mathewhe/aqua_rat huggingface dataset:
Question: A man sells a car to his friend at 13% loss. If the friend sells it for Rs.54000 and gains 20%, the original C.P.of the car was :
(A) Rs.21724.14
(B) Rs.31724.14
(C) Rs.51724.14
(D) Rs.61724.14
(E) None of these
Rationale: Explanation:
S.P = Rs.54,000. Gain earned = 20%
C.P = Rs.[100/120Ã—54000]
=Rs. 45000
This is the price the first person sold to the second at at loss of 13%.
Now S.P = Rs.45000 and loss = 13%
C.P. Rs.[100/87Ã—45000]= Rs.51724.14.
Correct Option : C
Answer: (C) Rs.51724.14
Question: Three people each took 6 tests. If the ranges of their scores in the 6 practice tests were 17, 28 and 35, 42 what is the minimum possible range in scores of the three test-takers?
(A) a 17
(B) b) 28
(C) c) 35
(D) d) 45
(E) e) 80
Rationale: It is finding the minimum range between all their scores, if all test taker scores are between 0 and maximum range we will have:
A- 0 and 17
B- 0 and 28
C- 0 and 35
D-0 and 42
therefore the minimum range is 42, it cant be any lower however you play with the numbers.
D
Answer: (D) d) 45
Question: A room 5.44m long and 3.74m broad is to be paved with square tiles. The least number of square tiles required to cover the floor is:
(A) 176
(B) 192
(C) 184
(D) 162
(E) 172
Rationale: Area of the room= 544*374 sq.cm
Size of largest square tile= HCF of 544 cm & 374cm
Area of 1 tile= 34*34 sq.cm
Therefore, number of tiles= (544*374/34*34)= 176
ANSWER:A
Answer: (A) 176
Question: A textile manufacturing firm employees 125 looms. It makes fabrics for a branded company. The aggregate sales value of the output of the 125 looms is Rs 5,00,000 and the monthly manufacturing expenses is Rs 1,50,000. Assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms. Monthly establishment charges are Rs 75000. If one loom breaks down and remains idle for one month, the decrease in profit is:
(A) 13000
(B) 7000
(C) 10000
(D) 2800
(E) None of these
Rationale: Explanation :
Profit = 5,00,000âˆ’(1,50,000+75,000) =Rs. 2,75,000.
Since, such loom contributes equally to sales and manufacturing expenses.
But the monthly charges are fixed at Rs 75,000.
If one loan breaks down sales and expenses will decrease.
New profit :-
=>500000Ã—(124/125)âˆ’150000Ã—(124/125)âˆ’75000.
=>Rs 2,72,200.
Decrease in profit
=>2,75,000âˆ’2,72,200
=>Rs. 2,800.
Answer : D
Answer: (D) 2800
Question: P, Q and R started a business by investing Rs.120000, Rs.135000 and Rs.150000 respectively. Find the share of each, out of the annual profit of Rs.56700.
(A) 17850, 18900, 21000
(B) 16800, 18900, 21000
(C) 17850, 18900, 22000
(D) 18900, 17850, 21000
(E) 21000, 18900, 17850
Rationale: P : Q : R = 120000:135000:150000
=120:135:150=24:27:30=8:9:10
Share of P
=56700×8/27=2100×8=16800
Share of Q
=56700×9/27=2100×9=18900
Share of R
=56700×10/27=2100×10=21000
Answer is B.
Answer: (B) 16800, 18900, 21000
Question: In a class of 40 students, 5 students did not borrow any books from the library, 15 students each borrowed 1 book, 10 students each borrowed 2 books, and the rest of the students each borrowed at least 3 books. If the average (arithmetic mean) number of books borrowed per student was 2, what is the maximum number of books that any single student could have borrowed ?
