mathewhe/aqua_rat huggingface dataset:
Question: The difference between a two-digit number and the number after interchanging the position of the two digits is 63. What is the difference between the two digits of the number?
(A) 4
(B) 7
(C) 3
(D) Cannot be determined
(E) None of these
Rationale: Let the two-digit no. be l0x + y.
Then, (10x + y) â€“ (10y + x) = 63
or, 9(x â€“ y) = 63
or, x â€“ y = 7
Answer B
Answer: (B) 7
Question: A tree on first day grows 1/2 of its size second day 1/3 of its size on the previous day similarly than 1/4 and so on..U have calculate after how many days the tree will be 100 times of original size.
(A) 188 days
(B) 198 days
(C) 178 days
(D) 168 days
(E) 158 days
Rationale: suppose 'x' is initial size and 'n' is no. of days.
1st day increment in size of tree = (1/2)x
After 1st day , size of tree = x+(1/2)x= (3/2)x
2nd day increment in size of tree = (1/3)*(3/2)x=(1/2)x
After 2nd day , size of tree = (3/2)x+(1/2)x=2x
3rd day increment in size of tree =(1/4)*2x=(1/2)x
After 3rd day , size of tree = 2x+(1/2)=(5/2)x
It is clear that every day tree grows (1/2)x in size.
therefore , according to given condition
x+ (1/2)x*n=100x
n=198 days.
ANSWER:B
Answer: (B) 198 days
Question: A committee of 5 is to be selected from among 5 boys and 5 girls. I how many ways can this be done if the committee is to consist of at-least one Girl?
what is the answer choice and how?
(A) 105
(B) 250
(C) 230
(D) 350
(E) 455
Rationale: I'm sure there is some problem with the question.
R U sure its atleast one boy and not atleast 1 boy and 1 girl?
if its 1 boy and 1 girl
5C1*5C4 + 5C2*5C3 + 5C3*5C2 + 5C4*5C1
5*5 + 10*10 + 10*10 + 5*5
25 + 100 + 100 + 25
250
B
Answer: (B) 250
Question: Length of a rectangular plot is 20 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
(A) 50 m
(B) 60 m
(C) 70 m
(D) 80 m
(E) 90 m
Rationale: Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m
B
Answer: (B) 60 m
Question: The number of arrangements that can be made with the letters of the word LUCK so that the vowels occupy the even places?
(A) 5
(B) 3
(C) 6
(D) 1
(E) 2
Rationale: The word MEADOWS has 7 letters of which 3 are vowels.
-V-V-V-
As the vowels have to occupy even places, they can be arranged in the 1 even places in 1! i.e., 1 ways. While the consonants can be arranged among themselves in the remaining 3 places in 3! i.e., 6 ways.
Hence the total ways are 1 * 6 = 6.
Answer:C
Answer: (C) 6
Question: A boatman can row 3 km against the stream in 36 minutes and return in 18 minutes. Find the rate of current ?
(A) 7/2 kmph
(B) 2.5 kmph
(C) 5/2 kmph
(D) 1/2 kmph
(E) 2/2 kmph
Rationale: Explanation:
Speed in upstream = Distance / Time = 3 x 60/36 = 5 km/hr.
Speed in downstream = 3 x 60/18 = 10 km/hr
Rate of current = (10-5)/2 = 2.5 km/hr.
Answer: B
Answer: (B) 2.5 kmph
Question: A space shuttle orbits the earth at about 4 kilometers per second. This speed is equal to how many kilometers per hour?
(A)  480
(B)  14,400
(C)  24,200
(D)  28,800
(E)  48,000
Rationale: Seconds in 1 hours:
60s in 1 min
60 min in 1 hr
60*60=3600 sec in 1 hr
4*3600=14,400
Answer: B
Answer: (B)  14,400
Question: Due to 10% decrease in the price of sugar and John can buy 5kg more sugar in Rs100 , then find the CP of sugar?
(A) Rs. 1(1/9)
(B) Rs. 2(2/9)
(C) Rs. 2(1/9)
(D) Rs. 2(2/7)
(E) Rs. 2(2/5)
Rationale: Here r = 10 % ,x = 100 and A = 5 kg
Actual price of sugar = 10*100/((100-10 )*5) = Rs. 2(2/9)
B
Answer: (B) Rs. 2(2/9)
Question: There are 16 bees in the hive , then 5 more fly. How many bees are there in all?
