mathewhe/aqua_rat huggingface dataset:
Question: When a merchant imported a certain item, he paid a 9 percent import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that the merchant paid was $67.50, what was the total value of the item?
(A) $1,150
(B) $1,450
(C) $1,750
(D) $2,150
(E) $2,450
Rationale: Let x be the value in excess of $1,000.
0.09x = 67.5
x = $750
The total value was $750 + $1,000 = $1,750.
The answer is C.
Answer: (C) $1,750
Question: The present age of a father is 4 years more than three times the age of his son. Three years hence, father's age will be 10 years more than twice the age of the son. Find the present age of the father.
(A) 30
(B) 38
(C) 29
(D) 40
(E) 48
Rationale: if the present age be x years.
father's will be (3x+4)years..
so, (3x+4+3)=2(x+3)+10
or, x=9
so the fathers present age =(3x+3)=(3*9+3)years =30years..
ANSWER : OPTION A
Answer: (A) 30
Question: A man can row upstream at 10kmph and downstream at 20kmph. Find man's rate in still water ?
(A) 5km/hr
(B) 15km/hr
(C) 10km/hr
(D) 20km/hr
(E) 7.5km/hr
Rationale: Rate in still water = 1/2 (10+20) = 15km/hr
Answer is B
Answer: (B) 15km/hr
Question: The difference between a number and its two-fifth is 510. What is 30% of that number?
(A) 253
(B) 255
(C) 252
(D) 251
(E) 254
Rationale: Let the number be x. Then,
x - 2/5 x = 510
x = (510 * 5)/3 = 850
30% of 850 = 255.
Answer:B
Answer: (B) 255
Question: By selling an article at Rs.1000, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%?
(A) s.600
(B) s.480
(C) s.500
(D) s.450
(E) s.550
Rationale: SP = 1000
Profit = 25%
CP = (SP)*[100/(100+P)]
= 1000 * [100/125]
= 800
Loss = 25% = 25% of 800 = Rs.200
SP = CP - Loss = 800 - 200 = Rs.600
ANSWER:A
Answer: (A) s.600
Question: Out of first 40 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is -.
(A) 1/2
(B) 16/19
(C) 4/5
(D) 31/40
(E) 3/5
Rationale: n(S) = 40
n(Even no) = 20 = n(E)
n(Prime no) = 12 = n(P)
P(EᴜP) = 20/40 + 12/40 - 1/40 = 31/40
ANSWER:D
Answer: (D) 31/40
Question: If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,861,997 minutes earlier? (Assume standard time in one location.)
(A) 6:35
(B) 6:30
(C) 6:27
(D) 6:24
(E) 6:21
Rationale: 6:27 minus 2,861,997 in any way must end with 0.
The only answer choice which ends with 0 is B.
The answer is B.
Answer: (B) 6:30
Question: Jacob is now 12 years younger than Michael. If 3 years from now Michael will be twice as old as Jacob, how old will Jacob be in 4 years?
(A)  3
(B)  7
(C)  15
(D)  21
(E)  13
Rationale: Jacob=x years, Mike=x+12 years
3 years from now,
2(x+3)=x+15
2x+6=x+15
x=9
x+4=13 years
Answer E
Answer: (E)  13
Question: Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old his son. Then the sum of the present ages of the son and the father is:
(A) 108
(B) 75
(C) 80
(D) 110
(E) 101
Rationale: Let the present ages of the father and son be 2x and x years respectively.
Then, (2x - 18) = 3(x - 18) => x = 36
Required sum = (2x + x) = 108 years.
ANSWER A
Answer: (A) 108
Question: In a 50-mile trip, the first 10 miles were completed at 50 mph. If the average speed for the whole trip was 60 mph, what was the average speed in the last 40 miles?
(A) 1200/19 mph
(B) 1100/19 mph
(C) 1000/17 mph
(D) 900/17 mph
(E) 800/17 mph
Rationale: The time to complete the first 10 miles was (10 miles / 50 mph) = (1/5) hours.
