mathewhe/aqua_rat huggingface dataset:
Question: There are 200 questions in a 3 hr examination. Among these questions there are 50 mathematics problems. It is suggested that twice as much time be spent on each maths problem as for each other question. How many minutes should be spent on mathematics problems
(A) 36 minutes
(B) 60 minutes
(C) 72 minutes
(D) 100 minutes
(E) None of these
Rationale: Explanation :
Let x = minutes spent on a non-math problem
then 2x = minutes spent on a math problem
x(200-50) + 2x(50) = 180
x(150) + 2x(50) = 180
150x + 100x = 180
250x = 180
x = 0.72 minutes
Time to spend on math problems:
2x(50)=100x = 100(0.72) = 72 minutes
Answer : C
Answer: (C) 72 minutes
Question: The Income of a man increase consistently by 2% per year. If his present income is Rs. 12000 then what will his income be after 1 year ?
(A) 12040
(B) 12140
(C) 12240
(D) 12340
(E) 12440
Rationale: Explanation :
Income = 12000 x 1.02 = 12240
Answer : Option C
Answer: (C) 12240
Question: Two men started from the same place walk at the rate of 5kmph and 5.5kmph respectively. What time will they take to be 8.5 km apart, if they walk in the same direction?
(A) 10hours
(B) 12hours
(C) 17hours
(D) 15hours
(E) 20hours
Rationale: To be 0.5km apart they take 1 hour
To be 8.5km apart they take = 1/0.5 * 8.5 = 17 hours
Answer is C
Answer: (C) 17hours
Question: What distance (in meters) will be covered by a bus moving at 54 km/hr in 30 seconds?
(A) 390
(B) 420
(C) 450
(D) 480
(E) 510
Rationale: 54 km/hr = 54 * 5/18 = 15 m/s
distance = 15 * 30 = 450 meters
The answer is C.
Answer: (C) 450
Question: A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1800. The difference between the profit shares of A and C is?
(A) 720
(B) 266
(C) 155
(D) 600
(E) 441
Rationale: Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit share of B is Rs. 1800
=> 5 parts out of 15 parts is Rs. 1800
Now, required difference is 6 - 4 = 2 parts
Required difference = 2/5 (1800) = Rs. 720
Answer:A
Answer: (A) 720
Question: A total of $20,000 was invested in two certificates of deposit at simple annual interest rates of 6 percent and 10 percent, respectively. If the total interest on the two certificates was $1,440 at the end of one year, what fractional part of the $20.000 was invested at the higher rate?
(A)  3/8
(B)  9/10
(C)  1/2
(D)  3/5
(E)  3/4
Rationale: x * 6/100 * 1 + (20000 - x) * 10/100 * 1 = 1440
6x - 8x = 144000 - 200000
=> -2x = -4000
=> x = 2000
So 18000/20000 = 9/10
Answer - B
Answer: (B)  9/10
Question: The sale price sarees listed for Rs.400 after successive discount is 25% and 20% is?
(A) 297
(B) 879
(C) 342
(D) 240
(E) 269
Rationale: 400*(75/100)*(80/100)
= 240
Answer: D
Answer: (D) 240
Question: A bus travels from town A to town B. If the bus's speed is 50 km/hr, it will arrive in town B 42 min later than scheduled. If the bus increases its speed by 509509 m/sec, it will arrive in town B 30 min earlier than scheduled. Find:
A) The distance between the two towns;
B) The bus's scheduled time of arrival in B;
C) The speed of the bus when it's on schedule.
(A) 60
(B) 37
(C) 26
(D) 28
(E) 11
Rationale: First we will determine the speed of the bus following its increase. The speed is increased by 509509 m/sec =50⋅60⋅6091000=50⋅60⋅6091000 km/hr =20=20 km/hr. Therefore, the new speed is V=50+20=70V=50+20=70 km/hr. If xx is the number of hours according to the schedule, then at the speed of 50 km/hr the bus travels from A to B within (x+4260)(x+4260) hr. When the speed of the bus is V=70V=70 km/hr, the travel time is x−3060x−3060 hr. Then
50(x+4260)=70(x−3060)50(x+4260)=70(x−3060)
5(x+710)=7(x−12)5(x+710)=7(x−12)
72+72=7x−5x72+72=7x−5x
2x=72x=7
x=72x=72 hr.
