mathewhe/aqua_rat huggingface dataset:
Question: The amount of time that three people worked on a special project was in the ratio of 4 to 3 to 5. If the project took 120 hours, how many more hours did the hardest working person work than the person who worked the least?
(A) 25 hours
(B) 30 hours
(C) 20 hours
(D) 26 hours
(E) 32 hours
Rationale: Let the persons be A, B, C.
Hours worked:
A = 4*120/12 = 40 hours
B = 3*120/12 = 30 hours
C = 5*120/12 = 50 hours
C is the hardest worker and B worked for the least number of hours. So the difference is 50-30 = 20 hours.
Answer : C
Answer: (C) 20 hours
Question: Certain stocks in January were 10% less than they were in February and 20% greater than they were in March. What was the percentage decrease in the stocks from February to March?
(A) 5%
(B) 10%
(C) 20%
(D) 25%
(E) 50%
Rationale: Let J,F,M be the values of the stock in Jan,Feb and March.
Thus, per the question, J = 0.9F = 1.2M ----> M =0.75F
Thus the % decrease from F to M = (F-M)/(F) *100 = (F-0.75F)/F * 100 = 0.25*100 = 25 %, D is the correct answer.
Answer: (D) 25%
Question: If a man walks at the rate of 5 kmph, he misses a train by 7 minutes. However, if he walks at the rate of 6 kmph, he reaches the station 5 minutes before the arrival of the train. Find the distance covered by him to reach the station.
(A) 8 km
(B) 6 km
(C) 12 km
(D) 9 km
(E) 7 km
Rationale: Sol. Let the required distance be x km
Difference in the time taken at two speeds=1 min =1/2 hr
Hence x/5-x/6=1/5<=>6x-5x=6
x=6
Hence, the required distance is 6 km
Ans:B
Answer: (B) 6 km
Question: A, B and C shared the profit in a business in the ratio 5 : 7 : 8. They had partnered for 14 months, 8 months and 14 months respectively. What was the ratio of their investments?
(A) 10:12:14
(B) 12:24:28
(C) 20:22:12
(D) 20:49:32
(E) None of these
Rationale: Explanation :
Ratio in which A,B and C shared the profit = 5 : 7 : 8
Assume that the ratio of their investment = a:b:c
Then 14a : 8b : 14c = 5 : 7 : 8
Good to go, we got the equation. Now it's a matter of time to find a, b and c
14a/8b = 5/7
=> 98a = 40b
=> b = 98a/40 = 49a/20 ---(1)
14a/14c =5/8
=> a/c =5/8
=>8a = 5c
=> c = 8a/5 ---(2)
a : b : c = a : 49a/20 : 8a/5 = 1 : 49/20 : 8/5 = 20 : 49 : 32. Answer : Option D
Answer: (D) 20:49:32
Question: a father is 5 times as faster as son in doing a work. Father completes a particular work in 40 days before son.If both of them work together in how many days can they complete the work?
(A) 8.33days
(B) 9.33days
(C) 10.33days
(D) 7.33days
(E) 6.33days
Rationale: f=5*s
f(t-40)=w=s*t
5*s*(t-40)=s*t
5t-t=200
t=50
father takes 10 day
son takes 50 days
together=50/6=8.33days
ANSWER:A
Answer: (A) 8.33days
Question: The radius of a sphere is increased by 10%. The surface area increases by?
(A) 21%
(B) 31%
(C) 41%
(D) 51%
(E) none of these
Rationale: Since 4 x pi x radius x radius = surface area.
Therefore, net % change in area
= ( x + y + xy/100) %
= [10 + 10 + (10 x 10)/100]% or 21%.
ANSWER:A
Answer: (A) 21%
Question: the hiker walking at a constant rate of 4 miles per hour is passed by a cyclist traveling in the same direction along the same path at 15 miles per hour. the cyclist stops to wait for the hiker 5 minutes after passing her, while the hiker continues to walk at her constant rate, how many minutes must the cyclist wait until the hiker catches up?
