#include <bits/stdc++.h>   using namespace std;   map<long long, int> last;   int b[1000000];   long long a[100000];   long long d[100][2];   pair<long long, long long> solve(long long x, long long y) {     long long xx, yy;     pair<long long, long long> ans;     if (x == 1) {       return make_pair(1, 0);     }     xx = x;     yy = y % x;     if (yy == 1) {       ans = make_pair(1, xx - 1);     } else {       ans = solve(xx % yy, yy);       ans.second += (xx / yy) * ans.first;       ans.first %= yy;       ans.second %= xx;     }     ans.first += (y / x) * ans.second;     ans.first %= y;     ans.second %= x;     return ans;   }   long long inv(long long x, long long y) {     x %= y;     pair<long long, long long> p = solve(x, y);     return p.first;   }   long long gcd(long long x, long long y) {     if (y == 0)       return x;     else       return gcd(y, x % y);   }   int main() {     vector<long long> primes;     long long i, j, k, l;     long long m, n, now, tmp, tmp1, cnt, b1, nn, ans, all;     memset(b, 0, sizeof(b));     primes.clear();     for (i = 2; i < 1000000; i++) {       if (b[i] == 0) {         primes.push_back(i);         for (j = i + i; j < 1000000; j += i) b[j] = 1;       }     }     scanf( %I64d%I64d%I64d , &n, &m, &k);     for (i = 0; i < k; i++) scanf( %I64d , &a[i]);     last.clear();     now = 1;     for (i = 0; i < k; i++) {       tmp = gcd(now, a[i]);       now /= tmp;       if ((1LL << 60) / now < a[i]) {         printf( NO n );         return 0;       }       now *= a[i];       if (now > n) {         printf( NO n );         return 0;       }       tmp = a[i];       for (j = 0; j < primes.size() && primes[j] * primes[j] <= tmp; j++) {         cnt = 0;         while (tmp % primes[j] == 0) {           tmp /= primes[j];           cnt++;         }         tmp1 = 1;         for (l = 0; l < cnt; l++) {           tmp1 *= primes[j];           if (i - tmp1 >= 0) {             if ((last.find(tmp1) == last.end()) || (last[tmp1] != i - tmp1)) {               printf( NO n );               return 0;             }             last[tmp1] = i;           } else {             if (last.find(tmp1) != last.end()) {               printf( NO n );               return 0;             }             last[tmp1] = i;           }         }       }       if (tmp > 1) {         tmp1 = tmp;         if (i - tmp1 >= 0) {           if ((last.find(tmp1) == last.end()) || (last[tmp1] != i - tmp1)) {             printf( NO n );             return 0;           }           last[tmp1] = i;         } else {           if (last.find(tmp1) != last.end()) {             printf( NO n );             return 0;           }           last[tmp1] = i;         }       }     }     for (map<long long, int>::iterator it = last.begin(); it != last.end();          it++) {       if (it->second + it->first < k) {         printf( NO n );         return 0;       }     }     nn = 0;     for (map<long long, int>::reverse_iterator it = last.rbegin();          it != last.rend(); it++) {       b1 = 1;       for (i = 0; i < nn; i++)         if (d[i][0] % it->first == 0) {           b1 = 0;           break;         }       if (b1 == 0) continue;       d[nn][0] = it->first;       d[nn][1] = k - 1 - it->second;       nn++;     }     ans = 0;     all = 1;     for (i = 0; i < nn; i++) all *= d[i][0];     for (i = 0; i < nn; i++) {       tmp = 1;       for (j = 0; j < nn; j++)         if (j != i) tmp *= d[j][0];       tmp *= inv(tmp, d[i][0]);       tmp *= d[i][1];       tmp %= all;       ans += tmp;     }     ans %= all;     if (ans - (k - 1) <= 0) ans += all;     if (ans <= m) {       printf( YES n );     } else       printf( NO n );   }