mathewhe/aqua_rat huggingface dataset:
Question: Kamal started a business investing Rs. 9000. After five months, Sameer joined with a capital of Rs. 8000. If at the end of the year, they earn a profit of Rs. 6970, then what will be the share of Sameer in the profit ?
(A) Rs. 1883.78
(B) Rs. 2380
(C) Rs. 3690
(D) Rs. 3864
(E) None of these
Rationale: Explanation:
Kamal : Sameer = (9000 * 12) : (8000 * 7) = 108 : 56 = 27 : 14.
âˆ´
Sameer's share = Rs.
(6970âˆ—14/41)
= Rs. 2380
ANSWER IS B
Answer: (B) Rs. 2380
Question: If |7x+2| = 16, then find the product of the values of x?
(A) -5.14
(B) 6.19
(C) -7.18
(D) -8.62
(E) 5.69
Rationale: |7x+2| = 16
7x+2 = 16 or 7x+2 = -16
7x = 14 or 7x = -18
x = 2 or x = -2.57
product = -2.57*2 = -5.14
Answer is A
Answer: (A) -5.14
Question: There are 16 teams in a soccer league, and each team plays each of the others once. Given that each game is played by two teams, how many total games will be played?
.
(A) 256
(B) 230
(C) 196
(D) 169
(E) 120
Rationale: Let's call the teams...ABCDE FGHIJ KLMNO P
Team A plays each of the other 15 teams, so that's 15 games.
Team B already played Team A, so it plays 14 OTHER games.
Team C already played Teams A and B, so it plays 13 OTHER games.
Team D already played Teams A, B and C, so it plays 12 OTHER games.
Etc.
The sum of all of these games is...
15+14+13.....+3+2+1 = 120
Final Answer:E
Answer: (E) 120
Question: For 600 km journey it will take 8hrs, if 120 km is done by bus and the rest by car. It takes 20 minutes more, if 200 km is done by busand the rest by car. The ratio of the speed of the train to that of the cars is?
(A) 1 : 3
(B) 3 : 4
(C) 3 : 5
(D) 3 : 7
(E) 4 : 5
Rationale: Let the speed of the train be x km/hr and that of the car be y km/hr.
Then, 120 + 480 = 8 1 + 4 = 1 ....(i)
x y x y 15
And, 200 + 400 = 25 1 + 2 = 1 ....(ii)
x y 3 x y 24
Solving (i) and (ii), we get: x = 60 and y = 80.
Ratio of speeds = 60 : 80 = 3 : 4
B
Answer: (B) 3 : 4
Question: x and y are positive integers. When x is divided by 15, the remainder is 2, and when x is divided by 10, the remainder is 7. When y is divided by 9, the remainder is 5, and when y is divided by 7, the remainder is 2. What is the least possible value of x * y?
(A) 389
(B) 390
(C) 388
(D) 391
(E) 392
Rationale: When x is divided by 15, the remainder is 2: So, the possible values of x are: 2, 17, 32, 47, etc.
When x is divided by 10, the remainder is 7: So, the possible values of x are: 7,17... STOP. Since both lists include 17, the smallest possible value of x is 17.
When y is divided by 9, the remainder is 5: So, the possible values of y are: 5, 14, 23,32 etc.
When y is divided by 7, the remainder is 2: So, the possible values of y are: 2, 9, 16, 23 ...STOP. Since both lists include 23, the smallest possible value of y is 23
Since the smallest possible values of x and y are 17 and 23 respectively, the smallest possible value of x * y is 391. So,D is the correct answer to the original question.
Answer: (D) 391
Question: The divisor is 21, the quotient is 14 and the remainder is 7.
What is the dividend?
(A) 201
(B) 394
(C) 302
(D) 301
(E) 294
Rationale: D = d * Q + R
D = 21 * 14 + 7
D = 294 + 7
D = 301
Answer: (D) 301
Question: Anne and Beth will participate in a sack race (In a sack race, people hop to reach the finish line). In the time that Anne takes 3 hops, Beth takes 4 hops but the distance covered by Anne in 4 hops is equal to distance covered by Beth in 5 hops. What is the ratio of Anne’s speed: Beth’s speed?
