math-eval/TAL-SCQ5K huggingface dataset:
Problem: In the Avengers League, there are $25$ superheroes. Six of the superheroes from the galaxy guard left. How many heroes are left?~(adapted from $$2007$$ Math kangaroo Problems, Level $$1-2$$, Question \#$$6$$) 
Options:
aoVal: A
content: $$19$$ 
aoVal: B
content: $$23$$ 
aoVal: C
content: $$24$$ 
aoVal: D
content: $$25$$ 
aoVal: E
content: $$20$$ 
Answer: A
Analysis: There are $25$ superheroes in total. After subtracting $6$, there are $25-6=19$ left. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction
Problem: In a verbal test, the average score of $$40$$ students is $$25$$. The lowest score is $$5$$. At most how many student(s) can get $$100$$ points? 
Options:
aoVal: A
content: $$11$$ 
aoVal: B
content: $$10$$ 
aoVal: C
content: $$9$$ 
aoVal: D
content: $$8$$ 
aoVal: E
content: $$7$$ 
Answer: D
Analysis: Total points: $$40\times 25=1000$$.  To have as many $100$ points as possible, we should consider there are only two groups of students: everyone gets $5$ points in a group and everyone gets $100$ in the other group.  $$10\times 100=1000$$, so there must be less than $10$ people getting $100$ points.  If there are nine $100$s: $$9\times 100+31\times 5=1055\textgreater1000$$, which is impossible.  If there are eight $100$s:$$8\times 100+32\times 5=960\textless{}1000$$.  Thus, the answer is $$8$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems 
Source: 其它
Problem: If I write all $$26$$ letters of the English alphabet in alphabetical order $$62$$ times in a row, then the $$806$$th letter I write will be． 
Options:
aoVal: A
content: $$A$$ 
aoVal: B
content: $$E$$ 
aoVal: C
content: $$V$$ 
aoVal: D
content: $$Z$$ 
Answer: D
Analysis: Since $$806\div 26=31$$, the $$806$$th letter Iwrite will be the last letter of the $$31$$st time I write the full alphabet; it will be a $$Z$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Basic Permutation
Problem: Amy mixes $$10$$ g of a $$20\textbackslash\%$$ sugar solution and $$40$$ g of a $$25\textbackslash\%$$ sugar solution together. After~\uline{~~~~~~~~~~}~of water evaporates, the percent concentration of solution is $40\textbackslash\%$. 
Options:
aoVal: A
content: $$15$$ g 
aoVal: B
content: $$18$$ g 
aoVal: C
content: $$20$$ g 
aoVal: D
content: $$25$$ g 
Answer: C
Analysis: $$10\times20\textbackslash\%+40\times 25\textbackslash\%=12$$ g.  $$(10+40)-12\div40\textbackslash\%=20$$ g. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Finding and Making Use of Invariants
Problem: A snail is climbing up from the bottom of a $15$-meter-deep well. It climbs up $3$ meters during the daytime, and slides down $1$ meter every night. How many days will it take to get out of the well? 
Options:
aoVal: A
content: $$5$$ 
aoVal: B
content: $$6$$ 
aoVal: C
content: $$7$$ 
aoVal: D
content: $$8$$ 
aoVal: E
content: $$9$$ 
Answer: C
Analysis: It climbs up $$3-1=2$$ meters actually everyday. It takes $$12\div 2 +1=7$$ days in total, and in the last day, it climbs up $3$ meters. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Snail Climbing out of Well Problems
Problem: Annie had twice as many paper clips as Beth, After Beth had used $$15$$ paper clips, Annie had $$4$$ times as many as Beth. How many paper clips did Annie have? 
Options:
aoVal: A
content: $$15$$ 
aoVal: B
content: $$45$$ 
aoVal: C
content: $$60$$ 
aoVal: D
content: $$75$$ 
Answer: C
Analysis: Let the number of Annie\textquotesingle s and Beth\textquotesingle s be 2n and n. 2n=4(n-15), so n=30, 2n=30 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Questions Involving Varying Multiples
Problem: It takes $$144$$ workers $$60$$ hours to paint a bridge. Working at the same rate, how many hours would $$108$$ workers require to do the job? 
