 runs. Find his average in all the 30 matches?
(A) 31
(B) 86
(C) 82
(D) 15
(E) 10
Rationale: Total score of the batsman in 20 matches = 800.
Total score of the batsman in the next 10 matches = 130.
Total score of the batsman in the 30 matches = 930.
Average score of the batsman = 930/30 =31.
Answer:A
Answer: (A) 31
Question: A used-book dealer sells paperback books at 3 times dealer's cost and hardback books at 4 times the dealer's cost. Last week, the dealer sold a total of 180 books, each of which had cost the dealer $1. If the gross profit (sales revenue minus the dealer's cost) on the sale of all of these books was $400, how many of the books sold were paperbacks?
(A) 100
(B) 110
(C) 120
(D) 130
(E) 140
Rationale: The dealer earns a profit of $2 per paperback and $3 per hardback.
If all 180 books were paperbacks, the dealer would earn a profit of $360.
Since the actual profit was $400, the dealer must have sold 40 hardbacks.
Then the number of paperbacks sold was 180-40 = 140.
The answer is E.
Answer: (E) 140
Question: Raman mixed 24 kg of butter at Rs. 150 per kg with 36 kg butter at the rate of Rs. 125 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
(A) 129
(B) 128
(C) 189
(D) 187
(E) 112
Rationale: CP per kg of mixture = [24(150) + 36(125)]/(24 + 36) = Rs. 135
SP = CP[(100 + profit%)/100]
= 135 * [(100 + 40)/100] = Rs. 189.
Answer: C
Answer: (C) 189
Question: In a two-digit, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is:
(A) 24
(B) 26
(C) 42
(D) 46
(E) None of these
Rationale: Let the ten's digit be x.
Then, unit's digit = x + 2.
Number = 10x + (x + 2) = 11x + 2.
Sum of digits = x + (x + 2) = 2x + 2.
(11x + 2)(2x + 2) = 144
22x2 + 26x - 140 = 0
11x2 + 13x - 70 = 0
(x - 2)(11x + 35) = 0
x = 2.
Hence, required number = 11x + 2 = 24.
ANSWER : A
Answer: (A) 24
Question: In the arithmetic sequence t1, t2, t3, ..., tn, t1=23 and tn= tn-1 - 3 for each n > 1. What is the value of n when tn = -1?
(A) -1
(B) 9
(C) 10
(D) 14
(E) 20
Rationale: We know that t1 = 23
So, using the given formula we have:
t1=(t1-1) -3 =23
t0 - 3 = 23
t0= 26
The same way we find that t2= 20
It seems that the sequence goes like this:
t0 = 26
t1 = 23
t2 = 20
t3 = 17
t4 = 14
t5 = 11
t6 = 8
t7 = 5
t8 = 2
t9 = -1
So, ourANS is B.
Answer: (B) 9
Question: Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.441 in 2 years?
(A) Rs.900
(B) Rs.800
(C) Rs.500
(D) Rs. 400
(E) Rs.200
Rationale: Explanation:
441 = P(21/20)2
P =Rs.400
Answer:D
Answer: (D) Rs. 400
Question: When a random experiment is conducted, the probability that event A occurs is 1/5. If the random experiment is conducted 4 independent times, what is the probability that event A occurs exactly twice?
(A) 16/625
(B) 56/625
(C) 96/625
(D) 126/625
(E) 156/625
Rationale: One case is: 1/5*1/5*4/5*4/5=16/625
The total number of possible cases is 4C2 = 6
P(event A occurs exactly twice) = 6*(16/625) = 96/625
The answer is C.
Answer: (C) 96/625
Question: The events A and B are independent, the probability that event A occurs is greater than 0, and the probability that event A occurs is twice the probability that event B occurs. The probability that at least one of events A and B occurs is 14 times the probability that both events A and B occur. What is the probability that event A occurs?
(A) 77/2
(B) 1/7
(C) 78/85
(D) 1/5
(E) 47/85
Rationale: Let us say probability of A occuring is a.
Let us say probability of B occuring is b.
a = 2b
Probability (either A or B or both) =14 times Probability (A and B)
a*(1-b) + b*(1-a) + ab = 14*ab
Substituting a=2b in the second equation:
2b*(1-b) + b*(1-2b) + 2b*b = 14*2b*b
3b-2b^2 = 28b^2
3b = 30b^2
b = 3/30 = 1/10
So, a = 2b = 1/5
THE CORRECT ANSWER IS D.
