mathewhe/aqua_rat huggingface dataset:
Question: A sports equipment store sold ping pong rackets for a total of $490. If the average (arithmetic mean) price of a pair of rackets is $9.8, how many pairs were sold?
(A) 50
(B) 100
(C) 490
(D) 500
(E) 980
Rationale: Average price for a pair of rackets = $9.8
Total cost = $9.8*x = $490
x = 50 pairs were sold.
ANSWER:A
Answer: (A) 50
Question: How many seconds will a 300 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
(A) 12 sec
(B) 30 sec
(C) 86 sec
(D) 15 sec
(E) 18 sec
Rationale: Speed of train relative to man = 63 - 3
= 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 300 * 3/50
= 18 sec.
Answer: E
Answer: (E) 18 sec
Question: By walking at 4/5 of his usual speed, Mohan is 6 minute late to his office. find his usual time to cover the distance.
(A) 25 minutes
(B) 23 minutes
(C) 24 minute
(D) 26 minute
(E) None of these
Rationale: Here, Change in time = 6 and a/b = 4/5
We have, change in time = (b/a - 1) x original time
=> Original time = Change in time/(b/a - 1)
=>6(5/4 - 1) = 24 minute.
ANSWER:C
Answer: (C) 24 minute
Question: A farm has only chickens and pigs. When the manager of the farm counted the heads of the animals on the farm, the number totaled up to 50. When the number of legs was counted, the number totaled up to 120. How many more chickens than pigs are there on the farm? Note: Each pig has 4 legs and each chicken had 2 legs.
(A) 30
(B) 32
(C) 34
(D) 36
(E) 38
Rationale: Let x be the number of chickens.
Then 50-x is the number of pigs.
2x+4(50-x)=120
2x=80
x=40 (chickens)
50-x=10 (pigs)
There are 40-10=30 more chickens on the farm.
The answer is A.
Answer: (A) 30
Question: If the operation ∆ is defined by a ∆ b = (b - a)^2/a^2 for all numbers a and b, and a ≠ 0, then what is the result when we evaluate this expression: (-5) ∆ (5 ∆ −5) ?
(A) 49/9
(B) 49/16
(C) 81/16
(D) 81/25
(E) 100/81
Rationale: (-5) ∆ (5 ∆ −5) =
(-5) ∆ (10^2/5^2) =
(-5) ∆ (4) =
(-9^2) / (-5)^2 = 81/25
The answer is D.
Answer: (D) 81/25
Question: A bag marked at $150 is sold for $120. The rate of discount is?
(A) 10%
(B) 25%
(C) 20%
(D) 50%
(E) 45%
Rationale: Rate of discount = 30/150 * 100 = 20%
Answer is C
Answer: (C) 20%
Question: Arabica coffee costs $0.5 per ounce while Robusta coffee costs $0.4 per ounce. If the blend of Arabica and Robusta costs $0.44 per ounce, what is the share of Arabica in this blend?
(A) 20%
(B) 24%
(C) 30%
(D) 33%
(E) 40%
Rationale: a= amount of arabica coffee
1-a = amount of robusta coffee. because if you subtract a from the 1 ounce, the remaining amount is robusta
therefore:
.5a + .4(1-a) = .44
.5a + .4 - .4a = .44
a= .4
therefore: .4/1 ounce = 40%. Therefore, the answer should be E
Answer: (E) 40%
Question: A family consists of grandparents, parents and three grandchildren. The average age of the grandparents is 67 years, that of the parents is 35 years and that of the grandchildren is 6 years. What is the average age of the family ?
(A) 31( 5/7)
(B) 31( 5/9)
(C) 31( 5/2)
(D) 31( 4/7)
(E) 41( 5/7)
Rationale: Required average = (67 * 2 + 35 * 2 + 6 * 3) / (2 + 2 + 3)
= (134 + 70 + 18) / 7 = 222 / 7
= 31(5/7) years.
