mathewhe/aqua_rat huggingface dataset:
Question: Aamir saves 32% of his monthly salary. If he spends Rs. 27200, then find his savings?
(A) 12877
(B) 12817
(C) 12171
(D) 12800
(E) 128722
Rationale: Let the monthly salary of Aamir be Rs. x.
68% of x = 27200
=> x = (27200 * 100)/68 = 40000
His savings = 32/100 * 40000 = 12800.
Answer:D
Answer: (D) 12800
Question: If a sample of data has mean of 20 and SD of 3, which of the following values is more than 2.4 SDs from the mean?
(A) 13
(B) 20
(C) 21
(D) 22
(E) 18
Rationale: 2.4 SD's mean is equal to: +/- 2.4*3 = +/- 7.2
ie. 12.8 to 27.2
Answer is: A
Answer: (A) 13
Question: If an object travels at 85 feet per second, how many feet does it travel in 30 minutes?
(A) 3000
(B) 1500
(C) 1800
(D) 9000
(E) 2500
Rationale: If an object travels at 85 feet per second it covers 85x60 feet in one minute, and 5x60x30 feet in 30 minutes.
Answer = 9000 Answer: D
Answer: (D) 9000
Question: The average marks of a class of 28 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students?
(A) 52.2
(B) 59.5
(C) 52.8
(D) 52.5
(E) 52.1
Rationale: Sum of the marks for the class of 28 students = 28 * 40 = 1120
Sum of the marks for the class of 50 students = 50 * 60 = 3000
Sum of the marks for the class of 78 students =
1120 + 3000 = 4120
Average marks of all the students = 4120/78
= 52.8
Answer:C
Answer: (C) 52.8
Question: 100 liters of a mixture contains milk and water in the ratio 4:1. If 10 liters of this mixture be replaced by 10 liters of milk, the ratio of milk to water in the new mixture would be?
(A) 7:5
(B) 9:2
(C) 6:1
(D) 5:4
(E) 11:4
Rationale: Quantity of milk in 100 liters if mix = 100*4/5 =80 liters
Quantity of milk in 110 liters of new mix = 80+10 = 90liters
Quantity of water in it = 110-90 = 20 liters
Ratio of milk and water in new mix = 90:20 = 9:2
Answer is B
Answer: (B) 9:2
Question: A number is missing from the number series below.
Can you find it ?
?, 155, 258, 399 , 584, 819.
(A) 275
(B) 84
(C) 399
(D) 421
(E) 449
Rationale: B
The missing number is 84.
155 = 5^3 + 5^2 + 5
258 = 6^3 + 6^2 + 6
399 = 7^3 + 7^2 + 7
584 = 8^3 + 8^2 + 8
819 = 9^3 + 9^2 + 9
Thus,
84 = 4^3 + 3^2 + 4
Answer: (B) 84
Question: -74x29+265=?
(A) 2436
(B) -1881
(C) -2801
(D) -2071
(E) None of them
Rationale: Given exp.=-74x(30-1)+265
=-(74x30)+74+265
=-2220+339
=-1881
Answer is B
Answer: (B) -1881
Question: Find the odd man out
3, 5, 7, 11, 14, 17, 19, 23
(A) 3
(B) 5
(C) 11
(D) 14
(E) 23
Rationale: as 14 is only odd number. 14 is not prime
ANSWER:D
Answer: (D) 14
Question: A certain lab experiments with white and brown mice only. In one experiment, 2/3 of the mice are white. If there are 9 brown mice in the experiment, how many mice in total are in the experiment?
(A) 39
(B) 33
(C) 27
(D) 21
(E) 10
Rationale: Let total number of mice = M
Number of white mice = 2/3 M
Number of brown mice = 1/3 M = 9
=> M = 27
Answer C
Answer: (C) 27
Question: Every Monday, Marina eats one croissant and every Tuesday she eats two croissants. On each subsequent day of the week, she eats a number of croissants equal to the sum of the croissants eaten on the two previous days, with the exception that if she eats more than four croissants on any particular day, the next day she will eat only one croissant. At the end of the week (which runs from Monday through Sunday), the cycle resets, and Marina goes back to eating one croissant on Monday, two on Tuesday, and so forth. If a particular month begins on a Thursday, how many croissants will Marina eat on the 27th of that month?
