mathewhe/aqua_rat huggingface dataset:
Question: John had a stock of 800 books in his bookshop. He sold 62 on Monday, 62 on Tuesday, 60 on Wednesday, 48 on Thursday and 40 on Friday. What percentage of the books were not sold?
(A) 78%
(B) 66%
(C) 62%
(D) 64%
(E) 60%
Rationale: Let N be the total number of books sold. Hence
N = 62 + 62 + 60 + 48 + 40 = 272
Let M be the books NOT sold
M = 800 - N = 1400- 272= 528
Percentage
Books not sold / total number of books = 528/800= 0.66 = 66%
correct answer B
Answer: (B) 66%
Question: In the first quarter of 2008, Harry's Hardware Store sold 300 hammers and 12,000 nails. In the second quarter of 2008, the store sold 375 hammers and 18,000 nails. By approximately what percent did the ratio of hammers sold to nails sold decrease from the first quarter to the second quarter.
(A) 0.4%
(B) 2.1%
(C) 2.5%
(D) 17%
(E) 25%
Rationale: 1st quarter: hammers/nails = 300/12,000 = 150/6000
2nd quarter: hammers/nails = 375/18,000 = 125/6000
ASIDE: It's useful to write both ratios with the same denominator. This allows us to IGNORE the denominator and focus solely on the numerators.
So, our ratio went from 150/6000 to 125/6000
Ignoring the denominators, we went from 150 to 125
The percent change = 100(difference in values)/(original value)
= (100)(150 - 125)/150
= (100)(25)/150)
= (100)(1)/(6)
= 100/6
≈ 16.666 ;
ANSWER:D
Answer: (D) 17%
Question: Avinash covers a distance of 8km in 50 minutes. If he covers 3km distance in 2/5th of time then, What speed should he maintain to cover the remaining distance in the remaining time?
(A) 13 Kmph
(B) 14 Kmph
(C) 15 Kmph
(D) 11 Kmph
(E) 10 Kmph
Rationale: Total distance = 8 Km
Total time = 50 Km
Time taken to cover the distence of 3 Km = 50*2/5 = 20 min = 1/3 hours
Remaining distance = 8 - 3 = 5 Km
Required speed = 5/1/3 = 15 Kmph
ANSWER IS C
Answer: (C) 15 Kmph
Question: A project scheduled to be carried out over a single fiscal year has a budget of $12,600, divided into12 equal monthly allocations. At the end of the fourth month of that fiscal year, the total amount actually spent on the project was $5,630. By how much was the project over its budget?
(A)  $380
(B)  $540
(C)  $1,050
(D)  $1,380
(E)  $1,430
Rationale: Difficulty level: 600
Each month's budget = 12600/12 = 1050
Budget for 4 months = 4*1050 = 4200
Actual amount spent = 5630
Amount spent over the budget = 5630 - 4200 = 1430
Answer (E),
Regards,
Answer: (E)  $1,430
Question: P is three times as fast as Q and working together, they can complete a work in 10 days. In how many days can Q alone complete the work?
(A) 11 days
(B) 16 days
(C) 40 days
(D) 15 days
(E) 19 days
Rationale: B
16 days
P = 3Q
P + Q = 3Q + Q = 4Q
These 4Q people can do the work in 10 days, which means Q can do the work in 4*10 =40 days.
Answer : C
Answer: (C) 40 days
Question: The average weight of 8 persons increases by 5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
(A) 100 kg
(B) 80 kg
(C) 105 kg
(D) 90 kg
(E) None
Rationale: Solution
Total weight increased	= (8 x 5)kg
= 40 kg.
Weight of new person	= (65 + 40)kg
= 105 kg.
Answer C
Answer: (C) 105 kg
Question: How many even integers n, such that 20<=n<=220 are of the form 3k+4, where k is any natural number?
(A) 28
(B) 31
(C) 34
(D) 37
(E) 40
Rationale: The first number is 22 = 16+6(1).
We can continue adding 6 to make a list: 22, 28, 34,...
The last number is 220 = 16+6(34)
There are 34 numbers in the list.
The answer is C.
