s is a set of 45 consecutive multiples of 5 . if the smallest number in s is 55 , then the greatest number in s is
"last term = first term + ( total no . of terms - 1 ) consecutive difference s is a set of 45 consecutive multiples of 5 . if the smallest number in s is 55 , then the greatest number in s is first term = 55 ; total terms = 45 ; difference = 5 55 + ( 44 ) 5 = 275 ans b"
add(55, multiply(subtract(45, const_1), 5))