a is twice as good a workman as b and together they finish a piece in 18 days . in how many days will a alone finish the work ?
"sol . ( a ’ s 1 day ’ s work ) : ) ( b ’ s 1 days work ) = 2 : 1 . ( a + b ) ' s 1 day ' s work = 1 / 18 divide 1 / 18 in the ratio 2 : 1 . : . a ’ s 1 day ' s work = ( 1 / 18 * 2 / 3 ) = 1 / 27 hence , a alone can finish the work in 27 days . ans : e"
multiply(add(const_1, const_2), 18)