mathewhe/aqua_rat huggingface dataset:
Question: A computer manufacturer produces a certain electronic component at a cost of $75 per component. Shipping costs for delivering the components are $2 per unit. Further, the manufacturer has costs of $16,500 a month related to the electronic component regardless of how many it produces. If the manufacturer produces and sells 150 components a month, what is the lowest price it can sell them for such that the costs don't exceed the revenues?
(A) $28
(B) $187
(C) $110
(D) $138
(E) $192
Rationale: This question can be solved easily using a equation model.
150*p = 16500(fixed cost) + 150*75+150*2.
= 16500 + 11250 + 300
P= $187
B
Answer: (B) $187
Question: A, B and C started a partnership business by investing Rs.5000, Rs.8000, Rs.9000 respectively. At the end of the year , the profit were distributed among them. If C's share of profit is 36000, What is the total profit?
(A) 70000
(B) 60000
(C) 88000
(D) 90000
(E) 50000
Rationale: A:B:C =5000:8000:9000
=5:8:9
Let total profit =p
Then pÃ—9/22=36000
p=(36000Ã—22)/9=88000
Answer is C.
Answer: (C) 88000
Question: A pupil’s marks were wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by half. The number of pupils in the class is:
(A) 10
(B) 20
(C) 40
(D) 73
(E) None of the above
Rationale: Let there be x pupils in the class.
Total increase in marks = (x × 1⁄2) = x⁄2.
∴ x⁄2 = (83 - 63) ⇒ x⁄2 = 20 ⇒ x = 40.
Answer C
Answer: (C) 40
Question: The manager of a produce market purchased a quantity of tomatoes for $0.80 per pound. Due to improper handling, 20 percent of the tomatoes, by weight, were ruined and discarded. At what price per pound should the manager sell the remaining tomatoes if she wishes to make a profit on the sale of the tomatoes equal to 8 percent of the cost of the tomatoes.
(A) $0.94
(B) $0.96
(C) $0.98
(D) $1.00
(E) $1.09
Rationale: Assume the manager bought 100 tomatoes.
Cost Price = 80
Given: 20% are damaged --> Available tomatoes to sell = 80
80 * x - 80 = 0.08 * 80
80x - 80 = 6.4
80x = 86.64
x = 86.64/80 = 87/80 (approx) = 1.0875
x is slightly under 1.0875 = 1.09
Answer: E
Answer: (E) $1.09
Question: In the rectangular coordinate system Point O has coordinates (0,0) and Point B has coordinates (6,6) and if point A is equidistant from points O and B and the area of the triangle OAB is 16, which of the following are the possible coordinates of point A.
(A) (-2,6)
(B) (0,4)
(C) (2,-6)
(D) (2,6)
(E) (4,8)
Rationale: Area.pngSince A is equidistant from points O and B, then it must be somewhere on the green line (perpendicular bisector of OB).
(2,-6) and (2,6) are not on that line. If A is at (0,6) or (6,0), then the area is 1/2*6*6=18. Thus A must be at (4,8).
Answer: E.
Answer: (E) (4,8)
Question: The average age of 3 boys is 25 years and their ages are in the proportion 3:5:7. The age of the youngest boy is?
(A) 10years
(B) 15years
(C) 20years
(D) 25years
(E) 18years
Rationale: Total age of 3 boys = 25*3 = 75
ratio of their ages = 3:5:7
Age of the youngest = 75*3/15 = 15 years
Answer is B
Answer: (B) 15years
Question: Ram professes to sell his goods at the cost price but he made use of 900 grms instead of a kg, what is the gain percent?
(A) 11 1/98%
(B) 11 9/9%
(C) 11 1/9%
(D) 12 1/9%
(E) 41 1/9%
Rationale: 900 --- 100
100 --- ? => 11 1/9%
Answer:C
Answer: (C) 11 1/9%
Question: Mohan's salary was first increased by 20% and then decreased by 20%. If his present salary is Rs. 7200, then what was his original salary?
