mathewhe/aqua_rat huggingface dataset:
Question: In how many different ways can pennies (1 cent), nickels (5 cents), dimes (10 cents), and quarters (25 cents) be combined for a total of $1.10 (110 cents), if at least one of each type of coin must be included?
(A) 36
(B) 51
(C) 70
(D) 87
(E) 101
Rationale: I. Case I = Four Quarters = this is impossible, because if we already have a dollar in quarters, then we either have to have one dime or nickels & pennies. We can't have all four coins represented if we have four quarters.
II. Case II = Three Quarters (75 cents)
This allows for two or one dime. Three dimes would bring us up to $1.05, and we wouldn't have room for both pennies & nickels.
Subcase 1 = 3Q, 2 D (95 cents)
Here, we could have have
1) two nickles
2) one nickle
(Notice that once the number of Q & D & N are determined, the number of pennies is fixed and doesn't have to be considered.
Subcase 2 = 3Q, 1 D (85 cents)
Here we could have
3) 4 nickles
4) 3 nickles
5) 2 nickles
6) 1 nickle
Case II allows for a total of six cases.
III. Case III = Two Quarters (50 cents)
This allows for 1-5 dimes.
Subcase 1 = 2Q, 5 D = we could have 1 nickle (1 case)
Subcase 2 = 2Q, 4 D = we could have 1-3 nickles (3 cases)
Subcase 3 = 2Q, 3 D = we could have 1-5 nickles (5 cases)
Subcase 4 = 2Q, 2 D = we could have 1-7 nickles (7 cases)
Subcase 5 = 2Q, 1 D = we could have 1-9 nickles (9 cases)
Case III allows for a total of 25 cases
IV. Case IV = One Quarter (25 cents)
This allows for 1-7 dimes
Subcase 1 = 1 Q, 7D = we could have 1-2 nickles (2 cases)
Subcase 2 = 1 Q, 6D = we could have 1-4 nickles (4 cases)
Subcase 3 = 1 Q, 5D = we could have 1-6 nickles (6 cases)
Subcase 4 = 1 Q, 4D = we could have 1-8 nickles (8 cases)
Subcase 5 = 1 Q, 3D = we could have 1-10 nickles (10 cases)
Subcase 6 = 1 Q, 2D = we could have 1-12 nickles (12 cases)
Subcase 7 = 1 Q, 1D = we could have 1-14 nickles (14 cases)
Case IV allows for a total of 56 cases.
There's no other case, because we have to have at least one quarter. The total over the cases equals
Total = 6 + 25 + 56 = 87
ANSWER:D
Answer: (D) 87
Question: What comes next?
120, 60, 40, 30, 24, ?
(A) 10
(B) 20
(C) 25
(D) 28
(E) 30
Rationale: Factors of 120 are arranging in descending order.
So, next would be 20
Final series is like : 120, 60, 40, 30, 24, 20
ANSWER:B
Answer: (B) 20
Question: In a friendship gang Andrew has 8 gang, in how many ways can he invite one or more of the gang to his house?
(A) 230
(B) 255
(C) 259
(D) 265
(E) 270
Rationale: Andrew can select one or more than one of his 8 gang.
=> Required number of ways = 28 – 1= 255.
B
Answer: (B) 255
Question: 2598 Successive discounts of 20% and 15% are equal to a single discount of
(A) 30%
(B) 32%
(C) 34%
(D) 35%
(E) 36%
Rationale: Successive discounts of 20% and 15% are equal to a single discount of 32 %.
As final value after discount is 0.8*0.85 = 0.68 of original value.
so discount is 0.32 of original value. means 32%.
ANSWER:B
Answer: (B) 32%
Question: The duplicate ratio of 4:5 is?
(A) 1:2
(B) 1:4
(C) 1:8
(D) 1:18
(E) 16:25
Rationale: 4^2: 5^2 = 16:25
ANSWER:E
Answer: (E) 16:25
Question: Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Child A has to sit next to both BG, with these two children immediately adjacent to here on either side. The other four children can sit in any order in any of the remaining seats. How many possible configurations R are there for the children?
