mathewhe/aqua_rat huggingface dataset:
Question: One paper sheet can be used to create 8 paper boats or 6 paper planes. If total exact 80 paper toys are to be made, minimum how many sheets need to be used to make paper boats?
(A) 5
(B) 4
(C) 3
(D) 2
(E) 1
Rationale: Let us say x sheets are used to create paper boats and y sheets are used to create paper planes. Since total 80 paper toys are to be created, 8x + 6y = 80.
=> 8x = 80 - 6y
=> x = 10 - (6/8)y
=> x = 10 - (3/4)y
To minimize x, we need to maximize y. And y needs to be multiple of 4.
y = 4, x = 10 - (3/4)4 = 7
y = 8, x = 10 - (3/4)8 = 4
y = 12, x = 10 - (3/4)12 = 1
Beyond this, x will become negative for greater values of y. So, minimum 1 sheet is required to be used for creating paper boats.
Answer: E
Answer: (E) 1
Question: A person travels equal distances with speeds of 3 km/hr, 4 km/hr and 5 km/hr and takes a total time of 40 minutes. The total distance is?
(A) 1 km
(B) 2 km
(C) 3 km
(D) 4 km
(E) 2.55 km
Rationale: E
3 km
Let the total distance be 3x km.
Then, x/3 + x/4 + x/5 = 40/60
47x/60 = 40/60 => x = 0.85.
Total distance = 3 * 0.85 = 2.55 km.
Answer: (E) 2.55 km
Question: Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in scheme B?
(A) 6400
(B) 6408
(C) 6406
(D) 6405
(E) 6402
Rationale: Let the sum invested in scheme A be Rs. x and that in scheme B be Rs. (13900 - x). Then,
(x * 14 * 2)/100 + [(13900 - x) * 11 * 2]/100 = 3508
28x - 22x = 350800 - (13900 * 22)
6x = 45000 => x = 7500
So, sum invested in scheme B = (13900 - 7500) = Rs. 6400.
Answer: A
Answer: (A) 6400
Question: A passenger sitting near the window in a train moving at 40 km/h, noticed that it took 3 sec. for the oncoming train to pass by. What was the speed of the oncoming train if the length of the oncoming train was 69 metres?
(A) a)50km/h
(B) b)42.8km/h
(C) c)56km/h
(D) d)60km/h
(E) e)70km/h
Rationale: im getting A
3 secs to pass a 75 mts train , therefore speed = 23 meters/sec
to convert m/s to km/hrs multiply by 3.6
23*3.6 = 90
so its 82.8-40 = 42.8 .
B
Answer: (B) b)42.8km/h
Question: There is a sequence such that each term is positive integer and each digit of the terms in the sequence has 3 to be ordered, what is the value Q of 100th term?
(A) 126
(B) 192
(C) 232
(D) 252
(E) 342
Rationale: (1~99) 19, (100~199)  19, (200~299) 19. The 100th term should be 100-(19+19+19)=43th number. Hence, the correct answer Q is 342. The correct answer is E.
Answer: (E) 342
Question: The ratio, by weight, of coffee to sugar to water in a pot of coffee is 4:1:15. The ratio is then altered so that the ratio of coffee to sugar is halved while the ratio of coffee to water is doubled. If the altered pot of coffee contains 16 grams of sugar, how many grams of water does it contain after alteration?
(A) 64
(B) 60
(C) 56
(D) 52
(E) 48
Rationale: The new ratio of coffee to sugar is 2:1
The new ratio of coffee to water is 8:15.
The new ratio of coffee to sugar to water is 8:4:15.
If there are 16 grams of sugar, then there are (15/4)*16=60 grams of water.
The answer is B.
Answer: (B) 60
Question: If T = 5/9 * (K - 32), and if T = 105, then what is the value of K?
(A) 209
(B) 212
(C) 215
(D) 218
(E) 221
Rationale: K-32=9T/5
K=9T/5 + 32
K=9(105)/5 + 32 = 221
The answer is E.
