mathewhe/aqua_rat huggingface dataset:
Question: James celebrated his 23rd Birthday on 2016 but he was strangely born in 1950. How can this be possible?
(A) 1250
(B) 1850
(C) 1980
(D) 1950
(E) 1750
Rationale: D
I was born in Hospital whose room number is 1950.
Answer: (D) 1950
Question: The average expenditure of a man for the first five months is Rs.240 and for the next seven months it is Rs.130. If he saves Rs.290 in that year, his monthly average income is :
(A) Rs.140
(B) Rs.150
(C) Rs.160
(D) Rs.200
(E) none
Rationale: Explanation:
Total income = Rs.(240Ã—5+130Ã—7+290)=Rs.2400
Average monthly income
= Rs. (2400/12)=Rs.200
Correct Option: D
Answer: (D) Rs.200
Question: In the board game Yahtzee one way to get a lot of points is to roll a "Yahtzee", which is rolling the same number for all five six-sided dice. What is the probability that you will roll a Yahtzee on your first roll?
(A) Less than 0.1%
(B) Between 0.1% and 0.5%
(C) Between 0.5% and 1%
(D) Between 1% and 2%
(E) Greater than 2%
Rationale: The acceptable rolls we need are any quad-tuple: 11111, 22222, 33333, 44444, 55555, and 66666. This makes 6 possibilities. The dice can fall in a combined 6*6*6*6*6 ways.
Hence the probability is 6/6^5 = 1/6^4 = 0.00077 = 0.077%
< 0.1%.
Answer: A
Answer: (A) Less than 0.1%
Question: A sum of Rs.4000 is lent out in two parts, one at 8% simple interest and the other at 10% simple interest. In the annual interest is Rs.352, the sum lent at 8% is
(A) 2376
(B) 3678
(C) 3657
(D) 2400
(E) 2661
Rationale: S.I = PNR/100
Answer with Explanation: Step (i) Given the total sum = Rs. 4000 Let the sum lent at 8% be Rs.x Let the sum lent at 10% be Rs. 4000 – x Ie) P = x , n=1, R = 8% P = 4000-x , n=1, R = 10%
100 81 XxX =
100 8x
100 1014000 XxX =
100 1040000 x 
Given annual interest = Rs. 352
100 8x +
100 1040000 x  = 352 8x – 10x = 35200 – 40000 -2x = -4800
X =
2 4800 = Rs.2400/-
Answer:D
Answer: (D) 2400
Question: The length of a rectangular garden is three times its width. If the area of the rectangular garden is 588 square meters, then what is the width of the rectangular garden?
(A) 12
(B) 13
(C) 14
(D) 15
(E) 16
Rationale: Let x be the width of the garden.
3x^2 = 588
x^2 = 196
x = 14
The answer is C.
Answer: (C) 14
Question: A class consists of 4 boys and 5 girls. Given that one kid can only hold one title, in how many ways can you pick 2 boys to be the class clown and the teacher's pet or 2 girls to be the most beautiful girl in class and the smartest kid on the block?
(A) 9
(B) 32
(C) 36
(D) 60
(E) 240
Rationale: Easiest way is to treat it like an arrangements question in the following manner:
From the boys we need to select 2 to be clown and pet: This can be done in 3*4 ways
Similarly for the girls, we have 4*5 ways.
Thus total = 20+12 = 32 ways. Thus B is the correct answer.
Answer: (B) 32
Question: a number divided by 44 leaves remainder 12 what is the remainder when same number divided by 12
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
Rationale: add 44+12=56
now 56divided by 12 so we get 8 as reaminder
ANSWER:B
Answer: (B) 8
Question: A,B and C started a business by investing Rs.2000/- , Rs.3000/- and Rs.4000/- respectively. Total profit is Rs.4500/-. Find the A’s share?
