what is the largest possible value of cc if 5 c + ( d − 12 ) ^ 2 = 235 ?
to maximize c , we should minimize ( d - 12 ) ^ 2 . ( d - 12 ) ^ 2 is a square of a number , thus its smallest possible value is 0 ( for d = 12 ) . in this case we ' d have 5 c + 0 = 235 - - > c = 47 . answer : e .
divide(235, 5)