two numbers are respectively 40 % and 60 % more than a third number . what percentage is the first of the second ?
"required answer = ( 100 + x ) / ( 100 + y ) * 100 = 140 * 100 / 160 = 87.5 % answer is b"
subtract(const_100, multiply(divide(add(40, const_100), add(60, const_100)), const_100))