mathewhe/aqua_rat huggingface dataset:
Question: A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?
(A) 111.12
(B) 111.18
(C) 131.12
(D) 211.12
(E) 111.17
Rationale: A runs 1000 m while B runs 900 m and C runs 800 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 800)/900 = 8000/9 = 888.88 m.
B can give C = 1000 - 888.88 = 111.12 m.
Answer:A
Answer: (A) 111.12
Question: A rectangular field has to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?
(A) 80 feet
(B) 85 feet
(C) 83 feet
(D) 88 feet
(E) 90 feet
Rationale: Given that area of the field = 680 sq. feet
=> lb = 680 sq. feet
Length(l) = 20 feet
=> 20 × b = 680
=> b = 680/20 = 34 feet
Required length of the fencing = l + 2b = 20 + (2 × 34) = 88 feet
Answer is D.
Answer: (D) 88 feet
Question: The average of first 8 prime numbers is?
(A) 10.11
(B) 9.625
(C) 12.11
(D) 13.11
(E) 14.11
Rationale: Sum of first 8 prime nos. = 2+3+5+7+11+13+17+19=77
Average = 77/8= 9.625
Answer : B
Answer: (B) 9.625
Question: The price of 10 bat is equal to that of 4 balls. The price of 15 balls and 2 bats together is Rs. 4000. The total price of 12 chairs and 3 balls is:
(A) Rs. 3200
(B) Rs. 3500
(C) Rs. 3700
(D) Rs. 3900
(E) Rs. 4000
Rationale: Let the cost of a chair and that of a table be Rs. x and Rs. y respectively.
Then, 10x = 4y or y = 5 x.
2
15x + 2y = 4000
15x + 2 x 5 x = 4000
2
20x = 4000
x = 200.
So, y = 5 x 200 = 500.
2
Hence, the cost of 12 chairs and 3 tables = 12x + 3y
= Rs. (2400 + 1500)
= Rs. 3900.
D)
Answer: (D) Rs. 3900
Question: The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 867 sq m, then what is the breadth of the rectangular plot?
(A) 65 m
(B) 17 m
(C) 16 m
(D) 76 m
(E) 27 m
Rationale: Let the breadth of the plot be b m.
Length of the plot = 3 b m
(3b)(b) = 867
3b2 = 867
b2 = 289 = 172 (b > 0)
b = 17 m.
Answer:B
Answer: (B) 17 m
Question: A money lender lends Rs.2000 for six months at 20% p.a. rate. It the interest is reckoned quarterly than find the amount given after time limit.
(A) 22075
(B) 2622
(C) 2677
(D) 2666
(E) 267
Rationale: Explanation:
A = 2000(21/20)2 = 2205
Answer: A
Answer: (A) 22075
Question: You can collect as many rubies and emeralds as you can. Each ruby is worth Rs. 4 crore and each emerald is worth Rs. 5 crore. Each ruby weighs 0.3 kg. And each emerald weighs 0.4 kg. Your bag can carry at the most 12 kg. What should you collect to get the maximum wealth?
(A) 20 rubies and 15 emeralds
(B) 40 rubies
(C) 28 rubies and 9 emeralds
(D) None of these
(E) Cannot be determined
Rationale: Explanation :
The limits our wealth is the capacity of bag which is 12 Kg. So we should make each unit of weight to worth the max.
Rubee: 0.3 Kg worth 4 Crore,
so 1 Kg of Rubee is worth 4/(0.3) = 40/3 = 13.33 Crore.
Emerald: 0.4 Kg worth 5 crore
so 1 Kg of Emerald is worth 5/(0.4) = 50/4 = 12.5 Crore.
As value per kilogram is more for Rubee we should pick max rubees for max wealth.
Here we can accomadate the whole 12Kg with 40 rubees which is worth 160 Crore.
Answer : B
Answer: (B) 40 rubies
Question: Evaluate : 980 x 436 + 980 x 764
(A) 1176000
(B) 968000
(C) 978000
(D) 117000
(E) None of them
Rationale: 980 x 436 + 980 x 764 = 986 x (436 + 664) = 986 x 1200 = 117600.
