math-eval/TAL-SCQ5K huggingface dataset:
Problem: Al ran twice as far as Bob ran. They ran a total off $$18\rm km$$. How far did Al run? 
Options:
aoVal: A
content: $$3\rm km$$ 
aoVal: B
content: $$6\rm km$$ 
aoVal: C
content: $$9\rm km$$ 
aoVal: D
content: $$12\rm km$$ 
Answer: D
Analysis: Al ran twice as far as Bob. Split $$18\rm km$$ into two parts, one twice the other, to see that Bob ran $$6\rm km$$ and Al ran twice as far, $$12\rm km$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems of Sum and Multiple
Problem: David has $$15$$ more candies than Andy at the beginning. David has $$3$$ candies more than Andy after giving some candies to Andy. How many candies does Debbic give to Aiden? 
Options:
aoVal: A
content: $$10$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$6$$ 
aoVal: D
content: $$4$$ 
aoVal: E
content: $$2$$ 
Answer: C
Analysis: $$15-3=12$, $$8\div 2=4$$. $$\text{D}$$． 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples
Problem: Adam paid ＄$$6$$ for $$15$$ buns. How many dollars did Tom pay for the same kind of buns if he bought $$5$$ more of them? (2008 Math Kangaroo Problem, Level 1-2, Question \#13) 
Options:
aoVal: A
content: $$7$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$9$$ 
aoVal: D
content: $$10$$ 
Answer: B
Analysis: There are $$3$$ groups of $$5$$ buns in $$15$$ buns: $$15\div 5=3$$, so $$5$$ buns cost $$6\div 3=$$＄$$2$$.  In total, Tom bought $$15 + 5 = 20$$ buns, which is $$4$$ groups of $$5$$ buns. So, Tom paid $$4\times 2 =$$＄$$8$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division
Problem: If $$20$$ years ago Allen was half as old as he is today, how old was he $$10$$ years ago? 
Options:
aoVal: A
content: $$20$$ 
aoVal: B
content: $$30$$ 
aoVal: C
content: $$40$$ 
aoVal: D
content: $$50$$ 
Answer: B
Analysis: If $$20$$ years ago Allen was half as old as he is today, then today he is $$40$$. Thus, $$10$$ years ago he was $$30$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems->When..., When... Type Age Problems
Problem: A teacher distributes scorecards equally to students, and there is a surplus of $8$ cards. If $2$ more cards are given to each student, all the cards will be distributed. Then there arestudents in the class in total. 
Options:
aoVal: A
content: $$2$$ 
aoVal: B
content: $$4$$ 
aoVal: C
content: $$6$$ 
aoVal: D
content: $$8$$ 
Answer: B
Analysis: If $2$ more scorecards are given to each student, all the cards are distributed. Therefore, the class has $8\div2=4$ students. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division
Problem: Ryan buys a watch on sale for $$20\textbackslash\%$$ off in a shopping mall. He has an additional $$200-$$dollar coupon since he is a member of this shopping mall. The sales tax in his city is $$5\textbackslash\%$$, and he paid $$\textbackslash$2730$$ for this watch. What was the original price of the watch? 
Options:
aoVal: A
content: ＄$$2600$$ 
aoVal: B
content: ＄$$2800$$ 
aoVal: C
content: ＄$$3200$$ 
aoVal: D
content: ＄$$3500$$ 
Answer: D
Analysis: $$\dfrac{2730}{1+5\textbackslash\%}=2600$$,  $$\dfrac{2600+200}{1-20\textbackslash\%}=3500$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Tax Problems
Problem: Workers want to plant some trees between houses. There are $17$ houses on one side of a road. Workers want to plant three trees between every two adjacent houses. How many trees do they need to plant? 
