mathewhe/aqua_rat huggingface dataset:
Question: A car gets 60 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 170 kilometers?
(A) 3.5 gallons
(B) 2.37 gallons
(C) 5.7 gallons
(D) 4.25 gallons
(E) 2.83 gallons
Rationale: Each 60 kilometers, 1 gallon is needed. We need to know how many 60 kilometers are there in 170 kilometers?
60 Ã· 170 = 2.83 Ã— 1 gallon = 2.83 gallons
correct answer is E) 2.83 gallons
Answer: (E) 2.83 gallons
Question: Look at this series: 70, 71, 76, __, 81, 86, 70, 91, ... What number should fill the blank?
(A) 70
(B) 71
(C) 80
(D) 90
(E) 96
Rationale: A
Answer: (A) 70
Question: The manager at a health foods store mixes a unique superfruit juice cocktail that costs $1399.45 per litre to make. The cocktail includes mixed fruit juice and açai berry juice, which cost $262.85 per litre and $3104.35 per litre, respectively. The manager has already opened 33 litres of the mixed fruit juice. How many litres of the açai berry juice does he need to add?
(A) 17 litres
(B) 22 litres
(C) 11 litres
(D) 07 litres
(E) 38 litres
Rationale: 262.85(33)+3,104.35x = 1,399.45(33 + x)
Solve the equation.
262.85(33)+3,104.35x = 1,399.45(33 + x)
8,674.05 + 3,104.35x = 46181.85 + 1,369.45x
8,674.05 + 1,704.9x = 46181.85
1,704.9x = 37,507.8
x = 22
Answer is B.
Answer: (B) 22 litres
Question: A rectangular farm has to be fenced one long side, one short side and the diagonal. If the cost of fencing is Rs.11 per meter. The area of farm is 1200 m2 and the short side is 30 m long. How much would the job cost?
(A) 1276
(B) 1200
(C) 2832
(D) 1299
(E) 1320
Rationale: Explanation:
l * 30 = 1200 è l = 40
40 + 30 + 50 = 120
120 * 11 = 1320
Answer: Option E
Answer: (E) 1320
Question: 189. The inside dimensions of a rectangular wooden box
are 12 inches by 14 inches by 16 inches. A cylindrical
canister is to be placed inside the box so that it stands
upright when the closed box rests on one of its six
faces. Of all such canisters that could be used, what is
the radius, in inches, of the one that has maximum
volume?
(A)  3
(B)  4
(C)  5
(D)  6
(E)  7
Rationale: Since the radius is squared, the biggest volume cylinder will have the biggest possible radius. To achieve that, let the smaller dimension of the rectangular box be the height. So, it will have 16x14width x length. The biggest cylinder must fit both dimensions, so it must have at most a diameter of 14, so the radius will be 7.
E
Answer: (E)  7
Question: If a fair coin is tossed six times, what is the probability of getting exactly five heads in a row?
(A) 1/64
(B) 1/32
(C) 1/16
(D) 3/64
(E) 3/32
Rationale: P(HHHHHT) = 1/64
P(THHHHH) = 1/64
The sum of these probabilities is 2/64 = 1/32
The answer is B.
Answer: (B) 1/32
Question: If an integer r is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that r(r + 1)(r + 2) will be divisible by 8?
(A) 1/4
(B) 3/8
(C) 1/2
(D) 5/8
(E) 3/4
Rationale: for r Total numbers 8*12
There are 12 numbers divisible by 8 -> 3*12 (if 8 is an example - (6,7,8), (7,8,9), (8,9,10))
and 12 numbers divisible by 4 but not divisible by 8 -> 2*12 (if 4 is an example (2,3,4) and (4,5,6))
The answer 5/8 -> D
Answer: (D) 5/8
Question: there are two sections A and B of a class consisting of 36 and 44 students respectively. If the average weight of section A is 40kg and that of section B is 35kg, find the average weight of the whole class?
