mathewhe/aqua_rat huggingface dataset:
Question: To complete a work A and B takes 8 days, B and C takes 12 days, A,B and C takes 6 days. How much
time A and C will take
(A) 24 days
(B) 16 days
(C) 12 days
(D) 8 days
(E) None of these
Rationale: Explanation:
A+B 1 day work = 1/8
B+C 1 day work = 1/12
A+B+C 1 day work = 1/6
We can get A work by (A+B+C)-(B+C)
And C by (A+B+C)-(A+B)
So A 1 day work =
16−112=112
Similarly C 1 day work =
16−18=4−324=124
So A and C 1 day work =
112+124=324=18
So A and C can together do this work in 8 days
Answer: D
Answer: (D) 8 days
Question: The current birth rate per certain number of people is 32, whereas corresponding death rate is 11 per same number of people. If the net growth rate in terms of population increase is 2.1 percent, find number of persons.(initally)
(A) 1000
(B) 10000
(C) 100
(D) 2000
(E) 20000
Rationale: Sol.
Net growth on X = (32- 11) =21.
Net growth on 100 = (21/X Ã— 100)% = 2.1%. Then X = 1000
Answer:A
Answer: (A) 1000
Question: A and B together can do a piece of work in 10 days. B alone can finish it in 20 days. In how many days can A alone finish the work ?
(A) 10
(B) 20
(C) 21
(D) 22
(E) 23
Rationale: Time taken by A to finish the work = XY/(Y-X)
= 10 x 20 / (20-10)
= 200/10
= 20 days
ANSWER : OPTION B
Answer: (B) 20
Question: 5358 x 52 = ?
(A) 273762
(B) 278616
(C) 273298
(D) 273258
(E) 277382
Rationale: B
5358 x 52 = 5358 x (50 + 2)
= 5358 x 50 + 5358 x 2
= 267900 + 10716
= 278616.
Answer: (B) 278616
Question: A can do a piece of work in 12 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in ?
(A) 3 days
(B) 5 days
(C) 6 days
(D) 7 days
(E) 11 days
Rationale: B's 9 day's work = 9 x (1/12) = 3/4
Remaining work = (1 - 3/4) = 1/4
1/4 work is done by A in = 12 x (1/4) = 3 days.
answer : A
Answer: (A) 3 days
Question: A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.700, what is the reduced price for kg?
(A) 35
(B) 60
(C) 70
(D) 80
(E) 20
Rationale: A
700*(25/100) = 175 ---- 5
? ---- 1 => Rs.35
Answer: (A) 35
Question: In the first 10 overs of a cricket game, the run rate was only 3.8. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
(A) 4.25
(B) 5
(C) 6.1
(D) 7
(E) 7.5
Rationale: Required run rate = 282 - (3.8 x 10) =	244
244/40= 6.1
C)
Answer: (C) 6.1
Question: By selling 12 toffees for a dollar, a man loses 20%. How many for a should dollar be sell to get a gain of 20%?
(A) 23
(B) 12
(C) 78
(D) 2
(E) 8
Rationale: E
S.P. of 12 toffees be $ x.
Then, 80:1 = 120:x or x = 120/180 = 3/2
For $ 3/2, toffees sold = 12.
For Re. 1, toffees sold = 12 * 2/3 = 8
Answer: (E) 8
Question: The average age of 20 students in a class is 15 years. If the age of teacher is also included, the average becomes 16 years, find the age of the teacher.
(A) 35
(B) 38
(C) 45
(D) 36
(E) 60
Rationale: Explanation:
If teacher's age is 15 years, there is no change in the average. But teacher has contributed 1 year to all the students along with maintaining his age at 16.
Age of teacher = Average age of all + Total increase in age
= 16 + (1 x 20 ) = 36 years
Answer:D
Answer: (D) 36
Question: A, B and C run around a circular track starting from the same point simultaneously and in the same direction at speeds of 4 kmph, 6 kmph and 8 kmph respectively. If the length of the track is 400 meters, when will A, B and C meet at the starting point for the first time after they started the race?
