a beaker contains 180 liters of alcohol . on 1 st day , 60 l of alcohol is taken out and replaced by water . 2 nd day , 60 l of mixture iss taken out and replaced by water and the process continues day after day . what will be the quantity of alcohol in beaker after 3 days
use the formula , final alcohol = initial alcohol × ( 1 − replacementquantityfinalvolume ) n × ( 1 − replacementquantityfinalvolume ) n final alcohol = 180 ( 1 − 60180 ) 3180 ( 1 − 60180 ) 3 = 180 × ( 23 ) 3 = 53.3 ans : a
multiply(180, power(subtract(1, divide(60, 180)), 3))