mathewhe/aqua_rat huggingface dataset:
Question: 7th number in the series....
99,18,36,9,18
(A) 17
(B) 18
(C) 19
(D) 20
(E) 21
Rationale: its 7 th number in the series 99,18,36,9,18,_,?
99 18.....9+9=18*2=36
36 9.......3+6=9*2=18
18 ?........1+8=9*2=18
ANSWER:B
Answer: (B) 18
Question: Given 5^x, for any real integer of x, which of the following is a possible resultant?
(A) 15,620
(B) 15,652
(C) 15,623
(D) 15,653
(E) 15,625
Rationale: Given that the answers have different last digits, there are several ways to solve this, but the most straight forward way is to check the algorithm. 5^x has a cycle of 0.
5^1 = 5
5^2 = 25
5^3 = 125
Observe that the last digit of all the resultants of 5^x is 5. If we continue 5^x, the last digit follows the pattern 5, 5, 5, 5, 5, 5, .... So, all we need look for is the last digit in the pattern, 5.
Answer: E
Answer: (E) 15,625
Question: If x = 1/8 and y = -1/2, what is the value of the expression -2x – y^2?
(A) -3/2
(B) -1/2
(C) 1
(D) 3/2
(E) 7/4
Rationale: -2X- y^2
-2x1/8 - (1/2)^2
-1/4-1/4
-1/2
B correct
Answer: (B) -1/2
Question: On a shelf, 2 books of Geology, 2 books of Sociology and 5 of Economics are to be arranged in such a way that the books of any subject are to be together. Find in how many ways can this be done?
(A) 2880
(B) 2778
(C) 2682
(D) 8222
(E) 6282
Rationale: Explanation:
There are books of 3 subjects (Geology, Sociology and Economics), hence they can be arranged in 3! (3 * 2 * 1) = 6 ways.
Further, in each category (subject), books are to be arranged in different order, we get,
Required number of ways: 3! * [2! * 2! * 5!] = 2880
ANSWER: A
Answer: (A) 2880
Question: What is the value of m and n ?
if log3m/log3n=log 52
(A) 1,5
(B) 2,5
(C) 3,5
(D) 4,5
(E) 2,3
Rationale: log (base a) b=log(base n)b/log(base n)a
here base are same in reverse way of formula
so
log(base n)m=log(base 5) 2
hence
n=5,m=2
ANSWER:B
Answer: (B) 2,5
Question: In what ratio should a variety of oil costing Rs. 9 per ltr be mixed with another variety of oil costing Rs. 17.25 per ltr to obtain a mixture costing Rs. 11.75 per ltr?
(A) 4 : 1
(B) 1 : 3
(C) 3 : 1
(D) 1 : 2
(E) 2 : 1
Rationale: Let us say the ratio of the quantities of cheaper and dearer varieties = x : y
By the rule of allegation, x/y = (17.25 - 11.75) / (11.75 - 9) = 22/11=2/1
ANSWER:E
Answer: (E) 2 : 1
Question: A small beaker is 1/2 filled with salt water. Another beaker, which has five times the capacity of the small beaker, is 1/2 filled with fresh water. After dumping all of the salt water from the small beaker into the large beaker, to what fraction of its capacity will the large beaker be filled?
(A) 2/5
(B) 3/5
(C) 3/10
(D) 7/20
(E) 11/20
Rationale: 1/2 of the small beaker is 1/10 of the large beaker.
1/10 + 1/2 = 3/5
The answer is B.
Answer: (B) 3/5
Question: A train 120 m long running at 60 kmph crosses a platform in 35 sec. What is the length of the platform?
(A) 338
(B) 277
(C) 463
(D) 456
(E) 271
Rationale: D = 60 * 5/18 = 35 = 583 – 120 = 463
Answer: C
Answer: (C) 463
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively . If they cross each other in 25 seconds, what is the ratio of their speeds?
