mathewhe/aqua_rat huggingface dataset:
Question: A fruit seller sells mangoes at the rate of Rs.13 per kg and thereby loses 25%. At what price per kg, he should have sold them to make a profit of 15%?
(A) Rs.11.81
(B) Rs.19.93
(C) Rs.12.25
(D) Rs.12.31
(E) None
Rationale: Solution
75 : 13 = 115 : x
x= (13Ã—115/75)
= Rs.19.93
Hence, S.p per Kg	= Rs.19.93
Answer B
Answer: (B) Rs.19.93
Question: Beverley rode 5 1/4 miles in 1 hours and 30 minutes. What was her average rate of speed in miles per hour?
(A) 3
(B) 3 1/4
(C) 3 1/2
(D) 3 3/4
(E) 4
Rationale: D = 5(1/4) = 21/4
T = 1(1/2) = 3/2 = 6/4
S = D/T = 3 3/4
Answer = D
Answer: (D) 3 3/4
Question: In a class of 50 students, 20 play SNOOKER, 15 play Cricket and 11 play Football. 7 play both SNOOKER and Cricket, 4 play Cricket and Football and 5 play SNOOKER and football. If 18 students do not play any of these given sports, how many students play exactly two of these sports?
(A) 10
(B) 12
(C) 34
(D) 45
(E) 566
Rationale: Notice that7 play both SNOOKER and Cricket does not mean that out of those 7, some does not play Football too. The same for Cricket/Football and SNOOKER/Football.
[color=#ffff00]{Total}={SNOOKER}+{Cricket}+{Football}-{HC+CH+HF}+{All three}+{Neither}For more check ADVANCED OVERLAPPING SETS PROBLEMS
[/color]
50=20+15+11-(7+4+5)+{All three}+18 --> {All three}=2;
Those who play ONLY SNOOKER and Cricket are 7-2=5;
Those who play ONLY Cricket and Football are 4-2=2;
Those who play ONLY SNOOKER and Football are 5-2=3;
Hence, 5+2+3=10 students play exactly two of these sports.
Answer: A.
Answer: (A) 10
Question: How many numbers from 2 to 8 are exactly divisible by 2?
(A) A)2
(B) B)4
(C) C)5
(D) D)7
(E) E)8
Rationale: 2/2 = 1 and 8/2 = 4
4- 1 = 3
3 + 1 = 4 Numbers.
Answer : B
Answer: (B) B)4
Question: If set A={2,2,2,....,n times} , set B={3,3,3,3....m times} and set C={13,13,13...k time} , then in terms of m,n and k , how many possible subsets from sets A,B, and C can be created ?
(A) a) k(n+m+mn)+ k
(B) b) (1+n+m+mn)(k+1)
(C) c) k^2(mn+n/m)
(D) d) kmn(k+m+n)
(E) e) None of the above.
Rationale: a) how many 2's are included?
b) how many 3's are included?
and
c) how many 11's are included?
For the number of 2, we could have zero 2's, or one 2, or two 2's, all the way up to n 2's. That's (n + 1) possibilities for the 2's. Similarly, (m + 1) possibilities for the 3's and (k + 1) possibilities for the 11's. We simply multiply these three numbers.
NOTICE that one set, the set that includes no 2's, no 3's, and no 11's, is included. This is known in mathematics as thenull set, sometimes called the empty set, a set with no members. Technically, this is a subset of every possible set, but that's a technical detail of set theory that goes well beyond what the GMAT would expect students to know. Even the the calculation is not that difficult, some of the technical aspects of this question are not in line with the GMAT's expectations.
The number of subsets is (m + 1)(n + 1)(k + 1). The answer is not given in that form. Instead, the first two factors have been FOILed together:
(mn + m + n + 1)(k + 1).
Mike
B
Answer: (B) b) (1+n+m+mn)(k+1)
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train?
(A) 150
(B) 872
(C) 287
(D) 288
(E) 212
Rationale: Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 9 = 150 meter
Answer:A
Answer: (A) 150
Question: Cecilia, Robbie, and Briony all bought stamps. The number of stamps Cecilia purchased was equal to a single digit. The number of stamps only one of them purchased was divisible by 7. The number of stamps one of them bought was an even number. Which of the following could represent the numbers of stamps each purchased?
(A) 3, 8, 24
(B) 7, 9, 17
(C) 6, 9, 12
(D) 5, 15, 18
(E) 9, 10, 13
Rationale: I didnt get your point on eliminating D.
