mathewhe/aqua_rat huggingface dataset:
Question: Peter invests a sum of money and gets back an amount of $ 810 in 3 years . David invests an equal amount of money and gets an amount of $854 in 4 years. If both amounts were invested at the same rate (simple interest ) What was the sum of money invested ?
(A) 670
(B) 683
(C) 698
(D) 744
(E) 700
Rationale: Since both Peter and David invested the same amount of money at the same rate, they would earn same interest per year.
David invested for one year more than Peter and hence he got interest amount for one more year.
Interest earned per year = Amount received by David - Amount received by Peter = 854 - 810 = 44
Interest earned for 3 years = 44*3 = 132
Amount invested = 815 - 132= 683
Answer: B
Answer: (B) 683
Question: Which of the following has a decimal equivalent that is a terminating decimal?
(A) 2/3^20
(B) 3^5/20^3
(C) 2^3/3^2
(D) 8^2/7^5
(E) 3^6/6^3
Rationale: For a fraction to have terminating decimal, it must either have only 2 and/or 5 in the denominator. All other values in the denominator leads to non terminating decimal values
Hence,
1. There is a 3 in the denominator, hence it is a non terminating decimal
2. Has both 2 and 5 in the denominator, hence terminating
3. There is a 3 in the denominator, hence it is a non terminating decimal
4. There is a 7 in the denominator, hence it is a non terminating decimal
5. Has both 2 & 3 in the denominator, hence non terminating
Option B
Answer: (B) 3^5/20^3
Question: What is theleast number should be added to 410, so the sum of the number is completely divisible by 20?
(A) 1
(B) 2
(C) 10
(D) 6
(E) 8
Rationale: (410 / 20) gives remainder 10
10 + 10 = 20, So we need to add 10
Answer : C
Answer: (C) 10
Question: A dishonest DEALER professes to sell goods at the cost price but uses a weight of 800 grams per kg, what is his percent?
(A) 29%
(B) 25%
(C) 235%
(D) 85%
(E) 22%
Rationale: 800 --- 200
100 --- ? => 25%
Answer: B
Answer: (B) 25%
Question: Let C be defined as the sum of all prime numbers between 0 and 38. What is C/3
(A) 155
(B) 76.6
(C) 61
(D) 47
(E) 43
Rationale: Prime numbers between 0 and 30 - 2 , 3 , 5 , 7, 11 , 13 , 17 , 19 , 23 , 29, 31, 33, 37
Sum,C = 230
C/3 = 76.6
Answer B
Answer: (B) 76.6
Question: If 3g + 1 < 2g < 9 - g, which of the following must be true?
I. -1 < g < 3
II. g < -1
III. g < 3
(A)  II only
(B)  III only
(C)  I and II only
(D)  II and III only
(E)  I, II and III
Rationale: Just try plugging g in a number like 0 or 1, and you'll quickly find that the inequality doesn't hold.
So you can immediately cross out any answers with I or III, leaving just (A) II only.
Answer: (A)  II only
Question: For any positive integer n, n>1, thelengthof n is the number of positive primes (not necessary distinct) whose product is n. For ex, the length of 60 is 3, since 50=2x5x5. What is the greatest possible length of a positive integer less than 1000.
(A) 10
(B) 9
(C) 8
(D) 7
(E) 6
Rationale: you are missing something in your post:
For any positive integer n , n > 1, thelengthof n is the number of positive primes (not distinct) whose product is n. For example, the length of 50 is 3 since 50 = (2)(5)(5)
the lenght of 1000 = (2)(5)(2)(5)(2)(5) = 6
but we need n < 1000
using 2 as the base = (2)(2)(2)(2)(2)(2)(2)(2)(2) = 8 the length of 512.
the answer is (C)
Answer: (C) 8
Question: If a student handwrites her homework it takes her 5 hours to complete it, instead if she types it takes her 8 hours to compete. Since her teacher does not mind, she starts handwriting and after 1 hour, she switches to the computer and continues by typing for 2 hours. Then asking her brother to help, he types another 11 hours and homework is completed. How long would it take to complete the homework, if she had asked her brother for help in the first place.
(A) 5 hours
(B) 10 hours
(C) 15 hours
(D) 20 hours
(E) 25 hours
Rationale: 1/5+2/8 + 3/x = 1x =20 hours. ANSWER =D
Answer: (D) 20 hours
Question: The average age of three boys is 15 years and their ages are in proportion 3:5:7. What is the age in years of the youngest boy?
