three coins are tossed . find the probability of at least 1 head and 1 tail ?
"n ( s ) = 2 ^ 3 = 8 . . . . ( 3 coins tossed ) let e is the event of getting at least 1 head and 1 tail n ( e ) = tth , htt , tht , hht , hth , thh = 6 p ( e ) = n ( e ) / n ( s ) = 6 / 8 = 3 / 4 ans - c"
multiply(const_4, multiply(divide(const_1, 1), divide(const_1, 1)))