mathewhe/aqua_rat huggingface dataset:
Question: A train sets off at 2 p.m. at the speed of 70 kmph. Another train starts at 3:30 p.m. in the same direction at the rate of 85 kmph. At what time the trains will meet?
(A) 10.36
(B) 10.39
(C) 10.3
(D) 10.34
(E) 10.31
Rationale: D = 70 * 1 ½ = 105 km
RS = 85 – 70 = 15
T = 105/15 = 7 h
3.30 + 7 h = 10.30 p.m.
Answer:C
Answer: (C) 10.3
Question: An entry in an unshaded square is obtained by adding the entries connected to it from the row above (11 is one such number). Write the value of n ?
(A) 10
(B) 11
(C) 12
(D) 9
(E) 8
Rationale: see the values row wise
5 6 n 7
11 6+n 7+n
11+6+n 6+n+7+n
60
hence 11+6+n+6+n+7+n =60
n= 10
ANSWER:A
Answer: (A) 10
Question: The population of a town is 10000. It increases annually at the rate of 40% p.a. What will be its population after 2 years?
(A) 14000
(B) 14400
(C) 19600
(D) 14600
(E) 14700
Rationale: Formula :
10000 × 140/100 × 140/100 = 19600
Answer : C
Answer: (C) 19600
Question: Length of a rectangular plot is 20mtr more than its breadth. If the cost of fencing theplot at 26.50 per meter is Rs.5300, what is the length of the plot in mtr?
(A) 40 m
(B) 60 m
(C) 70 m
(D) 77 m
(E) 80 m
Rationale: Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m
B
Answer: (B) 60 m
Question: How much interest will $10,000 earn in 9 months at an annual rate of 4%?
(A) $300
(B) $350
(C) $450
(D) $550
(E) $650
Rationale: Soln:-
9 months = 3/4 of year;
4% = 4/100=1/25;
$10,000(principal)*1/25(interest rate)*3/4(time)=$300.
ANSWER:A
Answer: (A) $300
Question: What is the remainder when 8^714 is divided by 5 ?
(A) 2
(B) 3
(C) 1
(D) 0
(E) 4
Rationale: 8^0 = 1
8^1 = 8
8^2 = 64
8^3 = 512
8^4 = 4096
8^5 = .....8
and so on after ignoring the first last-digit of 8^0 = 1, in a recurring last-digit pattern of 8,4,2,6,8,4,2,6....
715/4 = 178 (with a remainder 2) so the last number is a 4.
so when 8^714 is divided by 5 the remainder is 4, ANS = E
Answer: (E) 4
Question: A small table has a length of 12 inches and a breadth of b inches. Cubes are placed on the surface of the table so as to cover the entire surface. The maximum side of such cubes is found to be 4 inches. Also, a few such tables are arranged to form a square. The minimum length of side possible for such a square is 40 inches. Find b.
(A) 8
(B) 6
(C) 24
(D) 32
(E) 48
Rationale: From the info that the maximum sides of the cubes is 4, we know that the GCF of 12 (=2^2*3) andbis 4 (=2^2), sob=2^x, where x>=2.
From the second premise, we know that the LCM of 12 (2^2*3) andbis 40 (2^3*5), sob=2^3 or 2^3*5 (8 or 40).
Combining 2 premises shows the answer is B(6).
Answer: (B) 6
Question: The edge of a cube is 5a cm. Find its surface?
(A) 150a2 cm2
(B) 170a2 cm2
(C) 125a2 cm2
(D) 175a2 cm2
(E) 120a2 cm2
Rationale: 6a2 = 6 * 5a * 5a = 150a2
Answer:A
Answer: (A) 150a2 cm2
Question: Of the 65 cars on a car lot, 45 have power steering, 25 have power windows, and 17 have both power steering and power windows. How many of the cars on the lot have neither power steering nor power windows?
(A)  2
(B)  8
(C)  12
(D)  15
(E)  18
Rationale: Total -Neither = All power steering + All Power Windows - Both
or 65 - Neither = 45 + 25 -17 = 53.
=> Neither = 12, hence C.
