优质解答lim(1/x-1/tanx)=lim (1/x-cosx/sinx)简单的说当x->0时,cosx->1,sinx->x所以,应该猜到极限是0.lim(1/x-1/tanx)=lim (1/x-cosx/sinx)=lim (sinx-xcosx)/(xsinx)上下求导=lim (cosx -cosx+xsinx)/(sinx+xcosx) =lim (x...