the sum of the present age of henry and jill is 33 . what is their present ages if 6 years ago henry was twice the age of jill ?
"let the age of jill 6 years ago be x , age of henry be 2 x x + 6 + 2 x + 6 = 33 x = 7 present ages will be 13 and 20 answer : a"
subtract(33, divide(add(33, 6), const_3))