two numbers are less than third number by 20 % and 37 % respectively . how much percent is the second number less than by the first
"let the third number is x . then first number = ( 100 - 20 ) % of x = 80 % of x = 80 x / 100 second number is ( 63 x / 100 ) difference = 80 x / 100 - 63 x / 100 = 17 x / 100 so required percentage is , difference is what percent of first number ( 17 x / 100 * 100 / 80 x * 100 ) % = 5 % answer : a"
subtract(multiply(divide(subtract(37, 20), subtract(const_100, 20)), const_100), const_10)