mathewhe/aqua_rat huggingface dataset:
Question: The L.C.M. of 2 numbers is 40. The numbers are in the ratio 4:5. Find their sum?
(A) 18
(B) 40
(C) 48
(D) 32
(E) 56
Rationale: Let the numbers be 4x and 5x
L.C.M. = 20x
20x = 40
x = 2
The numbers are = 8 and 10
Required sum = 8+10 = 18
Answer is A
Answer: (A) 18
Question: For every X, the action [X] is defined: [X] is the greatest integer less than or equal to X. What is the value of [6.5] x [2/3] + [2] x 7.2 + [8.4] - 6.5?
(A) 12.6.
(B) 14.4.
(C) 15.8.
(D) 15.7.
(E) 16.4.
Rationale: [6.5] x [2/3] + [2] x 7.2 + [8.4] - 6.5
= 6*0 + 2*7.2 + 8 - 6.5
= 0 +14.4 +1.5
15.7
Answer D
Answer: (D) 15.7.
Question: The mean proportional between 4 and 9 is?
(A) 33
(B) 77
(C) 35
(D) 88
(E) 29
Rationale: 7/20 * 100 = 35
Answer:B
Answer: (B) 77
Question: How many different committees can be formed from a group of four women and eight men if three people are on the committee and at least one member must be a man?
(A) 215
(B) 220
(C) 225
(D) 216
(E) 210
Rationale: 4 Women and 8 Men. Three people needed
It is always better to subtract the total from none in case of at least one problems.
Total ways = 12C3 = 220
Total ways without any men = 4C3 = 4
Hence ways in which at least one man will be present = 220 - 4 = 216
Correct option: D
Answer: (D) 216
Question: The square root of 636 is between which set of integers?
(A) 24 and 25
(B) 25 and 26
(C) 26 and 27
(D) 27 and 28
(E) 28 and 29
Rationale: 25^2=625
26^2=676
Hence 636 lies between 25^2 & 26^2
ANSWER:B
Answer: (B) 25 and 26
Question: A salesman sold twice as much pears in the afternoon than in the morning. If he sold 360 kilograms of pears that day, how many kilograms did he sell in the morning and how many in the afternoon?
(A) 560
(B) 240
(C) 329
(D) 443
(E) 544
Rationale: Let x be the number of kilograms he sold in the morning.Then in the afternoon he sold 2xkilograms. So, the total is x+2x=3x This must be equal to 360.
3x=360
x=360/3
x=120
Therefore, the salesman sold 120 kg in the morning and 2⋅120=240 kg in the afternoon.
Answer: (B) 240
Question: What is the place value of 7 in the numeral 57468?
(A) 7000
(B) 5000
(C) 7
(D) 700
(E) 70
Rationale: place value of 7 = 7 * 1000 = 7000
Answer is A
Answer: (A) 7000
Question: Which of the following is closer to (7!+5!)-(7!-5!)?
(A) 120
(B) 150
(C) 200
(D) 240
(E) 360
Rationale: (7!+5!)-(7!-5!)=5040+120-5040+120
= 240
Answer: D
Answer: (D) 240
Question: For what k value(s) is the following equation satisfied: 2k-9-k = 4k+6-3k
(A) a. -5
(B) b. 0 only
(C) c. 5/2 only
(D) d. No value
(E) e. Any value
Rationale: 9k-9-8k = 4k+4-3k
k - 9 = k + 4
-9 = 4, which is false.
So, no k satisfies given equation.
Answer: D.
Answer: (D) d. No value
Question: x+(1/x) = 2.5 find x^2 + (1/x^2)
(A) 2.25
(B) 3.25
(C) 4.25
(D) 5.25
(E) 6.25
Rationale: squaring on both sides (x+1/x)^2=2.5^2
x^2+1/X^2=6.25-2
x^2+1/X^2=4.25
ANSWER:C
Answer: (C) 4.25
Question: A worker is to perform work for you for seven straight days. In return for his work, you will pay him 1/7th of a bar of gold per day. The worker requires a daily payment of 1/7th of the bar of gold. What and where are the fewest number of cuts to the bar of gold that will allow you to pay him 1/7th each day?
