the product of 3 consecutive numbers is 210 . then the sum of the smallest two numbers is ?
product of three numbers = 210 210 = 2 * 3 * 5 * 7 = 5 * 6 * 7 . so , the three numbers are 5 , 6 and 7 . and sum of smallest of these two = 5 + 6 = 11 . answer : option a
add(add(floor(power(210, const_0_33)), const_1), floor(power(210, const_0_33)))