mathewhe/aqua_rat huggingface dataset:
Question: Lisa and Robert have taken the same number of photos on their school trip. Lisa has taken 3 times as many photos as Claire and Robert has taken 28 more photos than Claire. How many photos has Claire taken?
(A) 6
(B) 8
(C) 10
(D) 12
(E) 14
Rationale: L = R
L = 3C
R = C + 28
3C = C + 28
C = 14
The answer is E.
Answer: (E) 14
Question: If the wheel is 42 cm then the number of revolutions to cover a distance of 1056 cm is?
(A) 18
(B) 4
(C) 6
(D) 8
(E) 19
Rationale: 2 * 22/7 * 42 * x = 1056
=> x = 4
Answer: B
Answer: (B) 4
Question: The present worth of Rs. 1404 due in two equal half-yearly installments at 8% per annum simple interest is :
(A) Rs. 1325
(B) Rs. 1300
(C) Rs. 1350
(D) Rs. 1500
(E) Rs. 1800
Rationale: Solution
Required sum = P.W. of Rs.702 due 6 months hence + P.W. of Rs. 702 due 1 year hence
= Rs. [( 100x 702/100 + 8 x1/2 ) + ( 100x 702/100 + 8x 1) ] = Rs. (675 + 650) = Rs. 1325.
Answer A
Answer: (A) Rs. 1325
Question: Solution X is 20% chemical A and 80% chemical B by volume; Solution Y is 30% chemical A and 70% chemical B. If a mixture of X and Y is 22% chemical A, what percent of the mixture is Solution X?
(A) 20%
(B) 44%
(C) 50%
(D) 80%
(E) 90%
Rationale: 22% of chemical A in X+Y grams of solution comes from 20% chemical A in solution X and 30% chemical A in solution Y, thus:
0.22(X + Y) = 0.2X + 0.3Y --> X = 4Y --> X/(X+Y)=4/5=0.8.
Answer: D.
Answer: (D) 80%
Question: If a : b = 2 : 3 and b : c = 5 : 7, then find a : b : c.
(A) 10 : 15 : 27
(B) 10 : 15 : 21
(C) 10 : 15 : 22
(D) 10 : 15 : 12
(E) 10 : 15 : 28
Rationale: a : b : c = (2 x 5) : ( 3 x 5) : (3 x 7) = (10) : (15) : (21)
Answer:	A
Answer: (A) 10 : 15 : 27
Question: Jaydeep purchased 25 kg of rice at the rate of 16.50 per kg and 35 kg of rice at the rate of 24.50 per kg. He mixed the two and sold the mixture. Approximately, at what price per kg did he sell the mixture to make 25 per cent profit?
(A) 26.5
(B) 27.5
(C) 28.5
(D) 30.0
(E) 29.0
Rationale: CP = 25 × 16.50 + 35 × 24.50 = 1270
SP = 1270 × 125⁄100 = 1587.50
Price per kg = 1587.50⁄60 ≈ 26.50
Answer A
Answer: (A) 26.5
Question: Jim takes a seconds to swim t meters at a constant rate from point M to point N in a pool. Roger, who is faster than Jim, can swim the same distance in b seconds at a constant rate. If Jim leaves point M the same time that Roger leaves point N, how many fewer meters will Jim have swum than Roger when the two swimmers pass each other?
(A) c(b-a)/ a+b
(B) c(a-b)/a+b
(C) c(a+b)/a-b
(D) t(a-b)/a+b
(E) ab(b-a)/a+b
Rationale: Both JimRoger are travelling at constant speedin opposite direction:
So, speed of Jim =t /a speed of Roger = t/b
Let say Jim travelled distance x from M where it met Roger, it means that Roger travelled (t-x) from point N
[x would be less than (t-x) as Jim is travelling slow]
From above, time taken by Jim to travel x = xa/t....................... (1)
Also, time taken by Roger to travel (t-x) = (t-x)b/t.....................(2)
Time taken by both JimRoger is same, so (1) = (2)
xa/t = (t-x)b/t,
Solving further, x = bt/(a+b).................... (3)
We require to find how many fewer meters will Jim have swum i.e
additional distance travelled by Roger = (t - x) - x
= t-2x
Substituting value of x from (3)solving the equation further, we get Answer = t(a-b)/a+b
Answer = (D)
Answer: (D) t(a-b)/a+b
Question: A committee of 5 is to be selected from among 4 boys and 6 girls. I how many ways can this be done if the committee is to consist of at-least one Girl?