(A) 240
(B) 480
(C) 720
(D) 1440
(E) 3600
Rationale: MAGOOSHOFFICIAL SOLUTION:
First, we will consider the restricted elements — children ABG have to be in three seats in a row. How many “three in a row” seats are there in a row of seven seats?
X X X _ _ _ _
_ X X X _ _ _
_ _ X X X _ _
_ _ _ X X X _
_ _ _ _ X X X
There are five different “three in a row” locations for these three children. Now, for any given triplet of seats, we know A has to be in the middle, so the children could be seated B-A-G or G-A-B — just those two orders. This means the total number of configurations for these three children is 5*2 = 10.
Now, consider the non-restricted elements, the other four. Once ABG are seated, the remaining four children can be seated in any order among the remaining four seats — that’s a permutation of the 4 items —- 4P4 = 4! = 24. For any single configuration of ABG, there are 24 ways that the other children could be seated in the remaining seats.
Finally, we’ll combine with the Fundamental Counting Principle. We have 10 ways for the first three, and 24 ways for the remaining four. That’s a total number of configurations R of 24*10 = 240.
Answer = A
Answer: (A) 240
Question: Length of a rectangular plot is 20 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
(A) 46 m
(B) 60 m
(C) 58 m
(D) 78 m
(E) 80 m
Rationale: Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m
B
Answer: (B) 60 m
Question: When running a mile during a recent track meet, Nuria was initially credited with a final time of 4 minutes, 44 seconds. Shortly after her run, officials realized that the timing mechanism malfunctioned. The stopwatch did not begin timing her until 11/25 of a minute after she began to run. If the time was otherwise correct, how long did it actually take Nuria to run the mile?
(A) 5 minutes, 17.6 seconds
(B) 5 minutes, 21.8 seconds
(C) 5 minutes, 43.56 seconds
(D) 5 minutes, 10.4 seconds
(E) 5 minutes, 44.44 seconds
Rationale: One approach:
The watch starts to work after Nuria began his running. It means the time should be greater than credited 4 minutes, 44 seconds. The only number is 5 minutes, 10.4 seconds.
Another approach:
11/25 close to 30 second when added to the 4 minutes, 44 seconds, it means it passes 5 minute.
Answer: D
Answer: (D) 5 minutes, 10.4 seconds
Question: What number has a 3:4 ratio to the number 400?
(A) 130
(B) 100
(C) 200
(D) 300
(E) 120
Rationale: 3:4 = x: 200
4x = 3*400
x=300
ANSWER:D
Answer: (D) 300
Question: My brother is 4 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 5 years of age of when my brother was born, then, what was the age of my father and mother respectively when my brother was born?
(A) 32 yrs, 23 yrs
(B) 32 yrs, 29 yrs
(C) 35 yrs, 29 yrs
(D) 35 yrs, 22 yrs
(E) none
Rationale: Sol.
Clearly, my brother was born 5 years before I was born and 4 years after my sister was born.
So, father's age when brother was born = (28 + 4) = 32 years.
mother's age when was born = (26 - 4) years = 22 years.
Answer D
Answer: (D) 35 yrs, 22 yrs
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 36 hours respectively. The ratio of their speeds is?
(A) 4:5
(B) 4:3
(C) 4:4
(D) 4:9
(E) 6:3
Rationale: Let us name the trains A and B.
Then, (A's speed) : (B's speed)
= √b : √a = √36 : √9 = 6:3
Answer:E
Answer: (E) 6:3
Question: AMOUNT OF BACTERIA PRESENT
Time Amount
1:00 P.M. 12.0 grams
4:00 P.M. x grams
7:00 P.M. 16.4 grams
Data for a certain biology experiment are given in the table above. If the amount of bacteria present increased by the same fraction during each of the two 3-hour periods shown, how many grams of bacteria were present at 4:00 P.M.?
