the sum of the ages of 5 children born at the intervals of 2 years each is 50 years . what is the age of the youngest child ?
let x = the youngest child . each of the other four children will then be x + 2 , x + 4 , x + 6 , x + 8 . we know that the sum of their ages is 50 . so , x + ( x + 2 ) + ( x + 4 ) + ( x + 6 ) + ( x + 8 ) = 50 therefore the youngest child is 6 years old answer : a
divide(subtract(divide(50, divide(5, const_2)), multiply(subtract(5, const_1), 2)), const_2)