the sum of 3 consecutive multiples of 3 is 117 . what is the largest number ?
let the numbers be 3 x , 3 x + 3 and 3 x + 6 . then , 3 x + ( 3 x + 3 ) + ( 3 x + 6 ) = 117 9 x = 108 x = 12 largest number = 3 x + 6 = 42 answer : d
add(divide(117, 3), 3)