mathewhe/aqua_rat huggingface dataset:
Question: Nicole cycles at a constant rate of 15 kilometers per hour, and is passed by Jessica, who cycles at a constant rate of 30 kilometers per hour. If Jessica cycles at her constant rate for x minutes after passing Nicole, then stops to wait for her, how many minutes will Jessica have to wait for Nicole to catch up to her?
(A) x/3
(B) x/2
(C) x
(D) 3x/2
(E) 2x
Rationale: In x minutes, Jessica travels (x/60)*30 = x/2 miles
The time it takes Nicole to travel x/2 miles is (x/2) / 15 = x/30 hours = 2x minutes
Jessica needs to wait 2x - x = x minutes.
The answer is C.
Answer: (C) x
Question: A bakery currently has 7 pies and 4 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?
(A) 3/11
(B) 5/11
(C) 14/33
(D) 29/77
(E) 36/77
Rationale: The total number of ways to choose 5 from 11 is 11C5 = 462.
The number of ways that include 3 pies is 7C3*4C2 = 35*6 = 210
P(exactly 3 pies) = 210/462 = 5/11
The answer is B.
Answer: (B) 5/11
Question: In the rectangular coordinate system, if the line x = 6y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p?
(A) 1/2
(B) 1/3
(C) 1/4
(D) 1/5
(E) 1/6
Rationale: x = 6y+5, and thus y = x/6 - 5/6
The slope is 1/6.
The slope of a line through points (m,n) and (m + 2,n + p) is (n+p-n)/(m+2-m) = p/2
p/2 = 1/6 and thus p = 1/3
The answer is B.
Answer: (B) 1/3
Question: I remember during the school days , the teacher asked the class "can you tell me the sum of the first 50 odd numbers ?".
I ran quickly to the teacher and told her "the answer is 2500". The teacher replied "lucky guess".
She then asked me "can you tell me the sum of first 70 odd numbers ?".
I wait for approx 10 seconds and replied with the correct answer.
How can i answer so quickly and whats the correct answer ?
(A) 8715
(B) 0152
(C) 3581
(D) 4900
(E) 9126
Rationale: D
5625
n^1
70 * 70 = 4900(sum of first 70 odd numbers).
50 * 50 = 2500 (sum of first 50 odd numbers).
Answer: (D) 4900
Question: Mary, Peter, and Lucy were picking chestnuts. Mary picked three times as much as much chestnuts than Peter. Lucy picked 5 kg more than Peter. Together the three of them picked 30 kg of chestnuts. How many kilograms of chestnuts did Mary, Peter, and Lucy pick respectively?
(A) 10, 15, and 5
(B) 15, 10, and 5
(C) 15, 5, and 10
(D) 10, 5, and 15
(E) 5, 10, and 15
Rationale: M = 3P
L = P+5
M + P + L = 30
3P + P + (P+5) = 30
P = 5, M = 15, L = 10
Therefore, Mary, Peter, and Lucy picked 15, 5, and 10 kg, respectively.
The answer is C.
Answer: (C) 15, 5, and 10
Question: If there are 20 apples and the apples have to be shared equally among 3 babies. What number of apples are to be added?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: Given there are 20 apples.If 1 extra apple is added, then it becomes 21 which can be divided equally that is 7 apples to each baby.
Option A is correct.
Answer: (A) 1
Question: The Natural Woman, a women's health food store, offers its own blends of trail mix. If the store uses 3 different ingredients, how many bins will it need to hold every possible blend, assuming that each blend must have at least three ingredients? (Also assume that each bin can hold one and only one blend.)
(A)  1
(B)  4
(C)  7
(D)  11
(E)  10
Rationale: We're told that there are 3 ingredients (we'll call them A, B, C ); we're told that each 'mix' must include AT LEAST 3 ingredients...
3 ingredient blends:
ABC
ABD
ACD
BCD
Total blends = 4
B
Answer: (B)  4
Question: A family consists of grandparents, parents and three grandchildren. The average age of the grandparents is 67 years, that of the parents is 35 years and that of the grandchildren is 6 years. What is the average age of the family?
(A) 31 5/8 years
(B) 31 5/7 years
(C) 31 9/7 years
(D) 38 5/7 years
(E) 31 5/4 years
Rationale: Required Average = [(67 * 2) + (35 * 2 ) + (6 * 3)]/(2 + 2 + 3)
= (134 + 70 + 18)/7
= 31 5/7 years.
