mathewhe/aqua_rat huggingface dataset:
Question: Evaluate: 10111 - 10*2*5 = ?
(A) 10101
(B) 10110
(C) 11100
(D) 11001
(E) 11011
Rationale: According to order of operations, 10?2?5 (division and multiplication) is done first from left to right
10/2=5* 2 = 10
Hence
10111 - 10*2*5 = 10111 - 10 = 10101
correct answer A
Answer: (A) 10101
Question: Two pipes can fill a tank in 18 minutes and 30 minutes. An outlet pipe can empty the tank in 45 minutes. If all the pipes are opened when the tank is empty, then how many minutes will it take to fill the tank?
(A) 1/15
(B) 1/16
(C) 1/11
(D) 1/10
(E) 1/12
Rationale: Part of the filled by all the three pipes in one minute
= 1/18 + 1/30 - 1/45 = 1/15
So, the tank becomes full in 15 minutes.
Answer:A
Answer: (A) 1/15
Question: Find the average of the first 20 natural numbers?
(A) 18.5
(B) 10.0
(C) 10.4
(D) 10.5
(E) 10.2
Rationale: Average of the first 'n' natural numbers = (n + 1)/2
We get (20 + 1)/2 = 10.5.Answer: D
Answer: (D) 10.5
Question: What will come in place of the question mark (?) in the following equation?
25(7.5) × 5(2.5) ÷ 125(1.5) = 5?
(A) 16
(B) 17.5
(C) 8.5
(D) ?=13
(E) None of these
Rationale: 25(7.5) × 5(2.5) ÷ 125(1.5) = 5?
or, 5(2 × 7.5) × 5(2.5) ÷ 5(3 × 1.5) = 5?
or 5(15) × 5(2.5) × 1⁄54.5 = 5?
or, 5(13)= 5? or, ? = 13
Answer D
Answer: (D) ?=13
Question: Two men can fill the tank in 5hr and 4hr respectively, while the third empty it in 20hr. If all pipes are opened simultaneously, then the tank will be filled in
(A) 2
(B) 2.5
(C) 3
(D) 3.5
(E) 3.7
Rationale: Work done by all the men working together in 1 hour.
1/5+1/4−1/20=8/20
Hence, tank will be filled in 20/8=2.5 hour
B
Answer: (B) 2.5
Question: If z is three times larger than n , and if 2n+3 is 20% of 25, what is the value of ?
(A) 1
(B) 2
(C) 3
(D) 6
(E) 12
Rationale: Then the wordings of question are misleading. Moreover, it'd also be a bad way to convey z=4n, if it really wanted to convey so.
From other questions that I have seen, proper wordings could be:
If z is three times as large as n
OR simply,
If z is three times n.C
Answer: (C) 3
Question: 3/5 of all married couples have more than one child. 1/2 of all married couples have more than 3 children. What fraction of all married couples have 2 or 3 children?
(A) 1/5
(B) 1/10
(C) 7/20
(D) 3/5
(E) It cannot be determined from the given information.
Rationale: Plug in simple numbers. Take 100 couples for example.
3/5 of 100 couples have more than one child = 60 couples.
1/2 of 100 couples have more than 3 kids = 50 couples.
This implies that 50 couples are a subset of 60 couples and the complement of 60 couples within those 100 couples, which equals 40 couples have either one or no kids at all.
We need to find couples that have 2 or 3 kids, so essentially, it is 60 - 50 = 10. Fraction will be 10/100 = 1/10.
Option B
Answer: (B) 1/10
Question: The number of degrees that the hour hand of a clock moves through between noon and 2.30 in the afternoon of the same day is
(A) 720
(B) 180
(C) 75
(D) 65
(E) 60
Rationale: Explanation:
The hour hand moves from pointing to 12 to pointing to half way between 2 and 3. The angle covered between each hour marking on the clock is 360/12 = 30. Since the hand has covered 2.5 of these divisions the angle moved through is 75.
ANSWER IS C
Answer: (C) 75
Question: An electric motor makes 4,800 revolutions per minutes. How many degrees does it rotate in one second?