Answer: A
Answer: (A) 31( 5/7)
Question: Simplify:12345679 x 72
(A) 888888888
(B) 888888881
(C) 888888887
(D) 888888886
(E) 888888885
Rationale: 12345679 x 72	= 12345679 x (70 +2)
= 12345679 x 70 + 12345679 x 2
= 864197530 + 24691358
= 888888888
Answer is A
Answer: (A) 888888888
Question: A man is walking at a speed of 10 km per hour. After every kilometre, he takes rest for 7 minutes. How much time will be take to cover a distance of 7 kilometres?
(A) 80 min.
(B) 70 min.
(C) 84 min.
(D) 55 min.
(E) None of these
Rationale: Rest time = Number of rest Ã— Time for each rest
= 6 Ã— 7 = 42 minutes
Total time to cover 7 km
= (7â„10 Ã— 60)minutes + 42 minutes = 84 minutes
Answer C
Answer: (C) 84 min.
Question: The first year, two cows produced 8100 litres of milk. The second year their production increased by 15% and 10% respectively, and the total amount of milk increased to 9100 litres a year. How many litres were milked from one cow?
(A) 2178 lt
(B) 3697 lt
(C) 6583 lt
(D) 4370 lt
(E) 5548 lt
Rationale: Let x be the amount of milk the first cow produced during the first year. Then the second cow produced (8100−x) litres of milk that year. The second year, each cow produced the same amount of milk as they did the first year plus the increase of 15%15% or 10%
So 8100+15100⋅x+10100⋅(8100−x)=9100
Therefore 8100+320x+110(8100−x)=9100
120x=190
x=3800
Therefore, the cows produced 3800 and 4300 litres of milk the first year, and 4370 and 4730 litres of milk the second year, => one cow produced 4370 litres
correct answer is D)4370 lt
Answer: (D) 4370 lt
Question: Three consecutive odd integers are in increasing order such that the sum of the last two integers is 13 more than the first integer. Find the three integers?
(A) 9, 11, 13
(B) 11, 13, 15
(C) 13, 15, 17
(D) 7, 9, 11
(E) None of these
Rationale: Let the three consecutive odd integers be x, x + 2 and x + 4 respectively.
x + 4 + x + 2 = x + 13 => x = 7
Hence three consecutive odd integers are 7, 9 and 11.
ANSWER:D
Answer: (D) 7, 9, 11
Question: Suzie’s Discount Footwear sells all pairs of shoes for one price and all pairs of boots for another price. On Monday the store sold 22 pairs of shoes and 16 pairs of boots for $508. On Tuesday the store sold 8 pairs of shoes and 32 pairs of boots for $656. How much more do pairs of boots cost than pairs of shoes at Suzie’s Discount Footwear?
(A) 10
(B) 12
(C) 14
(D) 16
(E) 8
Rationale: Let X be pair of shoes and Y be pair of boots.
22x+16y = 508 ... eq1
8x +32y = 656....eq 2.
Now multiply eq 1 by 2 and sub eq 2.
44x =1016
8x = 656.
36x = 360 => x = 10.
Sub x in eq 2.... we get 80 + 32y = 656... then we get 32y = 576 then y = 18
Differenece between X and Y is 8
Answer : E
Answer: (E) 8
Question: If A speaks the truth 80% of the times, B speaks the truth 60% of the times. What is the probability that at least one will tell the truth
(A) 0.8
(B) 0.92
(C) 1.02
(D) 1.2
(E) 1.3
Rationale: probability of A speaks truth p(A)=8/10;false=2/10
probability of B speaks truth p(B)=6/10;false=4/10.For given qtn
Ans=1-(neither of them tell truth).Because A & B are independent events
=1-[(2/10)*(4/10)]=1-8/10=1-0.08=0.92
ANSWER:B
Answer: (B) 0.92
Question: A certain sum of money doubles itself in 10 years in how much many years will it trible itself at the same rate?
