Prompt:
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.

    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index.

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:

    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.

    """

      return True
    sorted_array=sorted(arr)
    my_arr=[]

    min_value=min(arr)
    min_index=arr.index(min_value)
    my_arr=arr[min_index:]+arr[0:min_index]
    for i in range(len(arr)):
      if my_arr[i]!=sorted_array[i]:
        return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([3, 5, 10, 1, 2])==True
    assert candidate([4, 3, 1, 2])==False
    # Check some edge cases that are easy to work out by hand.
    assert candidate([3, 5, 4, 1, 2])==False, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([])==True


Prompt:
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.

    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index.

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:

    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.

    """
    if len(arr)==0:

    sorted_array=sorted(arr)
    my_arr=[]

    min_value=min(arr)
    min_index=arr.index(min_value)
    my_arr=arr[min_index:]+arr[0:min_index]
    for i in range(len(arr)):
      if my_arr[i]!=sorted_array[i]:
        return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([3, 5, 10, 1, 2])==True
    assert candidate([4, 3, 1, 2])==False
    # Check some edge cases that are easy to work out by hand.
    assert candidate([3, 5, 4, 1, 2])==False, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([])==True


Prompt:
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.

    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index.

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:

    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.

    """
    if len(arr)==0:
      return True

    my_arr=[]

    min_value=min(arr)
    min_index=arr.index(min_value)
    my_arr=arr[min_index:]+arr[0:min_index]
    for i in range(len(arr)):
      if my_arr[i]!=sorted_array[i]:
        return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([3, 5, 10, 1, 2])==True
    assert candidate([4, 3, 1, 2])==False
    # Check some edge cases that are easy to work out by hand.
    assert candidate([3, 5, 4, 1, 2])==False, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([])==True


Prompt:
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.

    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index.

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:

    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.

    """
    if len(arr)==0:
      return True
    sorted_array=sorted(arr)

    min_value=min(arr)
    min_index=arr.index(min_value)
    my_arr=arr[min_index:]+arr[0:min_index]
    for i in range(len(arr)):
      if my_arr[i]!=sorted_array[i]:
        return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([3, 5, 10, 1, 2])==True
    assert candidate([4, 3, 1, 2])==False
    # Check some edge cases that are easy to work out by hand.
    assert candidate([3, 5, 4, 1, 2])==False, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([])==True


Prompt:
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.

    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index.

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:

    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.

    """
    if len(arr)==0:
      return True
    sorted_array=sorted(arr)
    my_arr=[]

    min_index=arr.index(min_value)
    my_arr=arr[min_index:]+arr[0:min_index]
    for i in range(len(arr)):
      if my_arr[i]!=sorted_array[i]:
        return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([3, 5, 10, 1, 2])==True
    assert candidate([4, 3, 1, 2])==False
    # Check some edge cases that are easy to work out by hand.
    assert candidate([3, 5, 4, 1, 2])==False, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([])==True


Prompt:
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.

    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index.

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:

    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.

    """
    if len(arr)==0:
      return True
    sorted_array=sorted(arr)
    my_arr=[]

    min_value=min(arr)

    my_arr=arr[min_index:]+arr[0:min_index]
    for i in range(len(arr)):
      if my_arr[i]!=sorted_array[i]:
        return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([3, 5, 10, 1, 2])==True
    assert candidate([4, 3, 1, 2])==False
    # Check some edge cases that are easy to work out by hand.
    assert candidate([3, 5, 4, 1, 2])==False, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([])==True


Prompt:
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.

    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index.

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:

    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.

    """
    if len(arr)==0:
      return True
    sorted_array=sorted(arr)
    my_arr=[]

    min_value=min(arr)
    min_index=arr.index(min_value)

    for i in range(len(arr)):
      if my_arr[i]!=sorted_array[i]:
        return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([3, 5, 10, 1, 2])==True
    assert candidate([4, 3, 1, 2])==False
    # Check some edge cases that are easy to work out by hand.
    assert candidate([3, 5, 4, 1, 2])==False, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([])==True


Prompt:
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.