(A) 18.000 d/sec
(B) 28.800 d/sec
(C) 38.000 d/sec
(D) 26.000 d/sec
(E) 35.000 d/sec
Rationale: 4800 revolutions / minute
= 4800*360 degrees / 60 seconds
= 28,800 degrees / second
B
Answer: (B) 28.800 d/sec
Question: On dividing a number by 5, we get 3 as remainder. What will the remainder when the square of the this number is divided by 5 ?
(A) 0 Remainder
(B) 1 Remainder
(C) 2 Remainder
(D) 4 Remainder
(E) 5 Remainder
Rationale: EXPLANATION
Let the number be x and on dividing x by 5, we get k as quotient and 3 as remainder.
x = 5k + 3
x2 = (5k + 3)2
= (25k2 + 30k + 9)
= 5(5k2 + 6k + 1) + 4
On dividing x2 by 5, we get 4 as remainder.
Remainder = 4
Answer D
Answer: (D) 4 Remainder
Question: In how many ways a committee, consisting of 5 men and 6 women can be formed from 8men and 10 women?
(A) 10000
(B) 11760
(C) 12450
(D) 12666
(E) 13250
Rationale: Required number of ways = 8C5 * 10C6
= 8C3 * 10C4
= (8*7*6/3*2*1)*(10*9*8*7/4*3*2*1)
= 11760
Answer is B
Answer: (B) 11760
Question: Five A-list actresses are vying for the three leading roles in the new film, "Catfight in Denmark." The actresses are Julia Robards, Merly Strep, Sally Fieldstone, Lauren Bake-all, and Hallie Strawberry. Assuming that no actresses has any advantage in getting any role, what is the probability that Julia and Hallie will star in the film together?
(A) 3/10
(B) 3/125
(C) 6/10
(D) 3/5
(E) 1/125
Rationale: Pick Hallie and Julia. Now you can pick the third actress in 3 ways so total number of ways of picking 3 actresses (including Hallie and Julia) = 3
Total number of ways of picking any 3 actresses out of 5 = 5*4*3/3! = 10
Probability that both Hallie and Julia will be picked = 3/10
Ans:A
Answer: (A) 3/10
Question: In the faculty of Reverse-Engineering, 240 second year students study numeric methods, 423 second year students study automatic control of airborne vehicles and 134 second year students study them both. How many students are there in the faculty if the second year students are approximately 80% of the total?
(A) 515.
(B) 545.
(C) 661.
(D) 644.
(E) 666.
Rationale: Answer is C :661
Solution : Total number of students studying both are 423 + 240 - 134 = 529 (Subtracting the 134 since they were included in the both the other numbers already).
So 80% of total is 529, so 100% is approx. 661.
Answer: (C) 661.
Question: In 1990 the budgets for projects Q and V were $700,000 and $780,000, respectively. In each of the next 10 years, the budget for Q was increased by $30,000 and the budget for V was decreased by $10,000. In which year was the budget for Q equal to the budget for V ?
(A)  1992
(B)  1993
(C)  1994
(D)  1995
(E)  1996
Rationale: Let the no of years it takes is x.
700+30x = 780-10x --> 40x = 80 and x=2.
Thus, it happens in 1992.
A.
Answer: (A)  1992
Question: Jean drew a gumball at random from a jar of pink and blue gumballs. Since the gumball she selected was blue and she wanted a pink one, she replaced it and drew another. The second gumball also happened to be blue and she replaced it as well. If the probability of her drawing the two blue gumballs was 25/36, what is the probability that the next one she draws will be pink?
(A) 1/6
(B) 4/7
(C) 3/7
(D) 16/49
(E) 40/49
Rationale: The probability of drawing a pink gumball both times is the same. The probability that she drew two blue gumballs = 25/36 = (5/6) * (5/6)
Therefore probability that the next one she draws is pink =1/6
Option (A)
Answer: (A) 1/6
Question: In how many different number of ways 4 boys and 3 girls can sit on a bench such that girls always sit together?
