mathewhe/aqua_rat huggingface dataset:
Question: A person takes 5 hrs 45 min in walking to a place and riding back. He would have gained 1 hour by riding both ways. The time he would take to walk both ways is?
(A) 5 hours 45 min
(B) 5 hours 55 min
(C) 6 hours 45 min
(D) 7 hours 45 min
(E) 8 hours
Rationale: ----------------------------------------------------------------
Solution 1
----------------------------------------------------------------
Given that time taken for riding both ways will be 1 hours lesser than
the time needed for waking one way and riding back
From this, we can understand that
time needed for riding one way = time needed for waking one way - 1 hours
Given that time taken in walking one way and riding back = 5 hours 45 min
Hence The time he would take to walk both ways = 5 hours 45 min + 1 hours = 6 hours 45 min
C
Answer: (C) 6 hours 45 min
Question: if p is a positive integer greater than 8, which of the following must be divisible by 4?
(A)  p(p-1)(p+2)(p+3)
(B)  p(p-1)(p+3)(p+4)
(C)  p(p-3)(p+2)(p+4)
(D)  p(p-3)(p+2)(p+3)
(E)  p(p+1)(p+3)(p+4)
Rationale: D.
For any integer p, D is the only answer choice which will always be divisible by 4.
A product of 4 consecutive integers will always be divisible by 4. Since, none of the answer choices are a product of 4 consecutive integers, we have to ensure at least one of the integers is always a multiple of 4. The best way to do that is to ensure the answer choice isp* [(p-1)OR(p+3)] * [(p-2)OR(p+2)] * [(p-3)OR(p+1)]. (answer D)
Answer: (D)  p(p-3)(p+2)(p+3)
Question: Sum of the numbers from 1 to 25 is
(A) 210
(B) 325
(C) 320
(D) 105
(E) None of these
Rationale: Explanation: Sum of first n natural numbers = 1 + 2 + 3 + ..... n = n(n+1)/2
Substitute n = 25.
So S20=25Ã—26/2=325
Correct Option: B
Answer: (B) 325
Question: Set S consists of integers {2,3,4,5}. If two numbers are chosen from set S at random, what is the probability that the product of 2 numbers is more than 10?
(A) 1/2
(B) 1/4
(C) 2/5
(D) 3/7
(E) 1/6
Rationale: Number of ways you can choose 2 from 4 = 4C2 = 6
E = event of getting the 2 numbers product is more than 10 = (3,4),(3,5),(4,5) = 3
probability = 3/6 = 1/2
Answer is A
Answer: (A) 1/2
Question: A boat sails 15 km of a river towards upstream in 5 hours. How long will it take to cover the same distance downstream, if the speed of current is one-fourth the speed of the boat in still water:
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: Explanation:
Upstream speed = B-S
Downstream speed = B+s
B-S = 15/5 = 3 km/h
Again B= 4S
Therefore B-S = 3= 3S
=> S = 1 and B= 4 km/h
Therefore B+S = 5km/h
Therefore, Time during downstream = 15/5 = 3h
Answer: B) 3h
Answer: (B) 3
Question: Express of the following as a fraction:
44%
(A) 11/25
(B) 13/25
(C) 11/25
(D) 17/25
(E) None of them
Rationale: 44% = 44/100= 11/25.
Answer is A.
Answer: (A) 11/25
Question: What is the probability of getting a sum 9 from two throws of a dice?
(A) 1/9
(B) 1
(C) 2/9
(D) 2
(E) 2/3
Rationale: In two throws of a dice, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
P(E) = n(E)/n(S) = 4/36	= 1/9
Hence answer is A
Answer: (A) 1/9
Question: How many multiples of 4 are there between 12 and 92, inclusive?
(A) 21
(B) 22
(C) 23
(D) 24
(E) 25
Rationale: The multiples of 4 are from 4*3 up to 4*23.
23-3+1 = 21.
The answer is A.
