mathewhe/aqua_rat huggingface dataset:
Question: The price of a T.V. set worth Rs. 8000 is to be paid in 20 installments of Rs. 750 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be?
(A) 7250
(B) 7200
(C) 7820
(D) 6000
(E) 2799
Rationale: Money paid in cash = Rs. 750
Balance payment = (8000- 1000) = Rs. 7250
Answer:A
Answer: (A) 7250
Question: In a mixture of 60 liters, the ratio of milk and water is 2:1. What amount of water must be added to make the ratio of milk and water as 1:2?
(A) 20 liters
(B) 30 liters
(C) 60 liters
(D) 29 liters
(E) 82 liters
Rationale: 2:1 --- 60
1:2
2:4
---------------
3
3 ----------- 60
3 ----------- ? => 60 liters
Answer:C
Answer: (C) 60 liters
Question: A man swims downstream 72 km and upstream 45 km taking 6 hours each time; what is the speed of the current?
(A) 2.28
(B) 2.24
(C) 2.27
(D) 2.25
(E) 2.23
Rationale: 72 --- 6 DS = 12
? ---- 1
45 ---- 6 US = 7.5
? ---- 1 S = ?
S = (12 - 7.5)/2 = 2.25
Answer:D
Answer: (D) 2.25
Question: A book store bought copies of a new book by a popular author, in anticipation of robust sales. The store bought 400 copies from their supplier, each copy at wholesale price z. The store sold the first 150 copies in the first week at 80% more than z, and then over the next month, sold a 100 more at 20% more than z. Finally, to clear shelf space, the store sold the remaining copies to a bargain retailer at 40% less than z. What was the bookstore’s net percent profit or loss on the entire lot of 400 books?
(A)  30% loss
(B)  10% loss
(C)  10% profit
(D)  20% profit
(E)  60% profit
Rationale: [[z(150)(1.8)+z(100)(1.2)+z(150)(0.6)]/400z] - 1
[50[(3)(1.8) + (2)(1.2) + (3)(0.6)] / (50)(8)] - 1
[(5.4 + 2.4 + 1.8)/8] - [8/8]
+1.6/8
+20%
answer is D
Answer: (D)  20% profit
Question: 54 is to be divided into two parts such that the sum of 10 times the first and 22 times the second is 780. The bigger part is :
(A) 33
(B) 34
(C) 26
(D) 28
(E) 19
Rationale: Explanation:
Let the two parts be (54 - x) and x.
Then, 10 (54 - x) + 22x = 780
=> 12x = 240
=> x = 20.
Bigger part = (54 - x) = 34.
Answer: B) 34
Answer: (B) 34
Question: The speed of a boat in still water is 40kmph and the speed of the current is 10kmph. Find the speed downstream and upstream?
(A) 50,30 kmph
(B) 40,20 kmph
(C) 29,25 kmph
(D) 26,20 kmph
(E) 12 ,10kmph
Rationale: Speed downstream = 40 + 10
= 50 kmph
Speed upstream = 40 - 10
= 30 kmph
Answer: A
Answer: (A) 50,30 kmph
Question: 0.04 x 0.0162 is equal to:
(A) 6.48 x 10(power -4)
(B) 6.84 x 10(power -4)
(C) 4.68 x 10(power -4)
(D) 5.48 x 10(power -4)
(E) None of them
Rationale: 4 x 162 = 648. Sum of decimal places = 6.
So, 0.04 x 0.0162 = 0.000648 = 6.48 x 10(power -4)
Answer is A.
Answer: (A) 6.48 x 10(power -4)
Question: The average salary/head of all theworkers in a workshop is Rs.850, if the average salary/head of 7technician is Rs.1000 and the average salary/head of the rest is Rs.780, the total no. of workersin the work-shop is ?
(A) 18
(B) 19
(C) 22
(D) 26
(E) 28
Rationale: Let the total number of workers be y.
So sum of salary for all workers = sum of salary of 7 technician + sum of salary for other y -7 workers.