Answer: (C) 34
Question: John has 10 pairs of matched socks. If he loses 5 individual socks, what is the greatest number of pairs of matched socks he can have left?
(A)  8
(B)  7
(C)  5
(D)  4
(E)  3
Rationale: Because we have to maximize the pair of matched socks, we will remove 2 pairs(4 socks) out of 10 pairs 1 sock from the 3th pair.
Thus the no of matching socks pair remaining = 10 - 3= 7
Answer B
Answer: (B)  7
Question: If a copier makes 5 copies every 5 seconds, then continues at this rate, how many minutes will it take to make 6,000 copies?
(A) 100
(B) 200
(C) 150
(D) 125
(E) 130
Rationale: 5 copies 5 seconds
6000 copies = (6000*5)/5seconds
= 6000/60 minutes
= 100 minutes
Answer : B
Answer: (B) 200
Question: Souju's age is 125% of what it was 10 years ago, but 83 1/3% of what it will be after 10 years. What is her present age?
(A) 50 years
(B) 62 years
(C) 56 years
(D) 60 years
(E) 76 years
Rationale: Let the age before 10 years =x. Then,
125x/100=x+10
â‡’125x=100x+1000
â‡’x=1000/25=40
Present age =x+10=40+10=50
ANSWER:A
Answer: (A) 50 years
Question: e.	Janet has to pay back her bank loan over 11 months following the below sequence.
$50, $55, $65, $80, $85, $95, $110, $115, $125, $140, ?
How much will she pay back on the eleventh month?
(A) $155
(B) $145
(C) $135
(D) $125
(E) $130
Rationale: The sequence progresses +5, +10, +15 repeated; The amount to pay back on the 11th Month is $145
Ans B = $145
Answer: (B) $145
Question: If a survey shows that 30 citizens out of a sample of 200 support a particular Senate bill, what percent of the sample does not support the bill?
(A)  56%
(B)  64%
(C)  72%
(D)  85%
(E)  86%
Rationale: 30 out of 200 supports the bill and we are asked to find the percent who the does not support the bill.
3028 out of 200 supports the bill = 15 out of 100 supports the bill ( taking in % terms )
14 out of 100 supports the bill = 85 (100-15) doesn't support the bill
So, answer is (D) 85%
Answer: (D)  85%
Question: A football team lost 5 yards and then gained 13. What is the team's progress?
(A) 2
(B) 4
(C) 5
(D) 6
(E) 8
Rationale: For lost, use negative. For gain, use positive.
Progress = -5 + 13 = 8 yards
E
Answer: (E) 8
Question: The average weight of 10 girls increases by 5 kg when a new girl comes in place of one of them weighing 50 kg. What might be the weight of the new girl?
(A) 90 kg
(B) 100 kg
(C) 95 kg
(D) 85 kg
(E) 92 kg
Rationale: Total weight increased = 10 x 5 kg = 50 kg.
Weight of new person = 50 + 50 kg =100 kg
Answer : B
Answer: (B) 100 kg
Question: Nine men went to a hotel. 8 of them spent 3 each over their meals and the ninth spent 3 more than the average expenditure of all the nine. The total money spent by all of them was
(A) 26
(B) 40
(C) 29.25
(D) 30.375
(E) None of the above
Rationale: Let the average expenditure of all the ninte be x
Then, 3 × 8 + x + 3 = 9x
⇒ x = 3.375
∴ Total money spent = 9x = 9 × 3.375 = 30.375
Answer D
Answer: (D) 30.375
Question: In a sports club with 30 members, 17 play badminton and 21 play tennis and 2 do not play either. How many members play both badminton and tennis?
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
Rationale: Let x play both badminton and tennis so 17-x play only badminton and 19-x play only tennis. 2 play none and there are total 30 students. hence,
(17-x)+(21-x)+x+2=30
40-2x+x=30
40-x=30
x=10
So 10 members play both badminton and tennis.
D
Answer: (D) 10
Question: How many three letter words are formed using the letters of the word TIME?
(A) 12
(B) 65
(C) 26
(D) 24
(E) 71
Rationale: The number of letters in the given word is four.
