how much space , in cubic units , is left vacant when maximum number of 2 x 2 x 2 cubes are fitted in a rectangular box measuring 8 x 10 x 9 ?
"no of cubes that can be accommodated in box = ( 8 * 10 * 9 ) / ( 2 * 2 * 2 ) 8 * 10 in numerator can be perfectly divided by 2 * 2 in denominator . side with length 9 ca n ' t be perfectly divided by 2 and hence is the limiting factor . closet multiple of 2 less that 9 is 8 . so vacant area in cube = = 10 * 8 ( 9 - 8 ) = 10 * 8 * 1 = 80 ans - e"
multiply(subtract(8, multiply(2, const_2)), multiply(10, 9))