(A) 3
(B) 5
(C) 8
(D) 13
(E) 18
Rationale: The average number of books per student was 2means that total of 2*40=80 books were borrowed;
5+15+10=30 students borrowed total of 5*0+15*1+10*2=35 books;
So 80-35=45 books are left to distribute among 40-30=10 students, these 10 arethe rest who borrowed at least 3 books;
Tomaximizethe number of books one student from above 10 could have borrowed we shouldminimizethe number of books other 9 students from 10 could have borrowed. Minimum these 9 students could have borrowed is 3 books per student, so total number of books they could have borrowed is 9*3=27 books. So the 10th student could have borrowed is 45-27=18 books.
Answer: E.
Answer: (E) 18
Question: What least number must be subtracted from 427398 so that remaining no.is divisible by 14
(A) 3
(B) 5
(C) 6
(D) 7
(E) 8
Rationale: Explanation:
On dividing 427398 by 14 we get the remainder 6, so 6 should be subtracted
Answer: Option C
Answer: (C) 6
Question: If the perimeter of a rectangular stadium is 800 m, its length when its breadth is 300 m is?
(A) 500
(B) 400
(C) 300
(D) 200
(E) 100
Rationale: 2(l + 300) = 800 => l = 100 m Answer: E
Answer: (E) 100
Question: The average of 10 numbers is calculated as 15. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is?
(A) 28
(B) 27
(C) 16
(D) 29
(E) 24
Rationale: 10 * 15 + 36 – 26
= 160/10
= 16
Answer:C
Answer: (C) 16
Question: The areas, in kilometers squared, of some countries are given below. USA: 9,629,091, Russia: 18,098,242, China: 9,598,094, Canada: 9,984,670, the UK: 242,400 and India: 3,287,263.
What is the difference between the areas of Russia and China?
(A) 5,476,811 kilometers squared
(B) 8,500,148 kilometers squared
(C) 9,843,123 kilometers squared
(D) 1,878,965 kilometers squared
(E) 4,787,900 kilometers squared
Rationale: he difference between the areas of Russia and China is given by
18,098,242 - 9,598,094 = 8,500,148 kilometers squared
correct answer B
Answer: (B) 8,500,148 kilometers squared
Question: On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?
(A) 5
(B) 50
(C) 10^5
(D) 5^10
(E) 8^10 - 3^10
Rationale: For n=3, consider the intensity to be x.
For n+1 = 4 , we have [intensity*10 ]= 10x
For n+2 = 5 , we have [10x*10 ]= 100x
For n+3 = 6 , we have [100x*10 ]= 1000x
For n+4 = 7 , we have [1000x*10 ]= 10000x
For n+5 = 8 , we have [10000x*10 ]= 100000x
Now , for n = 8 -->100000x = 10^5 x
which is 10^5 times x, the original intensity at n=3
ANSWER:C
Answer: (C) 10^5
Question: If it takes a tub 4 minutes to drain 5/7 of its content, how much more time will it take for the tub to be empty?
(A) 48 seconds
(B) 1 minute, 12 seconds
(C) 1 minute, 36 seconds
(D) 2 minutes, 14 seconds
(E) 4 minutes, 12 seconds
Rationale: If 5/7 of tub's content is drained 2/7 th of tub still needs to be drained.
If it takes 4 minutes to drain 5/7 th of tub it takes 4*(7/5) minutes to drain the entire tub and 4*(7/5)*(2/7) min to drain 2/7 th of the tub which is 8/5 minutes or 1 3/5 minutes or 1 minute 36 seconds
So answer is C
Answer: (C) 1 minute, 36 seconds
Question: if none of the figures 2,4,5,7,8,0 be repeated,how many different numbers of 4 digits can be formed wiyh them.?
(A) 150
(B) 200
(C) 250
(D) 300
(E) 350
Rationale: here 1st place can be filled by five ways(i.e any one from 2,4,5,7,8),and second place will be again in 5 ways (remaining from 6 digits ,6-1=5) and next place in 4 ways ,and again in 3 ways so ans will be 5*5*4*3=300
ANSWER:D
Answer: (D) 300
Question: Find the least multiple of 23,which when divided by 18,21 and 24 leaves remainders 7,10 and 13 respectively.
