two 6 faced dice are thrown together . the probability that both show the same number on them is ?
"it all 3 numbers have to be same basically we want doublets . 11 , 22 , 33 , 44 , 55 and 66 . those are six in number . further the three dice can fall in 6 * 6 = 36 ways . hence the probability is 6 / 36 = 1 / 6 answer : a"
multiply(multiply(multiply(divide(const_1, 6), divide(const_1, 6)), divide(const_1, 6)), divide(const_1, 6))