ages of two persons differ by 18 years . if 6 year ago , the elder one be 3 times as old the younger one , find their present age
"explanation : let the age of younger person is x , then elder person age is ( x + 18 ) = > 3 ( x - 6 ) = ( x + 18 - 6 ) [ 6 years before ] = > 3 x - 18 = x + 12 = > x = 15 . so other person age is x + 18 = 33 answer : option b"
subtract(divide(subtract(add(multiply(6, 6), 18), 6), subtract(6, const_1)), const_1)