mathewhe/aqua_rat huggingface dataset:
Question: A batsman makes a score of 87 runs in the 17th inning and thus increases his avg by 3. Find his average after 17th inning.
(A) 15
(B) 26
(C) 41
(D) 32
(E) 39
Rationale: Sol. Let the average after 17th inning = x.
Then, average after 16th inning = (x - 3).
:. 16 (x - 3) + 87 = 17x or x = (87 - 48) = 39.
ANSWER E
Answer: (E) 39
Question: Rebecca's yearly income is $15,000 and Jimmy's annual income is $18,000. By how much must Rebecca's yearly income increase so that it constitutes 55% of Rebecca and Jimmy's combined income?
(A) 7000
(B) 8000
(C) 9000
(D) 10000
(E) 11000
Rationale: total rebecca = x+15000 ; total = x+15000+18000;
x+15000/x+33000 = 55/100 therefore x =7000
A
Answer: (A) 7000
Question: You hold some gold in a vault as an investment. Over the past year the price of gold increases by 40%. In order to keep your gold in the vault, you must pay 5% of the total value of the gold per year. What percentage has the value of your holdings changed by over the past year.
(A) 35%
(B) 33%
(C) 36%
(D) 38%
(E) 40%
Rationale: (100%+40%)*(100%-5%) = 140*0.95 = 133% an increase of 33%
Your gold holdings have increased in value by 33%.
The Answer is B
Answer: (B) 33%
Question: Determine the ratio of the number of people having characteristic X to the number of people having characteristic Y in a population of 100 subjects from the following table
People having X and Y are 20
People having X but not Y are 10
People having Y but not X are 30
People having neither X nor Y are 40.
(A) 3 : 5
(B) 3 : 4
(C) 4 : 3
(D) 5 : 3
(E) 1 : 2
Rationale: Number of people having characteristic X = 10 + 20 = 30
Number of people having characteristic Y = 20 + 30 = 50
Therefore Required ratio = 30 : 50 = 3 : 5
ANSWER:A
Answer: (A) 3 : 5
Question: A patient was given four pills which he is required to take one after every twenty-five minutes.
How long can the pills run for him?
(A) 1 hour 15 minutes
(B) 1 hour 35 minutes
(C) 1 hour 30 minutes
(D) 1 hour 40 minutes
(E) 1 hour 37 minutes
Rationale: Explanation:
He took the first pill at the zero minute.
He took the second pill after 25 minutes = 0+25=25
He took the third pill after 25 minutes = 25+25=50
He took the fourth pill after 25 minutes = 50+25=75
Then it will last for 75 minutes or an hour and 15 minutes
Answer A
Answer: (A) 1 hour 15 minutes
Question: If x:y=7:5, y:z= 8:9, find x:y:z =?
(A) 56:40:43
(B) 56:40:42
(C) 56:40:40
(D) 56:40:45
(E) 56:40:41
Rationale: x:y=7:5
y:z= 8:9
x:y:z =56:40:45
Answer : D
Answer: (D) 56:40:45
Question: A sum of money at simple interest amounts to $ 645 in 3 years and to $690 in 4 years. The sum is:
(A) $153
(B) $510
(C) $598
(D) $549
(E) $675
Rationale: B
$510
S.I. for 1 year = $(690 - 645) = $45.
S.I. for 3 years = $(45 x 3) = $135.
Principal = $(645 - 135) = $510.
Answer: (B) $510
Question: Tough and Tricky questions: Combinations.
Eight contestants representing four different countries advance to the finals of a fencing championship. Assuming all competitors have an equal chance of winning, how many possibilities are there with respect to how a first-place and second-place medal can be awarded?
(A) 6
(B) 7
(C) 12
(D) 16
(E) 24
Rationale: Number of ways First-place medal can be awarded to four contestants = 8
Number of ways Second-place medal can be awarded to contestants after awarding First-place medal =3
Therefore number of possibilities = 8 *3 =24
Answer:E
Answer: (E) 24
Question: Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 4 litres from vessel P is mixed with 6 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is?
