math-eval/TAL-SCQ5K huggingface dataset:
Problem: If $$19^{}\text{th}$$March is Monday, what day of the week is $$1$$\textsuperscript{st~}March ? 
Options:
aoVal: A
content: Sunday　 
aoVal: B
content: Monday　 
aoVal: C
content: Wednesday　 
aoVal: D
content: Thursday　 
aoVal: E
content: Saturday　 
Answer: D
Analysis: There are 19 days between $$19^{}\text{th}$$March and~ $$1$$\textsuperscript{st~}March.  Apart from $19$\textsuperscript{th} March itself, there are $18$ days,  18 days = 2 week and 4 days.  Therefore,~~$$1$$\textsuperscript{st~}March is Thursday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: Elsa started to raise some chicken in her farm in January. The number of chicken triples every month, while she goes to the market to sell $81$ chicken every month. On April when she came back from the market, she found she had no chicken left.  How many chicken did she raise in January? 
Options:
aoVal: A
content: $$30$$ 
aoVal: B
content: $$35$$ 
aoVal: C
content: $$40$$ 
aoVal: D
content: $$45$$ 
aoVal: E
content: $$50$$ 
Answer: C
Analysis: $81 \div 3 = 27$  $(81 + 27) \div 3 = 36$  $(36 + 81) \div 3 = 39$  $(39 + 81) \div 3 = 40$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Inverse Operation Problems
Source: 其它
Problem: Mariam had ＄$$4y$$. After buying some cloth at ＄$$7$$ per metre, she had ＄$$y$$ left. How many metres of cloth did she buy? 
Options:
aoVal: A
content: $$\frac{3y}{7}$$ 
aoVal: B
content: $$\frac{5y}{7}$$ 
aoVal: C
content: $21y$ 
aoVal: D
content: $$35y$$ 
Answer: A
Analysis: Amount of money she spent to buy the cloth  $$\rightarrow$$＄$$4y-$$＄$$y$$  $$=$$＄$$3y$$,  Length of cloth she bought  $$\rightarrow$$＄$$3y\div $$＄$$7/\text{m}$$  $$= \frac{3y}{7}\text{m}$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Unitary Method with One Variable
Problem: A pencil is one dollar, and a pencil box is two dollars more expensive than a pencil. Jimmy has seven dollars and bought a pencil box. How many pencils can Jimmy buy？(adapted from $$2009$$ Math kangaroo Problems, Level $$1-2$$, Question \#$$6$$) 
Options:
aoVal: A
content: $$8$$ 
aoVal: B
content: $$6$$ 
aoVal: C
content: $$1$$ 
aoVal: D
content: $$2$$ 
aoVal: E
content: $$4$$ 
Answer: E
Analysis: A pencil box costs two dollars more than a pencil, so it\textquotesingle s $1+2=3$ dollars. $7-3=4$. So~He can buy $4\div1=4$~pencils. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction
Problem: The February of a given year has five Fridays. What day of the week was January $$31$$\textsuperscript{th~}of that year? 
Options:
aoVal: A
content: Friday 
aoVal: B
content: Saturday 
aoVal: C
content: Wednesday 
aoVal: D
content: Thursday 
Answer: D
Analysis: There are seven days in a week. In order to have five Fridays, a month has at least $$4\times 7+1=29$$ days. Since February has at most $$29$$ days, the $$1$$\textsuperscript{st} and $$29$$\textsuperscript{th} days of this February must be Friday, which means that January $$31$$ is Thursday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: George takes 4 minutes to go from 1st floor to 3rd floor. He just realised that he forgot his water bottle on the 5th floor. He is now on the 2nd floor. How long would it take him to get his watter bottle? 
Options:
aoVal: A
content: 4 minutes 
aoVal: B
content: 5 minutes 
aoVal: C
content: 6 minutes 
aoVal: D
content: 8 minutes 
aoVal: E
content: None of the above. 
