in an examination , a student scores 3 marks for every correct answer and loses 1 mark for every wrong answer . if he attempts all 120 questions and secures 180 marks , the number of questions he attempts correctly , is :
"let the number of correct answers be x . number of incorrect answers = ( 120 â € “ x ) . 3 x â € “ ( 120 â € “ x ) = 180 or 4 x = 300 or x = 75 answer : d"
divide(add(180, 120), add(3, 1))