(A) 31:1
(B) 31:4
(C) 31:8
(D) 31:9
(E) 31:2
Rationale: Quantity of alcohol in vessel P = 62.5/100 * 4 = 5/2 litres
Quantity of alcohol in vessel Q = 87.5/100 * 6 = 21/4 litres
Quantity of alcohol in the mixture formed = 5/2 + 21/4 = 31/4 = 7.75 litres
As 10 litres of mixture is formed, ratio of alcohol and water in the mixture formed
= 7.75 : 2.25 = 31:9.
Answer: D
Answer: (D) 31:9
Question: A can finish a work in 24days, B in 9days and C in 2days, B and C start the work but are forced to leave after 3 days. The remaining work was done by A in?
(A) 10days
(B) 12days
(C) 6days
(D) 7days
(E) 8days
Rationale: B+C 1day work = 1/9 + 1/12 = 7/36
work done by B and C in 3days = 7/36 * 3 = 7/12
Remaining work = 1 - 7/12 = 5/12
1/24 work is done by A in 1day
5/12 work is done by A in 24*5/12 = 10days
Answer is A
Answer: (A) 10days
Question: The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 50 kg. What might be the weight of the new person?
(A) 70kg
(B) 80kg
(C) 85kg
(D) 90kg
(E) 95kg
Rationale: Total weight increased = (8 x 2.5) kg = 20 kg.
Weight of new person = (50 + 20) kg = 70 kg.
A)
Answer: (A) 70kg
Question: When the positive integer x is divided by 9,the remainder is 5.What is the remainder when 5x is divided by 9?
(A) 0
(B) 1
(C) 3
(D) 4
(E) 7
Rationale: i tried plugging in numbers
x = 9q+5
x = 14
5x = 70
5x/9= 63 + 7
remainder is 7.
Answer is E.
Answer: (E) 7
Question: The area of a square is equal to five times the area of a rectangle of dimensions 125 cm * 64 cm. What is the perimeter of the square?
(A) 80 cm
(B) 800 cm
(C) 287 cm
(D) 718 cm
(E) 86 cm
Rationale: Area of the square = s * s = 5(125 * 64)
=> s = 25 * 8 = 200 cm
Perimeter of the square = 4 * 200 = 800 cm.
Answer: B
Answer: (B) 800 cm
Question: Evaluate: (1 - 1/10)(1 - 1/11)(1 - 1/12)...(1 - 1/99)(1 - 1/100)
(A) 4/100
(B) 8/100
(C) 7/100
(D) 9/100
(E) 3/100
Rationale: (1 - 1/10)(1 - 1/11)(1 - 1/12)...(1 - 1/99)(1 - 1/100)
= (9/10)(10/11)(11/12)...(98/99)(99/100)
= 9/100 : simplify
correct answer D
Answer: (D) 9/100
Question: If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is
(A) 48 km
(B) 50 km
(C) 40 km
(D) 22 km
(E) 70 km
Rationale: B
50 km.
Let the actual distance travelled be x km.
Then x/10=(x+20)/14
--> 14x = 10x + 200
--> 4x = 200
--> x = 50 km.
Answer: (B) 50 km
Question: At exactly what time past 9:00 will the minute and hour hands of an accurate working clock be precisely perpendicular to each other for the first time?
(A) 20 13/21 minutes past 7:00
(B) 20 13/17 minutes past 9:00
(C) 21 3/23 minutes past 7:00
(D) 21 9/11 minutes past 7:00
(E) 22 4/9 minutes past 7:00
Rationale: A1 = hour angle
A2 = minute angle
A1-A2 = 90
Assume the minutes = M
A1 = (9*60+M)/12*60 )*360
A2 = M*360/60
Solving all three equation , results in the answer B
Answer: (B) 20 13/17 minutes past 9:00
Question: One millisecond is 0.001 of a second. The costs for a single run of a computer program are $1.07 for operating-system overhead, $0.027 per millisecond of computer time, and $4.35 for the mounting of a data tape. What is the total of these three costs for 1 run of a program that requires 1.5 seconds of computer time ?
