Abstract:
A device ( 1 ) for the tracheal intubation of and the administration of ventilation to a patient for rapid volume-compensating sealing of the trachea, wherein the sealing surfaces of a preferably fully and residually formed balloon-like film body ( 4 ) abut the wall of the trachea with a sealing pressure of the balloon ( 4 ) which is as constant as possible and follow the thoracic pressure acting on the balloon with the least possible time latency with regard to corresponding fluctuations of the balloon inflation pressure, and the trachea is kept sealed under such dynamic fluctuations or respiration synchronously alternating fluctuations of the balloon inflation pressure. This is enabled by a defined large lumen ( 7, 5 ) supply of the balloon inflation medium, the supplying lumen being measured in such a way that a sealing pressure-maintaining extracorporeal volume compensation that works in a time synchronous manner can be achieved in the sealing balloon element.

Description:
REFERENCE TO PENDING PRIOR PATENT APPLICATIONS 
       [0001]    This patent application claims benefit of International (PCT) Patent Application No. PCT/IB2015/002309, filed 4 Dec. 2015 by Creative Balloons GmbH for DEVICE AND METHOD FOR THE DYNAMICALLY SEALING OCCLUSION OR SPACE-FILLING TAMPONADE OF A HOLLOW ORGAN, which claims benefit of: (i) German Patent Application No. DE 10 2014 017 872.2, filed 4 Dec. 2014, (ii) German Patent Application No. DE 10 2015 000 621.5, filed 22 Jan. 2015, (iii) German Patent Application No. DE 10 2015 001 030.1, filed 29 Jan. 2015, (iv) German Patent Application No. DE 10 2015 002 995.9, filed 4 Mar. 2015 and (v) German Patent Application No. DE 10 2015 014 824.9, filed 18 Nov. 2015, which patent applications are hereby incorporated herein by reference. 
     