(A) 7
(B) 9
(C) 11
(D) 13
(E) 14
Rationale: Explanation:
3x + 5x + 7x = 45
x =3
3x = 9
B)
Answer: (B) 9
Question: Two trains 200 m and 180 m long are running on parallel rails at the rate of 40 kmph and 45 kmph respectively. In how much time will they cross each other, if they are running in the same direction?
(A) 72 sec
(B) 132 sec
(C) 192 sec
(D) 273.6 sec
(E) None
Rationale: Solution
Relative Speed	= (45 - 40 ) Kmph
= 5 kmph
=(5 x 5 / 18)m/sec
= (25 / 18 ) m/sec
Time taken	= (380 x 18 / 25) sec
= 273.6 sec.
Answer D
Answer: (D) 273.6 sec
Question: What will be the ratio of simple interest earned by certain amount at the same rate of interest for 3 years and that for 15 years?
(A) 3 : 2
(B) 1 : 5
(C) 2 : 3
(D) 3 : 1
(E) 2 : 1
Rationale: Explanation :
Simple Interest = PRT/100
Here Principal(P) and Rate of Interest (R) are constants
Hence, Simple Interest ∝ T
Required Ratio = Simple Interest for 3 years/Simple Interest for 15 years
=T1/T2
=3/15
=1/5
=1:5
Answer : Option B
Answer: (B) 1 : 5
Question: A 90-liter solution of cool-drink is made from 5% jasmine water. If 8 liters of jasmine and 2 liters of water were added to the solution, what percent of the solution is jasmine?
(A) 6.5%
(B) 8.5%
(C) 10.5%
(D) 12.5%
(E) 14.5%
Rationale: The percent of jasmine in the resulting solution is: (amount of jasmine) / (total volume)
(0.05(90) + 8) / 100 = 12.5/100 = 12.5%
The answer is D.
Answer: (D) 12.5%
Question: What is the units digit of 17^83 × 13^82 × 11^67?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: To find : the units digit of 17^83 × 13^82 × 11^87
Let's reduce the clutter and simplify the product
(7^83) (3^82) (1^87)
7 has a cyclicity of 4 : the last digit of any positive power of 7 repeats itself after every 4th power
so 7^5 has the same last digit as 7^1, 7^9, 7^13
Thus , 7^83 has the same last digit as 7^3, 7^7, 7^11 i.e.3
3 has a cyclicity of 4 : exactly the same routine as above
Thus , 3^82 has the same last digit as 3^2, 3^6, 3^10 i.e.9
Any power of 1 will result in1as the last digit
So, product of our last digits = 3 x 9 x 1 = 27....last digit is 4
Correct Option : A
Answer: (A) 4
Question: ABCD is a square where AB =âˆš6000. Let X be a point on AB and Y be a point on CD such that AX = CY . Compute the area of trapezoid AXYD.
(A) 3008
(B) 2002
(C) 1008
(D) 2016
(E) 3000
Rationale: Note that trapezoids AXY D and BXY C are congruent, so the area of AXY D is
always
6000/2= 3000 .
correct answer E
Answer: (E) 3000
Question: The sale price sarees listed for Rs.400 after successive discount is 12% and 5% is?
(A) 338
(B) 277
(C) 342
(D) 334.4
(E) 212
Rationale: 400*(88/100)*(95/100) = 334.4
Answer: D
Answer: (D) 334.4
Question: Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
(A) 5:4
(B) 4:5
(C) 2:5
(D) 5:2
(E) None of them
Rationale: Let the third number be x.
Then, first number = 120% of x = 120x/100 = 6x/5
Second number = 150% of x = 150x/100 = 3x/2
Therefore, Ratio of first two numbers = (6x/5 : 3x/2)
= 12x : 15x = 4 : 5.
Answer is B.
Answer: (B) 4:5
Question: There are 8 red, 7 blue and 6 green balls, 1 ball is picked up randomly thenwhat is the probability that neither blue nor green?
(A) 2/23
(B) 3/23
(C) 4/25
(D) 5/26
(E) 8/21
Rationale: Total number of balls = (8 + 7 + 6) = 21
Let E = event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.
Therefore, n(E) = 8.
P(E) = 8/21.
