mathewhe/aqua_rat huggingface dataset:
Question: Suresh started a business, investing Rs.18000. After 3 months and 4 months respectively, Rohan and Sudhir joined him with capitals of 12000 and 9000. At the end of the year the total profit was Rs.3960. What is the difference between Rohan’s and Sudhir’s share in the profit?
(A) s.345
(B) s.350
(C) s.352
(D) s.360
(E) s.368
Rationale: Suresh : Rohan : Sudhir
Ratio of their investments = 18000 × 12 : 12000 × 9 : 9000 × 8
= 6 : 3: 2
The difference between Rohan’s and Sudhir’s share = 1 share
:.i.e. = Rs. 3960 × 1/11 = Rs.360.
D
Answer: (D) s.360
Question: If k^2 = m^2, which of the following must be not true or false?
(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) A,B,C,D FALSE
Rationale: Since k^2=m^2 we have 0=k^2 – m^2 =(k-m)*(k+m). So k=m or k=-m.
So only (A) and only (B) cannot be an answer.
The choice (C) tells us that k should be greater than or equal to 0.
Similarly the choice (D) tells us that k should be less than or equal to 0.
So neither (C) nor (D) cannot be the answer.
The answer is, therefore, (E).
Answer: (E) A,B,C,D FALSE
Question: There are 200 rats in Rat-City. Out of the 200, 70 are street rats and the rest are domestic rats. 110 rats are gray, 30 out of the gray cats are NOT domestic ones. How many domestic rats are there which are not gray in Rat-City?
(A) 90
(B) 50
(C) 60
(D) 40
(E) 25
Rationale: SR=70,DR=130
GR=110,NGR=90
So SR,GR30 and DR,GR=80 NGR,SC=40 and NGR,DC=50
SR=stray rats
DR=domesticated rats
GR=Gray rats
NGR=Non Gray rats
Answer is B)
Answer: (B) 50
Question: The editor of an anthology of short stories has to select authors from a pool of 12 authors, of which 4 are female. If the anthology is to include the work of 8 authors of which at least 2 must be female, in how many ways can the editor select the authors?
(A) 168
(B) 201
(C) 294
(D) 462
(E) 495
Rationale: we have total 12 authors. we need to select 8. we have 8 males and 4 females.
we need to select in a such way, that at least 2 females are selected.
my first step:
12C8 = 495.
since this is a total number of combinations that we can have, regardless of the restrictions, we can eliminate right away A, B, C, and E.
why A, B, C - because the number of combinations when the restrictions are not respected is way smaller than the number of combinations in which the restrictions are respected.
nevertheless, I wanted to check further, so that to make sure I get the right answer:
second step, to get "at least 2 females", we need to deduct from 495 number of combinations when we have 8 males 0 females and when we have 7 males and 1 female.
8 males 7 females:
8C8 * 4C0 = 8
7 males and 1 female: 8C7*4C1=32.
Thus, the required number of combinations = Total - case with 0 females - case with 1 female = 495-1-32=462.
D is the correct answer.
Answer: (D) 462
Question: Line Q has the equation 3x + y = 7. Which of the following lines is perpendicular to Line Q?
(A)  y = 3x + 4
(B)  y = –3x – 6
(C)  y = (1/3)x – 1
(D)  y = (–1/3)x + 2
(E)  y = (–7/3)x – 5
Rationale: I first rewrote the equation in the standard y=mx+b form. Therefore, Line Q as presented, 3x + y = 7, can be rewritten as follows: y=-3x+7.
Thought process next is what line would be perpendicular to Line Q? Any line with a reciprocal of the slope but in the opposite direction. The reciprocal of any fraction/integer is 1 over that number/integer. Therefore the reciprocal of -3 is -1/3 - need to drop the negative sign because the line would kinda run parallel and we want perpendicular. Scan the answers choices and notice C as the only one.
