an employer pays rs . 20 for each day a worker works and for felts rs . 3 for each day is ideal at the end of sixty days a worker gets rs . 280 . for how many days did the worker remain ideal ?
suppose a worker remained ideal for x days then he worked for 60 - x days 20 * ( 60 - x ) - 3 x = 280 1200 - 23 x = 280 23 x = 920 x = 40 answer is b .
divide(subtract(multiply(20, const_60), 280), negate(subtract(negate(3), 20)))