find the compound interest on $ 1200 for 3 years at 20 % p . a . if ci is component yearly ?
"a = p ( 1 + r / 100 ) ^ t = 1200 ( 1 + 20 / 100 ) ^ 3 = $ 2074 ci = $ 874 answer is c"
subtract(multiply(1200, power(add(const_1, divide(20, const_100)), 3)), 1200)