Answer: (C)  y = (1/3)x – 1
Question: 0.01 is what percent of 0.1?
(A) 1%
(B) 10%
(C) 100%
(D) 50%
(E) 25%
Rationale: Required percentage = 0.01*100/0.1 = 100/10 = 10%
Answer is B
Answer: (B) 10%
Question: if 5 a = 3125, then the value of 5(a-3) is :
(A) 25
(B) 125
(C) 625
(D) 1625
(E) None of these
Rationale: Solution
5 a = 3125 ⇔ 5 a = 5 a ⇔ a = 5.
∴ 5(a - 3) = 5(5 - 3) = 52 = 25.
Answer A
Answer: (A) 25
Question: The average (arithmetic mean)T of the four distinct positive integers p, q, s and t is x. If p and q are odd, and s and t are even, which of the following must be true?
I. x is an integer
II. (x−0.5) is an integer.
III. 2x is an odd integer.
(A) I only
(B) II only
(C) III only
(D) II and III only
(E) None of the above
Rationale: Given :
p + q = EVEN (odd + odd = even)
p + q + s + t = EVEN (even + even = even) nothing more....
(p + q + s + t) / 4 = x
I.
x may or may not be integer, we only know sum of 4 variables is even not necessarily multiple of 4. I is out.
II.
Similarly, x an integer if sum of 4 variables is multiple of 4 but not an integer if it is not multiple of 4, we only know it is even. II is out.
III.
As in II, if X is integer 2x is Even, if X has decimal part (a.5), 2x is odd. III is out.
Answer E, None.
Answer: (E) None of the above
Question: A certain sum of money at simple interest amounted Rs.840 in 10 years at 3% per annum, find the sum?
(A) 378
(B) 277
(C) 299
(D) 646
(E) 261
Rationale: 840 = P [1 + (10*3)/100]
P = 646
Answer: D
Answer: (D) 646
Question: If an integer n is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 4?
(A) 1/4
(B) 3/8
(C) 1/2
(D) 5/8
(E) 3/4
Rationale: I get 5/8 as well
1 to 96 inclusive means we have 48 odd and 48 even integers
E O E / 4 = Integer, therefore we have 48 / 96 numbers divisible by 8
O E O / 4 = Not Integer
We cannot forget multiples of 8 from 1 to 96
We have 24 numbers that are multiple of 4
Therefore, 48/96 + 24/96 = 72/96 = 3/4
answer : E
Answer: (E) 3/4
Question: A train is 360 meter long is running at a speed of 56 km/hour. In what time will it pass a bridge of 140 meter length.
(A) 20.14 seconds
(B) 12.14 seconds
(C) 22.14 seconds
(D) 32.14 seconds
(E) None of these
Rationale: Explanation:
Speed = 56 Km/hr = 56*(5/18) m/sec
= 140/9 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
=500/140/9=32.14 seconds
Answer: D
Answer: (D) 32.14 seconds
Question: If the sum of a number and its square is 132, then what is the number?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
Rationale: Explanation:
Let the number be x. Then,
x2 + x = 132
=> x2 + x - 132 = 0
=> (x + 12)(x - 11) = 0
=> x = 11
Answer: Option B
Answer: (B) 11
Question: . How many shots of 1cm radius can be prepared from a sphere of 3cm radius?
(A) 20
(B) 72
(C) 27
(D) 83
(E) 83
Rationale: Explanation:
4/3 π * 3 * 3 * 3 = 4/3 π * 1 * 1 * 1 * x
x = 27
Answer: Option C
Answer: (C) 27
Question: If c<0, which of the following represents a positive number?
(A) |c|/c
(B) |c|c
(C) -c|c|
(D) c/ |c|
(E) c|c|
Rationale: Answer : C
Answer: (C) -c|c|
Question: Arun took a loan of Rs. 1400 with simple interest for as many years as the rate of interest. If he paid Rs.686 as interest at the end of the loan period, what was the rate of interest?
