in covering a distance of 30 km , abhay takes 2 hours more than sameer . if abhay doubles his speed , then he would take 1 hour less than sameer . abhay ' s speed is :
"abhay speed = x sameer speed = y ( 30 / x ) - ( 30 / y ) = 2 . . . . 1 - ( 30 / 2 x ) + ( 30 / y ) = 1 . . . - 2 solving 1 and 2 we get 6 x = 30 x = 5 answer e"
divide(subtract(30, divide(30, 2)), add(1, 2))