mathewhe/aqua_rat huggingface dataset:
Question: Two trains leave the same train station at 6:00 am and 6:30 am and they travel at 100 kph and 120 kph respectively. How many kilometers from the train station will the two trains be together?
(A) 300
(B) 320
(C) 340
(D) 360
(E) 380
Rationale: At 6:30, the first train is 50 km ahead.
The second train gains 20 km each hour.
The time it takes the second train to catch the first train is 50 /20 = 2.5 hours.
In this time, the second train travels 2.5*120=300 km.
The answer is A.
Answer: (A) 300
Question: One hour after Matthew started waking from e to y, a distance of 45km, Johnny started walking along the same road from y to e. Matthew's walking rate was 3 km per hour and Johnny's was 4km per hour, how many km had Johnny walked when they met?
(A) 24
(B) 23
(C) 22
(D) 21
(E) 19.5
Rationale: Just an alternative method...
After the first hour the distance e is 42 km (45-3). Now the problem can be treated as if bothof them started at the same time. Since the speeds are in the ratio 3 : 4, the distances will also be in the same ratio. Splitting 42 in that ratio we get 18 : 24. So answer is 24.
Hence A.
Answer: (A) 24
Question: what is the Max number of rectangular boxes, each measuring 4 inches by 6 inches by 10 inches, that can be packed into a rectangular packing box measuring 16 inches by 18 inches by 30 inches, if all boxes are aligned in the same direction?
(A) 36
(B) 14
(C) 12
(D) 15
(E) 11
Rationale: The 4 inch side should be aligned to the 16 inch side ( 4 layer)
6 inch side should be aligned to the 18 inch side. (3 layer)
and 10 inch side should be aligned to the 30 inch side.(3 layer)
Maximum number of rectangles =4*3*3=36
Answer is A
Answer: (A) 36
Question: In an arithmetic progression the difference between the any two consecutive terms is a constant. What is the arithmetic mean of all of the terms from the first to the 29th in an arithmetic progression if the sum of the 13th and 17th terms of the sequence is 102?
(A) 43
(B) 47
(C) 51
(D) 55
(E) 59
Rationale: Let x be the difference between any two consecutive terms.
The mean of a sequence like this is the middle term, thus the 15th term in the sequence.
Then the mean of the 14th and 16th term is also equal to the overall mean, because the 14th term is (15th term - x) and the 16th term is (15th term + x).
Similarly the mean of the 13th and 17th term is also equal to the mean.
etc...
Thus the mean is 102/2 = 51
The answer is C.
Answer: (C) 51
Question: Hariprasad and Madhusudan started a business, investing sums in the ratio of 2 : 3. If Hariprasad had invested an additional amount of 10,000 the ratio of Hariprasad's investment to Madhusudan's investment would have been 3 : 2. What was the amount invested by Hariprasad?
(A) 8000
(B) 12000
(C) 9000
(D) Data inadequate
(E) None of these
Rationale: Let the initial investments of Hariprasad and Madhusudan be 2x and 3x,respectively.
From the question,
2x+10000/3x=32
or, 4x + 20000 = 9x
\ x = 4000
\ Amount invested by Hariprasad = 2x = 8000
Answer A
Answer: (A) 8000
Question: In 1950, Richard was 4 times as old as Robert. In 1955, Richard was 3 times as old as Robert. In which year was Richard 1.5 times as old as Robert?
(A) 1960
(B) 1965
(C) 1970
(D) 1975
(E) 2000
Rationale: In 1950: Ri = 4 Ro -------------- eq1
In 1955: Ri +5 = 3(Ro+5)---------eq2
Thus in 1950, solving eq1 and eq2
Ro= 10 , Ri =40
Now for each year we can calculate:
2000: Ri= 60, Ro = 90
Thus Ans:E
Answer: (E) 2000
Question: In a hot dog eating contest the average number of hot dogs that were eaten by boys was 7 each, and the average number eaten by girls was 5 each. If the total number of hot dogs eaten during the contest was 50, what was the total number of boys and girls in the contest?
(A) 6
(B) 7
(C) 8
(D) 9
(E) 10
Rationale: We can determine quickly that total number should range between 50/7<= N <= 50/5 , so ans should be between 7 and 10.
