mathewhe/aqua_rat huggingface dataset:
Question: A parts store is having a store-wide sale of 10% off all merchandise. An out-of-stock part can be backordered, but at a 20% fee. If a customer orders an out-of-stock part whose presale price was $40, how much will he pay?
(A)  $41.40
(B)  $42.00
(C)  $42.60
(D)  $43.20
(E)  $43.80
Rationale: price = (original price - 10% decrease) + 20% increase
price = [40 * (90/100)] * (120/100) = 40 * (.90) * (1.2) = 36 * 1.2 = 43.20
The answer is D.
Answer: (D)  $43.20
Question: An ice cream store received shipments of ingredients on Tuesday and Wednesday. Tuesday's shipment had 6 different packages, with an average (arithmetic mean) of 11 and 2/3 pounds. Wednesday's shipment included 7 packages, weighing an average of 9 and 3/7 pounds. What was the average package weight, in pounds, of the shipments received on both days?
(A) 9 and 6/7 pounds
(B) 10 and 1/10 pounds
(C) 10 and 2/5 pounds
(D) 136/13 pounds
(E) 11 and 1/7 pounds
Rationale: Solution: Average weight = Total weight/number of packages. The total weight on Tuesday was 6 * (11 and 2/3 pounds), or 70 pounds. The total weight on Wednesday was 7 * (9 and 3/7 pounds), or 66 pounds. The sum of the weights for both days is 66 + 70, or 136 pounds. The average is 136 pounds/13 packages.
answer: D
Answer: (D) 136/13 pounds
Question: If 2464 / 1.12 = 2200, then 246.4 / 11.2 is equal to?
(A) 24
(B) 23
(C) 22
(D) 21
(E) 25
Rationale: Answer
Given expression 246.4 / 11.2 = 2464 / 112
= 2464 / (1.12 x 100)
= 2200 / 100
=22
Correct Option: C
Answer: (C) 22
Question: Fresh grapes contain 90% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 25 kg of fresh grapes?
(A) 2 kg
(B) 2.4 kg
(C) 3.12 kg
(D) 10 kg
(E) none of these
Rationale: The weight of non-water in 25 kg of fresh grapes (which is 100-90=10% of whole weight) will be the same as the weight of non-water in x kg of dried grapes (which is 100-20=80% of whole weight), so 25âˆ—0.1=xâˆ—0.8--> x=3.12
Answer: C.
Answer: (C) 3.12 kg
Question: On flipping 3 coins together what is the outcomes for at least One tail and three heads?
(A) 1/7
(B) 3/8
(C) 3/11
(D) 4/8
(E) 5/13
Rationale: Sample space, S = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}
Favorable outcomes for at least two heads
= favorable outcomes for exactly two heads and favorable outcomes for more than two heads
= {HHT, HTH, THH,HHH}
4/8
D
Answer: (D) 4/8
Question: An agent wants to sell x% of a list of 10,000 apartments in a residential area. After market price decreases, the agent must reduce this selection by (x − 8)%. In terms of x, how many apartments will he be able to sell?
(A) x*x – 8x
(B) (x)(108 – x)
(C) (100)(108 – x)
(D) (100)(92 – x)
(E) (x-8)/100
Rationale: Based on the answer choices and the question, this question begs the use of x=8 as a sample number.
Initial = 8%*10000 = 800
Reduction = 8-8=0%, so no math required here to calculate the reduction; just make sure that you can calculate 800 in your answer.