(A) 1
(B) 2
(C) 3
(D) 5
(E) 6
Rationale: She eat as follow
Mon - 1
Tue - 2
Wed - 3
Thr - 5
Fri - 1(since she had more than 4 previous day)
sat - 6
sunday - 1 (since she had more than 4 previous day)
so 27th day of month she will have 2.
Answer is B
Answer: (B) 2
Question: A and B together do a work in 20 days.B and C together in 15 days and C and A in 12 days.then B alone can finish same work in how many days?
(A) 50
(B) 60
(C) 45
(D) 35
(E) 48
Rationale: (A+B) work in 1 day= 1/20,(B+C) work in 1 days = 1/15.,(C+A) work in 1 days=1/12
(1) adding=2[A+B+C] in 1 day work = [1/20+1/15+1/12]=1/5
(A+B+C) work in 1 day= 1/10
B work in 1 days= [A+B+C] work in 1 days- work of (A+C) in 1 days
=[1/10-1/12]=1/60
B alone finish work in 60 days
Answer B
Answer: (B) 60
Question: A and B start a business with Rs.6000 and Rs.8000 respectively. Hoe should they share their profits at the end of one year?
(A) 3:6
(B) 3:4
(C) 3:9
(D) 3:3
(E) 3:1
Rationale: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B
=6000 : 8000 => 3:4
Answer:B
Answer: (B) 3:4
Question: Three brothers live in a farm. They agreed to buy new seeds: Adam and Ben would go and Charlie stayed to protect fields. Ben bought 75 sacks of wheat in the market whereas Adam bought 45 sacks. At home, they split the sacks equally. Charlie had paid 1400 dollars for the wheat. How much dollars did Ben and Adam get of the sum, considering equal split of the sacks?
(A) B$1150-A$180
(B) B$1400-A$160
(C) B$1225-A$175
(D) B$1327-A$199
(E) B$1876-A$250
Rationale: Every farmer's part is 1/3(45+75) = 40 sacks.
Charlie paid $1400 for 40 sacks, then 1 sack costs $1400/40 = $35/sack.
Adam got $35*(45-40)=35*5 = $175.
Ben got $35*(75-40)=35*35 = $1225.
Answer: Ben $1225, Adam $175
Answer: (C) B$1225-A$175
Question: In how many E ways can the letters of the word JUPITER be arranged in a row so that the vowels appear in alphabetic order?
(A)  736
(B)  768
(C)  792
(D)  840
(E)  876
Rationale: three letters can be arranged in 3! ways.
only one combination EIU is required.
7 letters can be arranged in 7! ways.
thus E=7!/ 3! * 1 = 840.
D
Answer: (D)  840
Question: A man is facing northwest. He turns 90 degrees in the clockwise direction and then 135degrees in the anti-clockwise direction. Which direction is he facing now?
(A) East
(B) West
(C) North
(D) South
(E) none
Rationale: Turns 90 degrees from northwest in clockwise direction is ;His position is Northeast
From Northeast, turns 135 degrees in anticlock : his position is west
ANSWER:B
Answer: (B) West
Question: If two letters are taken at random from the word HOME, what is the probability that none of the letters would be vowels?
