two numbers are respectively 71 % and 80 % more than a third number . the percentage that is first of the second is ?
"i ii iii 171 180 100 180 - - - - - - - - - - 171 100 - - - - - - - - - - - ? = > 5 % answer : b"
subtract(const_100, multiply(divide(add(71, const_100), add(80, const_100)), const_100))