(A) 1 minute
(B) 5 minutes
(C) 12 minutes
(D) 20 minutes
(E) 24 minutes
Rationale: 4 kmph, 6 kmph and 8 kmph is equal to 4000/60 mtrs/min, 6000/60 mtrs/min and 8000/60 mtrs/min or 200/3, 100, 400/3 mtrs/min respectively.
Seeing this we can infer that the answer should be at least divisible by 3. (minutes in options are integers. So if the answer is not divisible by 3, we will have 200/3*answer = distance traveled by A in fractions whereas 100*answer = distance traveled by A as integer)
So, A,B and D are out.
At 12 min A,B and C will travel 800, 1200 and 1600 mtrs respectively. Length of the circle is given as 400 mtrs.
As 800, 1200 and 1600 are divisible by 400, we can say that A,B and C will be at starting point after 12 min.
Hence, C will be the answer.
Answer: (C) 12 minutes
Question: There is a unique number which when multiplied by any number from 1 to 6, we will get the new number that contains same digits only.Can you find that number ?
(A) 142857
(B) 135957
(C) 123354
(D) 114457
(E) 133257
Rationale: 142857 * 1 = 142857
142857 * 2 = 285714
142857 * 3 = 428571
142857 * 4 = 571428
142857 * 5 = 714285
142857 * 6 = 857142
These number are considered as cyclic numbers.
correct answer is A)142857
Answer: (A) 142857
Question: The area of a sector of a circle of radius 5 cm formed by an arc of length 3.5 cm is?
(A) 8.78
(B) 8.67
(C) 8.75
(D) 8.98
(E) 8.28
Rationale: (5 * 3.5)/2
= 8.75
Answer:C
Answer: (C) 8.75
Question: A man traveled a total distance of 1800 km. He traveled one-third of the whole trip by plane and the distance traveled by train is three-fifth of the distance traveled by bus. If he traveled by train, plane and bus, then find the distance traveled by bus?
(A) 450 km
(B) 850 km
(C) 1200 km
(D) 750 km
(E) None of these
Rationale: Total distance traveled = 1800 km.
Distance traveled by plane = 600 km.
Distance traveled by bus = x
Distance traveled by train = 3x/5
=> x + 3x/5 + 600 = 1800
=> 8x/5 = 1200 => x = 750 km.
ANSWER:D
Answer: (D) 750 km
Question: Of the 3,600 employees of Company X, 1/3 are clerical. If the clerical staff were to be reduced by 1/6, what percent of the total number of the remaining employees would then be clerical?
(A)  25%
(B)  22.2%
(C)  20%
(D)  29.4%
(E)  11.1%
Rationale: Welcome, just post the question and the choices
Let's see, the way I did it was
1/3 are clerical out of 3600 so 1200 are clerical
1200 reduced by 1/6 is 1200*1/6
so it reduced 200 people , so there is 1000 clerical people left
but since 200 people left, it also reduced from the total of 3600 so there are 3400 people total
since 1000clerical left / 3400 people total
you get (A) 29.4%
Answer : D
Answer: (D)  29.4%
Question: 3 buffaloes eat as much as 4 cows or 2 oxen. At a farm there are 15 buffaloes, 8 oxen and 24 cows. The fodder for these cattle is available for 24days. If 8 more cows & 9 more buffaloes are brought in, how long will the fodder last?
(A) 11
(B) 12
(C) 14
(D) 18
(E) 21
Rationale: Sol. 2 oxen = 3 buffaloes = 4 cows 8 oxen = 16 cows and 15 buffaloes = 20 cows 16 cows + 20 cows + 24 cows = 60 cows Since fodder is available for 60 cows for 24 days
So fodder will be available for (60 + 8 + 12) = 80 cows c 24x60 .0 .
for-^—=18 days.
D
Answer: (D) 18
Question: Which is greater 2/3 or 3/4?
