the product of three consecutive numbers is 210 . then the sum of the smallest two numbers is ?
"product of three numbers = 210 210 = 2 * 3 * 5 * 7 = 5 * 6 * 7 . so , the three numbers are 5 , 6 and 7 . and sum of smallest of these two = 5 + 6 = 11 . answer : option a"
multiply(power(const_2, 210), factorial(210))