mathewhe/aqua_rat huggingface dataset:
Question: If a quarter kg of potato costs 60 yen, how many paise will 200 gm cost?
(A) yen 49
(B) yen 40
(C) yen 50
(D) yen 48
(E) yen 41
Rationale: D
yen 48
Let the required weight be x kg.
Less weight, Less cost (Direct Proportion)
250 : 200 :: 60 : x 250 x x = (200 x 60)
x= (200 x 60)/250
x = 48
Answer: (D) yen 48
Question: After decreasing 24% in the price of an article costs Rs.912. Find the actual cost of an article?
(A) 1400
(B) 1300
(C) 1200
(D) 1100
(E) 1500
Rationale: CP* (76/100) = 912
CP= 12 * 100 => CP = 1200
ANSWER:C
Answer: (C) 1200
Question: There are 50 doors marked with numbers 1 to 50. And there are 50 individuals marked 1 to 50.
An operation on a door is defined as changing the status of the door from open to closed or vice versa. All doors are closed to start with.
Now one at a time one randomly picked individual goes and operates the doors. The individual however operates only those doors which are a multiple of the number he/she is carrying. For e.g. individual marked with number 5 operates the doors marked with the following numbers: 5, 10, 15 ... 50.
If every individual in the group get one turn then how many doors are open at the end?
(A) 0
(B) 1
(C) 2
(D) 4
(E) 7
Rationale: Let us start with 1.
When 1 goes, all the doors are open since every number is a multiple of 1.
Also 1 will remain opened since 1 is not a multiple of any number.
Prime numbers can only be operated by people with prime numbers.
So 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47 will be closed when people with respective numbers perform operations on them.
From the other numbers, only those numbers will remain opened on which even number of operations are performed including the operation performed by number 1.
This is possible only for perfect squares which are 4,9, 16,25,36 and 49.
So our numbers are 1,4,9,16,25,36 and 49.
Answer:- E
Answer: (E) 7
Question: A hiker walked for 3 days. She walked 18 miles on the first day, walking 3 miles per hour. On the second day she walked for one less hour but she walked one mile per hour, faster than on the first day. On the third day 5 miles per hour for 6 hours. How many miles in total did she walk?
(A) 68
(B) 44
(C) 58
(D) 60
(E) 62
Rationale: First day - 18 miles with 3 miles per hours then total - 6 hours for that day
Second day - 4 miles per hour and 5 hours - 20 miles
Third day - 5 miles per hour and 6 hours - 30 miles
Total 18+20+30 = 68
Answer: option A.
Answer: (A) 68
Question: A cat leaps 6 leaps for every 5 leaps of a dog, but 2 leaps of the dog are equal to 3 leaps of the cat. What is the ratio of the speed of the cat to that of the dog?
(A) 4:5
(B) 2:3
(C) 4:1
(D) 1:9
(E) 3:2
Rationale: Given;
2 dog = 3 cat;
Or, dog/cat = 3/2;
Let cat's 1 leap = 2 meter and dogs 1 leap = 3 meter.
Then, ratio of speed of cat and dog = 2*6/3*5 = 4:5''Answer: 4:5;
Answer: (A) 4:5
Question: If 20% of certain quantity of work is done by A and the rest 80% by B, the work is completed in 20 days. If 80% of the work is done by A and the remaining 20% by B, then the work is completed in 30 days. How many days are required to complete the work , if A and B work together.
(A) 11 1/9
(B) 10 1/9
(C) 12
(D) 15
(E) Source: TIME material.
Rationale: Use algebra:
0.2/A + 0.8/B = 20
1 /A + 4/B = 100
0.8/A + 0.2/B = 30
4/A+ 1/B = 150
15/B = 250
B = 3/50 work per day
A = 3/100 work per day
Combined rate = 3/40 + 3/100 = 9/100
Time taken when working together = 100/9 = 11(1/9) days
Answer (A)
Answer: (A) 11 1/9
Question: Kate and Danny each have $10. Together, they flip a fair coin 5 times. Every time the coin lands on heads, Kate gives Danny $1. Every time the coin lands on tails, Danny gives Kate $1. After the five coin flips, what is the probability that Kate has more than $10 but less than $15?
