the total circumference of two circles is 80 . if the first circle has a circumference that is exactly twice the circumference of the second circle , then what is the approximate sum of their two radii ?
"let r = radius of smaller circle . let r = radius of larger circle therefore : 2 π r + 2 π r = 80 where 2 r = r thus : 2 π r + 4 π r = 80 6 π r = 80 r = approx 4.2 π r + 2 r π = 80 3 π r = 80 r = approx 8.4 r + r = approx 10.6 answer is c"
divide(add(divide(divide(80, const_3), const_3), divide(multiply(divide(80, const_3), const_2), const_3)), const_2)