solution p is 20 percent lemonade and 80 percent carbonated water by volume ; solution q is 45 percent lemonade and 55 percent carbonated water by volume . if a mixture of pq contains 60 percent carbonated water , what percent of the volume of the mixture is p ?
"60 % is 20 % - points below 80 % and 5 % - points above 55 % . so the ratio of solution p to solution q is 1 : 4 . mixture p is 1 / 5 = 20 % of the volume of mixture pq . the answer is a ."
multiply(divide(subtract(divide(60, const_100), divide(55, const_100)), add(subtract(divide(60, const_100), divide(55, const_100)), subtract(divide(80, const_100), divide(60, const_100)))), const_100)