mathewhe/aqua_rat huggingface dataset:
Question: I came across this problem in the GMATprep software and got it totally wrong!
A company consists of 6 senior and 4 junior staff officers. If a committee is created with 3 senior and 2 junior staff officers, how many possible committees are there?
(A) 12
(B) 44
(C) 56
(D) 120
(E) 200
Rationale: 6C3*4C2
=120=D
Answer: (D) 120
Question: Find 20 % of 240
(A) 96
(B) 94
(C) 86
(D) 74
(E) 48
Rationale: We know that R % of m is equal to R/100 × m.
So, we have 20 % of 240
20/100 × 240
= 48
Answer:E
Answer: (E) 48
Question: In what ratio must rice at Rs 9.30 per Kg be mixed with rice at Rs 10.80 per Kg so that the mixture be worth Rs 10 per Kg?
(A) 5:7
(B) 8:7
(C) 7:3
(D) 3:8
(E) 4:7
Rationale: Cost of 1 kg of 1st kind=930 P
Cost of 1 kg of 2nd kind=1080 P
Mean Price=1000 P
Cost of 1 kg of 1st kind - Mean Price=1000-930= 70
Cost of 1 kg of 2nd kind- Mean Price=1080-1000=80
Required ratio = 80 : 70 = 8 : 7
Answer:B
Answer: (B) 8:7
Question: The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is
(A) 48
(B) 22
(C) 56
(D) 27
(E) 35
Rationale: Explanation:
Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.
Answer: Option A
Answer: (A) 48
Question: A dealer sells his goods 10% less at cost price uses 850gm weight for 1kg his gain or loss percentage is
(A) 21% Gain
(B) 21% Loss
(C) 17 11/17% Gain
(D) 17 11/17% Loss
(E) None of these
Rationale: Explanation:
Cost price ---> 850
Selling price --->1000 - 100 = 900
= ( 900 ~ 850 )/850 * 100 = 150/850 * 100 = 17 11/17% Gain
Answer: Option C
Answer: (C) 17 11/17% Gain
Question: Find the circumference of radius 7 cm.
(A) 44
(B) 55
(C) 66
(D) 77
(E) 88
Rationale: Circumference of circle = 2πr
= 2 × 22/7 × 7
= 44 cm
ANSWER : A
Answer: (A) 44
Question: If a boat goes 7 km upstream in 42 minutes and the speed of the stream is 3 kmph, then the speed of the boat in still water is
(A) 12 kmph
(B) 13 kmph
(C) 14 kmph
(D) 15 kmph
(E) None of these
Rationale: Explanation:
Rate upstream = (7/42)*60 kmh = 10 kmph.
Speed of stream = 3 kmph.
Let speed in sttil water is x km/hr
Then, speed upstream = (x —3) km/hr.
x-3 = 10 or x = 13 kmph
Option B
Answer: (B) 13 kmph
Question: At the wholesale store you can buy an 8-pack of hot dogs for $1.55, a 20-pack for $3.05, and a 250-pack for $22.95. What is the greatest number of hot dogs you can buy at this store with $220?
(A) 1,108
(B) 2,100
(C) 2,108
(D) 2,124
(E) 2,218
Rationale: I can buy 9 250-pack for Rs 22.95*9 = $206.55
Now, I can buy 5 20-pack for 3.05*5 = $15.25
Now, I am left with only $1.15. I cannot but anything with this.
Hence Total Hotdogs = 250*8 + 20*5 = 2218
E
Answer: (E) 2,218
Question: Of the science books in a certain supply room, 50 are on botany, 60 are on zoology, 90 are on physics. 40 are on geology, and 110 are on chemistry. If science books are removed randomly from the supply room, how many must be removed to ensure that 80 of the books removed are on the same science?
(A) 81
(B) 159
(C) 309
(D) 285
(E) 324
Rationale: First, you can take all 50 Botany books, all 60 zoology books and all 40 geology books because you're sure to never pick 80 of them.
There are still 90 on physics and 110 on chemistry
The worst case could be that we pick 79 physics and 79 chemistry. So that the next book picked will necessary complete 80 books picked, either in physics or chemistry.
