mathewhe/aqua_rat huggingface dataset:
Question: The average weight of a group of boys is 20 kg. After a boy of weight 35 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
(A) 12
(B) 14
(C) 18
(D) 24
(E) 10
Rationale: Let the number off boys in the group originally be x.
Total weight of the boys = 20x
After the boy weighing 35 kg joins the group, total weight of boys = 20x + 35
So 20x + 35 = 21(x + 1) = > x = 14.
ANSWER:B
Answer: (B) 14
Question: A wholeseller has $329,864 in her savings account. What is the least amount of money (in whole number of dollars) that he must add to his account if she wants to split this money evenly among his 9 debters?
(A) $1
(B) $2
(C) $3
(D) $4
(E) $6
Rationale: To find the least amount the wholeseller should add to her saving account to split the money evenly among his 9 debtors,
he needs to make the total divisible by 9
Simply add the individual digits of the total = 3+2+9+8+6+4 = 32
If you add 4 , the number is divisible by 9 (32+ 4)
Correct Option : D
Answer: (D) $4
Question: The altitude drawn to the base of an isosceles triangle is 8 cm and the perimeter is 32 cm. The area of the triangle is
(A) 72 cm2
(B) 60 cm2
(C) 66 cm2
(D) 65 cm2
(E) None of these
Rationale: Let ABC be the isosceles triangle and AD be the altitude.
Let AB = AC = x. Then, BC = (32 – 2x).
Since, in an isosceles triangle, the altitude bisects the base. So, BD = DC = (16 – x).
In ΔADC, AC2 = AD2 + DC2
⇒ x2 = (8)2 + (16 – x)2
⇒ 32x = 320 ⇒ x = 10.
∴ BC = (32 – 2x) = (32 – 20) cm = 12 cm.
Hence, required area = (1⁄2 × BC × AD)
= (1⁄2 × 12 × 10) cm2 = 60 cm2
Answer B
Answer: (B) 60 cm2
Question: A salt manufacturing company produced a total of 2500 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its average monthly production for that year?
(A) 2060
(B) 3050
(C) 5550
(D) 2889
(E) 2506
Rationale: Total production of salt by the company in that year = 2500 + 2600 + 2700 + .... + 3600 = 36600.
Average monthly production of salt for that year = 36600/12 = 3050.
Answer: B
Answer: (B) 3050
Question: A train 110 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
(A) 6
(B) 7
(C) 9
(D) 5
(E) 3
Rationale: Speed of train relative to man = 60 + 6 = 66 km/hr.
= 66 * 5/18 = 55/3 m/sec.
Time taken to pass the men = 110 * 3/55
= 6 sec.
Answer: A
Answer: (A) 6
Question: A man can do a piece of work in 7days, but with the help of his son, he can finish it in 3days. In what time can the son do it alone?
(A) 5
(B) 4 1/5
(C) 7 1/2
(D) 6
(E) 9 1/2
Rationale: Son's 1day work = 1/3 - 1/7 = 5/21
Son alone can do the work in 21/5days = 4 1/5 days
Answer is B
Answer: (B) 4 1/5
Question: A man can row downstream at 22 kmph and upstream at 14 kmph. Find the speed of the man in still water and the speed of stream respectively?
(A) 13, 3
(B) 18, 4
(C) 15, 3
(D) 14, 4
(E) None of these
Rationale: Explanation:
Let the speed of the man in still water and speed of stream be x kmph and y kmph respectively.
Given x + y = 22 --- (1)
and x - y = 14 --- (2)
From (1) & (2) 2x = 36 => x = 18, y = 4.
Answer: Option B
Answer: (B) 18, 4
Question: A circular path of 13 m radius has marginal walk 2 m wide all round it. Find the cost of leveling the walk at 25p per m2?
(A) 46
(B) 47
(C) 44
(D) 42
(E) 41
Rationale: π (152 - 132) = 176
176 * 1/4 = Rs.44
Answer: C
Answer: (C) 44
Question: John has 6 friends who want to ride in his new car that can accommodate only 4 people at a time (John plus 3 passengers). How many different combinations of 3 passengers can be formed from John's 6 friends?
