mathewhe/aqua_rat huggingface dataset:
Question: In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 12 to the thrice of the remainder. The dividend is
(A) 74
(B) 78
(C) 86
(D) 126
(E) 98
Rationale: Divisor = (6 * 3) + 12 = 30
5 * Quotient = 30
Quotient = 6.
Dividend = (Divisor * Quotient) + Remainder
Dividend = (20 * 6) + 6 = 126.
D)
Answer: (D) 126
Question: The length of a room is 5.5 m and width is 3.75 m. Find the cost of paving the floor by slabs at the rate of Rs. 1000 per sq. metre.
(A) Rs. 15000
(B) Rs. 15550
(C) Rs. 15600
(D) Rs. 20625
(E) None of these
Rationale: Solution
Area of the floor = (5.5 × 3.75) m2 = 20.625 m2
∴ Cost of paving = Rs. (1000 × 20.625) = 20625. Answer D
Answer: (D) Rs. 20625
Question: What must be added to each term of the ratio 7:11, So as to make it equal to 3:4?
(A) 8
(B) 7.5
(C) 6.5
(D) 5
(E) 6
Rationale: Solution: Let x be added to each term.
According to question,
(7+x)/(11+x) = 3/4;
Or, 33+3x = 28+4x;
Or, x = 5.
Answer: Option D
Answer: (D) 5
Question: The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?
(A) 270
(B) 250
(C) 245
(D) 320
(E) 620
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Smaller number = 270.
ANSWER A
Answer: (A) 270
Question: A ladder 14 feet long is leaning against a wall that is perpendicular to level ground. The bottom of the ladder is 9 feet from the base of the wall. If the top of the ladder slips down 1 feet, how many feet will the bottom of the ladder slip?
(A) 4
(B) 10
(C) 18
(D) 19
(E) 25
Rationale: 14^2-9^2=115
it means that the height is equal to 10.72.
since the top of the ladder slips down 1 feet, then the height of the wall =10.72-1=9.72
the bottom =sqrt(14^2-9.72^2)=sqrt(196-94.47)=10.07~=10
ans is B
Answer: (B) 10
Question: What day of the week was 1 January 1901
(A) Monday
(B) Tuesday
(C) Saturday
(D) Friday
(E) Sunday
Rationale: Explanation:
1 Jan 1901 = (1900 years + 1st Jan 1901)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfect multiple of 400)
Number of odd days in the period 1601-1900
= Number of odd days in 300 years
= 5 x 3 = 15 = 1
(As we can reduce perfect multiples of 7 from odd days without affecting anything)
1st Jan 1901 = 1 odd day
Total number of odd days = (0 + 1 + 1) = 2
2 odd days = Tuesday
Hence 1 January 1901 is Tuesday.
Answer: Option B
Answer: (B) Tuesday
Question: ((-1.9)(0.6) – (2.6)(1.2))/2.0 = ?
(A) -0.71
(B) -2.13
(C) 1.07
(D) 1.71
(E) 2.71
Rationale: Dove straight into calculation
((-1.9)(0.6) – (2.6)(1.2))/2.0 = -2.13
Answer B
Answer: (B) -2.13
Question: Jayant opened a shop investing Rs. 30,000. Madhu joined him 2 months later, investing Rs. 45,000. They earned a profit of Rs. 52,000 after completion of one year. What will be Madhu's share of profit?
(A) Rs. 27,000
(B) Rs. 26,000
(C) Rs. 30,000
(D) Rs. 36,000
(E) None of these
Rationale: 30,000 *12=45,000*8
1:1
Madhu's share=1/2*52,000
i.e. Rs. 26,000
ANSWER:B
Answer: (B) Rs. 26,000
Question: In 22 minutes, the minute hand gains over the hour hand by
(A) 56°
(B) 80°
(C) 88°
(D) 96°
(E) 121°
Rationale: In one hour, the hour hand moves 30°, which is 0.5° each minute.
In one hour, the minute hand moves 360°, which is 6° each minutes.
The minute hand gains 5.5° each minute.
In 22 minutes, the minute hand gains 22 * 5.5° = 121°.
The answer is E.
