75 boys can complete a work in 36 days . how many men need to complete twice the work in 20 days
one man can complete the work in 36 * 75 = 2700 days = one time work to complete the work twice it will be completed in let m be the no . of worker assign for this therefore the eqn becomes m * 20 = 2 * 2700 m = 270 workers answer : c
divide(multiply(75, multiply(36, const_2)), 20)