mathewhe/aqua_rat huggingface dataset:
Question: A confectioner decides to sell all of his pastry due to the coming holiday. His pastry goods are equally divided among a group of 28 regular customers. If only 49 customers come to the bakery, each one will receive 6 less pastry goods. How much pastry does the confectioner needs to sell?
(A) 392
(B) 412.
(C) 432.
(D) 502
(E) 522
Rationale: Solution 1 : Given that number of pastries are equally divided in to 28 groups, so the answer should be a multiple of 28. And in the given choices, only 392 is divisible by 28 with remainder 0(Make sure others are no multiples of 28). So this is good enough to stop here, but to verify, 392/28 = 14 and 392/49 = 8, which confirms the second part of question, 14-8 , 6 pastry short of each customer.
Solution 2 : Going mathematical, expressing in the equation form, Let x be the number of pastries and , n be the number of customers in 28 groups.
So, x = 28 * n,
as per second statement, x = 49 * (n - 6 )
Solve the above 2 for n and then we get x as 392.
Answer is A : 392.
Answer: (A) 392
Question: A 6 by 8 rectangle is inscribed in circle. What is the circumference of the circle?
(A) 5π
(B) 10π
(C) 15π
(D) 20π
(E) 25π
Rationale: The diagonal of the rectangle will be the diameter of the circle.
and perimeter= 2*pi*r
Ans: B
Answer: (B) 10π
Question: In a series of six football matches between Germany and Argentina , the probability of Germany winning a match is 1/3 and the probability that the match ends in a draw is 1/4. If a win gets the team 2 points, a draw 1 point and a loss 0 Points, What is the probability that Germany will end up in 6 draws in the series?
(A) 24/576
(B) 125/864
(C) 1/25
(D) 1/4096
(E) 1/5
Rationale: Since the probability of a draw is 1/4, then the probability of 6 draws in 6 matches is (1/4)^6=1/4096.
Answer: D.
Answer: (D) 1/4096
Question: A train is 327 meter long is running at a speed of 40 km/hour. In what time will it pass a bridge of 122 meter length?
(A) 32.7
(B) 41
(C) 50.29
(D) 40.41
(E) 20.28
Rationale: Speed = 40 Km/hr = 40*(5/18) m/sec = 100/9 m/sec
Total distance = 327+122 = 449 meter
Time = Distance/speed
= 449 * (9/100) = 40.41 seconds.
Answer: D
Answer: (D) 40.41
Question: The value of a stock is X dollars. On Sunday the stock's value grew by half of its value, but on Monday its value dropped to a half of its new value. What is the stock's value at the end of Monday?
(A) X.
(B) X/2.
(C) 2X/3.
(D) 3X/4.
(E) X/4.
Rationale: Stock value= X
AT sunday end= x+.5X= 1.5 X
On monday the value drop to 1/2rd of its value on sunday
1.5x/2= .75x= 3X/4
D is the answer
Answer: (D) 3X/4.
Question: P alone can complete a piece of work in 10 days. Work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?
(A) 6 (1/4) days
(B) 30/4 days
(C) 7 (3/4) days
(D) 9/4 days
(E) 9 (3/4) days
Rationale: Work done by P alone in one day = 1/10th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/10 of the total) = 1/30 of the total.
Work done by P and Q, working together in one day = 1/10 + 1/30 = 4/30 of the total
They would take 30/4 days to complete the work working together.
ANSWER:B
Answer: (B) 30/4 days
Question: A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes ?
(A) 50 meter
(B) 100 meter
(C) 110 meter
(D) 120 meter
(E) 130 meter
Rationale: Explanation:
Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr
Distance covered in 6 minutes =
1/60∗6=1/10=100meters
So distance between them after 6 minutes = 200 - 100
= 100 meters
Option B
Answer: (B) 100 meter
Question: 1+3=2 2+3=10 3+3=30 4+3=68 5+3=??