Answer: (A) 21
Question: A train passes a station platform in 45 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
(A) 177 m
(B) 375 m
(C) 240 m
(D) 187 m
(E) 186 m
Rationale: Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 45 = 15
x + 300 = 675
x = 375 m.
Answer: B
Answer: (B) 375 m
Question: A mailman puts .05% of letters in the wrong mailbox. How many deliveries must he make to misdeliver 2 items?
(A) 4000
(B) 400
(C) 40
(D) 40000
(E) 4500
Rationale: Let the number of total deliveries be x
Then, .05% of x=2
(5/100)*(1/100)*x=2
x=4000
Answer is A
Answer: (A) 4000
Question: The probability of a lottery ticket being a prized ticket is 0.2. When 4 tickets are purchased, the probability of winning a prize on atleast one ticket is?
(A) 0.5908
(B) 0.5904
(C) 0.5901
(D) 0.5916
(E) 0.5925
Rationale: P(winning prize atleast on one ticket)
= 1 - P("Losing on all tickets")
= 1 - (0.8)4 = (1 + (0.8)2)(1 - (0.8)2)
= (1.64)(0.36) = 0.5904
Answer:B
Answer: (B) 0.5904
Question: In Company A, the total monthly payroll for the 12 factory workers is $18,000 and the total monthly payroll for the 40 office workers is $100,000. By how much does the average (arithmetic mean) monthly salary of an office worker exceed that of a factory worker in this company?
(A) $600
(B) $700
(C) $800
(D) $900
(E) $1000
Rationale: The average monthly salary of a factory worker is: $18,000 / 12 = $1500.
The average monthly salary of an office worker is: $100,000 / 40 = $2500.
The difference in average salary is: $2500 - $1500 = $1000.
The answer is E.
Answer: (E) $1000
Question: What is the place value of 4 in the numeral 57468?
(A) 400
(B) 40
(C) 4000
(D) 4
(E) 46
Rationale: place value of 4 = 4 * 100 = 400
Answer is A
Answer: (A) 400
Question: How many different subset of the set {I, II, III, IV, V, VI, VII, VIII, IX) do not contain V.
(A) 273
(B) 282
(C) 285
(D) 283
(E) 281
Rationale: This is a combination solution
Since we have 8 different Roman Numerals other than the V we can take any Roman numeral from the set of 8 to make a subset.
8C1 +8C2 + 8C3 + 8C4 + 8C5 + 8C6 + 8C7 + 8 C8 = 282
Plus the one set that is null that is the Set having no element in it which is 8C0 =1
= 282 + 1 = 16
D = 283
Answer: (D) 283
Question: Java House charges $4.25 for a cup of coffee that costs a total of $3.85 to make. Cup'O'Joe charges $4.80 for a cup that costs $4.65 to make. If Java House sells 55,000 cups of coffee, how many must Cup'O'Joe sell to make at least as much in total gross profit as its competitor does?
(A) 7,858
(B) 8,301
(C) 14,667
(D) 63,840
(E) 146,667
Rationale: Java: Profit/Cup = 4.25-3.85 = 0.4
: No of Cups = 55,000
: Gross Profit = 55,000*0.4 = 22,000
Joe: Profit/Cup = 0.15
: Gross Profit = 22,000
: No of Cups = 22,000/0.15 = 220,000/1.5 (only closes is 146,667)
Answer E
Answer: (E) 146,667
Question: In a forest 160 deer were caught, tagged with electronic markers, then released. A week later, 50 deer were captured in the same forest. Of these 50 deer, it was found that 5 had been tagged with the electronic markers. If the percentage of tagged deer in the second sample approximates the percentage of tagged deer in the forest, and if no deer had either left or entered the forest over the preceding week, what is the approximate number of deer in the forest?
(A) 150
(B) 750
(C) 1,250
(D) 1,600
(E) 2,500
Rationale: The percentage of tagged deer in the second sample = 5/50*100=10%.