(A) 1:3
(B) 4:1
(C) 2:3
(D) 3:2
(E) 3:4
Rationale: Let the speed of the trains be x and y respectively
length of train1 = 27x
length of train2 = 17y
Relative speed= x+ y
Time taken to cross each other = 25 s
= (27x + 17 y)/(x+y) = 25
= (27x + 17 y)/ = 25(x+y)
= 2x = 8y
=x/y = 8/2 = 4/1 i.e 4:1
Answer :B
Answer: (B) 4:1
Question: If Jake loses 12 pounds, he will weigh twice as much as his sister. Together they now weigh 156 pounds. What is Jake’s present weight, in pounds?
(A) 108
(B) 135
(C) 139
(D) 147
(E) 188
Rationale: Lets say J is the weight of Jack and S is the wt of his sister.
If he loses 8 pounds, he s twice as heavy as his sister.
J-12=2*S
Also, together they weight 156 pounds
J+S=156
solvong the 2 equation ,we get J=108 pounds !
A
Answer: (A) 108
Question: If the speed of X meters per second is equivalent to the speed of Y meters per minute, what is Y in terms of X? (1 kilometer=1000 meters)
(A) 15x/18
(B) 6x/5
(C) 18x/5
(D) 600x
(E) 60x
Rationale: x=y/60
y = 60x
Answer : E
Answer: (E) 60x
Question: What is the greatest number of three digits which is divisible by 4, 8, 12 ?
(A) 989
(B) 999
(C) 978
(D) 972
(E) 984
Rationale: Greatest number of 3 digits = 999
LCM of 4, 8, 12 = 24
999 ÷ 24= 41, remainder = 15
Hence, greatest number of four digits which is divisible by 4,8,12
= 999 - 15 = 984
answer : E
Answer: (E) 984
Question: Three-twentieths of the members of a social club are retirees who are also bridge players, eight-twentieths of the members are retirees, and one-half of the members are bridge players. If 120 of the members are neither retirees nor bridge players, what is the total number of members in the social club?
(A) 240
(B) 160
(C) 360
(D) 400
(E) 480
Rationale: {Total} = {Retirees} + {Bridge players} - {Both} + {Neither}
x = 8/20*x + x/2 - 3/20*x + 120
20x = 8x + 10x - 3x + 120*20 (multiply by 20)
15x = 120*20
x = 160
Answer: B
Answer: (B) 160
Question: In how many ways can the letters D, I, G, I, T, K be arranged so that the two I's are not next to each other?
(A) 36
(B) 48
(C) 72
(D) 96
(E) 240
Rationale: 1 D
2 I
1 G
1 T
1 K
Number of ways these letters can be arranged = 6!/2! (2! to account 2 same Is) = 360
Consider 2 Is as 1 entity and thus the number of arrangements for (II)DGT = 5! = 120
Total allowed cases = 360-120 =240
E is the correct answer.
Answer: (E) 240
Question: Find the invalid no.from the following series 13, 18, 25, 30, 37, 40
(A) 21
(B) 25
(C) 40
(D) 47
(E) 58
Rationale: The differences between two successive terms from the beginning are 7, 5, 7, 5, 7, 5. So, 40 is wrong.
C
Answer: (C) 40
Question: The contents of a certain box consist of 24 carrots and 30 kiwis. How many kiwis must be added to the box so that exactly 30% of the pieces of fruit in the box will be carrrots?
(A)  24
(B)  26
(C)  30
(D)  46
(E)  50
Rationale: carrrots = (carrrots + kiwi + x)*0.3
24 = (30 + 24 + x)*0.3
x = 26.
Answer: B.
Answer: (B)  26
Question: Convert the 12/43 m/s into kilometers per hour?
(A) 3.5 kmph.
(B) 2.5 kmph.
(C) 1 kmph.
(D) 1.5 kmph.
(E) 1.9 kmph.
Rationale: 12/43 m/s = 12/43 * 18/5 = 1 (1/250) = 1 kmph.
ANSWER:C
Answer: (C) 1 kmph.
