mathewhe/aqua_rat huggingface dataset:
Question: A house is getting ready for dinner table. There are 15 members in the family, and the butler must assign 10 people to the following positions: 1 main chair, 4 on left side, 4 on right side, and 1 most further away seat. Only 3 of the family members are elderly enough to sit on the main chair, and they will not sit at any other place. The other members can sit on any seat. How many different groupings are possible?
(A) 64585
(B) 100
(C) 80
(D) 59400
(E) 789300
Rationale: 3C1 select 1 for main chair from 3 elderly people;
12C4 select 4 people for left side chairs from 12 members (as 3 elderly would like to sit only on main chair 15-3=12);
8C4 select 4 people for right side chair from 8 members (as 3 are elderly, and 4 we have already selected for left side 15-3-4 = 8);
4C1 select 1 for the most further away chair from 4 people (again as as 3 are elderly, and 4 we have already selected for left side and 4 for right side chairs 15-3-4-4=4)
Total # of selection=3C1*12C4*8C4*4C1=59400
Answer: D
Answer: (D) 59400
Question: A works twice as fast as B.If B can complete a work in 18 days independently,the number of days in which A and B can together finish the work is:
(A) 4 days
(B) 6 days
(C) 8 days
(D) 10 days
(E) 12 days
Rationale: Explanation:
Ratio of rates of working of A and B =2:1. So, ratio of times taken =1:2
A's 1 day's work=1/9
B's 1 day's work=1/18
(A+B)'s 1 day's work=(1/9 + 1/18)=3/18=1/6
so, A and B together can finish the work in 6 days
ANSWER IS B
Answer: (B) 6 days
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 25 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
(A) 37
(B) 240
(C) 288
(D) 267
(E) 165
Rationale: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 25)m = 375 m. Let the length of the platform be x meters. Then, (x + 375)/36 = 15 ==> x + 375 = 540 ==> x = 165 m.Answer: E
Answer: (E) 165
Question: The cost price of 13 articles is equal to the selling price of 11 articles. Find the profit percent?
(A) 18 2/61%
(B) 18 2/11%
(C) 18 2/81%
(D) 18 2/12%
(E) 18 2/21%
Rationale: 13 CP = 11 SP
11 --- 2 CP
100 --- ? =>18 2/11%
Answer: B
Answer: (B) 18 2/11%
Question: If the difference of two numbers is 3 and the difference of their square is 39, then the larger number is:
(A) 9
(B) 2
(C) 12
(D) 14
(E) 8
Rationale: Let the numbers be x and y
Then x2-y2=39
And x-y=3
We get x+y=13
Solving x-y=3, x+y=13
X=8, y=5
Larger number 8
ANSWER E
Answer: (E) 8
Question: 9 people decided to split the food order evenly. If the bill was $86.14 dollars, how much money should be removed with 1 cent as the smallest unit?
(A) $86.10
(B) $86.11
(C) $86.12
(D) $86.13
(E) $86.19
Rationale: This is equivalent to finding the first number that is divisible by 9 that occurs after 8614.
In order to divide the sum in 9 parts, the amount must be divisible by 9
Divisibility rule of 9: The sum of the digits must be divisible by 9
Sum of digits of 8+6+1+4=19. If you remove 1 , the number is divisible by 9 (19 -1). 18 is divisible by 9.
Hence, we need to remove 1 cent from this number for it to be divisible by 9.
Answer: (D) $86.13
Question: How many words can be formed by using all letters of the word 'BIHAR'?
(A) 720
(B) 24
(C) 120
(D) 60
(E) None of these
Rationale: Explanation :
The word 'BIHAR' has 5 letters and all these 5 letters are different.
Total words formed by using all these 5 letters = 5p5 = 5!
= 5 x 4 x 3 x 2 x 1 = 120. Answer : Option C
Answer: (C) 120
Question: The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
(A) 542
(B) 546
(C) 566
(D) 548
(E) 589
Rationale: Least number = (L.C.M. of 12, 15, 20, 54) + 8 = 540 + 8 = 548.
ANSWER : D
Answer: (D) 548
Question: The least number which must be subtracted from 909 to make it exactly divisible by 9 is:
(A) A)2
(B) B)3
(C) C)0
(D) D)5
(E) E)6
Rationale: On dividing 909 by 9, we get remainder= 0
Therefore, required number to be subtracted= 0
Answer: C
Answer: (C) C)0
Question: If money is invested at r percent interest, compounded annually, the amount of the investment will double in approximately 50/r years. If Luke's parents invested $11,500 in a long term bond that pays 12 percent interest compounded annually, what will be the approximate total amount of the investment 12 years later, when Luke is ready for college?