(A) 12.0
(B) 14.0
(C) 14.2
(D) 12.3
(E) 14.4
Rationale: The question says that bacteria increased by same fraction, not by same amount in 2 intervals of 3 hours.
Let X represent the amount of bacteria present at 4:00 PM. Since the fractional increase must remain constant from 1 to 4pm as it is from 4pm to 7pm:
Fractional increase from 1 PM to 4 PM = X / 12.0
Fractional increase from 4 PM to 7 PM = 16.4 / X
X \ 12 = 16.4 \ X
X^2 = 16.4 * 12
X = 14
answer : B
Answer: (B) 14.0
Question: The length of a rectangle is halved while its width is also halved. What is the % change in area?
(A) 25%
(B) 30%
(C) 50%
(D) 65%
(E) 75%
Rationale: The original area is L*W
The new area is 0.5L*0.5W = 0.25*L*W = L*W - 0.75*L*W
The area decreased by 75%.
The answer is E.
Answer: (E) 75%
Question: In a rare coin collection, all coins are either pure gold or pure silver, and there is initially one gold coin for every three silver coins. With the addition of 10 more gold coins to the collection, the ratio of gold coins to silver coins is 1 to 2. Based on this information, how many total coins are there now in this collection (after the acquisition)?
(A) 40
(B) 50
(C) 60
(D) 80
(E) 90
Rationale: Let's call g = # of gold coins and s = # of silver coins
Initially 3g = s and after the acquisition 2(g+10) = s
Let's solve the simultaneous equations by subtracting the second expression form the first expression: 3g-2g+20 = 0, yields g = 20.
After the acquisition we have 30 gold coins and double that in silver coins (60). A total of 90 coins.
ANSWER:E
Answer: (E) 90
Question: Two trains travelling in the same direction at 50.8 and 14.8 kmph completely pass off another in 45 sec.. If the length of the first train is 112 m, what is the length of the second train?
(A) 338 m
(B) 287 m
(C) 450 m
(D) 383 m
(E) 833 m
Rationale: RS = 50.8 â€“ 14.8= 36* 5/18 =10 mps
T = 45 sec
D = 10* 45= 450 m
112
--------
338 m
Answer: A
Answer: (A) 338 m
Question: A survey of n people in the town of Eros found that 50% of them preferred Brand A. Another survey of 150 people in the town of Angie found that 60% preferred Brand A. In total, 55% of all the people surveyed together preferred Brand A. What is the total number of people surveyed?
(A) 50
(B) 100
(C) 150
(D) 300
(E) 250
Rationale: It is simply a weighted average question. Since the given average of 50% and 60% is 55% (right in the middle), it means the number of people surveyed in Eros (n) is same as the number of people surveyed in Angie.
So n = 150
Total = 150 + 150 = 300
Answer (D)
Answer: (D) 300
Question: What is the are of an equilateral triangle of side 16 cm?
(A) 63√6 cm2
(B) 64√4 cm2
(C) 64√3 cm2
(D) 62√3 cm2
(E) 14√3 cm2
Rationale: Area of an equilateral triangle
= √3/4 S2
If S = 16, Area of triangle
= √3/4 * 16 * 16
= 64√3 cm2;
Answer:D
Answer: (D) 62√3 cm2
Question: The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
(A) 288
(B) 277
(C) 208
(D) 750
(E) 287
Rationale: Speed = [90 * 5/18] m/sec = 25 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 25 è x = 25 * 60 / 2 = 750
Answer:D
Answer: (D) 750
Question: A train speeds past a pole in 15 seconds and speeds past a platform 100 meters long in 25 seconds. Its length in meters is :
(A) 60m
(B) 70m
(C) 100m
(D) 120m
(E) 150m
Rationale: Let the length of the train be X metres and its speed be Y metres/sec.
