find the smallest number of five digits exactly divisible by 32 , 40,56 and 64 .
"smallest number of five digits is 10000 . required number must be divisible by l . c . m . of 32,40 , 56,64 i . e 2240 , on dividing 10000 by 2240 , we get 1200 as remainder . therefore , required number = 10000 + ( 2240 â € “ 1200 ) = 11040 . answer is c ."
add(subtract(multiply(const_10, multiply(const_100, const_100)), const_100), 40,56)