(A)  $57.15
(B)  $45.92
(C)  $37.96
(D)  $31.57
(E)  $25.92
Rationale: Operating system overhead for 1 run = 1.07 $
Mounting of data tape = 4.35$
Cost per 1 millisecond of computer time = .027 $
Total cost of 1 run of a program that requires 1.5 seconds of computer time
= 1.07 + (.027*1500) + 4.35
=1.07 + 40.5 + 4.35
= 45.92$
Answer B
Answer: (B)  $45.92
Question: A man spends Rs. 1900 per month on an average for the first three months, Rs 1550 for next four months and Rs. 1800 per month for the last five months and saves Rs . 5200 a year. What is his average monthly income?
(A) 2075
(B) 2175
(C) 2275
(D) 2375
(E) 2475
Rationale: Explanation:
Total expenditure for the first 3 months = 3 Ã— 1900 = 5700
Total expenditure for 4 months = 4 Ã— 1550 = 6200
Total expenditure for 5 months = 5 Ã— 1800 = 9000
Total expenditure and saving (which is income for one year)
= 5700 + 6200 + 9000 + 5200 = Rs. 25200
So, Average monthly income = 26100/12 = Rs. 2175
Answer B
Answer: (B) 2175
Question: If a town of 45,000 people is growing at a rate of approx. 1% per year, the population of the town in 5 years will be closest to?
(A) a.46000
(B) b.47000
(C) c.48000
(D) d.49000
(E) e.50000
Rationale: 1% is quite small and hence the answer is A)
Answer: (A) a.46000
Question: Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
(A) 210
(B) 1050
(C) 25200
(D) 21400
(E) None of these
Rationale: Number of ways of selecting 3 consonants out of 7 and 2 vowels out of 4 = 7C3 x 4C2 = (7x6x5)/(3x2x1) x (4x3)/(2x1) = 210.
Number of groups, each having 3 consonants and 2 vowels = 210.
Each group contains 5 letters.
Number of ways of arranging 5 letters among themselves
= 5! = 5x4x3x2x1 = 120
Therefore the required number of words = 210 x 120 = 25200.
Answer C.
Answer: (C) 25200
Question: P can do a certain work in 18 days. Q is 60% more efficient than P. How many days does Q alone take to do the same job?
(A) 14.25
(B) 13.75
(C) 12.5
(D) 11.25
(E) 10.5
Rationale: Each day, P can do 1/18 of the work.
Each day, Q can do 1.6/18 of the work = 16/180 of the work
The time taken by B alone to complete the total work is 180/16 = 11.25 days.
The answer is D.
Answer: (D) 11.25
Question: Determine the value of 3*27/31+81/93
(A) 0
(B) 156/31
(C) 123/31
(D) 151/31
(E) none
Rationale: Solution:
Both fractions should be reduced before performing arithmetic operations. We get 3*27/31+3.27/3.31=3*27/31+27/31=4*27/31=151/31
Answer D
Answer: (D) 151/31
Question: If it is assumed that 70 percent of those who receive a questionnaire by mail will respond and 300 responses are needed, what is the minimum number of questionnaires that should be mailed?
(A) 400
(B) 428.5
(C) 480
(D) 500
(E) 600
Rationale: Minimum no of mail to be sent for getting 300 responses at 70%
= 300/0.7 = 428.5
Option B
Answer: (B) 428.5
Question: If a boat goes 7 km upstream in 42 minutes and the speed of the stream is 6 kmph, then the speed of the boat in still water is :
(A) 2.5 km/hr
(B) 4 km/hr
(C) 5 km/hr
(D) 10.5 km/hr
(E) None of these
Rationale: Solution
Speed of stream = 1/2 (16-8) km/hr= 4kmph . Answer B
Answer: (B) 4 km/hr
Question: The ratio of a to b is 4 to 5, where a and b are positive. If x equals a increased by 25 percent of a, and m equals b decreased by 80 percent of b, what is the value of m/x?
(A) 1/5
(B) 3/4
(C) 4/5
(D) 5/4
(E) 3/2
Rationale: a/b = 4/5
m/x = (1/5)*5 / (5/4)*4 = 1/5
The answer is A.