Minimum number of books picked to reach 80 in the same science should be : 50 + 60 + 40 + 79 +79 + 1 = 309
C
Answer: (C) 309
Question: Find the average of all the numbers between 6 and 34 which are divisible by 5.
(A) 18
(B) 20
(C) 24
(D) 30
(E) 32
Rationale: Solution
Average	= (10+15+20+25+30/5)
= 100 / 5
= 20.
Answer B
Answer: (B) 20
Question: How many 5 digit no. can b formed with digits 1, 2, 3,4,5,6 which r divisible by 4 and digits not repeated?
(A) 189
(B) 190
(C) 191
(D) 192
(E) 193
Rationale: for a no. to be divisible by 4, last two digit should be divisible by 4
last tw0 digit can be 12,16,24,32,36,52,56,64 (8 possibilities)
remaining 3 places can be filled in 4*3*2 ways for each
total 5 digit no. formed = 8*4*3*2 = 192
ANSWER:D
Answer: (D) 192
Question: In a school seats for Maths, Physics and Biology in a school are in the ratio 1:2:3. There is a proposal to increase these seats by 10%,20% and 30%. What will be the ratio of increased seats?
(A) 1:4:9
(B) 16:34:47
(C) 11:24:39
(D) 15:42:77
(E) 5:15:26
Rationale: Let the number of seats of M,P,B be x,2x,3x
Number of increased seats are 110% of x , 120% of 2x , 130% of 3x
x*110/100 , 2x*120/100 and 3x*130/100
i.e. 11x/10, 12x/5 and 39x/10
Required ratio = 11x:24x : 39x = 11:24:39
Answer is C
Answer: (C) 11:24:39
Question: In an election between the two candidates ,The candidates who gets 60% of votes polled is wined by 280 votes majority. What is the total number of votes polled?
(A) 1400
(B) 1500
(C) 1600
(D) 1700
(E) 1800
Rationale: Note : majority (20 %) = difference in votes polled to win (60 %) & defeated candidates (40 %)
20 % = 60 % - 40 %
20% -----> 280 (20×14 = 280 )
100% -----> 1400 (100×14 = 1400)
A
Answer: (A) 1400
Question: The length of a rectangular hall is 5m more than its breadth. The area of the hall is 750 m. The length of the hall is?
(A) 22
(B) 25
(C) 27
(D) 19
(E) 12
Rationale: Let breadth = x m
Then, length = (x+5)m
x(x+5) = 750
x² + 5x - 750= 0
(x+30)(x-25)= 0
x = 25
Answer: B
Answer: (B) 25
Question: A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?
(A) 32:42
(B) 32:41
(C) 32:45
(D) 32:49
(E) 32:47
Rationale: A : B
(8000*4)+(4000*8) : (9000*6)+(6000*6)
64000 : 90000
32 : 45
Answer: C
Answer: (C) 32:45
Question: A sum of Rs.4500 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
(A) Rs.2925
(B) Rs.3120
(C) Rs.3320
(D) Rs.2760
(E) None of these
Rationale: Let A be the amount received at the end of the three years.
A = 4500[1 + 10/100][1 + 20/100][1 + 25/100]
A = (4500 * 11 * 6 * 5)/(10 * 5 * 4)
A = Rs.7425
So the interest = 7425 - 4500 = Rs.2925
ANSWER:A
Answer: (A) Rs.2925
Question: If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
(A) 3 days
(B) 4 days
(C) 5 days
(D) 6 days
(E) 7 days
Rationale: Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, (6x + 8y) = 1/10 and (26x + 48y) = 1/2.
Solving these two equations, we get : x = 1/100	and y = 1/200.
(15 men + 20 boy)'s 1 day's work = (15/100 + 20/200) = 1/4.
Therefore, 15 men and 20 boys can do the work in 4 days.
CORRECT OPTION: "B".
Answer: (B) 4 days
Question: A train running at the speed of 180 km/hr crosses a pole in 18 seconds. What is the length of the train?