(A) 8%
(B) 6%
(C) 4%
(D) 7%
(E) 5%
Rationale: Explanation :
Let rate = R%
Then, Time, T = R years
P = Rs.1400
SI = Rs.686
SI= PRT/100
⇒686 = 1400 × R × R /100
⇒686=14 R^2
⇒49=R^2
⇒R=7
i.e.,Rate of Interest was 7%
Answer : Option D
Answer: (D) 7%
Question: Find the largest number of five digits which is exactly divisible by 12 and 15 ?
(A) A)12960
(B) B)13050
(C) C)10025
(D) D)11080
(E) E)12080
Rationale: The largest five digit numbers are
13050,12960,12080
13050 is not divisible by 12
12960 is divisible by both 12 and 15
ANSWER:A
Answer: (A) A)12960
Question: Find H.C.F. of 0.63 and 1.05
(A) 0.18
(B) 0.35
(C) 0.5
(D) 0.17
(E) 0.21
Rationale: H.C.F. of 63 and 105 is 21.
In decimal form: H.C.F. = 0.21
Answer: Option E
Answer: (E) 0.21
Question: Jansi’s age is one-sixth of her mother’s age. Jansi’s mother’s age will be two times of Lenin’s age after 10 years. If Lenin’s 8-th birthday was celebrated 2 years before, then what is Jansi’s current age?
(A) 2 years
(B) 5 years
(C) 7 years
(D) 8 years
(E) 9 years
Rationale: B
5 years.
Lenin’s age after 10 years = (8 + 2 + 10) years = 20 years
Jansi’s mom’s age after 10 years = 40 years.
Jansi’s mom’s current age = 30 years.
Therefore, Jansi’s age = (1/6)x 30 years
= 5 years.
Answer: (B) 5 years
Question: If n is a positive integer and the product of all integers from 1 to n, inclusive, is a multiple of 440, what is the least possible value of n?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
Rationale: is it 11 ?
440 = 2 * 2 * 2 * 5 * 11
so the least value forNcan be 11.
B
Answer: (B) 11
Question: If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
(A) 7
(B) 9
(C) 4
(D) 13
(E) None
Rationale: Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y
Then, 6x + 8y = 1/10 and 26x + 48y = 1/2
Solving these two equations, we get : x = 1/100 and y = 1/200
15 men + 20 boy)'s 1 day's work = (15/100 + 20/200) = 1/4
15 men and 20 boys can do the work in 4 days.
Answer: C
Answer: (C) 4
Question: Different breeds of dogs get older at different rates in “dog years.” Livonian wolfhounds age 6 times as fast as humans, whereas Khazarian terriers age 5 times as fast and Akkadian retrievers age 4 times as fast. If Dan bought a newborn Akkadian on January 1, 2010, a newborn Khazarian 1 year later, and a newborn Livonian 1 year after that, in what year will the sum of the dog-year ages of the Akkadian and the Khazarian first be exceeded by twice the age of the Livonian in dog years, rounding all ages down to the nearest integer?
(A) 2017
(B) 2014
(C) 2015
(D) 2016
(E) 2013
Rationale: chart starting at 2011: A=4
2012 = A=8 K=5 A+K =13
L=0.
Then I added 9 to a+k for each year and 12 to L for each year.
2013:AK=22 L=12
2014:AK=31 L=24
2015:AK=40 L=36
2016 :AK=49 L=48
2017: AK=59 L=60
A
Answer: (A) 2017
Question: If the sides of a triangle are 196 cm, 81 cm and 277 cm, what is its area?
(A) 5000
(B) 5656
(C) 7878
(D) 7900
(E) 7938
Rationale: The triangle with sides 196 cm, 81 cm and 277 cm is right angled, where the hypotenuse is 277 cm.
