stacy and heather are 15 miles apart and walk towards each other along the same route . stacy walks at constant rate that is 1 mile per hour fast than heather ' s constant rate of 5 miles / hour . if heather starts her journey 24 minutes after stacy , how far from the original destination has heather walked when the two meet ? .
"ss - stacy ' s speed = 6 m / hr sh - heather ' s speed = 5 m / hr in 24 minutes stacy will cover = ( 24 / 60 ) * 6 = 2.4 miles now since both are walking in opposite directions , add their speeds - 6 + 5 = 11 m / hr and distance to cover is 15 - 2.4 = 12.6 time taken = distance / speed = 12.6 / 11 = 1.145 hrs heather will cover = 5 * 1.145 = 5.72 miles . answer b"
multiply(divide(subtract(15, multiply(24, divide(add(1, 5), const_60))), add(5, add(1, 5))), 5)