Prompt:
def will_it_fly(q,w):
    '''
    Write a function that returns True if the object q will fly, and False otherwise.
    The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.

    Example:
    will_it_fly([1, 2], 5) ➞ False
    # 1+2 is less than the maximum possible weight, but it's unbalanced.

    will_it_fly([3, 2, 3], 1) ➞ False
    # it's balanced, but 3+2+3 is more than the maximum possible weight.

    will_it_fly([3, 2, 3], 9) ➞ True
    # 3+2+3 is less than the maximum possible weight, and it's balanced.

    will_it_fly([3], 5) ➞ True
    # 3 is less than the maximum possible weight, and it's balanced.
    '''
    if sum(q) > w:
        return False

    i, j = 0, len(q)-1
    while i<j:
        if q[i] != q[j]:
            return False

def check(candidate):

    # Check some simple cases
    assert candidate([3, 2, 3], 9) is True
    assert candidate([1, 2], 5) is False
    assert candidate([3], 5) is True
    assert candidate([3, 2, 3], 1) is False

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1, 2, 3], 6) is False
    assert candidate([5], 5) is True


Prompt:
def will_it_fly(q,w):
    '''
    Write a function that returns True if the object q will fly, and False otherwise.
    The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.

    Example:
    will_it_fly([1, 2], 5) ➞ False
    # 1+2 is less than the maximum possible weight, but it's unbalanced.

    will_it_fly([3, 2, 3], 1) ➞ False
    # it's balanced, but 3+2+3 is more than the maximum possible weight.

    will_it_fly([3, 2, 3], 9) ➞ True
    # 3+2+3 is less than the maximum possible weight, and it's balanced.

    will_it_fly([3], 5) ➞ True
    # 3 is less than the maximum possible weight, and it's balanced.
    '''
    if sum(q) > w:
        return False

    i, j = 0, len(q)-1
    while i<j:
        if q[i] != q[j]:
            return False
        i+=1

def check(candidate):

    # Check some simple cases
    assert candidate([3, 2, 3], 9) is True
    assert candidate([1, 2], 5) is False
    assert candidate([3], 5) is True
    assert candidate([3, 2, 3], 1) is False

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1, 2, 3], 6) is False
    assert candidate([5], 5) is True


Prompt:
def will_it_fly(q,w):
    '''
    Write a function that returns True if the object q will fly, and False otherwise.
    The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.

    Example:
    will_it_fly([1, 2], 5) ➞ False
    # 1+2 is less than the maximum possible weight, but it's unbalanced.

    will_it_fly([3, 2, 3], 1) ➞ False
    # it's balanced, but 3+2+3 is more than the maximum possible weight.

    will_it_fly([3, 2, 3], 9) ➞ True
    # 3+2+3 is less than the maximum possible weight, and it's balanced.

    will_it_fly([3], 5) ➞ True
    # 3 is less than the maximum possible weight, and it's balanced.
    '''
    if sum(q) > w:
        return False

    i, j = 0, len(q)-1
    while i<j:
        if q[i] != q[j]:
            return False
        i+=1
        j-=1

def check(candidate):

    # Check some simple cases
    assert candidate([3, 2, 3], 9) is True
    assert candidate([1, 2], 5) is False
    assert candidate([3], 5) is True
    assert candidate([3, 2, 3], 1) is False

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1, 2, 3], 6) is False
    assert candidate([5], 5) is True


Prompt:
def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """

    for i in range(len(arr) // 2):
        if arr[i] != arr[len(arr) - i - 1]:
            ans += 1
    return ans

def check(candidate):

    # Check some simple cases
    assert candidate([1,2,3,5,4,7,9,6]) == 4
    assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1
    assert candidate([1, 4, 2]) == 1
    assert candidate([1, 4, 4, 2]) == 1

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1, 2, 3, 2, 1]) == 0
    assert candidate([3, 1, 1, 3]) == 0
    assert candidate([1]) == 0
    assert candidate([0, 1]) == 1


Prompt:
def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    ans = 0

        if arr[i] != arr[len(arr) - i - 1]:
            ans += 1
    return ans

def check(candidate):

    # Check some simple cases
    assert candidate([1,2,3,5,4,7,9,6]) == 4
    assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1
    assert candidate([1, 4, 2]) == 1
    assert candidate([1, 4, 4, 2]) == 1

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1, 2, 3, 2, 1]) == 0
    assert candidate([3, 1, 1, 3]) == 0
    assert candidate([1]) == 0
    assert candidate([0, 1]) == 1


Prompt:
def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    ans = 0
    for i in range(len(arr) // 2):

def check(candidate):

    # Check some simple cases
    assert candidate([1,2,3,5,4,7,9,6]) == 4
    assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1
    assert candidate([1, 4, 2]) == 1
    assert candidate([1, 4, 4, 2]) == 1

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1, 2, 3, 2, 1]) == 0
    assert candidate([3, 1, 1, 3]) == 0
    assert candidate([1]) == 0
    assert candidate([0, 1]) == 1


Prompt:
def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    ans = 0
    for i in range(len(arr) // 2):
        if arr[i] != arr[len(arr) - i - 1]:

def check(candidate):

    # Check some simple cases
    assert candidate([1,2,3,5,4,7,9,6]) == 4
    assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1
    assert candidate([1, 4, 2]) == 1
    assert candidate([1, 4, 4, 2]) == 1