Area of the triangle = 1/2 * 81 * 196 = 7938 cm2
Answer: Option E
Answer: (E) 7938
Question: Presently a mixture in a tub contains substances A and B in the ratio of 7:5. If 9 litres of this solution is drawn out and B is added to the mixture in certain quantity the resulting mixture becomes 7:9. How much litres of liquid A was kept in the tub initially?
(A) 87
(B) 265
(C) 88
(D) 21
(E) 91
Rationale: Explanation:
Currently the mixture is in ratio of A/B: 7:5
=> This means fraction of A in the solution: 7/12
=> Fraction of B in the solvent: 5/12
=>New concentration of A= 7-(7/12)9
=>New concentration of B= 5-(5/12)9+x
=> (7-(7/12)9)/(5-(5/12)9+x) = 7/9
=>x=21
ANSWER: D
Answer: (D) 21
Question: For each hour of production, a certain factory requires 1 assembly line worker for every 25 units to be produced in that hour. The factory also requires 14 managers regardless of the number of units to be produced. Which of the following expressions represents the total number of assembly line workers and managers that this factory requires to produce 50N in one hour, where N is a positive integer?
(A) 12 + 50N
(B) 12 + 2N
(C) 62N
(D) 37N
(E) 14 + 2N
Rationale: 25 units = 1 worker;
50N units = 50N/25 = 2N workers.
So, the answer is 2N workers plus 14 managers.
Answer: E.
Answer: (E) 14 + 2N
Question: A and B can do a work in 25 days and 10 days respectively. A starts the work and B joins him after 2 days. In how many days can they complete the remaining work?
(A) 4.28 days
(B) 4.38 days
(C) 5.28 days
(D) 6.28 days
(E) 2.28 days
Rationale: Work done by A in 2 days = 2/5
Remaining work = 3/5
Work done by both A and B in one day = 1/25 + 1/10 = 7/50
Remaining work = 3/5 * 50/7 = 4.28 days.
ANSWER:A
Answer: (A) 4.28 days
Question: A 20 litre mixture of milk and water contains milk and water in the ratio 3 : 2. 10 litres of the mixture is removed and replaced with pure milk and the operation is repeated once more. At the end of the two removal and replacement, what is the ratio Q of milk and water in the resultant mixture?
(A) 17 : 3
(B) 9 : 1
(C) 3 : 17
(D) 5 : 3
(E) 11: 2
Rationale: he 20 litre mixture contains milk and water in the ratio of 3 : 2. Therefore, there will be 12 litres of milk in the mixture and 8 litres of water in the mixture.
Step 1.
When 10 litres of the mixture is removed, 6 litres of milk is removed and 4 litres of water is removed. Therefore, there will be 6 litres of milk and 4 litres of water left in the container. It is then replaced with pure milk of 10 litres. Now the container will have 16 litres of milk and 4 litres of water.
Step 2.
When 10 litres of the new mixture is removed, 8 litres of milk and 2 litres of water is removed. The container will have 8 litres of milk and 2 litres of water in it. Now 10 litres of pure milk is added. Therefore, the container will have 18 litres of milk and 2 litres of water in it at the end of the second step. Therefore, the ratio of milk and water is 18 : 2 or 9 : 1.
Shortcut.
We are essentially replacing water in the mixture with pure milk.
Let W_o be the amount of water in the mixture originally = 8 litres.
Let W_r be the amount of water in the mixture after the replacements have taken place.
Then,{W_r}/{W_o}= (1-R/M)^n
where R is the amount of the mixture replaced by milk in each of the steps, M is the total volume of the mixture and n is the number of times the cycle is repeated.
Hence, {W_r}/{W_o} =(1/2)^2  =1/4
Therefore Q,W_r ={W_o}/4= 8/4 = 2 litres.B
Answer: (B) 9 : 1
Question: The ratio of the ages of Anil and his son at present is 7:3. Six years hence, the ratio of the ages of the Anil's wife and the son will be 2:1. Find the ratio of the present ages of Anil and his wife?