(A) 1
(B) 4
(C) 3
(D) 2
(E) 6
Rationale: D
Just 2
Day One: You make your first cut at the 1/7th mark and give that to the worker.
Day Two: You cut 2/7ths and pay that to the worker and receive the original 1/7th in change.
Day three: You give the worker the 1/7th you received as change on the previous day.
Day four: You give the worker 4/7ths and he returns his 1/7th cut and his 2/7th cut as change.
Day Five: You give the worker back the 1/7th cut of gold.
Day Six: You give the worker the 2/7th cut and receive the 1/7th cut back in change.
Day Seven: You pay the worker his final 1/7th.
Answer: (D) 2
Question: How many kg of pure salt must be added to 100kg of 10% solution of salt and water to increase it to a 20% solution?
(A) 6.7
(B) 1.3
(C) 9.6
(D) 12.5
(E) 7.9
Rationale: Amount salt in 100kg solution = 10*100/100 = 10 kg
Let x kg of pure salt be added
then(10+x)/(100+x)=20/100
100+10x=200+2x
8x = 100
x = 12.5
Answer is D
Answer: (D) 12.5
Question: On a trip covering 350 km, a bicyclist travels the first 200 km at 20 km per hour and the remainder of the distance at 15 km per hour. What is the average speed, in km per hour, for the entire trip?
(A) 15.5
(B) 16.0
(C) 17.5
(D) 19.0
(E) 18.5
Rationale: time 1 = 200 / 20 = 10 hours
time 2 = 150 / 15 = 10 hours
total time = 20 hours
average speed = 350 / 20 = 17.5 km/hr
The answer is C.
Answer: (C) 17.5
Question: There were two candidates in an election. Winner candidate received 62% of votes and won the election by 360 votes. Find the number of votes casted to the winning candidate?
(A) 288
(B) 744
(C) 788
(D) 298
(E) 930
Rationale: W = 62% L = 38%
62% - 38% = 24%
24% -------- 360
62% -------- ? => 930
Answer: E
Answer: (E) 930
Question: A researcher computed the mean, the median, and the standard deviation W for a set of performance scores. If 5 were to be added to each score, which of these three statistics would change?
(A) The mean only
(B) The median only
(C) The standard deviation only
(D) The mean and the median
(E) The mean and the standard deviation
Rationale: If we add or subtract a constant to each term in a set the standard deviation W will not change..
If we add (or subtract) a constant to each term in a set the mean and the median will increase (decrease) by the value of that constant.
Answer: D.
Answer: (D) The mean and the median
Question: If 9 ministers are to be seated at a round table conference, then how many different ways can they be seated?
(A) 24
(B) 60
(C) 40320
(D) 720
(E) 180
Rationale: Simple formula:
There are (n - 1)! ways to arrange n distinct objects in a circle.
so its (9-1)! = 8! = 40320=C
Answer: (C) 40320
Question: If the productivity of a brigade grows by 12% when the number of the workers in the brigade is increased by one, then which of the following is closest to the ratio of the productivity of a 12-person brigade to that of a 10-person brigade?
(A) 0.21
(B) 0.82
(C) 1.2
(D) 1.232
(E) 1.44
Rationale: B = 10-men brigade
p = increase in the productivity = 12%
Solution: B x p = B x 1.12 = 1.12B -------> the productivity of 11 men brigade
1.12B x p = 1.12B x 1.1 = 1.232B -----> the productivity of 12 men brigade
The ratio of the productivity of a 12-men brigade to that of a 10-men brigade = 1.232B/B = 1.232
D
Answer: (D) 1.232
Question: The area of a square is 4096 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square.
