the product of two numbers is 4107 . if the h . c . f . of these numbers is 37 , then the greater number is : explanation :
let the numbers be 37 a and 37 b . then , 37 a x 37 b = 4107 ab = 3 . now , co - primes with product 3 are ( 1 , 3 ) . so , the required numbers are ( 37 x 1 , 37 x 3 ) i . e . , ( 37 , 111 ) . greater number = 111 . answer : option c
multiply(divide(4107, power(37, const_2)), 37)