题目<br>提示:由已知a=-(b+c)可得2a^2+bc=a^2-a(b+c)+bc=(a-b)(a-c)<br><img><br>答案解析<br>举报<br>因为a+b+c=0,则b=-a-c,bc=-ac-c2 所以2a2+bc=2a2-ac-c2=(2a+c)(a-c)=(a-b)(a-c) 故:[a2/(2a2+bc)]+[b2/(2b2+ac)]+[C2/(2c2+ab)] =[a2/(a-b)(a-c)]+[b2/(b-c)(b-a)]+[C2/(c-a)(c-b)] =(a-b)*[a2/(a-c)-b2/(b-c)]+[C2/...<br>解析看不懂?求助智能家教解答<br>查看解答<br>更多答案(1)<br>相似问题<br>已知a^2/(b+c-a)+b^2/(a+c-b)+c^2/(a+b-c)=0 a/(b+c-a)+b/(a+c-b)+c/(a+b-c)=?