(A) 5/16
(B) 1/2
(C) 12/30
(D) 15/32
(E) 3/8
Rationale: the probability of the coin landing tails up either 3 or 4 times = P(3t) + P(4t)
Binomial distribution formula: nCk p^k (1-p)^(n-k)
P(3t) = 5C3 (1/2)^3 (1/2)^2 = 10 (1/2)^5
P(4t) = 5C4 (1/2)^4 (1/2)^1 = 5 (1/2)^5
=> P(3t) + P(4t) = 15/32
Answer:D
Answer: (D) 15/32
Question: How many quarters are equal to 2 dollars?
(A) 1
(B) 8
(C) 12
(D) 9
(E) 7
Rationale: B. 8 quarters
Answer: (B) 8
Question: I walk a certain distance and ride back taking a total time of 37 minutes. I could walk both ways in 55 minutes. How long would it take me to ride both ways?
(A) 20mins
(B) 19mins
(C) 5mins
(D) 4mins
(E) 12mins
Rationale: Let the distance be x km. Then,
( Time taken to walk x km) + (time taken to ride x km) =37 min.
( Time taken to walk 2x km ) + ( time taken to ride 2x km )= 74 min.
But, the time taken to walk 2x km = 55 min.
Time taken to ride 2x km = (74-55)min =19 min.
Ans: B
Answer: (B) 19mins
Question: A shop owner professes to sell his articles at certain cost price but he uses false weights with which he cheats by 20% while buying and by 20% while selling. What is his percentage profit?
(A) 10.22%
(B) 20.22%
(C) 21.22%
(D) 50%
(E) Can't be calculated
Rationale: The owner buys 100 kg but actually gets 120kg;
The owner sells 100 kg but actually gives 80kg;
Profit: (120-80)/80*100=~50%
Answer: D.
Answer: (D) 50%
Question: If a quarter kg of potato costs 60 paise, how many paise will 200 gm cost?
(A) 54 paise
(B) 48 paise
(C) 72 paise
(D) 28 paise
(E) 36 paise
Rationale: Let the required weight be x kg.
Less weight, Less cost (Direct Proportion)
250 : 200 :: 60 : x 250 x x = (200 x 60)
x=	(200 x 60)/250
x = 48.
Answer is B
Answer: (B) 48 paise
Question: A rectangular plot measuring 90 metres by 60 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed ?
(A) 55
(B) 56
(C) 60
(D) 58
(E) None of these
Rationale: Solution
Perimeter of the plot = 2(90 + 60) = 300 m.
∴ Number of poles = [300/5] =60m Answer C
Answer: (C) 60
Question: A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
(A) 320
(B) 600
(C) 700
(D) 350
(E) 500
Rationale: Speed = 300/18 m/sec = 50/3 m/sec
(x+300/39) = 50/3
x=350 m
ANSWER D
Answer: (D) 350
Question: A football field is 10800 square yards. If 1200 pounds of fertilizer are spread evenly across the entire field, how many pounds of fertilizer were spread over an area of the field totaling 3600 square yards?
(A) 400
(B) 600
(C) 750
(D) 2400
(E) 3200
Rationale: Answer A) 10800 yards need 1200 lbs
1 Yard will need 1200/10800 = 1/9 lbs
3600 Yards will need 1/9* 3600 Yards = 400lbs
Answer: (A) 400
Question: A man took some money for borrowed, for 3 years the total will be Rs.4500 and 5 years it will be Rs.5500/-. Then how much amount he borrowed?
(A) s.2000/-
(B) s.2500/-
(C) s.2770/-
(D) s.2800/-
(E) s.3000/-
Rationale: 3 years --------> Rs.4500/-
5 years --------> Rs.5500/-
~ ~
------------------------------
2 years ---------> Rs.1000/-
1 year ----------> Rs.500/-
3years * Rs.500/- = Rs.1500/-
P = Rs.4500/- - Rs.1500/- = Rs.3000/-
P = Rs.3000/-
E
Answer: (E) s.3000/-
Question: In the following sum, “?”, stands for which digit?
