math-eval/TAL-SCQ5K huggingface dataset:
Problem: My age is $$3$$ years less than $$5$$ times my sister\textquotesingle s age. If I am $$27$$, the sum of my age and my sister\textquotesingle s age is． 
Options:
aoVal: A
content: $$33$$ 
aoVal: B
content: $$36$$ 
aoVal: C
content: $$39$$ 
aoVal: D
content: $$42$$ 
Answer: A
Analysis: My age, $$27$$, is $$3$$ years less than $$5$$ times my sister\textquotesingle s age, so $$30$$ is $$5$$ times her age. Thus, my sister is $$6$$. The sum of our ages is $$27+6=33$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems->Differences and Multiples in Age Problems
Problem: Valeria has $$65$$ grams of a $$20\textbackslash\%$$ sugar solution. How many grams of sugar is in the solution? How many grams of water is in the solution? 
Options:
aoVal: A
content: $$20$$; $$65$$ 
aoVal: B
content: $$13$$; $$52$$ 
aoVal: C
content: $$13$$; $$65$$ 
aoVal: D
content: $$20$$; $$52$$ 
Answer: B
Analysis: Sugar: $$65\times 20\textbackslash\% = 13$$ ounces;  Water: $$65 - 13 = 52$$ ounces. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems
Problem: Each watermelon\textquotesingle s full price is $$4$$ dollars. Currently, the watermelons on a discounted price for $$3$$ dollars each. Ms. Lee ~wants to buy $$3$$ of them. She needs to pay~\uline{~~~~~~~~~~}~dollars in total. 
Options:
aoVal: A
content: $$8$$ 
aoVal: B
content: $$9$$ 
aoVal: C
content: $$10$$ 
aoVal: D
content: $$12$$ 
aoVal: E
content: $$14$$ 
Answer: B
Analysis: $$3+3+3=9$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Unit Rate and then the Total Value
Problem: 19 less than 67 is~\uline{~~~~~~~~~~}~. 
Options:
aoVal: A
content: $$58$$ 
aoVal: B
content: $$68$$ 
aoVal: C
content: $$38$$ 
aoVal: D
content: $$48$$ 
Answer: D
Analysis: $$67-19=48$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction
Source: 其它
Problem: The ages of Tom\textquotesingle s father, Tom\textquotesingle s mother and Tom are $86$ together. Tom\textquotesingle s mother is $24$ years older than Tom and~~$2$ years younger than Tom\textquotesingle s father.How old is Tom? 
Options:
aoVal: A
content: $$6$$ 
aoVal: B
content: $$12$$ 
aoVal: C
content: $$32$$ 
aoVal: D
content: $$30$$ 
aoVal: E
content: $$36$$ 
Answer: B
Analysis: Tom\textquotesingle s mother is $(86+24-2)\div3=36$ years old.  Tom is $36-24=12$ years old. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems of Sum and Multiple
Source: 其它
Problem: How many ways are there to make $$$80$$ using some combination of $$$5$$, $$$10$$ and $$$20$$ notes? 
Options:
aoVal: A
content: $$16$$ 
aoVal: B
content: $$25$$ 
aoVal: C
content: $$36$$ 
aoVal: D
content: $$49$$ 
aoVal: E
content: None of the above 
Answer: E
Analysis: Condition on the number of $$$20$$ note you use.  $$4$$ gives $$1$$ possibility,  $$3$$ gives $$3$$ possibilities,  $$2$$ gives $$5$$ possibilities,  $$1$$ gives $$7$$ possibilities,  $$0$$ gives $$9$$ possibilities. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method
Problem: Mark and Karl have $$100$$ dollars in total. The money Mark owns is three times the money Karl owns. How many dollars does Mark have? (Adapted from 1999 Math Kangaroo Problem, Level 3 - 4, Question \#6) 
Options:
aoVal: A
content: $$20$$ 
aoVal: B
content: $$25$$ 
aoVal: C
content: $$35$$ 
aoVal: D
content: $$75$$ 
aoVal: E
content: $$80$$ 
Answer: D
Analysis: $100 \div (3 + 1)~ \times 3= 75$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems of Sum and Multiple->Sum and Multiple of Two Variables
Problem: If today is Monday, which day of the week will it be $$22$$ days later? ． 
Options:
aoVal: A
content: Sunday 
aoVal: B
content: Monday 
aoVal: C
content: Tuesday 
aoVal: D
content: Wednesday 
Answer: C
Analysis: Since there are 7 days in a week, the day will repeat again after 7 days.  Thus, if today is Monday, it will be Monday again a week later.  $$22\div 7=3$$ week R $$1$$.  The day after $$22$$ days is the same as the day after $$1$$ day.  $$1$$ day after Monday is Tuesday.  Therefore, it will be \textbf{Tuesday} $$22$$ days later. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: In a maths test, the average score of $$40$$ students is $$25$$. The lowest score is $$5$$. At most how many student(s) can get $$100$$ points? 
