a train 110 m long is running with a speed of 80 km / h . in how many seconds will the train pass a man who is running at 8 km / h in the direction opposite to that in which the train is going ?
"the speed of the train relative to the man = 80 + 8 = 88 km / h . 88000 m / h * 1 h / 3600 s = ( 880 / 36 ) m / s ( 110 m ) / ( 880 / 36 m / s ) = ( 110 * 36 ) / 880 = 36 / 8 = 4.5 seconds the answer is b ."
divide(110, divide(add(80, 8), const_3_6))