a can do a work in 40 days , b in 60 days . a alone start the work after 10 days he left work . in how many days b can finish the work ?
10 days work of a = 10 / 40 = 1 / 4 remaining work = 1 - 1 / 4 = 3 / 4 b can finish 3 / 4 work = 60 * 3 / 4 = 45 days answer is d
divide(subtract(const_1, multiply(10, divide(const_1, 40))), divide(const_1, 60))