mathewhe/aqua_rat huggingface dataset:
Question: If the price of a certain computer increased 20 percent from d dollars to 351 dollars, then 2d =
(A) 540
(B) 585
(C) 619
(D) 649
(E) 700
Rationale: Before Price increase Price = d
After 30% Price increase Price = d+(20/100)*D = 1.2d = 351 (Given)
i.e. d = 351/1.3 = $292,5
i.e. 2d = 2*292.5 = 585
Answer: option B
Answer: (B) 585
Question: an article with cost price of 280 is sold at 30% profit. what is the selling price?
(A) 198
(B) 364
(C) 369
(D) 207
(E) 210
Rationale: sp=1.30*280=364
ANSWER:B
Answer: (B) 364
Question: After successive discounts of 20%, 10% and 5% a certain good is sold for Rs. 6500. Find the actual price of the good.
(A) s. 6000
(B) s. 9000
(C) s. 10800
(D) s. 9503
(E) s. 9980
Rationale: Let actual price was 100.
After three successive discount this will become,
100 ==20% discount => 80 ==10% discount => 72 ==5% discount = 68.4
Now Compare,
68.4 = 6500
1 = 6500/68.4
100 = (6500*100)/68.4 = Rs. 9503.
Answer: Option D
Answer: (D) s. 9503
Question: In the gure below, arc SBT is one quarter of a circle with center R and radius
r. The length plus the width of rectangle ABCR is 8, and the perimeter of the shaded region
is 10 + 3. Find the value of r.
(A) 6
(B) 6:25
(C) 6:5
(D) 6:75
(E) 7
Rationale: Set x = RC and y = AR. It must then be x+y = 8 (by hypothesis) and x2+y2 = r2
(since the rectangle ABCR has one vertex in the circle). The perimeter of the shaded area is
then AS + SBT + TC + AC = (r 􀀀 y) + r=2 + (r 􀀀 x) +
p
x2 + y2 = 3r + r=2 􀀀 (x + y) =
3r + r=2 􀀀 8. All we need to so is solve for r in the equation 18 + 3 = (3 +
2 )r.
correct answer A
Answer: (A) 6
Question: If k, (k+200), (k+350), and 15*K are all multiples of V, then V could equal which of the following ?
(A) 20
(B) V=25
(C) V=75
(D) 100
(E) 150
Rationale: {Multiple of V} - {Multiple of V} = {Multiple of V}.
(K+200) - k = 200 = {Multiple of V}.
(K+350) - k = 350 = {Multiple of V}.
Both 200 and 350 are multiples of only option B.
Answer: B.
Answer: (B) V=25
Question: list of salaries of 8 employees are listed below. What is the median salary?
$40,000, $29,000, $35,500, $31,000, $43,000, $30,000, $27,000, $33,000
(A) $32,000
(B) $28,500
(C) $30,200
(D) $30,800
(E) $31,500
Rationale: Ordering the data from least to greatest, we get:
$27,000, $29,000, $30,000, $31,000, $33,000, $35,500, $40,000, $43,000
Since there is an even number of items in the data set, we compute the median by taking the mean of the two middlemost numbers.
$31,000 + $33,000 = $64,000
The median salary is $32,000.
Answer : A
Answer: (A) $32,000
Question: Tharak covers a part of the journey at 20 kmph and the balance at 70 kmph taking total of 8 hours to cover the distance of 400 km. How many hours has been driving at 20 kmph?
(A) 3 hours 12 minute
(B) 2 hours
(C) 4 hours 40 minutes
(D) 3 hours 20 minutes
(E) 3 hours 18 minute
Rationale: Let x be no. Of hours, and he travelled at 20kmph.
And balance distance (8-x)hr at 70kmph.
Total distance=20x+(8-x)hr =400
20x+(8-x)70=400
20x+560-70x=400
20x-70x=400-560
-50x=-160
x=3.2 =3 hr 12minutes
ANSWER:A
Answer: (A) 3 hours 12 minute
Question: In how many different ways can 5 girls and 4 boys form a circle such that the boys and the girls alternate?
(A) 576
(B) 425
(C) 215
(D) 321
(E) None of these
Rationale: Explanation :
In a circle, 5 boys can be arranged in 4! ways
Given that the boys and the girls alternate.