(A) 15.42
(B) 37.25
(C) 12.54
(D) 32.37
(E) 23.47
Rationale: Sol: total weight of(36+44) students=(36*40+44*35)kg =2980kg.
Therefore weight of the total class=(2980/80)kg =37.25kg.
Ans: B
Answer: (B) 37.25
Question: One side of a rectangle is 3 cm shorter than the other side. If we increase the length of each side by 1 cm, then the area of the rectangle will increase by 18 cm2. Find the lengths of all sides.
(A) 10 and 3
(B) 7 and 10
(C) 10 and 7
(D) 3 and 10
(E) 10 and 10
Rationale: Let x be the length of the longer side x>3, then the other side's length is x−3 cm. Then the area is S1 = x(x - 3) cm2. After we increase the lengths of the sides they will become (x+1) and (x−3+1)=(x−2) cm long. Hence the area of the new rectangle will be A2=(x+1)⋅(x−2) cm2, which is 18 cm2 more than the first area. Therefore
A1+18=A2
x(x−3)+18=(x+1)(x−2)
x2−3x+18=x2+x−2x−2
2x=20
x=10. So, the sides of the rectangle are 10 cm and (10−3)=7 cm long.
So answer is C.
Answer: (C) 10 and 7
Question: Ella leaves her home and walks toward Ed's house. Two hours later, Ed leaves his home and walks toward Ella's house. The distance between their homes is 42 kilometers, Ella's walking speed is 5 km/h, and Ed's walking speed is 3 km/h. How many kilometers will Ella walk before she meets Ed?
(A) 28
(B) 29
(C) 30
(D) 31
(E) 32
Rationale: Ella walks 10 km in the first two hours so there are 32 km remaining.
When Ed starts walking, they complete a total of 8 km per hour.
They will meet four hours after Ed starts walking.
Since Ella walks for 6 hours, she walks 30 km.
The answer is C.
Answer: (C) 30
Question: John bought 9.25m of cloth for $407. Find the cost price per metre.
(A) 46
(B) 47
(C) 58
(D) 44
(E) 54
Rationale: Cloth bought by John = 9.25 m
Cost of 9.25 m = $407
Cost per metre = 407 ÷ 9.25
The cost of the cloth per metre = $ 44
Answers: D
Answer: (D) 44
Question: A crate of mangoes contains one bruised mango for every thirty mango in the crate. If three out of every four bruised mango are considerably unsaleble and there are 11 unsaleable mangoes in the crate then how msny mango are there in the crate?
(A) 100 mangoes
(B) 110 mangoes
(C) 120 mangoes
(D) 130 mangoes
(E) 125 mangoes
Rationale: 110 mangoes
ANSWER:B
Answer: (B) 110 mangoes
Question: four children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Children AB must sit next to each other, and child C must be somewhere to the right of AB. How many possible configurations are there for the children?
(A) 560
(B) 720
(C) 1440
(D) 4320
(E) 4800
Rationale: A, B, C, D, E, F, G- seven children, of which AB must sit next to each other. Considering them as one X (A, B), we have X, C, D, E, F, G. These can be arranged in 6! ways. But A,B can arrange themselves in 2! ways. So a total of 6!*2! ways = 1440. Since in exactly half of them, C will be to the right of AB, and exactly half, C will be to the left of AB, therefore 1440/2 = 560.
A is the right answer.
Answer: (A) 560
Question: John was thrice as old as Tom 6 yrs back. He will be 5/3 times as old as Tom 6 years hence. How old is Tom today?
(A) 10
(B) 11
(C) 12
(D) 15
(E) 19
Rationale: Sol. RMBflSk -6 = 3 (Ravi - 6) ...(j)
and Rupesh + 6 = | (Ravi + 6) ...(ii)
Solving both the equations we get,
Ravi = 12 years.
C
Answer: (C) 12
Question: A bank pays interest to its customers on the last day of the year. The interest paid to a customer
is calculated as 10% of the average monthly balance maintained by the customer. John is a
customer at the bank. On the last day, when the interest was accumulated into his account, his
bank balance doubled to $6840. What is the average monthly balance maintained by John in his
account during the year?