Answer: C
Analysis: 2 gaps between 1st to 3rd floor. hence, 4/2=2 minutes per gap.  Moving from 2nd to 5th floor, 3 gaps -\textgreater{} 3 gaps x 2 minutes per gap = 6 minutes. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division->Simple Multiplication Applications
Source: 其它
Problem: Billy has three times as many llamas as lambs.  Milly has twice as many lambs as llamas.  They have $$17$$ animals in total.  How many of the animals are llamas? 
Options:
aoVal: A
content: $$5$$ 
aoVal: B
content: $$6$$ 
aoVal: C
content: $$7$$ 
aoVal: D
content: $$8$$ 
aoVal: E
content: $$9$$ 
Answer: E
Analysis: Let Billy have $$b$$ lambs and $$3b$$ llamas. Let Milly have $$m$$ llamas and $$2m$$ lambs.  Therefore, as they have $$17$$ animals in total, $$4b + 3m= 17$$. The only positive integer solution of this equation is $$b= 2$$, $$m= 3$$. So the number of llamas is $$3b + m = 3 \times 2 + 3 = 6 + 3 = 9$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Indefinite Equation Word Problems
Problem: If $$15^{}\text{th}$$March is Monday, what day of the week is $$26$$\textsuperscript{th} March ? 
Options:
aoVal: A
content: Sunday　 
aoVal: B
content: Monday　 
aoVal: C
content: Wednesday　 
aoVal: D
content: Friday　 
aoVal: E
content: Saturday　 
Answer: D
Analysis: There are 11 days between $$15^{}\text{th}$$March and~ $$26$$\textsuperscript{th} March.  11 days = 1 week and 4 days.  Therefore,~~$$26$$\textsuperscript{th} March is Friday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: Sarah is $$1.14\text{m}$$ tall. Benny is $$0.23\text{m}$$ taller than Sarah. What is the total height of the $$2$$ children? Round off your answer to $$1$$ decimal place. 
Options:
aoVal: A
content: $$1.4\text{m}$$ 
aoVal: B
content: $$2.1\text{m}$$ 
aoVal: C
content: $$2.5\text{m}$$ 
aoVal: D
content: $$2.6\text{m}$$ 
Answer: C
Analysis: Benny\textquotesingle s height $$=1.14+0.23=1.37\text{m}$$  Total heights of the $$2$$ children $$=1.14+1.37=2.51=2.5\text{m}$$ (rounded to $$1$$ d.p.) 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction
Problem: There are~ $$30$$ students in Pat\textquotesingle s math class. If there are twice as many girls as boys in the class, how many boys are in the class? 
Options:
aoVal: A
content: $$5$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$10$$ 
aoVal: D
content: $$20$$ 
Answer: C
Analysis: There are $$30$$ students in Pat\textquotesingle s math class. With twice as many girls as boys, the class has $$20$$ girls and $$10$$ boys. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Basic Computation of the Multiples
Problem: Lily\textquotesingle s family used $$21$$ tons of water in the first two months, and an average of $$31$$ tons of water on the remaining three tests. The average tons of water for the five months was~\uline{~~~~~~~~~~}~. 
Options:
aoVal: A
content: $$120$$ 
aoVal: B
content: $$22$$ 
aoVal: C
content: $$23$$ 
aoVal: D
content: $$27$$ 
aoVal: E
content: $$25$$ 
Answer: D
Analysis: Total tons of water: $$21\times 2+31\times 3=135$$  Average tons of water: $$135\div 5=27$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems
Problem: Mr.Smith wants to cut a wood into $5$ pieces. It takes him $2$ minutes to cut a piece. How many minutes will he use to cut? 
Options:
aoVal: A
content: $$3$$ 
aoVal: B
content: $$4$$ 
aoVal: C
content: $$8$$ 
aoVal: D
content: $$10$$ 
aoVal: E
content: $$12$$ 
Answer: C
Analysis: Mr.Smith needs to cut $5-1=4$ times, which means he needs to use $4 \times 2 = 8$ minutes to cut. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: Paul had eight $$\textbackslash$5$$-notes at first. He exchanged all his money for $$\textbackslash$2$$-notes only. How many notes did he have in the end? 
