if a # b = ab – b + b ^ 2 , then 3 # 7 =
solution - simply substitute 3 and 7 in equation in the place of a and b respectively . 3 # 7 = 3 * 7 - 7 + 7 ^ 2 = 21 - 7 + 49 = 63 . ans b
add(subtract(multiply(3, 7), 7), power(7, const_2))