(A) 20
(B) 55/4
(C) 25
(D) 14
(E) 13
Rationale: After passing the hiker the cyclist travels for 5 minutes at a rate of 15 miles/hour.
In those 5 mins the cyclist travels a distance of 5/4 miles.
In those 5 mins the hiker travels a distance of 1/3 miles.
So the hiker still has to cover 11/12 miles to meet the waiting cyclist.
The hiker will need 55/4 mins to cover the remaining 11/12 miles.
So the answer is B.
Answer: (B) 55/4
Question: Two pipes P and Q can fill a cistern in 12 and 17 minutes respectively. Both are opened together, but at the end of 3 minutes the first is turned off. How much longer will the cistern take to fill?
(A) 11 1/2 min
(B) 11 1/4 min
(C) 12 3/4 min
(D) 11 1/5 min
(E) 11 7/4 min
Rationale: 3/12 + x/17 = 1
x= 12 3/4
Answer: C
Answer: (C) 12 3/4 min
Question: If 4 (A's capital) = 6 (B's capital) = 10 (C's capital), then out of a profit of Rs. 930, C will receive
(A) 233
(B) 180
(C) 900
(D) 287
(E) 271
Rationale: Explanation:
Let 4A = 6B = 1OC = k. Then, A = k/4, B = k/6, and C =k/10 .
A : B :C = k/4 : k/6 : k/10 = 15 : 10 : 6.
Hence, C's share (930 * 6/31) = Rs, 180.
Answer: B) Rs.180
Answer: (B) 180
Question: Two numbers are in the ratio of 5:7. If 25 be subtracted from each, they are in the ratio of 35:59. Find the numbers?
(A) 60,88
(B) 60,86
(C) 60,82
(D) 60,84
(E) 60,83
Rationale: (5x-25):(7x-25)
= 35:59
x = 12
=>60,84
Answer: D
Answer: (D) 60,84
Question: Three persons A, B and C divide a certain amount of money such that A's share is Rs.4 less than half of the total amount. B's share is Rs.8 more than half of what is left and finally C takes the which is Rs.14. Find the total amount they initially had with them?
(A) 77
(B) 66
(C) 80
(D) 99
(E) 61
Rationale: Let the total amount be Rs.P
Let shares of A and B be Rs.X and Rs.Y respectively.
Given, C's share was Rs.14.
X + Y + 14 = P --- (1)
From the given data, X = P/2 - 4 --- (2)
Remaining amount = P - (P/2 - 4) = P/2 + 4
Y = 1/2(P/2 + 4) + 8
=> P/4 + 10 --- (3)
From (1), (2) and (3)
P/2 - 4 + P/4 + 10 + 14 = P
=> 3P/4 + 20 = P
=> P - 3P/4 = 20
=> P/4 = 20 => P = Rs.80
Answer:C
Answer: (C) 80
Question: A student chose a number, multiplied it by 5, then subtracted 138 from the result and got 102. What was the number he chose?
(A) 48
(B) 120
(C) 130
(D) 140
(E) 150
Rationale: Solution:
Let xx be the number he chose, then
5⋅x−138=102
5x=240
x=48
Answer A
Answer: (A) 48
Question: A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current?
(A) 3 kmph
(B) 1.5 kmph
(C) 13 kmph
(D) 6.5 kmph
(E) 7:3kmph
Rationale: Explanation:
72 --- 9 DS = 8
? ---- 1
45 ---- 9 US = 5
? ---- 1 S = ?
S = (8 - 5)/2 = 1.5
Answer: Option B
Answer: (B) 1.5 kmph
Question: Let S be the set of values which can be written as the sum of 5 consecutive perfect squares.
What is the smallest element of S which is divisible by 17?
(A) 255
(B) 355
(C) 522
(D) 355
(E) 664
Rationale: Each element of S can be written in the form
(x- 2)2 + (x - 1)2 + x2 + (x + 1)2 + (x + 2)2 = x2 + 2x2 + 2 + 2x2 + 8
= 5x2 + 10
= 5(x2 + 2)
where x is some positive integer with x 3. By iterating over values of x, we observe that when
x = 7, x2 + 2 = 51 = 3 * 17; no smaller value of x exists which satisfies the problem statement.
