mathewhe/aqua_rat huggingface dataset:
Question: A small college reduced its faculty by approximately 14 percent to 195 professors. What was the original number of faculty members?
(A) 182
(B) 208
(C) 227
(D) 254
(E) 302
Rationale: If x is the original number of faculty members, then after 14% reduction in faculty members number is .86x
but we are given .86x = 195
x = 227
So the original number of faculty members is 227
Correct Answer - C
Answer: (C) 227
Question: A bowl of nuts is prepared for a party. Brand P mixed nuts are 20% almonds and Brand Q's Deluxe nuts are 25% almonds. If a bowl contains a total of 67 ounces of nuts, representing a mixture of both brands, and 15 ounces of the mixture are almonds, how many ounces of Brand Q's Deluxe mixed nuts are used?
(A)  16
(B)  20
(C)  32
(D)  44
(E)  48
Rationale: lets say x ounces of P is mixed with Q.
=> 67-x ounces of Q is present in the mixture (as the total = 67 ounces)
given total almond weight = 15 ounces
(20x/100)+(25/100)(67-x) = 15
=> x = 35
=> 67-35 = 32 ounces of Q is present in the mixture.
Answer is C.
Answer: (C)  32
Question: 21 buses are running between two places P and Q. In how many ways can a person go from P to Q and return by a different bus?
(A) None of these
(B) 420
(C) 212
(D) 224
(E) 240
Rationale: Explanation :
He can go in any bus out of the 21 buses.
Hence He can go in 21 ways.
Since he can not come back in the same bus that he used for travelling,
He can return in 20 ways.
Total number of ways = 21 x 20 = 420. Answer : Option B
Answer: (B) 420
Question: Exactly two sides of a certain 10-sided die are red. What is the probability that Kumar rolls the die 4 times and the die lands with a red side up for the first time on the fourth roll?
(A) 0.1026
(B) 0.01024
(C) 0.02
(D) 0.03
(E) 0.04
Rationale: Total no. of sides = 10
Sides that are red = 2
Probability that the die lands with red side up = 2/10
Therefore, Probability that the die does not land with red side up = 1 - 2/10 = 8/10
Probability that Kumar rolls the die 3 times and the die lands with a red side up for the first time on the third roll
= (1st roll - non red face) X (2nd roll - non red face) X (3rd roll - non red face)x (4th roll- red face)
= (8/10) X (8/10) X (8/10) x(2/10)
= 1024/10000
= 0.01024
B
Answer: (B) 0.01024
Question: In a certain game, each player scores either 2 or 5 points. If n players score 2 points and m players score 5 points and the total number of points scored is 45, what is the least possible difference between n and m.
(A) a.1
(B) b.2
(C) c.5
(D) d.7
(E) e.9
Rationale: 2n+5m=45
try with n=5 and m=7 the equation will be satisfied
2(5)+5(7)=45
so difference between M and N is 2,
Answer B
Answer: (B) b.2
Question: The chance of rain on any given day in Tel-Aviv is 50%. What is the probability Z that it rained in Tel-Aviv on exactly 4 out of 6 randomly chosen days?
(A) 15/64
(B) 30/64
(C) 1/2
(D) 1/4
(E) 52/64
Rationale: chances of rain on exactly 4 days and not rain on 2 days = (1/2)^4* (1/2)^2 = 1/64
Chosing 4 days out of 6 = 6!/(4!*2!) = 15
chances of rain on exactly 4 days out of 6 days Z = 15/64
Ans A it is.
Answer: (A) 15/64
Question: Seven mobsters have arrived at the theater for the premiere of the film “Goodbuddies.” One of the mobsters, Frankie, is an informer, and he's afraid that another member of his crew, Joey, is on to him. Frankie, wanting to keep Joey in his sights, insists upon standing behind Joey in line at the concession stand, though not necessarily right behind him. How many ways can the seven arrange themselves in line such that Frankie’s requirement is satisfied?
(A) 1620
(B) 1820
(C) 2320
(D) 2420
(E) 2520
Rationale: 7 mobsters can stand in 7! ways = 5040
in half of the cases one person will be ahead and in the other person in the other half.
thus 5040/2= 2520 cases.
