75 boys can complete a work in 26 days . how many men need to complete twice the work in 20 days
"one man can complete the work in 26 * 75 = 1950 days = one time work to complete the work twice it will be completed in let m be the no . of worker assign for this therefore the eqn becomes m * 20 = 2 * 1950 m = 195 workers answer : b"
divide(multiply(75, multiply(26, const_2)), 20)