Options:
aoVal: A
content: $$45$$ 
aoVal: B
content: $$48$$ 
aoVal: C
content: $$51$$ 
aoVal: D
content: $$54$$ 
aoVal: E
content: $$57$$ 
Answer: B
Analysis: $(17 - 1）\times 3 = 48$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems
Source: 其它
Problem: A sum of $$\textbackslash$459$$ was shared among $$5$$ boys and $$14$$ girls. Each girl received $$\textbackslash$16$$.  How much did each boy get? 
Options:
aoVal: A
content: $$$38$$ 
aoVal: B
content: $$$47$$ 
aoVal: C
content: $$$52$$ 
aoVal: D
content: $$$56$$ 
Answer: B
Analysis: Girls $=14\times\textbackslash$16=\textbackslash$224$  Boys $=\textbackslash$459-\textbackslash$224=\textbackslash$235$  Each boy $=\textbackslash$235\div5=\textbackslash$47$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Unitary Method with One Variable
Problem: The radius of a coin is $$3\text{cm}$$. When $$4000$$ of these coins are placed side by side in a straight line, how long would this line be? 
Options:
aoVal: A
content: $$240\text{cm}$$ 
aoVal: B
content: $$12\text{m}$$ 
aoVal: C
content: $$240\text{m}$$ 
aoVal: D
content: $$1.2\text{km}$$ 
aoVal: E
content: $$2.4\text{km}$$ 
Answer: C
Analysis: The length of the line is $$4000\times 2\times 3\text{cm=}24000\text{cm=}240\text{m}$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method
Problem: Alicia, Bryant, and Charles work for a software company and they want to write a particular computer program. Alicia and Bryant first write $\frac{1}{3}$ of the program in $6$ days. Then Bryant and Charles write $\frac{1}{4}$ of the remaining program in $2$ days. In the end three of them work together to finish the program in $5$ days. How many days will it take if Alicia works on the program by herself? 
Options:
aoVal: A
content: $$20$$ 
aoVal: B
content: $$36$$ 
aoVal: C
content: $$45$$ 
aoVal: D
content: $$60$$ 
aoVal: E
content: $$75$$ 
Answer: D
Analysis: In the second part, Bryant and Charles can write $\left( 1-\frac{1}{3} \right) \times \frac{1}{4}=\frac{1}{6}$ of the program in 2 days. Therefore, they can write $\frac{1}{6} \div 2 =\frac{1}{12}$ in one day. There is still $1-\frac{1}{3}-\frac{1}{6}=\frac{1}{2}$ left.  Now in the last part, they work together and finish in $5$ days. They can write $\frac{1}{2} \div 5=\frac{1}{10}$ in one day. Therefore, Alicia can write $\frac{1}{10}-\frac{1}{12}=\frac{1}{60}$ in one day, which means she needs $60$ days to complete. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: A gardener has a box of bulbs to plant in a garden. The garden has three sections.  She plants 1/2~of the bulbs in the first section.  She plants 3 /4~of the remaining bulbs in the second section.  She has 6 bulbs left, which she plants in the third section.  How many bulbs were in the box at the start? 
Options:
aoVal: A
content: $$16$$ 
aoVal: B
content: $$18$$ 
aoVal: C
content: $$24$$ 
aoVal: D
content: $$32$$ 
aoVal: E
content: $$48$$ 
Answer: E
Analysis: 1- 1/2 - 1/2 x 3/4=1/8，1/8 means 6 bulbs, so in total there are 6~$\div$~1/8=48 bulbs. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: John is 8 years and 3 months old. Alice is 102 months old. Cindy has been alive for 4380 days. Who is the oldest? 
