mathewhe/aqua_rat huggingface dataset:
Question: An uneducated retailer marks all its goods at 50% above the cost price and thinking that he will still make 25% profit,offers a discount of 25% on the marked price.what is the actual profit on the sales?
(A) 12.50%
(B) 12%
(C) 13.50%
(D) 13%
(E) 11%
Rationale: Let C.P =Rs 100.
then ,marked price =Rs100
S.P=75% of Rs 150=Rs112.50
Hence,gain%=12.50%
Option A
Answer: (A) 12.50%
Question: Look at this series: 97, 97, 97, 87, 87, 87, 67, 67, 67 ... What number should come next?
(A) 47
(B) 57
(C) 45
(D) 48
(E) 55
Rationale: Explanation:
In this series, each number 20 is subtracted from previous number to arrive at the next number.
Answer: Option B
Answer: (B) 57
Question: Group A has 3 boys and 4 girls, group B has 2 boys and 2 girls and group C has 4 boys and 4 girls. One student is selected from each of the group. Find the probability that one girl and two boys are among the three selected?
(A) 13/4
(B) 19/28
(C) 9/15
(D) 29/35
(E) 77/27
Rationale: Group A has 3 boys and 4 girls; 7
Group B has 2 boys and 2 girls; 4
Group C has 4 boys and 4 girls. 8
Selected group should have one girl and two boys.
Girl from A, boy from B, boy from C: 4/7*2/4*4/8 = 1/7;
Boy from A, girl from B, boy from C: 3/7*2/4*4/8 = 3/28;
Boy from A, boy from B, girl from C: 3/7*2/4*4/8 = 3/7.
Sum = 1/7 + 3/28 + 3/7 = 19/28.
Answer: B.
Answer: (B) 19/28
Question: A restaurant meal cost $40 and there was no tax. If the tip was more than 10 percent but less than 15 percent of the cost of the meal, then the total amount paid must have been between
(A)  $43 and $47
(B)  $39 and $4 1
(C)  $38 and $40
(D)  $37 and $39
(E)  $36 and $37
Rationale: Hence it will be between 40 * (1+10/100) and 40 * (1+15/100).
i.e b/w 44 and 46. Hence the answer A (b/w 43 and 47).
Answer: (A)  $43 and $47
Question: The arithmetic mean and standard deviation of a certain normal distribution are 14.0 and 1.5, respectively. What value is exactly 2 standard deviations less than the mean?
(A) 10.5
(B) 11
(C) 11.5
(D) 12
(E) 12.5
Rationale: The value which isexactlytwo SD less than the mean is:mean-2*SD=14.0-2*1.5=11.
Answer: B.
Answer: (B) 11
Question: Worker A takes 4 hours to do a job. Worker B takes 10 hours to do the same job. How long it take both A & B, working together but independently, to do the same job?
(A) 20/9
(B) 40/9
(C) 40/14
(D) 60/9
(E) 80/9
Rationale: one day work of A = 1/4
one day work of B = 1/10
so one day work of A and B together = 1/4 + 1/10 = 14/40
so total days required = 40/14
ANSWER:C
Answer: (C) 40/14
Question: How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
(A) 12 sec
(B) 30 sec
(C) 27 sec
(D) 87 sec
(E) 15 sec
Rationale: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50
= 30 sec.
Answer:B
Answer: (B) 30 sec
Question: We can rent a car for x dollars per day for the first 3 days and then y dollars for each additional day. How much will it cost to rent a car for z days, where z>3?
(A) x + zy
(B) 3y+(z-3)x
(C) 3x + 3zy
(D) 3x+(z-3)y
(E) 3x + zy
Rationale: The first 3 days cost 3x.
The next (z-3) days cost (z-3)y.
The total cost is 3x+(z-3)y.
The answer is D.
Answer: (D) 3x+(z-3)y
Question: The average of 11 numbers is 12.9. If the average of first six is 12.5 and that of the last six is 11.4 the sixth number is?
(A) 10.5
(B) 11.5
(C) 12.5
(D) 13.5
(E) 14.5
Rationale: 1 to 11 = 11 * 12.9 = 141.9
1 to 6 = 6 * 15.5 = 93
6 to 11 = 6 * 11.4 = 68.4
93 + 68.4 = 161.4 – 149.9 = 11.5
6th number = 11.5
ANSWER:B
Answer: (B) 11.5
Question: A boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance upstream, it takes 4 hours. What is the speed of the boat in still water?