Answer is A.
Answer: (A) 1176000
Question: A train overtakes 2 girls who are walking inthe opposite direction in which the train is going at the rate of 3 km/hour & 6km/hour and passes them completely in 36sec & 30 sec respectively. Find the length of the train is?
(A) 120 m
(B) 130 m
(C) 150 m
(D) 200 m
(E) 250 m
Rationale: Let the length of the train e x meter, and let the speed of train be y km/h, then
\inline x=\left ( y+3 \right )\frac{5}{18}\times 36 ........(1)
and \inline x=\left ( y+6\right )\frac{5}{18}\times 30 ........(2)
From eq (1) and (2), we get
\inline (y+3)\times 36 = ( y+6)\times 30
y = 12 km/h
\inline \therefore \inline x=(y+3)\times \frac{5}{18}\times 36
x= 150 m
C
Answer: (C) 150 m
Question: Find the principle on a certain sum of money at 7% per annum for 2 2/5 years if the amount being Rs.1120?
(A) 939.6
(B) 958.9
(C) 927.78
(D) 926.82
(E) 902.1
Rationale: 1120 = P [1 + (7*12/5)/100]
P= 958.90
Answer: B
Answer: (B) 958.9
Question: The ratio of the present age of Viju to that of Aju is 7:2. Four years from now, the ratio of the ages of Viju to Aju will be 5:2. What was Viju age 6 years ago ?
(A) 10 years
(B) 15 years
(C) 20 years
(D) 25 years
(E) 30 years
Rationale: Let the present age of Viju be 7x years and that of Aju be 2x years.
Then, 4 years from now
7x + 4 / 2x + 4 = 5 / 2
or 4x = 12
or x = 3
Viju present age = 7 * 3 = 21 years
Viju age 6 years ago = 21 - 6 = 15 years
answer :B
Answer: (B) 15 years
Question: A straight line in the xy- plane has y-intercept of 12 and a slope of 4/7. Given the x-coordinate of the point is 49, find it's y-coordinate.
(A) 27
(B) 16
(C) 29.7
(D) 28
(E) 18
Rationale: Eq of line = Y = MX +C
M=4/7
C=12
X=49
Substitute the givens:
Y=(4/7 * 49) + 12,
Y=16 + 12 = 28
Correct option is D
Answer: (D) 28
Question: The average age of a husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
(A) 20
(B) 17
(C) 21
(D) 19
(E) 30
Rationale: Sum of the present ages of husband, wife and child = (23 * 2 + 5 * 2) = 57 years.
Required average = 57/3 = 19 years.
ANSWER D
Answer: (D) 19
Question: The cost price of an article is 64% of the marked price. Calculate the gain percent after allowing a discount of 15%?
(A) 32.8%
(B) 37.6%
(C) 38.5%
(D) 17.5%
(E) 37.2%
Rationale: Let marked price = Rs. 100.
Then, C.P. = RS. 64, S.P. = Rs. 85
Gain % = 21/64 * 100 = 32.8%.
Answer: A
Answer: (A) 32.8%
Question: A goods train runs at the speed of 72 km/hr and crosses a 280 m long platform in 26 sec. What is the length of the goods train?
(A) 240
(B) 277
(C) 276
(D) 270
(E) 281
Rationale: Speed = 72 * 5/18 = 20 m/sec.
Time = 26 sec.
Let the length of the train be x meters.
Then, (x + 280)/26 = 20
x = 240 m.
Answer: A
Answer: (A) 240
Question: Find the number of square tiles to cover the floor of a room measuring 4.5 m * 9.5 m leaving 0.25 m space around the room. A side of square tile is given to be 25 cms?
(A) 422
(B) 576
(C) 429
(D) 428
(E) 413
Rationale: Floor area to be covered by tiles = 4 * 9 = 36
tiles area = 0.25 * 0.25 =0.0625
No. of tiles = 36/0.0625 = 576
Answer : B
Answer: (B) 576
Question: The railway track length, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
(A) 300 m
(B) 245 m
(C) 350 m
(D) 250 m
(E) 260 m
Rationale: speed = (45*5/18) => 25/2 m/sec
time = 30 sec
length of bridge => x
=>130+x/30 = 25/2
2(130+x)=750
x=245 m
ANSWER B
Answer: (B) 245 m
Question: An athlete runs 200 metres race in 20 seconds. What is his speed?
