math-eval/TAL-SCQ5K huggingface dataset:
Problem: In a certain quiz show there are the following rules: every participant has $$10$$ points at the beginning and has to answer $$10$$ questions. For each correct answer, the participant earns $$1$$ point, and for each incorrect answer, the participant loses $1$ point. Mrs. Smith had $$14$$ points at the end of this quiz show. How many correct answers did she give? ($$2011$$ Math Kangaroo Problem, Level $$3-4$$, Question \#$$17$$) 
Options:
aoVal: A
content: $$7$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$9$$ 
aoVal: D
content: $$6$$ 
aoVal: E
content: $$4$$ 
Answer: A
Analysis: Full score: $10+10\times1=20$.  Smith gets $(20-14)\div(1+1)=3$ questions wrong, and $10-3=7$ questions correct. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Chicken-Rabbit Problems->Solving Chicken-Rabbit Problems by Using Hypothesis->Basic Type->Non-typical Types
Problem: My mom\textquotesingle s birthday is on Sunday, and my dad\textquotesingle s birthday is $$55$$ days after it. On what day of the week will my dad\textquotesingle s birthday be? ($$1999$$ Math Kangaroo Problem, Levels $$3-4$$, Question \#$$9$$) 
Options:
aoVal: A
content: Sunday 
aoVal: B
content: Monday 
aoVal: C
content: Tuesday 
aoVal: D
content: Thursday 
aoVal: E
content: Saturday 
Answer: E
Analysis: $$55\div7=7 \text{R}6$$. It is Saturday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: Penelope paid＄$$24.58$$ for pens and pencils. If pens cost $$9$$￠ each and pencils cost $$4$$￠ each, at most how many pens did Penelope purchase? 
Options:
aoVal: A
content: $$273$$ 
aoVal: B
content: $$272$$ 
aoVal: C
content: $$271$$ 
aoVal: D
content: $$270$$ 
Answer: D
Analysis: Continue subtracting $$4$$￠ from $$2458$$￠ until the difference is a multiple  of $$9$$. This happens when the difference is $$2430$$￠ which is $$270 \times 9$$￠. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division
Problem: The selling price of a sofa set is ＄$$5500$$ and the profit percentage is $$10\textbackslash\%$$ for each set sold. If the cost of the sofa set is not changed, what is the new profit percentage if raising the profit to ＄$$1800$$? 
Options:
aoVal: A
content: $$24\textbackslash\%$$ 
aoVal: B
content: $$25\textbackslash\%$$ 
aoVal: C
content: $$30\textbackslash\%$$ 
aoVal: D
content: $36\textbackslash\%$ 
Answer: D
Analysis: $$5500\div(1+10\textbackslash\%)=5000$$, $$1800\div5000=36\textbackslash\%$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts
Problem: A worm is at the bottom of a well with a depth of $$11$$ metres. If it climbs up $$3$$ metres in the day and slips down $$1$$ metre at night, how many days will it take the worm to climb up to the ground? 
Options:
aoVal: A
content: $$8$$ 
aoVal: B
content: $$7$$ 
aoVal: C
content: $$6$$ 
aoVal: D
content: $$5$$ 
aoVal: E
content: $$4$$ 
Answer: D
Analysis: It climbs up $$3$$ meters in the day time and slips down $$1$$ meter at night, so it climbs up $$2$$ meters in a whole day. For the first $$4$$ days, it climbs $$8$$ meters. During the day time of the fifth day, it climbs $$3$$ meters and reaches the ground. Then it needs five days to climb up to the ground. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Snail Climbing out of Well Problems
Problem: Bowen has $$40$$ ounces of a $$25\textbackslash\%$$ sugar solution. After~\uline{~~~~~~~~~~}~of water evaporates, the percent concentration of the solution is $$40\textbackslash\%$$. (Evaporate: the water turns from liquid into vapor and is no longer in the solution anymore.) 