(A) Rs.1000/-
(B) Rs.1500/-
(C) Rs.2000/-
(D) Rs.3000/-
(E) Rs.3400/-
Rationale: A = Rs.2000/- , that is 2 parts
B = Rs.3000/- , that is 3 parts
C = Rs.4000/- , that is 4 parts
Total 9 parts -------> profit (4500/-)
----->1 part -------->Rs.500/-
then A's share 2 parts -----> Rs.1000/-
A
Answer: (A) Rs.1000/-
Question: If x and y are positive integers, and x^3*y^4 = 3456, which of the following is the value of xy?
(A) 6
(B) 10
(C) 12
(D) 14
(E) 16
Rationale: 3456 = 2^7*3^3 = 2^4*6^3
xy = 2*6 = 12
The answer is C.
Answer: (C) 12
Question: Suppose that the angle between the minute hand and hour hand of a
clock is 60o. If the minute hand is 16 inches long and the hour hand is
10 inches long, then what is the distance between the tip ends of the
hands in inches?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
Rationale: This is a direct application of the Law of Cosines with two sides of a triangle
having lengths 10 inches and 16 inches and the angle between them being 60. If x denotes
the distance between the tips of the hands in inches, then
x2<-(square) = 102 +16-2<-(square)-2*10*16cos(60o)= 100 + 256-160 = 196
Hence, x = 14.
correct answer E
Answer: (E) 14
Question: If 20 typists can type 48 letters in 20 minutes, then how many letters will 30 typists working at the same rate complete in 1 hour?
(A) 63
(B) 72
(C) 144
(D) 216
(E) 400
Rationale: 20 typists can type 48 letters, so 30 typists can type = 48*30/20
48*30/20 letters can be typed in 20 mins. In 60 mins typist can type= 48*30*60/20*20= 216
D is the answer
Answer: (D) 216
Question: The ratio of number of boys and girls in a school is 3:5. If there are 320 students in the school, find the number of girls in the school?
(A) 150
(B) 250
(C) 300
(D) 200
(E) 280
Rationale: Let the number of boys and girls be 3x and 5x
Total students = 320
Number of girls in the school = 5*320/8 = 200
Answer is D
Answer: (D) 200
Question: If 1.5 a = 0.03 b, then the value of (b – a)/ (b + a) is
(A) 490/51
(B) 49/51
(C) 4.9/51
(D) 4.99/51
(E) None of these
Rationale: Explanation:
a/b = 0.03/1.5 = 3/150 = 1/50
(b – a)/(b + a)
= (1 – a/b)/((1 + a/b)
= (1 – 1/50)/ (1 + 1/50)
= 49/51
ANSWER B
Answer: (B) 49/51
Question: There is enough provisions for 600 men in an army camp for 25 days. If there were 250 men less, how long will the provision last?
(A) 10days
(B) 40days
(C) 50days
(D) 60days
(E) 80days
Rationale: Exp: We have, M1D1 = M2D2
600*25= 250* D2
D2 = 600*25/250 = 60 days.
Answer: D
Answer: (D) 60days
Question: The sale price sarees listed for Rs.495 after successive discount is 15% and 10% is?
(A) 288
(B) 378
(C) 342
(D) 662
(E) 262
Rationale: 495*(85/100)*(90/100)
= 378
Answer: B
Answer: (B) 378
Question: A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. If the smaller wheel has made 28 revolutions, what will be the number of revolutions made by the larger wheel?
(A) 15
(B) 12
(C) 21
(D) 9
(E) 22
Rationale: Explanation:
Let the number of revolutions made by the larger wheel be x
More cogs, less revolutions (Indirect proportion)
Hence we can write as
(cogs) 6 : 14 :: x : 28
â‡’6Ã—28=14 Ã— x
â‡’x = 12
Answer: Option B
Answer: (B) 12
Question: (1.00001)(0.99999) - (1.00005)(0.99995) =
(A) 0
(B) 10^-10
(C) 3(10^-10)
(D) 10^-5
(E) 24(10^-10)
Rationale: (1.00001*0.99999)-(1.00005*0.99995)
= (1+0.00001)(1-0.00001) - (1+0.00005)(1-0.00005)
= 1 - (0.00001)^2 - 1 + (0.00005)^2
= -(0.0000000001) + (0.0000000025)
= 0.00000000024=24(10^-10)
Answer E
Answer: (E) 24(10^-10)
Question: In each series, look for the degree and direction of change between the numbers. In other words, do the numbers increase or decrease, and by how much
Look at this series: 1.4, 2.4, 3.4, 4.4, ... What number should come next?