(A) 23
(B) 38
(C) 37
(D) 36
(E) 28
Rationale: Speed=Distance/Time = 200/20 = 10 m/s = 10 * 18/5 = 36 km/hr
Answer :D
Answer: (D) 36
Question: A family pays $900 per year for an insurance plan that pays 80 percent of the first $1,000 in expenses and 100 percent of all medical expenses thereafter. In any given year, the total amount paid by the family will equal the amount paid by the plan when the family's medical expenses total.
(A) $1,000
(B) $1,200
(C) $1,300
(D) $1,800
(E) $2,200
Rationale: Upfront payment for insurance plan = 900$
Family needs to pay 20 % of first 1000 $ in expense = 200$
Total amount paid by family when medical expenses are equal to or greater than 1000 $ = 900 + 200 = 1100 $
Total amount paid by insurance plan for first 1000 $ = 900 $
Total amount paid by family will equal amount paid by plan when medical expense = 1300 $
(Since insurance plan will pay 100% of amount that exceeds 1100$ )
Answer C
Answer: (C) $1,300
Question: A number is doubled and 15 is added. If the resultant is multiplied by 5, it becomes 125. What is that number?
(A) 5
(B) 10
(C) 8
(D) None of these
(E) Cannot be determined
Rationale: Solution
Let the number be x.
Then, 5(2x + 15) ‹=› 125
‹=› 2x+15 = 25
‹=› 2x= 10
x= 5.
Answer D
Answer: (D) None of these
Question: It was calculated that 100 men could complete a piece of work in 20 days. When work was scheduled to commence, it was found necessary to send 50 men to another project. How much longer will it take to complete the work?
(A) 45 days.
(B) 40 days.
(C) 38 days.
(D) 35 days.
(E) 30 days.
Rationale: One day work = 1 / 20
One man’s one day work = 1 / ( 20 * 100)
Now:
No. Of workers = 50
One day work = 50 * 1 / ( 20 * 100)
The total no. of days required to complete the work = (100 * 20) / 50 = 40
Answer:B
Answer: (B) 40 days.
Question: A can run 2 km distance in 2 min., while B can run this distance in 2 min 40 sec. By how much distance can A beat B?
(A) 150 m
(B) 100 m
(C) 500 m
(D) 180 m
(E) 190 m
Rationale: A takes time 2 minutes=120sec
B takes time 2.40 minutes=160sec
diffrence= 160-120=40sec
now we are to find distance covered in 40 sec by B
160sec=2000m
1sec=25/2 m
40sec=40 x 25/2=500m
ANSWER:C
Answer: (C) 500 m
Question: There are 35 kids in a play school. 26 kids play with white color balls and some kids play with yellow color balls and 19 kids play with both color balls. How many kids use yellow color balls?
(A) 12
(B) 32
(C) 5
(D) 28
(E) 35
Rationale: Explanation :
n(AuB)= n(A) + n(B) - n(AnB)....(1)
n(A) = number of kids playing with white color balls = 26
n(AUB) = total number of kids in the play school = 35
n(AnB) = number of kids playing with both white and yellow color balls = 19
we have to find,
n(B) = number of kids playing with yellow color balls
From (1), 35 = 26 + n(B) - 19
n(B) = 35 + 19 - 26 = 28
Hence, Answer is 28 kids play with yellow color
balls.
Answer : D
Answer: (D) 28
Question: If f(x)= 5x^3- 2x+4 and g(y)= 6y-4, then g(f(x)) =
(A) 11x^2+4x+4
(B) 30x^3-12x+20
(C) 8x^3-8x+32
(D) 30x^3+4x+4
(E) 30x^3-12x+44
Rationale: g(f(x)) = 6(f(x)) -4 = 6(5x^3- 2x+4) - 4 = 30x^3-12x+20 =>B
Answer: (B) 30x^3-12x+20
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8587 for a computer table, then what was the cost price of the computer table?
