find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number .
"sol . let the number be x . then , x + 17 = 60 / x ⇔ x 2 + 17 x - 60 = 0 ⇔ ( x + 20 ) ( x - 3 ) = 0 ⇔ x = 3 . answer a"
add(const_2, gcd(60, 17))