in an examination , a student scores 5 marks for every correct answer and loses 2 marks for every wrong answer . if he attempts all 100 questions and secures 290 marks , the number of questions he attempts correctly , is :
"let the number of correct answers be x . number of incorrect answers = ( 100 â € “ x ) . 5 x â € “ 2 ( 100 â € “ x ) = 290 or 7 x = 490 or x = 70 . answer : c"
divide(add(290, 100), add(5, 2))