find out the square of a number which when doubled exceeds its one fifth by 9 ?
a let the number be p , then the square will be p ^ 2 according to question : 2 p = ( p / 5 ) + 9 = > 10 p = p + 45 = > p = 5 p ^ 2 = 5 ^ 2 = 25 . answer : b
power(divide(9, subtract(const_2, divide(const_1, add(const_4, const_1)))), const_2)