mathewhe/aqua_rat huggingface dataset:
Question: Printer P can print one lakh books in 8 hours. Printer Q can print the same number of books in 10 hours while Printer R can print the same in 12 hours. All the Printers started printing at 9 A.M. Printer P is stopped at 11 A.M. and the remaining 2printers complete work. Approximately at what time will the printing of 1 lac books be completed?
(A) 10 pm
(B) 1 pm
(C) 12 pm
(D) 2 pm
(E) 3 pm
Rationale: Work done by P in 1 hour = 1/8
Work done by Q in 1 hour = 1/10
Work done by R in 1 hour = 1/12
Work done by P,Q and R in 1 hour = 1/8 + 1/10 + 1/12 = 37/120
Work done by Q and R in 1 hour = 1/10 + 1/12 = 22/120 = 11/60
From 9 am to 11 am, all the Printer were operating.
Ie, they all operated for 2 hours and work completed = 2 × (37/120) = 37/60
Pending work = 1- 37/60 = 23/60
Hours taken by Q an R to complete the pending work = (23/60) / (11/60) = 23/11
which is approximately equal to 2
Hence the work will be completed approximately 2 hours after 11 am ; ie around 1 pm
B
Answer: (B) 1 pm
Question: How many times the keys of a writter have to be pressed in order to write first 400 counting no.'s?
(A) 998
(B) 1000
(C) 1092 times
(D) 1100
(E) 1200
Rationale: 1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 400 = 301 * 3 = 903
-----------
1092
C
Answer: (C) 1092 times
Question: Three types of tea the a,b,c costs Rs. 95/kg,100/kg and70/kg respectively.How many kgs of each should be blended to produce 100 kg of mixture worth Rs.90/kg, given that the quantities of band c are equal
(A) 70,15,15
(B) 50,25,25
(C) 60,20,20
(D) 40,30,30
(E) 20,30,30
Rationale: given quantities of b and c are equal .
therefore instead of considering them as a different quantities take average of both and consider it as a single entity .
so the cost of the mixture "D" (equal quantities of "B" and "C") is 170/2=85rs/kg
now the tea contains only "A" of 95 rs/per and "D" of 85 rs/kg.
it is clearly seen that "A" is 5 more and "D" is 5 less than the required cost per kg .
therefore 50/50 will go well .
A=50kg and D=50kg. (D= B&C in equal ratio). therefore B&C=25kg each .
(A:B:C)=(50,25,25)
ANSWER:B
Answer: (B) 50,25,25
Question: There are four members in a family. Their average income is Rs.10000 per month. Three members get Rs.8000, Rs.15000, Rs.6000 respectively. Therefore what is the income of the fourth member of the family?
(A) Rs. 10000
(B) Rs. 11000
(C) Rs. 12000
(D) Rs. 9000
(E) Rs. 8500
Rationale: EXPLANATION
Total income of 3 members = Rs. (8000 + 15000 + 6000) = Rs. 29000.
Required income = Rs. [ (10000 x 4) – 29000 ]
= Rs. (40000 – 29000)
= Rs. 11000.
Answer B
Answer: (B) Rs. 11000
Question: The cost price of 15 articles is equal to the selling price of 11 articles. Find the profit percent?
(A) 18 2/91%
(B) 36 4/11%
(C) 18 9/11%
(D) 18 2/91%
(E) 12 2/11%
Rationale: 15 CP = 11 SP
11 --- 2 CP
100 --- ? =>36 4/11%
Answer:B
Answer: (B) 36 4/11%
Question: How many different number-plates for cars can be made if each number-plate contains four of the digits 0 to 9 followed by a letter A to Z, assuming that
(a) no repetition of digits is allowed?