A. x*x – 8x = 0; No
B. (x)(108 – x) = 800; Winner!
C. (100)(108 – x) > 800; No
D. (100)(92 – x) > 800; No
E. (x-8)/100 = 0; No
B
Answer: (B) (x)(108 – x)
Question: If four coins are tossed, the probability of getting two heads and two tails i
(A) 3/8
(B) 3/6
(C) 3/9
(D) 3/1
(E) 3/2
Rationale: Since four coins are tossed, sample space = 24
Getting two heads and two tails can happen in six ways.
n(E) = six ways
p(E) = 6/24 = 3/8
Answer:A
Answer: (A) 3/8
Question: A boat crossed a lake from North to East at the speed of 7 km/h, entered a river and covered twice as much distance going upstream at 6 km/h. It then turned around and stopped at the south shore of the lake. If it averaged 3.8 km/h that day, what was its approximate downstream speed?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: One way of solving this is:
Speed of boat on still water (lake)=7kmph
Speed upstream = 6kmph = speed in still water - speed of river => speed of river = 1kmph
=>Speed downstream = speed in still water + speed of river = 7+1 =8kmph
Ans is E
Answer: (E) 8
Question: At a dinner party,3 people are to be seated around a circular table. Two seating arrangements are considered different only when the positions of the people are different relative to each other. What is the total number of different possible seating arrangements for the group?
(A) 1) 5
(B) 2) 10
(C) 3) 24
(D) 4) 2
(E) 5) 120
Rationale: for number of distinct arrangements of 'n' items around a circular table, we get the arrangements by way of (n-1)!
in this case, there are 3 guests, so number of distinct arrangements = 2! = 2
Answer : D
Answer: (D) 4) 2
Question: A man can swim in still water at 9 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
(A) 1.7
(B) 1.9
(C) 3
(D) 1.5
(E) 1.2
Rationale: M = 9
S = x
DS = 9 + x
US = 9 - x
9 + x = (9 - x)2
9 + x = 18 -2x
3x = 9
x = 3
Answer:C
Answer: (C) 3
Question: If w/x = 1/3 and w/y = 4/15, then (x + y)/y =
(A) 4/5
(B) 6/5
(C) 7/5
(D) 8/5
(E) 9/5
Rationale: W/X = 1/3=>x=3w and W/Y = 4/15=>y=15/4w
(X+Y)/Y = (3w+15/4w)/(15/4w) = (27/4w)/(15/4w) = 9/5
Correct Option: E
Answer: (E) 9/5
Question: In a city, 40% of the adults are illiterate while 85% of the children are literate. If the ratio of the adults to that of the children is 2 : 3, then what percent of the population is literate ?
(A) 20%
(B) 25%
(C) 50%
(D) 75%
(E) 80%
Rationale: ET POPULATION 100
RATIO IS 2:3
So adults=2*100/5=40 chldren=3*100/5=60
illterate adult 40*40/100=16
literate adult 24
literate chldren 51
so total literate is 75
ANSWER:D
Answer: (D) 75%
Question: If x+y=4 and x2y3 + y2x3=36, what is the value of xy?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: xy=3
As x+y=4
x2y3+y2x3=36
x2y2(y+x)=36
Substituting x+y
x2y2=4
xy=4
ANSWER:D
Answer: (D) 4
Question: Trapezoid JKLM in the x-y plane has coordinates J = (–2, –1), K = (–2, 1), L = (6, 7), and M = (6, –1). What is its perimeter?
(A)  34
(B)  36
(C)  31
(D)  40
(E) (F) 42
Rationale: JK =2
LM = 11
KL =using distance formula 10
JM = using distance formula 8
Sum of all is 31
C
Answer: (C)  31
Question: The two lines y = x and x = -2 intersect on the coordinate plane. If z represents the area of the figure formed by the intersecting lines and the x-axis, what is the side length of a cube whose surface area is equal to 6z?
(A) 16
(B) 8√2
(C) 8
(D) √2
(E) (√2)/3
Rationale: 800score Official Solution:
The first step to solving this problem is to actually graph the two lines. The lines intersect at the point (-2, -2) and form a right triangle whose base length and height are both equal to 4. As you know, the area of a triangle is equal to one half the product of its base length and height: A = (1/2)bh = (1/2)(2 × 2) = 2; so z = 2.
The next step requires us to find the length of a side of a cube that has a face area equal to 2. As you know the 6 faces of a cube are squares. So, we can reduce the problem to finding the length of the side of a square that has an area of 2. Since the area of a square is equal to s², where s is the length of one of its side, we can write and solve the equation s² = 2. Clearly s = √2 , oranswer choice (D).