(A) 2:2
(B) 2:9
(C) 2:4
(D) Cannot be determined
(E) None of these
Rationale: Let the present ages of Anil and his son be 7x and 3x years respectively.
Let the present age of the son's mother be m years.
(m + 6)/(3x + 6) = 2/1
m = 6x + 6
Ratio of the present ages of Anil and his son's mother = 7x/(6x + 6).
This cannot be found uniquely.
Answer:D
Answer: (D) Cannot be determined
Question: Twenty six years ago,a father was three times as old as his son.Now the father is only twice as old as his son. Then the sum of the present ages of the son and the father is :
(A) 120
(B) 156
(C) 108
(D) 105
(E) 86
Rationale: Let the present ages of the father and son be 2x and x years respectively.
then,(2x-26)=3 (x-26)
x=52.
Required sum =(2x+x)=3x=156 years.
Answer is B
Answer: (B) 156
Question: 55% of respondents to a survey consisted of those who used both M and N and those who used neither M nor N. 47% of respondents did not use M. 40% used N. What percent of respondents used only N?
(A) 16%
(B) 21.5%
(C) 20%
(D) 18.5%
(E) 17.5%
Rationale: From the question, we can summarize the information as follows:
N Not N
M X
Not M Ans y 47
40 100
Then we can set a system of 3 equations 3 unknowns described below:
X + Y = 55
X + Ans = 40
Y + Ans = 47
Sum up all three equations to get 2X + 2Y + 2Ans = 142
Divide both sides by 2 to get X + Y + Ans = 71
Replace X + Y with 55 to get 55 + Ans = 71
Substract 55 from both sides to get Ans = 71 - 55 = 16
The answer must be A.
Answer: (A) 16%
Question: A palindrome is a word or a number that reads the same forward and backward. For example, 2442 and 111 are palindromes. If 5-digit palindromes are formed using one or more of the digits 1, 2, 3, 4, 5, and 6, how many palindromes are possible?
(A) 36
(B) 96
(C) 132
(D) 216
(E) 256
Rationale: There are 6 choices for each of the first three digits.
The number of possible palindromes is 6^3=216.
The answer is D.
Answer: (D) 216
Question: A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
(A) 40 sec
(B) 32 sec
(C) 12 sec
(D) 85 sec
(E) 56 sec
Rationale: Answer: Option A
Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 2/25 = 40 sec
Answer: (A) 40 sec
Question: A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m. ?
(A) 9.38 a.m
(B) 9.36 a.m
(C) 9.30 a.m
(D) 9.10 a.m
(E) 9.40 a.m
Rationale: Relative speed = 2 + 3 = 5 rounds per hour.
So, they cross each other 5 times in an hour and 2 times in half an hour.
Hence, they cross each other 7 times before 9.30 a.m.
Answer:C
Answer: (C) 9.30 a.m
Question: Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1120?
(A) 1000
(B) 289
(C) 209
(D) 280
(E) 892
Rationale: 1120 = P [1 + (5*12/5)/100]
P= 1000
Answer: A
Answer: (A) 1000
Question: One train is traveling 45 kmph and other is at 10 meters a second. Ratio of the speed of the two trains is?
(A) 5:4
(B) 2:8
(C) 5:1
(D) 5:2
(E) 5:9
Rationale: 45 * 5/18 = 10
25:20 => 5:4
Answer:A
Answer: (A) 5:4
Question: The sum of the ages of a father and son is 45 years. Five years ago, the product of their ages was four times the fathers age at that time. The present age of father and son
(A) 34,11
(B) 35,10
(C) 36,9
(D) 40,5
(E) 41,5
Rationale: Explanation:
Let sons age = x years. Then fathers age = (45 - x)years.
(x—5)(45—x—5) = 4(45- x - 5) hence (x—5) = 4 so x = 9
Their ages are 36 years and 9 years.