(A) 3
(B) 8
(C) 10
(D) 15
(E) 20
Rationale: 6C3 = 20
The answer is E.
Answer: (E) 20
Question: 12 men work 8 hours per day to complete the work in 10 days. To complete the same work in 8 days, working 15 hours a day, the number of men required
(A) 8 days
(B) 3 days
(C) 7 days
(D) 5 days
(E) 6 days
Rationale: That is, 1 work done = 12 × 8 × 10
Then, 12 8 × 10 = ? × 15 × 8
? (i.e. No. of men required) = 12 × 8 × 10/15× 10 = 8 days.
A
Answer: (A) 8 days
Question: A man can do a piece of work in 5days, but with the help of his son, he can do it in 3 days. In what time can the son do it alone?
(A) 13/2
(B) 7
(C) 15/2
(D) 8
(E) 9
Rationale: Son's 1day's work = (1/3)-(1/5) = 2/5
The son alone can do the work in 15/2 days
Answer is C
Answer: (C) 15/2
Question: If 60 men can do a piece of work in 25 hours, in how many hours will 15 men
do it ?
(A) 100 hours
(B) 90 hours
(C) 80 hours
(D) 70 hours
(E) 60 hours
Rationale: Let the required number of hours be x. Then,
Less men, More hours	(Indirect Proportion)
15 : 60 : : 25 : x<=>(15 x x) =(60 x 25)<=>(60 x 25)/15 = 100
Hence, 15 men can do it in 60 hours
Answer is A.
Answer: (A) 100 hours
Question: The length of the bridge, which a train 150 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
(A) 239
(B) 277
(C) 225
(D) 88
(E) 232
Rationale: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (150 + X)/30
= 25/2 ==> 2(150 + X) = 750 ==> X = 225 m.
Answer: C
Answer: (C) 225
Question: The sector of a circle has radius of 21 cm and central angle 144o. Find its perimeter?
(A) 80cm
(B) 82cm
(C) 90cm
(D) 94.8cm
(E) 95cm
Rationale: Perimeter of the sector = length of the arc + 2(radius)
= (144/360 * 2 * 22/7 * 21) + 2(21)
= 52.8 + 42 = 94.8 cm
Answer:D
Answer: (D) 94.8cm
Question: What is the ratio between perimeters of two squares one having 5 times the diagonal then the other?
(A) 5:1
(B) 3: 1
(C) 5: 8
(D) 3: 2
(E) 8: 3
Rationale: d = 5d d = d
a√2 = 5d a√2 = d
a = 5d/√2 a = d/√2 => 5: 1
Answer:A
Answer: (A) 5:1
Question: A student multiplied a number by	3/5 instead of 5/3. What is the percentage error in the calculation?
(A) 54
(B) 48
(C) 65
(D) 25
(E) 64
Rationale: Let the number be x.
Then, error = 5/3 X - 3/5 X = 16/15 X.
Error % = (16X/15 * 3/5X * 100)% = 64%
Answer E) 64%
Answer: (E) 64
Question: The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team ?
(A) 17 years
(B) 88 years
(C) 23 years
(D) 15 years
(E) 12 years
Rationale: Explanation:
Let the average age of the whole team be x years.
11x - (26 + 29) = 9 (x - 1)
=> 11x - 9x = 46
=> 2x = 46
=> x = 23.
So, average age of the team is 23 years.
Answer: C
Answer: (C) 23 years
Question: Rob also compared the Empire State Building and the Petronas
Towers. What is the height difference between the two if the Empire
State Building is 464m tall and the Petronas Towers is 472m tall?
(A) 9
(B) 8
(C) 23
(D) 45
(E) 12
Rationale: 472-464=8.Answer is B.
Answer: (B) 8
Question: Three friends rani, Bond and gokul divide $1107 amongs them in such a way that if $4, $6 and $8 are removed from the sums that rani, Bond and gokul received respectively, then the share of the sums that they got will be in the ratio of 2 : 4 : 10. How much did gokul receive?
