three 6 faced dice are thrown together . the probability that no two dice show the same number on them is
"explanation : no two dice show same number would mean all the three faces should show different numbers . the first can fall in any one of the six ways . the second die can show a different number in five ways . the third should show a number that is different from the first and second . this can happen in four ways . thus 6 * 5 * 4 = 120 favourable cases . the total cases are 6 * 6 * 6 = 216 . the probability = 120 / 216 = 5 / 9 . answer : b"
multiply(multiply(multiply(divide(const_1, 6), divide(const_1, 6)), divide(const_1, 6)), divide(const_1, 6))