mathewhe/aqua_rat huggingface dataset:
Question: Machine A can do a certain job in 8 hours. Machine B can do the same job in 10 hours. Machine C can do the same job in 12 hours. All three machines start the job at 9:00 a.m. Machine A breaks down at 11:00 a.m., and the other two machines finish the job. Approximately what time Q will the job be finished?
(A) Noon
(B) 12:30 p.m.
(C) 1:00 p.m.
(D) 1:30 p.m.
(E) 2:00 p.m.
Rationale: Ans: C (1:00pm)
From 9:00-11:00c(2 hrs)
A can do 1/8 Job/hr. so in 2 hours he can do 1/4 job.
B can do 1/10 job/hr so in 2 hrs. he can do 1/5 Job.
C can do 1/12 job/hr so in 2 hours he can do 1/6 job.
Total = 1/4+1/5+1/6 = 37/60 Job
Now balance work needs to be done by B and C.
Balance Work= 23/60 Job
Combined rate of B and C = 1/10+1/12 = 11/60 job/hr.
So they will do 22/60 work in 2 hrs (approx. to the balance work of 23/60)
Hence the Job will be completed 2hrs. after 11:00 i.e. @ 1:00pm=Q
Ans: C (1:00pm)
Answer: (C) 1:00 p.m.
Question: Three friends-whose walking rates are 1 ft./sec., 3ft./sec.,and 6ft./sec. start together walking in the same direction around a circular track that is 120 feet in circumference.After how many minutes are the three of them together again?
(A) 2 mins
(B) 10 mins
(C) 15 mins
(D) 3 mins
(E) 7 mins
Rationale: Answer will be A.
The time they take will be what the 1st friend takes to complete one circumference as he is the slowest and that is the point all 3 of them will be together at the end of 2 mins.
Answer: (A) 2 mins
Question: Stacy and Heather are 30 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour fast than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?.
(A) 15 mile
(B) 14 mile
(C) 11 mile
(D) 10 mile
(E) 12.5 mile
Rationale: Ss - Stacy's speed = 6m/hr
Sh - Heather's speed = 5m/hr
In 24 minutes Stacy will cover = (24/60)*6 = 2.4miles
Now since both are walking in opposite directions, add their speeds - 6+5 =11m/hr and distance to cover is 30 -2.4 = 17.6
Time taken = Distance/ Speed = 27.6/11 = 2.5 hrs
Heather will cover = 5*2.5 = 12.5miles.
Answer E
Answer: (E) 12.5 mile
Question: If (A+B) = 5, (B+C) = 6 and (C+D) = 3, what is the value of (A+D)?
(A) 16.
(B) 8.
(C) 7.
(D) 2.
(E) -2.
Rationale: Given A+B = 5
B+C = 6
C+D = 3
(A+B)-(B+C)+(C+D)=(A+D)
=> 5 - 6+3 = 2.
Option D...
Answer: (D) 2.
Question: If a motorist had driven 1 hour longer on a certain day and at an average rate of 4 miles per hour faster, he would have covered 70 more miles than he actually did. How many more miles would he have covered than he actually did if he had driven 2 hours longer and at an average rate of 10 miles per hour faster on that day?
(A)  100
(B)  120
(C)  140
(D)  150
(E)  160
Rationale: Case 1:
let rate = R, Time = T, and Distance =D
so D=RT
Case 2:
(D+70)=(R+4)(T+1)
Case 3:
(D+X)=(R+10)(T+2)
X=140
Ans C
Answer: (C)  140
Question: Last Sunday a certain store sold copies of Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the store sold no other newspapers that day. If r percent of the store's revenues from newspapers sales was from Newspaper A and if w percent of the newspapers that the store sold were copies of Newspaper A, which of the following expresses r in terms of w?
(A) 100p / (125 - p)
(B) 150p / (250 - p)
(C) 300p / (375 - p)
(D) 400w / (500 - w)
(E) 500p / (625 - p)
Rationale: I have just started with qunats section .. I solved this by making two equations and got the answer ... However it was long way of doing it ...
