there are 300 employees in a room . 99 % are managers . how many managers must leave the room to bring down the percentage of managers to 98 % ?
there are 297 managers and 3 others . the 3 others would compose 2 % of the total number of people if there were 150 people in the room . thus 150 managers must leave . the answer is c .
divide(subtract(multiply(300, divide(99, const_100)), multiply(300, divide(98, const_100))), subtract(const_1, divide(98, const_100)))