(A) $170
(B) $130
(C) $150
(D) $180
(E) $174
Rationale: Explanatory Answer
Let the sums of money received by A, B and C be x, y and z respectively.
Then x - 4 : y - 6 : z -8 is 2a : 4a : 10a
When $4, $6 and $8 are removed, we are removing a total of $18 from $1107.
Therefore, 2a + 4a + 10a = 1107 - 18 = 1089
i.e., 16a = 1089
or a = 68.
We know that z - 10 = 16a = 10 * 16 = 160
Therefore, z = 160 + 10 = $170
The correct choice is (A)
Answer: (A) $170
Question: If 10 men working 6 hours a day can do a work in 88 days. Then 6 men working 8 hours a day can do it in how many days?
(A) 78 days.
(B) 110 days.
(C) 49 days.
(D) 48 days.
(E) 67 days.
Rationale: B
110 days.
From the above formula i.e (m1*t1/w1) = (m2*t2/w2)
so (10*6*88/1) = (6*8*d/1)
on solving, d = 110 days.
Answer: (B) 110 days.
Question: think you are driving the car
1 3 5
2 4 ?
Do you know what will come in place of?
hint is Not 6
(A) R
(B) 6
(C) 0
(D) None of the Above
(E) B
Rationale: Correct Answer : A
It represents gear stick, the number 1-5 represents gears and the last one should be reverse gear R
Answer: (A) R
Question: If the value of a piece of house decreases by 10% while the new tax rate on the house represent 110% of the original tax rate, what is the effect on the taxes?
(A) a - taxes increase by 10%
(B) b- taxes increase by 1%
(C) c- there is no change in taxes
(D) d- taxes decrease by 1%
(E) c- taxes decrease by 10%
Rationale: Cansider the value of house = 100, Original tax rate 10%, hence tax value = 100*10% = 10.
Decreased value of house = 90, New tax rate = 110% of 10 = 11%, hence tax value = 90*11% = 9.9
10-9.9 = decrease by 1%.
Answer D.
Answer: (D) d- taxes decrease by 1%
Question: In a stockpile of products produced by three machines M1, M2 and M3, 40% and 30% were manufactured by M1 and M2 respectively. 3% of the products of M1 are defective, 1% of products of M2 defective, while 92% of the products of M3 III are not defective. What is the percentage of defective in the stockpile?
(A) 3%
(B) 5%
(C) 3.9%
(D) 4.9%
(E) 6.5%
Rationale: Explanation :
Let there be 100 products in the stockpile. 40% and 30% were manufactured by M1 and M2 respectively. So, 30% are manufactured by M3.
Products from M1 = 40, from M2 = 30 and from M3 = 30.
Number of defective products from M1 = 0.03 x 40 = 1.2, from M2 = 0.01 x 30 = 0.3 and from M3 = 0.08 x 30 = 2.4
Therefore, total number of defective products = 3.9
Answer : C
Answer: (C) 3.9%
Question: Angles AMB and CMD are right angles, ∠AMD is acute, and ∠BMC=y° is acute. What is ∠AMD ?
(A) 90°−y
(B) 180°−y
(C) 90°+y
(D) 2y
(E) y
Rationale: LAMB = 90
LCMB = y
so, LAMC = 90-y
and since LDMC = 90
LDMA = 90 - (90-y) = y
Answer: E
Answer: (E) y
Question: A larger cube has 216 cubic inch as a volume and in the cube there are 216 smaller cubes such that their volume is 1 cubic inch. What is the difference between the surface areas’ sum of the 216 smaller cubes and the surface area of the larger cube, in square inch?