Answer:B
Answer: (B) 31 5/7 years
Question: H.C.F of 3240, 3600 and a third number is 36 and their L.C.M is 24 * 35 * 52 * 72. The third number is?
(A) 22 * 35 * 72
(B) 22 * 35 * 78
(C) 22 * 35 * 72
(D) 22 * 35 * 71
(E) 22 * 35 * 73
Rationale: 3240 = 23 * 34 * 5; 3600 = 24 * 32 * 52
H.C.F = 36 = 22 * 32
Since H.C.F is the product of lowest powers of common factors, so the third number must have (22 * 32 ) as its factor.
Since L.C.M is the product of highest powers of common prime factors, so the third number must have 35 and 72 as its factors.
Third number = 22 * 35 * 72
Answer:A
Answer: (A) 22 * 35 * 72
Question: For any numbers a and b, a#b = ab(3 − b). If a and a#b both represent positive numbers, which of the following could be a value of b?
(A) −5
(B) −2
(C) 2
(D) 4
(E) 7
Rationale: if a#b is positive then there are 2 cases
either ab &(3-b) both are negatives or both positives
let both are positives then for (3-b) to be positive b has to less than 3 (3-b>0--->3>b)
from options b can be -5,-2,or 2
but if we take negative value of b then ab will negative & hence a#b which is not possible.
also if we do both negative then (3-b) to be negative b has to be greater than 3 which from options are only 4&7
if we take any value then the term ab will positive leaving a#b negative.which is not possible
Hence b=2
ANSWER:C
Answer: (C) 2
Question: A train crosses a platform of 150 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
(A) 150
(B) 887
(C) 167
(D) 197
(E) 161
Rationale: Length of the train be ‘X’
X + 150/15 = X + 250/20
4X + 600 = 3X + 750
X = 150m
Answer: A
Answer: (A) 150
Question: Select a card from pack of 52 playing cards, 2cards are drawn together at random. Find the probability of both the cards being king ?
(A) 1/111
(B) 2/121
(C) 1/221
(D) 2/213
(E) 3/412
Rationale: Two cards can be drawn from a pack of 52 playing cards in 52C2 ways. i,e., 52 x 51 / 2 = 1326 ways. The event that two kings appear in a single drawn of cards is 4C2 ways, i.e 6 ways.
∴ The probability that the two cards drawn from a pack of 52 cards are kings = 6/1326 = 1/221
C
Answer: (C) 1/221
Question: Twelve coins are tossed simultaneously. In how many of the outcomes will the third coin turn up a head?
(A) 2^9
(B) 2^11
(C) 3 * 2^8
(D) 3 * 2^9
(E) 3 * 2^10
Rationale: Fix the third coin as H. The remaining 11 coins have 2^11 outcomes.
B
Answer: (B) 2^11
Question: The instructions state that Cheryl needs 4/19 square yards of one type of material and 2/13 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 4/26 square yards left that she did not use. What is the total amount of square yards of material Cheryl used?
(A) 4/19
(B) 1/9
(C) 2/3
(D) 1 1/9
(E) 2 1/9
Rationale: Total bought = 4/19+2/13
left part 4/26--->2/13
so used part 4/19+2/13-2/13=4/19
ANSWER:A
Answer: (A) 4/19
Question: In how many different number of ways 2 boys and 2 girls can sit on a bench?
(A) 720
(B) 730
(C) 740
(D) 750
(E) 24
Rationale: npn = n!
4p4 =4 × 3 × 2 × 1 = 24
E
Answer: (E) 24
Question: A takes twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 2 ays, can do the work alone in
(A) 10 days
(B) 11 days
(C) 15 days
(D) 12 days
(E) 18 days
Rationale: work as x,x/2,x/3
==(1/x+2/x+3/x)
=1/2==>6/x=1/2
==>12
ANSWER D
Answer: (D) 12 days
Question: Two mixtures of A and B have A and B in the ratio 3:2 and 3:4. In what proportion should these two mixtures be mixed to get a new mixture in which the ration of A to B is 5:4?
(A) 6:1
(B) 5:4
(C) 20:7
(D) 10:9
(E) 14:11
Rationale: I got C but with a different, yet slightly longer approach, which I constantly use for proportion problems such as this one. Usually, this approach is very efficient when used with slightly difficult questions, but this problem is quite hard so I had to slightly tweak it. I will show you how I usually use the approach and later show you how to use it with this specific problem.
Example.