Answer: (A) 1/5
Question: Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win?
(A) 5/6
(B) 2/3
(C) 1/2
(D) 5/12
(E) 1/3
Rationale: There are 3*3=9 combinations (cases) possible. In 3 cases there will be a tie (rock-rock, scissors/scissors, paper/paper). Now, out of 6 cases left Jim and Renee have equal chances of winning, so in 3 cases Jim will win and in other 3 Renee will win. So the probability Jim winning the game is (favorable outcomes) / (total # of outcomes) = 3/9 = 1/3.
Or: no matter what sign Renee will select Jim can select 1 sign to win, 1 sign to get tie and 1 sign to loose, so the probability Jim winning the game is 1/3.
Answer: E.
Answer: (E) 1/3
Question: Cricket match is conducted in US. The run rate of a cricket game was only 3.2 in first 10 over. What should be the run rate in the remaining 40 overs to reach the target of 262 runs?
(A) 6
(B) 6.25
(C) 5.75
(D) 7.5
(E) 8
Rationale: Required run rate = 262 - (3.2 x 10) =	230 = 5.75
40	40
C
Answer: (C) 5.75
Question: A first grade teacher uses eight playing cards, each numbered from 1 to 8 to teach her students to order numbers correctly. She has students choose four flash cards randomly, then arrange the cards in ascending order. One day, she removes the cards '2' and '4' from the deck. On that day, how many different correct arrangements of four randomly selected cards are possible?
(A) 40
(B) 30
(C) 15
(D) 10
(E) 20
Rationale: problem of combination 6C4 = 6!/4!*(6-4)! = 6*5*4!/4!*2! =15
C
Answer: (C) 15
Question: Out of first 30 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is -.
(A) 1/2
(B) 16/19
(C) 4/5
(D) 24/30
(E) 3/5
Rationale: n(S) = 30
n(Even no) = 15 = n(E)
n(Prime no) = 10 = n(P)
P(EᴜP) = 15/30 + 10/30 - 1/30 = 24/30
ANSWER:D
Answer: (D) 24/30
Question: A computer wholesaler sells six different computers and each is priced differently. If the wholesaler chooses three computers for display at a trade show, what is the probability (all things being equal) that the two most expensive computers will be among the three chosen for display?
(A) 15/56
(B) 3/28
(C) 1/28
(D) 1/5
(E) 1/168
Rationale: Since, two of the choices are prefixed, we are free to choose 1 from the rest of the 4 avilable. so 4C1 is the numerator.
Total no of ways we can choose 3 from 6 is 6c3, which is the denominator.
So, the probability: 4c1/6c3= 1/5 ans is D.
Answer: (D) 1/5
Question: Ages of two persons differ by 22 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age
(A) 12,28
(B) 14,30
(C) 17,39
(D) 18,34
(E) 19,34
Rationale: Explanation:
Let the age of younger person is x,
Then elder person age is (x+22)
=> 3(x-6) = (x+22-6) [6 years before]
=> 3x-18 = x+16
=> x =17.
So other person age is x + 22 = 39
Answer: Option C
Answer: (C) 17,39
Question: A car traveled 65% of the way from Town A to Town B at an average speed of 65 mph.
The car traveled at an average speed of v mph for the remaining part of the trip.
The average speed for the entire trip was 50 mph. What is v in mph?
(A) 65
(B) 50
(C) 45
(D) 40
(E) 35
Rationale: Assume total distance = 100miles
Time taken for 65 miles = 65/65 = 1 hour
Time taken for the rest of the 35 miles = 35/v hours.
Average speed = 50
Therefore the total time needed = 2 hours.
2 = 1 + 35/v
Hence v = 35 mph
Correct Option: E
Answer: (E) 35
Question: The prices of tea and coffee per kg were the same in june. In August the price of coffee shot up by 20% and that of tea dropped by 20%. if in August , a mixture containing equal quantities of tea and coffee costs 50/kg. how much did a kg of coffee cost in june ?