(A) 20 years
(B) 76 years
(C) 88 years
(D) 44 years
(E) 11 years
Rationale: 100 ---- 100 --- 10
100 --- 10
--------------------
300 ---- 20 years
Answer: A
Answer: (A) 20 years
Question: if deepak has 5 pants and 3 shirts how many combinations can deepak make?
(A) 10
(B) 9
(C) 15
(D) 20
(E) 25
Rationale: If deepak can only choose one of each, there are 5*3 = 15 possible combinations.
Answer:C
Answer: (C) 15
Question: How many possible ways can 1 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?
(A)  3
(B)  4
(C)  5
(D)  6
(E)  8
Rationale: Any one girl can go with 3 boys.
3 (A) is the answer
Answer: (A)  3
Question: A painter intends to mixed two jars of paint to create a new color. He chooses one paint jar randomly from a display containing 3 red and 2 blue samples, and a second jar is chosen at random from a different display containing 3 red and 2 blue samples. If he plans on mixing the two chosen jars together, what is the probability that when mixed together, the result will be purple paint? (The color purple is created with 1 part red and 1 part blue.)
(A) 1/5
(B) 1/2
(C) 2/3
(D) 4/5
(E) 6/5
Rationale: Painter has two buckets he has to randomly pick from 2 different lists ... Let these Lists be A and B ... He has to choose the first bucket from List A , and the second bucket from List B
FOR THE FIRST BUCKET ...
Red color - 2
Blue color - 2
FOR THE SECOND BUCKET
Red color - 3
Blue color -2
In order to get Purple he has to mix red with blue .. Both the LISTS contain either blue or red , therefore we have two scenarios :
Scenario I - He picks Red color from List A and Blue color from List B
Scenario II - He picks Blue color from List A and Red color from List B
Scenario I - Odds for red color from List A are 1/2 .. and for Blue color from List B are 2 /5 .. Multiplying them (because we have to find the odds that both colors are selected from their respective lists together (this is a AND not an OR problem) we get 1/5
Scenario II - Odds for blue color from List A are 1/2 , and for Red color from List B are 3/5 ... Multiplying them we get 3/10 ...
Both the scenarios are equally possible therefore we must ADD the two (not multiply ) because both of them do not have to hold true together (have to independently) for our desired result to be achieved ...
We get 1/5 + 3/10 = 2/3 (C)
Answer: (C) 2/3
Question: The average weight of a class of 20 boys was calculated to be 58.4 kgs and it was later found that one weight was misread as 56 kg instead of 66 kg. What is the correct weight?
(A) 58kgs
(B) 58.85kgs
(C) 58.9kgs
(D) 59kgs
(E) 59.85kgs
Rationale: Actual total weight is (20X 58.4 - 56 + 66) = 1178 Kgs
Actual average weight is 1178/20 = 58.9kgs
C
Answer: (C) 58.9kgs
Question: What is the value of 3x^2 − 1.8x + 0.7 for x = 0.6?
(A) −0.3
(B) 0
(C) 0.3
(D) 0.7
(E) 2.46
Rationale: 3x^2-1.8x+0.7 for x=0.6
=3(0.6*0.6)-3*0.6*(0.6)+0.7
=0+0.7
=0.7
ANSWER:D
Answer: (D) 0.7
Question: The number of timeshare condos available at Sunset Beach is 3/5 the number of timeshare condos available at Playa del Mar. If the total number of timeshare condos available at the two beaches combined is 400, what is the difference between the number of condos available at Sunset Beach and the number of condos available at Playa del Mar?
(A) 60
(B) 90
(C) 120
(D) 100
(E) 240
Rationale: Let x be the number of timeshare condos available at Playa del Mar.
Then number of timeshare condos available at Sunset Beach = 3/5x
We know, x + 3/5 x = 400
Hence, x = 250. So, number of timeshare condos available at Playa del Mar = 250
the difference between the number of condos available at Sunset Beach and the number of condos available at Playa del Mar = x - 3/5x = 2/5x = 2/5(250) = 100
The correct answer is D
Answer: (D) 100
Question: Find the next no.