Answer: (D) √2
Question: The average of runs of a cricket player of 20 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 6 ?
(A) 96
(B) 106
(C) 158
(D) 116
(E) 122
Rationale: Average = total runs / no.of innings = 32
So, total = Average x no.of innings = 32 * 20 = 640
Now increase in avg = 4 runs. So, new avg = 32+6 = 38 runs
Total runs = new avg x new no. of innings = 38 * 21 = 798
Runs made in the 11th inning = 798-640 = 158
ANSWER:C
Answer: (C) 158
Question: 300 × ? + (12 + 4) × 1/8 = 602
(A) A)4
(B) B)3
(C) C)5
(D) D)2
(E) E)8
Rationale: Explanation:
=> 300 × ? + (12 + 4) × 1/8 = 602
=> 300 × ? = 602 - (12 + 4) × 1/8
=> 300 × ? = 602 - 2 = 600
=> ? = 600/300 = 2
Answer: Option D
Answer: (D) D)2
Question: Walking at the rate of 4 kmph a man cover certain distance in 2 hr 45 min. Running at a
speed of 16.5 kmph the man will cover the same distance in.
(A) 12 min
(B) 25 min
(C) 40 min
(D) 60 min
(E) None of these
Rationale: Explanation :
Distance = Speed * time
4*11/4 = 11km
New Speed = 16.5 kmph
Therefore time = D/S = 11/16.5 = 40min
Answer : C
Answer: (C) 40 min
Question: If C is a whole number, C+1 is a whole number after that. If A is a whole number, what is a whole number before that?
(A) -1
(B) 1
(C) 0
(D) 2
(E) -2
Rationale: Solution:
We know that the number ‘0’ together with the natural numbers gives us the numbers 0, 1, 2, 3, 4, 5, …………… which are called whole numbers.
If A is a whole number and it is greater than 0 then the whole number before that is A – 1, which will always be a whole number.
Again, when A is a whole number and it is equal to 0 then the whole number before that is A – 1 which means 0 – 1 = -1, which is not a whole number.
Therefore, if A is a whole number then the number before that will not always be a whole number.
Answer A
Answer: (A) -1
Question: A can do a piece of work in 4 hours; B and C together can do it in 2 hours, which A and C together can do it in 2 hours. How long will B alone take to do it?
(A) 2hours
(B) 3hours
(C) 4hours
(D) 5hours
(E) 6hours
Rationale: A's 1 hour work = 1/4;
(B + C)'s 1 hour work = 1/2;
(A + C)'s 1 hour work = 1/2
(A + B + C)'s 1 hour work = (1/4 + 1/2) = 3/4
B's 1 hour work = (3/4 - 1/2) = 1/4
B alone will take 4 hours to do the work.
Answer:C
Answer: (C) 4hours
Question: Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm.
(A) 289 cm2
(B) 285 cm2
(C) 287 cm2
(D) 267 cm2
(E) 207 cm2
Rationale: Area of a trapezium
= 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (20 + 18) * (15)
= 285 cm2
Answer: B
Answer: (B) 285 cm2
Question: Adam borrowed some money at the rate of 6% p.a. for the first two years, at the rate of 9% p.a. for the next three years, and at the rate of 14% p.a. for the period beyond four years. If he pays a total interest of 11,900 at the end of nine years, how much money did he borrow?
(A) 10,526
(B) 12,526
(C) 14,000
(D) 16,000
(E) 16,536
Rationale: Let the sum borrowed be x. Then,
(x×6×21/00)+(x×9×3/100)+(x×14×4/100)= 11900
⇒ (3⁄25x + 27⁄100x + 14⁄25x) = 11400 ⇒ 95⁄100x = 11900
⇒ x = (11900×100/95)= 12526
Hence, sum borrowed = 12,526
Answer B
Answer: (B) 12,526
Question: A man has Rs. 544 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
(A) 102
(B) 38
(C) 37
(D) 90
(E) 28
Rationale: Let number of notes of each denomination be x.
