a woman invested $ 1,000 , part at 5 % and the rest at 6 % . her total investment with interest at the end of the year was $ 1,051 . how much did she invest at 5 % ?
"et x be the portion invested at 5 % and let ( 1 - x ) be the rest which is invested at 6 % the question states that the return after 1 year is ( 1051 / 1000 ) - 1 = 0.051 = 5.1 % we want to find the dollar amount invested in x using our defined variables , put together the equation and solve for x ( the percentage of 1000 invested at 5 % ) 0.05 x + 0.06 ( 1 - x ) = 0.051 ( 0.05 ) x + 0.06 - ( 0.06 ) x = 0.051 - 0.01 x = - 0.009 x = - 0.009 / - 0.01 = 9 / 10 = 90 % so x = 90 % of the 1000 which is 900 answer : d"
subtract(multiply(multiply(5, const_2), const_100), subtract(multiply(subtract(add(multiply(multiply(5, const_2), const_100), add(multiply(multiply(5, const_2), 5), const_4)), multiply(multiply(5, const_2), const_100)), const_100), multiply(5, multiply(multiply(5, const_2), const_100))))