mathewhe/aqua_rat huggingface dataset:
Question: The sale price sarees listed for Rs.200 after successive discount is 10% and 5% is?
(A) 187
(B) 169
(C) 172
(D) 178
(E) 171
Rationale: 200*(90/100)*(95/100)
= 171
Answer:E
Answer: (E) 171
Question: Four bells commence tolling together and toll at intervals of 2, 4, 6, 8 seconds respectively. In 18 minutes, how many times do they toll together ?
(A) 43
(B) 44
(C) 45
(D) 46
(E) 47
Rationale: LCM of 2, 4, 6, 8 is 24.
So, after each 24 seconds, they would toll together.
Hence, in 18 minutes, they would toll 18*60 seconds / 24 seconds = 45 times
But then the question says they commence tolling together. So, they basically also toll at thebeginning(0second).
So, total tolls together = 45+1 = 46
Answer C
Answer: (C) 45
Question: 16 business executives and 7 chairmen meet at a conference. If each business executive shakes the hand of every other business executive and every chairman once, and each chairman shakes the hand of each of the business executives but not the other chairmen, how many handshakes would take place?
(A) 144
(B) 131
(C) 232
(D) 90
(E) 45
Rationale: there are 16 business exec and in each handshake 2 business execs are involved.
hence 16C2=120
Also, each of 16 exec will shake hand with every 7 other chairmen for total of 112 handshake.
total=120+112=232
ANS: C
Answer: (C) 232
Question: WHAT WILL BE THE VALUE OF
log e(e(e....)^1/2)^1/2)^1/2).....log base is e?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
Rationale: e(e(e....)^1/2)^1/2)^1/2 = e ^ (1/2 + 1/4 + 1/8 +....)
it is in G.P(Geometric progression) then sum to infinite terms = (a)/(1-r)
(1/2 + 1/4 + 1/8 +....) = (1/2)/(1-1/2) = 1
so e ^ 1
log(e^1) base e = 1
ANSWER:B
Answer: (B) 1
Question: The average age of 40 students is 8 years. If the age of teacher is also included , then their average age increases by half a year. What is the age of the teacher?
(A) 45 years
(B) 48.5 years
(C) 28.5 years
(D) 26.5 years
(E) 29.5 years
Rationale: Exp. Total age of 40 students = 40*8 = 320
Let the age of the the teacher be x, Then (320+x)/41 = 8+1/2 =8 ½.
320+x =17/2*41 =697/2 = 348.5, x =348.5-320 = 28.5
Answer: C
Answer: (C) 28.5 years
Question: A, B and C have Rs.300 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have?
(A) A)250
(B) B)249
(C) C)248
(D) D)247
(E) E)246
Rationale: A+B+C = 300
A+C = 200
B+C = 350
--------------
A+B+2C = 550
A+B+C = 300
----------------
C = 250
Answer:A
Answer: (A) A)250
Question: Of the 200 stamps in a collection, 90 are foreign and 50 are more than 10 years old. If 20 stamps are both foreign and more than 10 years old, how many stamps are neither foreign nor more than 10 years old?
(A) 30
(B) 80
(C) 100
(D) 130
(E) 150
Rationale: 20 stamps are both foreign and more than 10 years old.
70 stamps are foreign only.
30 stamps are 10 years old only.
The number of remaining stamps is 200 - (20+70+30) = 80
The answer is B.
Answer: (B) 80
Question: If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 4960 , R will receive
(A) 600
(B) 700
(C) 800
(D) 960
(E) None of these
Rationale: Explanation :
Let P's capital = p, Q's capital = q and R's capital = r
Then
4p = 6q = 10r
=> 2p = 3q = 5r
=>q = 2p/3
r = 2p/5
P : Q : R = p : 2p/3 : 2p/5
= 15 : 10 : 6
R's share = 4960 * (6/31) = 160*6 = 960. Answer : Option D
Answer: (D) 960
Question: The number of livestock in a farm at the beginning of year 2000 was 140,000. During the year, the number increased by p%. During the next year 2001, there was a famine and the number decreased by q%. A census at the end of year 2001 revealed that the number of livestock in the farm was 140,000. Which of the following expressions is correct?