1 Liter of Solution A contains 45% alcohol, while 1 Liter of Solution B contains 20% alcohol. In what ratio must the two solutions be used to get a solution with 30% alcohol
Solution:
1.	45/100*[A/(A+B)]+20/100*[B/(A+B)] = 30/100
2.	Multiply 100 to both sides to arrive at 45A/(A+B) + 20B/(A+B) = 30
3.	Multiply (A+B) to both sides to arrive at 45A + 20B = 30A + 30B
4.	Distribute to arrive at 15A = 10B
5.	Thus the ratio is A/B = 10/15 = 2/3
Now using this same approach, we tackle Gopu106’s question. It is important to first think of X in the mixture as the alcohol in the problem above; hence, a mixture of X and Y in the ratio of 3:2 translates to X is 3/5 of the solution. Applying this concept to all three equations, we write:
1.	3/5*[A/(A+B)]+3/7*[B/(A+B)] = 5/9
2.	Now here is the tweak that must be made to continue with this approach. You must find the common denominator for all three numbers and organize the fractions accordingly. By finding the common denominator of 5,7,9 (or 315) we re-write the equations as follows
3.	189/315*[A/(A+B)]+135/315*[B/(A+B)] = 175/315
4.	Multiply 315 to both sides to arrive at 189A/(A+B) + 135B/(A+B) = 175
5.	Multiply (A+B) to both sides to arrive at 189A + 135B = 175A + 175B
6.	Distribute to arrive at 14A = 40B
7.	Thus the ratio is A/B = 40/14 = 20/7 or answer C
Answer: (C) 20:7
Question: Cream costs twice as much as skim milk. A certain brand of milk is 2/5 cream and 3/5 skim milk. What fraction of the cost of this brand is due to the cream?
(A) 2/7
(B) 3/7
(C) 4/7
(D) 3/5
(E) 2/5
Rationale: Let x be the cost of the skim milk in the mixture.
The cost of the cream is (2/3)*x*2 = 4x/3.
The total cost is x+4x/3 = 7x/3 and the fraction due to the cream is (4x/3) / (7x/3) = 4/7
The answer is C.
Answer: (C) 4/7
Question: An art gallery has only paintings and sculptures. Currently, 1/3 of the pieces of art are displayed, and 1/6 of the pieces on display are sculptures. If 1/3 of the pieces not on display are paintings, and 1000 sculptures are not on display, how many pieces of art does the gallery have?
(A) 360
(B) 2250
(C) 540
(D) 640
(E) 720
Rationale: Too many words and redundant info there.
(i) 1/3 of the pieces of art are displayed, hence2/3 of the pieces of art are NOT displayed.
(ii) 1/6 of the pieces on display are sculptures, hence 5/6 of the pieces on display are paintings.
(iii) 1/3 of the pieces NOT on display are paintings, hence2/3 of the pieces NOT on display are sculptures.
1000 sculptures are not on display, so according to (iii) 2/3*{not on display} = 1000 --> {not on display} = 1500.
According to (i) 2/3*{total} = 1500 --> {total} = 2250.
Answer: B.
Answer: (B) 2250
Question: A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then, (a + b) = ?
(A) 10
(B) 11
(C) 23
(D) 43
(E) 66
Rationale: A
10
4 a 3 |
9 8 4 } ==> a + 8 = b ==> b - a = 8
13 b 7 |
Also, 13 b7 is divisible by 11 (7 + 3) - (b + 1) = (9 - b)
(9 - b) = 0
b = 9
(b = 9 and a = 1) (a + b) = 10.
Answer: (A) 10
Question: Riya covers journey from kavali to nellore by car at average speed of 50 Km/hr. She returns back by scooty with an average speed of 50 Km/hr. Find her average speed during the whole journey?
(A) 30Km/hr
(B) 50Km/hr
(C) 80Km/hr
(D) 90Km/hr
(E) 100km/hr
Rationale: Explanation:
Average speed = 2 xy/x+y
= 2*50*50/100
= 50 Km/hr
Answer: Option B
Answer: (B) 50Km/hr
Question: The average age of a group of 5 members is 20 years. Two years later, a new member joins the group. The average age of the group becomes 22.5 years. What is the age of the new member ?
(A) 20 years
(B) 21 years
(C) 22 years
(D) 25 years
(E) 24 years
Rationale: The average age of the 5 members is 20 years
=> The sum of the ages of the 5 members is 20*5 = 100 years
Once the new member joins, the average age becomes 22.5 years.
Let the age of the new member be x.
