there are 500 employees in a room . 99 % are managers . how many managers must leave the room to bring down the percentage of managers to 98 % ?
"there are 495 managers and 5 others . the 5 others would compose 2 % of the total number of people if there were 250 people in the room . thus 250 managers must leave . the answer is c ."
divide(subtract(multiply(500, divide(99, const_100)), multiply(500, divide(98, const_100))), subtract(const_1, divide(98, const_100)))