a meeting has to be conducted with 5 managers . find the number of ways in which the managers may be selected from among 8 managers , if there are 2 managers who refuse to attend the meeting together .
"the total number of ways to choose 5 managers is 8 c 5 = 56 we need to subtract the number of groups which include the two managers , which is 6 c 3 = 20 . 56 - 20 = 36 the answer is a ."
subtract(choose(8, 5), choose(subtract(8, 2), 2))