the area of one square is x ^ 2 + 6 x + 9 and the area of another square is 4 x ^ 2 − 20 x + 25 . if the sum of the perimeters of both squares is 52 , what is the value of x ?
"the areas are ( x + 3 ) ^ 2 and ( 2 x - 5 ) ^ 2 . the lengths of the sides are x + 3 and 2 x - 5 . if we add the two perimeters : 4 ( x + 3 ) + 4 ( 2 x - 5 ) = 52 12 x = 60 x = 5 the answer is c ."
divide(subtract(52, subtract(multiply(const_4, divide(6, 2)), 20)), 6)