82, 51, 28, 20, ?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
Rationale: 82=9^2+1
51=7^2+2
28=5^2+3
20=4^2+4
then next no is
3^2+5=14
ANSWER:E
Answer: (E) 14
Question: If a is a positive integer, then 2^a + 2^(a + 1) + 2^(a + 2)=
(A) 3^(a + 1)
(B) 2^(a + 1)
(C) 2a
(D) 2a^(a + 1)
(E) 7(2^a)
Rationale: If a is a positive integer, then 2^a + 2^(a + 1) =
2^a + 2^(a + 1)+2^(a + 2)
2^a(1+2+4)
2^a(7)
E. 7(2^a)
Answer: (E) 7(2^a)
Question: A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.600, what is the reduced price for kg?
(A) 30
(B) 60
(C) 70
(D) 80
(E) 20
Rationale: A
600*(25/100) = 150 ---- 5
? ---- 1 => Rs.30
Answer: (A) 30
Question: A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?
(A) 9, 46
(B) 9, 50
(C) 10, 46
(D) 10, 50
(E) 10, 60
Rationale: B = x
A = 3x-4
c = 6x-4
so. given A=3x-4 = 31
after 4 year A=3x = 31 -4 =27
B= x = 9
c = 6*9 -4 = 50
ANSWER:B
Answer: (B) 9, 50
Question: A fifth of Arunâ€™s marks in mathematics exceed a third of his marks in English by 20.If he got 260 marks in two subjects together how many marks did he got in English?
(A) 120,80
(B) 180,60
(C) 200,60
(D) 200,40
(E) None of them
Rationale: Let Arunâ€™s marks in mathematics and english be x and y
Then (1/5)x-(1/3)y=20
3x-5y=300â€¦â€¦>(1)
x+y=260â€¦â€¦.>(2)
solving (1) and (2)
x=200
and y=60
Answer is C.
Answer: (C) 200,60
Question: Which of the following is closest in value to (9^10)-(9^2)?
(A) 9^10
(B) 9^8
(C) 9^7
(D) 9^6
(E) 9^5
Rationale: 9^10 is much larger number than 9^2 and as we need approximate value then it's pretty much negligible in this case, so: (9^10)-(9^2) = ~9^10.
Answer: A.
Similar questions to practice:
Hope it helps.
Answer: (A) 9^10
Question: The arithmetic mean and standard deviation of a certain normal distribution are 15 and 1.5, respectively. What value is exactly 2 standard deviations less than the mean?
(A) 10.5
(B) 11
(C) 11.5
(D) 12
(E) 12.5
Rationale: The value which isexactlytwo SD less than the mean is:mean-2*SD=15-2*1.5=12.
Answer: D.
Answer: (D) 12
Question: Set A contains all the even numbers between 10 and 50 inclusive. Set B contains all the even numbers between 110 and 150 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A?
(A) 2100
(B) 2550
(C) 5050
(D) 6275
(E) 11325
Rationale: Set A contains 10, 12,14 , 16 ... 50
Set B contains 110 , 112 , 114 ... 150
Number of terms in each set = 21
Difference between corresponding terms in set A and B = 100
Difference between Sum of set B and set A = 100*21 = 2100
Answer A
Answer: (A) 2100
Question: A bag contains 6 green balls and 8 white balls. If two balls are drawn simultaneously, what is the probability that both balls are the same colour?
(A) 5/14
(B) 8/21
(C) 12/21
(D) 43/91
(E) 47/91
Rationale: The total number of ways to draw two balls is 14C2 = 91
The number of ways to draw two green balls is 6C2 = 15
The number of ways to draw two white balls is 8C2 = 28
P(two balls of the same colour) = 43/91
The answer is D.
Answer: (D) 43/91
Question: A’s speed is 20/16 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat?