(A) 20
(B) 33
(C) 12
(D) 17
(E) 25
Rationale: 16+5=20 . Answer is A.
Answer: (A) 20
Question: Find the area of the quadrilateral of one of its diagonals is 20 cm and its off sets 9 cm and 6 cm?
(A) 288
(B) 150
(C) 77
(D) 166
(E) 1812
Rationale: 1/2 * 20(9 + 6) = 150 cm2
Answer: B
Answer: (B) 150
Question: Dhoni weighs twice as much as Nameetha. Nameetha's weight is 60% of Bima's weight. Dravid weighs 45% of Leela's weight. Leela weighs 25% of Dhoni's weight. Who among these 5 persons weighs the least?
(A) Dhoni
(B) Bima
(C) Leela
(D) Dravid
(E) Nameetha
Rationale: if
Bima weight = x
we get
Nameetha's weight = 0.6x
Dhoni's weight = 1.2x
Leela's weight = 0.3x
and Dravid's weight = 0.135x
Answer : D
Answer: (D) Dravid
Question: The average weight of 10 persons increases by 6.3 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
(A) 176 kg
(B) 80 kg
(C) 185 kg
(D) 90 kg
(E) 128 kg
Rationale: Solution
Total weight increased	= (10 x 6.3)kg
= 63 kg.
Weight of new person	= (65 + 63)kg
= 128 kg.
Answer E
Answer: (E) 128 kg
Question: 40, 45, 50, 55, 60, 75, 75, 80, 100, 100.
The list above shows the scores of 10 schoolchildren on a certain test. If the standard deviation of the 10 scores is 20.4, rounded to the nearest tenth, how many of the scores are more than 1 standard deviation below the mean of the 10 scores?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Rationale: The average of {40, 45, 50, 55, 60, 75, 75, 80, 100, 100} is 68.
1 standard deviation below the mean is 68 - 20.4 = 47.6. Hence there are two scores (40 and 45) more than 1 standard deviation below the mean.
Answer B.
Answer: (B) 2
Question: The average of 9 numbers is 23. If each number is increased by 4, what will the new average be?
(A) 25
(B) 26
(C) 27
(D) 28
(E) 29
Rationale: Sum of the 9 numbers = 207
If each number is increased by 4, the total increase =
4 * 9 = 36
The new sum = 207 + 36 = 243 The new average = 243/9 = 27.
ANSWER:C
Answer: (C) 27
Question: Find the expenditure on digging a well 14m deep and of 3m diameter at Rs.14 per cubic meter?
(A) 1386
(B) 2799
(C) 2890
(D) 1485
(E) 2780
Rationale: 22/7 * 14 * 3/2 * 3/2
= 99 m2
99 * 14
= 1386
Answer:A
Answer: (A) 1386
Question: A can do a piece of work in 12 days. When he had worked for 2 days B joins him. If the complete work was finished in 8 days. In how many days B alone can finish the work?
(A) 18
(B) 77
(C) 66
(D) 55
(E) 12
Rationale: 8/12 + 6/x = 1
X = 18 days
Answer:A
Answer: (A) 18
Question: A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time cistern will get filled ?
(A) 7 hours
(B) 7.1 hours
(C) 7.2 hours
(D) 7.3 hours
(E) None of these
Rationale: Explanation:
When we have question like one is filling the tank and other is empting it, then we subtraction as,
Filled in 1 hour = 1/4
Empties in 1 hour = 1/9
Net filled in 1 hour = 1/4 - 1/9
= 5/36
So cistern will be filled in 36/5 hours i.e. 7.2 hours
Option C
Answer: (C) 7.2 hours
Question: Replace the ? by the correct Mathematics symbol to make the expression true
15 ? 3 ? 3 ? 5 = 10
(A) 15 ÷ 3 x 3 - 5 = 10
(B) 15 + 3 ÷ 3 + 5 = 10
(C) 15 x 3 + 3 + 5 = 10
(D) 15 x 3 ÷ 3 + 5 = 10
(E) 15 x 3 ÷ 3 + 6 = 10
Rationale: Answer : A
Answer: (A) 15 ÷ 3 x 3 - 5 = 10
Question: The cube root of .000216 is:
(A) 0.6
(B) 0.06
(C) 0.9
(D) 0.2
(E) 0.61
Rationale: Answer: B) .06
Answer: (B) 0.06
Question: Each month, after Jill pays for rent, utilities, food, and other necessary expenses, she has one fifth of her net monthly salary left as discretionary income. Of this discretionary income, she puts 30% into a vacation fund, 20% into savings, and spends 35% on eating out and socializing. This leaves her with $108 dollar, which she typically uses for gifts and charitable causes. What is Jill’s net monthly salary?
