in how many no . between 100 and 1000 exactly one of the digits is 3 ?
"3 scenarios possible 3 xy = 1 * 9 * 9 = 81 x 3 y ( with x ≠ ≠ 3 or 0 ) = 8 * 1 * 9 = 72 y 3 x ( with y ≠ ≠ 3 or 0 ) = 8 * 1 * 9 = 72 total cases possible = 144 + 81 = 225 d is the correct answer"
divide(divide(1000, 100), 3)