mathewhe/aqua_rat huggingface dataset:
Question: 2 friends X & Y walk from A to B at a distance of 39 miles at 3 miles/hr and 3.5 miles/hr respectively. Y reaches B, returns immediately and meets X at ‘C’ . find distance from A to C.
(A) 38 km
(B) 39 km
(C) 35 km
(D) 36 km
(E) 34 km
Rationale: Since the time of meeting will be same. Set the equation for time as equal.
---------------39---------------
A*...................C*...........*B
-----(39-x)-------|----x------
At C,
T(A)=T(B)
((39-x)/3)=((39+x)/3.5)
Solve for x. and subtract x from 39 to get the answer.
answer is 39-3=36km.
ANSWER:D
Answer: (D) 36 km
Question: Company KW is being sold, and both Company A and Company B were considering the purchase. The price of Company KW is 90% more than Company A has in assets, and this same price is also 100% more than Company B has in assets. If Companies A and B were to merge and combine their assets, the price of Company KW would be approximately what percent of these combined assets?
(A) 66%
(B) 75%
(C) 86%
(D) 97%
(E) 150%
Rationale: Let the price of Company A's assets be 100
Price of assets of KW is 90% more than company A's assets which is 190
Price of assets of KW is 100% more than company B's assets which means price of Company B's assets is half the price of KW = 95
A+B = 195
KW = 190
KW/(A+B)*100 = 190/195*100 = 97.43% or 97%D
Answer: (D) 97%
Question: Finch has s pairs of shoes, which is 1/6 as many as Guptil and twice as many as S.Smith. In terms of s, how many pairs of shoes do the three of them have combined?
(A) 5s
(B) 15/2*s
(C) 14s
(D) 3s
(E) 13/2*s
Rationale: == s +6s + s/2 ==> 7s + 1/2 s = 15/2*s
Ans .B
Answer: (B) 15/2*s
Question: What is the sum of all the multiples of 10 between 0 and 120?
(A) 500
(B) 620
(C) 450
(D) 340
(E) 780
Rationale: The multiples of 10 between 0 and 120 are 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110 and 120. If these are all added together, the result is 780.
Final Answer:
E
Answer: (E) 780
Question: If n=5p where p is a prime number greater than 1, how many different positive even divisors does n have, WITHOUT N VALUE?
(A) 1
(B) 2
(C) 3
(D) 45
(E) 5
Rationale: N = 5P and that P is a prime number greater than 1. Let's TEST P = 2; so N = 10
The question now asks how many DIFFERENT positive EVEN divisors does 10 have, including 10?
10:
1,10
5,2
How many of these divisors are EVEN? 2 …..1 even divisors.
ANSWER:A
Answer: (A) 1
Question: In a sports club with 35 members, 15 play badminton and 18 play tennis and 5 do not play either. How many members play both badminton and tennis?
(A) 3
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: 15+18=33
but where as total number is 35-5=30
therefore answer is 33-30=3
Hence Answer is A
Answer: (A) 3
Question: If 6th March, 2013 is Wednesday, what was the day of the week on 6th March, 2012?
(A) Sunday
(B) Saturday
(C) Tuesday
(D) Wednesday
(E) None of these
Rationale: Solution
The year 2012 is a leap year. So, it has 2 odd days.
But, Feb 2012 not included because we are calculating from March 2012 to March 2013. So it has 1 odd day only.
The day on 6th March, 2013 will be 1 day beyond the day on 6th March, 2012. Given that, 6th March, 2013 is Wednesday.
6th March, 2012 is Tuesday (1 day before to 6th March, 2013)
Answer C
Answer: (C) Tuesday
Question: In Winchard's company 60% of the employees earn less than $50,000 a year, 60% of the employees earn more than $40,000 a year, 11% of the employees earn $43,000 a year and 5% of the employees earn $49,000 a year. What is the median salary for the company?
