find the sum of all 2 digit numbers divisible by 3 .
"all 2 digit numbers divisible by 3 are 12,15 , 18,21 , … … … . . 99 this is an a . p with a = 12 , and d = 3 , let it contain n terms then , 12 + ( n – 1 ) * 3 = 99 , or n = ( 99 - 12 ) / 3 + 1 = 30 required sum = 30 / 2 * ( 12 + 99 ) = 15 * 111 = 1665 answer : b"
multiply(add(add(const_100, const_4), subtract(multiply(const_100, const_10), 3)), divide(add(divide(subtract(subtract(multiply(const_100, const_10), 3), add(const_100, const_4)), 3), const_1), const_2))