(A) $2400
(B) $3200
(C) $6000
(D) $3600
(E) $9600
Rationale: let x be the monthly salary
15%of 1/5*x=108
x=3600
answer D
Answer: (D) $3600
Question: The average of the marks of 12 students in a class is 36. If the marks of each student are doubled, find the new average?
(A) 72
(B) 77
(C) 26
(D) 27
(E) 29
Rationale: Sum of the marks for the 12 students
= 12 * 36 = 432. The marks of each student are doubled, the sum also will be doubled.
The new sum = 432 * 2 = 864. So, the new average
= 864/12 = 72.
Answer:A
Answer: (A) 72
Question: How many ways are there to split a group of 8 boys into two groups of 4 boys each? (The order of the groups does not matter)
(A) 24
(B) 35
(C) 43
(D) 60
(E) 72
Rationale: 8C4 = 70
If we consider these groups, each group will be counted twice.
The number of ways to choose 2 groups of 4 is 70/2 = 35
The answer is B.
Answer: (B) 35
Question: A man swims downstream 65 km and upstream 35 km taking 5 hours each time; what is the speed of the current?
(A) 2
(B) 3
(C) 5
(D) 7
(E) 9
Rationale: 65 --- 5 DS = 13
? ---- 1
35 ---- 5 US = 7
? ---- 1 S = ?
S = (13 - 7)/2 = 3
Answer: B
Answer: (B) 3
Question: x, a, z, and b are single digit positive integers. x = 1/8 a. z = 1/8 b. (10a + b) – (10x + z) could NOT equal
(A) 28
(B) 35
(C) 49
(D) 63
(E) 55
Rationale: a=8x , b =8z therefore(8x.10+8z) - (10x +z) = (8-1) (10x+z) =7.(10x+Z)
number should be divisible by 7
E
Answer: (E) 55
Question: A person walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 8 minutes earlier. How far is the office from his house?
(A) 3 1/5 Km
(B) 3 2/5 Km
(C) 3 3/5 Km
(D) 4 1/5 Km
(E) 5 1/5 Km
Rationale: Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 16/6
= 24/2 * 16/60
= 8 * 2/5
= 16/5 = 3 1/5 Km
A)
Answer: (A) 3 1/5 Km
Question: The average of fifteen results is 593 and that of the first fourteen is 594. The fifteenth result is?
(A) 575
(B) 602
(C) 579
(D) 586
(E) 592
Rationale: 15 * 593 â€“ 14 * 594 = 579
Answer: C
Answer: (C) 579
Question: Sequence A consists of 16 consecutive integers. If -6 is the least integer in sequence A, what is the range of the positive integers in sequence A?
(A)  16
(B)  15
(C)  9
(D)  8
(E)  7
Rationale: Since set A consists of 16 consecutive integers and -6 is the least integer then set A is consecutive integers from -6 to 9, inclusive: 9-(-6)+1=16.
The range of positive integers in sequence A is 9-1=8.
Answer: D.
Answer: (D)  8
Question: The entire range of values of x is marked by the dark region on the number line, as shown above. Which of the following expressions describes the range of values of x?
