the perimeter of a rhombus is 120 feet and one of its diagonal has a length of 40 feet . find the area of the rhombus .
a perimeter of 120 when divided by 4 gives the side of the rhombus 30 feet . the length of the side oc of the right triangle is equal to half the diagonal : 20 feet . let us now consider the right triangle boc and apply pythagora ' s theorem to find the length of side bo . 30 ^ 2 = bo ^ 2 + 20 ^ 2 bo = 10 sqrt ( 5 ) feet we now calculate the area of the right triangle boc and multiply it by 4 to obtain the area of the rhombus . area = 4 ( 1 / 2 ) bo * oc = 4 ( 1 / 2 ) 10 sqrt ( 5 ) * 20 = 400 sqrt ( 5 ) ft . sq answer is b
rhombus_area(multiply(const_2, sqrt(subtract(power(divide(120, const_4), const_2), power(divide(40, const_2), const_2)))), 40)