sam invested $ 1000 @ 20 % per annum for one year . if the interest is compounded half yearly , then the amount received by sam at the end of the year will be ?
"p = $ 1000 r = 20 % p . a . = 10 % t = 2 half years amount = 1000 * ( 1 + 10 / 100 ) ^ 2 = 1000 * 11 / 10 * 11 / 10 = $ 1210 answer is c"
multiply(multiply(add(divide(add(const_4, const_1), const_100), const_1), 1000), add(divide(add(const_4, const_1), const_100), const_1))