the spherical ball of lead 3 cm in diameter is melted and recast into 3 spherical balls . the diameters of two of these are 1 ½ cm and 2 cm respectively . the diameter of third ball is ?
4 / 3 π * 3 * 3 * 3 = 4 / 3 π [ ( 3 / 2 ) 3 + 23 + r 3 ] r = 1.25 d = 2.5 answer : b
multiply(power(subtract(subtract(power(divide(3, 2), const_3), power(divide(add(1, divide(1, 2)), 2), const_3)), 1), inverse(3)), const_2)