(A) 43.0
(B) 45.5
(C) 46.0
(D) 49.0
(E) 50.0
Rationale: In Winchard's company 60% of the employees earn less than $50,000 a year, 50 and 51 employee will be each 43K. hence median = (43K+43k)/2=A
Answer: (A) 43.0
Question: Jason flips a coin three times. What is the probability E that the coin will land on the same side in all three tosses?
(A) 1/16
(B) 1/8
(C) 1/4
(D) 1/3
(E) 1/2
Rationale: Total outcome is 2^3=8
Favorable cases HHH or TTT
Therefore, probability E is 2/8 or 1/4.C
Answer: (C) 1/4
Question: Two numbers when divided by a divisor leave remainders of 218 and 342 respectively. The remainder obtained when the sum of the numbers is divided by the same divisor is 68. Find the divisor.
(A) 387
(B) 423
(C) 492
(D) 512
(E) 602
Rationale: Let x be the divisor.
N1 = xa + 218
N2 = xb + 342
N1 + N2 = x(a+b) + 560 = xc + 68
x(c-a-b) = 492 but we know that x > 342, thus (c-a-b) must equal 1.
The answer is C.
Answer: (C) 492
Question: Find the middle one when The sum of three consecutive even numbers is 36?
(A) 10
(B) 12
(C) 14
(D) 16
(E) 17
Rationale: 3 consecutive numbers can be a - 1, a, a + 1
So sum of numbers = 3a = 36.
Hence a = 12.
B
Answer: (B) 12
Question: If Packard reads at a constant rate of 4 pages every 5 minutes, how many seconds will it take him to read N pages?
(A) 75
(B) 2N
(C) 5/2*N
(D) 24N
(E) 150
Rationale: Packard would read 1 page in 5/4 min
Packard would read N page in (5/4)*N min i.e. (5/4)*N*60 Seconds = 75N Seconds.
Option A is the correct Answer.
Answer: (A) 75
Question: Four friends built a colony for themselves. They built their own houses at different distances from each other.
Chris lived 60 km away from Alex.
Darren lived 40 km away from Bill.
Chris lived 10 km nearer to Darren than he lived to Bill.
Can you find out how far was Darren's house from Alex?
(A) 55 km.
(B) 65 km.
(C) 75 km.
(D) 85 km.
(E) 95 km.
Rationale: Solution:
75km
Explanation:
Distance between Bill and Darren = 40 km
Distance between Bill and Chris + Distance between Chris and Darren = 40 km
Distance between Bill and Chris + (Distance between Bill and Chris - 10) = 40 km
2 * Distance between Bill and Chris = 50 km
Distance between Bill and Chris = 25
Distance between Chris and Darren = 15 km
Therefore, distance between Darren's house and Alex's house = 60 + 15 = 75 km.
Answer C
Answer: (C) 75 km.
Question: A 700-level question for the GMAT committed souls studying over the weekend.
If a and b are distinct integers and a^b=b^a, how many solutions does the ordered pair (a, b) have?
(A) None
(B) 1
(C) 2
(D) 4
(E) Infinite
Rationale: (2,4) and (4,2)
a=1 b=1 and a=2 b=2 also has the solution. But we need distinct. Now when we will increase a>4, b^a increase more rapidly than a^b.
ANSWER:B
Answer: (B) 1
Question: If a man crosses a 400 m long street in 5 minutes. What is his speed?
(A) 7 km/hr
(B) 7.1 km/hr
(C) 7.2 km/hr
(D) 4.8 km/hr
(E) 8.5 km/hr
Rationale: distance = 400 meter
time = 5 minutes = 5 x 60 seconds = 300 seconds
Speed = distance/time=400/300=1.33m/s=1.33×18/5 km/hr=4.8 km/hr
D
Answer: (D) 4.8 km/hr
Question: If x + y = 8 and y − 3x = 7, then what is the value of y-x?
