the ages of 2 persons differ by 35 years . if 10 years ago the elder one be 6 times as old as the younger one , find the present age of elder person .
"age of the younger person = x age of the elder person = x + 35 6 ( x - 10 ) = x + 35 - 10 x = 15 age of elder person = 15 + 35 = 50 answer is d"
subtract(add(divide(multiply(2, 35), subtract(35, const_1)), 35), 2)