find a positive number , which when increased by 8 is equal to 128 times reciprocal of the number .
explanation : let the number be x . then , x + 8 = 128 x ( 1 / x ) = > x < sup > 2 < / sup > + 8 x - 128 = 0 = > ( x + 16 ) ( x - 8 ) = 0 = > x = 8 answer : option c
divide(subtract(sqrt(add(multiply(128, const_4), power(8, const_2))), 8), const_2)