Hence, the solution is 5(x2 + 2) = 5 *51 = 255
correct answer A
Answer: (A) 255
Question: Joe went on a diet 4 months ago when he weighed 212 pounds. If he now weighs 188 pounds and continues to lose at the same average monthly rate, in approximately how many months will he weigh 160 pounds?
(A)  3
(B)  3.5
(C)  4
(D)  4.5
(E)  5
Rationale: 212 - 188 = 24 pounds lost in 4 months
24/4 = 6, so Joe is losing weight at a rate of 6 pounds per month.
...in approximately how many months will he weigh 160 pounds?
A simple approach is to just list the weights.
Now: 188 lbs
In 1 month: 182 lbs
In 2 months: 176 lbs
In 3 months: 170 lbs
In 4 months: 164 lbs
In 5 months: 158 lbs
Since 160 pounds is halfway between 164 and 158, the correct answer must be 4.5 months.
Answer: D
Answer: (D)  4.5
Question: At a recent small town election for mayor a total of 975 votes were cast for the four candidates, the winner exceeding his opponents by 53, 79 and 105 votes, respectively. How many votes were cast for the candidate in fourth place?
(A) 134
(B) 178
(C) 198
(D) 166
(E) 194
Rationale: The number of votes the winning candidate received was
975 + 53 + 79 + 105	/4= 303.
The second received 303 – 53 = 247,
The fourth place received 303 – 105 = 198.
C
Answer: (C) 198
Question: Find the value of x from the below equation? : x^2-16 = 0
(A) 8
(B) 16
(C) -4
(D) 1
(E) -8
Rationale: a = 1, b = 0, c = -16
x1,2 = (0 Â± âˆš(0^2 - 4Ã—1Ã—-16)) / (2Ã—1) = (0Â± âˆš(64)) / 2 = (0 Â± 8) / 2
x1 = (0 + 8)/2 = 8/2 = 4
x2 = (0-8)/2 = -8/2 = -4
C
Answer: (C) -4
Question: The compounded ratio of (2 : 3), (6: 11) and (11 :2) is :
(A) 1:2
(B) 5:9
(C) 2:1
(D) 11:24
(E) None
Rationale: Answer: Option C
2/3 : 6/11 : 11/2 = 2:1
Answer: (C) 2:1
Question: Excluding stoppages, the speed of a bus is 90 km/hr and including stoppages, it is 84 km/hr. For how many minutes does the bus stop per hour?
(A) 18 min
(B) 4 min
(C) 8 min
(D) 6 min
(E) 5 min
Rationale: Due to stoppages, it covers 6 km less.
Time taken to cover 6 km = 6/90 * 60
= 4 min.
Answer:B
Answer: (B) 4 min
Question: In how many ways can the letters of the word ABCdef be rearranged such that the lower case letters always appear together?
(A) 196
(B) 255
(C) 299
(D) 144
(E) 169
Rationale: ABCdef
def will come together as a group which can be arranged in 3!=6ways.
def,A,B,C can be arranged in 4!=24 ways.
total possible arrangements = 6*24=144ways
ANSWER:D
Answer: (D) 144
Question: Positive Integer A gives the remainder of 9 when divided by another positive Integer B. If A/B = 47.45, what is the value of B?
(A) 96
(B) 75
(C) 48
(D) 20
(E) 12
Rationale: I think the answer should be 25.
This is how i solved.
.45 of B = Remainder
.45 of B = 9
B = (9 *100) / 45 = 20.
D
Answer: (D) 20
Question: If Mason is now twice as old as Gunther was 5 years ago, and G is Gunther's current age in years, which of the following represents the sum of Mason and Gunther's ages 10 years from now?
(A) 3G+14
(B) 3G+8
(C) 3G+15
(D) 3G+10
(E) 3G+9
Rationale: G is Gunther's current age.