(A) 3 : 5
(B) 12 : 20
(C) 15 : 16
(D) 1 : 1
(E) 5 : 3
Rationale: The distance covered by Anne in 4 hops is equal to distance covered by Beth in 5 hops --> 4*(distance of Ann's 1 hop) = 5*(distance of Beth's 1 hop).
The time that Anne takes 3 hops, Beth takes 4 hops --> time for Ann to take 12 hops --> 3*(time for Ann's 1 hop) = 4*(time for Beth's 1 hop).
Divide one by another:
4/3*(distance of Ann's 1 hop)/(time for Ann's 1 hop) = 5/4*(distance of Beth's 1 hop)/(time for Beth's 1 hop);
4/3*(Anne's speed) = 5/4*(Beth's speed);
4/3*(Anne's speed)/(Beth's speed) = 15/16.
Answer: C.
Answer: (C) 15 : 16
Question: In a partnership between A, B and C. A's capital is Rs.8000. If his share of a profit of Rs.800 is Rs.300 and C's share is Rs.230, what is B's capital?
(A) Rs.7600
(B) Rs.7800
(C) Rs.7200
(D) Rs.7400
(E) Rs.8400
Rationale: 300 + 230 = 530
800 - 530 = 270
300 ---- 8000
270 ---- ? => Rs.7200
ANSWER:C
Answer: (C) Rs.7200
Question: Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest?
(A) 80% p.a
(B) 50% p.a
(C) 20% p.a
(D) 27% p.a
(E) 23% p.a
Rationale: Rs.1440 - 1200
= Rs.240 is the interest on Rs.1200 for one year.
Rate of interest
= (100 * 240) / (100 * 1)
= 20% p.a
Answer:C
Answer: (C) 20% p.a
Question: 70% of a number is added to 120, the result is the same number. Find the number?
(A) 300
(B) 400
(C) 1687
(D) 997
(E) 121
Rationale: (70/100) * X + 120 = X
2X = 800
X = 400
Answer:B
Answer: (B) 400
Question: The population of a town is 20000. It decreases annually at the rate of 20% p.a. What will be its population after 2 years?
(A) 4300
(B) 4500
(C) 5120
(D) 5230
(E) 12800
Rationale: 20000 × 80/100 × 80/100 = 12800
Answer : E
Answer: (E) 12800
Question: What will be the day of the week 15th August, 2010?
(A) Sunday
(B) Wednesday
(C) Saturday
(D) Monday
(E) THUSAW
Rationale: Explanation:
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 = 4 odd days.
Jan. Feb. Mar. Apr. May. Jun. Jul. Aug.
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 = 0 odd days.
Given day is Sunday
Answer: A) Sunday
Answer: (A) Sunday
Question: Sony and Johnny caught 50 fishes. Sony caught four times as many as Johnny. How many fishes did Johnny catch?
(A) 12
(B) 16
(C) 10
(D) 38
(E) 42
Rationale: s+j=50
s=4*j
j=10
ANSWER:C
Answer: (C) 10
Question: Employees at a company will vote for an executive team of five people from eight qualified candidates. The executive team consists of a president, a treasurer, and three warrant officers. If an executive team is considered different if any of the same people hold different offices, then how many possible executive teams F could be selected from the eight candidates?
(A) 56
(B) 120
(C) 210
(D) 1120
(E) 6720
Rationale: If an executive team is considered different if any of the same people hold different offices,....
so you will not have answer as 6720..
president could be by any of 8 person..
treasurer could be any out of remaining 7 person..
remaining three order does not matter, so we have to choose 3 out of 6=6c3=20..
total ways F= 8*7*20=1120..
ans D...
Answer: (D) 1120
Question: What is the unit digit in 7^105?