(A) (3+x)(2−x) ≤ 0
(B) (3−x)(2+x) ≥ 0
(C) (x−3)(x+2) ≤ 0
(D) (x+3)(2−x) ≥ 0
(E) (3−x)(2−x) ≥ 0
Rationale: Given: x≥−3x≥−3 and x≤2 x≤2
(x+3)≥0(x+3)≥0 and (x−2)≤0(x−2)≤0
(x+3)≥0(x+3)≥0 and (2−x)≥0(2−x)≥0
Answer: D
Answer: (D) (x+3)(2−x) ≥ 0
Question: If n is an integer and n^4 is divisible by 9, which of the following could be the remainder when n is divided by 9?
(A) 1
(B) 3
(C) 5
(D) 6
(E) 8
Rationale: option 1
Remainder 1 means 9+1=10
n^4= 10^4= 10*10*10*10/9 is not an integer
option 2
Remainder 3 means 9+3=12
n^4= 12*12*12*12/9 is an integer means n^4 is divisible by 9 if we take n=3
so B is correct
Answer: (B) 3
Question: An gun can take a maximum of four shots at an enemy plane moving away from it. The probability of hitting the plane at the 1st, 2nd, third and 4th shots are 1.4, 1.3, 1.2 & 1.1 respectively. What is the probability that the plane is hit when all the four shots are fired?
(A) 0.2974
(B) 0.6976
(C) 0.7565
(D) 1.6465
(E) 2.3475
Rationale: Required probability:
=(0.4×0.7×0.8×0.9)+(0.6×0.3×0.8×0.9)+(0.6×0.7×0.2×0.9)+(0.6×0.7×0.8×0.1)+(0.4×0.3×0.8×0.9)+(0.4×0.7×0.2×0.9)+(0.4×0.7×0.8×0.1)+(0.6×0.3×0.2×0.9)+(0.6×0.3×0.8×0.1)+(0.6×0.7×0.2×0.1)+(0.4×0.3×0.2×0.9)+(0.6×0.3×0.2×0.1)+(0.4×0.3×0.8×0.1)+(0.4×0.7×0.2×0.1)+(0.4×0.3×0.2×0.1)=(0.4×0.7×0.8×0.9)+(0.6×0.3×0.8×0.9)+(0.6×0.7×0.2×0.9)+(0.6×0.7×0.8×0.1)+(0.4×0.3×0.8×0.9)+(0.4×0.7×0.2×0.9)+(0.4×0.7×0.8×0.1)+(0.6×0.3×0.2×0.9)+(0.6×0.3×0.8×0.1)+(0.6×0.7×0.2×0.1)+(0.4×0.3×0.2×0.9)+(0.6×0.3×0.2×0.1)+(0.4×0.3×0.8×0.1)+(0.4×0.7×0.2×0.1)+(0.4×0.3×0.2×0.1)
=0.2016+0.1296+0.756+0.336+0.864+0.504+0.224+0.324+0.144+0.0084+0.0216+0.0036+0.0096+0.0056+0.002=0.2016+0.1296+0.756+0.336+0.864+0.504+0.224+0.324+0.144+0.0084+0.0216+0.0036+0.0096+0.0056+0.002
=0.6976=0.6976
Edit: Thank you Vaibhav for providing an alternative method.
Alternate Method:
probability that the plane is hit when all the four shots are fired,
P=1−probability of not hitting the targetP=1−probability of not hitting the target
=1−(0.6×0.7×0.8×0.9)=1−(0.6×0.7×0.8×0.9)
=1−0.3024=1−0.3024
=0.6976
B
Answer: (B) 0.6976
Question: A boat can travel with aspeed of 20km/hr in still water. If the speed of the stream is 5km/hr, find the time taken by the boat to go 125km downstream.
(A) 1 hr
(B) 2 hrs
(C) 3 hrs
(D) 4 hrs
(E) 5 hrs
Rationale: Speed downstream = (20 + 5) km/hr = 25 km/hr.
Time taken to travel 125 km downstream = 125/25 hrs = 5 hrs.
Answer : E
Answer: (E) 5 hrs
Question: Dacid obtained 73, 69, 92, 64 and 82 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
(A) 79
(B) 99
(C) 88
(D) 88
(E) 76
Rationale: Average = (73+ 69+ 92+ 64+82)/5
= 380/5 = 76
Answer:E
Answer: (E) 76
Question: what is next no. 11 23 47 83 131 191 263 347 443 551???