(A) 6925
(B) 6887
(C) 6728
(D) 6725
(E) 2871
Rationale: :
CP = SP * (100/(100 + profit%))
= 8587(100/124) = Rs. 6925.
Answer: A
Answer: (A) 6925
Question: Veena ranks 65rd from the top in a class of 182. What is her rank from the bottom if 22 students have failed the examination?
(A) 96
(B) 108
(C) 110
(D) 90
(E) 93
Rationale: total student=182
failed=22
paasd student=182-22=160
from bottom her rank is=160-65+1=96
ANSWER:A
Answer: (A) 96
Question: A 180 meter long train crosses a man standing on the platform in 6 sec. What is the speed of the train?
(A) 109
(B) 108
(C) 109
(D) 106
(E) 101
Rationale: S = 180/6 * 18/5
= 108 kmph
AnswerB
Answer: (B) 108
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions?
(A) 794 m
(B) 704 m
(C) 454 m
(D) 186 m
(E) 176 m
Rationale: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4
= 70400 cm
= 704 m
Answer: B
Answer: (B) 704 m
Question: Find the sum The difference between the compound and S.I. on a certain sum of money for 2 years at 10% per annum is Rs.13 of money?
(A) 1300
(B) 1992
(C) 9921
(D) 2798
(E) 2789
Rationale: P = 13(100/10)2
=> P = 1300
Answer: A
Answer: (A) 1300
Question: If the cost price of 12 pens is equal to the selling price of 8 pens, the gain percent is:
(A) 22
(B) 77
(C) 50
(D) 77
(E) 23
Rationale: Let C.P. of each pen be Re. 1.
Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.
Gain % = 4/8 * 100 = 50%
Answer:C
Answer: (C) 50
Question: The third proportional to 2 and 6 is?
(A) 18
(B) 17
(C) 14
(D) 15
(E) 13
Rationale: (6*6)/2 = 18
Answer:A
Answer: (A) 18
Question: Ratio of the ages of Mahesh and Nilesh is 5:x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x?
(A) 14.9
(B) 14.5
(C) 14.3
(D) 14.2
(E) 14.5
Rationale: Let the present ages of Mahesh, Nilesh and Ramesh be M, N and R respectively.
M/N = 5/x --- (1)
M = R - 18 --- (2)
R + 9 = 47 --- (3)
M - N = R --- (4)
(3) => R = 47 - 9 = 38 years
(2) => M = 38 - 18 = 20 years
(1) => 20/N = 5/x => N = 4x
(4) => 4x - 20 = 38
=> 4x = 58 => x = 14.5
Answer: E
Answer: (E) 14.5
Question: What is the place value of 3 in the numeral 2734?
(A) 30
(B) 50
(C) 70
(D) 80
(E) 84
Rationale: Option 'A'
3 * 10 =30
Answer: (A) 30
Question: Three unbiased coins are tossed. What is the probability of getting at most two heads?
(A) 3/4
(B) 1/4
(C) 3/8
(D) 7/8
(E) None of these
Rationale: Explanation:
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
P(E) =	n(E)	/ n(S) =7/8.
ANSWER IS D
Answer: (D) 7/8
Question: A company produces 65000 bottles of water everyday. If a case can hold 13 bottles of water .How many cases are required by the company to hold its one day production
(A) 2000
(B) 4500
(C) 5000
(D) 8000
(E) 9000
Rationale: Number of bottles that can be held in a case = 13
Number of cases required to hold 65000 bottles = 65000/13=5000 cases.
So the answer is C =5000
Answer: (C) 5000
Question: In jar X there are 3 silver coins and 5 gold coins, in jar Y there are 4 silver coins and 2 gold coins. A jar is randomly picked, what is the probability of picking up a gold coin out of jar Y?
(A) 2/5.
(B) 3/5.
(C) 1/5.
(D) 3/4.
(E) 1/6.