(A) 5 : 12
(B) 5 : 14
(C) 5 : 17
(D) 5 : 18
(E) 5 : 16
Rationale: Let the length and the breadth of the rectangle be l cm and b cm respectively. Let the side of the square be a cm.
a2 = 4096 = 212
a = (212)1/2 = 26 = 64
L = 2a and b = a - 24
b : l = a - 24 : 2a = 40 : 128 = 5 : 16
Answer: Option E
Answer: (E) 5 : 16
Question: A mixture containing 6% boric acid is to be mixed with 2 quarts of a mixture which is 15% acid in
order to obtain a solution which is 12% acid. How much of the 6% solution must be used?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: This is a mixture problem.
The question asks, “How much of the 6% solution”.
Let x the number of quarts of 6% solution needed.
Write the equation and solve.
0.06+0.15(2)=0.12(x+2)
0.06x+0.30=0.12x+0.24
6x+30=12x+24
6=6x
x=1
The answer: 1 qt of 6% boric acid solution must be used.
correct answer A
Answer: (A) 1
Question: In a basket of apples, 12% of them are rotten and 66 are in good condition. Find the total number of apples in the basket.
(A) 33
(B) 75
(C) 23
(D) 20
(E) 287
Rationale: Let the total number of apples in the basket be m
12 % of the apples are rotten, and apples in good condition are 66
Therefore, according to the question,
88% of m = 66
88/100 × m = 66
m = (66 × 100)/88
m = 3 × 25
m = 75
Therefore, total number of apples in the basket is 75.
Answer:B
Answer: (B) 75
Question: A train speeds past a pole in 15 seconds and a platform 140 meters long in 25 seconds. What is the length of the train (in meters)?
(A) 190
(B) 200
(C) 210
(D) 220
(E) 230
Rationale: Let the length of the train be x meters.
The speed of the train is x / 15.
Then, x + 140 = 25*(x / 15)
10x = 2100
x = 210 meters
The answer is C.
Answer: (C) 210
Question: On a ranch, a rancher can place a loop of rope, called a lasso, once in every 2 throws around a cow’s neck. What is the probability that the rancher will be able to place a lasso around a cow’s neck at least once in 4 attempts?
(A) 3/4
(B) 5/8
(C) 7/8
(D) 11/16
(E) 15/16
Rationale: P(missing all 4)=(1/2)^4=1/16
P(success on at least one attempt)=1-1/16=15/16
The answer is E.
Answer: (E) 15/16
Question: (525 + 275) Ã— 4 Ã— (3 + 2) = ?
(A) 12000
(B) 24000
(C) 16000
(D) 14000
(E) 16200
Rationale: (525 + 275) Ã— 4 Ã— (3 + 2) = ?
or, ? = 800 Ã— 4 Ã— 5 = 16000
Answer C
Answer: (C) 16000
Question: A luxury liner, Queen Marry II, is transporting several cats as well as the crew (sailors, a cook, and one-legged captain) to a nearby port. Altogether, these passengers have 15 heads and 43 legs. How many cats does the ship host?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: sa's +co +ca +cats = 15. sa's + 1 +1 +cats =15 or sa's +cats =13.
sa's(2) +2 +1 +cats*4 =43 sa's*2 +cats*4 = 40 or sa's +cats*2 =20 or 13-cats +cat*2 =20
then cats =7
D
Answer: (D) 7
Question: How long will a boy take to run round a square field of side 40 meters, if he runs at the rate of 9km/hr?
(A) 64sec
(B) 45sec
(C) 1min
(D) 32sec
(E) 25sec
Rationale: Speed = 9 km/hr = 9*5/18 = 5/2 m/sec
Distance = 40*4 = 160m
Time taken = 160*2/5 = 64sec
Answer is A
Answer: (A) 64sec
Question: A triangle has a perimeter 17. The two shorter sides have integer lengths equal to x and x + 1. Which of the following could be the length of the other side?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 3
Rationale: The SHORTER sides have integral lengths equal to x and x + 1
Let the longest side be 'a'
So, a + x + (x +1) = 17
a + 2x = 17.......eqn (1)
We know that the sum of the lengths of the shorter sides has to be more than the length of the longer one. i.e 2x+1> a
a =7
D
Answer: (D) 7
Question: For each month of a given year except December, a worker earned the same monthly salary and donated one-tenth of that salary to charity. In December, the worker earned N times his usual monthly salary and donated one-third of his earnings to charity. If the worker's charitable contributions totaled one-eighth of his earnings for the entire year, what is the value of N?