(A) 4 km/hr
(B) 6 km/hr
(C) 7 km/hr
(D) 8 km/hr
(E) 2 km/hr
Rationale: Rate downstream =16/2 kmph = 8 kmph.
Rate upstream =16/4	kmph = 4 kmph.
Speed in still water =	1/2	(8 + 4) kmph = 6 kmph.
ANSWER:B
Answer: (B) 6 km/hr
Question: A sum of Rs. 4500 amounts to Rs. 9000 in 4 years at the rate of simple interest. What is the rate of interest?
(A) 37%
(B) 25%
(C) 35%
(D) 6%
(E) 20%
Rationale: S.I. = (9000 - 4500) = Rs. 4500\
Rate = (100 * 4500) / (4500* 4)
= 25%
Answer: B
Answer: (B) 25%
Question: The L.C.M of two numbers is 2310 and their H.C.F is 30. If one number is 462 the Other is
(A) 330
(B) 300
(C) 270
(D) 150
(E) 350
Rationale: The other number
= L.C.M * H.C.F/given number
= 2310*30/462 = 150
Answer is D.
Answer: (D) 150
Question: Crew A can build a complete car in 20 minutes and Crew B can build a complete car in 25 minutes. If both crews work independently and start at the same time, what is the shortest amount of time Q it could take for 10 cars to be complete?
(A) 111 1/9 minutes
(B) 115 2/5 minutes
(C) 116 minutes
(D) 120 minutes
(E) 125 minutes
Rationale: A builds 4 cars in 80 min
B builds 4 cars in 100 min
So A builds another car in another 20 min (i.e total 5 cars)
B builds another car in another 25 minutes (i.e, total 5 cars)
However, A can build another car in next 20 min (i.e total 6 cars)
So total time Q= 125 min by B, which is > 120 min by A
B - 4 cars, A - 6 cars
Answer = D
Answer: (D) 120 minutes
Question: Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 11 cm.
(A) 335 cm2
(B) 209 cm2
(C) 285 cm2
(D) 825 cm2
(E) 725 cm2
Rationale: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (20 + 18) * (11)
= 209 cm2
Answer: B
Answer: (B) 209 cm2
Question: Three fair coins are labeled with a zero (0) on one side and a one (1) on the other side. Jimmy flips all three coins at once and computes the sum of the numbers displayed. He does this over 1000 times, writing down the sums in a long list. What is the expected standard deviation of the sums on this list?
(A) 1/2
(B) 3/4
(C) √3/2
(D) √5 /2
(E) 5/4
Rationale: variance of binomial distribution is n*p*(1-p), n = 3, p = 1/2
variance = 3*1/2*(1-1/2)= 3/4
stddev = sqrt(variance) = sqrt(3)/2
After many trials sample standard deviation is close to theoretical standard deviation = sqrt(3)/2.
C is the answer.
Answer: (C) √3/2
Question: A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days A do the work if he is assisted by B and C on every third day?
(A) 22 days
(B) 15 days
(C) 77 days
(D) 99 days
(E) 11 days
Rationale: A's 2 day's work = (1/20 * 2) = 1/10
(A + B + C)'s 1 day work = (1/20 + 1/30 + 1/60) = 1/10
Work done in 3 days = (1/10 + 1/10) = 1/5
Now, 1/5 work is done in 3 days.
Whole work will be done in (3 * 5) = 15 days.
Answer: B
Answer: (B) 15 days
Question: How many positive 5-digit integers have the odd sum W of their digits?
(A) 9*10^2
(B) 9*10^3
(C) 10^4
(D) 45*10^3
(E) 9*10^4
Rationale: We are looking at numbers between 10000 and 99999 both inclusive.
There are 90000 numbers.
Now for
10000 : sum of digits is odd;
10001 :sum of digits is even;
10002 : sum of digits is odd ; so on and so forth. So every alternate number is such that the sum of digit is odd.
(Exception for the above statement :
When it is 10009 the sum is even and for 10010 again the sum is even; But if you look at 10019 :sum is odd; 10020 : sum is odd
and this pattern continues so basically the number of odd sum of digits and even sum of digits are equal)
This means exactly half of the numbers will have odd sum W of their digits. i.e 45000
Answer :D
Answer: (D) 45*10^3
Question: A company organized a recruiting process for 3 vacant positions of assistant manager for its product launches. The company's efforts yielded 13 eligible candidates. How many sets of 3 candidates can the company choose to fill the 3 assistant manager positions?
