two pipes a and b can separately fill a cistern in 60 minutes and 120 minutes respectively . there is a third pipe in the bottom of the cistern to empty it . if all the three pipes are simultaneously opened , then the cistern is full in 60 minutes . in how much time , the third pipe alone can empty the cistern ?
"1 / 60 - ( 1 / 60 + 1 / 120 ) = - 1 / 120 third pipe can empty in 120 minutes answer : d"
inverse(subtract(add(inverse(60), inverse(120)), inverse(60)))