there is 50 % increase in an amount in 6 years at s . i . what will be the c . i . of rs . 12,000 after 3 years at the same rate ?
"let p = rs . 100 . then , s . i . rs . 50 and t = 6 years . r = ( 100 * 50 ) / ( 100 * 6 ) = 10 % p . a . now , p = rs . 12000 , t = 3 years and r = 8.33 % p . a . c . i . = [ 12000 * { ( 1 + 8.33 / 100 ) 3 - 1 } ] = rs . 17988 answer : c"
subtract(multiply(add(multiply(const_100, const_100), multiply(multiply(const_100, divide(50, 6)), 3)), multiply(multiply(add(const_1, divide(divide(50, 6), const_100)), add(const_1, divide(divide(50, 6), const_100))), add(const_1, divide(divide(50, 6), const_100)))), add(multiply(const_100, const_100), multiply(multiply(const_100, divide(50, 6)), 3)))