(A) 1/6
(B) 1/9
(C) 8
(D) 2/2
(E) 1/1
Rationale: Answer: A) 1/6
Answer: (A) 1/6
Question: If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other
(A) 34
(B) 77
(C) 12
(D) 45
(E) 67
Rationale: Explanation:
For any this type of question, remember
Product of two numbers = Product of their HCF and LCM
So Other number =
693×11/99
= 77
Option B
Answer: (B) 77
Question: A man bought 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is
(A) 12
(B) 14
(C) 15
(D) 16
(E) 17
Rationale: Dividend on 20=(9/100*20)
=9/5
12 is an income on 100
9/5 is an income on (100/12*9/5)=15
Option C
Answer: (C) 15
Question: Alan buys 4 TVs, a 26 inch, a 28 inch, a 30 inch, and a 32 inch, for his new house. Each TV costs $200 more than the size below it. Alan spends a total of $4,400. How much would he have spent if he had bought only the 28 inch and 30 inch TVs?
(A) 850
(B) 1,100
(C) 1,700
(D) 2,200
(E) 3,400
Rationale: Assume the cost of the least sized (26 Inch) TV = x
Cost of 28 inches TV = x + 200
Cost of 30 inches TV = x + 400
Cost of 32 inches TV = x + 600
Total cost = 4x + 1200 = 4400
Therefore x = 3200/4 = 800
Price of 28inch + 30 inch = 1000 + 1200 = 2200
Option D
Answer: (D) 2,200
Question: If a and b are integers and (2^a)(3^b) is a factor of 900^40, what is the largest possible value of ab?
(A) 2a
(B) 5a
(C) 20a
(D) 40a
(E) 80a
Rationale: (2^a)(3^b) is a factor of 900^40
We need to find the largest possible value of ab.
We know that 900 = 2^2*5^2*3^2
Therefore 900^40 will have 2 powers of 3 in it.
Hence in (2^a)(3^b), b has to 2
Therefore value of ab = 2a
Correct Option: A
Answer: (A) 2a
Question: Aarti can do a piece of work in 9 days. In how many days will she complete three time of work of same type?
(A) 6 days
(B) 18 days
(C) 21 days
(D) 27 days
(E) 13 days
Rationale: We have the important relation, More work, More time (days)
A piece of work can be done in 9 days.
Three times of work of same type can be done in 9 x 3
= 27 days
Answer D
Answer: (D) 27 days
Question: 50 men do a work in 100days. How many men are needed to finish the work in 20days?
(A) 50
(B) 100
(C) 250
(D) 300
(E) 400
Rationale: men required to finish the work in 2days = 50*100/20 = 250
Answer is C
Answer: (C) 250
Question: Pipe A can fill a tank in 9 hours. Due to a leak at the bottom, it takes 12 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank?
(A) 36
(B) 88
(C) 18
(D) 26
(E) 12
Rationale: Let the leak can empty the full tank in x hours 1/9 - 1/x = 1/12
=> 1/x = 1/9 - 1/12 = 1/12
=> x = 36. Answer:A
Answer: (A) 36
Question: 85% of a number is added to 24, the result is the same number. Find the number?
(A) 28
(B) 288
(C) 279
(D) number=160
(E) 232
Rationale: ( 85/100) * X + 24 = X
3X = 480
X = 160
Answer:D
Answer: (D) number=160
Question: What is the units digit of (52^5)(37^3)(71^9)?
(A) 3
(B) 4
(C) 6
(D) 7
(E) 8
Rationale: The units digit of 52^5 is the units digit of 2^5 which is 2.
The units digit of 37^3 is the units digit of 7^3 which is 3.
The units digit of 71^9 is the units digit of 1^9 which is 1.
The units digit of 2*3*1 is 6.
The answer is C.
Answer: (C) 6
Question: In how many ways can 21 books on English and 19 books on Hindi be placed in a row on a shelf so that two books on Hindi may not be together?
(A) 3990
(B) 1540
(C) 1995
(D) 3672
(E) 2314
Rationale: We must place all these books as under:
XEXEX….XEX
There are 21 books on English, 19 books on Hindi
19 places out of 22 can be chosen 22C19=22C3=1540 ways
ANSWER B 1540
Answer: (B) 1540
Question: The average amount with a group of seven numbers is Rs. 20. If the newly joined member has Rs. 20 with him, what was the average amount with the group before his joining the group?