Options:
aoVal: A
content: $$16$$ 
aoVal: B
content: $$20$$ 
aoVal: C
content: $$40$$ 
aoVal: D
content: $$80$$ 
Answer: B
Analysis: He has $=\textbackslash$5\times8=\textbackslash$40$  Number of $\textbackslash$2$-notes $=\textbackslash$40\div\textbackslash$2=20$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Unitary Method with One Variable
Problem: Farmer Dunphy has $$16$$ metres of fencing.  He wants to make a closed rectangular pen.  He uses a long wall for one of the sides.  Each side of the pen is a whole number in metres.  What is the largest area that the pen can be? 
Options:
aoVal: A
content: $$25\text{m}^{2}$$ 
aoVal: B
content: $$27\text{m}^{2}$$ 
aoVal: C
content: $$30\text{m}^{2}$$ 
aoVal: D
content: $$28\text{m}^{2}$$ 
aoVal: E
content: $$32\text{m}^{2}$$ 
Answer: E
Analysis: $a+2b=16$, when $$a=2b=8$$, the largest area is $$8\times (8\div 2)=32$$ m\textsuperscript{2}. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems Combined with Geometry->Tile Word Problems
Problem: In how many places do we need to break a wooden stick in order to get $$5$$ pieces? (1999 Math Kangaroo Problem, Level 3-4, Question \#3) 
Options:
aoVal: A
content: $$3$$ 
aoVal: B
content: $$4$$ 
aoVal: C
content: $$5$$ 
aoVal: D
content: $$6$$ 
aoVal: E
content: It depends on how long the stick is. 
Answer: B
Analysis: $5-1=4$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems->Planting no Trees on either Side (straight line type)->Sawing Woods
Source: 其它
Problem: Tom starts a savings account with ＄$$4,000$$ at a bank. The interest rate is $$2\textbackslash\%$$ per year. How much interest will he earn in his savings account at the end of the second year? 
Options:
aoVal: A
content: ＄$$160$$ 
aoVal: B
content: ＄$$161.6$$ 
aoVal: C
content: ＄$$4,160$$ 
aoVal: D
content: ＄$$4,161.6$$ 
Answer: B
Analysis: $$4000\times \left( 1+2\textbackslash\% \right)\times \left( 1+2\textbackslash\% \right)-4000=161.6$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Interest Problems
Problem: If there are $$8$$ pencils in each box, how many pencils are in $$80$$ boxes?　 
Options:
aoVal: A
content: $$10$$ 
aoVal: B
content: $$88$$ 
aoVal: C
content: $$640$$ 
aoVal: D
content: $$808$$ 
Answer: C
Analysis: There are $$80 \times8 = 640$$ pencils in $$80$$ boxes. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division
Problem: At which of~ these times is the angle between the minute hand and the hour hand of a clock equal to $$150^{}\circ$$? 
Options:
aoVal: A
content: $$9\text{pm}$$ 
aoVal: B
content: $$8\text{pm}$$ 
aoVal: C
content: $$6\text{pm}$$ 
aoVal: D
content: $$5\text{pm}$$ 
aoVal: E
content: $$4\text{pm}$$ 
Answer: D
Analysis: At all the times given, the minute hand is pointing to $$12$$. When the minute hand is pointing to $$12$$ and the angle between the hands is $$150^{}\circ$$, the hour hand has turned $$\frac{150}{360}= \frac{5}{12}$$ of a complete turn. Therefore the hour hand will point at $$5$$ and the time will be $$5\text{pm}$$. (There are other times when the angle between the hands is $$150^{}\circ$$ but, of these, only at $$7\text{pm}$$ does the minute hand point to $$12$$ and $$7\text{pm}$$ is not one of the times given.) 
