a man ' s speed with the current is 20 kmph and speed of the current is 3 kmph . the man ' s speed against the current will be
"explanation : if you solved this question yourself , then trust me you have a all very clear with the basics of this chapter . if not then lets solve this together . speed with current is 20 , speed of the man + it is speed of the current speed in still water = 20 - 3 = 17 now speed against the current will be speed of the man - speed of the current = 17 - 3 = 14 kmph option c"
subtract(subtract(20, 3), 3)