two numbers are respectively 40 % and 30 % more than a third number . the second number expressed in terms of percentage of the first is ?
"here , x = 40 and y = 30 ; therefore second number = [ [ ( 100 + y ) / ( 100 + x ) ] x 100 ] % of first number = [ [ ( 100 + 30 ) / ( 100 + 40 ) ] x 100 ] % of first number = 92.8 % of the first answer : b"
subtract(const_100, multiply(divide(add(40, const_100), add(30, const_100)), const_100))