in how many ways 3 boys and 3 girls can be seated in a row so that they are alternate .
"solution : let the arrangement be , b g b g b g b 34 boys can be seated in 3 ! ways . girl can be seated in 3 ! ways . required number of ways , = 3 ! * 3 ! = 36 . answer : option c"
multiply(factorial(3), factorial(3))