Options:
aoVal: A
content: $$45$$ 
aoVal: B
content: $$65$$ 
aoVal: C
content: $$80$$ 
aoVal: D
content: $$96$$ 
Answer: C
Analysis: It takes $$144$$ workers $$60$$ hours to paint a bridge. That\textquotesingle s $$144\times60=8640$$ worker-hours. For $$108$$ workers, the job takes $$8640\div108=80$$ hours. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method
Problem: The speed of high-speed train is approximately $$350$$ kilometers per hour, while the walking speed of a person is approximately $$5$$ meters per second.  Approximately, how many times is the speed of a high-speed train faster than the walking speed of a person?． 
Options:
aoVal: A
content: $$2 $$ 
aoVal: B
content: $$20 $$ 
aoVal: C
content: $$70 $$ 
aoVal: D
content: $$200 $$ 
aoVal: E
content: $$700$$ 
Answer: B
Analysis: The speed of high-speed train is approximately $$350$$ kilometers per hour, which is approximately $$100$$ meters per second. So its speed is roughly $$20$$ times faster than $$5$$ meters per second. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Basic Computation of the Multiples
Problem: A gift store buys some gifts at＄$$125$$ each. It wants to earn＄$$25 $$ for each gift after a discount of $$25 \textbackslash\% $$. What is the selling price before the discount for each shirt? 
Options:
aoVal: A
content: $$160$$ dollars 
aoVal: B
content: $$180$$ dollars 
aoVal: C
content: $$190$$ dollars 
aoVal: D
content: $$200$$ dollars 
Answer: D
Analysis: $$\left( 125+25 \right)\div \left( 1-25 \textbackslash\% \right)=200$$ dollars. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts
Problem: Two motor-cyclists John and Kevin were $800 \text{km}$ apart and travelling towards each other at a constant speed. They started at the same time, meeting after $8$ hours. If Kevin started $1\dfrac{1}{2}$ hours later than John, they would be $70 \text{km}$ apart $8$ hours after John started. At what speed was John travelling in $\text{km/h}$? 
Options:
aoVal: A
content: $$50$$ 
aoVal: B
content: $$51 \frac{2}{3}$$ 
aoVal: C
content: $$52 \frac{1}{2}$$ 
aoVal: D
content: $$53 \frac{1}{3}$$ 
aoVal: E
content: None of the above 
Answer: D
Analysis: NA 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Word Problems for Linear Equations with One Variable
Problem: \textbf{Daniel is learning that five pennies spread out on his desk are the same number of coins as five pennies in a pile. According to Piaget, how old is Daniel likely to be?} 
Options:
aoVal: A
content: 1~\textbf{year} 
aoVal: B
content: 2~\textbf{years} 
aoVal: C
content: \textbf{4 years} 
aoVal: D
content: \textbf{8 years} 
aoVal: E
content: \textbf{13 years} 
Answer: D
Analysis: \textbf{Daniel is learning conservation of number, a skill that Piaget believed children learn in the concrete operational stage} 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: Amy mixes $$30$$ g of a $$30\textbackslash\%$$ salt solution and $$20$$ g of a $$20\textbackslash\%$$ salt solution together. How many g of water should she add to the mixture to make it a $$10\textbackslash\% $$ solution? 