Then (110+x)/6 = 22.5
=> x = 25 years
Answer D
Answer: (D) 25 years
Question: Water consists of hydrogen and oxygen, and the approximate ratio, by mass, of hydrogen to oxygen is 2:16. Approximately how many grams of oxygen are there in 117 grams of water?
(A)  16
(B)  104
(C)  112
(D)  128
(E)  142
Rationale: Since the ratio, by mass, of hydrogen to oxygen is 2:16, then oxygen is 16/(2+16)=8/9 of mass of water.
Therefore there are 117*8/9=104 grams of oxygen in 117 grams of water.
Answer: B.
Answer: (B)  104
Question: Chunilal invests 65% in machinery 20% in raw material ands till has 1,305 cash with him. Find his total investment.
(A) 6,500
(B) 7,225
(C) 8,500
(D) 7,395
(E) None of these
Rationale: Let he had originally x.
Then 65% of x + 20 % of x + 1305 = x
0.65x + 0.2x + 1305 = x
⇒ 0.15 x = 1305 ⇒ x = 8700
∴ His total investment = 65% of 8700 + 20% of 8700
= 85% of 700 = 7395
Answer D
Answer: (D) 7,395
Question: The largest 4 digit number exactly divisible by 44 is?
(A) 9988
(B) 9939
(C) 9944
(D) 9954
(E) 9960
Rationale: Largest 4-digit number = 9999
44) 9999 (227
9988
Largest number : 9988
Answer : A
Answer: (A) 9988
Question: What is the remainder when the number 14^2 * 15^8 is divided by 5?
(A) 0
(B) 1
(C) 2
(D) 4
(E) 5
Rationale: 14^2 has units digit 6
15^8 has units digit 5
Thus 14^2*15^8 has units digit 0 and will be divisible by 5. The remainder will be zero
Answer: (A)
Answer: (A) 0
Question: Find compound interest on $ 10000 at 15% per annum for 2 years 4 months, compounded annually.
(A) 3886.25
(B) 3286.25
(C) 3186.25
(D) 3386.25
(E) 3586.25
Rationale: Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.
Amount = $ [10000 X (1+­(15/100))2 X (1+((1/3)*15)/100)]
=$ [10000 * (23/20) * (23/20) * (21/20)]
= $ 13886.25	.
:. C.I. = Rs. (13886.25 -10000) = $ 3886.25
Answer A.
Answer: (A) 3886.25
Question: The ratio between x and y is 8/5; x is increased by 10 and y is multiplied by 10 , what is the ratio between the new values of x and y?
(A) 8/5
(B) 5/8
(C) 1
(D) 10
(E) It Cannot Be Determined
Rationale: Ratio = 8k/5k = 8/5, 16/10, etc.
x and y are decreased by 5 --> (8k + 10)/(5k * 10)
New ratio can be 18/50, 26/100, etc.
Answer: E
Answer: (E) It Cannot Be Determined
Question: The lenght of a room is 5.5 m and width is 4 m. Find the cost of paving the floor by slabs at the rate of Rs. 750 per sq. metre.
(A) s. 15,550
(B) s. 15,600
(C) s. 16,500
(D) s. 17,600
(E) s. 17,900
Rationale: Area of the floor = (5.5 Ã— 4) m2 = 22 m2.
Cost of paving = Rs. (750 Ã— 22) = Rs. 16500
.
Answer: Option C
Answer: (C) s. 16,500
Question: How long does a train 100 m long running at the speed of 65 km/hr takes to cross a bridge 145 m length?
(A) 13.6 sec
(B) 12.1 sec
(C) 17.9 sec
(D) 61.9 sec
(E) 47.98 sec
Rationale: Speed = 65 * 5/18 = 18 m/sec
Total distance covered = 100 + 145 = 245 m.
Required time = 245/18 = 13.6 sec.
Answer:A
Answer: (A) 13.6 sec
Question: The slant height of a cone is 12 cm and radius of the base is 4cm, find the curved surface of the cone.
(A) 49 π cm2
(B) 40 π cm2
(C) 48 π cm2
(D) 43 π cm2
(E) 41 π cm2
Rationale: Explanation:
π * 12 * 4 = 48
Answer: Option C
Answer: (C) 48 π cm2
Question: If P(A) = 4/5 and P (B) = 2/5, find P (A n B) if A and B are independent events.
