the l . c . m . of two numbers is 42 . the numbers are in the ratio 2 : 3 . then sum of the number is :
let the numbers be 2 x and 3 x . then , their l . c . m . = 6 x . so , 6 x = 42 or x = 7 . the numbers are 14 and 21 . hence , required sum = ( 14 + 21 ) = 35 . answer : option c
add(multiply(divide(42, multiply(2, 3)), 3), multiply(divide(42, multiply(2, 3)), 2))