I got the answer as : 100w /(125 - .25 w)...
Multiply this equation by 4 and you get D as the answer ,...
Answer: (D) 400w / (500 - w)
Question: What will come in place of the x in the following Number series? 25, 100, x, 1600, 6400
(A) 6400
(B) 5600
(C) 5790
(D) 8554
(E) 8756
Rationale: (A)
25 x 4 = 100, 100 x 4 = 400, 400 x 4 = 1600, 1600 x 4 = 6400.
Answer: (A) 6400
Question: At what price must an article costing Rs.47.50 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price?
(A) 62.5
(B) 62.1
(C) 62.9
(D) 62.2
(E) 42.5
Rationale: CP = 47.50
SP = 47.50*(125/100) = 59.375
MP*(95/100) = 59.375
MP = 62.5
Answer: A
Answer: (A) 62.5
Question: A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
(A) Rs. 4991
(B) Rs. 5001
(C) Rs. 5991
(D) Rs. 6001
(E) Rs. 6901
Rationale: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs. [ (6500 x 6) - 34009 ]
= Rs. (39000 - 34009)
= Rs. 4991.
answer :A
Answer: (A) Rs. 4991
Question: Find the sum of divisors of 544 which are perfect squares
(A) 21
(B) 22
(C) 23
(D) 24
(E) 25
Rationale: perfect squares divisiors are 1, 2^2 & 2^4 only
sum of divisors of 544 which are perfect squares = 1 + 2^2 + 2^4 = 21
ANSWER:A
Answer: (A) 21
Question: Sushil got twice as many marks in English as in Science. His total marks in English, Science and Maths are 170. If the ratio of his marks in English and Maths is 5:3, find his marks in Science?
(A) 50
(B) 77
(C) 66
(D) 55
(E) 31
Rationale: S:E = 1:2
E:M = 5:3
------------
S:E:M = 5:10:6
5/17 * 170 = 50
Answer: A
Answer: (A) 50
Question: If f(y)=y^2 and y is a positive integer, which of the following CAN be the value of f(f(y))?
(A) 10
(B) 15
(C) 144
(D) 81
(E) 254
Rationale: f(y)=y^2
f(f(y)) = (y^2)^2
f(f(3) = (3^2)^2 = 81
Answer D
Answer: (D) 81
Question: A certain number when divided by 45 leaves a remainder 31, what is the remainder if the same number be divided by 15?
(A) 2
(B) 7
(C) 6
(D) 1
(E) 9
Rationale: Explanation:
45 + 31 = 76/15 = 1 (Remainder)
Answer: D
Answer: (D) 1
Question: A test has 180 questions. Each question has 5 options, but only 1 option is correct. If test-takers mark the correct option, they are awarded 1 point. However, if an answer is incorrectly marked, the test-taker loses 0.25 points. No points are awarded or deducted if a question is not attempted. A certain group of test-takers attempted different numbers of questions, but each test-taker still received the same net score of 40. What is the maximum possible number of such test-takers?
(A) 29
(B) 33
(C) 35
(D) 40
(E) 42
Rationale: A correct answers get you 1 point, an incorrect answer gets you MINUS 1/4 point and a skipped question gets you 0 points. Since there are 200 total questions, there are a variety of ways to get a total of 40 points.
Let C be the number of correct answers and let I be the number of incorrect answers.
To get 40 points, a test taker must have at least 40 correct answers. Then C=> 40.
For every correct question above 40, the test taker has 4 incorrect answers.
Then, the I = 4*(C - 40).
Also, I + C <= 180. Thus 5C <= 340 and so C <= 68.
Then 40 <= C <= 68 and C can have 29 possible values.
The answer is A.
Answer: (A) 29
Question: A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 650 m long?
(A) 870
(B) 89
(C) 90
(D) 97
(E) 98
Rationale: Speed = 240/24 = 10 m/sec.