(A) Rs.7528
(B) Rs.7500
(C) Rs.7527
(D) Rs.7522
(E) Rs.7572
Rationale: Let Mohan's salary be Rs.100.
When increased by 20%, Mohan's salary = Rs.120
Again when decreased by 20%, Mohan's salary = 120 - 24 = Rs. 96.
But present salary is Rs. 7200
for, 96 ---> 100 ; 7200 ---> ?
Required salary is 7200/96 * 100
=Rs.7500
Answer:B
Answer: (B) Rs.7500
Question: Sam is training for the marathon. He drove 13 miles from his home to the Grey Hills Park and then ran 6 miles to Red Rock, retraced his path back for 2 miles, and then ran 3 miles to Rock Creek. If he is then n miles from home, what is the range of possible values for n?
(A) 1 ≤ n ≤23
(B) 3 ≤ n ≤21
(C) 5 ≤ n ≤19
(D) 6 ≤ n ≤20
(E) 9 ≤ n ≤15
Rationale: ANSWER: C To find the maximum and minimum range for his distance from home, assume that he traveled either directly toward his home or directly away from his home. The range then is between 13+6-2+3=20 for the maximum, and 13-6+2-3=6 for the minimum, so D is the answer
Answer: (D) 6 ≤ n ≤20
Question: For a certain set, the value range of its members is 88.8. A new set is created from the members of the old set as follows: 12 is subtracted from a member of the old set, and the result is divided by 4. The resulting value is a member of the new set. If this operation is done for each member of the old set, what is the range of values of the members of the new set?
(A) 19.2
(B) 22.2
(C) 36.6
(D) 44.4
(E) 88.8
Rationale: Let x and z be the smallest and largest of the original set, respectively.
z - x = 88.8
The smallest and largest members of the new set will be (x-12) / 4 and (z-12) / 4.
Then the range is (z-12) / 4 - (x-12) / 4 = (z-x) / 4 = 88.8 / 4 = 22.2
The answer is B.
Answer: (B) 22.2
Question: Eight persons participated in a shooting competition. The top score in the competition is 85 points. Had the top score been 92 points instead of 85 points, the average score would have been 84. Find the number of points actually scored in the competition.
(A) 645
(B) 655
(C) 665
(D) 636
(E) 646
Rationale: Exp. Let the actual number of points scored be x,
Then [ x + (92 –85 )] /8 = 84, ( x + 7) /8 = 84 , x = ( 84*8 )- 7,
= 672 - 7 = 665
Answer: C
Answer: (C) 665
Question: If a rooster laid 13 eggs, and the farmer took 8 of them, and then another rooster laid 12 eggs and 4 of them were rotten, how many of the eggs were left?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
Rationale: A
0
Roosters don't lay no eggs!
Answer: (A) 0
Question: When a number is divided by 13, the remainder is 11. When the same number is divided by 17, then remainder is 9. What is the number ?
(A) 300
(B) 349
(C) 500
(D) 550
(E) 370
Rationale: x = 13p + 11 and x = 17q + 9
13p + 11 = 17q + 9
17q - 13p = 2 => q = 2+13p/17
least value of p for which q = 2+13p/17 is whole no is p = 26
x = (13*26+11) = 349
ANSWER B
Answer: (B) 349
Question: What is the sum of all the multiples of 25 between 30 and 100?
(A) 800
(B) 625
(C) 600
(D) 250
(E) 200
Rationale: You first have to know all the multiples of 25 between 30 and 100. They are 25,50,75and100. If you add all these numbers together, you get 250.
Final Answer: D
Answer: (D) 250
Question: On a map the distance between two mountains is 312 inches. The actual distance between the mountains is 136 km. Ram is camped at a location that on the map is 34 inch from the base of the mountain. How many km is he from the base of the mountain?
