how many seconds will a train 200 meters long running at the rate of 36 kmph take to pass a certain telegraph post ?
distance = length of train = 200 meters speed = 36 kmph = 36 * 5 / 18 = 10 m / s required time = 200 / 10 = 20 sec answer is b
divide(200, multiply(const_0_2778, 36))