Question: How many different positive integers exist between 10^3 and 10^4, the sum of whose digits is equal to 2?
(A) 6
(B) 7
(C) 5
(D) 4
(E) 18
Rationale: So, the numbers should be from 1,000 to 10,000
The following two cases are possible for the sum of the digits to be 2:
1. Two 1's and the rest are 0's:
1,001
1,010
1,100
3 numbers.
2. One 2 and the rest are 0's:
2,000
1 number.
Total = 4 numbers.
Answer:D
Answer: (D) 4
Question: The average (arithmetic mean) of four distinct positive integers is 20. If the average of the smaller two of these four integers is 24, which of the following represents the maximum possible value of the largest integer?
(A) 8
(B) 16
(C) 36
(D) 20
(E) 1
Rationale: Let the distinct number be A,B,C, and D
Its given A > B > C > D
also A + B + C + D =80 and A + B = 24 means C + D = 56
Since the question ask for the largest possible number we should choose the least value for A and B,C. So D should be 36. If D=36 then C = 20 > A,B <20
Answer : C
Answer: (C) 36
Question: If 10 bulls can plough 20 identical fields in 3 days working 10 hours a day, then in how many days can 30 bulls plough 32 same identical fields working 8 hours a day?
(A) 8
(B) 7
(C) 5
(D) 2.0
(E) 1
Rationale: Explanation:
M1*D1*W2 = M2*D2*W1
10*3*10*32 = 30*d*8*20
d = 2 days
ANSWER: D
Answer: (D) 2.0
Question: There are 4 sections with 6 questions each. If two questions are selected from each section, the chance of getting different questions is________
(A) 225
(B) 245
(C) 300
(D) 240
(E) 289
Rationale: we have to select two questions from each section so the chances are 6C4.6C4=225
ANSWER:A
Answer: (A) 225
Question: From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?
(A) 231
(B) 756
(C) 125
(D) 451
(E) 123
Rationale: We may have (3 men and 2 women) or (4 men and 1 woman) or (5 men only).
Required number of ways	= (7C3 x 6C2) + (7C4 x 6C1) + (7C5)
= (525 + 210 + 21)
= 756.
Ans: B
Answer: (B) 756
Question: Which of the following is between 23/30 and 17/21?
(A) 1/3
(B) 3/8
(C) 1/2
(D) 5/8
(E) 7/9
Rationale: I see this as a POE (Process of Elimination) and Ballparking (Estimation) question. Not sure if this is the most efficient, but it worked:
1) I estimate 23/30 to be ~3/4+ (approximately slightly greater than 3/4)
2) I estimate 17/21 to be ~4/5+ (approximately slightly greater than 4/5)
3) So now I'm looking for an answer choice that is .75 < x < .80
It should be pretty easy to identify which answer choices are less than .75 (or 3/4) if you have had practice with fractions.
A) clearly wrong - it's less than 3/4
B) also clearly wrong - it's less than 3/4
C) also clearly wrong - it's less than 3/4
D) also clearly wrong - it's less than 3/4
I would just stop here and select E. But to verify:
E) 7/9 ~ .77 which is greater than .75 and less than .80
Answer: (E) 7/9
Question: A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 40%?
(A) 600
(B) 887
(C) 256
(D) 654
(E) 700
Rationale: Cost price = Rs.500
profit = 40% of 500 = Rs.200
Selling price = Cost price + Profit
= 500 + 200 = 700
Answer: E
Answer: (E) 700
Question: The average of first six prime numbers which are between 50 and 90 is
(A) 35.4
(B) 42
(C) 45.7
(D) 64
(E) 67
Rationale: Explanation :
first six prime numbers which are between 50 and 90 = 53, 59, 61, 67, 71, 73
average = (53 + 59 + 61 + 67 + 71 + 73)/6
= 64
Answer : D
Answer: (D) 64
Question: A bicyclist travels uphill from town A to town B for 2 hours at an average speed of 7 miles per hour and returns along the same road at an average speed of 6 miles per hour. What is the bicyclist’s average speed for the round trip, in miles per hour?
