in how many ways 4 boys and 2 girls can be seated in a row so that they are alternate .
"solution : let the arrangement be , b g b g b b 4 boys can be seated in 4 ! ways . girl can be seated in 2 ! ways . required number of ways , = 4 ! * 2 ! = 48 answer : option a"
multiply(factorial(4), factorial(2))