E
Answer: (E) 2520
Question: Which of the following fractions is the largest?
(A) 1/24
(B) 7/30
(C) 1/45
(D) 13/56
(E) 1/72
Rationale: For larger fraction, the numerator should be larger (denominators are same) and/or denominator should be smaller (numerators are same).
So comparing 1/24, 1/45 and 1/72, we ignore 1/45 and 1/72.
7/30 = 1/ (30/7) = 1/4.29
13/56 = 1/ (56/13) = 1/4.3
Since 1/4.29 has the smallest denominator, the largest fraction will be 7/30.
Answer (B)
Answer: (B) 7/30
Question: The cost price of 15 articles is equal to the selling price of 11 articles. Find the profit percent?
(A) 18 2/15
(B) 36 4/11
(C) 36 2/14
(D) 18 2/16
(E) 36 2/12
Rationale: 15 CP = 11 SP
11 --- 2 CP
100 --- ? =>36 4/11%.Answer: B
Answer: (B) 36 4/11
Question: Find the sum of first 10 odd numbers
(A) 10
(B) 40
(C) 200
(D) 100
(E) 540
Rationale: Explanation:
n2 = 102 = 100
Answer: Option D
Answer: (D) 100
Question: From a pack of cards, two cards are drawn one after the other, with replacement. What is the probability that the first card is a black card and the second card is a king or queen?
(A) 1/52
(B) 1/13
(C) 1/26
(D) 3/26
(E) 17/26
Rationale: P(black card) = 1/2
P(king or queen) = 2/13
P(black card then a king/queen) = 1/2 * 2/13 = 1/13
The answer is B.
Answer: (B) 1/13
Question: For my anniversary, I decided to surprise my wife. Since she is a voracious reader, I decided to collect a lot of books for her. On the first day of the month, I bought one book, on the second, I bought two and on the third, I bought three. This process went on till the anniversary and on the day, I had 190 books with me to gift her.
Can you calculate, on which day is our anniversary?
(A) 31
(B) 28
(C) 19
(D) 33
(E) 25
Rationale: C
19rd day
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 = 190
Thus our anniversary falls on the 19rd day of the month.
You can apply other formulas to shorten the process but that is the simplest way to do it.
Answer: (C) 19
Question: Two pipe A and B can fill a empty tank in 1 hour and 75 minute respectively.and there is pipe C for empty.if all three pipe open together in empty tank then tank get fill in 50 minutes.then in how much time pipe C take to empty the full tank?
(A) 100
(B) 90
(C) 80
(D) 70
(E) 60
Rationale: The work of pipe C in 1 hour=[1/60+1/75-1/50]=1/100
so,pipe C will empty that tank in 100 minute.
answer A
Answer: (A) 100
Question: A trader bought a car at 20% discount on its original price. He sold it at a 70% increase on the price he bought it. What percent of profit did he make on the original price?
(A) 18%
(B) 13%
(C) 12%
(D) 36%
(E) 15%
Rationale: Original price = 100
CP = 80
S = 80*(170/100) = 136
100 - 136= 36%
Answer: D
Answer: (D) 36%
Question: Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 42 white marbles. How many red marbles could be in bag A?
(A) 1
(B) 3
(C) 4
(D) 10
(E) 12
Rationale: 6 is the answer.
Bag A-
R:W:B = 2:6:9
Let W in bag A be 6K
Bab B -
R:W = 1:4
Let W in bag B be 4P
W = 42= 6K+4P
=> K =5, P=3
Total Red's in bag A will be 2K = 10
D
Answer: (D) 10
Question: Each student at a certain business school is assigned a 6-digit student identification number. The first digit of the identification number cannot be zero, and the last digit of the identification number must be prime. How many different student identification numbers can the school create?
(A) 9,000
(B) 3,600
(C) 2,700
(D) 360,000
(E) 1,944
Rationale: The identification number is of the form _ _ _ _
1. First digit cannot be 0
2. Middle digits can be anything
3. Last digit has to be prime - 2, 3, 5, 7
We can have the following number of possibilities for each space
__ __ __ __
9 10 10 10 10 4
Total cases = 360000
Option D
Answer: (D) 360,000
Question: A man took a loan at rate of 12% per annum simple interest. After 3 years he had to pay 6480 interest. The principal amount borrowed by him was.