Options:
aoVal: A
content: $$70$$ 
aoVal: B
content: $$72$$ 
aoVal: C
content: $$75$$ 
aoVal: D
content: $$80$$ 
Answer: D
Analysis: $$30\times30\textbackslash\%+20\times 20\textbackslash\%=9+4=13$$ g.  $$13\div10\textbackslash\%-(30+20)=80$$ g.  ~~ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Finding and Making Use of Invariants
Problem: Arrange $$28$$ balls to form a square.  One ball is placed at each corner of the square.  How many balls are there on each side of the square?~\uline{~~~~~~~~~~}~ 
Options:
aoVal: A
content: $$5$$ 
aoVal: B
content: $$6$$ 
aoVal: C
content: $$7$$ 
aoVal: D
content: $$8$$ 
aoVal: E
content: $$9$$ 
Answer: D
Analysis: Put $$1$$ ball in each corner ($$4$$ balls in total).  Remaining balls: $$28-4=24$$  $$24\div4=6$$  So, each side has $$1$$ ball at each corner and $$6$$ balls in the middle, giving a total of $$8$$ balls. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Squares->Hallow Squares
Problem: The average pocket money of the whole class is $91$ dollars. Each of the $24$ girls in the class has $92.5$ dollars on average. There are $18$ boys in the class, and their average pocket money is~\uline{~~~~~~~~~~}~dollars. 
Options:
aoVal: A
content: $$36$$ 
aoVal: B
content: $$28$$ 
aoVal: C
content: $$69$$ 
aoVal: D
content: $$85$$ 
aoVal: E
content: $$89$$ 
Answer: E
Analysis: More than average: $$(92.5-91)\times24=36$$.  Each boy should have $$36\div18=2$$ dollars less than the average, so each of them has $91-2=89$ dollars. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems 
Source: 其它
Problem: $$\frac{3}{7}$$ of the passengers on the bus were adults and the rest were children. There were $$24$$ children. How many adults were there? 
Options:
aoVal: A
content: $$42$$ 
aoVal: B
content: $$30$$ 
aoVal: C
content: $$18$$ 
aoVal: D
content: $$15$$ 
aoVal: E
content: $$10$$ 
Answer: C
Analysis: $$1- \frac{3}{7}= \frac{4}{7}$$  $24\div \frac47=42$  $42-24=18$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Finding the Base
Problem: When Teddy was $$5$$ years old, his father\textquotesingle s age was $$7$$ times his age. When his father is $$42$$ years old, how old will Teddy be? 
Options:
aoVal: A
content: $$6$$ 
aoVal: B
content: $$9$$ 
aoVal: C
content: $$11$$ 
aoVal: D
content: $$12$$ 
Answer: D
Analysis: $$7\times5=35$$,  His father was $$35$$ years old when Teddy was $$5$$ years old.  Age difference $=35-5=30$  $42-30=12$ years old  $\textasciitilde$  or  $\textasciitilde$  $$7\times5=35$$,  His father was $$35$$ years old when Teddy was $$5$$ years old.  $$42-35=7$$ years later  $$5+7=12$$ years old  $\textasciitilde$  Teddy will be $$12$$ years old when his father is $$42$$ years old. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems->When..., When... Type Age Problems
Problem: The average height of all the teachers in Grape School is $168$. There are $5$ male teachers in Grape School with an average height of $180$. The average height of female teachers is $162$. How many female teachers are there? 
Options:
aoVal: A
content: $$5$$ 
aoVal: B
content: $$9$$ 
aoVal: C
content: $$10$$ 
aoVal: D
content: $$18$$ 
aoVal: E
content: $$21$$ 
Answer: C
Analysis: Total height less than the average: $(180-168)\times5=60$.  Thus, there are $60\div(168-162)=10$ female teachers. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems
Problem: There are only lilies and roses in Bud\textquotesingle s garden. One third of the flowers are roses. There are 12 roses in total. How many flowers are there in Buds\textquotesingle s garden? 
Options:
aoVal: A
content: $$12$$ 
aoVal: B
content: $$16$$ 
aoVal: C
content: $$20$$ 
aoVal: D
content: $$24$$ 
aoVal: E
content: $$36$$ 
Answer: E
Analysis: $$12\div\frac13=36$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: A shop purchased some tennis rackets at ＄$$150$$ each. It then sold them at ＄$$175$$ each. How much did the shopkeeper earn for $$10$$ rackets? 