Answer: (E) 8/21
Question: 45 x ? = 45% of 900
(A) 16.2
(B) 4
(C) 5
(D) 9
(E) 11
Rationale: Answer
Let 45 x A = (25 x 900)/100
∴ A = (45 x 9)/45 = 9
Correct Option: D
Answer: (D) 9
Question: A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability E that all 3 jellybeans removed from the bag are blue?
(A) 9/100
(B) 2/19
(C) 1/8
(D) 3/20
(E) 3/10
Rationale: Method-1
10 red jellybeans and 10 blue jellybeans
Total Outcomes = No. of ways to choose 3 Jelly bean at random out of a total 20 jellybeans = 20C3 = 1140
Favourable Outcomes = No. of ways to choose 3 Jelly bean such that they are all Blue out of 10 Blue = 10C3 = 120
Probability = Favourable Outcomes / Total Outcomes = 10C3 / 20C3
Probability E= 120 / 1140 = 2/19
Answer: option B
Method-2
Probability of First jelly bean to be Blue = 10/20 [Total 10 Blue out of total 20 jellybeans]
Probability of Second jelly bean to be Blue = 9/19 [Total 9 Blue remaining out of total 19 jellybeans remaining]
Probability of Third jelly bean to be Blue = 8/18 [Total 8 Blue remaining out of total 18 jellybeans remaining]
Required Probability = (10/20)*(9/19)*(8/18) = 2/19
Answer: option B
Answer: (B) 2/19
Question: The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?
(A) 28
(B) 26
(C) 18
(D) 109
(E) 12
Rationale: Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l2 = 324 => l = 18.
Answer:C
Answer: (C) 18
Question: Machine C takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine C to make 40 widgets?
(A)  5
(B)  6
(C)  8
(D)  10
(E)  12
Rationale: i approached this one by plugging in numbers...started with C.
if 40 are made in 8 hours, then 20 are made in 4 hours. so time of C is 4, and time of B is 2.
rate together: 20/4 + 20/2 = 5+10 = 15. so in 1 hour, together make 15 widgets. in 3 hours = 45. way too much. we can eliminate right away C, B, and A - because B and C reduces the time - the total # of widgets made will be even higher.
now between D and E -> try only one ..if it doesn't work, then the other one is the answer.
i picked E:
12h to make 40 widgets, and 6 hours to make 20. this is the time of C. time of B=4 hours.
20/6 + 20/4 = 10/3 + 20/4
find LCM of 3 and 4 = 12. multiply first by 4, and second by 3:
40+60/12 = 100/12
divide by 4:
25/3
so this is the rate given.
E is the correct answer
Answer: (E)  12
Question: 50 boys and 100 girls are examined in a test; 50% of the boys and 40% of the girls pass. The percentage of the total who failed is ?
(A) 42.5%
(B) 62.1%
(C) 56.7%
(D) 39.9%
(E) 51.4%
Rationale: Total number of students = 50+100 = 150
Number of students passed = (50% of 50+40% of 100) = 25+40 = 65
number of failures = 85*100/150 = 56.7%
Answer is C
Answer: (C) 56.7%
Question: What is the cost of leveling the field in the form of parallelogram at the rate of Rs.50/10 sq.metre, whose base & perpendicular distance from the other side being 54m & 24m respectively?
(A) Rs. 6000
(B) Rs. 6300
(C) Rs. 6400
(D) Rs. 6480
(E) Rs. 7000
Rationale: Area of the parallelogram = Length of the base * Perpendicular height
= 54 * 24 = 1296 m.
Total cost of levelling = Rs. 6480
D
Answer: (D) Rs. 6480
Question: The radius of a cone is 4 m, height 5 m. Find the curved surface area?
(A) 1
(B) 3
(C) 5
(D) 7
(E) 9
Rationale: Cone curved surface area = πrl = 22/7 × 4 × 5 = 440/7 = 62 6/7
Slant height (l) = √r(power2)+h(power2) = √16+9 = √25 = 5
Answer: (C) 5
Question: Product of two co-prime numbers is 117. Their L.C.M should be
(A) 1
(B) 117
(C) equal to their H.C.F
(D) cannot be calculated
(E) None
Rationale: Solution
H.C.F of co-prime numbers is 1.
So, L.C.M	= 117/1
‹=› 117.
Answer B
Answer: (B) 117
Question: Find the C.I. on a sum of Rs.1600 for 9 months at 20% per annum, interest being compounded quarterly?
