math-eval/TAL-SCQ5K huggingface dataset:
Problem: Tom, Jim and Peter earned £$620$ together for painting a wall.  The ratio of Tom\textquotesingle s reward to Jim\textquotesingle s reward is $3:4$.  The ratio of Jim\textquotesingle s reward to Peter\textquotesingle s reward is $6:5$.  How much money did Tom earn? 
Options:
aoVal: A
content: £$60$ 
aoVal: B
content: £$180$ 
aoVal: C
content: £$80$ 
aoVal: D
content: £$240$ 
aoVal: E
content: £$200$ 
Answer: B
Analysis: $3:4=9:12$, $6:5=12:10$, their rewards were in the ratio of $9:12:10$.  $620\div(9+12+10)=20$, $20\times9=180$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Dividing Quantities Based on Ratio
Problem: My mom\textquotesingle s birthday is on Sunday, and my dad\textquotesingle s birthday is $$55$$ days after it. What day of the week will my dad\textquotesingle s birthday be? 
Options:
aoVal: A
content: Sunday 
aoVal: B
content: Monday 
aoVal: C
content: Tuesday 
aoVal: D
content: Thursday 
aoVal: E
content: Saturday 
Answer: E
Analysis: $$55\div7=7 \text{R}6$$. It is Saturday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: John bought some cupcakes, and each of them cost $4$ dollars. He gave the salesperson $20$ dollars and got $4$ dollars as change. How many cupcakes did John buy? (Adapted from 2005 Math Kangaroo Problem, Level 3-4, Question \#3) 
Options:
aoVal: A
content: $$6$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$10$$ 
aoVal: D
content: $$5$$ 
aoVal: E
content: $$4$$ 
Answer: E
Analysis: $(20-4)\div4=4$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Unitary Method with One Variable
Problem: There are two bookshelves, A and B. Shelf A has $$1100$$ books, and shelf B has books $$300$$. We need to take  books from shelf A to shelf B, so that books in shelf B is three times more than self A. 
Options:
aoVal: A
content: $$750$$ 
aoVal: B
content: $$800$$ 
aoVal: C
content: $$850$$ 
aoVal: D
content: $$900$$ 
Answer: A
Analysis: The sum is unchanged, which is $$1400$$，$$1400\div \left( 3+1 \right)=350$$，$$1100-350=750$$． 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems Involving Sum and Difference->Problems Involving Sum and Difference with Two Variables
Problem: A mixture of 45 liters of paint is $20 \textbackslash\%$ red tint, $30 \textbackslash\%$ yellow tint and $50 \textbackslash\%$ water. Five liters of yellow tint are added to the original mixture. What is the percent of yellow tint in the new mixture? (adapted from 2007 AMC 8, Question \#17 ) 
Options:
aoVal: A
content: $$33$$ 
aoVal: B
content: $$35$$ 
aoVal: C
content: $$37$$ 
aoVal: D
content: $$39$$ 
aoVal: E
content: $$40$$ 
Answer: C
Analysis: Since $30 \textbackslash\%$ of the original 45 liters of paint was yellow, and 5 liters of yellow paint were added to make the new mixture, there are $13.5+5=18.5$ liters of yellow tint in the new mixture. Since only 5 liters of paint were added to the original 45 , there are a total of 50 liters of paint in the new mixture. This gives $37 \textbackslash\%$ of yellow tint in the new mixture, which is (C) 37 . 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems
Source: 其它
Problem: Twice my house number, plus $$4$$, is $$18$$. What\textquotesingle s my house number? 
