abcd is a square . e , f , g , h is the midpoint of the sides of square . j and k is the midpoint of the sides hg and fg . l is a point on sides ef such that lf = 1 / 3 ef . find the ratio of area of triangle jkl to the area of square abcd .
ratio = 5 : 48 answer : d
triangle_area(divide(const_1, const_2), add(multiply(divide(const_1, const_2), divide(1, 3)), multiply(divide(const_1, const_2), divide(const_1, const_2))))