80 pie square inches of material of negligible thickness are required to construct a 1 / 16 scale model of a cylindrical barrel . if the diameter of the base of the barrel is 160 inches , then what is the volume of the barrel , to the nearest cubic foot ?
radius of barrel , r = 80 radius of model , r = 80 / 16 = 5 surface area of the model = 2 ∗ pi ∗ r ( r + h ) = 80 ∗ pi which gives h = 3 and h = 3 ∗ 16 = 48 so , volume of the barrel = pi ∗ r 2 ∗ h = pi ∗ ( 80 ) 2 ∗ ( 48 ) in cubic inches converting in cubic ft results : volume = pi ∗ ( 80 ) 2 ∗ ( 48 ) / ( 12 ) 3 = 178 pi cubic ft approximately answer [ c ]
floor(divide(volume_cylinder(divide(160, const_2), multiply(subtract(divide(divide(80, const_2), divide(80, 16)), divide(80, 16)), 16)), power(add(const_10, const_2), const_3)))