(A) 7/25
(B) 3/25
(C) 8/25
(D) 2/13
(E) 3/17
Rationale: P (A n B) = P(A) . P(B)
P (A n B) = 4/5 . 2/5
P (A n B) = 8/25.
C
Answer: (C) 8/25
Question: Sum of three nos is 98. The ratio between 1 and 2 is 2:3. The ratio between 2 and 3 is 5:8 .
Find the second no?
(A) 10
(B) 20
(C) 30
(D) 40
(E) 50
Rationale: x+y+z=98
x/y=2/3
x=2y/3
and
y/z=5/8
z=8y/5 subtitute this is x and z
2y/3+y+8y/5=98
y=30
ANSWER:C
Answer: (C) 30
Question: Kaushalya can do a work in 20 days, while kaikeyi can do the same work in 25 days. They started the work jointly.Few days later Sumitra also joined them and thus all of them completed the whole work in 10 days. All of them were paid total Rs.700. What is the Share of Sumitra?
(A) Rs.130
(B) Rs.185
(C) Rs.70
(D) can't be determined
(E) None of these
Rationale: Explanation:
Efficiency of kaushalya = 5%
Efficiency of kaikeyi = 4%
Thus, in 10 days working together they will complete only 90% of the work.
[(5 + 4) × 10] =90
Hence, the remaining work will surely done by sumitra, which is 10%.
Thus, sumitra will get 10% of Rs. 700, which is Rs.70
Answer: C
Answer: (C) Rs.70
Question: Three unbiased coins are tossed. What is the probability of getting 2 Heads and 2 Tail?
(A) 5/8
(B) 1/4
(C) 3/8
(D) 7/8
(E) 1/8
Rationale: Let, H --> Head , T --> Tail
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting 3 heads
Then E = {THH,HTH,HHT,THT,TTH}
P(E) = n(E)/n(S) =5/8
Answer is A
Answer: (A) 5/8
Question: A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is?
(A) 10
(B) 12
(C) 15
(D) 13
(E) 16
Rationale: Suppose, first pipe alone takes x hours to fill the tank. Then, second and third pipes will take (x - 5) and (x - 9) hours respectively to fill the tank.
1/x + 1/(x - 5) = 1/(x - 9)
(2x - 5)(x - 9) = x(x - 5)
x2 - 18x + 45 = 0
(x- 15)(x - 3) = 0 => x = 15
ANSWER C
Answer: (C) 15
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 23 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
(A) 877 m
(B) 195 m
(C) 167 m
(D) 887 m
(E) 265 m
Rationale: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train
= (15 x 23)m = 345 m. Let the length of the platform be x meters. Then, (x + 345)/36 = 15
==> x + 345 = 540 ==> x
= 195 m.
Answer: B
Answer: (B) 195 m
Question: A man purchased a watch for Rs.400 and sold it at a gain of 20% of the selling price. The selling price of the watch is:
(A) 232
(B) 480
(C) 178
(D) 277
(E) 1981
Rationale: Explanation:
Cost price = 400
Gain% = 20%
Gain = 400 × 2010020100 = 80
Cost price = 400 + 80 = 480
Answer: B
Answer: (B) 480
Question: A train passes a station platform in 40 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
(A) 180 m
(B) 240 m
(C) 260 m
(D) 300 m
(E) 380 m
Rationale: Speed = 54 x 5/18 = 15 m/s
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, (x + 300)/40 = 15
--> x + 300 = 600
x = 300m.
Answer : D.
Answer: (D) 300 m
Question: A family consists of two grandparents, two parents and four grandchildren. The average age of the grandparents is 70 years, that of the parents is 40 years and that of the grandchildren is 6 years. What is the average age of family?
(A) 8/4years
(B) B)31
(C) C)30
(D) D)33
(E) E)35
Rationale: Required average
= (70 x 2 + 40 x 2 + 6 x 4 )/(2 + 2 + 4)
= (140 + 80 + 24)/8
= 244/8
= 30 8/4years.
Answer is A
Answer: (A) 8/4years
Question: Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
(A) 12 sec
(B) 24 sec
(C) 48 sec
(D) 60 sec
(E) 65 sec
Rationale: Explanation:
Relative speed =	= (45 + 30) km/hr
=75 x	5/18 m/sec
=125/6 m/sec
We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
Required time =500 x	6/125 = 24 sec.