The number of three letter words that can be formed using these four letters is 4P3
= 4 * 3 * 2 = 24.
Answer: D
Answer: (D) 24
Question: Find the compound interest and the amount on Rs.8000 at 5% per annum for 3 years when C.I is reckoned yearly?
(A) 1261
(B) 887
(C) 2889
(D) 277
(E) 2991
Rationale: A = 8000(21/20)3
= 9261
= 8000
---------
1261.Answer:A
Answer: (A) 1261
Question: If y>x>0, which of the following must be true:
I. x^2>y^2
II. x^3 > y^3
III. |x|<y
(A) I only
(B) II only
(C) III only
(D) II and III
(E) I, II and III
Rationale: Assuming x and y to be integers
X=3,Y=2
X^2=3^2=9
Y^2=2^2=4
So I is true
Now lets look at option III because if option 3 is true E is the answer or else A
As per question X>Y>0 Hence |X| >Y
So OA=C
Answer: (C) III only
Question: A toy train produces 10 different sounds when it moves around a circular toy track of radius 5 m at 10 m per min. However, the toy train is defective and it now produces only 2 different tunes at random. What are the odds that the train produces for consecutive music tones of the same type?
(A) 1 in 16
(B) 1 in 4
(C) 1 in 8
(D) 1 in 32
(E) 1 in 3
Rationale: 1/(2^2)=1in4
ANSWER:B
Answer: (B) 1 in 4
Question: A person borrows 1000000 for 7 years at 3% p.a. simple interest. He immediately lends it to another person at 5 % p.a. for 7 years. Find his gain in the transaction per year.
(A) 20068
(B) 20050
(C) 20000
(D) 25000
(E) 28000
Rationale: Gain in 7 years
= [(1000000Ã—5Ã—7/100)âˆ’(1000000Ã—7Ã—3/100)]
= (350000 â€“ 210000) = 140000
âˆ´ Gain in 1 year = (140000/7) = 20000
Answer C
Answer: (C) 20000
Question: 61 + 5 * 12 / (180/3) = ?
(A) 22
(B) 77
(C) 29
(D) 62
(E) 21
Rationale: 61 + 5 * 12 / (180/3) = 61 + 5 * 12 / (60)
= 61 + (5 * 12)/60 = 61 + 1 = 62.Answer:D
Answer: (D) 62
Question: Three seventh of a number is 12 more than 40% of that number. What will be the 60% of that number?
(A) 126
(B) 230
(C) 120
(D) 144
(E) 250
Rationale: 3/7 x â€“ 40/100 x = 12
x = 35 * 12
35 * 12 * 60/100 = 252/2 = 126
ANSWER A
Answer: (A) 126
Question: A tank is filled to one quarter of its capacity with a mixture consisting of water and sodium chloride. The proportion of sodium chloride in the tank is 40% by volume and the capacity of the tank is 24 gallons. If the water evaporates from the tank at the rate of 0.5 gallons per hour, and the amount of sodium chloride stays the same, what will be the concentration of water in the mixture in 4 hours?
(A) 40%
(B) 44%
(C) 48%
(D) 52%
(E) 56%
Rationale: The number of gallons in the tank is (1/4)24 = 6 gallons
The amount of sodium chloride is 0.4(6) = 2.4 gallons
At the start, the amount of water is 0.6(6) = 3.6 gallons
After 4 hours, the amount of water is 3.6 - 0.5(4) = 1.6 gallons
The concentration of water is 1.6 / (2.4+1.6) = 40%
The answer is A.
Answer: (A) 40%
Question: Today my car meter reads as 72227 kms. I notes that this is a palindrome. How many minimum kms i need to travel so my car meter find another palindrom.
(A) 700 kms
(B) 625 kms
(C) 600 kms
(D) 210 kms
(E) 120 kms
Rationale: A
700 kms
72227 +700 = 72927 , a palindrome
Answer: (A) 700 kms
Question: A man crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
(A) 7.2
(B) 8.2
(C) 3.5
(D) 4.5
(E) 6.5
Rationale: speed = (600/5*60)sec
=2m/sec
=(2*18/5)=7.2km/hr
ANSWER A
Answer: (A) 7.2
Question: 3 buffaloes eat as much as 4 cows or 2 oxen. At a farm, there are 15 buffaloes, 8 oxen, and 24 cows. The fodder for these cattle is available for 36 days. If 40 more cows and 15 more buffaloes are brought in, how many days will the fodder last?
