mathewhe/aqua_rat huggingface dataset:
Question: A girl walks at a speed of 5 kmph. How much time does he take to walk a distance of 30 km?
(A) 10hrs
(B) 2hrs
(C) 3hrs
(D) 5hrs
(E) 6hrs
Rationale: Time = Distance / speed = 30/5= 6 hours.
Answer is E
Answer: (E) 6hrs
Question: Bruce purchased 8kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 55 per kg. How much amount did he pay to the shopkeeper?
(A) 1040
(B) 1050
(C) 1055
(D) 1065
(E) 1075
Rationale: Cost of 8 kg grapes = 70 × 8 = 560.
Cost of 9 kg of mangoes = 55 × 9 = 490.
Total cost he has to pay = 560 + 490 = 1055
C
Answer: (C) 1055
Question: After his first semester in college, Thomas is applying for a scholarship that has a minimum Grade Point Average (GPA) requirement of 3.5. The point values of pertinent college grades are given in the table below. If Thomas took 4 courses, each with an equal weight for GPA calculations, and received two grades of A-, one grade of B+, and one grade of B, what is the lowest grade that Thomas could receive for his fifth class to qualify for the scholarship?
Point Values of Select Grades
Grade: A | A- | B+ | B | B- | C+ | C | C-
Value: 4 | 3.7 | 3.3 | 3 | 2.7 | 2.3 | 2 | 1.7
(A)  A
(B)  B+
(C)  B
(D)  B-
(E)  C+
Rationale: Grade: A | A- | B+ | B | B- | C+ | C | C-
Value: 4 |3.7|3.3|3| 2.7 | 2.3 | 2 | 1.7
7.4 + 3.3 + 3 + x = 3.5 * 5
x = 17.5 - 13.7 = 3.8
Grade A is required to qualify
Answer = B
C
Answer: (C)  B
Question: If x and y are positive integers and 180x=y^3, which of the following must be an integer?
I. x/(2^2*3*5)
II. x/(2*3^2*5)
III. x/(2*3*5^2)
(A) None
(B) I only
(C) II only
(D) III only
(E) I and II
Rationale: x and y are integers and 180x=y^3 --> 180x equals to cube of an integer (y^3).
180x=2^2∗3^2∗5∗x=y^3 ,The smallest value of x for which 2^2∗3∗5∗x is a cube of an integer is when x=2∗3∗5^2.to complete powers of 2, 3 and 5 to cubes).
In this case 180x=(2^2∗3^2∗5)∗(2∗3∗5^2)=(2∗3∗5)^3=cube of an integer So x is definitely divisible by 2∗3∗5^2
Answer: D.
Answer: (D) III only
Question: A man can row 6.6 kmph in still water and he finds that it takes him twice as long to row up as to row down the river. Find the rate of stream.
(A) 2.2 km/hr
(B) 12.5 km/hr
(C) 1 2.6 km/hr
(D) 22.5 km/hr
(E) 22.6 km/hr
Rationale: Given that, time taken to travel upstream = 2 × time taken to travel downstream
When distance is constant, speed is inversely proportional to the time
Hence, 2 × speed upstream = speed downstream
Let speed upstream = x
Then speed downstream = 2x
we have, 1/2(x+2x) = speed in still water
⇒1/2(3x)=6.6
3x = 13.2
x = 4.4
i.e., speed upstream = 4.4 km/hr
Rate of stream = 1/2(2x−x)=x/2=4.4/2=2.2 km/hr
Answer is A
Answer: (A) 2.2 km/hr
Question: 11 friends are living in 11 different flats of an apartment. Each of them was allotted a parking spot to park their cars in the ground floor. But they used to park their cars randomly in any of the 11 parking spots. In how many ways can they park their cars so that exactly 9 people park their cars in the spots allotted to them?
(A) 40
(B) 45
(C) 50
(D) 55
(E) 60
Rationale: 11C9 = 55
The remaining 2 people in each case will be parked in each other's parking spots.
The answer is D.
