the ages of two persons differ by 16 years . 6 years ago , the elder one was 3 times as old as the younger one . what are their present ages of the elder person ?
let present age of the elder person = x and present age of the younger person = x − 16 ( x − 6 ) = 3 ( x − 16 − 6 ) x − 6 = 3 x − 66 2 x = 60 x = 60 / 2 = 30 answer : option c
add(divide(add(multiply(3, 6), subtract(16, 6)), const_2), 16)