7 x 1000 + 780(y -7) = 850 y
⇒ 7000 + 780y - 5460 = 850y
⇒ 70y = 1540
∴ y = 22
So total number of workers = 22
C
Answer: (C) 22
Question: Two identical machines have the ability to produce both nuts and bolts. However, it takes 1 second to produce a bolt but 2 seconds to produce a nut. What is the fastest the two machines, working together, can produce 800 nuts and 800 bolts?
(A) 1,200 seconds
(B) 1,500 seconds
(C) 1,750 seconds
(D) 2,000 seconds
(E) 3,000 seconds
Rationale: To minimize the amount of time, we should make both machines work all the time while producing 800 nuts and 800 bolts.
Two machines to produce 800 bolts will need (800*1)/2 = 400 seconds.
Two machines to produce 800 nuts will need (800*2)/2 = 8000 seconds.
Total = 400 + 800 = 1,200.
Answer: A.
Answer: (A) 1,200 seconds
Question: There are 7 orators A, B, C, D, E, F and G. In how many ways can the arrangements be made so that A always comes before B and B always comes before C.
(A) 7! / 3!
(B) 8! / 6!
(C) 5! x 3!
(D) 8! / (5! x 3!)
(E) 8! / (5! x 4!)
Rationale: Select any three places for A, B and C. They need no arrangement amongst themselves as A would always come before B and B would always come before C.
The remaining 4 people have to be arranged in 4 places.
Thus, 7C3 x 4! = 7!x4!/(4!x3!)=7!/3!
ANSWER:A
Answer: (A) 7! / 3!
Question: If q=4p where p is a prime number greater than 2, how many different positive even divisors does q have, including q?
(A) two
(B) three
(C) four
(D) six
(E) eight
Rationale: q=2, 2, p (p is in the prime factorization since were told it is a prime number in the question)
2
4 (because of 2*2)
2p (because of 2 * p)
4p (because of 2 * 2 * p)=C
Answer: (C) four
Question: 1398 x 1398
(A) 1954404
(B) 1981709
(C) 18362619
(D) 2031719
(E) None of these
Rationale: 1398 x 1398 = (1398)2
= (1400 - 2)2
= (1400)2 + (2)2 - (2 x 1400 x 2)
= 1954404.
Answer: Option A
Answer: (A) 1954404
Question: If * stands for +, / stands for * and + stands for /, then which of the following equations is TRUE?
(A) 7*14/7+35-14=-4.2
(B) 5+7*7-5/14=24
(C) 14*5/7+35-14=-10.1
(D) 5/7*7+35-14=4
(E) None of these
Rationale: 7*14/7+35-14 will become
7+14*7/35 - 14 = -7 + 14/5 = -21/5 = -4.2
ANSWER:A
Answer: (A) 7*14/7+35-14=-4.2
Question: A firm has 3 senior partners and 6 junior partners. How many different groups of 3 partners can be formed in which at least one member of the group is a senior partner? (2 groups are considered different if at least one group member is different)
(A) 64
(B) 72
(C) 84
(D) 96
(E) 120
Rationale: The total number of ways to form a group of 3 is 9C3 = 84
The number of groups without a senior partner is 6C3 = 20
The number of groups which include a senior partner is 84-20 = 64
The answer is A.
Answer: (A) 64
Question: Peter and Rhea lives some distance apart from each other, separated by a straight road. They both take out their cars and start driving at the same time with the same speed towards each other's home.
After some time, their cars meet at 500 miles away from Peter's house. They keep driving and reach at each other's home. Without stopping by, they turn back and start driving again. This time, they meet 300 miles away from each other's home.
What is the distance between their houses?
(A) 1200 Miles.
(B) 110 Miles.
(C) 1300 Miles.
(D) 1400 Miles.
(E) 1500 Miles.
Rationale: Solution:
Let the distance between Peter's (hereafter referred as P) and Rhea's (hereafter referred as R) be D.
When P and R meet for the first time, P has traveled 500 miles.
In that case, R has traveled (D - 500) miles.
