find a number such that when 15 is subtracted from 7 times the number , the result is 10 more than twice the number .
let the number be x . then , 7 x - 15 = 2 x + 10 = > 5 x = 25 = > x = 5 . hence , the required number is 5 . answer is c .
divide(add(15, 10), subtract(7, const_2))