(A) Rs 14000
(B) Rs 15000
(C) Rs 16000
(D) Rs 18000
(E) None of these
Rationale: Explanation:
S.I.=Pâˆ—Râˆ—T/100
=>P=S.I.âˆ—100/Râˆ—T
=>P=6480âˆ—100/12âˆ—3=Rs18000
Option D
Answer: (D) Rs 18000
Question: A boat goes 100 km downstream in 10 hours, and 45 m upstream in 15 hours. The speed of the stream is?
(A) 22 1/7
(B) 22 1/4
(C) 3 1/2
(D) 22 1/1
(E) 22 1/3
Rationale: 100 --- 10 DS = 10
? ---- 1
45 ---- 15 US = 3
? ----- 1 S = (10 - 3)/2
= 3 1/2 kmp Answer: C
Answer: (C) 3 1/2
Question: 40% of Ram's marks is equal to 20% of Rahim's marks which percent is equal to 30% of Robert's marks. If Robert's marks is 80, then find the average marks of Ram and Rahim?
(A) 70
(B) 97
(C) 87
(D) 90
(E) 76
Rationale: Given, 40% of Ram's marks = 20% of Rahim's marks = 30% of Robert's marks.
Given, marks of Robert = 80
30% of 80 = 30/100 * 8 = 24
Given, 40% of Ram's marks = 24.
=> Ram's marks = (24 * 100)/40 = 60
Also, 20% of Rahim's marks = 24
=> Rahim's marks = (24 * 100)/20 = 120
Average marks of Ram and Rahim = (60 + 120)/2 = 90.
Answer:D
Answer: (D) 90
Question: When Sourav increases his speed from 20 Km/hr to 25 Km/hr, he takes one hour less than the usual time to cover a certain distance. What is the distance usually covered by him?
(A) 125 Km
(B) 100 Km
(C) 80 Km
(D) 120 Km
(E) 60 km
Rationale: DETAILED SOLUTION
Here, the distance travelled by Sourav is constant in both the cases. So,
20 x t = 25 x (t-1) = D
=) 20t = 25t - 25
=) 5t = 25
=) t = 5 hrs So, Distance travelled = 20 X 5 = 100 Km.
CORRECT ANSWER B.
Answer: (B) 100 Km
Question: Stock / Number of shares
V ------------ 68
W ---------- 112
X ------------ 56
Y ------------ 94
Z ------------ 45
The table shows the number of shares of each of the 5 stocks owned by Mr Sami. If Mr. Sami was to sell 20 shares of Stock X and buy 19 shares of stock Y, what would be the increase in the range of the numbers of shares of the 5 stocks owned by Mr. Sami?
(A) 4
(B) 6
(C) 9
(D) 10
(E) 20
Rationale: Based on the original number of shares, the range would be: 112 - 45 = 67
However, the prompt tells us that two of the values in the table are going to change. After the changes, the values will be:
V 68
W 112
X 36
Y 113
Z 45
Now the range is 113 - 36 = 77
The INCREASE in the range requires us to compare thenewrange to theoldrange: 77 - 67 = 10
D
Answer: (D) 10
Question: 360 metres long yard, 31 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees
(A) 10
(B) 12
(C) 14
(D) 16
(E) 17
Rationale: 31 trees have 30 gaps between them,
Required distance (360/30) = 12
B
Answer: (B) 12
Question: The no. of girls in a class are seven times the no. of boys, which value cannever be the of total students?
(A) 2
(B) 5
(C) 8
(D) 9
(E) 10
Rationale: Let the boys are X, then girls are 7X, total = X+7X = 8X
So it should be multiple of 8, 30 is not a multiple of 8.
C
Answer: (C) 8
Question: Find the value of x from the below equation? : 3x^2+5x+2 = 0
(A) -1
(B) 1
(C) -2
(D) 2
(E) 3
Rationale: a = 3, b = 5, c = 2
x1,2 = (-5 ± √(52 - 4×3×2)) / (2×3) = (-5 ± √(25-24)) / 6 = (-5 ± 1) / 6
x1 = (-5 + 1)/6 = -4/6 = -2/3
x2 = (-5 - 1)/6 = -6/6 = -1
A
Answer: (A) -1
Question: A 360 m long train is running at a speed of 55 Km/hr. It crossed a platform of length 520 m in ?