? + 1? + 2? + ?3 + ?1 = 21?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: let the digit be x. so the series becomes:
x + (10 + x) + (20 + x) + (10x+3) + (10x + 1)=210 + x
=> 23x + 34 = 210 + x
=> 22x = 176
=>x = 176/22 = 8
ANSWER:E
Answer: (E) 8
Question: A circle is circumscribed around a quadrilateral, and the quadrilateral is ABCD, What is the value of w when angle C is 125 degrees?
(A) 45
(B) 55
(C) 65
(D) 75
(E) 85
Rationale: An inscribed angle is an angle in a circle composed of two chords with a common endpoint, that is, an angle with its vertex on the circle. In this problem, all four lettered angles are inscribed angles.
An inscribed angle necessarily opens to intersect an arc (the technical word is to subtend an arc). The Inscribed Angle Theorem said that the measure of an inscribed angle is always half the measure of the arc it intersects, or subtends.
angle C = 125 degrees
Thus,
arc DAB = 250 degrees
A whole circle has 360 degrees of arc, so arc BCD should be the rest of the circle.
arc BCD = 360 - 250 = 110 degrees
The angle that intersects this arc, angle A, should have half this measure.
angle A = w = 110/2 = 55 degrees
Answer =(B)
Answer: (B) 55
Question: If (10^4 * 3.456789)^11 is written as a single term, how many digits would be to the right of the decimal place?
(A) 12
(B) 18
(C) 22
(D) 28
(E) 36
Rationale: 3.456789^11 has 6*11 = 66 decimal places.
10^44 moves the decimal place to the right 44 places.
(10^4 * 3.456789)^11 has 66-44 = 22 digits after the decimal point.
The answer is C.
Answer: (C) 22
Question: The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. What is the average of the remaining two numbers ?
(A) 3.6
(B) 4.6
(C) 6.5
(D) 7.3
(E) None of these
Rationale: Explanation:
Sum of the remaining two numbers = (3.95 * 6) - [(3.4 * 2) + (3.85 * 2)]
= 23.70 - (6.8 + 7.7) = 23.70 - 14.5 = 9.20.
Required average = (9.2 / 2) = 4.6. Answer: B
Answer: (B) 4.6
Question: If 6 yrs are subtracted from the present age of John & the remainder is divided by 18, then the presentage of his grandson Anup is obtained. If Anup is 2 years younger to Madan whose age is 5 yrs, then whatis John’s present age?
(A) 20
(B) 30
(C) 60
(D) 70
(E) 80
Rationale: Sol. Anup's age = (5 - 2) years = 3 years. Let Gagan's age be x years.
Then, (x-6)/18 = 3 => x-6 = 54 x = 60.
C
Answer: (C) 60
Question: A person saved $10 in buying an item on sale. If he spent $200 for the item, approximately how much percent he saved in the transaction?
(A) 8%
(B) 10%
(C) 2%
(D) 5%
(E) 6%
Rationale: Actual price = 200+10 = $210
Saving = 10/210 * 100 = 100/21 = 5% approximately
Answer is D
Answer: (D) 5%
Question: The respective ages of father and his son are 42 and 16 years. In how many years will the father be twice as old as his son ?
(A) 19 years
(B) 9 years
(C) 10 years
(D) 15 years
(E) 12 years
Rationale: Suppose x years later the father will be twice as old as his son.
x + 42 = 2 (x + 16)
x = 42 - 32 = 10 years
answer : C
Answer: (C) 10 years
Question: At a certain hospital, 75% of the interns receive fewer than 6 hours of sleep and report feeling tired during their shifts. At the same time, 70% of the interns who receive 6 or more hours of sleep report no feelings of tiredness. If 80% of the interns receive fewer than 6 hours of sleep, what percent W of the interns report no feelings of tiredness during their shifts?