(A) 14.83
(B) 14.81
(C) 14.8
(D) 14.82
(E) 14.12
Rationale: Explanation:
Since 312 inch = 136 km
So 1 inch = 136/312 km
So 34 inch = (136 × 34)/ 312 = 14.82 km
Answer: D
Answer: (D) 14.82
Question: Each of the integers from 4 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 10?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: Answer is 3. In the worst case, you could end up drawing 4,5. 7th draw will result in either of 6,7,8,9 which would result in the numbers adding to 10.
A
Answer: (A) 3
Question: Concentrated apples juice comes inside a cylinder tube with a radius of 2.5 inches and a height of 15 inches. The tubes are packed into wooden boxes, each with dimensions of 11 inches by 10 inches by 31 inches. How many tubes of concentrated apples juice, at the most, can fit into 3 wooden boxes?
(A) 24.
(B) 28.
(C) 36.
(D) 42.
(E) 48.
Rationale: Concentrated apples juice comes inside a cylinder tube since height of a tube is 15 inches , the tubes can fit only in one way now, diameter of each tube = 5 inches
therefore, 4*2 can be put in each wooden box
in 3 boxes 3*4*2 can be accommodated
= 24=A
Answer: (A) 24.
Question: 20 % of 2 is equal to
(A) 0.2
(B) 0.3
(C) 0.4
(D) 0.5
(E) 0.6
Rationale: 20 % of 2 = (20 / 100) * 2 = 0.4
ANSWER (C) =0.4
Answer: (C) 0.4
Question: If q = 30! + 1, which of the following cannot be a prime factor of q?
I. 11
II. 19
III. 29
(A) I​ only
(B) III only
(C) II and III
(D) I and II
(E) I​, II, and III
Rationale: The numbers 11, 19, and 29 are all factors of 30!
Therefore they can not be factors of 30! + 1.
The answer is E.
Answer: (E) I​, II, and III
Question: The C.P of 10 pens is equal to the S.P of 12 pens. Find his gain % or loss%?
(A) 6 2/5%
(B) 6 2/7%
(C) 6 2/3%
(D) 6 5/3%
(E) 6 7/3%
Rationale: 10 CP = 12 SP
12 --- 2 CP loss
100 --- ?
=> 16 2/3%
Answer: C
Answer: (C) 6 2/3%
Question: A certain board game has a row of squares numbered 1 to 100. If a game piece is placed on a random square and then moved 7 consecutive spaces in a random direction, what is the probability W the piece ends no more than 7 spaces from the square numbered 49?
(A)  7%
(B)  8%
(C)  14%
(D)  15%
(E)  28%
Rationale: OA is E
required prob is 7 spaces any side of 49.
so total 14 spaces are required in 7 moves which can be achieved by max 7 move on any side
so total spaces = 28
probability W= 28%.E
Answer: (E)  28%
Question: 39 persons can construct a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?
(A) 10
(B) 13
(C) 14
(D) 15
(E) None of these
Rationale: Explanation :
Let the required number of days be x.
Less persons, More days (Indirect Proportion)
More working hours per day, Less days (Indirect Proportion)
Persons 30 : 39 :: 12 : x
Working hours/day 6 : 5
30 x 6 x x = 39 x 5 x 12
x = (39 x 5 x 12) /(30 x 6)
x = 13.
Answer : B
Answer: (B) 13
Question: Consider the sets Tn = {n, n + 1, n + 2, n + 3, n + 4}, where n = 1, 2, 3,...., 78. How many of these sets contain 6 or any integral multiple thereof (i.e., any one of the numbers 6, 12, 18, ...)?
(A) (a) 80
(B) (b) 81
(C) (c) 82
(D) (d) 65
(E) (e) 84
Rationale: T1: 1,2,3,4,5
T2: 2,3,4,5,6
T3: 3,4,5,6,7
etc.
means that every multiple of 6 will be involved in 5 sets. We have (78-6)/6+1=13 such multiples.