Options:
aoVal: A
content: ＄$$150$$ 
aoVal: B
content: ＄$$200$$ 
aoVal: C
content: ＄$$250$$ 
aoVal: D
content: ＄$$300$$ 
Answer: C
Analysis: $$(175-150)\times 10 = 250$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method
Problem: Little Pig is standing in a line. There are $$16$$ animals in the line and her position is the $$4$$\textsuperscript{th} counting from front to back. How many animals are behind her?~\uline{~~~~~~~~~~}~ 
Options:
aoVal: A
content: $$10$$ 
aoVal: B
content: $$11$$ 
aoVal: C
content: $$12$$ 
aoVal: D
content: $$13$$ 
aoVal: E
content: $$14$$ 
Answer: C
Analysis: Ms. Pig is included in the "$$4$$" , so there are $$16 - 4 = 12$$ animals behind her. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction
Problem: There are $5$ people in Linda\textquotesingle s family with an average weight of $56$ kg. The weights of Linda, Linda\textquotesingle s mom, Linda\textquotesingle s sister, and Linda\textquotesingle s brother are $45$ kg, $55$ kg, $50$ kg, and $60$ kg, respectively. What is the weight of Harry\textquotesingle s dad? 
Options:
aoVal: A
content: $$65$$ 
aoVal: B
content: $$66$$ 
aoVal: C
content: $$68$$ 
aoVal: D
content: $$70$$ 
aoVal: E
content: $$75$$ 
Answer: D
Analysis: $$56\times5-45-55-50-60=70$$ kg 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems 
Source: 其它
Problem: Della decides to buy some stationaries for her students. The price of two schoolbags is equal to the price of six notebooks, and the price of six pencilcases is equal to nine notebooks. Given that one schoolbag can be exchanged for four pens, how many pens can be exchanged for one pencilcase? 
Options:
aoVal: A
content: $$6$$ 
aoVal: B
content: $$5$$ 
aoVal: C
content: $$4$$ 
aoVal: D
content: $$3$$ 
aoVal: E
content: $$2$$ 
Answer: E
Analysis: $$1$$ schoolbag$$=3$$ notebooks$$=4$$ pens,  and $$6$$ pencilcases$$=9$$ notebooks,  Then, $$2$$ pencilcases$$=3$$ notebooks$$=4$$ pens.  So, $$1$$ pencilcase$$=2$$ pens. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division
Problem: Suppose $20 \textbackslash\%$ of $x$ equals $40\textbackslash\%$ of $y$. What percentage of $y$ is $x$ ? (adapted from 2020 AMC 8, Question 15) 
Options:
aoVal: A
content: $$35$$ 
aoVal: B
content: $$50$$ 
aoVal: C
content: $$75$$ 
aoVal: D
content: $150$ 
aoVal: E
content: $$200$$ 
Answer: E
Analysis: $20 \textbackslash\% \cdot x = 40\textbackslash\% \cdot y$  $ x = 2 \cdot y$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems
Source: 其它
Problem: If $$1000\textbackslash\%$$ of a certain number is $$100$$, the certain number is． 
Options:
aoVal: A
content: $$1$$ 
aoVal: B
content: $$10$$ 
aoVal: C
content: $$100$$ 
aoVal: D
content: $$1000$$ 
Answer: B
Analysis: If $$1000\textbackslash\%$$ is $$100$$, then $$\left(\frac{1}{10}\right)\text{th}$$ of that, $$10$$, is $$100\textbackslash\%$$ of the number. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Finding the Base
Problem: Jin loves carrots! Yesterday she ate $$\frac{7}{9}$$ of her carrots, and today she ate $$\frac{2}{7}$$ of the number of carrots she ate yesterday. She ate 14 carrots today. Yesterday she had started with  carrots. 
Options:
aoVal: A
content: $$18$$ 
aoVal: B
content: $$4$$ 
aoVal: C
content: $$49$$ 
aoVal: D
content: $$60$$ 
aoVal: E
content: $$63$$ 
Answer: E
Analysis: $14\div\dfrac{2}{7}\div\dfrac{7}{9}=63$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Finding the Base
Problem: A total of $$20$$ chickens and rabbits are caged together. If there are $$56$$ legs in total, how many chickens are there in the cage? 
