the sum of a number and the number preceding it is 33 . by how much is two less than 6 times the number ?
two numbers must be 16 and 17 16 + 17 = 33 required number is 17 six times of this number = 6 * 17 = 102 two less than 102 = 102 - 2 = 100 answer : d
subtract(multiply(subtract(33, multiply(const_4, const_4)), 6), const_2)