(A) 45
(B) 50
(C) 40
(D) 35
(E) 30
Rationale: Let the price of tea and coffee be x per kg in June.
Price of tea in August = 1.2x
Price of coffee in August = 0.8x .
In July the price of 1/2 kg (500gm) of tea and 1/2 kg (500gm) of coffee (equal quantities) = 50
1.2x(1/2) + 0.8x(1/2) = 50
=> x =50
B
Answer: (B) 50
Question: A number x is multiplied with itself and then added to the product of 4 and x. If the result of these two operations is 12, what is the value of x?
(A) -4
(B) -2
(C) 2 and 6
(D) 4
(E) Cannot be determined.
Rationale: A number x is multiplied with itself --> X^2
added to the product of 4 and x --> X^2+4X
If the result of these two operations is -4 --> X^2+4X=4
i.e X^2+4X-12=0 is the Quadratic equation which needs to be solved.
(X-2)(X+6) = 0
Hence X=2, X=-6
IMO C
Answer: (C) 2 and 6
Question: The average temperature of the town in the first four days of a month was 57 degrees. The average for the second, third, fourth and fifth days was 60 degrees. If the temperatures of the first and fifth days were in the ratio 7 : 8, then what is the temperature on the fifth day ?
(A) 62 degrees
(B) 64 degrees
(C) 65 degrees
(D) 66 degrees
(E) 96 degrees
Rationale: Explanation:
Sum of temperatures on 1st, 2nd, 3rd and 4th days = (57 * 4) = 228 degrees ... (1)
Sum of temperatures on 2nd, 3rd, 4th and 5th days - (60 * 4) = 240 degrees ....(2)
Subtracting (1) From (2), we get :
Temp, on 5th day - Temp on 1st day = 12 degrees.
Let the temperatures on 1st and 5th days be 7x and 8x degrees respectively.
Then, 8x - 7x = 12 or x = 12. Answer: E
Temperature on the 5th day = 8x = 96 degrees.
Answer: (E) 96 degrees
Question: Tom purchased 8kg of apples at the rate of 70 per kg and 9 kg of mangoes at the rate of 55 per kg. How much amount did he pay to the shopkeeper?
(A) 1040
(B) 1045
(C) 1055
(D) 1060
(E) 1075
Rationale: Cost of 8 kg apples= 70 × 8 = 560.
Cost of 9 kg of mangoes = 55 × 9 = 490.
Total cost he has to pay = 560 + 490 = 1055.
c)
Answer: (C) 1055
Question: P and Q can do a work in 30 days. Q and R can do the same work in 24 days and R and P in 20 days. They started the work together, but Q and R left after 10 days. How many days more will P take to finish the work?
(A) 10
(B) 15
(C) 18
(D) 22
(E) 25
Rationale: Explanation :
Let work done by P in 1 day = p,
Work done by Q in 1 day = q,
Work done by R in 1 day = r
p + q = 1/30
q + r = 1/24
r + p = 1/20
Adding all the above, 2p + 2q + 2r = 1/30 + 1/24+ 1/20 = 15/120 = 1/8
=> p + q + r = 1/16
=> Work done by P,Q and R in 1 day = 1/16
Work done by P, Q and R in 10 days = 10 × (1/16) = 10/16 = 5/8
Remaining work = 1 = 5/8 = 3/8
Work done by P in 1 day = Work done by P,Q and R in 1 day - Work done by Q and R in 1 day
= 1/16 – 1/24 = 1/48
Number of days P needs to work to complete the remaining work = (3/8) / (1/48) = 18
Answer : Option C
Answer: (C) 18
Question: A grocer has a sales of Euro 6435, Euro 6927, Euro 6855, Euro 7230 and Euro 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Euro 6500?
(A) Euro 4991
(B) Euro 5991
(C) Euro 6001
(D) Euro 6991
(E) None
Rationale: Explanation: Total sale for 5 months = Euro (6435 + 6927 + 6855 + 7230 + 6562) = Euro 34009.
Required sale = Euro [ (6500 x 6) - 34009 ]
= Euro (39000 - 34009)
= Euro 4991.