Answer: (E) 121°
Question: lexus car agency has 189 cars.he sold some cars at 9% profit and rest at 36% profit thus he gains 17% on the sale of all his cars.the no. of cars sold at 36% profit is?
(A) 56
(B) 37
(C) 38
(D) 39
(E) 40
Rationale: ratio of 36% profit cars to 9% profit cars = 8:19
so no. of cars sold at 36% profit = 189*8/27= 56 cars
ANSWER:A
Answer: (A) 56
Question: Tom, working alone, can paint a room in 10 hours. Peter and John, working independently, can paint the same room in 5 hours and 2 hours, respectively. Tom starts painting the room and works on his own for two hour. He is then joined by Peter and they work together for two hour. Finally, John joins them and the three of them work together to finish the room, each one working at his respective rate. What fraction of the whole job was done by Peter?
(A) 1/3
(B) 1/2
(C) 1/4
(D) 1/5
(E) 1/6
Rationale: Let the time when all three were working together be t hours. Then:
Tom worked for t+4 hour and has done 1/10*(t+4) part of the job;
Peter worked for t+2 hour and has done 1/5*(t+2) part of the job;
John worked for t hours and has done 1/2*t part of the job:
1/10*(t+4)+1/5*(t+2)+1/2*t=1 --> multiply by 10 --> (t+4)+(2t+2)+5t=10 --> t=1/2;
Hence Peter has done 1/5*(1/2+2)=1/5 *5/2=1/2
Answer: B
Answer: (B) 1/2
Question: A group consists of 5 men, 5 women and 3 children. In how many ways can 2 men , 2 women and 1 child selected from the given group?
(A) 300 ways
(B) 400 ways
(C) 500 ways
(D) 360 ways
(E) 380 ways
Rationale: Two men, two women and one child can be selected in 5C₂ * 5C2 * 3C₁ ways
5*4/2*1*5*4/2*1*3
= 300 ways
Answer : A
Answer: (A) 300 ways
Question: A butler is promised Rs. 100 and a cloak as his wages for a year. After 7 months he leaves this service, and receives the cloak and Rs.20 as his due. How much is the cloak worth?
(A) 22
(B) 98
(C) 92
(D) 72
(E) 71
Rationale: Explanation:
Let be the price of cloak is = x
According to the Question he should get 7/12th of 100 and 7/12th of cloak.
712(100)+712(x)=20+x712(100)+712(x)=20+x
⇒ x = 92.
Answer: C
Answer: (C) 92
Question: A barrel holds 4 litres of paint and 4 litres of turpentine. How many quarts of turpentinemust be added to the container to create a mixture that is 3 parts petrol to 5 parts turpentine by volume?
(A) 4/3
(B) 5/3
(C) 7/3
(D) 8/3
(E) 10/3
Rationale: An alternate to the alligation method is the more direct/algebraic method:
Let x be the amount of turpentine to be added.
New total amount of turpentine = 4+x
Total amount of paint = 4
New total = 4+4+x=8+x
Final ratio required (for turpentine) = 5/(5+3)=5/8
Thus, (4+x)/(8+x) = 5/8 --> solving for x you get x = 8/3.
D is thus the correct answer.
Answer: (D) 8/3
Question: A car covers a certain distance at aspeed of 50 kmph in 5 hours. To cover the same distance in 2 hrs, it must travel at a speed of?
(A) 125 km/hr
(B) 678 km/hr
(C) 782 km/hr
(D) 789 km/hr
(E) 720 km/hr
Rationale: Distance = (50 x 5) =250 km.
Speed = Distance/Time
Speed = 250/2 = 125 kmph
Answer : A
Answer: (A) 125 km/hr
Question: Jim’s Taxi Service charges an initial fee of $2.25 at the beginning of a trip and an additional charge of $0.25 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles?
(A) $3.15
(B) $4.5
(C) $4.80
(D) $5.05
(E) $5.40
Rationale: Let the fixed charge of Jim’s Taxi Service = 2.25 $
and charge per 2/5 mile(.4 mile) = .25$
Total charge for a trip of 3.6 miles = 2.25 + (3.6/.4) * .25
= 2.25 + 9*.25
= 4.5 $
Answer B
Answer: (B) $4.5
Question: If it is 7:27 in the evening on a certain day, what time in the morning was it exactly 2,880,717 minutes earlier? (Assume standard time in one location.)