(A) 5.4
(B) 3.6
(C) 4.9
(D) 5.0
(E) 4.4
Rationale: 5.4
In this simple addition series, each number increases by 1.0
Answer : A
Answer: (A) 5.4
Question: 4 dice are thrown simultaneously on the board. Find the probability show the same face?
(A) 2/121
(B) 2/227
(C) 1/216
(D) 1/219
(E) 1/213
Rationale: The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:
=6×6×6×6=64=6×6×6×6=64
n(S)=64n(S)=64
Let XX be the event that all dice show the same face.
X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}
n(X)=6n(X)=6
Hence required probability,
=n(X)n(S)=664=n(X)n(S)=664
=1/216
C
Answer: (C) 1/216
Question: Pablo plays 3 rounds of a game, in which his chances of winning each round are 1/2, 1/4, and 1/n, respectively. If n ≠ 0, what is the probability that Pablo wins the first two rounds, but loses the third?
(A) 1/16n
(B) (n-1)/8n
(C) 1/2n
(D) (n+2)/2n
(E) (3n-2)/2n
Rationale: 1/2 * 1/4 * (1-1/n)
= 1/8 * (n-1)/n
= (n-1)/8n
Answer - B
Answer: (B) (n-1)/8n
Question: If 5 men can paint a wall 100 metres long in 10 days of a 8 hours each. In how many days of 6 hours each will 8 men paint a wall 30 metres long?
(A) 1.5 DAY
(B) 2 days
(C) 2.5 days
(D) 3 days
(E) 3.5 days
Rationale: Total hours in 10 days = 10 *8 = 80 hours.
Total man-hours needed for paint 100m wall = 5 *8 = 40 man-hours.
Man-hour needed for 1 meter wall painting = 400/100 = 4 man-hour.
Now,
30*4 = 120 m-h to do 30 meters.
120 m-h/8 men = 15 hours.
15 hr/6 hr/day = 2.5 days.
answer : C
Answer: (C) 2.5 days
Question: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?
(A) 369
(B) 452
(C) 145
(D) 132
(E) 209
Rationale: We may have (1 boy and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4 boys).
Required number
of ways	= (6C1 x 4C3) + (6C2 x 4C2) + (6C3 x 4C1) + (6C4)
= (6C1 x 4C1) + (6C2 x 4C2) + (6C3 x 4C1) + (6C2)
= (24 + 90 + 80 + 15)
= 209.
Ans: E
Answer: (E) 209
Question: If a tire rotates at 400 revolutions per minute when the car is traveling 144km/h, what is the circumference of the tire?
(A) 2 meters
(B) 6 meters
(C) 5 meters
(D) 3 meters
(E) 7 meters
Rationale: 400 rev / minute = 400 * 60 rev / 60 minutes
= 24,000 rev / hour
24,000 * C = 144,000 m : C is the circumference
C = 6 meters
correct answer B
Answer: (B) 6 meters
Question: What is the area of a square field whose diagonal of length 20 m?
(A) 287
(B) 269
(C) 270
(D) 200
(E) 230
Rationale: d2/2 = (20 * 20)/2
= 200
Answer:D
Answer: (D) 200
Question: Can you please walk me through how to best approach this problem? Thanks
If #p# = ap^3+ bp – 1 where a and b are constants, and #-2# = 2, what is the value of #2#?
(A) 5
(B) 0
(C) -4
(D) -3
(E) -5
Rationale: #p# = ap^3 + bp - 1
#-2# = 2
putting p = -2 in above equation
-8a -(2b +1) = 2 or
#-2# = (8a+2b+1) = -2
therefore 8a+2b = -3 .....(1
now putting p =2
#2# = 8 a+2b - 1
using equation 1(8a+2b = -3)
#5# = -3-1 = -4
hence C
Answer: (C) -4
Question: Given a spinner with four sections of equal size labeled E, B, C, and D, what is the probability of NOT getting an E after spinning the spinner two times?
