mathewhe/aqua_rat huggingface dataset:
Question: How many three digit even numbers M can be formed that are divisible by 9 such that both M and M^2 have the same units digits?
(A)  20
(B)  21
(C)  22
(D)  23
(E)  24
Rationale: For an even number to have the same units digit as its square, it must have the units digit of 0 (0^2 = 0) or 6 (6^2 = 6). Thus the units digit of M must be 0 or 6.
For a number to be divisible by 9, the sum of its digit must be divisible by 9.
If the units digit of M is 0, then M could be:
900;
810, 180;
720, 270;
630, 360;
540, 450;
990.
10 numbers.
If the units digit of M is 0, then M could be:
306;
216, 126;
936, 396;
846, 486;
756, 576;
666.
10 numbers.
Total = 10 + 10 = 20.
Answer: A.
Answer: (A)  20
Question: There are seven pairs of black shoes and 5 pairs of white shoes .Tey all are put into a box and shoes are drawn at a time.To ensure that at leat one pair of black shoes are taken out,What is the minimum number of shoes required to be drawn out so as to get at leat 1 pair of correct shoes.
(A) 13
(B) 14
(C) 15
(D) 16
(E) 17
Rationale: All the one sided (assume only left) white shoes, total draws required: 5
All the one sided (assume only left) black shoes, total draws required: 7
So, total draws are: 5+7=12
Next draw or 13th draw will contain any color right footed shoe, i.e. making at least one correct pair.
So, minimum number of shoes required to be drawn out is: 13
ANSWER:A
Answer: (A) 13
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
(A) Rs.4529
(B) Rs.4586
(C) Rs.4597
(D) Rs.4530
(E) Rs.4528
Rationale: Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5
=Rs.4530
Answer: D
Answer: (D) Rs.4530
Question: If a 1 mm thick paper is folded so that the area is halved at every fold, then what would be the thickness of the pile after 50 folds ?
(A) 100 km
(B) 1000 km
(C) 1 million km
(D) 1 billion km
(E) None
Rationale: after 1 hold, thickness will be 2mm
After 2 hold, thich ness will be 4mm
after 50th hold thick ness will be 2^50 mm..converting to km....gives 1 billion km
ANSWER:D
Answer: (D) 1 billion km
Question: City I City II	City III	City IV	City V	City VI
City I
City II
City III
City IV
City V
City VI
In the table above, what is the least number of table entries that are needed to show the mileage between each city and each of the other five cities?
(A) 14
(B) 15
(C) 13
(D) 12
(E) 11
Rationale: Easy way to go about this problem is we have 6*6 = 36 enteries in table the least number of enteries would be (36 - 6) /2 since 6 enteries represent the distances between same points .
Alternatively this can be solved as combination problem.
Correct Answer B
Answer: (B) 15
Question: |-4| (|-25|-|15|)= ??
Source: Preparation Material MBA Center
(A) 40
(B) –60
(C) 60
(D) 75
(E) 100
Rationale: Absolute value will turn negatives into their positive 'equivalents', and will leave positives unchanged, so |-4| = 4, |-25| = 25, and |15| = 15. Getting rid of our absolute values we have:
|-4| (|-25|-|15|) = (4) (25 - 15) = 4*10 = 40
Answer: (A) 40
Question: What distance (in meters) will be covered by a bus moving at 54 km/hr in 20 seconds?
(A) 200
(B) 250
(C) 300
(D) 350
(E) 400
Rationale: 54 km/hr = 54 * 5/18 = 15 m/s
distance = 15 * 20 = 300 meters
The answer is C.
Answer: (C) 300
Question: A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
(A) Rs.1000
(B) Rs.1028
(C) Rs.1029
(D) Rs.1030
(E) Rs.1028
Rationale: 90%
104%
--------
14% ---- 140
100% ---- ? => Rs.1000
Answer: A
Answer: (A) Rs.1000
Question: A bicycle wheel has a diameter of 0.75m. How many complete revolutions does it make in 1km?