(A) 54
(B) 64
(C) 81
(D) 1080
(E) 120
Rationale: Volume of larger cube = 216 = 6^3
Side of larger cube = 6
Volume of smaller cube = 1 --> Side of smaller cube = 1
Surface area of larger cube = 6 * 6^2 = 216
Surface area of 27 smaller cubes = 216 * 6 * 1 = 1296
Difference = 1296 - 216 = 1080
Answer: D
Answer: (D) 1080
Question: At a certain resort, each of the 39 food service employees is trained to work in a minimum of 1 restaurant and a maximum of 3 restaurants. The 3 restaurants are the family buffet, the dining room, and the snack bar. Exactly 15 employees are trained to work in the family buffet, 18 are trained to work in the dining room, and 12 are trained to work in the snack bar. If 4 employees are trained to work in exactly 2 restaurants, how many employees are trained to work in all 3 restaurants?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 1
Rationale: 39 = 15+ 18 + 12 - 4 - 2x
2x = 15 + 18 + 12 - 4 - 39
= 41 - 39
= 2
x =1
E
Answer: (E) 1
Question: 587 * 999 = ?
(A) 586411
(B) 586413
(C) 486411
(D) 486413
(E) None of these
Rationale: Explanation:
Trick: 587 * (1000 - 1) = 587000 - 587 = 586413
Option B
Answer: (B) 586413
Question: A train passes a station platform in 36 sec and a man standing on the platform in 20 sec. If the speed of the train is 81 km/hr. What is the length of the platform?
(A) 240
(B) 288
(C) 277
(D) 360
(E) 422
Rationale: Speed = 81 * 5/18 = 22.5 m/sec.
Length of the train = 22.5 * 20 = 450 m.
Let the length of the platform be x m . Then,
(x + 450)/36 = 22.5 => x = 360 m.
Answer: D
Answer: (D) 360
Question: Find compound interest on $ 8000 at 15% per annum for 2 years 4 months, compounded annually.
(A) 3109
(B) 3209
(C) 3108
(D) 3107
(E) 3100
Rationale: Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.
Amount = $ [8000 X (1+­(15/100))2 X (1+((1/3)*15)/100)]
=$ [8000 * (23/20) * (23/20) * (21/20)]
= $ 11109.	.
:. C.I. = Rs. (11109 - 8000) = $ 3109.
Answer A.
Answer: (A) 3109
Question: In a rare coin collection, all coins are either pure gold or pure silver, and there is initially one gold coin for every three silver coins. With the addition of 11 more gold coins to the collection, the ratio of gold coins to silver coins is 1 to 2. Based on this information, how many total coins are there now in this collection (after the acquisition)?
(A) 64
(B) 72
(C) 80
(D) 90
(E) 99
Rationale: Initially the number of gold coins and silver coins is 2k and 6k.
After adding gold coins, the number of coins is 3k and 6k.
Thus k = 11 and the total number of coins is 9k = 99.
The answer is E.
Answer: (E) 99
Question: Find the area of a rhombus one side of which measures 20 cm and one diagonal is 27 cm.
(A) 600cm2
(B) 500cm2
(C) 400cm2
(D) 432cm2
(E) 100cm2
Rationale: Explanation: Let other diagonal = 2x cm.
Since diagonals of a rhombus bisect each other at right angles, we have:
(20)2 = (12)2 + (x)2 =>x =√(20)2 – (12)2= √256= 16 cm. _I
So, other diagonal = 32 cm.
Area of rhombus = (1/2) x (Product of diagonals) =(1/2× 27 x 32) cm2 = 432 cm2
Answer: Option D
Answer: (D) 432cm2
Question: A, Band C can do a piece of work in 11 days, 20 days and 20 days respectively, working alone. How soon can the work be done if A is assisted by Band C on alternate days?
(A) 7 days
(B) 8 days
(C) 9 days
(D) 10 days
(E) 11 days
Rationale: (A+B)'s 1 day's work = 1/11+1/20 = 31/220
(A+C)'s 1 day's work = 1/11+1/20 = 31/220
work done in 2 day's = 31/220+31/220= 31/110
31/110th work done in 2 days
work done= 110/31*2 = 7 days (approx)
ANSWER:A
Answer: (A) 7 days
Question: Meg and Bob are among the 4 participants in a cycling race. If each participant finishes the race and no two participants finish at the same time, in how many different possible orders can the participants finish the race so that Meg finishes ahead of Bob?