Answer: (D) 55
Question: A cube of edge 8 cm is cut into cubes each of edge 1 cm. The ratio of the total surface area of one of the small cubes to that of the large cube is equal to:
(A) 1:25
(B) 1:22
(C) 1:52
(D) 1:64
(E) None
Rationale: Sol.
Required ratio = 6 * 1 * 1 / 6 * 8 * 8 = 1/64 = 1:64.
Answer D
Answer: (D) 1:64
Question: What will come in place of the x in the following Number series? 6, 12, 24, x , 66
(A) 42
(B) 40
(C) 46
(D) 41
(E) 43
Rationale: (A)
The pattern is + 6, + 12, + 18, +24 â€¦â€¦â€¦..
So the missing term is = 24+ 18 = 42
Answer: (A) 42
Question: Find the no.of ways of arranging the boy and 7 guests at a circular table so that the boy always sits in a particular seat?
(A) 7!
(B) 8!
(C) 9!
(D) 10!
(E) 11!
Rationale: Ans.(A)
Sol. Total number of persons = 8 Host can sit in a particular seat in one way. Now, remaining positions are defined relative to the host. Hence, the remaining can sit in 8 places in 7P7 = 7! Ways ... The number of required arrangements = 7! x 1= 7! = 7! ways
Answer: (A) 7!
Question: m and n are the x and y coordinates, respectively, of a point in the coordinate plane. If the points (m, n) and (m + p, n + 4) both lie on the line defined by the equation x = (y/2) - (2/5), what is the value of p?
(A) 4/5
(B) 1
(C) 2
(D) 5
(E) 8
Rationale: (m,n)
m = x
n = y
m = n/2 - 2/5
10m = 5n - 4 (multiplied by 10 to simplify equation)
(m+p, n+4)
m + p = x
n + 4 = y
m+p = (n+4)/2 - 2/5
multiplied by 10 again
10m + 10P = 5n + 20 - 4
use both equations to solve for p and you get 10p = 20
p = 2
ANSWER:C
Answer: (C) 2
Question: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
(A) 128.5 m
(B) 127.5 m
(C) 127.7 m
(D) 127.9 m
(E) 227.5 m
Rationale: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs
= (900 * 700)/800 = 6300/8 = 787.5 m.
In a race of 1000 m, A beats C by (1000 - 787.5)
= 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C
= (600 * 212.5)/1000 = 127.5 m.
Answer:B
Answer: (B) 127.5 m
Question: In how many ways, a committee of 5 members can be selected from 6 men and 5 ladies, consisting of 3 men and 2 ladies?
(A) 150
(B) 320
(C) 200
(D) 140
(E) 123
Rationale: (3 men out 6) and (2 ladies out of 5) are to be chosen.
Required number of ways = (6c3x5c2)
= [6x5x4/3x2x1] x [5x4/2x1] = 200.
Ans: C
Answer: (C) 200
Question: List I: 1, 6, 8, 19
List II: x, 1, 6, 8, 19
(A) 5
(B) 6
(C) 7
(D) 9
(E) 10
Rationale: List I has even number of terms, thus its median is the average of two middle terms (when arranged in ascending/descending order), so median=(6+8)/2=7.
List II has odd number of terms, thus its median is the middle term (when arranged in ascending/descending order). As no other number in the list equal to 7, then x=7.
Answer: C.
Answer: (C) 7
Question: Two trains travelling in the same direction at 60 and 42 kmph completely pass off another in 1 minute. If the length of the first train is 120 m, what is the length of the second train?
(A) 228
(B) 266
(C) 175
(D) 180
(E) 171
Rationale: RS = 60 â€“ 42 = 18 * 5/18 = 5 mps
T = 60 sec
D = 5 * 60 = 300 m
120
--------
180 m
Answer: D
Answer: (D) 180
Question: A man is 30 years older than his son. In four years, his age will be twice the age of his son. The present age of this son is
(A) 22 years
(B) 23 years
(C) 24 years
(D) 25 years
(E) 26 years
Rationale: Explanation:
Let's Son age is x, then Father age is x+30.
=> 2(x+4) = (x+30+4)
=> 2x+8 = x+34
=> x = 26 years
Answer: Option E
Answer: (E) 26 years
Question: A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 50%?
