a car that moves at an average speed of 60 kmph , reaches its destination on time . when its average speed becomes 50 kmph , then it reaches its destination 45 minutes late . find the length of journey .
sol . difference between timings = 45 min = 3 / 4 hr . let the length of journey be x km . then , x / 50 - x / 60 = 1 / 4 â ‡ ” 6 x - 5 x = 225 â ‡ ” x = 225 km . answer b
multiply(divide(multiply(50, divide(45, const_60)), subtract(60, 50)), 60)