the age of father 8 years ago was thrice the age of his son . 5 years hence , father ' s age will be twice that of his son . the ratio of their present ages is :
let the ages of father and son 8 years ago be 3 x and x years respectively . then , ( 3 x + 8 ) + 5 = 2 [ ( x + 8 ) + 5 ] 3 x + 13 = 2 x + 26 x = 13 . required ratio = ( 3 x + 8 ) : ( x + 8 ) = 47 : 21 . answer : option d
divide(add(multiply(subtract(multiply(const_2, add(8, 5)), add(8, 5)), const_3), 8), add(subtract(multiply(const_2, add(8, 5)), add(8, 5)), 8))