if x # y is defined to equal x ^ 2 / y for all x and y , then ( - 1 # 3 ) # 3 =
"( - 1 ) ^ 2 / 3 = 1 / 3 ( 1 / 3 ) ^ 2 / 3 = 1 / 27 so c is my answer"
divide(power(divide(power(negate(1), 2), 2), 2), negate(3))