how many 3 digit odd numbers do not use any digit more than once
"the way i solved it is a b c ( hundreds , tens , units ) c can be 1 3 5 7 9 ( any of the 5 digits ) a can be anything except ( d or 0 ) so 8 possibilitie b can be anything execpt ( a d c ) so 7 possibilities total ways are 7 * 8 * 5 = 280 ans : e"
multiply(multiply(multiply(add(3, const_1), subtract(subtract(const_10, const_1), const_1)), subtract(subtract(const_10, const_1), const_1)), subtract(subtract(subtract(const_10, const_1), const_1), const_1))