Knowledge points: Overseas Competition->Knowledge Point->Distance Word Problems->Clock Problems
Problem: Lisa is buying potatoes at a grocery store. She can either spend $10$ dollars on a $25\text{-lb}$ bag or $15$ dollars on a $35\text{-lb}$ bag. Whic is the cheaper one? 
Options:
aoVal: A
content: The $25\text{-lb}$ bag 
aoVal: B
content: The $35\text{-lb}$ bag 
Answer: A
Analysis: $$\frac{10}{25}\textasciitilde\textbackslash$ \text{/lb}=0.4\textasciitilde\textbackslash$ \text{/lb}$$  $$\frac{15}{35}\textasciitilde\textbackslash$ \text{/lb}=0.43\textasciitilde\textbackslash$ \text{/lb}$$  $$\frac{10}{25}\textless\frac{15}{35}$$  So, the answer is $$A$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Unit Rate and then the Total Value
Source: 其它
Problem: Ali is arranging the books on his bookshelves. He puts half his books on the bottom shelf and two-thirds of what remains on the second shelf. Finally he splits the rest of his books over the other two shelves so that the third shelf contains four more books than the top shelf. There are three books on the top shelf. How many books are on the bottom shelf？ 
Options:
aoVal: A
content: $$60$$ 
aoVal: B
content: $$50$$ 
aoVal: C
content: $$40$$ 
aoVal: D
content: $$30$$ 
aoVal: E
content: $$20$$ 
Answer: D
Analysis: Since Ali places half his books on the bottom shelf and $$\frac{2}{3}$$ of the remainder on the second shelf, he places $$\frac{2}{3}\times\frac{1}{2}=\frac{1}{3}$$ of his books on the second shelf, leaving $$\left(1-\frac{1}{2}-\frac{1}{3}\right) =\frac{1}{6}$$~ of his books for the top two shelves. There are three books on the top shelf and four more, so seven books, on the third shelf. Therefore these $$10$$ books represent $$\frac{1}{6}$$ of the total number of books on the bookshelves. Hence there are $$60$$ books on the bookshelves and half of these, or $$30$$ books, on the bottom shelf. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Finding the Base
Problem: Given that May $2$nd of a given year is a Thursday, what day is May $29$th of the same year? 
Options:
aoVal: A
content: Saturday 
aoVal: B
content: Wednesday 
aoVal: C
content: Thursday 
aoVal: D
content: Tuesday 
Answer: B
Analysis: $29-2=27$ days later, it will be May $29$\textsuperscript{th}. $27\div7=3R6$, which means May $29$\textsuperscript{th}~is Wednesday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems
Source: 其它
Problem: Given that August $$15$$th of a given year is a Friday, What day is June $$10$$th of the same year? 
Options:
aoVal: A
content: Monday 
aoVal: B
content: Tuesday 
aoVal: C
content: Friday 
aoVal: D
content: Sunday 
Answer: B
Analysis: $$30-10+31+15=$$  $66\div7=9r3$  $$$$Tuesday$$$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: The selling price of a television is＄$$4800$$ and its profit percentage is $$20\textbackslash\%$$. If the cost of the television is not changed, how much should it be sold for if the profit percentage has to be $$75\textbackslash\%$$? 
Options:
aoVal: A
content: $$6000$$ dollars 
aoVal: B
content: $$6500$$ dollars 
aoVal: C
content: $$7000$$ dollars 
aoVal: D
content: $$8000$$ dollars 
Answer: C
Analysis: $$\frac{4800}{\left( 1+20\textbackslash\% \right)}=4000$$ dollars,  $$4000\times \left( 1+75\textbackslash\% \right)=7000$$ dollars. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts
Problem: The upper shelf of a bookshelf has $$143$$ books. The lower shelf has $$39$$ books. How many books should be taken from the upper shelf to the lower shelf so that both shelves will have the same number of books? 
