mathewhe/aqua_rat huggingface dataset:
Question: Sophika can buy watches at a price of P dollars per watch, which she marks up by a certain percentage before selling. If she makes a total profit of X by selling Y watches, then in terms of P and X and Y, what is the percent of the markup from her buy price to her sell price?
(A) (YP)/100X
(B) 100X/(YP)
(C) (YP)+100X
(D) (YP)-100X
(E) (YP)*100X
Rationale: Algebraic Solution:If she makes a total profit of X for Y watches, then that must be a profit of X/Y for each watch. That must be the markup above cost on each watch, the amount of the increase. Well, percent increase = (amount of increase)/(starting amount) x 100% = (X/Y)/P *100 = 100X/(YP)
Answer : B
Answer: (B) 100X/(YP)
Question: Fence X is twice as long as fence Y, and fence Y is 2 feet shorter than fence Z. If 2 feet were added to each fence, which of the following must be true?
I) X is twice as long as Y.
II) Y is 2 feet shorter than Z.
III) X is longer than Z.
(A) I only
(B) II only
(C) II and III
(D) I and II
(E) III only
Rationale: If X= 6
Y= 3
Z= 5
Then, after adding 3 feet to each:
X= 8
Y=5
Z=7
And the answer would be C, which is wrong.
Answer: (C) II and III
Question: A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
(A) 14 Years
(B) 18 Years
(C) 20 Years
(D) 22 Years
(E) 17 Years
Rationale: Let the son's present age be x years. Then, man's present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
ANSWER D
Answer: (D) 22 Years
Question: If a > 1, which of the following is equal to (2a + 6)/(a^2 + 4a + 3)?
(A) a
(B) a + 3
(C) 2/(a - 1)
(D) 2a/(a - 3)
(E) 2/(a + 1)
Rationale: Here's the algebraic approach:
(2A + 6)/(A^2 + 4A + 3) can be rewritten as...
2(A + 3)/(A+3)(A+1)
We can simplify the fraction, which leaves us with...
2/(A+1)
Ans : E
Answer: (E) 2/(a + 1)
Question: A motorist travels to a place 150 km away at an average speed of 50 km/hr and returns at 30 km/hr. His average speed for the whole journey in km/hr is ?
(A) 37.9
(B) 37.53
(C) 37.5
(D) 37.1
(E) 37.4
Rationale: Explanation:
Average speed = (2xy) /(x + y) km/hr
= (2 * 50 * 30) / (50 + 30) km/hr.
37.5 km/hr.
Answer: C
Answer: (C) 37.5
Question: A, B and C enter into a partnership. They invest Rs. 40,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. IN what ratio will the profit be shared at the end of 3 years?
(A) 3:4:9
(B) 3:4:7
(C) 3:4:2
(D) 3:4:4
(E) 3:4:3
Rationale: A:B:C = (40000 * 36) : (80000 * 12 + 40000 * 24) : (120000 * 24 + 40000 * 12)
= 144:192:336 = 3:4:7
Answer: B
Answer: (B) 3:4:7
Question: Two different primes may be said to “rhyme” around an integer if they are the same distance from the integer on the number line. For instance, 3 and 7 rhyme around 5. What integer between 1 and 20, inclusive, has the greatest number of distinct rhyming primes around it?
(A) 12
(B) 15
(C) 17
(D) 18
(E) 20
Rationale: Let's test each option:
A. 12 --> 2*12=24 --> 24=5+19=7+17=11+13: 6 rhyming primes (start from the least prime and see whether we can get the sum of 24 by adding another prime more than 12 to it);
B. 15 --> 2*15=30 --> 30=7+23=11+19=13+17: 6 rhyming primes;
C. 17 --> 2*15=30 --> 34=7+23=11+19=13+17: 6 rhyming primes;
D. 18 --> 2*18=36 --> 36=5+31=7+29=13+23=17+19: 8 rhyming primes;
E. 20 --> 2*20=40 --> 40=3+37=11+29=17+23: 6 rhyming primes.
Answer: D.
Answer: (D) 18
Question: A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
(A) 20%
(B) 30%
(C) 40%
(D) 50%
(E) 55%
Rationale: Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = (0.59x)/2x	x 100	%	= 30% (approx.)
B)
Answer: (B) 30%
Question: A and B together can do a work in 6 days. If A alone can do it in 15 days. In how many days can B alone do it?
