mathewhe/aqua_rat huggingface dataset:
Question: Which of the following CANNOT be a value of 8/(x–8)?
(A) -1
(B) -1/2
(C) 0
(D) 2
(E) 8
Rationale: The question doesn't ask for the value of x here, but for the possible results of the equation.
If 8/(x-8) = 0, then the numerator must be 0. But since the numerator is 8, the fraction can not be equal to 0.
The answer is C.
Answer: (C) 0
Question: Alok ordered 16 chapatis, 5 plates of rice, 7 plates of mixed vegetable and 6 ice-cream cups. The cost of each chapati is Rs.6, that of each plate of rice is Rs.45 and that of mixed vegetable is Rs.70. The amount that Alok paid the cashier was Rs.1021. Find the cost of each ice-cream cup?
(A) 35
(B) 66
(C) 77
(D) 99
(E) 91
Rationale: Let the cost of each ice-cream cup be Rs.x
16(6) + 5(45) + 7(70) + 6(x) = 1021
96 + 225 + 490 + 6x = 1021
6x = 210 => x = 35.
Answer: A
Answer: (A) 35
Question: If green means red, red means yellow, yellow means blue, blue means orange and orange means green, what is the colour of sun ?
(A) Blue
(B) Red
(C) Yellow
(D) Orange
(E) Pink
Rationale: Explanation:
The colour of sun is 'yellow' and as given 'red' means 'yellow'.
so, the colour of sun is 'red'.
Answer: B
Answer: (B) Red
Question: Before leaving home for the town of Madison, Pete checks a map which shows that Madison is 5 inches from his current location, Gardensquare. Pete arrives in Madison 6.5 hours later and drove at an average speed of 60 miles per hour. At what scale, in inches per mile, is the map drawn?
(A) 1/3
(B) 1/30
(C) 1/10
(D) 1/78
(E) 30
Rationale: Pete covered 6.5*60=390 miles which correspond to 5 inches on the map --> scale in inches per mile is 5/390=1/78.
Answer: D.
Answer: (D) 1/78
Question: How many times digit 2 is used while writing numbers from 400 to 700?
(A) 150
(B) 190
(C) 250
(D) 80
(E) 130
Rationale: in 400 to 500 there are 50 two's
in 500 to 600 there are 50 two's
in 600 to 700 there are 50 two's
so total is 150 two's
CORRECT OPTION :A
Answer: (A) 150
Question: A trader bought a car at 10% discount on its original price. He sold it at a 80% increase on the price he bought it. What percent of profit did he make on the original price?
(A) 17%
(B) 62%
(C) 12%
(D) 19%
(E) 22%
Rationale: Original price = 100
CP = 90
S = 90*(180/100) = 162
100 - 162 = 62%
Answer: B
Answer: (B) 62%
Question: A car traveled 45% of the way from Town A to Town B at an average speed of 45 mph.
The car traveled at an average speed of v mph for the remaining part of the trip.
The average speed for the entire trip was 50 mph. What is v in mph?
(A) 45
(B) 55
(C) 65
(D) 43
(E) 42
Rationale: Assume total distance = 100miles
Time taken for 45 miles = 45/45 = 1 hour
Time taken for the rest of the 55 miles = 55/v hours.
Average speed = 50
Therefore the total time needed = 2 hours.
2 = 1 + 55/v
Hence v = 55 mph
Answer : B
Answer: (B) 55
Question: One-sixth of the attendees at a certain convention are female students, two-thirds of the attendees are female, and one-third of the attendees are students. If 100 of the attendees are neither female nor students, what is the total number of attendees at the convention?
(A) 600
(B) 700
(C) 800
(D) 900
(E) 1000
Rationale: Let no. of Attendee are A.
Now As per the condition of the problem stated above .
We have following population in the convention as Attendee.