(A) 131040
(B) 116700
(C) 142369
(D) 147225
(E) 132547
Rationale: we want 4 digit of cars and repetition is not allowed
1st digit can be fill with 0 to 9 i.e = 10
2nd digit can be fill with 0 to 9 except earlier selected i.e = 9
3rd digit can be fill with 0 to 9 except earlier selected i.e = 8
4th digit can be fill with 0 to 9 except earlier selected i.e = 7
No of ways = 10 * 9 * 8 * 7 * (total aplphabets)
= 5040 * 26
= 1,31,040
Ans - A
Answer: (A) 131040
Question: During a two-week period, the price of an ounce of silver increased by 30 percent by the end of the first week and then decreased by 20 percent of this new price by the end of the second week. If the price of silver was x dollars per ounce at the beginning of the two-week period, what was the price, in dollars per ounce, by the end of the period?
(A) 1.16x
(B) 1.13x
(C) 1.1x
(D) 1.07x
(E) 1.04x
Rationale: The price at the end is 0.8(1.3x)=1.04x
The answer is E.
Answer: (E) 1.04x
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 9 minutes. The waste pipe can empty the full cistern in?
(A) 18
(B) 17
(C) 16
(D) 19
(E) 15
Rationale: 1/10 + 1/15 - 1/x = 1/9
x = 18
Answer:A
Answer: (A) 18
Question: If john makes a contribution to a charity fund at school, the average contribution size will increase by 50% reaching $75 per person. If there were 3 other contributions made before john's, what is the size of his donation?
(A) $100
(B) $150
(C) $200
(D) $250
(E) $450
Rationale: Cavg = average contribution before John
Cavg*1.5 = 75, therefore the average cont is $50 before John.
If he needs to increase the average contribution by $25, he must put in $25 for each of the 3 people.
so $75.
But, he also has to put in the average for himself (the fourth person), so add $75.
So $150 is your answer.
Answer B
Answer: (B) $150
Question: The average weight of 5 students decreases by 12 kg when one of them weighing 72 kg is replaced by a new student. The weight of the student is
(A) 12 kg
(B) 10 kg
(C) 20 kg
(D) 72 kg
(E) None of these
Rationale: Explanation :
Let the weight of student be x kg.
Given, Difference in average weight = 12 kg
=> (72-x)/5 = 12
=> x = 12
Answer : A
Answer: (A) 12 kg
Question: A container has a capacity of 20 gallons and is full of spirit. 4 gallons of spirit is drawn out and the container is again filled with water. This process is repeated 4 times. Find how much spirit is left in the resulting mixture finally?
(A) 8(257/525) gallons
(B) 8(346/625) gallons
(C) 8.192 gallons
(D) 8.25 gallons
(E) None of these
Rationale: There is a direct formula to calculate such repetition:
Left QTY / Orig QTY = ( (Orig QTY - Rep QTY) / Orig QTY )^n
where n is number of times mixing done:
Left QTY / 20 = (20 -4)^4 / 20^4
Left QTY = 20 (16/20)^4
Left QTY = 20 ( 4/5 )^4
Left QTY = 8.192
Answer is C
Answer: (C) 8.192 gallons
Question: Find the cost of fencing around a circular field of diameter 28 m at the rate of Rs.1.50 a meter?
(A) 289
(B) 132
(C) 279
(D) 277
(E) 278
Rationale: 2 * 22/7 * 14 = 88
88 * 1 1/2
= Rs.132
Answer: B
Answer: (B) 132
Question: If the price of an article decreases by 111/9 % and the sale of the article increases by 12 ½ %, what is the net effect on revenue?
(A) 1% loss
(B) 1% gain
(C) No loss or no gain
(D) Cannot be determined
(E) None of these
Rationale: M. F 1 = 100-100/9/100 =800/900 = 8/9
M. F 2 = 100+25/2/100 =225/200 =9/8
Total M. F =8/9*9/8 = 1
Overall % change = ( M. F – 1 ) * 100 = ( 1 – 1 ) * 100 = 0
ANSWER:C
Answer: (C) No loss or no gain
Question: A train 280 m long, running with a speed of 63 km / hr will pass a tree in
(A) 12 sec
(B) 15 sec
(C) 16 sec
(D) 20 sec
(E) None
Rationale: Sol.
Speed = (63 x 5/18) m/sec.
= 35 /2 m / sec.
