a bowl was filled with 10 ounces of water , and 0.08 ounce of the water evaporated each day during a 50 - day period . what percent of the original amount of water evaporated during this period ?
"total amount of water evaporated each day during a 50 - day period = . 08 * 50 = . 08 * 100 / 2 = 8 / 2 = 4 percent of the original amount of water evaporated during this period = ( 4 / 10 ) * 100 % = 40 % answer c"
multiply(divide(multiply(50, 0.08), 10), const_100)