Answer: (E) 221
Question: A person covered one-fourth of the total distance at 25 kmph and remaining distance at 24 kmph. What is the average speed for the total distance?
(A) 21 (1/8)
(B) 21 (1/33)
(C) 24 (8/33)
(D) 29 (1/33)
(E) 21 (4/33)
Rationale: Let the total distance be x km
total time taken = (x/4)/25 + (3x/4)/24 = x/100+ x/32 = 33x/800
Average speed = x/(33x/800) = 24 8/33 kmph.
Answer: C
Answer: (C) 24 (8/33)
Question: The cost per liter of petrol during a 4 year period is as follows:
Year 1, $1 per liter ;
Year 2, $1.5 per liter ;
Year 3, $1.2 per liter ;
Year 4, $2 per liter .
If a factory spent equal dollars on petrol each year, what was the average cost of a liter of petrol during the 4 year period?
(A) $1.22
(B) $1.333
(C) $1.425
(D) $1.175
(E) $1.500
Rationale: Let money spent each year = $6
liters bought first year = 6
liters bought second year = 4
liters bought third year = 5
liters bought fourth year = 3
Total number of liters = 18
Total money spent = 6*4 = 24
Average = 24/18 = 4/3 = 1.33
Answer is B
Answer: (B) $1.333
Question: If n denotes a number to the left of 0 on the number line such that the square of n is less than 1/36, then the reciprocal of n must be
(A) Less than -6
(B) Between -1 and -1/6
(C) Between -1/6 and 0
(D) Between 0 and 1/6
(E) Greater than 6
Rationale: n^2 < 1/36
abs(n) < 1/6
Since n<0, then 0 > n > -1/6
1/n < -6
The answer is A.
Answer: (A) Less than -6
Question: Everyone shakes hands with everyone else in a room. Total number of handshakes is 105. Number of persons=?
(A) 14
(B) 12
(C) 11
(D) 15
(E) 16
Rationale: In a room of n people, the number of possible handshakes is C(n,2) or n(n-1)/2
So n(n-1)/2 = 105 OR n(n-1)=210 OR n=15
Answer is (D)
Answer: (D) 15
Question: Average score in 10 matches is 32, How many runs one should should score to increase his average by 4
runs.
(A) 70
(B) 76
(C) 78
(D) 80
(E) 82
Rationale: Average after 11 innings should be 36
So, required score = (11 * 36) - (10 * 32)
= 396 - 320 = 76
Answer: Option B
Answer: (B) 76
Question: The simple interest accrued on an amount of Rs.49500 at he end of three is Rs.17820. What would be the compound interest accured on the same amount at teh same rate in the same period? (Round off your answer to two decimal places)
(A) Rs.20043.94
(B) Rs.20043.97
(C) Rs.20043.96
(D) Rs.20043.16
(E) Rs.20043.17
Rationale: Let the rate of interest be R% p.a.
(49500)(3)(R)/100 = 17820
495R = 5940
R = 12
CI on Rs.49500 at 12% p.a. for three years
= 49500{[1 + 12/100]3 - 1} = 69543.936 - 49500 = Rs.20043.94
when rounded off to two decimal places.
Answer:A
Answer: (A) Rs.20043.94
Question: Rahim bought 42 books for Rs.520 from one shop and 22 books for Rs.248 from another. What is the average price he paid per book ?
(A) s.17
(B) s.18
(C) s.12
(D) s.11
(E) s.10
Rationale: Average price per book
= (520 + 248) / (42 + 22) = 768/ 64
= Rs.12
Answer:C
Answer: (C) s.12
Question: In a class total 34 students, 16 are have a brother, 15 are have sisters, 9 students don't have either brothers or sisters.Find the number of students having both brother and sisters.
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: Total Number of students = 34
Let A be the Number of students have a brothers.
Let B be the number of students have a sisters.