Options:
aoVal: A
content: $$5$$ 
aoVal: B
content: $$7$$ 
aoVal: C
content: $$14$$ 
aoVal: D
content: $$40$$ 
Answer: B
Analysis: Twice $$7$$, plus $$4$$ is $$18$$, so $$7$$ is my house number 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division
Problem: Alex is $8$ years older than her two sisters who are twins. The sum of the ages of all three girls is $32$ years old. How old is Alex? ($2007$ Math Kangaroo Problem, Level $5$-$6$, Question \#$9$) 
Options:
aoVal: A
content: $$12$$ 
aoVal: B
content: $$18$$ 
aoVal: C
content: $$16$$ 
aoVal: D
content: $$20$$ 
aoVal: E
content: $$14$$ 
Answer: C
Analysis: The age of each sister is $(32-8) \div 3 =8$ years old. Thus, Alex is $8 +8 =16$ years old. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems
Source: 其它
Problem: Jacob and Zain take pencils from a box of $$21$$ pencils without replacing them. On Monday Jacob takes $$\frac{2}{3}$$ of the number of pencils that Zain takes. On Tuesday Jacob takes $$\frac{1}{2}$$ of the number of pencils that Zain takes. On Wednesday morning the box is empty. How many pencils does Jacob take? 
Options:
aoVal: A
content: $$8$$ 
aoVal: B
content: $$7$$ 
aoVal: C
content: $$6$$ 
aoVal: D
content: $$5$$ 
aoVal: E
content: $$4$$ 
Answer: A
Analysis: Let the number of pencils Zain takes on Monday and Tuesday be $$x$$ and $$y $$ respectively. Therefore $$x+\frac{2}{3}x+y+\frac{1}{2}y=21$$. Hence, when we multiply the equation through by $$6$$ to eliminate the fractions and simplify, we obtain $$10x+9y =126$$. Since $$x$$ and $$y$$ are both positive integers and since the units digit of $$10x$$ is $$0$$, the units digit of $$9y$$ is $$6$$ and hence $$y=4$$. Therefore $$x=9$$ and hence the number of pencils Zain takes is $$9+4=13$$. Therefore the number of pencils Jacob takes is $$21-13= 8$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Indefinite Equation Word Problems
Problem: The fruit store sold a total of $$33$$ boxes of apples in the first three days of last week, and an average of $$18$$ boxes of apples per day in the last four days. How many boxes of apples did this fruit store sell on average each day last week? 
Options:
aoVal: A
content: $$13$$ 
aoVal: B
content: $$14$$ 
aoVal: C
content: $$15$$ 
aoVal: D
content: $$16$$ 
Answer: C
Analysis: $$33+18\times4=105$$  $$105\div7=15$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems 
Source: 其它
Problem: The length of Amy\textquotesingle s string is $$12$$ cm. The length of David\textquotesingle s string is $$24$$ cm. What is the total length of their strings? 
Options:
aoVal: A
content: $$16$$ cm 
aoVal: B
content: $$26$$ cm 
aoVal: C
content: $$36$$ cm 
aoVal: D
content: $$46$$ cm 
Answer: C
Analysis: $12+24=36$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction
Problem: If a construction company can construct a $$1000-$$meter highway in $$5$$ days, how many days does it take to construct a $$2600-$$meter highway at the same rate? 
Options:
aoVal: A
content: $$10$$ 
aoVal: B
content: $$11$$ 
aoVal: C
content: $$12$$ 
aoVal: D
content: $$13$$ 
aoVal: E
content: $$14$$ 
Answer: D
Analysis: It can construct $$1000\div5=200$$ meters per day.  To construct $$2600$$ meters: $$2600\div200=13$$ days. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Unitary Method with Two Variables
Problem: A school bought $$12$$ volleyballs and basketballs in total for ＄$$340$$. Each basketball costs ＄$$30$$. Each volleyball costs ＄$$25$$.  How many basketballs did the school buy? 
