the age of the daughter is same as the digit in the mother ' s age , but in reverse order . in thirteen years mother will be twice as old as daughter will be then . what is the difference in their current age ?
daughter ' s age = 10 x + y so mother ' s age = 10 y + x . . after 13 years , 10 x + y + 13 = 2 * ( 10 y + x + 13 ) . . . . so 13 + 19 y = 8 x . . . check for odd values of y , y = 1 satisfies the eqn with x = 4 . . . so ages are 41 and 14 and ans as found correctly by u is c . . 27
subtract(add(multiply(divide(divide(add(add(const_12, const_1), add(subtract(const_10, const_1), const_10)), const_4), const_2), const_10), const_1), add(const_10, divide(divide(add(add(const_12, const_1), add(subtract(const_10, const_1), const_10)), const_4), const_2)))