Options:
aoVal: A
content: John 
aoVal: B
content: Alice 
aoVal: C
content: Cindy 
Answer: C
Analysis: omitted 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time->Period of Dates
Source: 其它
Problem: As a Grade 1 student, Jenny saw thirteen seats in a row in the class, and she didn\textquotesingle t know which one belonged to her. The teacher told her that there were seven students behind her seat. So which seat should she sit?(Adapted from 2015 Math Kangaroo Problem, Level 1-2, Question \#18)  ~\hspace{0pt}\hspace{0pt}\hspace{0pt}\hspace{0pt} 
Options:
aoVal: A
content: $$5$$\textsuperscript{th} 
aoVal: B
content: $$6$$\textsuperscript{th} 
aoVal: C
content: $$7$$\textsuperscript{th} 
aoVal: D
content: $$8$$\textsuperscript{th} 
aoVal: E
content: $$9$$\textsuperscript{th} 
Answer: B
Analysis: $$13-7=6$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: A clothing store bought some shirts at＄$$96$$ each. It wants to earn＄$$24 $$ for each shirt after a discount of $$20 \textbackslash\% $$. What is the selling price before the discount for each shirt? 
Options:
aoVal: A
content: $$100$$ dollars 
aoVal: B
content: $$120$$ dollars 
aoVal: C
content: $$150$$ dollars 
aoVal: D
content: $$180$$ dollars 
Answer: C
Analysis: $$\left( 96+24 \right)\div \left( 1-20 \textbackslash\% \right)=150$$ dollars. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts
Problem: Iate half an apple pie on Saturday and two thirds of the remainder on Sunday. What fraction of the pie was left for Monday?　 
Options:
aoVal: A
content: None　 
aoVal: B
content: $$\frac{1}{2}$$ 
aoVal: C
content: $$\frac{1}{3}$$ 
aoVal: D
content: $$\frac{2}{3}$$ 
aoVal: E
content: $$\frac{1}{6}$$ 
Answer: E
Analysis: After I eat one half, half of the apple pie is left. Eating two thirds of this half leaves one third of one half of the pie, which is one sixth, for Monday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Understanding the Base
Problem: $$1$$ similar skirt and $$3$$ similar blouses cost $$$75$$. If each skirt costs twice as much as each blouse, how much will each skirt cost? 
Options:
aoVal: A
content: $$$30$$ 
aoVal: B
content: $$$25$$ 
aoVal: C
content: $$$20$$ 
aoVal: D
content: $$$15$$ 
Answer: A
Analysis: 1S + 3B = 75;  1S = 2B;  2B + 3B = 75;  5B = 75;  B = 75~$\div$~5 = 15  1S = 2~$\times$~15 = 30 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Equivalent Substitution in Equation Word Problems
Problem: Felix and Marmalade are two cats. Together they weigh $$10\text{kg}$$.  Felix weighs $$4\text{kg}$$ less than Marmalade. How much does Marmalade weigh? 
Options:
aoVal: A
content: $$3\text{kg}$$ 
aoVal: B
content: $$6\text{kg}$$ 
aoVal: C
content: $$7 \text{kg}$$ 
aoVal: D
content: $$9\text{kg}$$ 
aoVal: E
content: $$14 \text{kg}$$ 
Answer: C
Analysis: $$F=M-4$$  $$M-4+M=10$$  $$M=7$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems Involving Sum and Difference
Problem: Six friends went to hike together and agreed to share the bill equally. However, James forgot to bring his wallet, so each of his five friends paid an extra of $10.2$ dollars to cover James\textquotesingle~portion. How much did they have to pay in total? 
Options:
aoVal: A
content: $$51$$ 
aoVal: B
content: $$58.4$$ 
aoVal: C
content: $$255$$ 
aoVal: D
content: $$306$$ 
aoVal: E
content: $$308.8$$ 
Answer: D
Analysis: Everyone should pay $10.2\times5=51$ dollars. $51\times 6=306$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems 
Source: 其它
Problem: Of $$60$$ people at a school board meeting, $$24$$ are men. The ratio of women to men at the meeting is． 
Options:
aoVal: A
content: $$3:2$$ 
aoVal: B
content: $$2:3$$ 
aoVal: C
content: $$11:6$$ 
aoVal: D
content: $$6:11$$ 
Answer: A
Analysis: Women: $$60-24=36$$,  Women: Men$$=36:24=3:2$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Basic Units
Problem: Water from the first faucet fills the swimming pool in $36$ hours. Water from each of the two other faucets fills the same swimming pool $4$ times faster. In how many hours will the swimming pool be filled if all three faucets are opened? 
