a thief steals a car at 2.30 pm and drives it at 60 kmph . the theft is discovered at 3 pm and the owner sets off in another car at 75 kmph when will he overtake the thief
let the thief is overtaken x hrs after 2.30 pm distance covered by the thief in x hrs = distance covered by the owner in x - 1 / 2 hr 60 x = 75 ( x - ½ ) x = 5 / 2 hr thief is overtaken at 2.30 pm + 2 ½ hr = 5 pm answer is d .
add(3, divide(divide(60, const_2), subtract(75, 60)))