AUB = Number of students have either brothers or sisters=34-9=25
n(AUB)= n(A)+n(B)-n(AnB)
25=16+15-n(AnB)
n(AnB)=31-25
n(AnB)=6
The number of students having both brother and sisters = 6
ANSWER:C
Answer: (C) 6
Question: What is the greatest 5-digit number when divided by 6, 7 ,8 , 9, and 10 leaves a remainder of 4, 5, 6, 7, and 9 respectively?
(A) 56780
(B) 78910
(C) 97479
(D) 97918
(E) 97920
Rationale: When you divide a positive integer by 10, the remainder will just be the units digit. We know the remainder is 9 when we divide by 10, so C is the only possible answer.
Answer: (C) 97479
Question: The inverse ratio of 6: 2: 1 is?
(A) 2:3:7
(B) 2:3:9
(C) 2:3:2
(D) 1:3:6
(E) 2:3:1
Rationale: 1/6: 1/2: 1/1 = 1:3:6
Answer:D
Answer: (D) 1:3:6
Question: If f(x) = ax^5 – 3x^2 + ax^2 – x, then f(b) – f(-b) will equal:
(A) 0
(B) 2ab
(C) 2ab^4 – 6
(D) 2ab^5-2b
(E) ab^5
Rationale: f(x)=ax^5 – 3x^2 + ax^2 – x
f(b) = ab^5 – 3b^2 + ab^2 – b
f(-b) = -ab^5 – 3b^2 + ab^2 + b
f(b) - f(-b) = ab^5 – 3b^2 + ab^2 – b + ab^5 + 3b^2 - ab^2 – b
=2ab^5-2b
Answer D
Answer: (D) 2ab^5-2b
Question: For the set { 3, 3, 4, 4, 5, 5, x}, which of the following values of x will most increase the standard deviation?
(A) (-3)^2
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: Standard Deviation Step 1, as pointed out by others, is to find out the mean = 4
Step 2, For each number: subtract the Mean and square the result =
(1-4)^2=(-3)^2
(2-4)^2=(-2)^2
(3-4)^2 =(-1)^2
(4-4)^2=(.0)^2
(5-4)^2=(1)^2
Clearly (1-4)^2=(-3)^2 will give you the greatest value among all the other options.
Hence A
Answer: (A) (-3)^2
Question: Gold is 10 times as heavy as water and copper is 5 times as heavy as water. In what ratio should these be mixed to get an alloy 9 times as heavy as water?
(A) 3:2
(B) 1:2
(C) 4:1
(D) 5:2
(E) 4:3
Rationale: G = 10W
C = 5W
Let 1gm of gold mixed with x gm of copper to get 1+x gm of the alloy
1gm gold + x gm copper = x+1 gm of alloy
10W+5Wx = x+1 * 9W
10+5x = 9(x+1)
x = 1/4
Ratio of gold with copper = 1:1/4 = 4:1
Answer is C
Answer: (C) 4:1
Question: Media companies sell their magazine through a distributor, which take a commission of 3% of the price set by the media company. The distributor obtains the magazines through each company at the price of $12 per subscription. What is the price that the buyer observers if the distributor wants to maintain a 3% profit on the cost of a subscription?
(A) 11.13
(B) 11.72
(C) 11.74
(D) 12.72
(E) 12.74
Rationale: Magazine price = $12;The distributor wants to maintain a 3% profit on the cost of each magazine subscription, thus he must get $12*1.03 = $12.36 after the distributor takes a commission of 3% of the final price --> (final price)*0.97 = $12.36 --> (final price) = $12.74Answer: E.
Answer: (E) 12.74
Question: How many 6 digit telephone numbers can be formed if each number starts with 35 and no digit appears more than once?
(A) 720
(B) 360
(C) 1420
(D) 1680
(E) 1780
Rationale: 6 digit number where first 2 digit are fixed .
1*1*8*7*6*5 =1680
ANSWER:D
Answer: (D) 1680
Question: The number of arrangement of letters of the word BANANA in which the two N's do not appear adjacently is:
(A) 40
(B) 50
(C) . 60
(D) 80
(E) 100
Rationale: Total # of arrangements of BANANA is 6!/(3!2!) = 60 (arrangement of 6 letters {B}, {A}, {N}, {A}, {N}, {A}, where 3 A's and 2 N's are identical).