Options:
aoVal: A
content: $$2$$ 
aoVal: B
content: $$3$$ 
aoVal: C
content: $$4$$ 
aoVal: D
content: $$5$$ 
Answer: C
Analysis: The efficiency of the first faucet is $\frac1{36}$ and that of the other two is $\frac4{36}$.  Thus it takes $1\div (\frac1{36}+\frac4{36}\times2)=4$ hours to fill the pool. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Work Word Problems
Source: 其它
Problem: My vacation will start three weeks and two days after yesterday. If today is Tuesday, my vacation will start on what day? 
Options:
aoVal: A
content: 　Monday 
aoVal: B
content: 　Tuesday 
aoVal: C
content: 　Wednesday 
aoVal: D
content: 　Thursday 
Answer: C
Analysis: Three weeks after yesterday, which was a Monday, is a Monday also. Two days after a Monday is a Wednesday. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: Mina put $12$ potted plants in a row from one end to the other end of the corridor. They were placed at an equal distance from one another. The distance between the first and the fifth potted plant was $28$ m. Mina went along the corridor from the first pot to the last pot. How many meters did she walk? 
Options:
aoVal: A
content: $$70$$ 
aoVal: B
content: $$77$$ 
aoVal: C
content: $$84$$ 
aoVal: D
content: $$91$$ 
aoVal: E
content: $$98$$ 
Answer: B
Analysis: $28 \div (5 - 1) = 7$  $7 \times (12 - 1) = 77$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems
Source: 其它
Problem: There are $6$ boxes each contains only oranges, apples, or pears. The boxes weigh $$15$$, $$16$$, $$18$$, $$19$$, $$20$$, and $$31$$ kg, respectively. If the total weight of apples is half of that of pears, and there is only one box of oranges, what is the weight of the box of oranges. 
Options:
aoVal: A
content: $$15$$ 
aoVal: B
content: $$18$$ 
aoVal: C
content: $$19$$ 
aoVal: D
content: $$20$$ 
aoVal: E
content: $$31$$ 
Answer: D
Analysis: The total weight of all the boxes is $15+16+18+19+20+31=119$ kg. The weight of pears is twice that of apples, so excluding the box of orange, the weight of the remaining boxes should be divisible by $3$. Only removing $20$, the remaining weight is divisible by $3$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Problem: A shop purchased some basketballs at ＄$$60$$ each. It then sold them at ＄$$75$$ each. How much did the shopkeeper earn for $$10$$ basketballs? 
Options:
aoVal: A
content: ＄$$150$$ 
aoVal: B
content: ＄$$200$$ 
aoVal: C
content: ＄$$250$$ 
aoVal: D
content: ＄$$300$$ 
Answer: A
Analysis: $$(75-60)\times 10 = 150$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method
Problem: Some students are going to an amusement park. If each student carries $9$ bottles of water in his or her backpack, there will be $2$ students left carrying nothing; if one of the students carries $2$ bottles of water and the rest students carry $8$ bottles each, all the bottles of water can be carried to the park. There are~\uline{~~~~~~~~~~}~bottles of water in total that need to be carried. 
Options:
aoVal: A
content: $$80$$ 
aoVal: B
content: $$90$$ 
aoVal: C
content: $$92$$ 
aoVal: D
content: $$102$$ 
Answer: B
Analysis: Solve the problem as a problem of surplus and shortage. If each student carries $9$ bottles, there will be a shortage of $9\times2=18$ bottles;  if each student carries $8$ bottles, there will be a shortage of $8-2=6$ bottles. Therefore, there are $(18-6)\div(9-8)=12$ students and $12\times9-18=90$ bottles of water. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Distribution Problems->Distribution Conversion Problems
Problem: Seventh grade students from a school line up and form a square array. There are $196$ students in the outermost layer. How many students in total are there in this array? 