    
     FIELD OF THE INVENTION 
       [0002]    The invention is directed to a device and a method for the dynamic occlusion or tamponade of a hollow organ by means of a balloon-like element, in particular for the dynamic, aspiration-preventing seal of the intubated trachea in patients who are breathing independently and in patients in a machine-assisted spontaneous ventilation mode. 
       BACKGROUND OF THE INVENTION 
       [0003]    In many cases, the continuous motility of the organ itself is a fundamental problem associated with the sealing closure or space-filling tamponade of organs or cavities with a fillable, balloon-like element in a way that is gentle to the organ and efficient. Organs or body cavities that are limited by musculo-connective tissue often have autonomous motility or are subjected to the dynamics of adjacent organs or structures. In order to create a continuous seal of the organ lumen, autonomous or correspondingly motile organs require a particular regulating mechanism that reacts quickly to fluctuations in the organ diameter or changes in the tone of the organ wall. As the changes in diameter or tone occur, said mechanism must act as a synchronously as possible. 
         [0004]    The problem of dynamic, synchronized adaptation of a balloon occlusion of a hollow organ can be illustrated with the example of the human trachea. The trachea is a tube-like structure with portions composed of cartilaginous tissue, connective tissue and muscle. It extends from the lower section of the larynx to the branching of the main bronchi. The front and side portions of the trachea are stabilized by clip-like, approximately horseshoe-shaped structures, which in turn are connected to each other in the longitudinal direction by connective tissue-like layers of tissue. The trachea lumen is closed off on the rear-wall side by the so-called pars membranacea, which consists of material made of continuous musculo-connective tissue, without any reinforcing cartilaginous elements. The esophagus, which is made of musculo-connective tissue, lies on its dorsal side. 
         [0005]    The upper third of the trachea is usually located outside of the thorax, while the two lower thirds lie within the thoracic cavity delimited by the thorax and diaphragm. The lower thoracic portion of the trachea is thereby especially subjected to the pressure fluctuations in the thoracic cavity that occur as part of the thoracic respiratory mechanics of a spontaneously breathing patient as well as a patient who is spontaneously breathing with assistance. 
         [0006]    When the patient breathes in, the thoracic volume is enlarged by the lifting of the ribs and simultaneous lowering of the diaphragm, and the intrathoracic pressure therefore decreases. As a result of respiratory mechanics, this drop in pressure leads to the inflow of inhaled air into the lungs, which expands with the increase in thoracic volume. 
         [0007]    However, the pressure drop in the thorax associated with the increase in thoracic volume also leads to corresponding drops in pressure within filled balloon elements positioned in the patient&#39;s thorax. Balloon elements such as these are used in tracheal tubes and tracheostomy cannulas, for example, to seal the deep airways against inflowing secretions from the throat and to permit positive pressure ventilation of the patient&#39;s lungs. The cyclical drops in thoracic pressure caused by the patient&#39;s own breathing can move the sealing pressure in the balloons of ventilation catheters into low ranges, in which a sufficient seal against secretions that collect in the trachea above the sealing balloon (cuff) is no longer ensured. See Badenhorst C H, Changes in tracheal cuff pressure in respiratory support, Crit Care Med, 1987; 15/4: 300-302. 
         [0008]    Whereas the sealing performance of conventional PVC tracheal tube cuffs correlates very closely with the effective filling pressure in the cuff, the especially thin-walled polyurethane tracheal tube cuffs demonstrate significantly more stable sealing efficiency when the tracheal sealing pressures fall into ranges around 15 mbar. See Bassi G L, Crit Care Med, 2013; 41: 518-526. 
         [0009]    Of particular importance for the secretion seal of tracheal sealing balloons, however, is the pressure range from 5 to 15 mbar, which is easily achieved during the independent breathing of a patient, essentially from breath to breath. Seal-optimized ventilation catheters with micro-thin-walled PUR cuffs can also still ensure good sealing performance at ca. 10 mbar filling pressure. However, they cannot protect against inflowing, infectious secretions during pressure drops below 10 mbar to sub-atmospheric thoracic pressure values. 
         [0010]    No sealing technology is yet available for sealing the trachea by means of a cuff-like sealing balloon, which synchronizes with the breathing effort of the thorax, is atraumatic, seals efficiently over sufficiently wide ranges of filling pressure and is cost-effective to manufacture. Although many different technical embodiments of filling pressure-regulating devices for tracheal ventilation catheters are described in the prior art, a sufficiently synchronized adaptation of the sealing pressure to alternating thoracic pressures, as are observed in autonomous breathing in patients, has not yet been achieved. 
         [0011]    In the known ventilation catheters, the trachea-sealing balloon element is usually filled by small-bore filling lines which are extruded into the shaft of the catheter. The small cross-sections of the filling lines generally do not ensure a flow rate of the filling medium which fills the balloon that is sufficiently strong to maintain a tracheal seal during the drop in thoracic pressure. Even technically complicated extracorporeal control mechanisms, such as the CDR 2000 device produced by Logomed GmbH (no longer commercially available), function inadequately because of the small-bore supply lines between the sealing balloon element and the regulator. 
       SUMMARY OF THE INVENTION 
       [0012]    The present invention describes a novel catheter technology that permits a quick flow rate between a regulating mechanism outside the body and a balloon-like sealing element placed in the trachea by means of an especially flow-efficient supply line for the filling medium. Technologically simple and cost-effective means are used to compensate for the cuff volume in a way that is sufficiently synchronized for the dynamic sealing of the trachea of a spontaneously breathing patient and that maintains the seal. 
         [0013]    The invention further describes a thin-walled ventilation catheter shaft that has a single lumen and a shaft wall that is preferably stabilized by a corrugated tube-like corrugation. The corrugation of the shaft permits especially low wall thicknesses, which optimally allows for large inner lumens for the particularly low-resistance breathing of the patient. The corrugation additionally gives the shaft a particular low-tension or non-elastic axial flexibility and thus adaptability in the trachea of a spontaneously breathing patient. A flexible shaft such as this can additionally be made of especially hard PUR types, which then permit particularly thin wall thicknesses. 
         [0014]    One possible embodiment of the invention is based on a balloon element which is fixedly and sealingly attached to the supporting shaft body at the distal end of the ventilation catheter and the proximal end of which narrows almost to the outer dimensions of the catheter shaft, but leaves a coaxial gap for the shaft. This proximal extension of the balloon can extend into the thoracic section of the trachea, but can also be guided into the extra-thoracic sections of the trachea as far as the region of the vocal cords or also to the lower region of the throat, wherein a particular free gap is formed between the sleeve of the proximal balloon segment that narrows in this way and the enclosed shaft. 
         [0015]    The gap created in this way permits an especially large-bore, efficient volume flow between a volume reservoir disposed outside the body and the trachea-sealing balloon element. The gap further prevents potentially damaging direct contact by the corrugated catheter shaft with the epithelium of the trachea. 
         [0016]    The concentric arrangement of the catheter shaft in a tapering, tube-like proximal balloon-segment is advantageous especially in the region of the vocal cords. Here, the balloon envelope that encloses the shaft rests against the vocal cords in a protective way and prevents abrasive effects by the shaft when it moves relative to the respiratory tract. 
         [0017]    In the proximal section of the tracheal ventilation catheter, the end of the tube-like tapered balloon segment is preferably accommodated by a multi-lumen shaft element. This shaft element preferably has a supply line cross-section whose flow-affecting cross-section preferably corresponds to the flow-affecting cross-section of the gap between the shaft and the proximal balloon segment. A filling tube then attaches to the supply lumen integrated into the proximal catheter, said filling tube having a diameter with corresponding flow characteristics to those ensured within the catheter. 
         [0018]    The invention shows an example of a method of calculating the dimensions of the claimed gap created between the catheter shaft and the proximal extension of the balloon end or balloon body, which provides a good approximation of how large the radial gap must be in order to achieve a sufficiently compensating volume flow between the regulator and balloon in under 10 milliseconds after thoracic pressure begins to decrease. 
         [0019]    Both the proximal balloon segment surrounding the shaft and the distal balloon segment sealing the trachea are preferably produced from a material that is as thin-walled as possible and only slightly elastic. In this way, the required dimensional stability of the balloon body is ensured when it is loaded with filling pressure from the inside or under mechanical stress from the outside. 
         [0020]    The invention further describes various methods for quickly sealing the trachea in a volume-compensating way, wherein a claimed catheter provided with an occluding or tamponading balloon element is connected to an extracorporeal regulator device. By coupling the catheter with the regulator, an interior space is created that can be charged with isobaric filling pressure. 
         [0021]    The continuously flow-efficient, large-bore connection between the sealing balloon element and a volume source in which the pressure is kept constant represents the required synchronicity between the patient&#39;s thoracic respiratory activity and the volume flow that is needed to obtain the tracheal seal. 
         [0022]    Quick shifts in volume are permitted in the claimed combination of a catheter and a regulator, e.g. by gravity- or spring-powered regulators, which function in the range of low, physiologically harmless pressures, i.e. in a pressure range of ca. 25 to 35 mbar, and do not require unphysiologically high pressure gradients that force the volume flow in order to ensure sufficient volume flows over the connecting supply line between the cuff and regulator. 
         [0023]    The regulator can be configured according to the design described in PCT/EP/2013/056169, for instance. The present invention is preferably designed for this simple form of control by a communicating system of interior spaces under isobaric pressure in the physiological pressure range of 20 to 50, preferably 20 to 35 mbar. 
         [0024]    The claimed optimized volume flow between the trachea-sealing balloon body and the extracorporeal regulator can also be achieved with tracheal tubes and tracheostomy cannulas of a conventional design, insofar as the supplying feed channel has a flow-affecting cross-sectional area that corresponds to a circular cross section with a circular diameter of at least 2 mm and preferably a circular diameter of 4 to 6 mm. In products with a convention design, the volume-supplying channel is usually circular and has an inner diameter of ca. 0.5 to 0.7 mm. The channel is extruded into the shaft wall of the tube shaft. It transitions outside the shaft into a tube line, which is normally connected to a one-way valve. For the purpose of the thinnest-walled shafts possible and/or in order to permit the largest possible inner diameter of the ventilation lumen, the supply lines in the shaft wall are kept correspondingly low-caliber. 
         [0025]    The principle of flow-optimized volume compensation described above can similarly be applied to the dynamic tamponade of the esophagus of a spontaneously breathing patient. The pressure fluctuations in a tamponade balloon placed in the esophagus, which correspond to independent breathing, are usually more pronounced than in a balloon placed in the trachea. They generally conform to the prevailing absolute intrathoracic pressure. To produce a balloon tamponade in the esophagus that seals as efficiently as possible, it is proposed that the balloon be segmented so that it corresponds to the trachea. While the distal segment of the balloon, which actually seals the esophagus, extends over the extent of the esophagus between its upper and lower sphincters, a tapering balloon segment attaches in the proximal direction and optionally extends to the proximal end of the catheter supporting the balloon. The diameter ratios that are hereafter represented on the ventilation catheter and that define the resulting gap between the shaft and the proximal balloon segment can also be applied in the case of gastric tubes for nutrition and/or decompression. Here, too, the shaft of the gastric tube can consist of a single-lumen, thin-walled tube that is corrugated, entirely or in segments, to improve the bending mechanics. The connection to an isobaric volume reservoir can occur in the manner according to the invention, similarly to the tracheal tube. 
     
    
     
       BRIEF DESCRIPTION OF THE DRAWINGS 
         [0026]    Further features, details, advantages and effects based on the invention arise from the following description of preferred embodiments of the invention and with the aid of the accompanying drawings. 
           [0027]      FIG. 1  shows a claimed tracheal tube in combination with an external volume-regulating device. 
           [0028]      FIG. 2  shows the volume-shafting gap S relative to the overall diameter G in the vicinity of the proximal balloon extension. 
           [0029]      FIG. 3  shows a tracheal tube with multiple volume-shifting supply lines arranged in or on the catheter shaft. 
           [0030]      FIG. 3 a    shows a cross-section of the supplying, shaft-integrated lumens of the tube described in  FIG. 3 . 
           [0031]      FIG. 4  shows a particular embodiment of the tube shown in  FIG. 1 , in which the trachea-sealing balloon extends beyond the glottis plane. 
           [0032]      FIG. 5  shows an illustrative embodiment of a claimed tracheostomy cannula. 
           [0033]      FIG. 6  shows a claimed tracheal tube with a sensor element in the region of the trachea-sealing balloon segment and a regulator unit that is arranged with a sensor in a control loop. 
           [0034]      FIG. 7  shows a combined valve/throttle mechanism which prevents the balloon from quickly emptying into the regulator/reservoir, which would be critical for the seal. 
           [0035]      FIG. 8  shows a gastric tube with a proximally extended balloon segment for the dynamically sealing tamponade of the esophagus in combination with an extracorporeal isobaric volume reservoir. 
       
