質問: As shown in the below code, the second and third table are side by side. How can I make these two tables align on the top? The rows in the second table can be more than those in the third table. ![enter image description here](https://i.stack.imgur.com/2GEqD.png) ``` \documentclass[a4paper]{article} \usepackage{fancyhdr} \usepackage[lmargin=0.80cm,rmargin=0.80cm,tmargin=2.50cm,bmargin=0.80cm]{geometry} \usepackage{upgreek} \usepackage[sfdefault]{carlito} \parindent=0pt \pagestyle{fancy} \fancyhf{} \headsep=2.0mm \newcommand{\defaultfontsize}{\fontsize{10pt}{\baselineskip}\selectfont} \begin{document}\defaultfontsize \begin{tabular}{@{}|l|l|l|l|l|p{2.7cm}|} \hline \multicolumn{6}{|c|}{\rule{0pt}{2.3ex}\textbf{Characteristic dead load and live load - Point load}}\\ \hline \rule{0pt}{2.3ex} & \multicolumn{1}{c|}{\textbf{DL}} & \multicolumn{1}{c|}{\textbf{LL}} & \multicolumn{2}{c|}{\textbf{Load geometry}} & \textbf{Comment}\\ \cline{2-5} \rule{0pt}{2.3ex} & \multicolumn{1}{c|}{\textbf{(kN)}} & \multicolumn{1}{c|}{\textbf{(kN)}} & \multicolumn{1}{c|}{\textbf{A(m)}} & \multicolumn{1}{c|}{\textbf{B(m)}} & \\ \hline 1 & 1.000 & 2.100 & 2.500 & 2.900 & From B1\\ \hline 2 & 1.100 & 2.200 & 1.500 & 3.900 & \\ \hline 3 & 1.200 & 2.300 & 3.500 & 1.900 & \\ \hline 4 & 1.300 & 2.400 & 4.500 & 0.900 & \\ \hline 5 & 1.400 & 2.500 & 0.300 & 5.100 & \\ \hline \end{tabular} \quad \vspace{0.5cm} \begin{tabular}{@{}|l|p{4.5cm}|l|l|l|l|} \hline \rule{0pt}{2.3ex} & \multicolumn{1}{l|}{\textbf{Load combination - ULS}} & \multicolumn{1}{c|}{\boldmath $\mathsf{M_{max}}$} & \multicolumn{1}{c|}{\boldmath $\mathsf{R_{1}}$} & \multicolumn{1}{c|}{\boldmath $\mathsf{R_{2}}$} & \multicolumn{1}{c|}{\boldmath $\mathsf{V_{max}}$}\\ \cline{3-6} \rule{0pt}{2.3ex} & $\mathsf{_{_U}=UDL,\,_{_C}=Concentrated}$ & \multicolumn{1}{c|}{\textbf{(kNm)}} & \multicolumn{1}{c|}{\textbf{kN}} & \multicolumn{1}{c|}{\textbf{kN}} & \multicolumn{1}{c|}{\textbf{kN}}\\ \hline 1 & $\mathsf{1.35DL}$ & 71.16 & 36.89 & 35.90 & 36.89\\ \hline 2 & $\mathsf{1.2DL + 1.5LL_{_U}}$ & \textbf{160.98} & 82.12 & 84.64 & \textbf{84.64}\\ \hline 3 & $\mathsf{1.2DL + 1.5LL_{_C}}$ & 65.48 & 33.62 & 32.73 & 33.62\\ \hline 4 & $\mathsf{1.2DL + 1.5\ \psi_{\mathit{l_U}}\ LL_{_U}}$ & 63.26 & 32.79 & 31.91 & 32.79\\ \hline 5 & $\mathsf{1.2DL + 1.5\ \psi_{\mathit{l_C}}\ LL_{_C}}$ & 63.26 & 32.79 & 31.91 & 32.79\\ \hline 6 & $\mathsf{0.9DL + W_{u_up}}$ & 11.07 & 3.54 & 7.29 & 7.29\\ \hline \end{tabular} \quad \begin{tabular}{@{}|l|p{4.5cm}|l|} \hline \rule{0pt}{2.3ex} & \multicolumn{1}{l|}{\textbf{Load combination - SLS}} & \multicolumn{1}{c|}{\boldmath $\mathsf{\updelta_{max}}$}\\ \rule{0pt}{2.3ex} & $\mathsf{_{_U}=UDL,\,_{_C}=Concentrated}$ & \multicolumn{1}{c|}{\textbf{(mm)}}\\ \hline 1 & $\mathsf{DL}$ & 5.18\\ \hline 2 & $\mathsf{LL_{_U}}$ & 6.45\\ \hline 3 & $\mathsf{LL_{_C}}$ & 0.12\\ \hline 4 & $\mathsf{DL + \psi_{\mathit{s_U}}\ LL_{_U}}$ & 9.70\\ \hline 5 & $\mathsf{DL + \psi_{\mathit{s_C}}\ LL_{_C}}$ & 5.30\\ \hline 6 & $\mathsf{DL + \psi_{\mathit{l_U}}\ LL_{_U}}$ & 5.18\\ \hline 7 & $\mathsf{DL + W_{s_up}}$ & 3.35\\ \hline \end{tabular} \end{document} ```
回答: !enter image description here Edit the code of the second and third table as follows ``` \begin{tabular}[t]{@{}|l|p{4.5cm}|l|l|l|l|} ...... \end{tabular} \quad \begin{tabular}[t]{@{}|l|p{4.5cm}|l|} ...... \end{tabular} ``` Rest of the code remains same