if you roll a fair - sided die twice , what is the probability of getting a ( 4.4 ) double ?
total no . in two dice ( 1,1 ) , ( 2,2 ) . . . . . ( 6 , ) total number of events = 6 * 6 total events of getting same pair ( 4 , 4 ) = 6 probability = 6 / 6 * 6 = 1 / 6 = 1 / 3 ! d
divide(add(subtract(4.4, divide(multiply(const_4, const_10), const_100)), const_2), multiply(add(subtract(4.4, divide(multiply(const_4, const_10), const_100)), const_2), add(subtract(4.4, divide(multiply(const_4, const_10), const_100)), const_2)))