    
    
     DETAILED DESCRIPTION OF THE PREFERRED EMBODIMENTS 
       [0036]      FIG. 1  describes, in an illustrative total overview, the communicating connection/coupling of a claimed device  1 , in the form of a tracheal tube, with a preferably gravity- or spring-driven, isobaric volume reservoir  2 . 
         [0037]    The supply chamber formed by the freely communicating coupling of the tracheal tube and volume reservoir  2  consists of the trachea-sealing balloon segment  4 , the tube-like tapered balloon end  5  that connects in the proximal direction, the supply lumen(s) in the proximal shaft element  6 , the flexible supply line  7  to the reservoir that attaches to the shaft as well as the reservoir volume  8  of the regulator. 
         [0038]    The distal shaft segment of the tube  3  supports a trachea-sealing balloon  4  at its distal end, said balloon being sealingly attached at its distal end  9   a  to the surface of the shaft. A tube-like proximal balloon segment  5 , which tapers relative to the diameter of the sealing balloon segment  4 , attaches to the balloon segment  4  in the proximal direction. Its proximal end locks tightly to the surface of the distal end  9   b  of the proximal shaft element  6 . 
         [0039]    If a decrease in intrathoracic pressure occurs during the course of inhaling (inspiration), and thus a corresponding transient widening of the tracheal cross-section, which in turn causes a corresponding drop in pressure within the balloon body placed in the trachea, volume flows from the reservoir  2  to the sealing balloon segment  4 , wherein the reservoir continuously charges the volume with a defined pressure. As a result, the tracheal sealing pressure can be maintained even when the patient inhales deeply, with a possible pressure drop in the thorax and/or in the trachea-sealing balloon to sub-atmospheric levels, without relevant losses in the sealing capacity. 
         [0040]    In a preferred embodiment, the reservoir  2  consists of a reservoir body  8 , which can be configured e.g. as a balloon or bellows, and establishes a constant isobaric pressure in the supply chamber by a force K acting on the reservoir. 
         [0041]    Crucial to achieving the smallest possible time latency between the initial widening of the tracheal cross-section or the initial reduction of the transmural thoracic forces acting on the tracheal sealing balloon and the start of a seal-creating shift of filling medium to the trachea-sealing balloon segment is, above all, the flow-affecting cross-sectional area of the gap S available the between the distal shaft segment  9  and the proximal extension  5  of the balloon. 
         [0042]    In the following figure, the invention proposes especially advantageously dimensioned ratios of the cross-sectional area S to the cross-sectional area of the ventilation lumen ID and to the overall cross-sectional area OD of the catheter between the proximal shaft  6  and the trachea-sealing balloon segment  4 . 
         [0043]      FIG. 2  shows a cross-section through the volume-supplying segment  5  of the balloon of the tracheal tube pictured in  FIG. 1 , said segment attaching to the trachea-sealing balloon in the proximal direction. 
         [0044]    S designates the gap surface that is preferred for the supply of filling medium to the balloon. It is defined as the difference between the cross-sectional area G, which is delimited by the sleeve wall of the supplying balloon end  5 , and the cross-sectional area OD of the shaft body, which is delimited by the outer surface of the shaft. Here the cross-sectional area S should be 1/10 to 5/10 of cross-sectional area G, especially preferably 2/10 to 3/10 of cross-sectional area G. 
         [0045]    Relative to the cross-sectional area ID of the inner lumen of the shaft body, cross-sectional area S should amount to 2/10 to 6/10 of cross-sectional area ID, especially preferably 3/10 to 4/10 of cross-sectional area ID. 
         [0046]    In addition to air as the preferred medium, liquid media can also be used to fill the trachea-sealing system. 
         [0047]    For the quantitative calculation of the flow conditions in the volume-conducting interior space of the balloon, in particular based on the pressure ratios in the trachea-sealing balloon segment  4 , the following place-holder values should be used: 
         [0000]    V i  Volume of the distal balloon segment  4 
 
p i  Pressure in the distal balloon segment  4 
 
ρ i  Filling density in the distal balloon segment  4 
 
M 1  Air mass in the distal balloon segment  4 
 
V 2  Volume of the extracorporeal reservoir  8 
 
P 2  Pressure in the extracorporeal reservoir  8 
 
ρ 2  Filling density in the extracorporeal reservoir  8 
 
m 2  Air mass in the extracorporeal reservoir  8 
 
         [0048]    The following applies for air masses m 1 , m 2 : 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       m 
                       1 
                     
                      
                     
                       ( 
                       t 
                       ) 
                     
                   
                   = 
                   
                     
                       m 
                       
                         1 
                         , 
                         0 
                       
                     
                     + 
                     
                       
                         ∫ 
                         
                           T 
                           = 
                           0 
                         
                         
                           T 
                           = 
                           t 
                         
                       
                        
                       
                         
                           
                             S 
                             
                               m 
                               , 
                               1 
                             
                           
                            
                           
                             ( 
                             T 
                             ) 
                           
                         
                          
                         
                           d 
                           T 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   1 
                   ) 
                 
               
             
             
               
                 
                   
                     
                       m 
                       2 
                     
                      
                     
                       ( 
                       t 
                       ) 
                     
                   
                   = 
                   
                     
                       m 
                       
                         2 
                         , 
                         0 
                       
                     
                     - 
                     
                       
                         ∫ 
                         
                           T 
                           = 
                           0 
                         
                         
                           T 
                           = 
                           t 
                         
                       
                        
                       
                         
                           
                             S 
                             
                               m 
                               , 
                               2 
                             
                           
                            
                           
                             ( 
                             T 
                             ) 
                           
                         
                          
                         
                           d 
                           T 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   2 
                   ) 
                 
               
             
           
         
       
     
         [0049]    S m,v  stands for the air flow to the respective balloon  4 ,  8  as an air mass flow. 
         [0050]    According to the Hagen-Poiseuille equation, the following is true for the mass fluid flow through a line with a circular cross-section and with an inner radius R and length I: 
         [0000]    
       
         
           
             
               
                 
                   
                     S 
                     
                       m 
                       , 
                       1 
                     
                   
                   = 
                   
                     
                       
                         ρ 
                         1 
                       
                       · 
                       
                         π 
                          
                         
                           ( 
                           
                             
                               p 
                               2 
                             
                             - 
                             
                               p 
                               1 
                             
                           
                           ) 
                         
                       
                       · 
                       
                         R 
                         4 
                       
                     
                     
                       8 
                        
                       
                         η 
                         · 
                         I 
                       
                     
                   
                 
               
               
                 
                   ( 
                   
                     3 
                      
                     a 
                   
                   ) 
                 
               
             
             
               
                 
                   
                     S 
                     
                       m 
                       , 
                       2 
                     
                   
                   = 
                   
                     
                       
