a bowl was filled with 10 ounces of water , and 0.006 ounce of the water evaporated each day during a 50 - day period . what percent of the original amount of water evaporated during this period ?
"total amount of water evaporated each day during a 50 - day period = . 006 * 50 = . 006 * 100 / 2 = . 6 / 2 = . 3 percent of the original amount of water evaporated during this period = ( . 3 / 10 ) * 100 % = 3 % answer d"
multiply(divide(multiply(50, 0.006), 10), const_100)