(A) 6
(B) 14
(C) 19
(D) 20
(E) 81
Rationale: < 6 hours sleep>= 6 hours sleepTOTAL
Tired75--
Not Tired-0.7*X?
TOTAL80X100
Interns who receive< than 6 hours sleepandNot Tired= 80 - 75 = 5;
TOTAL interns who receive >= 6 hours sleep= 100 - 80 = 20, so interns who receive>= 6 hours sleepand areNot Tired= 0.7 * 20 =14;
Interns who areNot Tired W= 5 + 14 = 19.
Answer: C.
Answer: (C) 19
Question: If $100 is invested at x percent simple annual interest for n years, which of the following represents the total amount of interest, in dollars, that will be earned by this investment in the n years?
(A) 10,000(x^n)
(B) 10,000(x/100)^n
(C) 100n(x/100)
(D) 10,000(1+x/100)^n
(E) 10,000n(1+x/100)
Rationale: I think answer D is for compound interest (which i assumed)
and answer C is for simple interest because it is not compounding
Answer: (C) 100n(x/100)
Question: A cylindrical container of radius 6 cm and height 15 cm is filled with ice-cream. The whole icecream has to be distributed to 10 children in equal cones with hemispherical tops. If the height of the conical portion is four times the radius of its base, find the radius of the ice-cream cone.
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: volume of given ice cream =(pie)*6²*15=540(pie)
dividing to 10 children volume given to a child =54(pie)
let r be radius and h be the height of the cone,then
(pie)r²h/3 + 2(pie)r³/3=54(pie)
also given h=4r
4r³/3 +2r³/3=54
2r³=54
r³=27
r=3
ANSWER:C
Answer: (C) 3
Question: In Net's hair salon 48% of the customers dye their hair blond, 36% dye their eyebrows blond and 35% straighten their hair. 20% of the customers have none of these three procedures, while 12% take all of these three procedures. What percent of the customers come for exactly 2 of these 3 procedures?
(A) 5%
(B) 9%
(C) 12%
(D) 15%
(E) 21%
Rationale: Let a total of 100 people visit the salon.
Total = 100
Dye hair blonde (A) = 45 % = 45
Dye Eyebrows blonde (B) = 36% = 36
Straighten Hair (C) = 35% = 35
Neither = 20% = 20
All Three = 12% =12
Total = A+B+C - (Sum of Exactly Two group overlaps) - 2*(All three) + Neither
100 = 45+36+35 - (Sum of Exactly Two group overlaps) - 2*12 + 20
(Sum of Exactly Two group overlaps) = 9
%of customers coming for exactly 2 of the 3 procedures = 15%
D
Answer: (D) 15%
Question: A shop owner sells 60mtr of cloth and gains SP of 10 mtrs. Find the gain %?
(A) 20%
(B) 40%
(C) 50%
(D) 60%
(E) 70%
Rationale: Here, selling price of 10 m cloth is obtained as profit.
Profit of 10 m cloth = (S.P. of 60 m cloth) – (C.P. of 60 m cloth)
Selling price of 50 m cloth = Selling Price of 60 m of cloth
Let cost of each metre be Rs. 100.
Therefore, cost price of 50 m cloth = Rs. 5000 and S.P. of 50 m cloth = Rs. Rs. 6000
Profit% = 10/50 × 100 = 20%
20
Profit of 20% was made by the merchant.
A
Answer: (A) 20%
Question: One hour before John started walking from P to Q, a distance of 28 miles, Ann had started walking along the same road from Q to P. Ann walked at a constant speed of 3 miles per hour and John at 2 miles per hour. How many miles had Ann walked when they met?
(A) 6 miles
(B) 8,4 miles
(C) 9 miles
(D) 9,6 miles
(E) 18 miles
Rationale: Ann walks from Q to P at a speed of 3 miles/hr for one hour. She covers 3 miles in 1 hour and now distance between John and Ann is 28 - 3 = 25 miles.
Ann walks at 3 mph and John at 2 mph so their relative speed is 3+2 = 5 mph.
