the sum of the present age of henry and jill is 40 . what is their present ages if 8 years ago henry was twice the age of jill ?
"let the age of jill 8 years ago be x , age of henry be 2 x x + 8 + 2 x + 8 = 40 x = 8 present ages will be 16 and 24 answer : b"
subtract(40, divide(add(40, 8), const_3))