(A) 2/3
(B) 3/4
(C) both are equal
(D) Cannot be determined
(E) both are equal and equal to 1
Rationale: To know which is greater 2/3 or 3/4
= Multiply both by 4*3 = 12 ( Product of denominator)
= 2/3 * 12 and 3/4 * 12 respectively
= 8 and 9 respectively
which means 3/4 is greater.
Ans: B
Answer: (B) 3/4
Question: A carpenter makes 7 bunk beds every day. A military school needs to organize a place to sleep for 143 soldiers. If there are 5 carpenters working on the job, how many whole days in advance should they receive the order and start working in order to finish the right number of beds assuming that each bunk- bed is used by two soldiers?
(A) 3.
(B) 4.
(C) 5.
(D) 6.
(E) 7.
Rationale: I believe it is C because if 1C makes 3 beds in 1 day then:
1C's rate = 3/1
So 5c's = 3/1 * 5 = 15/1 = 15 beds in a day.
Since we have 173 soldiers who need beds and bunk beds come in pairs, 72 is the least amount of beds needed.
Time = Amount / Rate
Time = 72 / (15/1) = 72/15, simplifying we get 72/15 = 24/5 = 7
So, in order for the carpenters to be able to finish they need 7 whole days. At first I made the mistake of thinking how many whole days it took them to finish (as in ignore the partial day) but the prompt clarifiesdays in advance, meaning how many days would they need to finish so even if they finish early, theyusedthat day.
E
Answer: (E) 7.
Question: A money lender lent a total of $1700 to two of his customers. He charged at the rate of 5%p.a. to one of them and 6% p.a. to the other. If he earned an average of 5.67% on $1700, how much did he lend to each of the two customers?
(A) 700; 1100
(B) 1139; 561
(C) 1000; 800
(D) 1200; 800
(E) None of the above
Rationale: The method given above is the one given in the book.
However the method I used was
(1*x*5)/100 + (1700-x)*6/100 = 1700*5.67/100
Simplifying we get x=561
B
Answer: (B) 1139; 561
Question: What should come in place of question mark (?) in the following equation?
45% of 1500 + 35% of 1700 = ? % of 3175.
(A) 50
(B) 45
(C) 30
(D) 35
(E) None of these
Rationale: 45% of 1500 + 35% of 1700 = ? % of 3175
∴ ? = 1270003175=40
Answer E
Answer: (E) None of these
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 sec. What is the length of the fast train?
(A) 27 7/8 m
(B) 77 7/9 m
(C) 27 8/9 m
(D) 27 7/9 m
(E) 22 7/9 m
Rationale: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 5 = 250/9
= 27 7/9 m.
Answer: D
Answer: (D) 27 7/9 m
Question: A class average mark in an exam is 70. The average of students who scored below 60 is 50. The average of students who scored 60 or more is 75. If the total number of students in this class is 20, how many students scored below 60?
(A) 10
(B) 20
(C) 38
(D) 42
(E) 33
Rationale: Let n the number of students who scored below 60 and N the number of students who scored 60 or more. Xi the grades below 60 and Yi the grades 60 or above.
[sum(Xi) + sum(Yi)] / 20 = 70 : class average
sum(Xi) / n = 50 : average for less that 60
sum(Yi) / N = 75 : average for 60 or more
50n + 75N = 1400 : combine the above equations
n + N = 20 : total number of students
n = 4 and N = 16 : solve the above system
correct answer B
Answer: (B) 20
Question: In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?
(A) 5/21
(B) 5/14
(C) 9/14
(D) 16/21
(E) 1/3
Rationale: Explanation:
Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)
As remaining person can be any one among three couples left.
Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅
= (10 * 6)/252 = 5/21
ANSWER IS A
Answer: (A) 5/21
Question: If t,u, and v are positive integers and 2t=2u+2v, which of the following must be true?
i. t=u
ii. u is not equal to v
iii. t > v
(A) None
(B) I only
(C) II only
(D) III and I
(E) III only
Rationale: Notice two things: 1. we are asked to find out which of the following MUST be true, not COULD be true and 2. t, u, and v are positive integers.