(A) 424
(B) 448
(C) 1408
(D) 710
(E) 223
Rationale: 1 revolution = 3.14 * diameter.
Number of revolutions in 1km = 1000m / ( 3.14 * 0.75m ) = 424.6. Hence 424 complete revolutions.
Answer A
Answer: (A) 424
Question: If 2x +3y = 30 and (x+y)/y = 11/8, then find the value of 5y + 6x
(A) 72
(B) 58
(C) 64
(D) 29
(E) 34
Rationale: Explanation:
The given equations are :
2x + 3y = 30 --------- (i)
and, (x+y)/y = 11/8
8x + 8y = 11y
8x – 3y =0 ----(ii)
Adding (i) & (ii), we get : 10 x = 30 or x = 3.
Put x = 3 in (i), we get : y = 8
Therefore, 5y + 6x = (5 * 8 + 6 * 3) = 40 + 18 = 58.
ANSWER: B
Answer: (B) 58
Question: A cycle is bought for Rs.1500 and sold for Rs.1620, find the gain percent?
(A) 11
(B) 8
(C) 10
(D) 20
(E) 12
Rationale: 1500 ---- 120
100 ---- ? =>8%
Answer: B
Answer: (B) 8
Question: One-sixth of the attendees at a certain convention are female students, two-thirds of the attendees are female, and one-third of the attendees are students. If 250 of the attendees are neither female nor students, what is the total number of attendees at the convention?
(A) 600
(B) 300
(C) 1200
(D) 1500
(E) 1600
Rationale: Let no. of Attendee are A.
Now As per the condition of the problem stated above .
We have following population in the convention as Attendee.
Total no. of females = [2/3]*A
Total no. of females as student : [1/6]*A
Total no. of students = [1/3]*A
Total no. of male as student = [1/6]*A
Total no. of males = A - [2/3]*A = [1/3]A
No. of males which are not student = [1/3]A - [1/6]*A = 250
Hence A = 1500
Total no of males who are not student will be the answer as it states it should be neither female nor student
So Answer is D
Answer: (D) 1500
Question: A basketball is dropped from a height of 20 feet. If it bounces back up to a height that is exactly half of its previous height, and it stops bouncing after hitting the ground for the fourth time, then how many total feet will the ball have traveled after 2 full bounces.
(A) 50
(B) 55
(C) 60
(D) 75
(E) 80
Rationale: Initial distance = 20 feet
first bounce = 10 feet up + 10 feet down = 20 feet
second bouche = 5 feet up + 5 feet down = 10 feet
total distance covered = 20+20+10+ = 50
ANSWER IS A
Answer: (A) 50
Question: A man completes of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
(A) 6
(B) 12
(C) 7
(D) 15
(E) 5
Rationale: Work done =5/8
Balance work =	(1 -5/8)=3/8
Let the required number of days be x.
Then,	(5/8):(3/8)= :: 10 : x
(5/8)* x =	(3/8)* 10
x =(3/8) * 10 *(8/5)
x = 6.
Answer is A.
Answer: (A) 6
Question: How many three digit numbers R are divisible by 78 or 91?
(A) 17
(B) 19
(C) 20
(D) 21
(E) 22
Rationale: The answer will be 19.
Explanation:
78= 2*3*13 now multiples of 78, 156 ....780, now 1000-780 = 220 only two more muktiples of 78 can exists. So total number of 3 digit Multiples of 78 are 9+2=11
91= 13*7--Total number of three digit multiples --9
No remember we have a common multiples as well-- 13*7*6=91*6=546
So total number of multiples R--11+9 -1 =19.
Hence Answer is 19.B
Answer: (B) 19
Question: The HCF of two numbers is 42 and the other two factors of their LCM are 10 and 20. What is the largest number.