So, the bus is scheduled to make the trip in 33 hr 3030 min.
The distance between the two towns is 70(72−12)=70⋅3=21070(72−12)=70⋅3=210 km and the scheduled speed is 210/7/2=60 km/hr.
Answer:A
Answer: (A) 60
Question: If x = |x| , then which one of the following statements could be true?
I. x = 0
II. x < 0
III. x > 0
(A)  None
(B)  I only
(C)  III only
(D)  I and II and III
(E)  II and III
Rationale: Answer copied from NOVA guide
Statement I could be true because ± 0 = −(+0) = −(0) = 0 .
Statement II could be true because the right side of the equation is always negative [ ± x = (a positive number) = a negative number].
Now, if one side of an equation is always negative, then the other side must always be negative,
otherwise the opposite sides of the equation would not be equal.
Since Statement III is the opposite of Statement II, it must be false. But let’s show this explicitly:
Suppose x were positive. Then x = x, and the equation x = ± x becomes x = x. Dividing both sides of this equation by x yields 1 = 1. This is contradiction.
Hence, x cannot be positive. The answer is (D).
Answer: (D)  I and II and III
Question: Maddie has 24 apples, if she give 12 to mike, how many does she have left?
(A) 12
(B) 14
(C) 16
(D) 18
(E) 5
Rationale: 24-12=12
A 12
Answer: (A) 12
Question: A stick of 30 cm is broken into two pieces, what is the length of the shorter piece if the longer piece is 6 cm longer than the other?
(A) 11
(B) 10
(C) 12
(D) 13
(E) 7
Rationale: Since, 30 is the total length. Smaller is any one from answers.
Try Back solving from answer D, i.e. 12. 12+(12+6) = 31 > 30
Hence, Select next smaller no. : 12 +(12+6) =30.
So, 12 is the answer
Answer is C
Answer: (C) 12
Question: A shopkeeper sold an article for Rs 2552.36. Approximately what was his profit percent if the cost price of the article was Rs 2400
(A) 4%
(B) 5%
(C) 6%
(D) 7%
(E) 8%
Rationale: Explanation:
Gain % = (152.36*100/2400) = 6.34 % = 6% approx
Option C
Answer: (C) 6%
Question: 2,5,10,17,?,41
(A) 26
(B) 27
(C) 29
(D) 25
(E) 28
Rationale: 2+3=5
5+5=10
10+7=17
17+11=28
28+13=41
ANSWER:E
Answer: (E) 28
Question: A train 110 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
(A) 5
(B) 6
(C) 7
(D) 9
(E) 2
Rationale: Speed of train relative to man = 60 + 6 = 66 km/hr.
= 66 * 5/18 = 55/3 m/sec.
Time taken to pass the men = 110 * 3/55 = 6 sec.
Answer: B
Answer: (B) 6
Question: Irin, Ingrid and Nell bake chocolate chip cookies in the ratio of 9.18: 5.17: 2.05. If altogether they baked a batch of 148 cookies, what percent of the cookies did Nell bake?
(A) 0.125%
(B) 1.25%
(C) 12.5%
(D) 125%
(E) 0.152%
Rationale: 9.18x+5.17x+2.05x = 16.4x = 148 cookies
x= 148/16.4 = 9 (approx)
So, tell baked 9*2.05 cookies or 19 cookies (approx)
% share = 19/148 = 12.5 approx
Hence, answer is C.
Answer: (C) 12.5%
Question: On adding four times the age of Chris Hemsworth four years from now to five times his age five years from now, we will get ten times his current age.
How old is Chris right now?
(A) 38 years
(B) 24 years
(C) 40 years
(D) 41 years
(E) 29 years
Rationale: D
41 years.