(A) s.17
(B) s.12
(C) s.15
(D) s.29
(E) s.20
Rationale: Total members in the group = 7
Average amount = Rs. 20
Total amount with them = 7 * 20 = Rs. 140
One number has Rs. 20. So, the amount with remaining 6 people = 140 - 20 = Rs. 20
The average amount with them = 120/6
= Rs.20.
Answer:E
Answer: (E) s.20
Question: If 1 tic equals 4 tacs and 5 tacs equal 8 tocs, what is the ratio of one tic to one toc?
(A) 15/2
(B) 6/5
(C) 5/6
(D) 32/5
(E) 1/15
Rationale: Tic=4*Tac and 5*Tac=8*Toc;
5*Tic=20*Tac and 20*Tac=32*Toc --> 5*Tic=32*Toc --> Tic/Toc=32/5.
Answer: D.
Answer: (D) 32/5
Question: In a class there are 20 boys and 30 girls. In how many ways can a boy and a girl be selected?
(A) 400
(B) 500
(C) 600
(D) 530
(E) 630
Rationale: Explanation:
We can select one boy from 20 boys in 20 ways.
We select one girl from 30 girls in 30 ways
We select a boy and girl in 20 * 30 ways i.e., = 600 ways.
Answer: Option C
Answer: (C) 600
Question: Two pipes A and B can separately fill a tank in 2 minutes and 15 minutes respectively. Both the pipes are opened together but 4 minutes after the start the pipe A is turned off. How much time will it take to fill the tank?
(A) 22
(B) 10 minutes
(C) 88
(D) 566
(E) 222
Rationale: 4/12 + x/15 = 1
x = 10.Answer: B
Answer: (B) 10 minutes
Question: Man1 alone can do a piece of work in 6 days and Man2 alone in 8 days. Man1 and Man2 undertook to do it for Rs. 3200. With the help of Man3, they completed the work in 3 days. How much is to be paid to Man3?
(A) 400
(B) 200
(C) 100
(D) 150
(E) 500
Rationale: Man3 1 day work = 1/3-(1/6+1/8) = 1/3-7/24 = 1/24
Man1 : Man2: Man3 = 1/6:1/8:1/24 ==>4:3:1
Man3 share = 3*1/24*3200 = Rs 400
ANSWER A
Answer: (A) 400
Question: A ratio between two numbers is 7:9 and their L.C.M. is 189. The Second number is
(A) 35
(B) 25
(C) 20
(D) 27
(E) None
Rationale: Sol.
Let the required numbers be 7x and 9x. Then, their L.C.M. is 63x.
∴ 63x = 189⇔ x = 3. Hence, the Second number is 27.
Answer D
Answer: (D) 27
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
(A) 11
(B) 50
(C) 88
(D) 65
(E) 22
Rationale: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr
= 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 45 ==> x
= 50 km/hr.
Answer:B
Answer: (B) 50
Question: 1.12.91 is the first Sunday. Which is the fourth Tuesday of December 91?
(A) 20.12.91
(B) 22.12.91
(C) 24.12.91
(D) 25.12.91
(E) None of these
Rationale: Explanation :
Given that 1.12.91 is the first Sunday
Hence we can assume that 3.12.91 is the first Tuesday
If we add 7 days to 3.12.91, we will get second Tuesday
If we add 14 days to 3.12.91, we will get third Tuesday
If we add 21 days to 3.12.91, we will get fourth Tuesday
=> fourth Tuesday = (3.12.91 + 21 days) = 24.12.91. Answer : Option C
Answer: (C) 24.12.91
Question: A rectangular parking space is marked out by painting three of its sides. If the length of the unpainted side is 9 feet, and the sum of the lengths of the painted sides is 37 feet, find out the area of the parking space in square feet?
(A) 124 sq.ft.
(B) 120 sq.ft.
(C) 126 sq.ft.
(D) 129 sq.ft.
(E) 132 sq.ft.
Rationale: Let l = 9 ft.
