in what ratio mental a at rs . 68 per kg be mixed with another metal at rs . 96 per kg so that cost of alloy ( mixture ) is rs . 76 per kg ?
"( 96 - 76 ) / ( 76 - 68 ) = 20 / 8 = 5 / 2 answer : e"
divide(divide(subtract(96, 76), subtract(96, 68)), subtract(const_1, divide(subtract(96, 76), subtract(96, 68))))