find the compound interest accrued on an amount of rs . 14,800 at 13.5 % p . a at the end of two years . ( round off your answer to nearest integer )
ci = 14800 { [ 1 + 13.5 / 100 ] 2 - 1 } = 14800 { [ 1 + 27 / 200 ] 2 - 1 = 14800 { 2 + 27 / 200 } { 27 / 200 } = ( 74 ) [ 2 + 27 / 200 ] ( 27 ) = 1998 [ 2 + 27 / 200 ] = 3996 + 269.73 = rs . 4266 answer : d
multiply(add(multiply(multiply(add(const_3, const_4), const_2), multiply(const_100, multiply(add(const_2, const_3), const_2))), multiply(subtract(multiply(add(const_2, const_3), const_2), const_2), const_100)), subtract(power(add(const_1, divide(13.5, const_100)), const_2), const_1))