Prompt:
def max_fill(grid, capacity):
    import math
    """
    You are given a rectangular grid of wells. Each row represents a single well,
    and each 1 in a row represents a single unit of water.
    Each well has a corresponding bucket that can be used to extract water from it,
    and all buckets have the same capacity.
    Your task is to use the buckets to empty the wells.
    Output the number of times you need to lower the buckets.

    Example 1:
        Input:
            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]
            bucket_capacity : 1
        Output: 6

    Example 2:
        Input:
            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]
            bucket_capacity : 2
        Output: 5

    Example 3:
        Input:
            grid : [[0,0,0], [0,0,0]]
            bucket_capacity : 5
        Output: 0

    Constraints:
        * all wells have the same length
        * 1 <= grid.length <= 10^2
        * 1 <= grid[:,1].length <= 10^2
        * grid[i][j] -> 0 | 1
        * 1 <= capacity <= 10
    """
    return sum([math.ceil(sum(arr)/c

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, "Error"
    assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, "Error"
    assert candidate([[0,0,0], [0,0,0]], 5) == 0, "Error"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([[1,1,1,1], [1,1,1,1]], 2) == 4, "Error"
    assert candidate([[1,1,1,1], [1,1,1,1]], 9) == 2, "Error"


Prompt:
def max_fill(grid, capacity):
    import math
    """
    You are given a rectangular grid of wells. Each row represents a single well,
    and each 1 in a row represents a single unit of water.
    Each well has a corresponding bucket that can be used to extract water from it,
    and all buckets have the same capacity.
    Your task is to use the buckets to empty the wells.
    Output the number of times you need to lower the buckets.

    Example 1:
        Input:
            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]
            bucket_capacity : 1
        Output: 6

    Example 2:
        Input:
            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]
            bucket_capacity : 2
        Output: 5

    Example 3:
        Input:
            grid : [[0,0,0], [0,0,0]]
            bucket_capacity : 5
        Output: 0

    Constraints:
        * all wells have the same length
        * 1 <= grid.length <= 10^2
        * 1 <= grid[:,1].length <= 10^2
        * grid[i][j] -> 0 | 1
        * 1 <= capacity <= 10
    """
    return

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, "Error"
    assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, "Error"
    assert candidate([[0,0,0], [0,0,0]], 5) == 0, "Error"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([[1,1,1,1], [1,1,1,1]], 2) == 4, "Error"
    assert candidate([[1,1,1,1], [1,1,1,1]], 9) == 2, "Error"


Prompt:
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
    return sorted(sorted(arr), key=lambda

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
    assert candidate([]) == []
    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]
    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
    return sorted(sorted(arr), key=la

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
    assert candidate([]) == []
    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]
    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
    return sorted(sorted(arr)

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
    assert candidate([]) == []
    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]
    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
    r

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
    assert candidate([]) == []
    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]
    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
    re

turn sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1')

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
    assert candidate([]) == []
    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]
    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
    return so

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
    assert candidate([]) == []
    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]
    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
    return sor

rted(arr), key=lambda x: bin(x)[2:].count('1'))

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
    assert candidate([]) == []
    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]
    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
    return sorted(sorted(arr), key

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
    assert candidate([]) == []
    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]
    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
    assert candidate([]) == []
    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]
    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
    retur

orted(arr), key=lambda x: bin(x)[2:].count('1'))

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
    assert candidate([]) == []
    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]
    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]
    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for

word in s.split():
        n_consonants = 0
        for i in range(0, len(word)):
            if word[i].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:
            result.append(word)
    return resul

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():
        n_consonants = 0
        for i in range(0, len(word)):
            if word[i].lower() not in ["a","e","i","o","u

"]:
                n_consonants += 1
        if n_consonants == n:
            result.a

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():
        n_consonants = 0
        for i in range(0,

len(word)):
            if word[i].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:
            result.append(word)
    r

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():
        n_consonants = 0
        for i in range(0, len(word)):

       result.append(word)
    return result

         if word[i].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for

 in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:
            result.append(word)
    return result

word in s.split():
        n_consonants = 0
        for i in range(0, len(word)):
            if word[i].lower() not

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for

  if word[i].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:
            result.append(word)
    return result

word in s.split():
        n_consonants = 0
        for i in range(0, len(word)):

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():
        n_consonants = 0

r i in range(0, len(word)):
            if word[i].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:
            result.append(word)
    return result

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result

           n_consonants += 1
        if n_consonants == n:
            result.append(word)
    return result

= []
    for word in s.split():
        n_consonants = 0
        for i in range(0, len(word)):
            if word[i].lower() not in ["a","e","i","o","u"]:

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():
        n_consonants = 0
        for i in range(0, l

].lower() not in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:
            result.append(word)
    return result

