mathewhe/aqua_rat huggingface dataset:
Question: A rectangular box has two sides whose
lengths are 3 centimeters and 9 centimeters
and a volume of 135 cm3. What is the area
of its largest side?
(A) 27 cm2*square
(B) 36 cm2*square
(C) 39 cm2*square
(D) 45 centimeter square
(E) 48 cm2*square
Rationale: The box has dimensions of 3 and 9 and a volume of 135, so plug these values into the
formula for the volume of a box:
V=lwh=>
135=(3)(9)h=>
135=27h=>
5h
So the remaining dimension of the box is 5. The two longest dimensions are 5 and 9, so the
area of the largest side is 5 × 9 = 45
correct answer D)45 cm2*square
Answer: (D) 45 centimeter square
Question: If both 5^2 and 3^3 are factors of n x (2^5) x (12^2) x (7^3), what is the smallest possible positive value of n?
(A) 25
(B) 75
(C) 125
(D) 150
(E) 175
Rationale: (2^5) x (12^2) x (7^3) has two appearances of 3 (in 12^2) and no appearances of 5.
Thus n must include at least 3 * 5^2 = 75
The answer is B.
Answer: (B) 75
Question: One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill tank in 39 min, then the slower pipe alone will be able to fill the tank in?
(A) 229
(B) 156
(C) 144
(D) 128
(E) 121
Rationale: Let the slower pipe alone fill the tank in x min.
Then, faster pipe will fill it in x/3 min.
1/x + 3/x = 1/39
4/x = 1/39 => x = 156 min.
Answer: B
Answer: (B) 156
Question: A boy is travelling from his home to school at 5 km/hr and reached 7 min late. Next day he traveled at 10 km/hr and reached 8 min early. Distance between home and school?
(A) 2.5km
(B) 3.5km
(C) 4.5km
(D) 5.5km
(E) 6.5km
Rationale: Let the distance be x
T1 = x/5 hr
T2 = x/10hr
Difference in time = 7+8 = 15 =1/4hr
x/5-x/10 = 1/4
x/10 = 1/4
x = 2.5 km
Answer is A
Answer: (A) 2.5km
Question: Two spherical balls lie on the ground touching. If one of the balls has a radius of 8 cm, and the point of contact is 12 cm above the ground, what is the radius of the other ball (in centimeters)?
(A) 20
(B) 24
(C) 28
(D) 32
(E) 36
Rationale: A straight line will join the two centers and the point of contact, thus making similar triangles.
4/8 = (r-12)/r
4r = 8r - 96
r = 24
The answer is B.
Answer: (B) 24
Question: Simplify
70âˆ’[5âˆ’(6+2(7âˆ’8âˆ’5Â¯Â¯Â¯Â¯Â¯Â¯Â¯Â¯Â¯Â¯Â¯))]
(A) 23
(B) 25
(C) 28
(D) 79
(E) 32
Rationale: Explanation:
=70âˆ’[5âˆ’(6+2(7âˆ’8+5))]
(Please check due to overline, sign has been changed)
=70âˆ’[5âˆ’(6+2Ã—4))]
=70âˆ’[âˆ’9]=70+9=79
Option D
Answer: (D) 79
Question: Each month, after Jill pays for rent, utilities, food, and other necessary expenses, she has one fifth of her net monthly salary left as discretionary income. Of this discretionary income, she puts 30% into a vacation fund, 20% into savings, and spends 35% on eating out and socializing. This leaves her with $102 dollar, which she typically uses for gifts and charitable causes. What is Jill’s net monthly salary?
(A) $3400
(B) $3200
(C) $6000
(D) $6400
(E) $9600
Rationale: let x be the monthly salary
15%of 1/5*x=102
x=3400
answer A
Answer: (A) $3400
Question: Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg.
(A) 1 : 3
(B) 2 : 3
(C) 3 : 4
(D) 4 : 5
(E) 5 : 6
Rationale: Cost of 1 kg of 1st kind 720 p
Cost of 1 kg of 2nd kind 570 p
Mean Price 630 p
Required ratio = 60 : 90 = 2 : 3.
