15 51 216 1100 ? 46452
"the format of the series 15 * 3 + 6 = 51 51 * 4 + 12 = 216 216 * 5 + 20 = 1100 1100 * 6 + 30 = 6630 6630 * 7 + 42 = 46452 answer : a"
divide(multiply(add(15, divide(51, 216)), 1100), const_100)