(A) 15 days
(B) 18 days
(C) 21 days
(D) 24 days
(E) 27 days
Rationale: 2 oxen = 3 buffaloes = 4 cows
Also: 15 buffaloes + 8 oxen + 24 cows
= 10 oxen + 8 oxen + 12 oxen = 30 oxen
There is enough fodder for 1 oxen for 30*36 days.
40 cows + 15 buffaloes = 20 oxen + 10 oxen = 30 oxen
The new total is equal to 60 oxen instead of 30 oxen.
30*36 / 60 oxen = 18 days
The answer is B.
Answer: (B) 18 days
Question: The average age 10 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
(A) 20
(B) 99
(C) 77
(D) 26
(E) 12
Rationale: 10 * 2 = 20 years
Answer: A
Answer: (A) 20
Question: Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 2 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is?
(A) 19 : 6
(B) 19 : 4
(C) 19 : 1
(D) 19 : 5
(E) 19 : 3
Rationale: Quantity of alcohol in vessel P = 62.5/100 * 2 = 5/4 litres
Quantity of alcohol in vessel Q = 87.5/100 * 4 = 7/2 litres
Quantity of alcohol in the mixture formed = 5/4 + 7/2 = 19/4 = 4.75 litres
As 6 litres of mixture is formed, ratio of alcohol and water in the mixture formed = 4.75 : 1.25 = 19 : 5.
Answer:D
Answer: (D) 19 : 5
Question: Kelly and Jody packed boxes with books. If Jody packed 30% of the total number of boxes, what was the ratio of the number of boxes Kelly packed to the number that Jody packed?
(A) 1 to 6
(B) 1 to 4
(C) 3 to 7
(D) 3 to 5
(E) 2 to 3
Rationale: Explanation:
If Jody packed 30% of the boxes then Kelly packed 70%. The ratio of the number of boxes Kelly packed to the number Jody packed is thus 30%/70%=3/7
Answer: Option C
Answer: (C) 3 to 7
Question: A clock is started at noon. By 10 minutes past 5, the hour hand has turned through how much?
(A) 175°
(B) 155°
(C) 145°
(D) 165°
(E) 195°
Rationale: We know that angle traced by hour hand in 12 hrs = 360°
Time duration from noon to 10 minutes past 5
= 5 hours 10 minutes
=5(10/60) hour =31/6 hour
Hence the angle traced by hour hand from noon to 10 minutes past 5
=31/6×360/12=31/6×30
=31×5=155°
Answer is B.
Answer: (B) 155°
Question: A plot ABCD is as shown in figure, where AF = 30 m, CE = 40 m, ED = 50 m, AE = 120 m. Find the area of the plot ABCD?
(A) 1828 sq.m
(B) 2767 sq.m
(C) 2789 sq.m
(D) 7200 sq.m
(E) 2651 sq.m
Rationale: Area of plot ABCD = Area of ADE + Area of AFB + Area of BCEF
= 1/2 * 50 * 120 + 1/2 * 40 * 30 + 40 * 90
= 3000 + 600 + 3600
= 7200 sq.m
Answer:D
Answer: (D) 7200 sq.m
Question: The cost of 5 kgs. of sugar is Rs.279. What is the cost of 1 kg of sugar?
(A) Rs.55
(B) Rs.55.80
(C) Rs.65.80
(D) Rs.65
(E) Rs.75
Rationale: Explanation:
The cost of kgs. of sugar = 279x 1/5= Rs.55.80
Answer: Option :B
Answer: (B) Rs.55.80
Question: By how much is three-fifth of 350 greater than four- seventh of 210 ?
(A) 95
(B) 110
(C) 120
(D) None of these
(E) Cannot be determined
Rationale: Solution
3/5of 350 - 4/7of 210 - 120 = 90.