Let Mason's current age be M.
given M = 2(G-5).
four years from now Mason's age will be = 2(G-5) + 10 = 2G
four years from now Gunther's age will be = G+10
Sum of ages of Mason and Gunther's after 4 years = 2G+G+10 = 3G+10
Ans : D
Answer: (D) 3G+10
Question: A sum of Rs. 1000 amounts to Rs. 1200 in 4 years at the rate of simple interest. What is the rate of interest?
(A) 7%
(B) 9%
(C) 5%
(D) 6%
(E) 2%
Rationale: S.I. = (1200 - 1000) = Rs. 200\
Rate = (100 * 200) / (1000* 4)
= 5%
Answer: C
Answer: (C) 5%
Question: If a(a - 6) = 7and b(b -6) = 7, where a ≠ b, then a + b =
(A) −48
(B) −2
(C) 6
(D) 9
(E) 48
Rationale: i.e. if a = -1 then b = 7
or if a = 7 then b = -1
But in each case a+b = -1+7= 6
Answer: option C
Answer: (C) 6
Question: Molly is rolling a number cube with faces numbered 1 to 6 repeatedly. When she receives a 2, she will stop rolling the cube. What is the probability that Molly will roll the die less than 3 times before stopping?
(A) 11/180
(B) 11/36
(C) 25/216
(D) 91/216
(E) 27/128
Rationale: The probability that Molly will roll the die less than 4 times before stopping is the sum of the following:
The probability that Molly will roll the die once: P=1/6 (she gets 2 on the first roll);
The probability that Molly will roll the die twice: P=5/6*1/6 (not 2, 2);
P = 1/6 + 5/6*1/6 = 11/36
Answer: B
Answer: (B) 11/36
Question: On a Monday in a certain restaurant, 30 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?
(A) 15%
(B) 16%
(C) 18%
(D) 22%
(E) 30%
Rationale: 30% of 180= 54
10% of 120=12
Total =66
percent for 2 days combined =66/300=0.22. so it should be less than 0.22 so it is 22%
Answer:D
Answer: (D) 22%
Question: Find large number from below question The difference of two numbers is 1015. On dividing the larger number by the smaller, we get 9 as quotient and the 15 as remainder
(A) 1209
(B) 1324
(C) 1245
(D) 1140
(E) 1635
Rationale: Let the smaller number be x. Then larger number = (x + 1015).
x + 1015 = 9x + 15
8x = 1000
x = 125
Large number = 125+1015= 1140
Answer : D
Answer: (D) 1140
Question: Albert buys 4 horses and 9 cows for Rs. 13,400. If he sells the horses at 10% profit and the cows at 20% profit, then he earns a total profit of Rs. 1880. The cost of a horse is:
(A) Rs.2007
(B) Rs.2000
(C) Rs.2089
(D) Rs.2067
(E) Rs.2098
Rationale: Let C.P. of each horse be Rs. x and C.P. of each cow be Rs. y.
Then, 4x + 9y = 13400 -- (i)
And, 10% of 4x + 20% of 9y = 1880
2/5 x + 9/5 y = 1880 => 2x + 9y = 9400 -- (ii)
Solving (i) and (ii), we get : x = 2000 and y = 600.
Cost price of each horse = Rs.2000.
Answer:B
Answer: (B) Rs.2000
Question: Three coins are tossed. Find the probability of at most 2 tails ?
(A) 1/2
(B) 1/4
(C) 2/3
(D) 7/8
(E) 3/8
Rationale: n(s) = 2^3 = 8
let E is the event of getting at most 2 tails
n(E) = HHH, TTH , HTT, THT, HHT, HTH, THH = 7
P(E) = n(E) / n(s)
= 7/8
Ans- D
Answer: (D) 7/8
Question: A trader marked the selling price of an article at 40% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of :
(A) 10 %
(B) 7.8 %
(C) 11 %
(D) 12.5 %
(E) None
Rationale: Sol.