(A) (a) 24/5
(B) (b) 5
(C) (c) 26/5
(D) (d) 84/13
(E) (e) 28/5
Rationale: from the uphill we can find out the distance = 7*2 = 14
average speed = total distance/total time
= 28/ (2+ (14/6)) = 84/13
Answer is D.
Answer: (D) (d) 84/13
Question: Two trains are moving at 85 kmph and 70 kmph in opposite directions. Their lengths are 150 m and 100 m respectively. The time they will take to pass each other completely is?
(A) 5 25/31 sec
(B) 7 1/17 sec
(C) 7 2/2 sec
(D) 8 1/2 sec
(E) 7 1/9 sec
Rationale: 70 + 85 = 155 * 5/18 = 775/18 mps
D = 150 + 100 = 250 m
T = 250 * 18/775 = 180/31 = 5 25/31 sec
Answer: A
Answer: (A) 5 25/31 sec
Question: In how many ways a group of 5 male and 2 female be made out of a total of 7 male and 3 female?
(A) 55
(B) 78
(C) 63
(D) 89
(E) 98
Rationale: req no of ways = 7c5*3c2 = 7*6/2*1 * 3 = 63
ANSWER C
Answer: (C) 63
Question: The least number which when subtracted from both the terms of the ratio 4 : 5 to give a ratio less than 14 : 23, is
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: Explanation :
Let x is subtracted. Then, ((4 - x)/(5 - x)) < 14 / 23
23(4 - x) < 14(5 - x) => 9x > 22 = x > 2.4.
Least such number is 3.
Answer : B
Answer: (B) 3
Question: AMS employs 8 professors on their staff. Their respective probability of remaining in employment for 10 years are 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9. The probability that after 10 years at least 8 of them still work in AMS is ?
(A) 0.19
(B) 1.22
(C) 0.00363.
(D) 0.16
(E) none of these
Rationale: Asking atleast 6 of them continue ,
it has 3 cases.
1 all 8 professors continue.
1st case all 8 continue is = 2/10*3/10*4/10*5/10*6/10*7/10*/8/10*9/10=
=>0.00363.
C
Answer: (C) 0.00363.
Question: A dishonest milkman wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing Rs.33 per litre so as to make a profit of 30% on cost when he sells the resulting milk and water mixture for Rs.36 In what ratio should he mix the water and milk?
(A) 1:20
(B) 23:120
(C) 1:8
(D) 1:4
(E) 6:11
Rationale: water = w (liter)
Milk = m (liter)
==> Cost = Price x Quantity = 0.33m
==> Revenue = Price x Quantity = 0.36(m + w)
==> Profit =0.36(m+w) - 0.33m = 0.3*(0.33m)[30% of cost]
==> 0.36m + 0.36w - 0.33m = 0.099m
==> 0.069m = 0.36w
==> m/w = 0.36/0.069 = 120/23
--OR--
w/m = 23/120
B is correct.
Answer: (B) 23:120
Question: What is the largest 4 digit number exactly divisible by 88?
(A) 8844
(B) 9944
(C) 7744
(D) 6644
(E) 5544
Rationale: Largest 4 digit number = 9999
9999 ÷ 88 = 113, remainder = 55
Hence largest 4 digit number exactly divisible by 88
= 9999 - 55 = 9944
Answer is B.
Answer: (B) 9944
Question: During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?
(A) 32
(B) 40
(C) 55
(D) 64
(E) 80
Rationale: Total smelt = x.
Then, 0.5*80+0.3(x-80)=0.4*x --> x=160 --> 0.4*x=64.
Answer: D.
Answer: (D) 64
Question: A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. The area of the lawn is 2109 sq. m. what is the width of the road?
