a can finish a work in 18 days and b can do same work in half the time taken by a . then working together , what part of same work they can finish in a day
"explanation : please note in this question , we need to answer part of work for a day rather than complete work . it was worth mentioning here because many do mistake at this point in hurry to solve the question so lets solve now , a ' s 1 day work = 1 / 18 b ' s 1 day work = 1 / 9 [ because b take half time than a ] ( a + b ) ' s one day work = ( 1 / 18 + 1 / 9 ) = ( 1 + 2 / 18 ) = 1 / 6 so in one day 1 / 6 work will be done . option b"
add(divide(const_1, 18), multiply(divide(const_1, 18), const_2))