Answer D
Answer: (D) None of these
Question: What will be the compound interest on a sum of Rs. 25,000 after 3 years at the rate of 12% p.a.?
(A) Rs.10123.77
(B) Rs.10123.21
(C) Rs.10123.20
(D) Rs.10123.28
(E) Rs.10123.21
Rationale: Amount = [25000 * (1 + 12/100)3]
= 25000 * 28/25 * 28/25 * 28/25
= Rs. 35123.20
C.I. = (35123.20 - 25000)
= Rs. 10123.20
Answer:C
Answer: (C) Rs.10123.20
Question: Among 250 viewers interviewed who watch at least one of the three TV channels namely A, BC. 116 watch A, 127 watch C, while 107 watch B. If 80 watch exactly two channels. How many watch exactly one channel?
(A) 185
(B) 160
(C) 175
(D) 190
(E) 195
Rationale: 250 = n(Exactly 1 channel) + n(Exactly 2 channels) + n(Exactly 3 channels)
250 = n(Exactly 1 channel) + 80 + n(Exactly 3 channels)
Let's find the value of n(Exactly 3 channels) = x
250 = n(A) + n(B) + n(C) - n(A and B) - n(B and C) - n(C and A) + n(A and B and C)
Note that each of n(A and B) is the sum of 'number of people watching exactly two channels A and B' and 'number of people watching all three channels'.
250 = 116 + 127 + 107 - n(Exactly 2 channels) - 3x + x
250 = 116 + 127 + 107 - 80 - 2x
x = 25
250 = n(Exactly 1 channel) + 80 + 25
n(Exactly 1 channel) = 160
Answer (B)
Answer: (B) 160
Question: A bag contains 4 yellow, 2 green balls. 3 balls are drawn randomly. What is the probability that balls drawn contain exactly two green balls?
(A) 1/5
(B) 2/9
(C) 3/11
(D) 4/17
(E) 2/3
Rationale: Total number of balls = 4+2 = 6
n(S) = 6C3 = 6*5*4 / 3*2 = 20
n(E) = 2C2* 4C1 = 4
Probability = 4/20 = 1/5
Answer is A
Answer: (A) 1/5
Question: Surekha started a business investing Rs.25,000 in 1999. In 2000, he invested an additional amount of Rs. 10,000 and Rajesh joined him with an amount of Rs. 35,000. In 2001, Surekha invested another additional amount of Rs.10,000 and Jay joined them with an amount of Rs.35,000. What will be Rajesh's share in the profit of Rs.2,10,000 earned at the end of 3 years from the start of the business in 1999?
(A) Rs 45000
(B) Rs 50000
(C) Rs 70000
(D) Rs 75000
(E) None
Rationale: Surekha:Rajesh:Jay= (25000×12+35000×12+45000×12):(35000×24) : (35000×12) = 1260000 : 840000 : 420000 = 3 : 2 : 1. Rajesh's share =Rs.(210000×2/6) = Rs.70000.
Answer C
Answer: (C) Rs 70000
Question: How many integers from 0 to 56, inclusive, have a remainder of 1 when divided by 3 ?
(A) 15
(B) 16
(C) 17
(D) 18
(E) 19
Rationale: My ans is also C.17.
Explanation:
1 also gives 1 remainder when divided by 3, another number is 4, then 7 and so on.
Hence we have an arithmetic progression: 1, 4, 7, 10,..... 55, which are in the form 3n+1.
Now we have to find out number of terms.
tn=a+(n-1)d, where tn is the nth term of an AP, a is the first term and d is the common difference.
so, 55 = 1+(n-1)3
or, (n-1)3 = 54
or, n-1 = 18
or, n = 19
E
Answer: (E) 19
Question: How much interest can a person get on Rs. 8200 at 17.5% p.a. simple interest for a period of two years and six months?
(A) 3587.58
(B) 3587.59
(C) 3587.5
(D) 3587.52
(E) 3587.56
Rationale: I = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50.Answer: C
Answer: (C) 3587.5
Question: N number of persons decide to raise 3 lakhs by equal contributions from each. If they contributed 50 each extra, the contribution would be 3.25 lakhs. How many persons are there?