(A) 110
(B) 120
(C) 130
(D) 140
(E) 150
Rationale: 1^3+3-2=2,
2^3+3-1=10,
3^3+3-0=30,
4^3+3+1=68,
5^3+3+2=130
ANSWER:C
Answer: (C) 130
Question: Find the average of all the numbers between 6 and 29 which are divisible by 5?
(A) 17
(B) 20
(C) 25
(D) 30
(E) 15
Rationale: Average = (10+15+20+25) 4 = 70/4 = 17
Answer is A
Answer: (A) 17
Question: If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 3:4 then find the largest number?
(A) 20
(B) 22
(C) 30
(D) 32
(E) 27
Rationale: Ratio is 2:3
2x + 10 : 3x + 10 = 3 : 4
4[2x + 10] = 3[3x + 10]
8x + 40 = 9x + 30
9x - 8x = 40 - 30
x = 10
Then largest number is = 3x
3x = 30
Ans = C
Answer: (C) 30
Question: What is the area of square field whose side of length 18 m?
(A) 225 sq m
(B) 186 sq m
(C) 586 sq m
(D) 324 sq m
(E) 296 sq m
Rationale: 18 * 18
= 324 sq m
Answer: D
Answer: (D) 324 sq m
Question: How many ways are there to split a group of 12 students into two groups of 6 students each? (The order of the groups does not matter)
(A) 180
(B) 262
(C) 384
(D) 462
(E) 512
Rationale: 12C6 = 924
If we consider these groups, each group will be counted twice.
The number of ways to choose 2 groups of 6 is 924/2 = 462
The answer is D.
Answer: (D) 462
Question: From the given equation find the value of x: x² − 3x + 2
(A) 0
(B) 1
(C) 2
(D) 3
(E) 6
Rationale: (x − 1)(x − 2)
x = 1 or 2.
C
Answer: (C) 2
Question: A woman has 7 daughters and they each have a brother, how many children does she have?
(A) 7
(B) 8
(C) 9
(D) 5
(E) 3
Rationale: B
8
8 children, the sisters have just one brother!
Answer: (B) 8
Question: In a kilometer race, A beats B by 50 meters or 10 seconds. What time does A take to complete the race?
(A) 187 sec
(B) 190 sec
(C) 168 sec
(D) 197 sec
(E) 191 sec
Rationale: Time taken by B run 1000 meters
= (1000 * 10)/50 = 200 sec.
Time taken by A = 200 - 10
= 190 sec.
Answer: B
Answer: (B) 190 sec
Question: A die is rolled twice. What is the probability of getting a sum equal to 9?
(A) 2/8
(B) 1/9
(C) 3/9
(D) 7/4
(E) 2/7
Rationale: Explanation :
Total number of outcomes possible when a die is rolled =6
Hence, total number of outcomes possible when a die is rolled twice, n(S)=6*6=36
E = Getting a sum of 9 when the two dice fall = {(3, 6), {4, 5}, {5, 4}, (6, 3)}
Hence, n(E) = 4
P(E) =n(E)/n(S)=4/36=1/9
B
Answer: (B) 1/9
Question: A and Bâ€™s salaries together amount to Rs. 2,000. A spends 95% of his salary and B spends 85% of his. If now their savings are the same, what is Aâ€™s salary?
(A) Rs.500
(B) Rs.750
(C) Rs.1250
(D) Rs.1500
(E) Rs.2000
Rationale: Explanation:
(5/100) A = (15/100) B
A = 3B
A + B = 2000
4B = 2000 => B = 500
A = 1500
ANSWER IS D
Answer: (D) Rs.1500
Question: Ramu bought an old car for Rs. 35000. He spent Rs. 13000 on repairs and sold it for Rs. 64900. What is his profit percent?