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1, 2, 3, 2, 1]) == 0
    assert candidate([3, 1, 1, 3]) == 0
    assert candidate([1]) == 0
    assert candidate([0, 1]) == 1


Prompt:
def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
    ans = 0
    for i in range(len(arr) // 2):
        if arr[i] != arr[len(arr) - i - 1]:
            ans += 1

def check(candidate):

    # Check some simple cases
    assert candidate([1,2,3,5,4,7,9,6]) == 4
    assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1
    assert candidate([1, 4, 2]) == 1
    assert candidate([1, 4, 4, 2]) == 1

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1, 2, 3, 2, 1]) == 0
    assert candidate([3, 1, 1, 3]) == 0
    assert candidate([1]) == 0
    assert candidate([0, 1]) == 1


Prompt:
def total_match(lst1, lst2):
    '''
    Write a function that accepts two lists of strings and returns the list that has
    total number of chars in the all strings of the list less than the other list.

    if the two lists have the same number of chars, return the first list.

    Examples
    total_match([], []) ➞ []
    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''

    for st in lst1:
        l1 += len(st)

    l2 = 0
    for st in lst2:
        l2 += len(st)

    if l1 <= l2:
        return lst1
    else:
        return lst2

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([], []) == []
    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']
    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']
    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([], ['this']) == []
    assert candidate(['this'], []) == []


Prompt:
def total_match(lst1, lst2):
    '''
    Write a function that accepts two lists of strings and returns the list that has
    total number of chars in the all strings of the list less than the other list.

    if the two lists have the same number of chars, return the first list.

    Examples
    total_match([], []) ➞ []
    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''
    l1 = 0

        l1 += len(st)

    l2 = 0
    for st in lst2:
        l2 += len(st)

    if l1 <= l2:
        return lst1
    else:
        return lst2

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([], []) == []
    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']
    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']
    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([], ['this']) == []
    assert candidate(['this'], []) == []


Prompt:
def total_match(lst1, lst2):
    '''
    Write a function that accepts two lists of strings and returns the list that has
    total number of chars in the all strings of the list less than the other list.

    if the two lists have the same number of chars, return the first list.

    Examples
    total_match([], []) ➞ []
    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''
    l1 = 0
    for st in lst1:

    l2 = 0
    for st in lst2:
        l2 += len(st)

    if l1 <= l2:
        return lst1
    else:
        return lst2

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([], []) == []
    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']
    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']
    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([], ['this']) == []
    assert candidate(['this'], []) == []


Prompt:
def total_match(lst1, lst2):
    '''
    Write a function that accepts two lists of strings and returns the list that has
    total number of chars in the all strings of the list less than the other list.

    if the two lists have the same number of chars, return the first list.

    Examples
    total_match([], []) ➞ []
    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''
    l1 = 0
    for st in lst1:
        l1 += len(st)

    for st in lst2:
        l2 += len(st)

    if l1 <= l2:
        return lst1
    else:
        return lst2

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([], []) == []
    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']
    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']
    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([], ['this']) == []
    assert candidate(['this'], []) == []


Prompt:
def total_match(lst1, lst2):
    '''
    Write a function that accepts two lists of strings and returns the list that has
    total number of chars in the all strings of the list less than the other list.

    if the two lists have the same number of chars, return the first list.

    Examples
    total_match([], []) ➞ []
    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''
    l1 = 0
    for st in lst1:
        l1 += len(st)

    l2 = 0

        l2 += len(st)

    if l1 <= l2:
        return lst1
    else:
        return lst2

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([], []) == []
    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']
    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']
    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([], ['this']) == []
    assert candidate(['this'], []) == []


Prompt:
def total_match(lst1, lst2):
    '''
    Write a function that accepts two lists of strings and returns the list that has
    total number of chars in the all strings of the list less than the other list.

    if the two lists have the same number of chars, return the first list.

    Examples
    total_match([], []) ➞ []
    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''
    l1 = 0
    for st in lst1:
        l1 += len(st)

    l2 = 0
    for st in lst2:

    if l1 <= l2:
        return lst1
    else:
        return lst2

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([], []) == []
    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']
    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']
    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([], ['this']) == []
    assert candidate(['this'], []) == []


Prompt:
def total_match(lst1, lst2):
    '''
    Write a function that accepts two lists of strings and returns the list that has
    total number of chars in the all strings of the list less than the other list.

    if the two lists have the same number of chars, return the first list.

    Examples
    total_match([], []) ➞ []
    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''
    l1 = 0
    for st in lst1:
        l1 += len(st)

    l2 = 0
    for st in lst2:
        l2 += len(st)

        return lst1
    else:
        return lst2

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([], []) == []
    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']
    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']
    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([], ['this']) == []
    assert candidate(['this'], []) == []


Prompt:
def total_match(lst1, lst2):
    '''
    Write a function that accepts two lists of strings and returns the list that has
    total number of chars in the all strings of the list less than the other list.

    if the two lists have the same number of chars, return the first list.

    Examples
    total_match([], []) ➞ []
    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''
    l1 = 0
    for st in lst1:
        l1 += len(st)

    l2 = 0
    for st in lst2:
        l2 += len(st)

    if l1 <= l2:

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([], []) == []
    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']
    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']
    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([], ['this']) == []
    assert candidate(['this'], []) == []


Prompt:
def total_match(lst1, lst2):
    '''
    Write a function that accepts two lists of strings and returns the list that has
    total number of chars in the all strings of the list less than the other list.

    if the two lists have the same number of chars, return the first list.

