if one positive integer is greater than another positive integer by 3 , and the difference of their cubes is 63 , what is their sum ?
1 ^ 3 = 1 2 ^ 3 = 8 3 ^ 3 = 27 4 ^ 3 = 64 the two numbers are 1 and 4 . the answer is a .
add(divide(add(power(3, const_3), sqrt(add(power(power(3, const_3), const_2), power(subtract(63, power(3, const_3)), const_2)))), multiply(power(3, const_2), const_2)), subtract(divide(add(power(3, const_3), sqrt(add(power(power(3, const_3), const_2), power(subtract(63, power(3, const_3)), const_2)))), multiply(power(3, const_2), const_2)), 3))