(A) A)14%
(B) B)16%
(C) C)18%
(D) D)30.7%
(E) of these
Rationale: Total CP = Rs. 35000 + Rs. 13000 = Rs. 48000 and SP = Rs. 64900
Profit(%) = (64900 - 48000)/55000 * 100 = 30.7%
ANSWER:D
Answer: (D) D)30.7%
Question: Bob bikes to school every day at a steady rate of b miles per hour. On a particular day, Bob had a flat tire exactly halfway to school. He immediately started walking to school at a steady pace of y miles per hour. He arrived at school exactly t hours after leaving his home. How many miles is it from the school to Bob's home?
(A) (b + y) / t
(B) 2(b + t) / by
(C) 2byt / (b + y)
(D) 2(b + y + t) / by
(E) x(y + t) + y(x + t)
Rationale: If we choose for d (distance): 10 miles, for b 10 and for y 5.
t would be 90 minutes or 1,5 hours.
If I try this for answer choice C it fits.
Answer: (C) 2byt / (b + y)
Question: There are between 100 and 110 marbles in a collection of cards. If they are counted out 3 at a time, there are 1 left over, but if they are counted out 4 at a time, there is 4 left over. How many marbles are in the collection?
(A)  100
(B)  103
(C)  106
(D)  108
(E)  109
Rationale: Let number of cards = x
If the cards are counted 3 at a time , there are 2 left over-
x = 3p+1
x can take values 100 , 104 , 109
If the cards are counted 4 at a time , there is 1 left over
x= 4q+4
x can take values 100 , 108
Therefore , x = 100
Answer A
Answer: (A)  100
Question: Adding two non multiples of C always results in a multiple of C; which of the following must be the value of C ?
(A) [A] two
(B) [B] three
(C) [C] five
(D) [D] ten
(E) [E] hundred
Rationale: NON- multiples of 2 would always be ODD and sum of two odd would be EVEN.
so irrespective of value of non-multiples, sum of two them would always be even and thus multiple of 2..
A
Answer: (A) [A] two
Question: A bag contains 5 red, 4 blue and 3 green balls. If 2 ballsare picked at random, what is the probability that both are red?
(A) 1/13
(B) 2/23
(C) 5/33
(D) 4/27
(E) 3/23
Rationale: P(Both are red),
=5C212C2=5C212C2
=10/66=5/33
C
Answer: (C) 5/33
Question: Johnny borrows $40,000 from Tony at 4% daily interest compounded daily. How much does Johnny owe Tony after 8 weeks?
(A) 40000*0.02^56
(B) 30000*1.12
(C) 40000*2.12
(D) 40000*1.04^56
(E) (40000*1.02)^56
Rationale: A=A= P(1+r100)^n
So, A=40000(1+4/100)^7âˆ—8
So, A= 40000(1.04)^56
Hence answer will be (D)
Answer: (D) 40000*1.04^56
Question: What least no. must be subtracted from 427398 so that remaining no.is divisible by 15?
(A) 344545629
(B) 723437481
(C) 354595321
(D) 964564944
(E) 458449909
Rationale: Explanation:
On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted
Option B
Answer: (B) 723437481
Question: Of the teams competing in the world archery championships, Fifty percent are from Europe. Half as many are from the United States and one twentieth are from Africa. What fraction of teams are from neither Europe, the US or Africa.
(A) 13/20
(B) 15/20
(C) 13/15
(D) 3/20
(E) 4/20
Rationale: Half as manymeans half of EU, then
EU 50%
US 25%
AF 5%
the rest is 20%, answer E
Answer: (E) 4/20
Question: Light glows for every 17 seconds . How many times did it between 1:57:58 and 3:20:47 am
(A) 291
(B) 292
(C) 293
(D) 384
(E) 285
Rationale: the diff in sec between 1:57:58 and 3:20:47 is 4969 sec, 4969/17 = 292.
so total 293 times light ll glow
ANSWER:C
Answer: (C) 293
Question: A rectangular field has a length 10 feet more than it is width. If the area of the field is 264, what are the dimensions of the rectangular field?