    Examples
    total_match([], []) ➞ []
    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''
    l1 = 0
    for st in lst1:
        l1 += len(st)

    l2 = 0
    for st in lst2:
        l2 += len(st)

    if l1 <= l2:
        return lst1

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([], []) == []
    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']
    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']
    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([], ['this']) == []
    assert candidate(['this'], []) == []


Prompt:
def total_match(lst1, lst2):
    '''
    Write a function that accepts two lists of strings and returns the list that has
    total number of chars in the all strings of the list less than the other list.

    if the two lists have the same number of chars, return the first list.

    Examples
    total_match([], []) ➞ []
    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''
    l1 = 0
    for st in lst1:
        l1 += len(st)

    l2 = 0
    for st in lst2:
        l2 += len(st)

    if l1 <= l2:
        return lst1
    else:

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([], []) == []
    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']
    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']
    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([], ['this']) == []
    assert candidate(['this'], []) == []


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """

        for j in range(2,n):
            if n%j == 0:
                return False
        return True

    for i in range(2,101):
        if not is_prime(i): continue
        for j in range(2,101):
            if not is_prime(j): continue
            for k in range(2,101):
                if not is_prime(k): continue
                if i*j*k == a: return True
    return False

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
    def is_prime(n):

            if n%j == 0:
                return False
        return True

    for i in range(2,101):
        if not is_prime(i): continue
        for j in range(2,101):
            if not is_prime(j): continue
            for k in range(2,101):
                if not is_prime(k): continue
                if i*j*k == a: return True
    return False

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
    def is_prime(n):
        for j in range(2,n):

                return False
        return True

    for i in range(2,101):
        if not is_prime(i): continue
        for j in range(2,101):
            if not is_prime(j): continue
            for k in range(2,101):
                if not is_prime(k): continue
                if i*j*k == a: return True
    return False

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
    def is_prime(n):
        for j in range(2,n):
            if n%j == 0:

        return True

    for i in range(2,101):
        if not is_prime(i): continue
        for j in range(2,101):
            if not is_prime(j): continue
            for k in range(2,101):
                if not is_prime(k): continue
                if i*j*k == a: return True
    return False

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
    def is_prime(n):
        for j in range(2,n):
            if n%j == 0:
                return False

    for i in range(2,101):
        if not is_prime(i): continue
        for j in range(2,101):
            if not is_prime(j): continue
            for k in range(2,101):
                if not is_prime(k): continue
                if i*j*k == a: return True
    return False

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
    def is_prime(n):
        for j in range(2,n):
            if n%j == 0:
                return False
        return True

        if not is_prime(i): continue
        for j in range(2,101):
            if not is_prime(j): continue
            for k in range(2,101):
                if not is_prime(k): continue
                if i*j*k == a: return True
    return False

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
    def is_prime(n):
        for j in range(2,n):
            if n%j == 0:
                return False
        return True

    for i in range(2,101):

        for j in range(2,101):
            if not is_prime(j): continue
            for k in range(2,101):
                if not is_prime(k): continue
                if i*j*k == a: return True
    return False

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
    def is_prime(n):
        for j in range(2,n):
            if n%j == 0:
                return False
        return True

    for i in range(2,101):
        if not is_prime(i): continue

            if not is_prime(j): continue
            for k in range(2,101):
                if not is_prime(k): continue
                if i*j*k == a: return True
    return False

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
    def is_prime(n):
        for j in range(2,n):
            if n%j == 0:
                return False
        return True

    for i in range(2,101):
        if not is_prime(i): continue
        for j in range(2,101):

            for k in range(2,101):
                if not is_prime(k): continue
                if i*j*k == a: return True
    return False

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
    def is_prime(n):
        for j in range(2,n):
            if n%j == 0:
                return False
        return True

    for i in range(2,101):
        if not is_prime(i): continue
        for j in range(2,101):
            if not is_prime(j): continue

                if not is_prime(k): continue
                if i*j*k == a: return True
    return False

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
    def is_prime(n):
        for j in range(2,n):
            if n%j == 0:
                return False
        return True

    for i in range(2,101):
        if not is_prime(i): continue
        for j in range(2,101):
            if not is_prime(j): continue
            for k in range(2,101):

                if i*j*k == a: return True
    return False

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
    def is_prime(n):
        for j in range(2,n):
            if n%j == 0:
                return False
        return True

    for i in range(2,101):
        if not is_prime(i): continue
        for j in range(2,101):
            if not is_prime(j): continue
            for k in range(2,101):
                if not is_prime(k): continue

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
    def is_prime(n):
        for j in range(2,n):
            if n%j == 0:
                return False
        return True

    for i in range(2,101):
        if not is_prime(i): continue
        for j in range(2,101):
            if not is_prime(j): continue
            for k in range(2,101):
                if not is_prime(k): continue
                if i*j*k == a: return True