(A) 10
(B) 99
(C) 77
(D) 65
(E) 55
Rationale: 1/6 – 1/15 = 1/10 => 10
Answer: A
Answer: (A) 10
Question: One night 25 percent of the female officers on a police force were on duty. If 500 officers were on duty that night and half of these were female officers, how many female officers were on the police force?
(A) 90
(B) 180
(C) 270
(D) 500
(E) 1,000
Rationale: Let total number of female officers in the police force = F
Total number of officers on duty on that night = 500
Number of female officers on duty on that night = 500/2 = 250
(25/100)*F = 250
=>F = 1000
Answer E
Answer: (E) 1,000
Question: In a group of Peacocks and cows, the total number of legs are 36 more than twice the no. of heads. Find the total no.of buffaloes.
(A) 10
(B) 19
(C) 12
(D) 16
(E) 18
Rationale: Let the number of buffaloes be x and the number of ducks be y
=> 4x + 2y = 2 (x + y) + 36
=> 2x = 36 => x = 18
E
Answer: (E) 18
Question: Two trains of equal length, running with the speeds of 60 and 40 kmph, take 50 seconds to cross each other while they are running in the same direction. What time will they take to cross each other if they are running in opposite directions?
(A) 10
(B) 8
(C) 77
(D) 26
(E) 22
Rationale: RS = 60 -40 = 20 * 5/18 = 100/18
T = 50
D = 50 * 100/18 = 2500/9
RS = 60 + 40 = 100 * 5/18
T = 2500/9 * 18/500 = 10 sec.Answer: A
Answer: (A) 10
Question: Which of these must the factor W of the product of four consecutive even integers:-
1) 48
2) 64
3) 96
4) 192
5) 80
(A) W=1,2 only
(B) W=2,3 only
(C) W=1,2,3 only
(D) W=1,2,3,4 only
(E) All of them
Rationale: Let the four variables be a< b< c< d.
Assume a worst case scenario where the a equal to a prime number (hence odd).
therefore
a = divisible by 1
b = a + 1 (divisible by 2)
c = a + 3 (divisible by 3)
d = a + 4 (divisible by 4)
therefore
each answer choice must be divisible by 2 x 3 x 4 = 24
only 80 is not divisible. Therefore answer = D
Answer: (D) W=1,2,3,4 only
Question: There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability Q that the both positions will be taken by members of just one party?
(A) 1/25
(B) 12/49
(C) 1/4
(D) 24/49
(E) 1/2
Rationale: Q probability of one party having both spots:
(1/2) * (24/49) = 12/49
(1/2) or (25/50) because it does not matter which party or which person gets the first spot. (24/49) because after one person from a particular party is chosen, there are 24 members of the same party left out of 49 total candidates.
Since this result can happen for both parties, (12/49) + (12/49) = (24/49)
Answer: D
Answer: (D) 24/49
Question: If there are 4 peanuts in a box and Mary puts 12 more peanuts inside, how many peanuts are in the box?
(A) 8
(B) 16
(C) 10
(D) 11
(E) 12
Rationale: 12+4=16
correct answer is B)16
Answer: (B) 16
Question: A qualified worker digs a well in 4 hours. He invites 2 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?
(A) 1:24
(B) 1:34
(C) 1:44
(D) 1:36
(E) 2:14
Rationale: and answer is correct as you have calculated : 100/72 hrs that is 1.64 hrs - 1 hr and 36 minutes, so 1:36, hence, D.
Answer: (D) 1:36
Question: The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 90 kmph. Find the speed of the boat in still water and the speed of the stream?
(A) 10 kmph.
(B) 15 kmph.
(C) 18 kmph.
(D) 11 kmph.
(E) 12 kmph.
Rationale: Speed of the boat in still water = (60+90)/2 = 75 kmph. Speed of the stream = (90-60)/2
= 15 kmph.
Answer:B
Answer: (B) 15 kmph.
Question: A coin has two sides. One side has the number 1 on it and the other side has the number 2 on it. If the coin is flipped three times what is the probability that the sum of the numbers on the landing side of the coin will be greater than 4?
(A) 3/8
(B) 1/16
(C) 1/8
(D) 1/2
(E) 1/4
Rationale: Cases for sum to be greater than 4 are as mentioned below
Case 1: (1, 2, 2)
Case 2: (2, 1, 2)
Case 3: (2, 2, 1)
Case 4: (2, 2, 2)
Total Outcomes = 2 x 2 x 2 = 8
Probability = Favorable Outcomes / Total Outcomes
I.e. Probability = 4/8 = 1/2
Answer: Option D
Answer: (D) 1/2
Question: Vijay lent out an amount Rs. 10000 into two parts, one at 8% p.a. and the remaining at 10% p.a. both on simple interest. At the end of the year he received Rs. 850 as total interest. What was the amount he lent out at 8% pa.a?
