if 4 men can paint 60 m long wall in 3 days , then 5 men can paint 50 m long wall in
the length of wall painted by one man in one day = 60 / 4 ã — 3 = 5 m no . of days required to paint 50 m wall by 5 men = 50 / 5 ã — 5 = 2 day . b
divide(50, multiply(divide(divide(60, 3), 4), 5))