(A) 462
(B) 450
(C) 840
(D) 504
(E) 555
Rationale: Explanation:
HCF of the two numbers = 42
HCF will be always a factor of LCM
42 is factor of LCM
other two factors are 10 & 20
Then the numbers are (42 *10) and (42 x 20)
= 420 and 840
Answer: Option C
Answer: (C) 840
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is?
(A) 1 : 3
(B) 3 : 2
(C) 3 : 4
(D) 4 : 3
(E) 3 : 5
Rationale: Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
( 27x + 17y ) / (x+ y )= 23
=> 27x + 17y = 23x + 23y
=> 4x = 6y
=> ( x/y ) = ( 3/2 )
Answer: Option B
Answer: (B) 3 : 2
Question: Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 14 percent alcohol by volume?
(A) 50
(B) 100
(C) 150
(D) 200
(E) 250
Rationale: 14% is 4%-points higher than 10% but 16%-points lower than 30%.
Thus there should be 4 parts of solution X for 1 part of solution Y.
We should add 50 ml of solution Y.
The answer is A.
Answer: (A) 50
Question: NHAI employs 100 men to build a highway of 2km in 50 days working 8 hours a day. If in 25 days, they completed 1/3 part of work. than how many more employees should NHAI hire to finish it in time working 10 hours a day?
(A) 55
(B) 60
(C) 70
(D) 50
(E) 65
Rationale: Explanation:
The given problem can be written in a tabular form like below: -
Men	Days	Hour	Work
Planned	100	50	8	1
Actual	100	25	8	1/3
Remaining	?	25	10	2/3
We can apply chain rule now.
Total men required to complete the remaining work = 100× (25/25) × (8/10) × (2/3)/ (1/3) = 160.
So additional men required = 160 - 100 = 60.
ANSWER IS B
Answer: (B) 60
Question: John had a stock of 1000 books in his bookshop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold?
(A) 59.8%
(B) 23.8%
(C) 66.5%
(D) 34.9%
(E) 43.5%
Rationale: Let N be the total number of books sold. Hence
N = 75 + 50 + 64 + 78 + 135 = 402
Let M be the books NOT sold
M = 1000 - N = 1000 - 402 = 598
Percentage
Books not sold / total number of books = 598/1000 = 59.8 = 59.8%
correct answer A
Answer: (A) 59.8%
Question: The number of sailors on a ship is 78% more than the number of officers. The ratio of sailors to officers would be
(A) 33:25
(B) 47:20
(C) 47:25
(D) 89:50
(E) 97:50
Rationale: Sailor = 1.78 * Officer
Sailor/Officer = 1.78/1 = 178/100 = 89/50
Answer will be D
Answer: (D) 89:50
Question: The cost of 100 articles is equal to selling price of 90. Find the gain or loss percent?
(A) 11%
(B) 20%
(C) 27%
(D) 32%
(E) 49%
Rationale: C.P. of each article be $1
C.P. of 90 articles = 100
gain% = 10/90*100 = 11% approximately
Answer is A
Answer: (A) 11%
Question: A farm has chickens, cows and sheep. There are eight times the number of chickens and cows than sheep. If there are more cows than chickens or sheep, and together, cows and chickens have a total of 100 feet and heads, how many sheep live at the farm?
(A) 5
(B) 8
(C) 10
(D) 14
(E) 3
Rationale: Chicken - ch
Cows - C
Sheep -S
ch+C=8S
C> ch and c>s
Each cow has 4 legs and 1 head
Each chicken has 2 legs and 1 head
So 5c+3ch=100 (sum of legs and head)
There are 2 possible solutions to this equation
c=22 and ch=30 or
c=14 and ch=10
Since from first equation where ch+c=8s
The sum of ch and c should be divisbile by 8. 20 is not so the only possible solution is c=14 and ch=10. So s=3
Answer : E
Answer: (E) 3
Question: On June 1 a bicycle dealer noted that the number of bicycles in stock had decreased by 4 for each of the past 5 months. If the stock continues to decrease at the same rate for the rest of the year, how many fewer bicycles will be in stock on September 1 than were in stock on January 1?