(A) 800
(B) 900
(C) 950
(D) 1000
(E) 1050
Rationale: Speed=(180 x(5/18)m/sec	=(50)m/sec.
Length of the train = (Speed x Time).
Length of the train =	((50)x 18)m = 900 m
B
Answer: (B) 900
Question: If (4,000)(5,000) = (20)(1,000^x), what is the value of x?
(A) 5
(B) 4
(C) 3
(D) 2
(E) 1
Rationale: (4,000)(5,000) = (20)(1,000^x)
=> (4,000)(5,000)/20 = 1,000^x
=> 1,000,000 = 1,000^x
=> 1,000^2 = 1,000^x
Since, base is same so powers will be same too.
So, x=2
Answer will be D
Answer: (D) 2
Question: If a certain number of labours can dig earth 100m deep, 25m long, and 30m broad in 12 days, then find the number of days the same number of labours will require to dig earth 75m deep, 20m long and 50m broad.
(A) 12
(B) 18
(C) 6
(D) 1
(E) 2
Rationale: Explanation :
More number of days means more length, more depth and more width. Hence, its a direct proportion.
(100*25*30):(75*20*50) :: 12:x
75000:75000::12:x
x = 12
Answer : A
Answer: (A) 12
Question: In a bag there are a certain number of orange balls and blue balls. The probability of picking up exactly 1 blue ball when 2 balls are randomly drawn, is 1/2. Which of the following is the ratio of the number of orange balls to blue balls in the bag
(A) 2:1
(B) 1:1
(C) 1:31
(D) 1:3
(E) 1:5
Rationale: since the probability of drawing a blue ball out of two picks is 1/2.
the ratio of the blue ball to orange balls should be 1:1
Answer : B
Answer: (B) 1:1
Question: The simple interest on a sum of money will be Rs.400 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year?
(A) 2261
(B) 2888
(C) 1200
(D) 800
(E) 2771
Rationale: P --- 10 ---- 400
P --- 5 ----- 200
3P --- 5 ----- 600
------
=> 800
Answer: D
Answer: (D) 800
Question: Club X has more than 20 but fewer than 50 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 4 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: The number of members is 4j+3 = 5k+4.
Let's start at 4(5)+3 = 23 and keep adding 4 until we find a number in the form 5k+4.
23, 27, 31, 35, 39 = 5(7) + 4
The club has 39 members.
39/6 = 6(6) + 3
The answer is C.
Answer: (C) 3
Question: What is the rate percent when the simple interest on Rs.800 amount to Rs.144 in 4 Years?
(A) 5%
(B) 8%
(C) 3%
(D) 4.5%
(E) 1%
Rationale: 144 = (800*4*R)/100
R = 4.5%
Answer: D
Answer: (D) 4.5%
Question: A man can row upstream at 40 kmph and downstream at 52 kmph, and then find the speed of the man in still water?
(A) 27
(B) 40
(C) 42
(D) 46
(E) 24
Rationale: US = 40
DS = 52
M = (40 + 52)/2
= 46
Answer:D
Answer: (D) 46
Question: Find the value of x from the below equation: x^2−7x+10=0
(A) 5 or 2
(B) 1 or 3
(C) 1 or 7
(D) 3 or 5
(E) None
Rationale: Here we need to find out a and b such that a + b = -7 and ab = +10
a = -5 and b = -2 satisfies the above condition.
Hence
x^2−7x+10=(x−5)(x−2)
x2−7x+10=(x−5)(x−2)
x^2−7x+10
=0
⇒(x−5)(x−2)
=0
x2−7x+10=0⇒(x−5)(x−2)=0
Step 3: Equate each factor to 0 and solve the equations
(x−5)(x−2)
=0
⇒(x−5)
=0or (x−2)=0
⇒x= 5 or 2
A
Answer: (A) 5 or 2
Question: In a certain store, the profit is 150% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
(A) 30%
(B) 70%
(C) 100%
(D) 50%
(E) 120%
Rationale: Let C.P. = Rs. 100. Then, profit = Rs. 150, S.P. = Rs. 250
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 250
Profit = 250 - 125 = Rs. 125
Required percentage = 125/250 * 100 = 50%
ANSWER:D
Answer: (D) 50%
Question: What percent of a day is six hours?
