what is the sum of all possible solutions to | x - 6 | ^ 2 + | x - 6 | = 20 ?
denote | x - 6 | as y : y ^ 2 + y = 20 - - > y = - 5 or y = 4 . discard the first solution since y = | x - 6 | , so it ' s an absolute value and thus can not be negative . y = | x - 6 | = 4 - - > x = 10 or x = - 2 . the sum = 12 . answer : d .
add(add(const_4, 6), subtract(6, const_4))