find the least number which when divided by 34 and 5 leaves a remainder of 4 in each case .
"the least number which when divided by different divisors leaving the same remainder in each case = lcm ( different divisors ) + remainder left in each case . hence the required least number = lcm ( 31 , 5 ) + 4 = 174 . answer : c"
add(4, lcm(34, 5))