Options:
aoVal: A
content: $$20$$ 
aoVal: B
content: $$16$$ 
aoVal: C
content: $$15$$ 
aoVal: D
content: $$12$$ 
aoVal: E
content: $$10$$ 
Answer: D
Analysis: Suppose the number of chickens is $x$, so the number of rabbits is $(20-x)$.  $2x+(20-x)\times4=56$, $x=12$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Chicken-Rabbit Problems->Solving Chicken-Rabbit Problems by Using Hypothesis
Problem: Ellie and Gloria have to interview a total of $$400$$ people. Ellie can interview $$60$$ people every week. If Gloria and Ellie work together, they can finish all the work in $$4$$ weeks. How many weeks will it take to finish interviewing everyone by Gloria herself? 
Options:
aoVal: A
content: $$8$$ 
aoVal: B
content: $$10$$ 
aoVal: C
content: $$12$$ 
aoVal: D
content: $$14$$ 
aoVal: E
content: $$16$$ 
Answer: B
Analysis: Working together: $$400\div4=100$$ people every week  Gloria: $$100-60=40$$ people every week  $$400\div40=10$$ weeks  $\textasciitilde$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Work Word Problems->Collaborative Work Word Problems
Problem: $50$ balloons are distributed to Ariel and seven other children. Each of them can get at least one balloon, and no two of them get the same number of balloons. For Ariel, what is the largest possible number of balloons she can get? 
Options:
aoVal: A
content: $$22$$ 
aoVal: B
content: $$18$$ 
aoVal: C
content: $$16$$ 
aoVal: D
content: $$14$$ 
aoVal: E
content: $$10$$ 
Answer: A
Analysis: The largest number of balloons Ariel can get is: $$50 -- (1 + 2 + 3 + 4 + 5+6+7) = 22$$, that is, $$22$$ balloons at most. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Problems Involving Extreme Value
Problem: $$29$$ students came into the classroom in turn. The number of students that came in before Mike was $$5$$ more than the number of students who came in after him. Which place did Mike come in? (Adapted from 2015 Math Kangaroo Problem, Level 3 - 4, Question \#13) 
Options:
aoVal: A
content: $$11$$ 
aoVal: B
content: $$12$$ 
aoVal: C
content: $$16$$ 
aoVal: D
content: $$17$$ 
aoVal: E
content: $$18$$ 
Answer: E
Analysis: The sum of the number of students that came in before Tom and the number of students that came in after him is $29 - 1 = 28$. The number of students that came in before Mike was $(28 + 6) \div 2 = 17$, so Mike was the eighteenth. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Problems Involving Queuing->Finding the Order of one Character
Source: 其它
Problem: A $$15\textbackslash\%$$ sugar solution contains $$18$$ ounces of pure sugar. How many ounces of solution are there? 
Options:
aoVal: A
content: $$90$$ ounces 
aoVal: B
content: $$100$$ ounces 
aoVal: C
content: $$120$$ ounces 
aoVal: D
content: $$150$$ ounces 
Answer: C
Analysis: $$18\div15\textbackslash\% = 120$$ ounces. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems
Problem: My first day of vacation is May $$10$$. My last day of vacation is May $$20$$ of the same year. How many days of vacation do I have? 
Options:
aoVal: A
content: $$9$$ 
aoVal: B
content: $$ 10 $$ 
aoVal: C
content: $$11$$ 
aoVal: D
content: $$12$$ 
Answer: C
Analysis: $20-10+1=11$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: The sum of two numbers is $$71$$. The difference of the two numbers is $$9$$. Find the bigger number. 
Options:
aoVal: A
content: $$31$$ 
aoVal: B
content: $$40$$ 
aoVal: C
content: $$62$$ 
aoVal: D
content: $$80$$ 
Answer: B
Analysis: 71 + 9 = 80  80 $\div $ 2 = 40 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems Involving Sum and Difference
Problem: For a quarter ($$25$$￠), Pat can play a video game for $$5$$ minutes.  How many quarters does Pat need to play for an hour? 
