the ratio , by volume , of soap to alcohol to water in a certain solution is 2 : 40 : 70 . the solution will be altered so that the ratio of soap to alcohol is doubled while the ratio of soap to water is halved . if the altered solution will contain 100 cubic centimeters of alcohol , how many cubic centimeters of water will it contain ?
"soap : alcohol initial ratio soap : alcohol : water - - > 2 : 40 : 70 initial soap : alcohol = 2 / 40 = 2 : 40 after doubled soap : alcohol = 2 * 2 / 40 = 4 : 40 initial soap : water = 2 / 70 = 2 : 70 after halved soap : water : 1 / 2 * 2 / 70 = 1 / 70 = 1 : 70 after soap : alcohol : water - - > 4 : 40 : 280 - - > 1 : 10 : 70 given alcohol 100 cubic centimeter . ratio is 10 : 100 : 700 ( 1 : 10 : 70 ) for 100 cubic centimeter of alcohol - - - 700 cubic cm water is required . answer - d"
divide(divide(divide(divide(divide(volume_rectangular_prism(100, 70, 40), const_3), const_2), const_4), const_4.0), const_4)