3 ltr of water is added with 11 ltr of a solution containing 42 % of alcohol in the water . the % of alcohol in the new mixture is ?
"we have a 11 litre solution containing 42 % of alcohol in the water . = > quantity of alcohol in the solution = 11 × 42 / 100 now 3 litre of water is added to the solution . = > total quantity of the new solution = 11 + 3 = 14 percentage of alcohol in the new solution = 11 × 42 / 100 14 × 100 = 11 × 4210014 × 100 = 11 × 3 / 100 = 33 % c"
multiply(const_100, divide(multiply(divide(42, const_100), 11), add(3, 11)))