(A) 600
(B) 400
(C) 450
(D) Cannot be determined
(E) None of these
Rationale: Required persons = 325000−300000/50 = 500
Answer E
Answer: (E) None of these
Question: If the sales tax be reduced from 4 (1/3) % to 2 (1/2) %, then what difference does it make to a person who purchases a bag with marked price of Rs. 8000?
(A) 146.69
(B) 146.66
(C) 146.62
(D) 146.61
(E) 146.6
Rationale: Explanation:
Required difference = (4 (1/3) of Rs. 8000) - (2 (1/2) of Rs. 8000)
= (13/3 – 5/2) % of Rs. 8000
= (11/6) x (1/100) x 8000
= Rs. 146.66
ANSWER: B
Answer: (B) 146.66
Question: In how many ways can you seat 8 people on a bench if one of them does not want to sit in one of the two middle seats or at either end?
(A) 17,540
(B) 18,360
(C) 19,320
(D) 20,160
(E) 21,480
Rationale: One person can choose 4 possible chairs to sit. The remaining 7 people can sit in 7! ways.
The number of arrangements is 4*7! = 20,160.
The answer is D.
Answer: (D) 20,160
Question: Express 25 mps in kmph?
(A) 22
(B) 87
(C) 90
(D) 77
(E) 22
Rationale: 25 * 18/5 = 90 kmph
Answer: C
Answer: (C) 90
Question: How many odd factors does 250 have?
(A)  3
(B)  4
(C)  5
(D)  6
(E)  8
Rationale: Start with the prime factorization: 250 = 2*5*7
For odd factors, we put aside the factor of two, and look at the other prime factors.
set of exponents = {1, 1}
plus 1 to each = {2, 2}
product = 2*2 = 4
Therefore, there are 4 odd factors of 250.
Answer: B.
Answer: (B)  4
Question: A mirror 2 inches wide is placed around a rectangular paper with dimensions 8 inches by 12 inches. What is the area of the frame, in square inches?
(A) 96
(B) 94
(C) 28
(D) 44
(E) 18
Rationale: This question is an example of a 'punch out' question - we have to find the area of EVERYTHING, then 'punch out' the part that we don't want.
We're told that a mirror 2 inches wide is placed around a rectangular paper with dimensions 8 inches by 12 inches. We're asked for the area of the mirror , in square inches.
Area of a rectangle = (length)(width)
So the area of the paper is... (8)(12) = 96
The mrror 'adds' 2 inches to the top, bottom, left and right 'sides' of the picture, so the area of EVERYTHING is...
(8+2+2)(12+2+2) = (12)(16) = 196
When we 'punch out' the area of the paper, we'll be left with the area of the FRAME:
192 - 96 = 96
Final Answer:
A
Answer: (A) 96
Question: If the perimeter of a rectangular garden is 700 m, its length when its breadth is 100 m is?
(A) 299 m
(B) 777 m
(C) 200 m
(D) 250 m
(E) 128 m
Rationale: 2(l + 100) = 700 => l
= 250 m
Answer:D
Answer: (D) 250 m
Question: The game of blackjack is played with a deck consisting of 13 cards (one of each of the numbers 2-10, one jack, one queen, one king, and one of ace) in each of four suits: clubs, diamonds, hearts, and spades.
In a game of blackjack, if your first card is a spade, what are the odds Q that it is an ace?
(A) 1/52
(B) 1/26
(C) 1/13
(D) 1/4
(E) 5/13
Rationale: The question should ask about the probability not the odds.
There are 13 spades, the probability Q that the spade we already have is an ace is therefore 1/13.
Answer: C.
Answer: (C) 1/13
Question: A certain stock exchange designates each stock with a 1, 2 or 3 letter code, where each letter is selected from the 10 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order, constitute a different code, how many diff stocks is it possible to designate with these codes?
(A) 1200
(B) 996
(C) 1110
(D) 896
(E) 1400
Rationale: Pretty simple actually
Number of 1 letter symbols = 10
Number of 2 letter symbols = 10*10
Number of 3 letter symbols = 10*10*10
The answer is sum of the 3. = 10+100+1000 =1110
So the answer is C.
