what is the sum of all possible 3 - digit numbers that can be constructed using the digits 1 , 3 , and 4 if each digit can be used only once in each number ?
"there are 6 possible arrangements of the three numbers . then each number will be in the hundreds , tens , and ones place two times each . the sum is 2 ( 111 ) + 2 ( 333 ) + 2 ( 444 ) = 1776 the answer is d ."
multiply(add(add(multiply(add(add(4, 3), 1), const_100), multiply(add(add(const_4.0, 3), 1), const_10)), add(add(4, 3), 1)), 3)