calculate how much time could be saved if the train would run at its usual speed , given that it ran at 3 / 4 of its own speed and got to its destination in 10 hours ?
"new speed = 3 / 4 of usual speed new time = 3 / 4 of usual time 3 / 4 of usual time = 10 hrs usual time = 10 * 3 / 4 = 7.5 hrs time saved = 10 - 7.5 = 2.5 hrs answer is b"
add(divide(reminder(subtract(multiply(10, const_60), multiply(multiply(10, divide(3, 4)), const_60)), const_60), const_100), floor(divide(subtract(multiply(10, const_60), multiply(multiply(10, divide(3, 4)), const_60)), const_60)))