if log 64 = 1.8061 , then the value of log 16 will be ( approx ) ?
"log 64 = 1.8061 log 4 ^ 3 = 1.8061 log 4 = 0.6020 2 log 4 = 1.2040 log 4 ^ 2 = 1.2040 log 16 = 1.2040 ( approx ) answer a"
add(multiply(const_4, 1.8061), divide(log(const_100), log(const_10)))