(A) 5 M
(B) 4 M
(C) 2 M
(D) 3 M
(E) 6 M
Rationale: AREA OF THE PARK = 60 * 40 = 2400 M^2
GIVEN AREA OF THE LAWN = 2109 M^2
TOTAL AREA OF THE CROSS ROADS = 2400 - 2109 = 291 M^2
ASSUME THAT THE WIDTH OF THE CROSS ROAD = X
= AREA OF ROAD 1 + ROAD 2- COMMON AREA CROSS ROAD
= 60X + 40 X - X^2
TOTAL AREA OF CROSS ROAD = 60X+40X-X^2 = 291 M^2
(X-97)(X-3) = 0
X =3
ANSWER D
Answer: (D) 3 M
Question: A family of 4 brothers and 3 sisters is to be arranged in a row, for a photograph. In how many ways can they be seated if all the sisters not together ?
(A) 4270
(B) 4820
(C) 4320
(D) 4620
(E) 4520
Rationale: Since the 3 sisters are inseperable, consider them as one single unit. This together with the 4 brothers make 5 persons who can be arranged among themselves in 5! ways. In everone of these permutations, the 3 sisters can be rearranged among themselves in 3!. Hence the total number of arrangement required = 5!x 3! =120x6=720. The number of arrangements of all the 7 persons without any restriction =7!= 5040 Number arrangement required =5040-720 =4320. Answer : C
Answer: (C) 4320
Question: The avg weight of A,B & C is 55 kg. If D joins the group, the avg weight of the group becomes 60 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 58 kg. What is the weight of A?
(A) 56
(B) 65
(C) 75
(D) 86
(E) 90
Rationale: A + B + C = 3 *55 = 165
A + B + C + D = 4 * 60 = 240 ---- (i)
So, D = 75& E = 75 + 3 = 78
B + C + D +E = 58 * 4 = 232 --- (ii)
From Eq. (i) & (ii)
A-E = 240 – 232 = 8
A = E +8 = 78 + 8 = 86
Answer : D
Answer: (D) 86
Question: When a certain number X is divided by 143, the remainder is 45. Which of the following numbers, if added to X, would result in a number divisible by 16?
(A) 7
(B) 10
(C) 34
(D) 47
(E) 55
Rationale: So the number given is N = 143Q + 45
If this number is divided by 13, the remainder would be R[(143Q + 45)/13]
Since 143 is divisible by 13 , the product 143Q gives no remainder
This means the remainder of 45/13 should be the remainder of the entire number N
which is 6
To make it divisible by 13 , the smallest number that can be added = 16 - 6 = 10
Correct Option : B
Answer: (B) 10
Question: A clock shows the time as 9 a.m. If the minute hand gains 5 minutes every hour, how many minutes will the clock gain by 6 p.m.?
(A) 45 minutes
(B) 55 minutes
(C) 35 minutes
(D) 25 minutes
(E) 40 minutes
Rationale: there are 9 hours in between 9 a.m. to 6 p.m.
9*5=45 minutes.
ANSWER:A
Answer: (A) 45 minutes
Question: A rich aristocrat decided that he would give every man rs.45 and every women Rs.60.Only one nineth of the man and only one twelfth of the women collected their dues .Can u tell me how much money thath aristocrat spent if their were 3552 people in total
(A) 17760
(B) 18540
(C) 16320
(D) 14640
(E) 15640
Rationale: iman=45 and 1women=60 then 1/9 man=1/9*45=5 and 1/12 of women=1/12*60=5
total people 3552 =3552*5=17760
ANSWER:A
Answer: (A) 17760
Question: Given that A and B are events such that
H(A)= 0.03
H(B)=0.18
H(AnB)=0.18
find H (A|B) and H(A|B)
(A) 1/7
(B) 1/5
(C) 1/3
(D) 1/2
(E) 1/6
Rationale: Here, A and B are events
H(A|B) = H(AnB)/H(B) = 0.18/0.18 = 1
H(A|B) = H(AnB)/H(A) = 0.18/0.03 = 1/6.
Answer is E
Answer: (E) 1/6
Question: 12 buckets of water fill a tank when the capacity of each bucket is 81 litres. How many buckets will be needed to fill the same tank, if the capacity of each bucket is 9 litres?