Then X/Y=15
Y= X/15
X+100/25
Now,(x+100) /25
=X/15
X=150m
ANSWER : E
Answer: (E) 150m
Question: If the sides of a cube are in the ratio 4:3. What is the ratio of their diagonals?
(A) 4:3
(B) 4:0
(C) 3:3
(D) 4:6
(E) 4:7
Rationale: a1:a2 = 4:3
d1:d2 = 4:3
Answer: A
Answer: (A) 4:3
Question: A family consists of grandparents, parents and three grand children. The average age of the grandparents is 67 years, that of the parents is 40 years and that of the grandchildren is 6 years. What is the average age of the family?
(A) 28 4â„7 years
(B) 31 5â„7 years
(C) 33 1â„7 years
(D) 27 1â„2 years
(E) None of these
Rationale: Required average = (67Ã—2+40Ã—2+6Ã—3/2+2+3)
=232/7
= 33 1â„7 years
Answer C
Answer: (C) 33 1â„7 years
Question: 80% of the population of a village is 64000. The total population of the village is?
(A) 26799
(B) 24000
(C) 80000
(D) 29973
(E) 12312
Rationale: X * (80/100) = 64000
X = 800 * 100
X = 80000
Answer: C
Answer: (C) 80000
Question: In the xy-plane, a line has slope 5 and x-intercept 3. What is the y-intercept of the line?
(A) -15
(B) -3
(C) 0
(D) 3
(E) 9
Rationale: Let the line be represented by a general equation y=mx+b, where m = slope (5) and b=y intercept. We are also given the value of x-intercept 3.
Theory : y intercept represents the point on the line where the x=0, and x intercept represents the point on the line where the y=0.
Putting these values in the equation : 0 = 5*3 + b => b = -15. Hence A.
Answer: (A) -15
Question: The greatest number by which the product of four consecutive multiples of 3 is always divisible is
(A) 54
(B) 76
(C) 152
(D) 162
(E) None of these
Rationale: Solution
Required number	= Product of first three multiplies of 3
= (3 Ã— 6 Ã— 9x12)= 1944.
Answer E
Answer: (E) None of these
Question: What is the greatest prime factor of 1+2+3+。。。+60?
(A) 59
(B) 61
(C) 31
(D) 37
(E) 41
Rationale: find the sum from direct formula = n(n+1)/2 = 60(60+1)/2 = 30*61...
61 is a PRIME number, so ans is 61..
B is the answer
Answer: (B) 61
Question: Three dice are rolled. The number of possible outcomes in which at least one dice shows 5 is
(A) 215
(B) 36
(C) 125
(D) 91
(E) None of these
Rationale: Required number of possible outcomes
= Total number of possible outcomes – Number of possible outcomes in which 5 does not appear on any dice. (hence 5 possibilities in each throw)
= 6(3) – 5(3) = 216 – 125 = 91
Answer D
Answer: (D) 91
Question: S is the set of all fractions defined by the formula n/(n + 1), where n is a positive integer less than 20. What is the product V of all the fractions that are in S?
(A) 1) 1/20
(B) 2) 1/21
(C) 3) 1/2
(D) 4) 19/40
(E) 5) 19/20
Rationale: 1/2 * 2/3 * 3/4 * ... 19/20
= 1/20
Answer - A
Answer: (A) 1) 1/20
Question: A trader has 50 kg of pulses, part of which he sells at 14% profit and rest at 6% loss. On the whole his loss is 4%. How much quantity is sold at 14% profit and that at 6% loss?
(A) 5 kg, 45 kg
(B) 15 kg, 35 kg
(C) 10kg, 40 kg
(D) None of these
(E) Cannot be determined
Rationale: Solution:
ratio of quantity sold at 14% profit and 6% loss,
= 2:18 = 1:9
Hence, pulses sold at 14% profit,
= (50*1)/10 = 5 kg
At 6% Wheat sold at loss = 45 kg.
Answer: Option A
Answer: (A) 5 kg, 45 kg
Question: A,B and C can do a piece of work in 6,8 and 12 days respectively. In how many days would all of them complete the same job together?