Let C.P. = Rs. 100. Then, Marked Price = Rs. 140, S.P. = Rs. 99.
∴ Discount % = [11/140 * 100] % = 7.8%
Answer B
Answer: (B) 7.8 %
Question: The price of an item is discounted 10 percent on day 1 of a sale. On day 2, the item is discounted another 10 percent, and on day 3, it is discounted an additional 30 percent. The price of the item on day 3 is what percentage of the sale price on day 1?
(A) 28%
(B) 63%
(C) 64.8%
(D) 70%
(E) 72%
Rationale: Let initial price be 1000
Price in day 1 after 10% discount = 900
Price in day 2 after 10% discount = 810
Price in day 3 after 30% discount = 567
So, Price in day 3 as percentage of the sale price on day 1 will be = 567/900*100 => 63%
Answer will definitely be (B)
Answer: (B) 63%
Question: Two friends P & Q started a business investing amounts in the ratio of 5 : 6. R joined them after six months investing an amount equal to that of Qâ€™s amount. At the end of the year 28% profit was earned which was equal to 98,000. What was the amount invested by R?
(A) 2,10,000
(B) 1,05,000
(C) 75,000
(D) Data inadequate
(E) None of these
Rationale: Ratio for amount invested by P, Q & R
= 5x Ã— 12 : 6x Ã— 12 : 6x Ã— 6
= 60x : 72x : 36x
= 5x : 6x : 3x
Profit = 98000 = 28% of T
where, T = Total amount
T = 350000
Amount received by
R = 3x /3x+6x+5x(350000)
= 75000
Answer C
Answer: (C) 75,000
Question: A man sold 20 articles for $60 and gained 20%. How many articles should he sell for $40 to incur a loss 20%?
(A) 20
(B) 36
(C) 40
(D) 50
(E) 48
Rationale: Production cost per article: $60*(100%-20%) / 20 = $2.40
Required production costs for a loss of 20%: $40*(100% + 20%) = $48
Number of articles to be sold for $48 to incur a 20% loss: $48 / $2.40 = 20
Thus, solution A is correct.
Answer: (A) 20
Question: If three people (A,B,C) want to raise $30000.00 capital to start a business as below: A raises half the amount of B and C raises 3 times the amount of A, how much A will raise?
(A) A - $5000
(B) B - $5005
(C) C - $5010
(D) D - $5015
(E) E - $5020
Rationale: Let the capital raised by A is x, the capital raised by B is 2x and capital raised by C is 3x. Then, total amount raised by A, B, C is x+2x+3x = 6x = $30000.00 Hence x = $30000.00/6 = $5000.00 Answer is A.
Answer: (A) A - $5000
Question: In a room filled with 6 people, all 6 people have exactly 2 siblings in the room. If two individuals are selected from the room at random, what is the probability that those two individuals are NOT siblings?
(A) 3/5
(B) 3/7
(C) 4/7
(D) 5/6
(E) 7/12
Rationale: The 6 people consist of two sets of 3 siblings.
The number of ways to choose 2 people is 6C2 = 15.
The number of ways to choose 2 from the first group of siblings is 3C2 = 3.
The number of ways to choose 2 from the second group of siblings is 3C2 = 3.
The number of ways to choose 2 people who are siblings is 3+3 = 6.
The number of ways to choose 2 people who are not siblings is 15-6=9.
P(the two people are not siblings) = 9/15 = 3/5
The answer is A.
Answer: (A) 3/5
Question: What is the sum of the greatest common factor and the lowest common multiple of 72 and 36?
(A) 120
(B) 150
(C) 145
(D) 108
(E) 112
Rationale: Prime factorization of 36 = 2 x 2 x 3 x 3
Prime factorization of 72 = 2 x 2 x 2 x 3 x 3
GCF = 36
LCM = 72
Sum = 108
Ans: D
Answer: (D) 108
Question: The timing of a college is from 12 p.m to 4.20 p.m. Six lectures are held in the given duration and a break of 5 minutes after each lecture is given to the students. Find the duration of each lecture.
