a jogger running at 9 kmph along side a railway track is 280 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction . in how much time will the train pass the jogger ?
"speed of train relative to jogger = ( 45 – 9 ) km / h = 36 km / h = ( 36 × 5 ⁄ 18 ) m / sec = 10 m / sec distance to be covered = ( 280 + 120 ) m = 400 m . ∴ time taken = ( 400 ⁄ 10 ) sec = 40 sec . answer b"
multiply(multiply(divide(divide(add(280, 120), const_1000), subtract(45, 9)), const_60), const_60)