(A) 750
(B) 882
(C) 772
(D) 652
(E) 271
Rationale: Cost price = Rs.500
profit = 50% of 500 = Rs.250
Selling price = Cost price + Profit
= 500 + 250 = 750
Answer:A
Answer: (A) 750
Question: 225 metres long yard, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees
(A) 10
(B) 12
(C) 14
(D) 15
(E) 16
Rationale: 26 trees have 25 gaps between them,
Required distance (225/25) = 10
A
Answer: (A) 10
Question: Solve the equation:
A) |2x – (3x + 2)| = 1,
B) |x|/3 – 2|x|/2 = - 1,
C) |3x – 1| = 2|3x – 1| - 2
(A) -1, - 3/2, - 1/3
(B) -2, - 3/2, - 1/3
(C) -3, - 3/2, - 1/3
(D) -1/2, - 3/2, - 1/3
(E) None of these
Rationale: Solution:
A) |2x – 3x – 2| = 1 <=> |-x – 2| = 1 <=>
-x - 2 = 1 or –x - 2 = -1
From the first equation we get -2 - 1 = x <=> x = -3,
and from the second -2 + 1 = x <=> x = -1
B) |x|/3 – 2 |x|/2 = -1 We reduce to a common denominator and we get
2|x| – 3.2.|x| = - 6 <=>
2|x| - 6|x| = - 6 <=>
- 4|x| = -6 <=> |x| = 3/2 <=>
x = 3/2 or x = - 3/2
C) |3x – 1| = 2|3x – 1| – 2 <=>
2 = 2|3x – 1| – |3x – 1| <=>
2 = |3x – 1| <=>
3x - 1 = 2 or 3x - 1 = - 2,
from where 3x = 3 <=> x = 1 or 3x = - 1 <=> x = - 1/3
Answer A
Answer: (A) -1, - 3/2, - 1/3
Question: From a container, 6 liters milk was drawn out and was replaced by water. Again 6 liters of mixture was drawn out and was replaced by the water. Thus the quantity of milk and water in the container after these two operations is 9:16. The quantity of mixture is:
(A) 15
(B) 26
(C) 22
(D) 27
(E) 11
Rationale: Explanation:
Let quantity of mixture be x liters.
Suppose a container contains x units of liquid from which y units are taken out and replaced by water. After operations , the quantity of pure liquid = units, Where n = no of operations .
So, Quantity of Milk =
Given that, Milk : Water = 9 : 16
Milk : (Milk + Water) = 9 : (9+16)
Milk : Mixture = 9 : 25
Answer: A) 15
Answer: (A) 15
Question: A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 8 days before the completion of the work. In how many days was the work completed?
(A) 12 days
(B) 16 days
(C) 18 days
(D) 11 days
(E) 38 days
Rationale: One day work of A, B and C = 1/24 + 1/30 + 1/40 = 1/10 Work done by A and B together in the last 8 days = 8*(1/24 + 1/30) = 3/5
Remaining work = 2/5
The number of days required for this initial work = 4 days.
The total number of days required = 8 + 4 = 12 days.
Answer: A
Answer: (A) 12 days
Question: Find the odd man out 4, 5, 15, 49, 201, 1011, 6073
(A) 10
(B) 7
(C) 5
(D) 2
(E) 3
Rationale: 4 x 1 + 2 = 6
6 x 2 + 3 = 15
15 x 3 + 4 = 49
49 x 4 + 5 = 210
ANSWER:C
Answer: (C) 5
Question: How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 8
Rationale: Any one girl can go with 3 boys.
2nd girl can go with remaining 2 boys
and 3rd girl can go with remaining 1 boy
3! i.e 6 (D) is the answer
Answer: (D) 6
Question: What will come in place of the x in the following Number series? 6, 12, 21, 33 , 48 , x
(A) 33
(B) 66
(C) 39
(D) 41
(E) 42
Rationale: The pattern is + 6, + 9, + 12, +15 +18 â€¦â€¦â€¦..
So the missing term is = 48 + 18 = 66
Answer : B
Answer: (B) 66
Question: Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 192 as interest at the end of the loan period, what was the rate of interest?