(A) 52 minutes
(B) 45 minutes
(C) 30 minutes
(D) 39 minutes
(E) 44 minutes
Rationale: Explanation:
Total time a student spends in college = 4 hours 20 minutes = 260 minutes
As there are 6 lectures, the number of breaks between lectures is 5. Total time of the break = 25 minutes
Hence, the duration of each lecture is = (260 â€“ 25)/6
= 39 minutes
ANSWER D
Answer: (D) 39 minutes
Question: The length of the room is 10m and width is 20m. Find the cost of paving the floor by slabs at the rate of Rs.400 per sq meter?
(A) 70000
(B) 80000
(C) 60000
(D) 50000
(E) 20000
Rationale: l=10m w=20m
area of the floor = 10 x 20 = 200 sq m
cost of paving = 400 x 200= Rs. 80000
Answer: B
Answer: (B) 80000
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a gain ?
(A) A)657
(B) B)200
(C) C)438
(D) D)290
(E) E)427
Rationale: x = price of a book sold at loss
x*(85/100)
= (480 - x)119/100
x = 280
Price of book sold at gain = 480 - 280 = 200
Answer:B
Answer: (B) B)200
Question: 10% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 2907, how much was it in the beginning?
(A) A)3800
(B) B)4200
(C) C)4400
(D) D)4500
(E) E)4600
Rationale: X * (90/100) * (85/100) = 2907
X = 3800
ANSWER:A
Answer: (A) A)3800
Question: Which of the following cannot be divided by 3 (the sum of 3 different prime numbers)?
(A) 10
(B) 23
(C) 14
(D) 15
(E) 19
Rationale: Option A: 10 = 2+3+5. Sum of 3 different prime numbers.
Option B: 15 = 7+5+3. Sum of 3 different prime numbers
Option C: 24 = 19+3+2. Sum of 3 different prime numbers
Option D: 12 = this is not a sum of 3 different prime numbers.
Option E: 18 = 3 + 5 + 11. Sum of 3 different prime numbers
Since 24, 15, 12, 18 divided by 3
Correct Option: A
Answer: (A) 10
Question: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2460?
(A) 28888
(B) 27789
(C) 2777
(D) 14000
(E) 2881
Rationale: 25*12: 30*12: 35*8
15:18:14
14/47 * 47000 = 14000
Answer: D
Answer: (D) 14000
Question: In a stack of cards, 9 cards are blue and the rest are red. If 2 cards are to be chosen at random from the stack without replacement, the probability that the cards chosen will both be blue is 9/11. What is the number of cards in the stack?
(A) 10
(B) 11
(C) 12
(D) 15
(E) 18
Rationale: This question can be solved by TESTing THE ANSWERS.
We're told that we have 9 blue cards and an unknown number of red cards. We're also told that if 2 cards are to be chosen at random from the stack WITHOUT replacement, then the probability that the cards chosen will BOTH be BLUE is 9/11. We're asked for the TOTAL number of cards.
Normally, when TESTing THE ANSWERS, we should start with either B or D. Answer B looks easier, so let's start there.
Answer A: 10 total cards
With 10 total cards, and 9 blue cards, the probability of pulling two blue cards is...
(9/10)(8/9) = 72/90~ 9/11
A
Answer: (A) 10
Question: Mrs. Evans gave a test to her freshmen economics class, which has 50 students enrolled and 25 of them answered question 1 correctly. If 20 answered question 2 correctly and 20 did not take the test then how many answered both questions correctly?
(A) 23
(B) 22
(C) 21
(D) 20
(E) 19
Rationale: Total number of enrolled students = 50
Number of students who did not take test = 20
Hence, number of students who took test = 50 - 20 = 30
Number of students who answered Q2 correctly =20, therefore, all students who took test answered Q2 correctly.
So, number of students who answered Q1 correctly, also answered Q2 correctly = 20.
Number of students who answered both Q1 & Q2 correctly = 20.