(A) There is no relation between p and q
(B) q > p
(C) p = q
(D) With the exception of 1 instance, p will be equal to q
(E) p > q
Rationale: Number plugging in will be best strategy for this question.
Let p = 5%,
Per the question 100000(1.05)(1-q/100) = 100000 ---> q = 4.7%. Thus p > q and hence E is the correct answer.
Answer: (E) p > q
Question: A and B can together finish a work in 10days. They worked together for 5days and then B left. After another 5days, A finished the remaining work. In how many days A alone can finish the job?
(A) 10
(B) 15
(C) 20
(D) 5
(E) 30
Rationale: A+B 5days work = 5*1/10 = 1/2
Remaining work = 1-1/2 = 1/2
1/2 work is done by A in 5days
whole work will be done by A in 5*2 = 10days
Answer is A
Answer: (A) 10
Question: Four hundred students at College Q study a foreign language. Of these, 190 of those students study French, and 260 study Spanish. If at least 105 students who study a foreign language at College Q study neither French nor Spanish, then the number of students who study Spanish but not French could be any number from
(A) 10 to 40
(B) 40 to 100
(C) 60 to 100
(D) 60 to 105
(E) 70 to 110
Rationale: 190 students study French
210 students do not study French
260 students study Spanish
140 students do not study Spanish
105 students study neither French nor Spanish
210-140=70
210-105=90
D. 60 to 105
Answer: (D) 60 to 105
Question: 40% of x is greater than 1/3rd of x by 110.what is x?
(A) 1100
(B) 2100
(C) 1300
(D) 1650
(E) 1400
Rationale: 4x/10-x/3=110
1x/15=110
x=1650
ANSWER:D
Answer: (D) 1650
Question: Evaluate :log3 27
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: Solution
log3 27	= n
=3n
=27
=33
n‹=›3.
Answer A
Answer: (A) 3
Question: The average weight of 4 person's increases by 1.5 kg when a new person comes in place of one of them weighing 95 kg. What might be the weight of the new person?
(A) 101 kg
(B) 103.4 kg
(C) 105 kg
(D) Data inadequate
(E) None of these
Rationale: Total weight increased = (4 x 1.5) kg = 6 kg.
Weight of new person = (95 + 6) kg = 101 kg.
Answer: Option A
Answer: (A) 101 kg
Question: Anne has pouches of grain that she wants to divide between the different areas of the petting zoo. Unfortunately, Anne's pouches of grain don't divide evenly. It turns out that in order for the pouches of grain to divide evenly, Anne will have to purchase two additional pouches of grain, and not visit two of the petting zoo areas. Which of the following can describe the initial number of grain pouches, and the initial number of areas in the petting zoo (in the order areas of the petting zoo; pouches of grain)?
(A) 20; 5.
(B) 16; 5.
(C) 12; 4
(D) 30; 4
(E) 21; 7
Rationale: Option B) Initially 16 petting zoo areas, then decreased to 14 petting zoo areas; and Initially 5 pouches of grain, then icreased to 7 pouces of grain fits the requirement.
14 / 7 = 2 pouches of grain per petting zoo area
Answer: (B) 16; 5.
Question: A group of tourists wants to visit at least three of the four cities A, B, C, and D. How many travel itineraries can they make? All cities are connected to one another and please note that visiting the same cities in a different order counts as a different itinerary.
(A) 24
(B) 36
(C) 48
(D) 60
(E) 64
Rationale: The number of ways to choose three cities is 4C3=4.
The number of itineraries for each group of 3 cities is 3!.
So the number of itineraries to three cities is 4*3!=24.
The number of ways to choose four cities is 4C4=1.
The number of itineraries for the group of 4 cities is 4!.
So the number of itineraries to four cities is 4!=24.
The total number of itineraries is 24+24=48.
The answer is C.
