what will be the compound interest on a sum of rs . 25,000 after 3 years at the rate of 12 p . c . p . a . ?
"explanation : amount = rs . [ 25000 x ( 1 + 12 / 100 ) 3 ] = rs . 35123.20 c . i . = rs . ( 35123.20 - 25000 ) = rs . 10123.20 answer is c"
subtract(multiply(multiply(multiply(const_4, const_100), const_100), power(add(const_1, divide(12, const_100)), 3)), multiply(multiply(const_4, const_100), const_100))