the average of 50 numbers id 62 . if two numbers , namely 45 and 55 are discarded , the average of the remaining numbers is :
"explanation : total of 50 numbers = ( 50 × 62 ) = 3100 total of 48 numbers = ( 3100 - ( 45 + 55 ) ] = 3000 required average = 3000 / 48 = 62.5 answer : e"
divide(subtract(multiply(50, 62), add(45, 55)), subtract(50, const_2))