Options:
aoVal: A
content: $$4$$ 
aoVal: B
content: $$5$$ 
aoVal: C
content: $$6$$ 
aoVal: D
content: $$7$$ 
aoVal: E
content: $$8$$ 
Answer: E
Analysis: If all were basketballs,  $$12\times $$＄$$30=$$＄$$360$$  the total cost would be ＄$$360$$.  ＄$$360-$$＄$$340=$$＄$$20$$  There is a difference of ＄$$20$$.  ＄$$30-$$＄$$25=$$＄$$5$$  ＄$$20\div $$＄$$5=4$$  $$12-4=8$$  The school bought $$8$$ basketballs. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Chicken-Rabbit Problems->Solving Chicken-Rabbit Problems by Using Hypothesis
Problem: Calculate  (1) 6+19=  (2) 15-8= 
Options:
aoVal: A
content: 26, 7 
aoVal: B
content: 25, 8 
aoVal: C
content: 26, 8 
aoVal: D
content: 25, 7 
Answer: D
Analysis: Partition 6 into 1 and 5. 19+1=20, 20+5=25  Partition 8 into 5 and 3. 15-5=10, 10-3=7 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction
Source: 其它
Problem: Nate eats $12$ pizza slices every day. How many pizza slices will nate eat after a week? 
Options:
aoVal: A
content: $$81$$ 
aoVal: B
content: $$82$$ 
aoVal: C
content: $$83$$ 
aoVal: D
content: $$84$$ 
Answer: D
Analysis: $7\times 12=84$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: There is a tournament at the pool, First, $$13$$ children signed up and then another $$19$$ children signed up, Six teams with an equal number of members each are needed for the tournament, At least how many more children need to sign up so that,the six teams can be formed . (2017 Math Kangaroo Problem, Level 3-4, Question \#13) 
Options:
aoVal: A
content: $$1$$ 
aoVal: B
content: $$2$$ 
aoVal: C
content: $$3$$ 
aoVal: D
content: $$4$$ 
aoVal: E
content: $$5$$ 
Answer: D
Analysis: The total number of children is $$13+19=32$$, To form six teams with the same number of children in each team, we divide $$32$$ by $$6$$, $$32\div6=5$$$$\rm R$$$$2$$, The remaining $$2$$ children will need $$4$$ more children to form the sixth team. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Unitary Method with One Variable
Problem: There are roughly three million people who live in Wales. Nearly six hundred thousand of them speak Welsh. Approximately what percentage of people living in Wales speak Welsh? 
Options:
aoVal: A
content: $$10\textbackslash\%$$ 
aoVal: B
content: $$20\textbackslash\%$$ 
aoVal: C
content: $$30\textbackslash\%$$ 
aoVal: D
content: $$40\textbackslash\%$$ 
aoVal: E
content: $$50\textbackslash\%$$ 
Answer: B
Analysis: The fraction of people living in Wales who speak Welsh is $$\frac{600000}{3000000}$$. This can be simplified to $$\frac{1}{5}$$, and so the percentage is $$20\textbackslash\%$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Finding the Rate
Problem: A slug called Glug eats $$2$$ tomatoes for every $$3$$ strawberries. Yesterday it had eaten $$35$$ tomatoes and strawberries altogether. How many tomatoes did it eat? 
Options:
aoVal: A
content: $$5$$ 
aoVal: B
content: $$7$$ 
aoVal: C
content: $$14$$ 
aoVal: D
content: $$15$$ 
aoVal: E
content: $$21$$ 
Answer: C
Analysis: $$35\times \frac {2} {2+3} = 14$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Basic Units
Source: 其它
Problem: At dinner, Mom tells Alice to take knifes and forks out of the cupboard and put it on each plate. It is known that there are six plates, four forks, and six knives. How many forks or knives does Alice need to get out of the cupboard ?~ (adapted from $$2011$$ Math kangaroo Problems, Level $$1-2$$, Question \#$$6$$) 
Options:
aoVal: A
content: a fork 
aoVal: B
content: a knife 
aoVal: C
content: two forks 
aoVal: D
content: two knives 
aoVal: E
content: None of the above 
Answer: C
Analysis: Each plate needs a knife and a fork. There are six plates here, so $6$$\times$1$=6$pairs of knives and forks are required, that is, six knives and six forks. But now there are only four forks. $6-4=2$ forks are required. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Including and Excluding
Problem: Linda was born on May $6$\textsuperscript{th}. Her brother was born $9$ days earlier than her. When her brother was born? (adapted from $$2008$$ Math kangaroo Problems, Level $$1-2$$, Question \#$$4$$) 
