in what ratio mental a at rs . 68 per kg be mixed with another metal at rs . 96 per kg so that cost of alloy ( mixture ) is rs . 78 per kg ?
"( 96 - 78 ) / ( 78 - 68 ) = 18 / 10 = 9 / 5 answer : d"
divide(divide(subtract(96, 78), subtract(96, 68)), subtract(const_1, divide(subtract(96, 78), subtract(96, 68))))