The number of stamps only one purchased was divisible by 7.Could that not be Cecilia with 9 stamps.
I choose this and marked D.
Answer: (D) 5, 15, 18
Question: The profit earned by selling an article for $ 832 is equal to the loss incurred when the same article is sold for $ 448. What should be the sale price for making 45% profit?
(A) $480
(B) $450
(C) $928
(D) $870
(E) $660
Rationale: Let C.P. = $ x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 145% of $ 640 = $ 928.
C
Answer: (C) $928
Question: If the sides of a cube are in the ratio 9:5. What is the ratio of their diagonals?
(A) 9:5
(B) 16:9
(C) 4:
(D) 3:4
(E) 3:8
Rationale: Explanation:
Diagonal of a Cube=a√3 where a is side
a1:a2 = 9:5
d1:d2 = 9:5 where√3 cancelled both side
ANSWER:A
Answer: (A) 9:5
Question: Both Robert and Alice leave from the same location at 8:00 a.m. driving in the same direction, but in separate cars. Robert drives 60 miles per hour while Alice drives 80 miles per hour. After 6 hours, Alice’s car stops. At what time will Robert’s car reach Alice’s car?
(A) 1 p.m.
(B) 3 p.m.
(C) 4 p.m.
(D) 8 p.m.
(E) 9 p.m.
Rationale: 8:00 am so 6 hours later is 2:00 pm
In six hours, Robert will have driven 6*60 = 360 miles
In six hours, Alive will have driven 6*80 = 480 miles
So Robert needs 480-360 = 120 miles do catch Alice up.
So at 60 mph, he will need 2 hours
2:00 pm + 2 hours = 4:00 pm
ANS : C
Answer: (C) 4 p.m.
Question: X percents of the rooms are suits, Y percent of the rooms are painted light blue. Which of the following best represents the least percentage of the light blue painted suits?
(A) X-Y
(B) Y-X +100
(C) 100X-Y
(D) X+Y-100
(E) 100-XY
Rationale: Using the simple formula
100 = X + Y - BOTH - > Here X = % of Suits , Y = % of light blue painted rooms and BOTH = % of suits painted in light blue colour
So now, BOTH = X+Y -100 and now you can manipulate the value of X and Y to get the max and minimum values.
Hence Answer D
Answer: (D) X+Y-100
Question: If a - b = 5 and a2 + b2 = 29, find the value of ab.
(A) 6
(B) 8
(C) 10
(D) 11
(E) 2
Rationale: 2ab = (a2 + b2) - (a - b)2
= 29 - 25 = 4
ab = 2.
Answer: E
Answer: (E) 2
Question: In a store, the profit is 320% of the cost. If the cost increases by 25% but the SP remainsconstant, approximately what %of the sp is the profit?
(A) 30%
(B) 70%
(C) 80%
(D) 90%
(E) 100%
Rationale: Let C.P. = Rs. 100. Then, profit = Rs. 320, S.P. = Rs. 420
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 420
Profit = 420 - 125 = Rs. 295
Required percentage = 295/420 * 100 = 1475/21 = 70%
B
Answer: (B) 70%
Question: ashok and pyarelal invested money together in a business and share a capital of ashok is 1/9 of that of pyarelal.if the incur a loss of Rs 1000 then loss of pyarelal?
(A) 600
(B) 700
(C) 800
(D) 900
(E) 1000
Rationale: Let the capital of Pyarelal be x, then capital of Ashok=x/9
So ratio of investment of Pyarelal and Ashok = x : x/9 =9x : x
Hence out of the total loss of 1000, loss of Pyarelal= 1000*9x/10x=900
ANSWER:D
Answer: (D) 900
Question: A and B start from Opladen and Cologne respectively at the same time and travel towards each other at constant speeds along the same route. After meeting at a point between Opladen and Cologne, A and B proceed to their destinations of Cologne and Opladen respectively. A reaches Cologne 40 minutes after the two meet and B reaches Opladen 70 minutes after their meeting. How long did A take to cover the distance between Opladen and Cologne?