Answer: (D) 1/5
Question: A train travelled from point A to point B at 160 Km/h. On its way back the train travelled at 120 Km/h and therefore the trip back lasted one hour longer. What is the distance (in Km) between A and B?
(A) 480.
(B) 500.
(C) 510.
(D) 600.
(E) 800.
Rationale: distance=speed*time
d1=s1t1
d2=s2t2
The distance from point A to point B is the same for each trip so,
d1=d2 and
t2=t1+1
thus,
s1t1=s2(t1+1)
160t1=120(t1+1)
t1=3
160*3=480
Answer: A
Answer: (A) 480.
Question: In how many ways 6 boys and 6 girls can be seated in a row so that boys and girls are alternate?
(A) 1063800
(B) 1083600
(C) 1036800
(D) 1053800
(E) 1073600
Rationale: number of ways = 2*6!*6! = 1036800
Answer is C
Answer: (C) 1036800
Question: The cost price of 17 articles is equal to the selling price of 11 articles. Find the profit percent?
(A) 18 2/15
(B) 36 2/11
(C) 45 2/14
(D) 54 6/11
(E) 18 2/12
Rationale: 17 CP = 11 SP
11 --- 2 CP
100 --- ? =>54 6/11%.Answer: D
Answer: (D) 54 6/11
Question: A part of certain sum of money is invested at 9% per annum and the rest at 12% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is?
(A) 4:7
(B) 4:0
(C) 4:3
(D) 4:1
(E) 4:2
Rationale: 12:9
= 4:3
Answer: C
Answer: (C) 4:3
Question: Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 5625 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.
(A) 2304
(B) 2305
(C) 2309
(D) 2310
(E) 2311
Rationale: Trees increase by 1/4 the number of trees in preceding year. Hence, correct answer must be divisible by 4. Based on divisibility rules, if last 2 digits are divisible by 4 then the number is divisible by 4. Thus, we can eliminate B, C,D,E The answer to be A
Again, trees increase by 1/4 the number of trees in preceding year. Hence, the number of trees increase by 5/4 times the number of trees the preceding year.
If x = initial number of trees = 2304
Year 1 = 5/4x
Year 2 = (5/4)(5/4)x
Year 3 = (5/4)(5/4)(5/4)x
Year 4 = (5/4)(5/4)(5/4)(5/4)x
Only for Answer D: (5/4)(5/4)(5/4)(5/4)2304 = 5625
Hence, correct answer = A
Answer: (A) 2304
Question: A number exceeds by 35 from its 3/8 part. Then the number is?
(A) A)56
(B) B)35
(C) C)39
(D) D)40
(E) E)45
Rationale: x – 3/8 x = 35
x = 56
ANSWER:A
Answer: (A) A)56
Question: A shopkeeper sells 10% of his stock at 20% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock?
(A) 20000
(B) 16000
(C) 18000
(D) 17000
(E) 15000
Rationale: Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/10 * x * 6/5 = 6x/50
The SP of 80% of the stock = 9/10* x * 0.95 = 171x/200
Total SP = 24x/200+171/200= 49x/50
Overall loss = x - 195/20050 = 5x/200
5x/200 = 400 => x = 16000
Answer:B
Answer: (B) 16000
Question: Find the ratio of speed of truck to train if truck covers 550m in 1 minute and train covers 33 km in 45 min.
(A) 3:9
(B) 8
(C) 3:2
(D) 3:4
(E) 3:1
Rationale: Explanation:
Using the formula, speed=distance/time
Speed of truck = 550/60 m/s
Speed of train= 33000/(45*60) m/s
Ratio of speed of truck to train= (550/60 ) / [33000/(45*60)]
=3:4
Hence, the ratio is 3:4
ANSWER: D
Answer: (D) 3:4
Question: If a quality control check is made inspecting a sample of 2 light bulbs from a box of 12 lighbulbs, how many different samples can be chosen?
(A) 6
(B) 24
(C) 36
(D) 66
(E) 72
Rationale: Try using the formula for combinations:
n!/r!(n-r)!
12!/2!(12-2)!
12!/2!*10!
12*11/2*1
=66
ANSWER:D
Answer: (D) 66
Question: The population of a city increases by 5% per year but due to migration it decrease by 1% per years. What will be the percentage increase in population in 3 years?
(A) 9%
(B) 9.27%
(C) 27%
(D) 12.48%
(E) None of these
Rationale: Actual increase in population=4%
Let, earlier population=100 then the population after 3 years
=100(1+4/100)^3=112.4864
∴Required percentage=12.48%
ANSWER:D
Answer: (D) 12.48%
Question: A wheel that has 12 cogs is meshed with a larger wheel of 21 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions made by the larger wheel is:
(A) 12
(B) 10
(C) 6
(D) 8
(E) 7
Rationale: Explanation :
Let the required number of revolutions made by larger wheel be x.
