51 + 52 + 53 + . . . . . . . . . + 100 ) is equal to
"51 + 52 + 53 + . . . . . . . . . . . + 100 = ( 1 + 2 + 3 + . . . . + 100 ) - ( ! + 2 + 3 + . . . . . . + 50 ) = = ( 5050 - 1275 ) = 3775 answer ; a"
divide(multiply(100, add(100, 51)), 52)