Answer : C
Answer: (C)  12
Question: If x, y, and z are negative integers and 3x - 3y = -3z, then which of the following statements must be true?
I.	x > y>z
II.	x > y
III. x = z
(A) I and II
(B) I only
(C) II only
(D) III only
(E) None
Rationale: 3x-3y=-3z
x-y=-z
Since z<0; -z>0
x-y>0
x>y
II correct.
We can't say much about z though;
x=-5; y=-100; z=-95
I and III incorrect.
Ans:C
Answer: (C) II only
Question: To create paint with a certain shade of gray, one must combine 2.116 liters of black paint with every one liter of white paint. Approximately how many liters of white paint must be combined with 350 liters of black paint to create the certain shade of gray?
(A) 165.4
(B) 176.4
(C) 347.1
(D) 694.4
(E) 705.6
Rationale: Since the ratio of Black to White is 2.016 to 1 this implies that Amount of Black is going to be more than (approximately double) the amount of White. This implies Option C, D and E can not be correct.
Now between A and B:
Black:White = 2.116:1 Since the ratio is more than double, the amount of White Paint should be less than half of Black Paint. B is more than half so can not be the answer, A fits the criteria hence should be the correct answer. No calculation needed whatsoever.
Answer: (A) 165.4
Question: Statements: The old order changed yielding place to new.
Assumption:
1) Change is the law of nature.
2) Discard old ideas because they are old.
(A) Only conclusion I follows
(B) Only conclusion II follows
(C) Either I or II follows
(D) Neither I nor II follows
(E) Both I and II follow
Rationale: Clearly, I directly follows from the given statement. Also, it is mentioned that old ideas are replaced by new ones, as thinking changes with the progressing time. So, II does not follow.
A
Answer: (A) Only conclusion I follows
Question: A man is 24 years older than his son.In two years, his age will be twice the age of his son.The present age of the son is :
(A) 22
(B) 25
(C) 45
(D) 32
(E) 15
Rationale: Let the son's present age be x years. Then, man's present age =(x+24) years.
(x+24)+2=2(x+2)
x+26=2x+4
x=22.
Answer is A
Answer: (A) 22
Question: The numbers in which of the following pairs do NOT have a pair of distinct prime divisors in common?
(A) 10 and 20
(B) 12 and 18
(C) 30 and 16
(D) 21 and 63
(E) 22 and 44
Rationale: 16 has only the prime 2 (16=2^4) in its prime factorization, so it can not have a PAIR of distinct prime divisors in common with ANY of the numbers.
The answer is C.
Answer: (C) 30 and 16
Question: In how many R ways can 4 white and 3 black chess pieces be arranged in a row such that they occupy alternate places? Assume that the pieces are distinct.
(A) 288
(B) R=144
(C) R=12
(D) R=48
(E) 96
Rationale: 4 white chess pieces can be arranged in 4! ways and 4 black pieces can be arranged in 3 ! ways.
W_ W_W_W
Number of ways = 4!*3! = 24 * 6 = 144
Answer B
Answer: (B) R=144
Question: If 25% of x is 20 less than 15% of 1500, then x is?
(A) 872
(B) 820
(C) 837
(D) 840
(E) 83
Rationale: 25% of x = x/4 ; 15% of 1500
= 15/100 * 1500 = 225
Given that, x/4 = 225 - 20
=> x/4 = 205 => x = 820.
Answer:B
Answer: (B) 820
Question: Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest?
(A) 29%p.a
(B) 28%p.a
(C) 20%p.a
(D) 24%p.a
(E) 26%p.a
Rationale: Rs.1440 - 1200
= Rs.240 is the interest on Rs.1200 for one year.
Rate of interest
= (100 * 240) / (100 * 1) = 20%p.a
Answer:C
Answer: (C) 20%p.a
Question: Which of the following functions does not intersect with E = 3x^2 + 2x + 1
(A) E = 3x^2 + 3x + 1
(B) E = 2x^2 + 3x + 1
(C) E = 3x^2 + 2x + 3
(D) E = 4x^2 + 2x - 3
(E) E = x^2 + 2x + 3
Rationale: Let’s find the actual intersecting point of given function and each choice E.