(A)  2,060
(B)  1,320
(C)  545
(D)  315
(E)  286
Rationale: 13*12*11/3*2*1 = 286
E
Answer: (E)  286
Question: A committee of 6 is chosen from 8 men and 5 women so as to contain at least 2 men and 3 women. How many different committees could be formed if two of the men refuse to serve together?
(A) 635
(B) 700
(C) 1404
(D) 2620
(E) 3510
Rationale: 8 Men - 5 Women
Choose 6 ( two cases)
Case 1:2 men, 4 women
No of ways to choose 2 men out of 8 is 8C2 . This includes that one case in which the two men who refuse to serve together are included. So men can be chosen in 8C2 - 1 ways.
No. of ways to choose 4 women out of 5 is 5C4.
Number of ways of choosing 2 men and 4 women = (8C2 - 1)*(5C4) = 27*5 = 135
Case 2: 3 men, 3 women
No of ways to choose 3 men out of 8 is 8C3. No of ways to choose those two men together is 6C1 (You choose them and choose one more to make 3). So men can be chosen in 8C3 - 6C1 ways.
No of ways to choose 3 women out of 5 is 5C3.
Number of ways of choosing 3 men and 3 women = (8C3 - 6C1)*(5C3) = 500
Total number of ways = 135 + 500 = 635
ANSWER:A
Answer: (A) 635
Question: John want to buy a $100 Trouser at the store, but he think itâ€™s too expensive. Finally, it goes on sale for $70. What is the percent decrease?
(A) 20%
(B) 30%
(C) 40%
(D) 50%
(E) 60%
Rationale: The is always the difference between our starting and ending points. In this case, itâ€™s 100 â€“ 70 = 30. The â€œoriginalâ€ is our starting point; in this case, itâ€™s 100. (30/100)*100 = (0.3)*100 = 30%.
B
Answer: (B) 30%
Question: There are 35 students in a hostel. If the no. of students increases by 7, the expenses of the mess increase by Rs.42/day while the average expenditure per head diminishes by Rs1. Find the original expenditure of the mess?
(A) 34
(B) 39
(C) 42
(D) 45
(E) 49
Rationale: Suppose the average join the mess , total expenditure = 35x + 42
Now, the average expenditure = (35x + 42)/ (35 + 7) = x – 1
or, 35x + 42 = 42x – 42
or, x = 12
Thus the original expenditure of the mess = 35 x 12 = Rs. 42
C
Answer: (C) 42
Question: A man is 46 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
(A) 44 years
(B) 18 years
(C) 20 years
(D) 22 years
(E) 16 years
Rationale: Let the son's present age be x years. Then, man's present age = (x + 24) years.
(x + 46) + 2 = 2(x + 2)
x + 48 = 2x + 4
x = 44.
answer :A
Answer: (A) 44 years
Question: The number of livestock in a farm at the beginning of year 2000 was 100,000. During the year, the number increased by p%. During the next year 2001, there was a famine and the number decreased by q%. A census at the end of year 2001 revealed that the number of livestock in the farm was 100,000. Which of the following expressions is correct?
(A) p > q
(B) q > p
(C) p = q
(D) With the exception of 1 instance, p will be equal to q
(E) There is no relation between p and q
Rationale: Number plugging in will be best strategy for this question.
Let p = 5%,
Per the question 100000(1.05)(1-q/100) = 100000 ---> q = 4.7%. Thus p > q and hence A is the correct answer
Answer: (A) p > q
Question: A number consists of 3 digit whose sum is 10. The middle digit is equal to the sum of the other two and the number will be increased by 99 if its digits are reversed. The number is:
(A) 145
(B) 253
(C) 370
(D) 352
(E) 300
Rationale: Explanation:
Let the middle digit be x. Then, 2x = 10 or x = 5.
So, the number is either 253 or 352. Since the number increases on reversing the digits, so the hundred's digit is smaller than the unit's digit. Hence, required number = 253.
ANSWER IS B
Answer: (B) 253
Question: A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
(A) 2 sec
(B) 6 sec
(C) 7 sec
(D) 8 sec
(E) 4 sec
Rationale: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [110 * 3/55] sec = 6 sec
Answer:B
Answer: (B) 6 sec
Question: The owner of an electronic store charges his customer 9% more than the cost price. If a customer paid 1,26440 for an LED T.V., then what was the original price of the T.V.?
