the lowest number which should be added to 5915 so that the sum is exactly divisible by 3 , 5 , 8 and 7 is :
"l . c . m . of 3 , 5 , 8 and 7 = 840 . on dividing 5915 by 840 , the remainder is 35 . number to be added = ( 840 - 35 ) = 805 . answer : option ' c '"
divide(5915, 5)