(A) 3.6
(B) 6
(C) 18
(D) 4
(E) None of these
Rationale: Let rate = R% and time = R years.
Then, (1200 x R x R)/100 = 192
12R2 = 192
R2 = 16
R = 4.
Answer: Option D
Answer: (D) 4
Question: At the quarterly birthday party of Sherry, a baby boy, 40 persons chose to kiss him and 25 chose to shake hands with him. 10 persons chose to both kiss him and shake hands with him. How many persons turned out at the party?
(A) 35
(B) 75
(C) 55
(D) 25
(E) 45
Rationale: Let n(A) = No. of persons who kissed Sherry = 40
n(B) = No. of persons who shook hands with Sherry = 25
and n(A ∩ B) = No. of persons who both shook hands with Sherry and kissed him = 10
Then, using the formula, n(A U B) = n(A) + n(B) - n(A ∩ B)
n(A U B) = 40 + 25 - 10 = 55.
ANSWER:C
Answer: (C) 55
Question: The arithmetic mean and standard deviation of a certain normal distribution are 17.5 and 2.5, respectively. What value is exactly 2 standard deviations less than the mean?
(A) 10.5
(B) 11
(C) 11.5
(D) 12
(E) 12.5
Rationale: Mean = 17.5
Two standard deviations is 2.5 + 2.5 = 5.0
There could be two calues for this.
Mean + two standard deviations = 22.5
Mean - Two standard deviations = 12.5
Answer choice has 12.5 and so E is the answer.
Answer: (E) 12.5
Question: A large box contains 16 small boxes and each small box contains 25 chocolate bars. How many chocolate bars are in the large box?
(A) 250
(B) 350
(C) 450
(D) 400
(E) 650
Rationale: The number of chocolate bars is equal to
16 * 25 = 400
correct answer D
Answer: (D) 400
Question: A student needs 30% of the marks on a test to pass the test. If the student gets 80 marks and fails the test by 40 marks, find the maximum marks set for the test.
(A) 400
(B) 500
(C) 600
(D) 700
(E) 800
Rationale: 30% = 120 marks
1% = 4 marks
100% = 400 marks
The answer is A.
Answer: (A) 400
Question: Gold is 10 times as heavy as water and copper is 5 times as heavy as water. In what ratio should these be mixed to get an alloy 8 times as heavy as water?
(A) 3:2
(B) 1:2
(C) 3:1
(D) 5:2
(E) 4:3
Rationale: G = 10W
C = 5W
Let 1gm of gold mixed with x gm of copper to get 1+x gm of the alloy
1gm gold + x gm copper = x+1 gm of alloy
10W+5Wx = x+1 * 8W
10+5x = 8(x+1)
x = 2/3
Ratio of gold with copper = 1:2/3 = 3:2
Answer is A
Answer: (A) 3:2
Question: A bullet train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the bullet train is 54 km/hr, what is the length of the platform?
(A) 210 cm
(B) 120 cm
(C) 340 cm
(D) 240 cm
(E) 330 cm
Rationale: D
240 cm
Answer: (D) 240 cm
Question: What is the ratio between perimeters of two squares one having 3 times the diagonal then the other?
(A) 3: 6
(B) 3: 3
(C) 3: 8
(D) 3: 1
(E) 3: 2
Rationale: d = 3d d = d
a√2 = 3d a√2 = d
a = 3d/√2 a = d/√2 => 3: 1
Answer: D
Answer: (D) 3: 1
Question: Anand and Deepak started a business investing Rs.22,500 and Rs.35,000 respectively. Out of a total profit of Rs. 13,800. Deepak's share is
(A) Rs.5400
(B) Rs.7200
(C) Rs.8400
(D) Rs.9600
(E) None
Rationale: Solution
Ratio of their shares	= 22500 : 35000
=9 : 14.
Deepak's share	= Rs.(13800×14/23)
= Rs. 8400.
Answer C
Answer: (C) Rs.8400
Question: There are two numbers. If 45% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?
(A) A)3/7
(B) B)5/9
(C) C)6
(D) D)6/7
(E) E)7
Rationale: Let the two numbers be x and y.
