what is the compound interest paid on a sum of rs . 3000 for the period of 3 years at 10 % per annum .
"solution = interest % for 1 st year = 10 interest % for 2 nd year = 10 + 10 % of 10 = 10 + 10 * 10 / 100 = 11 interest % for 3 rd year = 10 + 10 % ( 10 + 11 ) = 10 + 2.1 = 12.1 total % of interest = 10 + 11 + 12.1 = 33.1 total interest = 33.1 % 3000 = 3000 * ( 33.1 / 100 ) = 993 answer d"
subtract(multiply(3000, power(add(const_1, divide(10, const_100)), 3)), 3000)