Options:
aoVal: A
content: $$11$$ 
aoVal: B
content: $$10$$ 
aoVal: C
content: $$9$$ 
aoVal: D
content: $$8$$ 
aoVal: E
content: $$7$$ 
Answer: D
Analysis: Total points: $$40\times 25=1000$$.  To have as many $100$ points as possible, we should consider there are only two groups of students: everyone gets $5$ points in a group and everyone gets $100$ in the other group.  $$10\times 100=1000$$, so there must be less than $10$ people getting $100$ points.  If there are nine $100$s: $$9\times 100+31\times 5=1055\textgreater1000$$, which is impossible.  If there are eight $100$s:$$8\times 100+32\times 5=960\textless{}1000$$.  Thus, the answer is $$8$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems 
Source: 其它
Problem: The class organized students to do gymnastics side by side，$$and$$ there are two people in each row. Bob and Tick observed that there were $8$ rows in front of them and $11$ rows in the back. How many people in the class did gymnastics together?~(adapted from 2000 Math Kangaroo Problem, Level 3 - 4, Question \#12) 
Options:
aoVal: A
content: $$36$$ 
aoVal: B
content: $$38$$ 
aoVal: C
content: $$40$$ 
aoVal: D
content: $$42$$ 
aoVal: E
content: $$44$$ 
Answer: C
Analysis: It can be seen from the question that Bob and Tick have $8$ rows in front and $11$ rows in the back. There are $20$ rows in total, and there are two people in each row, so there are $40$ people in total. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Squares->Solid Squares->Basic Solid Square Problems
Problem: Felix and Marmalade are two cats. Together they weigh $$10\text{kg}$$.  Felix weighs $$4\text{kg}$$ less than Marmalade. How much does Marmalade weigh? 
Options:
aoVal: A
content: $$3\text{kg}$$ 
aoVal: B
content: $$6\text{kg}$$ 
aoVal: C
content: $$7 \text{kg}$$ 
aoVal: D
content: $$9\text{kg}$$ 
aoVal: E
content: $$14 \text{kg}$$ 
Answer: C
Analysis: It should be a moment\textquotesingle s work to see that Felix weighs $$3\text{kg}$$ , and Marmalade $$7\text{kg}$$ . 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems Involving Sum and Difference
Problem: If $6\text{cm}$ represents $50\text{km}$ on a map and the actual distance between two towns is $125\text{km}$, then their distance apart on the map is ． 
Options:
aoVal: A
content: $8\text{cm}$ 
aoVal: B
content: $10\text{cm}$ 
aoVal: C
content: $15\text{cm}$ 
aoVal: D
content: $18\text{cm}$ 
aoVal: E
content: $12\text{cm}$ 
Answer: C
Analysis: If $$6\textasciitilde\text{cm}$$ represents $$50\textasciitilde\text{km}$$, $$3\textasciitilde\text{cm}$$ represents $$25\textasciitilde\text{km}$$. So, their distance apart on the map is $$125\div25\times 3=15\textasciitilde\text{cm}$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Basic Units
Problem: How many days are there in exactly $$52$$ weeks? 