Answer:B
Answer: (B) 2 : 3
Question: If y is 90% greater than x, than x is what % less than y?
(A) 35.7%
(B) 39.8%
(C) 43.2%
(D) 47.4%
(E) 51.2%
Rationale: y = 1.9x
x = y/1.9 = 10y/19
x is 9/19 less which is 47.4% less than y.
The answer is D.
Answer: (D) 47.4%
Question: Find out the wrong term.
2, 5, 10, 50, 500, 5000
(A) 5
(B) 10
(C) 50
(D) 5000
(E) 500
Rationale: 2*5=10
5*10=50
10*50=500
50*?=5000
ANSWER:D
Answer: (D) 5000
Question: What is the average of 1/2, 2/5 and 1/10?
(A) 1/5
(B) 3/10
(C) 2/5
(D) 1/2
(E) 4/15
Rationale: Sum of 1/2,2/5,1/10 =8/10
Average = 8/10*1/3 =4/15
Answer E 4/15
Answer: (E) 4/15
Question: John invests $x at the semi-annual constant compounded rate of 2 percent and also does $20,000 at the quarterly constant compounded rate of 4 percent. If the interests are the same after 1 year, what is the value of x??
(A) 40,402
(B) 40404
(C) 40000
(D) 50000
(E) 50005
Rationale: A = P(1+r/n)^nt
A= total amount accrued
P = principal deposited
r = rate of interest in decimal form
n = number of times per year, interest compounded
t = time in number of years.
.
x(1+0.02/2)^2 - x = 20,000(1+0.04/4)^4 - 20,000 [ when the principal is subtracted from the total amount accrued , the resulting difference is the interest portion and question states interests are equal)
=> x[(1.01)^2 - 1] = 20,000[(1.01)^4 - 1]
=> x[(1.01)^2 - 1] = 20,000[(1.01)^2+1][(1.01)^2-1] --> Using a^2-b^2 = a+b X a-b formula and cancel common expression on both sides
=> x = 20,000(1.0201+1) =40,402.
Hence answer is A.
Answer: (A) 40,402
Question: 10^23-7 is divided by 6, remainder is?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: Anything power by 10 we got 10 and some zeros after that.(i.e,1000000000000000....)
On that, we minus 7 means, we must get last two digits is 93.
And 93 is divided by 6, we get reminder 3.
ANSWER:A
Answer: (A) 3
Question: Arjun started a business with Rs. 20,000 and is joined afterwards by Anoop with Rs.30, 000. After how many months did Anoop join if the profits at the end of the year are divided equally?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: Suppose Anoop joined after 3 months.
Then, 20000 * 12 = 30000 * (12 – x)
=> 120000 = 30000x
=> x = 4.
ANSWER:B
Answer: (B) 4
Question: John's Bank's saving amount is decreased 12% due to loan payment and current balance is Rs.44000. Find the actual balance before deduction?
(A) 8000
(B) 50000
(C) 9000
(D) 9500
(E) 10000
Rationale: 12% decreased
88% Balance = 44000
100% = 44000/88*100 = 50000
Answer : B
Answer: (B) 50000
Question: In a two-digit, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is?
(A) 12
(B) 24
(C) 36
(D) 38
(E) 40
Rationale: Let the ten's digit be x.
Then, unit's digit = x + 2.
Number = 10x + (x + 2) = 11x + 2.
Sum of digits = x + (x + 2) = 2x + 2.
(11x + 2)(2x + 2) = 144
22x2 + 26x - 140 = 0
11x2 + 13x - 70 = 0
(x - 2)(11x + 35) = 0
x = 2.
Hence, required number = 11x + 2 = 24.
Option B
Answer: (B) 24
Question: 3A = 4B = 5C, A : B : C = ?
(A) 12:15:22
(B) 20:15:12
(C) 15:20:12
(D) 12:20:15
(E) None of these
Rationale: Explanation :
Solution: 3A = 4B = 5C,
A : B : C = 1/3 : 1/4 : 1/5
=> 20/60 : 15/60 : 12/60 = 20 : 15 : 12
Answer : B
Answer: (B) 20:15:12
Question: Find the value of y from (12)^3 x 6^4 ÷ 432 = y?