what is the answer choice and how?
(A) 105
(B) 194
(C) 230
(D) 350
(E) 455
Rationale: I'm sure there is some problem with the question.
R U sure its atleast one boy and not atleast 1 boy and 1 girl?
if its 1 boy and 1 girl
6C1*4C3 + 6C2*4C2 + 6C3*4C1
6*4 + 15*6 + 20*4
24 + 90 + 80
194
B
Answer: (B) 194
Question: If a+5/b is a prime integer, which of the following must be true?
1.b=5a
2. b is a prime integer
3. a+5/b is ODD.
(A) None
(B) 1 only
(C) 2 only
(D) 1 and 2 only
(E) 2 and 3 only.
Rationale: I would pick up numbers and do .
i hope the question is (a+5)/b....
let a = 3 , b = 4
3+5/4 = 2 = Prime
1. b is not equal to 5a
2.b is not a prime number
3. (a+5)/b is not odd.
hence A
Answer: (A) None
Question: A car covers a distance of 624 km in 2 2/5 hours. Find its speed?
(A) 104 kmph
(B) 194 kmph
(C) 109 kmph
(D) 260 kmph
(E) 271 kmph
Rationale: 624/2 2/5
=260 kmph
Answer:D
Answer: (D) 260 kmph
Question: A man traveled a total distance of 900 km. He traveled one-third of the whole trip by plane and the distance traveled by train is two-thirds of the distance traveled by bus. If he traveled by train, plane and bus, how many kilometers did he travel by bus?
(A) 240
(B) 280
(C) 320
(D) 360
(E) 400
Rationale: total distance traveled = 900 km.
distance traveled by plane = 300 km.
distance traveled by bus = x
distance traveled by train = 2x/3
x + 2x/3 + 300 = 900
5x/3 = 600
x = 360 km
The answer is D.
Answer: (D) 360
Question: The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?
(A) 4
(B) 8
(C) 10
(D) 9
(E) 11
Rationale: Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
9x = 36
x = 4.
Required difference = (2x + x) - (2x - x) = 2x = 8.
Answer:B
Answer: (B) 8
Question: If w is divisible by 10 and 4, w must be a multiple of which of the following?
(A) 8
(B) 12
(C) 20
(D) 24
(E) 36
Rationale: If w is divisible by 2*2 and 2*5, then w is divisible by 2*2*5 = 20.
The answer is C.
Answer: (C) 20
Question: If r and s are positive integers and r-s=6, which of the following has the greatest value V?
(A) 2r
(B) 2s
(C) r +s
(D) 2r-s
(E) 2s-r
Rationale: You can answer this question by using Number Properties and logic or by TESTing VALUES.
We're told that R and S are POSITIVE INTEGERS and that R-S = 6. We're asked which of the 5 answers has the GREATEST value.
IF....
R = 8
S = 2
Answer A: 2R = 2(8) = 16
Answer B: 2S = 2(2) = 4
Answer C: R+S = 8+2 = 10
Answer D: 2R-S = 2(8) - 2 = 14
Answer E: 2S-R = 2(2) - 8 = -4
Final Answer:
A
Answer: (A) 2r
Question: The present ages of three persons in proportions 2 : 7 : 9. Eight years ago, the sum of their ages was 30. Find their present ages (in years).