Answer: Option C
Answer: (C) 36,9
Question: A train traveling at 100 kmph overtakes a motorbike traveling at 64 kmph in 18 seconds. What is the length of the train in meters?
(A) 180 meters
(B) 1111 meters
(C) 1777 meters
(D) 1822 meters
(E) None of these
Rationale: Train overtakes a bike means that we are talking about total length of the train. (train's head is close to bike when it started and its tail crosses the bike when it overtakes the bike)
Relative speed= 100-64= 36Km/h = 36000 m/h
time= 18 seconds
Distance= speed*time
36000* 18/3600= 180 meters.
A is the answer.
Answer: (A) 180 meters
Question: A, B and C can do a work in 7 , 14 and 21 days respectively. They completed the work and got Rs.242. What is the share of C?
(A) 33
(B) 44
(C) 55
(D) 11
(E) 31
Rationale: The ratio of their working rates = 1/7 : 1/14 : 1/21 = 6 : 3 : 2.
Since, they work together, the share of C
= 2/11 * 242 = Rs.44
Answer: B
Answer: (B) 44
Question: How many times the keys of a writer have to be pressed in order to write first 50 counting no's?
(A) 90
(B) 91
(C) 92
(D) 93
(E) 94
Rationale: 1 to 9 = 9 * 1 = 9
10 to 50 = 41 * 2 = 84
-----------
93
D
Answer: (D) 93
Question: An electric motor makes 3,000 revolutions per minutes. How many degrees does it rotate in one second?
(A) 19,000 degrees / second
(B) 17,000 degrees / second
(C) 16,000 degrees / second
(D) 18,000 degrees / second
(E) 28,000 degrees / second
Rationale: 3000 revolutions / minute
= 3000*360 degrees / 60 seconds
= 18,000 degrees / second.
Answer is D.
Answer: (D) 18,000 degrees / second
Question: Two pipes A and B can fill a tank in 10 hrs and 40 hrs respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?
(A) 8 hours
(B) 6 hours
(C) 4 hours
(D) 2 hours
(E) None of these
Rationale: Explanation :
Pipe A can fill 1⁄10 of the tank in 1 hr
Pipe B can fill 1⁄40 of the tank in 1 hr
Pipe A and B together can fill 1⁄10 + 1⁄40 = 1⁄8 of the tank in 1 hr
i.e., Pipe A and B together can fill the tank in 8 hours .Answer : Option A
Answer: (A) 8 hours
Question: If 6th March, 2021 is Thursday, what was the day of the week on 6th March, 2020?
(A) Sunday
(B) Saturday
(C) Tuesday
(D) Wednesday
(E) None of these
Rationale: Solution
The year 2020 is a leap year. So, it has 2 odd days.
But, Feb 2020 not included because we are calculating from March 2020 to March 2021. So it has 1 odd day only.
The day on 6th March, 2021 will be 1 day beyond the day on 6th March, 2020. Given that, 6th March, 2021 is Thursday.
6th March, 2020 is Wednesday (1 day before to 6th March, 2021)
Answer D
Answer: (D) Wednesday
Question: Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran's share in the profit?
(A) Rs.10528
(B) Rs.10521
(C) Rs.10511
(D) Rs.10411
(E) Rs.10500
Rationale: Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran's share = 24500 * 3/7
= Rs.10500
Answer: E
Answer: (E) Rs.10500
Question: How many distinct four-digit numbers can be formed by the digits {1, 2, 3, 4, 5, 5, 6, 6}?
(A) 280
(B) 360
(C) 486
(D) 560
(E) 606
Rationale: Option 1: each group of 4 different digits will produce 4!=24 four-digit numbers
- Option 2: each group of 4 digits that contains two 5's will produce 4!/2=12 four-digit numbers
- Option 3: same with option 2 -> 4!/2=12 four-digit numbers
- Option 4: 4!/4=6 four-digit numbers
In total, there are: 15*24 + 10*12 + 10*12 + 1*6 = 606 four-digit numbers.