(A) 8/5
(B) 5/2
(C) 3
(D) 33/25
(E) 4
Rationale: Let monthly salary for each of the 11 months except December was x, then
11x*1/10 + Nx*1/3 = 1/8(11x + Nx);
11/10 + N/3 = 1/8(11 + N)
33+10N/30= 11+N/8 =>264+80N= 330+30N=>50N=66
N = 66/50=33/25
Answer: D.
Answer: (D) 33/25
Question: The average of first nine prime numbers is?
(A) 10
(B) 11.1
(C) 12.5
(D) 15.8
(E) 13.6
Rationale: Average = (2+3+5+7+11+13+17+19+23)/9= 100/9 = 11.1
Answer is B
Answer: (B) 11.1
Question: If an integer t is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that t(t + 1)(t + 2) will be divisible by 8?
(A) 1/4
(B) 3/8
(C) 1/2
(D) 5/8
(E) 3/4
Rationale: for t Total numbers 8*12
There are 12 numbers divisible by 8 -> 3*12 (if 8 is an example - (6,7,8), (7,8,9), (8,9,10))
and 12 numbers divisible by 4 but not divisible by 8 -> 2*12 (if 4 is an example (2,3,4) and (4,5,6))
The answer 5/8 -> D
Answer: (D) 5/8
Question: If integers w and b are distinct factors of 30, which of the following CANNOT be a factor of 30?
I. wb + b^2
II. (w+ b)^2
III. w + b
(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I, II, and III
Rationale: Factors of 30 are: 1, 2, 3, 5, 6, 10, 15, and 30.
I. wb + b^2 --> if w=1 and b=2 then wb + b^2=6, which is a factor of 30. OK;
II. (w + b)^2 --> (w + b)^2 is a perfect square, no perfect square (but 1) is a factor of 30. DISCARD;
III. w + b --> if w=1 and b=2 then w + b=3, which is a factor of 30. OK.
Answer: B.
Answer: (B) II only
Question: Find the invalid no.from the following series 3, 6, 15, 31, 63, 127, 255
(A) 6
(B) 7
(C) 27
(D) 63
(E) 127
Rationale: Go on multiplying the number by 2 and adding 1 to it to get the next number.So, 6 is wrong.
A
Answer: (A) 6
Question: A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 3 of 10 candidates eligible to fill 3 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 4 candidates are there to fill the 4 positions?
(A) 420
(B) 770
(C) 840
(D) 165
(E) 315
Rationale: 1 of 7 will be chosen for the math
3 of 10 will be chosen for the computer
None of the 4 chosen people can be in more than one departments.
We can choose any of the 7 candidates for the math dep., which gives as 7 selections.
We can choose 3 of the 10 candidates for the computer dep., which gives us 3 selections and 7 rejections.
So, the way to find how many different selections of 2 candidates we can have for the computer dep., we do:
10! /3!*7!= 120
We are multiplying our individual selections: 7*120 = 840
In the bolded part, we don't have to multiply all of the numbers, as those in 8! are included in 10!, so we simplify instead.
Ans C
Answer: (C) 840
Question: Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 5 to 2 and the ratio of Indian to British stamps is 5 to 1, what is the ratio of US to British stamps?
(A) 10 : 5
(B) 15 : 2
(C) 20 : 2
(D) 25 : 2
(E) 28 : 2
Rationale: Indian stamps are common to both ratios. Multiply both ratios by factors such that the Indian stamps are represented by the same number.