Total no. of females = [2/3]*A
Total no. of females as student : [1/6]*A
Total no. of students = [1/3]*A
Total no. of male as student = [1/6]*A
Total no. of males = A - [2/3]*A = [1/3]A
No. of males which are not student = [1/3]A - [1/6]*A = 100
Hence A = 600
So Answer is A
Answer: (A) 600
Question: Length of a rectangular plot is 14 mtr more than its breadth. If the cost of fencing the plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
(A) 50 m
(B) 57 m
(C) 80 m
(D) 82 m
(E) 84 m
Rationale: Let breadth = x metres.
Then, length = (x + 14) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 14) + x] = 200
2x + 14 = 100
2x = 86
x = 43.
Hence, length = x + 14 = 57 m
B
Answer: (B) 57 m
Question: A car traveling at a certain constant speed takes 10 seconds longer to travel 1 km than it would take to travel 1 km at 80 km/hour. At what speed, in km/hr, is the car traveling?
(A) 70
(B) 72
(C) 74
(D) 65
(E) 78
Rationale: Time to cover 1 kilometer at 80 kilometers per hour is 1/80 hours = 3,600/80 seconds = 45 seconds;
Time to cover 1 kilometer at regular speed is 45 + 10 = 55 seconds = 55/3,600 hours = 1/65 hours;
So, we get that to cover 1 kilometer 1/65 hours is needed --> regular speed 65 kilometers per hour (rate is a reciprocal of time or rate=distance/time).
Answer: D
Answer: (D) 65
Question: A room 5m 55cm long and 3m 74cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor?
(A) 176
(B) 175
(C) 185
(D) 188
(E) None
Rationale: Solution
Area of the room	= (544 x 374)cm ²
Size of largest square tile	= H.C.F of 544 & 374cm
= 34 cm
Area of 1 tile	= (34 x 34)cm²
Number of tiles required	= [544 x 374 / 34 x 34]
= 176.
Answer A
Answer: (A) 176
Question: On Sunday morning, Pugsley and Wednesday are trading pet spiders. If Pugsley were to give Wednesday two of his spiders, Wednesday would then have nine times as many spiders as Pugsley does. But, if Wednesday were to give Pugsley six of her spiders, Pugsley would now have six fewer spiders than Wednesday had before they traded. How many pet spiders does Pugsley have before the trading game commences?
(A) 4
(B) 6
(C) 8
(D) 10
(E) 20
Rationale: If Pugsley were to give Wednesday two of his spiders, Wednesday would then have nine times as many spiders as Pugsley does:
(w + 2) = 9(p - 2)
If Wednesday were to give Pugsley six of her spiders, Pugsley would now have six fewer spiders than Wednesday had before they traded:
p + 6 = w - 6
Solving gives p = 4 and w = 16.
Answer: A.
Answer: (A) 4
Question: The average of the marks of 25 students in a class is 70. If the marks of each student are doubled, find the new average?
(A) 140
(B) 100
(C) 85
(D) 160
(E) 190
Rationale: Sum of the marks for the 25 students
= 25 * 70 = 1750. The marks of each student are doubled, the sum also will be doubled.
The new sum = 1750 * 2 = 3500. So, the new average
= 3500/25 = 140.
Answer:A
Answer: (A) 140
Question: If A and B get profits of Rs.60,000 and Rs.6,000 respectively at the end of year then ratio of their investments are
(A) 4:1
(B) 10:1
(C) 3:2
(D) 2:3
(E) 2:5
Rationale: Ratio = 60000/6000 = 10 : 1
Answer : B
Answer: (B) 10:1
Question: A horse is tethered to one corner of a rectangular grassy field 42 m by 26 m with a rope 16 m long. Over how much area of the field can it graze?
(A) 154 cm2
(B) 308 m2
(C) 201 m2
(D) 205 m2
(E) None of these
Rationale: Area of the shaded portion
= 1⁄4 × π × (16)2 = 201 m2
Answer C
Answer: (C) 201 m2
Question: The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
(A) 70, 10 kmph
(B) 35, 27 kmph
(C) 50, 60 kmph
(D) 45, 55 kmph
(E) 45, 65 kmph
Rationale: Speed of the boat in still water = (60+80)/2 = 70 kmph. Speed of the stream = (80-60)/2 = 10 kmph
ANSWER:A
Answer: (A) 70, 10 kmph
Question: Two dice are tossed. The probability that their product is a prime number is:
(A) 1/12
(B) 1/6
(C) 1/4
(D) 2/9
(E) 2/2
Rationale: Explanation :
Number of possible outcomes = 6x6 = 36.
