what is the sum of the multiples of 4 between 13 and 125 inclusive ?
"the first multiple of 12 between 13 and 125 is 16 while the last is 124 total number of terms is given by 124 = 16 + ( n - 1 ) 4 4 n - 4 = 108 n = 112 / 4 = 28 or , ( 124 - 16 ) / 4 + 1 = 28 so , we have 28 multiples of 12 between 13 and 125 sum = 14 ( 2 * 16 + ( 27 ) 4 ) = 14 ( 140 ) = 1960 answer : b"
multiply(divide(add(subtract(125, const_3), add(13, const_2)), const_2), add(divide(subtract(subtract(125, const_3), add(13, const_2)), 4), const_1))