(A) 720
(B) 790
(C) 800
(D) 820
(E) 840
Rationale: Option 'A'
Answer: (A) 720
Question: Given the two equations 7r + 2s = 43 and 4r - 3s = 8, by how much does r exceed s?
(A) 3
(B) 1
(C) 5
(D) 6
(E) 7
Rationale: Solve by Simultaneous Equations.
My Answer is B.
r=5
s=4
Answer: (B) 1
Question: If 3 workers collect 48 kg of cotton in 4 days, how many kg of cotton will 9 workers collect in 2 days?
(A) 87 kg
(B) 67 kg
(C) 72 kg
(D) 87 kg
(E) 46 kg
Rationale: (3 * 4)/48 = (9 * 2)/ x
x = 72 kg
Answer: C
Answer: (C) 72 kg
Question: Two trains, each 100 m long, moving in opposite directions, cross other in 10 sec. If one is moving twice as fast the other, then the speed of the faster train is?
(A) 22
(B) 98
(C) 48
(D) 88
(E) 12
Rationale: Let the speed of the slower train be x m/sec.
Then, speed of the train = 2x m/sec.
Relative speed = ( x + 2x) = 3x m/sec.
(100 + 100)/10 = 3x => x = 20/3.
So, speed of the faster train = 40/3 = 40/3 * 18/5 = 48 km/hr.
Answer:C
Answer: (C) 48
Question: What is the simplified result of following the steps below in order?
(1)	add 5y to 2v
(2)	multiply the sum by 3
(3)	subtract v + y from the product
(A) 5v + 14y
(B) 5x + 16y
(C) 5x + 5y
(D) 6x + 4y
(E) 3x + 12y
Rationale: 3(5Y+2V) -V-Y= 14Y+5V
'A' is the answer
Answer: (A) 5v + 14y
Question: A car started running at a speed of 30 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 10 hours of the journey?
(A) 288
(B) 390
(C) 287
(D) 266
(E) 161
Rationale: The total distance covered by the car in the first 10 hours
= 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44 + 46 + 48
= sum of 10 terms in AP whose first term is 30 and last term is 48 = 10/2 [30 + 48]
= 390 km.
Answer: B
Answer: (B) 390
Question: Of the 13 employees in a certain department, 1 has an annual salary of 38,000, 2 have an annual salary of 45,700 each, 2 have an annual salary of 42,500 each, 3 have an annual salary of 40,000 each and 5 have an annual salary of 48,500 each. What is the median annual salary for the 13 employees?
(A) 38,000
(B) 40,000
(C) 42,500
(D) 45,700
(E) 48,500
Rationale: Median is just the value in the middle when you arrange all values in the ascending order
In this question, the 7th value would be the median (Since there are 13 employees)
38, 40, 40, 40, 42.5, 42.5,45.7
So, answer is D.
Answer: (D) 45,700
Question: A man invested Rs. 1552 in a stock at 97 to obtain an income of Rs. 128. The dividend from the stock is:
(A) 7.5%
(B) 8%
(C) 9.7%
(D) 8.7%
(E) None of these
Rationale: Income of Rs 128 on Investment of Rs 1552
Income of Rs ? on Investment of Rs 96
=(96*128)/1522=8%
ANSWER:B
Answer: (B) 8%
Question: In 1995, the Johns spent $800 on the family’s water bills. Anticipating that water rates would increase in 1996 by 50%, the Johns cut back their water usage. By how much must the Johns have reduce their 1996 water usage to pay exactly the same amount in 1996 as they paid in 1995?
(A) a)	33 1/3 %
(B) b)	40 %
(C) c) 50 %
(D) d)	66 2/3 %
(E) e)	100 %
Rationale: Let x be the water usage and c be the cost water of Jhons
We have
xc =800, c=800/x
Y(1.5c)=800 where Y is the water usage in 1996
Y= 800/ (1.5*800/x)= 1/1.5x=2/3x
Thus reduction will be x-2/3x=1/3x=A
Answer: (A) a)	33 1/3 %
Question: If two resistors, A(R1) and B(R2) stand in parallel with each other in electrical wire, the total resistor appears as R1R2/(R1+R2). If three resistors, A(R1), B(R2), and C(2R2) stand in parallel in electrical wire, what is the ratio V of the resistors’ sum of A and C to the resistors’ sum of A and B?
