質問: How do you rewrite #(m^-2n^3p^-4)^-2# using a positive exponent? ================================================================
回答: #(m^4p^8)/n^6# #### Explanation: #(A^aB^bC^c)^d=(A^a)^d xx(B^b)^d xx(C^c)^d# #(A^a)^d=A^(a*d)# #(m^-2n^3p^-4)^-2=m^(-2*-2)n^(3*-2)p^(-4*-2)=m^4n^-6p^8# #A^-a=1/A^a# #m^4n^-6p^8=(m^4p^8)/n^6#