If the current age of Dakota is x
4(x+4) + 4(x+5) = 10x
Thus x=41 years
Answer: (D) 41 years
Question: If a, b, c are integers; a² + b² = 45 and b² + c² = 40, then the values of a, b and c respectively are :
(A) 2, 6, 3
(B) 3, 2, 6
(C) 5, 4, 3
(D) 4,5,3
(E) None of these
Rationale: a² + b² = 45 ….(1) and b² + c² = 40
Subtracting, we get: a² - c² = 5 => (a + c) (a – c) = 5.
(a + c) = 5 and (a – c) = 1.
Solving we get: a = 3, c = 2. Putting c = 2 in (ii), we get b = 6.
ANSWER:B
Answer: (B) 3, 2, 6
Question: in a powder mix two varieties of powders costing Rs. 15 and Rs. 20 per kg respectively so as toget a mixture worth Rs. 16.50 kg?
(A) 1:3
(B) 2:5
(C) 7 : 3
(D) 7:5
(E) 5:8
Rationale: By the rule of alligation:
Cost of 1 kg pulses of 1st kindCost of 1 kg pulses of 2nd kind
Rs. 15	Mean Price
Rs. 16.50	Rs. 20
3.50	1.50
Required rate = 3.50 : 1.50 = 7 : 3
C
Answer: (C) 7 : 3
Question: A jar full of whisky contains 40% alcohol. A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is:
(A) 1/3
(B) 2/3
(C) 2/5
(D) 3/5
(E) 4/5
Rationale: Explanation:
By the rule of alligation, we have:
So, ratio of 1st and 2nd quantities = 7 : 14 = 1 : 2
Required quantity replaced =2/3.
ANSWER IS B
Answer: (B) 2/3
Question: Find the odd man out. 1050, 510, 242, 108, 46, 16, 3
(A) 46
(B) 106
(C) 510
(D) 108
(E) None of these
Rationale: Explanation :
1050
(1050 - 30)/2 = 510
(510 - 26)/2 = 242
(242 - 22)/2 = 110
(110 - 18)/2 = 46
(46- 14)/2 = 16
(16- 10)/2 = 3
Hence, 110 should have come in place of 108. Answer : Option D
Answer: (D) 108
Question: Mangala completes a piece of work in 20 days, Raju completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is
(A) 4 days
(B) 6 days
(C) 13.33 days
(D) 10 days
(E) 11 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 20 × 40/60 = 13.33 days.
Answer : C
Answer: (C) 13.33 days
Question: From the set of numbers {p, t, u, v, w, x, y, z}, how many different combinations can we have without the t in them? Ex:. (x,y), (x), (w,z,y,x), etc... and note that (x,y)=(y,x)
(A) 32
(B) 63
(C) 64
(D) 127
(E) 128
Rationale: Any letter (p, u, v, w, x, y, z) can be included or not.
Thus there are 2^7 combinations - 1 empty combination = 127 combinations
The answer is D.
Answer: (D) 127
Question: How much 60% of 50 is greater than 40% of 30?
(A) 18
(B) 99
(C) 77
(D) 66
(E) 12
Rationale: (60/100) * 50 – (40/100) * 30
30 - 12 = 18ch 60% of 50 is greater than 40% of 30?
Answer:A
Answer: (A) 18
Question: In a Private Company 20 Nos. staffs are employed. In a Festival season their Boss give festival allowance to all. He says his accountant to calculate for 30 days @ 100. Also he says balance payment will give to driver and cleaning staff and to be adjust from petty cash. He had given Rs.65000/- to the accountant. How much amount will taken from Petty cash?
(A) A)1000
(B) B)3000
(C) C)3500
(D) D)2500
(E) E)2250
Rationale: For 20 staffs: 300*100*20 = 60000
for driver and cleaning staff: 300*100*2 =6000
From petty Cash : 1000
Answer is 1000 Answer is A
Answer: (A) A)1000
Question: How many triangles can be formed by joining vertices of a hexagon?