(A) 22
(B) 23
(C) 24
(D) 25
(E) 26
Rationale: Let x and y be the length and width of the field. The statement "a length 10 feet more than it is width" may be formulated by
x = 10 + y
The formula for the area is given by
A = x y
Substitute A and x in the above equation by 264 and 10 + y respectively to obtain
264 = (10 + y) y
Write the above equation in standard form as follows
y 2 + 10 y - 264 = 0
Solve the above equation for to obtain
y = 12 and y = - 22
Since y is the value of a width it must be positive. The dimensions of the field are given by
y = 12 and x = 10 + y = 22
As an exercise, check that the rectangular field has length 10 feet more than it is width and an area of 264.
Answer A
Answer: (A) 22
Question: The average of first three prime numbers greater than 5 is?
(A) 12.6
(B) 12.9
(C) 22.3
(D) 10.3
(E) 12.7
Rationale: 7 + 11+ 13 = 31/3 = 10.3
Answer: D
Answer: (D) 10.3
Question: What is the tens digit of 6^20?
(A) 1
(B) 3
(C) 5
(D) 7
(E) 9
Rationale: The tens digit of 6 in integer power starting from 2 (6^1 has no tens digit) repeats in a pattern of 5: {3, 1, 9, 7, 5}:
The tens digit of 6^2=36 is 3.
The tens digit of 6^3=216 is 1.
The tens digit of 6^4=...96 is 9.
The tens digit of 6^5=...76 is 7.
The tens digit of 6^6=...56 is 5.
The tens digit of 6^7=...36 is 3 again.
etc...
20 has the form 5n, so the tens digit of 6^20 is 7.
The answer is D.
Answer: (D) 7
Question: 96% of the population of a city is 23040. Find the total population of the city?
(A) 30000
(B) 28000
(C) 24000
(D) 25000
(E) 25500
Rationale: Population consider as x
x*(96/100) = 23040
x=240*100
==>24000
ANSWER C
Answer: (C) 24000
Question: A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
(A) 220 km
(B) 224 km
(C) 230 km
(D) 232 km
(E) 234 km
Rationale: 0.5x/21 + 0.5x/24 = 10
--> x/21 + x/24 = 20
--> 15x = 168 x 20
--> x = (168 x 20)/15 = 224 km.
Answer : B.
Answer: (B) 224 km
Question: If k is the greatest positive integer such that 3^k is a divisor of 21! then k =
(A) 3
(B) 4
(C) 5
(D) 6
(E) 9
Rationale: 21/3=7
21/9=2.33=2
7+2 =9
k=9
Answer: E
Answer: (E) 9
Question: Different breeds of dogs get older at different rates in “dog years.” Livonian wolfhounds age 7 times as fast as humans, whereas Khazarian terriers age 3 times as fast and Akkadian retrievers age 4 times as fast. If Dan bought a newborn Akkadian on January 1, 2010, a newborn Khazarian 1 year later, and a newborn Livonian 1 year after that, in what year will the sum of the dog-year ages of the Akkadian and the Khazarian first be exceeded by twice the age of the Livonian in dog years, rounding all ages down to the nearest integer?
(A) 2013
(B) 2014
(C) 2015
(D) 2016
(E) 2017
Rationale: chart starting at 2011: A=4 ;2012= A=8 ,K=3
A+K=11
L=0.
Then I added 7 to a+k for each year and 14 to L for each year.
2013:AK=18 L=14
2014:AK= 25 L=28
thus, 2014 is the correct answer.
B
Answer: (B) 2014
Question: My 5 sons are enrolled in an army's platoon of 80 men. The General is choosing randomly 2 men to a suicide mission. What is the probability of both of the selected men will be two of my sons?
(A)  1/80
(B)  2/80
(C)  5/80
(D)  1/316
(E)  2/316
Rationale: My sons are 5 in a group of 80 men. Thus the probability of choosing 2 of my sons is: (5/80)(4/79) = 1/316. The correct answer is D.
