given a two - digit number , the unit ' s digit exceeds its 10 ' s digit by 5 and the product of the given number and the sum of its digits is equal to 90 , which of the options is the number ?
using the elimination method the option that fits this description is 27 7 - 2 = 5 ( unit ' s digit that exceeds its ten ' s digit by 3 ) 27 * 9 = 243 ( the product of the given number and the sum of its digits is equal to 175 ) answer : a
add(multiply(const_2, 10), add(divide(subtract(sqrt(subtract(multiply(add(multiply(5, add(10, const_1)), 10), add(multiply(5, add(10, const_1)), 10)), multiply(multiply(subtract(multiply(5, 5), add(multiply(const_60, const_4), const_3)), multiply(add(10, const_1), const_2)), const_4))), add(multiply(5, add(10, const_1)), 10)), multiply(multiply(add(10, const_1), const_2), const_2)), 5))