the average mark obtained by 22 candidates in an examination is 48 . the average of the first 10 is 55 while the last 11 is 40 . the marks obtained by the 11 th candidate is ?
it is clear that 22 x 48 = 10 x 55 + k + 11 x 40 ⇒ ⇒ k = 66 answer : e
subtract(multiply(22, 48), add(multiply(10, 55), multiply(11, 40)))