                         ρ 
                         2 
                       
                       · 
                       
                         π 
                          
                         
                           ( 
                           
                             
                               p 
                               1 
                             
                             - 
                             
                               p 
                               2 
                             
                           
                           ) 
                         
                       
                       · 
                       
                         R 
                         4 
                       
                     
                     
                       8 
                        
                       
                         η 
                         · 
                         I 
                       
                     
                   
                 
               
               
                 
                   ( 
                   
                     3 
                      
                     b 
                   
                   ) 
                 
               
             
           
         
       
     
         [0051]    If, however—as in this case—the secondary lumen represents an annular structure around a primary lumen, then the Hagen-Poiseuille formula does not exactly apply. 
         [0052]    Instead, one must consider a space with a strip-like cross-section, which can ideally be imagined in a straightened form, i.e. having a flat structure or a rectangular cross-section with length L and thickness D, i.e. with a cross-sectional area Q=L·D. 
         [0053]    Between two plates at a distance D, the following applies for the distribution of the flow rate v(x) along a direction x perpendicular to the plates: 
         [0000]    
       
         
           
             
               
                 
                   
                     v 
                      
                     
                       ( 
                       x 
                       ) 
                     
                   
                   = 
                   
                     
                       
                         ( 
                         
                           
                             p 
                             1 
                           
                           - 
                           
                             p 
                             2 
                           
                         
                         ) 
                       
                       · 
                       
                         ( 
                         
                           
                             
                               D 
                               2 
                             
                             / 
                             4 
                           
                           - 
                           
                             x 
                             2 
                           
                         
                         ) 
                       
                     
                     
                       2 
                        
                       
                         η 
                         · 
                         I 
                       
                     
                   
                 
               
               
                 
                   ( 
                   4 
                   ) 
                 
               
             
           
         
       
     
         [0054]    This is a parabolic curve. By integration over cross-sectional area Q, the mass flowing through cross-sectional area Q during time t can be determined: 
         [0000]    
       
         
           
             
               
                 
                   
                     S 
                     
                       m 
                       , 
                       1 
                     
                   
                   = 
                   
                     
                       
                         ρ 
                         1 
                       
                       · 
                       
                         ( 
                         
                           
                             p 
                             2 
                           
                           - 
                           
                             p 
                             1 
                           
                         
                         ) 
                       
                       · 
                       L 
                       · 
                       
                         D 
                         3 
                       
                     
                     
                       12 
                        
                       
                         η 
                         · 
                         I 
                       
                     
                   
                 
               
               
                 
                   ( 
                   
                     5 
                      
                     a 
                   
                   ) 
                 
               
             
             
               
                 
                   
                     S 
                     
                       m 
                       , 
                       2 
                     
                   
                   = 
                   
                     
                       
                         ρ 
                         2 
                       
                       · 
                       
                         ( 
                         
                           
                             p 
                             1 
                           
                           - 
                           
                             p 
                             2 
                           
                         
                         ) 
                       
                       · 
                       L 
                       · 
                       
                         D 
                         3 
                       
                     
                     
                       12 
                        
                       
                         η 
                         · 
                         I 
                       
                     
                   
                 
               
               
                 
                   ( 
                   
                     5 
                      
                     b 
                   
                   ) 
                 
               
             
           
         
       
     
         [0055]    In any case, these formulas replace the above Hagen-Poiseuille formulas (3a) and (3b) for annular balloon segment  5 . 
         [0056]    Here η stands for the dynamic viscosity of the flowing gas. For air: 
       η is 17.1 μPa·s at 273 K. 
       [0057]    Furthermore, because of the thermal equation of state of ideal gases, the following applies in the balloon  4 : 
         [0000]      η 1 =ρ 1   ·R   S   ·T   1   (6a)
 
         [0000]    and in balloon  8 : 
         [0000]      η 2 =ρ 2   ·R   S   ·T   2 .  (6b)
 
         [0058]    In this case, R S  is the individual or specific gas constant, which for air has the value 287.058 J/(kg*K). 
         [0059]    T v  is the temperature in balloon sections  4  and  5  and in the balloon  8 . 
         [0060]    For a temperature of 23° C. or 296 K, the factor 
         [0000]        k=R   S,air   ·T   23° C. =85·10 3   J (kg·K)  (7)
 
         [0061]    It should be assumed hereafter that the temperature both in balloon  4  and in balloon  8  is a constant 23° C.: 
         [0000]        T   1   =T   2 =296 K. 
         [0062]    Then the following applies: 
         [0000]        p   1 =ρ 1   ·k   (8)
 
         [0000]        p   2 =ρ 2   ·k   (9)
 
         [0063]    Thus by inserting equation (5a) into equation (1), the result is: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       m 
                       1 
                     
                      
                     
                       ( 
                       t 
                       ) 
                     
                   
                   = 
                   
                     
                       m 
                       
                         1 
                         , 
                         0 
                       
                     
                     + 
                     
                       
                         ∫ 
                         
                           T 
                           = 
                           0 
                         
                         
                           T 
                           = 
                           t 
                         
                       
                        
                       
                         
                           
                             
                               ρ 
                               1 
                             
                             · 
                             L 
                             · 
                             
                               D 
                               3 
                             
                           
                           
                             12 
                              
                             
                               η 
                               · 
                               I 
                             
                           
                         
                          
                         
                           ( 
                           
                             
                               p 
                               2 
                             
                             - 
                             
                               p 
                               1 
                             
                           
                           ) 
                         
                          
                         
                           d 
                           T 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   10 
                   ) 
                 
               
             
           
         
       
     
         [0064]    With equation (8), it follows that: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       m 
                       1 
                     
                      
                     
                       ( 
                       t 
                       ) 
                     
                   
                   = 
                   
                     
                       m 
                       
                         1 
                         , 
                         0 
                       
                     
                     + 
                     
                       
                         ∫ 
                         
                           T 
                           = 
                           0 
                         
                         
                           T 
                           = 
                           t 
                         
                       
                        
                       
                         
                           
                             
                               ρ 
                               1 
                             
                             · 
                             L 
                             · 
                             
                               D 
                               3 
                             
                           
                           
                             12 
                              
                             
                               η 
                               · 
                               I 
                               · 
                               k 
                             
                           
                         
                          
                         
                           
                             p 
                             1 
                           
                            
                           
                             ( 
                             
                               
                                 p 
                                 2 
                               
                               - 
                               
                                 p 
                                 1 
                               
                             
                             ) 
                           
                         
                          
                         
                           d 
                           T 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   11 
                   ) 
                 
               
             
           
         
       
     
         [0065]    Moreover, the following applies in balloon  4 : 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       m 
                       1 
                     
                     
                       V 
                       1 
                     
                   
                   = 
                   
                     
                       ρ 
                       1 
                     
                     = 
                     
                       
                         p 
                         1 
                       
                       k 
                     
                   
                 
               
               
                 
                   ( 
                   12 
                   ) 
                 
               
             
           
         
       
     
         [0066]    Therefore, the following can be written in equation (11) for mass ml: 
         [0000]    
       
         
           
             
               
                 
                   
                     m 
                     1 
                   
                   = 
                   
                     
                       
