99 ! how many zero ' s ?
99 ! = 99 / 5 = 19 = 19 / 5 = 3 so 99 ! has ( 19 + 3 = 22 zeroes ) answer : c
add(floor(divide(99, add(const_1, const_4))), floor(divide(99, power(add(const_1, const_4), const_2))))