The # of arrangements in which the two N's ARE together is 5!/3!=20 (arrangement of 5 units letters {B}, {A}, {A}, {A}, {NN}, where 3 A's are identical)..
The # of arrangements in which the two N's do not appear adjacently is {total} - {restriction} = 60 - 20 = 40.
Answer: A.
Answer: (A) 40
Question: Bill has a small deck of 14 playing cards made up of only 2 suits of 7 cards each. Each of the 7 cards within a suit has a different value from 1 to 7; thus, there are 2 cards in the deck that have the same value. Bill likes to play a game in which he shuffles the deck, turns over 4 cards, and looks for pairs of cards that have the same value. What is the chance that Bill finds at least one pair of cards that have the same value?
(A) 8/67
(B) 61/130
(C) 17/33
(D) 63/143
(E) 25/88
Rationale: P(no pairs) = 12/13*10/12*8/11 = 80/143
P(at least one pair) = 1 - 80/143 = 63/143
The answer is D.
Answer: (D) 63/143
Question: In a theater, the first row has 15 seats and each row has 2 more seats than previous row. If the last row has 53 seats, what is the total number of seats in the theater?
(A) 600
(B) 640
(C) 680
(D) 720
(E) 760
Rationale: The number of seats in the theater is
15 + (15+2) + ...+ (15+38)=
20(15) + 2(1+2+...+19)=
20(15) + 2(19)(20)/2=
20(15+19) = 20(34) = 680
The answer is C.
Answer: (C) 680
Question: In an xy-coordinate plane, a line is defined by y = kx + 1. If (4, b), (a,3), and (a, b+1) are three points on the line, where a and b are unknown, then k = ?
(A)  1/2
(B)  1/4
(C)  3/2
(D)  2
(E)  5/2
Rationale: b=4k+1...(1)
b+1=ak+1...(2)
3=ak+1...(3)
Taking (2) and (3)
3=b+1
b=2
Taking (1)
2=4k+1
k=1/4
Answer : B
Answer: (B)  1/4
Question: What is the greatest prime factor of 8^13 - 2^30?
(A) 23
(B) 37
(C) 59
(D) 73
(E) 107
Rationale: 8^13 - 2^30
=(2^3)^13 - 2^30
= 2^39 - 2^30
= 2^30 (2^9 -1)
= 2^30 * (512-1)
= 2^30 * 511
= 2^30 * 7 * 73
The greatest prime factor is 73.
The answer is D.
Answer: (D) 73
Question: Ten identical machines, running continuously at the same constant rate, take 6 days to complete a shipment. How many additional machines, each running at the same constant rate, would be needed to reduce the time required to complete a shipment by four days?
(A) 25
(B) 20
(C) 14
(D) 9
(E) 5
Rationale: From the question you know that 10R = 1/6. The question asks you (partially) to make the rate from 1/6 to 1/2 (drop from 6 day to 2). So the only thing that you need to do is to find the magic number than can convert 1/6 to 1/2.
So 1/6 * x = 1/2 (1 equation with one unknown). So by solving this you get x = 6/2 or 3/1. Thats it then! Take the magic number 3/1 and multiply BOTH sides of the original equation and you have:
10*(3/1)*R = (3/1) * 1/6
10 * 3 * R = 1/2, Hence 30R = 1/2, therefore 20 more machines!
B
Answer: (B) 20
Question: If S is the sum of the reciprocals of the consecutive integers from 91 to 100, inclusive, which of the following is less than S?
I. 1/8
II. 1/9
III. 1/10
(A) None
(B) I only
(C) III only
(D) II and III only
(E) I, II, and III
Rationale: Since we summarize the reciprocals from 100 to 91, we can say also that we add ten numbers who are all (with one exception 1/100) greater than 1/100, so that the sum must be greater than 1/10.
On the other side we can say that we add the reciprocals from 91 to 100, so that the sum has to be less than the sum of ten times 1/91.