Options:
aoVal: A
content: $$364$$ 
aoVal: B
content: $$365$$ 
aoVal: C
content: $$366$$ 
aoVal: D
content: $$367$$ 
Answer: A
Analysis: Each week has $$7$$ days, so $$52$$ weeks has $$52 \times 7 = 364$$ days. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method
Problem: A "combo"~ticket to enter the fair and ride unlimited rides is ＄$$30$$. A``per ride" ticket costs ＄$$12.50$$ to enter and ＄$$5$$ per ride. For a"combo''ticket to cost less than a "per ride" ticket, a person must go on at least  rides. 
Options:
aoVal: A
content: $$3$$ 
aoVal: B
content: $$4$$ 
aoVal: C
content: $$6$$ 
aoVal: D
content: $$7$$ 
Answer: B
Analysis: A fair sells a``combo" ticket for ＄$$30$$ entry and a ``per ride" ticket for ＄$$12.50$$ to enter plus ＄$$5$$ per ride. A``per ride" ticket costs ＄$$12.50+$$ ＄$$15 =$$＄$$27.50$$ for $$3$$ rides and ＄$$12.50 +$$ ＄$$20 = $$＄$$32.50$$ for $$4$$ rides. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts
Problem: Niki usually leaves her cell phone on. If her cell phone is on but she is not actually using it, the battery will last for $$24$$ hours. If she is using it constantly, the battery will last for only $$3$$ hours. Since the last recharge, her phone has been on $$9$$ hours, and during that time she has used it for $$60$$ minutes. If she doesn\textquotesingle t use it any more but leaves the phone on, how many more hours will the battery last? 
Options:
aoVal: A
content: $$7$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$11$$ 
aoVal: D
content: $$14$$ 
Answer: B
Analysis: When not being used, the cell phone uses up $$\dfrac{1}{24}$$ of its battery per hour. When being used, the cell phone uses up $$\dfrac{1}{3}$$ of its battery per hour. Since Niki\textquotesingle s phone has been on for $$9$$ hours, of those $$8$$ simply on and~~being used to talk, $$8\left(\dfrac{1}{24}\right)+1\left(\dfrac{1}{3}\right)=\dfrac{2}{3}$$ of its battery has been used up. To drain the remaining $$\dfrac{1}{3}$$ the phone can last for $$\dfrac{\dfrac{1}{3}}{\dfrac{1}{24}}=\boxed{(\text{B})8}$$ more hours without being used. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Work Word Problems->Simple Work Word Problems
Problem: A worm is staying at the bottom of a well with a depth of $$11$$ meters. If it climbs up $$3$$ meters in the day time and slips down $$1$$ meter at night, which day will it climb up to the ground? 
Options:
aoVal: A
content: $$3$$ 
aoVal: B
content: $$4$$ 
aoVal: C
content: $$5$$ 
aoVal: D
content: $$6$$ 
aoVal: E
content: $$7$$ 
Answer: C
Analysis: It climbs up $$3$$ meters in the day time and slips down $$1$$ meter at night, so it climbs up $$2$$ meters in a whole day. For the first $$4$$ days, it climbs $$8$$ meters. During the day time of the fifth day, it climbs $$3$$ meters and reaches the ground. Then it needs five days to climb up to the ground. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Snail Climbing out of Well Problems
Problem: The sum of the ages of Anita and Peter is $$20$$ years. What is the sum of their ages three years ago? 