Then, More cogs, Less revolutions (Indirect Proportion)
21:12::21:x => 21 * x = 21 * 12
=> x = (21 * 12)/21
=> x = 12
Answer : A
Answer: (A) 12
Question: A started a business with an investment of Rs. 70000 and after 6 months B joined him investing Rs. 120000. If the profit at the end of a year is Rs. 39000, then the share of B is?
(A) A)34500
(B) B)24000
(C) C)24098
(D) D)19007
(E) E)18000
Rationale: Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6
Total profit = Rs. 39000
Share of B = 6/13 (39000)
= Rs. 18000
Answer:E
Answer: (E) E)18000
Question: Anand and Deepak started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Deepak's share is:
(A) Rs. 5400
(B) Rs. 7200
(C) Rs. 8400
(D) Rs. 9600
(E) Rs. 8600
Rationale: Ratio of their shares = 22500 : 35000 = 9:14
Deepak's share = 13800 * 14/23 = Rs. 8400.
ANSWER:C
Answer: (C) Rs. 8400
Question: A student took 6 courses last year and received an average (arithmetic mean) grade of 100 points. The year before, the student took 5 courses and received an average grade of 70 points. To the nearest tenth of a point, what was the student’s average grade for the entire two-year period?
(A) 79
(B) 89
(C) 95
(D) 86.36
(E) 97.2
Rationale: Let the 6 courses that were taken last year be A1 , A2, A3 , A4 , A5 , A6
A1+A2+A3+A4+A5+A6 = 100*6 = 600
The year before , the 5 courses be B1, B2 , B3 , B4 , B5
B1+B2+B3+B4+B5 = 70*5 = 350
Student's average = (600+350)/11 = 86.36
Answer D
Answer: (D) 86.36
Question: A man said to his son, "I was two-third of your present age when you were born". If the present age of the man is 48 years, find the present age of the son?
(A) 28.9
(B) 28.0
(C) 28.4
(D) 28.8
(E) 28.1
Rationale: Present age of the son be P, he was born P years ago.
The age of the man was: (48 - P).
His age when the son was born should be equal to 2/3 of P.
(48 - P) = 2/3 P
5P = 144 => P = 28.8
Answer: D
Answer: (D) 28.8
Question: Insert the missing number
17, 7, 24, 19, 9, 28, ..., 8, 31
(A) 20
(B) 21
(C) 18
(D) 23
(E) 25
Rationale: 17+7=24
19+9=28
x+8=31
therefore x=23
ANSWER:D
Answer: (D) 23
Question: In what ratio should a variety of rice costing Rs. 6 per kg be mixed with another variety of rice costing Rs. 8.75 per kg to obtain a mixture costing Rs. 7.50 per kg?
(A) 5/6
(B) 5/9
(C) 5/2
(D) 5/1
(E) 5/8
Rationale: Explanation:
Let us say the ratio of the quantities of cheaper and dearer varieties = x : y
By the rule of allegation, x/y = (87.5 - 7.50) / (7.50 - 6) = 5/6
Answer: A
Answer: (A) 5/6
Question: What is the remainder of Q= 3^19 when divided by 10?
(A) 0
(B) 1
(C) 5
(D) 7
(E) 9
Rationale: I looked for patterns:
^2 - units digit 9
^3 - units digit 7
^4 - units digit 1
^5 - units digit 3
hence, we can see that when raised to a power which is multiple of 4, the units digit is 1, and when to an even power not multiple of 4, the units digit is 9
and we can then see:
^16 - units digit 1, or
^18 - units digit 9
and ^19 - units digit 7
therefore, Q=when divided by 10, the remainder must be 7.D
Answer: (D) 7
Question: If Samson's home is 100 meters to his workplace and he trek's to work everyday, which of the following could be true?
I. Samson treks at least a distance of 200 meters everyday.
II. In 3 days, Samson would have covered a distance of 600 meters.
III. Daniel's work place is less than 100 meters from Samson's home.
(A)  I only
(B)  I and II only
(C)  I and III only
(D)  II and III only
(E)  I, II and III
Rationale: Let's Check each Statement.
Statement I: Samson treks at least a distance of 200 meters everyday. He treks 100 meters to work and 100 meters back to work. 100meters + 100 meters = 200 meters, in which case Statement I is True.