(A) 20.83%
(B) 25%
(C) 18x2/3%
(D) 22x1/2%
(E) None of these
Rationale: Explanation :
Required percentage = (6/24100)%
= 25%.
Answer : B
Answer: (B) 25%
Question: Pipe A fills a tank in 6 minutes. Pipe B can fill the same tank 2 times as fast as pipe A. If both the pipes are kept open when the tank is empty, how many minutes will it take to fill the tank?
(A) 0.5
(B) 1.0
(C) 1.5
(D) 2.0
(E) 2.5
Rationale: A's rate is 1/6 and B's rate is 1/3.
The combined rate is 1/6 + 1/3 = 1/2
The pipes will fill the tank in 2 minutes.
The answer is D.
Answer: (D) 2.0
Question: For a certain cylinder, the diameter equals the height. If every length in this cylinder is decreased by 60%, then to the nearest integer, by what percent does the volume decrease?
(A) 22%
(B) 40%
(C) 60%
(D) 84%
(E) 94%
Rationale: Again, the exact dimensions of the cylinder do not matter, as long as every length increases by the same percent or same ratio. We now have a percent decrease, which means we subtract to construct our multiplier. A 60% decrease means we have a multiplier of 1 – 0.60 = 0.4, and so k = 0.4 as well. For volume we need to cube the scale factor: k^3 = (0.4)^3 = 0.064 {approx} 0.06 approximately. That would be the multiplier for a 94% decrease, because 1 – 0.94 = 0.06; therefore, the volume decreases by 94%. Answer = E.
Answer: (E) 94%
Question: The C.P of 20 pens is equal to the S.P of 12 pens. Find his gain % or loss%?
(A) 10%
(B) 20%
(C) 30%
(D) 40%
(E) 50%
Rationale: 20 CP = 12 SP
20 --- 8 CPgain
100 --- ? => 40%
Answer: D
Answer: (D) 40%
Question: Divide $5000 among X,Y in the ratio 2:8. How many $ that X get?
(A) $1000
(B) $1050
(C) $1100
(D) $1150
(E) $1200
Rationale: Sum of ratio terms = 2+8 = 10
X = 5000*2/10 = $1000
Answer is A
Answer: (A) $1000
Question: There are 250 doctors and nurses at a hospital. If the ratio of doctors to nurses is 2 to 3, how many nurses are at the hospital?
(A) 134
(B) 138
(C) 142
(D) 146
(E) 150
Rationale: The number of nurses at the hospital is (3/5)*250=150.
The answer is E.
Answer: (E) 150
Question: If an integer n is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8?
(A) 1/4
(B) 3/8
(C) 1/2
(D) 5/8
(E) 3/4
Rationale: total nos of ways in which we can choose n = 96
n(n + 1)(n + 2) will be divisible by 8?
case 1: n = odd then n+2 =odd & n+1 will be even i.e this needs get divided by 8, hence is a multiple of 8 so we have 8..96 = 12 multiples to fill the n+1 pos hence 12 ways
case 2: n is even then n+2 will be even & the product will be divisible by 24 & thus 8
so nos of values that can be used for n= 2....96 (all even nos) i.e 48 nos
total = 48+12 =60 ways
so reqd P =60/96 =5/8;
ANSWER:D
Answer: (D) 5/8
Question: There is 50% increase in an amount in 6 years at S.I. What will be the C.I. of Rs. 12,000 after 3 years at the same rate?
(A) 2160
(B) 3120
(C) 17988
(D) 6240
(E) 5240
Rationale: Let P = Rs. 100. Then, S.I. Rs. 50 and T = 6 years.
R = (100 * 50)/(100 * 6) = 10% p.a.
Now, P = Rs. 12000, T = 3 years and R = 8.33% p.a.
