how many consecutive zeros are there at the end of 100 ! ( 100 factorial ) ?
number of zeros will be 24 reason 100 / 5 = 20 20 / 5 = 4 so the total number of 5 will be 20 + 4 = 24 answer : d
add(divide(100, add(const_4, const_1)), divide(100, multiply(add(const_4, const_1), add(const_4, const_1))))