5 ltr of water is added with 15 ltr of a solution containing 26 % of alcohol in the water . the % of alcohol in the new mixture is ?
we have a 15 litre solution containing 26 % alcohol in water . = > quantity of alcohol in the solution = 15 ã — 26 / 100 now 5 litre of water is added to the solution . = > total quantity of the new solution = 15 + 5 = 20 percentage of alcohol in the new solution = 15 ã — 26 / 100 20 ã — 100 = 15 ã — 26 / 10020 ã — 100 = 15 ã — 1.3 / 100 = 19.5 % c
multiply(const_100, divide(multiply(divide(26, const_100), 15), add(5, 15)))