(A) 2435
(B) 1243
(C) 1509
(D) 3456
(E) 5184
Rationale: Given Exp. = (12)3 x 64 = (12)3 x 64 = (12)2 x 62 = (72)2 = 5184
432 12 x 62
E
Answer: (E) 5184
Question: In a certain fish pond, 1 out of every 120 bass are caught. If 3 out of every 4 caught bass are fried for dinner, and there are 9 fried bass for dinner, how many bass total are there in the pond?
(A) 5,000
(B) 700
(C) 500
(D) 1,222
(E) 1,440
Rationale: Proportions: Let B = bass, and Bc = bass caught, and Bcf = caught fried bass.
9Bcf/xBc = 3Bcf/4Bc
xBc = 12Bc
12Bc/yB = 1Bc/120B
yB = 1,440B
Answer: E
Answer: (E) 1,440
Question: Reena took a loan of $. 1200 with simple interest for as many years as the rate of interest. If she paid $ 300 as interest at the end of the loan period, what was the rate of interest?
(A) 5
(B) 6
(C) 18
(D) Cannot be determined
(E) None of these
Rationale: Let rate = R% and time = R years.
Then,1200 x R x R/100= 300
12R2 = 300
R2 = 25
R = 5.
Answer:A
Answer: (A) 5
Question: The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
(A) 2
(B) 3
(C) 1
(D) 7
(E) 4
Rationale: Let the ages of the children be x, (x + 3), (x + 6), (x + 9) and (x +12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20 => x = 4.
Age of youngest child = x = 4 years.
answer is E.
Answer: (E) 4
Question: The angle between the minute hand and the hour hand of a clock when the time is 8.30, is
(A) 35°
(B) 65°
(C) 45°
(D) 75°
(E) 95°
Rationale: Angle between hands of a clock
When the minute hand is behind the hour hand, the angle between the two hands at M minutes past H 'o clock
=30(H−M/5)+M/2 degree
When the minute hand is ahead of the hour hand, the angle between the two hands at M minutes past H 'o clock
=30(M/5−H)−M/2 degree
Here H = 8, M = 30 and minute hand is behind the hour hand.
Hence the angle
=30(H−M/5)+M/2
=30(8−30/5)+30/2
=30(8−6)+15
=30×2+15 =75°
Answer is D.
Answer: (D) 75°
Question: A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.18000. A's share is?
(A) 228
(B) 278
(C) 600
(D) 288
(E) 121
Rationale: x* 12 : 2x* 6: 3x* 4
1:1:1
1/3 * 18000 = 600
Answer: C
Answer: (C) 600
Question: R is the set of positive even integers less than 20, and S is the set of the squares of the integers in R. How many elements does the intersection of R and S contain ?
(A) None
(B) Two
(C) three
(D) Five
(E) Seven
Rationale: squares < 20 {1,4,9,16}
S = {1,4,9,16}
R = {2,.....18}
Hence C.
Answer: (C) three
Question: Let q represent the integer length of a side of a triangle. If r represents the number of distinct values for q such that we can create a triangle with lengths q, 10, and 12, what is the value of r?
(A) 17
(B) 18
(C) 19
(D) 20
(E) 21
Rationale: From the triangle inequality rule, the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. So, the three inequalities are:
1. q + 10 > 12
2. 10 + 12 > q
3. q + 12 > 10
Equation 3 is true for any positive value of q.
From equation 1, q > 2
From equation 2, 22 > q
Then 22 > q > 2 so q can be any value from 3 to 21 inclusive.
The number of possible values is 19.
The answer is C.
Answer: (C) 19
Question: The sum of the two numbers is 12 and their product is 35. What is the sum of the reciprocals of these numbers?
(A) 12/35
(B) 1/35
(C) 35/8
(D) 7/32
(E) None of these
Rationale: Let the numbers be a and b. Then, a+b=12 and ab =35.
a+b/ab=12/35; (1/b+1/a)=12/35
Sum of reciprocals of given numbers=12/35.
