the income of a company increases 20 % per annum . if its income is 2664000 in the year 1999 what was its income in the year 1997 ?
let income in 1997 = x according to the question , income in 1998 = x + x ⁄ 5 = 6 x ⁄ 5 income in 1999 = 6 x ⁄ 5 + 6 x ⁄ 25 = 36 x ⁄ 25 but given , income in 1999 = 2664000 ∴ 36 x ⁄ 25 = 2664000 ⇒ x = 1850000 answer e
divide(2664000, multiply(divide(add(20, const_100), const_100), divide(add(20, const_100), const_100)))