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    result = []
    for word in s.split():
        n_consonants = 0
        for i in range(

 in ["a","e","i","o","u"]:
                n_consonants += 1
        if n_consonants == n:
            result.append(word)
    return result

0, len(word)):
            if word[i].lower() not

def check(candidate):

    # Check some simple cases
    assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
    assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little lamb", 3))
    assert candidate("simple white space", 2) == [], "Third test error: " + str(candidate("simple white space", 2))
    assert candidate("Hello world", 4) == ["world"], "Fourth test error: " + str(candidate("Hello world", 4))
    assert candidate("Uncle sam", 3) == ["Uncle"], "Fifth test error: " + str(candidate("Uncle sam", 3))

    # Check some edge cases that are easy to work out by hand.
    assert candidate("", 4) == [], "1st edge test error: " + str(candidate("", 4))
    assert candidate("a b c d e f", 1) == ["b", "c", "d", "f"], "2nd edge test error: " + str(candidate("a b c d e f", 1))


Prompt:
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between
    two consonants from the right side of the word (case sensitive).

    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition.

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
    if len(word) <

return ""

    vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
    for i in range(len(word)-2, 0, -1):
        if word[i] in vowels:
            if (word[i+1] not in vowels) and (word[i-1] not in vowels):
                return word[i]
    return ""

def check(candidate):

    # Check some simple cases
    assert candidate("yogurt") == "u"
    assert candidate("full") == "u"
    assert candidate("easy") == ""
    assert candidate("eAsy") == ""
    assert candidate("ali") == ""
    assert candidate("bad") == "a"
    assert candidate("most") == "o"
    assert candidate("ab") == ""
    assert candidate("ba") == ""
    assert candidate("quick") == ""
    assert candidate("anime") == "i"
    assert candidate("Asia") == ""
    assert candidate("Above") == "o"

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between
    two consonants from the right side of the word (case sensitive).

    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition.

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
    if len(word) < 3:
        return ""

    vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
    for i in range(len(word)-2, 0, -1):

d[i] in vowels:
            if (word[i+1] not in vowels) and (word[i-1] not in vowels):
                return word[i]
    return ""

def check(candidate):

    # Check some simple cases
    assert candidate("yogurt") == "u"
    assert candidate("full") == "u"
    assert candidate("easy") == ""
    assert candidate("eAsy") == ""
    assert candidate("ali") == ""
    assert candidate("bad") == "a"
    assert candidate("most") == "o"
    assert candidate("ab") == ""
    assert candidate("ba") == ""
    assert candidate("quick") == ""
    assert candidate("anime") == "i"
    assert candidate("Asia") == ""
    assert candidate("Above") == "o"

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between
    two consonants from the right side of the word (case sensitive).

    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition.

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
    if len(word) < 3:
        return ""

   vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
    for i in range(len(word)-2, 0, -1):
        if word[i] in vowels:
            if (word[i+1] not in vowels) and (word[i-1] not in vowels):

def check(candidate):

    # Check some simple cases
    assert candidate("yogurt") == "u"
    assert candidate("full") == "u"
    assert candidate("easy") == ""
    assert candidate("eAsy") == ""
    assert candidate("ali") == ""
    assert candidate("bad") == "a"
    assert candidate("most") == "o"
    assert candidate("ab") == ""
    assert candidate("ba") == ""
    assert candidate("quick") == ""
    assert candidate("anime") == "i"
    assert candidate("Asia") == ""
    assert candidate("Above") == "o"

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between
    two consonants from the right side of the word (case sensitive).

    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition.

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
    if len(word) < 3:
        return ""

    vowels = {"a",

ord)-2, 0, -1):
        if word[i] in vowels:
            if (word[i+1] not in vowels) and (word[i-1] not in vowels):
                return word[i]
    return ""

def check(candidate):

    # Check some simple cases
    assert candidate("yogurt") == "u"
    assert candidate("full") == "u"
    assert candidate("easy") == ""
    assert candidate("eAsy") == ""
    assert candidate("ali") == ""
    assert candidate("bad") == "a"
    assert candidate("most") == "o"
    assert candidate("ab") == ""
    assert candidate("ba") == ""
    assert candidate("quick") == ""
    assert candidate("anime") == "i"
    assert candidate("Asia") == ""
    assert candidate("Above") == "o"

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between
    two consonants from the right side of the word (case sensitive).

    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition.

