the sum of the present age of henry and jill is 41 . what is their present ages if 7 years ago henry was twice the age of jill ?
let the age of jill 7 years ago be x , age of henry be 2 x x + 7 + 2 x + 7 = 41 x = 9 present ages will be 16 and 25 answer : a
subtract(41, divide(add(41, 7), const_3))