Required time = (240 + 650)/10 = 89 sec.
Answer: Option B
Answer: (B) 89
Question: For a light that has an intensity of 60 candles at its source, the intensity in candles, S, of the light at a point d d feet from the source is given by the formula S=60k/d^2 60, where k is a constant. If the intensity of the light is 20 candles at a distance of 3 feet from the source, what is the intensity of the light at a distance of 30 feet from the source?
(A) 3/10 candles
(B) 1/2 candles
(C) 1 1/3 candles
(D) 1/5 candles
(E) 3 candles
Rationale: ANS = 3/10
S= 60k/d^2
At 3 feet
20 = 60k/9 so k = 3
At 20 feet
S = 60 *3/30^2 = 1/5
D
Answer: (D) 1/5 candles
Question: The areas, in kilometers squared, of some countries are given below. USA: 9,629,091, Russia: 20,098,242, China: 9,598,094, Canada: 9,984,670, the UK: 242,400 and India: 3,287,263.
What is the difference between the areas of Russia and China?
(A) 5,476,811 kilometers squared
(B) 10,500,148 kilometers squared
(C) 9,843,123 kilometers squared
(D) 1,878,965 kilometers squared
(E) 4,787,900 kilometers squared
Rationale: he difference between the areas of Russia and China is given by
20,098,242 - 9,598,094 = 10,500,148 kilometers squared
correct answer B
Answer: (B) 10,500,148 kilometers squared
Question: The true discount on Rs. 1760 due after a certain time at 12% per annum is Rs. 160. The time after which it is due is :
(A) 6 months
(B) 8 months
(C) 9 months
(D) 10 months
(E) None of these
Rationale: Solution
P.W = Rs. (1760 - 160) = Rs. 1600.
∴ S.I on Rs.1600 ar 12% is Rs. 160.
∴ Time = ( 100 x160/1600 x 12) = 5/6 = ( 5/6x12 ) months = 10 months.
Answer D
Answer: (D) 10 months
Question: Two trains 140 m and 200 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
(A) 10.9 sec
(B) 8.64 sec
(C) 53.8 sec
(D) 10.8 sec
(E) 10.4 sec
Rationale: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 200 = 240 m.
Required time = 240 * 9/250 = 8.64 sec.
Answer: B:
Answer: (B) 8.64 sec
Question: The sum of the digits of a two-digit number is 15 and the difference between the digits is 3. What is the two-digit number?
(A) 79
(B) 56
(C) 81
(D) Cannot be determined
(E) None of these
Rationale: Let the ten's digit be x and unit's digit be y.
Then, x + y = 15 and x - y = 3 or y - x = 3.
Solving x + y = 15 and x - y = 3, we get: x = 9, y = 6.
Solving x + y = 15 and y - x = 3, we get: x = 6, y = 9.
So, the number is either 96 or 69.
Hence, the number cannot be determined.
Answer:D
Answer: (D) Cannot be determined
Question: A candidate got 32% of the votes polled and he lost to his rival by 1908 votes. How many votes were cast?
(A) 5100
(B) 5200
(C) 5300
(D) 5400
(E) 5500
Rationale: Let x be the total number of votes.
0.32x + 1908 = 0.68x
0.36x = 1908
x = 1908/0.36 = 5300
The answer is C.
Answer: (C) 5300
Question: A certain car can travel 64 kilometers on a liter of fuel. If the fuel tank’s contents decrease by 3.9 gallons over a period of 5.7 hours as the car moves at a constant speed, how fast is the car moving, in miles per hour? (1 gallon = 3.8 liters; 1 mile = 1.6 kilometers)
(A) 52
(B) 65
(C) 78
(D) 91
(E) 104
Rationale: Fuel used 3.9 gallons ;convert to liters--> 3.9 x 3.8 liters
Time = 5.7 hours
1 mile = 1.6 kilometers ;convert to miles--> 1km = 1/1.6 mile
Speed (km/hour)= D/T = 64 (km*) x 3.9 x 3.8 / 5.7
replace (km*) to miles ; multiply by 1/1.6 mile
Speed (miles/hour)= 64 x 3.9 x 3.8 / 5.7 x 1.6 = 78 miles/hour
Ans :E
PS :i felt the factors were easy to cancel out ,so didn't require much rounding off
= 64 x 3.9 x 3.8 / 5.7 x 1.6
= 104 E
Answer: (E) 104
Question: A can do a job in 15days and B in 20days. If they work on it together for 5 days, then the fraction of the work that is left is?
