difference between the length and breadth of a rectangle is 23 m . ifits perimeter is 206 m , then its area is ? ?
we have : ( l - b ) = 23 and 2 ( l + b ) = 206 or ( l + b ) = 103 . solving the two equations , we get : l = 63 and b = 40 . area = ( l x b ) = ( 63 x 40 ) m 2 = 2520 m ^ 2 c
rectangle_area(add(divide(subtract(divide(206, const_2), 23), const_2), 23), divide(subtract(divide(206, const_2), 23), const_2))