at a small company , 64 percent of the employees are women , and 60 percent of the employees are married . if 2 / 3 of the men are single , what fraction of the women are married ?
"lets take total employees are 100 . given that , total women = 64 and total married = 60 . total men = 100 - 64 = 36 and single men = 2 / 3 * 36 = 24 . married men = total men - single men = 36 - 24 = 12 . married women = total married - married men = 60 - 12 = 48 . fraction of women are married = married women / total women = 48 / 64 = 3 / 4 . ans b"
divide(subtract(divide(60, const_100), multiply(subtract(const_1, divide(64, const_100)), subtract(const_1, divide(2, 3)))), divide(64, const_100))