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
    if len(word) < 3:
        return ""

    vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
    for i in range(len(word)-2, 0, -1):

   if word[i] in vowels:
            if (word[i+1] not in vowels) and (word[i-1] not in vowels):
                return word[i]
    retu

def check(candidate):

    # Check some simple cases
    assert candidate("yogurt") == "u"
    assert candidate("full") == "u"
    assert candidate("easy") == ""
    assert candidate("eAsy") == ""
    assert candidate("ali") == ""
    assert candidate("bad") == "a"
    assert candidate("most") == "o"
    assert candidate("ab") == ""
    assert candidate("ba") == ""
    assert candidate("quick") == ""
    assert candidate("anime") == "i"
    assert candidate("Asia") == ""
    assert candidate("Above") == "o"

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between
    two consonants from the right side of the word (case sensitive).

    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition.

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """

if len(word) < 3:
        return ""

    vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
    for i in range(len(word)-2, 0, -1):
        if word[i] in vowels:
            if (word[i+1] not in vowels) and (word[i-1] not in vowels):
                re

def check(candidate):

    # Check some simple cases
    assert candidate("yogurt") == "u"
    assert candidate("full") == "u"
    assert candidate("easy") == ""
    assert candidate("eAsy") == ""
    assert candidate("ali") == ""
    assert candidate("bad") == "a"
    assert candidate("most") == "o"
    assert candidate("ab") == ""
    assert candidate("ba") == ""
    assert candidate("quick") == ""
    assert candidate("anime") == "i"
    assert candidate("Asia") == ""
    assert candidate("Above") == "o"

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between
    two consonants from the right side of the word (case sensitive).

    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition.

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
    if len(word) < 3:
        return ""

    vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
    for i in range(len(w

ord)-2, 0, -1):
        if word[i] in vowels:
            if (word[i+1] not in vowels) and (word[i-1] not in vowels):
                ret

def check(candidate):

    # Check some simple cases
    assert candidate("yogurt") == "u"
    assert candidate("full") == "u"
    assert candidate("easy") == ""
    assert candidate("eAsy") == ""
    assert candidate("ali") == ""
    assert candidate("bad") == "a"
    assert candidate("most") == "o"
    assert candidate("ab") == ""
    assert candidate("ba") == ""
    assert candidate("quick") == ""
    assert candidate("anime") == "i"
    assert candidate("Asia") == ""
    assert candidate("Above") == "o"

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between
    two consonants from the right side of the word (case sensitive).

    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition.

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
    if len(word) < 3:
        return ""

    vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
    for i in range(len(word)-2, 0, -1):
        if word[i] in vowels:

if (word[i+1] not in vowels) and (word[i-1] not in vowels):

def check(candidate):

    # Check some simple cases
    assert candidate("yogurt") == "u"
    assert candidate("full") == "u"
    assert candidate("easy") == ""
    assert candidate("eAsy") == ""
    assert candidate("ali") == ""
    assert candidate("bad") == "a"
    assert candidate("most") == "o"
    assert candidate("ab") == ""
    assert candidate("ba") == ""
    assert candidate("quick") == ""
    assert candidate("anime") == "i"
    assert candidate("Asia") == ""
    assert candidate("Above") == "o"

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between
    two consonants from the right side of the word (case sensitive).

    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition.

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
    if len(word) < 3:
        return ""

    vowels = {

", "E", 'O', 'U', 'I'}
    for i in range(len(word)-2, 0, -1):
        if word[i] in vowels:
            if (word[i+1] not in vowels) and (word[i-1] not in vowels):
                return word[i]
    return ""

def check(candidate):

    # Check some simple cases
    assert candidate("yogurt") == "u"
    assert candidate("full") == "u"
    assert candidate("easy") == ""
    assert candidate("eAsy") == ""
    assert candidate("ali") == ""
    assert candidate("bad") == "a"
    assert candidate("most") == "o"
    assert candidate("ab") == ""
    assert candidate("ba") == ""
    assert candidate("quick") == ""
    assert candidate("anime") == "i"
    assert candidate("Asia") == ""
    assert candidate("Above") == "o"

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between
    two consonants from the right side of the word (case sensitive).

    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition.

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
    if len(word) < 3:
        return ""

    vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U'

     if word[i] in vowels:
            if (word[i+1] not in vowels) and (word[i-1] not in vowels):
                return word[i]
    return ""

, 'I'}
    for i in range(len(word)-2, 0, -1):

def check(candidate):

    # Check some simple cases
    assert candidate("yogurt") == "u"
    assert candidate("full") == "u"
    assert candidate("easy") == ""
    assert candidate("eAsy") == ""
    assert candidate("ali") == ""
    assert candidate("bad") == "a"
    assert candidate("most") == "o"
    assert candidate("ab") == ""
    assert candidate("ba") == ""
    assert candidate("quick") == ""
    assert candidate("anime") == "i"
    assert candidate("Asia") == ""
    assert candidate("Above") == "o"

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
    def check(s):
        val = 0
        for i in s:
            if i == '(':
                val = val + 1
            else:
                val = val -