(A) 2(R1+R2):(R1+2R2)
(B) (R1+R2):(R1+2R2)
(C) (2R1+R2):(R1+2R2)
(D) 2(R1+R2):(2R1+R2)
(E) 2(R1-R2):(R1+2R2)
Rationale: two resistors A (r1) and B (r2).
total or sum of two resistors appear as
r1r2/r1+r2. It is looks like inversion of sum of rates.
1/r1+1/r2= r1+r2/r1r2.
same way sum of A(r1) and c(2r2)=1/r1+1/2r2
=2r2+r1/r12r2.
inversion rate = r12r2/2r2+r1.
ratio V of sum of a and c/sum of a and b=2r2r1/2r2+r1*r1+r2/r1r2
=2(r1+r2)/2r2+r1.A
Answer: (A) 2(R1+R2):(R1+2R2)
Question: How many seconds will a 220 metre long train take to cross a man running with a speed of 8 km/hr in the direction of the moving train if the speed of the train is 80 km/hr?
(A) 25
(B) 30
(C) 40
(D) 11
(E) 60
Rationale: Explanation :
Speed of train relatively to man = ( 80 - 8)km/hr
= 72 km /hr
= (72 x 5 / 18)m/sec
= 20 m/sec
Time taken to pass the man = (220 / 20)sec = 11 sec.
Answer : D
Answer: (D) 11
Question: 4 bells first begin to toll together with an intervals of 5, 10, 15 & 20 sec. How many times does they toll together in an hr?
(A) 40
(B) 60
(C) 80
(D) 90
(E) 110
Rationale: 5|5, 10, 15, 20
2|1, 2, 3, 4
|1, 1, 3, 2
L.C.M of 5, 10, 15, 20 is 60
60 times
B
Answer: (B) 60
Question: A man rides at the rate of 30km/hr. But stops 30minutes to change horses at the end of every 25th kilometer. How long will he take to go a distance of 150 kilometers?
(A) 5hr
(B) 7hr 30min
(C) 8hr 10min
(D) 7hr 20min
(E) 9hr
Rationale: speed of man = 30km/hr
number of rests = (150/25)-1 = 5
time taken for the man = (150/30)+5*(30/60) = 7 hr 30 min
Answer is B
Answer: (B) 7hr 30min
Question: a spider web consists of 3 concurrent lines forming radial support for 20 concentric regular hexagon .the hexagon vertices are 5mm from their immidiate neighbour. if the innermost hexagon has a side length 3mm how many meters is the length of the entire web including the 3 diagonals ?
(A) 6.1
(B) 6.3
(C) 7.2
(D) 8.2
(E) 9.2
Rationale: for perimeter of all hexagon =6*(3+8+13+...........20th term.)
sum will be 6060 mm
and for length of one diagonal find 20th term=98
so total length =6060+294=6354 mm=6.354 m
ANSWER:B
Answer: (B) 6.3
Question: 39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 15 persons, working 6 hours a day, complete the work?
(A) 10
(B) 13
(C) 14
(D) 26
(E) 16
Rationale: Let the required number of days be x.
Less persons, More days (Indirect Proportion)
More working hours per day, Less days (Indirect Proportion)
Persons	15	:	39	:: 12 : x
Working hours/day	6	:	5
15 x 6 x x = 39 x 5 x 12
x =	(39 x 5 x 12)/(15 x 6)
x = 26.
ANSWER:D
Answer: (D) 26
Question: A man can row upstream at 5 kmph and downstream at 25kmph, and then find the speed of the man in still water?
