a is thrice as good a work man as b and together they finish a piece of work in 16 days . the number of days taken by b alone to finish the work is :
"solution ( a ’ s 1 day ’ s work ) : ( b ’ s 1 day ’ s work ) = 3 : 1 . ( a + b ) ' s 1 day ’ s work = 1 / 16 divide 1 / 14 in the ratio 3 : 1 . ∴ b ’ s 1 day ’ s work = ( 1 / 16 x 1 / 4 ) = 1 / 64 hence , b alone can finish the work in 64 days . answer a"
multiply(add(const_3, const_1), divide(16, const_3))