Given: 2st=2u+2v --> t=u+v. Now, since s, u, and v are positive integers then s is more than either u or v, so I is never true and III is always true. As for II: it's not necessarily true, for example 4=2+2. So, we have that only option III must be true.
Answer: E
Answer: (E) III only
Question: It is currently 9:53 PM. What time was it in the morning exactly 149,061 minutes ago?
(A) 9:12
(B) 9:18
(C) 9:26
(D) 9:32
(E) 9:38
Rationale: Divide by 60 to convert 149,061 minutes to hours: 149,061/60 = 2,484 R21. That is 2,484 hours and 21 minutes. All of the answers are in the 9AM hour before :53, thus we can assume 2,484 previous must be 9:53 AM. 21 minutes before that is 9:32 AM. D
Answer: (D) 9:32
Question: A photograph is copied onto a sheet of paper 8.5 inches by 10 inches. A 1.5 inch margin is left all around. What area in square inches does the picture cover?
(A) 76
(B) 65
(C) 59.5
(D) 49
(E) 38.5
Rationale: Area covered by photograph = (8.5-3)*(10-3)
=5.5*7
=38.5
Answer E
Answer: (E) 38.5
Question: Express of the following as a fraction: 0.6%
(A) 1/500
(B) 7/500
(C) 3/500
(D) 8/500
(E) None of them
Rationale: 0.6 =6/1000 = 3/500
Answer is C.
Answer: (C) 3/500
Question: The ratio of two quantities is 2 to 5. If each of the quantities is increased by 4, what is the ratio of these two new quantities?
(A) 2/5
(B) 5/8
(C) 7/13
(D) 22/25
(E) It cannot be determined from the information given.
Rationale: Correct Answer: E
Let x and y be the two quantities such that x/y = 2/5. There is no algebraic operation that can be used to increase x and y each by 3 and determine what happens to the ratio 2/5.
For example, if x = 2 and y = 5, then (x+4)/(y+4) = (2+4)/(5+4) = 6/9. However, if x = 4 and y = 10 (which would still set x/y = 2/5), then (x+3)/(y+3) = (4+4)/(10+4) = 8/14. The ratio of the two new quantities cannot be uniquely determined from the information given, and the correct answer is (E).
Answer: (E) It cannot be determined from the information given.
Question: A box contains 5 yellow balls and 6 black balls. One by one, every ball is selected at random without replacement. What is the probability that the fourth ball selected is black?
(A) 3/4
(B) 4/7
(C) 5/8
(D) 7/9
(E) 6/11
Rationale: Each ball has an equal chance (1/11) of being selected fourth.
The probability that a black ball is selected fourth is 6/11.
The answer is E.
Answer: (E) 6/11
Question: The ratio between the speeds of two trains is 7: 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is ?
(A) 83.5 km/hr
(B) 84.5 km/hr
(C) 86.5 km/hr
(D) 87.5 km/hr
(E) None of these
Rationale: Explanation:
Let the speeds of two trains be 7X and 8X km/hr.
8/X=400/4=>X=12.5Km/hr
So speed of first train is 12.5*7 = 87.5 km/hr
Option D
Answer: (D) 87.5 km/hr
Question: Adding two non multiples of W always results in a multiple of W; which of the following must be the value of W ?
(A) [A] two
(B) [B] three
(C) [C] five
(D) [D] ten
(E) [E] hundred
Rationale: NON- multiples of 2 would always be ODD and sum of two odd would be EVEN.
so irrespective of value of non-multiples, sum of two them would always be even and thus multiple of 2..
A
Answer: (A) [A] two
Question: The first three terms of an infinite sequence are 2, 7, and 22. After the first term, each consecutive term can be obtained by multiplying the previous term by 3 and then adding 1. What is the sum of the tens digit and the units digit of the fortythird term in the sequence?
