at an examination in which full marks were 500 . a got 10 % less than b , b got 25 % more than c and c got 20 % less than d . if a got 360 marks , what percentage of full marks was obtained by d ?
a b c d 90 100 80 100 a d 90 - - - - - 100 360 - - - - - - ? = 400 500 - - - - - - 400 100 - - - - - - - ? = > 80 % answer : c
multiply(divide(divide(360, multiply(multiply(divide(subtract(const_100, 10), const_100), divide(add(const_100, 25), const_100)), divide(subtract(const_100, 20), const_100))), 500), const_100)