(A) 1 hour
(B) 1 hour 10 minutes
(C) 2 hours 30 minutes
(D) 1 hour 20 minutes
(E) 2 hours 10 minutes
Rationale: v1 and V2 are speeds.
v1.t /70 = v2
v2.t/40 = v1
v1/v2 = 7/4
which train A would 70. 4/7 mins to cover the same distance
40 + 40 = 80 mins (ANS D)
Answer: (D) 1 hour 20 minutes
Question: The ratio R, by volume of soap to alcohol to water in a 76 litre solution is 2: 50: 100 . The solution is then altered by adding more soap, alcohol and water.After this alteration the ratio, by volume of soap to water in the solution doubles whereas the ratio, by volume of soap to water remains the same as before. What COULD BE the resulting volume.
(A) 79 litres
(B) 78 litres
(C) 77 litres
(D) 152 liters
(E) 304 litres
Rationale: I guess it should be
the ratio R, by volume ofsoaptowaterin the solutiondoubleswhereas the ratio, by volume ofalocoholtowaterremains thesameas before
2:50: 100 => 1 : 25 : 50. If we add all the parts, we get 76 liters
So we have 1 liters of Soap, 25 liters of Alcohol and 50 liters of Water.
Now as per the Question, Soap : Water doubles but alcohol to water remains the same.
So Soap becomes 2 liters, Alcohol remains 25 liters and Water remains at 50 liters.
Hence 77 liters - Option C)
Answer: (C) 77 litres
Question: Three people took GMAT practice tests in which the minimum and maximum possible scores are 200 and 800, respectively. They each took a test 3 times, and no one scored below 400 or over 700. If the individual ranges of the three people's scores in those 3 practice tests were 40, 70 and 100, what is the difference between the maximum and minimum possible ranges of all their scores put together.
(A) 70
(B) 80
(C) 100
(D) 140
(E) 200
Rationale: According to the information in the question the maximum range would be between 400 and 700(300). The minimum range would be the greatest range for any one individual, which is listed in the problem as 100. So the difference between these would be 300-100 or 200.
Answer:E
Answer: (E) 200
Question: A dishonest dealer uses a scale of 80 cm instead of a metre scale and claims to sell at cost price. His profit is
(A) 9%
(B) 10%
(C) 25%
(D) None of these
(E) Cannot be determined
Rationale: Solution
Gain%	= (20 / 80 x 100)%
= 25%
Answer C
Answer: (C) 25%
Question: If an amount of Rs 15,487 is divided equally among
76 students, approximately how much amount will
each student get?
(A) Rs 206
(B) Rs 210
(C) Rs 204
(D) Rs 218
(E) None
Rationale: Amount received by each student = 15487/76 ≈ Rs
204
Answer C
Answer: (C) Rs 204
Question: If 89/99 = 0.898, what is the 83rd digit to the right of the decimal point of the fraction?
(A) 5
(B) 2
(C) 8
(D) 7
(E) 9
Rationale: we are not concerned what 89/99 means..
we have to look at the decimal..
0.898 means 0.898989....
so right of decimal, all ODD numbered are 8 and all EVEn numbered are 9..
here 83 is ODD, so ans is 8
Answer is C
Answer: (C) 8
Question: There is a swimming match that is single elimination meaning that after one loss the team is out. There are 50 swimmers in this match. How many matches are swam?
(A) 25
(B) 50
(C) 49
(D) 15
(E) 10
Rationale: C
The number of matches always adds up to one less than the number of matches in a single elimination tournament. You may calculate it any way. Therefore, 49 races were swam.
Answer: (C) 49
Question: A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
(A) 238 ways
(B) 287 ways
(C) 266 ways
(D) 108 ways
(E) 121 ways
Rationale: Explanation:
The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 12 = 108 ways.
Answer: D
Answer: (D) 108 ways
Question: If A lends Rs. 3500 to B at 10% p.a. and B lends the same sum to C at 11.5% p.a., then the gain of B (in
Rs.) in a period of 3 years is
(A) Rs. 154.50
(B) Rs. 155.50
(C) Rs. 156.50
(D) Rs. 157.50
(E) None of these
Rationale: Explanation:
We need to calculate the profit of B.
It will be,
SI on the rate B lends - SI on the rate B gets
Gain of B=157.50=3500×11.5×3100−3500×10×3100
Answer: D
Answer: (D) Rs. 157.50
Question: A train 200 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train?
(A) 5 sec
(B) 9 sec
(C) 12 sec
(D) 18 sec
(E) 15 sec
Rationale: Answer : C.