Options:
aoVal: A
content: $$10$$ 
aoVal: B
content: $$12$$ 
aoVal: C
content: $$20$$ 
aoVal: D
content: $$55$$ 
Answer: B
Analysis: For a quarter ($$25$$￠), Pat can play a video game for $$5$$ minutes.  The number of $$5$$-minute intervals in $$1$$ hour is $$60 \div 5 = 12$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division
Problem: The teacher has $$14$$ sweets. She wants to give eight students the same number of sweets. How many more sweets should she prepare? (adapted from $$2020$$ Math kangaroo Problems, Level $$1-2$$, Question \#$$16$$) 
Options:
aoVal: A
content: $$0$$ 
aoVal: B
content: $$1$$ 
aoVal: C
content: $$2$$ 
aoVal: D
content: $$3$$ 
aoVal: E
content: $$4$$ 
Answer: C
Analysis: $$14=8+6$$, ~In this equation, $$8$$ means everyone can get $$1$$ sweet. There are $$6$$ sweets left, the teacher also needs $$8-6=2$$ sweets. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: Given that May $$16$$ of a certain year is a Monday, what day of the week will July $$8$$ fall on in the same year? 
Options:
aoVal: A
content: Monday 
aoVal: B
content: Tuesday 
aoVal: C
content: Wednesday 
aoVal: D
content: Thursday 
aoVal: E
content: Friday 
aoVal: F
content: Saturday 
aoVal: G
content: Sunday 
Answer: E
Analysis: May: $31-16+1=16$  June: $30$  July: $8$  $16+30+8=54$  $54\div7=7$ R $5$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: $$\frac{1}{4}$$ of the beads in a box are blue. $$\frac{1}{3}$$ of the blue beads are small. lf there are $$700$$ small blue beads, how many beads are there altogether in the box? 
Options:
aoVal: A
content: $$1200$$ 
aoVal: B
content: $$2100$$ 
aoVal: C
content: $$2450$$ 
aoVal: D
content: $$4900$$ 
aoVal: E
content: $$8400$$ 
Answer: E
Analysis: $\frac{1}{4}\times\frac{1}{3}=\frac{1}{12}$ of the total beads are small blue beads.  $700\times12=8400$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Finding the Base
Problem: Nick bought $20$ apples from the supermarket. $40$\% of them were red and $60$\% of them were green. How many red apples did he buy? 
Options:
aoVal: A
content: $$8$$ 
aoVal: B
content: $$10$$ 
aoVal: C
content: $$12$$ 
aoVal: D
content: $$14$$ 
Answer: A
Analysis: $20 \times 40$\%=$8$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems
Source: 其它
Problem: Famer $$A$$ had $$1233$$ ducks. He had three times as many ducks as Farmer $$B$$. Farmer $$B$$ had $$199$$ more ducks than Farmer $$C$$. How many ducks did Farmer $$C$$ have? 
Options:
aoVal: A
content: $$212$$ 
aoVal: B
content: $$411$$ 
aoVal: C
content: $$610$$ 
aoVal: D
content: $$3898$$ 
Answer: A
Analysis: Farmer B\textquotesingle s duck: $$1233 \div3 = 411$$  Farmer C\textquotesingle s duck: $$411-199=212$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Word Problems Involving Comparing and Ordering
Problem: Given that June $$14$$, $$2012$$ was Thursday, what day was June $$14$$, $$2014$$? 
Options:
aoVal: A
content: Monday 
aoVal: B
content: Tuesday 
aoVal: C
content: Friday 
aoVal: D
content: Saturday 
aoVal: E
content: Sunday 
Answer: D
Analysis: It would pass $365+365=730$ days, which means June $$14$$, $$2014$$ was two days after Thursday. It was Saturday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: There are some apples and $8$ pears in a basket, each of them are green or yellow. There are three more apples than the total number of green fruit. There are $6$ yellow pears. How many yellow apples are there in the basket? 
Options:
aoVal: A
content: $$4$$ 
aoVal: B
content: $$5$$ 
aoVal: C
content: $$6$$ 
aoVal: D
content: $$7$$ 
aoVal: E
content: $$8$$ 
Answer: B
Analysis: NA 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它