(A) 1
(B) 5
(C) 7
(D) 9
(E) None of them
Rationale: Unit digit in 7^105= Unit digit in [(7^4)^26 x 7]
But, unit digit in (7^4)^26=1
Therefore, Unit digit in 7^105=(1x7)=7
Answer is C
Answer: (C) 7
Question: If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $83. If $2,000 is the total amount invested, how much is invested at 8 percent?
(A) $550
(B) $650
(C) $750
(D) $850
(E) $950
Rationale: 0.1x = 0.08(2000-x)+83
0.18x = 243
x = 1350
Then the amount invested at 8% is $2000 - $1350 = $650
The answer is B.
Answer: (B) $650
Question: An equilateral triangle is inscribed in a circle, as shown above. What is the area of the shaded region, if the area of the circle is 2?
(A) 2 - 3√3
(B) 2 - 3√3/∏
(C) 2 - 3√3/4
(D) 2 - 3√3/(2∏)
(E) 2∏ - 3√3/(2∏)
Rationale: 1) since we are subtracting from overall so first term should be 2... E out
2) the area of triangle that is to be subtracted should be in terms of π...A and C are out.. also A gives you answer in negative
3) in B, ans would be around 0.3 and in D, ans will be around 1.2...
Clearly the shaded and unshaded are close to 1/2 each..
D is the answer
Answer: (D) 2 - 3√3/(2∏)
Question: Let X be the smallest positive integer such that 10 and 14 are factors of 250 + X, so the value of X is:
(A) 0
(B) 10
(C) 20
(D) 30
(E) 40
Rationale: You can calculate the LCM (10,14) = 70.
After that you should check which of the possible X values will result in a number divisible by 70.
The only possibility for this is 30 ( because 250 + 30 = 280 = 70*4)
Answer D
Answer: (D) 30
Question: Two friends P & Q started a business investing amounts in the ratio of 5 : 6. R joined them after six months investing an amount equal to that of Q’s amount. At the end of the year 20% profit was earned which was equal to 98,000. What was the amount invested by R?
(A) 2,10,000
(B) 1,05,000
(C) 1,75,000
(D) Data inadequate
(E) None of these
Rationale: Ratio for amount invested by P, Q & R
= 5x × 12 : 6x × 12 : 6x × 6
= 60x : 72x : 36x
= 5x : 6x : 3x
Profit = 98000 = 20% of T
where, T = Total amount
T = 490000
Amount received by
R = 3x /3x+6x+5x(490000)
= 105000
Answer B
Answer: (B) 1,05,000
Question: In how many H ways can a four-letter password be chosen, using the letters A, B, C, D, E, and/or F, such that at least one letter is repeated within the password?
(A) 720
(B) 864
(C) 900
(D) 936
(E) 1,296
Rationale: Total number of four letter passwords = 6*6*6*6= 1296 ------(1)
Total number of passwords in which no letter repeats = 6C4*4!= 15*24=360------(2)
therefore required value H= (1)-(2)= 1296-360=936.D
Answer: (D) 936
Question: How many of the positive factors of 16 are not factors of 20
(A) 2
(B) 3
(C) 4
(D) 1
(E) 5
Rationale: factors of 16 - 1, 2, 4, 8, 16
factors of 20 -1, 2, 4, 5, 10, 20.
Comparing both, we have 2 factors of 16 which are not factors of 20- 8,16
Answer: A
Answer: (A) 2
Question: Line m lies in the xy-plane. The y-intercept of line m is -2, and line m passes through the midpoint of the line segment whose endpoints are (2, 8) and (14,4). What is the slope of line m?
(A) -2
(B) -1
(C) 0
(D) 1
(E) 2
Rationale: The midpoint of (2,8) and (14,4) is (8,6).
The slope of a line through (0,-2) and (8,6) is (6-(-2))/(8-0) = 8/8 = 1
The answer is D.
Answer: (D) 1
Question: A student took five papers in an examination, where the full marks were the same for each paper. His marks in these papers were in the proportion of 6:7:8:9:10. In all papers together, the candidate obtained 60% of the total marks then, the number of papers in which he got more than 50% marks is
(A) 1
(B) 3
(C) 4
(D) 5
(E) 7
Rationale: Solution: Let the marks obtained in five subjects be 6x, 7x, 8x, 9x and 10x.