The time to complete the whole trip was (50 miles / 60 mph) = (5/6) hours.
The time to complete the last 40 miles was (5/6) - (1/5) = (19/30) hours.
The average speed in the last 40 miles was (40 miles / (19/30) hours) = 1200/19 mph.
The answer is A.
Answer: (A) 1200/19 mph
Question: The digital sum of a number is the sum of its digits. For how many of the positive integers 24-140 inclusive is the digital sum a multiple of 7?
(A) 7
(B) 8
(C) 14
(D) 15
(E) 20
Rationale: is there other way than just listing?
25
34
43
52
59
61
68
70
77
86
95
106
115
124
133
15 ways..
D
Answer: (D) 15
Question: 0.03 x 0.35=?
(A) 3.15e-05
(B) 0.000315
(C) 0.105
(D) 0.0105
(E) 0.00105
Rationale: 3 x 35 = 105
Sum of decimal places =4
Therefore, 0.03 x 0.35 = 0.0105
Answer is D.
Answer: (D) 0.0105
Question: If x is 20 percent greater than 80, then x =
(A) 68
(B) 70.4
(C) 96
(D) 105.6
(E) 108
Rationale: X is 20% greater than 80 means X is 1.2 times 80 (in other words 80 + 20/100 * 80 = 1.2 * 80)
Therefore, X = 1.2 * 80 = 96.00
ANSWER:C
Answer: (C) 96
Question: h, b, c, and d are positive integers. If the remainder is 9 when h is divided by b, and the remainder is 5 when c is divided by d, which of the following is NOT a possible value for b + d?
(A)  20
(B)  19
(C)  18
(D)  16
(E)  15
Rationale: When h is divided by b remainder is 9 that means b is greater than or equals to 10, similarly d is greater than or equals to 6.
b + d cannot be 15, hence E is the answer.
Answer: (E)  15
Question: The average of first 15 natural numbers is?
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
Rationale: Sum of 15 natural no. = 240/2 = 120
Average = 120/15 = 8
Answer:B
Answer: (B) 8
Question: Evaluate: 30 - 12÷3×2 = ?
(A) 20
(B) 22
(C) 24
(D) 26
(E) 28
Rationale: According to order of operations, 12÷3×2 (division and multiplication) is done first from left to right
12÷3×2 = 4 × 2 = 8
Hence
30 - 12÷3×2 = 30 - 8 = 22
correct answer B)22
Answer: (B) 22
Question: the sum of 5th and 21th term of A.P. is equal to the sum of 8th , 15th and 13 th term . find the term which is 0
(A) 11
(B) 10
(C) 12
(D) 13
(E) 14
Rationale: t5 + t21 = t8 + t15 + t13
=> a+4d + a+20d = a+7d + a+14d + a+12d
=> a + 9d = 0
=> t10 = 0 i.e. 10th term is zero.
ANSWER: B
Answer: (B) 10
Question: A began business with Rs.45000 and was joined afterwards by B with Rs.5400. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
(A) 6
(B) 5
(C) 7
(D) 4
(E) 1
Rationale: 45*12 : 54*x = 2: 1
x = 5
12 -5 = 7
Answer: C
Answer: (C) 7
Question: In a sports club with 30 members, 17 play badminton and 19 play tennis and 3 do not play either. How many members play both badminton and tennis?
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
Rationale: Let x play both badminton and tennis so 17-x play only badminton and 19-x play only tennis. 2 play none and there are total 30 students. hence,
(17-x)+(19-x)+x+3=30
39-2x+x=30
39-x=30
x=9
So 9 members play both badminton and tennis.
C
Answer: (C) 9
Question: In an election between two candidates, 75 % of the voters cast their votes, out of which 2% of the
votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. Find the
total number of votes
(A) 16800
(B) 15800
(C) 16700
(D) 15700
(E) None of these
Rationale: Explanation:
Let the total number of votes enrolled are x.