1
            if val < 0:
                return False
        return True if val == 0 else False

    S1 = lst[0] + lst[1]
    S2 = lst[1] + lst[0]
    return 'Yes' if chec

def check(candidate):

    # Check some simple cases
    assert candidate(['()(', ')']) == 'Yes'
    assert candidate([')', ')']) == 'No'
    assert candidate(['(()(())', '())())']) == 'No'
    assert candidate([')())', '(()()(']) == 'Yes'
    assert candidate(['(())))', '(()())((']) == 'Yes'
    assert candidate(['()', '())']) == 'No'
    assert candidate(['(()(', '()))()']) == 'Yes'
    assert candidate(['((((', '((())']) == 'No'
    assert candidate([')(()', '(()(']) == 'No'
    assert candidate([')(', ')(']) == 'No'

    # Check some edge cases that are easy to work out by hand.
    assert candidate(['(', ')']) == 'Yes'
    assert candidate([')', '(']) == 'Yes'


Prompt:
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
    def check(s):
        val = 0
        for i in s:
            if i == '(':
                val = val + 1
            else:
                val = val - 1
            if val < 0:

 lst[0] + lst[1]
    S2 = lst[1] + lst[0]
    return 'Yes' if check(S1) or check(S2) else 'No'

        return False
        return True if val == 0 else False

    S1 =

def check(candidate):

    # Check some simple cases
    assert candidate(['()(', ')']) == 'Yes'
    assert candidate([')', ')']) == 'No'
    assert candidate(['(()(())', '())())']) == 'No'
    assert candidate([')())', '(()()(']) == 'Yes'
    assert candidate(['(())))', '(()())((']) == 'Yes'
    assert candidate(['()', '())']) == 'No'
    assert candidate(['(()(', '()))()']) == 'Yes'
    assert candidate(['((((', '((())']) == 'No'
    assert candidate([')(()', '(()(']) == 'No'
    assert candidate([')(', ')(']) == 'No'

    # Check some edge cases that are easy to work out by hand.
    assert candidate(['(', ')']) == 'Yes'
    assert candidate([')', '(']) == 'Yes'


Prompt:
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
    def check(s):
        val = 0
        for i in s:
            if i == '(':

e

    S1 = lst[0] + lst[1]
    S2 = lst[1] + lst[0]
    return 'Yes' if check(S1) or check(S2) else 'No'

                val = val + 1
            else:
                val = val - 1
            if val < 0:
                return False
        return True if val == 0 else Fals

def check(candidate):

    # Check some simple cases
    assert candidate(['()(', ')']) == 'Yes'
    assert candidate([')', ')']) == 'No'
    assert candidate(['(()(())', '())())']) == 'No'
    assert candidate([')())', '(()()(']) == 'Yes'
    assert candidate(['(())))', '(()())((']) == 'Yes'
    assert candidate(['()', '())']) == 'No'
    assert candidate(['(()(', '()))()']) == 'Yes'
    assert candidate(['((((', '((())']) == 'No'
    assert candidate([')(()', '(()(']) == 'No'
    assert candidate([')(', ')(']) == 'No'

    # Check some edge cases that are easy to work out by hand.
    assert candidate(['(', ')']) == 'Yes'
    assert candidate([')', '(']) == 'Yes'


Prompt:
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
    def check(s):
        val = 0
        for i in s:
            if i == '(':
                v

1 = lst[0] + lst[1]
    S2 = lst[1] + lst[0]
    return 'Yes' if check(S1) or check(S2) else 'No'

al = val + 1
            else:
                val = val - 1
            if val < 0:
                return False
        return True if val == 0 else False

    S

def check(candidate):

    # Check some simple cases
    assert candidate(['()(', ')']) == 'Yes'
    assert candidate([')', ')']) == 'No'
    assert candidate(['(()(())', '())())']) == 'No'
    assert candidate([')())', '(()()(']) == 'Yes'
    assert candidate(['(())))', '(()())((']) == 'Yes'
    assert candidate(['()', '())']) == 'No'
    assert candidate(['(()(', '()))()']) == 'Yes'
    assert candidate(['((((', '((())']) == 'No'
    assert candidate([')(()', '(()(']) == 'No'
    assert candidate([')(', ')(']) == 'No'

    # Check some edge cases that are easy to work out by hand.
    assert candidate(['(', ')']) == 'Yes'
    assert candidate([')', '(']) == 'Yes'


Prompt:
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
    def check(s):
        val = 0
        for i in s:
            if i == '(':
                val = v

1 = lst[0] + lst[1]
    S2 = lst[1] + lst[0]
    return 'Yes' if check(S1) or check(S2) else 'No'

al + 1
            else:
                val = val - 1
            if val < 0:
                return False
        return True if val == 0 else False