(A) 1/7
(B) 3
(C) 15
(D) 15/2
(E) 60/7
Rationale: x+y=8 ...equation 1
-3x+y=7 ...equation 2
adding both the equations
-2x+2y=15=>y-x=15/2
correct answer option D
Answer: (D) 15/2
Question: The length and breadth of a rectangle is increased by 5% and 15% respectively. What is the increase in the area?
(A) 21.25
(B) 22.75
(C) 19.25
(D) 20.75
(E) 22.25
Rationale: 100*100 =10000
105*115 =12075
-----------
2075
10000------2075
100-----?=>20.75
Answer D
Answer: (D) 20.75
Question: The average of five numbers is 30. If one number is excluded, the average becomes 28. The excluded number is?
(A) 8
(B) 6
(C) 38
(D) 35
(E) 96
Rationale: Excluded number
= (30 * 5) - (28 * 4)
= 150 - 112 = 38
Answer:C
Answer: (C) 38
Question: If the price of a book is first decreased by 50% and then increased by 60%, then the net change in the price will be?
(A) 20% decrease
(B) 10% increase
(C) 10% decrease
(D) 15% increase
(E) 25% decrease
Rationale: Let the original price be $100
New final price = 160% of (50% of $100)
= 160/100 * 50/100 *100 = $80
Decrease is 20%
Answer is A
Answer: (A) 20% decrease
Question: Superman flied 200 miles in 1 hour 1 minute. What was the average speed of Superman?
(A) 180 miles / hour
(B) 170.3 miles / hour
(C) 196.72 miles / hour
(D) 160 miles / hour
(E) 150 miles / hour
Rationale: We first convert the time of 1 hours 1 minutes in minutes
1 hours 1 minutes = 1 * 60 + 1 = 61 minutes
Average speed S is given by distance / time. Hence
S = 200 miles / 61 minutes = 3.27 mile / minute
= 196.72 miles / hour
correct answer C
Answer: (C) 196.72 miles / hour
Question: Two circular blocks are placed one above the other. Block A at the bottom has a diameter of 24 cm. Block B at the top has a diameter of 16 cm. What fraction of Block A's surface is not covered by Block B?
(A) 5/6
(B) 2/3
(C) 2/9
(D) 18/20
(E) 4/5
Rationale: The questions asks us to find the surface which is not covered by the Block B i.e., area of the surface not covered.
Where as circumference is the length along the edge of the circle,
2*pi*r implies the length of the curve
pi*r^2 implies area enclosed by that curve..hence Area of the circle is considered for this problem
Area of the Block B=pi* r^2, where r=8
=>pi*64
Area of the Block A=pi*144
Surface not covered by the Block B=pi*144-pi*64=Pi*80
fraction of Block A surface is not covered by a Block B= Pi*80/total area of the Block A
=>Pi*80/Pi*144=2/9
Answer C
Answer: (C) 2/9
Question: 81,162,49,98,25,50,64
(A) 126
(B) 127
(C) 129
(D) 128
(E) 131
Rationale: 81*2=162
49*2=98
25*2=50
64*2=128
ANSWER:D
Answer: (D) 128
Question: Liam is pulled over for speeding just as he is arriving at work.He explains to the police officer that he could not afford to be late today, and has arrived at work only four minutes before he is to start. The officer explains that if Liam had driven 5mph slower for his whole commute, he would have arrived at work exactly on time. If Liam's commute is 40 miles long,how fast was he actually driving?(Assume that Liam drove at a constant speed for the duration of his commute.)
(A) 50 mph
(B) 45 mph
(C) 48 mph
(D) 52 mph
(E) 60 mph
Rationale: Let t be the number of hours he would need to reach office on time.
when he is driving with over speed, he reached office 4 min earlier! so the equation for this is s(t - 4/60) = 40
where s is the speed and 30 is the distance.
if he decreases his speed by 5mph then he would have reached his office on time: (s-5)t = 40
if you solve above equations, you will arrive at t = 2/3 hr and s = 60mph
therefore answer is E
Answer: (E) 60 mph
Question: Salesperson A's compensation for any week is $240 plus 6 percent of the portion of A's total sales above $1,000 for that week. Salesperson B's compensation for any week is 8 percent of B's total sales for that week. For what amount of total weekly sales would both salespeople earn the same compensation?
