if the sum of two positive integers is 12 and the difference of their squares is 48 , what is the product of the two integers ?
"let the 2 positive numbers x and y x + y = 12 - - 1 x ^ 2 - y ^ 2 = 48 = > ( x + y ) ( x - y ) = 48 - - 2 using equation 1 in 2 , we get = > x - y = 4 - - 3 solving equation 1 and 3 , we get x = 8 y = 4 product = 8 * 4 = 32 answer a"
multiply(divide(subtract(12, divide(48, 12)), divide(48, 12)), add(divide(subtract(12, divide(48, 12)), divide(48, 12)), divide(48, 12)))