ANSWER:E
Answer: (E) 606
Question: A train 360 m long is running at a speed of 72 km/hr. In what time will it pass a bridge 140 m long?
(A) 40 sec
(B) 29 sec
(C) 25 sec
(D) 27 sec
(E) 34 sec
Rationale: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 1/20
= 25 sec
Answer: C
Answer: (C) 25 sec
Question: The length of a rectangle is reduced by 22%. By what % would the width have to be increased to maintainthe original area?
(A) 15%
(B) 20%
(C) 28%
(D) 35%
(E) 40%
Rationale: Sol. Required change = (22*100)/(100-22)=28%
C
Answer: (C) 28%
Question: The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 50% profit?
(A) 260.
(B) 960.
(C) 968.
(D) 9690.
(E) 260.
Rationale: Let C.P. = Rs. x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 150% of Rs. 640 = 150/100 * 640 = Rs. 960.
Answer:B
Answer: (B) 960.
Question: The sum of the ages 4 members of a family 5years ago was 94.Today,when the daughter has been married off and replaced by a daughter-in-law,the sum of their ages is 100.Assuming that there has been no other change in the family structure and all members are alive,what is the difference in the ages of daughter and daughter-in-law ?
(A) 22
(B) 11
(C) 25
(D) 14
(E) 16
Rationale: Solution:sum of ages of 4 members 5 years ago=94
=>sum of present ages of 4 members=94+ 4*5=114
Difference in the sum of the ages=Difference in the ages of daughter and daughter-in-law
Difference in the sum of the ages=114-100=14
=>Difference in the ages of daughter and daughter-in-law=14
Answer D
Answer: (D) 14
Question: In a Lake, there is a patch of lily pads. Every day, the patch doubles in size. It takes 50 days for the patch to cover the entire lake, how many days would it take the patch to cover half of the lake?
(A) 36
(B) 2^4*3
(C) 24
(D) 38
(E) 49
Rationale: So 49 days
Answer E=49
Answer: (E) 49
Question: In a garden, there are three blue flowers, three blue flowers, three yellow flowers, and three grey flowers. What is the probability that a girl will choose three flowers of the same color when randomly picking three flowers?
(A) 4/55
(B) 3/55
(C) 7/55
(D) 4/33
(E) 1/55
Rationale: P(all the same color) = P(1st flower is ANY color AND 2nd flower is same as first AND 3rd flower is also the same color)
= P(1st flower is ANY color)xP(2nd flower is same as 1st)ANDP(3rd flower is the same color)
= 1x2/11x1/10
= 1/55
Answer: E
Answer: (E) 1/55
Question: The radius of a cylinder is 2 r units and height is 3 r units. Find the curved surface?
(A) 27
(B) 16
(C) 12
(D) 18
(E) 11
Rationale: 2 * π * 2r * 3r = 12 πr2
Answer:C
Answer: (C) 12
Question: 500 x 223 + 500 x 77 = ?
(A) 2736900
(B) 2738800
(C) 150000
(D) 2716740
(E) None of them
Rationale: =8796 x (223+77) (by distributive law)
=500 x 300
=150000
Answer is C
Answer: (C) 150000
Question: j, b, and c are positive integers. If j, b, and c are assembled into the six-digit number jbcjbc, which one of the following must be a factor of jbcjbc?
(A)  16
(B)  13
(C)  5
(D)  3
(E)  none of the above
Rationale: Plug in some values and check -
jbcjbc = 123123
Not divisible by 16 and 5
let jbcjbc = 125125
Not divisible by 3
Only option (B) and (E) is left in both the cases...
Check once more to marke (B) as correct answer
let jbcjbc = 135135
Again divisible by 13
So, mark answer as (B) 13
Answer: (B)  13