Correct Option: A
Answer: (A) 12/35
Question: The greatest number by which the product of three consecutive multiples of 7 is always
(A) 54
(B) 81
(C) 162
(D) 243
(E) None of these
Rationale: Explanation:
7*14*21 = 2058
Option E
Answer: (E) None of these
Question: If a number is formed by writing integers 1 to 150 one after another, like 12345...150. How many digits does this integer consists of?
(A) 150
(B) 339
(C) 342
(D) 359
(E) 362
Rationale: 1-digit integers
Number of 1-digit integers (1 to 9) = 9 - 1 + 1 = 9
Number of digits used = (9)(1) = 9
2-digit integers
Number of 2-digit integers (10 to 99) = 99 - 10 + 1 = 90
Number of digits used = (90)(2) = 180
3-digit integers
Number of 3-digit integers (100 to 150) = 150 - 100 + 1 = 51
Number of digits used = (51)(3) = 153
TOTAL # of digits uses = 9 + 180 + 153 = 342
Answer: C
Answer: (C) 342
Question: The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 24 years. Find the average age of the women?
(A) 25 years
(B) 20 years
(C) 30 years
(D) 15 years
(E) 10 years
Rationale: Answer: Option C
20 + 24 + 8 * 2 = 60/2 = 30
Answer: (C) 30 years
Question: A piece of work can be done by Ram and shyam in 12 days, By shyam Nad hari in 15 days and by hari and ram in 20 days. Ram alone can complete the work in how much days ?
(A) . 30
(B) . 35
(C) . 25
(D) . 32
(E) . 28
Rationale: Rate*Time = Work
Since the work done is same throughout the question so we can take the work done as 1
Let Rate of Ram be R, Hari be H and Shaym be S
A piece of work can be done by Ram and shyam in 12 days
When Ram and Shyam will work together then their rate will be added. So combined rate will be R+S
(R+S)*12 = 1
R+S = 1/12 ...(1)
By shyam Nad hari in 15 days
Similarly
S+H = 1/15 ...(2)
hari and ram in 20 days
Similarly
H+R = 1/20 ...(3)
(2)-(3)
S+H - (H+R) = 1/15 - 1/20
=> S-R = 1/60 ..(4)
(1) - (4)
R + S - (S - R) = 1/12 - 1/60 = 4/60 = 1/15
2R = 1/15 => R = 1/30
Ram alone can complet the work in how much days ?
R * t = 1
t = 1/R = 1/ (1/30) = 30 days
So, Answer will be A
Answer: (A) . 30
Question: John has 4 friends who want to ride in his new car that can accommodate only 3 people at a time (John plus 2 passengers). How many different combinations of 2 passengers can be formed from John's 4 friends?
(A) 6
(B) 8
(C) 10
(D) 15
(E) 18
Rationale: 4C2 = 6
The answer is A.
Answer: (A) 6
Question: As x increases from 165 to 168, which of the following must increase?
I. 2x - 5
II. 1 - 1/x
III. 1/(x^2 - x)
(A)  I only
(B)  III only
(C)  I and II
(D)  I and III
(E)  II and III
Rationale: I. 2x - 5 --> x increases from 165 to 168 --> 2x increases --> 2x - 5 increases. Correct.
II. 1 - 1/x --> x increases from 165 to 168 --> 1/x decreases --> 1 -1/x increases. Correct.
III. 1/(x^2 - x) --> x increases from 165 to 168 --> x^2-x increases --> 1/(x^2 - x) decreases.
Answer: C.
Answer: (C)  I and II
Question: The charge for a single room at Hotel P is 50 percent less than the charge for a single room at Hotel R and 10 percent less than the charge for a single room at Hotel G. The charge for a single room at Hotel R is what percent greater than the charge for a single room at Hotel G?
(A) 45%
(B) 50%
(C) 60%
(D) 80%
(E) 90%
Rationale: P = 0.5R = 0.9G
R = 0.9G/0.5 = 1.8*G
Thus R is 80% greater than G.
The answer is D.
