p has $ 35 more than what q and r together would have had if both b and c had 1 / 7 of what p has . how much does p have ?
"p = ( 2 / 7 ) * p + 35 ( 5 / 7 ) * p = 35 p = 49 the answer is c ."
divide(35, subtract(1, multiply(divide(1, 7), const_2)))