victor gets 92 % marks in examinations . if these are 368 marks , find the maximum marks .
"let the maximum marks be m then 92 % of m = 368 ⇒ 92 / 100 × m = 368 ⇒ m = ( 368 × 100 ) / 92 ⇒ m = 36800 / 92 ⇒ m = 400 therefore , maximum marks in the examinations are 400 . answer : c"
divide(368, divide(92, const_100))