Options:
aoVal: A
content: $$15$$ ounces 
aoVal: B
content: $$12$$ ounces 
aoVal: C
content: $$9$$ ounces 
aoVal: D
content: $$6$$ ounces 
Answer: A
Analysis: $$40-40\times25\textbackslash\%\div40\textbackslash\%=40-25=15$$ ounces. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Finding and Making Use of Invariants
Problem: Patrick gets $80 \textbackslash\%$ on a 10 -problem test, $60 \textbackslash\%$ on a 20 -problem test and $50 \textbackslash\%$ on a 30 -problem test. If the three tests are combined into one 60 problem test, which percent is closest to her overall score? (adapted from 2006 AMC 8, Question \#12) 
Options:
aoVal: A
content: $$50$$ 
aoVal: B
content: $$52$$ 
aoVal: C
content: $$55$$ 
aoVal: D
content: $$58$$ 
aoVal: E
content: $$60$$ 
Answer: D
Analysis: $80 \textbackslash\% \cdot 10=8$, $60\textbackslash\% \cdot 20=12$, $50\textbackslash\% \cdot 30=15$  Adding them up gets $8+12+15=35$. The overall percentage correct would be $\frac{35}{60} \approx 0.58$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems
Source: 其它
Problem: Gawel lives on the 2\textsuperscript{nd} floor, and Pawel lives in the same building but has to walk up twice as many stairs as Gawel. There are no stairs to the entrance of the building. On which floor does Pawel live? 
Options:
aoVal: A
content: on the $2$\textsuperscript{nd} floor 
aoVal: B
content: on the $3$\textsuperscript{rd} floor 
aoVal: C
content: on the $4$\textsuperscript{th} floor 
aoVal: D
content: on the $5$\textsuperscript{th} floor 
aoVal: E
content: on the $6$\textsuperscript{th} floor 
Answer: B
Analysis: Gawel lives on the second floor, so he only needs to walk up one floor.  Pawel has to walk up twice as many stairs as Gawel, so he needs to walk up two floors. So, Pawel lives on the $3$\textsuperscript{rd} floor. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems
Source: 其它
Problem: Ben stands in line and has $$76$$ people behind him, If there are a total of $$110$$ people in line, how many people are there in front of Ben? 
Options:
aoVal: A
content: $$33$$ 
aoVal: B
content: $$34$$ 
aoVal: C
content: $$35$$ 
aoVal: D
content: $$36$$ 
Answer: A
Analysis: If there are a total of $$110$$ people in line, subtract those behind Ben and Ben himself: $$110-76-1=33$$, the number in front of Ben. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Problems Involving Queuing->Finding the Total Number According to the Position of one Character in a Line
Problem: A jacket was on sale. The original price was ＄$$180$$, and Peter bought it at ＄$$135$$. What was the discount? 
Options:
aoVal: A
content: $$135\textbackslash\%$$ 
aoVal: B
content: $$180\textbackslash\%$$ 
aoVal: C
content: $$75\textbackslash\%$$ 
aoVal: D
content: $$25\textbackslash\%$$ 
Answer: D
Analysis: $$1-135\div180=25\textbackslash\%$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts
Problem: The sum of two numbers is $$800$$. The smaller number is $$356$$.  What is the greater number? 
Options:
aoVal: A
content: $$1156$$ 
aoVal: B
content: $$556$$ 
aoVal: C
content: $$454$$ 
aoVal: D
content: $$444$$ 
Answer: D
Analysis: $$800-356=444$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples
Overseas In-curriculum->Knowledge Point->Operations of Numbers ->Addition and Subtraction of Whole Numbers->Adding and Subtracting within 10000->Subtraction of 3-digit Numbers
Problem: There are $$20$$ chickens and rabbits in the case, and the total number of legs is $$48$$. How many rabbits in this case? 