(A) 3002
(B) 3013
(C) 3024
(D) 3036
(E) None of these
Rationale: Solution
Here (18 - 7) = 11, (21 - 10) = 11 and (24 - 13) = 11. L.C.M. of 18,21 and 24 is 504.
Let required number be 504 k - 11.
Least value of k for which (504 k - 11 ) is divisible 23 is k = 6.
So, Required number = 504 × 6 - 11 =3024 - 11 = 3013.
Answer B
Answer: (B) 3013
Question: In how many ways can the letters of the word AGENDA be rearranged such that the vowels always appear together?
(A) 6!/2!
(B) 3!*3!
(C) 4!/2!
(D) (4! *3!)/2!
(E) 3!*3!/2
Rationale: In the word ABACUS , there are 3 vowels - 2 A's and E
Number of ways the letters of word AGENDA be rearranged such that the vowels always appear together
= (4! * 3! )/2!
We can consider the the 3 vowels as a single unit and there are 3 ways to arrange them . But since 2 elements of vowel group are identical we divide by 2! .
The entire vowel group is considered as a single group .
Answer D
Answer: (D) (4! *3!)/2!
Question: At a kennel with 80 dogs, 45 of the dogs wear tags and 40 wear flea collars. If 6 of the dogs wear both, then how many of the dogs wear neither a collar nor tags?
(A) 1
(B) 6
(C) 34
(D) 79
(E) 85
Rationale: Dogs wear neither a collar nor tags = 80 - ( 45 + 40 - 6 )
Dogs wear neither a collar nor tags = 80 - 79
Dogs wear neither a collar nor tags = 80 - 79
Hence, answer will be 1
ANSWER:A
Answer: (A) 1
Question: The difference between a two-digit number and the number after interchanging the position of the two digits is 36. What is the difference between the two digits of the number?
(A) 4
(B) 6
(C) 3
(D) Cannot be determined
(E) None of these
Rationale: Let the two-digit no. be l0x + y.
Then, (10x + y) – (10y + x) = 36
or, 9(x – y) = 36
or, x – y = 4
Answer A
Answer: (A) 4
Question: 3 litre of water is added to 11 litre of a solution containing 42% of alcohol in the water. The percentage of alcohol in the new mixture is?
(A) 30%
(B) 33%
(C) 35%
(D) 40%
(E) 45%
Rationale: We have a 11 litre solution containing 42% of alcohol in the water.
=> Quantity of alcohol in the solution
=
11
×
42
100
=11×42100
Now 3 litre of water is added to the solution.
=> Total quantity of the new solution = 11 + 3 = 14
Percentage of alcohol in the new solution
=
11
×
42
100
14
×
100
=11×4210014×100
=
11
×
3
100
=
33%
B)
Answer: (B) 33%
Question: The population of a town is 10000. It increases annually at the rate of 27% p.a. What will be its population after 2 years?
(A) 14000
(B) 14400
(C) 16129
(D) 14600
(E) 14700
Rationale: Formula :
10000 × 127/100 × 127/100 = 16129
Answer : C
Answer: (C) 16129
Question: Find the no of ways in which 6 toffees can be distributed over 5 different people namely A,B,C,D,E.
(A) 210
(B) 211
(C) 212
(D) 213
(E) 214
Rationale: acc to formula (n+r-1)C (r-1) = (6+5-1)C(5-1)
=10C4 = 210
ANSWER:A
Answer: (A) 210
Question: The price of a bushel of corn is currently $3.20, and the price of a peck of wheat is $6.80. The price of corn is increasing at a constant rate of 5x cents per day while the price of wheat is decreasing at a constant rate of x(2^1/2) - x cents per day. What is the approximate price when a bushel of corn costs the same amount as a peck of wheat?