A. 3x^2 + 2x + 1 = 3x^2 + 3x + 1 --> x=0
B. 3x^2 + 2x + 1 = 2x^2 + 3x + 1 --> x^2 – x =0 --> x=0 or 1
C. 3x^2 + 2x + 1 = 3x^2 + 2x + 3 --> 1=3(X) --> they don’t have any intersect.
D. 3x^2 + 2x + 1 = 4x^2 + 2x - 3 --> x^2 –4=0 --> x= 2 or -2
E. 3x^2 + 2x + 1 = x^2 + 2x + 3 --> 2x^2 –2 =0 --> x= 1 or –1.
So only choice (C) has no intersecting point. The answer is (C).
Answer: (C) E = 3x^2 + 2x + 3
Question: Look at this series: 53, 53, 40, 40, 27, 27, ... What number should come next?
(A) 12
(B) 14
(C) 27
(D) 53
(E) 86
Rationale: In this series, each number is repeated, then 13 is subtracted to arrive at the next number.
Answer: B
Answer: (B) 14
Question: A fast food truck spends one third of its monthly budget for truck rent and half of the rest for food and beverages. What percentage of the budget does the fast food truck spend for food and beverages?
(A) 23.5%
(B) 32.5%
(C) 33.33%
(D) 30%
(E) 75%
Rationale: Spend on rent = 1/3
Spend on food and beverage= 1/2 of remaining = 1/2*2/3= 2/6=1/3
So 1/3= 33.33%
C is the answer
Answer: (C) 33.33%
Question: In a apartment, 30% of the people speak English, 20% speak Hindi and 12% speak both. If a people is selected at random, what is the probability that he has speak English or Hindi?
(A) 1/30
(B) 2/30
(C) 19/50
(D) 12/90
(E) 3/70
Rationale: P (E) = 30 / 100 , P (H) = 20 / 100 and P (E âˆ© H) = 12 / 100 =
P (E or H) = P (E U H)
= P (E) + P (H) - P (E âˆ© H)
= (30 / 100) + (20/100 - (12 / 100) = 38/100 = 19/50
C
Answer: (C) 19/50
Question: Difference of two numbers is 1760. If 7.5% of the number is 12.5% of the other number , find the number ?
(A) 2640, 1000
(B) 3660, 4400
(C) 3000, 4160
(D) 2490, 4150
(E) 4660, 3000
Rationale: Let the numbers be x and y. Then, 7.5 % of x =12.5% of y
X = 125*y/75 = 5*y/3.
Now, x-y =1760
5*y/3 –y =1760
2*y/3= 1760
y =[ (1760*3)/2] =2640.
One number = 2640, Second number =5*y/3 =4400.
Answer B.
Answer: (B) 3660, 4400
Question: A student multiplied a number by 3/5 instead of 5/3.
What is the percentage error in the calculation?
(A) 34%
(B) 44%
(C) 54%
(D) 64%
(E) None
Rationale: Let the number be x
Then error = 5/3x - 3/5x = 16/15x
Error%= (16x/15 x 3/5x x 100)% = 64%
Answer: Option D
Answer: (D) 64%
Question: If it is assumed that 60 percent of those who receive a questionnaire by mail will respond and 222 responses are needed, what is the minimum number of questionnaires that should be mailed?
(A) 280
(B) 370
(C) 460
(D) 550
(E) 640
Rationale: Let x be the minimum number of questionnaires to be mailed.
0.6x = 222
x = 370
The answer is B.
Answer: (B) 370
Question: A fruit salad mixture consists of apples, peaches, and grapes. There are 2 times as many pounds of apples as grapes and 3 times as many pounds of peaches as grapes. If a mixture that has an average (arithmetic mean) of 12 pounds per fruit, how many more pounds of apples than grapes does the mixture have?
(A) 15
(B) 12
(C) 9
(D) 6
(E) 4
Rationale: A+P+G= 12*2
A=2G
P=3G
3G+2G+G= 12*2
G= 12*2/6= 4
A= 4*2=8
Difference = 8-4=4
'E' is the answer
Answer: (E) 4
Question: 34 is related to 12 in the same way as 59 is related to
(A) 45
(B) 66
(C) 77
(D) 88
(E) 61
Rationale: Explanation:
The second number is the product of the digits of the first.