Time taken = (280 x 2/35) sec = 16 sec
Answer C
Answer: (C) 16 sec
Question: A salesman travels a distance of 50 km in 2 hours and 30 minutes. How much faster in kilometer per hour, on an average, must he travel to make such trip in 5/6 hour less time?
(A) 10km/hr
(B) 15km/hr
(C) 20km/hr
(D) 30km/hr
(E) 25km/hr
Rationale: Time required = 2 hrs 30 min - 50 min = 1 hr 40 min = 1 2/3 hrs
Required speed = 50*3/5 = 30km/hr
Original speed = 50*2/5 = 20 km/hr
Difference = 30-20 = 10 km/hr
Answer is A
Answer: (A) 10km/hr
Question: John tossed a fair coin 2 times. What is the probability that the coin landed heads up exactly twice?
(A) 0.5
(B) 0.55
(C) 0.6
(D) 0.65
(E) 0.7
Rationale: The probability is exactly same as the cion landed tail up once. That is 2*(1/2)^2 = 2/4 =0.5.
The answer is, therefore, (A).
Answer: (A) 0.5
Question: 0.002 x 0.5 = ?
(A) 0.0001
(B) 0.001
(C) 0.01
(D) 0.1
(E) 1.0
Rationale: 2 x 5 = 10.
Sum of decimal places = 4
0.002 x 0.5 = 0.001
Answer: Option B
Answer: (B) 0.001
Question: Andy completes a piece of work in 10 days, Raju completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is
(A) 6 days
(B) 8 days
(C) 9 days
(D) 10 days
(E) 11 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 × 40/50 = 8 days.
B
Answer: (B) 8 days
Question: The price of commodity X increases by 40 paise every year, while the price of commodityY increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?
(A) 2010
(B) 2011
(C) 2012
(D) 2013
(E) None
Rationale: EXPLANATION
Suppose commodity X will cost 40 paise more than Y after z years.
Then, (4.20 + 0.40z) – (6.30 + 0.15z) = 0.40
0.25z = 0.40 + 2.10
x =2.50/ 0.25 =250/25 =10
X will cost 40 paise more than Y 10 years after 2001 i.e., 2011.
Answer B
Answer: (B) 2011
Question: Let's find out how sharp your mind is. Let's see if you can find the missing numbers in the series:
192, 021, 222, 324, 252, 627, 2__, 9__?
(A) 281 and 930.
(B) 282 and 930.
(C) 283 and 930.
(D) None
(E) Cannot be determined
Rationale: Solution:
If you look closely, you will find a sequence in every alternating number.
192, 222 and 252 form one series where 30 is added each time.
021, 324 and 627 form one series where 303 is added each time.
Thus the next two numbers will be 282 and 930.
Answer B
Answer: (B) 282 and 930.
Question: A watch was sold at a loss of 21%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
(A) 560
(B) 882
(C) 799
(D) 778
(E) 901
Rationale: 79%
104%
--------
25% ---- 140
100% ---- ? => Rs.560
Answer: A
Answer: (A) 560
Question: Each factor of 200 is inscribed on its own plastic ball, and all of the balls are placed in a jar. If a ball is randomly selected from the jar, what is the probability that the ball is inscribed with a multiple of 42?
(A) 1/16
(B) 5/42
(C) 1/8
(D) 3/16
(E) 1/9
Rationale: 200=2*3*5*7, so the # of factors 210 has is (1+1)(1+1)(1+1)(1+1)=16 (see below);
42=2*3*7, so out of 16 factors only two are multiples of 42: 42 and 210, itself;
So, the probability is 2/16=1/9.
Answer: E.
Answer: (E) 1/9
Question: The radius of a cylinder is 8 m, height 13 m. The volume of the cylinder is:
(A) 2200
(B) 2614.9
(C) 3300
(D) 1100
(E) 4400
Rationale: Cylinder volume = Ï€r(power2)h
= 22/7 Ã— 8 Ã— 8 Ã— 13
= 2614.9 m(power3)
Answer is B.