US : Indian = 5 : 2, and Indian : British = 5 : 1. Multiply the first by 5, and the second by 2.
Now US : Indian = 25 : 10, and Indian : British = 10 : 2
Hence the two ratios can be combined and US : British = 25 : 2 Answer: D
Answer: (D) 25 : 2
Question: . A boy has five trousers and 11 shirts. In how many different ways can he select a trouser and a shirt?
(A) 45
(B) 55
(C) 65
(D) 75
(E) 80
Rationale: Explanation:
The boy can select one trouser in five ways.
The boy can select one shirt in 11 ways.
The number of ways in which he can select one trouser and one shirt is 5 * 11 = 55 ways.
Answer: Option B
Answer: (B) 55
Question: Jim is able to sell a hand-carved statue for $540 which was a 35% profit over his cost. How much did the statue originally cost him?
(A) $400.00
(B) $412.40
(C) $455.40
(D) $474.90
(E) $488.20
Rationale: 540 = 1.35*X
X = 540/1.35 = 400
$400, which is (A).
Answer: (A) $400.00
Question: What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent?
(A) 988
(B) 500
(C) 378
(D) 373
(E) 287
Rationale: 70 = (P*4*7/2)/100
P = 500
Answer: B
Answer: (B) 500
Question: In a car wheel, ten spokes cover 60 degrees. Then for the entire car,how many spokes are there?
(A) 120
(B) 140
(C) 240
(D) 320
(E) 340
Rationale: given, 10 spokes cover 60degrees,
so for 360 degrees.---->360*10/60=60..
so, for entire car, 4*60=240
ANSWER:C
Answer: (C) 240
Question: If y = x^2 + cx + d, y is minimum when x is:
(A) c/d
(B) -c/d
(C) -c/2
(D) -d/2
(E) d/c
Rationale: We're given the equation Y = X^2 + cX + d.
IF.. we use a simple Classic Quadratic....
c = 2
d = 1
Y = X^2 + 2X + 1
We can then go about finding the answer that yields the MINIMUM result when X = ...
Answer A: c/d = 2/1 = 2 --> 4+4+1 = +9
Answer B: -c/d = -2/1 = -2 --> 4-4+1 = +1
Answer C: -c/2 = -2/2 = -1 --> 1-2+1 = 0
Answer D: -d/2 = -1/2 -->(1/4)-1+1 = +1/4
Answer E: d/c = 1/2 --> (1/4)+1+1 = +2 1/4
From these results, we can see the minimum result:
C
Answer: (C) -c/2
Question: If two sides of a triangle are 12 and 4, which of the following could be the area of triangle?
1. 35
2. 48
3. 56
(A) a) 1 only
(B) b) 1 and 2 only
(C) c) 1 and 3 only
(D) d) 2 and 3 only
(E) e) 1, 2 and 3 only
Rationale: when two sides of a triangle are known , the maximum area occurs when the angle between those two sides is 90.
lets say base = 12 , height =8 (angle = 90)
maximum area = (1/2)*12*8 = 48 ( this is the same maximum area even when base is 8 and height is 12).
if we fix the base and keep lowering the angle, it will result in a lower height . hence the resulting area will always be < 48.
C,D and E are ruled out.
3 and 2 are possible areas as their areas are less than 48.
Hence the answer is D.
Answer: (D) d) 2 and 3 only
Question: How many bricks each measuring 22cm x 10.25cm x 8cm, will be needed to build a wall 9m x 7m x 10.5m
(A) 5600
(B) 3066
(C) 3055
(D) 7200
(E) None of these
Rationale: Explanation:
no. of bricks= volume of the wall/volume of 1 brick = (900 x 700 x 10.5) / (22 x 10.25 x 8) = 3066
Answer: B
Answer: (B) 3066
Question: An association of mathematics teachers has 1,500 members. Only 525 of these members cast votes in the election for president of the association. What percent of the total membership voted for the winning candidate if the winning candidate received 36 percent of the votes cast?