(A) 171
(B) 181
(C) 191
(D) 201
(E) 671
Rationale: 11+12*1=23
23+12*2=47
47+12*3=83
83+12*4=131
131+12*5=191
191+ 12*6=263
263+12*7=347
347+12*8=443
443+12*9=551
551+12*10=671
ANSWER:E
Answer: (E) 671
Question: What amount does Kiran get if he invests Rs.8000 at 10% p.a. compound interest for two years, compounding done annually?
(A) Rs.9688
(B) Rs.9687
(C) Rs.3338
(D) Rs.9632
(E) Rs.9680
Rationale: Explanation:
A= P{1 + R/100}n
=> 8000{1 + 10/100}2 = Rs.9680
Answer: E
Answer: (E) Rs.9680
Question: Pavan travelled for 11 hours. He covered the first half of the distance at 30 kmph and remaining half of the distance at 25 kmph. Find the distance travelled by Pavan.
(A) 228
(B) 266
(C) 289
(D) 300
(E) 271
Rationale: Let the distance travelled be x km.
Total time = (x/2)/30 + (x/2)/25 = 11 => x/60 + x/50 = 11 => (5x + 6x)/300 = 11 => x = 300 km.Answer: D
Answer: (D) 300
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 7350 sq m, the cost of fencing it at 50 ps per meter is?
(A) 287
(B) 1287
(C) 125
(D) 988
(E) 175
Rationale: 3x * 2x = 7350 => x = 35
2(105 + 70) = 350 m
350 * 1/2 = Rs.175
Answer: E
Answer: (E) 175
Question: Two trains 121 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?
(A) 7.18
(B) 7.12
(C) 7.1
(D) 7.15
(E) 7.11
Rationale: T = (121 + 165)/ (80 + 65) * 18/5
T = 7.15
Answer:D
Answer: (D) 7.15
Question: A dishonest milkman sells a 40 liter mixture of milk and water that contains milk and water in the ratio of 2:3. He takes out 20 liters of the mixture and replaces it with an equal amount of milk. He then takes out 20 liters of this new mixture and replaces it with an equal amount of water to create his final mixture. What is the ratio of milk and water in the final mixture?
(A) 2:5
(B) 3:5
(C) 2:3
(D) 3:2
(E) 5:3
Rationale: ............................... Water ............... Milk ....................... Total
Initial ...................... 24 .................... 16 .............................. 40
20 Lts mix. taken out 24-12 ............... 16-8 ........................... 40-20
20 Lts milk added..... 12+20 ................ 8 .............................. 40
20 Lts mix. taken out 32-16 ............... 8-4 ........................... 40-20
20 Lts water added..... 16 ................ 4+20 .............................. 40
New ratio = 24:16 = 3:2
D
Answer: (D) 3:2
Question: Nitin borrowed some money at the rate of 6% p.a. for the first three years, 9% p.a. for the next five years and 13% p.a. for the period beyond eight years. If the total interest paid by him at the end of eleven years is Rs. 13260, how much money did he borrow?
(A) 13000
(B) 80288
(C) 2668
(D) 2600
(E) 2781
Rationale: Let the sum be Rs. x. Then,
[(x * 6 * 3)/100] + [(x * 9 * 5)/100] + [(x * 13 * 3)/100] = 13260
18x + 45x + 39x = (13260* 100)
102x = 1326000 => x = 13000.
Answer:A
Answer: (A) 13000
Question: The probability of Sam passing the exam is 1/4. The probability of Sam passing the exam and Michael passing the driving test is 1/5. What is the probability of Michael passing his driving test?
(A) 1/24.
(B) 4/5.
(C) 1/3.
(D) 2/3.
(E) 2/5
Rationale: 1/4 *1/m= 1/5 , 1/m = 4/5
Answer B
Answer: (B) 4/5.
Question: A cycle is bought for Rs.900 and sold for Rs.1080, find the gain percent?
(A) 70%
(B) 20%
(C) 90%
(D) 27%
(E) 22%
Rationale: 900 ---- 180
100 ---- ? => 20%
Answer: B
Answer: (B) 20%
Question: What is the value of (P + Q)/(P - Q) if P/Q is 8?
