find the area of right angled triangle whose hypotenuse is 15 cm and one of the sides is 12 cm .
ab ² = ac ² - bc ² = 15 ² - 12 ² = 225 - 144 = 81 therefore , ab = 9 therefore , area of the triangle = ¹ / ₂ × base × height = ¹ / ₂ × 12 × 9 = 54 cm ² answer : c
divide(multiply(sqrt(subtract(power(15, const_2), power(12, const_2))), 12), const_2)