two numbers are respectively 17 % and 30 % more than a third number . the percentage that is first of the second is ?
"i ii iii 117 130 100 130 - - - - - - - - - - 117 100 - - - - - - - - - - - ? = > 90 % answer : e"
subtract(const_100, multiply(divide(add(17, const_100), add(30, const_100)), const_100))