3 men can complete a piece of work in 6 days . two days after they started the work , 3 more men joined them . how many days will they take to complete the remaining work ?
explanation : 3 man 1 day work = 1616 3 man 2 days work = 2626 remaining work = ( 1 – 2626 ) = 2 / 3 parts . 6 man together perform the work in 1 day is = 1616 + 1616 = 2626 parts 2626 parts completed in 1 day 2323 parts will b completed in 2 days answer : a
divide(multiply(subtract(const_1, divide(const_2, 6)), multiply(3, 6)), 6)