Favourable outcomes = {1x2,1x3,1x5,2x1,3x1,5x1}
Number of favourable outcomes = 6.
Hence, probability of the event = 6/36 = 1/6.
Answer : B
Answer: (B) 1/6
Question: In a rectangular coordinate system, if a line passes through the points (-12,-18), (18,22) and (x,2) then what is the value of x?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: The slope of the line m is rise/run = 22-(-18) / 18-(-12) = 4/3
4/3 = 22-2 / 18-x
72-4x = 66-6
x = 3
The answer is B.
Answer: (B) 3
Question: hat should come in place of question mark (?) in the following equation ?
197 × ? + 16(2) = 2620
(A) 22
(B) 12
(C) 14
(D) 16
(E) None of these
Rationale: ? = 2620−256 /197=12
Answer B
Answer: (B) 12
Question: A man took loan from a bank at the rate of 12% p.a. S.I. After 10 years he had to pay Rs. 1500 interest only for the period. The principal amount borrowed by him was?
(A) 1502
(B) 1900
(C) 1250
(D) 1750
(E) 2000
Rationale: Principal = (100 * 1500) / (12 * 10)
= Rs.1250
Answer: C
Answer: (C) 1250
Question: Consider a lady took a loan from a bank at the rate of 12% p.a. simple interest. After 3 years she had to pay Rs. 7200 interest only for the period. The principal amount borrowed by her was
(A) Rs. 2000
(B) Rs. 10000
(C) Rs. 15000
(D) Rs. 20000
(E) None of these
Rationale: Explanation :
Principal = Rs. (100×7200 / 12×3)
=> Rs. 20,000.
Answer : D
Answer: (D) Rs. 20000
Question: What annual payment will discharge a debt of Rs. 1025 due in 2 years at the rate of 5% compound interest?
(A) Rs. 550
(B) Rs. 551.25
(C) Rs. 560
(D) Rs. 560.75
(E) Rs. 660.75
Rationale: Let each installment be Rs. x. Then,
x/(1 + 5/100) + x/(1 + 5/100)2 = 1025
820x + 1025 * 441
x = 551.25
So, value of each installment = Rs. 551.25
ANSWER:B
Answer: (B) Rs. 551.25
Question: What is the last digit of (2^3)^4 ?
(A) 0
(B) 2
(C) 6
(D) 4
(E) 8
Rationale: the unit digit of
2^1=2
2^5=2
2^9=2 and so on
therefore, 2^81 =2
Hence the correct option is B
Answer: (B) 2
Question: Anil invested a sum of money at a certain rate of simple interest for a period of five years. Had he invested the sum for a period of eight years for the same rate, the total intrest earned by him would have been sixty percent more than the earlier interest amount. Find the rate of interest p.a.
(A) 8PR/108
(B) 8PR/100
(C) 8PR/102
(D) 8PR/100
(E) 8PR/101
Rationale: Let the sum be Rs.P. Let the rate of interest be R% p.a.
(P)(8)(R)/100 = [1 + 6/100][ (P)(5)(R) /100] = 1.6{5PR/100]
8PR/100 = 8PR/100
Answer: D
Answer: (D) 8PR/100
Question: When positive integer x is divided by 11, the quotient is y and the remainder is 4. When 2x is divided by 8, the quotient is 3y and the remainder is 1. What is the value of 13y – x ?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: (1) x = 11y + 4
(2) 2x = 24y + 1
Let's subtract equation (1) from equation (2).
13y - 3 = x
13y - x = 3
The answer is B.
Answer: (B) 3
Question: If x is a positive integer, f(x) is defined as the number of positive integers which are less than x and do not have a common factor with x other than 1. If x is prime, then f(x) =?
(A) x-2
(B) x-1
(C) (x+1)/2
(D) (x-1)/2
(E) 2
Rationale: x is a prime, all positive numbers less than x have no common factors with x (except common factor 1). So there would be x-1 such numbers (as we are looking number of integers less than x).