(A) 8
(B) 12
(C) 20
(D) 32
(E) 36
Rationale: Jan 1 = C
Feb 1 = C - 4
March 1 = C - 8
April 1 = C - 12
May 1 = C - 16
June 1 = C - 20
July 1 = C - 24
Aug 1 = C - 28
Sept 1 = C - 32
Difference between stock on September 1 than were in stock on January 1 will be -
C - ( C - 32 )= 32
Hence answer will be (D)
Answer: (D) 32
Question: Out of 8 consonants and 5 vowels, how many words of 4 consonants and 3 vowels can be formed?
(A) 15000
(B) 352800
(C) 25200
(D) 214000
(E) None of these
Rationale: Solution
Number of ways of selecting (4 consonants out of 8) and (3 vowels out of 5)
nCr=n!/r!(n-r)!
8c4 x 5c3= (8x7x6x5/4x3x2x1)x(5x4x3/3x2x1) =70x10=700
Number of group,each having 4 consonants and 3 vowels = 700
Each group contains 7 letter.
Number of ways of arranging 7 letters among themselves
= 7 ! = (7 x 6 x 5 × 4 × 3 × 2 × 1) = 5040 .
So, Required number of words = (5040 × 700) = 352800 .Answer B
Answer: (B) 352800
Question: The probability that A speaks truth is 3/5 and that of B speaking truth is 4/7. What is the probability that they agree in stating the same fact?
(A) 18/35
(B) 18/39
(C) 18/36
(D) 18/33
(E) 18/32
Rationale: If both agree stating the same fact, either both of them speak truth of both speak false.
Probability = 3/5 * 4/7 + 2/5 * 3/7
= 12/35 + 6/35 = 18/35
Answer: A
Answer: (A) 18/35
Question: In how many different number of ways a combination of 3 persons can be selected from 4 men and 2 women?
(A) 160
(B) 180
(C) 200
(D) 210
(E) 220
Rationale: 6C3 × 5C2
6C3
= 6!/(3! . 3!)
= (6 × 5 × 4)/(3 × 2)
= 5 × 4 = 20.
5C2
= 5!/(3! . 2!)
= 5 × 2 = 10
= 20 × 10 = 200.
C)
Answer: (C) 200
Question: A canteen requires 112 kgs of wheat for one week. How many kgs of wheat will it require for 69 days?
(A) 1,204kgs
(B) 1,401kgs
(C) 1,104kgs
(D) 1,014kgs
(E) None
Rationale: Quantity of wheat for 7 days = 112kg
quantity of wheat for one day = 112/7 kg
quantity of wheat for 69 days= 112/7 * 69 = 1104 kg
Answer C
Answer: (C) 1,104kgs
Question: The value of a "Tin-Rin" stock in the stock market decreased by 15% in the last two years. The economic experts believe that the value of the stock will increase by 7% during the following year, which will make the value $440. What was the approximate price of the stock two years ago?
(A) $473.
(B) $464.
(C) $455.
(D) $445
(E) $430.
Rationale: Let the stock value was x.
x* 0.85 * 1.07= 440
x= 440/0.85*1.07= 490 (approximately)
A is the answer
Answer: (A) $473.
Question: A contractor undertakes to complete the construction of a tunnel 720 meters long in 240 days and employs 60 men for the purpose. After 120 days, he finds that only 240 meters of the tunnel is complete. How many more men should be employ in order to complete the work in time?
(A) 22
(B) 27
(C) 60
(D) 88
(E) 12
Rationale: In 120days, only 240m of the tunnel is constructed by 60 men.
The remaining 120days, 480m of the tunnel can be constructed by 120 men.
Additional number of men required = 120 - 60 = 60 men.
