if xy denotes x is raised to the power y , find the last two digits of 19413844 + 19714181
"1941 ^ 3844 unit digit = 1 ^ 4 = 1 10 th digit = 4 * 4 = 16 = 2 means last two digit = 61 and 1971 ^ 4181 unit digit = 1 10 th digit = 7 * 1 = 7 mean last two digit = 71 hence , 71 + 61 = 132"
subtract(subtract(add(subtract(subtract(reminder(reminder(19714181, power(const_100, const_2)), const_100), const_10), const_10), reminder(floor(divide(19413844, power(const_100, const_2))), const_100)), const_10), const_10)