Answer: (B) 2614.9
Question: A started a business with an investment of Rs. 70000 and after 6 months B joined him investing Rs. 120000. If the profit at the end of a year is Rs. 26000, then the share of B is?
(A) A)14500
(B) B)14000
(C) C)12000
(D) D)13007
(E) E)14098
Rationale: Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6
Total profit = Rs. 26000
Share of B = 6/13 (26000)
= Rs. 12000
Answer:C
Answer: (C) C)12000
Question: Farm Tax is levied on the 60% of the cultivated Land. The tax department collected total $ 3840 through the farm Tax from the village of Mr. william. Mr. william paid only $ 480 as farm tax. The percentage of total land of Mr. willam over the total taxable land of the village is :
(A) 15%
(B) 25%
(C) 0.125%
(D) 0.2083%
(E) none
Rationale: This will be equal to the percentage of total cultivated land he holds over the total cultivated land in the village. That leads to (480/3840)x100 =12.5%in percentage terms.
But the question asks ratio between his total land to total cultivated land. Hence the answer is 12.5%x (100/60) = 20.833% and the answer is not there in the options.
The correct answer is (E).
Answer: (E) none
Question: If a+b+c=13, a2+b2+c2=69, then find ab+bc+ca
(A) 50
(B) 60
(C) 69
(D) 75
(E) 80
Rationale: (a+b+c)2= a2+b2+c2+2(ab+bc+ca)
2(ab+bc+ca)= (a+b+c)2- a2+b2+c2
=169-69
=100
ab+bc+ca=50
ANSWER A 50
Answer: (A) 50
Question: M = {-6, -5, -4, -3, -2}
T = {-2, -1, 0, 1, 2, 3, 4, 5}
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above, what is the probability that the product of the two integers will be negative?
(A) 5/8
(B) 1/3
(C) 2/5
(D) 1/2
(E) 3/5
Rationale: Answer A.
Total # of outcomes: 5*8= 40
# of outcomes where Product is -ve : (-6,1) ,(-6,2), (-6,3)... Hence, total: 25
Probability: 25/40 = 5/8
Answer: (A) 5/8
Question: Thabo owns exactly 280 books, and each book is either paperback fiction, paperback nonfiction, or hardcover nonfiction. If he owns 20 more paperback nonfiction books than hardcover nonfiction books, and twice as many paperback fiction books as paperback nonfiction books, how many hardcover books nonfiction books does Thabo own?
(A) 10
(B) 20
(C) 30
(D) 40
(E) 55
Rationale: I think we can use double-matrix method and solve using only one variable.
Our goal is to find the number of hardcover nonfiction books. Let that number be x. We are given that all 140 books are either paperback fiction, paperback nonfiction, or hardcover nonfiction. This implies that number of hardcover fiction books is 0.
Double-matrix: P = paperback; H = hardcover; F = fiction; NF = nonfiction
P H Total
F 2x+40 0
NF x+20 x
Total 3x+60 x 280
3x + 60 + x = 280
x = 55
Answer (E.)
Answer: (E) 55
Question: Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 108 as interest at the end of the loan period, what was the rate of interest?
(A) 3.6
(B) 3
(C) 18
(D) 24
(E) None of these
Rationale: Let rate = R% and time = R years.
Then, (1200 x R x R)/100 = 108
12R2 = 108
R2 =9
R = 3.
Answer: Option B
Answer: (B) 3
Question: In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 5:6:2. If there are in all Rs.37, the number of 25 paisa coins is?
(A) 30
(B) 31
(C) 32
(D) 34
(E) 37
Rationale: 5x 6x 2x
50 25 100
250x + 150x + 200x = 3700
600x = 3700
x = 6.16 => 6x = 37
ANSWER:E
Answer: (E) 37
Question: A sum of money is to be distributed among A, B, C, D in the proportion of 5:2:4:3. If C gets Rs. 1000 more than D, what is B's share?
(A) 2778
(B) 2679
(C) 2000
(D) 2699
(E) 2661
Rationale: Let the shares of A, B, C and D be 5x, 2x, 4x and 3x Rs. respectively.
Then, 4x - 3x = 1000 => x = 1000.