(A) 2888
(B) 2689
(C) 2522
(D) 277
(E) 2911
Rationale: A = 1600(21/20)3 = 2522.Answer: C
Answer: (C) 2522
Question: Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 4x boxes?
(A) 3 minutes
(B) 4 minutes
(C) 5 minutes
(D) 6 minutes
(E) 8 minutes
Rationale: Rate = Work / Time
Given Rate of Machine A = X / 10 min
Machine B Produces 2x boxes in 5 min hence , Machine B produces 4x boxes in 10 min .
Rate of Machine B = 4x / 10
we need tofind the combined time that machines A and B, working simultaneouslytakeat their respective constant rates
let's first find the combined Rate of Machine A and B
Rate of Machine A = X / 10 min + Rate of Machine B = 4x / 10 = 5X/10
Now combine Time = combine work needs to be done / Combine Rate = 4x/5x * 10 = 8 Min
Ans: E
Answer: (E) 8 minutes
Question: A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 5.4 kilometer long bridge, at the same speed?
(A) 4 min
(B) 2 min
(C) 8 min
(D) 6 min
(E) 3 min
Rationale: S = 600/40 = 15 mps
S =5400/15 = 360 sec = 6 min.Answer:D
Answer: (D) 6 min
Question: The average of 6 observations is 15. A new observation is included and the new average is decreased by 1. The seventh observation is?
(A) 1
(B) 8
(C) 5
(D) 6
(E) 7
Rationale: Let seventh observation = X.
Then, according to the question we have
=> (90 + X) / 7 = 14
=> X = 8
Hence, the seventh observation is 8
ANSWER:B
Answer: (B) 8
Question: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 200 per month. What is his monthly salary?
(A) 6000
(B) 5000
(C) 5500
(D) 4000
(E) 3500
Rationale: Income = Rs. 100
Expenditure = Rs. 80
Savings = Rs. 20
Present Expenditure 80*(20/100) = Rs. 96
Present Savings = 100 â€“ 96 =Rs. 4
100 ------ 4
? --------- 200 => 5000
ANSWER B
Answer: (B) 5000
Question: A bag contains 12 white and 18 black balls.Two balls are drawn in succession without replacement. What is the probability that first is white and second is black?
(A) 36/145
(B) 29/145
(C) 18/145
(D) 20/145
(E) 15/145
Rationale: The probability that first ball is white=12C1/30C1=12/30=2/5
Since.the balls is not replaced; hence the number of balls left in bag=29.
Hence the probability of second ball is black is 18C1/29C1=18/29
Required probability =(2/5)*(18/29)=36/145
The answer is option A
Answer: (A) 36/145
Question: With a uniform speed a car covers the distance in 8 hours. Had the speed been increased by 4 km/hr, the same distance could have been covered in 7 1/2 hours. What is the distance covered?
(A) 400 km
(B) 480 km
(C) 490 km
(D) 380 km
(E) 330 km
Rationale: B
480 km
Let the distance be x km. Then,
x/(7 1/2) - x/8 = 4
2x/15 - x/8 = 4 => x = 480 km.
Answer: (B) 480 km
Question: The average monthly salary of 20 employees in an organisation is Rs. 1700. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ?
(A) 3800
(B) 3890
(C) 88798
(D) 2789
(E) 2891
Rationale: Explanation:
Manager's monthly salary Rs. (1800 * 21 - 1700 * 20) = Rs. 3800.
Answer: A) 3800
Answer: (A) 3800
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 20%?
(A) 20%
(B) 70%
(C) 29%
(D) 50%
(E) 24%
Rationale: SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20%
Answer:A
Answer: (A) 20%
Question: Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 1250 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.
(A) 513
(B) 512
(C) 517
(D) 519
(E) 521
Rationale: Trees increase by 1/4 the number of trees in preceding year. Hence, correct answer must be divisible by 4. Based on divisibility rules, if last 2 digits are divisible by 4 then the number is divisible by 4. Thus, we can eliminate A, C, D,E The answer to be B
Again, trees increase by 1/4 the number of trees in preceding year. Hence, the number of trees increase by 5/4 times the number of trees the preceding year.
