calculate how much time could be saved if the train would run at its usual speed , given that it ran at 6 / 8 of its own speed and got to its destination in 11 hours ?
new speed = 6 / 8 of usual speed new time = 6 / 8 of usual time 6 / 8 of usual time = 10 hrs usual time = 10 * 6 / 8 = 7.5 hrs time saved = 10 - 7.5 = 2.5 hrs answer is a
add(divide(reminder(subtract(multiply(11, const_60), multiply(multiply(11, divide(6, 8)), const_60)), const_60), const_100), floor(divide(subtract(multiply(11, const_60), multiply(multiply(11, divide(6, 8)), const_60)), const_60)))