Statement II: In 3 days, Samson would have covered a distance of 600 meters. Each day he treks 200 meters. 3 days will be 200 meters * 3 = 600 meters, in which case Statement II is TRUE.
Statement III: Daniel's work place is less than 100 meters from Samson's home. Distance from work to school is equal to distance from school to work, in which case Statement III can NEVER BE TRUE.
Only Statement I and II are True. So, the Correct answer is B
Answer: (B)  I and II only
Question: A man has Rs. 720 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
(A) 33
(B) 38
(C) 135
(D) 90
(E) 28
Rationale: Let number of notes of each denomination be x.
Then x + 5x + 10x = 720
⇒ 16x = 720
∴ x = 45.
Hence, total number of notes = 3x = 135
Answer:C
Answer: (C) 135
Question: When asked what the time is,a person answered that the amount of time left is 4/8 of the time already completed.what is the time.
(A) 2 PM
(B) 9 PM
(C) 4 PM
(D) 8 PM
(E) 6 PM
Rationale: A day has 24 hrs. Assume x hours have passed. Remaining time is (24 - x)
24−x=4/8x⇒x=20
Time is 4 PM
Answer:C
Answer: (C) 4 PM
Question: Two years ago, Arthur gave each of his five children 20 percent of his fortune to invest in any way they saw Fit. In the first year, three of the children, Alice, Bob, and Carol, each earned a profit of 50 percent on their Investments, while two of the children, Dave and Errol, lost 40 percent on their investments. In the second Year, Alice and Bob each earned a 20 percent profit, Carol lost 60 percent, Dave earned 25 percent in profit, And Errol lost all the money he had remaining. What percentage of Arthur's fortune currently remains?
(A) 99%
(B) 97%
(C) 100%
(D) 107%
(E) 120%
Rationale: Say Arthur's fortune was $100. Then:
A = 20*1.5*1.2 = 36
B = 20*1.5*1.2 = 36
C = 20*1.5*0.4 = 12
D = 20*0.6*1.25 = 15
E = 0
Total 39 + 39 + 12 + 15 = 99.
Answer: A.
Answer: (A) 99%
Question: If .08216 and 68.01 are multiplied to give x as product , how many digit to the right of the decimal point does x have?
(A) 8
(B) 7
(C) 6
(D) 8
(E) 9
Rationale: Product of .08216 and 68.01 is 5.5877016.
Therefore number of digits to right of decimal point is 7
Answer is B.
Answer: (B) 7
Question: The sum of ages of 4 children born at the intervals of 10 years each is 80 years. What is the age of the youngest child?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 10) + (x + 20) + (x + 30) = 80
4x = 20
x = 5.
Age of the youngest child = x = 5 years.
Answer:B
Answer: (B) 5
Question: A CAN FINISH A WORK IN 9 DAYS AND B CAN DO THE SAME WORK IN15 DAYS. B WORKED FOR 10 DAYS AND LEFT THE JOB. IN HOW MANY DAYS, A ALONE CAN FINISH THE REMAINING WORK?
(A) 3
(B) 5 1/2
(C) 6
(D) 8
(E) NONE OF THESE
Rationale: B'S 10 DAY'S WORK=(1/15*10)=2/3 REMAINING WORK = (1-2/3)=1/3
NOW, 1/18 WORK IS DONE BY A IN 1 DAY
1/3 WORK IS DONE BY A IN (9*1/3)=3 DAYS.
CORRECT OPTION:A
Answer: (A) 3
Question: Stuart bought a sweater on sale for 30% off the original price and another 25% off the discounted price. If the original price of the sweater was $40, what was the final price of the sweater?
(A) $25.75
(B) $35.75
(C) $15.75
(D) $ 21
(E) $16.75
Rationale: The price with 30% off
40 - 30% of 40 = 40 - (30 / 100) *40 = 40 - 12 = 28
The price with another 25% off
28 - 25% of 28 = 28 - (25/100)* 28
= $21
correct answer D
Answer: (D) $ 21
Question: Which number is the odd one out?
159
248
963
357
951
753
(A) 143
(B) 269
(C) 358
(D) 486
(E) 753
Rationale: E
753
In the rest there is the same difference between each digit, eg:7 (Ã¢â‚¬â€œ2)5 (Ã¢â‚¬â€œ2)3
Answer: (E) 753
Question: When 21 is divided by the positive integer k, the remainder is 3, for how many different values of k is this true?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: This means that 18 must be a multiple of k.
The factors of 18 are 1, 2, 3, 6, 9, and 18.