Answer: (D)  1/316
Question: Ganet has to pay back her bank loan over 6 months following the below sequence.
$50, $55, $65, $80, $85, ?
How much will she pay back on the sixthmonth?
(A) $155
(B) $145
(C) $95
(D) $125
(E) $130
Rationale: The sequence progresses +5, +10, +15 repeated; The amount to pay back on the 6th Month is $95
Ans C
Answer: (C) $95
Question: a man owns 1/3 of market reserch beauro buzness,and sells 3/5 of his shares for 2000rs,what is the value of buzness?
(A) 40000
(B) 60000
(C) 10000
(D) 25000
(E) 50000
Rationale: If value of business=x
Total sell (1x/3)(3/5)=2000
->x=10000
ANSWER:C
Answer: (C) 10000
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 25 hours and 81 hours respectively. The ratio of their speeds is:
(A) 2 : 3
(B) 4 : 3
(C) 9 : 5
(D) 9 : 16
(E) None of these
Rationale: Let us name the trains as A and B. Then,
(A's speed) : (B's speed) = âˆšb : âˆša = âˆš81 : âˆš25 = 9 : 5.
Answer C
Answer: (C) 9 : 5
Question: There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
(A) 100
(B) 150
(C) 200
(D) 220
(E) 240
Rationale: Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Answer: (A) 100
Question: A garrison of 2000 men has provisions for 62 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement?
(A) 1977
(B) 1893
(C) 2700
(D) 1900
(E) 1278
Rationale: 2000 ---- 62
2000 ---- 47
x ----- 20
x*20 = 2000*47
x = 4700
2000
-------
2700
Answer: C
Answer: (C) 2700
Question: When x and y are rounded to the nearest tenth, x is 0.3 and y is 0.6. The exact value of (x/y) must be between
(A) 5/12 and 7/12
(B) 6/11 and 6/13
(C) 5/13 and 7/11
(D) 3/7 and 7/12
(E) 5/11 and 7/13
Rationale: x rounded to nearest tenth is 0.3
i.e. x may vary from 0.25 to 0.34
0.25 < x < 0.34
y rounded to nearest tenth is 0.6
i.e. x may vary from 0.55 to 0.64
0.55 < y < 0.64
Min (x/y) = 0.25/0.64 = 25/64 = 25/65 (Approx) = 5/13 (Approx)
Max (x/y) = 0.34/0.55 = 34/55 = 35/55 (Approx) = 7/11 (Approx)
Answer: option C
Answer: (C) 5/13 and 7/11
Question: A motorist knows nine different routes from Bristol to Birmingham. From Birmingham to Sheffield he knows three different routes and from Sheffield to Carlisle he knows two different routes. How many routes does he know from Bristol to Carlisle ?
(A) 4
(B) 8
(C) 12
(D) 24
(E) 54
Rationale: Explanation:
Total number of routes from Bristol to Carlisle = (9 x 3 x 2) = 54.
Answer: E
Answer: (E) 54
Question: The perimeter of a square is equal to the perimeter of a rectangle of length 17 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)
(A) 23.57
(B) 23.54
(C) 23.5
(D) 24.35
(E) 24.51
Rationale: Let the side of the square be a cm.
Perimeter of the rectangle = 2(17 + 14) = 62 cm
Perimeter of the square = 62 cm
i.e. 4a = 62
A = 15.5
Diameter of the semicircle = 15.5 cm
Circumference of the semicircle
= 1/2(∏)(15.5)
= 1/2(22/7)(15.5) = 24.35 cm to two decimal places
Answer: D
Answer: (D) 24.35
Question: If r and s are positive integers and r-s=6, which of the following has the greatest value K?
(A) 2r
(B) 2s
(C) r +s
(D) 2r-s
(E) 2s-r
Rationale: You can answer this question by using Number Properties and logic or by TESTing VALUES.
We're told that R and S are POSITIVE INTEGERS and that R-S = 6. We're asked which of the 5 answers has the GREATEST value.