(A) $7000
(B) $9000
(C) $11,000
(D) $13,000
(E) $15,000
Rationale: 240+0.06(x-1000) = 0.08x
0.02x = 180
x = $9,000
The answer is B.
Answer: (B) $9000
Question: A train passes a station platform in 21 seconds and a man standing on the platform in 15 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
(A) 299
(B) 277
(C) 90
(D) 88
(E) 112
Rationale: Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 15) m = 225 m.
Let the length of the platform be x meters.
Then, x + 225 / 21 = 15
x + 225 = 315
x = 90 m.
Answer:C
Answer: (C) 90
Question: Evaluate combination
11C3
(A) 10000
(B) 1000
(C) 165
(D) 1
(E) 0
Rationale: Explanation:
nCn=1
nCr=n!/r!(n-r)!
11C3=11!/3!(11-3)!=165
Option C
Answer: (C) 165
Question: The present ratio of students to teachers at a certain school is 40 to 1. If the student enrollment were to increase by 50 students and the number of teachers were to increase by 5, the ratio of students to teachers would then be 25 to 1. What is the present number of teachers?
(A) 5
(B) 8
(C) 10
(D) 12
(E) 15
Rationale: We are given that the ratio of students to teacher is 40 to 1. We can rewrite this using variable multipliers.
students : teachers = 40x : x
We are next given that student enrollment increases by 50 and the number of teachers increases by 5. With this change the new ratio becomes 25 to 1. We can put all this into an equation:
Students/Teachers  25/1 = (40x + 50)/(x + 5)
If we cross multiply we have:
25(x + 5) = 40x + 50
25x + 125 = 40x + 50
5 = x
Since x is the present number of teachers, currently there are 5 teachers.
Answer A.
Answer: (A) 5
Question: There are 15 points in a given plane, no three of which are on the same line. If one of the points is represented as 'L', then how many triangles can be determined with the 15 points that contain the point L?
(A) 91
(B) 105
(C) 182
(D) 210
(E) 455
Rationale: Fist point is L which is fixed so can be selected in 1 way
Second point can be selected in 14 ways
Third point can be selected in 13 ways
so total ways = 1x14x13 = 182
but answer is 91 which is 182/2=C
Answer: (C) 182
Question: Choose the number pair/group which is different from others?
(A) 8 : 39
(B) 8 : 38
(C) 8 : 33
(D) 8 : 32
(E) 8 : 31
Rationale: Explanation:
In all other pairs, 2nd number = (1st number × 3) + 1.
Answer: C) 8 : 33
Answer: (C) 8 : 33
Question: A and B together can do a piece of work in 8 days. If A alone can do the same work in 12 days, then B alone can do the same work in?
(A) 22 days
(B) 77 days
(C) 24 days
(D) 17 days
(E) 18 days
Rationale: B = 1/8 – 1/2 = 1/24 => 24 days
Answer: C
Answer: (C) 24 days
Question: Which of the following CANNOT be weighed using a balance scale and these unit weights: 1, 4, 7, and 10
(A) 13
(B) 15
(C) 17
(D) 20
(E) 21
Rationale: A. 18 (can be weighed by keeping weights of 10,1 and 7 )
B. 15 (can be weighed by keeping weights of 10,4 and 1 kg)
C. 17 (can be weighed by keeping weights of 10 and 7 kg)
D. 20(cannot be weighed)
E. 21 (can be weighed by keeping weights of 10, 7 and 4 kg)
D
Answer: (D) 20
Question: If pqr = 1 , rqt = 0 , and tpr = 0, which of the following must be zero?
