what is the sum of all possible 3 - digit numbers that can be constructed using the digits 2 , 4 , and 5 if each digit can be used only once in each number ?
"there are 6 possible arrangements of the three numbers . then each number will be in the hundreds , tens , and ones place two times each . the sum is 2 ( 222 ) + 2 ( 444 ) + 2 ( 555 ) = 2442 the answer is a ."
multiply(add(add(multiply(add(add(5, 4), 2), const_100), multiply(add(add(const_4.0, 4), 2), const_10)), add(add(5, 4), 2)), 4)