Then x + 5x + 10x = 544
⇒ 16x = 544
∴ x = 34.
Hence, total number of notes = 3x = 102
Answer:A
Answer: (A) 102
Question: If r>0, which of the following must be true?
(A) 1 < r
(B) 0 < r < 2
(C) -1 < r < 1
(D) -10 < r
(E) 1/100 < r
Rationale: All we know is that r is some positive number. Right away we can see that D must be true: if r is positive then it MUST be true that it's greater than -10. Still let's check each option.
A. 1 < r. We don't know whether the number is greater than 1, it could be a positive number less than or equal to 1. Discard.
B. 0 < r < 2. The same here: we don't know whether the number is less than 2, it could be more than or equal to 2. Discard.
C. -1 < r < 1. The same as A. Discard.
E. 1/100 < r. We don't know whether the number is greater than 1/100, it could be a positive number less than or equal to 1/100. Discard.
Answer: D.
Answer: (D) -10 < r
Question: A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
(A) 6
(B) 3
(C) 4
(D) 9
(E) 2
Rationale: D = 25 * 60 + 1500 = 3000 m
T = 3000/60 * 18/5 = 180 sec = 3 mins
Answer:B
Answer: (B) 3
Question: A motorcyclist started riding at highway marker A, drove 120 miles to highway marker B, and then, without pausing, continued to highway marker C, where she stopped. The average speed of the motorcyclist, over the course of the entire trip, was 20 miles per hour. If the ride from marker A to marker B lasted 3 times as many hours as the rest of the ride, and the distance from marker B to marker C was half of the distance from marker A to marker B, what was the average speed, in miles per hour, of the motorcyclist while driving from marker B to marker C?
(A) 40
(B) 135
(C) 50
(D) 55
(E) 60
Rationale: A- B = 120 Miles
B - C = 60 Miles
Avg Speed = 20 Miles
Time taken for A-B 3t and B-C be t
avg speed = (120+60) / Total time
20 = 180/4t
t = 135
B-C = 135mph
Answer B
Answer: (B) 135
Question: The average weight of a class is x pounds. When a new student weighing 90 pounds joins the class, the average decreases by 1 pound. In a few months the student’s weight increases to 110 pounds and the average weight of the class becomes x + 4 pounds. None of the other students’ weights changed. What is the value of x?
(A) 85
(B) 86
(C) 88
(D) 90
(E) 99
Rationale: When the student weighs 90 pounds the average weight is x - 1 pounds;
When the student weighs 110 pounds the average weight is x + 4 pounds.
So, the increase in total weight of 110 - 90 = 20 pounds corresponds to the increase in average weight of (x + 4) - (x - 1) =5 pounds, which means that there are 20/5 = 4 students (including the new one). So, initially there were 5 student.
Total weight = 5x + 90 = 6(x-1) --> x = 96 pounds.
Answer: E.
Answer: (E) 99
Question: Margaret is 10 years more than twice the age of his son. The age of son is 12. Find the age of mother and find the difference between their ages
(A) 10yrs
(B) 22yrs
(C) 30yrs
(D) 40yrs
(E) 50yrs
Rationale: Let, age of son x=12
Margaret is 10 years more than twice the age of his son, y = 10+2(x)
=10+2(12)
=10+24
=34yrs
Difference = 34 - 12
=22yrs
ANSWER:B
Answer: (B) 22yrs
Question: Tina’s cat weighs 2.6 kilograms. Her dog weighs 6 times as much as her cat. How much does her dog weigh in kilograms?
(A) A)10.4kg
(B) B)38kg
(C) C)22kg
(D) D)15.6kg
(E) E)20kg
Rationale: 2.6*6=15.6kg.Answer is D.
Answer: (D) D)15.6kg
Question: If it takes 70 workers 3 hours to disassemble the exhibition rides at a small amusement park, how many hours would it take 30 workers to do this same job?
