pat , kate , and mark charged a total of 135 hours to a certain project . if pat charged twice as much time to the project as kate and 1 / 3 as much time as mark , how many more hours did mark charge to the project than kate ?
75 all u do is do 2 : 1 : 6 = > 2 x + x + 6 x = 135 = > x = 15 30 : 15 : 90 90 - 15 = 75 answer c
subtract(divide(135, add(add(1, divide(1, 3)), divide(1, multiply(3, const_2)))), divide(divide(135, add(add(1, divide(1, 3)), divide(1, multiply(3, const_2)))), multiply(3, const_2)))