    S

def check(candidate):

    # Check some simple cases
    assert candidate(['()(', ')']) == 'Yes'
    assert candidate([')', ')']) == 'No'
    assert candidate(['(()(())', '())())']) == 'No'
    assert candidate([')())', '(()()(']) == 'Yes'
    assert candidate(['(())))', '(()())((']) == 'Yes'
    assert candidate(['()', '())']) == 'No'
    assert candidate(['(()(', '()))()']) == 'Yes'
    assert candidate(['((((', '((())']) == 'No'
    assert candidate([')(()', '(()(']) == 'No'
    assert candidate([')(', ')(']) == 'No'

    # Check some edge cases that are easy to work out by hand.
    assert candidate(['(', ')']) == 'Yes'
    assert candidate([')', '(']) == 'Yes'


Prompt:
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
    def check(s):
        val = 0

lst[1]
    S2 = lst[1] + lst[0]
    return 'Yes' if check(S1) or check(S2) else 'No'

   for i in s:
            if i == '(':
                val = val + 1
            else:
                val = val - 1
            if val < 0:
                return False
        return True if val == 0 else False

    S1 = lst[0] +

def check(candidate):

    # Check some simple cases
    assert candidate(['()(', ')']) == 'Yes'
    assert candidate([')', ')']) == 'No'
    assert candidate(['(()(())', '())())']) == 'No'
    assert candidate([')())', '(()()(']) == 'Yes'
    assert candidate(['(())))', '(()())((']) == 'Yes'
    assert candidate(['()', '())']) == 'No'
    assert candidate(['(()(', '()))()']) == 'Yes'
    assert candidate(['((((', '((())']) == 'No'
    assert candidate([')(()', '(()(']) == 'No'
    assert candidate([')(', ')(']) == 'No'

    # Check some edge cases that are easy to work out by hand.
    assert candidate(['(', ')']) == 'Yes'
    assert candidate([')', '(']) == 'Yes'


Prompt:
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
    def check(s):
        val = 0
        for i in s:
            if i == '(':
                val =

return 'Yes' if check(S1) or check(S2) else 'No'

 val + 1
            else:
                val = val - 1
            if val < 0:
                return False
        return True if val == 0 else False

    S1 = lst[0] + lst[1]
    S2 = lst[1] + lst[0]

def check(candidate):

    # Check some simple cases
    assert candidate(['()(', ')']) == 'Yes'
    assert candidate([')', ')']) == 'No'
    assert candidate(['(()(())', '())())']) == 'No'
    assert candidate([')())', '(()()(']) == 'Yes'
    assert candidate(['(())))', '(()())((']) == 'Yes'
    assert candidate(['()', '())']) == 'No'
    assert candidate(['(()(', '()))()']) == 'Yes'
    assert candidate(['((((', '((())']) == 'No'
    assert candidate([')(()', '(()(']) == 'No'
    assert candidate([')(', ')(']) == 'No'

    # Check some edge cases that are easy to work out by hand.
    assert candidate(['(', ')']) == 'Yes'
    assert candidate([')', '(']) == 'Yes'


Prompt:
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
    def check(s):
        val = 0
        for i in s:
            if i == '(':
                val = val + 1
            else:
                val = val - 1
            if val < 0:
                return False
        re

return 'Yes' if check(S1) or check(S2) else 'No'

turn True if val == 0 else False

    S1 = lst[0] + lst[1]
    S2 = lst[1] + lst[0]

def check(candidate):

    # Check some simple cases
    assert candidate(['()(', ')']) == 'Yes'
    assert candidate([')', ')']) == 'No'
    assert candidate(['(()(())', '())())']) == 'No'
    assert candidate([')())', '(()()(']) == 'Yes'
    assert candidate(['(())))', '(()())((']) == 'Yes'
    assert candidate(['()', '())']) == 'No'
    assert candidate(['(()(', '()))()']) == 'Yes'
    assert candidate(['((((', '((())']) == 'No'
    assert candidate([')(()', '(()(']) == 'No'
    assert candidate([')(', ')(']) == 'No'

    # Check some edge cases that are easy to work out by hand.
    assert candidate(['(', ')']) == 'Yes'
    assert candidate([')', '(']) == 'Yes'


Prompt:
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
    def check(s):
        val = 0
        for i in s:
            if i == '(':
                val = val + 1
            el

if val == 0 else False

    S1 = lst[0] + lst[1]
    S2 = lst[1] + lst[0]
    return 'Yes' if check(S1) or check(S2) else 'No'

se:
                val = val - 1
            if val < 0:
                return False
        return True

def check(candidate):

