by approximately what percent is x greater than 2 / 5 if ( 3 / 5 ) ( x ) = 1 ?
"what percent is x greater than 2 / 5 if ( 3 / 5 ) ( x ) = 1 ? = > x = 5 / 3 % change = [ ( 5 / 3 - 2 / 5 ) / ( 2 / 5 ) ] * 100 = 316.5 % = 316 % approx ans , c"
multiply(divide(subtract(5, divide(2, 5)), divide(2, 5)), const_100)