a certain basketball team that has played 2 / 3 of its games has a record of 13 wins and 7 losses . what is the greatest number of the remaining games that the team can lose and still win at least 3 / 4 of all of its games ?
13 wins , 7 losses - total 20 games played . the team has played 2 / 3 rd of all games so total number of games = 30 3 / 4 th of 30 is 22.5 so the team must win 23 games and can afford to lose at most 7 total games . it has already lost 7 games so it can lose another 0 at most . answer ( a )
subtract(multiply(divide(3, 2), add(13, 7)), add(floor(multiply(divide(3, 4), multiply(divide(3, 2), add(13, 7)))), const_1))