B's share = Rs. 2x = 2 * 1000 = Rs.2000.
Answer:C
Answer: (C) 2000
Question: When I acquired my Mercedes-Benz car in Germany, the first thing I had to do was to get a license plate. The plate I got had a peculiar number on it. It consisted of 5 different numbers and by mistake when I fixed it upside down the number could be still read, but the value had increased by 78633.
(A) 10966
(B) 10968
(C) 10967
(D) 10966
(E) 10965
Rationale: 5 differ numbers can be read upside down same are 0 , 1 , 6 , 8 , 9
try with these no.s
number is 10968.
10968
78633
-------
89601
--------
ANSWER:B
Answer: (B) 10968
Question: A basket contains 10 apples, of which 1 is spoiled and the rest are good. If we select 2 apples from the basket simultaneously and at random, what is the probability that the 2 apples selected will include the spoiled apple?
(A) 2/9
(B) 3/8
(C) 2/7
(D) 1/6
(E) 1/5
Rationale: The total number of ways to choose 2 apples is 10C2 = 45
The number of ways that include the spoiled apple is 9C1 = 9
P(the spoiled apple is included) = 9/45 = 1/5
The answer is E.
Answer: (E) 1/5
Question: Ram has two dies which has a nos 2,3,4,6 when he throws the two dies together find the no of possibility so that the some of the two dies should be even...???
(A) 4/8
(B) 5/8
(C) 6/8
(D) 7/8
(E) 3/8
Rationale: total possible combinations=(2,2)(2,4)(2,6)(4,2)(4,4)(4,6)(3,3)(6,2)(6,4)(6,6)=10
so probability=10/16=5/8
ANSWER:B
Answer: (B) 5/8
Question: When positive integer N is divided by positive integer J, the remainder is 16. If N/J = 127.05, what is value of J?
(A) 300
(B) 320
(C) 370
(D) 400
(E) 450
Rationale: When a number is divided by another number, we can represent it as : Dividend = Quotient * Divisor + Remainder
So, Dividend/Divisor = Quotient + Remainder/Divisor
Given that N/J = 127.05
Here 127 is the quotient.
Given that Remainder = 16
So, 127.05 = 127 + 16/J
So, J = 320
Answer: B
Answer: (B) 320
Question: When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 15-inch boxes. If the university pays $1.20 for every box, and if the university needs 3.06 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes?
(A) $255
(B) $275
(C) $510
(D) $612
(E) $2,550
Rationale: Total no. Of boxes = 3060000/(20×20×15) = 510
Total cost = 510×$1.20=$612
Answer D
Answer: (D) $612
Question: Which of the following describes all values of x for which 9–x^2 >= 0?
(A)  x >= 1
(B)  x <= –1
(C)  -3 <= x <= 3
(D)  x <= –1 or x >= 1
(E)  –1 <= x <= 1
Rationale: 9 - x^2 >=0
means x^2 - 9 <=0
=> (x-3)(x+3) <= 0
=> -3 <= x <= 3
Answer - C
Answer: (C)  -3 <= x <= 3
Question: How many integers between 324,700 and 458,600 have a 2 in the tens digit and a 1 in the units digit?
(A) 1339
(B) 2300
(C) 4200
(D) 1340
(E) 2414
Rationale: There is one number in hundred with 2 in th tens digit and 1 in the units digit: 21, 121, 221, 321, ...
The difference between 324,700 and 458,600 is 458,600-324,700=133,900 - one number per each hundred gives 133,900/100=1,339 numbers.
Answer: 1,339 A
Answer: (A) 1339
Question: In business, A and C invested amounts in the ratio 4:2, whereas the ratio between amounts invested by A and B was 4:1, If Rs 20,000 was their profit, how much amount did A receive.
(A) 13333
(B) 26758
(C) 45896
(D) 14639
(E) 89576
Rationale: Explanation:
A:B = 4:1 = 4:1
=> A:C = 4:2 = 4:2
=> A:B:C = 4:1:2
A share = (4/6)*20000
= 13333
Option A
Answer: (A) 13333
Question: The arithmetic mean and standard deviation of a certain normal distribution are 14.5 and 1.7, respectively. What value is exactly 2 standard deviations less than the mean?