(A) 7:22
(B) 7:24
(C) 7:27
(D) 7:30
(E) 7:32
Rationale: 7:27minus 2,880,717in any way must end with 0, the only answer choice which ends with 0 is D.
Answer: D.
Answer: (D) 7:30
Question: In covering a distance of 90 km, A takes 2 hours more than B. If A doubles his speed, then he would take 1 hour less than B. A's speed is:
(A) 5 km/h
(B) 8 km/h
(C) 10 km/h
(D) 15 km/h
(E) 25 km/h
Rationale: Let A's speed be X km/hr.
Then, 90/x - 90/2x = 3
6x = 90
x = 15 km/hr.
Answer : D.
Answer: (D) 15 km/h
Question: What will come in place of the x in the following number series? 1, 4, 10, 22, 46, x
(A) 84
(B) 92
(C) 94
(D) 98
(E) 104
Rationale: 11 × 2 + 2 = 44 × 2 + 2 = 1010 × 2 + 2 = 2222 × 2 + 2 = 4646 × 2 + 2 = 94 C
Answer: (C) 94
Question: In a certificate by mistake a candidate gave his height as 20% more than actual height. In the interview panel, he clarified that his height was 5 feet 5 nches. Find the % correction made by the candidate from his stated height to his actual height?
(A) 13
(B) 20
(C) 30
(D) 43
(E) 50
Rationale: His height was = 5 feet 5 inch = 5 + 60 = 65 inch. Required % correction =65*(1.20-1) = 13
A
Answer: (A) 13
Question: In Township K each property is taxed at 12 percent of its assessed value. If the assessed value of a property in Township K is increased from $20,000 to $24,000, by how much will the property tax increase?
(A)  $32
(B)  $50
(C)  $320
(D)  $400
(E)  $480
Rationale: Increase in house value = $24,000 - $20,000 =$4000
So, tax increase = 12% of$4000=$480
Answer: E
Answer: (E)  $480
Question: A person crosses a 600 metre long street in 5 minutes. What is his speed in km per hour?
(A) 8.2
(B) 4.2
(C) 6.1
(D) 7.2
(E) 8.5
Rationale: Distance =600 metre =0.6 km
Time = 5 min = 1/12 hr
speed = dist/time = 0.6/(1/2) = 7.2 km/hr
ANSWER D
Answer: (D) 7.2
Question: The volume of the sphere QQ is (dfrac{37}{64}%)less than the volume of sphere PP and the volume of sphere RR is (dfrac{19}{27}%) less than that of sphere QQ. By what is the surface areaof sphere RR less than the surfacearea of sphere PP?
(A) 50%
(B) 60%
(C) 75%
(D) 80%
(E) 83%
Rationale: Let the volume of sphere PP be 64 parts.
Therefore volume of sphere QQ
=64−3764%=64−3764% of 6464
=64−37=27=64−37=27 parts.
The volume of RR
=27−1927×27=27−1927×27
=27−19=8=27−19=8 parts.
Volume ratio:
=P:Q:R=64:27:8=P:Q:R=64:27:8
Radius ratio:
=P:Q:R=4:3:2=P:Q:R=4:3:2
The surface area will be 16:9:516:9:5
Surface area of RR is less than the surface area of sphere PP
16k−4k=12k16k−4k=12k
Now,
=12k16k×100=12k16k×100
=75%=75%
Thus surface area of sphere RR is less than the surface area of sphere P by 75%
C
Answer: (C) 75%
Question: If f(a)=a^2, what is the value of (f(a+b)+f(a))/b ?
(A) a
(B) b
(C) 2a
(D) 2a + b
(E) 2a+b+2a^2
Rationale: start with f(a+b) before start calculations: f(a+b)=(a+b)^2= a^2+2ab+b^2
a^2+2ab+b^2 + a^2/b = (simplify a^2)
2ab+b^2/b+2a^2 = (cancel b's)
= 2a+b+2a^2
Answer : E
Answer: (E) 2a+b+2a^2
Question: An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:
(A) 4.04%
(B) 4.14%
(C) 4.16%
(D) 4.20%
(E) 5.04%
Rationale: 100 cm is read as 102 cm.