Number of votes cast = 75% of x
Valid votes = 98% of 75% of x
Now, as 9261 is the 75% of valid casted votes so,
75% of 98% of 75% of x = 9261 [imporant]
=>75×98×75×x100×100×100=9261=>x=16800
Answer: Option A
Answer: (A) 16800
Question: In a basket 7 apples are available. Jack wants to take 5 apples.In how many ways to choose apples?
(A) 21
(B) 12
(C) 22
(D) 30
(E) 35
Rationale: There are 7C5 possible ways to choose apples
7C5=7!/5!*2!=7*6*5!/5!*2*1
=21 ways
Ans:option A
Answer: (A) 21
Question: Two numbers N and 14 have LCM = 56 and GCF = 10. Find N.
(A) 24
(B) 40
(C) 44
(D) 54
(E) 64
Rationale: The product of two integers is equal to the product of their LCM and GCF. Hence.
14 × N = 56 × 10
N = 56 × 10 / 14 = 40
correct answer B
Answer: (B) 40
Question: The operationis defined for all integers a and b by the equation ab = (a - 1)(b - 1). If x15 = 98, what is the value of x ?
(A) 8
(B) 7
(C) 10
(D) 11
(E) 12
Rationale: ab = (a - 1)(b - 1)
x15 = (x-1)(15-1) = 98 --> x-1=7 --> x=8
Answer: A.
Answer: (A) 8
Question: The price of a certain car this year is $ 42,000, which is 25 percent greater than the cost of the car last year. What was the price of the car last year?
(A) $27,000
(B) $28,000
(C) $31,500
(D) $33,600
(E) $34,500
Rationale: 125% of Cost of car last year = $42000
1.25 of Cost of car last year = $42000
i.e. Cost of car last year = $42000/1.25 = $33600
Answer: option D
Answer: (D) $33,600
Question: Find the odd man out
3, 8, 15, 24, 34, 48, 63
(A) 15
(B) 24
(C) 34
(D) 48
(E) 58
Rationale: difference between numbers are 5, 7, 9, 11, 13, 15
3+5=8
8+7=15
15+9=24
24+11=35
35+13=48
48+15=63
ANSWER:C
Answer: (C) 34
Question: By selling 12 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
(A) 8
(B) 9
(C) 10
(D) 89
(E) 81
Rationale: 80% --- 12
120% --- ?
80/120 * 12 = 8
Answer: A
Answer: (A) 8
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
(A) 9.8 sec
(B) 12.1 sec
(C) 12.42 sec
(D) 14.3 sec
(E) 9.2 sec
Rationale: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.
ANSWER:B
Answer: (B) 12.1 sec
Question: When x divided by 288, the remainder is 47. Find the remainder when the same x is divided by 24?
(A) 20
(B) 21
(C) 23
(D) 26
(E) 29
Rationale: 23
Option C
Answer: (C) 23
Question: What is the last digit in(7^95 - 3^58)?
(A) 5
(B) 6
(C) 4
(D) 9
(E) 5.5
Rationale: Explanation:
Unit digit in 795 = Unit digit in [(74)23 x 73]
= Unit digit in [(Unit digit in(2401))23 x (343)]
= Unit digit in (123 x 343)
= Unit digit in (343)
= 3
Unit digit in 358 = Unit digit in [(34)14 x 32]
= Unit digit in [Unit digit in (81)14 x 32]
= Unit digit in [(1)14 x 32]
= Unit digit in (1 x 9)
= Unit digit in (9)
= 9
Unit digit in (795 - 358) = Unit digit in (343 - 9) = Unit digit in (334) = 4.
So, Answer C
Answer: (C) 4
Question: The sector of a circle has radius of 21 cm and central angle 130o. Find its perimeter?
