find the area of a rhombus whose side is 25 cm and one of the diagonals is 30 cm ?
consider the rhombus abcd . let the diagonals intersect at e . since diagonals bisect at right angles in a rhombus . be 2 + ae 2 = ab 2 252 = 152 + ae 2 ae = √ ( 625 - 225 ) = √ 400 = 20 , ac = 20 + 20 = 40 cm . area of a rhombus = 1 / 2 * d 1 d 2 = 1 / 2 * 40 * 30 = 600 sq . cm . answer : a
rhombus_area(multiply(multiply(const_2, const_10), const_2), 30)