(A) 2
(B) 3
(C) 6
(D) 4
(E) 5
Rationale: Following the rule of Infinite sequence we obtain the terms of the sequence as mentioned below
02,07,22,67, 202, 607, 1822, 5467...
Observe the last two digits of the sequence which have the cyclicity of4and the last two digits repeat in the order {02, 07, 22, 67}
Also 43rd Term =5*8 +3
i.e. 35th Terms will have same Last two digits as 3rd term of the sequence = 22
i.e. Sum of lat two digits of 35th Term = 2+2 = 4
D
Answer: (D) 4
Question: How many terminating zeroes Q does 200! have?
(A)  40
(B)  48
(C)  49
(D)  55
(E)  64
Rationale: You have 40 multiples of 5, 8 of 25 and 1 of 125. This will give 49 zeros.C
Answer: (C)  49
Question: Evaluate ((5.68)2 – (4.32)2)/5.68- 4.32
(A) 8
(B) 9
(C) 10
(D) 11
(E) 12
Rationale: Given Expression = a2-b2/ a-b = (a+b) (a-b)/ a-b = (a+b)
(5.68)2 – (4.32)2/5.68- 4.32 = (5.68+ 4.32) = 10
ANSWER:C
Answer: (C) 10
Question: A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
(A) 22
(B) 23
(C) 24
(D) 26
(E) 25
Rationale: Explanation:
Let the number of hens be x and the number of cows be y.
Then, x + y = 48 .... (i)
and 2x + 4y = 140 x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
The required answer = 26.
ANSWER IS D
Answer: (D) 26
Question: Skier SARAH completes a straight 300-meter downhill run in t seconds and at an average speed of (x + 10) meters per second. She then rides a chairlift back up the mountain the same distance at an average speed of (x - 8) meters per second. If the ride up the mountain took 135 seconds longer than her run down the mountain, what was her average speed, in meters per second, during her downhill run?
(A)  10
(B)  15
(C)  20
(D)  25
(E)  30
Rationale: Backsolving is the preferred approach for this one
300/(x-8) - 300/(x+10) = 135
We are asked for the value of x+10
So we can start with C = X+10 = 20
So x = 10
300/2 - 300 / 20 = 135
Hence answer is C
Answer: (C)  20
Question: John is measuring a banner for the school play and needs to know how many inches are in 5 yards and 2 feet. Can you help him out?
(A) 235 inches.
(B) 204 inches.
(C) 220 inches.
(D) 206 inches.
(E) 208 inches.
Rationale: B
204 inches.
5 yards is the same as 15 feet(3 feet = 1 yard).15 feet +2 feet = 17 feet. There are 12 inches in each foot. So 17 feet x 12 = 204 inches.
Answer: (B) 204 inches.
Question: A train 150 m long running at 72 kmph crosses a platform in 25 sec. What is the length of the platform?
(A) 443 m
(B) 354 m
(C) 450 m
(D) 350 m
(E) 250 m
Rationale: D
350
D = 72 * 5/18 = 25 = 500 – 150 = 350
Answer: (D) 350 m
Question: The diagonals of a rhombus are 13 cm and 20 cm. Find its area?
(A) 329
(B) 288
(C) 150
(D) 130
(E) 31
Rationale: 1/2 * 13 * 20 = 130
Answer: D
Answer: (D) 130
Question: Find the area of trapezium whose parallel sides are 10 cm and 18 cm long, and the distance between them is 10 cm.
(A) 140 cm2
(B) 185 cm2
(C) 185 cm2
(D) 185 cm2
(E) 195 cm2
Rationale: Explanation:
Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them) = 1/2 (10 + 18) * (10) = 140 cm2
Answer: Option A
Answer: (A) 140 cm2
Question: 45 men can complete a work in 14 days. Six days after they started working, 30 more men joined them. How many days will they now take to complete the remaining work?