    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index.

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:

    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.

    """
    if len(arr)==0:
      return True
    sorted_array=sorted(arr)
    my_arr=[]

    min_value=min(arr)
    min_index=arr.index(min_value)
    my_arr=arr[min_index:]+arr[0:min_index]

      if my_arr[i]!=sorted_array[i]:
        return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([3, 5, 10, 1, 2])==True
    assert candidate([4, 3, 1, 2])==False
    # Check some edge cases that are easy to work out by hand.
    assert candidate([3, 5, 4, 1, 2])==False, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([])==True


Prompt:
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.

    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index.

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:

    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.

    """
    if len(arr)==0:
      return True
    sorted_array=sorted(arr)
    my_arr=[]

    min_value=min(arr)
    min_index=arr.index(min_value)
    my_arr=arr[min_index:]+arr[0:min_index]
    for i in range(len(arr)):

def check(candidate):

    # Check some simple cases
    assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([3, 5, 10, 1, 2])==True
    assert candidate([4, 3, 1, 2])==False
    # Check some edge cases that are easy to work out by hand.
    assert candidate([3, 5, 4, 1, 2])==False, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([])==True


Prompt:
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.

    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index.

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:

    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.

    """
    if len(arr)==0:
      return True
    sorted_array=sorted(arr)
    my_arr=[]

    min_value=min(arr)
    min_index=arr.index(min_value)
    my_arr=arr[min_index:]+arr[0:min_index]
    for i in range(len(arr)):
      if my_arr[i]!=sorted_array[i]:

def check(candidate):

    # Check some simple cases
    assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([3, 5, 10, 1, 2])==True
    assert candidate([4, 3, 1, 2])==False
    # Check some edge cases that are easy to work out by hand.
    assert candidate([3, 5, 4, 1, 2])==False, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([])==True


Prompt:
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.

    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index.

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:

    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.

    """
    if len(arr)==0:
      return True
    sorted_array=sorted(arr)
    my_arr=[]

    min_value=min(arr)
    min_index=arr.index(min_value)
    my_arr=arr[min_index:]+arr[0:min_index]
    for i in range(len(arr)):
      if my_arr[i]!=sorted_array[i]:
        return False

def check(candidate):

    # Check some simple cases
    assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([3, 5, 10, 1, 2])==True
    assert candidate([4, 3, 1, 2])==False
    # Check some edge cases that are easy to work out by hand.
    assert candidate([3, 5, 4, 1, 2])==False, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([])==True


Prompt:
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """

    even = 0
    for i in lst1:
        if i%2 == 1:
            odd += 1
    for i in lst2:
        if i%2 == 0:
            even += 1
    if even >= odd:
        return "YES"
    return "NO"

def check(candidate):

    # Check some simple cases
    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 3]) == "NO"
    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == "NO"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([100, 200], [200, 200]) == "YES"


Prompt:
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
    odd = 0

    for i in lst1:
        if i%2 == 1:
            odd += 1
    for i in lst2:
        if i%2 == 0:
            even += 1
    if even >= odd:
        return "YES"
    return "NO"

def check(candidate):

    # Check some simple cases
    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 3]) == "NO"
    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == "NO"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([100, 200], [200, 200]) == "YES"


Prompt:
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
    odd = 0
    even = 0

        if i%2 == 1:
            odd += 1
    for i in lst2:
        if i%2 == 0:
            even += 1
    if even >= odd:
        return "YES"
    return "NO"

def check(candidate):

    # Check some simple cases
    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 3]) == "NO"
    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == "NO"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([100, 200], [200, 200]) == "YES"


Prompt:
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
    odd = 0
    even = 0
    for i in lst1:

            odd += 1
    for i in lst2:
        if i%2 == 0:
            even += 1
    if even >= odd:
        return "YES"
    return "NO"

def check(candidate):