So, final number of sets is 13*5=65
Answer: D
Answer: (D) (d) 65
Question: Two cubes of their volumes in the ratio 343 : 729. The ratio of their surface area is:
(A) 7:9
(B) 2:5
(C) 3:5
(D) 1:5
(E) 4:5
Rationale: The ratio of their surface area is
343 : 729
7 : 9
Answer is A.
Answer: (A) 7:9
Question: A metered rikshaw charges Rs 13.50 for the first 1 Km and 2.50 per 1/3 km there after. What would the charge if this rikshaw is hired for 13 Kms? In approx??
(A) 103.5 Rs
(B) 104.5 Rs
(C) 105.5 Rs
(D) 106.5 Rs
(E) 107.5 Rs
Rationale: For 1st Km: Rs.13.50
Ramaining distance:13-1=12 KM
1/3 km costs 2.5 rs
1 km costs (2.5*3)
Remaining 12KM costs (2.5*3)*12=90 Rs
total cost=90+13.5=103.5 Rs
ANSWER:A
Answer: (A) 103.5 Rs
Question: If after 200 grams of water were added to the 24%-solution of alcohol, the strength of the solution decreased by one-third, how much of the 24%-solution was used?
(A) 180 grams
(B) 220 grams
(C) 250 grams
(D) 350 grams
(E) 400 grams
Rationale: The h20 content in 200 gms of water is 1
h20 content in 24% solution is 0.76
Resulting new solution's concentration decreases by one third means. Now it becomes 16% solution which means h20 content is 0.84
Let amount of solution be X
Then the equation can be set up
200*1 + 0.76X = 0.84 (X+200)
0.08X = 32
8X = 3200
X = 400
ANSWER:E
Answer: (E) 400 grams
Question: In a group of600 readers who read science fiction or literacy works or both, 200 read science fiction and 230 read literacy works. How many read both science fiction and literacy works?
(A) 70
(B) 30
(C) 25
(D) 100
(E) 110
Rationale: Consider total number of reader n(S U L) = 600
People who read science fiction n(S) = 400
People who read literacy works n(L) = 230
both science fiction and literacy n(S âˆ© L) = ?
n(S U L) = n(S)+ n(L) - n(S âˆ© L)
600 = 400 + 230 - n(S âˆ© L)
n(S âˆ© L) =630 -600
n(S âˆ© L) = 30
SO People read both science fiction and literacy works are 30
ANSWER:B
Answer: (B) 30
Question: Ayesha's father was 38 years of age when she was born while her mother was 36 years old when her brother 5 years younger to her was born. What is the difference between the ages of her parents?
(A) 2 years
(B) 4 years
(C) 6 years
(D) 7 years
(E) 8 years
Rationale: Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 5) years = 43 years.
Required difference = (43 - 36) years = 7 years.
Answer: Option D
Answer: (D) 7 years
Question: A family travelled for 12 hours. They covered the first half of the distance at 35 kmph and remaining half of the distance at 40 kmph. Find the distance travelled by the family?
(A) 270 km
(B) 890 km
(C) 684 km
(D) 320 km
(E) 560 km
Rationale: Let the distance travelled be x km.
Total time = (x/2)/35 + (x/2)/40 = 12 => x/70 + x/80
= 12 => (8x + 7x)/560 = 12 => x
= 560 km
Answer: E
Answer: (E) 560 km
Question: In a 100 m race, A runs at 8km per hour. If A gives B a start of 8 m and still him by 15 seconds, what is the speed of B ?
(A) 5.52 km/hr.
(B) 5.06 km/hr.
(C) 5.76 km/hr.
(D) 6.76 km/hr.
(E) 5.72 km/hr.
Rationale: Time taken by A to cover 100 m =(60 X 60 / 8000)	x 100 sec = 45 sec.
B covers (100 - 8) m = 92 m in (45 + 15) sec = 60 sec.
B's speed = (92 x 60 x 60)/(60 x 1000)km/hr = 5.52 km/hr.
