質問: lim x--- pi sqrt(1-cosx)-sqrt(2)/sin^2 x sin - math - limits lim x---> pi sqrt(1-cosx)-sqrt(2)/sin^2 x
回答: dear student , here is detailed solution to your querylimx→π 1-cosx - 2sin2x→applying l'hospitals rule , → limx→π d (1-cosx - 2)dxd(sin2x)dx→ limx→π 121-cosx (sinx)2sinxcosx→ limx→π 14cosx1-cosxsubstituting x=π :⇒ 14cosπ1-cosπ = 14 (-1)1-(-1)⇒-142regards