a bowl was filled with 10 ounces of water , and 0.0008 ounce of the water evaporated each day during a 50 - day period . what percent of the original amount of water evaporated during this period ?
total amount of water evaporated each day during a 50 - day period = . 0008 * 50 = . 0008 * 100 / 2 = . 08 / 2 = . 04 percent of the original amount of water evaporated during this period = ( . 04 / 10 ) * 100 % = 0.4 % answer c
multiply(divide(multiply(50, 0.0008), 10), const_100)