If we consider x=7 how many numbers are less than 7 having no common factors with 7: 1, 2, 3, 4, 5, 6 --> 7-1=6.
Answer: B.
Answer: (B) x-1
Question: If q and y are positive integer and q/y is an even integer, which of the following can be an odd integer?
(A) x
(B) xy
(C) x−y
(D) x+2y
(E) q/3
Rationale: C q-Y
Let says q =12 Y=3 iT BECOMES q-Y =9 This is odd True
q = 12 Y = 6 THEN q-Y = 2, Which is even hence this is False.
so both Yes and NO situations are exists for this Option. C can't be the correct answer same logic goes for E. I believe this question is incomplete b'coz of Irrelevant Options.
Answer: (E) q/3
Question: Cheese, bologna, and peanut butter sandwiches were made for a picnic in a ratio of 4 to 5 to 11. If a total of 120 sandwiches were made, how many bologna sandwiches
were made?
(A) 15
(B) 30
(C) 38
(D) 42
(E) 48
Rationale: For deciding such task we should calculate all parts 4 + 5 + 11 = 20 parts
and we should calculate how many sandwiches holds 1 part:
120 / 20 = 6 sandwiches in one part
For bologna we have 7 parts so:
5* 6 = 30
Answer is B
Answer: (B) 30
Question: P and Q can complete a work in 20 days and 12 days respectively. P alone started the work and Q joined him after 4 days till the completion of the work. How long did the work last?
(A) 5 days
(B) 9 days
(C) 30 days
(D) 20 days
(E) 10 days
Rationale: Work done by P in 1 day = 1/20
Work done by Q in 1 day = 1/12
Work done by P in 4 days = 4 × (1/20) = 1/5
Remaining work = 1 – 1/5 = 4/5
Work done by P and Q in 1 day = 1/20 + 1/12 = 8/60 = 2/15
Number of days P and Q take to complete the remaining work = (4/5) / (2/15) = 6
Total days = 4 + 6 = 10
ANSWER:E
Answer: (E) 10 days
Question: For some integer m, m^2 - 5 is divisible by all of the following EXCEPT
(A) 38
(B) 41
(C) 30
(D) 31
(E) 29
Rationale: Hint: m^2-5 (m is an integer) is never multiple of 3 (try to prove this), hence 30 is out.
Answer: C
Answer: (C) 30
Question: John deposited $10,000 to open a new savings account that earned 8 percent annual interest, compounded quarterly. If there were no other transactions in the account, what was the amount of money in John’s account 6 months after the account was opened?
(A) $10,100
(B) $10,101
(C) $10,200
(D) $10,201
(E) $10,404
Rationale: 8 percent annual interest compounded quarterly --> 2% in 3 moths.
For the first 3 moths interest was 2% of $10,000, so $200;
For the next 3 moths interest was 2% of $10,000,plus 4 earned on previous interest of $100, so $200+$4=$204;
Total interest for 6 months was $200+$204=$404, hence balance after 6 months was $10,000+ $404=$10,404.
Answer:E.
Answer: (E) $10,404
Question: The number of the members of a club is more than 50 and less than 80. When 4 people sit at a table, other people exactly divided to 8-people groups (8 people sit at a table) or 7-people groups (7 people sit at a table). If the members are divided to 9-people groups, how many people will be left?
(A) 0
(B) 2
(C) 4
(D) 6
(E) 8
Rationale: The number of members is 7k+4 = 8j+4
The only number in this range which satisfies this is 60.
60/9 = 6(9) + 6
The answer is D.
Answer: (D) 6
Question: A sum was put at simple interest at a certain rate for 3 years. Had it been put at 2% higher rate, it would have fetched Rs. 360 more. Find the sum.
(A) Rs. 600
(B) Rs. 60
(C) Rs. 60000
(D) Rs. 600000
(E) Rs. 6000
Rationale: Let sum = P and original rate = R.
Then, [ (P*(R+2)*3)/100] – [ (P*R*3)/100] = 360.
