math-eval/TAL-SCQ5K huggingface dataset:
Problem: Chole has $64$ crackers and she is distributing the crackers to her $8$ friends. How many crackers will each of them get? 
Options:
aoVal: A
content: $$4$$ 
aoVal: B
content: $$6$$ 
aoVal: C
content: $$8$$ 
aoVal: D
content: $$10$$ 
Answer: C
Analysis: $64\div 8=8$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: Marko has $$9$$ pieces of candy and Tomo has $$17$$ pieces of candy. How many pieces of candy does Tomo need to give to Marko so that each boy has the same number of pieces of candy? 
Options:
aoVal: A
content: $$2$$ 
aoVal: B
content: $$3$$ 
aoVal: C
content: $$4$$ 
aoVal: D
content: $$5$$ 
aoVal: E
content: $$6$$ 
Answer: C
Analysis: Difference: $17-9=8$  Move: Half of $8=4$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems ->Giving and Receiving
Problem: There are $10$ trees on one side of a road. Workers plan to set one rubbish bin bwtween every two adjacent trees. How many rubbish bins do they need to prepare? 
Options:
aoVal: A
content: $$8$$ 
aoVal: B
content: $$9$$ 
aoVal: C
content: $$10$$ 
aoVal: D
content: $$11$$ 
aoVal: E
content: $$12$$ 
Answer: B
Analysis: $10 - 1 = 9$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems
Source: 其它
Problem: Mary and Jimmy are eating ice cream of the same size. Jimmy eats ice cream twice as fast as Mary. Mary finishes in four minutes. How many minutes Jimmy need?~(adapted from $$2008$$ Math kangaroo Problems, Level $$1-2$$, Question \#$$6$$) 
Options:
aoVal: A
content: $$2$$ 
aoVal: B
content: $$6$$ 
aoVal: C
content: $$3$$ 
aoVal: D
content: $$4$$ 
aoVal: E
content: $$5$$ 
Answer: A
Analysis: Jimmy\textquotesingle s speed is twice as fast as Mary\textquotesingle s, and the ice cream they eat is the same size, so Jimmy\textquotesingle s time is only half as long as Mary\textquotesingle s, that is, $4$$\div$$2= $$2$ minutes. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method
Problem: If $$60\text{cm}$$ of snow falls each hour, how much falls in $$100$$ minutes? 
Options:
aoVal: A
content: $$90\text{cm}$$ 
aoVal: B
content: $$1\text{m}$$ 
aoVal: C
content: $$110\text{cm}$$ 
aoVal: D
content: $$120\text{cm}$$ 
Answer: B
Analysis: $$60 \text{cm}/\text{hr} =1 \text{cm}/\min = 100 \text{cm}/100 \text{mins} = 1 \text{m}/100 \text{mins}$$. 
Knowledge points: Overseas Competition->Knowledge Point->Distance Word Problems->Distance Word Problems on Straight Road
Problem: There are $$9$$ numbers with an average of $$72$$. After eliminating a number, the average of the remaining numbers is $$78$$. What is the eliminated number? 
Options:
aoVal: A
content: $$6$$ 
aoVal: B
content: $$64$$ 
aoVal: C
content: $$24$$ 
aoVal: D
content: $$48$$ 
aoVal: E
content: $$60$$ 
Answer: C
Analysis: $(78-72)\times8=48$, $72-48=24$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems 
Source: 其它
Problem: James made a running plan for this week. He ran $4$ km on average for the three days, and ran an average of $6$ km for the next two dyas, and ran $18$ km in total for the remaining two days to complete his plan. How many kilometers are there in James\textquotesingle{} running plan? 
Options:
aoVal: A
content: $$28$$ 
aoVal: B
content: $$34$$ 
aoVal: C
content: $$38$$ 
aoVal: D
content: $$42$$ 
aoVal: E
content: $$60$$ 
Answer: D
Analysis: $4\times3+6\times2+18=42$ km. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems 
Source: 其它
Problem: THere are 3 families in my neighbourhood with three children each; two of the families have twins. All twins are boys. At most how many girls are in these families? 