A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.
(A2 - A1) = [(102)2 - (100)2]
= (102 + 100) x (102 - 100)
= 404 cm2.
Percentage error = 404 x 100 % = 4.04%
100 x 100
A)
Answer: (A) 4.04%
Question: Pipe A fills a tank of capacity 700 liters at the rate of 40 liters a minute. Another pipe B fills the same tank at the rate of 30 liters a minute. A pipe at the bottom of the tank drains the tank at the rate of 20 liters a minute. If pipe A is kept open for a minute and then closed and pipe B is open for a minute and then closed and then pipe C is open for a minute and then closed and the cycle is repeated, when will the tank be full?
(A) 42 minutes
(B) 14 minutes
(C) 39 minutes
(D) 40 minutes 20 seconds
(E) None of these
Rationale: In one cycle they fill 40+30-20 = 50 liters
700 = 50*n => n = 14
here n = number of cycles.
total time = 14*3 = 42 as in one cycle there are 3 minutes.
thus 42 minutes
ANSWER:A
Answer: (A) 42 minutes
Question: If x is divisible by 2 and 7, which of the following must divide evenly into x? I. 60 II. 32 III. 14
(A) I,II only
(B) I,III only
(C) I only
(D) III only
(E) II only
Rationale: If x is divisible by 2,7 means it will be = or > 14, 28,42 etc...
That are not divisible by 60, 32.
So, the answer is D
Answer: (D) III only
Question: Ramu bought an old car for Rs. 42000. He spent Rs. 13000 on repairs and sold it for Rs. 66900. What is his profit percent?
(A) 17%
(B) 19%
(C) 18%
(D) 21.6%
(E) 16%
Rationale: Total CP = Rs. 42000 + Rs. 13000
= Rs. 55000 and SP
= Rs. 66900
Profit(%) = (66900 - 55000)/55000 * 100
= 21.6%
Answer: D
Answer: (D) 21.6%
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 36 hours and 16 hours respectively. The ratio of their speeds is?
(A) 4:5
(B) 4:3
(C) 4:6
(D) 4:9
(E) 4:2
Rationale: Let us name the trains A and B.
Then, (A's speed) : (B's speed)
= √b : √a = √16 : √36 = 4:6
Answer:C
Answer: (C) 4:6
Question: Betty picked a number of pears, each of which she sold, canned, or poached. If she canned 30 percent more than she poached, and she poached 10 percent less than she sold. If there were a total of 614 pears, then how many pears did she sell?
(A) 190
(B) 200
(C) 210
(D) 220
(E) 230
Rationale: Let x be the amount of pears that she sold.
Then she poached 0.9x.
Then she canned 1.3*0.9x=1.17x.
The total amount of pears is x+0.9x+1.17x=3.07x
The fraction of pears that she sold is 1/3.07=100/307.
The number of pears she sold is (100/307)*614=200.
The answer is B.
Answer: (B) 200
Question: The second smallest prime number is?
(A) 67
(B) 71
(C) 73
(D) 21
(E) 23
Rationale: The second smallest prime number is 67.
A)
Answer: (A) 67
Question: If the length of an edge of cube M is four times the length of an edge of cube N, what is the ratio of the volume of cube N to the volume of cube M?
(A) 1/32
(B) 1/16
(C) 1/8
(D) 1/64
(E) 1/12
Rationale: The length of cube N = 1;
The length of cube M = 4;
The ratio of the volume of cube N to the volume of cube M = 1^3/4^3 = 1/64
Answer : D
Answer: (D) 1/64
Question: The number of permutations of the letters of the word 'REMEMBER' is?
(A) 7!/(2!)2 3!
(B) 8!/(2!)2 8!
(C) 8!/(8!)2 3!
(D) 8!/(2!)2 3!
(E) 8!/(2!)2 1!
Rationale: n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.
The letter pattern 'REMEMBER' consists of 8 letters of which there are 2R's, 3E's, 2M's and 1B.
Number of arrangements = 8!/(2!)2 3!
Answer: D
Answer: (D) 8!/(2!)2 3!
