in what ratio mental a at rs . 68 per kg be mixed with another metal at rs . 96 per kg so that cost of alloy ( mixture ) is rs . 75 per kg ?
"( 96 - 75 ) / ( 75 - 68 ) = 21 / 7 = 3 / 1 answer : b"
divide(divide(subtract(96, 75), subtract(96, 68)), subtract(const_1, divide(subtract(96, 75), subtract(96, 68))))