(A) Rs. 15000
(B) Rs. 6000
(C) Rs. 25000
(D) Rs. 10000
(E) Rs. 18000
Rationale: Let the amount lent out at 8% p.a. be Rs. A
=> (A * 8)/100 + [(10000 - A) * 10]/100 = 850
=> A = Rs. 15000.
ANSWER:A
Answer: (A) Rs. 15000
Question: What is the next number of the following sequence
3^2,27,3^4,243
(A) 3^6
(B) 3^5
(C) 3^4
(D) 3^2
(E) 3^1
Rationale: 3^2,27,3^4,243,x
3^2,3^3,3^4,3^5,3^6
x=3^6
ANSWER:A
Answer: (A) 3^6
Question: Out of 15 consecutive numbers, 2 are chosen at random. The probability that they are both odds or both primes is?
(A) 1/8
(B) 1/7
(C) 1/9
(D) 1/2
(E) 1/1
Rationale: A leap year has 52 weeks and two days
Total number of cases = 7
Number of favourable cases = 1
i.e., {Saturday, Sunday}
Required Probability = 1/7
Answer: B
Answer: (B) 1/7
Question: The number of sequences in which 10 players can throw a ball, so that the youngest player may not be the last is ?
(A) 4300028
(B) 3265920
(C) 4320201
(D) 3786220
(E) 3101242
Rationale: x Not younger
The last ball can be thrown by any of the remaining 10 players. The first 6 players can throw the ball in 9P9 ways.
The required number of ways = 9(9!)
= 3265920
Answer:B
Answer: (B) 3265920
Question: A and B are two partially filled buckets of water. If 5 liters are transferred from A to B, then A would contain one-third of the amount of water in B. Alternatively, if 3 liters are transferred from B to A, B would contain one-half of the amount of water in A. Bucket A contains how many liters of water?
(A) 11
(B) 13
(C) 17
(D) 49/5
(E) 23
Rationale: Let A contains A, B contains B liters
so, (A-5)/(B+5)= 1/3.......(1)
again, (B-3)/(A+3)= 1/2..........(2)
from (1)(2) we find A= 49/5
ans: (D)
Answer: (D) 49/5
Question: Two bullet trains of equal lengths take 10 seconds and 12 seconds respectively to cross a telegraph post. If the length of each bullet train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
(A) 11 sec.
(B) 15 sec.
(C) 12 sec.
(D) 17 sec.
(E) 19 sec.
Rationale: Speed of the first bullet train = 120/10 m/sec = 12 m/sec.
Speed of the second bullet train = 120/12 m/sec = 10 m/sec.
Relative speed = (12 + 10) = 22 m/sec.
Required time = (120 + 120)/22 sec = 11 sec.
A
Answer: (A) 11 sec.
Question: A batsman scored 120 runs which included 10 boundaries and 6 sixes. What % of his total score did he make by running between the wickets
(A) 40%
(B) 50%
(C) 36.67%
(D) 70%
(E) 75%
Rationale: Number of runs made by running = 120 - (10 x 4 + 6 x 6)
= 120 - (76)
= 44
Now, we need to calculate 60 is what percent of 120.
=> 44/120 * 100 = 36.67 %
C
Answer: (C) 36.67%
Question: In the interior of a forest, a certain number of apes equal to the square of one-sixth of the total number are playing and having great fun. The remaining five apes are on a hill and the echo of their shrieks by the adjoining hills frightens them. They came and join the apes in the forest and play with enthusiasm. What is the total number of apes?
(A) 48
(B) 16
(C) 64
(D) 6 or 30
(E) 16 or 48
Rationale: Let total number be x
No in the interior = (x/6)^2
No outside = 5
So : x - (x/6)^2=5
x^2-36x+180=0
x^2-30x-6x+180=0
(x-6)(x-30)=0
So either x=6 or x=30
D
Answer: (D) 6 or 30
Question: Ajay and Vijay have some marbles with them. Ajay told Vijay "if you give me 'x' marbles, both of us will have equal number of marbles". Vijay then told Ajay "if you give me twice as many marbles, I will have 30 more marbles than you would". Find 'x'?
