two numbers are less than a third number by 30 % and 37 % . how much percent is the second number is less than the first ?
let the third number be x first number = 70 % of x = 7 x / 10 ; second number = 63 % of x = 63 x / 100 ; difference = 7 x / 10 - 63 x / 100 = 7 x / 100 ; required percentage = 7 x / 100 * 10 / 7 x * 100 = 10 % answer is a
multiply(subtract(add(30, const_1), 30), const_10)