Now solving the expression 7A+5B =50
decreasing 50 by multiples of 7 and checking divisibility of that number by 5, we get
5 boys and 3 girls will total 50 hot dogs, 5*7 + 3*5 = 50
Hence total number is 5 + 3 = 8
Ans C
Answer: (C) 8
Question: A certain restaurant offers 8 different salads, 6 different main courses, 6 different desserts. If customers choose one salad, one main course and two different desserts for their meal, how many different meals are possible?
(A) 120
(B) 240
(C) 480
(D) 600
(E) 1200
Rationale: MAGOOSHOFFICIAL SOLUTION:
To count the number of meals, we have to count the possibilities for the three components, and then, according to theFundamental Counting Principle, we multiply. For more on the FCP, seethis blog.
For salads, there are 8 possibilities. Done.
For main courses, there are 5 different possibilities. Done.
For desserts, there are 6 choices, but we pick two different choices. This would be 6C2. To calculate this, we can usethe shortcut, nC2 = (n*(n-1))/2.
6C2 = (6*5)/2 = 15
So, there are 15 combinations of two different desserts.
For the number of meals, we multiply 8*6*15=720
Answer = A
Answer: (A) 120
Question: A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 650 sq. feet, how many feet of fencing will be required?
(A) 34
(B) 40
(C) 85
(D) 88
(E) None
Rationale: EXPLANATION
We have: l = 20 ft and lb = 650 sq. ft.
So, b = 32.5 ft.
Length of fencing = (l + 2b) = (20 + 65) ft = 85 ft.
Answer C
Answer: (C) 85
Question: If an article is sold at 19% profit instead of 12% profit, then the profit would be Rs. 105 more. What is the cost price?
(A) 1533
(B) 1543
(C) 1500
(D) 1278
(E) 1202
Rationale: Explanation:
Let the cost price of an article be Rs. x.
(19% of x) - (12% of x) = 105
19x/100 - 12x/100 = 105 => 7x = 105 * 100
=> x = 1500
Cost price = Rs. 1500
Answer:C
Answer: (C) 1500
Question: A shipment of 1500 heads of cabbage, each of which was approximately the same size, was purchased for $600. The day the shipment arrived 1/3 of the heads were sold, each at 25% above the cost per head. The following day the rest were sold at a price equal to 5% less than the price each head sold for on the day before. What was the total gross profit on this shipment.
(A) $100
(B) b $115
(C) c $120
(D) d $125
(E) e $135
Rationale: Purchase cost = 600/1500= $ 0.4
25% above the cost per head = (125/100)*0.4= $ 0.5
2/3 of the heads were sold means 1/3*1500 =500 ,Selling amount for 500 cabbage = 500 * 0.5 = $ 250
Remaining were sold at a price equal to 10% less than the price each head sold for on the day before i.e , (95/100)*0.5 = $ 0.475
Hence selling cost for the remaining cabbage = 1000 * 0.475 = $ 475
Total selling cost = 475 + 250 = $ 725
Gross profit = $ 725 - $ 600 = $ 125
Hence Answer is D
Answer: (D) d $125
Question: 30 men can complete a piece of work in 18 days. In how many days will 27 men complete the same work ?
(A) 20
(B) 77
(C) 36
(D) 25
(E) 13
Rationale: Explanation:
Less Men, means more Days {Indirect Proportion}
Let the number of days be x
then,
27 : 30 :: 18 : x
[Please pay attention, we have written 27 : 30 rather than 30 : 27, in indirect proportion, if you get it then chain rule is clear to you :)]
{\color{Blue} x=\frac{30\times 18}{27}}
x = 20
So 20 days will be required to get work done by 27 men.
Answer: A
Answer: (A) 20
Question: QUANT 4-PACK SERIES Problem Solving Pack 4 Question 2 For every positive integer n...
For every positive integer n that is greater than 1, the function a(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The a(n) could have any of the following units digits except…?
(A) 1
(B) 2
(C) 4
(D) 6
(E) 9
Rationale: For every positive integer n that is greater than 1, the function a(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The a(n) could have any of the following units digits except…?
Used brute force on this one to calculate. Not sure if there is a quicker way.
1+3=4 C is out
1+3+....15= 81 A is out
1+3+5+7=16 D is out
1+3+5=9 E i out
Answer: B
Answer: (B) 2
Question: A towel, when bleached, lost 30% of its length and 25% of its breadth. What is the percentage decrease in area?