(A) 40/3
(B) 11
(C) 7
(D) 7/3
(E) 9/7
Rationale: 70 Workers = 3 hours then,
1 Worker = 3*70 Hours
30 Workers = (3*70) /(30) = 7
ANSWER:C
Answer: (C) 7
Question: g(x) is defined as the product of all even integers k such that 0 < k ≤ x. For example, g(14) = 2 × 4 × 6 × 8 × 10 × 12 × 14. If g(e) is divisible by 4^11, what is the smallest possible value for e?
(A)  22
(B)  24
(C)  28
(D)  32
(E)  44
Rationale: g(e)=4^11=2^22. So we have to find a product with atleast 22 2's in it.
in option 1 22 the total no of 2's = [22/2] + [22/4] +[22/8] +[22/16] = 11+5+2+1 = 19
in option 2 24 the total no of 2's = [24/2] + [24/4] +[24/8] +[24/16] = 12+6+3+1 = 22 . Hence B
Answer: (B)  24
Question: A rectangular grass field is 75 m * 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m?
(A) 2999
(B) 1350
(C) 2677
(D) 2898
(E) 2787
Rationale: Area = (l + b +2d) 2d
= (75 + 55 +2.5 * 2) 2*2.5 => 675
675 * 2 = Rs.1350
AnswerB
Answer: (B) 1350
Question: Due to an increase in 30% in the price of eggs, 3 eggs less are available for Rs. 7.80. Find the present rate of eggs per dozen.
(A) Rs. 8.36
(B) Rs. 9.36
(C) Rs. 10.36
(D) Rs. 11.36
(E) Rs. 11.98
Rationale: Let the original price per egg be Rs x
Then increased price will be,
(130/100 x)
=7.80/x −7.80/(130/100) x =3
=7.80/x −780/130x =3
=390x=234
x=0.6
Actual price was Rs 0.6
Present price per dozen will be
Rs.(12∗130/100 ∗0.6)=Rs.9.36
Answer : B
Answer: (B) Rs. 9.36
Question: Which of the following could be the value of x, if |-6x + 24| = 54?
(A) 5
(B) 1
(C) 1/5
(D) 12
(E) -12
Rationale: |-6x + 24| = 54
=> -6x + 24 = 54
or -6x + 24 = -54
=> -6x = 30 or -6x = -78
=> x = -5 or x = 12
Answer D
Answer: (D) 12
Question: Juan is a gold medalist in athletics. In the month of May, if Juan takes 11 seconds to run y yards, how many seconds will it take him to run x yards at the same rate?
(A) 10x/y
(B) 11x/y
(C) 9x/y
(D) 12x/y
(E) 13x/y
Rationale: velocity=distance/time;
since he ran at same rate both d tyms,
y/11=x/t
so t=11x/y
ANSWER:B
Answer: (B) 11x/y
Question: Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 2.5% more. She would get how much?
(A) 9800
(B) 96288
(C) 26667
(D) 1662
(E) 2882
Rationale: (8000*3*2.5)/100 = 600
9200
--------
9800
Answer:A
Answer: (A) 9800
Question: There are between 500 and 510 cards in a collection of cards. If they are counted out 3 at a time, there are 2 left over, but if they are counted out 4 at a time, there is 1 left over. How many cards are in the collection?
(A)  501
(B)  503
(C)  506
(D)  507
(E)  510
Rationale: Let number of cards = x
If the cards are counted 3 at a time , there are 2 left over-
x= 3p+2
x can take values 503 , 506 , 510
If the cards are counted 4 at a time , there is 1 left over
x= 4q+1
x can take values 501 , 506
Therefore , x = 506
Answer C
Answer: (C)  506
Question: Solve:-
555 x 555 x 555 + 555 x 555 x 555 = ?(555 x 555 - 555 x 555 + 555 x 555)
(A) 888
(B) 333
(C) 555
(D) 988
(E) 1110
Rationale: Given Exp. = (a3 + b3) = (a + b) = (555 + 555) = 1110(a2 - ab + b2)
Answer E
Answer: (E) 1110
Question: A fair 2 sided coin is flipped 4 times. What is the probability that tails will be the result at least twice, but not more than 4 times?