(A) 20
(B) 30
(C) 40
(D) 60
(E) 10
Rationale: One triangle is formed by selecting group of three vertices from 6 vertices of a hexagon.This can be done in 6C3 ways. ie) 6!/3!x3!=20 ways. Ans : A
Answer: (A) 20
Question: A student chose a number, multiplied it by 2, then subtracted 138 from the result and got 104. What was the number he chose?
(A) 123
(B) 121
(C) 277
(D) 267
(E) 120
Rationale: Let xx be the number he chose, then
2â‹…xâˆ’138=104 2â‹…xâˆ’138=104
x=121
Answer:B
Answer: (B) 121
Question: What is the next number of the following sequence
8, 24, 12, 36, 18, 54 (...)
(A) 30
(B) 32
(C) 34
(D) 36
(E) 38
Rationale: The series is
4*4=16
16/2=8
8*4=32
32/2=16
16*4=64
64/2=32
ANSWER: B
Answer: (B) 32
Question: What is the total number of W integers between 100 and 200 that are divisible by 3?
(A)  33
(B)  32
(C)  31
(D)  30
(E)  29
Rationale: yes there is a different way of arriving at that answer ....
u can also use arithmetic progression to get the answer
since the first term to be divisble by 3 is 102 ..take that as A .. the starting no
and since 198 is the last digit to be divisible by 3 take that as N ...
since the difference is 3 take that as D
no u have to find what term is 198 take that as nth term
the formula for that is N = A + (n-1) * d
198 = 102 +(n-1) * 3
from this u get n =33
Answer: (A)  33
Question: An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is 81 times the difference between the two numbers. How many coins did the old man have?
(A)  24
(B)  26
(C)  30
(D)  81
(E)  40
Rationale: Let the number of coins one son got be x and the number of coins another got be y. Total = x + y.
x^2 - y^2 = 81(x - y) --> x + y = 81.
Answer: D.
Answer: (D)  81
Question: Which of the following is equal to the cube of a non-integer?
(A) -64
(B) -1
(C) 8
(D) 9
(E) 27
Rationale: A. -64 -> cube of -4
B. -1 -> cube of -1
C. 8 -> cube of 2
D. 9
E. 27 -> cube of 3
All other options are cubes of integers except 9. 9 will be the cube of a number slightly greater than 2 since the cube of 2 is 8.
Answer (D)
Answer: (D) 9
Question: The speed of a train is 90 kmph. What is the distance covered by it in 10 minutes?
(A) 15
(B) 66
(C) 77
(D) 52
(E) 42
Rationale: 90 * 10/60 = 15 kmph
Answer:A
Answer: (A) 15
Question: The fourth proportional to 5, 8, 15 is:
(A) 15
(B) 5
(C) 24
(D) 8
(E) 28
Rationale: Let the fourth proportional to 5, 8, 15 be x.
Then, 5 : 8 : 15 : x
= 5x = (8 x 15)
x = (8 x 15)/5= 24.
Answer is C.
Answer: (C) 24
Question: If the tens digit of positive integer x is 4 and the tens digit of positive integer y is 4, how many possible values of the tens digit of 2(x+y) can there be?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: We only need to consider the tens and ones digits of x and y, and the last two digits can be represented as 40 + p and 40 + q respectively.
2(40+p+40+q)= 160 + 2(p + q)
2(p+q) can range from 0 up to a maximum value of 36 when p=q=9.
Then the tens and ones digits of 2(x+y) can range from 60 up to 96.
There can be 4 possibilities for the tens digit.
The answer is C.
Answer: (C) 4
Question: Sophia finished 23 of a book. She calculated that she finished 90 more pages than she has yet to read. How long is her book?
(A) 180
(B) 200
(C) 250
(D) 270
(E) 300
Rationale: Let x be the total number of pages in the book, then she finished 23⋅x pages.
Then she has x−23⋅x=13⋅x pages left.
23⋅x−13⋅x=90
13⋅x=90
x=270.
So answer is D.
Answer: (D) 270
Question: How many seconds will a 300 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
(A) 11
(B) 30
(C) 99
(D) 88
(E) 18
Rationale: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 300 * 3/50 = 18 sec.