(A) 2/15
(B) 8/15
(C) 3/11
(D) 5/12
(E) 6/13
Rationale: A's 1 day work = 1/15
B's 1day work = 1/20
A+B 1day work = 1/15 + 1/20 = 7/60
A+B 5days work = 7/60*5 = 7/12
Remaining work = 1 - 7/12 = 5/12
Answer is D
Answer: (D) 5/12
Question: A and B walk around a circular track. They start at 9 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 10.30 a.m.?
(A) 8
(B) 7
(C) 12
(D) 5
(E) 3
Rationale: Sol.
Relative speed = (2 + 3) = 5 rounds per hour.
So, they cross each other 5 times in an hour and 2 times in half an hour.
Hence, they cross each other 12 times before 10.30 a.m.
Answer C
Answer: (C) 12
Question: What amount does Kiran get if he invests Rs.8000 at 10% p.a. compound interest for two years, compounding done annually?
(A) Rs.9630
(B) Rs.9680
(C) Rs.9610
(D) Rs.9650
(E) None of these
Rationale: A= P{1 + R/100}n
=> 8000{1 + 10/100}2 = Rs.9680
ANSWER:E
Answer: (E) None of these
Question: A can do a job in 20 days and B can do it in 30 days. A and B working together will finish twice the amount of work in ------- days?
(A) 24 days
(B) 22 ½ days
(C) 23 ½ days
(D) 12 ½ days
(E) None of these
Rationale: Explanation:
1/20 + 1/30 = 5/60 = 1/12
12 = 12 *2 = 24 days
Answer: A
Answer: (A) 24 days
Question: Which of the following inequalities has a solution set, when graphed on the number line, is a single line segment of finite length?
(A) 2 <= 5x+6 <= 6
(B) 2 <= 3x+4 <= 6
(C) 2 <= 5x+4 <= 6
(D) 2 <= 3x+7 <= 6
(E) 2 <= 3x+8 <= 6
Rationale: The key words in the stem are:a singleline segment offinite length
Now, answer choices A, B, and C can not be correct answers as solutions sets for these exponential functions are not limited at all (>= for even powers and <= for odd power) and thus can not be finite (x can go to + or -infinity for A and C and x can got to -infinity for B). As for D: we have thatabsolute valueof x is between two positive values, thus the solution set for x (because of absolute value) will be two line segments which will be mirror images of each other.
Answer: B.
Answer: (B) 2 <= 3x+4 <= 6
Question: U(x, y) is the intersection point between the circle (x^2 + y^2 = 4) and the line (y = x +2). Which of the following can be the point U?
(A) (1, 2).
(B) (2, 0).
(C) (0, -2).
(D) (-2, 0).
(E) (2, 2).
Rationale: A quick glance at the options,U(x, y) and we can see that A and E do not satisfy the circle equation. Now we are left with B, C and D. Now B and C do not satisfy the line equation. So we are just left with D. And thats the answer=D
Answer: (D) (-2, 0).
Question: If a man lost 8% by selling oranges at the rate of 25 a rupee at how many a rupee must he sell them to gain 25%?
(A) 20
(B) 15
(C) 18.4
(D) 20
(E) 12.8
Rationale: 92% ---- 25
125% ---- ?
92/125* 25 = 18.4
Answer: C
Answer: (C) 18.4
Question: There are 2 bars of gold-silver alloy; one piece has 2 parts of gold to 3 parts of silver and another has 3 parts of gold to 7 parts of silver. If both bars are melted into 8 kg bar with the final gold to silver ratio of 5:11. What was the weight of the first bar?
