jose completes a piece of work in 10 days , raju completes the same work in 40 days . if both of them work together , then the number of days required to complete the work is
if a can complete a work in x days and b can complete the same work in y days , then , both of them together can complete the work in x y / x + y days . that is , the required no . of days = 10 × 40 / 50 = 8 days . c )
inverse(add(inverse(40), inverse(10)))