(A) 15/16
(B) 9/16
(C) 1/2
(D) 1/4
(E) 1/8
Rationale: The probability of NOT getting an E after spinning the spinner two times is 3/4*3/4=9/16 (so getting any of the remaining 3 letters out of 4).
Answer: B.
Answer: (B) 9/16
Question: A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is
(A) 400 m
(B) 450 m
(C) 560 m
(D) 600 m
(E) 680 m
Rationale: Length of the Ist train=2x m and the length of the other train be x m(1/2)
The relative speed of the train(48+42)=90kmph or 25m/s
Time taken to cross one another=12s
Hence, 12=2x+x/25
Solving, x=100m and 200m
Now to determine the length of the platform
45=100+length of the platform/speed of the Ist train
45=100+L/240/18( 48kmph=240/118m/s)
Solving, we get L=600M
ANSWER:D
Answer: (D) 600 m
Question: On Sunday Mario handled 75 sales. Deshawn handled 20% more sales than Mario, Callie handled 1/5 of the sales that Deshawn handled, and Jane handled 5 less sales than Callie. How much transactions did Jane handle?
(A) 90
(B) 13
(C) 65
(D) 70
(E) 42
Rationale: B
15
Mario handled 75 transactions
Deshawn handled 20% more transactions than Mario
Anthony = 75 + 75 × 20%
= 75+ 75 × 0.20
= 75 + 15
= 90
Callie handled 1/5 of the transactions than Deshawn handled
Callie = 1/5 × 90
= 18
Jane handled 5 less than Callie.
Jane = 18 - 5
= 13
Jane handled 13 transactions.
The correct answer is B.
Answer: (B) 13
Question: The H.C.F. of two numbers is 11 and their L.C.M. is 693. If one of the number is 77, find the other?
(A) 88
(B) 99
(C) 76
(D) 55
(E) 66
Rationale: Other number = 11*693/77 = 99
Answer is B
Answer: (B) 99
Question: A clock loses a minute every three hours for 4 days and gains 2% in the subsequent 6 days. If it was set right on Friday at 11 AM, what will be the time at the end of 10 days?
(A) 11:54:40 AM
(B) 01:20:13 PM
(C) 12:16:40 PM
(D) 11:54:24 AM
(E) 12:06:36 PM
Rationale: Clock loses: 1 minute in 3 hours = 8 minutes in 24 hours = 32 minutes in 4 days.
Clock gains: 1% in the subsequent 6 days = 2% in 6*24*60 minutes = 172.8 minute in 6 days;
Net gain in 10 days = 172.8 - 32 = 140.8 minutes.
11AM + 140.8 minutes = 01:20 and 13 seconds.
Answer: B.
Answer: (B) 01:20:13 PM
Question: John weighs twice as much as Susan. Susan's weight is 60% of Sam's weight. Mark weighs 50% of Lynn's weight. Lynn weighs 190% of John's weight. Which of these 5 people weighs the least?
(A) John
(B) Susan
(C) Sam
(D) Mark
(E) Lynn
Rationale: Let J – John’s weight
S – Susan’s weight
M – Mark’s weight
A – Sam’s weight
L – Lynn’s weight
J = 2S
S = 0.6A
M = 0.5L
L = 1.9J
Let us convert these weights to one variable
S = J/2
A = S/0.6 = J/1.2 = 5J/6
L = 1.9J
M = 0.5 * 1.9J = 0.95J
So Susan has the least weight.
Answer - B
Answer: (B) Susan
Question: If n is an odd integer less than 10, which of the following must also be an odd integer?
(A) 2n + n^2 + 2
(B) n^3 + 2n
(C) 3n + 2^n
(D) n^3 + 1
(E) 3n
Rationale: Answer: D
A: 2n = even
B: 3n = even
C: 3n + n^2 + 2 = even
D: n^2 + 1 = odd
E: 2n + n^2 = even
Answer: D
Answer: (D) n^3 + 1
Question: P and Q need 8 days to complete a work. Q and R need 12 days to complete the same work. But P, Q and R together can finish it in 6 days. How many days will be needed if P and R together do it?
