square a is inscribed in circle b . if the perimeter of a is 32 , what is the circumference of b ?
square forms two right angled triangles . any time we have a right angle triangle inside a circle , the hypotenuse is the diameter . hypotenuse here = diagonal of the square = 8 sqrt ( 2 ) = diameter = > radius = 4 sqrt ( 2 ) circumference of the circle = 2 pi r = 8 pi sqrt ( 2 ) answer is c .
circumface(divide(sqrt(add(power(square_edge_by_perimeter(32), const_2), power(square_edge_by_perimeter(32), const_2))), const_2))