(A) 4/3
(B) 2/3
(C) 2/6
(D) 7/8
(E) 9/7
Rationale: (P + Q)/(P - Q) = [(P/Q) + 1]/[(P/Q) - 1]
= (8 + 1)/(8 - 1)
= 9/7
ANSWER:E
Answer: (E) 9/7
Question: On dividing a number by 56, we get 29 as remainder. On dividing the same number by 8, what will be the remainder ?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Rationale: Number=56x+29 (∵ since the number gives 29 as remainder on dividing by 56)
=(7×8×x)+(3×8)+5
Hence, if the number is divided by 8, we will get 5 as remainder.
ANSWER:D
Answer: (D) 5
Question: When asked what the time is,a person answered that the amount of time left is 1/5 of the time already completed.what is the time.
(A) 2
(B) 9
(C) 3
(D) 8
(E) 6
Rationale: A day has 24 hrs. Assume x hours have passed. Remaining time is (24 - x)
24−x=15x⇒x=2024−x=15x⇒x=20
Time is 8 PM
Answer:D
Answer: (D) 8
Question: The price of commodity X increases by 45 cents every year, while the price of commodity Y increases by 20 cents every year. In 2001, the price of commodity X was $5.20 and the price of commodity Y was $7.30. In which year will the price of commodity X be 35 cents less than the price of commodity Y?
(A) 2006
(B) 2007
(C) 2008
(D) 2009
(E) 2010
Rationale: The price of commodity X increases 25 cents each year relative to commodity Y.
The price difference is $2.10 and commodity X needs to be 35 cents less than commodity Y.
$1.75 / 25 cents = 7 years
The answer is 2001 + 7 years = 2008.
The answer is C.
Answer: (C) 2008
Question: What was the day of the week on 11th March, 2006?
(A) Monday
(B) Friday
(C) Thursday
(D) Sunday
(E) Saturday
Rationale: 28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March
(31 + 28 + 11 ) = 70 days
70 days = (6 weeks + 0 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 0) = 6 0 odd day.
Given day is Saturday.
Answer: Option E
Answer: (E) Saturday
Question: Find the ratio in which wheat of inferior quality (Rs.14/kg) be mixed with wheat of superior quality (Rs.28/kg) so that the shopkeeper gains Rs.2 by selling the resulting mixture at Rs.20/kg.
(A) 1 : 3
(B) 5 : 2
(C) 3 : 4
(D) 2 : 5
(E) None of these
Rationale: Explanation:
Let the resulting mixture be 1 kg, and x kg be the amount of wheat of inferior quality.
Therefore, (1-x)kg is the amount of wheat of superior quality.
As the shopkeeper gains Rs.2, the cost of the mixture is Rs.18
14*x + 28*(1-x) = 18
14x - 28x + 28 = 18
14x = 10
x = 5/7
(1 – x) = 2/7
x : (1-x) = 5/7 : 2/7
= 5 : 2
ANSWER B
Answer: (B) 5 : 2
Question: In a fuel station the service costs $2.05 per car, every liter of fuel costs 0.6$. Assuming that you fill up 3 mini-vans and 2 trucks, how much money will the fuel cost to all the cars owners total, if a mini- van's tank is 65 liters and a truck's tank is 140% bigger and they are all empty-?
(A) 122.6$
(B) 128.9$
(C) 243.7$
(D) 298.85$
(E) 314.45$
Rationale: Service cost of 3 van and 2 truck = 2.05*(3+2)=10.5
Fuel in 3 Van = 3*65=195 litre
Fuel in 2 Trucks =2 * 65(1+140/100)= 312
Total fuel(Van+Truck) = 507 Litre
Total Fuel cost = 507*0.6 =304.2
TOTAL COST =FUEL+SERVICE=304.2+10.25=314.45
ANSWER IS E
Answer: (E) 314.45$
Question: 20% of A is B, then B% of 20 is same as what?
(A) 7% of A
(B) 4% of A
(C) 8% of A
(D) 1% of A
(E) 3% of A
Rationale: Explanation:
It is given that B measures 20% of A
=> So, 20% of A = B or 20/100 * A = B - (1)
B% of 20= B/100 X 20= 2B/10 ---(2)
=> Now, B% of 20
Substituting (1) in (2) we get
2*(2A/10) / 10= 4A/100
Hence, B% of 20 = 4% of A
ANSWER: B
Answer: (B) 4% of A
Question: A number is said to be a “digifac” if each of its digits is a factor of the number itself. What is the sum N of the missing digits of the following five-digit digifac: 9, 5, 3 _ _ ?
