the ratio , by volume , of soap to alcohol to water in a certain solution is 4 : 40 : 90 . the solution will be altered so that the ratio of soap to alcohol is doubled while the ratio of soap to water is halved . if the altered solution will contain 200 cubic centimeters of alcohol , how many cubic centimeters of water will it contain ?
soap : alcohol initial ratio soap : alcohol : water - - > 4 : 40 : 90 initial soap : alcohol = 4 / 40 = 4 : 40 after doubled soap : alcohol = 2 * 4 / 40 = 8 : 40 initial soap : water = 4 / 90 = 4 : 90 after halved soap : water : 1 / 2 * 4 / 90 = 2 / 90 = 2 : 90 after soap : alcohol : water - - > 8 : 40 : 360 - - > 1 : 5 : 45 given alcohol 200 cubic centimeter . ratio is 40 : 200 : 1800 ( 1 : 5 : 45 ) for 200 cubic centimeter of alcohol - - - 1800 cubic cm water is required . answer - e
divide(divide(divide(divide(divide(volume_rectangular_prism(200, 90, 40), const_3), const_2), const_4), 4), const_4)