Total marks obtained= 40x
Max. Marks of the five subjects = 40x/0.6 [40x is 60% of total marks]
Max. Marks in each subject = 40x/0.6*5 = 13.33x
Hence, % of each subject = 6x*100/13.33 = 45.01%
Or, 7x*100/13.33 = 52.51
In same way other percentage are 60.01%, 67.52%, 75.01%.
Hence, number of subjects in which he gets more than 50% marks = 4.
Answer: Option C
Answer: (C) 4
Question: How many integers are between 4 and 87/8, inclusive?
(A) 4
(B) 5
(C) 7
(D) 9
(E) 10
Rationale: 87/8 = 10.xx
We are not concerned about the exact value of 87/8 as we just need the integers.
Since the values are small, we can write down the integers.
The different integers between 4 and 87/8 would be 4, 5, 6, 7, 8, 9, 10
Total number of integers = 7
Option C
Answer: (C) 7
Question: The average age of a group of 5 members is 20 years. Two years later, a new member joins the group. The average age of the group becomes 21 years. What is the age of the new member ?
(A) 20 years
(B) 21 years
(C) 16 years
(D) 23 years
(E) 24 years
Rationale: The average age of a group of 5 members is 20 years --> the sum of the ages is 5*20=100;
Two years later the sum of the ages of these 5 members would be 100+5*2=110;
Now, say the age of the new member is x years, so the sum of the ages of a new 6 member group is 110+x. Since given that the average age of this group of 6 members is 21 years then: 21*6=110+x --> x=16.
Answer: C.
Answer: (C) 16 years
Question: A certain family has 3 sons: Richard is 6 years older than David, and David is 8 years older than Scott. If in 8 years, Richard will be twice as old as Scott, then how old was David 3 years ago?
(A)  8
(B)  11
(C)  12
(D)  14
(E)  16
Rationale: Let's say
Age of Richard isR
Age of David isD
Age of Scott isS
Now
Richard is 6 years older than David,
i.e. R = D +6
David is 8 years older than Scott
i.e. D = S +8
If in 8 years, Richard will be twice as old as Scott
i.e. R+8 = 2x(S+8)
i.e. R+8 = 2S + 16
i.e. R = 2S+8
But R = D+6 = (S+8)+6 = S+14
therefore, 2S + 8 = S +14
i.e. S = 6
i.e. R = 20
i.e. D = 14
Now,
how old was David 3 years ago?
i.e. D-3 = 14-3 = 11 years
Answer: Option
B
Answer: (B)  11
Question: Margaret is 7 years more than twice the age of his son. The age of son is 12. Find the age of mother and find the difference between their ages
(A) 19yrs
(B) 20yrs
(C) 30yrs
(D) 40yrs
(E) 50yrs
Rationale: Let, age of son x=12
Margaret is 7 years more than twice the age of his son, y = 7+2(x)
=7+2(12)
=7+24
=31yrs
Difference = 31 - 12
=19yrs
ANSWER:A
Answer: (A) 19yrs
Question: Barbata invests $2800 in the National Bank at 5%. How much additional money must she invest at 8% so that the total annual income will be equal to 6% of her entire investment?
(A) 1200
(B) 3000
(C) 1000
(D) 1400
(E) 2400
Rationale: Let the additional invested amount for 8% interest be x;
Equation will be;
2800+0.05*2800+x+0.08x = 2800+x+0.06(2800+x)
0.05*2800+0.08x = 0.06x+0.06*2800
0.02x = 2800(0.06-0.05)
x = 2800*0.01/0.02 = 1400
Ans: "D"
Answer: (D) 1400
Question: If December 3rd, 1999 is a Friday, what day is January 5th, 2000?
(A) Wednesday
(B) Thursday
(C) Friday
(D) Saturday
(E) Sunday
Rationale: There is difference of 33 days from Dec. 3rd 1999 to Jan. 5th 2000.