Rationale: Probability of picking up one jar out of two= 1/2
probability of picking 1 gold coin from jar Y= 2/6= 1/3
Hence the desired probability= 1/2*1/3= 1/6
E is the answer
Answer: (E) 1/6.
Question: The charge for a single room at Hotel P is 25 percent less than the charge for a single room at Hotel R and 15 percent less than the charge for a single room at Hotel G. The charge for a single room at Hotel R is what percent greater than the charge for a single room at Hotel G ?
(A) 15%
(B) 20%
(C) 40%
(D) 13%
(E) 150%
Rationale: Let rate in R = 100x
then P = 75x
G = 100y
P = 85y
Thus
75 x=85y
or x = 1.13 y
Ans R = 113y
so increase = 13%
Answer: D
Answer: (D) 13%
Question: If the perimeter of square region D and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3 then the ratio of the area of R to the area of D
(A) 25:16
(B) 24:25
(C) 5:6
(D) 4:5
(E) 4:9
Rationale: We know Perimeter of a square (Pd) = 4*side
Perimeter of a rectangle (Pr) = 2(length+breath)
Let us assume 40 to be the perimeter of the square (since we know each side of a square is equal and the perimeter is divisible by 4, also take in to account the length and breadth of the rectangle is in the ration 2k:3k = 5k; we can assume such a number)
Therefore,
Pd = Pr = 40
Area of the square = 100 sq. units
We know 2(length+breadth) = 40
i.e. length + breadth = 20 (or 5k = 20 given that l:b (or b:l) = 2:3)
Therefore length = 8, breath = 12
Area of the rectangle = 8*12 = 96 sq. units
Question asked = Area of the rectangle : Area of the square = 96:100 ==> 24:25=B
Answer: (B) 24:25
Question: How many natural numbers are there between 43 and 200 which are exactly divisible by 6?
(A) 26
(B) 25
(C) 24
(D) 22
(E) 23
Rationale: 43/6 = 7, remainder = 1. Hence 5 more should be added to 43 to get the minimum
number divisible by 6 between 43 and 200.
=> Minimum number divisible by 6 between 43 and 200 = 43 + 5 = 48
200/6 = 33, remainder = 2. Hence 2 should be decreased from 200 to get the maximum
number divisible by 6 between 43 and 200.
=> Maximum number divisible by 6 between 43 and 200 = 200 - 2 = 198
Hence, natural numbers numbers divisible by 6 between 43 and 200 are 48, 54, 60,...198
This is Arithmetic Progression with a = 48, d = 6, l=198
Number of terms =(l−a)/d+1=(198−48)/6+1=150/6+1=25+1=26
Answer is A
Answer: (A) 26
Question: If x and y are positive integers and 25x=10y what is the least possible value of xy?
(A)  14
(B)  25
(C)  63
(D)  84
(E)  252
Rationale: 25x=10y
=> x/y = 2/5
=> 5x=2y
5(3)=2(3) => x*y=9 But it is not given
5(5)=2(5) => x*y=25
B
Answer: (B)  25
Question: A person's present age is two-fifth of the age of his mother. After 10 years, he will be one - half of the age of his mother. How old is the mother at present ?
(A) A)25
(B) B)40
(C) C)32
(D) D)50
(E) E)28
Rationale: Let the mother's present age be x years
Then the person's present age = 2x/5
(2x/5)+10 = 1/2(x+10)
2(2x+50) = 5 (x+10)
x = 50
Answer is D
Answer: (D) D)50
Question: It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
(A) Tuesday
(B) Friday
(C) Monday
(D) Sunday
(E) MondSD
Rationale: On 31st December, 2005 it was Saturday.
Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday
Answer: B
Answer: (B) Friday
Question: In covering a distance of 30 km, A takes 2 hours more than B. If Abhay doubles his speed, then he would take 1 hour less than B. A's speed is:
(A) 5 kmph
(B) 6 kmph
(C) 6.25 kmph
(D) 7.5 kmph
(E) 8.5 kmph
Rationale: Let A's speed be x km/hr.
Then, 30/x -30/2x = 3
--> 6x = 30
--> x = 5 km/hr.
Answer : A.
