the average of 6 number is 3.95 . the average of two of them is 3.8 , while the average of the other two is 3.85 . what is the average of the remaining two number ?
solution : sum of the remaining two numbers = ( 3.95 × 6 ) - [ ( 3.8 × 2 ) + ( 3.85 × 2 ) ] = 23.70 - ( 7.6 + 7.7 ) = 23.70 - 15.3 = 8.4 . ∴ required average = 8.4 / 2 = 4.2 answer b
divide(subtract(multiply(3.95, 6), add(multiply(3.8, const_2), multiply(3.85, const_2))), const_2)