45/100 * x + y = 5/4y
=> 9/20 x = 1/4 y => x/y = 5/9
B)
Answer: (B) B)5/9
Question: What are the last two digits of (301*402*503*604*646*547*449*349)^2
(A)  96
(B)  76
(C)  56
(D)  36
(E)  24
Rationale: ((301*402*503*604*646)*(547*449*349))^2
If you observe above digits, last digit are: 1,2,3,4,6,7,9,9; 5&9 are missing; so I have rearranged them so that multiplication will be easy for me as initial 4 digits have last two digits as 01,02,03,04,46 and final three as 47*49*49.
Solving for only last two digits and multiplying them we get:( (06*04*46)(47*01))^2 = (44*47)^2=68^2=24
Hence answer is E
Answer: (E)  24
Question: In a new housing development, trees are to be planted along the sidewalk of a certain street. Each tree takes up one square foot of sidewalk space, and there are to be 12 feet between each tree. How many trees can be planted if the road is 157 feet long?
(A) 8
(B) 9
(C) 10
(D) 11
(E) 13
Rationale: Let T be the number of trees. Then the length required for trees on the sidewalk will be 1*T= T
To maximize the number of trees, the number of 12 feet spaces between trees should be 1 less than total number of trees.
For example, If there are 3 trees, then there should be 2 spaces between them.
So the number of 12 feet spaces will be T-1. Then, the length of sidewalk required for 12 feet spaces will be 12*(T-1)
It is given that total lenght of sidewalk is 157 feet.
or 12(T-1)+T = 157
or 12T-12+T = 157
or 13T = 169
or T=13
Answer:- E
Answer: (E) 13
Question: Find the number that fits somewhere into the middle of the series. Some of the items involve both numbers and letters
Look at this series: VI, 10, V, 11, __, 12, III, ... What number should fill the blank?
(A) IV
(B) X
(C) VI
(D) V
(E) III
Rationale: A
IV
This is an alternating addition and subtraction series. Roman numbers alternate with Arabic numbers. In the Roman numeral pattern, each number decreases by 1. In the Arabic numeral pattern, each number increases by 1.
Answer: (A) IV
Question: Find compound interest on $ 6000 at 15% per annum for 2 years 4 months, compounded annually.
(A) 2331.75
(B) 2209.75
(C) 2108.75
(D) 2107.75
(E) 2100.75
Rationale: Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.
Amount = $ [6000 X (1+­(15/100))2 X (1+((1/3)*15)/100)]
=$ [6000 * (23/20) * (23/20) * (21/20)]
= $ 8331.75	.
:. C.I. = Rs. (8331.75 - 6000) = $ 2331.75
Answer A.
Answer: (A) 2331.75
Question: A double decked bus can accomodate 70 passengers,30 in the upper deck and 40 in the lower deck.In how many ways can the passengers be accomodated if 15 refuse to be in the upper deck while 10 others refuse to be in the lower deck?
(A) 1. 85!50!60!/40!45!
(B) 2. 85!/40!45!
(C) 3. 45!/20!25!
(D) 4. 110!50!60!/40!45!
(E) 5. 110!/40!45!
Rationale: 70 passengers,30 in the upper deck and 40 in the lower deck.
25 passengers have issues as 15 refuse to be in the upper deck while 10 others refuse to be in the lower deck
So those 15 will be put in lower deck and 10 will be in upper deck
So from the rest 45 passengers(70-25), we need to find 20 people to put into upper deck and the rest go to lower deck
So the ways are: C(45,20) = 45!/20!25! . Answer C
Answer: (C) 3. 45!/20!25!
Question: Each of the following equations has at least one solution EXCEPT E. Is it true?
(A) -2*-a = 2a
(B) 2* -a = (–2)*a
(C) (–2)-a = –2-a
(D) 2*a = (–2)*-a
(E) -3*a = -3-a
Rationale: If we put a= 1 then
A. 2= 2
B. -2=-2
C. -3=-3
D. 2=2
E. -3=-4 not true
Answer: (E) -3*a = -3-a
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
(A) 89
(B) 20
(C) 36
(D) 88
(E) 34
Rationale: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec.
