if the average ( arithmetic mean ) of 7 consecutive integers is 20 , then the product of the greatest and least integer is
n = smallest number n + 6 = largest number ( n + n + 6 ) / 2 = 20 = > ( 2 n + 6 ) / 2 = 20 = > n + 3 = 20 = > n = 17 so product of n and n + 6 = ( 17 ) ( 23 ) = 391 answer - d
multiply(divide(subtract(multiply(7, 20), multiply(const_3, 7)), 7), add(subtract(7, const_1), divide(subtract(multiply(7, 20), multiply(const_3, 7)), 7)))