a man walking at the speed of 4 kmph crosses a square field diagonally in 3 minutes . the area of the field is :
length of the diagonal = distance covered in 3 min . at 4 km / hr . = ( 4000 / 60 * 3 ) = 200 m . therefore , area of the field = 1 / 2 * diagonal 2 = ½ * 200 * 200 = 20000 m 2 answer : b
square_area(divide(multiply(multiply(4, const_1000), divide(3, multiply(multiply(const_2, const_3), const_10))), sqrt(const_2)))