the sum of the present age of henry and jill is 40 . what is their present ages if 11 years ago henry was twice the age of jill ?
"let the age of jill 11 years ago be x , age of henry be 2 x x + 11 + 2 x + 11 = 40 x = 6 present ages will be 17 and 23 answer : c"
subtract(40, divide(add(40, 11), const_3))