So, 160 tagged deers comprise 10% of total # of deers --> total # of deers = 160*10 = 1,600.
Answer: D.
Answer: (D) 1,600
Question: If each term in the sum T=a1+a2+a3+...+an either 2 or 22 and the sum equals 100, which of the following could be equal to n?
(A) 38
(B) 39
(C) 40
(D) 41
(E) 42
Rationale: Min value of 'n' can be 10 i.e 4*22+6*12=T => 22+22+22+22+2+2+2+2+2+2 = 100
Since we don't have 10 in the options proceed further, (10-1)+22/2 => 20 digits, which is again not in the options
(20-1) + 22/2 = 30 digits ( not in options)
(30-1) + 22/2 = 40 digits
Hence C.
Answer: (C) 40
Question: When x + p is divided by p - 2, the quotient is n and there is no remainder. Which of the following must be the value of x?
(A) n(p +1)
(B) n(p − 1)
(C) p(n + 1) + 2n
(D) p(n - 1) + 2n
(E) n(p + 1) (p − 1)
Rationale: Given in question (x+p)/p-2= n
=> x+p= n(p-2)
=>x= np+2n-p
or x= np-p+2n
Now we are good to check the options
x= p(n-1) + 2n
Answer D
Answer: (D) p(n - 1) + 2n
Question: Indu gave Bindu Rs.2500 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: 2500 = D(100/4)2
D = 4
Answer: D
Answer: (D) 4
Question: What was the day of the week on, 16th July, 1776?
(A) Tuesday
(B) Wednesday
(C) Monday
(D) Saturday
(E) SUNDAY
Rationale: 16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776)
Counting of odd days :
1600 years have 0 odd day.
100 years have 5 odd days.
75 years = (18 leap years + 57 ordinary years) = [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days.
1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day.
Jan Feb Mar Apr May Jun Jul
31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 2 days)
Total number of odd days = (0 + 2) = 2.
Required day was 'Tuesday'.
Answer:A
Answer: (A) Tuesday
Question: A horse is tethered to one corner of a rectangular grassy field 45 m by 25 m with a rope 22 m long. Over how much area of the field can it graze?
(A) 354 cm2
(B) 380 m2
(C) 350 m2
(D) 407 m2
(E) None of these
Rationale: Area of the shaded portion
= 1⁄4 × π × (22)2 = 380 m2
Answer B
Answer: (B) 380 m2
Question: A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
(A) 20 hrs
(B) 25 hrs
(C) 35 hrs
(D) Cannot be determined
(E) None of these
Rationale: Suppose pipe A alone takes x hours to fill the tank.
Then, pipes B and C will take x/2 and x/4 hours respectively to fill the tank.
1/x + 2/x + 4/x = 1/5
7/x = 1/5 => x = 35 hrs.
ANSWER:C
Answer: (C) 35 hrs
Question: If 0 < a < b < c < 1 , which of the following are positive?
I.	b-c
II.	a-b
III.	c-a
(A) I only
(B) II only
(C) III only
(D) I and II
(E) I and III
Rationale: We could solve this easily using examples.
I is false since b<c and both are positive
II is false since b<c and both are positive
III is true since c>a and both are positive
So, the answer is C.
Answer: (C) III only
Question: Evaluate combination
100C97=100!/(97)!(3)!
(A) 161700
(B) 151700
(C) 141700
(D) 131700
(E) None of these
Rationale: Explanation:
nCr=n!/(r)!(n−r)!
100C97=100!/(97)!(3)!
=100∗99∗98∗97!/(97)!(3)!
=100∗99∗98/3∗2∗1
=100∗99∗98/3∗2∗1=161700
Option A
Answer: (A) 161700
Question: Find the area of trapezium whose parallel sides are 26 cm and 18 cm long, and the distance between them is 15 cm.