Question: The number 311311311311311311311 is:
(A) divisible by 3 but not by 11
(B) divisible by 11 but not by3
(C) divisible by both 3 and 11
(D) neither divisible by 3 nor by 11.
(E) none of these
Rationale: Sum of digits= 35 and so it is not divisible by 3.
(Sum of digits at odd places)- (Sum of digits at even places)= 19-16=3, not divisible by 11.
So, the given number is neither divided by 3 nor by 11.
ANSWER:D
Answer: (D) neither divisible by 3 nor by 11.
Question: During a two-week period, the price of an ounce of silver increased by 5 percent by the end of the first week and then decreased by 10 percent of this new price by the end of the second week. If the price of silver was x dollars per ounce at the beginning of the two-week period, what was the price, in dollars per ounce, by the end of the period?
(A) 0.945x
(B) 0.985x
(C) 0.995x
(D) 1.05x
(E) 1.15x
Rationale: The price at the end is 0.9(1.05x)=0.945x
The answer is A.
Answer: (A) 0.945x
Question: Simple interest on a certain sum is 9 over 25 of the sum. Find the rate per cent and time, if both are equal.
(A) 8% and 8 years
(B) 6% and 6 years
(C) 10% and 10 years
(D) 6 % and 6 years
(E) None of these
Rationale: 9â„25 P = PÃ—RÃ—R/100
â‡’ R2 = 900â„25 â‡’ R^2 = 36 R= 6
Also, time = 6 years
Answer D
Answer: (D) 6 % and 6 years
Question: A data set with a mean of 90 has a standard deviation of 2.5. Which of the following is the smallest number that falls within one standard deviation of the mean?
(A) 53
(B) 56
(C) 59
(D) 63.5
(E) 87
Rationale: One standard deviation of the mean is from{mean}-{deviation}=90-2.5=87.5 to{mean}+{deviation}=90+2.5=92.5. The smallest number within this range from the options is 87.
Answer: E.
Hope this helps.
Answer: (E) 87
Question: if A=2^65 AND B=2^64+2^63.....+2^0
(A) A is larger than B by 2^64 times
(B) B is larger than A by 1
(C) A is larger than B by 1
(D) A is equal to B
(E) None
Rationale: lets say A : 2^4=16 , B: 2^3+2^2+2^1+2^0 = 15 so A is larger than B by 1 always
ANSWER:C
Answer: (C) A is larger than B by 1
Question: X, Y and Z together invested Rs.106000, X invested Rs.4000 more than Y, and Rs.10000 more than Z. what is the share of X out of annual profit of Rs.26500 ?
(A) Rs.10000
(B) Rs.10800
(C) Rs.10500
(D) Rs.11000
(E) Rs.11500
Rationale: Let Z share be ‘a’ then
Y = a + Rs.6000 [as X investment is Rs.10000 more than Z, and Rs.4000 more than Y, then Y share more than Z by Rs.10000 – Rs.4000 = Rs.6000]
X = a + Rs.10000.
X + Y + Z = 3a + 16000 = Rs.106000.
3a = 106000 – 16000 = Rs.90000.
a = 90000 / 3 = Rs.30000.
therefore Z investment = Rs.30000.
Y = Rs.30000 + Rs.6000 = Rs.36000.
X = Rs.30000 + Rs.10000 = Rs.40000.
Ratio of shares X : Y : Z = 20 : 18 : 15 = [53 units].
Investment Ratio = Profit sharing Ratio.
X = 26500 × 20 / 53 = Rs.10000
Option A
Answer: (A) Rs.10000
Question: A trade analyst announced 10% reduction in the unit price of bike. As a result, the sales volume went up by 25%. What was the net effect on the sales revenue?
(A) no change
(B) decreases by 12.5%
(C) increases by 12.5%
(D) increases by 10%
(E) None of these
Rationale: Explanation :
Reduction of price = (100 -10)% = 90% = 0.9
Increase of sale = (100+25)% = 125% = 1.25
Total effect = 0.90X 1.25 = 112.5%, Increases by 12.5%
Answer : C
Answer: (C) increases by 12.5%
Question: 10, 50, 13, 45, 18, 38, ?.
What a number should replace the question mark?