(A) 115000
(B) 115500
(C) 116000
(D) 117000
(E) 118000
Rationale: Selling Price = 109% of CP;
:. CP = 126440 × 100/109 = 116000
D)
Answer: (D) 117000
Question: If x is an odd negative integer and y is an even integer, which of the following statements must be true?
I. (3x - 2y) is odd
II. xy^2 is an even negative integer
III. (y^2 - x) is an odd negative integer
(A) I only
(B) II only
(C) I and II
(D) I and III
(E) II and III
Rationale: If x is an odd negative integer and y is an even integer, which of the following statements must be true?
I. (3x - 2y) is odd
3x - is always negative and odd
2y - can be 0, when y=0, or always even integer (positive or negative)
odd integer +/- even integer = always odd
I statement is always true
II. xy^2 is an even negative integer
y can be 0 => xy^2 = 0 (non-negative even) => II statement is not true
III. (y^2 - x) is an odd negative integer
y can be 0 => -x will be positive => III statement is not true
basing on above, only I statement will always be true
answer is A
Answer: (A) I only
Question: If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, what is the average marks of all the students?
(A) 53.23
(B) 54.68
(C) 51.33
(D) 50
(E) 52
Rationale: Explanation:
Average marks of batch 1 = 50
Students in batch 1 = 55
Total marks of batch 1 = 55 × 50
Average marks of batch2 = 55
Students in batch2 = 60
Total marks of batch2 = 60 × 55
Average marks of batch3 = 60
Students in batch3 = 45
Total marks of batch3 = 45 × 60
Total students = 55 + 60 + 45 = 160
Average marks of all the students
=(55×50)+(60×55)+(45×60)/160
=275+330+270/16
=875/16=54.68
Answer: Option B
Answer: (B) 54.68
Question: A room is 15m long, 4m broad and 3m height. Find the cost of white washing its four walls at 50p per m2 ?
(A) 33
(B) 57
(C) 55
(D) 99
(E) 12
Rationale: 2 *3(15 + 4) = 114
114 * 1/2 = Rs.57
Answer: B
Answer: (B) 57
Question: In a camp, there is a meal for 120 men or 200 children. If 170 children have taken the meal, how many men will be catered to with remaining meal?
(A) 30
(B) 20
(C) 18
(D) 57
(E) 63
Rationale: There is a meal for 200 children.
170 children have taken the meal.
Remaining meal is to be catered to 30 children.
Now, 200 children 120 men.
30 children = (120/200)x 30 = 18 men.
C
Answer: (C) 18
Question: A family had dinner in a restaurant and paid $30 for food. They also had to pay 9.5% sale tax and 10% for the tip. How much did they pay for the dinner?
(A) $35.83
(B) $35.84
(C) $35.85
(D) $35.86
(E) $35.87
Rationale: SOLUTION
They paid for food, sales tax and tip, hence
total paid = $30 + 9.5% * 30 + 10% * 30 = $35.85
Answer C
Answer: (C) $35.85
Question: Two coins are tossed, find the probability that two Tails are obtained
(A) 1/3
(B) 1/4
(C) 1/5
(D) 1/7
(E) 2/3
Rationale: The sample space S is given by.
S = {(H,T),(H,H),(T,H),(T,T)}
Let E be the event "two heads are obtained".
E = {(T,T)}
P(E) = n(E) / n(S) = 1/4
B
Answer: (B) 1/4
Question: Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 7 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered?
(A) 60
(B) 56
(C) 84
(D) 90
(E) 108
Rationale: B is the answer....
D = TS where D=distance, T=Time and S=Speed
To travel half distance, (2+2T) = 7T ==> T = 2/5 ==> 24 minutes
To travel double distance, 2(2+2T) = 7T ==> 2 ==>80 minutes
Difference, 56 minutes
B
Answer: (B) 56
Question: The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 13 runs. Find his average in all the 30 matches?
(A) 31
(B) 67
(C) 29
(D) 97
(E) 27
Rationale: Total score of the batsman in 20 matches = 800.
Total score of the batsman in the next 10 matches = 130.
Total score of the batsman in the 30 matches = 930.
Average score of the batsman = 930/30 = 31.
Answer: A
Answer: (A) 31
Question: A certain airline's fleet consisted of 110 type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired 3 of the TYPE A planes and acquired 4 new type B plans. How many years did it take before the number of type A planes left in the airline's fleet was less than 50 percent of the fleet?