(A) 17,20, 28
(B) 22,28, 36
(C) 21,35, 45
(D) 33,42,43
(E) 6,21,27
Rationale: Let their present ages be 2x, 7x and 9x years respectively.
Then, (2x - 8) + (7x - 8) + (9x - 8) = 30
18x = 54
x = 3.
Their present ages are 2x = 6 years, 7x = 21 years and 9x = 27 years respectively.
ANSWER:E
Answer: (E) 6,21,27
Question: What amount does Kiran get if he invests Rs. 18000 at 15% p.a. simple interest for four years?
(A) 3888
(B) 26989
(C) 26700
(D) 28800
(E) 2879
Rationale: Simple interest = (18000 * 4 * 15)/100 = Rs. 10800
Amount = P + I = 18000 + 10800 = Rs. 28800
Answer: D
Answer: (D) 28800
Question: What is the probability of getting exactly 4 heads in a single throw of five fair coins?
(A) 1/4
(B) 3/8
(C) 3/16
(D) 5/32
(E) 7/32
Rationale: One possible case is HHHHT.
P(HHHHT) = 1/2*1/2*1/2*1/2*1/2 = 1/32
There are 5C4 = 5 possible cases.
P(4 heads) = 5*1/32 = 5/32
The answer is D.
Answer: (D) 5/32
Question: Carmelo and LeBron participate in a four-person footrace on the basketball court during All-Star Weekend. If all four contestants finish (including Charles Barkley) and there are no ties, how many different arrangements of finishes are there in which Carmelo defeats LeBron?
(A) 5040
(B) 2520
(C) 720
(D) 12
(E) 42
Rationale: 4! = 24
24/2=12half the time carmelo is in front, vice versa
Answer:
(D) 12
Answer: (D) 12
Question: A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 3 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold?
(A) 360
(B) 487
(C) 481
(D) 729
(E) 268
Rationale: 1/x - 1/20 = -1/24
x = 120
120 * 3 = 360
Answer:A
Answer: (A) 360
Question: A parking garage rents parking spaces for $10 per week or $24 per month. How much does a person save in a year by renting by the month rather than by the week?
(A)  $140
(B)  $160
(C)  $220
(D)  $232
(E)  $260
Rationale: 10$ per week!
An year has 52 weeks.
Annual charges per year = 52* 10 = 520$
30$ per month!
An year has 12 months.
Annual charges per year = 12 * 24= 288$
520 - 288 = 232
Ans D
Answer: (D)  $232
Question: A train crosses a platform of 150 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
(A) 150m
(B) 120m
(C) 186m
(D) 167m
(E) 189m
Rationale: Length of the train be ‘X’
X + 150/15 = X + 250/20
4X + 600 = 3X + 750
X = 150m
Answer: A
Answer: (A) 150m
Question: The first photo shoot takes 3 minutes long and then the following shoots are taken at a rate of 25seconds/shoot as the model is already at the scene. What is the maximum number of photo shoots taken under 10 minuntes ?
(A) 13
(B) 14
(C) 15
(D) 16
(E) 17
Rationale: a must be an integer as it is the number shoots at a rate of 25sec/shoot
3*60 + 25a = 10*60
25a = 420
a = 16
The total number of shoots -->1 +16 = 17 and
18th shoot will be taken at 605seconds which is above 10 minutes
ANSWER: E
Answer: (E) 17
Question: What is the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 2 m high?
(A) 7
(B) 12.8
(C) 11
(D) 13
(E) None
Rationale: Explanation:
d2 = 122 + 42 + 22 = 12.8
B)
Answer: (B) 12.8
Question: How many three letter words are formed using the letters of the word TIME?
(A) 20
(B) 55
(C) 76
(D) 24
(E) 42
Rationale: The number of letters in the given word is four.
The number of three letter words that can be formed using these four letters is ⁴P₃
= 4 * 3 * 2 = 24.
Answer: D
Answer: (D) 24
Question: A car travels first 160 km at 75 km/hr and the next 160 km at 70 km/hr. What is the average speed for the first 320 km of the tour?