(A) 34
(B) 27
(C) 25
(D) 46
(E) 51
Rationale: C
25
There are two alternate sequences: start at 10 and add 3, 5, 7;
start at 50 and deduct 5, 7, 9.
Answer: (C) 25
Question: Two trains are running in opposite directions in the same speed. The length of each train is 120 meter. If they cross each other in 4 seconds, the speed of each train (in km/hr) is
(A) 42
(B) 36
(C) 108
(D) 120
(E) 124
Rationale: Explanation:
Distance covered = 120+120 = 240 m
Time = 4 s
Let the speed of each train = v. Then relative speed = v+v = 2v
2v = distance/time = 240/4 = 60 m/s
Speed of each train = v = 60/2 = 30 m/s
= 30×36/10 km/hr = 108 km/hr
Answer: Option C
Answer: (C) 108
Question: Calculate how much time could be saved if the train would run at its usual speed, given that it ran at 4/9 of its own speed and got to its destination in 13 hours?
(A) 1.22 hrs
(B) 2.22 hrs
(C) 5.22 hrs
(D) 6.22 hrs
(E) 7.22 hrs
Rationale: New speed = 4/9 of usual speed
New time = 4/9 of usual time
4/9 of usual time = 13 hrs
Usual time = 13*4/9 = 5.78 hrs
Time saved = 13-5.78 = 7.22 hrs
Answer is E
Answer: (E) 7.22 hrs
Question: In a college, 50% of total 400 Arts students are Locals. 25% of students from 100 Science students are locals and 85% of total 120 Commerce students are locals. What is the total percentage of locals from Arts, Science and Commerce.
(A) 322
(B) 340
(C) 333
(D) 327
(E) 500
Rationale: locals from Arts = 50% of 400 = 200
locals from Science = 25% of 100 = 25
locals from Commerce = 85% of 120 = 102
total locals = 200+25+102 = 327
D
Answer: (D) 327
Question: Of 5 employees, 3 are to be assigned an office and 2 are to be assigned a cubicle. If 3 of the employees are men and 2 are women, and if those assigned an office are to be chosen at random, what is the probability that the offices will be assigned to 2 of the men and 1 of the women?
(A) 1/3
(B) 2/5
(C) 1/2
(D) 3/5
(E) 2/3
Rationale: probability = Desired Outcomes/Total Outcomes
Event = Selection of 3 employees to assign office from 5 such that 2 are men and 1 is woman
Total Outcomes = Selection of any 3 employees from 5 employees = 5 C 3 = 10
Desired Outcomes = Selection of 2 Men from 3 Men AND selection of 1 woman from 2 Women. = (3 C 2) * (2 C 1) = 3*2 = 6
Probability = 6/10 --------> 3/5
ANSWER:D
Answer: (D) 3/5
Question: What is the quotient between the place values of two 5's in the numeral 57005
(A) 11401
(B) 0.5
(C) 49995
(D) 50000
(E) 10000
Rationale: Required quotient = 50000 / 5 = 10000
Answer is E
Answer: (E) 10000
Question: An outlet pipe can empty 2/3 rd of a cistern in 12 minutes. In 8 minutes, what part of the cistern will be emptied?
(A) 4/9
(B) 2/3
(C) 3/4
(D) 5/6
(E) 6/8
Rationale: 2/3 ---- 12
? ----- 8 ==> 4/9
ANSWER A
Answer: (A) 4/9
Question: Truck P and Truck Q drive on the highway in the same direction at respective rates of 70 kph and 77 kph. If Truck Q is 4 km behind Truck P, by how much does Truck P need to increase the speed to catch up with Truck P in 15 minutes?
(A) 1 kph
(B) 3 kph
(C) 5 kph
(D) 7 kph
(E) 9 kph
Rationale: Truck Q needs to gain 4 km in 15 minutes.
The relative speed difference needs to be 4 km / 15 minutes = 16 km/hour
Truck Q needs to increase up to 86 kph, thus an increase in 9 kph.
The answer is E.
Answer: (E) 9 kph
Question: A couple who own an appliance store discover that if they advertise a sales discount of 10% on every item in the store, at the end of one month the number of total items sold increases 20%. Their gross income from sales for one month increases by what percent?