(A) 24
(B) 30
(C) 12
(D) 90
(E) 120
Rationale: Total # of ways the race can be finished is 4!. In half of the cases Meg finishes ahead of Bob and in other half Bob finishes ahead of Meg. So, ways Meg to finish ahead of Bob is 4!/2=12.
Answer: C.
Answer: (C) 12
Question: The length of a rectangle hall is 5 m more than its breadth. The area of the hall is 750 m2. The length of the hall is :
(A) 15 m
(B) 22.5 m
(C) 25 m
(D) 30 m
(E) None of these
Rationale: Solution
Let breadth = x metres. Then, length = (x + 5) metres.
Then x(x+5) = 750 ⇔ x2 + 5x −750 = 0 ⇔ (x + 30) (x + 25) = 0 ⇔ x = 25.
∴ Length = (x + 5) = 30 m. Answer D
Answer: (D) 30 m
Question: Find the L.C.M of 2^2 * 3^3 * 5 *7^2*11, 2^3 * 3^2* 5^2* 7^4*11, 2 * 3* 5^3* 7^4*11
(A) 2^3 * 3^3 * 5^3 * 7^4 * 11
(B) 2^2*3^3*5^3 * 7^4 * 11
(C) 2^2*3^3*5^2 * 7^4 * 11
(D) 2^3*3^3*5^2* 7^4 * 11
(E) 2^3*3^3*5^2* 7^3 * 11
Rationale: L.C.M= product of the highest powers of 2,3,5,7 and 11=2^3 * 3^3 * 5^3 * 7^4 * 11
Answer (A)
Answer: (A) 2^3 * 3^3 * 5^3 * 7^4 * 11
Question: Michele invests 500 of her money in a mutual fund that quickly goes sour, losing 25% of its value each day for a week. Which of the following COULD be the value of Michele’s investment at the close-of-business any day that week?
(A) $0.00
(B) $133.00
(C) $250.05
(D) $66.74
(E) $10000.00
Rationale: Suppose she invests n$ in the starting then in the subesequent days the money left after the day will be
n/4, n/8, n/16, n/32
So, answer will be D
Answer: (D) $66.74
Question: A boat can move upstream at 25 kmph and downstream at 35 kmph, then the speed of the current is?
(A) 5
(B) 9
(C) 4
(D) 1
(E) 3
Rationale: US = 25
DS = 35
M = (35 - 25)/2
= 5
Answer: A
Answer: (A) 5
Question: Kishore has 4 pairs of shoes; each pair is a different color. If Kim randomly selects 2 shoes without replacement from the 8 shoes, what is the probability that she will select 2 shoes of the same color?
(A) 2/5
(B) 1/5
(C) 1/9
(D) 1/7
(E) 1/25
Rationale: Can be tackled in this way as well: Probability of selecting any 1 out of 8 shoes = 8/8 = 1
Probability of selecting the next shoe (out of 8 available) having the same color = 1/7 (as after selecting the 1st one, there is only 1 another shoe left with the same color).
Thus the total probability = 1*1/7=1/7.
D is the correct answer.
Answer: (D) 1/7
Question: A boat speed with the diesel is 15 km/hr and the speed of the diesel is 2.5 km/hr. The boat 's speed against the diesel is
(A) 9 km/hr
(B) 10 km/hr
(C) 12 km/hr
(D) 13 km/hr
(E) 14 km/hr
Rationale: Boat's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr.
Boat's rate against the diesel= (12.5 - 2.5) km/hr = 10 km/hr
B
Answer: (B) 10 km/hr
Question: 50% of x is greater than 1/3rd of x by 110.what is x?
(A) 100
(B) 200
(C) 300
(D) 350
(E) 660
Rationale: 5x/10-x/3=110
1x/6=110
x=660
ANSWER:E
Answer: (E) 660
Question: The population of a city is 5265538. If there are 4169577 adults in the city, how many children are there in the city?