(A) 6
(B) 5
(C) 8
(D) 7
(E) 9
Rationale: Explanation:
If Vijay gives 'x' marbles to Ajay then Vijay and Ajay would have V - x and A + x marbles.
V - x = A + x --- (1)
If Ajay gives 2x marbles to Vijay then Ajay and Vijay would have A - 2x and V + 2x marbles.
V + 2x - (A - 2x) = 30 => V - A + 4x = 30 --- (2)
From (1) we have V - A = 2x
Substituting V - A = 2x in (2)
6x = 30 => x = 5.
Answer: B
Answer: (B) 5
Question: If x and y are integers and x^2*y is a negative odd integer, which of the following must be true?
I. xy^2 is odd.
II. xy is negative.
III. x + y is even.
(A) I only
(B) III only
(C) I and II only
(D) I and III only
(E) I, II, and III
Rationale: x^2*y = negative odd integer
inference:
1. Odd * Odd = Odd
2. y is negative odd integer
3. x is odd (since its squared, the result is positive - so x could be either positive or negative).
Statement I - xy is odd, so is its sqaure - statement must be true
Statement II - xy may or may not be negative - statement may be true but NOT must
Statement III - x and y are odd, so Odd + Odd = Even - statement must be true
Answer is D
Answer: (D) I and III only
Question: Three friends-whose walking rates are 1 ft./sec., 3ft./sec.,and 6ft./sec. start together walking in the same direction around a circular track that is 240 feet in circumference.After how many minutes are the three of them together again?
(A) 4 mins
(B) 10 mins
(C) 15 mins
(D) 3 mins
(E) 7 mins
Rationale: Answer will be A
The time they take will be what the 1st friend takes to complete one circumference as he is the slowest and that is the point all 3 of them will be together at the end of 4 mins.
Answer: (A) 4 mins
Question: A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?
(A) 1 min
(B) 9 min
(C) 4 min
(D) 3 min
(E) 8 min
Rationale: C
4 min
S = 600/40 = 15 mps
S = 3600/15 = 240 sec = 4 min
Answer: (C) 4 min
Question: P is three times as fast as Q and working together, they can complete a work in 16 days. In how many days can Q alone complete the work?
(A) 11 days
(B) 16 days
(C) 13 days
(D) 64 days
(E) 19 days
Rationale: P = 3Q
P + Q = 3Q + Q = 4Q
These 4Q people can do the work in 16 days,
which means Q can alone do the work in 4*16=64 days.
Answer : D
Answer: (D) 64 days
Question: Set A: {1, 3, 6, 9, 12, 15,18}
If three numbers are randomly selected from set A without replacement, what is the probability that the sum of the three numbers is divisible by 3?
(A) 3/14
(B) 2/7
(C) 9/14
(D) 4/7
(E) 11/14
Rationale: probability : 6/7*5/6*4/5=4/7.
Ans D
Answer: (D) 4/7
Question: The numbers of pizza slices that are sold in Joey's Pizza are only in quantities of 5 and 8 slices per customer. How many slices cannot be bought?
(A) 42.
(B) 38.
(C) 33.
(D) 22.
(E) 20
Rationale: Let X pizzas of 5 slices and Y pizzas of 8 slices.
5X + 8Y.
Lets check options wise.
A. 42 => 5(2) + 8(4)
B. 38 => 5(6) + 8(1)
C. 33 => 5(5) + 8(1)
D. 22 = we can't write anything with 5 and 8 series..Lets try 5(1) + 8(2) = 21 , 5(3) + 8(1) = 23 , nothing works out.
E. 20 = 5(4) + 8(0)
Answer: correct option is D
Answer: (D) 22.
Question: A room contains 240 people, 15 percent of whom are women. A group of people, 30 percent of whom are women, leaves the room. Of the people remaining in the room, 10 percent are women. How many people left the room?
(A) 02
(B) 04
(C) 06
(D) 08
(E) 10
Rationale: Say group of x people left the room.
# of women in the room was 0.15*240=36;
# of women in the group that left 0.3x;
# of women in the room after the group left it is 0.1(240-x);
So, 36-0.3x= 0.1(240-x) --> x=6.
Answer: C.