                         V 
                         1 
                       
                       · 
                       
                         p 
                         1 
                       
                     
                     k 
                   
                 
               
               
                 
                   ( 
                   13 
                   ) 
                 
               
             
           
         
       
     
         [0067]    The result: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       
                         V 
                         1 
                       
                       k 
                     
                     · 
                     
                       
                         p 
                         1 
                       
                        
                       
                         ( 
                         t 
                         ) 
                       
                     
                   
                   = 
                   
                     
                       
                         
                           V 
                           1 
                         
                         k 
                       
                       · 
                       
                         p 
                         1.0 
                       
                     
                     - 
                     
                       
                         ∫ 
                         
                           T 
                           = 
                           0 
                         
                         
                           T 
                           = 
                           t 
                         
                       
                        
                       
                         
                           
                             
                               L 
                               · 
                               
                                 D 
                                 3 
                               
                             
                             
                               12 
                                
                               
                                   
                               
                                
                               
                                 η 
                                 · 
                                 l 
                                 · 
                                 k 
                               
                             
                           
                            
                           
                               
                           
                           · 
                           
                             [ 
                             
                               
                                 p 
                                 1 
                                 2 
                               
                               - 
                               
                                 
                                   p 
                                   1 
                                 
                                  
                                 
                                   p 
                                   2 
                                 
                               
                             
                             ] 
                           
                         
                          
                         
                           d 
                           T 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   14 
                   ) 
                 
               
             
           
         
       
     
         [0068]    The entire equation can be shorted to V 1 /k. A differentiation on both sides results in: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       dp 
                       1 
                     
                     dt 
                   
                   = 
                   
                     
                       - 
                       
                         
                           L 
                           · 
                           
                             D 
                             3 
                           
                         
                         
                           12 
                            
                           
                               
                           
                            
                           
                             V 
                             1 
                           
                            
                           η 
                            
                           
                               
                           
                            
                           l 
                         
                       
                     
                     · 
                     
                       [ 
                       
                         
                           p 
                           1 
                           2 
                         
                         - 
                         
                           
                             p 
                             1 
                           
                            
                           
                             p 
                             2 
                           
                         
                       
                       ] 
                     
                   
                 
               
               
                 
                   ( 
                   15 
                   ) 
                 
               
             
           
         
       
     
         [0069]    This is a Bernoulli differential equation in the form: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       x 
                       ′ 
                     
                     = 
                     
                       
                         - 
                         a 
                       
                       · 
                       x 
                       · 
                       
                         ( 
                         
                           x 
                           - 
                           b 
                         
                         ) 
                       
                     
                   
                   , 
                 
               
               
                 
                   ( 
                   16 
                   ) 
                 
               
             
             
               
                 wherein 
               
               
                 
                     
                 
               
             
             
               
                 
                   a 
                   = 
                   
                     
                       L 
                       · 
                       
                         D 
                         3 
                       
                     
                     
                       12 
                        
                       
                           
                       
                        
                       
                         V 
                         1 
                       
                        
                       η 
                        
                       
                           
                       
                        
                       l 
                     
                   
                 
               
               
                 
                   ( 
                   17 
                   ) 
                 
               
             
             
               
                 
                   b 
                   = 
                   
                     p 
                     2 
                   
                 
               
               
                 
                   ( 
                   18 
                   ) 
                 
               
             
           
         
       
     
         [0070]    Hereafter it should be assumed that balloon  8  is significantly larger than balloon  4 : 
         [0000]        V   2   &gt;&gt;V   1 . 
         [0071]    From this it follows that the pressure p 2  in balloon  8  remains nearly constant, even when pressure p 1  in balloon  4  briefly changes. Under this assumption, the coefficients a and b from Bernoulli differential equation (16) are constant, and the solution to the Bernoulli differential equation is: 
         [0000]    
       
         
           
             
               
                 
                   
                     x 
                      
                     
                       ( 
                       t 
                       ) 
                     
                   
                   = 
                   
                     b 
                     
                       1 
                       - 
                       
                         e 
                         
                           
                             - 
                             abt 
                           
                           - 
                           
                             bc 
                             1 
                           
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   19 
                   ) 
                 
               
             
           
         
       
     
         [0072]    The constant of integration c 1  can be determined as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       p 
                       1 
                     
                      
                     
                       ( 
                       t 
                       ) 
                     
                   
                   = 
                   
                     
                       p 
                       2 
                     
                     
                       1 
                       - 
                       
                         e 
                         
                           
                             
                               - 
                               
                                 ap 
                                 2 
                               
                             
                              
                             t 
                           
                           - 
                           
                             
                               p 
                               2 
                             
                              
                             
                               c 
                               1 
                             
                           
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   20 
                   ) 
                 
               
             
           
         
       
     
         [0073]    For t=0, the following must apply: 
         [0000]        P   1 ( t )= p   1.0   (21)
 
         [0074]    The result: 
         [0000]    
       
         
           
             
               
                 
                   
                     p 
                     1.0 
                   
                   = 
                   
                     
                       p 
                       2 
                     
                     
                       1 
                       - 
                       
                         e 
                         
                           
                             - 
                             
                               p 
                               2 
                             
                           
                            
                           
                             c 
                             1 
                           
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   22 
                   ) 
                 
               
             
             
               
                 
                   
                     
                       p 
                       2 
                     
                     
                       p 
                       1.0 
                     
                   
                   = 
                   
                     1 
                     - 
                     
                       e 
                       
                         
                           - 
                           
                             p 
                             2 
                           
                         
                          
                         
                           c 
                           1 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   23 
                   ) 
                 
               
             
             
               
                 
                   
                     e 
                     
                       
                         - 
                         
                           p 
                           2 
                         
                       
                        
                       
                         c 
                         1 
                       
                     
                   
                   = 
                   
                     
                       
                         p 
                         1.0 
                       
                       - 
                       
                         p 
                         2 
                       
                     
                     
                       p 
                       1.0 
                     
                   
                 
               
               
                 
                   ( 
                   24 
                   ) 
                 
               
             
             
               
                 
                   
                     
                       - 
                       
                         p 
                         2 
                       
                     
                      
                     
                       c 
                       1 
                     
                   
                   = 
                   
                     ln 
                      
                     
                         
                     
                      
                     
                       
                         
                           p 
                           1.0 
                         
                         - 
                         
                           p 
                           2 
                         
                       
                       
                         p 
                         1.0 
                       
                     
                   
                 
               
               
                 
                   ( 
                   25 
                   ) 
                 
               
             
             
               
                 
                   
                     c 
                     1 
                   
                   = 
                   
                     
                       
                         
                           - 
                           
                             1 
                             
                               p 
                               2 
                             
                           
                         
                         · 
                         ln 
                       
                        
                       
                           
                       
                        
                       
                         
                           
                             p 
                             1.0 
                           
                           - 
                           
                             p 
                             2 
                           
                         
                         
                           p 
                           1.0 
                         
                       
                     
                     = 
                     
                       
                         
                           1 
                           
                             p 
                             2 
                           
                         
                         · 
                         ln 
                       
                        
                       
                           
                       
                        
                       
                         
                           p 
                           1.0 
                         
                         
                           