They have to cover 25 miles so it will take them 25/5 = 5 hours to meet.
In 5 hrs, Ann would have covered 5 hrs * 3 miles per hour = 15 miles.
Adding this to the 3 miles she covered before John, Ann covered a total of 3 + 15 = 18 miles.
Answer (E)
Answer: (E) 18 miles
Question: If a fair die is rolled two times, what is the probability that a 3 occurs on at least one roll?
(A) 25/36
(B) 125/216
(C) 91/216
(D) 11/36
(E) 36/216
Rationale: Questions such as these that talk aboutat leastormaximumorminimumin probability questions should make sure realize that probability of any event (N) to occur = 1- P(Not N)
Thus, the probability of at least 1 roll = 1- Probability of NO 3s = 1- (5/6)(5/6) = 1-25/36 = 11/36.
5/6 is the probability of NOT getting a 3 in any 1 roll with 5 allowed numbers (=1,2,4,5,6) out of a total of 6 possibilities.
D is thus the correct answer.
Answer: (D) 11/36
Question: In 1937, the ship of the great sailor SINBAD left an Egyptian port heading Ivory coast at R mile/month .
One month later another ship of the greatest pirate ever CHENG I SAO was 5000 miles due south of the same Egyptian port and heading due north at Y miles/month. Six months later after the leaving of Sinbad’s ship from Egyptian port, how far apart were the ships? [Ivory coast is in the west of Egypt]
(A) { (6R)^2 + (5000-5y)^2 }^1/2
(B) { (36x)^2 + (5000-7y)^2 }^1/2
(C) { (16x)^2 + (5000-7y)^2 }^1/2
(D) { (7x)^2 + (5200-7y)^2 }^1/2
(E) { (2x)^2 + (300-7y)^2 }^1/2
Rationale: The chinese ship sailed for 5 months i.e. 5Y miles @Y miles/month, therefore distance from Egyptian port is 5000-5Y. Since A is the only option with this value ...therefore A is the answer
Answer: (A) { (6R)^2 + (5000-5y)^2 }^1/2
Question: The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. What is the period (in years)?
(A) 1
(B) 2
(C) 3
(D) 3.5
(E) 5
Rationale: Explanation:
Let the period be n years
Then, amount after n years = Rs.(30000 + 4347) = Rs. 34347
P(1+R/100)T=34347
30000(1+7/100)n=34347
30000(107100)n=34347
(107/100)n=34347/30000=11449/10000=(107/100)2
n=2 years
Answer: Option B
Answer: (B) 2
Question: A sum of money becomes 7/6 of itself in 7 years at a certain rate of simple interest. The rate per annum is?
(A) 50/13
(B) 50/17
(C) 50/19
(D) 50/21
(E) 50/23
Rationale: Let sum = x. Then, amount = 7x/6
S.I. = 7x/6 - x = x/6; Time = 7 years.
Rate = (100 * x) / (x * 6 * 7) = 50/21 %.
Answer:D
Answer: (D) 50/21
Question: Ashok secured average of 77 marks in 6 subjects. If the average of marks in 5 subjects is 74, how many marks did he secure in the 6th subject?
(A) 38
(B) 27
(C) 92
(D) 17
(E) 80
Rationale: Explanation:
Number of subjects = 6
Average of marks in 6 subjects = 77
Therefore total marks in 6 subjects = 77 * 6 = 462
Now, No. of subjects = 5
Total marks in 5 subjects = 74 * 5 = 370
Therefore marks in 6th subject = 462 – 370 = 92
ANSWER: C
Answer: (C) 92
Question: In the x-y plane, the area of the region bounded by the graph of |x+y| + |x-y| = 10 is
(A) 8
(B) 625
(C) 16
(D) 20
(E) 24
Rationale: I've never seen such kind of question in GMAT before.