(A) 2840
(B) 5680
(C) 6840
(D) 7540
(E) 34200
Rationale: Soln:-
Bank balance is doubled with accumulation of interest to 6840..
this means INTEREST is 6840/2=3420 for entire year..
although since interest is 10% of avg MONthly balance, it becomes 34200..
ANSWER:E
Answer: (E) 34200
Question: n is a positive integer and k is the product of all integers from 1 to n inclusive. If k is a multiple of 1680, then what is the smallest possible value of n?
(A) 4
(B) 6
(C) 7
(D) 10
(E) 12
Rationale: 3360=2^4*3*5*7
2^4 means that n must be at least 6. That is, We need 2, 4, and 6.
However, we also need 7, so n must be at least 7.
The answer is C.
Answer: (C) 7
Question: The average of first 16 even numbers is?
(A) 19
(B) 18
(C) 16
(D) 11
(E) 17
Rationale: Sum of 16 even numbers = 16 * 17 = 272
Average = 272/16 = 17
Answer:E
Answer: (E) 17
Question: The number of students in the three sections of a class are in the ratio 2:3:4. The average marks scored in each of these sections is in the ratio 4:3:1. By what percent is the average mark of the second section more than the class average?
(A) 23.27%
(B) 28.57%
(C) 32.38%
(D) 36.74%
(E) 38.74%
Rationale: Let the number of students be 2x, 3x, 4x.
Let the average marks be 4y,3y,y.
Average mark of class = ( 8xy+9xy+4xy)/(2x+3x+4x)
=21xy/9x=7y/3
Percentage difference = ( 3y - 7y/3)/7y/3 *100
= 28.57%
ANSWER:B
Answer: (B) 28.57%
Question: If a*b=2a-3b+ab,then3*5+5*3 is equal to
(A) 22
(B) 24
(C) 26
(D) 28
(E) 30
Rationale: 3*5+5*3= (2x3-3x5+3x5)+(2x5-3x3+5x3)
=22
ANSWER A 22
Answer: (A) 22
Question: A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1500. The difference between the profit shares of A and C is?
(A) 299
(B) 277
(C) 298
(D) 600
(E) 271
Rationale: Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit share of B is Rs. 1500
=> 5 parts out of 15 parts is Rs. 1500
Now, required difference is 6 - 4 = 2 parts
Required difference = 2/5 (1500) = Rs. 600
Answer: D
Answer: (D) 600
Question: The average of a non zero number and its square is 5 times the number. The number is
(A) 9
(B) 17
(C) 29
(D) 295
(E) None
Rationale: Sol.
Let the number be x. Then,
x + x2 / 2 = 5x
‹=› x2 – 9x = 0
‹=› x (x - 9) = 0
‹=› x = 0 or x = 9.
So, the number is 9.
Answer A
Answer: (A) 9
Question: If the mean of numbers 38, x, 70, 88 and 110 is 69, what is the mean of 50, 72, 97, 125,147 and x?
(A) 73.5
(B) 77.86
(C) 86.67
(D) 66.69
(E) 70.56
Rationale: Mean = (Sum of all no. in series)/(no. in series)
M1 = 69 = (X+38+70+88+110)/(5)
69 x 5 = 290 + X
X = 39
Therefore mean of 2nd series
M2 = (X+50+62+97+125+147)/6
M2 = 86.67
Answer = C
Answer: (C) 86.67
Question: What is the ratio whose terms differ by 40 and the measure of which is 2⁄7
(A) 16 : 56
(B) 14 : 56
(C) 15 : 56
(D) 16 : 72
(E) None of these
Rationale: Let the ratio be x: (x + 40).Then,
x/(x+40)=2/7 ⇒ 2x + 80 ⇒ x = 16.
∴ Required ratio = 16 : 56.