Then l + 2b = 37
=> 2b = 37 - l = 37 - 9 = 28
=> b = 28/2 = 14 ft
Area = lb = 9 × 14 = 126 sq. ft.
Answer is C.
Answer: (C) 126 sq.ft.
Question: Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction Q of the work will be done by Adam?
(A)  1/4
(B)  12/47
(C)  1/3
(D)  5/12
(E)  20/47
Rationale: Let the total work be 60 units. Pual does 60/3 =20 units of work per hr. abdul does 15 units per hr and adam does 12 units per hr. If all work together they do (20 + 15 + 12) units per hr = 47 units per hr. So the time taken to finish the work = 60/47 hrs.
adam will do 60/47 * 12 units of work in 60/47 hr . fraction of work adam does =work done by adam / total work
Q>( 60/47 *12)/60 =12/47
Answer B
Answer: (B)  12/47
Question: The average weight of 10 oarsmen in a boat is increased by 1.8 kg when one of the crew, who weighs 53 kg is replaced by a new man. Find the weight of the new man.
(A) 69
(B) 72
(C) 75
(D) 71
(E) None of them
Rationale: Total weight increased =(1.8 x 10) kg =18 kg.
:. Weight of the new man =(53 + 18) kg =71 kg.
Answer is D
Answer: (D) 71
Question: Which number, when found in the denominator of any given fraction, gives a terminating decimal?
(A) 2^3 * 3^4
(B) 5^2 * 7^3
(C) 2^4 * 11^3
(D) 5^3 * 11^2
(E) 2^4 * 5^3
Rationale: All the other choices except Option E have numbers other than 2 or 5.
Option E.
Answer: (E) 2^4 * 5^3
Question: A man sold 18 toys for Rs. 21000, gaining thereby the cost price of 3 toy find the cost price of a toy
(A) s. 600
(B) s. 800
(C) s.500
(D) s.900
(E) s. 1000
Rationale: Let the cost of one toy = X.
Then, cost of 18 toys = 18X.
Gain = 3X.
SP of 18 toys = Rs. 21000.
Gain = SP â€“ CP
3X = 21000 â€“ 18X
21X = 21000
X = Rs. 1000.
ANSWER : OPTION E
Answer: (E) s. 1000
Question: If the tens digit x and the units digit y of a positive integer n are reversed, the resulting integer is 45 more than n. What is y in terms of x ?
(A) x+5
(B) x+3
(C) x+4
(D) x-3
(E) x-4
Rationale: Original Digits=xy i.e. Number=10x+y
After reversing the digits:
Digits=yx i.e. Number=10y+x
10y+x is 45 more than 10x+y
10x+y+45=10y+x
10x-x+45=10y-y
9x+45=9y
x+5=y
OR
y=x+5
Answer : A
Answer: (A) x+5
Question: A man has Rs. 630 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
(A) 45
(B) 60
(C) 75
(D) 90
(E) 118.125
Rationale: Let number of notes of each denomination be x.
Then x + 5x + 10x = 630
16x = 630
x = 39.375.
Hence, total number of notes = 3x = 118.125.
Answer = E
Answer: (E) 118.125
Question: One-third of Rahul's savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,90,000 as total savings, how much has he saved in Public Provident Fund ?
(A) 80000
(B) 60000
(C) 50000
(D) 76000
(E) 90000
Rationale: Let savings in N.S.C and P.P.F. be Rs. x and Rs. (190000 - x) respectively. Then,
=1/3 x = 1/2 (190000 - x)
=x/3 + x/2 = 95000
=5x/6 = 95000
=x = 95000 x 6 /5	= 114000
Savings in Public Provident Fund = Rs. (190000 - 114000) = Rs. 76000
Answer is D
Answer: (D) 76000
Question: A shopkeeper buys mangoes at the rate of 6 a rupee and sells them at 5 a rupee. Find his net profit or loss percent?