Options:
aoVal: A
content: $$1960$$ 
aoVal: B
content: $$2401$$ 
aoVal: C
content: $$2000$$ 
aoVal: D
content: $$2601$$ 
aoVal: E
content: $$2500$$ 
Answer: E
Analysis: The number of students on each side of the outermost layer was $$196\div 4+1=50$$ students. The total number of students in the array was $$50\times 50=2500$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Squares->Solid Squares
Problem: Given March $$25$$ of a certain year is Monday, what day of the week would May $$1$$ fall on this year? ． 
Options:
aoVal: A
content: Tuesday 
aoVal: B
content: Wednesday 
aoVal: C
content: Thursday 
aoVal: D
content: Friday 
Answer: B
Analysis: $(31-25+30+1=37$  $37\div7=5R2$  Exactly $5$ weeks from $25$ Mar, it will also be a Monday; another $2$ days later will be a Wednesday 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time
Problem: A mixture of 45 liters of paint is $20 \textbackslash\%$ red tint, $30 \textbackslash\%$ yellow tint and $50 \textbackslash\%$ water. Five liters of yellow tint are added to the original mixture. What is the percent of yellow tint in the new mixture? (2007 AMC 8, Question \#17 ) 
Options:
aoVal: A
content: $$30$$ 
aoVal: B
content: $$35$$ 
aoVal: C
content: $$37$$ 
aoVal: D
content: $$39$$ 
aoVal: E
content: $$40$$ 
Answer: C
Analysis: Since $30 \textbackslash\%$ of the original 45 liters of paint was yellow, and 5 liters of yellow paint were added to make the new mixture, there are $13.5+5=18.5$ liters of yellow tint in the new mixture. Since only 5 liters of paint were added to the original 45 , there are a total of 50 liters of paint in the new mixture. This gives $ 37\textbackslash\%$ of yellow tint in the new mixture, which is (C) 37 . 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems
Source: 其它
Problem: A ship is being attacked by pirates. One by one the pirates climb a rope to get on the ship. The pirate captain is the $$8$$\textsuperscript{th} in line, and there are as many pirates in front of him as there are behind him. How many pirates are in line to climb the rope?（）($$2015$$ Math Kangaroo Problem, Levels $$1-2$$, Question \#$$18$$) 
Options:
aoVal: A
content: $$7$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$15$$ 
aoVal: D
content: $$16$$ 
Answer: C
Analysis: The $$8$$\textsuperscript{th} means there are $$7$$ people in front of him. So there are also $$7$$ people behind him. The total number of pirates can be calculated: $$7+7+1=15$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Problems Involving Queuing->Finding the Total Number According to the Position of one Character in a Line
Problem: A $$12$$-metre long steel pipe was cut into few pieces. The length of each piece is $$3$$ metres. It takes $$18$$ minutes to complete the whole process. How long does it take to cut a $$12$$-metre pipe into $$6$$-metre sections? 
Options:
aoVal: A
content: $$6$$ minutes 
aoVal: B
content: $$9$$ minutes 
aoVal: C
content: $$12$$ minutes 
aoVal: D
content: $$18$$ minutes 
aoVal: E
content: None of the above 
Answer: A
Analysis: $$18\div3=6$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems
Source: 其它
Problem: A city council decided to put lanterns on both sides of a river. The distance between any two neighbouring lanterns on each side must be $11$ metres. The length of the river is $132$ metres. The distance between the first and the last lantern on each side must be also $132$ metres. How many lanterns will there be in total? 