Options:
aoVal: A
content: $$4$$ 
aoVal: B
content: $$6$$ 
aoVal: C
content: $$8$$ 
aoVal: D
content: $$10$$ 
aoVal: E
content: $$12$$ 
Answer: A
Analysis: If all were rabbits,  $20\times 4= 80$  the total number of legs would be $$$80$$.  $80- 48=32$  The difference is $$$32$$.  $4-2=2$  $32\div 2=16$  $20-16=4$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Chicken-Rabbit Problems->Solving Chicken-Rabbit Problems by Using Hypothesis
Problem: A sugar solution is made by mixing $$10$$ ounces of sugar and $$15$$ ounces of water. Find the percent concentration of the solution. 
Options:
aoVal: A
content: $$20\textbackslash\%$$ 
aoVal: B
content: $25\textbackslash\%$ 
aoVal: C
content: $30\textbackslash\%$ 
aoVal: D
content: $40\textbackslash\%$ 
Answer: D
Analysis: $$10\div(10+15)=40\textbackslash\%$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems
Problem: Mother baked $$40$$ cookies. She gave $$8$$ cookies to her friend and packed the rest equally into bottles. She put $$4$$ cookies in each bottle. How many bottles did she use? 
Options:
aoVal: A
content: $$7$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$9$$ 
aoVal: D
content: $$10$$ 
Answer: B
Analysis: $$40-8=32$$,  $$32\div4=8$$.  Mother used $$8$$ bottles. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Unitary Method with One Variable
Problem: Julian started reading a book with $$348$$ pages. He read $$6$$ pages on each day from Monday to Friday and $$11$$ pages on each day on Saturday and Sunday. He started reading on a Thursday. On which day of the week did he finish reading the book? ． 
Options:
aoVal: A
content: Friday 
aoVal: B
content: Saturday 
aoVal: C
content: Sunday 
aoVal: D
content: Monday 
Answer: D
Analysis: Thursday to Sunday $$\rightarrow 6\times 2+11\times 2=34$$ pages  $$348-34=314$$  $1$ week (Monday to Sunday) $$\rightarrow 11\times 2+6\times 5=52$$ pages  $6$ weeks $$\rightarrow 52\times6=312$$ pages  After reading another $312$ pages in $6$ weeks, Julian has another $(314 -- 312) = 2$ pages left to read. It will now be a Monday and Julian can finish reading the last $2$ pages. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: $5$\% of the students at Hamilton Middle School have red hair. There are $800$ students at Hamilton Middle School. How many students at Hamilton Middle School have red hair? 
Options:
aoVal: A
content: $$5$$ 
aoVal: B
content: $$40$$ 
aoVal: C
content: $$400$$ 
aoVal: D
content: $$760$$ 
Answer: B
Analysis: $800 \times 5$\%=$40$,  $40$ students at Hamilton Middle School have red hair. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems
Source: 其它
Problem: My pay is the same every day I work. I worked \emph{every} day in $$1992$$, even weekends. In March, I earned ＄$$930$$. I earned for all of $$1992$$. 
Options:
aoVal: A
content: ＄$$11346$$ 
aoVal: B
content: ＄$$11315$$ 
aoVal: C
content: ＄$$10980$$ 
aoVal: D
content: ＄$$10950$$ 
Answer: C
Analysis: In March, there are $$31$$ days. I earned ＄$$930 \div 31$$, which is ＄$$30$$ each day. For all of $$1992$$, I earned $$366\times$$ ＄$$30 =$$＄$$10980$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Unit Rate and then the Total Value
Problem: Zosia is drawing kangaroos. The first one is blue, the next one green, the one after it red, the fourth one yellow, and then again blue, green, red, yellow, and so on, in the same order. What color will the seventeenth kangaroo be? (2003 Math Kangaroo Problem, Level 3-4, Question \#4) 
Options:
aoVal: A
content: $$$$Blue 
aoVal: B
content: $$$$Green 
aoVal: C
content: $$$$Red 
aoVal: D
content: $$$$Black 
aoVal: E
content: $$$$Yellow 
Answer: A
Analysis: A group of the blue one, the green one, the red one, and the yellow one is repeating. $17 \div 4 = 4R1$, so the seventeenth one is blue. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Basic Permutation
Problem: William is 15 years old, and his sister is 23 years old. How old will his sister be when William is 23 years old? 