C.I. = [12000 * {(1 + 8.33/100)3 - 1}]
= Rs. 17988
ANSWER:C
Answer: (C) 17988
Question: The average marks obtained by 50 candidates in a certain examination is 40.Find the total marks.
(A) 1800
(B) 2000
(C) 1640
(D) 2200
(E) 2400
Rationale: Following the above formula, we have the total marks =50*40=2000
Answer is B
Answer: (B) 2000
Question: If 20% of (x-y) = 15% of (x+y), then what percent of x is y?
(A) 50.5%
(B) 44.4%
(C) 22.2%
(D) 14.3%
(E) 25%
Rationale: 20% of (x-y) = 15% of (x+y)
20/100 (x-y) = 15/100 (x+y)
5x = 35y
Required percentage = y/x *100 = 5y/35y * 100 = 14.28%
Answer is D
Answer: (D) 14.3%
Question: 4,6,12,24,36,48....
(A) 58
(B) 60
(C) 61
(D) 62
(E) 63
Rationale: 2*2=4
3*2=6
6*2=12
12*2=24
18*2=36
24*2=48
30*2=60
ANSWER:B
Answer: (B) 60
Question: 30 men shake hands with each other. Maximum no of handshakes without cyclic handshakes.
(A) 190
(B) 200
(C) 210
(D) 220
(E) 435
Rationale: or, if there are n persons then no. of shakehands = nC2 = 30C2 = 435
ANSWER:E
Answer: (E) 435
Question: If a - b = 3 and a2 + b2 = 29, find the value of ab.
(A) 10
(B) 12
(C) 13
(D) 15
(E) 18
Rationale: 2ab = (a2 + b2) - (a - b)2
= 29 - 9 = 20
ab = 10.
answer :A
Answer: (A) 10
Question: A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline
than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type
of gasoline that costs 20% less per gallon than does the gasoline used by a T-Car. If the two
cars are driven the same distance, what percent less than the money spent on gasoline for the
T-Car is the money spent on gasoline for the P-Car?
(A) 16 2/3%
(B) 33 1/3 %
(C) 50%
(D) 55.56%
(E) 66 2/3 %
Rationale: Assumption
Miles/Gallon
T = 100
P = 180 ( 80% more)
$/gallon
T = 100
P = 80 (20% less)
Miles
100 for both
Cost = (Miles X $/ Gallon)/ M/gallon
T = 100
P = 44.44
Hence 100 - 44.44 =55.56%
Ans D
Answer: (D) 55.56%
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:
(A) 14
(B) 17
(C) 19
(D) 22
(E) 24
Rationale: Let the son's present age be x years. Then, (38 - x) = x
2x = 38.
x = 19.
Son's age 5 years back (19 - 5) = 14 years.
Answer : A
Answer: (A) 14
Question: he total marks obtained by a student in Physics, Chemistry and Mathematics is 110 more than the marks obtained by him in Physics. What is the average mark obtained by him in Chemistry and Mathematics?
(A) 55
(B) 65
(C) 75
(D) 85
(E) 95
Rationale: Let the marks obtained by the student in Physics, Chemistry and Mathematics be P, C and M respectively.
P + C + M = 110 + P
C + M = 110
Average mark obtained by the student in Chemistry and Mathematics = (C + M)/2 = 110/2 = 55.
ANSWER:A
Answer: (A) 55
Question: The investment of A, B, and C in a business are in the ratio 3:1:4. The total investment is Rs. 60,000. Find the investment made by each.
(A) 22500, 7500, 30000
(B) 22000, 8000, 30000
(C) 23500, 7500, 29000
(D) 23000, 8500, 28500
(E) 23000, 8000, 29000
Rationale: ratio of the investment is 3:1:4
Total investment =60000
so, 8x = 60000 ie)x =7500
so the investment of A, B,C are : A's investment 3x = 22500 B's investment x = 7500 C's investment 4x =30000
ANSWER:A
Answer: (A) 22500, 7500, 30000
Question: On dividing 13698 by a certain number, we get 89 as quotient and 14 as remainder. What is the divisor?