(A) 24%
(B) 30 %
(C) 44%
(D) 54%
(E) 47.5%
Rationale: percentage change in area
=(−30−25+(30×25)/100)%=−47.5%
i.e., area is decreased by 47.5%
ANSWER:E
Answer: (E) 47.5%
Question: A computer manufacturer produces a certain electronic component at a cost of $80 per component. Shipping costs for delivering the components are $7 per unit. Further, the manufacturer has costs of $16,500 a month related to the electronic component regardless of how many it produces. If the manufacturer produces and sells 150 components a month, what is the lowest price it can sell them for such that the costs don't exceed the revenues?
(A) $28
(B) $82
(C) $110
(D) $138
(E) $197
Rationale: by the question, the equation would be 150 p - 87*150 - 16500 = 0
p being the price we want to find and equation resulting zero means revenue and costs are equal so we can get the minimum price of the component.
solving the equation, we get p = $ 197. Answer E for me.
Answer: (E) $197
Question: 2 hours after a freight train leaves Delhi a passenger train leaves the same station travelling in the same direction at an average speed of 16 km/hr. After travelling 4 hrs the passenger train overtakes the freight train. The average speed of the freight train was?
(A) 30
(B) 40
(C) 58
(D) 60
(E) 11
Rationale: let the speed of freight train be xkm/hr
distance covered by freight train in 6 hours=distance covered by passenger train in 4 hrs
6x=16*4
x=10.66
x=11 km/hr
ANSWER:E
Answer: (E) 11
Question: A certain car traveled twice as many miles from Town A to Town B as it did from Town B to Town C. From Town A to Town B, the car averaged 12 miles per gallon, and from Town B to Town C, the car averaged 11 miles per gallon. What is the average miles per gallon that the car achieved on its trip from Town A through Town B to Town C?
(A) 13
(B) 13.5
(C) 14
(D) 14.5
(E) 15.3
Rationale: Ans is B
Given d_ab = 2*d_bc
let d_ab = d and d_bc = x so d=2x
for average miles per gallon = (d+x)/((d/12)+(x/11)) = 15.3 (formula avg speed = total distance/ total time)
Answer: (B) 13.5
Question: If 5 less than x is 2 greater than y, then a number z that is 5 greater than x reduced by y is equal to
(A) 12
(B) 9
(C) 14
(D) y + 9
(E) y + 14
Rationale: 12 it is....nice one....
A
Answer: (A) 12
Question: An analyst will recommend a combination of 2 industrial stocks, 2 transportation stocks, and 2 utility stocks. If the analyst can choose from 5 industrial stocks, 4 transportation stocks, and 3 utility stocks, how many different combinations of 6 stocks are possible?
--
(A) 12
(B) 19
(C) 60
(D) 160
(E) 180
Rationale: 5C2 * 4C2 * 3C2 = 10*6*3 = 180.
Answer: E.
Answer: (E) 180
Question: A trader marked the selling price of an article at 10% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of :
(A) 10 %
(B) 10.5 %
(C) 11 %
(D) 12.5 %
(E) None
Rationale: Sol.
Let C.P. = Rs. 100. Then, Marked Price = Rs. 110, S.P. = Rs. 99.
∴ Discount % = [11/110 * 100] % = 10%
Answer A
Answer: (A) 10 %
Question: Karen places a bet with Tom that she will beat Tom in a car race by 4 miles even if Karen starts 4 minutes late. Assuming that Karen drives at an average speed of 60 mph and Tom drives at an average speed of 45 mph, how many Y miles will Tom drive before Karen wins the bet?
(A) 15
(B) 18
(C) 21
(D) 24
(E) 27
Rationale: Let K and T be the speeds of Karen and Tom respectively.
t be the time that Karen will travel ----> t+4/60 will be the total time Tom will travel by the time the distance between Karen and Tom is 4 miles.
Thus, per the question , K(t) - T(t+4/60) = 4 ---> t = 7/15 hours
Thus the distance traveled by Tom when Karen is 4 miles ahead of him Y: T*(t+4/60) = 45 (7/15+4/60) = 24 miles. D is the correct answer.
Answer: (D) 24
Question: The price of a scooter and TV are in the ratio 7:5. If the scooter costs $100 more than the TV. then the price of the TV?
