a cistern 8 m long and 6 m wide contains water up to a depth of 1 m 25 cm . the total area of the wet surface is :
area of the wet surface = [ 2 ( lb + bh + lh ) - lb ] = 2 ( bh + lh ) + lb = [ 2 ( 6 x 1.25 + 8 x 1.25 ) + 8 x 6 ] m 2 = 83 m 2 . answer : c
add(multiply(const_2, add(multiply(add(divide(25, const_100), 1), 6), multiply(add(divide(25, const_100), 1), 8))), multiply(6, 8))