two dice are thrown simultaneously . what is the probability of getting two numbers whose product is not an even ?
total number of cases = 6 * 6 = 36 favourable cases = [ ( 1,3 ) , ( 1,5 ) , ( 1,1 ) , ( 3,1 ) , ( 3,3 ) , ( 3,5 ) , ( 5,1 ) , ( 5,3 ) , ( 5,5 ) ] = 9 so probability = 9 / 36 = 1 / 4 answer is b
multiply(divide(const_3, add(const_3, const_3)), divide(const_3, add(const_3, const_3)))