(A) 96
(B) 110
(C) 100
(D) 90
(E) 108
Rationale: Capacity of the tank = (12 Ã— 81) litre
Number of buckets required of capacity of each bucket is 17 litre = 12 Ã—81/9=12Ã—9=108
Answer is E
Answer: (E) 108
Question: If â€˜KARNATAKAâ€™ is coded as â€˜BAIEABABAâ€™, then â€˜BIHARâ€™ is coded as
(A) BARHI
(B) BHARI
(C) BHIAR
(D) BIHAI
(E) BIHAR
Rationale: M=13,1+3=4=D
A=1=A
SIMILARLY,
B=2=B
I=9=I
H=8=H
A=1=A
R=18=1+8=9=I
SO ANS IS
BIHAI
ANSWER:D
Answer: (D) BIHAI
Question: Of the three numbers, the first is twice as second and three times the third. The average of the three numbers is 33, and the three numbers in order are?
(A) 54,27,18
(B) 98,49,33
(C) 126,63,36
(D) 108,54,36
(E) None of these
Rationale: Explanation :
Solution: Let A =x,
B =x/2, C = x/3.
=x + x/2 + x/3 / 3 = 33
By solving we will get x = 54.
Hence A= 54
B= 54/2= 27
C= 54/3 = 18
Answer : A
Answer: (A) 54,27,18
Question: A circular swimming pool is surrounded by a concrete wall 4ft wide. If the area of the concrete wall surrounding the pool is 11/25 that of the pool, then the radius of the pool is?
(A) 10ft
(B) 20ft
(C) 30ft
(D) 40ft
(E) 50ft
Rationale: Explanation:
let the radius of the pool be Rft
radius of the pool including the wall = (R+4)ft
area of the concrete wall = π[(R + 4)2 - R2] = π[(R + 4 + R)(R + 4 - R)] = 8π(R + 2) sq feet
⇒ 8π(R + 2) = 11/25πR2 ⇒ 11 R2 = 200(R + 2)
Radius of the pool R = 20ft Answer: B
Answer: (B) 20ft
Question: A certain musical scale has has 13 notes, each having a different frequency, measured in cycles per second. In the scale, the notes are ordered by increasing frequency, and the highest freq is twice the lowest. For each of the 12 lower freq , the ratio of a frequency to the next higher freq is a fixed constant. If the lowest freq is 440 cycles per second, then the freq of the 7th note in the scale is how many cycles/second?
(A) 440 * sqrt 2
(B) 440 *2
(C) 400 * sqrt 2
(D) 320 * sqrt 3
(E) None
Rationale: let the constant be k
F1 = 440
F2 = 440k
F3 = 440 k * k = 440 * k^2
F13= 440 * k^12
we know F13 = 2 *F1 = 2 * 440 = 880
880/440 = k^12
k = twelfth root of 2
for F7...
F7 = 440 * k^6 ( as we wrote for F2 and F3)
F7 = 440 * (twelfth root of 2) ^ 6
F7 = 440 * sqrt (2)
Answer A
Answer: (A) 440 * sqrt 2
Question: How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
(A) 22
(B) 30
(C) 88
(D) 266
(E) 121
Rationale: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50 = 30 sec.
Answer:B:
Answer: (B) 30
Question: Peter obtained 76, 65, 82, 67 and 95 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
(A) A)87
(B) B)99
(C) C)68
(D) D)82
(E) E)75
Rationale: Average = (76 + 65 + 82 + 67 + 95)/5
= 385/5
= 77.
Answer:E
Answer: (E) E)75
Question: Manoj borrowed Rs.3750 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.824.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?
(A) 22877
(B) 5555
(C) 2778
(D) 6787
(E) 1771
Rationale: Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3750.3.6/100 = Rs.824.85
27P = 67500 = 82485
P = (82485 + 67500)/27 = 3055 + 2500 = Rs.5555
Answer: B
Answer: (B) 5555
Question: When a certain shoe store reduces the price of its best-selling style of shoe by 10 percent, the weekly sales of this style increase by 20 percent. Which of the following best describes the resulting change in the store's weekly revenue from sales of this style of shoe?