(A) 3
(B) 8
(C) 12
(D) 4
(E) 15
Rationale: Let work done by P in 1 day = p
work done by Q in 1 day =q
Work done by R in 1 day = r
p + q = 1/8 ---(1)
q + r= 1/12	---(2)
p+ q+ r = 1/6	---(3)
(3) – (2) => p = 1/6 - 1/12 = 1/12
(3) – (1) => r = 1/6 – 1/8 = 1/24
p + r = 1/12 + 1/24 = 3/24 = 1/8
=> P and R will finish the work in 8 days
Option B
Answer: (B) 8
Question: A Student got 78 marks in avg of 4 subjects.the avg odf 5 subjects is 80.what is the amrk he got in 5th subject.
(A) 87
(B) 88
(C) 89
(D) 90
(E) 91
Rationale: avg mrk he got in 5th subject=80*5-78*4
avg mrk he got in 5th subject=400-312=88
ANSWER:B
Answer: (B) 88
Question: In her backyard, Florry grows only yellow roses and white roses. Some of the rose bushes have flowers of both colors, and some have flowers of one color only. The number of rose bushes that have only yellow roses is 50% greater than the number of rose bushes that have only white roses. If there are yellow roses on 80% of Florry's rose bushes, then what percent F of her bushes have only yellow roses?
(A) 20
(B) 30
(C) 50
(D) 70
(E) 80
Rationale: let, the number of bushes with only yellow flowers be x
so, number of bushes with only yellow flowers will be 1.5x
if total number of bushes of flowers= T
then total number of bushes with yellow flowers= 0.8T
we can say that total number of bushes with yellow flowers+ bushes with only white flowers= total number of bushes with flowers
so, F=0.8T+x=T
x=0.2T
so, 1.5x=0.3T
30% flowers are yellow flowers
OA B
Answer: (B) 30
Question: A small pool filled only with water will require an additional 300 gallons of water in order to be filled to 80% of its capacity. If pumping in these additional 300 gallons of water will increase the amount of water in the pool by 40%, what is the total capacity of the pool in gallons?
(A) 1000
(B) 1312.5
(C) 1400
(D) 1600
(E) 1625
Rationale: 300 gallons of water increases capacity by 40% that means
40% is 300 gallons, so 100% would be = 300*100/40= 750 gallons
Now 750 +300 gallons is 80% capacity of tank.
so 100% capacity would be= 1050 *100/80= 1312.5
B is the answer
Answer: (B) 1312.5
Question: A circular garden is surrounded by a fence of negligible width along the boundary. If the length of the fence is 1/3 of th area of the garden. What is the radius of the circular garden?
(A) 6
(B) 2
(C) 4
(D) 8
(E) 16
Rationale: as per the question-- width is negligible
now,
let L be the length of the fence =2pir
L=1/3(pir^2)
pir^2=6pir
r=6
Answer : A
Answer: (A) 6
Question: If 60! is written out as an integer, with how many consecutive 0’s will that integer end?
(A) 6
(B) 12
(C) 14
(D) 42
(E) 56
Rationale: Soln:-
60/5+60/52=12+2=14
Answer: C
Answer: (C) 14
Question: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?
(A) 160
(B) 175
(C) 180
(D) 195
(E) 200
Rationale: Explanation:
Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.40 + x x 3.20 = 432
3.20x = 432 - 384 = 48
x = 15.
Hence, total hours of work = (160 + 15) = 175.
ANSWER IS B
Answer: (B) 175
Question: In an arithmetic progression the difference between the any two consecutive terms is a constant. What is the arithmetic mean of all of the terms from the first to the 31st in an arithmetic progression if the sum of the 14th and 18th terms of the sequence is 122?
(A) 46
(B) 51
(C) 56
(D) 61
(E) 66
Rationale: Let x be the difference between any two consecutive terms.
The mean of a sequence like this is the middle term, thus the 16th term in the sequence.