(A) 10.5
(B) 11
(C) 11.1
(D) 12
(E) 12.5
Rationale: Mean = 14.5
Two standard deviations is 1.7 + 1.7 = 3.4
There could be two calues for this.
Mean + two standard deviations = 17.9
Mean - Two standard deviations = 11.1
Answer choice has 11.1 and so C is the answer.
Answer: (C) 11.1
Question: What number comes next?
482, 693, 754, 826, 937, ?
(A) 113
(B) 231
(C) 245
(D) 548
(E) 123
Rationale: D
548
The numbers 48269375 are being repeated in the same sequence.
Answer: (D) 548
Question: There is a certain relation between two given words on one side of : : and one word is given on another side of : : while another word is to be found from the given alternatives, having the same relation with this word as the given pair has.
(A) Chauffeur
(B) Steering
(C) Mechanic
(D) Brake
(E) gren
Rationale: Explanation:
Horse is driven by a jockey .
Similarly,car is driven by a chauffeur
Answer: A)
Answer: (A) Chauffeur
Question: If B> 0 and B is divisible by the product of the first nine positive integers, all of the following must be factors of B except
(A) 35
(B) 40
(C) 63
(D) 315
(E) 704
Rationale: The question states taht B is divisible by 9!,which is 1*2*3*4*5*6*7*8*9
B=(9!) * some number
A. 35 = 5*7 so will divide B
B. 40 =5*8 so will divide B
C. 63 =9*7 so will divide B
D. 315 =5*7*9 so will divide B
E. 704 =8*8*11 This will not divide B
Ans E
Answer: (E) 704
Question: In one hour, a boat goes 11 km/hr along the stream and 5 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
(A) 3 km/hr
(B) 2 km/hr
(C) 4 km/hr
(D) 6 km/hr
(E) 8 km/hr
Rationale: Speed in still water =	1/2	(11 + 5) kmph = 8 kmph.
ANSWER:E
Answer: (E) 8 km/hr
Question: Anil spends 40% of his income on rent, 30% of the remaining on medicines and 20% of the remaining on education. If he saves Rs. 840 every month, then find his monthly salary?
(A) 2882
(B) 2672
(C) 2288
(D) 2500
(E) 1288
Rationale: Let's Anil's salary be Rs. 100.
Money spent on Rent = 40% of 100 = Rs. 40.
Money spent on medical grounds = 30% of (100 - 40) = 3/10 * 60 = Rs. 18.
Money spent on education = 20% of (60 - 18) = 1/5 * 42 = Rs. 8.40
Anil saves 100 - (40 + 18 + 8.40) i.e., Rs. 33.60
for 33.6 ---> 100 ; 840 ---> ?
Required salary = 840/33.6 * 100 = Rs. 2500
Answer: D
Answer: (D) 2500
Question: 15 men take 21 days of 8 hrs. each to do a piece of work. How many days of 3 hrs. each would it take for 21 women if 3 women do as much work as 2 men?
(A) 60
(B) 20
(C) 19
(D) 29
(E) 39
Rationale: Let 1Man does 1unit/hr of work
15M in 21 days of 8hrs will do (15*21*8) units
3W = 2M
1W=(2/3)units/hr
21W with 3hrs a day will take (15*21*8)/(21*3*(2/3)) days
=> 60 Days
ANSWER:A
Answer: (A) 60
Question: Shopkeeper rise price by 31% and gives successive discount of 10% and 15%. What is overall % gain or loss?
(A) 0.215%
(B) 1.215%
(C) 3.215%
(D) 6.215%
(E) 7.215%
Rationale: Let d initial price be 100
31 % rise
now price = 131/100*100 = 131
10% discount
Then price = 131 * 90/100 = 117.9
15 % discount
Then price = 117.9 * 85/100 = 100.215
So Gain = 100.215 - 100 = 0.215
Gain % = Gain * 100 /CP
==> 0.215 * 100 /100 = 0.215%
ANSWER:A
Answer: (A) 0.215%
Question: Jane covered a distance of 330 miles between city A and city B taking a total of 5 hours. If part of the distance was covered at 60 miles per hour speed and the balance at 80 miles per hour speed, how many hours did she travel at 60 miles per hour?