(A) 6
(B) 10
(C) 15
(D) 7
(E) 4.8
Rationale: 45*14 men can complete the work in 1 day
1 man's 1 day work = 1/630
45 men 6 days work = 6*1/14 = 3/7
remaining work = 1-3/7 = 4/7
75 men's 1 day's work = 75/630 = 5/42
4/7 work is done by them in 42/5 * 4/7 = 4.8 days
Answer is E
Answer: (E) 4.8
Question: On a ferry, there are 32 cars and 8 trucks. The cars have an average mass of 900 kg and the trucks have an average mass of 3000 kg. What is the average mass of all 40 vehicles on the ferry?
(A) 1200
(B) 1240
(C) 1280
(D) 1320
(E) 1360
Rationale: The total mass of the vehicles is 32*900+8*3000=52800
The average mass is 52800/40=1320
The answer is D.
Answer: (D) 1320
Question: If the sides of a triangle are 26 cm, 24 cm and 12 cm, what is its area?
(A) 120 cm2
(B) 112 cm2
(C) 144 cm2
(D) 666 cm2
(E) 886 cm2
Rationale: The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle = 1/2 * 24 * 12 = 144 cm2
Answer: C
Answer: (C) 144 cm2
Question: Which one of the following numbers is a solution of the equation
(x(2sq)-2)(x(2sq) + 6)(x(third3)-8) = 0?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: One checks each of the ve given possible answers. Since 2-3third- - 8 = 0, the answer
is 2.
correct answer B
Answer: (B) 2
Question: In a consumer survey, 70% of those surveyed liked at least one of three products: 1, 2, and 3. 50% of those asked liked product 1, 30% liked product 2, and 20% liked product 3. If 5% of the people in the survey liked all three of the products, what percentage of the survey participants liked more than one of the three products?
(A) 5
(B) 10
(C) 15
(D) 20
(E) 25
Rationale: pick 100 and x= all set with exactly two items
70=30+50+20 -(X)-10
X=20
so the answer is 20+5/100= 25%
Answer E
Answer: (E) 25
Question: Three partners A, B, C in a business invested money such that 3(Aâ€™s capital) = 2(Bâ€™s capital) = 5(Câ€™s capital) then, The ratio of their capitals is
(A) 63 : 45 : 34
(B) 63 : 54 : 34
(C) 36 : 54 : 28
(D) 63 : 45 : 35
(E) 10 : 15 : 6
Rationale: Explanation:
Let 3(Aâ€™s capital) = 2(Bâ€™s capital) = 5(Câ€™s capital) = Rs.x
Then, Aâ€™s capital = Rs x/3, Bâ€™s capital = Rs. x/2 and Câ€™s capital = Rs. x/5.
A : B : C = x/3 : x/2 : x/5
10 : 15 : 6
Answer: Option E
Answer: (E) 10 : 15 : 6
Question: Rs. 850 becomes Rs. 956 in 3 years at a certain rate of simple interest.If the rate of interest is increased by 4% ,What amount will Rs. 850 become in 3 years ?
(A) Rs. 1020.80
(B) Rs. 1025
(C) Rs. 1058
(D) Data inadequate
(E) None of these
Rationale: Solution
S.I. = Rs.(956-850 )=Rs.106
Rate = (100x106/850x3) = 212/51%
New rate = (212/51 +4)% = 416/51%
New S.I. = Rs.(850 x416/51x3/100) Rs. 208.
∴ New amount = Rs.(850+208)= Rs. 1058.
Answer C
Answer: (C) Rs. 1058
Question: Of the films Empty Set Studios released last year, 60% were comedies and the rest were horror films. 75% of the comedies were profitable, but 75% of the horror moves were unprofitable. If the studio made a total of 41 films, and broke even on none of them, how many of their films were profitable?
(A) 18
(B) 19
(C) 20
(D) 21
(E) 40
Rationale: After fiddling some more, this is how I got to answer choice E...but did I get here using voodoo math or is it sound?