Options:
aoVal: A
content: April $27$\textsuperscript{th} 
aoVal: B
content: May $15$\textsuperscript{th} 
aoVal: C
content: April $28$\textsuperscript{th} 
aoVal: D
content: April $26$\textsuperscript{th} 
aoVal: E
content: May $16$\textsuperscript{th} 
Answer: A
Analysis: Nine days before May $6$\textsuperscript{th} is April $27$\textsuperscript{th} 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time->Period of Dates
Problem: There are $$15$$ balls in a box: white balls, red balls and black balls. The number of white balls is $$7$$ times greater than the number of red balls. How many black balls are there in the box? ($$1998$$ Math Kangaroo Problem, Level $$3-4$$, Question \#$$16$$) 
Options:
aoVal: A
content: $$1$$ 
aoVal: B
content: $$3$$ 
aoVal: C
content: $$5$$ 
aoVal: D
content: $$7$$ 
aoVal: E
content: $$9$$ 
Answer: D
Analysis: The numbers of white balls and red balls in total must be a multiple of $7+1=8$, so from $1$ to $15$, only $8$ itself can match the condition. Thus, there are $15-8=7$ black balls in the box. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems of Sum and Multiple
Problem: \textbf{\hspace{0pt}If a business owner has a \textsuperscript{$}100,000 accounting profit and could have made exactly $60,000 in his next best business opportunity, he has earned} 
Options:
aoVal: A
content: \textbf{$160,000 in economic profits.} 
aoVal: B
content: \textbf{$100,000 in economic profits.} 
aoVal: C
content: \textbf{$40,000 in economic profits.} 
aoVal: D
content: \textbf{neither an economic profit or loss.} 
aoVal: E
content: \textbf{none of the above.} 
Answer: C
Analysis: \textbf{Accounting profit = revenue minus explicit costs. Economic profit = revenue minus both explicit and implicit costs. Accounting profit is always greater than economic profit as there's always an opportunity cost. \textsuperscript{$}100,000 accounting profit minus the implicit cost of \textsuperscript{$}60,000 = $40,000 in economic profit.} 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: Two motor-cyclists John and Kevin were $800 \text{km}$ apart and travelling towards each other at a constant speed. They started at the same time, meeting after $8$ hours. If Kevin started $1\dfrac{1}{2}$ hours later than John, they would be $70 \text{km}$ apart $8$ hours after John started. At what speed was John travelling in $\text{km/h}$? 
Options:
aoVal: A
content: $$50$$ 
aoVal: B
content: $$51 \frac{2}{3}$$ 
aoVal: C
content: $$52 \frac{1}{2}$$ 
aoVal: D
content: $$53 \frac{1}{3}$$ 
aoVal: E
content: None of the above 
Answer: D
Analysis: Kevin\textquotesingle s speed $=\dfrac{70}{1\dfrac{1}{2}}=\dfrac{140}{3} \text{km/h}$  Let John\textquotesingle s speed be $x \text{km/h}$.  $$\left (x+ \frac{140}{3}\right ) \times 8=800 \Rightarrow x=100- \frac{140}{3}= \frac{160}{3}=53 \frac{1}{3}\text{km/h}$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Word Problems for Linear Equations with One Variable
Problem: February 8th, 2016 is Monday. What day is March $$30$$th, 2016? 
Options:
aoVal: A
content: Monday 
aoVal: B
content: Tuesday 
aoVal: C
content: Wednesday 
aoVal: D
content: Thursday 
Answer: C
Analysis: $29-8+30=51$, $51\div7=7\textbackslash{} \rm R\textasciitilde2$,~ it\textquotesingle s Wednesday 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: The largest possible sum of $$4$$ unequal even numbers, none greater than $$100$$, is． 
Options:
aoVal: A
content: $$380$$ 
aoVal: B
content: $$388$$ 
aoVal: C
content: $$390$$ 
aoVal: D
content: $$394$$ 
Answer: B
Analysis: The largest possible sum is $$100 +98+96 + 94 =388$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction
Problem: There were some pieces of candy in a bowl. Sally took half of the pieces of candy. Then Tom took half of the pieces left in the bowl. After that, Clara took half of the remaining pieces. In the end, there were $$6$$ pieces of candy left in the bowl. How many pieces of candy were in the bowl at the beginning? 