Answer: (C) 1110
Question: In a 1000 m race, A beats B by 200 meters or 25 seconds. Find the speed of B?
(A) 8
(B) 9
(C) 7
(D) 6
(E) 2
Rationale: Since A beats B by 200 m or 25 seconds, i
t implies that B covers 200 m in 25 seconds.
Hence speed of B = 200/25 = 8 m/s.
Answer: A
Answer: (A) 8
Question: Boy purchased two flats for Rs.5,00,000. On one he gains 15 % while on the other he losses 15%. How much does he gain or lose?
(A) 1.25%
(B) 2.1%
(C) 2.25%
(D) 2.65%
(E) 3%
Rationale: Generally in such cases, there is always loss.
So always remember, when two materials are sold and if one material gets profit and the other gets a loss, then use the trick shown below to calculate the loss.
Loss% = Common loss and gain% 2 = x 2
10 10
Therefore, here common loss and gain % = 15%
Hence,
Loss% = 15 2 = 2.25%
C
Answer: (C) 2.25%
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
(A) 3 : 1
(B) 3 : 2
(C) 3 : 6
(D) 3 : 7
(E) 3 : 9
Rationale: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y = 23 x + 23 y ==> 4 x = 6 y ==> x/y = 3/2.
Answer: Option B
Answer: (B) 3 : 2
Question: A no.when divided by 222 gives a remainder 43, what remainder will beobtained by dividingthe same no.17?
(A) 2
(B) 7
(C) 9
(D) 10
(E) 15
Rationale: 222 + 43 = 265/17 = 10 (Remainder)
D
Answer: (D) 10
Question: How many cuboids of length 5 m, width 4 m and height 3 m can be farmed from a cuboid of 16 m length, 10 m width and 12 m height.
(A) 32
(B) 28
(C) 36
(D) 40
(E) 50
Rationale: (16 Ã— 10 Ã— 12)/(5 Ã— 4 Ã— 3) = 32
Answer is A.
Answer: (A) 32
Question: A school has received 50% of the amount it needs for a new building by receiving a donation of $400 each from people already solicited. People already solicited represent 40% of the people from whom the school will solicit donations. How much average contribution is requited from the remaining targeted people to complete the fund raising exercise?
(A) $400
(B) $177.78
(C) $320
(D) $277
(E) $200
Rationale: Let us suppose there are 100 people. 40% of them donated $16000 ( 400 * 40 )
$16000 is 50% of total amount.
So total amount = 16000 * 100/50
Remaining amount is 50% of total amount.
50% of total amount = 16000 * (100/50) * (50/100) =16000
This amount has to be divided by 50 ( remaining people are 50 )
So per head amount is 16000 / 50 = 320
ANSWER:C
Answer: (C) $320
Question: If a, b, and c are consecutive integers such that a < b < c and a is an even prime number, which of the following is true?
I. a × b × c < a^3
II. 5b < bc
III. a + b + c > a^3
(A) I only
(B) II only
(C) III only
(D) II and III
(E) I, II, and III
Rationale: Only 'C' is possible solution. If a is even prime number i.e 2, b is 3 and c is 4
Putting the values in the answers only 'C' seems valid.
Answer: (C) III only
Question: Jerome anticipated that the WebWeb.com stock price would fall and sold all his WebWeb.com stocks for $5 per stock. He paid $10,000 tax on the revenue. A week later, Jerome became convinced that the WebWeb.com stock price would rise, and he used the money that he had gotten from selling the WebWeb.com stocks to purchase them again, this time at $6 per stock. If Jerome ended up having 7000 WebWeb.com stocks fewer than the number he had before selling them, how many WebWeb.com stocks did he have originally?
(A) 10,000
(B) 11,600
(C) 17,000
(D) 14,000
(E) 16,400
Rationale: Let the number of shares be x.
5*x -10000(money paid in taxes) = 6(x- 7000)
Solving for x, we get the shares as 17000.
Ans :(Option C)
Answer: (C) 17,000