if xy denotes x is raised to the power y , find the last two digits of 19413843 + 19614181
"1721 ^ 3856 unit digit = 1 ^ 2 = 1 10 th digit = 5 * 6 = 30 = 0 means last two digit = 1 and 1982 ^ 4181 unit digit = 1 10 th digit = 8 * 2 = 16 mean last two digit = 61 hence , 61 + 1 = 62"
subtract(subtract(add(subtract(subtract(reminder(reminder(19614181, power(const_100, const_2)), const_100), const_10), const_10), reminder(floor(divide(19413843, power(const_100, const_2))), const_100)), const_10), const_10)