the amount of time that three people worked on a special project was in the ratio of 1 to 2 to 3 . if the project took 120 hours , how many more hours did the hardest working person work than the person who worked the least ?
"let the persons be a , b , c . hours worked : a = 1 * 120 / 6 = 20 hours b = 2 * 120 / 6 = 40 hours c = 3 * 120 / 6 = 60 hours c is the hardest worker and a worked for the least number of hours . so the difference is 60 - 20 = 40 hours . answer : b"
subtract(multiply(divide(120, add(add(1, 2), 3)), 3), multiply(divide(120, add(add(1, 2), 3)), 1))