(A) $4.50
(B) $5.10
(C) $5.30
(D) $5.50
(E) $6.50
Rationale: I Tried using Time/Rate approach:-
Initial Price Difference = 6.80 - 3.20 = 3.60
Price of Corn increasing by 5x
Price of Wheat decreasing by x(1.4)-x = .4x
Since both the quantities are moving towards reducing the Price Gap hence:-
Relative Increase = 5x +.4x
Let T be the Time by which GAP is filled so,
3.6 = T(5.4x) -> T= (3.6)/5.4X
Final Price = 3.20 + 5X * T -> 3.20 + 5*3.6/5.4 = 6.5
Answer E.
Answer: (E) $6.50
Question: The three competitors in a race have to be randomly chosen from a group of four men and three women. How many different such trios contain at least one woman?
(A) 10
(B) 15
(C) 16
(D) 31
(E) 46
Rationale: The total number of ways to choose three runners 7C3 = 35
The number of trios with only males is 4C3 = 4
The number of trios which include at least one woman is 31.
The answer is D.
Answer: (D) 31
Question: Four percent of the programmers in a startup company weigh 200 pounds or more. Twenty-five percent of the programmers that are under 200 pounds in that same company weigh 100 pounds or less. What percent of the programmers in the startup company weigh between 100 and 200 pounds?
(A) 15%
(B) 20%
(C) 25%
(D) 60%
(E) 72%
Rationale: Initially 96% and 4% split
80% is further divided as 25% and 75%
Q is asking about that 75%
let total be '100' then that 75% is (3/4)∗96
so, the required % is [(3/4)∗96/100]∗100 = 72%
ANSWER:E
Answer: (E) 72%
Question: There are three guys who have equal number of bullets. All of them shoot 12 bullets. The remaining bullets are equal to the total number of bullets remaining is equal to the bullets each had after division. What was the original number of bullets each one had?
(A) 18
(B) 19
(C) 30
(D) 45
(E) 54
Rationale: let initially each was having x bullets
they shot 12 bullets
so 3x-36=x
x=18
so each was having 18 bullets.
total was 54.
ANSWER:E
Answer: (E) 54
Question: What is the sum of all four digit integers formed using the digits 3 ,4 ,5 and 6 (repetition is allowed)
(A) 1279874
(B) 1279872
(C) 1279875
(D) 1279876
(E) 1279870
Rationale: n = 4 * 4 * 4 * 4 = 256
<x> = (6666 + 3333) / 2 = 4999.5
Sum = number of integers x average value
n * <x> = 256 * 4999.5 = 1279872
answer = B
Answer: (B) 1279872
Question: Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?
(A) 015
(B) 28
(C) 17
(D) 19
(E) 11
Rationale: Explanation:
x + y = 80
x â€“ 4y = 5
x = 65 y = 15
Answer:A
Answer: (A) 015
Question: Y invested $1000 in a business and Z invested $3000 in a business. At the end of the year they got $4000 as the profit. Find their share?
(A) $1000,$2000
(B) $2000,$3000
(C) $1000,$3000
(D) $2000,$3000
(E) $3000,$4000
Rationale: Y:Z = 1000:3000
Y:Z = 1:3
Y's share = 4000*1/4 = $1000
Z's share = 4000*3/4 = $3000
Answer is C
Answer: (C) $1000,$3000
Question: If the price of petrol increases by 25% and Bill intends to spend only an additional 15% on petrol, by how much % will he reduce the quantity of petrol purchased?
(A) A)8%
(B) B)7%
(C) C)10%
(D) D)6%
(E) E)9%
Rationale: Explanation:
Assume that the initial price of 1 Litre petrol = Rs.100 ,Bill spends Rs.100 for petrol,
such that Bill buys 1 litre of petrol
After the increase by 25%, price of 1 Litre petrol = 100 × (100+25)/100 = Rs.125
Since Bill spends additional 15% on petrol,
amount spent by Bill = 100× (100+15)/100 = Rs.115
Hence Quantity of petrol that he can purchase = 115/125 Litre
Quantity of petrol reduced = (1−115/125) Litre
Percentage Quantity of reduction = (1−115125)/1 × 100 = 10/125 × 100 = 105 × 4 = 2 × 4 = 8%
Answer: Option A
Answer: (A) A)8%
Question: A person invested in all Rs. 2600 at 4%, 6% and 8% per annum simple interest. At the end of the year, he got the same interest in all the three cases. The money invested at 4% is?