=> Speed of P / Speed of R = 500 / (D - 500) ...... (1)
When P and R meet for the second time, P has traveled (D - 500) + 300 miles
Now, R has traveled (500 + D - 300)
=> Speed of P / Speed of R = 5 / (D - 5) ..... (2)
Equating (1) and (2)
500 / (D - 500) = (D - 2) / (D + 2)
D = 1200 Miles.
Answer A
Answer: (A) 1200 Miles.
Question: A type of extra-large SUV averages 12.2 miles per gallon (mpg) on the highway, but only 7.6 mpg in the city. What is the maximum distance, in miles, that this SUV could be driven on 20 gallons of gasoline?
(A) 190
(B) 284.6
(C) 300
(D) 244
(E) 312
Rationale: so 12.2 * 20 = 244..
IMO option D is correct answer..
Answer: (D) 244
Question: R-R-R-G-G-G-Y-Y-B-R-R-R-G-G-G-Y-Y-B… B-R-R
The preceding is a representation of the different colored beads on a string. The beads follow a repeating pattern and the colors Red, Green, Yellow, and Blue are represented by R, G, Y, and B respectively. Which of the following is a possible number of beads in the missing section of the string represented above?
(A) 62
(B) 63
(C) 64
(D) 65
(E) 66
Rationale: The repeated pattern R-R-R-G-G-G-Y-Y-B has 9 beads.
But the missing section includes R-R-R-G-G-G-Y-Y at the end.
Thus the number of beads in the missing section has the form 9k + 8.
The answer is A.
Answer: (A) 62
Question: If 4 pounds of dried apricots that cost x dollars per pound are mixed with 2 pounds of prunes that cost y dollars per pound, what is the cost, in dollars, per pound of the mixture?
(A) (4x + 2y)/5
(B) (4x + 2y)/(x + y)
(C) (4x + 2y)/(xy)
(D) 5(4x + 2y)
(E) 4x + 2y
Rationale: Total Cost = Weight(in pounds) * Price/pound;
To find Total cost/pound, Divide by total pounds.
Cost of Dried apricots = 4x;
Cost of prunes = 2y;
Cost per pound = (4x + 2y)/5;
Ans is (A).
Answer: (A) (4x + 2y)/5
Question: Once I had been to the post office to buy five-rupee, two-rupee and one-rupee stamps. I paid the clerk Rs. 20, and since he had no change, he gave me three more one-rupee stamps. If the number of stamps of each type that I had ordered initially was more than one, what was the total number of stamps that I bought ?
(A) 10
(B) 9
(C) 12
(D) 8
(E) 4
Rationale: Explanation :
At least two stamps of each type were ordered initially.
So, Rs.2 ( 5 + 2 + 1 ) = Rs.16 have been spent.
That leaves ( 20 – 16 ) = Rs.4.
In this Rs.4, three more stamps of one rupee were given, thus accounting for Rs.19 in all.
Since, one more rupee remains, it means that one more stamps of Rs.1 were bought initially.
So the total number of stamps is 2(of Rs.5) + 2(of Rs.2) + 6(of Rs.1). i.e 10.
Answer : A
Answer: (A) 10
Question: Three unbiased coins are tossed. What is the probability of getting at most two heads?
(A) 3/4
(B) 1/4
(C) 7/8
(D) 3/8
(E) 2/8
Rationale: Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
P(E) =	n(E)	=	7	.
n(S)	8
Answer : C.
Answer: (C) 7/8
Question: What number has a 5:1 ratio to the number 13?
(A) 22
(B) 50
(C) 88
(D) 65
(E) 12
Rationale: 5:1 = x: 13
x = 65
Answer: D
Answer: (D) 65
Question: The average of 20 numbers is zero. Of them, How many of them may be greater than zero, at the most?
(A) 19
(B) 20
(C) 1
(D) 0
(E) 25
Rationale: Avg of 20 nos = 0
sum of 20 numbers/20 = 0
sum of 20 nos = 0
=>19 positive nos
ANSWER A
Answer: (A) 19
Question: In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class ?