(A)  5
(B)  7
(C)  9
(D)  10
(E)  14
Rationale: Here, the term “digifac” should look intimidating. You probably haven’t studied digifacs before, so how should you approach this problem? Well, keep in mind that digifacs aren’t being tested; in fact, the author of this question just made that term up, and then defined it for you. What makes this question hard is that the non-challenge-seeker (I think I just made that term up, too…) will see the unfamiliar term “digifac” and lose faith immediately. “I don’t know what that is!” She who finds the challenge in the GMAT fun, however, will read the definition and think “got it – I need to find the two digits that ensure that 9, 5, and 3 are both factors of the overall number, and that the remaining two digits are also factors”. And work from there. The number must be divisible by 5, so the only units digits that work are 0 or 5. And the number must be divisible by 9 (and also 3), so we need the sum N of all digits to be a multiple of 9. 9 + 5 + 3 = 17, so our only options are to get the sum to 18 (by adding 1) or to 27 (by adding 10). A quick glance at the answer choices shows that 0 1 isn’t an option. Why not? That would require 0 to be one of the digits…and 0 isn’t a factor of anything. So the units digit must be 5, making the tens digit 5, and we have 95,355. That number is a multiple of 5, 3, and 9, so it works:the correct answer is D, and more importantly this fun challenge required no “trivial” information about digifacs…that term only existed to obscure the link between the given information and the path to the answer.D
Answer: (D)  10
Question: 30% of the men are more than 25 years old and 80% of the men are less than or equal to 50 years old. 20% of all men play football. If 20% of the men above the age of 50 play football, what percentage of the football players are less than or equal to 50 years?
(A) 60%
(B) 70%
(C) 80%
(D) 90%
(E) 100%
Rationale: Explanation :
Let total number of men = 100
Then
80 men are less than or equal to 50 years old
(Since 80% of the men are less than or equal to 50 years old)
=> 20 men are above 50 years old (Since we assumed total number of men as 100)
20% of the men above the age of 50 play football
⇒Number of men above the age of 50 who play football = 20× (20/100) = 4
Number of men who play football = 20 (Since 20% of all men play football)
Percentage of men who play football above the age of 50 = (4/20) × 100=20%
=>Percentage of men who play football less than or equal to the age 50 = 100%−20%=80%
ANSWER IS C
Answer: (C) 80%
Question: A group of college friends plan to rent a house together for x dollars per month, which is to be shared equally among them. If five, rather than seven people rent the house together, how many more dollars, in terms of x, will each person have to pay for rent per month?
(A) 2x/35
(B) 4x/15
(C) x/7
(D) 3x/20
(E) 5x/7
Rationale: If 7 people share the rent, each person would pay x/7.
If 5 people share the rent, each person will pay x/5.
The extra amount each person pays is x/5 - x/7 = 7x/35 - 5x/35 = 2x/35
The answer is A.
Answer: (A) 2x/35
Question: Missing number in the series
4 9 20 43 90 185 376 759 1526 ?
(A) 3750
(B) 3061
(C) 3903
(D) 3952
(E) 3804
Rationale: 4*2+1=9
9*2+2=20
20*2+3=43
43*2+4=90
90*2+5=185
185*2+6=376
376*2+7=759
759*2+8=1526
1526*2+9=3061
ANSWER:B
Answer: (B) 3061
Question: Average of five numbers is 12. If one number is excluded the average becomes 10. The excluded number is
(A) 35
(B) 20
(C) 40
(D) 30
(E) 67
Rationale: Explanation:
Number is (5*12) - (4*10) = 60-40= 20
Answer: Option B
Answer: (B) 20
Question: 20 men do a work in 20days. How many men are needed to finish the work in 5days?
(A) 50
(B) 20
(C) 80
(D) 10
(E) 15
Rationale: men required to finish the work in 5days = 20*20/5 = 80
Answer is C
Answer: (C) 80