Answer A
Answer: (A) 16 : 56
Question: Find the greatest number which leaves the same remainder when it divides 21, 57 and 105.
(A) 18
(B) 8
(C) 12
(D) 16
(E) None of these
Rationale: 105 - 57 = 48
57 - 21 = 36
105 - 21 = 84
The H.C.F of 36, 48 and 84 is 12.
ANSWER:C
Answer: (C) 12
Question: Two pipes A and B can fill a tank in 15 min and 20 min respectively. Both the pipes are opened together but after 4 min, pipe A is turned off. What is the total time required to fill the tank?
(A) 10 min 20 sec
(B) 11 min 45 sec
(C) 12 min 30 sec
(D) 14 min 40 sec
(E) 15 min 40 sec
Rationale: Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15
Remaining part = 1 - 7/15 = 8/15
Part filled by B in 1 minute = 1/20
1/20 : 8/15 :: 1 ; x
x = 8/15 * 1 * 20 = 10 2/3 min = 10 min 40 sec.
The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec.
ANSWER:D
Answer: (D) 14 min 40 sec
Question: Tommy makes a bet that a coin will land on heads 2 times out of 8. After the first 6 tosses, the coin has landed on heads twice and tails four times. What is the probability that Tommy will win the bet?
(A) 1/4
(B) 1/2
(C) 1/8
(D) 1/3
(E) 1/6
Rationale: For Tommy to win, the coin must land on tails for both the remaining two tosses.
The probability of this happening given a fair coin is 1/2 * 1/2 = 1/4
Answer:A
Answer: (A) 1/4
Question: what is the remainder when 7894104 is divided by 72
(A) 8
(B) 25
(C) 32
(D) 4
(E) 24
Rationale: 7894104 / 72
7894104 / 9*8
986763 / 9 => rem = 3
we have cancelled it by 8
reqd remainder = 8*3 = 24
ANSWER:E
Answer: (E) 24
Question: If c and d are prime numbers, which of the following CANNOT be the sum of c and d?
(A) 5
(B) 9
(C) 13
(D) 23
(E) 33
Rationale: All answer choices but D are odd. In order odd number to be the sum of two prime numbers one must be even, so 2, and another odd.
Now, 23=2+21. Since 21 is not a prime then 23 cannot be written as the sum of two prime numbers.
Answer: D
Answer: (D) 23
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 180 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:
(A) 31 km/hr.
(B) 52 km/hr.
(C) 34 km/hr.
(D) 54 km/hr.
(E) 36 km/hr.
Rationale: Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (180 + 180)/12
2x = 30
x = 15.
Speed of each train = 15 m/sec = 15 x 18/5 km/hr = 54 km/hr.
answer :D
Answer: (D) 54 km/hr.
Question: Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 50% Vermouth by volume. How many ounces of Gin must he add?
(A) n/6
(B) n/3
(C) 3n/5
(D) 5n/6
(E) 8n/5
Rationale: 4 ounces is vermouth
6 ounces of gin...
Total volume 10.
To make vermouth account for 50% of total volume the new volume must be....
x*0.5=4
x=8 ounces....
So now you see that he must add 2 ounces of gin...
Plug in 6 for n in the answer choices and look for answer 2
B
Answer: (B) n/3
Question: A number when, 28 subtracted from it reduces to its one third. What is the value of 50% of that number?
(A) 42
(B) 84
(C) 21
(D) 24
(E) 25
Rationale: 2/3 x = 28 => x = 42
42 * 1/2 = 21
ANSWER:C
Answer: (C) 21
Question: Laura took out a charge account at the General Store and agreed to pay 5% simple annual interest. If she charges $35 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments?
(A) $2.10
(B) $36.75
(C) $37.16
(D) $38.10
(E) $38.80
Rationale: Principal that is amount taken by Laura at year beginning = 35$
Rate of interest = 5%
Interest = (5/100)*35 = 1.75$
Total amount that Laura owes a year later = 35+1.75 = 36.75 $
Answer B
Answer: (B) $36.75
Question: Sheik Abdullah decides to buy 4 new cars for his collection. If he has to choose between nine different cars, what is the number of purchasing possibilities he has?