Then the mean of the 15th and 17th term is also equal to the overall mean, because the 15th term is (16th term - x) and the 17th term is (16th term + x).
Similarly the mean of the 14th and 18th term is also equal to the mean.
etc...
Thus the mean is 122/2 = 61
The answer is D.
Answer: (D) 61
Question: Yogesh started a business investing Rs. 45000. After 3 months, Pranab joined him with a capital of Rs. 60000. After another 6 months, Atul joined them with a capital of Rs. 90000. At the end of the year, they made a profit of Rs. 20000. What would be Atuls share in it?
(A) Rs 7000
(B) Rs 6000
(C) Rs 5000
(D) Rs 4000
(E) None of these
Rationale: Explanation:
Just take care of the months of investment, rest all will be simple.
Yogesh:Pranab:Atul = 45000*12:60000*9:90000*3
= 2:2:1
Atul's share = Rs. 20000 * (1/5) = Rs. 4000
Option D
Answer: (D) Rs 4000
Question: In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 20 percent, but profits were 15 percent of revenues. The profits in 1999 were what percent of the profits in 1998?
(A) 80%
(B) 105%
(C) 120%
(D) 124.2%
(E) 138%
Rationale: Let's TEST:
1998
Revenues= $100
Profits = $10
Next we're told that, in 1999, revenue FELL by 20%, but profits were 15% of revenues. Using the numbers from 1998 (above), we end up with...
1999
Revenues = $80
Profits = $12
We're asked to compare the profits in 1999 to the profits in 1998 (as a percentage):
$12/$10 = 1.2 = 120%
ANSWER:C
Answer: (C) 120%
Question: If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 25 men in 3 days?
(A) 65mtr.
(B) 52mtr
(C) 70mtr.
(D) 78mtr.
(E) 17mtr.
Rationale: 20 men is 6 days can build 112 metres
25 men in 3 days can build = 112*(25/20)x(3/6)
= 70 meters
Answer: C.
Answer: (C) 70mtr.
Question: A cyclist rides a bicycle 9 km at an average speed of 11 km/hr and again travels 11 km at an average speed of 9 km/hr. What is the average speed for the entire trip?
(A) 9.3
(B) 9.6
(C) 9.8
(D) 10.1
(E) 10.3
Rationale: distance = 20 km
time = 9/11 + 11/9 = (81 + 121) / 99 = 202 / 99 hours
average speed = (20 * 99) / 202 = 9.8 km/h
The answer is C.
Answer: (C) 9.8
Question: If M and N are positive integers that have remainders of 2 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 89
(B) 53
(C) 34
(D) 29
(E) 11
Rationale: M=6p+2
N=6q+3
We need M+N=6p+3+6q+3=6(p+q)+5
Pick numbers for pq
Since it is an addition of pq and the answer to this expression should be an integer (because all the numbers being added are integers),
we just need to choose values so that we get integer multiples of 6 so
p+q=0 ; M+n = 5
p+q=1 ; M+N = 11
P+q=2 ; M+N = 17
and so on, so basically you get something like - 5,11,17,23,29,35,41,..... all the other options were turning up.
Then I directly tried p+q=5 because it was closer to 34 , i got 35,
So Answer C.
Answer: (C) 34
Question: If the sum of two positive integers is 18 and the difference of their squares is 36, what is the product of the two integers?
(A) 108
(B) 80
(C) 128
(D) 135
(E) 143
Rationale: Let the 2 positive numbers x and y
x+ y = 18 -- 1
x^2 - y^2 = 36
=> (x+y)(x-y)=36 -- 2
Using equation 1 in 2 , we get
=> x-y = 2 -- 3
Solving equation 1 and 3 , we get
x= 10
y= 8
Product = 10*8 = 80
Answer B
Answer: (B) 80
Question: A, B and C, each working alone can complete a job in 6, 8 and 12 days respectively. If all three of them work together to complete a job and earn $ 2340, what will be C's share of the earnings?
(A) $1100
(B) $520
(C) $1080
(D) $1170
(E) $630
Rationale: Explanatory Answer
A, B and C will share the amount of $2340 in the ratio of the amounts of work done by them.
