one day a car rental agency rented 2 / 3 of its cars , including 3 / 5 of its cars with cd players . if 3 / 4 of its cars have cd players , what percent of the cars that were not rented had cd players ?
let us try to solve this by getting some number for total cars . let there be 3,4 and 5 = 60 cars . . . ( we have taken denominators of 2 / 3,3 / 4 and 3 / 5 least common number ) . 2 / 3 ( 60 ) = 40 cars . . . total rented cars , then 1 / 3 ( 60 ) = 20 cars were not rented . 3 / 4 ( 60 ) = 45 cars with cd players . . . total cdp cars now 3 / 5 ( 3 / 4 ) = 3 / 5 ( 45 ) = 27 cdp cars and these are cars that we rented . non rented cdp = total cdp - rented cdp = 45 - 27 = 18 . 18 / 20 = 90 % . answer : e
multiply(divide(subtract(divide(multiply(3, multiply(multiply(3, 5), 4)), 4), divide(multiply(divide(multiply(3, multiply(multiply(3, 5), 4)), 4), 3), 5)), subtract(multiply(multiply(3, 5), 4), divide(multiply(const_2, multiply(multiply(3, 5), 4)), 3))), const_100)