(A) 71.11
(B) 71.12
(C) 72.4
(D) 71.17
(E) 71.13
Rationale: Car travels first 160 km at 75 km/hr
Time taken to travel first 160 km = distancespeed=160/75
Car travels next160 km at 70 km/hr
Time taken to travel next 160 km = distancespeed=160/70
Total distance traveled = 160+160=2×160
Total time taken = 160/75+160/70
Average speed = Total distance traveled/Total time taken=320/(160/75+160/70)=72.4 km/hr
Answer:C
Answer: (C) 72.4
Question: Mangala completes a piece of work in 10 days, Raju completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is?
(A) 8 days
(B) 12 days
(C) 14 days
(D) 16 days
(E) 18 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 × 40/50 = 8 days
A)
Answer: (A) 8 days
Question: raghu, working alone, can paint a room in 6 hours. Peter and John, working independently, can paint the same room in 3 hours and 2 hours, respectively. Tom starts painting the room and works on his own for one hour. He is then joined by Peter and they work together for an hour. Finally, John joins them and the three of them work together to finish the room, each one working at his respective rate. What fraction of the whole job was done by Peter?
(A) 4/9
(B) 1/6
(C) 1/3
(D) 7/18
(E) 1/9
Rationale: Let's use smart numbers here -->Work=18
Rate * Time = Work
Tom: 3 x 6 = 18
Peter: 6 x 3 = 18
John: 9 x 2 = 18
Before John joined Tom and Peter: Tom worked 2 Hours -> 2*3=6 and Peter 1*6=6 gives us 12. So we are left with 18-12=6 for all three of them --> (3+6+9)*t=6, thus t=1/3 this means that Peter worked 2+1/3 Hours = 6+2=8 --> 8/18=4/9
At least this approach helps me... Don't like dealind with fractions when you're tired.
Answer:a
Answer: (A) 4/9
Question: Divide $ 1162 among A, B, C in the ratio 35 : 28 : 20.
(A) 490,490,490
(B) 360,392,460
(C) 490,382,280
(D) 260,160,60
(E) 492,390,280
Rationale: Sum of ratio terms = (35 + 28 + 20) = 83.
A's share = $ (1162 x (35/83))= $ 490; B's share = $ (1162 x(28/83))= $. 392;
C's share = $ (1162 x (20/83))= $ 280.
Option C
Answer: (C) 490,382,280
Question: What is the measure of the radius of the circle inscribed in a triangle whose sides measure 4, 11 and 12 units?
(A) 1.6 units
(B) 6 units
(C) 3 units
(D) 5 units
(E) 12 units
Rationale: Sides are 4, 11 and 12...thus it is right angle triangle Since 12^2 = 4^2 + 11^2
therefore, area = 1/2 * 11 * 4 = 22
We have to find in-radius
Therefore, area of triangle = S*r ....where S=semi-perimeter and r= in-radius
Now S=semi-perimeter = 12+11+4 /2 =13,5
Thus , 22 =13,5*r
and hence r=in-radius= 1.6
Option A
Answer: (A) 1.6 units
Question: The parameter of a square is equal to the perimeter of a rectangle of length 16 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)
(A) 23.56
(B) 23.54
(C) 23.51
(D) 23.52
(E) 23.57
Rationale: Let the side of the square be a cm.
Parameter of the rectangle = 2(16 + 14) = 60 cm Parameter of the square = 60 cm
i.e. 4a = 60
A = 15
Diameter of the semicircle = 15 cm
Circimference of the semicircle
= 1/2(∏)(15)
= 1/2(22/7)(15) = 330/14 = 23.57 cm to two decimal places
Answer: E
Answer: (E) 23.57
Question: A garrison of 2000 men has provisions for 54 days. At the end of 21 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement?
