find the simple interest on $ 10000 at 9 % per annum for 12 months ?
p = $ 10000 r = 9 % t = 12 / 12 years = 1 year s . i . = p * r * t / 100 = 10000 * 9 * 1 / 100 = $ 900 answer is e
multiply(10000, divide(9, const_100))