(A) 15
(B) 16
(C) 17
(D) 18
(E) 19
Rationale: Let x be the number of years.
4x > 110 - 3x
7x > 110
x > 15 + 5/7
The answer is B.
Answer: (B) 16
Question: The circumferences of the wheels of a carriage are 6 3/14 dm and 8 1/18 dm. What is the least distance in which both wheels simultaneously complete an integral number of revolutions ? How often will the points of the two wheels which were lowest at the time of starting touch the ground together in 1 kilometre ?
(A) 47
(B) 24
(C) 45
(D) 34
(E) 56
Rationale: LCM of 6 3/14 dm and 8 1/18 dm =435/2=217 1/2 dm
and the required no. of revolutions = 2*10000/435= 45.9
The required answer =45 times
Answer is C
Answer: (C) 45
Question: A tour group of 25 people paid a total of $630 for entrance to a museum. If this price included a 10% sales tax, and all the tickets cost the same amount, what was the face value of each ticket price without the sales tax?
Choices
(A) $22.68
(B) $23.94
(C) $24
(D) $25.20
(E) $30
Rationale: A.
Answer: (A) $22.68
Question: What is the next number in the sequence below?
1 4 9 16 25 36 49 64__ ?
(A) 121
(B) 100
(C) 49
(D) 64
(E) 81
Rationale: as the series of numbers are squares of numbers
1^2=1
2^2=4
3^2=9
and so on
therefore 9^2=81
ANSWER:E
Answer: (E) 81
Question: A rectangular swimming pool is 20 feet by 28 feet. A deck that has uniform width surrounds the pool. The total area of the pool and deck is 884 square feet. What is the width of the deck?
(A) 2 feet
(B) 2.5 feet
(C) 3 feet
(D) 4 feet
(E) 5 feet
Rationale: Assume the width of the deck = x
Area of pool and deck = (20 + 2x)*(28 + 2x) =884 {The deck is present at both ends of the length and the breadth, hence we need to add 2x}
(20 + 2x)*(28 + 2x) =884 can be written as
(10 + x)*(14 + x) = 221
140 + 24x + x^2 = 221
x^2 + 24x - 81 = 0
(x + 27)(x - 3) = 0
Hence x = -27 or 3. But a length cannot be negative
Hence width of the deck = x = 3
Correct option: C
Answer: (C) 3 feet
Question: The probability that B can shoot a target two out of two times is 0.35. What is the probability that the target will be missed by B immediately after such two shots?
(A) 0.25
(B) 0.65
(C) 0.75
(D) 0.4
(E) 0.8
Rationale: Suppose there are total 'x' shots.
B shoots 2 out of 2 times. means out of x shots (x>2) B shots 2 out of 2 ----> B shots at least 2 out of x.
therefore, 2/x = 0.25 (given)
the target will be missed by B immediately after such two shots : this means he can shot just twice ...the third shot cannot happen which means he missed (x-2) shots.
thus, the probabilty of missing just after 2 shots is (x-2)/x.
(x-2)/x = 1 - 2/x
= 1 - 0.35
= 0.65
Answer : D
Answer: (D) 0.4
Question: Rectangular Floors X and Y have equal area. If Floor X is 8 feet by 18 feet and Floor Y is 9 feet wide, what is the length of Floor Y, in feet?
(A)  13 1/2
(B)  18
(C)  18 3/4
(D)  21
(E)  16
Rationale: The area of a rectangle is: Area = length x width
We are given that floor X is 8 feet by 18 feet and that floor Y is 9 feet wide. So we can say:
length of X = 8
width of X = 18
width of Y = 9
length of Y = n
We also can say:
Area of Floor X = Area of Floor Y
(length of X)(width of X) = (length of Y)(width of Y)
(8)(18) = 9n
(8)(2) = n
16 = n
Answer E.
Answer: (E)  16
Question: When 2/9 of the votes on a certain resolution have been counted, 3/4 of those counted are in favor of the resolution. What fraction x of the remaining votes must be against the resolution so that the total count will result in a vote of 2 to 1 against the resolution?
(A) 11/14
(B) 13/18
(C) 4/7
(D) 3/7
(E) 3/14
Rationale: If we use variable for total votes there will be too many fractions to manipulate with, so pick some smart #: let set total # of votes is 18.