Options:
aoVal: A
content: $$23$$ 
aoVal: B
content: $$31$$ 
aoVal: C
content: $$38$$ 
aoVal: D
content: $$26$$ 
Answer: B
Analysis: omitted 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems
Source: 其它
Problem: Luna, Lily, and Lucy are talking about their ages. $6$ years ago, Luna was born, and Lily was $5$ years old. This year, the sum of ages of these $3$ people is $33$. When Luna was born, how old was Lucy? 
Options:
aoVal: A
content: $$7$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$9$$ 
aoVal: D
content: $$10$$ 
aoVal: E
content: $$11$$ 
Answer: D
Analysis: Six years ago, the sum of ages of Luna, Lily, and Lucy was $33-6\times3=15$. Lucy was $15-0-5=10$ years old. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems
Source: 其它
Problem: Jack mixed $200$ g of $10\textbackslash\%$ salt solution, $200$ g of $15\textbackslash\%$ salt solution, and $400$ g of $20\textbackslash\%$ salt solution together. What is the percent concentration of salt solution at this time? 
Options:
aoVal: A
content: $15\textbackslash\%$ 
aoVal: B
content: $16\textbackslash\%$ 
aoVal: C
content: $16.25\textbackslash\%$ 
aoVal: D
content: $17\textbackslash\%$ 
Answer: C
Analysis: $$\frac{200\times 10\textbackslash\%+200\times 15\textbackslash\%+400\times 20\textbackslash\%}{200+200+400}\times 100\textbackslash\%=16.25\textbackslash\%$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems->Calculating Solution from Solute and Solvent
Problem: After Sally takes 20 shots, she has made $75 \textbackslash\%$ of her shots. After she takes 10 more shots, she drops her percentage to $60 \textbackslash\%$. How many of the last 5 shots did she make? (adapted from 2004 AMC 8, Question\#6) 
Options:
aoVal: A
content: $$2$$ 
aoVal: B
content: $$3$$ 
aoVal: C
content: $$4$$ 
aoVal: D
content: $$5$$ 
aoVal: E
content: $$6$$ 
Answer: B
Analysis: Sally made $0.75 * 20=15$ shots originally. Letting $x$ be the number of shots she made, we have $\frac{15+x}{30}=0.6$. Solving for $x$ gives us $x=3$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems
Source: 其它
Problem: Crystal and Angela had a poem recitation game. Each poem in their game earned $$2$$ points. Crystal recited $$7$$ poems and Angela recited $$11$$ poems. How many more points than Crystal did Angela earn?~(adapted from $$2021$$ Math kangaroo, Level $$1-2$$, Question \#$$14$$) 
Options:
aoVal: A
content: $$4$$ 
aoVal: B
content: $$6$$ 
aoVal: C
content: $$8$$ 
aoVal: D
content: $$10$$ 
aoVal: E
content: $$12$$ 
Answer: C
Analysis: Angela recited $$11-7=4$$ poems more than Crystal.  There are 4$$\times$$2$$=8$$ points 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: A test is with a full score of $100$ points. Five students in a group wants to reach an average of $92$ points. If everyone scores a different whole number, the lowest score among them could be~\uline{~~~~~~~~~~}~. 
Options:
aoVal: A
content: $$60$$ 
aoVal: B
content: $$61$$ 
aoVal: C
content: $$66$$ 
aoVal: D
content: $$70$$ 
aoVal: E
content: $$71$$ 
Answer: C
Analysis: $92\times5-(100+99+98+97)=66$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems
Problem: Given that April $$15$$, $$2011$$ was Friday, what day was May $$11$$, $$2011$$? 