(A) 20
(B) 25
(C) 30
(D) Data inadequate
(E) None of these
Rationale: In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively.
say 3x and 2x respectively.
If the number of boys participating in the sports is 15,no of girls participating in sports = 10.
Total students participating out of 60 in class = 15+10=25
Total students not participating out of 60 in class = 60-25=35
The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports.
so out of 45 not participating in sports, 20 are girls and 15 are boys.
No of girls in class = 20+10=30
ANSWER:C
Answer: (C) 30
Question: Lisa earns a profit of $3 on each ribbon that she sells, and $5 on each bracelet. If at the end of the day Lisa has earned $120 and she has sold at least 10 pieces of each item. At least how many bracelets she has sold?
(A) 2
(B) 5
(C) 9
(D) 12
(E) 15
Rationale: Since Lisa has sold at least 10 pieces for each item, let us say Lisa sells (10 + r) number of ribbons and (10 + b) number of bracelets, her profit for the day = 3(10 + r) + 5(10 + b)
=> 3(10 + r) + 5(10 + b) = 120
=> 30 + 3r + 50 + 5b = 120
=> 3r + 5b = 120 - 30 - 50 = 40
=> 5b = 40 - 3r
=> b = 8 - (3/5)r
To minimize b, we need to maximize r and it will be a multiple of 5.
r = 5, b = 8 - (3/5)5 = 5
r = 10, b = 8 - (3/5)10 = 2
Beyond that b will become -ve. So Lisa has sold at least 10 + 2 = 12 bracelets.
Answer: D
Answer: (D) 12
Question: The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 14000, then find the annual income of A?
(A) Rs. 420000
(B) Rs. 180000
(C) Rs. 201600
(D) Rs. 470400
(E) None of these
Rationale: B's monthly income = 14000 * 112/100 = Rs. 15680
B's monthly income = 2 parts ----> Rs. 15680
A's monthly income = 5 parts = 5/2 * 15680 = Rs. 39200
A's annual income = Rs. 39200 * 12 = Rs. 470400
ANSWER:D
Answer: (D) Rs. 470400
Question: If Bill can buy 3 pairs of jeans and 2 shirts for $69 or 2 pairs of jeans and 3 shirts for $61, how much does one shirt cost?
(A) $9
(B) $12
(C) $13.20
(D) $15
(E) $16.80
Rationale: 3J + 2S = 69
2J + 3S = 61
----------------
5J + 5S = 130 ----(divide by 5)---> J + S = 26
3J + 2S = J + 2(J + S) = J + 52 = 69 ---> J = 17
3*17 + 2S = 69
51 + 2S = 69
2S = 18
S = 9
Answer: A
Answer: (A) $9
Question: Every student in a room is either a junior or a senior. There is at least one junior and at least one senior in the room. If 2/3 of the juniors is equal to 1/2 of the seniors, what fraction of the students in the room are juniors?
(A) 3/20
(B) 1/3
(C) 3/7
(D) 2/7
(E) 7/2
Rationale: Let total number of juniors= J
total number of seniors =S
(2/3) J = (1/2) S
=> S = 4/3 J
Total number of students = J+S = (7/3) J
Fraction of the students in the room are juniors = J/(J+S) = J/[(7/3) J]
=3/7
Answer C
Answer: (C) 3/7
Question: If x is a positive integer, which of the following must be odd?
(A) x+1
(B) x^2+x
(C) x^2+x+5
(D) x^2−1
(E) 3x^2−3
Rationale: A. X+1 = can be odd or even. Since O + O =E or E + O = O
B. X^2 + X = X(X+1). Since from the above derivation we already know the term X+1 can be Odd or Even, directly substitute here. X(ODD) = Even (When X is Even) or X(EVEN) = EVEN [When X is ODD]
C. Here's the answer. Since we know the term x^2 + X can always take a EVEN number, EVEN + 5 = ODD
Hence C.
