the ages of 2 persons differ by 16 years . if 6 years ago the elder one be 3 times as old as the younger one , find the present age of younger person .
"age of the younger person = x age of the elder person = x + 16 3 ( x - 6 ) = x + 16 - 6 x = 14 answer is b"
subtract(add(divide(multiply(2, 16), subtract(6, const_1)), 6), 2)