(A) 62,000
(B) 85,500
(C) 95,500
(D) 100,500
(E) 100,000
Rationale: Answer equals C in 48 years. I thought by 50th year it would reach 95,500. Options should have been separated more widely for clarity.
Answer: (C) 95,500
Question: Find the maximum value of n such that 50! is perfectly divisible by 2520^n
(A) 7
(B) 8
(C) 9
(D) 6
(E) 5
Rationale: 2520 = 2^3*3^2*5*7
Here, 7 is the highest prime,so find the no. of 7's in 50! only
no. of 7's in 50! = [50/7] + [50/7^2] = 7+1 = 8
ANSWER:B
Answer: (B) 8
Question: A comic collector sells his memorabilia through an on-line distributor, which take a commission of 5% of the price set by the collector. The on-line store obtains the product from an artist at the price of $100 per item. What is the price that the buyer observers on-line if the distributor wants to maintain a 5% profit on the cost of the item?
(A) 98.42
(B) 105.15
(C) 110.53
(D) 107.22
(E) 66.68
Rationale: Collector price = $100;The on-line distributor wants to maintain a 5% profit on the cost of the memorabilia, thus he must get $100*1.05 = $105 after the distributor takes a commission of 5% of the final price --> (final price)*0.95 = $105 --> (final price) = $110.53.Answer: C.
Answer: (C) 110.53
Question: The speed of a boat in still water is 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is
(A) 1.2 km
(B) 1.8 km
(C) 2.4 km
(D) 3.6 km
(E) 1.6 km
Rationale: B = 15km/hr, S= 3km/hr, Downstream B+S = 15+3 =18 km/hr
down stream time t = 12 min, we have to change it to hours so t = 12/60=1/5 hrs.
Distance = Speed*time = 18*1/5 = 3.6 km.
ANSWER:D
Answer: (D) 3.6 km
Question: (5568 / 87)1/3 + (72 x 2)1/2 = (?)1/2 ?
(A) 256
(B) 4
(C) √2
(D) 16
(E) None
Rationale: Answer
?)1/2 = (5568 / 87)1/3 + (72 x 2)1/2
= (64)1/3 + (144)1/2
∴ ? = (4 + 12)2 = 256
Correct Option: A
Answer: (A) 256
Question: A car travels at a speed of 65 miles per hour. How far will it travel in 5 hours?
(A) 425 miles
(B) 625 miles
(C) 325 miles
(D) 225 miles
(E) 625 miles
Rationale: During each hour, the car travels 65 miles. For 5 hours it will travel
65 + 65 + 65 + 65 + 65 = 5 *65 = 325 miles correct answer C
Answer: (C) 325 miles
Question: A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?
(A) 32 years
(B) 36 years
(C) 40 years
(D) 48 years
(E) None
Rationale: Solution
Let the mother's present age be x years.Then, the person's present age	= (2/5 x) years.
Therefore	=[2/5x+8]
= 1/2(x+8)
= 2(2x+40)
=5(x+8)
= 40 year
Answer C
Answer: (C) 40 years
Question: If 4 people are selected from a group of 7 married couples, what is the probability that none of them would be married to each other?
(A) 1/33
(B) 2/33
(C) 1/3
(D) 16/33
(E) 47/84
Rationale: If we are to select 4 people from 7 couples WITHOUT any restriction, how many ways can we make the selection? 14!/4!10! =1001
If we are to select 4 people from 7 couples WITH restriction that no married couple can both make it to the group, only a representative?
7!/4!3! = 35
But we know that to select a person from each couple, take 2 possibilities
35*2*2*2*2 = 560
Probability = Desired/All Possibilities = 560/1001 = 47/84
Answer: E
Answer: (E) 47/84
Question: A bag contains 6 red, 5 blue and 2 green balls. If 2 ballsare picked at random, what is the probability that both are red?
(A) 5/21
(B) 5/24
(C) 5/26
(D) 5/31
(E) 6/29
Rationale: P(Both are red),
=6C213C2=6C213C2
=5/26
C
Answer: (C) 5/26
Question: There are 8 orators A, B, C, D, E, F, G and H. In how many ways can the arrangements be made so that A always comes before B and B always comes before C.
(A) 8! / 3!
