the sum of the ages of 4 children born at the intervals of 3 years each is 38 years . what is the age of the youngest child ?
"let the ages of the children be x , ( x + 3 ) , ( x + 6 ) , ( x + 9 ) years . then , x + ( x + 3 ) + ( x + 6 ) + ( x + 9 ) = 38 4 x = 20 = > x = 5 . age of youngest child = x = 5 years . answer : d"
divide(subtract(divide(38, divide(4, 3)), multiply(subtract(4, const_1), 3)), 3)