2/9 of the votes on a certain resolution have been counted--> 4 counted and 18-4=14 votes left to be counted;
3/4 of those counted are in favor of the resolution--> 3 in favor and 1 against;
Ratio of those who voted against to those who voted for to be 2 to 1 there should be total of 18*2/3=12 people who voted against, so in the remaining 14 votes there should be 12-1=11 people who voted against. Thus x=11/14 of the remaining votes must be against.
Answer: A.
Answer: (A) 11/14
Question: How many positive integers less than 250 are there such that they are multiples of 15 or multiples of 16?
(A) 28.
(B) 29.
(C) 30.
(D) 31.
(E) 32.
Rationale: 250/15 = 16 (plus remainder) so there are 16 multiples of 15
250/16 = 15 (plus remainder) so there are 15 multiples of 16
We need to subtract 1 because 15*16 is a multiple of both so it was counted twice.
The total is 16+15-1 = 30
The answer is C.
Answer: (C) 30.
Question: A boy can reach a certain place in 18 hours. If he reduces his speed by 1/30th, he goes 3 km less in that time. Find his speed.
(A) 5 km/hr.
(B) 6 km/hr
(C) 8 km/hr
(D) 14 km/hr
(E) None of these
Rationale: Explanation :
Solution: Let the speed be x km/hr. then,
18x - (18 * 29x/30) = 3
=> 3X/5= 3
=> x = 5 km/hr.
Answer : A
Answer: (A) 5 km/hr.
Question: There are 6 identical pens and 8 identical books. In how many different ways can a person select at least one object from this set?
(A) 14
(B) 28
(C) 45
(D) 62
(E) 75
Rationale: We can select from 0 to 6 pens and from 0 to 8 books.
Thus the total possible ways to select objects is 7*9 = 63
We must subtract 1 for the case with 0 pens and 0 books.
The answer is D.
Answer: (D) 62
Question: A boat takes 19 hours for travelling downstream fro poin A to point B and coming back to a point C midway between A and B. If the velocity of the stream is 4 kmph and the speed of the boat in still water is 14 kmph, what is the distance between A and B?
(A) 180 km
(B) 190 km
(C) 220 km
(D) 230 km
(E) None
Rationale: Sol.
Speed downstream = (14 + 4) km/hr = 18 km/hr;
Speed upstream = (14 - 4) km/hr = 10 km/hr.
Let the distance between A and B be x km. Then,
x/18 + (x/2)/10 = 19 ⇔ x/18 + x/20 = 19 ⇒ x = 180 km.
Answer A
Answer: (A) 180 km
Question: If the cost price of 10 articles is same as the selling price of 25 articles. Find the gain or loss percentage?
(A) 30% Gain
(B) 30% Loss
(C) 40% Gain
(D) 60% Loss
(E) 50% Loss
Rationale: Explanation:
10 cp = 25 sp
Cost price CP = 25
Selling price SP = 10
Formula = (SP-CP)/CP * 100 = (10 - 25)/25 * 100 = 60 % Loss
Answer: Option D
Answer: (D) 60% Loss
Question: If 5 women or 8 girls can do a work in 84 days. In how many days can 10 women and 5 girls can do the same work ?
(A) 33
(B) 66
(C) 55
(D) 32
(E) 88
Rationale: Given that 5 women is equal to 8 girls to complete a work so, 10 women=16 girls. Therefore 10women +5girls=16girls+5girls=21girls. 8 girls can do a work in 84 days then 21 girls= (8*84/21)=32days. Therefore 10 women and 5 girls can a work in 32days
Answer: D
Answer: (D) 32
Question: If 1/12 of the passengers on a ship are from North America, 1/4 are Europeans, 1/9 are from Africa, 1/6 are from Asia and the remaining 42 people are citizens of other continents, then how many passengers are on board the ship?
(A) 96
(B) 100
(C) 104
(D) 108
(E) 112
Rationale: 1/12 + 1/4 + 1/9 + 1/6 = (3+9+4+6)/36 = 11/18
Let x be the number of passengers on the ship.
42 = (7/18)x
x = 108
The answer is D.
Answer: (D) 108
Question: A women purchased 3 towels @ Rs.100 each, 5 towels @ Rs.150 each and two towels at a certain rate which is now slipped off from his memory. But she remembers that the average price of the towels was Rs.160. Find the unknown rate of two towels?
(A) A)400
(B) B)450
(C) C)500
(D) D)550
(E) E)600
Rationale: 10 * 160 = 1600
3 * 100 + 5 * 150 = 1050
1600 – 1050 = 550
D
Answer: (D) D)550