if a monkey can climb 6 meter & slip down 3 meter in alternate minutes , than how much time can be taken by the monkey to climb up to a height of 60 meter .
in 1 st min it climb 6 m and in 2 nd min it slips 3 m , so it final displacement is 3 m in 2 min . now for 51 m it has taken 34 min . in 35 min it goes to 57 m . in 36 min come down to 54 m . in 37 min it goes to 60 answer : b
add(divide(subtract(60, 6), divide(3, const_2)), const_1)