the difference between compound interest and simple interest on a sum for 3 years at 10 % p . a . is rs . 124 find the sum .
"for 3 years , we know c . i - s . i = p ( r / 100 ) ^ 3 + 3 ( r / 100 ) ^ 2 so , putting all values we have , 124 = p ( ( 10 / 100 ) ^ 3 + 3 ( 10 / 100 ) ^ 2 ) = 4000 answer : b"
divide(124, subtract(power(add(const_1, divide(3, const_100)), 10), add(const_1, multiply(10, divide(3, const_100)))))