mike needs 30 % to pass . if he scored 212 marks and falls short by 28 marks , what was the maximum marks he could have got ?
"if mike had scored 28 marks more , he could have scored 30 % therefore , mike required 212 + 28 = 240 marks let the maximum marks be m . then 30 % of m = 240 ( 30 / 100 ) × m = 240 m = ( 240 × 100 ) / 30 m = 24000 / 30 m = 800 answer : c"
divide(add(212, 28), divide(30, const_100))