find a number such that when 15 is subtracted from 7 times the number , the results is more than twice the number ?
solution let the number be x . = then , 7 x - 15 = 2 x + 10 = 5 x = 25 ‹ = › x = 5 . hence the required number is 5 . answer d
divide(add(15, const_10), subtract(7, const_2))