the average of 50 numbers is 38 . if two numbers 45 and 55 are discarded , the average of the remaining set of numbers is
average of the remaining set of numbers [ 50 x 38 - ( 45 + 55 ) ] / ( 50 - 2 ) = ( 1900 - 100 ) / 48 = 37.5 answer : b
divide(subtract(subtract(multiply(50, 38), 45), 55), subtract(50, const_2))