by approximately what percent is x greater than 1 / 3 if ( 2 / 3 ) ( x ) = 1 ?
"what percent is x greater than 1 / 3 if ( 2 / 3 ) ( x ) = 1 ? = > x = 3 / 2 % change = [ ( 3 / 2 - 1 / 3 ) / ( 1 / 3 ) ] * 100 = 350 ans d , 350 %"
multiply(divide(subtract(3, divide(1, 3)), divide(1, 3)), const_100)