Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:

            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:

                dict1[i]=t
    return dict1

        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:

        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:

        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':

    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':

        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

            t=list1.count(i)
    if t>0:

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':

            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

            t=list1.count(i)
    if t>0:
        for i in list1:

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':

                dict1[i]=t
    return dict1

            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':

            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':

            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)

        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)

            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)

                dict1[i]=t
    return dict1

    if t>0:
        for i in list1:
            if(list1.count(i)==t):

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)

    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)

    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:

            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:

                dict1[i]=t
    return dict1

        for i in list1:
            if(list1.count(i)==t):

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:

        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:

        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:

            if(list1.count(i)==t):

                dict1[i]=t

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:

            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t
    return dict1

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    dict1={}
    list1=test.split(" ")
    t=0

    for i in list1:
        if(list1.count(i)>t) and i!='':
            t=list1.count(i)
    if t>0:
        for i in list1:
            if(list1.count(i)==t):

                dict1[i]=t

def check(candidate):

    # Check some simple cases
    assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate('b b b b a') == {'b': 4}, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, "This prints if this assert fails 6 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('') == {}, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate('a') == {'a': 1}, "This prints if this assert fails 8 (also good for debugging!)"


Prompt:
def reverse_delete(s,c):
    """Task
    We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
    then check if the result string is palindrome.
    A string is called palindrome if it reads the same backward as forward.
    You should return a tuple containing the result string and True/False for the check.
    Example
    For s = "abcde", c = "ae", the result should be ('bcd',False)
    For s = "abcdef", c = "b"  the result should be ('acdef',False)
    For s = "abcdedcba", c = "ab", the result should be ('cdedc',True)
    """

s = ''.join([char for char in s if char not in c])

def check(candidate):

    assert candidate("abcde","ae") == ('bcd',False)
    assert candidate("abcdef", "b") == ('acdef',False)
    assert candidate("abcdedcba","ab") == ('cdedc',True)
    assert candidate("dwik","w") == ('dik',False)
    assert candidate("a","a") == ('',True)
    assert candidate("abcdedcba","") == ('abcdedcba',True)
    assert candidate("abcdedcba","v") == ('abcdedcba',True)
    assert candidate("vabba","v") == ('abba',True)
    assert candidate("mamma", "mia") == ("", True)


Prompt:
def reverse_delete(s,c):
    """Task
    We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
    then check if the result string is palindrome.
    A string is called palindrome if it reads the same backward as forward.
    You should return a tuple containing the result string and True/False for the check.
    Example
    For s = "abcde", c = "ae", the result should be ('bcd',False)
    For s = "abcdef", c = "b"  the result should be ('acdef',False)
    For s = "abcdedcba", c = "ab", the result should be ('cdedc',True)
    """

    s = ''.join([char for char in s if char not in c])
    return (s,s[::-1] == s)

def check(candidate):

    assert candidate("abcde","ae") == ('bcd',False)
    assert candidate("abcdef", "b") == ('acdef',False)
    assert candidate("abcdedcba","ab") == ('cdedc',True)
    assert candidate("dwik","w") == ('dik',False)
    assert candidate("a","a") == ('',True)
    assert candidate("abcdedcba","") == ('abcdedcba',True)
    assert candidate("abcdedcba","v") == ('abcdedcba',True)
    assert candidate("vabba","v") == ('abba',True)
    assert candidate("mamma", "mia") == ("", True)


Prompt:
def reverse_delete(s,c):
    """Task
    We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
    then check if the result string is palindrome.
    A string is called palindrome if it reads the same backward as forward.
    You should return a tuple containing the result string and True/False for the check.
    Example
    For s = "abcde", c = "ae", the result should be ('bcd',False)
    For s = "abcdef", c = "b"  the result should be ('acdef',False)
    For s = "abcdedcba", c = "ab", the result should be ('cdedc',True)
    """
    s = ''.join([char for char in s if char not in c])

def check(candidate):

    assert candidate("abcde","ae") == ('bcd',False)
    assert candidate("abcdef", "b") == ('acdef',False)
    assert candidate("abcdedcba","ab") == ('cdedc',True)
    assert candidate("dwik","w") == ('dik',False)
    assert candidate("a","a") == ('',True)
    assert candidate("abcdedcba","") == ('abcdedcba',True)
    assert candidate("abcdedcba","v") == ('abcdedcba',True)
    assert candidate("vabba","v") == ('abba',True)
    assert candidate("mamma", "mia") == ("", True)


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """

    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """

        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """

        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

    res = []
    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """

    res = []
    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """

    res = []
    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []

        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []

        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []

    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []

    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []
    for arr in lst:

        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []
    for arr in lst:

        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []
    for arr in lst:

        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []
    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)

res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []
    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)

        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    res = []
    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """

    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """

    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """

        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

    max_sum = 0
    s = 0
    for num in nums:

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """

        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

    max_sum = 0
    s = 0
    for num in nums:
        s += -num

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """

            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """

        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """

    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """

        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """

    min_sum = -max_sum
    return min_sum

    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """

    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """

    max_sum = 0
    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0

    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0

        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0

        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

    s = 0
    for num in nums:
        s += -num

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0

            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

    s = 0
    for num in nums:
        s += -num
        if (s < 0):

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0

        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0

    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0

        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0

    min_sum = -max_sum
    return min_sum

    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0

    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0

    s = 0
    for num in nums:
        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1


Prompt:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    max_sum = 0
    s = 0

        s += -num
        if (s < 0):
            s = 0
        max_sum = max(s, max_sum)
    if max_sum == 0:
        max_sum = max(-i for i in nums)
    min_sum = -max_sum
    return min_sum

def check(candidate):

    # Check some simple cases
    assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([-1, -2, -3]) == -6
    assert candidate([-1, -2, -3, 2, -10]) == -14
    assert candidate([-9999999999999999]) == -9999999999999999
    assert candidate([0, 10, 20, 1000000]) == 0
    assert candidate([-1, -2, -3, 10, -5]) == -6
    assert candidate([100, -1, -2, -3, 10, -5]) == -6
    assert candidate([10, 11, 13, 8, 3, 4]) == 3
    assert candidate([100, -33, 32, -1, 0, -2]) == -33

    # Check some edge cases that are easy to work out by hand.
    assert candidate([-10]) == -10, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([7]) == 7
    assert candidate([1, -1]) == -1