(A) 33 1/8 %
(B) 33 7/3 %
(C) 33 1/3 %
(D) 33 5/8 %
(E) 20 %
Rationale: The total number of mangoes bought by the shopkeeper be 30.
If he buys 6 a rupee, his CP = 5
He selling at 5 a rupee, his SP = 6
Profit = SP - CP = 6 - 5 = 1
Profit Percent = 1/5 * 100 = 20 %
Answer: E
Answer: (E) 20 %
Question: In how many different number of ways 5 men and 3 women can sit on a shopa which can accommodate persons?
(A) A)160
(B) B)6720
(C) C)6570
(D) D)210
(E) E)230
Rationale: 8p2 =8 x 7 × 6 × 5 x4 =6720
Option 'B'
Answer: (B) B)6720
Question: The list price of an article is Rs.66. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?
(A) 3.45%
(B) 4.45%
(C) 5.45%
(D) 6.45%
(E) 7.45%
Rationale: 66*(90/100)*((100-x)/100) = 56.16
x = 5.45%
ANSWER:C
Answer: (C) 5.45%
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 30% profit on the first article and 30% loss on second article. Find the net profit or loss percent?
(A) 200
(B) 768
(C) 276
(D) 300
(E) 279
Rationale: Profit on first article = 30% of 1000 = 300.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer: D
Answer: (D) 300
Question: Excluding the stoppages, the speed of a bus is 12 km/hr and including the stoppages the speed of the bus is 6 km/hr. For how many minutes does the bus stop per hour?
(A) 15 min
(B) 30 min
(C) 12 min
(D) 20 min
(E) 18 min
Rationale: Speed of the bus without stoppage=12 km/hr
Speed of the bus with stoppage=6 km/hr
Difference in speed=6 km/hr
so,the time taken in the stoppages = time taken to cover 6 km=(6/12)hr = 1/2 hr =30 min
ANSWER:B
Answer: (B) 30 min
Question: A square is of side 1 km. A man travels first 2 sides with the 30 mph and third side with 60 kmph. What is the speed that man has to travel the fourth side if the average speed is 60 kmph
(A) 100 Kmph
(B) 110 Kmph
(C) 120 Kmph
(D) 130 Kmph
(E) 140 Kmph
Rationale: 1 Mile= 1.6 Km
Total time taken to travel 3 sides =(1/48)+(1/48)+(1/60)= 7/120 hr
time taken to travel 4 sides at avg speed= 1/15 hr
So, reqred speed for fourth side= 1/{(1/15)-(7/120)}= 120 Kmph
ANSWER:C
Answer: (C) 120 Kmph
Question: A library has an average of 510 visitors on Sunday and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is
(A) 250
(B) 276
(C) 280
(D) 285
(E) None
Rationale: Sol.
Since the month begins with a Sunday, so there will be five Sundays in the month.
∴ Required average = [510 x 5 + 240 x 25 / 30] = 8550 / 30 = 285
Answer D
Answer: (D) 285
Question: If a store adds 100 chairs to its current inventory, the total number of chairs will be the same as three-halves the current inventory of chairs. If the manager wants to increase the current inventory by 10%, what will the new inventory of chairs be?
(A) 40
(B) 60
(C) 100
(D) 140
(E) 220
Rationale: Explanation:
Letâ€™s say t = total current inventory of chairs. The first sentence states that 100 + t = (3/2)t. First solve for the current inventory:
100 + t = (3/2)t
100 = (3/2)t âˆ’ t
100 = (1/2)t
200 = t
The manager wants to increase this by 10%.
10% of 200 is 20, so the new inventory will be 220
Answer: E
Answer: (E) 220
Question: A can do a work in 24 days and B can do it in 12 days. In how many days A and B can do the work?
(A) 20 days
(B) 10 days
(C) 6 days
(D) 5 days
(E) 8 days
Rationale: Explanation:
A's 1day's work = 1/24
B's 1day's work = 1/12
They work together = 1/24 + 1/12 = 3/24 = 24/3 = 8 days
Answer: Option E
Answer: (E) 8 days
Question: How many prime numbers between 1 and 100 are factors of 143?