    # Check some simple cases
    assert candidate(['()(', ')']) == 'Yes'
    assert candidate([')', ')']) == 'No'
    assert candidate(['(()(())', '())())']) == 'No'
    assert candidate([')())', '(()()(']) == 'Yes'
    assert candidate(['(())))', '(()())((']) == 'Yes'
    assert candidate(['()', '())']) == 'No'
    assert candidate(['(()(', '()))()']) == 'Yes'
    assert candidate(['((((', '((())']) == 'No'
    assert candidate([')(()', '(()(']) == 'No'
    assert candidate([')(', ')(']) == 'No'

    # Check some edge cases that are easy to work out by hand.
    assert candidate(['(', ')']) == 'Yes'
    assert candidate([')', '(']) == 'Yes'


Prompt:
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
    def check(s):
        val = 0
        for i in s:

 0:
                return False
        return True if val == 0 else False

    S1 = lst[0] + lst[1]
    S2 = lst[1] + lst[0]
    return 'Yes' if check(S1) or check(S2) else 'No'

    if i == '(':
                val = val + 1
            else:
                val = val - 1
            if val <

def check(candidate):

    # Check some simple cases
    assert candidate(['()(', ')']) == 'Yes'
    assert candidate([')', ')']) == 'No'
    assert candidate(['(()(())', '())())']) == 'No'
    assert candidate([')())', '(()()(']) == 'Yes'
    assert candidate(['(())))', '(()())((']) == 'Yes'
    assert candidate(['()', '())']) == 'No'
    assert candidate(['(()(', '()))()']) == 'Yes'
    assert candidate(['((((', '((())']) == 'No'
    assert candidate([')(()', '(()(']) == 'No'
    assert candidate([')(', ')(']) == 'No'

    # Check some edge cases that are easy to work out by hand.
    assert candidate(['(', ')']) == 'Yes'
    assert candidate([')', '(']) == 'Yes'


Prompt:
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """
    if k == 0:
        return []
    arr.sort()
    ans = arr


Prompt:
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """
    if

urn []
    arr.sort()
    ans = arr[-k:]
    return ans


Prompt:
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """
    if k == 0

:
        return []
    arr.sort()
    ans = arr[-k:]


Prompt:
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """

if k == 0:
        return []
    arr.sort()
    an


Prompt:
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """

   if k == 0:
        return []
    arr.sort()
    ans = arr


Prompt:
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """
    if k == 0:

   return []
    arr.sort()
    ans = arr[-k:]
    return


Prompt:
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """
    if k

   return []
    arr.sort()
    ans = arr[-k:]
    return ans


Prompt:
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """
    if k == 0:
        return []
    a


Prompt:
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """

if k == 0:
        return []
    arr.sort()
    ans = arr[-k


Prompt:
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """
    if k ==


Prompt:
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    return sum([x for idx, x in

def check(candidate):

    # Check some simple cases
    assert candidate([5, 8, 7, 1])    == 12
    assert candidate([3, 3, 3, 3, 3]) == 9
    assert candidate([30, 13, 24, 321]) == 0
    assert candidate([5, 9]) == 5
    assert candidate([2, 4, 8]) == 0
    assert candidate([30, 13, 23, 32]) == 23
    assert candidate([3, 13, 2, 9]) == 3

    # Check some edge cases that are easy to work out by hand.


Prompt:
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    return sum([x for idx, x in enu

def check(candidate):

    # Check some simple cases
    assert candidate([5, 8, 7, 1])    == 12
    assert candidate([3, 3, 3, 3, 3]) == 9
    assert candidate([30, 13, 24, 321]) == 0
    assert candidate([5, 9]) == 5
    assert candidate([2, 4, 8]) == 0
    assert candidate([30, 13, 23, 32]) == 23
    assert candidate([3, 13, 2, 9]) == 3

    # Check some edge cases that are easy to work out by hand.


Prompt:
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    return

sum([x for idx, x in enumerate(lst) if idx%2==0 and

def check(candidate):

    # Check some simple cases
    assert candidate([5, 8, 7, 1])    == 12
    assert candidate([3, 3, 3, 3, 3]) == 9
    assert candidate([30, 13, 24, 321]) == 0
    assert candidate([5, 9]) == 5
    assert candidate([2, 4, 8]) == 0
    assert candidate([30, 13, 23, 32]) == 23
    assert candidate([3, 13, 2, 9]) == 3

    # Check some edge cases that are easy to work out by hand.


Prompt:
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    return sum([x fo

def check(candidate):

    # Check some simple cases
    assert candidate([5, 8, 7, 1])    == 12
    assert candidate([3, 3, 3, 3, 3]) == 9
    assert candidate([30, 13, 24, 321]) == 0
    assert candidate([5, 9]) == 5
    assert candidate([2, 4, 8]) == 0
    assert candidate([30, 13, 23, 32]) == 23
    assert candidate([3, 13, 2, 9]) == 3