(A) 91.5 cm
(B) 89.6 cm
(C) 91.8 cm
(D) 92.5 cm
(E) 99.5 cm
Rationale: Perimeter of the sector = length of the arc + 2(radius)
= (130/360 * 2 * 22/7 * 21) + 2(21)
= 47.6 + 42
= 89.6 cm
Answer:B
Answer: (B) 89.6 cm
Question: In a camp, there is a meal for 110 men or 180 children. If 145 children have taken the meal, how many men will be catered to with remaining meal?
(A) 20
(B) 30
(C) 50
(D) 21
(E) 40
Rationale: There is a meal for 180 children. 145 children have taken the meal.
Remaining meal is to be catered to 35 children.
Now, 180 children 110 men.
35 children (110/180)	* 35 = 21 men
Answer is D.
Answer: (D) 21
Question: Find the odd man out. 23, 27, 36, 52, 77, 111, 162
(A) 162
(B) 111
(C) 52
(D) 27
(E) 23
Rationale: Explanation :
23 + 22 = 27
27 + 32 = 36
36 + 42 = 52
52 + 52 = 77
77 + 62 = 113
113 + 72 = 162
Hence, 113 should have come in place of 111
Answer : Option B
Answer: (B) 111
Question: A watch was sold at a loss of 10%. If it was sold for Rs.225 more, there would have been a gain of 5%. What is the cost price?
(A) 1000
(B) 1500
(C) 2778
(D) 2788
(E) 2991
Rationale: 90%
105%
--------
15% ---- 225
100% ---- ? => Rs.1500
Answer:B
Answer: (B) 1500
Question: A train 100 m long crosses a platform 125 m long in 2 sec; find the speed of the train?
(A) 36
(B) 405
(C) 200
(D) 302
(E) 404
Rationale: D = 100 + 125 = 225
T = 2
S = 225/2 * 18/5 = 405 kmph
Answer: B
Answer: (B) 405
Question: If x is an integer, then x(x - 1)(x - m) must be evenly divisible by three when m is any of the following values EXCEPT
(A) -4
(B) -2
(C) -1
(D) 2
(E) 5
Rationale: here's another approach
x(x - 1)(x - m)
all three are consecutive, so the product MUST be a multiple of 3
we don't know the value of k just yet ... so let's extend the series ... the extension itself reveals the answers
..(x-5)..(x-2)(x-1)x(x+1)..(x+4)..
we can see the possible values of m too from the series
m = 2 OR 2+3n [25]
m= -1 OR -1+3n [-1-4]
B i.e. -2 does not fit in any value of m
so B it is
Answer: (B) -2
Question: A train 400 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
(A) 298 m
(B) 500 m
(C) 900 m
(D) 967 m
(E) 1181 m
Rationale: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (400 + x)/60 = 65/3
x = 900 m.
Answer: C
Answer: (C) 900 m
Question: sale of Rs 6835, Rs. 9927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 7000 ?
(A) 4966
(B) 2477
(C) 2877
(D) 7991
(E) 8881
Rationale: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6500 x 6) - 34009]
= Rs. (42000 - 34009)
= Rs. 7991
Answer: D
Answer: (D) 7991
Question: What is 990*990?
(A)  974,169
(B)  974,219
(C)  974,549
(D)  980,100
(E)  985,369
Rationale: if you take a base of 1000 then 990 is 10 less than 1000
to get the product of 990 x 990 write like this
990- 10( as 10 less than base1000)
990- 10
now 10 x 10 = 100
and 990-10 = 980
so 990 x 990 = 980100 ... (bingo the answer is D . you can even have a shortcut ...... 10 x 10 = 100... only answer choice has last three digits as 100.. so no need to calculate 990-10 . after you get 10 x 10 you can straight way pick answer choice D.
Answer: (D)  980,100
Question: An ore contains 25% of an alloy that has 90% iron. Other than this, in the remaining 75% of the ore, there is no iron. How many kilograms of the ore are needed to obtain 60 kg of pure iron?
(A) 250 kg
(B) 275 kg
(C) 300 kg
(D) 266.66 kg
(E) None
Rationale: Solution: Let there is 100 kg of ore.