Speed of the train relative to man = (68 - 8) kmph
= (60* 5/18) m/sec = (50/3)m/sec
Time taken by the train to cross the man
= Time taken by It to cover 200 m at 50/3 m / sec = 200 *3/ 50 sec = 12sec
Answer: (C) 12 sec
Question: If c = (1/10)a and b = 5c, then which of the following represents the result of a^2+b^2+c^2 in terms of c
(A) 25c^2
(B) 56c^3
(C) 52c
(D) 126c^2
(E) 110c^2
Rationale: a = 10c and b =5c.
a^2+b^2+c^2 = (10c)^2+(5c)^2+c^2 = 126c^2.
Answer is D
Answer: (D) 126c^2
Question: Due to 10% decrease in the price of sugar and John can buy 4kg more sugar in Rs100 , then find the CP of sugar?
(A) s. 1(2/9)
(B) s. 2(7/9)
(C) s. 2(1/9)
(D) s. 3(2/7)
(E) s. 4(2/9)
Rationale: Here r = 10 % ,x = 100 and A = 4 kg
Actual price of sugar = 10*100/((100-10 )*4) = Rs. 2(7/9)
B
Answer: (B) s. 2(7/9)
Question: From a group of boys and girls,15 girls leave.There are then left 2 boys for each girl.After this,45 boys leave.There are then 5 girls for each boy.Find the number of girls in the beginning?
(A) 20
(B) 30
(C) 40
(D) 50
(E) 60
Rationale: 15 girls leave,B+(g-15)=0
then,B=2*(g-15)---------------------->>>1
45 boys leave,(b-45)+(g-15)=0
then,(g-15)=5(b-45)
Hence,the number of girls in the beginning are,
5(b-45)-(g-15)=0------------------->>>2
put 1 in 2, we get,
5(2*(g-15)-45)-(g-15)=0
10g-150-225-g+15=0
9g-360=0
9g=360
g=40
ANSWER:C
Answer: (C) 40
Question: If x is a positive integer, then the least value of x for which x! is divisible by 100,000 is?
Can someone please explain intuitively what the question is asking?
(A) 5
(B) 9
(C) 12
(D) 20
(E) 30
Rationale: In order x! to be divisible by 1,000, it should have at least 3 trailing zeros. A trailing 0 in factorial of a number is produced by 2 and 5 in it: 2*5 = 10. So, we need 10 to be in x! at least in power of 3.
5! = 120 has 1 trailing zeros.
10! will have 2 trailing zeros.
15! will have 3 trailing zeros.
20! will have 5 trailing zeros.
Answer: D.
Answer: (D) 20
Question: Find the average of first 40 natural numbers?
(A) 12.6
(B) 20.5
(C) 22.9
(D) 30.5
(E) 32.1
Rationale: Sum of first n natural numbers = n(n+1)/2
sum of first 40 natural numbers = 40*41/2 =820
average = 820/40 = 20.5
Answer is B
Answer: (B) 20.5
Question: Two trains, each 100 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is?
(A) 76 km/hr
(B) 66 km/hr
(C) 60 km/hr
(D) 67 km/hr
(E) 22 km/hr
Rationale: Let the speed of the slower train be x m/sec.
Then, speed of the train = 2x m/sec.
Relative speed = ( x + 2x) = 3x m/sec.
(100 + 100)/8 = 3x => x = 25/3.
So, speed of the faster train = 50/3 = 50/3 * 18/5 = 60 km/hr.
Answer:C
Answer: (C) 60 km/hr
Question: What is the measure of the radius of the circle that circumscribes a triangle whose sides measure 7, 24 and 25?
(A) 2.5
(B) 6.5
(C) 12.5
(D) 14
(E) 16
Rationale: Some of pyhtagron triplets we need to keep it in mind.
Like {( 2,3,5) , ( 5,12,13) ,( 7, 24,25), ( 11, 60,61).
So now we know the triangle is an right angle triangle. The circle circumscribes the triangle.
The circumraduis of the circle that circumscribes the right angle triangle = hypotanse / 2 = 25 / 2 = 12.5
Ans. C
Answer: (C) 12.5
Question: How many plants will be there in a circular bed whose outer edge measure 35 cms, allowing 4 cm2 for each plant ?
(A) 18
(B) 750
(C) 24
(D) 19
(E) None of these
Rationale: Circumference of circular bed = 35 cm
Area of circular bed = (35)2â„4Ï€
Space for each plant = 4 cm2
âˆ´ Required number of plants
= (35)2â„4Ï€ Ã· 4 = 24.36 = 24(approx)
Answer C
Answer: (C) 24
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 1.4 km respectively. The time taken by the slower train to cross the faster train in seconds is?