ANSWER:D
Answer: (D) 20
Question: Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/7 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent?
(A) 11/30
(B) 29/42
(C) 17/30
(D) 19/30
(E) 11/15
Rationale: Let s assume the platinum card spending limit =x
Gold card spending limit will be =x/2
balance on gold card is =x/2*1/3=x/6
Platinum card unspent limit is= x-1/7x=6/7x
So if gold card balance is transferred then the rest unspent will be
6/7x-x/6=29/42x
So the ans is B
Answer: (B) 29/42
Question: Tom and Jerry are running on the same road towards each other. If Tom is running at a speed of 2.5 meters per second and Jerry is running 36% slower, how much time will it take them to meet if the initial distance between the two is 50 meters and Tom started running 20 seconds before Jerry did?
(A) 2 minute and 12 seconds.
(B) two minutes.
(C) 44 seconds.
(D) 20 seconds.
(E) 12 seconds.
Rationale: Tom is running alone for 20 seconds.
So he will cover a distance of 20*2.5 = 50 m in 20 seconds.
Basically, Jerry has not started yet , and Tom has covered the distance alone and met Jerry on the other side
D is the answer
Answer: (D) 20 seconds.
Question: If x is to be chosen at random from the set {1, 2, 3, 4} and y is to be chosen at random from the set {5, 6, 7}, what is the probability that xy will be even?
(A) 1/6
(B) 1/3
(C) 1/2
(D) 2/3
(E) 5/6
Rationale: In order to make even nos. by multiplication,
we should have even * odd, odd * even or even * even
Total even nos. possible by multiplying nos. from the 2 sets:
(1*6);
2* any of the three from Set B;
3*6;&
4* any of the three from set B
1+3+1+3=8
Total possibilities=4 * 3=12
P(event)=8/12 or 2/3
Ans D
Answer: (D) 2/3
Question: If a man buys 25 lollipops for $100 and sold them for $3 dollars determine his loss.
(A) $ 50
(B) $ 35
(C) $ 52
(D) $ 60
(E) $ 25
Rationale: Cost of 25 lollipops = $90
Sold each lollipop for $3
So he sold 25 lollipops for $(25 × 3) = $75
Loss = $(100 – 75) = $25
Therefore, loss = $ 25.
Answer:E
Answer: (E) $ 25
Question: 4242 × 9999 = ?
(A) 42415758
(B) 42415751
(C) 42415752
(D) 42415753
(E) 42415754
Rationale: A
42415758
4242 × 9999 = 4242 × (10000 - 1)
= 4242 × 10000 - 4242 × 1
= 42420000 - 4242
= 42415758
Answer: (A) 42415758
Question: The number of livestock in a farm at the beginning of year 2000 was 120,000. During the year, the number increased by p%. During the next year 2001, there was a famine and the number decreased by q%. A census at the end of year 2001 revealed that the number of livestock in the farm was 120,000. Which of the following expressions is correct?
(A) p = q
(B) q > p
(C) p > q
(D) With the exception of 1 instance, p will be equal to q
(E) There is no relation between p and q
Rationale: Number plugging in will be best strategy for this question.
Let p = 5%,
Per the question 100000(1.05)(1-q/100) = 100000 ---> q = 4.7%. Thus p > q and hence C is the correct answer.
Answer: (C) p > q
Question: A fellow borrowed a certain sum of money at 5% per annum at simple interest and in 5 years the interest amounted to Rs.750 less than the sum lent. What was the sum lent?
(A) 1000
(B) 1220
(C) 1250
(D) 1060
(E) 1110
Rationale: P - 750 = (P*5*5)/100
P = 1000
Answer: A
Answer: (A) 1000
Question: Find the value of 3.5 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)]
(A) 800
(B) 500
(C) 2800
(D) 1600
(E) None
Rationale: Answer
3.5 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)]
= 3.5 x [(36 x 48 x 250) / (12 x 9 x 5)]
= 3.5 x 4 x 4 x 50 = 2800
Correct Option: C
Answer: (C) 2800