Answer: E
Answer: (E) 18
Question: Evaluate 28% of 450 + 45% of 240
(A) 232
(B) 242
(C) 252
(D) 262
(E) 234
Rationale: Explanation:
= (28/100) * 450 + (45/100) * 240
= 126 + 108 = 234
Answer: Option E
Answer: (E) 234
Question: There are 10 people in a room. If each person shakes hands with exactly 3 other people, what is the total number of handshakes?
(A) 15
(B) 30
(C) 45
(D) 60
(E) 120
Rationale: 4 people: shrive 555, cranky, karishma and Mr X
We have to shake hands in this group such that each person shakes hands with 3 people.
So shrive555 starts:
shrive555 - craky : 1 handshake but 2 hands were shaken. shrive 555's and cranky's
shrive 555 - karishma : 1 handshake but 2 hands were shaken. shrive 555's and karishma's
shrive 555 - Mr X : 1 handshake but 2 hands were shaken. shrive 555's and Mr X's
Now shrive 555 has shaken hands with 3 people. There were 3 handshakes. But 6 hands were shaken.
Now, when all 4 of us shake hands with 3 people, each person's hand will be shaken 3 times. i.e. in all 12 hands will be shaken. But they will add up to only 6 handshakes.
The other 3 handshakes will be:
cranky - karishma
cranky - Mr X
karishma - Mr X
So all of us have shaken hands with exactly 3 people.
Similarly when there are 10 people, each person shakes his hand 3 times. So in all 30. But 2 of these hands combined to make one handshake. So we will get only 15 total handshakes.
ANSWER:A
Answer: (A) 15
Question: A farmer divides his herd of x cows among his 4 sons so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 7 cows. Then x is equal to
(A) 100
(B) 140
(C) 180
(D) 160
(E) 120
Rationale: no. of cows:: x
1st son: x/2
2nd son: x/4
3rd son: x/5
4th son: 7
(x)+(x/4)+(x/5)+7=x
=> x - (19x/20)=7
=> (20x-19x)/20=7
=> x =140
ANSWER:B
Answer: (B) 140
Question: Which of the following is closest to (5!-4!)/(5!+4!)?
(A) 0.01
(B) 0.1
(C) 0.2
(D) 0.7
(E) 10
Rationale: (5!-4!)/(5!+4!)
4! (5-1)/4! (5+1)
4/6 = 2/3 =0.7 (approximately)
D is the answer
Answer: (D) 0.7
Question: Given that -1 ≤ v ≤ 1, -2 ≤ u ≤ -0.5, and -2 ≤ z ≤ -0.5 and w = vz/u, then which of the following is necessarily true ?
(A) -0.5 ≤ w ≤ -2
(B) -4 ≤ w ≤ 4
(C) -4 ≤ w ≤ 2
(D) -2 ≤ w ≤ -0.5
(E) None of these
Rationale: Explanation :
u is always negative. Hence, for us to have a minimum value of vz/u , vz should be positive.
Also for the least value, the numerator has to be the maximum positive value and the denominator has to be the smallest negative value. In other words, vz has to be 2 and u has to be –0.5.
Hence the minimum value of vz/u = 2−0.5 = –4.
For us to get the maximum value, vz has to be the smallest negative value and u has to be the highest negative value.
Thus, vz has to be –2 and u has to be –0.5. Hence the maximum value of vz/u = 2 / -0.5 = 4.
Answer : B
Answer: (B) -4 ≤ w ≤ 4
Question: How many six-digit numbers are there such that all six digits are different and the first digit is not zero?
(A) 472392
(B) 648421
(C) 720756
(D) 729951
(E) 810364
Rationale: All six digits are different and first digit is not zero.
So first digit can be filled in 9 ways.
And, second digit can be filled in 9 ways.
And, third digit can be filled in 9 ways.
And, fourth digit can be filled in 9 ways.
And, fifth digit can be filled in 9 ways.
And, sixth digit can be filled in 8 ways.
Total ways = 9*9*9*9*9*8
= 472392
Hence option (A).
Answer: (A) 472392
Question: Tickets numbered from 1 to 20 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bearsa number which is a multiple of 3?