    # Check some simple cases
    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 3]) == "NO"
    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == "NO"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([100, 200], [200, 200]) == "YES"


Prompt:
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
    odd = 0
    even = 0
    for i in lst1:
        if i%2 == 1:

    for i in lst2:
        if i%2 == 0:
            even += 1
    if even >= odd:
        return "YES"
    return "NO"

def check(candidate):

    # Check some simple cases
    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 3]) == "NO"
    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == "NO"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([100, 200], [200, 200]) == "YES"


Prompt:
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
    odd = 0
    even = 0
    for i in lst1:
        if i%2 == 1:
            odd += 1

        if i%2 == 0:
            even += 1
    if even >= odd:
        return "YES"
    return "NO"

def check(candidate):

    # Check some simple cases
    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 3]) == "NO"
    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == "NO"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([100, 200], [200, 200]) == "YES"


Prompt:
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
    odd = 0
    even = 0
    for i in lst1:
        if i%2 == 1:
            odd += 1
    for i in lst2:

            even += 1
    if even >= odd:
        return "YES"
    return "NO"

def check(candidate):

    # Check some simple cases
    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 3]) == "NO"
    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == "NO"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([100, 200], [200, 200]) == "YES"


Prompt:
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
    odd = 0
    even = 0
    for i in lst1:
        if i%2 == 1:
            odd += 1
    for i in lst2:
        if i%2 == 0:

    if even >= odd:
        return "YES"
    return "NO"

def check(candidate):

    # Check some simple cases
    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 3]) == "NO"
    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == "NO"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([100, 200], [200, 200]) == "YES"


Prompt:
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
    odd = 0
    even = 0
    for i in lst1:
        if i%2 == 1:
            odd += 1
    for i in lst2:
        if i%2 == 0:
            even += 1

def check(candidate):

    # Check some simple cases
    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 3]) == "NO"
    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == "NO"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([100, 200], [200, 200]) == "YES"


Prompt:
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
    odd = 0
    even = 0
    for i in lst1:
        if i%2 == 1:
            odd += 1
    for i in lst2:
        if i%2 == 0:
            even += 1
    if even >= odd:

def check(candidate):

    # Check some simple cases
    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 3]) == "NO"
    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == "NO"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([100, 200], [200, 200]) == "YES"


Prompt:
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
    odd = 0
    even = 0
    for i in lst1:
        if i%2 == 1:
            odd += 1
    for i in lst2:
        if i%2 == 0:
            even += 1
    if even >= odd:
        return "YES"

def check(candidate):

    # Check some simple cases
    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
    assert candidate([5, 7, 3], [2, 6, 3]) == "NO"
    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == "NO"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([100, 200], [200, 200]) == "YES"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """

    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}

    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:

            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':

    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)

        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:

            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def reverse_delete(s,c):
    """Task
    We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
    then check if the result string is palindrome.
    A string is called palindrome if it reads the same backward as forward.
    You should return a tuple containing the result string and True/False for the check.
    Example
    For s = "abcde", c = "ae", the result should be ('bcd',False)
    For s = "abcdef", c = "b"  the result should be ('acdef',False)
    For s = "abcdedcba", c = "ab", the result should be ('cdedc',True)
    """

s = ''.join([char for char in s if char not in c])

def check(candidate):

    assert candidate("abcde","ae") == ('bcd',False)
    assert candidate("abcdef", "b") == ('acdef',False)
    assert candidate("abcdedcba","ab") == ('cdedc',True)
    assert candidate("dwik","w") == ('dik',False)
    assert candidate("a","a") == ('',True)
    assert candidate("abcdedcba","") == ('abcdedcba',True)
    assert candidate("abcdedcba","v") == ('abcdedcba',True)
    assert candidate("vabba","v") == ('abba',True)
    assert candidate("mamma", "mia") == ("", True)


