two unbiased coins are tossed . what is probability of getting at most one tail ?
"explanation : total 4 cases = [ hh , tt , th , ht ] favourable cases = [ hh , th , ht ] please note we need atmost one tail , not atleast one tail . so probability = 3 / 4 answer : d"
negate_prob(divide(const_1, power(const_2, const_3)))