square p is inscribed in circle q . if the perimeter of p is 40 , what is the circumference of q ?
square forms two right angled triangles . any time we have a right angle triangle inside a circle , the hypotenuse is the diameter . hypotenuse here = diagonal of the square = 10 sqrt ( 2 ) = diameter = > radius = 5 sqrt ( 2 ) circumference of the circle = 2 pi r = 10 pi sqrt ( 2 ) answer is b .
multiply(multiply(const_2, const_pi), divide(sqrt(add(power(divide(40, const_4), const_2), power(divide(40, const_4), const_2))), const_2))