質問: How do you solve #2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5)#? ========================================================
回答: #2 4/13# #### Explanation: #2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5)# #:.cancel(-6k^2)+8kcancel(+6k^2)+60=cancel(4k^2)-8kcancel(-4k^2)-10k# #:.8k+60=-18k# #:.8k+18k=-60# #:.26k=-60# #:.k=cancel60^color(red)30/cancel26^color(red)13# #:.k=30/13# #:.k=2 4/13#