質問: if `a=[{:(costheta,sintheta),(sintheta,-costheta):}]`, `b=[{:(1,0),(-1,1):}]` , `c=aba^(t)`, then `a^(t)c^(n)a` equals to `(n in i^(+))` if `a=[{:(costheta,sintheta),(sintheta,-costheta):}]`, `b=[{:(1,0),(-1,1):}]` , `c=aba^(t)`, then `a^(t)c^(n)a` equals to `(n in i^(+))`
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