a rectangular paper , when folded into two congruent parts had a perimeter of 34 cm for each part folded along one set of sides and the same is 38 cm when folded along the other set of sides . what is the area of the paper ?
solution when folded along breadth , we have : 2 ( l / 2 + b ) = 34 or l + 2 b = 34 when folded along length , we have : 2 ( l / 2 + b ) = 38 or 2 l + b = 38 solving ( i ) and ( ii ) , we get : l = 14 and b = 10 . ∴ area of the paper = ( 1410 ) cm 2 = 140 cm 2 answer a
multiply(divide(subtract(multiply(38, const_2), 34), const_3), subtract(38, multiply(divide(subtract(multiply(38, const_2), 34), const_3), const_2)))