Hence there are 4 places for girls which can be arranged in 4! ways
Total number of ways = 4! x 4! = 24 x 24 = 576. Answer : Option A
Answer: (A) 576
Question: Find the C.I. on Rs. 15,625 for 9 months at 16% per annum compounded quarterly?
(A) Rs. 1851
(B) Rs. 1941
(C) Rs. 1951
(D) Rs. 1961
(E) Rs. 1861
Rationale: P = Rs. 15625, n = 9 months = 3 quarters, R = 16% p.a. per quarter.
Amount = [15625 * (1 + 4/100)3]
= (15625 * 26/25 * 26/25 * 26/25) = Rs. 17576 C.I. = 17576 - 15625 = Rs. 1951.
ANSWER:C
Answer: (C) Rs. 1951
Question: In order to obtain an income of Rs. 650 from 10% stock at Rs. 96, one must make an investment of:
(A) Rs. 3100
(B) Rs. 6240
(C) Rs. 6500
(D) Rs. 9600
(E) Rs. 8600
Rationale: To get Rs. 10, Investment is 96
To get Rs. 650, investment is (96/10)*650 = 6240
ANSWER:B
Answer: (B) Rs. 6240
Question: Find the product of place value and face value of 5 in 65231
(A) 28000
(B) 25000
(C) 27000
(D) 26000
(E) 28000
Rationale: Place value of 5 in 65231 = 5 x 1000 = 5000
Face value = 5
required product = 5000 x 5 = 25000
Answer :B
Answer: (B) 25000
Question: The average weight of 4 students decreases by 8 kg when one of them weighing 96 kg is replaced by a new student. The weight of the student is
(A) 62 kg
(B) 60 kg
(C) 64 kg
(D) 72 kg
(E) None of these
Rationale: Explanation :
Let the weight of student be x kg.
Given, Difference in average weight = 8 kg
=> (96-x)/4 = 8
=> x = 64
Answer : C
Answer: (C) 64 kg
Question: The cost of 4 bags and 12 purses is Rs.1520, what is the cost of 10 bags and 30 purses?
(A) Rs.3600
(B) Rs.3500
(C) Rs.3800
(D) Rs.3900
(E) None of these
Rationale: Explanation:
Cost of 4 bags + 12 purses = Rs.1520
Multiply each term by 5/2, we get,
Cost of 10 bags + 30 purses = Rs.3800.
Answer: Option C
Answer: (C) Rs.3800
Question: Johnny travels a total of one hour to and from school. On the way there he jogs at 4 miles per hour and on the return trip he gets picked up by the bus and returns home at 20 miles per hour. How far is it to the school?
(A) 2 miles
(B) 6.6 miles
(C) 4.8 miles
(D) 8 miles
(E) 10 miles
Rationale: Answer: B) 6.6 miles.
Average speed for round trip = 2*a*b/(a+b), where a,b are speeds
so, average speed was = 2*4*20/(4+20) = 6.6m/hr
the distance between schoolhome should be half of that. ie. 6.6 miles
answer B
Answer: (B) 6.6 miles
Question: If two numbers are in the ratio 4:7. If 10 is added to both of the numbers then the ratio becomes 6:10 then find the largest number?
(A) 80
(B) 40
(C) 140
(D) 100
(E) None of these
Rationale: Explanation:
4:7
4x + 10 : 7x + 10 = 6 : 10
10[4x + 10] = 6[7x + 10]
40x + 100 = 42x + 60
100 – 60 = 42x – 40x
2x = 40
X = 20
Then the first number is = 4
7x = 140
Short cut method:
a:b = 4:7
c:d = 6:10
1.Cross multiplication with both ratios
a * d ~ b * c = 4 * 10 ~ 7 * 6 = 40 ~ 42 = 2
2. If 10 is added both the number means 10 * 6 = 60 and 10 * 10 = 100,
Then 60 ~ 100 = 40
===> 2 -----> 40
===> 1 -----> 20
==> 7 -----> 140
Answer: Option C
Answer: (C) 140
Question: The price of 80 apples is equal to that of 120 oranges. The price of 60 apples and 75 oranges together is Rs.1320. The total price of 25 apples and 40 oranges is
(A) Rs. 660
(B) Rs. 620
(C) Rs. 820
(D) Rs. 780
(E) Rs. 960
Rationale: Explanation :
Let the price of one apple = a and price of one orange = b
The price of 80 apples is equal to that of 120 oranges
80a = 120b
=> 2a = 3b
⇒b=2a3-----(Equation 1)
price of 60 apples and 75 oranges together is Rs.1320
=>60a + 75b = 1320
=> 4a + 5b = 88
⇒4a+5(2a)3=88(∵ Substituted the value of b from equation 1)
=> 12a + 10a = 88 × 3
=> 6a + 5a = 44 × 3
=> 11a = 44 × 3
=> a = 4 × 3 = 12
b=2a3=2×123=8
Total price of 25 apples and 40 oranges
= 25a + 40b = (25 × 12) + (40 × 8) = 300 + 320 = 620
Answer : B
Answer: (B) Rs. 620
Question: A cylinder is being filled with sand weighing 200 kg per cubic foot. The cylinder has a diameter of 1 foot and is 5 feet tall. How much sand is being used??