(A) 227
(B) 299
(C) 330
(D) 161
(E) 212
Rationale: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (26 + 18) * (15)
= 330 cm2
Answer: C
Answer: (C) 330
Question: X and Y started a business by investing Rs.36000 and Rs.42000 respectively after 4 months Z joined in the business with an investment of Rs.48000, then find share of Z in the profit of Rs.14080 ?
(A) 3200
(B) 4000
(C) 3250
(D) 3825
(E) 4096
Rationale: Ratio of investment, as investments is for different time.
Investment x Number of units of time.
Ratio of investments X : Y : Z = 36000 : 42000 : 48000 => 6 : 7 : 8.
X = 6 x 12 Months = 72, Y = 7 x 12 = 84, Z = 8 X 8 = 64 => 18 : 21 : 16.
Ratio of investments => X : Y : Z = 18 : 21 : 16.
Investment Ratio = Profit sharing Ratio.
Z = 14080 Ã— 16/55 = Rs.4096.
Share of Z in the profit is Rs.4096.
Option E
Answer: (E) 4096
Question: Two persons start running simultaneously around a circular track of length 300 m from the same point at speeds of 15 km/hr and 25 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions?
(A) 16 seconds
(B) 18 seconds
(C) 19 seconds
(D) 27 seconds
(E) 10 seconds
Rationale: Time taken to meet for the first time anywhere on the track
= length of the track / relative speed
= 300 / (15 + 25)5/18 = 300* 18 / 40 * 5
= 27 seconds.
Answer:D
Answer: (D) 27 seconds
Question: If the manufacturer gains 10 %, the wholesale dealer 15 % and the retailer 25 %, then find the cost of production of a table if the retail price was Rs 1265
(A) Rs. 750
(B) Rs. 800
(C) Rs. 850
(D) Rs. 900
(E) None of these
Rationale: Explanation:
Let the cost of Production = Rs. P
Then, as per question,
=>(125/100∗115/100∗110/100∗P)=1265
=>253/160P=1265
=>P=800
Option B
Answer: (B) Rs. 800
Question: The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 60 metres?
(A) 12
(B) 16
(C) 17
(D) 19
(E) 10
Rationale: Speed of the boat downstream = 15 + 3 = 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 60 m = 60/5 = 12 seconds.
Answer: A
Answer: (A) 12
Question: A meeting has to be conducted with 5 managers.Find the number of ways in which the managers may be selected from among 8 managers,if 2 managers will not attend the meeting together.
(A) 1.35
(B) 2.91
(C) 3.12
(D) 4.36
(E) 5.15
Rationale: 8 managers, but two of them cannot attend the meeting together.
We can split it into two cases.
1. Meeting without these two managers in it. That would mean selecting 5, from the remaining 6 which is 6C5 = 6
2. Meeting with one of the two managers. select 1 manager from two, and then select 4 from the remaining 6, which is 2C1 X 6C4 = 15.
So, answer is 30 + 6 = 36.
Answer : D
Answer: (D) 4.36
Question: If 0.25 of a number is equal to 0.05 of another number, the ratio of the numbers is :
(A) 2 : 5
(B) 3 : 4
(C) 1 : 5
(D) 20 : 5
(E) 30:7
Rationale: 0.25A = 0.05B
-> A/B = 0.05/0.25 = 5/25 = 1/5
:. A : B = 1 : 5
ANSWER:C
Answer: (C) 1 : 5
Question: The average weight of A,B,C is 45 Kg. The avgwgt of A & B be 40Kg & that of B,C be 43Kg. Find the wgt of B.
(A) 23
(B) 43
(C) 21
(D) 31
(E) 43
Rationale: Sol. Let A,B,c represent their individual wgts.
Then,
A+B+C=(45*3)Kg=135Kg
A+B=(40*2)Kg=80Kg & B+C=(43*2)Kg=86Kg
B=(A+B)+(B+C)-(A+B+C)
=(80+86-135)Kg
=31Kg.
