質問: How many grams of carbon tetrafluoride, #CF_4#, are produced from the complete reaction of 1.46 moles of carbon in the reaction #C+2F_2 -> CF_4#? ====================================================================================================================================================
回答: 128g #### Explanation: #n("CF"_4)=n("C") = 1.46mol# #M("CF"_4)=(1xx12+4xx19)gmol^-1 = 88gmol^-1# #m("CF"_4)=nM = 1.46molxx88gmol^-1 = 128g# (3s.f)