(A) A)106
(B) B)116
(C) C)126
(D) D)136
(E) E)146
Rationale: Sheik Abdullah decides to buy 4 new cars for his collection. He has to choose between nine different cars
8C3= 9*8*7*6/(4*3*2*1) = 126 ANS:C
Answer: (C) C)126
Question: There were five baskets of apples on the table. Each basket had one more apple in it than the basket before it. The average number of apples in the baskets A, B, C, D and E is 220. What percent is E of C ?
(A) 99.1
(B) 99.2
(C) 99.3
(D) 99.4
(E) 99.5
Rationale: Explanation :
In such a case the middle number (C) is the average
∴ C = 220 and E = 222
Required percentage = 220/222 x 100 = 99.1
Answer : Option A
Answer: (A) 99.1
Question: Find the average of the first 20 natural numbers?
(A) 10.9
(B) 10.8
(C) 10.2
(D) 10.5
(E) 10.4
Rationale: Average of the first 'n' natural numbers = (n + 1)/2
We get (20 + 1)/2 = 10.5
Answer:D
Answer: (D) 10.5
Question: A car traveling at a certain constant speed takes 15 seconds longer to travel 1 kilometer than it would take to travel 1 kilometer at 48 kilometers per hour. At what speed, in kilometers per hour, is the car traveling?
(A) 39
(B) 40
(C) 41
(D) 42
(E) 43
Rationale: 48 * T = 1 km => T = 1/48 km/h
V*(T+15/3600) = 1
V (1/48 + 15/3600) = 1
V (90/3600) = 1
V = 40 km/h
The answer is B.
Answer: (B) 40
Question: Jennifer had $180 to spend on herself. She spent 1/5 of the money on a sandwich, 1/6 for a ticket to a museum, and 1/2 of it on a book. How much money does Jennifer have left over?
(A) $4
(B) $14
(C) $5
(D) $15
(E) $24
Rationale: 1/5 x $180 = $36 for sandwich
1/6 x $180 = $30 for museum
1/2 x $180 = $90 for book
$36 + $30 + $90 = $156 spent
$180 - $156 = $24 left over
correct answer E
Answer: (E) $24
Question: Of the 200 stamps in a collection, 90 are foreign and 60 are more than 10 years old. If 20 stamps are both foreign and more than 10 years old, how many stamps are neither foreign nor more than 10 years old?
(A) 50
(B) 70
(C) 100
(D) 130
(E) 150
Rationale: 20 stamps are both foreign and more than 10 years old.
70 stamps are foreign only.
40 stamps are 10 years old only.
The number of remaining stamps is 200 - (20+70+40) = 70
The answer is B.
Answer: (B) 70
Question: Read the following three equations:
5 ~ 4 ~ 3 ~ 9 = 4215
6 ~ 9 ~ 2 ~ 6 = 3816
4 ~ 7 ~ 3 ~ 3 = 1122
Now based on the rule that has been used, solve the following equation:
4 ~ 2 ~ 7 ~ 4 = ____
(A) 1416
(B) 2910
(C) 2940
(D) 3749
(E) 4470
Rationale: A
1416
1416
The rule that is being followed here is
P ~ Q ~ R ~ S = [first digit of (P * S)] [last digit of (Q * R)] [first digit of (Q * R)] [last digit of (P * S)]
Using the same rule in the incomplete equation,
4 ~ 2 ~ 7 ~ 4 = [first digit of (4 * 4)] [last digit of (2 * 7)] [first digit of (2 * 7)] [last digit of (4 * 4)]
= 1416
Thus 1416 is the missing number.
Answer: (A) 1416
Question: Of the 800 employees of Company X, 80 percent have been with the company for at least ten years. If y of theselong-termmembers were to retire and no other employee changes were to occur, what value of y would reduce the percent oflong-termemployees in the company to 60 percent ?