Out of these, k can be 6, 9, and 18.
The answer is C.
Answer: (C) 3
Question: A small company employs 3 men and 5 women. If a team of 4 employees is to be randomly selected to organize the company retreat, what is the probability F that the team will have exactly 2 women?
(A) 1/14
(B) 1/7
(C) 2/7
(D) 3/7
(E) 1/2
Rationale: 5C2 * 3C2 -> it gives combination of exactly 2 women and 2 men.
8C4 -> gives total possibilities of 4 people from 5 women and 3 men.
Probability = 5C2* 3C2 / 8C4 = 3/7
SECOND METHOD:
Probability of two women -> 5/8 * 4/7.
probability of two men -> 3/6 * 2/5.
Probability: (5/8 * 4/7) * (3/6 * 2/5) = 1/14.
Answer: (D) 3/7
Question: If the sides of a cube are in the ratio 4:3. What is the ratio of their diagonals?
(A) 4:3
(B) 4:8
(C) 4:1
(D) 4:2
(E) 4:7
Rationale: a1:a2 = 4:3
d1:d2 = 4:3
Answer:A
Answer: (A) 4:3
Question: The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
(A) 30/90 kmph
(B) 80,40 kmph
(C) 24,98 kmph
(D) 30,54 kmph
(E) 45.98 kmph
Rationale: Speed downstream = 60 + 20 = 80 kmph
Speed upstream = 60 - 20 = 40 kmph
Answer:B
Answer: (B) 80,40 kmph
Question: A student has to obtain 33% of the total marks to pass. He got 175 marks and failed by 89 marks. The maximum marks are?
(A) 450
(B) 300
(C) 800
(D) 610
(E) 175
Rationale: Let the maximum marks be x
Then, 33% of x = 175+89
33x/100 = 264
x = 800
Answer is C
Answer: (C) 800
Question: A $500 investment and a $1,500 investment have a combined yearly return of 8.5 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1 ,500 investment have?
(A) 9%
(B) 10%
(C) 10 5/8%
(D) 11%
(E) 12%
Rationale: The ratio of investments is 500:1,500 = 1:3.
The deviation from the average return from $500 investment and $1,500 investment must be in the ration 3:1.
$500 investment return has the deviation from the mean of 8.5-7=1.5%, thus $1,500 investment return must have the deviation from the mean equal to 0.5%, which means that $1 ,500 investment has 8.5+0.5=9% yearly return.
Answer: A.
Answer: (A) 9%
Question: A wolf eats 5.5 Kg of meat in 3 days. A baby tiger eats 3 Kg of meat in 4 days. How much meat can the two combined eat in three days?
(A) 10.
(B) 9.
(C) 8.
(D) 7.75
(E) 6.
Rationale: 3/3*5.5+3/4*3=7.75 kg
D
Answer: (D) 7.75
Question: Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?
(A) 3.6
(B) 6
(C) 18
(D) 22
(E) 25
Rationale: Let rate = R% and time = R years.
Then, (1200 x R x R)/100	= 432
12R^2 = 432
R^2 = 36
R = 6.
Answer: Option B
Answer: (B) 6
Question: When the positive integer e is divided by 11, the quotient is f and the remainder 3. When e is divided by 19, the remainder is also 3. What is the remainder when f is divided by 19?
(A) 4
(B) 3
(C) 2
(D) 1
(E) 0
Rationale: Any Number which when divided by divisor d1,d2, etc. leaving same remainderrtakes the form ofK+r
where k = LCM (d1,d2)
In this case the divisors are 1119 and remainder is 3.
so LCM (11,19) = 209
So N= 209+3 = 212
Also e =d1q+3 ; which means d1q=209d1=11 therefore q=19
And ( f divided by 19)19/19 leaves remainder 0.
Answer is E
Answer: (E) 0
Question: What is the units digit of 23^2 * 17^2 * 39^2?
(A) 1
(B) 3
(C) 5
(D) 7
(E) 9
Rationale: The units digit of 23^2 is the units digit of 3*3 = 9 which is 9.
The units digit of 17^2 is the units digit of 7*7 = 49 which is 9.
The units digit of 39^2 is the units digit of 9*9 = 81 which is 1.
The units digit of 9*9*1 = 81 is 1.
The answer is A.
Answer: (A) 1
Question: John found that the average of 15 numbers is 40. If 10 is added to each number then the mean of number is?
(A) 50
(B) 60
(C) 70
(D) 80
(E) 90
Rationale: (x+x1+...x14)/15 = 40
50
Option A
Answer: (A) 50