60 men shake hands with each other . maximum no of handshakes without cyclic handshakes .
"1 st person will shake hand with 59 people 2 nd person will shake hand with 58 people 3 rd person will shake hand with 57 people . . . . . . total no . of handshakes = 59 + 58 + 57 + . . . + 3 + 2 + 1 = 19 * ( 19 + 1 ) / 2 = 1770 or , if there are n persons then no . of shakehands = nc 2 = 60 c 2 = 1770 answer : d"
multiply(subtract(60, const_1), divide(60, const_2))