Answer: (D) 80%
Question: What is the minimum number of years upon which SI on Rs 2600 at 6.67% interest rate will be in whole number?
(A) 2
(B) 6
(C) 3
(D) 4
(E) 5
Rationale: Explanation:
Simple Interest =Principal * Rate * Time
Principal = 2600 Rs
Interest Rate = 6.67%
=> SI = 2600 * (20/3)*Time
SI of the number will be a whole number for the first time when time is three as denominator of rate is 3.
Hence time should be set to 3 years.
ANSWER C
Answer: (C) 3
Question: Three partners A, B, C in a business invested money such that 5(A’s capital) = 7(B’s capital) = 9(C’s capital) then, The ratio of their capitals is
(A) 63 : 45 : 34
(B) 63 : 54 : 34
(C) 36 : 54 : 28
(D) 63 : 45 : 35
(E) None of these
Rationale: Explanation:
Let 5(A’s capital) = 7(B’s capital) = 9(C’s capital) = Rs.x
Then, A’s capital = Rs x/5, B’s capital = Rs. x/7 and C’s capital = Rs. x/9.
A : B : C = x/5 : x/7 : x/9
63 : 45 : 35
Answer: Option D
Answer: (D) 63 : 45 : 35
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
(A) 165 m
(B) 167 m
(C) 987 m
(D) 150 m
(E) 168 m
Rationale: Speed=(60 * 5/18) m/sec
= (50/3) m/sec Length of the train
= (Speed x Time) = (50/3 * 9) m
= 150 m.
Answer: D
Answer: (D) 150 m
Question: a man owns 2/3 of market reserch beauro buzness,and sells 3/4 of his shares for 75000rs,what is the value of buzness?
(A) 150000
(B) 160000
(C) 170000
(D) 190000
(E) 250000
Rationale: If value of business=x
Total sell (2x/3)(3/4)=75000
->x=150000
ANSWER:A
Answer: (A) 150000
Question: A train is running at a speed of 40 km/hr and it crosses a post in 18 seconds. What is the length of the train?
(A) metres
(B) metres
(C) metres
(D) metres
(E) metres
Rationale: Explanation:
Speed of the train, v = 40 km/hr = 40000/3600 m/s = 400/36 m/s
Time taken to cross, t = 18 s
Distance Covered, d = vt = (400/36)× 18 = 200 m
Distance covered is equal to the length of the train = 200 m
Answer: Option C
Answer: (C) metres
Question: If 15% of A is the same as 30% of B, then A : B is :
(A) 1:4
(B) 4:3
(C) 6:7
(D) 3:5
(E) 2:1
Rationale: Expl : 15% of A I= 30 % of B =15A/100 = 30B/100 = 2/1 = 2:1
Answer:E
Answer: (E) 2:1
Question: In the accounting branch of a commercial institute, the percentage of male and female workers is 48% and 52% respectively. In this branch, 40% of males and 20% of females are age 25 or older. If one of the workers is selected at random, what is the probability R that the worker is under 25 years old?
(A)  0.30
(B)  0.25
(C)  0.45
(D)  0.70
(E)  0.90
Rationale: Percentage of male worker = 48
Percentage of female worker = 52
Let total number of workers = 1000
number of male workers= 480
number of female workers = 520
Number of male age 25 or older = (4/10)*480 = 192
Number of female age 25 or older =(2/10)*520 = 104
Total number of workers 25 or older = 192+104 = 296
Total number of workers under 25 = 1000 - 296 = 704
Probability that a worker randomly selected is under 25 years old = 704/1000 = .704
Alternatively , since the answer options are not close , we can use estimation here .
Percentage of male worker 25 or older = (4/10)*48 = 20 % approx
Percentage of female worker 25 or older = (2/10)*52 = 10 % approx
Percentage of total worker 25 or older = 30 %
Percentage of total worker under 25 = 70 %
Probability that a worker randomly selected is under 25 years old R= .7
Answer D
Answer: (D)  0.70
Question: If 76 is divided into four parts proportional to 7, 5, 3, 4 then the smallest part is
(A) 12
(B) 15
(C) 16
(D) 19
(E) 20
Rationale: Sol.
