the sum of three consecutive integers is 102 . find the lowest of the three ?
"explanation : three consecutive numbers can be taken as ( p - 1 ) , p , ( p + 1 ) . so , ( p - 1 ) + p + ( p + 1 ) = 102 3 p = 102 = > p = 34 . the lowest of the three = ( p - 1 ) = 34 - 1 = 33 . answer b"
add(add(power(add(add(divide(subtract(subtract(102, const_10), const_2), const_4), const_2), const_2), const_2), power(add(add(add(divide(subtract(subtract(102, const_10), const_2), const_4), const_2), const_2), const_2), const_2)), add(power(divide(subtract(subtract(102, const_10), const_2), const_4), const_2), power(add(divide(subtract(subtract(102, const_10), const_2), const_4), const_2), const_2)))