Options:
aoVal: A
content: $$12$$ 
aoVal: B
content: $$13$$ 
aoVal: C
content: $$24$$ 
aoVal: D
content: $$26$$ 
aoVal: E
content: None of the above 
Answer: D
Analysis: 132/11 = 12 lanterns  12 lanterns + 1 = 13 lanterns  13 x 2 = 26 lanterns. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying of Multiplication and Division
Source: 其它
Problem: Nine bus stops are equally spaced along a certain bus route. The distance between the first stop and the third stop is $$600$$ m. How long is the bus route? ($$2004$$ Math kangaroo Problem, Level $$5-6$$, Question \#$$9$$) 
Options:
aoVal: A
content: $$1800$$ m 
aoVal: B
content: $$2100$$ m 
aoVal: C
content: $$2400$$ m 
aoVal: D
content: $$2700$$ m 
aoVal: E
content: $$3000$$ m 
Answer: C
Analysis: Each interval is $600\div2=300$ m. There are $9-1=8$ intervals in total, so the bus route\textquotesingle s length is $300\times8=2400$ m. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems->Straight Line Type with Objects on Both Sides->Planting Trees on Both Sides
Source: 其它
Problem: A ship is being attacked by pirates. One by one the pirates climb a rope to get on the ship. The pirate captain is the $$8$$\textsuperscript{th} in line, and there are as many pirates in front of him as there are behind him. How many pirates are in line to climb the rope?（） 
Options:
aoVal: A
content: $$7$$ 
aoVal: B
content: $$8$$ 
aoVal: C
content: $$15$$ 
aoVal: D
content: $$16$$ 
Answer: C
Analysis: The $$8$$\textsuperscript{th} means there are $$7$$ people in front of him. So there are also $$7$$ people behind him. The total number of pirates can be calculated: $$7+7+1=15$$. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Problems Involving Queuing->Finding the Total Number According to the Position of one Character in a Line
Problem: Students in the third grade lined up and formed a square array to perform a dance. Each side of the outermost layer had $37$ students. How many students in total are there in the outermost layer? 
Options:
aoVal: A
content: $$148$$ 
aoVal: B
content: $$152$$ 
aoVal: C
content: $$144$$ 
aoVal: D
content: $$140$$ 
aoVal: E
content: $$156$$ 
Answer: C
Analysis: $$36\times 4=144$$, or $$37\times 4-4=144$$ students. 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Squares->Solid Squares
Problem: On Think Planet, each Thinkyear has $8$ Thinkmonths and each Thinkmonth has $6$ Thinkweeks. How many Thinkweeks are there in one quarter of a Thinkyear? 
Options:
aoVal: A
content: $$48$$ 
aoVal: B
content: $$24$$ 
aoVal: C
content: $$16$$ 
aoVal: D
content: $$12$$ 
aoVal: E
content: $$8$$ 
Answer: D
Analysis: $8\times6\div4=12$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules
Source: 其它
Problem: When asked about his age, my uncle said "If you multiply my current age by $2$, then subtract the product by $6$, divide the answer by $2$ and then add $8$, the final answer is $38$." My uncle\textquotesingle s age isyears old． 
Options:
aoVal: A
content: $$8$$ 
aoVal: B
content: $$33$$ 
aoVal: C
content: $$38$$ 
aoVal: D
content: $$43$$ 
Answer: B
Analysis: $$[（38-8）\times2+6]\div2=33$$ 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Work Word Problems->Collaborative Work Word Problems->Finding the Working Hours
Problem: Alex, John and Sam went to buy oranges. Alex paid $\textbackslash$20$, John paid $\textbackslash$15$, and Sam only paid $\textbackslash$5$. They bought 120 oranges altogether. They divided them in proportion to the amount of money each of them had paid. How many oranges did John get? 
Options:
aoVal: A
content: $$15$$ 
aoVal: B
content: $$30$$ 
aoVal: C
content: $$45$$ 
aoVal: D
content: $$60$$ 
aoVal: E
content: None of the above 
Answer: C
Analysis: A: J: S  20:15:5 = 40  120/40 = 3 oranges per person  3*15= 45 oranges 
Knowledge points: Overseas Competition->Knowledge Point->Word Problem Modules->Applying of Multiplication and Division
Source: 其它