(A) 1/11
(B) 2/13
(C) 3/10
(D) 4/15
(E) 5/16
Rationale: Here, S = [1, 2, 3, 4, …., 19, 20]
Let E = event of getting a multiple of 3 = [3, 6, 9, 12, 15, 18]
P (E) = n (E) / n (S) = 6 / 20 = 3/10
C
Answer: (C) 3/10
Question: You have been given a physical balance and 7 weights of 52, 50, 48, 44, 45, 46 and 78 kgs. Keeping weights on one pan and object on the other, what is the maximum you can weigh less than 183 kgs.
(A) 180
(B) 181
(C) 182
(D) 183
(E) 184
Rationale: 52+50+78 = 180
Answer: A
Answer: (A) 180
Question: In the class of 40 students, 30 speak Hindi and 20 speak English. What is the lowest possible number of students who
speak both the languages?
(A) 10
(B) 15
(C) 20
(D) 25
(E) 30
Rationale: let the student who speaks hindi-x
let the student who speaks english-y
as (xuy)-(xny)=total
30+20-(xny)=40
=10
A)
Answer: (A) 10
Question: Find the next number in the Sequence
5, 14, 41, 86, ?
(A) 146
(B) 145
(C) 149
(D) 143
(E) 148
Rationale: +9 =>14
+27 =>41
+45 =>86
+63 =>149
Answer is C
Answer: (C) 149
Question: Choose the missing terms out of the given alternatives.
AZ, GT, MN, ?, YB
(A) KF
(B) RX
(C) TS
(D) FM
(E) SH
Rationale: E
SH
First letter moves 6 steps forward. Second letter moves 6 steps backward.
Answer: (E) SH
Question: The diameter of the driving wheel of a bus in 140 cm. How many revolutions per minute must the wheel make in order to keep a speed of 33 kmph?
(A) 210
(B) 220
(C) 125
(D) 240
(E) 250
Rationale: distance covered in 1 min=(33*1000)/60=550m
circumference of the wheel=(2*(22/7)*.70)=4.4m
no of revolution per min=550/4.4=125
ANSWER:C
Answer: (C) 125
Question: In an election between two candidates, one got 45% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 2000, the number of valid votes that the other candidate got, was:
(A) 1500
(B) 4500
(C) 3270
(D) 1100
(E) 4000
Rationale: Number of valid votes = 80% of 2000= 1600.
Valid votes polled by other candidate = 55% of 2000
=(55/100)X2000 =1100
ANSWER =D
Answer: (D) 1100
Question: If four coins are tossed, the probability of getting two heads and two tails is
(A) 3/8
(B) 3/9
(C) 3/6
(D) 3/1
(E) 3/3
Rationale: Explanation:
Since four coins are tossed, sample space = 24
Getting two heads and two tails can happen in six ways.
n(E) = six ways
p(E) = 6/24 = 3/8
Answer:A
Answer: (A) 3/8
Question: A person bought an article and sold it at a loss of 10%. If he had bought it for 20% less and sold it for Rs.55 more he would have had a profit of 40%. The cost price of the article is___
(A) 125
(B) 150.5
(C) 112.5
(D) 113
(E) None
Rationale: now x is CP
sold it at a loss of 10%=90x/100=9x/10
bought it for 20% less=80x/100=4x/5
profit 40%of 4x/5=140x/100*4x/5=56x/50
56x/50-9x/10=55rs
560x-450x/500=55rs
110x/500=55rs
x=500*55/110
x=27500/110=250
x=250
ANSWER:E
Answer: (E) None
Question: A can do a job in 30days and B in 40days. If they work on it together for 10 days, then the fraction of the work that is left is?
(A) 2/11
(B) 3/13
(C) 5/12
(D) 7/10
(E) 6/15
Rationale: A's 1 day work = 1/30
B's 1day work = 1/40
A+B 1day work = 1/30 + 1/40 = 7/120
A+B 4days work = 7/120*10 = 7/12
Remaining work = 1 - 7/12 = 5/12
Answer is C
Answer: (C) 5/12
Question: A motor cycle is moving with the speed of 47.52 km/hr and the radius of the wheel of the motorcycle is 21 cms. Calculate the approximate no of revolutions made by the wheel in one minute.