(A) 250pi kg
(B) 500pi kg
(C) 500pi^2 kg
(D) 1000pi kg
(E) 1000pi^2 kg
Rationale: Answer is A.
Volume of Cylinder = Pi*r^2 *h --------> Pi * (1/2)^2 * 5 --------> Pi * (1/4) * 5 --------> (5/4)Pi cubic feet.
1 cubic feet = 200 kg. so (5/4)Pi cubic feet = ((200*5)/4)Pi ---------> 250Pi
Regards,
Abhijit answer is A
Answer: (A) 250pi kg
Question: How many 3-digit numbers are completely divisible 6 ?
(A) 25
(B) 78
(C) 93
(D) 150
(E) 14
Rationale: Explanation:
3-digit number divisible by 6 are: 102, 108, 114,... , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
a + (n - 1)d = 996
102 + (n - 1) x 6 = 996
6 x (n - 1) = 894
(n - 1) = 149
n = 150
Number of terms = 150.
D)
Answer: (D) 150
Question: Speed of a boat in standing water is 10kmph and speed of the stream is 1.5kmph. A man can rows to a place at a distance of 105km and comes back to the starting point. The total time taken by him is?
(A) 20.48hours
(B) 21.48hours
(C) 22.48hours
(D) 23.48hours
(E) 24.48hours
Rationale: Speed upstream = 8.5kmph
Speed downstream = 11.5kmph
Total time taken = 105/8.5 + 105/11.5 = 21.48 hours
Answer is B
Answer: (B) 21.48hours
Question: An escalator moves towards the top level at the rate of 11 ft.sec and its length is 126 feet. If a person walks on the moving escalator at the rate of 3 feet per second towards the top level, how much time does he take to cover the entire length.
(A) 14 sec
(B) 10 sec
(C) 12 sec
(D) 8 sec
(E) 9 sec
Rationale: Time taken to cover the entire length = tot.dist/resultant speed
= 126/ (11+3)
= 9 sec
ANSWER:E
Answer: (E) 9 sec
Question: How many seconds will a 750 meter long train moving with a speed of 63 km/hr take to cross a man walking with a speed of 3 km/hr in the direction of the train ?
(A) 48
(B) 36
(C) 26
(D) 11
(E) 45
Rationale: Explanation:
Here distance d = 750 mts
speed s = 63 - 3 = 60 kmph = 60 x 5/18 m/s
time t = = 45 sec.
Answer: E
Answer: (E) 45
Question: Jane started baby-sitting when she was 18 years old. Whenever she baby-sat for a child, that child was no more than half her age at the time. Jane is currently 34 years old, and she stopped baby-sitting 12 years ago. What is the current age of the oldest person for whom Jane could have baby-sat?
(A) 20
(B) 21
(C) 22
(D) 23
(E) 25
Rationale: Check two extreme cases:
Jane = 18, child = 9, years ago = 34-18 = 16 --> child's age now = 9+16 = 25;
Jane = 22, child = 11, years ago = 34-22 = 12 --> child's age now = 11+12 = 23.
Answer: E.
Answer: (E) 25
Question: The average of first seven prime numbers which are odd is?
(A) 15.5
(B) 15.7
(C) 15.2
(D) 15.8
(E) 10.7
Rationale: Sum of first 7 prime no. which are odd = 75
Average = 75/7 = 10.7
Answer:E
Answer: (E) 10.7
Question: A candidate got 35% of the votes polled and he lost to his rival by 2250 votes. How many votes were cast?