(A) 743
(B) 154
(C) 852
(D) 741
(E) 785
Rationale: Divisor *quotient+remainder=dividend
divisor=(dividend)-(remainder)/quotient
(13698-14)/89=154
Answer(B)
Answer: (B) 154
Question: A train speeds past a pole in 15 sec and a platform 100 m long in 25 sec, its length is?
(A) 218
(B) 150
(C) 167
(D) 166
(E) 112
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 100)/25 = x/15 => x = 150 m.
Answer: B
Answer: (B) 150
Question: In a company with 48 employees, some part-time and some full-time, exactly (1/3) of the part-time employees and (1/4) of the full-time employees take the subway to work. What is the greatest possible number Q of employees who take the subway to work?
(A) 12
(B) 13
(C) 14
(D) 15
(E) 16
Rationale: P/3 + F/4 = P/3 + (48-P)/4 = 12 + P/2
P/3 + F/3 = (P+F)/3 = 48/3 = 16
P/4 + F/4 = 12
P/3 + F/3 > P/3 + F/4 > P/4 + F/4
--> 16> 12 + P/12 > 12
GREATEST Possible Q: 12 + p/12 = 15 --> p = 36 ( integer --> good)
15 or D is the answer
Answer: (D) 15
Question: In the junior basketball league there are 15 teams, 1/3 of them are bad and ½ are rich. What can't be the number of teams that are rich and bad?
(A) 4.
(B) 6.
(C) 7.
(D) 8.
(E) 9.
Rationale: total teams =15
bad teams=(1/3)*15=5
rich teams=8
so maximum value that the both rich and bad can take will be 8. so E= 9 can not be that value.
ans E.
Answer: (E) 9.
Question: A man is 26 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is?
(A) 16
(B) 19
(C) 15
(D) 24
(E) 10
Rationale: Let the son's present age be x years.
Then, man's present age = (x + 26) years.
(x + 26) + 2 = 2(x + 2)
x + 28 = 2x + 4
=> x =24 .
Answer: D
Answer: (D) 24
Question: Two numbers are in the ratio of 5:7. If 25 be subtracted from each, they are in the ratio of 35:59. Find the numbers?
(A) 60,89
(B) 60,88
(C) 60,86
(D) 60,84
(E) 60,81
Rationale: (5x-25):(7x-25) = 35:59
x = 12 => 60,84
Answer: D
Answer: (D) 60,84
Question: If u r genius solve it:-
40 * 14 = 11
30 * 13 = 12
20 * 12 = 6
10 * 11 = 2
9 * 10 = ?
(A) 2
(B) 4
(C) 6
(D) 9
(E) 10
Rationale: Logic :
40*14=560=5+6+0=11
30*13=390=3+9+0=12
20*12=240=2+4+0=6
10*11=110=1+1+0=2
So 9*10=90=9+0=9
Answer : D
Answer: (D) 9
Question: The simple interest accrued on an amount of Rs.49500 at he end of three is Rs.17820. What would be the compound interest accured on the same amount at teh same rate in the same period? (Round off your answer to two decimal places)
(A) 20043.94
(B) 38933.3
(C) 93832.39
(D) 29334.93
(E) 20483.33
Rationale: Let the rate of interest be R% p.a.
(49500)(3)(R)/100 = 17820
495R = 5940
R = 12
CI on Rs.49500 at 12% p.a. for three years
= 49500{[1 + 12/100]3 - 1} = 69543.936 - 49500 = Rs.20043.94
when rounded off to two decimal places.
Answer: A
Answer: (A) 20043.94
Question: Bucket P has thrice the capacity as bucket Q. It takes 80 turns for bucket P to fill the empty drum. How many turns it will take for both the buckets P and Q, having each turn together to fill the empty drum?
(A) 30
(B) 45
(C) 60
(D) 80
(E) 100
Rationale: Explanation:
Let capacity of Q =1 litre.
Then, capacity of P =3 litre.
Given that it takes 80 turns for bucket P to fill the empty drum.
=> capacity of the drum =80×3=240 litre.