(A) 57.6 sec
(B) 20.2 sec
(C) 31.8 sec
(D) 50.4 sec
(E) none of the above
Rationale: Speed = 55 Km/hr
(to convert km/hr in to M/s)
= 55 x 5/18 M/s
Distance = 360 m + 520 m ( If questions is about train crossing a post you need to consider only the length of Train, )
= 880 m
Time = Distance / Speed
= 880 x 18 / (5 x 55)
= 57.6 sec
Ans is :A
Answer: (A) 57.6 sec
Question: What is the value of: 2^6 + 2^9 ?
(A)  5(2^6)
(B)  3(2^6)
(C)  2^15
(D)  2^84
(E)  4^15
Rationale: 2^6 + 2^9 = 2^6 (1 + 2^2) = 2^6 (1 + 4) = 5 (2^6), Answer A.
Answer: (A)  5(2^6)
Question: Two brothers A and B leave point A and point B simultaneously and travel towards Point B and Point A on the same route at their respective constant speeds. They meet along the route and immediately proceed to their respective destinations in 32 minutes and 50 minutes respectively. How long will B take to cover the entire journey between Point B and point A?
(A) 65
(B) 70
(C) 75
(D) 90
(E) 80
Rationale: Let x per minute be the speed of A and y per minute be the speed of B.
After meeting at a point, A travels for 32 mins and B travels for 50 mins. So distance covered by each of them post point of crossing
A= 32x and B=50y
The distance covered by A and B before they cross each would be distance covered by B and A post crossing respectively.
Therefore distance covered by B before he meets A= 32x
Time taken by B cover 32x distance= 32x/y mins
Therefore total time taken by B= 32x/y + 50 mins ................. I
We need to find value of x in terms of y to arrive at final answer.
Total distance= 32x+50y
Combined speed of A and B= x+y
Therefore time taken before A and B meet en-route= (32x+50y)/(x+y)
Time taken by B reach destination after meeting A= 50 mins
Total travel time for B= [(32x+50y)/(x+y)]+50 mins ...................II
Equate I and II
32x/y+50= [(32x+50y)/(x+y)]+50
(32x+50y)/y=(82x+100y)/(x+y)
32x^2+50xy+32xy+50y^2=82xy+100y^2
32x^2+82xy-82xy+50y^2-100y^2=0
32x^2-50y^2=0
32x^2=50y^2
16x^2=25y^2
Taking square root.. (since x and y denote speed, square root can't be negative)
4x=5y
y=4x/5 ............ III
substitute in I
=32x/(4x/5) + 50
=32x*5/4x + 50
=40+50
=90 mins
D
Answer: (D) 90
Question: An enterprising businessman earns an income of Re 1 on the first day of his business. On every subsequent day, he earns an income which is just double of that made on the previous day. On the 20th day of business, he earns an income of:
(A) Rs 219
(B) Rs 220
(C) Rs 20²
(D) Rs 20
(E) Rs 30
Rationale: 2nd day he earns = 2 = 2(2 – 1)
3rd day he earns = 2(3 – 1)
On 20th day he earns 2(20 -1) = 219 rupees
ANSWER:A
Answer: (A) Rs 219
Question: In the reading room of a library, there are 23 reading spots. Each reading spot
consists of a round table with 9 chairs placed around it. There are some readers such
that in each occupied reading spot there are different numbers of readers. If in all there
are 36 readers, how many reading spots do not have even a single reader?
(A) 12
(B) 13
(C) 14
(D) 15
(E) 16
Rationale: 1+2+3+4+5+6+7+8 = 36
so, 8 spots are occupied by users
23-8 = 15
ANSWER:D
Answer: (D) 15
Question: A man's speed with the current is 20 kmph and speed of the current is 3 kmph. The Man's speed against the current will be
(A) 11 kmph
(B) 12 kmph
(C) 14 kmph
(D) 17 kmph
(E) 19 kmph
Rationale: Explanation:
If you solved this question yourself, then trust me you have a all very clear with the basics of this chapter.