(A) 1 kg
(B) 3 kg
(C) 5 kg
(D) 6 kg
(E) 7 kg
Rationale: irst bar is x kg, then second bar is (8-x)kg
First bar:
Amt of gold = 2x/5kg
Amt of silver = 3x/5 kg
Second bar:
Amt of gold = 3(8-x)/10 kg
Amt of silver = 7(8-x)/10 kg
Total amt of gold = 2x/5 + 3(8-x)/10 = (4x+24-3x)/10 = (x+24)/10 kg
Total amt of silver = 3x/5 + 7(8-x)/10 = (6x+56-7x)/10 = (56-x)/10 kg
Ratio of gold/silver = 5/11 = (x+24)/10 * 10/(56-x)
5/11 = (x+24)/(56-x)
5(56-x) = (x+24)(11)
x = 1kg
ANSWER:A
Answer: (A) 1 kg
Question: Watermelon Computer Company began production in 2001 with a total of only 10 employees. From 2001 to 2006, the total number of employees increased to 500. From 2001 to 2016, the total number of employees increased to 5,000. What was the percentage increase of employees from 2006 to 2016?
(A)  10,000%
(B)  6,700%
(C)  2,000%
(D)  3,000%
(E)  5,000%
Rationale: The percentage increase of employees 2006-16 is calculated by;
(100)[(total employees 2001-16) - (total employees 2001-06)]/(total employees 2006) percent.
Solution:(100) [(5,000-500)/150]% = 3,000%
Answer is D
Answer: (D)  3,000%
Question: If 75 % of a boys answered the first question on a certain test correctly, 55 % answered the second question on the test correctly, and 20 % answered neither of the questions correctly, what % answered both correctly?
(A)  10%
(B) (8) 20%
(C)  50%
(D)  60%
(E)  65%
Rationale: {Total} = {First} + {Second} - {Both} + {Neither}
100% = 75% + 55% - {Both} + 20% --> {Both} = 50%.
Answer: C
Answer: (C)  50%
Question: What least number should be subtracted from 13601 such that the remainder is divisible by 87 ?
(A) 27
(B) 29
(C) 28
(D) 30
(E) 31
Rationale: 13601 ÷ 87 = 156, remainder = 29
Hence 29 is the least number which can be subtracted from 13601 such that the remainder
is divisible by 87
Answer is B
Answer: (B) 29
Question: If 3 persons can do 3 times of a particular work in 3 days, then, 7 persons can do 7 times of that work in?
(A) 3 days
(B) 5 days
(C) 7 days
(D) 11 days
(E) 12 days
Rationale: That is, 1 person can do one time of the work in 3 days.
Therefore, 7 persons can do 7 times work in the same 3 days itself.
A)
Answer: (A) 3 days
Question: The average weight of 20 persons sitting in a boat had some value. A new person added to them whose weight was 45 kg only. Due to his arrival, the average weight of all the persons decreased by 5 kg. Find the average weight of first 20 persons?
(A) 55
(B) 56
(C) 57
(D) 58
(E) 60
Rationale: 20x + 45 = 21(x – 5)
X=60
ANSWER:E
Answer: (E) 60
Question: A can do a half of certain work in 60 days and B one third of the same in 35 days. They together will do the whole work in.
(A) 56 days
(B) 420 days
(C) 46 days
(D) 560 days
(E) 96 days
Rationale: A = 120 days
B = 105 days
1/120 + 1/105 = 45/2520 = 1/56
=>56 days
ANSWER:A
Answer: (A) 56 days
Question: If x = -5/4 and y = -3/2, what is the value of the expression -2x – y^2?
