the sum of three consecutive even numbers is 36 , find the first number ?
"let the first number be n let the second number be n + 2 let the third number be n + 4 n + n + 2 + n + 4 = 36 combine like terms : 3 n + 6 = 36 3 n = 36 - 6 3 n = 30 3 n = 30 n = 10 n + 2 = 12 n + 4 = 16 the first number is 10 answer : e"
add(add(power(add(add(divide(subtract(subtract(36, const_10), const_2), const_4), const_2), const_2), const_2), power(add(add(add(divide(subtract(subtract(36, const_10), const_2), const_4), const_2), const_2), const_2), const_2)), add(power(divide(subtract(subtract(36, const_10), const_2), const_4), const_2), power(add(divide(subtract(subtract(36, const_10), const_2), const_4), const_2), const_2)))