If not then lets solve this together.
Speed with current is 20,
speed of the man + It is speed of the current
Speed in still water = 20 - 3 = 17
Now speed against the current will be
speed of the man - speed of the current
= 17 - 3 = 14 kmph
ANSWER IS C
Answer: (C) 14 kmph
Question: How many of the positive factors of 42 , 104 and how many common factors are there in numbers?
(A) 4
(B) 2
(C) 3
(D) 5
(E) 1
Rationale: factors of 42 - 1,2,3,6,7,14,21,42
factors of 104 - 1,2,4,8,13,26,52,104
Comparing both, we have two common factors of 40 and 104- 1,2,
Answer(B)
Answer: (B) 2
Question: Kim has 8 pairs of shoes; each pair is a different color. If Kim randomly selects 2 shoes without replacement from the 16 shoes, what is the probability that she will select 2 shoes of the same color?
(A) 2/5
(B) 1/5
(C) 1/9
(D) 1/10
(E) 1/15
Rationale: Total pairs = 16C2 = 120; Same Color Pairs= 8C1*1C1=8; Prob = 1/15
Ans E
Answer: (E) 1/15
Question: 4,8,16,32,....
(A) 64
(B) 60
(C) 61
(D) 62
(E) 63
Rationale: 2*2=4
4*2=8
8*2=16
16*2=32
32*2=64
ANSWER:A
Answer: (A) 64
Question: Evaluate permutation equation
59P3
(A) 195052
(B) 195053
(C) 195054
(D) 185054
(E) None of these
Rationale: Explanation:
nPr=n!/(n−r)!
59P3=59!/(56)!
=59∗58∗57∗56!/(56)!=195054
Option C
Answer: (C) 195054
Question: A mobile battery in 1 hour charges to 20 percent.How much time (in minute) will it require more to charge to 65 percent.
(A) 145
(B) 150
(C) 195
(D) 160
(E) 130
Rationale: 1 hr =20 percent.Thus 15 min=5 percent .Now to charge 65 percent 195 min.Answer:C
Answer: (C) 195
Question: Find the invalid no.from the following series 15 46 63 71 75 77 78
(A) 15
(B) 46
(C) 75
(D) 77
(E) 78
Rationale: In this question, if you start from the beginning, firstly the difference is 31, then the difference is 17, then the difference is 8. So there is no logic. If you start backwards,you can see that firstly, 1 is added, then 2 is added, then 4 is added, then 8,16 and 32 should have been added. So you have got the right clue. So 15 + 32 the first number should be 47 and afterwards, the series becomes + 16, + 8, + 4and so on.
B
Answer: (B) 46
Question: A train running at the speed of 50 km/hr crosses a pole in 18 seconds. Find the length of the train.
(A) 150
(B) 188
(C) 250
(D) 288
(E) 300
Rationale: Speed = 50*(5/18) m/sec = 125/9 m/sec
Length of Train (Distance) = Speed * Time
(125/9) * 18 = 250 meter
Answer: C
Answer: (C) 250
Question: Find the number of factors of 300 excluding 1 and itself.
(A) 18
(B) 17
(C) 16
(D) 14
(E) 12
Rationale: 300 = 4.75 = 4.25.3 = 22.52.31
Number of factors of 300 = (2 + 1)(2 + 1)(1 + 1) = 18.
There are 16 factors of 300 excluding 1 and itself.
ANSWER:C
Answer: (C) 16
Question: The average marks of a class of 35 students is 45 and that of another class of 55 students is 65. Find the average marks of all the students?
(A) 52.6
(B) 52.4
(C) 52.1
(D) 57
(E) 52.9
Rationale: Sum of the marks for the class of 35 students = 35 * 45 = 1575
Sum of the marks for the class of 55 students = 55 * 65 = 3575
Sum of the marks for the class of 90 students =
1575 + 3575 = 5150
Average marks of all the students = 5150/90 = 57.Answer: D
Answer: (D) 57
Question: The average of five results is 46 and that of the first four is 45. The fifth result is?