(A) Revenue decreases by 10%
(B) Revenue decreases by 1%
(C) There is no change in revenue
(D) Revenue increases by 1%
(E) Revenue increases by 8%
Rationale: Old price = 10, old sales = 10 --> old revenue = 100;
New price = 9, new sales = 12 --> new revenue = 108.
Revenue increased by 8%.
Answer: E
Answer: (E) Revenue increases by 8%
Question: Find avrg speed if a man travels at speed of 16km/hr up and 30km/hr dawn at an altitude of 200m.
(A) 22.8
(B) 21.8
(C) 20.8
(D) 28.8
(E) 29.8
Rationale: avg speed=2*x*y/(x+y)
=2*16*30/(16+30)=20.8
ANSWER:C
Answer: (C) 20.8
Question: Nine coins are tossed simultaneously. In how many of the outcomes will the third coin turn up a head?
(A) 2^9
(B) 2^10
(C) 2^8
(D) 3 * 2^9
(E) 3 * 2^10
Rationale: Fix the third coin as H. The remaining 8 coins have 2^8 outcomes.
Ans:C
Answer: (C) 2^8
Question: If 8 men or 12 women can do a piece of work in 40 days, in how many days can the same work be done by 6 men and 11 women?
(A) 10 days
(B) 11 days
(C) 13 days
(D) 15 days
(E) 24 days
Rationale: 8men = 12women (i.e 2men = 3women)
12women 1 day work= 1/40
soln:
6men(9women)+ 11women=20women=?
1 women 1 day work =12*40= 1/480
so, 20 women work= 20/480=1/24
ans: 24 days
ANSWER:E
Answer: (E) 24 days
Question: The vertex of a rectangle are (1, 0), (9, 0), (1, 4) and (9, 4) respectively. If line L passes through the origin and divided the rectangle into two identical quadrilaterals, what is the slope of line L?
(A) 4
(B) 2
(C) 1/4
(D) 2/5
(E) 5/6
Rationale: If line L divides the rectangle into two identical quadrilaterals, then it must pass through the center (5, 2). The slope of a line passing through (0,0) and (5, 2) is 2/5.
The answer is D.
Answer: (D) 2/5
Question: A man sells a horse for Rs.920 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse?
(A) 287
(B) 279
(C) 267
(D) 860
(E) 940
Rationale: CP = SP + 1CP = SP - g
920 + x = 980 - 2x
3x = 60 => x
=20
CP = 920 + 20
= 940
Answer:E
Answer: (E) 940
Question: Find 103 ×× 10
(A) 106/19
(B) 108/12
(C) 108/19
(D) 108/15
(E) 108/11
Rationale: By taking 100 as a base we can easily get the answer for the above question within seconds.
103 is 3 more than 100 and 105 is 5 more than 100 So we will write
Add the excess of the second number to first number or excess of first number to second number as show below to get left most digits and multiply the excesses to get the right most two digits.
Note: Always remember if you get a single digit number put zero in the left two make it a two digit number to get the right most two digits.
Answer:D
Answer: (D) 108/15
Question: Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 12 cm.
(A) 335 cm2
(B) 228 cm2
(C) 285 cm2
(D) 825 cm2
(E) 725 cm2
Rationale: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (20 + 18) * (12)
= 228 cm2
Answer: B
Answer: (B) 228 cm2
Question: A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the sum of the profits of B and C. Find the total profit?
(A) 2679
(B) 2976
(C) 2690
(D) 3000
(E) 2698
Rationale: A:B:C = 5:6:4
Let the total profit = 100 - 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 - 160/3 = 140/3
A-(B+C) = 160/3 - 140/3 = 20/3
20/3 ---- 200
100 ---- ? => 3000
Answer:D
Answer: (D) 3000