the sum of four consecutive even numbers is 52 , find the third number ?
"let the first number be n let the second number be n + 2 let the third number be n + 4 let the third number be n + 6 n + n + 2 + n + 4 + n + 6 = 52 combine like terms : 4 n + 12 = 52 4 n + 12 = 52 4 n = 52 - 12 4 n = 40 n = 10 n + 2 = 12 n + 4 = 14 n + 6 = 16 the third number is 14 answer : a"
add(add(power(add(add(divide(subtract(subtract(52, const_10), const_2), const_4), const_2), const_2), const_2), power(add(add(add(divide(subtract(subtract(52, const_10), const_2), const_4), const_2), const_2), const_2), const_2)), add(power(divide(subtract(subtract(52, const_10), const_2), const_4), const_2), power(add(divide(subtract(subtract(52, const_10), const_2), const_4), const_2), const_2)))