the sum of the ages of 4 children born at the intervals of 4 years each is 48 years . what is the age of the youngest child ?
"let the ages of the children be x , ( x + 4 ) , ( x + 4 ) and ( x + 12 ) years . then , x + ( x + 4 ) + ( x + 8 ) + ( x + 12 ) = 48 4 x = 24 = > x = 6 . age of youngest child = x = 6 years . answer : c"
divide(subtract(divide(48, divide(4, 4)), multiply(subtract(4, const_1), 4)), 4)