two numbers are less than third number by 32 % and 37 % respectively . how much percent is the second number less than by the first
"let the third number is x . then first number = ( 100 - 32 ) % of x = 68 % of x second number is ( 63 x / 100 ) difference = 68 x / 100 - 63 x / 100 = x / 20 so required percentage is , difference is what percent of first number ( x / 20 * 100 / 68 x * 100 ) % = 14 % answer : e"
subtract(multiply(divide(subtract(37, 32), subtract(const_100, 32)), const_100), const_10)