We can conclude that the sum has to be less than 1/9 but more than 1/10. That leaves us C as the only possible answer.
Answer: (C) III only
Question: A cistern 9m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:
(A) 49 m2
(B) 50 m2
(C) 53.5 m2
(D) 68.5 m2
(E) 57 m2
Rationale: Area of the wet surface	= [2(lb + bh + lh) - lb]
= 2(bh + lh) + lb
= [2 (4 x 1.25 + 9 x 1.25) + 9 x 4] m2
= 68.5 m2.
Answer: Option D
Answer: (D) 68.5 m2
Question: A delegation of 5 members has to be formed from 3 ladies and 5 gentlemen. In how many ways the delegation can be formed, if 2 particular ladies are always included in the delegation?
(A) 20
(B) 30
(C) 37
(D) 40
(E) 39
Rationale: There are three ladies and five gentlemen and a committee of 5 members to be formed.
Number of ways such that two ladies are always included in the committee
= ⁶C₃ = (6 * 5 * 4)/6 = 20.
Answer:A
Answer: (A) 20
Question: A and B start a business jointly. A invests Rs.16000 for 8 months and B remains in the business for 4 months. Out of the total profit B claims 2/7th share. How much money is contributed by B?
(A) 12288
(B) 12800
(C) 27636
(D) 19287
(E) 19281
Rationale: Explanation:
16*8: x*4 = 5:2
x = 12.8 => Rs.12800
Answer: B
Answer: (B) 12800
Question: In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the rate in the remaining 40 overs to reach the target of 252 runs?
(A) 6.25
(B) 6.22
(C) 5.5
(D) 6.39
(E) 6.13
Rationale: Required run rate
= [252 - (3.2 * 10)]/40
= 220/40
= 5.5
Answer: C
Answer: (C) 5.5
Question: A bag contains 14 wool scarves, exactly one of which is red and exactly one of which is green. If Deborah reaches in and draws three scarves, simultaneously and at random, what is the probability that she selects the red scarf but not the green scarf?
(A) 2/15
(B) 11/23
(C) 18/121
(D) 33/182
(E) 51/273
Rationale: Total possible ways to choose three scarves is 14C3 = 364
We need to choose the red scarf and two of 12 other scarves (not the green scarf).
The number of successful possibilities is 12C2 = 66
P(red scarf but not green scarf) = 66/364 = 33/182
The answer is D.
Answer: (D) 33/182
Question: Rs.630/- distributed among A,B and C such that on increasing their shares by RS.10,RS.5 and RS.15 respectively, The balance money would be divided among them in the ratio 3:4:5. Then, A’s share is:?
(A) Rs.155
(B) Rs.145
(C) Rs.150
(D) Rs.140/-
(E) Rs.160
Rationale: A:B:C = 3:4:5
Total parts = 12
A's share is = 3 parts
12 -----> Rs.600/-
3 -----> Rs.150/-
A's total = 150 - 10 = Rs.140/-
D)
Answer: (D) Rs.140/-
Question: Five years ago the average of the ages of A and B was 40 years and now the average of the ages of B and C is 48 years. What will be the age of the B ten years hence?
(A) 22
(B) 27
(C) 96
(D) 51
(E) 2
Rationale: Let the present ages of A, B and C be a, b and c respectively.
Given, [(a - 5) + (b - 5)] / 2 = 40 => a + b = 90 --- (1)
(b + c)/2 = 48 => b + c = 96 --- (2)
From (1) and (2), we cannot find b.
Answer:D
Answer: (D) 51
Question: Two persons start running simultaneously around a circular track of length 200 m from the same point at speeds of 10 km/hr and 15 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions?
(A) 28 sec
(B) 19.2 sec
(C) 17 sec
(D) 23 sec
(E) 27 sec
Rationale: Time taken to meet for the first time anywhere on the track
= length of the track / relative speed
= 200 / (10 + 15)5/18 = 300* 18 / 25 * 5 = 19.2 seconds.
Answer : B
Answer: (B) 19.2 sec
Question: A car covers a distance of 1728 km in 6 hours. Find its speed?