(A) 2 hours 30 minutes
(B) 3 hours
(C) 2 hours
(D) 1 hour 45 minutes
(E) None of these
Rationale: Answer
Let Jane travel 'x' at 60 miles per hour.
As the total time taken to cover 340 miles is 5 hours, Jane would have traveled (5 - x) hours at 80 miles per hour.
Distance covered at 60 miles per hour = Speed * time = 60 * x = 60x miles.
Distance covered at 80 miles per hour = Speed * time = 80 (5 - x) = 400 - 80x miles.
Total distance covered = Distance covered at 60 miles per hour + Distance covered at 80 miles per hour.
Therefore, total distance = 60x + 400 - 80x.
Total distance travelled = 340 miles.
Therefore, 330 = 60x + 400 - 80x
20x = 50 or x = 2 hours 30 minutes.
Choice A
Answer: (A) 2 hours 30 minutes
Question: 1^2 – 2^2 + 3^2 – 4^2 + 5^2 – 6^2 + 7^2 – 8^2 + 9^2 – 10^2=?
(A) -21
(B) -53
(C) -35
(D) -55
(E) -58
Rationale: 1-4+9-16+25-36+49-64+81-100= -55
ANSWER:D
Answer: (D) -55
Question: Find 4 + 7 + 10 + 13 + 16 + . . . up to 20 terms
(A) 650
(B) 640
(C) 630
(D) 620
(E) 610
Rationale: a = 4
d = 7 – 4 = 3
Sum of first 20 terms, S20
ANSWER IS A
Answer: (A) 650
Question: A man invested Rs. 26000 in 5% stock at 104. He sold the stock when the price rose to Rs. 120 and invested the sale proceeds in 6% stock. By doing this his income increased by Rs. 2500. At what price did he purchase the second stock?
(A) 125
(B) 40
(C) 48
(D) 35
(E) 50
Rationale: Assuming that face value of the first stock = Rs.100 as it is not given in the question
Since it is a 5% stock, we can take the dividend per stock = Rs.5
Market Value of the first stock = Rs.104
Investment on the first stock = Rs.26000
Number of stocks purchases = 26000/104 = 250
His total income from all these stocks = Rs.250 × 5 = Rs.1250
He sells each of this stock at Rs.120
ie, amount he earns = Rs.120 × 250 = Rs.30000
He invest this Rs.30000 in 6% stock (here also face value is not given and hence take it as Rs.100)
His new income = Rs.(1250 + 2500) = Rs.3750
ie, By Rs.30000 of investment , he earns an income of Rs.3750
To get an income of Rs.6, investment needed = 30000×6/3750=Rs.48
This is the market value of the second stock
Answer is C.
Answer: (C) 48
Question: 55
a6
+ 2b
____
96
If a and b represent positive single digits in the correctly worked computation above, what is the value of a + 2b ?
(A) 2
(B) 7
(C) 9
(D) 11
(E) 12
Rationale: Adding the digits in unit's place , 5+ 6 + b = 16 (Since a and b are positive single digits )
=> b = 5
Now adding the digits in ten's place , 5+a + 2 + 1= 9 (1 has been carried over from unit's place addition)
=> a= 1
a+2b = 1+2*5
=11
Answer D
Answer: (D) 11
Question: The average weight of 29 students is 28 kg. By the admission of a new student, the average weight is reduced to 27.3 kg. The weight of the new student is
(A) 22 kg
(B) 21.6 kg
(C) 22.4 kg
(D) 21 kg
(E) 7 Kg
Rationale: Exp . The total weight of 29 students = 29* 28
The total weight of 30 students = 30* 27.3
Weight of the new student = ( 30*27.3 – 29*28)
= 819 - 812 = 7
Answer:E
Answer: (E) 7 Kg