(A) 1/17
(B) 3/17
(C) 1/10
(D) 4/20
(E) 3/10
Rationale: We have the ratio of A’s speed and B’s speed. This means, we know how much distance A covers compared with B in the same time.
This is what the beginning of the race will look like:
(Start) A_________B______________________________
If A covers 20 meters, B covers 16 meters in that time. So if the race is 20 meters long, when A reaches the finish line, B would be 4 meters behind him. If we want the race to end in a dead heat, we want B to be at the finish line too at the same time. This means B should get a head start of 4 meters so that he doesn’t need to cover that. In that case, the time required by A (to cover 20 meters) would be the same as the time required by B (to cover 16 meters) to reach the finish line.
So B should get a head start of 4/20th of the race.
Answer (D)
Answer: (D) 4/20
Question: What is the probability of randomly selecting one of the shortest diagonals from all the diagonals of a regular octagon?
(A) 1/4
(B) 1/3
(C) 1/2
(D) 2/5
(E) 7/8
Rationale: From any vertex, there are two vertices on sides, which do not make a diagonal but a side.
So the remaining n-3 vertices make diagonals.
There are 2 of these diagonals which are the shortest.
The probability of choosing one of the shortest diagonals is 2/5.
The answer is D.
Answer: (D) 2/5
Question: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?
(A) 223
(B) 175
(C) 297
(D) 267
(E) 911
Rationale: Explanation:
Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
{\color{Blue} \therefore } 160 x 2.40 + x x 3.20 = 432
=> 3.20x = 432 - 384 = 48
=> x = 15.
Hence, total hours of work = (160 + 15) = 175.
Answer: B) 175
Answer: (B) 175
Question: A boy has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
(A) 90
(B) 110
(C) 140
(D) 130
(E) 120
Rationale: Let number of notes of each denomination be x.
Then x + 5x + 10x = 480
16x = 480
x = 30.
Hence, total number of notes = 3x = 90.
A
Answer: (A) 90
Question: A vendor bought toffees at 6 for a rupee. How many for a rupee must he sell to gain 20%?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: C.P. of 6 toffees = Rs. 1
S.P. of 6 toffees = 120% of Rs. 1 = Rs 6/5
For Rs. 6/5 Toffees Sold 6
For Rs. 1, toffees sold = 6x (5/6)= 5
answer :C
Answer: (C) 5
Question: Find the area of the quadrilateral of one of its diagonals is 22 cm and its off sets 9 cm and 6 cm?
(A) 188 cm2
(B) 165 cm2
(C) 168 cm2
(D) 198 cm2
(E) 987 cm2
Rationale: 1/2 * 22(9 + 6)
= 165 cm2
Answer: B
Answer: (B) 165 cm2
Question: The cross-section of a tunnel is a trapezium in shape. If the tunnel is 15 m wide at the top and 5 m wide at the bottom and the area of cross-section is 400 sq m, the depth of tunnel is?
(A) 200 m
(B) 600 m
(C) 400 m
(D) 800 m
(E) 900 m
Rationale: 1/2 * d (15 + 5) = 400
d = 400
ANSWER:C
Answer: (C) 400 m
Question: The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum.
(A) 17008
(B) 17000
(C) 170028
(D) 171776
(E) 170892
Rationale: The simple interest for the first year is 10200/2 is Rs.5100 and compound interest for first year also is Rs.5100. The compound interest for second year on Rs.5100 for one year
So rate of the interest = (100 * 1530)/ (5100 * 1) = 30% p.a.