Answer: (A) 5 kmph
Question: In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 49 as quotient. What is the correct quotient ?
(A) 0
(B) 12
(C) 13
(D) 20
(E) 28
Rationale: 12*49=588
588%21=28
ANSWER:E
Answer: (E) 28
Question: Three solid metallic balls of radii, 3 cm, 4cm and 5 cm are
melted and moulded into a single solid ball. The radius of the
new ball is
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: Total volume of three metallic balls(spheres)= (4/3)*Pi*(3^3+4^3+5^3)
=(4/3)*Pi*216= Volume of new ball with radius 'r'
so (4/3)*Pi*r^3=(4/3)*Pi*216
r^3=216 , r=6
ANSWER:B
Answer: (B) 5
Question: The average of first six prime numbers which are between 30 and 70 is
(A) 35.4
(B) 42
(C) 45.7
(D) 57
(E) 67
Rationale: Explanation :
first six prime numbers which are between 30 and 70 = 31, 37, 41, 43, 47, 53
average = (31 + 37 +41 + 43 + 47 + 53)/6
= 42
Answer : B
Answer: (B) 42
Question: JAK, KBL, LCM, MDN, _____
(A) NEO
(B) SAS
(C) DFG
(D) JKL
(E) JHN
Rationale: This is an alternating series in alphabetical order. The middle letters follow the order ABCDE. The first and third letters are alphabetical beginning with J. The third letter is repeated as a first letter in each subsequent three-letter segment.
ANSWER:A
Answer: (A) NEO
Question: If G is to be chosen at random from the set {5,8,7,1} and K is to be chosen at random from the set {14,8,3}, what is the probability that GK will be even?
(A) 1
(B) 5
(C) 8
(D) 4
(E) 3
Rationale: Method-1
GK will be even when
1) G is even and K is odd, Probability of G even is (1/4) and Probability of K odd is (1/3), so Probability of Case(1) = (1/4)*(1/3) = (1/12)
2) G is Odd and K is Even, Probability of G Odd is (3/4) and Probability of K Even is (2/3), so Probability of Case(2) = (3/4)*(2/3) = (6/12)
3) G is even and K is Even, Probability of G even is (1/4) and Probability of K Even is (2/3), so Probability of Case(1) = (1/4)*(2/3) = (2/12)
Total Favorable Probability = (1/12)+(6/12)+(2/12) = (12/12) = 1
Answer: option A
Answer: (A) 1
Question: A pump can fill a tank with water in 2 hours. Because of a leak, it took 7/3 hours to fill the tank. The leak can drain all the water of the tank in?
(A) 7
(B) 12
(C) 5
(D) 14
(E) 13/3
Rationale: P --> Pump, L ---> Leak
Pipe----------P---------L------------(P-L)--
Time---------2---------x-------------7/3
*
Rate-------7/3---------x-------------2
Work------14/3-------14/3---------14/3
Time required to empty the tank if leakage present = (14/3)/((7/3) - 2)
= (14/3)/(1/3)
= 14
Ans -D
Answer: (D) 14
Question: Find the simple interest on Rs. 68,000 at 16 2/3% per year for 9 months.
(A) 7500
(B) 6500
(C) 8500
(D) 9500
(E) None of them
Rationale: P = Rs.68000,R = 50/3% p.a and T = 9/12 years = 3/4years.
Simple Interest = (P*R*T)/100 = Rs.(68,000*(50/3)*(3/4)*(1/100))= Rs.8500
Answer is C.
Answer: (C) 8500
Question: The total of company C's assets in 1994 was 150% greater than the total in 1993, which in turn was 400% greater than the total in 1992. If the total of company C's assets in in 1992 was N dollars, which one of the following represents company C's assets in 1994:
(A) 7N
(B) 8N
(C) 9N
(D) 12.5N
(E) 20
Rationale: Let's use actual numbers. Starting in 1992, let's say company C had $100 in assets.
In 1993, the total assets were 400% GREATER, which means 1992 PLUS 400% of 1992:
$100 + 4x$100 = $100 + $400 =$500
In 1994, the total assets were 150% GREATER than they were in 1993, which means 1993 PLUS 300% of 1993:
$500 + 1.5x$500 = $500 + $750 =$1250
This is 12.5 times the 1992 number, so the correct answer is 12.5N.