OK there can be 4 cases:
|x+y| + |x-y| = 10
A. x+y+x-y = 10 --> x=5
B. x+y-x+y = 10 --> y=5
C. -x-y +x-y= 10 --> y=-5
D. -x-y-x+y=10 --> x=-5
The area bounded by 4 graphs x=5, x=-5, y=5, y=-5 will be square with the side of 4 so the area will be25*25=625
Answer: B
Answer: (B) 625
Question: On a baseball team, 11 players including Alice want to play 1st base, 2nd base, or 3rd base. Before every game, the coach chooses a name randomly from a bag and this person plays 1st base. Then the coach chooses the next name randomly and this person plays 2nd base. The coach then chooses a third name randomly and this person plays 3rd base. What is the probability that Alice plays 1st, 2nd, or 3rd base?
(A) 1/8
(B) 3/8
(C) 1/11
(D) 2/11
(E) 3/11
Rationale: Each of the 11 players has an equal chance to be chosen to play 1st, 2nd, or 3rd base.
Each game, three players out of eleven are chosen randomly.
The probability that a player is chosen to play one of the three bases is 3/11.
The answer is E.
Answer: (E) 3/11
Question: A can do a piece of work in 6 days and B can do it in 6 days how long will they both work together to complete the work?
(A) 6/11
(B) 1/2
(C) 3/4
(D) 9/11
(E) 10/11
Rationale: Explanation:
A’s one day work = 1/5
B’s one day work = 1/6
(A+B)’s one day work = 1/6 + 1/6 = 2/3= => time = 3/2 = 1 1/2 days
Answer: Option B
Answer: (B) 1/2
Question: The average of first five multiples of 2 is :
(A) 3
(B) 9
(C) 12
(D) 15
(E) E
Rationale: Solution
Average = 2(1+2+3+4+5)/5 =30/5 =6 Answer E
Answer: (E) E
Question: Three gentlemen and three ladies are candidates for two vacancies. A voter has to vote for two candidates. In how many ways can one cast his vote?
(A) 9
(B) 30
(C) 36
(D) 15
(E) None
Rationale: Solution: There are 6 candidates and a voter has to vote for any two of them.
So, the required number of ways is,
= 6C2 = 6!/2!*4!
= 15.
Answer: Option D
Answer: (D) 15
Question: There were two candidates in an election. Winner candidate received 58% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate?
(A) 776
(B) 1044
(C) 299
(D) 257
(E) 125
Rationale: W = 58% L = 42%
58% - 42% = 16%
16% -------- 288
58% -------- ? => 1044
Answer:B
Answer: (B) 1044
Question: A school has 4 section of Chemistry in Class X having 55, 35, 45 and 42 students. The mean marks obtained in Chemistry test are 50, 60, 55 and 45 respectively for the 4 sections. Determine the overall average of marks per student.
(A) 50.15
(B) 52.06
(C) 51.25
(D) 53.06
(E) None of the above
Rationale: Required average marks
= 55Ã—50+35Ã—60+45Ã—55+42Ã—45/55+35+45+42
= 2750+2100+2475+1890/162
= 9215â„177 = 52.06
Answer B
Answer: (B) 52.06
Question: The tax on a commodity is diminished by 15% and its consumption increased by 10%. The effect on revenue is?
(A) 8.5
(B) 6.5
(C) 5.5
(D) 5.6
(E) 4.4
Rationale: 100 * 100 = 10000
85 * 110 = 9350
-----------
10000-----------650
100-----------? => 6.5% decrease
Answer:B
Answer: (B) 6.5
Question: From the set of numbers x, y, t, z, s and w, how many different combinations can we have without the t in them? Ex:. (x,y), (x), (w,z,y,x,s), etc and (x,y)=(y,x)
(A) 10
(B) 14
(C) 15
(D) 16
(E) 31
Rationale: Another way: Any letter (x, y, z, w, s) can be included or not. So, we have 2^5 combinations - 1 empty combination = 31 combinations
E
Answer: (E) 31
Question: A takes twice as much time as B & C takes thrice as much time as B to finish a piece of work. Working together they can finish the work in 18 days. The no. of days need for B to do the work alone is?
(A) 30 days
(B) 31 days
(C) 33 days
(D) 41 days
(E) 52 days
Rationale: Let A takes x days to complete the work , then B takes
x/2
days and C takes
3x/2
days to complete the work.