(.60*.75) + (.40*.25) = .44 + .10 = .55
55/100 = 11/20
Then subtract from 41:
41 - 11/20 = 40 (answer E)
Answer: (E) 40
Question: Instead of multiplying a number by 2, the number is divided by 10. What is the percentage of error obtained ?
(A) 94%
(B) 92%
(C) 95%
(D) 93%
(E) 97%
Rationale: let the number be x
the right number is 2x
the wrong number is x/10
error is(2x-x/10)=19x/10
percentage of error is((19x/10)/2x)*100=95%
ANSWER:C
Answer: (C) 95%
Question: Eight years ago, P was half of Q's age. If the ratio of their present ages is 3:4 what will be the total of their present ages?
(A) 33
(B) 67
(C) 28
(D) 31
(E) 35
Rationale: Let present age of P and Q be 3x3x and 4x4x respectively.
Eight years ago, P was half of Q's age
â‡’(3xâˆ’8)=1/2(4xâˆ’8)
â‡’6xâˆ’16=4xâˆ’8
â‡’2x=8
â‡’x=4
Total of their present ages
=3x+4x=7x=7Ã—4=28
C
Answer: (C) 28
Question: Albert invested amount of 4000 in a fixed deposit for 2 years at compound interest rate of 5 % per annum. How much Albert will get on the maturity of the fixed deposit
(A) Rs. 8510
(B) Rs. 8620
(C) Rs. 4410
(D) Rs. 8820
(E) None of these
Rationale: Explanation:
=>(4000×(1+5/100)2)
=>4000×21/20×21/20
=>4410
Option C
Answer: (C) Rs. 4410
Question: Total dinning bill for 6 people was $211.00.If they add 15% tip and divided the bill evenly ,approximate.What was each persons find share
(A) $30.14
(B) 40.44
(C) 34.66
(D) 32.29
(E) 33.16
Rationale: 211*15=3165/100=31.65
211+31.65=242.65
242.65/6=40.44
ANSWER:B
Answer: (B) 40.44
Question: The probability is 0.6 that an “unfair” coin will turn up tails on any given toss. If the coin is tossed 3 times, what is the probability that at least one of the tosses will turn up tails?
(A) 0.064
(B) 0.36
(C) 0.64
(D) 0.784
(E) 0.936
Rationale: probability that at least one of the tosses will turn up tails = 1 - probability that all will be heads
= 1 - (0.4*0.4*0.4)
= 1 - 0.064
= 0.936 E
Answer: (E) 0.936
Question: If x is a positive even number, then each of the following is even odd EXCEPT
(A) (x + 3)(x + 5)
(B) x^2 +4
(C) x^2 + 6x + 9
(D) 3x^2 + 4
(E) 5(x + 3)
Rationale: Since it is given tht x is even number, so any integer multiplied with x will also be even..
so, we should concentrate only on other terms..
lets see the choices..
A. (x + 3)(x + 5)
We have two terms with x and each is added with a odd number..
each bracket becomes odd and Odd*Odd=Odd
B. x^2 + 5
here we are adding an Odd number to even.. so E + O=O
C. x^2 + 6x + 9
here we are again adding an Odd number to even.. so E +E + O=O
D. 3x^2 + 4
here we are adding an Even number to even.. so E + E=E..
so tjis is our answer
E. 5(x + 3)
again O*O=O
B
Answer: (B) x^2 +4
Question: Barbata invests $2400 in the National Bank at 5%. How much additional money must she invest at 10% so that the total annual income will be equal to 6% of her entire investment?
(A) 120
(B) 600
(C) 1000
(D) 360
(E) 240
Rationale: Let the additional invested amount for 10% interest be x;
Equation will be;
2400+0.05*2400+x+0.10x = 2400+x+0.06(2400+x)
0.05*2400+0.10x = 0.06x+0.06*2400
0.04x = 2400(0.06-0.05)
x = 2400*0.01/0.04 = 600
Ans:B
Answer: (B) 600