Options:
aoVal: A
content: $$12$$ 
aoVal: B
content: $$18$$ 
aoVal: C
content: $$20$$ 
aoVal: D
content: $$24$$ 
aoVal: E
content: $$48$$ 
Answer: E
Analysis: $6+6=12$  $12+12=24$  $24+24=48$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Inverse Operation Problems->Giving Half of a Whole
Source: 其它
Problem: Peter has $$20$$ ounces of a $$20\textbackslash\%$$ salt solution. How many ounces of salt should he add to make it a $$25\textbackslash\%$$ solution? 
Options:
aoVal: A
content: $1$ ounces 
aoVal: B
content: $$\dfrac{4}{3}$$ ounces 
aoVal: C
content: $4$ ounces 
aoVal: D
content: $5$ ounces 
Answer: B
Analysis: Method $$1$$:  Suppose $$x$$ ounces of salt should be added to the solution:  $$\dfrac{20\times20\textbackslash\%+x}{20+x}=25\textbackslash\%$$  $$\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde x=\dfrac{4}{3}$$.  Method $$2$$:  $$20\times(1-20\textbackslash\%)\div(1-25\textbackslash\%)-20=\dfrac{4}{3}$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems
Problem: There were $$8$$ students in a class. Each student shook hands only once with the other $$7$$ students in the class. How many handshakes were there in total? 
Options:
aoVal: A
content: $$28$$ 
aoVal: B
content: $$36$$ 
aoVal: C
content: $$49$$ 
aoVal: D
content: $$56$$ 
Answer: A
Analysis: $7+6+5+4+3+2+1=28$ 
Knowledge points: Overseas In-curriculum->Knowledge Point->Fun Problems in Math->Reasoning
Overseas Competition->Knowledge Point->Word Problem Modules
Problem: If $$1$$ out of $$6$$ lightbulbs is defective and there are $$2016$$ lightbulbs, how many of them are not defective? 
Options:
aoVal: A
content: $$5$$ 
aoVal: B
content: $$336$$ 
aoVal: C
content: $$1680$$ 
aoVal: D
content: $$2016$$ 
Answer: C
Analysis: $$5$$ out of $$6$$ of the $$2016$$ lightbulbs are not defective. Thus $$2016 \times \frac{5}{6} =1680$$ lightbulbs are not defective. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Knowing the Base
Problem: In a very popular Chinese restaurant, all seats were filled and there were still $$8$$ customers in line outside the door. After some time, $$11$$ customers finish eating and leave the restaurant, and then $$15$$ more customers join the waiting line. How many people are still in line outside the door? 
Options:
aoVal: A
content: $$0$$ 
aoVal: B
content: $$12$$ 
aoVal: C
content: $$15$$ 
aoVal: D
content: $$18$$ 
aoVal: E
content: $$23$$ 
Answer: B
Analysis: The line at the door started with $$8$$ people and $$15$$ more came in, for a total of $$23$$ people. After leaving $$11$$ customers, $$11$$ seats were empty, so the number of people left in line was $$23-11=12$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction
Problem: Siti has $$198$$ bookmarks. If she were to give $$6$$ bookmarks to each of her classmates, she would need $$18$$ more bookmarks. How many classmates does Siti have? 
Options:
aoVal: A
content: $$12$$ 
aoVal: B
content: $$24$$ 
aoVal: C
content: $$30$$ 
aoVal: D
content: $$36$$ 
Answer: D
Analysis: $198+18=216$  $216\div6=36$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Distribution Problems->Basic Distribution Problems
Problem: If I start with $2$ , and begin to count by $3\textquotesingle s$ , my $50^{th}$ number will be． 
Options:
aoVal: A
content: $$149$$ 
aoVal: B
content: $$150$$ 
aoVal: C
content: $$151$$ 
aoVal: D
content: $$152$$ 
Answer: A
Analysis: $2+(50-1)\times3=149$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Practical Application of Arithmetic Progression
Problem: Factory $$A$$ can assemble $$20$$ televisions per hour and Factory $$B$$ can assemble $$30$$ televisions per hour. With these constant rates, if $$A$$ assembles $$300$$ televisions in a period, how many televisions can $$B$$ assemble within the same period? 
