which of the numbers 1 , 2 , 3 , 4 , or 5 is nearest in value to the sum 2007 / 2999 + 8001 / 5998 + 2001 / 3999 = ?
the sum is a little more than ( 2 / 3 ) + ( 8 / 6 ) + ( 2 / 4 ) = 2.5 . correct answer c
add(divide(5, const_10), add(add(divide(2007, 2999), divide(8001, 5998)), divide(2001, add(2999, multiply(const_10, const_100)))))