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_simple_power(x, n):
    """Your task is to write a function that returns true if a number x is a simple
    power of n and false in other cases.
    x is a simple power of n if n**int=x
    For example:
    is_simple_power(1, 4) => true
    is_simple_power(2, 2) => true
    is_simple_power(8, 2) => true
    is_simple_power(3, 2) => false
    is_simple_power(3, 1) => false
    is_simple_power(5, 3) => false
    """

        return (x == 1)
    power = 1
    while (power < x):
        power = power * n
    return (power == x)

def check(candidate):

    # Check some simple cases
    assert candidate(16, 2)== True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(143214, 16)== False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(4, 2)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(9, 3)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(16, 4)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(24, 2)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(128, 4)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(12, 6)==False, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1, 1)==True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate(1, 12)==True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def is_simple_power(x, n):
    """Your task is to write a function that returns true if a number x is a simple
    power of n and false in other cases.
    x is a simple power of n if n**int=x
    For example:
    is_simple_power(1, 4) => true
    is_simple_power(2, 2) => true
    is_simple_power(8, 2) => true
    is_simple_power(3, 2) => false
    is_simple_power(3, 1) => false
    is_simple_power(5, 3) => false
    """
    if (n == 1):

    power = 1
    while (power < x):
        power = power * n
    return (power == x)

def check(candidate):

    # Check some simple cases
    assert candidate(16, 2)== True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(143214, 16)== False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(4, 2)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(9, 3)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(16, 4)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(24, 2)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(128, 4)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(12, 6)==False, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1, 1)==True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate(1, 12)==True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def is_simple_power(x, n):
    """Your task is to write a function that returns true if a number x is a simple
    power of n and false in other cases.
    x is a simple power of n if n**int=x
    For example:
    is_simple_power(1, 4) => true
    is_simple_power(2, 2) => true
    is_simple_power(8, 2) => true
    is_simple_power(3, 2) => false
    is_simple_power(3, 1) => false
    is_simple_power(5, 3) => false
    """
    if (n == 1):
        return (x == 1)

    while (power < x):
        power = power * n
    return (power == x)

def check(candidate):

    # Check some simple cases
    assert candidate(16, 2)== True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(143214, 16)== False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(4, 2)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(9, 3)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(16, 4)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(24, 2)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(128, 4)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(12, 6)==False, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1, 1)==True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate(1, 12)==True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def is_simple_power(x, n):
    """Your task is to write a function that returns true if a number x is a simple
    power of n and false in other cases.
    x is a simple power of n if n**int=x
    For example:
    is_simple_power(1, 4) => true
    is_simple_power(2, 2) => true
    is_simple_power(8, 2) => true
    is_simple_power(3, 2) => false
    is_simple_power(3, 1) => false
    is_simple_power(5, 3) => false
    """
    if (n == 1):
        return (x == 1)
    power = 1

        power = power * n
    return (power == x)

def check(candidate):

    # Check some simple cases
    assert candidate(16, 2)== True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(143214, 16)== False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(4, 2)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(9, 3)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(16, 4)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(24, 2)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(128, 4)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(12, 6)==False, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1, 1)==True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate(1, 12)==True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def is_simple_power(x, n):
    """Your task is to write a function that returns true if a number x is a simple
    power of n and false in other cases.
    x is a simple power of n if n**int=x
    For example:
    is_simple_power(1, 4) => true
    is_simple_power(2, 2) => true
    is_simple_power(8, 2) => true
    is_simple_power(3, 2) => false
    is_simple_power(3, 1) => false
    is_simple_power(5, 3) => false
    """
    if (n == 1):
        return (x == 1)
    power = 1
    while (power < x):

def check(candidate):

    # Check some simple cases
    assert candidate(16, 2)== True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(143214, 16)== False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(4, 2)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(9, 3)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(16, 4)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(24, 2)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(128, 4)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(12, 6)==False, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1, 1)==True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate(1, 12)==True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def is_simple_power(x, n):
    """Your task is to write a function that returns true if a number x is a simple
    power of n and false in other cases.
    x is a simple power of n if n**int=x
    For example:
    is_simple_power(1, 4) => true
    is_simple_power(2, 2) => true
    is_simple_power(8, 2) => true
    is_simple_power(3, 2) => false
    is_simple_power(3, 1) => false
    is_simple_power(5, 3) => false
    """
    if (n == 1):
        return (x == 1)
    power = 1
    while (power < x):
        power = power * n

def check(candidate):

    # Check some simple cases
    assert candidate(16, 2)== True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(143214, 16)== False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(4, 2)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(9, 3)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(16, 4)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(24, 2)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(128, 4)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(12, 6)==False, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1, 1)==True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate(1, 12)==True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def iscube(a):
    '''
    Write a function that takes an integer a and returns True
    if this ingeger is a cube of some integer number.
    Note: you may assume the input is always valid.
    Examples:
    iscube(1) ==> True
    iscube(2) ==> False
    iscube(-1) ==> True
    iscube(64) ==> True
    iscube(0) ==> True
    iscube(180) ==> False
    '''

def check(candidate):

    # Check some simple cases
    assert candidate(1) == True, "First test error: " + str(candidate(1))
    assert candidate(2) == False, "Second test error: " + str(candidate(2))
    assert candidate(-1) == True, "Third test error: " + str(candidate(-1))
    assert candidate(64) == True, "Fourth test error: " + str(candidate(64))
    assert candidate(180) == False, "Fifth test error: " + str(candidate(180))
    assert candidate(1000) == True, "Sixth test error: " + str(candidate(1000))