Answer: B
Answer: (B) 27
Question: K-numbers are positive integers with only 2's as their digits. For example, 2, 22, and 222 are K-numbers. The K-weight of a number n is the minimum number of K-numbers that must be added together to equal n. For example, the K-weight of 50 is 5, because 50 = 22 + 22 + 2 + 2 + 2. What is the K-weight of 750?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 15
Rationale: 750 = 3*222 + (22*3) + 9*2
K weight of 600 = 3 +3+9 = 15
Answer E
Answer: (E) 15
Question: A bag contains 30 red jellybeans and 30 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability that all 3 jellybeans removed from the bag are blue?
(A) 9/100
(B) 2/19
(C) 1/8
(D) 1/20
(E) 3/10
Rationale: Method-1
10 red jellybeans and 10 blue jellybeans
Total Outcomes = No. of ways to choose 3 Jelly bean at random out of a total 20 jellybeans = 20C3 = 1140
Favourable Outcomes = No. of ways to choose 3 Jelly bean such that they are all Blue out of 10 Blue = 10C3 = 120
Probability = Favourable Outcomes / Total Outcomes = 10C3 / 20C3
Probability = 120 / 1140 = 2/19
Answer: option B
Method-2
Probability of First jelly bean to be Blue = 10/20 [Total 10 Blue out of total 20 jellybeans]
Probability of Second jelly bean to be Blue = 9/19 [Total 9 Blue remaining out of total 19 jellybeans remaining]
Probability of Third jelly bean to be Blue = 8/18 [Total 8 Blue remaining out of total 18 jellybeans remaining]
Required Probability = (10/20)*(9/19)*(8/18) = 1/20
Answer: option D
Answer: (D) 1/20
Question: Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?
(A) 57%
(B) 60%
(C) 90%
(D) 65%
(E) 70%
Rationale: Req percentage = 11628/20400*100 = 57%
ANSWER A
Answer: (A) 57%
Question: At Winson's firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a $1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?
(A) 700
(B) 1000
(C) 1300
(D) 1600
(E) 2000
Rationale: At Winson's firm's annual revenue grows twice as fast as its costs. First solve for how much revenue is increasing each year:
R2008= R2007*(1+x)
R2009= R2007*(1+x)^2=1.44*R2007
(1+x)^2 = 1.44
1+x=1.2
x=0.2 aka revenue increases 20% each year and cost increases 10% annually
Next solve for R2007and C2007:
R2007= C2007- 1000
1.2*R2007- 1.1*C2007= 0
1.2*[C2007- 1000] - 1.1*C2007= 0
0.1*C2007= 1,200
C2007= 12,000
R2007= 11,000
Finally find 2009 profits:
Profit2009= 1.44*11,000 - 1.21*12,000
Profit2009= 15,840 - 14,520
Profit2009= 1320
Answer: C
Answer: (C) 1300
Question: Find the invalid no.from the following series 2,3,12,37,86,166,288
(A) 3
(B) 12
(C) 166
(D) 86
(E) 288
Rationale: 3-2=1
12-3=9
37-12=25
86-37=49
166-86=80(this must be 81=167-86=81)
so wrong number in the sequence is 166
difference between two sucessive numbers sequence would be
1,9,25,49,81,121(square of 1,3,5,7,9,11)
C
Answer: (C) 166
Question: A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 18, what is the total amount?
(A) 115
(B) 116
(C) 117
(D) 78
(E) 119
Rationale: x:y:z = 100:45:50
20:9:10
9 --- 18
39 --- ? => 78
ANSWER:D
Answer: (D) 78
Question: In a group of cows and hens, the number of legs are 10 more than twice the number of heads. The number of cows is :
(A) 5
(B) 6
(C) 7
(D) 10
(E) 12
Rationale: Let no of cows be x, no of hens be y.
So heads=x+y
Legs=4x+2y
Now, 4x+2y = 2(x+y)+ 10
2x = 10
x = 5.