Answer: A) 45
Answer: (A) 45
Question: Evaluate 28% of 450 + 45% of 260
(A) 232
(B) 243
(C) 252
(D) 262
(E) 282
Rationale: Explanation:
= (28/100) * 450 + (45/100) * 260
= 126 + 117 = 243
Answer: Option B
Answer: (B) 243
Question: Find the principal which yields a simple interest of Rs. 20 and compound interest of Rs. 25 in two years, at the same percent rate per annum?
(A) s. 40
(B) s. 48
(C) s. 49
(D) s. 20
(E) s. 60
Rationale: Explanation:
SI in 2 years = Rs. 20, SI in 1 year = Rs. 10
CI in 2 years = Rs. 25
% rate per annum = [(CI – SI) / (SI in 1 year)] *100
= [(25 – 20) / 20] * 100
= 25 % p.a.
Let the principal be Rs. X
Time = T = 2 years
% rate = 25% p.a.
SI = (PRT/100)
20 = (X*25*2) / 100
X = Rs. 40
ANSWER: A
Answer: (A) s. 40
Question: What is the largest 4 digit number exactly divisible by 88?
(A) 9999
(B) 9944
(C) 9988
(D) 9900
(E) 9991
Rationale: Largest 4 digit number = 9999
9999 ÷ 88 = 113, remainder = 55
Hence largest 4 digit number exactly divisible by 88 = 9999 - 55 = 9944
Answer is B
Answer: (B) 9944
Question: Two cyclists are running on a circular track of 500m.They start from the same point A at the same time.If they meet for the first time at a point 300 m from A, which of the following could be the possible ratio of their speeds?
(A) 1:3
(B) 2:3
(C) 3:2
(D) 5:7
(E) 7:11
Rationale: well, the key aspect of this question is the distance mentioned, when they met for the first time, which is 300m away from the starting point. This distance between their first meeting can be less than 500 in only two circumstance.
1) if both are travelling in the same direction and one of them has been given a head start say by few meters.
2) or if both are travelling in the opposite direction.
now since they start their journey at the same time. hence option 1 is ruled out. hence they must be running in the opposite direction. hence answer should be 3:2
Why?? here is a solution
As here time is constant, therefore, distance traveled will be directly proportional to the the respective velocities/speed of the two runners.(d1/d2=v1/v2)
now one of them has covered 300m, therefore other must have covered 200m, therefore ratio of their speeds/velocities will be 3:2
C
Answer: (C) 3:2
Question: There are 4 more women than there are men on a local co-ed softball team. If there are a total of 18 players on the team, what is the ratio of men to women?
(A) 10/16
(B) 6/16
(C) 7/11
(D) 6/10
(E) 4/10
Rationale: w = m+4
w+m = 18
m+4+m = 18
2m = 14
m = 7
w = 11
ratio:7:11
Ans: C
Answer: (C) 7/11
Question: What value should come in place of question mark (?) in the following equations ?
64% of 1775 + 36% of 550 = ? % of 6670
(A) 20
(B) 24
(C) 30
(D) 40
(E) 45
Rationale: Explanation :
64x1775/100 + 36x550/100 = ?x6670/100
∴ ? = 1136 + 198/6670 x 100 = 20%
Answer : Option A
Answer: (A) 20
Question: Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 20 percent alcohol by volume?
(A) 200
(B) 300
(C) 400
(D) 500
(E) 600
Rationale: 20% is an equal distance between 10% and 30%.
Thus there should be equal parts of both solutions.
We should add 200 ml of solution Y.
The answer is A.
Answer: (A) 200
Question: If each term in the sum a1+a2+a3+.....+an is either 7 or 77 and the sum equals 329, which of the following could be equal to n?
(A) 37
(B) 38
(C) 39
(D) 41
(E) 42
Rationale: Since, there is no 47 in the answer choices (329/7 = 47), we know there is at least one 77.
329 - 77 = 252
252/7 = 36
36+1 = 37.
If 37 wasn't there, I would have subtracted 77 from 252 and continued in a similar way.