    # Check some edge cases that are easy to work out by hand.
    assert candidate(0) == True, "1st edge test error: " + str(candidate(0))
    assert candidate(1729) == False, "2nd edge test error: " + str(candidate(1728))


Prompt:
def iscube(a):
    '''
    Write a function that takes an integer a and returns True
    if this ingeger is a cube of some integer number.
    Note: you may assume the input is always valid.
    Examples:
    iscube(1) ==> True
    iscube(2) ==> False
    iscube(-1) ==> True
    iscube(64) ==> True
    iscube(0) ==> True
    iscube(180) ==> False
    '''
    a = abs(a)

def check(candidate):

    # Check some simple cases
    assert candidate(1) == True, "First test error: " + str(candidate(1))
    assert candidate(2) == False, "Second test error: " + str(candidate(2))
    assert candidate(-1) == True, "Third test error: " + str(candidate(-1))
    assert candidate(64) == True, "Fourth test error: " + str(candidate(64))
    assert candidate(180) == False, "Fifth test error: " + str(candidate(180))
    assert candidate(1000) == True, "Sixth test error: " + str(candidate(1000))

    # Check some edge cases that are easy to work out by hand.
    assert candidate(0) == True, "1st edge test error: " + str(candidate(0))
    assert candidate(1729) == False, "2nd edge test error: " + str(candidate(1728))


Prompt:
def hex_key(num):
    """You have been tasked to write a function that receives
    a hexadecimal number as a string and counts the number of hexadecimal
    digits that are primes (prime number, or a prime, is a natural number
    greater than 1 that is not a product of two smaller natural numbers).
    Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
    Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
    So you have to determine a number of the following digits: 2, 3, 5, 7,
    B (=decimal 11), D (=decimal 13).
    Note: you may assume the input is always correct or empty string,
    and symbols A,B,C,D,E,F are always uppercase.
    Examples:
    For num = "AB" the output should be 1.
    For num = "1077E" the output should be 2.
    For num = "ABED1A33" the output should be 4.
    For num = "123456789ABCDEF0" the output should be 6.
    For num = "2020" the output should be 2.
    """

    total = 0
    for i in range(0, len(num)):
        if num[i] in primes:
            total += 1
    return total

def check(candidate):

    # Check some simple cases
    assert candidate("AB") == 1, "First test error: " + str(candidate("AB"))
    assert candidate("1077E") == 2, "Second test error: " + str(candidate("1077E"))
    assert candidate("ABED1A33") == 4, "Third test error: " + str(candidate("ABED1A33"))
    assert candidate("2020") == 2, "Fourth test error: " + str(candidate("2020"))
    assert candidate("123456789ABCDEF0") == 6, "Fifth test error: " + str(candidate("123456789ABCDEF0"))
    assert candidate("112233445566778899AABBCCDDEEFF00") == 12, "Sixth test error: " + str(candidate("112233445566778899AABBCCDDEEFF00"))

    # Check some edge cases that are easy to work out by hand.
    assert candidate([]) == 0


Prompt:
def hex_key(num):
    """You have been tasked to write a function that receives
    a hexadecimal number as a string and counts the number of hexadecimal
    digits that are primes (prime number, or a prime, is a natural number
    greater than 1 that is not a product of two smaller natural numbers).
    Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
    Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
    So you have to determine a number of the following digits: 2, 3, 5, 7,
    B (=decimal 11), D (=decimal 13).
    Note: you may assume the input is always correct or empty string,
    and symbols A,B,C,D,E,F are always uppercase.
    Examples:
    For num = "AB" the output should be 1.
    For num = "1077E" the output should be 2.
    For num = "ABED1A33" the output should be 4.
    For num = "123456789ABCDEF0" the output should be 6.
    For num = "2020" the output should be 2.
    """
    primes = ('2', '3', '5', '7', 'B', 'D')

    for i in range(0, len(num)):
        if num[i] in primes:
            total += 1
    return total

def check(candidate):

    # Check some simple cases
    assert candidate("AB") == 1, "First test error: " + str(candidate("AB"))
    assert candidate("1077E") == 2, "Second test error: " + str(candidate("1077E"))
    assert candidate("ABED1A33") == 4, "Third test error: " + str(candidate("ABED1A33"))
    assert candidate("2020") == 2, "Fourth test error: " + str(candidate("2020"))
    assert candidate("123456789ABCDEF0") == 6, "Fifth test error: " + str(candidate("123456789ABCDEF0"))
    assert candidate("112233445566778899AABBCCDDEEFF00") == 12, "Sixth test error: " + str(candidate("112233445566778899AABBCCDDEEFF00"))

    # Check some edge cases that are easy to work out by hand.
    assert candidate([]) == 0


Prompt:
def hex_key(num):
    """You have been tasked to write a function that receives
    a hexadecimal number as a string and counts the number of hexadecimal
    digits that are primes (prime number, or a prime, is a natural number
    greater than 1 that is not a product of two smaller natural numbers).
    Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
    Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
    So you have to determine a number of the following digits: 2, 3, 5, 7,
    B (=decimal 11), D (=decimal 13).
    Note: you may assume the input is always correct or empty string,
    and symbols A,B,C,D,E,F are always uppercase.
    Examples:
    For num = "AB" the output should be 1.
    For num = "1077E" the output should be 2.
    For num = "ABED1A33" the output should be 4.
    For num = "123456789ABCDEF0" the output should be 6.
    For num = "2020" the output should be 2.
    """
    primes = ('2', '3', '5', '7', 'B', 'D')
    total = 0

        if num[i] in primes:
            total += 1
    return total

def check(candidate):