IF....
R = 8
S = 2
Answer A: 2R = 2(8) = 16
Answer B: 2S = 2(2) = 4
Answer C: R+S = 8+2 = 10
Answer D: 2R-S = 2(8) - 2 = 14
Answer E: 2S-R = 2(2) - 8 = -4
Final Answer:
A
Answer: (A) 2r
Question: Felix earned 30% more per month than Oscar. If Felix’s salary is decreased 10% and Oscar’s salary is increased by 10%, then Felix would be earning what percent more than Oscar?
(A) 10%
(B) 9.09%
(C) 7%
(D) 6.36%
(E) It cannot be determined from the information given.
Rationale: the very first step requires taking some numbers for each..
ONE should be 100...
it is easy to take 70 and 100 here..
but the BASE is 100 here, so the salary can be 100 and 130..
100 increases 10% =110..
130 decreases 10%=117..
so the increase is 7..
again the BASE is 110, so answer 7/110 * 100= 6.36% D
without calculations,
answer cannot be equal to or greater than 7, as 7 is on 110..
so D is the only one left
ANSWER:D
Answer: (D) 6.36%
Question: 1/5 of a number is equal to 5/8 of the second number. If 35 is added to the first number then it becomes 4 times of second number. What is the second number ?
(A) 125
(B) 70
(C) 40
(D) 25
(E) 27
Rationale: Answer
Let first and second numbers are p & q.
p/5 = 5q/8
∴ p/q = 25/8 ...(i)
p + 35 = 4q
or 25q/8 + 35= 4q
∴ q = 40
Correct Option: C
Answer: (C) 40
Question: A and B can do a work in 4 hours and 12 hours respectively. A starts the work at 6AM and they work alternately for one hour each. When will the work be completed?
(A) 3 days
(B) 6 days
(C) 7 days
(D) 2 days
(E) 8 days
Rationale: B
6 days
Work done by A and B in the first two hours, working alternately = First hour A + Second hour B = 1/4 + 1/12 = 1/3.
Total time required to complete the work = 2 * 3 = 6 days.
Answer: (B) 6 days
Question: The difference of the squares of two consecutive even integers is divisible by which of the following integers ?
(A) 3
(B) 4
(C) 6
(D) 7
(E) 9
Rationale: Let the two consecutive even integers be 2n and (2n + 2). Then,
(2n + 2)2 = (2n + 2 + 2n)(2n + 2 - 2n)
= 2(4n + 2)
= 4(2n + 1), which is divisible by 4.
ANSWER B
Answer: (B) 4
Question: There are two numbers. If 60% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?
(A) A)3/7
(B) B)5/8
(C) C)6
(D) D)6/7
(E) E)5/12
Rationale: Let the two numbers be x and y.
60/100 * x + y = 5/4y
=> 3/5 x = 1/4 y => x/y = 5/12
E)
Answer: (E) E)5/12
Question: In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 250 newborn members of the population, approximately how many would be expected to survive the first 3 months of life?
(A) 140
(B) 146
(C) 152
(D) 162
(E) 183
Rationale: The probability of survival for each of the first 3 months of life is 1-1/10=9/10, so of 250 newborn 250*9/10*9/10*9/10=~183 is expected to survive.
Answer: E.
Answer: (E) 183
Question: Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability E that Jane will be on the same committee as Albert?
(A)  12%
(B)  20%
(C)  33%
(D)  40%
(E)  50%
Rationale: Total number of ways to choose 3 member committee - 6C3=(6!/3!3!)=20
No. of ways Albert n Jane are in same committee:- (4C1 * 2)= 8
Probability E= (8/20) *100 =40%.