Options:
aoVal: A
content: $$300$$ 
aoVal: B
content: $$400$$ 
aoVal: C
content: $$450$$ 
aoVal: D
content: $$600$$ 
aoVal: E
content: $$900$$ 
Answer: C
Analysis: Time: $$300\div20=15$$ hours.  So, Factory $$B$$ can assemble $$15\times30=450$$ televisions. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Work Word Problems->Simple Work Word Problems
Problem: Mike deposited ＄$$10000$$ in the bank. He earned an interest of＄$$2100$$ at the end of the second year. What is the interest rate per year of this bank? 
Options:
aoVal: A
content: $21\textbackslash\%$ 
aoVal: B
content: $11\textbackslash\%$ 
aoVal: C
content: $10\textbackslash\%$ 
aoVal: D
content: $9\textbackslash\%$ 
Answer: C
Analysis: Suppose the interest rate is $$m$$:  $$\begin{eqnarray}10000\times \left( 1+m \right)\times \left( 1+m \right)\&=\&10000+2100 \textbackslash\textbackslash{} m\&=\&0.1 \end{eqnarray}$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Word Problems for Linear Equations with One Variable
Problem: Given that May $4$ of a given year is a Wednesday, what day is May $30$ of the same year? 
Options:
aoVal: A
content: Saturday 
aoVal: B
content: Wednesday 
aoVal: C
content: Thursday 
aoVal: D
content: Tuesday 
aoVal: E
content: Monday 
Answer: E
Analysis: $30-4=26$ days later, it will be May $30$\textsuperscript{th}. $26\div7=3R5$, which means May $30$\textsuperscript{th}~is Monday.~ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems
Source: 其它
Problem: There are two factories producing the same kind of car parts. There are $36$ workers in factory $A$, and every worker produces $81$ parts on average. Each worker produces $101$ parts on average in factory $B$. Each worker can produce $89$ parts on average in two factories together. How many workers are there in factory $B$? 
Options:
aoVal: A
content: $$38$$ 
aoVal: B
content: $$34$$ 
aoVal: C
content: $$24$$ 
aoVal: D
content: $$22$$ 
aoVal: E
content: $$18$$ 
Answer: C
Analysis: $$36\times (89-81)\div (101-89)=24$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems
Problem: Alex and Bob love to fold cranes. For a bag of $N$ cranes, Alex will need $2$ hours to complete while Bob will need $3$ hours. One morning, Alex and Bob started to fold cranes at the same time. After $30$ minutes, Alex rested for $10$ minutes before continuing to fold cranes while Bob did not rest at all. When they finished a bag of $N$ cranes together, Alex folded $24$ more cranes than Bob. Find the value of $N$. 
Options:
aoVal: A
content: $$60$$ 
aoVal: B
content: $$90$$ 
aoVal: C
content: $$120$$ 
aoVal: D
content: $$150$$ 
aoVal: E
content: $$180$$ 
aoVal: F
content: None of the above 
Answer: E
Analysis: E 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Work Word Problems
Source: 其它
Problem: Jill is now $$14$$ years old. Jack is now $$6$$ years older than Jill was $$2$$ years ago. How old is Jack now? 
Options:
aoVal: A
content: $$10$$ 
aoVal: B
content: $$18$$ 
aoVal: C
content: $$20$$ 
aoVal: D
content: $$22$$ 
Answer: B
Analysis: Jill is now $$14$$. Two years ago, she was $$12$$. Since Jack is now $$6$$ years older than Jill was $$2$$ years ago, Jack is now $$12 + 6= 18$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems
Source: 其它