(A) 7500
(B) 2028
(C) 2775
(D) 5496
(E) 6851
Rationale: 35%-----------L
65%-----------W
------------------
30%----------2250
100%---------? => 7500
Answer:A
Answer: (A) 7500
Question: John was thrice as old as Tom 6 yrs back. He will be 5/3 times as old as Tom 6 years hence. How old is Tom today?
(A) 10
(B) 11
(C) 12
(D) 14
(E) 15
Rationale: Sol. RMBflSk -6 = 3 (Ravi - 6) ...(j)
and Rupesh + 6 = | (Ravi + 6) ...(ii)
Solving both the equations we get,
Ravi = 12 years.
C
Answer: (C) 12
Question: It takes Avery 3 hours to build a brick wall while Tom can do it in 5 hours. If the two start working together and after an hour Avery leaves, how much time will it take Tom to complete the wall on his own?
(A) 100
(B) 110
(C) 120
(D) 130
(E) 140
Rationale: Avery takes 3 hours
Tom takes 2 hours
Efficiency of Avery is 1/3 units/hr
Efficiency of Tom is 1/5 units/hr
Combined efficiency of Tom and Avery is 1/3 +1/5 = 8/15 units/hr
Since they worked for 1 hour they completed 8/15 units of work and 7/15 units of work is left which is to be completed by Tom ( Since Avery left )
So Time taken by Tom to complete the remaining work will be 7/15/1/5 hours => 7/3*60 =140 minutes...
Answer will be (E)
Answer: (E) 140
Question: A restaurant meal cost $32.50 and there was no tax. If the tip was more than 10 percent but less than 15 percent of the cost of the meal, then total amount paid must have been between:
(A) $40 and $42
(B) $39 and $41
(C) $38 and 40
(D) $37 and $39
(E) $36 and $38
Rationale: let tip=t
meal cost=32.50
range of tip = from 10% of 32.5 to 15% of 32.5 = 3.55 to 5.325
hence range of amount paid= 32.5+T= 36.05 to 37.825
ANSWER:E
Answer: (E) $36 and $38
Question: On what dates of April, 2001 did Wednesday fall?
(A) 2nd, 9th, 16th, 23rd
(B) 4th, 11th, 18th, 25th
(C) 3rd, 10th, 17th, 24th
(D) 1st, 8th, 15th, 22nd, 29th
(E) 3rd, 8th, 15th, 17th, 23rd
Rationale: Explanation:
We need to find out the day of 01-Apr-2001
01-Apr-2001 = (2000 years + period from 1-Jan-2001 to 01-Apr-2001)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Days from 1-Jan-2001 to 01-Apr-2001 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 1(Apr) = 91
91 days = 13 weeks = 0 odd day
Total number of odd days = (0 + 0) = 0 odd days
0 odd day = Sunday. Hence 01-Apr-2001 is Sunday.
Hence first Wednesday of Apr 2011 comes in 04th and successive Wednesdays come in 11th, 18th and 25th
Answer: Option B
Answer: (B) 4th, 11th, 18th, 25th
Question: Rs 1000 is invested at 5% pa simple interest. If interest is added to principal after every 10 yr. Then we will get amount 2000 after how many year?
(A) 12 years.
(B) 13.66 years.
(C) 14 years.
(D) 16.66 years.
(E) 15 YEARS
Rationale: P = 1000.
R = 5%.
T = 10 years.
I = PTR/100 = (1000 * 5*10)/100 = 500.
Now,
Principal = 1000 + 500 = 1500.
A = 2000
I = 500
R = 5%
T = (100 * I)/PR = (100 * 500)/(1500 *5) = 6.66 Years.
Total Time = 10 + 6.66 = 16.66 years.
ANSWER : OPTION D
Answer: (D) 16.66 years.
Question: Which of the following functions does not intersect with T = 3x^2 + 2x + 1
(A) T = 3x^2 + 3x + 1
(B) T = 2x^2 + 3x + 1
(C) T = 3x^2 + 2x + 3
(D) T = 4x^2 + 2x - 3
(E) T = x^2 + 2x + 3
Rationale: Let’s find the actual intersecting point of given function and each choice T.
