in a can , there is a mixture of milk and water in the ratio 4 : 5 . if it is filled with an additional 8 litres of milk the can would be full and ratio of milk and water would become 6 : 5 . find the capacity of the can ?
"let the capacity of the can be t litres . quantity of milk in the mixture before adding milk = 4 / 9 ( t - 8 ) after adding milk , quantity of milk in the mixture = 6 / 11 t . 6 t / 11 - 8 = 4 / 9 ( t - 8 ) 10 t = 792 - 352 = > t = 44 . answer : b"
add(add(multiply(5, divide(8, subtract(multiply(divide(6, 5), 5), 4))), divide(8, subtract(multiply(divide(6, 5), 5), 4))), 8)