(A) 5 2/3 days.
(B) 3 2/3 days.
(C) 2 2/3 days.
(D) 4 2/3 days.
(E) 1 2/3 days.
Rationale: Explanation:
A,B and C can do the work in 6,8 and 12 days respectively. Therefore,
part done by A in 1 day =1/6
part done by B in 1 day = 1/8
part done by C in 1 day = 1/12
part done by A,B and C in 1 day = 1/6+1/8+1/12
=9/24
Net job can be done by A,B,C together in 1 day =24/9 =2 2/3 days.
Answer: Option C
Answer: (C) 2 2/3 days.
Question: A football team plays games only against the other five teams in its league and always in the following order: Smith, Jones, Glen, Fader, and Gary . If the team’s final game of the season is against Fader, which of the following could be the number of games in the team’s schedule?
(A) 18
(B) 52
(C) 24
(D) 72
(E) 81
Rationale: IMO 'C' is the answer.
Matches will be in multiples of 5x+4. The answer that satisfies this condition is C
Answer: (C) 24
Question: If a monkey can climb 6 meter & slip down 3 meter in alternate minutes, than how much time can be taken by the monkey to climb up to a height of 60 meter.
(A) 36 min
(B) 37 min
(C) 38 min
(D) 39 min
(E) 32 min
Rationale: In 1st min it climb 6m and in 2nd min it slips 3m,
so it final displacement is 3m in 2min.
now for 51m it has taken 34 min.
in 35 min it goes to 57m.
in 36 min come down to 54 m.
in 37 min it goes to 60
ANSWER:B
Answer: (B) 37 min
Question: Kiran travels from A to B by car and returns from B to A by cycle in 7 hours. If he travels both ways by car he saves 3 hours. What is the time taken to cover both ways by cycle?
(A) 10 hours
(B) 17 hours
(C) 19 hours
(D) 16 hours
(E) 27 hours
Rationale: Let the time taken to cover from A to B in car and cycle be x hours and y hours respectively.
x + y = 7 --- (1) ; 2x = 4 --- (2)
solving both the equations, we get y = 5
So, time taken to cover both ways by cycle = 2y hours = 10 hours.
Answer: A
Answer: (A) 10 hours
Question: An association of mathematics teachers has 1,260 members. Only 445 of these members cast votes in the election for president of the association. What percent of the total membership voted for the winning candidate if the winning candidate received 60 percent of the votes cast?
(A) 75%
(B) 58%
(C) 42%
(D) 34%
(E) 22%
Rationale: Total umber of members = 1260
Number of members that cast votes = 445
Since , winning candidate received 60 percent of the votes cast
Number of votes for winning candidate = (60/100)*445 = 267
Percent of total membership that voted for winning candidate = (267/1260)*100 = 21.19%
Answer E
Answer: (E) 22%
Question: The value of 99^(95/99) x 99 is:
(A) 9989
(B) 9896
(C) 9890
(D) 9809
(E) 9810
Rationale: (100 – 4/99) x 99 = 9900 – 4
= 9896.
ANSWER:B
Answer: (B) 9896
Question: A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man's rate is?
(A) 1 kmph
(B) 6 kmph
(C) 8 kmph
(D) 9 kmph
(E) 3 kmph
Rationale: DS = 6
US = 4
S = ?
S = (6 - 4)/2 = 1 kmph
Answer: A
Answer: (A) 1 kmph
Question: A company has a hierarchical system where for every 10 workers, there is one team lead, and for every 3 teams leads, there is one supervisor. If the company has 13 supervisors, how many workers does it have?
(A) 140
(B) 321
(C) 390
(D) 500
(E) 130
Rationale: Some students may initially answer 130 to this question, especially if answering similar problems. However, that would be incorrect, as this is not a straight-forward ratio of 1:3:10.