Given ratio = 7 : 5 : 3 : 4, Sum of ratio terms = 19.
∴ Smallest part =[76x3/19] = 12.
Answer A
Answer: (A) 12
Question: The H.C.F of two numbers is 36 and their L.C.M is 1600. If one of the numbers is 160, find the other?
(A) 320
(B) 350
(C) 360
(D) 330
(E) 320
Rationale: Explanation:
The other number is = 36 * 1600/160 = 360
Answer: Option C
Answer: (C) 360
Question: The function f(W) represents the number of ways that prime numbers can be uniquely summed to form a certain number W such that W = a + b + c + d… where those summed variables are each prime and a ≤ b ≤ c ≤ d ... For instance f(8) = 3 and the unique ways are 2 + 2 + 2 + 2 and 2 + 3 + 3 and 3 + 5. What is f(12)?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: So It is better to start with 2 and check whether sum of two primes is primes is even.
1) 2(6 times)
2) 2(3 times) + 3(2 times)
3) 2(2 times) + 3 + 5
4) 2 + 3 + 7
5) 2 + 5 + 5
6) 3(4 times)
7) 5 + 7
Answer: D
Answer: (D) 7
Question: Which of the following is closest to 1/3+1/33+1/333
(A) 2/3
(B) 1/3
(C) 1/4
(D) 1/6
(E) 1/5
Rationale: 1/3+1/33+1/333=0.33+0.03+0.003=0.333=1/3
Answer B
Answer: (B) 1/3
Question: When you draw 2 dices together, find the probability of getting a total of 6?
(A) 3/13
(B) 2/31
(C) 5/36
(D) 7/41
(E) 7/43
Rationale: S = {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}
N (S) = 36
Set of total of 6, A = {(1,5), (5,1), (2,4), (4,2), (3,3)}; N (A) = 5
P (total of 6) = N(A)N(S)N(A)N(S) = 5/36
C
Answer: (C) 5/36
Question: Find the area of a parallelogram with base 34 cm and height 18 cm?
(A) 198 cm2
(B) 384 cm2
(C) 510 cm2
(D) 612 cm2
(E) 680 cm2
Rationale: Area of a parallelogram
= base * height
= 34 * 18 = 612 cm2
Answer:D
Answer: (D) 612 cm2
Question: The sum of three consecutive multiples of 3 is 90. What is the largest number?
(A) 30
(B) 33
(C) 36
(D) 39
(E) 42
Rationale: Let the numbers be 3x, 3x + 3 and 3x + 6.
Then,
3x + (3x + 3) + (3x + 6) = 90
9x = 81
x = 9
Largest number = 3x + 6 = 33
Answer : B
Answer: (B) 33
Question: An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the cases?
(A) 8:8
(B) 8:7
(C) 8:1
(D) 8:2
(E) 8:6
Rationale: Let the length and breadth of the carpet in the first case be 3x units and 2x units respectively.
Let the dimensions of the carpet in the second case be 7y, 3y units respectively.
From the data,.
2(3x + 2x) = 2(7y + 3y)
=> 5x = 10y
=> x = 2y
Required ratio of the areas of the carpet in both the cases
= 3x * 2x : 7y : 3y
= 6x2 : 21y2
= 6 * (2y)2 : 21y2
= 6 * 4y2 : 21y2
= 8:7
Answer: B
Answer: (B) 8:7
Question: After taking N tests, each containing 100 questions, John had an average of 70% of correct answers. How much does John need to score on the next test to make his average equal 74%?
M13-03.
(A) N−35
(B) N+72
(C) 2N+76
(D) 2N+70
(E) 2N−35
Rationale: Say N=1.
So, after 1 test John has 70 correct answers.
In 2 tests, so in 200 questions he needs to have 0.74*200=148 correct answers, so in the second test he must get 148-70=78 questions correctly.
Now, plug N=1 into the answer choices to see which one yields 78. Only option D fits.
Answer: C.