(A) 104
(B) 288
(C) 271
(D) 276
(E) 128
Rationale: 1728/6 = 288 kmph
Answer: B
Answer: (B) 288
Question: A certain candy manufacturer reduced the weight of Candy Bar M by 25 percent buy left the price unchanged. What was the resulting percent increase in the price per ounce of Candy Bar M?
(A) 20
(B) 30
(C) 34
(D) 35
(E) 33.33
Rationale: assume 1oz candy cost $1 before.
now price remain same $1 but weight of candy reduces to 0.75 oz
new price of candy = 1/0.75 =1.3333
price increase 33.33 %
E
Answer: (E) 33.33
Question: a renowned battery sells six different-sized wedding cakes. Each cake costs x dollars more than the next one below it in size, and the price of the largest cake is $24.50. If the sum of the prices of the six different cakes is $109.50, what is the value of x?
(A)  1.50
(B)  1.75
(C)  2.00
(D)  2.50
(E)  3.00
Rationale: Since the price of the largest cake (6th) is $24.50, then the price of the smallest cake (1st) is $(24.50-5x). Now, the prices of the cakes are evenly spaced so the sum of the prices is (average price)*(# of cakes)=(first+last)/2*(# of cakes). So, (24.50-5x+24.50)/2*6=109.50 --> x=2.5.
Answer: D.
Answer: (D)  2.50
Question: Fifteen more than three times a number is the same as ten less than six times the
number. What is the number
(A) 20/2
(B) 15/4
(C) 30/5
(D) 25/3
(E) 9/6
Rationale: 3x+15 First, addition is built backwards
6x−10 Then, subtraction is also built backwards
3x+15=6x−10 Is between the parts tells us theymust be equal
−3x −3x Subtract 3x so variable is all on one side
15=3x−10 Nowwe have a two−step equation
+10 +10 Add 10 to both sides
25=3x The variable ismultiplied by 3
3 3 Divide both sides by 3
25/3=x Our number is
25/3
correct answer D
Answer: (D) 25/3
Question: Mandrake has to choose from 4 from 10 people. There are 3 girls, 5 boys , 2 children. What is total probability that he will choose 1G , 2B , 1C?
(A) 1/7
(B) 2/7
(C) 3/7
(D) 4/7
(E) 5//7
Rationale: (3C1 * 5C2 * 2C1)/ 10C4 = 3*10*2/210 = 60/210=2/7
ANSWER:B
Answer: (B) 2/7
Question: Maddie has 48 apples, if she give 22 to mike, how many does she have left?
(A) 12
(B) 21
(C) 26
(D) 22
(E) 5
Rationale: 48-22=26
C. 26
Answer: (C) 26
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is?
(A) 3/7
(B) 3/2
(C) 3/5
(D) 3/1
(E) 3/3
Rationale: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23
==> 27 x + 17 y = 23 x + 23 y ==> 4 x = 6 y ==> x/y
= 3/2.
Answer: B
Answer: (B) 3/2
Question: The sume of the ages of a father and his son is 45 years.Five years ago,the product of their ages was 34 .The ages of the son and the father are respectively :
(A) 6 and 39
(B) 7 and 38
(C) 9 and 36
(D) 11 and 34
(E) 12 and 74
Rationale: Solution
Let the ages of father and son be x and (45 - x) years respectively.
Then,(x - 5)(45 - x - 5)=34 ⇔ (x - 5) (40 - x)=34 ⇔x2 - 45x + 234 = 0
⇔ (x - 39)(x - 6)= 0 ⇔ x = 39 or x =6.
∴ Father's age = 39 years and son's age =6 years. Answer A
Answer: (A) 6 and 39
Question: Divide Rs. 5500 among A, B and C so that A receives 1/3 as much as B and C together and B receives 1/5 as A and C together. A's share is?