    # Check some edge cases that are easy to work out by hand.


Prompt:
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    return sum([x for idx

def check(candidate):

    # Check some simple cases
    assert candidate([5, 8, 7, 1])    == 12
    assert candidate([3, 3, 3, 3, 3]) == 9
    assert candidate([30, 13, 24, 321]) == 0
    assert candidate([5, 9]) == 5
    assert candidate([2, 4, 8]) == 0
    assert candidate([30, 13, 23, 32]) == 23
    assert candidate([3, 13, 2, 9]) == 3

    # Check some edge cases that are easy to work out by hand.


Prompt:
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    return sum([x for idx, x in e

def check(candidate):

    # Check some simple cases
    assert candidate([5, 8, 7, 1])    == 12
    assert candidate([3, 3, 3, 3, 3]) == 9
    assert candidate([30, 13, 24, 321]) == 0
    assert candidate([5, 9]) == 5
    assert candidate([2, 4, 8]) == 0
    assert candidate([30, 13, 23, 32]) == 23
    assert candidate([3, 13, 2, 9]) == 3

    # Check some edge cases that are easy to work out by hand.


Prompt:
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    return sum([x for idx, x in enumerate(lst) if i

def check(candidate):

    # Check some simple cases
    assert candidate([5, 8, 7, 1])    == 12
    assert candidate([3, 3, 3, 3, 3]) == 9
    assert candidate([30, 13, 24, 321]) == 0
    assert candidate([5, 9]) == 5
    assert candidate([2, 4, 8]) == 0
    assert candidate([30, 13, 23, 32]) == 23
    assert candidate([3, 13, 2, 9]) == 3

    # Check some edge cases that are easy to work out by hand.


Prompt:
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    return sum([x for idx, x

def check(candidate):

    # Check some simple cases
    assert candidate([5, 8, 7, 1])    == 12
    assert candidate([3, 3, 3, 3, 3]) == 9
    assert candidate([30, 13, 24, 321]) == 0
    assert candidate([5, 9]) == 5
    assert candidate([2, 4, 8]) == 0
    assert candidate([30, 13, 23, 32]) == 23
    assert candidate([3, 13, 2, 9]) == 3

    # Check some edge cases that are easy to work out by hand.


Prompt:
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    return sum([x fo

def check(candidate):

    # Check some simple cases
    assert candidate([5, 8, 7, 1])    == 12
    assert candidate([3, 3, 3, 3, 3]) == 9
    assert candidate([30, 13, 24, 321]) == 0
    assert candidate([5, 9]) == 5
    assert candidate([2, 4, 8]) == 0
    assert candidate([30, 13, 23, 32]) == 23
    assert candidate([3, 13, 2, 9]) == 3

    # Check some edge cases that are easy to work out by hand.


Prompt:
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    return s

def check(candidate):

    # Check some simple cases
    assert candidate([5, 8, 7, 1])    == 12
    assert candidate([3, 3, 3, 3, 3]) == 9
    assert candidate([30, 13, 24, 321]) == 0
    assert candidate([5, 9]) == 5
    assert candidate([2, 4, 8]) == 0
    assert candidate([30, 13, 23, 32]) == 23
    assert candidate([3, 13, 2, 9]) == 3

    # Check some edge cases that are easy to work out by hand.


Prompt:
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """
    return sum(e

lem for elem in arr[:k] if len(str(elem)) <= 2)

def check(candidate):

    # Check some simple cases
    assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
    assert candidate([111,121,3,4000,5,6], 2) == 0
    assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
    assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1], 1) == 1, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """
    retu

def check(candidate):

    # Check some simple cases
    assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
    assert candidate([111,121,3,4000,5,6], 2) == 0
    assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
    assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1], 1) == 1, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """

return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)

def check(candidate):

    # Check some simple cases
    assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
    assert candidate([111,121,3,4000,5,6], 2) == 0
    assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
    assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1], 1) == 1, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """
    return sum(elem for elem in arr[:k] if len(

def check(candidate):

    # Check some simple cases
    assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
    assert candidate([111,121,3,4000,5,6], 2) == 0
    assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
    assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1], 1) == 1, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """
    retur

def check(candidate):

    # Check some simple cases
    assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
    assert candidate([111,121,3,4000,5,6], 2) == 0
    assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
    assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1], 1) == 1, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """
    return sum(elem for elem in arr[:k] if len(str(elem))

def check(candidate):

    # Check some simple cases
    assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
    assert candidate([111,121,3,4000,5,6], 2) == 0
    assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
    assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1], 1) == 1, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """
    return sum(elem

def check(candidate):

