a is twice as good as workman as b and together they finish a piece of work in 18 days . in how many days will b alone finish the work .
explanation : as per question , a do twice the work as done by b . so a : b = 2 : 1 also ( a + b ) one day work = 1 / 18 to get days in which b will finish the work , lets calculate work done by b in 1 day = = ( 118 ∗ 13 ) = 154 [ please note we multiplied by 1 / 3 as per b share and total of ra ɵ o is 1 / 3 ] so b will finish the work in 54 days answer : b
multiply(18, const_3)