As A takes 6 days to complete the job, if A works alone, A will be able to complete 1/6 th of the work in a day.
Similarly, B will complete 1/8th and C will complete 1/12th of the work.
So, the ratio of the work done by A : B : C when they work together will be equal to 1/6 : 1/8 : 1/12
Multiplying the numerator of all 3 fractions by 24, the LCM of 6, 8 and 12 will not change the relative values of the three values.
We get 24/6 : 24/8 : 24/12 = 4 : 3 : 2.
i.e., the ratio in which A : B : C will share $2340 will be 4 : 3 : 2.
Hence, C's share will be 2*2340/9 = 520.
correct choice is (B)
Answer: (B) $520
Question: A man can row three-quarters of a kilometre against the stream in 11 1/4 minutes. The speed (in km/hr) of the man in still water is:
(A) 4 1/4 km/hr
(B) 5 km/hr
(C) 6 km/hr
(D) 7 km/hr
(E) None
Rationale: Sol.
Rate upstream = [750 / 675] m/sec = 10/9 m/sec.
Rate downstream = [750 / 450] m/sec = 5/3 m/sec.
∴ Rate in still water = 1/2 [10/9 + 5/3] m/sec = 25/18 m/sec = [25/18 * 18/5] km/hr
= 5 km/hr
Answer B
Answer: (B) 5 km/hr
Question: we have 6 weights one of 2 kg one of 3 kg one of 5 kg one of 1 kg one of 0.5 kg one of 0.25 kg by using only two weight how many wight u can weight
(A) 11
(B) 12
(C) 13
(D) 14
(E) 15
Rationale: select 2 weight out of 6, 6C2=15
ANSWER:E
Answer: (E) 15
Question: Running at the same constant rate,6 identical machines can produce a total of 270 bottles per minute.At this rate,how many bottles could 14 such machines produce in 4 minutes ?
(A) 2520
(B) 1800
(C) 2700
(D) 10800
(E) None of these
Rationale: Solution
Let the required number of bottles be x.
More machines,More bottles (Direct Proportion)
More minutes,More bottles (Direct Proportion)
âˆ´ 6 Ã— 1 Ã— x = 14 Ã— 4 Ã— 270 â‡” x = 14x4x270/6= 2520 . Answer A
Answer: (A) 2520
Question: If a 2-digit integer is selected at random from the integers 60 through 99, inclusive, what is the probability that the first digit is equal to two less than the second digit?
(A)  4/40
(B)  4/90
(C)  60/100
(D)  1/99
(E)  4/60
Rationale: The tens digit may be 6, 7, 8, or 9
The units digit may be 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9
The tens digit has to be 2 less than the value of the units digit so we will add 2 to possible tens digits
6+2 = 8
7+2 = 9
8+2 = 10
9+2 = 11
Of these values, 8 and 9 are possible units digits which means that 6 and 7 are possible tens digits
Possible numbers are 68, 69, 78, and 79
We have 4 possible numbers
Total numbers between 60 and 99 = (99-60)+1 = 40
Probability = 4/40
Answer A
Answer: (A)  4/40
Question: In an examination, a student scores 6 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 60 questions and secures 280 marks, the no of questions he attempts correctly is :
(A) A)20
(B) B)38
(C) C)90
(D) D)88
(E) E)37
Rationale: Let the number of correct answers be X.
Number of incorrect answers = (60 – X).
6x – (60 – x) = 280
=> 7x = 340
=> x = 20
Answer:A
Answer: (A) A)20
Question: If 11 ml of water is mixed with 1 ml of a chemical, a magical perfume is manufactured. The manufacturer initially wanted to have 500 ml of one box of the magical perfume. How much extra ml is to be added with the proposed box size to comply with the formula?
(A) 3
(B) 4
(C) 5
(D) 7
(E) 8
Rationale: The magical perfume should have 11/12 of water and 1/12 of chemical. With 500 ml, there will be a need to add 4 ml more such that the final solution is divisible by 12; that is , 42x12=504. Answer B.
Answer: (B) 4