Answer is A
Answer: (A) 5.52 km/hr.
Question: ABCD is a square where AB =âˆš4032. Let X be a point on AB and Y be a point on CD such that AX = CY . Compute the area of trapezoid AXYD.
(A) 3008
(B) 2002
(C) 1008
(D) 2016
(E) 3000
Rationale: Note that trapezoids AXY D and BXY C are congruent, so the area of AXY D is
always
4032/2= 2016 .
correct answer D
Answer: (D) 2016
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 800 m long?
(A) 176 Sec
(B) 190 Sec
(C) 178 Sec
(D) 267 Sec
(E) 200 Sec
Rationale: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 2000 m
T = D/S
T = 2000/10
T = 200 Sec
Answer:E
Answer: (E) 200 Sec
Question: The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 30 per cent. The two reductions together are equal to a single reduction of
(A) 45%
(B) 47.5%
(C) 35%
(D) 32.5%
(E) 30%
Rationale: Price = p
initially price reduced by 25% which means new price is 3/4P
Now on this new price further 30percent is reduced which means the new price is merely 70percent of 3/4P
==> (3/4)x(7/10)P = 21/40P is the new price after both deduction which is 52.5 percent of the original value P. This implies this entire series of deduction is worth having discounted 47.5% of P. So answer is B = 47.5%
Answer: (B) 47.5%
Question: A and B finish the job in 15 days.while A,B and C can finish it in 3 days . C alone will finish the job in
(A) 4.75 days
(B) 3.75 days
(C) 6.50 days
(D) 7.50 days
(E) 5.50 days
Rationale: Explanation:
3 = (15 * x)/(15 + x)
45+3x=15x
12x=45
X=3.75
Answer: Option B
Answer: (B) 3.75 days
Question: A project manager needs to select a group of 4 people from a total of 4 men and 4 women. How many possible group combinations exist such that no group has all men or all women?
(A) 72
(B) 68
(C) 74
(D) 82
(E) 48
Rationale: First list all the possible combinations of Groups wit F = Female and M = Male:
MMMF
Total Combinations of 16 (4*3*2/3! *4)
FFFM
Total Combinations of 16 (same as above)
FFMM
Total Combinations of 36 (4*3/2! * 4*3/2!)
Altogether that makes 68.
Answer Choice B
Answer: (B) 68
Question: If the ratio of the roots of the equation 2x2-6x+q=0 is equal to that of the roots 3x2-6x+s=0, then:
(A) 2s=q
(B) s=q
(C) 2q=s
(D) 4s-q
(E) None
Rationale: 2x2-6x+q=0 for this eqn... roots are R1=6/2=3 R2=-q/2
3x2-6x+s=0 for this eqn... roots are R3=6/3=2 R4=-s/3
As per Question, 3/(-q/2)=2/(-s/3)
=> s=q
ANSWER:B
Answer: (B) s=q
Question: a, b, c are integers. |a| ≠ |b| ≠ |c| and -10 ≤ a, b, c ≤ 10. What will be the maximum possible value of [abc – (a+b+c)]?
(A) 524
(B) 693
(C) 731 is answer
(D) 970
(E) None of the above
Rationale: Is the answer bank correct? Shouldn't option C be 713? C
Answer: (C) 731 is answer
Question: A circular box kept around a circular place. If the difference between the circumference of the outer circle and the inner circle is 44m, find the width of the box?
(A) 2 m
(B) 3 m
(C) 4 m
(D) 7 m
(E) 8 m
Rationale: Let radius of the outer circle be R and radius of the inner circle be r.
Circumference of the outer circle =
Circumference of the inner circle =
But,
or, R - r =
Thus, width of the road = 7 m
D
Answer: (D) 7 m
Question: A certain telephone company offers two plans, A and B. Under plan A, the company charges a total of $0.60 for the first 8 minutes of each call and $0.06 per minute thereafter. Under plan B, the company charges $0.08 per minute of each call. What is the duration of a call, in minutes, for which the company charges the same amount under plan A and under plan B?