                             p 
                             1.0 
                           
                           - 
                           
                             p 
                             2 
                           
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   26 
                   ) 
                 
               
             
           
         
       
     
         [0075]    Inserted into equation (2), this provides: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       
                         p 
                         1 
                       
                        
                       
                         ( 
                         t 
                         ) 
                       
                     
                     
                       p 
                       1.0 
                     
                   
                   = 
                   
                     
                       p 
                       2 
                     
                     
                       
                         p 
                         1.0 
                       
                       - 
                       
                         
                           [ 
                           
                             
                               p 
                               1.0 
                             
                             - 
                             
                               p 
                               2 
                             
                           
                           ] 
                         
                         · 
                         
                           e 
                           
                             
                               - 
                               
                                 ( 
                                 
                                   π 
                                    
                                   
                                       
                                   
                                    
                                   
                                     R 
                                     4 
                                   
                                    
                                   
                                     p 
                                     2 
                                   
                                    
                                   t 
                                 
                                 ) 
                               
                             
                             / 
                             
                               ( 
                               
                                 8 
                                  
                                 
                                   V 
                                   1 
                                 
                                  
                                 η 
                                  
                                 
                                     
                                 
                                  
                                 l 
                               
                               ) 
                             
                           
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   27 
                   ) 
                 
               
             
           
         
       
     
         [0076]    This equation is in the form: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       
                         p 
                         1 
                       
                        
                       
                         ( 
                         t 
                         ) 
                       
                     
                     
                       p 
                       1.0 
                     
                   
                   = 
                   
                     
                       p 
                       2 
                     
                     
                       
                         p 
                         1.0 
                       
                       - 
                       
                         
                           [ 
                           
                             
                               p 
                               1.0 
                             
                             - 
                             
                               p 
                               2 
                             
                           
                           ] 
                         
                         · 
                         
                           e 
                           
                             
                               - 
                               t 
                             
                             / 
                             T 
                           
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   28 
                   ) 
                 
               
             
             
               
                 where 
               
               
                 
                     
                 
               
             
             
               
                 
                   τ 
                   = 
                   
                     
                       ( 
                       
                         12 
                         · 
                         
                           V 
                           1 
                         
                         · 
                         η 
                         · 
                         1 
                       
                       ) 
                     
                     / 
                     
                       ( 
                       
                         L 
                         · 
                         
                           D 
                           3 
                         
                         · 
                         
                           p 
                           2 
                         
                       
                       ) 
                     
                   
                 
               
               
                 
                   ( 
                   29 
                   ) 
                 
               
             
           
         
       
     
         [0077]    The following applies for minor pressure fluctuations in balloon  4 , for example: 
         [0000]        P   1.0 ≈0.9 p   2  
 
         [0078]    Moreover, for t=T: 
         [0000]        e   −t/τ   =e   −1 ≈0.368= k   1 .
 
         [0079]    Additionally, for t=2τ: 
         [0000]        e   −t/τ   =e   −2 ≈0.135= k   2 .
 
         [0080]    And for t=4τ: 
         [0000]        e   −t/τ   =e   −4 ≈0.018= k   4 .
 
         [0081]    In equation (28) this yields: 
         [0000]    
       
         
           
             
               
                 
                   p 
                   1 
                 
                  
                 
                   ( 
                   
                     t 
                     = 
                     vT 
                   
                   ) 
                 
               
               
                 0.9 
                  
                 
                   p 
                   2 
                 
               
             
             = 
             
               
                 p 
                 2 
               
               
                 
                   0.9 
                    
                   
                     p 
                     2 
                   
                 
                 - 
                 
                   
                     ( 
                     
                       
                         0.9 
                          
                         
                           p 
                           2 
                         
                       
                       - 
                       
                         p 
                         2 
                       
                     
                     ) 
                   
                   · 
                   
                     k 
                     v 
                   
                 
               
             
           
         
       
       
         
           
             and 
              
             
               : 
             
           
         
       
       
         
           
             
               
                 
                   p 
                   1 
                 
                  
                 
                   ( 
                   
                     t 
                     = 
                     vT 
                   
                   ) 
                 
               
               
                 0.9 
                  
                 
                   p 
                   2 
                 
               
             
             = 
             
               
                 p 
                 2 
               
               
                 
                   ( 
                   
                     0.9 
                     + 
                     
                       0.1 
                       · 
                       
                         k 
                         v 
                       
                     
                   
                   ) 
                 
                 · 
                 
                   p 
                   2 
                 
               
             
           
         
       
     
         [0082]    The result: 
         [0000]    
       
         
           
             
               
                 p 
                 1 
               
                
               
                 ( 
                 
                   t 
                   = 
                   T 
                 
                 ) 
               
             
             = 
             
               
                 
                   p 
                   2 
                 
                 · 
                 
                   0.9 
                   
                     0.9 
                     + 
                     
                       0.1 
                       · 
                       0.368 
                     
                   
                 
               
               ≈ 
               
                 0.96 
                 · 
                 
                   p 
                   2 
                 
               
             
           
         
       
     
         [0083]    The control deviation of approximately 0.04·p 2  remaining after t=τ corresponds to 40% of the initial deviation of 0.10·p 2 . 
         [0000]    
       
         
           
             
               
                 p 
                 1 
               
                
               
                 ( 
                 
                   t 
                   = 
                   
                     2 
                      
                     T 
                   
                 
                 ) 
               
             
             = 
             
               
                 
                   p 
                   2 
                 
                 · 
                 
                   0.9 
                   
                     0.9 
                     + 
                     
                       0.1 
                       · 
                       0.135 
                     
                   
                 
               
               ≈ 
               
                 0.98 
                 · 
                 
                   p 
                   2 
                 
               
             
           
         
       
     
         [0084]    The control deviation of approximately 0.02·p 2  remaining after t=2τ corresponds to 20% of the initial deviation of 0.10·p 2 . 
         [0000]    
       
         
           
             
               
                 p 
                 1 
               
                
               
                 ( 
                 
                   t 
                   = 
                   
                     4 
                      
                     T 
                   
                 
                 ) 
               
             
             = 
             
               
                 
                   p 
                   2 
                 
                 · 
                 
                   0.9 
                   
                     0.9 
                     + 
                     
                       0.1 
                       · 
                       0.018 
                     
                   
                 
               
               ≈ 
               
                 0.99 
                 · 
                 
                   p 
                   2 
                 
               
             
           
         
       
     
         [0085]    The control deviation of approximately 0.01·p 2  remaining after t=4τ corresponds to 10% of the initial deviation of 0.10·p 2 . 
         [0086]    When applied within the framework of thoracic respiration, it should be noted that a breathing cycle lasts about 3 sec. So that the cuff does not become leaky over the course of a thoracic breathing cycle, this compensation time should be t a =VT=20 ms, wherein, with the parameter v, it is possible to choose how good the compensation should be after 20 ms. 
         [0087]    This results in T=20 ms/v. 
         [0088]    The minimal result to be sought for v=1 and t a =20 is provided as follows: 
         [0089]    From this comes: 
         [0000]    
       
         
           
             T 
             = 
             
               
                 
                   20 
                   · 
                   
                     10 
                     
                       - 
                       3 
                     
                   
                 
                  
                 s 
               
               = 
               
                 
                   
                     12 
                     · 
                     5 
                     · 
                     
                       10 
                       
                         - 
                         6 
                       
                     
                   
                    
                   
                     
                       m 
                       3 
                     
                     · 
                     0.2 
                   
                    
                   
                       
                   
                    
                   
                     m 
                     · 
                     17.1 
                     · 
                     
                       10 
                       
                         - 
                         6 
                       
                     
                   
                    
                   Pas 
                 
                 
                   
                     L 
                     · 
                     
                       D 
                       3 
                     
                     · 
                     
                       10 
                       5 
                     
                   
                    
                   Pa 
                 
               
             
           
         
       
     
         [0090]    In the process, it was assumed:
       V 1 =5 cm 3      I=20 cm   p 2 =10 5  Pa       
 
         [0094]    This results in: 
         [0000]        L·D   3 =10.26·10 −14   m   4 .
 
