two numbers are respectively 20 % and 50 % more than a third number . the ratio of the two numbers is :
"third no is x first no - 120 % of x = 6 x / 5 second no = 150 x / 100 = 3 x / 2 ration of first nos = 6 x / 5 : 3 x / 2 = 12 x : 15 x = 4 : 5 answer b"
subtract(const_100, multiply(divide(add(20, const_100), add(50, const_100)), const_100))