33/7 has a remainder of 5.
Jan. 5th is: Friday + 5 days = Wednesday
The answer is A.
Answer: (A) Wednesday
Question: In a class of 40 students, 2 students did not borrow any books from the library, 12 students each borrowed 1 book, 11 students each borrowed 2 books, and the rest borrowed at least 3 books. If the average number of books per student was 2, what is the maximum number of books any single student could have borrowed?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Rationale: The class borrowed a total of 40*2 = 80 books.
The 25 students who borrowed 0, 1, or 2 books borrowed a total of 12 + 11*2 = 34.
To maximize the number of books borrowed by 1 student, let's assume that 14 students borrowed 3 books and 1 student borrowed the rest.
80 - 34 - 3*14 = 4
The maximum number of books borrowed by any student is 4.
The answer is B.
Answer: (B) 4
Question: If the price of petrol increases by 25% and Benson intends to spend only an additional 15% on petrol, by how much % will he reduce the quantity of petrol purchased?
(A) A)8%
(B) B)7%
(C) C)10%
(D) D)6%
(E) E)9%
Rationale: Explanation:
Assume that the initia price of 1 Litre petrol = Rs.100 ,Benson spends Rs.100 for petrol,
such that Benson buys 1 litre of petrol
After the increase by 25%, price of 1 Litre petrol = 100 × (100+25)/100 = Rs.125
Since Benson spends additional 15% on petrol,
amount spent by Benson = 100× (100+15)/100 = Rs.115
Hence Quantity of petrol that he can purchase = 115/125 Litre
Quantity of petrol reduced = (1−115/125) Litre
Percentage Quantity of reduction = (1−115125)/1 × 100 = 10/125 × 100 = 105 × 4 = 2 × 4 = 8%
Answer: Option A
Answer: (A) A)8%
Question: If 50 apprentices can finish a job in 4 hours, and 30 journeymen can finish the same job in 6 hours, how much of the job should be completed by 10 apprentices and 15 journeymen in one hour?
(A) 1/9
(B) 29/180
(C) 26/143
(D) 2/15
(E) 39/121
Rationale: 50 apprentices can finish the job in 4 hours,thus:
10 apprentices can finish the job in 4*5 = 20 hours;
In 1 hour 10 apprentices can finish 1/20 of the job.
30 journeymen can finish the same job in 4,5 hours,thus:
15 journeymen can finish the job in 6*2 = 12 hours;
In 1 hour 15 journeymen can finish 1/12 of the job.
Therefore, in 1 hour 10 apprentices and 15 journeymen can finish 1/20+1/12=2/15 of the job.
Answer: D.
Answer: (D) 2/15
Question: A taxi leaves Point A 3 hours after a bus left the same spot. The bus is traveling 30 mph slower than the taxi. Find the speed of the taxi, if it overtakes the bus in three hours.
(A) 60
(B) 72
(C) 48
(D) 36
(E) 64
Rationale: Let the speed of bus be v - 30, speed of taxi be v
The bus travelled a total of 6 hrs and taxi a total of 3 hrs.
Hence 6 * (v-30) = 3v
6v - 180 = 3v
3v = 180
v = 60 mph
A
Answer: (A) 60
Question: What is the 8th digit to the right of the decimal point in the decimal equivalent of 73/11?
(A) 1
(B) 3
(C) 4
(D) 5
(E) 2
Rationale: 73/11 = 6.6363....
63 is non-terminating repeating decimal.
The 8th digit to the right of decimal point will be 3.
Answer B
Answer: (B) 3
Question: In a certain deck of cards, each card has a positive integer written on it. In a multiplication game, a child draws a card and multiples the integer on the card by the next larger integer. If each possible product is between 28 and 200, then the least and greatest integers on the card could be
(A) 3 and 15
(B) 3 and 20
(C) 5 and 13
(D) 4 and 14
(E) 5 and 14
Rationale: There child draws one number then multiplies that number by the number above it. The number must be more than 28 and less than 200.
x * (x+1)
Answer gives us choices of 3,4 and 5 (JUST ABOVE 28)
3*(3+1) =12 <- WRONG
4*(4+1) =20 <- WRONG
5*(5+1) =30 <- CORRECT AS IT IS ABOVE 28
Answer gives us choices 13,14,15 and 20 (BELOW 200)
Immediately by knowing squares you should be able to rule out 15 (225) and 20 (400). And common sense dictates that as 14^2 is 196 that 14*(14+1) is above 200.
