an amount of rs . 100000 is invested in two types of shares . the first yields an interest of 9 % p . a and the second , 11 % p . a . if the total interest at the end of one year is 9 2 / 3 % , then the amount invested in each share was ?
let the sum invested at 9 % be rs . x and that invested at 11 % be rs . ( 100000 - x ) . then , ( x * 9 * 1 ) / 100 + [ ( 100000 - x ) * 11 * 1 ] / 100 = ( 100000 * 29 / 3 * 1 / 100 ) ( 9 x + 1100000 - 11 x ) / 100 = 29000 / 3 = 9700 ( 9 x + 1100000 - 11 x ) = 970000 x = 65000 sum invested at 9 % = rs . 65000 sum invested at 11 % = rs . ( 100000 - 65000 ) = rs . 35000 . answer : b
subtract(100000, divide(subtract(multiply(divide(11, const_100), 100000), multiply(divide(add(9, divide(2, 3)), const_100), 100000)), subtract(divide(11, const_100), divide(9, const_100))))