what will be the compound interest on a sum of rs . 25,000 after 3 years at the rate of 12 p . c . p . a ?
"= rs . ( 25000 x ( 1 + 12 / 100 ) ³ = rs . ( 25000 x 28 / 25 x 28 / 25 x 28 / 25 ) = rs . 35123.20 . c . i = rs ( 35123.20 - 25000 ) = rs . 10123.20 answer : b"
subtract(multiply(multiply(multiply(const_4, const_100), const_100), power(add(const_1, divide(12, const_100)), 3)), multiply(multiply(const_4, const_100), const_100))