    # Check some simple cases
    assert candidate("AB") == 1, "First test error: " + str(candidate("AB"))
    assert candidate("1077E") == 2, "Second test error: " + str(candidate("1077E"))
    assert candidate("ABED1A33") == 4, "Third test error: " + str(candidate("ABED1A33"))
    assert candidate("2020") == 2, "Fourth test error: " + str(candidate("2020"))
    assert candidate("123456789ABCDEF0") == 6, "Fifth test error: " + str(candidate("123456789ABCDEF0"))
    assert candidate("112233445566778899AABBCCDDEEFF00") == 12, "Sixth test error: " + str(candidate("112233445566778899AABBCCDDEEFF00"))

    # Check some edge cases that are easy to work out by hand.
    assert candidate([]) == 0


Prompt:
def hex_key(num):
    """You have been tasked to write a function that receives
    a hexadecimal number as a string and counts the number of hexadecimal
    digits that are primes (prime number, or a prime, is a natural number
    greater than 1 that is not a product of two smaller natural numbers).
    Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
    Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
    So you have to determine a number of the following digits: 2, 3, 5, 7,
    B (=decimal 11), D (=decimal 13).
    Note: you may assume the input is always correct or empty string,
    and symbols A,B,C,D,E,F are always uppercase.
    Examples:
    For num = "AB" the output should be 1.
    For num = "1077E" the output should be 2.
    For num = "ABED1A33" the output should be 4.
    For num = "123456789ABCDEF0" the output should be 6.
    For num = "2020" the output should be 2.
    """
    primes = ('2', '3', '5', '7', 'B', 'D')
    total = 0
    for i in range(0, len(num)):

def check(candidate):

    # Check some simple cases
    assert candidate("AB") == 1, "First test error: " + str(candidate("AB"))
    assert candidate("1077E") == 2, "Second test error: " + str(candidate("1077E"))
    assert candidate("ABED1A33") == 4, "Third test error: " + str(candidate("ABED1A33"))
    assert candidate("2020") == 2, "Fourth test error: " + str(candidate("2020"))
    assert candidate("123456789ABCDEF0") == 6, "Fifth test error: " + str(candidate("123456789ABCDEF0"))
    assert candidate("112233445566778899AABBCCDDEEFF00") == 12, "Sixth test error: " + str(candidate("112233445566778899AABBCCDDEEFF00"))

    # Check some edge cases that are easy to work out by hand.
    assert candidate([]) == 0


Prompt:
def hex_key(num):
    """You have been tasked to write a function that receives
    a hexadecimal number as a string and counts the number of hexadecimal
    digits that are primes (prime number, or a prime, is a natural number
    greater than 1 that is not a product of two smaller natural numbers).
    Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
    Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
    So you have to determine a number of the following digits: 2, 3, 5, 7,
    B (=decimal 11), D (=decimal 13).
    Note: you may assume the input is always correct or empty string,
    and symbols A,B,C,D,E,F are always uppercase.
    Examples:
    For num = "AB" the output should be 1.
    For num = "1077E" the output should be 2.
    For num = "ABED1A33" the output should be 4.
    For num = "123456789ABCDEF0" the output should be 6.
    For num = "2020" the output should be 2.
    """
    primes = ('2', '3', '5', '7', 'B', 'D')
    total = 0
    for i in range(0, len(num)):
        if num[i] in primes:

def check(candidate):

    # Check some simple cases
    assert candidate("AB") == 1, "First test error: " + str(candidate("AB"))
    assert candidate("1077E") == 2, "Second test error: " + str(candidate("1077E"))
    assert candidate("ABED1A33") == 4, "Third test error: " + str(candidate("ABED1A33"))
    assert candidate("2020") == 2, "Fourth test error: " + str(candidate("2020"))
    assert candidate("123456789ABCDEF0") == 6, "Fifth test error: " + str(candidate("123456789ABCDEF0"))
    assert candidate("112233445566778899AABBCCDDEEFF00") == 12, "Sixth test error: " + str(candidate("112233445566778899AABBCCDDEEFF00"))

    # Check some edge cases that are easy to work out by hand.
    assert candidate([]) == 0


Prompt:
def hex_key(num):
    """You have been tasked to write a function that receives
    a hexadecimal number as a string and counts the number of hexadecimal
    digits that are primes (prime number, or a prime, is a natural number
    greater than 1 that is not a product of two smaller natural numbers).
    Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
    Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
    So you have to determine a number of the following digits: 2, 3, 5, 7,
    B (=decimal 11), D (=decimal 13).
    Note: you may assume the input is always correct or empty string,
    and symbols A,B,C,D,E,F are always uppercase.
    Examples:
    For num = "AB" the output should be 1.
    For num = "1077E" the output should be 2.
    For num = "ABED1A33" the output should be 4.
    For num = "123456789ABCDEF0" the output should be 6.
    For num = "2020" the output should be 2.
    """
    primes = ('2', '3', '5', '7', 'B', 'D')
    total = 0
    for i in range(0, len(num)):
        if num[i] in primes:
            total += 1

def check(candidate):