D
Answer: (D) 12.5N
Question: Two spherical balls lie on the ground touching. If one of the balls has a radius of 9 cm, and the point of contact is 10 cm above the ground, what is the radius of the other ball (in centimeters)?
(A) 50/4
(B) 70/6
(C) 80/7
(D) 90/8
(E) 100/9
Rationale: A straight line will join the two centers and the point of contact, thus making similar triangles.
1/9 = (r-10)/r
r = 9r - 90
r = 90/8
The answer is D.
Answer: (D) 90/8
Question: Peeta asks Katniss, 'It is 6 pm as per my watch right now.Do you know what will be the time 23, 999, 999 hours later?'
Katniss knows the answer. Do you ?
(A) 3pm
(B) 6pm
(C) 4am
(D) 7am
(E) 8pm
Rationale: A
3pm
The time after 24, 000, 000 hours will be the same as it is now. We want the time 3 hours before that and thus you can deduct three hours from 9 pm. So the time will be 6 pm.
Answer: (A) 3pm
Question: If a tap could fill entire tank in 18 hrs due to leakage, then in how much time
tank can be emptied by leakage if tap can fill entire tank in 12 hrs without leakage
(A) 12hrs
(B) 24hrs
(C) 36hrs
(D) 48hrs
(E) 52hrs
Rationale: time take to fill[withleakage] =18hrs so workdone in 1hr=1/18
time tkae to fill[without leakage]=12hrs so workdone in 1hr=1/12
if u subtract both u'll get time taken by leakage to empty...
1/18-1/12=1/36 so 36hrs
ANSWER:C
Answer: (C) 36hrs
Question: In a simultaneous throw of two coins, the probability of getting atleast one headis:
(A) 1/4
(B) 2/5
(C) 7/9
(D) 4/5
(E) 3/4
Rationale: n(S)=4
E = even getting at least one head
N(E)=3
P(E)=3/4
Ans: E
Answer: (E) 3/4
Question: A circular logo is enlarged to fit the lid of a jar. The new diameter is 20 per cent larger than the original. By what percentage has the area of the logo increased?
(A) 50
(B) 80
(C) 100
(D) 44
(E) 250
Rationale: Let old diameter be 4 , so radius is 2
Old area = 4π
New diameter is 4.8 , so radius is 2.4
New area = 5.76π
Increase in area is 1.76π
% increase in area = 1.76/4*100
So, % increase is 44%
Answer will be (D)
Answer: (D) 44
Question: Two teams are distributing information booklets. Team A distributes 60% more boxes of booklets than Team H, but each box of Team A’s has 60% fewer booklets than each box of Team H’s. Which of the following could be the total number of booklets distributed by the two groups?
(A) 2,000
(B) 3,200
(C) 4,100
(D) 4,800
(E) 4,900
Rationale: Let x be the no of booklets in each box that team H distributes. So, Team A has 60% fewer - 0.4x.
Let y be the no. of boxes distributed by team H. So, Team A distributes 60% more - 1.6y
Total booklets distributed by team A = xy
Total booklets distributed by team H=0.64xy
Total booklets distributed = xy+0.64xy=1.64xy
As no. of booklets can only be integer, plugging the answer choice equal to 1.64xy should give an integer.
Choice A - 1.64xy=2000; xy=2000/1.64 = doesn't provide an integer value.
Similarly all answer choices, except choice C, fail to provide an integer value.
Choice C = 4100/1.64= 2500 and is the correct answer.
Answer: (C) 4,100
Question: Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $250, what were her original savings?
(A) $500
(B) $600
(C) $700
(D) $800
(E) $1000
Rationale: If Linda spent 3/4 of her savings on furnitute, the rest
4 / 4 - 3 / 4 = 1 / 4 on a TV
But the TV cost her $250. So 1 / 4 of her savings is $250. So her original savings are 4 times $250 = $1000
correct answer E
Answer: (E) $1000