13*(13+1)=182 <- CORRECT
Answer is C) 5 and 13
Answer: (C) 5 and 13
Question: Marcus deposited $8,000 to open a new savings account that earned five percent annual interest, compounded semi-annually. If there were no other transactions in the account, what the amount of money in Marcuss account one year after the account was opened?
(A) $8,200
(B) $8,205
(C) $8,400
(D) $8,405
(E) $8,500
Rationale: Approach #1:
5 percent annual interest compounded semi-annually --> 2.5% in 6 moths.
For the first 6 moths interest was 2.5% of $8,000, so $200;
For the next 6 moths interest was 2.5% of $8,000, plus 2.5% earned on previous interest of $200, so $200+$5=$205;
Total interest for one year was $200+$205=$405, hence balance after one year was $8,000+ $405=$8,405.
Answer: D.
Answer: (D) $8,405
Question: If a is the interest on y and y is the interest on z, the rate and time is the same on both the cases. What is the relation between a, y and z?
(A) Y^2 = aZ
(B) Y^3 = aZ
(C) Y^3 = aY
(D) Y^1 = aZ
(E) Z^3 = aZ
Rationale: a = (Y*NR)/100 Y = (Z*NR)/100
a/Y = NR/100 Y/Z = NR/100
a/Y = Y/Z
Y^2 = aZ
ANSWER:B
Answer: (B) Y^3 = aZ
Question: The table shows the number of calls received by each of five operators during each of 4 one-hour periods. For which operator was the standard deviation of the numbers of calls received during these 4 periods the least
(A) Operator A: 3, 7, 7, 3
(B) Operator B: 4, 5, 5, 6
(C) Operator C: 8, 2, 5, 5
(D) Operator D: 6, 4, 4, 6
(E) Operator E: 3, 4, 5, 8
Rationale: E
it has 2 numbers right at the average, E has none.
Answer: (E) Operator E: 3, 4, 5, 8
Question: On Sunday, Bill ran 4 more miles than he ran on Saturday. Julia did not run on Saturday, but she ran twice the number of miles on Sunday that Bill ran on Sunday. If Bill and Julia ran a total of 32 miles on Saturday and Sunday, how many miles did Bill run on Sunday?
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
Rationale: Let Bill run x on saturday, so he will run x+4 on sunday..
Julia will run 2*(x+4) on sunday..
totai= x+x+4+2x+8=32..
4x+12=32..
x=5..
ans =x+4=5+4=9
Answer E
Answer: (E) 9
Question: If a > 1 and b = 2^(a −1), then 4^a =
(A) 16b^2
(B) 4b^2
(C) b^2
(D) b^2/4
(E) b^2/16
Rationale: If a > 1 and b = 2^(a −1), then 4^a
Given a>1, so let's assume a=2
b=2^(a-1) = 2^(2-1) = 2, so b=2
hence, 4^a = 4^2 = 16
only 1 ans. choice can satisfy this:
A) 16b^2 --> clearly > 16
B) 4b^2 --> 4*2^2 = 16(we can stop after this as there can be only 1 right answer)
C) b^2 --> clearly < 16
D) b^2/4 --> clearly < 16
E) b^2/16 --> clearly < 16
Ans. B) 4b^2
Answer: (B) 4b^2
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 8 kmph, what is the time taken to row a distance of 60 km downstream?
(A) 30/18
(B) 30/29
(C) 30/14
(D) 30/13
(E) 30/82
Rationale: Speed downstream = 20 + 8 = 28 kmph.
Time required to cover 60 km downstream = d/s = 60/28
= 30/14 hours.