Answer: (C) 48
Question: 2/3rd of the boys and 3/4th of the girls of a school participate in a function. If the no.of participating students is 550, out of which 150 are girls, what is the total no.of students in the school?
(A) 620
(B) 780
(C) 800
(D) 880
(E) 900
Rationale: Let total number of boys be x and total number of girls be y. y=400=>x = 600and^= I50=>y = 200 Now, x + y = 800
C
Answer: (C) 800
Question: The owner of a furniture shop charges his customer 20% more than the cost price. If a customer paid Rs. 3000 for a computer table, then what was the cost price of the computer table?
(A) 2500
(B) 2772
(C) 1991
(D) 6725
(E) 2099
Rationale: CP = SP * (100/(100 + profit%))
= 3000(100/120) = Rs. 2500.
Answer: A
Answer: (A) 2500
Question: If f(x) =6* (x^4 - 1)/(x^2), what is f(1/x) in terms of f(x)?
(A) f(x)
(B) -f(x)
(C) 1/f(x)
(D) -1/f(x)
(E) -6*f(x)
Rationale: f(1/x) =6* ((1/x)^4 - 1) / ((1/x)^2)
= 6*((1/x^4) - 1) / (1/x^2)
= 6*((1-x^4)/(x^4)) / (1/x^2)
= 6*(1-x^4)/(x^2)
= - 6*( (x^4) -1) / (x^2)
= -6f(x)
Answer is E.
Answer: (E) -6*f(x)
Question: Mangoes, Oranges and Apples in a fruit shop are in the ratio of 10: 2 : 3. If there are 120 Mangoes, the number of Apples in the shop is:.
(A) 36
(B) 42
(C) 72
(D) 400
(E) 56
Rationale: Explanation :
Let Mangoes = 10x, Oranges = 2x & Apples = 3x. Now, 10x = 120 hence x = 12.
Number of Apples = 3x = 36.
Answer : A
Answer: (A) 36
Question: The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person?
(A) 11
(B) 19
(C) 12
(D) 17
(E) 14
Rationale: Initial average age of the 10 persons be P.
Age of the new person Q.
Sum of the ages of the initial 10 persons = 10P
New average = (P-3) 10(P-3) = 10P - 42 + Q => Q
= 12
Answer: C
Answer: (C) 12
Question: There are 3 classes having 20, 24 and 30 students respectively having average marks in
an examination as 20,25 and 30 respectively. The three classes are represented by A, B and C and you have the following information about the three classes.
a. In class A highest score is 22 and lowest score is 18
b. In class B highest score is 31 and lowest score is 23
c. In class C highest score is 33 and lowest score is 26.
(A) can't be determined in both cases
(B) definite decrease in both cases
(C) definite increase in both cases
(D) will remain constant in both cases
(E) will remain constant in both cases21
Rationale: Ans: B
Explanation:
Class A average is 20. And their range is 18 to 22
Class B average is 25. And their range is 23 to 31
Class A average is 30. And their range is 26 to 33
If 5 students transferred from A to B, A's average cannot be determined but B's average comes down as the highest score of A is less than lowest score of B.
If 5 students transferred from B to C, C's average cannot be determined the B's range fo marks and C's range of marks are overlapping.
Answer:A
Answer: (A) can't be determined in both cases
Question: The price of a jewel, passing through three hands, rises on the whole by 65%. If the first and second sellers earned 20% and 25% profit respectively, find the percentage profit earned by the third seller.
(A) 10%
(B) 22%
(C) 18%
(D) 12%
(E) 15%
Rationale: Let the original price of the jewel be Rs. P and let the profit earned by the third seller
be x%.
Then, ( 100 +x )% of 125% of 120% of P = 165% of p
[ ( 100+x )/100*125/100*120/100* P ] = [ 165/100* P ]
( 100 + X ) = 165*100*100/125*120 = 110,
X = 10%.
ANSWER:A
Answer: (A) 10%
Question: A ship sails out to a mark at the rate of 19 kmph. and sails back at the rate of 13 kmph. The average rate of sailing is ?