(A) 1095961
(B) 1065961
(C) 1085961
(D) 1097961
(E) 1056961
Rationale: population of a city = 5265538
Number of Adults = 4169577
Number of Children = 5265538-4169577
= 1095961
answer :A
Answer: (A) 1095961
Question: In the sixth grade at Parkway elementary school there are 450 students. 300 students are boys and 250 students are playing soccer. 86% of the students that play soccer are boys. How many girl student are in Parkway that is not playing soccer?
(A) 69.
(B) 115
(C) 81.
(D) 91.
(E) 108.
Rationale: Total students = 450
Boys = 300, Girls = 150
Total playing soccer = 250
86%of 250 = 215 are boys who play soccer.
Girls who play soccer = 35.
Total girls who do not play soccer = 150 - 35 = 115.
Correct option: B
Answer: (B) 115
Question: How many seconds does Sandy take to cover a distance of 500 meters, if Sandy runs at a speed of 18 km/hr?
(A) 80
(B) 100
(C) 120
(D) 140
(E) 160
Rationale: 18 km/hr = 18000 m / 3600 s = 5 m/s
time = 500 / 5 = 100 seconds
The answer is B.
Answer: (B) 100
Question: Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is:
(A) 24 hours
(B) 22 hours
(C) 23 hours
(D) 21 hours
(E) 41 hours
Rationale: Speed upstream = 7.5 kmph.
Speed downstream = 10.5 kmph.
Total time taken =105/7.5+105/10.5=24 hours
Answer: A
Answer: (A) 24 hours
Question: If a man lost 8% by selling oranges at the rate of 18 a rupee at how many a rupee must he sell them to gain 45%?
(A) 33.56
(B) 23.68
(C) 11.42
(D) 9.56
(E) 23.55
Rationale: 92% ---- 18
145% ---- ?
92/145 * 18 = 11.42
Answer: C
Answer: (C) 11.42
Question: What is the unit’s digit of 7^4
(A) 3
(B) 1
(C) 5
(D) 7
(E) 9
Rationale: 7^1=7
7^2=49
7^3=343
7^4=1(last digit)
Therefore, last digit of 7^4=1
Answer B
Answer: (B) 1
Question: A boat has an upstream speed of at 50 kmph and downstream at 80 kmph, and then find the speed of the boat in still water?
(A) 65
(B) 60
(C) 75
(D) 70
(E) 90
Rationale: US = 25
DS = 35
M = (50 +80)/2
= 65
Answer:A
Answer: (A) 65
Question: How many seconds does a train 110 meters long, traveling at 54 km/h, take to completely cross a bridge of 160 meters in length?
(A) 18
(B) 20
(C) 22
(D) 24
(E) 26
Rationale: 54 km/h = 54000/3600 = 15 m/s
Time = 270 / 15 = 18 seconds
The answer is A.
Answer: (A) 18
Question: An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq m?
(A) Rs.4082.43
(B) Rs.4082.20
(C) Rs.4882.40
(D) Rs.4082.40
(E) Rs.4082.21
Rationale: Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 * 7) = 315 (13 - 0.04)
= 4095 - 12.6 = Rs.4082.40
Answer:D
Answer: (D) Rs.4082.40
Question: Anitha had 80 currency notes in all, some of which are of Rs 95 denomination and the remaining of Rs 45 denomination. The total amount of all these currency notes was Rs. 4000. How much amount (in Rs) did she have in the denomination of Rs 45?
(A) 3500
(B) 72
(C) 2000
(D) 3000
(E) 4000
Rationale: Let the number of 45-rupee notes = x
Then, the number of 95-rupee notes = (80 – x)
45x + 95(80 – x) = 4000 or x + 2(80 – x) = 95 or x = 72.
ANSWER:B
Answer: (B) 72
Question: One-tenth of the students at a nursery school are 4 years old or older. If 20 students have not yet reached their third birthday, and a total of 50 students are not between 3 years old and 4 years old, how many children are in the nursery school?