The ratio of supervisors to team leads is 1:3, and the ratio of team leads to workers is 1:10. Therefore, the ratio of supervisors to workers is 1:30.
Therefore, 13*30=390
Answer: C)
Answer: (C) 390
Question: A car covers a distance of 180 km in 10 hrs. What is its speed in mps.
(A) 40 m/s
(B) 5 m/s
(C) 20 m/s
(D) 15 m/s
(E) 16 m/s
Rationale: Explanation:
Distance = Speed x Time
Speed = (180/10) = 18 kmph
Spees in mps = 18 x 5/18 = 1 x 5 = 5 mps.
Answer: Option B
Answer: (B) 5 m/s
Question: A fraction bears the same ratio to 1/27 as 3/7 does to 5/9. The fraction is?
(A) 1/23
(B) 1/35
(C) 1/25
(D) 1/13
(E) 1/15
Rationale: Let the fraction be x. Then,
x:1/27 = 3/7 : 5/9
x × 5/9 = 1/27 × 3/7
x × 5/9 = 1/9 × 1/7
x × 5/9 = 1/63
x × 5 = 9/63
5x = 1/7 = 1/35
B
Answer: (B) 1/35
Question: If the tens digit of positive integer x is 5 and the tens digit of positive integer y is 5, how many possible values of the tens digit of 2(x+y) can there be?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: We only need to consider the tens and ones digits of x and y, and the last two digits can be represented as 50 + p and 50 + q respectively.
2(50+p+50+q)= 200 + 2(p + q)
2(p+q) can range from 0 up to a maximum value of 36 when p=q=9.
Then the tens and ones digits of 2(x+y) can range from 00 up to 36.
There can be 4 possibilities for the tens digit.
The answer is C.
Answer: (C) 4
Question: A began business with 1000 and is joined afterwards by B with 6000. When did B join, if the profits at the end of the year are divided equally?
(A) 8 months
(B) 9 months
(C) 10 months
(D) 2 months
(E) None of these
Rationale: Let B join after x months of the start of the business so that B’s money is invested for (12 – x) months.
∴ Profit ratio is 12 × 1000 : (12 – x) × 6000
or 12 : 6(12 – x)
Since profit is equally divided so
12 = 6(12 – x) or x = 2. Thus B joined after 8 months.
Answer D
Answer: (D) 2 months
Question: The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area?
(A) Remains same
(B) 5% decrease
(C) 7% decrease
(D) 2% decrease
(E) 3% decrease
Rationale: 100 * 100 = 10000
125 * 80 = 10000
No change
A
Answer: (A) Remains same
Question: A box contains either blue or red flags. The total number of flags in the box is an even number. A group of children are asked to pick up two flags each. If all the flags are used up in the process such that 60% of the children have blue flags, and 65% have red flags, what percentage of children have flags of both the colors?
(A) 5%
(B) 10%
(C) 15%
(D) 20%
(E) 25%
Rationale: Solution: let the total number of flags be 100(even number)
let the total number of 'blue' flags alone be 'a'
let the total number of 'red' flags alone be 'b'
let the total number of 'both' flags be 'c'
We have given,
total number of blue flags = 60% = 60 = a+c
total number of red flags=65%=65=b+c
total number of flags = a+b+c=100 (since all the flags have been utilized)
So, substituting for c in the third equation, we have,
60-c+c+65-c=100
c=25
Option E.
Answer: (E) 25%
Question: Which of the following is equivalent to the pair of inequalities x + 7 > 10 and x - 1 <= 5 ?
(A)  2 < x < 16
(B)  2 <= x < 4
(C)  3 < x <= 6
(D)  4 < x <= 8
(E)  4 <= x <= 16
Rationale: Solution:
Let’s isolate x in both inequalities, starting with x + 7 > 10.
x + 7 > 10
x > 3
Next we isolate x in the inequality x – 1  5.
x – 1 <= 5
x <= 6
Bringing these two inequalities together we know:
3 < x <= 6
The answer is C.