Answer: Option A
Answer: (A) Euro 4991
Question: The ratio between the sale price and the cost price of an article is 7:4. What is the ratio between the profit and the cost price of that article?
(A) 3:4
(B) 1:2
(C) 2:5
(D) 3:5
(E) 25
Rationale: C.P. = Rs. 4x and S.P. = Rs. 7x.
Then, Gain = Rs. 3x
Required ratio = 3x : 4x = 3:4
A
Answer: (A) 3:4
Question: A starts business with a capital of Rs.1200 B and C join with some investments after 3 and 6 months respectively. If the end of a year, the profit is divided in the ratio 2:3:5 respectively. What is B's investment in the business?
(A) 2400
(B) 2882
(C) 2277
(D) 2656
(E) 2778
Rationale: 1200 * 12: x * 9 = 2:3
x = 2400
Answer: A
Answer: (A) 2400
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 20%?
(A) 20%
(B) 29%
(C) 90%
(D) 90%
(E) 112%
Rationale: SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20%
Answer:A
Answer: (A) 20%
Question: A farm has chickens, cows and sheep. There are 10 times the number of chickens and cows than sheep. If there are more cows than chickens or sheep, and together, cows and chickens have a total of 100 feet and heads, how many sheep live at the farm?
(A) 5
(B) 8
(C) 2
(D) 14
(E) 17
Rationale: Chicken - ch
Cows - C
Sheep -S
ch+C=10S
C> ch and c>s
Each cow has 4 legs and 1 head
Each chicken has 2 legs and 1 head
So 5c+3ch=100 (sum of legs and head)
There are 2 possible solutions to this equation
c=11 and ch=9 or
c=14 and ch=10
Since from first equation where ch+c=10s
The sum of ch and c should be divisbile by 10. 24 is not so the only possible solution is c=11 and ch=9. So s=2
Answer : C
Answer: (C) 2
Question: The average age of 40 passengers in a ferry is 35. What is the average age of the new group formed when combining the passengers with the 5 crew members of ferry whose average age is 25?
(A) 36.45
(B) 38.89
(C) 39.67
(D) 40.12
(E) 41.88
Rationale: Sum of ages of passengers= 40x35= 1400
Sum of ages of crew= 25x5= 125
Sum of ages of new group formed= 1525
Average=1525/45=38.89
Answer: B
Answer: (B) 38.89
Question: A certain animal in the zoo has consumed 39 pounds of food in six days. If it continues to eat at the same rate, in how many more days will its total consumption be 117 pounds?
(A) 8
(B) 7
(C) 12
(D) 9
(E) none of the above
Rationale: Ans is C:
39 pounds --> 6 days
117 pounds --> x days
x = 117*6/39 = 18
the animal has already consumed food in 6 days so the the number of days
for it's total consumption be 117 pounds is 18-6 = 12
Answer: (C) 12
Question: Tane and Thomas are among the 8 people from which a committee of 4 people is to be selected. How many different possible committees of 4 people can be selected from these 8 people if at least one of either Tane or Thomas is to be selected?
(A) 28
(B) 46
(C) 55
(D) 63
(E) 70
Rationale: Ans:C
Solution:
T+T+6 = total 8 ,
we need to select at least one of the T and T or both= total 4 out of 8 - 4 out of 6
8C4 - 6C4
=55
Answer: (C) 55
Question: The average temperature for Monday, Tuesday and Wednsday is 36.3 degrees C. The average temperature for Tuesday, Wednesday and Thursday is 36.7 degrees C. if Monday’s temperature recorded as 39 degrees c, find the Thursday’s temperature ?