25% ore contains 90% off Iron that means 25 kg contains;
25*90/100 = 22.5 kg Iron.
22.5 kg Iron contains 100 kg of ore.
Then, 1 kg of iron contains = 25/100 kg ore;
Hence, 60 kg iron contains = 100*60/22.5 = 266.66 kg ore.
Answer: Option D
Answer: (D) 266.66 kg
Question: The probability of rain showers in Barcelona on any given day is 0.2. What is the probability that it will rain on exactly one out of three straight days in Barcelona?
(A) 0.144
(B) 0.072
(C) 0.432
(D) 0.72
(E) 0.384
Rationale: IMO This is just for first day! It can rain on 2nd day or 3 rd day (and not rain on other days) in 3 consecutive days!
Hence,
0.2*0.8*0.8 + 0.8*0.2*0.8 + 0.8*0.8*0.2 = 0.384
Option - E
Answer: (E) 0.384
Question: A man purchased 3 blankets @ Rs.100 each, 6 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?
(A) A)300
(B) B)350
(C) C)450
(D) D)470
(E) E)500
Rationale: Explanation:
10 * 150 = 1500
3 * 100 + 6* 150 = 1200
1500 – 1200 =300
A
Answer: (A) A)300
Question: In how many different number of ways 5 men and 2 women can sit on a shopa which can accommodate persons?
(A) 210
(B) 220
(C) 240
(D) 250
(E) 270
Rationale: 7p3 = 7 × 6 × 5 = 210
A)
Answer: (A) 210
Question: What is the compound interest paid on a sum of Rs.700 for the period of 2 years at 10% per annum.
(A) 130
(B) 620
(C) 147
(D) 120
(E) None of these
Rationale: Solution= Interest % for 1st year= 10
Interest % for 2nd year= 10+ 10% of 10= 10+ 10 *10/100=11
Total % of interest= 10 + 11=21
Total interest = 21 % 700 = 700 * (21/100)= 147
Answer C
Answer: (C) 147
Question: Of the 80 electronics components that a factory must manufacture, 60 percent would be most e¢ ciently manufactured by Machine A and the remaining 40 percent would be most efficiently manufactured by Machine B, though either machine could manufacture any of the 80 components. If 60 percent of the components were manufactured by Machine A and the remainder were manufactured by Machine B, what is thehighest possible number of components that were manufactured by the machine that would manufacture them the most efficiently?
(A) 80
(B)  32
(C)  33
(D)  35
(E)  36
Rationale: A can manufacture 60 % of 80 efficiently, which is 48.
B can manufacure 40 % of 80 efficiently, which is 32.
Now 60 % of 80 are produced by A. This means 48 parts. Since A can produce 48 efficiently, all 48 are produced efficiently. Rest (32) is produced by B, which can produce max. 32 parts efficiently.
Hence parts that were produced efficiently = 32+48 = 80. (A).
Answer: (A) 80
Question: Raja purchased a refrigerator for Rs. 12500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 10% if no discount was offered?
(A) 68980
(B) 46898
(C) 56849
(D) 17600
(E) 21349
Rationale: D
Price at which the TV set is bought = Rs. 12,500
Discount offered = 20%
Marked Price = 12500 * 100/80 = Rs. 15625
The total amount spent on transport and installation = 125 + 250 = Rs. 375\Total price of TV set = 15625 + 375 = Rs. 16000
The price at which the TV should be sold to get a profit of 10% if no discount was offered = 16000 * 110/100 = Rs. 17600
Answer: (D) 17600
Question: The edges of a cuboid are respectively 3cm, 4cm and 12 cm. Find the length of the diagonal of cuboid.
(A) 9: 8
(B) 9: 5
(C) 9: 1
(D) 9: 2
(E) 9: 4
Rationale: a1 : a2 = 3 : 1
6 a12 : 6 a22 = 9: 1
Answer:C
Answer: (C) 9: 1
Question: When x is divided by y, the quotient is z with remainder r. Which of the following is equal to r?
