whats the reminder when 54,879 , 856,985 , 421,547 , 895,689 , 874,525 , 826,547 is divided by 2
"a number ending in a 0 is divisible by 2 . given the obscene number , you should immediately be convinced that you will need to focus on a very small part of it . 54,879 , 856,985 , 421,547 , 895,689 , 874,525 , 826,547 = 54,879 , 856,985 , 421,547 , 895,689 , 874,525 , 826,540 + 7 the first number is divisible by 16 . you just have to find the remainder when you divide 5287 by 16 . that will be the remainder when you divide the original number by 2 . 7 / 16 gives remainder 1 . answer ( a )"
add(multiply(const_4, const_2), reminder(add(add(multiply(subtract(const_10, const_1), const_100), multiply(multiply(add(const_3, const_2), const_100), const_10)), multiply(add(const_12, add(const_3, const_2)), add(const_3, const_2))), 2))