the sum of the present age of henry and jill is 43 . what is their present ages if 5 years ago henry was twice the age of jill ?
"let the age of jill 5 years ago be x , age of henry be 2 x x + 5 + 2 x + 5 = 43 x = 11 present ages will be 16 and 27 answer : a"
subtract(43, divide(add(43, 5), const_3))