(A) 15 km/hr
(B) 12 km/hr
(C) 12.5 km/hr
(D) 25 km/hr
(E) None
Rationale: Answer
Average = ( 2uv / u +v ) km/hr
= ( 2 x 19 x 13 ) / (19 +13 ) km/hr.
= 15 km/hr.
Correct Option: A
Answer: (A) 15 km/hr
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 30 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
(A) 12 sec
(B) 24 sec
(C) 48 sec
(D) 60 sec
(E) 62 sec
Rationale: Relative speed = 30 + 30 = 60 km/hr.
60 * 5/18 = 50/3 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 3/50 = 60 sec.
ANSWER:D
Answer: (D) 60 sec
Question: If x is positive integer,y is negative integer, and 3x + 2y = 13, which of the following could be the value of x ?
(A) 9
(B) 10
(C) 12
(D) 13
(E) 4
Rationale: Use answer options to solve this problem -
Put x= 9
3x+2y=13
3(9)+2y=13
27+2y=13
2y=13-27;2y=-14
y=-7(y is negative integer)
Answer will be (A)
Answer: (A) 9
Question: Some of the workers at a hedge fund are analysts; the others are not analysts. There are a total of 2x/3 analysts at the hedge fund. A total of x hedge fund workers have an MBA. Furthermore, x/3 analysts have an MBA, y/4 of the hedge fund workers are neither analysts nor have an MBA, and 70 workers are not analysts. If there are y total workers at the hedge fund, x is equal to which of the following?
(A) 45
(B) 50
(C) 63
(D) 75
(E) 80
Rationale: AnalystsNot AnalystsTotal
MBAx/32x/3x
No MBAy/4
Total2x/350y
We are asked for the value of x.
From the table: 2x/3 = y - 70
y - 70 + (y/4) = 70
5y/4 = 140
y = 112
2x/3 = 112 - 70 = 42
x = 126/2 = 63
Answer: C
Answer: (C) 63
Question: Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
(A) 4
(B) 6
(C) 5
(D) 7
(E) 9
Rationale: N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Answer: Option A
Answer: (A) 4
Question: If the true discount on a sum due 3 years hence at 14% per annum be Rs. 168, the sum due is:
(A) 698
(B) 768
(C) 1430
(D) 1980
(E) None
Rationale: Sol.
P.W. = 100 * T.D./R * T = 100 * 168 / 14 * 2 = 600.
∴ Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.
Answer B
Answer: (B) 768
Question: William earned $9.50 an hour. He worked 40 hours one week and received a bonus
of $75.00. How much did he earn that week?
(A) $455.00
(B) $555.00
(C) $655.00
(D) $755.00
(E) $855.00
Rationale: Multiply $9.50 x 40 = $380.00
Add bonus $75.00 + $380.00= $455.00
$380.00
+ 75.00
$455.00
correct answer A
Answer: (A) $455.00
Question: Find the unit's digit in the product 2467 153 * 34172?
(A) 1
(B) 3
(C) 2
(D) 5
(E) 7
Rationale: Unit's digit in the given product=Unit's digit in 7 153 * 172
Now 7 4 gives unit digit 1
7 152 gives unit digit 1
7 153 gives 1*7=7.Also 172 gives 1
Hence unit's digit in the product =7*1=7.
Option A
Answer: (A) 1
Question: Find the surface area of a 10cm*4cm*3cm brick.
(A) 154 cm square
(B) 156 cm square
(C) 160 cm square
(D) 164 cm square
(E) None of these
Rationale: Explanation:
Surface area of a cuboid = 2(lb+bh+hl) cm square
So,
Surface area of a brick = 2(10*4+4*3+3*10) cm square
= 2(82) cm square = 164 cm square
Option D
Answer: (D) 164 cm square
Question: The banker's discount on a sum of money for 3 years is Rs. 1116. The true discount on the same sum for 4 years is Rs. 1200. What is the rate per cent?