(A) P
(B) Q
(C) R
(D) S
(E) T
Rationale: pqr = 1 which means neither p / q/ r is 0
rq x t = 0 , we know r and q are not 0 from above hence t must be 0.
similarly p and r are not 0
t x p x r = 0, p and r are not 0 hence t =0.
option E
Answer: (E) T
Question: If q is an integer, what is the greatest possible value for q that would still make the following statement true: 11*10^q < 1/10 ?
(A)  –4
(B)  –3
(C)  –2
(D)  –1
(E)  0
Rationale: Just putting values, the LHS becomes
q=0 --> 11
q=-1 --> 11/10
q=-2 --> 11/100
q=-3 --> 11/1000
Anything lower will be smaller than 11/1000. q=-2, equality does not hold but it does for q=-3.
Answer is B.
Answer: (B)  –3
Question: Three 6 faced dice are thrown together. The probability that no two dice show the same number on them is
(A) 5/7
(B) 5/9
(C) 5/4
(D) 5/1
(E) 5/3
Rationale: No two dice show same number would mean all the three faces should show different numbers. The first can fall in any one of the six ways. The second die can show a different number in five ways. The third should show a number that is different from the first and second. This can happen in four ways.
Thus 6 * 5 * 4 = 120 favourable cases.
The total cases are 6 * 6 * 6 = 216.
The probability = 120/216 = 5/9.
Answer:B
Answer: (B) 5/9
Question: In a certain year, the population of a certain town was 9000. If in the next year the population of males increases by 3% and that of the females by 9% and the total population increases to 9600, then what was the ratio of population of males and females in that given year?
(A) 7 : 11
(B) 5 : 4
(C) 2 : 3
(D) Data inadequate
(E) None of these
Rationale: Let the population of males = x; then the population of females = 9000 – x
Now, 3% of x + 9% of (9000 – x)
= (9600 – 9000 ) = 600
or 0.03x + 720 – 0.09x = 600
or 720 – 600 = 0.09x – 0.03x
or, 120 = 0.06x
x = 3500
Reqd ratio of population of males and females
3500/9000−3500=3500/5500=7:11
Answer A
Answer: (A) 7 : 11
Question: Find the greatest number that will divide 54, 87 and 172 so as to leave the same remainder in each case
(A) 13
(B) 3
(C) 15
(D) 1
(E) 2
Rationale: Explanation:
Required number = (87-54),(172-87),(172-54)
= H.C.F of 33,85 and 118 is 1
Answer: Option D
Answer: (D) 1
Question: A dishonest milkman wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing Rs.42 per litre so as to make a profit of 20% on cost when he sells the resulting milk and water mixture for Rs.48 In what ratio should he mix the water and milk?
(A) 1:20
(B) 1:10
(C) 1:8
(D) 1:4
(E) 6:11
Rationale: water = w (liter)
Milk = m (liter)
==> Cost = Price x Quantity = 0.42m
==> Revenue = Price x Quantity = 0.48(m + w)
==> Profit =0.48(m+w) - 0.42m = 0.2*(0.42m)[20% of cost]
==> 0.48m + 0.48w - 0.42m = 0.084m
==> 0.024m = 0.48w
==> m/w = 0.48/0.024 = 20
--OR--
w/m = 1/20
A is correct.
Answer: (A) 1:20
Question: If the average marks of three batches of 45, 68 and 55 students respectively is 50, 55, 60, then the average marks of all the students is
(A) 55.29
(B) 54.68
(C) 54.6
(D) 54.58
(E) None of these
Rationale: Explanation:
(45Ã—50)+(68Ã—55)+(55Ã—60) / 45+68+55
9290 / 168=55.29
Option A
Answer: (A) 55.29
Question: The average of first five multiples of 3 is :
(A) 3
(B) 9
(C) 12
(D) 15
(E) 17
Rationale: Solution
Average = 3(1+2+3+4+5)/5 =45/5 =9 Answer B
Answer: (B) 9
Question: A bus takes 6 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2 th of the previous time?