Ans. A
Answer: (A) 37
Question: If N is the product of all positive integers less than 31, than what is the greatest integer k for which N/18^k is an integer?
(A) 3
(B) 6
(C) 7
(D) 14
(E) 26
Rationale: Basically the question is asking us what is the highest power of 18 that can give us a number that is a factor of 31!
So remember 18 after prime factorization is (3^2)(2). Now there are going to be less factors of 3 in 31!, than factors of 2.
Therefore, let's find how many factors of 3 in 31! We can use this quick method
31/3^1 = 10
31/3^2= 3
31/3^3=1
Sum = 14
Just ignore the remainders.
So we have that 3^14 must be the least. Now don't forget that 18 is 3^2k so k must be ONLY 7, because 2k will give us the 14.
Hence answer is (C)
Answer: (C) 7
Question: The average weight of 16 students in a class is 50.25 kg and that of the remaining 8 students is 45.15 kg. Find the average weights of all the students in the class.
(A) A)48.55
(B) B)49
(C) C)51
(D) D)61
(E) E)62
Rationale: Required average
= (50.25 x 16 + 45.15 x 8)/(16 + 8)
= (804 + 361.20)/24
= 1165.20/24
= 48.55kg
Answer is A
Answer: (A) A)48.55
Question: A cylinder of radius R and height H is reshaped. Which of the following changes results in the cylinder of greatest volume?
(A) a 20% decrease in H and a 50% increase in R.
(B) a 500% increase in H and a 50% decrease in R.
(C) a 300% increase in H and a 30% decrease in R
(D) a 70% decrease in H and a 100% increase in R
(E) a 100% increase in H and a 10% decrease in R
Rationale: Volume of a cylinder = Pi. R^2.H
Check for options as per given Q.
A. (1.5)^2 * (0.8) = 2.25 * 0.8 = 1.8 (Since 20% decrease in H and a 50% increase in R.)
B. (0.5)^2 * (6) = 0.25 * 6 = 1.5 (Since 500% increase in H and a 50% decrease in R)
C. (0.7)^2 * (4) = 0.49 * 4 = 1.96 (Since 300% increase in H and a 30% decrease in R )
D. (2)^2 * (0.3) = 4 * 0.3 = 1.2 (Since 70% decrease in H and a 100% increase in R. )
E. (0.9)^2 * (2) = 0.81 * 2 = 1.62 (Since 100% increase in H and a 10% decrease in R. )
Maximum value is 1.96
Option C
Answer: (C) a 300% increase in H and a 30% decrease in R
Question: A bucket full of nuts was discovered by the crow living in the basement. The crow eats a sixth of the total number of nuts in 4 hours. How many hours i total will it take the crow to finish a quarter of the nuts?
(A) 6
(B) 8
(C) 10
(D) 12
(E) 14
Rationale: In one hour, the crow eats 1/24 of the nuts.
(1/4) / (1/24) = 6 hours
The answer is A.
Answer: (A) 6
Question: A computer program produces a sequence a1, a2, a3, ... such that a1=a2=1 and ak=a(k-1)*3-1 for 2 < k < n for some n. If n=9, what is a6?
(A) 35
(B) 37
(C) 39
(D) 41
(E) 43
Rationale: a1=1
a2=1
a3=1*3-1=2
a4=2*3-1=5
a5=5*3-1=14
a6=14*3-1=42-1=41
41
Answer: (D) 41
Question: Every letter in the alphabet has a number value that is equal to its place in the alphabet. Thus, the letter A has a value of 1, the letter B has a value of 2, the letter C has a value of 3, etc... The number value of a word is obtained by adding up the value of the letters in the word and then multiplying that sum by the length of the word. What is the number value of the word "DOG"?
(A) 72
(B) 75
(C) 78
(D) 81
(E) 84
Rationale: "DOG" = (4+15+7)*3=78.
The answer is C.
Answer: (C) 78
Question: All of the students of Music High School are in the band, the orchestra, or both. 60 percent of the students are in only one group. There are 106 students in the band. If 10 percent of the students are in the band only, how many students are in the orchestra only?
