what is the measure of the radius of the circle that circumscribes a triangle whose sides measure 9 , 40 and 41 ?
"explanatory answer 9 , 40 and 41 is pythagorean triplet . so , the triangle is right angled . key property about right triangles in a right angled triangle , the radius of the circle that circumscribes the triangle is half the hypotenuse . in the given triangle , the hypotenuse = 41 . therefore , the radius of the circle that circumscribes the triangle = 41 / 2 = 20.5 units . choice d"
divide(triangle_area_three_edges(9, 40, 41), divide(triangle_perimeter(9, 40, 41), const_2))