victor gets 95 % marks in examinations . if these are 285 marks , find the maximum marks .
let the maximum marks be m then 95 % of m = 285 ⇒ 95 / 100 × m = 285 ⇒ m = ( 285 × 100 ) / 95 ⇒ m = 28500 / 95 ⇒ m = 300 therefore , maximum marks in the examinations are 300 . answer : e
divide(285, divide(95, const_100))