in an examination , there were 2000 candidates , out of which 900 candidates were girls and rest were boys . if 28 % of the boys and 32 % of the girls passed , then the total percentage of failed candidates is ?
girls = 900 , boys = 1100 passed = ( 28 % of 1100 ) + ( 32 % of 900 ) = 308 + 288 = 596 failed = 2000 - 596 = 1404 failed % = [ ( 1404 / 2000 ) x 100 ] % = 70.2 % . answer : d
multiply(divide(subtract(2000, add(divide(multiply(900, 32), const_100), divide(multiply(subtract(2000, 900), 28), const_100))), 2000), const_100)