If x = initial number of trees = 512
Year 1 = 5/4x
Year 2 = (5/4)(5/4)x
Year 3 = (5/4)(5/4)(5/4)x
Year 4 = (5/4)(5/4)(5/4)(5/4)x
Only for Answer D: (5/4)(5/4)(5/4)(5/4) 512 = 1250
Hence, correct answer = B
Answer: (B) 512
Question: In a forest 170 deer were caught, tagged with electronic markers, then released. A week later, 50 deer were captured in the same forest. Of these 50 deer, it was found that 5 had been tagged with the electronic markers. If the percentage of tagged deer in the second sample approximates the percentage of tagged deer in the forest, and if no deer had either left or entered the forest over the preceding week, what is the approximate number of deer in the forest?
(A) 150
(B) 750
(C) 1,250
(D) 1,700
(E) 2,500
Rationale: The percentage of tagged deer in the second sample = 5/50*100=10%.
So, 170 tagged deers comprise 10% of total # of deers --> total # of deers = 170*10 = 1,700.
Answer: D.
Answer: (D) 1,700
Question: Fresh grapes contain 60% water by weight and raisins obtained by drying fresh grapes contain 25% water by weight. How many kgs of fresh grapes are needed to get 20kgs of raisins?
(A) 75 kgs
(B) 64kgs
(C) 37.5 kgs
(D) 65 kgs
(E) 70 kgs
Rationale: The weight of non-water in 20 kg of dried grapes (which is 100-25=75% of whole weight) will be the same as the weight of non-water in x kg of fresh grapes (which is 100-60=40% of whole weight),
so 20*0.75 = x*0.4
--> x = 37.5.
Answer: C
Answer: (C) 37.5 kgs
Question: In a school 50% of the students are younger than 10, 1/20 are 10 years old and 1/10 are older than 10 but younger than 12, the remaining 70 students are 12 years or older. How many students are 10 years old?
(A) 20
(B) 40
(C) 10
(D) 39
(E) 48
Rationale: Let us write the fraction for each group of students
Group A: younger than 10: 50% = 50/100 = 1/2
Group B: 10 years old: 1/20
Group C: older that 10 but younger than 12: 1/10
Group D: 12 years or older: 70 students
The fraction for group A, B and C together is given by
1 / 2 + 1 / 20 + 1 / 10 = 10 / 20 + 1 / 20 + 2 / 20 , common denominator
= 13 / 20 , add numerators
The fraction for group D is given by
20 / 20 - 13 / 20 = 7 / 20 and corresponds to 70 students
If X is the total number of students, then
7 / 20 of X = 70
or (7 / 20) * X = 70
Solve for X
X = 70 * (20 / 7) = 200
Students who are 10 years old have a fraction of 1 / 20 of the total X and their number is equal to
(1 / 20) of 200 = 10 students
correct answer C
Answer: (C) 10
Question: Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
(A) 250
(B) 100
(C) 150
(D) 300
(E) 200
Rationale: Let amount paid to X per week = x
and the amount paid Y per week = y
x=120% of y = 120y/100 = 12y/10
22y/10=550
y=250
ANSWER A
Answer: (A) 250
Question: X and Y are integers, X is even and negative, Y is odd and positive. Which of the following could be false?
1. (X + Y) is an odd number.
2. Y^(X + Y) is an integer.
3. X^Y is a negative number.
(A) 2 only.
(B) 3 only.
(C) 1 and 3 only.
(D) 2 and 3 only.
(E) 1, 2 and 3.
Rationale: Statement I is TRUE
Statement II is not TRUE
Statement III is TRUE
Answer : C
Answer: (C) 1 and 3 only.
Question: The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
(A) 17 kmph
(B) 40 kmph
(C) 18 kmph
(D) 13kmph
(E) 19 kmph
Rationale: Speed downstream = 60 + 20 = 80 kmph
Speed upstream = 60 - 20
= 40 kmph
Answer:B
Answer: (B) 40 kmph
Question: A shopkeeper sells an article for Rs. 200 with a loss of Rs. 20 %. Find the cost price of the article.
(A) 220
(B) 250
(C) 280
(D) 260
(E) 275
Rationale: Explanation:
Hint:
Cost Price =	100/(100-Loss%)*S.P.
We are given that,
S.P. = Rs. 200 and loss = 20
Cost Price =	100/(100-20)*200
Cost Price =	100/80*200
Cost Price = Rs. 250
ANSWER IS B
Answer: (B) 250
Question: A city had 300 migrants in the year 2000. Since then, The number of migrants in a countrythe city has doubled every 3 years. If there were 300 migrants in the country in the year 2000, What was the increase in the population of migrants during the period from 2009 to 2012?
