ages of two persons differ by 22 years . if 6 year ago , the elder one be 3 times as old the younger one , find their present age
"explanation : let the age of younger person is x , then elder person age is ( x + 22 ) = > 3 ( x - 6 ) = ( x + 22 - 6 ) [ 6 years before ] = > 3 x - 18 = x + 16 = > x = 17 . so other person age is x + 22 = 39 answer : option c"
subtract(divide(subtract(add(multiply(6, 6), 22), 6), subtract(6, const_1)), const_1)