what is the smallest no . which must be added to 25268 so as to obtain a sum which is divisible by 11 ?
"for divisibility by 11 , the difference of sums of digits at even and odd places must be either zero or divisible by 11 . for 25268 , difference = ( 2 + 2 + 8 ) - ( 5 + 6 ) = 12 - 11 = 1 . the units digit is at odd place . so we add 10 to the number = > 25268 + 10 = 25278 now , ( 2 + 2 + 8 ) - ( 5 + 7 ) = 12 - 12 = 0 = > 25268 is also divisible by 11 b"
divide(multiply(25268, 11), 25268)