(A) 23
(B) 27
(C) 21
(D) 50
(E) 23
Rationale: 5 * 46 – 4 * 45
= 50
Answer: D
Answer: (D) 50
Question: Two hoses are pouring water into an empty pool. Hose 1 alone would fill up the pool in 6 hours. Hose 2 alone would fill up the pool in 9 hours. How long would it take for both hoses to fill up two-thirds of the pool?
(A) 5/12 hours
(B) 5/8 hours
(C) 8/5 hours
(D) 12/7 hours
(E) 12/5 hours
Rationale: Hose 1 would fill the pool alone in 6 hours
i.e. 1 Hour work of Hose 1 = 1/6
Hose 2 would fill the pool alone in 9 hours
i.e. 1 Hour work of Hose 2 = 1/9
i.e. 1 Hour work of Hose1 and Hose2 together = (1/6)+(1/9) = (5/18)
i.e. (5/18) work can be finished by Hose1 and Hose2 together in 1 hour
i.e. (2/3) work can be finished by Hose1 and Hose2 together in 1*(18/5)*(2/3) = 12/5 hour
Answer: Option E
Answer: (E) 12/5 hours
Question: The smallest ratio out of 1:1, 2:1, 1:3,4:1 and 3:1 is?
(A) 1:1
(B) 1:3
(C) 2:1
(D) 3:1
(E) 4:1
Rationale: 1/1=1
1/3=0.333
2/1=2
3/1=3
4/1=4
ANSWER:B
Answer: (B) 1:3
Question: The area of a square is 4489 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square.
(A) 5:28
(B) 5:19
(C) 5:12
(D) 5:13
(E) 43:134
Rationale: Let the length and the breadth of the rectangle be l cm and b cm respectively. Let the side of the square be a cm.
a2 = 4489
a = 67
L = 2a and b = a - 24
b : l = a - 24 : 2a = 43 : 134
Answer:E
Answer: (E) 43:134
Question: 5^2*2^2*5*2^4 =
(A) 3^5*2^5
(B) 2^9*3^4
(C) 2^4*3^9
(D) 5^8
(E) 6^10
Rationale: 5^2*2^2*5*2^4 =
A) 3^5*2^5
B) 2^9*3^4
C) 2^4*3^9
D) 5^8
E) 2^6*5^3
If the base is same, powers are added so that follows A) 3^5*2^5.
Hence the answer is E
Answer: (E) 6^10
Question: A can complete a project in 10 days and B can complete the same project in 30 days. If A and B start working on the project together and A quits 10 days before the project is completed, in how many days will the project be completed?
(A) 18 days
(B) 15 days
(C) 26.67 days
(D) 16 days
(E) 12 days
Rationale: Let X = the number of days taken to complete the project.
The amount of work done by A is (x-10) * (1/20).
The amount of work done by B is (x) * (1/30).
(1/10)*(x-10) + (1/30)*(x) = 1
(x/10) + (x/30) - 1) = 1
4x/30 = 2
x = 15
Therefore, the answer is B: 15.
Answer: (B) 15 days
Question: A and B go around a circular track of length 1500 m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point?
(A) 120 sec
(B) 165 sec
(C) 300 sec
(D) 167 sec
(E) 168 sec
Rationale: Time taken to meet for the first time at the starting point
= LCM { length of the track / speed of A , length of the track / speed of B}
= LCM { 1500/ (36 * 5/18) , 1500/ (54 * 5 /18) }
= LCM (150, 100)
=300sec.
Answer:C
Answer: (C) 300 sec
Question: In a country there are 2 hospitals for every 1000 citizens. If there are 50,000 citizens, how many hospitals are there in that country?
(A) 50
(B) 100
(C) 60
(D) 75
(E) 80
Rationale: 2/1000=x/50,000
x=100
Answer is B
Answer: (B) 100
Question: A student was asked to find the arithmetic mean of the numbers 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14 and x. He found the mean to be 12. What should be the number in place of x ?
(A) 2
(B) 7
(C) 8
(D) 9
(E) 3
Rationale: Explanation:
Clearly, we have (3 + 11 + 7 + 9 + 15 + 13 + 8 + 19 + 17 + 21 + 14 + x) / 12 = 12.
or 137 + x = 144 or x = 144 - 137 = 7.
