a bowl was filled with 10 ounces of water , and 0.00008 ounce of the water evaporated each day during a 50 - day period . what percent of the original amount of water evaporated during this period ?
"total amount of water evaporated each day during a 50 - day period = . 00008 * 50 = . 00008 * 100 / 2 = . 008 / 2 = . 004 percent of the original amount of water evaporated during this period = ( . 004 / 10 ) * 100 % = 0.04 % answer b"
multiply(divide(multiply(50, 0.00008), 10), const_100)