find the smallest number which when divided by 12 and 15 leaves respective remainders of 8 and 11 .
"let ' n ' is the smallest number which divided by 12 and 15 leaves respective remainders of 8 and 11 . required number = ( lcm of 12 and 15 ) - ( common difference of divisors and remainders ) = ( 60 ) - ( 4 ) = 56 . answer : e"
subtract(multiply(12, 15), add(const_10, const_1))