(A) 60 Kmph
(B) 72 Kmph
(C) 80 Kmph
(D) 84 Kmph
(E) 86 Kmph
Rationale: Time = 6
Distance = 540
3/2 of 6 hours = 6 * 3/2 = 9 Hours
Required speed = 540/9 = 60 Kmph
A
Answer: (A) 60 Kmph
Question: Evaluate 50!/47!
(A) 102500
(B) 112584
(C) 117600
(D) 118450
(E) 128450
Rationale: Evaluate 50!/47! = 50*49*48* (47!)/47!
= 50*49*48
= 117600
ANSWER:C
Answer: (C) 117600
Question: In the next Worldcup of cricket there will be 12 teams, divided equally in 2groups. Teams of eachgroup will play a match against each other. From each group 3 top teams will qualify for the next round. In this round each team will play against each others once. 4top teams of this round will qualify for the semifinal round, where they play the best of 3matches. The Minimum number of matches in the next World cup will be
(A) 34
(B) 36
(C) 53
(D) 59
(E) 61
Rationale: The number of matches in first round,
= 6C2 +6C2;
Number of matches in next round,
= 6C2;
Number of matches in semifinals,
= 4C2;
Total number of matches,
= 6C2 +6C2+6C2+4C2+2.
= 53.
C
Answer: (C) 53
Question: In how many ways can 5 men & 4 women can be made from a gang of 7 men & 8 women ?
(A) 91
(B) 98
(C) 97
(D) 86
(E) 90
Rationale: Explanation:
7C5 * 8C4 = 91
A
Answer: (A) 91
Question: A group of 55 adults and 70 children go for trekking. If there is meal for either 70 adults or 90 children and if 35 adults have their meal, find the total number of children that can be catered with the remaining food.
(A) 33
(B) 54
(C) 18
(D) 45
(E) 01
Rationale: Explanation:
As there is meal for 70 adults and 35 have their meal, the meal left can be catered to 35 adults.
Now, 70 adults = 90 children
7 adults = 9 children
Therefore, 35 adults = 45 children
Hence, the meal can be catered to 45 children.
ANSWER: D
Answer: (D) 45
Question: On his first 5 tests, David received an average score of N points. If on his sixth test, he exceeds his previous average score by 36 points, what is his average score for his first 6 tests?
(A) N +12
(B) N +6
(C) N +3
(D) N +8
(E) N +18
Rationale: Total of 1st 5 tests= 5N
6th test score = N + 36
Total of all 6 tests = 6N + 36
Average = N +6
Answer : B
Answer: (B) N +6
Question: What number has a 5:1 ratio to the number 10?
(A) 11
(B) 50
(C) 99
(D) 77
(E) 21
Rationale: 5:1 = x: 10
x = 50
Answer: B
Answer: (B) 50
Question: Each side of a rectangular field diminished by 40%. By how much per cent is the area of the field diminished?
(A) 32
(B) 64
(C) 25
(D) 16
(E) None
Rationale: Solution: Let the Original length of the rectangle be 20 unit and breadth be 10 unit. Then
Original Area = length *breadth = 20*10 = 200 Square unit.
40% decrease in each side, then
Length = (20 - 40% of 20) = 12 unit.
Breadth = (10 - 40% of 10) = 6 unit.
Now, Area = 12 *6 = 72 Square unit.
Decrease in area = 200 - 72 = 128 square unit.
% Decrease in Area = (128/200)*100 = 64%
Mind Calculation Method:
Let the original area be 100 square unit.
100 ===40%↓(decrease in length)===> 60 ===40%↓===(decrease in breadth)===> 36.
Diminished in area = 100-36 = 64%
Answer: Option B
Answer: (B) 64
Question: A certain club has 10 members, including Jarry. One of the 10 members is chosen at random to be the president, one of the remaining 9 members is to be chosen at random to be the secretary, and one of the remaining 8 members is to be chosen at random to be the treasurer. What is the probability that Jarry will be either the member chose to be secretary or the member chose to be treasurer?