Answer: (C) x^2+x+5
Question: log3 N+log9 N what is 3 digit number N that will be whole number
(A) 629
(B) 729
(C) 829
(D) 929
(E) 727
Rationale: No of values N can take is 1
9^3=729
ANSWER:B
Answer: (B) 729
Question: What least number must be added to 3000 to obtain a number exactly divisible by 19 ?
(A) 2
(B) 19
(C) 9
(D) 4
(E) 8
Rationale: On dividing 3000 by 19, we get 17 as remainder.
Number to be added = (19 - 17) = 2.
ANSWER A 2
Answer: (A) 2
Question: The speed of a boat in upstream is 20 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
(A) 30 kmph
(B) 13 kmph
(C) 65 kmph
(D) 55 kmph
(E) 14 kmph
Rationale: Speed of the boat in still water
= (20+80)/2
= 50 kmph. Speed of the stream
= (80-20)/2
= 30 kmph.
Answer: A
Answer: (A) 30 kmph
Question: The cost of 2 chairs and 3 tables is Rs.1800. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?
(A) 228
(B) 287
(C) 277
(D) 188
(E) 600
Rationale: Explanation:
2C + 3T = 1800 --- (1)
3C + 3T = 1200 --- (2)
Subtracting 2nd from 1st, we get
-C + T = 600 => T - C = 600
Answer:E
Answer: (E) 600
Question: If 3^a - 3^(a-1) = 162 then a(a-1) =
(A) 12
(B) 16
(C) 20
(D) 30
(E) 81
Rationale: It seems like you were really close but you solved for a - 1 instead. I am curious - how did you reason through the question? Perhaps you figured the answer has to be in the form of a(a -1), e.g. (3)(4) = 12. Even then, had you figured a has to be a little bigger (plugging in 4 for a gives you 81 which is too low), So when you reasoned the answer to be 4 you may have plugged the 4 in the (a - 1) exponent place.
Again, a quick plugging in should get you (C) 20 as, the only other answer with consecutive integers as factors is far too big.
Answer: (C) 20
Question: A family has two children. find the probability that both the children are girls given that at least
one of them is a girl?
(A) 1/3
(B) 1/5
(C) 1/7
(D) 1/9
(E) 2/3
Rationale: Let b stand for boy and g for girl. The sample space of the experiment is
S = {(g, g), (g, b), (b, g), (b, b)}
Let E and F denote the following events :
E : ‘both the children are girls’
F : ‘at least one of the child is a girl’
Then E = {(g,g)} and F = {(g,g), (g,b), (b,g)}
Now E n F = {(g,g)}
Thus P(F) = 3/4
and P (E n F )= 1/4
Therefore P(E|F) = P(E ∩ F)/P(F) = (1/4)/(3/4) = 1/3
A)
Answer: (A) 1/3
Question: A certain company’s profit in 1996 was 17 percent greater than its profit in 1995, and its profit in 1997 was 25 percent greater than its profit in 1996. The company’s profit in 1997 was what percent greater than its profit in 1995?
(A) 5%
(B) 18%
(C) 33%
(D) 35%
(E) 46.25%
Rationale: Profit in 1995 - 100
Profit in 1996 - 117
%increae Profit in 1997 in comparison to 1995 = 17 + 117*25%= 46.25
Correct Option : E
Answer: (E) 46.25%
Question: What is the measure of the radius of the circle that circumscribes a triangle whose sides measure 5, 12 and 13?
(A) 2.5
(B) 6.5
(C) 5
(D) 6.0
(E) 7
Rationale: Some of pyhtagron triplets we need to keep it in mind.
Like {( 2,3,5) , ( 5,12,13) ,( 7, 24,25), ( 11, 60,61).
So now we know the triangle is an right angle triangle. The circle circumscribes the triangle.
The circumraduis of the circle that circumscribes the right angle triangle = hypotanse / 2 = 13 / 2 = 6.5
Ans. B
Answer: (B) 6.5
Question: {-10, -6, -5, -4, -2.5, -1, 0, 2.5, 4, 6, 7, 10}
A number is to be selected at random from the set above. What is the probability that the number will be a solution to the equation (x-5)(x+4)(2X+5) = 0?
