running at the same constant rate , 6 identical machines can produce a total of 270 bottles per minute . at this rate , how many bottles could 20 such machines produce in 4 minutes ?
"solution let the required number of bottles be x . more machines , more bottles ( direct proportion ) more minutes , more bottles ( direct proportion ) â ˆ ´ 6 ã — 1 ã — x = 20 ã — 4 ã — 270 â ‡ ” x = 20 x 4 x 270 / 6 = 3600 . answer e"
multiply(multiply(divide(270, 6), 4), 20)