(A) 1977
(B) 1893
(C) 1979
(D) 1900
(E) 1300
Rationale: 2000 ---- 54
2000 ---- 33
x ----- 20
x*20 = 2000*33
x = 3300
2000
-------
1300
Answer: E
Answer: (E) 1300
Question: Carol is three times Alice’s age but only twice as old as Betty. Alice is twenty years younger than Carol. How old is Betty?
(A) 26
(B) 29
(C) 32
(D) 28
(E) 15
Rationale: Beyond the obvious Algebra approach to this question, it can also be solved by TESTing THE ANSWERS.
We're told 3 facts about the relative ages of 3 people:
1) Carol's age is 3 times Alice's age
2) Carol's age is 2 times Betty's age
3) Carol is 20 years older than Alice
We're asked for BETTY'S age.
From the answer choices and the information provided, Carol can't be that old (The difference of 20 years = 3 times; that relationship can only occur when the numbers are relatively small). Since Carol is TWICE Betty's age, Betty is clearly younger than Carol, so we'll TEST a smaller answer first.
IF....
Betty = 15
Then Carol = 2(15) = 30
Then Alice = 30 - 20= 10 AND 30/3 = 10
All of these values mesh perfectly with the facts and with one another, so Betty MUST be 15
E
Answer: (E) 15
Question: A pharmaceutical company received $3 million in royalties on the first $20 million in sales of and then $9 million in royalties on the next $108 million in sales. By approximately what percentage did the ratio of royalties to sales decrease from the first $20 million in sales to the next $108 million in sales?
(A) 8%
(B) 15%
(C) 45%
(D) 52%
(E) 56%
Rationale: First ratio= 3/20=15%
second ratio = (3+12)/(9+108)=15/117= 12,8%
decrease = 2,2%
2,2%/15%=15% approximately.
ANSWER:B
Answer: (B) 15%
Question: Rs.160 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio 4:5:6. What is the number of 25 paisa coins?
(A) 100
(B) 110
(C) 120
(D) 125
(E) 130
Rationale: 4x 5x 6x
100 50 25
400x + 350x + 150x = 16000
x = 20
6x = 120
ANSWER C
Answer: (C) 120
Question: Joe drives 600 miles at 60 miles per hour, and then he drives the next 120 miles at 40 miles per hour. What is his average speed for the entire trip in miles per hour?
(A) 42
(B) 55
(C) 50
(D) 54
(E) 56
Rationale: t1= 600/60=10 hours
t2=120/40=3 hours
T=t1+t2=13 hours
Avg speed = Total Distance/T
= 720/13 = 55mph=B
Answer: (B) 55
Question: Two pipes A and B can fill a cistern in 12 and 20 minutes respectively, and a third pipe C can empty it in 30 minutes. How long will it take to fill the cistern if all the three are opened at the same time?
(A) 15 min
(B) 13 min
(C) 12 min
(D) 10 min
(E) 17 min
Rationale: 1/12 + 1/20 - 1/30
= 1/10
10/1 = 10
Answer:D
Answer: (D) 10 min
Question: What number should replace the question mark?
24, 30, ?, 60, 84, 114
(A) 45
(B) 44
(C) 48
(D) 42
(E) 49
Rationale: D
42
The sequence progresses +6, +12, +18, +24, +30.
Answer: (D) 42
Question: 4 pipes can fill a reservoir in 15, 20, 30 and 60 hrs the first was opened at 6 am and 2nd at 7 am and thirds at 8 am and 4th at 9 am when will the reservoir be full?
(A) 6 hrs
(B) 7 hrs
(C) 8 hrs
(D) 9 hrs
(E) 10 hrs
Rationale: Explanation:
let time be t hrs after 6 am
t/15 + (t-1)/30 + (t-2)/30 + (t-3)/60 =1
t = 7 hrs
Answer: Option B
Answer: (B) 7 hrs
Question: A man took loan from a bank at the rate of 8% p.a. simple interest. After 4 years he had to pay $250 interest only for the period. The principal amount borrowed by him was:
(A) $881.25
(B) $781.25
(C) $761.35
(D) $661.25
(E) $681.55
Rationale: Principal(P) = ?
