the product of three consecutive numbers is 120 . then the sum of the smallest two numbers is ?
"product of three numbers = 120 120 = 2 * 2 * 5 * 6 = 4 * 5 * 6 so , the three numbers are 4,5 and 6 . and sum of smallest of these two = 4 + 5 = 9 . answer : option a"
multiply(power(const_2, 120), factorial(120))