A. 3x^2 + 2x + 1 = 3x^2 + 3x + 1 --> x=0
B. 3x^2 + 2x + 1 = 2x^2 + 3x + 1 --> x^2 – x =0 --> x=0 or 1
C. 3x^2 + 2x + 1 = 3x^2 + 2x + 3 --> 1=3(X) --> they don’t have any intersect.
D. 3x^2 + 2x + 1 = 4x^2 + 2x - 3 --> x^2 –4=0 --> x= 2 or -2
E. 3x^2 + 2x + 1 = x^2 + 2x + 3 --> 2x^2 –2 =0 --> x= 1 or –1.
So only choice (C) has no intersecting point. The answer is (C).
Answer: (C) T = 3x^2 + 2x + 3
Question: If x and y are different integers, both divisible by 6, then which is not necessarily true?
(A) x^2 + y^2 is divisible by 6
(B) x - y is divisible by 6
(C) xy is divisible by 6
(D) x + y is divisible by 6
(E) x + y is divisible by 12
Rationale: Let x = 6k and let y = 6j.
Then x+y = 6(k+j) and k+j could be even or odd.
Thus 6(k+j) is not necessarily divisible by 12.
The answer is E.
Answer: (E) x + y is divisible by 12
Question: 40% of Ram's marks is equal to 20% of Rahim's marks which percent is equal to 30% of Robert's marks. If Robert's marks is 80, then find the average marks of Ram and Rahim?
(A) 76
(B) 56
(C) 56
(D) 90
(E) 15
Rationale: Given, 40% of Ram's marks = 20% of Rahim's marks = 30% of Robert's marks.
Given, marks of Robert = 80
30% of 80 = 30/100 * 8 = 24
Given, 40% of Ram's marks = 24.
=> Ram's marks = (24 * 100)/40 = 60
Also, 20% of Rahim's marks
= 24
=> Rahim's marks
= (24 * 100)/20 = 120
Average marks of Ram and Rahim
= (60 + 120)/2 = 90.
Answer: D
Answer: (D) 90
Question: A and B enter into partnership with capital as 7:9. At the end of 8 months, A withdraws. If they receive the profits in the ratio of 8:9 find how long B's capital was used?
(A) 7
(B) 9
(C) 10
(D) 12
(E) 14
Rationale: Explanation:
7 * 8 : 9 * x = 8:9 => x= 7
A)
Answer: (A) 7
Question: The average of numbers 0.64206, 0.64207, 0.64208 and 0.64209 is ?
(A) 0.64202
(B) 0.64204
(C) 0.642022
(D) 0.642075
(E) None
Rationale: Answer
Average = (0.64206 + 0.64207 + 0.64208 + 0.64209)/ 4
=2.5683/ 4
=0.642075
Correct Option: D
Answer: (D) 0.642075
Question: Pid intended to type a seven-digit number, but the two 3's he meant to type did not appear. What appeared instead was the five-digit number 52115. How many different seven-digit numbers could Pid have meant to type?
(A) 10
(B) 16
(C) 21
(D) 24
(E) 27
Rationale: Should be 21.
Pid intended to type a seven-digit number there are two possibilities for placing 2 3s .
case 1: two 3s were missed consecutively. i.e. he typed 33 and it came blank on screen.
-5-2-1-1-5- in this arrangement we can fit 33 in 6 ways . (Six dashes, each dash represent one possible place for placing 33)
case 2: two 3s are not together, i.e. they have one or more digits between them .
-5-2-1-1-5- , in this arrangement
if we place first 3 at first dash i.e. 35-2-1-1-5- then the other 3 can fit into 5 places.
if we place first 3 at second dash i.e. -532-1-1-5- then the other 3 can fit into 4 places.
if we place first 3 at third dash i.e. -5-231-1-5- then the other 3 can fit into 3 places.
if we place first 3 at fourth dash i.e. -5-2-131-5- then the other 3 can fit into 2 places.
if we place first 3 at Fifth dash i.e. -5-2-1-135- then the other 3 can fit into 1 place.
so total 15 ways.
case 2 + case 1 = 6+ 15 = 21 ways
Answer C
Answer: (C) 21
Question: In a class, there are 18 boys who are over 160 cm tall. If these constitute three-fourths of the boys and the total number of boys is two-thirds of the total number of students in the class, what is the number of girls in the class ?