(A) 6
(B) 5
(C) 4
(D) 2
(E) 3
Rationale: factor of 143= 11*13--- 2 prime numbers
D
Answer: (D) 2
Question: Solve below question
y : 6y - 27 + 3y = 4 + 9 - y
(A) 2
(B) 4
(C) 6
(D) 7
(E) 8
Rationale: 9 y + y = 13 + 27
10 y = 40 => y = 4
B
Answer: (B) 4
Question: In the fifth grade at Parkway elementary school there are 420 students. 296 students are boys and 250 students are playing soccer. 86% of the students that play soccer are boys. How many girl student are in Parkway that is not playing soccer?
(A) 69.
(B) 73.
(C) 81
(D) 91
(E) 89
Rationale: Total students = 420
Boys = 296, Girls = 124
Total playing soccer = 250
86%of 250 = 215 are boys who play soccer.
Girls who play soccer = 35.
Total girls who do not play soccer = 124 - 35 = 89.
Correct option: E
Answer: (E) 89
Question: The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:10. If P invested the money for 5 months, find for how much time did Q invest the money?
(A) 29
(B) 10
(C) 28
(D) 20
(E) 11
Rationale: 7*5: 5*x = 7:10
x = 10
Answer: B
Answer: (B) 10
Question: what is the area of a circle having the same perimeter as that of a square whose area is 121.
(A) 306
(B) 307
(C) 308
(D) 309
(E) 310
Rationale: side of the square=sqrt(12)=11
perimeter of the square=44
2*pie*r=44
r=44/2*pie
area of the circle=pie*r^2=308
ANSWER:C
Answer: (C) 308
Question: A password for a computer uses five digits from 0 to 9, inclusive. What is the probability that the digits of the password solely consist of prime numbers or zero?
(A) A)1/32
(B) B)1/16
(C) C)1/8
(D) D)2/5
(E) E)1/2
Rationale: Favorable outcomes will be obtained by making Password using {0, 2, 3, 5, 7} i.e. 5 digits
Total Such Passwords = 5*5*5*5*5 = 5^5
Total Possible Password = 10*10*10*10*10 = 10^5
Probability = (5^5) / (10^5) = 1/2^5 = 1/32
Answer: option A
Answer: (A) A)1/32
Question: A train passes a man standing on the platform. If the train is 170 meters long and its speed is 72 kmph, how much time it took in doing so?
(A) 8 1/6 sec
(B) 8 1/9 sec
(C) 8 2/2 sec
(D) 8 1/2 sec
(E) 2 1/2 sec
Rationale: D = 170
S = 72 * 5/18 = 20 mps
T = 170/20 = 8 1/2 sec
Answer: D
Answer: (D) 8 1/2 sec
Question: Erik's mother gave him $86 to go to the store. Erik bought 3 loaves of bread and 3 cartons of orange juice. Each loaf of bread cost $3 and each carton of orange juice cost $6. How much money does Erik have left?
(A) $24
(B) $27
(C) $59
(D) $75
(E) $35
Rationale: Step 1: Find the cost of the loaves of bread.
3 × $3 = $9
Step 2: Find the cost of the orange juice.
3 × $6 = $18
Step 3: Find the total cost of the groceries.
$9 + $18 = $27
Step 4: Find the amount of money left.
$86 – $27 = $59
Erik has $59 left.
Answer is C.
Answer: (C) $59
Question: A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:
(A) 9 1/5 days
(B) 9 2/5 days
(C) 9 3/5 days
(D) 10
(E) 15
Rationale: Explanation:
(A + B + C)'s 1 day's work =	1/4
A's 1 day's work =	1/16
B's 1 day's work =	1/12
C's 1 day's work =	1/4-(1/16+1/12)=5/48
So, C alone can do the work in	48/5=9 3/5 days
ANSWER IS C
Answer: (C) 9 3/5 days