a passenger train takes two hours less for a journey of 300 km if its speed is increased by 5 kmph from its normal speed . the normal speed is
let normal speed = x increased speed = x + 5 initial = > x = 300 / t 1 = > t 1 = 300 / x after = > ( x + 5 ) = 300 / ( t 1 - 2 ) = > ( x + 5 ) = 300 / [ ( 300 / x ) - 2 ] = > x = 25 kmph answer : c
multiply(5, 5)