(A) 400
(B) 350
(C) 250
(D) 500
(E) 150
Rationale: Let the price of the scooter and TV is 7x and 5x
7x-5x = 100
x = 50
Price of TV = 7*50 = $350
Answer is B
Answer: (B) 350
Question: A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6900?
(A) s. 4991
(B) s. 5991
(C) s. 6001
(D) s. 6991
(E) s. 7391
Rationale: total fr 5 mnths=(6435+6927+6855+7230+6562)=Rs34009.
Reqd.sale=Rs.[(6900*6)-34009]
= Rs.(41400-34009)
= Rs.7391.
ANSWER:E
Answer: (E) s. 7391
Question: In an animal behavior experiment, 25 tagged white pigeons and 250 tagged gray pigeons were released from a laboratory. Within one week, 88 percent of the white pigeons and 80.5 percent of the gray pigeons had returned to the laboratory. What percent of the total number of pigeons returned to the laboratory?
(A) 80.5
(B) 82
(C) 81.5
(D) 85
(E) 81.25
Rationale: Weighted mix method is best here....
Ratio is 1:10 for 88:80.5...
So the answer required = 80.5+ (88-80.5)*1/10=80.5+7.5*1/10
80.5+0.75=81.25
E
Answer: (E) 81.25
Question: If four boxes of crayons contain six different colored crayons in each box, and a crayon is randomly selected from each box, what is the probability of getting at least one pair of the same colored crayons?
(A) 13/18
(B) 5/18
(C) 1/2
(D) 2/3
(E) 1/6
Rationale: AT LEAST one pair of matching crayons.
First solve for NO matching crayons:
1st box = any color = 6/6
2nd box = not a match to the first = 5/6
3rd box = not a match to the 1st or 2nd = 4/6
4th box = not a match to the 1st or 2nd or 3rd = 3/6
(6/6)(5/6)(4/6)(3/6) =
(1)(5/6)(2/3)(1/2) =
10/36
10/36 is the probability of NO matching crayons, so...
1 - 10/36 = 26/36 = the probability of getting at least one matching pair of crayons.
26/36 = 13/18
Answer: A
Answer: (A) 13/18
Question: A certain quantity is measured on two different scales, the R scale and the S scale, that are related linearly. Measurements on the R scale of 6 and 24 correspond to the measurements on the S scale of 30 and 60 respectively. What measurement on the R scale corresponds to a measurement of 75 on the S scale?
(A) 30
(B) 33
(C) 36
(D) 39
(E) 42
Rationale: A change of +18 on the R scale is a change of +30 on the S scale.
R = (18/30)*S + K = 3S/5 + K
6 = 3(30)/5 + K
K = -12
R = 3S/5 - 12
R = 3(75)/5 - 12 = 45-12 = 33
The answer is B.
Answer: (B) 33
Question: John invested $ 30000 at 7% per annum, He got 34347 after some period, The interest was calculated compoundly. Find the period?
(A) 2 Years
(B) 2 1/2 Years
(C) 3 Years
(D) 4 Years
(E) 3 1/2 Years
Rationale: P(1+(R/100))power of n
so
=30000(1+(7/100))power of n = 34347
=(107/100)Power of n=34347/30000
To simplify 34347/30000
We get 11449/10000
This is in the form of (107/100) power of 2
so The value of n is 2
Answer is 2 years
Answer: (A) 2 Years
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
(A) 35 years
(B) 40 years
(C) 50 years
(D) 45 years
(E) None of these
Rationale: Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Answer: Option B
Answer: (B) 40 years
Question: A call center has two teams. Each member of Team A was able to process 2/5 calls as compared to each member of Team B. If Team A has 5/8 as many number of call center agents as Team B, what fraction of the total calls was processed by Team B?
(A) 3/2
(B) 3/4
(C) 4/5
(D) 1/2
(E) 1/5
Rationale: Let team B has 8 agents, so team A has 5 agents
Let each agent of team B picked up 5 calls, so total calls by team B = 40
So, each agent in Team A picked up 2 calls, so total calls for team A = 10
Fraction for team B = 40/(40+10) = 4/5 = Answer = C
Answer: (C) 4/5
Question: A grocer has 400 pounds of coffee in stock, 30 percent of which is decaffeinated. If the grocer buys another 100 pounds of coffee of which 60 percent is decaffeinated, what percent, by weight, of the grocer’s stock of coffee is decaffeinated?