(A) 1/8
(B) 2/3
(C) 5/8
(D) 4/7
(E) 3/7
Rationale: at least twice, but not more than 4 timesmeans exactly 2 times, 3 times, 4 times
The probability of getting exactly k results out of n flips is nCk/2^n
4C2/2^4+4C3/2^4=10/16=5/8
Option: C
Answer: (C) 5/8
Question: Rs.590 is divided amongst A, B, C so that 5 times A's share, six times B's share and eight times C's share are all equal. Find C's share?
(A) 177
(B) 150
(C) 817
(D) 716
(E) 616
Rationale: A+B+C = 590
5A = 6B = 8C = x
A:B:C = 1/5:1/6:1/8
= 24:20:15
15/59 * 590
= Rs.150
Answer: B
Answer: (B) 150
Question: Find the value of 72516 x 9999 = m?
(A) 456578972
(B) 436567874
(C) 725087484
(D) 725117481
(E) 357889964
Rationale: 72516 x 9999 = 72516 x (10000 - 1)
= 72516 x 10000 - 72516 x 1
= 725160000 - 72516
= 725087484
C
Answer: (C) 725087484
Question: What is the value of 4^5+4^4?
(A)  4^12
(B)  5(4^4)
(C)  17(4^5)
(D)  8^12
(E)  7(4^5)
Rationale: 4^5+4^4
=4^4(4+1)
=4^4 * 5
Answer B
Answer: (B)  5(4^4)
Question: If a truck is traveling at a constant rate of 54 kilometers per hour, how many seconds will it take the truck to travel a distance of 600 meters? (1 kilometer = 1000 meters)
(A) 18
(B) 24
(C) 30
(D) 36
(E) 40
Rationale: Speed = 54 Km/hr => 54,000 m/hr
In one minute => 54000/60 = 900 meters
In one sec => 900/60 = 15 meters
Time = Total distance need to be covered / Avg. speed
=> 600/ 15 =40 and hence the Answer : E
Answer: (E) 40
Question: When a number is divided by 6 &then multiply by 12 the answer is 15 what is the no.?
(A) 4.5
(B) 5
(C) 5.6
(D) 7.5
(E) 6.5
Rationale: if $x$ is the number, x/6 * 12 = 15
=> 2x = 15
=> x = 7.5
D
Answer: (D) 7.5
Question: For all even integers n, h(n) is defined to be the sum of the even integers between 4 and n, inclusive. What is the value of h(18)/h(10) ?
(A)  3
(B)  1.8
(C)  6
(D)  18
(E)  60
Rationale: CONCEPT: When terms are in Arithmetic Progression (A.P.) i.e. terms are equally spaced then
Mean = Median =(First+Last)/2
and Sum = Mean*Number of terms
h(18) = [(4+18)/2]*8 = 88
h(10) = (4+10)/2]*4 = 28
h(18)/h(10) = (88) / (28) ~ 3
Answer : A
Answer: (A)  3
Question: A is thrice as efficient as B and is, therefore, able to finish a piece of work 10 days earlier than B. In how many days A and B will finish it together?
(A) 62
(B) 78
(C) 23
(D) 5
(E) 32
Rationale: WC = 3:1
WT = 1:3
x 3x
1/x – 1/3x = 1/10
x = 20/3
3/20 + 1/20 = 1/5 => 5 days
Answer: D
Answer: (D) 5
Question: On multiplying a number by 7, the product is a number each of whose digits is 3. The smallest such number is:
(A) 48759
(B) 51236
(C) 47619
(D) 6974
(E) 1235
Rationale: Explanation:
By hit and trial, we find that
47619 x 7 = 333333.
ANSWER:C
Answer: (C) 47619
Question: By selling 50 meters of cloth. I gain the selling price of 15 meters. Find the gain percent?
(A) 42 6/7
(B) 35
(C) 20
(D) 25
(E) 40
Rationale: 50 SP = 50 CP + 15 SP
35 SP = 50 CP
35 --- 15 CP gain
100 --- ? => 42 6/7%
ANSWER A
Answer: (A) 42 6/7
Question: What decimal of an hour is a second ?
