in what ratio mental a at rs . 68 per kg be mixed with another metal at rs . 96 per kg so that cost of alloy ( mixture ) is rs . 72 per kg ?
"( 96 - 72 ) / ( 72 - 68 ) = 24 / 4 = 6 / 1 answer : a"
divide(divide(subtract(96, 72), subtract(96, 68)), subtract(const_1, divide(subtract(96, 72), subtract(96, 68))))