a sum was put at simple interest at a certain rate for 3 years had it been put at 3 % higher rate , it would have fetched 81 more . find the sum .
"difference in s . i . = p × t / 100 ( r 1 − r 2 ) ⇒ 81 = p × 3 x 3 / 100 ( ∵ r 1 - r 2 = 2 ) ⇒ p = 81 × 100 / 3 x 3 = 900 answer e"
divide(81, multiply(divide(3, const_100), 3))