two numbers are less than third number by 34 % and 37 % respectively . how much percent is the second number less than by the first
"let the third number is x . then first number = ( 100 - 34 ) % of x = 66 % of x = 66 x / 100 second number is ( 63 x / 100 ) difference = 66 x / 100 - 63 x / 100 = 3 x / 100 so required percentage is , difference is what percent of first number ( 3 x / 100 * 100 / 63 x * 100 ) % = 22 % answer : e"
subtract(multiply(divide(subtract(37, 34), subtract(const_100, 34)), const_100), const_10)