(A) .0025
(B) .0256
(C) .00027
(D) .000126
(E) none of the above
Rationale: Required decimal = 1/(60*60) =1/3600 = .00027
Answer = C
Answer: (C) .00027
Question: In an election a candidate who gets 84% of the votes is elected by a majority of 476 votes. What is the total number of votes polled?
(A) 630
(B) 700
(C) 535
(D) 450
(E) 815
Rationale: Let the total number of votes polled be x
Then, votes polled by other candidate = (100-84)% of x = 16% of x
84% of x - 16% of x = 476
68x/100 = 476
x = 476*100/68 = 700
Answer is B
Answer: (B) 700
Question: The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 64% of the required amount. What is the net difference in the expenditure on that product?
(A) 12.5%
(B) 13%
(C) 15%
(D) 17%
(E) 20%
Rationale: Quantity X Rate = Price
1 x 1 = 1
0.64 x 1.25 = 0.8
Decrease in price = (0.2/1) × 100 = 20%
E)
Answer: (E) 20%
Question: When running a mile during a recent track meet, Nuria was initially credited with a final time of 3 minutes, 44 seconds. Shortly after her run, officials realized that the timing mechanism malfunctioned. The stopwatch did not begin timing her until 11/25 of a minute after she began to run. If the time was otherwise correct, how long did it actually take Nuria to run the mile?
(A) 5 minutes, 17.6 seconds
(B) 5 minutes, 21.8 seconds
(C) 4 minutes, 10.4 seconds
(D) 5 minutes, 44.44 seconds
(E) 5 minutes, 43.56 seconds
Rationale: One approach:
The watch starts to work after Nuria began his running. It means the time should be greater than credited 3 minutes, 44 seconds. The only number is 4 minutes, 10.4 seconds.
Another approach:
11/25 close to 30 second when added to the 3 minutes, 44 seconds, it means it passes 4 minute.
Answer: C
Answer: (C) 4 minutes, 10.4 seconds
Question: In how many ways can the letters of the word CAVERN be arranged in a row so that the vowels appear in alphabetic order?
(A) 360
(B) 720
(C) 620
(D) 180
(E) 36
Rationale: Two letters can be arranged in 2! ways.
only one combination EIU is required.
6 letters can be arranged in 6! ways.
thus 6!/ 2! * 1 = 360.
A
Answer: (A) 360
Question: If two letters are chosen at random (without replacement) from the word DANCE, what is the probability that none of the letters are vowels?
(A) 1/5
(B) 2/5
(C) 3/10
(D) 7/20
(E) 11/30
Rationale: The number of ways to choose two letters is 5C2 = 10
The number of ways to choose two consonants is 3C2 = 3.
P(no vowels) = 3/10
The answer is C.
Answer: (C) 3/10
Question: A train running at the speed of 60 km/hr crosses a pole in 15 seconds. Find the length of the train.
(A) 150 m
(B) 145 m
(C) 240 m
(D) 135 m
(E) 250 m
Rationale: Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 15 = 250 meter
ANSWER: E
Answer: (E) 250 m
Question: Mrs. Rodger got a weekly raise of $147. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.
(A) $140
(B) $141
(C) $142
(D) $147
(E) $145
Rationale: Let the 1st paycheck be x (integer).
Mrs. Rodger got a weekly raise of $ 147.
So after completing the 1st week she will get $ (x+147).
Similarly after completing the 2nd week she will get $ (x + 147) + $ 147.
= $ (x + 147 + 147)
= $ (x + 294)
So in this way end of every week her salary will increase by $ 147.
correct answer D)$147
Answer: (D) $147
Question: Calculate how many seconds it will take for 4 bells to toll together again, given that they begin to toll together respectively at the intervals of 5, 6, 10 and 12 seconds. ?
(A) 61
(B) 60
(C) 79
(D) 70
(E) 78
Rationale: LCM of 5, 6, 10 and 12 is
60
LCM=60
ANSWER:B
Answer: (B) 60