(A) 1266
(B) 2887
(C) 2668
(D) 1200
(E) 1765
Rationale: Let the parts be x, y and [2600 - (x + y)].
Then,
(x * 4 * 1)/100 = (y * 6 * 1)/100 = {[2600 - (x + y)] * 8 * 1}/100
y/x = 4/6 = 2/3 or y = 2/3 x
So, (x * 4 * 1)/100 = [(2600 - 5/3 x) * 80/100
52x = (7800 * 8) => x = 1200
Money invested at 4% = Rs. 1200.
Answer:D
Answer: (D) 1200
Question: What is the difference between the place value of 2 in the numeral 7889?
(A) 160
(B) 165
(C) 180
(D) 190
(E) 720
Rationale: Answer: Option 'E'
800 - 80 = 720
Answer: (E) 720
Question: If two balls are randomly selected from a green urn containing 7 black and 7 white balls and placed into a yellow urn initially containing 5 black and 3 white balls. What is the probability that the yellow urn will contain an equal number of black and white balls after the change?
(A) A.2/9
(B) B.4/9
(C) C.3/13
(D) D.1/3
(E) E.1/9
Rationale: To have equal number of black and white balls, the yellow urn must have 5 black and 5 white balls. So the balls we select out of the green urn must be both white.
Probability (first ball is white) = 7/14
Probability(second ball is white) = 6/13
Probability (both balls are white) = (7/14)*(6/13) = 3/13
Answer C
Answer: (C) C.3/13
Question: What is the probability of rolling a total of 4 with a single roll of two fair six-sided dice, each with the distinct numbers 1 through 6 on each side?
(A) 1/12
(B) 1/6
(C) 2/7
(D) 1/3
(E) 1/2
Rationale: Totalsample spacefrom two fair six-sided dice is 36.
There are six possible ways to be 7 i.e. (1+3), (2+2), (3+1)
So, total probability is 3/36 or 1/12.
Answer is A.
Answer: (A) 1/12
Question: The age of man is three times the sum of the ages of his two sons. Six years hence,his age will be double of the sum of the ages of his sons.The fatherâ€™s present age is :
(A) 40 years
(B) 45 years
(C) 50 years
(D) 54 years
(E) 75 years
Rationale: Solution
Let the sum of present ages of the two sons be x years.
Then,father's present age = 3x years.
âˆ´ (3x + 6)=2 (x +12) â‡” 3x + 6 = 2x + 24â‡” x =18.
Hence,father's present age = 54 years. Answer D
Answer: (D) 54 years
Question: The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 14000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is
(A) 20
(B) 21
(C) 22
(D) 28
(E) NONE
Rationale: Sol.
Let the total number of workers be x. Then,
8000x = (14000 × 7) + 6000 ( x – 7)
‹=› 2000x = 56000
‹=› x = 28.
Answer D
Answer: (D) 28
Question: A gang of 8 boys goes on an tour in 2 cars, of which 1 canseat 5 & the other only 4. In how many ways can they travel?
(A) 110
(B) 130
(C) 126
(D) 135
(E) 156
Rationale: There are 8 students and the maximum capacity of the cars together is 9.
We may divide the 8 students as follows
Case I: 5 students in the first car and 3 in the second
Or Case II: 4 students in the first car and 4 in the second
Hence, in Case I: 8 students are divided into groups of 5 and 3 in8C3 ways.
Similarly, in Case II: 8 students are divided into two groups of 4 and 4 in 8C4ways.
Therefore, the total number of ways in which 8 students can travel is:
\inline {\color{Blue}8C_{3}+8C_{4}}=56 + 70= 126
C
Answer: (C) 126
Question: A sum of money at simple interest amounts to 815 in 3 years and to 854 in 4 years. The sum is:
(A) 698
(B) 387
(C) 373
(D) 593
(E) 372
Rationale: A
698
S.I. for 1 year = (854 - 815) = 39.