(B) 8! / 6!
(C) 5! x 3!
(D) 8! / (5! x 3!)
(E) 8! / (5! x 4!)
Rationale: Select any three places for A, B and C. They need no arrangement amongst themselves as A would always come before B and B would always come before C.
The remaining 5 people have to be arranged in 5 places.
Thus, 8C3 x 5! = 56 x 120 = 67200 = 8! / 3!
ANSWER:A
Answer: (A) 8! / 3!
Question: A copy machine, working at a constant rate, makes 40 copies per minute. A second copy machine, working at a constant rate, makes 55 copies per minute. Working together at their respective rates, how many copies do the two machines make in half an hour ?
(A) 90
(B) 2,700
(C) 4,500
(D) 5,400
(E) 2,850
Rationale: Together the two machines make 40+55=95 copies per minute. So, in half an hour they will make 95*30=2,850 copies.
Answer: E.
Answer: (E) 2,850
Question: The present age of a father is 3 years more than three times the age of his son. Three years hence, father's age will be 12 years more than twice the age of the son. Find the present age of the father.
(A) 33
(B) 39
(C) 29
(D) 40
(E) 48
Rationale: if the present age be x years.
father's will be (3x+3)years..
so, (3x+3+3)=2(x+3)+12
or, x=12
so the fathers present age =(3x+3)=(3*12+3)years =39years..
ANSWER : OPTION B
Answer: (B) 39
Question: Two unbiased coins are tossed.What is the probability of getting at most one head?
(A) 2/3
(B) 1
(C) 3/4
(D) 2
(E) 1/2
Rationale: s={hh,tt,ht,th}
e=event of getting at most one head.
e={tt,ht,th}.
p(e)=n(e)/n(s)=3/4
Answer is option C
Answer: (C) 3/4
Question: A sum of Rs. 2665 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
(A) 2277
(B) 1640
(C) 2977
(D) 2991
(E) 2771
Rationale: (x*8*3)/100 = ((2665 - x)*3*5)/100
24x/100 = 39975/100 - 15x/100
39x = 39975 => x = 1025
Second sum = 2665 – 1025 = 1640
Answer: B
Answer: (B) 1640
Question: An alloy weighing 24 ounces is 70 percent gold. How many ounces of pure gold must be added to create an alloy that is 90 percent gold?
(A) 6
(B) 9
(C) 12
(D) 24
(E) 48
Rationale: In 24 ounces, gold is 24 * (70/100) = 16.8 ounces. Now we add x ounces of pure gold to make it 90% gold.
So 16.8 + x = (24 + x)* 90/100 => x =48.
Answer is E.
Answer: (E) 48
Question: Find b and c so that the parabola with equation y = 4x2 - bx - c has a vertex at (2 , 4)?
(A) -10
(B) -20
(C) -30
(D) -40
(E) -50
Rationale: h = b / 8 = 2 : formula for x coordinate of vertex
b = 16 : solve for b
y = 4 for x = 2 : the vertex point is a solution to the equation of the parabola
4(2)2 - 16(2) - c = 4
c = -20 : solve for c
correct answer B
Answer: (B) -20
Question: Seven years ago the average age of a family of 2 members was 26 years. A child has been born. due to Which the average age of the family is 23 years today. What is the present age of the child?
(A) 25years
(B) 29years
(C) 30years
(D) 35years
(E) 40years
Rationale: Explanation:
Average of the family of two numbers
7 years ago = 26
= (26+ 7) * 2 = 40 years
Average age of the family of three members at present = 23 years
= 23 * 3 = 69 YEARS
Age of child = 69 - 40 = 29 years
Answer: Option B
Answer: (B) 29years
Question: Which of the following is a prime number ?
(A) 90
(B) 94
(C) 96
(D) 97
(E) 98
Rationale: Clearly, 97 is a prime number.
D
Answer: (D) 97
Question: The total of the ages of Mahesh, Suresh, Ramesh is 138 years. Ten years ago, the ratio of their ages was 2:3:4. What is the present age of Mahesh?
(A) 32years
(B) 58years
(C) 42years
(D) 35years
(E) 30years
Rationale: Let ages of Mahesh, Suresh, Ramesh 10years ago be 2x,3x,4x
2x+10 + 3x+10 +4x+10 = 138
x = 12
Ramesh present age = 4*12+10 = 58 years
Answer is B
Answer: (B) 58years
Question: Each week, Harry is paid x dollars per hour for the first 30 hours and 1.5x dollars for each additional hour worked that week. Each week, Annie is paid x dollars per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week Annie worked a total of 50 hours. If Harry and Annie were paid the same amount last week, how many hours did Harry work last week?
