a rope of which a calf is tied is increased from 10 m to 23 m , how much additional grassy ground shall it graze ?
π ( 232 – 102 ) = 1348.2 answer : b
multiply(subtract(power(23, const_2), power(const_10, const_2)), divide(add(multiply(const_10, const_2), const_2), add(const_4, const_3)))