ANSWER D
Answer: (D) 31
Question: A family made a down payment of $20
and borrowed the balance on a set of
encyclopedias that cost $120. The
balance with interest was paid in 7
monthly payments of $15.2 each and a
final payment of $7. The amount of
interest paid was what percent of the
amount borrowed?
(A)  6%
(B)  12%
(C)  13.4%
(D)  16%
(E)  20%
Rationale: interest paid = 15.2*7+7 - 100 = 13.4
% off the balance = (13.4/100) * 100 = 13.4 %
Answer is C.
Answer: (C)  13.4%
Question: If x^2 = 161, which of the following is closest to a potential value of x?
(A) -127
(B) -11
(C) 12
(D) 13
(E) 131
Rationale: Here the thing we must not forget is that X^even has two potential solutions
=> x =+- √161 => +- 13 (approx)
this value is closer to 13
Hence D is correct.
Answer: (D) 13
Question: What least number should be subtracted from 1398 so that the remainder when divided by 7, 9, and 11 will leave in each case the same remainder 5 ?
(A) 6
(B) 7
(C) 8
(D) 10
(E) 11
Rationale: The LCM of 7, 9, and 11 is 693. The next multiple is 2*693 = 1386.
1386 + {remainder} = 1386 + 5 = 1391, which is 7 less than 1398.
Answer: B.
Answer: (B) 7
Question: If 1 + 9 + 11 = 1, Then what is the value of
12 + 11 + 9 = ?
(A) 12
(B) 7
(C) 11
(D) 9
(E) 10
Rationale: E
Explanation:
Equation 1 + 9 + 11 = 1 can be derived from
One (o) + nine (n) + eleven (e) = one => 1
Similarly for equation,
12 + 11 + 9
Twelve (t) + eleven (e) + nine (n) => ten (10)
Answer: (E) 10
Question: If 90% of A =30% of B and B=x% of A, then the value of x is?
(A) 800
(B) 300
(C) 700
(D) 400
(E) None of these
Rationale: 0.9 A= 0.3 B
so b=3A means 300% of A
ANSWER:B
Answer: (B) 300
Question: During the first two weeks of May, the total rainfall in Springdale was 35 inches. If the rainfall during the second week was 1.5 times the rainfall during the first week, what was the rainfall in inches during the second week of May?
(A) 12
(B) 15
(C) 18
(D) 21
(E) 24
Rationale: Let x be the rainfall in the first week. Then 1.5x was the rainfall in the second week.
2.5x = 35
x = 14
The rainfall during the second week was 1.5 * 14 = 21 inches
The answer is D.
Answer: (D) 21
Question: An athlete runs 200 metres race in 25 seconds. What is his speed?
(A) 23
(B) 38
(C) 37
(D) 30
(E) 28.8
Rationale: Speed=Distance/Time = 200/25 = 8 m/s = 8 * 18/5 = 28.8 km/hr
Answer :E
Answer: (E) 28.8
Question: If 5 machines can produce 20 units in 10 hours, how long would it take 25 to produce 100 units?
(A) 5
(B) 9
(C) 6
(D) 10
(E) 2
Rationale: 5 machines would produce 100 units in 50 hours. Increasing the amount of machines by 5 would mean dividing 50 hours by 5.
50/5 = 10
Answer : D
Answer: (D) 10
Question: A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work?
(A) 22
(B) 88
(C) 27
(D) 14
(E) 99
Rationale: Let A worked for x days.
x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18
A worked for 18 days. So, A can complete the remaining work in 18 - 4 = 14 days.
Answer: D
Answer: (D) 14
Question: Four milkmen rented a pasture. A grazed 24 cows for 3 months; B 10 for 5 months; C 35 cows for 4 months and D 21 cows for 3 months. If A's share of rent is Rs. 1440, find the total rent of the field.
