what will be the remainder when ( 67 ^ 67 ) + 67 is divided by 68 ?
"x ^ n + 1 will be divisible by x + 1 only when n is odd 67 ^ 67 + 1 will be divisible by 67 + 1 ( 67 ^ 67 + 1 ) + 66 , when divided by 68 will give 66 as remainder answer is c"
power(const_2.0, const_2)