solution y is 30 percent liquid x and 70 percent water . if 2 kilograms of water evaporate from 8 kilograms of solution y and 2 kilograms of solution y are added to the remaining 6 kilograms of liquid , what percent of this new solution is liquid x ?
"initial solution = > 8 kg ( x : w : : 2.4 : 5.6 ) after evaporation initial solution = > 6 kg ( x : w : : 2.4 : 3.6 ) new solution = > 2 kg ( x : w : : 0.6 : 1.4 ) mixing ( initial solution + new solution ) = > 6 kg ( 2.4 : 3.6 ) + 2 kg ( 0.6 : 1.4 ) = = 8 kg [ ( 2.4 + 0.6 ) : ( 3.6 + 1.4 ) ] = 8 kg ( x : water : : 3 kg : 5 kg ) hence % of x = 3 / 8 = 37.5 % answer : c"
multiply(const_100, divide(add(multiply(8, divide(30, const_100)), multiply(2, divide(30, const_100))), add(add(multiply(8, divide(30, const_100)), multiply(2, divide(30, const_100))), add(subtract(multiply(8, divide(70, const_100)), 2), multiply(2, divide(70, const_100))))))