(A) 1/4
(B) -1
(C) 5/4
(D) 3/2
(E) 3/4
Rationale: x = -5/4 and y = -3/2
==> -2(-5/4) - (3/2)^2 = 10/4 - 9/4 = 1/4
Ans: A
Answer: (A) 1/4
Question: A does half as much work as Band C does half as much work as A and B together. If C alone can finish the work in 20 days, then together ,all will finish the work in :
(A) 13 1/3 days
(B) 12 1/3 days
(C) 15 days
(D) 20 days
(E) 10 days
Rationale: C alone can finish the work in 20 days.
(A + B)can do it in 20 days
(A + B)s 1 days wok = 1/20.
As 1 days work : Bs 1 days Work = 1/2 : 1 = 1:2.
Aâ€™s 1 dayâ€™s work = (1/20) * (1/3) = (1/60). [Divide 1/20 in the raio 1:2] Bs 1 days work = (1/20) * (2/3) = 1/30
(A+B+c)S 1 dayâ€™s work = (1/60) + (1/30) + (1/20) = 1/10
All the three together will finish it in = 10days.
ANSWER:E
Answer: (E) 10 days
Question: The ratio of number of ladies to gents at a party was 1 : 2, but when 2 ladies and 2 gents left, the ratio became 1 : 3. How many people were originally present at the party?
(A) 6
(B) 9
(C) 12
(D) 10
(E) None of these
Rationale: Let number of ladies = x
then, number of gents = 2x
Now, x−2/2x−2=13⇒ 3x - 6 = 2x - 2
⇒ x = 4
∴ Total number of people originally present = 4 + 8 = 12
Answer C
Answer: (C) 12
Question: The number which exceeds 12% of it by 52.8 is:
(A) 50
(B) 52
(C) 58
(D) 60
(E) None of these
Rationale: Explanation:
Let the number be x. Then, x – 12% of x = 52.8
x – (12/100)x = 52.8
x (1– 12/100) = 52.8
(88/100)x = 52.8
x = (100 X 52.8) / 88 = 60
ANSWER D
Answer: (D) 60
Question: Baney covered a distance of 340 miles between city A and city B taking a total of 5 hours. If part of the distance was covered at 60 miles per hour speed and the balance at 80 miles per hour speed, how many hours did she travel at 60 miles per hour?
(A) 1 hour 45 minutes
(B) 2 hours
(C) 2 hours 30 minutes
(D) 3 hours
(E) None of these
Rationale: Baney covered a distance of 340 miles between city A and city B taking a total of 5 hours.time taken at 60:time taken at 80::(greater speed-average speed):(average speed-lower speed)
average speed is 340/5=68
That gives the answer 3:2=D
Answer: (D) 3 hours
Question: An exam consists of 200 questions to be solved in 3 hours, out of which 50 are maths questions. It is suggested that twice as much time be spent on each math question as for each other question. How many minutes should be spent on maths problems?
(A) 36/25 minutes
(B) 36/24 minutes
(C) 36/26 minutes
(D) 35/25 minutes
(E) 34/25 minutes
Rationale: x=time for each math problem
y= time for every other problem
50x+150y=180 minutes
x=2y because spent twic as much time on the math problems as the other
50(2y)+150y=180
100y+150y=180
250y=180
y= 180/250=18/25 of a minute per problem on the other questions
x=2(18/25)
x=36/25 minutes
ANSWER:A
Answer: (A) 36/25 minutes
Question: I am five letter word. if you remove one, only two letters remain.
What word am I
(A) I am phone
(B) I am table
(C) I am Water
(D) I am Stone
(E) None
Rationale: Correct Answer : D
Stone is five letter word. If your remove one from stone(not 1letter) we will get St
Answer: (D) I am Stone
Question: Which of the following describes all values of x for which 16–x^2 >= 0?
(A)  x >= 1
(B)  x <= –1
(C)  0 <= x <= 1
(D)  x <= –1 or x >= 1
(E)  –4 <= x <= 4
Rationale: 16 - x^2 >=0
means x^2 - 16 <=0
=> (x-4)(x+4) <= 0
=> -4 <= x <= 4
Answer - E
Answer: (E)  –4 <= x <= 4
Question: In a caravan, in addition to 50 hens there are 45 goats and 8 camels with some keepers. If the total number of feet be 224 more than the number of heads, find the number of keepers.
