a ladder 25 m long reaches a window of building 20 m above the ground . then the distance of the foot of the ladder from the building is ?
let it forms a right angled triangle and follow c ^ 2 = a ^ 2 + b ^ 2 then 25 ^ 2 = 20 ^ 2 + b ^ 2 b ^ 2 = 625 - 400 b = 15 answer : d
sqrt(subtract(power(25, const_2), power(20, const_2)))