(A) 120
(B) 110
(C) 116
(D) 106
(E) 112
Rationale: % of students in one group only = 60%
% of students in both groups = 100 - 60 = 40%
% of students in the band only = 10%
Number of students who are in band = 106
40% + 10% = 50% = 106 Students
Finding total students:
x = (106 x 100)/50
x = 212
Students in orchestra only = 212 - 106 = 106
Answer:D
Answer: (D) 106
Question: There are 500 employees in a room. 99% are managers. How many managers must leave the room to bring down the percentage of managers to 98%?
(A) 150
(B) 200
(C) 250
(D) 350
(E) 400
Rationale: There are 495 managers and 5 others. The 5 others would compose 2% of the total number of people if there were 250 people in the room. Thus 250 managers must leave.
The answer is C.
Answer: (C) 250
Question: A shirt goes on sale for 60% of its original price. One week later, the sale price is marked down 10%. The final price is what percent of the original price?
(A) 72%
(B) 70%
(C) 52%
(D) 50%
(E) 28%
Rationale: Just assume original price is 100.
Sale price = 60
Then it is marked down by 10% = 60-6=52.
Hence it is 52% od the original price. Hence answer is C.
Answer: (C) 52%
Question: The third proportional to 1 and 5 is?
(A) 8
(B) 27
(C) 24
(D) 25
(E) 3
Rationale: (5*5)/1 = 25
Answer:D
Answer: (D) 25
Question: A man covers a certain distance Q in a train. If the train moved 4km/hr faster, it would take 30 min less. If it moved 2km/hr slower, it would take 20 mins more. Find the distance?
(A) 200 km
(B) 50 km
(C) 20 km
(D) 60 km
(E) 80 km
Rationale: Not really. When you solve the 2 equation above, you get,
6T-4/3 = 5R/6 from simplifying equation 1
4T-2=R/2 from simplifying equation 2
You can now multiply equation 2 by 5 to get
5(4T-2=R/2 ) = 20T-10=5R/2 and then subtract this new equation from equation 1 to get T=3, followed by R=20 to give you distance Q = R*T=20*3=60 km.D
Answer: (D) 60 km
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 40 ps per meter is?
(A) 287
(B) 369
(C) 100
(D) 279
(E) 361
Rationale: 3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 0.40
= Rs.100
Answer:C
Answer: (C) 100
Question: Dana borrows 5000 pounds annually for her college education. If Dana gives her parents 4% of that amount back each month, how much will she still owe her parents after four years of college?
(A) 9800
(B) 10000
(C) 10200
(D) 10400
(E) 10600
Rationale: dana borrows 5000 and returns 4% per month.
so returns 200 per month. and 2400 per year.
so dana owes 5000-2400=2600 per year.
after 4 years she will owe 10400.
Ans (C)
Answer: (C) 10200
Question: Running at the same constant rate,6 identical machines can produce a total of 270 bottles per minute.At this rate,how many bottles could 12 such machines produce in 4 minutes ?
(A) 648
(B) 1800
(C) 2700
(D) 2160
(E) None of these
Rationale: Solution
Let the required number of bottles be x.
More machines,More bottles (Direct Proportion)
More minutes,More bottles (Direct Proportion)
âˆ´ 6 Ã— 1 Ã— x = 12 Ã— 4 Ã— 270 â‡” x = 12x4x270/6= 2160 . Answer D
Answer: (D) 2160
Question: If 7125¸1.25= 5700< the value of 712.5÷12.5 is:
(A) 5.7
(B) 57
(C) 570
(D) 0.57
(E) 0.057
Rationale: Given 7125/1.25 = 5700
712.5/12.5 =71.25/1.25 = 7125*1/1.25*100 = 5700/100 = 57
ANSWER:B
Answer: (B) 57
Question: Find the percentage gain if a shop owner sells 10 mtr of fabric and gains Cost Price of 2 meters?
(A) 10%
(B) 12%
(C) 19%
(D) 25%
(E) 20%
Rationale: Let cost of each metre be Rs. 100.
