the base of a right triangle is 8 and hypotenuse is 10 . its area is ?
explanation : h 2 = ( 10 ) 2 - ( 8 ) 2 - ( 6 ) 2 - > h = 6 1 / 2 * 8 * 6 = 24 answer is d
divide(multiply(sqrt(subtract(multiply(10, 10), multiply(8, 8))), 8), const_2)