(A) a) 1/12
(B) b) 1/6
(C) c) 1/4
(D) d) 1/3
(E) e) 1/2
Rationale: x = -1
Prob = 1/12
Answer - A
Answer: (A) a) 1/12
Question: One drier dries certain quantity of material in 24 minutes. Another drier does the same work in 2 minutes how much time will it take to do the same job when both driers are put to work ?
(A) 1.00 minutes
(B) 1.20 minutes
(C) 1.50 minutes
(D) 1.85 minutes
(E) 2.00 minutes
Rationale: By guess it is clear that the time taken will be less than 2 minutes and more than 1.5 mintes Therefore, answer 1.85 minutes will be correct. Answer-D
Answer: (D) 1.85 minutes
Question: How many integers from 101 to 700, inclusive, remains the value unchanged when the digits were reversed?
(A)  50
(B)  60
(C)  70
(D)  80
(E)  90
Rationale: question is asking for palindrome
first digit possibilities - 1 through 6 = 6
7 is not possible here because it would result in a number greater than 7 (i.e 707 , 717..)
second digit possibilities - 0 though 9 = 10
third digit is same as first digit
=>total possible number meeting the given conditions = 6*10 =60
Answer is B.
Answer: (B)  60
Question: A restaurant meal cost $55 and there was no tax. If the tip was more than 20 percent but less than 30 percent of the cost of the meal, then total amount paid must have been between:
(A) $65 and $72
(B) $66 and $71
(C) $64 and $71
(D) $63 and $70
(E) $67 and $73
Rationale: let tip=t
meal cost=55
range of tip = from 20% of 55 to 30% of 55 = 11 to 16.5
hence range of amount paid= 55+T= 66 to 71.5 i.e. A
Answer: (A) $65 and $72
Question: A train 180 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
(A) 7
(B) 10
(C) 8
(D) 2
(E) 4
Rationale: Speed of train relative to man = 60 + 6 = 66 km/hr.
= 66 * 5/18 = 55/3 m/sec.
Time taken to pass the men = 180 * 3/55
= 10 sec.
Answer B
Answer: (B) 10
Question: List I: 3, 6, 8, 10
List II: x, 3, 6, 8, 10
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
Rationale: List I has even number of terms, thus its median is the average of two middle terms (when arranged in ascending/descending order), so median=(6+8)/2=7.
List II has odd number of terms, thus its median is the middle term (when arranged in ascending/descending order). As no other number in the list equal to 7, then x=7.
Answer: A.
Answer: (A) 7
Question: Consider the word RMTMR. Whichever way you read it, from left to right or from right to left, you get the same word. Such a word is known as palindrome. Find the maximum possible number of 5 letter palindromes.
(A) 15343
(B) 16423
(C) 17576
(D) 17809
(E) 18790
Rationale: The first letter from the right can be chosen in 26 ways because there are 26 alphabets.
Having chosen this, the second letter can be chosen in 26 ways
The first two letters can chosen in 26 x 26 = 676 ways
Having chosen the first two letters, the third letter can be chosen in 26 ways.
All the three letters can be chosen in 676 x 26 =17576 ways.
It implies that the maximum possible number of five letter palindromes is 17576 because the fourth letter is the same as the second letter and the fifth letter is the same as the first letter.
C
Answer: (C) 17576
Question: Look at this series: (1/9), (1/3), 1, ____ , 9, ... What number should fill the blank?
(A) 3
(B) 4
(C) 1
(D) 6
(E) 9
Rationale: A
3
This is a multiplication series; each number is 3 times the previous number.