(A) 7.5%
(B) 5.8%
(C) 4.2%
(D) 34.5%
(E) 12.6%
Rationale: Total umber of members = 1500
Number of members that cast votes = 525
Since , winning candidate received 36 percent of the votes cast
Number of votes for winning candidate = (36/100)*525 = 189
Percent of total membership that voted for winning candidate = (189/1260)*100 = 12.6%
Answer E
Answer: (E) 12.6%
Question: Today is Sunday. After 36 days, what day of the week will it be?
(A) Thursday
(B) Monday
(C) Tuesday
(D) Saturday
(E) Sunday
Rationale: Each weekday is repeated every 7 days. 36 divided by 7 is 5 with a remainder of 1. So, after 35 days it will be a Sunday. After 36 days, it will be a Monday. Answer: B
Answer: (B) Monday
Question: The LCM and HCF of two numbers are 60 and 2 respectively. Find the larger of the two numbers if their sum is 22.
(A) 12
(B) 2
(C) 4
(D) 54
(E) 56
Rationale: There are 2 approaches in solving this.
Methode 1.
HCF * LCM = The Actual Number.
60* 2= 120
So the answer which we are looking for has to be a factor of 120.
So among the options shortlist the answers by eliminating those numbers which is not divisible by 120. and then take the highest number as the answer as the question asks abt the highest number.
answer is A
Answer: (A) 12
Question: In Cliff’s impressive rock collection, there are half as many igneous rocks as sedimentary rocks. Of the igneous rocks, 4/5 are shiny and the rest are matte, while 1/5 of the sedimentary rocks are shiny. If there are 40 shiny igneous rocks, how many total rocks does Cliff have?
(A) 30
(B) 150
(C) 60
(D) 90
(E) 135
Rationale: We can start with the known quantity and then go on to find the others.
Shiny igneous ricks are 40. These are (4/5) of total igneous rocks.
(4/5)*Total igneous rocks = 40
Total igneous rocks = 40 * (5/4) = 50
Total sedimentary rocks = 2*Total igneous rocks = 2*50 = 100
Total number of rocks = 50 + 100 = 150
Answer (B)
Answer: (B) 150
Question: In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 10:6:5. If there are in all Rs.92, the number of 25 paisa coins is?
(A) 26
(B) 46
(C) 48
(D) 42
(E) 28
Rationale: 10x 6x 5x
50 25 100
500x + 150x + 500x = 9200
1150x = 9200
x = 8 => 6x = 48
Answer: C
Answer: (C) 48
Question: The probability that event A occurs is 0.4, and the probability that events A and B both occur is 0.45. If the probability that either event A or event B occurs is 0.6, what is the probability that event B will occur?
(A) 0.05
(B) 0.15
(C) 0.45
(D) 0.5
(E) 0.55
Rationale: P(A or B) = P (A) + P(B) - p(a n b)
0.6= 0.4 + P(B) - 0.45
P(B) = 0.55
Ans : E
Answer: (E) 0.55
Question: 1. Mrs. Ram got a weekly raise of $145. If he gets paid every other week, write an integer describing how the raise will affect her paycheck.
(A) 145
(B) 245
(C) 100
(D) 150
(E) 345
Rationale: Let the 1st paycheck be x (integer).
Mrs. Ram got a weekly raise of $ 145.
So after completing the 1st week he will get $ (x+145).
Similarly after completing the 2nd week she will get $ (x + 145) + $ 145.
= $ (x + 145 + 145)
= $ (x + 290)
So in this way end of every week her salary will increase by $ 145.
Answer :A
Answer: (A) 145
Question: Rs.900 amounts to Rs.920 in 3 years at simple interest. If the interest is increased by 3%, it would amount to how much?
(A) Rs.1056
(B) Rs.1001
(C) Rs.2056
(D) Rs.1026
(E) Rs.1856
Rationale: (900*3*3)/100 = 81
920 + 81 = 1001
ANSWER:B
Answer: (B) Rs.1001
Question: If x > y, x < 6, and y > -3, what is the largest prime number that could be equal to x + y?