(A) 1/720
(B) 1/80
(C) 1/10
(D) 1/9
(E) 1/5
Rationale: In order to become a secretary the person cannot be chosen as a president. This can be done in 9/10 ways. Then to become a secretary this person's probability is 1/9
Probability to become a secretary = (9/10 * 1/9) = 1/10
Similar concept for treasurer. Probability of not president = 9/10, Probability of not secretary = 8/9, probability of treasurer 1/8
probability to become a treasurer = (9/10 * 8/9 * 1/8) = 1/10
Since, the problem is saying Jarry secretary OR Treasurer it is addition: 1/10 + 1/10 = 1/5=E
Answer: (E) 1/5
Question: In how many ways can be 8 boys and 8 girls sit around circular table so that no two boys sit next to each other?
(A) (5!)^2
(B) (6!)^2
(C) 7!8!
(D) 11!
(E) (5!)^2*6!
Rationale: first fix one boy and place other 7 in alt seats so total ways is 7!
now place each girl between a pair of boys... total ways of seating arrangement of girls 8!
total is 7!*8!
ANS C
Answer: (C) 7!8!
Question: Out of first 35 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ?
(A) 17/35
(B) 7/35
(C) 37/70
(D) 27/35
(E) 27/70
Rationale: n(S) = 35
n(Even no) = 17 = n(E)
n(Prime no) = 11 = n(P)
P(EᴜP)
= 17/35 + 11/35 - 1/35
= 27/35
Answer:D
Answer: (D) 27/35
Question: A small pool filled only with water will require an additional 600 gallons of water in order to be filled to 80% of its capacity. If pumping in these additional 600 gallons of water will increase the amount of water in the pool by 30%, what is the total capacity of the pool in gallons?
(A) 1000
(B) 1250
(C) 1300
(D) 1600
(E) 2000
Rationale: Since pumping in additional 600 gallons of water will increase the amount of water in the pool by 30%, then initially the pool is filled with 1,000 gallons of water.
So, we have that 1,000 + 600 = 0.8*{total} --> {total} = 2,000.
Answer: E.
Answer: (E) 2000
Question: Chris mixed 3 pounds of raisins with 4 pounds of nuts. If a pound of nuts costs 2 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture?
(A)  1/7
(B)  1/5
(C)  1/4
(D)  1/3
(E)  3/11
Rationale: 1 lbs of raisin = $1
3 lbs of raisin = $3
1 lbs of nuts = $2
4 lbs of nuts = $8
Total value of mixture = 8+3 = 11
Fraction of the value of raisin = 3/11
Ans:E
Answer: (E)  3/11
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 20% profit on the first article and 20% loss on second article. Find the net profit or loss percent?
(A) 200
(B) 768
(C) 276
(D) 280
(E) 279
Rationale: Profit on first article = 20% of 1000 = 200.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer: A
Answer: (A) 200
Question: The cost of 10 kg of mangos is equal to the cost of 24 kg of rice. The cost of 6 kg of flour equals the cost of 2 kg of rice. The cost of each kg of flour is $24. Find the total cost of 4 kg of mangos, 3 kg of rice and 5 kg of flour?
(A) 347.4
(B) 987.4
(C) 877.2
(D) 1027.2
(E) 1667.2
Rationale: Let the costs of each kg of mangos and each kg of rice be $a and $r respectively.
10a = 24r and 6 * 24 = 2r
a = 12/5 r and r = 72
a = 144
Required total cost = 4 * 144 + 3 * 72 + 5 * 24
= 691.2 + 216 + 120 = $1027.20
D
Answer: (D) 1027.2
Question: Three partners A,B and C invest Rs.18000, Rs.22500 and Rs.27000 respectively in a business. If total profit is Rs.12000 then A's share is (in Rs.)
(A) 10000
(B) 6500
(C) 5000
(D) 3200
(E) 1500
Rationale: 18000:22500:27000
4:5:6
A's share=12000*4/15=3200
ANSWER:D
Answer: (D) 3200