in a box carrying one dozen of oranges , one - third have become bad . if 3 oranges are taken out from the box at random , what is the probability that at least one orange out of the 3 oranges picked up is good ?
n ( s ) = 12 c 3 = 12 × 11 × 10 / 3 × 2 = 2 × 11 × 10 = 220 no . of selection of 3 oranges out of the total 12 oranges = 12 c 3 = 2 × 11 × 10 = 220 no . of selection of 3 bad oranges out of the total 4 bad oranges = 4 c 3 = 4 \ n ( e ) = no . of desired selection of oranges = 220 – 4 = 216 \ p ( e ) = n ( e ) / n ( s ) = 216 / 220 = 54 / 55 answer b
divide(subtract(divide(multiply(multiply(add(const_10, const_1), const_12), const_10), multiply(3, const_2)), const_4), divide(multiply(multiply(add(const_10, const_1), const_12), const_10), multiply(3, const_2)))