(A) 1227
(B) 1268
(C) 1375
(D) 1200
(E) 1210
Rationale: A+B+C = 5500
A = 1/3(B+C); B = 1/5(A+C)
A/(B+C) = 1/3
A = 1/4 * 5500 => 1375
Answer: C
Answer: (C) 1375
Question: There are 2 sections with 4 questions each. If three questions are selected from each section, the chance of getting different questions is________
(A) 10
(B) 214
(C) 300
(D) 216
(E) 245
Rationale: we have to select three questions from each section so the chances are 4C2.4C2.4C2=216
ANSWER:D
Answer: (D) 216
Question: Samantha's investment portfolio consists of three stocks: an airline, a bank, and a computer company. In the month of February, the price of the airline's stock rose by 10%, that of the bank decreased by 15% and that of the computer company also decreased by 12%, but the overall value of her portfolio increased. If Samantha owns equal amounts of all three stocks, which of the following could be the initial prices of the three stocks in the order airline, bank, and computer company respectively?
(A) $75, $25, $20
(B) $65, $60, $60
(C) $65, $55, $90
(D) $55, $85, $40
(E) $25, $60, $70
Rationale: Since Samantha owns equal amounts of stocks, the 10% increase alone should set off the 15% decrease in each of the other two stocks. i.e The stock which increased should have a substantially higher value than the two stocks which decreased. Between B and A, A is obviously the safer bet and is the right answer.
Answer is A.
Answer: (A) $75, $25, $20
Question: A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1.5 cm when a man gets on it. The mass of man is
(A) 12 kg
(B) 90 kg
(C) 72 kg
(D) 96 kg
(E) None
Rationale: Solution
Volume of water displaced	= (3 x 2 x 0.015)m3
= 0.09m3.
Mass of man	=Volume of water displaced ×Density of water
= (0.09×1000) kg
= 90 kg.
Answer B
Answer: (B) 90 kg
Question: Tough and Tricky questions: Ratios
4/5 of a certain class left on a field trip. 1/3 of the students who stayed behind did not want to go on the field trip (all the others did want to go). When another vehicle was located, 1/2 of the students who did want to go on the field trip but had been left behind were able to join. What fraction of the class ended up going on the field trip?
(A) 1/2
(B) 2/3
(C) 13/15
(D) 23/30
(E) 4/5
Rationale: let total no. of students be 30
students left on a field trip = 4/5(30) =24
thus 6 students left behind
1/3(6)=2 students did not want to go. thus 4 students want to go on the trip
1/2(4)=2 were able to join the other students on the field trip.
thus total number of students that went on a field trip =24+2 =26
thus required fraction = 26/30 =13/15
C
Answer: (C) 13/15
Question: What is M : N if M is 40% of N
(A) 2:3
(B) 5:2
(C) 3:2
(D) 2:5
(E) 1:2
Rationale: Solution:
M = 40% of N = 40*N/100 = 2*N/5 = 5M = 2N ; M : N = 2 : 5
ANSWER IS D
Answer: (D) 2:5
Question: A group of people were given 2 puzzles. 70% people solved puzzle X and 89% people solved puzzle Y. What is the maximum and minimum percentage of people who could have solved both the puzzles?
(A)  11%, 0%
(B)  49%, 33%
(C)  70%, 57%
(D)  79%, 68%
(E)  89%, 79%
Rationale: To solve this question, we don't need any formulas. Just read the question carefully. If 70% of the people solved puzzle X and 89% solved puzzle Y, then maximum % that can solve both correctly can only be 70%. From the given options, only D looks good
Answer C
Answer: (C)  70%, 57%
Question: A tradesman by means of his false balance defrauds to the extent of 30%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
(A) 17%
(B) 77%
(C) 44%
(D) 16%
(E) 69%
Rationale: g% = 30 + 30 + (30*30)/100
= 69%
Answer: E
Answer: (E) 69%
Question: If a train, travelling at a speed of 180 kmph, crosses a pole in 6 sec, then the length of train is?
(A) 300
(B) 125
(C) 288
(D) 266
(E) 121
Rationale: D = 180 * 5/18 * 6
= 300 m
Answer: A
Answer: (A) 300