(A) 2
(B) 9
(C) 6
(D) 21
(E) 30
Rationale: Let the duration, in minutes, for which the company charges the same under plan A and plan B be t minutes.
Then under plan A the cost would be $0.6+0.06(t-8) and under plan B the cost would be $0.08t. We want these amount to be equal: 0.6+0.06(t-8)=0.08t --> 60+6(t-8)=8t --> t=6.
Answer: C.
Answer: (C) 6
Question: A man has about 4 children and 16 apples.He cuts the apple into quarter pieces and distribute them among the Children.One of the children eats one apple and returns remaining to the father.The father now distribute it among remaining.How many pieces does each of remaining child have?
(A) 24
(B) 25
(C) 20
(D) 36
(E) 30
Rationale: Each one gets 4 apples at first.One of them is eaten and 3 gets returned to father who distribute it again .So 3 apples get distributed among 3 children who get total of 5 apples.The apple is cut into a quarter.Thus 5*4=20 pieces.Answer:C
Answer: (C) 20
Question: If Q= x^4 + y^4 = 100, then the greatest possible value of x is between
(A) 0 and 3
(B) 3 and 6
(C) 6 and 9
(D) 9 and 12
(E) 12 and 15
Rationale: My attempt:
If Q=x^4+y^4=100, then the greatest possible value of x would be when y is minimum.
Let y^4 be 0. Now x^4 = 100. x should be definitely greater than 3 but less than 4. The only option that fits this range is B
Hence answer is --
b) 3 and 6.
Answer: (B) 3 and 6
Question: A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
(A) 12 liters.
(B) 10 liters.
(C) 10 liters.
(D) 16 liters.
(E) 15 liters.
Rationale: Explanation:
Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters.
Answer: Option C
Answer: (C) 10 liters.
Question: 2ab5 is a four digit number divisible by 25. If a number formed from the two digits ab is a multiple of 13, then ab is
(A) 52
(B) 27
(C) 20
(D) 26
(E) 201
Rationale: For a number to be divisible by 25, last two digits of that number should be divisible by 25. So b must be either 2 or 7
it is given that ab must be divisible by 13 and in the options only 52 is divisible by 13.
Answer:A
Answer: (A) 52
Question: Find the value for m?
19(m + n) + 17 = 19(-m + n) - 173
(A) 0
(B) -1
(C) -5
(D) 2
(E) 3
Rationale: 19m + 19n + 17 = -19m + 19n - 173
38m= -190 => m = -5
A
Answer: (A) 0
Question: A water tank has three taps A, B and C. Tap A, when opened,can fill the water tank alone in 4 hours. Tap B, when opened, can fill the water tank alone in 6 hours and tap C, when opened, can empty the water tank alone in 3 hours. If taps A, B and C are opened simultaneously, how long will it take to fill the tank completely?
(A) 10 hours
(B) 8 hours
(C) 18 hours
(D) 12 hours
(E) None of these
Rationale: Required time to fill the tank
= 1 /(1/4+1/6)−1/3=1 /5/12−1/3=1 /1/12=12h
Answer D
Answer: (D) 12 hours
Question: Martha has 3 dogs and 4 cats. She takes each animal separately for a daily walk. She can take the animals for a walk to the park or to the barber shop. How many different options for a walk with a single animal does Martha have?
(A) 8
(B) 9
(C) 10
(D) 14
(E) 20
Rationale: 5 dogs, 4 cats; park/barber shop
1 dog - 2 options - either park or barber shop, so, 3 dogs - 6 options and 4 dogs - 8 options.
Total = 14 options.
D
Answer: (D) 14
Question: On simplification, 3500 – (1000 ÷ 20.50) is equal to :
(A) 3451.21
(B) 3451.29
(C) 3451.223
(D) 3451.28
(E) 3441.29
Rationale: Explanation:
Given exp. = 3500 - ((1000 ÷ 2050) * 100)
= 3451.21
ANSWER: A
Answer: (A) 3451.21
Question: The average age of 20 men in the class is 17.6 years. Five new men join and the new average becomes 15.56 years. What was the average age of five new men?