Options:
aoVal: A
content: $$18$$ 
aoVal: B
content: $$17$$ 
aoVal: C
content: $$14$$ 
aoVal: D
content: $$11$$ 
Answer: C
Analysis: $20-3\times2=14$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems->Basic Relationships in Age Problems->Basic Sum and Differences Problems in Age Problems
Problem: James makes a long noodle. He takes some bites of the noodle, each time eating $5$ cm of the noodle from the middle of only one piece. At last, he has $12$ pieces of the noodle with the total length of $24$ cm. How long was the entire noodle in cm at the beginning? (Adapted from 2022 AMC 8 Problem, Question \#11) 
Options:
aoVal: A
content: $$94$$ 
aoVal: B
content: $$89$$ 
aoVal: C
content: $$80$$ 
aoVal: D
content: $$79$$ 
aoVal: E
content: $$75$$ 
Answer: D
Analysis: There are $12$ pieces of noodle left, so he takes $12-1=11$ bites of the noodle. Thus, the length of the noodle he ate is $11\times5=55$ cm. The total length of the entire noodle was $55+24=79$ cm. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems
Source: 其它
Problem: A mixture of $25$ liters of paint is $16 \textbackslash\%$ red tint, $24\textbackslash\%$ yellow tint and $60\textbackslash\%$ water. $15$ liters of yellow tint are added to the original mixture. What is the percent of yellow tint in the new mixture? (adapted from 2007 AMC 8, Question \#17 ) 
Options:
aoVal: A
content: $$52.5$$ 
aoVal: B
content: $$55$$ 
aoVal: C
content: $$57.5$$ 
aoVal: D
content: $$60$$ 
Answer: A
Analysis: The original mixture contains $25\times 24\textbackslash\% = 6$ liters of yellow tint.  $$15$$ liters of yellow tint is added to the mixture, the new mixture now has $6+15=21$ liters of yellow tint.  New percent of yellow =$\frac{21}{25+15} =52.5\textbackslash\% $ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems
Source: 其它
Problem: Edwin has three flowers, one red, one blue and one yellow. They have $50$ petals in total. The blue flower has $4$ petals less than the red one and $5$ petals more than the yellow one. How many petals does the red flower have? 
Options:
aoVal: A
content: $$12$$ 
aoVal: B
content: $$13$$ 
aoVal: C
content: $$17$$ 
aoVal: D
content: $$21$$ 
aoVal: E
content: $$22$$ 
Answer: E
Analysis: Blue: $(50 + 5 - 4) \div 3 = 17$  Red: $17 + 4 = 21$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Word Problems Involving Comparing and Ordering
Source: 其它
Problem: Mike has a bookcase with three layers, and the proportion of books placed on the upper, middle and lower layers is $$5:6:4$$. Given that there are $$240$$ books on the middle level,  books should be removed from middle level and added to the lower level so that the number of books on each level can be exactly the same. 
Options:
aoVal: A
content: $$48$$ 
aoVal: B
content: $$40$$ 
aoVal: C
content: $$60$$ 
aoVal: D
content: $$80$$ 
Answer: B
Analysis: Lower level: $$240\div6\times4=160$$,  The number of books to be added to the lower level: $$(240-160)\div2=40$$.  So, the answer is $$\text{B}$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Ratio Word Problems with an Invariant Part
Problem: Barb likes to help her father with housework. She dusts every $3$ days, sweeps every $4$ days, and cooks dinner every $5$ days. If she does all $3$ chores on one Sunday, she next does all $3$ on the same day on a ． 
Options:
aoVal: A
content: Wednesday 
aoVal: B
content: Thursday 
aoVal: C
content: Friday 
aoVal: D
content: Saturday 
Answer: B
Analysis: The least common multiple of $3$, $4$ and $5$ is $60$. We know that $60\div7=8\ldots\ldots4$, then the remainder tells us that it will be on Thursday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: This year, October $$28$$ falls on a Sunday. What day of the week will it be after $$38$$ days? (adapted from 2015 Math Kangaroo Problem, Level 3-4, Question \#8) 
Options:
aoVal: A
content: Wednesday 
aoVal: B
content: Thursday 
aoVal: C
content: Tuesday 
aoVal: D
content: Friday 
aoVal: E
content: Sunday 
Answer: A
Analysis: $$38\div7=5 \text{R} 3$$, three days after Sunday, which is Wednesday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: A family made a $$100\text{km}$$ trip. For half the distance, they drove at $$50\text{km}$$~ per hour; for the other half, they drove at $$25\text{km}$$~ per hour How many hours did this trip take? 
