find the simple interest on $ 6000 at 15 % per annum for 9 months ?
"p = $ 6000 r = 15 % t = 9 / 12 years = 3 / 4 years s . i . = p * r * t / 100 = 6000 * 15 * 3 / 400 = $ 675 answer is c"
multiply(6000, divide(15, const_100))