the diagonal of a square is twice the side of equilateral triangle then the ratio of area of the triangle to the area of square is ?
let the side of equilateral triangle = 1 unit . we know that area of an equilateral triangle = 3 – √ 4 a 234 a 2 as side = 1 unit area of the equilateral triangle = 3 – √ 434 now diagonal of the square = 2 ( side of the equilateral triangle ) = 2 we know that area of the square = 12 d 212 d 2 where d = diagonal so area of the square = 12 ( 22 ) = 212 ( 22 ) = 2 ratio of the areas of equilateral triangle and square = 3 – √ 434 : 2 ⇒ ⇒ 3 √ 8 answer : b
divide(triangle_area_three_edges(const_1, const_1, const_1), square_area(sqrt(divide(power(const_2, const_2), add(const_1, const_1)))))