(A) 10
(B) 11
(C) 12
(D) 14
(E) 16
Rationale: Primes: 2, 3, 5, 7, 11, 13, 17, etc
If X is less than 6 and y is less than X, then 6+6 = 12 would be impossible. We know 13 and all the primes > 13 are out. Let's try 11.
5.9 + 5.1 = 11
5.9 < 6
5.1 < 5.9
everything checks out
Answer 11
ANSWER:B
Answer: (B) 11
Question: In a certain game there are 8 steps, referred to as step 1, step 2, and so on with the final step being step 8. The steps are played one after the other. In each step a score of 1, 2, 3, or 4 is obtained. Angel played the game, getting at least one score of each of 1, 2, 3, and 4, and never getting the same score in consecutive steps. What is the greatest possible score that Angel could have gotten?
(A) 15
(B) 18
(C) 21
(D) 23
(E) 29
Rationale: There are two conditions:
1. Angel got at least one score of each of 1, 2, 3, and 4.
2. She never got the same score in consecutive steps.
Taking that into account, the greatest possible score that Angel could have gotten is 4 + 1 + 4 + 2 + 4 + 3 = 18.
Answer: B.
Answer: (B) 18
Question: The length of the room is 5.5m and width is 3.75m. Find the cost of paving the floor by slabs at the rate of Rs.800 per sq meter
(A) Rs.16500
(B) Rs.15500
(C) Rs.17500
(D) Rs.18500
(E) Rs.19500
Rationale: l=5.5m w=3.75m
area of the floor = 5.5 x 3.75 = 20.625 sq m
cost of paving = 800 x 20.625 = Rs. 16500 Answer: A
Answer: (A) Rs.16500
Question: Look at this series: 83, 73, 93, 63, __, 93, 43, ... What number should fill the blank?
(A) 55
(B) 59
(C) 52
(D) 53
(E) 51
Rationale: D
53
This is a simple subtraction series in which a random number, 93, is interpolated as every third number. In the subtraction series, 10 is subtracted from each number to arrive at the next.
Answer: (D) 53
Question: 81,162,49,98,25,50,62
(A) 124
(B) 127
(C) 129
(D) 128
(E) 131
Rationale: 81*2=162
49*2=98
25*2=50
62*2=124
ANSWER:A
Answer: (A) 124
Question: The present ages of three persons are in the proportion of 4 : 7 : 9. Eight years ago, the sum of their ages was 116. Find their present ages.
(A) 20,35,45
(B) 28,49,63
(C) 16,28,36
(D) 16,28,46
(E) None of these
Rationale: Let the present ages of three persons be 4K,7K and 9K respectively.
(4K - 8) + (7K - 8) + (9K - 8) = 116
20K = 140
K = 7
Therefore, then present ages are 28,49,63.
ANSWER:B
Answer: (B) 28,49,63
Question: Two teams are distributing information booklets. Team A distributes 60% more boxes of booklets than Team X, but each box of Team A’s has 60% fewer booklets than each box of Team X’s. Which of the following could be the total number of booklets distributed by the two groups?
(A) 2,000
(B) 3,200
(C) 4,100
(D) 4,800
(E) 4,900
Rationale: Let x be the no of booklets in each box that team X distributes. So, Team A has 60% fewer - 0.4x.
Let y be the no. of boxes distributed by team X. So, Team A distributes 60% more - 1.6y
Total booklets distributed by team A = xy
Total booklets distributed by team X=0.64xy
Total booklets distributed = xy+0.64xy=1.64xy
As no. of booklets can only be integer, plugging the answer choice equal to 1.64xy should give an integer.
Choice A - 1.64xy=2000; xy=2000/1.64 = doesn't provide an integer value.
Similarly all answer choices, except choice C, fail to provide an integer value.
Choice C = 4100/1.64= 2500 and is the correct answer.
Answer: (C) 4,100