3PR + 6P - 3PR = 36000
6P=36000
P=6000
Hence, sum = Rs. 6000
Answer is E.
Answer: (E) Rs. 6000
Question: The length of rectangle is thrice its breadth and its perimeter is 88 m, find the area of the rectangle?
(A) 432 sq m
(B) 363 sq m
(C) 452 sq m
(D) 428 sq m
(E) 525 sq m
Rationale: 2(3x + x) = 88
l = 33 b = 11
lb = 33 * 11 = 363
ANSWER:B
Answer: (B) 363 sq m
Question: A rectangular tiled patio is composed of 80 square tiles. The rectangular patio will be rearranged so that there will be 2 fewer columns of tiles and 4 more rows of tiles. After the change in layout, the patio will still have 80 tiles, and it will still be rectangular. How many rows are in the tile patio before the change in layout?
(A) 5
(B) 6
(C) 10
(D) 12
(E) 28
Rationale: r*c=80 and (12+4)(c-2)=80 --> r=12 and c=7.
Answer: D.
Answer: (D) 12
Question: The distance from Steve's house to work is 35 Km. On the way back Steve drives twice as fast as he did on the way to work. Altogether, Steve is spending 6 hours a day on the roads. What is Steve's speed on the way back from work?
(A) 5.
(B) 10.
(C) 14.
(D) 15.
(E) 17.5
Rationale: Time is in the ratio 2:1 :: to: fro office
Therefore, 2x+1x=6 hrs
Time take to come back - 2 hrs, distance travelled - 35km => Speed = 17.5kmph
E
Answer: (E) 17.5
Question: During a certain two-week period, 60 percent of the movies rented from a video store were comedies, and of the remaining movies rented, there were 3 times as many dramas as action movies. If no other movies were rented during that two-week period and there were A action movies rented, then how many comedies, in terms of A, were rented during that two-week period?
(A) 5 A
(B) 6 A
(C) 8 A
(D) 14 A
(E) 20 A
Rationale: Movies: 60 % comedies. 40 % remaining genre.
Now in this 40 %, there are only 2 categories. Action movies and Drama Movies.
If Action = x; Drama movies = 3x. Total 4x.
4x = 40; x = 10
Action movies: 10 %
Drama movies: 30 %
we can say that out of 100z,:
comedies: 60z
action: 10z
drama: 30 z
Now action movies wereA
This means:
A = 10z.
z = (A/10)
Comedies: 60z = 60 * (A/10)
6 A
B is the answer.
Answer: (B) 6 A
Question: For any natural number n, F(n) is the least common multiple of all natural numbers upto. For how many values of n less than 100, F(n+1) - F(n) = 0?
(A) 33
(B) 64
(C) 29
(D) 27
(E) 01
Rationale: F(n) is the LCM of al natural numbers upto n.
For example,
F(3) = 6
F(5) = 60
F(6) = 60 etc.
F(n + 1) - F(n) = 0
⇒⇒ F(n + 1) = F(n)
It would hapen only when factors of (n + 1) are already present in the LCM of first n natural numbers. In other words, Whenever (n + 1) is Prime number or is any Integral power of any prime number, F(n + 1) ≠≠ F(n)
for example, F(31) ≠≠ F(32) as 32 = 2525 which is, 2 raised to power 5. or F(4) ≠≠ F(5) as 5 is prime so the power of 5 does not contain in F(4).
Between 1 and 100, there are 25 prime numbers. So if (n+1) is one of these number then F(n + 1) ≠≠ F(n).
Also {4, 8, 16, 32, 64, 9, 27, 81, 25, 49} are prime numbers raised to some exponent.
Hence, none of these 35 numbers from 1 to 99 cannot be the possible values of n. So for 99 - 35 = 64 numbers F(n)
= F(n+1)
Answer:B
Answer: (B) 64
Question: How many integers between 263,205and 658,805 have tens digit 1 and units digit 3?
(A) 3,955
(B) 3,925
(C) 3,956
(D) 3,926
(E) 3,915
Rationale: There is one number in hundred with 1 in the tens digit and 3 in the units digit: 13, 113, 213, 313, ...