(A) 6
(B) 12
(C) 18
(D) 19
(E) 22
Rationale: In a class, there are 18 boys who are over 160 cm tall. If these constitute three-fourths of the boys , then total no of boys = 18*4/3 = 24 boys.
the total number of boys (24)is two-thirds of the total number of students in the class, then total students = 24*3/2= 36
no. of girls = 36-24=12
ANSWER:B
Answer: (B) 12
Question: 0.04 x 0.0162 is equal to:
(A) 6.48 x 10(power -4)
(B) 6.48 x 10(power -3)
(C) 9.48 x 10(power -4)
(D) 5.48 x 10(power -4)
(E) 6.08 x 10(power -4)
Rationale: 4 x 162 = 648. Sum of decimal places = 6.
So, 0.04 x 0.0162 = 0.000648 = 6.48 x 10(power -4)
Answer is A.
Answer: (A) 6.48 x 10(power -4)
Question: The speed of a boat in still water is 80kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
(A) 22 kmph
(B) 40 kmph
(C) 60 kmph
(D) 15 kmph
(E) 23 kmph
Rationale: Speed downstream = 80 + 20 = 100 kmph
Speed upstream = 80 - 20 = 60 kmph
Answer:C
Answer: (C) 60 kmph
Question: At a certain supplier, a machine of type A costs $30,000 and a machine of type B costs $70,000. Each machine can be purchased by making a 20 percent down payment and repaying the remainder of the cost and the finance charges over a period of time. If the finance charges are equal to 40 percent of the remainder of the cost, how much less would 2 machines of type A cost than 1 machine of type B under this arrangement?
(A) $10,000
(B) $11,200
(C) $12,000
(D) $12,800
(E) $13,200
Rationale: Total Cost of 2 Machines of Type A
= 20% of (Cost of 2 machine A) + remainder + 40 % remainder
= 20% of 30000 + (30000 - 20% of 30000) + 40% of (40000 - 20% of 30000)
= 79200
Total Cost of 1 Machine of Type B
= 20% of (Cost of 1 machine B) + remainder + 40 % remainder
= 20% of 70000 + (70000 - 20% of 70000) + 40% of (50000 - 20% of 70000)
= 92400
Diff = 92400 - 79200 = 13200
Hence, E.
Answer: (E) $13,200
Question: What is the total number of integers between 20 and 70 that are divisible by 2?
(A) 19
(B) 25
(C) 24
(D) 26
(E) 20
Rationale: 22, 24, 26, ..., 56,58
This is an equally spaced list; you can use the formula:
n = (largest - smallest) / ('space') + 1 = (70 - 22) / (2) + 1 = 48/2 + 1 = 24 + 1 = 25
Answer is B
Answer: (B) 25
Question: The second of two numbers is two less than three times the first. Find the numbers if there sum is
82.
(A) 7-19
(B) 8-20
(C) 10-16
(D) 15-9
(E) 21-61
Rationale: We are looking for two numbers.
#1 - x
#2 - 3x â€“ 2
The sum is 82. #1 + #2 = 82
Substituting x + 3x â€“ 2 = 82
4x â€“ 2 = 82
4x = 84
x = 21
The first number is 21, the second number is two less than three times 21 or 61.
correct answer E
Answer: (E) 21-61
Question: A room 4 m 47 cm long and 7m 77 cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor.
(A) 38636
(B) 38640
(C) 38647
(D) 38591
(E) 38675
Rationale: Explanation:
Area of the room = (447 x 777) cm2.
Size of largest square tile = H.C.F. of 447 cm and 777 cm = 3 cm.
Area of 1 tile = (3 x 3) cm2.
Number of tiles required =(447×777)/(3×3)=38591
Answer: Option D
Answer: (D) 38591
Question: A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
(A) 16
(B) 14
(C) 15
(D) 18
(E) 13
Rationale: A's 2 day's work= (1/20)*2=1/10
(A + B + C)'s 1 day's work =(1/20+1/30+1/60) = 6/60 =1/10
Work done in 3 days = (1/10+1/10) = 1/5
Now,	1/5 work is done in 3 days.
Whole work will be done in (3 x 5) = 15 days.