    # Check some simple cases
    assert candidate("AB") == 1, "First test error: " + str(candidate("AB"))
    assert candidate("1077E") == 2, "Second test error: " + str(candidate("1077E"))
    assert candidate("ABED1A33") == 4, "Third test error: " + str(candidate("ABED1A33"))
    assert candidate("2020") == 2, "Fourth test error: " + str(candidate("2020"))
    assert candidate("123456789ABCDEF0") == 6, "Fifth test error: " + str(candidate("123456789ABCDEF0"))
    assert candidate("112233445566778899AABBCCDDEEFF00") == 12, "Sixth test error: " + str(candidate("112233445566778899AABBCCDDEEFF00"))

    # Check some edge cases that are easy to work out by hand.
    assert candidate([]) == 0


Prompt:
def decimal_to_binary(decimal):
    """You will be given a number in decimal form and your task is to convert it to
    binary format. The function should return a string, with each character representing a binary
    number. Each character in the string will be '0' or '1'.

    There will be an extra couple of characters 'db' at the beginning and at the end of the string.
    The extra characters are there to help with the format.

    Examples:
    decimal_to_binary(15)   # returns "db1111db"
    decimal_to_binary(32)   # returns "db100000db"
    """

def check(candidate):

    # Check some simple cases
    assert candidate(0) == "db0db"
    assert candidate(32) == "db100000db"
    assert candidate(103) == "db1100111db"
    assert candidate(15) == "db1111db", "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def is_happy(s):
    """You are given a string s.
    Your task is to check if the string is happy or not.
    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
    For example:
    is_happy(a) => False
    is_happy(aa) => False
    is_happy(abcd) => True
    is_happy(aabb) => False
    is_happy(adb) => True
    is_happy(xyy) => False
    """

      return False

    for i in range(len(s) - 2):

      if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:
        return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate("a") == False , "a"
    assert candidate("aa") == False , "aa"
    assert candidate("abcd") == True , "abcd"
    assert candidate("aabb") == False , "aabb"
    assert candidate("adb") == True , "adb"
    assert candidate("xyy") == False , "xyy"
    assert candidate("iopaxpoi") == True , "iopaxpoi"
    assert candidate("iopaxioi") == False , "iopaxioi"


Prompt:
def is_happy(s):
    """You are given a string s.
    Your task is to check if the string is happy or not.
    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
    For example:
    is_happy(a) => False
    is_happy(aa) => False
    is_happy(abcd) => True
    is_happy(aabb) => False
    is_happy(adb) => True
    is_happy(xyy) => False
    """
    if len(s) < 3:

    for i in range(len(s) - 2):

      if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:
        return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate("a") == False , "a"
    assert candidate("aa") == False , "aa"
    assert candidate("abcd") == True , "abcd"
    assert candidate("aabb") == False , "aabb"
    assert candidate("adb") == True , "adb"
    assert candidate("xyy") == False , "xyy"
    assert candidate("iopaxpoi") == True , "iopaxpoi"
    assert candidate("iopaxioi") == False , "iopaxioi"


Prompt:
def is_happy(s):
    """You are given a string s.
    Your task is to check if the string is happy or not.
    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
    For example:
    is_happy(a) => False
    is_happy(aa) => False
    is_happy(abcd) => True
    is_happy(aabb) => False
    is_happy(adb) => True
    is_happy(xyy) => False
    """
    if len(s) < 3:
      return False

      if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:
        return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate("a") == False , "a"
    assert candidate("aa") == False , "aa"
    assert candidate("abcd") == True , "abcd"
    assert candidate("aabb") == False , "aabb"
    assert candidate("adb") == True , "adb"
    assert candidate("xyy") == False , "xyy"
    assert candidate("iopaxpoi") == True , "iopaxpoi"
    assert candidate("iopaxioi") == False , "iopaxioi"


Prompt:
def is_happy(s):
    """You are given a string s.
    Your task is to check if the string is happy or not.
    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
    For example:
    is_happy(a) => False
    is_happy(aa) => False
    is_happy(abcd) => True
    is_happy(aabb) => False
    is_happy(adb) => True
    is_happy(xyy) => False
    """
    if len(s) < 3:
      return False

    for i in range(len(s) - 2):

def check(candidate):

    # Check some simple cases
    assert candidate("a") == False , "a"
    assert candidate("aa") == False , "aa"
    assert candidate("abcd") == True , "abcd"
    assert candidate("aabb") == False , "aabb"
    assert candidate("adb") == True , "adb"
    assert candidate("xyy") == False , "xyy"
    assert candidate("iopaxpoi") == True , "iopaxpoi"
    assert candidate("iopaxioi") == False , "iopaxioi"


Prompt:
def is_happy(s):
    """You are given a string s.
    Your task is to check if the string is happy or not.
    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
    For example:
    is_happy(a) => False
    is_happy(aa) => False
    is_happy(abcd) => True
    is_happy(aabb) => False
    is_happy(adb) => True
    is_happy(xyy) => False
    """
    if len(s) < 3:
      return False

    for i in range(len(s) - 2):

      if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:

def check(candidate):

    # Check some simple cases
    assert candidate("a") == False , "a"
    assert candidate("aa") == False , "aa"
    assert candidate("abcd") == True , "abcd"
    assert candidate("aabb") == False , "aabb"
    assert candidate("adb") == True , "adb"
    assert candidate("xyy") == False , "xyy"
    assert candidate("iopaxpoi") == True , "iopaxpoi"
    assert candidate("iopaxioi") == False , "iopaxioi"


