what is the greater of the two numbers whose product is 2560 , given that the sum of the two numbers exceeds their difference by 32 ?
"let the greater and the smaller number be g and s respectively . gs = 2560 g + s exceeds g - s by 32 i . e . , g + s - ( g - s ) = 32 i . e . , 2 s = 32 = > s = 16 g = 2560 / s = 160 . answer : c"
divide(2560, multiply(power(const_2, const_4), const_2))