Options:
aoVal: A
content: $$2$$ 
aoVal: B
content: $$3$$ 
aoVal: C
content: $$4$$ 
aoVal: D
content: $$5$$ 
aoVal: E
content: $$6$$ 
Answer: D
Analysis: There are 3 families with 3 children = 3 x 3=9.  If there are 2 twin boys, 2 x 2 = 4, 0-4=5. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction
Source: 其它
Problem: Abigail is saving $$50$$p each week.  How many weeks will she take to save £$$20$$? 
Options:
aoVal: A
content: $$20$$ 
aoVal: B
content: $$25$$ 
aoVal: C
content: $$30$$ 
aoVal: D
content: $$35$$ 
aoVal: E
content: $$40$$ 
Answer: E
Analysis: £$$20 \div 50p=40$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method
Problem: My sister runs $$10\text{km}$$ per hour, and I run $$2\text{km}$$ in $$15$$ minutes. If we both run for $$2$$ hours, my sister will run$$\text{km}$$ farther than I will. 
Options:
aoVal: A
content: $$2$$ 
aoVal: B
content: $$4$$ 
aoVal: C
content: $$6$$ 
aoVal: D
content: $$8$$ 
Answer: B
Analysis: I run $$2\text{km}$$ in $$15$$ minutes, or $$8\text{km}$$ in $$1$$ hour. In $$2$$ hours, I will run $$16\text{km}$$ and my sister will run $$20\text{km}$$. She will run $$4\text{km}$$ farther than I will. 
Knowledge points: Overseas Competition->Knowledge Point->Distance Word Problems->Distance Word Problems on Straight Road
Problem: Tobby attended a Nasional Maths Olympaid (NMO). Tobby answered all $50$ questions. For each correct answer, Tobby will get $4$ marks. However, for each wrong answer, Tobby will deduct $1$ mark. If Tobby scored $110$ marks in total, how many questions did Tobby answer correctly? 
Options:
aoVal: A
content: $$42$$ 
aoVal: B
content: $$32$$ 
aoVal: C
content: $$18$$ 
aoVal: D
content: $$8$$ 
Answer: B
Analysis: Assume all questions were answered correctly,  Total score $=50\times4=200$  Difference in total score $=200-110=90$  Change in score $=4+1=5$  No. of incorrect answer $=90\div5=18$  Correct answers $=50-18=32$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Chicken-Rabbit Problems
Source: 其它
Problem: Patrick gets $50 \textbackslash\%$ on a 10 -problem test, $30 \textbackslash\%$ on a 20 -problem test and $30 \textbackslash\%$ on a 30 -problem test. If the three tests are combined into one 60 problem test, which percent is closest to her overall score? (adapted from 2006 AMC 8, Question \#12) 
Options:
aoVal: A
content: $$33$$ 
aoVal: B
content: $$44$$ 
aoVal: C
content: $$55$$ 
aoVal: D
content: $$66$$ 
aoVal: E
content: $$99$$ 
Answer: A
Analysis: $50 \textbackslash\% \cdot 10=5$ $30 \textbackslash\% \cdot 20=6$ $30 \textbackslash\% \cdot 30=9$ Adding them up gets $5+6+9=20$. The overall percentage correct would be $\frac{20}{60}=\frac{1}{3}=0 . \overline{3} \approx(\mathbf{A}) 33$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems
Source: 其它
Problem: The state income tax where Kristin lives is levied at the rate of $$p\textbackslash\%$$ of the first ＄$$28000$$ of annual income plus $$ \left( {p+2} \right) \textbackslash\%$$ of any amount above ＄$$28000$$. Kristin noticed that the state income tax she paid amounted to $$ \left( {p+0.25} \right) \textbackslash\%$$ of her annual income. What was her annual income? 