(A) 8%
(B) 12%
(C) 10%
(D) 6%
(E) 7%
Rationale: Explanation :
BD for 3 years = Rs. 1116
BD for 4 years = 11163 × 4 = Rs. 1488
TD for 4 years = Rs. 1200
F = BD × TD(BD – TD) = (1488 × 1200)/(1488–1200) = (1488×1200)/288
= (124 × 1200)/24 = (124 × 100)/2 = 62 × 100 = Rs. 6200
=> Rs.1488 is the simple interest on Rs. 6200 for 4 years
⇒ 1488 = (6200 × 4 × R)/100
⇒ R = (1488 × 100)/(6200 × 4)
= (372 × 100)/6200 = 372/62 = 6% Answer : Option D
Answer: (D) 6%
Question: If the average (arithmetic mean) of a and b is 100, and c – a = 120, what is the average of b and c?
(A) 150
(B) 140
(C) 160
(D) 170
(E) 180
Rationale: a+b/2 = 100
=> a+b = 200
a = c - 120...sub this value
c-120+b = 200
=>c+b = 320
=>c+b/2 = 160
Answer : C
Answer: (C) 160
Question: In the x-y plane, the area of the region bounded by the graph of |x+y| + |x-y| = 8 is
(A) 8
(B) 12
(C) 256
(D) 20
(E) 24
Rationale: I've never seen such kind of question in GMAT before.
OK there can be 4 cases:
|x+y| + |x-y| = 8
A. x+y+x-y = 8 --> x=4
B. x+y-x+y = 8 --> y=4
C. -x-y +x-y= 8 --> y=-4
D. -x-y-x+y=8 --> x=-4
The area bounded by 4 graphs x=4, x=-4, y=4, y=-4 will be square with the side of 4 so the area will be 16*16=256
Answer: C
Answer: (C) 256
Question: A bowl has only 7 apples and 7 bananas. If one piece of fruit is selected from the bowl at random, and a second piece is selected from the bowl without replacing the first, what is the probability that both pieces of fruit chosen are apples?
(A) 1/10
(B) 1/5
(C) 2/9
(D) 2/5
(E) 3/13
Rationale: 7/14 * 6/13
=3/13
E. 3/13
Answer: (E) 3/13
Question: There are 7 players in a bowling team with an average weight of 121 Kg. If two new players join the team, one weighs 110 Kg and the second weighs 60 Kg, what will be the new average weight?
(A) 115 Kg.
(B) 118 Kg.
(C) 113 Kg.
(D) 110 Kg.
(E) 112 Kg.
Rationale: The New average will be= (121*7+110+60)/9= 113 kgs
C is the answer
Answer: (C) 113 Kg.
Question: Can you find next number in tricky mathematical series below?
111 , 113 , 117 , 119 , 123 , 137 ?
(A) 151
(B) 161
(C) 171
(D) 131
(E) 121
Rationale: Solution:
151 (131+20)
Explanation:
1st 7 prime numbers post 100 are
101 , 103 , 107 , 109 , 113 , 127 , 131
...Adding 20 to numbers
121 , 123 , 127 , 129 , 133 , 147 , 151
Answer A
Answer: (A) 151
Question: A and B working separately can do a piece of work in 9 and 12 days respectively, If they work for a day alternately, A beginning, in how many days, the work will be completed?
(A) 9 days
(B) 11 days
(C) 8 days
(D) 10 1/4 days
(E) None of them
Rationale: (A + B)'s 2 days' work =(1/9+1/12)=7/36
Work done in 5 pairs of days =(5*7/36)=35/36
Remaining work =(1-35/36)=1/36
On 11th day, it is A’s turn. 1/9 work is done by him in 1 day.
1/36 work is done by him in(9*1/36)=1/4 day
Total time taken = (10 + 1/4) days = 10 1/4days.
Answer is D.
Answer: (D) 10 1/4 days
Question: There are two numbers. If 30% of the first number is added to the second number, then the second number increases to its six-fifth. What is the ratio of the first number to the second number?
(A) 1 : 4
(B) 4 : 5
(C) 3 : 5
(D) 5 : 8
(E) 2 : 3
Rationale: Let the two numbers be x and y.
