the sum of the present age of henry and jill is 48 . what is their present ages if 9 years ago henry was twice the age of jill ?
"let the age of jill 9 years ago be x , age of henry be 2 x x + 9 + 2 x + 9 = 48 x = 10 present ages will be 19 and 29 answer : d"
subtract(48, divide(add(48, 9), const_3))