(A) 40
(B) 45
(C) 50
(D) 55
(E) 60
Rationale: Annie earned 40x + 10(2x) = 60x
Let H be the number of hours that Harry worked.
Harry earned 30x + 1.5x(H-30) = 60x
(1.5x)(H) = 75x
H = 50 hours
The answer is C.
Answer: (C) 50
Question: Suppose that this fresh fruit contains 80% water and dry fruit contains 20% water. How much dry fruit can be obtained from 100kg of fresh fruit?
(A) A)32kg
(B) B)40kg
(C) C)25kg
(D) D)80kg
(E) E)100kg
Rationale: Quantity of pulp in 100kg of fresh fruits = (100-80)% of 100kg = 20kg
Let the quantity of dry fruit obtained be x kg
then, (100-20)% of x = 20
(80/100)*x = 20
x = 25
correct option is C
Answer: (C) C)25kg
Question: A circle graph shows how the budget of a certain company was spent: 20 percent for transportation, 9 percent for research and development, 5 percent for utilities, 4 percent for equipment, 2 percent for supplies, and the remainder for salaries. If the area of each sector of the graph is proportional to the percent of the budget it represents, how many degrees of the circle are used to represent salaries?
(A) 90°
(B) 135°
(C) 216°
(D) 240°
(E) 270°
Rationale: The percent of the budget for salaries is 100 - (20+9+5+4+2)= 60%
100% of the circle is 360 degrees.
Then (60%/100%)*360 = 216 degrees
The answer is C.
Answer: (C) 216°
Question: The current in a river is 4 mph. A boat can travel 18 mph in still water. How far up the river can the boat travel if the round trip is to take 10 hours?
(A) 69 miles
(B) 85.5 miles
(C) 96 miles
(D) 100 miles
(E) 112 miles
Rationale: Upstream Speed = 18-4=14 mph
Downstream Speed = 18+4 = 22 mph
D/14 + D/22 = 10 hours
Solving for D we get D=85.5
Answer: B
Answer: (B) 85.5 miles
Question: It is required to seat 7 boys and 4 girls in a row so that the girls occupy the even places. How many such arrangements are possible?
(A) 86,288
(B) 86,214
(C) 86,400
(D) 86,328
(E) 86,368
Rationale: Total number of candidates = 6 + 5 = 11. In the row of 11 positions, the even places are 2nd, 4th, 6th,8th,10th.
Now, number of even places = 5.
Number of girls to occupy the even places = 5.
Even places can be filled = P (5, 5) ways.
Number of boys = 6.
The remaining 6 places can be filled by 6 boys = P (6, 6) ways
By the fundamental principle of counting:
The required number of seating arrangements
P(5, 5) x P(6, 6) = 5! x 6! = 120 x 720 = 86,400
ANSWER:C
Answer: (C) 86,400
Question: For which of the following functions is f(e) = f(−e) for all values of e ?
(A) f(x) = x^3 + 3
(B) f(x) = −x
(C) f(x) = 2x + 3
(D) f(e) = −e^2 + 2
(E) f(x) = 5x − 4
Rationale: f(e) = f(−e)
The above is a property of an even function .
f(e) = f^(n)
f(e) = f(−e) will hold when n is an even integer .
The only case when e is even is option D
Answer D
Answer: (D) f(e) = −e^2 + 2
Question: The weights of three boys are in the ratio 4 : 5 : 6. If the sum of the weights of the heaviest and the lightest boy is 46 kg more than the weight of the third boy, what is the weight of the lightest boy?
(A) 87 kg
(B) 36.8 kg
(C) 98.8 kg
(D) 65.8 kg
(E) 87.8 kg
Rationale: Let the weights of the three boys be 4k, 5k and 6k respectively.
4k + 6k = 5k + 46
=> 5k = 46 => k = 9.2
Therefore the weight of the lightest boy
= 4k = 4(9.2) = 36.8 kg.
Answer:B
Answer: (B) 36.8 kg
Question: A train speeds past a pole in 15 sec and a platform 100 m long in 25 sec, its length is?
(A) 288
(B) 150
(C) 277
(D) 269
(E) 261
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 100)/25 = x/15 => x = 150 m.