ANSWER IS B
Answer: (B) 24 sec
Question: A chair is bought for Rs.400/- and sold at Rs.500/- find gain or loss percentage
(A) 15% loss
(B) 20% gain
(C) 25% gain
(D) 30% gain
(E) 35% gain
Rationale: Formula = (Selling price ~ Cost price)/Cost price * 100
= (500 - 400)/400 = 25% gain
C
Answer: (C) 25% gain
Question: A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?
(A) 289
(B) 278
(C) 211
(D) 450
(E) 476
Rationale: 10 * 150 = 1500
3 * 100 + 5 * 150 = 1050
1500 – 1050
= 450
Answer:D
Answer: (D) 450
Question: If √(3 + ³√x) = 2, then x is equal to :
(A) 1
(B) 2
(C) 4
(D) 8
(E) 12
Rationale: On squaring both sides, we get:
3 + ³√x = 4 or ³√x = 1.
Cubing both sides, we get x = (1 x 1 x 1) = 1
ANSWER:A
Answer: (A) 1
Question: A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
(A) 60 birds
(B) 72 birds
(C) 30 birds
(D) 80 birds
(E) 20 birds
Rationale: Let the total number of shots be x. Then,
Shots fired by A =(5/8)x
Shots fired by B =(3/8)x
Killing shots by A =(1/3)of	(5/8)x=(5/24)x
Shots missed by B =(1/2) of (3/8)x	=(3/16)x
3x/16= 27 or x =(27 x 16)/3= 144.
Birds killed by A =(5x/24)	=(5/24*144)= 30.
Answer is C.
Answer: (C) 30 birds
Question: The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
(A) 542
(B) 540
(C) 591
(D) 567
(E) 548
Rationale: Required number = (L.C.M. of 12, 15, 20, 54) + 8
= 540 + 8
= 548.
Answer: Option E
Answer: (E) 548
Question: When y is divided by 288, the remainder is 45. What is the remainder when the same y is divided by 24?
(A) 20
(B) 21
(C) 23
(D) 25
(E) 26
Rationale: y = 288*a + 45 = (24*12)*a + 24 + 21
The answer is B.
Answer: (B) 21
Question: Which of the following is not a prime number ?
(A) 502
(B) 503
(C) 509
(D) 521
(E) 523
Rationale: Clearly, 502 is not a prime number.
Answer : A
Answer: (A) 502
Question: Best friends Sprite and Icey have are playing a game of marbles. They invite 10 of their friends to play with them. There are 36 marbles in the bag. If all 12 people are playing, how many marbles does each person get?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: Answer= A
36 / 12 = 3
Answer= A
Answer: (A) 3
Question: Of the families in City X in 1904, 50 percent owned a personal computer. The number of families in City X owning a computer in 1908 was 30 percent greater than it was in 1904, and the total number of families in City X was 5 percent greater in 1908 than it was in 1904. what percent of the families in City X owned a personal computer in 1908?
(A) 61.90%
(B) 52.20%
(C) 56.20%
(D) 70.45%
(E) 74.41%
Rationale: Say a 100 families existed in 1904 then the number of families owning a computer in 1904 - 50
Number of families owning computer in 1908 = 50 * 130/100 = 65
Number of families in 1908 = 105
The percentage = 65/105 * 100 = 61.90%.
Option: A
Answer: (A) 61.90%
Question: A father was twelve times as old as his son twenty years back. Now he is twice as old as his son. What are their present ages?
(A) Father 44 and Son 22
(B) Father 35 and Son 23
(C) Father 38 and Son 44
(D) Father 55 and Son 22
(E) None of these
Rationale: Let present age of the Son = X.
Present age of the father = 2X.
Now according to question,
2X -20 = 12*(X-20)
2X - 20 = 12X -240
10X = 220
X = 22
Present age son = 22 years,
Present age father = 2*22 = 44.
ANSWER : OPTION A
Answer: (A) Father 44 and Son 22
Question: The difference between a 4-digit number and the number formed by reversing its digit is not a multiple of
(A) 3
(B) 27
(C) 243
(D) 81
(E) 11
Rationale: Another approach is to TEST a number.
Let's say the original number is 2031
So, the REVERSED number is 1302
The DIFFERENCE = 2031-1302 =729
No check the answer choices
729 is a multiple of 3,27,81,243
11 is NOT a multiple of 729
Answer:E
Answer: (E) 11
Question: John found that the average of 15 no.'s is 40. If 10 is added to each number then the mean of number is?
(A) 50
(B) 55
(C) 65
(D) 72
(E) 78
Rationale: (x+x1+...x14)/15 = 40
50
Option A
Answer: (A) 50