two students appeared at an examination . one of them secured 9 marks more than the other and his marks was 56 % of the sum of their marks . the marks obtained by them are :
let their marks be ( x + 9 ) and x . then x + 9 = 56 / 100 ( x + 9 + x ) 3 x = 99 x = 33 their marks 42 and 33 answer c
add(divide(subtract(multiply(9, const_100), multiply(56, 9)), subtract(multiply(56, const_2), const_100)), 9)