質問: How do you simplify #(5sqrt54)/(15sqrt2)#? ==========================================
回答: #sqrt3# #### Explanation: #sqrt54/(3sqrt2)# #(sqrt(2*3*9)*sqrt2)/6# #(3sqrt(6)*sqrt2)/6# #(sqrt(6)*sqrt2)/2# #(sqrt(2*3)*sqrt2)/2# #(2sqrt3)/2# #sqrt3#