(A) 15.5
(B) 7.4
(C) 15.25
(D) 15.3
(E) 15.6
Rationale: Total age of 20 men = 17.6 x 20 = 352
Now, total age of 25 men = 389.
Total age of five men added later = 389 - 352 = 37.
Hence, the total average of five men = 37/5 = 7.4
ANSWER:B
Answer: (B) 7.4
Question: The average age of three boys is 25 years and their ages are in proportion 3:5:7. What is the age in years of the youngest boy?
(A) 6
(B) 9
(C) 6
(D) 4
(E) 15
Rationale: 3x + 5x + 7x = 75
x =5
3x = 15
Answer:E
Answer: (E) 15
Question: A train covers a distance of 100km in 1 hour. If its speed is decreased by 25km/hr, the time taken by the car to cover the same distance will be?
(A) 1hr
(B) 1hr 20min
(C) 50min
(D) 1hr 30min
(E) 1hr 45min
Rationale: Speed = 100/1 = 100km/hr
New speed = 100-25 = 75 km/hr
Time taken = 100/75 = 1hr 20min
Answer is B
Answer: (B) 1hr 20min
Question: Danny drove his old car 100 kilometers, from his home to a friend. To prevent the engine from overheating, he stopped his car for 12 minutes every time he completed 40 kilometers of continuous driving. When the car was moving, Danny drove it at an average speed of 60 kilometers per hour. What was Danny's average speed on that trip?
(A) 37.5 kilometers per hour
(B) 48.4 kilometers per hour
(C) 50 kilometers per hour
(D) 75 kilometers per hour
(E) 100 kilometers per hour
Rationale: Time taken to reach first 40 km is 40/60 = 2/3 hr
Time taken to reach next 40 km is 40/60 = 2/3 hr
Time taken to reach next 20 km is 20/60 = 1/3 hr
Danny stopped twice on his way at 40 km from starting point and at 80km from the starting point...
Each stop was of 12 min , so two 12min break = 2*1/5 => 2/5 hr
Total time taken to reach 100 km is (2/3 + 2/3 + 1/3+2/5 ) = 31/15 hrs
So, Average speed is 100/(31/15) = 48.4km/hour
Answer will be B
Answer: (B) 48.4 kilometers per hour
Question: November 2, 1962, fell on a Friday. On which day of the week did November 2, 1985, fall? (Note: 1964 was a leap year and every succeeding fourth year were leap years.)
(A)  Sunday
(B)  Tuesday
(C)  Thursday
(D)  Friday
(E)  Saturday
Rationale: There are 365 days in a non-leap year and 366 in a leap year. In the period in question, there are 17 non-leap years and 6 leap years, thus the number of days in the period is (17 * 365) + (6 * 366) = 8401. Dividing by 7 yields 1200 and a remainder of 1. Since the first date was a Friday, we advance the day of the week by the remainder of 1 and thus the second date is a Saturday. The answer is E.
Answer: (E)  Saturday
Question: A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
(A) 1000
(B) 1526
(C) 5625
(D) 1090
(E) 1829
Rationale: 90%
104%
--------
14% ---- 140
100% ---- ? => Rs.1000
Answer: A
Answer: (A) 1000
Question: The average height of 30 students in a class was calculated as 177 cm. It has later found that the height of one of the students in the class was incorrectly written as 151 cm whereas the actual height was 106 cm. What was the actual average height of the students in the class?
(A) 176.5 cm
(B) 175.5 cm
(C) 174.5 cm
(D) 173.5 cm
(E) 172.5 cm
Rationale: The total height was 45 cm too much.
The average height should be reduced by 45 cm/30 = 1.5 cm
The answer is B.
Answer: (B) 175.5 cm