Prompt:
def reverse_delete(s,c):
    """Task
    We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
    then check if the result string is palindrome.
    A string is called palindrome if it reads the same backward as forward.
    You should return a tuple containing the result string and True/False for the check.
    Example
    For s = "abcde", c = "ae", the result should be ('bcd',False)
    For s = "abcdef", c = "b"  the result should be ('acdef',False)
    For s = "abcdedcba", c = "ab", the result should be ('cdedc',True)
    """
    s = ''.join([char for char in s if char not in c])

def check(candidate):

    assert candidate("abcde","ae") == ('bcd',False)
    assert candidate("abcdef", "b") == ('acdef',False)
    assert candidate("abcdedcba","ab") == ('cdedc',True)
    assert candidate("dwik","w") == ('dik',False)
    assert candidate("a","a") == ('',True)
    assert candidate("abcdedcba","") == ('abcdedcba',True)
    assert candidate("abcdedcba","v") == ('abcdedcba',True)
    assert candidate("vabba","v") == ('abba',True)
    assert candidate("mamma", "mia") == ("", True)


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """

    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []

        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []
    for arr in lst:

        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []
    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)

res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []
    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """

    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0

    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0
    s = 0

        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0
    s = 0
    for num in nums:

        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0
    s = 0
    for num in nums:
        s += -num

            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):

        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0

    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)

        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:

    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def max_fill(grid, capacity):
    import math
    """
    You are given a rectangular grid of wells. Each row represents a single well,
    and each 1 in a row represents a single unit of water.
    Each well has a corresponding bucket that can be used to extract water from it,
    and all buckets have the same capacity.
    Your task is to use the buckets to empty the wells.
    Output the number of times you need to lower the buckets.

    Example 1:
        Input:
            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]
            bucket_capacity : 1
        Output: 6

    Example 2:
        Input:
            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]
            bucket_capacity : 2
        Output: 5

    Example 3:
        Input:
            grid : [[0,0,0], [0,0,0]]
            bucket_capacity : 5
        Output: 0

    Constraints:
        * all wells have the same length
        * 1 <= grid.length <= 10^2
        * 1 <= grid[:,1].length <= 10^2
        * grid[i][j] -> 0 | 1
        * 1 <= capacity <= 10
    """

return sum([math.ceil(sum(arr)/capacity) for arr in grid])

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, "Error"
    assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, "Error"
    assert candidate([[0,0,0], [0,0,0]], 5) == 0, "Error"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([[1,1,1,1], [1,1,1,1]], 2) == 4, "Error"
    assert candidate([[1,1,1,1], [1,1,1,1]], 9) == 2, "Error"


Prompt:
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """

return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
    assert candidate([]) == []
    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]
    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """

    for word in s.split():
        n_consonants = 0
        for i in range(0, len(word)):
            if word[i].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:
            result.append(word)
    return result

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []

        n_consonants = 0
        for i in range(0, len(word)):
            if word[i].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:
            result.append(word)
    return result

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():

        for i in range(0, len(word)):
            if word[i].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:
            result.append(word)
    return result

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():
        n_consonants = 0

            if word[i].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:
            result.append(word)
    return result

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():
        n_consonants = 0
        for i in range(0, len(word)):

                n_consonants += 1
        if n_consonants == n:
            result.append(word)
    return result

if word[i].lower() not in ["a","e","i","o","u"]:

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():
        n_consonants = 0
        for i in range(0, len(word)):
            if word[i].lower() not in ["a","e","i","o","u"]:

        if n_consonants == n:
            result.append(word)
    return result

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():
        n_consonants = 0
        for i in range(0, len(word)):
            if word[i].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1

            result.append(word)
    return result

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():
        n_consonants = 0
        for i in range(0, len(word)):
            if word[i].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():
        n_consonants = 0
        for i in range(0, len(word)):
            if word[i].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:
            result.append(word)

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))