S.I. for 3 years = (39 x 3) = 117.
Principal = (815 - 117) = 698.
Answer: (A) 698
Question: What is the are of an equilateral triangle of side 16 cm?
(A) 64√3
(B) 64√7
(C) 64√5
(D) 64√3
(E) 64√1
Rationale: Area of an equilateral triangle = √3/4 S2
If S = 16, Area of triangle = √3/4 * 16 * 16
= 64√3 cm2;
Answer:D
Answer: (D) 64√3
Question: In a certain school, the ratio of boys to girls is 5 to 13. If there are 80 more girls than boys, how many boys are there?
(A) 27
(B) 36
(C) 45
(D) 50
(E) 117
Rationale: The ratio of b to G is 5:13 and the other data point is G are more than boys by 80...
Looking at the ratio we can say that the 8(13-5) extra parts caused this diff of 80. so 1 part corresponds to 80/8=10 and so
5 parts correspond to 5*10 = 50.
D
Answer: (D) 50
Question: A committee has 5 men and 6 women. What are the number of ways of selecting a group of eight persons?
(A) 165 ways
(B) 196 ways
(C) 156 ways
(D) 186 ways
(E) 618 ways
Rationale: Total number of persons in the committee
= 5 + 6 = 11
Number of ways of selecting group of eight persons
= ¹¹C₈ = ¹¹C₃
= (11 * 10 * 9)/(3 * 2)
= 165 ways.
Answer:A
Answer: (A) 165 ways
Question: Find the unit's digit in the product 2467 153 * 34172?
(A) 1
(B) 2
(C) 3
(D) 6
(E) 7
Rationale: Unit's digit in the given product=Unit's digit in 7 153 * 172
Now 7 4 gives unit digit 1
7 152 gives unit digit 1
7 153 gives 1*7=7.Also 172 gives 1
Hence unit's digit in the product =7*1=7.
ANSWER E
Answer: (E) 7
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. In how much time will the trains cross each other?
(A) 100/7 sec
(B) 80/7 sec
(C) 57/7 sec
(D) 120/7 sec
(E) 50/7 sec
Rationale: Relative speed = (54 + 72)* 5/18 = 7 * 5 = 35 mps.
The time required = d/s = (100 + 100 + 300)/35
= 500/35 = 100/7 sec.
ANSWER:A
Answer: (A) 100/7 sec
Question: There is a point P on the circle. A and B started running in two constant different speeds. A in Clockwise and B in Anti-clockwise. First time 500 m in Clockwise from P then 400 Anti-clockwise. If B is yet to complete one round, What is the circumference of the circle?
(A) 700
(B) 800
(C) 900
(D) 1000
(E) 1100
Rationale: Let the speeds of A & B be u and v resp. and let circumference be C.
Let their first meeting be after time t then ut+vt = C and ut = 500
∴ vt = C−500 and u/v = 500/(C−500)
For their second meeting after time T, uT+vT = 2C and vT = 400
∴ uT = 2C−400 and u/v = (2C−400 )/400
Hence 500/(C−500) = (2C−400) /400
Simplifying, 100000 = (C−200)(C−500) = C²−700C+100000 → C=700
ANSWER:A
Answer: (A) 700
Question: It is required to seat 3 boys and 2 girls in a row so that the girls occupy the even places. How many such arrangements are possible?
(A) 2880
(B) 2148
(C) 3680
(D) 3280
(E) 96
Rationale: Total number of candidates = 3 + 2 = 5. In the row of 5 positions, the even places are 2nd, 4th.
Now, number of even places = 2.
Number of girls to occupy the even places = 2.
Even places can be filled = P (2, 2) ways.
Number of boys = 3.
