micheal and adam can do together a piece of work in 20 days . after they have worked together for 11 days micheal stops and adam completes the remaining work in 10 days . in how many days micheal complete the work separately .
rate of both = 1 / 20 together they do = 1 / 20 * 11 = 11 / 20 left work = 1 - 11 / 20 = 9 / 20 adam completes 9 / 20 work in 10 day so he took 10 * 20 / 9 = 200 / 9 days to complete the left work alone . thus the rate of adam is 9 / 200 rate of micheal = 1 / 20 - 9 / 200 = 1 / 200 thus micheal takes 200 days to complete the whole work . ans . e .
inverse(subtract(inverse(20), inverse(multiply(inverse(subtract(const_1, multiply(inverse(20), 11))), 10))))