rhoda tosses a coin 5 times . find the probability of getting exactly 4 heads .
exactly 4 heads out of 5 would be : hhhht , hhthh , or many other combinations . therefore , no . of possible combinations are 5 ! / 4 ! * 1 ! = 5 probability = 5 / 2 ^ 5 = 5 / 32 answer : a
divide(choose(5, 4), power(const_2, 5))