a precious stone weighing 35 grams worth rs . 12,250 is accidentally dropped and gets broken into two pieces having weights in the ratio of 2 : 5 . if the price varies as the square of the weight then find the loss incurred .
the price varies as the square of the weight , p = k x w 2 12250 = k x 352 k = 10 thus , p = 10 w 2 when the two pieces are in the ratio 2 : 5 ( weight wise ) then we know that their weights must be 10 g and 25 g respectively . their values should be : 10 g piece : 10 x 102 = rs . 1000 ; 25 g piece : 10 x 252 = rs . 6250 . total value of stone now , = 1000 + 6250 = rs . 7250 loss incurred = 12250 - 7250 = rs . 5000 answer : d
subtract(subtract(subtract(subtract(add(multiply(const_100, const_100), divide(divide(multiply(const_100, const_100), const_2), 2)), const_100), const_100), divide(const_100, const_2)), add(multiply(divide(subtract(subtract(subtract(add(multiply(const_100, const_100), divide(divide(multiply(const_100, const_100), const_2), 2)), const_100), const_100), divide(const_100, const_2)), power(35, const_2)), power(multiply(5, 2), const_2)), multiply(divide(subtract(subtract(subtract(add(multiply(const_100, const_100), divide(divide(multiply(const_100, const_100), const_2), 2)), const_100), const_100), divide(const_100, const_2)), power(35, const_2)), power(multiply(5, 5), const_2))))