So P = (100 * 10200)/ (30 * 2) = Rs.17000
Answer: B
Answer: (B) 17000
Question: Working together, Jose and Jane can complete an assigned task in 30 days. However, if Jose worked alone and complete half the work and then Jane takes over the task and completes the second half of the task, the task will be completed in 45 days. How long will Jose take to complete the task if he worked alone? Assume that Jane is more efficient than Jose
(A) 90 days
(B) 30 days
(C) 60 days
(D) 65 days
(E) 36 days
Rationale: Assume:
Jose does 1 job in x days, so Jose does 1/x job in a day
Jane does 1 job in y days, so Jane does 1/y job in a day
Together, they does (x+y)/xy job in a day. This is equals to 1/20. So
(x+y)/xy = 1/30
30(x+y) = xy
Next, we're told 1 job takes 45 days to complete if Jose and Jane each does half the work. So since Jose does 1 job in x days, he wil need x/2 days to do half the job. Jane similarly will need y/2 days to do the other half.
x/2 + y/2 = 45
x+y = 90
So
xy = 30 *90 =2700
The answer choices are:
90 days
30 days
60 days
65 days
36 days
From the answer choices, So I'll go for 90 days for Jose and 30 days for Jane.
Answer : A
Answer: (A) 90 days
Question: The sum of the ages of Latha and Geetha is 60years. Also 5 years ago, the Latha's age was 5 times the age of the Geetha. What is the age of the Geetha?
(A) 13years
(B) 15yeas
(C) 20years
(D) 18years
(E) 22years
Rationale: Let the age of the Geetha be x years
The age of the Latha is 60-x years
5 years ago 5(x-5) = 60-x-5
x = 13 approximately
Geetha's age = 13years
Answer is B
Answer: (B) 15yeas
Question: The speed at which a man can row a boat in still water is 150 kmph. If he rows downstream, where the speed of current is 48 kmph, what time will he take to cover 390 metres?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
Rationale: Speed of the boat downstream = 150 + 48 = 198 kmph
= 198 * 5/18 = 30 m/s
Hence time taken to cover 390 m = 390/30 = 13 seconds. Answer: D
Answer: (D) 13
Question: The 15 homes in a new development are each to be sold for one of three different prices so that the developer receives an average (arithmetic mean) of $200,000 per home. If 4 of the homes are to be sold for $170,000 each and 5 are to be sold for $200,000 each, what will be the selling price of each of the remaining 16 homes?
(A) $200,000
(B) $210,000
(C) $215,000
(D) $207,500
(E) $230,000
Rationale: IMO the answer has to be D.
5 houses are being sold for 200,000. 4 houses are being sold for $30,000 less, resulting in a loss of $120,000. To make the average selling price intact i.e. $200,000, the remaining 16 houses must be sold at such a profit that it compensates for the loss of 120,000. Hence 16x=120,000.
x=7500.
The 16 houses are sold at $7,500 profit or at $207,500. (ANSWER D)
Answer: (D) $207,500
Question: Simple interest on a certain amount is 9/16 of the principal. If the numbers representing the rate of interest in percent and time in years be equal, then time, for which the principal is lent out, is :
(A) 6 1/2
(B) 7 1/2
(C) 8
(D) 9 1/2
(E) None
Rationale: Sol.
Let sum = x. Then, S.I. = 9/16 x.
Let rate = R% and time = R years.
∴ [x * R * R / 100] = 9x / 16 ⇔ R² = 900/16
⇔ R = 30/4 = 7 1/2
Hence, time = 7 1/2 years.
Answer B
Answer: (B) 7 1/2
Question: What is the area of an equilateral triangle whose one side length is 70?
(A) 825√3
(B) 925√3
(C) 1025√3
(D) 1125√3
(E) 1225√3
Rationale: -> The area of an equilateral triangle with one side length of a is √3a2/4. Thus, √3(70^2)/4=1225√3 and the answer is E.
Answer: (E) 1225√3
Question: A bacteria gives birth to two new bacteria in each second and the life span of each bacteria is 5 seconds. The process of the reproduction is continuous until the death of the bacteria. initially there is one newly born bacteria at time t = 0, the find the total number of live bacteria just after 10 seconds :
(A) 3 10 /2
(B) (3)10 - (2)10
(C) 243 *(35 -1)
(D) (3)10 -(2)5
(E) None of these
Rationale: Solution: Total number of bacteria after 10 seconds,
= (3)10 - (3)5
= (3)5 *(3)(5 -1)
= 243 *(3)(5 -1)
Since, just after 10 seconds all the bacterias (i.e. 35 ) are dead after living 5 seconds each.