(A) yz – x
(B) y/x−z
(C) x – y – z
(D) x – yz
(E) zx – y
Rationale: (x/y)=z(+r)
(18/8)=2(+2)
x-yz
which is 18-(8*2)=2
Answer is D
Answer: (D) x – yz
Question: A miniature gumball machine contains 4 blue, 3 green, and 2 red gumballs, which are identical except for their colors. If the machine dispenses three gumballs at random, what is the probability that it dispenses one gumball of each color?
(A) 2/7
(B) 3/7
(C) 3/14
(D) 5/24
(E) 7/24
Rationale: The total number of ways to dispense 3 gumballs is 9C3=84.
The number of ways to choose one of each color is 4*3*2=24.
P(dispensing one of each color)=24/84=2/7.
The answer is A.
Answer: (A) 2/7
Question: In a History examination, the average for the entire class was 80 marks. If 10% of the students scored 35 marks and 20% scored 90 marks, what was the average marks of the remaining students of the class ?
(A) 22
(B) 27
(C) 75
(D) 29
(E) 271
Rationale: Explanation:
Let the number of students in the class be 100 and let this required average be x.
Then, (10 * 95) + (20 * 90) + (70 * x) = (100 * 80)
=> 70x = 8000 - (950 + 1800) = 5250
=> x = 75.
Answer: C) 75
Answer: (C) 75
Question: In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many
men will be catered to with the remaining meal ?
(A) 38 men
(B) 32 men
(C) 34 men
(D) 30 men
(E) None of these
Rationale: Explanation:
There is meal for 200 children. 150 children have taken the meal.
Remaining meal is to be catered to 50 children.
Now, 200 children = 120 men
So, 50 Children = 120/200 * 50 = 30 men
Answer: D
Answer: (D) 30 men
Question: A car is purchased on hire-purchase. The cash price is $25 000 and the terms are a deposit of 10% of the price, then the balance to be paid off over 60 equal monthly installments. Interest is charged at 12% p.a. What is the monthly installment?
(A) $500
(B) $504
(C) $505
(D) $560
(E) $600
Rationale: Explanation:
Cash price = $25 000
Deposit = 10% Ã— $25 000 = $2500
Loan amount = $25000 âˆ’ $2500
Number of payments = 60
= $22500
I=p*r*t/100
I=13500
Total amount = 22500 + 13500 = $36000
Regular payment = total amount /number of payments =600
Answer: E
Answer: (E) $600
Question: The ratio between the presents of the A and B is 6:7. If B is 4 years older than A, what will be the ratio of the ages of A and B after 4 years?
(A) 1:2
(B) 9:11
(C) 7:8
(D) 6:7
(E) 3:4
Rationale: Let A and B ages will be 6x and 7x
7x - 6x = 4
x = 4
Required ratio = 6x+4 : 7x+4 = 28:32 = 7:8
Answer is C
Answer: (C) 7:8
Question: The salary of A, B, C, D, E is Rs. 10000, Rs. 5000, Rs. 11000, Rs. 7000, Rs. 9000 per month respectively, then the average salary of A, B, C, D, and E per month is
(A) Rs. 7000
(B) Rs. 8400
(C) Rs. 8500
(D) Rs. 9000
(E) None
Rationale: Answer
Average salary
= 10000 + 5000 + 11000 + 7000 + 9000 / 5
= Rs. 8400
Correct Option: B
Answer: (B) Rs. 8400
Question: The triplicate ratio of 1:8 is?
(A) 1:0
(B) 1:8
(C) 1:7
(D) 1:512
(E) 1:1
Rationale: 13: 83 = 1:512
Answer: D
Answer: (D) 1:512
Question: The length of the bridge, which a train 110 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
(A) 328
(B) 279
(C) 265
(D) 288
(E) 211
Rationale: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (110 + X)/30 = 25/2 ==> 2(110 + X) = 750 ==> X = 265 m.Answer: C
Answer: (C) 265
Question: A man and a boy complete a work together in 24 days. If for the last 6 days man alone does the work then it is completed in 26 days. How long the boy will take to complete the work alone?