    # Check some simple cases
    assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
    assert candidate([111,121,3,4000,5,6], 2) == 0
    assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
    assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1], 1) == 1, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """
    ret

def check(candidate):

    # Check some simple cases
    assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
    assert candidate([111,121,3,4000,5,6], 2) == 0
    assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
    assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1], 1) == 1, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """
    return sum(elem for elem in arr[:k] if len(s

def check(candidate):

    # Check some simple cases
    assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
    assert candidate([111,121,3,4000,5,6], 2) == 0
    assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
    assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1], 1) == 1, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """
    return sum(e

lem for elem in arr[:k] if len(str(elem)) <

def check(candidate):

    # Check some simple cases
    assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
    assert candidate([111,121,3,4000,5,6], 2) == 0
    assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
    assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1], 1) == 1, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the
    previous term as follows: if the previous term is even, the next term is one half of
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note:
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
    if n%2==0:
        odd_collatz = []
    else:
        odd_colla

 1

        if n%2 == 1:
            odd_collatz.append(int(n))

    return sorted(odd_collatz)

tz = [n]
    while n > 1:
        if n % 2 == 0:
            n = n/2
        else:
            n = n*3 +

def check(candidate):

    # Check some simple cases
    assert candidate(14) == [1, 5, 7, 11, 13, 17]
    assert candidate(5) == [1, 5]
    assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1) == [1], "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the
    previous term as follows: if the previous term is even, the next term is one half of
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note:
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
    if n%2==0:
        odd_collatz = []
    else:
        odd_collatz = [n]
    while

  if n % 2 == 0:
            n = n/2
        else:
            n = n*3 + 1

        if n%2 == 1:
            odd_collatz.append(int(n))

    return sorted(odd_collatz)

def check(candidate):

    # Check some simple cases
    assert candidate(14) == [1, 5, 7, 11, 13, 17]
    assert candidate(5) == [1, 5]
    assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1) == [1], "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the
    previous term as follows: if the previous term is even, the next term is one half of
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note:
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
    if

n%2 == 1:
            odd_collatz.append(int(n))

    return sorted(odd_collatz)

n%2==0:
        odd_collatz = []
    else:
        odd_collatz = [n]
    while n > 1:
        if n % 2 == 0:
            n = n/2
        else:
            n = n*3 + 1

        if

def check(candidate):

    # Check some simple cases
    assert candidate(14) == [1, 5, 7, 11, 13, 17]
    assert candidate(5) == [1, 5]
    assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1) == [1], "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the
    previous term as follows: if the previous term is even, the next term is one half of
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note:
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
    if n%2==0:
        odd_collatz = []

 n > 1:
        if n % 2 == 0:
            n = n/2
        else:
            n = n*3 + 1

        if n%2 == 1:
            odd_collatz.append(int(n))

    return sorted(odd_collatz)

   else:
        odd_collatz = [n]
    while

def check(candidate):

    # Check some simple cases
    assert candidate(14) == [1, 5, 7, 11, 13, 17]
    assert candidate(5) == [1, 5]
    assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1) == [1], "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the
    previous term as follows: if the previous term is even, the next term is one half of
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note:
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
    if n%2==0:
        odd_collatz = []
    else:
        odd_collatz = [n]
    while n > 1:
        if n %

            n = n*3 + 1

        if n%2 == 1:
            odd_collatz.append(int(n))

    return sorted(odd_collatz)

def check(candidate):

    # Check some simple cases
    assert candidate(14) == [1, 5, 7, 11, 13, 17]
    assert candidate(5) == [1, 5]
    assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1) == [1], "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the
    previous term as follows: if the previous term is even, the next term is one half of
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note:
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
    if n%2==0:

 n/2
        else:
            n = n*3 + 1

        if n%2 == 1:
            odd_collatz.append(int(n))

    return sorted(odd_collatz)

       odd_collatz = []
    else:
        odd_collatz = [n]
    while n > 1:
        if n % 2 == 0:
            n =

def check(candidate):

    # Check some simple cases
    assert candidate(14) == [1, 5, 7, 11, 13, 17]
    assert candidate(5) == [1, 5]
    assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1) == [1], "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the
    previous term as follows: if the previous term is even, the next term is one half of
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note:
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
    if n%2==0:
        odd_collatz = []
    else:
        odd_collatz = [n]
    while n > 1:
        if n % 2 == 0:
            n = n/2
        el

se:
            n = n*3 + 1

        if n%2 == 1:
            odd_collatz.append(int(n))

    return sorted(odd_colla

def check(candidate):

    # Check some simple cases
    assert candidate(14) == [1, 5, 7, 11, 13, 17]
    assert candidate(5) == [1, 5]
    assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1) == [1], "This prints if this assert fails 2 (also good for debugging!)"