Answer: (C) 06
Question: If a and b are positive integers such that a/b = 9.32, which of the following must be a divisor of a
(A) 4
(B) 3
(C) 11
(D) 10
(E) 5
Rationale: a/b = 9.32
a/b = 932/100
a/b = 466/50
a = 466/50*b
We require to find from the available 5 options that must be a divisor of a"
This also means which of the following 5 options can divide 466 evenly
(Ignore b as its value unknown; Ignore 50 as in denominator)
Only option A = 4 best fits in
Answer = 4
ANSWER:A
Answer: (A) 4
Question: The cost price of an article is 64% of the marked price. Calculate the gain percent after allowing a discount of 12%?
(A) 37.5%
(B) 37.8%
(C) 38.5%
(D) 27.5%
(E) 37.1%
Rationale: Explanation:
Let marked price = Rs. 100.
Then, C.P. = RS. 64, S.P. = Rs. 88
Gain % = 24/64 * 100 = 37.5%.
Answer:A
Answer: (A) 37.5%
Question: The average of 11numbers is 50. Out of 11numbers the average of first 6no. is 58, and last 6numbers is 65 then find 6th number?
(A) A)188
(B) B)65
(C) C)58
(D) D)62
(E) E)48
Rationale: 6th number = sum of 1st 6no.s + sum of last 6no.s - sum of 11no.s
answer = 6*58+6*65-11*50= 188
Answer is A
Answer: (A) A)188
Question: Points X, Y, and Z lie, in that order, on a straight railroad track. The distance from point X to point Y is twice the distance from point Y to point Z. A train traveled from point X to point Z without stopping. The train's average speed when traveling from point X to point Y was 300 miles per hour and the train's average speed when traveling from point Y to point Z was 100 miles per hour. What was the train's average speed, in miles per hour, when traveling from point X to point Z?
(A) 200
(B) 220
(C) 240
(D) 180
(E) 260
Rationale: Average speed = distance/time
Because we are looking for average speed we can pick a distance for the variable D.
Speed X-Y = 300
Speed Y-Z = 100
Average Speed = total distance/total rate
rate = distance/time
X====================Y==========Z
If X-Y is twice the length of Y-Z then let X-Y = 2d and let Y-Z= d
Average speed = 3d/(2d/300) + (d/100)
3d/(2d/300) + (3d/300)
3d/(5d/300)
900d/5d
Average speed = 180
ANSWER: D
Answer: (D) 180
Question: The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 80 metres?
(A) 16 seconds
(B) 76 seconds
(C) 26 seconds
(D) 12 seconds
(E) 18 seconds
Rationale: Speed of the boat downstream = 15 + 3
= 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 80 m
= 80/5
= 16 seconds.
Answer: A
Answer: (A) 16 seconds
Question: During a recent track meet, Peter ran x meters of the 100 meter dash in 8 seconds; running at the same rate, how many seconds will it take Peter to run z meters of the 200 meter dash?
(A) xz/8
(B) 8zx
(C) 8x/z
(D) 8/xz
(E) 8z/x
Rationale: Speed of Peter = x/8 meters per second
Time needed to run z meters = DISTANCE/SPEED = z / (x/8) = 8z/x
Option E
The values 100m and 200m have no role to play here and are just given to confuse you.
Answer: (E) 8z/x
Question: Average between two sets of numbers is closer to the set withmore numbers?
(A) 70
(B) 80
(C) 90
(D) 95
(E) 98
Rationale: If on a test three people answered 90% of the questions correctly and two people answered 80% correctly, then the average for the group is not 85% but rather 3×90+2×805=4305=86.3×90+2×805=4305=86.
Here, 90 has a weight of 3 => it occurs 3 times.
Whereas 80 has a weight of 2 => it occurs 2 times.
So the average is closer to 90 than to 80 as we have just calculated.
B
Answer: (B) 80
Question: Exactly one side of a certain 10-sided die are red. What is the probability that Kumar rolls the die 3 times and the die lands with a red side up for the first time on the third roll?
(A) 0.09
(B) 0.1
(C) 0.081
(D) 0.091
(E) 0.074
Rationale: Total no. of sides = 10
Side that are red = 1
Probability that the die lands with red side up = 1/10
Therefore, Probability that the die does not land with red side up = 1 - 1/10 = 9/10
Probability that Kumar rolls the die 3 times and the die lands with a red side up for the first time on the third roll
= (1st roll - non red face) X (2nd roll - non red face) X (3rd roll - red face)
= (9/10) X (9/10) X (1/10)
= 81/1000
= 0.081
C
Answer: (C) 0.081
Question: With out any halt a train travels a certain distance with an average speed of 75 km ph , and with halts it covers the same distance at an average speed of 60 kmph. When it is traveling with halts, how many minutes/per hour does the train halt on an average ?
