the ratio , by volume , of soap to alcohol to water in a certain solution is 2 : 50 : 100 . the solution will be altered so that the ratio of soap to alcohol is doubled while the ratio of soap to water is halved . if the altered solution will contain 100 cubic centimeters of alcohol , how many cubic centimeters of water will it contain ?
"soap : alcohol initial ratio soap : alcohol : water - - > 2 : 50 : 100 initial soap : alcohol = 2 / 50 = 2 : 50 after doubled soap : alcohol = 2 * 2 / 50 = 4 : 50 initial soap : water = 2 / 100 = 2 : 100 after halved soap : water : 1 / 2 * 2 / 100 = 1 / 100 = 1 : 100 = 4 : 400 after soap : alcohol : water - - > 4 : 50 : 400 given alcohol 100 cumeter . ratio is 8 : 100 : 800 ( 4 : 50 : 400 ) for 100 cu meter of alcohol - - - 800 cu m water is required answer : e"
divide(divide(divide(divide(divide(volume_rectangular_prism(100, 100, 50), const_3), const_2), 2), 2), 2)