if the diagonals of a rhombus are 24 cm and 10 cm , what will be its perimeter
explanation : let the diagonals be pr and sq such that pr = 24 cm and sq = 10 cm po = or = 24 / 2 = 12 cm so = oq = 10 / 2 = 5 cm pq = qr = rs = sp = √ ( 122 + 52 ) = √ ( 144 + 25 ) = √ 169 = √ 13 cm perimeter = 4 × 13 = 52 cm answer : option d
rhombus_perimeter(sqrt(add(power(divide(24, const_2), const_2), power(divide(10, const_2), const_2))))