victor gets 90 % marks in examinations . if these are 405 marks , find the maximum marks .
"let the maximum marks be m then 90 % of m = 405 ⇒ 90 / 100 × m = 405 ⇒ m = ( 405 × 100 ) / 90 ⇒ m = 40500 / 90 ⇒ m = 450 therefore , maximum marks in the examinations are 450 answer : d"
divide(405, divide(90, const_100))