(A) 28%
(B) 30%
(C) 36%
(D) 36%
(E) 40%
Rationale: 1. 30% of 400=120 pounds of decaffeinated coffee
2. 60% of 100=60 pounds of decaffeinated coffee
3. Wt have 180 pounds of decaffeinated out of 500 pounds, that means 180/500*100%=36%. The correct answer is D.
Answer: (D) 36%
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years.
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
Rationale: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years.
Answer: Option D
Answer: (D) 10
Question: A reduction of 10% in the price of rice enables a man to obtain 2 kgs more for Rs.1000, what is the reduced price for kg?
(A) Rs.40
(B) Rs.44
(C) Rs.46
(D) Rs.48
(E) Rs.50
Rationale: Explanation:
1000*(10/100) = 100 ---- 2
? ---- 1 => Rs.50
Answer: E
Answer: (E) Rs.50
Question: A, B and C can do a work in 4 days, 8 days and 12 days respectively. In how many days can all three of them working together, complete the work?
(A) 2 9/11 days
(B) 5 2/11 days
(C) 2 1/11 days
(D) 3 2/11 days
(E) 2 2/11 days
Rationale: Work done by all three of them in one day = 1/4+ 1/8 + 1/12 = 11/24.
The number of days required = 24/11 = 2 2/11 days.
ANSWER:E
Answer: (E) 2 2/11 days
Question: A monkey start climbing up a tree 20ft tall.Each hour it hops 3 ft and slips back 2ft.How much time would it take the monkey to reach the top.
(A) 15 hrs
(B) 18 hrs
(C) 19 hrs
(D) 17 hrs
(E) 16 hrs
Rationale: if monkey hops 3ft and slips back 2ft in a hour, it means the monkey hops (3ft-2ft)= 1ft/hr.
similarly in 17hrs it wil be 17ft.
Bt since the height of the tree is 20ft, so if the monkey hops up the tree in the next hr i.e 18th hr then it reaches at the top of the tree.
hence it takes 18 hrs for monkey to reach at the top
ANSWER:B
Answer: (B) 18 hrs
Question: A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 2 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m. ?
(A) A)5
(B) B)61
(C) C)8
(D) D)6
(E) E)9
Rationale: Relative speed = 2 + 2 = 4 rounds per hour.
So, they cross each other 4 times in an hour and 2 times in half an hour.
Hence, they cross each other 6 times before 9.30 a.m.
ANSWER:D
Answer: (D) D)6
Question: How many digits are in the number 50^8 × 8^3 × 11?
(A) 18
(B) 20
(C) 19
(D) 22
(E) 17
Rationale: Whenever you are asked to find the number of digits, try to bring the number in multiples of 10. This way, we can wasily calculate the umber of 0's through the powers of 10
50^8 × 8^3 × 11 = (5^2*2)^8*2^9*11 = 5^16*2^17*11 = 2*11*10^16 = 22*10^16
Hence we would have 16 trailing 0's and the three digits from 22
Total digits = 2 + 16 = 18
Correct Option: A
Answer: (A) 18
Question: If the average (arithmetic mean) of a and b is 140, and the average of b and c is 100, what is the value of a − c?
(A) −220
(B) −100
(C) 100
(D) 135
(E) 80
Rationale: a+b = 280
b+c = 200
a-c = 80.
IMO option E.
Answer: (E) 80
Question: If [x] is the greatest integer less than or equal to x, what is the value of [-6.2]+[-3.4]+[12.7] ?
(A)  -1
(B)  0
(C)  1
(D)  2
(E)  3
Rationale: You are asked what the closest lesser integer value to [x] is.
[-6.2] = -7.0
[-3.4] = -4.0
[12.7] = 12.0
Therefore , answer is: -7.0 -4.0 + 12.0 = -1.0
Option A.
Answer: (A)  -1
Question: Pipe P can drain the liquid from a tank in 1/4 the time that it takes pipe Q to drain it and in 2/3 the time that it takes pipe R to do it. If all 3 pipes operating simultaneously but independently are used to drain liquid from the tank, then pipe Q drains what portion of the liquid from the tank?