(A) 11
(B) 12
(C) 13
(D) 14
(E) 15
Rationale: Let the number of keepers be x.
Then, total number of feet = 2*50+4*45+4*8+2x
= 2x + 312
Total number of heads = 50+45+8+x = 103 + x
Now, (2x+312) = (103+x)+224
=> x = 15
ANSWER:E
Answer: (E) 15
Question: Albert completes a piece of work in 20 days, Rose completes the same work in 30 days. If both of them work together, then the number of days required to complete the work is?
(A) 10
(B) 12
(C) 15
(D) 20
(E) 18
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 20 × 30/50 = 12 days
Answer is B
Answer: (B) 12
Question: Ernie invested Rs. 2000, with compounded interest annually. After 3 and half years the investment doubled. How many more years will it take before he earns another Rs. 4000 compound interest?
(A) 3.5 years
(B) 1.5 years
(C) 2.5 years
(D) 3 years
(E) 5 years
Rationale: Explanatory Answer
Rs.2000 invested in compound interest becomes Rs.4000 in 3.5 years.
The amount will double again in another 3.5 years.
i.e., the amount will become Rs.4000 in another 3.5 years.
So, to earn another Rs.4000 interest, it will take another 3.5 years.
Answer A
Answer: (A) 3.5 years
Question: Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 30 years. What is Deepak present age?
(A) 18
(B) 15
(C) 77
(D) 266
(E) 182
Rationale: Present age is 4x and 3x,
=> 4x + 6 = 30 => x = 6
So Deepak age is = 3(6) = 18
Answer: A
Answer: (A) 18
Question: A wheel that has 14cogs is meshed with a larger wheel of 28cogs. When the smaller wheel has made 20evolutions, then the number of revolutions mad by the larger wheel is:
(A) 20
(B) 11
(C) 12
(D) 10
(E) 15
Rationale: D
10
Let the required number of revolutions made by larger wheel be x.
Then, More cogs, Less revolutions (Indirect Proportion)
28 : 14 :: 20 : x <-> 28 x x = 14 x 20
x = (14 x 20)/28
x =10
Answer: (D) 10
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
(A) 5.79
(B) 5.71
(C) 5.76
(D) 5.79
(E) 5.73
Rationale: M = 6
S = 1.2
DS = 7.2
US = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
D = 2.88 * 2 = 5.76
Answer: C
Answer: (C) 5.76
Question: √5 percent of 5√5 =
(A) 0.05
(B) 0.25
(C) 0.5
(D) 2.5
(E) 25
Rationale: √/1005/100* 55√5
= (5*5∗5− − √5∗5 )/100
= (5*5) /100
= 25/100
=.25
ANSWER:B
Answer: (B) 0.25
Question: A and B started a partnership business investing some amount in the ratio of 3 : 5. C joined then after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed among A, B and C?
(A) 4 : 9 : 8
(B) 5 : 7 : 4
(C) 6 : 10 : 5
(D) 7 : 9: 4
(E) 5 : 4 : 8
Rationale: Let the initial investments of A and B be 3x and 5x.
A : B : C = (3x x 12) : (5x x 12) : (5x x 6) = 36 : 60 : 30
= 6 : 10 : 5.
ANSWER :C
Answer: (C) 6 : 10 : 5
Question: Out of 450 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ?
(A) 75
(B) 100
(C) 125
(D) 150
(E) 175
Rationale: Explanation:
Students who play cricket, n(A) = 325
Students who play football, n(B) = 175
Total students who play either or both games,
=n(AâˆªB)=450âˆ’50=400Required Number,n(Aâˆ©B)=n(A)+n(B)âˆ’n(AâˆªB)=325+175âˆ’400=100
ANSWER IS B
Answer: (B) 100