(3/10) * x + y = (6/5) * y
(3/10) * x = (1/5) * y
x/y = 10/15 = 2/3
The answer is E.
Answer: (E) 2 : 3
Question: If q is an odd integer, which of the following must also be odd?
(A) 6q + 4
(B) q + q
(C) 3q + 3
(D) 2q + q
(E) q^2 + 1
Rationale: Things to keep in mind:
Odd + odd = even
Odd + even = odd
Odd*odd = odd
Odd*even = even
On checking each option
A. 6q + 4
6q = even, 6q + 4 = even + even = even.
B. q + q
Odd + odd = even. This will be even
C. 3q + 3
3q = odd, 3q + 3 = odd + odd = even
D. 2q + q
2q = even, 2q +q = even + odd = odd
E. q^2 + 1
q^2 = odd, q^2 + 1 = odd + odd = even
Correct option: D
Answer: (D) 2q + q
Question: The average age of a group of 5 members is 20 years. Two years later, a new member joins the group. The average age of the group becomes 20 years. What is the age of the new member ?
(A) 20 years
(B) 21 years
(C) 10 years
(D) 23 years
(E) 24 years
Rationale: The average age of a group of 5 members is 20 years --> the sum of the ages is 5*20=100;
Two years later the sum of the ages of these 5 members would be 100+5*2=110;
Now, say the age of the new member is x years, so the sum of the ages of a new 6 member group is 110+x. Since given that the average age of this group of 6 members is 20 years then: 20*6=110+x --> x=10.
Answer: C.
Answer: (C) 10 years
Question: If M and N are positive integers, and the remainder obtained when M is divided by N is the same as the remainder obtained when N is divided by M, which of the following is a possible value of MN?
(A)  62
(B)  55
(C)  42
(D)  35
(E)  16
Rationale: I am not too sure on this. I guess it is possible only when M and N are both same. If they are both same, MN must be a perfect square.
16 is a perfect square.
Ans:E
Answer: (E)  16
Question: A is half good a work man as B and together they finish a job in 15 days. In how many days working alone B finish the job?
(A) 23
(B) 22
(C) 45/2
(D) 36
(E) 48
Rationale: C
45/2
WC = 1:2
2x + x = 1/15 => x = 1/45
2x = 2/45 => 45/2 days
Answer: (C) 45/2
Question: Bobby bought 2 shares, and which he sold for $96 each. If he had a profit of 80% on the sale of one of the shares but a loss of 80% on the sale of the other share, then on the sale of both shares Bobby had...
(A) a profit of 10
(B) a profit of 8
(C) a loss of 800
(D) a loss of 342
(E) neither a profit nor a loss
Rationale: Cost of the first stock: 96/1.8=53.33, so profit from it 96-53.33=42.67
Cost of the second stock: 96/0.2=480, so loss from it 96-480=-384
Overall loss 42.67-384=-342
Answer: D.
Answer: (D) a loss of 342
Question: Denise is trying to open a safe whose combination she does not know.
IF the safe has 4000 possible combinations,and she can try 75 different
possibilities,what is the probability that she does not pick the one
correct combination.
(A) 1
(B) 159/160
(C) 157/160
(D) 4 3/160
(E) 0
Rationale: When trying the first time the probability Denise doesn't pick the correct combination=3999/4000
Second time, as the total number of possible combinations reduced by one, not picking the right one would be 3998/3999.
Third time 3997/3998
...
And the same 75 times.
So we get: 3999/4000∗3998/3999∗...∗3925/39263999/4000∗3998/3999∗...∗3925/3926 every denominator but the first will cancel out and every nominator but the last will cancel out as well.
We'll get 3925/4000=157/160.
Answer: C.
Answer: (C) 157/160
Question: A man purchased a grinder for Rs. 600 and sold it at a profit of 12%. The selling price is:
(A) Rs. 672
(B) Rs. 812
(C) Rs. 684
(D) None of these
(E) Cannot be determined
Rationale: s.p.=112/100 × 600=672
Answer: A
Answer: (A) Rs. 672
Question: Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is ?
