what is the sum of all possible 3 - digit numbers that can be constructed using the digits 1 , 2 , and 4 if each digit can be used only once in each number ?
there are 6 possible arrangements of the three numbers . then each number will be in the hundreds , tens , and ones place two times each . the sum is 2 ( 111 ) + 2 ( 222 ) + 2 ( 444 ) = 1554 the answer is e .
multiply(add(add(multiply(add(add(4, 2), 1), const_100), multiply(add(add(4, 2), 1), const_10)), add(add(4, 2), 1)), const_2)