質問: How do you solve the system of equations algebraically #3/5x-1/6y=1, 1/5x+5/6y=11#? ===================================================================================
回答: #y=12,x=5# #### Explanation: #3/5 x-1/6 y=1#------(1) #1/5 x+5/6 y=11#------(2) #:.(1) xx 5# #:.(5)3/5x-(5)1/6y=5# #:.15/5x-5/6y=5# #:.3x-5/6 y=5#------(3) #:.(2)+(3)# #:.3 1/5x=16# #:.16/5 x=16# #:.x=16/(16/5)# #:.x=cancel(16)^1/1 xx 5/cancel(16)^1# #:.color(magenta)(x=5# substitute #color(magenta)(x=5# in(1) #:.3/5(color(magenta)5)-1/6 y=1# #:.15/5-1/6y=1# #:.3-1/6 y=1# #:.-1/6 y=1-3# #:.-1/6 y=-2# #:.y=2/(1/6)# #:.y=2 xx 6# #:.color(magenta)(y=12# substitute #color(magenta)(y=12,x=5# in (2) #:.1/5(color(magenta)5)+5/6(color(magenta)12)=11# #:.5/5+60/6=11# #:.1+10=11# #:.color(magenta)(11=11#