(A) 6500
(B) 3550
(C) 4250
(D) 2250
(E) 3250
Rationale: Ratio of shares of A, B, C, D = (24 x 3) : (10 x 5) : (35 x 4) : (21 x 3) = 72 : 50 : 140 : 63.
Let total rent be Rs. x. Then, A’s share = Rs. (72x)/325
(72x)/325=1440 = x=(1440 x 325)/72 = 6500
Hence, total rent of the field is Rs. 6500.
Answer is A.
Answer: (A) 6500
Question: Which of the following is equal to (x+2)!/x!?
(A) x-1
(B) 1+(1/x)
(C) 1
(D) x+1
(E) (x+1)(x+2)
Rationale: (x + 1)! = (x + 1) (x+2)* x!
(x + 1)!/x! = (x + 1)(x+2)
Answer: E
Answer: (E) (x+1)(x+2)
Question: A can do a job in 8 days and B can do it in 20 days. A and B working together will finish twice the amount of work in ------- days?
(A) 21 ½ days
(B) 11 3/7 days
(C) 23 ½ days
(D) 12 ½ days
(E) None of these
Rationale: Explanation:
1/8 + 1/20 = 7/40
40/7 = 40/7 *2 = 11 3/7 days
Answer: B
Answer: (B) 11 3/7 days
Question: A man purchases 8 pens for Rs.9 and sells 9 pens for Rs.8, how much profit or loss does he make?
(A) 11
(B) 99
(C) 28
(D) 20
(E) 87
Rationale: In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages.
Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr.
stoppage time = 20/60 hrs = 20 min.
Answer:D
Answer: (D) 20
Question: The price of 3 tables and 4 chairs is Rs. 3300. With the same money one can buy 2 tables and 10 chairs. If one wants to buy 1 table and 1 chair, how much does he need to pay?
(A) Rs.940
(B) Rs.1050
(C) Rs.1040
(D) Rs.950
(E) Rs.960
Rationale: Explanation :
Let price of a table = t
and price of a chair = c
3t + 4c = 3300 ---(Equation 1)
2t + 10c = 3300
=> t + 5c = 1650 ---(Equation 2)
(Equation 2) × 3 => 3t + 15c = 4950 ---(Equation 3)
(Equation 3) - (Equation 1) => 11c = 1650
=> c = 150
Substituting the value of c in equation 1, we get
3t + (4 × 150) = 3300
=> 3t = 3300 – 600 = 2700
=>t = 2700/3 = 900
Cost of 1 table and 1 chair = c + t = 150 + 900 = 1050
Answer : B
Answer: (B) Rs.1050
Question: All the stocks on the over-the-counter market are designated by either a 6 letter or 5 letter codes that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be designated with these codes?
(A) 2(26^5)
(B) 26(26^4)
(C) 27(26^6)
(D) 26(26^5)
(E) 27(26^5)
Rationale: with 4 letters: 26^6
with 5 letters: 26^5
26^6 + 26^5 = 27*(26^5)
C
Answer: (C) 27(26^6)
Question: If (10^86) – 23 is written as a base 10 integer, which of the following options is the sum of the digits in that integer?
(A) 780
(B) 775
(C) 790
(D) 730
(E) 770
Rationale: We know that (10^86) is ending 00, so (10^86) – 23=9....9977
total number of digits in (10^86) – 23 is 86, or 84 digits of 9 and two digits 7 and 7.
answer choice is 84*9+14=770
Answer is E 770
Answer: (E) 770
Question: On dividing 109 by a number, the quotient is 9 and the remainder is 1. Find the divisor.
(A) 12
(B) 14
(C) 16
(D) 18
(E) 22
Rationale: d = (D-R)/Q
= (109 - 1)/9
= 108/9 = 12
A)
Answer: (A) 12
Question: m and n are the x and y coordinates, respectively, of a point in the coordinate plane. If the points (m, n) and (m + p, n + 21) both lie on the line defined by the equation x = (y/7) - (2/5), what is the value of p?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: x = (y/7) - (2/5), and so y = 7x + 14/5. The slope is 7.