The difference between 263,205 and is 658,805 -263205=395,600 - one number per each hundred gives 133,900/100=3,956
Answer:C.
Answer: (C) 3,956
Question: What is the perimeter of a regular polygon with sides of length 15 cm and internal angles measuring 145° each?
(A) 96 cm
(B) 108 cm
(C) 120 cm
(D) 132 cm
(E) 154.28 cm
Rationale: Sum of all interior angles is given by:
180(n-2) = n is number of sides
180(n-2) = 145*n
from here
n = 10.28
So perimeter becomes 15*10.28= 154.28
Answer: E
Answer: (E) 154.28 cm
Question: A man can row with a speed of 15 kmph in still water. If the stream flows at 20 kmph, then the speed in downstream is?
(A) 27
(B) 27
(C) 20
(D) 99
(E) 35
Rationale: M = 15
S = 25
DS = 15 + 25 = 35
Answer:E
Answer: (E) 35
Question: Every person in a certain group is either a Cowboys fan or a Saints fan, but not both. The ratio of Cowboys fans to Saints fans is 6 to 4. If 54 Cowboys fans change teams to become Saints fans, the ratio of Saints fans to Cowboys fans will be 1 to 1. How many people are in the group?
(A) 90
(B) 64
(C) 30
(D) 360
(E) 240
Rationale: By checking the answer choices:
Since we have a initial ratio of 6:4, the total count should be divisible by 10.
A. 90/10=9, Cowboys Fan = 54, Saints Fan = 27, Since 54-54 is not equal to 27+54 this can not be the answer.
B. Out, since not divisible by 10.
C. 30/10=3, Cowboys Fan = 36, Saints Fan = 9, Since 36-54 is not equal to 9+54 this as well can not be the answer.
D. 360/10=36, Cowboys Fan = 216, Saints Fan = 108, Since 216-54 equal to 108+54 this is the correct answer.
E. 240/10=24, Cowboys Fan = 144, Saints Fan = 72, Since 144-54 is not equal to 72+54 this as well can not be the answer.
D is the correct answer.
Answer: (D) 360
Question: In what time a sum of money double itself at 4% per annum simple interest?
(A) 25%
(B) 33 1/3%
(C) 83 1/3%
(D) 33 4/3%
(E) 73 1/3%
Rationale: P = (P*4*R)/100
R = 25%
Answer:A
Answer: (A) 25%
Question: Cara and Dan will throw three dice each. The score is the sum of points on all three dice. If Cara scores 16 in her attempt, what is the probability that Dan will outscore Cara in his attempt?
(A) 1/36
(B) 1/54
(C) 5/54
(D) 1/216
(E) 5/216
Rationale: The total number of ways the dice can land is 6*6*6=216.
Dan can get a score of 18=6+6+6
There is only 1 way to do this.
Dan can get a score of 17=6+6+5
There are 3 ways to do this.
P(Dan wins)=4/216=1/54
The answer is B.
Answer: (B) 1/54
Question: Each of the three people individually can complete a certain job in 4, 5, and 6 hours, respectively. What is the lowest fraction of the job that can be done in 1 hour by 2 of the people working together at their respective rates?
(A) 4/15
(B) 7/30
(C) 11/30
(D) 5/18
(E) 7/18
Rationale: The two slowest people work at rates of 1/5 and 1/6 of the job per hour.
The sum of these rates is 1/5 + 1/6 = 11/30 of the job per hour.
The answer is C.
Answer: (C) 11/30
Question: A car traveled 40% of the way from Town X to Town Y at an average speed of 40 mph. The car traveled at an average speed of v mph for the remaining part of the trip. The average speed for the entire trip was 50 mph. What is v in mph?
(A) 50
(B) 45
(C) 55
(D) 60
(E) 65
Rationale: Assume total distance = 100miles
Time taken for 40 miles = 40/40 = 1 hour
Time taken for the rest of the 60 miles = 60/v hours.
Average speed = 50
Therefore the total time needed = 2 hours.
