in a certain corporation , there are 300 male employees and 150 female employees . it is known that 50 % of the male employees have advanced degrees and 40 % of the females have advanced degrees . if one of the 450 employees is chosen at random , what is the probability this employee has an advanced degree or is female ?
"p ( female ) = 150 / 450 = 1 / 3 p ( male with advanced degree ) = 0.5 * 300 / 450 = 150 / 450 = 1 / 3 the sum of the probabilities is 2 / 3 the answer is b ."
add(divide(multiply(subtract(const_1, divide(40, multiply(50, 50))), 150), 450), divide(add(multiply(divide(50, multiply(50, 50)), 300), multiply(divide(40, multiply(50, 50)), 150)), 450))