(A) 9/29
(B) 3/23
(C) 3/8
(D) 17/29
(E) 3/4
Rationale: Suppose Q can drain in 1 hr. So, rQ = 1/1 = 1
So, rP = 1/[(1/4)rQ] = 4
Also, rP = rR/(2/3) => 4 = rR/(2/3) => rR = 8/3
Let H is the time it takes to drain by running all 3 pipes simultaneously
So combined rate = rC = 1/H = 1 + 4 + 8/3 = 23/3 = 1/(3/23)
Thus running simultaneously, Pipe Q will drain 3/23 of the liquid.
Thus answer = B.
Answer: (B) 3/23
Question: Find the sum which will yield an interest of Rs.910 in 2 1/2 years at 7% p/a simple interest.
(A) Rs.3200
(B) Rs.4200
(C) Rs.6200
(D) Rs.5200
(E) Rs.7200
Rationale: 70 = (P*4*7/2)/100
P = (910x100x2)/(5x7)=Rs.5200
Answer: D
Answer: (D) Rs.5200
Question: John has taken four (4) tests that have an average of 81. In order to bring his course grade up to a ‘B’, he will need to have a final average of 87. What will he need to average on his final two tests to achieve this grade?
(A) 87
(B) 90
(C) 92
(D) 94
(E) 99
Rationale: 87-81=6*4=24 points
2*87=174
174+24=198 points to be scored in the 2 tests.
Avg of 2 tests = 198/2=99
Answer: E
Traditional Method:
Total scored till now 81*4=324
Total score to avg 87 in 6 tests = 87*6=522
Total to be scored on 2 tests = 522-324=198
Avg on 2 tests = 198/2 = 99
Answer E
Answer: (E) 99
Question: The H.C.F. of two numbers is 59 and the other two factors of their L.C.M. are 13 and 16. The larger of the two numbers is:
(A) 678
(B) 944
(C) 456
(D) 323
(E) 899
Rationale: :	Explanation:
Clearly, the numbers are (59 x 13) and (59 x 16).
{\color{Blue} \therefore } Larger number = (59 x 16) = 944.
Answer: B)944
Answer: (B) 944
Question: In the first M games of a team's season, the ratio of the team's wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:4. If M:N = 4:5, what was the ratio of the team's wins to its losses for all M+N games?
(A) 7:20
(B) 9:23
(C) 11:27
(D) 23:54
(E) 31:77
Rationale: M = 4/9 of total games
N = 5/9 of total games
Wins = 1/3*4/9 + 1/5*5/9 = 4/27 + 3/27 = 7/27
Losses = 1 - 7/27 = 20/27
The ratio of wins to losses is 7:20.
The answer is A.
Answer: (A) 7:20
Question: A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will be
(A) 1,2
(B) 2,3
(C) 3,7
(D) 2,7
(E) 8,7
Rationale: 4 | x y = (5 x 1 + 4) = 9
--------
5 | y -1 x = (4 x y + 1) = (4 x 9 + 1) = 37
--------
| 1 -4
Now, 37 when divided successively by 5 and 4, we get
5 | 37
---------
4 | 7 - 2
---------
| 1 - 3
Respective remainders are 2 and 3.
Correct Option is B
Answer: (B) 2,3
Question: Which of the following is equal to 10^-(-3)^3?
(A) 1/(10^30)
(B) 1/(10^28)
(C) 1/(10^29)
(D) 1/(10^27)
(E) 1/(10^25)
Rationale: 10^-(-3)^3 => 10^-(-3^3) => 10^-(27) = 1/(10^27)
Answer : D
Answer: (D) 1/(10^27)
Question: 3 men or 6 women can do a piece of work in 24 days. In how many days will 12 men and 8 women do the same work?
(A) 15/9 days
(B) 9/2 days
(C) 18/4 days
(D) 11/4 days
(E) 35/4 days
Rationale: 3M = 6W ---- 24 days
12M + 8W -----?
24W + 8 W = 32W ---?
6W ---- 24 32 -----?
6 * 24 = 32 * x => x = 9/2 days
Answer:B
Answer: (B) 9/2 days
Question: In what time will Rs.5000 lent at 3% per annum on simple interest earn as much interest as Rs.5000 will earn in 5 years at 4% per annum on simple interest?
(A) 6 2/3
(B) 6 1/6
(C) 6 1/3
(D) 6 1/2
(E) 6 1/5
Rationale: (5000*3*R)/100 = (5000*5*4)/100
R = 6 2/3
Answer: A
Answer: (A) 6 2/3