(A) 1200
(B) 2400
(C) 4800
(D) 6800
(E) 8400
Rationale: The population will increase in the following order:
2000: 300
2003: 600
2006: 1200
2009: 2400
2012: 4800
Difference between 2009 and 2012 = 2400
Option B
Answer: (B) 2400
Question: To save money, Arkadelphia Cream Cheese will reduce each dimension of its rectangular box container (which is entirely full of cream cheese) by 20%, and reduce the price it charges its consumers by 20% as well. By what percentage does this increase the price-per-cubic-inch that each consumer will pay for cream cheese?
(A) 1. No change
(B) 2. 56.25%
(C) 3. 100%
(D) 4. 300%
(E) 5. 400%
Rationale: Let,
L = 20: B = 10: H= 10 of initial box and Price = 50$
Therefore Price / cubic inch = 50 / (20*10*10) =0.025
Now, when dimensions are reduced by 50% and price also reduced by 50%
L = 16; B=8; H=8 and Price = 40$
Therefore price / cubic inch = 40 / (16*8*8) =0.039
Percentage change = (0.039 - 0.025) *100/ 0.025 = 56.25%
Answer is B
Answer: (B) 2. 56.25%
Question: If n=3*4*p where p is a prime number greater than 3,how many different positive non-prime divisors does n have, excluding 1 and n?
(A) Six
(B) Seven
(C) Eight
(D) Nine
(E) Ten
Rationale: n=3∗2^2∗p
Number of divisors = 2 * 3 * 2 = 12
The 12 divisors includes 1, n, 3, 2 and p
Number of different non prime divisors excluding 1 and n = 12 - 5 = 7
Answer: B
Answer: (B) Seven
Question: The least number which should be added to 1789 so that the sum is exactly divisible by 5, 6, 4 and 3 is?
(A) 1
(B) 11
(C) 21
(D) 31
(E) 41
Rationale: L.C.M. of 5, 6, 4 and 3 = 60.
On dividing 1789 by 60, the remainder is 49.
Number to be added = (60 - 49) = 11
B)
Answer: (B) 11
Question: 16 boys or 24 girls can construct the wall in 6 days. the number of days that 16 boys and 12 girls Will take to construct?
(A) 7 days
(B) 4 days
(C) 6 days
(D) 8 days
(E) 9 days
Rationale: Explanation:
16 boys =24 girls, 1 boy = 24/16 girls
1 boy = 6/4 girls
16 boys + 12 girls = 16 Ã— 6/4 + 12 = 24+ 12 = 36 girls
4 days to complete the work
Answer: Option B
Answer: (B) 4 days
Question: What will be the ratio of simple interest earned by certain amount at the same rate of interest for 25 years and that for 40 years?
(A) 5:8
(B) 7:5
(C) 3:8
(D) Data inadequate
(E) None of these
Rationale: Let the principal be P and rate of interest be R%.
∴ Required Ratio = [(P×R×25/100) /(P×R×40/100)]=25PR/40PR=25/40=5:8
Answer A
Answer: (A) 5:8
Question: Shipment --- No. of Defective Chips/shipment --- Total Chips in shipment
S1 ---------------------- 2 ------------------------------------------ 5,000
S2 ---------------------- 4 ------------------- ---------------------- 12,000
S3 ---------------------- 2 ------------------------------------------ 15,000
S4 ---------------------- 4 ------------------------------------------ 16,000
A computer chip manufacturer expects the ratio of the number of defective chips to the total number of chips in all future shipments to equal the corresponding ratio for shipments S1, S2, S3, and S4 combined, as shown in the table above. What’s the expected number of defective chips in a shipment of 60,000 chips?
(A) 14
(B) 20
(C) 22
(D) 24
(E) 15
Rationale: for a total of 51000 chips (adding S1,S2,S3,S4) total number of defective chips is 17 ((adding defective chips of S1,S2,S3,S4) so ratio is 12/48000 or 1 every 4000 chips.
Keeping this ratio constant for 60000 chips number of defective chips will be (1/4000) * 60000 = 15
E
Answer: (E) 15
Question: A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 11.00 a.m. ?
(A) 15
(B) 12
(C) 10
(D) 12
(E) 8
Rationale: A
15
Relative speed = 2 + 3 = 5 rounds per hour.
So, they cross each other 5 times in an hour and 2 times in half an hour.
Hence, they cross each other 15 times before 11.00 a.m.
Answer: (A) 15