from a container having pure milk , 20 % is replaced by water and the process is repeated thrice . at the end of the third operation , the milk is
"solution let total quantity of original milk = 100 gm . milk after first operation = 80 % of 1000 ‹ = › 800 gm . milk after second operation = 80 % of 800 ‹ = › 640 gm . milk after third operation = 80 % of 640 ‹ = › 512 gm . strength of final mixtures = 51.2 % . answer c"
multiply(power(divide(subtract(const_100, 20), const_100), const_3), const_100)