Answer: (C) 2N+76
Question: What is the units' digit of the following expression (13)^5*(15)^4*(17)^5?
(A) 0
(B) 1
(C) 3
(D) 5
(E) 9
Rationale: The unit digit of 3^5 is 3.
The unit digit of 5^4 is 5
the unit digit of 7^5 is 7.
The unit digit of 3∗5∗7 is 5.
Answer D.
Answer: (D) 5
Question: By selling an article for $180, a person gains $30. What is the gain %?
(A) 25%
(B) 30%
(C) 50%
(D) 20%
(E) 10%
Rationale: S.P. = $180
Gain = $30
C.P. = 180-30 = 150
Gain% = 30/150 * 100 = 20%
Answer is D
Answer: (D) 20%
Question: All of the stocks on the over-the-counter market are designated by either a 6-letter or a 7-letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be designated with these codes?
(A) 2(26^5)
(B) 26(26^4)
(C) 27(26^4)
(D) 26(26^5)
(E) 27(26^6)
Rationale: Number of 4-letter codes: 26 * 26 * 26 * 26 * 26 * 26= 26^6
Number of 5-letter codes: 26 * 26 * 26 * 26 * 26 * 26 *26= 26^7
Total Number of codes: 26^6 + 26^7 = 26^6 + 26*(26^6) = 27*(26^6)
Therefore, the answer isE: 27*(26^6).
Answer: (E) 27(26^6)
Question: What will come in place of the x in the following Number series? 6, 12, 21, x , 48
(A) 33
(B) 45
(C) 49
(D) 53
(E) 61
Rationale: (A)
The pattern is + 6, + 9, + 12, +15 ………..
So the missing term is = 21 + 12 = 33
Answer: (A) 33
Question: The total price of a basic computer and printer are $2,500. If the same printer had been purchased with an enhanced computer whose price was $500 more than the price of the basic computer, then the price of the printer would have been 2/5 of that total. What was the price of the basic computer?
(A) 1300
(B) 1600
(C) 1750
(D) 1900
(E) 2000
Rationale: Let the price of basic computer be C and the price of the printer be P: C+P=$2,500.
The price of the enhanced computer will be C+500 and total price for that computer and the printer will be 2,500+500=$3,000. Now, we are told that the price of the printer is 2/5 of that new total price: P=2/5*$3,000=$1200.
Plug this value in the first equation: C+1200=$2,500 --> C=$1,300.
Answer: A.
Answer: (A) 1300
Question: A sells a Cricket Bat to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays $234 for it, the cost price of the Cricket Bat for A is:
(A) 156
(B) 120
(C) 130
(D) 160
(E) 210
Rationale: 125% of 120% of A = 234
125/100 * 120/100 * A = 234
A = 234 * 2/3 = 156.
ANSWER A
Answer: (A) 156
Question: A train 400 m long can cross an electric pole in 20 sec and then find the speed of the train?
(A) 17 Kmph
(B) 78 Kmph
(C) 72 Kmph
(D) 18 Kmph
(E) 19 Kmph
Rationale: Length = Speed * time
Speed = L/T
S = 400/20
S = 20 M/Sec
Speed= 20*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 72 Kmph
Answer: C
Answer: (C) 72 Kmph
Question: Select the one which is different from other Four alternatives.
(A) ROAD
(B) BOARD
(C) DOOR
(D) SET
(E) WINDOW
Rationale: D
All the option has two vowels but option (D) has only one vowel
Answer: (D) SET
Question: Which one of the following numbers is the greatest positive integer x such that 3^x is a factor of 729^5?
(A) 5
(B) 8
(C) 10
(D) 15
(E) 30
Rationale: 729 = 3*3*3*3*3*3== 3^36
729^5 =(3^6)^5
=3^30
we have to find the greatest positive integer value for x
when x=30, it divides exactly once and that is the least positive integer value of the quotient
therefore, the correct option is E
Answer: (E) 30
Question: Solve below question 2x + 1 = -11
(A) -8
(B) -6
(C) 9
(D) 8
(E) -7
Rationale: 2x + 1 = -11
x = -6
B
Answer: (B) -6