10 men and 15 women finish a work in 6 days . one man alone finishes that work in 100 days . in how many days will a woman finish the work ?
15 women ' s work of a day = 1 ⁄ 6 - 1 ⁄ 10 ⇒ 1 ⁄ 15 part ∴ for 1 whole part a woman will take = 15 × 15 = 225 days . answer d
inverse(divide(subtract(divide(const_1, 6), multiply(10, divide(const_1, 100))), 15))