a circle in the coordinate plane passes through points ( - 3 , - 2 ) and ( - 1 , - 4 ) . what is the smallest possible area of that circle ?
the distance between the two points is sqrt ( 8 ) radius = sqrt ( 8 ) / 2 area = pi * ( sqrt ( 8 ) / 2 ) ^ 2 e . 4 π
square_area(divide(sqrt(add(multiply(add(3, 1), add(3, 1)), multiply(add(2, 4), add(2, 4)))), const_2))