(A) 5/16
(B) 5/12
(C) 5/87
(D) 5/56
(E) 5/38
Rationale: Using question number 11 and 12, we get the probability as
1 - (1/36 + 5/9) = 5/12
Answer:B
Answer: (B) 5/12
Question: If a train, travelling at a speed of 90 kmph, crosses a pole in 4 sec, then the length of train is?
(A) 281
(B) 125
(C) 288
(D) 100
(E) 121
Rationale: D = 90 * 5/18 * 4
= 100 m
Answer: D
Answer: (D) 100
Question: X divided by Y equals 6.32 what is a possible remainder?
(A) 2
(B) 4
(C) 6
(D) 8
(E) 7
Rationale: With the decimal being 32/100, the simplest form is 8/25. If the divisor is a multiple of 25, the remainder must be a multiple of 8. The only number that is so is 8. Answer D.
Answer: (D) 8
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 723 grams per kg, what is his percent?
(A) 38.3%
(B) 25%
(C) 77%
(D) 99%
(E) 12%
Rationale: 723 --- 277
100 --- ? => 38.3%
Answer: A
Answer: (A) 38.3%
Question: Find the area of a parallelogram with base 32 cm and height 15 cm.
(A) 200
(B) 384
(C) 345
(D) 480
(E) 242
Rationale: Area of a parallelogram = base * height = 32 * 15 = 480 cm2
Answer: Option D
Answer: (D) 480
Question: During the first two weeks of February, the total rainfall in Springdale was 20 inches. If the rainfall during the second week was 1.5 times the rainfall during the first week, what was the rainfall in inches during the second week of February?
(A) 5
(B) 6
(C) 9
(D) 10
(E) 12
Rationale: Let x be the rainfall in the first week. Then 1.5x was the rainfall in the second week.
2.5x = 20
x = 8
The rainfall during the second week was 1.5 * 8 = 12 inches
The answer is E.
Answer: (E) 12
Question: A train covers a distance of 100km in 1 hour. If its speed is decreased by 10km/hr, the time taken by the car to cover the same distance will be?
(A) 1hr
(B) 1hr 6min
(C) 50min
(D) 1hr 30min
(E) 1hr 45min
Rationale: Speed = 100/1 = 100km/hr
New speed = 100-10 = 90 km/hr
Time taken = 100/90 = 1hr 6min
Answer is B
Answer: (B) 1hr 6min
Question: If 8 men and 2 boys working together, can do seven times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time?
(A) 1:5
(B) 2:3
(C) 3:8
(D) 5:1
(E) 5:2
Rationale: 8M + 2B = 7(1M + 1B)
8M + 2B = 7M + 7B
1M = 5B
The required ratio of work done by a man and a boy = 5:1
Answer:D
Answer: (D) 5:1
Question: An empty pool being filled with water at a constant rate takes 3 hours to fill to 3/5 of its capacity. How much more time will it take to finish filling the pool?
(A) 5 hr 30 min
(B) 5 hr 20 min
(C) 4 hr 48 min
(D) 3 hr 12 min
(E) 2 hr 00 min
Rationale: (3/5) of a pool/ 2 hours = 1/5 (the rate)
(1 pools/5 hours) = (2/5* pool)/ x hours
Cross multiply x = (2/5) 5
x = 2
E
Answer: (E) 2 hr 00 min
Question: One train is traveling 72 kmph and other is at 10 meters a second. Ratio of the speed of the two trains is?
(A) 5:4
(B) 5:6
(C) 2:1
(D) 5:4
(E) 5:1
Rationale: 72 * 5/18 = 10
20:10 => 2:1
Answer: C
Answer: (C) 2:1
Question: 11 times a number gives 132. The number is
(A) 11
(B) 12
(C) 13.2
(D) None
(E) Cannot be determined
Rationale: Explanation:
Let the number be 'N'
11×N=132⇒N=12
Correct Option: B
Answer: (B) 12