two letters from the word khantkar are selected at random . what is the probability that at least one of the selected letters is a consonant ?
there are 6 consonants and 2 vowels in khantkar . probability that at least one of the selected letters is a consonant = 1 - ( probability of both vowels ) probability of both vowels = 2 c 2 / 8 c 2 = 1 / 28 so , answer is 1 - 1 / 28 = 27 / 28 answer : b
negate_prob(divide(const_1, choose(multiply(const_2, const_4), const_2)))