+1 for me.. :D
Answer: (D)  40%
Question: Insert the missing number. 2, 7, 10, 22, 18, 37, 26, 52, 34,
(A) 42
(B) 52
(C) 77
(D) 62
(E) 68
Rationale: Explanation :
There are two series here
2, 10, 18, 26, 34 ... (Increase by 8)
7, 22, 37, 52 ... (Increase by 15)
Hence, next term is 52+15 = 77
Answer : Option C
Answer: (C) 77
Question: A man can row 8 Kmph in still water. If the velocity of the current is 2 Kmph and it takes him 2 hours to row to a place and come back. How far is the place?
(A) 5.5
(B) 8.5
(C) 6.5
(D) 9.5
(E) 7.5
Rationale: Man's rate down stream = 8 + 2 = 10 kmph
Man's rate upstream = 8 - 2 = 6 kmph
Let the required distance be X km
Then X/10 + X/6 = 2
3X + 5X = 60
8X = 60
X = 7.5 km
Answer is E.
Answer: (E) 7.5
Question: Rajiv can do a piece of work in 10 days , Venky in 12 days and Ravi in 15 days. They all start the work together, but Rajiv leaves after 2 days and Venky leaves 3 days before the work is completed. In how many days is the work completed ?
(A) 7
(B) 8
(C) 98
(D) 6
(E) 5
Rationale: Explanation: Let the work be 60 units. If venky leave 3 days before the work, Last 3 days must be worked by Ravi. So the remaining days of work be x days, total days to complete the work be x + 3 days.
Now Capacities of Rajiv is 60/10 = 6, Venky is 5, Ravi is 4.
(6 + 5 + 4) 2 + (5 + 4) (x – 3) + 4 x 3 = 60.
30 + 9x – 27 + 12 = 60
9x – 15 =30
9x = 45
x = 5
So total days to complete the work = 2 + 5 = 7 days.
Answer:A
Answer: (A) 7
Question: In a flower shop there were 4 flowers in each bouquet. If the seller has doubled the number of flowers in each bouquet then the new average of flowers in each bouque is
(A) 12
(B) 3
(C) 8
(D) 9
(E) None of these
Rationale: Answer
Now required average
= old average x Multiplicand
= 4 x 2 = 8
Correct Option: C
Answer: (C) 8
Question: The 100-milliliter solution of sugar and water is 12% sugar. How much water (in milliliters) must be added to make a solution that is 8% sugar?
(A) 30
(B) 40
(C) 50
(D) 60
(E) 70
Rationale: In the original solution the amount of sugar is 0.12*100=12 ml.
Let the volume of the new solution be V.
0.08V=12 ml.
V=150 ml.
The amount of water we need to add is 150 - 100 = 50 ml.
The answer is C.
Answer: (C) 50
Question: Use distributive property to solve the problem below:
Maria bought 18 notebooks and 8 pens costing 2 dollars each.How much did Maria pay?
(A) 30 dollars
(B) 40 dollars
(C) 50 dollars
(D) 60 dollars
(E) 52 dollars
Rationale: Solution
2 × (18 + 8) = 2 × 18 + 2 × 8 = 36 + 16 = 52 dollars
Answer E
Answer: (E) 52 dollars
Question: It takes John 25 minutes to walk to the car park and 45 to drive to work. At what time should he get out of the house in order to get to work at 9:00 a.m.?
(A) 6am
(B) 7:30am
(C) 8am
(D) 5:45am
(E) 7:50am
Rationale: The time it takes John to get to work: time to walk to car park + time to drive
25 + 45 = 70 minutes = 1 hour and 10 minutes
John needs to get out of the house 1 hour and 10 minutes before 9:00 am at
9:00 - 1:10 = 7:50 a.m.
Answer- E
Answer: (E) 7:50am
Question: How many Single-digit whole numbers yield a remainder of 1 when divided by 10 and also yield a remainder of 1 when divided by 6?
(A) None
(B) One
(C) Two
(D) Three
(E) Four
Rationale: The possible number N can be written as follow:
N = Multiple of LCM(6,10) + 1st such number
N = 30x + 1
Possible values = 1
Answer : B
Answer: (B) One