(A) 60.2 degrees C
(B) 50.2 degrees C
(C) 40.2 degrees C
(D) 70.2 degrees C
(E) None of these
Rationale: Explanation:
MOn + Tue + wed Temperature = 3X36.3 = 108.9
Tue + wed Temperature = 108.9 – 39 = 69.9
Tue + wed + Thu temperature = 3X36.7 = 110.1
So, Thursday’s temperature = 110.1 – 69.9 = 40.2 degrees C
Answer: C
Answer: (C) 40.2 degrees C
Question: Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:
(A) broke even,
(B) lost 4 cents
(C) gained 4 cents
(D) lost 10 cents
(E) gained 10 cents
Rationale: Solution:
20 % profit on $ 1.20
= $ 20/100 × 1.20
= $ 0.20 × 1.20
= $ 0.24
Similarly, 20 % loss on $ 1.20
= $ 20/100 × 1.20
= $ 0.20 × 1.20
= $ 0.24
Therefore, in one pipe his profit is $ 0.24 and in the other pipe his loss is $ 0.24.
Since both profit and loss amount is same so, it’s broke even.
Answer: A
Answer: (A) broke even,
Question: Find the average of first 50 natural numbers.
(A) 20.5
(B) 18
(C) 25.5
(D) 19
(E) 17
Rationale: Exp. Sum of first n natural numbers = n( n+1)/2
So, sum of first 50 natural numbers = 50*51/2 = 1275
Required average =1275/50 =25.5
Answer:C
Answer: (C) 25.5
Question: At what time between 3 o'clock and 4 o'clock, both the needles of a clock will coincide each other?
(A) 16 2/11 minutes past 3
(B) 16 4/11 minutes past 3
(C) 16 7/11 minutes past 3
(D) 16 8/11 minutes past 3
(E) 16 4/11 minutes past 3
Rationale: Here H = 3. Hands will be together at
=60H/11 minutes past 3
=60Ã—3/11 minutes past 3
=180/11 minutes past 3
=16 4/11 minutes past 3
Answer: E
Answer: (E) 16 4/11 minutes past 3
Question: When f is divided by 5, the remainder is 3. When y is divided by 5, the remainder is 4. What is the remainder when f + y is divided by 5?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
Rationale: In my view the answer should be C
f/5 has Remainder=3 -> f = 5 x Q + 3
Y/5 has a Remainder=4 -> Y = 5 x Q + 3
Combining both
((5 x Q1 + 3) + (5 x Q2 + 3))/5 =
5(Q1+Q2)/5 + 7/5 =
Q1+Q2 + 7/5
7/5 = 1+ 2/5 => Remainder 2
Answer C
Answer: (C) 2
Question: A reduction of 50% in the price of bananas would enable a man to obtain 64 more for Rs.40, what is reduced price per dozen?
(A) 2.75
(B) 8.75
(C) 7.75
(D) 3.75
(E) 1.75
Rationale: Explanation:
40*(50/100) = 20 --- 64
? --- 12 => Rs.3.75
Answer: D
Answer: (D) 3.75
Question: In his pocket, a boy has 5 red marbles, 6 blue marbles, and 7 green marbles. How many will he have to take out of his pocket to ensure that he has taken out at least one of each color?
(A) 11
(B) 12
(C) 13
(D) 14
(E) 15
Rationale: The worst case scenario would be that he has taken 6 blue and 7 green, a total of 13 marbles, and still doesn't have 3 distinct colors. But the next draw, marble number 14, will surely be red as only the red marbles are left in his pocket.
The answer is D.
Answer: (D) 14
Question: Two hundred multiples of seven are chosen at random, and 200 multiples of eight are chosen at random. Approximately what percentage of the 400 selected numbers are odd?
(A) 20%
(B) 25%
(C) 40%
(D) 50%
(E) 80%
Rationale: About half the multiples of seven will be odd while all the multiples of eight are even.
The percentage of odd numbers is about (1/2)(200) / 400 = 25%
The answer is B.
Answer: (B) 25%
Question: Two pipes A and B can separately fill a tank in 12 and 15 minutes respectively. A third pipe C can drain off 56 liters of water per minute. If all the pipes are opened, the tank can be filled in 15 minutes. What is the capacity of the tank?
(A) 549
(B) 540
(C) 542
(D) 672
(E) 279
Rationale: 1/12 + 1/15 - 1/x = 1/15
x = 12
12 * 56 = 672
Answer: D
Answer: (D) 672