Options:
aoVal: A
content: ＄$$28000$$ 
aoVal: B
content: ＄$$32000$$ 
aoVal: C
content: ＄$$35000$$ 
aoVal: D
content: ＄$$42000$$ 
aoVal: E
content: ＄$$56000$$ 
Answer: B
Analysis: method $$1$$：$$Let$$ the income amount be denoted by $$A$$.  We know that $$\frac{A\left( p+.25 \right)}{100}=\frac{28000p}{100}+\frac{\left( p+2 \right)\left( A-28000 \right)}{100}$$  We can now try to solve for $$A$$:  $$\left( p+.25 \right)A=28000p+Ap+2A-28000p-56000$$  $$.25A=2A-56000$$  $$A=32000$$  so the answer is $$\boxed{ \text {B}}$$.  method $$2$$：$$Let$$ $$A$$, $$T$$ be Kristin\textquotesingle s annual income and the income tax total, respectively.  Notice that　  $$T=p\textbackslash\%\cdot 28000+\left( p+2 \right)\textbackslash\%\cdot \left( A-28000 \right)$$  $$\textasciitilde\textasciitilde\textasciitilde\textasciitilde$$$$=\left[ p\textbackslash\%\cdot 28000+p\textbackslash\%\cdot \left( A-28000 \right) \right]+2\textbackslash\%\cdot \left( A-28000 \right)$$  $$\textasciitilde\textasciitilde\textasciitilde\textasciitilde$$$$=p\textbackslash\%\cdot A+2\textbackslash\%\cdot \left( A-28000 \right)$$  We are also given that  $$T=\left( p+0.25 \right)\textbackslash\%\cdot A=p\textbackslash\%\cdot A+0.25\textbackslash\%\cdot A$$  Thus, $$p\textbackslash\%\cdot A+2\textbackslash\%\cdot \left( A-28000 \right)=p\textbackslash\%\cdot A+0.25\textbackslash\%\cdot A$$  $$2\textbackslash\%\cdot \left( A-28000 \right)=0.25\textbackslash\%\cdot A$$  Solve for $$A$$ to obtain $$A=32000$$. $$\boxed{ \text {B}}$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Complex Money Word Problems
Problem: A salt solution is made by mixing $$8$$ grams of pure salt and $$32$$ grams of water. Find the percent concentration of the solution. 
Options:
aoVal: A
content: $$10\textbackslash\%$$ 
aoVal: B
content: $$15\textbackslash\%$$ 
aoVal: C
content: $$20\textbackslash\%$$ 
aoVal: D
content: $$25\textbackslash\%$$ 
Answer: C
Analysis: $$8\div(8+32)=20\textbackslash\%$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems
Problem: There are $$8$$ standing in a straight line. The first student is at the start of the line, and the last student is at the end of the line. The distance between each student is $$2$$ meters. How long is the line? (Ignore the thickness of the trees.) 
Options:
aoVal: A
content: $8$ meters 
aoVal: B
content: $$11$$ meters 
aoVal: C
content: $$14$$ meters 
aoVal: D
content: $15$ meters 
aoVal: E
content: $16$ meters 
Answer: C
Analysis: There are $7$ intervals between the first student and the last student. Thus, the line is $7 \times2 = 14$ meters long. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems
Source: 其它
Problem: June $$1^{}\text{st}$$ $$2013$$ falls on a Saturday. On what day of the week will August $$21^{}\text{st}$$ $$2013$$ fall? 
Options:
aoVal: A
content: Monday 
aoVal: B
content: Wednesday 
aoVal: C
content: Friday 
aoVal: D
content: Saturday 
aoVal: E
content: Sunday 
Answer: B
Analysis: $$30-1+31+21=81$$, $$81\div7=11$$R$$4$$. $$4$$ days after a Saturday is a Wednesday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: SASMO 2015 P2 Q3  The sum of two numbers is 300. One number is 5 times of the other number. What is the difference between the two numbers? 
Options:
aoVal: A
content: $$50$$ 
aoVal: B
content: $$60$$ 
aoVal: C
content: $$180$$ 
aoVal: D
content: $$200$$ 
aoVal: E
content: None of the above 
Answer: D
Analysis: x = 1u  y = 5u  6u = 300  1u = 50  So, x=50, y=250  Difference 250-50=200 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems
Source: 其它
Problem: Cathy is drawing flowers. The first one is red, the next one blue, the one after it yellow, the fourth one pink, and then again red, blue, yellow, pink, and so on, in the same order. What color will be the $19$\textsuperscript{th}~flower? (Adapted from 2003 Math Kangaroo Problem, Level 3-4, Question \#4) 
Options:
aoVal: A
content: $$$$Blue 
aoVal: B
content: $$$$Pink 
aoVal: C
content: $$$$Red 
aoVal: D
content: $$$$Black 
aoVal: E
content: $$$$Yellow 
Answer: E
Analysis: $19\div4=4R3$, so the $19$\textsuperscript{th} flower is yellow. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Basic Permutation
Problem: John drinks $x$ cups of boba everyday on weekdays and $2$ cups of boba everyday on the weekends. Which of the following equations represents how many cups of boba John drinks every week? 