ANSWER:A
Answer: (A) 5
Question: If a < b < c , which of the following must be true?
(I) a < b^2
(II) b − a < c
(III) a^2 > b^2 > c^2
(A) None
(B) I only
(C) II only
(D) III only
(E) II and III
Rationale: (I) a < b^2. Not necessarily true fractions: try a=1/3 and b=1/2.
(II) b − a < c. Not necessarily true: try a=-1, b=0, and c=1.
(III) a^2 < b^2 < c^2. Not necessarily true: try a=1, b=2, and c=3.
None of the options must be true.
Answer: A.
Answer: (A) None
Question: A company D has 45 percent of the employees are secretaries and 45 percent are salespeople. If there are 50 other employees of Company D, how many employees does Company D have?
(A) 500
(B) 162
(C) 180
(D) 152
(E) 250
Rationale: Let the total number of employees in the company be x
% of secretaries = 45%
% of salespeople = 45%
% of of employees other than secretaries and salespeople = 100 - 90 = 10%
But this number is given as 50
so 10% of x = 50
x = 500
Therefore there a total of 500 employees in the company D
Correct answer - A
Answer: (A) 500
Question: 3640 ÷ 14 × 16 + 340 = ?
(A) 0.7
(B) 3525
(C) 4480
(D) None of these
(E) Cannot be determined
Rationale: Solution
Given exp. = 260 × 16 + 340 = 4160 + 340 = 4500.
Answer D
Answer: (D) None of these
Question: The ratio of investments of two partners is 11:12 and the ratio of their profits is 2 : 3. If A invested the money for 8 months , find for how much time B invested his money?
(A) 11
(B) 27
(C) 28
(D) 12
(E) 19
Rationale: Suppose A invested Rs.11 for 8 months and B invested Rs. 12 for x months.
Ratio of investments of A and B
= (11 x 8) : (12 x x)
= 88 : 12x
{88}/{12x}={2}/{3}\Rightarrow x=11
Answer:A
Answer: (A) 11
Question: To a sugar solution of 10 liters containing 50% sugar, 10 liter of water is added. The percentage of sugar in the new solution is?
(A) 25%
(B) 30%
(C) 15%
(D) 20%
(E) 18%
Rationale: Quantity of sugar = 50*10/100 = 5kg
New percentage = 5/20 * 100 = 25%
Answer is A
Answer: (A) 25%
Question: Three runners W, B and C run a race, with runner W finishing 12m ahead of runner B and 18m ahead of runner C, while runner B finishes 8m ahead of runner C. Each runner travels entire distance at a constant speed. What was the length of the race?
(A) 36m
(B) 48m
(C) 60m
(D) 72m
(E) 84m
Rationale: Let distance of race be x mtrs. Then when W finishes x m , B has run (x- 12)mtrs and C has run x-18 mtrs. so at this point B is 6 m ahead of C. Now to finish race b needs to run another 12 m, so he runs another 12 m. when B finishes race he is 8 m ahead of C. so last 12 m B has run, C has run 10 m.
as speeds are constant, we have equation,
x-12/ x-18 = 12/10 > x = 48.
Answer B
Answer: (B) 48m
Question: the value of (1+.1+.01+.001) is:
(A) 1.001
(B) 1.011
(C) 1.003
(D) 1.111
(E) None of them
Rationale: 1.0
0.1
0.01
0.001
-------
1.111
Answer is D
Answer: (D) 1.111
Question: If m and n are positive integers, and m=2n and k=5m, then -
(A) 3m is a factor of k/2.
(B) 2m is a factor of k.
(C) m/2 is a factor of k.
(D) k is a factor of m.
(E) k is a factor of m/2.
Rationale: m=2n --> m is even.
k=5m --> m is factor of k, thus m/2 = integer must also be a factor of k.
Answer: C.
Answer: (C) m/2 is a factor of k.
