apple costs l rupees per kilogram for first 30 kgs and q rupees per kilogram for each additional kilogram . if the price of 33 kilograms is 168 and for 36 kgs of apples is 186 then the cost of first 20 kgs of apples is
"ans : by framing equations we get 30 l + 3 q = 168 30 l + 6 q = 186 eliminate q by multiplying the first equation by 2 and subtracting second equation from the first 30 l = 150 = > l = 5 then we get l = 5 cost of 20 kgs of apples = 20 x 5 = 100 answer : d"
multiply(divide(subtract(168, multiply(subtract(33, 30), divide(subtract(186, 168), subtract(36, 33)))), 30), 20)