Options:
aoVal: A
content: $$52$$ 
aoVal: B
content: $$104$$ 
aoVal: C
content: $$91$$ 
aoVal: D
content: $$46$$ 
Answer: A
Analysis: $$143-39=104$$,  $$104$$~$\div$ $$2$$ = $$52$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems Involving Sum and Difference
Problem: If Pip was 18 years old 5 years ago, how old will he be 7 years from now? 
Options:
aoVal: A
content: $$22$$ 
aoVal: B
content: $$24$$ 
aoVal: C
content: $$16$$ 
aoVal: D
content: $$30$$ 
aoVal: E
content: $$32$$ 
Answer: D
Analysis: $$18+5+7=30$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems
Source: 其它
Problem: My dad, Burly Ird, says he has to moan at me two school mornings in every three to get me out of bed.  In a twelve-week term, with five schooldays each week, on how many mornings will he moan at me? 
Options:
aoVal: A
content: $$30$$ 
aoVal: B
content: $$35$$ 
aoVal: C
content: $$36$$ 
aoVal: D
content: $$40$$ 
aoVal: E
content: $$42$$ 
Answer: D
Analysis: The number of moaning mornings is $$\frac{2}{3}\times 12 \times 5 = 40$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method
Problem: In one year, there were 5 Sundays in February. What day of the week was 3\textsuperscript{rd~}Feb ? 
Options:
aoVal: A
content: Saturday 
aoVal: B
content: Monday 
aoVal: C
content: Tuesday 
aoVal: D
content: Wednesday 
Answer: C
Analysis: Normally, there are 28 days in February, which has 4 Sundays at most. Therefore, it could be the leap year with 29 days in February. If there are 5 Sundays, the first day in Februray should be Sunday, so Feb 3rd is Tuesday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time->Period of Dates
Source: 其它
Problem: The cost of a computer is $3500$ dollars and the profit percentage is $12\textbackslash\%$ for each computer. Find the price of the computer. 
Options:
aoVal: A
content: $$3850$$ dollars 
aoVal: B
content: $$3920$$ dollars 
aoVal: C
content: $$4200$$ dollars 
aoVal: D
content: $$4550$$ dollars 
Answer: B
Analysis: The price of the computer is: $3500\times(1+12\textbackslash\%)=3920$ dollars. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts->Calculating Price from Cost and Profit
Source: 其它
Problem: Given that March $$26$$\textsuperscript{th}, $$2021$$ was Friday, what day was April $$20$$\textsuperscript{th}, $$2021$$?  $\textasciitilde$ 
Options:
aoVal: A
content: Monday 
aoVal: B
content: Tuesday 
aoVal: C
content: Thursday 
aoVal: D
content: Wednesday 
aoVal: E
content: Friday 
Answer: B
Analysis: Counting from March $$26$$\textsuperscript{th}, $$2021$$, after $31-26=5$ days it was March $$31$$\textsuperscript{st}, $$2021$$. After $20$ days it was April $$20$$\textsuperscript{th}, $$2021$$. In total, there were $5+20=25$ days. $25\div 7 =3R4$, which means April $$20$$\textsuperscript{th}, $$2021$$ was Tuesday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: Tom, Joanna and Jacky each come up with a number. The sum of the three numbers is $$360$$. Tom\textquotesingle s number is twice Joanna\textquotesingle s number, and Joanna\textquotesingle s number is three times Jacky\textquotesingle s number. What are these three numbers? 
Options:
aoVal: A
content: $$36$$ 
aoVal: B
content: $$108$$ 
aoVal: C
content: $$216$$ 
aoVal: D
content: $$360$$ 
Answer: C
Analysis: Jacky\textquotesingle s number is ``$$1$$'', so Joanna\textquotesingle s number is ``$$3$$'', and Tom\textquotesingle s number is ``$$6$$''.  Jacky\textquotesingle s number: $$360 \div (6 +3+1) =36$$. Joanna\textquotesingle s number: $$36 \times 3=108$$. Tom\textquotesingle s number: $$36 \times 6 =216$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems of Sum and Multiple
Problem: ( $$2004$$ AMC $$8$$ Problem, Question \#$$12$$)  Niki usually leaves her cell phone on. If her cell phone is on but she is not actually using it, the battery will last for $$24$$ hours. If she is using it constantly, the battery will last for only $$3$$ hours. Since the last recharge, her phone has been on $$9$$ hours, and during that time she has used it for $$60$$ minutes. If she doesn\textquotesingle t use it any more but leaves the phone on, how many more hours will the battery last? 