Question: One out of every 500 light bulbs are defected. If 5 out of every 10 defected light bulbs have a broken glass and there are 20 broken glass light bulbs in the shipment, how many light bulbs total are there in the shipment?
(A) 2,000
(B) 5,000
(C) 10,000
(D) 20,000
(E) 52,000
Rationale: out of 500 only 1 bulb is defective.So for 10 defective bulbs, we must have 5000 bulbs
Now out of these 10 bulbs, 5 bulbs, have broken glass
i.e 5 broken glass out of 5000 bulbs
20 broken glass will be from 20000 bulbs
Answer is D
Answer: (D) 20,000
Question: How much is 70% of 40 is greater than 4/5 of 25?
(A) 12
(B) 27
(C) 18
(D) 12
(E) 8
Rationale: (70/100) * 40 â€“ (4/5) * 25
28- 20 = 8
Answer:E
Answer: (E) 8
Question: If a sample of data has mean of 21 and SD of 3, which of the following values is more than 2.5 SDs from the mean?
(A) a. 12
(B) b. 13.5
(C) c. 17
(D) d. 23.5
(E) e. 26.5
Rationale: Value ismore than 2.5SDfrom the mean means that the distance between the mean and the value must be more than 2.5SD=7.5. So the value either <21-7.5=13.5 or >21+7.5=28.5.
Answer: A.
Answer: (A) a. 12
Question: Two numbers are less than a third number by 40% and 47% respectively. How much per cent is the second number less than the first ?
(A) 95%
(B) 88%
(C) 85%
(D) 90%
(E) none of these
Rationale: Here, x = 40 and y = 47
Therefore second number
= [[(100 - y)/(100 - x )] x 100 ]% of first number
= [[(100 - 47)/(100 - 40 )] x 100 ]% of first number
i.e, 88.3% of the first.
ANSWER:B
Answer: (B) 88%
Question: A restaurant meal cost $37.50 and there was no tax. If the tip was more than 10 percent but less than 15 percent of the cost of the meal, then the total amount paid must have been between
(A)  $40 and $42
(B)  $42 and $44
(C)  $38 and $40
(D)  $37 and $39
(E)  $36 and $37
Rationale: The total amount for the meal was between 37.5*1.1=41.25 and 37.5*1.15=43.125. Only option which covers all possible values of the meal is B.
Answer: B.
Answer: (B)  $42 and $44
Question: The number of stamps that Kaye and Alberto had were in the ration of 5:3 respectively. After Kaye gave Alberto 12 of her stamps, the ration of the number of Kaye had to the number of Alberto had was 8:6. As a result of the gift, Kaye had how many more stamps than Alberto?
(A) 20
(B) 30
(C) 40
(D) 32
(E) 90
Rationale: C
K1 = 5x
A1 = 3x
K2 = 5x - 12
A2 = 3x + 12
K2/A2 = 8/6
(5x-12)/(3x+12) = 8/6
6*(5x-12) = 8*(3x+12)
30x - 72 = 24x + 96
6x = 168
x = 28
K2 = 5*28 - 12 = 128
A2 = 3*28 + 12= 96
K2 - A2 = 32
Answer : D
Answer: (D) 32
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 60 km/hr and 90 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
(A) 48
(B) 93
(C) 24
(D) 23
(E) 12
Rationale: Relative speed = 60 + 90 = 150 km/hr.
150 * 5/18 = 125/3 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 3/125 = 24 sec.
Answer:C
Answer: (C) 24
Question: Colin has an app on his phone that generates a random integer betwen 1 and 10. He generates
10 random numbers and computes the sum. Compute the number of distinct possible sums
Colin can end up with.
(A) 41
(B) 32
(C) 75
(D) 91
(E) 82
Rationale: The maximum possible sum is 10 * 10 = 100. The minimum possible sum is 10.
Hence, there are 100 - 10 + 1 = 91 possible sums
correct answer D
Answer: (D) 91