a sum was put at simple interest at a certain rate for 3 years . had it been put at 2 % higher rate , it would have fetched rs . 360 more . find the sum .
"let sum = p and original rate = r . then , [ ( p * ( r + 2 ) * 3 ) / 100 ] – [ ( p * r * 3 ) / 100 ] = 360 . = 3 pr + 6 p - 3 pr = 36000  6 p = 36000  p = 6000 hence , sum = rs . 6000 . answer is b ."
divide(360, multiply(divide(2, const_100), 3))