ANSWER:C
Answer: (C) 15
Question: A certain number of donkeys and an equal number of men are going to a village. Half of the men are on their donkey's back while the remaining are walking along leading their donkeys. If the number of legs walking on the ground is 70. How many donkeys are there?
(A) 218
(B) 277
(C) 299
(D) 267
(E) 11
Rationale: Answer:B
Answer: (B) 277
Question: Two numbers are respectively 20% and 25% more than a third number. The percentage that is first of the second is?
(A) 33
(B) 71
(C) 96
(D) 55
(E) 77
Rationale: I II III
120 125 100
125----------120
100-----------? => 96%
\Answer:C
Answer: (C) 96
Question: A certain research group plans to create computer models of x% of a list of 10,000 bacterial species known to inhabit the human body. After a budget cut, the group finds it must reduce this selection by (x − 7)%. In terms of x, how many species of bacteria will the group be able to model?
(A) x*x – 5x
(B) (x)*(107 – x)
(C) (100)(105 – x)
(D) (100)(95 – x)
(E) (x-5)/100
Rationale: Initial: (x/100)*10000 = 100x (bacterial species)
After reduce BY (x - 7)%, the percentage of bacterial species = 1 - (x - 7)% = 1 - (x - 7)/100 = (107 - x)/100
Note: Difference between reduce to[means: the remain] and reduce by[means: the remain = 1 -reduce by]
So, the number of bacterial species after reducing: 100x*(107 - x)/100 = (x)*(107 - x)
Ans is B.
Answer: (B) (x)*(107 – x)
Question: In each of the following questions a number series is given with one term missing. Choose the correct alternative that will continue the same pattern and fill in the blank spaces.
2, 7, ?, 23, 34, 47
(A) 31
(B) 14
(C) 36
(D) 31
(E) 33
Rationale: B
14
The given sequence is +5, +7, +9, ——
ie. 2+ 5 = 7, 7 + 7 = 14, 14 + 9 = 23
Answer: (B) 14
Question: Mid intended to type a seven-digit number, but the two 3's he meant to type did not appear. What appeared instead was the five-digit number 52115. How many different seven-digit numbers could Mid have meant to type?
(A) 10
(B) 16
(C) 21
(D) 24
(E) 27
Rationale: Should be 21.
Mid intended to type a seven-digit number there are two possibilities for placing 2 3s .
case 1: two 3s were missed consecutively. i.e. he typed 33 and it came blank on screen.
-5-2-1-1-5- in this arrangement we can fit 33 in 6 ways . (Six dashes, each dash represent one possible place for placing 33)
case 2: two 3s are not together, i.e. they have one or more digits between them .
-5-2-1-1-5- , in this arrangement
if we place first 3 at first dash i.e. 35-2-1-1-5- then the other 3 can fit into 5 places.
if we place first 3 at second dash i.e. -532-1-1-5- then the other 3 can fit into 4 places.
if we place first 3 at third dash i.e. -5-231-1-5- then the other 3 can fit into 3 places.
if we place first 3 at fourth dash i.e. -5-2-131-5- then the other 3 can fit into 2 places.
if we place first 3 at Fifth dash i.e. -5-2-1-135- then the other 3 can fit into 1 place.
so total 15 ways.
case 2 + case 1 = 6+ 15 = 21 ways
Answer C
Answer: (C) 21
Question: The workforce of Company Samsung is 60% female. The company hired 20 additional male workers, and as a result, the percent of female workers dropped to 50%.How many employees did the company have after hiring the additional male workers?
(A) 180
(B) 170
(C) 160
(D) 150
(E) 145
Rationale: let x be the total worker then 0.6x =female worker and 0.4x is male worker then 20 male worker added
06x/(0.4x +20) = 50/100 or 60x = 50*( 0.4x+100) = 20x+ 5000 or 40x = 5000 , x = 125
total worker = 125+20= 145
E
Answer: (E) 145
Question: A computer was sold at a loss of 20%. If it was sold for Rs.3200 more, there would have been a gain of 12%. What is the cost price?
(A) Rs.12000
(B) Rs. 8000
(C) Rs.10000
(D) Rs. 20000
(E) Rs. 11000
Rationale: 80%
112%
--------
32% ---- 3200
100% ---- ? => Rs.10000
Answer:C
Answer: (C) Rs.10000