if z is a multiple of 9402 , what is the remainder when z ^ 2 is divided by 9 ?
"the sum of the digits is 9 + 4 + 2 = 15 . thus 3 is a factor of 9402 , so 3 is a factor of z . then 3 ^ 3 = 9 is a factor of z ^ 2 . then the remainder when z ^ 2 is divided by 9 is 0 . the answer is a ."
multiply(subtract(divide(power(divide(9402, const_3), 2), 9), add(add(add(multiply(multiply(const_1000, subtract(9, 2)), const_100), multiply(multiply(const_1000, subtract(9, 2)), const_10)), multiply(2, const_100)), subtract(const_100, 2))), 9)