Options:
aoVal: A
content: $$3$$ 
aoVal: B
content: $$4$$ 
aoVal: C
content: $$5$$ 
aoVal: D
content: $$6$$ 
Answer: A
Analysis: For the first $$50\text{km}$$, they drove at $$50\text{km/hr}$$-that took $$1\text{hr}$$. For the other second $$50\text{km}$$, they drove at $$25\text{km/hr}$$-that took $$2\text{hrs}$$ . The trip took $$3\text{hrs}$$ . 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Problem: James has $600$ g of a $$8\textbackslash\%$$ salt solution, and then $120$ g of water evaporates. Find the percent concentration of salt solution at this time. 
Options:
aoVal: A
content: $10\textbackslash\%$ 
aoVal: B
content: $12\textbackslash\%$ 
aoVal: C
content: $15\textbackslash\%$ 
aoVal: D
content: $18\textbackslash\%$ 
Answer: A
Analysis: $$600\times 8\textbackslash\%=48$$ g,  $$600-120=480$$ g,  $$48\div 480\times 100\textbackslash\%=10\textbackslash\%$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems
Problem: Alex is $8$ years older than her two sisters who are twins. The sum of the ages of all three girls is $32$ years old. How old is Alex? ($2007$ Math Kangaroo Problem, Level $5$-$6$, Question \#$9$) 
Options:
aoVal: A
content: $$12$$ 
aoVal: B
content: $$18$$ 
aoVal: C
content: $$16$$ 
aoVal: D
content: $$20$$ 
aoVal: E
content: $$14$$ 
Answer: C
Analysis: The age of each twin is $(32-8) \div 3 =8$ years old. Thus, Alex is $8 +8 =16$ years old. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems
Source: 其它
Problem: The rabbit Cici picks mushrooms in the forest. She finds one mushroom every $5$ meters, and she finds $8$ mushrooms in total. How long does Cici walk from where she finds the first mushroom to where she finds the last one? 
Options:
aoVal: A
content: $$13$$ 
aoVal: B
content: $$35$$ 
aoVal: C
content: $$36$$ 
aoVal: D
content: $$40$$ 
Answer: B
Analysis: There are $8-1=7$ spaces. $7\times 5=35$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems
Source: 其它
Problem: Given March $$25$$ of a certain year is Monday, what day of the week would May $$1$$ fall on that year? ． 
Options:
aoVal: A
content: Tuesday 
aoVal: B
content: Wednesday 
aoVal: C
content: Thursday 
aoVal: D
content: Friday 
Answer: B
Analysis: $$1$$ May is $$6+30+1=37$$ days after March $$25$$. Since $$37\div7=5 \text{ R }2$$, $$5$$ weeks after is still Monday and $$2$$ days after that is a Wednesday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: Jane released a homing pigeon at $$5:30\rm$$ a.m.. The pigeon arrived at its destination at $$11:30\rm$$ a.m.. How many miles did the pigeon travel if it flies $$120$$ miles in $$2$$ hours? (adapted from 2007 Math Kangaroo Problem, Level 5-6, Question \#18) 
Options:
aoVal: A
content: $$120$$ 
aoVal: B
content: $$720$$ 
aoVal: C
content: $$360$$ 
aoVal: D
content: $$300$$ 
aoVal: E
content: $$420$$ 
Answer: C
Analysis: The flying speed is $$120\div2=60$$ miles/hr, and the flying time is $$11:30-5:30=6$$ hours. So, the total distance is $$60\times 6=360$$ miles. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Problem: A bag of toffee is $8$ dollars, a bag of cotton candy is $6$ dollars, and a bag of orange candy is $13$ dollars. Now, the candy shop decides to mix $30$ bags of toffee, $50$ bags of cotton candy, and $20$ bags of orange candy for $100$ bags of assorted candy. What should be the price of the assorted candy in dollars to keep the total revenue unchanged? 
Options:
aoVal: A
content: $$7.5$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$9.5$$ 
aoVal: D
content: $$10$$ 
aoVal: E
content: $$12$$ 
Answer: B
Analysis: Total revenue: $30\times 8+50\times 6+20\times 13=800$ dollars  A bag of assorted candy: $$800\div 100=8$$ dollars 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems
Problem: There are some ducks and sheep in a farm. The number of sheep is $10$ more than ducks. The number of ducks is half the number of sheep. In total, how many ducks and sheep are there in the farm?  ~ 
Options:
aoVal: A
content: $26$ 
aoVal: B
content: $$30$$ 
aoVal: C
content: $$33$$ 
aoVal: D
content: $$39$$ 
aoVal: E
content: $$40$$ 
Answer: B
Analysis: $10+10+10=30$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: Pat paints twice as fast as Lee. If it took Lee $6$ hours to paint a room, how long would it have taken if both had painted the room together? 