Answer: Option C
Answer: (C) 36
Question: A rectangular courtyard 3.78 meters long 5.25 meters wide is to be paved exactly with square tiles, all of the same size. what is the largest size of the tile which could be used for the purpose?
(A) 33
(B) 21
(C) 88
(D) 77
(E) 99
Rationale: 3.78 meters =378 cm = 2 × 3 × 3 × 3 × 7
5.25 meters=525 cm = 5 × 5 × 3 × 7
Hence common factors are 3 and 7
Hence LCM = 3 × 7 = 21
Hence largest size of square tiles that can be paved exactly with square tiles is 21 cm.
Answer: B
Answer: (B) 21
Question: The are 6 Black & 6 White socks in a tub, You need to take a pair of socks of same color, what is the max possibility?
(A) 5/11
(B) 6/11
(C) 7/11
(D) 8/11
(E) 9/11
Rationale: 2*6c2/12c2=5/11
ANSWER:A
Answer: (A) 5/11
Question: A woman invested $1,000, part at 5% and the rest at 6%. Her total investment with interest at the end of the year was $1,052. How much did she invest at 5%?
(A) $500
(B) $600
(C) $700
(D) $800
(E) $950
Rationale: et x be the portion invested at 5% and
Let (1-x) be the rest which is invested at 6%
The question states that the return after 1 year is (1052/1000)-1 = 0.052 = 5.2%
We want to find the dollar amount invested in X
Using our defined variables, put together the equation and solve for x (the percentage of 1000 invested at 5%)
0.05x+0.06(1-x)= 0.052
(0.05)x +0.06 - (0.06)x = 0.052
-0.01x = -0.008
x= -0.008/-0.01 = 8/10 = 80%
So X = 80% of the 1000 which is 800
ANSWER:D
Answer: (D) $800
Question: If the sum of the interior angles of a regular polygon measures up to 1440 degrees, then how many sides does the polygon have?
(A) 10
(B) 16
(C) 12
(D) 11
(E) 14
Rationale: one of the interior angle = 180 - 360/n
sum of the interior angles is = n (180 - 360/n)
given
n(180 - 360/n)=1440
180n - 360 = 1440
180n = 1800
n = 1800/180 = 10
ANSWER:A
Answer: (A) 10
Question: Disha drives a car at an average speed of 48 km/h and reach her destination in 6 hours. Himanshu covers that distance in 4 hours. If Disha increases her average speed by 8 km/h and Himanshu increases his average speed by 4 km/h, then what will be the difference in time taken by them to reach their destination?
(A) 1 47/133 hr
(B) 1 41/133 hr
(C) 2 47/133 hr
(D) 1 40/133 hr
(E) 1 45/133 hr
Rationale: 48=d/6
therefore, distance(d)=288km
himanshu's speed=288/4=72kmph
then, disha's speed=48+8=56kmph
disha's time=288/56=5.143hr
then, himanshu's speed=72+4=76kmph
himanshu's time=288/76=3.789hr
difference in time=5.143-3.789=1.354hr=1 47/133hr
ANSWER:A
Answer: (A) 1 47/133 hr
Question: 75 is what percent of 125?
(A) 60%
(B) 40%
(C) 45%
(D) 50%
(E) 55%
Rationale: 75/125×100=50% ANSWER : A
Answer: (A) 60%
Question: A man takes 6 hours 15 minutes in walking a distance and riding back to the starting place. He could walk both ways in 7 hours 45 minutes. The time taken by him to ride both ways, is ?
(A) 6 hours 45 minutes
(B) 2 hours 45 minutes
(C) 4 hours 45 minutes
(D) 9 hours 45 minutes
(E) 5 hours 45 minutes
Rationale: Explanation:
Time taken in walking both ways = 7 hours 45 minutes --------(i)
Time taken in walking one way and riding back= 6 hours 15 minutes-------(ii)
By equation (ii)*2 -(i), we have
Time taken to man ride both ways, = 12 hours 30 minutes - 7 hours 45 minutes
= 4 hours 45 minutes
Answer: C
Answer: (C) 4 hours 45 minutes
Question: he distance light travels in one year is approximately 5,870,000,000,000 miles. The distance light travels in 100 years is:
(A) 587 × 108 miles
(B) 587 × 1010 miles
(C) 587 × 10-10 miles
(D) 587 × 1012 miles
(E) 587 × 10-12 miles
Rationale: The distance of the light travels in 100 years is:
5,870,000,000,000 × 100 miles.