(A) 15
(B) 77
(C) 30
(D) 88
(E) 34
Rationale: US = 5
DS = 25
M = (5 + 25)/2 = 15
Answer:A
Answer: (A) 15
Question: Anthony and Michael sit on the six member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent W of all the possible subcommittees that include Michael also include Anthony?
(A)  20%
(B)  30%
(C)  40%
(D)  50%
(E)  60%
Rationale: The answer is C. Let's look at a committee where Mike belongs (he's person # 1) on that committee. When we choose person #2, there is a 1/5 probability that it's going to be Anthony (then it doesn't matter who the third person is), and 4/5 probability that it's going to be someone else (then person #3 is going to be Anthony with probability 1/4). Total probability W= 1/5+4/5*1/4 = 2/5.C
Answer: (C)  40%
Question: Right triangle PQR is the base of the prism in the figure above. If PQ=PR=âˆš5 and the height of the prism is 10, what is the volume of the prism?
(A) 5
(B) 10
(C) 15
(D) 20
(E) 25
Rationale: Volume of prism = Area of base * height = 1/2* (square root of 5) * (square root of 5)*10 = 25
Answer: E
Answer: (E) 25
Question: The height of the wall is 6 times its width and length of the wall is 8 times its height .if the volume of the wall be 36000 cu.m.its width is
(A) 4m
(B) 5m
(C) 6m
(D) 7m
(E) 8m
Rationale: Explanation:
Let width = x
Then, height=6x and length=48x
48x Ã— 6x Ã— x = 36000
x = 5
Answer: B
Answer: (B) 5m
Question: A cricket bat is sold for $900, making a profit of $150. The profit percentage would be
(A) 24%
(B) 20%
(C) 30%
(D) 36%
(E) 40%
Rationale: 150/(900 - 150) = 150/750 = 0.2 = 20%.
Answer: B
Answer: (B) 20%
Question: The average weight of a group of boys is 20 kg. After a boy of weight 32 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
(A) 12
(B) 11
(C) 18
(D) 24
(E) 10
Rationale: Let the number off boys in the group originally be x.
Total weight of the boys = 20x
After the boy weighing 32 kg joins the group, total weight of boys = 20x + 32
So 20x + 32 = 21(x + 1) = > x = 11.
ANSWER:B
Answer: (B) 11
Question: A shopkeeper buys mangoes at the rate of 5 a rupee and sells them at 3 a rupee. Find his net profit or loss percent?
(A) 33 4/3 %
(B) 33 1/7 %
(C) 40 %
(D) 32 1/3 %
(E) 50 %
Rationale: The total number of mangoes bought by the shopkeeper be 15.
If he buys 5 a rupee, his CP = 3
He selling at 3 a rupee, his SP = 5
Profit = SP - CP = 5 - 3 = 2
Profit Percent = 2/5 * 100 = 40 %
Answer:C
Answer: (C) 40 %
Question: The cost of10 kgs. of sugar is Rs.300. What is the cost of .200kgs. of sugar?
(A) Rs.3
(B) Rs.50
(C) Rs.5
(D) Rs.6
(E) Rs.60
Rationale: Explanation:
The cost of .200 kgs. of sugar = 300x .200/10 = Rs.6
Answer: Option D
Answer: (D) Rs.6
Question: A does a work in 10 days and B does the same work in 15 days. In how many days they together will do the same work ?
(A) 5 days
(B) 6 days
(C) 7 days
(D) 8 days
(E) 9 days
Rationale: Explanation:
Firstly we will find 1 day work of both A and B, then by adding we can get collective days for them,
So,
A's 1 day work = 1/10
B's 1 day work = 1/15
(A+B)'s 1 day work =
(1/10+1/15)=(3+2/30)=1/6
So together they can complete work in 6 days.
Option B
Answer: (B) 6 days
Question: A man can hit the target once in four shots. If he fires two shots in succession, what is the probability that he will hit the target?