(A) 2%
(B) 4%
(C) 5%
(D) 8%
(E) 12%
Rationale: Let List price of an item = 100
Discount on each item = 10%
Discounted price of an item = .9*100 = 90
If they advertise a sales discount of 10% on every item in the store, at the end of one month the number of total items sold increases 20%
Originally if 10 items were sold in a month , with the new discount 12 items will be sold
Original revenue = No of items* Price of an item = 10 * 100 = 1000
New revenue = 12 * 90 = 1080
Increase in gross income = 1080 - 1000 = 80
% increase in gross revenue = 80/1000 * 100% = 8%
Answer D
Answer: (D) 8%
Question: Mohit sold an article for Rs. 18000. Had he offered a discount of 22% on the selling price, he would have earned a profit of 8%. What is the cost price of the article?
(A) 13000
(B) 27767
(C) 16688
(D) 26678
(E) 19987
Rationale: Let the CP be Rs. x.
Had he offered 22% discount, profit = 8%
Profit = 8/100 x and hence his SP = x + 8/100 x = Rs. 1.08x = 18000 - 22/100(18000) = Rs. 14040
=> 1.08x = 14040
=> x = 13000
\Answer: A
Answer: (A) 13000
Question: 50 men can complete a work in 65 days.Five days after started the work, 20 men left the group. In how many days can the remaining work be completed?
(A) 767 days
(B) 666 days
(C) 555 days
(D) 5126 days
(E) 100 days
Rationale: After 5 days, the following situation prevails.
50 men can complete the work in 60 days.
30 men can complete the work in ? days.
M1 D1 = M2 D2
=> 50 * 60 = 30 * D2
=> D2 = (50 * 60)/30 = 100 days.
Answer:E
Answer: (E) 100 days
Question: The average age of three persons is 52 years. Their ages are in the proportion of 1:5:7. What is the age in years of the oldest one among them.
(A) 9 years
(B) 12 years
(C) 60 years
(D) 70 years
(E) 80 years
Rationale: Explanation:
Let the age of three persons be x, 5x, 7x
= 13x/3 = 52
x= 12 years
Answer: Option D
Answer: (D) 70 years
Question: The cost of 10 kg of apples is equal to the cost of 24 kg of rice. The cost of 6 kg of flour equals the cost of 2 kg of rice. The cost of each kg of flour is Rs.20.50. Find the total cost of 4 kg of apples, 3 kg of rice and 5 kg of flour?
(A) 777.4
(B) 877.4
(C) 577.4
(D) 477.4
(E) 177.4
Rationale: Let the costs of each kg of apples and each kg of rice be Rs.a and Rs.r respectively.
10a = 24r and 6 * 20.50 = 2r
a = 12/5 r and r = 61.5
a = 147.6
Required total cost = 4 * 147.6 + 3 * 61.5 + 5 * 20.5
= 590.4 + 184.5 + 102.5 = Rs.877.40
Answer: B
Answer: (B) 877.4
Question: If A is thrice as fast as B and together can do a work in 21 days. In how many days A alone can do the work?
(A) 36
(B) 42
(C) 28
(D) 54
(E) 45
Rationale: A’s one day’s work= 1/X
B’s one day’s work= 1/3x
A + B’s one day’s work= 1/x + 1/3x = 1/21
= 3+1/3x = 4/3x = 1/21
x = 21*4/3 = 28
ANSWER:C
Answer: (C) 28
Question: When n is divided by 5 the remainder is 3. What is the remainder when (n + 3)^2 is divided by 5?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
Rationale: n = 5x+3, for some integer x
(n+3)^2=(5x+6)^2=5y+36, for some integer y
When we divide this by 5, the remainder is 1.
The answer is B.
Answer: (B) 1
Question: A team scored a total of 126 points. If each player on the team scored at least 14 points, then what is the greatest possible number of players on the team?
(A) A)6
(B) B)7
(C) C)8
(D) D)9
(E) E)10
Rationale: 126/14=9 plus remainder.
The answer is D.
Answer: (D) D)9
Question: The sale price sarees listed for Rs.400 after successive discount is 20% and 15% is?
(A) 297
(B) 272
(C) 342
(D) 762
(E) 269
Rationale: 400*(80/100)*(85/100)
= 272
Answer: B
Answer: (B) 272