Options:
aoVal: A
content: Thursday 
aoVal: B
content: Saturday 
aoVal: C
content: Tuesday 
aoVal: D
content: Wednesday 
Answer: D
Analysis: Counting from April $$15$$, $$2011$$, after $30-15=15$ days it will be April $$30$$, $$2011$$. After $11$ days, it will be May $$11$$, $$2011$$. In total, there are $15+11=26$ days. $26\div 7 =3R5$, which means May $$11$$, $$2011$$ was Wednesday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: The perimeter of a cuboid is $180$. What is the largest volume? 
Options:
aoVal: A
content: $$216$$ 
aoVal: B
content: $$3375$$ 
aoVal: C
content: $$720$$ 
aoVal: D
content: $$9600$$ 
aoVal: E
content: $$1200$$ 
Answer: B
Analysis: $180\div12=15$  $15\times15\times15=3375$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Problems Involving Extreme Value
Source: 其它
Problem: A train travels from Exeter to Cambridge at a~ speed of $$55km/h$$. Given that Cambridge is $$420km$$ away from Exeter, How far is the train away from Cambridge after setting off for 5 hours? 
Options:
aoVal: A
content: $$55km$$ 
aoVal: B
content: $$145km$$ 
aoVal: C
content: $$275km$$ 
aoVal: D
content: $$420km$$ 
Answer: B
Analysis: $420-\left( 55\times5\right)=420-275=145$ 
Knowledge points: Overseas Competition->Knowledge Point->Distance Word Problems->Distance Word Problems on Straight Road
Problem: In the teachers\textquotesingle{} lounge there are $$6$$ tables with $$4$$ chairs by each one, $$4$$ tables with $$2$$ chairs by each, and $$3$$ tables with $$6$$ chairs by each. How many chairs are there in the lounge? (2003 Math Kangaroo Problem, Level 3-4, Question \#5) 
Options:
aoVal: A
content: $$40$$ 
aoVal: B
content: $$25$$ 
aoVal: C
content: $$50$$ 
aoVal: D
content: $$36$$ 
aoVal: E
content: $$44$$ 
Answer: C
Analysis: $6\times4+4\times2+3\times6=50$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division->Simple Multiplication Applications
Problem: Helga is climbing stairs in such a way that she goes up $$2$$ steps at a time. She is standing on the third step now. On which step will she be after she moves up $$3$$ times? 
Options:
aoVal: A
content: $$9$$ 
aoVal: B
content: $$1$$ 
aoVal: C
content: $$6$$ 
aoVal: D
content: $$5$$ 
aoVal: E
content: $$8$$ 
Answer: A
Analysis: Moving up $3$ times is $6$ steps. Now she is on the third step, after moving up $6$ steps, she is on the ninth step. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division->Simple Multiplication Applications
Problem: If today is Tuesday, what day of the week will be 86 days later? 
Options:
aoVal: A
content: Wednesday 
aoVal: B
content: Thursday 
aoVal: C
content: Friday 
aoVal: D
content: Saturday 
Answer: B
Analysis: $$86\div 7=12\cdots \cdots 2$$．  2 days later will be Thursday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time->Period of Dates
Problem: Last month, the price of a couch increased by $\textbackslash$600$. During a sale this month, the couch was offered at a $25\textbackslash\%$ discount. John bought the couch at $\textbackslash$2250$ at the sale. What is the percentage decrease in the cost of the couch as compared to the original price of the couch before the discount? 
Options:
aoVal: A
content: $6.66\textbackslash\%$ 
aoVal: B
content: $5\textbackslash\%$ 
aoVal: C
content: $6.25\textbackslash\%$ 
aoVal: D
content: None of the above. 