Options:
aoVal: A
content: $x+2$ 
aoVal: B
content: $5x+2$ 
aoVal: C
content: $5x+4$ 
aoVal: D
content: $5x-4$ 
Answer: C
Analysis: The boba that John drinks during weekdays: $$5x$$  The boba that John drinks during weekends: $$2\times 2 =4$$  The total boba that John drinks during a week: $$5x+4$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems
Source: 其它
Problem: Of $$60$$ flamingos, twice as many stood on $$2$$ legs as stood on $$1$$. All together, on how many legs did all of these flamingos stand? 
Options:
aoVal: A
content: $$80$$ 
aoVal: B
content: $$90$$ 
aoVal: C
content: $$100$$ 
aoVal: D
content: $$110$$ 
aoVal: E
content: $$120$$ 
Answer: C
Analysis: Of $$60$$ flamingos, $$40$$ stood on $$2$$ legs and $$20$$ stood on $$1$$. All together, these flamingos stood on $$[(40\times2)+20]$$ legs $$=100$$ legs. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems of Sum and Multiple
Problem: A worm is staying at the bottom of a well with a depth of $$10$$ metres. If it climbs up $$3$$ metres in the daytime and slips down $$2$$ metres at night, which day will it climb up to the ground? 
Options:
aoVal: A
content: The $$6$$th day 
aoVal: B
content: The $$7$$th day 
aoVal: C
content: The $$8$$th day 
aoVal: D
content: The $$9$$th day 
Answer: C
Analysis: omitted 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Snail Climbing out of Well Problems
Problem: Peter has some toy cars, and Paul has $$4$$ more toy cars than Peter. Altogether they have $$28$$ toy cars. How many toy cars does Paul have? 
Options:
aoVal: A
content: $$16$$ 
aoVal: B
content: $$48$$ 
aoVal: C
content: $$20$$ 
aoVal: D
content: $$12$$ 
Answer: A
Analysis: Paul has $$(28 + 4) \div 2 = 16$$ toy cars. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems Involving Sum and Difference->Sum and Differences Problems with multiple Variables
Source: 其它
Problem: The average age of all the teachers in Gotia School is $34$. There are $3$ male teachers in Gotia School with an average age of $27$. The average age of female teachers is $35$. How many female teachers are there? 
Options:
aoVal: A
content: $$5$$ 
aoVal: B
content: $$9$$ 
aoVal: C
content: $$12$$ 
aoVal: D
content: $$18$$ 
aoVal: E
content: $$21$$ 
Answer: E
Analysis: Total age less than the average: $(34-27)\times3=21$.  Thus, there are $21\div(35-34)=21$ female teachers. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems
Problem: Cagney can frost a cupcake every $$20$$ seconds and Lacey can frost a cupcake every $$30$$ seconds. Working together, how many cupcakes can they frost in $$5$$ minutes? ($$2012$$ AMC $$10\rm A$$ Problem, Question \#$$11$$) 
Options:
aoVal: A
content: $$10$$ 
aoVal: B
content: $$15$$ 
aoVal: C
content: $$20$$ 
aoVal: D
content: $$25$$ 
aoVal: E
content: $$30$$ 
Answer: D
Analysis: Method1: Cagney can frost one in $$20$$ seconds, and Lacey can frost one in $$30$$ seconds. Working together, they can frost one in $$\dfrac{20\cdot30}{20+30}=\dfrac{600}{50}=12$$ seconds. In $$300$$ seconds ( $$5$$ minutes), they can frost $$\boxed{(\text{D})25}$$ cupcakes.  Method2: In $$300$$ seconds ($$5$$ minutes), Cagney will frost $$\dfrac{300}{20}=15$$ cupcakes, and Lacey will frost $$\dfrac{300}{30}=10$$ ~cupcakes. Therefore, working together they will frost $$15+10=\boxed{(\text{D})25}$$ cupcakes.  Method3: Since Cagney frosts $$3$$ cupcakes a minute, and Lacey frosts $$2$$ cupcakes a minute, they together frost $$3+2=5$$ cupcakes a minute. Therefore, in $$5$$ minutes, they frost $$5\times5=25\Rightarrow\boxed{(\text{D})}$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Work Word Problems->Collaborative Work Word Problems
Problem: Bill, Sarah and James each has $4$ candies. Bill gives James some candies and James gives Sarah some candies. How many candies are there in total? 
