a large field of 700 hectares is divided into two parts . the difference of the areas of the two parts is one – fifth of the average o fthe two areas . what is the area of the smaller part in hectares ?
"solution let the areas of the two parts be x and ( 700 - x ) hectares = [ x - ( 700 - x ) ] = 1 / 5 x [ x + ( 700 - x ) / 2 ] = 2 x - 700 = 70 x = 385 . answer d"
divide(subtract(700, multiply(divide(700, const_2), divide(const_1, add(const_1, const_4)))), const_2)