find the area of a rhombus having each side equal to 13 cm and one of whose diagonal is 24 cm .
let abcd is a rhombus with diagonals ac and bd which intersect each other at o . ac = 24 ⇒ ao = 12 let bo = x and ab = 13 cm ( given ) by pythagorean theorem c 2 = a 2 + b 2 13 2 = 12 2 + x 2 169 = 144 + x 2 x 2 = 169 – 144 x 2 = 25 x = 5 cm bo = 5 cm diagonal bd = 2 x 5 = 10 cm . area = ½ x [ product of diagonals ] = ½ x 24 x 10 area = 120 sq . cm answer is b
rhombus_area(24, multiply(sqrt(subtract(power(13, const_2), power(divide(24, const_2), const_2))), const_2))