Answer: B
Answer: (B) 150
Question: Jon had an average score of 85 on his first five quizzes. He had an
average score of 83 on his first six quizzes. What score did he receive on
his sixth quiz?
(A) 55
(B) 69
(C) 75
(D) 73
(E) 80
Rationale: The sum of Jon's first five scores is 5 Â· 85 and the sum of his first six scores is 6 Â· 83, so he received
6 Â· 83 âˆ’ 5 Â· 85 on his 6th quiz. You can do the arithmetic or note that the answer ends in a 3. The correct answer is D.
Answer: (D) 73
Question: After giving a discount of rs.45 the shopkeeper still gets a profit of 20%,if the cost price is rs.180.find the markup %?
(A) 0.4
(B) 0.55
(C) 0.45
(D) 0.48
(E) 0.58
Rationale: cost price=180
s.p=180*120/100=216
disc=45
so...mark price=216+45=261......
mark up%=261-180/180=81/180=.45 or 45%
ANSWER:C
Answer: (C) 0.45
Question: If a1 = 1 and an+1= 2an + 5, n = 1, 2 .. , then a50 is equal to ?
(A) a. 5*2^99-6
(B) b. 5*2^99+6
(C) c. 6*2^99+5
(D) d. 6*2^99-5
(E) e. 6*2^99-6
Rationale: Here is my solution:
an+1=2an+5............(1)
lets ADD 5 to both sides....
so (an+1) + 5= 2 (an+5)....................taking 2 as common factor
now a1=1. so for n=1, an+5=6.......
putting n=1. we get both sides as,
a2 + 5= 2 * 6 ..............as ( an+5=6 .......(for n=1)..)
a2= 2 *6 - 5
a2= 2 * 2 *3 - 5
a2= 2^2 *3 - 5................. so with same progression
a50= 2^50 * 3 - 5
a50=2 * 2^49 * 3 - 5
a50= 6*2^49 - 5
E
Answer: (E) e. 6*2^99-6
Question: A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km.
(A) 24 kmph
(B) 22 kmph
(C) 21 kmph
(D) 28 kmph
(E) 29 kmph
Rationale: A
24 kmph
Total time taken = x/40 + 2x/20 hours
= 5x/40 = x/8 hours
Average speed = 3x/(x/8) = 24 kmph
Answer: (A) 24 kmph
Question: A theater charges $12 for seats in the orchestra and $8 for seats in the balcony. On a certain night, a total of 360 tickets were sold for a total cost of $3,320. How many more tickets were sold that night for seats in the balcony than for seats in the orchestra?
(A)  90
(B)  110
(C)  120
(D)  140
(E)  220
Rationale: Orchestra Seats - a
Balcony Seats - b
a+b = 360
and 12a + 8b = 3320
Solving equations simultaneously (Multiply Equation 1 with 8 and subtract from second equation)
4a = 3320 - 8*360 = 3320 - 2880 = 440
i.e. a = 110
and b = 360-110 = 250
More seats in balcony than orchestra = b-a = 250 - 110 = 140
Answer: option D
Answer: (D)  140
Question: When 732 is subtracted form the square of a number, the answer that is obtained is 5280. What is the number?
(A) 97
(B) 103
(C) 99
(D) 101
(E) None of these
Rationale: Let the number be x
x2 - 732 = 5280
x2 = 5280 + (70+3)2 = 5280 + 4900 + 420 + 9 = 10609
= 10000 + 2(100)(3) + 32 = (100 + 3)2
x = 100 + 3 = 103.
ANSWER:B
Answer: (B) 103
Question: Of the 20,210 employees of the anvil factory, 2/7 are journeymen. If half of the journeymen were laid off, what percentage of the total remaining employees would be journeymen?
(A)  14.3%
(B)  16.67%
(C)  33%
(D)  28.6%
(E)  49.67%
Rationale: The exam gives us a number that is easily divisible by 7 to pique our curiosity and tempt us into calculating actual numbers (also because otherwise the ratio would be incorrect). Since the question is about percentages, the actual numbers will be meaningless, as only the ratio of that number versus others will be meaningful. Nonetheless, for those who are curious, each 1/7 portion represents (14210/7) 2,030 employees. This in turn means that 4,060 employees are journeymen and the remaining 10,150 are full time workers.
If half the journeymen were laid off, that would mean 1/7 of the total current workforce would be removed. This statistic is what leads many students to think that since half the journeymen are left, the remaining journeymen would represent half of what they used to be, which means 1/7 of the total workforce. If 1/7 of the workforce is journeymen, and 1/7 is roughly 14.3%, then answer choice A should be the right answer. In this case, though, it is merely the tempting trap answer choice.