         [0095]    It should hereafter further be assumed that, at most, an interior opening with a maximum diameter of 10 mm, corresponding to a radius of 5 mm, is available in the tracheal tube. If one further disregards the cross-section of the outer surface of tube  3  and balloon  4 , then the secondary lumen extends a maximum distance outward, and a medium radius R m  of e.g. 4.8 mm can thus be assumed. From this, it is possible to calculate a circumferential length L m =2·TT·R m  of approximately 30 mm=30·10 −3  m, and from this results: 
         [0000]        D   3 =10.26*10 −14   m   4   /L    
         [0000]      and: 
         [0000]        D   3 =102.6·10 −12   m   3 /30
 
         [0000]        D   3 =3.42·10 −12   m   3  
 
         [0000]        D= 1.5·10 −4   m= 0.15 mm.
 
         [0096]    The secondary lumen thus has a cross-sectional area Q 2  of 
         [0000]        Q   2   =L·D= 30·mm·0.15 mm=4.5 mm 2 .
 
         [0097]    For cross-sectional area Q 1  of the primary lumen, D can be subtracted from the 5 mm maximum radius of the tracheal tube, and the result is 4.8 mm. This corresponds to a cross-sectional area Q 1  of 
         [0000]        Q   1 =4.85 mm·4.85 mm·3.14=74 mm 2 .
 
         [0098]    The overall free cross-section Q=Q 1 +Q 2 =78.5 mm 2 . This means: 
         [0000]        Q   2   /Q=Q   2 /( Q   1   +Q   2 )=4.5/78.5=0.06. 
         [0099]    If a shorter compensation time or better compensation within this compensation time t a  is required, then more stringent requirements arise for the above ratio. Accordingly, the value of 0.06 represents the absolute lower limit, which should never be undercut because this would threaten aspiration. In order to have a safety reserve, at least the following should be selected: 
         [0000]        Q   2   /Q=Q   2 /( Q   1   +Q   2 )≧0.08.
 
         [0100]    Moreover, the extracorporeal supply line  7  was likewise disregarded in the above calculation, although its contribution to flow resistance is not insignificant. It is therefore recommended: 
         [0000]        Q   2   /Q=Q   2 /( Q   1   +Q   2 )≧0.10.
 
         [0101]    If, on the other hand, one sets v=4 and t a =10 ms (i.e. the requirement that the remaining control deviation should be less than 10% after 10 ms), then the following is obtained: 
         [0000]    
       
         
           
             T 
             = 
             
               
                 10 
                  
                 
                     
                 
                  
                 
                   ms 
                   / 
                   4 
                 
               
               = 
               
                 
                   
                     25 
                     · 
                     
                       10 
                       
                         - 
                         4 
                       
                     
                   
                    
                   s 
                 
                 = 
                 
                   
                     
                       12 
                       · 
                       5 
                       · 
                       
                         10 
                         
                           - 
                           6 
                         
                       
                     
                      
                     
                       
                         m 
                         3 
                       
                       · 
                       0.2 
                     
                      
                     
                         
                     
                      
                     
                       m 
                       · 
                       17.1 
                       · 
                       
                         10 
                         
                           - 
                           6 
                         
                       
                     
                      
                     Pas 
                   
                   
                     
                       L 
                       · 
                       
                         D 
                         3 
                       
                       · 
                       
                         10 
                         5 
                       
                     
                      
                     Pa 
                   
                 
               
             
           
         
       
     
         [0102]    This then results in: 
         [0000]        L·D   3 =82.08·10 −14   m   4 ,
 
         [0000]        D   3 =82.08·10 −14   m   4   /L  
 
         [0000]    or, when L=30 mm: 
         [0000]        D   3 =27.4·10 −12   m   3  
 
         [0000]        D= 3·10 −4   m= 0.3 mm.
 
         [0103]    The secondary lumen thus has a cross-sectional area Q 2  of 
         [0000]        Q   2   =L·D= 30·mm·0.3 mm=9 mm 2 .
 
         [0104]    For the cross-sectional area Q 1  of the primary lumen, D can be subtracted from the 5 mm maximum radius of the tracheal tube, and the result is then 4.6 mm. This corresponds to a cross-sectional area Q 1  of 
         [0000]        Q   1 =4.6 mm·4.6 mm·3.14=66 mm 2 .
 
