two numbers are in the ratio 3 : 5 . if 9 is subtracted from each , the new numbers are in the ratio 12 : 23 . the smaller number is :
"let the numbers be 3 x and 5 x . then , ( 3 x - 9 ) / ( 5 x - 9 ) = 12 / 23 9 x = 99 = > x = 11 the smallest number = 3 * 11 = 33 . answerb"
add(multiply(3, divide(9, multiply(3, 5))), multiply(5, divide(9, multiply(3, 5))))