Prompt:
def is_happy(s):
    """You are given a string s.
    Your task is to check if the string is happy or not.
    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
    For example:
    is_happy(a) => False
    is_happy(aa) => False
    is_happy(abcd) => True
    is_happy(aabb) => False
    is_happy(adb) => True
    is_happy(xyy) => False
    """
    if len(s) < 3:
      return False

    for i in range(len(s) - 2):

      if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:
        return False

def check(candidate):

    # Check some simple cases
    assert candidate("a") == False , "a"
    assert candidate("aa") == False , "aa"
    assert candidate("abcd") == True , "abcd"
    assert candidate("aabb") == False , "aabb"
    assert candidate("adb") == True , "adb"
    assert candidate("xyy") == False , "xyy"
    assert candidate("iopaxpoi") == True , "iopaxpoi"
    assert candidate("iopaxioi") == False , "iopaxioi"


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    for gpa in grades:
        if gpa == 4.0:
            letter_grade.append("A+")
        elif gpa > 3.7:
            letter_grade.append("A")
        elif gpa > 3.3:
            letter_grade.append("A-")
        elif gpa > 3.0:
            letter_grade.append("B+")
        elif gpa > 2.7:
            letter_grade.append("B")
        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []

        if gpa == 4.0:
            letter_grade.append("A+")
        elif gpa > 3.7:
            letter_grade.append("A")
        elif gpa > 3.3:
            letter_grade.append("A-")
        elif gpa > 3.0:
            letter_grade.append("B+")
        elif gpa > 2.7:
            letter_grade.append("B")
        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []
    for gpa in grades:

            letter_grade.append("A+")
        elif gpa > 3.7:
            letter_grade.append("A")
        elif gpa > 3.3:
            letter_grade.append("A-")
        elif gpa > 3.0:
            letter_grade.append("B+")
        elif gpa > 2.7:
            letter_grade.append("B")
        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []
    for gpa in grades:
        if gpa == 4.0:

        elif gpa > 3.7:
            letter_grade.append("A")
        elif gpa > 3.3:
            letter_grade.append("A-")
        elif gpa > 3.0:
            letter_grade.append("B+")
        elif gpa > 2.7:
            letter_grade.append("B")
        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []
    for gpa in grades:
        if gpa == 4.0:
            letter_grade.append("A+")

            letter_grade.append("A")
        elif gpa > 3.3:
            letter_grade.append("A-")
        elif gpa > 3.0:
            letter_grade.append("B+")
        elif gpa > 2.7:
            letter_grade.append("B")
        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []
    for gpa in grades:
        if gpa == 4.0:
            letter_grade.append("A+")
        elif gpa > 3.7:

        elif gpa > 3.3:
            letter_grade.append("A-")
        elif gpa > 3.0:
            letter_grade.append("B+")
        elif gpa > 2.7:
            letter_grade.append("B")
        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []
    for gpa in grades:
        if gpa == 4.0:
            letter_grade.append("A+")
        elif gpa > 3.7:
            letter_grade.append("A")

            letter_grade.append("A-")
        elif gpa > 3.0:
            letter_grade.append("B+")
        elif gpa > 2.7:
            letter_grade.append("B")
        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []
    for gpa in grades:
        if gpa == 4.0:
            letter_grade.append("A+")
        elif gpa > 3.7:
            letter_grade.append("A")
        elif gpa > 3.3:

        elif gpa > 3.0:
            letter_grade.append("B+")
        elif gpa > 2.7:
            letter_grade.append("B")
        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []
    for gpa in grades:
        if gpa == 4.0:
            letter_grade.append("A+")
        elif gpa > 3.7:
            letter_grade.append("A")
        elif gpa > 3.3:
            letter_grade.append("A-")

            letter_grade.append("B+")
        elif gpa > 2.7:
            letter_grade.append("B")
        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []
    for gpa in grades:
        if gpa == 4.0:
            letter_grade.append("A+")
        elif gpa > 3.7:
            letter_grade.append("A")
        elif gpa > 3.3:
            letter_grade.append("A-")
        elif gpa > 3.0:

        elif gpa > 2.7:
            letter_grade.append("B")
        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []
    for gpa in grades:
        if gpa == 4.0:
            letter_grade.append("A+")
        elif gpa > 3.7:
            letter_grade.append("A")
        elif gpa > 3.3:
            letter_grade.append("A-")
        elif gpa > 3.0:
            letter_grade.append("B+")

            letter_grade.append("B")
        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []
    for gpa in grades:
        if gpa == 4.0:
            letter_grade.append("A+")
        elif gpa > 3.7:
            letter_grade.append("A")
        elif gpa > 3.3:
            letter_grade.append("A-")
        elif gpa > 3.0:
            letter_grade.append("B+")
        elif gpa > 2.7:

        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []
    for gpa in grades:
        if gpa == 4.0:
            letter_grade.append("A+")
        elif gpa > 3.7:
            letter_grade.append("A")
        elif gpa > 3.3:
            letter_grade.append("A-")
        elif gpa > 3.0:
            letter_grade.append("B+")
        elif gpa > 2.7:
            letter_grade.append("B")

            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True