jack , jill , and sandy each have one try to make a basket from half court . if their individual probabilities of making the basket are 1 / 6 , 1 / 7 , and 1 / 8 respectively , what is the probability that jack and sandy will make a basket but jill will miss ?
"the probability that jack and sandy will make a basket but jill will miss is 1 / 6 * 6 / 7 * 1 / 8 = 1 / 56 . the answer is e ."
multiply(multiply(divide(1, 7), divide(1, 8)), subtract(1, divide(1, 6)))