a rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn . the area of the lawn is 2109 sq . m . what is the width of the road ?
"area of the park = 60 * 40 = 2400 m ^ 2 given area of the lawn = 2109 m ^ 2 total area of the cross roads = 2400 - 2109 = 291 m ^ 2 assume that the width of the cross road = x = area of road 1 + road 2 - common area cross road = 60 x + 40 x - x ^ 2 total area of cross road = 60 x + 40 x - x ^ 2 = 291 m ^ 2 ( x - 97 ) ( x - 3 ) = 0 x = 3 answer d"
divide(subtract(negate(negate(add(40, 60))), sqrt(subtract(power(const_100, const_2), multiply(multiply(const_4, const_1), subtract(multiply(60, 40), 2109))))), multiply(const_2, const_1))