(A) days
(B) days
(C) days
(D) days
(E) days
Rationale: Explanation:
(man + boy)’s 1 day’s work = 1/24
Their 20 day’s work = 1/24 × 20 = 5/6
The remaining 1/6 work is done by the man in 6days
Therefore, the man alone will finish the work in 6 × 6 days = 36 days
Man’s 1 day’s work = 1/36
Therefore, boy’s 1 day’s work = 1/24 – 1/36 = 3 – 2 /72 = 1/72
Therefore, the Boy alone will finish the work in 72 days.
Answer: Option A
Answer: (A) days
Question: Pinky bought six Chocolate at an average price (arithmetic mean) of 5¢. If Pinky returned four chocolate to the retailer, and the average price of the remaining chocolate was 2¢, then what is the average price, in cents, of the four returned chocolates?
(A) 6.5
(B) 5.5
(C) 4.5
(D) 5
(E) 6.4
Rationale: Total price of 6 chocolates=6*5=30
Total price of 2 chocolates=2*2=4
Total price of 4 returned chocolates=30-4=26
Average price of 4 returned chocolate=26/4=6.5
Correct option Answer:A
Answer: (A) 6.5
Question: John makes $30 a week from his job. He earns a raise andnow makes $40 a week. What is the % increase?
(A) 16%
(B) 33.33%
(C) 33.69%
(D) 33.98%
(E) 37%
Rationale: Increase = (10/30)*100 = (1/3)*100 = 33.33%.
B
Answer: (B) 33.33%
Question: The avearage age of boys in a class is 16 years and that of the girls is 15 years. The average age for the whole class is
(A) 15 years
(B) 15.5 years
(C) 16 years
(D) Cannot be computed
(E) None of these
Rationale: Solution
Clearly, to find the average,we ought to know the numbers of boys , girls or students in the class, neither of which has been given.
so the data provided is inadequate.
Answer D
Answer: (D) Cannot be computed
Question: Shipment --- No. of Defective Chips/shipment --- Total Chips in shipment
S1 ---------------------- 5 ------------------------------------------ 5,000
S2 ---------------------- 5 ------------------- ---------------------- 12,000
S3 ---------------------- 8 ------------------------------------------ 17,000
S4 ---------------------- 7 ------------------------------------------ 16,000
A computer chip manufacturer expects the ratio of the number of defective chips to the total number of chips in all future shipments to equal the corresponding ratio for shipments S1, S2, S3, and S4 combined, as shown in the table above. What’s the expected number of defective chips in a shipment of 60,000 chips?
(A) 14
(B) 20
(C) 22
(D) 30
(E) 25
Rationale: for a total of 51000 chips (adding S1,S2,S3,S4) total number of defective chips is 17 ((adding defective chips of S1,S2,S3,S4) so ratio is 25/50000 or 1 every 2000 chips.
Keeping this ratio constant for 60000 chips number of defective chips will be (1/2000) * 60000 = 30
D
Answer: (D) 30
Question: A classroom has equal number of boys and girls. NINE girls left to play kho-kho, leaving twice as many boys as girls in the classroom. What was the total number of girls and boys present initially?
(A) 36
(B) 24
(C) 32
(D) 48
(E) 54
Rationale: after 9 girls left remaining 9 girls
now boys 18 are twice as many as remaining girls.
initially boys=18 and girls=18.
ANSWER:A
Answer: (A) 36
Question: A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
(A) 31.11 km/hr
(B) 35.55 km/hr
(C) 71.11 km/hr
(D) 36 km/hr
(E) 71 km/hr
Rationale: Total time taken = 160/64 + 160/80 = 9/2 hours
--> Average speed = 320 x 2/9 = 71.11 km/hr.
Answer : C.
Answer: (C) 71.11 km/hr