Therefore, cost price of 2m cloth = 2*100 = 200
cost price of 10m cloth = 10*100 = 1000
Since the trader made the CP of 2m from the sale of 10m therefore
Profit on sale of 10m = cost price of 2 m cloth = 200
Selling price of 10m = 1000+200 = 1200
Profit % = 20%
E
Answer: (E) 20%
Question: A sum is invested at compounded interest payable annually. The interest in the first two successive years was Rs. 400 and Rs. 420. The sum is
(A) Rs. 8000
(B) Rs. 8200
(C) Rs.7500
(D) Rs. 8500
(E) Rs. 9000
Rationale: Explanation:
his means that, simple Interest on Rs.400 for 1 year = 420 - 400 = 20
Rate = (100 Ã—SI)/PT = (100 Ã— 20)/(400Ã—1) = 5%
Rs.400 is the interest on the sum for 1st year
Hence, sum = (100 Ã— SI)/RT = (100 Ã— 400)/(5 Ã— 1) = Rs. 8000
ANSWER IS A
Answer: (A) Rs. 8000
Question: A chocolate has 12 equal piece. Monju gave 1/4th of it to Anju, 1/3rd of it to Sujata and 1/6th of it to Fiza. The number of piece of chocolate left with Manju is?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: Answer
The number of pieces of chocolate left with Manju
= 1- [(1/4) + (1/3) + (1/6)
= 1 - (3 + 4 + 2)/12
= 1 - 9/12 = (12 - 9) / 12
= 3/12
Option: C
Answer: (C) 3
Question: A certain manufacturer sells its products	to stores in 110 different	regions worldwide, with an average (arithmetic mean) of 181 stores per region. If last year these stores sold an	average of 51,752 units of the manufacturer’s product per store, which of the following is closest to the total number of units of manufacturer’s product	sold	worldwide last	year?
(A) 10^5
(B) 10^6
(C) 10^7
(D) 10^8
(E) 10^9
Rationale: 51752*181*110 or
51000*180*110 or
50000*200*100
=10^9
E
Answer: (E) 10^9
Question: If 4x + 3y = 8 and y-3x = 8, then what is the value of x + 4y?
(A) 1/7
(B) 16
(C) 15
(D) 52/7
(E) 60/7
Rationale: 4x+3y=8 ...equation 1
-3x+y=8 ...equation 2
adding both the equations
x+4y=16
correct answer option B
Answer: (B) 16
Question: The total of company C's assets in 1994 was 100% greater than the total in 1993, which in turn was 400% greater than the total in 1992. If the total of company C's assets in in 1992 was N dollars, which one of the following represents company C's assets in 1994:
(A) 7N
(B) 8N
(C) 9N
(D) 10
(E) 20
Rationale: Let's use actual numbers. Starting in 1992, let's say company C had $100 in assets.
In 1993, the total assets were 400% GREATER, which means 1992 PLUS 400% of 1992:
$100 + 4x$100 = $100 + $400 =$500
In 1994, the total assets were 100% GREATER than they were in 1993, which means 1993 PLUS 100% of 1993:
$500 + 1x$500 = $500 + $500 =$1000
This is 10 times the 1992 number, so the correct answer is 10N.
D
Answer: (D) 10
Question: z is a positive integer and multiple of 2; p = 4^z, what is the remainder when p is divided by 10?
(A) 10
(B) 6
(C) 4
(D) 0
(E) It Cannot Be Determined
Rationale: Given: z is an even Integer
The cyclicity of Unit Digit of 4 is 2 i.e. Unit digit of powers of 4 repeat after every two powers in the pattern {4, 6, 4, 6, 4, ....}
4^1=4
4^2=16
4^3=64
4^4=256
i.e. Every Even Power of 4 gives the Unit digit = 6 = Remainder
Answer: Option B
Answer: (B) 6
Question: How many positive integers, from 2 to 100, inclusive, are not divisible by odd integers greater than 1?
(A) 5
(B) 6
(C) 8
(D) 10
(E) 50
Rationale: The no will be of the form 2^n to achieve this. Since any other form will have odd no in the prime factorization.
Hence we need to find solution of n for equation - 1< 2^n < 101.
2^6 = 64, 2^7 - 128
Hence n can take values from 1 to 6.
Hence Answer : B
Answer: (B) 6