(A) 48 min.
(B) 12min.
(C) 15min.
(D) 18min.
(E) 19min.
Rationale: With halt in 1 hour the train travels 60km
With out halt for traveling same distance it take 60/75 = 4/5 = 48 minutes
:. 12 minutes is the halting time per hour
ANSWER:B
Answer: (B) 12min.
Question: 20 percent of Andrea's living room floor is covered by a carpet that is 4 feet by 9 feet. What is the area of her living room floor?
(A) 14.4
(B) 180
(C) 50.4
(D) 60
(E) 90
Rationale: 20% of Area of the floor = 4*9 square feet = 36 square feet
i.e. 100% Area of Floor = (36/20)*100 = 180 square feet
Answer: Option B
Answer: (B) 180
Question: In a school 50% of the students are younger than 10, 1/20 are 10 years old and 1/10 are older than 10 but younger than 12, the remaining 70 students are 12 years or older. How many students are 10 years old?
(A) 50
(B) 60
(C) 10
(D) 20
(E) 30
Rationale: Let us write the fraction for each group of students
Group A: younger than 10: 50% = 50/100 = 1/2
Group B: 10 years old: 1/20
Group C: older that 10 but younger than 12: 1/10
Group D: 12 years or older: 70 students
The fraction for group A, B and C together is given by
1 / 2 + 1 / 20 + 1 / 10 = 10 / 20 + 1 / 20 + 2 / 20 , common denominator
= 13 / 20 , add numerators
The fraction for group D is given by
20 / 20 - 13 / 20 = 7 / 20 and corresponds to 70 students
If X is the total number of students, then
7 / 20 of X = 70
or (7 / 20) * X = 70
Solve for X
X = 70 * (20 / 7) = 200
Students who are 10 years old have a fraction of 1 / 20 of the total X and their number is equal to
(1 / 20) of 200 = 10 students
correct answer C
Answer: (C) 10
Question: A cricketer has certain average for 5 innings. In the 6 inning he scored 90 runs, there by increasing his average by 8 runs. His new average is
(A) 42
(B) 52
(C) 60
(D) 48
(E) 36
Rationale: Let the average for 5 innings be x
Then, (5x+90)/6 = x+8
x = 42
Answer is A
Answer: (A) 42
Question: The average salary of Raj and Roshan is Rs. 4000 but the average salary of Raj, Roshan and Thomas is Rs. 5000. What is the salary of Thomas?
(A) 4000
(B) 5000
(C) 6000
(D) 7000
(E) 8000
Rationale: Total salary of Raj and Roshan= 2x4000=8000
Total salary of Raj Roshan and Thomas= 3x5000=15000
Salary of Thomas= 15000-8000= Rs. 7000
Answer: D
Answer: (D) 7000
Question: 300 metres long yard, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees
(A) 10
(B) 12
(C) 14
(D) 16
(E) 18
Rationale: 26 trees have 25 gaps between them,
Required distance (300/25) = 12
B
Answer: (B) 12
Question: A movie buff buys movies on DVD and on Blu-ray in a ratio of 17:4. If she returns 4 Blu-ray movies, that ratio would change to 9:2. If she buys movies on no other medium, what was the original number of movies purchased?
(A) 22
(B) 28
(C) 77
(D) 99
(E) 378
Rationale: if u can just keep an eye on the options
99 is the only multiple of 9 in options given .. SO you can mark it wid in seconds.
Now coming to the process m(D) = 17x and b(D) = 4x
now from the next line the new eqn becomes 17x/ (4x -4) = 9/2
Solving it 34x = 36x -36
x =18
which means m (d) = 306 and b(d) = 72
SO total initially is m(d) + b(d) = 378
E
Answer: (E) 378
Question: The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent. The two reductions together are equal to a single reduction of
(A) 45%
(B) 40%
(C) 35%
(D) 32.5%
(E) 30%
Rationale: Price = p
initially price reduced by 25% which means new price is 3/4P
Now on this new price further 20 percent is reduced which means the new price is merely 80 percent of 3/4P
==> (3/4)x(4/5)P = 12/20P is the new price after both deduction which is 60 percent of the original value P. This implies this entire series of deduction is worth having discounted 40% of P. So answer is B = 40%
ANSWER:B
Answer: (B) 40%