Options:
aoVal: A
content: $2$ hours 
aoVal: B
content: $3$ hours 
aoVal: C
content: $9$ hours 
aoVal: D
content: $18$ hours 
Answer: A
Analysis: Lee paints the room once in $6$ hours. Pat paints the room twice in $6$ hours. Together, they paint the room $3$ times in $6$ hours. So, it takes them $2$ hours to paint it once together. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Work Word Problems->Collaborative Work Word Problems
Problem: Ben and Ken have some books. After Ben sends $4$ books to Ken, he has $1$ fewer book than Ken. Which of the following is true? 
Options:
aoVal: A
content: Originally, Ben had $3$ more books than Ken. 
aoVal: B
content: Originally, Ben had $4$ more books than Ken. 
aoVal: C
content: Originally, Ben had $1$ fewer book than Ken. 
aoVal: D
content: Originally, Ben had $9$ more books than Ken. 
aoVal: E
content: Originally, Ben had $7$ more books than Ken. 
Answer: E
Analysis: $4+4-1=7$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems 
Source: 其它
Problem: John bought $10$ pencils and notebooks in total for £$44$. Each pencil cost £$$2$$. Each notebook costs £$$8$$. How many notebooks did John buy? 
Options:
aoVal: A
content: $$4$$ 
aoVal: B
content: $$5$$ 
aoVal: C
content: $$6$$ 
aoVal: D
content: $$7$$ 
aoVal: E
content: $$8$$ 
Answer: A
Analysis: If all were pencils,  $10\times 2= 20$  the total cost would be £$$20$$.  $44- 20=24$  The difference is £$$24$$.  $8-2=6$  $24\div 6=4$  John bought $4$ notebooks. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Chicken-Rabbit Problems->Solving Chicken-Rabbit Problems by Using Hypothesis
Problem: Lily\textquotesingle s age plus Judy\textquotesingle s age was equal to $$17$$ two years ago. What is the sum of their ages this year? (adapted from 2016 Math Kangaroo Problem, Level 1-2, Question \#16) 
Options:
aoVal: A
content: $$16$$ 
aoVal: B
content: $$17$$ 
aoVal: C
content: $$18$$ 
aoVal: D
content: $$19$$ 
aoVal: E
content: $$21$$ 
Answer: E
Analysis: $17 + 2 \times 2 = 21$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems->Basic Relationships in Age Problems->Sum of Ages
Source: 其它
Problem: If I start with $2$, and begin to count by $$3\textquotesingle$$s, my $50^{}\text{th}$ number will be~\uline{~~~~~~~~~~}~. 
Options:
aoVal: A
content: $$148$$ 
aoVal: B
content: $$149$$ 
aoVal: C
content: $$150$$ 
aoVal: D
content: $$151$$ 
aoVal: E
content: $$152$$ 
Answer: B
Analysis: $2+(50-1)\times3=149$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Practical Application of Arithmetic Progression
Problem: Jucy and Nicole are celebrating their birthdays together. Seven years ago, when Jucy turned $6$ years old, she received a newborn cat as a birthday present. Today the sum of the ages of the two people and the cat is $34$ years. Jucy is~\uline{~~~~~~~~~~}~years younger than Nicole. 
Options:
aoVal: A
content: $$1$$ 
aoVal: B
content: $$2$$ 
aoVal: C
content: $$3$$ 
aoVal: D
content: $$4$$ 
Answer: A
Analysis: Seven years ago:  Jucy : $7$  cat: $$0$$  This year:  Jucy : $7+6=13$  cat: $0+7=7$  Nicole : $34-13-7=14$$  $$14-13=1$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems
Source: 其它