Time(T) = 4 years
Simple Interest(SI) = $250
R = 8%
P = 100×SI / RT=100×250 / 8×4 = $781.25
ANSWER:B
Answer: (B) $781.25
Question: A train is approaching a tunnel which is AB in length.Ther is a cat inside the tunnel which is 3/8 distance from the starting point of the tunnel.When the train whistes the cat starts to run.The train catches the cat exactly at the entry point of the tunnel.If the cat runs towards the exit,the train catches tha cat exactly at the exit point.The speed of the train is greater than the speed of the cat in what order?
(A) 1:4
(B) 4:1
(C) 1:3
(D) 3:1
(E) 1:2
Rationale: D / v1 = (3/8) x / v2 ... ( 1 )
( D + x ) / v1 = (5/8) x / v2
=> D / v1 = (5/8) x / v2 - x / v1 ... ( 2 )
From equns. ( 1 ) and ( 2 ),
(3/8) x /v2 = (5/8) x / v2 - x / v1
=> 3 / (8v2) = 5 (8v2) - 1/ v1
=> 1 / v1 = ( 5/8 - 3/8) / v2
=> 4v2 = v1
ANSWER:B
Answer: (B) 4:1
Question: If M and N are positive integers that have remainders of 2 and 3, respectively, when divided by 5, which of the following could NOT be a possible value of M+N?
(A) 80
(B) 52
(C) 35
(D) 25
(E) 10
Rationale: M=5p+2
N=5q+3
We need M+N=5p+2+5q+3=5(p+q)+5
Pick numbers for pq
Since it is an addition of pq and the answer to this expression should be an integer (because all the numbers being added are integers),
we just need to choose values so that we get integer multiples of 5 so
p+q=0 ; M+n = 5
p+q=1 ; M+N = 10
P+q=2 ; M+N = 15
and so on, so basically you get something like - 5,,10,15,20,25,30,..... all are multiples of 5 except 52
So Answer B.
Answer: (B) 52
Question: What are the last two digits of 63*35*37*82?
(A)  10
(B)  30
(C)  40
(D)  70
(E)  80
Rationale: We know that to find the last two digits, we need to find the remainder we get when we divide the product by 100.
Remainder of (63*35*37*82*71*41)/ 100
Note that we can simplify this expression by canceling out the 5 and 2 in the numerator and denominator. But before we do that, here is an important note:
Note: We cannot just cancel off the common terms in the numerator and denominator to get the remainder. But, if we want to cancel off to simplify the question, we can do it, provided we remember to multiply it back again.
So say, we want to find the remainder when 14 is divided by 10 i.e. 14/10 (remainder 4). But we cancel off the common 2 to get 7/5. The remainder here will be 2 which is not the same as the remainder obtained by dividing 14 by 10. But if we multiply 2 back by 2 (the number we canceled off), the remainder will become 2*2 = 4 which is correct.
Take another example to reinforce this – what is the remainder when 85 is divided by 20? It is 5.
We might rephrase it as – what is the remainder when 17 is divided by 4 (cancel off 5 from the numerator and the denominator). The remainder in this case is 1. We multiply the 5 back to 1 to get the remainder as 5 which is correct.
So keeping this very important point in mind, let’s go ahead and cancel the common 5 and 2.
We need the
Remainder of (63*7*37*41*71*41*5*2)/10*5*2
Remainder of (63*7*37*41*71*41)/10
Now using concept 2, let’s write the numbers in form of multiples of 10
Remainder of (60+3)*7*(30+7)*(40+1)*(70+1)*(40+1)/10
Remainder of 3*7*7*1*1*1/10
Remainder of 147/10 = 7
Now remember, we had canceled off 10 so to get the actual remainder so we need to multiply by 10: 7*10 = 70.