Options:
aoVal: A
content: $$0$$ 
aoVal: B
content: $$5$$ 
aoVal: C
content: $$10$$ 
aoVal: D
content: $$12$$ 
aoVal: E
content: $$15$$ 
Answer: D
Analysis: Giving candies to each other won\textquotesingle t affect the sum of their candies, so there are $$4+4+4=12$$~in total. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: Grandma made some cheese dumplings and some blueberry dumplings. Altogether, she made $$31$$ dumplings. If she had made $$11$$ more cheese dumplings, then there would be the same number of blueberry dumplings as cheese dumplings. How many cheese dumplings did grandma make? (2009 Math Kangaroo Problem, Levels 1-2, Question \#19) 
Options:
aoVal: A
content: $$10$$ 
aoVal: B
content: $$21$$ 
aoVal: C
content: $$20$$ 
aoVal: D
content: $$15$$ 
Answer: A
Analysis: $$(31-11)\div2=10.$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems Involving Sum and Difference
Problem: If an object is thrown straight upward with an initial speed of 8 m/s and takes 3 seconds to strike the ground, from what height was the object thrown?  $\textasciitilde$  $\textasciitilde$  $\textasciitilde$  $\textasciitilde$ 
Options:
aoVal: A
content: $$24.2m$$ 
aoVal: B
content: $$21m$$ 
aoVal: C
content: $$23m$$ 
aoVal: D
content: $$2.3m$$ 
aoVal: E
content: $$69m$$ 
Answer: B
Analysis: Key: object is thrown upward. When it reaches the highest point, the velocity is 0. The whole journey is divided into 2 parts: upward - highest point - downward to hit the ground. 2 parts have different displacement (and different time). 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Snail Climbing out of Well Problems->Finding the Height in Snail Climbing out of Wall Problems (completed) 
Source: 其它
Problem: Amit, Bede, Cain, Devi, Emily and Frederick sit around a circular table in that order. Amit starts by saying "$$2015$$", Bede says "$$2016$$", Cain says~"$$2017$$" and so on round the table. Who will eventually say"$$5102$$"? 
Options:
aoVal: A
content: $$$$Amit 
aoVal: B
content: $$$$Bede 
aoVal: C
content: $$$$Cain 
aoVal: D
content: $$$$Devi 
aoVal: E
content: $$$$Emily 
Answer: D
Analysis: After Amit says "$$2015$$", there are $$5102-2015=3087$$ numbers remaining. Thus the counting goes round the table $$3087\div6= 514$$ times with a remainder of $$3$$, so the last to count is Devi. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Circular Operations
Problem: The length of a rectangle is increased by $50\textbackslash\%$ and the width is decreased by $20\textbackslash\%$. What percent of the old area is the new area? (adapted from 2009 AMC 8, Question \#8) 
Options:
aoVal: A
content: $$90$$ 
aoVal: B
content: $$95$$ 
aoVal: C
content: $$100$$ 
aoVal: D
content: $$110$$ 
aoVal: E
content: $$120$$ 
Answer: E
Analysis: $1.5\times 0.8= 120\textbackslash\%$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems
Source: 其它
Problem: $$2$$ apples and $$3$$ peaches cost $$$11$$.  $$2$$ apples and $$2$$ peaches cost $$$8$$.  What is the cost of an apple? 
Options:
aoVal: A
content: $$$1$$ 
aoVal: B
content: $$$2$$ 
aoVal: C
content: $$$3$$ 
aoVal: D
content: $$$4$$ 
Answer: A
Analysis: $$2$$ apples $$+\textasciitilde3$$ peaches$$\to $$ ＄$$11$$  $$2$$ apples $$+\textasciitilde2$$ peaches $$\to $$ ＄$$8$$  $$1$$ peach $$\to $$ ＄$$3$$  $$2$$ apples $$+$$ ($$2$$ $$\times$$ ＄$$3$$) $$\to $$ ＄$$8$$  $$2$$ apples $$\to $$ ＄$$8\textasciitilde-$$ ＄$$6=$$＄$$2$$  $$1$$ apple $$\to $$ ＄$$2\div2=$$＄$$1$$  The cost of an apple is ＄$$1$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Equivalent Substitution in Equation Word Problems
Problem: Jenny need to reach her teacher house by $$2.15 \rm{p.m}$$ for piano class. From her house to teacher\textquotesingle s house, she need to walk for $$20$$ minutes. She was late for $$10$$ minutes. What time did she leave her house? 
