質問: How do you simplify #((-3)^0 x^4 y^-1) /( x^-1 yz ^-2)#? ========================================================
回答: #((-3)^0 x^4 y^-1) /( x^-1 yz ^-2)=(x^5z^2)/y^2# #### Explanation: Some rules which apply to indices: #a^0-=1,# #"given"# # a!=0# #a^m/a^n-=a^(m-n),# #"given"# # m-n>0# #"where"# #a=0# #a^(-n)-=1/(a^n),# #"given"# #a!=0# #-3^0=1# #x^4/x^-1=x^(4--1)=x^5# #y^-1/y=y^(-1-1)=y^-2# #(1(z^0))/z^-2=z^(0--2)=z^2# #((-3)^0 x^4 y^-1) /( x^-1 yz ^-2)=x^5y^-2z^2=x^5 1/y^2 z^2=(x^5z^2)/y^2#