When 63*35*37*82*71*41 is divided by 100, the remainder is 70. So the last two digits of 63*35*37*82*71*41 must be 30.
Answer (B)
Answer: (B)  30
Question: Samantha is driving from City A to City B. The distance between the two cities is 88 miles. She is driving at a constant speed of 22 miles per hour, and has been travelling for half an hour after starting from City A. What percent of the total distance she is yet to cover?
(A) 87
(B) 87.5
(C) 88
(D) 90
(E) 97.5
Rationale: She is driving at the rate of 22 miles per hour for half an hour.
Means the distance she has covered so far is = speed x time = 22 miles per hour x 0.5 hour = 11 miles.
Therefore, the distance she is yet to cover is 88 - 11 = 77 miles.
We want to know 77 miles is what percent of the total distance (88 miles). Let it be x % of the total distance.
This means x % of 88 = 77
Solving we get, x = 87.5
Ans B
Answer: (B) 87.5
Question: Laura took out a charge account at the General Store and agreed to pay 8% simple annual interest. If she charges $35 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments?
(A) $2.10
(B) $37.10
(C) $37.16
(D) $37.8
(E) $38.80
Rationale: Principal that is amount taken by Laura at year beginning = 35$
Rate of interest = 8%
Interest = (8/100)*35 = 2.8$
Total amount that Laura owes a year later = 35+2.8 = 37.8 $
Answer D
Answer: (D) $37.8
Question: What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 3?
(A) 897
(B) 164,850
(C) 164,749
(D) 149,700
(E) 156,720
Rationale: Explanatory Answer
Step 1: Identify the series
The smallest 3 digit number that will leave a remainder of 2 when divided by 3 is 101.
The next couple of numbers that will leave a remainder of 2 when divided by 3 are 104 and 107.
The largest 3 digit number that will leave a remainder of 2 when divided by 3 is 998.
It is evident that any number in the sequence will be a 3 digit positive integer of the form (3n + 2).
So, the given numbers are in an Arithmetic sequence with the first term being 101 and the last term being 998 and the common difference being 3.
Step 2: Compute the sum
Sum of an Arithmetic Progression (AP) = [first term + last term/2]n
We know the first term: 101
We know the last term: 998.
The only unknown is the number of terms, n.
In an A.P., the nth term an = a1 + (n - 1)*d
In this case, therefore, 998 = 101 + (n - 1)* 3
Or 897 = (n - 1) * 3
(n - 1) = 299 or n = 300.
Sum of the AP will therefore, be [101+998/2]∗300 = 164,850
Choice B is the correct answer.
Answer: (B) 164,850
Question: Insert the missing number.
8, 7, 11, 12, 14, 17, 17, (....)
(A) 27
(B) 20
(C) 22
(D) 24
(E) 26
Rationale: There are two series (8, 11, 14, 17) and (7, 12, 17, 22) increasing by 3 and 5 respectively.
answer : C
Answer: (C) 22
Question: Car E and Car Y traveled the same 80-mile route. If Car E took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car E, how many hours did it take Car Y to travel the route?
(A)  2/3
(B)  1
(C)  4/3
(D)  8/5
(E)  3
Rationale: The speed of car E is (distance)/(time) = 80/2 = 40 miles per hour.
The speed of car Y = 3/2*40 = 60 miles per hour --> (time) = (distance)/(speed) = 80/60 = 4/3 hours.
Answer: C.
Or: to cover the same distance at 3/2 as fast rate 2/3 as much time is needed --> (time)*2/3 = 2*2/3 = 4/3 hours.
Answer: C.
Answer: (C)  4/3
Question: What is the product of all the prime factors of 22?
(A) 18
(B) 9
(C) 22
(D) 6
(E) 3
Rationale: 22 , factors are 2,11,1. Now again prime Numbers are Only Two i.e 2 and 11 , this time we would have 2*11=22
Answer : C
Answer: (C) 22