(A) 60
(B) 277
(C) 48
(D) 99
(E) 22
Rationale: Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 1.4 = 2.5 km = 2500 m.
Required time = 2500 * 3/125 = 60 sec.
Answer:A
Answer: (A) 60
Question: (0.0066)(3.6) / (0.04)(0.1)(0.006)=
(A) 990
(B) 99.0
(C) 9.9
(D) 0.99
(E) 0.099
Rationale: (0.0066)(3.6) / (0.04)(0.1)(0.006)=0.0060 * 360/4 * (0.1)(0.006)
= 0.066*90/1 * 0.006 = 66*90/6 = 11*90
=990
Answer : A
Answer: (A) 990
Question: Which of the following points is symmetric with y=x at (2,3)?
(A) (-2,-1)
(B) (-2,1)
(C) (2,1)
(D) (3,2)
(E) (-1,2)
Rationale: We can think of line y = x as a mirror. Any point (x,y) becomes (y,x) when it isreflectedover the mirror. Reverse the coordinate and keep the same sign. These two points will be symmetric to the line y = x.
(2,3) would become (3,2).
Answer (D).
Answer: (D) (3,2)
Question: Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran's share in the profit?
(A) 10508
(B) 10567
(C) 10528
(D) 10512
(E) 10500
Rationale: Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran's share = 24500 * 3/7 = Rs. 10500
Answer:E
Answer: (E) 10500
Question: The average amount with a group of seven numbers is Rs. 20. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?
(A) 22
(B) 27
(C) 15
(D) 77
(E) 16
Rationale: Total members in the group = 7
Average amount = Rs. 20
Total amount with them = 7 * 20 = Rs. 140
One number has Rs. 50. So, the amount with remaining 6 people = 140 - 50 = Rs. 90
The average amount with them = 90/6 = Rs. 15.
Answer: C
Answer: (C) 15
Question: Farm Tax is levied on the 45% of the cultivated Land. The tax department collected total $ 3840 through the farm Tax from the village of Mr. willam. Mr. willam paid only $ 480 as farm tax. The percentage of total land of Mr. willam over the total taxable land of the village is :
(A) 15%
(B) 25%
(C) 15.125%
(D) 27.78%
(E) none
Rationale: Only trick n this question is to ignore 45% information as farm tax is levied uniformly in the village and that includes Mr William's land.
What percentage of tax Mr William paid ? This will be equal to the percentage of total cultivated land he holds over the total cultivated land in the village. That leads to (480/3840)x100 =12.5%in percentage terms.
But the question asks ratio between his total land to total cultivated land. Hence the answer is 12.5%x (100/45) = 27.78% and the answer is not there in the options.
The correct answer is (D).
Answer: (D) 27.78%
Question: A patient was given four pills which he is required to take one after every forty minutes.
How long can the pills run for him?
(A) 1 hour and 10 minutes.
(B) 1 hour and 15 minutes.
(C) 1 hour and 20 minutes.
(D) 1 hour and 30 minutes.
(E) 1 hour and 40 minutes.
Rationale: He took the first pill at the zero minute.
He took the second pill after 20 minutes = 0+40=40
He took the third pill after 20 minutes = 40+40=80
He took the fourth pill after 20 minutes = 80+40=100
Then it will last for 100 minutes or an hour and 40 minutes.
Answer E
Answer: (E) 1 hour and 40 minutes.
Question: A pharmaceutical company received $5 million in royalties on the first $40 million in sales of and then $9 million in royalties on the next $210million in sales. By approximately what percentage did the ratio of royalties to sales decrease from the first $40 million in sales to the next $210 million in sales?
(A) 8%
(B) 15%
(C) 45%
(D) 52%
(E) 66%
Rationale: (9/210)/(5/40) = 12/35 = 34% it means that 9/210 represents only 34%. Therefore a decrease of 66%.
Answer E
Answer: (E) 66%
Question: A restaurant meal cost $50 and there was no tax. If the tip was more than 15 percent but less than 20 percent of the cost of the meal, then the total amount paid must have been between
(A)  $58 and $59
(B)  $56 and $61
(C)  $58 and $60
(D)  $57 and $59
(E)  $56 and $57
Rationale: Hence it will be between 50 * (1+15/100) and 50 * (1+20/100).
i.e b/w 57.5 and 60. Hence the answer B (b/w 56 and 61).