Answer: C
Analysis: Price before discount $=\frac{100}{75}\times\textbackslash$2250=\textbackslash$3000$  Original price of the couch before increase $=\textbackslash$3000-\textbackslash$600=\textbackslash$2400$  Price decrease $=\textbackslash$2400-\textbackslash$2250=\textbackslash$150$  Percentage decrease $=\frac{\textbackslash$150}{\textbackslash$2400}\times100\textbackslash\%=6.25\textbackslash\%$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages
Source: 其它
Problem: Anna is lining up to get some ice-cream. Counting from the front, she is the $$4$$\textsuperscript{th}~in the line. Counting from the back, she is the $$7$$\textsuperscript{th}. How many people are there lining up?~\uline{~~~~~~~~~~}~ 
Options:
aoVal: A
content: $$9$$ 
aoVal: B
content: $$10$$ 
aoVal: C
content: $$11$$ 
aoVal: D
content: $$12$$ 
Answer: B
Analysis: $$4+7-1=10$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: Jerry starts a savings account with ＄$$7,000$$ at a bank. The interest rate is $$3\textbackslash\%$$ per year. How much interest will he earn in his savings account at the end of the second year? 
Options:
aoVal: A
content: ＄$$426$$ 
aoVal: B
content: ＄$$426.3$$ 
aoVal: C
content: ＄$$4,263$$ 
aoVal: D
content: ＄$$4,263.6$$ 
Answer: B
Analysis: $$7000\times \left( 1+3\textbackslash\% \right)\times \left( 1+3\textbackslash\% \right)-7000=426.3$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Interest Problems
Problem: A bookstore purchases some story books at ＄$$22$$ each. If the bookstore wants to earn ＄$$11$$ for each book, what is the selling price of each book? 
Options:
aoVal: A
content: ＄$$22$$ 
aoVal: B
content: ＄$$33$$ 
aoVal: C
content: ＄$$35$$ 
aoVal: D
content: ＄$$44$$ 
Answer: B
Analysis: $$22+11=33$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts
Problem: There are four books on my shelf. The almanac and the dictionary together weigh $$4310\text{g}$$. The biography and the cookbook together weigh $$2325\text{g}$$. If the almanac and the biography together weigh $$2795\text{g}$$, what is the weigh of the cookbook and dictionary together? 
Options:
aoVal: A
content: $$2620\text{g}$$ 
aoVal: B
content: $$3270\text{g}$$ 
aoVal: C
content: $$3840\text{g}$$ 
aoVal: D
content: $$4100\text{g}$$ 
Answer: C
Analysis: The almanac, the dictionary, the biography, and the cookbook together weigh $$4310\text{g}+2325\text{g=6635g}$$. Since the almanac and the biography together weigh $$2795\text{g}$$, the cookbook and the dictionary together weigh $$6635\text{g}-2795\text{g=3840g}$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Including and Excluding
Problem: There are $72$ balloons in the shop. Pip bought $$\frac49$$ of them. The shop left~\uline{~~~~~~~~~~}~balloons. 
Options:
aoVal: A
content: $$20$$ 
aoVal: B
content: $$32$$ 
aoVal: C
content: $$40$$ 
aoVal: D
content: $$52$$ 
aoVal: E
content: $$60$$ 
Answer: C
Analysis: $72\times(1-\dfrac{4}{9})=32$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Knowing the Base
Source: 其它
Problem: On Monday morning, a snail fell down a well which is $$10$$ meters deep. During the day, it climbs up $$2$$ meters, and during the night it slides down $$1$$ meter. On what day of the week will the snail get out of the well? ($$1998$$ Math kangaroo Problem, Level $$5-6$$, Question \#$$18$$) 
Options:
aoVal: A
content: $$$$Tuesday 
aoVal: B
content: $$$$Thursday 
aoVal: C
content: $$$$Saturday 
aoVal: D
content: $$$$Sunday 
aoVal: E
content: $$$$Monday 
Answer: A
Analysis: Except the last day, the snail could climb up $2-1=1$ m. Thus, it takes the snail $(10-2)\div1+1=9$ days to get out of the well. $9$ days from Monday is the next Tuesday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Snail Climbing out of Well Problems->Snail Climbing out of Well (completed)
Source: 其它