A,B and C together complete the work in 18 days
In 1 day , all they together can do => 1/x+ 2/x+ 2/3x
= 1/18
3+6+2/3x = 1/18
3x23x2 = 18
X = 66 days
The number of days B alone takes to finish the work = x/2
= 33 days
C
Answer: (C) 33 days
Question: A fort had provision of food for 150 men for 45 days. After 15 days, 10 men left the fort. The number of days for which the remaining food will last, is:
(A) 32
(B) 37	1/4
(C) 42
(D) 54
(E) 45
Rationale: we have food for 150 men for 45 days.
After 15 days food left for 150 men for 30 days.
so
150 : 30
now we have 140 men and x days
140 : 150 :: 30 : x
x = (150*30)/140 = 32 days.
ANSWER:A
Answer: (A) 32
Question: The simple interest on a sum of money will be Rs.600 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year?
(A) 1209
(B) 6677
(C) 1200
(D) 3356
(E) 3235
Rationale: P --- 10 ---- 600
P --- 5 ----- 300
3P --- 5 ----- 900
------
=> 1200
Answer:C
Answer: (C) 1200
Question: Train A and Train B began traveling towards each other from opposite ends of a 500-mile long track at 1:00 PM. If Train A traveled at 35 miles per hour and Train B traveled at 15 miles per hour, at what time did the trains meet?
(A) 5:40 PM
(B) 6:00 PM
(C) 7:20 PM
(D) 11:00 PM
(E) 9:20 PM
Rationale: This question tests your concepts of relative speed:
If two trains are moving in opposite direction, then distance will reduce at a rate of (Speed of 1 + Speed of 2)
If two trains are moving in same direction, then distance will reduce at a rate of (Speed of 1 - Speed of 2)
Here the trains are moving towards each other, hence in opposite direction.
Trains will cover the 500 mile track in a time of 500/(15 + 35) = 500/50 = 10 hours
Trains started at 1:00 PM, there they will meet at 11:00 PM
Option D
Answer: (D) 11:00 PM
Question: Five Siblings are to be seated in a round table for lunch. If Daniel and David are among the five siblings, what is the probability that they sit next to each other
(A)  5%
(B)  10%
(C)  15%
(D)  20%
(E)  25%
Rationale: Possible Sitting position is 5! = 120
Daniel and David sitting next to each other is 5 Combination 2
=5!/2!(5-2)!
=120/2(6)
=120/12
= 10
Answer = B
Answer: (B)  10%
Question: During a sale, the price of a pair of shoes is marked down 10% from the regular price. After the sale ends, the price goes back to the original price. What is the percent of increase to the nearest percent from the sale price back to the regular price for the shoes?
(A) 9%
(B) 10%
(C) 11%
(D) 15%
(E) 90%
Rationale: Assume the price = 100
Price during sale = 90
Price after sale = 100
Percent increase = 10/90*100 = 11% approx.
Correct Option: C
Answer: (C) 11%
Question: Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.76800?
(A) 81000
(B) 97200
(C) 27772
(D) 29889
(E) 22312
Rationale: 76800* 9/8 * 9/8 = 97200.Answer:B
Answer: (B) 97200
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 6 boys when a boy gets any no. of prizes?
(A) 216
(B) 220
(C) 289
(D) 240
(E) 200
Rationale: Ans.(A)
Sol. In this case, repetitions are allowed, so all the three prizes can be given in 6 ways, i.e. (6 x 6 x 6) ways = 63 ways = 216 ways Or nr ways = 63 ways = 216 ways
Answer: (A) 216
Question: What distance will be covered by a bus moving at 72 kmph in 30 seconds?
(A) 416.66 m
(B) 516.66 m
(C) 250 m
(D) 616.66 m
(E) 716.66 m
Rationale: 62 kmph = 62 * 5/18 = 17.22 mps
D = Speed * time = 17.22 * 30 = 516.66 m.
ANSWER:B
Answer: (B) 516.66 m