(A) 400 rpm
(B) 500 rpm
(C) 600 rpm
(D) 700 rpm
(E) 800 rpm
Rationale: Given Speed = 47.52 km/h = 47.52 * 1000/60 m/s
= 792 metre/minute
the radius of the wheel of the motorcycle = 21 cm
circumference of the wheels = 2*22/7*21 = 132cm = 1.32 m
Number of revolutions made by the wheel in one minute
= Speed (in metre/minute)/circumference(in m)
= 792/1.32 = 600
So no of revolutions made by the wheel in one minute will be 600
ANSWER:C
Answer: (C) 600 rpm
Question: Three persons invested Rs.9000 in a joint business. The second person invested Rs.1000 more than the first and the third Rs.1000 more than second. After two years, they gained Rs.2700. How much third person will get?
(A) 2400
(B) 2429
(C) 2980
(D) 1200
(E) 2872
Rationale: First persons investment = x
Second persons investment = x + 1000
Third persons investments = x + 2000
x + x + 1000 + x + 2000 = 9000
3x = 6000
x = 2000
Ratio = 2000 : 3000 : 4000
2:3:4
4/9 * 2700 = 1200
Answer:D
Answer: (D) 1200
Question: A car takes 6 hours to cover a distance of 469 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
(A) 48 Kmph
(B) 50 Kmph
(C) 52 Kmph
(D) 56 Kmph
(E) 60 Kmph
Rationale: Time = 6
Distence = 469
3/2 of 6 hours = 6 * 3/2 = 9 Hours
Required speed = 469/9 = 52 Kmph
C
Answer: (C) 52 Kmph
Question: when W is divided by 14, the reminder is 0. if W is three lesser than it value and when divided by 5 its remainder is 0. what is the value of W ?
(A) 14
(B) 28
(C) 42
(D) 45
(E) 33
Rationale: W is divided by 14 so that is multiple of 14 as 14,28,42...
W-3 is divided by 5 the remainder is 0 so it is divisible by 5. Consider from option let us take the number is 14 it is divisible by 14 but 14-3 is not divisible by 5 so it is not answers so let us take 2nd option 28 which is divisible by 14 and 28-3=25 is divisible by 5 so ans is B
Answer: (B) 28
Question: Sarah signed 1/2 of the Christmas cards, and Richard signed 3/8 of them. If there are 32 cards in
all, how many are left to be signed?
(A) 6
(B) 7
(C) 4
(D) 9
(E) 2
Rationale: 1/2 x 32 = 16 Sarah signed
3/8 x 32 = 12 Richard signed
16 + 12 = 28 are signed
32 - 28 = 4 cards left to be signed
correct answer C
Answer: (C) 4
Question: The population of a city is 8000. It decreases annually at the rate of 20% p.a. What will be its population after 2 years?
(A) 1000
(B) 1200
(C) 1250
(D) 3000
(E) 5120
Rationale: Formula :
( After =100 denominator
Ago = 100 numerator)
8000 × 80/100 × 80/100 = 5120
E
Answer: (E) 5120
Question: A man buys an article for Rs. 27.50 and sells it for Rs 28.60. Find his gain percent
(A) 1%
(B) 2%
(C) 3%
(D) 4%
(E) 5%
Rationale: Explanation:
So we have C.P. = 27.50
S.P. = 28.60
Gain = 28.60 - 27.50 = Rs. 1.10
Gain%=(GainCost∗100)%=(1.1027.50∗100)%=4%
ANSWER IS D
Answer: (D) 4%
Question: What is the ratio between perimeters of two squares one having 3 times the diagonal then the other?
(A) 3: 5
(B) 3: 9
(C) 3: 4
(D) 3: 1
(E) 3: 2
Rationale: d = 3d d = d
a√2 = 3d a√2 = d
a = 3d/√2 a = d/√2 => 3: 1
Answer: D
Answer: (D) 3: 1