(A) 150
(B) 300
(C) 450
(D) 490
(E) 620
Rationale: x/10 students are > 4 yrs
20 students are < 3 yrs
x/10+ 20 = 50
x/10 = 30
x = 300
Answer: B
Answer: (B) 300
Question: A train is moving at a speed of 75km/hr and its length is 500m. Find the time taken by it to pass a man standing near the railway line?
(A) 30sec
(B) 45sec
(C) 36sec
(D) 24sec
(E) 52sec
Rationale: Speed of the train = 75*5/18 = 125/6 m/sec
Distance moved in passing the standing man = 500m
Required time taken = 500/(125/6) = 24sec
Answer is D
Answer: (D) 24sec
Question: A man is 20 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?
(A) 23 years
(B) 22 years
(C) 21 years
(D) 20 years
(E) 18 years
Rationale: Let present age of the son =x years
Then, present age the man =(x+20) years
Given that, in 2 years, man's age will be twice the age of his son
â‡’(x+20)+2=2(x+2)
â‡’x=18
ANSWER:E
Answer: (E) 18 years
Question: At a certain college there are twice as many English majors as history majors and three times as many English majors as mathematics majors. What is the ratio of the number of mathematics majors to the number of history majors?
(A) 2 o 3
(B) 3 to 2
(C) 2 to 4
(D) 1 to 5
(E) 1 to 6
Rationale: This is how I translated the question:
At a certain college there are twice as many english majors as history majors
E = 2H
and three times as many english majors as mathematics majors.
E = 3M
What is the ratio of the number of history majors to the number of mathematics majors?
What is H:M?
Just set E equal to each other to get the ratio in terms of H and M.
2H = 3M
H/M = 2/3
The answer is 2:3
Answer : A
Answer: (A) 2 o 3
Question: The price of sugar is increased by 2%. By how much percent should a home maker reduce her consumption of sugar to have no extra expenditure?
(A) (700/107) %
(B) (107/100) %
(C) (100/107)%
(D) (7/100)%
(E) (200/102)%
Rationale: Old price = $100 (assume);
Old consumption = 1 kg (assume).
New price = $102.
We want the spendings to remain at $100.
(New consumption)*102 = 100 --> (New consumption) = 100/102 kg.
Percent decrease = Change/Original *100 = (1 - 100/102)/1*100 = 200/102%.
Answer: E.
Answer: (E) (200/102)%
Question: Look at this series: 97, 92, 85, 78, 71, 64, 57, 50, ... What number should come next?
(A) 45
(B) 33
(C) 43
(D) 38
(E) 36
Rationale: Explanation:
In this series, each number 7 is subtracted from previous number to arrive at the next number.
Answer: Option C
Answer: (C) 43
Question: A bank pays interest to its customers on the last day of the year. The interest paid to a customer
is calculated as 10% of the average monthly balance maintained by the customer. John is a
customer at the bank. On the last day, when the interest was accumulated into his account, his
bank balance doubled to $5660. What is the average monthly balance maintained by John in his
account during the year?
(A)  28300
(B)  5680
(C)  6840
(D)  7540
(E)  28400
Rationale: bank balance is doubled with accumulation of interest tp 5660..
this means INTEREST is 5660/2=2830 for entire year..
although since interest is 10% of avg MONthly balance, it becomes 28300..
A
Answer: (A)  28300
Question: A certain sum of money at simple interest amounted Rs.940 in 5 years at 2% per annum, find the sum?
(A) 450
(B) 867
(C) 899
(D) 854
(E) 261
Rationale: 940 = P [1 + (5*2)/100]
P = 854
Answer: D
Answer: (D) 854
Question: The length of a side of a hexagon is 5 inches. What is the perimeter?
(A) 116
(B) 25
(C) 30
(D) 24
(E) 15
Rationale: Hexagon. It means 6 equal sides.
p = 5 + 5 + 5 + 5 + 5 + 5 = 10+ 10 + 10 = 30 inches
Answer C
Answer: (C) 30