Answer: (B)  $56 and $61
Question: In a throw of dice what is the probability of getting number greater than 5
(A) 1/7
(B) 1/6
(C) 1/11
(D) 1/13
(E) 2/9
Rationale: Number greater than 5 is 6, so only 1 number
Total cases of dice = [1,2,3,4,5,6]
So probability = 1/6
B)
Answer: (B) 1/6
Question: The function f is defined for all the positive integers d by the following rule: f(d) is the number of positive integers each of which is less than d and has no positive factor in common with d other than 1 . if p is a prime number then f(p)?
(A) p-1
(B) p-2
(C) (p+1)/2
(D) (p-1)/2
(E) 2
Rationale: The moment you put a prime number in the function f(d), notice that all the numbers lesser than d have no divisor clashing with divisor of d since d is prime!!.
For instance f(7)= {6, 5, 4, 3, 2, 1}
Thus for f(p) number of integers falling under this set will be p-1
Answer :- A
Answer: (A) p-1
Question: Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 50 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h. What is the distance traveled by Maxwell when they meet in the middle?
(A) 16
(B) 18
(C) 20
(D) 24
(E) 30
Rationale: Distance between Maxwell's and Brad's home = 50 km
Maxwell's speed = 4 km/h
Brad's speed = 6 km/h
Relative speed of approach = 10 km/h
Time = 50/ 10 = 5 hours
Distance traveled by Maxwell when they meet in the middle = 4*5 = 20 km
Answer C
Answer: (C) 20
Question: If 85 percent of the test takers taking an old paper and pencil GMAT exam answered the first question on a given math section correctly, and 80 percent of the test takers answered the second question correctly, and 5 percent of the test takers answered neither question correctly, what percent answered both correctly?
(A) 60 %
(B) 65 %
(C) 70%
(D) 75%
(E) 80%
Rationale: {Total} = {First correctly} + {Second correctly} - {Both correctly} + {Neither correctly}
100 = 85 + 80 - {Both correctly} + 5
{Both correctly} = 70.
Answer: C.
Answer: (C) 70%
Question: How many pieces of 0.85 metres can be cut from a rod 42.5 metres long?
(A) 30
(B) 40
(C) 50
(D) 60
(E) 70
Rationale: Number of pieces = 42.5/0.85
= 42.50/0.85
= 4250/85
= 50.
ANSWER:C
Answer: (C) 50
Question: Of the 1000 inhabitants of a town, 60% are males of whom 20% are literate. If, of all the inhabitants, 25% are literate, then what percent of the females of the town are literate?
(A) 22.5
(B) 27.5
(C) 32.5
(D) 37.5
(E) None
Rationale: Sol.
Number of males = 60% of 1000 = 600.
Number of females = (1000-600) = 400.
Number of literates = 25% of 1000 = 250.
Number of literate males = 20% of 600 = 120.
Number of literate females = (250 - 120) = 130.
∴ Required percentage = (130 / 400 x 100)% = 32.5%
Answer C
Answer: (C) 32.5
Question: A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 6km?
(A) 3
(B) 5
(C) 6
(D) 67
(E) 7
Rationale: M = 4
S = 2
US = 4 - 2 = 2
D = 6
T = 6/2 = 3
Answer:A
Answer: (A) 3
Question: A cyclist climbs a hill with a length of 400 m with a speed of 7.2 km/h. When descending, the speed is two times greater. How much time is necessary for the cyclist to climb and descend the hill?
(A) 30 seconds
(B) 20 seconds
(C) 40 seconds
(D) 10 seconds
(E) None
Rationale: 7.2 km = 7200 m. 1 h = 3600 s. The speed will be 7200 m/3600 s = 2 m/s. The necessary time to climb will be 20 seconds. When descending, if the speed is two times greater, the necessary time will be two times smaller, so 10 seconds. The total necessary time is 20 s + 10 s = 30 seconds.
Answer A
Answer: (A) 30 seconds
Question: 12,31,68,129,220,347,?
(A) 129
(B) 220
(C) 347
(D) 516
(E) 520
Rationale: 2*2*2 + 4 = 12
3*3*3 +4 = 31
4*4*4 + 4 = 68
5*5*5 + 4 = 129
6*6*6 + 4 = 220
7 *7 *7 + 4 = 347
8 *8 *8 + 4 = 516.
ANSWER : D
Answer: (D) 516