質問: (2010: 67-3х): 3+2х=2009 📍 pomogite pojaluista (2010: 67-3х): 3+2х=2009 pomogite pojaluista
回答: (2010: 67 -3x): 3+2x=2009 -(3x-30)/3 +2x-2009=0 (2x-2009)*3/3 - (3x-30)/3=0 (2x-2009)*3-(3x-30)=0 (...