Answer: B) 7
Answer: (B) 7
Question: A student has to obtain 35% of the total marks to pass. He got 100 marks and failed by 40 marks. The maximum marks are?
(A) 280
(B) 400
(C) 420
(D) 480
(E) 520
Rationale: Let the maximum marks be x
Then, 35% of x = 100+40
35x/100 = 140
35x= 140*100= 14000
x = 400
Answer is B
Answer: (B) 400
Question: A rectangular-shaped carpet that measures x feet by y feet is priced at $24. What is the cost of the carpet, in dollars per square yard? (1 square yard = 9 square feet)
(A) 180xy
(B) 216/(xy)
(C) 20xy
(D) 20xy/9
(E) xy/180
Rationale: The area of the carpet in feet is xy.
The area in square yards is xy / 9.
The price per square yard is 24 / (xy/9) = 216/(xy).
The answer is B.
Answer: (B) 216/(xy)
Question: What is the remainder when 3^86 is divided by 5 ?
(A) 1
(B) 2
(C) 4
(D) 0
(E) 3
Rationale: 3^0 = 1
3^1 = 3
3^2 = 9
3^3 = 27
3^4 = ...1
3^5 = ....3
3^6 = ......9
and so on.
86/4 = 21 (with a remainder 2) so the last number is a 9.
so when 3^86 is divided by 5 the remainder is 4, ANS = C
Answer: (C) 4
Question: ‘A’ completes a work in 12 days. ‘B’ completes the same work in 15 days. ‘A’ started working alone and after 3 days B joined him. How many days will they now take together to complete the remaining work?
(A) 5
(B) 8
(C) 6
(D) 4
(E) None of these
Rationale: Work done by ‘A’ in 3 days
= 1⁄12 × 3 = 1⁄4
∴ Remaining work = 1 - 1⁄4 = 3⁄4
Work done by A and B together = 12×15/27=20/3
∴ Remaining work done by A and B together in
= 3⁄4 × 20⁄3 = 5 days
Answer A
Answer: (A) 5
Question: The average of 10 numbers is 23. If each number is increased by 1, what will the new average be?
(A) 36
(B) 24
(C) 72
(D) 29
(E) 22
Rationale: Sum of the 10 numbers = 230
If each number is increased by 1, the total increase =
1 * 10 = 10
The new sum = 230 + 10 = 240 The new average = 240/10
= 24.
Answer:B
Answer: (B) 24
Question: Jaya purchase 13 jars in a store then she returned 5 jars to store .Now how many jars she had?
(A) A)5
(B) B)11
(C) C)19
(D) D)8
(E) E)4
Rationale: 13-5=8. Answer is D
Answer: (D) D)8
Question: A certain tax rate is $.62 per $100.00. What is the rate, expressed as a percent?
(A) 62%
(B) 6.2%
(C) 0.62%
(D) 0.062%
(E) 0.0062%
Rationale: Here in question it is asking $.82 is what percent of $ 100.Suppose $ .82 is x% of 100 means
100* (x/100) = .62
Hence x = .82%
So answer is C.
Answer: (C) 0.62%
Question: How many meters are there in 440 centimeters?
(A) 440 meters
(B) 3.2 meters
(C) 4.4 meters
(D) 4.5 meters
(E) 4 meter
Rationale: Solution:
1 meter = 100 centimeters
Just divide 440 by 100
440 Ã· 100 = 4.4, so there are 4.4 meters in 440 centimeters
Option C
Answer: (C) 4.4 meters
Question: You roll N (N > 1) number of M (M > 1) sided dice at once. What is the probability they will all land on the same number?
(A) N/(M^N)
(B) M/(N^M)
(C) 1/(M^(N-1))
(D) 1/(N^(M-1))
(E) 1/(M-1)^N
Rationale: The correct rolls are any M-ples: 11...1, 22...2, ..., MM...M. This is makes M possibilities. The N dice can roll M*M*...*M (M^N) number of ways. Thus the probability of landing on the same number is M/(M^N)
= 1/(M^(N-1)).
Answer: C.
Answer: (C) 1/(M^(N-1))