two numbers are less than third number by 35 % and 37 % respectively . how much percent is the second number less than by the first
"let the third number is x . then first number = ( 100 - 35 ) % of x = 65 % of x = 65 x / 100 second number is ( 63 x / 100 ) difference = 65 x / 100 - 63 x / 100 = x / 50 so required percentage is , difference is what percent of first number ( x / 50 * 100 / 65 x * 100 ) % = 33 % answer : c"
subtract(multiply(divide(subtract(37, 35), subtract(const_100, 35)), const_100), const_10)