(n+21-n) / (m+p-m) = 7
p = 3
The answer is C.
Answer: (C) 3
Question: Length of a rectangular plot is 20 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
(A) 45 m
(B) 60 m
(C) 56 m
(D) 67 m
(E) 70 m
Rationale: Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m
B
Answer: (B) 60 m
Question: A student was asked to find 4/5 of a number. But the student divided the number by 4/5, thus the student got 36 more than the correct answer. Find the number.
(A) 60
(B) 70
(C) 80
(D) 90
(E) 100
Rationale: Let the number be x.
(5/4) * x = (4/5)*x + 36
25x = 16x + 720
9x = 720
x = 80
The answer is C.
Answer: (C) 80
Question: Every year an amount increases by 1/6th of itself. How much will it be after two years if its present value is Rs.64000?
(A) 87111
(B) 81007
(C) 81008
(D) 81066
(E) 81022
Rationale: 64000* 7/6 * 7/6 = 87111
Answer:A
Answer: (A) 87111
Question: Find the missing number: ? - 1936248 = 1635773
(A) 3572021
(B) 3572012
(C) 3770221
(D) 3570221
(E) None of them
Rationale: Let x - 1936248=1635773.
Then, x = 1635773 + 1936248
=3572021.
Answer is B.
Answer: (B) 3572012
Question: The perimeter of one square is 40 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?
(A) 11.2√2
(B) 13√2
(C) 23√2
(D) 12√4
(E) 13√9
Rationale: 4a = 40 4a = 20
a = 10 a = 5
a2 = 100 a2 = 25
Combined area = a2 = 125 => a = 11.2
d = 11.2√2
Answer: A
Answer: (A) 11.2√2
Question: If john makes a contribution to a charity fund at school, the average contribution size will increase by 50% reaching $75 per person. If there were 2 other contributions made before john's, what is the size of his donation?
(A) $125
(B) $150
(C) $200
(D) $250
(E) $450
Rationale: Cavg = average contribution before John
Cavg*1.5 = 75, therefore the average cont is $50 before John.
If he needs to increase the average contribution by $25, he must put in $25 for each of the 2 people.
so $50.
But, he also has to put in the average for himself (the threeth person), so add $75.
So $125 is your answer.
Answer A
Answer: (A) $125
Question: If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area ?
(A) 108 sq.cm
(B) 112 sq.cm
(C) 116 sq.cm
(D) 120 sq.cm
(E) 130 sq.cm
Rationale: Explanation:
The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle =1/2 x base x height => 1/2 x 24 x 10 = 120 sq.cm
ANSWER IS D
Answer: (D) 120 sq.cm
Question: P sells an article to Q at 10 % profit. Q sells it to R at 25 % profit. If R pays Rs. 250 for it, What did P pay for it ?
(A) Rs. 181.81
(B) Rs. 181.88
(C) Rs. 181.82
(D) Rs. 181.89
(E) Rs. 181.812
Rationale: Explanation:
Selling price of P = Cost price of Q
Selling Price of Q = Cost price of R = Rs. 250 ….. Given
Q sold it to R with 25 % profit.
Cost price of Q = 100/125 * 250/1 = Rs. 200 = Selling price of P.
P sold it to Q with 10 % profit.
Cost price of P = 100 / 110 * 200 / 1 = Rs. 181.81
ANSWER: A
Answer: (A) Rs. 181.81
Question: If 4 women can color 48 m long cloth in 2 days, then 6 women can color 36 m long cloth in
(A) 2 days
(B) 3 days
(C) 1 day
(D) 4 days
(E) 5 days
Rationale: The length of cloth painted by one woman in one day = 48 / 4 × 2 = 6 m
No. of days required to paint 36 m cloth by 6 women = 36/ 6 × 6 = 1 day.
C
Answer: (C) 1 day