find the least number which when divided by 38 and 3 leaves a remainder of 1 in each case .
"the least number which when divided by different divisors leaving the same remainder in each case = lcm ( different divisors ) + remainder left in each case . hence the required least number = lcm ( 38 , 3 ) + 1 = 115 . answer : e"
add(1, lcm(38, 3))