a sum of rs . 2665 is lent into two parts so that the interest on the first part for 5 years at 3 % per annum may be equal to the interest on the second part for 3 years at 5 % per annum . find the second sum ?
"( x * 5 * 3 ) / 100 = ( ( 2665 - x ) * 3 * 5 ) / 100 15 x / 100 = 39975 / 100 - 15 x / 100 30 x = 39975 = > x = 1332.5 second sum = 2665 – 1025 = 1332.5 answer : c"
subtract(2665, divide(multiply(multiply(3, 5), 2665), add(multiply(3, 5), multiply(5, 3))))