= 587,000,000,000,000 miles.
= 587 × 1012 miles.
CORRECT ANSWER :D
Answer: (D) 587 × 1012 miles
Question: The difference between two positive numbers is 10 and the ratio between them is 5:3. Find the product of the two numbers.
(A) 375
(B) 175
(C) 275
(D) 125
(E) 250
Rationale: Solution: Let the two positive numbers be 5x and 3x respectively.
According to question,
5x-3x = 10;
Or, x = 5.
Then numbers are 25 and 15.
Thus, their product = 25*15 = 375.
Answer: Option A
Answer: (A) 375
Question: A father said to his son, "I was as old as you are at present at the time of your birth." If the father's age is 38 years now, the son's age five years back was:
(A) 19 years
(B) 14 years
(C) 33 years
(D) 38 years
(E) 40 years
Rationale: Explanation:
Let the son's present age be x years.
Then, (38 - x) = x
2x = 38 => x = 19
Son's age 5 years back = (19 - 5) = 14 years.
ANSWER IS B
Answer: (B) 14 years
Question: Anirudh, Harish and Sahil invested a total of Rs.35,000 in the ratio 5:6:4 Anirudh invested has capital for 8 months. Harish invested for 6 months and Sahil invested for 4 months. If they earn a profit of Rs.75,900,then what is the share of Sahil in the profit?
(A) Rs.12,400
(B) Rs.14,700
(C) Rs.15,800
(D) Rs.13,200
(E) None of these
Rationale: Total units={(5*8)+(6*6)+(4*4)}
=92.
sahil profit={16/92}75,900.
=13,200.
ANSWER:D
Answer: (D) Rs.13,200
Question: In a shopping mall with staff of 5 members the average age is 45 years. After 5 years a person joined them and the average age is again 45 years. What is the age of 6th person?
(A) 15 yrs
(B) 16 yrs
(C) 17 yrs
(D) 19 yrs
(E) 20 yrs
Rationale: avg age of 5 person after 5 yrs will be 50 yrs..
so total age of 5 person = 50*5=250
and total age of 6 person = 45*6=270
so age of 6th person= 270-250= 20 yrs
ANSWER:E
Answer: (E) 20 yrs
Question: Mr. loyd wants to fence his Square shaped land of 130Sqft each side.If a pole is laid every 10ft how many poles do he need?
(A) 20
(B) 30
(C) 40
(D) 50
(E) 52
Rationale: If each side is 120 feet..then total perimeter is 130*4=520
poles every 10 feet hence no of poles= 520/10=52
ANSWER:E
Answer: (E) 52
Question: If an investor puts $700 in a savings account that earns 10 percent annual interest compounded semiannually, how much money will be in the account after one year?
(A) $769.75
(B) $771.75
(C) $773.75
(D) $775.75
(E) $777.75
Rationale: 1.05*1.05*700=$771.75
The answer is B.
Answer: (B) $771.75
Question: 50,48,44,?,20
(A) 14
(B) 15
(C) 13
(D) 36
(E) 17
Rationale: The Pattern is - 2, - 4, -8, ...
44-8=36
Answer :D
Answer: (D) 36
Question: 2 + 2 + 2 + 2 × 2^2 + 2 × 2^3 + 2 × 2^4 + 2 × 2^5 + 2 × 2^6 + 2 × 2^7 =
(A) 2^7
(B) 2^14
(C) 2^10
(D) 2^15
(E) 2^16
Rationale: We have the sum of 9 terms. Now, if all terms were equal to the largest term 2*2^7 we would have: sum=9*(2*2^7)=18*2^7=~2^11, so the actual sum is less than 2^11 and more than 2^7 (option A) as the last term is already more than that. So the answer is clearly C.
Answer: C
Answer: (C) 2^10