(A) 400
(B) 160
(C) 112
(D) 80
(E) 56
Rationale: The # oflong-termemployees is 80%*800=640.
After y of them retire new # oflong-termemployees would become 640-y.
Total # of employees would become 800-y.
We want 640-y to be 60% of 800-y --> 640-y=(800 -y)*60% --> y = 400.
Answer: A.
Answer: (A) 400
Question: In how many ways can a group of 6 men and 3 women be made out of a total of 7 men and 4 women?
(A) 63
(B) 29
(C) 70
(D) 74
(E) 28
Rationale: We need to select 7 men from 6 men and 4 women from 3 women. Number of ways to do this= 7C6 × 4C328E)
Answer: (E) 28
Question: Suraj has a certain average of runs for 9 innings. In the 10th innings he scores 200 runs thereby increasing his average by 8 runs. What is his average after the 10th innings?
(A) 149
(B) 190
(C) 128
(D) 178
(E) 190
Rationale: To improve his average by 8 runs per innings he has to contribute 9 x 8 = 72 runs for the previous 8 innings.
Thus, the average after the 9th innings
= 200 - 72 = 128.
ANSWER:C
Answer: (C) 128
Question: The duplicate ratio of 2:3 is?
(A) 4:9
(B) 1:4
(C) 1:8
(D) 1:18
(E) 1:13
Rationale: 2^2: 3^2 = 4:9
ANSWER:A
Answer: (A) 4:9
Question: If x is 25 percent greater than 88, then x =
(A) 110
(B) 70.4
(C) 86
(D) 105.6
(E) 108
Rationale: x=88*1.25=110
So the answer is A.
Answer: (A) 110
Question: On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with four times the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.40 per glass on the first day, what was the price per glass on the second day?
(A)  $0.16
(B)  $0.20
(C)  $0.30
(D)  $0.40
(E)  $0.45
Rationale: On the first day 1 unit of orange juice and 1 unit of water was used to make 2 units of orangeade;
On the second day 1 unit of orange juice and 4 units of water was used to make 5 units of orangeade;
So, the ratio of the amount of orangeade made on the first day to the amount of orangeade made on the second day is 2 to 5. Naturally the ratio of the # of glasses of orangeade made on the first day to the # of glasses of orangeade made on the second day is 2 to 5.
We are told thatthe revenue from selling the orangeade was the same for both daysso the revenue from 2 glasses on the first day equals to the revenue from 5 glasses on the second day.
Say the price of the glass of the orangeade on the second day was $x then 2*0.4=5*x --> x=$0.16.
Answer: A.
Answer: (A)  $0.16
Question: In a games hour 4 different types of players came to the ground? cricket 11, hockey 15, football 21, softball 15. In these 4 people play both cricket and hockey, 3people play both softball and football. 4 people play both cricket and football. How many people play only cricket?
(A) 11
(B) 3
(C) 5
(D) 7
(E) 9
Rationale: people play only cricket = total players in cricket- both cricket and football- both cricket and hockey.
people play only cricket = 11-4-4 = 3
Answer is B
Answer: (B) 3
Question: A discount electronics store normally sells all merchandise at a discount of 10 percent to 30 percent off the suggested retail price. If, during a special sale, an additional 20 percent were to be deducted from the discount price, what would be the lowest possible price of an item costing $260 before any discount?
(A) $130.00
(B) $145.60
(C) $163.80
(D) $182.00
(E) $210.00
Rationale: Original price : 260 $
Max first discount = -30%
Thus : 260∗(1−30/100)=182
Second discount on the discounted price = -20%
Thus : 182∗(1−20/100)=145,6
Answer B.
Answer: (B) $145.60
Question: 8 litres are drawn from a cask full of wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of the water is 16 : 65. How much wine the cask hold originally ?
(A) 18 litres
(B) 24 litres
(C) 32 litres
(D) 42 litres
(E) None
Rationale: Solution
Let the quantity of the wine in the cask originally be x litres
then, quantity of wine left in cask after 4 operations
= [x(1- 8/x)4] litres.