Options:
aoVal: A
content: $$2.05 \rm{a.m.}$$ 
aoVal: B
content: $$2.05 \rm{p.m.}$$ 
aoVal: C
content: $$1.55 \rm{a.m.}$$ 
aoVal: D
content: $$1.55 \rm{p.m.}$$ 
aoVal: E
content: $$2.25 \rm{p.m.}$$ 
Answer: B
Analysis: She reached at $$2.25 \rm{p.m.}$$, thus, $$20$$ minutes before that is $$2.05 \rm{p.m.}$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Problem: I am twice the age of each of my sons, Barry and Larry. Our three ages have a total of $$76$$. How old is Barry?　 
Options:
aoVal: A
content: $$9\frac{1}{2}$$ 
aoVal: B
content: $$18$$ 
aoVal: C
content: $$19$$ 
aoVal: D
content: $$36$$ 
aoVal: E
content: $$38$$ 
Answer: C
Analysis: The three ages have a total of four times Barry\textquotesingle s age. So Barry is $$76\div4 = 19$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems->Sums and Multiples in Age Problems
Problem: Mike has $$47$$ ounces of salt solution. Given that there are $$12$$ ounces of pure salt in the solution, how much water is there? 
Options:
aoVal: A
content: $$25$$ ounces 
aoVal: B
content: $$35$$ ounces 
aoVal: C
content: $$45$$ ounces 
aoVal: D
content: $$59$$ ounces 
Answer: B
Analysis: $$47 -- 12 = 35$$ ounces. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems
Problem: Orange peel is a type of orange color mixing red and yellow paint with a ratio of $1:2$. In the shop, red paint is selling at $5$ dollars per ounce and yellow paint is selling at $4$ dollars per ounce. If Richard wants to make $12$ ounces of orange peel, how much money does she need? 
Options:
aoVal: A
content: $48$ dollars 
aoVal: B
content: $52$ dollars 
aoVal: C
content: $56$ dollars 
aoVal: D
content: $60$ dollars 
Answer: B
Analysis: $12\div (1+2)=4$  $4\times (1\times 5+2\times 4)=4\times 13=52$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Finding the Rate
Source: 其它
Problem: At the "Think Flea Market", a vendor is offering a "fair special" on plushies. If you buy one plushie at the regular price of $\textbackslash$ 50$, you get a second one at a $40 \textbackslash\%$ discount, and a third one at half the regular price. Owen takes advantage of the "fair special" to buy three plushies. What percentage of the $\textbackslash$ 150$ regular price will he save? (adapted from 2013 AMC 8, Question \#12) 
Options:
aoVal: A
content: $$25$$ 
aoVal: B
content: $$30$$ 
aoVal: C
content: $$33$$ 
aoVal: D
content: $$40$$ 
aoVal: E
content: $$45$$ 
Answer: B
Analysis: First, find the amount of money one will pay for three sandals without the discount. We have $\textbackslash$ 50 \times 3$ sandals $=\textbackslash$ 150$. Then, find the amount of money using the discount: $50+0.6 \times 50+\frac{1}{2} \times 50=\textbackslash$ 105$. Finding the percentage yields $\frac{105}{150}=70 \textbackslash\%$ To find the percent saved, we have $100 \textbackslash\%-70 \textbackslash\%=(\text{B}) 30$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems
Source: 其它
Problem: In London 2012, the USA won the most medals: 46 Gold, 29 Silver and 29 Bronze. China was second with 38 Gold, 27 Silver and 23 Bronze. How many more medals did the USA win compared to China? 
Options:
aoVal: A
content: $$6$$ 
aoVal: B
content: $$14$$ 
aoVal: C
content: $$16$$ 
aoVal: D
content: $$24$$ 
aoVal: E
content: $$26$$ 
Answer: C
Analysis: USA won - 104 medals in total\textquotesingle{} China won 88 medals. Difference = 16. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction
Source: 其它