(A) 7/16
(B) 1/256
(C) 81/256
(D) 175/256
(E) 185/256
Rationale: In two shots he can hit once,all hit
the probability of hitting the target is p(1hit out of 2+ p(All hit)
it is total probability-probability of not hitting the target
=>1-(3/4*3/4)
=>7/16
ANSWER:A
Answer: (A) 7/16
Question: 12 times a positive integer is more than its square by 36, then the positive integer is
(A) 6
(B) 10
(C) 11
(D) 12
(E) 14
Rationale: Explanation:
Let the number be x. Then,
12x = x2 + 36
=> x2 - 12x + 36 = 0
=>(x - 6)(x - 6) = 0
=> x = 6
Answer: A
Answer: (A) 6
Question: pipes P and Q would fill a cistern 18 and 24 minutes respectively. Both pipes being opened, find when the first pipe must be turned off so that the cistern may be just filled in 12 minutes?
(A) 2
(B) 9
(C) 8
(D) 7
(E) 5
Rationale: x/18 + 12/24 = 1
x = 9
Answer: B
Answer: (B) 9
Question: Machines P and Q are two different machines that cover jars in machine shop. When Machine P works alone, it covers 5 jars in m hours. When Machines P and Q work simultaneously at their respective rates, they cover 5 jars in n hours. In terms of m and n, how many hours does it take Machine Q, working alone at its constant rate, to cover 5 jars?
(A) m
(B) n
(C) m+n
(D) 5n/25-mn
(E) m-n
Rationale: working rate p = 5/m ; working rate pq =( 1/p +1/q)* n =5 or mn/5 +n/q =5 0r n/q = 5-mn/5 = 25-mn/5
q = 5n/25-mn
D
Answer: (D) 5n/25-mn
Question: Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed ?
(A) 412
(B) 512
(C) 312
(D) 112
(E) 122
Rationale: Let total number of children be x.
Then, (x) x 1/8x = (x/2)x 16
= x = 64.
Number of notebooks = 1/8 x2 = (1/8	x 64 x 64)	= 512.
Answer is B.
Answer: (B) 512
Question: A man sells two articles for Rs.2850 each and he gains 32% on the first and loses 18% on the next. Find his total gain or loss?
(A) 9%loss
(B) 2%loss
(C) 7%loss
(D) 6%loss
(E) 1%loss
Rationale: Explanation:
(32*18)/100
= 6%loss
Answer:D
Answer: (D) 6%loss
Question: The perimeter of a square is 48 m. Find the area of the square.
(A) 161 mÂ².
(B) 144 mÂ².
(C) 166 mÂ².
(D) 169 mÂ².
(E) 273 mÂ².
Rationale: Perimeter of square = 48 m
But perimeter of square = 4 Ã— side
Therefore, 4 Ã— side = 48 m
Therefore, side= 48/4 m = 12m
Now, the area of the square = (side Ã— side)
Therefore, area of the square = 12 Ã— 12 mÂ² = 144 mÂ².
ANSWER : OPTION B
Answer: (B) 144 mÂ².
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 48, the dividend is:
(A) 5336
(B) 5340
(C) 5342
(D) 5345
(E) 5808
Rationale: Divisor = (5 * 48) = 240
= 10 * Quotient = Divisor
=> Quotient = 240/10 = 24
Dividend = (Divisor * Quotient) + Remainder
Dividend = (240 * 24) + 48 = 5808
E
Answer: (E) 5808
Question: Five bells first begin to toll together and then at intervals of 5, 10, 15, 20 and 25 seconds respectively. After what interval of time will they toll again together?
(A) 5 min
(B) 5.5 min
(C) 5.2 min
(D) 6.2 min
(E) None
Rationale: LCM = 300/60 = 5 min
ANSWER:A
Answer: (A) 5 min
Question: As x increases from 131 to 132, which of the following increases?
I) x−1/x
II) 17−1/x
III) (17+x)/x
(A) I only
(B) II only
(C) I,II only
(D) II,III only
(E) III only
Rationale: On Increasing the value of x from 131 to 132
I) x−1/x will increase as 1/x will be very small and x will increase by 1 unit
II) 17−1/x Will Increase as the value of 1/x will decrease thereby increasing the value of 17-(1/x)
III) (17+x)/x = (17/x)+1 will Decrease as 1/x will decrease thereby decreasing the value of (17/x)
Answer:C
Answer: (C) I,II only
Question: 16 men can complete a piece of work in 25 days. In how many days can 20 men complete that piece of work?