The remaining 3 places can be filled by 3 boys = P (3, 3) ways
By the fundamental principle of counting:
The required number of seating arrangements
P(2, 2) x P(3, 3) = 2! x 4! = 4 x 24 = 96
ANSWER:E
Answer: (E) 96
Question: What is the smallest integer z for which 27^z> 3^24?
(A) 7
(B) 8
(C) 9
(D) 10
(E) 12
Rationale: 27^z> 3^24
Converting into the same bases:
27^z> 27^8
Therefore for the equation to hold true, z> 8 or z= 9
Option C
Answer: (C) 9
Question: Its festive time and all big companies are offering the big discount especially on iPhone whose price is staggering Rs. 65,000.
Following is the offer from the three major companies in India.
: Amazon offers Flat 65% discount
: Flipkart offers 10% discount over and over again.
: Snapdeal offers RS 42,000 off.
Which is the best offer for you ?
(A) Flipkart
(B) Amazon
(C) Snapdeal
(D) All
(E) None of Above
Rationale: A
Explanation:
Flipkart : 22664, Amazon: 22750 and Snapdeal: 23000
SnapDeal discount :
65000 - 42000 = 23000
Amazon 65% discount :
35/100 * 65000 = 22750
Flipkart 10% recursive discount:
After 1st 10% discount, Amount is 58500
After 2nd 10% discount, Amount is 52650
After 3rd 10% discount, Amount is 47385
After 4th 10% discount, Amount is 42646.5
After 5th 10% discount, Amount is 38381.85
After 6th 10% discount, Amount is 34543.665
After 7th 10% discount, Amount is 31089.2985
After 8th 10% discount, Amount is 27980.36865
After 9th 10% discount, Amount is 25182.331785
After 10th 10% discount, Amount is 22664.0986065
Answer: (A) Flipkart
Question: 300 first-time customers of a fashion store were surveyed for their shopping experience right after leaving the store. 60% of the customers in the survey had purchased clothes for less than $100. 40% of the customers in the survey reported they were overall satisfied with their purchase. 45% of the customers that had purchased clothes for less than $100 reported they were overall satisfied with their purchase. What percent of the customers surveyed purchased clothes for at least $100 and reported that they were NOT overall satisfied with their purchase?
(A) 15
(B) 25
(C) 13
(D) 45
(E) 75
Rationale: Out of 300 - 180 purchased for less than 100$120 for more
Out of 300 - 120 responded as satisfied and 180 responded disatisfied
Out of 180 ( Purchased less than 100$) - 45% = 81 responded as satisfied, So remaining Satisfied are 120 - 81 = 39
so 39 is what percentage of 300 - 13%
So the answer should be C
Answer: (C) 13
Question: A retailer set the tag price of an item at $200. On a certain public holiday, the retailer set a 20% discount on the tag price, thinking that he will still make a profit equal to 25% of the price he had originally paid for the item. How much did the retailer originally pay for the item?
(A) $96
(B) $120
(C) $128
(D) $144
(E) $160
Rationale: Price Tagged : $200
Price after discount = $160 = Original Price + 25% Extra
Original Price = x
So, 1.25 x = 160
or x = 128. Hence, C
Answer: (C) $128
Question: Find the compound interest on $1000 in 2years at 4% per annum, the interest being compounded half-yearly?
(A) $645.56
(B) $82.43
(C) $954.26
(D) $745.69
(E) $1020.45
Rationale: Principle = $10000
Rate = 2% half yearly = 4 half years
Amount = 1000*(1 + 2/100)^4 = 1000 * 51/50 * 51/50 * 51/50 * 51/50
= $1082.43
C.I. = 1082.43-1000 = $82.43
Answer is B
Answer: (B) $82.43
Question: The average weight of 8 girls increases by 3 kg when a new girl comes in place of one of them weighing 70 kg. What might be the weight of the new girl?
(A) 94 kg
(B) 95 kg
(C) 96 kg
(D) 97 kg
(E) 98 kg
Rationale: Total weight increased = 8 x 3 kg = 24 kg.
Weight of new person = 70 + 24 kg = 94 kg
Answer : A
Answer: (A) 94 kg