Therefore x(1- 8/x)4 / x = 16/81 =› (1- 8/x)4 = (2/3)2
=› (x - 8 / x) = 2/3 =› 3x - 24 = 2x =› x = 24.
Answer B
Answer: (B) 24 litres
Question: In a kilometer race, A beats B by 50 meters or 10 seconds. What time does A take to complete the race?
(A) 167 sec
(B) 190 sec
(C) 176 sec
(D) 716 sec
(E) 123 sec
Rationale: Time taken by B run 1000 meters
= (1000 * 10)/50 = 200 sec.
Time taken by A = 200 - 10
= 190 sec.
Answer:B
Answer: (B) 190 sec
Question: To apply for the position of photographer at a local magazine, a photographer needs to include two or three photos in an envelope accompanying the application. If the photographer has pre-selected seven photos representative of her work, how many choices does she have to provide the photos for the magazine?
(A) 42
(B) 48
(C) 56
(D) 60
(E) 64
Rationale: 7C2 + 7C3 = 21 + 35 = 56
The answer is C.
Answer: (C) 56
Question: A man counted his animals, 80 heads and 240 legs (ducks and goats). how many goats are there?
(A) 30
(B) 40
(C) 50
(D) 60
(E) 70
Rationale: let no of ducks=d and no of goat=g
d+g=80(heads)----------> eq 1
each duck has 2 legs and goat has 4 legs
2d+4g=240 and divide 2d+4g=240 by 2 we get d+2g=120 -----------> eq2
subtract eq1 from eq2
we get no of goats=40
ANSWER:B
Answer: (B) 40
Question: There are some rabbits and peacocks in a zoo. The total number of their heads is 60 and total number of their legs is 192. Find the number of total rabbits?
(A) 36
(B) 77
(C) 88
(D) 99
(E) 22
Rationale: Let the number of rabbits and peacocks be 'r' and 'p' respectively. As each animal has only one head, so r + p = 60 --- (1)
Each rabbit has 4 legs and each peacock has 2 legs. Total number of legs of rabbits and peacocks, 4r + 2p = 192 --- (2)
Multiplying equation (1) by 2 and subtracting it from equation (2), we get
=> 2r = 72 => r = 36.
Answer: A
Answer: (A) 36
Question: How many seconds will a train 200 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph?
(A) 22 sec
(B) 35 sec
(C) 25 sec
(D) 18 sec
(E) 17 sec
Rationale: D = 200 + 150 = 350
S = 36 * 5/18 = 10 mps
T = 350/10 = 35 sec
Answer:B
Answer: (B) 35 sec
Question: A shopkeeper sold 10 articles at the cost price of 12 articles. Then find the profit% or lost%
(A) -10%
(B) 10%
(C) 15%
(D) 20%
(E) 25%
Rationale: here 10 articles selling price = 12 articles cost price
so the difference = 12-10 = 2
% of profit = 2*100/10 = 20%
correct option is D
Answer: (D) 20%
Question: What is the perimeter of a regular polygon with sides of length 12 cm and internal angles measuring 84° each?
(A) 45 cm
(B) 108 cm
(C) 120 cm
(D) 132 cm
(E) 144 cm
Rationale: Sum of all interior angles is given by:
180(n-2) = n is number of sides
180(n-2) = 84*n
from here
n = 3.75
So perimeter becomes 12*3.75= 45
answer A
Answer: (A) 45 cm
Question: a^3 - b^3 - 3ab = 1,
a^3 - b^3 + ab = x! + 1,
where a,b,x are positive integers,x is least.
Find (a + b) ?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: a^3 - b^3 + ab = x! + 1,
a^3 - b^3 - 3ab = 1,
subtracting,
ab+3ab =x!
4ab=x!
if x=4
a=3
b=2
a+b=3+2=5 and x=4.
ANSWER:D
Answer: (D) 5