Number of turns required if both P and Q are used having each turn together
240/3+1 =60 litre.
Answer: Option C
Answer: (C) 60
Question: 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.90 only. Men’s wages are?
(A) 6Rs
(B) 8Rs
(C) 9Rs
(D) 1Rs
(E) 2Rs
Rationale: 5M = xW = 8B
5M + xW + 8B ----- 90 Rs.
5M + 5M + 5M ----- 90 Rs.
15M ------ 90 Rs. => 1M =6Rs.
Answer:A
Answer: (A) 6Rs
Question: What is the sum of the different positive prime factors of 350?
(A) 10
(B) 11
(C) 14
(D) 16
(E) 18
Rationale: 350
35*10 --> 5*7*2*5 --> 5+7+2=14. Remember its asking for the DIFFERENT positive prime factors of 350.
C
Answer: (C) 14
Question: The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
(A) 328
(B) 279
(C) 245
(D) 288
(E) 211
Rationale: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.Answer: C
Answer: (C) 245
Question: The manufacturing cost of a shoe is Rs.190 and the transportation lost is Rs.500 for 100 shoes. What will be the selling price if it is sold at 20% gains
(A) s 234
(B) s 216
(C) s 220
(D) s 210
(E) s 217
Rationale: Explanation :
Total cost of a watch = 190 + (500/100) = 195.
Gain = 20% => SP = 1.2CP = 1.2 X 195 = 234
Answer : A
Answer: (A) s 234
Question: One night 19 percent of the female officers on a police force were on duty. If 152 police officers were on duty that night and half of these were female officers, how many female officers were on the police force?
(A) 300
(B) 350
(C) 400
(D) 450
(E) 500
Rationale: Let x be the number of female police officers on the police force.
The number of female police officers on duty was 76.
0.19x = 76
x = 400
The answer is C.
Answer: (C) 400
Question: If the number is decreased by 5 and divided by 7 the result is 7. What would be the result if 14 is subtracted and divided by 10?
(A) 4
(B) 7
(C) 8
(D) 5
(E) 3
Rationale: Explanation:
Let the number be x. Then,
(x - 5)/7 = 7 => x - 5 = 49
x = 54
.: (x - 14)/10 = (54 - 14)/10 = 4
Answer: Option A
Answer: (A) 4
Question: 200 is what percent of 50?
(A) 0.2%
(B) 2%
(C) 5%
(D) 20%
(E) 400%
Rationale: 200= x*50/100
x = 400%
Ans; E
Answer: (E) 400%
Question: 3-5*6+2=
(A) A)2
(B) B)-13
(C) C)-18
(D) D)-17
(E) E) -25
Rationale: 3-5*6+2 = 5-30 = -25...
so the answer is -25... E
Answer: (E) E) -25
Question: What is the remainder of W=3^19 when divided by 10?
(A) 0
(B) 1
(C) 5
(D) 7
(E) 9
Rationale: I looked for patterns:
^2 - units digit 9
^3 - units digit 7
^4 - units digit 1
^5 - units digit 3
hence, we can see that when raised to a power which is multiple of 4, the units digit is 1, and when to an even power not multiple of 4, the units digit is 9
and we can then see:
^16 - units digit 1, or
^18 - units digit 9
and ^19 - units digit 7
therefore, W=when divided by 10, the remainder must be 7.D
Answer: (D) 7
Question: A, B and C enter into a partnership. A invests 3 times as much as B invests and 2/3 of what C invests. At the end of the year, the profit earned is Rs. 11000. What is the share of C?
(A) Rs. 2250
(B) Rs. 3000
(C) Rs. 6750
(D) Rs. 5625
(E) None of these
Rationale: Explanation:
Let the investment of C be Rs. x.
The inverstment of B = Rs.(2x/3)
The inverstment of A = Rs. (3 × (2/3)x) = Rs. (2x)
Ratio of capitals of A, B and C = 2x : 2x/3 : x = 6 : 2 : 3
C's share = Rs. [(3/11) × 11000] = Rs. 3000
Answer: Option B
Answer: (B) Rs. 3000