Answer: (A) 3
Question: A pipe takes a hours to fill the tank. But because of a leakage it took 4 times of its original time. Find the time taken by the leakage to empty the tank
(A) 50 min
(B) 60 min
(C) 90 min
(D) 80 min
(E) 70 min
Rationale: pipe a can do a work 60 min.
lets leakage time is x;
then
1/60 -1/x=1/240
x=80 min
ANSWER:D
Answer: (D) 80 min
Question: The G.C.D. of 1.08, 0.36 and 0.5 is:
(A) 0.02
(B) 0.9
(C) 0.18
(D) 0.108
(E) 0.118
Rationale: Given numbers are 1.08, 0.36 and 0.50. H.C.F. of 108, 36 and 50 is 18,
H.C.F. of given numbers = 0.02.
Answer: Option A
Answer: (A) 0.02
Question: The average age of 10 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is
(A) 22
(B) 30
(C) 99
(D) 38
(E) 32
Rationale: total age increased = (10 * 2) years = 20 years.
Sum of ages of two new men = (21 + 23 + 20) years = 64 years
Average age of two new men = (64/2) years = 32 years.
Answer: E
Answer: (E) 32
Question: A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and received Rs.1760 in all from both of them as interest. The rate of interest per annum is?
(A) 16%
(B) 12%
(C) 74%
(D) 10%
(E) 8%
Rationale: Let the rate be R% p.a. Then,
(5000 * R * 2)/100 + (3000 * R * 4)/100 = 1760
100 R + 120 R = 1760
R = 8%
Answer:E
Answer: (E) 8%
Question: (17)5.5 x (17)? = 178
(A) 2.29
(B) 2.75
(C) 4.25
(D) 4.5
(E) None of these
Rationale: Solution
let (17)5.5 * (17)x = 178. then, (17)5.5 + x = (17)8.
∴ 5.5 + x = 8 ⇔ x = (8 - 5.5) ⇔ x = 2.5
Answer E
Answer: (E) None of these
Question: A man buys an article for 10% less than its value and sells it for 10% more than its value. His gain or loss percent is:
(A) 70%
(B) 80%
(C) 90%
(D) 20%
(E) 10%
Rationale: Explanation:
Let the article be worth Rs. x.
C.P. 90% of Rs. x = Rs. 9x/10
S.P. = 110% of Rs. x = Rs. 11x/10
Gain = (11x/10 - 9x/10) = Rs. x/5
Gain % = x/5 * 10/9x * 100 = 22 2/9 % > 20%
Answer:D
Answer: (D) 20%
Question: A can do a piece of work in 16 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in ?
(A) 3 days
(B) 4 days
(C) 6 days
(D) 7 days
(E) 11 days
Rationale: B's 9 day's work = 9 x (1/12) = 3/4
Remaining work = (1 - 3/4) = 1/4
1/4 work is done by A in = 16 x (1/4) = 4 days.
answer : B
Answer: (B) 4 days
Question: Find the sub-triplicate ratio of 27:125
(A) 3:5
(B) 3:9
(C) 3:6
(D) 3:1
(E) 3:2
Rationale: The sub-triplicate ration of 27 : 125 = 3:5
Answer:A
Answer: (A) 3:5
Question: the profit of certain article is 25 percent.had it been bought at 10 percent discount and sold for 20 percent more than the earliest cost,the profit would have been rs600.what is the cost price of the article.
(A) 1800
(B) 2000
(C) 2200
(D) 2400
(E) 2600
Rationale: Let CP be x
Gain% = 25%
Then SP = x*125/100
SP = 5x/4
If it had been bought at 10% discount
Then CP = x*90/100
CP = 9x/10
sold at 20% more that the earliest cost... [earliest cost means x]
Then SP = x*120/100 = 600+9x/10
6x/5 = 6000+9x/10
12x = 6000+9x
3x = 6000
x = 2000
ANSWER:B
Answer: (B) 2000
Question: A dishonest shopkeeper deceives by 15% at the time of purchase of article and also 15% at the time of sale.Find out the profit percentage
Profit%
(A) 32.25%.
(B) 32
(C) 42.25%
(D) 42
(E) 50
Rationale: Solution
=15+15+(15*15 / 100)=30 + 225/100 =30+2.25=32.25%.
Answer A
Answer: (A) 32.25%.