Answer: (C)  3 < x <= 6
Question: Ramu bought an old car for Rs. 40000. He spent Rs. 13000 on repairs and sold it for Rs. 64900. What is his profit percent?
(A) 20
(B) 22.5
(C) 18
(D) 99
(E) 88
Rationale: Total CP = Rs. 40000 + Rs. 13000 = Rs. 53000 and SP = Rs. 64900
Profit(%) = (64900 - 53000)/53000 * 100 = 22.5%
Answer: B
Answer: (B) 22.5
Question: A room has equal number of men and women. Eight women left the room, leaving twice as many men as women in the room . What was the total number of men and women present in the room initially?
(A) 32
(B) 34
(C) 28
(D) 30
(E) 36
Rationale: Explanation :
Assume that initial number of men = initial number of women = x
2(x-8) = x
=> 2x - 16 = x
=> x = 16
Total number of men and women = 2x = 2 × 16 = 32
Answer : A
Answer: (A) 32
Question: Selling an kite for Rs. 30, a shop keeper gains 40%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?
(A) 8%
(B) 10%
(C) 11%
(D) 15%
(E) 26%
Rationale: Explanation:
Marked price = Rs. 30
C.P. = 100/140 * 30 = Rs. 21.42
Sale price = 90% of Rs. 30 = Rs. 27
Required gain % = 5.57/21.42 * 100 = 26%.
Answer: E
Answer: (E) 26%
Question: On June 1 a bicycle dealer noted that the number of bicycles in stock had decreased by 4 for each of the past 5 months. If the stock continues to decrease at the same rate for the rest of the year, how many fewer bicycles will be in stock on december 1 than were in stock on January 1?
(A)  8
(B)  12
(C)  20
(D)  44
(E)  36
Rationale: Jan 1 = C
Feb 1 = C - 4
March 1 = C - 8
April 1 = C - 12
May 1 = C - 16
June 1 = C - 20
July 1 = C - 24
Aug 1 = C - 28
Sept 1 = C - 32
Oct 1 = C - 36
Nov 1 = C - 40
Dec 1 = C - 44
Difference between stock on December 1 than were in stock on January 1 will be -
C - ( C - 44 )= 44
Hence answer will be (D)
Answer: (D)  44
Question: A certain country had a total annual expenditure of $1.2x10^12. If the population of the country was 240 million last year, what was the per capita expenditure?
(A) $500
(B) $1000
(C) $2000
(D) $3000
(E) $5000
Rationale: Explanation:
In scientific notation 240 million is 2.4x10^8. So the per capita expenditure was:
($1.2x10^12)/(2.4x10^8)=($1.2)/(2.4)x10^12-8=$0.5x10^4=$5000
Answer: Option E
Answer: (E) $5000
Question: If you are given $4, and the amount doubles every day, how much money will you have after 8 days?
(A) $256
(B) $512
(C) $1024
(D) $65536
(E) $4096
Rationale: 4^8=65536
The answer is D.
Answer: (D) $65536
Question: Fill in the blanks:
3 3 5 4 4 ? 5
(A) 2
(B) 7
(C) 8
(D) 3
(E) 1
Rationale: D
3
Number of letters in one, two, three, four, five, six, seven and so on.
Answer: (D) 3
Question: A reduction of 50% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg?
(A) s.42
(B) s.46
(C) s.40
(D) s.80
(E) s.34
Rationale: 800*(50/100) = 400 ---- 5
? ---- 1 => Rs.80
Answer: D
Answer: (D) s.80
Question: How many digits are used to number a book containg 300 pages.
(A) 694
(B) 792
(C) 698
(D) 784
(E) 789
Rationale: Explanation:
Number of digits in 1 digit numbers = 1 to 9 = 9
Number of digits in 2 digit numbers = 10 to 99 = 90 (2) = 180
Number of digits in 3 digit numbers = 100 to 300 = 201 (3) = 603
Total = 792
Answer: Option B
Answer: (B) 792