2 = 1 + 60/v
Hence v = 60 mph
Answer : D
Answer: (D) 60
Question: The ratio of the volumes of two cubes is 343 : 512. What is the ratio of their total surface areas?
(A) 12:24
(B) 8:16
(C) 45:25
(D) 18:56
(E) 49:64
Rationale: Ratio of the sides = Â³âˆš343 : Â³âˆš512
= 7 : 8
Ratio of surface areas =49:64
Answer: E
Answer: (E) 49:64
Question: A car mechanic purchased four old cars for Rs. 1 lakh. He spent total 2 lakh in the maintenance and repairing of these four cars. what is the average sale price of the rest three cars to get 40% total profit if he has already sold one of the four cars at Rs. 1.2 lakh?
(A) 1.8 lakh
(B) 1.0 lakh
(C) 1.9 lakh
(D) 8.1 lakh
(E) 6.1 lakh
Rationale: Explanation:
Total cost of 4 cars = 1+2 = 3 lakh
Total SP of 4 cars = 3 x 1.4 = 4.2 lakh
SP of 1 car = 1.2 lakh
SP of rest 3 cars = 4.2 - 1.2 = 3 lakh
Average SP of all the 3 cars = 1 lakh
Answer: B) 1 lakh
Answer: (B) 1.0 lakh
Question: 3 persons started placementpapers with a capital of Rs.3000 . B invest Rs.600 less than A, C invest Rs.300 less than B. Then what is the share amount of B in a profit of Rs.886 ?
(A) Rs.245.8
(B) Rs.265.8
(C) Rs.285.8
(D) Rs.365.8
(E) Rs.165.8
Rationale: a+(a-600)+(a-900)=3000
sove then a=1500 (50%)
b=900 (30%)
c=600 (20%)
Hence share for B = 886*30/100 => B share = Rs.265.8
ANSWER:B
Answer: (B) Rs.265.8
Question: A jogger running at 9 km/hr along side a railway track is 200 m ahead of the engine of a 210 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
(A) 89
(B) 20
(C) 36
(D) 41
(E) 34
Rationale: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 200 + 210 = 410 m.
Time taken = 410/10 = 41 sec.
Answer: Option D
Answer: (D) 41
Question: Two equilateral triangle of side 12cm are placed one on top another, such a 6 pionted star is formed if the six vertices lie on a circle what is the area of the circle not enclosed by the Star?
(A) 21
(B) 88937
(C) 269
(D) 279
(E) 2701
Rationale: Answer:A
Answer: (A) 21
Question: Rectangular tile each of size 70cm by 30cm must be laid horizontally on a rectangular floor of size 110cm by 130cm,such that the tiles do not overlap and they are placed with edges jutting against each other on all edges. A tile can be placed in any orientation so long as its edges are parallel to the edges of floor. No tile should overshoot any edge of the floor. The maximum number of tiles that can be accommodated on the floor is:
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
Rationale: Area of tile = 70*30 = 2100
Area of floor = 130*110 = 14300
No of tiles = 14300/2100 = 6.8
So, the no of tile = 6
ANSWER:B
Answer: (B) 6
Question: If x is positive integer,y is negative integer, and 5x+2y=4, which of the following could be the value of x ?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
Rationale: Use answer options to solve this problem -
Put x = 2
So, 5x+2y=4
Or, 5(2)+2y=4
Or, 10+2y=4
Or, 2y=4-10;2y=-6
Or, y=-3(y is negative integer)
Answer will be (C)
Answer: (C) 2
Question: Each of the cucumbers in 100 pounds of cucumbers is composed of 99% water, by weight. After some of the water evaporates, the cucumbers are now 98% water by weight. What is the new weight of the cucumbers, in pounds?
(A) 2
(B) 50
(C) 92
(D) 96
(E) 98
Rationale: Out of 100 pounds 99% or 99 pounds is water and 1 pound is non-water. After some water evaporates the cucumbers become 98% water and 2% of non-water, so now 1 pound of non-water composes 2% of cucucmbers, which means that the new weight of cucumbers is 1/0.02=50 pounds.
Answer: B.
Answer: (B) 50