a contractor undertook to do a piece of work in 10 days . he employed certain number of laboures but 5 of them were absent from the very first day and the rest could finish the work in only 13 days . find the number of men originally employed ?
"let the number of men originally employed be x . 10 x = 13 ( x â € “ 5 ) or x = 21.6 answer a"
divide(multiply(13, 5), subtract(13, 10))