a works thrice as much as b . if a takes 60 days less than b to do a work then find the number of days it would take to complete the work if both work together ?
if a finishes the job in x days b finishes it in 3 x days 3 x = x + 60 thus x = 30 in one hour 1 / t = 1 / 30 + 1 / 90 = 4 / 90 where t is the number of days they finish the job together . t = 90 / 4 = 22.5 days answer : a
inverse(add(inverse(multiply(const_3, divide(60, subtract(const_3, const_1)))), inverse(divide(60, subtract(const_3, const_1)))))