         [0105]    The overall free cross-section Q=Q 1 +Q 2 =75 mm 2 . This means: 
         [0000]        Q   2   /Q=Q   2 /( Q   1   +Q   2 )=9/75=0.12. 
         [0106]      FIG. 3  describes an embodiment of the shaft body  3  that is integrated into the shaft wall, has one or more volume-supplying channels with a volume-shifting overall cross-section that corresponds in its flow mechanics with the ratios represented in  FIG. 2 . Here the shaft body preferably consists of multi-lumen extruded tube material which, in addition to a central lumen for ventilation, contains supply lumens disposed around said central lumen. In one such multi-lumen embodiment, the individual lumens can be bundled or combined at the proximal shaft end by an annular structure  10 . 
         [0107]      FIG. 3 a    shows an illustrative shaft cross-section with multi-lumen volume supply lines  11 . 
         [0108]      FIG. 4  shows an embodiment variant in which the trachea-sealing balloon segment  4  is extended proximally up to or beyond the plane of the vocal folds GL. This embodiment, in which the balloon segment that is elongated in this way protrudes proportionally from the thorax and is thus not exposed to fluctuations in thoracic pressure, permits an especially large balloon volume that is capable of developing a pressure-receiving buffer effect when a reduction in transmural force on the balloon, caused by breathing mechanics, occurs in the distal, tracheal segment of the balloon. The volume reserve created in this way also has a partial buffering effect when no external volume-compensating unit is connected to the tracheal tube. 
         [0109]    In addition, owing to the large contact surface with the exposed tracheal, glottic and supraglottic mucous membranes, a maximally elongated migration path for secretions and pathogens contained therein is created. 
         [0110]    To facilitate the trans-glottic positioning of the tube, the balloon can be provided with a circular constriction  12  in the region of the vocal cords GL. This constriction additionally allows for the free movement of the vocal folds, largely independent of the prevailing filling pressure in the balloon. 
         [0111]    The distal shaft segment is preferably configured as a thin-walled, single-lumen tube that is stabilized by a corrugation in the shaft wall. The distal shaft transitions in the proximal direction into a shaft segment  6  that, as described in  FIG. 1 , allows for a large-bore supply line to the proximal balloon segment  5 . In a preferred embodiment, as described in  FIG. 3 a   , the shaft  6  is designed with a multi-lumen profile. The multi-lumen shaft segment  6  is configured to be stable enough to serve as a bite guard, which prevents a lumen-sealing closure of the ventilation lumen. 
         [0112]    The supplying lumens that are integrated into the shaft  6  can be bundled by a terminal element  10  at the proximal end of the tube. In turn, the connection element  7  is attached to a reservoir with a sufficiently large-bore connection. 
         [0113]    The thin-walled, single-lumen shaft body  3  is equipped with a wavy corrugation to stabilize the shaft lumen and to permit the largely tension-free axial bending of the shaft. In the preferred embodiment, it should be possible in this way to bend the shaft from 90 to 135 degrees without relevant lumen constriction and without elastic restoring forces acting upon the tissue. 
         [0114]    For inner shaft diameters of 7 to 10 mm in the combination of a wall thickness of ca. 0.4 mm, a Shore hardness value of 95A, a peak-to-peak wave distance of 0.5 mm and a wave amplitude of 0.75 mm, it is possible to produce a correspondingly kink-resistant lumen- and flow-optimized shaft. 
         [0115]    In the case of the corrugated embodiment of the shaft  3 , when an exchangeable inner cannula is used, such as those that are conventional in tracheostomy cannulas, it is possible to use an inner cannula with a congruently corrugated profile with a corrugation that optimally conforms to the corrugation of the outer cannula and advantageously stabilizes the outer cannula. 
         [0116]      FIG. 5  shows an illustrative application of the flow-optimized embodiment of the supplying lumen to the trachea-sealing balloon element  4  in a tracheostomy cannula  13 . Similar to the embodiment of tracheal tubes, the volume-supplying balloon end  5  here is led to the surgically created stoma to the trachea and applied to a connector  10  below the cannula flange. The cross-sectional area G of the supplying end  5  can be selected such that, beyond the claimed requirements of a fast volume flow, it is suitable to seal the stoma and thus prevent the escape of secretions. The proximal balloon end  19  can also advantageously be configured as a bulge-like widening, which lies sealingly against the stoma directly below the cannula flange. 
         [0117]      FIG. 6  shows a tracheal tube  20 , which is provided in the region of the trachea-sealing balloon segment  4  with a pressure-sensitive or pressure-measuring sensor element  21 . In a preferred embodiment, the pressure sensor is an electronic component that relays its measurement signal to an electronically controlled regulator RE via a cable line  22 . The sensor element preferably consists of an absolute pressure sensor. For example, sensors based on strain gauges or piezoelectric sensors can be used. The regulator RE has a bellows-like or piston-like reservoir  23 , for example, which is actuated by a drive  24  and either shifts volume to the balloon  4  or removes volume from the balloon  4 ; the drive can consist of a step motor or can be configured as a linear magnetic drive. The control of the regulator RE is designed such that immediate compensation can be made for deviations in filling pressure in the region of the sealing balloon segment  4  by a corresponding volume shift, or the filling pressure can be kept constant at a setpoint value SW, which can be adjusted with the regulator. In this method, the sealing balloon pressure is stabilized at a point before a mechanical breath commences and before an actual volume flow of breathing gas into the patient&#39;s lungs. This is relevant especially in patients who, for example, must expend increased breathing effort after a long period of controlled machine-assisted ventilation in order to stretch an insufficiently elastic lung in the thorax to a point that triggers a volume flow of breathing air into the lung. 
         [0118]    In this phase of the “isometric” tension of the lung within the thorax and thus of the accompanying decrease in pressure within the thorax, drops in the filling pressure of the balloon can occur which are critical to the seal. In clinically apneic patients, i.e. patients who can perform (isometric) breathing but do not produce a perceptible breathing gas stream, the described sensor technology also makes it possible to ensure intubation in a manner that prevents aspiration. 
         [0119]    If sudden pressure fluctuations occur in the balloon, such as when the patient changes positions or suffers a coughing attack, the control loop described can likewise efficiently and quickly shift volume to the sealing balloon or remove volume from it. 
         [0120]    In contrast to a regulating reservoir  2 , like the one described in  FIG. 1  which provides a compensating reserve volume at an isobaric pressure of preferably 20 to 35 mbar, in the electronic regulation within the pressure-generating element  22  of the regulator RE it is possible to build up pressure that briefly exceeds the tracheally uncritical sealing pressure of 20 to 35 mbar and thereby accelerate the volume flow toward the sealing balloon by means of a corresponding transient pressure gradient. The continuous measurement function of the sensor thereby ensures that the pressure in the balloon does not reach critical levels. 
         [0121]      FIG. 7 . In order to avoid larger deflations of the tracheal balloon segment or balloon into the reservoir, which would be critical for the seal, such as those that can occur when the patient coughs or clenches, the connecting supply line Z between the balloon and the regulator can be provided with a large-bore, flow-directing valve  25 , which prevents the backflow of filling medium from the balloon BL to the reservoir R. A throttle element  26  that is not flow-directing is arranged in parallel thereto to permit the slow exchange of volume between the balloon and reservoir. 
         [0122]      FIG. 8  shows a similar application of the described dynamic tamponade, which allows a patient&#39;s esophagus to be sealingly closed by means of a fillable balloon element. The sealing balloon segment  4  transitions to a proximally elongated constriction  5  that defines a free gap S in the direction of the shaft element  3  for the flow-efficient shifting of a filling medium. The proximal elongation  5  of the balloon body optionally extends to or beyond the height of the mouth or nose placement. The elongation  5  transitions into a tube line  7  that is configured for an efficient flow and that, in turn, is coupled to a claimed reservoir or is connected to a different claimed regulating mechanism. 
         [0123]    With the devices described in the preceding figures for the flow-optimized shift of volume between a trachea- or esophagus-sealing balloon  4  and an extracorporeal regulating reservoir  2 , seal-creating volume compensations can take place within a tracheal or esophageal balloon body within 10 to 30 milliseconds, preferably within 10 to 15 milliseconds, after the beginning of a change in intra-thoracic pressure. 
       LIST OF REFERENCE SIGNS 
       [0000]    
       
           1  Device 
           2  Reservoir 
           3  Tube 
           4  Balloon 
           5  Proximal tapered balloon end 
           6  Proximal shaft element 
           7  Extracorporeal supply line 
           8  Reservoir volume 
           9   a  Distal tube end 
           9   b  Proximal tube end 
           10  Annular structure 
           11  Volume supply line 
           12  Constriction 
           13  Tracheostomy cannula 
           19  Proximal balloon end 
           20  Tracheal tube 
           21  Sensor element 
           22  Cable line 
           23  Reservoir 
           24  Drive 
           25  Flow-straightening valve 
           26  Throttle element 
         K Force 
         G Cross-sectional area 
         S Gap 
         ID Inner cross-section of the tube 
         OD Outer cross-section of the tube 
         GL Vocal fold plane 
         RE Regulator 
         SW Setpoint value 
         BL Balloon 
         R Reservoir