the smallest 5 digit number exactly divisible by 41 is ?
"the smallest 5 - digit number = 10000 . 41 ) 10000 ( 243 82 - - - 180 164 - - - - 160 123 - - - 37 - - - required number = 10000 + ( 41 - 37 ) = 10004 . option b"
add(multiply(const_1000, const_100), subtract(41, reminder(multiply(const_1000, const_100), 41)))