Options:
aoVal: A
content: $$7$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$11$$ 
aoVal: D
content: $$14$$ 
aoVal: E
content: $$15$$ 
Answer: B
Analysis: When not being used, the cell phone uses up $$\dfrac{1}{24}$$ of its battery per hour. When being used, the cell phone uses up $$\dfrac{1}{3}$$ of its battery per hour. Since Niki\textquotesingle s phone has been on for $$9$$ hours, of those $$8$$ simply on and~~being used to talk, $$8\left(\dfrac{1}{24}\right)+1\left(\dfrac{1}{3}\right)=\dfrac{2}{3}$$ of its battery has been used up. To drain the remaining $$\dfrac{1}{3}$$ the phone can last for $$\dfrac{\dfrac{1}{3}}{\dfrac{1}{24}}=\boxed{(\text{B})8}$$ more hours without being used. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Work Word Problems->Simple Work Word Problems
Problem: Mike bought five ice creams. He had three brothers and he gave each brother an ice cream. How many ice creams was left?~(adapted from $$2011$$ Math kangaroo Problems, Level $$1-2$$, Question \#$$3$$) 
Options:
aoVal: A
content: $$1$$ 
aoVal: B
content: $$3$$ 
aoVal: C
content: $$4$$ 
aoVal: D
content: $$2$$ 
aoVal: E
content: $$0$$ 
Answer: D
Analysis: Each brother gets one ice cream, and three brothers need three ice cream, so Mike has $5-3=2$~ice cream left. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Knowing the Base
Problem: Elmp visits the Sesame Street Park every Wednesday. If the 1st of January 2017 was Sunday and February has 28 days, what was the last date in March 2017 in which Elmo visited Sesame Street Park? 
Options:
aoVal: A
content: 28th March 
aoVal: B
content: 29th March 
aoVal: C
content: 30th March 
aoVal: D
content: 31st March 
aoVal: E
content: None of the above. 
Answer: B
Analysis: Draw the calendar out. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems
Source: 其它
Problem: A construction team is going to build a road of $50$ miles. The plan is that it finishes $30$\% of the road in the first month, $40$\% of the road in the second month and $30$\% of the road in the third month. How many miles can be built after two months? 
Options:
aoVal: A
content: $$15$$ 
aoVal: B
content: $$20$$ 
aoVal: C
content: $$30$$ 
aoVal: D
content: $$35$$ 
Answer: D
Analysis: $30$\%+$40$\%=$70$\%,  $50 \times 70$\%=$35$  After two months, $35$ miles of road can be built. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems
Source: 其它
Problem: Kate bought $$2$$ apple pies and Lucy bought $$4$$ cupcakes. They each paid the same amount of money and together they paid $$16$$ dollars. How many dollars does $$1$$ cupcake cost? 
Options:
aoVal: A
content: $$2$$ 
aoVal: B
content: $$4$$ 
aoVal: C
content: $$6$$ 
aoVal: D
content: $$10$$ 
aoVal: E
content: $$12$$ 
Answer: A
Analysis: $4$ cupcakes cost $16\div2=8$ dollars, so one cupcake cost $8\div4=2$ dollars. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division->Applying Division
Source: 其它
Problem: Esther made $$18$$ paper stars and she made $$3$$ times as many paper stars as Amy. How many paper stars did Amy make? 
Options:
aoVal: A
content: $$6$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$9$$ 
aoVal: D
content: $$12$$ 
Answer: A
Analysis: omitted 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Basic Computation of the Multiples