two trains are moving in the same direction at 162 kmph and 18 kmph . the faster train crosses a man in the slower train in 33 seconds . find the length of the faster train ?
"relative speed = ( 162 - 18 ) * 5 / 18 = 8 * 5 = 40 mps . distance covered in 33 sec = 33 * 40 = 1320 m . the length of the faster train = 1320 m . answer : c"
multiply(divide(subtract(162, 18), const_3_6), 33)