a mixture of 40 liters of milk and water contains 10 % water . how much water should be added to this so that water may be 20 % in the new mixture ?
4 ltr - water 36 ltr - milk let x water be added then the new mixture must have 20 % water then 4 + x = 20 / 100 ( 40 + x ) x = 5 answer : c
divide(subtract(multiply(40, divide(20, const_100)), multiply(40, divide(10, const_100))), divide(subtract(const_100, 20), const_100))