What changed between the initial statement and the final tally? Well, you let go of 1/7 of the workforce, so the total number of workers went down. The remaining workers are still 1/7 of the initial workers, but the group has changed. The new workforce is smaller than the original group, specifically 6/7 of it because 1/7 was eliminated. The remaining workers now account for 1/7 out of 6/7 of the force, which if we multiply by 7 gives us 1 out of 6. This number as a percentage is answer choice B, 49.67%.
Using the absolute numbers we calculated before, there were 4,060 journeymen employees out of 14,210 total. If 2,030 of them are laid off, then there are 2,030 journeyman employees left, but now out of a total of (14,210-2,030) 12,180 employees. 2,030/12,180 is exactly 1/6, or 16.67%. The answer will work with either percentages or absolute numbers, but the percentage calculation will be significantly faster and applicable to any similar situation.
The underlying principle of percentages (and, on a related note, ratios) can be summed up in the brainteaser I like to ask my students: If you’re running a race and you overtake the 2nd place runner just before the end, what position do you end up in?
The correct answer is 2nd place.
Percentages, like ratios and other concepts of relative math, depend entirely on the context. Whether 100% more of something is better than 50% more of something else depends on the context much more than the percentages quoted. When it comes to percentages on the GMAT, the goal is to understand them enough to instinctively not fall into the traps laid out for you.E
Answer: (E)  49.67%
Question: In packing for a trip, Sarah puts three pairs of socks - one red, one blue, and one green - into one compartment of her suitcase. If she then pulls four individual socks out of the suitcase, simultaneously and at random, what is the probability that she pulls out exactly two matching pairs?
(A) 1/5
(B) 1/4
(C) 1/3
(D) 2/3
(E) 4/5
Rationale: the successful events are when Sarah pulls 2 matching pair of socks out of 3 matching pairs of socks, which can be done in 3C2 ways as the order is not important
So,3C2 = 3 ways are:
RRBB
RRGG
BBGG
Now,the ways in which 4 socks can be pulled out of 6 socks (3 pairs) = 6C4 = 15
So, probability = 3/15 = 1/5
Ans: A
Answer: (A) 1/5
Question: Tom purchased 8kg of apples at the rate of 70 per kg and 9 kg of mangoes at the rate of 70 per kg. How much amount did he pay to the shopkeeper?
(A) A)1040
(B) B)1045
(C) C)1055
(D) D)1190
(E) E)1075
Rationale: Cost of 8 kg apples= 70 × 8 = 560.
Cost of 9 kg of mangoes = 70 × 9 = 630.
Total cost he has to pay = 560 + 630 = 1190.
D)
Answer: (D) D)1190
Question: The ratio of income of Anand to that of Balu is 5 : 4 and the expenditure of Anand to that of Balu is 3: 2. If at the end of the year, each saves Rs, 800, the income of Anand is :
(A) Rs 1600
(B) Rs 1800
(C) Rs 2000
(D) Rs 2200
(E) None of these
Rationale: Explanation :
Let the income of Anand and Balu be 5x and 4x and. the expenditures of Anand and Balu be 3y and 2y.
Then, 5x3y = 800 and 4x 2y= 800.
On solving we get : x = 400. As income = 5x = Rs. 2000.
Answer : C
Answer: (C) Rs 2000
Question: The average runs of a cricket player of 10 innings was 20. How many runs must he make in his next innings so as to increase his average of runs by 4?
(A) 22
(B) 77
(C) 64
(D) 19
(E) 17
Rationale: Explanation:
Average after 11 innings = 24
Required number of runs = (24 * 11) – (20 * 10)
= 264 – 200 = 64
ANSWER: C
Answer: (C) 64
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 10% profit on the first article and 10% loss on second article. Find the net profit or loss percent?
(A) 200
(B) 100
(C) 276
(D) 280
(E) 279
Rationale: Profit on first article = 10% of 1000 = 100.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer: B
Answer: (B) 100
Question: On my sister's birthday, she was 126 cm in height, having grown 5% since the year before. How tall was she the previous year?
(A) 124 cm
(B) 120 cm
(C) 116 cm
(D) 112 cm
(E) 110 cm
Rationale: Let the previous year's height be x.
1.05x = 126
x = 120
The answer is B.
Answer: (B) 120 cm