Answer: Option C
Answer: (C) 243 *(35 -1)
Question: What should come in place of the question mark (?) in the following number series?
11 16 23 32 43 ?
(A) 55
(B) 56
(C) 57
(D) 58
(E) 59
Rationale: Explanation:
The difference is 5,7,9,11.
It increases by every consecutive odd number.
Answer: E
Answer: (E) 59
Question: A man buys an article and sells it at a profit of 20%. If he had bought it at 20% less and sold it for Rs.65 less, he could have gained 25%. What is the cost price?
(A) 325
(B) 375
(C) 278
(D) 267
(E) 288
Rationale: CP1 = 100 SP1 = 120
CP2 = 80 SP2 = 80 * (125/100) = 100
20 ----- 100
65 ----- ? => 325
Answer:A
Answer: (A) 325
Question: How many numbers from 10 to 50 are exactly divisible by 3?
(A) 13
(B) 15
(C) 16
(D) 17
(E) 18
Rationale: 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45,48.
13 Numbers.
10/3 = 3 and 50/3 = 16 ==> 16 - 3 = 13. Therefore 13 digits
A)
Answer: (A) 13
Question: The speed of a boat in still water in 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is:
(A) 1.2 km
(B) 2.4 km
(C) 3.2 km
(D) 3.6 km
(E) 4.6 km
Rationale: Speed downstream = (15 + 3) kmph = 18 kmph.
Distance travelled = 18 x 12/60	km = 3.6 km.
ANSWER:D
Answer: (D) 3.6 km
Question: The average of first 40 prime numbers is?
(A) 15.41
(B) 16.41
(C) 15.61
(D) 15
(E) 16.91
Rationale: Explanation:
Average = (2+3+5+7+11+13+17+19+23+29+31+37)/12= 197/12= 16.41(Approx)
Answer is B
Answer: (B) 16.41
Question: Aishwarya’s mom was 38 years of age at the time of her birth, while her mom was 34 years old when her 4 years younger sister was born. The variance between the parents ages is :
(A) 6 years
(B) 11 years
(C) 10years
(D) 12 years
(E) 8 years
Rationale: E
8 years
Mom’s age when Aishwarya’s sister was born = 34 years.
Dad’s age when Aishwarya’s sister was born = (38 + 4) years = 42 years.
Needed Variance = (42 – 34) years = 8 years.
Answer is E
Answer: (E) 8 years
Question: A thief steals at a car at 2.00 p.m. and drives it at 60 km/hr. The theft is discovered at 3 p.m. and the owner sets off in another car at 75 km/hr. When will he overtake the thief?
(A) 1 p.m
(B) 3 p.m
(C) 4 p.m
(D) 4.30 p.m
(E) 6 p.m
Rationale: D
4.30 p.m
Suppose the thief is overtaken x hrs after 2.00 p.m.
Then, distance covered by the owner in (x - 1/2) hrs.
60x = 75(x - 1/2) => x = 5/2 hrs.
So, the thief is overtaken at 4.30 p.m.
Answer: (D) 4.30 p.m
Question: If TIER is written as 7163 and BRAIN is written as 23415, how is RENT coded ?
(A) 7536
(B) 7653
(C) 3657
(D) 3765
(E) None of these
Rationale: Explanation:
Given :
Letter : T I E R B A N
Code : 7 1 6 3 2 4 5
Thus, the code for RENT is 3657.
ANSWER C
Answer: (C) 3657
Question: How much time will it take for an amount of Rs. 900 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
(A) 2 years
(B) 3 years
(C) 1 year
(D) 4 years
(E) 5years
Rationale: Solution:
P = Rs.900
SI = Rs.81
T = ?
R = 4.5%
T= 100×SI/PR=100×81/900×4.5=2 years
Answer : Option A
Answer: (A) 2 years