a present value of a machine is $ 40000 . its value depletiation rate is 5 % per annum then find the machine value after 2 years ?
"p = $ 40000 r = 5 % t = 2 years machine value after 3 years = p / ( 1 - r / 100 ) ^ t = 40000 * 19 / 20 * 19 / 20 * 19 / 20 = $ 36100 answer is b"
multiply(40000, power(subtract(const_1, divide(5, const_100)), 2))