質問: How do you simplify #(a^ -6) * (b^ 2) / (a^ -3) * (b^8)#? =========================================================
回答: #a^(-3).b^10# #### Explanation: #1/a^-3 = a^((-3).(-1)) = a^3# So ; #a^(-6)*(b^2)/a^(-3)*b^8 =a^(-6)*b^2.a^3*b^8# = #a^((-6+3)).b^((2+8))# = #a^(-3).b^10#