(A) 27
(B) 29
(C) 20
(D) 22
(E) 12
Rationale: 16 * 25 = 20 * x => x = 20 days
Answer:C
Answer: (C) 20
Question: Two cars start at the same time from opposite ends of a highway that is 333 miles long. One car is riding at 54 mph and the second car is riding at 57 mph. How long after they begin will they meet?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: As cars are moving in opposite directions their speeds will be added. So their relative speeds: 57+54 = 111 mph
Total distance to be covered = 333 miles.
Time taken would be: 333 miles/111 mph = 3 hours
C is the answer.
Answer: (C) 3
Question: You have a rock solid dark chocolate bar of size 2 x 8. You need to break it and get 1 x 1 pieces of that chocolate.
If you can break that bar only along its length or breadth, how many times will you have to break to get the 1 x 1 pieces?
(A) 12 times.
(B) 13 times.
(C) 14 times.
(D) 15 times.
(E) 16 times.
Rationale: Solution:
There is a simple logic to solve this question.
The size of the chocolate is 2 x 8. Thus, you need to have 2 x 8 = 16 pieces.
Every time you break the chocolate, you will get one extra piece.
Thus, to get 16 pieces, you must break it (16 - 1) = 15 times.
Answer D
Answer: (D) 15 times.
Question: The price of an item is discounted 5 percent on day 1 of a sale. On day 2, the item is discounted another 10 percent, and on day 3, it is discounted an additional 15 percent. The price of the item on day 3 is what percentage of the sale price on day 1?
(A) 28%
(B) 40%
(C) 64.8%
(D) 76.5%
(E) 78%
Rationale: Let initial price be 1000
Price in day 1 after 5% discount = 950
Price in day 2 after 10% discount = 855
Price in day 3 after 15% discount = 726.75
So, Price in day 3 as percentage of the sale price on day 1 will be = 726.75/950*100 => 76.5%
Answer will definitely be (D)
Answer: (D) 76.5%
Question: A and B started a partnership business investing some amount in the ratio of 7 : 5. C joined then after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed among A, B and C?
(A) 4 : 9 : 8
(B) 5 : 7 : 4
(C) 6 : 10 : 5
(D) 14 : 10: 5
(E) 5 : 4 : 8
Rationale: Let the initial investments of A and B be 7x and 5x.
A : B : C = (7x x 12) : (5x x 12) : (5x x 6) = 84 : 60 : 30
= 14 : 10 : 5.
ANSWER :D
Answer: (D) 14 : 10: 5
Question: 6 people meet for a business gathering. Each person shakes hands once with each other person present. How many handshakes take place?
(A) 30
(B) 21
(C) 18
(D) 15
(E) 10
Rationale: Let's look at the logic.
Every person shakes hand with other '5'. So, 6 people shake hands with 6X5= 30 people
But in this 30 we have counted two times the total handshakes (m shakes hand with n and n shakes hand with m)
So just divide 30/2= 15 total handshakes
Answer is D
Answer: (D) 15
Question: Find a two digit number, given that the sum of the digits is 9 and the difference of the digits is 3.?
(A) 75
(B) 63
(C) 83
(D) 94
(E) 39
Rationale: Using elimination method find which of the options fit the description of the number
... from the option only 63 meets this description
sum of digits---6+3 = 9
difference of digits ---6-3 = 3
Answer B.
Answer: (B) 63
Question: If 20% of 30 is greater than 25% of a number by 2, the number is:
(A) 16
(B) 24
(C) 20
(D) 32
(E) None of these
Rationale: Explanation :
=>20/100 * 30 - 25/100 * x = 2
=> x/4 = 4 so x = 16
Answer : A
Answer: (A) 16