Answer:C
Answer: (C) 30/14
Question: A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 500. How much did he have with him in the beginning?
(A) s 200
(B) s 1250
(C) s 300
(D) s 450
(E) s 550
Rationale: Suppose the amount in the beginning was Rs ’x’
Money spent on clothes = Rs 1x/3 Balance = Rs 2x/3
Money spent on food = 1/5 of 2x/3 = Rs 2x/15
Balance = 2x/3 - 2x/15 = Rs 8x/15
Money spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5
Therefore 2x/5 = 500 = 1250
ANSWER:B
Answer: (B) s 1250
Question: If a store owner increases a product’s price by 20 percent and then increases this price by another 15 percent, what percent of the original price is the total price increase?
(A) 20%
(B) 35%
(C) 38%
(D) 65%
(E) 135%
Rationale: let the initial price be 100
1st increase =20 % the price now is 120
2nd increase of 15% on 120 =18
final price =138, total increase =38%
ANSWER:C
Answer: (C) 38%
Question: Today is Peter's birthday. One year, from today he will be twice as old as he was 9 years ago. How old is Peter today ?
(A) 25 years
(B) 19 years
(C) 17 years
(D) 23 years
(E) 21 years
Rationale: let Peter's age=xx+1=2(x-9)x=19ANSWER:B
Answer: (B) 19 years
Question: In a certain game, you perform three tasks. You flip a coin, and success would be tail. You roll a single die, and success would be a six. You pick a card from a full playing-card deck, and success would be picking a spades card. If exactly one of these three tasks is successful, then you win the game. What is the probability of winning?
(A) 11/16
(B) 23/48
(C) 15/32
(D) 14/36
(E) 17/56
Rationale: The answer is B
Probability of just one enent will be happining
So, Probability heads=1/2
Probability number 6 =1/6
Probability picking a spades card =1/4
so, Probability win by getting tails= 1/2*5/6*3/4 = 15/48
Probability win by getting number 6 = 1/2*1/6*3/4 = 3/48
Probability win by picking a spades card =1/2*5/6*1/4=5/48
Probability wining= 15/48+3/48+5/48 =23/48
Answer: (B) 23/48
Question: Kathleen can paint a room in 3 hours, and Anthony can paint an identical room in 4 hours. How many hours would it take Kathleen and Anthony to paint both rooms if they work together at their respective rates?
(A) 8/15
(B) 4/3
(C) 15/8
(D) 24/7
(E) 15/4
Rationale: (1/3 + 1/4)t=2
t=24/7
Answer: D
Answer: (D) 24/7
Question: The marks obtained by Vijay and Amith are in the ratio 4:4 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of?
(A) 3:2
(B) 6:1
(C) 6:5
(D) 6:2
(E) 6:3
Rationale: 4:4
3:2
-------
12:12:8
12:8
3:2
Answer: A
Answer: (A) 3:2
Question: A work as fast as B. If B can complete a work in 24days independently,the number of days in which A and B can together finish the work in?
(A) 2days
(B) 3days
(C) 8days
(D) 5days
(E) 6days
Rationale: Ratio of rates of working of A and B = 2:1
ratio of times taken = 1:2
A's 1day work = 1/12
B's 1day work = 1/24
A+B 1day work = 1/12 + 1/24 = 3/24 = 1/8
A and B can finish the work in 8days
Answer is C
Answer: (C) 8days
Question: one person Tharak speed with the current is 15 km/hr and the speed of the current is 6 km/hr. Tharak's speed against the current is:
(A) 0 km/hr
(B) 1 km/hr
(C) 2 km/hr
(D) 3 km/hr
(E) 4 km/hr
Rationale: Man's speed with the current = 15 km/hr
=> speed of the man + speed of the current = 15 km/hr
speed of the current is 6 km/hr
Hence, speed of the man = 15-6 = 9 km/hr
man's speed against the current = speed of the man - speed of the current
= 9-6 = 3 km/hr
ANSWER:D
Answer: (D) 3 km/hr